diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/0S3RQpMgcY8_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/0S3RQpMgcY8_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..1b3cf8ace341cd3a8626323f34660386a10f8273
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/0S3RQpMgcY8_postprocess.srt
@@ -0,0 +1,1196 @@
+1
+00:00:00,000 --> 00:00:05,160
+بسم الله الرحمن الرحيم سنبدأ بشرح مساق فيزياء عامة
+
+2
+00:00:05,160 --> 00:00:11,520
+لطلبة العلوم الصحية من كتاب college physics للمؤلف
+
+3
+00:00:11,520 --> 00:00:18,680
+Sir Wei هنبدأ بالفصل الأول اللي هي المحاضرات لطلبة
+
+4
+00:00:18,680 --> 00:00:25,650
+العلوم الصحيةالهدف من هذا المساق هو عبارة عن هدف
+
+5
+00:00:25,650 --> 00:00:32,310
+ذو شقين تزويد الطالب بعرض واضح ومنطقي لأساليب
+
+6
+00:00:32,310 --> 00:00:38,450
+الفيزياء تعزيز وتقويت فهم الطلبة لمجموعة واسعة من
+
+7
+00:00:38,450 --> 00:00:42,990
+الأمور والاهتمامات والتطبيقات في الحياة ولتحقيق
+
+8
+00:00:42,990 --> 00:00:50,890
+هذه الأهداف سنعمل على تحفيز الطالبمن خلال يعني
+
+9
+00:00:50,890 --> 00:00:57,230
+أمثلة عملية تظهر دور الفيزياء في التخصصات الأخرى
+
+10
+00:00:57,230 --> 00:01:04,390
+سنبدأ ان شاء الله بشطر الأول شطر الأول هو عبارة عن
+
+11
+00:01:04,390 --> 00:01:09,430
+ال units اللي هي الوحدات tri-geometry اللي هي
+
+12
+00:01:09,430 --> 00:01:14,450
+الحساب المثلثات and vectors اللي هو المتجهات
+
+13
+00:01:15,230 --> 00:01:21,250
+section 11 standards of length, mass and time
+
+14
+00:01:21,250 --> 00:01:28,130
+المعايير الأساسية أو المقاييس الأساسية للطول
+
+15
+00:01:28,130 --> 00:01:34,290
+والكتلة والزمنلحساب طبعا او لقياس كأي كمية
+
+16
+00:01:34,290 --> 00:01:40,930
+فيزيائية بحتاج أنا إلى وحدة لكي أفرق بين أي رقم
+
+17
+00:01:40,930 --> 00:01:48,750
+رياضي أو رقم فيزيائي فالوحدة هي اللتي تميز هذا
+
+18
+00:01:48,750 --> 00:01:56,720
+الرقم على أنه كمية فيزيائيةفي عام 1960 وافقت
+
+19
+00:01:56,720 --> 00:02:02,140
+اللجنة الدولية على اعتماد نظام معياري للوحدات وهذا
+
+20
+00:02:02,140 --> 00:02:06,820
+النظام المعياري بنسمي SI أو system international
+
+21
+00:02:06,820 --> 00:02:12,220
+هو عبارة عن النظام الدولي النظام الدولي طبعا
+
+22
+00:02:12,220 --> 00:02:17,300
+الكميات الأساسية في هذا النظام ووحدات اللي هي
+
+23
+00:02:17,300 --> 00:02:23,130
+الطول و الكتلة و الزمنالمتر والكيلو جرام والثانية
+
+24
+00:02:23,130 --> 00:02:30,090
+على التوالي يعني النظام الدولي رمزه SI معناها ال
+
+25
+00:02:30,090 --> 00:02:34,590
+system international ال system international وحدته
+
+26
+00:02:34,590 --> 00:02:41,010
+طبعا وحدة يقيس بالكيلو جرام متر ثانية يعني الطول
+
+27
+00:02:41,010 --> 00:02:44,890
+يقاس بالمتر و الكتلة اللي هي ال mass تقاس بالكيلو
+
+28
+00:02:44,890 --> 00:02:49,350
+جرام و ال time اللي هو الزمن يقاس بالثانية
+
+29
+00:02:53,590 --> 00:02:58,250
+بالنسبة للطول .. بالنسبة للطول طبعا هو عبارة عن ال
+
+30
+00:02:58,250 --> 00:03:07,970
+length في عام 1977 .. 1900 أو 1799 أصبح ال meter
+
+31
+00:03:07,970 --> 00:03:13,650
+هو عبارة عن المقياس المعياري أو القانونيلطول في
+
+32
+00:03:13,650 --> 00:03:22,290
+فرنسا في عام 1983 تم تعريف المتر بإن المسافة التي
+
+33
+00:03:22,290 --> 00:03:28,370
+يقطعها الأضوء في الفراغ في فترة زمنية تساوي 1 على
+
+34
+00:03:28,370 --> 00:03:33,710
+2.99792458
+
+35
+00:03:33,710 --> 00:03:39,740
+أو 1 على 2.9108The meter was defined يعني المتر
+
+36
+00:03:39,740 --> 00:03:43,880
+يعرف به المسافة التي the distance travelled by
+
+37
+00:03:43,880 --> 00:03:47,760
+light المسافة التي يقطعها الضوء في الفراغ vacuum
+
+38
+00:03:47,760 --> 00:03:53,320
+فراغ خلال during time interval خلال الفترة 1 على 2
+
+39
+00:03:53,320 --> 00:03:59,300
+.9 في 10 رقص تمانية ثانية This latest definition
+
+40
+00:03:59,300 --> 00:04:02,720
+established the speed of a light طبعا هذا التعريف
+
+41
+00:04:02,720 --> 00:04:10,720
+الخاص بالمتريوصلنا ل .. اللي هي سرعة الضوء و من
+
+42
+00:04:10,720 --> 00:04:14,800
+خلاله يتم اعتماد سرعة الضوء و هي عبارة عن 2
+
+43
+00:04:14,800 --> 00:04:19,840
+.99792458
+
+44
+00:04:19,840 --> 00:04:24,800
+في عشر عقوس تمانية او 2.99792458
+
+45
+00:04:24,800 --> 00:04:29,700
+او ممكن نقربها الى 3 في عشر عقوس تمانية متر per
+
+46
+00:04:29,700 --> 00:04:30,320
+second
+
+47
+00:04:36,010 --> 00:04:42,490
+بالنسبة للكتلة اللي هي ال mass تعريفها الكتلة ال
+
+48
+00:04:42,490 --> 00:04:46,390
+system international الاصئعي unit of mass اللي هو
+
+49
+00:04:46,390 --> 00:04:51,310
+الكتلة في ان وحدة الكتلة في النظام الدولي هي عبارة
+
+50
+00:04:51,310 --> 00:04:56,110
+عن ال kilogram و تعريفها is defined as تعرف as the
+
+51
+00:04:56,110 --> 00:05:00,550
+mass of a specific platinum iridium alloy cylinder
+
+52
+00:05:00,550 --> 00:05:03,730
+kept at the international period of weights and
+
+53
+00:05:03,730 --> 00:05:09,130
+measures at Sievers Franceيعني معناها تعريف اللي
+
+54
+00:05:09,130 --> 00:05:13,690
+هي الكتلة في النظام الدولي عبارة عن كتلة سبيكة
+
+55
+00:05:13,690 --> 00:05:19,230
+أسطوانيةمن ال platinum iridium محفوظة في طبعا
+
+56
+00:05:19,230 --> 00:05:24,010
+المركز أو المكتب الدولي الأوزان في فرنسا والشكل
+
+57
+00:05:24,010 --> 00:05:29,310
+واحد واحد طبعا يوضح هذه السبيكة اللي هي عبارة عن
+
+58
+00:05:29,310 --> 00:05:35,850
+استوانة مصنوعة من platinum iridium ومحفوظة في مركز
+
+59
+00:05:35,850 --> 00:05:41,070
+أو المكتب الدولي في فرنسا بالنسبة للزمن اللي هي ال
+
+60
+00:05:41,070 --> 00:05:46,990
+timeالزمن the basic unit of time طبعا الزمن هو ال
+
+61
+00:05:46,990 --> 00:05:51,130
+.. ال .. يعني الوحدة الأساسية للزمن هي الثانية و
+
+62
+00:05:51,130 --> 00:05:56,650
+the .. is defined as تعريفها as تسعة واحد تسعة
+
+63
+00:05:56,650 --> 00:06:00,490
+اتنين ستة تلاتة واحد سبعة zero zero times هي عبارة
+
+64
+00:06:00,490 --> 00:06:05,410
+عن طبعا عدد معين عدد المرات أو عدد الدورات التي
+
+65
+00:06:05,410 --> 00:06:11,770
+تحتزها ذرة .. ذرهات ال cesiumأو عدد اللي هي
+
+66
+00:06:11,770 --> 00:06:17,750
+الدبدبات اللتي تهتزها أو تشيعها ضرر مصنوعة من ال
+
+67
+00:06:17,750 --> 00:06:25,780
+cesiumبالنسبة ل section 1.14 طبعا هذا ملغي section
+
+68
+00:06:25,780 --> 00:06:31,880
+121314 برضه ملغي بالنسبة لطلبة العلوم الصحية
+
+69
+00:06:31,880 --> 00:06:37,720
+section 15 unit conversion for physical quantity
+
+70
+00:06:37,720 --> 00:06:42,800
+اللي هو عبارة عن تحويل الوحدات لكميات الفيزيائية
+
+71
+00:06:43,380 --> 00:06:48,700
+conversion factors between SI and US بدي أحول أنا
+
+72
+00:06:48,700 --> 00:06:52,500
+بعض المعاملات بين اللي هي النظام الدولي اللي هي SI
+
+73
+00:06:52,500 --> 00:06:56,020
+system international و بين اللي هي ال united
+
+74
+00:06:56,020 --> 00:07:02,380
+states النظام الأمريكي لبعض الوحدات زي مثلا لما
+
+75
+00:07:02,380 --> 00:07:06,640
+أجي أحكي واحد ميل الواحد ميل بدي يساوي ألف و سبعة
+
+76
+00:07:06,640 --> 00:07:11,790
+أو ستمية أو تسعة متر و يساوي واحد point ستةكيلو
+
+77
+00:07:11,790 --> 00:07:15,930
+متر تقريبا الواحد متر بدى يساوي تسعة و تلاتين
+
+78
+00:07:15,930 --> 00:07:19,430
+point تلاتة سبعة inch و بدها تساوي تلاتة point
+
+79
+00:07:19,430 --> 00:07:24,230
+اتنين تمانية واحد feet او قدم الواحد feet او واحد
+
+80
+00:07:24,230 --> 00:07:28,770
+foot بتساوي القدم بتساوي point تلاتة متر يعني
+
+81
+00:07:28,770 --> 00:07:33,610
+تلاتين point اربعة تمانية مترالواحد inch بدها
+
+82
+00:07:33,610 --> 00:07:38,030
+تساوي اتنين و نص سانتي أو خمسة و عشرين من الف من
+
+83
+00:07:38,030 --> 00:07:41,270
+المتر الواحد inch بيساوي خمسة و عشرين من الف من
+
+84
+00:07:41,270 --> 00:07:45,970
+المتر ممكن احكي انه التلاتين سانتي بدها تساوي قدم
+
+85
+00:07:45,970 --> 00:07:53,070
+و ال inch اللي هي بيساوي اتنين و نص سانتي we can
+
+86
+00:07:53,070 --> 00:07:56,090
+take fraction with the conversion that will cancel
+
+87
+00:07:56,090 --> 00:07:59,920
+the units we don't wantand multiply that fraction
+
+88
+00:07:59,920 --> 00:08:04,000
+by the quantity in questions for example يعني
+
+89
+00:08:04,000 --> 00:08:11,400
+بالنسبة لبعض تحويل بعض الوحدات يعني
+
+90
+00:08:11,400 --> 00:08:17,040
+كمثال طبعا الحل الهدف من تحويل الوحدات باستخدام
+
+91
+00:08:17,040 --> 00:08:23,490
+عدة عوامل تحويل المتر مثلاالى meal او ال .. يعني
+
+92
+00:08:23,490 --> 00:08:27,990
+لو انا حكيت مثال انه خمسة عشر انش مطلوب مني احولهم
+
+93
+00:08:27,990 --> 00:08:35,600
+لصنتىفبعرف أنا بعرف أن ال 1 inch بدي ساوي 2.54 cm
+
+94
+00:08:35,600 --> 00:08:42,440
+إذا ال 15 ممكن أضربها في 2.54 أو لتخلص من الوحدات
+
+95
+00:08:42,440 --> 00:08:46,660
+بنحكي ال 15 inch راح أضربها أنا ب fraction في كسر
+
+96
+00:08:46,660 --> 00:08:49,840
+زي ما حكالي هو fraction by the quantity in the
+
+97
+00:08:49,840 --> 00:08:57,910
+cushions الآن 2.54 cm ال 1 inch بتساوي 2.45فضربت
+
+98
+00:08:57,910 --> 00:09:04,630
+في 2.54 cm على 1 inch ال inch الوحدة دي راحت معاها
+
+99
+00:09:04,630 --> 00:09:15,050
+دل عندي 38.1 cm مثال
+
+100
+00:09:15,050 --> 00:09:18,990
+آخر example 1.4 convert units using several
+
+101
+00:09:18,990 --> 00:09:25,150
+conversion factorsبدأ أستخدم الوحدات أيضا لعدد
+
+102
+00:09:25,150 --> 00:09:29,710
+أنواع أو عوامل التحولات convert ال meter to mile
+
+103
+00:09:29,710 --> 00:09:34,230
+بدأ أحول ال meter إلى mile لو كان عندي أنا عشرين
+
+104
+00:09:34,230 --> 00:09:38,110
+meter في الثانية و بدأ أحولها إلى mile في الثانية
+
+105
+00:09:38,110 --> 00:09:42,050
+طبعا ال 28 mile في الثانية بروح لل bus ال bus هو
+
+106
+00:09:42,050 --> 00:09:45,890
+عبارة عن meter بدأ أحوله إلى mileلما أحول من متر
+
+107
+00:09:45,890 --> 00:09:54,350
+لميل بأقسم على 1609 متر بأقسم أو بأضرب بواحد على
+
+108
+00:09:54,350 --> 00:09:59,710
+1609 يعني الواحد ميل بيساوي 1609 متر علشان أضيع
+
+109
+00:09:59,710 --> 00:10:03,150
+الوحدات اللي هي المتر مع المتر بيطلع عندي 28 على
+
+110
+00:10:03,150 --> 00:10:11,290
+1609 متر بيطلع عندي 1.74 فعشرة أص ناقص 2 ميل لكل
+
+111
+00:10:11,290 --> 00:10:15,730
+ثانيةالان لو انا بدأ احول الثانية الى ساعة يعني
+
+112
+00:10:15,730 --> 00:10:21,470
+انا المطلوب منى 28 متر في الثانية بحولها الى ميل
+
+113
+00:10:21,470 --> 00:10:26,050
+فى الساعة فى البداية طبعا ال bus ال متر حولته الى
+
+114
+00:10:26,050 --> 00:10:31,290
+ميل بقسم لقسمة على 1609 بعد هيك الجواب هي الجواب
+
+115
+00:10:31,290 --> 00:10:38,310
+طلع عندى 1.74 فى 10 عقل سالب 2ميل في الثانية بدي
+
+116
+00:10:38,310 --> 00:10:41,930
+أحول الآن الثانية إلى ساعة طبعا ال meal ال bus مش
+
+117
+00:10:41,930 --> 00:10:46,330
+هلعب معاه أظل زي ما هو الثانية بدي أحولها إلى ساعة
+
+118
+00:10:46,330 --> 00:10:53,590
+فبقسم الثانية على ستين على ستين يعني هقسم على واحد
+
+119
+00:10:53,590 --> 00:10:58,990
+على تلات تلاف قصت مية أو بدي أعمل أن هذا الرقم
+
+120
+00:10:58,990 --> 00:11:01,910
+اللي هو واحد point سبعة أربع في عشر عصر نقص اتنين
+
+121
+00:11:01,910 --> 00:11:07,930
+meal لكل ثانية راح أضربه بستيناللي هي ب 60 في 60
+
+122
+00:11:07,930 --> 00:11:13,470
+اللي هي ثانية على دقيقة ثانية على دقيقة والدقيقة
+
+123
+00:11:13,470 --> 00:11:18,930
+بتحولها إلى ساعة بيصير عندي انا 62.6 ممكن طريقة
+
+124
+00:11:18,930 --> 00:11:29,310
+اخرى طريقة مباشرة 28 اقسمها على1609 وكمان الثانية
+
+125
+00:11:29,310 --> 00:11:34,590
+أقسمها على 60 وعلى 60 يعني أقسم على 3600 بطلع
+
+126
+00:11:34,590 --> 00:11:41,650
+معايا نفس الجواب يعني حولت اللي هو ال 1.74 في 10
+
+127
+00:11:41,650 --> 00:11:48,050
+أس سالب 2 ميل في الثانية إلى 1.74 في 10 أس ناقص 2
+
+128
+00:11:48,050 --> 00:11:56,320
+ميل في الساعة بطلع الجواب 62.6 ميل في الساعةمثال
+
+129
+00:11:56,320 --> 00:12:03,360
+example 1.5 مثال 1.5 برضه بدنا نحو .. نحول قيمة
+
+130
+00:12:03,360 --> 00:12:08,900
+معينة أو قيمة فيزيائية معينة إلها طبعا واحدة أو
+
+131
+00:12:08,900 --> 00:12:16,030
+عامل مضروب يعني تربيعي زي مثال لو كان عندي أنا22
+
+132
+00:12:16,030 --> 00:12:21,310
+متر في الثانية تربيع 22 متر في الثانية تربيع بدي
+
+133
+00:12:21,310 --> 00:12:27,330
+أحولها إلى كيلو في الدقيقة تربيع طبعا حد في البسط
+
+134
+00:12:27,330 --> 00:12:33,530
+22 متر المتر راح أحوله من متر إلى كيلو راح أقسم
+
+135
+00:12:33,530 --> 00:12:37,890
+طبعا لإن الواحد كيلو بساوي ألف متر أو واحد فعشرة
+
+136
+00:12:37,890 --> 00:12:45,020
+أس تلاتة متر قسمت 22 على ألف أو 22 على1×10 أُس 3
+
+137
+00:12:45,020 --> 00:12:47,980
+متر لإن المتر راحت مع المتر وضل عندي هنا وحدة
+
+138
+00:12:47,980 --> 00:12:51,800
+الكلو على second تربية طبعا ال second تربية عشان
+
+139
+00:12:51,800 --> 00:12:56,740
+أحولها إلى minute راح أقسمها على 60 لكل تربية معنى
+
+140
+00:12:56,740 --> 00:13:01,880
+الكلام قسم تقسيم التقسيم بيطلع ايش يعني ضرب في
+
+141
+00:13:01,880 --> 00:13:05,700
+البصد يعني هحكي انا ال second تربية اللي هي 1 على
+
+142
+00:13:05,700 --> 00:13:14,750
+60 تربية تطلع ل60 على تربية minuteيعني الجوا 79.2
+
+143
+00:13:14,750 --> 00:13:22,750
+كيلومتر على minute تربية بالنسبة لsection 1.6 هذا
+
+144
+00:13:22,750 --> 00:13:29,770
+ملغي نجي ل 1.7 بعنوان coordinate system اللي هي
+
+145
+00:13:29,770 --> 00:13:36,090
+أنظمة المحاورa point on a line can be located with
+
+146
+00:13:36,090 --> 00:13:40,850
+one coordinate لو أنا عندي أنا نقطة موجودة في مكان
+
+147
+00:13:40,850 --> 00:13:45,910
+معين بأحكي هذه النقطة إلها محور واحد لو كانت عندي
+
+148
+00:13:45,910 --> 00:13:50,030
+النقطة موجودة على a plane أو a plane يعني عبارة عن
+
+149
+00:13:50,030 --> 00:13:54,130
+مستوى والمستوى هو عبارة عن محورين a point in a
+
+150
+00:13:54,130 --> 00:13:57,810
+plane with two coordinates and ممكن and a point in
+
+151
+00:13:57,810 --> 00:14:01,610
+space with three يعنيممكن أي نقطة تكون موجودة على
+
+152
+00:14:01,610 --> 00:14:05,950
+محور واحد أو تكون موجودة في مستوى على محورين أو
+
+153
+00:14:05,950 --> 00:14:11,830
+موجودة في space فراغ عبارة عن تلت محاور ال
+
+154
+00:14:11,830 --> 00:14:15,590
+coordinate system used to specify locations in
+
+155
+00:14:15,590 --> 00:14:20,530
+space consists of the following الآن أي في نظام
+
+156
+00:14:20,530 --> 00:14:29,160
+المحاورنظام المحاور بيستخدم موقع معين في الفراغ
+
+157
+00:14:29,160 --> 00:14:35,160
+بتكون من القاتل هذه التكوينة عبارة عن fixed
+
+158
+00:14:35,160 --> 00:14:38,640
+reference point في عندي أنا نقطة ثابتة اسمها O أو
+
+159
+00:14:38,640 --> 00:14:42,610
+بسميها نقطة الأصل originفي عندي انا نقطة ثابتة
+
+160
+00:14:42,610 --> 00:14:47,590
+لنقطة الأصل في عندي set of specific axis axis في
+
+161
+00:14:47,590 --> 00:14:52,570
+عندي مجموعة من المحاور الأساسية أو الاتجاهات with
+
+162
+00:14:52,570 --> 00:14:58,110
+an appropriate scale and label on the axis هذه
+
+163
+00:14:58,110 --> 00:15:04,850
+المحاور لها تدرج معين وترويسة لكل محور أو اسم يوضع
+
+164
+00:15:04,850 --> 00:15:09,860
+على المحور نفسهinstructions on label at point in
+
+165
+00:15:09,860 --> 00:15:15,460
+space بعض التعليمات حول النقطة المطلوبة بالنسبة
+
+166
+00:15:15,460 --> 00:15:21,160
+لنقطة الأصل بالنسبة لنقطة الأصلone convent and
+
+167
+00:15:21,160 --> 00:15:23,960
+commonly used coordinate system is the Cartesian
+
+168
+00:15:23,960 --> 00:15:28,820
+coordinate system في استخدام شائع ومناسب لنظام
+
+169
+00:15:28,820 --> 00:15:32,740
+المحاور بسميه نظام المحاور الكارتيزية أو
+
+170
+00:15:32,740 --> 00:15:36,300
+الديكارتيية بسموها Cartesian coordinate ديكارتيية
+
+171
+00:15:36,300 --> 00:15:39,520
+أو كارتيزيةSometimes called rectangular
+
+172
+00:15:39,520 --> 00:15:44,960
+coordinates أحيانا بنسمي نظام إحداثيات مستطيلة
+
+173
+00:15:44,960 --> 00:15:49,800
+Such a system in two dimensions is illustrated in
+
+174
+00:15:49,800 --> 00:15:56,700
+figures 1.5 هذا النظام اللي له بعدين موضح بالشكل 1
+
+175
+00:15:56,700 --> 00:16:02,740
+.5 اللي هو عبارة عن نقطة النقطة هذه ممثلة
+
+176
+00:16:02,740 --> 00:16:09,140
+بالإحداثيات XYلو كان عندى نقطة B إحداثياتها خمسة
+
+177
+00:16:09,140 --> 00:16:14,880
+أو تلاتة كمان sometimes it's more convenient to
+
+178
+00:16:14,880 --> 00:16:18,080
+locate a point in space by طبعا plane polar
+
+179
+00:16:18,080 --> 00:16:23,840
+coordinate ممكن كمان أنا أحدد نقطة عن طريق المحاور
+
+180
+00:16:23,840 --> 00:16:28,550
+اللى هي plane polar coordinate المحاوراللي هي
+
+181
+00:16:28,550 --> 00:16:34,250
+المستوى القطبي اللي هي عبارة عن R ومثلة بالـR و
+
+182
+00:16:34,250 --> 00:16:38,630
+بالثيتا الـR والثيتا عبارة عن reference أو مرجعية
+
+183
+00:16:38,630 --> 00:16:42,870
+على أساس أنه a point is specified by distance R
+
+184
+00:16:42,870 --> 00:16:49,870
+أنا ممكن أحدد النقطة بالمسافة R يعني النقطة المراد
+
+185
+00:16:49,870 --> 00:16:54,720
+تحديدها بتكون على بعد R من نقطة الأصلwe are ممكن
+
+186
+00:16:54,720 --> 00:16:59,520
+تمثل ب X و Y كأنها في مستوى إضافة إلى أنه تحدد
+
+187
+00:16:59,520 --> 00:17:05,060
+أيضًا بالزاوية theta و هذه الزاوية عبارة عن الخط
+
+188
+00:17:05,060 --> 00:17:13,080
+المرسوم من نقطة الأصل إلى الخط المرسوم من محور X
+
+189
+00:17:13,080 --> 00:17:20,090
+الموجب إلى هذه الزاويةيعني الشكل هذا 1.5 بيمثل
+
+190
+00:17:20,090 --> 00:17:24,610
+لنقطة P إحداثياتها خمسة أو تلاتة الخمسة عبارة عن X
+
+191
+00:17:24,610 --> 00:17:29,010
+و Y اللي هي ال X خمسة و Y بالساعة و تلاتة النقطة
+
+192
+00:17:29,010 --> 00:17:33,010
+هذه Q إحداثياتها ناقص تلاتة و أربع موجودة في الربع
+
+193
+00:17:33,010 --> 00:17:38,070
+التاني ال X بالسالب و ال Y بي الموجب هنا في الربع
+
+194
+00:17:38,070 --> 00:17:44,250
+الأول X موجب و Y موجب الشكل التاني الشكل التاني
+
+195
+00:17:44,250 --> 00:17:49,760
+اللي هو 1.6 بيوضح ليالنقطة ممثلة بـPlan Polar
+
+196
+00:17:49,760 --> 00:17:54,800
+Coordinate اللي هي R وTheta الـR هي عبارة عن الخط
+
+197
+00:17:54,800 --> 00:17:58,220
+الواصل بين نقطة الأصل و النقطة والـR ممثلة
+
+198
+00:17:58,220 --> 00:18:01,280
+بالمحورين
+
+199
+00:18:01,280 --> 00:18:08,260
+X وY وTheta هذه عبارة عن الزاوية المحصورة بين
+
+200
+00:18:08,260 --> 00:18:12,180
+اتجاه X الموجة و اللي هي النقطة أو المتجاه R
+
+201
+00:18:18,270 --> 00:18:23,690
+Trie Geometric Review الآن بالنسبة لها يعني نتذكر
+
+202
+00:18:23,690 --> 00:18:28,690
+بعض حساب المثلثات consider the right triangle لو
+
+203
+00:18:28,690 --> 00:18:33,790
+أنا فرضت في عندي أنا مثلث المثلث هذا قائم الزاوية
+
+204
+00:18:33,790 --> 00:18:38,350
+المثلث قائم الزاوية بالشكل هذا هذا طبعا الزاوية
+
+205
+00:18:38,350 --> 00:18:42,590
+حادة فهذا الاتجاه R لو نزلت أنا عمود اللي هو اتجاه
+
+206
+00:18:42,590 --> 00:18:45,490
+Y صار عندي أنا مثلث قائم الزاوية هي القائمة فهذا
+
+207
+00:18:45,490 --> 00:18:51,900
+الشكللو كان عندي أنهيب الزاوية sin θ اللي هي مقابل
+
+208
+00:18:51,900 --> 00:18:57,440
+على وطر Y على R cos θ عبارة عن X على R تاني
+
+209
+00:18:57,440 --> 00:19:02,580
+الزاوية عبارة عن مقابل على مجاور هذه حساب مثلثات
+
+210
+00:19:02,580 --> 00:19:08,120
+أخدناها سابقاً the basic trigeometric function
+
+211
+00:19:08,120 --> 00:19:14,580
+defined as such triangle as the follow يعنيبرضه
+
+212
+00:19:14,580 --> 00:19:21,000
+نتذكر انه sine الزاوية عبارة عن مقابل على water
+
+213
+00:19:21,000 --> 00:19:25,500
+cosine الزاوية عبارة عن مجاور على water و tan
+
+214
+00:19:25,500 --> 00:19:29,700
+الزاوية عبارة عن مقابل على مجاور كما هو موضح
+
+215
+00:19:29,700 --> 00:19:33,960
+بالشكل أول والثالث another important relationship
+
+216
+00:19:33,960 --> 00:19:39,120
+في برضه طبعا علاقة مهمة و هندرس عليها كتير و
+
+217
+00:19:39,120 --> 00:19:42,860
+هنشتغل عليها كتير اللي هي بيسموها نظرية FIFA golf
+
+218
+00:19:43,260 --> 00:19:47,040
+exist between the length of the side of the right
+
+219
+00:19:47,040 --> 00:19:53,240
+triangle هي تحدد العلاقة بين أطوال أضلاع القائمة
+
+220
+00:19:53,240 --> 00:19:59,960
+اللي هي الوطر تربيع بساوي X تربيع زائد Y تربيع لو
+
+221
+00:19:59,960 --> 00:20:03,860
+أنا فرضت أن عندي sign الزاوية بتساوي point 866
+
+222
+00:20:03,860 --> 00:20:08,620
+معنى الكلام أن الزاوية عشان أجيبها لازم أعمل sign
+
+223
+00:20:08,620 --> 00:20:13,520
+inverse للزاوية تطلع للزاويةSin Inverse هاي بجيبها
+
+224
+00:20:13,520 --> 00:20:20,680
+من خلال .. من خلال القالة Shift Sin تطلع ل60 درجة
+
+225
+00:20:20,680 --> 00:20:25,140
+لو أنا بدأ أجرب مرة تانية أنه أنا أوجد Tan Inverse
+
+226
+00:20:25,140 --> 00:20:32,090
+لل point 4 معنى الكلام هتطلع لزاوية 21.8لازم be
+
+227
+00:20:32,090 --> 00:20:35,430
+sure that your calculator is a set of degree لازم
+
+228
+00:20:35,430 --> 00:20:39,210
+نتأكد أنه القالة الحاسبة موجودة على degree اللي هي
+
+229
+00:20:39,210 --> 00:20:44,270
+درجات وليس رديان وليس بالمخدر الخيار الدائري in
+
+230
+00:20:44,270 --> 00:20:47,050
+addition the inverse tangent function can return
+
+231
+00:20:47,050 --> 00:20:54,190
+only view a value between minus 90 أو زائد 90 so
+
+232
+00:20:54,190 --> 00:20:59,520
+when an angle is in the secondor third quadrant
+
+233
+00:20:59,520 --> 00:21:04,000
+it's necessary to add 120 لو كان انا طلعت لزاوية
+
+234
+00:21:04,000 --> 00:21:09,280
+معينة فى الرُبع التانى او الرُبع التالت فلازم احنا
+
+235
+00:21:09,280 --> 00:21:15,060
+نضيف على الزاوية طبعا مية و تمانين درجة لإنه احنا
+
+236
+00:21:15,060 --> 00:21:20,390
+إنا أرباع الرُبع الأول بيكونالـ X موجبة والـ Y
+
+237
+00:21:20,390 --> 00:21:25,790
+موجبة والزاوية موجبة الربع التاني بيكون X سالبة و
+
+238
+00:21:25,790 --> 00:21:32,570
+X سالبة و Y موجبة الربع التالت X سالبة و Y سالبة
+
+239
+00:21:32,570 --> 00:21:38,580
+طبعا مثالthe Cartesian coordinate of the point in
+
+240
+00:21:38,580 --> 00:21:42,440
+the XY plane لو أنا عندي إحداثيات لنقطة النقطة هي
+
+241
+00:21:42,440 --> 00:21:46,260
+عبارة عن ال X بتساوي minus تلاتة و نص و Y minus
+
+242
+00:21:46,260 --> 00:21:49,600
+اتنين و نص إذا ال X سالبة و ال Y سالبة هتكون في
+
+243
+00:21:49,600 --> 00:21:56,200
+الربع التالت كما هو موضح بالشكل أوجد أوجد find the
+
+244
+00:21:56,200 --> 00:22:00,640
+polar coordinate of this point B بدي أوجد ال polar
+
+245
+00:22:00,640 --> 00:22:06,140
+coordinate بعدين convert اللي هي R أو فيتاto
+
+246
+00:22:06,140 --> 00:22:11,500
+rectangular coordinate علشان أحل هذا السؤالطبعا
+
+247
+00:22:11,500 --> 00:22:14,680
+إحنا عندنا الـ Cartesian coordinate القانون اللي
+
+248
+00:22:14,680 --> 00:22:17,960
+هي الـR أو الـR تربيع بتساوي X تربيع زاد Y تربيع
+
+249
+00:22:17,960 --> 00:22:21,180
+إذا ان الـR بتساوي جزر X تربيع زاد Y تربيع هدعى
+
+250
+00:22:21,180 --> 00:22:25,880
+فيتا غورث جيبنا قيمة الـR اللي قال لإيجاد الزاوية
+
+251
+00:22:25,880 --> 00:22:30,260
+10 فيتا بتساوي Y على X فبحط ال Y بالإشارة تبعتها و
+
+252
+00:22:30,260 --> 00:22:36,620
+ال X بالإشارة تبعتها طلعت عند الزاوية 35.5من وين
+
+253
+00:22:36,620 --> 00:22:41,240
+أجت الزاوية من tan inverse للكلام هذا طلع عندي 35
+
+254
+00:22:41,240 --> 00:22:48,740
+.5 طبعا ال 35.5 رح أضيف إلها 180 علشان هذه الزاوية
+
+255
+00:22:48,740 --> 00:22:53,740
+موجودة في الربع التالت و أنا بقيس الزاوية أو ال
+
+256
+00:22:53,740 --> 00:22:58,800
+reference line المرجعية الخطة بقى كانت بيبدأ دايما
+
+257
+00:22:58,800 --> 00:23:03,060
+من اتجاه X الموجب فبتطلع الزاوية 216 فعلا هي
+
+258
+00:23:03,060 --> 00:23:07,450
+الزاوية في الربع التالتلإيجاد ال .. البولر ..
+
+259
+00:23:07,450 --> 00:23:12,310
+البولر طبعا ال coordinate البولر to cartesian
+
+260
+00:23:12,310 --> 00:23:16,030
+conversion عشان أحول فأنا عندي X بتساوي ال R
+
+261
+00:23:16,030 --> 00:23:20,890
+cosine ال theta و ال Y بتساوي ال R sine ال theta و
+
+262
+00:23:20,890 --> 00:23:28,010
+بالتالي تطلع عندي ال X 3.99 و ال Y بتساوي 3.05
+
+263
+00:23:32,710 --> 00:23:38,710
+مثال آخر problems 1.10 a person measures the
+
+264
+00:23:38,710 --> 00:23:42,070
+height of the building by walking out a distance
+
+265
+00:23:42,070 --> 00:23:49,090
+of 46 متر from its base and shining a flash light
+
+266
+00:23:49,090 --> 00:23:53,390
+beam towards the top طبعا في عندي شخص بده يقيس
+
+267
+00:23:53,390 --> 00:23:59,690
+ارتفاع مبنى هو طبعا ماشي طبعا مسافة 46 متر من
+
+268
+00:23:59,690 --> 00:24:05,320
+قاعدة المبنىو أضاء فلاش ضوء فلاش أو إشعاع فلاش
+
+269
+00:24:05,320 --> 00:24:09,620
+نحيط الأعلى المبنى when the beam is elevate هذه
+
+270
+00:24:09,620 --> 00:24:14,540
+طبعا الأشعة صعدت أو وصلت أو يعني وصلت لأعلى المبنى
+
+271
+00:24:14,540 --> 00:24:17,840
+كانت الزاوية تسعة و تلاتين درجة بالنسبالها ال
+
+272
+00:24:17,840 --> 00:24:21,640
+horizontal the beam just struck the top of the
+
+273
+00:24:21,640 --> 00:24:25,740
+building if the flash light is held at height طبعا
+
+274
+00:24:25,740 --> 00:24:30,300
+احنا زي ما احنا شايفين بالشكل هي في عند man أو رجل
+
+275
+00:24:30,590 --> 00:24:34,210
+الرجل كان طوله اتنين بالنسبة لأ الأرضية المبنى
+
+276
+00:24:34,210 --> 00:24:39,690
+الرجل علشان يوصل لأعلى المبنى أضاء طبعا light أو
+
+277
+00:24:39,690 --> 00:24:44,550
+ضوء flash الضوء هذا هيمشي لأعلى المبنى لما كانت
+
+278
+00:24:44,550 --> 00:24:47,850
+الزاوية تسعة وتلاتين درجة بالنسبة لمين لأ ال
+
+279
+00:24:47,850 --> 00:24:51,330
+horizontal أو الأفقي المسافة كانت .. المسافة
+
+280
+00:24:51,330 --> 00:24:56,210
+الأفقية من الرجل للمبنى كانت ستة أو أربعين مترطبعا
+
+281
+00:24:56,210 --> 00:24:58,730
+المطلوب في هذا السؤال find the height of the
+
+282
+00:24:58,730 --> 00:25:02,510
+building بدي ارتفاع المبنى علشان اجيب ارتفاع
+
+283
+00:25:02,510 --> 00:25:06,730
+المبنى طبعا انا عندي علاقة انه تاني الزاوية بدها
+
+284
+00:25:06,730 --> 00:25:12,110
+تساوي مقابل على مجاور طبعا هستخدم فيثا غورث طبعا
+
+285
+00:25:12,110 --> 00:25:16,900
+عندي انا هنا كأنها مثلث قائم الزاويةعندي فيه ثغارت
+
+286
+00:25:16,900 --> 00:25:20,540
+المقابل على المجاور بساوي تان الزاوية الزاوية
+
+287
+00:25:20,540 --> 00:25:26,360
+موجودة والمجاور موجود ممكن احصل على مقابل المجاور
+
+288
+00:25:26,360 --> 00:25:26,920
+ممكن احصل على مقابل المجاور ممكن احصل على مقابل
+
+289
+00:25:26,920 --> 00:25:27,240
+المجاور ممكن احصل على مقابل المجاور ممكن احصل على
+
+290
+00:25:27,240 --> 00:25:27,380
+مقابل المجاور ممكن احصل على مقابل المجاور ممكن
+
+291
+00:25:27,380 --> 00:25:27,560
+احصل على مقابل المجاور ممكن احصل على مقابل المجاور
+
+292
+00:25:27,560 --> 00:25:28,060
+ممكن احصل على مقابل المجاور ممكن احصل على مقابل
+
+293
+00:25:28,060 --> 00:25:30,820
+المجاور ممكن احصل على مقابل المجاور ممكن احصل على
+
+294
+00:25:30,820 --> 00:25:36,940
+مقابل المجاور ممكن احصل على مقابل
+
+295
+00:25:41,210 --> 00:25:47,370
+37.3 متر هذا هو ارتفاع المبنى الآن لإيجاد طول
+
+296
+00:25:47,370 --> 00:25:51,510
+الشعاع calculate the length of the light بدي انا
+
+297
+00:25:51,510 --> 00:25:55,570
+طول الشعاع معناته بدي اوجد ال water برضه كفي ثغات
+
+298
+00:25:55,570 --> 00:25:59,750
+ال water بيساوي جزر التربيع إلى X تربيع زائد Y
+
+299
+00:25:59,750 --> 00:26:06,030
+تربيع تطلع عندى 59.8 متر هذا هو طول المبنى
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/0S3RQpMgcY8_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/0S3RQpMgcY8_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..1b3cf8ace341cd3a8626323f34660386a10f8273
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/0S3RQpMgcY8_raw.srt
@@ -0,0 +1,1196 @@
+1
+00:00:00,000 --> 00:00:05,160
+بسم الله الرحمن الرحيم سنبدأ بشرح مساق فيزياء عامة
+
+2
+00:00:05,160 --> 00:00:11,520
+لطلبة العلوم الصحية من كتاب college physics للمؤلف
+
+3
+00:00:11,520 --> 00:00:18,680
+Sir Wei هنبدأ بالفصل الأول اللي هي المحاضرات لطلبة
+
+4
+00:00:18,680 --> 00:00:25,650
+العلوم الصحيةالهدف من هذا المساق هو عبارة عن هدف
+
+5
+00:00:25,650 --> 00:00:32,310
+ذو شقين تزويد الطالب بعرض واضح ومنطقي لأساليب
+
+6
+00:00:32,310 --> 00:00:38,450
+الفيزياء تعزيز وتقويت فهم الطلبة لمجموعة واسعة من
+
+7
+00:00:38,450 --> 00:00:42,990
+الأمور والاهتمامات والتطبيقات في الحياة ولتحقيق
+
+8
+00:00:42,990 --> 00:00:50,890
+هذه الأهداف سنعمل على تحفيز الطالبمن خلال يعني
+
+9
+00:00:50,890 --> 00:00:57,230
+أمثلة عملية تظهر دور الفيزياء في التخصصات الأخرى
+
+10
+00:00:57,230 --> 00:01:04,390
+سنبدأ ان شاء الله بشطر الأول شطر الأول هو عبارة عن
+
+11
+00:01:04,390 --> 00:01:09,430
+ال units اللي هي الوحدات tri-geometry اللي هي
+
+12
+00:01:09,430 --> 00:01:14,450
+الحساب المثلثات and vectors اللي هو المتجهات
+
+13
+00:01:15,230 --> 00:01:21,250
+section 11 standards of length, mass and time
+
+14
+00:01:21,250 --> 00:01:28,130
+المعايير الأساسية أو المقاييس الأساسية للطول
+
+15
+00:01:28,130 --> 00:01:34,290
+والكتلة والزمنلحساب طبعا او لقياس كأي كمية
+
+16
+00:01:34,290 --> 00:01:40,930
+فيزيائية بحتاج أنا إلى وحدة لكي أفرق بين أي رقم
+
+17
+00:01:40,930 --> 00:01:48,750
+رياضي أو رقم فيزيائي فالوحدة هي اللتي تميز هذا
+
+18
+00:01:48,750 --> 00:01:56,720
+الرقم على أنه كمية فيزيائيةفي عام 1960 وافقت
+
+19
+00:01:56,720 --> 00:02:02,140
+اللجنة الدولية على اعتماد نظام معياري للوحدات وهذا
+
+20
+00:02:02,140 --> 00:02:06,820
+النظام المعياري بنسمي SI أو system international
+
+21
+00:02:06,820 --> 00:02:12,220
+هو عبارة عن النظام الدولي النظام الدولي طبعا
+
+22
+00:02:12,220 --> 00:02:17,300
+الكميات الأساسية في هذا النظام ووحدات اللي هي
+
+23
+00:02:17,300 --> 00:02:23,130
+الطول و الكتلة و الزمنالمتر والكيلو جرام والثانية
+
+24
+00:02:23,130 --> 00:02:30,090
+على التوالي يعني النظام الدولي رمزه SI معناها ال
+
+25
+00:02:30,090 --> 00:02:34,590
+system international ال system international وحدته
+
+26
+00:02:34,590 --> 00:02:41,010
+طبعا وحدة يقيس بالكيلو جرام متر ثانية يعني الطول
+
+27
+00:02:41,010 --> 00:02:44,890
+يقاس بالمتر و الكتلة اللي هي ال mass تقاس بالكيلو
+
+28
+00:02:44,890 --> 00:02:49,350
+جرام و ال time اللي هو الزمن يقاس بالثانية
+
+29
+00:02:53,590 --> 00:02:58,250
+بالنسبة للطول .. بالنسبة للطول طبعا هو عبارة عن ال
+
+30
+00:02:58,250 --> 00:03:07,970
+length في عام 1977 .. 1900 أو 1799 أصبح ال meter
+
+31
+00:03:07,970 --> 00:03:13,650
+هو عبارة عن المقياس المعياري أو القانونيلطول في
+
+32
+00:03:13,650 --> 00:03:22,290
+فرنسا في عام 1983 تم تعريف المتر بإن المسافة التي
+
+33
+00:03:22,290 --> 00:03:28,370
+يقطعها الأضوء في الفراغ في فترة زمنية تساوي 1 على
+
+34
+00:03:28,370 --> 00:03:33,710
+2.99792458
+
+35
+00:03:33,710 --> 00:03:39,740
+أو 1 على 2.9108The meter was defined يعني المتر
+
+36
+00:03:39,740 --> 00:03:43,880
+يعرف به المسافة التي the distance travelled by
+
+37
+00:03:43,880 --> 00:03:47,760
+light المسافة التي يقطعها الضوء في الفراغ vacuum
+
+38
+00:03:47,760 --> 00:03:53,320
+فراغ خلال during time interval خلال الفترة 1 على 2
+
+39
+00:03:53,320 --> 00:03:59,300
+.9 في 10 رقص تمانية ثانية This latest definition
+
+40
+00:03:59,300 --> 00:04:02,720
+established the speed of a light طبعا هذا التعريف
+
+41
+00:04:02,720 --> 00:04:10,720
+الخاص بالمتريوصلنا ل .. اللي هي سرعة الضوء و من
+
+42
+00:04:10,720 --> 00:04:14,800
+خلاله يتم اعتماد سرعة الضوء و هي عبارة عن 2
+
+43
+00:04:14,800 --> 00:04:19,840
+.99792458
+
+44
+00:04:19,840 --> 00:04:24,800
+في عشر عقوس تمانية او 2.99792458
+
+45
+00:04:24,800 --> 00:04:29,700
+او ممكن نقربها الى 3 في عشر عقوس تمانية متر per
+
+46
+00:04:29,700 --> 00:04:30,320
+second
+
+47
+00:04:36,010 --> 00:04:42,490
+بالنسبة للكتلة اللي هي ال mass تعريفها الكتلة ال
+
+48
+00:04:42,490 --> 00:04:46,390
+system international الاصئعي unit of mass اللي هو
+
+49
+00:04:46,390 --> 00:04:51,310
+الكتلة في ان وحدة الكتلة في النظام الدولي هي عبارة
+
+50
+00:04:51,310 --> 00:04:56,110
+عن ال kilogram و تعريفها is defined as تعرف as the
+
+51
+00:04:56,110 --> 00:05:00,550
+mass of a specific platinum iridium alloy cylinder
+
+52
+00:05:00,550 --> 00:05:03,730
+kept at the international period of weights and
+
+53
+00:05:03,730 --> 00:05:09,130
+measures at Sievers Franceيعني معناها تعريف اللي
+
+54
+00:05:09,130 --> 00:05:13,690
+هي الكتلة في النظام الدولي عبارة عن كتلة سبيكة
+
+55
+00:05:13,690 --> 00:05:19,230
+أسطوانيةمن ال platinum iridium محفوظة في طبعا
+
+56
+00:05:19,230 --> 00:05:24,010
+المركز أو المكتب الدولي الأوزان في فرنسا والشكل
+
+57
+00:05:24,010 --> 00:05:29,310
+واحد واحد طبعا يوضح هذه السبيكة اللي هي عبارة عن
+
+58
+00:05:29,310 --> 00:05:35,850
+استوانة مصنوعة من platinum iridium ومحفوظة في مركز
+
+59
+00:05:35,850 --> 00:05:41,070
+أو المكتب الدولي في فرنسا بالنسبة للزمن اللي هي ال
+
+60
+00:05:41,070 --> 00:05:46,990
+timeالزمن the basic unit of time طبعا الزمن هو ال
+
+61
+00:05:46,990 --> 00:05:51,130
+.. ال .. يعني الوحدة الأساسية للزمن هي الثانية و
+
+62
+00:05:51,130 --> 00:05:56,650
+the .. is defined as تعريفها as تسعة واحد تسعة
+
+63
+00:05:56,650 --> 00:06:00,490
+اتنين ستة تلاتة واحد سبعة zero zero times هي عبارة
+
+64
+00:06:00,490 --> 00:06:05,410
+عن طبعا عدد معين عدد المرات أو عدد الدورات التي
+
+65
+00:06:05,410 --> 00:06:11,770
+تحتزها ذرة .. ذرهات ال cesiumأو عدد اللي هي
+
+66
+00:06:11,770 --> 00:06:17,750
+الدبدبات اللتي تهتزها أو تشيعها ضرر مصنوعة من ال
+
+67
+00:06:17,750 --> 00:06:25,780
+cesiumبالنسبة ل section 1.14 طبعا هذا ملغي section
+
+68
+00:06:25,780 --> 00:06:31,880
+121314 برضه ملغي بالنسبة لطلبة العلوم الصحية
+
+69
+00:06:31,880 --> 00:06:37,720
+section 15 unit conversion for physical quantity
+
+70
+00:06:37,720 --> 00:06:42,800
+اللي هو عبارة عن تحويل الوحدات لكميات الفيزيائية
+
+71
+00:06:43,380 --> 00:06:48,700
+conversion factors between SI and US بدي أحول أنا
+
+72
+00:06:48,700 --> 00:06:52,500
+بعض المعاملات بين اللي هي النظام الدولي اللي هي SI
+
+73
+00:06:52,500 --> 00:06:56,020
+system international و بين اللي هي ال united
+
+74
+00:06:56,020 --> 00:07:02,380
+states النظام الأمريكي لبعض الوحدات زي مثلا لما
+
+75
+00:07:02,380 --> 00:07:06,640
+أجي أحكي واحد ميل الواحد ميل بدي يساوي ألف و سبعة
+
+76
+00:07:06,640 --> 00:07:11,790
+أو ستمية أو تسعة متر و يساوي واحد point ستةكيلو
+
+77
+00:07:11,790 --> 00:07:15,930
+متر تقريبا الواحد متر بدى يساوي تسعة و تلاتين
+
+78
+00:07:15,930 --> 00:07:19,430
+point تلاتة سبعة inch و بدها تساوي تلاتة point
+
+79
+00:07:19,430 --> 00:07:24,230
+اتنين تمانية واحد feet او قدم الواحد feet او واحد
+
+80
+00:07:24,230 --> 00:07:28,770
+foot بتساوي القدم بتساوي point تلاتة متر يعني
+
+81
+00:07:28,770 --> 00:07:33,610
+تلاتين point اربعة تمانية مترالواحد inch بدها
+
+82
+00:07:33,610 --> 00:07:38,030
+تساوي اتنين و نص سانتي أو خمسة و عشرين من الف من
+
+83
+00:07:38,030 --> 00:07:41,270
+المتر الواحد inch بيساوي خمسة و عشرين من الف من
+
+84
+00:07:41,270 --> 00:07:45,970
+المتر ممكن احكي انه التلاتين سانتي بدها تساوي قدم
+
+85
+00:07:45,970 --> 00:07:53,070
+و ال inch اللي هي بيساوي اتنين و نص سانتي we can
+
+86
+00:07:53,070 --> 00:07:56,090
+take fraction with the conversion that will cancel
+
+87
+00:07:56,090 --> 00:07:59,920
+the units we don't wantand multiply that fraction
+
+88
+00:07:59,920 --> 00:08:04,000
+by the quantity in questions for example يعني
+
+89
+00:08:04,000 --> 00:08:11,400
+بالنسبة لبعض تحويل بعض الوحدات يعني
+
+90
+00:08:11,400 --> 00:08:17,040
+كمثال طبعا الحل الهدف من تحويل الوحدات باستخدام
+
+91
+00:08:17,040 --> 00:08:23,490
+عدة عوامل تحويل المتر مثلاالى meal او ال .. يعني
+
+92
+00:08:23,490 --> 00:08:27,990
+لو انا حكيت مثال انه خمسة عشر انش مطلوب مني احولهم
+
+93
+00:08:27,990 --> 00:08:35,600
+لصنتىفبعرف أنا بعرف أن ال 1 inch بدي ساوي 2.54 cm
+
+94
+00:08:35,600 --> 00:08:42,440
+إذا ال 15 ممكن أضربها في 2.54 أو لتخلص من الوحدات
+
+95
+00:08:42,440 --> 00:08:46,660
+بنحكي ال 15 inch راح أضربها أنا ب fraction في كسر
+
+96
+00:08:46,660 --> 00:08:49,840
+زي ما حكالي هو fraction by the quantity in the
+
+97
+00:08:49,840 --> 00:08:57,910
+cushions الآن 2.54 cm ال 1 inch بتساوي 2.45فضربت
+
+98
+00:08:57,910 --> 00:09:04,630
+في 2.54 cm على 1 inch ال inch الوحدة دي راحت معاها
+
+99
+00:09:04,630 --> 00:09:15,050
+دل عندي 38.1 cm مثال
+
+100
+00:09:15,050 --> 00:09:18,990
+آخر example 1.4 convert units using several
+
+101
+00:09:18,990 --> 00:09:25,150
+conversion factorsبدأ أستخدم الوحدات أيضا لعدد
+
+102
+00:09:25,150 --> 00:09:29,710
+أنواع أو عوامل التحولات convert ال meter to mile
+
+103
+00:09:29,710 --> 00:09:34,230
+بدأ أحول ال meter إلى mile لو كان عندي أنا عشرين
+
+104
+00:09:34,230 --> 00:09:38,110
+meter في الثانية و بدأ أحولها إلى mile في الثانية
+
+105
+00:09:38,110 --> 00:09:42,050
+طبعا ال 28 mile في الثانية بروح لل bus ال bus هو
+
+106
+00:09:42,050 --> 00:09:45,890
+عبارة عن meter بدأ أحوله إلى mileلما أحول من متر
+
+107
+00:09:45,890 --> 00:09:54,350
+لميل بأقسم على 1609 متر بأقسم أو بأضرب بواحد على
+
+108
+00:09:54,350 --> 00:09:59,710
+1609 يعني الواحد ميل بيساوي 1609 متر علشان أضيع
+
+109
+00:09:59,710 --> 00:10:03,150
+الوحدات اللي هي المتر مع المتر بيطلع عندي 28 على
+
+110
+00:10:03,150 --> 00:10:11,290
+1609 متر بيطلع عندي 1.74 فعشرة أص ناقص 2 ميل لكل
+
+111
+00:10:11,290 --> 00:10:15,730
+ثانيةالان لو انا بدأ احول الثانية الى ساعة يعني
+
+112
+00:10:15,730 --> 00:10:21,470
+انا المطلوب منى 28 متر في الثانية بحولها الى ميل
+
+113
+00:10:21,470 --> 00:10:26,050
+فى الساعة فى البداية طبعا ال bus ال متر حولته الى
+
+114
+00:10:26,050 --> 00:10:31,290
+ميل بقسم لقسمة على 1609 بعد هيك الجواب هي الجواب
+
+115
+00:10:31,290 --> 00:10:38,310
+طلع عندى 1.74 فى 10 عقل سالب 2ميل في الثانية بدي
+
+116
+00:10:38,310 --> 00:10:41,930
+أحول الآن الثانية إلى ساعة طبعا ال meal ال bus مش
+
+117
+00:10:41,930 --> 00:10:46,330
+هلعب معاه أظل زي ما هو الثانية بدي أحولها إلى ساعة
+
+118
+00:10:46,330 --> 00:10:53,590
+فبقسم الثانية على ستين على ستين يعني هقسم على واحد
+
+119
+00:10:53,590 --> 00:10:58,990
+على تلات تلاف قصت مية أو بدي أعمل أن هذا الرقم
+
+120
+00:10:58,990 --> 00:11:01,910
+اللي هو واحد point سبعة أربع في عشر عصر نقص اتنين
+
+121
+00:11:01,910 --> 00:11:07,930
+meal لكل ثانية راح أضربه بستيناللي هي ب 60 في 60
+
+122
+00:11:07,930 --> 00:11:13,470
+اللي هي ثانية على دقيقة ثانية على دقيقة والدقيقة
+
+123
+00:11:13,470 --> 00:11:18,930
+بتحولها إلى ساعة بيصير عندي انا 62.6 ممكن طريقة
+
+124
+00:11:18,930 --> 00:11:29,310
+اخرى طريقة مباشرة 28 اقسمها على1609 وكمان الثانية
+
+125
+00:11:29,310 --> 00:11:34,590
+أقسمها على 60 وعلى 60 يعني أقسم على 3600 بطلع
+
+126
+00:11:34,590 --> 00:11:41,650
+معايا نفس الجواب يعني حولت اللي هو ال 1.74 في 10
+
+127
+00:11:41,650 --> 00:11:48,050
+أس سالب 2 ميل في الثانية إلى 1.74 في 10 أس ناقص 2
+
+128
+00:11:48,050 --> 00:11:56,320
+ميل في الساعة بطلع الجواب 62.6 ميل في الساعةمثال
+
+129
+00:11:56,320 --> 00:12:03,360
+example 1.5 مثال 1.5 برضه بدنا نحو .. نحول قيمة
+
+130
+00:12:03,360 --> 00:12:08,900
+معينة أو قيمة فيزيائية معينة إلها طبعا واحدة أو
+
+131
+00:12:08,900 --> 00:12:16,030
+عامل مضروب يعني تربيعي زي مثال لو كان عندي أنا22
+
+132
+00:12:16,030 --> 00:12:21,310
+متر في الثانية تربيع 22 متر في الثانية تربيع بدي
+
+133
+00:12:21,310 --> 00:12:27,330
+أحولها إلى كيلو في الدقيقة تربيع طبعا حد في البسط
+
+134
+00:12:27,330 --> 00:12:33,530
+22 متر المتر راح أحوله من متر إلى كيلو راح أقسم
+
+135
+00:12:33,530 --> 00:12:37,890
+طبعا لإن الواحد كيلو بساوي ألف متر أو واحد فعشرة
+
+136
+00:12:37,890 --> 00:12:45,020
+أس تلاتة متر قسمت 22 على ألف أو 22 على1×10 أُس 3
+
+137
+00:12:45,020 --> 00:12:47,980
+متر لإن المتر راحت مع المتر وضل عندي هنا وحدة
+
+138
+00:12:47,980 --> 00:12:51,800
+الكلو على second تربية طبعا ال second تربية عشان
+
+139
+00:12:51,800 --> 00:12:56,740
+أحولها إلى minute راح أقسمها على 60 لكل تربية معنى
+
+140
+00:12:56,740 --> 00:13:01,880
+الكلام قسم تقسيم التقسيم بيطلع ايش يعني ضرب في
+
+141
+00:13:01,880 --> 00:13:05,700
+البصد يعني هحكي انا ال second تربية اللي هي 1 على
+
+142
+00:13:05,700 --> 00:13:14,750
+60 تربية تطلع ل60 على تربية minuteيعني الجوا 79.2
+
+143
+00:13:14,750 --> 00:13:22,750
+كيلومتر على minute تربية بالنسبة لsection 1.6 هذا
+
+144
+00:13:22,750 --> 00:13:29,770
+ملغي نجي ل 1.7 بعنوان coordinate system اللي هي
+
+145
+00:13:29,770 --> 00:13:36,090
+أنظمة المحاورa point on a line can be located with
+
+146
+00:13:36,090 --> 00:13:40,850
+one coordinate لو أنا عندي أنا نقطة موجودة في مكان
+
+147
+00:13:40,850 --> 00:13:45,910
+معين بأحكي هذه النقطة إلها محور واحد لو كانت عندي
+
+148
+00:13:45,910 --> 00:13:50,030
+النقطة موجودة على a plane أو a plane يعني عبارة عن
+
+149
+00:13:50,030 --> 00:13:54,130
+مستوى والمستوى هو عبارة عن محورين a point in a
+
+150
+00:13:54,130 --> 00:13:57,810
+plane with two coordinates and ممكن and a point in
+
+151
+00:13:57,810 --> 00:14:01,610
+space with three يعنيممكن أي نقطة تكون موجودة على
+
+152
+00:14:01,610 --> 00:14:05,950
+محور واحد أو تكون موجودة في مستوى على محورين أو
+
+153
+00:14:05,950 --> 00:14:11,830
+موجودة في space فراغ عبارة عن تلت محاور ال
+
+154
+00:14:11,830 --> 00:14:15,590
+coordinate system used to specify locations in
+
+155
+00:14:15,590 --> 00:14:20,530
+space consists of the following الآن أي في نظام
+
+156
+00:14:20,530 --> 00:14:29,160
+المحاورنظام المحاور بيستخدم موقع معين في الفراغ
+
+157
+00:14:29,160 --> 00:14:35,160
+بتكون من القاتل هذه التكوينة عبارة عن fixed
+
+158
+00:14:35,160 --> 00:14:38,640
+reference point في عندي أنا نقطة ثابتة اسمها O أو
+
+159
+00:14:38,640 --> 00:14:42,610
+بسميها نقطة الأصل originفي عندي انا نقطة ثابتة
+
+160
+00:14:42,610 --> 00:14:47,590
+لنقطة الأصل في عندي set of specific axis axis في
+
+161
+00:14:47,590 --> 00:14:52,570
+عندي مجموعة من المحاور الأساسية أو الاتجاهات with
+
+162
+00:14:52,570 --> 00:14:58,110
+an appropriate scale and label on the axis هذه
+
+163
+00:14:58,110 --> 00:15:04,850
+المحاور لها تدرج معين وترويسة لكل محور أو اسم يوضع
+
+164
+00:15:04,850 --> 00:15:09,860
+على المحور نفسهinstructions on label at point in
+
+165
+00:15:09,860 --> 00:15:15,460
+space بعض التعليمات حول النقطة المطلوبة بالنسبة
+
+166
+00:15:15,460 --> 00:15:21,160
+لنقطة الأصل بالنسبة لنقطة الأصلone convent and
+
+167
+00:15:21,160 --> 00:15:23,960
+commonly used coordinate system is the Cartesian
+
+168
+00:15:23,960 --> 00:15:28,820
+coordinate system في استخدام شائع ومناسب لنظام
+
+169
+00:15:28,820 --> 00:15:32,740
+المحاور بسميه نظام المحاور الكارتيزية أو
+
+170
+00:15:32,740 --> 00:15:36,300
+الديكارتيية بسموها Cartesian coordinate ديكارتيية
+
+171
+00:15:36,300 --> 00:15:39,520
+أو كارتيزيةSometimes called rectangular
+
+172
+00:15:39,520 --> 00:15:44,960
+coordinates أحيانا بنسمي نظام إحداثيات مستطيلة
+
+173
+00:15:44,960 --> 00:15:49,800
+Such a system in two dimensions is illustrated in
+
+174
+00:15:49,800 --> 00:15:56,700
+figures 1.5 هذا النظام اللي له بعدين موضح بالشكل 1
+
+175
+00:15:56,700 --> 00:16:02,740
+.5 اللي هو عبارة عن نقطة النقطة هذه ممثلة
+
+176
+00:16:02,740 --> 00:16:09,140
+بالإحداثيات XYلو كان عندى نقطة B إحداثياتها خمسة
+
+177
+00:16:09,140 --> 00:16:14,880
+أو تلاتة كمان sometimes it's more convenient to
+
+178
+00:16:14,880 --> 00:16:18,080
+locate a point in space by طبعا plane polar
+
+179
+00:16:18,080 --> 00:16:23,840
+coordinate ممكن كمان أنا أحدد نقطة عن طريق المحاور
+
+180
+00:16:23,840 --> 00:16:28,550
+اللى هي plane polar coordinate المحاوراللي هي
+
+181
+00:16:28,550 --> 00:16:34,250
+المستوى القطبي اللي هي عبارة عن R ومثلة بالـR و
+
+182
+00:16:34,250 --> 00:16:38,630
+بالثيتا الـR والثيتا عبارة عن reference أو مرجعية
+
+183
+00:16:38,630 --> 00:16:42,870
+على أساس أنه a point is specified by distance R
+
+184
+00:16:42,870 --> 00:16:49,870
+أنا ممكن أحدد النقطة بالمسافة R يعني النقطة المراد
+
+185
+00:16:49,870 --> 00:16:54,720
+تحديدها بتكون على بعد R من نقطة الأصلwe are ممكن
+
+186
+00:16:54,720 --> 00:16:59,520
+تمثل ب X و Y كأنها في مستوى إضافة إلى أنه تحدد
+
+187
+00:16:59,520 --> 00:17:05,060
+أيضًا بالزاوية theta و هذه الزاوية عبارة عن الخط
+
+188
+00:17:05,060 --> 00:17:13,080
+المرسوم من نقطة الأصل إلى الخط المرسوم من محور X
+
+189
+00:17:13,080 --> 00:17:20,090
+الموجب إلى هذه الزاويةيعني الشكل هذا 1.5 بيمثل
+
+190
+00:17:20,090 --> 00:17:24,610
+لنقطة P إحداثياتها خمسة أو تلاتة الخمسة عبارة عن X
+
+191
+00:17:24,610 --> 00:17:29,010
+و Y اللي هي ال X خمسة و Y بالساعة و تلاتة النقطة
+
+192
+00:17:29,010 --> 00:17:33,010
+هذه Q إحداثياتها ناقص تلاتة و أربع موجودة في الربع
+
+193
+00:17:33,010 --> 00:17:38,070
+التاني ال X بالسالب و ال Y بي الموجب هنا في الربع
+
+194
+00:17:38,070 --> 00:17:44,250
+الأول X موجب و Y موجب الشكل التاني الشكل التاني
+
+195
+00:17:44,250 --> 00:17:49,760
+اللي هو 1.6 بيوضح ليالنقطة ممثلة بـPlan Polar
+
+196
+00:17:49,760 --> 00:17:54,800
+Coordinate اللي هي R وTheta الـR هي عبارة عن الخط
+
+197
+00:17:54,800 --> 00:17:58,220
+الواصل بين نقطة الأصل و النقطة والـR ممثلة
+
+198
+00:17:58,220 --> 00:18:01,280
+بالمحورين
+
+199
+00:18:01,280 --> 00:18:08,260
+X وY وTheta هذه عبارة عن الزاوية المحصورة بين
+
+200
+00:18:08,260 --> 00:18:12,180
+اتجاه X الموجة و اللي هي النقطة أو المتجاه R
+
+201
+00:18:18,270 --> 00:18:23,690
+Trie Geometric Review الآن بالنسبة لها يعني نتذكر
+
+202
+00:18:23,690 --> 00:18:28,690
+بعض حساب المثلثات consider the right triangle لو
+
+203
+00:18:28,690 --> 00:18:33,790
+أنا فرضت في عندي أنا مثلث المثلث هذا قائم الزاوية
+
+204
+00:18:33,790 --> 00:18:38,350
+المثلث قائم الزاوية بالشكل هذا هذا طبعا الزاوية
+
+205
+00:18:38,350 --> 00:18:42,590
+حادة فهذا الاتجاه R لو نزلت أنا عمود اللي هو اتجاه
+
+206
+00:18:42,590 --> 00:18:45,490
+Y صار عندي أنا مثلث قائم الزاوية هي القائمة فهذا
+
+207
+00:18:45,490 --> 00:18:51,900
+الشكللو كان عندي أنهيب الزاوية sin θ اللي هي مقابل
+
+208
+00:18:51,900 --> 00:18:57,440
+على وطر Y على R cos θ عبارة عن X على R تاني
+
+209
+00:18:57,440 --> 00:19:02,580
+الزاوية عبارة عن مقابل على مجاور هذه حساب مثلثات
+
+210
+00:19:02,580 --> 00:19:08,120
+أخدناها سابقاً the basic trigeometric function
+
+211
+00:19:08,120 --> 00:19:14,580
+defined as such triangle as the follow يعنيبرضه
+
+212
+00:19:14,580 --> 00:19:21,000
+نتذكر انه sine الزاوية عبارة عن مقابل على water
+
+213
+00:19:21,000 --> 00:19:25,500
+cosine الزاوية عبارة عن مجاور على water و tan
+
+214
+00:19:25,500 --> 00:19:29,700
+الزاوية عبارة عن مقابل على مجاور كما هو موضح
+
+215
+00:19:29,700 --> 00:19:33,960
+بالشكل أول والثالث another important relationship
+
+216
+00:19:33,960 --> 00:19:39,120
+في برضه طبعا علاقة مهمة و هندرس عليها كتير و
+
+217
+00:19:39,120 --> 00:19:42,860
+هنشتغل عليها كتير اللي هي بيسموها نظرية FIFA golf
+
+218
+00:19:43,260 --> 00:19:47,040
+exist between the length of the side of the right
+
+219
+00:19:47,040 --> 00:19:53,240
+triangle هي تحدد العلاقة بين أطوال أضلاع القائمة
+
+220
+00:19:53,240 --> 00:19:59,960
+اللي هي الوطر تربيع بساوي X تربيع زائد Y تربيع لو
+
+221
+00:19:59,960 --> 00:20:03,860
+أنا فرضت أن عندي sign الزاوية بتساوي point 866
+
+222
+00:20:03,860 --> 00:20:08,620
+معنى الكلام أن الزاوية عشان أجيبها لازم أعمل sign
+
+223
+00:20:08,620 --> 00:20:13,520
+inverse للزاوية تطلع للزاويةSin Inverse هاي بجيبها
+
+224
+00:20:13,520 --> 00:20:20,680
+من خلال .. من خلال القالة Shift Sin تطلع ل60 درجة
+
+225
+00:20:20,680 --> 00:20:25,140
+لو أنا بدأ أجرب مرة تانية أنه أنا أوجد Tan Inverse
+
+226
+00:20:25,140 --> 00:20:32,090
+لل point 4 معنى الكلام هتطلع لزاوية 21.8لازم be
+
+227
+00:20:32,090 --> 00:20:35,430
+sure that your calculator is a set of degree لازم
+
+228
+00:20:35,430 --> 00:20:39,210
+نتأكد أنه القالة الحاسبة موجودة على degree اللي هي
+
+229
+00:20:39,210 --> 00:20:44,270
+درجات وليس رديان وليس بالمخدر الخيار الدائري in
+
+230
+00:20:44,270 --> 00:20:47,050
+addition the inverse tangent function can return
+
+231
+00:20:47,050 --> 00:20:54,190
+only view a value between minus 90 أو زائد 90 so
+
+232
+00:20:54,190 --> 00:20:59,520
+when an angle is in the secondor third quadrant
+
+233
+00:20:59,520 --> 00:21:04,000
+it's necessary to add 120 لو كان انا طلعت لزاوية
+
+234
+00:21:04,000 --> 00:21:09,280
+معينة فى الرُبع التانى او الرُبع التالت فلازم احنا
+
+235
+00:21:09,280 --> 00:21:15,060
+نضيف على الزاوية طبعا مية و تمانين درجة لإنه احنا
+
+236
+00:21:15,060 --> 00:21:20,390
+إنا أرباع الرُبع الأول بيكونالـ X موجبة والـ Y
+
+237
+00:21:20,390 --> 00:21:25,790
+موجبة والزاوية موجبة الربع التاني بيكون X سالبة و
+
+238
+00:21:25,790 --> 00:21:32,570
+X سالبة و Y موجبة الربع التالت X سالبة و Y سالبة
+
+239
+00:21:32,570 --> 00:21:38,580
+طبعا مثالthe Cartesian coordinate of the point in
+
+240
+00:21:38,580 --> 00:21:42,440
+the XY plane لو أنا عندي إحداثيات لنقطة النقطة هي
+
+241
+00:21:42,440 --> 00:21:46,260
+عبارة عن ال X بتساوي minus تلاتة و نص و Y minus
+
+242
+00:21:46,260 --> 00:21:49,600
+اتنين و نص إذا ال X سالبة و ال Y سالبة هتكون في
+
+243
+00:21:49,600 --> 00:21:56,200
+الربع التالت كما هو موضح بالشكل أوجد أوجد find the
+
+244
+00:21:56,200 --> 00:22:00,640
+polar coordinate of this point B بدي أوجد ال polar
+
+245
+00:22:00,640 --> 00:22:06,140
+coordinate بعدين convert اللي هي R أو فيتاto
+
+246
+00:22:06,140 --> 00:22:11,500
+rectangular coordinate علشان أحل هذا السؤالطبعا
+
+247
+00:22:11,500 --> 00:22:14,680
+إحنا عندنا الـ Cartesian coordinate القانون اللي
+
+248
+00:22:14,680 --> 00:22:17,960
+هي الـR أو الـR تربيع بتساوي X تربيع زاد Y تربيع
+
+249
+00:22:17,960 --> 00:22:21,180
+إذا ان الـR بتساوي جزر X تربيع زاد Y تربيع هدعى
+
+250
+00:22:21,180 --> 00:22:25,880
+فيتا غورث جيبنا قيمة الـR اللي قال لإيجاد الزاوية
+
+251
+00:22:25,880 --> 00:22:30,260
+10 فيتا بتساوي Y على X فبحط ال Y بالإشارة تبعتها و
+
+252
+00:22:30,260 --> 00:22:36,620
+ال X بالإشارة تبعتها طلعت عند الزاوية 35.5من وين
+
+253
+00:22:36,620 --> 00:22:41,240
+أجت الزاوية من tan inverse للكلام هذا طلع عندي 35
+
+254
+00:22:41,240 --> 00:22:48,740
+.5 طبعا ال 35.5 رح أضيف إلها 180 علشان هذه الزاوية
+
+255
+00:22:48,740 --> 00:22:53,740
+موجودة في الربع التالت و أنا بقيس الزاوية أو ال
+
+256
+00:22:53,740 --> 00:22:58,800
+reference line المرجعية الخطة بقى كانت بيبدأ دايما
+
+257
+00:22:58,800 --> 00:23:03,060
+من اتجاه X الموجب فبتطلع الزاوية 216 فعلا هي
+
+258
+00:23:03,060 --> 00:23:07,450
+الزاوية في الربع التالتلإيجاد ال .. البولر ..
+
+259
+00:23:07,450 --> 00:23:12,310
+البولر طبعا ال coordinate البولر to cartesian
+
+260
+00:23:12,310 --> 00:23:16,030
+conversion عشان أحول فأنا عندي X بتساوي ال R
+
+261
+00:23:16,030 --> 00:23:20,890
+cosine ال theta و ال Y بتساوي ال R sine ال theta و
+
+262
+00:23:20,890 --> 00:23:28,010
+بالتالي تطلع عندي ال X 3.99 و ال Y بتساوي 3.05
+
+263
+00:23:32,710 --> 00:23:38,710
+مثال آخر problems 1.10 a person measures the
+
+264
+00:23:38,710 --> 00:23:42,070
+height of the building by walking out a distance
+
+265
+00:23:42,070 --> 00:23:49,090
+of 46 متر from its base and shining a flash light
+
+266
+00:23:49,090 --> 00:23:53,390
+beam towards the top طبعا في عندي شخص بده يقيس
+
+267
+00:23:53,390 --> 00:23:59,690
+ارتفاع مبنى هو طبعا ماشي طبعا مسافة 46 متر من
+
+268
+00:23:59,690 --> 00:24:05,320
+قاعدة المبنىو أضاء فلاش ضوء فلاش أو إشعاع فلاش
+
+269
+00:24:05,320 --> 00:24:09,620
+نحيط الأعلى المبنى when the beam is elevate هذه
+
+270
+00:24:09,620 --> 00:24:14,540
+طبعا الأشعة صعدت أو وصلت أو يعني وصلت لأعلى المبنى
+
+271
+00:24:14,540 --> 00:24:17,840
+كانت الزاوية تسعة و تلاتين درجة بالنسبالها ال
+
+272
+00:24:17,840 --> 00:24:21,640
+horizontal the beam just struck the top of the
+
+273
+00:24:21,640 --> 00:24:25,740
+building if the flash light is held at height طبعا
+
+274
+00:24:25,740 --> 00:24:30,300
+احنا زي ما احنا شايفين بالشكل هي في عند man أو رجل
+
+275
+00:24:30,590 --> 00:24:34,210
+الرجل كان طوله اتنين بالنسبة لأ الأرضية المبنى
+
+276
+00:24:34,210 --> 00:24:39,690
+الرجل علشان يوصل لأعلى المبنى أضاء طبعا light أو
+
+277
+00:24:39,690 --> 00:24:44,550
+ضوء flash الضوء هذا هيمشي لأعلى المبنى لما كانت
+
+278
+00:24:44,550 --> 00:24:47,850
+الزاوية تسعة وتلاتين درجة بالنسبة لمين لأ ال
+
+279
+00:24:47,850 --> 00:24:51,330
+horizontal أو الأفقي المسافة كانت .. المسافة
+
+280
+00:24:51,330 --> 00:24:56,210
+الأفقية من الرجل للمبنى كانت ستة أو أربعين مترطبعا
+
+281
+00:24:56,210 --> 00:24:58,730
+المطلوب في هذا السؤال find the height of the
+
+282
+00:24:58,730 --> 00:25:02,510
+building بدي ارتفاع المبنى علشان اجيب ارتفاع
+
+283
+00:25:02,510 --> 00:25:06,730
+المبنى طبعا انا عندي علاقة انه تاني الزاوية بدها
+
+284
+00:25:06,730 --> 00:25:12,110
+تساوي مقابل على مجاور طبعا هستخدم فيثا غورث طبعا
+
+285
+00:25:12,110 --> 00:25:16,900
+عندي انا هنا كأنها مثلث قائم الزاويةعندي فيه ثغارت
+
+286
+00:25:16,900 --> 00:25:20,540
+المقابل على المجاور بساوي تان الزاوية الزاوية
+
+287
+00:25:20,540 --> 00:25:26,360
+موجودة والمجاور موجود ممكن احصل على مقابل المجاور
+
+288
+00:25:26,360 --> 00:25:26,920
+ممكن احصل على مقابل المجاور ممكن احصل على مقابل
+
+289
+00:25:26,920 --> 00:25:27,240
+المجاور ممكن احصل على مقابل المجاور ممكن احصل على
+
+290
+00:25:27,240 --> 00:25:27,380
+مقابل المجاور ممكن احصل على مقابل المجاور ممكن
+
+291
+00:25:27,380 --> 00:25:27,560
+احصل على مقابل المجاور ممكن احصل على مقابل المجاور
+
+292
+00:25:27,560 --> 00:25:28,060
+ممكن احصل على مقابل المجاور ممكن احصل على مقابل
+
+293
+00:25:28,060 --> 00:25:30,820
+المجاور ممكن احصل على مقابل المجاور ممكن احصل على
+
+294
+00:25:30,820 --> 00:25:36,940
+مقابل المجاور ممكن احصل على مقابل
+
+295
+00:25:41,210 --> 00:25:47,370
+37.3 متر هذا هو ارتفاع المبنى الآن لإيجاد طول
+
+296
+00:25:47,370 --> 00:25:51,510
+الشعاع calculate the length of the light بدي انا
+
+297
+00:25:51,510 --> 00:25:55,570
+طول الشعاع معناته بدي اوجد ال water برضه كفي ثغات
+
+298
+00:25:55,570 --> 00:25:59,750
+ال water بيساوي جزر التربيع إلى X تربيع زائد Y
+
+299
+00:25:59,750 --> 00:26:06,030
+تربيع تطلع عندى 59.8 متر هذا هو طول المبنى
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f429cc9dbbc5c5fc3bb541d6bda25e9d8cb268f6
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI.srt
@@ -0,0 +1,1002 @@
+1
+00:00:01,060 --> 00:00:06,280
+بسم الله الرحمن الرحيم نستكمل أمثلة chapter الرابع
+
+2
+00:00:06,280 --> 00:00:12,600
+طبعا الـ problems أربعة، slip is type three on
+
+3
+00:00:12,600 --> 00:00:16,500
+frictionless snow-covered hill as shown in the
+
+4
+00:00:16,500 --> 00:00:21,580
+figure. If the slip weighed 77 N, find the
+
+5
+00:00:21,580 --> 00:00:26,440
+magnitude of the tension force T exerted by the
+
+6
+00:00:26,440 --> 00:00:29,860
+rope on the sled and that of the normal force N
+
+7
+00:00:29,860 --> 00:00:31,880
+exerted by the hill on the sled.
+
+8
+00:00:37,240 --> 00:00:41,320
+الـ  frictionless ice معناه تفرخش الناس، في عنده هنا
+
+9
+00:00:41,320 --> 00:00:45,520
+شجرة مربوط فيها خط، المفروض هنا مربوط فيها يعني
+
+10
+00:00:45,520 --> 00:00:54,750
+عربات يعني تزلج على الجليد. مطلوب مني LGD اللي هو الـ
+
+11
+00:00:54,750 --> 00:01:00,170
+tension. طبعا هذه مربوطة بخيط، فلما أرسل في الـ
+
+12
+00:01:00,170 --> 00:01:06,390
+diagram، هنزل أول شيء LGD اللي هو كتلة  العربة، وهنا
+
+13
+00:01:06,390 --> 00:01:10,650
+في عندي خيوط الشد اتجاه ناحية الشجرة، الـ LGD راح
+
+14
+00:01:10,650 --> 00:01:16,690
+أحللها إلى LG sin θ بهذا الاتجاه و LG cos θ بهذا
+
+15
+00:01:16,690 --> 00:01:20,570
+الاتجاه، اللي هو عمودي على اللي هو عمودي على
+
+16
+00:01:20,570 --> 00:01:28,000
+المستوى. طبعا هذا المسار مائل بزاوية ثلاثين درجة.
+
+17
+00:01:28,000 --> 00:01:34,440
+الحل حققه بقانون نيوتن الثاني، بحيث أن القصور الذاتي بيساوي
+
+18
+00:01:34,440 --> 00:01:37,500
+زيرو، يعني في عندي نوع من الاتزان.
+
+19
+00:01:45,620 --> 00:01:50,260
+بالتالي، إذا extract the X component from this
+
+20
+00:01:50,260 --> 00:01:55,280
+equation to find T، بدي أوجد أو أطبق قانون نيوتن
+
+21
+00:01:55,280 --> 00:01:59,320
+الثاني في اتجاه الـ X axis. طبعا أنا بأعتبر اللي هو
+
+22
+00:01:59,320 --> 00:02:06,010
+انحدار الخط المنحدر هو امتداد الـ X axis. Fx بتساوي T
+
+23
+00:02:06,010 --> 00:02:12,890
+زائد صفر ناقص mg sin θ، إذا T ناقص mg sin θ
+
+24
+00:02:12,890 --> 00:02:16,310
+اللي إحنا طلعناها من قبل، هيك اللي هو هذه أبداً عن
+
+25
+00:02:16,310 --> 00:02:21,110
+الـ mg اللي هي الـ m في 9.8 في sin θ
+
+26
+00:02:21,110 --> 00:02:25,490
+بتطلع صفر لأن في عندي أنا اتزان. إذا الـ T
+
+27
+00:02:25,490 --> 00:02:29,780
+بتساوي 38.5 N. بدي أستخدم قانون
+
+28
+00:02:29,780 --> 00:02:33,800
+نيوتن الثاني بالنسبة للـ Y dimensions، اللي هو الـ Y
+
+29
+00:02:33,800 --> 00:02:38,100
+component of the tension is zero. طبعا ما فيش حركة
+
+30
+00:02:38,100 --> 00:02:42,800
+باتجاه أيضاً الـ Y. معناه الكلام أن summation للقوى
+
+31
+00:02:42,800 --> 00:02:47,440
+بيبقى تساوي صفر زائد N ناقص mg cos θ
+
+32
+00:02:47,440 --> 00:02:54,590
+بيبقى تساوي N ناقص mg cos θ بيساوي صفر.
+
+33
+00:02:54,590 --> 00:02:58,230
+إذا N بيساوي 66.7 N. إحنا
+
+34
+00:02:58,230 --> 00:03:01,910
+أوجدنا، الشباب، أوجدنا قوة رد الفعل اللي هي الـ
+
+35
+00:03:01,910 --> 00:03:07,030
+normal force. في هذا الـ quiz كان هو موضح بالشكل
+
+36
+00:03:07,030 --> 00:03:11,990
+for a woman being pulled forward on the top of gang
+
+37
+00:03:13,080 --> 00:03:20,120
+يعني طبعاً المرأة هذه سائلة على عربة التزلج، وطبعاً أحد
+
+38
+00:03:20,120 --> 00:03:26,040
+الأشخاص بيجذبها بهذا الشكل بخيط معين بزاوية طبعاً.
+
+39
+00:03:26,040 --> 00:03:28,800
+بالنسبة للـ normal force في هذه الحالة، the
+
+40
+00:03:28,800 --> 00:03:31,340
+magnitude of the normal force exerted by the
+
+41
+00:03:31,340 --> 00:03:36,920
+ground on the toboggan اللي هو قوة رد الفعل
+
+42
+00:03:36,920 --> 00:03:42,170
+العمودية من الأرض على العربة، هل هي بتساوي الـ total
+
+43
+00:03:42,170 --> 00:03:48,410
+weight of the woman plus the tension، ولا greater than
+
+44
+00:03:48,410 --> 00:03:54,250
+the total weight، ولا less than the total weight، or
+
+45
+00:03:54,250 --> 00:03:57,050
+possibly greater than or less than the total
+
+46
+00:03:57,050 --> 00:04:00,690
+weight depending on the size of the tension relative to
+
+47
+00:04:00,690 --> 00:04:04,290
+the tension in the rope. طبعاً الـ answer، السؤال
+
+48
+00:04:04,290 --> 00:04:08,110
+الجواب عبارة عن أنها less than the total weight.
+
+49
+00:04:08,110 --> 00:04:14,940
+لماذا؟ لأنه إذا فرضنا أن الشد بهذا الاتجاه، بمقدار معين، زي
+
+50
+00:04:14,940 --> 00:04:20,440
+الـ θ، لو بدأ أنا أرسل هنا الشد، هنا في عندي
+
+51
+00:04:20,440 --> 00:04:25,100
+N، وتحت هيكون اللي هو الـ mg. راح أحلل الشد إلى
+
+52
+00:04:25,100 --> 00:04:31,360
+T cos θ وهنا T sin θ. إذا الـ N زائد T sin θ
+
+53
+00:04:31,360 --> 00:04:37,770
+بيساوي mg. إذا الـ N بيساوي mg ناقص T sin
+
+54
+00:04:37,770 --> 00:04:41,610
+θ. معناه الكلام أنه في هذه الحالة، الـ normal عبارة
+
+55
+00:04:41,610 --> 00:04:47,490
+عن أقل قيمة، أقل، less than the total weight زي ما
+
+56
+00:04:47,490 --> 00:04:54,010
+أخذنا بالنسبة لقوة رد الفعل، كانت الـ normal أقل في
+
+57
+00:04:54,010 --> 00:04:58,630
+حالة ما إحنا شدينا أي جسم بقوة tension، اللي هي بقوة
+
+58
+00:04:58,630 --> 00:04:59,030
+شد.
+
+59
+00:05:09,680 --> 00:05:13,860
+الجسم للأعلى متسارع باستخدام قانون نيوتن
+
+60
+00:05:13,860 --> 00:05:18,220
+الثاني. When a net force acts on an object، لو كان
+
+61
+00:05:18,220 --> 00:05:23,200
+عنده مجموعة من القوى مؤثرة على أي جسم والجسم يحدث
+
+62
+00:05:23,200 --> 00:05:27,570
+له تسارع، and we use Newton’s second law to
+
+63
+00:05:27,570 --> 00:05:31,190
+analyze the motion. باستخدام قانون نيوتن الثاني
+
+64
+00:05:31,190 --> 00:05:37,150
+لتحليل اللي هي الحركة. في عندنا أنا خزانة، الخزانة
+
+65
+00:05:37,150 --> 00:05:41,750
+هذه موجودة على عربة. طبعاً، بدنا نزل، أنا الآن نزل
+
+66
+00:05:41,750 --> 00:05:46,070
+الخزانة زي العربة. هي الـ Fg اللي هي الـ mg للعربة زي
+
+67
+00:05:46,070 --> 00:05:50,840
+اللي هي العربة، تحتها هي الخزانة. هنا في عندي قوات شد،
+
+68
+00:05:50,840 --> 00:05:55,400
+مربوطة بخيط وبشدها. في عندي قوات رد فعل الأرض
+
+69
+00:05:55,400 --> 00:06:01,860
+على الخزانة زائد اللي هو العربة. الـ example اللي
+
+70
+00:06:01,860 --> 00:06:05,300
+عندنا اللي هو زي ما هو مرسوم بالشكل الأعلى. The
+
+71
+00:06:05,300 --> 00:06:08,540
+combined weight of the crate and the trolley.  بلد و
+
+72
+00:06:08,540 --> 00:06:13,680
+عربة، زي ما حكينا، كان هو موضح من هذا الشكل، ثلاثة
+
+73
+00:06:13,680 --> 00:06:18,440
+نيوتن.
+
+74
+00:06:18,440 --> 00:06:22,320
+If the man pulls on the rope with a constant force
+
+75
+00:06:22,320 --> 00:06:27,080
+طبعاً الراجل هذا بيشد الخزانة بقوة مقدارها عشرين
+
+76
+00:06:27,080 --> 00:06:34,000
+نيوتن. What is the acceleration of the
+
+77
+00:06:34,000 --> 00:06:37,700
+system؟ الـ system هو عبارة عن النظام كله، عبارة عن
+
+78
+00:06:37,700 --> 00:06:42,660
+الدولاب زائد العربة. And how far will it move in 2
+
+79
+00:06:42,660 --> 00:06:47,520
+seconds؟  كانت المسافة اللي بيمشيها خلال زمن ثانيتين.
+
+80
+00:06:48,100 --> 00:06:51,400
+بدنا نفترض أن الـ system started from rest and
+
+81
+00:06:51,400 --> 00:06:55,580
+that there are no friction forces within the
+
+82
+00:06:55,580 --> 00:07:00,360
+motion. طبعاً العربة والخزانة أو العربة والدولاب
+
+83
+00:07:00,360 --> 00:07:07,400
+بيمشوا على خط اللي هو frictionless. الحل، أول
+
+84
+00:07:07,400 --> 00:07:10,900
+شيء، find the mass of the system from the
+
+85
+00:07:10,900 --> 00:07:14,840
+definition. طبعاً هو وزن الـ system كله، وزن الـ system
+
+86
+00:07:14,840 --> 00:07:19,140
+كله 322 N.  من القانون أن الوزن بيساوي الـ mg، الـ m في هذه الحالة
+
+87
+00:07:19,140 --> 00:07:22,680
+بيساوي الوزن على الـ g اللي هي التسارع الأرضي. إذا
+
+88
+00:07:22,680 --> 00:07:26,020
+الـ mass اللي هي الكتلة للـ system كله بيساوي الوزن
+
+89
+00:07:26,020 --> 00:07:30,700
+على الـ g. 322 نيوتن على 9.8
+
+90
+00:07:30,700 --> 00:07:34,140
+متر/ثانية تربيع، يعطينا 32.9 kg. لإيجاد
+
+91
+00:07:34,140 --> 00:07:38,440
+التسارع، find acceleration of the system.  بستخدم
+
+92
+00:07:38,440 --> 00:07:41,900
+قانون نيوتن الثاني.  Summation للـ Fx بتساوي الـ m في
+
+93
+00:07:41,900 --> 00:07:45,700
+Ax. إذا الـ Ax بيبقى تساوي الـ F على m. الـ F باتجاه x
+
+94
+00:07:45,700 --> 00:07:50,480
+كانت عشرين، والـ m طلعناها 32.9، بيطلع
+
+95
+00:07:50,480 --> 00:07:53,460
+عندي 0.61 m/s تربيع.
+
+96
+00:07:53,460 --> 00:07:56,880
+متر في الثانية تربيع.
+
+97
+00:08:01,540 --> 00:08:07,060
+بأستخدم معادلات الحركة علشان أوجد المسافة اللي
+
+98
+00:08:07,060 --> 00:08:12,520
+مشيتها العربة طبعاً في زمن قدره ثانيتين.
+
+99
+00:08:21,020 --> 00:08:25,200
+بتبقى عندي Δx بتساوي نصف Ax تربيع، يعني
+
+100
+00:08:25,200 --> 00:08:31,100
+بتساوي نصف، والـ A طلعناها 0.61 في اللي
+
+101
+00:08:31,100 --> 00:08:36,720
+هو الزمن t تربيع، بتطلع 1.23 متر. الآن
+
+102
+00:08:36,720 --> 00:08:41,320
+example رقم 14. الـ problem عبارة عن a car of
+
+103
+00:08:41,320 --> 00:08:46,260
+mass m، سيارة كتلتها m، is on an icy driveway
+
+104
+00:08:46,260 --> 00:08:52,150
+inclined at an angle θ = 20°. سيارة كتلتها
+
+105
+00:08:52,150 --> 00:08:59,230
+m موجودة في مسار ثلجي مائل على الأفق بزاوية 20 درجة.
+
+106
+00:08:59,230 --> 00:09:04,330
+بتعمل acceleration، أو بتتسارع السيارة، باعتبار
+
+107
+00:09:04,330 --> 00:09:09,290
+أن assuming the incline is frictionless. If the
+
+108
+00:09:09,290 --> 00:09:12,950
+length of the driveway is 25 m and
+
+109
+00:09:12,950 --> 00:09:17,770
+the car starts from rest. طبعاً السؤال الثاني بيحكي
+
+110
+00:09:17,770 --> 00:09:21,850
+إن إذا كان طول المسار 25 متر، والسيارة
+
+111
+00:09:21,850 --> 00:09:26,190
+بتتحرك بدأت من السكون اللي في الأعلى. How long does
+
+112
+00:09:26,190 --> 00:09:30,310
+it take to travel to the bottom؟ بده الزمن اللازم لكي
+
+113
+00:09:30,310 --> 00:09:34,790
+تصل إلى أسفل المنحدر. بعد هيك بيطلب What is the car's
+
+114
+00:09:34,790 --> 00:09:38,850
+speed at the bottom؟ بده سرعة السيارة في نهاية اللي هو
+
+115
+00:09:38,850 --> 00:09:44,050
+المسار. الآن عندي أنا مسار منحدر، هي عربة
+
+116
+00:09:44,050 --> 00:09:50,930
+ثلجي، ومسار طبعاً خط مائل، ثلجي، معناه frictionless.
+
+117
+00:09:50,930 --> 00:09:55,950
+السيارة نازلة على هذا المنحدر. طبعاً السيارة نازلة على هذا
+
+118
+00:09:55,950 --> 00:10:00,150
+المنحدر، في البداية مطلوب منه أن نجد ماذا؟ مطلوب
+
+119
+00:10:00,150 --> 00:10:03,490
+منه أن نجد الـ acceleration of the car. بدي الـ
+
+120
+00:10:03,490 --> 00:10:07,110
+acceleration للـ car. إذا أنا بدي أرسم أول حاجة الـ
+
+121
+00:10:07,110 --> 00:10:12,850
+free body diagram كما هو موضح بالشكل. في عندي اللي
+
+122
+00:10:12,850 --> 00:10:16,530
+عندي اللي هي قوة الجاذبية، أو الـ mg. الـ mg، هي نفسها
+
+123
+00:10:16,530 --> 00:10:21,050
+الـ m في g، وفي عندي الـ Normal عمودية
+
+124
+00:10:21,050 --> 00:10:25,910
+على السطح، ده هو السطح المائل، والـ N عمودية على
+
+125
+00:10:25,910 --> 00:10:31,890
+السطح المائل. بدنا نحلل الـ mg إلى mg sin θ على
+
+126
+00:10:31,890 --> 00:10:36,310
+نفس المستوى، و mg cos θ عمودي على المستوى.
+
+127
+00:10:37,080 --> 00:10:41,340
+طبعاً ما في frictionless، معناه مش هاخد احتكاك في
+
+128
+00:10:41,340 --> 00:10:45,700
+هذا الاتجاه. إذا هو الذي ينزل على أسفل المنحدر.
+
+129
+00:10:45,700 --> 00:10:49,560
+فالقوة اللي هذي بأعتبر هذي كإنها الـ x-axis، و
+
+130
+00:10:49,560 --> 00:10:53,920
+بأعتبر هذي كإنها الـ y-axis. لما بدنا نوجد الـ
+
+131
+00:10:53,920 --> 00:10:56,940
+acceleration، to find the acceleration of the car،
+
+132
+00:10:56,940 --> 00:11:02,520
+بدنا نستخدم قانون نيوتن الثاني. Summation للـ Fy بتساوي
+
+133
+00:11:02,520 --> 00:11:05,940
+الصفر.  طبعاً عندي أنا الـ Fg
+
+134
+00:11:18,980 --> 00:11:23,030
+بالنسبة للقوى الموجودة في البرنامج، هو عبارة عن
+
+135
+00:11:23,030 --> 00:11:28,430
+N ناقص mg cos θ بيساوي صفر، لأن ما في حركة
+
+136
+00:11:28,430 --> 00:11:32,470
+باتجاه الـ y-axis، وحركة التسارع باتجاه الـ x-axis.
+
+137
+00:11:38,950 --> 00:11:43,990
+Dividing المعادلة الأولى by m، المعادلة الأولى، بدي
+
+138
+00:11:43,990 --> 00:11:48,410
+أقسمها على m، أو بدي أشيل m من الطرفين، تطلع الـ Ax
+
+139
+00:11:48,410 --> 00:11:51,990
+بيساوي g sin θ. إذا إن الـ A باتجاه x
+
+140
+00:11:51,990 --> 00:11:54,590
+بيساوي g sin θ، و g تسعة وثمانية من عشرة،
+
+141
+00:11:54,590 --> 00:11:59,090
+sin العشرين، تطلع عندي A 3.35 m/s²
+
+142
+00:11:59,090 --> 00:12:01,710
+عبارة عن التسارع اللي بتمشي فيه السيارة على
+
+143
+00:12:01,710 --> 00:12:08,580
+المنحدر. المنحدر أنا اعتبرته كأنه محور x.  في b يجب أن
+
+144
+00:12:08,580 --> 00:12:13,220
+تجد الوقت الذي يتطلبه لتحقيق الـ Cartridge. بمدّ
+
+145
+00:12:13,220 --> 00:12:22,280
+الزمن اللازم لكي تصل السيارة إلى أسفل المنحدر. طبعاً
+
+146
+00:12:22,280 --> 00:12:26,740
+أنا بدأت من الريست، V0x بيساوي صفر. عندي أنا
+
+147
+00:12:26,740 --> 00:12:30,820
+الـ Δx بتساوي V0t زائد نصف at تربيع، و V0
+
+148
+00:12:30,820 --> 00:12:35,710
+بيساوي صفر. وذلك عندي نصف at تربيع. نصف الـ a اللي هي
+
+149
+00:12:35,710 --> 00:12:40,770
+3.35، والزمن اللي هو t تربيع ما عنديش، في عندي أنا
+
+150
+00:12:40,770 --> 00:12:44,770
+اللي هي Δx، هي مسافة لأن طول المنحدر كانت السيارة
+
+151
+00:12:44,770 --> 00:12:51,230
+ماشية بمسافة 25 متر، وطالب منها الزمن اللازم علشان
+
+152
+00:12:51,230 --> 00:12:55,090
+السيارة تصل إلى نهاية المنحدر، اللي هو نهايته طوله
+
+153
+00:12:55,090 --> 00:12:59,730
+كان بيمشي مسافة 25 متر. بيطلع الزمن 3.86
+
+154
+00:12:59,730 --> 00:13:04,710
+ثانية. في c، find the speed of the car at the bottom
+
+155
+00:13:04,710 --> 00:13:10,130
+of the driveway. بده سرعة السيارة في نهاية المسار
+
+156
+00:13:10,130 --> 00:13:17,590
+أو في نهاية المنحدر. فبأستخدم إن Vx بتساوي V0x
+
+157
+00:13:17,590 --> 00:13:21,510
+زائد At. V0 كانت صفر، هي V0x بتساوي
+
+158
+00:13:21,510 --> 00:13:26,790
+صفر، بيبقى عندي Ax في t. 3.35 و t
+
+159
+00:13:26,790 --> 00:13:30,450
+3.86 طلعناها، بيطلع عندي السرعة
+
+160
+00:13:30,450 --> 00:13:34,610
+النهائية بتساوي 12.9 m/s. إذا
+
+161
+00:13:34,610 --> 00:13:39,150
+السؤال السابق كان عند سيارة تتحرك على منحدر،
+
+162
+00:13:39,150 --> 00:13:43,610
+تتحرك على منحدر، بدأت من السكون، ووصلت لآخر المنحدر،
+
+163
+00:13:43,610 --> 00:13:47,370
+منحدر كان طوله 25 متر. بدأنا نعتبر المنحدر هو
+
+164
+00:13:47,370 --> 00:13:52,710
+الـ x-axis. راح نحلل الـ mg. الـ mg sin θ باتجاه
+
+165
+00:13:52,710 --> 00:13:57,330
+المنحدر، والـ mg cos θ عمودي عليه. وطبقت قانون نيوتن
+
+166
+00:13:57,330 --> 00:14:01,010
+الثاني على summation للـ Fx و summation للـ Fy، وأوجدت
+
+167
+00:14:01,010 --> 00:14:06,190
+التسارع، وأوجدت السرعة النهائية في آخر المنحدر.
+
+168
+00:14:07,630 --> 00:14:12,170
+بالضبط مثلًا problems. في عندي woman، وقت الـ
+
+169
+00:14:12,170 --> 00:14:18,490
+«مصعد»
+
+170
+00:14:18,490 --> 00:14:25,750
+تقف امرأة في مصعد، بدها توزن سمكة معلقة في
+
+171
+00:14:25,750 --> 00:14:31,990
+spring scale، تدريج، في سقف اللي هو المصعد.
+
+172
+00:14:35,010 --> 00:14:42,150
+واللي المصعد ساكن، كانت قراءته 40 نيوتن.
+
+173
+00:14:42,150 --> 00:14:46,230
+والآن مطلوب مني ماهي قراءة
+
+174
+00:14:46,230 --> 
+
+223
+00:18:01,190 --> 00:18:03,930
+الـG تسعة وثمانية من عشرة، يطلع معايا T ثمانية و
+
+224
+00:18:03,930 --> 00:18:07,660
+أربعين. بطلع واحد. المُطينالان. بقى بدي استخدم نفس
+
+225
+00:18:07,660 --> 00:18:11,260
+الخوانين، ولكن الـ elevator إلى أسفل، لما يكون الـ
+
+226
+00:18:11,260 --> 00:18:15,160
+elevator إلى أسفل، فالإيه تعتبر سالب، لأن إحنا
+
+227
+00:18:15,160 --> 00:18:19,420
+نشتغل حسب المحاور، المتجه الأعلى بيكون موجب،
+
+228
+00:18:19,420 --> 00:18:23,600
+والأسفل سالب، وعلى اليمين موجب وعلى اليسار سالب. الآن الـ
+
+229
+00:18:23,600 --> 00:18:27,160
+analysis is the same، بيقوم with the change being
+
+230
+00:18:27,160 --> 00:18:34,780
+acceleration which is now negative. إذا T بتساوي MA
+
+231
+00:18:34,780 --> 00:18:41,080
+زائد G، لكن الـ M نفسها، والـ A سالب اثنين متر في
+
+232
+00:18:41,080 --> 00:18:43,400
+الثانية تربيع، والـ G تسعة وثمانية من عشرة، بيطلع عندي
+
+233
+00:18:43,400 --> 00:18:46,120
+الـ T ثمانية وثلاثين point. تمام. معنى الكلام
+
+234
+00:18:46,120 --> 00:18:51,000
+أن الشد أو الـ scale reading، الـ scale reading أو الـ
+
+235
+00:18:51,000 --> 00:18:54,700
+spring reading، لما يكون الـ elevator طالع، يكون الشد
+
+236
+00:18:54,700 --> 00:19:00,120
+أعلى (greater than the weight). لما يكون نازل يكون
+
+237
+00:19:00,120 --> 00:19:05,840
+أقل من الـ weight. في الحالة جيم، المطلوب مني find the scale
+
+238
+00:19:05,840 --> 00:19:10,660
+reading after the elevator cable breaks. المطلوب الـ
+
+239
+00:19:10,660 --> 00:19:15,580
+scale reading عندما ينقطع الحبل، عندما ينقطع الحبل
+
+240
+00:19:15,580 --> 00:19:20,440
+معناه  T بتساوي صفر، معناته الـ a عندنا  ناقص الـ G
+
+241
+00:19:20,440 --> 00:19:25,200
+بيصير أن الجسم نزل بتسارع جاذبية، فالـ a بتساوي ناقص
+
+242
+00:19:25,200 --> 00:19:28,560
+تسعة وثمانية من عشرة. الـ acceleration هذا  أيه؟ لسبب
+
+243
+00:19:28,560 --> 00:19:35,030
+الجاذبية. في T = MA زائد G. الآن لو عوضت عن هذا
+
+244
+00:19:35,030 --> 00:19:38,730
+القانون، الآن أربعة اللي طلعناها سابقاً، والـ a
+
+245
+00:19:38,730 --> 00:19:42,410
+انكسرت، هو نزل بتسارع جاذبية تسعة وثمانية من عشرة زائد
+
+246
+00:19:42,410 --> 00:19:45,570
+تسعة وثمانية من عشرة، بيطلع عندي الشد بيساوي صفر بكل
+
+247
+00:19:45,570 --> 00:19:50,590
+الأحوال. أي سؤال؟ موجود عندنا. أن الخيطان انقطع، معناته
+
+248
+00:19:50,590 --> 00:19:52,790
+الشد بيساوي صفر.
+
+249
+00:20:04,890 --> 00:20:09,530
+problems. طبعاً مثلاً بالبند واحد، اثنين، بيحكي أن
+
+250
+00:20:09,530 --> 00:20:15,470
+الـ hockey puck in figure is hit by a hockey stick is
+
+251
+00:20:15,470 --> 00:20:18,490
+given an initial speed of عشرين متر في الثانية، on
+
+252
+00:20:18,490 --> 00:20:23,050
+a frozen pond, the puck remained on the ice. الـ puck
+
+253
+00:20:23,050 --> 00:20:27,570
+remained on the ice and slides 1.2 × 10<sup>2</sup> meters
+
+254
+00:20:27,570 --> 00:20:32,870
+slowing down steadily until it comes to rest. to
+
+255
+00:20:32,870 --> 00:20:34,670
+determine the coefficient of kinetic friction
+
+256
+00:20:34,670 --> 00:20:36,130
+between the puck and the ice.
+
+257
+00:20:39,120 --> 00:20:44,960
+العجلة اللي بتستخدم على الجليد، وهذه العجلة ممكن
+
+258
+00:20:44,960 --> 00:20:49,520
+تضرب بقوة معينة، وبتتمشي مسافة معينة على الجليد.
+
+259
+00:20:49,520 --> 00:20:55,000
+طبعاً عندي أنا اللي هي العجلة، أو لأن الجسم طبعاً أنا
+
+260
+00:20:55,000 --> 00:21:00,580
+قدفته بقوة معينة على الجليد، هذه هي الـ motion، حركته
+
+261
+00:21:00,580 --> 00:21:06,740
+أو جسم جمعته بحركة معينة، في مقابل اتجاه. طبعاً في
+
+262
+00:21:06,740 --> 00:21:09,300
+عندي قوة احتكاك عن طريق البرامج الأخرى، وهي الـ FK.
+
+263
+00:21:09,300 --> 00:21:12,220
+لما أرسم أنا الـ Free Body Diagram لهذا الـ Z  سمح،
+
+264
+00:21:12,220 --> 00:21:16,580
+يكون عندي Normal إلى أعلى، و MG إلى أسفل. المطلوب مني الـ
+
+265
+00:21:16,580 --> 00:21:18,600
+coefficient of kinetic friction.
+
+266
+00:21:22,450 --> 00:21:24,830
+سنحل  الآن.
+
+267
+00:21:24,830 --> 00:21:26,090
+(repeated word removed)
+
+268
+00:21:26,090 --> 00:21:28,750
+(repeated word removed)
+
+269
+00:21:28,750 --> 00:21:30,230
+(repeated word removed)
+
+270
+00:21:30,230 --> 00:21:31,950
+(repeated word removed)
+
+271
+00:21:31,950 --> 00:21:31,990
+(repeated word removed)
+
+272
+00:21:31,990 --> 00:21:34,970
+(repeated word removed)
+
+273
+00:21:34,970 --> 00:21:37,910
+(repeated word removed)
+
+274
+00:21:37,910 --> 00:21:44,110
+(repeated word removed)
+
+275
+00:21:50,780 --> 00:21:54,980
+هذه المعطيات اللي عندي: V النهائية Zero، V البدائية كانت
+
+276
+00:21:54,980 --> 00:21:59,320
+عشرين متر في الثانية، Delta X واحد واثنين في عشرة
+
+277
+00:21:59,320 --> 00:22:04,420
+أُس اثنين متر. Note that the negative sign in answer
+
+278
+00:22:04,420 --> 00:22:09,440
+A is opposite V. طبعاً لما أوجد أنا التسارع، هو هيطلع
+
+279
+00:22:09,440 --> 00:22:14,560
+عنده سالب لأنه هو بدأ بسرعة وانتهى بصفر، يعني
+
+280
+00:22:14,560 --> 00:22:20,010
+بتباطأ الجسيم لغاية ما وصل للصفر، إذن الـ A سالب. في
+
+281
+00:22:20,010 --> 00:22:26,030
+V<sub>0</sub><sup>2</sup> = 20 تربيع على 2 Delta X  1.2 × 10<sup>2</sup> متر، بيطلع
+
+282
+00:22:26,030 --> 00:22:31,290
+أنه ناقص 1.67 متر في الثانية تربيع، معناته التسارع
+
+283
+00:22:31,290 --> 00:22:37,190
+تبعه هو سالب، حتى يصل للسرعة النهائية صفر.
+
+284
+00:22:37,190 --> 00:22:40,910
+يعني بيتباطأ. المطلوب الـ Normal force، find the normal
+
+285
+00:22:40,910 --> 00:22:45,790
+force by from the y component. بدي الـ Normal
+
+286
+00:22:45,790 --> 00:22:50,390
+force.  قوة رد الفعل. راح أطبق قانون نيوتن على اتجاه
+
+287
+00:22:50,390 --> 00:22:55,330
+الـ Y: الـ Normal ناقص اللي هو الـ FG، بتساوي الـ N ناقص
+
+288
+00:22:55,330 --> 00:22:59,190
+MG بتساوي صفر، لأن مافي حركة باتجاه الـ Y. إذن الـ Normal
+
+289
+00:22:59,190 --> 00:23:06,710
+بتساوي الـ MG في هذه الحالة. عشان أوجد الـ
+
+290
+00:23:06,710 --> 00:23:11,030
+coefficient of kinetic friction، الـ FK بتساوي Mu
+
+291
+00:23:11,030 --> 00:23:15,690
+K في الـ Normal. الـ FK بتساوي Mu K في الـ Normal
+
+292
+00:23:15,690 --> 00:23:22,790
+بتساوي Mu K في M G. إذاً ناقص FK بتساوي ناقص Mu K في
+
+293
+00:23:22,790 --> 00:23:29,840
+M G. طبعاً في هذه الحالة، بدي أرسم أنا المعادلة، أكتب
+
+294
+00:23:29,840 --> 00:23:33,520
+هذه المعادلة لو بنتجرها على الـ X axis. في هذه الحالة
+
+295
+00:23:33,520 --> 00:23:39,360
+الـ Mu K، يعني الـ FK هي اللي بتساوي M في A. و FK
+
+296
+00:23:39,360 --> 00:23:43,520
+بتساوي ناقص Mu K في N G بتساوي M في A. الـ M بتروح
+
+297
+00:23:43,520 --> 00:23:46,860
+من اللي مع الـ M، بيبقى عندي Mu K بتساوي ناقص A على
+
+298
+00:23:46,860 --> 00:23:47,200
+G
+
+299
+00:24:02,410 --> 00:24:04,930
+سنستكمل إن شاء الله في الدرس القادم.
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..5399a63038ffbe8106868eed6f9bc854a9df74aa
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_postprocess.srt
@@ -0,0 +1,1196 @@
+1
+00:00:01,060 --> 00:00:06,280
+بسم الله الرحمن الرحيم نستكمل أمثلة chapter أربع
+
+2
+00:00:06,280 --> 00:00:12,600
+طبعا ال problems أبارعان slip is type three on
+
+3
+00:00:12,600 --> 00:00:16,500
+frictionless snow covered hill as shown in the
+
+4
+00:00:16,500 --> 00:00:21,580
+figure if the slip weighed 77 in NewtonFind the
+
+5
+00:00:21,580 --> 00:00:26,440
+magnitude of the tension force T exerted by the
+
+6
+00:00:26,440 --> 00:00:29,860
+rope on the sled and that of the normal force M
+
+7
+00:00:29,860 --> 00:00:31,880
+exerted by the hill on the sled
+
+8
+00:00:37,240 --> 00:00:41,320
+الـ Fungible ice معناه تفرخش الناس، في عنده هنا
+
+9
+00:00:41,320 --> 00:00:45,520
+شجرة مربوط فيها خط، المفروض هنا مربوط فيها يعني
+
+10
+00:00:45,520 --> 00:00:54,750
+عربات يعني تزلج على الجليدمطلب مني LGD اللي هو ال
+
+11
+00:00:54,750 --> 00:01:00,170
+tension طبعا هذه مربوطة بخيط فلما أرسل في ال
+
+12
+00:01:00,170 --> 00:01:06,390
+diagram هنزل أول شي LGD اللي هو كتلة العرضة وهنا
+
+13
+00:01:06,390 --> 00:01:10,650
+في عندي خيوط الشد اتجاه ناحية الشجرة ال LGD راح
+
+14
+00:01:10,650 --> 00:01:16,690
+أحللها إلى LG sin θ بهذا الاتجاه و LG cos θ بهذا
+
+15
+00:01:16,690 --> 00:01:20,570
+الاتجاه اللي هو عمودي على اللي هو عمودي على
+
+16
+00:01:20,570 --> 00:01:28,000
+المستوىطبعا هذا المسار مائد بزاوية تلاتين درجة
+
+17
+00:01:28,000 --> 00:01:34,440
+الحل حقق بقانون متل التاني بحيث ان القسارة بساوي
+
+18
+00:01:34,440 --> 00:01:37,500
+زيرو يعني في عند نوع من الاتزان
+
+19
+00:01:45,620 --> 00:01:50,260
+بالتالي اذا extract the X component from this
+
+20
+00:01:50,260 --> 00:01:55,280
+equation to find T بدي اوجد او اطبق قانون نوتن
+
+21
+00:01:55,280 --> 00:01:59,320
+التاني في اتجاه ال X axis طبعا انا باعتبر اللي هو
+
+22
+00:01:59,320 --> 00:02:06,010
+انحدار الخط المنحدر هو أبارع ال X axisفكس بتساوي T
+
+23
+00:02:06,010 --> 00:02:12,890
+زائد زير ناقص NG SIN فيته اذا T ناقص NG SIN فيته
+
+24
+00:02:12,890 --> 00:02:16,310
+اللي احنا طلعناها من قبل هيك اللي هو هذه أبدا عن
+
+25
+00:02:16,310 --> 00:02:21,110
+ال NG اللي هي ال N في تسعة وتمانية من عشرة في SIN
+
+26
+00:02:21,110 --> 00:02:25,490
+فيته بتطلع زيره لإن في عندي انا اتزان اذا ال T
+
+27
+00:02:25,490 --> 00:02:29,780
+بتساوي تمانية او تلاتين ونص المتينبدي استخدم قانون
+
+28
+00:02:29,780 --> 00:02:33,800
+متعدد تاني بالنسبة للـY dimensions اللي هو الـY
+
+29
+00:02:33,800 --> 00:02:38,100
+component of the tension is zero طبعا مافيش حركة
+
+30
+00:02:38,100 --> 00:02:42,800
+باتجاه ايضا الـY معناه الكلام ان summation للأفوال
+
+31
+00:02:42,800 --> 00:02:47,440
+بيبقى تساوي Zero زائد الان ناقص MG كزاين فيتا
+
+32
+00:02:47,440 --> 00:02:54,590
+بيبقى تساوي Normal ناقص MGفي كوزاينة يتا بالسواء
+
+33
+00:02:54,590 --> 00:02:58,230
+Zero اذا نرى بالسواء ستة و ستين point سبعة احنا
+
+34
+00:02:58,230 --> 00:03:01,910
+اوجدنا الشباب اوجدنا قوة رد الفئة اللي هي ال
+
+35
+00:03:01,910 --> 00:03:07,030
+normal efforts في هذا ال quiz كان هي مضح بالشكل
+
+36
+00:03:07,030 --> 00:03:11,990
+for the woman being pulled forward in the top gang
+
+37
+00:03:13,080 --> 00:03:20,120
+يعني طبعا المرأة هذه زالت على عرب التزلج وطبعا أحد
+
+38
+00:03:20,120 --> 00:03:26,040
+الأشخاص بيجيب بهذا الشكل بخياط معين بزاوية طبعا
+
+39
+00:03:26,040 --> 00:03:28,800
+بالنسبة لل normal force في هذه الحالة the
+
+40
+00:03:28,800 --> 00:03:31,340
+magnitude of the normal force exceeded by the
+
+41
+00:03:31,340 --> 00:03:36,920
+ground in the top gun اللي هو قوة رد الفائل
+
+42
+00:03:36,920 --> 00:03:42,170
+العمضية من الأرض على العربةهل بيه بتساوي ال total
+
+43
+00:03:42,170 --> 00:03:48,410
+weight of the woman plus تبجان ولا greater than
+
+44
+00:03:48,410 --> 00:03:54,250
+the total weight ولا less than the total weight or
+
+45
+00:03:54,250 --> 00:03:57,050
+possibly greater than or less than the total
+
+46
+00:03:57,050 --> 00:04:00,690
+depending on the size of the weight relative to
+
+47
+00:04:00,690 --> 00:04:04,290
+the tension in the rope طبعا ال answer السؤال
+
+48
+00:04:04,290 --> 00:04:08,110
+الجواب عبارة عن ان هي less than the total weight
+
+49
+00:04:08,110 --> 00:04:14,940
+لماذا؟لأنه إذا فرضنا إن الشد بهذا الإتجار بميئة زي
+
+50
+00:04:14,940 --> 00:04:20,440
+الـθيتا لو بدأ أنا أرسل هنا الشد هنا في عندي
+
+51
+00:04:20,440 --> 00:04:25,100
+Normal و تحت هيكون اللي هو الـMg راح أحلل الشد إلى
+
+52
+00:04:25,100 --> 00:04:31,360
+T Cos θ وهنا T Sin θ إذا الـNormal زي الـT Sin θ
+
+53
+00:04:31,360 --> 00:04:37,770
+بيساوي الـMg إذا الـNormal بيساوي الـMg ناقصT sin
+
+54
+00:04:37,770 --> 00:04:41,610
+θ معناه الكلام انه في هذه الحالة ال normal عبارة
+
+55
+00:04:41,610 --> 00:04:47,490
+عن اقل قيمته اقل less than the total weight زي ما
+
+56
+00:04:47,490 --> 00:04:54,010
+أخدنا بالنسبة لقوة رد الفعل كانت ال normal اقل في
+
+57
+00:04:54,010 --> 00:04:58,630
+حالة ما احنا شدنا اي جسم بقوة tension اللي هي بقوة
+
+58
+00:04:58,630 --> 00:04:59,030
+شد
+
+59
+00:05:09,680 --> 00:05:13,860
+الجسم للأسام المتسارعة باستخدام قانون الموتون
+
+60
+00:05:13,860 --> 00:05:18,220
+التاني when a net force acts on an object لو كان
+
+61
+00:05:18,220 --> 00:05:23,200
+عنده مجموعة من القوة مؤثرة على أي جسم والجسم يحدث
+
+62
+00:05:23,200 --> 00:05:27,570
+له تسارعand we use the Newton's second law to
+
+63
+00:05:27,570 --> 00:05:31,190
+analyze the motion باستخدام قانون ال Newton التاني
+
+64
+00:05:31,190 --> 00:05:37,150
+لتحليل اللي هي الحركة في عندنا أنا خزانة الخزانة
+
+65
+00:05:37,150 --> 00:05:41,750
+هذه موجودة على العربة طبعا بدا نزل انا الان نزل
+
+66
+00:05:41,750 --> 00:05:46,070
+الخزانة زي العربة هي ال FG اللي هي ال MG للعربة زي
+
+67
+00:05:46,070 --> 00:05:50,840
+اللي هي العربة تحته هي الخزانةهنا في عندى قوات شد
+
+68
+00:05:50,840 --> 00:05:55,400
+مربوطة بخيط وبشدها، في عندى قوات red فيها الأرض
+
+69
+00:05:55,400 --> 00:06:01,860
+على الخزانة زائد اللى هو العرباالـ example اللي
+
+70
+00:06:01,860 --> 00:06:05,300
+عندنا اللي هو زي ما هو مرسوم بالشكل الأعلى the
+
+71
+00:06:05,300 --> 00:06:08,540
+combined weight of the crate and bullion بلد و
+
+72
+00:06:08,540 --> 00:06:13,680
+عربة زي ما حكيناه كان هو موضح من هذا الشكل تلاتة
+
+73
+00:06:13,680 --> 00:06:18,440
+نوتين
+
+74
+00:06:18,440 --> 00:06:22,320
+if the man pull on the rope with constant force
+
+75
+00:06:22,320 --> 00:06:27,080
+طبعا الراجل هذا بشد الخزانة بقوة مقدارها عشرين
+
+76
+00:06:27,080 --> 00:06:34,000
+نوتين what isWhat is the acceleration of the
+
+77
+00:06:34,000 --> 00:06:37,700
+system؟ ال system هو عبارة عن النظام كله عبارة عن
+
+78
+00:06:37,700 --> 00:06:42,660
+الدولاب زائد العربة and how far will it move in 2
+
+79
+00:06:42,660 --> 00:06:47,520
+seconds كان المسافة اللي بنتمشيها خلال زمن 2 ثانية
+
+80
+00:06:48,100 --> 00:06:51,400
+بدا أنا أفرض إن ال system started from rest and
+
+81
+00:06:51,400 --> 00:06:55,580
+that there are no friction force within the
+
+82
+00:06:55,580 --> 00:07:00,360
+motion، طبعا العربة و الخزانة أو العربة و الدلاب
+
+83
+00:07:00,360 --> 00:07:07,400
+بيمشوا على خط اللي هو less friction less، الحلأول
+
+84
+00:07:07,400 --> 00:07:10,900
+شيء find the mass of the system from the
+
+85
+00:07:10,900 --> 00:07:14,840
+definition طبعا هو وزن ال system كله وزن ال system
+
+86
+00:07:14,840 --> 00:07:19,140
+كله أدارة عن تلاتة في عشر أفس اتنين او اتنين فمن
+
+87
+00:07:19,140 --> 00:07:22,680
+القانون ان الوزن بيساوي ال M G ال M في هذه الحالة
+
+88
+00:07:22,680 --> 00:07:26,020
+بيساوي الوزن على ال G اللي هي التسارع الجاذبية اذا
+
+89
+00:07:26,020 --> 00:07:30,700
+ال mass اللي هي الكتلة لل system كله بيساوي الوزن
+
+90
+00:07:30,700 --> 00:07:34,140
+على ال Gتلاتة فى عشرة أقصى اتنين نيوتن على تسعة
+
+91
+00:07:34,140 --> 00:07:38,440
+بون تمانية تعطيه تلاتين بون ستة كيلو جرام لإيجاد
+
+92
+00:07:38,440 --> 00:07:41,900
+التسارع find acceleration of the system بستخدم
+
+93
+00:07:41,900 --> 00:07:45,700
+قانون نيوتن التاني summation لل Fx بتساوي ال M في
+
+94
+00:07:45,700 --> 00:07:50,480
+Ax إذا ال Ax بيبقى تساوي ال F على M ال F تجاه ال X
+
+95
+00:07:50,480 --> 00:07:53,460
+كانت عشرين و ال M طلعناها تلاتين بون ستة بيطلع
+
+96
+00:07:53,460 --> 00:07:56,880
+عندي point six خمسة أربعة متر في الثانية تربيع
+
+97
+00:08:01,540 --> 00:08:07,060
+استخد المعادلات الحركة علشان اوجد المسافة اللى
+
+98
+00:08:07,060 --> 00:08:12,520
+مشيتها العربة طبعا في زمن قبل اتنين ثانية
+
+99
+00:08:21,020 --> 00:08:25,200
+بتبقى لعندي delta X بتساوي نص A X تربيه يعني
+
+100
+00:08:25,200 --> 00:08:31,100
+بتساوي نص وال A طلعناها بين ستة خمسة أربعة في اللي
+
+101
+00:08:31,100 --> 00:08:36,720
+هو زمان T الترويه تلعبي واحد بين تلاتة مترالان
+
+102
+00:08:36,720 --> 00:08:41,320
+example أربع عشرة ال problem عبارة عن a car of
+
+103
+00:08:41,320 --> 00:08:46,260
+mass M سيارة كتلتها M is on an icy driveway
+
+104
+00:08:46,260 --> 00:08:52,150
+inclined at an angle فتة بالساعة عشرين سيارةكتلتها
+
+105
+00:08:52,150 --> 00:08:59,230
+M موجودة في مثال ثلجي بنيل على الأفق زاوية 20 درجة
+
+106
+00:08:59,230 --> 00:09:04,330
+بتعمل acceleration أو دقاء بتسارق السيارة باعتبار
+
+107
+00:09:04,330 --> 00:09:09,290
+أن assuming the incline is frictionlessIf the
+
+108
+00:09:09,290 --> 00:09:12,950
+length of the drive away is خمسة و عشرين متر and
+
+109
+00:09:12,950 --> 00:09:17,770
+the car start from west طبعا السلوب التاني بيحكي
+
+110
+00:09:17,770 --> 00:09:21,850
+إن إذا كان طول المسار خمسة و عشرين متر والسيارة
+
+111
+00:09:21,850 --> 00:09:26,190
+بتتحرك بدأت من السكوناللي في الأعلى how long does
+
+112
+00:09:26,190 --> 00:09:30,310
+it take to travel to Buton بده الزمن اللازم لكي
+
+113
+00:09:30,310 --> 00:09:34,790
+تصل إلى أسفل المنحدر بعد هيك بطلب what is the car
+
+114
+00:09:34,790 --> 00:09:38,850
+speed ال Buton بده سرعة السيارة في نهاية اللي هو
+
+115
+00:09:38,850 --> 00:09:44,050
+المسار الان عندي أنا مسار منحدر هي كهيوم وقالسي
+
+116
+00:09:44,050 --> 00:09:50,930
+فلجي ومسار طبعا خط سريع وفلجي معناته frictionless
+
+117
+00:09:50,930 --> 00:09:55,950
+السيارة نازلة على هدأ المنحدرطبعا سير نزل على هذا
+
+118
+00:09:55,950 --> 00:10:00,150
+المنحدر في البداية مطلوب منه أن نجد في ايه؟ مطلوب
+
+119
+00:10:00,150 --> 00:10:03,490
+منه أن نجد ال acceleration of the car بدي ال
+
+120
+00:10:03,490 --> 00:10:07,110
+acceleration ل ال car اذا انا بدي ارسم اول حاجة ال
+
+121
+00:10:07,110 --> 00:10:12,850
+free body diagramكما هو مضح بالشكل فى عندى اللى
+
+122
+00:10:12,850 --> 00:10:16,530
+عندى اللى هى قوة الجغرية او الـ Mg الـ Mg غير يوم
+
+123
+00:10:16,530 --> 00:10:21,050
+الـ Mg بساوي الـ N في G وفى عندى الـ Normal عمودية
+
+124
+00:10:21,050 --> 00:10:25,910
+على السطح ده هو السطح المارين و الـ N عمودية على
+
+125
+00:10:25,910 --> 00:10:31,890
+السطح المارين بدأ أحلل الـ Mg إلى Mg صينة فيتا على
+
+126
+00:10:31,890 --> 00:10:36,310
+نفس المستوى و Mg كوزاينة فيتا عمودي على المستوى
+
+127
+00:10:37,080 --> 00:10:41,340
+طبعا مافي frictionless معناته مش هاخد احتكاك في
+
+128
+00:10:41,340 --> 00:10:45,700
+هذا الاتجاه اذا هو الذسن نازل على أسفل المنحضر
+
+129
+00:10:45,700 --> 00:10:49,560
+فالقوة اللي هادة باعتبر هادة كإن ال X-axis و
+
+130
+00:10:49,560 --> 00:10:53,920
+باعتبر هادة كإن ال Y-axis لما بدأ اويد ال
+
+131
+00:10:53,920 --> 00:10:56,940
+acceleration to find the acceleration of the car
+
+132
+00:10:56,940 --> 00:11:02,520
+بدأ استخدم قانون لوتن التاني summation لل F يتساوي
+
+133
+00:11:02,520 --> 00:11:05,940
+ال 1000 في A طبعا عندي انا ال FG
+
+134
+00:11:18,980 --> 00:11:23,030
+بالنسبة للأفعال الموجودة في البرنامجهو عبارة عن
+
+135
+00:11:23,030 --> 00:11:28,430
+Normal ماخص Mg Cos θ بساوي Zero لأن هناك حركة
+
+136
+00:11:28,430 --> 00:11:32,470
+باتجاه الـ Y-Axis وحركة التسارع باتجاه الـ X-Axis
+
+137
+00:11:38,950 --> 00:11:43,990
+Dividing المعادلة واحد by M المعادلة واحد بدي
+
+138
+00:11:43,990 --> 00:11:48,410
+اقسمها على M او بدي اشيل M من الطرفين تطلع ال A X
+
+139
+00:11:48,410 --> 00:11:51,990
+بالساعة G Sine of Theta اذا ان ال A بتجاه X
+
+140
+00:11:51,990 --> 00:11:54,590
+بالساعة G Sine of Theta و G تسعة و تمانية من عشرة
+
+141
+00:11:54,590 --> 00:11:59,090
+Sine العشرين تطلع اندي A تلاتة بور تلاتة خمسة هدوي
+
+142
+00:11:59,090 --> 00:12:01,710
+عبارة عن التسعة رقم اللي بتمشي فيها السيارة على
+
+143
+00:12:01,710 --> 00:12:08,580
+المنحدر المنحدر انا اعتبرته كأنه محور Xفي B يجب أن
+
+144
+00:12:08,580 --> 00:12:13,220
+تجد الوقت اللذي يتأخده لتحقيق الـ Cartridge بمدّ
+
+145
+00:12:13,220 --> 00:12:22,280
+الزمن اللازم لكي تصل السيارة إلى أسفل المنحضر طبعا
+
+146
+00:12:22,280 --> 00:12:26,740
+اني بدأت من الريست V mod X متساوي Zero عندي أنا
+
+147
+00:12:26,740 --> 00:12:30,820
+القرن بلتا X متساوي V mod T زي نص A T تربيع وB mod
+
+148
+00:12:30,820 --> 00:12:35,710
+بزير وذلك عندي نص A X T تربيعنص الـ ETA اللي عمرها
+
+149
+00:12:35,710 --> 00:12:40,770
+3.35 والزمن اللي هو T تربيه ماعنديش، في عندي أنا
+
+150
+00:12:40,770 --> 00:12:44,770
+اللي هي Delta X حكاية لإن طول المنحبر كان السيارة
+
+151
+00:12:44,770 --> 00:12:51,230
+ماشية بمسافة 25 متر وطالب منها الزمن اللازم علشان
+
+152
+00:12:51,230 --> 00:12:55,090
+السيارة تصل إلى نهاية المنحبر اللي هو نهاته طوله
+
+153
+00:12:55,090 --> 00:12:59,730
+كان بيمشي مسافة 25 متر، بطلع الزمن بالساعة 3.86
+
+154
+00:12:59,730 --> 00:13:04,710
+Secondفي C Find the speed of the car at the bottom
+
+155
+00:13:04,710 --> 00:13:10,130
+of the driveway بدّه سرعة السيارة في نهاية المسار
+
+156
+00:13:10,130 --> 00:13:17,590
+أو في نهاية المحضر فبستخدم إن VX بيبقى تساوي V not
+
+157
+00:13:17,590 --> 00:13:21,510
+X زائد A T V not كانت Zero هي V not X بالساوية
+
+158
+00:13:21,510 --> 00:13:26,790
+Zero بيبقى عنا A X في Tتلاتة بين تلاتة خمسة و T
+
+159
+00:13:26,790 --> 00:13:30,450
+تلاتة بين تمانية ستة طلعناه، بطلع عنده السرعه
+
+160
+00:13:30,450 --> 00:13:34,610
+النهائيه بتساوي اتناش بين تسعة متر فيه اتانى، اذا
+
+161
+00:13:34,610 --> 00:13:39,150
+السؤال السابق كان عند سيارات تتحرك على منحضر،
+
+162
+00:13:39,150 --> 00:13:43,610
+تتحرك على منحضر بدأت من السكون و وصلت لاخر منحضر،
+
+163
+00:13:43,610 --> 00:13:47,370
+منحضر كان طوله خمسة و عشرينبتدأ تباركة المنحضر هو
+
+164
+00:13:47,370 --> 00:13:52,710
+الـ x-axis هروح نحلل للـ mg الـ mg sin θ باتجاه
+
+165
+00:13:52,710 --> 00:13:57,330
+المنحضر و الـ mg cos عمضية عليه و تطبخت خانة نيوتر
+
+166
+00:13:57,330 --> 00:14:01,010
+التاني على سماشية للـfx و سماشية للـfi و أوجدت
+
+167
+00:14:01,010 --> 00:14:06,190
+التسارع و أوجدت السرعه النهائية في آخر المنحضر
+
+168
+00:14:07,630 --> 00:14:12,170
+بالظبط مثلًا، Problems. في عندى woman وقت الـ
+
+169
+00:14:12,170 --> 00:14:18,490
+«مسعد»
+
+170
+00:14:18,490 --> 00:14:25,750
+تقف في إمرأة نلقا بدها توزان اللي هو سمكة معلقة في
+
+171
+00:14:25,750 --> 00:14:31,990
+Spring Scaling تدريج في سقف اللي هو المسعد.
