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of a pseudo vector is just like what is there for a vector. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xnXvyQYxow4_109.wav |
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you do not know anything it can be lengthy I say. What is by lengthy? I am not giving | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xo4gv-I0Ruw_173.wav |
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. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xoAU2J_JeoM_58.wav |
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you | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xo_uZBrHotI_460.wav |
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And, this is what makes it different, from other disciplines. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xp-9DvMTwuE_179.wav |
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form actually; that is what we are going to show. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xpLc4b984zc_160.wav |
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there is some address give to that node instead of the way the global address space was given | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xs727GE6AM4_236.wav |
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I write this in an integral ?? T so I am going to write this as DT w by D ? which is the | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xsXYFGdV5V8_264.wav |
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so that the second term here minus integral at omega0, how do I write now? Delta ui, very | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xt4mvADa0mw_92.wav |
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of L over omega H that is mu 1, mu 2 sigma square: mu 1 is equal to mu 2 and sigma square | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xtBbj6IfYKY_38.wav |
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So, you can understand it in that way the total amount of motion and rest is the infinite | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xtlXNBwBCrQ_559.wav |
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was going at a velocity here without without any sway velocity. Now, I have got this sway | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xtpdgUqRMlo_237.wav |
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system where you have the paired electron. So, that you all know that this second thing | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xuI4KMH3ZZc_445.wav |
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power s plus kp plus i it will be is equal to R power s plus I in this case when q is | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xuhZSt4Rw0k_161.wav |
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to do let us forget about this channel noise right now | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xuqe1pWwf7U_95.wav |
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is far away and writing to text longer then writing to ready right so ready got done data | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xv3XCYmdTkQ_342.wav |
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there were 2 definitions for incompressible flow. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xvASvEHs5sI_122.wav |
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1, 2, 3 and j 0, 1, 2, 3. So, now the boundary u | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xvGO0AxuO1A_128.wav |
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the pressure there always has to be the same as the ambient pressure. So the impingement | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xvasNmeZBWc_260.wav |
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subtract from this here, so, this becomes plus half; this is minus half 0 minus half | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xwIyd4oCygo_73.wav |
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be the techniques of it? | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xwtgJ0jsJE4_179.wav |
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we can have these amino acid residues can supply good donor atoms to coordinate to the | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xxBxhYK8rSU_398.wav |
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point 1 u f you can see the cloud forming, okay. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xy7Gy8KmYTY_60.wav |
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obviously we will have to tell that well these are the testing or these are the tests that | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xyxWyvA0Ppo_284.wav |
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and ah ah one has to prove that ah and this is how one proves it so um so lets lets do | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xz5VprwtFEY_413.wav |
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Let us try to understand this variation in a bit more details. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/xztDNgsY13Q_119.wav |
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by 0.52, so according to an observer in s double prime frame the charge is moving in | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y-xBbg5q7Jk_406.wav |
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indifferent, this is the strategy that player 1 will keep in mind when he decides his optimal | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y0-RJl_RocM_164.wav |
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And it depends on whether if he is benevolent or equity sensitive, or he is the entitled | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y0H8ZOTB_dg_186.wav |
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of the left hand side and the transpose of the right hand side. And this equation becomes | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yLo7KJCmNzg_56.wav |
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as I have seen this is not is equal to D this is mass transport coefficient So, this is | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yM3zWGMnLmo_25.wav |
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comparator can also be given as large time as necessary for the auto zero capacitors | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yMSgzkiAQ3A_313.wav |
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a finite element model. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yNJGZ0NwdpM_499.wav |
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You also need to consider the minimum permissible velocity. Why the minimum permissible velocity, | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yNNaLnlkqYo_65.wav |
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of the product. It is the product of the moduli, plural of modulus is moduli. If I have 2 complex | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yOWT-STIbag_320.wav |
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in hot condition, suitable for welding of thicker steels, and steels with higher carbon | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yOdXvagHK_M_464.wav |
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so, normally what happens here is in a fluid flow problem, you know I am just put a diverging | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yOwCLNFN66k_112.wav |
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the various type of dampers like the voltage oscillations. If they are there then we are | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yP7OACmLP48_101.wav |
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nonlinear system, feedback linearization technique for nonlinear system, direct adaptive control | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yPfHGYulXc0_335.wav |
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with how we understand vectors and what will see in this now, is that we want | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yPvYn0kOyjI_283.wav |
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x is related to y then y is related to x for all x y ? a that is R is symmetric if x is | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yQ03lewFU8U_87.wav |
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noun and plural noun and in the part of speech tag corpus, which is used for training if | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yQ2qMzRI1b8_84.wav |
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a y of x is equal to 0. This equation where a and c are this is known as the confluent | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yQfm0RyduxY_166.wav |
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two again, this is if it is a bipolar then you are having here and then, it is here connected. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yRXvFrzUnug_27.wav |
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1 photon ,there is 1 way of getting both photons in 3, and none other than 4, because this | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yRZuWst1dbo_114.wav |
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Hence, you get a system of equations, so we will pay more attention to the implicit method | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ySFnHjfMKd8_246.wav |
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one can important impose a very strict and stringent regulation about environmental management | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ySLUsdL1m6k_188.wav |
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when you see some data you could infer different possible hypothesis. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ySTr4TO3IiU_386.wav |
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to H1, in this case there is a H2, so H2 to H1 and kz dz. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ySUn9Rky1DY_294.wav |
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be filled with and without water. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ySUr60U6jiM_459.wav |
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classified various I L P machine. And this is the first classification where he classified | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yT4uhDMDp8o_55.wav |