+
+172
+00:14:35,010 --> 00:14:42,150
+واللي المصعد ساكن كانت مقارنة بقيمته 40 ميوتيم
+
+173
+00:14:42,150 --> 00:14:46,230
+والان مقصود مني ماهي عملية عملية عملية عملية عملية
+
+174
+00:14:46,230 --> 00:14:46,670
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+175
+00:14:46,670 --> 00:14:48,550
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+176
+00:14:48,550 --> 00:14:49,070
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+177
+00:14:49,070 --> 00:14:49,110
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+178
+00:14:49,110 --> 00:14:50,570
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+179
+00:14:50,570 --> 00:14:51,750
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+180
+00:14:51,750 --> 00:14:59,330
+عملية
+
+181
+00:14:59,330 --> 00:15:05,630
+عالشد خلال طبعا الـ silk المعلقة في هذه السمكة
+
+182
+00:15:05,630 --> 00:15:11,950
+طبعا هاي هذا الشكل المضح في عندى هنا شكلا عندى انا
+
+183
+00:15:11,950 --> 00:15:17,350
+قبل ألا توزن سمكة هذا تدريج طبعا مربوط فيه spring
+
+184
+00:15:17,350 --> 00:15:21,280
+او scale divingبتبقى اعراف اللي بيواجه الـ Scale
+
+185
+00:15:21,280 --> 00:15:25,220
+Building يعني بيبقى زي الشبق على السمكة لما المصعد
+
+186
+00:15:25,220 --> 00:15:28,840
+يكون طالع أو لما المصعد يكون مازل طبعا لما المصعد
+
+187
+00:15:28,840 --> 00:15:32,180
+يكون طالع بيعطينا دي اشارة ان الحركة في اتجاه
+
+188
+00:15:32,180 --> 00:15:37,660
+الأعلىهنا بيحكي إن وين الـ elevator accelerate
+
+189
+00:15:37,660 --> 00:15:41,220
+أبواب، الـ spring scale rates evaluated better
+
+190
+00:15:41,220 --> 00:15:44,540
+than the weight of the fish، الـ spring scale
+
+191
+00:15:44,540 --> 00:15:47,220
+rates هي عبارة عن الـ tension، اللي هو ماسك أو
+
+192
+00:15:47,220 --> 00:15:53,380
+اللي هو مربوط فيه هأس سمكةهنا لما ويل الـ elevator
+
+193
+00:15:53,380 --> 00:15:58,340
+accelerate downward لما نصعد بنزل الى أسفل بس
+
+194
+00:15:58,340 --> 00:16:02,180
+bring scale reads value less than the load of the
+
+195
+00:16:02,180 --> 00:16:06,120
+fish بدنا نشوف هذا الكلام الآن السؤال المطلوب في
+
+196
+00:16:06,120 --> 00:16:10,240
+هذا السؤال مطلوب من هنا نجد أول حاجة what does the
+
+197
+00:16:10,240 --> 00:16:13,360
+scale read if the elevator accelerate؟ بيحكي انه
+
+198
+00:16:13,360 --> 00:16:18,070
+بده ال scale read يعني بده الشدلما المصعد يتحرك
+
+199
+00:16:18,070 --> 00:16:22,310
+بسرعه اتنين متر في الثاني الى اعلى و بده ايضا what
+
+200
+00:16:22,310 --> 00:16:24,990
+does the scale mean if the elevator accelerate
+
+201
+00:16:24,990 --> 00:16:29,650
+downward اذا كان نزلت بسرعه اتنين متر في الثاني
+
+202
+00:16:29,650 --> 00:16:34,890
+تربيعوكمان if the elevator cable breaks اذا قطع
+
+203
+00:16:34,890 --> 00:16:38,390
+سينك اللي هو اللي صعد what does the scale mean
+
+204
+00:16:38,390 --> 00:16:44,630
+ناخد واحدة واحدة بمثل لا الحل هنحل احنا هنرسم ال
+
+205
+00:16:44,630 --> 00:16:48,030
+free body diagram find the scale reading as the
+
+206
+00:16:48,030 --> 00:16:51,670
+elevator accelerates upward طبعا بأطبق عن نيوتن
+
+207
+00:16:51,670 --> 00:16:55,330
+التاني taking upward as the positive direction بدي
+
+208
+00:16:55,330 --> 00:16:58,990
+أخد اللي أعلى نوجة واللي أسفل سالد اللي أعلى كان
+
+209
+00:16:58,990 --> 00:17:04,210
+عندتي معقص ال Mgبتساوي الـ M في A إذا T بيبقى
+
+210
+00:17:04,210 --> 00:17:09,630
+تساوي MA زائد MG معنى الكلام T بيبقى تساوي MA زائد
+
+211
+00:17:09,630 --> 00:17:14,470
+G MA زائد G إذا الشد هو أكبر من الوزن في هذه
+
+212
+00:17:14,470 --> 00:17:20,320
+الحالة بعد ذلك find the mass of the fishكتلة
+
+213
+00:17:20,320 --> 00:17:23,180
+السمكة من خلال الوزن اللي أعطانا إياها في حالة ما
+
+214
+00:17:23,180 --> 00:17:27,920
+كان ال elevator ما بتتحركش، إذا ال M بتساوي الوزن
+
+215
+00:17:27,920 --> 00:17:31,840
+على ال G لإن الوزن بتساوي ال MG، الوزن كان 40
+
+216
+00:17:31,840 --> 00:17:35,760
+ميوتين على ال G 9.8 متر في ثانوية أربعية، بدها
+
+217
+00:17:35,760 --> 00:17:41,130
+تساوي 4.08 كيلو جرامالان بدأ أحسب اللي هو الشد من
+
+218
+00:17:41,130 --> 00:17:43,870
+خلال المعادلة السابقة على أساس إن الـA كانت
+
+219
+00:17:43,870 --> 00:17:47,210
+positive، طبعا الأعلى كانت الـA positive، باعود
+
+220
+00:17:47,210 --> 00:17:51,130
+عنها بـA موجة، إذن، بدأ أعود عن هذا الخانون T
+
+221
+00:17:51,130 --> 00:17:56,870
+بالساوية الـM، A زائد G، اللي هي الـM كانت أربعة
+
+222
+00:17:56,870 --> 00:18:01,190
+بُط و تمانية، و الـA كانت اتنين مُقطة مُجبة، و
+
+223
+00:18:01,190 --> 00:18:03,930
+الـG تسعة و تمانية من عشرة، بطلع معاية T تمانية و
+
+224
+00:18:03,930 --> 00:18:07,660
+أربعين بُط واحد المُطينالان بقى بدي استخدم نفس
+
+225
+00:18:07,660 --> 00:18:11,260
+الخوانين ولكن ال elevator إلى أسفل، لما يكون ال
+
+226
+00:18:11,260 --> 00:18:15,160
+elevator إلى أسفل فالإيه تعتبر سالب، لإن احنا
+
+227
+00:18:15,160 --> 00:18:19,420
+نشتغل حسب المحاور، المتجر الأعلى بيكون موجب،
+
+228
+00:18:19,420 --> 00:18:23,600
+والأسفل سالب، وعلى يمين موجب وعلى شمال سالبالان ال
+
+229
+00:18:23,600 --> 00:18:27,160
+analysis is the same بيقوم with change being
+
+230
+00:18:27,160 --> 00:18:34,780
+acceleration which is now negative اذا T بتساوي MA
+
+231
+00:18:34,780 --> 00:18:41,080
+زائد G لكن ال M نفسها ال A سالب اتنينمتر في
+
+232
+00:18:41,080 --> 00:18:43,400
+الثانوية وترابية والجي دسعة وتونية وعشرة بيطلع عند
+
+233
+00:18:43,400 --> 00:18:46,120
+الـ T بساعة واحدة وتلاتين point تمام معنى الكلام
+
+234
+00:18:46,120 --> 00:18:51,000
+ان الشد او ال scale reading ال scale reading او ال
+
+235
+00:18:51,000 --> 00:18:54,700
+spring reading لما يكون ال elevator ساعد يكون الشد
+
+236
+00:18:54,700 --> 00:19:00,120
+اعلى greater than the weight لما يكون نازل يكون
+
+237
+00:19:00,120 --> 00:19:05,840
+نسبة با weightفي الحالة c مطلب مني find the scale
+
+238
+00:19:05,840 --> 00:19:10,660
+reading after the elevator cable breaks مطلب ال
+
+239
+00:19:10,660 --> 00:19:15,580
+scale reading عندما ينقطع الحبل عندما ينقطع الحبل
+
+240
+00:19:15,580 --> 00:19:20,440
+معناه تبتي بالساوية 0 معناها ال a عند ناقب ال c
+
+241
+00:19:20,440 --> 00:19:25,200
+بيصير ان الجسم نزل بتسرع جاذبية فال a بتساوي ناقص
+
+242
+00:19:25,200 --> 00:19:28,560
+تسعة و تمانية عشرة ال acceleration هذا ايه لسبب
+
+243
+00:19:28,560 --> 00:19:35,030
+الجاذبيةم في ا زائد جي فالان لو عوضت عن هذا
+
+244
+00:19:35,030 --> 00:19:38,730
+القانون الان اربعة اللي طلعناها سابقا و ال a
+
+245
+00:19:38,730 --> 00:19:42,410
+اسكسرت هو نزل بتسارع جاذبية تسعة أبعد تمانية زائد
+
+246
+00:19:42,410 --> 00:19:45,570
+تسعة أبعد تمانية بيطلع عند الشت بيساوي زيرو بكل
+
+247
+00:19:45,570 --> 00:19:50,590
+الأحوال اي سؤال موجود عند ان الخيطان خاطع معناته
+
+248
+00:19:50,590 --> 00:19:52,790
+الشت بيساوي زيرو
+
+249
+00:20:04,890 --> 00:20:09,530
+problems طبعا مثلا بالاربع بند واحد اتنين بيحكي ان
+
+250
+00:20:09,530 --> 00:20:15,470
+ال hockey puck in figures by a hockey stick is
+
+251
+00:20:15,470 --> 00:20:18,490
+given an initial speed of عشرين متر في الثانية on
+
+252
+00:20:18,490 --> 00:20:23,050
+a frozen pond, the puck remained on the iceالـ bug
+
+253
+00:20:23,050 --> 00:20:27,570
+remained on the ice and slides 1.2X10.2 meters
+
+254
+00:20:27,570 --> 00:20:32,870
+slowing down steadily until it comes to rest to
+
+255
+00:20:32,870 --> 00:20:34,670
+determine the coefficient of kinetic friction
+
+256
+00:20:34,670 --> 00:20:36,130
+between the bug and the ice
+
+257
+00:20:39,120 --> 00:20:44,960
+العجلة اللى بتستخدم على الجليد و هذه العجلة ممكن
+
+258
+00:20:44,960 --> 00:20:49,520
+تضرب في عصر معينة و بتمشي مسافة معينة على الجليد
+
+259
+00:20:49,520 --> 00:20:55,000
+طبعا عندى انا اللى هى العجلة او لإن الجسم طبعا أنا
+
+260
+00:20:55,000 --> 00:21:00,580
+قدفته بعصر معينة على الجليد هذه هى ال motion حركته
+
+261
+00:21:00,580 --> 00:21:06,740
+أو جسم جمعته بحركة معينة في الدقابل اتجاه طبعا فى
+
+262
+00:21:06,740 --> 00:21:09,300
+عندى قوة احتكاكعن طريق البرامج الاخرى وهي الـ FK
+
+263
+00:21:09,300 --> 00:21:12,220
+لما ارسم أنا الـ Free Body Diagram لهذا الـ Z سمح
+
+264
+00:21:12,220 --> 00:21:16,580
+يكون عندي Normal إلى أعلى و MG إلى أسفل مطلب من ال
+
+265
+00:21:16,580 --> 00:21:18,600
+coefficient of kinetic friction
+
+266
+00:21:22,450 --> 00:21:24,830
+سنحل الانتقال الانتقال الانتقال الانتقال الانتقال
+
+267
+00:21:24,830 --> 00:21:26,090
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+268
+00:21:26,090 --> 00:21:28,750
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+269
+00:21:28,750 --> 00:21:30,230
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+270
+00:21:30,230 --> 00:21:31,950
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+271
+00:21:31,950 --> 00:21:31,990
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+272
+00:21:31,990 --> 00:21:34,970
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+273
+00:21:34,970 --> 00:21:37,910
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+274
+00:21:37,910 --> 00:21:44,110
+الانتقال الانتقال الانتقال الانتقال
+
+275
+00:21:50,780 --> 00:21:54,980
+هذه المعطيات اللي عندي Vنهاية Zero Vبتدائية كانت
+
+276
+00:21:54,980 --> 00:21:59,320
+عشرين متر في الثانية Delta X وواحد واثنين في عشر
+
+277
+00:21:59,320 --> 00:22:04,420
+أقصى اتنين مترNot that the negative sign in answer
+
+278
+00:22:04,420 --> 00:22:09,440
+A is opposite V طبعا لما أوجد أنا التسارع هو هيطلع
+
+279
+00:22:09,440 --> 00:22:14,560
+عنده ساند لإنه هو بدأ بسرعة وانتهى لاقى الـ0 يعني
+
+280
+00:22:14,560 --> 00:22:20,010
+بتباطأ الجسيم لغاية ما وصل للـ0، إذن A لسه Zeroفي
+
+281
+00:22:20,010 --> 00:22:26,030
+V0 20 تربيه على 2 Delta X 1.2 X 10 عقل 2 متر بيطلع
+
+282
+00:22:26,030 --> 00:22:31,290
+ان بيناقص 1.67 متر في second تربيه معناته التسارع
+
+283
+00:22:31,290 --> 00:22:37,190
+تبعه هو بالقلم حتى يصل إلى الادية النهائية Zero
+
+284
+00:22:37,190 --> 00:22:40,910
+يعني بتبطعطالب الـ Normal force find the normal
+
+285
+00:22:40,910 --> 00:22:45,790
+force by from the a y component بدي ال normal
+
+286
+00:22:45,790 --> 00:22:50,390
+force قوم ترد الفعل راح اطبق قانون ميوتن على اتجاه
+
+287
+00:22:50,390 --> 00:22:55,330
+ال y ال normal ناقص اللي هو ال FG بتساوي ال N ناقص
+
+288
+00:22:55,330 --> 00:22:59,190
+MG بساوي 0 لإن مافي حركة باتجاه ال Y اذا ال normal
+
+289
+00:22:59,190 --> 00:23:06,710
+بتساوي ال MG في هذه الحالةعشان اوجد الـ
+
+290
+00:23:06,710 --> 00:23:11,030
+coefficient of chemical friction الـ FK بتساوي Mu
+
+291
+00:23:11,030 --> 00:23:15,690
+K في الـ Normal الـ FK بتساوي Mu K في الـ Normal
+
+292
+00:23:15,690 --> 00:23:22,790
+بتساوي Mu K في M G إذا ناقص FK بتساوي ناقص Mu K في
+
+293
+00:23:22,790 --> 00:23:29,840
+M G طبعا في هذه الحالة بدي أرسم أنا العادلةأكتب
+
+294
+00:23:29,840 --> 00:23:33,520
+هذه المعادلة لو بنتجرها الـ X axis في هذه الحالة
+
+295
+00:23:33,520 --> 00:23:39,360
+الـ Mu K يعني ال FK هي اللي بتساوي N في A و FK
+
+296
+00:23:39,360 --> 00:23:43,520
+بتساوي ناقص Mu K في NG بتساوي ال N في A ال N بتروح
+
+297
+00:23:43,520 --> 00:23:46,860
+من اللي مع ال M بيبقى لعندي Mu K بتساوي ناقص A على
+
+298
+00:23:46,860 --> 00:23:47,200
+G
+
+299
+00:24:02,410 --> 00:24:04,930
+بنستكمل ان شاء الله في التزيين القادم
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..0ad97cc575d41b9e7e8b51cfeb22d6d78baca320
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_raw.json
@@ -0,0 +1 @@
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280.25, "end": 280.65, "word": " الحالة", "probability": 0.962890625}, {"start": 280.65, "end": 280.79, "word": " ال", "probability": 0.7607421875}, {"start": 280.79, "end": 281.09, "word": " normal", "probability": 0.292724609375}, {"start": 281.09, "end": 281.61, "word": " عبارة", "probability": 0.819580078125}, {"start": 281.61, "end": 281.79, "word": " عن", "probability": 0.99169921875}, {"start": 281.79, "end": 282.33, "word": " اقل", "probability": 0.8016764322916666}, {"start": 282.33, "end": 283.57, "word": " قيمته", "probability": 0.9788411458333334}, {"start": 283.57, "end": 283.95, "word": " اقل", "probability": 0.9235026041666666}, {"start": 283.95, "end": 284.25, "word": " less", "probability": 0.07342529296875}, {"start": 284.25, "end": 284.59, "word": " than", "probability": 0.94677734375}, {"start": 284.59, "end": 284.77, "word": " the", "probability": 0.62109375}, {"start": 284.77, "end": 285.31, "word": " total", "probability": 0.84619140625}, {"start": 285.31, "end": 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0.986083984375}], "temperature": 1.0}, {"id": 14, "seek": 32416, "start": 309.68, "end": 324.16, "text": "الجسم للأسام المتسارعة باستخدام قانون الموتون التاني when a net force acts on an object لو كان عنده مجموعة من القوة مؤثرة على أي جسم والجسم يحدث له تسارع", "tokens": [6027, 7435, 38251, 24976, 10721, 3794, 10943, 9673, 2655, 3794, 9640, 27884, 4724, 995, 14851, 9778, 3215, 10943, 12174, 7649, 11536, 9673, 35473, 11536, 16712, 7649, 1829, 562, 257, 2533, 3464, 10672, 322, 364, 2657, 45164, 25961, 43242, 3224, 3714, 7435, 2304, 2407, 27884, 9154, 25062, 2407, 3660, 3714, 33604, 49115, 3660, 15844, 36632, 10874, 38251, 4032, 6027, 7435, 38251, 7251, 24401, 12984, 46740, 6055, 3794, 9640, 3615], "avg_logprob": -0.2703804209612418, "compression_ratio": 1.5212121212121212, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 309.68, "end": 310.68, "word": "الجسم", "probability": 0.6438395182291666}, {"start": 310.68, "end": 311.28, "word": " للأسام", "probability": 0.708251953125}, {"start": 311.28, "end": 312.14, "word": " المتسارعة", "probability": 0.88759765625}, {"start": 312.14, "end": 312.8, "word": " باستخدام", "probability": 0.8640950520833334}, {"start": 312.8, "end": 313.5, "word": " قانون", "probability": 0.82373046875}, {"start": 313.5, "end": 313.86, "word": " الموتون", "probability": 0.5819498697916666}, {"start": 313.86, "end": 314.92, "word": " التاني", "probability": 0.85888671875}, {"start": 314.92, "end": 315.42, "word": " when", "probability": 0.1195068359375}, {"start": 315.42, "end": 315.64, "word": " a", "probability": 0.83544921875}, {"start": 315.64, "end": 315.8, "word": " net", "probability": 0.58984375}, {"start": 315.8, "end": 316.4, "word": " force", "probability": 0.95166015625}, {"start": 316.4, "end": 316.9, "word": " acts", "probability": 0.91845703125}, {"start": 316.9, "end": 317.1, "word": " on", "probability": 0.955078125}, {"start": 317.1, "end": 317.32, "word": " an", "probability": 0.91943359375}, {"start": 317.32, "end": 317.82, "word": " object", "probability": 0.97900390625}, {"start": 317.82, "end": 318.02, "word": " لو", "probability": 0.72607421875}, {"start": 318.02, "end": 318.22, "word": " كان", "probability": 0.97509765625}, {"start": 318.22, "end": 318.5, "word": " عنده", "probability": 0.552734375}, {"start": 318.5, "end": 318.98, "word": " مجموعة", "probability": 0.974609375}, {"start": 318.98, "end": 319.2, "word": " من", "probability": 0.97802734375}, {"start": 319.2, "end": 319.66, "word": " القوة", "probability": 0.9529622395833334}, {"start": 319.66, "end": 320.2, "word": " مؤثرة", "probability": 0.7122802734375}, {"start": 320.2, "end": 320.4, "word": " على", "probability": 0.90869140625}, {"start": 320.4, "end": 320.66, "word": " أي", "probability": 0.72607421875}, {"start": 320.66, "end": 321.18, "word": " جسم", "probability": 0.968994140625}, {"start": 321.18, "end": 322.34, "word": " والجسم", "probability": 0.64447021484375}, {"start": 322.34, "end": 323.2, "word": " يحدث", "probability": 0.97705078125}, {"start": 323.2, "end": 323.42, "word": " له", "probability": 0.94482421875}, {"start": 323.42, "end": 324.16, "word": " تسارع", "probability": 0.982177734375}], "temperature": 1.0}, {"id": 15, "seek": 34789, "start": 324.57, "end": 347.89, "text": "and we use the Newton's second law to analyze the motion باستخدام قانون ال Newton التاني لتحليل اللي هي الحركة في عندنا أنا خزانة الخزانة هذه موجودة على العربة طبعا بدا نزل انا الان نزل الخزانة زي العربة هي ال FG اللي هي ال MG للعربة زي اللي هي العربة تحته هي الخزانة", "tokens": [474, 321, 764, 264, 19541, 311, 1150, 2101, 281, 12477, 264, 5394, 4724, 995, 14851, 9778, 3215, 10943, 12174, 7649, 11536, 2423, 19541, 16712, 7649, 1829, 5296, 2655, 5016, 20292, 1211, 13672, 1829, 39896, 21542, 31747, 3660, 8978, 43242, 8315, 41850, 16490, 11622, 7649, 3660, 33962, 11622, 7649, 3660, 29538, 3714, 29245, 23328, 3660, 15844, 18863, 25513, 3660, 23032, 3555, 3615, 995, 4724, 28259, 8717, 11622, 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327.25, "end": 327.57, "word": " to", "probability": 0.947265625}, {"start": 327.57, "end": 328.25, "word": " analyze", "probability": 0.6259765625}, {"start": 328.25, "end": 328.53, "word": " the", "probability": 0.80078125}, {"start": 328.53, "end": 328.93, "word": " motion", "probability": 0.83203125}, {"start": 328.93, "end": 329.65, "word": " باستخدام", "probability": 0.7799479166666666}, {"start": 329.65, "end": 330.13, "word": " قانون", "probability": 0.89453125}, {"start": 330.13, "end": 330.31, "word": " ال", "probability": 0.60888671875}, {"start": 330.31, "end": 330.59, "word": " Newton", "probability": 0.53564453125}, {"start": 330.59, "end": 331.19, "word": " التاني", "probability": 0.9127604166666666}, {"start": 331.19, "end": 331.95, "word": " لتحليل", "probability": 0.8931640625}, {"start": 331.95, "end": 332.15, "word": " اللي", "probability": 0.662109375}, {"start": 332.15, "end": 332.31, "word": " هي", "probability": 0.8515625}, {"start": 332.31, "end": 333.03, "word": " الحركة", "probability": 0.9842122395833334}, {"start": 333.03, "end": 333.59, "word": " في", "probability": 0.57763671875}, {"start": 333.59, "end": 334.09, "word": " عندنا", "probability": 0.876220703125}, {"start": 334.09, "end": 334.41, "word": " أنا", "probability": 0.462158203125}, {"start": 334.41, "end": 335.85, "word": " خزانة", "probability": 0.972900390625}, {"start": 335.85, "end": 337.15, "word": " الخزانة", "probability": 0.8717041015625}, {"start": 337.15, "end": 337.55, "word": " هذه", "probability": 0.269775390625}, {"start": 337.55, "end": 338.13, "word": " موجودة", "probability": 0.8162841796875}, {"start": 338.13, "end": 338.27, "word": " على", "probability": 0.90771484375}, {"start": 338.27, "end": 338.81, "word": " العربة", "probability": 0.96533203125}, {"start": 338.81, "end": 339.63, "word": " طبعا", "probability": 0.9661865234375}, {"start": 339.63, "end": 340.37, "word": " بدا", "probability": 0.3974609375}, {"start": 340.37, "end": 340.75, "word": " نزل", "probability": 0.92333984375}, {"start": 340.75, "end": 340.97, "word": " انا", "probability": 0.661865234375}, {"start": 340.97, "end": 341.29, "word": " الان", "probability": 0.51708984375}, {"start": 341.29, "end": 341.75, "word": " نزل", "probability": 0.9029947916666666}, {"start": 341.75, "end": 342.37, "word": " الخزانة", "probability": 0.9736328125}, {"start": 342.37, "end": 342.49, "word": " زي", "probability": 0.4908447265625}, {"start": 342.49, "end": 342.99, "word": " العربة", "probability": 0.9156901041666666}, {"start": 342.99, "end": 343.15, "word": " هي", "probability": 0.71484375}, {"start": 343.15, "end": 343.29, "word": " ال", "probability": 0.65087890625}, {"start": 343.29, "end": 343.85, "word": " FG", "probability": 0.719970703125}, {"start": 343.85, "end": 344.55, "word": " اللي", "probability": 0.900634765625}, {"start": 344.55, "end": 344.73, "word": " هي", "probability": 0.76318359375}, {"start": 344.73, "end": 344.87, "word": " ال", "probability": 0.69873046875}, {"start": 344.87, "end": 345.19, "word": " MG", "probability": 0.6376953125}, {"start": 345.19, "end": 345.83, "word": " للعربة", "probability": 0.864501953125}, {"start": 345.83, "end": 346.07, "word": " زي", "probability": 0.81103515625}, {"start": 346.07, "end": 346.27, "word": " اللي", "probability": 0.8603515625}, {"start": 346.27, "end": 346.45, "word": " هي", "probability": 0.75}, {"start": 346.45, "end": 346.89, "word": " العربة", "probability": 0.98486328125}, {"start": 346.89, "end": 347.21, "word": " تحته", "probability": 0.7827962239583334}, {"start": 347.21, "end": 347.31, "word": " هي", "probability": 0.4169921875}, {"start": 347.31, "end": 347.89, "word": " الخزانة", "probability": 0.994873046875}], "temperature": 1.0}, {"id": 16, "seek": 35876, "start": 348.7, "end": 358.76, "text": "هنا في عندى قوات شد مربوطة بخيط وبشدها، في عندى قوات red فيها الأرض على الخزانة زائد اللى هو العربا", "tokens": [3224, 8315, 8978, 43242, 7578, 12174, 2407, 9307, 13412, 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"probability": 0.76865234375}, {"start": 352.76, "end": 353.0, "word": " في", "probability": 0.60986328125}, {"start": 353.0, "end": 353.28, "word": " عندى", "probability": 0.919921875}, {"start": 353.28, "end": 353.56, "word": " قوات", "probability": 0.9755859375}, {"start": 353.56, "end": 353.76, "word": " red", "probability": 0.39453125}, {"start": 353.76, "end": 354.18, "word": " فيها", "probability": 0.846435546875}, {"start": 354.18, "end": 355.4, "word": " الأرض", "probability": 0.679443359375}, {"start": 355.4, "end": 355.76, "word": " على", "probability": 0.65625}, {"start": 355.76, "end": 357.2, "word": " الخزانة", "probability": 0.9022216796875}, {"start": 357.2, "end": 357.68, "word": " زائد", "probability": 0.8172200520833334}, {"start": 357.68, "end": 357.86, "word": " اللى", "probability": 0.64306640625}, {"start": 357.86, "end": 358.14, "word": " هو", "probability": 0.7314453125}, {"start": 358.14, "end": 358.76, "word": " العربا", "probability": 0.7408854166666666}], "temperature": 1.0}, {"id": 17, "seek": 38972, "start": 360.26, "end": 389.72, "text": "الـ example اللي عندنا اللي هو زي ما هو مرسوم بالشكل الأعلى the combined weight of the crate and bullion بلد و عربة زي ما حكيناه كان هو موضح من هذا الشكل تلاتة نوتين if the man pull on the rope with constant force طبعا الراجل هذا بشد الخزانة بقوة مقدارها عشرين نوتين what is", "tokens": [6027, 39184, 1365, 13672, 1829, 43242, 8315, 13672, 1829, 31439, 30767, 1829, 19446, 31439, 3714, 2288, 3794, 20498, 20666, 8592, 28820, 16247, 3615, 23942, 264, 9354, 3364, 295, 264, 42426, 293, 4693, 313, 4724, 1211, 3215, 4032, 6225, 25513, 3660, 30767, 1829, 19446, 11331, 4117, 1829, 8315, 3224, 25961, 31439, 3714, 2407, 11242, 5016, 9154, 23758, 25124, 28820, 6055, 1211, 9307, 3660, 8717, 35473, 9957, 498, 264, 587, 2235, 322, 264, 13540, 365, 5754, 3464, 23032, 3555, 3615, 995, 34892, 26108, 1211, 23758, 4724, 8592, 3215, 33962, 11622, 7649, 3660, 4724, 4587, 2407, 3660, 3714, 28543, 9640, 11296, 6225, 46309, 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363.78, "word": " بالشكل", "probability": 0.9806315104166666}, {"start": 363.78, "end": 364.98, "word": " الأعلى", "probability": 0.9275716145833334}, {"start": 364.98, "end": 365.3, "word": " the", "probability": 0.125244140625}, {"start": 365.3, "end": 365.86, "word": " combined", "probability": 0.9130859375}, {"start": 365.86, "end": 366.24, "word": " weight", "probability": 0.93017578125}, {"start": 366.24, "end": 366.44, "word": " of", "probability": 0.96337890625}, {"start": 366.44, "end": 366.62, "word": " the", "probability": 0.8408203125}, {"start": 366.62, "end": 366.92, "word": " crate", "probability": 0.1650390625}, {"start": 366.92, "end": 367.24, "word": " and", "probability": 0.9287109375}, {"start": 367.24, "end": 367.62, "word": " bullion", "probability": 0.3790283203125}, {"start": 367.62, "end": 368.16, "word": " بلد", "probability": 0.7068684895833334}, {"start": 368.16, "end": 368.54, "word": " و", "probability": 0.8291015625}, {"start": 368.54, "end": 368.9, 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"seek": 53117, "start": 515.88, "end": 531.18, "text": "الان example أربع عشرة ال problem عبارة عن a car of mass M سيارة كتلتها M is on an icy driveway inclined at an angle فتة بالساعة عشرين سيارة", "tokens": [6027, 7649, 1365, 5551, 25513, 3615, 6225, 8592, 25720, 2423, 1154, 6225, 3555, 9640, 3660, 18871, 257, 1032, 295, 2758, 376, 8608, 1829, 9640, 3660, 9122, 2655, 1211, 2655, 11296, 376, 307, 322, 364, 42015, 38276, 28173, 412, 364, 5802, 6156, 2655, 3660, 20666, 3794, 995, 27884, 6225, 46309, 9957, 8608, 1829, 9640, 3660], "avg_logprob": -0.33409092209555885, "compression_ratio": 1.271523178807947, "no_speech_prob": 0.0, "words": [{"start": 515.88, "end": 516.72, "word": "الان", "probability": 0.759521484375}, {"start": 516.72, "end": 517.3, "word": " example", "probability": 0.308349609375}, {"start": 517.3, "end": 517.76, "word": " أربع", "probability": 0.7378743489583334}, {"start": 517.76, "end": 518.26, "word": " عشرة", "probability": 0.8194986979166666}, {"start": 518.26, 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car بدي ال acceleration ل ال car اذا انا بدي ارسم اول حاجة ال free body diagram", "tokens": [9566, 3555, 3615, 995, 8608, 13546, 8717, 11622, 1211, 15844, 23758, 9673, 1863, 24401, 2288, 8978, 29739, 28259, 10632, 3714, 9566, 1211, 37746, 9154, 3224, 14739, 8717, 7435, 3215, 8978, 1975, 1829, 3224, 22807, 3714, 9566, 1211, 37746, 9154, 3224, 14739, 8717, 7435, 3215, 2423, 17162, 295, 264, 1032, 4724, 16254, 2423, 17162, 5296, 2423, 1032, 1975, 15730, 1975, 8315, 4724, 16254, 1975, 2288, 38251, 1975, 12610, 11331, 26108, 3660, 2423, 1737, 1772, 10686], "avg_logprob": -0.31937501271565755, "compression_ratio": 1.627906976744186, "no_speech_prob": 1.7881393432617188e-07, "words": [{"start": 594.33, "end": 594.97, "word": "طبعا", "probability": 0.794036865234375}, {"start": 594.97, "end": 595.25, "word": " سير", "probability": 0.716064453125}, {"start": 595.25, "end": 595.61, "word": " نزل", "probability": 0.8924153645833334}, {"start": 595.61, "end": 595.73, "word": " على", "probability": 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"word": " car", "probability": 0.82666015625}, {"start": 604.93, "end": 605.19, "word": " اذا", "probability": 0.5718994140625}, {"start": 605.19, "end": 605.35, "word": " انا", "probability": 0.52752685546875}, {"start": 605.35, "end": 605.49, "word": " بدي", "probability": 0.7008056640625}, {"start": 605.49, "end": 605.93, "word": " ارسم", "probability": 0.9422200520833334}, {"start": 605.93, "end": 606.63, "word": " اول", "probability": 0.825927734375}, {"start": 606.63, "end": 606.99, "word": " حاجة", "probability": 0.9265950520833334}, {"start": 606.99, "end": 607.11, "word": " ال", "probability": 0.291748046875}, {"start": 607.11, "end": 607.31, "word": " free", "probability": 0.89111328125}, {"start": 607.31, "end": 607.55, "word": " body", "probability": 0.82177734375}, {"start": 607.55, "end": 607.99, "word": " diagram", "probability": 0.9365234375}], "temperature": 1.0}, {"id": 29, "seek": 63630, "start": 609.59, "end": 636.31, "text": "كما هو مضح بالشكل فى عندى اللى عندى اللى هى قوة الجغرية او الـ Mg الـ Mg غير يوم الـ Mg بساوي الـ N في G وفى عندى الـ Normal عمودية على السطح ده هو السطح المارين و الـ N عمودية على السطح المارين بدأ أحلل الـ Mg إلى Mg صينة فيتا على نفس المستوى و Mg كوزاينة فيتا عمودي على المستوى", "tokens": [4117, 15042, 31439, 3714, 11242, 5016, 20666, 8592, 28820, 6156, 7578, 43242, 7578, 13672, 7578, 43242, 7578, 13672, 7578, 8032, 7578, 12174, 2407, 3660, 2423, 7435, 17082, 16572, 3660, 1975, 2407, 2423, 39184, 376, 70, 2423, 39184, 376, 70, 32771, 13546, 7251, 20498, 2423, 39184, 376, 70, 4724, 3794, 995, 45865, 2423, 39184, 426, 8978, 460, 4032, 5172, 7578, 43242, 7578, 2423, 39184, 21277, 6225, 2304, 2407, 16254, 3660, 15844, 21136, 9566, 5016, 11778, 3224, 31439, 21136, 9566, 5016, 9673, 9640, 9957, 4032, 2423, 39184, 426, 6225, 2304, 2407, 16254, 3660, 15844, 21136, 9566, 5016, 9673, 9640, 9957, 47525, 10721, 5551, 5016, 1211, 1211, 2423, 39184, 376, 70, 30731, 376, 70, 20328, 9957, 3660, 6156, 36081, 995, 15844, 8717, 36178, 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" أحلل", "probability": 0.8326416015625}, {"start": 628.71, "end": 629.33, "word": " الـ", "probability": 0.947265625}, {"start": 629.33, "end": 629.67, "word": " Mg", "probability": 0.890625}, {"start": 629.67, "end": 630.03, "word": " إلى", "probability": 0.77783203125}, {"start": 630.03, "end": 631.01, "word": " Mg", "probability": 0.901611328125}, {"start": 631.01, "end": 631.43, "word": " صينة", "probability": 0.5477701822916666}, {"start": 631.43, "end": 631.71, "word": " فيتا", "probability": 0.5938313802083334}, {"start": 631.71, "end": 631.89, "word": " على", "probability": 0.9052734375}, {"start": 631.89, "end": 632.13, "word": " نفس", "probability": 0.994384765625}, {"start": 632.13, "end": 632.89, "word": " المستوى", "probability": 0.9808349609375}, {"start": 632.89, "end": 633.49, "word": " و", "probability": 0.9541015625}, {"start": 633.49, "end": 634.03, "word": " Mg", "probability": 0.802490234375}, {"start": 634.03, "end": 634.57, "word": " كوزاينة", "probability": 0.8004557291666666}, {"start": 634.57, "end": 634.89, "word": " فيتا", "probability": 0.9091796875}, {"start": 634.89, "end": 635.29, "word": " عمودي", "probability": 0.9852294921875}, {"start": 635.29, "end": 635.59, "word": " على", "probability": 0.84521484375}, {"start": 635.59, "end": 636.31, "word": " المستوى", "probability": 0.9669189453125}], "temperature": 1.0}, {"id": 30, "seek": 66594, "start": 637.08, "end": 665.94, "text": "طبعا مافي frictionless معناته مش هاخد احتكاك في هذا الاتجاه اذا هو الذسن نازل على أسفل المنحضر فالقوة اللي هادة باعتبر هادة كإن ال X-axis و باعتبر هادة كإن ال Y-axis لما بدأ اويد ال acceleration to find the acceleration of the car بدأ استخدم قانون لوتن التاني summation لل F يتساوي ال 1000 في A طبعا عندي انا ال FG", "tokens": [9566, 3555, 3615, 995, 19446, 41185, 17710, 1832, 20449, 8315, 47395, 37893, 8032, 47283, 3215, 1975, 33753, 4117, 995, 4117, 8978, 23758, 2423, 9307, 7435, 40294, 1975, 15730, 31439, 32545, 3794, 1863, 8717, 31377, 1211, 15844, 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{"start": 644.7, "end": 645.14, "word": " أسفل", "probability": 0.82916259765625}, {"start": 645.14, "end": 645.7, "word": " المنحضر", "probability": 0.725244140625}, {"start": 645.7, "end": 646.78, "word": " فالقوة", "probability": 0.92861328125}, {"start": 646.78, "end": 646.98, "word": " اللي", "probability": 0.80810546875}, {"start": 646.98, "end": 647.24, "word": " هادة", "probability": 0.4905598958333333}, {"start": 647.24, "end": 647.62, "word": " باعتبر", "probability": 0.8525390625}, {"start": 647.62, "end": 647.92, "word": " هادة", "probability": 0.6394449869791666}, {"start": 647.92, "end": 648.2, "word": " كإن", "probability": 0.89599609375}, {"start": 648.2, "end": 648.34, "word": " ال", "probability": 0.8310546875}, {"start": 648.34, "end": 648.58, "word": " X", "probability": 0.54931640625}, {"start": 648.58, "end": 649.16, "word": "-axis", "probability": 0.5238037109375}, {"start": 649.16, "end": 649.56, "word": " و", "probability": 0.53466796875}, {"start": 649.56, 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find", "probability": 0.89599609375}, {"start": 655.52, "end": 655.66, "word": " the", "probability": 0.4404296875}, {"start": 655.66, "end": 656.18, "word": " acceleration", "probability": 0.89404296875}, {"start": 656.18, "end": 656.42, "word": " of", "probability": 0.9775390625}, {"start": 656.42, "end": 656.58, "word": " the", "probability": 0.91796875}, {"start": 656.58, "end": 656.94, "word": " car", "probability": 0.92236328125}, {"start": 656.94, "end": 657.72, "word": " بدأ", "probability": 0.870849609375}, {"start": 657.72, "end": 658.14, "word": " استخدم", "probability": 0.8653971354166666}, {"start": 658.14, "end": 658.68, "word": " قانون", "probability": 0.9879557291666666}, {"start": 658.68, "end": 659.88, "word": " لوتن", "probability": 0.7853190104166666}, {"start": 659.88, "end": 660.82, "word": " التاني", "probability": 0.8849283854166666}, {"start": 660.82, "end": 661.6, "word": " summation", "probability": 0.794921875}, {"start": 661.6, "end": 661.96, "word": " لل", "probability": 0.68994140625}, {"start": 661.96, "end": 662.14, "word": " F", "probability": 0.42138671875}, {"start": 662.14, "end": 662.52, "word": " يتساوي", "probability": 0.75595703125}, {"start": 662.52, "end": 662.64, "word": " ال", "probability": 0.431884765625}, {"start": 662.64, "end": 662.78, "word": " 1000", "probability": 0.352783203125}, {"start": 662.78, "end": 662.94, "word": " في", "probability": 0.76025390625}, {"start": 662.94, "end": 663.24, "word": " A", "probability": 0.8349609375}, {"start": 663.24, "end": 664.34, "word": " طبعا", "probability": 0.9327392578125}, {"start": 664.34, "end": 664.66, "word": " عندي", "probability": 0.6593017578125}, {"start": 664.66, "end": 664.94, "word": " انا", "probability": 0.747314453125}, {"start": 664.94, "end": 665.24, "word": " ال", "probability": 0.89794921875}, {"start": 665.24, "end": 665.94, "word": " FG", "probability": 0.75732421875}], "temperature": 1.0}, {"id": 31, "seek": 68194, "start": 678.98, "end": 681.94, "text": "بالنسبة للأفعال الموجودة في البرنامج", "tokens": [3555, 6027, 1863, 35457, 3660, 24976, 10721, 5172, 3615, 6027, 9673, 29245, 23328, 3660, 8978, 2423, 26890, 8315, 2304, 7435], "avg_logprob": -0.8526785600753057, "compression_ratio": 1.0625, "no_speech_prob": 1.7881393432617188e-07, "words": [{"start": 678.98, "end": 680.38, "word": "بالنسبة", "probability": 0.61180419921875}, {"start": 680.38, "end": 681.78, "word": " للأفعال", "probability": 0.6056640625}, {"start": 681.78, "end": 681.94, "word": " الموجودة", "probability": 0.585723876953125}, {"start": 681.94, "end": 681.94, "word": " في", "probability": 0.442626953125}, {"start": 681.94, "end": 681.94, "word": " البرنامج", "probability": 0.6038330078125}], "temperature": 1.0}, {"id": 32, "seek": 69247, "start": 681.97, "end": 692.47, "text": "هو عبارة عن Normal ماخص Mg Cos θ بساوي Zero لأن هناك حركة باتجاه الـ Y-Axis وحركة التسارع باتجاه الـ X-Axis", "tokens": [3224, 2407, 6225, 3555, 9640, 3660, 18871, 21277, 3714, 47283, 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"word": " اشارة", "probability": 0.853759765625}, {"start": 930.54, "end": 930.68, "word": " ان", "probability": 0.62548828125}, {"start": 930.68, "end": 931.4, "word": " الحركة", "probability": 0.9759114583333334}, {"start": 931.4, "end": 931.76, "word": " في", "probability": 0.93603515625}, {"start": 931.76, "end": 932.18, "word": " اتجاه", "probability": 0.875244140625}, {"start": 932.18, "end": 932.7, "word": " الأعلى", "probability": 0.8102213541666666}], "temperature": 1.0}, {"id": 43, "seek": 95120, "start": 934.82, "end": 951.2, "text": "هنا بيحكي إن وين الـ elevator accelerate أبواب، الـ spring scale rates evaluated better than the weight of the fish، الـ spring scale rates هي عبارة عن الـ tension، اللي هو ماسك أو اللي هو مربوط فيه هأس سمكة", "tokens": [3224, 8315, 4724, 1829, 5016, 4117, 1829, 36145, 4032, 9957, 2423, 39184, 18782, 21341, 5551, 3555, 14407, 3555, 12399, 2423, 39184, 5587, 4373, 6846, 25509, 1101, 813, 264, 3364, 295, 264, 3506, 12399, 2423, 39184, 5587, 4373, 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0.10662841796875}, {"start": 1410.78, "end": 1411.18, "word": " بنتجرها", "probability": 0.664697265625}, {"start": 1411.18, "end": 1411.28, "word": " الـ", "probability": 0.489013671875}, {"start": 1411.28, "end": 1411.4, "word": " X", "probability": 0.34423828125}, {"start": 1411.4, "end": 1412.02, "word": " axis", "probability": 0.4736328125}, {"start": 1412.02, "end": 1412.6, "word": " في", "probability": 0.27001953125}, {"start": 1412.6, "end": 1412.78, "word": " هذه", "probability": 0.7197265625}, {"start": 1412.78, "end": 1413.52, "word": " الحالة", "probability": 0.98388671875}, {"start": 1413.52, "end": 1414.26, "word": " الـ", "probability": 0.40643310546875}, {"start": 1414.26, "end": 1414.38, "word": " Mu", "probability": 0.09552001953125}, {"start": 1414.38, "end": 1414.68, "word": " K", "probability": 0.54150390625}, {"start": 1414.68, "end": 1416.54, "word": " يعني", "probability": 0.56396484375}, {"start": 1416.54, "end": 1416.66, "word": " ال", "probability": 0.53466796875}, {"start": 1416.66, "end": 1416.98, "word": " FK", "probability": 0.6708984375}, {"start": 1416.98, "end": 1417.18, "word": " هي", "probability": 0.837890625}, {"start": 1417.18, "end": 1417.34, "word": " اللي", "probability": 0.884521484375}, {"start": 1417.34, "end": 1417.82, "word": " بتساوي", "probability": 0.80859375}, {"start": 1417.82, "end": 1418.02, "word": " N", "probability": 0.379638671875}, {"start": 1418.02, "end": 1418.18, "word": " في", "probability": 0.74755859375}, {"start": 1418.18, "end": 1418.4, "word": " A", "probability": 0.92041015625}, {"start": 1418.4, "end": 1419.0, "word": " و", "probability": 0.36865234375}, {"start": 1419.0, "end": 1419.36, "word": " FK", "probability": 0.7783203125}, {"start": 1419.36, "end": 1419.76, "word": " بتساوي", "probability": 0.88916015625}, {"start": 1419.76, "end": 1420.1, "word": " ناقص", "probability": 0.8177490234375}, {"start": 1420.1, "end": 1420.3, "word": " Mu", "probability": 0.6455078125}, {"start": 1420.3, "end": 1420.48, "word": " K", "probability": 0.875}, {"start": 1420.48, "end": 1420.62, "word": " في", "probability": 0.82666015625}, {"start": 1420.62, "end": 1421.1, "word": " NG", "probability": 0.4228515625}, {"start": 1421.1, "end": 1422.08, "word": " بتساوي", "probability": 0.841796875}, {"start": 1422.08, "end": 1422.2, "word": " ال", "probability": 0.385009765625}, {"start": 1422.2, "end": 1422.32, "word": " N", "probability": 0.625}, {"start": 1422.32, "end": 1422.48, "word": " في", "probability": 0.9765625}, {"start": 1422.48, "end": 1422.72, "word": " A", "probability": 0.98583984375}, {"start": 1422.72, "end": 1422.96, "word": " ال", "probability": 0.5283203125}, {"start": 1422.96, "end": 1423.1, "word": " N", "probability": 0.413330078125}, {"start": 1423.1, "end": 1423.52, "word": " بتروح", "probability": 0.86669921875}, {"start": 1423.52, "end": 1423.66, "word": " من", "probability": 0.6611328125}, {"start": 1423.66, "end": 1423.8, "word": " اللي", "probability": 0.617919921875}, {"start": 1423.8, "end": 1423.94, "word": " مع", "probability": 0.9833984375}, {"start": 1423.94, "end": 1424.1, "word": " ال", "probability": 0.9853515625}, {"start": 1424.1, "end": 1424.4, "word": " M", "probability": 0.94580078125}, {"start": 1424.4, "end": 1425.02, "word": " بيبقى", "probability": 0.6847412109375}, {"start": 1425.02, "end": 1425.32, "word": " لعندي", "probability": 0.800537109375}, {"start": 1425.32, "end": 1425.64, "word": " Mu", "probability": 0.95263671875}, {"start": 1425.64, "end": 1425.8, "word": " K", "probability": 0.9404296875}, {"start": 1425.8, "end": 1426.18, "word": " بتساوي", "probability": 0.84991455078125}, {"start": 1426.18, "end": 1426.52, "word": " ناقص", "probability": 0.98388671875}, {"start": 1426.52, "end": 1426.66, "word": " A", "probability": 0.9169921875}, {"start": 1426.66, "end": 1426.86, "word": " على", "probability": 0.75537109375}, {"start": 1426.86, "end": 1427.2, "word": " G", "probability": 0.95458984375}], "temperature": 1.0}, {"id": 66, "seek": 144493, "start": 1442.41, "end": 1444.93, "text": "بنستكمل ان شاء الله في التزيين القادم", "tokens": [3555, 1863, 14851, 24793, 1211, 16472, 13412, 16606, 21984, 8978, 16712, 11622, 1829, 9957, 25062, 18513, 2304], "avg_logprob": -0.405164940489663, "compression_ratio": 1.0461538461538462, "no_speech_prob": 5.900859832763672e-06, "words": [{"start": 1442.41, "end": 1442.93, "word": "بنستكمل", "probability": 0.595751953125}, {"start": 1442.93, "end": 1443.01, "word": " ان", "probability": 0.316650390625}, {"start": 1443.01, "end": 1443.23, "word": " شاء", "probability": 0.88623046875}, {"start": 1443.23, "end": 1443.39, "word": " الله", "probability": 0.9462890625}, {"start": 1443.39, "end": 1443.65, "word": " في", "probability": 0.8173828125}, {"start": 1443.65, "end": 1444.27, "word": " التزيين", "probability": 0.685272216796875}, {"start": 1444.27, "end": 1444.93, "word": " القادم", "probability": 0.9835611979166666}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1445.070625, "duration_after_vad": 1421.4881249999994}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..fef86c00e2741c6ac1e1a87d5347d19b1386e995
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2752NjWDfSI_raw.srt
@@ -0,0 +1,1200 @@
+1
+00:00:01,060 --> 00:00:06,280
+بسم الله الرحمن الرحيم نستكمل أمثلة chapter أربع
+
+2
+00:00:06,280 --> 00:00:12,600
+طبعا ال problems أبارعان slip is type three on
+
+3
+00:00:12,600 --> 00:00:16,500
+frictionless snow covered hill as shown in the
+
+4
+00:00:16,500 --> 00:00:21,580
+figure if the slip weighed 77 in NewtonFind the
+
+5
+00:00:21,580 --> 00:00:26,440
+magnitude of the tension force T exerted by the
+
+6
+00:00:26,440 --> 00:00:29,860
+rope on the sled and that of the normal force M
+
+7
+00:00:29,860 --> 00:00:31,880
+exerted by the hill on the sled
+
+8
+00:00:37,240 --> 00:00:41,320
+الـ Fungible ice معناه تفرخش الناس، في عنده هنا
+
+9
+00:00:41,320 --> 00:00:45,520
+شجرة مربوط فيها خط، المفروض هنا مربوط فيها يعني
+
+10
+00:00:45,520 --> 00:00:54,750
+عربات يعني تزلج على الجليدمطلب مني LGD اللي هو ال
+
+11
+00:00:54,750 --> 00:01:00,170
+tension طبعا هذه مربوطة بخيط فلما أرسل في ال
+
+12
+00:01:00,170 --> 00:01:06,390
+diagram هنزل أول شي LGD اللي هو كتلة العرضة وهنا
+
+13
+00:01:06,390 --> 00:01:10,650
+في عندي خيوط الشد اتجاه ناحية الشجرة ال LGD راح
+
+14
+00:01:10,650 --> 00:01:16,690
+أحللها إلى LG sin θ بهذا الاتجاه و LG cos θ بهذا
+
+15
+00:01:16,690 --> 00:01:20,570
+الاتجاه اللي هو عمودي على اللي هو عمودي على
+
+16
+00:01:20,570 --> 00:01:28,000
+المستوىطبعا هذا المسار مائد بزاوية تلاتين درجة
+
+17
+00:01:28,000 --> 00:01:34,440
+الحل حقق بقانون متل التاني بحيث ان القسارة بساوي
+
+18
+00:01:34,440 --> 00:01:37,500
+زيرو يعني في عند نوع من الاتزان
+
+19
+00:01:45,620 --> 00:01:50,260
+بالتالي اذا extract the X component from this
+
+20
+00:01:50,260 --> 00:01:55,280
+equation to find T بدي اوجد او اطبق قانون نوتن
+
+21
+00:01:55,280 --> 00:01:59,320
+التاني في اتجاه ال X axis طبعا انا باعتبر اللي هو
+
+22
+00:01:59,320 --> 00:02:06,010
+انحدار الخط المنحدر هو أبارع ال X axisفكس بتساوي T
+
+23
+00:02:06,010 --> 00:02:12,890
+زائد زير ناقص NG SIN فيته اذا T ناقص NG SIN فيته
+
+24
+00:02:12,890 --> 00:02:16,310
+اللي احنا طلعناها من قبل هيك اللي هو هذه أبدا عن
+
+25
+00:02:16,310 --> 00:02:21,110
+ال NG اللي هي ال N في تسعة وتمانية من عشرة في SIN
+
+26
+00:02:21,110 --> 00:02:25,490
+فيته بتطلع زيره لإن في عندي انا اتزان اذا ال T
+
+27
+00:02:25,490 --> 00:02:29,780
+بتساوي تمانية او تلاتين ونص المتينبدي استخدم قانون
+
+28
+00:02:29,780 --> 00:02:33,800
+متعدد تاني بالنسبة للـY dimensions اللي هو الـY
+
+29
+00:02:33,800 --> 00:02:38,100
+component of the tension is zero طبعا مافيش حركة
+
+30
+00:02:38,100 --> 00:02:42,800
+باتجاه ايضا الـY معناه الكلام ان summation للأفوال
+
+31
+00:02:42,800 --> 00:02:47,440
+بيبقى تساوي Zero زائد الان ناقص MG كزاين فيتا
+
+32
+00:02:47,440 --> 00:02:54,590
+بيبقى تساوي Normal ناقص MGفي كوزاينة يتا بالسواء
+
+33
+00:02:54,590 --> 00:02:58,230
+Zero اذا نرى بالسواء ستة و ستين point سبعة احنا
+
+34
+00:02:58,230 --> 00:03:01,910
+اوجدنا الشباب اوجدنا قوة رد الفئة اللي هي ال
+
+35
+00:03:01,910 --> 00:03:07,030
+normal efforts في هذا ال quiz كان هي مضح بالشكل
+
+36
+00:03:07,030 --> 00:03:11,990
+for the woman being pulled forward in the top gang
+
+37
+00:03:13,080 --> 00:03:20,120
+يعني طبعا المرأة هذه زالت على عرب التزلج وطبعا أحد
+
+38
+00:03:20,120 --> 00:03:26,040
+الأشخاص بيجيب بهذا الشكل بخياط معين بزاوية طبعا
+
+39
+00:03:26,040 --> 00:03:28,800
+بالنسبة لل normal force في هذه الحالة the
+
+40
+00:03:28,800 --> 00:03:31,340
+magnitude of the normal force exceeded by the
+
+41
+00:03:31,340 --> 00:03:36,920
+ground in the top gun اللي هو قوة رد الفائل
+
+42
+00:03:36,920 --> 00:03:42,170
+العمضية من الأرض على العربةهل بيه بتساوي ال total
+
+43
+00:03:42,170 --> 00:03:48,410
+weight of the woman plus تبجان ولا greater than
+
+44
+00:03:48,410 --> 00:03:54,250
+the total weight ولا less than the total weight or
+
+45
+00:03:54,250 --> 00:03:57,050
+possibly greater than or less than the total
+
+46
+00:03:57,050 --> 00:04:00,690
+depending on the size of the weight relative to
+
+47
+00:04:00,690 --> 00:04:04,290
+the tension in the rope طبعا ال answer السؤال
+
+48
+00:04:04,290 --> 00:04:08,110
+الجواب عبارة عن ان هي less than the total weight
+
+49
+00:04:08,110 --> 00:04:14,940
+لماذا؟لأنه إذا فرضنا إن الشد بهذا الإتجار بميئة زي
+
+50
+00:04:14,940 --> 00:04:20,440
+الـθيتا لو بدأ أنا أرسل هنا الشد هنا في عندي
+
+51
+00:04:20,440 --> 00:04:25,100
+Normal و تحت هيكون اللي هو الـMg راح أحلل الشد إلى
+
+52
+00:04:25,100 --> 00:04:31,360
+T Cos θ وهنا T Sin θ إذا الـNormal زي الـT Sin θ
+
+53
+00:04:31,360 --> 00:04:37,770
+بيساوي الـMg إذا الـNormal بيساوي الـMg ناقصT sin
+
+54
+00:04:37,770 --> 00:04:41,610
+θ معناه الكلام انه في هذه الحالة ال normal عبارة
+
+55
+00:04:41,610 --> 00:04:47,490
+عن اقل قيمته اقل less than the total weight زي ما
+
+56
+00:04:47,490 --> 00:04:54,010
+أخدنا بالنسبة لقوة رد الفعل كانت ال normal اقل في
+
+57
+00:04:54,010 --> 00:04:58,630
+حالة ما احنا شدنا اي جسم بقوة tension اللي هي بقوة
+
+58
+00:04:58,630 --> 00:04:59,030
+شد
+
+59
+00:05:09,680 --> 00:05:13,860
+الجسم للأسام المتسارعة باستخدام قانون الموتون
+
+60
+00:05:13,860 --> 00:05:18,220
+التاني when a net force acts on an object لو كان
+
+61
+00:05:18,220 --> 00:05:23,200
+عنده مجموعة من القوة مؤثرة على أي جسم والجسم يحدث
+
+62
+00:05:23,200 --> 00:05:27,570
+له تسارعand we use the Newton's second law to
+
+63
+00:05:27,570 --> 00:05:31,190
+analyze the motion باستخدام قانون ال Newton التاني
+
+64
+00:05:31,190 --> 00:05:37,150
+لتحليل اللي هي الحركة في عندنا أنا خزانة الخزانة
+
+65
+00:05:37,150 --> 00:05:41,750
+هذه موجودة على العربة طبعا بدا نزل انا الان نزل
+
+66
+00:05:41,750 --> 00:05:46,070
+الخزانة زي العربة هي ال FG اللي هي ال MG للعربة زي
+
+67
+00:05:46,070 --> 00:05:50,840
+اللي هي العربة تحته هي الخزانةهنا في عندى قوات شد
+
+68
+00:05:50,840 --> 00:05:55,400
+مربوطة بخيط وبشدها، في عندى قوات red فيها الأرض
+
+69
+00:05:55,400 --> 00:06:01,860
+على الخزانة زائد اللى هو العرباالـ example اللي
+
+70
+00:06:01,860 --> 00:06:05,300
+عندنا اللي هو زي ما هو مرسوم بالشكل الأعلى the
+
+71
+00:06:05,300 --> 00:06:08,540
+combined weight of the crate and bullion بلد و
+
+72
+00:06:08,540 --> 00:06:13,680
+عربة زي ما حكيناه كان هو موضح من هذا الشكل تلاتة
+
+73
+00:06:13,680 --> 00:06:18,440
+نوتين
+
+74
+00:06:18,440 --> 00:06:22,320
+if the man pull on the rope with constant force
+
+75
+00:06:22,320 --> 00:06:27,080
+طبعا الراجل هذا بشد الخزانة بقوة مقدارها عشرين
+
+76
+00:06:27,080 --> 00:06:34,000
+نوتين what isWhat is the acceleration of the
+
+77
+00:06:34,000 --> 00:06:37,700
+system؟ ال system هو عبارة عن النظام كله عبارة عن
+
+78
+00:06:37,700 --> 00:06:42,660
+الدولاب زائد العربة and how far will it move in 2
+
+79
+00:06:42,660 --> 00:06:47,520
+seconds كان المسافة اللي بنتمشيها خلال زمن 2 ثانية
+
+80
+00:06:48,100 --> 00:06:51,400
+بدا أنا أفرض إن ال system started from rest and
+
+81
+00:06:51,400 --> 00:06:55,580
+that there are no friction force within the
+
+82
+00:06:55,580 --> 00:07:00,360
+motion، طبعا العربة و الخزانة أو العربة و الدلاب
+
+83
+00:07:00,360 --> 00:07:07,400
+بيمشوا على خط اللي هو less friction less، الحلأول
+
+84
+00:07:07,400 --> 00:07:10,900
+شيء find the mass of the system from the
+
+85
+00:07:10,900 --> 00:07:14,840
+definition طبعا هو وزن ال system كله وزن ال system
+
+86
+00:07:14,840 --> 00:07:19,140
+كله أدارة عن تلاتة في عشر أفس اتنين او اتنين فمن
+
+87
+00:07:19,140 --> 00:07:22,680
+القانون ان الوزن بيساوي ال M G ال M في هذه الحالة
+
+88
+00:07:22,680 --> 00:07:26,020
+بيساوي الوزن على ال G اللي هي التسارع الجاذبية اذا
+
+89
+00:07:26,020 --> 00:07:30,700
+ال mass اللي هي الكتلة لل system كله بيساوي الوزن
+
+90
+00:07:30,700 --> 00:07:34,140
+على ال Gتلاتة فى عشرة أقصى اتنين نيوتن على تسعة
+
+91
+00:07:34,140 --> 00:07:38,440
+بون تمانية تعطيه تلاتين بون ستة كيلو جرام لإيجاد
+
+92
+00:07:38,440 --> 00:07:41,900
+التسارع find acceleration of the system بستخدم
+
+93
+00:07:41,900 --> 00:07:45,700
+قانون نيوتن التاني summation لل Fx بتساوي ال M في
+
+94
+00:07:45,700 --> 00:07:50,480
+Ax إذا ال Ax بيبقى تساوي ال F على M ال F تجاه ال X
+
+95
+00:07:50,480 --> 00:07:53,460
+كانت عشرين و ال M طلعناها تلاتين بون ستة بيطلع
+
+96
+00:07:53,460 --> 00:07:56,880
+عندي point six خمسة أربعة متر في الثانية تربيع
+
+97
+00:08:01,540 --> 00:08:07,060
+استخد المعادلات الحركة علشان اوجد المسافة اللى
+
+98
+00:08:07,060 --> 00:08:12,520
+مشيتها العربة طبعا في زمن قبل اتنين ثانية
+
+99
+00:08:21,020 --> 00:08:25,200
+بتبقى لعندي delta X بتساوي نص A X تربيه يعني
+
+100
+00:08:25,200 --> 00:08:31,100
+بتساوي نص وال A طلعناها بين ستة خمسة أربعة في اللي
+
+101
+00:08:31,100 --> 00:08:36,720
+هو زمان T الترويه تلعبي واحد بين تلاتة مترالان
+
+102
+00:08:36,720 --> 00:08:41,320
+example أربع عشرة ال problem عبارة عن a car of
+
+103
+00:08:41,320 --> 00:08:46,260
+mass M سيارة كتلتها M is on an icy driveway
+
+104
+00:08:46,260 --> 00:08:52,150
+inclined at an angle فتة بالساعة عشرين سيارةكتلتها
+
+105
+00:08:52,150 --> 00:08:59,230
+M موجودة في مثال ثلجي بنيل على الأفق زاوية 20 درجة
+
+106
+00:08:59,230 --> 00:09:04,330
+بتعمل acceleration أو دقاء بتسارق السيارة باعتبار
+
+107
+00:09:04,330 --> 00:09:09,290
+أن assuming the incline is frictionlessIf the
+
+108
+00:09:09,290 --> 00:09:12,950
+length of the drive away is خمسة و عشرين متر and
+
+109
+00:09:12,950 --> 00:09:17,770
+the car start from west طبعا السلوب التاني بيحكي
+
+110
+00:09:17,770 --> 00:09:21,850
+إن إذا كان طول المسار خمسة و عشرين متر والسيارة
+
+111
+00:09:21,850 --> 00:09:26,190
+بتتحرك بدأت من السكوناللي في الأعلى how long does
+
+112
+00:09:26,190 --> 00:09:30,310
+it take to travel to Buton بده الزمن اللازم لكي
+
+113
+00:09:30,310 --> 00:09:34,790
+تصل إلى أسفل المنحدر بعد هيك بطلب what is the car
+
+114
+00:09:34,790 --> 00:09:38,850
+speed ال Buton بده سرعة السيارة في نهاية اللي هو
+
+115
+00:09:38,850 --> 00:09:44,050
+المسار الان عندي أنا مسار منحدر هي كهيوم وقالسي
+
+116
+00:09:44,050 --> 00:09:50,930
+فلجي ومسار طبعا خط سريع وفلجي معناته frictionless
+
+117
+00:09:50,930 --> 00:09:55,950
+السيارة نازلة على هدأ المنحدرطبعا سير نزل على هذا
+
+118
+00:09:55,950 --> 00:10:00,150
+المنحدر في البداية مطلوب منه أن نجد في ايه؟ مطلوب
+
+119
+00:10:00,150 --> 00:10:03,490
+منه أن نجد ال acceleration of the car بدي ال
+
+120
+00:10:03,490 --> 00:10:07,110
+acceleration ل ال car اذا انا بدي ارسم اول حاجة ال
+
+121
+00:10:07,110 --> 00:10:12,850
+free body diagramكما هو مضح بالشكل فى عندى اللى
+
+122
+00:10:12,850 --> 00:10:16,530
+عندى اللى هى قوة الجغرية او الـ Mg الـ Mg غير يوم
+
+123
+00:10:16,530 --> 00:10:21,050
+الـ Mg بساوي الـ N في G وفى عندى الـ Normal عمودية
+
+124
+00:10:21,050 --> 00:10:25,910
+على السطح ده هو السطح المارين و الـ N عمودية على
+
+125
+00:10:25,910 --> 00:10:31,890
+السطح المارين بدأ أحلل الـ Mg إلى Mg صينة فيتا على
+
+126
+00:10:31,890 --> 00:10:36,310
+نفس المستوى و Mg كوزاينة فيتا عمودي على المستوى
+
+127
+00:10:37,080 --> 00:10:41,340
+طبعا مافي frictionless معناته مش هاخد احتكاك في
+
+128
+00:10:41,340 --> 00:10:45,700
+هذا الاتجاه اذا هو الذسن نازل على أسفل المنحضر
+
+129
+00:10:45,700 --> 00:10:49,560
+فالقوة اللي هادة باعتبر هادة كإن ال X-axis و
+
+130
+00:10:49,560 --> 00:10:53,920
+باعتبر هادة كإن ال Y-axis لما بدأ اويد ال
+
+131
+00:10:53,920 --> 00:10:56,940
+acceleration to find the acceleration of the car
+
+132
+00:10:56,940 --> 00:11:02,520
+بدأ استخدم قانون لوتن التاني summation لل F يتساوي
+
+133
+00:11:02,520 --> 00:11:05,940
+ال 1000 في A طبعا عندي انا ال FG
+
+134
+00:11:18,980 --> 00:11:23,030
+بالنسبة للأفعال الموجودة في البرنامجهو عبارة عن
+
+135
+00:11:23,030 --> 00:11:28,430
+Normal ماخص Mg Cos θ بساوي Zero لأن هناك حركة
+
+136
+00:11:28,430 --> 00:11:32,470
+باتجاه الـ Y-Axis وحركة التسارع باتجاه الـ X-Axis
+
+137
+00:11:38,950 --> 00:11:43,990
+Dividing المعادلة واحد by M المعادلة واحد بدي
+
+138
+00:11:43,990 --> 00:11:48,410
+اقسمها على M او بدي اشيل M من الطرفين تطلع ال A X
+
+139
+00:11:48,410 --> 00:11:51,990
+بالساعة G Sine of Theta اذا ان ال A بتجاه X
+
+140
+00:11:51,990 --> 00:11:54,590
+بالساعة G Sine of Theta و G تسعة و تمانية من عشرة
+
+141
+00:11:54,590 --> 00:11:59,090
+Sine العشرين تطلع اندي A تلاتة بور تلاتة خمسة هدوي
+
+142
+00:11:59,090 --> 00:12:01,710
+عبارة عن التسعة رقم اللي بتمشي فيها السيارة على
+
+143
+00:12:01,710 --> 00:12:08,580
+المنحدر المنحدر انا اعتبرته كأنه محور Xفي B يجب أن
+
+144
+00:12:08,580 --> 00:12:13,220
+تجد الوقت اللذي يتأخده لتحقيق الـ Cartridge بمدّ
+
+145
+00:12:13,220 --> 00:12:22,280
+الزمن اللازم لكي تصل السيارة إلى أسفل المنحضر طبعا
+
+146
+00:12:22,280 --> 00:12:26,740
+اني بدأت من الريست V mod X متساوي Zero عندي أنا
+
+147
+00:12:26,740 --> 00:12:30,820
+القرن بلتا X متساوي V mod T زي نص A T تربيع وB mod
+
+148
+00:12:30,820 --> 00:12:35,710
+بزير وذلك عندي نص A X T تربيعنص الـ ETA اللي عمرها
+
+149
+00:12:35,710 --> 00:12:40,770
+3.35 والزمن اللي هو T تربيه ماعنديش، في عندي أنا
+
+150
+00:12:40,770 --> 00:12:44,770
+اللي هي Delta X حكاية لإن طول المنحبر كان السيارة
+
+151
+00:12:44,770 --> 00:12:51,230
+ماشية بمسافة 25 متر وطالب منها الزمن اللازم علشان
+
+152
+00:12:51,230 --> 00:12:55,090
+السيارة تصل إلى نهاية المنحبر اللي هو نهاته طوله
+
+153
+00:12:55,090 --> 00:12:59,730
+كان بيمشي مسافة 25 متر، بطلع الزمن بالساعة 3.86
+
+154
+00:12:59,730 --> 00:13:04,710
+Secondفي C Find the speed of the car at the bottom
+
+155
+00:13:04,710 --> 00:13:10,130
+of the driveway بدّه سرعة السيارة في نهاية المسار
+
+156
+00:13:10,130 --> 00:13:17,590
+أو في نهاية المحضر فبستخدم إن VX بيبقى تساوي V not
+
+157
+00:13:17,590 --> 00:13:21,510
+X زائد A T V not كانت Zero هي V not X بالساوية
+
+158
+00:13:21,510 --> 00:13:26,790
+Zero بيبقى عنا A X في Tتلاتة بين تلاتة خمسة و T
+
+159
+00:13:26,790 --> 00:13:30,450
+تلاتة بين تمانية ستة طلعناه، بطلع عنده السرعه
+
+160
+00:13:30,450 --> 00:13:34,610
+النهائيه بتساوي اتناش بين تسعة متر فيه اتانى، اذا
+
+161
+00:13:34,610 --> 00:13:39,150
+السؤال السابق كان عند سيارات تتحرك على منحضر،
+
+162
+00:13:39,150 --> 00:13:43,610
+تتحرك على منحضر بدأت من السكون و وصلت لاخر منحضر،
+
+163
+00:13:43,610 --> 00:13:47,370
+منحضر كان طوله خمسة و عشرينبتدأ تباركة المنحضر هو
+
+164
+00:13:47,370 --> 00:13:52,710
+الـ x-axis هروح نحلل للـ mg الـ mg sin θ باتجاه
+
+165
+00:13:52,710 --> 00:13:57,330
+المنحضر و الـ mg cos عمضية عليه و تطبخت خانة نيوتر
+
+166
+00:13:57,330 --> 00:14:01,010
+التاني على سماشية للـfx و سماشية للـfi و أوجدت
+
+167
+00:14:01,010 --> 00:14:06,190
+التسارع و أوجدت السرعه النهائية في آخر المنحضر
+
+168
+00:14:07,630 --> 00:14:12,170
+بالظبط مثلًا، Problems. في عندى woman وقت الـ
+
+169
+00:14:12,170 --> 00:14:18,490
+«مسعد»
+
+170
+00:14:18,490 --> 00:14:25,750
+تقف في إمرأة نلقا بدها توزان اللي هو سمكة معلقة في
+
+171
+00:14:25,750 --> 00:14:31,990
+Spring Scaling تدريج في سقف اللي هو المسعد.
+
+172
+00:14:35,010 --> 00:14:42,150
+واللي المصعد ساكن كانت مقارنة بقيمته 40 ميوتيم
+
+173
+00:14:42,150 --> 00:14:46,230
+والان مقصود مني ماهي عملية عملية عملية عملية عملية
+
+174
+00:14:46,230 --> 00:14:46,230
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+175
+00:14:46,230 --> 00:14:46,670
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+176
+00:14:46,670 --> 00:14:48,550
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+177
+00:14:48,550 --> 00:14:49,070
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+178
+00:14:49,070 --> 00:14:49,110
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+179
+00:14:49,110 --> 00:14:50,570
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+180
+00:14:50,570 --> 00:14:51,750
+عملية عملية عملية عملية عملية عملية عملية عملية
+
+181
+00:14:51,750 --> 00:14:59,330
+عملية
+
+182
+00:14:59,330 --> 00:15:05,630
+عالشد خلال طبعا الـ silk المعلقة في هذه السمكة
+
+183
+00:15:05,630 --> 00:15:11,950
+طبعا هاي هذا الشكل المضح في عندى هنا شكلا عندى انا
+
+184
+00:15:11,950 --> 00:15:17,350
+قبل ألا توزن سمكة هذا تدريج طبعا مربوط فيه spring
+
+185
+00:15:17,350 --> 00:15:21,280
+او scale divingبتبقى اعراف اللي بيواجه الـ Scale
+
+186
+00:15:21,280 --> 00:15:25,220
+Building يعني بيبقى زي الشبق على السمكة لما المصعد
+
+187
+00:15:25,220 --> 00:15:28,840
+يكون طالع أو لما المصعد يكون مازل طبعا لما المصعد
+
+188
+00:15:28,840 --> 00:15:32,180
+يكون طالع بيعطينا دي اشارة ان الحركة في اتجاه
+
+189
+00:15:32,180 --> 00:15:37,660
+الأعلىهنا بيحكي إن وين الـ elevator accelerate
+
+190
+00:15:37,660 --> 00:15:41,220
+أبواب، الـ spring scale rates evaluated better
+
+191
+00:15:41,220 --> 00:15:44,540
+than the weight of the fish، الـ spring scale
+
+192
+00:15:44,540 --> 00:15:47,220
+rates هي عبارة عن الـ tension، اللي هو ماسك أو
+
+193
+00:15:47,220 --> 00:15:53,380
+اللي هو مربوط فيه هأس سمكةهنا لما ويل الـ elevator
+
+194
+00:15:53,380 --> 00:15:58,340
+accelerate downward لما نصعد بنزل الى أسفل بس
+
+195
+00:15:58,340 --> 00:16:02,180
+bring scale reads value less than the load of the
+
+196
+00:16:02,180 --> 00:16:06,120
+fish بدنا نشوف هذا الكلام الآن السؤال المطلوب في
+
+197
+00:16:06,120 --> 00:16:10,240
+هذا السؤال مطلوب من هنا نجد أول حاجة what does the
+
+198
+00:16:10,240 --> 00:16:13,360
+scale read if the elevator accelerate؟ بيحكي انه
+
+199
+00:16:13,360 --> 00:16:18,070
+بده ال scale read يعني بده الشدلما المصعد يتحرك
+
+200
+00:16:18,070 --> 00:16:22,310
+بسرعه اتنين متر في الثاني الى اعلى و بده ايضا what
+
+201
+00:16:22,310 --> 00:16:24,990
+does the scale mean if the elevator accelerate
+
+202
+00:16:24,990 --> 00:16:29,650
+downward اذا كان نزلت بسرعه اتنين متر في الثاني
+
+203
+00:16:29,650 --> 00:16:34,890
+تربيعوكمان if the elevator cable breaks اذا قطع
+
+204
+00:16:34,890 --> 00:16:38,390
+سينك اللي هو اللي صعد what does the scale mean
+
+205
+00:16:38,390 --> 00:16:44,630
+ناخد واحدة واحدة بمثل لا الحل هنحل احنا هنرسم ال
+
+206
+00:16:44,630 --> 00:16:48,030
+free body diagram find the scale reading as the
+
+207
+00:16:48,030 --> 00:16:51,670
+elevator accelerates upward طبعا بأطبق عن نيوتن
+
+208
+00:16:51,670 --> 00:16:55,330
+التاني taking upward as the positive direction بدي
+
+209
+00:16:55,330 --> 00:16:58,990
+أخد اللي أعلى نوجة واللي أسفل سالد اللي أعلى كان
+
+210
+00:16:58,990 --> 00:17:04,210
+عندتي معقص ال Mgبتساوي الـ M في A إذا T بيبقى
+
+211
+00:17:04,210 --> 00:17:09,630
+تساوي MA زائد MG معنى الكلام T بيبقى تساوي MA زائد
+
+212
+00:17:09,630 --> 00:17:14,470
+G MA زائد G إذا الشد هو أكبر من الوزن في هذه
+
+213
+00:17:14,470 --> 00:17:20,320
+الحالة بعد ذلك find the mass of the fishكتلة
+
+214
+00:17:20,320 --> 00:17:23,180
+السمكة من خلال الوزن اللي أعطانا إياها في حالة ما
+
+215
+00:17:23,180 --> 00:17:27,920
+كان ال elevator ما بتتحركش، إذا ال M بتساوي الوزن
+
+216
+00:17:27,920 --> 00:17:31,840
+على ال G لإن الوزن بتساوي ال MG، الوزن كان 40
+
+217
+00:17:31,840 --> 00:17:35,760
+ميوتين على ال G 9.8 متر في ثانوية أربعية، بدها
+
+218
+00:17:35,760 --> 00:17:41,130
+تساوي 4.08 كيلو جرامالان بدأ أحسب اللي هو الشد من
+
+219
+00:17:41,130 --> 00:17:43,870
+خلال المعادلة السابقة على أساس إن الـA كانت
+
+220
+00:17:43,870 --> 00:17:47,210
+positive، طبعا الأعلى كانت الـA positive، باعود
+
+221
+00:17:47,210 --> 00:17:51,130
+عنها بـA موجة، إذن، بدأ أعود عن هذا الخانون T
+
+222
+00:17:51,130 --> 00:17:56,870
+بالساوية الـM، A زائد G، اللي هي الـM كانت أربعة
+
+223
+00:17:56,870 --> 00:18:01,190
+بُط و تمانية، و الـA كانت اتنين مُقطة مُجبة، و
+
+224
+00:18:01,190 --> 00:18:03,930
+الـG تسعة و تمانية من عشرة، بطلع معاية T تمانية و
+
+225
+00:18:03,930 --> 00:18:07,660
+أربعين بُط واحد المُطينالان بقى بدي استخدم نفس
+
+226
+00:18:07,660 --> 00:18:11,260
+الخوانين ولكن ال elevator إلى أسفل، لما يكون ال
+
+227
+00:18:11,260 --> 00:18:15,160
+elevator إلى أسفل فالإيه تعتبر سالب، لإن احنا
+
+228
+00:18:15,160 --> 00:18:19,420
+نشتغل حسب المحاور، المتجر الأعلى بيكون موجب،
+
+229
+00:18:19,420 --> 00:18:23,600
+والأسفل سالب، وعلى يمين موجب وعلى شمال سالبالان ال
+
+230
+00:18:23,600 --> 00:18:27,160
+analysis is the same بيقوم with change being
+
+231
+00:18:27,160 --> 00:18:34,780
+acceleration which is now negative اذا T بتساوي MA
+
+232
+00:18:34,780 --> 00:18:41,080
+زائد G لكن ال M نفسها ال A سالب اتنينمتر في
+
+233
+00:18:41,080 --> 00:18:43,400
+الثانوية وترابية والجي دسعة وتونية وعشرة بيطلع عند
+
+234
+00:18:43,400 --> 00:18:46,120
+الـ T بساعة واحدة وتلاتين point تمام معنى الكلام
+
+235
+00:18:46,120 --> 00:18:51,000
+ان الشد او ال scale reading ال scale reading او ال
+
+236
+00:18:51,000 --> 00:18:54,700
+spring reading لما يكون ال elevator ساعد يكون الشد
+
+237
+00:18:54,700 --> 00:19:00,120
+اعلى greater than the weight لما يكون نازل يكون
+
+238
+00:19:00,120 --> 00:19:05,840
+نسبة با weightفي الحالة c مطلب مني find the scale
+
+239
+00:19:05,840 --> 00:19:10,660
+reading after the elevator cable breaks مطلب ال
+
+240
+00:19:10,660 --> 00:19:15,580
+scale reading عندما ينقطع الحبل عندما ينقطع الحبل
+
+241
+00:19:15,580 --> 00:19:20,440
+معناه تبتي بالساوية 0 معناها ال a عند ناقب ال c
+
+242
+00:19:20,440 --> 00:19:25,200
+بيصير ان الجسم نزل بتسرع جاذبية فال a بتساوي ناقص
+
+243
+00:19:25,200 --> 00:19:28,560
+تسعة و تمانية عشرة ال acceleration هذا ايه لسبب
+
+244
+00:19:28,560 --> 00:19:35,030
+الجاذبيةم في ا زائد جي فالان لو عوضت عن هذا
+
+245
+00:19:35,030 --> 00:19:38,730
+القانون الان اربعة اللي طلعناها سابقا و ال a
+
+246
+00:19:38,730 --> 00:19:42,410
+اسكسرت هو نزل بتسارع جاذبية تسعة أبعد تمانية زائد
+
+247
+00:19:42,410 --> 00:19:45,570
+تسعة أبعد تمانية بيطلع عند الشت بيساوي زيرو بكل
+
+248
+00:19:45,570 --> 00:19:50,590
+الأحوال اي سؤال موجود عند ان الخيطان خاطع معناته
+
+249
+00:19:50,590 --> 00:19:52,790
+الشت بيساوي زيرو
+
+250
+00:20:04,890 --> 00:20:09,530
+problems طبعا مثلا بالاربع بند واحد اتنين بيحكي ان
+
+251
+00:20:09,530 --> 00:20:15,470
+ال hockey puck in figures by a hockey stick is
+
+252
+00:20:15,470 --> 00:20:18,490
+given an initial speed of عشرين متر في الثانية on
+
+253
+00:20:18,490 --> 00:20:23,050
+a frozen pond, the puck remained on the iceالـ bug
+
+254
+00:20:23,050 --> 00:20:27,570
+remained on the ice and slides 1.2X10.2 meters
+
+255
+00:20:27,570 --> 00:20:32,870
+slowing down steadily until it comes to rest to
+
+256
+00:20:32,870 --> 00:20:34,670
+determine the coefficient of kinetic friction
+
+257
+00:20:34,670 --> 00:20:36,130
+between the bug and the ice
+
+258
+00:20:39,120 --> 00:20:44,960
+العجلة اللى بتستخدم على الجليد و هذه العجلة ممكن
+
+259
+00:20:44,960 --> 00:20:49,520
+تضرب في عصر معينة و بتمشي مسافة معينة على الجليد
+
+260
+00:20:49,520 --> 00:20:55,000
+طبعا عندى انا اللى هى العجلة او لإن الجسم طبعا أنا
+
+261
+00:20:55,000 --> 00:21:00,580
+قدفته بعصر معينة على الجليد هذه هى ال motion حركته
+
+262
+00:21:00,580 --> 00:21:06,740
+أو جسم جمعته بحركة معينة في الدقابل اتجاه طبعا فى
+
+263
+00:21:06,740 --> 00:21:09,300
+عندى قوة احتكاكعن طريق البرامج الاخرى وهي الـ FK
+
+264
+00:21:09,300 --> 00:21:12,220
+لما ارسم أنا الـ Free Body Diagram لهذا الـ Z سمح
+
+265
+00:21:12,220 --> 00:21:16,580
+يكون عندي Normal إلى أعلى و MG إلى أسفل مطلب من ال
+
+266
+00:21:16,580 --> 00:21:18,600
+coefficient of kinetic friction
+
+267
+00:21:22,450 --> 00:21:24,830
+سنحل الانتقال الانتقال الانتقال الانتقال الانتقال
+
+268
+00:21:24,830 --> 00:21:26,090
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+269
+00:21:26,090 --> 00:21:28,750
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+270
+00:21:28,750 --> 00:21:30,230
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+271
+00:21:30,230 --> 00:21:31,950
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+272
+00:21:31,950 --> 00:21:31,990
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+273
+00:21:31,990 --> 00:21:34,970
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+274
+00:21:34,970 --> 00:21:37,910
+الانتقال الانتقال الانتقال الانتقال الانتقال
+
+275
+00:21:37,910 --> 00:21:44,110
+الانتقال الانتقال الانتقال الانتقال
+
+276
+00:21:50,780 --> 00:21:54,980
+هذه المعطيات اللي عندي Vنهاية Zero Vبتدائية كانت
+
+277
+00:21:54,980 --> 00:21:59,320
+عشرين متر في الثانية Delta X وواحد واثنين في عشر
+
+278
+00:21:59,320 --> 00:22:04,420
+أقصى اتنين مترNot that the negative sign in answer
+
+279
+00:22:04,420 --> 00:22:09,440
+A is opposite V طبعا لما أوجد أنا التسارع هو هيطلع
+
+280
+00:22:09,440 --> 00:22:14,560
+عنده ساند لإنه هو بدأ بسرعة وانتهى لاقى الـ0 يعني
+
+281
+00:22:14,560 --> 00:22:20,010
+بتباطأ الجسيم لغاية ما وصل للـ0، إذن A لسه Zeroفي
+
+282
+00:22:20,010 --> 00:22:26,030
+V0 20 تربيه على 2 Delta X 1.2 X 10 عقل 2 متر بيطلع
+
+283
+00:22:26,030 --> 00:22:31,290
+ان بيناقص 1.67 متر في second تربيه معناته التسارع
+
+284
+00:22:31,290 --> 00:22:37,190
+تبعه هو بالقلم حتى يصل إلى الادية النهائية Zero
+
+285
+00:22:37,190 --> 00:22:40,910
+يعني بتبطعطالب الـ Normal force find the normal
+
+286
+00:22:40,910 --> 00:22:45,790
+force by from the a y component بدي ال normal
+
+287
+00:22:45,790 --> 00:22:50,390
+force قوم ترد الفعل راح اطبق قانون ميوتن على اتجاه
+
+288
+00:22:50,390 --> 00:22:55,330
+ال y ال normal ناقص اللي هو ال FG بتساوي ال N ناقص
+
+289
+00:22:55,330 --> 00:22:59,190
+MG بساوي 0 لإن مافي حركة باتجاه ال Y اذا ال normal
+
+290
+00:22:59,190 --> 00:23:06,710
+بتساوي ال MG في هذه الحالةعشان اوجد الـ
+
+291
+00:23:06,710 --> 00:23:11,030
+coefficient of chemical friction الـ FK بتساوي Mu
+
+292
+00:23:11,030 --> 00:23:15,690
+K في الـ Normal الـ FK بتساوي Mu K في الـ Normal
+
+293
+00:23:15,690 --> 00:23:22,790
+بتساوي Mu K في M G إذا ناقص FK بتساوي ناقص Mu K في
+
+294
+00:23:22,790 --> 00:23:29,840
+M G طبعا في هذه الحالة بدي أرسم أنا العادلةأكتب
+
+295
+00:23:29,840 --> 00:23:33,520
+هذه المعادلة لو بنتجرها الـ X axis في هذه الحالة
+
+296
+00:23:33,520 --> 00:23:39,360
+الـ Mu K يعني ال FK هي اللي بتساوي N في A و FK
+
+297
+00:23:39,360 --> 00:23:43,520
+بتساوي ناقص Mu K في NG بتساوي ال N في A ال N بتروح
+
+298
+00:23:43,520 --> 00:23:46,860
+من اللي مع ال M بيبقى لعندي Mu K بتساوي ناقص A على
+
+299
+00:23:46,860 --> 00:23:47,200
+G
+
+300
+00:24:02,410 --> 00:24:04,930
+بنستكمل ان شاء الله في التزيين القادم
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM.srt
new file mode 100644
index 0000000000000000000000000000000000000000..470f4d33ecddfaf075b6eb73ca3998335b47c7f2
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM.srt
@@ -0,0 +1,1187 @@
+1
+00:00:00,000 --> 00:00:04,480
+بسم الله الرحمن الرحيم بنستكمل chapter تلاتة و
+
+2
+00:00:04,480 --> 00:00:07,520
+بنستكمل الموضوع اللي هو ال projectile motion اللي
+
+3
+00:00:07,520 --> 00:00:11,820
+هو في المقضوفات حكينا في المقضوفات أنه على طول ما
+
+4
+00:00:11,820 --> 00:00:14,860
+صار المقضوفة the x component of the velocity
+
+5
+00:00:14,860 --> 00:00:18,540
+remained constant يعني المركبة الأفقية للسرعة
+
+6
+00:00:18,830 --> 00:00:23,130
+بتبقى كما هي وفي أعلى ارتفاع بيكون السرعة النهائية
+
+7
+00:00:23,130 --> 00:00:28,090
+باتجاه ال Y بتساوي صفر وفي المنطقة عند منطقة اللي
+
+8
+00:00:28,090 --> 00:00:34,130
+هي القذف لأي particle أو أي جسم طبعا بنحلل السرعة
+
+9
+00:00:34,130 --> 00:00:37,830
+الابتدائية إلى سرعة ابتدائية باتجاه X أو V0 X اللي
+
+10
+00:00:37,830 --> 00:00:42,890
+هي عبارة عن V0 Cos θ و V0 Y اللي هي عبارة عن V0
+
+11
+00:00:42,890 --> 00:00:48,730
+Sin θ the positive x direction is horizontal and to
+
+12
+00:00:48,730 --> 00:00:52,050
+the right and the y direction is vertical and
+
+13
+00:00:52,050 --> 00:00:56,230
+positive upward بالنسبة للمقضوفة بنكون قدفينها
+
+14
+00:00:56,230 --> 00:00:59,790
+احنا باتجاه ال x direction اللي هي اللي .. اللي ..
+
+15
+00:00:59,790 --> 00:01:04,450
+اللي هو الاتجاه الأفقي لمحور x و .. و
+
+16
+00:01:04,450 --> 00:01:09,390
+بعدين بالنسبة للمحور y بيكون عمودية في اتجاه ال y
+
+17
+00:01:09,390 --> 00:01:14,600
+الموجبة اللي هي upwardالفعالية المهمة بالنسبة للتجارب
+
+18
+00:01:14,600 --> 00:01:20,740
+البروجيكتية في النتائج هي أن في شغلات مهمة
+
+19
+00:01:20,740 --> 00:01:26,880
+بالنسبة لحقائق خلال التجارب يعني العملية تبين إن
+
+20
+00:01:26,880 --> 00:01:29,700
+ال horizontal and vertical motion are completely
+
+21
+00:01:29,700 --> 00:01:34,760
+independent of each otherالحركة الأفقية و الحركة
+
+22
+00:01:34,760 --> 00:01:39,220
+الرأسية لا يعتمدان على بعض this means that
+
+23
+00:01:39,220 --> 00:01:43,940
+motion هذا يعني أن هذه الحركة in one dimension
+
+24
+00:01:43,940 --> 00:01:46,900
+has no effect on .. no motion in the other
+
+25
+00:01:46,900 --> 00:01:50,920
+direction يعني الحركة باتجاه ال X لا تؤثر على
+
+26
+00:01:50,920 --> 00:01:55,020
+الحركة باتجاه Y لكن هناك عامل مشترك بين ال X و ال
+
+27
+00:01:55,020 --> 00:01:59,340
+Y هو الزمن الزمن خلال ال X هو يساوي الزمن خلال
+
+28
+00:01:59,340 --> 00:02:02,900
+الحركة بال Y if a basketball is tossed in a
+
+29
+00:02:02,900 --> 00:02:07,380
+parabola  كورة لو أنا قذفت كرة بشكل parabola أو شكل
+
+30
+00:02:07,380 --> 00:02:11,000
+قطع ناقص زي ما بالشكل the motion in y direction
+
+31
+00:02:11,000 --> 00:02:14,320
+will look like a ball tossed straight up فالحركة
+
+32
+00:02:14,320 --> 00:02:18,260
+بتكون كأنه كرة أنا قذفتها في خط مستقيم إلى أعلى
+
+33
+00:02:18,260 --> 00:02:25,860
+تحت أثير الجاذبيةطبعا الشكل ال .. ال .. الأسفل بي
+
+34
+00:02:25,860 --> 00:02:28,840
+.. shows the effect of various initial angles
+
+35
+00:02:28,840 --> 00:02:36,020
+بيبين تأثير طبعا حركة مقضوفة في اتجاه معين و
+
+36
+00:02:36,020 --> 00:02:40,840
+بزوايا مختلفة بيعطيني طبعا ال range أيضا مختلف كما
+
+37
+00:02:40,840 --> 00:02:45,120
+هو مبين بالشكل بلاحظ في هذه المنطقة يعني قدفته
+
+38
+00:02:45,120 --> 00:02:49,280
+بزاوية ثلاثين درجة ال range كان مئة لو أنا زوّدت
+
+39
+00:02:49,280 --> 00:02:55,240
+الزاوية إلى 45 درجة ال range هيصير 230 لو أنا
+
+40
+00:02:55,240 --> 00:03:01,320
+قدفته مثلا بزاوية 45 ال range هيكون 260 و لو قدفته
+
+41
+00:03:01,320 --> 00:03:05,820
+بزاوية 60 ال range طبعا هي .. هيبدأ ال range يقل
+
+42
+00:03:05,820 --> 00:03:11,620
+زي بالظبط ال .. اللي هي الزاوية 30كمان إضافة لإنه
+
+43
+00:03:11,620 --> 00:03:15,380
+لو أنا قدفته بزاوية 75 ال range هيكون بالظبط لو
+
+44
+00:03:15,380 --> 00:03:20,860
+أنا قدفته بزاوية 15 فاحنا بنحكي هنا إنه
+
+45
+00:03:20,860 --> 00:03:24,520
+complementary values of the initial angle θ result
+
+46
+00:03:24,520 --> 00:03:28,720
+in the same value of the range R يعني الزوايا اللي
+
+47
+00:03:28,720 --> 00:03:35,680
+بتتمم بعضها بيكون ال range متساوي يعني ال 15 و 75  و ال 30 و 60
+
+48
+00:03:35,680 --> 00:03:40,900
+فال range بتلع نفس النقطة ال 30 و ال 60 برضه ال
+
+49
+00:03:40,900 --> 00:03:45,840
+range نفس النقطة ال 45 برضه مع يعني ال 45 بتعطي نفس
+
+50
+00:03:45,840 --> 00:03:49,760
+ال .. ال range .. نفس ال range هذا يعني الشكل
+
+51
+00:03:49,760 --> 00:03:54,120
+من خلال تجارب عملية لو أنا قدفته بنفس السرعة اللي
+
+52
+00:03:54,120 --> 00:03:58,760
+هي V initial 50 مع اختلاف الزوايا بنجد أنه إذا قذفت
+
+53
+00:03:58,760 --> 00:04:04,120
+الجسم بزوايا تتمم بعضها فبيحصل على نفس ال range نفس
+
+54
+00:04:04,120 --> 00:04:07,680
+ال range اللي هو اللي .. اللي هي المسافة باتجاه ال
+
+55
+00:04:07,680 --> 00:04:12,820
+X-axis بنسميه ال range أو المدى الشكل السابعة is
+
+56
+00:04:12,820 --> 00:04:15,600
+an experiment illustrating the independence of
+
+57
+00:04:15,600 --> 00:04:19,400
+horizontal and vertical motion. The gun is aimed
+
+58
+00:04:19,400 --> 00:04:22,220
+directly at the target ball and fired at the
+
+59
+00:04:22,220 --> 00:04:27,740
+instant the target is released في الشكل التالي
+
+60
+00:04:27,740 --> 00:04:32,740
+المرفق أدناه هذا الشكل يوضح أن اللي هي الحركة ال
+
+61
+00:04:32,740 --> 00:04:35,540
+أفقية اللي هي الحركة الأفقية و الحركة الرأسية
+
+62
+00:04:35,750 --> 00:04:40,850
+لا يعتمدان على بعض لو عندي أنا طبعا بندقية قذفت
+
+63
+00:04:40,850 --> 00:04:46,230
+منها target اللي هي هدف directly and fired at the
+
+64
+00:04:46,230 --> 00:04:49,630
+instant the target is released. In the absence of
+
+65
+00:04:49,630 --> 00:04:52,570
+gravity the projectile would hit the target
+
+66
+00:04:52,570 --> 00:04:55,950
+because the target would not move. However, the
+
+67
+00:04:55,950 --> 00:05:00,610
+projectile still hits the target in the presence
+
+68
+00:05:00,610 --> 00:05:03,410
+of gravity. That means the projectile is
+
+69
+00:05:03,410 --> 00:05:07,070
+falling through the same vertical displacement as
+
+70
+00:05:07,070 --> 00:05:11,750
+the target despite its horizontal motion. طبعا هنفسر هذا
+
+71
+00:05:11,750 --> 00:05:17,330
+الكلام أنه في عندي هنا بندقية البندقية طبعا رميت
+
+72
+00:05:17,330 --> 00:05:22,400
+قذيفة معينة هذه القذيفة رميتها بحركة projectile
+
+73
+00:05:22,400 --> 00:05:26,820
+motion حركة مقذوفة على شكل parabola في نفس اللحظة
+
+74
+00:05:26,820 --> 00:05:31,140
+في عندي هدف برضه رمى مقذوفة مقذوفة اللي هي الهدف
+
+75
+00:05:31,140 --> 00:05:35,840
+مع مقذوفة البندقية تلاقوا في نقطة وتصادموا في نقطة
+
+76
+00:05:35,840 --> 00:05:41,850
+معينة بنلاحظ أن ال .. البندقية رميت اللي هي ال ..
+
+77
+00:05:41,850 --> 00:05:47,430
+ال .. ال .. ال .. رميت المقذوفة طبعا بزاوية أو
+
+78
+00:05:47,430 --> 00:05:51,110
+بسرعة ابتدائية horizontally و بالتالي فهي تحركت في
+
+79
+00:05:51,110 --> 00:05:54,890
+هذه الحركة حركة اللي هي projectile motion و تصعد و
+
+80
+00:05:54,890 --> 00:05:56,670
+تتلاقين في نفس النقطة
+
+81
+00:05:59,820 --> 00:06:03,560
+بصفة عامة معادلة the equation of constant
+
+82
+00:06:03,560 --> 00:06:08,860
+acceleration are developed. These topics will be covered separately
+
+83
+00:06:08,860 --> 00:06:12,720
+for both the X direction and Y direction بالنسبة
+
+84
+00:06:12,720 --> 00:06:16,100
+للمقذوفات طبعا في معادلة الحركة بالنسبة للمقذوفات
+
+85
+00:06:16,100 --> 00:06:21,460
+بنستخدم معادلة لمحور X معادلة لمحور Yأي مختلفة
+
+86
+00:06:21,460 --> 00:06:29,040
+مهمة هي أن السرعة الأولى الآن لديها جزئين السرعة
+
+87
+00:06:29,040 --> 00:06:34,000
+الأولى ستكون V0 في اتجاه X و V0 في اتجاه Y ونفرض
+
+88
+00:06:34,000 --> 00:06:38,140
+أن T تساوي 0 فالمقذوف يترك الأصل مع
+
+89
+00:06:38,140 --> 00:06:42,320
+السرعة الأولى V0 أي مقذوف بكون أنا رميتها بسرعة
+
+90
+00:06:42,320 --> 00:06:46,930
+ابتدائية V0 هذه السرعة الابتدائية تميل بزاوية θ0
+
+91
+00:06:46,930 --> 00:06:53,510
+وبالتالي فاحنا بنحلل ال V0 إلى V0 X و V0 Y V0 X
+
+92
+00:06:53,510 --> 00:07:00,910
+ستكون V0 Cos θ0 و V0 Y ستساوي V0 Sin θ0  Velocity
+
+93
+00:07:00,910 --> 00:07:06,250
+vector makes an angle θ اللي هي السرعة تميل
+
+94
+00:07:06,250 --> 00:07:10,650
+بزاوية θ أو تتجه بزاوية θ with a horizontal θ0
+
+95
+00:07:10,650 --> 00:07:14,560
+تسمى زاوية القذف then
+
+96
+00:07:14,560 --> 00:07:21,280
+from بالنسبة للشكل نلاحظ أن بنحلل ال V0 إلى V0X
+
+97
+00:07:21,280 --> 00:07:27,880
+بتساوي V0 Cos θ و V0Y V0 Sin θ V0X بنسميها the
+
+98
+00:07:27,880 --> 00:07:31,360
+initial velocity في ال X direction اللي هي عبارة
+
+99
+00:07:31,360 --> 00:07:35,520
+عن السرعة الابتدائية في اتجاه ال X و V0Y هي عبارة
+
+100
+00:07:35,520 --> 00:07:38,240
+عن ال initial velocity in the Y direction يعني
+
+101
+00:07:38,240 --> 00:07:42,640
+السرعة الابتدائية في اتجاه ال Y الآن نحدد
+
+102
+00:07:42,640 --> 00:07:46,080
+معادلات الحركة بالنسبة لل X و بالنسبة لل Y في ال
+
+103
+00:07:46,080 --> 00:07:49,540
+two dimension في عندي طبعا ثلاث معادلات لل X و ثلاث
+
+104
+00:07:49,540 --> 00:07:54,520
+معادلات لل Y لو أنا تحركت بال X axis ف VX بتساوي
+
+105
+00:07:54,520 --> 00:08:00,030
+V not X زائد AX T و Delta X = V NOT X T + نص A X T تربيع
+
+106
+00:08:00,030 --> 00:08:04,470
+و V X تربيع = V NOT X تربيع + اتنين A X Delta X
+
+107
+00:08:04,470 --> 00:08:07,310
+هذه معادلات الحركة اللي احنا اشتغلنا عليهم في
+
+108
+00:08:07,310 --> 00:08:11,650
+الفصول السابقة لكن هنا في في المقذوف بنلاحظ أن ال
+
+109
+00:08:11,650 --> 00:08:18,550
+A Xالـ A في اتجاه ال X هي طبعا تساوي 0 لإن الحركة
+
+110
+00:08:18,550 --> 00:08:23,450
+باتجاه ال X مافي تسارع باتجاه ال X وبالتالي ال
+
+111
+00:08:23,450 --> 00:08:26,470
+A X اللي هو يتحرك بالنسبة لل X بتسارع .. بسرعة
+
+112
+00:08:26,470 --> 00:08:30,890
+ثابتة وبالتالي ال A X بالنسبة لهذه المعادلة هتساوي
+
+113
+00:08:30,890 --> 00:08:36,230
+0 بالنسبة للمقذوف الآن V Note X بتساوي V Note
+
+114
+00:08:36,230 --> 00:08:41,930
+Cos θ إذا بالنسبة لل Y Direction هناخد ال V Y
+
+115
+00:08:42,430 --> 00:08:50,600
+بتساوي V Not Y زائد A Y T و delta y بتساوي v not
+
+116
+00:08:50,600 --> 00:08:55,220
+y T + نص a T تربيع و v y تربيع بتساوي v not y
+
+117
+00:08:55,220 --> 00:08:59,020
+تربيع + 2 a y Delta y طبعا هذه المعادلة احنا اشتغلنا
+
+118
+00:08:59,020 --> 00:09:03,220
+عليها بالنسبة ل ال free falling يعني أي معادلة
+
+119
+00:09:03,220 --> 00:09:06,600
+فيها اللي هي ال a y اللي هي أنا هعوض عنها بال
+
+120
+00:09:06,600 --> 00:09:10,600
+minus g لإنها تتحرك تحت تأثير influence of
+
+121
+00:09:10,600 --> 00:09:14,540
+acceleration of gravity فبالتالي ال a هذا ال a y
+
+122
+00:09:14,540 --> 00:09:19,030
+هو هيتحرك تحت تأثير الجاذبية لكن a x مش موجودة
+
+123
+00:09:19,030 --> 00:09:24,370
+وبالتالي فاحنا لآن معادلات المقذوفات v not y
+
+124
+00:09:24,370 --> 00:09:28,970
+بتساوي v not sin θ و ال ay is constant اذا
+
+125
+00:09:28,970 --> 00:09:31,830
+projectile speed v can be calculated from its
+
+126
+00:09:31,830 --> 00:09:34,930
+components of velocity ممكن أنا أحسب قيمة v
+
+127
+00:09:34,930 --> 00:09:39,090
+بالنسبة لمركبات اللي هي بالنسبة للسرعة النهائية لأي
+
+128
+00:09:39,090 --> 00:09:43,930
+مقذوف اللي هي v ك magnitude كقيمة بتساوي جزر Vx
+
+129
+00:09:43,930 --> 00:09:48,830
+تربيع زائد Vy تربيع The angle that the velocity
+
+130
+00:09:48,830 --> 00:09:52,530
+vector makes with the x-axis is given by طبعا هذا
+
+131
+00:09:52,530 --> 00:09:58,790
+اللي هي ال direction لل result بتساوي tan inverse
+
+132
+00:09:58,790 --> 00:10:04,900
+Vy على Vx طبعا احنا بنعرف الزاوية إذا كانت موجبة أو
+
+133
+00:10:04,900 --> 00:10:09,220
+سالبة أو إذا كانت في الربع الثاني أو الربع الثالث
+
+134
+00:10:09,220 --> 00:10:15,960
+بنضيف لها 180 حسب إشارة vy و vx إذا كانت vy موجبة
+
+135
+00:10:15,960 --> 00:10:20,280
+و vx موجبة فبتكون الزاوية طبعا في الربع الأول إذا
+
+136
+00:10:20,280 --> 00:10:23,940
+كانت vy موجبة و vx سالبة بتكون في الربع الثاني إذا
+
+137
+00:10:23,940 --> 00:10:29,330
+كانت vy سالبة أو vx سالبة بتكون في الربع الثالث
+
+138
+00:10:29,330 --> 00:10:33,450
+إذا كانت vy سالبة و vx موجبة بتكون في الربع
+
+139
+00:10:33,450 --> 00:10:39,730
+الرابع لكن إذا كان عندنا V التي هي θ كانت موجبة
+
+140
+00:10:39,730 --> 00:10:43,170
+في الربع الثاني أو الثالث بنضيف لها ال 180
+
+141
+00:10:43,170 --> 00:10:49,820
+كما درسناه سابقا this formula for θ طبعا as .. هذا
+
+142
+00:10:49,820 --> 00:10:52,400
+الكلام  حكينا as previously stated must be
+
+143
+00:10:52,400 --> 00:10:55,060
+used with care because the inverse tangent
+
+144
+00:10:55,060 --> 00:10:59,140
+function returns values only between minus 90 and
+
+145
+00:10:59,140 --> 00:11:03,400
+plus 90. Adding 180 is necessary for vectors lying
+
+146
+00:11:03,400 --> 00:11:06,960
+in the second or third quadrant الان هنا يحكي لي إذا
+
+147
+00:11:06,960 --> 00:11:12,360
+كانت الزاوية تقع أو المحصلة تقع بالربع الثاني أو
+
+148
+00:11:12,360 --> 00:11:17,380
+الثالث فاحنا بنضيف لها 180 درجة إذا كانت موجودة في
+
+149
+00:11:17,380 --> 00:11:20,800
+الربع second or third quadrant طبعا هذا ببين
+
+150
+00:11:20,800 --> 00:11:25,900
+من خلال vy و vx حسب إشارة vy و vx ممكن احنا نعرف
+
+151
+00:11:25,900 --> 00:11:31,120
+المحصلة موجودة في أي ربع assuming air
+
+152
+00:11:31,120 --> 00:11:35,660
+friction is negligible طبعا مع إهمال احتكاك الهواء
+
+153
+00:11:35,660 --> 00:11:38,500
+the acceleration in the x direction is zero زي ما
+
+154
+00:11:38,500 --> 00:11:42,180
+حكينا ال ax باتجاه ال x بتساوي صفر لإنه اللي هي
+
+155
+00:11:42,180 --> 00:11:45,320
+because air resistance is neglected. This means that
+
+156
+00:11:45,320 --> 00:11:48,740
+ax تساوي صفر و the projectile velocity
+
+157
+00:11:48,740 --> 00:11:51,500
+component along the x direction remains constant
+
+158
+00:11:51,500 --> 00:11:56,460
+فاللي هي مركبة السرعة باتجاه ال x axis بتكون مقدار
+
+159
+00:11:56,460 --> 00:12:01,900
+ثابت وبالتالي a تساوي 0 لأنها تتحرك بسرعة ثابتة
+
+160
+00:12:01,900 --> 00:12:05,760
+فال a باتجاه ال x بتساوي 0 if the initial value of
+
+161
+00:12:05,760 --> 00:12:09,080
+the velocity component in the x direction is v not
+
+162
+00:12:09,080 --> 00:12:12,400
+x بتساوي v not cosine theta معناه الكلام this
+
+163
+00:12:12,400 --> 00:12:18,500
+is also the value of vx at any later time يعني أنه
+
+164
+00:12:18,700 --> 00:12:23,020
+على طول مسار المقذوف لو كانت V NOT X بتساوي V NOT
+
+165
+00:12:23,020 --> 00:12:28,240
+Cos θ NOT فال V النهائية للمقذوف على طول المسار
+
+166
+00:12:28,240 --> 00:12:33,820
+ستساوي V NOT X بتساوي V NOT Cos θ NOT يعني VX
+
+167
+00:12:33,820 --> 00:12:39,600
+بتساوي V NOT X على طول مسار المقذوف كما عرفناه
+
+168
+00:12:39,600 --> 00:12:45,550
+سابقا وبالتالي Vx بتساوي V not X بتساوي V not cos θ
+
+169
+00:12:45,550 --> 00:12:50,810
+بتساوي constant على طول مسار المقذوف وعلى كل نقطة من
+
+170
+00:12:50,810 --> 00:12:55,150
+المقذوف الـ Horizontal displacement Delta X
+
+171
+00:12:55,150 --> 00:12:59,510
+بتساوي V not X في T طبعا ال AX بتساوي 0  راح
+
+172
+00:12:59,510 --> 00:13:03,450
+تساوي V not cos θ not في T هذا هو Delta X أو ال
+
+173
+00:13:03,450 --> 00:13:07,370
+range أو المدى اللي المقذوف سيمشي خلاله
+
+174
+00:13:10,600 --> 00:13:13,540
+بالنسبة للحركة بالـ y-axis أو بالـ y-direction
+
+175
+00:13:13,540 --> 00:13:17,580
+نقوم بـ substituting a y طبعا راح نعوض عن كل ال
+
+176
+00:13:17,580 --> 00:13:21,360
+a باتجاه ال y اللي هي minus g و v not y تساوي
+
+177
+00:13:21,360 --> 00:13:26,060
+v not sin θ كما هو موضح في المعادلات السابقة طبعا
+
+178
+00:13:26,060 --> 00:13:31,420
+عوضنا عن ال a yحطينا بدلا منها minus g لإن الجسم بالنسبة
+
+179
+00:13:31,4
+
+223
+00:16:35,310 --> 00:16:39,250
+إلى أعلى وبدأ أمسكها لازم أنا أرميها بخط مستقيم و
+
+224
+00:16:39,250 --> 00:16:45,700
+بأمسكها بنفس اللحظة بالنسبة لهذا الـ quiz تلاتة خمسة
+
+225
+00:16:45,700 --> 00:16:51,660
+as the projectile moves in its parabolic path, where are
+
+226
+00:16:51,660 --> 00:16:53,840
+the velocity and acceleration vectors perpendicular
+
+227
+00:16:53,840 --> 00:16:58,160
+to each other؟ الآن لو أنا بالنسبة لحركة المقذوفة هي
+
+228
+00:16:58,160 --> 00:17:02,000
+حركة بالشكل هذا، المقذوفة السؤال بيحكي لوين بتكون
+
+229
+00:17:02,000 --> 00:17:05,220
+الـ velocity والـ acceleration متعامدات على بعض؟
+
+230
+00:17:05,220 --> 00:17:09,640
+طبعاً لكل مسار المقذوفة، الـ acceleration بتكون
+
+231
+00:17:09,640 --> 00:17:15,340
+عمودية إلى أسفل، والسرعة بتكون مماسّ ل... مماسّ لل...
+
+232
+00:17:15,340 --> 00:17:19,700
+للخط ال... الخط الم... مسار المقذوفة، وبالتالي عند
+
+233
+00:17:19,700 --> 00:17:23,780
+أعلى نقطة بتكون... بيكون التسارع والسرعة متعامدتان
+
+234
+00:17:23,780 --> 00:17:26,960
+على بعض. نشوف إيش هنا عامل everywhere along the
+
+235
+00:17:26,960 --> 00:17:31,780
+projectile? everywhere along the projectile? لا طبعاً
+
+236
+00:17:31,780 --> 00:17:35,300
+مش طول مسار المقذوفة أن التسارع عمودي على السرعة.
+
+237
+00:17:35,300 --> 00:17:39,440
+نمر اثنين: at the peak of its path. فعلاً على قمة أو
+
+238
+00:17:39,440 --> 00:17:43,320
+في الـ maximum، عند الـ maximum height بتكون التسارع
+
+239
+00:17:43,320 --> 00:17:48,000
+والسرعة عموديتان على بعض. الـ C بيحكي: nowhere along
+
+240
+00:17:48,000 --> 00:17:51,040
+its path. نمرة D بيحكي: not enough information is
+
+241
+00:17:51,040 --> 00:17:54,940
+given. طبعاً الـ C خطأ، وD خطأ، والـ B هي الصح، أنه
+
+242
+00:17:54,940 --> 00:18:00,140
+التسارع والسرعة بيكونان عموديتان عند أعلى نقطة.
+
+243
+00:18:00,140 --> 00:18:04,080
+التسارع والسرعة بتكونان متعامدتان عند الـ maximum
+
+244
+00:18:04,080 --> 00:18:07,580
+height، أو عند أعلى نقطة اللي اتفقنا عليها، أعلى
+
+245
+00:18:07,580 --> 00:18:11,560
+نقطة بتكون V النهائية بالنسبة للـ Y بيساوي 0، وV
+
+246
+00:18:11,560 --> 00:18:16,550
+النهائية بالنسبة للـ X بيساوي V<sub>x</sub>. بالنسبة لهذه
+
+247
+00:18:16,550 --> 00:18:19,650
+الجزئية اللي هي problem solving strategy، يعني كيف
+
+248
+00:18:19,650 --> 00:18:23,690
+أنا ممكن أحل المسائل بالنسبة للـ projectile motion.
+
+249
+00:18:23,690 --> 00:18:28,130
+النمرة واحد: select a coordinate system and sketch
+
+250
+00:18:28,130 --> 00:18:30,710
+the path of the projectile, including initial and
+
+251
+00:18:30,710 --> 00:18:34,110
+final position, velocity, and acceleration. بالأول
+
+252
+00:18:34,110 --> 00:18:39,450
+أنا بحدد المحاور، وبأرسم محاور تجاه X وتجاه Y، و
+
+253
+00:18:39,450 --> 00:18:42,170
+بحدد اللي هي الـ initial والـ final position.
+
+254
+00:18:42,170 --> 00:18:45,350
+بالنسبة ل... بحدد نقطة البداية ونقطة النهاية.
+
+255
+00:18:45,350 --> 00:18:50,190
+بالنسبة للسرعة والتسارع. بعد هيك Resolve، بحلل الـ
+
+256
+00:18:50,190 --> 00:18:53,170
+initial values اللي لازم أحللها إلى مركباتها
+
+257
+00:18:53,170 --> 00:18:57,330
+بالنسبة لـ X، بالنسبة لـ Y، يعني V الابتدائية بتساوي
+
+258
+00:18:57,330 --> 00:19:05,280
+V<sub>0</sub>X Cos θ، وV<sub>0</sub>Y بتساوي V<sub>0</sub>Y Sin θ. It treats
+
+259
+00:19:05,280 --> 00:19:07,240
+the horizontal motion and the vertical motion
+
+260
+00:19:07,240 --> 00:19:11,040
+independently. بتحل المعادلة الـ Y ومعادلة الـ X كل
+
+261
+00:19:11,040 --> 00:19:14,320
+واحدة على ناحية. بعدين follow the technique for
+
+262
+00:19:14,320 --> 00:19:16,800
+solving a problem with constant velocity to
+
+263
+00:19:16,800 --> 00:19:19,420
+analyze the horizontal motion of the projectile.
+
+264
+00:19:19,420 --> 00:19:24,320
+بعدين ب... بوجد الـ range من محور الـ X اللي هي الـ R
+
+265
+00:19:24,320 --> 00:19:29,720
+أو ΔX بتساوي V<sub>0</sub>X أو V<sub>0</sub> Cos θ في
+
+266
+00:19:29,720 --> 00:19:33,460
+T. Follow the technique of solving a problem with
+
+267
+00:19:33,460 --> 00:19:35,560
+constant acceleration to analyze the vertical
+
+268
+00:19:35,560 --> 00:19:39,160
+motion. بأستخدم التسارع الجاذبية اللي هو ناقص G
+
+269
+00:19:39,160 --> 00:19:44,500
+علشان أحل معادلات الحركة باتجاه الـ Y، وبالتالي أنا
+
+270
+00:19:44,500 --> 00:19:49,600
+ممكن أحل المسائل اللي هي بالنسبة للمقذوفات، مسائل
+
+271
+00:19:49,600 --> 00:19:53,900
+باتجاه X، معادلات باتجاه X، معادلات باتجاه Y، واللي
+
+272
+00:19:53,900 --> 00:19:58,480
+بيربط بينهم هو الزمن. ناخد هذا السؤال اللي هي
+
+273
+00:19:58,480 --> 00:20:03,760
+example تلاتة اثنين: ال... الـ scanners you blame
+
+274
+00:20:03,760 --> 00:20:08,420
+drops a package of emergency ratio to stranded
+
+275
+00:20:08,420 --> 00:20:12,060
+hikers as shown in the figure. في عندي أنا طائرة
+
+276
+00:20:12,060 --> 00:20:17,020
+إنقاذ، رمت package لناس كانوا تائِهين في مكان يعني
+
+277
+00:20:17,020 --> 00:20:20,920
+بوسط الغابة. The plane is traveling، طبعاً هي طائرة
+
+278
+00:20:20,920 --> 00:20:23,820
+الإنقاذ traveling horizontally، هي كانت ماشية
+
+279
+00:20:23,820 --> 00:20:26,980
+horizontally بسرعة أربعين متر في الثانية، يعني هي
+
+280
+00:20:26,980 --> 00:20:31,800
+ماشية بسرعة ابتدائية باتجاه الـ X بتساوي أربعين، على
+
+281
+00:20:31,800 --> 00:20:36,380
+ارتفاع 120 متر. Neglect the air
+
+282
+00:20:36,380 --> 00:20:39,860
+resistance. مطلوب منه نوجد: where does the package
+
+283
+00:20:39,860 --> 00:20:43,380
+strike the ground relative to the point at which
+
+284
+00:20:43,380 --> 00:20:47,590
+it was released؟ يعني هو بده أين تقع اللي هي الـ
+
+285
+00:20:47,590 --> 00:20:51,910
+package أو هذه الشنطة اللي هو رماها للناس لإنقاذهم.
+
+286
+00:20:51,910 --> 00:20:56,050
+أين ستقع إذا كانت هي الطيارة تتحرك بسرعة أربعين
+
+287
+00:20:56,050 --> 00:20:59,450
+متر في الثانية horizontally، وعلى ارتفاع 120 يعني
+
+288
+00:20:59,450 --> 00:21:04,170
+بده الـ range أو بده ΔX. في البداية بدنا نوجد
+
+289
+00:21:04,170 --> 00:21:08,930
+ΔX. طبعاً هي الطائرة... هي الطائرة تتحرك
+
+290
+00:21:08,930 --> 00:21:12,690
+horizontally وليس بزاوية، يعني horizontally، يعني V<sub>0</sub>X
+
+291
+00:21:12,690 --> 00:21:17,030
+40، V<sub>0</sub>Y صفر. رمت الـ package للجماعة
+
+292
+00:21:17,030 --> 00:21:19,850
+اللي تايهين كانت على بعد 120 متر.
+
+293
+00:21:19,850 --> 00:21:24,450
+يعني أربعين، طالب المسافة اللي هي اللي الأفقية، يعني
+
+294
+00:21:24,450 --> 00:21:28,790
+وين هذه الـ package بدها تقع؟ بدنا نحل الآن. عشان نحل
+
+295
+00:21:28,790 --> 00:21:32,460
+في عندي أنا معادلات الحركة باتجاه x، معادلات الحركة
+
+296
+00:21:32,460 --> 00:21:35,320
+باتجاه الـ Y. في البداية find the range of the
+
+297
+00:21:35,320 --> 00:21:39,540
+package، يعني ΔX بالنسبة للـ package. To find the
+
+298
+00:21:39,540 --> 00:21:46,020
+Y displacement، هأحكي أنا: ΔY بتساوي V<sub>0</sub>Y t
+
+299
+00:21:46,020 --> 00:21:51,200
+ناقص نص gt تربيع. الآن substitute Y<sub>0</sub> بتساوي صفر،
+
+300
+00:21:51,200 --> 00:21:57,600
+وV<sub>0</sub>Y كانت صفر لأن الجسم... الجسم... طبعاً
+
+301
+00:21:57,600 --> 00:22:02,080
+الطائرة اتحركت horizontally، معناته V<sub>0</sub>X 40
+
+302
+00:22:02,080 --> 00:22:05,840
+وV<sub>0</sub>Y صفر. الـ Y كانت ناقص 120 لأن أنا رميها
+
+303
+00:22:05,840 --> 00:22:09,830
+لتحت، بحط السالب 120 متر. The final
+
+304
+00:22:09,830 --> 00:22:12,210
+vertical position of the package relative to the
+
+305
+00:22:12,210 --> 00:22:15,910
+airplane is solved for time. طبعاً أنا ببدأ أوجد الزمن
+
+306
+00:22:15,910 --> 00:22:20,690
+اللازم علشان توصل الـ package إلى الأرض. طبعاً أنا
+
+307
+00:22:20,690 --> 00:22:24,650
+عندي معلومات عن الـ Y axis، فبوجد الزمن باتجاه الـ Y.
+
+308
+00:22:24,650 --> 00:22:33,490
+الـ Y هي: V<sub>0</sub>Y(0) في T<sub>0</sub> ناقص نص G(9.8) على 2، طلعت 4.9 في
+
+309
+00:22:33,490 --> 00:22:38,690
+T تربيع. بنوجد T بتساوي 4.5. هذا الزمن اللي أنا
+
+310
+00:22:38,690 --> 00:22:43,970
+استخدمت فيه معادلات Y هو نفس الزمن اللازم للمحور X،
+
+311
+00:22:43,970 --> 00:22:48,260
+فبروح أستخدمه على معادلة اللي هي الـ X. فΔX
+
+312
+00:22:48,260 --> 00:22:52,300
+بتساوي X ناقص X<sub>0</sub> بتساوي V<sub>0</sub> في T. بدنا
+
+313
+00:22:52,300 --> 00:22:57,100
+نعوض عن X<sub>0</sub> بـ صفر، الـ V<sub>0</sub>X كانت 40، والـ
+
+314
+00:22:57,100 --> 00:23:05,000
+T بأوجدها من هنا اللي هي 4.52، فبتطلع عند الـ range
+
+315
+00:23:05,000 --> 00:23:10,980
+أو المسافة اللي هي سقطت فيها الـ package 181 متر. في
+
+316
+00:23:10,980 --> 00:23:14,560
+B طالب find the components of the package velocity
+
+317
+00:23:14,560 --> 00:23:18,500
+at impact. بدنا اللي هي الـ components السرعة
+
+318
+00:23:18,500 --> 00:23:22,100
+النهائية في اتجاه الـ X، والسرعة النهائية في اتجاه
+
+319
+00:23:22,100 --> 00:23:26,360
+الـ Y. اتفقنا في اتجاه الـ X أن السرعة النهائية في
+
+320
+00:23:26,360 --> 00:23:31,280
+اتجاه الـ X ثابتة، ما بتتغير، فV<sub>X</sub> بتساوي V<sub>0</sub>X
+
+321
+00:23:31,280 --> 00:23:34,640
+Cos θ، هي نفسها 40، 40 متر في الثانية.
+
+322
+00:23:35,240 --> 00:23:38,060
+بالنسبة للـ Y، ببدأ أوجد اللي هي السرعة النهائية
+
+323
+00:23:38,060 --> 00:23:44,540
+باتجاه الـ Y، V<sub>Y</sub> بتساوي V<sub>0</sub>Y Sin θ ناقص GT. V<sub>0</sub>Y
+
+324
+00:23:44,540 --> 00:23:49,080
+اللي هي كانت صفر في اتجاه الـ Y، بيبقى عندي
+
+325
+00:23:49,080 --> 00:23:55,600
+الـ G(9.8) في T بيطلع -44.3. الناقص هذه لأنها
+
+326
+00:23:55,600 --> 00:24:01,440
+طبعاً هي نازلة إلى أسفل. عشان القذيفة أو الـ package
+
+327
+00:24:01,440 --> 00:24:08,660
+نزلت لأسفل، فV<sub>Y</sub> بتساوي -44، V<sub>X</sub> ضلتها 40 ثابتة.
+
+328
+00:24:08,660 --> 00:24:13,800
+في C طالب مني find the angle of impact. طبعاً
+
+329
+00:24:13,800 --> 00:24:18,360
+عشان أوجد الزاوية، الزاوية بتساوي tan<sup>-1</sup>(V<sub>Y</sub>/V<sub>X</sub>). V<sub>Y</sub> ناقص
+
+330
+00:24:18,360 --> 00:24:25,680
+44، وV<sub>X</sub> 40. طالما أن V<sub>Y</sub> ناقص 44، وV<sub>Y</sub> موجبة، V<sub>X</sub> موجبة،
+
+331
+00:24:25,680 --> 00:24:31,470
+V<sub>Y</sub> سالبة، وV<sub>X</sub> موجبة، في أي ربع ستكون؟ هذه طبعاً في أي
+
+332
+00:24:31,470 --> 00:24:36,630
+ربع، V<sub>Y</sub> سالبة وV<sub>X</sub> موجبة، ستكون في الربع الرابع. الرابع،
+
+333
+00:24:36,630 --> 00:24:41,290
+وبالتالي ما بضيف لها أنا 180، فبيطلع أنا tan<sup>-1</sup>
+
+334
+00:24:41,290 --> 00:24:47,860
+لهذا الرقم. tan<sup>-1</sup> لـ -1.1 تطلع -48. طبعاً
+
+335
+00:24:47,860 --> 00:24:51,160
+ما بجمعها الـ 180 لأنها موجودة في الربع الرابع. إيش
+
+336
+00:24:51,160 --> 00:24:54,820
+عرفني إنها في الربع الرابع؟ لأن V<sub>Y</sub> سالبة، وV<sub>X</sub>
+
+337
+00:24:54,820 --> 00:24:59,040
+موجبة، فهي في الربع الرابع، وبالتالي أي زاوية في
+
+338
+00:24:59,040 --> 00:25:03,300
+الربع الرابع أو الأول ما بضيف لها 180. إذا كانت في
+
+339
+00:25:03,300 --> 00:25:08,960
+الربع الثاني أو الثالث بضيف لها الـ 180. إن شاء الله
+
+340
+00:25:08,960 --> 00:25:11,860
+المرة الجاية بنكمل باقي اللي هي الأمثلة.
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..6086625be85179ab6a0be548fc0feabc40227ab3
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM_postprocess.srt
@@ -0,0 +1,1360 @@
+1
+00:00:00,000 --> 00:00:04,480
+بسم الله الرحمن الرحيم بستكمل chapter تلاتة و
+
+2
+00:00:04,480 --> 00:00:07,520
+بنستكمل الموضوع اللي هو ال projectile motion اللي
+
+3
+00:00:07,520 --> 00:00:11,820
+هو في المقضوفات حكينا في المقضوفات أنه على طول ما
+
+4
+00:00:11,820 --> 00:00:14,860
+صار المقضوفة the x component of the velocity
+
+5
+00:00:14,860 --> 00:00:18,540
+remained constant يعني المركبة الصينية لا السرعة
+
+6
+00:00:18,830 --> 00:00:23,130
+بتبقى كما هي وفي أعلى ارتفاع بيكون السرعة النهائية
+
+7
+00:00:23,130 --> 00:00:28,090
+باتجاه ال Y بتساوي صفر وفي المنطقة عند منطقة اللي
+
+8
+00:00:28,090 --> 00:00:34,130
+هي القذف لأي particle أو أي جسم طبعا بنحلل السرعة
+
+9
+00:00:34,130 --> 00:00:37,830
+الابتدائية إلى سرعة ابتدائية باتجاه X أو V0 X اللي
+
+10
+00:00:37,830 --> 00:00:42,890
+هي عبارة عن V0 Cos θ و V0 Y اللي هي عبارة عن V0
+
+11
+00:00:42,890 --> 00:00:48,730
+Sin θthe positive x direction is horizontal and to
+
+12
+00:00:48,730 --> 00:00:52,050
+the right and the y direction is vertical and
+
+13
+00:00:52,050 --> 00:00:56,230
+positive upward بالنسبة للمقضوفة بنكون قدفينها
+
+14
+00:00:56,230 --> 00:00:59,790
+احنا باتجاه ال x direction اللي هي اللي .. اللي ..
+
+15
+00:00:59,790 --> 00:01:04,450
+اللي هو الاتجاه القفقي لل x axis لمحور x و .. و
+
+16
+00:01:04,450 --> 00:01:09,390
+بعدين بالنسبة للمحور y بيكون عمودية في اتجاه ال y
+
+17
+00:01:09,390 --> 00:01:14,600
+الموجبة اللي هي upwardالفعل الأهم بالنسبة للتجارب
+
+18
+00:01:14,600 --> 00:01:20,740
+البروجيكتية في الانتصارات هي أن في شغلات مهمة
+
+19
+00:01:20,740 --> 00:01:26,880
+بالنسبة لحقائق خلال التجارب يعني العملية تبين إن
+
+20
+00:01:26,880 --> 00:01:29,700
+ال horizontal and vertical motion are completely
+
+21
+00:01:29,700 --> 00:01:34,760
+independent of each otherالحركة الأفقية و الحركة
+
+22
+00:01:34,760 --> 00:01:39,220
+الرأسية لا يعتمدان على .. على بعض this mean that
+
+23
+00:01:39,220 --> 00:01:43,940
+motion هذا بيعني أنه هذه الحركة in one dimension
+
+24
+00:01:43,940 --> 00:01:46,900
+has no effect on .. no motion in the other
+
+25
+00:01:46,900 --> 00:01:50,920
+direction يعني الحركة باتجاه ال X لا تؤثر على
+
+26
+00:01:50,920 --> 00:01:55,020
+الحركة باتجاه Y لكن هناك عامل مشترك بين ال X و ال
+
+27
+00:01:55,020 --> 00:01:59,340
+Y هو الزمن الزمن خلال ال X هو بساوي الزمن خلال
+
+28
+00:01:59,340 --> 00:02:02,900
+الحركة بال Yif a basketball is tossed in a
+
+29
+00:02:02,900 --> 00:02:07,380
+parabola كبار لو أنا قذفت كرة بشكل parabola أو شكل
+
+30
+00:02:07,380 --> 00:02:11,000
+قطع ناقص زي ما بالشكل the motion in y direction
+
+31
+00:02:11,000 --> 00:02:14,320
+will look like a ball tossed straight up فالحركة
+
+32
+00:02:14,320 --> 00:02:18,260
+بتكون كأنه كرة أنا قذفتها في خط مستقيم إلى أعلى
+
+33
+00:02:18,260 --> 00:02:25,860
+تحت أثير الجاذبيةطبعا الشكل ال .. ال .. الأسفل بي
+
+34
+00:02:25,860 --> 00:02:28,840
+.. shows the effect of various inertial angles
+
+35
+00:02:28,840 --> 00:02:36,020
+بيبين تأثير طبعا حركة مقضوفة في اتجاه معين و
+
+36
+00:02:36,020 --> 00:02:40,840
+بزوايا مختلفة بيعطيني طبعا ال range أيضا مختلف كما
+
+37
+00:02:40,840 --> 00:02:45,120
+هو مبين بالشكل بلاحظ في هذه المنطقة يعني قدفته
+
+38
+00:02:45,120 --> 00:02:49,280
+بزاوية تلاتين درجة ال range كان ميةلو أنا زوّتت
+
+39
+00:02:49,280 --> 00:02:55,240
+الزاوية إلى 30 درجة ال range هيصير 230 لو أنا
+
+40
+00:02:55,240 --> 00:03:01,320
+قدفته مثلا بزاوية 45 ال range هيكون 260 و لو قدفته
+
+41
+00:03:01,320 --> 00:03:05,820
+بزاوية 60 ال range طبعا هي .. هيبدأ ال range يقل
+
+42
+00:03:05,820 --> 00:03:11,620
+زي بالظبط ال .. اللي هي الزاوية 30كمان إضافة لإنه
+
+43
+00:03:11,620 --> 00:03:15,380
+لو أنا قدفته بزاوية 75 ال range هيكون بالظبط لو
+
+44
+00:03:15,380 --> 00:03:20,860
+أنا قدفته بزاوية 15 فاحنا بنحكي هنا إنه
+
+45
+00:03:20,860 --> 00:03:24,520
+complementary value of the initial angle θ result
+
+46
+00:03:24,520 --> 00:03:28,720
+in the same value of the range R يعني الزوايا اللي
+
+47
+00:03:28,720 --> 00:03:35,680
+بتتمم بعضبيكون ال range متساوي يعني ال 15 و 75 90
+
+48
+00:03:35,680 --> 00:03:40,900
+فال range بتلع نفس النقطة ال 30 و ال 60 برضه ال
+
+49
+00:03:40,900 --> 00:03:45,840
+range نفس النقطة ال 45 برضه مع يعني ال 45 بتلع نفس
+
+50
+00:03:45,840 --> 00:03:49,760
+ال .. ال range .. نفس ال range هذا هي يعني الشكل
+
+51
+00:03:49,760 --> 00:03:54,120
+من خلال تجارب عملية لو أنا قدفته بنفس السرعة اللي
+
+52
+00:03:54,120 --> 00:03:58,760
+هي V initial 50 مع اختلاف الزوايا بنجد أنه إذا قدف
+
+53
+00:03:58,760 --> 00:04:04,120
+الجسم بزوايامتممة لبعض فبيحصل على نفس ال range نفس
+
+54
+00:04:04,120 --> 00:04:07,680
+ال range اللي هو اللي .. اللي هي المسافة باتجاه ال
+
+55
+00:04:07,680 --> 00:04:12,820
+X-axis بنسميه ال range أو المدى الشكل السابعة is
+
+56
+00:04:12,820 --> 00:04:15,600
+an experiment illustrated the independence of
+
+57
+00:04:15,600 --> 00:04:19,400
+horizontal and vertical motionThe gun is aimed
+
+58
+00:04:19,400 --> 00:04:22,220
+directly at the target ball and fire at the
+
+59
+00:04:22,220 --> 00:04:27,740
+instant a target is released في الشكل التالي
+
+60
+00:04:27,740 --> 00:04:32,740
+المرفق أدناه هذا الشكل بوضح أنه اللي هي الحركة ال
+
+61
+00:04:32,740 --> 00:04:35,540
+horizontal اللي هي الحركة الأفقية و الحركة الرأسية
+
+62
+00:04:35,750 --> 00:04:40,850
+لا يعتمدان على بعض لو عندي أنا طبعا منضقية قدفت
+
+63
+00:04:40,850 --> 00:04:46,230
+منها target اللي هي هدف directly and fired at the
+
+64
+00:04:46,230 --> 00:04:49,630
+instant the target is released in that absence of
+
+65
+00:04:49,630 --> 00:04:52,570
+the gravity the projectile would hit the target
+
+66
+00:04:52,570 --> 00:04:55,950
+becausethe target would not move however the
+
+67
+00:04:55,950 --> 00:05:00,610
+projectile still hits the target in the presence
+
+68
+00:05:00,610 --> 00:05:03,410
+of the gravity that means the projectile is
+
+69
+00:05:03,410 --> 00:05:07,070
+falling through the same vertical displacement as
+
+70
+00:05:07,070 --> 00:05:11,750
+the target spit a horizontal motion طبعا هنفسر هذا
+
+71
+00:05:11,750 --> 00:05:17,330
+الكلام أنه في عندى هنا بندقية البندقية طبعا رمت
+
+72
+00:05:17,330 --> 00:05:22,400
+قضيفة معينةهذه القذيفة رمتها بحركة projectile
+
+73
+00:05:22,400 --> 00:05:26,820
+motion حركة مقظوفة على شكل برابولة في نفس اللحظة
+
+74
+00:05:26,820 --> 00:05:31,140
+في عندي هدف برضه رمى مقظوفة مقظوفة اللي هي الهدف
+
+75
+00:05:31,140 --> 00:05:35,840
+مع مقظوفة البندقية تلاقوا في نقطة وتصادموا في نقطة
+
+76
+00:05:35,840 --> 00:05:41,850
+معينةبنلاحظ أنه ال .. البندقية رمت اللي هي ال ..
+
+77
+00:05:41,850 --> 00:05:47,430
+ال .. ال .. ال .. رمت المقضوفة بطبعا بزاوية أو
+
+78
+00:05:47,430 --> 00:05:51,110
+بسرعة ابتدائية horizontally و بالتالي فهي مشت في
+
+79
+00:05:51,110 --> 00:05:54,890
+هذه الحركة حركة اللي هي projectile motion و تصعد و
+
+80
+00:05:54,890 --> 00:05:56,670
+متنتين في نفس النقطة
+
+81
+00:05:59,820 --> 00:06:03,560
+بصفة عامة معادلة the equation of constant
+
+82
+00:06:03,560 --> 00:06:08,860
+acceleration developed topics to follow separately
+
+83
+00:06:08,860 --> 00:06:12,720
+for both the X direction and Y direction بالنسبة
+
+84
+00:06:12,720 --> 00:06:16,100
+للمقضوفات طبعا في معادلة الحركة بالنسبة للمقضوفات
+
+85
+00:06:16,100 --> 00:06:21,460
+بنستخدم معادلة لمحور X معادلة لمحور Yأي مختلفة
+
+86
+00:06:21,460 --> 00:06:29,040
+مهمة هي أن السرعة الأولى الآن لديها 2 جزئين السرعة
+
+87
+00:06:29,040 --> 00:06:34,000
+الأولى ستكون V0 في اتجاه X و V0 في اتجاه Y ونفرض
+
+88
+00:06:34,000 --> 00:06:38,140
+أن T بالساوية 0 فالبروجيكتال يترك الأصلية مع
+
+89
+00:06:38,140 --> 00:06:42,320
+السرعة الأولى V0 أي مخدوفة بكون أنا رميتها بسرعة
+
+90
+00:06:42,320 --> 00:06:46,930
+ابتدائية V0 هذه السرعة الابتدائيةبتميل بزاوية θ0
+
+91
+00:06:46,930 --> 00:06:53,510
+وبالتالي فاحنا بنحلل ال V0 إلى V0 X و V0 Y V0 X
+
+92
+00:06:53,510 --> 00:07:00,910
+هتكون V0 Cos θ0 و V0 Y هتساوي V0 Sin θ0 Velocity
+
+93
+00:07:00,910 --> 00:07:06,250
+vector makes an angle θ اللي هي السرعة بتميل
+
+94
+00:07:06,250 --> 00:07:10,650
+بزاوية θ أو بتتجه بزاوية θ with a horizontal θ0
+
+95
+00:07:10,650 --> 00:07:14,560
+تسمى ال projection angle اللي هي زاوية القذفthen
+
+96
+00:07:14,560 --> 00:07:21,280
+from بالنسبة للشكل بنلاحظ أنه بنحلل ال V0 إلى V0X
+
+97
+00:07:21,280 --> 00:07:27,880
+بتساوي V0 Cos θ و V0Y V0 Sin θ V0X بنسميها the
+
+98
+00:07:27,880 --> 00:07:31,360
+initial velocity في ال X direction اللي هي عبارة
+
+99
+00:07:31,360 --> 00:07:35,520
+عن السرعة الابتدائية في اتجاه ال X و V0Y هي عبارة
+
+100
+00:07:35,520 --> 00:07:38,240
+عن ال initial velocity in the Y direction يعني
+
+101
+00:07:38,240 --> 00:07:42,640
+السرعة الابتدائية في اتجاه ال Yالان بدنا ان نحدد
+
+102
+00:07:42,640 --> 00:07:46,080
+معادلات الحركة بالنسبة لل X و بالنسبة لل Y في ال
+
+103
+00:07:46,080 --> 00:07:49,540
+two dimension في عندى طبعا تلت معادلات لل X و تلت
+
+104
+00:07:49,540 --> 00:07:54,520
+معادلات لل Y لو انا اتحركت بال X axis ف VX بتساوي
+
+105
+00:07:54,520 --> 00:08:00,030
+V not X زائد AXو Delta X V NOT X T نص A X T تربيع
+
+106
+00:08:00,030 --> 00:08:04,470
+و V X تربيع V NOT A X تربيع زائد اتنين A X Delta X
+
+107
+00:08:04,470 --> 00:08:07,310
+دول المعادلة الحركة اللي احنا اشتغلنا عليهم في
+
+108
+00:08:07,310 --> 00:08:11,650
+الفصول السابقة لكن هنا في في المقضوفة بنلاحظ ان ال
+
+109
+00:08:11,650 --> 00:08:18,550
+A Xالـ A في اتجاه ال X هي طبعا بتساوي 0 لإن الحركة
+
+110
+00:08:18,550 --> 00:08:23,450
+بتجاه ال X مافي تسارع بتجاه ال X وبقوا بالتالي ال
+
+111
+00:08:23,450 --> 00:08:26,470
+A X اللي هو بتحرك بالنسبة لل X بتسارع .. بسرعة
+
+112
+00:08:26,470 --> 00:08:30,890
+ثابت وبالتالي ال A X بالنسبة لهذه المعادلة هيتساوي
+
+113
+00:08:30,890 --> 00:08:36,230
+0 بالنسبة للمخضوفة الآن V Note X لكل بتساوي V Note
+
+114
+00:08:36,230 --> 00:08:41,930
+Cos θ إذا بالنسبة لل Y Direction هناخد ال V Y
+
+115
+00:08:42,430 --> 00:08:50,600
+بتساوى V Not Y زائد A Y في Tو delta y بتساوي v not
+
+116
+00:08:50,600 --> 00:08:55,220
+y t زي نص a t تربيع و v y تربيع بتساوي v not y
+
+117
+00:08:55,220 --> 00:08:59,020
+تربيع زي 2 a y دي 8 طبعا هذه المعادلة احنا اشتغلنا
+
+118
+00:08:59,020 --> 00:09:03,220
+عليها بالنسبة ل ال free falling يعني اي معادلة
+
+119
+00:09:03,220 --> 00:09:06,600
+فيها اللي هي ال a y اللي هي انا هعوض عنها بال
+
+120
+00:09:06,600 --> 00:09:10,600
+minus g لإنها بتتحرك ب تحت تأثير influence of
+
+121
+00:09:10,600 --> 00:09:14,540
+acceleration of gravity فوبالتالي ال a هذا ال a y
+
+122
+00:09:14,540 --> 00:09:19,030
+هو هيتحرك تحت تأثير الجاذبية لكن a xمش موجودة
+
+123
+00:09:19,030 --> 00:09:24,370
+وبالتالي فاحنا لان معادلات المقضوفات v not y
+
+124
+00:09:24,370 --> 00:09:28,970
+بتساوي v not sin θ و ال ay is constant اذا
+
+125
+00:09:28,970 --> 00:09:31,830
+projects speed v can be calculated from a
+
+126
+00:09:31,830 --> 00:09:34,930
+component of the velocity ممكن انا احسب قيمة v
+
+127
+00:09:34,930 --> 00:09:39,090
+بنسبة لمركبات اللي هي بالنسبة للسرعة النهائية لأي
+
+128
+00:09:39,090 --> 00:09:43,930
+مقضوفة اللي هي v ك magnitude كقيمة بتساوي جزرVx
+
+129
+00:09:43,930 --> 00:09:48,830
+تربيع زائد Vy تربيع The angle that the velocity
+
+130
+00:09:48,830 --> 00:09:52,530
+vector make with the x-axis is given by طبعا هذا
+
+131
+00:09:52,530 --> 00:09:58,790
+اللي هي ال direction لل result بتساوي 10 inverse
+
+132
+00:09:58,790 --> 00:10:04,900
+Vy على Vx طبعا احنا بنعرف الزاويةإذا كانت موجبة أو
+
+133
+00:10:04,900 --> 00:10:09,220
+سالبة أو إذا كانت في الربع التاني أو الربع التالت
+
+134
+00:10:09,220 --> 00:10:15,960
+بنضيف لها 180 حسب إشارة vy و vx إذا كانت vy موجبة
+
+135
+00:10:15,960 --> 00:10:20,280
+و vx موجبة فبتكون الزاوية طبعا في الربع الأول إذا
+
+136
+00:10:20,280 --> 00:10:23,940
+كانت vy موجبة و vx سالبة بتكون في الربع التاني إذا
+
+137
+00:10:23,940 --> 00:10:29,330
+كانت vyطبعا سالب أو VX سالب بتكون في الربع التالت
+
+138
+00:10:29,330 --> 00:10:33,450
+إذا كانت VY سالب أو VX موجودة بتكون في الربع
+
+139
+00:10:33,450 --> 00:10:39,730
+الرابع لكن إذا كان عندنا V التي هي θ كانت متساوي
+
+140
+00:10:39,730 --> 00:10:43,170
+موجودة في الربع التاني أو التالت بنضيف لها ال 180
+
+141
+00:10:43,170 --> 00:10:49,820
+كما درسناه سابقاthis formula for θ طبعا as .. هذا
+
+142
+00:10:49,820 --> 00:10:52,400
+الكلام احنا حكينا as previously stated must be
+
+143
+00:10:52,400 --> 00:10:55,060
+used with care because the inverse tangent
+
+144
+00:10:55,060 --> 00:10:59,140
+function retain value only between minus 90 and
+
+145
+00:10:59,140 --> 00:11:03,400
+plus 90 adding 180 is necessary for vector lying
+
+146
+00:11:03,400 --> 00:11:06,960
+in the second third quadrant الان هنا بيحكيلي اذا
+
+147
+00:11:06,960 --> 00:11:12,360
+كانت الزاوية تقع او المحصرة تقع بالربع التاني او
+
+148
+00:11:12,360 --> 00:11:17,380
+التالت فاحنا بنضيف لها180 درجة إذا كانت موجودة في
+
+149
+00:11:17,380 --> 00:11:20,800
+الربع second or third quadrant طبعا هذا احنا بيبين
+
+150
+00:11:20,800 --> 00:11:25,900
+من خلال vy و vx حسب إشارة vy و vx ممكن احنا نعرف
+
+151
+00:11:25,900 --> 00:11:31,120
+موجودة هي بأي ربع هي المحصلة بأي ربعassuming air
+
+152
+00:11:31,120 --> 00:11:35,660
+friction is negligible طبعا مع اهمال احتكاك الهواء
+
+153
+00:11:35,660 --> 00:11:38,500
+the acceleration in x direction is zero زي ما
+
+154
+00:11:38,500 --> 00:11:42,180
+حكينا ال ax بتجاه ال x بتساوي zero لإنه اللي هي
+
+155
+00:11:42,180 --> 00:11:45,320
+because air resistance is neglected this mean that
+
+156
+00:11:45,320 --> 00:11:48,740
+ax بتساوي zero and the projectile velocity
+
+157
+00:11:48,740 --> 00:11:51,500
+component along the x direction remain constant
+
+158
+00:11:51,500 --> 00:11:56,460
+فاللي هي مراكبة السرعة بتجاه ال x axis بتكون مقدار
+
+159
+00:11:56,460 --> 00:12:01,900
+ثابت وبالتالي ال aتساوي 0 لأنها بتتحرك بسرعة ثابتة
+
+160
+00:12:01,900 --> 00:12:05,760
+فال a بتجاه ال x بتساوي 0 if the initial value of
+
+161
+00:12:05,760 --> 00:12:09,080
+the velocity component in the x direction is v not
+
+162
+00:12:09,080 --> 00:12:12,400
+x بتساوي v not cosine of theta معناه الكلام this
+
+163
+00:12:12,400 --> 00:12:18,500
+is also the value of vx at any later time يعني أنه
+
+164
+00:12:18,700 --> 00:12:23,020
+على طول مسار المقضوفة لو كانت V NOT X بتساوي V NOT
+
+165
+00:12:23,020 --> 00:12:28,240
+Cos θ NOT فال V النهائية للمقضوفة على طول المسار
+
+166
+00:12:28,240 --> 00:12:33,820
+هتساوي V NOT X بتساوي V NOT Cos θ NOT يعني VX
+
+167
+00:12:33,820 --> 00:12:39,600
+بتساوي V NOT X على طول مسار المقضوفة كما عرفناه
+
+168
+00:12:39,600 --> 00:12:45,550
+سابقا وبالتاليVx بتساوي V not X بتساوي V not cos θ
+
+169
+00:12:45,550 --> 00:12:50,810
+بتساوي constant لطول مسار المقظوفة وعلى كل نقطة من
+
+170
+00:12:50,810 --> 00:12:55,150
+المقظوفة الـ Horizontal displacement Delta X
+
+171
+00:12:55,150 --> 00:12:59,510
+بتساوي V not X في T طبعا ال AX بتساوي 0 راحة
+
+172
+00:12:59,510 --> 00:13:03,450
+بتساوي V not cos θ not في T هذا هو Delta X أو ال
+
+173
+00:13:03,450 --> 00:13:07,370
+range أو المدى اللي المقظوفة هتمشي خلاله
+
+174
+00:13:10,600 --> 00:13:13,540
+بالنسبة للحركة بالـ y-axis أو بالـ y-direction
+
+175
+00:13:13,540 --> 00:13:17,580
+نعمل الـ substituting a y طبعاً راح اعوض عن كل ال
+
+176
+00:13:17,580 --> 00:13:21,360
+a باتجاه ال y اللي هي minus g and v not y بالساوية
+
+177
+00:13:21,360 --> 00:13:26,060
+v not sin θ كما هو مضح في المعادلات السابقة طبعا
+
+178
+00:13:26,060 --> 00:13:31,420
+رفعنا ال a yحطينا بدالها minus g لإن الجسم بالنسبة
+
+179
+00:13:31,420 --> 00:13:35,680
+للمقضوفة بتحرك تحت أثير الجاذبية باتجاه ال y-axis
+
+180
+00:13:35,680 --> 00:13:40,020
+بالنسبة ل ال x-axis فالax دائما بتساوي zero لإن
+
+181
+00:13:40,020 --> 00:13:45,120
+السرعة ثابتة باتجاه ال x the important facts of
+
+182
+00:13:45,120 --> 00:13:47,920
+the projectile motion can be summarized as the
+
+183
+00:13:47,920 --> 00:13:52,850
+follow في بعض الملاحظات والحقائق بالنسبة لالحركة
+
+184
+00:13:52,850 --> 00:13:57,490
+المقضوفات أول حاجة احنا بنهمل مقاومة الهواء
+
+185
+00:13:57,490 --> 00:14:01,110
+provided air resistance is negligible the
+
+186
+00:14:01,110 --> 00:14:03,530
+horizontal component of the velocity vx remain
+
+187
+00:14:03,530 --> 00:14:07,570
+constant أول شيء بنهمل مقاومة الهواء زي ما حكينا
+
+188
+00:14:07,570 --> 00:14:12,710
+أن السرعة النهائية لطول مسار المقضوف هتساوي السرعة
+
+189
+00:14:12,710 --> 00:14:17,140
+الابتدائية v not xbecause there is no horizontal
+
+190
+00:14:17,140 --> 00:14:21,440
+component of the acceleration وبالتالي VX ثابتة
+
+191
+00:14:21,440 --> 00:14:27,680
+معناه الكلام ان ال AX بتساوي 0 في اتجاه ال X the
+
+192
+00:14:27,680 --> 00:14:31,060
+vertical component of the acceleration بالنسبة
+
+193
+00:14:31,060 --> 00:14:36,320
+للمركبة الرأسية لاتساره بساوي طبعا هي بتتحرك حركة
+
+194
+00:14:36,320 --> 00:14:39,880
+حركة كأنها free falling بتتحرك تحت اثير جذبية
+
+195
+00:14:39,880 --> 00:14:43,040
+بتساوي minus Gthe vertical component of the
+
+196
+00:14:43,040 --> 00:14:45,380
+velocity vy and the displacement in the y
+
+197
+00:14:45,380 --> 00:14:48,920
+direction the identical to those to freely falling
+
+198
+00:14:48,920 --> 00:14:54,940
+body بالنسباله إذا قدفنا جسم إلى أعلى ف vy موجبة و
+
+199
+00:14:54,940 --> 00:14:58,880
+ال displacement موجبة لإن احنا متعامل معاه كإنه
+
+200
+00:14:58,880 --> 00:15:03,830
+free falling و إذا قدفت جسم إلى أسفلفالـ VY سالبة
+
+201
+00:15:03,830 --> 00:15:08,370
+والـ displacement سالبة والـ acceleration دائما
+
+202
+00:15:08,370 --> 00:15:13,530
+minus G أو هي عبارة عن G gravity of acceleration
+
+203
+00:15:13,530 --> 00:15:16,690
+وهي عبارة عن ناقص Z downward always downward
+
+204
+00:15:18,250 --> 00:15:20,670
+Projectile motion can be described as a
+
+205
+00:15:20,670 --> 00:15:23,110
+superposition of two independent motions in the x
+
+206
+00:15:23,110 --> 00:15:27,330
+and y direction بالنسبة لحركة المقضفات ممكن أوصفها
+
+207
+00:15:27,330 --> 00:15:31,590
+إن هي عبارة عن حركتين حركة بال X و حركة بال Y و
+
+208
+00:15:31,590 --> 00:15:34,610
+حركة X إلها معادلاتها و حركة Y إلها معادلاتها لا
+
+209
+00:15:34,610 --> 00:15:39,190
+يعتمدوا على بعض ولكن ممكن أربط بينهم بالزمن ممكن
+
+210
+00:15:39,190 --> 00:15:44,070
+أربط بين تنتين بالزمننشوف هذا ال quiz suppose you
+
+211
+00:15:44,070 --> 00:15:47,410
+are carrying a ball and running at constant
+
+212
+00:15:47,410 --> 00:15:51,090
+velocity on level ground you wish to throw a throw
+
+213
+00:15:51,090 --> 00:15:55,090
+the ball and catch it as it comes back down يعني
+
+214
+00:15:55,090 --> 00:15:58,990
+رميت كرة و بدي أنا أمسكها neglecting بدي أحمل
+
+215
+00:15:58,990 --> 00:16:03,990
+مقاومة الهواءshould you throw the ball at an angle
+
+216
+00:16:03,990 --> 00:16:09,250
+of about 45 above the horizontal هل علشان انا احصل
+
+217
+00:16:09,250 --> 00:16:12,330
+على الكرة او كاتش او امسك الكرة هل لازم ان انا
+
+218
+00:16:12,330 --> 00:16:17,710
+اقضفها بزاوية 45 above the horizontalو لا throw
+
+219
+00:16:17,710 --> 00:16:21,730
+the ball straight و لا بدأ .. بدأ أرميها بخط
+
+220
+00:16:21,730 --> 00:16:26,070
+مستقيم عبر الهوى و لا throw the ball straight up
+
+221
+00:16:26,070 --> 00:16:30,250
+in the air and maintain the same speed الأصل أنه
+
+222
+00:16:30,250 --> 00:16:35,310
+عشان أنا طبعا أرميها و بعد هيك أمسكها يعني أرميتها
+
+223
+00:16:35,310 --> 00:16:39,250
+إلى أعلى و بدأ أمسكها لازم أنا أرميها بخط مستقيم و
+
+224
+00:16:39,250 --> 00:16:45,700
+بأمسكها بنفس اللحظةبالنسبة لهذا ال quiz تلاتة خمسة
+
+225
+00:16:45,700 --> 00:16:51,660
+as projectile move in its parabolic path where are
+
+226
+00:16:51,660 --> 00:16:53,840
+the velocity and acceleration vector perpendicular
+
+227
+00:16:53,840 --> 00:16:58,160
+to each otherالان لو انا بالنسبة لحركة المقضوفة هي
+
+228
+00:16:58,160 --> 00:17:02,000
+حركة بالشكل هذا المقضوفة السؤال بيحكي لوين بتكون
+
+229
+00:17:02,000 --> 00:17:05,220
+ال velocity و ال acceleration متعامدات على بعض
+
+230
+00:17:05,220 --> 00:17:09,640
+طبعا لكل مصاري المقضوفة ال acceleration بتكون
+
+231
+00:17:09,640 --> 00:17:15,340
+عمودية إلى أسفل والسرعة بتكون مماس ل .. مماس لل ..
+
+232
+00:17:15,340 --> 00:17:19,700
+للخط ال .. الخط الم .. مصاري المقضوفة وبالتاليعند
+
+233
+00:17:19,700 --> 00:17:23,780
+أعلى نقطة بتكون .. بيكون التسارع والسرعة متعامدة
+
+234
+00:17:23,780 --> 00:17:26,960
+على بعض نشوف إيش هنا عامل everywhere along the
+
+235
+00:17:26,960 --> 00:17:31,780
+projectile everywhere along the projectile لأ طبعا
+
+236
+00:17:31,780 --> 00:17:35,300
+مش لطول مسار المخضوفة إنه التسارع عمودي على السرعة
+
+237
+00:17:35,300 --> 00:17:39,440
+نمر اتنين at the peak of its path فعلا على قمة أو
+
+238
+00:17:39,440 --> 00:17:43,320
+في ال maximum عند ال maximum height بتكون التسارع
+
+239
+00:17:43,320 --> 00:17:48,000
+والسرعة عموديات على بعضالـ C بيحكي ل nowhere along
+
+240
+00:17:48,000 --> 00:17:51,040
+its path نمرا دي بيحكي ل not enough information is
+
+241
+00:17:51,040 --> 00:17:54,940
+given طبعا ال C خطأ و دي خطأ و ال B هي الصح أنه
+
+242
+00:17:54,940 --> 00:18:00,140
+التسارع والسرعة بيكونوا عموديات عند أعلى نقطة
+
+243
+00:18:00,140 --> 00:18:04,080
+التسارع والسرعة بتكون في متعامدات عند ال maximum
+
+244
+00:18:04,080 --> 00:18:07,580
+height أو عند أعلى نقطة اللي اتفقنا عليها أعلى
+
+245
+00:18:07,580 --> 00:18:11,560
+نقطة بتكون V النهائية بالنسبة لل Y بيساوي 0 و V
+
+246
+00:18:11,560 --> 00:18:16,550
+النهائية بالنسبة لل X بيساوي V not Xبالنسبة لهذه
+
+247
+00:18:16,550 --> 00:18:19,650
+الجزئية اللي هي problem solving strategy يعني كيف
+
+248
+00:18:19,650 --> 00:18:23,690
+أنا ممكن أحل المسائل بالنسبة لل projectile motion
+
+249
+00:18:23,690 --> 00:18:28,130
+النمرة واحد select a coordinate system and sketch
+
+250
+00:18:28,130 --> 00:18:30,710
+the path of the projectile including initial and
+
+251
+00:18:30,710 --> 00:18:34,110
+final position, velocity and acceleration بالأول
+
+252
+00:18:34,110 --> 00:18:39,450
+أنا بحدد المحاورو بأرسم محاول تجاه X وتجاه Y و
+
+253
+00:18:39,450 --> 00:18:42,170
+بحدد اللي هي ال initial و ال final position
+
+254
+00:18:42,170 --> 00:18:45,350
+بالنسبة ل .. بحدد نقطة البداية و نقطة النهاية
+
+255
+00:18:45,350 --> 00:18:50,190
+بالنسبة للسرعة و التسارع بعد هيك Resolve بحلل ال
+
+256
+00:18:50,190 --> 00:18:53,170
+initial values اللي لازم أحللها إلى مركباتها
+
+257
+00:18:53,170 --> 00:18:57,330
+بالنسبة ل X بالنسبة ل Y يعني V الابتدائية بتساوي
+
+258
+00:18:57,330 --> 00:19:05,280
+V0 X Cos θ و V0 Y بتساوي V0 Y هي Sin θIt treats
+
+259
+00:19:05,280 --> 00:19:07,240
+the horizontal motion and the vertical motion
+
+260
+00:19:07,240 --> 00:19:11,040
+independently بتاح المعادلة ال Y ومعادلة ال X كل
+
+261
+00:19:11,040 --> 00:19:14,320
+واحدة على ناحية بعدين follow the technique for
+
+262
+00:19:14,320 --> 00:19:16,800
+solving a problem with constant velocity to
+
+263
+00:19:16,800 --> 00:19:19,420
+analyze the horizontal motion of the projectile
+
+264
+00:19:19,420 --> 00:19:24,320
+بعدين ب .. بوجد ال range من محور ال X اللي هي ال R
+
+265
+00:19:24,320 --> 00:19:29,720
+او Delta X بتساوي V naught X او V naught cos θ في
+
+266
+00:19:29,720 --> 00:19:33,460
+TFollow the technique of solving problem with
+
+267
+00:19:33,460 --> 00:19:35,560
+constant acceleration to analyze the vertical
+
+268
+00:19:35,560 --> 00:19:39,160
+motion بأستخدم التسارق الجاذبية اللى هو ناقص G
+
+269
+00:19:39,160 --> 00:19:44,500
+علشان أحل معادلات الحركة باتجاه ال Y وبالتالي أنا
+
+270
+00:19:44,500 --> 00:19:49,600
+ممكن أحل المسائل اللى هي بالنسبة للمخضفات مسائل
+
+271
+00:19:49,600 --> 00:19:53,900
+باتجاه X معادلات باتجاه X معادلات باتجاه Y واللي
+
+272
+00:19:53,900 --> 00:19:58,480
+بيربط بينهم هو الزمانناخد هذا السؤال اللي هي
+
+273
+00:19:58,480 --> 00:20:03,760
+example تلاتة اتنين ال .. الـ scanners you blame
+
+274
+00:20:03,760 --> 00:20:08,420
+drops package of emergency ratio to standard
+
+275
+00:20:08,420 --> 00:20:12,060
+hackers as shown in the figure في عندي أنا طائرة
+
+276
+00:20:12,060 --> 00:20:17,020
+إنقاذ رمت package لناس كانوا طيهين في مكان يعني
+
+277
+00:20:17,020 --> 00:20:20,920
+بوسط الغابةthe plane is traveling طبعا هي طائرة
+
+278
+00:20:20,920 --> 00:20:23,820
+الإنخاذ traveling horizontally هي كانت ماشية
+
+279
+00:20:23,820 --> 00:20:26,980
+horizontally بسرعة أربعين متر في الثانية يعني هي
+
+280
+00:20:26,980 --> 00:20:31,800
+ماشية بسرعة ابتدائية باتجاه ال X بتساوي أربعين على
+
+281
+00:20:31,800 --> 00:20:36,380
+ارتفاع واحد في عشر أقصى اتنين متر neglect the air
+
+282
+00:20:36,380 --> 00:20:39,860
+resistance مطلوب منه نوجد where does the package
+
+283
+00:20:39,860 --> 00:20:43,380
+strike the ground relative to the point at which
+
+284
+00:20:43,380 --> 00:20:47,590
+it was released يعني هو بده أين تقعاللي هي ال
+
+285
+00:20:47,590 --> 00:20:51,910
+package أو هذه الشنطة اللي هو رماها للناس لإنقاذهم
+
+286
+00:20:51,910 --> 00:20:56,050
+أين ستقع إذا كانت هي الطيارة تتحرك بسرعة أربعين
+
+287
+00:20:56,050 --> 00:20:59,450
+متر في الثاني horizontally وعلى ارتفاع واحد يعني
+
+288
+00:20:59,450 --> 00:21:04,170
+بده ال range أو بده delta X في البداية بدنا نوجد
+
+289
+00:21:04,170 --> 00:21:08,930
+delta X طبعا هي الطائرةهي الطائرة تتحرك
+
+290
+00:21:08,930 --> 00:21:12,690
+horizontally وليس بزاوية يعني horizontally يعني v
+
+291
+00:21:12,690 --> 00:21:17,030
+not x أربعين v not y سفر رمت ال package للجماعة
+
+292
+00:21:17,030 --> 00:21:19,850
+اللي تايهين كانت على بعد واحد في عشر وستين متر
+
+293
+00:21:19,850 --> 00:21:24,450
+يعني أربعين طالب المسافة اللي هي اللي الأفقية يعني
+
+294
+00:21:24,450 --> 00:21:28,790
+وين هذه ال package بدها تقع بدنا نحل الآن عشان نحل
+
+295
+00:21:28,790 --> 00:21:32,460
+في عندي أنا معادلات الحركة بتجاه xمعادلات الحركة
+
+296
+00:21:32,460 --> 00:21:35,320
+باتجاه الـ Y في البداية find the range of the
+
+297
+00:21:35,320 --> 00:21:39,540
+package يعني Delta X بالنسبة لل packageto find the
+
+298
+00:21:39,540 --> 00:21:46,020
+y displacement هأحكي أنا delta y بتساوي v not y t
+
+299
+00:21:46,020 --> 00:21:51,200
+نقص نص gt تربيع الان substitute y not بتساوي zero
+
+300
+00:21:51,200 --> 00:21:57,600
+و v not y كانت zero لإن الجسم .. الجسم .. طبعا
+
+301
+00:21:57,600 --> 00:22:02,080
+الطيارة اتحركت horizontally معناته v not x أربعين
+
+302
+00:22:02,080 --> 00:22:05,840
+و v not y zero ال y كانت ناقص واحد لإن أنا رميها
+
+303
+00:22:05,840 --> 00:22:09,830
+لتحت بحط السلب في عشر أقصى اتنين متر.the final
+
+304
+00:22:09,830 --> 00:22:12,210
+vertical position of the package relative to the
+
+305
+00:22:12,210 --> 00:22:15,910
+airplane solved for time طبعا أنا بدأ أوجد الزمن
+
+306
+00:22:15,910 --> 00:22:20,690
+اللازم علشان توصل ال package إلى الأرض طبعا أنا
+
+307
+00:22:20,690 --> 00:22:24,650
+عندي معلومات عن ال Y axis فبوجد الزمن باتجاه ال Y
+
+308
+00:22:24,650 --> 00:22:33,490
+ال Y هيV0Y0 في T0 ناقص نص G9 من 10 ع 2 طلعت 4.9 في
+
+309
+00:22:33,490 --> 00:22:38,690
+T تربيع بنوجة T بتساوي 4.5 هذا الزمن اللي أنا
+
+310
+00:22:38,690 --> 00:22:43,970
+استخدمت فيه معادلات Y هو نفس الزمن اللازم للمحور X
+
+311
+00:22:43,970 --> 00:22:48,260
+فبروح أستخدمه على معادلة اللي هي ال Xف Delta X
+
+312
+00:22:48,260 --> 00:22:52,300
+بتساوي X ناقص X naught بتساوي V naught في T بدنا
+
+313
+00:22:52,300 --> 00:22:57,100
+نعوض عن X naught ب Zero ال V naught X كانت 40 وال
+
+314
+00:22:57,100 --> 00:23:05,000
+T بأوجدها من هنا اللي هي 4.52 فبتطلع عند ال range
+
+315
+00:23:05,000 --> 00:23:10,980
+أو المسافة اللي هي سقطت فيها ال package 181 امترفي
+
+316
+00:23:10,980 --> 00:23:14,560
+B طالب find the component of the package velocity
+
+317
+00:23:14,560 --> 00:23:18,500
+at impact بدنا اللي هي ال component السرعة
+
+318
+00:23:18,500 --> 00:23:22,100
+النهائية في اتجاه ال X والسرعة النهائية في اتجاه
+
+319
+00:23:22,100 --> 00:23:26,360
+ال Y اتفقنا في اتجاه ال X ان السرعة النهائية في
+
+320
+00:23:26,360 --> 00:23:31,280
+اتجاه ال X ثابتة ما بتتغير ف VX بتساوي V naught
+
+321
+00:23:31,280 --> 00:23:34,640
+cosine ال theta هي نفسها 40 40 متر في الثانية
+
+322
+00:23:35,240 --> 00:23:38,060
+بالنسبة للـ Y بدأ أوجد اللي هي السرعة النهائية
+
+323
+00:23:38,060 --> 00:23:44,540
+باتجاه الـ Y VY بتساوي V naught sin θ ناقص GT V
+
+324
+00:23:44,540 --> 00:23:49,080
+naught اللي هي كانت Zero في اتجاه الـ Y بيبقى عند
+
+325
+00:23:49,080 --> 00:23:55,600
+الـ G 9.8 في T بيطلع minus 44.3 الناقص هذه لإنها
+
+326
+00:23:55,600 --> 00:24:01,440
+طبعا هي نازلة إلى أسفلعشان القذيفة أو ال package
+
+327
+00:24:01,440 --> 00:24:08,660
+نزلت لأسفل ف VY بتساوي سالب 44 VX بتضالها 40 ثابتة
+
+328
+00:24:08,660 --> 00:24:13,800
+في C طالب من find the angle of the impact طبعا
+
+329
+00:24:13,800 --> 00:24:18,360
+عشان أوجد الزاوية الزاوية بتساوي VY على VX VY ناقص
+
+330
+00:24:18,360 --> 00:24:25,680
+44 و VX 40 طالما أن VY ناقص 44 و VY موجة VX موجة
+
+331
+00:24:25,680 --> 00:24:31,470
+VY سالبو VX موجة في أي ربع ستكون هذه طبعا في أي
+
+332
+00:24:31,470 --> 00:24:36,630
+ربع VY سالب و VX موجة ستكون في الرابع الرابع
+
+333
+00:24:36,630 --> 00:24:41,290
+وبالتالي ما بزودلها انا 180 فبطلع انا 10 inverse
+
+334
+00:24:41,290 --> 00:24:47,860
+لهذا الرقم10 inverse لناقص 1.11 تطلع ناقص 48 طبعا
+
+335
+00:24:47,860 --> 00:24:51,160
+ما بجمعها ال 180 لإنها موجودة في الربع الرابع إيش
+
+336
+00:24:51,160 --> 00:24:54,820
+عرفني إنها في الربع الرابع لإنه vy سالبة و vx
+
+337
+00:24:54,820 --> 00:24:59,040
+موجبة فهي في الربع الرابع و بالتالي أي زاوية في
+
+338
+00:24:59,040 --> 00:25:03,300
+الربع الرابع أو الأول ما بزودلها 180 إذا كانت في
+
+339
+00:25:03,300 --> 00:25:08,960
+الربع التاني أو التالت بزودلها ال 180 ان شاء الله
+
+340
+00:25:08,960 --> 00:25:11,860
+المرة الجاية بنكمل باقية اللي هي الأمثلة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..01432e3c2b07ee332a516c3b72b7e167d88e7448
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2WaulyBZLcM_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 1854, "start": 0.0, "end": 18.54, "text": "بسم الله الرحمن الرحيم بستكمل chapter تلاتة و بنستكمل الموضوع اللي هو ال projectile motion اللي هو في المقضوفات حكينا في المقضوفات أنه على طول ما صار المقضوفة the x component of the velocity remained constant يعني المركبة الصينية لا السرعة", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 4724, 14851, 24793, 1211, 7187, 6055, 1211, 9307, 3660, 4032, 44945, 14851, 24793, 1211, 9673, 2407, 11242, 45367, 13672, 1829, 31439, 2423, 1716, 794, 5394, 13672, 1829, 31439, 8978, 9673, 4587, 11242, 38688, 9307, 11331, 4117, 1829, 8315, 8978, 9673, 4587, 11242, 38688, 9307, 14739, 3224, 15844, 23032, 12610, 19446, 20328, 9640, 9673, 4587, 11242, 38688, 3660, 264, 2031, 6542, 295, 264, 9269, 12780, 5754, 37495, 22653, 9673, 31747, 49401, 31767, 9957, 10632, 20193, 21136, 2288, 27884], "avg_logprob": -0.12984913724592362, "compression_ratio": 1.6954545454545455, "no_speech_prob": 8.940696716308594e-07, 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" الاتجاه", "probability": 0.82806396484375}, {"start": 60.89, "end": 61.55, "word": " القفقي", "probability": 0.7577311197916666}, {"start": 61.55, "end": 61.75, "word": " لل", "probability": 0.79931640625}, {"start": 61.75, "end": 61.99, "word": " x", "probability": 0.744140625}, {"start": 61.99, "end": 62.59, "word": " axis", "probability": 0.96484375}, {"start": 62.59, "end": 62.99, "word": " لمحور", "probability": 0.908203125}, {"start": 62.99, "end": 63.33, "word": " x", "probability": 0.76220703125}, {"start": 63.33, "end": 64.09, "word": " و", "probability": 0.83544921875}, {"start": 64.09, "end": 64.17, "word": " ..", "probability": 0.72900390625}, {"start": 64.17, "end": 64.45, "word": " و", "probability": 0.978515625}, {"start": 64.45, "end": 64.87, "word": " بعدين", "probability": 0.944580078125}, {"start": 64.87, "end": 65.35, "word": " بالنسبة", "probability": 0.9981689453125}, {"start": 65.35, "end": 65.83, "word": " للمحور", "probability": 0.8753662109375}, {"start": 65.83, "end": 66.09, "word": " y", "probability": 0.86279296875}, {"start": 66.09, "end": 66.87, "word": " بيكون", "probability": 0.88330078125}, {"start": 66.87, "end": 68.11, "word": " عمودية", "probability": 0.88046875}, {"start": 68.11, "end": 68.31, "word": " في", "probability": 0.94140625}, {"start": 68.31, "end": 68.85, "word": " اتجاه", "probability": 0.97998046875}, {"start": 68.85, "end": 69.05, "word": " ال", "probability": 0.98828125}, {"start": 69.05, "end": 69.39, "word": " y", "probability": 0.78076171875}, {"start": 69.39, "end": 70.61, "word": " الموجبة", "probability": 0.896484375}, {"start": 70.61, "end": 70.85, "word": " اللي", "probability": 0.97802734375}, {"start": 70.85, "end": 71.03, "word": " هي", "probability": 0.89013671875}, {"start": 71.03, "end": 71.43, "word": " upward", "probability": 0.86279296875}], "temperature": 1.0}, {"id": 4, "seek": 9126, "start": 71.8, "end": 91.26, "text": "الفعل الأهم بالنسبة للتجارب البروجيكتية في الانتصارات هي أن في شغلات مهمة بالنسبة لحقائق خلال التجارب يعني العملية تبين إن ال horizontal and vertical motion are completely independent of each other", "tokens": [6027, 5172, 30241, 16247, 16095, 20666, 1863, 35457, 3660, 24976, 2655, 7435, 9640, 3555, 2423, 26890, 29245, 1829, 4117, 2655, 10632, 8978, 2423, 7649, 2655, 9381, 9640, 9307, 39896, 14739, 8978, 13412, 17082, 1211, 9307, 3714, 16095, 3660, 20666, 1863, 35457, 3660, 5296, 5016, 4587, 16373, 4587, 16490, 1211, 6027, 16712, 7435, 9640, 3555, 37495, 22653, 18863, 42213, 10632, 6055, 3555, 9957, 36145, 2423, 12750, 293, 9429, 5394, 366, 2584, 6695, 295, 1184, 661], "avg_logprob": -0.3929166658719381, "compression_ratio": 1.51, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 71.8, "end": 72.26, "word": "الفعل", "probability": 0.4952799479166667}, {"start": 72.26, "end": 72.34, "word": " الأهم", "probability": 0.6123046875}, {"start": 72.34, "end": 73.96, "word": " بالنسبة", "probability": 0.728271484375}, {"start": 73.96, "end": 74.6, "word": " للتجارب", "probability": 0.765087890625}, {"start": 74.6, "end": 75.16, "word": " البروجيكتية", "probability": 0.5610525948660714}, {"start": 75.16, "end": 76.08, "word": " في", "probability": 0.299560546875}, {"start": 76.08, "end": 77.26, "word": " الانتصارات", "probability": 0.4280598958333333}, {"start": 77.26, "end": 77.5, "word": " هي", "probability": 0.475830078125}, {"start": 77.5, "end": 78.52, "word": " أن", "probability": 0.426025390625}, {"start": 78.52, "end": 79.4, "word": " في", "probability": 0.478515625}, {"start": 79.4, "end": 80.02, "word": " شغلات", "probability": 0.9161376953125}, {"start": 80.02, "end": 80.74, "word": " مهمة", "probability": 0.98583984375}, {"start": 80.74, "end": 81.26, "word": " بالنسبة", "probability": 0.9842529296875}, {"start": 81.26, "end": 83.28, "word": " لحقائق", "probability": 0.87333984375}, {"start": 83.28, "end": 83.68, "word": " خلال", "probability": 0.97607421875}, {"start": 83.68, "end": 84.26, "word": " التجارب", "probability": 0.98193359375}, {"start": 84.26, "end": 84.9, "word": " يعني", "probability": 0.6861572265625}, {"start": 84.9, "end": 85.58, "word": " العملية", "probability": 0.9410807291666666}, {"start": 85.58, "end": 86.62, "word": " تبين", "probability": 0.9122721354166666}, {"start": 86.62, "end": 86.88, "word": " إن", "probability": 0.30615234375}, {"start": 86.88, "end": 87.18, "word": " ال", "probability": 0.90087890625}, {"start": 87.18, "end": 87.6, "word": " horizontal", "probability": 0.291259765625}, {"start": 87.6, "end": 87.92, "word": " and", "probability": 0.59033203125}, {"start": 87.92, "end": 88.32, "word": " vertical", "probability": 0.82470703125}, {"start": 88.32, "end": 88.8, "word": " motion", "probability": 0.8740234375}, {"start": 88.8, "end": 89.06, "word": " are", "probability": 0.80859375}, {"start": 89.06, "end": 89.7, "word": " completely", "probability": 0.755859375}, {"start": 89.7, "end": 90.28, "word": " independent", "probability": 0.95703125}, {"start": 90.28, "end": 90.68, "word": " of", "probability": 0.947265625}, {"start": 90.68, "end": 90.94, "word": " each", "probability": 0.962890625}, {"start": 90.94, "end": 91.26, "word": " other", "probability": 0.89892578125}], "temperature": 1.0}, {"id": 5, "seek": 12066, "start": 92.56, "end": 120.66, "text": "الحركة الأفقية و الحركة الرأسية لا يعتمدان على .. على بعض this mean that motion هذا بيعني أنه هذه الحركة in one dimension has no effect on .. no motion in the other direction يعني الحركة باتجاه ال X لا تؤثر على الحركة باتجاه Y لكن هناك عامل مشترك بين ال X و ال Y هو الزمن الزمن خلال ال X هو بساوي الزمن خلال الحركة بال Y", "tokens": [6027, 5016, 31747, 3660, 16247, 5172, 4587, 10632, 4032, 21542, 31747, 3660, 34892, 10721, 3794, 10632, 20193, 7251, 34268, 2304, 3215, 7649, 15844, 4386, 15844, 45030, 11242, 341, 914, 300, 5394, 23758, 4724, 40228, 22653, 14739, 3224, 29538, 21542, 31747, 3660, 294, 472, 10139, 575, 572, 1802, 322, 4386, 572, 5394, 294, 264, 661, 3513, 37495, 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"end": 889.34, "word": " body", "probability": 0.88134765625}, {"start": 889.34, "end": 890.36, "word": " بالنسباله", "probability": 0.767041015625}, {"start": 890.36, "end": 890.64, "word": " إذا", "probability": 0.907470703125}, {"start": 890.64, "end": 891.3, "word": " قدفنا", "probability": 0.8065185546875}, {"start": 891.3, "end": 891.68, "word": " جسم", "probability": 0.973876953125}, {"start": 891.68, "end": 891.9, "word": " إلى", "probability": 0.78564453125}, {"start": 891.9, "end": 892.34, "word": " أعلى", "probability": 0.9781901041666666}, {"start": 892.34, "end": 892.78, "word": " ف", "probability": 0.916015625}, {"start": 892.78, "end": 893.32, "word": " vy", "probability": 0.32080078125}, {"start": 893.32, "end": 894.28, "word": " موجبة", "probability": 0.9794921875}, {"start": 894.28, "end": 894.94, "word": " و", "probability": 0.767578125}, {"start": 894.94, "end": 895.06, "word": " ال", "probability": 0.70166015625}, {"start": 895.06, "end": 896.1, "word": " displacement", "probability": 0.935546875}, {"start": 896.1, "end": 897.1, "word": " موجبة", "probability": 0.9840494791666666}, {"start": 897.1, "end": 897.6, "word": " لإن", "probability": 0.8180338541666666}, {"start": 897.6, "end": 897.78, "word": " احنا", "probability": 0.802734375}, {"start": 897.78, "end": 898.26, "word": " متعامل", "probability": 0.85693359375}, {"start": 898.26, "end": 898.5, "word": " معاه", "probability": 0.754638671875}, {"start": 898.5, "end": 898.88, "word": " كإنه", "probability": 0.876708984375}, {"start": 898.88, "end": 899.18, "word": " free", "probability": 0.445556640625}, {"start": 899.18, "end": 899.66, "word": " falling", "probability": 0.787109375}, {"start": 899.66, "end": 899.82, "word": " و", "probability": 0.92578125}, {"start": 899.82, "end": 899.9, "word": " إذا", "probability": 0.846923828125}, {"start": 899.9, "end": 900.32, "word": " قدفت", "probability": 0.9884033203125}, {"start": 900.32, "end": 900.62, "word": " جسم", "probability": 0.9775390625}, {"start": 900.62, "end": 900.84, "word": " إلى", "probability": 0.9228515625}, {"start": 900.84, "end": 901.36, "word": " أسفل", "probability": 0.9906005859375}], "temperature": 1.0}, {"id": 41, "seek": 91669, "start": 901.43, "end": 916.69, "text": "فالـ VY سالبة والـ displacement سالبة والـ acceleration دائما minus G أو هي عبارة عن G gravity of acceleration وهي عبارة عن ناقص Z downward always downward", "tokens": [5172, 6027, 39184, 691, 56, 8608, 6027, 49401, 16070, 39184, 21899, 8608, 6027, 49401, 16070, 39184, 17162, 11778, 16373, 15042, 3175, 460, 34051, 39896, 6225, 3555, 9640, 3660, 18871, 460, 12110, 295, 17162, 37037, 1829, 6225, 3555, 9640, 3660, 18871, 8717, 995, 4587, 9381, 1176, 24805, 1009, 24805], "avg_logprob": -0.2230548518044608, "compression_ratio": 1.417808219178082, "no_speech_prob": 0.0, "words": [{"start": 901.43, "end": 902.31, "word": "فالـ", "probability": 0.684814453125}, {"start": 902.31, "end": 902.87, "word": " VY", "probability": 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"probability": 0.6897786458333334}, {"start": 1473.97, "end": 1474.05, "word": " و", "probability": 0.861328125}, {"start": 1474.05, "end": 1474.41, "word": " VX", "probability": 0.96142578125}, {"start": 1474.41, "end": 1474.69, "word": " موجة", "probability": 0.9825846354166666}, {"start": 1474.69, "end": 1475.05, "word": " ستكون", "probability": 0.8011067708333334}, {"start": 1475.05, "end": 1475.15, "word": " في", "probability": 0.81396484375}, {"start": 1475.15, "end": 1475.61, "word": " الرابع", "probability": 0.830078125}, {"start": 1475.61, "end": 1476.63, "word": " الرابع", "probability": 0.8553059895833334}, {"start": 1476.63, "end": 1477.13, "word": " وبالتالي", "probability": 0.9234375}, {"start": 1477.13, "end": 1477.21, "word": " ما", "probability": 0.33984375}, {"start": 1477.21, "end": 1478.13, "word": " بزودلها", "probability": 0.862109375}, {"start": 1478.13, "end": 1478.85, "word": " انا", "probability": 0.730712890625}, {"start": 1478.85, "end": 1479.47, "word": " 180", "probability": 0.736328125}, {"start": 1479.47, "end": 1480.39, "word": " فبطلع", "probability": 0.8748046875}, {"start": 1480.39, "end": 1480.59, "word": " انا", "probability": 0.778076171875}, {"start": 1480.59, "end": 1480.83, "word": " 10", "probability": 0.72509765625}, {"start": 1480.83, "end": 1481.29, "word": " inverse", "probability": 0.8681640625}, {"start": 1481.29, "end": 1481.87, "word": " لهذا", "probability": 0.8505859375}, {"start": 1481.87, "end": 1482.39, "word": " الرقم", "probability": 0.9871419270833334}], "temperature": 1.0}, {"id": 67, "seek": 151186, "start": 1482.92, "end": 1511.86, "text": "10 inverse لناقص 1.11 تطلع ناقص 48 طبعا ما بجمعها ال 180 لإنها موجودة في الربع الرابع إيش عرفني إنها في الربع الرابع لإنه vy سالبة و vx موجبة فهي في الربع الرابع و بالتالي أي زاوية في الربع الرابع أو الأول ما بزودلها 180 إذا كانت في الربع التاني أو التالت بزودلها ال 180 ان شاء الله المرة الجاية بنكمل باقية اللي هي الأمثلة", "tokens": [3279, 17340, 5296, 8315, 4587, 9381, 502, 13, 5348, 6055, 9566, 1211, 3615, 8717, 995, 4587, 9381, 11174, 23032, 3555, 3615, 995, 19446, 4724, 7435, 2304, 3615, 11296, 2423, 11971, 5296, 28814, 1863, 11296, 3714, 29245, 23328, 3660, 8978, 34892, 3555, 3615, 34892, 16758, 3615, 11933, 1829, 8592, 6225, 28480, 22653, 36145, 11296, 8978, 34892, 3555, 3615, 34892, 16758, 3615, 5296, 28814, 1863, 3224, 44766, 8608, 6027, 49401, 4032, 371, 87, 3714, 29245, 49401, 6156, 3224, 1829, 8978, 34892, 3555, 3615, 34892, 16758, 3615, 4032, 20666, 2655, 6027, 1829, 36632, 30767, 995, 2407, 10632, 8978, 34892, 3555, 3615, 34892, 16758, 3615, 34051, 16247, 12610, 19446, 4724, 11622, 23328, 1211, 11296, 11971, 11933, 15730, 25961, 2655, 8978, 34892, 3555, 3615, 16712, 7649, 1829, 34051, 16712, 6027, 2655, 4724, 11622, 23328, 1211, 11296, 2423, 11971, 16472, 13412, 16606, 21984, 9673, 25720, 25724, 995, 10632, 44945, 24793, 1211, 4724, 995, 4587, 10632, 13672, 1829, 39896, 16247, 2304, 12984, 37977], "avg_logprob": -0.14032643539890363, "compression_ratio": 2.147286821705426, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 1482.92, "end": 1483.2, "word": "10", "probability": 0.405029296875}, {"start": 1483.2, "end": 1483.58, "word": " inverse", "probability": 0.625}, {"start": 1483.58, "end": 1484.62, "word": " لناقص", "probability": 0.71881103515625}, {"start": 1484.62, "end": 1485.14, "word": " 1", "probability": 0.79345703125}, {"start": 1485.14, "end": 1485.72, "word": ".11", "probability": 0.76416015625}, {"start": 1485.72, "end": 1486.0, "word": " تطلع", "probability": 0.916259765625}, {"start": 1486.0, "end": 1486.34, "word": " ناقص", "probability": 0.9697265625}, {"start": 1486.34, "end": 1486.98, "word": " 48", "probability": 0.95654296875}, {"start": 1486.98, "end": 1487.86, "word": " طبعا", "probability": 0.969482421875}, {"start": 1487.86, "end": 1487.96, "word": " ما", "probability": 0.90185546875}, {"start": 1487.96, "end": 1488.5, "word": " بجمعها", "probability": 0.74912109375}, {"start": 1488.5, "end": 1488.6, "word": " ال", "probability": 0.66845703125}, {"start": 1488.6, "end": 1489.02, "word": " 180", "probability": 0.822265625}, {"start": 1489.02, "end": 1489.44, "word": " لإنها", "probability": 0.842041015625}, {"start": 1489.44, "end": 1489.76, "word": " موجودة", "probability": 0.9798583984375}, {"start": 1489.76, "end": 1489.88, "word": " في", "probability": 0.8642578125}, {"start": 1489.88, "end": 1490.06, "word": " الربع", "probability": 0.7417805989583334}, {"start": 1490.06, "end": 1490.56, "word": " الرابع", "probability": 0.9752604166666666}, {"start": 1490.56, "end": 1491.16, "word": " إيش", "probability": 0.7332356770833334}, {"start": 1491.16, "end": 1491.54, "word": " عرفني", "probability": 0.82421875}, {"start": 1491.54, "end": 1491.66, "word": " إنها", "probability": 0.804443359375}, {"start": 1491.66, "end": 1491.76, "word": " في", "probability": 0.9697265625}, {"start": 1491.76, "end": 1491.96, "word": " الربع", "probability": 0.88720703125}, {"start": 1491.96, "end": 1492.32, "word": " الرابع", "probability": 0.9947916666666666}, {"start": 1492.32, "end": 1492.68, "word": " لإنه", "probability": 0.83154296875}, {"start": 1492.68, "end": 1492.92, "word": " vy", "probability": 0.60693359375}, {"start": 1492.92, "end": 1493.5, "word": " سالبة", "probability": 0.677490234375}, {"start": 1493.5, "end": 1494.22, "word": " و", "probability": 0.9892578125}, {"start": 1494.22, "end": 1494.82, "word": " vx", "probability": 0.6904296875}, {"start": 1494.82, "end": 1495.52, "word": " موجبة", "probability": 0.9869791666666666}, {"start": 1495.52, "end": 1495.88, "word": " فهي", "probability": 0.9835611979166666}, {"start": 1495.88, "end": 1496.02, "word": " في", "probability": 0.9765625}, {"start": 1496.02, "end": 1496.32, "word": " الربع", "probability": 0.9534505208333334}, {"start": 1496.32, "end": 1496.8, "word": " الرابع", "probability": 0.994140625}, {"start": 1496.8, "end": 1497.2, "word": " و", "probability": 0.5751953125}, {"start": 1497.2, "end": 1497.82, "word": " بالتالي", "probability": 0.94384765625}, {"start": 1497.82, "end": 1498.42, "word": " أي", "probability": 0.787109375}, {"start": 1498.42, "end": 1498.88, "word": " زاوية", "probability": 0.974365234375}, {"start": 1498.88, "end": 1499.04, "word": " في", "probability": 0.982421875}, {"start": 1499.04, "end": 1499.3, "word": " الربع", "probability": 0.9677734375}, {"start": 1499.3, "end": 1499.88, "word": " الرابع", "probability": 0.9944661458333334}, {"start": 1499.88, "end": 1500.36, "word": " أو", "probability": 0.875}, {"start": 1500.36, "end": 1500.88, "word": " الأول", "probability": 0.989990234375}, {"start": 1500.88, "end": 1501.08, "word": " ما", "probability": 0.96337890625}, {"start": 1501.08, "end": 1501.64, "word": " بزودلها", "probability": 0.9646484375}, {"start": 1501.64, "end": 1502.1, "word": " 180", "probability": 0.82275390625}, {"start": 1502.1, "end": 1502.86, "word": " إذا", "probability": 0.95947265625}, {"start": 1502.86, "end": 1503.2, "word": " كانت", "probability": 0.99072265625}, {"start": 1503.2, "end": 1503.3, "word": " في", "probability": 0.9833984375}, {"start": 1503.3, "end": 1503.58, "word": " الربع", "probability": 0.9698893229166666}, {"start": 1503.58, "end": 1504.08, "word": " التاني", "probability": 0.9256184895833334}, {"start": 1504.08, "end": 1504.32, "word": " أو", "probability": 0.916015625}, {"start": 1504.32, "end": 1504.92, "word": " التالت", "probability": 0.9544270833333334}, {"start": 1504.92, "end": 1506.16, "word": " بزودلها", "probability": 0.9845703125}, {"start": 1506.16, "end": 1506.44, "word": " ال", "probability": 0.86669921875}, {"start": 1506.44, "end": 1507.46, "word": " 180", "probability": 0.81298828125}, {"start": 1507.46, "end": 1508.7, "word": " ان", "probability": 0.52978515625}, {"start": 1508.7, "end": 1508.96, "word": " شاء", "probability": 0.950927734375}, {"start": 1508.96, "end": 1508.96, "word": " الله", "probability": 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2hg30QN6v_A.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2hg30QN6v_A.srt
new file mode 100644
index 0000000000000000000000000000000000000000..ac6eaa274d88d61a6d0391bfe92a36e782ae5ed6
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2hg30QN6v_A.srt
@@ -0,0 +1,1096 @@
+
+1
+00:00:01,210 --> 00:00:04,170
+بسم الله الرحمن الرحيم section 72 rotational
+
+2
+00:00:04,170 --> 00:00:08,410
+motion under constant angular acceleration الحركة
+
+3
+00:00:08,410 --> 00:00:15,330
+الدورانية تحت تأثير اللي هو تسارع زاوي ثابت a
+
+4
+00:00:15,330 --> 00:00:20,060
+number of parallels exist between the equations for
+
+5
+00:00:20,060 --> 00:00:22,440
+rotational motion and those for linear motion فيه
+
+6
+00:00:22,440 --> 00:00:28,840
+طبعا هي كمثل توازي بين اللي هي معادلات الحركة
+
+7
+00:00:28,840 --> 00:00:32,020
+الخطية و معادلات الحركة الدورانية ولكن مع تغيير
+
+8
+00:00:32,020 --> 00:00:38,480
+اللي هو الرموز و مقارنتهم مع بعض طبعا هي تغيير
+
+9
+00:00:38,480 --> 00:00:42,420
+تكافؤ لإن في بينهم نصف قطر بيدوروا زي مثلا ال
+
+10
+00:00:42,420 --> 00:00:47,700
+omega اللي هي ال average angular velocity = θ
+
+11
+00:00:47,700 --> 00:00:51,820
+final − θ initial / T final − T initial  Δ
+
+12
+00:00:51,820 --> 00:00:56,800
+تيتا / ΔT طبعا بكافئها أو مقابل لها اللي هي
+
+13
+00:00:56,800 --> 00:01:02,260
+السرعة الخطية اللي هي V average  = X
+
+14
+00:01:02,260 --> 00:01:05,780
+final − X initial / T final − T initial  Δ
+
+15
+00:01:05,780 --> 00:01:11,420
+X / ΔT في هذه الحالة أوميجا يأخذ المكان يعني
+
+16
+00:01:11,420 --> 00:01:15,180
+الآن حطينا الأوميجا بدل ال V و تيتا بدل ال X و
+
+17
+00:01:15,180 --> 00:01:21,820
+Alpha بدل ال A in the same way في نفس اللحظة every
+
+18
+00:01:21,820 --> 00:01:26,480
+linear quantity we have encountered so far has a
+
+19
+00:01:26,480 --> 00:01:30,670
+corresponding quantity in rotational motion يعني في علاقة
+
+20
+00:01:30,670 --> 00:01:35,450
+بين الحركة الخطية و الحركة الدورانية لكن الآن احنا
+
+21
+00:01:35,450 --> 00:01:39,310
+بنحط في القوانين الحركة الخطية لها قوانين و
+
+22
+00:01:39,310 --> 00:01:43,170
+الدورانية لها قوانين لكن الرموز بتختلف لكن نفس
+
+23
+00:01:43,170 --> 00:01:46,970
+القوانين تقريبا ولكن في علاقة بين الحركة الخطية و
+
+24
+00:01:46,970 --> 00:01:51,450
+الحركة الدورانية الآن معادلات الحركة الدورانية
+
+25
+00:01:51,450 --> 00:01:57,180
+الخطية اللي هي .. و الخطية Linear motion with a
+
+26
+00:01:57,180 --> 00:02:01,060
+constant هنا Rotational motion with α constant
+
+27
+00:02:01,060 --> 00:02:04,920
+اللي بالنسبة لأ الخطية كان عندنا V = V
+
+28
+00:02:04,920 --> 00:02:07,960
+initial + AT في الدورانية ω = ω
+
+29
+00:02:07,960 --> 00:02:12,180
+initial + αT ال ω بدل V و ال ω
+
+30
+00:02:12,180 --> 00:02:15,700
+initial بدل V initial و ال T زي ما هي و ال A
+
+31
+00:02:15,700 --> 00:02:20,400
+بدلنا معها α  إذا القانون التاني ΔX =
+
+32
+00:02:20,400 --> 00:02:24,610
+V initial T + ½AT²  Δθ =
+
+33
+00:02:24,610 --> 00:02:28,570
+ω initial T + ½αT² V² =
+
+34
+00:02:28,570 --> 00:02:31,130
+= V initial² + 2AΔX
+
+35
+00:02:31,130 --> 00:02:33,510
+و ω² = V initial² + 2
+
+36
+00:02:33,510 --> 00:02:37,170
+αΔθ باللاحظ انه نفس قوانين الحركة
+
+37
+00:02:37,170 --> 00:02:43,530
+ولكن هي حاجة تمثل حركة خطية تمثل حركة دورانية نجي
+
+38
+00:02:43,530 --> 00:02:49,210
+لل quiz بيحكي لنا ارجع لل quiz واحد طبعا عندنا
+
+39
+00:02:49,210 --> 00:02:52,930
+زوجين يعني زوجين من اللي هي displacement أو ال
+
+40
+00:02:52,930 --> 00:02:56,730
+position في ال initial و ال final السؤال if the
+
+41
+00:02:56,730 --> 00:02:59,810
+object starts from rest لو بدأ من ال rest يعني
+
+42
+00:02:59,810 --> 00:03:02,210
+ω initial = 0 at the initial angular
+
+43
+00:03:02,210 --> 00:03:05,130
+position moves counter-clockwise و بتحرك counter-clockwise
+
+44
+00:03:05,130 --> 00:03:08,890
+يعني بيزيد with constant angular acceleration all
+
+45
+00:03:08,890 --> 00:03:11,230
+arrives at the final angular position with the
+
+46
+00:03:11,230 --> 00:03:14,410
+same angular velocity in all three cases طبعاً عندنا
+
+47
+00:03:14,410 --> 00:03:17,930
+ثلاث حالات في عندنا الحالة الأولى ال position الأول
+
+48
+00:03:17,930 --> 00:03:21,510
+6 و النهائي 3،  و النهائي 6، ال position
+
+49
+00:03:21,510 --> 00:03:25,390
+الأولى -1 و النهائي 1 طبعاً هذا فيه a
+
+50
+00:03:25,390 --> 00:03:29,690
+δθ ال c هذا θ initial = 1 till final = 5
+
+51
+00:03:29,690 --> 00:03:34,550
+المطلوب من هدول القيم ال initial و ال final بتكون
+
+52
+00:03:34,550 --> 00:03:39,650
+فيها ال angular acceleration اللي هي السرعة الزاوية
+
+53
+00:03:39,650 --> 00:03:46,050
+التسارع الزاوي أعلى حاجة طبعا إذا كانت طبعا
+
+54
+00:03:46,050 --> 00:03:49,570
+احنا α = ω² − ω initial²
+
+55
+00:03:49,570 --> 00:03:52,730
+²/ 2Δθ إذا كانت Δθ أقل
+
+56
+00:03:52,730 --> 00:03:56,730
+ما يمكن بتكون α أكبر ما يمكن فمتى كانت Δ
+
+57
+00:03:56,730 --> 00:04:00,970
+θ أقل ما يمكن لما كانت ال θ initial −
+
+58
+00:04:00,970 --> 00:04:04,590
+1 و ال final = 1 كنا نحكي 1 − (−1)
+
+59
+00:04:04,590 --> 00:04:09,020
+بتطلع 2 أقل من 3.14 إذا هذي B
+
+60
+00:04:09,020 --> 00:04:12,260
+هو الجواب الصحيح هذي بتكون Δθ أقل ما يمكن
+
+61
+00:04:12,260 --> 00:04:16,120
+وبالتالي α أكبر ما يمكن the highest value
+
+62
+00:04:16,120 --> 00:04:19,160
+section
+
+63
+00:04:19,160 --> 00:04:25,680
+سابعة ثلاثة اللي هي بيحكي read it by yourself from
+
+64
+00:04:25,680 --> 00:04:30,130
+the textbook اقرأه بنفسك موجودة في الكتاب الآن
+
+65
+00:04:30,130 --> 00:04:33,070
+will rotate with constant angular acceleration
+
+66
+00:04:33,070 --> 00:04:42,710
+العجلة بتدور بتسارع زاوي ثابت = 3 rad
+
+67
+00:04:42,710 --> 00:04:46,510
+per second square زي ما هو موجود 3.5 rad
+
+68
+00:04:46,510 --> 00:04:50,110
+per second square if the angular velocity زي كانت
+
+69
+00:04:50,110 --> 00:04:54,370
+السرعة الزاوية للعجلة 2 rad per second لما
+
+70
+00:04:54,370 --> 00:04:57,760
+كانت = 0 يعني ω initial = 2
+
+71
+00:04:57,760 --> 00:05:02,460
+لما T = 0 الآن السؤال ال throw up angle بس
+
+72
+00:05:02,460 --> 00:05:05,800
+ده will rotate between T = 0 ل T
+
+73
+00:05:05,800 --> 00:05:10,980
+= 2  قالب الزاوية اللي بدور فيها يعني مطلوب
+
+74
+00:05:10,980 --> 00:05:17,420
+مننا نوجد اللي هو بالبداية نوجد θ طبعا هذا السؤال
+
+75
+00:05:17,420 --> 00:05:24,270
+ممكن ان يحل موجود في الكتاب محلول حله بالكتاب ممكن
+
+76
+00:05:24,270 --> 00:05:28,870
+تشجع على الكتاب و انحله بمعادلات الحركة  Δθ =
+
+77
+00:05:28,870 --> 00:05:33,210
+ω initial T + ½αT²  T = 0 ,T = 2 ,ω initial =
+
+78
+00:05:33,210 --> 00:05:38,830
+2 أيضاً و ال acceleration = 3 طالب
+
+79
+00:05:38,830 --> 00:05:42,430
+θ أو Δθ = ω
+
+80
+00:05:42,430 --> 00:05:48,850
+initial T + ½αT²  فبنعوض عن
+
+81
+00:05:48,850 --> 00:05:52,990
+ω initial ب 2 و بعدين ½ × α اللي هي
+
+82
+00:05:52,990 --> 00:05:55,450
+3.5 × T² اللي هي 2² بتطلع
+
+83
+00:05:55,450 --> 00:06:02,770
+θ  كمان ممكن احنا نحولها الى  degrees من
+
+84
+00:06:02,770 --> 00:06:06,430
+ال radian الى degrees أو العكس what is the angular
+
+85
+00:06:06,430 --> 00:06:09,530
+velocity بده طالب ال ω النهائية لما T =
+
+86
+00:06:09,530 --> 00:06:13,700
+2 ال ω النهائية نحكي ω final =
+
+87
+00:06:13,700 --> 00:06:17,560
+ω initial + αT والمعطيات كلها موجودة
+
+88
+00:06:17,560 --> 00:06:23,240
+معنا ان شاء الله initial
+
+89
+00:06:23,240 --> 00:06:27,640
+section 7-3 tangential velocity
+
+90
+00:06:27,640 --> 00:06:30,220
+tangential acceleration and centripetal
+
+91
+00:06:30,220 --> 00:06:35,200
+acceleration ال tangential يعني السرعة المماسية و
+
+92
+00:06:35,200 --> 00:06:40,360
+التسارع المماسي tangential المماس و التسارع اللي هي
+
+93
+00:06:40,360 --> 00:06:46,540
+المركزي centripetal التسارع المركزي نجي لل
+
+94
+00:06:46,540 --> 00:06:49,380
+section الاول tangential velocity and acceleration
+
+95
+00:06:49,380 --> 00:06:53,680
+the angular variables are related
+
+96
+00:06:53,680 --> 00:06:57,940
+to the linear variables consider الآن المتغيرات
+
+97
+00:06:57,940 --> 00:07:01,320
+اللي موجودة عندي لها علاقة بدأوجد علاقتها مع
+
+98
+00:07:01,320 --> 00:07:06,020
+يعني بدأوجد علاقة المتغيرات الخطية بالمتغيرات
+
+99
+00:07:06,020 --> 00:07:11,540
+الزاوية المتغيرات يعني X, V, A بيوجد علاقتها
+
+100
+00:07:11,540 --> 00:07:16,520
+ب θ, ω, α طبعا بأفرض في عندي أنا مجسم
+
+101
+00:07:16,520 --> 00:07:21,740
+بهذا الشكل طبعا بدور حركة دورانية عكس عقرب الساعة ال
+
+102
+00:07:21,740 --> 00:07:24,660
+X-axis هذا عبارة عن reference line خط المرجع
+
+103
+00:07:24,660 --> 00:07:30,260
+منه لو كانت النقطة B كانت مثلاً هنا و اتحركت و وصلت
+
+104
+00:07:30,260 --> 00:07:35,330
+النقطة B فمشيت إزاحة اللي هي Δθ نسميها الـ
+
+105
+00:07:35,330 --> 00:07:38,930
+Angular Displacement وعملت قوس ΔS اللي أنا
+
+106
+00:07:38,930 --> 00:07:42,270
+عند النقطة B باخد المماس المماس ده هي عبارة عن
+
+107
+00:07:42,270 --> 00:07:46,010
+Linear Velocity عند هذه النقطة Linear Velocity عند
+
+108
+00:07:46,010 --> 00:07:50,550
+هذه النقطة إيش علاقة ال ω بالـ V؟ بدنا
+
+109
+00:07:50,550 --> 00:07:55,590
+نعرفها Δθ = ΔS / R لما أجي أقسم
+
+110
+00:07:55,590 --> 00:08:00,730
+الطرفين على ΔT قسم الطرفين على ΔT يطلع
+
+111
+00:08:00,730 --> 00:08:05,110
+ΔT Δθ / ΔT هي عبارة عن اللي هي
+
+112
+00:08:05,110 --> 00:08:11,450
+نسميها ω = (1/R) × طبعاً ΔS /
+
+113
+00:08:11,450 --> 00:08:15,310
+ΔT = V  طب when ΔT is very small ΔT
+
+114
+00:08:15,310 --> 00:08:19,250
+صغيرة جداً فΔθ / ΔT عبارة عن
+
+115
+00:08:19,250 --> 00:08:22,810
+بتكون قريبة من اللي هي السرعة الزاوية اللحظية
+
+116
+00:08:22,810 --> 00:08:28,540
+ω وبالتالي أيضاً ΔS / ΔT سرعة لحظية
+
+117
+00:08:28,540 --> 00:08:34,360
+خطية إذا ΔT تصبح صغيرة في معنى الكلام ω
+
+118
+00:08:34,360 --> 00:08:38,400
+فهذه الحالة = V / R ω = V / R أو
+
+119
+00:08:38,400 --> 00:08:42,140
+V = Rω هذه أعطتنا علاقة بين السرعة
+
+120
+00:08:42,140 --> 00:08:46,620
+الزاوية وبين اللي هي السرعة الخطية Vt اللي هي
+
+121
+00:08:46,620 --> 00:08:49,880
+عبارة عن tangential السرعة المماسية = R ×
+
+122
+00:08:49,880 --> 00:08:53,340
+ω ال V = Vt = tangential velocity
+
+123
+00:08:53,340 --> 00:08:59,760
+اللي هي السرعة المماسية طبعاً معادلة 17 توضح السرعة
+
+124
+00:08:59,760 --> 00:09:04,680
+المماسية عند نقطة معينة خلال دوران الجسم وقبلها
+
+125
+00:09:04,680 --> 00:09:09,800
+طبعاً هو بيزداد increasing as that point is moved
+
+126
+00:09:09,800 --> 00:09:14,140
+outward from the center of rotation toward the rim
+
+127
+00:09:14,140 --> 00:09:17,360
+as expected however every point on the rotating
+
+128
+00:09:17,360 --> 00:09:21,220
+object has the same angular velocity طبعاً زي ما
+
+129
+00:09:21,220 --> 00:09:25,280
+حكينا سابقاً أي جسم بدور كل نقطة على هذا الجسم
+
+130
+00:09:25,280 --> 00:09:29,700
+بيكون النقاط كلها لها نفس اللي هي السرعة الزاوية
+
+131
+00:09:29,700 --> 00:09:32,820
+ال angular velocity ال tangential speed is the
+
+132
+00:09:32,820 --> 00:09:36,060
+magnitude of the tangential velocity and is also
+
+133
+00:09:36,060 --> 00:09:39,300
+called tangential speed هي نفس ال tangential
+
+134
+00:09:39,300 --> 00:09:43,440
+velocity وتسمى ال linear speed ال linear speed
+
+135
+00:09:45,430 --> 00:09:51,430
+معادلة 17 صحيحة لما تكون ال ω تقاس بال rad per
+
+136
+00:09:51,430 --> 00:09:55,670
+unit time suppose a rotating object لو كان عندي
+
+137
+00:09:55,670 --> 00:10:00,250
+أنجسم برضه بدور و بتتغير ال angular speed من
+
+138
+00:10:00,250 --> 00:10:05,620
+Δω تغيرات خلال فترة زمنية ΔT معناه
+
+139
+00:10:05,620 --> 00:10:10,520
+الكلام أن ΔV = R × Δω طبعاً
+
+140
+00:10:10,520 --> 00:10:14,320
+نقسم على ΔT لأن بدنا نوجد العلاقة بين ال
+
+141
+00:10:14,320 --> 00:10:19,980
+α و ال A as the time interval ΔT أيضاً
+
+142
+00:10:19,980 --> 00:10:23,880
+صغيرة جداً فΔω / ΔT بيسموها
+
+143
+00:10:23,880 --> 00:10:29,820
+Instantaneous Angular Acceleration و Δ.. طبعاً
+
+144
+00:10:29,820 --> 00:10:33,340
+V / ΔT بيسموها Instantaneous Tangential
+
+145
+00:10:33,340 --> 00:10:37,900
+Acceleration Tangential Acceleration  ما هي الكلام
+
+146
+00:10:37,900 --> 00:10:42,300
+الآن أوجدت العلاقة بين A Tangential Acceleration و
+
+147
+00:10:42,300 --> 00:10:47,620
+Angular اللي هي Acceleration إذا At = R ×
+
+148
+00:10:47,620 --> 00:10:52,040
+α بينهم R اللي هي نصف القطر At = R ×
+
+149
+00:10:52,040 --> 00:10:57,870
+ال α مرة ثانية  The radian measure must be used
+
+150
+00:10:57,870 --> 00:11:00,510
+for the angular acceleration term in this equation
+
+151
+00:11:00,510 --> 00:11:05,670
+في هذه المعادلة طبعاً بقيس ال α بال radian ممكن
+
+152
+00:11:05,670 --> 00:11:08,070
+أن نقيس ال angular acceleration بال rad per
+
+153
+00:11:08,070 --> 00:11:12,530
+second squared الآن
+
+154
+00:11:12,530 --> 00:11:17,670
+quiz 7-4 بيحكي اللي في يدي شخص اسمه Andrew and
+
+155
+00:11:17,670 --> 00:11:22,370
+Chuck شخصين are riding on a merry-go-round under a
+
+156
+00:11:22,370 --> 00:11:26,280
+Andrew rides on a horse at the outer rim of the
+
+157
+00:11:26,280 --> 00:11:30,520
+circular platform في السباق اللي .. اللي هي الحصان
+
+158
+00:11:30,520 --> 00:11:36,440
+أو ال .. ال .. ال .. يعني حلقة للسباق في عند شخصين
+
+159
+00:11:36,440 --> 00:11:40,240
+في شخص راكب على الحصان و بيدور على ذراع طبعاً ال
+
+160
+00:11:40,240 --> 00:11:43,580
+circular platform على اللي هي الدائرة التي اعتبرها
+
+161
+00:11:43,580 --> 00:11:47,740
+twice as far from the center of the circular على
+
+162
+00:11:47,740 --> 00:11:52,180
+بعد طبعاً twice as far from the center of the
+
+163
+00:11:52,180 --> 00:11:58,840
+circular platform as Chuck واحد بيتحرك على مسافة
+
+164
+00:11:58,840 --> 00:12:02,420
+على طرف اللي هي الحلقة الحلقة اللي هي السباق تبع
+
+165
+00:12:02,420 --> 00:12:07,780
+الحصان و واحد موجود على بعد يعني نصف اللي هي نصف نصف
+
+166
+00:12:07,780 --> 00:12:13,420
+القطر على the inner horse طبعاً راكب على
+
+167
+00:12:13,420 --> 00:12:16,360
+الحصان بالداخل when the wheel goes around in
+
+168
+00:12:16,360 --> 00:12:21,450
+rotating at constant angular speed ممكن نفسرها
+
+169
+00:12:21,450 --> 00:12:26,270
+زي اللعبة اللي موجودة على الحصان اللي هي اللي عندي
+
+170
+00:12:26,270 --> 00:12:30,990
+أنا disk كبير وفي عندي حصانين حصان موجود على طرف
+
+171
+00:12:30,990 --> 00:12:35,730
+هذه الدائرة و حصان موجود في نصف المسافة بين نصف
+
+172
+00:12:35,730 --> 00:12:40,090
+القطر فيه شخصين راكبين طبعاً و ال disk هذا بدور كـ ..
+
+173
+00:12:40,090 --> 00:12:44,990
+كـ .. يعني ك لعبة ممكن نفسرها ك حلقة سباق وطبعاً
+
+174
+00:12:44,990 --> 00:12:48,780
+راكبين موجودين على الحصان الآن شخصين اللي هو ال
+
+175
+00:12:48,780 --> 00:12:54,220
+Andrew and Chuck  الآن ال Andrew
+
+176
+00:12:54,220 --> 00:12:58,260
+is angular speed ال Andrew angular speed is twice
+
+177
+00:12:58,260 --> 00:13:02,180
+Chuck's  ولا the same as Chuck's ولا half of
+
+178
+00:13:02,180 --> 00:13:05,520
+Chuck's ولا impossible to determine هاي طبعاً الرسمة
+
+179
+00:13:05,520 --> 00:13:09,840
+هذه الرسمة هذه نفس الرسمة هذه عبارة عن اللعبة هنا
+
+180
+00:13:09,840 --> 00:13:13,900
+في disk كبير بدور الحصانين اللي موجودين يعني لمسافات
+
+181
+00:13:13,900 --> 00:13:16,380
+واحد موجود على الطرف و الثاني موجود في النص بالشكل
+
+182
+00:13:16,380 --> 00:13:19,780
+هذا واحد على الطرف و الثاني في نصف المسافة و ال disk
+
+183
+00:13:19,780 --> 00:13:25,360
+هذا إيش بدور الآن بيحكي لي طبعاً mean ال angular
+
+184
+00:13:25,360 --> 00:13:30,960
+اللي هي ال angular هنا بيحكي لي أنه بالنسبة لل
+
+185
+00:13:30,960 --> 00:13:34,040
+angular speed بالنسبة لل angular speed ال mean
+
+186
+00:13:34,040 --> 00:13:38,480
+أكبر من الثاني طبعاً ال angular speed عشان هال
+
+223
+00:16:14,430 --> 00:16:18,810
+بيدّو الزاوية اللي الـ disk بدور فيها كلمة الزاوية
+
+224
+00:16:18,810 --> 00:16:23,870
+اللي الـ disk بدور فيها يعني إيجاد ثيتا الآن T
+
+225
+00:16:23,870 --> 00:16:26,750
+بتساوي 0.89 و الـ Omega initial صفر
+
+226
+00:16:26,750 --> 00:16:30,070
+هي المعطيات بستخدم القانون اللي هو Delta Theta
+
+227
+00:16:30,070 --> 00:16:36,010
+بتساوي Omega initial T زائد نصف Alpha T تربيع Omega
+
+228
+00:16:36,010 --> 00:16:40,030
+initial كانت صفر إذا نصف الـ Alpha كانت ناقص خمسة و
+
+229
+00:16:40,030 --> 00:16:43,010
+ثلاثين point اثنين rad per second square وT تربيع
+
+230
+00:16:43,010 --> 00:16:46,310
+بتساوي 0.892 بيطلع برضه ناقص
+
+231
+00:16:46,310 --> 00:16:52,830
+أربع عشرة rad في C مطلوب find the final tangential
+
+232
+00:16:52,830 --> 00:16:57,310
+velocity بدي الـ V بدي الـ final tangential velocity
+
+233
+00:16:57,310 --> 00:17:03,510
+of a microbe at اللي هي لما تكون R أربعة point
+
+234
+00:17:03,510 --> 00:17:08,030
+أربعة خمسة طبعاً في علاقة بين الـ angular velocity و
+
+235
+00:17:08,030 --> 00:17:11,350
+tangential velocity اللي هي V tangential بتساوي
+
+236
+00:17:11,350 --> 00:17:15,410
+R في Omega أعطينا الـ R اللي هي 0.44
+
+237
+00:17:15,410 --> 00:17:18,230
+متر اللي كانت أعطاني إياها أربعة point أربعة خمسة سم
+
+238
+00:17:18,230 --> 00:17:22,210
+حولناها لمتر طبعاً ضربناها في عشرة أس سالب اثنين أو
+
+239
+00:17:22,210 --> 00:17:26,910
+على مئة تطلع 0.44 متر ضربناها في
+
+240
+00:17:26,910 --> 00:17:30,890
+اللي هي الـ Omega ناقص واحد point ثلاثين point أربعة rad
+
+241
+00:17:30,890 --> 00:17:34,490
+per second تطلع ناقص واحد point أربعة متر في ث
+
+242
+00:17:34,490 --> 00:17:39,290
+انية في دي طالب الـ tangential acceleration
+
+243
+00:17:39,290 --> 00:17:43,390
+tangential acceleration لما تكون الـ R أربعة point
+
+244
+00:17:43,390 --> 00:17:48,470
+أربعة خمسة سم إذا الـ A tangential تساوي الـ R في
+
+245
+00:17:48,470 --> 00:17:52,830
+الفا الـ R حولت من سم لمتر نفسها والالفا
+
+246
+00:17:52,830 --> 00:17:55,830
+ناقص خمسة و ثلاثين point اثنين rad per second
+
+247
+00:17:55,830 --> 00:17:58,730
+square تطلع ناقص واحد point خمسة سبعة متر في
+
+248
+00:17:58,730 --> 00:18:06,600
+الثانية  مثال آخر example سبعة أربعة in a comeback
+
+249
+00:18:06,600 --> 00:18:11,660
+disc أيضا  bear any disc بدور as the read head move
+
+250
+00:18:11,660 --> 00:18:15,220
+out from the center of the disc the angular speed
+
+251
+00:18:15,220 --> 00:18:18,440
+of the disc change so that the linear speed of the
+
+252
+00:18:18,440 --> 00:18:22,100
+position of the head remain at a constant value
+
+253
+00:18:22,100 --> 00:18:26,080
+about واحد point ثلاثة متر في الثانية find the
+
+254
+00:18:26,080 --> 00:18:31,880
+angular speed of CD of radius ستة centimeter when
+
+255
+00:18:31,880 --> 00:18:35,980
+the red head is at R بتساوي اثنين طبعا الـ CD هو
+
+256
+00:18:35,980 --> 00:18:40,520
+بتحرك فيه معلومات طبعا هو بيقرأها ل... لما يكون في
+
+257
+00:18:40,520 --> 00:18:45,060
+عند رأس أو إبرة صغيرة بتكون على طبعاً هو بدور الـ CD
+
+258
+00:18:45,060 --> 00:18:49,440
+وهو بدور بي... بيعلم أن مسافات معينة وبعضها عن
+
+259
+00:18:49,440 --> 00:18:53,940
+المحور بيعطيني عند مثلاً R بتساوي واحد اثنين
+
+260
+00:18:53,940 --> 00:18:56,900
+ثلاثة كذا لعند R نصف الخطوة بيعطيني كل المعلومات
+
+261
+00:18:56,900 --> 00:19:02,880
+على مسافات معينة من الآن بيحكي لنا find the angular
+
+262
+00:19:02,880 --> 00:19:06,940
+speed of CD radius 6 cm when the read head لما
+
+263
+00:19:06,940 --> 00:19:13,120
+تكون القراءة مركزة على الـ R بتساوي 2 cm وبعدين
+
+264
+00:19:13,120 --> 00:19:20,140
+نجدها لما R بيصير 5.6 الحل طبعاً طبعنا find the
+
+265
+00:19:20,140 --> 00:19:24,040
+angular speed of the disk when the read head at R
+
+266
+00:19:24,040 --> 00:19:27,980
+بتساوي 2 أو اه وR كمان بتساوي 5.6 لأنه نعيد الحل
+
+267
+00:19:27,980 --> 00:19:32,620
+مرتين الآن الـ V بتساوي R في Omega الـ R بتساوي
+
+268
+00:19:32,620 --> 00:19:38,000
+2 إذا اللي هي الـ V tangential على الـ R بيعطيني
+
+269
+00:19:38,000 --> 00:19:43,680
+Omega الـ V tangential كانت 1.3 و الـ R كانت 2  فعشرة
+
+270
+00:19:43,680 --> 00:19:49,050
+أصل نقص 2 بيعطيني 0.65 rad per second بالظبط نفس اللي
+
+271
+00:19:49,050 --> 00:19:53,590
+عملناها  لأ اللي هي الـ R بتساوي اثنين بنعمل الـ R
+
+272
+00:19:53,590 --> 00:19:56,650
+بتساوي خمسة point ستة و الـ R بتساوي خمسة point
+
+273
+00:19:56,650 --> 00:20:02,310
+ستة بتكون Omega ثلاثة وعشرة rad per second في B
+
+274
+00:20:02,310 --> 00:20:08,730
+find the linear speed in متر في الثانية of خمسة و
+
+275
+00:20:08,730 --> 00:20:12,730
+أربعين هنا revolution per minute زي ما حكينا record
+
+276
+00:20:12,730 --> 00:20:19,290
+at point 2 cm and 5.6 cm لأن بدي أحول الـ rev per
+
+277
+00:20:19,290 --> 00:20:25,650
+minute بدي أضرب اللي هي 45 rev per minute بتساوي 45
+
+278
+00:20:25,650 --> 00:20:31,190
+في 2 باي على اللي هو 60 اللي هي الـ revolution
+
+279
+00:20:31,190 --> 00:20:41,700
+الدورة 2 باي على 60 بتساوي 4.71 rad per second لأنه
+
+280
+00:20:41,700 --> 00:20:46,900
+آه صحيح خمسة وأربعين revolution per minute
+
+281
+00:20:46,900 --> 00:20:52,900
+calculate the linear speed at ... لأن الدورة
+
+282
+00:20:52,900 --> 00:20:55,760
+الكاملة هي عبارة عن اثنين باي الدورة الكاملة هي
+
+283
+00:20:55,760 --> 00:20:59,880
+عبارة عن اثنين باي اللي هي مئة وثمانين درجة اثنين باي يعني
+
+284
+00:20:59,880 --> 00:21:03,440
+ثلاثمائة وستين درجة اثنين باي  فـ calculate the linear
+
+285
+00:21:03,440 --> 00:21:08,140
+speed at R بتساوي اثنين is tangential بتساوي R
+
+286
+00:21:08,140 --> 00:21:12,890
+في Omega بنعوض عن الـ R بنعوض عن الـ Omega اللي احنا
+
+287
+00:21:12,890 --> 00:21:18,330
+طلعناها هنا تعطينا طبعاً 0.094 متر في
+
+288
+00:21:18,330 --> 00:21:23,790
+الثانية الـ calculator دلوقت دا linear speed بتعوز
+
+289
+00:21:23,790 --> 00:21:27,070
+للـ linear speed لما R بتساوي خمسة point ستة
+
+290
+00:21:27,070 --> 00:21:31,250
+فبنعوض V tangential بتساوي R في Omega بنعوض عن
+
+291
+00:21:31,250 --> 00:21:34,050
+الـ R اللي هي الجديدة اللي أعطاني إياها بنحول من سم ل
+
+292
+00:21:34,050 --> 00:21:41,790
+متر عشان هيك صارت 5.6 × 10⁻² في الـ omega 4.71 rad per
+
+293
+00:21:41,790 --> 00:21:47,230
+second تطلع 0.26 متر في الثانية في C calculate the
+
+294
+00:21:47,230 --> 00:21:51,310
+total length of the track for CD designed to play
+
+295
+00:21:51,310 --> 00:21:56,330
+for one hour بدنا الـ total length الـ total length
+
+296
+00:21:56,330 --> 00:22:00,550
+طبعاً احنا بدنا طول الآن فبستخدم الـ V tangential مع
+
+297
+00:22:00,550 --> 00:22:06,610
+الزمن اللي أعطاني إياه الـ D بدها تساوي 1.3 في اللي هي
+
+298
+00:22:06,610 --> 00:22:12,210
+الـ hour اللي هي الـ hour عبارة عن 60 في 60 60 دقيقة
+
+299
+00:22:12,210 --> 00:22:16,290
+والدقيقة 60 ثانية تطلع 3600 ثانية الساعة بتطلع
+
+300
+00:22:16,290 --> 00:22:21,330
+4680 متر هذا بالنسبة له اللي هو الـ linear speed
+
+301
+00:22:21,330 --> 00:22:25,290
+اللي هي الحركة الخطية أو المسافة الخطية اللي مشيها
+
+302
+00:22:25,290 --> 00:22:29,820
+جبناها باستخدام السرعة الخطية tangential أو
+
+303
+00:22:29,820 --> 00:22:35,220
+المماسية مع الزمن اللي هو المعطى ساعة ضربناهم
+
+304
+00:22:35,220 --> 00:22:38,240
+في بعض وطلع عندي أربعة آلاف وستمائة وثمانين متر
+
+305
+00:22:38,240 --> 00:22:43,280
+طبعاً هنا متر لأنه هذه مسافة خطية وهنا سرعة
+
+306
+00:22:43,280 --> 00:22:48,120
+tangential وهنا اللي هو الزمن اللازم اللي هو واحد
+
+307
+00:22:48,120 --> 00:22:52,260
+أولاً حولنا من الساعة إلى ثانية اللي هي ثلاث آلاف وستمائة
+
+308
+00:22:52,260 --> 00:22:56,400
+ثلاث آلاف وستمائة الأول هذه المقصود فيها هي الساعة
+
+309
+00:22:56,400 --> 00:23:00,340
+طبعاً إن شاء الله نستكمل المحاضرة القادمة إن شاء
+
+310
+00:23:00,340 --> 00:23:00,520
+الله
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2hg30QN6v_A_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2hg30QN6v_A_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..32fe8853b968c2ece72280d5d4c9accdb0170b4e
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/2hg30QN6v_A_raw.srt
@@ -0,0 +1,1252 @@
+1
+00:00:01,210 --> 00:00:04,170
+بسم الله الرحمن الرحيم section 72 rotational
+
+2
+00:00:04,170 --> 00:00:08,410
+motion under constant angular acceleration الحركة
+
+3
+00:00:08,410 --> 00:00:15,330
+الدورانية تحت تأثير اللي هو تسارع زاوى ثابت a
+
+4
+00:00:15,330 --> 00:00:20,060
+number of parallel exist betweenthe equation for
+
+5
+00:00:20,060 --> 00:00:22,440
+rotational motion and those for linear motion فيه
+
+6
+00:00:22,440 --> 00:00:28,840
+طبعا هي ك بالظبط توازي بين اللي هي معادلات الحركة
+
+7
+00:00:28,840 --> 00:00:32,020
+الخطية و معادلات الحركة الدورانية ولكن مع تغيير
+
+8
+00:00:32,020 --> 00:00:38,480
+اللي هو الرموز و مقارنتهم مع بعض طبعا هي تغيير
+
+9
+00:00:38,480 --> 00:00:42,420
+تكافي لإن في بينهم نصف قطر بيدوروا زي مثلا ال
+
+10
+00:00:42,420 --> 00:00:47,700
+omega اللي هي ال average angular velocityبساوي θ
+
+11
+00:00:47,700 --> 00:00:51,820
+final نخص θ initial على T final نخص T initial دلتا
+
+12
+00:00:51,820 --> 00:00:56,800
+تتا دلتا T طبعا بكافئها أو مقابل لها اللي هي
+
+13
+00:00:56,800 --> 00:01:02,260
+السرعة الخطية اللي هي V average مكافئة بساوي X
+
+14
+00:01:02,260 --> 00:01:05,780
+final نخص X initial على T final نخص T initial دلتا
+
+15
+00:01:05,780 --> 00:01:11,420
+X على دلتا Tفي هذه الحالة أوميجا يأخذ المكان يعني
+
+16
+00:01:11,420 --> 00:01:15,180
+الآن حطينا الأوميجا بدل ال V و Theta بدل ال X و
+
+17
+00:01:15,180 --> 00:01:21,820
+Alpha بدل ال A in the same way في نفس اللحظة every
+
+18
+00:01:21,820 --> 00:01:26,480
+linear quantity we have encountered so far has
+
+19
+00:01:26,480 --> 00:01:30,670
+corresponding to in rotational motionيعني في علاقة
+
+20
+00:01:30,670 --> 00:01:35,450
+بين الحركة الخطية و الحركة الدورانية لكن الآن احنا
+
+21
+00:01:35,450 --> 00:01:39,310
+بنحط في القوانين الحركة الخطية لها قوانين و
+
+22
+00:01:39,310 --> 00:01:43,170
+الدورانية لها قوانين لكن الرموز بتختلف لكن نفس
+
+23
+00:01:43,170 --> 00:01:46,970
+القوانين تقريبا ولكن في علاقة بين الحركة الخطية و
+
+24
+00:01:46,970 --> 00:01:51,450
+الحركة الدورانية الآن معادلات الحركة الدورانية
+
+25
+00:01:51,450 --> 00:01:57,180
+الخطية اللي هي .. و الخطيةLinear motion with a
+
+26
+00:01:57,180 --> 00:02:01,060
+constant هنا rotational motion with alpha constant
+
+27
+00:02:01,060 --> 00:02:04,920
+اللي بالنسبة لأ الخطية كان عندنا V بيساوي V
+
+28
+00:02:04,920 --> 00:02:07,960
+initial زايد AT في الدورانية Omega بيساوي Omega
+
+29
+00:02:07,960 --> 00:02:12,180
+initial زايد Alpha T ال Omega بدل V و ال Omega
+
+30
+00:02:12,180 --> 00:02:15,700
+initial بدل Omega V initial و ال T زي ما هي و ال A
+
+31
+00:02:15,700 --> 00:02:20,400
+بدلنا معها Alpha إذا الخانون التاني Delta X بتساوي
+
+32
+00:02:20,400 --> 00:02:24,610
+V initial T زايد نص AT تربيعو Delta Theta بالساوية
+
+33
+00:02:24,610 --> 00:02:28,570
+Omega initial T زايد نص Alpha T تربيع V تربيع
+
+34
+00:02:28,570 --> 00:02:31,130
+بالساوية V initial تربيع زايد اتنين Alpha Delta X
+
+35
+00:02:31,130 --> 00:02:33,510
+و Omega تربيع بالساوية V initial تربيع زايد اتنين
+
+36
+00:02:33,510 --> 00:02:37,170
+Alpha Delta Theta باللاحظ انه نفس قوانين الحركة
+
+37
+00:02:37,170 --> 00:02:43,530
+ولكن هي حاجة تمثل حركة خطية تمثل حركة دورانية نجي
+
+38
+00:02:43,530 --> 00:02:49,210
+لل quiz بيحكي لنا ارجع لل quiz واحد طبعا عند احنا
+
+39
+00:02:49,210 --> 00:02:52,930
+زوجين يعني زوجين من اللي هي displacementأو ال
+
+40
+00:02:52,930 --> 00:02:56,730
+position في ال initial و ال final السؤال if the
+
+41
+00:02:56,730 --> 00:02:59,810
+object start from rest لو بدأ من ال rest يعني
+
+42
+00:02:59,810 --> 00:03:02,210
+omega initial zero at the initial angular
+
+43
+00:03:02,210 --> 00:03:05,130
+positions move count و بتحرك counter clockwise
+
+44
+00:03:05,130 --> 00:03:08,890
+يعني بزيد with constant angular acceleration all
+
+45
+00:03:08,890 --> 00:03:11,230
+arrives at the final angular position with the
+
+46
+00:03:11,230 --> 00:03:14,410
+same angular velocity in all three casesطبعاً إنا
+
+47
+00:03:14,410 --> 00:03:17,930
+تلت حالات في عندنا الحالة الأولى ال position الأول
+
+48
+00:03:17,930 --> 00:03:21,510
+ستة و النهائي ستة تلتة و النهائي ستة ال position
+
+49
+00:03:21,510 --> 00:03:25,390
+الأولى ينقص واحد و النهائي واحد طبعاً هذا فيه a
+
+50
+00:03:25,390 --> 00:03:29,690
+δماصر θ ال c هذا θ initial واحد till final خمسة
+
+51
+00:03:29,690 --> 00:03:34,550
+المطلوب من هدول القيم ال initial و ال final بتكون
+
+52
+00:03:34,550 --> 00:03:39,650
+فيها ال angular accelerationاللي هي السرعة الزاوية
+
+53
+00:03:39,650 --> 00:03:46,050
+السرعة التسارق الزاوي أعلى حاجة طبعا إذا كانت طبعا
+
+54
+00:03:46,050 --> 00:03:49,570
+إحنا ال alpha بتساوي أمجا تربيع ناقص أمجا initial
+
+55
+00:03:49,570 --> 00:03:52,730
+تربيع على اتنين delta تيتا إذا كانت delta تيتا أقل
+
+56
+00:03:52,730 --> 00:03:56,730
+ما يمكن بتكون alpha أكبر ما يمكن فمتى كانت delta
+
+57
+00:03:56,730 --> 00:04:00,970
+تيتا أقل ما يمكن لما كانت ال theta initial ناقص
+
+58
+00:04:00,970 --> 00:04:04,590
+واحد و ال final واحد كنا نحكي واحد ناقص ناقص واحد
+
+59
+00:04:04,590 --> 00:04:09,020
+بتطلع اتنينأقل من تلاتة point واحد أربعة إذا هذي B
+
+60
+00:04:09,020 --> 00:04:12,260
+هو الجواب الصحيح هذي بتكون Delta Theta أقل ما يمكن
+
+61
+00:04:12,260 --> 00:04:16,120
+وبالتالي Alpha أكبر ما يمكن the highest value
+
+62
+00:04:16,120 --> 00:04:19,160
+section
+
+63
+00:04:19,160 --> 00:04:25,680
+سابعة تلاتة اللي هي بيحكي read it by yourself from
+
+64
+00:04:25,680 --> 00:04:30,130
+the textbook اقرأه بنفسك موجودة في الكتابالان ا
+
+65
+00:04:30,130 --> 00:04:33,070
+will rotate with constant angular acceleration
+
+66
+00:04:33,070 --> 00:04:42,710
+العجلة بتدور بتسارع زاوية ثابت بساوية تلاتة rad
+
+67
+00:04:42,710 --> 00:04:46,510
+per second square زي ما هو موجود تلاتة و نص rad
+
+68
+00:04:46,510 --> 00:04:50,110
+per second square if the angular velocity زي كانت
+
+69
+00:04:50,110 --> 00:04:54,370
+السرعة الزاوية للعجلة اتنين rad per second لما
+
+70
+00:04:54,370 --> 00:04:57,760
+كانت بالساوية زيرو يعني omega initial بالساوية2
+
+71
+00:04:57,760 --> 00:05:02,460
+لما T بالساوية 0 الآن السؤال ال throw up angle بس
+
+72
+00:05:02,460 --> 00:05:05,800
+ده will rotate between feet T بالساوية 0 ل T
+
+73
+00:05:05,800 --> 00:05:10,980
+بالساوية 2 قالب الزاوية اللي بدور فيها يعني مطلوب
+
+74
+00:05:10,980 --> 00:05:17,420
+مننا نوجد اللي هو بالبدأ نوجد فيتا طبعا هذا السؤال
+
+75
+00:05:17,420 --> 00:05:24,270
+ممكن انحل موجود في الكتاب محلول حله بالكتابممكن
+
+76
+00:05:24,270 --> 00:05:28,870
+تشجع على الكتاب وانحله بمعادلات الحركة في N دي T
+
+77
+00:05:28,870 --> 00:05:33,210
+بالساوة Zero T بالساوة اتنين Omega initial بتساوية
+
+78
+00:05:33,210 --> 00:05:38,830
+اتنين ايضا و ال acceleration بتساوية تلاتة طالب
+
+79
+00:05:38,830 --> 00:05:42,430
+فيتا ممكن فيتا او دولتا فيتا بالساوية Omega
+
+80
+00:05:42,430 --> 00:05:48,850
+initial في T زائد نصالـ Alpha T تربيع فبنعود عن
+
+81
+00:05:48,850 --> 00:05:52,990
+Omega initial ب Zero و بعدين نص فى Alpha اللى هى
+
+82
+00:05:52,990 --> 00:05:55,450
+تلاتة و نص فى T تربيع اللى هى اتنين تربيع بتطلع
+
+83
+00:05:55,450 --> 00:06:02,770
+عند Peta كمان ممكن احنا نحولها الى evaluation من
+
+84
+00:06:02,770 --> 00:06:06,430
+الراد لل evaluation او العكس what is the angular
+
+85
+00:06:06,430 --> 00:06:09,530
+velocity بده طالب ال Omega النهائية لما T بالساوة
+
+86
+00:06:09,530 --> 00:06:13,700
+اتنين ال Omega النهائية نحكي Omegafinal بيساوي
+
+87
+00:06:13,700 --> 00:06:17,560
+امجي initial زائد alpha T والمعطلات كلها موجودة
+
+88
+00:06:17,560 --> 00:06:23,240
+معانا ان شاء الله initial
+
+89
+00:06:23,240 --> 00:06:27,640
+section تلاتة سبعة تلاتة tangential velocity
+
+90
+00:06:27,640 --> 00:06:30,220
+tangential acceleration and centripetal
+
+91
+00:06:30,220 --> 00:06:35,200
+acceleration ال tangential يعني السرع الممسية و
+
+92
+00:06:35,200 --> 00:06:40,360
+التسارع الممسي tangential ممس و التسارع اللي هي
+
+93
+00:06:40,360 --> 00:06:46,540
+المركزي centripetalالتسارع اللى هى المركزى نجلى ال
+
+94
+00:06:46,540 --> 00:06:49,380
+section الاول tangential velocity and acceleration
+
+95
+00:06:49,380 --> 00:06:53,680
+ال angular variable angular variable are related
+
+96
+00:06:53,680 --> 00:06:57,940
+to the linear variables consider الان المتغيرات
+
+97
+00:06:57,940 --> 00:07:01,320
+اللى موجودة عندى اللها علاقة بدأوجد علاقتها مع
+
+98
+00:07:01,320 --> 00:07:06,020
+يعني بدأوجد علاقة المتغيرات الخطية بالمتغيرات
+
+99
+00:07:06,020 --> 00:07:11,540
+الزاوية المتغيرات يعني X و V و A بيقش علاقتها
+
+100
+00:07:11,540 --> 00:07:16,520
+بفيتاو Omega و Alpha طبعا بأفرض في عندي أنا مجسم
+
+101
+00:07:16,520 --> 00:07:21,740
+بهذا الشكل طبعا بدور حركة دورانية X عقرب الساعة ال
+
+102
+00:07:21,740 --> 00:07:24,660
+X-axis هذا عبارة عن reference line خط اللي مطلوب
+
+103
+00:07:24,660 --> 00:07:30,260
+منه لو كانت النقطة B كانت مثلا هنا و اتحركت و وصلت
+
+104
+00:07:30,260 --> 00:07:35,330
+النقطة B فمشيت مزاحة اللي هي Delta فيتابسموها الـ
+
+105
+00:07:35,330 --> 00:07:38,930
+Angular Displacement وعملت لقوس Delta AS اللي انا
+
+106
+00:07:38,930 --> 00:07:42,270
+عند النقطة بيه باخد المماس المماس ده هي عبارة عن
+
+107
+00:07:42,270 --> 00:07:46,010
+Linear Velocity عند هذه النقطة Linear Velocity عند
+
+108
+00:07:46,010 --> 00:07:50,550
+هذه النقطة إيش علاقة ال Omega بيه ال V؟ بدنا
+
+109
+00:07:50,550 --> 00:07:55,590
+نعرفها لإلا دلتا T تبساو دلتا S على R لما أجي أقسم
+
+110
+00:07:55,590 --> 00:08:00,730
+الطرفين على Delta T قسم الطرفين على Delta Tبطلع
+
+111
+00:08:00,730 --> 00:08:05,110
+Delta T ثيتا على Delta T هي عبارة عن اللي هي
+
+112
+00:08:05,110 --> 00:08:11,450
+نسميها Omega بتساوي واحد على R في طبعا Delta S على
+
+113
+00:08:11,450 --> 00:08:15,310
+Delta T V طب when Delta T is very small Delta T
+
+114
+00:08:15,310 --> 00:08:19,250
+صغيرة كتير فDelta T ثيتا على Delta T عبارة عن
+
+115
+00:08:19,250 --> 00:08:22,810
+بتكون قريبا من اللي هي السرعة الزاوية اللحظية
+
+116
+00:08:22,810 --> 00:08:28,540
+Omega وبالتاليأيضا Delta S على Delta T سرعة لحظية
+
+117
+00:08:28,540 --> 00:08:34,360
+خطية إذا Delta T تصبح صغيرة في معنى الكلام Omega
+
+118
+00:08:34,360 --> 00:08:38,400
+فهذه الحالة بساوية V على R Omega بساوية V على R أو
+
+119
+00:08:38,400 --> 00:08:42,140
+V بساوية R في Omega هذه أعطتنا علاقة بين السرعة
+
+120
+00:08:42,140 --> 00:08:46,620
+الزاوية وبين اللي هي السرعة الخطية Vt اللي هي
+
+121
+00:08:46,620 --> 00:08:49,880
+عبارة عن tangential السرعة الممسية بساوية R في
+
+122
+00:08:49,880 --> 00:08:53,340
+Omegaالـ V بيساوي VT بيساوي tangential velocity
+
+123
+00:08:53,340 --> 00:08:59,760
+اللي هي السرعة الممسية طبعا معادلة 17 توضح السرعة
+
+124
+00:08:59,760 --> 00:09:04,680
+الممسية عند نقطة معينة خلال دوران الجسم وقبلها
+
+125
+00:09:04,680 --> 00:09:09,800
+طبعا هو بيزداد increasing as that point is moved
+
+126
+00:09:09,800 --> 00:09:14,140
+outward from the center of the rotation toward rim
+
+127
+00:09:14,140 --> 00:09:17,360
+as expected however every point on the rotating
+
+128
+00:09:17,360 --> 00:09:21,220
+object has the same angular velocityطبعا زى ما
+
+129
+00:09:21,220 --> 00:09:25,280
+حكينا سابقا اى جسم بدور كل نقطة على هذا الجسم
+
+130
+00:09:25,280 --> 00:09:29,700
+بيكون النقاط كلها لها نفس اللى هى السرعة الزاوية
+
+131
+00:09:29,700 --> 00:09:32,820
+ال angular velocity ال tangential speed is the
+
+132
+00:09:32,820 --> 00:09:36,060
+magnitude of the tangential velocity and is also
+
+133
+00:09:36,060 --> 00:09:39,300
+called tangential speed هى نفس ال tangential
+
+134
+00:09:39,300 --> 00:09:43,440
+velocity وتسمى ال linear speed ال linear speed
+
+135
+00:09:45,430 --> 00:09:51,430
+معادلة 17 صحيحة لما تكون الـ omega تقاس بالrad per
+
+136
+00:09:51,430 --> 00:09:55,670
+unit time suppose a rotating object لو كان عندي
+
+137
+00:09:55,670 --> 00:10:00,250
+أنجسيم برضه بدور و بتتغير ال angular speed من
+
+138
+00:10:00,250 --> 00:10:05,620
+delta omegaتغيرات خلال فترة زمنية Delta T معناه
+
+139
+00:10:05,620 --> 00:10:10,520
+الكلام ان Delta V بتساوي R في Delta Omega طبعا
+
+140
+00:10:10,520 --> 00:10:14,320
+همقسم على Delta T لان بدأ اوجد العلاقة بين ال
+
+141
+00:10:14,320 --> 00:10:19,980
+Alpha و ال A as the time interval Delta T أيضا
+
+142
+00:10:19,980 --> 00:10:23,880
+صغيرة جدا فDelta Omega ع Delta T بيسموها
+
+143
+00:10:23,880 --> 00:10:29,820
+Instantaneous Angular Accelerationو Delta .. طبعا
+
+144
+00:10:29,820 --> 00:10:33,340
+V على Delta T بيسموها Instantaneous Tangential
+
+145
+00:10:33,340 --> 00:10:37,900
+Acceleration Tangential Acceleration ما هي الكلام
+
+146
+00:10:37,900 --> 00:10:42,300
+الآن أوجدت العلاقة بين A Tangential Acceleration و
+
+147
+00:10:42,300 --> 00:10:47,620
+Angular اللي هي Acceleration اذا AT بيساوي ال R في
+
+148
+00:10:47,620 --> 00:10:52,040
+Alpha بين هم R اللي هي نص القطر AT بيساوي ال R في
+
+149
+00:10:52,040 --> 00:10:57,870
+ال Alpha مرة تانيةالradian measure must be used
+
+150
+00:10:57,870 --> 00:11:00,510
+for the angular acceleration term in this equation
+
+151
+00:11:00,510 --> 00:11:05,670
+في هذه المعادلة طبعا بقيس ال alpha بال radian ممكن
+
+152
+00:11:05,670 --> 00:11:08,070
+أن اقيس ال angular acceleration بالradius per
+
+153
+00:11:08,070 --> 00:11:12,530
+second squared الان
+
+154
+00:11:12,530 --> 00:11:17,670
+quiz 7-4 بيحكي اللي في يدي شخص اسمه andrew and
+
+155
+00:11:17,670 --> 00:11:22,370
+chuck شخصيا are riding on a merry-go-round under a
+
+156
+00:11:22,370 --> 00:11:26,280
+andrew rides on a horseat the outer rim of the
+
+157
+00:11:26,280 --> 00:11:30,520
+circular platform في السباق اللي .. اللي هي الحصن
+
+158
+00:11:30,520 --> 00:11:36,440
+أو ال .. ال .. ال .. يعني حلقة للسباق في عند شخصين
+
+159
+00:11:36,440 --> 00:11:40,240
+في شخص راكب على الحصان و بيدور على دراع طبعا ال
+
+160
+00:11:40,240 --> 00:11:43,580
+circular platform على اللي هي الدائرة اللي اعترفها
+
+161
+00:11:43,580 --> 00:11:47,740
+twice as far from the center of the circular على
+
+162
+00:11:47,740 --> 00:11:52,180
+بعد طبعا twice as far from the center of the
+
+163
+00:11:52,180 --> 00:11:58,840
+circularplatform as it shook واحد بيتحرك على مسافة
+
+164
+00:11:58,840 --> 00:12:02,420
+على طرف اللي هي الحلقة الحلقة اللي هي السباق تبع
+
+165
+00:12:02,420 --> 00:12:07,780
+الحصن وواحد موجود في على بعد يعني نص اللي هي نص نص
+
+166
+00:12:07,780 --> 00:12:13,420
+القطار هو راد on the inner horse طبعا راكب على
+
+167
+00:12:13,420 --> 00:12:16,360
+الحصان بالداخل when the wheel go around in
+
+168
+00:12:16,360 --> 00:12:21,450
+rotating at constant angular speedممكن هي نفسرها
+
+169
+00:12:21,450 --> 00:12:26,270
+زى اللعبة اللى موجودة على الحصان اللى هى اللى عندى
+
+170
+00:12:26,270 --> 00:12:30,990
+انا disk كبير وفي عندى إحصانين إحصان موجود على طرف
+
+171
+00:12:30,990 --> 00:12:35,730
+هذه الدائرة و إحصان موجود على في نص المسافة بين نص
+
+172
+00:12:35,730 --> 00:12:40,090
+القطار فى شخصين ركبين طبعا و ال disk هدا بدور ك ..
+
+173
+00:12:40,090 --> 00:12:44,990
+ك .. يعني كلعبه ممكن نفسرها كإيه كحلقة سباق و طبعا
+
+174
+00:12:44,990 --> 00:12:48,780
+ركاب موجودين على الحصانالان شخصيا اللي هو ال
+
+175
+00:12:48,780 --> 00:12:54,220
+android and the truck twice trucks الان ال android
+
+176
+00:12:54,220 --> 00:12:58,260
+is angular speed ال android angular speed is twice
+
+177
+00:12:58,260 --> 00:13:02,180
+truck ولا the same as the truck ولا half of the
+
+178
+00:13:02,180 --> 00:13:05,520
+truck او impossible to determine هاي طبعا الرسمة
+
+179
+00:13:05,520 --> 00:13:09,840
+هذه الرسمة هذه نفس الرسمة هذه عبارة عن اللعبة هنا
+
+180
+00:13:09,840 --> 00:13:13,900
+في ديسك كبير بدور اللحوص اللي موجودين يعني لمسافات
+
+181
+00:13:13,900 --> 00:13:16,380
+واحد موجود على الطرف والتاني موجود في النص بالشكل
+
+182
+00:13:16,380 --> 00:13:19,780
+هذاواحد على الطرف والتاني في نص المسافة و ال disk
+
+183
+00:13:19,780 --> 00:13:25,360
+هذا ايش بدور الان بيحكيلي طبعا mean ال angular
+
+184
+00:13:25,360 --> 00:13:30,960
+اللي هي ال angular هنا بيحكيلي انه بالنسبة لل
+
+185
+00:13:30,960 --> 00:13:34,040
+angular speed بالنسبة لل angular speed ال mean
+
+186
+00:13:34,040 --> 00:13:38,480
+أكبر من التاني طبعا ال angular speed عشان هالزاوية
+
+187
+00:13:38,480 --> 00:13:41,420
+حكينا عند أي نقطة على هذا ال disk فال angular
+
+188
+00:13:41,420 --> 00:13:44,720
+speed واحدة عند أي نقطة على ال disk فال angular
+
+189
+00:13:44,720 --> 00:13:53,170
+speed واحدةالحل اللى هو بالنسبة للحل اللى هو B
+
+190
+00:13:53,170 --> 00:13:57,770
+بالنسبة للسؤال التانى بنرجع ل ال quiz نفس السؤال
+
+191
+00:13:57,770 --> 00:14:02,910
+بدنا اللى هى ال angular tangential speed
+
+192
+00:14:02,910 --> 00:14:05,650
+tangential tangential speed دلوقت بدنا ال velocity
+
+193
+00:14:05,650 --> 00:14:09,130
+طبعا ال velocity فى لها علاقة بينها و بين ال R ال
+
+194
+00:14:09,130 --> 00:14:13,130
+R نص الخطر علاقة اللى هى السرعة الخطية مع اللى هى
+
+195
+00:14:13,130 --> 00:14:16,920
+ال angular velocity فى بينهم ال Rبالنسبة لل
+
+196
+00:14:16,920 --> 00:14:19,200
+angular velocity جميع النخاط نفس ال angular
+
+197
+00:14:19,200 --> 00:14:21,880
+velocity لكن بالنسبة لل tangential speed أو ال
+
+198
+00:14:21,880 --> 00:14:26,420
+tangential velocity بيختلف حسب اللى هو البعد عن
+
+199
+00:14:26,420 --> 00:14:30,240
+المركز او محور الدوران الان بيحكي ل وين ده merry
+
+200
+00:14:30,240 --> 00:14:33,340
+go around بالنسبة لهذا ال disk الكبير اللى بدور
+
+201
+00:14:33,340 --> 00:14:37,910
+طبعا بالنسبة لكوين سبعة اربعةrotating at constant
+
+202
+00:14:37,910 --> 00:14:39,630
+angular speed بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك
+
+203
+00:14:39,630 --> 00:14:39,630
+بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك
+
+204
+00:14:39,630 --> 00:14:40,010
+بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك بتحرك
+
+205
+00:14:40,010 --> 00:14:40,650
+بتحرك بتحرك بتحرك بتحرك بتحريك بتحريك بتحريك
+
+206
+00:14:40,650 --> 00:14:41,270
+بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك
+
+207
+00:14:41,270 --> 00:14:42,930
+بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك
+
+208
+00:14:42,930 --> 00:14:42,930
+بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك
+
+209
+00:14:42,930 --> 00:14:45,010
+بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك بتحريك
+
+210
+00:14:45,010 --> 00:14:45,010
+بتحريك بتحريك بتحريك بتحريك
+
+211
+00:15:10,830 --> 00:15:18,250
+نرجع لـ example 7-3 comeback disk ال CD بدور حوالي
+
+212
+00:15:18,250 --> 00:15:22,410
+from rest up to angular velocity بدأ من ال rest و
+
+213
+00:15:22,410 --> 00:15:27,490
+وصل ل angular velocity of minus 31.4 rad per
+
+214
+00:15:27,490 --> 00:15:32,290
+second in time of في زمن قدره 0.892 what is the
+
+215
+00:15:32,290 --> 00:15:34,590
+angular acceleration of the disk بدنا ال angular
+
+216
+00:15:34,590 --> 00:15:40,440
+acceleration ل ال disk نحلطبعا عندى انا angular
+
+217
+00:15:40,440 --> 00:15:43,280
+acceleration بدى انا التسارع الزاوى عندنا معطيات
+
+218
+00:15:43,280 --> 00:15:47,520
+اعطانى omega ناقص واحد و تلاتين way of T اذا ال
+
+219
+00:15:47,520 --> 00:15:50,860
+alpha بتساوي omega على T لان omega initial زيرو T
+
+220
+00:15:50,860 --> 00:15:54,040
+initial بساوي زيرو فلو قدرت طبخت القانون الاول من
+
+221
+00:15:54,040 --> 00:15:56,800
+قوانين الحركة omega بتساوي omega initial زايد
+
+222
+00:15:56,800 --> 00:16:00,440
+alpha T ف omega initial زيرو اذا ال alpha بتساوي
+
+223
+00:16:00,440 --> 00:16:04,240
+omega على T بنعود عن ال omega بإشرتها بتطلع ل
+
+224
+00:16:04,240 --> 00:16:10,030
+alpha ناقص35.2 rad per second squared في السؤال B
+
+225
+00:16:10,030 --> 00:16:13,950
+بيحكيلنا through what angle does the disc turn؟
+
+226
+00:16:14,430 --> 00:16:18,810
+بيدّو الزاوية اللي ال disk بدور فيها كلمة الزاوية
+
+227
+00:16:18,810 --> 00:16:23,870
+اللي ال disk بدور فيها يعني إيجاد ثيتا الان T
+
+228
+00:16:23,870 --> 00:16:26,750
+بتساوي point تمانية تسعة و ال Omega initial zero
+
+229
+00:16:26,750 --> 00:16:30,070
+هي المعطيات بستخدم القانون اللي هو Delta Theta
+
+230
+00:16:30,070 --> 00:16:36,010
+بتساوي Omega initial T زائد نص Alpha T تربيع Omega
+
+231
+00:16:36,010 --> 00:16:40,030
+initial كانت Zero إذا نص ال Alpha كانت ناقص خمسة و
+
+232
+00:16:40,030 --> 00:16:43,010
+تلاتين point اتنين rad per second square وT تربيع
+
+233
+00:16:43,010 --> 00:16:46,310
+بتساوي point تمانيةتسعة اتنين بيطلع برضه ناقص
+
+234
+00:16:46,310 --> 00:16:52,830
+اربعتاش Red في C مطلوب find the final tangential
+
+235
+00:16:52,830 --> 00:16:57,310
+velocity بدي ال V بدي ال final tangential velocity
+
+236
+00:16:57,310 --> 00:17:03,510
+of a microbe at اللي هي لما تكون R اربعة point
+
+237
+00:17:03,510 --> 00:17:08,030
+اربعة خمسةطبعاً في علاقة بين ال angular velocity و
+
+238
+00:17:08,030 --> 00:17:11,350
+tangential velocity اللي هي V tangential بالساوية
+
+239
+00:17:11,350 --> 00:17:15,410
+R في Omega أعطينا ال R اللي هي point O أربع أربع
+
+240
+00:17:15,410 --> 00:17:18,230
+متر اللي كانت أعطانيها أربع point أربع خمس صنط
+
+241
+00:17:18,230 --> 00:17:22,210
+حولناها لمتر طبعاً ضربناها في عشر أسالي باتنين أو
+
+242
+00:17:22,210 --> 00:17:26,910
+على مية تطلع ل point O أربع أربع متر ضربناها في
+
+243
+00:17:26,910 --> 00:17:30,890
+اللي هي ال Omega ناقص واحد بتلاتين point أربع rad
+
+244
+00:17:30,890 --> 00:17:34,490
+per second تطلع ناقص واحد point أربعمتر في ات
+
+245
+00:17:34,490 --> 00:17:39,290
+ثانية في دي طالب ال tangential acceleration
+
+246
+00:17:39,290 --> 00:17:43,390
+tangential acceleration لما تكون ال R اربعة point
+
+247
+00:17:43,390 --> 00:17:48,470
+اربعة خمسة سانتي اذا ال A tangential تساوي ال R في
+
+248
+00:17:48,470 --> 00:17:52,830
+الفا ال R حولت المتر السانت لمتر نفسها والالفا
+
+249
+00:17:52,830 --> 00:17:55,830
+ناقص خمسة و تلاتين point اتنين rad per second
+
+250
+00:17:55,830 --> 00:17:58,730
+square تطلع ناقص واحد point خمسة سبعة متر في
+
+251
+00:17:58,730 --> 00:18:06,600
+الثانية اكتر بيهexample سبعة أربعة in a comeback
+
+252
+00:18:06,600 --> 00:18:11,660
+disc أيضا bear any disc بدور as the read head move
+
+253
+00:18:11,660 --> 00:18:15,220
+out from the center of the disc the angular speed
+
+254
+00:18:15,220 --> 00:18:18,440
+of the disc change so that the linear speed of the
+
+255
+00:18:18,440 --> 00:18:22,100
+position of the head remain at a constant value
+
+256
+00:18:22,100 --> 00:18:26,080
+about واحد point تلاتة متر فيئة ثانية find the
+
+257
+00:18:26,080 --> 00:18:31,880
+angular speed of CD of radius ستة centimeterwhen
+
+258
+00:18:31,880 --> 00:18:35,980
+the red head is at R بالساوية اتنين طبعا ال CD هو
+
+259
+00:18:35,980 --> 00:18:40,520
+بتحرك فيه معلومات طبعا هو بيقرأها ل .. لما يكون في
+
+260
+00:18:40,520 --> 00:18:45,060
+عند راس او ابره صغيرة بتكون على طبعا هو بدور ال CD
+
+261
+00:18:45,060 --> 00:18:49,440
+و هو بدور بي .. بيعلم أن مسافات معينة و بعضها عن
+
+262
+00:18:49,440 --> 00:18:53,940
+المحور بيعطيني عند مثلا R بالساوية واحد اتنين
+
+263
+00:18:53,940 --> 00:18:56,900
+تلاتة كذا لعند R نص الخطوة بيعطيني كل المعلومات
+
+264
+00:18:56,900 --> 00:19:02,880
+على مسافات معينة منالان بيحكي لنا find the angular
+
+265
+00:19:02,880 --> 00:19:06,940
+speed of CD radius 6 cm when the read head لما
+
+266
+00:19:06,940 --> 00:19:13,120
+تكون القراءة مركزة على ال R بتساوية 2 cm وبعدين
+
+267
+00:19:13,120 --> 00:19:20,140
+نجدها لما R بيصير 5.6الحل طبعا طبعنا find the
+
+268
+00:19:20,140 --> 00:19:24,040
+angular speed of the disk when the read head at R
+
+269
+00:19:24,040 --> 00:19:27,980
+بيساوي 2 او اه وR كمان بيساوي 5.6 لانه نعيد الحل
+
+270
+00:19:27,980 --> 00:19:32,620
+مرتين الان ال V بيساوي R في Omega ال R بتها تساوي
+
+271
+00:19:32,620 --> 00:19:38,000
+2 اذا اللي هي ال V tangential على ال R بيعطيني
+
+272
+00:19:38,000 --> 00:19:43,680
+Omega ال V tangential كانت 1.3 و ال R كانت 2 فعشرة
+
+273
+00:19:43,680 --> 00:19:49,050
+أص نقص 2 بيعطيني 65 rad per secondبالظبط نفس اللي
+
+274
+00:19:49,050 --> 00:19:53,590
+عملناها لأ اللي هي ال R بيساوي اتنين بنعمل ال R
+
+275
+00:19:53,590 --> 00:19:56,650
+بيساوي خمسة point ستة and ال R بتساوي خمسة point
+
+276
+00:19:56,650 --> 00:20:02,310
+ستة بتكون Omega تلاتة و عشرين راد per second في B
+
+277
+00:20:02,310 --> 00:20:08,730
+find the linear speed in متر في التانية of خمسة و
+
+278
+00:20:08,730 --> 00:20:12,730
+أربعين هنا revolution per minute زي ما حكيناrecord
+
+279
+00:20:12,730 --> 00:20:19,290
+at point 2 cm and 5.6 cm لان بدى احول الرف بير
+
+280
+00:20:19,290 --> 00:20:25,650
+minute بدى اضرب اللى هى 45 رف بير minute بتساوي 45
+
+281
+00:20:25,650 --> 00:20:31,190
+فى 2 باى على اللى هو 60 اللى هى ال evaluation
+
+282
+00:20:31,190 --> 00:20:41,700
+الدورة 2 باى على 60 بتساوي 4.7 عرات بير secondلإنه
+
+283
+00:20:41,700 --> 00:20:46,900
+اه صحيح خمسة وعربين evaluation per minute
+
+284
+00:20:46,900 --> 00:20:52,900
+calculate the linear speed at .. لإن الدورة
+
+285
+00:20:52,900 --> 00:20:55,760
+الكاملة هي عبارة عن اتنين باى الدورة الكاملة هي
+
+286
+00:20:55,760 --> 00:20:59,880
+عبارة عن اتنين باى اللي هي مية للاتنين باى يعني
+
+287
+00:20:59,880 --> 00:21:03,440
+تلتنية وستين درجة اتنين باى فcalculate the linear
+
+288
+00:21:03,440 --> 00:21:08,140
+speed at R بالساوة اتنين is tangential بالساوة R
+
+289
+00:21:08,140 --> 00:21:12,890
+في Omegaبنعوض عن ال R بنعوض عن ال Omega اللى احنا
+
+290
+00:21:12,890 --> 00:21:18,330
+طلعناها هنا تعطينا طبعا point oh تسعة اربعة متر في
+
+291
+00:21:18,330 --> 00:21:23,790
+الثانية ال calculator دلوقت دا linear speed بتعوز
+
+292
+00:21:23,790 --> 00:21:27,070
+لل linear speed لما R بالساوية خمسة point ستة
+
+293
+00:21:27,070 --> 00:21:31,250
+فبنعوض V tangential بالساوية R في Omega بنعوض عن
+
+294
+00:21:31,250 --> 00:21:34,050
+ال R اللى هى الجديدة اللى أعطانيها بنحول من سنة ل
+
+295
+00:21:34,050 --> 00:21:41,790
+مترعشان هيك صارت 5.6×10-9 في ال omega 4.71 rad per
+
+296
+00:21:41,790 --> 00:21:47,230
+second تطلع 0.26 متر في الثاني في C calculate the
+
+297
+00:21:47,230 --> 00:21:51,310
+total length of the track for CD designed to play
+
+298
+00:21:51,310 --> 00:21:56,330
+for one hour بدنا ال total length ال total length
+
+299
+00:21:56,330 --> 00:22:00,550
+طبعا احنا بدنا خط الآن فبستخدم ال V tangential مع
+
+300
+00:22:00,550 --> 00:22:06,610
+الزمن اللي أعطانياهالـD بدها تساوي 1.3 في اللي هي
+
+301
+00:22:06,610 --> 00:22:12,210
+ال hour اللي هي ال hour عبارة عن 60 في 60 60 دقيقة
+
+302
+00:22:12,210 --> 00:22:16,290
+و الدقيقة ستين تانية تطلع 3600 تانية الساعة بتطلع
+
+303
+00:22:16,290 --> 00:22:21,330
+4700 متر هذا بالنسبة له اللي هو ال linear speed
+
+304
+00:22:21,330 --> 00:22:25,290
+اللي هي الحركة الخطية أو المسافة الخطية اللي مشيها
+
+305
+00:22:25,290 --> 00:22:29,820
+جيبناها باستخدامالسرعة الخطية tangential او
+
+306
+00:22:29,820 --> 00:22:35,220
+الممسية مع الزمن اللى هو المعطى واحد ساعة ضربناهم
+
+307
+00:22:35,220 --> 00:22:38,240
+في بعض وطلع عندى اربعمية اربع تلاف وسبعميت متر
+
+308
+00:22:38,240 --> 00:22:43,280
+طبعا هنا متر لإنه هدى دى مسافة خطية و هنا سرعة
+
+309
+00:22:43,280 --> 00:22:48,120
+tangential و هنا اللى هو الزمن اللازم اللى هو واحد
+
+310
+00:22:48,120 --> 00:22:52,260
+اول حولنا من الساعة إلى ثانية اللى هى الف وستمية
+
+311
+00:22:52,260 --> 00:22:56,400
+.. تلت الف وستميةالأول هذه المقصود فيها ايه الساعة
+
+312
+00:22:56,400 --> 00:23:00,340
+طبعا ان شاء الله نستكمل المحاضرة القادمة ان شاء
+
+313
+00:23:00,340 --> 00:23:00,520
+الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g.srt
new file mode 100644
index 0000000000000000000000000000000000000000..169de25a3f8ede7c9484df6350b101bab13b2929
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g.srt
@@ -0,0 +1,1327 @@
+
+1
+00:00:00,990 --> 00:00:05,950
+بسم الله الرحمن الرحيم problem-solving strategy
+
+2
+00:00:05,950 --> 00:00:13,590
+طريقة حل المسائل طبعا هنا هذا الموضوع اللي هو ال
+
+3
+00:00:13,590 --> 00:00:17,850
+work-energy theorem أو تغيرات الطاقة apply
+
+4
+00:00:17,850 --> 00:00:20,930
+conservation of mechanical energy لما بده ييجي
+
+5
+00:00:20,930 --> 00:00:25,990
+عندي أنا السؤال هطبق اللي هي الطاقة الميكانيكية
+
+6
+00:00:26,440 --> 00:00:29,460
+take the following steps when applying
+
+7
+00:00:29,460 --> 00:00:31,820
+conservation of mechanical energy to problems
+
+8
+00:00:31,820 --> 00:00:35,900
+involving gravity طبعا لما أجي أحل السؤال و أطبق
+
+9
+00:00:35,900 --> 00:00:39,180
+اللي هي أحله عن طريق تغيرات الطاقة أو الطاقة
+
+10
+00:00:39,180 --> 00:00:43,510
+الميكانيكية، نمروحها define the system including all
+
+11
+00:00:43,510 --> 00:00:47,170
+interacting bodies أول شيء بحدد من المتغيرات
+
+12
+00:00:47,170 --> 00:00:53,390
+الموجودة في السؤال يعني المعطيات والمجاهيل، verify
+
+13
+00:00:53,390 --> 00:00:57,470
+the absence of non-conservative forces بحدد أنه هذا
+
+14
+00:00:57,470 --> 00:01:01,110
+النظام أو هذه المثلة فيها احتكاك أو ما فيها احتكاك
+
+15
+00:01:01,110 --> 00:01:04,310
+طبعا إذا ما فيها احتكاك هي conservative، إذا ما
+
+16
+00:01:04,310 --> 00:01:07,410
+فيها احتكاك .. إذا فيه احتكاك طبعا non-
+
+17
+00:01:07,410 --> 00:01:09,570
+conservative، إذا ما فيها احتكاك conservative
+
+18
+00:01:10,370 --> 00:01:14,730
+النمرة اتنين choose the equation for Y طبعا بختار
+
+19
+00:01:14,730 --> 00:01:17,730
+برضه level النمرة اتنين بختار ال level، ال level ها ده
+
+20
+00:01:17,730 --> 00:01:21,750
+بيكون ال Y بيساوي Zero، بيسموها أو Zero Potential
+
+21
+00:01:21,750 --> 00:01:25,790
+Gravitational Potential Energy، بختار level بعدين
+
+22
+00:01:25,790 --> 00:01:32,810
+بختار نقطتين، نقطة طبعا initial و final point، one
+
+23
+00:01:32,810 --> 00:01:35,470
+point where you have given information، نقطة بيكون
+
+24
+00:01:35,470 --> 00:01:38,010
+المعلومات الموجودة عندي ونقطة تانية بيطلب مني
+
+25
+00:01:38,010 --> 00:01:42,670
+المعلومات اللي لازمة سواء كان سرعة نهائية سواء
+
+26
+00:01:42,670 --> 00:01:46,290
+سرعة ابتدائية و هكذا، write down the conservation of
+
+27
+00:01:46,290 --> 00:01:50,890
+energy equation بعد هي بكتب المعادلة، المعادلة طبعا
+
+28
+00:01:50,890 --> 00:01:54,330
+احنا اخترنا level، اخترنا نقطتين، بكتب معادلة ال
+
+29
+00:01:54,330 --> 00:01:58,250
+conservation of energy اللي هي اللي هي نص MV
+
+30
+00:01:58,250 --> 00:02:03,450
+initial تربيع زائد MGH أو Mgy initial يساوي نص MV
+
+31
+00:02:03,450 --> 00:02:07,910
+final تربيع زائد Mgy final اللي هي المعادلة 5.15
+
+32
+00:02:07,910 --> 00:02:14,710
+بعد هيك بحدد المتغيرات أو المجاهيل الموجودة، ليه؟ كي
+
+33
+00:02:14,710 --> 00:02:18,910
+أحل بعوض عن المعطيات و بحل الأسئلة و بوجد المجاهيل
+
+34
+00:02:18,910 --> 00:02:24,270
+سواء كانت speed أو position أو أي أي مجهول موجود
+
+35
+00:02:24,270 --> 00:02:28,620
+في السؤال،الناجينية نطبق ما ذكرها سابقا في هذا ال
+
+36
+00:02:28,620 --> 00:02:34,100
+example، example 5.5 a diver of mass M dropped from
+
+37
+00:02:34,100 --> 00:02:37,660
+a port 10 متر above the water surface طبعا برضه
+
+38
+00:02:37,660 --> 00:02:44,220
+غواص، الغواص بده يغطس من ارتفاع 10 متر من أعلى
+
+39
+00:02:44,220 --> 00:02:48,260
+above the water، أعلى سطح المياه زي ما هو موضح
+
+40
+00:02:48,260 --> 00:02:52,480
+بالشكل، هي الغواص بده من هنا من المنصة هذه، ارتفاعها
+
+41
+00:02:52,480 --> 00:02:57,340
+عن السطح الميه كان 10 متر، طبعا الغواص بدأ إذا ..
+
+42
+00:02:57,340 --> 00:03:01,380
+إذا الغواص released أو بدأ من ال rest، بتكون V0، V
+
+43
+00:03:01,380 --> 00:03:04,720
+initial 0، وبالتالي ال energy zero، لما يبدأ الغواص
+
+44
+00:03:04,720 --> 00:03:09,180
+من هذه النقطة بتكون طاقة الوضع اللي هي أقصى ما
+
+45
+00:03:09,180 --> 00:03:14,260
+يمكن اللي هي MgY initial، طبعا غطس الغطاس و نزل وصل
+
+46
+00:03:14,260 --> 00:03:17,640
+على سطح الميه، سطح الميه بعتبره .. بعتبره هو ال
+
+47
+00:03:17,640 --> 00:03:20,580
+level، وبالتالي potential energy اللي هي هذه نقطة
+
+48
+00:03:20,580 --> 00:03:24,740
+ال final، يعني من البداية بعتبر أنه هنا ال level، نمر
+
+49
+00:03:24,740 --> 00:03:27,800
+اتنين، هي نقطة ال initial وهي نقطة ال final في ال
+
+50
+00:03:27,800 --> 00:03:32,820
+initial، بسأل نفسي في طاقة حركة؟ نعم؟ Zero، لإنه
+
+51
+00:03:32,820 --> 00:03:37,220
+السرعة Zero، إذا طاقة الوضع أقصى ما يمكن، لما يوصل
+
+52
+00:03:37,220 --> 00:03:40,160
+على سطح الميه اللي هي ال final بتكون طاقة الحركة
+
+53
+00:03:40,160 --> 00:03:45,000
+نصف V تربيع final وطاقة الوضع Zero، نشوف الحل زي ما
+
+54
+00:03:45,000 --> 00:03:51,200
+هو موضح في الكتاب، الحل neglect طبعا بيحكيلنا اهمل
+
+55
+00:03:51,200 --> 00:03:54,500
+مقاومة الهواء، استخدم use conservation of
+
+56
+00:03:54,500 --> 00:03:58,620
+mechanical energy، باستخدم قانون اللي هو الطاقة
+
+57
+00:03:58,620 --> 00:04:01,460
+الميكانيكية اللي هي ال conservation، يعني ال a initial
+
+58
+00:04:01,460 --> 00:04:05,620
+بتساوي ال a final أو k زائد b initial بتساوي k
+
+59
+00:04:05,620 --> 00:04:10,370
+زائد b، a final، find his speed 5 meters above، أوجد
+
+60
+00:04:10,370 --> 00:04:14,790
+سرعته على مسافة 5 متر من سطح الميه، يعني ماوصل لسطح
+
+61
+00:04:14,790 --> 00:04:20,670
+الميه، الحل find the diver's speed halfway down
+
+62
+00:04:20,670 --> 00:04:24,130
+طبعا المسافة الكلية كانت عشرة، مطلوب منه نوجد سرعته
+
+63
+00:04:24,130 --> 00:04:28,510
+على بعد 5 متر من سطح الميه، يعني الآن بختار نقطتين
+
+64
+00:04:28,510 --> 00:04:32,470
+نقطة البداية هي اللي هي على بعد عشرة، والنقطة
+
+65
+00:04:32,470 --> 00:04:36,030
+النهائية على بعد 5 من سطح الميه، السطح الميه هو ال
+
+66
+00:04:36,030 --> 00:04:39,170
+level، write the energy conservation equation and
+
+67
+00:04:39,170 --> 00:04:43,790
+supply the proper terms، إذا بدي أعوض فيه معادلات
+
+68
+00:04:43,790 --> 00:04:49,470
+اللي هي الطاقة الميكانيكية، Ke initial زائد Pe
+
+69
+00:04:49,470 --> 00:04:52,730
+initial بتساوي Ke final زائد Pe final، طاقة
+
+70
+00:04:52,730 --> 00:04:55,410
+الحركة زائد طاقة الوضع initial بتساوي طاقة الحركة
+
+71
+00:04:55,410 --> 00:05:00,110
+زائد طاقة الوضع final، في ال initial كانت نص mv
+
+72
+00:05:00,110 --> 00:05:04,630
+initial تربيع زائد mgy initial بتساوي نص mv final
+
+73
+00:05:04,630 --> 00:05:08,130
+تربيع زائد mgy final، طبعا في ال initial هو بدأ من
+
+74
+00:05:08,130 --> 00:05:12,730
+ال rest، فمعنى الكلام v initial بتساوي zero، cancel
+
+75
+00:05:12,730 --> 00:05:16,590
+the mass and solve for v final، طبعا بدي أرفع ال mass
+
+76
+00:05:16,590 --> 00:05:22,680
+من كل الأطراف، وهنا هعوض عنها بـ 0، إذاً 0 زائد gy
+
+77
+00:05:22,680 --> 00:05:27,780
+initial يساوي نص v final تربيع زائد gy final، طبعا
+
+78
+00:05:27,780 --> 00:05:33,660
+ال y final كانت خمسة، ال y initial كانت عشرة، فبنعوض
+
+79
+00:05:33,660 --> 00:05:37,040
+9.8 من عشرة اللي هي الجاذبية، ال y
+
+80
+00:05:37,040 --> 00:05:40,900
+initial كانت عشرة، و ال y final كانت خمسة، تطلع عند
+
+81
+00:05:40,900 --> 00:05:45,620
+v final 9.9 متر في الثانية، عند نقطة خمسة متر بتبعد
+
+82
+00:05:45,620 --> 00:05:50,790
+عن سطح المي اللي احنا اعتبرناه هو ال level، في B،
+
+83
+00:05:51,010 --> 00:05:54,850
+find the diver's speed at the water's surface، بدي
+
+84
+00:05:54,850 --> 00:05:59,690
+أنا أجد السرعة لما على سطح الميه، معناته ال Y بيساوي
+
+85
+00:05:59,690 --> 00:06:04,810
+Zero، هنستخدم نفس القانون اللي هي K زائد B initial
+
+86
+00:06:04,810 --> 00:06:08,550
+يساوي K زائد B final، ال K initial بدت من ال rest
+
+87
+00:06:08,550 --> 00:06:12,170
+أو released، معناته ال V initial Zero، إذا هدي Zero
+
+88
+00:06:12,170 --> 00:06:16,750
+MgY، Y كان عشرة، يساوي نص Mv final زائد Zero، تقريبا
+
+89
+00:06:16,750 --> 00:06:20,970
+وصلت اللي هي Mgy final Zero، لإنه وصلت على نفس ال
+
+90
+00:06:20,970 --> 00:06:24,930
+level، وأي طاقة وضع على ال level نفسه Y بيساوي Zero
+
+91
+00:06:24,930 --> 00:06:27,830
+وبالتالي ال potential energy بيساوي Zero، إذا V
+
+92
+00:06:27,830 --> 00:06:34,570
+final بتساوي جزر 2Gy initial، اللي هي 2 في 9.8 من 10
+
+93
+00:06:34,570 --> 00:06:37,610
+مضروبة في ال Y initial اللي هي 10، تطلع 14 متر في
+
+94
+00:06:37,610 --> 00:06:43,960
+الثانية عند سطح الميه، النشلة example خمسة ستة
+
+95
+00:06:43,960 --> 00:06:49,800
+powerful across chubar launch itself at an angle
+
+96
+00:06:49,800 --> 00:06:52,400
+of 45° above the horizontal and rises to
+
+97
+00:06:52,400 --> 00:06:56,000
+the maximum height of 1 متر during the ليب
+
+98
+00:06:56,000 --> 00:07:02,620
+الجندب تبع الحقول، طبعا الطار من الأرض، يجي ندب أو أي
+
+99
+00:07:02,620 --> 00:07:06,360
+حشرة أو أي جسم طار من سطح الأرض ممكن نعتبرها كرة
+
+100
+00:07:06,360 --> 00:07:13,640
+حجر، جسم طبعا الطار بزاوية 45 درجة هنا بسرعة
+
+101
+00:07:13,640 --> 00:07:18,780
+ابتدائية V initial، هو طاير طبعا وصل لأقصى ارتفاع
+
+102
+00:07:18,780 --> 00:07:22,260
+عند أقصى ارتفاع في هذه المنطقة بتكون السرعة
+
+103
+00:07:22,260 --> 00:07:26,800
+النهائية باتجاه Y 0، السرعة الابتدائية هي نفس السرعة
+
+104
+00:07:26,800 --> 00:07:33,570
+باتجاه X، مابتتغيرش، إذن هنا إنه بيحكي لإنه powerful
+
+105
+00:07:33,570 --> 00:07:37,530
+crust shovel launches itself at angle 45 away from
+
+106
+00:07:37,530 --> 00:07:40,910
+the horizontal and rises to maximum height، ارتفاع
+
+107
+00:07:40,910 --> 00:07:45,730
+عند أقصى ارتفاع كان واحد متر خلال during the leap
+
+108
+00:07:45,730 --> 00:07:49,870
+with what speed v initial did it leave the ground؟
+
+109
+00:07:50,290 --> 00:07:53,390
+بدي السرعة الابتدائية اللي هدا الجندب أو هدا
+
+110
+00:07:53,390 --> 00:07:57,950
+الحشرة تركت الأرض أو طارته، واضح السؤال بدأ الجسم
+
+111
+00:07:57,950 --> 00:08:02,250
+من هنا بدأ V initial، زاوية، أول حاجة بنعملها بدي
+
+112
+00:08:02,250 --> 00:08:07,150
+أحلل ال V initial إلى مركبتين، V initial cosine ال
+
+113
+00:08:07,150 --> 00:08:12,630
+45 و V initial sine ال 45، الآن V initial X بتتغيرش
+
+114
+00:08:12,630 --> 00:08:17,050
+على طول ال trajectory، طول مسار هدا الطيران لعند
+
+115
+00:08:17,050 --> 00:08:21,820
+أقصى ارتفاع، الآن دا استخدم قانون ال conservation of
+
+116
+00:08:21,820 --> 00:08:27,640
+energy، ده نستخدم ال conservation of energy و نحل ..
+
+117
+00:08:27,640 --> 00:08:31,320
+نستخدم ال conservation of energy و نحل السؤال
+
+118
+00:08:31,320 --> 00:08:38,830
+السؤال، طبعا، حكاية ليه؟ Substitute، بدي أحط V initial
+
+119
+00:08:38,830 --> 00:08:43,590
+V initial الموجودة حاليًا لمركباتها، Y initial 0، بدي
+
+120
+00:08:43,590 --> 00:08:48,710
+أعتبر أن هذا هو ال level، و V final هي نفسها V X
+
+121
+00:08:48,710 --> 00:08:54,190
+لأن V final باتجاه ال Y بيساوي Zero، ال Y final هي
+
+122
+00:08:54,190 --> 00:08:59,000
+ال H maximum، معنى الكلام معناته أنه هي ال .. يعني
+
+123
+00:08:59,000 --> 00:09:02,400
+هذا الكلام ما فيش عندنا friction، وبالتالي هي اللي
+
+124
+00:09:02,400 --> 00:09:04,960
+عن طريق ال gravity أو الجاذبية، هو بتطير بفعل
+
+125
+00:09:04,960 --> 00:09:09,600
+جاذبية، إذا أن بأستخدم conservation force، إذا أن
+
+126
+00:09:09,600 --> 00:09:12,780
+بأستخدم أن .. أنه طاقة الميكانيكية initial بيساوي
+
+127
+00:09:12,780 --> 00:09:17,180
+الطاقة الميكانيكية final، معناها نص Mv initial
+
+128
+00:09:17,180 --> 00:09:20,600
+تربيع زائد، زائد Mgy initial بتساوي نص Mv
+
+129
+00:09:20,600 --> 00:09:25,580
+final تربيع زائد Mgy final، هنعوض اللي هي ال V
+
+130
+00:09:25,580 --> 00:09:31,720
+initial، نص Mv initial تربيع بدها تساوي نص Mv X
+
+131
+00:09:31,720 --> 00:09:38,560
+تربيع زائد Mg اللي هو H، أقصى ارتفاع، H، ال initial
+
+132
+00:09:38,560 --> 00:09:41,660
+ال Mgy كانت بتساوي zero لإنه بدأ من نفس ال level
+
+133
+00:09:42,100 --> 00:09:46,240
+هضرب الطرفين طبعا هنا M على 2، بـ 2 على M علشان أضيع
+
+134
+00:09:46,240 --> 00:09:50,920
+اللي هي M على 2، M على 2، هضيع ال M على 2، بيظل عندنا
+
+135
+00:09:50,920 --> 00:09:57,340
+V initial تربيع بيساوي VX تربيع زائد 2GH، الآن
+
+136
+00:09:57,340 --> 00:10:03,100
+eliminate VX، بده أعوض عن VX من خلال تحليل اللي هي
+
+137
+00:10:03,100 --> 00:10:07,600
+ال V initial، هنعوض عنها بـ substituting VX بتساوي V
+
+138
+00:10:07,600 --> 00:10:15,890
+initial cosine 45، إذاً VAI تربيعها تساوي VX تربيع
+
+139
+00:10:15,890 --> 00:10:19,890
+اللي هي عبارة عن V Initial Cos 45 الكل تربيع زائد
+
+140
+00:10:19,890 --> 00:10:26,110
+2GH، عوضنا عنها هنا، Cos 45 اللي هي 1 على جزر
+
+141
+00:10:26,110 --> 00:10:29,440
+2، لما أجي أربعها بتصير نص، بتصير عندنا V initial
+
+142
+00:10:29,440 --> 00:10:34,160
+تربيع بدها تساوي نص V initial تربيع زائد 2GH،
+
+143
+00:10:34,160 --> 00:10:38,360
+إذا V initial في هذه الحالة زي ما تساوي 2 جزر GH،
+
+144
+00:10:38,360 --> 00:10:42,340
+الجي تسعة و 8 من عشرة، و ال H واحد، integer،
+
+145
+00:10:42,340 --> 00:10:48,260
+طلعنا السرعة الابتدائية اللي هدا الحشرة اطارت فيها،
+
+146
+00:10:48,260 --> 00:10:52,800
+نجي ل section خمسة أربعة، gravity and non-
+
+147
+00:10:52,800 --> 00:10:56,260
+conservative forces، الآن الجاذبية والقوة الغير
+
+148
+00:10:56,260 --> 00:11:00,870
+محفوظة، when non-conservative forces are involved
+
+149
+00:11:00,870 --> 00:11:05,750
+along with gravitation, the full work-energy theorem
+
+150
+00:11:05,750 --> 00:11:09,710
+must be used, often with techniques from topics for
+
+151
+00:11:09,710 --> 00:11:14,030
+solving problems require the basic procedure of
+
+152
+00:11:14,030 --> 00:11:17,070
+the problem-solving strategy for conservation of
+
+153
+00:11:17,070 --> 00:11:20,270
+energy problems in the previous section، إيش معناها
+
+154
+00:11:20,270 --> 00:11:26,580
+لما أنا استخدم، لما تكون عندي القوة غير محفوظة، طبعا
+
+155
+00:11:26,580 --> 00:11:31,140
+involved along، غير محفوظة إضافة لإيه؟ اللي هي الشغل
+
+156
+00:11:31,140 --> 00:11:34,300
+الناتج عن الجاذبية أو طاقة الوضع الخاصة بالجاذبية،
+
+157
+00:11:34,300 --> 00:11:39,020
+فال full work-energy theorem، نظرية كلية للطاقة
+
+158
+00:11:39,020 --> 00:11:44,020
+والشغل، ممكن أنا أستخدم أجمع الجهتين، even with
+
+159
+00:11:44,020 --> 00:11:48,800
+techniques .. بتكنيك معين، بأحل هذه المعادلة لكن
+
+160
+00:11:48,800 --> 00:11:53,320
+بحتاج إلى أساسيات وخطوات أساسية لحل هذه
+
+161
+00:11:53,320 --> 00:11:56,020
+الستراتيجية اللي هي conservation of energy problems
+
+162
+00:11:56,020 --> 00:11:59,980
+في ال previous section، ممكن أنا أحل اللي هي
+
+163
+00:11:59,980 --> 00:12:03,810
+conservative و non-conservative في مسألة واحدة، The
+
+164
+00:12:03,810 --> 00:12:07,290
+only difference lies in substituting equation 5
+
+165
+00:12:07,290 --> 00:12:11,310
+.13، the work-energy equation with potential
+
+166
+00:12:11,310 --> 00:12:16,550
+energy for equation 5.15، طبعا هنوضع هذا الكلام في
+
+167
+00:12:16,550 --> 00:12:22,280
+هذا المثال، يعني ممكن احنا نحل اللي هي
+
+168
+00:12:22,280 --> 00:12:24,820
+ال conservative و ال non-conservative في سؤال واحد
+
+169
+00:12:24,820 --> 00:12:28,780
+فـ في الحالة بيكون عندي الشغل الكلي هو عبارة عن شغل non-
+
+170
+00:12:28,780 --> 00:12:32,340
+conservative وشغل conservative، يعني طاقة
+
+171
+00:12:32,340 --> 00:12:34,920
+الميكانيكية final ناقص الطاقة الميكانيكية
+
+172
+00:12:34,920 --> 00:12:39,120
+initial بيساوي الشغل الناتج عن الاحتكاك، طبعا نجلة
+
+173
+00:12:39,120 --> 00:12:43,390
+هذا السؤال، water slides، شوان شوان زي ما أنتم احنا
+
+174
+00:12:43,390 --> 00:12:47,270
+شايفين اللي هو، طبعا ال water slides اللي هو اللي
+
+175
+00:12:47,270 --> 00:12:51,510
+بتزلقوا حتى يوصلوا للميه، وطبعا يقطصوا في الميه عن
+
+176
+00:12:51,510 --> 00:12:57,570
+طريق مسار معين، ال hand determine the speed of، بدا
+
+177
+00:12:57
+
+223
+00:16:21,670 --> 00:16:26,850
+وصت ل level الـ Y final بتساوي 0 ناقص 60 في 9.8 في
+
+224
+00:16:26,850 --> 00:16:34,420
+21.9 إذن بيطلع عندي W and C بيساوي ناقص تلاتة point
+
+225
+00:16:34,420 --> 00:16:38,900
+واحد وستة من عشرة تقريبا تلاتة G هذا الشغل المبذول
+
+226
+00:16:38,900 --> 00:16:44,320
+بواسطة الاحتكاك example
+
+227
+00:16:44,320 --> 00:16:45,060
+آخر
+
+228
+00:16:48,330 --> 00:16:54,950
+نجلة example خمسة تمانية scars start from breast
+
+229
+00:16:54,950 --> 00:17:05,530
+طبعا برضه بتزلج أو بتتزلج بدأ من الـ wrist من أعلى
+
+230
+00:17:05,530 --> 00:17:12,010
+decline height من أعلى سطح مايل frictionless وليست
+
+231
+00:17:12,010 --> 00:17:17,440
+خشنة أملس يعني عن ارتفاع عشرين متر، طبعا هي الشكل
+
+232
+00:17:17,440 --> 00:17:25,720
+لأن شخص بيتزلج على مسار ما ناعم أملس، ممكن يكون
+
+233
+00:17:25,720 --> 00:17:29,280
+ثلج، ممكن يكون أي سطح أملس، بدأ من النقطة A وصل
+
+234
+00:17:29,280 --> 00:17:33,300
+للنقطة B، هذا اتزلج، بدأ من ارتفاع عشرين متر على
+
+235
+00:17:33,300 --> 00:17:37,700
+سطح مايل، السطح المايل طبعا مايل بزاوية θ نشوف
+
+236
+00:17:37,700 --> 00:17:42,740
+السؤال مطلوب .. مطلوب منا نشوف السؤال السؤال find
+
+237
+00:17:42,740 --> 00:17:48,340
+the sky at speed at the bottom  لابد نوجد سرعة هذا
+
+238
+00:17:48,340 --> 00:17:53,820
+المتزلج على .. من النقطة A لنقطة B بعدين طالب how
+
+239
+00:17:53,820 --> 00:17:56,940
+far does the skier travel on the horizontal surface
+
+240
+00:17:56,940 --> 00:18:02,240
+before coming to rest مطلوب منا نوجد المسافة اللى
+
+241
+00:18:02,240 --> 00:18:09,330
+بيمشيها على السطح الأفقي قبل ما يقف يعني في البداية
+
+242
+00:18:09,330 --> 00:18:14,970
+بدأ من النقطة A وصل للنقطة B بدأ من ارتفاع 20 وصل
+
+243
+00:18:14,970 --> 00:18:19,230
+للنقطة B وبعدين من B طالب مني المسافة اللى بده
+
+244
+00:18:19,230 --> 00:18:22,890
+يمشيها على المستوى الأفقي لحتى يقف عند النقطة C
+
+245
+00:18:22,890 --> 00:18:28,720
+نبدأ نحل Solution A. Find the skier speed at the
+
+246
+00:18:28,720 --> 00:18:33,480
+bottom ببدأ أوجد اللي هو سرعة الـ skier هذا المتزلج
+
+247
+00:18:33,480 --> 00:18:38,860
+عند النقطة B Follow the procedure used in part A of
+
+248
+00:18:38,860 --> 00:18:41,780
+the previous example as the skier moves from the
+
+249
+00:18:41,780 --> 00:18:45,660
+top point A to the bottom point طبعا بدي أستخدم
+
+250
+00:18:45,660 --> 00:18:49,140
+نفس العلاقة اللي استخدمتها في السؤال الأول ونفس
+
+251
+00:18:49,140 --> 00:18:53,320
+الخطوات بسأل نفسي هل في احتكاك ولا مافي إذا مافي
+
+252
+00:18:53,320 --> 00:18:57,720
+احتكاك معناها أنه باستخدم اللي هو الـ E initial
+
+253
+00:18:57,720 --> 00:19:00,500
+بتساوي الـ E final الـ E هي عبارة عن طاقة وضع وحركة
+
+254
+00:19:00,500 --> 00:19:03,480
+في الـ initial بتساوي طاقة الوضع والحركة بالـ final
+
+255
+00:19:03,480 --> 00:19:07,760
+بالنسبة للـ initial طاقة الحركة zero فبيكون عندي
+
+256
+00:19:07,760 --> 00:19:12,400
+MGY initial بتساوي نصف MV final تربيع لأن أنا وصلت
+
+257
+00:19:12,400 --> 00:19:17,740
+لـ level باعتبر أن المنطقة هذه هي الـ level معناته
+
+258
+00:19:17,740 --> 00:19:20,820
+هذه النقطة الإبتدائية طاقة الحركة  Zero تغطي
+
+259
+00:19:20,820 --> 00:19:26,360
+الوضع Mgh أو Mgy في المنطقة هذه صارت نصف Mv تربيع
+
+260
+00:19:26,360 --> 00:19:29,920
+طاقة الوضع Zero لأن الـ Y بيساوي Zero لأنه وصلت ل
+
+261
+00:19:29,920 --> 00:19:35,000
+الـ level طبعا من خلال المعادلة بحصل على إنه الـ V
+
+262
+00:19:35,000 --> 00:19:40,600
+عند النقطة B بدها تساوي 2 جذر Gh يعني 2 جذر 9.8 في
+
+263
+00:19:40,600 --> 00:19:47,070
+الارتفاع كان 20 بتطلع عندي V B بيساوي 19.8 في B
+
+264
+00:19:47,070 --> 00:19:49,430
+مطلوب find the distance travelled on the
+
+265
+00:19:49,430 --> 00:19:52,670
+horizontal rough surface أو جد الآن المسافة
+
+266
+00:19:52,670 --> 00:19:57,190
+الأفقية اللي هذا المتزلج بيمشيها على مستوى خشن حتى
+
+267
+00:19:57,190 --> 00:20:01,690
+يصل أو يتوقف عند النقطة C طبعا applying the work
+
+268
+00:20:01,690 --> 00:20:05,250
+energy طالما أنا في احتكاك ببدأ أستخدم قانون اللي
+
+269
+00:20:05,250 --> 00:20:10,210
+هو الـ work energy theorem أو قانون نظرية الشغل والطاقة
+
+270
+00:20:10,210 --> 00:20:14,290
+اللي فيها احتكاك من القانون اللي هو W net بيساوي
+
+271
+00:20:14,290 --> 00:20:19,420
+ناقص FK في D بيساوي Delta K E طبعا هنا هو أشتغل على
+
+272
+00:20:19,420 --> 00:20:24,540
+المستوى الأفقي من النقطة B إلى النقطة C إذا الشغل
+
+273
+00:20:24,540 --> 00:20:28,160
+الناتج عن الاحتكاك اللي هو الشغل الكلي بيساوي ناقص
+
+274
+00:20:28,160 --> 00:20:33,700
+FK في D  FK بيساوي ميو K في الـ normal دلتا KE ليه
+
+275
+00:20:33,700 --> 00:20:38,300
+نصف MV final عند الـ C تربيع ناقص نصف MV initial
+
+276
+00:20:38,300 --> 00:20:42,660
+عند الـ C  حكاية الـ stop معناته VC بيساوي Zero والـ
+
+277
+00:20:42,660 --> 00:20:45,320
+FK بيساوي ميو K في الـ normal والـ normal بتساوي
+
+278
+00:20:45,320 --> 00:20:51,790
+الـ MG بنعوض ميو K ميو K ميو K ميو K ميو K ميو
+
+279
+00:20:51,790 --> 00:20:58,690
+K ميو K ميو K ميو K
+
+280
+00:21:04,680 --> 00:21:13,220
+VB تربيع على 2 ميو K في G فدي على المستوى الخشن كانت
+
+281
+00:21:13,220 --> 00:21:19,320
+هيمشي مسافة 95.2 V عند النقطة B اللي أنا طلعتها من
+
+282
+00:21:19,320 --> 00:21:24,960
+المطلوب الأول هو 2 جذر GH 19.8 تربيع على الـ 2
+
+283
+00:21:24,960 --> 00:21:31,230
+ميو K هو معامل الاحتكاك الحركي هو معطى مضروب في
+
+284
+00:21:31,230 --> 00:21:35,070
+تسعة و ثمانية من عشرة فبتطلع معي خمسة وتسعين
+
+285
+00:21:35,070 --> 00:21:38,610
+point اتنين متر هو المسافة اللي مشيها على المستوى
+
+286
+00:21:38,610 --> 00:21:44,790
+الخشن نجي
+
+287
+00:21:44,790 --> 00:21:49,410
+لـ section خمسة .. خمسة بعنوان spring potential
+
+288
+00:21:49,410 --> 00:21:54,410
+energy الـ spring potential energy اللي هو طاقة
+
+289
+00:21:54,410 --> 00:21:59,150
+الوضع داخل اللي هي النابض أو الـ spring الـ work done
+
+290
+00:21:59,150 --> 00:22:02,310
+by applied force is stretching or compressed
+
+291
+00:22:02,310 --> 00:22:05,790
+spring can be recovered by removing the applied
+
+292
+00:22:05,790 --> 00:22:10,130
+force so like gravity الآن بالنسبة للـ spring أو
+
+293
+00:22:10,130 --> 00:22:15,150
+النابض بعتبره قوة conservative محفوظة لأن
+
+294
+00:22:15,150 --> 00:22:20,430
+النابض ممكن يكون stretched يعني مشدود أو compressed
+
+295
+00:22:20,430 --> 00:22:25,860
+أو مضغوط كمان الـ spring برجع لب وضعه اللي كان عليه
+
+296
+00:22:25,860 --> 00:22:29,180
+يعني ممكن أنا أشده وأفلت وبرجع لوضعه أو أنا أضغط
+
+297
+00:22:29,180 --> 00:22:32,840
+وأفلت وبرجع لوضعه الطبيعي الـ spring force is
+
+298
+00:22:32,840 --> 00:22:35,440
+conservative زي ما حكينا الآن رجعنا لحكاية
+
+299
+00:22:35,440 --> 00:22:39,200
+السابقة أن conservative force هي الـ gravity أو
+
+300
+00:22:39,200 --> 00:22:41,880
+gravitational potential energy أو الـ spring force
+
+301
+00:22:41,880 --> 00:22:45,620
+يسموها conservative force as long as losses
+
+302
+00:22:45,620 --> 00:22:49,620
+through internal friction of the spring can be
+
+303
+00:22:49,620 --> 00:22:53,300
+neglected ممكن أعمل أنا احتكاك ناتج عن حلقات الـ
+
+304
+00:22:53,300 --> 00:22:56,220
+spring أو الـ spring أو النابض this means that
+
+305
+00:22:56,220 --> 00:22:59,640
+means a potential energy function can be found and
+
+306
+00:22:59,640 --> 00:23:02,180
+used in the work energy theory ممكن أطبق قانون
+
+307
+00:23:02,180 --> 00:23:10,580
+الشغل والطاقة على الـ spring يعني مثل لو كان
+
+308
+00:23:10,580 --> 00:23:14,100
+الـ spring لا هو مضغوط ولا مشدود فهذه باعتبرها نقطة
+
+309
+00:23:14,100 --> 00:23:17,680
+اتزان بيسموها equilibrium point equilibrium point
+
+310
+00:23:17,680 --> 00:23:22,140
+يعني X بيساوي 0 هذه الكتلة بعد هيك جيبت أنا
+
+311
+00:23:22,140 --> 00:23:28,170
+الكتلة وضغطت هذا الـ spring أو النابض ضغطته مسافة X
+
+312
+00:23:28,170 --> 00:23:32,770
+معناها هذا الـ spring إله طاقة وضع مرنة بيسموها
+
+313
+00:23:32,770 --> 00:23:37,070
+PE بيساوي نصف K X تربيع طبعا لما أنا أضغطه على
+
+314
+00:23:37,070 --> 00:23:41,050
+الآخر فالكتلة هذه بتتحركش بعدها بتتحركش فطاقة
+
+315
+00:23:41,050 --> 00:23:50,310
+الحركة للكتلة بيساوي Zero في C هنا لو أنا الـ spring
+
+316
+00:23:50,310 --> 00:23:55,450
+هذا أو النابض شديته أو stretched يعني شديته فبيكون أنه
+
+317
+00:23:55,450 --> 00:24:01,430
+عند نقطة الاتزان بتكون طاقة الوضع تبعته بيساوي
+
+318
+00:24:01,430 --> 00:24:06,240
+Zero لأنه فلت فلت بعد ما أنا كنت ضغطته فلت  هاللحظة
+
+319
+00:24:06,240 --> 00:24:12,180
+فلته الكتلة هاي بتتحرك بسرعة V وبالتالي لها طاقة
+
+320
+00:24:12,180 --> 00:24:18,100
+حركة نصف MV تربيع هنا لما يوصل لمنطقة الاتزان
+
+321
+00:24:18,100 --> 00:24:21,780
+بتكون الـ potential energy للـ spring بيساوي Zero
+
+322
+00:24:21,780 --> 00:24:26,560
+وهنا الكتلة تبدأ بأقصى سرعة لها وبأقصى طاقة حركتها
+
+323
+00:24:27,190 --> 00:24:32,130
+لو أنا أشد الـ spring مسافة معينة للآخر بتكون طاقة
+
+324
+00:24:32,130 --> 00:24:35,870
+الوضع للـ spring برضه نصف K X تربيع وطاقة الحركة
+
+325
+00:24:35,870 --> 00:24:40,150
+بتساوي Zero لكن هذه المرحلة لما يكون مضغوط
+
+326
+00:24:40,150 --> 00:24:45,020
+الـ spring وتركناه طبعا هذا الشكل بيوضح كيف الـ
+
+327
+00:24:45,020 --> 00:24:49,460
+spring ممكن يكون stretched أو .. أو اللي هي
+
+328
+00:24:49,460 --> 00:24:53,600
+compressed هذا الـ figure بيوضح الـ spring in its
+
+329
+00:24:53,600 --> 00:24:56,420
+equilibrium position where the spring is neither
+
+330
+00:24:56,420 --> 00:25:00,640
+compressed or يعني ممكن الـ spring هذا النابض ممكن
+
+331
+00:25:00,640 --> 00:25:04,830
+يكون مضغوط أو مشدود pushing block against spring as
+
+332
+00:25:04,830 --> 00:25:08,310
+figure طبعا زي ما هو موضح في الشكل خمسة واحد وعشرة
+
+333
+00:25:08,310 --> 00:25:11,510
+بيه compressed تبقى distance X  هذه distance X
+
+334
+00:25:11,510 --> 00:25:14,050
+represent the magnitude of the displacement from
+
+335
+00:25:14,050 --> 00:25:18,010
+the equilibrium position بيسموها اللي هي قيمة
+
+336
+00:25:18,010 --> 00:25:21,570
+الإزاحة اللي الـ spring أو النابض هو طبعا يا إما
+
+337
+00:25:21,570 --> 00:25:25,910
+بيكون مضغوط أو مشدود الـ X بيساوي Zero في حالة الـ
+
+338
+00:25:25,910 --> 00:25:31,250
+equilibrium position وبالتالي طالما أنه أو أنا
+
+339
+00:25:31,250 --> 00:25:36,050
+ضغطته أو شديته وإحنا شديناه أو ضغطناه بيكون عندي أنا
+
+340
+00:25:36,050 --> 00:25:40,670
+الإزاحة عكس القوة وبالتالي في عندي أنا قوة داخل الـ
+
+341
+00:25:40,670 --> 00:25:46,310
+spring بيسموها الـ Fspring Spring Force بتساوي ناقص KX
+
+342
+00:25:47,260 --> 00:25:50,480
+طبعا الـ X هو عبارة عن المسافة اللي الـ spring
+
+343
+00:25:50,480 --> 00:25:54,460
+انضغط أو انشدها والـ K بيسموها constant
+
+344
+00:25:54,460 --> 00:26:00,080
+proportionality ثابت التناسب للـ spring constant
+
+345
+00:26:00,080 --> 00:26:03,580
+طبعا carrying unit of a Newton's per meter لأن الـ
+
+346
+00:26:03,580 --> 00:26:12,040
+K هذه وحدتها Newton per meter حسب القانون الموجود
+
+347
+00:26:12,040 --> 00:26:15,100
+هذا بسميه Hooke's law هذه المعادلة بسميها قانون
+
+348
+00:26:15,100 --> 00:26:19,410
+Hooke القوة Fs is often called بيسموها restoring
+
+349
+00:26:19,410 --> 00:26:23,610
+force for positive value of x the force is
+
+350
+00:26:23,610 --> 00:26:29,070
+negative لما تكون الـ x موجبة بتكون الـ Fs سالبة
+
+351
+00:26:29,070 --> 00:26:32,890
+متجهة للخلف باتجاه  equilibrium at x بيساوي 0
+
+352
+00:26:32,890 --> 00:26:36,190
+and for negative x the force لما تكون الـ x بيساوي
+
+353
+00:26:36,190 --> 00:26:41,580
+سالبة القوة بتكون موجبة again pointing towards x
+
+354
+00:26:41,580 --> 00:26:45,240
+بيساو 0  the minus sign طبعا الإشارة السالبة
+
+355
+00:26:45,240 --> 00:26:49,240
+بمعناها إنها قوة الـ spring أو قوة النابض دائما
+
+356
+00:26:49,240 --> 00:26:53,060
+بتكون directed back towards the equilibrium point
+
+357
+00:26:53,060 --> 00:26:58,180
+دائما بتكون الـ spring force is always directed
+
+358
+00:26:58,180 --> 00:27:01,440
+back towards the equilibrium point بتكون دائما
+
+359
+00:27:01,440 --> 00:27:05,850
+راجعه لنقطة الاتزان as in the case of the
+
+360
+00:27:05,850 --> 00:27:09,750
+gravitation برضه نفس ما احنا شرحنا بالنسبة ل
+
+361
+00:27:09,750 --> 00:27:14,530
+gravitation أو potential energy أو اللي هو بيسموها
+
+362
+00:27:14,530 --> 00:27:17,110
+الـ elastic potential energy طاقة الوضع المرنة
+
+363
+00:27:17,110 --> 00:27:19,870
+المخزونة داخل الـ spring هي تعتبر conservative
+
+364
+00:27:19,870 --> 00:27:22,450
+force can be associated with the spring force
+
+365
+00:27:22,450 --> 00:27:25,490
+elastic potential energy is another way of looking
+
+366
+00:27:25,490 --> 00:27:28,030
+at the work done by spring during motion because
+
+367
+00:27:28,030 --> 00:27:32,890
+it is equal to the negative of the work done by the
+
+368
+00:27:32,890 --> 00:27:36,850
+spring طبعا الـ elastic potential energy بيسموها
+
+369
+00:27:36,850 --> 00:27:41,090
+طاقة زي ما حكينا طاقة وضع مرنة مخزونة داخل الـ
+
+370
+00:27:41,090 --> 00:27:44,250
+spring وهي طريقة ثانية عشان أنا ممكن أحسب الشغل
+
+371
+00:27:44,250 --> 00:27:49,270
+المبذول بواسطة الـ spring وهذا بيسموها طبعا طاقة وضع
+
+372
+00:27:49,270 --> 00:27:54,080
+لكنها مرنة  نصف KX تربيع ممكن هي تكون
+
+373
+00:27:54,080 --> 00:27:58,480
+مخزونة داخل الـ spring الـ spring ممكن يعمل شغل إذا
+
+374
+00:27:58,480 --> 00:28:02,800
+أنا شديته compressed or stretched ممكن أنا إذا كان الـ
+
+375
+00:28:02,800 --> 00:28:08,280
+spring أنا شديته أو ضغطته بكون أنا يعني بذلت شغل
+
+376
+00:28:08,280 --> 00:28:14,260
+فيه طبعا بنستكمل هذا الـ .. هذه التسجيلات وهذا
+
+377
+00:28:14,260 --> 00:28:16,340
+الشرح في المحاضرة القادمة إن شاء الله
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..3a7804d9eb180e44d49da686c7c0bf5ec65c99c7
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_postprocess.srt
@@ -0,0 +1,1508 @@
+1
+00:00:00,990 --> 00:00:05,950
+بسم الله الرحمن الرحيم problem solving strategy
+
+2
+00:00:05,950 --> 00:00:13,590
+طريقة حل المسائل طبعا هنا هذا الموضوع اللي هو ال
+
+3
+00:00:13,590 --> 00:00:17,850
+work energy theorem أو تغيرات الطاقة apply
+
+4
+00:00:17,850 --> 00:00:20,930
+conservation of mechanical energy لما بده ييجي
+
+5
+00:00:20,930 --> 00:00:25,990
+عندي أنا السؤال هطبق اللي هي الطاقة الميكانيكية
+
+6
+00:00:26,440 --> 00:00:29,460
+take the following steps when applying
+
+7
+00:00:29,460 --> 00:00:31,820
+conservation of mechanical energy to problems
+
+8
+00:00:31,820 --> 00:00:35,900
+involving gravity طبعا لما أجي أحل السؤال و أطبق
+
+9
+00:00:35,900 --> 00:00:39,180
+اللي هي أحله عن طريق تغيرات الطاقة أو الطاقة
+
+10
+00:00:39,180 --> 00:00:43,510
+الميكانيكيةنمروحها define the system including all
+
+11
+00:00:43,510 --> 00:00:47,170
+interacting body أول شيء بحدد من المتغيرات
+
+12
+00:00:47,170 --> 00:00:53,390
+الموجودة في السؤال يعني المعطيات والمجاهيل verify
+
+13
+00:00:53,390 --> 00:00:57,470
+the absence of non-conservative force بحدد أنه هذا
+
+14
+00:00:57,470 --> 00:01:01,110
+النظام أو هذه المثلة فيها احتكاك أو ما فيها احتكاك
+
+15
+00:01:01,110 --> 00:01:04,310
+طبعا إذا ما فيها احتكاك هي conservative إذا ما
+
+16
+00:01:04,310 --> 00:01:07,410
+فيها احتكاك .. إذا فيه احتكاك طبعا non
+
+17
+00:01:07,410 --> 00:01:09,570
+-conservative إذا ما فيها احتكاك conservative
+
+18
+00:01:10,370 --> 00:01:14,730
+النمرة اتنين choose ال equation for Y طبعا بختار
+
+19
+00:01:14,730 --> 00:01:17,730
+برضه level النمرة اتنين بختار level ال level ها ده
+
+20
+00:01:17,730 --> 00:01:21,750
+بيكون ال Y بيساوي Zero بيسموها أو Zero Potential
+
+21
+00:01:21,750 --> 00:01:25,790
+Gravitational Potential Energy بختار level بعدين
+
+22
+00:01:25,790 --> 00:01:32,810
+بختار نقطتين نقطة طبعا initial و final pointone
+
+23
+00:01:32,810 --> 00:01:35,470
+point where you have given information نقطة بيكون
+
+24
+00:01:35,470 --> 00:01:38,010
+المعلومات الموجودة عندي ونقطة تانية بيطلب مني
+
+25
+00:01:38,010 --> 00:01:42,670
+المعلومات اللي لازمة سواء كان سرعة نهائية سواء
+
+26
+00:01:42,670 --> 00:01:46,290
+سرعة تدائية و هكذا write down the conservation of
+
+27
+00:01:46,290 --> 00:01:50,890
+energy equation بعد هي بكتب المعادلةالمعادلة طبعا
+
+28
+00:01:50,890 --> 00:01:54,330
+احنا اخترنا level اخترنا نقطتين بكتب معادلة ال
+
+29
+00:01:54,330 --> 00:01:58,250
+conservation of energy اللي هي اللي هي نص MV
+
+30
+00:01:58,250 --> 00:02:03,450
+initial تربيع زاد MGH او Mgy initial ساوي نص MV
+
+31
+00:02:03,450 --> 00:02:07,910
+final تربيع زاد Mgy final اللي هي المعادلة 5.15
+
+32
+00:02:07,910 --> 00:02:14,710
+بعد هيك بحدد المتغيرات او المجاهيل الموجودةليه؟ كي
+
+33
+00:02:14,710 --> 00:02:18,910
+أحل بعوض عن المعطيات و بحل الأسئلة و بوجد المجاهد
+
+34
+00:02:18,910 --> 00:02:24,270
+سواء كانت speed أو position أو أي اي مجهول موجود
+
+35
+00:02:24,270 --> 00:02:28,620
+في السؤالالناجينية نطبق ما ذكرها سابقا في هذا ال
+
+36
+00:02:28,620 --> 00:02:34,100
+example example 55 a diver of mass M dropped from
+
+37
+00:02:34,100 --> 00:02:37,660
+a port 10 متر above the water surface طبعا برضه
+
+38
+00:02:37,660 --> 00:02:44,220
+غواص الغواص بده يغطس من ارتفاع 10 متر من أعلى
+
+39
+00:02:44,220 --> 00:02:48,260
+above the water أعلى سطح المياه زي ما هو موضح
+
+40
+00:02:48,260 --> 00:02:52,480
+بالشكل هي الغواص بده من هنا من المنصة هذهارتفاعها
+
+41
+00:02:52,480 --> 00:02:57,340
+عن السطح الميه كان 10 متر طبعا الغواص بدأ إذا ..