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So, that angle normally decided that where they will lead it is normally decided by the | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yTwcX-EwGOY_247.wav |
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ahh this is a vast source and this most of the data which is been which is available | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yU1eNIbskTk_221.wav |
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The equipment that is used for testing a sample in the laboratory is known as the oedometer. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yV20t-MHxTg_390.wav |
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or less the same as what Rayleigh-Jeans proposed | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yVN09TdSHHg_26.wav |
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contains z and vice-versa So, the equality of these two definitions | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yV_v6zxADgY_375.wav |
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will give you immediately as long as this angle is less than 180 degrees. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yVorHR_yJ6w_192.wav |
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multicollinearity issue? due to multicolinearity Fourth is how to detect? how to detect So | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yW31us3V5zg_361.wav |
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published by the company in terms of the balance sheet income statement all; so, this is the | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yWIeTQfyZHE_617.wav |
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Let me choose one omega I. What this mean? This means I have a wave which is this particular | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yWTJIb46cpE_253.wav |
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So, I think definitely you have to follow, I mean, the continuity is a subject, continuity | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yWUk1NI_Q_g_322.wav |
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x i and x j, and then for all the variables having values greater than x j. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yWxoC3k-PW8_197.wav |
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quantization noise has to go somewhere, our plant and like other plants. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yY6gJ2W4X4M_24.wav |
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has to be completed by that worker or that equipment. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yYIVumq6sVM_569.wav |
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This is a very common way of using post. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yYy3oAapQHM_422.wav |
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and timing variant. If the input is the output corresponding to the impulse as an | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yZ1MDsr5G5Y_121.wav |
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in most switch mode converters dc dc converters power converters. Now, let us go a bit mode | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yZ9tfsmzvpk_101.wav |
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to M times mod z 1 minus z 2 this is what I will get because I can replace this f hash | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yZFn3rojyAA_259.wav |
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possibility of sharing, there is no possibility of congestion. And the second important advantage | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yZV3y-usK_g_139.wav |
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Because I can as well write this in a other way manner; that is all contributions of what | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y_67Dqu4soo_30.wav |
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which is omega variation omega m is taken or is the modal frequency and specific mode. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y_EPnxLhj5Y_228.wav |
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I said if D by 2 r is more than 1, which is normally the situation spacing is always more | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y_UJvHMEun0_92.wav |
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Eg., they have something called Timeline consistency model. The basic idea is, a particular object | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/y_WLkS3yP5M_113.wav |
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So, the total strain in one direction or along one is due to the application of the hydrostatic | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yaxmnGTrZrA_383.wav |
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So, the actual gain that you get will be in terms of set gain one can obtain. So, if I | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yb4YNZ0X3SE_178.wav |
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impression that they have a high profit. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ybmDUg8S02g_160.wav |
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so we would like to have this tabular form okay so in this lecture we would stop at this | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ycH-AP_7n8U_295.wav |
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So, that is what he says that attenuation will be more in a thin coax cable compared | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ycpDqmlPRdc_148.wav |
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Next if you put x is equal to L here this is minus 12L square, this is plus 12L square; | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ydflDCPUgYo_139.wav |
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macroscopic energy to internal energy. So mechanical energy to internal energy. So we | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ydjXmcQn_zk_114.wav |
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concept is the same the methodology of calculating phi bar remains the same however that energy | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ydt4Hm4L4bQ_25.wav |
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Decrease the residence time Kinetics varies | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yeJ5TLFUGNo_64.wav |
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We are working with finite dimensional linear vector spaces. And I want to show, that the | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yeJodeFuDd0_47.wav |
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Therefore, first we have to move towards the left side. That means we will move towards | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yePqOE53AgY_304.wav |
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t = 5, then for t = 1, this is the first expansion, for t = 2, this is the second expansion. So, | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yecGyZFyfbQ_161.wav |
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the peclet number, the Reynolds number and the dimensionless fluxes. So, that briefly | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yehPVQB8AJU_448.wav |
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trigonometry also hold for complex sin and cosine functions. So, for example, so I will | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yfruyHKBTl8_71.wav |
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of the fluid should be low One of the reasons for this is so that it can easily flow in | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ygdAnz97fVI_58.wav |
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expression in terms of number of variables and number of terms involving a non essential | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ygm25sqqepg_84.wav |
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is the A M wave form; another is A M detected wave form. That is, what is in between that | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yhYLt9aFqBM_349.wav |
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In this case, the output is lesser than the input. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yhvXfAC8AtA_331.wav |
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have the inertia force in the vertical direction that will be m into del square v by del t | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yiH5FPrvQe8_181.wav |
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square. So, a square minus plus a dagger square minus a a dagger minus a dagger a, this goes | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yis0Chfc8c4_84.wav |
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this prevail cases that we express the given function as some of simpler functions well. | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yityOaXR9kY_158.wav |
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a quotient of homogeneous polynomials of the same degree ok. Whereas on affine in affine | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yjUh100FqpE_56.wav |
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here. How is this dipole field produced, this dipole field is produced by the currents the | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ykD80iHdL04_137.wav |
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of a, upon probability of b 1 and probability of a given b 2, is equal to probability of | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ykLy7coEVRk_78.wav |
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are possible out of this. So, there are let us say a large number dichotomies which will | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/yk_dsPu9Hmg_450.wav |
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are going to use the same coefficients A n in this series; lambda values 2 were tabulated | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ykhHwSP9d5Q_34.wav |
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be factor over | /content/drive/MyDrive/IITKGP/dataset/tie_train_dataset/wav1/ykzJO3xVL3M_279.wav |
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