+
+42
+00:02:57,340 --> 00:03:01,380
+إذا الغواص released أو بدأ من ال rest بتكون V0 V
+
+43
+00:03:01,380 --> 00:03:04,720
+initial 0 وبالتالي ال energy zero لما يبدأ الغواص
+
+44
+00:03:04,720 --> 00:03:09,180
+من هذه النقطة بتكون طاقة الوضع اللي هي أقصى ما
+
+45
+00:03:09,180 --> 00:03:14,260
+يمكن اللي هي MgY initial طبعا غطس الغطاس و نزل وصل
+
+46
+00:03:14,260 --> 00:03:17,640
+على سطح الميه سطح الميه بعتبره .. بعتبره هو ال
+
+47
+00:03:17,640 --> 00:03:20,580
+level وبالتالي potential energy اللي هي هذه نقطة
+
+48
+00:03:20,580 --> 00:03:24,740
+ال finalيعني من البداية بعتبر أنه هنا ال level نمر
+
+49
+00:03:24,740 --> 00:03:27,800
+اتنين هي نقطة ال initial وهي نقطة ال final في ال
+
+50
+00:03:27,800 --> 00:03:32,820
+initial بسأل نفسي في طاقة حركة نعم؟ Zero لإنه
+
+51
+00:03:32,820 --> 00:03:37,220
+السرعة Zero إذا طاقة الوضع أقصى ما يمكن لما يوصل
+
+52
+00:03:37,220 --> 00:03:40,160
+على سطح الميه اللي هي ال final بتكون طاقة الحركة
+
+53
+00:03:40,160 --> 00:03:45,000
+نصف V تربيع final وطاقة الوضع Zero نشوف الحل زي ما
+
+54
+00:03:45,000 --> 00:03:51,200
+هو موضح في الكتابالحل neglect طبعا بيحكيلنا اهمل
+
+55
+00:03:51,200 --> 00:03:54,500
+مقاومة الهواء استخدم use conservation of
+
+56
+00:03:54,500 --> 00:03:58,620
+mechanical energy باستخدم قانون اللي هو الطاقة
+
+57
+00:03:58,620 --> 00:04:01,460
+الميكانيكية اللي هي ال conservation يعني a initial
+
+58
+00:04:01,460 --> 00:04:05,620
+بتساوي ال a final أو k زائد b initial بتساوي k
+
+59
+00:04:05,620 --> 00:04:10,370
+زائد b a finalfind his speed 5 meters above أوجد
+
+60
+00:04:10,370 --> 00:04:14,790
+سرعته على مسافة 5 متر من سطح الميه يعني ماوصل لسطح
+
+61
+00:04:14,790 --> 00:04:20,670
+الميه الحل find the divers speed half way down
+
+62
+00:04:20,670 --> 00:04:24,130
+طبعا المسافة الكلية كانت عشرة مطلوب منه نوجد سرعته
+
+63
+00:04:24,130 --> 00:04:28,510
+على بعد 5 متر من سطح الميه يعني الآن بختار نقطتين
+
+64
+00:04:28,510 --> 00:04:32,470
+نقطة البداية هي اللي هي على بعد عشرة و النقطة
+
+65
+00:04:32,470 --> 00:04:36,030
+النهائية على بعد 5 من سطح الميه السطح الميه هو ال
+
+66
+00:04:36,030 --> 00:04:39,170
+levelwrite the energy conservation equation and
+
+67
+00:04:39,170 --> 00:04:43,790
+supply the proper terms إذا بدي أعوض فيه معادلات
+
+68
+00:04:43,790 --> 00:04:49,470
+اللي هي الطاقة الميكانيكية K e initial زائد P e
+
+69
+00:04:49,470 --> 00:04:52,730
+initial بتساوي K e final زائد P e final طاقة
+
+70
+00:04:52,730 --> 00:04:55,410
+الحركة زائد طاقة الوضع initial بتساوي طاقة الحركة
+
+71
+00:04:55,410 --> 00:05:00,110
+زائد طاقة الوضع finalفي ال initial كانت نُص mv
+
+72
+00:05:00,110 --> 00:05:04,630
+initial تربيع زائد mgy initial بتساوي نُص mv final
+
+73
+00:05:04,630 --> 00:05:08,130
+تربيع زائد mgy final طبعا في ال initial هو بدأ من
+
+74
+00:05:08,130 --> 00:05:12,730
+ال rest فمعنى الكلام v initial بتساوي zero cancel
+
+75
+00:05:12,730 --> 00:05:16,590
+the mass and solve v final طبعا بدي أرفع ال mass
+
+76
+00:05:16,590 --> 00:05:22,680
+من كل الأطرافوهنا هعوض عنها بـ 0 إذاً 0 زائد gy
+
+77
+00:05:22,680 --> 00:05:27,780
+initial ساوي نص v final تربيه زائد gy final طبعا
+
+78
+00:05:27,780 --> 00:05:33,660
+ال y final كانت خمسةالـ y initial كانت عشرة فبنعوض
+
+79
+00:05:33,660 --> 00:05:37,040
+اتنين تسعة و تمانية من عشرة اللي هي الجاذبية ال y
+
+80
+00:05:37,040 --> 00:05:40,900
+initial كانت عشرة و ال y final كانت خمسة تطلع عند
+
+81
+00:05:40,900 --> 00:05:45,620
+v final 9.9 متر في الثانية عند نقطة خمسة متر بتبعد
+
+82
+00:05:45,620 --> 00:05:50,790
+عن سطح المي اللي احنا اكبرناه هو ال levelفي B,
+
+83
+00:05:51,010 --> 00:05:54,850
+find the diver's speed at the water's surface بدي
+
+84
+00:05:54,850 --> 00:05:59,690
+أنا أجد السرعة لما على سطح الميه معناته ال Y بساوة
+
+85
+00:05:59,690 --> 00:06:04,810
+Zero هنستخدم نفس القانون اللي هي K زائد B initial
+
+86
+00:06:04,810 --> 00:06:08,550
+بساوة K زائد B final ال K initial بدت من ال rest
+
+87
+00:06:08,550 --> 00:06:12,170
+أو released معناته ال V initial Zero إذا هدي Zero
+
+88
+00:06:12,170 --> 00:06:16,750
+MgY Y كان عشرةبساوة نص Mv final زائد Zero تقرينا
+
+89
+00:06:16,750 --> 00:06:20,970
+وصلت اللي هي Mgy final Zero لإنه وصلت على نفس ال
+
+90
+00:06:20,970 --> 00:06:24,930
+level و أي طاقة وضع على ال level نفسه Y بساوة Zero
+
+91
+00:06:24,930 --> 00:06:27,830
+وبالتالي ال potential energy بساوة Zero إذا V
+
+92
+00:06:27,830 --> 00:06:34,570
+final بتساوة جزر 2Gy initial اللي 2 في 9 و 8 من 10
+
+93
+00:06:34,570 --> 00:06:37,610
+مضروبة في ال Y initial اللي هي 10 تطلع 14 متر في
+
+94
+00:06:37,610 --> 00:06:43,960
+التانية عند سطح الميهالنشلة example خمسة ستة
+
+95
+00:06:43,960 --> 00:06:49,800
+powerful across chubar launch itself at an angle
+
+96
+00:06:49,800 --> 00:06:52,400
+of خمسة واربين above the horizontal and rises to
+
+97
+00:06:52,400 --> 00:06:56,000
+the maximum height of آحد متر during the ليب
+
+98
+00:06:56,000 --> 00:07:02,620
+الجندب تبع الحقولطبعا الطار من الأرض يجي ندب أو أي
+
+99
+00:07:02,620 --> 00:07:06,360
+حشر أو أي جسم طار من سطح الأرض ممكن نعتبرها كرة
+
+100
+00:07:06,360 --> 00:07:13,640
+حجر جسم طبعا الطار بزاوية 45 درجة هنا بسرعة
+
+101
+00:07:13,640 --> 00:07:18,780
+ابتدائية V initial هو طاير طبعا وصل لأقصى ارتفاع
+
+102
+00:07:18,780 --> 00:07:22,260
+عند أقصى ارتفاع في هذه المنطقة بتكون السرعة
+
+103
+00:07:22,260 --> 00:07:26,800
+النهائية باتجاه Y0 السرعة الابتدائية هي نفس السرعة
+
+104
+00:07:26,800 --> 00:07:33,570
+باتجاه X مابتتغيرشإذن هنا إنه بيحكي لإنه powerful
+
+105
+00:07:33,570 --> 00:07:37,530
+crust shovel launches itself at angle 45 away from
+
+106
+00:07:37,530 --> 00:07:40,910
+the horizontal and rises to maximum height ارتفاع
+
+107
+00:07:40,910 --> 00:07:45,730
+عند أقصى ارتفاع كان واحد متر خلال during the leap
+
+108
+00:07:45,730 --> 00:07:49,870
+with what speed v initial did it leave the ground
+
+109
+00:07:50,290 --> 00:07:53,390
+بدي السرعة الابتدائية اللى هدى الجندب أو هدى
+
+110
+00:07:53,390 --> 00:07:57,950
+الحشرة تركت الأرض أو طاعته واضح السؤال بدأ الجسم
+
+111
+00:07:57,950 --> 00:08:02,250
+من هنا بدأ V initial زاوية أول حاجة بنعملها بدي
+
+112
+00:08:02,250 --> 00:08:07,150
+أحلل ال V initial إلى مركبتين V initial cosine ال
+
+113
+00:08:07,150 --> 00:08:12,630
+45 و V initial sine ال 45 الآن V initial X بتتغيرش
+
+114
+00:08:12,630 --> 00:08:17,050
+على طول ال trajectory طول مسار هدى الطيران لعند
+
+115
+00:08:17,050 --> 00:08:21,820
+أقصى ارتفاعالأن دا استخدم قانون ال conservation of
+
+116
+00:08:21,820 --> 00:08:27,640
+energy ده نستخدم ال conservation energy و نحل ..
+
+117
+00:08:27,640 --> 00:08:31,320
+نستخدم ال conservation of energy و نحل السؤال
+
+118
+00:08:31,320 --> 00:08:38,830
+السؤال طبعاحكاية ليه؟ Substitute بدي أحط V initial
+
+119
+00:08:38,830 --> 00:08:43,590
+V initial موجودة حاليًا لمركباتها Y initial 0 بدي
+
+120
+00:08:43,590 --> 00:08:48,710
+أعتبر أن هذا هو ال level و V final هي نفسها V X
+
+121
+00:08:48,710 --> 00:08:54,190
+لإن V final بتجاه ال Y بيساوي Zero ال Y final هي
+
+122
+00:08:54,190 --> 00:08:59,000
+ال H maximumمعنى الكلام معناته أنه هي ال .. يعني
+
+123
+00:08:59,000 --> 00:09:02,400
+هذا الكلام مافيش عندنا friction وبالتالي هي اللي
+
+124
+00:09:02,400 --> 00:09:04,960
+عن طريق ال gravity أو الجاذبية هو بتطير بفعل
+
+125
+00:09:04,960 --> 00:09:09,600
+جاذبية إذا أن بأستخدم conservation force إذا أن
+
+126
+00:09:09,600 --> 00:09:12,780
+بأستخدم ان .. انه طاقة الميكانيكية initial بيساوي
+
+127
+00:09:12,780 --> 00:09:17,180
+الطاقة الميكانيكية finalمعناها نُص Mv initial
+
+128
+00:09:17,180 --> 00:09:20,600
+تربيع زائد نُص زائد Mgy initial بتساوي نُص Mv
+
+129
+00:09:20,600 --> 00:09:25,580
+final تربيع زائد Mgy final هنعوض اللي هي ال V
+
+130
+00:09:25,580 --> 00:09:31,720
+initial نُص Mv initial تربيع بدها تساوي نُص Mv X
+
+131
+00:09:31,720 --> 00:09:38,560
+تربيع زائد Mg اللي هو H أقصى ارتفاع H ال initial
+
+132
+00:09:38,560 --> 00:09:41,660
+ال Mgy كانت بتساوي zero لإنه بدأ من نفس ال level
+
+133
+00:09:42,100 --> 00:09:46,240
+هضرب الطرفين طبعا هنا M على 2 ب2 على M علشان أضيع
+
+134
+00:09:46,240 --> 00:09:50,920
+اللي هي M على 2 M على 2 هضيع ال M على 2 بيظل عندنا
+
+135
+00:09:50,920 --> 00:09:57,340
+V initial تربيع بيساوي VX تربيع زائد 2GH الان
+
+136
+00:09:57,340 --> 00:10:03,100
+eliminate VX بده أعوض عن VX من خلال تحليل اللي هي
+
+137
+00:10:03,100 --> 00:10:07,600
+ال V initial هنعوض عنها بsubstituting VX بتساوي V
+
+138
+00:10:07,600 --> 00:10:15,890
+initial cosine 45إذاً V A I تربيعها تسوى V X تربيع
+
+139
+00:10:15,890 --> 00:10:19,890
+اللي هي عبارة عن V Initial Cos 45 كل تربيع زائد
+
+140
+00:10:19,890 --> 00:10:26,110
+اتنين GH عوضنا عنها هنا Cos 45 اللي هي واحد ع جزر
+
+141
+00:10:26,110 --> 00:10:29,440
+اتنين لما أجي ربيعها بتصير نصبتصير عند V initial
+
+142
+00:10:29,440 --> 00:10:34,160
+تربيع بدها تساوي نص V initial تربيع زائد اتنين GH
+
+143
+00:10:34,160 --> 00:10:38,360
+اذا V initial في هذه الحالة زي تساوي اتنين جزر GH
+
+144
+00:10:38,360 --> 00:10:42,340
+الجي تسعة و تمانية من عشرة و ال H واحد integer
+
+145
+00:10:42,340 --> 00:10:48,260
+طلعنا السرعة الابتدائية اللى هدا الحشرة اطارت فيها
+
+146
+00:10:48,260 --> 00:10:52,800
+نجي ل section خمسة أربعة gravity and non
+
+147
+00:10:52,800 --> 00:10:56,260
+conservative force الان الجاذبية و القوة الغير
+
+148
+00:10:56,260 --> 00:11:00,870
+محفوظةwhen non conservative force are involved
+
+149
+00:11:00,870 --> 00:11:05,750
+along with gravitation the full work energy theory
+
+150
+00:11:05,750 --> 00:11:09,710
+must be used often with technique from topics for
+
+151
+00:11:09,710 --> 00:11:14,030
+solving problems require the basic procedure of
+
+152
+00:11:14,030 --> 00:11:17,070
+the problem solving strategy for conservation of
+
+153
+00:11:17,070 --> 00:11:20,270
+energy problem in the previous section ايش معناها
+
+154
+00:11:20,270 --> 00:11:26,580
+لما انا استخدم لما تكون عندى القوة غير محفوظةطبعا
+
+155
+00:11:26,580 --> 00:11:31,140
+involved along غير محفوظة إضافة لإيه اللي هي الشغل
+
+156
+00:11:31,140 --> 00:11:34,300
+الناتج عن الجاذبية أو طاقة الوضع الخاصة بالجاذبية
+
+157
+00:11:34,300 --> 00:11:39,020
+فال full work energy theorem نظرية كلية للطاقة
+
+158
+00:11:39,020 --> 00:11:44,020
+والشغل ممكن أنا أستخدم أجمع الجهتين even with
+
+159
+00:11:44,020 --> 00:11:48,800
+technique .. بتكنيك معينبأحل هذه المعادلة لكن
+
+160
+00:11:48,800 --> 00:11:53,320
+بحتاج إلى أساسيات وخطوات أساسية لحل هذه
+
+161
+00:11:53,320 --> 00:11:56,020
+الستراتيجية اللي هي conservation of energy problem
+
+162
+00:11:56,020 --> 00:11:59,980
+في ال previous section ممكن أنا أحل اللي هي
+
+163
+00:11:59,980 --> 00:12:03,810
+conservative و non conservative في مسألة واحدةThe
+
+164
+00:12:03,810 --> 00:12:07,290
+only difference lies in substituting equation 5
+
+165
+00:12:07,290 --> 00:12:11,310
+.13, the work energy equation with potential
+
+166
+00:12:11,310 --> 00:12:16,550
+energy for equation 5.15 طبعا هنوضع هذا الكلام في
+
+167
+00:12:16,550 --> 00:12:22,280
+هذا المثاليعني ممكن احنا نحل اللى هى ال
+
+168
+00:12:22,280 --> 00:12:24,820
+conservative و ال non-conservative فى سؤال واحد
+
+169
+00:12:24,820 --> 00:12:28,780
+فدلحالة بيكون عندى الشغل القلي هو عبارة عن شغل non
+
+170
+00:12:28,780 --> 00:12:32,340
+-conservative و شغل conservative يعنى طقه
+
+171
+00:12:32,340 --> 00:12:34,920
+الميكانيكية ال final ناقص الطقه الميكانيكية
+
+172
+00:12:34,920 --> 00:12:39,120
+initial بساوي الشغل الناتج عن الاحتكاك طبعا نجلة
+
+173
+00:12:39,120 --> 00:12:43,390
+هذا السؤالwater slides شوان شوان زي ما انتوا احنا
+
+174
+00:12:43,390 --> 00:12:47,270
+شايفين اللي هو بطبعا ال water slides اللي هو اللي
+
+175
+00:12:47,270 --> 00:12:51,510
+بتزلقوا حتى يوصلوا للميه و طبعا يقطصوا في الميه عن
+
+176
+00:12:51,510 --> 00:12:57,570
+طريق مسار معين ال hand determine the speed of بدا
+
+177
+00:12:57,570 --> 00:13:04,000
+أوجد سرعتمرأة كتلتها 60 كيلو جرام at the bottom of
+
+178
+00:13:04,000 --> 00:13:08,800
+such slide and أسفل ال slide assuming no friction
+
+179
+00:13:08,800 --> 00:13:12,720
+is present طبعا بأفرض الآن مافي friction بأفرض في
+
+180
+00:13:12,720 --> 00:13:16,840
+البداية مافي friction هي كتلتها بده تكون 60 كيلو
+
+181
+00:13:16,840 --> 00:13:23,820
+جرام وبده أوجد سرقتها على أسفل اللي هو اللي هي
+
+182
+00:13:23,820 --> 00:13:30,720
+المسار تبعنا طبعا نحل الجزئية A ونرجع ل BFind the
+
+183
+00:13:30,720 --> 00:13:33,240
+woman's speed at the bottom of the slide assuming
+
+184
+00:13:33,240 --> 00:13:35,920
+no friction طبعا بالبداية بدى افرض انه مافي
+
+185
+00:13:35,920 --> 00:13:40,000
+friction كلمة no friction معناها انه mechanical
+
+186
+00:13:40,000 --> 00:13:43,420
+energy ال initial بتساوي ال final بختار نقطة بداية
+
+187
+00:13:43,420 --> 00:13:48,210
+و نقطة نهاية وبختار levelهنعود فى قانون نص Mv
+
+188
+00:13:48,210 --> 00:13:52,390
+initial تربيع زايد Mgy initial بتساوي نص Mv final
+
+189
+00:13:52,390 --> 00:13:56,410
+تربيع زايد Mgy final ال V initial طبعا start from
+
+190
+00:13:56,410 --> 00:14:00,930
+the rest V initial بتساوي 0 و ال Y final بتساوي 0
+
+191
+00:14:00,930 --> 00:14:07,900
+لإن هى بدت من مسافة معيرة و نزلت لبطومالـ MgY
+
+192
+00:14:07,900 --> 00:14:11,980
+initial كانت على ارتفاع معين و نزلت خلال مسار و
+
+193
+00:14:11,980 --> 00:14:15,540
+فيه ماء فيه friction طبعا هذا بالنسبة للمرأة كأنها
+
+194
+00:14:15,540 --> 00:14:18,560
+يعني بدأت من مسار معين من أعلى سطح الميه و نزلت
+
+195
+00:14:18,560 --> 00:14:22,200
+لها الماء بدأ أوجد V final على السطح طبعا على
+
+196
+00:14:22,200 --> 00:14:25,440
+السطح بتكون الـY final بساوي 0 لإن ال level هو
+
+197
+00:14:25,440 --> 00:14:29,700
+نفسه على الـ0 فتخطى الوضع بساوي 0ببوجد طبعا v
+
+198
+00:14:29,700 --> 00:14:32,640
+final من هذه المعادلة ال M بتروح مع ال M بظهر ان v
+
+199
+00:14:32,640 --> 00:14:41,740
+final بيساوي جزر 2gy initial تطلع انه 20.7 20.7
+
+200
+00:14:41,740 --> 00:14:48,170
+نيجي لاقى ان السؤال B او مطلوب BFind the work done
+
+201
+00:14:48,170 --> 00:14:53,550
+on the woman by friction if V final بساوة 18 طبعا
+
+202
+00:14:53,550 --> 00:14:56,670
+أقل من ال 20.7 متر في الثانية الآن مطلوب من أن
+
+203
+00:14:56,670 --> 00:15:01,350
+نوجد الشغل المفروض واسط أو ال friction بدي الشغل
+
+204
+00:15:01,350 --> 00:15:04,710
+المفروض واسط ال friction ده أفرض أن المسار اللى
+
+205
+00:15:04,710 --> 00:15:08,470
+مشيته هى المرأة أو هى البنت هذا المسار فيه
+
+206
+00:15:08,470 --> 00:15:14,840
+friction علشان تتزلج او تتزلج خلالأو تتسحر خلال
+
+207
+00:15:14,840 --> 00:15:18,520
+هذا المسار إلى تصل لسطح الميّه طبعا بدي اكتب
+
+208
+00:15:18,520 --> 00:15:22,180
+المعادلة لكن المعادلة الأولى انه مش بس ال
+
+209
+00:15:22,180 --> 00:15:24,060
+mechanical energy ال initial بيساوي ال final في
+
+210
+00:15:24,060 --> 00:15:28,120
+عندي أنا شغل فالشغل المبدو الوسط الاحتكاك بيساوي
+
+211
+00:15:28,120 --> 00:15:33,320
+اللي هي ال E final ناقص E initial يعني الطاقة
+
+212
+00:15:33,320 --> 00:15:37,800
+الميكانيكية final ناقص ال initial بأوصل لهذه
+
+213
+00:15:37,800 --> 00:15:43,670
+المعادلة لإنه Delta K زائد Delta P أوK final نخس K
+
+214
+00:15:43,670 --> 00:15:47,290
+initial زائد B final نخس B initial هي W and C طبعا
+
+215
+00:15:47,290 --> 00:15:50,630
+ليها أكتر من صورة هذه المعادلة معنى الكلام أن نص
+
+216
+00:15:50,630 --> 00:15:54,390
+Mv final تربيع نخس نص Mv initial تربيع بتساوي ال
+
+217
+00:15:54,390 --> 00:15:58,610
+Mgy final نخس Mgy initial لإنه في عندنا friction
+
+218
+00:15:58,610 --> 00:16:01,930
+لو مافي friction بنعتبرها دي zero إذا وجود ال
+
+219
+00:16:01,930 --> 00:16:06,490
+friction بنعتبرها موجودة بتعود عن ال M بتساوي 60
+
+220
+00:16:07,150 --> 00:16:11,550
+Vfinal أعطانيها 18 Vinitial 0 لإنها released أو
+
+221
+00:16:11,550 --> 00:16:15,570
+بدأت من ال rest وبنحل بقى وجه ال W and C نص في M
+
+222
+00:16:15,570 --> 00:16:21,670
+في V تربيع ناقص 0 ال initial بتساوي ال final لإن
+
+223
+00:16:21,670 --> 00:16:26,850
+وصت ل level ال Y final بتساوي 0 ناقص 60 في 9.8 في
+
+224
+00:16:26,850 --> 00:16:34,420
+21.9إذن بيطلع عندى W and C بساوي ناقص تلاتة point
+
+225
+00:16:34,420 --> 00:16:38,900
+واحد وستة فعشرة أقص تلاتة G هذا الشغل المبذول
+
+226
+00:16:38,900 --> 00:16:44,320
+بواسطة الاحتكاك example
+
+227
+00:16:44,320 --> 00:16:45,060
+آخر
+
+228
+00:16:48,330 --> 00:16:54,950
+نجلة example خمسة تمانية scars start from breast
+
+229
+00:16:54,950 --> 00:17:05,530
+طبعا برضه بتزلج أو بتتزلج بدأ من ال wrist من أعلى
+
+230
+00:17:05,530 --> 00:17:12,010
+decline height من أعلى سطح مايل frictionless وليست
+
+231
+00:17:12,010 --> 00:17:17,440
+خشين أملاس يعنيعن ارتفاع عشرين متر، طبعا هي الشكل
+
+232
+00:17:17,440 --> 00:17:25,720
+لإن شخص بيتزلج على مسار ما ناعم أملس، ممكن يكون
+
+233
+00:17:25,720 --> 00:17:29,280
+تلج، ممكن يكون أي سطح أملس، بدأ من النقطة A وصل
+
+234
+00:17:29,280 --> 00:17:33,300
+للنقطة B، هاد اتزلج، بدأ من ارتفاع عشرين متر على
+
+235
+00:17:33,300 --> 00:17:37,700
+سطح مايل، السطح المايل طبعا مايل بزاوية Eθنشوف
+
+236
+00:17:37,700 --> 00:17:42,740
+السؤال مطلوب .. مطلوب مننا نشوف السؤال السؤال find
+
+237
+00:17:42,740 --> 00:17:48,340
+the sky at speed at the bottom لدى نوجد سرعة هذا
+
+238
+00:17:48,340 --> 00:17:53,820
+المتزلج على .. من النقطة A لنقطة B بعدين طالب how
+
+239
+00:17:53,820 --> 00:17:56,940
+far does the sky travel on the horizontal surface
+
+240
+00:17:56,940 --> 00:18:02,240
+before coming to rest مطلوب مننا نوجد المسافة اللى
+
+241
+00:18:02,240 --> 00:18:09,330
+بيمشيها على السطح الأفقي قبل ما يقف يعنيفي البداية
+
+242
+00:18:09,330 --> 00:18:14,970
+بدأ من النقطة A وصل للنقطة B بدأ من ارتفاع 20 وصل
+
+243
+00:18:14,970 --> 00:18:19,230
+للنقطة B و بعدين من B طالب مني المسافة اللى بدى
+
+244
+00:18:19,230 --> 00:18:22,890
+يمشيها على المستوى الأفقي لحتى يقف عند النقطة C
+
+245
+00:18:22,890 --> 00:18:28,720
+نبدأ نحلSolution A. Find the sky speed at the
+
+246
+00:18:28,720 --> 00:18:33,480
+bottom بدا أوجد اللي هو سرعة ال skies هذا المتزلج
+
+247
+00:18:33,480 --> 00:18:38,860
+عند النقطة BFollow the procedure used in part A of
+
+248
+00:18:38,860 --> 00:18:41,780
+the previous example as the skies move from the
+
+249
+00:18:41,780 --> 00:18:45,660
+top point A to the bottom point طبعا بدي أستخدم
+
+250
+00:18:45,660 --> 00:18:49,140
+نفس العلاقة اللي استخدمتها في السؤال الأول ونفس
+
+251
+00:18:49,140 --> 00:18:53,320
+الخطوات بسأل نفسي هل في احتكاك ولا مافيإذا مافي
+
+252
+00:18:53,320 --> 00:18:57,720
+احتكاك معناها أنه باستخدم اللي هو الـE initial
+
+253
+00:18:57,720 --> 00:19:00,500
+بتساوي الـE final الـE هي عبارة عن طاقة وضع وحركة
+
+254
+00:19:00,500 --> 00:19:03,480
+في ال initial بتساوي طاقة الوضع وحركة بال final
+
+255
+00:19:03,480 --> 00:19:07,760
+بالنسبة لل initial طاقة الحركة zero فبيكون عندي
+
+256
+00:19:07,760 --> 00:19:12,400
+MGY initial بتساوي نص MV final تربيع لإن أنا وصلت
+
+257
+00:19:12,400 --> 00:19:17,740
+لل level باعتبر أن المنطقة هذه هي ال levelمعناته
+
+258
+00:19:17,740 --> 00:19:20,820
+هذه النقطة الإبتدائية تغطي الحركة عن Zero تغطي
+
+259
+00:19:20,820 --> 00:19:26,360
+الوضع Mgh أو Mgy في المنطقة هذه صارت نص Mv تربيع
+
+260
+00:19:26,360 --> 00:19:29,920
+طاقة الوضع Zero لإن ال Y بيساوي Zero لإنه وصلت ل
+
+261
+00:19:29,920 --> 00:19:35,000
+ال level طبعا من خلال المعادلة بحصل على إنه ال V
+
+262
+00:19:35,000 --> 00:19:40,600
+عند النقطة B بدها تساوي 2 جزر Gh يعني 2.980 هو
+
+263
+00:19:40,600 --> 00:19:47,070
+الارتفاع كان 20 بتطلع عند V P بيساوي 19.8في B
+
+264
+00:19:47,070 --> 00:19:49,430
+مطلوب find the distance travelled on the
+
+265
+00:19:49,430 --> 00:19:52,670
+horizontal rough surface أو جد الأن المسافة
+
+266
+00:19:52,670 --> 00:19:57,190
+الأفقية اللي هذا المتزلج بيمشيها على مستوى خشن حتى
+
+267
+00:19:57,190 --> 00:20:01,690
+يصل أو يتوقف عنده النقطة Cطبعا applying the work
+
+268
+00:20:01,690 --> 00:20:05,250
+energy طالما انا في احتكاك بدأ استخدم قانون اللي
+
+269
+00:20:05,250 --> 00:20:10,210
+هو ال energy theorem او قانون نظرية الشغل والطاقة
+
+270
+00:20:10,210 --> 00:20:14,290
+اللي فيها احتكاك من القانون اللي هو W net بالساوة
+
+271
+00:20:14,290 --> 00:20:19,420
+ناقص FK في D بساوة Delta K Eطبعا هنا هو أشتغل على
+
+272
+00:20:19,420 --> 00:20:24,540
+المستوى الأفقي من النقطة B إلى النقطة C إذا الشغل
+
+273
+00:20:24,540 --> 00:20:28,160
+الناتج عن الاحتكاك اللي هو الشغل الكلي بيساوي ناقص
+
+274
+00:20:28,160 --> 00:20:33,700
+FK في D FK بيساوي ميو كي في ال normal دلتا KE ليه
+
+275
+00:20:33,700 --> 00:20:38,300
+نص MV final هي عند ال C تربية ناقص نص MV initial
+
+276
+00:20:38,300 --> 00:20:42,660
+عند ال C حكاية ال stop معناته VC بيساوي Zero و ال
+
+277
+00:20:42,660 --> 00:20:45,320
+FK بيساوي ميو كي في ال normal و ال normal بتساوي
+
+278
+00:20:45,320 --> 00:20:51,790
+ال MGبنعوض ميو كي ميو كي ميو كي ميو كي ميو كي ميو
+
+279
+00:20:51,790 --> 00:20:58,690
+كي ميو كي ميو كي ميو كي
+
+280
+00:21:04,680 --> 00:21:13,220
+VP تربيع على 2 MUK في G فدي على المستوى الخشن كانت
+
+281
+00:21:13,220 --> 00:21:19,320
+هيمشي مسافة 95.2 V عند النقطة P اللي أنا طلعتها من
+
+282
+00:21:19,320 --> 00:21:24,960
+المطلوب الأول هو جزر 2 GH 19.8 لكل تربيع على ال 2
+
+283
+00:21:24,960 --> 00:21:31,230
+MUK هو معامل الاحتكاك المتحرك هو أعطانيمضروب في
+
+284
+00:21:31,230 --> 00:21:35,070
+تسعة و تمانية من عشرة فبتطلع معايا خمسة وتسعين
+
+285
+00:21:35,070 --> 00:21:38,610
+point اتنين متر هو المسافة اللى مشيها على المستوى
+
+286
+00:21:38,610 --> 00:21:44,790
+الخشن نيجي
+
+287
+00:21:44,790 --> 00:21:49,410
+ل section خمسة .. خمسة بعنوان spring potential
+
+288
+00:21:49,410 --> 00:21:54,410
+energy ال spring potential energy اللى هو طاقة
+
+289
+00:21:54,410 --> 00:21:59,150
+الوضع داخل اللى هى النعبد أو ال springالwork done
+
+290
+00:21:59,150 --> 00:22:02,310
+by applied force is stretching or compressed
+
+291
+00:22:02,310 --> 00:22:05,790
+spring can be recovered by removing the applied
+
+292
+00:22:05,790 --> 00:22:10,130
+force so like gravity الآن بالنسبة للspring أو
+
+293
+00:22:10,130 --> 00:22:15,150
+النعبد بعتبره هي قوة conservative محفوظة لإن
+
+294
+00:22:15,150 --> 00:22:20,430
+النعبد ممكن يكون stretch يعني مشدود أو compressed
+
+295
+00:22:20,430 --> 00:22:25,860
+أو مضغوطكمان ال spring برجع لبضعه اللي كان عليه
+
+296
+00:22:25,860 --> 00:22:29,180
+يعني ممكن أنا أشده و أفلط و برجع لبضعه أو أنا أضغط
+
+297
+00:22:29,180 --> 00:22:32,840
+و أفلط و برجع لبضعه الطبيعي ال spring force is
+
+298
+00:22:32,840 --> 00:22:35,440
+conservative زي ما حكينا الآن رجعنا لحكيناها
+
+299
+00:22:35,440 --> 00:22:39,200
+السابقان أنه conservative force هي ال gravity أو
+
+300
+00:22:39,200 --> 00:22:41,880
+gravitational potential energy أو ال spring force
+
+301
+00:22:41,880 --> 00:22:45,620
+يسموها conservative force as long as losses
+
+302
+00:22:45,620 --> 00:22:49,620
+through internala friction of the spring can be
+
+303
+00:22:49,620 --> 00:22:53,300
+neglected ممكن أعمل انا احتكاك ناتج عن حلقات ال
+
+304
+00:22:53,300 --> 00:22:56,220
+spring أو ال spring أو النابط this means that
+
+305
+00:22:56,220 --> 00:22:59,640
+means a potential energy function can be found and
+
+306
+00:22:59,640 --> 00:23:02,180
+used in the work energy theory ممكن أطبق قانون
+
+307
+00:23:02,180 --> 00:23:10,580
+الشغل والشغل والطاقة على ال spring يعني مثللو كان
+
+308
+00:23:10,580 --> 00:23:14,100
+الـspring لا هو مضغوط ولا مشدود فهذه باعتبرها نقطة
+
+309
+00:23:14,100 --> 00:23:17,680
+اتزان بيسموها equilibrium point equilibrium point
+
+310
+00:23:17,680 --> 00:23:22,140
+يعني X بالساوة 0 هاي هاي الكتلة بعد هيك جيبت أنا
+
+311
+00:23:22,140 --> 00:23:28,170
+الكتلة وضغطت هذا ال spring أو النعبطضغطوا مسافة X
+
+312
+00:23:28,170 --> 00:23:32,770
+معناها هذا الـspring إله طاقة ووضع مرنية بيسموها
+
+313
+00:23:32,770 --> 00:23:37,070
+BES بتساوي نص K X تربيع طبعا لما أنا أضغطه على
+
+314
+00:23:37,070 --> 00:23:41,050
+الآخر فالكتلة هذه بتتحركش بعديها بتتحركش فطاقة
+
+315
+00:23:41,050 --> 00:23:50,310
+الحركة للكتلة بيساوي Zeroفي C هنا لو انا ال spring
+
+316
+00:23:50,310 --> 00:23:55,450
+هذا او النعبد شدته او stretch يعني شدته فبكون انه
+
+317
+00:23:55,450 --> 00:24:01,430
+عند نقطة الاتزان بيكون تغطي الوضع تبعته بالسوء
+
+318
+00:24:01,430 --> 00:24:06,240
+zero لانه فلت فلت بعد ما انا كنت ضغطها فلتهلما
+
+319
+00:24:06,240 --> 00:24:12,180
+فلته الكتلة هاي تتحرك بسرعة V وبالتالي لها طاقة
+
+320
+00:24:12,180 --> 00:24:18,100
+حركة نص K نص MV تربيع هنا لما يوصل لمنطقة الإتزان
+
+321
+00:24:18,100 --> 00:24:21,780
+بتكون B potential energy ل ال sprint بالساوة Zero
+
+322
+00:24:21,780 --> 00:24:26,560
+وهنا الكتلة تبدأ بأقصى سرعة لها و بأقصى طاقة وضعها
+
+323
+00:24:27,190 --> 00:24:32,130
+لو أنا أشد الـspring مسافة معينة للآخر بتكون طاقة
+
+324
+00:24:32,130 --> 00:24:35,870
+الوضع للـspring برضه نص K X تربيع وطاقة الحركة
+
+325
+00:24:35,870 --> 00:24:40,150
+بتساوي Zero لكن هذه المرحلة لما احنا كان مضغوط
+
+326
+00:24:40,150 --> 00:24:45,020
+الـspring و تركناطبعا هذا الشكل بيوضح كيف ال
+
+327
+00:24:45,020 --> 00:24:49,460
+spring ممكن يكون stretched أو .. او اللي هي
+
+328
+00:24:49,460 --> 00:24:53,600
+compressed هذا ال figure بيوضح ال spring in its
+
+329
+00:24:53,600 --> 00:24:56,420
+equilibrium position where the spring is neither
+
+330
+00:24:56,420 --> 00:25:00,640
+compressed or يعني ممكن ال spring هذا النبض ممكن
+
+331
+00:25:00,640 --> 00:25:04,830
+يكون مضغوط أو مشدودpushing block against spring as
+
+332
+00:25:04,830 --> 00:25:08,310
+figure طبعا زى ما هو مضح فى الشكل خمسة واحد وعشر
+
+333
+00:25:08,310 --> 00:25:11,510
+بيه compressed تبقى distance X ده distance X
+
+334
+00:25:11,510 --> 00:25:14,050
+represent the magnitude of the displacement for
+
+335
+00:25:14,050 --> 00:25:18,010
+the equilibrium position بيسموها اللى هى قيمة
+
+336
+00:25:18,010 --> 00:25:21,570
+الإزاحة اللى ال spring أو النابض هوطبعاً يا إما
+
+337
+00:25:21,570 --> 00:25:25,910
+بيكون مضغوط أو مشدود ال X بيساوي Zero في حالة ال
+
+338
+00:25:25,910 --> 00:25:31,250
+equilibrium position وبالتالي طالما أنه أو أنا
+
+339
+00:25:31,250 --> 00:25:36,050
+ضغطاه أو شداه واحنا شدينه أو ضغطينه بيكون عندي أنا
+
+340
+00:25:36,050 --> 00:25:40,670
+الإزاحة عكس القوة وبالتالي في عندي أنا قوة داخل ال
+
+341
+00:25:40,670 --> 00:25:46,310
+spring بيسموها ال AFS Spring Force بتساوي ناقص KX
+
+342
+00:25:47,260 --> 00:25:50,480
+طبعا ال X هو عبارة عن المسافة اللي ال spring
+
+343
+00:25:50,480 --> 00:25:54,460
+انضغطها أو انشدها و ال K بيسموها constant
+
+344
+00:25:54,460 --> 00:26:00,080
+proportionality ثابت التناسب ل ال spring constant
+
+345
+00:26:00,080 --> 00:26:03,580
+طبعا carrying unit of a Newton's perimeter لإن ال
+
+346
+00:26:03,580 --> 00:26:12,040
+K هذه واحدتها Newton per meter حسب القانون الموجود
+
+347
+00:26:12,040 --> 00:26:15,100
+هذا بسميه Hooke's law هذا المعادلة بسميها قانون
+
+348
+00:26:15,100 --> 00:26:19,410
+Hookeالقوة fs is often called بيسموها restoring
+
+349
+00:26:19,410 --> 00:26:23,610
+force for positive value of x the force is
+
+350
+00:26:23,610 --> 00:26:29,070
+negative لما تكون ال x موجبة بتكون ال fs negative
+
+351
+00:26:29,070 --> 00:26:32,890
+pointing back towards equilibrium at x بالساوة 0
+
+352
+00:26:32,890 --> 00:26:36,190
+and for negative x the force لما تكون ال x بالساوة
+
+353
+00:26:36,190 --> 00:26:41,580
+سالبة القوة بتكون موجبةagain pointing towards x
+
+354
+00:26:41,580 --> 00:26:45,240
+بالساوية 0 the minus sign طبعا الإشارة السالية
+
+355
+00:26:45,240 --> 00:26:49,240
+بمعناها إنه هي قوة ال spring أو قوة النعبة دايما
+
+356
+00:26:49,240 --> 00:26:53,060
+بتكون directed back towards the equilibrium point
+
+357
+00:26:53,060 --> 00:26:58,180
+دايما بتكون ال spring force is always directed
+
+358
+00:26:58,180 --> 00:27:01,440
+back towards the equilibrium point بتكون دايما
+
+359
+00:27:01,440 --> 00:27:05,850
+راجعة نقطة الإتزانas in the case of the
+
+360
+00:27:05,850 --> 00:27:09,750
+gravitation برضه نفس ما احنا شرحنا بالنسبة لـ
+
+361
+00:27:09,750 --> 00:27:14,530
+gravitation أو potential energy أو اللي هو بيسموها
+
+362
+00:27:14,530 --> 00:27:17,110
+الـ elastic potential energy طاقة الوضع المرنية
+
+363
+00:27:17,110 --> 00:27:19,870
+المخزونة داخل ال spring هي تعتبر conservative
+
+364
+00:27:19,870 --> 00:27:22,450
+force can be associated with the spring force
+
+365
+00:27:22,450 --> 00:27:25,490
+elastic potential energy is another way of looking
+
+366
+00:27:25,490 --> 00:27:28,030
+at the work done by spring during motion because
+
+367
+00:27:28,030 --> 00:27:32,890
+it is equal to thenegative of the work done by the
+
+368
+00:27:32,890 --> 00:27:36,850
+spring طبعا ال elastic potential energy بيسموها
+
+369
+00:27:36,850 --> 00:27:41,090
+طاقة زي ما حكينا طاقة وضع مرونية مخزونة داخل ال
+
+370
+00:27:41,090 --> 00:27:44,250
+spring وهي طريقة تانية عشان انا ممكن احسب الشغل
+
+371
+00:27:44,250 --> 00:27:49,270
+المبدول بواسط ال spring وهذا بيسميها طبعا طاقة وضع
+
+372
+00:27:49,270 --> 00:27:54,080
+لكنها مرونيةبساعة و نص KX تربيع ممكن هي تكون
+
+373
+00:27:54,080 --> 00:27:58,480
+مخزونة داخل ال spring ال spring ممكن يعمل شغل اذا
+
+374
+00:27:58,480 --> 00:28:02,800
+انا شديته compress or stretch ممكن انا اذا كان ال
+
+375
+00:28:02,800 --> 00:28:08,280
+spring انا شديته او ضغطه بكون انا يعني بزلت شغل
+
+376
+00:28:08,280 --> 00:28:14,260
+فيه طبعا بنستكمل هذا ال .. هذه التسجيلات و هذا
+
+377
+00:28:14,260 --> 00:28:16,340
+الشرح في المحاضرة القادمة ان شاء الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..b61d4282d3b3bcca2b3d96c2193fdb8bdca5c586
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 2599, "start": 0.99, "end": 25.99, "text": "بسم الله الرحمن الرحيم problem solving strategy طريقة حل المسائل طبعا هنا هذا الموضوع اللي هو ال work energy theorem أو تغيرات الطاقة apply conservation of mechanical energy لما بده ييجي عندي أنا السؤال هطبق اللي هي الطاقة الميكانيكية", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 1154, 12606, 5206, 23032, 16572, 28671, 11331, 1211, 9673, 3794, 16373, 1211, 23032, 3555, 3615, 995, 34105, 23758, 9673, 2407, 11242, 45367, 13672, 1829, 31439, 2423, 589, 2281, 20904, 34051, 6055, 17082, 13546, 9307, 41950, 995, 28671, 3079, 16185, 295, 12070, 2281, 5296, 15042, 47525, 3224, 7251, 1829, 7435, 1829, 18871, 16254, 41850, 21136, 33604, 6027, 8032, 9566, 3555, 4587, 13672, 1829, 39896, 41950, 995, 28671, 9673, 1829, 41361, 1829, 4117, 10632], "avg_logprob": -0.12461889807770891, "compression_ratio": 1.5682819383259912, "no_speech_prob": 8.881092071533203e-06, "words": [{"start": 0.99, "end": 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"word": " energy", "probability": 0.88427734375}, {"start": 106.61, "end": 106.97, "word": " equation", "probability": 0.83349609375}, {"start": 106.97, "end": 107.21, "word": " بعد", "probability": 0.7763671875}, {"start": 107.21, "end": 107.35, "word": " هي", "probability": 0.60986328125}, {"start": 107.35, "end": 107.91, "word": " بكتب", "probability": 0.83819580078125}, {"start": 107.91, "end": 108.67, "word": " المعادلة", "probability": 0.9837646484375}], "temperature": 1.0}, {"id": 6, "seek": 13299, "start": 109.55, "end": 132.99, "text": "المعادلة طبعا احنا اخترنا level اخترنا نقطتين بكتب معادلة ال conservation of energy اللي هي اللي هي نص MV initial تربيع زاد MGH او Mgy initial ساوي نص MV final تربيع زاد Mgy final اللي هي المعادلة 5.15 بعد هيك بحدد المتغيرات او المجاهيل الموجودة", "tokens": [45340, 3615, 18513, 37977, 23032, 3555, 3615, 995, 1975, 5016, 8315, 1975, 46456, 2288, 8315, 1496, 1975, 46456, 2288, 8315, 8717, 47432, 2655, 9957, 4724, 4117, 2655, 3555, 20449, 18513, 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"word": " بحدد", "probability": 0.9508463541666666}, {"start": 130.01, "end": 130.81, "word": " المتغيرات", "probability": 0.9927734375}, {"start": 130.81, "end": 131.05, "word": " او", "probability": 0.859130859375}, {"start": 131.05, "end": 131.75, "word": " المجاهيل", "probability": 0.8056640625}, {"start": 131.75, "end": 132.99, "word": " الموجودة", "probability": 0.9678955078125}], "temperature": 1.0}, {"id": 7, "seek": 14477, "start": 133.79, "end": 144.77, "text": "ليه؟ كي أحل بعوض عن المعطيات و بحل الأسئلة و بوجد المجاهد سواء كانت speed أو position أو أي اي مجهول موجود في السؤال", "tokens": [20292, 3224, 22807, 9122, 1829, 5551, 5016, 1211, 45030, 2407, 11242, 18871, 9673, 3615, 9566, 1829, 9307, 4032, 4724, 5016, 1211, 16247, 3794, 19986, 37977, 4032, 4724, 29245, 3215, 9673, 7435, 40294, 3215, 8608, 2407, 16606, 25961, 2655, 3073, 34051, 2535, 34051, 36632, 1975, 1829, 3714, 7435, 3224, 12610, 3714, 29245, 23328, 8978, 21136, 33604, 6027], "avg_logprob": -0.17543860067401015, 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"end": 1117.34, "word": " procedure", "probability": 0.91357421875}, {"start": 1117.34, "end": 1117.76, "word": " used", "probability": 0.89013671875}, {"start": 1117.76, "end": 1117.94, "word": " in", "probability": 0.95751953125}, {"start": 1117.94, "end": 1118.24, "word": " part", "probability": 0.84228515625}, {"start": 1118.24, "end": 1118.6, "word": " A", "probability": 0.8232421875}, {"start": 1118.6, "end": 1118.86, "word": " of", "probability": 0.95751953125}, {"start": 1118.86, "end": 1118.98, "word": " the", "probability": 0.9130859375}, {"start": 1118.98, "end": 1119.32, "word": " previous", "probability": 0.8603515625}, {"start": 1119.32, "end": 1119.98, "word": " example", "probability": 0.962890625}, {"start": 1119.98, "end": 1120.62, "word": " as", "probability": 0.76806640625}, {"start": 1120.62, "end": 1120.76, "word": " the", "probability": 0.89697265625}, {"start": 1120.76, "end": 1121.06, "word": " skies", "probability": 0.69287109375}, {"start": 1121.06, "end": 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الطبيعي ال spring force is conservative زي ما حكينا الآن رجعنا لحكيناها السابقان أنه conservative force هي ال gravity أو gravitational potential energy أو ال spring force يسموها conservative force as long as losses through internal", "tokens": [24793, 7649, 2423, 5587, 4724, 47341, 3615, 5296, 3555, 11242, 3615, 3224, 13672, 1829, 25961, 47356, 37495, 22653, 3714, 43020, 41850, 5551, 8592, 3215, 3224, 4032, 5551, 5172, 1211, 9566, 4032, 4724, 47341, 3615, 5296, 3555, 11242, 3615, 3224, 34051, 41850, 5551, 11242, 17082, 9566, 4032, 5551, 5172, 1211, 9566, 4032, 4724, 47341, 3615, 5296, 3555, 11242, 3615, 3224, 41950, 21292, 3615, 1829, 2423, 5587, 3464, 307, 13780, 30767, 1829, 19446, 11331, 4117, 1829, 8315, 6024, 48506, 12602, 7435, 3615, 8315, 5296, 5016, 4117, 1829, 8315, 11296, 21136, 16758, 4587, 7649, 14739, 3224, 13780, 3464, 39896, 2423, 12110, 34051, 28538, 3995, 2281, 34051, 2423, 5587, 3464, 7251, 38251, 2407, 11296, 13780, 3464, 382, 938, 382, 15352, 807, 6920], 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" تبعته", "probability": 0.83001708984375}, {"start": 1441.01, "end": 1441.43, "word": " بالسوء", "probability": 0.4542236328125}, {"start": 1441.43, "end": 1441.69, "word": " zero", "probability": 0.447509765625}, {"start": 1441.69, "end": 1441.95, "word": " لانه", "probability": 0.7757975260416666}, {"start": 1441.95, "end": 1442.39, "word": " فلت", "probability": 0.9239908854166666}, {"start": 1442.39, "end": 1443.55, "word": " فلت", "probability": 0.8992513020833334}, {"start": 1443.55, "end": 1443.83, "word": " بعد", "probability": 0.9736328125}, {"start": 1443.83, "end": 1443.95, "word": " ما", "probability": 0.8701171875}, {"start": 1443.95, "end": 1444.11, "word": " انا", "probability": 0.906494140625}, {"start": 1444.11, "end": 1444.43, "word": " كنت", "probability": 0.8916015625}, {"start": 1444.43, "end": 1445.09, "word": " ضغطها", "probability": 0.80419921875}, {"start": 1445.09, "end": 1445.65, "word": " فلته", "probability": 0.85888671875}], "temperature": 1.0}, {"id": 65, "seek": 146656, "start": 1445.9, "end": 1466.56, "text": "لما فلته الكتلة هاي تتحرك بسرعة V وبالتالي لها طاقة حركة نص K نص MV تربيع هنا لما يوصل لمنطقة الإتزان بتكون B potential energy ل ال sprint بالساوة Zero وهنا الكتلة تبدأ بأقصى سرعة لها و بأقصى طاقة وضعها", "tokens": [1211, 15042, 6156, 1211, 47395, 33251, 2655, 37977, 8032, 47302, 6055, 2655, 5016, 31747, 4724, 3794, 2288, 27884, 691, 46599, 6027, 2655, 6027, 1829, 5296, 11296, 23032, 995, 28671, 11331, 31747, 3660, 8717, 9381, 591, 8717, 9381, 17663, 6055, 2288, 21292, 3615, 34105, 5296, 15042, 7251, 2407, 36520, 5296, 27842, 9566, 28671, 33688, 2655, 11622, 7649, 39894, 30544, 363, 3995, 2281, 5296, 2423, 25075, 20666, 3794, 995, 2407, 3660, 17182, 37037, 8315, 33251, 2655, 37977, 6055, 44510, 10721, 4724, 10721, 4587, 9381, 7578, 8608, 2288, 27884, 5296, 11296, 4032, 4724, 10721, 4587, 9381, 7578, 23032, 995, 28671, 4032, 11242, 3615, 11296], "avg_logprob": -0.21384803819305756, "compression_ratio": 1.5952380952380953, "no_speech_prob": 0.0001137852668762207, "words": [{"start": 1445.9, "end": 1446.24, "word": "لما", "probability": 0.6751708984375}, {"start": 1446.24, "end": 1446.7, "word": " فلته", "probability": 0.771484375}, {"start": 1446.7, "end": 1447.28, "word": " الكتلة", "probability": 0.9070638020833334}, {"start": 1447.28, "end": 1447.66, "word": " هاي", "probability": 0.684326171875}, {"start": 1447.66, "end": 1448.7, "word": " تتحرك", "probability": 0.9019775390625}, {"start": 1448.7, "end": 1449.54, "word": " بسرعة", "probability": 0.9510498046875}, {"start": 1449.54, "end": 1451.3, "word": " V", "probability": 0.76416015625}, {"start": 1451.3, "end": 1451.82, "word": " وبالتالي", "probability": 0.87802734375}, {"start": 1451.82, "end": 1452.0, "word": " لها", "probability": 0.576416015625}, {"start": 1452.0, "end": 1452.18, "word": " طاقة", "probability": 0.9560546875}, {"start": 1452.18, "end": 1452.62, "word": " حركة", "probability": 0.9654947916666666}, {"start": 1452.62, "end": 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"word": " potential", "probability": 0.71630859375}, {"start": 1460.24, "end": 1460.6, "word": " energy", "probability": 0.94580078125}, {"start": 1460.6, "end": 1460.74, "word": " ل", "probability": 0.6708984375}, {"start": 1460.74, "end": 1460.84, "word": " ال", "probability": 0.260009765625}, {"start": 1460.84, "end": 1461.1, "word": " sprint", "probability": 0.84228515625}, {"start": 1461.1, "end": 1461.5, "word": " بالساوة", "probability": 0.66015625}, {"start": 1461.5, "end": 1461.78, "word": " Zero", "probability": 0.396484375}, {"start": 1461.78, "end": 1462.16, "word": " وهنا", "probability": 0.724365234375}, {"start": 1462.16, "end": 1462.58, "word": " الكتلة", "probability": 0.9895833333333334}, {"start": 1462.58, "end": 1463.4, "word": " تبدأ", "probability": 0.9228515625}, {"start": 1463.4, "end": 1464.32, "word": " بأقصى", "probability": 0.99052734375}, {"start": 1464.32, "end": 1464.8, "word": " سرعة", "probability": 0.9547526041666666}, {"start": 1464.8, "end": 1465.08, "word": " لها", "probability": 0.94482421875}, {"start": 1465.08, "end": 1465.26, "word": " و", "probability": 0.578125}, {"start": 1465.26, "end": 1465.6, "word": " بأقصى", "probability": 0.91591796875}, {"start": 1465.6, "end": 1465.98, "word": " طاقة", "probability": 0.9925130208333334}, {"start": 1465.98, "end": 1466.56, "word": " وضعها", "probability": 0.8341064453125}], "temperature": 1.0}, {"id": 66, "seek": 148147, "start": 1467.19, "end": 1481.47, "text": "لو أنا أشد الـspring مسافة معينة للآخر بتكون طاقة الوضع للـspring برضه نص K X تربيع وطاقة الحركة بتساوي Zero لكن هذه المرحلة لما احنا كان مضغوط الـspring و تركنا", "tokens": [1211, 2407, 41850, 5551, 8592, 3215, 2423, 39184, 30757, 47524, 31845, 3660, 20449, 9957, 3660, 24976, 148, 95, 34740, 39894, 30544, 23032, 995, 28671, 2423, 2407, 11242, 3615, 24976, 39184, 30757, 4724, 43042, 3224, 8717, 9381, 591, 1783, 6055, 2288, 21292, 3615, 4032, 9566, 995, 28671, 21542, 31747, 3660, 39894, 3794, 995, 45865, 17182, 44381, 29538, 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طاقة", "probability": 0.8455403645833334}, {"start": 1472.13, "end": 1472.71, "word": " الوضع", "probability": 0.991455078125}, {"start": 1472.71, "end": 1473.27, "word": " للـspring", "probability": 0.8642578125}, {"start": 1473.27, "end": 1473.61, "word": " برضه", "probability": 0.8885091145833334}, {"start": 1473.61, "end": 1473.81, "word": " نص", "probability": 0.8662109375}, {"start": 1473.81, "end": 1473.95, "word": " K", "probability": 0.625}, {"start": 1473.95, "end": 1474.17, "word": " X", "probability": 0.366455078125}, {"start": 1474.17, "end": 1474.69, "word": " تربيع", "probability": 0.75677490234375}, {"start": 1474.69, "end": 1475.27, "word": " وطاقة", "probability": 0.8486328125}, {"start": 1475.27, "end": 1475.87, "word": " الحركة", "probability": 0.9860026041666666}, {"start": 1475.87, "end": 1476.29, "word": " بتساوي", "probability": 0.63916015625}, {"start": 1476.29, "end": 1476.53, "word": " Zero", "probability": 0.3681640625}, {"start": 1476.53, "end": 1476.77, 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in its equilibrium position where the spring is neither compressed or يعني ممكن ال spring هذا النبض ممكن يكون مضغوط أو مشدود", "tokens": [9566, 3555, 3615, 995, 23758, 25124, 28820, 4724, 1829, 2407, 11242, 5016, 9122, 33911, 2423, 5587, 3714, 43020, 7251, 30544, 23563, 34051, 4386, 1975, 2407, 13672, 1829, 39896, 30353, 23758, 2423, 2573, 4724, 1829, 2407, 11242, 5016, 2423, 5587, 294, 1080, 15625, 2535, 689, 264, 5587, 307, 9662, 30353, 420, 37495, 22653, 3714, 43020, 2423, 5587, 23758, 28239, 3555, 11242, 3714, 43020, 7251, 30544, 3714, 11242, 17082, 2407, 9566, 34051, 37893, 3215, 23328], "avg_logprob": -0.1851773640593967, "compression_ratio": 1.6598984771573604, "no_speech_prob": 1.4901161193847656e-06, "words": [{"start": 1483.14, "end": 1483.46, "word": "طبعا", "probability": 0.881103515625}, {"start": 1483.46, "end": 1483.6, "word": " هذا", "probability": 0.5888671875}, {"start": 1483.6, "end": 1483.9, "word": " الشكل", "probability": 0.986572265625}, {"start": 1483.9, "end": 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compressed", "probability": 0.89794921875}, {"start": 1490.7, "end": 1491.28, "word": " هذا", "probability": 0.70263671875}, {"start": 1491.28, "end": 1491.4, "word": " ال", "probability": 0.806640625}, {"start": 1491.4, "end": 1491.58, "word": " figure", "probability": 0.95263671875}, {"start": 1491.58, "end": 1492.16, "word": " بيوضح", "probability": 0.9880859375}, {"start": 1492.16, "end": 1492.6, "word": " ال", "probability": 0.7099609375}, {"start": 1492.6, "end": 1492.96, "word": " spring", "probability": 0.94287109375}, {"start": 1492.96, "end": 1493.36, "word": " in", "probability": 0.92724609375}, {"start": 1493.36, "end": 1493.6, "word": " its", "probability": 0.794921875}, {"start": 1493.6, "end": 1494.0, "word": " equilibrium", "probability": 0.845703125}, {"start": 1494.0, "end": 1494.6, "word": " position", "probability": 0.982421875}, {"start": 1494.6, "end": 1495.12, "word": " where", "probability": 0.85302734375}, {"start": 1495.12, "end": 1495.34, "word": " the", 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{"start": 1654.67, "end": 1654.99, "word": " elastic", "probability": 0.369140625}, {"start": 1654.99, "end": 1655.65, "word": " potential", "probability": 0.93359375}, {"start": 1655.65, "end": 1656.17, "word": " energy", "probability": 0.958984375}, {"start": 1656.17, "end": 1656.85, "word": " بيسموها", "probability": 0.94423828125}, {"start": 1656.85, "end": 1657.91, "word": " طاقة", "probability": 0.97412109375}, {"start": 1657.91, "end": 1658.71, "word": " زي", "probability": 0.590576171875}, {"start": 1658.71, "end": 1658.77, "word": " ما", "probability": 0.95263671875}, {"start": 1658.77, "end": 1659.05, "word": " حكينا", "probability": 0.950439453125}, {"start": 1659.05, "end": 1659.33, "word": " طاقة", "probability": 0.9853515625}, {"start": 1659.33, "end": 1659.63, "word": " وضع", "probability": 0.9842122395833334}, {"start": 1659.63, "end": 1660.15, "word": " مرونية", "probability": 0.86474609375}, {"start": 1660.15, "end": 1660.61, "word": " مخزونة", "probability": 0.89697265625}, {"start": 1660.61, "end": 1660.95, "word": " داخل", "probability": 0.9778645833333334}, {"start": 1660.95, "end": 1661.09, "word": " ال", "probability": 0.95166015625}, {"start": 1661.09, "end": 1661.53, "word": " spring", "probability": 0.72265625}, {"start": 1661.53, "end": 1662.11, "word": " وهي", "probability": 0.8642578125}, {"start": 1662.11, "end": 1662.47, "word": " طريقة", "probability": 0.99072265625}, {"start": 1662.47, "end": 1662.79, "word": " تانية", "probability": 0.9915364583333334}, {"start": 1662.79, "end": 1663.07, "word": " عشان", "probability": 0.982421875}, {"start": 1663.07, "end": 1663.23, "word": " انا", "probability": 0.819580078125}, {"start": 1663.23, "end": 1663.45, "word": " ممكن", "probability": 0.96728515625}, {"start": 1663.45, "end": 1663.81, "word": " احسب", "probability": 0.8759765625}, {"start": 1663.81, "end": 1664.25, "word": " الشغل", "probability": 0.9931640625}, {"start": 1664.25, "end": 1664.77, "word": " المبدول", "probability": 0.5985514322916666}, {"start": 1664.77, "end": 1665.57, "word": " بواسط", "probability": 0.904052734375}, {"start": 1665.57, "end": 1665.77, "word": " ال", "probability": 0.978515625}, {"start": 1665.77, "end": 1666.39, "word": " spring", "probability": 0.9052734375}, {"start": 1666.39, "end": 1666.65, "word": " وهذا", "probability": 0.65625}, {"start": 1666.65, "end": 1667.23, "word": " بيسميها", "probability": 0.98642578125}, {"start": 1667.23, "end": 1668.07, "word": " طبعا", "probability": 0.989501953125}, {"start": 1668.07, "end": 1668.91, "word": " طاقة", "probability": 0.9913736979166666}, {"start": 1668.91, "end": 1669.27, "word": " وضع", "probability": 0.99560546875}, {"start": 1669.27, "end": 1669.71, "word": " لكنها", "probability": 0.805908203125}, {"start": 1669.71, "end": 1670.29, "word": " مرونية", "probability": 0.9793701171875}], "temperature": 1.0}, {"id": 75, "seek": 169634, "start": 1670.4, "end": 1696.34, "text": "بساعة و نص KX تربيع ممكن هي تكون مخزونة داخل ال spring ال spring ممكن يعمل شغل اذا انا شديته compress or stretch ممكن انا اذا كان ال spring انا شديته او ضغطه بكون انا يعني بزلت شغل فيه طبعا بنستكمل هذا ال .. هذه التسجيلات و هذا الشرح في المحاضرة القادمة ان شاء الله", "tokens": [3555, 3794, 995, 27884, 4032, 8717, 9381, 591, 55, 6055, 2288, 21292, 3615, 3714, 43020, 39896, 6055, 30544, 3714, 9778, 11622, 11536, 3660, 11778, 47283, 1211, 2423, 5587, 2423, 5587, 3714, 43020, 7251, 25957, 1211, 13412, 17082, 1211, 1975, 15730, 1975, 8315, 13412, 16254, 47395, 14778, 420, 5985, 3714, 43020, 1975, 8315, 1975, 15730, 25961, 2423, 5587, 1975, 8315, 13412, 16254, 47395, 1975, 2407, 48812, 17082, 9566, 3224, 4724, 30544, 1975, 8315, 37495, 22653, 4724, 11622, 1211, 2655, 13412, 17082, 1211, 8978, 3224, 23032, 3555, 3615, 995, 44945, 14851, 24793, 1211, 23758, 2423, 4386, 29538, 16712, 3794, 7435, 26895, 9307, 4032, 23758, 25124, 2288, 5016, 8978, 9673, 5016, 46958, 25720, 25062, 18513, 46007, 16472, 13412, 16606, 21984], "avg_logprob": -0.14790783847792674, "compression_ratio": 1.8057851239669422, "no_speech_prob": 1.6748905181884766e-05, "words": [{"start": 1670.4, "end": 1671.08, "word": "بساعة", "probability": 0.885498046875}, {"start": 1671.08, "end": 1671.22, "word": " و", "probability": 0.96044921875}, {"start": 1671.22, "end": 1671.34, "word": " نص", "probability": 0.90283203125}, {"start": 1671.34, "end": 1671.92, "word": " KX", "probability": 0.494140625}, {"start": 1671.92, "end": 1672.58, "word": " تربيع", "probability": 0.862060546875}, {"start": 1672.58, "end": 1673.72, "word": " ممكن", "probability": 0.8798828125}, {"start": 1673.72, "end": 1673.86, "word": " هي", "probability": 0.6123046875}, {"start": 1673.86, "end": 1674.08, "word": " تكون", "probability": 0.9794921875}, {"start": 1674.08, "end": 1674.78, "word": " مخزونة", "probability": 0.9150390625}, {"start": 1674.78, "end": 1675.36, "word": " داخل", "probability": 0.9720052083333334}, {"start": 1675.36, "end": 1675.6, "word": " ال", "probability": 0.9541015625}, {"start": 1675.6, "end": 1676.0, "word": " spring", "probability": 0.457275390625}, {"start": 1676.0, "end": 1676.96, "word": " ال", "probability": 0.8427734375}, {"start": 1676.96, "end": 1677.22, "word": " spring", "probability": 0.91259765625}, {"start": 1677.22, "end": 1677.58, "word": " ممكن", "probability": 0.98876953125}, {"start": 1677.58, "end": 1677.94, "word": " يعمل", "probability": 0.9173177083333334}, {"start": 1677.94, "end": 1678.28, "word": " شغل", "probability": 0.9886067708333334}, {"start": 1678.28, "end": 1678.48, "word": " اذا", "probability": 0.681640625}, {"start": 1678.48, "end": 1678.64, "word": " انا", "probability": 0.7734375}, {"start": 1678.64, "end": 1679.22, "word": " شديته", "probability": 0.7875162760416666}, {"start": 1679.22, "end": 1679.64, "word": " compress", "probability": 0.525390625}, {"start": 1679.64, "end": 1680.04, "word": " or", "probability": 0.8095703125}, {"start": 1680.04, "end": 1681.38, "word": " stretch", "probability": 0.6376953125}, {"start": 1681.38, "end": 1681.7, "word": " ممكن", "probability": 0.90185546875}, {"start": 1681.7, "end": 1681.98, "word": " انا", "probability": 0.9580078125}, {"start": 1681.98, "end": 1682.48, "word": " اذا", "probability": 0.8974609375}, {"start": 1682.48, "end": 1682.66, "word": " كان", "probability": 0.986328125}, {"start": 1682.66, "end": 1682.8, "word": " ال", "probability": 0.97021484375}, {"start": 1682.8, "end": 1683.18, "word": " spring", "probability": 0.94580078125}, {"start": 1683.18, "end": 1683.46, "word": " انا", "probability": 0.95458984375}, {"start": 1683.46, "end": 1684.1, "word": " شديته", "probability": 0.9786783854166666}, {"start": 1684.1, "end": 1684.48, "word": " او", "probability": 0.968994140625}, {"start": 1684.48, "end": 1685.74, "word": " ضغطه", "probability": 0.9393310546875}, {"start": 1685.74, "end": 1686.3, "word": " بكون", "probability": 0.913330078125}, {"start": 1686.3, "end": 1686.62, "word": " انا", "probability": 0.72998046875}, {"start": 1686.62, "end": 1686.96, "word": " يعني", "probability": 0.932373046875}, {"start": 1686.96, "end": 1687.54, "word": " بزلت", "probability": 0.8277587890625}, {"start": 1687.54, "end": 1688.28, "word": " شغل", "probability": 0.9837239583333334}, {"start": 1688.28, "end": 1689.48, "word": " فيه", "probability": 0.99169921875}, {"start": 1689.48, "end": 1689.94, "word": " طبعا", "probability": 0.9847412109375}, {"start": 1689.94, "end": 1691.36, "word": " بنستكمل", "probability": 0.93115234375}, {"start": 1691.36, "end": 1691.66, "word": " هذا", "probability": 0.5009765625}, {"start": 1691.66, "end": 1692.06, "word": " ال", "probability": 0.93505859375}, {"start": 1692.06, "end": 1692.28, "word": " ..", "probability": 0.71484375}, {"start": 1692.28, "end": 1692.7, "word": " هذه", "probability": 0.389404296875}, {"start": 1692.7, "end": 1694.06, "word": " التسجيلات", "probability": 0.937109375}, {"start": 1694.06, "end": 1694.16, "word": " و", "probability": 0.9443359375}, {"start": 1694.16, "end": 1694.26, "word": " هذا", "probability": 0.47705078125}, {"start": 1694.26, "end": 1694.58, "word": " الشرح", "probability": 0.8761393229166666}, {"start": 1694.58, "end": 1694.72, "word": " في", "probability": 0.9482421875}, {"start": 1694.72, "end": 1695.26, "word": " المحاضرة", "probability": 0.9730224609375}, {"start": 1695.26, "end": 1695.84, "word": " القادمة", "probability": 0.9943033854166666}, {"start": 1695.84, "end": 1696.02, "word": " ان", "probability": 0.6357421875}, {"start": 1696.02, "end": 1696.18, "word": " شاء", "probability": 0.97314453125}, {"start": 1696.18, "end": 1696.34, "word": " الله", "probability": 0.9453125}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1696.473125, "duration_after_vad": 1667.0006249999992}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..3a7804d9eb180e44d49da686c7c0bf5ec65c99c7
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/5W1AMeNpv0g_raw.srt
@@ -0,0 +1,1508 @@
+1
+00:00:00,990 --> 00:00:05,950
+بسم الله الرحمن الرحيم problem solving strategy
+
+2
+00:00:05,950 --> 00:00:13,590
+طريقة حل المسائل طبعا هنا هذا الموضوع اللي هو ال
+
+3
+00:00:13,590 --> 00:00:17,850
+work energy theorem أو تغيرات الطاقة apply
+
+4
+00:00:17,850 --> 00:00:20,930
+conservation of mechanical energy لما بده ييجي
+
+5
+00:00:20,930 --> 00:00:25,990
+عندي أنا السؤال هطبق اللي هي الطاقة الميكانيكية
+
+6
+00:00:26,440 --> 00:00:29,460
+take the following steps when applying
+
+7
+00:00:29,460 --> 00:00:31,820
+conservation of mechanical energy to problems
+
+8
+00:00:31,820 --> 00:00:35,900
+involving gravity طبعا لما أجي أحل السؤال و أطبق
+
+9
+00:00:35,900 --> 00:00:39,180
+اللي هي أحله عن طريق تغيرات الطاقة أو الطاقة
+
+10
+00:00:39,180 --> 00:00:43,510
+الميكانيكيةنمروحها define the system including all
+
+11
+00:00:43,510 --> 00:00:47,170
+interacting body أول شيء بحدد من المتغيرات
+
+12
+00:00:47,170 --> 00:00:53,390
+الموجودة في السؤال يعني المعطيات والمجاهيل verify
+
+13
+00:00:53,390 --> 00:00:57,470
+the absence of non-conservative force بحدد أنه هذا
+
+14
+00:00:57,470 --> 00:01:01,110
+النظام أو هذه المثلة فيها احتكاك أو ما فيها احتكاك
+
+15
+00:01:01,110 --> 00:01:04,310
+طبعا إذا ما فيها احتكاك هي conservative إذا ما
+
+16
+00:01:04,310 --> 00:01:07,410
+فيها احتكاك .. إذا فيه احتكاك طبعا non
+
+17
+00:01:07,410 --> 00:01:09,570
+-conservative إذا ما فيها احتكاك conservative
+
+18
+00:01:10,370 --> 00:01:14,730
+النمرة اتنين choose ال equation for Y طبعا بختار
+
+19
+00:01:14,730 --> 00:01:17,730
+برضه level النمرة اتنين بختار level ال level ها ده
+
+20
+00:01:17,730 --> 00:01:21,750
+بيكون ال Y بيساوي Zero بيسموها أو Zero Potential
+
+21
+00:01:21,750 --> 00:01:25,790
+Gravitational Potential Energy بختار level بعدين
+
+22
+00:01:25,790 --> 00:01:32,810
+بختار نقطتين نقطة طبعا initial و final pointone
+
+23
+00:01:32,810 --> 00:01:35,470
+point where you have given information نقطة بيكون
+
+24
+00:01:35,470 --> 00:01:38,010
+المعلومات الموجودة عندي ونقطة تانية بيطلب مني
+
+25
+00:01:38,010 --> 00:01:42,670
+المعلومات اللي لازمة سواء كان سرعة نهائية سواء
+
+26
+00:01:42,670 --> 00:01:46,290
+سرعة تدائية و هكذا write down the conservation of
+
+27
+00:01:46,290 --> 00:01:50,890
+energy equation بعد هي بكتب المعادلةالمعادلة طبعا
+
+28
+00:01:50,890 --> 00:01:54,330
+احنا اخترنا level اخترنا نقطتين بكتب معادلة ال
+
+29
+00:01:54,330 --> 00:01:58,250
+conservation of energy اللي هي اللي هي نص MV
+
+30
+00:01:58,250 --> 00:02:03,450
+initial تربيع زاد MGH او Mgy initial ساوي نص MV
+
+31
+00:02:03,450 --> 00:02:07,910
+final تربيع زاد Mgy final اللي هي المعادلة 5.15
+
+32
+00:02:07,910 --> 00:02:14,710
+بعد هيك بحدد المتغيرات او المجاهيل الموجودةليه؟ كي
+
+33
+00:02:14,710 --> 00:02:18,910
+أحل بعوض عن المعطيات و بحل الأسئلة و بوجد المجاهد
+
+34
+00:02:18,910 --> 00:02:24,270
+سواء كانت speed أو position أو أي اي مجهول موجود
+
+35
+00:02:24,270 --> 00:02:28,620
+في السؤالالناجينية نطبق ما ذكرها سابقا في هذا ال
+
+36
+00:02:28,620 --> 00:02:34,100
+example example 55 a diver of mass M dropped from
+
+37
+00:02:34,100 --> 00:02:37,660
+a port 10 متر above the water surface طبعا برضه
+
+38
+00:02:37,660 --> 00:02:44,220
+غواص الغواص بده يغطس من ارتفاع 10 متر من أعلى
+
+39
+00:02:44,220 --> 00:02:48,260
+above the water أعلى سطح المياه زي ما هو موضح
+
+40
+00:02:48,260 --> 00:02:52,480
+بالشكل هي الغواص بده من هنا من المنصة هذهارتفاعها
+
+41
+00:02:52,480 --> 00:02:57,340
+عن السطح الميه كان 10 متر طبعا الغواص بدأ إذا ..
+
+42
+00:02:57,340 --> 00:03:01,380
+إذا الغواص released أو بدأ من ال rest بتكون V0 V
+
+43
+00:03:01,380 --> 00:03:04,720
+initial 0 وبالتالي ال energy zero لما يبدأ الغواص
+
+44
+00:03:04,720 --> 00:03:09,180
+من هذه النقطة بتكون طاقة الوضع اللي هي أقصى ما
+
+45
+00:03:09,180 --> 00:03:14,260
+يمكن اللي هي MgY initial طبعا غطس الغطاس و نزل وصل
+
+46
+00:03:14,260 --> 00:03:17,640
+على سطح الميه سطح الميه بعتبره .. بعتبره هو ال
+
+47
+00:03:17,640 --> 00:03:20,580
+level وبالتالي potential energy اللي هي هذه نقطة
+
+48
+00:03:20,580 --> 00:03:24,740
+ال finalيعني من البداية بعتبر أنه هنا ال level نمر
+
+49
+00:03:24,740 --> 00:03:27,800
+اتنين هي نقطة ال initial وهي نقطة ال final في ال
+
+50
+00:03:27,800 --> 00:03:32,820
+initial بسأل نفسي في طاقة حركة نعم؟ Zero لإنه
+
+51
+00:03:32,820 --> 00:03:37,220
+السرعة Zero إذا طاقة الوضع أقصى ما يمكن لما يوصل
+
+52
+00:03:37,220 --> 00:03:40,160
+على سطح الميه اللي هي ال final بتكون طاقة الحركة
+
+53
+00:03:40,160 --> 00:03:45,000
+نصف V تربيع final وطاقة الوضع Zero نشوف الحل زي ما
+
+54
+00:03:45,000 --> 00:03:51,200
+هو موضح في الكتابالحل neglect طبعا بيحكيلنا اهمل
+
+55
+00:03:51,200 --> 00:03:54,500
+مقاومة الهواء استخدم use conservation of
+
+56
+00:03:54,500 --> 00:03:58,620
+mechanical energy باستخدم قانون اللي هو الطاقة
+
+57
+00:03:58,620 --> 00:04:01,460
+الميكانيكية اللي هي ال conservation يعني a initial
+
+58
+00:04:01,460 --> 00:04:05,620
+بتساوي ال a final أو k زائد b initial بتساوي k
+
+59
+00:04:05,620 --> 00:04:10,370
+زائد b a finalfind his speed 5 meters above أوجد
+
+60
+00:04:10,370 --> 00:04:14,790
+سرعته على مسافة 5 متر من سطح الميه يعني ماوصل لسطح
+
+61
+00:04:14,790 --> 00:04:20,670
+الميه الحل find the divers speed half way down
+
+62
+00:04:20,670 --> 00:04:24,130
+طبعا المسافة الكلية كانت عشرة مطلوب منه نوجد سرعته
+
+63
+00:04:24,130 --> 00:04:28,510
+على بعد 5 متر من سطح الميه يعني الآن بختار نقطتين
+
+64
+00:04:28,510 --> 00:04:32,470
+نقطة البداية هي اللي هي على بعد عشرة و النقطة
+
+65
+00:04:32,470 --> 00:04:36,030
+النهائية على بعد 5 من سطح الميه السطح الميه هو ال
+
+66
+00:04:36,030 --> 00:04:39,170
+levelwrite the energy conservation equation and
+
+67
+00:04:39,170 --> 00:04:43,790
+supply the proper terms إذا بدي أعوض فيه معادلات
+
+68
+00:04:43,790 --> 00:04:49,470
+اللي هي الطاقة الميكانيكية K e initial زائد P e
+
+69
+00:04:49,470 --> 00:04:52,730
+initial بتساوي K e final زائد P e final طاقة
+
+70
+00:04:52,730 --> 00:04:55,410
+الحركة زائد طاقة الوضع initial بتساوي طاقة الحركة
+
+71
+00:04:55,410 --> 00:05:00,110
+زائد طاقة الوضع finalفي ال initial كانت نُص mv
+
+72
+00:05:00,110 --> 00:05:04,630
+initial تربيع زائد mgy initial بتساوي نُص mv final
+
+73
+00:05:04,630 --> 00:05:08,130
+تربيع زائد mgy final طبعا في ال initial هو بدأ من
+
+74
+00:05:08,130 --> 00:05:12,730
+ال rest فمعنى الكلام v initial بتساوي zero cancel
+
+75
+00:05:12,730 --> 00:05:16,590
+the mass and solve v final طبعا بدي أرفع ال mass
+
+76
+00:05:16,590 --> 00:05:22,680
+من كل الأطرافوهنا هعوض عنها بـ 0 إذاً 0 زائد gy
+
+77
+00:05:22,680 --> 00:05:27,780
+initial ساوي نص v final تربيه زائد gy final طبعا
+
+78
+00:05:27,780 --> 00:05:33,660
+ال y final كانت خمسةالـ y initial كانت عشرة فبنعوض
+
+79
+00:05:33,660 --> 00:05:37,040
+اتنين تسعة و تمانية من عشرة اللي هي الجاذبية ال y
+
+80
+00:05:37,040 --> 00:05:40,900
+initial كانت عشرة و ال y final كانت خمسة تطلع عند
+
+81
+00:05:40,900 --> 00:05:45,620
+v final 9.9 متر في الثانية عند نقطة خمسة متر بتبعد
+
+82
+00:05:45,620 --> 00:05:50,790
+عن سطح المي اللي احنا اكبرناه هو ال levelفي B,
+
+83
+00:05:51,010 --> 00:05:54,850
+find the diver's speed at the water's surface بدي
+
+84
+00:05:54,850 --> 00:05:59,690
+أنا أجد السرعة لما على سطح الميه معناته ال Y بساوة
+
+85
+00:05:59,690 --> 00:06:04,810
+Zero هنستخدم نفس القانون اللي هي K زائد B initial
+
+86
+00:06:04,810 --> 00:06:08,550
+بساوة K زائد B final ال K initial بدت من ال rest
+
+87
+00:06:08,550 --> 00:06:12,170
+أو released معناته ال V initial Zero إذا هدي Zero
+
+88
+00:06:12,170 --> 00:06:16,750
+MgY Y كان عشرةبساوة نص Mv final زائد Zero تقرينا
+
+89
+00:06:16,750 --> 00:06:20,970
+وصلت اللي هي Mgy final Zero لإنه وصلت على نفس ال
+
+90
+00:06:20,970 --> 00:06:24,930
+level و أي طاقة وضع على ال level نفسه Y بساوة Zero
+
+91
+00:06:24,930 --> 00:06:27,830
+وبالتالي ال potential energy بساوة Zero إذا V
+
+92
+00:06:27,830 --> 00:06:34,570
+final بتساوة جزر 2Gy initial اللي 2 في 9 و 8 من 10
+
+93
+00:06:34,570 --> 00:06:37,610
+مضروبة في ال Y initial اللي هي 10 تطلع 14 متر في
+
+94
+00:06:37,610 --> 00:06:43,960
+التانية عند سطح الميهالنشلة example خمسة ستة
+
+95
+00:06:43,960 --> 00:06:49,800
+powerful across chubar launch itself at an angle
+
+96
+00:06:49,800 --> 00:06:52,400
+of خمسة واربين above the horizontal and rises to
+
+97
+00:06:52,400 --> 00:06:56,000
+the maximum height of آحد متر during the ليب
+
+98
+00:06:56,000 --> 00:07:02,620
+الجندب تبع الحقولطبعا الطار من الأرض يجي ندب أو أي
+
+99
+00:07:02,620 --> 00:07:06,360
+حشر أو أي جسم طار من سطح الأرض ممكن نعتبرها كرة
+
+100
+00:07:06,360 --> 00:07:13,640
+حجر جسم طبعا الطار بزاوية 45 درجة هنا بسرعة
+
+101
+00:07:13,640 --> 00:07:18,780
+ابتدائية V initial هو طاير طبعا وصل لأقصى ارتفاع
+
+102
+00:07:18,780 --> 00:07:22,260
+عند أقصى ارتفاع في هذه المنطقة بتكون السرعة
+
+103
+00:07:22,260 --> 00:07:26,800
+النهائية باتجاه Y0 السرعة الابتدائية هي نفس السرعة
+
+104
+00:07:26,800 --> 00:07:33,570
+باتجاه X مابتتغيرشإذن هنا إنه بيحكي لإنه powerful
+
+105
+00:07:33,570 --> 00:07:37,530
+crust shovel launches itself at angle 45 away from
+
+106
+00:07:37,530 --> 00:07:40,910
+the horizontal and rises to maximum height ارتفاع
+
+107
+00:07:40,910 --> 00:07:45,730
+عند أقصى ارتفاع كان واحد متر خلال during the leap
+
+108
+00:07:45,730 --> 00:07:49,870
+with what speed v initial did it leave the ground
+
+109
+00:07:50,290 --> 00:07:53,390
+بدي السرعة الابتدائية اللى هدى الجندب أو هدى
+
+110
+00:07:53,390 --> 00:07:57,950
+الحشرة تركت الأرض أو طاعته واضح السؤال بدأ الجسم
+
+111
+00:07:57,950 --> 00:08:02,250
+من هنا بدأ V initial زاوية أول حاجة بنعملها بدي
+
+112
+00:08:02,250 --> 00:08:07,150
+أحلل ال V initial إلى مركبتين V initial cosine ال
+
+113
+00:08:07,150 --> 00:08:12,630
+45 و V initial sine ال 45 الآن V initial X بتتغيرش
+
+114
+00:08:12,630 --> 00:08:17,050
+على طول ال trajectory طول مسار هدى الطيران لعند
+
+115
+00:08:17,050 --> 00:08:21,820
+أقصى ارتفاعالأن دا استخدم قانون ال conservation of
+
+116
+00:08:21,820 --> 00:08:27,640
+energy ده نستخدم ال conservation energy و نحل ..
+
+117
+00:08:27,640 --> 00:08:31,320
+نستخدم ال conservation of energy و نحل السؤال
+
+118
+00:08:31,320 --> 00:08:38,830
+السؤال طبعاحكاية ليه؟ Substitute بدي أحط V initial
+
+119
+00:08:38,830 --> 00:08:43,590
+V initial موجودة حاليًا لمركباتها Y initial 0 بدي
+
+120
+00:08:43,590 --> 00:08:48,710
+أعتبر أن هذا هو ال level و V final هي نفسها V X
+
+121
+00:08:48,710 --> 00:08:54,190
+لإن V final بتجاه ال Y بيساوي Zero ال Y final هي
+
+122
+00:08:54,190 --> 00:08:59,000
+ال H maximumمعنى الكلام معناته أنه هي ال .. يعني
+
+123
+00:08:59,000 --> 00:09:02,400
+هذا الكلام مافيش عندنا friction وبالتالي هي اللي
+
+124
+00:09:02,400 --> 00:09:04,960
+عن طريق ال gravity أو الجاذبية هو بتطير بفعل
+
+125
+00:09:04,960 --> 00:09:09,600
+جاذبية إذا أن بأستخدم conservation force إذا أن
+
+126
+00:09:09,600 --> 00:09:12,780
+بأستخدم ان .. انه طاقة الميكانيكية initial بيساوي
+
+127
+00:09:12,780 --> 00:09:17,180
+الطاقة الميكانيكية finalمعناها نُص Mv initial
+
+128
+00:09:17,180 --> 00:09:20,600
+تربيع زائد نُص زائد Mgy initial بتساوي نُص Mv
+
+129
+00:09:20,600 --> 00:09:25,580
+final تربيع زائد Mgy final هنعوض اللي هي ال V
+
+130
+00:09:25,580 --> 00:09:31,720
+initial نُص Mv initial تربيع بدها تساوي نُص Mv X
+
+131
+00:09:31,720 --> 00:09:38,560
+تربيع زائد Mg اللي هو H أقصى ارتفاع H ال initial
+
+132
+00:09:38,560 --> 00:09:41,660
+ال Mgy كانت بتساوي zero لإنه بدأ من نفس ال level
+
+133
+00:09:42,100 --> 00:09:46,240
+هضرب الطرفين طبعا هنا M على 2 ب2 على M علشان أضيع
+
+134
+00:09:46,240 --> 00:09:50,920
+اللي هي M على 2 M على 2 هضيع ال M على 2 بيظل عندنا
+
+135
+00:09:50,920 --> 00:09:57,340
+V initial تربيع بيساوي VX تربيع زائد 2GH الان
+
+136
+00:09:57,340 --> 00:10:03,100
+eliminate VX بده أعوض عن VX من خلال تحليل اللي هي
+
+137
+00:10:03,100 --> 00:10:07,600
+ال V initial هنعوض عنها بsubstituting VX بتساوي V
+
+138
+00:10:07,600 --> 00:10:15,890
+initial cosine 45إذاً V A I تربيعها تسوى V X تربيع
+
+139
+00:10:15,890 --> 00:10:19,890
+اللي هي عبارة عن V Initial Cos 45 كل تربيع زائد
+
+140
+00:10:19,890 --> 00:10:26,110
+اتنين GH عوضنا عنها هنا Cos 45 اللي هي واحد ع جزر
+
+141
+00:10:26,110 --> 00:10:29,440
+اتنين لما أجي ربيعها بتصير نصبتصير عند V initial
+
+142
+00:10:29,440 --> 00:10:34,160
+تربيع بدها تساوي نص V initial تربيع زائد اتنين GH
+
+143
+00:10:34,160 --> 00:10:38,360
+اذا V initial في هذه الحالة زي تساوي اتنين جزر GH
+
+144
+00:10:38,360 --> 00:10:42,340
+الجي تسعة و تمانية من عشرة و ال H واحد integer
+
+145
+00:10:42,340 --> 00:10:48,260
+طلعنا السرعة الابتدائية اللى هدا الحشرة اطارت فيها
+
+146
+00:10:48,260 --> 00:10:52,800
+نجي ل section خمسة أربعة gravity and non
+
+147
+00:10:52,800 --> 00:10:56,260
+conservative force الان الجاذبية و القوة الغير
+
+148
+00:10:56,260 --> 00:11:00,870
+محفوظةwhen non conservative force are involved
+
+149
+00:11:00,870 --> 00:11:05,750
+along with gravitation the full work energy theory
+
+150
+00:11:05,750 --> 00:11:09,710
+must be used often with technique from topics for
+
+151
+00:11:09,710 --> 00:11:14,030
+solving problems require the basic procedure of
+
+152
+00:11:14,030 --> 00:11:17,070
+the problem solving strategy for conservation of
+
+153
+00:11:17,070 --> 00:11:20,270
+energy problem in the previous section ايش معناها
+
+154
+00:11:20,270 --> 00:11:26,580
+لما انا استخدم لما تكون عندى القوة غير محفوظةطبعا
+
+155
+00:11:26,580 --> 00:11:31,140
+involved along غير محفوظة إضافة لإيه اللي هي الشغل
+
+156
+00:11:31,140 --> 00:11:34,300
+الناتج عن الجاذبية أو طاقة الوضع الخاصة بالجاذبية
+
+157
+00:11:34,300 --> 00:11:39,020
+فال full work energy theorem نظرية كلية للطاقة
+
+158
+00:11:39,020 --> 00:11:44,020
+والشغل ممكن أنا أستخدم أجمع الجهتين even with
+
+159
+00:11:44,020 --> 00:11:48,800
+technique .. بتكنيك معينبأحل هذه المعادلة لكن
+
+160
+00:11:48,800 --> 00:11:53,320
+بحتاج إلى أساسيات وخطوات أساسية لحل هذه
+
+161
+00:11:53,320 --> 00:11:56,020
+الستراتيجية اللي هي conservation of energy problem
+
+162
+00:11:56,020 --> 00:11:59,980
+في ال previous section ممكن أنا أحل اللي هي
+
+163
+00:11:59,980 --> 00:12:03,810
+conservative و non conservative في مسألة واحدةThe
+
+164
+00:12:03,810 --> 00:12:07,290
+only difference lies in substituting equation 5
+
+165
+00:12:07,290 --> 00:12:11,310
+.13, the work energy equation with potential
+
+166
+00:12:11,310 --> 00:12:16,550
+energy for equation 5.15 طبعا هنوضع هذا الكلام في
+
+167
+00:12:16,550 --> 00:12:22,280
+هذا المثاليعني ممكن احنا نحل اللى هى ال
+
+168
+00:12:22,280 --> 00:12:24,820
+conservative و ال non-conservative فى سؤال واحد
+
+169
+00:12:24,820 --> 00:12:28,780
+فدلحالة بيكون عندى الشغل القلي هو عبارة عن شغل non
+
+170
+00:12:28,780 --> 00:12:32,340
+-conservative و شغل conservative يعنى طقه
+
+171
+00:12:32,340 --> 00:12:34,920
+الميكانيكية ال final ناقص الطقه الميكانيكية
+
+172
+00:12:34,920 --> 00:12:39,120
+initial بساوي الشغل الناتج عن الاحتكاك طبعا نجلة
+
+173
+00:12:39,120 --> 00:12:43,390
+هذا السؤالwater slides شوان شوان زي ما انتوا احنا
+
+174
+00:12:43,390 --> 00:12:47,270
+شايفين اللي هو بطبعا ال water slides اللي هو اللي
+
+175
+00:12:47,270 --> 00:12:51,510
+بتزلقوا حتى يوصلوا للميه و طبعا يقطصوا في الميه عن
+
+176
+00:12:51,510 --> 00:12:57,570
+طريق مسار معين ال hand determine the speed of بدا
+
+177
+00:12:57,570 --> 00:13:04,000
+أوجد سرعتمرأة كتلتها 60 كيلو جرام at the bottom of
+
+178
+00:13:04,000 --> 00:13:08,800
+such slide and أسفل ال slide assuming no friction
+
+179
+00:13:08,800 --> 00:13:12,720
+is present طبعا بأفرض الآن مافي friction بأفرض في
+
+180
+00:13:12,720 --> 00:13:16,840
+البداية مافي friction هي كتلتها بده تكون 60 كيلو
+
+181
+00:13:16,840 --> 00:13:23,820
+جرام وبده أوجد سرقتها على أسفل اللي هو اللي هي
+
+182
+00:13:23,820 --> 00:13:30,720
+المسار تبعنا طبعا نحل الجزئية A ونرجع ل BFind the
+
+183
+00:13:30,720 --> 00:13:33,240
+woman's speed at the bottom of the slide assuming
+
+184
+00:13:33,240 --> 00:13:35,920
+no friction طبعا بالبداية بدى افرض انه مافي
+
+185
+00:13:35,920 --> 00:13:40,000
+friction كلمة no friction معناها انه mechanical
+
+186
+00:13:40,000 --> 00:13:43,420
+energy ال initial بتساوي ال final بختار نقطة بداية
+
+187
+00:13:43,420 --> 00:13:48,210
+و نقطة نهاية وبختار levelهنعود فى قانون نص Mv
+
+188
+00:13:48,210 --> 00:13:52,390
+initial تربيع زايد Mgy initial بتساوي نص Mv final
+
+189
+00:13:52,390 --> 00:13:56,410
+تربيع زايد Mgy final ال V initial طبعا start from
+
+190
+00:13:56,410 --> 00:14:00,930
+the rest V initial بتساوي 0 و ال Y final بتساوي 0
+
+191
+00:14:00,930 --> 00:14:07,900
+لإن هى بدت من مسافة معيرة و نزلت لبطومالـ MgY
+
+192
+00:14:07,900 --> 00:14:11,980
+initial كانت على ارتفاع معين و نزلت خلال مسار و
+
+193
+00:14:11,980 --> 00:14:15,540
+فيه ماء فيه friction طبعا هذا بالنسبة للمرأة كأنها
+
+194
+00:14:15,540 --> 00:14:18,560
+يعني بدأت من مسار معين من أعلى سطح الميه و نزلت
+
+195
+00:14:18,560 --> 00:14:22,200
+لها الماء بدأ أوجد V final على السطح طبعا على
+
+196
+00:14:22,200 --> 00:14:25,440
+السطح بتكون الـY final بساوي 0 لإن ال level هو
+
+197
+00:14:25,440 --> 00:14:29,700
+نفسه على الـ0 فتخطى الوضع بساوي 0ببوجد طبعا v
+
+198
+00:14:29,700 --> 00:14:32,640
+final من هذه المعادلة ال M بتروح مع ال M بظهر ان v
+
+199
+00:14:32,640 --> 00:14:41,740
+final بيساوي جزر 2gy initial تطلع انه 20.7 20.7
+
+200
+00:14:41,740 --> 00:14:48,170
+نيجي لاقى ان السؤال B او مطلوب BFind the work done
+
+201
+00:14:48,170 --> 00:14:53,550
+on the woman by friction if V final بساوة 18 طبعا
+
+202
+00:14:53,550 --> 00:14:56,670
+أقل من ال 20.7 متر في الثانية الآن مطلوب من أن
+
+203
+00:14:56,670 --> 00:15:01,350
+نوجد الشغل المفروض واسط أو ال friction بدي الشغل
+
+204
+00:15:01,350 --> 00:15:04,710
+المفروض واسط ال friction ده أفرض أن المسار اللى
+
+205
+00:15:04,710 --> 00:15:08,470
+مشيته هى المرأة أو هى البنت هذا المسار فيه
+
+206
+00:15:08,470 --> 00:15:14,840
+friction علشان تتزلج او تتزلج خلالأو تتسحر خلال
+
+207
+00:15:14,840 --> 00:15:18,520
+هذا المسار إلى تصل لسطح الميّه طبعا بدي اكتب
+
+208
+00:15:18,520 --> 00:15:22,180
+المعادلة لكن المعادلة الأولى انه مش بس ال
+
+209
+00:15:22,180 --> 00:15:24,060
+mechanical energy ال initial بيساوي ال final في
+
+210
+00:15:24,060 --> 00:15:28,120
+عندي أنا شغل فالشغل المبدو الوسط الاحتكاك بيساوي
+
+211
+00:15:28,120 --> 00:15:33,320
+اللي هي ال E final ناقص E initial يعني الطاقة
+
+212
+00:15:33,320 --> 00:15:37,800
+الميكانيكية final ناقص ال initial بأوصل لهذه
+
+213
+00:15:37,800 --> 00:15:43,670
+المعادلة لإنه Delta K زائد Delta P أوK final نخس K
+
+214
+00:15:43,670 --> 00:15:47,290
+initial زائد B final نخس B initial هي W and C طبعا
+
+215
+00:15:47,290 --> 00:15:50,630
+ليها أكتر من صورة هذه المعادلة معنى الكلام أن نص
+
+216
+00:15:50,630 --> 00:15:54,390
+Mv final تربيع نخس نص Mv initial تربيع بتساوي ال
+
+217
+00:15:54,390 --> 00:15:58,610
+Mgy final نخس Mgy initial لإنه في عندنا friction
+
+218
+00:15:58,610 --> 00:16:01,930
+لو مافي friction بنعتبرها دي zero إذا وجود ال
+
+219
+00:16:01,930 --> 00:16:06,490
+friction بنعتبرها موجودة بتعود عن ال M بتساوي 60
+
+220
+00:16:07,150 --> 00:16:11,550
+Vfinal أعطانيها 18 Vinitial 0 لإنها released أو
+
+221
+00:16:11,550 --> 00:16:15,570
+بدأت من ال rest وبنحل بقى وجه ال W and C نص في M
+
+222
+00:16:15,570 --> 00:16:21,670
+في V تربيع ناقص 0 ال initial بتساوي ال final لإن
+
+223
+00:16:21,670 --> 00:16:26,850
+وصت ل level ال Y final بتساوي 0 ناقص 60 في 9.8 في
+
+224
+00:16:26,850 --> 00:16:34,420
+21.9إذن بيطلع عندى W and C بساوي ناقص تلاتة point
+
+225
+00:16:34,420 --> 00:16:38,900
+واحد وستة فعشرة أقص تلاتة G هذا الشغل المبذول
+
+226
+00:16:38,900 --> 00:16:44,320
+بواسطة الاحتكاك example
+
+227
+00:16:44,320 --> 00:16:45,060
+آخر
+
+228
+00:16:48,330 --> 00:16:54,950
+نجلة example خمسة تمانية scars start from breast
+
+229
+00:16:54,950 --> 00:17:05,530
+طبعا برضه بتزلج أو بتتزلج بدأ من ال wrist من أعلى
+
+230
+00:17:05,530 --> 00:17:12,010
+decline height من أعلى سطح مايل frictionless وليست
+
+231
+00:17:12,010 --> 00:17:17,440
+خشين أملاس يعنيعن ارتفاع عشرين متر، طبعا هي الشكل
+
+232
+00:17:17,440 --> 00:17:25,720
+لإن شخص بيتزلج على مسار ما ناعم أملس، ممكن يكون
+
+233
+00:17:25,720 --> 00:17:29,280
+تلج، ممكن يكون أي سطح أملس، بدأ من النقطة A وصل
+
+234
+00:17:29,280 --> 00:17:33,300
+للنقطة B، هاد اتزلج، بدأ من ارتفاع عشرين متر على
+
+235
+00:17:33,300 --> 00:17:37,700
+سطح مايل، السطح المايل طبعا مايل بزاوية Eθنشوف
+
+236
+00:17:37,700 --> 00:17:42,740
+السؤال مطلوب .. مطلوب مننا نشوف السؤال السؤال find
+
+237
+00:17:42,740 --> 00:17:48,340
+the sky at speed at the bottom لدى نوجد سرعة هذا
+
+238
+00:17:48,340 --> 00:17:53,820
+المتزلج على .. من النقطة A لنقطة B بعدين طالب how
+
+239
+00:17:53,820 --> 00:17:56,940
+far does the sky travel on the horizontal surface
+
+240
+00:17:56,940 --> 00:18:02,240
+before coming to rest مطلوب مننا نوجد المسافة اللى
+
+241
+00:18:02,240 --> 00:18:09,330
+بيمشيها على السطح الأفقي قبل ما يقف يعنيفي البداية
+
+242
+00:18:09,330 --> 00:18:14,970
+بدأ من النقطة A وصل للنقطة B بدأ من ارتفاع 20 وصل
+
+243
+00:18:14,970 --> 00:18:19,230
+للنقطة B و بعدين من B طالب مني المسافة اللى بدى
+
+244
+00:18:19,230 --> 00:18:22,890
+يمشيها على المستوى الأفقي لحتى يقف عند النقطة C
+
+245
+00:18:22,890 --> 00:18:28,720
+نبدأ نحلSolution A. Find the sky speed at the
+
+246
+00:18:28,720 --> 00:18:33,480
+bottom بدا أوجد اللي هو سرعة ال skies هذا المتزلج
+
+247
+00:18:33,480 --> 00:18:38,860
+عند النقطة BFollow the procedure used in part A of
+
+248
+00:18:38,860 --> 00:18:41,780
+the previous example as the skies move from the
+
+249
+00:18:41,780 --> 00:18:45,660
+top point A to the bottom point طبعا بدي أستخدم
+
+250
+00:18:45,660 --> 00:18:49,140
+نفس العلاقة اللي استخدمتها في السؤال الأول ونفس
+
+251
+00:18:49,140 --> 00:18:53,320
+الخطوات بسأل نفسي هل في احتكاك ولا مافيإذا مافي
+
+252
+00:18:53,320 --> 00:18:57,720
+احتكاك معناها أنه باستخدم اللي هو الـE initial
+
+253
+00:18:57,720 --> 00:19:00,500
+بتساوي الـE final الـE هي عبارة عن طاقة وضع وحركة
+
+254
+00:19:00,500 --> 00:19:03,480
+في ال initial بتساوي طاقة الوضع وحركة بال final
+
+255
+00:19:03,480 --> 00:19:07,760
+بالنسبة لل initial طاقة الحركة zero فبيكون عندي
+
+256
+00:19:07,760 --> 00:19:12,400
+MGY initial بتساوي نص MV final تربيع لإن أنا وصلت
+
+257
+00:19:12,400 --> 00:19:17,740
+لل level باعتبر أن المنطقة هذه هي ال levelمعناته
+
+258
+00:19:17,740 --> 00:19:20,820
+هذه النقطة الإبتدائية تغطي الحركة عن Zero تغطي
+
+259
+00:19:20,820 --> 00:19:26,360
+الوضع Mgh أو Mgy في المنطقة هذه صارت نص Mv تربيع
+
+260
+00:19:26,360 --> 00:19:29,920
+طاقة الوضع Zero لإن ال Y بيساوي Zero لإنه وصلت ل
+
+261
+00:19:29,920 --> 00:19:35,000
+ال level طبعا من خلال المعادلة بحصل على إنه ال V
+
+262
+00:19:35,000 --> 00:19:40,600
+عند النقطة B بدها تساوي 2 جزر Gh يعني 2.980 هو
+
+263
+00:19:40,600 --> 00:19:47,070
+الارتفاع كان 20 بتطلع عند V P بيساوي 19.8في B
+
+264
+00:19:47,070 --> 00:19:49,430
+مطلوب find the distance travelled on the
+
+265
+00:19:49,430 --> 00:19:52,670
+horizontal rough surface أو جد الأن المسافة
+
+266
+00:19:52,670 --> 00:19:57,190
+الأفقية اللي هذا المتزلج بيمشيها على مستوى خشن حتى
+
+267
+00:19:57,190 --> 00:20:01,690
+يصل أو يتوقف عنده النقطة Cطبعا applying the work
+
+268
+00:20:01,690 --> 00:20:05,250
+energy طالما انا في احتكاك بدأ استخدم قانون اللي
+
+269
+00:20:05,250 --> 00:20:10,210
+هو ال energy theorem او قانون نظرية الشغل والطاقة
+
+270
+00:20:10,210 --> 00:20:14,290
+اللي فيها احتكاك من القانون اللي هو W net بالساوة
+
+271
+00:20:14,290 --> 00:20:19,420
+ناقص FK في D بساوة Delta K Eطبعا هنا هو أشتغل على
+
+272
+00:20:19,420 --> 00:20:24,540
+المستوى الأفقي من النقطة B إلى النقطة C إذا الشغل
+
+273
+00:20:24,540 --> 00:20:28,160
+الناتج عن الاحتكاك اللي هو الشغل الكلي بيساوي ناقص
+
+274
+00:20:28,160 --> 00:20:33,700
+FK في D FK بيساوي ميو كي في ال normal دلتا KE ليه
+
+275
+00:20:33,700 --> 00:20:38,300
+نص MV final هي عند ال C تربية ناقص نص MV initial
+
+276
+00:20:38,300 --> 00:20:42,660
+عند ال C حكاية ال stop معناته VC بيساوي Zero و ال
+
+277
+00:20:42,660 --> 00:20:45,320
+FK بيساوي ميو كي في ال normal و ال normal بتساوي
+
+278
+00:20:45,320 --> 00:20:51,790
+ال MGبنعوض ميو كي ميو كي ميو كي ميو كي ميو كي ميو
+
+279
+00:20:51,790 --> 00:20:58,690
+كي ميو كي ميو كي ميو كي
+
+280
+00:21:04,680 --> 00:21:13,220
+VP تربيع على 2 MUK في G فدي على المستوى الخشن كانت
+
+281
+00:21:13,220 --> 00:21:19,320
+هيمشي مسافة 95.2 V عند النقطة P اللي أنا طلعتها من
+
+282
+00:21:19,320 --> 00:21:24,960
+المطلوب الأول هو جزر 2 GH 19.8 لكل تربيع على ال 2
+
+283
+00:21:24,960 --> 00:21:31,230
+MUK هو معامل الاحتكاك المتحرك هو أعطانيمضروب في
+
+284
+00:21:31,230 --> 00:21:35,070
+تسعة و تمانية من عشرة فبتطلع معايا خمسة وتسعين
+
+285
+00:21:35,070 --> 00:21:38,610
+point اتنين متر هو المسافة اللى مشيها على المستوى
+
+286
+00:21:38,610 --> 00:21:44,790
+الخشن نيجي
+
+287
+00:21:44,790 --> 00:21:49,410
+ل section خمسة .. خمسة بعنوان spring potential
+
+288
+00:21:49,410 --> 00:21:54,410
+energy ال spring potential energy اللى هو طاقة
+
+289
+00:21:54,410 --> 00:21:59,150
+الوضع داخل اللى هى النعبد أو ال springالwork done
+
+290
+00:21:59,150 --> 00:22:02,310
+by applied force is stretching or compressed
+
+291
+00:22:02,310 --> 00:22:05,790
+spring can be recovered by removing the applied
+
+292
+00:22:05,790 --> 00:22:10,130
+force so like gravity الآن بالنسبة للspring أو
+
+293
+00:22:10,130 --> 00:22:15,150
+النعبد بعتبره هي قوة conservative محفوظة لإن
+
+294
+00:22:15,150 --> 00:22:20,430
+النعبد ممكن يكون stretch يعني مشدود أو compressed
+
+295
+00:22:20,430 --> 00:22:25,860
+أو مضغوطكمان ال spring برجع لبضعه اللي كان عليه
+
+296
+00:22:25,860 --> 00:22:29,180
+يعني ممكن أنا أشده و أفلط و برجع لبضعه أو أنا أضغط
+
+297
+00:22:29,180 --> 00:22:32,840
+و أفلط و برجع لبضعه الطبيعي ال spring force is
+
+298
+00:22:32,840 --> 00:22:35,440
+conservative زي ما حكينا الآن رجعنا لحكيناها
+
+299
+00:22:35,440 --> 00:22:39,200
+السابقان أنه conservative force هي ال gravity أو
+
+300
+00:22:39,200 --> 00:22:41,880
+gravitational potential energy أو ال spring force
+
+301
+00:22:41,880 --> 00:22:45,620
+يسموها conservative force as long as losses
+
+302
+00:22:45,620 --> 00:22:49,620
+through internala friction of the spring can be
+
+303
+00:22:49,620 --> 00:22:53,300
+neglected ممكن أعمل انا احتكاك ناتج عن حلقات ال
+
+304
+00:22:53,300 --> 00:22:56,220
+spring أو ال spring أو النابط this means that
+
+305
+00:22:56,220 --> 00:22:59,640
+means a potential energy function can be found and
+
+306
+00:22:59,640 --> 00:23:02,180
+used in the work energy theory ممكن أطبق قانون
+
+307
+00:23:02,180 --> 00:23:10,580
+الشغل والشغل والطاقة على ال spring يعني مثللو كان
+
+308
+00:23:10,580 --> 00:23:14,100
+الـspring لا هو مضغوط ولا مشدود فهذه باعتبرها نقطة
+
+309
+00:23:14,100 --> 00:23:17,680
+اتزان بيسموها equilibrium point equilibrium point
+
+310
+00:23:17,680 --> 00:23:22,140
+يعني X بالساوة 0 هاي هاي الكتلة بعد هيك جيبت أنا
+
+311
+00:23:22,140 --> 00:23:28,170
+الكتلة وضغطت هذا ال spring أو النعبطضغطوا مسافة X
+
+312
+00:23:28,170 --> 00:23:32,770
+معناها هذا الـspring إله طاقة ووضع مرنية بيسموها
+
+313
+00:23:32,770 --> 00:23:37,070
+BES بتساوي نص K X تربيع طبعا لما أنا أضغطه على
+
+314
+00:23:37,070 --> 00:23:41,050
+الآخر فالكتلة هذه بتتحركش بعديها بتتحركش فطاقة
+
+315
+00:23:41,050 --> 00:23:50,310
+الحركة للكتلة بيساوي Zeroفي C هنا لو انا ال spring
+
+316
+00:23:50,310 --> 00:23:55,450
+هذا او النعبد شدته او stretch يعني شدته فبكون انه
+
+317
+00:23:55,450 --> 00:24:01,430
+عند نقطة الاتزان بيكون تغطي الوضع تبعته بالسوء
+
+318
+00:24:01,430 --> 00:24:06,240
+zero لانه فلت فلت بعد ما انا كنت ضغطها فلتهلما
+
+319
+00:24:06,240 --> 00:24:12,180
+فلته الكتلة هاي تتحرك بسرعة V وبالتالي لها طاقة
+
+320
+00:24:12,180 --> 00:24:18,100
+حركة نص K نص MV تربيع هنا لما يوصل لمنطقة الإتزان
+
+321
+00:24:18,100 --> 00:24:21,780
+بتكون B potential energy ل ال sprint بالساوة Zero
+
+322
+00:24:21,780 --> 00:24:26,560
+وهنا الكتلة تبدأ بأقصى سرعة لها و بأقصى طاقة وضعها
+
+323
+00:24:27,190 --> 00:24:32,130
+لو أنا أشد الـspring مسافة معينة للآخر بتكون طاقة
+
+324
+00:24:32,130 --> 00:24:35,870
+الوضع للـspring برضه نص K X تربيع وطاقة الحركة
+
+325
+00:24:35,870 --> 00:24:40,150
+بتساوي Zero لكن هذه المرحلة لما احنا كان مضغوط
+
+326
+00:24:40,150 --> 00:24:45,020
+الـspring و تركناطبعا هذا الشكل بيوضح كيف ال
+
+327
+00:24:45,020 --> 00:24:49,460
+spring ممكن يكون stretched أو .. او اللي هي
+
+328
+00:24:49,460 --> 00:24:53,600
+compressed هذا ال figure بيوضح ال spring in its
+
+329
+00:24:53,600 --> 00:24:56,420
+equilibrium position where the spring is neither
+
+330
+00:24:56,420 --> 00:25:00,640
+compressed or يعني ممكن ال spring هذا النبض ممكن
+
+331
+00:25:00,640 --> 00:25:04,830
+يكون مضغوط أو مشدودpushing block against spring as
+
+332
+00:25:04,830 --> 00:25:08,310
+figure طبعا زى ما هو مضح فى الشكل خمسة واحد وعشر
+
+333
+00:25:08,310 --> 00:25:11,510
+بيه compressed تبقى distance X ده distance X
+
+334
+00:25:11,510 --> 00:25:14,050
+represent the magnitude of the displacement for
+
+335
+00:25:14,050 --> 00:25:18,010
+the equilibrium position بيسموها اللى هى قيمة
+
+336
+00:25:18,010 --> 00:25:21,570
+الإزاحة اللى ال spring أو النابض هوطبعاً يا إما
+
+337
+00:25:21,570 --> 00:25:25,910
+بيكون مضغوط أو مشدود ال X بيساوي Zero في حالة ال
+
+338
+00:25:25,910 --> 00:25:31,250
+equilibrium position وبالتالي طالما أنه أو أنا
+
+339
+00:25:31,250 --> 00:25:36,050
+ضغطاه أو شداه واحنا شدينه أو ضغطينه بيكون عندي أنا
+
+340
+00:25:36,050 --> 00:25:40,670
+الإزاحة عكس القوة وبالتالي في عندي أنا قوة داخل ال
+
+341
+00:25:40,670 --> 00:25:46,310
+spring بيسموها ال AFS Spring Force بتساوي ناقص KX
+
+342
+00:25:47,260 --> 00:25:50,480
+طبعا ال X هو عبارة عن المسافة اللي ال spring
+
+343
+00:25:50,480 --> 00:25:54,460
+انضغطها أو انشدها و ال K بيسموها constant
+
+344
+00:25:54,460 --> 00:26:00,080
+proportionality ثابت التناسب ل ال spring constant
+
+345
+00:26:00,080 --> 00:26:03,580
+طبعا carrying unit of a Newton's perimeter لإن ال
+
+346
+00:26:03,580 --> 00:26:12,040
+K هذه واحدتها Newton per meter حسب القانون الموجود
+
+347
+00:26:12,040 --> 00:26:15,100
+هذا بسميه Hooke's law هذا المعادلة بسميها قانون
+
+348
+00:26:15,100 --> 00:26:19,410
+Hookeالقوة fs is often called بيسموها restoring
+
+349
+00:26:19,410 --> 00:26:23,610
+force for positive value of x the force is
+
+350
+00:26:23,610 --> 00:26:29,070
+negative لما تكون ال x موجبة بتكون ال fs negative
+
+351
+00:26:29,070 --> 00:26:32,890
+pointing back towards equilibrium at x بالساوة 0
+
+352
+00:26:32,890 --> 00:26:36,190
+and for negative x the force لما تكون ال x بالساوة
+
+353
+00:26:36,190 --> 00:26:41,580
+سالبة القوة بتكون موجبةagain pointing towards x
+
+354
+00:26:41,580 --> 00:26:45,240
+بالساوية 0 the minus sign طبعا الإشارة السالية
+
+355
+00:26:45,240 --> 00:26:49,240
+بمعناها إنه هي قوة ال spring أو قوة النعبة دايما
+
+356
+00:26:49,240 --> 00:26:53,060
+بتكون directed back towards the equilibrium point
+
+357
+00:26:53,060 --> 00:26:58,180
+دايما بتكون ال spring force is always directed
+
+358
+00:26:58,180 --> 00:27:01,440
+back towards the equilibrium point بتكون دايما
+
+359
+00:27:01,440 --> 00:27:05,850
+راجعة نقطة الإتزانas in the case of the
+
+360
+00:27:05,850 --> 00:27:09,750
+gravitation برضه نفس ما احنا شرحنا بالنسبة لـ
+
+361
+00:27:09,750 --> 00:27:14,530
+gravitation أو potential energy أو اللي هو بيسموها
+
+362
+00:27:14,530 --> 00:27:17,110
+الـ elastic potential energy طاقة الوضع المرنية
+
+363
+00:27:17,110 --> 00:27:19,870
+المخزونة داخل ال spring هي تعتبر conservative
+
+364
+00:27:19,870 --> 00:27:22,450
+force can be associated with the spring force
+
+365
+00:27:22,450 --> 00:27:25,490
+elastic potential energy is another way of looking
+
+366
+00:27:25,490 --> 00:27:28,030
+at the work done by spring during motion because
+
+367
+00:27:28,030 --> 00:27:32,890
+it is equal to thenegative of the work done by the
+
+368
+00:27:32,890 --> 00:27:36,850
+spring طبعا ال elastic potential energy بيسموها
+
+369
+00:27:36,850 --> 00:27:41,090
+طاقة زي ما حكينا طاقة وضع مرونية مخزونة داخل ال
+
+370
+00:27:41,090 --> 00:27:44,250
+spring وهي طريقة تانية عشان انا ممكن احسب الشغل
+
+371
+00:27:44,250 --> 00:27:49,270
+المبدول بواسط ال spring وهذا بيسميها طبعا طاقة وضع
+
+372
+00:27:49,270 --> 00:27:54,080
+لكنها مرونيةبساعة و نص KX تربيع ممكن هي تكون
+
+373
+00:27:54,080 --> 00:27:58,480
+مخزونة داخل ال spring ال spring ممكن يعمل شغل اذا
+
+374
+00:27:58,480 --> 00:28:02,800
+انا شديته compress or stretch ممكن انا اذا كان ال
+
+375
+00:28:02,800 --> 00:28:08,280
+spring انا شديته او ضغطه بكون انا يعني بزلت شغل
+
+376
+00:28:08,280 --> 00:28:14,260
+فيه طبعا بنستكمل هذا ال .. هذه التسجيلات و هذا
+
+377
+00:28:14,260 --> 00:28:16,340
+الشرح في المحاضرة القادمة ان شاء الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/CcnVm4W23EM.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/CcnVm4W23EM.srt
new file mode 100644
index 0000000000000000000000000000000000000000..7a1c714847d405ce41b44d16846964d7607fc1d0
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/CcnVm4W23EM.srt
@@ -0,0 +1,1408 @@
+
+1
+00:00:00,560 --> 00:00:05,500
+بسم الله الرحمن الرحيم، بنستكمل طبعا بعض الأسئلة من
+
+2
+00:00:05,500 --> 00:00:09,080
+chapter.. الـchapter الثاني، السؤال اللي هو
+
+3
+00:00:09,080 --> 00:00:13,600
+example اتنين، أربعة، a race car starting from
+
+4
+00:00:13,600 --> 00:00:17,100
+rest, accelerates at a constant rate of five meters per
+
+5
+00:00:17,100 --> 00:00:20,640
+second squared، اللي إن في عندي أنا سيارة سباق بدأت
+
+6
+00:00:20,640 --> 00:00:27,000
+من السكون وaccelerates، صار إلها تسارع، اتسرعت بمعدل
+
+7
+00:00:27,000 --> 00:00:31,870
+ثابت بمعدل خمسة متر في الثانية تربيع. المطلوب: what is
+
+8
+00:00:31,870 --> 00:00:36,770
+the velocity of the car after it has traveled واحد
+
+9
+00:00:36,770 --> 00:00:40,670
+في عشرة أس اثنين feet؟ مطلوب مني أوجد اللي هي سرعة
+
+10
+00:00:40,670 --> 00:00:47,130
+السيارة بعد ما تمشي مسافة واحد في عشرة أس اثنين
+
+11
+00:00:47,130 --> 00:00:51,580
+feet. وبعدين طالب منا: how much time has elapsed
+
+12
+00:00:51,580 --> 00:00:54,800
+بدأ الزمن اللازم علشان هي تمشي هذه.. هذه المسافة.
+
+13
+00:00:54,800 --> 00:00:57,960
+و C: calculate the average velocity two different
+
+14
+00:00:57,960 --> 00:01:00,460
+ways. بدي أوجد الـaverage velocity، السرعة الاتجاهية
+
+15
+00:01:00,460 --> 00:01:05,020
+المتوسطة بطريقتين. الآن السر.. السؤال عندي أنا أنه
+
+16
+00:01:05,020 --> 00:01:09,020
+في عندي سيارة، سيارة سباق بدأت من rest، يعني السرعة
+
+17
+00:01:09,020 --> 00:01:12,620
+الابتدائية كانت zero، والـX الابتدائية كانت
+
+18
+00:01:12,620 --> 00:01:15,420
+باعتبرها zero. مطلوب مني أوجد السرعة النهائية، مطلوب
+
+19
+00:01:15,420 --> 00:01:20,360
+أوجد.. أوجد الزمن اللازم علشان تمشي مسافة واحد في
+
+20
+00:01:20,360 --> 00:01:25,020
+عشرة أس اثنين feet. طبعا في البداية لازم أحول أو
+
+21
+00:01:25,020 --> 00:01:31,240
+يعني أخلي الوحدات متجانسة أو زي بعض، توحيد الوحدات،
+
+22
+00:01:31,240 --> 00:01:36,540
+convert units of delta X، بدي أحول الـdelta X إلى
+
+23
+00:01:36,540 --> 00:01:41,250
+في النظام الدولي اللي هو system international. فـ
+
+24
+00:01:41,250 --> 00:01:46,210
+واحد في عشرة أس اثنين feet، قدم، بدي أحولها إلى
+
+25
+00:01:46,210 --> 00:01:51,110
+متر. طبعا الواحد متر بيساوي ثلاثة point اثنين
+
+26
+00:01:51,110 --> 00:01:54,870
+قدم، فمعنى الكلام الواحد في عشرة أس اثنين قدم ده
+
+27
+00:01:54,870 --> 00:01:59,950
+نقسمه على ثلاثة point اثنين، ثلاثة point اثنين
+
+28
+00:01:59,950 --> 00:02:03,650
+ثمانية قدم، بيطلع عندي ثلاثين و نصف متر. معنى الكلام
+
+29
+00:02:03,650 --> 00:02:09,860
+السيارة بدأت من السكون ومشت مسافة ثلاثين و نصف متر،
+
+30
+00:02:09,860 --> 00:02:14,020
+مطلوب مني السرعة النهائية، هستخدم القانون اللي طبعا
+
+31
+00:02:14,020 --> 00:02:17,780
+معروف زمان: V تربيع بتساوي V naught تربيع زائد اثنين A
+
+32
+00:02:17,780 --> 00:02:22,220
+Delta X. V naught سرعة ابتدائية، V naught هي سرعة ابتدائية، V
+
+33
+00:02:22,220 --> 00:02:26,000
+naught سرعة ابتدائية، والـA تسارع، Delta X اللي هي
+
+34
+00:02:26,000 --> 00:02:29,600
+المسافة اللي مشيتها. فـV naught بدأت من السكون إذا
+
+35
+00:02:29,600 --> 00:02:35,650
+zero. الـA أعطانيها خمسة، Delta X طلعناها ثلاثين و
+
+36
+00:02:35,650 --> 00:02:40,510
+نصف متر. فالجواب الـV النهائية سبعة عشر و نصف متر
+
+37
+00:02:40,510 --> 00:02:45,910
+في الثانية. نمر بـhow much time has elapsed؟ بدي
+
+38
+00:02:45,910 --> 00:02:50,650
+الزمن اللازم لكي تمشي هذه المسافة أو لكي تصل إلى
+
+39
+00:02:50,650 --> 00:02:54,710
+سرعة نهائية مقدارها 17.5. طبعا ممكن أستخدم أكثر من
+
+40
+00:02:54,710 --> 00:02:59,310
+القانون لأن هو طالب الزمن. الـV بتساوي V naught
+
+41
+00:02:59,310 --> 00:03:03,210
+زائد AT أو بتساوي AT زائد V naught. الـV هي السرعة
+
+42
+00:03:03,210 --> 00:03:06,990
+النهائية اللي إحنا طلعناها من المطلوب الأول، 17.5 متر
+
+43
+00:03:06,990 --> 00:03:11,210
+في الثانية. الـA هي عبارة عن خمسة، معطى متر في
+
+44
+00:03:11,210 --> 00:03:15,370
+الثانية تربيع. الـT مطلوبة، والـV naught عوضنا عنها بـ
+
+45
+00:03:15,370 --> 00:03:18,810
+zero لأنها بدأت من الـrest. إذن من خلال هذه
+
+46
+00:03:18,810 --> 00:03:22,930
+المعادلة، بقسم على خمسة وهنا على خمسة، بتطلع عندي T
+
+47
+00:03:22,930 --> 00:03:27,050
+سبعة عشر و نصف على خمسة متر في الثانية تربيع، بتطلع
+
+48
+00:03:27,050 --> 00:03:30,390
+عندي الزمن اللي استغرقته السيارة لتصل إلى سرعة
+
+49
+00:03:30,390 --> 00:03:34,890
+السبعة عشر و نصف، هو عبارة عن ثلاثة و نصف ثانية. في C:
+
+50
+00:03:34,890 --> 00:03:37,370
+Calculate the average velocity in two different
+
+51
+00:03:37,370 --> 00:03:41,290
+ways. مطلوب مني أوجد الـaverage velocity بطريقتين.
+
+52
+00:03:41,290 --> 00:03:44,670
+الطريقة الأولى إن أنا بتطبق القانون إن V average
+
+53
+00:03:44,670 --> 00:03:48,590
+بِتساوي Delta X على Delta T، أو X final ناقص X
+
+54
+00:03:48,590 --> 00:03:52,770
+initial على T final ناقص T initial. X initial كانت
+
+55
+00:03:52,770 --> 00:03:56,390
+Zero، وX final هي مشت مسافة ثلاثين و نصف. T initial
+
+56
+00:03:56,390 --> 00:04:00,470
+Zero، وT final كانت ثلاثة و نصف. هنا ثلاثين و نصف على
+
+57
+00:04:00,470 --> 00:04:04,350
+ثلاثة و نصف، بيطلع عندي 8.7 متر في الثانية، اللي هي الـ
+
+58
+00:04:04,350 --> 00:04:08,770
+average velocity، السرعة الاتجاهية المتوسطة. ممكن
+
+59
+00:04:08,770 --> 00:04:11,790
+أستخدم طريقة ثانية إنه احنا خدنا لو كان عندي أنا
+
+60
+00:04:11,790 --> 00:04:16,870
+سرعتين، سرعتين، وطلب مني متوسط السرعة لهذه السرعتين،
+
+61
+00:04:16,870 --> 00:04:21,530
+طبعا بنعمل مجموع السرعتين على اثنين. مجموع السرعتين
+
+62
+00:04:21,530 --> 00:04:26,170
+على اثنين. V naught كانت 0، وV النهائية 17.5 على اثنين، بيطلع
+
+63
+00:04:26,170 --> 00:04:31,870
+برضه الجواب 8.75، يعني قريب من الجواب الأولاني. هذه
+
+64
+00:04:31,870 --> 00:04:35,650
+هي الـaverage velocity بطريقتين. هيك السؤال الأول
+
+65
+00:04:35,650 --> 00:04:42,640
+اللي هو 2.4. نجي لسؤال ثاني، example 2.5: a car
+
+66
+00:04:42,640 --> 00:04:46,520
+traveling at a constant speed of 40 meters في الثانية.
+
+67
+00:04:46,520 --> 00:04:53,360
+في عندي سيارة ماشية بـconstant speed، بسرعة 40 متر
+
+68
+00:04:53,360 --> 00:04:57,280
+في الثانية. constant speed أخذناها سابقا: أي جسم
+
+69
+00:04:57,280 --> 00:05:00,160
+بتحرك بـconstant speed أو constant velocity،
+
+70
+00:05:00,160 --> 00:05:05,180
+فالتسارع بيساوي صفر. الآن، passes a trooper hidden
+
+71
+00:05:05,180 --> 00:05:09,560
+behind a billboard. هذه السيارة وهي ماشية بتسارع
+
+72
+00:05:09,560 --> 00:05:15,120
+طبعا zero، constant، بسرعة ثابتة، مشيت أو عدت على
+
+73
+00:05:15,120 --> 00:05:20,480
+شرطي كان موجود خلف لوحة إعلانات كما هو موضح بالشكل.
+
+74
+00:05:20,480 --> 00:05:26,450
+بعد ثانية، انتبه الشرطي أن السيارة عدت من أمامه. one
+
+75
+00:05:26,450 --> 00:05:30,510
+second after the speeding car passes the billboard،
+
+76
+00:05:30,510 --> 00:05:34,230
+بعد ثانية، الـtrooper اللي هو الشرطي، sits off in
+
+77
+00:05:34,230 --> 00:05:39,210
+pursuit with a constant acceleration. بعد ثانية الشرطي
+
+78
+00:05:39,210 --> 00:05:43,490
+بدأ يتحرك على أساس يلحق بالسيارة. طبعا الشرطي لكي
+
+79
+00:05:43,490 --> 00:05:49,430
+يلحق بالسيارة بدأ عنده يتسارع بتسارع ثابت مقداره
+
+80
+00:05:49,430 --> 00:05:54,160
+ثلاثة متر في الثانية تربيع. المطلوب: how long does it
+
+81
+00:05:54,160 --> 00:05:57,360
+take the trooper to overtake the speeding car؟
+
+82
+00:05:57,360 --> 00:06:01,360
+طبعا السيارة بتتحرك بـconstant speed، الشرطي بدأ
+
+83
+00:06:01,360 --> 00:06:07,120
+يتحرك بعد واحد ثانية، وبالتالي طالب مني كم الزمن
+
+84
+00:06:07,120 --> 00:06:11,600
+اللازم لكي يستطيع الشرطي يلحق، يلحق بمين؟ بالسيارة
+
+85
+00:06:11,600 --> 00:06:15,900
+اللي هي السيارة المسرعة. بدنا الزمن اللازم اللي بيخلي
+
+86
+00:06:15,900 --> 00:06:21,580
+الشرطي catch أو بيوصل للسيارة. زي ما هو موضح بالشكل،
+
+87
+00:06:21,580 --> 00:06:24,660
+هنا شرطي وراء اللي هي بالـpart اللي هي لوحة إعلانات،
+
+88
+00:06:24,660 --> 00:06:28,760
+السيارة ماشية بسرعة كبيرة لكنها constant speed،
+
+89
+00:06:28,760 --> 00:06:33,900
+الشرطي بعد ثانية بدأ يتحرك لغاية ما الشرطي مسك
+
+90
+00:06:33,900 --> 00:06:38,190
+السيارة عند المنطقة هذه. طبعا عشان أحل هذا السؤال،
+
+91
+00:06:38,190 --> 00:06:43,150
+solving this problem involves two simultaneous
+
+92
+00:06:43,150 --> 00:06:47,610
+equations of positions. عشان أحل هذا السؤال محتاج
+
+93
+00:06:47,610 --> 00:06:53,150
+اللي هي أنا معادلتين، one for the trooper، معادلة
+
+94
+00:06:53,150 --> 00:06:57,540
+خاصة بالشرطي، معادلة خاصة بالسيارة. it shows t بتساوي
+
+95
+00:06:57,540 --> 00:07:00,940
+0.2 corresponds to the time that robert takes up the
+
+96
+00:07:00,940 --> 00:07:06,680
+gas when the car is at x car بتساوي 24 متر. الـX للـ
+
+97
+00:07:06,680 --> 00:07:12,440
+car كانت 24، و نُقِشت الـ24 لإنه its head start، هو
+
+98
+00:07:12,440 --> 00:07:17,490
+بدأ بسرعة 24 متر في الثانية، لكل ثانية. وبالتالي من
+
+99
+00:07:17,490 --> 00:07:21,950
+هذه العلاقة بِستطيع إيجاد اللي هي الـX للـcar، الـX
+
+100
+00:07:21,950 --> 00:07:26,370
+للـcar اللي هي عبارة عن الـV في T. فبيطلع الـX من
+
+101
+00:07:26,370 --> 00:07:31,410
+خلال إنه حكى لإنه هي بتتحرك بمعدل 24 متر في ثانية
+
+102
+00:07:31,410 --> 00:07:34,790
+لكل ثانية. إذا الـX للـcar، مسافة اللي مشيتها
+
+103
+00:07:34,790 --> 00:07:39,560
+السيارة 24 متر. the trooper catches up، اللي هو الشرطي
+
+104
+00:07:39,560 --> 00:07:44,000
+يمسك السيارة when.. when their positions are the
+
+105
+00:07:44,000 --> 00:07:47,840
+same. طبعا لما هم ماشيين نفس المسافة. إذا الشيء
+
+106
+00:07:47,840 --> 00:07:52,540
+المشترك بين الـtrooper وبين السيارة اللي هو الـX،
+
+107
+00:07:52,540 --> 00:07:55,860
+المسافة، مشتركة. بين الـX للـtrooper بيساوي الـX للـ
+
+108
+00:07:55,860 --> 00:07:59,980
+car. إذا بجيب الـX للـtrooper وبجيب الـX للـcar و
+
+109
+00:07:59,980 --> 00:08:07,350
+بحل المعادلتين عشان أوجد الزمن. الآن السؤال حل how
+
+110
+00:08:07,350 --> 00:08:09,990
+long does it take the trooper to overtake the car؟
+
+111
+00:08:09,990 --> 00:08:15,350
+كم الوقت اللازم؟ ما هو الوقت اللازم الذي يستغرقه
+
+112
+00:08:15,350 --> 00:08:19,950
+الشرطي للحق بالسيارة؟ بنكتب معادلة اللي هي
+
+113
+00:08:19,950 --> 00:08:24,450
+الإزاحة الخاصة بالسيارة، Delta X للـcar، بدها تساوي
+
+114
+00:08:24,450 --> 00:08:29,420
+X للـcar ناقص X naught. طبعا دلتا X بتساوي V naught T زائد
+
+115
+00:08:29,420 --> 00:08:34,740
+نصف A T تربيع. X naught هي مشت مسافة 24 متر في حالة ما
+
+116
+00:08:34,740 --> 00:08:39,120
+كانت تتحرك بمعدل 24 متر في الثانية لكل ثانية. هذه
+
+117
+00:08:39,120 --> 00:08:43,740
+بتعتبرها X naught. V naught اللي هي 24 متر في الثانية، الـ
+
+118
+00:08:43,740 --> 00:08:49,760
+A للـcar Zero لأنها اتحركت بـconstant speed. هنحل
+
+119
+00:08:49,760 --> 00:08:51,760
+هذه المعادلة. إذا X للـcar
+
+120
+00:09:00,240 --> 00:09:05,390
+هي معادلة الأولى الخاصة بالسيارة. هكتب معادلة ثانية
+
+121
+00:09:05,390 --> 00:09:09,670
+خاصة بالـtrooper الآن. trooper بدأ، أفرض أنه
+
+122
+00:09:09,670 --> 00:09:14,310
+بدأ x naught بتساوي 0، وv naught 0، والـa للـtrooper
+
+123
+00:09:14,310 --> 00:09:17,970
+كانت ثلاثة متر في الثانية تربيع. إذا x للـ
+
+124
+00:09:17,970 --> 00:09:22,050
+trooper بتساوي v naught t زائد نصف a t تربيع. v
+
+125
+00:09:22,050 --> 00:09:27,170
+naught بدأ من صفر، راحت، دلوقتي عندي نصف a t تربيع. الـa
+
+126
+00:09:27,170 --> 00:09:32,340
+كانت بتتحرك بيه تسارع ثابت مقداره ثلاثة. إذا النصف في
+
+127
+00:09:32,340 --> 00:09:37,160
+ثلاثة في T تربيع. بيطلع عندي معادلة برضه، معادلة فيها
+
+128
+00:09:37,160 --> 00:09:40,500
+T من الدرجة الثانية، اللي هي T تربيع. الآن عندي
+
+129
+00:09:40,500 --> 00:09:43,340
+معادلة أولى خاصة بالسيارة، معادلة ثانية خاصة
+
+130
+00:09:43,340 --> 00:09:46,340
+بالـtrooper. هساوي المعادلتين في بعض، لأن الـX للـcar
+
+131
+00:09:46,340 --> 00:09:50,000
+بِتساوي X للـtrooper. فبيطلع عندي واحد و نصف متر في
+
+132
+00:09:50,000 --> 00:09:53,520
+الثانية تربيع في T تربيع. اللي هي X للـtrooper بدها
+
+133
+00:09:53,520 --> 00:09:56,340
+تساوي أربعة وعشرين زائد أربعة وعشرين متر في
+
+134
+00:09:56,340 --> 00:10:00,160
+الثانية في T. صارت عندي معادلة من الدرجة الثانية.
+
+135
+00:10:01,470 --> 00:10:04,610
+المعادلة من الدرجة الثانية ممكن أحلها بواسطة اللي
+
+136
+00:10:04,610 --> 00:10:08,450
+هي حل المعادلة.. المعادلة هذه، أو بواسطة الـ..
+
+137
+00:10:08,450 --> 00:10:12,730
+طبعا اللي هي القانون العام، بحل، إيجاد الـT اللي
+
+138
+00:10:12,730 --> 00:10:16,710
+هي بتطلع عندي ستة عشر وتسعة من عشرة ثانية. هذا
+
+139
+00:10:16,710 --> 00:10:20,750
+الزمن اللازم لاقي الشرطة عشان إيه.. يعني catch أو
+
+140
+00:10:20,750 --> 00:10:24,360
+يعني يمسك في السيارة أو يلحق بالسيارة. بعد هي طالب
+
+141
+00:10:24,360 --> 00:10:27,480
+find the trooper's speed at that time. بدي السرعة
+
+142
+00:10:27,480 --> 00:10:31,320
+النهائية للـtrooper علشان يمسك في السيارة. فسرعة
+
+143
+00:10:31,320 --> 00:10:35,480
+النهائية هحكي: سرعة النهائية بدها تساوي V naught
+
+144
+00:10:35,480 --> 00:10:41,620
+زائد AT. طبعا V naught كانت zero للـtrooper، الـA كانت
+
+145
+00:10:41,620 --> 00:10:47,020
+ثلاثة، والـT طلعناها 16.9، بتطلع V النهائية للـtrooper
+
+146
+00:10:47,020 --> 00:10:50,760
+بدها تساوي 50.7 متر في الثانية.
+
+147
+00:10:54,260 --> 00:11:02,640
+example 2.6، example 2.6، حكالي: typical jet liner..
+
+148
+00:11:02,640 --> 00:11:08,680
+liner.. linear، lands at a speed of، طبعا الطيارة بدها
+
+149
+00:11:08,680 --> 00:11:16,620
+تهبط بسرعة 1.6 في 10 أس اثنين ميل في الساعة. and
+
+150
+00:11:16,620 --> 00:11:20,600
+accelerates at a rate of، عشرة ميل في الساعة لكل ثانية.
+
+151
+00:11:20,600 --> 00:11:25,540
+طبعا الطيارة عندما تهبط تبدأ بسرعة كبيرة وبعد هيك
+
+152
+00:11:25,540 --> 00:11:31,020
+تبدأ تتباطأ لغاية ما تقف. فهي بدأت بسرعة، طبعا هبطت
+
+153
+00:11:31,020 --> 00:11:33,560
+بسرعة واحد point ستة في عشرة أس اثنين ميل في
+
+154
+00:11:33,560 --> 00:11:38,920
+الساعة، بدأت تتباطأ بمعدل عشرة ميل في الساعة لكل
+
+155
+00:11:38,920 --> 00:11:44,150
+ثانية. بيحكي لي السؤال: if the plane، إذا كانت الطيارة
+
+156
+00:11:44,150 --> 00:11:48,950
+هذه travels at a constant speed، 1.6×10² miles في
+
+157
+00:11:48,950 --> 00:11:56,230
+الساعة. طبعا هي مشيت بسرعة constant speed، 1.6 يعني
+
+158
+00:11:56,230 --> 00:12:00,720
+سرعة ثابتة، معناته التسارع zero. 1.6 في 10 أس 2 ميل
+
+159
+00:12:00,720 --> 00:12:04,460
+في الساعة for one second after landing before
+
+160
+00:12:04,460 --> 00:12:08,600
+applying the brakes. طبعا بعد ما هي هبطت قبل ما
+
+161
+00:12:08,600 --> 00:12:15,200
+إنها تستخدم اللي هي الـbrake، اللي هي الـstop أو
+
+162
+00:12:15,200 --> 00:12:19,480
+القفّة، الطائرة. what is the total displacement of
+
+163
+00:12:19,480 --> 00:12:23,200
+the aircraft between touchdown on the runway and
+
+164
+00:12:23,200 --> 00:12:28,760
+coming to rest. بده الإزاحة الكلية للـaircraft،
+
+165
+00:12:28,760 --> 00:12:33,520
+اللي هي الطائرة، between، بالفترة من إنها مجرد ما
+
+166
+00:12:33,520 --> 00:12:40,670
+لمست أرض اللي هي المطار أو المدرج، on the runway and
+
+167
+00:12:40,670 --> 00:12:45,130
+coming، من مجرد ما هبطت الطائرة ولمست أرض المدرج أو
+
+168
+00:12:45,130 --> 00:12:50,610
+أرض المطار حتى تقف. هذا هو المطلوب، دول مسافة اللي
+
+169
+00:12:50,610 --> 00:12:55,950
+مشيتها الطائرة من مجرد ما إنها هبطت حتى وقفت. طبعا
+
+170
+00:12:55,950 --> 00:13:00,870
+هنا في عندي أنا بدأت من الـV، هي الـorigin، الحركة
+
+171
+00:13:00
+
+223
+00:17:15,700 --> 00:17:21,520
+المرحلة الثانية لغاية ما هي بتتباطأ حتى تقف، نجمع
+
+224
+00:17:21,520 --> 00:17:25,780
+الـ Delta X الأولى زي الـ Delta X الثانية، بتطلع عندي 644
+
+225
+00:17:25,780 --> 00:17:30,280
+متر، هي عبارة عن المسافة الكلية للمرحلة الأولى، و
+
+226
+00:17:30,280 --> 00:17:37,470
+المرحلة الثانية. طبعًا، section جديد 2.4 free
+
+227
+00:17:37,470 --> 00:17:43,650
+-falling object، اللي هو السقوط الحر للأجسام، when
+
+228
+00:17:43,650 --> 00:17:47,070
+air resistance is negligible. طبعًا، الآن هذا الدرس
+
+229
+00:17:47,070 --> 00:17:50,770
+احنا بدنا نعتبر أن مقاومة الهواء، طبعًا احنا بدنا
+
+230
+00:17:50,770 --> 00:17:55,400
+نهملها. All objects dropped under the influence of
+
+231
+00:17:55,400 --> 00:17:58,380
+gravity near Earth's surface fall towards Earth with
+
+232
+00:17:58,380 --> 00:18:01,880
+the same constant acceleration. المعنى أن معظم
+
+233
+00:18:01,880 --> 00:18:07,540
+الأجسام تسقط تحت تأثير الجاذبية الأرضية، طبعًا
+
+234
+00:18:07,540 --> 00:18:11,100
+باتجاه الأرض بنفس الـ constant acceleration، بنفس
+
+235
+00:18:11,100 --> 00:18:15,160
+التسارع. معنى الكلام: جميع الأجسام تسقط بفعل
+
+236
+00:18:15,160 --> 00:18:19,640
+الجاذبية الأرضية، وهي طبعًا مقدار ثابت لجميع الأجسام.
+
+237
+00:18:20,380 --> 00:18:23,640
+The expression "freely falling object" does not
+
+238
+00:18:23,640 --> 00:18:26,700
+necessarily refer to an object dropped from rest.
+
+239
+00:18:26,700 --> 00:18:31,660
+مش من الضروري أن أي جسم يسقط سقوطًا من الـ rest، يعني
+
+240
+00:18:31,660 --> 00:18:35,920
+ممكن أنا أبدأ السؤال بقول: جسم أنا أسقطه بسرعة كذا،
+
+241
+00:18:35,920 --> 00:18:40,180
+يعني، وممكن أنه أحكي أن أي جسم سقط من الـ rest،
+
+242
+00:18:40,180 --> 00:18:44,670
+معناته V0 = 0. Free falling object is any
+
+243
+00:18:44,670 --> 00:18:48,390
+object moving freely under the influence of
+
+244
+00:18:48,390 --> 00:18:54,090
+gravity alone, regardless of its initial motion. الـ
+
+245
+00:18:54,090 --> 00:18:58,670
+free falling، أنه لأي جسم، معناته أن أي جسم بيتحرك
+
+246
+00:18:58,670 --> 00:19:05,550
+بحرية تحت تأثير الجاذبية الأرضية. الـ objects down، ده
+
+247
+00:19:05,550 --> 00:19:08,970
+thrown upward or downward، يعني لو أنا رميت الجسم
+
+248
+00:19:08,970 --> 00:19:14,370
+لأعلى أو لأسفل بخط مستقيم، طبعًا، فبحكي أنه بيتحرك
+
+249
+00:19:14,370 --> 00:19:19,470
+حركة free falling، حركة سقوط حر، وليس أنه يكون ساقط
+
+250
+00:19:19,470 --> 00:19:22,290
+من أعلى إلى أسفل. ممكن أنا أرمي حجر إلى أعلى أو
+
+251
+00:19:22,290 --> 00:19:27,170
+أرمي حجر من أعلى إلى أسفل. And those released from
+
+252
+00:19:27,170 --> 00:19:31,850
+rest are all considered freely falling. ممكن نعتبر
+
+253
+00:19:31,850 --> 00:19:35,250
+أي جسم بدأ released أو سقط. كلمة released معناته
+
+254
+00:19:35,250 --> 00:19:39,290
+بالابتدائية صفر. كلمة جسم بدأ من الـ rest معناته
+
+255
+00:19:39,290 --> 00:19:42,840
+السرعة الابتدائية = 0. We denote the
+
+256
+00:19:42,840 --> 00:19:45,440
+magnitude of the freely falling acceleration. طبعًا،
+
+257
+00:19:45,440 --> 00:19:49,400
+بالنسبة للتسارع الخاص بالـ free falling، هنرمز له
+
+258
+00:19:49,400 --> 00:19:53,400
+بالرمز G، اللي هو acceleration of gravity. The value
+
+259
+00:19:53,400 --> 00:19:59,700
+of G decreases. قيمة الـ G هذه ممكن تزيد أو تقل حسب
+
+260
+00:19:59,700 --> 00:20:02,440
+اللي هو الـ altitude، الارتفاع. كلمة altitude يعني
+
+261
+00:20:02,440 --> 00:20:06,890
+ارتفاع، ارتفاعات شاهقة عالية جدًا. At Earth's surface
+
+262
+00:20:06,890 --> 00:20:11,510
+على سطح الأرض، the value of G is approximately 9.8
+
+263
+00:20:11,510 --> 00:20:15,730
+على سطح الأرض، فاللي هي التسارع الجاذبية بده يساوي
+
+264
+00:20:15,730 --> 00:20:18,470
+تقريبًا تسعة وثمانية من عشرة متر في الثانية تربيع.
+
+265
+00:20:18,470 --> 00:20:22,330
+If we neglect air resistance، لو أنا أهملت مقاومة
+
+266
+00:20:22,330 --> 00:20:28,440
+الهواء، and assume that the free fall acceleration
+
+267
+00:20:28,440 --> 00:20:31,540
+does not vary with altitude over the short
+
+268
+00:20:31,540 --> 00:20:36,600
+vertical distance، بدي أنا يعني أهمل مقاومة الهواء،
+
+269
+00:20:36,600 --> 00:20:42,640
+واعتبر أنه التسارع لأي جسم يسقط سقوطًا حرًا does not
+
+270
+00:20:42,640 --> 00:20:46,560
+vary، مش هيختلف من مكان لمكان على سطح الأرض إذا كان
+
+271
+00:20:46,560 --> 00:20:51,360
+الارتفاع، طبعًا، ارتفاعات قصيرة وليس شاهقة، then the
+
+272
+00:20:51,360 --> 00:20:54,520
+motion of the freely falling object is the same as
+
+273
+00:20:54,520 --> 00:20:56,640
+the motion in one dimension under constant
+
+274
+00:20:56,640 --> 00:21:02,820
+acceleration. فالسقوط الحر بيمثل حركة في خط مستقيم
+
+275
+00:21:03,890 --> 00:21:07,290
+بتسارع ثابت، اللي هي الـ G، ولكن اتجاه التسارع هذا
+
+276
+00:21:07,290 --> 00:21:12,550
+بيكون إلى أسفل. ممكن أعتبر أنا الحركة اللي بتميز
+
+277
+00:21:12,550 --> 00:21:16,330
+بالموجب أو السالب. إذا أنا رميت الحجر إلى أعلى، إذا أنا
+
+278
+00:21:16,330 --> 00:21:20,590
+رميت الحجر إلى أعلى (up)، بيكون الـ Y (الإزاحة) موجبة.
+
+279
+00:21:20,590 --> 00:21:24,390
+إذا رميت الحجر إلى أسفل، أو الـ ball، أو أي جسم إلى
+
+280
+00:21:24,390 --> 00:21:30,550
+أسفل، بيكون الإزاحة سالبة. بالإضافة لأن الـ A، الـ A اللي
+
+281
+00:21:30,550 --> 00:21:33,630
+هي عبارة بتساوي ناقص G، اللي هي تسارع الجاذبية،
+
+282
+00:21:33,630 --> 00:21:38,450
+بتساوي G، واتجاهها إلى أسفل، أو سالب تسعة وثمانية من
+
+283
+00:21:38,450 --> 00:21:44,470
+عشرة متر في الثانية تربيع. ناخد لهذا الـ quiz، tennis
+
+284
+00:21:44,470 --> 00:21:49,830
+player on serve tosses a ball straight up. لاعب تنس
+
+285
+00:21:49,830 --> 00:21:53,570
+رمى كرة بخط مستقيم. While the ball is in free
+
+286
+00:21:53,570 --> 00:21:58,670
+fall، طبعًا الـ ball، الكرة هذه كأنها بدنا نتعامل
+
+287
+00:21:58,670 --> 00:22:02,510
+معاها إنها سقوط حر. Thus its acceleration، الآن هل
+
+288
+00:22:02,510 --> 00:22:08,560
+التسارع؟ هل التسارع بيزيد (increase) أو يقل (decrease) أو
+
+289
+00:22:08,560 --> 00:22:11,200
+يزيد ثم يقل (increase and then decrease) أو يقل ثم يزيد (decrease and then
+
+290
+00:22:11,200 --> 00:22:17,080
+increase) أو يبقى ثابتًا (remain constant)؟ اتفقنا، أي جسم بيتحرك
+
+291
+00:22:17,080 --> 00:22:21,690
+حركة free falling، حركة free falling، يعني ممكن أرمي
+
+292
+00:22:21,690 --> 00:22:25,210
+الحجر من أسفل إلى أعلى أو من أعلى إلى أسفل، بسميها
+
+293
+00:22:25,210 --> 00:22:29,230
+free falling. الـ free falling هي حركة الجسم في خط
+
+294
+00:22:29,230 --> 00:22:33,550
+مستقيم في بعد واحد، في خط مستقيم رأسي، تسمى free
+
+295
+00:22:33,550 --> 00:22:38,450
+falling. طبعًا، في الـ free falling بصفة عامة هو
+
+296
+00:22:38,450 --> 00:22:42,190
+بيتحرك بتسارع منتظم، هو تسارع الجاذبية. أي جسم بيتحرك
+
+297
+00:22:42,700 --> 00:22:46,260
+free falling، فهو بيتحرك بـ constant acceleration، و
+
+298
+00:22:46,260 --> 00:22:50,360
+معنى الكلام أنه الجواب هو إيه؟ بيتحرك الجسم with
+
+299
+00:22:50,360 --> 00:22:56,330
+remain acceleration، بيتحرك بتسارع ثابت. الكوز الثاني،
+
+300
+00:22:56,330 --> 00:23:01,230
+الآن، at the tennis ball of a quick quiz in، السؤال
+
+301
+00:23:01,230 --> 00:23:05,850
+السابق اللي هي كرة التنس، travel through the air،
+
+302
+00:23:05,850 --> 00:23:09,310
+طبعًا احنا، كرة التنس كأنها في السؤال اللي قبله،
+
+303
+00:23:09,310 --> 00:23:13,550
+اتفقنا أنه هي اتحركت حركة free falling، قدفناها إلى
+
+304
+00:23:13,550 --> 00:23:17,160
+أعلى. Travel through the air، مشيت خلال الهواء، does
+
+305
+00:23:17,160 --> 00:23:22,380
+it's speed؟ هل سرعتها.. هل سرعتها increase؟ هل
+
+306
+00:23:22,380 --> 00:23:27,820
+سرعتها زادت؟ هل سرعتها decrease؟ هل سرعتها decrease
+
+307
+00:23:27,820 --> 00:23:31,900
+and then increase؟ يعني هل سرعتها قلت بعدين زادت؟ هل
+
+308
+00:23:31,900 --> 00:23:36,080
+سرعتها increase، يعني زادت، and then بعدين قلت؟ Or
+
+309
+00:23:36,080 --> 00:23:41,350
+remain at the same؟ لإن احنا رمينا كرة إلى أعلى، طبعًا
+
+310
+00:23:41,350 --> 00:23:46,370
+لما توصل الكورة أعلى، أو أعلى ارتفاع، أو maximum
+
+311
+00:23:46,370 --> 00:23:49,810
+height، عند أقصى ارتفاع، معنى الكلام سرعتها هتكون
+
+312
+00:23:49,810 --> 00:23:55,010
+صفر. إذا الكورة الآن، لما أنا رميتها من الأرض إلى
+
+313
+00:23:55,010 --> 00:23:59,710
+أعلى، سرعتها بتقل لغاية ما توصل صفر، وبعدين سرعتها
+
+314
+00:23:59,710 --> 00:24:03,790
+بترجع، لما ترجع على الأرض بتزيد. فمعنى الكلام، الـ
+
+315
+00:24:03,790 --> 00:24:07,890
+answer اللي هو C. الآن الكرة، decrease، تبدأ سرعتها
+
+316
+00:24:07,890 --> 00:24:12,910
+تقل لغاية ما توصل أعلى، أو أقصى ارتفاع، and then
+
+317
+00:24:12,910 --> 00:24:16,630
+increase، وبعدين بتزيد، لإنها بتوصل أقصى ارتفاع،
+
+318
+00:24:16,630 --> 00:24:22,330
+بتكون V باتجاه الـ Y = 0، وبعدين بترجع على الأرض بسرعة
+
+319
+00:24:22,330 --> 00:24:26,450
+كبيرة. طبعًا، قبل ما تصدم في الأرض بيكون سرعتها أعلى
+
+320
+00:24:26,450 --> 00:24:30,050
+ما يمكن أن هي نفس السرعة اللي أنا رميت الكرة فيها،
+
+321
+00:24:30,050 --> 00:24:34,340
+وبالتالي هي decrease and then increase. Decrease and
+
+322
+00:24:34,340 --> 00:24:39,580
+then increase. A skydiver jumps out of the
+
+323
+00:24:39,580 --> 00:24:47,660
+hovering helicopter. في عندي طبعًا رجل بده يقفز من
+
+324
+00:24:47,660 --> 00:24:52,540
+helicopter. A few seconds later, another skydiver
+
+325
+00:24:52,540 --> 00:24:56,400
+jumps out, so they both fall along the same
+
+326
+00:24:56,400 --> 00:25:00,900
+vertical line. في عندي أنا رجلين بدهم يقفزوا من
+
+327
+00:25:00,900 --> 00:25:08,710
+الطائرة. الأولاني قفز، وبعد فترة معينة، بعد ثانية، قفز
+
+328
+00:25:08,710 --> 00:25:12,310
+الثاني. الثاني مشوا نفس الـ vertical line،
+
+329
+00:25:15,920 --> 00:25:20,040
+relative to the helicopter. Assume both skydivers
+
+330
+00:25:20,040 --> 00:25:24,100
+fall with the same acceleration. طبعًا، طالما أنه
+
+331
+00:25:24,100 --> 00:25:29,220
+الرجلين قفزوا من الطائرة أو الهليكوبتر، قفزوا،
+
+332
+00:25:29,220 --> 00:25:32,260
+وطبعًا هم، هي بعد ما يقفزوا هيتحركوا حركة أفقية،
+
+333
+00:25:32,260 --> 00:25:37,080
+كإنها مقذوفة، وبالتالي هيتحركوا بنفس التسارع. الآن
+
+334
+00:25:37,080 --> 00:25:39,840
+السؤال: Does the vertical distance between them
+
+335
+00:25:39,840 --> 00:25:46,920
+الآن، اللي هي المسافة اللي هي الرأسية بينهم، increase؟
+
+336
+00:25:46,920 --> 00:25:52,260
+ولا decrease؟ ولا stay the same؟ ولا إيه؟ هي بالحد
+
+337
+00:25:52,260 --> 00:25:57,300
+هنا، طبعًا بالنسبة له، اللي هي with the same
+
+338
+00:25:57,300 --> 00:26:00,080
+acceleration. Thus the vertical distance، هل المسافة
+
+339
+00:26:00,080 --> 00:26:05,480
+الرأسية بينهم increase، هتزيد؟ ولا هتقل؟ ولا هتضل زي
+
+340
+00:26:05,480 --> 0:26:10,360
+ما هي؟ الآن، طالما أن واحد قفز قبل الثاني بزمن قدر واحد
+
+341
+00:26:10,360 --> 00:26:14,540
+ثانية، معنى الكلام المسافة بين الاثنين هتكون
+
+342
+00:26:14,540 --> 00:26:18,900
+increase. السؤال الثاني: Does the difference in their
+
+343
+00:26:18,900 --> 00:26:23,620
+velocity؟ الآن الفرق بسرعتهم، الفرق في السرعات،
+
+344
+00:26:23,620 --> 00:26:27,160
+الآن هما الاثنين نزلوا بنفس التسارع، نزلوا بنفس
+
+345
+00:26:27,160 --> 00:26:31,600
+التسارع، وبدأوا، طبعًا احنا هنعتبرها بدأوا من الـ rest،
+
+346
+00:26:31,600 --> 00:26:35,620
+ونزلوا بنفس التسارع، فمعنى الكلام أن هما الاثنين
+
+347
+00:26:35,620 --> 00:26:40,380
+هينزلوا بنفس السرعة، الاثنين هينزلوا بنفس السرعة،
+
+348
+00:26:40,380 --> 00:26:45,260
+لإن سرعتهم stay the same، هينزلوا بنفس السرعة هما
+
+349
+00:26:45,260 --> 00:26:45,680
+الاثنين.
+
+350
+00:26:48,660 --> 00:26:54,460
+طبعًا هذا تفسير لشرح السؤال. الجسم الأول بالنسبة
+
+351
+00:26:54,460 --> 00:26:58,060
+للثاني، مين بده يفوت الثاني، مين بيفوت الثاني، أو كده،
+
+352
+00:26:58,060 --> 00:27:02,760
+بنحكي أن الجسم الأول متقدم في الزمن عن الثاني. احنا
+
+353
+00:27:02,760 --> 00:27:07,210
+حكينا أن الثاني بدأ يقفز بعد one second. التغير في
+
+354
+00:27:07,210 --> 00:27:10,530
+موضعه خلال نفس الفترة الزمنية بيكون أكبر مقارنة
+
+355
+00:27:10,530 --> 00:27:15,230
+بالجسم الثاني. لذلك فإن المسافة بين الجسمين تزداد
+
+356
+00:27:15,230 --> 00:27:19,890
+مع مرور الزمن. بالنسبة للسؤال الثاني، إن هم هما نزلوا
+
+357
+00:27:19,890 --> 00:27:25,430
+بنفس السرعة، فإن بالنسبة للسرعة فإن معدل تغير السرعة
+
+358
+00:27:25,430 --> 00:27:30,470
+لكل الجسمين ثابت مع الزمن. أي أن الفرق بين سرعتين
+
+359
+00:27:30,470 --> 00:27:34,970
+هما، تبقى ثابتة مع مرور الزمن، لإن التسارع تبعهم
+
+360
+00:27:34,970 --> 00:27:41,940
+بيتحركوا بتسارع الجاذبية. اللي هيكون سؤال.. كمان
+
+361
+00:27:41,940 --> 00:27:46,140
+سؤال بالنسبة لهذا الـ chapter، إن شاء الله. في عندي
+
+362
+00:27:46,140 --> 00:27:52,600
+سؤال، problem 28: Paul is thrown from the top of the
+
+363
+00:27:52,600 --> 00:27:56,740
+building. رميت أنا كرة من أعلى مبنى، with initial
+
+364
+00:27:56,740 --> 00:28:01,260
+velocity 20 متر في الثانية straight upward. أنا
+
+365
+00:28:01,260 --> 00:28:07,330
+رميتها من أعلى مبنى. المبنى طبعًا كان طوله خمسين، وقفت
+
+366
+00:28:07,330 --> 00:28:10,750
+على حافة المبنى، ورميت كرة بسرعة عشرين متر في
+
+367
+00:28:10,750 --> 00:28:14,790
+الثانية above the ground. طبعًا هذه الخمسين متر
+
+368
+00:28:14,790 --> 00:28:17,870
+المبنى.. بعد المبنى بالنسبة لي للأرض، يعني مبنى
+
+369
+00:28:17,870 --> 00:28:23,720
+ارتفاعه خمسين متر، ووقف شخص، رمى الكرة من عن
+
+370
+00:28:23,720 --> 00:28:27,220
+ارتفاع خمسين متر، وكان سرعتها.. سرعة هذه الكرة
+
+371
+00:28:27,220 --> 00:28:32,240
+عشرين متر في الثانية. Paul فقط نزل الكرة وهي
+
+372
+00:28:32,240 --> 00:28:39,780
+نازلة. الكرة وصلت لنفس مستوى حافة المبنى، كما هو مبين
+
+373
+00:28:39,780 --> 00:28:42,780
+في الشكل، هنشوفه الآن. Let's find the time needed
+
+374
+00:28:42,780 --> 00:28:45,300
+for the ball to reach its maximum height. بده الزمن
+
+375
+00:28:45,300 --> 00:28:49,880
+اللازم عشان تصل الكرة إلى أقصى ارتفاع، و بده الـ
+
+376
+00:28:49,880 --> 00:28:54,320
+maximum height، و بده الزمن اللازم عشان ترجع لمستوى
+
+377
+00:28:54,320 --> 00:28:57,680
+المبنى.
+
+378
+00:28:57,680 --> 00:29:04,080
+الآن عندي أنا الشكل، الشكل في عندي y naught = 0،
+
+379
+00:29:04,080 --> 00:29:09,540
+اللي أنا على حافة المبنى، بعتبر y naught = 0، والـ
+
+380
+00:29:09,540 --> 00:29:14,100
+Y بزيادة في upward، هنكتب المعادلات هي الشكل المبين
+
+381
+00:29:14,100 --> 00:29:17,950
+بهذا الشكل، هي، هي الشكل اللي عندنا.
+
+382
+00:29:52,560 --> 00:29:57,680
+الشكل هي زي هو موضح، هذا المبنى ارتفاعه خمسين متر،
+
+383
+00:29:57,680 --> 00:30:02,460
+هي الشخص هنا يقف في هذا المكان، على حافة المبنى طبعًا،
+
+384
+00:30:02,460 --> 00:30:07,220
+رمى الكرة بسرعة عشرين متر في الثانية، وصلت أقصى
+
+385
+00:30:07,220 --> 00:30:12,420
+ارتفاع، ونزلت للمنطقة هذه، المستوى اللي بطلبه طبعًا،
+
+386
+00:30:12,420 --> 00:30:16,500
+المستوى هذا، الإزاحة الكلية الـ Y = 0، لإن
+
+387
+00:30:16,500 --> 00:30:19,520
+أنا روحت مسافة ورجعت على نفس المستوى، فالإزاحة
+
+388
+00:30:19,520 --> 00:30:24,200
+الكلية = 0. في المنطقة هذه بتكون برضه
+
+389
+00:30:24,200 --> 00:30:27,600
+السرعة، بنزل أنا بنفس السرعة، بس باتجاه الـ minus،
+
+390
+00:30:27,600 --> 00:30:34,420
+لإن هو طالب.. طالب الزمن اللازم لكي يصل أقصى
+
+391
+00:30:34,420 --> 00:30:39,820
+ارتفاع. الزمن اللازم لأقصى ارتفاع، نجي نحل، find the
+
+392
+00:30:39,820 --> 00:30:42,560
+time when the ball reach maximum height. Maximum
+
+393
+00:30:42,560 --> 00:30:46,460
+height، معناته V النهائية = 0. إذا V = V naught + AT، وهستخدم Delta Y =
+
+394
+00:30:46,460 --> 00:30:50,740
+= Y - Y naught = V naught T + نص AT تربيع، وهستخدم Delta Y =
+
+
+445
+00:34:44,110 --> 00:34:47,170
+find the velocity and position of the ball at T = 5
+
+446
+00:34:47,170 --> 00:34:51,070
+بساوية ٥ ممكن نستخدم المعادلة الأولى و الثانية
+
+447
+00:34:51,070 --> 00:34:54,950
+بعوض عن الـ T بخمسة تطلع النتيجة اللى هى الـ V ناقص ٢٩
+
+448
+00:34:54,950 --> 00:34:58,030
+هدى هى السرعة عندما يكون الزمن خمسة، وهنا هو
+
+449
+00:34:58,030 --> 00:35:01,930
+المسافة عندما يكون الـ ... عندما يكون الـ ...
+
+450
+00:35:01,930 --> 00:35:04,890
+الزمن بساوية خمسة برضه بنعوض بنفس المعادلات بس
+
+451
+00:35:04,890 --> 00:35:11,590
+بعوض عن الزمن بساوية خمسة. عندى سؤال، آخر سؤال.
+
+452
+00:35:11,590 --> 00:35:17,450
+نفس الفكرة، آخر سؤال، نفس الفكرة إن شاء الله بنكمله
+
+453
+00:35:17,450 --> 00:35:18,690
+المرة اللى جاية بإذن الله
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E.srt
new file mode 100644
index 0000000000000000000000000000000000000000..5ed1d59548def68b66e2eab6c35bbbcb5512b51f
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E.srt
@@ -0,0 +1,1373 @@
+1
+00:00:00,980 --> 00:00:05,800
+بسم الله الرحمن الرحيم section سبعة ثلاثة اثنين by
+
+2
+00:00:05,800 --> 00:00:09,440
+one centripetal acceleration التسارع اللي هو
+
+3
+00:00:09,440 --> 00:00:16,200
+المركزي في أن الشكل التالي يوضح سيارة بتتحرك بمسار
+
+4
+00:00:16,200 --> 00:00:21,480
+دائري with constant linear speed بسرعة خطية ثابتة
+
+5
+00:00:21,480 --> 00:00:24,860
+even though the car moves at constant speed, it
+
+6
+00:00:24,860 --> 00:00:28,860
+still has an acceleration طالما أنها بتتحرك بسرعة
+
+7
+00:00:28,860 --> 00:00:34,720
+ثابتة، بتتحرك بسرعة ثابتة، لكن ما زال في لها تسارع
+
+8
+00:00:34,720 --> 00:00:39,540
+عشان أدرس هذه الظاهرة، لإنه إذا مشيت بسرعة خطية ب
+
+9
+00:00:39,540 --> 00:00:43,440
+constant speed، في التسارع بيكون صفر، لكن هنا
+
+10
+00:00:43,440 --> 00:00:48,780
+التسارع موجود، عشان هيك بندرس هذه الظاهرة، بنوجد
+
+11
+00:00:48,780 --> 00:00:54,380
+معادلة بتربط بين اللي هي التسارع و...و السرعة
+
+12
+00:00:54,380 --> 00:01:00,740
+خلال...خلال طبعا حركة دائرية، عندنا احنا A<sub>average</sub>
+
+13
+00:01:00,740 --> 00:01:03,720
+بيساوي V<sub>final</sub> ناقص V<sub>initial</sub> على T<sub>final</sub> ناقص T<sub>initial</sub>
+
+14
+00:01:03,720 --> 00:01:08,120
+initial، طبعا احنا الـ ΔV بيمثل الفرق بين اللي هي
+
+15
+00:01:08,120 --> 00:01:13,670
+ΔV = V<sub>initial</sub> و V<sub>final</sub>، هذا الـ vector طبعا has
+
+16
+00:01:13,670 --> 00:01:18,250
+the same magnitude، بيمثل the same speed, but if
+
+17
+00:01:18,250 --> 00:01:21,350
+they have different directions، طبعا هذا بالحركة
+
+18
+00:01:21,350 --> 00:01:25,310
+الخطية، لو كان عندي أنا نفس الـ...الـ...السرعة اللي
+
+19
+00:01:25,310 --> 00:01:28,250
+بداية ونفس السرعة النهائية، وبالتالي هيكون
+
+20
+00:01:28,250 --> 00:01:32,770
+التسارع صفر، لكن لو بتحرك باتجاهات مختلفة، معنى
+
+21
+00:01:32,770 --> 00:01:37,460
+الكلام أن هو لا يساوي صفر، فلو إحنا مشينا سيارة بهذا
+
+22
+00:01:37,460 --> 00:01:42,100
+الحركة الدائرية على دور معين، طبعا هنا نقطة الدوران
+
+23
+00:01:42,100 --> 00:01:49,000
+هتتحرك طبعا من الـ A هنا، كأنها نقطة initial، السرعة
+
+24
+00:01:49,000 --> 00:01:54,600
+المماسية V<sub>initial</sub>، لو وصلت لنقطة B ومشيت إزاحة
+
+25
+00:01:54,600 --> 00:01:59,340
+Δθ، هيكون هنا عندي أنا أيضاً اللي هي سرعة مماسية
+
+26
+00:01:59,340 --> 00:02:04,250
+طبعا هنا اتجاهها بيختلف عن هذا الاتجاه، وبالتالي الـ
+
+27
+00:02:04,250 --> 00:02:08,830
+a في هذه الحالة لا تساوي صفر، اتجاه السرعة زي ما
+
+28
+00:02:08,830 --> 00:02:14,330
+حكينا خلال حركة دائرية بتتغير، for a circular
+
+29
+00:02:14,330 --> 00:02:18,090
+motion، في الحركة الدائرية، at constant speed, the
+
+30
+00:02:18,090 --> 00:02:21,650
+acceleration vector always points، التسارع دائماً
+
+31
+00:02:21,650 --> 00:02:25,970
+بيتجه ناحية المركز، زي such as acceleration is
+
+32
+00:02:25,970 --> 00:02:29,570
+called، هذا التسارع بيسموه centripetal acceleration
+
+33
+00:02:30,460 --> 00:02:34,460
+Its magnitude، الآن الـ centripetal acceleration a<sub>c</sub>
+
+34
+00:02:34,460 --> 00:02:38,900
+بتساوي V<sup>2</sup> على R، هذه عبارة عن التسارع المركزي
+
+35
+00:02:38,900 --> 00:02:43,240
+هي علاقة اللي هي التسارع المركزي مع السرعة
+
+36
+00:02:43,240 --> 00:02:47,440
+tangential velocity، because the tangential
+
+37
+00:02:47,440 --> 00:02:50,260
+velocity is related to the angular velocity، طبعا
+
+38
+00:02:50,260 --> 00:02:54,260
+في علاقة بين الـ V و الـ ω، فـ V<sub>tangential</sub> كانت
+
+39
+00:02:54,260 --> 00:03:00,040
+بتساوي R في ω، إذا الـ...الـ alternative...يعني الـ
+
+40
+00:03:00,040 --> 00:03:07,580
+alternative هنا...an alternative form، فده الحالة بده
+
+41
+00:03:07,580 --> 00:03:12,220
+يساوي اللي هي V<sub>tangential</sub> بتساوي R في ω، لما
+
+42
+00:03:12,220 --> 00:03:15,540
+بده أعوض، إذا الـ a<sub>c</sub> بتساوي R<sup>2</sup> في ω<sup>2</sup>
+
+43
+00:03:15,540 --> 00:03:19,060
+تربيع على R، يعني R في ω<sup>2</sup>، يعني ممكن نحكي a<sub>c</sub>
+
+44
+00:03:19,060 --> 00:03:22,580
+بتساوي V<sup>2</sup> على R أو a<sub>c</sub> بتساوي R في ω<sup>2</sup>
+
+45
+00:03:23,040 --> 00:03:27,540
+Physically، فيزيائياً، اللي هي الـ acceleration تحدث
+
+46
+00:03:27,540 --> 00:03:32,660
+only if some force is present، وجود القوة، for
+
+47
+00:03:32,660 --> 00:03:36,160
+example، فـ if a car travels in a circle on flat
+
+48
+00:03:36,160 --> 00:03:41,120
+ground، الآن إذا السيارة بدها تدور على طبعا منحنى
+
+49
+00:03:41,120 --> 00:03:45,620
+أو دوار مستوٍ، فيه عندنا الـ force of static
+
+50
+00:03:45,620 --> 00:03:48,240
+friction، القوة اللي بتخلي السيارة تدور حركة
+
+51
+00:03:48,240 --> 00:03:52,500
+دائرية هي عبارة عن قوة الاحتكاك الساكن، قوة
+
+52
+00:03:52,500 --> 00:03:56,640
+الاحتكاك الساكن هي طبعاً متجهة ناحية المركز، بيسموها
+
+53
+00:03:56,640 --> 00:04:01,400
+centripetal force، طبعاً الـ a<sub>c</sub> in equation، طبعاً الـ
+
+54
+00:04:01,400 --> 00:04:04,680
+a<sub>c</sub> اللي هي centripetal acceleration، بتمثل only the
+
+55
+00:04:04,680 --> 00:04:07,180
+magnitude، تمثل فقط الـ magnitude لـ centripetal
+
+56
+00:04:07,180 --> 00:04:11,130
+acceleration، للتسارع المركزي، الـ acceleration itself
+
+57
+00:04:11,130 --> 00:04:14,510
+is always directed toward the center, centripetal
+
+58
+00:04:14,510 --> 00:04:17,730
+اللي هي centripetal acceleration، تسارع المركزي
+
+59
+00:04:17,730 --> 00:04:21,850
+بيتجه دائماً ناحية المركز، the foregoing
+
+60
+00:04:21,850 --> 00:04:27,150
+clarification concerns a circular motion at
+
+61
+00:04:27,150 --> 00:04:29,790
+constant speed، when an object moves in a circle
+
+62
+00:04:29,790 --> 00:04:33,830
+but is speeding up or slowing down، tangential
+
+63
+00:04:33,830 --> 00:04:38,090
+component of the acceleration، فـ a<sub>T</sub> بتساوي R في
+
+64
+00:04:38,090 --> 00:04:42,190
+الـ α، it's also present because the tangential
+
+65
+00:04:42,190 --> 00:04:45,110
+and centripetal components of acceleration are
+
+66
+00:04:45,110 --> 00:04:49,190
+perpendicular to each other، الـ tangential...
+
+67
+00:04:49,190 --> 00:04:54,610
+tangential and centripetal components، المركبة اللي
+
+68
+00:04:54,610 --> 00:04:58,090
+...اللي هي الـ a<sub>tangential</sub> و الـ a<sub>centripetal</sub>، يعني
+
+69
+00:04:58,090 --> 00:05:02,610
+التسارع المركزي والتسارع المماسي متعامدين على بعض
+
+70
+00:05:02,610 --> 00:05:06,730
+لأن التسارع المماسي طبعاً مماس للدائرة، والتسارع
+
+71
+00:05:06,730 --> 00:05:09,670
+المركزي ناحية المركز، وبالتالي الاثنين متعامدين
+
+72
+00:05:09,670 --> 00:05:13,970
+على بعض، لإيجاد التسارع الكلي، عشان الاثنين
+
+73
+00:05:13,970 --> 00:05:17,110
+المتعامدتين على بعض، فالتسارع الكلي بيساوي جذر الـ
+
+74
+00:05:17,110 --> 00:05:20,370
+a<sub>T</sub><sup>2</sup> زائد a<sub>C</sub><sup>2</sup>، بالاستخدام اللي
+
+75
+00:05:20,370 --> 00:05:26,350
+هي نظرية فيثاغورس، طبعاً هذه كلها بنعرف فيها
+
+76
+00:05:26,350 --> 00:05:29,880
+اللي هي التسارع المركزي، A racetrack is
+
+77
+00:05:29,880 --> 00:05:34,700
+constructed such that two arcs of radius، في عندي طبعاً
+
+78
+00:05:34,700 --> 00:05:40,180
+حركة في قوس ثمانين متر at A، واتحركت أربعين متر at
+
+79
+00:05:40,180 --> 00:05:45,740
+B، are joined by two stretches of straight track in
+
+80
+00:05:45,740 --> 00:05:50,580
+figure سبعة ثمانية، in a particular trial run،
+
+81
+00:05:50,580 --> 00:05:54,840
+driver travels at a constant speed of خمسين متر
+
+82
+00:05:54,840 --> 00:05:59,140
+per second for one complete lap، the ratio of the tangential
+
+83
+00:05:59,140 --> 00:06:05,120
+acceleration at A to that at B is، بدي أنا اللي هي
+
+84
+00:06:05,120 --> 00:06:10,140
+الـ ratio of tangential، بالنسبة لـ...اللي هي النسبة
+
+85
+00:06:10,140 --> 00:06:14,900
+بين الـ tangential acceleration عند النقطة A و
+
+86
+00:06:14,900 --> 00:06:19,380
+النقطة B، بدها تساوي طبعاً اللي هي عبارة عن
+
+87
+00:06:19,380 --> 00:06:23,280
+tangential acceleration، صفر عند كلا النقطتين،
+
+88
+00:06:23,280 --> 00:06:28,580
+tangential acceleration بتساوي صفر in...يعني
+
+89
+00:06:28,580 --> 00:06:35,560
+اللي هي في كده النقاط اللي هو إحنا...إحنا...الشكل...الشكل
+
+90
+00:06:35,560 --> 00:06:40,930
+كما هو موضح في الشكل سبعة ثمانية، figure سبعة ثمانية، لو
+
+91
+00:06:40,930 --> 00:06:47,390
+نرجع لـ figure سبعة ثمانية إن شاء الله، figure سبعة
+
+92
+00:06:47,390 --> 00:06:49,170
+ثمانية، طبعاً هو موضح في الكتاب
+
+93
+00:07:12,230 --> 00:07:17,050
+عموماً...عموماً طبعاً هو موجود في الكتاب، الآن
+
+94
+00:07:17,050 --> 00:07:22,430
+racetrack، يعني فيه إن هو مسار Constructed to arcs of
+
+95
+00:07:22,430 --> 00:07:28,930
+radius، مسار بتمشي فيه طبعاً جسم معين أو سيارة بـ...
+
+96
+00:07:28,930 --> 00:07:33,370
+طبعاً بيتحرك على طبعاً قوس ثمانين متر عند النقطة A and
+
+97
+00:07:33,370 --> 00:07:36,990
+أربعين متر عند النقطة B، are joined by two stretches
+
+98
+00:07:36,990 --> 00:07:40,850
+of straight track as...الفجر...طبعاً الفجر موجود، بس مش
+
+99
+00:07:40,850 --> 00:07:46,990
+موجود هنا، in a particular trial run، driver travels
+
+100
+00:07:46,990 --> 00:07:51,470
+at a constant speed of خمسين...طبعاً السائق بيتحرك بـ
+
+101
+00:07:51,470 --> 00:07:55,990
+constant speed، بسرعة خمسين متر في الثانية، طبعاً لما
+
+102
+00:07:55,990 --> 00:08:00,850
+يتحرك بـ constant speed، طبعاً إذا كان أنا بدي
+
+103
+00:08:00,850 --> 00:08:06,170
+التسارع الـ...التسارع الـ tangential، مع أن الكلام
+
+104
+00:08:06,170 --> 00:08:10,910
+إنه التسارع المماسي هيكون عندنا صفر، لإنه بيتحرك بـ
+
+105
+00:08:10,910 --> 00:08:14,850
+constant speed، زي ما هو طبعاً الـ ratio of tangential
+
+106
+00:08:14,850 --> 00:08:18,490
+acceleration at...at B، من A لـ B طبعاً هيكون
+
+107
+00:08:18,490 --> 00:08:22,890
+عندي أنا صفر، اللي هي الجواب A، لكن الآن الـ ratio of
+
+108
+00:08:22,890 --> 00:08:27,570
+the centripetal acceleration at A to B، لما أحسب الـ
+
+109
+00:08:27,570 --> 00:08:32,170
+tangential acceleration، هو بيتحرك حركة...بتتحرك
+
+110
+00:08:32,170 --> 00:08:36,450
+حركة دائرية، الـ tangential اللي هي اللي عند نقطة A
+
+111
+00:08:36,450 --> 00:08:39,550
+و لا نقطة B بتساوي صفر، لإنه بيتحرك بـ constant
+
+112
+00:08:39,550 --> 00:08:42,950
+speed، لكن لما آجي أحسب الـ centripetal acceleration
+
+113
+00:08:42,950 --> 00:08:48,970
+من النقطة A للـ B، بلاحظ أنه هو بيساوي طبعاً بيساوي
+
+114
+00:08:48,970 --> 00:08:53,270
+نصف، من النقطة A لـ B، لإنه في عندي أنا V<sup>2</sup> على
+
+115
+00:08:53,270 --> 00:08:57,810
+...على R، والـ R هي اللي بتحدد، واحدة نصف الثانية
+
+116
+00:08:57,810 --> 00:09:01,930
+بده الـ angular speed is greatest at...الـ
+
+117
+00:09:01,930 --> 00:09:06,770
+angular speed is greatest عند النقطة B، الـ angular
+
+118
+00:09:06,770 --> 00:09:13,160
+speed is greatest at النقطة B، الكلام الثاني، an
+
+119
+00:09:13,160 --> 00:09:15,740
+object moves in a circular path، جسم بيتحرك حركة
+
+120
+00:09:15,740 --> 00:09:19,480
+دائرية بـ constant speed، which the following...meaning
+
+121
+00:09:19,480 --> 00:09:24,340
+الجمال الآن is...اللي هي is true بالنسبة للجسم،
+
+122
+00:09:24,340 --> 00:09:29,900
+هل سرعتها ثابتة؟ هل التسارع بيتغير؟ هل التسارع طبعاً
+
+123
+00:09:29,900 --> 00:09:34,660
+ثابت؟ والـ velocity changing؟ ولا both its طبعاً
+
+124
+00:09:34,660 --> 00:09:38,090
+velocity and acceleration are changing؟ ولا its
+
+125
+00:09:38,090 --> 00:09:40,590
+velocity and acceleration remain constant؟ الآن
+
+126
+00:09:40,590 --> 00:09:44,670
+بيتحرك حركة دائرية، بيتحرك حركة دائرية بـ constant
+
+127
+00:09:44,670 --> 00:09:47,430
+speed، which of the following statements is correct؟ الجملة
+
+128
+00:09:47,430 --> 00:09:51,270
+ده صحيحة؟ الجملة الأولى، its velocity is constant،
+
+129
+00:09:51,270 --> 00:09:57,950
+سرعتها ثابتة، لكن التسارع بيتغير، الآن التسارع ثابت
+
+130
+00:09:57,950 --> 00:10:01,430
+والسرعة بتتغير؟ ولا both its velocity and
+
+131
+00:10:01,430 --> 00:10:04,730
+acceleration are changing؟ طبعاً في الحركة الدائرية
+
+132
+00:10:04,730 --> 00:10:08,050
+both its velocity and acceleration are changing،
+
+133
+00:10:08,050 --> 00:10:11,610
+لأن الـ velocity بتغير اتجاهها في كل نقطة، والتسارع
+
+134
+00:10:11,610 --> 00:10:14,050
+بيغير بناء على الـ velocity اللي نفسها، و V<sup>2</sup>
+
+135
+00:10:14,050 --> 00:10:19,090
+على الـ R، فالجواب الصحيح هو C، لأن both its velocity
+
+136
+00:10:19,090 --> 00:10:24,930
+and acceleration are changing، example سبعة خمسة،
+
+137
+00:10:24,930 --> 00:10:32,770
+في عندنا race car accelerate uniformly،
+
+138
+00:10:32,770 --> 00:10:37,850
+تتحرك بانتظام طبعاً من سرعة أربعين متر في الثانية
+
+139
+00:10:37,850 --> 00:10:41,810
+إلى سرعة ستين في زمن قدره خمسة ثواني، while traveling
+
+140
+00:10:41,810 --> 00:10:44,910
+counterclockwise، طبعاً هتتحرك حركة دائرية عكس
+
+141
+00:10:44,910 --> 00:10:49,170
+عقارب الساعة خلال radius أربعة في عشر أو ستين
+
+142
+00:10:49,170 --> 00:10:53,850
+متر، when the car reaches a speed of خمسين، لما السيارة
+
+143
+00:10:53,850 --> 00:10:58,700
+توصل لسرعة خمسين، احسب calculate the magnitude of
+
+144
+00:10:58,700 --> 00:11:01,580
+the car's centripetal acceleration، طبعاً نحسب
+
+145
+00:11:01,580 --> 00:11:04,380
+الـ centripetal acceleration، V<sup>2</sup> على R، نحسب
+
+146
+00:11:04,380 --> 00:11:08,460
+الـ centripetal acceleration، الـ V عندي خمسين، والـ R
+
+147
+00:11:08,460 --> 00:11:13,080
+كانت أربعة في عشر أس اثنين، بتساوي خمسين تربيع على أربعة، طبعاً
+
+148
+00:11:13,080 --> 00:11:15,640
+خمسين تربيع، لأن هو V<sup>2</sup> على أربعة، بيطلع ستة
+
+149
+00:11:15,640 --> 00:11:19,260
+فاصلة اثنين خمسة متر في الثانية تربيع، في B، بـ
+
+150
+00:11:19,260 --> 00:11:22,180
+calculate the angular velocity، طبعاً طالما إحنا
+
+151
+00:11:22,180 --> 00:11:25,330
+عرفنا الـ V موجودة والـ R موجودة، العلاقة الـ...الـ
+
+152
+00:11:25,330 --> 00:11:29,570
+linear في الـ angular، ω بتساوي V على R، اللي
+
+153
+00:11:29,570 --> 00:11:32,830
+هي خمسين على R، أربعة في عشر أس اثنين متر، بتطلع فاصلة
+
+154
+00:11:32,830 --> 00:11:37,670
+واحد اثنين خمسة rad per second، في C، calculate the
+
+155
+00:11:37,670 --> 00:11:40,790
+magnitude of the tangential acceleration، الـ
+
+156
+00:11:40,790 --> 00:11:43,210
+tangential acceleration اللي هي ΔV على ΔT،
+
+157
+00:11:43,210 --> 00:11:48,520
+V<sub>final</sub> كانت ستين، V<sub>initial</sub> أربعين، و Δt خمسة، بيطلع أربعة
+
+158
+00:11:48,520 --> 00:11:52,200
+متر في الثانية تربيع، بعد هيك بـ calculate the
+
+159
+00:11:52,200 --> 00:11:55,740
+magnitude of the total acceleration، بدنا نحسب الـ
+
+160
+00:11:55,740 --> 00:11:59,040
+total acceleration، اللي عبارة عن a<sub>tangential</sub>
+
+161
+00:11:59,040 --> 00:12:03,620
+تربيع زائد a<sub>c</sub> تربيع، الـ a = جذر a<sub>T</sub><sup>2</sup> زائد a<sub>c</sub><sup>2</sup>
+
+162
+00:12:03,620 --> 00:12:07,700
+تربيع، بتساوي أربعة تربيع زائد ستة فاصلة اثنين خمسة تربيع، اللي إحنا
+
+163
+00:12:07,700 --> 00:12:11,500
+وجدناهم سابقاً، بيطلع الـ total acceleration بتساوي سبعة
+
+164
+00:12:11,500 --> 00:12:17,920
+فاصلة أربعة اثنين متر في الثانية تربيع، section 7-4، Newton's second
+
+165
+00:12:17,920 --> 00:12:21,360
+law for uniform circular motion، قانون نيوتن الثاني
+
+166
+00:12:21,360 --> 00:12:26,260
+للحركة الدائرية المنتظمة، Newton's second law، قانون
+
+167
+00:12:26,260 --> 00:12:30,280
+نيوتن الثاني للحركة، ممكن إنه إحنا طبعاً نستخدمه
+
+168
+00:12:30,280 --> 00:12:35,370
+عشان نحل مسائل تتضمن الحركة الدائرية، in the case
+
+169
+00:12:35,370 --> 00:12:38,170
+of uniform circular motion، في حالة الحركة
+
+170
+00:12:38,170 --> 00:12:42,990
+الدائرية المنتظمة، قانون نيوتن الثاني will feature
+
+171
+00:12:42,990 --> 00:12:45,790
+the centripetal acceleration and variability of the
+
+172
+00:12:45,790 --> 00:12:50,100
+radial force، في عندي طبعاً هتظهر عندي مجموعة قوة
+
+173
+00:12:50,100 --> 00:12:53,100
+بتساوي الـ m في a، هذا قانون نيوتن الثاني، فبيظهر عندي
+
+174
+00:12:53,100 --> 00:12:57,160
+radial force، في قوة مركزية، that are either
+
+175
+00:12:57,160 --> 00:13:01,700
+directed...القوة المركزية ممكن تكون تتجه towards
+
+176
+00:13:01,
+
+223
+00:16:17,750 --> 00:16:21,810
+straight line لإنه هي بتتحرك حركة دائرية، ممكن
+
+224
+00:16:21,810 --> 00:16:24,370
+أحركها وأتركها، بتستمر في الحركة نتيجة اللي هي
+
+225
+00:16:24,370 --> 00:16:29,570
+القصور الذاتي.  By extending a radial force on
+
+226
+00:16:29,570 --> 00:16:32,990
+the puck, a tension force that makes it follow the
+
+227
+00:16:32,990 --> 00:16:36,030
+circular path. في عندي حركة دائرية في مسار دائري
+
+228
+00:16:36,030 --> 00:16:40,430
+الشد هذا، directed towards the center، وبالتالي في
+
+229
+00:16:40,430 --> 00:16:44,480
+أبقى أُمثل عن اللي هي الحركة المركزية، الحركة الـ
+
+230
+00:16:44,480 --> 00:16:47,680
+centripetal force بتساوي  m a c، بتساوي m v تربيع
+
+231
+00:16:47,680 --> 00:16:52,000
+على r.  F<sub>c</sub> بيسموها centripetal أو net centripetal
+
+232
+00:16:52,000 --> 00:16:55,460
+force.  The net force causing centripetal
+
+233
+00:16:55,460 --> 00:16:58,320
+acceleration. هذه القوة المركزية بتسبب التسارع
+
+234
+00:16:58,320 --> 00:17:02,540
+المركزي، اللي هو اتجاهه ناحية المركز، and effects
+
+235
+00:17:02,540 --> 00:17:04,900
+a change in the direction of the velocity vector.
+
+236
+00:17:04,900 --> 00:17:09,700
+بيأثر على حركة أو اتجاه اللي هي اتجاه السرعة. If
+
+237
+00:17:09,700 --> 00:17:13,820
+that force should vanish، إذا كان السرعة هذه أو
+
+238
+00:17:13,820 --> 00:17:17,460
+القوة انتهت، the object would immediately leave its
+
+239
+00:17:17,460 --> 00:17:20,600
+circular path and move along a straight line. إذا هذه
+
+240
+00:17:20,600 --> 00:17:25,560
+القوة المركزية، أو القوة هذه تلاشت، فالجسم بيرجع
+
+241
+00:17:25,560 --> 00:17:30,340
+بيتحرك حركة كأنها خط مستقيم مماسي للي هي الحركة
+
+242
+00:17:30,340 --> 00:17:34,220
+الأساسية، اللي هي الـ circular. A radial force is a
+
+243
+00:17:34,220 --> 00:17:39,320
+vector. القوة المركزية اللي هي إنتاجها عند  نصف القطر
+
+244
+00:17:39,320 --> 00:17:43,210
+الـ radial، عبارة عن قوة متجهة، and has direction toward the
+
+245
+00:17:43,210 --> 00:17:47,250
+center. The second law for uniform circular motion involves
+
+246
+00:17:47,250 --> 00:17:50,250
+forces that are directed either towards or away from the
+
+247
+00:17:50,250 --> 00:17:54,070
+center. طبعا في عندي نوعين من القوة: ناحية المركز
+
+248
+00:17:54,070 --> 00:17:57,670
+وبعيدة عن المركز.  The force acting, the force that
+
+249
+00:17:57,670 --> 00:18:03,450
+acts toward the center, I consider it negative، والقوة اللي
+
+250
+00:18:03,450 --> 00:18:09,250
+بتأثر خارج المركز باعتبرها positive. The centripetal
+
+251
+00:18:09,250 --> 00:18:11,930
+acceleration is negative. الآن الـ centripetal
+
+252
+00:18:11,930 --> 00:18:15,590
+acceleration. القوة المركزية، بناء على ما ذكر، تعتبر
+
+253
+00:18:15,590 --> 00:18:21,170
+سالبة، لأنها تؤثر ناحية المركز. قانون نيوتن الثاني
+
+254
+00:18:21,170 --> 00:18:25,270
+لـ uniform circular motion، ممكن أكتبه بهذا الشكل:
+
+255
+00:18:25,270 --> 00:18:29,370
+ΣF<sub>r</sub> بتساوي -m v تربيع على r. هذه
+
+256
+00:18:29,370 --> 00:18:32,050
+بيسموها الـ radial force.  ΣF<sub>r</sub>  for the radial force
+
+257
+00:18:32,480 --> 00:18:35,380
+بتساوي -m v تربيع على r. في الـ radial force
+
+258
+00:18:35,380 --> 00:18:38,800
+القوة اللي ناحية المركز سالبة، واللي خارجها من
+
+259
+00:18:38,800 --> 00:18:43,640
+المركز تعتبر موجبة.  F<sub>r</sub> بيسموها الـ radial force
+
+260
+00:18:43,640 --> 00:18:49,120
+acting on the mass m. Positive if the force is away
+
+261
+00:18:49,120 --> 00:18:53,520
+from the center, and negative if the force is
+
+262
+00:18:53,520 --> 00:18:57,280
+towards the center. بالنسبة لها الـ استراتيجية، كيف
+
+263
+00:18:57,280 --> 00:19:00,580
+ممكن نحل مسائل بالنسبة لها الـ centripetal
+
+264
+00:19:00,580 --> 00:19:04,300
+acceleration. بنستخدم الخطوات التالية: بنرسم الـ
+
+265
+00:19:04,300 --> 00:19:08,500
+free body diagram، وبنرسم القوى على المحاور، وبنرسم
+
+266
+00:19:08,500 --> 00:19:14,040
+القوى المؤثرة على، طبعا على الجسم. بالنسبة للـ net
+
+267
+00:19:14,040 --> 00:19:17,220
+force، F<sub>c</sub> towards the center. الـ F<sub>c</sub> بتساوي  Σ
+
+268
+00:19:17,220 --> 00:19:21,620
+F<sub>r</sub>. الـ F<sub>r</sub> is the sum of the radial components.
+
+269
+00:19:21,620 --> 00:19:26,120
+This net radial force. ببستخدم بعد كده Σ
+
+270
+00:19:26,120 --> 00:19:29,520
+للقوة بتساوي اللي هي الـ… اللي هي الـ m v
+
+271
+00:19:29,520 --> 00:19:33,010
+squared على r. يعني الـ F<sub>r</sub> بيساوي m × a<sub>c</sub>، و الـ F
+
+272
+00:19:33,010 --> 00:19:36,830
+<sub>T</sub> بيساوي m × a<sub>T</sub>، و الـ F<sub>N</sub> بيساوي m × a<sub>N</sub> حسب
+
+273
+00:19:36,830 --> 00:19:41,290
+الـ F، وحسب التسارع. The magnitude of the centripetal
+
+274
+00:19:41,290 --> 00:19:44,430
+acceleration for the uniform circular motion
+
+275
+00:19:44,430 --> 00:19:48,390
+بيساوي v تربيع على r. بعد هيك بنحل المثلث، وبنجد
+
+276
+00:19:48,390 --> 00:19:54,270
+المتغيرات.  ناخد هذا السؤال: عندي سيارة is a car
+
+277
+00:19:54,270 --> 00:19:59,300
+traveling at a constant speed of  ثلاثين ميل في الساعة on a
+
+278
+00:19:59,300 --> 00:20:03,340
+level circular road of radius 50 meters. تتحرك بسرعة 30 ميل
+
+279
+00:20:03,340 --> 00:20:08,780
+في الساعة، يعني 13.4 متر في الثانية، على مستوى دائري
+
+280
+00:20:08,780 --> 00:20:15,360
+بـ radius 50 متر. طبعا shown in the bird’s eye
+
+281
+00:20:15,360 --> 00:20:21,260
+view. كأنه يعني هي in focus، مركزة، يعني كأنه طائر
+
+282
+00:20:21,260 --> 00:20:25,130
+بيطير وشايف الوضع. What minimum coefficient of
+
+283
+00:20:25,130 --> 00:20:29,810
+static friction, μ<sub>s</sub>, between the tires and the
+
+284
+00:20:29,810 --> 00:20:32,870
+roadway will allow the car to make the circular
+
+285
+00:20:32,870 --> 00:20:38,230
+turn without sliding? بدي معامل احتكاك الساكن اللي
+
+286
+00:20:38,230 --> 00:20:42,730
+بين العجلات وبين الأرض بيخلي السيارة تتحرك حركة
+
+287
+00:20:42,730 --> 00:20:47,510
+دائرية منتظمة. طبعا هي الشكل عندنا، احنا الشكل من
+
+288
+00:20:47,510 --> 00:20:52,010
+أعلى، كأنه يعني طائر بينظر إلى أعلى. هذه السيارة على
+
+289
+00:20:52,010 --> 00:20:55,960
+الأرض. السيارة هذه بتدور بهذا الـ… على الـ curve. طبعا
+
+290
+00:20:55,960 --> 00:20:59,620
+في قوة بتمنعها إنها تتحرك، قوة الاحتكاك الساكن هي
+
+291
+00:20:59,620 --> 00:21:02,320
+اللي بتحافظ على إنها… إنها ما… لا تنزلق. هذه
+
+292
+00:21:02,320 --> 00:21:08,100
+السيارة، وطبعا… طبعا بتلف أو بتدور حوالي… في
+
+293
+00:21:08,100 --> 00:21:12,540
+مسار دائري، أو بتتحرك في مسار دائري منتظم. بنكتب اللي هي
+
+294
+00:21:12,540 --> 00:21:16,880
+… بنستخدم قانون نيوتن الثاني، وبنحكي إنه اللي هي
+
+295
+00:21:16,880 --> 00:21:21,330
+m v squared على r بتساوي μ<sub>s</sub> × F<sub>N</sub>، اللي هي
+
+296
+00:21:21,330 --> 00:21:24,570
+الـ F<sub>s</sub>. القوة هذه، اللي هي الـ F<sub>s</sub> هي القوة
+
+297
+00:21:24,570 --> 00:21:27,790
+المركزية. القوة الـ F<sub>s</sub> هي القوة المركزية.
+
+298
+00:21:27,790 --> 00:21:30,750
+ΣF<sub>r</sub> بتساوي -m v تربيع على r.
+
+299
+00:21:30,750 --> 00:21:34,370
+و الـ F<sub>r</sub> بتساوي -μ<sub>s</sub> × F<sub>N</sub>.  الـ F<sub>N</sub>
+
+300
+00:21:34,370 --> 00:21:37,970
+بتساوي m g. إذا F<sub>N</sub> - m g بتساوي صفر.
+
+301
+00:21:37,970 --> 00:21:42,690
+هذا الـ vertical component. وبنرجع للي هي الـ
+
+302
+00:21:42,690 --> 00:21:46,630
+F<sub>N</sub> بتساوي m g. الـ m بتساوي -m، والـ سالب
+
+303
+00:21:46,630 --> 00:21:50,560
+بتروح مع السالب، بتطلع عندي μ<sub>s</sub> بتساوي v تربيع
+
+304
+00:21:50,560 --> 00:21:56,680
+على r × g. v أطانيها 13.4 تربيع، على الـ r 50، والـ g
+
+305
+00:21:56,680 --> 00:22:02,920
+9.8، بتطلع μ<sub>s</sub> 0.366.  دوغمها اسمه معامل احتكاك
+
+306
+00:22:02,920 --> 00:22:07,700
+ال ساكن الذي يجعل السيارة تدور حركة دائرية منتظمة.
+
+307
+00:22:07,700 --> 00:22:13,420
+نوع ثاني من الأسئلة بيسموها اللي هي banked
+
+308
+00:22:13,420 --> 00:22:18,960
+road. اللي هي سيارة بتدور على، يعني طريق دائري
+
+309
+00:22:18,960 --> 00:22:23,520
+بانكاد، يعني طريق عالي شوية، منحدر ودائري، with
+
+310
+00:22:23,520 --> 00:22:27,340
+a maximum radius. الـ radius كانت 316 متر.
+
+311
+00:22:27,340 --> 00:22:31,000
+If a car negotiates the curve too slowly، طبعا
+
+312
+00:22:31,000 --> 00:22:35,560
+السيارة بدها تدور على المنحنى بكل بطء حتى تستطيع
+
+313
+00:22:35,560 --> 00:22:40,070
+إنها تدور على المنحنى دورة، أو… أو مسار دائري. It
+
+314
+00:22:40,070 --> 00:22:44,450
+tends to slip down the incline of the turn. طبعا
+
+315
+00:22:44,450 --> 00:22:50,430
+بتميل، إنها بتدور حوالين مسار، يعني ميل منحدر، ميل
+
+316
+00:22:50,430 --> 00:22:56,730
+بزاوية معينة، وبتحاول إنها تنزلق في… في هذا
+
+317
+00:22:56,730 --> 00:23:01,020
+المسار، وتدور حركة دائرية. في هذه الحالة مطلوب مننا
+
+318
+00:23:01,020 --> 00:23:06,460
+نوجد اللي هي centripetal acceleration، ونوجد اللي
+
+319
+00:23:06,460 --> 00:23:12,160
+هي سرعة السيارة مع إهمال الاحتكاك. طبعا هي السيارة
+
+320
+00:23:12,160 --> 00:23:15,210
+على مستوى مايل، وهي بدأت تدور حركة دائرية. الحركة
+
+321
+00:23:15,210 --> 00:23:18,130
+الدائرية بهذا الشكل. طبعا في هذا السؤال احنا
+
+322
+00:23:18,130 --> 00:23:21,370
+ما بنحلل الـ m g، لأنه إذا حللنا الـ m g هيجي بهذا
+
+323
+00:23:21,370 --> 00:23:24,130
+الاتجاه، وهذا الاتجاه بعيدًا عن الحركة الدائرية.
+
+324
+00:23:24,130 --> 00:23:28,250
+الحركة الدائرية بهذا الشكل هنا. هيك إذا راح أحلل الـ
+
+325
+00:23:28,250 --> 00:23:33,050
+F<sub>N</sub>، راح أحلل الـ F<sub>N</sub> إلى قوتين هنا، اللي هو الـ
+
+326
+00:23:33,050 --> 00:23:38,070
+F<sub>N</sub> sin θ، وهنا في الـ vertical F<sub>N</sub> cos θ. القوة الداخلة
+
+327
+00:23:38,070 --> 00:23:41,430
+ناحية المركز هي عبارة عن الـ F<sub>N</sub> بهذا الاتجاه، اللي هي
+
+328
+00:23:41,430 --> 00:23:42,390
+F<sub>N</sub> sin θ.
+
+329
+00:23:51,840 --> 00:23:54,700
+الآن -m g بتساوي صفر. يعني F<sub>N</sub> - m
+
+330
+00:23:54,700 --> 00:23:55,440
+g بتساوي صفر. يعني F<sub>N</sub> - m g بتساوي
+
+331
+00:23:55,440 --> 00:23:56,420
+صفر. يعني F<sub>N</sub> - m g بتساوي صفر. يعني F<sub>N</sub>
+
+332
+00:23:56,420 --> 00:23:57,320
+= m g بتساوي صفر. يعني F<sub>N</sub> - m g
+
+333
+00:23:57,320 --> 00:24:00,780
+بتساوي صفر. يعني F<sub>N</sub> - m g بتساوي صفر.
+
+334
+00:24:00,780 --> 00:24:07,740
+يعني F<sub>N</sub> - m g بتساوي صفر. يعني F<sub>N</sub> -
+
+335
+00:24:07,740 --> 00:24:13,250
+m g. الآن، m g على cos θ / sin θ بتساوي
+
+336
+00:24:13,250 --> 00:24:19,250
+tan θ. -m g tan θ. بعد هيك بنعوض اللي هي
+
+337
+00:24:19,250 --> 00:24:24,050
+الـ a<sub>c</sub>، عشان أوجدها. اللي هي F<sub>c</sub> بتساوي m × a<sub>c</sub>، إذا
+
+338
+00:24:24,050 --> 00:24:28,010
+الـ a<sub>c</sub> بتساوي F<sub>c</sub> على m. بنعوض و بتطلع -g tan
+
+339
+00:24:28,010 --> 00:24:32,830
+θ. الـ a<sub>c</sub> بدها تساوي g، تسعة وثمانية من
+
+340
+00:24:32,830 --> 00:24:36,070
+عشرة، والـ tan 31. بعد هيك ببدأ أوجد سرعة
+
+341
+00:24:36,070 --> 00:24:40,870
+السيارة. طبعا سرعة السيارة من الـ a<sub>c</sub> بتساوي v تربيع
+
+342
+00:24:40,870 --> 00:24:45,570
+على r، بتطلع لـ v = √r × a<sub>c</sub>. طبعا هذه ناقص وهذه
+
+343
+00:24:45,570 --> 00:24:50,730
+ناقص، بتطلع موجب تحت الجذر: 43.1 متر في الثانية.
+
+344
+00:24:54,600 --> 00:24:58,300
+عنا مثال، اللي هي a roller coaster car moving
+
+345
+00:24:58,300 --> 00:25:02,120
+around a circle of radius R. What speed must the
+
+346
+00:25:02,120 --> 00:25:05,100
+car have at the top of the loop so that it will
+
+347
+00:25:05,100 --> 00:25:08,240
+just make it over the top without any assistance
+
+348
+00:25:08,240 --> 00:25:12,340
+from the track. طبعا الشكل هذا السيارة بتتحرك في
+
+349
+00:25:12,340 --> 00:25:16,640
+مسار دائري. اللعبة طبعا بتتحرك في مسار دائري، طبعا
+
+350
+00:25:16,640 --> 00:25:23,040
+منحنى في منطقة معينة هنا. مطلوب مننا نوجد اللي هي
+
+351
+00:25:23,040 --> 00:25:28,410
+السرعة عند  A.  مطلوب مننا نوجد الـ speed at the bottom of
+
+352
+00:25:28,410 --> 00:25:31,230
+the loop. طبعا عندي أنا loop دائرة، لنوجد عند
+
+353
+00:25:31,230 --> 00:25:35,030
+المنطقة هذه السرعة. طبعا عند المنطقة هذه فيها أنا
+
+354
+00:25:35,030 --> 00:25:38,590
+سيارة، وفي عندي مسار. طالما إنه في جسم على المسار
+
+355
+00:25:38,590 --> 00:25:42,190
+إذا في عندي F<sub>N</sub> إلى أعلى، وفي عندي m g إلى أسفل.
+
+356
+00:25:42,190 --> 00:25:45,970
+اتفقنا أن القوة ناحية المركز سالبة، ولطالعة من
+
+357
+00:25:45,970 --> 00:25:50,650
+المركز موجبة.  عفوا، اللي جوا المركز سالبة… موج…
+
+358
+00:25:50,650 --> 00:25:54,960
+سالبة، ولطالعة من المركز موجبة. هنستخدم قانون نيوتن
+
+359
+00:25:54,960 --> 00:26:00,820
+الثاني. إذا m a<sub>c</sub> بتساوي F<sub>N</sub> + m g، اللي هي
+
+360
+00:26:00,820 --> 00:26:06,400
+هي الـ summation للـ F<sub>c</sub>.  F<sub>c</sub> بتساوي m a<sub>c</sub>. بستخدم
+
+361
+00:26:06,400 --> 00:26:12,340
+قانون نيوتن الثاني. إذا F<sub>N</sub> at the top of the
+
+362
+00:26:12,340 --> 00:26:16,520
+loop، إذا حطينا F<sub>N</sub> بتساوي صفر، the force of gravity
+
+363
+00:26:16,520 --> 00:26:19,340
+acts towards the center and provides the
+
+364
+00:26:19,340 --> 00:26:23,470
+centripetal acceleration. بتصير a<sub>c</sub> بتساوي -v تربيع
+
+365
+00:26:23,470 --> 00:26:30,910
+على r. إذا m g بتساوي m v تربيع على r. بنحلها، و
+
+366
+00:26:30,910 --> 00:26:35,890
+بنطلع الـ v at the top. الـ v عند الـ… at the top
+
+367
+00:26:35,890 --> 00:26:44,330
+of the track، أو المسار. v بتساوي √g r. طبعا عند
+
+368
+00:26:44,330 --> 00:26:48,870
+الأسفل الـ F<sub>N</sub> موجودة. Apply conservation of
+
+369
+00:26:48,870 --> 00:26:53,150
+mechanical energy.  بستخدم الـ mechanical energy. طبعا
+
+370
+00:26:53,150 --> 00:26:56,850
+بأوجد اللي هي السرعة.  ½ m v تربيع عند الـ
+
+371
+00:26:56,850 --> 00:27:00,630
+top + m g h. طبعا عند الـ top بيكون لها طاقة وضع
+
+372
+00:27:00,630 --> 00:27:06,290
+وطاقة حركة، اللي هي m g r. الـ r اللي هي البعد
+
+373
+00:27:06,290 --> 00:27:10,730
+العمودي، اللي هي… اللي هي البعد من الـ… من البعد
+
+374
+00:27:10,730 --> 00:27:15,870
+اللي هي نصف القطر. + m g × 2 r بتساوي
+
+375
+00:27:15,870 --> 00:27:20,110
+2.5 m g r. لما أوجد الـ total mechanical energy
+
+376
+00:27:21,500 --> 00:27:25,060
+at the bottom، الـ E<sub>bottom</sub> بيساوي ½ m v تربيع عند
+
+377
+00:27:25,060 --> 00:27:28,460
+الـ bottom، النقطة اللي تحت. The energy is conserved
+
+378
+00:27:28,460 --> 00:27:33,240
+so this energy is made equal and solve for V<sub>bottom</sub>. للـ… للـ
+
+379
+00:27:33,240 --> 00:27:37,900
+bottom. إذا ½ m v تربيع للـ bottom بتساوي 2.5
+
+380
+00:27:37,900 --> 00:27:43,700
+m g r. الـ v للـ bottom بتساوي √5 g r. يعني عند
+
+381
+00:27:43,700 --> 00:27:47,240
+… لما أوجد الـ normal force لـ… للنقطة اللي هي
+
+382
+00:27:47,240 --> 00:27:51,300
+الـ bottom. بدي أوجد الـ F<sub>N</sub>.  عندي m g ناقص الـ
+
+383
+00:27:51,300 --> 00:27:55,080
+F<sub>N</sub>. طبعا الـ m g موجب، هو F<sub>N</sub> سالب، لأن الـ
+
+384
+00:27:55,080 --> 00:27:58,060
+F<sub>N</sub> ناحية المركز، و الـ m g طالع من المركز. هدول
+
+385
+00:27:58,060 --> 00:28:01,300
+الاثنين بدهم يساووا m v² على r، اللي هي القوة
+
+386
+00:28:01,300 --> 00:28:05,760
+المركزية أو القوة المركزية. فمن هنا بنوجد الـ F<sub>N</sub>
+
+387
+00:28:05,760 --> 00:28:09,940
+at the bottom. بنلاحظ إن الـ F<sub>N</sub>
+
+388
+00:28:09,940 --> 00:28:13,520
+بتصرف towards the center of the circle. عبارة…
+
+389
+00:28:13,520 --> 00:28:17,810
+عشان هي ك… هي negative. The car weight acts away
+
+390
+0
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f4382048755a09c8eff86dcf84922e498e00f5ba
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_postprocess.srt
@@ -0,0 +1,1584 @@
+1
+00:00:00,980 --> 00:00:05,800
+بسم الله الرحمن الرحيم section سبعة تلاتة اتنين by
+
+2
+00:00:05,800 --> 00:00:09,440
+one centripetal acceleration التسارع اللي هو
+
+3
+00:00:09,440 --> 00:00:16,200
+المركزي في إن الشكل التالي يوضح سيارة بتتحرك بمصار
+
+4
+00:00:16,200 --> 00:00:21,480
+دائريwith constant linear speed بسرعة خطية ثابتة
+
+5
+00:00:21,480 --> 00:00:24,860
+even though the car move at constant speed it
+
+6
+00:00:24,860 --> 00:00:28,860
+still has an acceleration طالما أنها بتتحرك بسرعة
+
+7
+00:00:28,860 --> 00:00:34,720
+ثابتة بتتحرك بسرعة ثابتة لكن ما زال في إلها تسارع
+
+8
+00:00:34,720 --> 00:00:39,540
+عشان أدرس هذه الظاهرة لإنه إذا مشيت بسرعة خطية ب
+
+9
+00:00:39,540 --> 00:00:43,440
+constant طبعا speed في التسارع بيكون zero لكن هنا
+
+10
+00:00:43,440 --> 00:00:48,780
+التسارع موجودعشان هيك بندرس هذه الظاهرة بنوجد
+
+11
+00:00:48,780 --> 00:00:54,380
+معادلة بتربط بين اللي هي التسارع و ال .. و السرعة
+
+12
+00:00:54,380 --> 00:01:00,740
+خلال .. خلال طبعا حركة دائرية عندنا احنا A average
+
+13
+00:01:00,740 --> 00:01:03,720
+بيسوي V final نخس V initial ع T final نخس T
+
+14
+00:01:03,720 --> 00:01:08,120
+initial طبعا احنا ال bus بيمثل الفرق بين اللي هي
+
+15
+00:01:08,120 --> 00:01:13,670
+delta V V initial و V finalهذا ال vector طبعا have
+
+16
+00:01:13,670 --> 00:01:18,250
+the same magnitude بيمثل the same speed but if
+
+17
+00:01:18,250 --> 00:01:21,350
+they have different direction طبعا هذا بالحركة
+
+18
+00:01:21,350 --> 00:01:25,310
+الخطية لو كان عندي أنا نفس ال .. ال .. السرعة اللي
+
+19
+00:01:25,310 --> 00:01:28,250
+بداية و نفس السرعة النهائية و بالتالي هيكون
+
+20
+00:01:28,250 --> 00:01:32,770
+التسارع zero لكن لو بتحرك باتجاهات مختلفة معنى
+
+21
+00:01:32,770 --> 00:01:37,460
+الكلام أن هو لا يساوي zeroفلو احنا مشيت سيارة بهذا
+
+22
+00:01:37,460 --> 00:01:42,100
+الحركة الدائرية على دور معين طبعا هنا نقطة الدوران
+
+23
+00:01:42,100 --> 00:01:49,000
+هتتحرك طبعا من ال A هنا كأنها نقطة initial السرعة
+
+24
+00:01:49,000 --> 00:01:54,600
+الممسية V initial لو وصلت لنقطة B ومشيت ازاحة
+
+25
+00:01:54,600 --> 00:01:59,340
+دلتاتيتا هكون هنا عندى انا ايضا اللى هى سرعة ممسية
+
+26
+00:01:59,340 --> 00:02:04,250
+طبعا هنا اتجاهها بيختلف عن هذا الاتجاه وبالتاليالـ
+
+27
+00:02:04,250 --> 00:02:08,830
+a في هذه الحالة لاتساوي zero اتجاه السرع زي ما
+
+28
+00:02:08,830 --> 00:02:14,330
+حكينا خلال حركة دائرية بتتغير for a circular
+
+29
+00:02:14,330 --> 00:02:18,090
+motion في الحركة الدائرية at constant speed the
+
+30
+00:02:18,090 --> 00:02:21,650
+acceleration vector always point التسارع دايما
+
+31
+00:02:21,650 --> 00:02:25,970
+بيتجه ناحية المركز زي such as acceleration is
+
+32
+00:02:25,970 --> 00:02:29,570
+called هذا التسارع بيسموه centripetal acceleration
+
+33
+00:02:30,460 --> 00:02:34,460
+its magnitude الان الcentimeter acceleration AC
+
+34
+00:02:34,460 --> 00:02:38,900
+بتساوي V تربيه على R هذه عبارة عن التسارع المركزي
+
+35
+00:02:38,900 --> 00:02:43,240
+هي علاقة اللي هي التسارع المركزي مع السرعة
+
+36
+00:02:43,240 --> 00:02:47,440
+tangential velocity because the tangential
+
+37
+00:02:47,440 --> 00:02:50,260
+velocity is related to the angular velocity طبعا
+
+38
+00:02:50,260 --> 00:02:54,260
+في علاقة بين ال V و ال Omega ف V tangential كانت
+
+39
+00:02:54,260 --> 00:03:00,040
+بتساوي R في Omegaإذا ال .. ال alternate .. يعني ال
+
+40
+00:03:00,040 --> 00:03:07,580
+alternate هنا un .. alternate form فده الحالة بده
+
+41
+00:03:07,580 --> 00:03:12,220
+يساوي اللي هي V tangential بساوي R في Omega لما
+
+42
+00:03:12,220 --> 00:03:15,540
+بده أعوض إذا ال A .. A C بساوي R تربيع في Omega
+
+43
+00:03:15,540 --> 00:03:19,060
+تربيع على R يعني R في Omega تربيع يعني ممكن نحكي A
+
+44
+00:03:19,060 --> 00:03:22,580
+C بساوي V تربيع على R أو A C بساوي R في Omega
+
+45
+00:03:23,040 --> 00:03:27,540
+physically فزيائيا اللي هي ال acceleration تحدث
+
+46
+00:03:27,540 --> 00:03:32,660
+only if some force is present وجود القوة for
+
+47
+00:03:32,660 --> 00:03:36,160
+example ف if a car travel in a circle on flat
+
+48
+00:03:36,160 --> 00:03:41,120
+ground الآن إذا السيارة بدها تدور على طبعا منحنى
+
+49
+00:03:41,120 --> 00:03:45,620
+أو دوار flat مستويففي عندنا ال force of static
+
+50
+00:03:45,620 --> 00:03:48,240
+frictional القوة اللي بتخلي السيارة تدور حركة
+
+51
+00:03:48,240 --> 00:03:52,500
+دائرية هي عبارة عن قوة الاحتكاك الساكن قوة
+
+52
+00:03:52,500 --> 00:03:56,640
+الاحتكاك الساكن هي طبعا متجهة ناحية المركز بيسموها
+
+53
+00:03:56,640 --> 00:04:01,400
+centripetal force طبعا ال AC in equation طبعا ال
+
+54
+00:04:01,400 --> 00:04:04,680
+AC اللي هي centripetal acceleration بتمثل only the
+
+55
+00:04:04,680 --> 00:04:07,180
+magnitude تمثل فقط ال magnitude لcentripetal
+
+56
+00:04:07,180 --> 00:04:11,130
+acceleration لتسرع المركزيال acceleration itself
+
+57
+00:04:11,130 --> 00:04:14,510
+is always directed toward the center, centripetal
+
+58
+00:04:14,510 --> 00:04:17,730
+اللي هي centripetal acceleration تسارع المركزي
+
+59
+00:04:17,730 --> 00:04:21,850
+بيتجه دائما ناحية المركز the foregoing
+
+60
+00:04:21,850 --> 00:04:27,150
+clarification concern a circular motion at
+
+61
+00:04:27,150 --> 00:04:29,790
+constant speed when an object moves in a circle
+
+62
+00:04:29,790 --> 00:04:33,830
+but is speeding up or slowing down tangential
+
+63
+00:04:33,830 --> 00:04:38,090
+component of the acceleration فAT بالساوة ال R في
+
+64
+00:04:38,090 --> 00:04:42,190
+ال alphait's also present because the tangential
+
+65
+00:04:42,190 --> 00:04:45,110
+and centripetal component of acceleration are
+
+66
+00:04:45,110 --> 00:04:49,190
+perpendicular to each other ال tangential ..
+
+67
+00:04:49,190 --> 00:04:54,610
+tangential and centripetal component المركبة اللي
+
+68
+00:04:54,610 --> 00:04:58,090
+.. اللي هي ال a tangential و ال a centripetal يعني
+
+69
+00:04:58,090 --> 00:05:02,610
+التسارع المركزي و التسارع المماسي متعمدين على بعض
+
+70
+00:05:02,610 --> 00:05:06,730
+لإن التسارع المماسي طبعا مماس للدائرة و التسارع
+
+71
+00:05:06,730 --> 00:05:09,670
+المركزي ناحية المركزو بالتالي التانين المتعمدين
+
+72
+00:05:09,670 --> 00:05:13,970
+على بعض لإن ده إيجاد التسارق الكلي عشان التانين
+
+73
+00:05:13,970 --> 00:05:17,110
+المتعمدين على بعض فالإيه الكلي بيساوي جزر ال
+
+74
+00:05:17,110 --> 00:05:20,370
+tangential تربية زائد ال AC تربية بالاستخدام اللي
+
+75
+00:05:20,370 --> 00:05:26,350
+هي نظرية Field of Work طبعا هذه كلها بنعرف فيها
+
+76
+00:05:26,350 --> 00:05:29,880
+اللي هي التسارق المركزيNigella race track is
+
+77
+00:05:29,880 --> 00:05:34,700
+construct such that two arc of radius في عندي طبعا
+
+78
+00:05:34,700 --> 00:05:40,180
+حركة في قوس تمانين متر at A واتحركت أربعين متر at
+
+79
+00:05:40,180 --> 00:05:45,740
+B are joined by two stretch of straight track in
+
+80
+00:05:45,740 --> 00:05:50,580
+figure سبعة تمانية in a particular trail run
+
+81
+00:05:50,580 --> 00:05:54,840
+driver travels at a constant speed of خمسين متر
+
+82
+00:05:54,840 --> 00:05:59,140
+for one complete lapthe ratio of the tangential
+
+83
+00:05:59,140 --> 00:06:05,120
+acceleration at A to that at B is بدي أنا اللي هي
+
+84
+00:06:05,120 --> 00:06:10,140
+ال ratio of tangential بالنسبة ل .. اللي هي النسبة
+
+85
+00:06:10,140 --> 00:06:14,900
+بين ال tangential acceleration عند النقطة Aلا
+
+86
+00:06:14,900 --> 00:06:19,380
+النقطة B بدها تساوي طبعا اللي هي عبارة عن
+
+87
+00:06:19,380 --> 00:06:23,280
+tangential acceleration ال zero at both point
+
+88
+00:06:23,280 --> 00:06:28,580
+tangential acceleration بتساوي zero in .. يعني
+
+89
+00:06:28,580 --> 00:06:35,560
+اللي في كده النقاط اللي هو احنا انا شكل .. الشكل
+
+90
+00:06:35,560 --> 00:06:40,930
+كما هو موضح بشكلسبعة تمانية figure سبعة تمانية لو
+
+91
+00:06:40,930 --> 00:06:47,390
+نرجعله figure سبعة تمانية ان شاء الله figure سبعة
+
+92
+00:06:47,390 --> 00:06:49,170
+تمانية طبعا هو موضح في الكتاب
+
+93
+00:07:12,230 --> 00:07:17,050
+عموما .. عموما طبعا هو موجود في الكتاب، الآن
+
+94
+00:07:17,050 --> 00:07:22,430
+racetrack يعني فيه انما سار Constructed to ears of
+
+95
+00:07:22,430 --> 00:07:28,930
+radiusمسار بتمشي فيه طبعا جسم معين أو سيارة بي ..
+
+96
+00:07:28,930 --> 00:07:33,370
+طبعا بحرك على طبعا قوس تمانين متر عند النقطة A and
+
+97
+00:07:33,370 --> 00:07:36,990
+أربعين متر عند النقطة B are joined by two stretch
+
+98
+00:07:36,990 --> 00:07:40,850
+of straight track as الفجر طبعا الفجر موجود بس مش
+
+99
+00:07:40,850 --> 00:07:46,990
+موجود هنا in a particular trail run driver travels
+
+100
+00:07:46,990 --> 00:07:51,470
+at a constant speed SBC طبعا السائقبتحرك ب
+
+101
+00:07:51,470 --> 00:07:55,990
+constant speed بسرعة خمسين متر في التانية طبعا لما
+
+102
+00:07:55,990 --> 00:08:00,850
+يتحرك ب constant speed طبعا اذا كان انا بدي
+
+103
+00:08:00,850 --> 00:08:06,170
+التسارع ال .. التسارع ال tangential مع أن الكلام
+
+104
+00:08:06,170 --> 00:08:10,910
+انه التسارع الممسي هيكون عندنا zero لإنه بيتحرك ب
+
+105
+00:08:10,910 --> 00:08:14,850
+constant speed زي هو طبعا ال ratio of tangential
+
+106
+00:08:14,850 --> 00:08:18,490
+acceleration to the .. at B من A لB طبعا هيكون
+
+107
+00:08:18,490 --> 00:08:22,890
+عندي أنا zeroاللي هي الجواب a لكن الآن ال ratio of
+
+108
+00:08:22,890 --> 00:08:27,570
+the centripetal acceleration at a to b لما أحسب ال
+
+109
+00:08:27,570 --> 00:08:32,170
+tangential acceleration هو بتحرك حركة .. بتتحرك
+
+110
+00:08:32,170 --> 00:08:36,450
+حركة دائرية ال tangential اللي هي اللي عند نقطة a
+
+111
+00:08:36,450 --> 00:08:39,550
+و لا نقطة b بتساوي zero لإنه بتحرك ب constant
+
+112
+00:08:39,550 --> 00:08:42,950
+speed لكن لما أجى أحسب ال centripetal acceleration
+
+113
+00:08:42,950 --> 00:08:48,970
+من النقطة a ل ال b بلاحظ أنه هو بيساوي طبعا بيساوي
+
+114
+00:08:48,970 --> 00:08:53,270
+نصنص من النقطة A ل B لإنه في عندي انا في تربية على
+
+115
+00:08:53,270 --> 00:08:57,810
+.. على R و ال R هي اللي بتحدد واحدة نص التانية
+
+116
+00:08:57,810 --> 00:09:01,930
+بدهوا ال angular speed is greatest at .. ال
+
+117
+00:09:01,930 --> 00:09:06,770
+angular speed is greatest عند النقطة B ال angular
+
+118
+00:09:06,770 --> 00:09:13,160
+speed is greatest at النقطة Bالكوز التاني an
+
+119
+00:09:13,160 --> 00:09:15,740
+object move in a circular path جسم بتحرك حركة
+
+120
+00:09:15,740 --> 00:09:19,480
+دائرية ب constant speed which the flow .. meaning
+
+121
+00:09:19,480 --> 00:09:24,340
+الجمال الآن is .. اللي هي is true بالنسبة للجسم،
+
+122
+00:09:24,340 --> 00:09:29,900
+هل سرعتها ثابتة، هل التسارع بتغير، هل التسارع طبعا
+
+123
+00:09:29,900 --> 00:09:34,660
+constant و ال velocity changing و لا both its طبعا
+
+124
+00:09:34,660 --> 00:09:38,090
+velocity and acceleration are changingوالا its
+
+125
+00:09:38,090 --> 00:09:40,590
+velocity and acceleration remain constant الآن
+
+126
+00:09:40,590 --> 00:09:44,670
+بتحرك حركة دائرية بتحرك حركة دائرية ب constant
+
+127
+00:09:44,670 --> 00:09:47,430
+speed which of the following statement مين الجملة
+
+128
+00:09:47,430 --> 00:09:51,270
+ده صحيحة الجملة الأولى its velocity is constant
+
+129
+00:09:51,270 --> 00:09:57,950
+سرعتها ثابتة لكن التسارع بتغير الآن التسارع ثابت
+
+130
+00:09:57,950 --> 00:10:01,430
+والسرعة بتتغير و لا both its velocity and
+
+131
+00:10:01,430 --> 00:10:04,730
+acceleration are changing طبعافي الحركة الدائرية
+
+132
+00:10:04,730 --> 00:10:08,050
+both its velocity and acceleration are changing
+
+133
+00:10:08,050 --> 00:10:11,610
+لإن ال velocity بتغير اتجاهها في كل نقطة و التسرع
+
+134
+00:10:11,610 --> 00:10:14,050
+بتتغير بناء على ال velocity اللى نفسها و V تربية
+
+135
+00:10:14,050 --> 00:10:19,090
+على ال R فالجواب الصحي هو C لإيه both its velocity
+
+136
+00:10:19,090 --> 00:10:24,930
+and acceleration are exchanging example سبعة خمسة
+
+137
+00:10:24,930 --> 00:10:32,770
+في عندنا راس كسيارة سباق accelerateuniformally
+
+138
+00:10:32,770 --> 00:10:37,850
+تتحرك بانتظام طبعا من سرعة أربعين متر في الثاني
+
+139
+00:10:37,850 --> 00:10:41,810
+إلى سرعة ستين في زمن قدره خمسة while traveling
+
+140
+00:10:41,810 --> 00:10:44,910
+counterclockwise طبعا هيتحركت حركة دائرية عكس
+
+141
+00:10:44,910 --> 00:10:49,170
+عقارب الساعة خلال ال radius أربعة في عشر أو ستين
+
+142
+00:10:49,170 --> 00:10:53,850
+متر when the car reach speed of خمسين لما السيارة
+
+143
+00:10:53,850 --> 00:10:58,700
+توصل لهاسرعة خمسين احسب calculate the magnitude of
+
+144
+00:10:58,700 --> 00:11:01,580
+the car's centripetal acceleration طبعا نحسب
+
+145
+00:11:01,580 --> 00:11:04,380
+الcentripetal acceleration V تربيع على نحسب
+
+146
+00:11:04,380 --> 00:11:08,460
+الcentripetal acceleration ال V عندي خمسين و ال R
+
+147
+00:11:08,460 --> 00:11:13,080
+كانت أربعة ال N أسي بالساوي خمسين على أربعة طبعا
+
+148
+00:11:13,080 --> 00:11:15,640
+خمسين تربيع لإن هو V تربيع على أربعة بطلع ستة
+
+149
+00:11:15,640 --> 00:11:19,260
+point اتنين خمس متر في الثانية تربيع في B ب
+
+150
+00:11:19,260 --> 00:11:22,180
+calculate the angular velocity طبعا طالما احنا
+
+151
+00:11:22,180 --> 00:11:25,330
+عرفنا ال V موجودة و ال R موجودةالعلاقة ال ال
+
+152
+00:11:25,330 --> 00:11:29,570
+linear في ال angular omega بالساوي V على AR اللي
+
+153
+00:11:29,570 --> 00:11:32,830
+هي خمسين على R في عشر عصر اتنين متر تطلع point
+
+154
+00:11:32,830 --> 00:11:37,670
+واحد اتنين خمس راد per second في C calculate the
+
+155
+00:11:37,670 --> 00:11:40,790
+magnitude of the tangential acceleration ال
+
+156
+00:11:40,790 --> 00:11:43,210
+tangential acceleration اللي هي Delta V ع Delta T
+
+157
+00:11:43,210 --> 00:11:48,520
+V final كانت ستينov initial 40 و delta t 5 بطلع 4
+
+158
+00:11:48,520 --> 00:11:52,200
+متر في الثانية تربيع بعد هيك ا calculate the
+
+159
+00:11:52,200 --> 00:11:55,740
+magnitude of the total acceleration بدنا نحسب ال
+
+160
+00:11:55,740 --> 00:11:59,040
+total acceleration اللي عبارة عن a tangential
+
+161
+00:11:59,040 --> 00:12:03,620
+تربيع زايد ال a c تربيع ال a جزر a t تربيع زايد a
+
+162
+00:12:03,620 --> 00:12:07,700
+c تربيع بتسوى 4 تربيع زايد 6.25 تربيع اللي احنا
+
+163
+00:12:07,700 --> 00:12:11,500
+وجدناهم سابقا بتلع ال total acceleration بتسوى 7
+
+164
+00:12:11,500 --> 00:12:17,920
+.42 متر في الثانية تربيعsection 7-4 newtons second
+
+165
+00:12:17,920 --> 00:12:21,360
+law for uniform circular motion قانون نيوتن التانى
+
+166
+00:12:21,360 --> 00:12:26,260
+للحركة الدائرية المتضامة نيوتونس second law قانون
+
+167
+00:12:26,260 --> 00:12:30,280
+نيوتن التانى للحركة ممكن انه احنا طبعا نستخدمه
+
+168
+00:12:30,280 --> 00:12:35,370
+علشان احلمسائل تتضمن الحركة الدائرية in the case
+
+169
+00:12:35,370 --> 00:12:38,170
+of the uniform circular motion في حالة الحركة
+
+170
+00:12:38,170 --> 00:12:42,990
+الدائرية المنتظمة قانون نيوتن التاني will feature
+
+171
+00:12:42,990 --> 00:12:45,790
+the centripetal acceleration and variability of
+
+172
+00:12:45,790 --> 00:12:50,100
+the radial forceفي عندي طبعا هتظهر عندي مجموعة قوة
+
+173
+00:12:50,100 --> 00:12:53,100
+بتساوي ال M في A هذا قانونية من التاني فبيظهر عندي
+
+174
+00:12:53,100 --> 00:12:57,160
+Radial force في قوة مركزية that are either
+
+175
+00:12:57,160 --> 00:13:01,700
+directed .. القوة المركزية ممكن تكون تتجه towards
+
+176
+00:13:01,700 --> 00:13:05,600
+or away from the center ممكن تتجه داخل المركز أو
+
+177
+00:13:05,600 --> 00:13:10,140
+خارج من المركز نيجي نوضح هذا الكلام في section
+
+178
+00:13:10,140 --> 00:13:14,900
+سبعة أربعة واحدال forces causes centripetal
+
+179
+00:13:14,900 --> 00:13:20,360
+acceleration ال un .. un object أي جسم بتحرك حركة
+
+180
+00:13:20,360 --> 00:13:23,620
+بيت in centripetal acceleration only if some
+
+181
+00:13:23,620 --> 00:13:28,500
+external force acts on in لما يتحرك في تسارع مركزي
+
+182
+00:13:28,500 --> 00:13:34,060
+بحس أنه فيه قوة خارجية أثرت عليه for a ball
+
+183
+00:13:34,060 --> 00:13:36,560
+whirling in a circle at the end of the string لو
+
+184
+00:13:36,560 --> 00:13:41,930
+أنا مساكت كرة و ربطتها في خيط و حركت حركة دائريةلح
+
+185
+00:13:41,930 --> 00:13:44,990
+يكون في هناك قوة شد that the force is the tension
+
+186
+00:13:44,990 --> 00:13:47,790
+in the string في قوة شد in the case of the car
+
+187
+00:13:47,790 --> 00:13:51,590
+برضه moving إذا كان السيارة تتحرك حركة دائرية على
+
+188
+00:13:51,590 --> 00:13:56,720
+سطح flat ففي عندي أنا قوة الاحتكاك الساكنبين
+
+189
+00:13:56,720 --> 00:13:59,960
+الإجال وبين السيارة هي اللي بتخلي السيارة تتحرك
+
+190
+00:13:59,960 --> 00:14:03,880
+حركة دائرية منتظمة كمان في عندي حركة اللي هي ال
+
+191
+00:14:03,880 --> 00:14:08,400
+satellite الحركة اللي هي الأقمار الصناعية الحركة
+
+192
+00:14:08,400 --> 00:14:11,980
+المدارية حوالين الأرض has برضه بتحيه عبارة عن
+
+193
+00:14:11,980 --> 00:14:15,020
+التحرك اللي هي تسارع مركزي centripetal
+
+194
+00:14:15,020 --> 00:14:19,300
+acceleration بسبب قوة الجذب العام بين ال satellite
+
+195
+00:14:19,300 --> 00:14:23,040
+وبين الأرض some books used ممكن في كتب تستخدم
+
+196
+00:14:23,040 --> 00:14:28,390
+centripetal forceو في كتب تستخدم اللي هي ال .. ال
+
+197
+00:14:28,390 --> 00:14:32,930
+.. ال radial force أو centripetal force طبعا هي
+
+198
+00:14:32,930 --> 00:14:38,170
+نفس ال .. نفس المعنى ولكن واحدة عكس التانية لأ
+
+199
+00:14:38,170 --> 00:14:41,550
+this is not the case that a jacket centripetal in
+
+200
+00:14:41,550 --> 00:14:46,170
+centripetal force simply means that the force in a
+
+201
+00:14:46,170 --> 00:14:49,230
+cushion acts towards the center ال centripetal
+
+202
+00:14:49,230 --> 00:14:52,150
+force هي معناها أن القوة اللي هي مؤثرة ناحية
+
+203
+00:14:52,150 --> 00:14:56,160
+المركزthe force of tension بالنسبة لا ال string
+
+204
+00:14:56,160 --> 00:14:59,580
+اللى هى عبارة عن قوة الشدف الحبل هى عبارة عن قوة
+
+205
+00:14:59,580 --> 00:15:04,700
+مركزية كمان بالنسبة لا ال vertical circle in an
+
+206
+00:15:04,700 --> 00:15:07,900
+example centripetal force as in the force of
+
+207
+00:15:07,900 --> 00:15:11,960
+gravity برضه عبارة عن قوة الجاذبية بالنسبة لا
+
+208
+00:15:11,960 --> 00:15:15,670
+الستالاية اللى بدور حوالين الأرضconsider a pack of
+
+209
+00:15:15,670 --> 00:15:22,130
+mass M لو عندي أنا طبعا كتلة M مربوطة بخيط اتحرك
+
+210
+00:15:22,130 --> 00:15:27,530
+حركة دائرية زي ما هو موضح بالشكل طبعا بتدور بسرعة
+
+211
+00:15:27,530 --> 00:15:32,930
+ثابتة هذا الحركة دي هي حركة horizontal يعني الحركة
+
+212
+00:15:32,930 --> 00:15:38,430
+ال horizontal ولكن دائرية كما هو موضح بالشكل فطبعا
+
+213
+00:15:38,430 --> 00:15:42,570
+لهي الشخص وهي الحبل اتحرك حركة دائرية horizontal
+
+214
+00:15:42,570 --> 00:15:47,430
+في عندي أنا شدناحية المركز بيسموها ده هي
+
+215
+00:15:47,430 --> 00:15:50,090
+الcentrifugal force القوة ناحية المركز هي قوة
+
+216
+00:15:50,090 --> 00:15:53,990
+الcentrifugal force هي قوة الشد وفي المنطقة ده في
+
+217
+00:15:53,990 --> 00:15:59,970
+عندي أنا سرعة ممسية tangential force لأن why why
+
+218
+00:15:59,970 --> 00:16:03,570
+does the puck move in a circle طبعا هي بتتحرك حركة
+
+219
+00:16:03,570 --> 00:16:06,130
+دائرية بسبب وجود القوة المركزية هي اللي بتخليها
+
+220
+00:16:06,130 --> 00:16:09,590
+تتحرك حركة دائرية منتظمة because of its inertia
+
+221
+00:16:09,590 --> 00:16:13,390
+the tendency of the puck is to move in a straight
+
+222
+00:16:13,390 --> 00:16:17,750
+lineبأي حال the string prevent motion along the
+
+223
+00:16:17,750 --> 00:16:21,810
+straight line لإنه هي بتتحرك حركة دائرية ممكن
+
+224
+00:16:21,810 --> 00:16:24,370
+أحركها و أتركها بتستمر في الحركة نتيجة اللي هي
+
+225
+00:16:24,370 --> 00:16:29,570
+القصور الذاتى الالث by extending a radial force on
+
+226
+00:16:29,570 --> 00:16:32,990
+the puck a tension force that make it follow the
+
+227
+00:16:32,990 --> 00:16:36,030
+circular path في عندي حركة دائرية في مسار دائري
+
+228
+00:16:36,030 --> 00:16:40,430
+الشد هذا directed towards the center وبالتالي في
+
+229
+00:16:40,430 --> 00:16:44,480
+أبقى تمثل عن اللي هي الحركة المركزيةالحركة ال
+
+230
+00:16:44,480 --> 00:16:47,680
+centripetal force بتساوي ال MAC بتساوي ال MV تربيع
+
+231
+00:16:47,680 --> 00:16:52,000
+على R FC بيسموها centripetal أو net centripetal
+
+232
+00:16:52,000 --> 00:16:55,460
+force ال net force causing centripetal
+
+233
+00:16:55,460 --> 00:16:58,320
+acceleration هذه القوة المركزية بتسبب التسارق
+
+234
+00:16:58,320 --> 00:17:02,540
+المركزي اللي هو اتجاهه ناحية المركز and effects
+
+235
+00:17:02,540 --> 00:17:04,900
+change in the direction of the velocity vector
+
+236
+00:17:04,900 --> 00:17:09,700
+بيأثر على حركة او اتجاه اللي هي من تجاه السرعة if
+
+237
+00:17:09,700 --> 00:17:13,820
+that force should vanishإذا كان السرعة هذه أو
+
+238
+00:17:13,820 --> 00:17:17,460
+القوة انتهت the object would immediately leave its
+
+239
+00:17:17,460 --> 00:17:20,600
+circular path and move along the straight إذا هذه
+
+240
+00:17:20,600 --> 00:17:25,560
+القوة المركزية أو القوة هذه تلاشت فالجسم بيرجع
+
+241
+00:17:25,560 --> 00:17:30,340
+بتحرك حركة كأنها خط مستقيم مماسي لاللي هي الحركة
+
+242
+00:17:30,340 --> 00:17:34,220
+الأساسية اللي هي ال circular a radial force is a
+
+243
+00:17:34,220 --> 00:17:39,320
+vector القوة المركزية اللي هي إنتاجها عند نص الخطر
+
+244
+00:17:39,320 --> 00:17:43,210
+ال radialعبارة عن قوة متجهة and has direction the
+
+245
+00:17:43,210 --> 00:17:47,250
+second law for uniform circular motion involve
+
+246
+00:17:47,250 --> 00:17:50,250
+force that are directed either towards or the
+
+247
+00:17:50,250 --> 00:17:54,070
+center طبعا في عندي أنواعين من القوة ناحية المركز
+
+248
+00:17:54,070 --> 00:17:57,670
+وطالة عن المركز ال force acting ال force اللي بتثق
+
+249
+00:17:57,670 --> 00:18:03,450
+تؤثر داخل المركز باعتبرها negative و القوة اللي
+
+250
+00:18:03,450 --> 00:18:09,250
+بتأثر خارج المركز باعتبرها positivethe centripetal
+
+251
+00:18:09,250 --> 00:18:11,930
+acceleration is negative الآن الcentripetal
+
+252
+00:18:11,930 --> 00:18:15,590
+acceleration القوة المركزية بناء على ما ذكر تعتبر
+
+253
+00:18:15,590 --> 00:18:21,170
+سالبة لإنها تؤثر ناحية المركز قانون نيوتن التاني
+
+254
+00:18:21,170 --> 00:18:25,270
+لل uniform circular motion ممكن أكتبه بهذا الشكل
+
+255
+00:18:25,270 --> 00:18:29,370
+summation للأفقار بتساوي ناخص mv تربيع على r هذي
+
+256
+00:18:29,370 --> 00:18:32,050
+بيسموها ال radial force summation لل radial force
+
+257
+00:18:32,480 --> 00:18:35,380
+بتساوى ناقص mv تربيع على r في ال radial force
+
+258
+00:18:35,380 --> 00:18:38,800
+القوة اللى ناحية المركز سالبة و اللى خارجها من
+
+259
+00:18:38,800 --> 00:18:43,640
+المركز تعتبر موجبة الاف R بيسموها ال radial force
+
+260
+00:18:43,640 --> 00:18:49,120
+acting on the mass m positive if the force is away
+
+261
+00:18:49,120 --> 00:18:53,520
+from the center and negative if the force is
+
+262
+00:18:53,520 --> 00:18:57,280
+towards the center بالنسبة لها ال استراتيجية كيف
+
+263
+00:18:57,280 --> 00:19:00,580
+ممكن نحل مسائل بالنسبة لها ال centripetal
+
+264
+00:19:00,580 --> 00:19:04,300
+accelerationبنستخدم هاي الخطوات التالية بنرسم ال
+
+265
+00:19:04,300 --> 00:19:08,500
+free body diagram و بنرسم القوة المحاور و بنرسم
+
+266
+00:19:08,500 --> 00:19:14,040
+القوة المؤثرة على كل طبعا على الجسم بالنسبة لل net
+
+267
+00:19:14,040 --> 00:19:17,220
+force Fc towards the center ال Fc بتساوي summation
+
+268
+00:19:17,220 --> 00:19:21,620
+لل Fr ال Fr is the sum of the radial component
+
+269
+00:19:21,620 --> 00:19:26,120
+this net radial force ببستخدم بعد هي كده summation
+
+270
+00:19:26,120 --> 00:19:29,520
+للقوة بتساوي اللي هي ال ال .. اللي هي ال MV
+
+271
+00:19:29,520 --> 00:19:33,010
+squared على Rيعني ال F R بيستوى ال M في AC و ال F
+
+272
+00:19:33,010 --> 00:19:36,830
+T بيستوى ال M في TT و ال F N بيستوى ال M في AN حسب
+
+273
+00:19:36,830 --> 00:19:41,290
+ال F و حسب التسارع ال magnitude of the centripetal
+
+274
+00:19:41,290 --> 00:19:44,430
+acceleration for the uniform circular motion
+
+275
+00:19:44,430 --> 00:19:48,390
+بيستوى V تربيه على R بعد هيك بنحل المثلة و بنوجد
+
+276
+00:19:48,390 --> 00:19:54,270
+المتغيرات ناخد هذا السؤال عندي سيارة is a car
+
+277
+00:19:54,270 --> 00:19:59,300
+travel at constant speed تلاتين ميل في الساعةon
+
+278
+00:19:59,300 --> 00:20:03,340
+level circular 10 of radius 50 تتحرك بسرعة 30 ميل
+
+279
+00:20:03,340 --> 00:20:08,780
+في الساعة يعني 13.4 متر في الثانية على مستوى دائري
+
+280
+00:20:08,780 --> 00:20:15,360
+طبعا ب radius 50 متر طبعا shown in the paired eye
+
+281
+00:20:15,360 --> 00:20:21,260
+view كأنه يعني هي in focus مركزة يعني كأنه طائر
+
+282
+00:20:21,260 --> 00:20:25,130
+بيطير وشايف الوضعwhat minimum coefficient of
+
+283
+00:20:25,130 --> 00:20:29,810
+static friction mus between the tires and the
+
+284
+00:20:29,810 --> 00:20:32,870
+roadway will allow the car to make the circular
+
+285
+00:20:32,870 --> 00:20:38,230
+turn without sliding بدي معامل احتكاك الساكن اللي
+
+286
+00:20:38,230 --> 00:20:42,730
+بين العجلات وبين الأرض بيخلي السيارة تتحرك حركة
+
+287
+00:20:42,730 --> 00:20:47,510
+دائرية منتظمة طبعا هي الشكل عندنا احنا الشكل من
+
+288
+00:20:47,510 --> 00:20:52,010
+أعلى كأنه يعني طائر بينظر إلى أعلى هد السيارة على
+
+289
+00:20:52,010 --> 00:20:55,960
+الأرضالسيارة ده تدور بهذا ال .. على ال curve طبعا
+
+290
+00:20:55,960 --> 00:20:59,620
+في قوة بتمنعها انها تتحرك قوة الاحتكاك الساكن هي
+
+291
+00:20:59,620 --> 00:21:02,320
+اللي بتحافظ على انها .. انها ما .. لا تنزلق هذه
+
+292
+00:21:02,320 --> 00:21:08,100
+السيارة و طبعا .. طبعا بتلف او بتدور حوالي .. في
+
+293
+00:21:08,100 --> 00:21:12,540
+مسار دائر أو بتتحرك مسار دائر منتظم بنكتب اللي هي
+
+294
+00:21:12,540 --> 00:21:16,880
+.. بنستخدم قانون و تن التاني و بنحكي انه اللي هي
+
+295
+00:21:16,880 --> 00:21:21,330
+mv squared على r بتها تساويميو أس في ال normal
+
+296
+00:21:21,330 --> 00:21:24,570
+اللي هي الأف أس القوة هذه اللي هي الأف أس هي القوة
+
+297
+00:21:24,570 --> 00:21:27,790
+المركزية القوة الأس الأف أس هي القوة المركزية
+
+298
+00:21:27,790 --> 00:21:30,750
+summation للأف أر بتساوي ناقص mv squared على r
+
+299
+00:21:30,750 --> 00:21:34,370
+والأف أر بتساوي ناقص ميو أس في ال normal ال normal
+
+300
+00:21:34,370 --> 00:21:37,970
+بتساوي ال mg إذا ال normal ناقص ال mg بتساوي zero
+
+301
+00:21:37,970 --> 00:21:42,690
+هذا ال vertical component وبنعود عن اللي هي ال
+
+302
+00:21:42,690 --> 00:21:46,630
+normal بتساوي ال mg ال m بتساوي ناقص ال m وال سالب
+
+303
+00:21:46,630 --> 00:21:50,560
+بتروح مع السالب بتطلع عندىالـ mu s بتساوي V تربيه
+
+304
+00:21:50,560 --> 00:21:56,680
+على R في G V أطانيها 13.4 تربيه على ال R 50 وال G
+
+305
+00:21:56,680 --> 00:22:02,920
+9.8 بتطلع mu s 0.366 دوغمها اسمه معامل احتكاك
+
+306
+00:22:02,920 --> 00:22:07,700
+الساكن الذي يجعل السيارة تدور حركة دائرية منطقة
+
+307
+00:22:07,700 --> 00:22:13,420
+نجل نوع تاني من الأسئلة بيسموها اللي هي banquet
+
+308
+00:22:13,420 --> 00:22:18,960
+roadاللي هي سيارة بتدور على يعني طريق دائري
+
+309
+00:22:18,960 --> 00:22:23,520
+pancadi يعني طريق عالي شوية منحضر ودائري with
+
+310
+00:22:23,520 --> 00:22:27,340
+maximum radius ال radius كانت تلت مية وست عشر متر
+
+311
+00:22:27,340 --> 00:22:31,000
+if a car negotiated the curve too slowly طبعا
+
+312
+00:22:31,000 --> 00:22:35,560
+السيارة بدها تدور على المنحنة بكل بطوء حتى تستطيع
+
+313
+00:22:35,560 --> 00:22:40,070
+انها تدور على المنحنةدورة او .. او مسار دائري it
+
+314
+00:22:40,070 --> 00:22:44,450
+tends to slip down the incline of the turn طبعا
+
+315
+00:22:44,450 --> 00:22:50,430
+بتميل انها بتدور حوالين مسار يعني ميل منحدر ميل
+
+316
+00:22:50,430 --> 00:22:56,730
+بزاوية معينة و بتحاول انها تسرق في .. في هذا
+
+317
+00:22:56,730 --> 00:23:01,020
+المسار و تدور حركة دائرية في هذه الحالةمطلوب مننا
+
+318
+00:23:01,020 --> 00:23:06,460
+نوجد اللى هى centripetal acceleration ونوجد اللى
+
+319
+00:23:06,460 --> 00:23:12,160
+هى سرعة السيارة مع اهمال الاحتكاك طبعا هى السيارة
+
+320
+00:23:12,160 --> 00:23:15,210
+هى المستوى المايل و هى بدأ تدور حركة دائريةالحركة
+
+321
+00:23:15,210 --> 00:23:18,130
+الدائرية بهذا الشكل طبعا في هذا السؤال احنا
+
+322
+00:23:18,130 --> 00:23:21,370
+مابنحلل ال mg لأنه اذا حللنا ال mg هييجي بهذا
+
+323
+00:23:21,370 --> 00:23:24,130
+الاتجاه وهذا الاتجاه بعيدا عن الحركة الدائرية
+
+324
+00:23:24,130 --> 00:23:28,250
+الحركة الدائرية بهذا الشكل هنا هيك اذا راح احلل ال
+
+325
+00:23:28,250 --> 00:23:33,050
+normal راح نحلل ال normal إلى قوتين هنا اللي هو ال
+
+326
+00:23:33,050 --> 00:23:38,070
+n sin θ و هنا في ال vertical n cos θ الخوة الداخلة
+
+327
+00:23:38,070 --> 00:23:41,430
+ناحية المركز هي عبارة عن ال n بهذا الاتجاه اللي هي
+
+328
+00:23:41,430 --> 00:23:42,390
+n sin θ
+
+329
+00:23:51,840 --> 00:23:54,700
+الان ناقص الام جي بالساوة zero يعني الان ناقص الام
+
+330
+00:23:54,700 --> 00:23:55,440
+جي بالساوة zero يعني الان ناقص الام جي بالساوة
+
+331
+00:23:55,440 --> 00:23:56,420
+zero يعني الان ناقص الام جي بالساوة zero يعني الان
+
+332
+00:23:56,420 --> 00:23:57,320
+الام جي بالساوة zero يعني الان ناقص الام جي
+
+333
+00:23:57,320 --> 00:24:00,780
+بالساوة zero يعني الان ناقص الام جي بالساوة zero
+
+334
+00:24:00,780 --> 00:24:07,740
+يعني الان ناقص الام جي بالساوة zero يعني الان ناقص
+
+335
+00:24:07,740 --> 00:24:13,250
+الامالان mg على cosine ساين على كوزاين بتساوي
+
+336
+00:24:13,250 --> 00:24:19,250
+التان ناقص mg تان ال theta بعد هيك بنعوض اللي هي
+
+337
+00:24:19,250 --> 00:24:24,050
+ال ac عشان اوجدها اللي هي fc بتساوي ال m في ac اذا
+
+338
+00:24:24,050 --> 00:24:28,010
+ال ac بتساوي ال fc على m بنعوض و بتطلع ناقص g تان
+
+339
+00:24:28,010 --> 00:24:32,830
+ال theta ال ac بدها تساوي ال g تسعة و تمانية من
+
+340
+00:24:32,830 --> 00:24:36,070
+عشرة و التان واحد تلاتين بعد هيك بدأ اوجد سرعة
+
+341
+00:24:36,070 --> 00:24:40,870
+السيارة طبعا سرعة السيارة من ال acبتساوي V تربيع
+
+342
+00:24:40,870 --> 00:24:45,570
+على R بتطلع ل V ناقص R على AC طبعا هذه ناقص وهذه
+
+343
+00:24:45,570 --> 00:24:50,730
+ناقص تطلع موجب تحت الجزر 43.1 متر في الثانية تربيع
+
+344
+00:24:54,600 --> 00:24:58,300
+عنا مثال اللى هى a roller coaster car moving
+
+345
+00:24:58,300 --> 00:25:02,120
+around a circle of radius R what speed must the
+
+346
+00:25:02,120 --> 00:25:05,100
+car have at the top of the loop so that it will
+
+347
+00:25:05,100 --> 00:25:08,240
+just make it over the top without any assistance
+
+348
+00:25:08,240 --> 00:25:12,340
+from the track طبعا الشكل هذا السيارة بتتحرك فى
+
+349
+00:25:12,340 --> 00:25:16,640
+مسار دائري اللعبة طبعا بتتحرك فى مسار دائري طبعا
+
+350
+00:25:16,640 --> 00:25:23,040
+منحنى فى منطقة معينة هنا مطلوب منها نوجد اللى هى
+
+351
+00:25:23,040 --> 00:25:28,410
+نمرة Aمطلوب مننا نوجد ال speed at the bottom of
+
+352
+00:25:28,410 --> 00:25:31,230
+the loop طبعا عندي أنا loop دائرة لنوجد عند
+
+353
+00:25:31,230 --> 00:25:35,030
+المنطقة هاد السرعة طبعا عند المنطقة هاد فيها أنا
+
+354
+00:25:35,030 --> 00:25:38,590
+سيارة و في عندي مسار طالما أنه في جسم على المسار
+
+355
+00:25:38,590 --> 00:25:42,190
+إذا في عندي normal إلى أعلى و في عندي MG إلى أسفل
+
+356
+00:25:42,190 --> 00:25:45,970
+اتفقنا أن القوة للاهية المركز سالبة و لطالع من
+
+357
+00:25:45,970 --> 00:25:50,650
+المركز موجبة عفوا اللي جوا المركز سالب .. موج ..
+
+358
+00:25:50,650 --> 00:25:54,960
+سالبة و لطالع من المركزموجبة هنستخدم قانون نيوتن
+
+359
+00:25:54,960 --> 00:26:00,820
+التاني اذا ال MAC بسوء ال normal زائد ال MG اللي
+
+360
+00:26:00,820 --> 00:26:06,400
+هي المسف الأكسوميشن لل FAC FAC بسوء ال MAC بستخدم
+
+361
+00:26:06,400 --> 00:26:12,340
+قانون نيوتن التاني اذا ال normal at the top of the
+
+362
+00:26:12,340 --> 00:26:16,520
+loop اذا حطينا لان بسوء zero the force of gravity
+
+363
+00:26:16,520 --> 00:26:19,340
+acts towards the center and provide the
+
+364
+00:26:19,340 --> 00:26:23,470
+centripetal acceleration بتصير AC بسوء ناقصV تربيع
+
+365
+00:26:23,470 --> 00:26:30,910
+على R اذا MG بتساوي ال MV تربيع على R بنحلها و
+
+366
+00:26:30,910 --> 00:26:35,890
+بنطلق ال V at the top of ال V عند ال .. at the top
+
+367
+00:26:35,890 --> 00:26:44,330
+of the track او المسار V بتساوي جزر ال GR طبعا عند
+
+368
+00:26:44,330 --> 00:26:48,870
+الأسفل ال normal موجودة apply conservation of
+
+369
+00:26:48,870 --> 00:26:53,150
+mechanical energy بستخدم ال mechanical energyطبعا
+
+370
+00:26:53,150 --> 00:26:56,850
+بأوجد اللى هى السرعة بالساوية نص Mv تربيه عند ال
+
+371
+00:26:56,850 --> 00:27:00,630
+top زايد ال Mgh طبعا عند ال top بيكونيلها طاقة وضع
+
+372
+00:27:00,630 --> 00:27:06,290
+وطاقة حركة اللى هى Mgr Mg في R ال R اللى هى البعد
+
+373
+00:27:06,290 --> 00:27:10,730
+العمودي اللى هى .. اللى هى البعد من ال .. من البعد
+
+374
+00:27:10,730 --> 00:27:15,870
+اللى هى نص الخطور زايد Mg في اتنين R بالساوية
+
+375
+00:27:15,870 --> 00:27:20,110
+اتنين و نص Mgr لما أوجد ال total mechanical energy
+
+376
+00:27:21,500 --> 00:27:25,060
+at the bottom ال E bottom بيساوي نص M V تربيع عند
+
+377
+00:27:25,060 --> 00:27:28,460
+ال bottom النقطة اللي تحت ال energy is conserved
+
+378
+00:27:28,460 --> 00:27:33,240
+so this energy make equal and solve for V لل .. لل
+
+379
+00:27:33,240 --> 00:27:37,900
+bottom اذا نص M V تربيع لل bottom بيساوي اتنين و
+
+380
+00:27:37,900 --> 00:27:43,700
+نص MGR ال V لل bottom بيساوي جزر خمسة GR يعني عند
+
+381
+00:27:43,700 --> 00:27:47,240
+.. لما اوجد ال normal force ل .. لل نقطة اللي هي
+
+382
+00:27:47,240 --> 00:27:51,300
+ال bottom بده اوجد ال normalفعنا ال MG ناقص ال
+
+383
+00:27:51,300 --> 00:27:55,080
+normal طبعا ال MG موجب هو normal سالب لإن ال
+
+384
+00:27:55,080 --> 00:27:58,060
+normal ناحية المركز و ال MG طالع من المركز هدولا
+
+385
+00:27:58,060 --> 00:28:01,300
+التنتين بدهم يساووا ال MV² على R اللي هي القوة
+
+386
+00:28:01,300 --> 00:28:05,760
+المركزية او القوة المركزية فمن هنا بنوجد ال normal
+
+387
+00:28:05,760 --> 00:28:09,940
+force and ال bottom بنلاحظ إن ال normal force
+
+388
+00:28:09,940 --> 00:28:13,520
+بتصرف towards the center of the circle عبارة ..
+
+389
+00:28:13,520 --> 00:28:17,810
+عشان هي ك .. هي negativethe car weight acts away
+
+390
+00:28:17,810 --> 00:28:22,070
+from the center هي positive وبالتالي ال normal
+
+391
+00:28:22,070 --> 00:28:26,970
+بيساوي ال mg زايد m v تربيع على r بيساوي ال mg
+
+392
+00:28:26,970 --> 00:28:31,630
+زايد m خمسة gr على r اللي هي ستة mg كده بنكون
+
+393
+00:28:31,630 --> 00:28:36,450
+أوجدنا ال normal at the bottom of the .. at the
+
+394
+00:28:36,450 --> 00:28:40,090
+bottom of the اللي هي ال motion بالنسبة للحركة
+
+395
+00:28:40,090 --> 00:28:45,650
+section سبعة أربعة ملغي كدهالى هنا بنكون قد
+
+396
+00:28:45,650 --> 00:28:49,250
+انتهينا من الأجزاء المطلوبة من chapter 7
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..b6a124ac6da81168f87de75a98b482c4bee22760
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_raw.json
@@ -0,0 +1 @@
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0.98095703125}], "temperature": 1.0}, {"id": 30, "seek": 75098, "start": 735.46, "end": 750.98, "text": "section 7-4 newtons second law for uniform circular motion قانون نيوتن التانى للحركة الدائرية المتضامة نيوتونس second law قانون نيوتن التانى للحركة ممكن انه احنا طبعا نستخدمه علشان احل", "tokens": [11963, 1614, 12, 19, 777, 83, 892, 1150, 2101, 337, 9452, 16476, 5394, 12174, 7649, 11536, 8717, 1829, 35473, 1863, 16712, 7649, 7578, 5296, 1211, 5016, 31747, 3660, 32748, 16373, 2288, 10632, 9673, 2655, 11242, 10943, 3660, 8717, 1829, 35473, 11536, 3794, 1150, 2101, 12174, 7649, 11536, 8717, 1829, 35473, 1863, 16712, 7649, 7578, 24976, 5016, 31747, 3660, 3714, 43020, 16472, 3224, 1975, 5016, 8315, 23032, 3555, 3615, 995, 8717, 14851, 9778, 40448, 3224, 11203, 8592, 7649, 1975, 5016, 1211], "avg_logprob": -0.22415122868102275, "compression_ratio": 1.6432748538011697, "no_speech_prob": 2.980232238769531e-07, "words": [{"start": 735.46, "end": 736.1, "word": "section", "probability": 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{"start": 741.36, "end": 742.14, "word": " للحركة", "probability": 0.82109375}, {"start": 742.14, "end": 742.68, "word": " الدائرية", "probability": 0.865478515625}, {"start": 742.68, "end": 743.78, "word": " المتضامة", "probability": 0.6892578125}, {"start": 743.78, "end": 745.28, "word": " نيوتونس", "probability": 0.657568359375}, {"start": 745.28, "end": 745.76, "word": " second", "probability": 0.81591796875}, {"start": 745.76, "end": 745.98, "word": " law", "probability": 0.85400390625}, {"start": 745.98, "end": 746.26, "word": " قانون", "probability": 0.93408203125}, {"start": 746.26, "end": 746.5, "word": " نيوتن", "probability": 0.8624267578125}, {"start": 746.5, "end": 746.96, "word": " التانى", "probability": 0.97509765625}, {"start": 746.96, "end": 747.68, "word": " للحركة", "probability": 0.906494140625}, {"start": 747.68, "end": 748.32, "word": " ممكن", "probability": 0.76953125}, {"start": 748.32, "end": 748.62, "word": " انه", "probability": 0.601318359375}, {"start": 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uniform", "probability": 0.90869140625}, {"start": 756.31, "end": 756.83, "word": " circular", "probability": 0.53564453125}, {"start": 756.83, "end": 757.19, "word": " motion", "probability": 0.97216796875}, {"start": 757.19, "end": 757.35, "word": " في", "probability": 0.60791015625}, {"start": 757.35, "end": 757.67, "word": " حالة", "probability": 0.9952799479166666}, {"start": 757.67, "end": 758.17, "word": " الحركة", "probability": 0.99560546875}, {"start": 758.17, "end": 758.65, "word": " الدائرية", "probability": 0.994140625}, {"start": 758.65, "end": 759.41, "word": " المنتظمة", "probability": 0.7645263671875}, {"start": 759.41, "end": 760.29, "word": " قانون", "probability": 0.9514973958333334}, {"start": 760.29, "end": 760.57, "word": " نيوتن", "probability": 0.7406005859375}, {"start": 760.57, "end": 761.25, "word": " التاني", "probability": 0.92431640625}, {"start": 761.25, "end": 762.25, "word": " will", "probability": 0.68798828125}, {"start": 762.25, "end": 762.99, 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0.794921875}], "temperature": 1.0}, {"id": 39, "seek": 97373, "start": 944.69, "end": 973.73, "text": "ناحية المركز بيسموها ده هي الcentrifugal force القوة ناحية المركز هي قوة الcentrifugal force هي قوة الشد وفي المنطقة ده في عندي أنا سرعة ممسية tangential force لأن why why does the puck move in a circle طبعا هي بتتحرك حركة دائرية بسبب وجود القوة المركزية هي اللي بتخليها تتحرك حركة دائرية منتظمة because of its inertia the tendency of the puck is to move in a straight line", "tokens": [8315, 5016, 10632, 9673, 31747, 11622, 4724, 1829, 38251, 2407, 11296, 11778, 3224, 39896, 2423, 2207, 22575, 17812, 3464, 25062, 2407, 3660, 8717, 39319, 10632, 9673, 31747, 11622, 39896, 12174, 2407, 3660, 2423, 2207, 22575, 17812, 3464, 39896, 12174, 2407, 3660, 25124, 3215, 4032, 41185, 9673, 1863, 9566, 28671, 11778, 3224, 8978, 18871, 16254, 41850, 8608, 2288, 27884, 3714, 2304, 3794, 10632, 10266, 2549, 3464, 5296, 33456, 983, 983, 775, 264, 47181, 1286, 294, 257, 6329, 23032, 3555, 3615, 995, 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"end": 964.37, "word": " بسبب", "probability": 0.9482421875}, {"start": 964.37, "end": 964.65, "word": " وجود", "probability": 0.979736328125}, {"start": 964.65, "end": 964.95, "word": " القوة", "probability": 0.92578125}, {"start": 964.95, "end": 965.51, "word": " المركزية", "probability": 0.9881591796875}, {"start": 965.51, "end": 965.67, "word": " هي", "probability": 0.951171875}, {"start": 965.67, "end": 965.77, "word": " اللي", "probability": 0.931884765625}, {"start": 965.77, "end": 966.13, "word": " بتخليها", "probability": 0.9326171875}, {"start": 966.13, "end": 966.41, "word": " تتحرك", "probability": 0.9705810546875}, {"start": 966.41, "end": 966.77, "word": " حركة", "probability": 0.9925130208333334}, {"start": 966.77, "end": 967.05, "word": " دائرية", "probability": 0.9937744140625}, {"start": 967.05, "end": 967.57, "word": " منتظمة", "probability": 0.79248046875}, {"start": 967.57, "end": 968.55, "word": " because", "probability": 0.94091796875}, {"start": 968.55, "end": 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"temperature": 1.0}, {"id": 44, "seek": 111205, "start": 1087.61, "end": 1112.05, "text": "the centripetal acceleration is negative الآن الcentripetal acceleration القوة المركزية بناء على ما ذكر تعتبر سالبة لإنها تؤثر ناحية المركز قانون نيوتن التاني لل uniform circular motion ممكن أكتبه بهذا الشكل summation للأفقار بتساوي ناخص mv تربيع على r هذي بيسموها ال radial force summation لل radial force", "tokens": [3322, 1489, 470, 7275, 304, 17162, 307, 3671, 6024, 48506, 2423, 2207, 470, 7275, 304, 17162, 25062, 2407, 3660, 9673, 31747, 11622, 10632, 44945, 16606, 15844, 19446, 29910, 37983, 6055, 34268, 26890, 8608, 6027, 49401, 5296, 28814, 1863, 11296, 6055, 33604, 49115, 8717, 39319, 10632, 9673, 31747, 11622, 12174, 7649, 11536, 8717, 1829, 35473, 1863, 16712, 7649, 1829, 24976, 9452, 16476, 5394, 3714, 43020, 5551, 4117, 2655, 3555, 3224, 39627, 15730, 25124, 28820, 28811, 24976, 10721, 5172, 4587, 9640, 39894, 3794, 995, 45865, 8717, 47283, 9381, 275, 85, 6055, 2288, 21292, 3615, 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{"start": 1472.15, "end": 1472.41, "word": " تسعة", "probability": 0.9669596354166666}, {"start": 1472.41, "end": 1472.49, "word": " و", "probability": 0.63818359375}, {"start": 1472.49, "end": 1472.69, "word": " تمانية", "probability": 0.94140625}, {"start": 1472.69, "end": 1472.83, "word": " من", "probability": 0.99560546875}, {"start": 1472.83, "end": 1473.17, "word": " عشرة", "probability": 0.94091796875}, {"start": 1473.17, "end": 1473.31, "word": " و", "probability": 0.68212890625}, {"start": 1473.31, "end": 1473.53, "word": " التان", "probability": 0.937255859375}, {"start": 1473.53, "end": 1473.75, "word": " واحد", "probability": 0.896240234375}, {"start": 1473.75, "end": 1474.23, "word": " تلاتين", "probability": 0.90380859375}, {"start": 1474.23, "end": 1474.93, "word": " بعد", "probability": 0.9052734375}, {"start": 1474.93, "end": 1475.15, "word": " هيك", "probability": 0.97412109375}, {"start": 1475.15, "end": 1475.41, "word": " بدأ", "probability": 0.7646484375}, {"start": 1475.41, "end": 1475.67, "word": " اوجد", "probability": 0.6740315755208334}, {"start": 1475.67, "end": 1476.07, "word": " سرعة", "probability": 0.8014322916666666}, {"start": 1476.07, "end": 1476.99, "word": " السيارة", "probability": 0.9915771484375}, {"start": 1476.99, "end": 1477.63, "word": " طبعا", "probability": 0.989990234375}, {"start": 1477.63, "end": 1477.93, "word": " سرعة", "probability": 0.98046875}, {"start": 1477.93, "end": 1478.43, "word": " السيارة", "probability": 0.9932861328125}, {"start": 1478.43, "end": 1478.63, "word": " من", "probability": 0.99560546875}, {"start": 1478.63, "end": 1478.87, "word": " ال", "probability": 0.9931640625}, {"start": 1478.87, "end": 1479.23, "word": " ac", "probability": 0.5771484375}], "temperature": 1.0}, {"id": 59, "seek": 149073, "start": 1479.65, "end": 1490.73, "text": "بتساوي V تربيع على R بتطلع ل V ناقص R على AC طبعا هذه ناقص وهذه ناقص تطلع موجب تحت الجزر 43.1 متر في الثانية تربيع", "tokens": [3555, 2655, 3794, 995, 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over the top without any assistance from the track طبعا الشكل هذا السيارة بتتحرك فى مسار دائري اللعبة طبعا بتتحرك فى مسار دائري طبعا منحنى فى منطقة معينة هنا مطلوب منها نوجد اللى هى نمرة A", "tokens": [3615, 8315, 50113, 6027, 13672, 7578, 8032, 7578, 257, 15948, 28442, 1032, 2684, 926, 257, 6329, 295, 15845, 497, 437, 3073, 1633, 264, 1032, 362, 412, 264, 1192, 295, 264, 6367, 370, 300, 309, 486, 445, 652, 309, 670, 264, 1192, 1553, 604, 9683, 490, 264, 2837, 23032, 3555, 3615, 995, 25124, 28820, 23758, 21136, 1829, 9640, 3660, 39894, 2655, 5016, 31747, 6156, 7578, 47524, 9640, 11778, 16373, 16572, 13672, 3615, 49401, 23032, 3555, 3615, 995, 39894, 2655, 5016, 31747, 6156, 7578, 47524, 9640, 11778, 16373, 16572, 23032, 3555, 3615, 995, 9154, 5016, 1863, 7578, 6156, 7578, 9154, 9566, 28671, 20449, 9957, 3660, 34105, 3714, 9566, 1211, 37746, 9154, 11296, 8717, 29245, 3215, 13672, 7578, 8032, 7578, 8717, 2304, 25720, 316], "avg_logprob": -0.12660091761194292, "compression_ratio": 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"word": " circle", "probability": 0.71923828125}, {"start": 1499.1, "end": 1499.32, "word": " of", "probability": 0.2340087890625}, {"start": 1499.32, "end": 1499.78, "word": " radius", "probability": 0.94775390625}, {"start": 1499.78, "end": 1500.32, "word": " R", "probability": 0.6884765625}, {"start": 1500.32, "end": 1501.16, "word": " what", "probability": 0.79248046875}, {"start": 1501.16, "end": 1501.56, "word": " speed", "probability": 0.9189453125}, {"start": 1501.56, "end": 1501.86, "word": " must", "probability": 0.85546875}, {"start": 1501.86, "end": 1502.12, "word": " the", "probability": 0.8876953125}, {"start": 1502.12, "end": 1502.36, "word": " car", "probability": 0.92822265625}, {"start": 1502.36, "end": 1502.66, "word": " have", "probability": 0.94873046875}, {"start": 1502.66, "end": 1502.9, "word": " at", "probability": 0.96044921875}, {"start": 1502.9, "end": 1503.02, "word": " the", "probability": 0.92236328125}, {"start": 1503.02, "end": 1503.18, "word": " top", 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{"start": 1506.38, "end": 1506.56, "word": " top", "probability": 0.95458984375}, {"start": 1506.56, "end": 1506.94, "word": " without", "probability": 0.90380859375}, {"start": 1506.94, "end": 1507.4, "word": " any", "probability": 0.91796875}, {"start": 1507.4, "end": 1508.24, "word": " assistance", "probability": 0.8974609375}, {"start": 1508.24, "end": 1508.54, "word": " from", "probability": 0.72216796875}, {"start": 1508.54, "end": 1508.78, "word": " the", "probability": 0.88671875}, {"start": 1508.78, "end": 1509.16, "word": " track", "probability": 0.97314453125}, {"start": 1509.16, "end": 1509.76, "word": " طبعا", "probability": 0.9759521484375}, {"start": 1509.76, "end": 1510.14, "word": " الشكل", "probability": 0.992919921875}, {"start": 1510.14, "end": 1510.58, "word": " هذا", "probability": 0.69775390625}, {"start": 1510.58, "end": 1511.76, "word": " السيارة", "probability": 0.9588623046875}, {"start": 1511.76, "end": 1512.22, "word": " بتتحرك", "probability": 0.989990234375}, {"start": 1512.22, "end": 1512.34, "word": " فى", "probability": 0.838134765625}, {"start": 1512.34, "end": 1512.68, "word": " مسار", "probability": 0.981689453125}, {"start": 1512.68, "end": 1513.24, "word": " دائري", "probability": 0.8723958333333334}, {"start": 1513.24, "end": 1514.26, "word": " اللعبة", "probability": 0.9874674479166666}, {"start": 1514.26, "end": 1514.5, "word": " طبعا", "probability": 0.9827880859375}, {"start": 1514.5, "end": 1515.34, "word": " بتتحرك", "probability": 0.8197021484375}, {"start": 1515.34, "end": 1515.48, "word": " فى", "probability": 0.9736328125}, {"start": 1515.48, "end": 1515.74, "word": " مسار", "probability": 0.996826171875}, {"start": 1515.74, "end": 1516.16, "word": " دائري", "probability": 0.93212890625}, {"start": 1516.16, "end": 1516.64, "word": " طبعا", "probability": 0.982666015625}, {"start": 1516.64, "end": 1517.92, "word": " منحنى", "probability": 0.85888671875}, {"start": 1517.92, "end": 1519.08, "word": " فى", 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at the bottom of the loop طبعا عندي أنا loop دائرة لنوجد عند المنطقة هاد السرعة طبعا عند المنطقة هاد فيها أنا سيارة و في عندي مسار طالما أنه في جسم على المسار إذا في عندي normal إلى أعلى و في عندي MG إلى أسفل اتفقنا أن القوة للاهية المركز سالبة و لطالع من المركز موجبة عفوا اللي جوا المركز سالب .. موج .. سالبة و لطالع من المركز", "tokens": [2304, 9566, 1211, 37746, 9154, 8315, 8717, 29245, 3215, 2423, 3073, 412, 264, 2767, 295, 264, 6367, 23032, 3555, 3615, 995, 18871, 16254, 41850, 6367, 11778, 16373, 25720, 5296, 1863, 29245, 3215, 43242, 9673, 1863, 9566, 28671, 8032, 18513, 21136, 2288, 27884, 23032, 3555, 3615, 995, 43242, 9673, 1863, 9566, 28671, 8032, 18513, 8978, 11296, 41850, 8608, 1829, 9640, 3660, 4032, 8978, 18871, 16254, 47524, 9640, 23032, 6027, 15042, 14739, 3224, 8978, 10874, 38251, 15844, 9673, 3794, 9640, 11933, 15730, 8978, 18871, 16254, 2710, 30731, 5551, 3615, 23942, 4032, 8978, 18871, 16254, 36856, 30731, 5551, 3794, 5172, 1211, 1975, 2655, 5172, 4587, 8315, 14739, 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"الى هنا بنكون قد انتهينا من الأجزاء المطلوبة من chapter 7", "tokens": [6027, 7578, 34105, 44945, 30544, 12174, 3215, 16472, 47395, 1829, 8315, 9154, 16247, 7435, 11622, 16606, 9673, 9566, 1211, 37746, 3660, 9154, 7187, 1614], "avg_logprob": -0.155625, "compression_ratio": 1.0666666666666667, "no_speech_prob": 0.0, "words": [{"start": 1723.19, "end": 1724.37, "word": "الى", "probability": 0.530181884765625}, {"start": 1724.37, "end": 1724.65, "word": " هنا", "probability": 0.77734375}, {"start": 1724.65, "end": 1725.39, "word": " بنكون", "probability": 0.964111328125}, {"start": 1725.39, "end": 1725.65, "word": " قد", "probability": 0.9921875}, {"start": 1725.65, "end": 1726.13, "word": " انتهينا", "probability": 0.9053955078125}, {"start": 1726.13, "end": 1726.37, "word": " من", "probability": 0.99462890625}, {"start": 1726.37, "end": 1727.51, "word": " الأجزاء", "probability": 0.9415283203125}, {"start": 1727.51, "end": 1728.03, "word": " المطلوبة", "probability": 0.985546875}, {"start": 1728.03, "end": 1728.25, "word": " من", "probability": 0.96240234375}, {"start": 1728.25, "end": 1728.71, "word": " chapter", "probability": 0.88818359375}, {"start": 1728.71, "end": 1729.25, "word": " 7", "probability": 0.78662109375}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1730.1885, "duration_after_vad": 1683.5443749999959}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..82df2f2c31e0efc82519aec797f41f2b51c9bd51
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/EquSaof4h-E_raw.srt
@@ -0,0 +1,1596 @@
+1
+00:00:00,980 --> 00:00:05,800
+بسم الله الرحمن الرحيم section سبعة تلاتة اتنين by
+
+2
+00:00:05,800 --> 00:00:09,440
+one centripetal acceleration التسارع اللي هو
+
+3
+00:00:09,440 --> 00:00:16,200
+المركزي في إن الشكل التالي يوضح سيارة بتتحرك بمصار
+
+4
+00:00:16,200 --> 00:00:21,480
+دائريwith constant linear speed بسرعة خطية ثابتة
+
+5
+00:00:21,480 --> 00:00:24,860
+even though the car move at constant speed it
+
+6
+00:00:24,860 --> 00:00:28,860
+still has an acceleration طالما أنها بتتحرك بسرعة
+
+7
+00:00:28,860 --> 00:00:34,720
+ثابتة بتتحرك بسرعة ثابتة لكن ما زال في إلها تسارع
+
+8
+00:00:34,720 --> 00:00:39,540
+عشان أدرس هذه الظاهرة لإنه إذا مشيت بسرعة خطية ب
+
+9
+00:00:39,540 --> 00:00:43,440
+constant طبعا speed في التسارع بيكون zero لكن هنا
+
+10
+00:00:43,440 --> 00:00:48,780
+التسارع موجودعشان هيك بندرس هذه الظاهرة بنوجد
+
+11
+00:00:48,780 --> 00:00:54,380
+معادلة بتربط بين اللي هي التسارع و ال .. و السرعة
+
+12
+00:00:54,380 --> 00:01:00,740
+خلال .. خلال طبعا حركة دائرية عندنا احنا A average
+
+13
+00:01:00,740 --> 00:01:03,720
+بيسوي V final نخس V initial ع T final نخس T
+
+14
+00:01:03,720 --> 00:01:08,120
+initial طبعا احنا ال bus بيمثل الفرق بين اللي هي
+
+15
+00:01:08,120 --> 00:01:13,670
+delta V V initial و V finalهذا ال vector طبعا have
+
+16
+00:01:13,670 --> 00:01:18,250
+the same magnitude بيمثل the same speed but if
+
+17
+00:01:18,250 --> 00:01:21,350
+they have different direction طبعا هذا بالحركة
+
+18
+00:01:21,350 --> 00:01:25,310
+الخطية لو كان عندي أنا نفس ال .. ال .. السرعة اللي
+
+19
+00:01:25,310 --> 00:01:28,250
+بداية و نفس السرعة النهائية و بالتالي هيكون
+
+20
+00:01:28,250 --> 00:01:32,770
+التسارع zero لكن لو بتحرك باتجاهات مختلفة معنى
+
+21
+00:01:32,770 --> 00:01:37,460
+الكلام أن هو لا يساوي zeroفلو احنا مشيت سيارة بهذا
+
+22
+00:01:37,460 --> 00:01:42,100
+الحركة الدائرية على دور معين طبعا هنا نقطة الدوران
+
+23
+00:01:42,100 --> 00:01:49,000
+هتتحرك طبعا من ال A هنا كأنها نقطة initial السرعة
+
+24
+00:01:49,000 --> 00:01:54,600
+الممسية V initial لو وصلت لنقطة B ومشيت ازاحة
+
+25
+00:01:54,600 --> 00:01:59,340
+دلتاتيتا هكون هنا عندى انا ايضا اللى هى سرعة ممسية
+
+26
+00:01:59,340 --> 00:02:04,250
+طبعا هنا اتجاهها بيختلف عن هذا الاتجاه وبالتاليالـ
+
+27
+00:02:04,250 --> 00:02:08,830
+a في هذه الحالة لاتساوي zero اتجاه السرع زي ما
+
+28
+00:02:08,830 --> 00:02:14,330
+حكينا خلال حركة دائرية بتتغير for a circular
+
+29
+00:02:14,330 --> 00:02:18,090
+motion في الحركة الدائرية at constant speed the
+
+30
+00:02:18,090 --> 00:02:21,650
+acceleration vector always point التسارع دايما
+
+31
+00:02:21,650 --> 00:02:25,970
+بيتجه ناحية المركز زي such as acceleration is
+
+32
+00:02:25,970 --> 00:02:29,570
+called هذا التسارع بيسموه centripetal acceleration
+
+33
+00:02:30,460 --> 00:02:34,460
+its magnitude الان الcentimeter acceleration AC
+
+34
+00:02:34,460 --> 00:02:38,900
+بتساوي V تربيه على R هذه عبارة عن التسارع المركزي
+
+35
+00:02:38,900 --> 00:02:43,240
+هي علاقة اللي هي التسارع المركزي مع السرعة
+
+36
+00:02:43,240 --> 00:02:47,440
+tangential velocity because the tangential
+
+37
+00:02:47,440 --> 00:02:50,260
+velocity is related to the angular velocity طبعا
+
+38
+00:02:50,260 --> 00:02:54,260
+في علاقة بين ال V و ال Omega ف V tangential كانت
+
+39
+00:02:54,260 --> 00:03:00,040
+بتساوي R في Omegaإذا ال .. ال alternate .. يعني ال
+
+40
+00:03:00,040 --> 00:03:07,580
+alternate هنا un .. alternate form فده الحالة بده
+
+41
+00:03:07,580 --> 00:03:12,220
+يساوي اللي هي V tangential بساوي R في Omega لما
+
+42
+00:03:12,220 --> 00:03:15,540
+بده أعوض إذا ال A .. A C بساوي R تربيع في Omega
+
+43
+00:03:15,540 --> 00:03:19,060
+تربيع على R يعني R في Omega تربيع يعني ممكن نحكي A
+
+44
+00:03:19,060 --> 00:03:22,580
+C بساوي V تربيع على R أو A C بساوي R في Omega
+
+45
+00:03:23,040 --> 00:03:27,540
+physically فزيائيا اللي هي ال acceleration تحدث
+
+46
+00:03:27,540 --> 00:03:32,660
+only if some force is present وجود القوة for
+
+47
+00:03:32,660 --> 00:03:36,160
+example ف if a car travel in a circle on flat
+
+48
+00:03:36,160 --> 00:03:41,120
+ground الآن إذا السيارة بدها تدور على طبعا منحنى
+
+49
+00:03:41,120 --> 00:03:45,620
+أو دوار flat مستويففي عندنا ال force of static
+
+50
+00:03:45,620 --> 00:03:48,240
+frictional القوة اللي بتخلي السيارة تدور حركة
+
+51
+00:03:48,240 --> 00:03:52,500
+دائرية هي عبارة عن قوة الاحتكاك الساكن قوة
+
+52
+00:03:52,500 --> 00:03:56,640
+الاحتكاك الساكن هي طبعا متجهة ناحية المركز بيسموها
+
+53
+00:03:56,640 --> 00:04:01,400
+centripetal force طبعا ال AC in equation طبعا ال
+
+54
+00:04:01,400 --> 00:04:04,680
+AC اللي هي centripetal acceleration بتمثل only the
+
+55
+00:04:04,680 --> 00:04:07,180
+magnitude تمثل فقط ال magnitude لcentripetal
+
+56
+00:04:07,180 --> 00:04:11,130
+acceleration لتسرع المركزيال acceleration itself
+
+57
+00:04:11,130 --> 00:04:14,510
+is always directed toward the center, centripetal
+
+58
+00:04:14,510 --> 00:04:17,730
+اللي هي centripetal acceleration تسارع المركزي
+
+59
+00:04:17,730 --> 00:04:21,850
+بيتجه دائما ناحية المركز the foregoing
+
+60
+00:04:21,850 --> 00:04:27,150
+clarification concern a circular motion at
+
+61
+00:04:27,150 --> 00:04:29,790
+constant speed when an object moves in a circle
+
+62
+00:04:29,790 --> 00:04:33,830
+but is speeding up or slowing down tangential
+
+63
+00:04:33,830 --> 00:04:38,090
+component of the acceleration فAT بالساوة ال R في
+
+64
+00:04:38,090 --> 00:04:42,190
+ال alphait's also present because the tangential
+
+65
+00:04:42,190 --> 00:04:45,110
+and centripetal component of acceleration are
+
+66
+00:04:45,110 --> 00:04:49,190
+perpendicular to each other ال tangential ..
+
+67
+00:04:49,190 --> 00:04:54,610
+tangential and centripetal component المركبة اللي
+
+68
+00:04:54,610 --> 00:04:58,090
+.. اللي هي ال a tangential و ال a centripetal يعني
+
+69
+00:04:58,090 --> 00:05:02,610
+التسارع المركزي و التسارع المماسي متعمدين على بعض
+
+70
+00:05:02,610 --> 00:05:06,730
+لإن التسارع المماسي طبعا مماس للدائرة و التسارع
+
+71
+00:05:06,730 --> 00:05:09,670
+المركزي ناحية المركزو بالتالي التانين المتعمدين
+
+72
+00:05:09,670 --> 00:05:13,970
+على بعض لإن ده إيجاد التسارق الكلي عشان التانين
+
+73
+00:05:13,970 --> 00:05:17,110
+المتعمدين على بعض فالإيه الكلي بيساوي جزر ال
+
+74
+00:05:17,110 --> 00:05:20,370
+tangential تربية زائد ال AC تربية بالاستخدام اللي
+
+75
+00:05:20,370 --> 00:05:26,350
+هي نظرية Field of Work طبعا هذه كلها بنعرف فيها
+
+76
+00:05:26,350 --> 00:05:29,880
+اللي هي التسارق المركزيNigella race track is
+
+77
+00:05:29,880 --> 00:05:34,700
+construct such that two arc of radius في عندي طبعا
+
+78
+00:05:34,700 --> 00:05:40,180
+حركة في قوس تمانين متر at A واتحركت أربعين متر at
+
+79
+00:05:40,180 --> 00:05:45,740
+B are joined by two stretch of straight track in
+
+80
+00:05:45,740 --> 00:05:50,580
+figure سبعة تمانية in a particular trail run
+
+81
+00:05:50,580 --> 00:05:54,840
+driver travels at a constant speed of خمسين متر
+
+82
+00:05:54,840 --> 00:05:59,140
+for one complete lapthe ratio of the tangential
+
+83
+00:05:59,140 --> 00:06:05,120
+acceleration at A to that at B is بدي أنا اللي هي
+
+84
+00:06:05,120 --> 00:06:10,140
+ال ratio of tangential بالنسبة ل .. اللي هي النسبة
+
+85
+00:06:10,140 --> 00:06:14,900
+بين ال tangential acceleration عند النقطة Aلا
+
+86
+00:06:14,900 --> 00:06:19,380
+النقطة B بدها تساوي طبعا اللي هي عبارة عن
+
+87
+00:06:19,380 --> 00:06:23,280
+tangential acceleration ال zero at both point
+
+88
+00:06:23,280 --> 00:06:28,580
+tangential acceleration بتساوي zero in .. يعني
+
+89
+00:06:28,580 --> 00:06:35,560
+اللي في كده النقاط اللي هو احنا انا شكل .. الشكل
+
+90
+00:06:35,560 --> 00:06:40,930
+كما هو موضح بشكلسبعة تمانية figure سبعة تمانية لو
+
+91
+00:06:40,930 --> 00:06:47,390
+نرجعله figure سبعة تمانية ان شاء الله figure سبعة
+
+92
+00:06:47,390 --> 00:06:49,170
+تمانية طبعا هو موضح في الكتاب
+
+93
+00:07:12,230 --> 00:07:17,050
+عموما .. عموما طبعا هو موجود في الكتاب، الآن
+
+94
+00:07:17,050 --> 00:07:22,430
+racetrack يعني فيه انما سار Constructed to ears of
+
+95
+00:07:22,430 --> 00:07:28,930
+radiusمسار بتمشي فيه طبعا جسم معين أو سيارة بي ..
+
+96
+00:07:28,930 --> 00:07:33,370
+طبعا بحرك على طبعا قوس تمانين متر عند النقطة A and
+
+97
+00:07:33,370 --> 00:07:36,990
+أربعين متر عند النقطة B are joined by two stretch
+
+98
+00:07:36,990 --> 00:07:40,850
+of straight track as الفجر طبعا الفجر موجود بس مش
+
+99
+00:07:40,850 --> 00:07:46,990
+موجود هنا in a particular trail run driver travels
+
+100
+00:07:46,990 --> 00:07:51,470
+at a constant speed SBC طبعا السائقبتحرك ب
+
+101
+00:07:51,470 --> 00:07:55,990
+constant speed بسرعة خمسين متر في التانية طبعا لما
+
+102
+00:07:55,990 --> 00:08:00,850
+يتحرك ب constant speed طبعا اذا كان انا بدي
+
+103
+00:08:00,850 --> 00:08:06,170
+التسارع ال .. التسارع ال tangential مع أن الكلام
+
+104
+00:08:06,170 --> 00:08:10,910
+انه التسارع الممسي هيكون عندنا zero لإنه بيتحرك ب
+
+105
+00:08:10,910 --> 00:08:14,850
+constant speed زي هو طبعا ال ratio of tangential
+
+106
+00:08:14,850 --> 00:08:18,490
+acceleration to the .. at B من A لB طبعا هيكون
+
+107
+00:08:18,490 --> 00:08:22,890
+عندي أنا zeroاللي هي الجواب a لكن الآن ال ratio of
+
+108
+00:08:22,890 --> 00:08:27,570
+the centripetal acceleration at a to b لما أحسب ال
+
+109
+00:08:27,570 --> 00:08:32,170
+tangential acceleration هو بتحرك حركة .. بتتحرك
+
+110
+00:08:32,170 --> 00:08:36,450
+حركة دائرية ال tangential اللي هي اللي عند نقطة a
+
+111
+00:08:36,450 --> 00:08:39,550
+و لا نقطة b بتساوي zero لإنه بتحرك ب constant
+
+112
+00:08:39,550 --> 00:08:42,950
+speed لكن لما أجى أحسب ال centripetal acceleration
+
+113
+00:08:42,950 --> 00:08:48,970
+من النقطة a ل ال b بلاحظ أنه هو بيساوي طبعا بيساوي
+
+114
+00:08:48,970 --> 00:08:53,270
+نصنص من النقطة A ل B لإنه في عندي انا في تربية على
+
+115
+00:08:53,270 --> 00:08:57,810
+.. على R و ال R هي اللي بتحدد واحدة نص التانية
+
+116
+00:08:57,810 --> 00:09:01,930
+بدهوا ال angular speed is greatest at .. ال
+
+117
+00:09:01,930 --> 00:09:06,770
+angular speed is greatest عند النقطة B ال angular
+
+118
+00:09:06,770 --> 00:09:13,160
+speed is greatest at النقطة Bالكوز التاني an
+
+119
+00:09:13,160 --> 00:09:15,740
+object move in a circular path جسم بتحرك حركة
+
+120
+00:09:15,740 --> 00:09:19,480
+دائرية ب constant speed which the flow .. meaning
+
+121
+00:09:19,480 --> 00:09:24,340
+الجمال الآن is .. اللي هي is true بالنسبة للجسم،
+
+122
+00:09:24,340 --> 00:09:29,900
+هل سرعتها ثابتة، هل التسارع بتغير، هل التسارع طبعا
+
+123
+00:09:29,900 --> 00:09:34,660
+constant و ال velocity changing و لا both its طبعا
+
+124
+00:09:34,660 --> 00:09:38,090
+velocity and acceleration are changingوالا its
+
+125
+00:09:38,090 --> 00:09:40,590
+velocity and acceleration remain constant الآن
+
+126
+00:09:40,590 --> 00:09:44,670
+بتحرك حركة دائرية بتحرك حركة دائرية ب constant
+
+127
+00:09:44,670 --> 00:09:47,430
+speed which of the following statement مين الجملة
+
+128
+00:09:47,430 --> 00:09:51,270
+ده صحيحة الجملة الأولى its velocity is constant
+
+129
+00:09:51,270 --> 00:09:57,950
+سرعتها ثابتة لكن التسارع بتغير الآن التسارع ثابت
+
+130
+00:09:57,950 --> 00:10:01,430
+والسرعة بتتغير و لا both its velocity and
+
+131
+00:10:01,430 --> 00:10:04,730
+acceleration are changing طبعافي الحركة الدائرية
+
+132
+00:10:04,730 --> 00:10:08,050
+both its velocity and acceleration are changing
+
+133
+00:10:08,050 --> 00:10:11,610
+لإن ال velocity بتغير اتجاهها في كل نقطة و التسرع
+
+134
+00:10:11,610 --> 00:10:14,050
+بتتغير بناء على ال velocity اللى نفسها و V تربية
+
+135
+00:10:14,050 --> 00:10:19,090
+على ال R فالجواب الصحي هو C لإيه both its velocity
+
+136
+00:10:19,090 --> 00:10:24,930
+and acceleration are exchanging example سبعة خمسة
+
+137
+00:10:24,930 --> 00:10:32,770
+في عندنا راس كسيارة سباق accelerateuniformally
+
+138
+00:10:32,770 --> 00:10:37,850
+تتحرك بانتظام طبعا من سرعة أربعين متر في الثاني
+
+139
+00:10:37,850 --> 00:10:41,810
+إلى سرعة ستين في زمن قدره خمسة while traveling
+
+140
+00:10:41,810 --> 00:10:44,910
+counterclockwise طبعا هيتحركت حركة دائرية عكس
+
+141
+00:10:44,910 --> 00:10:49,170
+عقارب الساعة خلال ال radius أربعة في عشر أو ستين
+
+142
+00:10:49,170 --> 00:10:53,850
+متر when the car reach speed of خمسين لما السيارة
+
+143
+00:10:53,850 --> 00:10:58,700
+توصل لهاسرعة خمسين احسب calculate the magnitude of
+
+144
+00:10:58,700 --> 00:11:01,580
+the car's centripetal acceleration طبعا نحسب
+
+145
+00:11:01,580 --> 00:11:04,380
+الcentripetal acceleration V تربيع على نحسب
+
+146
+00:11:04,380 --> 00:11:08,460
+الcentripetal acceleration ال V عندي خمسين و ال R
+
+147
+00:11:08,460 --> 00:11:13,080
+كانت أربعة ال N أسي بالساوي خمسين على أربعة طبعا
+
+148
+00:11:13,080 --> 00:11:15,640
+خمسين تربيع لإن هو V تربيع على أربعة بطلع ستة
+
+149
+00:11:15,640 --> 00:11:19,260
+point اتنين خمس متر في الثانية تربيع في B ب
+
+150
+00:11:19,260 --> 00:11:22,180
+calculate the angular velocity طبعا طالما احنا
+
+151
+00:11:22,180 --> 00:11:25,330
+عرفنا ال V موجودة و ال R موجودةالعلاقة ال ال
+
+152
+00:11:25,330 --> 00:11:29,570
+linear في ال angular omega بالساوي V على AR اللي
+
+153
+00:11:29,570 --> 00:11:32,830
+هي خمسين على R في عشر عصر اتنين متر تطلع point
+
+154
+00:11:32,830 --> 00:11:37,670
+واحد اتنين خمس راد per second في C calculate the
+
+155
+00:11:37,670 --> 00:11:40,790
+magnitude of the tangential acceleration ال
+
+156
+00:11:40,790 --> 00:11:43,210
+tangential acceleration اللي هي Delta V ع Delta T
+
+157
+00:11:43,210 --> 00:11:48,520
+V final كانت ستينov initial 40 و delta t 5 بطلع 4
+
+158
+00:11:48,520 --> 00:11:52,200
+متر في الثانية تربيع بعد هيك ا calculate the
+
+159
+00:11:52,200 --> 00:11:55,740
+magnitude of the total acceleration بدنا نحسب ال
+
+160
+00:11:55,740 --> 00:11:59,040
+total acceleration اللي عبارة عن a tangential
+
+161
+00:11:59,040 --> 00:12:03,620
+تربيع زايد ال a c تربيع ال a جزر a t تربيع زايد a
+
+162
+00:12:03,620 --> 00:12:07,700
+c تربيع بتسوى 4 تربيع زايد 6.25 تربيع اللي احنا
+
+163
+00:12:07,700 --> 00:12:11,500
+وجدناهم سابقا بتلع ال total acceleration بتسوى 7
+
+164
+00:12:11,500 --> 00:12:17,920
+.42 متر في الثانية تربيعsection 7-4 newtons second
+
+165
+00:12:17,920 --> 00:12:21,360
+law for uniform circular motion قانون نيوتن التانى
+
+166
+00:12:21,360 --> 00:12:26,260
+للحركة الدائرية المتضامة نيوتونس second law قانون
+
+167
+00:12:26,260 --> 00:12:30,280
+نيوتن التانى للحركة ممكن انه احنا طبعا نستخدمه
+
+168
+00:12:30,280 --> 00:12:35,370
+علشان احلمسائل تتضمن الحركة الدائرية in the case
+
+169
+00:12:35,370 --> 00:12:38,170
+of the uniform circular motion في حالة الحركة
+
+170
+00:12:38,170 --> 00:12:42,990
+الدائرية المنتظمة قانون نيوتن التاني will feature
+
+171
+00:12:42,990 --> 00:12:45,790
+the centripetal acceleration and variability of
+
+172
+00:12:45,790 --> 00:12:50,100
+the radial forceفي عندي طبعا هتظهر عندي مجموعة قوة
+
+173
+00:12:50,100 --> 00:12:53,100
+بتساوي ال M في A هذا قانونية من التاني فبيظهر عندي
+
+174
+00:12:53,100 --> 00:12:57,160
+Radial force في قوة مركزية that are either
+
+175
+00:12:57,160 --> 00:13:01,700
+directed .. القوة المركزية ممكن تكون تتجه towards
+
+176
+00:13:01,700 --> 00:13:05,600
+or away from the center ممكن تتجه داخل المركز أو
+
+177
+00:13:05,600 --> 00:13:10,140
+خارج من المركز نيجي نوضح هذا الكلام في section
+
+178
+00:13:10,140 --> 00:13:14,900
+سبعة أربعة واحدال forces causes centripetal
+
+179
+00:13:14,900 --> 00:13:20,360
+acceleration ال un .. un object أي جسم بتحرك حركة
+
+180
+00:13:20,360 --> 00:13:23,620
+بيت in centripetal acceleration only if some
+
+181
+00:13:23,620 --> 00:13:28,500
+external force acts on in لما يتحرك في تسارع مركزي
+
+182
+00:13:28,500 --> 00:13:34,060
+بحس أنه فيه قوة خارجية أثرت عليه for a ball
+
+183
+00:13:34,060 --> 00:13:36,560
+whirling in a circle at the end of the string لو
+
+184
+00:13:36,560 --> 00:13:41,930
+أنا مساكت كرة و ربطتها في خيط و حركت حركة دائريةلح
+
+185
+00:13:41,930 --> 00:13:44,990
+يكون في هناك قوة شد that the force is the tension
+
+186
+00:13:44,990 --> 00:13:47,790
+in the string في قوة شد in the case of the car
+
+187
+00:13:47,790 --> 00:13:51,590
+برضه moving إذا كان السيارة تتحرك حركة دائرية على
+
+188
+00:13:51,590 --> 00:13:56,720
+سطح flat ففي عندي أنا قوة الاحتكاك الساكنبين
+
+189
+00:13:56,720 --> 00:13:59,960
+الإجال وبين السيارة هي اللي بتخلي السيارة تتحرك
+
+190
+00:13:59,960 --> 00:14:03,880
+حركة دائرية منتظمة كمان في عندي حركة اللي هي ال
+
+191
+00:14:03,880 --> 00:14:08,400
+satellite الحركة اللي هي الأقمار الصناعية الحركة
+
+192
+00:14:08,400 --> 00:14:11,980
+المدارية حوالين الأرض has برضه بتحيه عبارة عن
+
+193
+00:14:11,980 --> 00:14:15,020
+التحرك اللي هي تسارع مركزي centripetal
+
+194
+00:14:15,020 --> 00:14:19,300
+acceleration بسبب قوة الجذب العام بين ال satellite
+
+195
+00:14:19,300 --> 00:14:23,040
+وبين الأرض some books used ممكن في كتب تستخدم
+
+196
+00:14:23,040 --> 00:14:28,390
+centripetal forceو في كتب تستخدم اللي هي ال .. ال
+
+197
+00:14:28,390 --> 00:14:32,930
+.. ال radial force أو centripetal force طبعا هي
+
+198
+00:14:32,930 --> 00:14:38,170
+نفس ال .. نفس المعنى ولكن واحدة عكس التانية لأ
+
+199
+00:14:38,170 --> 00:14:41,550
+this is not the case that a jacket centripetal in
+
+200
+00:14:41,550 --> 00:14:46,170
+centripetal force simply means that the force in a
+
+201
+00:14:46,170 --> 00:14:49,230
+cushion acts towards the center ال centripetal
+
+202
+00:14:49,230 --> 00:14:52,150
+force هي معناها أن القوة اللي هي مؤثرة ناحية
+
+203
+00:14:52,150 --> 00:14:56,160
+المركزthe force of tension بالنسبة لا ال string
+
+204
+00:14:56,160 --> 00:14:59,580
+اللى هى عبارة عن قوة الشدف الحبل هى عبارة عن قوة
+
+205
+00:14:59,580 --> 00:15:04,700
+مركزية كمان بالنسبة لا ال vertical circle in an
+
+206
+00:15:04,700 --> 00:15:07,900
+example centripetal force as in the force of
+
+207
+00:15:07,900 --> 00:15:11,960
+gravity برضه عبارة عن قوة الجاذبية بالنسبة لا
+
+208
+00:15:11,960 --> 00:15:15,670
+الستالاية اللى بدور حوالين الأرضconsider a pack of
+
+209
+00:15:15,670 --> 00:15:22,130
+mass M لو عندي أنا طبعا كتلة M مربوطة بخيط اتحرك
+
+210
+00:15:22,130 --> 00:15:27,530
+حركة دائرية زي ما هو موضح بالشكل طبعا بتدور بسرعة
+
+211
+00:15:27,530 --> 00:15:32,930
+ثابتة هذا الحركة دي هي حركة horizontal يعني الحركة
+
+212
+00:15:32,930 --> 00:15:38,430
+ال horizontal ولكن دائرية كما هو موضح بالشكل فطبعا
+
+213
+00:15:38,430 --> 00:15:42,570
+لهي الشخص وهي الحبل اتحرك حركة دائرية horizontal
+
+214
+00:15:42,570 --> 00:15:47,430
+في عندي أنا شدناحية المركز بيسموها ده هي
+
+215
+00:15:47,430 --> 00:15:50,090
+الcentrifugal force القوة ناحية المركز هي قوة
+
+216
+00:15:50,090 --> 00:15:53,990
+الcentrifugal force هي قوة الشد وفي المنطقة ده في
+
+217
+00:15:53,990 --> 00:15:59,970
+عندي أنا سرعة ممسية tangential force لأن why why
+
+218
+00:15:59,970 --> 00:16:03,570
+does the puck move in a circle طبعا هي بتتحرك حركة
+
+219
+00:16:03,570 --> 00:16:06,130
+دائرية بسبب وجود القوة المركزية هي اللي بتخليها
+
+220
+00:16:06,130 --> 00:16:09,590
+تتحرك حركة دائرية منتظمة because of its inertia
+
+221
+00:16:09,590 --> 00:16:13,390
+the tendency of the puck is to move in a straight
+
+222
+00:16:13,390 --> 00:16:17,750
+lineبأي حال the string prevent motion along the
+
+223
+00:16:17,750 --> 00:16:21,810
+straight line لإنه هي بتتحرك حركة دائرية ممكن
+
+224
+00:16:21,810 --> 00:16:24,370
+أحركها و أتركها بتستمر في الحركة نتيجة اللي هي
+
+225
+00:16:24,370 --> 00:16:29,570
+القصور الذاتى الالث by extending a radial force on
+
+226
+00:16:29,570 --> 00:16:32,990
+the puck a tension force that make it follow the
+
+227
+00:16:32,990 --> 00:16:36,030
+circular path في عندي حركة دائرية في مسار دائري
+
+228
+00:16:36,030 --> 00:16:40,430
+الشد هذا directed towards the center وبالتالي في
+
+229
+00:16:40,430 --> 00:16:44,480
+أبقى تمثل عن اللي هي الحركة المركزيةالحركة ال
+
+230
+00:16:44,480 --> 00:16:47,680
+centripetal force بتساوي ال MAC بتساوي ال MV تربيع
+
+231
+00:16:47,680 --> 00:16:52,000
+على R FC بيسموها centripetal أو net centripetal
+
+232
+00:16:52,000 --> 00:16:55,460
+force ال net force causing centripetal
+
+233
+00:16:55,460 --> 00:16:58,320
+acceleration هذه القوة المركزية بتسبب التسارق
+
+234
+00:16:58,320 --> 00:17:02,540
+المركزي اللي هو اتجاهه ناحية المركز and effects
+
+235
+00:17:02,540 --> 00:17:04,900
+change in the direction of the velocity vector
+
+236
+00:17:04,900 --> 00:17:09,700
+بيأثر على حركة او اتجاه اللي هي من تجاه السرعة if
+
+237
+00:17:09,700 --> 00:17:13,820
+that force should vanishإذا كان السرعة هذه أو
+
+238
+00:17:13,820 --> 00:17:17,460
+القوة انتهت the object would immediately leave its
+
+239
+00:17:17,460 --> 00:17:20,600
+circular path and move along the straight إذا هذه
+
+240
+00:17:20,600 --> 00:17:25,560
+القوة المركزية أو القوة هذه تلاشت فالجسم بيرجع
+
+241
+00:17:25,560 --> 00:17:30,340
+بتحرك حركة كأنها خط مستقيم مماسي لاللي هي الحركة
+
+242
+00:17:30,340 --> 00:17:34,220
+الأساسية اللي هي ال circular a radial force is a
+
+243
+00:17:34,220 --> 00:17:39,320
+vector القوة المركزية اللي هي إنتاجها عند نص الخطر
+
+244
+00:17:39,320 --> 00:17:43,210
+ال radialعبارة عن قوة متجهة and has direction the
+
+245
+00:17:43,210 --> 00:17:47,250
+second law for uniform circular motion involve
+
+246
+00:17:47,250 --> 00:17:50,250
+force that are directed either towards or the
+
+247
+00:17:50,250 --> 00:17:54,070
+center طبعا في عندي أنواعين من القوة ناحية المركز
+
+248
+00:17:54,070 --> 00:17:57,670
+وطالة عن المركز ال force acting ال force اللي بتثق
+
+249
+00:17:57,670 --> 00:18:03,450
+تؤثر داخل المركز باعتبرها negative و القوة اللي
+
+250
+00:18:03,450 --> 00:18:09,250
+بتأثر خارج المركز باعتبرها positivethe centripetal
+
+251
+00:18:09,250 --> 00:18:11,930
+acceleration is negative الآن الcentripetal
+
+252
+00:18:11,930 --> 00:18:15,590
+acceleration القوة المركزية بناء على ما ذكر تعتبر
+
+253
+00:18:15,590 --> 00:18:21,170
+سالبة لإنها تؤثر ناحية المركز قانون نيوتن التاني
+
+254
+00:18:21,170 --> 00:18:25,270
+لل uniform circular motion ممكن أكتبه بهذا الشكل
+
+255
+00:18:25,270 --> 00:18:29,370
+summation للأفقار بتساوي ناخص mv تربيع على r هذي
+
+256
+00:18:29,370 --> 00:18:32,050
+بيسموها ال radial force summation لل radial force
+
+257
+00:18:32,480 --> 00:18:35,380
+بتساوى ناقص mv تربيع على r في ال radial force
+
+258
+00:18:35,380 --> 00:18:38,800
+القوة اللى ناحية المركز سالبة و اللى خارجها من
+
+259
+00:18:38,800 --> 00:18:43,640
+المركز تعتبر موجبة الاف R بيسموها ال radial force
+
+260
+00:18:43,640 --> 00:18:49,120
+acting on the mass m positive if the force is away
+
+261
+00:18:49,120 --> 00:18:53,520
+from the center and negative if the force is
+
+262
+00:18:53,520 --> 00:18:57,280
+towards the center بالنسبة لها ال استراتيجية كيف
+
+263
+00:18:57,280 --> 00:19:00,580
+ممكن نحل مسائل بالنسبة لها ال centripetal
+
+264
+00:19:00,580 --> 00:19:04,300
+accelerationبنستخدم هاي الخطوات التالية بنرسم ال
+
+265
+00:19:04,300 --> 00:19:08,500
+free body diagram و بنرسم القوة المحاور و بنرسم
+
+266
+00:19:08,500 --> 00:19:14,040
+القوة المؤثرة على كل طبعا على الجسم بالنسبة لل net
+
+267
+00:19:14,040 --> 00:19:17,220
+force Fc towards the center ال Fc بتساوي summation
+
+268
+00:19:17,220 --> 00:19:21,620
+لل Fr ال Fr is the sum of the radial component
+
+269
+00:19:21,620 --> 00:19:26,120
+this net radial force ببستخدم بعد هي كده summation
+
+270
+00:19:26,120 --> 00:19:29,520
+للقوة بتساوي اللي هي ال ال .. اللي هي ال MV
+
+271
+00:19:29,520 --> 00:19:33,010
+squared على Rيعني ال F R بيستوى ال M في AC و ال F
+
+272
+00:19:33,010 --> 00:19:36,830
+T بيستوى ال M في TT و ال F N بيستوى ال M في AN حسب
+
+273
+00:19:36,830 --> 00:19:41,290
+ال F و حسب التسارع ال magnitude of the centripetal
+
+274
+00:19:41,290 --> 00:19:44,430
+acceleration for the uniform circular motion
+
+275
+00:19:44,430 --> 00:19:48,390
+بيستوى V تربيه على R بعد هيك بنحل المثلة و بنوجد
+
+276
+00:19:48,390 --> 00:19:54,270
+المتغيرات ناخد هذا السؤال عندي سيارة is a car
+
+277
+00:19:54,270 --> 00:19:59,300
+travel at constant speed تلاتين ميل في الساعةon
+
+278
+00:19:59,300 --> 00:20:03,340
+level circular 10 of radius 50 تتحرك بسرعة 30 ميل
+
+279
+00:20:03,340 --> 00:20:08,780
+في الساعة يعني 13.4 متر في الثانية على مستوى دائري
+
+280
+00:20:08,780 --> 00:20:15,360
+طبعا ب radius 50 متر طبعا shown in the paired eye
+
+281
+00:20:15,360 --> 00:20:21,260
+view كأنه يعني هي in focus مركزة يعني كأنه طائر
+
+282
+00:20:21,260 --> 00:20:25,130
+بيطير وشايف الوضعwhat minimum coefficient of
+
+283
+00:20:25,130 --> 00:20:29,810
+static friction mus between the tires and the
+
+284
+00:20:29,810 --> 00:20:32,870
+roadway will allow the car to make the circular
+
+285
+00:20:32,870 --> 00:20:38,230
+turn without sliding بدي معامل احتكاك الساكن اللي
+
+286
+00:20:38,230 --> 00:20:42,730
+بين العجلات وبين الأرض بيخلي السيارة تتحرك حركة
+
+287
+00:20:42,730 --> 00:20:47,510
+دائرية منتظمة طبعا هي الشكل عندنا احنا الشكل من
+
+288
+00:20:47,510 --> 00:20:52,010
+أعلى كأنه يعني طائر بينظر إلى أعلى هد السيارة على
+
+289
+00:20:52,010 --> 00:20:55,960
+الأرضالسيارة ده تدور بهذا ال .. على ال curve طبعا
+
+290
+00:20:55,960 --> 00:20:59,620
+في قوة بتمنعها انها تتحرك قوة الاحتكاك الساكن هي
+
+291
+00:20:59,620 --> 00:21:02,320
+اللي بتحافظ على انها .. انها ما .. لا تنزلق هذه
+
+292
+00:21:02,320 --> 00:21:08,100
+السيارة و طبعا .. طبعا بتلف او بتدور حوالي .. في
+
+293
+00:21:08,100 --> 00:21:12,540
+مسار دائر أو بتتحرك مسار دائر منتظم بنكتب اللي هي
+
+294
+00:21:12,540 --> 00:21:16,880
+.. بنستخدم قانون و تن التاني و بنحكي انه اللي هي
+
+295
+00:21:16,880 --> 00:21:21,330
+mv squared على r بتها تساويميو أس في ال normal
+
+296
+00:21:21,330 --> 00:21:24,570
+اللي هي الأف أس القوة هذه اللي هي الأف أس هي القوة
+
+297
+00:21:24,570 --> 00:21:27,790
+المركزية القوة الأس الأف أس هي القوة المركزية
+
+298
+00:21:27,790 --> 00:21:30,750
+summation للأف أر بتساوي ناقص mv squared على r
+
+299
+00:21:30,750 --> 00:21:34,370
+والأف أر بتساوي ناقص ميو أس في ال normal ال normal
+
+300
+00:21:34,370 --> 00:21:37,970
+بتساوي ال mg إذا ال normal ناقص ال mg بتساوي zero
+
+301
+00:21:37,970 --> 00:21:42,690
+هذا ال vertical component وبنعود عن اللي هي ال
+
+302
+00:21:42,690 --> 00:21:46,630
+normal بتساوي ال mg ال m بتساوي ناقص ال m وال سالب
+
+303
+00:21:46,630 --> 00:21:50,560
+بتروح مع السالب بتطلع عندىالـ mu s بتساوي V تربيه
+
+304
+00:21:50,560 --> 00:21:56,680
+على R في G V أطانيها 13.4 تربيه على ال R 50 وال G
+
+305
+00:21:56,680 --> 00:22:02,920
+9.8 بتطلع mu s 0.366 دوغمها اسمه معامل احتكاك
+
+306
+00:22:02,920 --> 00:22:07,700
+الساكن الذي يجعل السيارة تدور حركة دائرية منطقة
+
+307
+00:22:07,700 --> 00:22:13,420
+نجل نوع تاني من الأسئلة بيسموها اللي هي banquet
+
+308
+00:22:13,420 --> 00:22:18,960
+roadاللي هي سيارة بتدور على يعني طريق دائري
+
+309
+00:22:18,960 --> 00:22:23,520
+pancadi يعني طريق عالي شوية منحضر ودائري with
+
+310
+00:22:23,520 --> 00:22:27,340
+maximum radius ال radius كانت تلت مية وست عشر متر
+
+311
+00:22:27,340 --> 00:22:31,000
+if a car negotiated the curve too slowly طبعا
+
+312
+00:22:31,000 --> 00:22:35,560
+السيارة بدها تدور على المنحنة بكل بطوء حتى تستطيع
+
+313
+00:22:35,560 --> 00:22:40,070
+انها تدور على المنحنةدورة او .. او مسار دائري it
+
+314
+00:22:40,070 --> 00:22:44,450
+tends to slip down the incline of the turn طبعا
+
+315
+00:22:44,450 --> 00:22:50,430
+بتميل انها بتدور حوالين مسار يعني ميل منحدر ميل
+
+316
+00:22:50,430 --> 00:22:56,730
+بزاوية معينة و بتحاول انها تسرق في .. في هذا
+
+317
+00:22:56,730 --> 00:23:01,020
+المسار و تدور حركة دائرية في هذه الحالةمطلوب مننا
+
+318
+00:23:01,020 --> 00:23:06,460
+نوجد اللى هى centripetal acceleration ونوجد اللى
+
+319
+00:23:06,460 --> 00:23:12,160
+هى سرعة السيارة مع اهمال الاحتكاك طبعا هى السيارة
+
+320
+00:23:12,160 --> 00:23:15,210
+هى المستوى المايل و هى بدأ تدور حركة دائريةالحركة
+
+321
+00:23:15,210 --> 00:23:18,130
+الدائرية بهذا الشكل طبعا في هذا السؤال احنا
+
+322
+00:23:18,130 --> 00:23:21,370
+مابنحلل ال mg لأنه اذا حللنا ال mg هييجي بهذا
+
+323
+00:23:21,370 --> 00:23:24,130
+الاتجاه وهذا الاتجاه بعيدا عن الحركة الدائرية
+
+324
+00:23:24,130 --> 00:23:28,250
+الحركة الدائرية بهذا الشكل هنا هيك اذا راح احلل ال
+
+325
+00:23:28,250 --> 00:23:33,050
+normal راح نحلل ال normal إلى قوتين هنا اللي هو ال
+
+326
+00:23:33,050 --> 00:23:38,070
+n sin θ و هنا في ال vertical n cos θ الخوة الداخلة
+
+327
+00:23:38,070 --> 00:23:41,430
+ناحية المركز هي عبارة عن ال n بهذا الاتجاه اللي هي
+
+328
+00:23:41,430 --> 00:23:42,390
+n sin θ
+
+329
+00:23:51,840 --> 00:23:54,700
+الان ناقص الام جي بالساوة zero يعني الان ناقص الام
+
+330
+00:23:54,700 --> 00:23:55,440
+جي بالساوة zero يعني الان ناقص الام جي بالساوة
+
+331
+00:23:55,440 --> 00:23:56,420
+zero يعني الان ناقص الام جي بالساوة zero يعني الان
+
+332
+00:23:56,420 --> 00:23:56,420
+ناقص الام جي بالساوة zero يعني الان ناقص الام جي
+
+333
+00:23:56,420 --> 00:23:56,420
+بالساوة zero يعني الان ناقص الام جي بالساوة zero
+
+334
+00:23:56,420 --> 00:23:56,420
+يعني الان ناقص الام جي بالساوة zero يعني الان ناقص
+
+335
+00:23:56,420 --> 00:23:57,320
+الام جي بالساوة zero يعني الان ناقص الام جي
+
+336
+00:23:57,320 --> 00:24:00,780
+بالساوة zero يعني الان ناقص الام جي بالساوة zero
+
+337
+00:24:00,780 --> 00:24:07,740
+يعني الان ناقص الام جي بالساوة zero يعني الان ناقص
+
+338
+00:24:07,740 --> 00:24:13,250
+الامالان mg على cosine ساين على كوزاين بتساوي
+
+339
+00:24:13,250 --> 00:24:19,250
+التان ناقص mg تان ال theta بعد هيك بنعوض اللي هي
+
+340
+00:24:19,250 --> 00:24:24,050
+ال ac عشان اوجدها اللي هي fc بتساوي ال m في ac اذا
+
+341
+00:24:24,050 --> 00:24:28,010
+ال ac بتساوي ال fc على m بنعوض و بتطلع ناقص g تان
+
+342
+00:24:28,010 --> 00:24:32,830
+ال theta ال ac بدها تساوي ال g تسعة و تمانية من
+
+343
+00:24:32,830 --> 00:24:36,070
+عشرة و التان واحد تلاتين بعد هيك بدأ اوجد سرعة
+
+344
+00:24:36,070 --> 00:24:40,870
+السيارة طبعا سرعة السيارة من ال acبتساوي V تربيع
+
+345
+00:24:40,870 --> 00:24:45,570
+على R بتطلع ل V ناقص R على AC طبعا هذه ناقص وهذه
+
+346
+00:24:45,570 --> 00:24:50,730
+ناقص تطلع موجب تحت الجزر 43.1 متر في الثانية تربيع
+
+347
+00:24:54,600 --> 00:24:58,300
+عنا مثال اللى هى a roller coaster car moving
+
+348
+00:24:58,300 --> 00:25:02,120
+around a circle of radius R what speed must the
+
+349
+00:25:02,120 --> 00:25:05,100
+car have at the top of the loop so that it will
+
+350
+00:25:05,100 --> 00:25:08,240
+just make it over the top without any assistance
+
+351
+00:25:08,240 --> 00:25:12,340
+from the track طبعا الشكل هذا السيارة بتتحرك فى
+
+352
+00:25:12,340 --> 00:25:16,640
+مسار دائري اللعبة طبعا بتتحرك فى مسار دائري طبعا
+
+353
+00:25:16,640 --> 00:25:23,040
+منحنى فى منطقة معينة هنا مطلوب منها نوجد اللى هى
+
+354
+00:25:23,040 --> 00:25:28,410
+نمرة Aمطلوب مننا نوجد ال speed at the bottom of
+
+355
+00:25:28,410 --> 00:25:31,230
+the loop طبعا عندي أنا loop دائرة لنوجد عند
+
+356
+00:25:31,230 --> 00:25:35,030
+المنطقة هاد السرعة طبعا عند المنطقة هاد فيها أنا
+
+357
+00:25:35,030 --> 00:25:38,590
+سيارة و في عندي مسار طالما أنه في جسم على المسار
+
+358
+00:25:38,590 --> 00:25:42,190
+إذا في عندي normal إلى أعلى و في عندي MG إلى أسفل
+
+359
+00:25:42,190 --> 00:25:45,970
+اتفقنا أن القوة للاهية المركز سالبة و لطالع من
+
+360
+00:25:45,970 --> 00:25:50,650
+المركز موجبة عفوا اللي جوا المركز سالب .. موج ..
+
+361
+00:25:50,650 --> 00:25:54,960
+سالبة و لطالع من المركزموجبة هنستخدم قانون نيوتن
+
+362
+00:25:54,960 --> 00:26:00,820
+التاني اذا ال MAC بسوء ال normal زائد ال MG اللي
+
+363
+00:26:00,820 --> 00:26:06,400
+هي المسف الأكسوميشن لل FAC FAC بسوء ال MAC بستخدم
+
+364
+00:26:06,400 --> 00:26:12,340
+قانون نيوتن التاني اذا ال normal at the top of the
+
+365
+00:26:12,340 --> 00:26:16,520
+loop اذا حطينا لان بسوء zero the force of gravity
+
+366
+00:26:16,520 --> 00:26:19,340
+acts towards the center and provide the
+
+367
+00:26:19,340 --> 00:26:23,470
+centripetal acceleration بتصير AC بسوء ناقصV تربيع
+
+368
+00:26:23,470 --> 00:26:30,910
+على R اذا MG بتساوي ال MV تربيع على R بنحلها و
+
+369
+00:26:30,910 --> 00:26:35,890
+بنطلق ال V at the top of ال V عند ال .. at the top
+
+370
+00:26:35,890 --> 00:26:44,330
+of the track او المسار V بتساوي جزر ال GR طبعا عند
+
+371
+00:26:44,330 --> 00:26:48,870
+الأسفل ال normal موجودة apply conservation of
+
+372
+00:26:48,870 --> 00:26:53,150
+mechanical energy بستخدم ال mechanical energyطبعا
+
+373
+00:26:53,150 --> 00:26:56,850
+بأوجد اللى هى السرعة بالساوية نص Mv تربيه عند ال
+
+374
+00:26:56,850 --> 00:27:00,630
+top زايد ال Mgh طبعا عند ال top بيكونيلها طاقة وضع
+
+375
+00:27:00,630 --> 00:27:06,290
+وطاقة حركة اللى هى Mgr Mg في R ال R اللى هى البعد
+
+376
+00:27:06,290 --> 00:27:10,730
+العمودي اللى هى .. اللى هى البعد من ال .. من البعد
+
+377
+00:27:10,730 --> 00:27:15,870
+اللى هى نص الخطور زايد Mg في اتنين R بالساوية
+
+378
+00:27:15,870 --> 00:27:20,110
+اتنين و نص Mgr لما أوجد ال total mechanical energy
+
+379
+00:27:21,500 --> 00:27:25,060
+at the bottom ال E bottom بيساوي نص M V تربيع عند
+
+380
+00:27:25,060 --> 00:27:28,460
+ال bottom النقطة اللي تحت ال energy is conserved
+
+381
+00:27:28,460 --> 00:27:33,240
+so this energy make equal and solve for V لل .. لل
+
+382
+00:27:33,240 --> 00:27:37,900
+bottom اذا نص M V تربيع لل bottom بيساوي اتنين و
+
+383
+00:27:37,900 --> 00:27:43,700
+نص MGR ال V لل bottom بيساوي جزر خمسة GR يعني عند
+
+384
+00:27:43,700 --> 00:27:47,240
+.. لما اوجد ال normal force ل .. لل نقطة اللي هي
+
+385
+00:27:47,240 --> 00:27:51,300
+ال bottom بده اوجد ال normalفعنا ال MG ناقص ال
+
+386
+00:27:51,300 --> 00:27:55,080
+normal طبعا ال MG موجب هو normal سالب لإن ال
+
+387
+00:27:55,080 --> 00:27:58,060
+normal ناحية المركز و ال MG طالع من المركز هدولا
+
+388
+00:27:58,060 --> 00:28:01,300
+التنتين بدهم يساووا ال MV² على R اللي هي القوة
+
+389
+00:28:01,300 --> 00:28:05,760
+المركزية او القوة المركزية فمن هنا بنوجد ال normal
+
+390
+00:28:05,760 --> 00:28:09,940
+force and ال bottom بنلاحظ إن ال normal force
+
+391
+00:28:09,940 --> 00:28:13,520
+بتصرف towards the center of the circle عبارة ..
+
+392
+00:28:13,520 --> 00:28:17,810
+عشان هي ك .. هي negativethe car weight acts away
+
+393
+00:28:17,810 --> 00:28:22,070
+from the center هي positive وبالتالي ال normal
+
+394
+00:28:22,070 --> 00:28:26,970
+بيساوي ال mg زايد m v تربيع على r بيساوي ال mg
+
+395
+00:28:26,970 --> 00:28:31,630
+زايد m خمسة gr على r اللي هي ستة mg كده بنكون
+
+396
+00:28:31,630 --> 00:28:36,450
+أوجدنا ال normal at the bottom of the .. at the
+
+397
+00:28:36,450 --> 00:28:40,090
+bottom of the اللي هي ال motion بالنسبة للحركة
+
+398
+00:28:40,090 --> 00:28:45,650
+section سبعة أربعة ملغي كدهالى هنا بنكون قد
+
+399
+00:28:45,650 --> 00:28:49,250
+انتهينا من الأجزاء المطلوبة من chapter 7
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs.srt
new file mode 100644
index 0000000000000000000000000000000000000000..6f1424795470a5c4b3c1f905c9a059af05c76ae4
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs.srt
@@ -0,0 +1,702 @@
+1
+00:00:00,000 --> 00:00:03,700
+بسم الله الرحمن الرحيم example تلاتة تلاتة مثال
+
+2
+00:00:03,700 --> 00:00:08,580
+تلاتة تلاتة a long jumper leaves the ground at an
+
+3
+00:00:08,580 --> 00:00:12,740
+angle of عشرين درجة to the horizontal and at a
+
+4
+00:00:12,740 --> 00:00:17,560
+speed of أحد عشر متر في الثانية الرجل بده يقفز قفزة
+
+5
+00:00:17,560 --> 00:00:24,320
+طويلة طبعًا قفز بدرجات عشرين درجة مئوية يعني سرعة
+
+6
+00:00:24,320 --> 00:00:31,260
+سرعة القذف عشرين درجة to the horizontal and بسرعة
+
+7
+00:00:31,260 --> 00:00:35,640
+ابتدائية 11 متر في الثانية how long does it
+
+8
+00:00:35,640 --> 00:00:39,500
+take for him to reach maximum height مطلب مني أوجد
+
+9
+00:00:39,500 --> 00:00:43,440
+أقصى ارتفاع أيضًا what is the maximum height أيضًا
+
+10
+00:00:43,440 --> 00:00:47,940
+أقصى ارتفاع و how far does he jump بده المسافة
+
+11
+00:00:47,940 --> 00:00:52,500
+اللي هو قذفها assume his motion is equivalent to
+
+12
+00:00:52,500 --> 00:00:56,260
+that of a particle بدي اعتبر أن حركته زي حركة أي
+
+13
+00:00:56,260 --> 00:01:03,920
+particle طبعًا بدنا نحل و نستخدم معادلات الحركة هي
+
+14
+00:01:03,920 --> 00:01:11,840
+الشكل بده يقفز قفزة بزاوية 20 و قفز مسافة معينة
+
+15
+00:01:11,840 --> 00:01:20,300
+طبعًا بسرعة 11 متر في الثانية هنحل الآن السؤال اللي
+
+16
+00:01:20,300 --> 00:01:24,180
+هو المطلوب الأول Find the time T maximum taken to
+
+17
+00:01:24,180 --> 00:01:27,460
+reach maximum height مطلوب منها نوجد أقصى الزمن
+
+18
+00:01:27,460 --> 00:01:32,580
+اللازم للوصول إلى أقصى ارتفاع VY بنعتبرها Zero لأن
+
+19
+00:01:32,580 --> 00:01:36,960
+عند أقصى ارتفاع V النهائية بتساوي Zero وبدأ أحل له
+
+20
+00:01:36,960 --> 00:01:43,100
+ذا بأستخدم معادلة 3.9 VY بتساوي V not Y V
+
+21
+00:01:43,100 --> 00:01:52,640
+not sin θ ناقص GT V not sin θ على G بتساوي T لأن V
+
+22
+00:01:52,640 --> 00:01:59,640
+النهائية بتساوي 0 بنعوض V note 11 sin θ sin 20
+
+23
+00:01:59,640 --> 00:02:05,540
+والجي 9.8 من عشرة بتطلع 0.38 ثانية هذا الزمن
+
+24
+00:02:05,540 --> 00:02:10,520
+اللازم علشان يوصل لأقصى ارتفاع find the maximum
+
+25
+00:02:10,520 --> 00:02:16,460
+height هي reach مطلوب أقصى ارتفاع بيوصله بدي أفرض
+
+26
+00:02:16,460 --> 00:02:21,970
+أن ال T maximum معادلة الوقت تي ماكسيمام into
+
+27
+00:02:21,970 --> 00:02:25,550
+equation y بيقوم بتعويض عن تي ماكسيمام
+
+28
+00:02:35,850 --> 00:02:51,830
+V0Y V0SINθT-1.5GT2T-1.5GT2V0SINθT
+
+29
+00:02:51,830 --> 00:02:53,570
+-1.5GT2T-1.5Y
+
+30
+00:02:58,960 --> 00:03:03,800
+Find the horizontal distance هي jump بده المسافة
+
+31
+00:03:03,800 --> 00:03:08,160
+الأفقية اللي هو قفزها يعني بده ال range يعني بده
+
+32
+00:03:08,160 --> 00:03:14,840
+ال fixed أول حاجة بده أوجد الزمن for the jump which is
+
+33
+00:03:14,840 --> 00:03:19,300
+Yc maximum بده الزمن كله إحنا حسبنا بالأول الزمن
+
+34
+00:03:19,300 --> 00:03:25,380
+اللازم لكي يصل لأقصى ارتفاع كانت 3.8
+
+35
+00:03:25,380 --> 00:03:29,320
+الزمن اللازم لكل حركة بنضربه في اثنين أو زمن
+
+36
+00:03:29,320 --> 00:03:33,000
+التحليق كله بيسموه T بتساوي اثنين في T maximum
+
+37
+00:03:33,000 --> 00:03:38,140
+بتطلع 7.6 ثانية Substitute this result
+
+38
+00:03:38,140 --> 00:03:42,040
+into the equation بالعودة بهذه النتيجة في المعادلة
+
+39
+00:03:42,040 --> 00:03:55,550
+عشان معادلة ال X لإيجاد دلتا X V0 X T V0 X T V0 X T
+
+40
+00:03:55,550 --> 00:04:07,980
+V0 X T V0 X T V0 X T لإيجاد ال maximum height ممكن
+
+41
+00:04:07,980 --> 00:04:12,000
+استخدم طريقة أخرى لإيجاد ال maximum height ممكن
+
+42
+00:04:12,000 --> 00:04:20,040
+استخدم أن دلتا Y بتساوي V not V not تربيع أو V
+
+43
+00:04:20,040 --> 00:04:24,300
+تربيع نهائية بتساوي V not تربيع ناقص 2GY أو VY
+
+44
+00:04:24,300 --> 00:04:28,560
+تربيع ناقص V not Y تساوي ناقص 2GY إذا دلتا Y
+
+45
+00:04:28,560 --> 00:04:34,150
+بتساوي VY تربيع ناقص V not Y تربيع على 2GVy أن
+
+46
+00:04:34,150 --> 00:04:42,750
+أقصى ارتفاع كانت 0 V0 كانت 11 sin θ والجي 9.8 من عشرة
+
+47
+00:04:42,750 --> 00:04:44,850
+بنعوض في القانون
+
+48
+00:04:53,790 --> 00:04:59,810
+V0 11 SIN 20 V0 11 SIN 20 V0 11 SIN 20
+
+49
+00:04:59,810 --> 00:05:10,650
+V0 11 SIN 20 V0 11 SIN 20
+
+50
+00:05:16,030 --> 00:05:22,010
+مثال تلاتة أربعة أن ثلاثة participate in a long
+
+51
+00:05:22,010 --> 00:05:25,330
+jump competition leaping into the air with
+
+52
+00:05:25,330 --> 00:05:28,570
+velocity v naught at an angle theta naught with
+
+53
+00:05:28,570 --> 00:05:30,950
+the horizontal obtain the expression of the length
+
+54
+00:05:30,950 --> 00:05:35,510
+of the jump in terms of v naught and theta naught
+
+55
+00:05:35,510 --> 00:05:43,380
+and g طبعًا لو كان عندي أحد بده يقفز مسافة معينة أو
+
+56
+00:05:43,380 --> 00:05:46,200
+مشاركين في مسابقة بدهم يقفزوا مسافة معينة بدنا
+
+57
+00:05:46,200 --> 00:05:50,640
+نوجد اللي هي ال horizontal range أو ال distance
+
+58
+00:05:50,640 --> 00:05:55,280
+horizontal displacement أو كمان بدنا نوجد اللي هي
+
+59
+00:05:55,280 --> 00:05:58,860
+V note و G note بدنا نوجد أيضًا ال maximum height
+
+60
+00:05:58,860 --> 00:06:02,580
+ممكن نوجد الزمن اللي هو ال time magnitude V
+
+61
+00:06:02,580 --> 00:06:08,270
+maximum بدل ما نوجد V0 وθ0 وG اتفقنا أن T بتساوي 2T
+
+62
+00:06:08,270 --> 00:06:14,590
+maximum T maximum بتساوي V0 sin θ على G إذا ممكن
+
+63
+00:06:14,590 --> 00:06:18,250
+نعوض بهذه القيمة اللي هي عن ال T في المعادلة
+
+64
+00:06:18,250 --> 00:06:22,710
+الثانية اللي إحنا استخدمناها يعني Delta X بتساوي
+
+65
+00:06:22,710 --> 00:06:28,930
+V0 Cos θ في T كانت بتساوي 2V0 sin θ0 على G ممكن
+
+66
+00:06:28,930 --> 00:06:34,190
+نستخدم المعادلات طبعًا حفظ القانون ما بيضبط إلا إحنا
+
+67
+00:06:34,190 --> 00:06:38,010
+نحّل من البداية بوصف قوانين الحركة هنا إحنا جبنا
+
+68
+00:06:38,010 --> 00:06:44,050
+delta x بدلالة v0 و g جبنا T بدلالة v0 و g ممكن
+
+69
+00:06:44,050 --> 00:06:50,160
+نجيب اللي هي delta x أيضًا بدلالة v0 و sin 2θ الدلتا
+
+70
+00:06:50,160 --> 00:06:54,320
+اكس بتساوي اثنين V0 تربيع كوزاين تيتا ساين تيتا
+
+71
+00:06:54,320 --> 00:07:01,680
+على G طبعًا كوزاين تيتا 0 ساين تيتا نوت في اثنين
+
+72
+00:07:01,680 --> 00:07:07,020
+بتساوي ساين اثنين تيتا نوت هذا قانون رياضي طبعًا
+
+73
+00:07:07,020 --> 00:07:10,840
+هذه القوانين ممكن إحنا نحصل عليها بدلالة تيتا نوت
+
+74
+00:07:10,840 --> 00:07:11,820
+و G V0
+
+75
+00:07:16,080 --> 00:07:21,920
+سؤال problem 35 بيقول بيقول بذكرها أُلقيت كرة
+
+76
+00:07:21,920 --> 00:07:27,260
+رأسياً من أعلى مبنى بزاوية 30
+
+77
+00:07:27,260 --> 00:07:31,760
+درجة و بسرعة and with an initial speed of 20
+
+78
+00:07:31,760 --> 00:07:37,200
+متر في الثانية من مبنى طوله 45 متر و رمينا
+
+79
+00:07:37,200 --> 00:07:44,350
+منه كرة بسرعة 20 متر في الثانية بزاوية 30 درجة The
+
+80
+00:07:44,350 --> 00:07:47,430
+point of the release is أعلى المبنى نقطة طول
+
+81
+00:07:47,430 --> 00:07:50,710
+الارتفاع المبدئي من الground How long does it take
+
+82
+00:07:50,710 --> 00:07:54,130
+for the ball to hit the ground؟ بدو الزمن اللازم
+
+83
+00:07:54,130 --> 00:07:59,210
+علشان الكورة تصل إلى الأرض بدو الزمن اللازم
+
+84
+00:07:59,210 --> 00:08:03,970
+لكي تصل الكورة إلى الأرض كمان مطلوب the ball speed
+
+85
+00:08:03,970 --> 00:08:08,070
+at impact بدو السرعة النهائية للكرة you see find
+
+86
+00:08:08,070 --> 00:08:11,450
+the horizontal range of the ball بدو المسافة
+
+87
+00:08:11,450 --> 00:08:16,030
+الأفقية اللي وقعت فيها الكرة أو ال range طبعًا
+
+88
+00:08:16,030 --> 00:08:20,190
+بإهمال
+
+89
+00:08:20,190 --> 00:08:26,420
+مقاومة الهواء هي الشكل الموضح هي الشكل في عندي أنا
+
+90
+00:08:26,420 --> 00:08:33,420
+ارتفاع مبنى 45 وفي عندي شخص واقف في هذه النقطة وقدف
+
+91
+00:08:33,420 --> 00:08:40,060
+كرة بزاوية 34 درجة و بسرعة 20 متر في الثانية الكرة
+
+92
+00:08:40,060 --> 00:08:44,200
+مشيت هذا المسار اللي هو الموضح لغاية ما وصلت
+
+93
+00:08:44,200 --> 00:08:48,060
+الأرض و بدو الزمن اللازم لكي تصل هذه الكرة إلى
+
+94
+00:08:48,060 --> 00:08:52,620
+هذه المنطقة وبدو أين وقعت بدي أوجد المسافة هذه
+
+95
+00:08:52,620 --> 00:08:58,470
+كلها اللي هي ال X والارتفاع قبلها كان 45 في البداية
+
+96
+00:08:58,470 --> 00:09:03,130
+بدي أوجد ال ball time of flight بدي أوجد زمن
+
+97
+00:09:03,130 --> 00:09:12,650
+التحليق زمن التحليق للكرة بأوجد V0X هي V0 cos θ 20
+
+98
+00:09:12,650 --> 00:09:22,030
+متر في cos 30 بتطلع 17.3  لأن V0Y V0 sin θ تساوي 20
+
+99
+00:09:22,030 --> 00:09:27,740
+sin 30 يعني 10 متر في الثانية بدءًا أختار الـ Y
+
+100
+00:09:27,740 --> 00:09:32,240
+displacement يجب أن أعتبر الـ Y0 بتساوي 0 و الـ Y
+
+101
+00:09:32,240 --> 00:09:40,280
+ناقص 45 و V0 Y بتساوي 10 فـ delta Y بتساوي Y ناقص
+
+102
+00:09:40,280 --> 00:09:40,960
+Y0
+
+103
+00:09:46,600 --> 00:09:52,960
+Y كانت ناقص خمسة و أربعين لأن هو الجسم نازل V not
+
+104
+00:09:52,960 --> 00:09:59,380
+بتاع V not عشرة في T اللي هي مجهولة ناقص نصف في
+
+105
+00:09:59,380 --> 00:10:02,580
+تسعة و ثمانية من عشرة في T تربيع
+
+106
+00:10:02,580 --> 00:10:07,460
+طبعًا هي معادلة تربيعية لها طبعًا حل يا إما بواسط
+
+107
+00:10:07,460 --> 00:10:12,900
+القانون يا إما بواسط تحليل المعادلة فتطلع T فأخذ
+
+108
+00:10:12,900 --> 00:10:18,560
+T التي هي قريبة من 4.32 هذا الزمن
+
+109
+00:10:18,560 --> 00:10:24,020
+هو أقل زمن اللازم لتصل الكرة إلى نهاية مسارها
+
+110
+00:10:24,020 --> 00:10:29,460
+تبعها اللي برا Find the ball speed at impact بده
+
+111
+00:10:29,460 --> 00:10:34,240
+سرعة الكرة عندما تصطدم بالأرض Substitute the
+
+112
+00:10:34,240 --> 00:10:38,420
+value of T found in part A into the equation 3.9
+
+113
+00:10:38,420 --> 00:10:43,300
+to find the Y component إذا بده أوجد ال VY
+
+114
+00:10:43,300 --> 00:10:51,720
+المتجهة  Y ناقص GT V0Y 10 - 9.8 في الزمن 4.32 فبتطلع
+
+115
+00:10:51,720 --> 00:10:57,620
+عندي VY ناقص 31.3 فطبعًا بالسالب لأنه نازل من ارتفاع
+
+116
+00:10:57,620 --> 00:11:04,180
+الثاني و عملتها طبعًا VY جبتها VX موجودة عندي
+
+117
+00:11:04,180 --> 00:11:12,000
+فاستخدم اللي هي القانون اللي هو فيثاغورس في
+
+118
+00:11:12,000 --> 00:11:17,160
+فيثاغورس فبنستخدم فيثاغورس  فبنوجد ال V بتساوي جذر VX
+
+119
+00:11:17,160 --> 00:11:22,900
+تربيع زائد VY تربيع VX تربيع هي نفسها V0 VX تربيع
+
+120
+00:11:22,900 --> 00:11:31,400
+هي 17.3 تربيع زائد هي ناقص 31.4 تربيع فبنحصل على 35.9
+
+121
+00:11:31,400 --> 00:11:35,040
+متر في الثانية هذه هي السرعة النهائية اللي الكرة
+
+122
+00:11:35,040 --> 00:11:41,720
+وصلت فيها للأرض في C طالب مني find the Horizontal Range
+
+123
+00:11:41,720 --> 00:12:04,040
+of the ball هو أي مسافة قطعتها يعني Delta X
+
+124
+00:12:04,930 --> 00:12:08,470
+سيكشن جديد وهو two-dimensional constant
+
+125
+00:12:08,470 --> 00:12:12,840
+acceleration. We have studied only problems in which an
+
+126
+00:12:12,840 --> 00:12:15,980
+object with an initial velocity follows a
+
+127
+00:12:15,980 --> 00:12:18,500
+trajectory determined by the acceleration of the
+
+128
+00:12:18,500 --> 00:12:24,760
+gravity alone. لو إحنا اللي درسناها سابقًا كانت
+
+129
+00:12:24,760 --> 00:12:30,220
+بتتحرك ب constant speed و الحركة AX تساوي zero و أن
+
+130
+00:12:30,220 --> 00:12:32,500
+أنا بتحرك بالتسارع اللي هي acceleration of the
+
+131
+00:12:32,500 --> 00:12:36,200
+gravity in the more general case other agents such
+
+132
+00:12:36,200 --> 00:12:40,690
+as air trapped surface friction or engines can
+
+133
+00:12:40,690 --> 00:12:45,010
+cause acceleration ممكن يكون عندي أنا اعتقاد ممكن
+
+134
+00:12:45,010 --> 00:12:50,650
+يكون عندي يعني عوامل خاصة في ال .. في الظروف
+
+135
+00:12:50,650 --> 00:12:55,480
+المحيطة بالـ .. بال object أو في الجسم بيصير عندي
+
+136
+00:12:55,480 --> 00:12:58,740
+acceleration  إضافي and this acceleration
+
+137
+00:12:58,740 --> 00:13:01,040
+taken together forms the vector of amplitude
+
+138
+00:13:01,040 --> 00:13:06,560
+components dx ممكن أستخدم dx في هذه الحالة إذا كان
+
+139
+00:13:06,560 --> 00:13:10,040
+أنا الجسم بعد ما وصل للأرض ممكن يمشي أو يتحرك
+
+140
+00:13:10,040 --> 00:13:13,440
+بسرعة معينة when both components are constant
+
+141
+00:13:13,440 --> 00:13:19,220
+ويكون يواصل حركته بثبات هذه هي المعادلات
+
+142
+00:13:19,220 --> 00:13:24,530
+اللي أنا ممكن أحلها لو الجسم تحرك بتسارع AX موجود
+
+143
+00:13:24,530 --> 00:13:29,110
+يعني VX بتساوي V not X زائد AX في T نقطة X بتساوي
+
+144
+00:13:29,110 --> 00:13:34,090
+V not X في T زائد نصف AX T تربيع VX تربيع بتساوي V
+
+145
+00:13:34,090 --> 00:13:38,790
+not X تربيع زائد اثنين AX تربيع في نقطة X وVY
+
+146
+00:13:38,790 --> 00:13:42,050
+بتساوي V not Y زائد AY T يعني بتعمل معادلة الحركة
+
+147
+00:13:42,050 --> 00:13:48,480
+مرة بال X و مرة بال Y معادلة الحركة ناخذ سؤال عن
+
+148
+00:13:48,480 --> 00:13:51,540
+هذا الموضوع بيحكي عن طائرة  A plane traveling Brazil
+
+149
+00:13:51,540 --> 00:13:57,140
+to Calais الطائرة اتحركت أو بتسافر بسرعة 1
+
+150
+00:13:57,140 --> 00:14:00,500
+في 10 أس 2 متر في الثانية drops a rocket
+
+151
+00:14:00,500 --> 00:14:06,540
+from considerable height هذه الطائرة قدفت صاروخ the
+
+152
+00:14:06,540 --> 00:14:09,440
+rocket immediately fired its engine accelerating
+
+153
+00:14:09,440 --> 00:14:13,160
+at عشرين متر في الثانية في ال X direction  الطائرة
+
+154
+00:14:13,160 --> 00:14:19,480
+رمت صاروخ الصاروخ لما وصل على الأرض طبعًا طلع اللي
+
+155
+00:14:19,480 --> 00:14:24,620
+هو نار أو ماشي بتسارع 20 متر في الثانية تربيع
+
+156
+00:14:24,620 --> 00:14:28,540
+باتجاه ال X while falling under the influence of
+
+157
+00:14:28,540 --> 00:14:31,360
+gravity in the Y direction when the rocket has
+
+158
+00:14:31,360 --> 00:14:34,520
+fallen واحد كيلو متر find its velocity in the Y
+
+159
+00:14:34,520 --> 00:14:38,920
+direction بدي سرعته في ال Y direction و بدي سرعته
+
+160
+00:14:38,920 --> 00:14:42,840
+في ال X direction و بدي magnitude and direction of
+
+161
+00:14:42,840 --> 00:14:46,870
+the blast طبعًا هي الطائرة الطائرة بتتحرك بسرعة V0
+
+162
+00:14:46,870 --> 00:14:49,990
+واحد في عشرة أس اثنين متر في الثانية هذه الطائرة على
+
+163
+00:14:49,990 --> 00:14:54,270
+ارتفاع واحد كيلومتر يعني واحد في عشرة أس ثلاثة
+
+164
+00:14:54,270 --> 00:14:59,350
+الطائرة رمت صاروخ اللي هو rocket رمت صاروخ على
+
+165
+00:14:59,350 --> 00:15:05,830
+الأرض الصاروخ انفجر على الأرض واتحرك بتسارع AX
+
+166
+00:15:05,830 --> 00:15:10,910
+في ال X Axis هنا اتحرك في ال Y Axis ب G هنا اللي
+
+167
+00:15:10,910 --> 00:15:19,200
+تسارع بالتسارع X Axis طبعًا مش هنهمل AX لأن بدي
+
+168
+00:15:19,200 --> 00:15:23,720
+أوجد في ال Y direction VY تربيع تساوي V not Y
+
+169
+00:15:23,720 --> 00:15:29,440
+تربيع ناقص اثنين GY V not Y زيرو لأنها اتحركت
+
+170
+00:15:29,440 --> 00:15:33,400
+horizontally G بتساوي ناقص تسعة و ثمانية من عشرة دلتا Y
+
+171
+00:15:33,400 --> 00:15:39,840
+ناقص واحد هذه المعطيات بنحل في ال Y لأن VY تربيع نهائية
+
+172
+00:15:39,840 --> 00:15:47,520
+V0 تربيع نهائية Zero ناقص اثنين GY ناقص واحد في
+
+173
+00:15:47,520 --> 00:15:53,200
+عشرة أس ثلاثة لأن الجسم نازل فبتطلع VY ناقص واحد
+
+174
+00:15:53,200 --> 00:15:56,210
+point أربعة في عشرة أس اثنين متر في الثانية Find
+
+175
+00:15:56,210 --> 00:16:00,190
+Velocity في الـ X direction بدنا نوجد السرعة في
+
+176
+00:16:00,190
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..861c1b352c20e9bb5b697ce82939ca39a0233c61
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs_postprocess.srt
@@ -0,0 +1,792 @@
+1
+00:00:00,000 --> 00:00:03,700
+بسم الله الرحمن الرحيم example تلاتة تلاتة مثال
+
+2
+00:00:03,700 --> 00:00:08,580
+تلاتة تلاتة a long jumper leaves the ground at an
+
+3
+00:00:08,580 --> 00:00:12,740
+angle of عشرين درجة to the horizontal and at a
+
+4
+00:00:12,740 --> 00:00:17,560
+speed of احداشر متر في الثانية الرجل بده يقفز قفزة
+
+5
+00:00:17,560 --> 00:00:24,320
+طويلة طبعا قفز بدرجات عشرين درجة مؤوية يعني سرعة
+
+6
+00:00:24,320 --> 00:00:31,260
+سرعة القذف عشرين درجة to the horizontal andبسرعة
+
+7
+00:00:31,260 --> 00:00:35,640
+مبتدأ ابتدائية 11 متر في الثانية how long does it
+
+8
+00:00:35,640 --> 00:00:39,500
+take for him to reach maximum height مطلب مني أوجد
+
+9
+00:00:39,500 --> 00:00:43,440
+أقصى ارتفاع ايضا what is the maximum height ايضا
+
+10
+00:00:43,440 --> 00:00:47,940
+أقصى ارتفاع و how far does he jump بده المسافة
+
+11
+00:00:47,940 --> 00:00:52,500
+اللي هو قدفها assume his motion is equivalent to
+
+12
+00:00:52,500 --> 00:00:56,260
+that of the particleبدي اعتبر ان حركته زى حركة اى
+
+13
+00:00:56,260 --> 00:01:03,920
+particle طبعا بدنا نحل و نستخدم معادلات الحركة هى
+
+14
+00:01:03,920 --> 00:01:11,840
+الشكل بدى يقفز قفز بزاوية 20 و قفز مسافة معينة
+
+15
+00:01:11,840 --> 00:01:20,300
+طبعا بسرعة 11 متر فى التانية هنحل الان السؤال اللى
+
+16
+00:01:20,300 --> 00:01:24,180
+هو المطلوب الاولFind the time T maximum taken to
+
+17
+00:01:24,180 --> 00:01:27,460
+reach maximum height مطلوب منها نوجد أقص الزمن
+
+18
+00:01:27,460 --> 00:01:32,580
+اللازم للوصول الى أقصى ارتفاع VY بنتبعها Zero لإن
+
+19
+00:01:32,580 --> 00:01:36,960
+عند أقصى ارتفاع V النهائية بتساوي Zero وبدأ أحل لأ
+
+20
+00:01:36,960 --> 00:01:43,100
+ت بأستخدم معادلة تلاتة تسعة VY بتساوي V not Y V
+
+21
+00:01:43,100 --> 00:01:52,640
+not sin θ ناقص GT V not sin θ على G بتساوي Tلأن V
+
+22
+00:01:52,640 --> 00:01:59,640
+النهائية بتساوي 0 بنعود V note 11 sin θ sin 20
+
+23
+00:01:59,640 --> 00:02:05,540
+والجي 9.8 من عشرة بتطلع 3.38 ثانية هذا الزمن
+
+24
+00:02:05,540 --> 00:02:10,520
+اللازم علشان يوصل أقصى ارتفاع find the maximum
+
+25
+00:02:10,520 --> 00:02:16,460
+height هي reach مطلوب أقصى ارتفاع بيوصله بدي أفرض
+
+26
+00:02:16,460 --> 00:02:21,970
+أن ال T maximumمعادلة الوقت تي ماكسمام into
+
+27
+00:02:21,970 --> 00:02:25,550
+equation y بيقوم بتعوض عن تي ماكسمام
+
+28
+00:02:35,850 --> 00:02:51,830
+V0Y V0SINθT-1.5GT2T-1.5GT2V0SINθT
+
+29
+00:02:51,830 --> 00:02:53,570
+-1.5GT2T-1.5Y
+
+30
+00:02:58,960 --> 00:03:03,800
+Find the horizontal distance هي jump بده المسافة
+
+31
+00:03:03,800 --> 00:03:08,160
+الأفقية اللى هو قفزها يعني بده ال range يعني بده
+
+32
+00:03:08,160 --> 00:03:14,840
+ال fixed اول حاجة بده اوجد الزمن for jump which is
+
+33
+00:03:14,840 --> 00:03:19,300
+yc maximum بده الزمن الكله احنا حسبنا بالأول الزمن
+
+34
+00:03:19,300 --> 00:03:25,380
+اللازم لكى يصلأقصى ارتفاع كانت point تلاتة تمانية
+
+35
+00:03:25,380 --> 00:03:29,320
+الزمن اللازم لكل حركة بتدرُه في اتنين او زمن
+
+36
+00:03:29,320 --> 00:03:33,000
+التحليق الكل بيسموه T بتساوي اتنين في T maximum
+
+37
+00:03:33,000 --> 00:03:38,140
+بتطلع point سبعة ستة تمانية Substitute this result
+
+38
+00:03:38,140 --> 00:03:42,040
+into the equation بالعودة هذه النتيجة في المعادلة
+
+39
+00:03:42,040 --> 00:03:55,550
+عشان معادلة ال X لإيجاد دلتا XV0 X T V0 X T V0 X T
+
+40
+00:03:55,550 --> 00:04:07,980
+V0 X T V0 X T V0 X Tلإيجاد ال maximum height ممكن
+
+41
+00:04:07,980 --> 00:04:12,000
+استخدم طريقة أخرى لإيجاد ال maximum height ممكن
+
+42
+00:04:12,000 --> 00:04:20,040
+استخدم ان دلتا Y بتساوي V not V not تربيع او V
+
+43
+00:04:20,040 --> 00:04:24,300
+تربيع نهائية بتساوي V not تربيع ناقص 2GY او VY
+
+44
+00:04:24,300 --> 00:04:28,560
+تربيع ناقص V not Y تساوي ناقص 2GY اذا دلتا Y
+
+45
+00:04:28,560 --> 00:04:34,150
+بتساوي VY تربيع ناقص V not Y تربيع على 2GVy أن
+
+46
+00:04:34,150 --> 00:04:42,750
+أقصى ارتفاع كانت 0 V0 كانت 11 sin θ والجي 9.8 عشرة
+
+47
+00:04:42,750 --> 00:04:44,850
+بنعود في القانون
+
+48
+00:04:53,790 --> 00:04:59,810
+V011SIN20 V011SIN20 V011SIN20
+
+49
+00:04:59,810 --> 00:05:10,650
+V011SIN20 V011SIN20
+
+50
+00:05:16,030 --> 00:05:22,010
+مثال تلاتة أربعة أن أتلت participate in a long
+
+51
+00:05:22,010 --> 00:05:25,330
+jump competition leaping into the air with
+
+52
+00:05:25,330 --> 00:05:28,570
+velocity v naught at an angle theta naught with
+
+53
+00:05:28,570 --> 00:05:30,950
+the horizontal obtain the expression of the length
+
+54
+00:05:30,950 --> 00:05:35,510
+of the jump in term of v naught and theta naught
+
+55
+00:05:35,510 --> 00:05:43,380
+and g طبعا لو كان عندى أحد بده يقفز مسافة معينةأو
+
+56
+00:05:43,380 --> 00:05:46,200
+مشاركين في مسابقة بدون يخفزوا مسافة معينة بدنا
+
+57
+00:05:46,200 --> 00:05:50,640
+نوجد اللي هي ال horizontal range او ال distance
+
+58
+00:05:50,640 --> 00:05:55,280
+horizontal displacement او كمان بدنا نوجد اللي هي
+
+59
+00:05:55,280 --> 00:05:58,860
+B note و G note بدنا نوجد برضه ال maximum height
+
+60
+00:05:58,860 --> 00:06:02,580
+ممكن نوجد الزمن اللي هو ال time magnitude V
+
+61
+00:06:02,580 --> 00:06:08,270
+maximumبدل الات V0 وθ0 وG اتفقنا ان T بتساوي 2T
+
+62
+00:06:08,270 --> 00:06:14,590
+maximum T maximum بتساوي V0 sin θ على G اذا ممكن
+
+63
+00:06:14,590 --> 00:06:18,250
+نعود بهذه القيمة اللي هي عن ال T في المعادلة
+
+64
+00:06:18,250 --> 00:06:22,710
+التانية اللي احنا استخدمناها يعني Delta X بتساوي
+
+65
+00:06:22,710 --> 00:06:28,930
+V0 Cos θ في Tت كانت بتساوي 2v0 sin θ0 على g ممكن
+
+66
+00:06:28,930 --> 00:06:34,190
+استخد المعادلات طبعا حفظ القانون ما بيظبط إلا إحنا
+
+67
+00:06:34,190 --> 00:06:38,010
+نحل من البداية بوصف القوانين الحركة هنا إحنا جيبنا
+
+68
+00:06:38,010 --> 00:06:44,050
+delta x بدلالة v0 و g جيبنا T بدلالة v0 و g ممكن
+
+69
+00:06:44,050 --> 00:06:50,160
+نجيب اللي هي delta x برضه بدلالة v0 و sin 2θالدلتا
+
+70
+00:06:50,160 --> 00:06:54,320
+اكس بتساوي اتنين V0 كتر بيه كوزاين تيتا ساين تيتا
+
+71
+00:06:54,320 --> 00:07:01,680
+على G طبعا كوزاين تيتا A0 ساين تيتا نوت في اتنين
+
+72
+00:07:01,680 --> 00:07:07,020
+بتساوي ساين اتنين تيتا نوت هذا قانون رياضي طبعا
+
+73
+00:07:07,020 --> 00:07:10,840
+هذه القوانين ممكن احنا نحصل عليها بدلالة تيتا نوت
+
+74
+00:07:10,840 --> 00:07:11,820
+و G A0
+
+75
+00:07:16,080 --> 00:07:21,920
+سؤال problem 35 بيقول بيقول بذكرها الأقوى قُرة
+
+76
+00:07:21,920 --> 00:07:27,260
+قرنها رأسيا دي الأعلى من أعلى المبنى بزاوية 30
+
+77
+00:07:27,260 --> 00:07:31,760
+درجة و بفضل روسيتر and with an initial speed of 20
+
+78
+00:07:31,760 --> 00:07:37,200
+متر في الثانية قدنا المبنى طول قصر المتر و رمينا
+
+79
+00:07:37,200 --> 00:07:44,350
+منه قرة بسرعة 20 متر في الثانية بزاوية 30 درجةThe
+
+80
+00:07:44,350 --> 00:07:47,430
+point of the release is صعب المدر نقطة طول
+
+81
+00:07:47,430 --> 00:07:50,710
+الارتفاع المبدأ من الground How long does it take
+
+82
+00:07:50,710 --> 00:07:54,130
+for the ball to hit the ground؟ بدو الزمن اللازم
+
+83
+00:07:54,130 --> 00:07:59,210
+علشان الكورة تصل أعلى إلى الأرض بدو الزمن اللازم
+
+84
+00:07:59,210 --> 00:08:03,970
+لكي تصل الكورة إلى الأرض كمان مطلوب the ball speed
+
+85
+00:08:03,970 --> 00:08:08,070
+at impact بدو السرعة النهائية للكورة you see find
+
+86
+00:08:08,070 --> 00:08:11,450
+the horizontal range of the ballمدوا المسافة
+
+87
+00:08:11,450 --> 00:08:16,030
+الأفقية اللى وقعت فيها الكورة أو ال range طبعا
+
+88
+00:08:16,030 --> 00:08:20,190
+بإهمال
+
+89
+00:08:20,190 --> 00:08:26,420
+مقاومة الهواءهي الشكل الموضح هي الشكل في عندي انا
+
+90
+00:08:26,420 --> 00:08:33,420
+ارتفاع مبنى 45 وفي عندي شخص وطف في هذه النقطة وقدف
+
+91
+00:08:33,420 --> 00:08:40,060
+كرة بزاوية 34 درجة و بسرعة 20 متر في الثانية الكرة
+
+92
+00:08:40,060 --> 00:08:44,200
+مشيت هذه المسار اللي هو المقتوفة لغاية ما وصلت
+
+93
+00:08:44,200 --> 00:08:48,060
+الأرض وطف من الزمن اللازم لكي تصل هذه الكرة إلى
+
+94
+00:08:48,060 --> 00:08:52,620
+هذه المنطقةأتخذ مني أين وقعت بدي أوجد المسافة هذه
+
+95
+00:08:52,620 --> 00:08:58,470
+كلها اللي هي ال X والتفاعل قبلها كان 45في البداية
+
+96
+00:08:58,470 --> 00:09:03,130
+بدي اوجد ال ball time of flight بدي اوجد زمان
+
+97
+00:09:03,130 --> 00:09:12,650
+التحريق زمان التحريق لكرة باوجد v0x هي v0 cos θ 20
+
+98
+00:09:12,650 --> 00:09:22,030
+متر في cos 30 تطلع 17.3 عشان v0y v0 sin θ تساوي 20
+
+99
+00:09:22,030 --> 00:09:27,740
+sin 30 يعني 10 متر في الثانيبدا أولا اختار الـ y
+
+100
+00:09:27,740 --> 00:09:32,240
+displacement يجب ان اعتبر الـ y0 يتساوي 0 و الـ y
+
+101
+00:09:32,240 --> 00:09:40,280
+ناقص 45 و v0 y يتساوي 10 فـ delta y يتساوي y ناقص
+
+102
+00:09:40,280 --> 00:09:40,960
+y0
+
+103
+00:09:46,600 --> 00:09:52,960
+Y كانت ماينس خمسة و أربعين لإن هو الجسم نازل V not
+
+104
+00:09:52,960 --> 00:09:59,380
+بتاع V not عشرة في D اللي هي مجغولة ناقص نص في
+
+105
+00:09:59,380 --> 00:10:02,580
+تسعة و تمانية و عشر تطلع أربعة و تسعة في T تربية
+
+106
+00:10:02,580 --> 00:10:07,460
+طبعا هي معادلة تربعية إلها طبعا حل يا إما بواسط
+
+107
+00:10:07,460 --> 00:10:12,900
+القانون يا إما بواسط تحليل المعادلة فتطلع Tفهاخد
+
+108
+00:10:12,900 --> 00:10:18,560
+تير هي قريبا مشابه تحت الجدر 4.32 هذا الزمن تحت
+
+109
+00:10:18,560 --> 00:10:24,020
+أقل الزمن اللازم تصل القرى إلى نهاية ما هي المسار
+
+110
+00:10:24,020 --> 00:10:29,460
+تبعها اللي براFind the ball speed at impact بيته
+
+111
+00:10:29,460 --> 00:10:34,240
+سرعة القرة عندما تصطدر في القارن Substitute the
+
+112
+00:10:34,240 --> 00:10:38,420
+value of D found in part A into the equation 3.9
+
+113
+00:10:38,420 --> 00:10:43,300
+to find the Y component اذا بيته اوجد ال VY
+
+114
+00:10:43,300 --> 00:10:51,720
+متساوينه Y ناقص GTv0y10-9.10 في الزمن 4.22 فبتطلع
+
+115
+00:10:51,720 --> 00:10:57,620
+عندى v y ناقص 31.3 فطبعا بالسالب لإنه نازل من ترفي
+
+116
+00:10:57,620 --> 00:11:04,180
+الثانية و عملتها طبعا v y جبتها v x موجودة عندى
+
+117
+00:11:04,180 --> 00:11:12,000
+فاستخدم اللى هى القانون اللى هوالثالث القائم في
+
+118
+00:11:12,000 --> 00:11:17,160
+فغورث فظلت في فغورث بقى وجد ال V بتساوي جزر VX
+
+119
+00:11:17,160 --> 00:11:22,900
+تربيع زائد VY تربيع VX تربيع هي نفسها V0 VX تربيع
+
+120
+00:11:22,900 --> 00:11:31,400
+هي 17.3 تربيع زائد هي نقص 31.4 تربيع فاندي 35.9
+
+121
+00:11:31,400 --> 00:11:35,040
+متر في الثانية هذه هي السرعة النهائية اللي ال كرة
+
+122
+00:11:35,040 --> 00:11:41,720
+وصلت فيها الورد في C طالب مني findHorizontal Range
+
+123
+00:11:41,720 --> 00:12:04,040
+of the ball هو أي نسخة تتركها يعني Delta X
+
+124
+00:12:04,930 --> 00:12:08,470
+سيكشن جديد وهو two-dimensional constant
+
+125
+00:12:08,470 --> 00:12:12,840
+accelerationWe have study only problem in which an
+
+126
+00:12:12,840 --> 00:12:15,980
+object with an initial velocity follow a
+
+127
+00:12:15,980 --> 00:12:18,500
+trajectory determined by the acceleration of the
+
+128
+00:12:18,500 --> 00:12:24,760
+gravity alone لو أنا احنا اللي درسناها سابقة كانت
+
+129
+00:12:24,760 --> 00:12:30,220
+بتحرك ب constant speed و الحركة Ax تساوي zero و ان
+
+130
+00:12:30,220 --> 00:12:32,500
+انا بتحرك بالتسارع اللي هي acceleration of the
+
+131
+00:12:32,500 --> 00:12:36,200
+gravity in the more general case other agents such
+
+132
+00:12:36,200 --> 00:12:40,690
+as air trapped surface frictionor engines can
+
+133
+00:12:40,690 --> 00:12:45,010
+cause acceleration ممكن يكون عندي انا اعتقاد ممكن
+
+134
+00:12:45,010 --> 00:12:50,650
+يكون عندي يعني عاجات خاصة في ال .. في الظروف
+
+135
+00:12:50,650 --> 00:12:55,480
+المحيطةبال .. بال object أو في الجسم بيصير عندي
+
+136
+00:12:55,480 --> 00:12:58,740
+acceleration تجاه نفسي أساسي and this acceleration
+
+137
+00:12:58,740 --> 00:13:01,040
+taken together from the vector of amplitude
+
+138
+00:13:01,040 --> 00:13:06,560
+component dx ممكن أستخدم dx في هذه الحالة إذا كان
+
+139
+00:13:06,560 --> 00:13:10,040
+أنا الجسم بعد ما وصل للأرض ممكن يمشي أو يتحرك
+
+140
+00:13:10,040 --> 00:13:13,440
+بسرعة معينة when both components are constant
+
+141
+00:13:13,440 --> 00:13:19,220
+ويكون يواصل هوشين ثلاثة او ستة فهذه هي المعادلات
+
+142
+00:13:19,220 --> 00:13:24,530
+اللي انا ممكن أحلهالو الجسم اتحرك بتسارع Ax موجود
+
+143
+00:13:24,530 --> 00:13:29,110
+يعني Vx بتساوي P non X زائد Ax في D نقطة X بتساوي
+
+144
+00:13:29,110 --> 00:13:34,090
+P non X في D زائد نصف Ax التربية Vx تربية بتساوي P
+
+145
+00:13:34,090 --> 00:13:38,790
+non X تربية زائد اتنين من X تربية في نقطة X وVy
+
+146
+00:13:38,790 --> 00:13:42,050
+بتساوي P non Y زائد EY يعني بتعمل معادلة الحركة
+
+147
+00:13:42,050 --> 00:13:48,480
+مرة بال X و مرة بال Y معادلة الحركةناخد سؤال عن
+
+148
+00:13:48,480 --> 00:13:51,540
+هذا الموضوع بيحكي لجد بلايان traveling Brazil
+
+149
+00:13:51,540 --> 00:13:57,140
+Calais الطائرة الطائرة اتحركت او بتسافر بسرعة واحد
+
+150
+00:13:57,140 --> 00:14:00,500
+في عشر أقصى اتنين متر في الثانية drops a rocket
+
+151
+00:14:00,500 --> 00:14:06,540
+from considerable height هي الطائرة قدفت صاروخ the
+
+152
+00:14:06,540 --> 00:14:09,440
+rocket immediately fired its engine accelerating
+
+153
+00:14:09,440 --> 00:14:13,160
+at عشرين متر في الثانية in the X direction الطائرة
+
+154
+00:14:13,160 --> 00:14:19,480
+رمت صاروخالصاروخ لما وصل على الأرض طبعا طلع اللي
+
+155
+00:14:19,480 --> 00:14:24,620
+هو نار أو ماشي بتسارع 20 متر في التاني تربيع
+
+156
+00:14:24,620 --> 00:14:28,540
+باتجاه ال X while falling under the influence of
+
+157
+00:14:28,540 --> 00:14:31,360
+gravity in the Y direction when the rocket has
+
+158
+00:14:31,360 --> 00:14:34,520
+fallen واحد كيلومتر find its velocity in the Y
+
+159
+00:14:34,520 --> 00:14:38,920
+direction بدي سرعته بال Y direction و بدي سرعته
+
+160
+00:14:38,920 --> 00:14:42,840
+بال X direction و بدي magnitude and direction of
+
+161
+00:14:42,840 --> 00:14:46,870
+the blast طبعا هي الطيارةالطيارة بتتحرك بسرعة V0
+
+162
+00:14:46,870 --> 00:14:49,990
+واحد فى عشر أقصى اتنين موريزين تالي الطيارة على
+
+163
+00:14:49,990 --> 00:14:54,270
+ارتفاع واحد كيلو متر يعني واحد فى عشر أقصى تلاتة
+
+164
+00:14:54,270 --> 00:14:59,350
+الطيارة رمت صاروخ اللى هو rocket رمت صاروخ على
+
+165
+00:14:59,350 --> 00:15:05,830
+الأرض الصاروخ انفجر على الأرض واتحرك بتسارع بال AX
+
+166
+00:15:05,830 --> 00:15:10,910
+بال X Axis هنا اتحرك بال Y Axis بال G هنا اللى
+
+167
+00:15:10,910 --> 00:15:19,200
+تسارع بالتزارع X Axisطبعا مش هنهم ال ax لان بدي
+
+168
+00:15:19,200 --> 00:15:23,720
+اوجد في ال y direction vy تربيع تساوي v not y
+
+169
+00:15:23,720 --> 00:15:29,440
+تربيع نقص اتنين gy v not y زيرو لإنها اتحركت
+
+170
+00:15:29,440 --> 00:15:33,400
+horizontally جي بتساوي نقص ساعة تمانية عشرة دلتا y
+
+171
+00:15:33,400 --> 00:15:39,840
+نقص واحد هذا المعطياتبتحل ال Y لان VY تربيع نهائية
+
+172
+00:15:39,840 --> 00:15:47,520
+V0 تربيع نهائية Zero ناقص اتنين GY ناقص واحد في
+
+173
+00:15:47,520 --> 00:15:53,200
+عشر أقص تلاتة لان الجسم نازل فبتطلع VY ناقص واحد
+
+174
+00:15:53,200 --> 00:15:56,210
+point أربع في عشر أقص اتنين متر في الثانيFind
+
+175
+00:15:56,210 --> 00:16:00,190
+Velocity في الـ X-direction بدنا نوجد السرعة في
+
+176
+00:16:00,190 --> 00:16:05,210
+الـ X-direction لإيجاد السرعة محتاجين الزمن ف VY
+
+177
+00:16:05,210 --> 00:16:11,150
+بتساوي V0Y زائد AT VY minus 1.4 في 10 عقل 2 متر في
+
+178
+00:16:11,150 --> 00:16:16,150
+الثانية بساوي 0 V0Y 0 لإنها اتحركت .. كانت بتتحرك
+
+179
+00:16:16,150 --> 00:16:20,130
+مبدئيا horizontally AY تسعة و تمانية من عشرة و T
+
+180
+00:16:20,130 --> 00:16:25,830
+إذا T بتساوي 14.3 ثانية أو سكانبتعود عن T في
+
+181
+00:16:25,830 --> 00:16:31,230
+معادلة X لإن T المشتركة بين حركة Y وحركة X VX
+
+182
+00:16:31,230 --> 00:16:35,370
+بتسوى V NOT X زائد AX في T V NOT X كانت واحد في
+
+183
+00:16:35,370 --> 00:16:40,810
+عشرة أقصى اتنين AX عشرين معقاة وT كانت أربعة عشر
+
+184
+00:16:40,810 --> 00:16:45,250
+بين تلاتة منها دي العلاقة بقوجة VX تلاتمية أو ستة
+
+185
+00:16:45,250 --> 00:16:48,980
+أو تمانين متر في التانيةبعد هيك بدأ اوجد ال
+
+186
+00:16:48,980 --> 00:16:53,500
+magnitude and direction of the velocity ال
+
+187
+00:16:53,500 --> 00:16:57,760
+magnitude هي عبارة عن جزر Vx تربيع زائد Vy تربيع
+
+188
+00:16:57,760 --> 00:17:04,520
+Vx تربيع اللي هي Vx تربيع زائد V0 تربيع زي ما احنا
+
+189
+00:17:04,520 --> 00:17:09,600
+أخدناها سابقا هذه تمثل Vx تلتمية وستة و تمانية متر
+
+190
+00:17:09,600 --> 00:17:13,100
+في التان وهذه Vy نخس واحد point أربعة فعشرة أقصى
+
+191
+00:17:13,100 --> 00:17:16,280
+اتنين متر في التانى تربيع الجواب بتطلع أربعمية و
+
+192
+00:17:16,280 --> 00:17:20,520
+أحد عاشرعند إيجاد V التي هي الـ direction مع أن
+
+193
+00:17:20,520 --> 00:17:27,700
+الكلام هي tan inverse ل VY على VX VY كانت بالسالب
+
+194
+00:17:27,700 --> 00:17:34,280
+و VX كانت بالموجة فبطلع معانا نقص 19 ما بضف لها
+
+195
+00:17:34,280 --> 00:17:38,460
+اللي هي 180 لأنها موجودة في الربع الرابع وهذا
+
+196
+00:17:38,460 --> 00:17:43,880
+يتمثل اتجاهالاتجاه اللى هى ال result أو المحصلة
+
+197
+00:17:43,880 --> 00:17:48,280
+بالنسبة لغيرها في طريقة ال motion طبعا احنا طلنا
+
+198
+00:17:48,280 --> 00:17:48,820
+ألغاها
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..88e590ef4db02e002a74422da6a4f89a9778ca8b
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/FItlJ_s9zSs_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 2898, "start": 0.0, "end": 28.98, "text": "بسم الله الرحمن الرحيم example تلاتة تلاتة مثال تلاتة تلاتة a long jumper leaves the ground at an angle of عشرين درجة to the horizontal and at a speed of احداشر متر في الثانية الرجل بده يقفز قفزة طويلة طبعا قفز بدرجات عشرين درجة مؤوية يعني سرعة سرعة القذف عشرين درجة to the horizontal and", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 1365, 6055, 1211, 9307, 3660, 6055, 1211, 9307, 3660, 50113, 6027, 6055, 1211, 9307, 3660, 6055, 1211, 9307, 3660, 257, 938, 44061, 5510, 264, 2727, 412, 364, 5802, 295, 6225, 46309, 9957, 11778, 47341, 3660, 281, 264, 12750, 293, 412, 257, 3073, 295, 1975, 24401, 33599, 2288, 44650, 2288, 8978, 6024, 104, 7649, 10632, 34892, 7435, 1211, 47525, 3224, 7251, 4587, 5172, 11622, 12174, 5172, 11622, 3660, 23032, 2407, 26895, 3660, 23032, 3555, 3615, 995, 12174, 5172, 11622, 4724, 3215, 47341, 9307, 6225, 46309, 9957, 11778, 47341, 3660, 3714, 33604, 2407, 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معادلات الحركة هى الشكل بدى يقفز قفز بزاوية 20 و قفز مسافة معينة طبعا بسرعة 11 متر فى التانية هنحل الان السؤال اللى هو المطلوب الاول", "tokens": [3555, 16254, 1975, 34268, 26890, 16472, 11331, 31747, 47395, 30767, 7578, 11331, 31747, 3660, 1975, 7578, 12359, 23032, 3555, 3615, 995, 47525, 8315, 8717, 5016, 1211, 4032, 8717, 14851, 9778, 40448, 20449, 18513, 1211, 9307, 21542, 31747, 3660, 8032, 7578, 25124, 28820, 47525, 7578, 7251, 4587, 5172, 11622, 12174, 5172, 11622, 4724, 11622, 995, 2407, 10632, 945, 4032, 12174, 5172, 11622, 47524, 31845, 3660, 20449, 9957, 3660, 23032, 3555, 3615, 995, 4724, 3794, 2288, 27884, 2975, 44650, 2288, 6156, 7578, 16712, 7649, 10632, 8032, 1863, 5016, 1211, 2423, 7649, 21136, 33604, 6027, 13672, 7578, 31439, 9673, 9566, 1211, 37746, 42963, 12610], "avg_logprob": -0.15640318116136626, "compression_ratio": 1.6984924623115578, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 54.0, "end": 54.26, "word": "بدي", "probability": 0.5517578125}, 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71.84, "end": 73.02, "word": " طبعا", "probability": 0.9383544921875}, {"start": 73.02, "end": 74.4, "word": " بسرعة", "probability": 0.98388671875}, {"start": 74.4, "end": 75.2, "word": " 11", "probability": 0.892578125}, {"start": 75.2, "end": 76.18, "word": " متر", "probability": 0.63818359375}, {"start": 76.18, "end": 76.4, "word": " فى", "probability": 0.5526123046875}, {"start": 76.4, "end": 77.16, "word": " التانية", "probability": 0.8746744791666666}, {"start": 77.16, "end": 78.6, "word": " هنحل", "probability": 0.9395751953125}, {"start": 78.6, "end": 79.1, "word": " الان", "probability": 0.6614990234375}, {"start": 79.1, "end": 79.82, "word": " السؤال", "probability": 0.8308919270833334}, {"start": 79.82, "end": 80.3, "word": " اللى", "probability": 0.986083984375}, {"start": 80.3, "end": 80.48, "word": " هو", "probability": 0.94775390625}, {"start": 80.48, "end": 80.88, "word": " المطلوب", "probability": 0.9647216796875}, {"start": 80.88, "end": 81.3, "word": " الاول", "probability": 0.809326171875}], "temperature": 1.0}, {"id": 4, "seek": 11166, "start": 81.96, "end": 111.66, "text": "Find the time T maximum taken to reach maximum height مطلوب منها نوجد أقص الزمن اللازم للوصول الى أقصى ارتفاع VY بنتبعها Zero لإن عند أقصى ارتفاع V النهائية بتساوي Zero وبدأ أحل لأ ت بأستخدم معادلة تلاتة تسعة VY بتساوي V not Y V not sin θ ناقص GT V not sin θ على G بتساوي T", "tokens": [37, 471, 264, 565, 314, 6674, 2726, 281, 2524, 6674, 6681, 3714, 9566, 1211, 37746, 9154, 11296, 8717, 29245, 3215, 5551, 4587, 9381, 2423, 11622, 27842, 13672, 31377, 2304, 24976, 2407, 9381, 12610, 2423, 7578, 5551, 4587, 9381, 7578, 1975, 43500, 5172, 45761, 691, 56, 4724, 29399, 3555, 3615, 11296, 17182, 5296, 28814, 1863, 43242, 5551, 4587, 9381, 7578, 1975, 43500, 5172, 45761, 691, 28239, 3224, 16373, 10632, 39894, 3794, 995, 45865, 17182, 4032, 44510, 10721, 5551, 5016, 1211, 5296, 10721, 6055, 4724, 10721, 14851, 9778, 3215, 2304, 20449, 18513, 37977, 6055, 1211, 9307, 3660, 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"word": " بالموجة", "probability": 0.769287109375}, {"start": 1050.2, "end": 1050.96, "word": " فبطلع", "probability": 0.787841796875}, {"start": 1050.96, "end": 1051.64, "word": " معانا", "probability": 0.8502604166666666}, {"start": 1051.64, "end": 1052.9, "word": " نقص", "probability": 0.5057373046875}, {"start": 1052.9, "end": 1053.38, "word": " 19", "probability": 0.5205078125}, {"start": 1053.38, "end": 1053.58, "word": " ما", "probability": 0.47607421875}, {"start": 1053.58, "end": 1053.9, "word": " بضف", "probability": 0.5386555989583334}, {"start": 1053.9, "end": 1054.28, "word": " لها", "probability": 0.79736328125}, {"start": 1054.28, "end": 1054.78, "word": " اللي", "probability": 0.5655517578125}, {"start": 1054.78, "end": 1054.9, "word": " هي", "probability": 0.92236328125}, {"start": 1054.9, "end": 1055.32, "word": " 180", "probability": 0.382080078125}, {"start": 1055.32, "end": 1056.36, "word": " لأنها", "probability": 0.8214518229166666}, {"start": 1056.36, "end": 1056.8, "word": " موجودة", "probability": 0.9832763671875}, {"start": 1056.8, "end": 1056.92, "word": " في", "probability": 0.951171875}, {"start": 1056.92, "end": 1057.28, "word": " الربع", "probability": 0.753173828125}, {"start": 1057.28, "end": 1057.88, "word": " الرابع", "probability": 0.9910481770833334}, {"start": 1057.88, "end": 1058.46, "word": " وهذا", "probability": 0.625}, {"start": 1058.46, "end": 1058.98, "word": " يتمثل", "probability": 0.87158203125}, {"start": 1058.98, "end": 1059.66, "word": " اتجاه", "probability": 0.88330078125}], "temperature": 1.0}, {"id": 46, "seek": 106882, "start": 1060.94, "end": 1068.82, "text": "الاتجاه اللى هى ال result أو المحصلة بالنسبة لغيرها في طريقة ال motion طبعا احنا طلنا ألغاها", "tokens": [6027, 9307, 7435, 40294, 13672, 7578, 8032, 7578, 2423, 1874, 34051, 9673, 5016, 36520, 3660, 20666, 1863, 35457, 3660, 5296, 17082, 13546, 11296, 8978, 23032, 16572, 28671, 2423, 5394, 23032, 3555, 3615, 995, 1975, 5016, 8315, 23032, 1211, 8315, 5551, 1211, 17082, 995, 11296], "avg_logprob": -0.28038193384806315, "compression_ratio": 1.2682926829268293, "no_speech_prob": 9.5367431640625e-07, "words": [{"start": 1060.94, "end": 1061.74, "word": "الاتجاه", "probability": 0.88330078125}, {"start": 1061.74, "end": 1061.98, "word": " اللى", "probability": 0.775146484375}, {"start": 1061.98, "end": 1062.2, "word": " هى", "probability": 0.78369140625}, {"start": 1062.2, "end": 1062.36, "word": " ال", "probability": 0.85888671875}, {"start": 1062.36, "end": 1062.78, "word": " result", "probability": 0.984375}, {"start": 1062.78, "end": 1063.06, "word": " أو", "probability": 0.6552734375}, {"start": 1063.06, "end": 1063.88, "word": " المحصلة", "probability": 0.869384765625}, {"start": 1063.88, "end": 1065.06, "word": " بالنسبة", "probability": 0.8648681640625}, {"start": 1065.06, "end": 1065.46, "word": " لغيرها", "probability": 0.67950439453125}, {"start": 1065.46, "end": 1065.48, "word": " في", "probability": 0.41455078125}, {"start": 1065.48, "end": 1065.82, "word": " طريقة", "probability": 0.597412109375}, {"start": 1065.82, "end": 1065.96, "word": " ال", "probability": 0.60986328125}, {"start": 1065.96, "end": 1066.46, "word": " motion", "probability": 0.96533203125}, {"start": 1066.46, "end": 1066.84, "word": " طبعا", "probability": 0.99365234375}, {"start": 1066.84, "end": 1067.58, "word": " احنا", "probability": 0.83349609375}, {"start": 1067.58, "end": 1068.28, "word": " طلنا", "probability": 0.6003011067708334}, {"start": 1068.28, "end": 1068.82, "word": " ألغاها", "probability": 0.825244140625}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1069.882625, "duration_after_vad": 1055.2984687500007}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8.srt
new file mode 100644
index 0000000000000000000000000000000000000000..8e640bb7abc6f0b3d6c8c8beccbe1cb3915c3b58
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8.srt
@@ -0,0 +1,883 @@
+1
+00:00:00,000 --> 00:00:04,700
+بسم الله الرحمن الرحيم. بنستكمل مساق فيزياء عامة
+
+2
+00:00:04,700 --> 00:00:08,420
+لطلبة العلم الصحية. بنبدأ بـ chapter 4 بعنوان
+
+3
+00:00:08,420 --> 00:00:14,600
+Newton's laws of motion. قوانين نيوتن للحركة. هنعرف
+
+4
+00:00:14,600 --> 00:00:18,860
+section 4-1 اللي هي الـ forces. القوة. هنعرف القوة
+
+5
+00:00:18,860 --> 00:00:23,700
+بداية، القوة is commonly imagined as a push or a pull.
+
+6
+00:00:23,700 --> 00:00:29,560
+أي جسم ممكن أنا أدفعه أو أسحبه، ممكن أنا بأثر عليه
+
+7
+00:00:29,560 --> 00:00:33,060
+بقوة. it is a vector quantity. الـ force عبارة عن
+
+8
+00:00:33,060 --> 00:00:36,420
+كمية متجهة. just like velocity and acceleration.
+
+9
+00:00:36,420 --> 00:00:43,090
+تشبه السرعة الاتجاهية والتسارع. الـ type of force الـ
+
+10
+00:00:43,090 --> 00:00:46,910
+type of forces. في عندي أنا نوعين من القوة، الأولى
+
+11
+00:00:46,910 --> 00:00:51,550
+اسمها contact force. contact force. دا قوة التلامس.
+
+12
+00:00:51,550 --> 00:00:54,910
+they result from physical contact between two
+
+13
+00:00:54,910 --> 00:00:58,890
+objects, as in figures. الـ figure طبعا أربعة، اتنين
+
+14
+00:00:58,890 --> 00:01:02,190
+اللي هي الـ contact force هي عبارة عن قوة التلامس
+
+15
+00:01:02,190 --> 00:01:09,150
+بين جسمين of two objects. بين جسمين. frictional force.
+
+16
+00:01:09,150 --> 00:01:11,990
+الـ contact force ممكن تكون زي الـ frictional force.
+
+17
+00:01:11,990 --> 00:01:15,970
+كمثال. قوة الاحتكاك. الـ tension force. قوة الشد. الـ
+
+18
+00:01:15,970 --> 00:01:19,290
+normal force. قوة اللي هي رد الفعل العمودية. والـ air
+
+19
+00:01:19,290 --> 00:01:23,010
+resistance force, and spring force are examples
+
+20
+00:01:23,010 --> 00:01:27,460
+of contact force. يعنيكأمثلة على قوة التلامس. قوة
+
+21
+00:01:27,460 --> 00:01:31,400
+الاحتكاك، الـ tension اللي هو الشد، الـ normal force.
+
+22
+00:01:31,400 --> 00:01:35,640
+قوة رد الفعل العمودية، والـ air resistance force. قوة
+
+23
+00:01:35,640 --> 00:01:39,760
+مقاومة الهواء، وقوة اللي هو النابض أو الـ spring
+
+24
+00:01:39,760 --> 00:01:43,400
+كهيولة. كلها أمثلة على الـ contact force. النوع
+
+25
+00:01:43,400 --> 00:01:46,340
+التاني من الـ contact من القوة هي اسمها field
+
+26
+00:01:46,340 --> 00:01:51,030
+forces. الـ field force دي doesn't involve any direct
+
+27
+00:01:51,030 --> 00:01:54,890
+physical contact between objects. طبعا مافيش تلامس
+
+28
+00:01:54,890 --> 00:01:59,550
+بينها وبين الأجسام. زي الـ gravitational force. قوة
+
+29
+00:01:59,550 --> 00:02:02,490
+الجاذبية. أو بعدين electrical force. قوة الكهربية.
+
+30
+00:02:02,490 --> 00:02:06,250
+and magnetic force. قوة المغناطيسية. هدولة برضه أمثلة
+
+31
+00:02:06,250 --> 00:02:10,940
+على الـ field force. يعني مافي contact. مافيش تلامس. هي
+
+32
+00:02:10,940 --> 00:02:15,940
+هذا الشكل بـ.. بـ.. الأشكال هذه طبعا شكل A وB وC
+
+33
+00:02:15,940 --> 00:02:20,540
+بـ.. بيمثل ليه؟ اللي هي بالنسبة لـ الـ contact force.
+
+34
+00:02:20,540 --> 00:02:24,140
+اللي هي قوة الزنبرك. contact force. لما أشد أنا
+
+35
+00:02:24,140 --> 00:02:28,060
+عربة. برضه contact force. لما أضرب كرة، لمستها.
+
+36
+00:02:28,060 --> 00:02:33,060
+contact force. لكن الـ field force. قوة بين جسمين أو
+
+37
+00:02:33,060 --> 00:02:39,940
+particle. قوة بين مثلاً جسم صغير مع جسم صغير. في عندي
+
+38
+00:02:39,940 --> 00:02:44,600
+قوة. أو قوة بين شحنتين. طبعا في قوة مجال كهربي هنا.
+
+39
+00:02:44,600 --> 00:02:48,040
+ممكن مجال مغناطيسي. اللي هي اللي هي الـ iron. قطعة من
+
+40
+00:02:48,040 --> 00:02:52,400
+الحديد وقربت لها مغناطيس، بيكون عندنا قوة تجاذب.
+
+41
+00:02:52,400 --> 00:02:57,000
+فهذه بيسموها الـ field force. لا يشترط التلامس فيها.
+
+42
+00:02:57,000 --> 00:03:02,560
+لا يشترط التلامس فيها. إذا اللي هي في عندنا قوتين.
+
+43
+00:03:02,560 --> 00:03:08,540
+الـ contact force و الـ field force. section 4-2. The
+
+44
+00:03:08,540 --> 00:03:14,880
+laws of motion. قوانين اللي هي الحركة. إسحاق نيوتن
+
+45
+00:03:14,880 --> 00:03:18,580
+proposed three laws of motion. طبعا قوانين الحركة
+
+46
+00:03:18,580 --> 00:03:25,200
+اللي هي اللي طبعا اكتشفها هو إسحاق نيوتن. to offer a
+
+47
+00:03:25,200 --> 00:03:29,320
+systematic method of calculating an object's motion
+
+48
+00:03:29,320 --> 00:03:31,300
+due to the forces exerted on it.
+
+49
+00:03:53,970 --> 00:03:59,390
+ويظل أيضاً الجسم متحرك ما لم تؤثر عليه قوة تغير من
+
+50
+00:03:59,390 --> 00:04:02,970
+حالته. تغير من حالته. طبعاً بالنسبة لقانونه الأول.
+
+51
+00:04:02,970 --> 00:04:06,710
+Consider... consider a book lying on a table. لو
+
+52
+00:04:06,710 --> 00:04:10,790
+عندي أنا كتاب، الكتاب موجود على الطاولة. Obviously,
+
+53
+00:04:10,790 --> 00:04:15,880
+the book remains at rest if it... if left alone. طبعاً
+
+54
+00:04:15,880 --> 00:04:19,500
+الكتاب كمثال موجود على طاولة، الكتاب هيظل موجود ما
+
+55
+00:04:19,500 --> 00:04:23,320
+لم تؤثر عليه أي قوة. Now imagine pushing the book.
+
+56
+00:04:23,320 --> 00:04:27,580
+بدأ أتصور أنه أنا شديت الكتاب بقوة أفقية. With
+
+57
+00:04:27,580 --> 00:04:32,280
+horizontal force great enough to overcome the
+
+58
+00:04:32,280 --> 00:04:35,460
+force of friction between the book and the table.
+
+59
+00:04:35,460 --> 00:04:40,320
+نفترض أنه أنا شديت هذا الكتاب بقوة أكبر من قوة
+
+60
+00:04:40,320 --> 00:04:44,730
+اللي هي التلامس أو الاحتكاك بين الكتاب وبين الجسم
+
+61
+00:04:44,730 --> 00:04:48,850
+أو الأرض. وبالتالي فالكتاب سوف يتحرك. Setting the
+
+62
+00:04:48,850 --> 00:04:53,490
+book in motion. هيظل موجود الكتاب في الحركة. Because
+
+63
+00:04:53,490 --> 00:04:56,770
+the magnitude of the applied force exceeds exceeds
+
+64
+00:04:56,770 --> 00:04:59,630
+the magnitude of the friction force, the book
+
+65
+00:04:59,630 --> 00:05:02,870
+accelerates. طبعاً إذا كانت القوة اللي أنا شدت فيها
+
+66
+00:05:02,870 --> 00:05:07,050
+الكتاب أكبر من قوة الاحتكاك، فالكتاب طبعاً هيمشي
+
+67
+00:05:07,050 --> 00:05:11,530
+يتسارع. When the applied force is withdrawn, إذا
+
+68
+00:05:11,530 --> 00:05:15,290
+أنا رفعت القوة اللي أعطيته إياها، الـ friction slows
+
+69
+00:05:15,290 --> 00:05:21,070
+the book to a stop. قوة الاحتكاك طبعاً بتخلي الكتاب
+
+70
+00:05:21,070 --> 00:05:26,550
+طبعاً حركته تقل شوية لإنه هي عبارة عن يعني قوته
+
+71
+00:05:26,550 --> 00:05:30,450
+يعني عكس اتجاه الحركة. Now imagine the book is
+
+72
+00:05:30,450 --> 00:05:33,410
+moving on a horizontal frictionless surface. الآن
+
+73
+00:05:33,410 --> 00:05:37,750
+بدي أفرض في عندي أنا كتاب محطوط على سطح أملس.
+
+74
+00:05:37,750 --> 00:05:41,530
+frictionless surface. It continues to move in a
+
+75
+00:05:41,530 --> 00:05:44,250
+straight line with constant velocity until it hits
+
+76
+00:05:44,250 --> 00:05:48,430
+a wall or some other obstruction. طبعاً لو كان
+
+77
+00:05:48,430 --> 00:05:52,760
+الكتاب هو أساساً بيمشي على سطح أملس، هيضل يمشي بـ
+
+78
+00:05:52,760 --> 00:05:57,280
+constant velocity ما لم تؤثر عليه، يؤثر عليه أي شيء.
+
+79
+00:05:57,280 --> 00:06:02,040
+كما أنه ممكن يصطدم بحائط أو ممكن يصطدم بأي حاجة.
+
+80
+00:06:02,040 --> 00:06:07,180
+الآن لو كان عندي أنا هذا الكتاب، الكتاب بيتحرك
+
+81
+00:06:07,180 --> 00:06:12,720
+بسرعة معينة. أنا شديته طبعاً عكس، عكس الحركة. هذه قوة
+
+82
+00:06:12,720 --> 00:06:16,300
+احتكاك عكس الحركة. لو كانت أنا شديته بقوة عكس الحركة
+
+83
+00:06:16,300 --> 00:06:19,460
+أكبر من قوة الاحتكاك، هيمشي، هيبقى اللي يمشي للكتاب.
+
+84
+00:06:20,900 --> 00:06:24,540
+ما لم تأثر عليه قوة تغير من حالته. وكذلك لو كان
+
+85
+00:06:24,540 --> 00:06:28,460
+الكتاب أساساً هو ماشي ومافي أي قوة وقفته، هيظل ماشي.
+
+86
+00:06:28,460 --> 00:06:32,080
+إذا هذا قانون نيوتن الأول. الـ net force. No change
+
+87
+00:06:32,080 --> 00:06:34,820
+in the velocity. القوة. قانون نيوتن الأول بيحكي أنه
+
+88
+00:06:34,820 --> 00:06:38,240
+يظل الجسم ساكن ما لم تؤثر عليه قوة تغير من حالته.
+
+89
+00:06:38,240 --> 00:06:42,980
+ويظل الجسم متحرك ما لم تؤثر عليه قوة تغير من حالته.
+
+90
+00:06:44,370 --> 00:06:47,730
+قانون نيوتن الأول للحركة. An object moves with
+
+91
+00:06:47,730 --> 00:06:50,370
+a velocity that is constant in magnitude and
+
+92
+00:06:50,370 --> 00:06:53,730
+direction unless a non-zero net force acts on it.
+
+93
+00:06:53,730 --> 00:06:57,790
+هذا بالإنقليزي. تعريف قانون نيوتن الأول بيحكي لنا
+
+94
+00:06:57,790 --> 00:07:03,030
+the net force on an object is defined as the
+
+95
+00:07:03,030 --> 00:07:06,750
+vector sum of all external forces exerted on the
+
+96
+00:07:06,750 --> 00:07:11,710
+object. طبعاً net force هي عبارة عن مجموعة للقوة
+
+97
+00:07:11,710 --> 00:07:16,550
+المؤثرة على الجسم، هي عبارة عن مجموع القوى  متجهة
+
+98
+00:07:16,550 --> 00:07:23,230
+متجه لكل القوى الخارجية التي تؤثر على الجسم. هنا
+
+99
+00:07:23,230 --> 00:07:26,930
+القانون نيوتن الأول، أنه on object moves. أي جسم
+
+100
+00:07:26,930 --> 00:07:32,090
+هيتحرك بسرعة معينة، بسرعة constant magnitude and
+
+101
+00:07:32,090 --> 00:07:37,790
+direction. بيضل الجسم يتحرك ما لم تؤثر عليه قوة تغير من
+
+102
+00:07:37,790 --> 00:07:42,150
+حالته. معنى الكلام أنه بنجيب احنا الـ net force
+
+103
+00:07:42,150 --> 00:07:46,450
+المؤثرة على هذا الجسم. The external forces come
+
+104
+00:07:46,450 --> 00:07:50,010
+from an object's environment. القوة الخارجية بتيجي من
+
+105
+00:07:50,010 --> 00:07:54,830
+من اللي هي اللي يعني الجو المحيط أو الظروف المحيطة
+
+106
+00:07:54,830 --> 00:07:58,730
+وليس من داخل الجسم. بيسموها external force. القوة
+
+107
+00:07:58,730 --> 00:08:03,750
+الخارجية. التعريف الـ mass and inertia. الـ inertia هي
+
+108
+00:08:03,750 --> 00:08:07,230
+القصورة الذاتي. is the tendency of an object to
+
+109
+00:08:07,230 --> 00:08:11,310
+continue its motion in the absence of force. هي
+
+110
+00:08:11,310 --> 00:08:17,690
+يعني قدرة اللي هي الـ أي جسم أنه يستمر في حركته في
+
+111
+00:08:17,690 --> 00:08:21,890
+عدم وجود القوة المؤثرة. And mass is the measure of
+
+112
+00:08:21,890 --> 00:08:25,090
+the object's resistance to the change in its motion
+
+113
+00:08:25,090 --> 00:08:29,790
+due to the force. اللي الـ mass اللي هي الكتلة هي
+
+114
+00:08:29,790 --> 00:08:35,150
+عبارة عن مقياس لمقاومة الجسم لإنه يغير من حركته
+
+115
+00:08:35,150 --> 00:08:38,630
+بسبب هذه القوة. This kind of mass is often called
+
+116
+00:08:38,630 --> 00:08:43,470
+inertial mass. هذا النوع من الـ mass يسمى الـ inertial
+
+117
+00:08:43,470 --> 00:08:48,250
+mass أو كتلة القصور الذاتي. Because it's associated
+
+118
+00:08:48,250 --> 00:08:52,390
+with inertia. الـ mass مرتبطة بالقصور الذاتي. يعني الـ
+
+119
+00:08:52,390 --> 00:08:56,600
+mass is associated with inertia. The greater the
+
+120
+00:08:56,600 --> 00:08:59,440
+mass of the body, the less it accelerates under the
+
+121
+00:08:59,440 --> 00:09:03,620
+action of a given applied force. لو كانت الكتلة
+
+122
+00:09:03,620 --> 00:09:08,780
+كبيرة بالنسبة للجسم، the less it. طبعاً الكتلة كبيرة
+
+123
+00:09:08,780 --> 00:09:14,920
+هتكون التسارع تبعه أقل إذا كانت القوة ثابتة. Under
+
+124
+00:09:14,920 --> 00:09:18,100
+the action of a given applied force. يعني أنا
+
+125
+00:09:18,100 --> 00:09:22,100
+عندي قوة ثابتة. إذا كانت السرعة، الكتلة بتزيد
+
+126
+00:09:22,100 --> 00:09:27,820
+فالتسارع بيقل. هذه الكتلة. The unit of mass. اللي هي الـ
+
+127
+00:09:27,820 --> 00:09:31,680
+system international unit of mass is kilogram. اللي
+
+128
+00:09:31,680 --> 00:09:37,280
+هي وحدة الـ mass بالنظام الدولي. الـ kilogram. الـ mass
+
+129
+00:09:37,280 --> 00:09:41,760
+is scalar. و الـ mass هي عبارة عن كمية قياسية. That
+
+130
+00:09:41,760 --> 00:09:47,380
+obeys the rules of ordinary arithmetic. نجي للقانون
+
+131
+00:09:47,380 --> 00:09:53,110
+نيوتن الثاني. قانون نيوتن الثاني بيحكي لنا. Newton's
+
+132
+00:09:53,110 --> 00:09:55,690
+first law explained what happened to an object
+
+133
+00:09:55,690 --> 00:09:59,310
+that has no net force acting on it. القانون نيوتن
+
+134
+00:09:59,310 --> 00:10:05,750
+الأول كان بيشرح أنه that has no net force acting
+
+135
+00:10:05,750 --> 00:10:08,830
+on it. The object either remains at rest or remains
+
+136
+00:10:08,830 --> 00:10:12,290
+continues to move. قانون نيوتن الأول كان بيحكي أنه يظل
+
+137
+00:10:12,290 --> 00:10:15,710
+الجسم ساكن ما لم تؤثر عليه قوة تغير من حالته، ويظل
+
+138
+00:10:15,710 --> 00:10:19,250
+الجسم متحرك ما لم تؤثر عليه قوة تغير من حالته. يعني
+
+139
+00:10:19,250 --> 00:10:22,750
+بيمكنه يظل يستمر بالحركة بخط مستقيم و with
+
+140
+00:10:22,750 --> 00:10:25,530
+constant speed. Newton's second law. قانون نيوتن
+
+141
+00:10:25,530 --> 00:10:28,940
+الثاني answers the question of what happened to an
+
+142
+00:10:28,940 --> 00:10:32,820
+object that does have a net force acting on it.
+
+143
+00:10:32,820 --> 00:10:36,240
+بيحكي لنا قانون نيوتن الثاني ماذا يحدث إذا أثرنا
+
+144
+00:10:36,240 --> 00:10:42,780
+على الجسم بقوة معينة. طبعاً، وبنلاحظ من
+
+145
+00:10:42,780 --> 00:10:47,240
+الأشكال هذه، يعني شكل 4-5 A وB. We observe
+
+146
+00:10:47,240 --> 00:10:50,420
+that the acceleration of an object is directly
+
+147
+00:10:50,420 --> 00:10:54,490
+proportional to the net force acting on it. التسارع
+
+148
+00:10:54,490 --> 00:10:59,050
+بيتناسب تناسب طردي مع القوة اللي أنا بعطيها للجسم.
+
+149
+00:10:59,050 --> 00:11:03,010
+والتسارع بيتناسب تناسب عكسي مع الكتلة. We observe
+
+150
+00:11:03,010 --> 00:11:05,910
+that the acceleration of an object is inversely
+
+151
+00:11:05,910 --> 00:11:10,390
+proportional to its mass. أنه التسارع بيتناسب تناسب
+
+152
+00:11:10,390 --> 00:11:14,130
+طردي مع القوة اللي أنا بعطيها للجسم زي ما هو موضح
+
+153
+00:11:14,130 --> 00:11:20,450
+بالشكل. أيضاً الكتلة بتتناسب تناسب طردي مع التسارع.
+
+154
+00:11:20,920 --> 00:11:27,350
+يعني هنا بالنسبة لشكل الأول، اندي أنا جسم كتلته M
+
+155
+00:11:27,350 --> 00:11:32,570
+.. أعطيته قوة AF، فهيتحرك بـ.. بـ.. بـ.. يعني هيصير
+
+156
+00:11:32,570 --> 00:11:36,090
+عنده تسارع A. لكن لو أنا نفس الكتلة، أعطيته
+
+157
+00:11:36,090 --> 00:11:41,150
+قوة 2F، هيتسارع بتسارع 2A. معنى الكلام أنه القوة
+
+158
+00:11:41,150 --> 00:11:46,790
+تتناسب تناسب طردي مع التسارع، وتتناسب تناسب عكسي
+
+159
+00:11:46,790 --> 00:11:51,550
+مع الـ.. التسارع بتناسب تناسب عكسي مع الـ mass. التسارع
+
+160
+00:11:51,550 --> 00:11:54,850
+بيتناسب تناسب عكسي مع الـ mass. لو أنا القوة كانت
+
+161
+00:11:54,850 --> 00:11:59,490
+ثابتة في جسم أعطيته قوة F، وأنا بـ.. بشده بقوة F
+
+162
+00:11:59,490 --> 00:12:04,390
+بلاحظ أنه التسارع هيكون A. لو أنا أعطيته الـ.. الـ
+
+163
+00:12:04,390 --> 00:12:07,810
+mass، يعني صارت double، يعني كترت هنا M وهنا M وأنا
+
+164
+00:12:07,810 --> 00:12:12,150
+شديت بنفس القوة، بلاحظ أنه التسارع صار A/2. طبعاً نص
+
+165
+00:12:12,150 --> 00:12:17,910
+A. A/2. لإنه التسارع والـ mass بتناسب، وتناسب عكسي.
+
+166
+00:12:17,910 --> 00:12:21,810
+والتسارع والقوة بتناسب، وتناسب طردي. هذا هو قانون
+
+167
+00:12:21,810 --> 00:12:28,270
+نيوتن الثاني. فمعنى
+
+168
+00:12:28,270 --> 00:12:33,730
+الكلام أنه قانون نيوتن الثاني ينص على أن الـ
+
+169
+00:12:33,730 --> 00:12:37,630
+acceleration (a) of an object is directly
+
+170
+00:12:37,630 --> 00:12:42,810
+proportional to the net force acting on it and
+
+171
+00:12:42,810 --> 00:12:46,670
+inversely proportional to its mass. معنى الكلام أن
+
+172
+00:12:46,670 --> 00:12:53,070
+التسارع (a) بيتناسب تناسب طردي مع القوة ويتناسب تناسب
+
+173
+00:12:53,070 --> 00:12:58,310
+عكسي مع اللي هي اللي هي الكتلة. معنى الكلام أنه التسارع
+
+174
+00:12:58,310 --> 00:13:02,190
+(A) بتساوي summation للـ F على الـ M. ممكن أن الـ F اللي
+
+175
+00:13:02,190 --> 00:13:05,830
+أنا بأثر عليه على الجسم ممكن تكون طبعاً هو جمع
+
+176
+00:13:05,830 --> 00:13:09,890
+متجه. ممكن القوة اللي أنا بعطيها، في
+
+223
+00:16:23,970 --> 00:16:30,830
+an object (الجسم) can move when no force acts on it
+
+224
+00:16:30,830 --> 00:16:38,410
+ممكن الجسم يتحرك حتى لو مافي قوة عليه an object can
+
+225
+00:16:38,410 --> 00:16:42,190
+move even when no force acts against it. طبعا هذا
+
+226
+00:16:42,190 --> 00:16:46,310
+صحيح. لماذا؟ لأنه ممكن الجسم لما ما تكون عليه قوة
+
+227
+00:16:46,310 --> 00:16:50,610
+يعني معناته القوة تساوي صفر، إذا التسارع يساوي
+
+228
+00:16:50,610 --> 00:16:54,050
+صفر، لكنه بيتحرك بسرعة منتظمة. معناه الكلام أنه ممكن
+
+229
+00:16:54,050 --> 00:16:59,680
+يتحرك بسرعة منتظمة إذا كان مجموع القوى على هذا الجسم
+
+230
+00:16:59,680 --> 00:17:03,120
+يساوي صفر. فالـ a يساوي صفر، فهو بيتحرك بسرعة
+
+231
+00:17:03,120 --> 00:17:09,620
+ثابتة. إذا الـ a صحيحة. نجي للـ b. if an
+
+232
+00:17:09,620 --> 00:17:13,480
+object isn't moving. الجسم ما بيتحرك. no external
+
+233
+00:17:13,480 --> 00:17:18,500
+force acts on it. الجسم ما بيتحرك معناته مافيش قوة
+
+234
+00:17:18,500 --> 00:17:22,240
+خارجية مؤثرة عليه. خطأ، لإنه ممكن يكون مجموع القوى
+
+235
+00:17:22,240 --> 00:17:26,220
+يساوي صفر. يعني ممكن يكون في عندي قوة مؤثرة عليه،
+
+236
+00:17:26,220 --> 00:17:31,150
+ومجموعها يساوي صفر. هذا اللي فيه خطأ. نجي لـ C. if a
+
+237
+00:17:31,150 --> 00:17:35,550
+single force acts on an object. لو عندي أنا قوة
+
+238
+00:17:35,550 --> 00:17:40,030
+واحدة لحالها (مفردة). single force acts on an object, the
+
+239
+00:17:40,030 --> 00:17:43,770
+object accelerates. اه ممكن. ممكن أنا آثر على الجسم
+
+240
+00:17:43,770 --> 00:17:48,810
+بقوة واحدة ويصير عنده تسارع. ممكن. في في في
+
+241
+00:17:48,810 --> 00:17:55,290
+الحالة دي. في الحالة دي. if an object accelerates, at
+
+242
+00:17:55,290 --> 00:18:00,340
+least one force is acting on it. نعم. ممكن أنه يصير
+
+243
+00:18:00,340 --> 00:18:05,020
+عندي تسارع لو كان عندي at least one force is
+
+244
+00:18:05,020 --> 00:18:09,300
+acting on it. طيب يعني ممكن أن الجسم يتحرك لو
+
+245
+00:18:09,300 --> 00:18:15,940
+أثرنا عليه بقوة واحدة. نمرّ لـ  if an object is
+
+246
+00:18:15,940 --> 00:18:20,200
+accelerating, no external force is acting on it. ممكن
+
+247
+00:18:20,200 --> 00:18:25,280
+هل ممكن أنه الجسم does not accelerate? هل أن الجسم
+
+248
+00:18:25,280 --> 00:18:28,980
+does not accelerate أو isn't accelerating, no
+
+249
+00:18:28,980 --> 00:18:33,640
+external force is acting on it. خطأ في E. هذه خطأ
+
+250
+00:18:33,640 --> 00:18:39,140
+لأنها ممكن يصير لها تعجيل. هي if an object is not
+
+251
+00:18:39,140 --> 00:18:44,040
+accelerating, no external force is acting on it. لأ.
+
+252
+00:18:44,040 --> 00:18:48,540
+يعني هنا السؤال بيحكي لو أنا عندي جسم ما بيتسارع، ما
+
+253
+00:18:48,540 --> 00:18:52,040
+بيتسارع معناه الكلام أنه no external force is
+
+254
+00:18:52,040 --> 00:18:55,640
+acting on it. ممكن يكون عندي أنا قوة مؤثرة عليه،
+
+255
+00:18:55,640 --> 00:18:58,640
+ولكن مجموع القوى (summation) للـ external force
+
+256
+00:18:58,640 --> 00:19:04,000
+يساوي صفر، وبالتالي هو بيتحرك بتسارع بسرعة منتظمة،
+
+257
+00:19:04,000 --> 00:19:10,260
+والتسارع تبعه صفر. if the net force acting on the
+
+258
+00:19:10,260 --> 00:19:13,700
+object is in the positive x direction, the object
+
+259
+00:19:13,700 --> 00:19:17,550
+moves only in the positive x direction. طبعا لأ. طبعا
+
+260
+00:19:17,550 --> 00:19:21,770
+ممكن يكون الـ net force في اتجاه الـ الـ اللي
+
+261
+00:19:21,770 --> 00:19:25,830
+هي باتجاه الـ الـ negative. ممكن يكون باتجاه
+
+262
+00:19:25,830 --> 00:19:28,910
+الـ negative وبتاع، اللي هي القوى (force). هدول طبعا جمل يعني
+
+263
+00:19:28,910 --> 00:19:32,350
+بيحدد لنا أن العلاقة بين مجموع الـ F ده
+
+264
+00:19:32,350 --> 00:19:37,090
+تساوي الكتلة (mass) في التسارع (acceleration). نستكمل في
+
+265
+00:19:37,090 --> 00:19:41,970
+المحاضرة القادمة بعض الأسئلة اللي هي الخاصة بـ
+
+266
+00:19:41,970 --> 00:19:44,650
+اللي هي قانون نيوتن الأول، قانون نيوتن
+
+267
+00:19:44,650 --> 00:19:45,210
+الثاني
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..1047b4da3ad6e57bbe5b54107cbb195530d59769
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_postprocess.srt
@@ -0,0 +1,1068 @@
+1
+00:00:00,000 --> 00:00:04,700
+بسم الله الرحمن الرحيم بنستكمل مساق فيزياء عامة
+
+2
+00:00:04,700 --> 00:00:08,420
+لطلبة العلم الصحية بنبدأ ب chapter 4 بعنوان
+
+3
+00:00:08,420 --> 00:00:14,600
+Newton's laws of motion قوانين نيوتن للحركة هنعرف
+
+4
+00:00:14,600 --> 00:00:18,860
+section 4-1 اللي هي ال forces القوة هنعرف القوة
+
+5
+00:00:18,860 --> 00:00:23,700
+بداية القوة is commonly imagined as push or pull
+
+6
+00:00:23,700 --> 00:00:29,560
+أي جسم ممكن أنا أدفعه أو أسحبهممكن أنا بأثر عليه
+
+7
+00:00:29,560 --> 00:00:33,060
+بقوة it is a vector quantity ال force عبارة عن
+
+8
+00:00:33,060 --> 00:00:36,420
+كمية متجهة just like velocity and acceleration
+
+9
+00:00:36,420 --> 00:00:43,090
+تشبه السرعة الاتجاهية والتسارع ال type of forceال
+
+10
+00:00:43,090 --> 00:00:46,910
+type of forces في عندي أنا نوعين من القوة الأولى
+
+11
+00:00:46,910 --> 00:00:51,550
+اسمها contact force contact force دا قوة التلامس
+
+12
+00:00:51,550 --> 00:00:54,910
+they result from physical contact between two
+
+13
+00:00:54,910 --> 00:00:58,890
+objects as in figures ال figure طبعا أربعة اتنين
+
+14
+00:00:58,890 --> 00:01:02,190
+اللي هي ال contact force هي عبارة عن قوة التلامس
+
+15
+00:01:02,190 --> 00:01:09,150
+بين جسمينof two objects بين جسمين frictional force
+
+16
+00:01:09,150 --> 00:01:11,990
+ال contact force ممكن تكون زي ال frictional force
+
+17
+00:01:11,990 --> 00:01:15,970
+كمثال قوة الاحتكاك ال tension force قوة الشد ال
+
+18
+00:01:15,970 --> 00:01:19,290
+normal force قوة اللي هي رد الفعل عمودية وال air
+
+19
+00:01:19,290 --> 00:01:23,010
+resistance of force and spring force are examples
+
+20
+00:01:23,010 --> 00:01:27,460
+of contact force يعنيكأمثلة على قوة التلامس قوة
+
+21
+00:01:27,460 --> 00:01:31,400
+الاحتكاك ال tension اللي هو الشد ال normal force
+
+22
+00:01:31,400 --> 00:01:35,640
+قوة رد الفعل العمودية وال air resistance force قوة
+
+23
+00:01:35,640 --> 00:01:39,760
+مقاومة الهواء و قوة اللي هو النابض أو ال spring
+
+24
+00:01:39,760 --> 00:01:43,400
+كهيولة كلها أمثلة على ال contact force النوع
+
+25
+00:01:43,400 --> 00:01:46,340
+التاني من ال contact من القوة هي اسمها field
+
+26
+00:01:46,340 --> 00:01:51,030
+forcesال field force دي doesn't involve any direct
+
+27
+00:01:51,030 --> 00:01:54,890
+physical contact between object طبعا مافيش تلامس
+
+28
+00:01:54,890 --> 00:01:59,550
+بينها وبين الأجسام زي ال gravitational force قوة
+
+29
+00:01:59,550 --> 00:02:02,490
+الجاذبية أو بعدين electrical force قوة الكهربية
+
+30
+00:02:02,490 --> 00:02:06,250
+and magnetic force قوة المغناطسية هدولة برضه أمثلة
+
+31
+00:02:06,250 --> 00:02:10,940
+على ال field forceيعني مافي contact مافي تلامس هي
+
+32
+00:02:10,940 --> 00:02:15,940
+هذا الشكل ب .. ب .. الأشكال هذه طبعا شكل A و B و C
+
+33
+00:02:15,940 --> 00:02:20,540
+ب .. بيمثل ليه؟ اللي هي بالنسبة ل ال contact force
+
+34
+00:02:20,540 --> 00:02:24,140
+اللي هي قوة الزنبارك contact force لما أشد أنا
+
+35
+00:02:24,140 --> 00:02:28,060
+عربة برضه contact force لما أضرب كرة لمستها
+
+36
+00:02:28,060 --> 00:02:33,060
+contact force لكن ال field force قوة بين جسمين أو
+
+37
+00:02:33,060 --> 00:02:39,940
+particle قوة بين مثلا جسم صغير مع جسم صغيرفي عندى
+
+38
+00:02:39,940 --> 00:02:44,600
+قوة او قوة بين شحنتين طبعا فى قوة مجال كهربي هنا
+
+39
+00:02:44,600 --> 00:02:48,040
+ممكن مجال مغناطيس اللى هى اللى هى ال iron قطعة من
+
+40
+00:02:48,040 --> 00:02:52,400
+الحديد و قربت لها مغناطيس بيكون عندنا قوة تجاذب
+
+41
+00:02:52,400 --> 00:02:57,000
+فهذه بيسموها ال field force لا يشترط التلامس فيها
+
+42
+00:02:57,000 --> 00:03:02,560
+لا يشترط التلامس فيها اذا اللى هى فى عندنا قوتين
+
+43
+00:03:02,560 --> 00:03:08,540
+ال contact force و ال field force section 4-2The
+
+44
+00:03:08,540 --> 00:03:14,880
+laws of motion قوانين اللي هي الحركة أسحاق نيوتن
+
+45
+00:03:14,880 --> 00:03:18,580
+propose three laws of motion طبعا قوانين الحركة
+
+46
+00:03:18,580 --> 00:03:25,200
+اللي هي اللي طبعا اكتشفها هو أسحاق نيوتنto offer a
+
+47
+00:03:25,200 --> 00:03:29,320
+systematic method of calculating an object motion
+
+48
+00:03:29,320 --> 00:03:31,300
+due to the forces exerted on it
+
+49
+00:03:53,970 --> 00:03:59,390
+و يظل أيضا الجسم متحرك ما لم تؤثر عليه قوة من
+
+50
+00:03:59,390 --> 00:04:02,970
+حالته تغير من حالته طبعا بالنسبة لقانونه الأول
+
+51
+00:04:02,970 --> 00:04:06,710
+consider .. consider a book lying on a table لو
+
+52
+00:04:06,710 --> 00:04:10,790
+عندي أنا كتاب، الكتاب موجود على الطاولة obviously
+
+53
+00:04:10,790 --> 00:04:15,880
+the book remain at rest if it .. if left aloneطبعا
+
+54
+00:04:15,880 --> 00:04:19,500
+الكتاب كمثال موجود على طاولة الكتاب هيظل موجود ما
+
+55
+00:04:19,500 --> 00:04:23,320
+لم تؤثر عليه أي قوة now imagining pushing the book
+
+56
+00:04:23,320 --> 00:04:27,580
+بدأ أتصور أنه أنا شديت الكتاب بقوة أفقية with
+
+57
+00:04:27,580 --> 00:04:32,280
+horizontal forces great enough to overcome the
+
+58
+00:04:32,280 --> 00:04:35,460
+force of friction between the book and the table
+
+59
+00:04:35,460 --> 00:04:40,320
+نفترض أنه أنا شديت هذا الكتاب بقوة أكبر من قوة
+
+60
+00:04:40,320 --> 00:04:44,730
+اللي هي التلامسأو الاحتكاك بين الكتاب وبين الجسم
+
+61
+00:04:44,730 --> 00:04:48,850
+أو الأرض وبالتالي فالكتاب سوف يتحرك Setting the
+
+62
+00:04:48,850 --> 00:04:53,490
+book in motion هيظل موجود الكتاب في الحركة because
+
+63
+00:04:53,490 --> 00:04:56,770
+the magnitude of the applied force exceed exceed
+
+64
+00:04:56,770 --> 00:04:59,630
+the magnitude of the friction force the book
+
+65
+00:04:59,630 --> 00:05:02,870
+accelerate طبعا إذا كانت القوة اللي أنا شدت فيها
+
+66
+00:05:02,870 --> 00:05:07,050
+الكتاب أكبر من قوة الاحتكاك فالكتاب طبعا هيمشي
+
+67
+00:05:07,050 --> 00:05:11,530
+يتسارعwhen the applied force is with the drone إذا
+
+68
+00:05:11,530 --> 00:05:15,290
+أنا رسمت القوة اللي أعطته إياها ال friction slow
+
+69
+00:05:15,290 --> 00:05:21,070
+the book to stop قوة الاحتكاك طبعا بتخلي الكتاب
+
+70
+00:05:21,070 --> 00:05:26,550
+طبعا حركته تقل شوية لإنه هي عبارة عن يعني قوته
+
+71
+00:05:26,550 --> 00:05:30,450
+يعني عكس اتجاه الحركةNow imagine the book is
+
+72
+00:05:30,450 --> 00:05:33,410
+moving on a horizontal frictionless surface الان
+
+73
+00:05:33,410 --> 00:05:37,750
+بده افرض في عندى انا كتاب محطوط على سطح أملس
+
+74
+00:05:37,750 --> 00:05:41,530
+frictionless surface it continue to move in a
+
+75
+00:05:41,530 --> 00:05:44,250
+straight line with constant velocity until it hits
+
+76
+00:05:44,250 --> 00:05:48,430
+a wall or some other obstruction طبعا لو كان
+
+77
+00:05:48,430 --> 00:05:52,760
+الكتاب هو أساسا بيمشي على سطح أملس هيضل يمشيب
+
+78
+00:05:52,760 --> 00:05:57,280
+constant velocity ما لم تؤثر عليه يؤثر عليه أي شيء
+
+79
+00:05:57,280 --> 00:06:02,040
+كما أنه ممكن يصطدم بحائط أو ممكن يصطدم بأي حاجة
+
+80
+00:06:02,040 --> 00:06:07,180
+الآن لو كان عندي أنا هاي الكتاب الكتاب بيتحرك
+
+81
+00:06:07,180 --> 00:06:12,720
+بسرعة معينة أنا شدته طبعا عكس العكس الحركة هذه قوة
+
+82
+00:06:12,720 --> 00:06:16,300
+احتكاك عكس الحركة لو كانت أنا شدته بقوة عكس الحركة
+
+83
+00:06:16,300 --> 00:06:19,460
+أكبر من قوة الاحتكاك هيمشي هيبقى اللي يمشي للكتاب
+
+84
+00:06:20,900 --> 00:06:24,540
+ما لم تأثر عليه قوة تغير من حالته وكذلك لو كان
+
+85
+00:06:24,540 --> 00:06:28,460
+الكتاب أساسا هو ماشي ومافي أي قوة وقفته هيظل ماشي
+
+86
+00:06:28,460 --> 00:06:32,080
+إذا هذا قانون نيوتن الأول ال net force no change
+
+87
+00:06:32,080 --> 00:06:34,820
+in the velocity القوة قانون نيوتن الأول بيحكي أنه
+
+88
+00:06:34,820 --> 00:06:38,240
+يظل الجسم ساكن ما لم تأثر عليه قوة تغير من حالته
+
+89
+00:06:38,240 --> 00:06:42,980
+ويظل الجسم متحرك ما لم تأثر عليه قوة تغير من حالته
+
+90
+00:06:44,370 --> 00:06:47,730
+قانون نيوتن الأول للحركة an object moves with
+
+91
+00:06:47,730 --> 00:06:50,370
+velocity that is constant in magnitude and
+
+92
+00:06:50,370 --> 00:06:53,730
+direction unless a non-zero net force acts on it
+
+93
+00:06:53,730 --> 00:06:57,790
+هذا بالإنقليش تعريف قانون نيوتن الأول بيحكي لنا
+
+94
+00:06:57,790 --> 00:07:03,030
+the net force on an object is defined as the
+
+95
+00:07:03,030 --> 00:07:06,750
+vector sum of all external force exerted on the
+
+96
+00:07:06,750 --> 00:07:11,710
+objectطبعا net force هي عبارة عن مجموعة للقوة
+
+97
+00:07:11,710 --> 00:07:16,550
+المؤثرة على الجسم، هي عبارة عن مجموعة للقوة جامعية
+
+98
+00:07:16,550 --> 00:07:23,230
+متجاهي لكل القوة الخارجية التي تؤثر على الجسمهنا
+
+99
+00:07:23,230 --> 00:07:26,930
+القانون نيوتن الأول انه on object move أي جسم
+
+100
+00:07:26,930 --> 00:07:32,090
+هيتحرك بسرعة معينة بسرعة constant magnitude and
+
+101
+00:07:32,090 --> 00:07:37,790
+direction بيضل الجسم يتحرك ما لم تؤثر عليه قوة غير
+
+102
+00:07:37,790 --> 00:07:42,150
+من حالتهمعنى الكلام أنه بنجيب احنا ال net force
+
+103
+00:07:42,150 --> 00:07:46,450
+المؤثرة على هذا الجسم the external forces come
+
+104
+00:07:46,450 --> 00:07:50,010
+from an object environment القوة الخارجية بتيجي من
+
+105
+00:07:50,010 --> 00:07:54,830
+من اللي هي اللي يعني الجو المحيط أو الظروف المحيطة
+
+106
+00:07:54,830 --> 00:07:58,730
+وليس من داخل الجسم بيسموها external force القوة
+
+107
+00:07:58,730 --> 00:08:03,750
+الخارجيةالتعريف ال mass and inertia ال inertia هي
+
+108
+00:08:03,750 --> 00:08:07,230
+الخصور الذاتي is the tendency of an object to
+
+109
+00:08:07,230 --> 00:08:11,310
+continue its motion in the absence of the force هي
+
+110
+00:08:11,310 --> 00:08:17,690
+يعني قدرة اللي هي ال اي جسم انه يستمر في حركته في
+
+111
+00:08:17,690 --> 00:08:21,890
+عدم وجود القوة المؤثرة and mass is the measure of
+
+112
+00:08:21,890 --> 00:08:25,090
+the object resistance to the change in its motion
+
+113
+00:08:25,090 --> 00:08:29,790
+due to the force اللي ال mass اللي هي الكتلةهي
+
+114
+00:08:29,790 --> 00:08:35,150
+عبارة عن مقياس لمقاومة الجسم لإنه يغير من حركته
+
+115
+00:08:35,150 --> 00:08:38,630
+بسبب هذه القوة This kind of mass is often called
+
+116
+00:08:38,630 --> 00:08:43,470
+inertia mass هذا النوع من ال mass يسمى ال inertial
+
+117
+00:08:43,470 --> 00:08:48,250
+mass أو كتلة القصور الذاتي because it's associated
+
+118
+00:08:48,250 --> 00:08:52,390
+with inertia ال mass مرتبطة بالقصور الذاتي يعني ال
+
+119
+00:08:52,390 --> 00:08:56,600
+mass is associated with inertiathe greater the
+
+120
+00:08:56,600 --> 00:08:59,440
+mass of the body the less it accelerates under the
+
+121
+00:08:59,440 --> 00:09:03,620
+action of the given applied force لو كانت الكتلة
+
+122
+00:09:03,620 --> 00:09:08,780
+كبيرة بالنسبة للجسم the less it طبعا الكتلة كبيرة
+
+123
+00:09:08,780 --> 00:09:14,920
+هتكون التسارع تبعه أقل إذا كانت القوة ثابتة under
+
+124
+00:09:14,920 --> 00:09:18,100
+the action of the given applied force يعني أنا
+
+125
+00:09:18,100 --> 00:09:22,100
+عندي قوة ثابتة إذا كانت السرعه الكتلة بتزيد
+
+126
+00:09:22,100 --> 00:09:27,820
+فالتسارع بقل هذه الكتلةthe unit of mass اللى هى ال
+
+127
+00:09:27,820 --> 00:09:31,680
+system international unit of mass is kilogram اللى
+
+128
+00:09:31,680 --> 00:09:37,280
+هى وحدة ال mass بالنظام الدولى ال kilogram ال mass
+
+129
+00:09:37,280 --> 00:09:41,760
+is scalar و ال mass هى عبارة عن كمية قياسية that
+
+130
+00:09:41,760 --> 00:09:47,380
+obey the rules of ordinary arithmetic نجلا القانون
+
+131
+00:09:47,380 --> 00:09:53,110
+نيوتن التانىقانون نيوتن التاني بيحكي لنا Newton's
+
+132
+00:09:53,110 --> 00:09:55,690
+first law explained what happened to an object
+
+133
+00:09:55,690 --> 00:09:59,310
+that has no net force acting on it القانون نيوتن
+
+134
+00:09:59,310 --> 00:10:05,750
+الأول كان بيشرح أنه that has no net force acting
+
+135
+00:10:05,750 --> 00:10:08,830
+on it the object either remain at rest or remain
+
+136
+00:10:08,830 --> 00:10:12,290
+continue moveقانون نيوتن الأول كان بيحكي أنه يظل
+
+137
+00:10:12,290 --> 00:10:15,710
+الجسم ساكن ما لم تؤثر عليه قوة غير من حالته و يظل
+
+138
+00:10:15,710 --> 00:10:19,250
+الجسم متحرك ما لم تؤثر عليه قوة غير من حالته يعني
+
+139
+00:10:19,250 --> 00:10:22,750
+بيمكنه يظل يستمر بالحركة بخط مستقيم و with
+
+140
+00:10:22,750 --> 00:10:25,530
+constant speed Newton's second law قانون نيوتن
+
+141
+00:10:25,530 --> 00:10:28,940
+التاني answer the question of what happenedto an
+
+142
+00:10:28,940 --> 00:10:32,820
+object that does have a net force acting on it
+
+143
+00:10:32,820 --> 00:10:36,240
+بيحكي لنا قانون يوتر التاني ماذا يحدث إذا أثرنا
+
+144
+00:10:36,240 --> 00:10:42,780
+على الجسم بسرعة بقوة معينة طبعا و بنلاحظ من
+
+145
+00:10:42,780 --> 00:10:47,240
+الأشكال هذه يعني شكل أربعة خمسة a و b we observe
+
+146
+00:10:47,240 --> 00:10:50,420
+that the acceleration of an object is directly
+
+147
+00:10:50,420 --> 00:10:54,490
+proportional to the net force acting on itالتسارع
+
+148
+00:10:54,490 --> 00:10:59,050
+بيتناسب تناسب ترضي مع القوة اللي أنا بعطيها للجسم
+
+149
+00:10:59,050 --> 00:11:03,010
+والتسارع بيتناسب تناسب عكسي مع الكتلة we observe
+
+150
+00:11:03,010 --> 00:11:05,910
+that the acceleration of an object is inversely
+
+151
+00:11:05,910 --> 00:11:10,390
+proportional to the mass أنه التسارع بيتناسب تناسب
+
+152
+00:11:10,390 --> 00:11:14,130
+ترضي مع القوة اللي أنا بعطيها للجسم زي ما هو موضح
+
+153
+00:11:14,130 --> 00:11:20,450
+بالشكل أيضا الكتلة بتتناسب تناسب ترضي مع التسارع
+
+154
+00:11:20,920 --> 00:11:27,350
+يعني هنا بالنسبة لشكل الأول اندي أنا جسم كتل تقامب
+
+155
+00:11:27,350 --> 00:11:32,570
+.. اعطيته قوة AF فهيتحرك ب .. ب .. ب .. يعني هيصير
+
+156
+00:11:32,570 --> 00:11:36,090
+عنده تسارع A لكن لو أنا كتلة و نفسي الكتلة اعطيته
+
+157
+00:11:36,090 --> 00:11:41,150
+قوة 2F هيتسارع بتسارع 2A معناه الكلام انه القوة
+
+158
+00:11:41,150 --> 00:11:46,790
+تتناسب تناسب ترضي مع التسارع و تتناسب تناسب عكسي
+
+159
+00:11:46,790 --> 00:11:51,550
+مع ال .. التسارع بتناسب تناسب عكسي مع ال massتسارع
+
+160
+00:11:51,550 --> 00:11:54,850
+بتناسب تناسب عكسي مع ال mask لو أنا القوة كانت
+
+161
+00:11:54,850 --> 00:11:59,490
+ثابتة في جسم أعطيته قوة F و أنا ب .. بشده بقوة F
+
+162
+00:11:59,490 --> 00:12:04,390
+بلاحظ أنه التسارع هيكون A لو أنا أعطيته ال .. ال
+
+163
+00:12:04,390 --> 00:12:07,810
+mask يعني صارت double يعني كترت هنا M و هنا M و
+
+164
+00:12:07,810 --> 00:12:12,150
+أنا شدت بنفس القوة بلاحظ أنه التسارع صار A طبعا نص
+
+165
+00:12:12,150 --> 00:12:17,910
+A A ع 2 لإنه التسارع و ال mask بتناسب و تناسب عكسي
+
+166
+00:12:17,910 --> 00:12:21,810
+و التسارع و القوة بتناسب و تناسب ترددهذا هو قانون
+
+167
+00:12:21,810 --> 00:12:28,270
+نيوتن التاني فمعنى
+
+168
+00:12:28,270 --> 00:12:33,730
+الكلام أنه قانون نيوتن التاني ينص على أن ال
+
+169
+00:12:33,730 --> 00:12:37,630
+acceleration a of an object is directly
+
+170
+00:12:37,630 --> 00:12:42,810
+proportional to the net force acting on it and
+
+171
+00:12:42,810 --> 00:12:46,670
+inversely proportional to its mass معنى الكلام أن
+
+172
+00:12:46,670 --> 00:12:53,070
+التسارع a بتناسب تناسبترضي مع القوة ويتناسب تناسب
+
+173
+00:12:53,070 --> 00:12:58,310
+عكس ما اللى اللى هي الكتلة معنى الكلام أنه التسارع
+
+174
+00:12:58,310 --> 00:13:02,190
+A بتساوي summation لل F على ال M ممكن أن ال F اللى
+
+175
+00:13:02,190 --> 00:13:05,830
+أنا بأثر عليه على الجسم ممكن تكون طبعا هو جمع
+
+176
+00:13:05,830 --> 00:13:09,890
+اتجاهي ممكن القوة اللى أنا بعطيها في قوة احتكاك في
+
+177
+00:13:09,890 --> 00:13:15,610
+قوة أخرى فالمجموعة القوة ال F ده تساوي ال M في AA
+
+178
+00:13:15,610 --> 00:13:18,230
+where A is the acceleration of the object و ال M
+
+179
+00:13:18,230 --> 00:13:21,590
+هي عبارة عن الماس اللي هي الكتلة و ال A summation
+
+180
+00:13:21,590 --> 00:13:26,070
+لل F is the vector sum هو المجموع اللي هي مجموع
+
+181
+00:13:26,070 --> 00:13:29,530
+الخواجم اتجاهي of all forces acting on it
+
+182
+00:13:29,530 --> 00:13:33,810
+Multiplying through by M, we observe لو أنا ضربت
+
+183
+00:13:33,810 --> 00:13:39,260
+الالطبعا القانون المُعطى ب M هيصير عندي summation
+
+184
+00:13:39,260 --> 00:13:42,880
+لل F تساوي ال M في A وهذا هو قانون ال Newton
+
+185
+00:13:42,880 --> 00:13:47,920
+التاني ال A عبارة عن vector و ال F vector و ال M
+
+186
+00:13:47,920 --> 00:13:51,880
+هي عبارة عن scalar ال A و ال M في بينهم تناسب ..
+
+187
+00:13:51,880 --> 00:13:57,960
+تتناسب تناسب هنا عكسي و ال F و ال A بتناسب تناسب
+
+188
+00:13:57,960 --> 00:13:58,460
+تاردي
+
+189
+00:14:04,250 --> 00:14:07,930
+The second law is a vector equation equivalent to
+
+190
+00:14:07,930 --> 00:14:11,250
+the following three components طبعا summation لل F
+
+191
+00:14:11,250 --> 00:14:15,410
+هذه ال F as a vector عبارة عن summation لل F بتجاه
+
+192
+00:14:15,410 --> 00:14:19,230
+ال X بالساوية M في A بتجاه ال X بال X axis ممكن
+
+193
+00:14:19,230 --> 00:14:23,690
+انا اعمل summation لل FY M في Ay summation لل FZ
+
+194
+00:14:23,690 --> 00:14:27,240
+بالساوية M في AZ لكن هذا القانون بصفة عامة انهالـ
+
+195
+00:14:27,240 --> 00:14:30,760
+Assumption ال F ك vector سوى ال M في A ك vector ال
+
+196
+00:14:30,760 --> 00:14:35,380
+A ممكن تكون A X A Y A Z وال F ممكن تكون F X F Y F
+
+197
+00:14:35,380 --> 00:14:35,660
+Z
+
+198
+00:14:39,810 --> 00:14:43,090
+when there is no net force on an object لو مافيه
+
+199
+00:14:43,090 --> 00:14:47,190
+قوة يعني محصلة قوة مؤثرة على الجسم its
+
+200
+00:14:47,190 --> 00:14:50,970
+acceleration is zero لو كانت عند صماش المجموعة
+
+201
+00:14:50,970 --> 00:14:54,310
+القوة المؤثرة على الجسم ساوة صفر معنى الكلام اللي
+
+202
+00:14:54,310 --> 00:14:57,830
+قابد هتساوي زفق صفر which is mean معنى هذا أنه
+
+203
+00:14:57,830 --> 00:15:01,750
+التسائل السرعة الاتجاهية هي عبارة عن ثابت او اذا
+
+204
+00:15:01,750 --> 00:15:06,410
+حكالي انهالسرعة الاتجاهية ثابتة معناه الكلام انه
+
+205
+00:15:06,410 --> 00:15:11,430
+التسارع بيساوي zero وبالتالي summation لل F بيساوي
+
+206
+00:15:11,430 --> 00:15:17,090
+zeroبالنسبة ل ال units of force and mass نسبة
+
+207
+00:15:17,090 --> 00:15:21,050
+لوحدة القوة و ال mass في النظام الدولي ال system
+
+208
+00:15:21,050 --> 00:15:24,710
+international unit of force is the newton طبعا ال
+
+209
+00:15:24,710 --> 00:15:28,450
+force وحدتها newton when واحد newton of the force
+
+210
+00:15:28,450 --> 00:15:31,990
+act on an object that has mass of واحد كيلو it
+
+211
+00:15:31,990 --> 00:15:36,410
+produce an acceleration of واحد متر في الثانية
+
+212
+00:15:36,410 --> 00:15:39,510
+تربية in the object from this definition and
+
+213
+00:15:39,510 --> 00:15:42,580
+newton's second law we see thatمعنى الكلام الواحد
+
+214
+00:15:42,580 --> 00:15:45,500
+نيوتن بيبقى تساوي واحد كيلو جرام مضروبة في متر في
+
+215
+00:15:45,500 --> 00:15:48,600
+الثانية تربيع يعني ال mass في ال acceleration وحدة
+
+216
+00:15:48,600 --> 00:15:52,140
+ال mass كيلو جرام وحدة التسارق متر في الثانية
+
+217
+00:15:52,140 --> 00:15:55,240
+تربيع إذا الواحد نيوتن بيبقى تساوي واحد كيلو جرام
+
+218
+00:15:55,240 --> 00:16:02,530
+مضروبة في متر في الثانية تربيعنشوف هذا ال quiz ال
+
+219
+00:16:02,530 --> 00:16:05,690
+quiz أربعة واحد which of the following statement
+
+220
+00:16:05,690 --> 00:16:09,730
+are true؟ مين من الجمال هذه صحيحة؟ مين من الجمال
+
+221
+00:16:09,730 --> 00:16:12,570
+هذه المعطاش صحيحة؟
+
+222
+00:16:19,730 --> 00:16:23,970
+الان an object can move even when no force acting
+
+223
+00:16:23,970 --> 00:16:30,830
+on it الجسم ممكن يتحرك when no force acts on it
+
+224
+00:16:30,830 --> 00:16:38,410
+ممكن الجسم يتحرك حتى لو مافي قوة عليهan object can
+
+225
+00:16:38,410 --> 00:16:42,190
+move even when no force acts against it طبعا هذا
+
+226
+00:16:42,190 --> 00:16:46,310
+صحيح لماذا؟ لأنه ممكن الجسم لما ما تكون قالي قوة
+
+227
+00:16:46,310 --> 00:16:50,610
+يعني معناته القوة بالساوء صفر إذا التسارق بالساوء
+
+228
+00:16:50,610 --> 00:16:54,050
+صفر لكنه بتحرك بسرعة منتظمة معناه الكلام أنه ممكن
+
+229
+00:16:54,050 --> 00:16:59,680
+يتحرك بسرعة منتظمة إذا كانهذا الجسم مجموع القوة
+
+230
+00:16:59,680 --> 00:17:03,120
+بيساوي zero فال a بيساوي zero فهو بتحرك بسرعة
+
+231
+00:17:03,120 --> 00:17:09,620
+إثابتة إذا ال a true ال a صحيحة نجي لل b if an
+
+232
+00:17:09,620 --> 00:17:13,480
+object isn't moving الجسم ما بتحرك no external
+
+233
+00:17:13,480 --> 00:17:18,500
+force act on itالجسم ما بتحرك معناته مافيش قوة
+
+234
+00:17:18,500 --> 00:17:22,240
+خارجية مؤثرة عليه خطأ لإنه ممكن يكون مجموع القوة
+
+235
+00:17:22,240 --> 00:17:26,220
+بتساوي zero يعني ممكن يكون في عندي قوة مؤثرة عليه
+
+236
+00:17:26,220 --> 00:17:31,150
+ومجموعة بتساوي zero هذا اللي في بيه خطأ نجلة Cif a
+
+237
+00:17:31,150 --> 00:17:35,550
+single force acts on an object لو عندي أنا قوة
+
+238
+00:17:35,550 --> 00:17:40,030
+لحالها مفردة single force acts on an object the
+
+239
+00:17:40,030 --> 00:17:43,770
+object accelerates اه ممكن ممكن انا اثر على الجسم
+
+240
+00:17:43,770 --> 00:17:48,810
+بقوة واحدة و يصير عنده تسارق ممكن في في في في
+
+241
+00:17:48,810 --> 00:17:55,290
+الحالة دي في الحالة دي if an object accelerates at
+
+242
+00:17:55,290 --> 00:18:00,340
+least one force is acting on itنعم ممكن أنه يصير
+
+243
+00:18:00,340 --> 00:18:05,020
+عندى تسارع لو كان عندى at least one force is
+
+244
+00:18:05,020 --> 00:18:09,300
+acting on it طيب يعني الممكن أن الجسم اتحرك لو
+
+245
+00:18:09,300 --> 00:18:15,940
+أثرنا عليه بقوة واحدة نمرأي if an object is
+
+246
+00:18:15,940 --> 00:18:20,200
+accelerate no external force is acting on it ممكن
+
+247
+00:18:20,200 --> 00:18:25,280
+هل ممكن أنه الجسم does not accelerateهل ان الجسم
+
+248
+00:18:25,280 --> 00:18:28,980
+does not accelerate او isn't accelerating, no
+
+249
+00:18:28,980 --> 00:18:33,640
+external force is acting on it خطأ في E هذه خطأ
+
+250
+00:18:33,640 --> 00:18:39,140
+لإنها ممكن يصير لها تعجيل هي if an object is not
+
+251
+00:18:39,140 --> 00:18:44,040
+accelerating, no external force is acting on it لأ
+
+252
+00:18:44,040 --> 00:18:48,540
+يعني هنا السؤال بيحكي لو أنا عندي جسم ما بتسارعما
+
+253
+00:18:48,540 --> 00:18:52,040
+بتسارع معناه الكلام انه no external force is
+
+254
+00:18:52,040 --> 00:18:55,640
+acting on it ممكن يكون عندي أنا قوة مؤثرة عليه
+
+255
+00:18:55,640 --> 00:18:58,640
+ولكن القوة summation لل force ال external force
+
+256
+00:18:58,640 --> 00:19:04,000
+بتساوي zero و بالتالي هو بتحرك بتسارع بسرعة منتظمة
+
+257
+00:19:04,000 --> 00:19:10,260
+و التسارع تبعه zero if the net force acting on the
+
+258
+00:19:10,260 --> 00:19:13,700
+object is in the positive x direction the object
+
+259
+00:19:13,700 --> 00:19:17,550
+move only in the positive x direction طبعا لأطب
+
+260
+00:19:17,550 --> 00:19:21,770
+ممكن يكون ال net force في اتجاه ال .. ال .. اللي
+
+261
+00:19:21,770 --> 00:19:25,830
+هي باتجاه ال .. ال negative ممكن يكون باتجاه
+
+262
+00:19:25,830 --> 00:19:28,910
+النجدة و بتاع اللي هي force هدول طبعا جمل يعني
+
+263
+00:19:28,910 --> 00:19:32,350
+بيحددلنا انه العلاقة بين ال summation لل F ده
+
+264
+00:19:32,350 --> 00:19:37,090
+تساوي ال mass في ال acceleration نستكمل في
+
+265
+00:19:37,090 --> 00:19:41,970
+المحاضرة القادمة بعض الأسئلة اللي هي الخاصة بيه
+
+266
+00:19:41,970 --> 00:19:44,650
+اللي هي Newton قانون نيوتن الأول قانون نيوتن
+
+267
+00:19:44,650 --> 00:19:45,210
+التاني
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..ee4ed960d2c43d7d90b5bc1d428174aa05a1859b
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 2752, "start": 0.0, "end": 27.52, "text": "بسم الله الرحمن الرحيم بنستكمل مساق فيزياء عامة لطلبة العلم الصحية بنبدأ ب chapter 4 بعنوان Newton's laws of motion قوانين نيوتن للحركة هنعرف section 4-1 اللي هي ال forces القوة هنعرف القوة بداية القوة is commonly imagined as push or pull أي جسم ممكن أنا أدفعه أو أسحبه", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 44945, 14851, 24793, 1211, 47524, 995, 4587, 8978, 11622, 1829, 16606, 6225, 10943, 3660, 5296, 9566, 46152, 3660, 18863, 19528, 31767, 5016, 10632, 44945, 44510, 10721, 4724, 7187, 1017, 45030, 1863, 2407, 7649, 19541, 311, 6064, 295, 5394, 12174, 2407, 7649, 9957, 8717, 1829, 35473, 1863, 5296, 1211, 5016, 31747, 3660, 8032, 1863, 3615, 28480, 3541, 1017, 12, 16, 13672, 1829, 39896, 2423, 5874, 25062, 2407, 3660, 8032, 1863, 3615, 28480, 25062, 2407, 3660, 4724, 28259, 10632, 25062, 2407, 3660, 307, 12719, 16590, 382, 2944, 420, 2235, 36632, 10874, 38251, 3714, 43020, 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607.39, "end": 607.81, "word": " remain", "probability": 0.5126953125}, {"start": 607.81, "end": 608.03, "word": " at", "probability": 0.9677734375}, {"start": 608.03, "end": 608.29, "word": " rest", "probability": 0.939453125}, {"start": 608.29, "end": 608.57, "word": " or", "probability": 0.9638671875}, {"start": 608.57, "end": 608.83, "word": " remain", "probability": 0.66748046875}, {"start": 608.83, "end": 609.27, "word": " continue", "probability": 0.80615234375}, {"start": 609.27, "end": 609.61, "word": " move", "probability": 0.8203125}], "temperature": 1.0}, {"id": 27, "seek": 62795, "start": 609.91, "end": 627.95, "text": "قانون نيوتن الأول كان بيحكي أنه يظل الجسم ساكن ما لم تؤثر عليه قوة غير من حالته و يظل الجسم متحرك ما لم تؤثر عليه قوة غير من حالته يعني بيمكنه يظل يستمر بالحركة بخط مستقيم و with constant speed Newton's second law قانون نيوتن التاني answer the question of what happened", "tokens": [4587, 7649, 11536, 8717, 1829, 35473, 1863, 16247, 12610, 25961, 4724, 1829, 5016, 4117, 1829, 14739, 3224, 7251, 19913, 1211, 25724, 38251, 8608, 995, 19452, 19446, 32767, 6055, 33604, 49115, 47356, 12174, 2407, 3660, 32771, 13546, 9154, 11331, 6027, 47395, 4032, 7251, 19913, 1211, 25724, 38251, 44650, 5016, 31747, 19446, 32767, 6055, 33604, 49115, 47356, 12174, 2407, 3660, 32771, 13546, 9154, 11331, 6027, 47395, 37495, 22653, 4724, 32640, 19452, 3224, 7251, 19913, 1211, 7251, 14851, 29973, 20666, 5016, 31747, 3660, 4724, 9778, 9566, 3714, 14851, 4587, 32640, 4032, 365, 5754, 3073, 19541, 311, 1150, 2101, 12174, 7649, 11536, 8717, 1829, 35473, 1863, 16712, 7649, 1829, 1867, 264, 1168, 295, 437, 2011], "avg_logprob": -0.12730189066912448, "compression_ratio": 1.8189655172413792, "no_speech_prob": 1.341104507446289e-05, "words": [{"start": 609.91, "end": 610.31, "word": "قانون", "probability": 0.9108072916666666}, {"start": 610.31, "end": 610.59, "word": " نيوتن", "probability": 0.81396484375}, {"start": 610.59, "end": 610.91, "word": " الأول", "probability": 0.927734375}, {"start": 610.91, "end": 611.13, "word": " كان", "probability": 0.91162109375}, {"start": 611.13, "end": 611.47, "word": " بيحكي", "probability": 0.97744140625}, {"start": 611.47, "end": 611.85, "word": " أنه", "probability": 0.76611328125}, {"start": 611.85, "end": 612.29, "word": " يظل", "probability": 0.9168294270833334}, {"start": 612.29, "end": 612.65, "word": " الجسم", "probability": 0.97509765625}, {"start": 612.65, "end": 613.03, "word": " ساكن", "probability": 0.9796549479166666}, {"start": 613.03, "end": 613.15, "word": " ما", "probability": 0.841796875}, {"start": 613.15, "end": 613.31, "word": " لم", "probability": 0.9658203125}, {"start": 613.31, "end": 613.65, "word": " تؤثر", "probability": 0.8787434895833334}, {"start": 613.65, "end": 613.85, "word": " عليه", "probability": 0.97119140625}, {"start": 613.85, "end": 614.15, "word": " قوة", "probability": 0.9689127604166666}, {"start": 614.15, "end": 614.41, "word": " غير", "probability": 0.968017578125}, {"start": 614.41, "end": 614.55, "word": " من", "probability": 0.99169921875}, {"start": 614.55, "end": 614.97, "word": " حالته", "probability": 0.9889322916666666}, {"start": 614.97, "end": 615.47, "word": " و", "probability": 0.93115234375}, {"start": 615.47, "end": 615.71, "word": " يظل", "probability": 0.900390625}, {"start": 615.71, "end": 616.03, "word": " الجسم", "probability": 0.984375}, {"start": 616.03, "end": 616.47, "word": " متحرك", "probability": 0.9943033854166666}, {"start": 616.47, "end": 616.61, "word": " ما", "probability": 0.97412109375}, {"start": 616.61, "end": 616.73, "word": " لم", "probability": 0.93798828125}, {"start": 616.73, "end": 617.07, "word": " تؤثر", "probability": 0.95947265625}, {"start": 617.07, "end": 617.31, "word": " عليه", "probability": 0.9736328125}, {"start": 617.31, "end": 617.61, "word": " قوة", "probability": 0.9873046875}, {"start": 617.61, "end": 617.93, "word": " غير", "probability": 0.992919921875}, {"start": 617.93, "end": 618.07, "word": " من", "probability": 0.99365234375}, {"start": 618.07, "end": 618.53, "word": " حالته", "probability": 0.9952799479166666}, {"start": 618.53, "end": 619.25, "word": " يعني", "probability": 0.801025390625}, {"start": 619.25, "end": 619.71, "word": " بيمكنه", "probability": 0.61505126953125}, {"start": 619.71, "end": 619.85, "word": " يظل", "probability": 0.9388020833333334}, {"start": 619.85, "end": 620.35, "word": " يستمر", "probability": 0.9939778645833334}, {"start": 620.35, "end": 621.39, "word": " بالحركة", "probability": 0.9664306640625}, {"start": 621.39, "end": 622.03, "word": " بخط", "probability": 0.8859049479166666}, {"start": 622.03, "end": 622.57, "word": " مستقيم", "probability": 0.9530029296875}, {"start": 622.57, "end": 622.67, "word": " و", "probability": 0.89404296875}, {"start": 622.67, "end": 622.75, "word": " with", "probability": 0.08819580078125}, {"start": 622.75, "end": 623.03, "word": " constant", "probability": 0.88232421875}, {"start": 623.03, "end": 623.51, "word": " speed", "probability": 0.9267578125}, {"start": 623.51, "end": 624.39, "word": " Newton's", "probability": 0.551513671875}, {"start": 624.39, "end": 624.65, "word": " second", "probability": 0.787109375}, {"start": 624.65, "end": 624.95, "word": " law", "probability": 0.921875}, {"start": 624.95, "end": 625.31, "word": " قانون", "probability": 0.9454752604166666}, {"start": 625.31, "end": 625.53, "word": " نيوتن", "probability": 0.906494140625}, {"start": 625.53, "end": 626.01, "word": " التاني", "probability": 0.8181966145833334}, {"start": 626.01, "end": 626.53, "word": " answer", "probability": 0.88330078125}, {"start": 626.53, "end": 626.77, "word": " the", "probability": 0.89697265625}, {"start": 626.77, "end": 627.11, "word": " question", "probability": 0.9365234375}, {"start": 627.11, "end": 627.33, "word": " of", "probability": 0.958984375}, {"start": 627.33, "end": 627.57, "word": " what", "probability": 0.95703125}, {"start": 627.57, "end": 627.95, "word": " happened", "probability": 0.7255859375}], "temperature": 1.0}, {"id": 28, "seek": 65308, "start": 628.56, "end": 653.08, "text": "to an object that does have a net force acting on it بيحكي لنا قانون يوتر التاني ماذا يحدث إذا أثرنا على الجسم بسرعة بقوة معينة طبعا و بنلاحظ من الأشكال هذه يعني شكل أربعة خمسة a و b we observe that the acceleration of an object is directly proportional to the net force acting on it", "tokens": [1353, 364, 2657, 300, 775, 362, 257, 2533, 3464, 6577, 322, 309, 4724, 1829, 5016, 4117, 1829, 5296, 8315, 12174, 7649, 11536, 7251, 35473, 2288, 16712, 7649, 1829, 3714, 45636, 995, 7251, 24401, 12984, 11933, 15730, 5551, 49115, 8315, 15844, 25724, 38251, 4724, 3794, 2288, 27884, 4724, 4587, 2407, 3660, 20449, 9957, 3660, 23032, 3555, 3615, 995, 4032, 44945, 15040, 5016, 19913, 9154, 16247, 8592, 4117, 6027, 29538, 37495, 22653, 13412, 28820, 5551, 25513, 27884, 16490, 2304, 3794, 3660, 257, 4032, 272, 321, 11441, 300, 264, 17162, 295, 364, 2657, 307, 3838, 24969, 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"word": " on", "probability": 0.947265625}, {"start": 632.54, "end": 632.82, "word": " it", "probability": 0.9736328125}, {"start": 632.82, "end": 633.46, "word": " بيحكي", "probability": 0.88603515625}, {"start": 633.46, "end": 633.64, "word": " لنا", "probability": 0.6634521484375}, {"start": 633.64, "end": 633.94, "word": " قانون", "probability": 0.9864908854166666}, {"start": 633.94, "end": 634.2, "word": " يوتر", "probability": 0.6693522135416666}, {"start": 634.2, "end": 634.58, "word": " التاني", "probability": 0.77978515625}, {"start": 634.58, "end": 634.82, "word": " ماذا", "probability": 0.9412434895833334}, {"start": 634.82, "end": 635.3, "word": " يحدث", "probability": 0.9698893229166666}, {"start": 635.3, "end": 635.74, "word": " إذا", "probability": 0.90625}, {"start": 635.74, "end": 636.24, "word": " أثرنا", "probability": 0.91015625}, {"start": 636.24, "end": 636.44, "word": " على", "probability": 0.88720703125}, {"start": 636.44, "end": 637.12, "word": " الجسم", "probability": 0.988037109375}, {"start": 637.12, "end": 638.84, "word": " بسرعة", "probability": 0.9744873046875}, {"start": 638.84, "end": 639.8, "word": " بقوة", "probability": 0.9439697265625}, {"start": 639.8, "end": 640.54, "word": " معينة", "probability": 0.990234375}, {"start": 640.54, "end": 641.88, "word": " طبعا", "probability": 0.9599609375}, {"start": 641.88, "end": 642.02, "word": " و", "probability": 0.4677734375}, {"start": 642.02, "end": 642.66, "word": " بنلاحظ", "probability": 0.90869140625}, {"start": 642.66, "end": 642.78, "word": " من", "probability": 0.99267578125}, {"start": 642.78, "end": 643.32, "word": " الأشكال", "probability": 0.987060546875}, {"start": 643.32, "end": 643.62, "word": " هذه", "probability": 0.391845703125}, {"start": 643.62, "end": 644.1, "word": " يعني", "probability": 0.60528564453125}, {"start": 644.1, "end": 644.48, "word": " شكل", "probability": 0.73779296875}, {"start": 644.48, "end": 645.0, "word": " أربعة", "probability": 0.6805013020833334}, {"start": 645.0, "end": 645.86, "word": " خمسة", "probability": 0.8897705078125}, {"start": 645.86, "end": 645.98, "word": " a", "probability": 0.460693359375}, {"start": 645.98, "end": 646.12, "word": " و", "probability": 0.93212890625}, {"start": 646.12, "end": 646.36, "word": " b", "probability": 0.50048828125}, {"start": 646.36, "end": 646.82, "word": " we", "probability": 0.80322265625}, {"start": 646.82, "end": 647.24, "word": " observe", "probability": 0.82568359375}, {"start": 647.24, "end": 647.48, "word": " that", "probability": 0.93896484375}, {"start": 647.48, "end": 647.62, "word": " the", "probability": 0.759765625}, {"start": 647.62, "end": 648.2, "word": " acceleration", "probability": 0.86865234375}, {"start": 648.2, "end": 648.72, "word": " of", "probability": 0.978515625}, {"start": 648.72, "end": 648.98, "word": " an", "probability": 0.76123046875}, {"start": 648.98, "end": 649.6, "word": " object", "probability": 0.98193359375}, {"start": 649.6, "end": 649.9, "word": " is", "probability": 0.96337890625}, {"start": 649.9, "end": 650.42, "word": " directly", "probability": 0.859375}, {"start": 650.42, "end": 650.98, "word": " proportional", "probability": 0.919921875}, {"start": 650.98, "end": 651.38, "word": " to", "probability": 0.98583984375}, {"start": 651.38, "end": 651.5, "word": " the", "probability": 0.91552734375}, {"start": 651.5, "end": 651.68, "word": " net", "probability": 0.947265625}, {"start": 651.68, "end": 652.06, "word": " force", "probability": 0.9755859375}, {"start": 652.06, "end": 652.5, "word": " acting", "probability": 0.9560546875}, {"start": 652.5, "end": 652.78, "word": " on", "probability": 0.95654296875}, {"start": 652.78, "end": 653.08, "word": " it", "probability": 0.96875}], "temperature": 1.0}, {"id": 29, "seek": 68045, "start": 653.63, "end": 680.45, "text": "التسارع بيتناسب تناسب ترضي مع القوة اللي أنا بعطيها للجسم والتسارع بيتناسب تناسب عكسي مع الكتلة we observe that the acceleration of an object is inversely proportional to the mass أنه التسارع بيتناسب تناسب ترضي مع القوة اللي أنا بعطيها للجسم زي ما هو موضح بالشكل أيضا الكتلة بتتناسب تناسب ترضي مع التسارع", "tokens": [6027, 2655, 3794, 9640, 3615, 4724, 36081, 8315, 35457, 6055, 8315, 35457, 6055, 43042, 1829, 20449, 25062, 2407, 3660, 13672, 1829, 41850, 4724, 3615, 9566, 1829, 11296, 24976, 7435, 38251, 16070, 2655, 3794, 9640, 3615, 4724, 36081, 8315, 35457, 6055, 8315, 35457, 6225, 4117, 3794, 1829, 20449, 33251, 2655, 37977, 321, 11441, 300, 264, 17162, 295, 364, 2657, 307, 21378, 736, 24969, 281, 264, 2758, 14739, 3224, 16712, 3794, 9640, 3615, 4724, 36081, 8315, 35457, 6055, 8315, 35457, 6055, 43042, 1829, 20449, 25062, 2407, 3660, 13672, 1829, 41850, 4724, 3615, 9566, 1829, 11296, 24976, 7435, 38251, 30767, 1829, 19446, 31439, 3714, 2407, 11242, 5016, 20666, 8592, 28820, 36632, 11242, 995, 33251, 2655, 37977, 39894, 2655, 8315, 35457, 6055, 8315, 35457, 6055, 43042, 1829, 20449, 16712, 3794, 9640, 3615], "avg_logprob": -0.11403827519379844, "compression_ratio": 2.292452830188679, "no_speech_prob": 0.00010257959365844727, "words": [{"start": 653.63, "end": 654.49, "word": "التسارع", "probability": 0.97138671875}, {"start": 654.49, "end": 655.07, "word": " بيتناسب", "probability": 0.8277587890625}, {"start": 655.07, "end": 655.53, "word": " تناسب", "probability": 0.9319661458333334}, {"start": 655.53, "end": 655.93, "word": " ترضي", "probability": 0.8465169270833334}, {"start": 655.93, "end": 656.07, "word": " مع", "probability": 0.9833984375}, {"start": 656.07, "end": 656.73, "word": " القوة", "probability": 0.9796549479166666}, {"start": 656.73, "end": 657.13, "word": " اللي", "probability": 0.709228515625}, {"start": 657.13, "end": 657.31, "word": " أنا", "probability": 0.5478515625}, {"start": 657.31, "end": 657.97, "word": " بعطيها", "probability": 0.8994140625}, {"start": 657.97, "end": 659.05, "word": " للجسم", "probability": 0.9222005208333334}, {"start": 659.05, "end": 660.03, 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0.927734375}, {"start": 880.43, "end": 880.65, "word": " no", "probability": 0.9560546875}, {"start": 880.65, "end": 880.89, "word": " net", "probability": 0.95556640625}, {"start": 880.89, "end": 881.33, "word": " force", "probability": 0.94287109375}, {"start": 881.33, "end": 881.51, "word": " on", "probability": 0.94921875}, {"start": 881.51, "end": 881.73, "word": " an", "probability": 0.943359375}, {"start": 881.73, "end": 882.29, "word": " object", "probability": 0.97900390625}, {"start": 882.29, "end": 882.57, "word": " لو", "probability": 0.93701171875}, {"start": 882.57, "end": 883.09, "word": " مافيه", "probability": 0.8186848958333334}, {"start": 883.09, "end": 883.59, "word": " قوة", "probability": 0.9441731770833334}, {"start": 883.59, "end": 884.27, "word": " يعني", "probability": 0.899169921875}, {"start": 884.27, "end": 884.95, "word": " محصلة", "probability": 0.8701171875}, {"start": 884.95, "end": 885.33, "word": " قوة", "probability": 0.9853515625}, {"start": 885.33, 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"probability": 0.9532877604166666}, {"start": 895.79, "end": 896.27, "word": " which", "probability": 0.96142578125}, {"start": 896.27, "end": 896.49, "word": " is", "probability": 0.94189453125}, {"start": 896.49, "end": 896.83, "word": " mean", "probability": 0.82958984375}, {"start": 896.83, "end": 897.21, "word": " معنى", "probability": 0.8660481770833334}, {"start": 897.21, "end": 897.45, "word": " هذا", "probability": 0.92822265625}, {"start": 897.45, "end": 897.83, "word": " أنه", "probability": 0.728759765625}, {"start": 897.83, "end": 898.47, "word": " التسائل", "probability": 0.869140625}, {"start": 898.47, "end": 899.29, "word": " السرعة", "probability": 0.80126953125}, {"start": 899.29, "end": 900.03, "word": " الاتجاهية", "probability": 0.881640625}, {"start": 900.03, "end": 900.29, "word": " هي", "probability": 0.859375}, {"start": 900.29, "end": 900.57, "word": " عبارة", "probability": 0.9937744140625}, {"start": 900.57, "end": 900.77, "word": " عن", "probability": 0.99658203125}, {"start": 900.77, "end": 901.31, "word": " ثابت", "probability": 0.9884440104166666}, {"start": 901.31, "end": 901.55, "word": " او", "probability": 0.62164306640625}, {"start": 901.55, "end": 901.75, "word": " اذا", "probability": 0.877197265625}, {"start": 901.75, "end": 902.25, "word": " حكالي", "probability": 0.83526611328125}, {"start": 902.25, "end": 902.59, "word": " انه", "probability": 0.81787109375}], "temperature": 1.0}, {"id": 40, "seek": 91187, "start": 902.91, "end": 911.87, "text": "السرعة الاتجاهية ثابتة معناه الكلام انه التسارع بيساوي zero وبالتالي summation لل F بيساوي zero", "tokens": [6027, 3794, 2288, 27884, 2423, 9307, 7435, 40294, 10632, 38637, 16758, 2655, 3660, 20449, 8315, 3224, 2423, 28820, 10943, 16472, 3224, 16712, 3794, 9640, 3615, 4724, 1829, 3794, 995, 45865, 4018, 46599, 6027, 2655, 6027, 1829, 28811, 24976, 479, 4724, 1829, 3794, 995, 45865, 4018], "avg_logprob": -0.20125679833733517, "compression_ratio": 1.373913043478261, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 902.91, "end": 903.39, "word": "السرعة", "probability": 0.833251953125}, {"start": 903.39, "end": 904.01, "word": " الاتجاهية", "probability": 0.9224609375}, {"start": 904.01, "end": 904.63, "word": " ثابتة", "probability": 0.9600830078125}, {"start": 904.63, "end": 905.25, "word": " معناه", "probability": 0.8175455729166666}, {"start": 905.25, "end": 905.69, "word": " الكلام", "probability": 0.789306640625}, {"start": 905.69, "end": 906.41, "word": " انه", "probability": 0.685791015625}, {"start": 906.41, "end": 907.59, "word": " التسارع", "probability": 0.8519287109375}, {"start": 907.59, "end": 908.49, "word": " بيساوي", "probability": 0.726416015625}, {"start": 908.49, "end": 908.99, "word": " zero", "probability": 0.3408203125}, {"start": 908.99, "end": 909.91, "word": " وبالتالي", "probability": 0.8833984375}, {"start": 909.91, "end": 910.35, "word": " summation", "probability": 0.81298828125}, {"start": 910.35, "end": 910.63, "word": " لل", "probability": 0.8076171875}, {"start": 910.63, "end": 910.85, "word": " F", "probability": 0.71240234375}, {"start": 910.85, "end": 911.43, "word": " بيساوي", "probability": 0.97841796875}, {"start": 911.43, "end": 911.87, "word": " zero", "probability": 0.74462890625}], "temperature": 1.0}, {"id": 41, "seek": 94119, "start": 914.17, "end": 941.19, "text": "بالنسبة ل ال units of force and mass نسبة لوحدة القوة و ال mass في النظام الدولي ال system international unit of force is the newton طبعا ال force وحدتها newton when واحد newton of the force act on an object that has mass of واحد كيلو it produce an acceleration of واحد متر في الثانية تربية in the object from this definition and newton's second law we see that", "tokens": [3555, 6027, 1863, 35457, 3660, 5296, 2423, 6815, 295, 3464, 293, 2758, 8717, 35457, 3660, 45164, 24401, 3660, 25062, 2407, 3660, 4032, 2423, 2758, 8978, 28239, 19913, 10943, 32748, 12610, 1829, 2423, 1185, 5058, 4985, 295, 3464, 307, 264, 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"probability": 0.939453125}, {"start": 930.33, "end": 930.61, "word": " mass", "probability": 0.83056640625}, {"start": 930.61, "end": 930.75, "word": " of", "probability": 0.93896484375}, {"start": 930.75, "end": 931.01, "word": " واحد", "probability": 0.899658203125}, {"start": 931.01, "end": 931.41, "word": " كيلو", "probability": 0.8720703125}, {"start": 931.41, "end": 931.99, "word": " it", "probability": 0.87451171875}, {"start": 931.99, "end": 932.43, "word": " produce", "probability": 0.6953125}, {"start": 932.43, "end": 932.69, "word": " an", "probability": 0.71435546875}, {"start": 932.69, "end": 933.31, "word": " acceleration", "probability": 0.85791015625}, {"start": 933.31, "end": 933.81, "word": " of", "probability": 0.951171875}, {"start": 933.81, "end": 935.09, "word": " واحد", "probability": 0.961669921875}, {"start": 935.09, "end": 935.83, "word": " متر", "probability": 0.96435546875}, {"start": 935.83, "end": 935.95, "word": " في", "probability": 0.8505859375}, {"start": 935.95, "end": 936.41, "word": " الثانية", "probability": 0.9290771484375}, {"start": 936.41, "end": 936.91, "word": " تربية", "probability": 0.6873372395833334}, {"start": 936.91, "end": 937.13, "word": " in", "probability": 0.90087890625}, {"start": 937.13, "end": 937.21, "word": " the", "probability": 0.91357421875}, {"start": 937.21, "end": 937.67, "word": " object", "probability": 0.97998046875}, {"start": 937.67, "end": 938.35, "word": " from", "probability": 0.89697265625}, {"start": 938.35, "end": 938.61, "word": " this", "probability": 0.9619140625}, {"start": 938.61, "end": 939.15, "word": " definition", "probability": 0.9296875}, {"start": 939.15, "end": 939.51, "word": " and", "probability": 0.8642578125}, {"start": 939.51, "end": 940.01, "word": " newton's", "probability": 0.677490234375}, {"start": 940.01, "end": 940.21, "word": " second", "probability": 0.86083984375}, {"start": 940.21, "end": 940.49, "word": " law", "probability": 0.9365234375}, {"start": 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"probability": 0.8291015625}, {"start": 1170.29, "end": 1170.71, "word": " العلاقة", "probability": 0.91845703125}, {"start": 1170.71, "end": 1170.99, "word": " بين", "probability": 0.94970703125}, {"start": 1170.99, "end": 1171.19, "word": " ال", "probability": 0.79150390625}, {"start": 1171.19, "end": 1171.71, "word": " summation", "probability": 0.62109375}, {"start": 1171.71, "end": 1172.01, "word": " لل", "probability": 0.431640625}, {"start": 1172.01, "end": 1172.19, "word": " F", "probability": 0.6982421875}, {"start": 1172.19, "end": 1172.35, "word": " ده", "probability": 0.911865234375}, {"start": 1172.35, "end": 1172.87, "word": " تساوي", "probability": 0.963134765625}, {"start": 1172.87, "end": 1173.43, "word": " ال", "probability": 0.97900390625}, {"start": 1173.43, "end": 1173.85, "word": " mass", "probability": 0.86767578125}, {"start": 1173.85, "end": 1174.25, "word": " في", "probability": 0.83056640625}, {"start": 1174.25, "end": 1174.35, "word": " ال", "probability": 0.96337890625}, {"start": 1174.35, "end": 1174.99, "word": " acceleration", "probability": 0.90185546875}, {"start": 1174.99, "end": 1176.31, "word": " نستكمل", "probability": 0.9019775390625}, {"start": 1176.31, "end": 1177.09, "word": " في", "probability": 0.97314453125}, {"start": 1177.09, "end": 1177.75, "word": " المحاضرة", "probability": 0.985595703125}, {"start": 1177.75, "end": 1178.37, "word": " القادمة", "probability": 0.9933268229166666}, {"start": 1178.37, "end": 1179.01, "word": " بعض", "probability": 0.9697265625}, {"start": 1179.01, "end": 1179.91, "word": " الأسئلة", "probability": 0.9444580078125}, {"start": 1179.91, "end": 1180.73, "word": " اللي", "probability": 0.977294921875}, {"start": 1180.73, "end": 1180.85, "word": " هي", "probability": 0.90283203125}, {"start": 1180.85, "end": 1181.41, "word": " الخاصة", "probability": 0.9599609375}, {"start": 1181.41, "end": 1181.97, "word": " بيه", "probability": 0.8310546875}, {"start": 1181.97, "end": 1182.41, "word": " اللي", "probability": 0.984375}, {"start": 1182.41, "end": 1182.63, "word": " هي", "probability": 0.85107421875}, {"start": 1182.63, "end": 1183.07, "word": " Newton", "probability": 0.5732421875}, {"start": 1183.07, "end": 1183.37, "word": " قانون", "probability": 0.8972981770833334}, {"start": 1183.37, "end": 1183.53, "word": " نيوتن", "probability": 0.69580078125}, {"start": 1183.53, "end": 1183.87, "word": " الأول", "probability": 0.953369140625}, {"start": 1183.87, "end": 1184.21, "word": " قانون", "probability": 0.8372395833333334}, {"start": 1184.21, "end": 1184.65, "word": " نيوتن", "probability": 0.9910888671875}, {"start": 1184.65, "end": 1185.21, "word": " التاني", "probability": 0.8636067708333334}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1185.471625, "duration_after_vad": 1157.6340937499997}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..1047b4da3ad6e57bbe5b54107cbb195530d59769
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/GXE1JWixNA8_raw.srt
@@ -0,0 +1,1068 @@
+1
+00:00:00,000 --> 00:00:04,700
+بسم الله الرحمن الرحيم بنستكمل مساق فيزياء عامة
+
+2
+00:00:04,700 --> 00:00:08,420
+لطلبة العلم الصحية بنبدأ ب chapter 4 بعنوان
+
+3
+00:00:08,420 --> 00:00:14,600
+Newton's laws of motion قوانين نيوتن للحركة هنعرف
+
+4
+00:00:14,600 --> 00:00:18,860
+section 4-1 اللي هي ال forces القوة هنعرف القوة
+
+5
+00:00:18,860 --> 00:00:23,700
+بداية القوة is commonly imagined as push or pull
+
+6
+00:00:23,700 --> 00:00:29,560
+أي جسم ممكن أنا أدفعه أو أسحبهممكن أنا بأثر عليه
+
+7
+00:00:29,560 --> 00:00:33,060
+بقوة it is a vector quantity ال force عبارة عن
+
+8
+00:00:33,060 --> 00:00:36,420
+كمية متجهة just like velocity and acceleration
+
+9
+00:00:36,420 --> 00:00:43,090
+تشبه السرعة الاتجاهية والتسارع ال type of forceال
+
+10
+00:00:43,090 --> 00:00:46,910
+type of forces في عندي أنا نوعين من القوة الأولى
+
+11
+00:00:46,910 --> 00:00:51,550
+اسمها contact force contact force دا قوة التلامس
+
+12
+00:00:51,550 --> 00:00:54,910
+they result from physical contact between two
+
+13
+00:00:54,910 --> 00:00:58,890
+objects as in figures ال figure طبعا أربعة اتنين
+
+14
+00:00:58,890 --> 00:01:02,190
+اللي هي ال contact force هي عبارة عن قوة التلامس
+
+15
+00:01:02,190 --> 00:01:09,150
+بين جسمينof two objects بين جسمين frictional force
+
+16
+00:01:09,150 --> 00:01:11,990
+ال contact force ممكن تكون زي ال frictional force
+
+17
+00:01:11,990 --> 00:01:15,970
+كمثال قوة الاحتكاك ال tension force قوة الشد ال
+
+18
+00:01:15,970 --> 00:01:19,290
+normal force قوة اللي هي رد الفعل عمودية وال air
+
+19
+00:01:19,290 --> 00:01:23,010
+resistance of force and spring force are examples
+
+20
+00:01:23,010 --> 00:01:27,460
+of contact force يعنيكأمثلة على قوة التلامس قوة
+
+21
+00:01:27,460 --> 00:01:31,400
+الاحتكاك ال tension اللي هو الشد ال normal force
+
+22
+00:01:31,400 --> 00:01:35,640
+قوة رد الفعل العمودية وال air resistance force قوة
+
+23
+00:01:35,640 --> 00:01:39,760
+مقاومة الهواء و قوة اللي هو النابض أو ال spring
+
+24
+00:01:39,760 --> 00:01:43,400
+كهيولة كلها أمثلة على ال contact force النوع
+
+25
+00:01:43,400 --> 00:01:46,340
+التاني من ال contact من القوة هي اسمها field
+
+26
+00:01:46,340 --> 00:01:51,030
+forcesال field force دي doesn't involve any direct
+
+27
+00:01:51,030 --> 00:01:54,890
+physical contact between object طبعا مافيش تلامس
+
+28
+00:01:54,890 --> 00:01:59,550
+بينها وبين الأجسام زي ال gravitational force قوة
+
+29
+00:01:59,550 --> 00:02:02,490
+الجاذبية أو بعدين electrical force قوة الكهربية
+
+30
+00:02:02,490 --> 00:02:06,250
+and magnetic force قوة المغناطسية هدولة برضه أمثلة
+
+31
+00:02:06,250 --> 00:02:10,940
+على ال field forceيعني مافي contact مافي تلامس هي
+
+32
+00:02:10,940 --> 00:02:15,940
+هذا الشكل ب .. ب .. الأشكال هذه طبعا شكل A و B و C
+
+33
+00:02:15,940 --> 00:02:20,540
+ب .. بيمثل ليه؟ اللي هي بالنسبة ل ال contact force
+
+34
+00:02:20,540 --> 00:02:24,140
+اللي هي قوة الزنبارك contact force لما أشد أنا
+
+35
+00:02:24,140 --> 00:02:28,060
+عربة برضه contact force لما أضرب كرة لمستها
+
+36
+00:02:28,060 --> 00:02:33,060
+contact force لكن ال field force قوة بين جسمين أو
+
+37
+00:02:33,060 --> 00:02:39,940
+particle قوة بين مثلا جسم صغير مع جسم صغيرفي عندى
+
+38
+00:02:39,940 --> 00:02:44,600
+قوة او قوة بين شحنتين طبعا فى قوة مجال كهربي هنا
+
+39
+00:02:44,600 --> 00:02:48,040
+ممكن مجال مغناطيس اللى هى اللى هى ال iron قطعة من
+
+40
+00:02:48,040 --> 00:02:52,400
+الحديد و قربت لها مغناطيس بيكون عندنا قوة تجاذب
+
+41
+00:02:52,400 --> 00:02:57,000
+فهذه بيسموها ال field force لا يشترط التلامس فيها
+
+42
+00:02:57,000 --> 00:03:02,560
+لا يشترط التلامس فيها اذا اللى هى فى عندنا قوتين
+
+43
+00:03:02,560 --> 00:03:08,540
+ال contact force و ال field force section 4-2The
+
+44
+00:03:08,540 --> 00:03:14,880
+laws of motion قوانين اللي هي الحركة أسحاق نيوتن
+
+45
+00:03:14,880 --> 00:03:18,580
+propose three laws of motion طبعا قوانين الحركة
+
+46
+00:03:18,580 --> 00:03:25,200
+اللي هي اللي طبعا اكتشفها هو أسحاق نيوتنto offer a
+
+47
+00:03:25,200 --> 00:03:29,320
+systematic method of calculating an object motion
+
+48
+00:03:29,320 --> 00:03:31,300
+due to the forces exerted on it
+
+49
+00:03:53,970 --> 00:03:59,390
+و يظل أيضا الجسم متحرك ما لم تؤثر عليه قوة من
+
+50
+00:03:59,390 --> 00:04:02,970
+حالته تغير من حالته طبعا بالنسبة لقانونه الأول
+
+51
+00:04:02,970 --> 00:04:06,710
+consider .. consider a book lying on a table لو
+
+52
+00:04:06,710 --> 00:04:10,790
+عندي أنا كتاب، الكتاب موجود على الطاولة obviously
+
+53
+00:04:10,790 --> 00:04:15,880
+the book remain at rest if it .. if left aloneطبعا
+
+54
+00:04:15,880 --> 00:04:19,500
+الكتاب كمثال موجود على طاولة الكتاب هيظل موجود ما
+
+55
+00:04:19,500 --> 00:04:23,320
+لم تؤثر عليه أي قوة now imagining pushing the book
+
+56
+00:04:23,320 --> 00:04:27,580
+بدأ أتصور أنه أنا شديت الكتاب بقوة أفقية with
+
+57
+00:04:27,580 --> 00:04:32,280
+horizontal forces great enough to overcome the
+
+58
+00:04:32,280 --> 00:04:35,460
+force of friction between the book and the table
+
+59
+00:04:35,460 --> 00:04:40,320
+نفترض أنه أنا شديت هذا الكتاب بقوة أكبر من قوة
+
+60
+00:04:40,320 --> 00:04:44,730
+اللي هي التلامسأو الاحتكاك بين الكتاب وبين الجسم
+
+61
+00:04:44,730 --> 00:04:48,850
+أو الأرض وبالتالي فالكتاب سوف يتحرك Setting the
+
+62
+00:04:48,850 --> 00:04:53,490
+book in motion هيظل موجود الكتاب في الحركة because
+
+63
+00:04:53,490 --> 00:04:56,770
+the magnitude of the applied force exceed exceed
+
+64
+00:04:56,770 --> 00:04:59,630
+the magnitude of the friction force the book
+
+65
+00:04:59,630 --> 00:05:02,870
+accelerate طبعا إذا كانت القوة اللي أنا شدت فيها
+
+66
+00:05:02,870 --> 00:05:07,050
+الكتاب أكبر من قوة الاحتكاك فالكتاب طبعا هيمشي
+
+67
+00:05:07,050 --> 00:05:11,530
+يتسارعwhen the applied force is with the drone إذا
+
+68
+00:05:11,530 --> 00:05:15,290
+أنا رسمت القوة اللي أعطته إياها ال friction slow
+
+69
+00:05:15,290 --> 00:05:21,070
+the book to stop قوة الاحتكاك طبعا بتخلي الكتاب
+
+70
+00:05:21,070 --> 00:05:26,550
+طبعا حركته تقل شوية لإنه هي عبارة عن يعني قوته
+
+71
+00:05:26,550 --> 00:05:30,450
+يعني عكس اتجاه الحركةNow imagine the book is
+
+72
+00:05:30,450 --> 00:05:33,410
+moving on a horizontal frictionless surface الان
+
+73
+00:05:33,410 --> 00:05:37,750
+بده افرض في عندى انا كتاب محطوط على سطح أملس
+
+74
+00:05:37,750 --> 00:05:41,530
+frictionless surface it continue to move in a
+
+75
+00:05:41,530 --> 00:05:44,250
+straight line with constant velocity until it hits
+
+76
+00:05:44,250 --> 00:05:48,430
+a wall or some other obstruction طبعا لو كان
+
+77
+00:05:48,430 --> 00:05:52,760
+الكتاب هو أساسا بيمشي على سطح أملس هيضل يمشيب
+
+78
+00:05:52,760 --> 00:05:57,280
+constant velocity ما لم تؤثر عليه يؤثر عليه أي شيء
+
+79
+00:05:57,280 --> 00:06:02,040
+كما أنه ممكن يصطدم بحائط أو ممكن يصطدم بأي حاجة
+
+80
+00:06:02,040 --> 00:06:07,180
+الآن لو كان عندي أنا هاي الكتاب الكتاب بيتحرك
+
+81
+00:06:07,180 --> 00:06:12,720
+بسرعة معينة أنا شدته طبعا عكس العكس الحركة هذه قوة
+
+82
+00:06:12,720 --> 00:06:16,300
+احتكاك عكس الحركة لو كانت أنا شدته بقوة عكس الحركة
+
+83
+00:06:16,300 --> 00:06:19,460
+أكبر من قوة الاحتكاك هيمشي هيبقى اللي يمشي للكتاب
+
+84
+00:06:20,900 --> 00:06:24,540
+ما لم تأثر عليه قوة تغير من حالته وكذلك لو كان
+
+85
+00:06:24,540 --> 00:06:28,460
+الكتاب أساسا هو ماشي ومافي أي قوة وقفته هيظل ماشي
+
+86
+00:06:28,460 --> 00:06:32,080
+إذا هذا قانون نيوتن الأول ال net force no change
+
+87
+00:06:32,080 --> 00:06:34,820
+in the velocity القوة قانون نيوتن الأول بيحكي أنه
+
+88
+00:06:34,820 --> 00:06:38,240
+يظل الجسم ساكن ما لم تأثر عليه قوة تغير من حالته
+
+89
+00:06:38,240 --> 00:06:42,980
+ويظل الجسم متحرك ما لم تأثر عليه قوة تغير من حالته
+
+90
+00:06:44,370 --> 00:06:47,730
+قانون نيوتن الأول للحركة an object moves with
+
+91
+00:06:47,730 --> 00:06:50,370
+velocity that is constant in magnitude and
+
+92
+00:06:50,370 --> 00:06:53,730
+direction unless a non-zero net force acts on it
+
+93
+00:06:53,730 --> 00:06:57,790
+هذا بالإنقليش تعريف قانون نيوتن الأول بيحكي لنا
+
+94
+00:06:57,790 --> 00:07:03,030
+the net force on an object is defined as the
+
+95
+00:07:03,030 --> 00:07:06,750
+vector sum of all external force exerted on the
+
+96
+00:07:06,750 --> 00:07:11,710
+objectطبعا net force هي عبارة عن مجموعة للقوة
+
+97
+00:07:11,710 --> 00:07:16,550
+المؤثرة على الجسم، هي عبارة عن مجموعة للقوة جامعية
+
+98
+00:07:16,550 --> 00:07:23,230
+متجاهي لكل القوة الخارجية التي تؤثر على الجسمهنا
+
+99
+00:07:23,230 --> 00:07:26,930
+القانون نيوتن الأول انه on object move أي جسم
+
+100
+00:07:26,930 --> 00:07:32,090
+هيتحرك بسرعة معينة بسرعة constant magnitude and
+
+101
+00:07:32,090 --> 00:07:37,790
+direction بيضل الجسم يتحرك ما لم تؤثر عليه قوة غير
+
+102
+00:07:37,790 --> 00:07:42,150
+من حالتهمعنى الكلام أنه بنجيب احنا ال net force
+
+103
+00:07:42,150 --> 00:07:46,450
+المؤثرة على هذا الجسم the external forces come
+
+104
+00:07:46,450 --> 00:07:50,010
+from an object environment القوة الخارجية بتيجي من
+
+105
+00:07:50,010 --> 00:07:54,830
+من اللي هي اللي يعني الجو المحيط أو الظروف المحيطة
+
+106
+00:07:54,830 --> 00:07:58,730
+وليس من داخل الجسم بيسموها external force القوة
+
+107
+00:07:58,730 --> 00:08:03,750
+الخارجيةالتعريف ال mass and inertia ال inertia هي
+
+108
+00:08:03,750 --> 00:08:07,230
+الخصور الذاتي is the tendency of an object to
+
+109
+00:08:07,230 --> 00:08:11,310
+continue its motion in the absence of the force هي
+
+110
+00:08:11,310 --> 00:08:17,690
+يعني قدرة اللي هي ال اي جسم انه يستمر في حركته في
+
+111
+00:08:17,690 --> 00:08:21,890
+عدم وجود القوة المؤثرة and mass is the measure of
+
+112
+00:08:21,890 --> 00:08:25,090
+the object resistance to the change in its motion
+
+113
+00:08:25,090 --> 00:08:29,790
+due to the force اللي ال mass اللي هي الكتلةهي
+
+114
+00:08:29,790 --> 00:08:35,150
+عبارة عن مقياس لمقاومة الجسم لإنه يغير من حركته
+
+115
+00:08:35,150 --> 00:08:38,630
+بسبب هذه القوة This kind of mass is often called
+
+116
+00:08:38,630 --> 00:08:43,470
+inertia mass هذا النوع من ال mass يسمى ال inertial
+
+117
+00:08:43,470 --> 00:08:48,250
+mass أو كتلة القصور الذاتي because it's associated
+
+118
+00:08:48,250 --> 00:08:52,390
+with inertia ال mass مرتبطة بالقصور الذاتي يعني ال
+
+119
+00:08:52,390 --> 00:08:56,600
+mass is associated with inertiathe greater the
+
+120
+00:08:56,600 --> 00:08:59,440
+mass of the body the less it accelerates under the
+
+121
+00:08:59,440 --> 00:09:03,620
+action of the given applied force لو كانت الكتلة
+
+122
+00:09:03,620 --> 00:09:08,780
+كبيرة بالنسبة للجسم the less it طبعا الكتلة كبيرة
+
+123
+00:09:08,780 --> 00:09:14,920
+هتكون التسارع تبعه أقل إذا كانت القوة ثابتة under
+
+124
+00:09:14,920 --> 00:09:18,100
+the action of the given applied force يعني أنا
+
+125
+00:09:18,100 --> 00:09:22,100
+عندي قوة ثابتة إذا كانت السرعه الكتلة بتزيد
+
+126
+00:09:22,100 --> 00:09:27,820
+فالتسارع بقل هذه الكتلةthe unit of mass اللى هى ال
+
+127
+00:09:27,820 --> 00:09:31,680
+system international unit of mass is kilogram اللى
+
+128
+00:09:31,680 --> 00:09:37,280
+هى وحدة ال mass بالنظام الدولى ال kilogram ال mass
+
+129
+00:09:37,280 --> 00:09:41,760
+is scalar و ال mass هى عبارة عن كمية قياسية that
+
+130
+00:09:41,760 --> 00:09:47,380
+obey the rules of ordinary arithmetic نجلا القانون
+
+131
+00:09:47,380 --> 00:09:53,110
+نيوتن التانىقانون نيوتن التاني بيحكي لنا Newton's
+
+132
+00:09:53,110 --> 00:09:55,690
+first law explained what happened to an object
+
+133
+00:09:55,690 --> 00:09:59,310
+that has no net force acting on it القانون نيوتن
+
+134
+00:09:59,310 --> 00:10:05,750
+الأول كان بيشرح أنه that has no net force acting
+
+135
+00:10:05,750 --> 00:10:08,830
+on it the object either remain at rest or remain
+
+136
+00:10:08,830 --> 00:10:12,290
+continue moveقانون نيوتن الأول كان بيحكي أنه يظل
+
+137
+00:10:12,290 --> 00:10:15,710
+الجسم ساكن ما لم تؤثر عليه قوة غير من حالته و يظل
+
+138
+00:10:15,710 --> 00:10:19,250
+الجسم متحرك ما لم تؤثر عليه قوة غير من حالته يعني
+
+139
+00:10:19,250 --> 00:10:22,750
+بيمكنه يظل يستمر بالحركة بخط مستقيم و with
+
+140
+00:10:22,750 --> 00:10:25,530
+constant speed Newton's second law قانون نيوتن
+
+141
+00:10:25,530 --> 00:10:28,940
+التاني answer the question of what happenedto an
+
+142
+00:10:28,940 --> 00:10:32,820
+object that does have a net force acting on it
+
+143
+00:10:32,820 --> 00:10:36,240
+بيحكي لنا قانون يوتر التاني ماذا يحدث إذا أثرنا
+
+144
+00:10:36,240 --> 00:10:42,780
+على الجسم بسرعة بقوة معينة طبعا و بنلاحظ من
+
+145
+00:10:42,780 --> 00:10:47,240
+الأشكال هذه يعني شكل أربعة خمسة a و b we observe
+
+146
+00:10:47,240 --> 00:10:50,420
+that the acceleration of an object is directly
+
+147
+00:10:50,420 --> 00:10:54,490
+proportional to the net force acting on itالتسارع
+
+148
+00:10:54,490 --> 00:10:59,050
+بيتناسب تناسب ترضي مع القوة اللي أنا بعطيها للجسم
+
+149
+00:10:59,050 --> 00:11:03,010
+والتسارع بيتناسب تناسب عكسي مع الكتلة we observe
+
+150
+00:11:03,010 --> 00:11:05,910
+that the acceleration of an object is inversely
+
+151
+00:11:05,910 --> 00:11:10,390
+proportional to the mass أنه التسارع بيتناسب تناسب
+
+152
+00:11:10,390 --> 00:11:14,130
+ترضي مع القوة اللي أنا بعطيها للجسم زي ما هو موضح
+
+153
+00:11:14,130 --> 00:11:20,450
+بالشكل أيضا الكتلة بتتناسب تناسب ترضي مع التسارع
+
+154
+00:11:20,920 --> 00:11:27,350
+يعني هنا بالنسبة لشكل الأول اندي أنا جسم كتل تقامب
+
+155
+00:11:27,350 --> 00:11:32,570
+.. اعطيته قوة AF فهيتحرك ب .. ب .. ب .. يعني هيصير
+
+156
+00:11:32,570 --> 00:11:36,090
+عنده تسارع A لكن لو أنا كتلة و نفسي الكتلة اعطيته
+
+157
+00:11:36,090 --> 00:11:41,150
+قوة 2F هيتسارع بتسارع 2A معناه الكلام انه القوة
+
+158
+00:11:41,150 --> 00:11:46,790
+تتناسب تناسب ترضي مع التسارع و تتناسب تناسب عكسي
+
+159
+00:11:46,790 --> 00:11:51,550
+مع ال .. التسارع بتناسب تناسب عكسي مع ال massتسارع
+
+160
+00:11:51,550 --> 00:11:54,850
+بتناسب تناسب عكسي مع ال mask لو أنا القوة كانت
+
+161
+00:11:54,850 --> 00:11:59,490
+ثابتة في جسم أعطيته قوة F و أنا ب .. بشده بقوة F
+
+162
+00:11:59,490 --> 00:12:04,390
+بلاحظ أنه التسارع هيكون A لو أنا أعطيته ال .. ال
+
+163
+00:12:04,390 --> 00:12:07,810
+mask يعني صارت double يعني كترت هنا M و هنا M و
+
+164
+00:12:07,810 --> 00:12:12,150
+أنا شدت بنفس القوة بلاحظ أنه التسارع صار A طبعا نص
+
+165
+00:12:12,150 --> 00:12:17,910
+A A ع 2 لإنه التسارع و ال mask بتناسب و تناسب عكسي
+
+166
+00:12:17,910 --> 00:12:21,810
+و التسارع و القوة بتناسب و تناسب ترددهذا هو قانون
+
+167
+00:12:21,810 --> 00:12:28,270
+نيوتن التاني فمعنى
+
+168
+00:12:28,270 --> 00:12:33,730
+الكلام أنه قانون نيوتن التاني ينص على أن ال
+
+169
+00:12:33,730 --> 00:12:37,630
+acceleration a of an object is directly
+
+170
+00:12:37,630 --> 00:12:42,810
+proportional to the net force acting on it and
+
+171
+00:12:42,810 --> 00:12:46,670
+inversely proportional to its mass معنى الكلام أن
+
+172
+00:12:46,670 --> 00:12:53,070
+التسارع a بتناسب تناسبترضي مع القوة ويتناسب تناسب
+
+173
+00:12:53,070 --> 00:12:58,310
+عكس ما اللى اللى هي الكتلة معنى الكلام أنه التسارع
+
+174
+00:12:58,310 --> 00:13:02,190
+A بتساوي summation لل F على ال M ممكن أن ال F اللى
+
+175
+00:13:02,190 --> 00:13:05,830
+أنا بأثر عليه على الجسم ممكن تكون طبعا هو جمع
+
+176
+00:13:05,830 --> 00:13:09,890
+اتجاهي ممكن القوة اللى أنا بعطيها في قوة احتكاك في
+
+177
+00:13:09,890 --> 00:13:15,610
+قوة أخرى فالمجموعة القوة ال F ده تساوي ال M في AA
+
+178
+00:13:15,610 --> 00:13:18,230
+where A is the acceleration of the object و ال M
+
+179
+00:13:18,230 --> 00:13:21,590
+هي عبارة عن الماس اللي هي الكتلة و ال A summation
+
+180
+00:13:21,590 --> 00:13:26,070
+لل F is the vector sum هو المجموع اللي هي مجموع
+
+181
+00:13:26,070 --> 00:13:29,530
+الخواجم اتجاهي of all forces acting on it
+
+182
+00:13:29,530 --> 00:13:33,810
+Multiplying through by M, we observe لو أنا ضربت
+
+183
+00:13:33,810 --> 00:13:39,260
+الالطبعا القانون المُعطى ب M هيصير عندي summation
+
+184
+00:13:39,260 --> 00:13:42,880
+لل F تساوي ال M في A وهذا هو قانون ال Newton
+
+185
+00:13:42,880 --> 00:13:47,920
+التاني ال A عبارة عن vector و ال F vector و ال M
+
+186
+00:13:47,920 --> 00:13:51,880
+هي عبارة عن scalar ال A و ال M في بينهم تناسب ..
+
+187
+00:13:51,880 --> 00:13:57,960
+تتناسب تناسب هنا عكسي و ال F و ال A بتناسب تناسب
+
+188
+00:13:57,960 --> 00:13:58,460
+تاردي
+
+189
+00:14:04,250 --> 00:14:07,930
+The second law is a vector equation equivalent to
+
+190
+00:14:07,930 --> 00:14:11,250
+the following three components طبعا summation لل F
+
+191
+00:14:11,250 --> 00:14:15,410
+هذه ال F as a vector عبارة عن summation لل F بتجاه
+
+192
+00:14:15,410 --> 00:14:19,230
+ال X بالساوية M في A بتجاه ال X بال X axis ممكن
+
+193
+00:14:19,230 --> 00:14:23,690
+انا اعمل summation لل FY M في Ay summation لل FZ
+
+194
+00:14:23,690 --> 00:14:27,240
+بالساوية M في AZ لكن هذا القانون بصفة عامة انهالـ
+
+195
+00:14:27,240 --> 00:14:30,760
+Assumption ال F ك vector سوى ال M في A ك vector ال
+
+196
+00:14:30,760 --> 00:14:35,380
+A ممكن تكون A X A Y A Z وال F ممكن تكون F X F Y F
+
+197
+00:14:35,380 --> 00:14:35,660
+Z
+
+198
+00:14:39,810 --> 00:14:43,090
+when there is no net force on an object لو مافيه
+
+199
+00:14:43,090 --> 00:14:47,190
+قوة يعني محصلة قوة مؤثرة على الجسم its
+
+200
+00:14:47,190 --> 00:14:50,970
+acceleration is zero لو كانت عند صماش المجموعة
+
+201
+00:14:50,970 --> 00:14:54,310
+القوة المؤثرة على الجسم ساوة صفر معنى الكلام اللي
+
+202
+00:14:54,310 --> 00:14:57,830
+قابد هتساوي زفق صفر which is mean معنى هذا أنه
+
+203
+00:14:57,830 --> 00:15:01,750
+التسائل السرعة الاتجاهية هي عبارة عن ثابت او اذا
+
+204
+00:15:01,750 --> 00:15:06,410
+حكالي انهالسرعة الاتجاهية ثابتة معناه الكلام انه
+
+205
+00:15:06,410 --> 00:15:11,430
+التسارع بيساوي zero وبالتالي summation لل F بيساوي
+
+206
+00:15:11,430 --> 00:15:17,090
+zeroبالنسبة ل ال units of force and mass نسبة
+
+207
+00:15:17,090 --> 00:15:21,050
+لوحدة القوة و ال mass في النظام الدولي ال system
+
+208
+00:15:21,050 --> 00:15:24,710
+international unit of force is the newton طبعا ال
+
+209
+00:15:24,710 --> 00:15:28,450
+force وحدتها newton when واحد newton of the force
+
+210
+00:15:28,450 --> 00:15:31,990
+act on an object that has mass of واحد كيلو it
+
+211
+00:15:31,990 --> 00:15:36,410
+produce an acceleration of واحد متر في الثانية
+
+212
+00:15:36,410 --> 00:15:39,510
+تربية in the object from this definition and
+
+213
+00:15:39,510 --> 00:15:42,580
+newton's second law we see thatمعنى الكلام الواحد
+
+214
+00:15:42,580 --> 00:15:45,500
+نيوتن بيبقى تساوي واحد كيلو جرام مضروبة في متر في
+
+215
+00:15:45,500 --> 00:15:48,600
+الثانية تربيع يعني ال mass في ال acceleration وحدة
+
+216
+00:15:48,600 --> 00:15:52,140
+ال mass كيلو جرام وحدة التسارق متر في الثانية
+
+217
+00:15:52,140 --> 00:15:55,240
+تربيع إذا الواحد نيوتن بيبقى تساوي واحد كيلو جرام
+
+218
+00:15:55,240 --> 00:16:02,530
+مضروبة في متر في الثانية تربيعنشوف هذا ال quiz ال
+
+219
+00:16:02,530 --> 00:16:05,690
+quiz أربعة واحد which of the following statement
+
+220
+00:16:05,690 --> 00:16:09,730
+are true؟ مين من الجمال هذه صحيحة؟ مين من الجمال
+
+221
+00:16:09,730 --> 00:16:12,570
+هذه المعطاش صحيحة؟
+
+222
+00:16:19,730 --> 00:16:23,970
+الان an object can move even when no force acting
+
+223
+00:16:23,970 --> 00:16:30,830
+on it الجسم ممكن يتحرك when no force acts on it
+
+224
+00:16:30,830 --> 00:16:38,410
+ممكن الجسم يتحرك حتى لو مافي قوة عليهan object can
+
+225
+00:16:38,410 --> 00:16:42,190
+move even when no force acts against it طبعا هذا
+
+226
+00:16:42,190 --> 00:16:46,310
+صحيح لماذا؟ لأنه ممكن الجسم لما ما تكون قالي قوة
+
+227
+00:16:46,310 --> 00:16:50,610
+يعني معناته القوة بالساوء صفر إذا التسارق بالساوء
+
+228
+00:16:50,610 --> 00:16:54,050
+صفر لكنه بتحرك بسرعة منتظمة معناه الكلام أنه ممكن
+
+229
+00:16:54,050 --> 00:16:59,680
+يتحرك بسرعة منتظمة إذا كانهذا الجسم مجموع القوة
+
+230
+00:16:59,680 --> 00:17:03,120
+بيساوي zero فال a بيساوي zero فهو بتحرك بسرعة
+
+231
+00:17:03,120 --> 00:17:09,620
+إثابتة إذا ال a true ال a صحيحة نجي لل b if an
+
+232
+00:17:09,620 --> 00:17:13,480
+object isn't moving الجسم ما بتحرك no external
+
+233
+00:17:13,480 --> 00:17:18,500
+force act on itالجسم ما بتحرك معناته مافيش قوة
+
+234
+00:17:18,500 --> 00:17:22,240
+خارجية مؤثرة عليه خطأ لإنه ممكن يكون مجموع القوة
+
+235
+00:17:22,240 --> 00:17:26,220
+بتساوي zero يعني ممكن يكون في عندي قوة مؤثرة عليه
+
+236
+00:17:26,220 --> 00:17:31,150
+ومجموعة بتساوي zero هذا اللي في بيه خطأ نجلة Cif a
+
+237
+00:17:31,150 --> 00:17:35,550
+single force acts on an object لو عندي أنا قوة
+
+238
+00:17:35,550 --> 00:17:40,030
+لحالها مفردة single force acts on an object the
+
+239
+00:17:40,030 --> 00:17:43,770
+object accelerates اه ممكن ممكن انا اثر على الجسم
+
+240
+00:17:43,770 --> 00:17:48,810
+بقوة واحدة و يصير عنده تسارق ممكن في في في في
+
+241
+00:17:48,810 --> 00:17:55,290
+الحالة دي في الحالة دي if an object accelerates at
+
+242
+00:17:55,290 --> 00:18:00,340
+least one force is acting on itنعم ممكن أنه يصير
+
+243
+00:18:00,340 --> 00:18:05,020
+عندى تسارع لو كان عندى at least one force is
+
+244
+00:18:05,020 --> 00:18:09,300
+acting on it طيب يعني الممكن أن الجسم اتحرك لو
+
+245
+00:18:09,300 --> 00:18:15,940
+أثرنا عليه بقوة واحدة نمرأي if an object is
+
+246
+00:18:15,940 --> 00:18:20,200
+accelerate no external force is acting on it ممكن
+
+247
+00:18:20,200 --> 00:18:25,280
+هل ممكن أنه الجسم does not accelerateهل ان الجسم
+
+248
+00:18:25,280 --> 00:18:28,980
+does not accelerate او isn't accelerating, no
+
+249
+00:18:28,980 --> 00:18:33,640
+external force is acting on it خطأ في E هذه خطأ
+
+250
+00:18:33,640 --> 00:18:39,140
+لإنها ممكن يصير لها تعجيل هي if an object is not
+
+251
+00:18:39,140 --> 00:18:44,040
+accelerating, no external force is acting on it لأ
+
+252
+00:18:44,040 --> 00:18:48,540
+يعني هنا السؤال بيحكي لو أنا عندي جسم ما بتسارعما
+
+253
+00:18:48,540 --> 00:18:52,040
+بتسارع معناه الكلام انه no external force is
+
+254
+00:18:52,040 --> 00:18:55,640
+acting on it ممكن يكون عندي أنا قوة مؤثرة عليه
+
+255
+00:18:55,640 --> 00:18:58,640
+ولكن القوة summation لل force ال external force
+
+256
+00:18:58,640 --> 00:19:04,000
+بتساوي zero و بالتالي هو بتحرك بتسارع بسرعة منتظمة
+
+257
+00:19:04,000 --> 00:19:10,260
+و التسارع تبعه zero if the net force acting on the
+
+258
+00:19:10,260 --> 00:19:13,700
+object is in the positive x direction the object
+
+259
+00:19:13,700 --> 00:19:17,550
+move only in the positive x direction طبعا لأطب
+
+260
+00:19:17,550 --> 00:19:21,770
+ممكن يكون ال net force في اتجاه ال .. ال .. اللي
+
+261
+00:19:21,770 --> 00:19:25,830
+هي باتجاه ال .. ال negative ممكن يكون باتجاه
+
+262
+00:19:25,830 --> 00:19:28,910
+النجدة و بتاع اللي هي force هدول طبعا جمل يعني
+
+263
+00:19:28,910 --> 00:19:32,350
+بيحددلنا انه العلاقة بين ال summation لل F ده
+
+264
+00:19:32,350 --> 00:19:37,090
+تساوي ال mass في ال acceleration نستكمل في
+
+265
+00:19:37,090 --> 00:19:41,970
+المحاضرة القادمة بعض الأسئلة اللي هي الخاصة بيه
+
+266
+00:19:41,970 --> 00:19:44,650
+اللي هي Newton قانون نيوتن الأول قانون نيوتن
+
+267
+00:19:44,650 --> 00:19:45,210
+التاني
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY.srt
new file mode 100644
index 0000000000000000000000000000000000000000..aa280fea146893f4bef3942f524ff565697f415f
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY.srt
@@ -0,0 +1,1115 @@
+1
+00:00:01,090 --> 00:00:06,390
+بنستكمل طبعا ال chapter الخامس ب section one اللي
+
+2
+00:00:06,390 --> 00:00:11,290
+هو ال work.  الـ work always requires a system of more
+
+3
+00:00:11,290 --> 00:00:17,990
+than just one object.  في الـ, for example, مثال على
+
+4
+00:00:17,990 --> 00:00:22,170
+هذا الكلام، لو كان أنا بدي أدخل مصمار في الحائط.
+
+5
+00:00:22,170 --> 00:00:27,590
+المصمار لحاله can't do work on itself، طبعا لحاله.
+
+6
+00:00:27,590 --> 00:00:34,870
+مش هيعمل شغل، لكن الـشاكوش أو المطرقة can do work on
+
+7
+00:00:34,870 --> 00:00:38,310
+the nail by driving it into the board. طبعا لما
+
+8
+00:00:38,310 --> 00:00:41,070
+بدخل أنا مصمار في الحائط أو في الخزانة أو كده، بضطر
+
+9
+00:00:41,070 --> 00:00:44,230
+أضغط عليها وأضرب فيها، يعني أنا بَعطِيها قوة.
+
+10
+00:00:44,620 --> 00:00:49,180
+وبالتالي، هو هيمشي إزاحة معينة، مجموعة القوة،
+
+11
+00:00:49,180 --> 00:00:52,900
+ومجموعة الإزاحات هيعطيني الشغل الكلي. In general, an
+
+12
+00:00:52,900 --> 00:00:55,400
+object may be moving under the influence of
+
+13
+00:00:55,400 --> 00:00:59,380
+several external forces. ممكن أن الجسم يتحرك تحت
+
+14
+00:00:59,380 --> 00:01:05,020
+تأثير مجموعة من القوى. In that case, the net work في
+
+15
+00:01:05,020 --> 00:01:09,360
+الشغل الكلي في هذه الحالة، اللي يبذل من خلال هذا
+
+16
+00:01:09,360 --> 00:01:15,550
+الجسم تحت تأثير طبعا إزاحة معينة، يعتبر عبارة عن
+
+17
+00:01:15,550 --> 00:01:23,210
+مجموع الشغل التي طبعا يحدث  بِـيُـؤَثر وسط كل قوة.
+
+18
+00:01:23,210 --> 00:01:29,050
+الـ work. ممكن الشغل يكون موجب أو سالب. الـ work can
+
+19
+00:01:29,050 --> 00:01:33,910
+be either positive or negative in the definition
+
+20
+00:01:33,910 --> 00:01:38,050
+of the work. الـ F و الـ D are magnitudes which are
+
+21
+00:01:38,050 --> 00:01:42,260
+never negative. فالـ work is therefore positive or
+
+22
+00:01:42,260 --> 00:01:46,620
+negative depending on whether cos θ is positive or
+
+23
+00:01:46,620 --> 00:01:52,280
+negative. طبعا إحنا بنحدد أن هذا الشغل موجب أو سالب
+
+24
+00:01:52,280 --> 00:01:57,820
+أو zero حسب الزاوية. إذا كانت الزاوية zero، فالشغل
+
+25
+00:01:57,820 --> 00:02:02,200
+موجب. إذا كانت الزاوية 180 درجة، فالشغل
+
+26
+00:02:02,200 --> 00:02:07,380
+سالب. إذا كانت الزاوية 90، فالشغل zero. when these
+
+27
+00:02:07,380 --> 00:02:10,500
+vectors are pointing in the same direction, the
+
+28
+00:02:10,500 --> 00:02:15,000
+angle between them is zero.  So cos الـ zero واحد، زي
+
+29
+00:02:15,000 --> 00:02:19,980
+ما حكينا، فالشغل في هذه الحالة موجب. for example, when
+
+30
+00:02:19,980 --> 00:02:27,120
+a student lifts a box. يعني لو شخص طبعا حمل box أو
+
+31
+00:02:27,120 --> 00:02:31,380
+صندوق، the work he does on the box is positive
+
+32
+00:02:31,380 --> 00:02:34,780
+because the force he exerted on the box is upward
+
+33
+00:02:35,480 --> 00:02:38,740
+in the same direction as displacement. لو شخص أو
+
+34
+00:02:38,740 --> 00:02:43,100
+طالب حمل books من الأرض إلى أعلى، فبتكون القوة إلى
+
+35
+00:02:43,100 --> 00:02:46,380
+أعلى والإزاحة إلى أعلى، فالشغل موجب في هذه الحالة.
+
+36
+00:02:46,380 --> 00:02:51,040
+لأنه الإزاحة والقوة في نفس الاتجاه، في الزاوية بينهم
+
+37
+00:02:51,040 --> 00:02:55,780
+zero، فالشغل في هذه الحالة موجب. the student still
+
+38
+00:02:55,780 --> 00:02:59,100
+exerts an upward force on the books, but the motion
+
+39
+00:02:59,100 --> 00:03:03,310
+of the books is downwards. Because the vector F and
+
+40
+00:03:03,310 --> 00:03:09,610
+ΔX are now in opposite directions. لو كان أنا طبعا القوة لتحت
+
+41
+00:03:09,610 --> 00:03:15,070
+Mg، وإزاحة إلى أعلى، فبتكون الزاوية بين الإزاحة و
+
+42
+00:03:15,070 --> 00:03:19,190
+القوة 180 درجة، فـ cos 180 هو ناقص، فدي الحالة الشغل
+
+43
+00:03:19,190 --> 00:03:23,470
+سالب. طبعا، هي الشغل زي ما موضح. إذا أنا رفعت الجسم
+
+44
+00:03:23,470 --> 00:03:28,730
+إلى أعلى بقوة F، فبتكون F و ΔX على نفس الاتجاه،
+
+45
+00:03:28,730 --> 00:03:32,590
+فالزاوية بينهم zero، فده الشغل موجب. لو كانت أنا بدأت
+
+46
+00:03:32,590 --> 00:03:36,710
+أطبق أنه عندي أنا، يعني هو الجاذبية لأسفل والإزاحة
+
+47
+00:03:36,710 --> 00:03:39,250
+لأعلى، فالشغل الناتج عن الجاذبية في هذه الحالة
+
+48
+00:03:39,250 --> 00:03:43,850
+سالب. وبالتالي، طبعا هي الزاوية اللي بتحدد إذا كان
+
+49
+00:03:43,850 --> 00:03:49,910
+الشغل موجب أو سالب. في هذا الـ quiz، في عندي أنا أكتر
+
+50
+00:03:49,910 --> 00:03:53,710
+من شكل. الـ block moves to the right in the positive
+
+51
+00:03:53,710 --> 00:03:57,730
+x direction through the displacement delta x, while
+
+52
+00:03:57,730 --> 00:04:00,110
+under the influence of the force with the same
+
+53
+00:04:00,110 --> 00:04:05,800
+magnitude. الآن عندي أنا يعني جسم بيتحرك تحت تأثير
+
+54
+00:04:05,800 --> 00:04:10,700
+قوة.  الـسؤال: which of the following is
+
+55
+00:04:10,700 --> 00:04:13,280
+the correct answer of the amount of the work done
+
+56
+00:04:13,280 --> 00:04:17,300
+by the force F, from most positive to the most
+
+57
+00:04:17,300 --> 00:04:23,400
+negative. يعني بدي أرتب هذه الأشكال من الشغل من
+
+58
+00:04:23,400 --> 00:04:29,200
+الموجب إلى السالب. طبعا عندي أنا A، يعني هل
+
+59
+00:04:29,200 --> 00:04:34,420
+هو D الموجب، بعدين C، بعدين A، بعدين B؟ أو هو C، A، B، D؟
+
+60
+00:04:34,420 --> 00:04:38,460
+أو هو C، A، D، B؟ طبعا عندي أنا أربعة أشكال، الشكل الأول
+
+61
+00:04:38,460 --> 00:04:42,840
+A, B, C, D. طبعا بدي أروح لكل شكل وأشوف مين الشغل
+
+62
+00:04:42,840 --> 00:04:47,680
+الموجب وأتدرج من الموجب إلى السالب. بلاحظ أن هنا
+
+63
+00:04:47,680 --> 00:04:51,580
+الزاوية 90، فالشغل هذا zero. هنا الزاوية 180، فالشغل
+
+64
+00:04:51,580 --> 00:04:56,480
+هذا سالب. هنا الزاوية طبعا منفرجة، فـ cosine الزاوية
+
+65
+00:04:56,480 --> 00:05:00,840
+المنفرجة، هنا الزاوية طبعا zero، و cos الـ zero
+
+66
+00:05:00,840 --> 00:05:07,300
+بيساوي واحد، فبيطلع عندي هنا الـ C هي الموجب. بعدين، بعد
+
+67
+00:05:07,300 --> 00:05:11,480
+الموجب بيجيني اللي هو zero، كأنه يعني خط أعداد: موجب،
+
+68
+00:05:11,480 --> 00:05:18,640
+zero، بعدين سالب، بعدين طبعا اللي هي بعدين هاي، بعدين
+
+69
+00:05:18,640 --> 00:05:23,720
+هاي. يعني هاي الحالة.  أرتب الـ C، هاي هي أول واحدة اللي
+
+70
+00:05:23,720 --> 00:05:30,940
+هي قيمتها موجب، C. بعدين A اللي هي zero، بعدين طبعا
+
+71
+00:05:30,940 --> 00:05:33,960
+قبل ما توصل إلى السالب، واحد هيكون هي سالب، بس قبل ما
+
+72
+00:05:33,960 --> 00:05:38,810
+توصل لسالب واحد، اللي هي D، بعدين B. فالترتيب هذه
+
+73
+00:05:38,810 --> 00:05:43,450
+الأربعة أشكال هيترتبوا زي اللي هو الموجود فيه
+
+74
+00:05:43,450 --> 00:05:48,970
+الخيار C. هيكون عندي C هي موجبة، هيكون عندي A هذه
+
+75
+00:05:48,970 --> 00:05:53,610
+zero، بعدين اللي هي هذه D اللي هي يعني لسة ما وصلت
+
+76
+00:05:53,610 --> 00:05:58,130
+إلى إنها تكون الزاوية 180 درجة، فبيكون عندي C A D B.
+
+77
+00:05:58,130 --> 00:06:01,630
+هذا هو الترتيب، from positive to the most negative.
+
+78
+00:06:01,630 --> 00:06:06,740
+هذا هو الترتيب الصحيح، فالـ answer عندي C. ناخد سؤال
+
+79
+00:06:06,740 --> 00:06:11,740
+problems example خمسة واحد. في عندي a man returning
+
+80
+00:06:11,740 --> 00:06:15,960
+from a successful ice fishing trip pulls a sled
+
+81
+00:06:15,960 --> 00:06:21,120
+loaded with salmon. the total mass of the sled and
+
+82
+00:06:21,120 --> 00:06:25,380
+salmon is خمسين كيلو جرام، and the man exerts a
+
+83
+00:06:25,380 --> 00:06:30,980
+force of magnitude الرجل بياثر بقوة 120 نيوتن
+
+84
+00:06:30,980 --> 00:06:35,220
+on the sled by pulling on
+
+85
+00:06:35,220 --> 00:06:39,330
+the rope. How much work does the... what does he do
+
+86
+00:06:39,330 --> 00:06:42,970
+on the sled if the rope is horizontal to the
+
+87
+00:06:42,970 --> 00:06:49,870
+ground؟ طبعا في عندي أنا رجل، الرجل هذا زي ما إحنا
+
+88
+00:06:49,870 --> 00:06:57,270
+شايفين، بده يسحب مثلا سمكة من على، يعني عربة تزلج
+
+89
+00:06:57,270 --> 00:07:04,070
+على الجليد. طبعا، سحبها بقوة F، مائلة بزاوية θ، وهذا
+
+90
+00:07:04,070 --> 00:07:08,800
+في عندي أنا قوة احتكاك. طبعا، لما دي في عندي قوة
+
+91
+00:07:08,800 --> 00:07:11,980
+احتكاك، في عندي قوة مؤثرة على هذه العربة، في عندي
+
+92
+00:07:11,980 --> 00:07:17,920
+normal، وفي عندي mg. السؤال طالب بالبداية، السؤال إيه؟
+
+93
+00:07:17,920 --> 00:07:23,960
+حكى لي: how much work does he do on the sled if the
+
+94
+00:07:23,960 --> 00:07:27,320
+rope is horizontal to the ground؟ مطلوب مني أوجد
+
+95
+00:07:27,320 --> 00:07:31,540
+الشغل، إذا كان الحبل اللي بيشد في هذه العربة
+
+96
+00:07:31,540 --> 00:07:34,620
+horizontal. الحبل اللي بيشد هذه العربة horizontal،
+
+97
+00:07:34,620 --> 00:07:39,070
+معناته θ بيساوي zero، and he pulls the sled خمسة متر.
+
+98
+00:07:39,070 --> 00:07:44,290
+وهو سحبها مقدار خمسة متر. نجي لحل الأولاني، طبعا
+
+99
+00:07:44,290 --> 00:07:48,510
+بتعتبر هذا horizontal، ففي الزاوية، ففي عندي أنا
+
+100
+00:07:48,510 --> 00:07:52,250
+الشغل الناتج. find the work done when the force is
+
+101
+00:07:52,250 --> 00:07:56,630
+horizontal. علشان أجيبها، بقول بحكي أن الشغل بتساوي
+
+102
+00:07:56,630 --> 00:08:00,710
+الـ F باتجاه الـ X في Delta X. فإحنا أعطينا هو F 120،
+
+103
+00:08:00,710 --> 00:08:03,550
+و Delta X اللي هي
+
+104
+00:08:03,550 --> 00:08:08,030
+المسافة أو الإزاحة اللي مشيها، بتطلع عندي 6 × 10² جول.
+
+105
+00:08:08,030 --> 00:08:12,850
+هذا الكلام إذا كانت القوة موازية للسطح، والزاوية
+
+106
+00:08:12,850 --> 00:08:19,610
+zero. بعد هيك، طالب مني إيجاد الشغل لما أنا أسحبه
+
+107
+00:08:19,610 --> 00:08:23,930
+بقوة F وميلة على الـ horizontal بزاوية الثلاثين.
+
+108
+00:08:23,930 --> 00:08:28,670
+طبعا هنطبق نفس القانون، لكن هيكون عندي أنا الشغل دي
+
+109
+00:08:28,670 --> 00:08:35,940
+بيساوي F cos θ في D. هندخل cos θ، الـ F نفسه 1.2 × 10²، و
+
+110
+00:08:35,940 --> 00:08:39,720
+الـ θ كوزين الثلاثين، والمسافة D خمسة، بيطلع عندي
+
+111
+00:08:39,720 --> 00:08:44,900
+5.2 × 10² جول. في C، طالب
+
+112
+00:08:44,900 --> 00:08:49,840
+how much work done، بده الشغل الناتج عن قوة
+
+113
+00:08:49,840 --> 00:08:53,300
+الاحتكاك، إذا كانت في عندي أنا قوة الاحتكاك طبعا
+
+114
+00:08:53,300 --> 00:08:57,940
+عكس الحركة، بيساوي 45 نيوتن. طبعا بدي أوجد
+
+115
+00:08:57,940 --> 00:09:04,080
+أنا هو ماشي مسافة 12.4، يعني ماشي أنا، الاحتكاك من
+
+116
+00:09:04,080 --> 00:09:10,660
+مسافة 12.4 متر إلى 18.2. طبعا، طالما إنه أعطاني X
+
+117
+00:09:10,660 --> 00:09:14,340
+initial و X final، هجيب Delta X. إذا، هجيب الشغل
+
+118
+00:09:14,340 --> 00:09:19,440
+الناتج عن الاحتكاك، نسميه W friction، بتساوي Fx في
+
+119
+00:09:19,440 --> 00:09:26,270
+Delta X. الـ Fx في Delta X، Fk في Delta X. طبعا الـ F
+
+120
+00:09:26,270 --> 00:09:29,950
+هي 45 نيوتن، الاحتكاك. الشغل الناتج عن الاحتكاك
+
+121
+00:09:29,950 --> 00:09:35,330
+سالب، لإنه الإزاحة عكس القوة. وبالتالي، الـ Fk بيساوي
+
+122
+00:09:35,330 --> 00:09:40,750
+ناقص 45 مضروبة في Delta X. X final ناقص X initial، الـ
+
+123
+00:09:40,750 --> 00:09:46,630
+final كان 18.2، و الـ initial 12.4. ممكن نحسب الشغل
+
+124
+00:09:46,630 --> 00:09:50,740
+الناتج عن الاحتكاك، اللي هي FK ناقص 45 في
+
+125
+00:09:50,740 --> 00:09:54,220
+Delta X، بيطلع ناقص 260 جول. طبعا، هي كإحنا حددنا الشغل الناتج عن
+
+126
+00:09:54,220 --> 00:09:59,340
+القوة إذا كانت أفقية، الشغل الناتج عن القوة إذا
+
+127
+00:09:59,340 --> 00:10:03,120
+كانت ميلة بزاوية 30، والشغل الناتج عن قوة
+
+128
+00:10:03,120 --> 00:10:06,640
+الاحتكاك. فهنا الشغل أنواع حسب القوة، حسب المطلوب،
+
+129
+00:10:06,640 --> 00:10:10,980
+حسب القوة الموجودة، وحسب المطلوب، الشغل الناتج، أو إذا
+
+130
+00:10:10,980 --> 00:10:15,950
+طلب مني الشغل الكلي، هجمع كل الشغل اللي إحنا حسبناه.
+
+131
+00:10:15,950 --> 00:10:19,110
+في section خمسة واحد، مطلوب مني الـ work and
+
+132
+00:10:24,930 --> 00:10:29,590
+dissipative forces. الشغل، الـ frictional force is
+
+133
+00:10:29,590 --> 00:10:33,370
+extremely important. طبعا الشغل الناتج عن الاحتكاك
+
+134
+00:10:33,370 --> 00:10:39,790
+مهم جدا في حياتنا العملية، because doing almost any
+
+135
+00:10:39,790 --> 00:10:43,290
+other kind of work is impossible without it. هذا
+
+136
+00:10:43,290 --> 00:10:46,790
+نوع من الـ... طبعا الشغل ناتج عنه هو الاحتكاك. the
+
+137
+00:10:46,790 --> 00:10:50,470
+man in the last example, for instance، الراجل في
+
+138
+00:10:50,470 --> 00:10:54,450
+المثال السابق، لحظة معينة، يعتمد على الـ surface
+
+139
+00:10:54,450 --> 00:10:58,010
+friction. طبعا بيعتمد على السطح عشان يشد هذه
+
+140
+00:10:58,010 --> 00:11:03,680
+العربة، otherwise the rope would slip in his hands
+
+141
+00:11:03,680 --> 00:11:07,640
+and exert no force on the sled, while his feet slid
+
+142
+00:11:07,640 --> 00:11:13,420
+out from underneath him and he fell flat on
+
+143
+00:11:13,420 --> 00:11:20,580
+his face. طبعا هذا اللي عندما سحب الرجل العربة، بنجد
+
+144
+00:11:20,580 --> 00:11:25,020
+أنه هاي اللي... اللي... اللي هي السطح. لو كان في
+
+145
+00:11:25,020 --> 00:11:29,330
+احتكاك، فالشغل الناتج عن الاحتكاك، إحنا بناخده في
+
+146
+00:11:29,330 --> 00:11:33,290
+الاعتبار، وهم مهم جدا. لكن في عندي أنا قوة احتكاك of
+
+147
+00:11:33,290 --> 00:11:36,710
+two objects in contact. قوة الاحتكاك هذا بيصير إذا
+
+148
+00:11:36,710 --> 00:11:40,270
+كان عندي أنا جسمين في بينهم احتكاك، أو سطحين
+
+149
+00:11:40,270 --> 00:11:44,610
+بتلامسوا، في بينهم احتكاك، and in relative motion to
+
+150
+00:11:44,610 --> 00:11:48,550
+each other, always dissipates energy in relatively
+
+151
+00:11:48,550 --> 00:11:51,990
+complex ways. ده energy loss. طبعا الاحتكاك بيعمل
+
+152
+00:11:51,990 --> 00:11:56,910
+على فقد طاقة، وبالتالي في عندي طبعا زي ما حكينا
+
+153
+00:11:56,910 --> 00:11:59,570
+زمان، إنه طاقة الميكانيكية الـ final ناقص الـ initial، بس
+
+154
+00:11:59,570 --> 00:12:05,070
+هو الشغل المبذول. with some energy converted to sound.
+
+155
+00:12:05,070 --> 00:12:09,630
+For our purpose, the phrase "work done by friction"
+
+156
+00:12:09,910 --> 00:12:13,110
+will denote the effect of friction on mechanical
+
+157
+00:12:13,110 --> 00:12:17,250
+energy alone. طبعا الشغل اللي هي التغير في طاقة
+
+158
+00:12:17,250 --> 00:12:21,850
+الطاقة الميكانيكية، دي بيساوي هو الشغل المبذول. طبعا
+
+159
+00:12:21,850 --> 00:12:26,830
+الشغل المبذول بيكون بالسالب، إن أنا فقدت طاقة. مثال،
+
+160
+00:12:26,830 --> 00:12:29,170
+إن suppose that، لو افترض أنا في الـ example
+
+161
+00:12:29,170 --> 00:12:33,930
+السابق، في عندي أنا قوة احتكاك، أو  مش قوة احتكاك، في
+
+162
+00:12:33,930 --> 00:12:36,950
+عندي coefficient of kinetic friction between the
+
+163
+00:12:36,950 --> 00:12:40,350
+loaded، اللي هي الخمسين كيلو، sled and snow، بين
+
+164
+00:12:40,350 --> 00:12:43,210
+العربة وبين الثلج. في عندي أنا معامل احتكاك اللي هو
+
+165
+00:12:43,210 --> 00:12:46,950
+0.2. في السؤال السابق، أعطاني قيمة احتكاك
+
+166
+00:12:46,950 --> 00:12:52,890
+يعني جاهزة. لو كان عندي أنا معامل احتكاك بيساوي 0.
+
+167
+00:12:52,890 --> 00:12:57,970
+2 بين سطح العربة والثلج. the man again pulled
+
+168
+00:12:57,970 --> 00:13:03,950
+the sled خمسة متر، exerted a force of 1.2 × 10² N في
+
+169
+00:13:03,950 --> 00:13:08,610
+زاوية 0. مطلوب مني أوجد الشغل المبذول بواسطة الـ
+
+170
+00:13:08,610 --> 00:13:12,630
+friction. بدنا نوجد الشغل المبذول بواسطة الـ
+
+171
+00:13:12,630 --> 00:13:16,270
+friction بالأول
+
+223
+00:16:59,310 --> 00:17:03,550
+على محور الـ X-axis الآن، لما بدي أجيب الـ network
+
+224
+00:17:03,550 --> 00:17:07,770
+الشغل الكلي، فعندي الشغل اللي ناتج عن القوة الـ
+
+225
+00:17:07,770 --> 00:17:13,830
+applied اللي هي 5.2×10²، اللي هي قيمة الـ F كوزين
+
+226
+00:17:13,830 --> 00:17:18,860
+الزاوية في الإزاحة، هنا الـ frictional work اللي هي
+
+227
+00:17:18,860 --> 00:17:24,040
+عبارة عن نقص 4.3×10²، والشغل اللي ناتج عن الـ normal
+
+228
+00:17:24,040 --> 00:17:27,060
+force يساوي 0، والشغل اللي ناتج عن الجاذبية
+
+229
+00:17:27,060 --> 00:17:32,280
+يساوي 0، لإنه قوة الـ normal عمودية على الإزاحة
+
+230
+00:17:32,280 --> 00:17:35,360
+وده اللي هي الـ G، الـ MG عمودية على الإزاحة، فالشغل
+
+231
+00:17:35,360 --> 00:17:40,700
+اللي ناتج عنها يساوي 0، فهذا الشغل الكلي 9×10×1
+
+232
+00:17:40,700 --> 00:17:46,160
+جول. نيجي نلاقي شغلة ثانية، اللي هي الـ kinetic energy
+
+233
+00:17:46,160 --> 00:17:51,120
+and the work energy في نظرية الشغل وطاقة الحركة
+
+234
+00:17:51,120 --> 00:17:57,100
+نظرية الشغل وطاقة الحركة، طبعاً احنا بنحل المعادلات
+
+235
+00:17:57,100 --> 00:18:01,240
+أو أي problems، أو أي مثال باستخدام قانون نيوتن
+
+236
+00:18:01,240 --> 00:18:05,600
+الثاني، لكن ممكن يكون صعب شوية استخدام قانون نيوتن
+
+237
+00:18:05,600 --> 00:18:11,190
+الثاني، فممكن احنا نستخدم قانون الشغل وطاقة الحركة، و
+
+238
+00:18:11,190 --> 00:18:14,710
+الشغل وعلاقتهم في بعض، إذا كان عندي أنا المسألة
+
+239
+00:18:14,710 --> 00:18:18,410
+بتحتوي على سرعات لـ object، to the network done
+
+240
+00:18:18,410 --> 00:18:21,990
+on its external force، if the network can be
+
+241
+00:18:21,990 --> 00:18:24,630
+calculated by given displacement، لو أنا حسبت الـ
+
+242
+00:18:24,630 --> 00:18:29,610
+network، وعندي سرعات، أو عندي سرعات مطلوب مني الـ
+
+243
+00:18:29,610 --> 00:18:35,300
+network، فده الحالة لو كان عندي هنا كتلة بدي أحركها
+
+244
+00:18:35,300 --> 00:18:39,740
+إذا تحركت X، فهنا القوة الكلية F net في المسافة
+
+245
+00:18:39,740 --> 00:18:46,940
+بيعطيني W net، برضه أيضاً بيعطيني W net في هذا
+
+246
+00:18:46,940 --> 00:18:52,480
+الشكل، بيعني بي shows an object of mass M move to
+
+247
+00:18:52,480 --> 00:18:55,020
+the right under the action of the constant net
+
+248
+00:18:55,020 --> 00:18:59,960
+force F net، فـ directed to the right because the
+
+249
+00:18:59,960 --> 00:19:03,950
+force is constant، لأن القوة ثابتة. We know from
+
+250
+00:19:03,950 --> 00:19:06,850
+Newton's second law، احنا عارفين من قانون نيوتن
+
+251
+00:19:06,850 --> 00:19:11,850
+الثاني، أنه مجموع الـ F بتساوي M في A، إذا
+
+252
+00:19:11,850 --> 00:19:15,890
+كانت الـ F constant، فالـ acceleration constant، if
+
+253
+00:19:15,890 --> 00:19:20,330
+the object is displaced by Delta X، فإذا الـ W net
+
+254
+00:19:20,330 --> 00:19:25,850
+بتساوي F net في Delta X، و F net بتساوي M في A في
+
+255
+00:19:25,850 --> 00:19:30,300
+Delta X. We find that the following relationship
+
+256
+00:19:30,300 --> 00:19:35,920
+holds، في عندي علاقة جديدة علشان أوجد أنا تغير الـ
+
+257
+00:19:35,920 --> 00:19:40,700
+W net، إيش علاقته في طاقة الحركة، فـ V تربيع يساوي V
+
+258
+00:19:40,700 --> 00:19:44,820
+not تربيع زائد 2 A Delta X، فـ A Delta X يساوي V
+
+259
+00:19:44,820 --> 00:19:49,740
+تربيع ناقص V not تربيع على 2، وبالتالي الـ W net
+
+260
+00:19:49,740 --> 00:19:56,860
+بتساوي الـ M في V تربيع ناقص V، طبعاً هي الـ M في A، والـ
+
+261
+00:19:56,860 --> 00:20:02,240
+A بتساوي هذا الكلام على 2، فـ الـ W net في هذه
+
+262
+00:20:02,240 --> 00:20:07,220
+الحالة بده يساوي التغير في طاقة الحركة، إذا اللي
+
+263
+00:20:07,220 --> 00:20:10,640
+بهمني أنا هذا القانون، اشتراك القانون، احنا مش لازم
+
+264
+00:20:10,640 --> 00:20:14,920
+فـ W net بتساوي نص M V تربيع ناقص نص M V تربيع
+
+265
+00:20:14,920 --> 00:20:20,890
+initial، هنا final ناقص initial، فمعنى الكلام، التغير
+
+266
+00:20:20,890 --> 00:20:25,370
+في طاقة الحركة بيعطينا الـ W net، اللي هي الـ kinetic
+
+267
+00:20:25,370 --> 00:20:29,070
+energy، رمزها K، والـ kinetic energy بتساوي نص M V
+
+268
+00:20:29,070 --> 00:20:34,190
+تربيع، بيسموها طاقة الحركة، إذا الجسم اتحرك بسرعة
+
+269
+00:20:34,190 --> 00:20:39,590
+كتلة M، واتحرك بسرعة V، فطاقة الحركة نص M V تربيع
+
+270
+00:20:39,590 --> 00:20:45,570
+طبعاً وحدتها برضه جول، إنها طاقة، الجول يساوي كيلو
+
+271
+00:20:45,570 --> 00:20:49,240
+جرام متر تربيع على second تربيع. طاقة الحركة كمية
+
+272
+00:20:49,240 --> 00:20:54,420
+قياسية، ممكن أستخدم هذا التعريف. we arrive at the
+
+273
+00:20:54,420 --> 00:20:57,380
+important result known as the work energy theorem
+
+274
+00:20:57,380 --> 00:21:02,300
+طبعاً علاقة اللي هي التغيير في طاقة الحركة مع الشغل
+
+275
+00:21:02,300 --> 00:21:07,660
+الكلي، بيسموها work energy theorem، يعني W net بده
+
+276
+00:21:07,660 --> 00:21:12,620
+تساوي Delta K، يعني K final ناقص K initial
+
+277
+00:21:19,980 --> 00:21:24,940
+التغير في طاقة الحركة بسبب التغير في السرعة، من
+
+278
+00:21:24,940 --> 00:21:29,540
+المعادلة بنلاحظ أن الـ positive network means that
+
+279
+00:21:29,540 --> 00:21:34,860
+إذا كان أنا الـ network موجب، فمعنى الكلام أنه طاقة
+
+280
+00:21:34,860 --> 00:21:38,780
+الحركة النهائية أكبر من الإبتدائية، وإذا كان سالب
+
+281
+00:21:38,780 --> 00:21:42,160
+بتكون طاقة الحركة الإبتدائية أكبر من النهائية
+
+282
+00:21:42,160 --> 00:21:47,160
+وهكذا. So positive network increases an object's
+
+283
+00:21:47,160 --> 00:21:51,260
+speed, the negative network decreases its speed
+
+284
+00:21:51,260 --> 00:21:56,280
+يعني لما يكون عندي أنا W net موجب، معناها إن في
+
+285
+00:21:56,280 --> 00:22:00,100
+عندي أنا زيادة في السرعة النهائية، لما يكون عندي
+
+286
+00:22:00,100 --> 00:22:06,420
+الشغل network سالب، معناته إن السرعة
+
+287
+00:22:06,420 --> 00:22:11,760
+النهائية بتكون قاعد بتتناقص. For convince the work
+
+288
+00:22:11,760 --> 00:22:14,080
+energy theorem was derived under the assumption
+
+289
+00:22:14,080 --> 00:22:16,380
+that the net force acting on the object was
+
+290
+00:22:16,380 --> 00:22:20,320
+constant. باللاحظ أو بنستنتج منه من نظرية الشغل و
+
+291
+00:22:20,320 --> 00:22:24,380
+الطاقة، أنه الـ net force المؤثر على الجسم مقداره
+
+292
+00:22:24,380 --> 00:22:30,340
+ثابت. More general derivation using calculus would
+
+293
+00:22:30,340 --> 00:22:35,400
+show that، ممكن احنا نثبت هذا في معادلة 5-2، ونثبت إنها صحيحة. Including the application
+
+294
+00:22:35,400 --> 00:22:39,570
+of the variable بتغيرات اللي هي القوة. ناخد هذا الـ
+
+295
+00:22:39,570 --> 00:22:44,370
+quiz: a pluck slides at constant speed down ramp
+
+296
+00:22:44,370 --> 00:22:48,830
+while acting on the by three forces. الجسم ينزلق
+
+297
+00:22:48,830 --> 00:22:53,950
+على سطح مايل، منحدر مايل، هي why acting acted on by
+
+298
+00:22:53,950 --> 00:23:02,050
+three forces. طبعاً بتأثر بثلاث قوى، اللي هي قوة الوزن
+
+299
+00:23:02,050 --> 00:23:06,250
+والـ normal force، وقوة الاحتكاك contact friction
+
+300
+00:23:06,250 --> 00:23:09,830
+المتحرك. Response to each statement true or false
+
+301
+00:23:09,830 --> 00:23:14,230
+الآن، بدنا نشوف مين الجمل هذه صحيحة أم خاطئة، ناخد
+
+302
+00:23:14,230 --> 00:23:19,690
+الأولى، اللي هو: a combined network done by all
+
+303
+00:23:19,690 --> 00:23:23,810
+three forces on the block equals zero. مجموعة الشغل
+
+304
+00:23:23,810 --> 00:23:28,830
+الكلي، طبعاً المبدول بواسطة ثلاث قوى يساوي zero. هذا
+
+305
+00:23:28,830 --> 00:23:35,160
+طبعاً صحيح، لإنه الشغل الناتج عن الـ normal force
+
+306
+00:23:35,160 --> 00:23:41,780
+يساوي zero، الشغل الناتج عن اللي هي الـ frictional
+
+307
+00:23:41,780 --> 00:23:46,180
+force سالب، والشغل الناتج عن…عن القوة ال…
+
+308
+00:23:46,180 --> 00:23:51,160
+الوزن، الشغل الناتج عن قوة الوزن، يعني بيساوي إذا
+
+309
+00:23:51,160 --> 00:23:57,720
+كان الجسم نازل إلى أسفل، بتكون قوة الشغل الناتج عن
+
+310
+00:23:57,720 --> 00:24:01,990
+ال…ال…وزن إلى…إلى أسفل، والشغل الناتج عن
+
+311
+00:24:01,990 --> 00:24:08,090
+ال…ال…وزن إلى…إلى أسفل، والشغل الناتج عن
+
+312
+00:24:08,090 --> 00:24:10,470
+الـ friction اللي لأعلى، مجموعهم يساوي zero
+
+313
+00:24:10,470 --> 00:24:13,930
+فالشغل الكلي، الـ network يساوي zero، والشغل الناتج عن
+
+314
+00:24:13,930 --> 00:24:18,170
+الـ normal force يساوي zero، إذن هذه الجملة صحيحة
+
+315
+00:24:18,170 --> 00:24:22,850
+الجملة الثانية: each force does zero work on the
+
+316
+00:24:22,850 --> 00:24:27,500
+block as it slides. كل قوة ممكن تأثر بشغل صفر على الـ
+
+317
+00:24:27,500 --> 00:24:31,100
+block. لأ، طبعاً، لأن الشغل الكلي هو الـ zero، لكن في شغل
+
+318
+00:24:31,100 --> 00:24:36,820
+ناتج عن الاحتكاك، وفي شغل ناتج عن اللي هو الوزن، لكن
+
+319
+00:24:36,820 --> 00:24:40,700
+شغل الـ normal force يساوي zero، لأن الـ normal force
+
+320
+00:24:40,700 --> 00:24:45,310
+عمودي على الإزاحة. خطأ. برسى each force does
+
+321
+00:24:45,310 --> 00:24:49,810
+negative work on the block as it slides. كل قوة
+
+322
+00:24:49,810 --> 00:24:53,670
+بتعطيني شغل سالب. لأ، مش مظبوط، false، لأن اللي
+
+323
+00:24:53,670 --> 00:25:01,990
+بتعطيني شغل سالب. each force does negative work on
+
+324
+00:25:01,990 --> 00:25:06,790
+the block as it slides. لأ، طبعاً، محصلتهم بتساوي zero
+
+325
+00:25:06,790 --> 00:25:13,800
+محصلتهم بتساوي zero، لأن الشغل الناتج عن الوزن بيكون
+
+326
+00:25:13,800 --> 00:25:16,480
+بنفس اتجاه الإزاحة، موجب، الشغل الناتج عن الـ
+
+327
+00:25:16,480 --> 00:25:19,820
+friction force سالب، الشغل الناتج عن الـ normal
+
+328
+00:25:19,820 --> 00:25:26,120
+force اللي هو يعني zero، لأنها normal force عمودية
+
+329
+00:25:26,120 --> 00:25:30,040
+على…normal force عمودية على الإزاحة، فالشغل يساوي
+
+330
+00:25:30,040 --> 00:25:30,880
+zero
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..1c8082817c00ff5adf00cfea17d855ec4487d97c
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY_postprocess.srt
@@ -0,0 +1,1320 @@
+1
+00:00:01,090 --> 00:00:06,390
+بنستكمل طبعا ال chapter خامسة ب section one اللي
+
+2
+00:00:06,390 --> 00:00:11,290
+هو ال work ال work always require a system of more
+
+3
+00:00:11,290 --> 00:00:17,990
+than just one object in ال for example مثال على
+
+4
+00:00:17,990 --> 00:00:22,170
+هذا الكلام لو كان أنا بدي أدخل مصمار في الحيط
+
+5
+00:00:22,170 --> 00:00:27,590
+المصمار لحاله can't do work on itself طبعا لحاله
+
+6
+00:00:27,590 --> 00:00:34,870
+مش هيعمل شغل لكنالشكوش او المطرقة can do work in
+
+7
+00:00:34,870 --> 00:00:38,310
+the nail by driving it into the board طبعا لما
+
+8
+00:00:38,310 --> 00:00:41,070
+بدخل انا مصمر في الحيط او في الخزانة او كده بضلني
+
+9
+00:00:41,070 --> 00:00:44,230
+اضغط عليها و اضرب فيها يعني انا بيعطيها قوة
+
+10
+00:00:44,620 --> 00:00:49,180
+وبالتالي هو هيمشي إزاحة معينة، مجموعة القوة،
+
+11
+00:00:49,180 --> 00:00:52,900
+مجموعة الإزاحات هيعطيني الشغل الكلي In general, an
+
+12
+00:00:52,900 --> 00:00:55,400
+object may be moving under the influence of
+
+13
+00:00:55,400 --> 00:00:59,380
+several external forces ممكن أن الجسم يتحرك تحت
+
+14
+00:00:59,380 --> 00:01:05,020
+أثير مجموعة من القوة In that case, the network في
+
+15
+00:01:05,020 --> 00:01:09,360
+الشغل الكل في هذه الحالة اللي يبذل من خلال هذا
+
+16
+00:01:09,360 --> 00:01:15,550
+الجسمتحت تأثير طبعا إزاحة معينة يعتبر عبارة عن
+
+17
+00:01:15,550 --> 00:01:23,210
+مجموع الشغل اللتي طبعا يحدث أبيو ذالب وسط كل قوة
+
+18
+00:01:23,210 --> 00:01:29,050
+ال work ممكن الشغل يكون موجب أو سالب ال work can
+
+19
+00:01:29,050 --> 00:01:33,910
+be either positive or negative in the definition
+
+20
+00:01:33,910 --> 00:01:38,050
+of the work ال F and D are magnitude which is are
+
+21
+00:01:38,050 --> 00:01:42,260
+never negativeفالwork is therefore positive or
+
+22
+00:01:42,260 --> 00:01:46,620
+negative depending on whether cos θ is positive or
+
+23
+00:01:46,620 --> 00:01:52,280
+negative طبعا احنا بنحدد ان هذا الشغل موجب او سالب
+
+24
+00:01:52,280 --> 00:01:57,820
+او zero حسب الزاويةإذا كانت الزاوية zero فالشغل
+
+25
+00:01:57,820 --> 00:02:02,200
+موجب إذا كانت الزاوية مية و تمانين درجة فالشغل
+
+26
+00:02:02,200 --> 00:02:07,380
+سالب إذا كانت الزاوية تسعين فالشغل zero when these
+
+27
+00:02:07,380 --> 00:02:10,500
+vectors are pointing in the same direction the
+
+28
+00:02:10,500 --> 00:02:15,000
+angle between them is zero so قزين ال zero واحد زي
+
+29
+00:02:15,000 --> 00:02:19,980
+ما حكينا فالشغل في هذه الحالة موجب for examplewhen
+
+30
+00:02:19,980 --> 00:02:27,120
+a student lift a box يعني لو شخص طبعا حمل box أو
+
+31
+00:02:27,120 --> 00:02:31,380
+صندوق the work he he does on the box is positive
+
+32
+00:02:31,380 --> 00:02:34,780
+because the force he exerted on the box is upward
+
+33
+00:02:35,480 --> 00:02:38,740
+in the same direction as displacement لو شخص أو
+
+34
+00:02:38,740 --> 00:02:43,100
+طالب حمل books من القالد إلى أعلى فبتكون القوة إلى
+
+35
+00:02:43,100 --> 00:02:46,380
+أعلى والإزاح إلى أعلى فالشغل موجب في هذه الحالة
+
+36
+00:02:46,380 --> 00:02:51,040
+لإنه الإزاح والقوة في نفس الاتجاه في الزاوية بينهم
+
+37
+00:02:51,040 --> 00:02:55,780
+zero فالشغل في هذه الحالة موجب the student still
+
+38
+00:02:55,780 --> 00:02:59,100
+exert an upward force on the books but the motion
+
+39
+00:02:59,100 --> 00:03:03,310
+of the books is downwardsbecause the vector F and
+
+40
+00:03:03,310 --> 00:03:09,610
+ΔX are now in opposite لو كان أنا طبعا القوة لتحت
+
+41
+00:03:09,610 --> 00:03:15,070
+MG وإزاحة إلى أعلى فبتكون الزاوية بين الإزاحة و
+
+42
+00:03:15,070 --> 00:03:19,190
+القوة 180 درجة فcos 180 هو ناقص فده الحالة الشغل
+
+43
+00:03:19,190 --> 00:03:23,470
+سالب طبعا هي الشغل زي ما موضح إذا أنا رفعت الجسم
+
+44
+00:03:23,470 --> 00:03:28,730
+إلى أعلى بقوة F فبتكون F و ΔX على نفس الاتجاه
+
+45
+00:03:28,730 --> 00:03:32,590
+فالزاوية بينهم zero فده الشغل موجبلو كانت أنا بدأ
+
+46
+00:03:32,590 --> 00:03:36,710
+أطبق أنه عندي أنا يعني هو الجاذبية الأسفل والإزاحي
+
+47
+00:03:36,710 --> 00:03:39,250
+الأعلى فالشغل الناتج عن الجاذبية في هذه الحالة
+
+48
+00:03:39,250 --> 00:03:43,850
+سالب وبالتالي طبعا هي الزاوية اللي بتحدد إذا كان
+
+49
+00:03:43,850 --> 00:03:49,910
+الشغل موجب أو سالب في هذا ال quiz في عندي أنا أكتر
+
+50
+00:03:49,910 --> 00:03:53,710
+من شكل ال block move to the right in the positive
+
+51
+00:03:53,710 --> 00:03:57,730
+x direction through the displacement delta x while
+
+52
+00:03:57,730 --> 00:04:00,110
+under the influence of the force with the same
+
+53
+00:04:00,110 --> 00:04:05,800
+magnitudeالان عندي انا يعني جسم بتحرك تحت تأثير
+
+54
+00:04:05,800 --> 00:04:10,700
+كتلة حاكية ليه السؤال which of the following is
+
+55
+00:04:10,700 --> 00:04:13,280
+the correct answer of the amount of the work done
+
+56
+00:04:13,280 --> 00:04:17,300
+by the force Ffrom most positive to the most
+
+57
+00:04:17,300 --> 00:04:23,400
+negative يعني بدي أكتب هذه الأشكال من الشغل حد من
+
+58
+00:04:23,400 --> 00:04:29,200
+الشغل الموجة و إلى السالب طبعا عندي انا A يعني هل
+
+59
+00:04:29,200 --> 00:04:34,420
+هو D الموجة بعدين C بعدين A بعدين B او هو C A B D
+
+60
+00:04:34,420 --> 00:04:38,460
+او هو C A D B طبعا عندي انا أربع أشكالالشكل الأول
+
+61
+00:04:38,460 --> 00:04:42,840
+a,b,c,d طبعا بدي أروح لكل شكل و أشوف مين الشغل
+
+62
+00:04:42,840 --> 00:04:47,680
+الموجب و أتدرج من الموجب إلى السالب بلاحظ أن هنا
+
+63
+00:04:47,680 --> 00:04:51,580
+الزاوية 90 فالشغل هذا zero هنا الزاوية 180 فالشغل
+
+64
+00:04:51,580 --> 00:04:56,480
+هذا سالب هنا الزاوية طبعا منفرجة ف cosine الزاوية
+
+65
+00:04:56,480 --> 00:05:00,840
+المنفرجة فهنا الزاوية طبعا zero و cosine ال zero
+
+66
+00:05:00,840 --> 00:05:07,300
+بساوي واحد فبطلع عندى هنا ال C هي الموجببعدين بعد
+
+67
+00:05:07,300 --> 00:05:11,480
+الموجب بيجيني اللي هو zero كأنه يعني خط أعداد موجب
+
+68
+00:05:11,480 --> 00:05:18,640
+zero بعدين سالب بعدين طبعا اللي هي بعدين هاي بعدين
+
+69
+00:05:18,640 --> 00:05:23,720
+هاي يعني هاي حالة أرتب ال C هاي هي أول واحدة اللي
+
+70
+00:05:23,720 --> 00:05:30,940
+هي قيمتها موجب C بعدين A اللي هي zero بعدين طبعا
+
+71
+00:05:30,940 --> 00:05:33,960
+قبل ما توصل إلى السلب واحد هيكون هي سالب بس قبل ما
+
+72
+00:05:33,960 --> 00:05:38,810
+توصل لسلب واحداللي هي D بعدين B فالترتيب هذه
+
+73
+00:05:38,810 --> 00:05:43,450
+الأربع أشكال هيترتبوا زي اللي هو الموجود فيه
+
+74
+00:05:43,450 --> 00:05:48,970
+الخيار C هيكون عندي C هي موجة هيكون عندي A هذه
+
+75
+00:05:48,970 --> 00:05:53,610
+Zero بعدين اللي هي هذه D اللي هي يعني لسه ماوصلت
+
+76
+00:05:53,610 --> 00:05:58,130
+إلى أنها تكون الزاوية 180 درجة فبيكون عندي C A D B
+
+77
+00:05:58,130 --> 00:06:01,630
+هذا هو الترتيب from positive to the most negative
+
+78
+00:06:01,630 --> 00:06:06,740
+هذا هو الترتيب الصحيح فالanswer عندي Cناخد سؤال
+
+79
+00:06:06,740 --> 00:06:11,740
+problems example خمسة واحد في عندي a man returning
+
+80
+00:06:11,740 --> 00:06:15,960
+from successful ice fishing trip pulls sails
+
+81
+00:06:15,960 --> 00:06:21,120
+loaded with salmon the total mass of the sled and
+
+82
+00:06:21,120 --> 00:06:25,380
+salmon is خمسين كيلو جرام and the man exert a
+
+83
+00:06:25,380 --> 00:06:30,980
+force of magnitude الرجل بأثر بقوة واحد واتنين
+
+84
+00:06:30,980 --> 00:06:35,220
+وعشر في عشر وستين نيوتن on the sled by pulling on
+
+85
+00:06:35,220 --> 00:06:39,330
+the ropehow much work does the .. what does he do
+
+86
+00:06:39,330 --> 00:06:42,970
+on the sled if the rope is horizontal to the
+
+87
+00:06:42,970 --> 00:06:49,870
+ground طبعا في عندي أنا رجل الرجل هذا زي ما احنا
+
+88
+00:06:49,870 --> 00:06:57,270
+شايفين بده يسحب مثلا سمكة من على يعني عرب التزلج
+
+89
+00:06:57,270 --> 00:07:04,070
+على الجليد طبعا سحبها بقوة F ميلة بزاوية تيتا وهذا
+
+90
+00:07:04,070 --> 00:07:08,800
+في عندي أنا قوة احتكاكطبعا لما دي في عندى قوة
+
+91
+00:07:08,800 --> 00:07:11,980
+احتكار في عندى قوة مؤثرة على هذه العربة في عندى
+
+92
+00:07:11,980 --> 00:07:17,920
+normal وفي عندى mg السؤال طالب بالبداية السؤال ايه
+
+93
+00:07:17,920 --> 00:07:23,960
+حكى لي how much work does he do on the sled if the
+
+94
+00:07:23,960 --> 00:07:27,320
+rope is horizontal to the ground مطلوب منى اوجد
+
+95
+00:07:27,320 --> 00:07:31,540
+الشغل اذا كان الحبل اللى بيشد في هذه العربة
+
+96
+00:07:31,540 --> 00:07:34,620
+horizontal الحبل اللى بيشد هذه العربة horizontal
+
+97
+00:07:34,620 --> 00:07:39,070
+معناته θ بساوة zeroand he pulls the sled خمسة متر
+
+98
+00:07:39,070 --> 00:07:44,290
+و هو سحبها مقدار خمسة متر نجلاق الحل الأولاني طبعا
+
+99
+00:07:44,290 --> 00:07:48,510
+بتعتبر هذا horizontal في الشيزاوية ففي عندي أنا
+
+100
+00:07:48,510 --> 00:07:52,250
+الشغل الناتج find the work done when the force is
+
+101
+00:07:52,250 --> 00:07:56,630
+horizontal علشان أجيبها بقول بحكي أن الشغل بتساوي
+
+102
+00:07:56,630 --> 00:08:00,710
+ال F باتجاه ال X في Delta X فاحنا أعطينا هو F واحد
+
+103
+00:08:00,710 --> 00:08:03,550
+point اتنين في عشرة أقصى اتنين و Delta X اللي هي
+
+104
+00:08:03,550 --> 00:08:08,030
+المسافة أو الإزاحة اللي مشيها بتطلع عندي6×10² جول
+
+105
+00:08:08,030 --> 00:08:12,850
+هذا الكلام إذا كانت القوة موازية للسطح والزاوية
+
+106
+00:08:12,850 --> 00:08:19,610
+zero بعد هيك طالب بني إيجاد الشغل لما أنا أسحبه
+
+107
+00:08:19,610 --> 00:08:23,930
+بقوة F وميلة على ال horizontal بزاوية التلاتين
+
+108
+00:08:23,930 --> 00:08:28,670
+طبعا هنطبق نفس القانون لكن هيكون عندي أنا الشغل دي
+
+109
+00:08:28,670 --> 00:08:35,940
+يساوي F cos θ في D هندخل cos θ ال F نفسه 1.2×10²و
+
+110
+00:08:35,940 --> 00:08:39,720
+ال θ كوزينة تلاتين و المسافة دي خمسة بطلع عندي
+
+111
+00:08:39,720 --> 00:08:44,900
+خمسة point اتنين في عشرة أقصى اتنين جول في C طالب
+
+112
+00:08:44,900 --> 00:08:49,840
+how much work done بده الشغل الناتج عن قوة
+
+113
+00:08:49,840 --> 00:08:53,300
+الاحتكاك إذا كانت في عندي أنا قوة الاحتكاك طبعا
+
+114
+00:08:53,300 --> 00:08:57,940
+أكس الحركة بسوء خمسة واربعين نيوتينطبعا بدي اوجد
+
+115
+00:08:57,940 --> 00:09:04,080
+انا هو ماشي مسافة 12.4 يعني ماشي انا الاحتكاك من
+
+116
+00:09:04,080 --> 00:09:10,660
+مسافة 12.4 متر الى 18.2 طبعا طالما انه اعطاني X
+
+117
+00:09:10,660 --> 00:09:14,340
+initial و X final هجيب Delta X اذا هجيب الشغل
+
+118
+00:09:14,340 --> 00:09:19,440
+الناتج عن الاحتكاك نسميه W friction بتساوي Fx في
+
+119
+00:09:19,440 --> 00:09:26,270
+Delta Xالـ Fx في Delta X Fk في Delta X طبعا الـ F
+
+120
+00:09:26,270 --> 00:09:29,950
+هي أبارع نقوط الاحتكاك الشغل الناتج عن الاحتكاك
+
+121
+00:09:29,950 --> 00:09:35,330
+سلب لإنه الإزاحة عكس القوة وبالتالي الـ Fk بيساوي
+
+122
+00:09:35,330 --> 00:09:40,750
+نقص 45 مضروبة في Delta X X final نقص X initial الـ
+
+123
+00:09:40,750 --> 00:09:46,630
+Final كان 18.2 و ال initial 12.4 ممكن نحسب الشغل
+
+124
+00:09:46,630 --> 00:09:50,740
+الناتج عن الاحتكاكاللي هي FK ناقص خمسة واربعين فى
+
+125
+00:09:50,740 --> 00:09:54,220
+Delta X بطلع ناقص اتنين اقصى تمان عشرة فعشرة اقصى
+
+126
+00:09:54,220 --> 00:09:59,340
+اتنين جول طبعا هي كاحنا حددنا الشغل الناتج عن
+
+127
+00:09:59,340 --> 00:10:03,120
+القوة إذا كانت أفقية الشغل الناتج عن القوة إذا
+
+128
+00:10:03,120 --> 00:10:06,640
+كانت بميلة بزاوية تلاتين والشغل الناتج عن قوة
+
+129
+00:10:06,640 --> 00:10:10,980
+الاحتكاك فهنا الشغل أنواع حسب القوة حسب المطلوب
+
+130
+00:10:10,980 --> 00:10:15,950
+حسب القوة الموجودةوحسب المطلوب الشغل الناتج او اذا
+
+131
+00:10:15,950 --> 00:10:19,110
+طلب مني الشغل الكل هجمع كل الشغل اللي احنا حسبنا
+
+132
+00:10:19,110 --> 00:10:24,930
+في section خمسة واحد مطلوب مني ال work and
+
+133
+00:10:24,930 --> 00:10:29,590
+dissipative force الشغل ال frictional force is
+
+134
+00:10:29,590 --> 00:10:33,370
+extremely important طبعا الشغل الناتج عن الاحتكاك
+
+135
+00:10:33,370 --> 00:10:39,790
+مهم جدا في حياتنا العمليةbecause doing almost any
+
+136
+00:10:39,790 --> 00:10:43,290
+other kind of work is impossible without it هذا
+
+137
+00:10:43,290 --> 00:10:46,790
+نوع من ال .. طبعا الشغل ناتج عنه هو الاحتكاك the
+
+138
+00:10:46,790 --> 00:10:50,470
+man in the last example for instance الراجل في
+
+139
+00:10:50,470 --> 00:10:54,450
+المثال السابق للحظة معينة يعتمد على ال surface
+
+140
+00:10:54,450 --> 00:10:58,010
+friction طبعا بيعتمد على السطح عشان يجدب هذه
+
+141
+00:10:58,010 --> 00:11:03,680
+العربةotherwise the rope would slip in his hands
+
+142
+00:11:03,680 --> 00:11:07,640
+and exert no force on the sled while his feet slid
+
+143
+00:11:07,640 --> 00:11:13,420
+out from the underneath him and he feel flat on
+
+144
+00:11:13,420 --> 00:11:20,580
+his face طبعا هذا اللي عندما سحب الرجل العربة بنجد
+
+145
+00:11:20,580 --> 00:11:25,020
+أنه هاي اللي .. اللي .. اللي هي الصطح لو كان في
+
+146
+00:11:25,020 --> 00:11:29,330
+احتكاك فالشغل الناتج عن الاحتكاكحدة بحناخدها بين
+
+147
+00:11:29,330 --> 00:11:33,290
+الاعتبار وهم هم جدا لكن في عندى انا قوة احتكاك of
+
+148
+00:11:33,290 --> 00:11:36,710
+two objects in contact قوة الاحتكاك هدا بيصير اذا
+
+149
+00:11:36,710 --> 00:11:40,270
+كان عندى انا جسمين في بينهم احتكاك او سطحين
+
+150
+00:11:40,270 --> 00:11:44,610
+بتلامسوا في بينهم احتكاك and in relative motion to
+
+151
+00:11:44,610 --> 00:11:48,550
+each other always dissipate energyin relatively
+
+152
+00:11:48,550 --> 00:11:51,990
+complex ways ده energy loss طبعا الاحتكاك بيعمل
+
+153
+00:11:51,990 --> 00:11:56,910
+على فقد طاقة وبالتالي في عندى طبعا زى ما حكينا
+
+154
+00:11:56,910 --> 00:11:59,570
+زمان انه طاقة الميكانيكية ال final نقص الانشطة بس
+
+155
+00:11:59,570 --> 00:12:05,070
+هو الشغل المبدول with some energy convert to sound
+
+156
+00:12:05,070 --> 00:12:09,630
+for our purpose the phrase work done by friction
+
+157
+00:12:09,910 --> 00:12:13,110
+will denote the effect of friction on mechanical
+
+158
+00:12:13,110 --> 00:12:17,250
+energy alone طبعا الشغل اللي هي التغير في طاقة
+
+159
+00:12:17,250 --> 00:12:21,850
+الطاقة الميكانيكية دي ساوي هو الشغل المبذول طبعا
+
+160
+00:12:21,850 --> 00:12:26,830
+الشغل المبذول بيكون بالسلب ان انا فقدت طاقة مثال
+
+161
+00:12:26,830 --> 00:12:29,170
+ان suppose that لو بدأ افرض انا في ال example
+
+162
+00:12:29,170 --> 00:12:33,930
+السابق في عندي انا قوة احتكاك او مش قوة احتكاك في
+
+163
+00:12:33,930 --> 00:12:36,950
+عندي coefficient of kinetic frictionbetween the
+
+164
+00:12:36,950 --> 00:12:40,350
+loaded اللي هي الخمسة كيلو sled and snow بين
+
+165
+00:12:40,350 --> 00:12:43,210
+العربة وبين التلج في عندي أنا معامل احتكاك اللي هو
+
+166
+00:12:43,210 --> 00:12:46,950
+point اتنين في السؤال السابق أعطاني خبط احتكاك
+
+167
+00:12:46,950 --> 00:12:52,890
+يعني جاهزة لو كان عندي أنا معامل احتكاك بسوء point
+
+168
+00:12:52,890 --> 00:12:57,970
+اتنين بين السطح العربة والتلج the man again pulled
+
+169
+00:12:57,970 --> 00:13:03,950
+the sled خمس متر exceeded a force of1.2×10-2N في
+
+170
+00:13:03,950 --> 00:13:08,610
+زاوية 0 مطلوب مني أوجد الشغل المبذول بواسطة ال
+
+171
+00:13:08,610 --> 00:13:12,630
+friction بدنا نوجد الشغل المبذول بواسطة ال
+
+172
+00:13:12,630 --> 00:13:16,270
+friction بالأول طبعا الشغل المبذول بواسطة ال
+
+173
+00:13:16,270 --> 00:13:20,350
+friction اللي هي FKM UK في ال normal و ال normal
+
+174
+00:13:20,350 --> 00:13:24,550
+ال normal عندنا هنا في هذه الحالة normal نقص MG
+
+175
+00:13:24,550 --> 00:13:28,280
+بسوء 0لأن الحركة بالـ x-axis ومافي حركة بالـ y
+
+176
+00:13:28,280 --> 00:13:32,160
+-axis فالـ normal بيساوي الـ mg هنستخدم ال normal
+
+177
+00:13:32,160 --> 00:13:36,180
+force عشان انا احسب اللي .. اللي هي قوة الاحتكاك
+
+178
+00:13:36,180 --> 00:13:39,060
+او الشغل الناتج عن الاحتكاك بساوي قوة الاحتكاك في
+
+179
+00:13:39,060 --> 00:13:42,840
+الإزاحة فالشغل الناتج عن الاحتكاك بساوي ناقص fk في
+
+180
+00:13:42,840 --> 00:13:46,620
+delta x fk عبارة عن mu k في ال normal و ال normal
+
+181
+00:13:46,620 --> 00:13:50,620
+بيساوي ال mg وفي delta x طبعا السلب لإنه قوة
+
+182
+00:13:50,620 --> 00:13:54,360
+الاحتكاك عكس الإزاحة فهو الزاوية 180 درجة وبالتالي
+
+183
+00:13:54,690 --> 00:13:59,690
+أنا عندي سالب FK في Delta X FK بساومي و K أعطانيها
+
+184
+00:13:59,690 --> 00:14:03,810
+مُعطى point اتنين و ال normal هي ال MG خمسين في
+
+185
+00:14:03,810 --> 00:14:06,690
+تسعة و تمانية من عشرة في خمسة اللي هو الإزاحة
+
+186
+00:14:06,690 --> 00:14:10,710
+بيطلع ناقص اربع تسعة من عشرة في عشر أقصى اتنين جول
+
+187
+00:14:10,710 --> 00:14:15,090
+some of the frictional work with the work done by
+
+188
+00:14:15,090 --> 00:14:19,610
+the applied force لما بدأ أوجد أنا ال network راح
+
+189
+00:14:19,610 --> 00:14:22,650
+أجمع الشغل الناتج عن القوة ال applied اللي أنا
+
+190
+00:14:22,650 --> 00:14:25,810
+أعطيته إياهاالشغل الناتج عن ال frictional force
+
+191
+00:14:25,810 --> 00:14:29,110
+والشغل الناتج عن ال normal force والشغل الناتج عن
+
+192
+00:14:29,110 --> 00:14:32,890
+الجاذبية إذا الشغل الناتج عن ال applied احنا
+
+193
+00:14:32,890 --> 00:14:39,210
+حسبناها سابقاً 6×10² الشغل الناتج عن ال friction 4
+
+194
+00:14:39,210 --> 00:14:44,870
+.9×10² اللي هي بالسالب الشغل الناتج عن ال normal 0
+
+195
+00:14:44,870 --> 00:14:50,210
+لإن ال normal عمودي على الإزاحة وبالتالي زاوية 90
+
+196
+00:14:50,210 --> 00:14:53,600
+فالشغل 0والشغل الناتج عن قوة الجاذبية أو ال MG
+
+197
+00:14:53,600 --> 00:14:56,700
+بيساوي Zero لإنه ال MG عمودي على الإزاحة وبالتالي
+
+198
+00:14:56,700 --> 00:15:02,880
+شغل Zero فبطلع عندي الشغل الكل بيساوي 1.1×10-2 في
+
+199
+00:15:02,880 --> 00:15:06,080
+B
+
+200
+00:15:06,080 --> 00:15:10,500
+بيحكي لي Recalculate ده Frictional work عيد حسبة
+
+201
+00:15:10,500 --> 00:15:15,260
+حسبتك لأ اللي في القوة اللي هو شرمتش عن احتكاك and
+
+202
+00:15:15,260 --> 00:15:20,990
+ال network إذا كانالخوة اللى انا اعطيتها هي تعمل
+
+203
+00:15:20,990 --> 00:15:24,270
+زاوية تلاتين درجة مع ال X-axis يعني بدنا نعيد نفس
+
+204
+00:15:24,270 --> 00:15:27,950
+الشغل ولكن موجود الزاوية تلاتين اذا لما تكون
+
+205
+00:15:27,950 --> 00:15:30,690
+الزاوية موجودة و الخوة عاملة زاوية تلاتين ده حل
+
+206
+00:15:30,690 --> 00:15:35,430
+للخوة بيصير عندي طبعا في ال X-axis F sine ال θ في
+
+207
+00:15:35,430 --> 00:15:41,190
+ال Y-axis F sine في ال Y-axis و F cosine في ال X
+
+208
+00:15:41,190 --> 00:15:46,900
+-axisبيصير عندى normal زائد ال F sine بساوية ال MG
+
+209
+00:15:46,900 --> 00:15:50,940
+معناه الكلام ان ال normal فى هذه الحالة اختلف فإذا
+
+210
+00:15:50,940 --> 00:15:56,080
+كان القوة اللى أنا بعطيها للجسم ميلة بزاوية فيتا
+
+211
+00:15:56,080 --> 00:15:59,320
+فال normal بساوية ال MG ناقص F applied في sine
+
+212
+00:15:59,320 --> 00:16:04,420
+الزاوية هنجيب القوة الناتجة عن الاحتكاك باستخدام
+
+213
+00:16:04,420 --> 00:16:07,440
+ال normal الجديد اللى هو MG ناقص F applied sine
+
+214
+00:16:07,440 --> 00:16:11,260
+فيتا اذا الشغل الناتج عن الاحتكاك ال W لل friction
+
+215
+00:16:12,200 --> 00:16:17,680
+بساوي ناقص FK في Delta X بساوي ميو K في N في Delta
+
+216
+00:16:17,680 --> 00:16:21,820
+X والـ N في هذه الحالة MG ناقص ال F sine الزاوية
+
+217
+00:16:21,820 --> 00:16:25,600
+في Delta X بطلع عند الشغل الناتج عن ال friction
+
+218
+00:16:25,600 --> 00:16:35,800
+ناقص 4.3×10² طبعا بعد التعويض لميو K.2 MG 59.9
+
+219
+00:16:35,800 --> 00:16:40,980
+ناقص اللي هي ال F applied1.2 من 10 فى 10 أقصى 2 فى
+
+220
+00:16:40,980 --> 00:16:45,040
+sin 30 فى delta X اللى هى الخمسة متر بطلع عندى
+
+221
+00:16:45,040 --> 00:16:50,960
+الشغل الناتج عن الاحتكاك ناقص 443 فى 10 أقصى 2 إذا
+
+222
+00:16:50,960 --> 00:16:59,310
+كانانا طبعا سحبت هذه العربة بقوة ميلاء بزاوية 30
+
+223
+00:16:59,310 --> 00:17:03,550
+على محور ال X-axis الان لما بدي اجيب ال network
+
+224
+00:17:03,550 --> 00:17:07,770
+الشغل الكلي فعندي الشغل اللي ناتج عن القوة ال
+
+225
+00:17:07,770 --> 00:17:13,830
+applied اللي هي 5.2×10² اللي هي أبارعا ال F كزين
+
+226
+00:17:13,830 --> 00:17:18,860
+الزاوية في الإزاحةهنا ال frictional work اللى هي
+
+227
+00:17:18,860 --> 00:17:24,040
+عبارة عن نقص 4.3×10² والشغل اللى ناتج عن ال normal
+
+228
+00:17:24,040 --> 00:17:27,060
+force بالساوة 0 والشغل اللى ناتج عن الجاذبية
+
+229
+00:17:27,060 --> 00:17:32,280
+بالساوة 0 لإنه قوة ال normal عمودية على الإزاحة
+
+230
+00:17:32,280 --> 00:17:35,360
+وده اللى هى ال G ال MG عمودية على الإزاحة فالشغل
+
+231
+00:17:35,360 --> 00:17:40,700
+اللى ناتج عنها بالساوة 0 فهذا الشغل الكل 9×10×1
+
+232
+00:17:40,700 --> 00:17:46,160
+جولنيجي نلاقي شغلة تانية اللي هي ال kinetic energy
+
+233
+00:17:46,160 --> 00:17:51,120
+and the work energy في نظرية الشغل و طاقة الحركة
+
+234
+00:17:51,120 --> 00:17:57,100
+نظرية الشغل و طاقة الحركة طبعا احنا بنحل المعادلات
+
+235
+00:17:57,100 --> 00:18:01,240
+او اي problems او اي مثال باستخدام قانون نيوتن
+
+236
+00:18:01,240 --> 00:18:05,600
+التاني لكن ممكن يكون صعب شوية استخدام قانون نيوتن
+
+237
+00:18:05,600 --> 00:18:11,190
+التانيفممكن احنا نستخدم قانون الشغل تقط الحركة و
+
+238
+00:18:11,190 --> 00:18:14,710
+الشغل و علاقتهم في بعض إذا كان عندي أنا المسألة
+
+239
+00:18:14,710 --> 00:18:18,410
+بتحتوي على سرعات ل ال object to the network done
+
+240
+00:18:18,410 --> 00:18:21,990
+on its external force if the network can be
+
+241
+00:18:21,990 --> 00:18:24,630
+calculated by given displacement لو أنا حسبت ال
+
+242
+00:18:24,630 --> 00:18:29,610
+network و عندي سرعات او عندي سرعات مطلوب مني ال
+
+243
+00:18:29,610 --> 00:18:35,300
+network فده الحالة لو كان عندي هنا كتلةبدي أحركها
+
+244
+00:18:35,300 --> 00:18:39,740
+إذا حدلت X فهنا القوة الكلية F net في المسافة
+
+245
+00:18:39,740 --> 00:18:46,940
+بيعطيني W net برضه أيضا في بيعطيني W net في هذا
+
+246
+00:18:46,940 --> 00:18:52,480
+الشكل بيعني بي shows an object of mass M move to
+
+247
+00:18:52,480 --> 00:18:55,020
+the right under the action of the constant net
+
+248
+00:18:55,020 --> 00:18:59,960
+force F net ف directed to the right because the
+
+249
+00:18:59,960 --> 00:19:03,950
+force is constant لإن القوة ثابتةWe know from
+
+250
+00:19:03,950 --> 00:19:06,850
+Newton's second law احنا عارفين من خانونته ان
+
+251
+00:19:06,850 --> 00:19:11,850
+التاني انه مش summation لل F بتساوي M في A إذا
+
+252
+00:19:11,850 --> 00:19:15,890
+كانت ال F constant في ال acceleration constant if
+
+253
+00:19:15,890 --> 00:19:20,330
+the object is displaced by Delta X فإذا ال W net
+
+254
+00:19:20,330 --> 00:19:25,850
+بتساوي F net في Delta X و F net بتساوي M في A في
+
+255
+00:19:25,850 --> 00:19:30,300
+Delta XWe find that the following relationship
+
+256
+00:19:30,300 --> 00:19:35,920
+holds في عندي علاقة جديدة علشان اوجد انا تغير الهو
+
+257
+00:19:35,920 --> 00:19:40,700
+W net ايش علاقته في طاقة الحركة ف V تربيع بيساوي V
+
+258
+00:19:40,700 --> 00:19:44,820
+not تربيع زي اتنين A Delta X فA Delta X بيساوي V
+
+259
+00:19:44,820 --> 00:19:49,740
+تربيع ناقص V not تربيع على اتنين وبالتالي ال W net
+
+260
+00:19:49,740 --> 00:19:56,860
+بتساوي ال Mفي V تربيع ناقص V طبعا هي ال M في A وال
+
+261
+00:19:56,860 --> 00:20:02,240
+A بتساوي هذا الكلام على اتنين ف ال W net في هذه
+
+262
+00:20:02,240 --> 00:20:07,220
+الحالة بدو يساوي التغير في طاقة الحركة اذا اللي
+
+263
+00:20:07,220 --> 00:20:10,640
+بهمني انا هذا القانون اشتراك القانون احنا مش لازم
+
+264
+00:20:10,640 --> 00:20:14,920
+ف W net بتساوي نص M V تربيع ناقص نص M V تربيع
+
+265
+00:20:14,920 --> 00:20:20,890
+initial هنا final ناقص initial فمعنى الكلامالتغير
+
+266
+00:20:20,890 --> 00:20:25,370
+في طاقة الحركة بيعطينا ال W net اللي هي ال kinetic
+
+267
+00:20:25,370 --> 00:20:29,070
+energy رمز هكائي و ال kinetic energy بيستوى نص M V
+
+268
+00:20:29,070 --> 00:20:34,190
+تربيه بيسموها طاقة الحركة إذا الجسم اتحرك بسرعة
+
+269
+00:20:34,190 --> 00:20:39,590
+كتلة و M و اتحرك بسرعة V فطاقة الحركة نص M V تربيه
+
+270
+00:20:39,590 --> 00:20:45,570
+طبعا وحدتها برضه جول إنها طاقة الجول بيستوى كيلو
+
+271
+00:20:45,570 --> 00:20:49,240
+جرام متر تربيه على second تربيهطاقة الحركة كمية
+
+272
+00:20:49,240 --> 00:20:54,420
+قياسية ممكن استخدم هذا التعريف we arrive at the
+
+273
+00:20:54,420 --> 00:20:57,380
+important result known as the work energy theorem
+
+274
+00:20:57,380 --> 00:21:02,300
+طبعا علاقة اللي هي التغيير في طاقة الحركة مع الشغل
+
+275
+00:21:02,300 --> 00:21:07,660
+الكل يسموها work energy theorem يعني W net بده
+
+276
+00:21:07,660 --> 00:21:12,620
+تسوى Delta K يعني K final ناقص K initial
+
+277
+00:21:19,980 --> 00:21:24,940
+التغير في طاقة الحركة بسبب التغير في السرعة من
+
+278
+00:21:24,940 --> 00:21:29,540
+المعادلة بنلاحظ أن ال positive network means that
+
+279
+00:21:29,540 --> 00:21:34,860
+إذا كان أنا ال network موجب فمعنى الكلام أنه طاقة
+
+280
+00:21:34,860 --> 00:21:38,780
+الحركة النهائية أكبر من الإبتدائية وإذا كان سالب
+
+281
+00:21:38,780 --> 00:21:42,160
+بتكون طاقة الحركة الإبتدائية أكبر من النهائية
+
+282
+00:21:42,160 --> 00:21:47,160
+وهكذاSo positive network increases an object's
+
+283
+00:21:47,160 --> 00:21:51,260
+speed, the negative network decreases its speed
+
+284
+00:21:51,260 --> 00:21:56,280
+يعني لما يكون عندي انا w net موجب معناها ان في
+
+285
+00:21:56,280 --> 00:22:00,100
+عندي انا زيادة في السرعة النهائية لما يكون عندي
+
+286
+00:22:00,100 --> 00:22:06,420
+الشغل network سالب معناته القوة اللي هي السرعة
+
+287
+00:22:06,420 --> 00:22:11,760
+النهائية بتكون قاعدة بتتناقصfor convince the work
+
+288
+00:22:11,760 --> 00:22:14,080
+energy theorem was derived under the assumption
+
+289
+00:22:14,080 --> 00:22:16,380
+that the net force acting on the object was
+
+290
+00:22:16,380 --> 00:22:20,320
+constant باللاحظ أو بنستنتج منه من نظرية الشغل و
+
+291
+00:22:20,320 --> 00:22:24,380
+الطاقة أنه ال net force المؤثر على الجسم مقدار
+
+292
+00:22:24,380 --> 00:22:30,340
+ثابت more general derivation using calculus would
+
+293
+00:22:30,340 --> 00:22:35,400
+show that ممكن احنا نثبت هذا في نسبة معادلة خمسة
+
+294
+00:22:35,400 --> 00:22:39,570
+اتنين و نثبت انها صحيحةincluding the application
+
+295
+00:22:39,570 --> 00:22:44,370
+of the variable بتغيرات اللي هي القوة ناخد هذا ال
+
+296
+00:22:44,370 --> 00:22:48,830
+quiz a pluck slides at constant speed down ramp
+
+297
+00:22:48,830 --> 00:22:53,950
+while acting on the by three forces الجسم ينزلق
+
+298
+00:22:53,950 --> 00:23:02,050
+على سطح مايل منحدر مايل هي why acting acted on by
+
+299
+00:23:02,050 --> 00:23:06,250
+three forces طبعا بتأثر بتلات قوةاللي هي قوة الوزن
+
+300
+00:23:06,250 --> 00:23:09,830
+والnormal force وcontact friction قوة الاحتكاك
+
+301
+00:23:09,830 --> 00:23:14,230
+المتحرك response to each statement true or false
+
+302
+00:23:14,230 --> 00:23:19,690
+الآن بدأ أشوف مين الجمال هذه صحيحة أم خاطئة ناخد
+
+303
+00:23:19,690 --> 00:23:23,810
+الأولى اللي هو a combined network done by all
+
+304
+00:23:23,810 --> 00:23:28,830
+three forces on the block equals zero مجموعة الشغل
+
+305
+00:23:28,830 --> 00:23:35,160
+الكلي طبعا المبدور بواسطة تلت قوة يساوي zeroهذا
+
+306
+00:23:35,160 --> 00:23:41,780
+طبعا صحيح لإنه الشغل الناتج عن ال normal force
+
+307
+00:23:41,780 --> 00:23:46,180
+بيساوي zero الشغل الناتج عن اللي هي ال frictional
+
+308
+00:23:46,180 --> 00:23:51,160
+force سالب و الشغل الناتج عن .. عن القوة ال ..
+
+309
+00:23:51,160 --> 00:23:57,720
+الوزن الشغل الناتج عن قوة الوزن يعني بيساوي إذا
+
+310
+00:23:57,720 --> 00:24:01,990
+كان الجسم نازل إلى أسفلبتكون قوة الشغل الناتج عن
+
+311
+00:24:01,990 --> 00:24:08,090
+ال .. ال .. الوزن إلى .. إلى أسفل والشغل الناتج عن
+
+312
+00:24:08,090 --> 00:24:10,470
+ال friction اللي أعلى في محاصرتهم بساوي zero
+
+313
+00:24:10,470 --> 00:24:13,930
+فالشغل كله ال network بساوي zero والشغل الناتج عن
+
+314
+00:24:13,930 --> 00:24:18,170
+ال normal force بساوي zero إذاً هذه الجملة صحيحة
+
+315
+00:24:18,170 --> 00:24:22,850
+الجملة التانية each force does zero work on the
+
+316
+00:24:22,850 --> 00:24:27,500
+block as it slides كل قوةممكن تأثر بشغل سفر على ال
+
+317
+00:24:27,500 --> 00:24:31,100
+block لأ طبعا لإن الشغل الكل هو ال zero لكن في شغل
+
+318
+00:24:31,100 --> 00:24:36,820
+ناتج عن الاحتكاك وفي شغل ناتج عن اللي هو الوزن لكن
+
+319
+00:24:36,820 --> 00:24:40,700
+شغل ال normal force بساوي zero لإن ال normal force
+
+320
+00:24:40,700 --> 00:24:45,310
+عمودي على الإزاحة خطأنبرسى each force does
+
+321
+00:24:45,310 --> 00:24:49,810
+negative work on the block as it slides كل قوة
+
+322
+00:24:49,810 --> 00:24:53,670
+بتعطيني شغل سالب لأ مش مظبوط false لإن اللي
+
+323
+00:24:53,670 --> 00:25:01,990
+بتعطيني شغل سالب each force does negative work on
+
+324
+00:25:01,990 --> 00:25:06,790
+the block as it slides لأ طبعا محصلتهم بتساوي zero
+
+325
+00:25:06,790 --> 00:25:13,800
+محصلتهم بتساوي zero لإن الشغل الناتج عن الوزنبيكون
+
+326
+00:25:13,800 --> 00:25:16,480
+بنفس اتجاه الإزاحة موجة الشغل الناتج عن ال
+
+327
+00:25:16,480 --> 00:25:19,820
+friction force سالب الشغل الناتج عن ال normal
+
+328
+00:25:19,820 --> 00:25:26,120
+force اللي هو يعني zero لإنها normal force عمودية
+
+329
+00:25:26,120 --> 00:25:30,040
+على normal force عمودية على الإزاحة في الشغل بساوي
+
+330
+00:25:30,040 --> 00:25:30,880
+zero
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..1c8082817c00ff5adf00cfea17d855ec4487d97c
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/KbZ2ZX8NRsY_raw.srt
@@ -0,0 +1,1320 @@
+1
+00:00:01,090 --> 00:00:06,390
+بنستكمل طبعا ال chapter خامسة ب section one اللي
+
+2
+00:00:06,390 --> 00:00:11,290
+هو ال work ال work always require a system of more
+
+3
+00:00:11,290 --> 00:00:17,990
+than just one object in ال for example مثال على
+
+4
+00:00:17,990 --> 00:00:22,170
+هذا الكلام لو كان أنا بدي أدخل مصمار في الحيط
+
+5
+00:00:22,170 --> 00:00:27,590
+المصمار لحاله can't do work on itself طبعا لحاله
+
+6
+00:00:27,590 --> 00:00:34,870
+مش هيعمل شغل لكنالشكوش او المطرقة can do work in
+
+7
+00:00:34,870 --> 00:00:38,310
+the nail by driving it into the board طبعا لما
+
+8
+00:00:38,310 --> 00:00:41,070
+بدخل انا مصمر في الحيط او في الخزانة او كده بضلني
+
+9
+00:00:41,070 --> 00:00:44,230
+اضغط عليها و اضرب فيها يعني انا بيعطيها قوة
+
+10
+00:00:44,620 --> 00:00:49,180
+وبالتالي هو هيمشي إزاحة معينة، مجموعة القوة،
+
+11
+00:00:49,180 --> 00:00:52,900
+مجموعة الإزاحات هيعطيني الشغل الكلي In general, an
+
+12
+00:00:52,900 --> 00:00:55,400
+object may be moving under the influence of
+
+13
+00:00:55,400 --> 00:00:59,380
+several external forces ممكن أن الجسم يتحرك تحت
+
+14
+00:00:59,380 --> 00:01:05,020
+أثير مجموعة من القوة In that case, the network في
+
+15
+00:01:05,020 --> 00:01:09,360
+الشغل الكل في هذه الحالة اللي يبذل من خلال هذا
+
+16
+00:01:09,360 --> 00:01:15,550
+الجسمتحت تأثير طبعا إزاحة معينة يعتبر عبارة عن
+
+17
+00:01:15,550 --> 00:01:23,210
+مجموع الشغل اللتي طبعا يحدث أبيو ذالب وسط كل قوة
+
+18
+00:01:23,210 --> 00:01:29,050
+ال work ممكن الشغل يكون موجب أو سالب ال work can
+
+19
+00:01:29,050 --> 00:01:33,910
+be either positive or negative in the definition
+
+20
+00:01:33,910 --> 00:01:38,050
+of the work ال F and D are magnitude which is are
+
+21
+00:01:38,050 --> 00:01:42,260
+never negativeفالwork is therefore positive or
+
+22
+00:01:42,260 --> 00:01:46,620
+negative depending on whether cos θ is positive or
+
+23
+00:01:46,620 --> 00:01:52,280
+negative طبعا احنا بنحدد ان هذا الشغل موجب او سالب
+
+24
+00:01:52,280 --> 00:01:57,820
+او zero حسب الزاويةإذا كانت الزاوية zero فالشغل
+
+25
+00:01:57,820 --> 00:02:02,200
+موجب إذا كانت الزاوية مية و تمانين درجة فالشغل
+
+26
+00:02:02,200 --> 00:02:07,380
+سالب إذا كانت الزاوية تسعين فالشغل zero when these
+
+27
+00:02:07,380 --> 00:02:10,500
+vectors are pointing in the same direction the
+
+28
+00:02:10,500 --> 00:02:15,000
+angle between them is zero so قزين ال zero واحد زي
+
+29
+00:02:15,000 --> 00:02:19,980
+ما حكينا فالشغل في هذه الحالة موجب for examplewhen
+
+30
+00:02:19,980 --> 00:02:27,120
+a student lift a box يعني لو شخص طبعا حمل box أو
+
+31
+00:02:27,120 --> 00:02:31,380
+صندوق the work he he does on the box is positive
+
+32
+00:02:31,380 --> 00:02:34,780
+because the force he exerted on the box is upward
+
+33
+00:02:35,480 --> 00:02:38,740
+in the same direction as displacement لو شخص أو
+
+34
+00:02:38,740 --> 00:02:43,100
+طالب حمل books من القالد إلى أعلى فبتكون القوة إلى
+
+35
+00:02:43,100 --> 00:02:46,380
+أعلى والإزاح إلى أعلى فالشغل موجب في هذه الحالة
+
+36
+00:02:46,380 --> 00:02:51,040
+لإنه الإزاح والقوة في نفس الاتجاه في الزاوية بينهم
+
+37
+00:02:51,040 --> 00:02:55,780
+zero فالشغل في هذه الحالة موجب the student still
+
+38
+00:02:55,780 --> 00:02:59,100
+exert an upward force on the books but the motion
+
+39
+00:02:59,100 --> 00:03:03,310
+of the books is downwardsbecause the vector F and
+
+40
+00:03:03,310 --> 00:03:09,610
+ΔX are now in opposite لو كان أنا طبعا القوة لتحت
+
+41
+00:03:09,610 --> 00:03:15,070
+MG وإزاحة إلى أعلى فبتكون الزاوية بين الإزاحة و
+
+42
+00:03:15,070 --> 00:03:19,190
+القوة 180 درجة فcos 180 هو ناقص فده الحالة الشغل
+
+43
+00:03:19,190 --> 00:03:23,470
+سالب طبعا هي الشغل زي ما موضح إذا أنا رفعت الجسم
+
+44
+00:03:23,470 --> 00:03:28,730
+إلى أعلى بقوة F فبتكون F و ΔX على نفس الاتجاه
+
+45
+00:03:28,730 --> 00:03:32,590
+فالزاوية بينهم zero فده الشغل موجبلو كانت أنا بدأ
+
+46
+00:03:32,590 --> 00:03:36,710
+أطبق أنه عندي أنا يعني هو الجاذبية الأسفل والإزاحي
+
+47
+00:03:36,710 --> 00:03:39,250
+الأعلى فالشغل الناتج عن الجاذبية في هذه الحالة
+
+48
+00:03:39,250 --> 00:03:43,850
+سالب وبالتالي طبعا هي الزاوية اللي بتحدد إذا كان
+
+49
+00:03:43,850 --> 00:03:49,910
+الشغل موجب أو سالب في هذا ال quiz في عندي أنا أكتر
+
+50
+00:03:49,910 --> 00:03:53,710
+من شكل ال block move to the right in the positive
+
+51
+00:03:53,710 --> 00:03:57,730
+x direction through the displacement delta x while
+
+52
+00:03:57,730 --> 00:04:00,110
+under the influence of the force with the same
+
+53
+00:04:00,110 --> 00:04:05,800
+magnitudeالان عندي انا يعني جسم بتحرك تحت تأثير
+
+54
+00:04:05,800 --> 00:04:10,700
+كتلة حاكية ليه السؤال which of the following is
+
+55
+00:04:10,700 --> 00:04:13,280
+the correct answer of the amount of the work done
+
+56
+00:04:13,280 --> 00:04:17,300
+by the force Ffrom most positive to the most
+
+57
+00:04:17,300 --> 00:04:23,400
+negative يعني بدي أكتب هذه الأشكال من الشغل حد من
+
+58
+00:04:23,400 --> 00:04:29,200
+الشغل الموجة و إلى السالب طبعا عندي انا A يعني هل
+
+59
+00:04:29,200 --> 00:04:34,420
+هو D الموجة بعدين C بعدين A بعدين B او هو C A B D
+
+60
+00:04:34,420 --> 00:04:38,460
+او هو C A D B طبعا عندي انا أربع أشكالالشكل الأول
+
+61
+00:04:38,460 --> 00:04:42,840
+a,b,c,d طبعا بدي أروح لكل شكل و أشوف مين الشغل
+
+62
+00:04:42,840 --> 00:04:47,680
+الموجب و أتدرج من الموجب إلى السالب بلاحظ أن هنا
+
+63
+00:04:47,680 --> 00:04:51,580
+الزاوية 90 فالشغل هذا zero هنا الزاوية 180 فالشغل
+
+64
+00:04:51,580 --> 00:04:56,480
+هذا سالب هنا الزاوية طبعا منفرجة ف cosine الزاوية
+
+65
+00:04:56,480 --> 00:05:00,840
+المنفرجة فهنا الزاوية طبعا zero و cosine ال zero
+
+66
+00:05:00,840 --> 00:05:07,300
+بساوي واحد فبطلع عندى هنا ال C هي الموجببعدين بعد
+
+67
+00:05:07,300 --> 00:05:11,480
+الموجب بيجيني اللي هو zero كأنه يعني خط أعداد موجب
+
+68
+00:05:11,480 --> 00:05:18,640
+zero بعدين سالب بعدين طبعا اللي هي بعدين هاي بعدين
+
+69
+00:05:18,640 --> 00:05:23,720
+هاي يعني هاي حالة أرتب ال C هاي هي أول واحدة اللي
+
+70
+00:05:23,720 --> 00:05:30,940
+هي قيمتها موجب C بعدين A اللي هي zero بعدين طبعا
+
+71
+00:05:30,940 --> 00:05:33,960
+قبل ما توصل إلى السلب واحد هيكون هي سالب بس قبل ما
+
+72
+00:05:33,960 --> 00:05:38,810
+توصل لسلب واحداللي هي D بعدين B فالترتيب هذه
+
+73
+00:05:38,810 --> 00:05:43,450
+الأربع أشكال هيترتبوا زي اللي هو الموجود فيه
+
+74
+00:05:43,450 --> 00:05:48,970
+الخيار C هيكون عندي C هي موجة هيكون عندي A هذه
+
+75
+00:05:48,970 --> 00:05:53,610
+Zero بعدين اللي هي هذه D اللي هي يعني لسه ماوصلت
+
+76
+00:05:53,610 --> 00:05:58,130
+إلى أنها تكون الزاوية 180 درجة فبيكون عندي C A D B
+
+77
+00:05:58,130 --> 00:06:01,630
+هذا هو الترتيب from positive to the most negative
+
+78
+00:06:01,630 --> 00:06:06,740
+هذا هو الترتيب الصحيح فالanswer عندي Cناخد سؤال
+
+79
+00:06:06,740 --> 00:06:11,740
+problems example خمسة واحد في عندي a man returning
+
+80
+00:06:11,740 --> 00:06:15,960
+from successful ice fishing trip pulls sails
+
+81
+00:06:15,960 --> 00:06:21,120
+loaded with salmon the total mass of the sled and
+
+82
+00:06:21,120 --> 00:06:25,380
+salmon is خمسين كيلو جرام and the man exert a
+
+83
+00:06:25,380 --> 00:06:30,980
+force of magnitude الرجل بأثر بقوة واحد واتنين
+
+84
+00:06:30,980 --> 00:06:35,220
+وعشر في عشر وستين نيوتن on the sled by pulling on
+
+85
+00:06:35,220 --> 00:06:39,330
+the ropehow much work does the .. what does he do
+
+86
+00:06:39,330 --> 00:06:42,970
+on the sled if the rope is horizontal to the
+
+87
+00:06:42,970 --> 00:06:49,870
+ground طبعا في عندي أنا رجل الرجل هذا زي ما احنا
+
+88
+00:06:49,870 --> 00:06:57,270
+شايفين بده يسحب مثلا سمكة من على يعني عرب التزلج
+
+89
+00:06:57,270 --> 00:07:04,070
+على الجليد طبعا سحبها بقوة F ميلة بزاوية تيتا وهذا
+
+90
+00:07:04,070 --> 00:07:08,800
+في عندي أنا قوة احتكاكطبعا لما دي في عندى قوة
+
+91
+00:07:08,800 --> 00:07:11,980
+احتكار في عندى قوة مؤثرة على هذه العربة في عندى
+
+92
+00:07:11,980 --> 00:07:17,920
+normal وفي عندى mg السؤال طالب بالبداية السؤال ايه
+
+93
+00:07:17,920 --> 00:07:23,960
+حكى لي how much work does he do on the sled if the
+
+94
+00:07:23,960 --> 00:07:27,320
+rope is horizontal to the ground مطلوب منى اوجد
+
+95
+00:07:27,320 --> 00:07:31,540
+الشغل اذا كان الحبل اللى بيشد في هذه العربة
+
+96
+00:07:31,540 --> 00:07:34,620
+horizontal الحبل اللى بيشد هذه العربة horizontal
+
+97
+00:07:34,620 --> 00:07:39,070
+معناته θ بساوة zeroand he pulls the sled خمسة متر
+
+98
+00:07:39,070 --> 00:07:44,290
+و هو سحبها مقدار خمسة متر نجلاق الحل الأولاني طبعا
+
+99
+00:07:44,290 --> 00:07:48,510
+بتعتبر هذا horizontal في الشيزاوية ففي عندي أنا
+
+100
+00:07:48,510 --> 00:07:52,250
+الشغل الناتج find the work done when the force is
+
+101
+00:07:52,250 --> 00:07:56,630
+horizontal علشان أجيبها بقول بحكي أن الشغل بتساوي
+
+102
+00:07:56,630 --> 00:08:00,710
+ال F باتجاه ال X في Delta X فاحنا أعطينا هو F واحد
+
+103
+00:08:00,710 --> 00:08:03,550
+point اتنين في عشرة أقصى اتنين و Delta X اللي هي
+
+104
+00:08:03,550 --> 00:08:08,030
+المسافة أو الإزاحة اللي مشيها بتطلع عندي6×10² جول
+
+105
+00:08:08,030 --> 00:08:12,850
+هذا الكلام إذا كانت القوة موازية للسطح والزاوية
+
+106
+00:08:12,850 --> 00:08:19,610
+zero بعد هيك طالب بني إيجاد الشغل لما أنا أسحبه
+
+107
+00:08:19,610 --> 00:08:23,930
+بقوة F وميلة على ال horizontal بزاوية التلاتين
+
+108
+00:08:23,930 --> 00:08:28,670
+طبعا هنطبق نفس القانون لكن هيكون عندي أنا الشغل دي
+
+109
+00:08:28,670 --> 00:08:35,940
+يساوي F cos θ في D هندخل cos θ ال F نفسه 1.2×10²و
+
+110
+00:08:35,940 --> 00:08:39,720
+ال θ كوزينة تلاتين و المسافة دي خمسة بطلع عندي
+
+111
+00:08:39,720 --> 00:08:44,900
+خمسة point اتنين في عشرة أقصى اتنين جول في C طالب
+
+112
+00:08:44,900 --> 00:08:49,840
+how much work done بده الشغل الناتج عن قوة
+
+113
+00:08:49,840 --> 00:08:53,300
+الاحتكاك إذا كانت في عندي أنا قوة الاحتكاك طبعا
+
+114
+00:08:53,300 --> 00:08:57,940
+أكس الحركة بسوء خمسة واربعين نيوتينطبعا بدي اوجد
+
+115
+00:08:57,940 --> 00:09:04,080
+انا هو ماشي مسافة 12.4 يعني ماشي انا الاحتكاك من
+
+116
+00:09:04,080 --> 00:09:10,660
+مسافة 12.4 متر الى 18.2 طبعا طالما انه اعطاني X
+
+117
+00:09:10,660 --> 00:09:14,340
+initial و X final هجيب Delta X اذا هجيب الشغل
+
+118
+00:09:14,340 --> 00:09:19,440
+الناتج عن الاحتكاك نسميه W friction بتساوي Fx في
+
+119
+00:09:19,440 --> 00:09:26,270
+Delta Xالـ Fx في Delta X Fk في Delta X طبعا الـ F
+
+120
+00:09:26,270 --> 00:09:29,950
+هي أبارع نقوط الاحتكاك الشغل الناتج عن الاحتكاك
+
+121
+00:09:29,950 --> 00:09:35,330
+سلب لإنه الإزاحة عكس القوة وبالتالي الـ Fk بيساوي
+
+122
+00:09:35,330 --> 00:09:40,750
+نقص 45 مضروبة في Delta X X final نقص X initial الـ
+
+123
+00:09:40,750 --> 00:09:46,630
+Final كان 18.2 و ال initial 12.4 ممكن نحسب الشغل
+
+124
+00:09:46,630 --> 00:09:50,740
+الناتج عن الاحتكاكاللي هي FK ناقص خمسة واربعين فى
+
+125
+00:09:50,740 --> 00:09:54,220
+Delta X بطلع ناقص اتنين اقصى تمان عشرة فعشرة اقصى
+
+126
+00:09:54,220 --> 00:09:59,340
+اتنين جول طبعا هي كاحنا حددنا الشغل الناتج عن
+
+127
+00:09:59,340 --> 00:10:03,120
+القوة إذا كانت أفقية الشغل الناتج عن القوة إذا
+
+128
+00:10:03,120 --> 00:10:06,640
+كانت بميلة بزاوية تلاتين والشغل الناتج عن قوة
+
+129
+00:10:06,640 --> 00:10:10,980
+الاحتكاك فهنا الشغل أنواع حسب القوة حسب المطلوب
+
+130
+00:10:10,980 --> 00:10:15,950
+حسب القوة الموجودةوحسب المطلوب الشغل الناتج او اذا
+
+131
+00:10:15,950 --> 00:10:19,110
+طلب مني الشغل الكل هجمع كل الشغل اللي احنا حسبنا
+
+132
+00:10:19,110 --> 00:10:24,930
+في section خمسة واحد مطلوب مني ال work and
+
+133
+00:10:24,930 --> 00:10:29,590
+dissipative force الشغل ال frictional force is
+
+134
+00:10:29,590 --> 00:10:33,370
+extremely important طبعا الشغل الناتج عن الاحتكاك
+
+135
+00:10:33,370 --> 00:10:39,790
+مهم جدا في حياتنا العمليةbecause doing almost any
+
+136
+00:10:39,790 --> 00:10:43,290
+other kind of work is impossible without it هذا
+
+137
+00:10:43,290 --> 00:10:46,790
+نوع من ال .. طبعا الشغل ناتج عنه هو الاحتكاك the
+
+138
+00:10:46,790 --> 00:10:50,470
+man in the last example for instance الراجل في
+
+139
+00:10:50,470 --> 00:10:54,450
+المثال السابق للحظة معينة يعتمد على ال surface
+
+140
+00:10:54,450 --> 00:10:58,010
+friction طبعا بيعتمد على السطح عشان يجدب هذه
+
+141
+00:10:58,010 --> 00:11:03,680
+العربةotherwise the rope would slip in his hands
+
+142
+00:11:03,680 --> 00:11:07,640
+and exert no force on the sled while his feet slid
+
+143
+00:11:07,640 --> 00:11:13,420
+out from the underneath him and he feel flat on
+
+144
+00:11:13,420 --> 00:11:20,580
+his face طبعا هذا اللي عندما سحب الرجل العربة بنجد
+
+145
+00:11:20,580 --> 00:11:25,020
+أنه هاي اللي .. اللي .. اللي هي الصطح لو كان في
+
+146
+00:11:25,020 --> 00:11:29,330
+احتكاك فالشغل الناتج عن الاحتكاكحدة بحناخدها بين
+
+147
+00:11:29,330 --> 00:11:33,290
+الاعتبار وهم هم جدا لكن في عندى انا قوة احتكاك of
+
+148
+00:11:33,290 --> 00:11:36,710
+two objects in contact قوة الاحتكاك هدا بيصير اذا
+
+149
+00:11:36,710 --> 00:11:40,270
+كان عندى انا جسمين في بينهم احتكاك او سطحين
+
+150
+00:11:40,270 --> 00:11:44,610
+بتلامسوا في بينهم احتكاك and in relative motion to
+
+151
+00:11:44,610 --> 00:11:48,550
+each other always dissipate energyin relatively
+
+152
+00:11:48,550 --> 00:11:51,990
+complex ways ده energy loss طبعا الاحتكاك بيعمل
+
+153
+00:11:51,990 --> 00:11:56,910
+على فقد طاقة وبالتالي في عندى طبعا زى ما حكينا
+
+154
+00:11:56,910 --> 00:11:59,570
+زمان انه طاقة الميكانيكية ال final نقص الانشطة بس
+
+155
+00:11:59,570 --> 00:12:05,070
+هو الشغل المبدول with some energy convert to sound
+
+156
+00:12:05,070 --> 00:12:09,630
+for our purpose the phrase work done by friction
+
+157
+00:12:09,910 --> 00:12:13,110
+will denote the effect of friction on mechanical
+
+158
+00:12:13,110 --> 00:12:17,250
+energy alone طبعا الشغل اللي هي التغير في طاقة
+
+159
+00:12:17,250 --> 00:12:21,850
+الطاقة الميكانيكية دي ساوي هو الشغل المبذول طبعا
+
+160
+00:12:21,850 --> 00:12:26,830
+الشغل المبذول بيكون بالسلب ان انا فقدت طاقة مثال
+
+161
+00:12:26,830 --> 00:12:29,170
+ان suppose that لو بدأ افرض انا في ال example
+
+162
+00:12:29,170 --> 00:12:33,930
+السابق في عندي انا قوة احتكاك او مش قوة احتكاك في
+
+163
+00:12:33,930 --> 00:12:36,950
+عندي coefficient of kinetic frictionbetween the
+
+164
+00:12:36,950 --> 00:12:40,350
+loaded اللي هي الخمسة كيلو sled and snow بين
+
+165
+00:12:40,350 --> 00:12:43,210
+العربة وبين التلج في عندي أنا معامل احتكاك اللي هو
+
+166
+00:12:43,210 --> 00:12:46,950
+point اتنين في السؤال السابق أعطاني خبط احتكاك
+
+167
+00:12:46,950 --> 00:12:52,890
+يعني جاهزة لو كان عندي أنا معامل احتكاك بسوء point
+
+168
+00:12:52,890 --> 00:12:57,970
+اتنين بين السطح العربة والتلج the man again pulled
+
+169
+00:12:57,970 --> 00:13:03,950
+the sled خمس متر exceeded a force of1.2×10-2N في
+
+170
+00:13:03,950 --> 00:13:08,610
+زاوية 0 مطلوب مني أوجد الشغل المبذول بواسطة ال
+
+171
+00:13:08,610 --> 00:13:12,630
+friction بدنا نوجد الشغل المبذول بواسطة ال
+
+172
+00:13:12,630 --> 00:13:16,270
+friction بالأول طبعا الشغل المبذول بواسطة ال
+
+173
+00:13:16,270 --> 00:13:20,350
+friction اللي هي FKM UK في ال normal و ال normal
+
+174
+00:13:20,350 --> 00:13:24,550
+ال normal عندنا هنا في هذه الحالة normal نقص MG
+
+175
+00:13:24,550 --> 00:13:28,280
+بسوء 0لأن الحركة بالـ x-axis ومافي حركة بالـ y
+
+176
+00:13:28,280 --> 00:13:32,160
+-axis فالـ normal بيساوي الـ mg هنستخدم ال normal
+
+177
+00:13:32,160 --> 00:13:36,180
+force عشان انا احسب اللي .. اللي هي قوة الاحتكاك
+
+178
+00:13:36,180 --> 00:13:39,060
+او الشغل الناتج عن الاحتكاك بساوي قوة الاحتكاك في
+
+179
+00:13:39,060 --> 00:13:42,840
+الإزاحة فالشغل الناتج عن الاحتكاك بساوي ناقص fk في
+
+180
+00:13:42,840 --> 00:13:46,620
+delta x fk عبارة عن mu k في ال normal و ال normal
+
+181
+00:13:46,620 --> 00:13:50,620
+بيساوي ال mg وفي delta x طبعا السلب لإنه قوة
+
+182
+00:13:50,620 --> 00:13:54,360
+الاحتكاك عكس الإزاحة فهو الزاوية 180 درجة وبالتالي
+
+183
+00:13:54,690 --> 00:13:59,690
+أنا عندي سالب FK في Delta X FK بساومي و K أعطانيها
+
+184
+00:13:59,690 --> 00:14:03,810
+مُعطى point اتنين و ال normal هي ال MG خمسين في
+
+185
+00:14:03,810 --> 00:14:06,690
+تسعة و تمانية من عشرة في خمسة اللي هو الإزاحة
+
+186
+00:14:06,690 --> 00:14:10,710
+بيطلع ناقص اربع تسعة من عشرة في عشر أقصى اتنين جول
+
+187
+00:14:10,710 --> 00:14:15,090
+some of the frictional work with the work done by
+
+188
+00:14:15,090 --> 00:14:19,610
+the applied force لما بدأ أوجد أنا ال network راح
+
+189
+00:14:19,610 --> 00:14:22,650
+أجمع الشغل الناتج عن القوة ال applied اللي أنا
+
+190
+00:14:22,650 --> 00:14:25,810
+أعطيته إياهاالشغل الناتج عن ال frictional force
+
+191
+00:14:25,810 --> 00:14:29,110
+والشغل الناتج عن ال normal force والشغل الناتج عن
+
+192
+00:14:29,110 --> 00:14:32,890
+الجاذبية إذا الشغل الناتج عن ال applied احنا
+
+193
+00:14:32,890 --> 00:14:39,210
+حسبناها سابقاً 6×10² الشغل الناتج عن ال friction 4
+
+194
+00:14:39,210 --> 00:14:44,870
+.9×10² اللي هي بالسالب الشغل الناتج عن ال normal 0
+
+195
+00:14:44,870 --> 00:14:50,210
+لإن ال normal عمودي على الإزاحة وبالتالي زاوية 90
+
+196
+00:14:50,210 --> 00:14:53,600
+فالشغل 0والشغل الناتج عن قوة الجاذبية أو ال MG
+
+197
+00:14:53,600 --> 00:14:56,700
+بيساوي Zero لإنه ال MG عمودي على الإزاحة وبالتالي
+
+198
+00:14:56,700 --> 00:15:02,880
+شغل Zero فبطلع عندي الشغل الكل بيساوي 1.1×10-2 في
+
+199
+00:15:02,880 --> 00:15:06,080
+B
+
+200
+00:15:06,080 --> 00:15:10,500
+بيحكي لي Recalculate ده Frictional work عيد حسبة
+
+201
+00:15:10,500 --> 00:15:15,260
+حسبتك لأ اللي في القوة اللي هو شرمتش عن احتكاك and
+
+202
+00:15:15,260 --> 00:15:20,990
+ال network إذا كانالخوة اللى انا اعطيتها هي تعمل
+
+203
+00:15:20,990 --> 00:15:24,270
+زاوية تلاتين درجة مع ال X-axis يعني بدنا نعيد نفس
+
+204
+00:15:24,270 --> 00:15:27,950
+الشغل ولكن موجود الزاوية تلاتين اذا لما تكون
+
+205
+00:15:27,950 --> 00:15:30,690
+الزاوية موجودة و الخوة عاملة زاوية تلاتين ده حل
+
+206
+00:15:30,690 --> 00:15:35,430
+للخوة بيصير عندي طبعا في ال X-axis F sine ال θ في
+
+207
+00:15:35,430 --> 00:15:41,190
+ال Y-axis F sine في ال Y-axis و F cosine في ال X
+
+208
+00:15:41,190 --> 00:15:46,900
+-axisبيصير عندى normal زائد ال F sine بساوية ال MG
+
+209
+00:15:46,900 --> 00:15:50,940
+معناه الكلام ان ال normal فى هذه الحالة اختلف فإذا
+
+210
+00:15:50,940 --> 00:15:56,080
+كان القوة اللى أنا بعطيها للجسم ميلة بزاوية فيتا
+
+211
+00:15:56,080 --> 00:15:59,320
+فال normal بساوية ال MG ناقص F applied في sine
+
+212
+00:15:59,320 --> 00:16:04,420
+الزاوية هنجيب القوة الناتجة عن الاحتكاك باستخدام
+
+213
+00:16:04,420 --> 00:16:07,440
+ال normal الجديد اللى هو MG ناقص F applied sine
+
+214
+00:16:07,440 --> 00:16:11,260
+فيتا اذا الشغل الناتج عن الاحتكاك ال W لل friction
+
+215
+00:16:12,200 --> 00:16:17,680
+بساوي ناقص FK في Delta X بساوي ميو K في N في Delta
+
+216
+00:16:17,680 --> 00:16:21,820
+X والـ N في هذه الحالة MG ناقص ال F sine الزاوية
+
+217
+00:16:21,820 --> 00:16:25,600
+في Delta X بطلع عند الشغل الناتج عن ال friction
+
+218
+00:16:25,600 --> 00:16:35,800
+ناقص 4.3×10² طبعا بعد التعويض لميو K.2 MG 59.9
+
+219
+00:16:35,800 --> 00:16:40,980
+ناقص اللي هي ال F applied1.2 من 10 فى 10 أقصى 2 فى
+
+220
+00:16:40,980 --> 00:16:45,040
+sin 30 فى delta X اللى هى الخمسة متر بطلع عندى
+
+221
+00:16:45,040 --> 00:16:50,960
+الشغل الناتج عن الاحتكاك ناقص 443 فى 10 أقصى 2 إذا
+
+222
+00:16:50,960 --> 00:16:59,310
+كانانا طبعا سحبت هذه العربة بقوة ميلاء بزاوية 30
+
+223
+00:16:59,310 --> 00:17:03,550
+على محور ال X-axis الان لما بدي اجيب ال network
+
+224
+00:17:03,550 --> 00:17:07,770
+الشغل الكلي فعندي الشغل اللي ناتج عن القوة ال
+
+225
+00:17:07,770 --> 00:17:13,830
+applied اللي هي 5.2×10² اللي هي أبارعا ال F كزين
+
+226
+00:17:13,830 --> 00:17:18,860
+الزاوية في الإزاحةهنا ال frictional work اللى هي
+
+227
+00:17:18,860 --> 00:17:24,040
+عبارة عن نقص 4.3×10² والشغل اللى ناتج عن ال normal
+
+228
+00:17:24,040 --> 00:17:27,060
+force بالساوة 0 والشغل اللى ناتج عن الجاذبية
+
+229
+00:17:27,060 --> 00:17:32,280
+بالساوة 0 لإنه قوة ال normal عمودية على الإزاحة
+
+230
+00:17:32,280 --> 00:17:35,360
+وده اللى هى ال G ال MG عمودية على الإزاحة فالشغل
+
+231
+00:17:35,360 --> 00:17:40,700
+اللى ناتج عنها بالساوة 0 فهذا الشغل الكل 9×10×1
+
+232
+00:17:40,700 --> 00:17:46,160
+جولنيجي نلاقي شغلة تانية اللي هي ال kinetic energy
+
+233
+00:17:46,160 --> 00:17:51,120
+and the work energy في نظرية الشغل و طاقة الحركة
+
+234
+00:17:51,120 --> 00:17:57,100
+نظرية الشغل و طاقة الحركة طبعا احنا بنحل المعادلات
+
+235
+00:17:57,100 --> 00:18:01,240
+او اي problems او اي مثال باستخدام قانون نيوتن
+
+236
+00:18:01,240 --> 00:18:05,600
+التاني لكن ممكن يكون صعب شوية استخدام قانون نيوتن
+
+237
+00:18:05,600 --> 00:18:11,190
+التانيفممكن احنا نستخدم قانون الشغل تقط الحركة و
+
+238
+00:18:11,190 --> 00:18:14,710
+الشغل و علاقتهم في بعض إذا كان عندي أنا المسألة
+
+239
+00:18:14,710 --> 00:18:18,410
+بتحتوي على سرعات ل ال object to the network done
+
+240
+00:18:18,410 --> 00:18:21,990
+on its external force if the network can be
+
+241
+00:18:21,990 --> 00:18:24,630
+calculated by given displacement لو أنا حسبت ال
+
+242
+00:18:24,630 --> 00:18:29,610
+network و عندي سرعات او عندي سرعات مطلوب مني ال
+
+243
+00:18:29,610 --> 00:18:35,300
+network فده الحالة لو كان عندي هنا كتلةبدي أحركها
+
+244
+00:18:35,300 --> 00:18:39,740
+إذا حدلت X فهنا القوة الكلية F net في المسافة
+
+245
+00:18:39,740 --> 00:18:46,940
+بيعطيني W net برضه أيضا في بيعطيني W net في هذا
+
+246
+00:18:46,940 --> 00:18:52,480
+الشكل بيعني بي shows an object of mass M move to
+
+247
+00:18:52,480 --> 00:18:55,020
+the right under the action of the constant net
+
+248
+00:18:55,020 --> 00:18:59,960
+force F net ف directed to the right because the
+
+249
+00:18:59,960 --> 00:19:03,950
+force is constant لإن القوة ثابتةWe know from
+
+250
+00:19:03,950 --> 00:19:06,850
+Newton's second law احنا عارفين من خانونته ان
+
+251
+00:19:06,850 --> 00:19:11,850
+التاني انه مش summation لل F بتساوي M في A إذا
+
+252
+00:19:11,850 --> 00:19:15,890
+كانت ال F constant في ال acceleration constant if
+
+253
+00:19:15,890 --> 00:19:20,330
+the object is displaced by Delta X فإذا ال W net
+
+254
+00:19:20,330 --> 00:19:25,850
+بتساوي F net في Delta X و F net بتساوي M في A في
+
+255
+00:19:25,850 --> 00:19:30,300
+Delta XWe find that the following relationship
+
+256
+00:19:30,300 --> 00:19:35,920
+holds في عندي علاقة جديدة علشان اوجد انا تغير الهو
+
+257
+00:19:35,920 --> 00:19:40,700
+W net ايش علاقته في طاقة الحركة ف V تربيع بيساوي V
+
+258
+00:19:40,700 --> 00:19:44,820
+not تربيع زي اتنين A Delta X فA Delta X بيساوي V
+
+259
+00:19:44,820 --> 00:19:49,740
+تربيع ناقص V not تربيع على اتنين وبالتالي ال W net
+
+260
+00:19:49,740 --> 00:19:56,860
+بتساوي ال Mفي V تربيع ناقص V طبعا هي ال M في A وال
+
+261
+00:19:56,860 --> 00:20:02,240
+A بتساوي هذا الكلام على اتنين ف ال W net في هذه
+
+262
+00:20:02,240 --> 00:20:07,220
+الحالة بدو يساوي التغير في طاقة الحركة اذا اللي
+
+263
+00:20:07,220 --> 00:20:10,640
+بهمني انا هذا القانون اشتراك القانون احنا مش لازم
+
+264
+00:20:10,640 --> 00:20:14,920
+ف W net بتساوي نص M V تربيع ناقص نص M V تربيع
+
+265
+00:20:14,920 --> 00:20:20,890
+initial هنا final ناقص initial فمعنى الكلامالتغير
+
+266
+00:20:20,890 --> 00:20:25,370
+في طاقة الحركة بيعطينا ال W net اللي هي ال kinetic
+
+267
+00:20:25,370 --> 00:20:29,070
+energy رمز هكائي و ال kinetic energy بيستوى نص M V
+
+268
+00:20:29,070 --> 00:20:34,190
+تربيه بيسموها طاقة الحركة إذا الجسم اتحرك بسرعة
+
+269
+00:20:34,190 --> 00:20:39,590
+كتلة و M و اتحرك بسرعة V فطاقة الحركة نص M V تربيه
+
+270
+00:20:39,590 --> 00:20:45,570
+طبعا وحدتها برضه جول إنها طاقة الجول بيستوى كيلو
+
+271
+00:20:45,570 --> 00:20:49,240
+جرام متر تربيه على second تربيهطاقة الحركة كمية
+
+272
+00:20:49,240 --> 00:20:54,420
+قياسية ممكن استخدم هذا التعريف we arrive at the
+
+273
+00:20:54,420 --> 00:20:57,380
+important result known as the work energy theorem
+
+274
+00:20:57,380 --> 00:21:02,300
+طبعا علاقة اللي هي التغيير في طاقة الحركة مع الشغل
+
+275
+00:21:02,300 --> 00:21:07,660
+الكل يسموها work energy theorem يعني W net بده
+
+276
+00:21:07,660 --> 00:21:12,620
+تسوى Delta K يعني K final ناقص K initial
+
+277
+00:21:19,980 --> 00:21:24,940
+التغير في طاقة الحركة بسبب التغير في السرعة من
+
+278
+00:21:24,940 --> 00:21:29,540
+المعادلة بنلاحظ أن ال positive network means that
+
+279
+00:21:29,540 --> 00:21:34,860
+إذا كان أنا ال network موجب فمعنى الكلام أنه طاقة
+
+280
+00:21:34,860 --> 00:21:38,780
+الحركة النهائية أكبر من الإبتدائية وإذا كان سالب
+
+281
+00:21:38,780 --> 00:21:42,160
+بتكون طاقة الحركة الإبتدائية أكبر من النهائية
+
+282
+00:21:42,160 --> 00:21:47,160
+وهكذاSo positive network increases an object's
+
+283
+00:21:47,160 --> 00:21:51,260
+speed, the negative network decreases its speed
+
+284
+00:21:51,260 --> 00:21:56,280
+يعني لما يكون عندي انا w net موجب معناها ان في
+
+285
+00:21:56,280 --> 00:22:00,100
+عندي انا زيادة في السرعة النهائية لما يكون عندي
+
+286
+00:22:00,100 --> 00:22:06,420
+الشغل network سالب معناته القوة اللي هي السرعة
+
+287
+00:22:06,420 --> 00:22:11,760
+النهائية بتكون قاعدة بتتناقصfor convince the work
+
+288
+00:22:11,760 --> 00:22:14,080
+energy theorem was derived under the assumption
+
+289
+00:22:14,080 --> 00:22:16,380
+that the net force acting on the object was
+
+290
+00:22:16,380 --> 00:22:20,320
+constant باللاحظ أو بنستنتج منه من نظرية الشغل و
+
+291
+00:22:20,320 --> 00:22:24,380
+الطاقة أنه ال net force المؤثر على الجسم مقدار
+
+292
+00:22:24,380 --> 00:22:30,340
+ثابت more general derivation using calculus would
+
+293
+00:22:30,340 --> 00:22:35,400
+show that ممكن احنا نثبت هذا في نسبة معادلة خمسة
+
+294
+00:22:35,400 --> 00:22:39,570
+اتنين و نثبت انها صحيحةincluding the application
+
+295
+00:22:39,570 --> 00:22:44,370
+of the variable بتغيرات اللي هي القوة ناخد هذا ال
+
+296
+00:22:44,370 --> 00:22:48,830
+quiz a pluck slides at constant speed down ramp
+
+297
+00:22:48,830 --> 00:22:53,950
+while acting on the by three forces الجسم ينزلق
+
+298
+00:22:53,950 --> 00:23:02,050
+على سطح مايل منحدر مايل هي why acting acted on by
+
+299
+00:23:02,050 --> 00:23:06,250
+three forces طبعا بتأثر بتلات قوةاللي هي قوة الوزن
+
+300
+00:23:06,250 --> 00:23:09,830
+والnormal force وcontact friction قوة الاحتكاك
+
+301
+00:23:09,830 --> 00:23:14,230
+المتحرك response to each statement true or false
+
+302
+00:23:14,230 --> 00:23:19,690
+الآن بدأ أشوف مين الجمال هذه صحيحة أم خاطئة ناخد
+
+303
+00:23:19,690 --> 00:23:23,810
+الأولى اللي هو a combined network done by all
+
+304
+00:23:23,810 --> 00:23:28,830
+three forces on the block equals zero مجموعة الشغل
+
+305
+00:23:28,830 --> 00:23:35,160
+الكلي طبعا المبدور بواسطة تلت قوة يساوي zeroهذا
+
+306
+00:23:35,160 --> 00:23:41,780
+طبعا صحيح لإنه الشغل الناتج عن ال normal force
+
+307
+00:23:41,780 --> 00:23:46,180
+بيساوي zero الشغل الناتج عن اللي هي ال frictional
+
+308
+00:23:46,180 --> 00:23:51,160
+force سالب و الشغل الناتج عن .. عن القوة ال ..
+
+309
+00:23:51,160 --> 00:23:57,720
+الوزن الشغل الناتج عن قوة الوزن يعني بيساوي إذا
+
+310
+00:23:57,720 --> 00:24:01,990
+كان الجسم نازل إلى أسفلبتكون قوة الشغل الناتج عن
+
+311
+00:24:01,990 --> 00:24:08,090
+ال .. ال .. الوزن إلى .. إلى أسفل والشغل الناتج عن
+
+312
+00:24:08,090 --> 00:24:10,470
+ال friction اللي أعلى في محاصرتهم بساوي zero
+
+313
+00:24:10,470 --> 00:24:13,930
+فالشغل كله ال network بساوي zero والشغل الناتج عن
+
+314
+00:24:13,930 --> 00:24:18,170
+ال normal force بساوي zero إذاً هذه الجملة صحيحة
+
+315
+00:24:18,170 --> 00:24:22,850
+الجملة التانية each force does zero work on the
+
+316
+00:24:22,850 --> 00:24:27,500
+block as it slides كل قوةممكن تأثر بشغل سفر على ال
+
+317
+00:24:27,500 --> 00:24:31,100
+block لأ طبعا لإن الشغل الكل هو ال zero لكن في شغل
+
+318
+00:24:31,100 --> 00:24:36,820
+ناتج عن الاحتكاك وفي شغل ناتج عن اللي هو الوزن لكن
+
+319
+00:24:36,820 --> 00:24:40,700
+شغل ال normal force بساوي zero لإن ال normal force
+
+320
+00:24:40,700 --> 00:24:45,310
+عمودي على الإزاحة خطأنبرسى each force does
+
+321
+00:24:45,310 --> 00:24:49,810
+negative work on the block as it slides كل قوة
+
+322
+00:24:49,810 --> 00:24:53,670
+بتعطيني شغل سالب لأ مش مظبوط false لإن اللي
+
+323
+00:24:53,670 --> 00:25:01,990
+بتعطيني شغل سالب each force does negative work on
+
+324
+00:25:01,990 --> 00:25:06,790
+the block as it slides لأ طبعا محصلتهم بتساوي zero
+
+325
+00:25:06,790 --> 00:25:13,800
+محصلتهم بتساوي zero لإن الشغل الناتج عن الوزنبيكون
+
+326
+00:25:13,800 --> 00:25:16,480
+بنفس اتجاه الإزاحة موجة الشغل الناتج عن ال
+
+327
+00:25:16,480 --> 00:25:19,820
+friction force سالب الشغل الناتج عن ال normal
+
+328
+00:25:19,820 --> 00:25:26,120
+force اللي هو يعني zero لإنها normal force عمودية
+
+329
+00:25:26,120 --> 00:25:30,040
+على normal force عمودية على الإزاحة في الشغل بساوي
+
+330
+00:25:30,040 --> 00:25:30,880
+zero
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/LXPjKg0lMWM_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/LXPjKg0lMWM_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..0adf9eb05a1b1c6f16dbd3771a9e80a99fa4ab8c
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/LXPjKg0lMWM_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 2138, "start": 0.0, "end": 21.38, "text": "بسم الله الرحمن الرحيم نستكمل chapter 6 section 6-2 بانوان conservation of momentum حفظ الزخم أو حفظ كمية التحرك ال momentum هي عبارة عن كمية التحرك أو الزخم when a collision occurs in an isolated system عندما يحدث تصادم في نظام معزول", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 8717, 14851, 24793, 1211, 7187, 1386, 3541, 1386, 12, 17, 4724, 7649, 2407, 7649, 16185, 295, 11244, 11331, 5172, 19913, 6024, 110, 9778, 2304, 34051, 11331, 5172, 19913, 9122, 2304, 10632, 16712, 5016, 31747, 2423, 11244, 39896, 6225, 3555, 9640, 3660, 18871, 9122, 2304, 10632, 16712, 5016, 31747, 34051, 6024, 110, 9778, 2304, 562, 257, 24644, 11843, 294, 364, 14621, 1185, 43242, 15042, 7251, 24401, 12984, 6055, 9381, 18513, 2304, 8978, 8717, 19913, 10943, 20449, 11622, 12610], "avg_logprob": -0.09707255404571007, "compression_ratio": 1.5155555555555555, "no_speech_prob": 9.5367431640625e-07, "words": 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"word": " الشخص", "probability": 0.99169921875}, {"start": 1342.15, "end": 1342.81, "word": " من", "probability": 0.982421875}, {"start": 1342.81, "end": 1343.13, "word": " خلال", "probability": 0.9944661458333334}, {"start": 1343.13, "end": 1343.41, "word": " طبعا", "probability": 0.935302734375}, {"start": 1343.41, "end": 1343.75, "word": " رميه", "probability": 0.950927734375}, {"start": 1343.75, "end": 1344.05, "word": " لهذا", "probability": 0.97998046875}, {"start": 1344.05, "end": 1344.43, "word": " السهم", "probability": 0.98583984375}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1344.667625, "duration_after_vad": 1324.1015937499988}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/LXPjKg0lMWM_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/LXPjKg0lMWM_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..bd28f6803166134015c9dfd373e142523721dba5
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/LXPjKg0lMWM_raw.srt
@@ -0,0 +1,1156 @@
+1
+00:00:00,000 --> 00:00:05,180
+بسم الله الرحمن الرحيم نستكمل chapter 6 section 6
+
+2
+00:00:05,180 --> 00:00:09,960
+-2 بانوان conservation of momentum حفظ الزخم أو
+
+3
+00:00:09,960 --> 00:00:14,020
+حفظ كمية التحرك ال momentum هي عبارة عن كمية
+
+4
+00:00:14,020 --> 00:00:17,560
+التحرك أو الزخم when a collision occurs in an
+
+5
+00:00:17,560 --> 00:00:22,480
+isolated system عندما يحدث تصادم في نظام معزولthe
+
+6
+00:00:22,480 --> 00:00:25,660
+total momentum of the system does not change with
+
+7
+00:00:25,660 --> 00:00:30,820
+the passage of the time فكمية التحرك الكلية لأي
+
+8
+00:00:30,820 --> 00:00:35,380
+نظام لا تتغير حسب يعنيها بالنسبة لها الزمن طبعا
+
+9
+00:00:35,380 --> 00:00:42,140
+المار أو الزمن خلال فترة زمنية معينةinstead it
+
+10
+00:00:42,140 --> 00:00:44,740
+remain a constant both in magnitude and direction
+
+11
+00:00:44,740 --> 00:00:49,580
+ممكن بطريقة أخرى نقول إن كمية التحرك تبقى ثابتة
+
+12
+00:00:49,580 --> 00:00:55,320
+both in magnitude بالنسبة لطبعا القيمة والاتجاه
+
+13
+00:00:55,320 --> 00:00:59,040
+the momentum of the individual object in the
+
+14
+00:00:59,040 --> 00:01:05,000
+system may change كمية التحرك بالنسبة لنظام مثلا
+
+15
+00:01:05,000 --> 00:01:12,260
+واحدلحاله ممكن تكون ممكن تتغير لكن the vector sum
+
+16
+00:01:12,260 --> 00:01:17,460
+of all momentum will not change المجموعة الكل اللي
+
+17
+00:01:17,460 --> 00:01:22,520
+هي كمية التحرك بتكون طبعا لا تتغير the total
+
+18
+00:01:22,520 --> 00:01:25,940
+momentum is therefore said to be constant وبالتالي
+
+19
+00:01:25,940 --> 00:01:31,200
+إذا ما اتغيرت كمية التحرك ما اتغيرت وضلت فتعتبر
+
+20
+00:01:31,200 --> 00:01:35,660
+ثابتة إذا كانت ثابتة بنسميهاكمية التحرك conserved
+
+21
+00:01:35,660 --> 00:01:40,120
+يعني كمية التحرك قبل بساوة كمية التحرك بعد، كمية
+
+22
+00:01:40,120 --> 00:01:46,810
+محفوظة يعني مافيش فيها تشتت أو فقدالcollision
+
+23
+00:01:46,810 --> 00:01:49,570
+التصادم is the result of physical interaction
+
+24
+00:01:49,570 --> 00:01:53,370
+between two objects طبعا التصادم هو عبارة عن يعني
+
+25
+00:01:53,370 --> 00:01:59,410
+ظاهرة أو فيزيائية بين جسمين زي ما هو موضح بالشكل
+
+26
+00:01:59,410 --> 00:02:03,210
+خلال التصادم ال particle interact and transfer
+
+27
+00:02:03,210 --> 00:02:09,050
+momentarily خلال التصادم طبعا بتأثروا الكتلتير مع
+
+28
+00:02:09,050 --> 00:02:13,520
+بعض وبالتالييحدث اللي هو انتقال في كمية التحرك
+
+29
+00:02:13,520 --> 00:02:17,040
+طبعا هندي أنا كتلة اما واحد او اما اتنين زي ومواضح
+
+30
+00:02:17,040 --> 00:02:21,340
+بالشكل اما واحد او اما اتنين صدموا في بعض طبعا كل
+
+31
+00:02:21,340 --> 00:02:25,920
+كتلة افترت على التانية بسرعة بقوة معينةفهنا ال F 2
+
+32
+00:02:25,920 --> 00:02:30,400
+1 يبدأ تساوي ال F 1 2 القوة المؤثرة من واحد على
+
+33
+00:02:30,400 --> 00:02:34,040
+اتنين هي نفس القوة المؤثرة من اتنين على واحد ولكن
+
+34
+00:02:34,040 --> 00:02:39,540
+متساوية في المقدار ومختلفة بالاتجاه في الشكل
+
+35
+00:02:39,540 --> 00:02:44,220
+التاني بيحكي اللي في اننا تصادم collision بين بين
+
+36
+00:02:44,220 --> 00:02:49,750
+طبعا ال proton و بين ال heliumزي ما هو موضح بالشكل
+
+37
+00:02:49,750 --> 00:02:54,110
+و طبعا لكن هنا التنتين كانوا على استقامة واحدة هنا
+
+38
+00:02:54,110 --> 00:03:00,750
+كل واحدة يعني باتجاه معين فهذا الشكل السابق يعني
+
+39
+00:03:00,750 --> 00:03:03,990
+shows an isolated system of two particles before
+
+40
+00:03:03,990 --> 00:03:09,510
+and after recollision بيوضح اللي هو التصادم بين
+
+41
+00:03:09,510 --> 00:03:15,070
+particle two يعني جثيمين أو كتلتين قبل التصادم أو
+
+42
+00:03:15,070 --> 00:03:19,490
+بعد التصادمالكلمة isolated يعني we mean no
+
+43
+00:03:19,490 --> 00:03:22,930
+external force كلمة isolated يعني هذا النظام معزول
+
+44
+00:03:22,930 --> 00:03:26,470
+مافيش أي قوة خارجية بتأثر عليه زي مثلا قوة
+
+45
+00:03:26,470 --> 00:03:30,490
+الجاذبية أو ال friction المؤثرة على ال system أو
+
+46
+00:03:30,490 --> 00:03:34,630
+النظام before the collision قبل التصادم فالسرعات
+
+47
+00:03:34,630 --> 00:03:39,510
+بتكون V1 initial و V2 initial و after ده كله و بعد
+
+48
+00:03:39,510 --> 00:03:44,330
+التصادم بتكون السرعات V1 final and V2 finalThe
+
+49
+00:03:44,330 --> 00:03:47,810
+impulse momentum therefore applied to M1 التي
+
+50
+00:03:47,810 --> 00:03:54,490
+تتدفع بالنسبة لكتلة
+
+51
+00:03:54,490 --> 00:03:58,910
+الأولى ممكن تكون بالطريقة هذه أنه لو كان عندي أنا
+
+52
+00:03:58,910 --> 00:04:03,580
+كتلة M1 و M2ف before the collision these particles
+
+53
+00:04:03,580 --> 00:04:08,020
+are equal and opposite direction ال M1 بتسير بسرعة
+
+54
+00:04:08,020 --> 00:04:11,540
+V1 initial و M2 بتسير بسرعة V2 initial عكس بعض
+
+55
+00:04:11,540 --> 00:04:17,320
+طبعا بعد التصادم هيكون الأمر كل واحدة راحت في
+
+56
+00:04:17,320 --> 00:04:21,680
+الأولى يعني .. يعني الأولى تسير بسرعة V1 final و
+
+57
+00:04:21,680 --> 00:04:25,400
+التانى بتسير بسرعة V2 final طبعا و اتجاهات مختلفة
+
+58
+00:04:25,400 --> 00:04:28,900
+بيحكي لنا after the collision both velocity it
+
+59
+00:04:28,900 --> 00:04:31,520
+changedbut the total momentum of the system
+
+60
+00:04:31,520 --> 00:04:36,740
+remains the same السرعات بتختلف لكن ال total
+
+61
+00:04:36,740 --> 00:04:42,100
+momentum للنظام كله بيبقى ثابت remain the same
+
+62
+00:04:42,100 --> 00:04:47,040
+ليجيلا اللي اللي هي ال impulse ال F في Delta T
+
+63
+00:04:47,040 --> 00:04:52,970
+اللي هي Delta P بيساوي ال M1 في V1 finalناقص M2 في
+
+64
+00:04:52,970 --> 00:04:59,290
+V2 a final likewise هذا طبعا بشبه الكلام ل M2 يعني
+
+65
+00:04:59,290 --> 00:05:03,380
+ممكن انا اللي انا طبقته على M1 اطبقه ل M2بنلاحظ أن
+
+66
+00:05:03,380 --> 00:05:12,740
+F1 F2 F1 F2 F1 F2 F1 F2 F1 F2 F1
+
+67
+00:05:12,740 --> 00:05:14,900
+F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2
+
+68
+00:05:14,900 --> 00:05:14,980
+F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2
+
+69
+00:05:14,980 --> 00:05:15,240
+F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2
+
+70
+00:05:15,240 --> 00:05:15,240
+F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2
+
+71
+00:05:15,240 --> 00:05:15,240
+F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2
+
+72
+00:05:15,240 --> 00:05:23,040
+F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2 F2
+
+73
+00:05:24,500 --> 00:05:28,600
+خلال عملية اتصاده ال F12 هي عبارة عن ال average
+
+74
+00:05:28,600 --> 00:05:33,580
+force يعني هي عبارة عن ال M1 أثرت على M2 خلال
+
+75
+00:05:33,580 --> 00:05:39,020
+اتصاده طبعا هذا الكلام بينطبخ على او بيجي يعني
+
+76
+00:05:39,020 --> 00:05:44,420
+بنستحضر قانون نيوتن التالت انه لكل فعل ردفع
+
+77
+00:05:44,420 --> 00:05:48,140
+المساوئله بالمقدار ومضادله بالاتجاه نيوتن ثايرد
+
+78
+00:05:48,140 --> 00:05:51,760
+لاو stated that at all time these two forces are
+
+79
+00:05:51,760 --> 00:05:54,540
+equal in magnitude and opposite in directionإن
+
+80
+00:05:54,540 --> 00:05:59,520
+القوة F21 بدها تساوي نفس القوة F12 ولكن مختلفة في
+
+81
+00:05:59,520 --> 00:06:05,960
+الاتجاه يعني هذا يعني بيأكد قانون نيوتن التالت
+
+82
+00:06:05,960 --> 00:06:12,220
+كمان القوتين بتتصرفوا بنفس ال interval time يعني
+
+83
+00:06:12,220 --> 00:06:16,600
+the two forces act over the same time interval as
+
+84
+00:06:16,600 --> 00:06:21,680
+a result we have وبالتالي F12 Delta T بيساوي ناقص
+
+85
+00:06:21,680 --> 00:06:28,980
+F12 Delta Tيعني F21 هي نفسها F12 لكن بالسالب إذا
+
+86
+00:06:28,980 --> 00:06:32,440
+لو عوضت أنا بال .. بالنسبة لهذه قيمة هذه بساوي
+
+87
+00:06:32,440 --> 00:06:38,180
+ناقص قيمة هذه إذا M1 V1 final ناقص M1 V1 initial
+
+88
+00:06:38,180 --> 00:06:43,780
+ساوي ناقص M2 V2 final ناقص M2 V2 initial هذه
+
+89
+00:06:43,780 --> 00:06:47,320
+المعادلة ممكن إحنا نعيدها بترتيبة معينة لو منعيدها
+
+90
+00:06:47,320 --> 00:06:52,240
+بترتيبة معينة بيكون عندنا M1 V1 initialزاد M2V2
+
+91
+00:06:52,240 --> 00:06:56,000
+initial بيساوي M1V1 final زاد M2V2 final معناه
+
+92
+00:06:56,000 --> 00:07:00,660
+الكلام انه كمية التحرك قبل بيساوي كمية التحرك بعد
+
+93
+00:07:00,660 --> 00:07:04,380
+طبعا هذه النتيجة بيسموها result special case يعني
+
+94
+00:07:04,380 --> 00:07:07,940
+حالة خاصة لقانون اللي هو conservation of momentum
+
+95
+00:07:07,940 --> 00:07:12,320
+قانون حفظ كمية التحركand is it true of isolated
+
+96
+00:07:12,320 --> 00:07:18,240
+set وهي صحيحة لأنظمة اللي هي المعزولة و تحتوي اي
+
+97
+00:07:18,240 --> 00:07:23,060
+تحتوي على يعني اي عدد من اللي هي الأجسام هنا عشان
+
+98
+00:07:23,060 --> 00:07:27,160
+عندنا اتنين فهي طبعا لا الأولى ولا التانية في ال
+
+99
+00:07:27,160 --> 00:07:32,250
+initial ولا التانية في ال finalWhen مافي قوة
+
+100
+00:07:32,250 --> 00:07:36,470
+خارجية مؤثرة على النظام أو ال system كله فال total
+
+101
+00:07:36,470 --> 00:07:39,350
+momentum of the system remains constant in time
+
+102
+00:07:39,350 --> 00:07:45,170
+there is when there is no external force معناها ان
+
+103
+00:07:45,170 --> 00:07:52,070
+ال B initial بتساوي ال B final لإن ال F اللي هي ال
+
+104
+00:07:52,070 --> 00:07:55,230
+force ال external force بتساوي Zero نيجي ل
+
+105
+00:07:55,230 --> 00:08:01,290
+application تطبيق بيرجيالتطبيق بيولوجي هذا التطبيق
+
+106
+00:08:01,290 --> 00:08:04,570
+طبعا هو عبارة عن اسمه ال conservation momentum and
+
+107
+00:08:04,570 --> 00:08:10,150
+speed propulsion يعني ممكن نحكي عنه انه اللي هي
+
+108
+00:08:10,150 --> 00:08:14,520
+كمية التحرك ال conservation حفظ كمية التحركand
+
+109
+00:08:14,520 --> 00:08:20,100
+squid propulsion يعني دفع بيسموه دفع يعني الحبار
+
+110
+00:08:20,100 --> 00:08:23,820
+زي ما هو يعني كمثال أنه بيبدأ من تحت و بينطلق إلى
+
+111
+00:08:23,820 --> 00:08:27,840
+أعلى بيسموه دفع الحبار يعني زي النوع من الأنواع
+
+112
+00:08:27,840 --> 00:08:31,860
+اللي هي ال .. ال .. الأسماك اللي بتعيش في الميه
+
+113
+00:08:31,860 --> 00:08:37,980
+بيكون مثلا في منطقة سفلة و يندفع فجأة إلى أعلى
+
+114
+00:08:37,980 --> 00:08:43,850
+طبعا هذا مثالdefining the isolated system لو احنا
+
+115
+00:08:43,850 --> 00:08:49,130
+عرفنا النظام المعزول هذا تعريفه مهم جدا لتطبيق
+
+116
+00:08:49,130 --> 00:08:52,190
+اللي هي ال conservation اللي هو حفظ الحفظ يعني او
+
+117
+00:08:52,190 --> 00:08:55,270
+قانون حفظ الكمية التحرك او قانون الحفظ
+
+118
+00:08:55,270 --> 00:08:59,450
+cheerleaders jumping aboard from lists might
+
+119
+00:08:59,450 --> 00:09:02,690
+appear to violate conservation of momentum احدى
+
+120
+00:09:02,690 --> 00:09:07,510
+المشجعات يعني طبعا احدى المشجعات يعني هي بنت سيدة
+
+121
+00:09:07,830 --> 00:09:12,430
+قفزت فجأة وكانت في حالة rest قفزت فجأة إلى أعلى
+
+122
+00:09:12,430 --> 00:09:17,910
+قفزت فجأة إلى أعلى من السكون طبعا قفزها إلى أعلى
+
+123
+00:09:17,910 --> 00:09:23,030
+من السكون بيكسر قاعدة اللي هي حفظ التحرك قاعدة
+
+124
+00:09:23,030 --> 00:09:28,570
+كمية التحرك او الزخم ليش؟ لإن ال momentum is zero
+
+125
+00:09:28,570 --> 00:09:31,150
+لأن في البداية كمية التحرك اللي كانت zero كانت هي
+
+126
+00:09:31,150 --> 00:09:36,690
+at rest وفجأة تركت مكانها أو تركت الأرضو اتحركت
+
+127
+00:09:36,690 --> 00:09:41,010
+بسرعة اللي هي V The flaw in this reasoning lies in
+
+128
+00:09:41,010 --> 00:09:44,010
+the fact that career isn't as isolated setting
+
+129
+00:09:44,010 --> 00:09:47,870
+طبعا في هذه الحالة في البداية كانت هي في حالة سكون
+
+130
+00:09:47,870 --> 00:09:54,630
+و قيمة التحرك لها Zero و فجأة اتحركت بسرعة V طبعا
+
+131
+00:09:54,630 --> 00:10:01,940
+سبب هذا اللي بيصير هو انه .. انه يعنيإنه هذا
+
+132
+00:10:01,940 --> 00:10:06,200
+النظام the flow is this reasoning هذا سبب ذلك هو
+
+133
+00:10:06,200 --> 00:10:11,540
+إنه هذه السيدة يعني لا تخضع لنظام اللي هو النظام
+
+134
+00:10:11,540 --> 00:10:15,920
+معزوم isolated ليش؟ لإن خلال قفزها اتأثرت بقوة
+
+135
+00:10:15,920 --> 00:10:20,040
+الجاذبية طبعا ال isolated system عشان نحكي إن هو
+
+136
+00:10:20,040 --> 00:10:23,840
+هذا isolated system لازم يكون عندي مافي أي قوة
+
+137
+00:10:23,840 --> 00:10:27,100
+خارجيةلكن هنا في عندى أنا قوة خارجية و هي قوة
+
+138
+00:10:27,100 --> 00:10:31,960
+الجاذبية هلقان هى السيدة عندما قفزت من الأرض إلى
+
+139
+00:10:31,960 --> 00:10:37,760
+أعلى طبعا صار عندى صار عندنا غيرت كمية التحرك
+
+140
+00:10:37,760 --> 00:10:42,940
+الخاصة ب .. بالأرض ال is not as ولا تتحكينا in
+
+141
+00:10:42,940 --> 00:10:46,420
+jumping she exceeds downward force on earth it
+
+142
+00:10:46,420 --> 00:10:49,720
+changing is its momentum اتغيرت كمية التحرك للأرض
+
+143
+00:10:49,720 --> 00:10:55,230
+لكن هذا التغيرما بيظهر لنا لإن كتلة الأرض كبيرة
+
+144
+00:10:55,230 --> 00:11:01,330
+كتير فما بيظهر لنا أن الأرض اتأثرت أو طبعا لها
+
+145
+00:11:01,330 --> 00:11:06,030
+سرعة when we define the system to be cheerleader
+
+146
+00:11:06,030 --> 00:11:09,750
+and earth momentum is conserved طبعا إذا احنا
+
+147
+00:11:09,750 --> 00:11:14,190
+عرفنا هذا النظام على أساس أن السيدة مع الأرض
+
+148
+00:11:14,190 --> 00:11:18,440
+لحالهم بدونقوة الجاذبية ممكن أسميه conserve لكن
+
+149
+00:11:18,440 --> 00:11:23,100
+بوجود قوة الجاذبية ما بنسميه بيصير عندنا non
+
+150
+00:11:23,100 --> 00:11:29,400
+isolated و ليست isolated علشان هيك بسميه في هذا
+
+151
+00:11:29,400 --> 00:11:32,000
+الحال اللي أنا عندي الأن جسمين system من الأرض و
+
+152
+00:11:32,000 --> 00:11:37,080
+من السيدة أو أي شخص قفز من الأرض إلى أعلى بيصير
+
+153
+00:11:37,080 --> 00:11:40,300
+عندي أنا كمية تحرك محفوظة لإن اللي بتفقد و البينت
+
+154
+00:11:40,300 --> 00:11:44,320
+بتكسسه بالأرض أو العكس لكن سرعة الأرض صغيرة كتلتها
+
+155
+00:11:44,320 --> 00:11:47,710
+كبيرة و بالتالةالكمية التحرك هي عبارة عن ال M في V
+
+156
+00:11:47,710 --> 00:11:51,530
+ال initial بتساوي ال final في ال initial كان
+
+157
+00:11:51,530 --> 00:11:55,050
+السكون و ال final كان في عندي طبعا كمية التحرك
+
+158
+00:11:55,050 --> 00:11:58,570
+محفوظة لإنه كتلة الأرض كبيرة الكتلة في السرعة و
+
+159
+00:11:58,570 --> 00:12:02,790
+السيدة كتلتها الصغيرة و سرعتها بتكون كبيرة و
+
+160
+00:12:02,790 --> 00:12:06,110
+بالتالي النظام اللي هو عبارة عن ال cheerleader and
+
+161
+00:12:06,110 --> 00:12:11,050
+the earth is conserved محفوظة نجي ل example ستة
+
+162
+00:12:11,050 --> 00:12:16,660
+تلاتةفي عندي archer stand at rest on frictionless
+
+163
+00:12:16,660 --> 00:12:23,440
+ice رامي سيهم رجل رامي سيهم يقف على أرض تلجية يعني
+
+164
+00:12:23,440 --> 00:12:30,700
+فيها طبعا مافي احتكاك ملساق يعني أملس it is total
+
+165
+00:12:30,700 --> 00:12:35,120
+mass including his paw and giver of a rose is 16
+
+166
+00:12:35,120 --> 00:12:42,700
+kilogram كتلتهكتلته هو مع السهم وجعب السهم 60 كيلو
+
+167
+00:12:42,700 --> 00:12:46,460
+جرام يعني هو والجعب والسهم 60 كيلو جرام الآن if
+
+168
+00:12:46,460 --> 00:12:52,380
+the archer fires إذا كان هو ضرب سهم كتلته 300 طبعا
+
+169
+00:12:52,380 --> 00:12:55,760
+السهم صغير horizontally at 50 متر في الثانية هو
+
+170
+00:12:55,760 --> 00:13:01,440
+ضرب سهم بطريقة أفقية بسرعة 50 متر في الثانية كتلة
+
+171
+00:13:01,440 --> 00:13:05,910
+السهم كانت 300 في اتجاه ال X axiswhat is the
+
+172
+00:13:05,910 --> 00:13:10,630
+subsequent velocity across the .. the ice بده
+
+173
+00:13:10,630 --> 00:13:14,730
+السرعة subsequent اللاحقة across the ice بده سرعته
+
+174
+00:13:14,730 --> 00:13:19,990
+هو المتأثرة بعد ما ضرب السهم سرعة اللي هي الرجل
+
+175
+00:13:19,990 --> 00:13:24,030
+بعد ما ضرب السهم طبعا لكل فعل رد فعل زي ما حكينا
+
+176
+00:13:24,030 --> 00:13:28,580
+هو ضرب سهم وبالتالي هيتأثرidentical around at the
+
+177
+00:13:28,580 --> 00:13:31,660
+same speed relative to the ground but at an angle
+
+178
+00:13:31,660 --> 00:13:33,060
+of 30 above the horizontal
+
+179
+00:13:42,870 --> 00:13:46,090
+بعدين في فيلم دا C طالب estimate the average
+
+180
+00:13:46,090 --> 00:13:48,530
+normal force acting on the archer as the second
+
+181
+00:13:48,530 --> 00:13:51,570
+row is accelerated by the post starting assuming a
+
+182
+00:13:51,570 --> 00:13:55,230
+drawing بده طبعا ال average normal force الخاصة
+
+183
+00:13:55,230 --> 00:13:58,830
+بهذا رمى السهم زى ما احنا شايفين في البداية رمى
+
+184
+00:13:58,830 --> 00:14:04,390
+السهم رمع سهم horizontally اتجاه ال X axis طبعا
+
+185
+00:14:04,390 --> 00:14:08,730
+كانت كتلته 3 من 100 و رمها بسرعة 50 متر في الثاني
+
+186
+00:14:08,730 --> 00:14:11,650
+مطلوب من سرعة الرجل او سرعة ارتداد الرجل هي
+
+187
+00:14:11,650 --> 00:14:15,530
+بالاحرىFind the arc subsequent velocity across the
+
+188
+00:14:15,530 --> 00:14:19,650
+ice Write أول حاجة طبعا بدنا نستخدم قانون حفظ كمية
+
+189
+00:14:19,650 --> 00:14:23,110
+التحرك Write the conservation of momentum equation
+
+190
+00:14:23,110 --> 00:14:29,110
+for the X direction يعني BX initial بالساوية BX
+
+191
+00:14:29,110 --> 00:14:35,280
+finalالـ B طب أفرض أن M1 و V1 لقوا الرجل Archer
+
+192
+00:14:35,280 --> 00:14:40,080
+Mass اللي هي عبارة عن كتلته و سرعته after firing
+
+193
+00:14:40,080 --> 00:14:44,120
+the arrow irrespective land M2 and V2 the arrow
+
+194
+00:14:44,120 --> 00:14:49,580
+mass and velocity طبعا هذه M1 و M2 قبل ما يضرب
+
+195
+00:14:49,580 --> 00:14:54,680
+السهم و M2 و V2 قبل بعد ما ضرب السهمboth
+
+196
+00:14:54,680 --> 00:14:57,660
+velocities are in the X direction كلا السرعتين بال
+
+197
+00:14:57,660 --> 00:15:02,320
+X direction هطبق قانون ال B-initial و B-final B
+
+198
+00:15:02,320 --> 00:15:06,740
+-initial كانوا rest سواء الرجل أو السهم ال final
+
+199
+00:15:06,740 --> 00:15:14,620
+M1 V1 final و M2 V2 final solve يعني هذه بتمثل
+
+200
+00:15:14,620 --> 00:15:22,060
+الرجل وهذه بتمثل السهم فبده حل بالنسبة ل V1 final
+
+201
+00:15:22,060 --> 00:15:28,290
+بده اوجدهاM1 كانت 59.97 مُعطَى M2 كانت 0.03
+
+202
+00:15:28,290 --> 00:15:34,050
+kilogram V2 final كانت 50 متر في الثانية إذن هعود
+
+203
+00:15:34,050 --> 00:15:41,750
+في هذا القانون M1 59.97 V1 مجهولة M2 كانت 0.03
+
+204
+00:15:41,750 --> 00:15:46,110
+أسرعت V2 كانت 50 إذن V1 final هتطلع بالدروجة هتطلع
+
+205
+00:15:46,110 --> 00:15:49,990
+بالسالب لإنه لكل فعل رد فعلهيكون بسالب ال X-axis
+
+206
+00:15:49,990 --> 00:15:54,510
+لإنه رمى السهم باتجاه ال .. ال .. باتجاه ال X-axis
+
+207
+00:15:54,510 --> 00:15:58,750
+الموجب طبعا بطلع عندي V1 final 25 من الف يعني
+
+208
+00:15:58,750 --> 00:16:02,730
+صغيرة كتير صغيرة كتير لإن كتلة الرجل أكبر من كتلة
+
+209
+00:16:02,730 --> 00:16:06,830
+السهم السهم كتلته صغيرة فبتطلع سرعته كبيرة لإن ال
+
+210
+00:16:06,830 --> 00:16:12,140
+M في V مقدار ثابتنجلا بي calculate the archer
+
+211
+00:16:12,140 --> 00:16:15,340
+velocity after he fires a second arrow at an angle
+
+212
+00:16:15,340 --> 00:16:18,860
+30 درجة above the horizontal مطلوب إن نجد أيضا
+
+213
+00:16:18,860 --> 00:16:24,840
+سرعة هذا الراجل رام السيها بعد ما رام السهم لكن
+
+214
+00:16:24,840 --> 00:16:29,120
+رام السهم الثاني الآن بزاوية 30 درجة أعلى ال
+
+215
+00:16:29,120 --> 00:16:34,120
+horizontal هاكتب بالنسبة للمومنتع بال X axis و بال
+
+216
+00:16:34,120 --> 00:16:40,130
+Y axis هاكتبها يعني بالنسبة لل two dimensionsالان
+
+217
+00:16:40,130 --> 00:16:45,390
+بعد ما الراجل ضرب السهم طبعا الكتلة قلت كتلته فنجي
+
+218
+00:16:45,390 --> 00:16:49,250
+نحل الان P initial بساوي P final ال initial هو في
+
+219
+00:16:49,250 --> 00:16:52,510
+البداية طبعا هو ابدا اعتبر انه هادا النقطة اللي
+
+220
+00:16:52,510 --> 00:16:55,670
+انتهى عندها هي البداية ف V ايه هتكون V واحد
+
+221
+00:16:55,670 --> 00:17:01,590
+initial هي نفسها اللي هي ال 25 من الف وبالتالي
+
+222
+00:17:01,590 --> 00:17:08,840
+عوضت عنها M1 في V واحد initial موجودةM1 ناقص M2
+
+223
+00:17:08,840 --> 00:17:17,540
+لإن هو طبعا في يعني طبعا فقد هو جزء من ال .. من ال
+
+224
+00:17:17,540 --> 00:17:22,860
+.. الكتلة بدل ما أحكي M1 V1 final لإنه كان عنده M1
+
+225
+00:17:22,860 --> 00:17:28,540
+كانت هي 60 ناقص اللي هي 3 من 100 وبالتالي صار
+
+226
+00:17:28,540 --> 00:17:34,280
+عندنا كتلة جديدة نتيجة إنه فقد سهم دل عنده مجموعة
+
+227
+00:17:34,280 --> 00:17:41,370
+السهم زائد كتلتهM2 V2 final cos θ طبعا احنا أخدنا
+
+228
+00:17:41,370 --> 00:17:46,170
+ال X axis هذه فلما أجى أحلل ال V final كانت بزاوية
+
+229
+00:17:46,170 --> 00:17:50,250
+30 هكون عندي في ال X axis cos θ V2 final cos θ
+
+230
+00:17:50,250 --> 00:17:59,530
+باتجاه ال Y هتكون V2 final sin θ طبعا بنعود من
+
+231
+00:17:59,530 --> 00:18:06,610
+خلال هذا القانون عشان أوجد ال V1 finalV1 initial
+
+232
+00:18:06,610 --> 00:18:11,530
+هي نفسها اللي إحنا انتهينا منها M1 اللي هي كتلة
+
+233
+00:18:11,530 --> 00:18:20,350
+الرجل هيها M1-M2 احنا حكينا 59.97-0.03 تطلع هذه
+
+234
+00:18:20,350 --> 00:18:24,670
+الكتلة بعد مرمى السهم الأول M2 هي موجودة اللي هي
+
+235
+00:18:24,670 --> 00:18:29,050
+كتلة السهم على الكتلة الكلية بعد مرتمى السهم في V2
+
+236
+00:18:29,050 --> 00:18:33,660
+final اللي كانت 50في كوزاين التلاتين بطلع معايا V1
+
+237
+00:18:33,660 --> 00:18:38,820
+final طبعا point O أربع ستة سبعة متر في الثاني هذه
+
+238
+00:18:38,820 --> 00:18:43,360
+كتلته بعد مرام السهم بزاوية تلاتين أفوان سرعته بعد
+
+239
+00:18:43,360 --> 00:18:49,660
+مرام السهم بزاوية تلاتين درجة و بسرعة خمسين في C
+
+240
+00:18:49,660 --> 00:18:53,740
+هكلنا estimate the average normal force مطلوب من
+
+241
+00:18:53,740 --> 00:18:59,380
+أن نجد قوة قوة رد الفعل عمودية المؤثرة على هذا
+
+242
+00:18:59,380 --> 00:19:03,400
+الرجلas the arrow is accelerated by the power
+
+243
+00:19:03,400 --> 00:19:09,060
+stirring حيث انه السهم هذا طبعا اتعصق .. طبعا
+
+244
+00:19:09,060 --> 00:19:13,880
+السهم هذا اتسارع بواسطة ال water طبعا اللي هو
+
+245
+00:19:13,880 --> 00:19:17,460
+موجود معاه اللي هو ال water اللي طبعا المربوط فيه
+
+246
+00:19:17,460 --> 00:19:21,810
+اللي اسمه power stirringهيستخدم انا الكيناماتيك in
+
+247
+00:19:21,810 --> 00:19:24,650
+one dimensions واسمية ده acceleration بدأ اوجد ال
+
+248
+00:19:24,650 --> 00:19:28,590
+acceleration لان طبعا قبل ما اوجد ال acceleration
+
+249
+00:19:28,590 --> 00:19:33,830
+لازم اوجد بدنا نوجد الآن السرعه قبل السرعه او
+
+250
+00:19:33,830 --> 00:19:39,030
+التسارع عفوا عشان نوجد التسارع فبستخدم هذا القانون
+
+251
+00:19:39,030 --> 00:19:43,650
+V تربيع بالثوابين وتربيع زاد اتنين A Delta X بدأ
+
+252
+00:19:43,650 --> 00:19:46,390
+احلى ال acceleration واعوض عن V بالثوابين V اتنين
+
+253
+00:19:46,390 --> 00:19:52,000
+finalف to find the final velocity of the arrow is
+
+254
+00:19:52,000 --> 00:19:58,100
+طبعا جيبنا احنا ال final velocity كانت zero V
+
+255
+00:19:58,100 --> 00:20:01,160
+naught تربية عفوا zero و ال V2 final كانت اللي هي
+
+256
+00:20:01,160 --> 00:20:06,780
+الخمسين هذا بالنسبة للسهم دوجة تسارع السهم اللي هي
+
+257
+00:20:06,780 --> 00:20:09,680
+على اتنين دلتا X حكيلنا انه في السؤال انها مشيت
+
+258
+00:20:09,680 --> 00:20:13,860
+مسافة بعد ما تمشي مسافة point تمانية متر او تمانين
+
+259
+00:20:13,860 --> 00:20:18,570
+صنطةبعد هيك طالع find the time of the row
+
+260
+00:20:18,570 --> 00:20:22,210
+accelerating using احنا بعد ما جيبنا ال .. طبعا
+
+261
+00:20:22,210 --> 00:20:27,570
+التسارع بدأ اوجد الزمن V2 final ناقص V0 على A من
+
+262
+00:20:27,570 --> 00:20:31,970
+خلال قانون .. من قوانين الحركة V بالساوي V0 زايد
+
+263
+00:20:31,970 --> 00:20:36,470
+AT اذا T بالساوي V2 final ناقص V0 على A V2 كانت
+
+264
+00:20:36,470 --> 00:20:39,350
+V50 فعلا V0 Zero و ال acceleration جيبناها من
+
+265
+00:20:39,350 --> 00:20:44,110
+المطلوب الأول فبطلع عند الزمن 32 من 1000 A ثانية
+
+266
+00:20:44,900 --> 00:20:48,120
+الان بدنا نجد اللى هو ال V average اللى هى ال
+
+267
+00:20:48,120 --> 00:20:50,860
+normal force ال V average فانا جبت الزمن بتجاه ال
+
+268
+00:20:50,860 --> 00:20:56,660
+X axis و هستخدمه لل Y طبعا زمن X هو نفسه زمن Y
+
+269
+00:20:56,660 --> 00:21:00,080
+احنا بدنا قوة رد الفعل بسميها ال F average اللى هى
+
+270
+00:21:00,080 --> 00:21:04,730
+بتجاه ال Y Delta T بسوا Delta BYdelta by هي ال M
+
+271
+00:21:04,730 --> 00:21:09,090
+في V2 final sin θ على delta T فبنجيب V average
+
+272
+00:21:09,090 --> 00:21:15,550
+باتجاه اللي هي ال Y axis هيها بتساوي اللي هي ال M2
+
+273
+00:21:15,550 --> 00:21:18,690
+هذا كله للسهم وينتقل تلاتة في خمسين في sin
+
+274
+00:21:18,690 --> 00:21:21,730
+التلاتين على اللي هي delta T اللي احنا طلعناها من
+
+275
+00:21:21,730 --> 00:21:28,470
+الجزئية الأولى بعد هيك ال average normal force is
+
+276
+00:21:28,470 --> 00:21:30,910
+given by the pressure weight plus the reaction
+
+277
+00:21:30,910 --> 00:21:35,840
+forceطبعا السهم لما يرتمى هيكون فيه عندنا ردة فعل
+
+278
+00:21:35,840 --> 00:21:39,440
+اسمها R reaction force of the around السهم يعني
+
+279
+00:21:39,440 --> 00:21:43,160
+السهم إذا طلع إلى أعلى هيكون باتجاه ال Y-axis طبعا
+
+280
+00:21:43,160 --> 00:21:48,340
+لما احنا حللنا في عندي قوة رد فعل باتجاه ال Y و
+
+281
+00:21:48,340 --> 00:21:51,680
+هيتأثر في عندي أنا طبعا هو طلع إلى أعلى هتكون قوة
+
+282
+00:21:51,680 --> 00:21:55,740
+رد الفعل إلى أسفل وبالتالي لما نيجي نعمل المعادلة
+
+283
+00:21:55,740 --> 00:21:59,450
+summation لل FY بالساول N ناقص MG ناقص ال Rالان
+
+284
+00:21:59,450 --> 00:22:03,790
+هتكون موجبة باتجاه ال y axis الموجبة و ال MG لتحت
+
+285
+00:22:03,790 --> 00:22:07,650
+و ال R هي قوة رد الفعل اللي هي بعد ما يرتمع الأعلى
+
+286
+00:22:07,650 --> 00:22:10,230
+هيكون في عنده قوة رد الفعل الأسفل وبالتالي ناقص R
+
+287
+00:22:10,230 --> 00:22:15,250
+اذا ال normal بيساوي ال MG زائد ال R وبالتالي بوجد
+
+288
+00:22:15,250 --> 00:22:20,210
+هنا قوة رد الفعل العمودية اللتي سببها هذا السهم
+
+289
+00:22:20,210 --> 00:22:24,430
+لهذا الشخص من خلال طبعا رميه لهذا السهم
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/MfYemOPI8-U_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/MfYemOPI8-U_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..89524cb9225de96616736b2cd1ba8525835c96e2
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/MfYemOPI8-U_postprocess.srt
@@ -0,0 +1,1204 @@
+1
+00:00:00,000 --> 00:00:06,060
+بسم الله الرحمن الرحيم هنتابع مع بعض quiz الاتنين
+
+2
+00:00:06,060 --> 00:00:11,220
+تلاتة ال quiz بيحكي اللي في عندي أنا تلت أجزاء A
+
+3
+00:00:11,220 --> 00:00:16,660
+وB وC كما هو موضح بالشكل أدناه هدول التلت أشكال
+
+4
+00:00:16,660 --> 00:00:24,940
+بمثله تلت ال graphs تلت أشكالمنحنيات للسرعة of
+
+5
+00:00:24,940 --> 00:00:28,820
+different objects moving in a straight يعني سرعة
+
+6
+00:00:28,820 --> 00:00:35,140
+جسم بتحرك بخط مستقيم وبعدين بتحرك بخط path as a
+
+7
+00:00:35,140 --> 00:00:38,870
+function of T بخط كده اللي في الزمنوكمان الـ
+
+8
+00:00:38,870 --> 00:00:42,690
+possible acceleration of each object as a function
+
+9
+00:00:42,690 --> 00:00:47,070
+of time are shown in part الآن الأجزاء التلاتة D
+
+10
+00:00:47,070 --> 00:00:53,370
+وE وF تمثل احتمالية اللي هي التسارع بالنسبة للزمن
+
+11
+00:00:53,370 --> 00:00:56,710
+المطلوب من ال match each velocity versus time
+
+12
+00:00:56,710 --> 00:00:59,570
+graph with acceleration versus time graph that
+
+13
+00:00:59,570 --> 00:01:04,250
+best describe the motion بيحكي لنا وصل من الأشكال
+
+14
+00:01:04,250 --> 00:01:09,590
+المناسبة تتناسب مع مثلتهاحيث إن الأشكال الأولى A
+
+15
+00:01:09,590 --> 00:01:15,170
+وB وC تمثل علاقة الـV مع الـT العلاقة الأولى خط
+
+16
+00:01:15,170 --> 00:01:18,550
+مستقيم والعلاقة التانية منحنة علاقة بين V وT
+
+17
+00:01:18,550 --> 00:01:22,510
+والعلاقة التالتة خط مستقيم وبعدين مقدار ثابت علاقة
+
+18
+00:01:22,510 --> 00:01:27,210
+بينهم V وT الآن عندي تلاتة A وB وC تلت أشكال مطلوب
+
+19
+00:01:27,210 --> 00:01:32,760
+منها نوصلهمبالـ 3 أشكال اللي تحت بيمثله علاقة بين
+
+20
+00:01:32,760 --> 00:01:36,600
+الـ A و بين الـ T بين الـ A و بالـ T و بين الـ A و
+
+21
+00:01:36,600 --> 00:01:42,330
+T الأن للشكل الأول لو جينا للشكل الأولالشكل الأول
+
+22
+00:01:42,330 --> 00:01:46,610
+علاقة بين ال .. الشكل الأول زي ما أحنا شايفين
+
+23
+00:01:46,610 --> 00:01:52,870
+علاقة بين ال .. ال V و ال T علاقة بين ال V و ال T
+
+24
+00:01:52,870 --> 00:01:57,610
+و بالتالي لما بده أوجد أنا التسارع فالتسارع
+
+25
+00:01:57,610 --> 00:02:02,570
+بالمنطقة هذه عشان هذه خط مستقيم هيكون عندي التسارع
+
+26
+00:02:02,570 --> 00:02:06,510
+ثابت لكل الخط المستقيم لو إجيت أختار مين الشكل
+
+27
+00:02:06,510 --> 00:02:10,270
+المناسبلو إجيت أنا للشكل هذا، هذا علاقة بين الـV
+
+28
+00:02:10,270 --> 00:02:15,030
+وT، بين الـA وT، فالعلاقة هنا ترضية، يعني كل ما
+
+29
+00:02:15,030 --> 00:02:17,850
+تزيد الـA بتزيد الـT وها كده، وليس مقدار ثابت، بدي
+
+30
+00:02:17,850 --> 00:02:23,390
+أبحث عن شكل يمثل الـA وT كمقدار ثابت، فبلاحظ أن
+
+31
+00:02:23,390 --> 00:02:27,870
+الـV، الشكل الأول، علاقة بين الـV وT بيمثله الشكل
+
+32
+00:02:27,870 --> 00:02:31,290
+هذااللي هو الـ E علاقة بين الـ A و T، هذا مقدار
+
+33
+00:02:31,290 --> 00:02:34,890
+ثابت، يعني لو أنا جيبت .. أجيبت التسارع في أي نقطة
+
+34
+00:02:34,890 --> 00:02:40,150
+على هذا الخط، بأجده مقدار A ثابت، معنى الكلام، بدي
+
+35
+00:02:40,150 --> 00:02:45,490
+أوصل، بتطلع إن الـ A في الشكل هذا A B C D E، هنا
+
+36
+00:02:45,490 --> 00:02:51,410
+الـ F، A مع الـ F، تمام؟ نجرى الشكل B، الشكل B هذا
+
+37
+00:02:51,410 --> 00:02:56,660
+منحنى،المنحنة هذا علاقة بين ال V و ال T علاقة بين
+
+38
+00:02:56,660 --> 00:03:00,140
+ال V و ال T لما اوجد انا ال instantaneous
+
+39
+00:03:00,140 --> 00:03:05,480
+acceleration في هذا المنحنة باخد نقطة و بعدين باخد
+
+40
+00:03:05,480 --> 00:03:08,600
+اللي هو ميل المماس لهذا النقطة باجد ان ميل المماس
+
+41
+00:03:08,600 --> 00:03:13,060
+هيكون موجة بهذا الشكل فمعنى الكلام ال B بوصلها
+
+42
+00:03:13,060 --> 00:03:18,100
+بهذا الشكلبالنسبة للشكل التالت علاقة بين ال V و T
+
+43
+00:03:18,100 --> 00:03:22,780
+في المنطقة المرحلة الأولى ال V و T لما أنا في هو
+
+44
+00:03:22,780 --> 00:03:26,200
+عبارة عن طبعا عند انا اوجد ال acceleration وعندي
+
+45
+00:03:26,200 --> 00:03:30,600
+أنا خط وعبارة عن ميل هذا الخط الميل هذا الخط طبعا
+
+46
+00:03:30,600 --> 00:03:35,440
+ثابت لكل النقاط وبالتالي المنطقة هذه بتمثلها هذه
+
+47
+00:03:35,440 --> 00:03:39,900
+المنطقة ثابتة يعني ال V على T مقدار ثابت مافي
+
+48
+00:03:39,900 --> 00:03:43,880
+تغيير على المنطقة ده وبالتالي التسارع تبقى مقدار
+
+49
+00:03:43,880 --> 00:03:49,320
+ثابت بالشكل هذابعد هيك علاقة ال V والـ T صارت
+
+50
+00:03:49,320 --> 00:03:53,520
+علاقة V على T هنا سفر لأنه مافيش تسارع في المنطقة
+
+51
+00:03:53,520 --> 00:03:57,700
+هذه، إذا ال تسارع V على T بنزلة ال Zero فمعنى
+
+52
+00:03:57,700 --> 00:04:02,180
+الكلام أن الشكل أول A يمثل بهذا الشكل، B يمثل بهذا
+
+53
+00:04:02,180 --> 00:04:05,000
+الشكل وC يمثل بهذا الشكل
+
+54
+00:04:08,060 --> 00:04:14,300
+زي ما هو موضح بالحل الموضح ان انه في عندي انا ال A
+
+55
+00:04:14,300 --> 00:04:18,500
+بيمثله في هذا المنطقة و ال B هو عبارة عن ال D و ال
+
+56
+00:04:18,500 --> 00:04:21,940
+C عبارة عن ال F كما هو موضح بالشكل
+
+57
+00:04:25,610 --> 00:04:32,030
+نجلى example بيحكي لنا example اتنين تلاتة المطلوب
+
+58
+00:04:32,030 --> 00:04:39,390
+مني أوجد طبعا التسارع لحركة particle pass ball a
+
+59
+00:04:39,390 --> 00:04:41,910
+player moves in a straight line path in order to
+
+60
+00:04:41,910 --> 00:04:47,030
+catch a fly ball into to out to the outfield عندي
+
+61
+00:04:47,030 --> 00:04:53,850
+حركة كرات سلةكرة السلة بتتحرك أول حاجة بخط مستقيم
+
+62
+00:04:53,850 --> 00:04:58,830
+حتى تصل إلى طبعا المنطقة اللي هم رمين الكرة فيها
+
+63
+00:04:58,830 --> 00:05:03,030
+طبعا هي بصفة عامة هو مسار لكرة المسار اتحرك بهذا
+
+64
+00:05:03,030 --> 00:05:07,670
+الشكل اتحرك من ال a ل ال b ل ال c مطلوب مني اوجد
+
+65
+00:05:07,670 --> 00:05:12,470
+find its instantaneous acceleration مطلوب مني اوجد
+
+66
+00:05:12,470 --> 00:05:16,770
+ال instantaneous acceleration التسارق اللحظي عند
+
+67
+00:05:16,770 --> 00:05:22,770
+النقطة aو B و C بدا أوجد التسارق اللحظي عند النقطة
+
+68
+00:05:22,770 --> 00:05:28,240
+A و B و Cالان عند النقطة A التسارع اللحظي إذا كان
+
+69
+00:05:28,240 --> 00:05:32,900
+عندي أنا علاقة بين V وT وعندي أنا خط مستقيم
+
+70
+00:05:32,900 --> 00:05:36,380
+فالتسارع اللحظي عند هذه النقطة هو ميل الخط فميل
+
+71
+00:05:36,380 --> 00:05:40,840
+الخط في المنطقة هذه عنده النقطة A هو عبارة عن ميل
+
+72
+00:05:40,840 --> 00:05:44,560
+هذا الخط الميل الخط هو عبارة عن مقابل على مجاور أو
+
+73
+00:05:44,560 --> 00:05:49,000
+تاني الزاوية مقابل على مجاور ممكن أخد النقطة عند A
+
+74
+00:05:49,000 --> 00:05:53,610
+اللي هي الاتنين على واحد بينفعممكن أخد الأربع على
+
+75
+00:05:53,610 --> 00:05:57,110
+الإتنين برضه بتنفع ميل الخط عند كل النقاط مقدار
+
+76
+00:05:57,110 --> 00:06:03,570
+ثابت عند المنطقة B لما بدأ أجي أوجد أنا التسارع
+
+77
+00:06:03,570 --> 00:06:06,630
+اللحظة عند المنطقة B بقى ميل الخط عند المنطقة B
+
+78
+00:06:06,630 --> 00:06:10,470
+صفر، مالوش ميل مع أن الكلام دي V على D تهان مقدار
+
+79
+00:06:10,470 --> 00:06:14,230
+Zero مع أن الكلام ميل الخط لهذا الـ Instantaneous
+
+80
+00:06:14,230 --> 00:06:18,990
+Acceleration بدأ تساوي صفر عند المنطقة B عند
+
+81
+00:06:18,990 --> 00:06:22,950
+المنطقة Cالـ instantaneous acceleration برضه بدأ
+
+82
+00:06:22,950 --> 00:06:28,510
+أوجد ميل الخط عند هذه المنطقة فميل الخط ممكن أحكي
+
+83
+00:06:28,510 --> 00:06:33,410
+أنا المقابل أيضًا على المجاور أو ممكن أجيب اللي هي
+
+84
+00:06:33,410 --> 00:06:37,310
+V هذه منطقة البداية و هذه النهاية معنى الكلام إنه
+
+85
+00:06:37,310 --> 00:06:42,510
+في عندي V final كانت اتنين و V initial أربعة راح
+
+86
+00:06:42,510 --> 00:06:47,890
+نحكي اتنين ناقص أربعة بالنسبة للزمن أربعة ناقص
+
+87
+00:06:47,890 --> 00:06:51,760
+تلاتة بتطلع عندي بالسالب كما هو موضحالحل اللي هو
+
+88
+00:06:51,760 --> 00:06:55,080
+المرفق بالشكل هذا إذا ال instantaneous
+
+89
+00:06:55,080 --> 00:07:00,640
+acceleration عند المنطقة A هي عبارة عن ميل الخط
+
+90
+00:07:00,640 --> 00:07:05,080
+equals the slope of the line إذا delta V ميل الخط
+
+91
+00:07:05,080 --> 00:07:08,520
+هو عبارة عن delta V على delta T ال V النهائية كانت
+
+92
+00:07:08,520 --> 00:07:13,730
+4 والابتدائية 0 على ال 2 ناقص 0بتساوي موجب اتنين
+
+93
+00:07:13,730 --> 00:07:18,490
+لإن الخط ميل جهة اليمين فالاتسار عندي انا موجب او
+
+94
+00:07:18,490 --> 00:07:21,870
+ميل الخط موجب زى ما احنا شايفين بهذا الشكل ميل
+
+95
+00:07:21,870 --> 00:07:24,850
+الخط موجب او ممكن احكي اتنين على واحد بيظبط بتطلع
+
+96
+00:07:24,850 --> 00:07:28,270
+نفس الجواب اتنين على واحد او المنطقة هادى واحد على
+
+97
+00:07:28,270 --> 00:07:32,720
+نص بتطلع نفس الجوابالمنطقة B زي ما احنا شايفين في
+
+98
+00:07:32,720 --> 00:07:37,180
+المنطقة B Delta V بتساوي سفر وبالتالي مافيش تغير
+
+99
+00:07:37,180 --> 00:07:39,760
+في السرعة، السرعة ثابتة إذا Delta V على Delta T
+
+100
+00:07:39,760 --> 00:07:42,900
+أربعة ناقص أربعة على تلاتة ناقص اتنين بيطلع عندي
+
+101
+00:07:42,900 --> 00:07:46,420
+سفر لإنه مافي ميل للخط وبالتالي تسارع اللحظة
+
+102
+00:07:46,420 --> 00:07:51,250
+بيساوي Zeroعند المنطقة C زي ما حكينا هي عبارة عن
+
+103
+00:07:51,250 --> 00:07:53,970
+ميل الخاط اللي هي equals the slope of the line
+
+104
+00:07:53,970 --> 00:07:59,010
+connecting the point بين النقطة 3 و 4 و 4 و 2 إذا
+
+105
+00:07:59,010 --> 00:08:04,190
+ال A بدها تساوي Delta V على Delta T V نهائية كانت
+
+106
+00:08:04,190 --> 00:08:10,000
+2الابتدائية كانت أربعة والنهائية بالنسبة للزمن
+
+107
+00:08:10,000 --> 00:08:13,600
+كانت أربعة والابتدائية تلاتة فبطلع عندي ناقص اتنين
+
+108
+00:08:13,600 --> 00:08:19,120
+زي ما هو موضح بهذا الشكل and المنطقة C هي ده جيب
+
+109
+00:08:19,120 --> 00:08:23,960
+ال mail هو مقابل على مجاور أو المسافة هذه اللي هي
+
+110
+00:08:23,960 --> 00:08:28,540
+عبارة المسافة هذه أربعة ناقص اتنين طبعا الأربعة
+
+111
+00:08:28,540 --> 00:08:33,120
+هذه الابتدائية الاتنين النهائية فبنحكي اللي هي
+
+112
+00:08:33,120 --> 00:08:37,660
+الاتنين ناقص أربعة علىهذه البداية وهذه النهائية
+
+113
+00:08:37,660 --> 00:08:41,800
+أربعة ناقص تلاتة بطلع عندى بالسالب كمان لأو أي خط
+
+114
+00:08:41,800 --> 00:08:47,840
+اتجاهه على اليسار بيكون ميله بالسالب فعلا الجواب
+
+115
+00:08:47,840 --> 00:08:51,580
+بطلع عندى بالسالب اللى هو بساوي ناقص اتنين متر في
+
+116
+00:08:51,580 --> 00:08:57,730
+الثانية تربيعطبعاً بنبدأ موضوع تاني اللي هو عبارة
+
+117
+00:08:57,730 --> 00:09:03,930
+عن section 22 motion diagram اللي هي عبارة عن حركة
+
+118
+00:09:03,930 --> 00:09:08,850
+motion diagram هذا احنا مش هنشرحه اللي هي .. اللي
+
+119
+00:09:08,850 --> 00:09:16,520
+هي الحركة اللي هي curve أو منحنة لحركةمابدناش إياه
+
+120
+00:09:16,520 --> 00:09:22,100
+لكن ممكن نبدأ في section اتنين تلاتة بعنوان one
+
+121
+00:09:22,100 --> 00:09:25,520
+dimensional emotion with constant acceleration
+
+122
+00:09:25,520 --> 00:09:31,820
+الحركة في بعد واحد بتسارع ثابت الحركة في بعد واحد
+
+123
+00:09:31,820 --> 00:09:37,850
+بتسارع ثابتكثير من التطبيقات أو الـ Mechanica
+
+124
+00:09:37,850 --> 00:09:44,830
+تتضمن تتضمن مواضيع
+
+125
+00:09:44,830 --> 00:09:51,930
+تتحرك بتسارع ثابت عندما يتحرك
+
+126
+00:09:51,930 --> 00:09:54,230
+الجسم بتسارع ثابت
+
+127
+00:09:57,850 --> 00:10:03,110
+التسارع اللحظي عند أي نقطة في فترة زمانية T is
+
+128
+00:10:03,110 --> 00:10:06,050
+equal to the value of the average acceleration
+
+129
+00:10:06,050 --> 00:10:13,570
+over the time intervalمعنى الكلام بالفقرة هذه اللي
+
+130
+00:10:13,570 --> 00:10:17,430
+في اللون الأحمر معناها أن أي جسم بتحرك بتسارع ثابت
+
+131
+00:10:17,430 --> 00:10:23,810
+فالتسارع اللحظي عند أي زمن قدرته يساوي التسارع
+
+132
+00:10:23,810 --> 00:10:26,790
+اللي هو اتجاهه أو average acceleration متوسط
+
+133
+00:10:26,790 --> 00:10:31,570
+السرعة اللي متوسط التسارع التسارع اللحظي بساوي
+
+134
+00:10:31,570 --> 00:10:36,670
+متوسط التسارع over the عند تلك الفترةبناء عليه
+
+135
+00:10:36,670 --> 00:10:44,350
+السرعة تزداد أو تقل خلال هذه الحركة وبالتالي
+
+136
+00:10:44,350 --> 00:10:51,990
+السرعة ممكن تزداد أو تقل خلال هذه الحركة ولو احنا
+
+137
+00:10:51,990 --> 00:10:58,250
+رسمنا علاقة بين V و T تعطينا خط مستقيم ممكن يكون
+
+138
+00:10:58,250 --> 00:11:01,910
+خط مستقيم موجة ممكن يكون Zero ممكن يكون ال slope
+
+139
+00:11:01,910 --> 00:11:06,020
+negative زي الرسمة اللي كانت بالسابقلأن الـ
+
+140
+00:11:06,020 --> 00:11:08,500
+Average Acceleration بتساوي الـ Instantaneous
+
+141
+00:11:08,500 --> 00:11:10,960
+Acceleration Acceleration اللي ما يكون تسارع متوسط
+
+142
+00:11:10,960 --> 00:11:15,480
+التسارع يساوي التسارع اللحظي معنى الكلام لما أيه
+
+143
+00:11:15,480 --> 00:11:18,480
+بدها تساوي لما أيه بدها تساوي Zero We can
+
+144
+00:11:18,480 --> 00:11:21,960
+eliminate the part used to denote في هذه الحالة لو
+
+145
+00:11:21,960 --> 00:11:27,880
+أننا فرضنا إنه أو لو كان عندي أنا تسارع ثابتطبعا
+
+146
+00:11:27,880 --> 00:11:30,640
+احنا كنا نكتب التسارع المتوسط التسارع A بالساوية
+
+147
+00:11:30,640 --> 00:11:34,300
+Zero لكن لما تكون التسارع ثابت فالتسارع اللحظي
+
+148
+00:11:34,300 --> 00:11:39,000
+بيساوي التسارع المتوسط التسارع وبالتالي ممكن اكتب
+
+149
+00:11:39,000 --> 00:11:43,260
+ال A average اللي هي متوسط التسارع بده يساوي ال A
+
+150
+00:11:43,260 --> 00:11:48,900
+اللي هي اللحظية فممكن نكتب ان ال A بدها تساوي V
+
+151
+00:11:48,900 --> 00:11:53,830
+finalناقص V initial و T final ناقص T initial يعني
+
+152
+00:11:53,830 --> 00:11:58,770
+رفعنا شرطة ال average لإن ال A average بتساوي ال A
+
+153
+00:11:58,770 --> 00:12:02,550
+ال constant acceleration زي ما اتفقنا إن أنا بدي
+
+154
+00:12:02,550 --> 00:12:07,030
+أوجد معادلات الحركة في بعد واحد عندما يكون التسارع
+
+155
+00:12:07,030 --> 00:12:12,770
+ثابت كمان بدي أفرض إن T initial هذه بتساوي سفر لما
+
+156
+00:12:12,770 --> 00:12:17,310
+أنا تكون عندي ال T initial عند سرعة ابتدائي أو
+
+157
+00:12:17,310 --> 00:12:22,480
+بداية الحركةكمان بدي افرض ان V initial هي بتساوي V
+
+158
+00:12:22,480 --> 00:12:27,380
+naught لي تمثل السرعة عند T بتساوي صفر V naught
+
+159
+00:12:27,380 --> 00:12:31,820
+يعني عند T بتساوي صفر كمان بدي افرض ان T final
+
+160
+00:12:31,820 --> 00:12:36,540
+اسميها T لان هي عبارة عن انت صار عند لحظة زمنية
+
+161
+00:12:36,540 --> 00:12:41,260
+اسمها T او لحظة بتساوي T و V final هياللي هي عبارة
+
+162
+00:12:41,260 --> 00:12:46,780
+عن الـ V السرعة النهائية عند أي زمان قدرتي معنى
+
+163
+00:12:46,780 --> 00:12:49,680
+الكلام القانون الأساسي اللي كان عند ال A average
+
+164
+00:12:49,680 --> 00:12:54,080
+بتساوي V final ناقص V initial على T final ناقص T
+
+165
+00:12:54,080 --> 00:12:59,080
+initial غيرت فيه شوية فرضت لإنه انا عندي شرط إنه
+
+166
+00:12:59,080 --> 00:13:03,740
+تسارع ثابت إذا ال A average صارت A V final صارت V
+
+167
+00:13:03,740 --> 00:13:09,400
+V initial صارت V naught وT initial سفر راحتT final
+
+168
+00:13:09,400 --> 00:13:15,220
+صارت T من خلال هذه المعادلة ممكن أنا أكتب بهذا
+
+169
+00:13:15,220 --> 00:13:18,960
+الشكل ال A average صارت A V final صارت V V initial
+
+170
+00:13:18,960 --> 00:13:22,640
+صارت V not و T final صارت T not و T ال initial
+
+171
+00:13:22,640 --> 00:13:27,460
+zero راحت من خلال هذه المعادلة بأوجد أول قانون من
+
+172
+00:13:27,460 --> 00:13:31,980
+قوانين الحركة بخط مستقيم طبعا حيصير عندي أنا لو
+
+173
+00:13:31,980 --> 00:13:37,760
+أضرب ضرب تبادليهيصير عندى انا v ناقص v not بتساوي
+
+174
+00:13:37,760 --> 00:13:43,820
+at او v بتساوي v not زائد at هذا الكلام هو قانون
+
+175
+00:13:43,820 --> 00:13:49,640
+الاول لمعادلات الحركة الخطية ببعد واحد تسارع ثابت
+
+176
+00:13:49,640 --> 00:13:54,550
+اسمه a at constant a او for constant aيعني لو
+
+177
+00:13:54,550 --> 00:13:57,690
+أخدنا مثال على هذا القانون إذا كانت عندي سيارة if
+
+178
+00:13:57,690 --> 00:14:03,490
+a car starts عندي أنا سيارة بتتحرك بسرعة اتنين
+
+179
+00:14:03,490 --> 00:14:08,530
+موجبة متر في الثاني لليمين وبتسارع لليمين برضه أيه
+
+180
+00:14:08,530 --> 00:14:13,230
+بتساوي ستة متر في الثاني تربيع it will have the
+
+181
+00:14:13,230 --> 00:14:16,690
+velocity of اربعة عشر متر بعد زمن قدر اتنين معنى
+
+182
+00:14:16,690 --> 00:14:19,950
+الكلامعند تطبيق هذا القانون أنا بحتاج سرعة
+
+183
+00:14:19,950 --> 00:14:25,870
+ابتدائية أو سرعة نهائية تسارع زمن طبعا هنا احنا
+
+184
+00:14:25,870 --> 00:14:30,050
+مطلوب مني اوجد السرعة النهائية فالسؤال حكى لو كان
+
+185
+00:14:30,050 --> 00:14:34,950
+عند سرعة ابتدائية اتنين تسارع كان تسارع كان ستة
+
+186
+00:14:34,950 --> 00:14:42,790
+والزمن كان قدره اتنين فممكن احله من خلال القانونv0
+
+187
+00:14:42,790 --> 00:14:47,310
+كانت اتنين ال a بعوض عنها ستة و ال t بعوض عنها
+
+188
+00:14:47,310 --> 00:14:51,230
+باتنين فبتطلع عند السرعة النهائية بتساوي موجة
+
+189
+00:14:51,230 --> 00:14:56,970
+باربعتاشر متر في الثاني لإنه السرعة ال velocity is
+
+190
+00:14:56,970 --> 00:15:00,950
+increase because the velocity is increasing or
+
+191
+00:15:00,950 --> 00:15:06,090
+decreasing uniformly with timeWe can express V هذا
+
+192
+00:15:06,090 --> 00:15:09,630
+طبعا الكلام احنا أخدناه لما يكون Indiana التسارع
+
+193
+00:15:09,630 --> 00:15:12,570
+والسرعة في نفس الاتجاه فالسرعة النهائية بتطلع
+
+194
+00:15:12,570 --> 00:15:18,630
+لبرضه موجبة في هذا الشكل لكنلو كان عندى انا السرعة
+
+195
+00:15:18,630 --> 00:15:25,950
+بتزيد او بتقل بانتظام مع الزمن يعنى بيكون عندى انا
+
+196
+00:15:25,950 --> 00:15:29,070
+V average بتساوي V ابتدائية زائد V نهائية على
+
+197
+00:15:29,070 --> 00:15:32,310
+اتنين يعنى لو كان عندى انا سرعتين سرعة ابتدائية
+
+198
+00:15:32,310 --> 00:15:38,200
+سرعة نهائية و بتحركوا بانتظامفالمتوسط السرعة إلها
+
+199
+00:15:38,200 --> 00:15:42,140
+بحكي أنا السرعة الأولى زائد السرعة التانية على
+
+200
+00:15:42,140 --> 00:15:46,320
+اتنين لما هدش طبعا الشرط أنه يكون عندي constant
+
+201
+00:15:46,320 --> 00:15:51,580
+acceleration أو تسارع ثابت الآن عشان هذه القانون
+
+202
+00:15:51,580 --> 00:15:55,520
+الأول خلصناها بدأ أوجد القانون التاني عشان أوجد
+
+203
+00:15:55,520 --> 00:15:58,580
+القانون التاني طبعا كان عندي أنا القانون التاني V
+
+204
+00:15:58,580 --> 00:16:02,600
+averageبتساوى Delta X على Delta T سرعة الاتجاهية
+
+205
+00:16:02,600 --> 00:16:07,040
+المتوسطة بتساوى Delta X على Delta T X Final ناقص X
+
+206
+00:16:07,040 --> 00:16:11,580
+Initial ع T Final ناقص T Initial فرضت أن T Initial
+
+207
+00:16:11,580 --> 00:16:19,980
+صفر و T Final TT final T معنى الكلام Delta X بدها
+
+208
+00:16:19,980 --> 00:16:24,820
+تساوي V average في T Delta T كانت هي V final T
+
+209
+00:16:24,820 --> 00:16:28,480
+final نقص T initial وبالتالي هذه Delta T راح أقعد
+
+210
+00:16:28,480 --> 00:16:33,180
+عنها T و أضرب ضرب تبادلي V average في T يساوي
+
+211
+00:16:33,180 --> 00:16:39,660
+Delta Xفالـ V average بتعوض عنها من القانون السابق
+
+212
+00:16:39,660 --> 00:16:44,140
+اللي هي V initial زائد V على 2 لو كان عندي أنا
+
+213
+00:16:44,140 --> 00:16:48,200
+سرعتين بتحرك بيه تسارع ثابت أو بيتحركوا حركة
+
+214
+00:16:48,200 --> 00:16:52,800
+منتظمة فبعوض عن V average V naught زائد V على 2 في
+
+215
+00:16:52,800 --> 00:16:59,340
+Tسارت عندى delta X بتساوي V not زائد V على 2 في T
+
+216
+00:16:59,340 --> 00:17:03,320
+طبعا هضرب ضرب تبادلى بتصير هان اتنين في delta X
+
+217
+00:17:03,320 --> 00:17:09,080
+اتنين delta X بتساوي V not زائد V على T اذا delta
+
+218
+00:17:09,080 --> 00:17:17,520
+X بتساوي نص V not زائد V على Tأو 2X بتساوي V0 زائد
+
+219
+00:17:17,520 --> 00:17:25,700
+V في T الآن بدنا نعوض عن ال V نهائية ال V hat
+
+220
+00:17:25,700 --> 00:17:29,160
+النهائية هنا بتسير بتعود عن ال V النهائية اللي هي
+
+221
+00:17:29,160 --> 00:17:32,920
+أخدناها القانون الأول V النهائية بتساوي V0 زائد AT
+
+222
+00:17:32,920 --> 00:17:39,040
+صار عندي نص V0 زائد V0 اتنين V0 زائد AT
+
+223
+00:17:51,730 --> 00:17:54,770
+طبعا الـ T دخلت على الحد هذا و الحد هذا و الحد هذا
+
+224
+00:17:55,200 --> 00:17:59,240
+صار عندى انا delta X بتساوى V naught في T زائد نص
+
+225
+00:17:59,240 --> 00:18:04,640
+لإنه نص هنا A T تربيع DX بتساوى V naught T زائد نص
+
+226
+00:18:04,640 --> 00:18:09,060
+A T تربيع إذن هذا يعتبر هو القانون التانى من
+
+227
+00:18:09,060 --> 00:18:15,780
+قوانين الحركة بخط بعد واحد بسرعة بتسارع ثابتة
+
+228
+00:18:16,320 --> 00:18:20,200
+القانون التالت عشان أوجده «we can obtain an
+
+229
+00:18:20,200 --> 00:18:23,020
+expression that does not contain time» ممكن أوجد
+
+230
+00:18:23,020 --> 00:18:26,740
+أنا القانون التالت لو أنا ماعندي أنا زمان ولكن
+
+231
+00:18:26,740 --> 00:18:30,160
+عندي سرعة نهائية وعندي سرعة ابتدائية وعندي مسافة
+
+232
+00:18:30,160 --> 00:18:34,720
+فعندي أنا delta X من القانون السابق بالثورة نص V
+
+233
+00:18:34,720 --> 00:18:40,300
+زائد V naughtفي V ناقص V naught على A هذا طبعا
+
+234
+00:18:40,300 --> 00:18:45,300
+اللي هو T عوضت عن T عوضنا عن T وبالتالي لما هذا
+
+235
+00:18:45,300 --> 00:18:49,860
+الحد V ناقص V naught على V مضروبة في V زائد V
+
+236
+00:18:49,860 --> 00:18:54,260
+naught هذا بسميهم فرق مربعين بتساوى V في V V تربيع
+
+237
+00:18:54,440 --> 00:18:59,180
+ناقص V not ناقص في نوجة ناقص V not تربيع على اتنين
+
+238
+00:18:59,180 --> 00:19:02,320
+A الاتنين ضربتها في اتنين صارت Delta X بدها تساوي
+
+239
+00:19:02,320 --> 00:19:06,460
+لإن أنا ضيعت ال T لإن أنا بدي علاقة بدون T Delta X
+
+240
+00:19:06,460 --> 00:19:09,620
+بتساوي V تربيع ناقص V not تربيع على الاتنين A أو
+
+241
+00:19:09,620 --> 00:19:15,540
+بكتبها بطريقة تانية V تربيع بدها تساوي V not تربيع
+
+242
+00:19:15,540 --> 00:19:19,420
+زائد اتنين A X وهذا القانون التالت من قوانين
+
+243
+00:19:19,420 --> 00:19:25,010
+الحركة في خط مستقيم بتسارع ثابتهذه القوانين
+
+244
+00:19:25,010 --> 00:19:28,990
+التلاتة هي عبارة عن حركة جسم في اتجاه الـ X-axis
+
+245
+00:19:28,990 --> 00:19:32,750
+اتجاه محور X الأفقي لأنها تتحرك بخط مستقيم مثل
+
+246
+00:19:32,750 --> 00:19:37,230
+حركة سيارة، حركة دراجة، حركة إنسان، كل هذا تتحرك
+
+247
+00:19:37,230 --> 00:19:43,060
+بخط مستقيمعلى الـ X-axis بتسارع ثابت وبعد واحد
+
+248
+00:19:43,060 --> 00:19:47,340
+طبعا هو الـ X-axis التلت قوانين بيمثلوا V بساوة V0
+
+249
+00:19:47,340 --> 00:19:50,920
+زائد AT هذا القانون الأول بتمثل اللي هي عبارة عن
+
+250
+00:19:50,920 --> 00:19:55,300
+السرعة كدالة في الزمن و Delta X بتساوة V0 T زائد
+
+251
+00:19:55,300 --> 00:19:58,840
+نص AT تربيع هذا القانون التاني هي عبارة عن الإزاحة
+
+252
+00:19:58,840 --> 00:20:01,980
+as a function of time كدالة في الزمن القانون
+
+253
+00:20:01,980 --> 00:20:08,640
+التالت هو عبارة عن V تربيعبدها تساوي V0 تربيع زائد
+
+254
+00:20:08,640 --> 00:20:12,120
+2AX
+
+255
+00:20:12,120 --> 00:20:16,200
+هي عبارة عن السرعة كدالة في الإزاحة في حالة عدم
+
+256
+00:20:16,200 --> 00:20:20,280
+وجود الزمن، هذا الخانون التالت فإحنا التلت قوانين
+
+257
+00:20:20,280 --> 00:20:24,860
+ممكن نستخدمهم لحل بعض المسائل على اعتبار أن T
+
+258
+00:20:24,860 --> 00:20:30,220
+الابتدائية بيساوي 0 وT النهائية بتساوي T و V
+
+259
+00:20:30,220 --> 00:20:34,040
+initial بتساوي V0هذا الكلام Problem Solving
+
+260
+00:20:34,040 --> 00:20:36,920
+Strategy يعني كيف أنا أحل المسائل من هذا النوع
+
+261
+00:20:36,920 --> 00:20:40,820
+مسائل من هذا النوع اللي هي الحركة في بعد واحد
+
+262
+00:20:40,820 --> 00:20:45,820
+بتسارق ثابتبحكي لي أن الـ following procedure is
+
+263
+00:20:45,820 --> 00:20:48,640
+recommended for solving problems involving
+
+264
+00:20:48,640 --> 00:20:52,880
+accelerated motions في عندي أنا بعض الخطوات عشان
+
+265
+00:20:52,880 --> 00:20:58,020
+أنا أحل طبعا مسائل بخط مستقيم طبعا هذه ممكن تفيدني
+
+266
+00:20:58,020 --> 00:21:03,590
+لمعظم المسائل أول حاجة بقرأ المسألة قراءة متأنيةو
+
+267
+00:21:03,590 --> 00:21:11,150
+بكتب المعطيات الموجودة بعدين أرسم
+
+268
+00:21:11,150 --> 00:21:18,910
+منحناء أو محاور X و Y في البداية ممكن أرسم على
+
+269
+00:21:18,910 --> 00:21:23,640
+الصيني بشوف نقطة البداية و نقطة النهايةإذا كان في
+
+270
+00:21:23,640 --> 00:21:26,640
+عندي أنا منحنى نقطة البداية ونقطة النهاية بالنسبة
+
+271
+00:21:26,640 --> 00:21:31,440
+لمحور X أو محور Y إذا كان عندي أنا علاقة بين
+
+272
+00:21:31,440 --> 00:21:34,980
+السرعة أو التسارع label all a quantity ممكن أنا
+
+273
+00:21:34,980 --> 00:21:38,820
+على المنحنى اللي أنا أكتبه لازم أحدد اللي هي نوع
+
+274
+00:21:38,820 --> 00:21:43,880
+هذه الكمية محور X تمثل مثلا T او محور Y تمثل V أو
+
+275
+00:21:43,880 --> 00:21:49,020
+A circle the unknown convert units are need ممكن
+
+276
+00:21:49,020 --> 00:21:55,780
+أنا أحددالوحدة اللي أنا طبعا label all quantity كل
+
+277
+00:21:55,780 --> 00:22:02,340
+الكميات circling the unknowns convert units as
+
+278
+00:22:02,340 --> 00:22:08,880
+need ممكن أي وحدة أنا محتاج إن أناأحولها لأنه لازم
+
+279
+00:22:08,880 --> 00:22:13,780
+طبعا تناسق الوحدات وتجانس الوحدات أن اتحل أي مسألة
+
+280
+00:22:13,780 --> 00:22:19,040
+مانفعش مثلا أحل مسألة مثلا السرعة متر في الثانه
+
+281
+00:22:19,040 --> 00:22:23,660
+وبيعطيني مسافة بالقدم أو المسافة بال foot أو
+
+282
+00:22:23,660 --> 00:22:27,600
+المسافة بال yard أو المسافة بنوع تاني وبالتالي
+
+283
+00:22:27,600 --> 00:22:29,560
+لازم انا اوحد الوحدات
+
+284
+00:22:37,940 --> 00:22:40,640
+معظم المسائل ممكن أحلها بالقانون أو القانون التاني
+
+285
+00:22:40,640 --> 00:22:44,400
+إذا كان في عندي أنا زمن ممكن أجيب الزمن من
+
+286
+00:22:44,400 --> 00:22:48,300
+المعادلة الأولى و أحلها في التانية أو العكس بعد
+
+287
+00:22:48,300 --> 00:22:52,440
+هيك بقى أحل المسئلة for the unknowns though it so
+
+288
+00:22:52,440 --> 00:22:55,060
+often involves solving the two equations for two
+
+289
+00:22:55,060 --> 00:22:59,520
+unknowns لو كان عندي أنا مجهولينفانا محتاج
+
+290
+00:22:59,520 --> 00:23:01,940
+معادلتين هذا لو كنت عندي مجهولين كنت أكتب
+
+291
+00:23:01,940 --> 00:23:06,860
+المعادلتين و من خلال المعادلتين أنا بجيب المتغير
+
+292
+00:23:06,860 --> 00:23:09,700
+الأول بدلالة المتغير التاني و بروح أعوض في
+
+293
+00:23:09,700 --> 00:23:14,620
+المعادلة التانية ممكن أنا يعني أفحص هل الشغل صح
+
+294
+00:23:14,620 --> 00:23:18,040
+ولا لأ من خلال أن أنا أعوض في قوانين اللي هي
+
+295
+00:23:18,040 --> 00:23:21,770
+القانون التالت و هكذامعنى الكلام أنه أنا عندي تلت
+
+296
+00:23:21,770 --> 00:23:26,850
+قوانين أساسية هذه القوانين الأساسية هي قوانين
+
+297
+00:23:26,850 --> 00:23:30,450
+الحركة في بعد واحد باتجاه الـ X-axis المرة الجاية
+
+298
+00:23:30,450 --> 00:23:34,110
+إن شاء الله بنحل بعض المسائل أو بنشرح فكرة أنه لو
+
+299
+00:23:34,110 --> 00:23:38,530
+كان عندي أنا حركة بخط مستقيم لكن باتجاه ال Y-axis
+
+300
+00:23:38,530 --> 00:23:41,450
+وهي عبارة عن الـ Free Falling هنستكمل إن شاء الله
+
+301
+00:23:41,450 --> 00:23:42,750
+المحاضرة القادمة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/MfYemOPI8-U_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/MfYemOPI8-U_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..89524cb9225de96616736b2cd1ba8525835c96e2
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/MfYemOPI8-U_raw.srt
@@ -0,0 +1,1204 @@
+1
+00:00:00,000 --> 00:00:06,060
+بسم الله الرحمن الرحيم هنتابع مع بعض quiz الاتنين
+
+2
+00:00:06,060 --> 00:00:11,220
+تلاتة ال quiz بيحكي اللي في عندي أنا تلت أجزاء A
+
+3
+00:00:11,220 --> 00:00:16,660
+وB وC كما هو موضح بالشكل أدناه هدول التلت أشكال
+
+4
+00:00:16,660 --> 00:00:24,940
+بمثله تلت ال graphs تلت أشكالمنحنيات للسرعة of
+
+5
+00:00:24,940 --> 00:00:28,820
+different objects moving in a straight يعني سرعة
+
+6
+00:00:28,820 --> 00:00:35,140
+جسم بتحرك بخط مستقيم وبعدين بتحرك بخط path as a
+
+7
+00:00:35,140 --> 00:00:38,870
+function of T بخط كده اللي في الزمنوكمان الـ
+
+8
+00:00:38,870 --> 00:00:42,690
+possible acceleration of each object as a function
+
+9
+00:00:42,690 --> 00:00:47,070
+of time are shown in part الآن الأجزاء التلاتة D
+
+10
+00:00:47,070 --> 00:00:53,370
+وE وF تمثل احتمالية اللي هي التسارع بالنسبة للزمن
+
+11
+00:00:53,370 --> 00:00:56,710
+المطلوب من ال match each velocity versus time
+
+12
+00:00:56,710 --> 00:00:59,570
+graph with acceleration versus time graph that
+
+13
+00:00:59,570 --> 00:01:04,250
+best describe the motion بيحكي لنا وصل من الأشكال
+
+14
+00:01:04,250 --> 00:01:09,590
+المناسبة تتناسب مع مثلتهاحيث إن الأشكال الأولى A
+
+15
+00:01:09,590 --> 00:01:15,170
+وB وC تمثل علاقة الـV مع الـT العلاقة الأولى خط
+
+16
+00:01:15,170 --> 00:01:18,550
+مستقيم والعلاقة التانية منحنة علاقة بين V وT
+
+17
+00:01:18,550 --> 00:01:22,510
+والعلاقة التالتة خط مستقيم وبعدين مقدار ثابت علاقة
+
+18
+00:01:22,510 --> 00:01:27,210
+بينهم V وT الآن عندي تلاتة A وB وC تلت أشكال مطلوب
+
+19
+00:01:27,210 --> 00:01:32,760
+منها نوصلهمبالـ 3 أشكال اللي تحت بيمثله علاقة بين
+
+20
+00:01:32,760 --> 00:01:36,600
+الـ A و بين الـ T بين الـ A و بالـ T و بين الـ A و
+
+21
+00:01:36,600 --> 00:01:42,330
+T الأن للشكل الأول لو جينا للشكل الأولالشكل الأول
+
+22
+00:01:42,330 --> 00:01:46,610
+علاقة بين ال .. الشكل الأول زي ما أحنا شايفين
+
+23
+00:01:46,610 --> 00:01:52,870
+علاقة بين ال .. ال V و ال T علاقة بين ال V و ال T
+
+24
+00:01:52,870 --> 00:01:57,610
+و بالتالي لما بده أوجد أنا التسارع فالتسارع
+
+25
+00:01:57,610 --> 00:02:02,570
+بالمنطقة هذه عشان هذه خط مستقيم هيكون عندي التسارع
+
+26
+00:02:02,570 --> 00:02:06,510
+ثابت لكل الخط المستقيم لو إجيت أختار مين الشكل
+
+27
+00:02:06,510 --> 00:02:10,270
+المناسبلو إجيت أنا للشكل هذا، هذا علاقة بين الـV
+
+28
+00:02:10,270 --> 00:02:15,030
+وT، بين الـA وT، فالعلاقة هنا ترضية، يعني كل ما
+
+29
+00:02:15,030 --> 00:02:17,850
+تزيد الـA بتزيد الـT وها كده، وليس مقدار ثابت، بدي
+
+30
+00:02:17,850 --> 00:02:23,390
+أبحث عن شكل يمثل الـA وT كمقدار ثابت، فبلاحظ أن
+
+31
+00:02:23,390 --> 00:02:27,870
+الـV، الشكل الأول، علاقة بين الـV وT بيمثله الشكل
+
+32
+00:02:27,870 --> 00:02:31,290
+هذااللي هو الـ E علاقة بين الـ A و T، هذا مقدار
+
+33
+00:02:31,290 --> 00:02:34,890
+ثابت، يعني لو أنا جيبت .. أجيبت التسارع في أي نقطة
+
+34
+00:02:34,890 --> 00:02:40,150
+على هذا الخط، بأجده مقدار A ثابت، معنى الكلام، بدي
+
+35
+00:02:40,150 --> 00:02:45,490
+أوصل، بتطلع إن الـ A في الشكل هذا A B C D E، هنا
+
+36
+00:02:45,490 --> 00:02:51,410
+الـ F، A مع الـ F، تمام؟ نجرى الشكل B، الشكل B هذا
+
+37
+00:02:51,410 --> 00:02:56,660
+منحنى،المنحنة هذا علاقة بين ال V و ال T علاقة بين
+
+38
+00:02:56,660 --> 00:03:00,140
+ال V و ال T لما اوجد انا ال instantaneous
+
+39
+00:03:00,140 --> 00:03:05,480
+acceleration في هذا المنحنة باخد نقطة و بعدين باخد
+
+40
+00:03:05,480 --> 00:03:08,600
+اللي هو ميل المماس لهذا النقطة باجد ان ميل المماس
+
+41
+00:03:08,600 --> 00:03:13,060
+هيكون موجة بهذا الشكل فمعنى الكلام ال B بوصلها
+
+42
+00:03:13,060 --> 00:03:18,100
+بهذا الشكلبالنسبة للشكل التالت علاقة بين ال V و T
+
+43
+00:03:18,100 --> 00:03:22,780
+في المنطقة المرحلة الأولى ال V و T لما أنا في هو
+
+44
+00:03:22,780 --> 00:03:26,200
+عبارة عن طبعا عند انا اوجد ال acceleration وعندي
+
+45
+00:03:26,200 --> 00:03:30,600
+أنا خط وعبارة عن ميل هذا الخط الميل هذا الخط طبعا
+
+46
+00:03:30,600 --> 00:03:35,440
+ثابت لكل النقاط وبالتالي المنطقة هذه بتمثلها هذه
+
+47
+00:03:35,440 --> 00:03:39,900
+المنطقة ثابتة يعني ال V على T مقدار ثابت مافي
+
+48
+00:03:39,900 --> 00:03:43,880
+تغيير على المنطقة ده وبالتالي التسارع تبقى مقدار
+
+49
+00:03:43,880 --> 00:03:49,320
+ثابت بالشكل هذابعد هيك علاقة ال V والـ T صارت
+
+50
+00:03:49,320 --> 00:03:53,520
+علاقة V على T هنا سفر لأنه مافيش تسارع في المنطقة
+
+51
+00:03:53,520 --> 00:03:57,700
+هذه، إذا ال تسارع V على T بنزلة ال Zero فمعنى
+
+52
+00:03:57,700 --> 00:04:02,180
+الكلام أن الشكل أول A يمثل بهذا الشكل، B يمثل بهذا
+
+53
+00:04:02,180 --> 00:04:05,000
+الشكل وC يمثل بهذا الشكل
+
+54
+00:04:08,060 --> 00:04:14,300
+زي ما هو موضح بالحل الموضح ان انه في عندي انا ال A
+
+55
+00:04:14,300 --> 00:04:18,500
+بيمثله في هذا المنطقة و ال B هو عبارة عن ال D و ال
+
+56
+00:04:18,500 --> 00:04:21,940
+C عبارة عن ال F كما هو موضح بالشكل
+
+57
+00:04:25,610 --> 00:04:32,030
+نجلى example بيحكي لنا example اتنين تلاتة المطلوب
+
+58
+00:04:32,030 --> 00:04:39,390
+مني أوجد طبعا التسارع لحركة particle pass ball a
+
+59
+00:04:39,390 --> 00:04:41,910
+player moves in a straight line path in order to
+
+60
+00:04:41,910 --> 00:04:47,030
+catch a fly ball into to out to the outfield عندي
+
+61
+00:04:47,030 --> 00:04:53,850
+حركة كرات سلةكرة السلة بتتحرك أول حاجة بخط مستقيم
+
+62
+00:04:53,850 --> 00:04:58,830
+حتى تصل إلى طبعا المنطقة اللي هم رمين الكرة فيها
+
+63
+00:04:58,830 --> 00:05:03,030
+طبعا هي بصفة عامة هو مسار لكرة المسار اتحرك بهذا
+
+64
+00:05:03,030 --> 00:05:07,670
+الشكل اتحرك من ال a ل ال b ل ال c مطلوب مني اوجد
+
+65
+00:05:07,670 --> 00:05:12,470
+find its instantaneous acceleration مطلوب مني اوجد
+
+66
+00:05:12,470 --> 00:05:16,770
+ال instantaneous acceleration التسارق اللحظي عند
+
+67
+00:05:16,770 --> 00:05:22,770
+النقطة aو B و C بدا أوجد التسارق اللحظي عند النقطة
+
+68
+00:05:22,770 --> 00:05:28,240
+A و B و Cالان عند النقطة A التسارع اللحظي إذا كان
+
+69
+00:05:28,240 --> 00:05:32,900
+عندي أنا علاقة بين V وT وعندي أنا خط مستقيم
+
+70
+00:05:32,900 --> 00:05:36,380
+فالتسارع اللحظي عند هذه النقطة هو ميل الخط فميل
+
+71
+00:05:36,380 --> 00:05:40,840
+الخط في المنطقة هذه عنده النقطة A هو عبارة عن ميل
+
+72
+00:05:40,840 --> 00:05:44,560
+هذا الخط الميل الخط هو عبارة عن مقابل على مجاور أو
+
+73
+00:05:44,560 --> 00:05:49,000
+تاني الزاوية مقابل على مجاور ممكن أخد النقطة عند A
+
+74
+00:05:49,000 --> 00:05:53,610
+اللي هي الاتنين على واحد بينفعممكن أخد الأربع على
+
+75
+00:05:53,610 --> 00:05:57,110
+الإتنين برضه بتنفع ميل الخط عند كل النقاط مقدار
+
+76
+00:05:57,110 --> 00:06:03,570
+ثابت عند المنطقة B لما بدأ أجي أوجد أنا التسارع
+
+77
+00:06:03,570 --> 00:06:06,630
+اللحظة عند المنطقة B بقى ميل الخط عند المنطقة B
+
+78
+00:06:06,630 --> 00:06:10,470
+صفر، مالوش ميل مع أن الكلام دي V على D تهان مقدار
+
+79
+00:06:10,470 --> 00:06:14,230
+Zero مع أن الكلام ميل الخط لهذا الـ Instantaneous
+
+80
+00:06:14,230 --> 00:06:18,990
+Acceleration بدأ تساوي صفر عند المنطقة B عند
+
+81
+00:06:18,990 --> 00:06:22,950
+المنطقة Cالـ instantaneous acceleration برضه بدأ
+
+82
+00:06:22,950 --> 00:06:28,510
+أوجد ميل الخط عند هذه المنطقة فميل الخط ممكن أحكي
+
+83
+00:06:28,510 --> 00:06:33,410
+أنا المقابل أيضًا على المجاور أو ممكن أجيب اللي هي
+
+84
+00:06:33,410 --> 00:06:37,310
+V هذه منطقة البداية و هذه النهاية معنى الكلام إنه
+
+85
+00:06:37,310 --> 00:06:42,510
+في عندي V final كانت اتنين و V initial أربعة راح
+
+86
+00:06:42,510 --> 00:06:47,890
+نحكي اتنين ناقص أربعة بالنسبة للزمن أربعة ناقص
+
+87
+00:06:47,890 --> 00:06:51,760
+تلاتة بتطلع عندي بالسالب كما هو موضحالحل اللي هو
+
+88
+00:06:51,760 --> 00:06:55,080
+المرفق بالشكل هذا إذا ال instantaneous
+
+89
+00:06:55,080 --> 00:07:00,640
+acceleration عند المنطقة A هي عبارة عن ميل الخط
+
+90
+00:07:00,640 --> 00:07:05,080
+equals the slope of the line إذا delta V ميل الخط
+
+91
+00:07:05,080 --> 00:07:08,520
+هو عبارة عن delta V على delta T ال V النهائية كانت
+
+92
+00:07:08,520 --> 00:07:13,730
+4 والابتدائية 0 على ال 2 ناقص 0بتساوي موجب اتنين
+
+93
+00:07:13,730 --> 00:07:18,490
+لإن الخط ميل جهة اليمين فالاتسار عندي انا موجب او
+
+94
+00:07:18,490 --> 00:07:21,870
+ميل الخط موجب زى ما احنا شايفين بهذا الشكل ميل
+
+95
+00:07:21,870 --> 00:07:24,850
+الخط موجب او ممكن احكي اتنين على واحد بيظبط بتطلع
+
+96
+00:07:24,850 --> 00:07:28,270
+نفس الجواب اتنين على واحد او المنطقة هادى واحد على
+
+97
+00:07:28,270 --> 00:07:32,720
+نص بتطلع نفس الجوابالمنطقة B زي ما احنا شايفين في
+
+98
+00:07:32,720 --> 00:07:37,180
+المنطقة B Delta V بتساوي سفر وبالتالي مافيش تغير
+
+99
+00:07:37,180 --> 00:07:39,760
+في السرعة، السرعة ثابتة إذا Delta V على Delta T
+
+100
+00:07:39,760 --> 00:07:42,900
+أربعة ناقص أربعة على تلاتة ناقص اتنين بيطلع عندي
+
+101
+00:07:42,900 --> 00:07:46,420
+سفر لإنه مافي ميل للخط وبالتالي تسارع اللحظة
+
+102
+00:07:46,420 --> 00:07:51,250
+بيساوي Zeroعند المنطقة C زي ما حكينا هي عبارة عن
+
+103
+00:07:51,250 --> 00:07:53,970
+ميل الخاط اللي هي equals the slope of the line
+
+104
+00:07:53,970 --> 00:07:59,010
+connecting the point بين النقطة 3 و 4 و 4 و 2 إذا
+
+105
+00:07:59,010 --> 00:08:04,190
+ال A بدها تساوي Delta V على Delta T V نهائية كانت
+
+106
+00:08:04,190 --> 00:08:10,000
+2الابتدائية كانت أربعة والنهائية بالنسبة للزمن
+
+107
+00:08:10,000 --> 00:08:13,600
+كانت أربعة والابتدائية تلاتة فبطلع عندي ناقص اتنين
+
+108
+00:08:13,600 --> 00:08:19,120
+زي ما هو موضح بهذا الشكل and المنطقة C هي ده جيب
+
+109
+00:08:19,120 --> 00:08:23,960
+ال mail هو مقابل على مجاور أو المسافة هذه اللي هي
+
+110
+00:08:23,960 --> 00:08:28,540
+عبارة المسافة هذه أربعة ناقص اتنين طبعا الأربعة
+
+111
+00:08:28,540 --> 00:08:33,120
+هذه الابتدائية الاتنين النهائية فبنحكي اللي هي
+
+112
+00:08:33,120 --> 00:08:37,660
+الاتنين ناقص أربعة علىهذه البداية وهذه النهائية
+
+113
+00:08:37,660 --> 00:08:41,800
+أربعة ناقص تلاتة بطلع عندى بالسالب كمان لأو أي خط
+
+114
+00:08:41,800 --> 00:08:47,840
+اتجاهه على اليسار بيكون ميله بالسالب فعلا الجواب
+
+115
+00:08:47,840 --> 00:08:51,580
+بطلع عندى بالسالب اللى هو بساوي ناقص اتنين متر في
+
+116
+00:08:51,580 --> 00:08:57,730
+الثانية تربيعطبعاً بنبدأ موضوع تاني اللي هو عبارة
+
+117
+00:08:57,730 --> 00:09:03,930
+عن section 22 motion diagram اللي هي عبارة عن حركة
+
+118
+00:09:03,930 --> 00:09:08,850
+motion diagram هذا احنا مش هنشرحه اللي هي .. اللي
+
+119
+00:09:08,850 --> 00:09:16,520
+هي الحركة اللي هي curve أو منحنة لحركةمابدناش إياه
+
+120
+00:09:16,520 --> 00:09:22,100
+لكن ممكن نبدأ في section اتنين تلاتة بعنوان one
+
+121
+00:09:22,100 --> 00:09:25,520
+dimensional emotion with constant acceleration
+
+122
+00:09:25,520 --> 00:09:31,820
+الحركة في بعد واحد بتسارع ثابت الحركة في بعد واحد
+
+123
+00:09:31,820 --> 00:09:37,850
+بتسارع ثابتكثير من التطبيقات أو الـ Mechanica
+
+124
+00:09:37,850 --> 00:09:44,830
+تتضمن تتضمن مواضيع
+
+125
+00:09:44,830 --> 00:09:51,930
+تتحرك بتسارع ثابت عندما يتحرك
+
+126
+00:09:51,930 --> 00:09:54,230
+الجسم بتسارع ثابت
+
+127
+00:09:57,850 --> 00:10:03,110
+التسارع اللحظي عند أي نقطة في فترة زمانية T is
+
+128
+00:10:03,110 --> 00:10:06,050
+equal to the value of the average acceleration
+
+129
+00:10:06,050 --> 00:10:13,570
+over the time intervalمعنى الكلام بالفقرة هذه اللي
+
+130
+00:10:13,570 --> 00:10:17,430
+في اللون الأحمر معناها أن أي جسم بتحرك بتسارع ثابت
+
+131
+00:10:17,430 --> 00:10:23,810
+فالتسارع اللحظي عند أي زمن قدرته يساوي التسارع
+
+132
+00:10:23,810 --> 00:10:26,790
+اللي هو اتجاهه أو average acceleration متوسط
+
+133
+00:10:26,790 --> 00:10:31,570
+السرعة اللي متوسط التسارع التسارع اللحظي بساوي
+
+134
+00:10:31,570 --> 00:10:36,670
+متوسط التسارع over the عند تلك الفترةبناء عليه
+
+135
+00:10:36,670 --> 00:10:44,350
+السرعة تزداد أو تقل خلال هذه الحركة وبالتالي
+
+136
+00:10:44,350 --> 00:10:51,990
+السرعة ممكن تزداد أو تقل خلال هذه الحركة ولو احنا
+
+137
+00:10:51,990 --> 00:10:58,250
+رسمنا علاقة بين V و T تعطينا خط مستقيم ممكن يكون
+
+138
+00:10:58,250 --> 00:11:01,910
+خط مستقيم موجة ممكن يكون Zero ممكن يكون ال slope
+
+139
+00:11:01,910 --> 00:11:06,020
+negative زي الرسمة اللي كانت بالسابقلأن الـ
+
+140
+00:11:06,020 --> 00:11:08,500
+Average Acceleration بتساوي الـ Instantaneous
+
+141
+00:11:08,500 --> 00:11:10,960
+Acceleration Acceleration اللي ما يكون تسارع متوسط
+
+142
+00:11:10,960 --> 00:11:15,480
+التسارع يساوي التسارع اللحظي معنى الكلام لما أيه
+
+143
+00:11:15,480 --> 00:11:18,480
+بدها تساوي لما أيه بدها تساوي Zero We can
+
+144
+00:11:18,480 --> 00:11:21,960
+eliminate the part used to denote في هذه الحالة لو
+
+145
+00:11:21,960 --> 00:11:27,880
+أننا فرضنا إنه أو لو كان عندي أنا تسارع ثابتطبعا
+
+146
+00:11:27,880 --> 00:11:30,640
+احنا كنا نكتب التسارع المتوسط التسارع A بالساوية
+
+147
+00:11:30,640 --> 00:11:34,300
+Zero لكن لما تكون التسارع ثابت فالتسارع اللحظي
+
+148
+00:11:34,300 --> 00:11:39,000
+بيساوي التسارع المتوسط التسارع وبالتالي ممكن اكتب
+
+149
+00:11:39,000 --> 00:11:43,260
+ال A average اللي هي متوسط التسارع بده يساوي ال A
+
+150
+00:11:43,260 --> 00:11:48,900
+اللي هي اللحظية فممكن نكتب ان ال A بدها تساوي V
+
+151
+00:11:48,900 --> 00:11:53,830
+finalناقص V initial و T final ناقص T initial يعني
+
+152
+00:11:53,830 --> 00:11:58,770
+رفعنا شرطة ال average لإن ال A average بتساوي ال A
+
+153
+00:11:58,770 --> 00:12:02,550
+ال constant acceleration زي ما اتفقنا إن أنا بدي
+
+154
+00:12:02,550 --> 00:12:07,030
+أوجد معادلات الحركة في بعد واحد عندما يكون التسارع
+
+155
+00:12:07,030 --> 00:12:12,770
+ثابت كمان بدي أفرض إن T initial هذه بتساوي سفر لما
+
+156
+00:12:12,770 --> 00:12:17,310
+أنا تكون عندي ال T initial عند سرعة ابتدائي أو
+
+157
+00:12:17,310 --> 00:12:22,480
+بداية الحركةكمان بدي افرض ان V initial هي بتساوي V
+
+158
+00:12:22,480 --> 00:12:27,380
+naught لي تمثل السرعة عند T بتساوي صفر V naught
+
+159
+00:12:27,380 --> 00:12:31,820
+يعني عند T بتساوي صفر كمان بدي افرض ان T final
+
+160
+00:12:31,820 --> 00:12:36,540
+اسميها T لان هي عبارة عن انت صار عند لحظة زمنية
+
+161
+00:12:36,540 --> 00:12:41,260
+اسمها T او لحظة بتساوي T و V final هياللي هي عبارة
+
+162
+00:12:41,260 --> 00:12:46,780
+عن الـ V السرعة النهائية عند أي زمان قدرتي معنى
+
+163
+00:12:46,780 --> 00:12:49,680
+الكلام القانون الأساسي اللي كان عند ال A average
+
+164
+00:12:49,680 --> 00:12:54,080
+بتساوي V final ناقص V initial على T final ناقص T
+
+165
+00:12:54,080 --> 00:12:59,080
+initial غيرت فيه شوية فرضت لإنه انا عندي شرط إنه
+
+166
+00:12:59,080 --> 00:13:03,740
+تسارع ثابت إذا ال A average صارت A V final صارت V
+
+167
+00:13:03,740 --> 00:13:09,400
+V initial صارت V naught وT initial سفر راحتT final
+
+168
+00:13:09,400 --> 00:13:15,220
+صارت T من خلال هذه المعادلة ممكن أنا أكتب بهذا
+
+169
+00:13:15,220 --> 00:13:18,960
+الشكل ال A average صارت A V final صارت V V initial
+
+170
+00:13:18,960 --> 00:13:22,640
+صارت V not و T final صارت T not و T ال initial
+
+171
+00:13:22,640 --> 00:13:27,460
+zero راحت من خلال هذه المعادلة بأوجد أول قانون من
+
+172
+00:13:27,460 --> 00:13:31,980
+قوانين الحركة بخط مستقيم طبعا حيصير عندي أنا لو
+
+173
+00:13:31,980 --> 00:13:37,760
+أضرب ضرب تبادليهيصير عندى انا v ناقص v not بتساوي
+
+174
+00:13:37,760 --> 00:13:43,820
+at او v بتساوي v not زائد at هذا الكلام هو قانون
+
+175
+00:13:43,820 --> 00:13:49,640
+الاول لمعادلات الحركة الخطية ببعد واحد تسارع ثابت
+
+176
+00:13:49,640 --> 00:13:54,550
+اسمه a at constant a او for constant aيعني لو
+
+177
+00:13:54,550 --> 00:13:57,690
+أخدنا مثال على هذا القانون إذا كانت عندي سيارة if
+
+178
+00:13:57,690 --> 00:14:03,490
+a car starts عندي أنا سيارة بتتحرك بسرعة اتنين
+
+179
+00:14:03,490 --> 00:14:08,530
+موجبة متر في الثاني لليمين وبتسارع لليمين برضه أيه
+
+180
+00:14:08,530 --> 00:14:13,230
+بتساوي ستة متر في الثاني تربيع it will have the
+
+181
+00:14:13,230 --> 00:14:16,690
+velocity of اربعة عشر متر بعد زمن قدر اتنين معنى
+
+182
+00:14:16,690 --> 00:14:19,950
+الكلامعند تطبيق هذا القانون أنا بحتاج سرعة
+
+183
+00:14:19,950 --> 00:14:25,870
+ابتدائية أو سرعة نهائية تسارع زمن طبعا هنا احنا
+
+184
+00:14:25,870 --> 00:14:30,050
+مطلوب مني اوجد السرعة النهائية فالسؤال حكى لو كان
+
+185
+00:14:30,050 --> 00:14:34,950
+عند سرعة ابتدائية اتنين تسارع كان تسارع كان ستة
+
+186
+00:14:34,950 --> 00:14:42,790
+والزمن كان قدره اتنين فممكن احله من خلال القانونv0
+
+187
+00:14:42,790 --> 00:14:47,310
+كانت اتنين ال a بعوض عنها ستة و ال t بعوض عنها
+
+188
+00:14:47,310 --> 00:14:51,230
+باتنين فبتطلع عند السرعة النهائية بتساوي موجة
+
+189
+00:14:51,230 --> 00:14:56,970
+باربعتاشر متر في الثاني لإنه السرعة ال velocity is
+
+190
+00:14:56,970 --> 00:15:00,950
+increase because the velocity is increasing or
+
+191
+00:15:00,950 --> 00:15:06,090
+decreasing uniformly with timeWe can express V هذا
+
+192
+00:15:06,090 --> 00:15:09,630
+طبعا الكلام احنا أخدناه لما يكون Indiana التسارع
+
+193
+00:15:09,630 --> 00:15:12,570
+والسرعة في نفس الاتجاه فالسرعة النهائية بتطلع
+
+194
+00:15:12,570 --> 00:15:18,630
+لبرضه موجبة في هذا الشكل لكنلو كان عندى انا السرعة
+
+195
+00:15:18,630 --> 00:15:25,950
+بتزيد او بتقل بانتظام مع الزمن يعنى بيكون عندى انا
+
+196
+00:15:25,950 --> 00:15:29,070
+V average بتساوي V ابتدائية زائد V نهائية على
+
+197
+00:15:29,070 --> 00:15:32,310
+اتنين يعنى لو كان عندى انا سرعتين سرعة ابتدائية
+
+198
+00:15:32,310 --> 00:15:38,200
+سرعة نهائية و بتحركوا بانتظامفالمتوسط السرعة إلها
+
+199
+00:15:38,200 --> 00:15:42,140
+بحكي أنا السرعة الأولى زائد السرعة التانية على
+
+200
+00:15:42,140 --> 00:15:46,320
+اتنين لما هدش طبعا الشرط أنه يكون عندي constant
+
+201
+00:15:46,320 --> 00:15:51,580
+acceleration أو تسارع ثابت الآن عشان هذه القانون
+
+202
+00:15:51,580 --> 00:15:55,520
+الأول خلصناها بدأ أوجد القانون التاني عشان أوجد
+
+203
+00:15:55,520 --> 00:15:58,580
+القانون التاني طبعا كان عندي أنا القانون التاني V
+
+204
+00:15:58,580 --> 00:16:02,600
+averageبتساوى Delta X على Delta T سرعة الاتجاهية
+
+205
+00:16:02,600 --> 00:16:07,040
+المتوسطة بتساوى Delta X على Delta T X Final ناقص X
+
+206
+00:16:07,040 --> 00:16:11,580
+Initial ع T Final ناقص T Initial فرضت أن T Initial
+
+207
+00:16:11,580 --> 00:16:19,980
+صفر و T Final TT final T معنى الكلام Delta X بدها
+
+208
+00:16:19,980 --> 00:16:24,820
+تساوي V average في T Delta T كانت هي V final T
+
+209
+00:16:24,820 --> 00:16:28,480
+final نقص T initial وبالتالي هذه Delta T راح أقعد
+
+210
+00:16:28,480 --> 00:16:33,180
+عنها T و أضرب ضرب تبادلي V average في T يساوي
+
+211
+00:16:33,180 --> 00:16:39,660
+Delta Xفالـ V average بتعوض عنها من القانون السابق
+
+212
+00:16:39,660 --> 00:16:44,140
+اللي هي V initial زائد V على 2 لو كان عندي أنا
+
+213
+00:16:44,140 --> 00:16:48,200
+سرعتين بتحرك بيه تسارع ثابت أو بيتحركوا حركة
+
+214
+00:16:48,200 --> 00:16:52,800
+منتظمة فبعوض عن V average V naught زائد V على 2 في
+
+215
+00:16:52,800 --> 00:16:59,340
+Tسارت عندى delta X بتساوي V not زائد V على 2 في T
+
+216
+00:16:59,340 --> 00:17:03,320
+طبعا هضرب ضرب تبادلى بتصير هان اتنين في delta X
+
+217
+00:17:03,320 --> 00:17:09,080
+اتنين delta X بتساوي V not زائد V على T اذا delta
+
+218
+00:17:09,080 --> 00:17:17,520
+X بتساوي نص V not زائد V على Tأو 2X بتساوي V0 زائد
+
+219
+00:17:17,520 --> 00:17:25,700
+V في T الآن بدنا نعوض عن ال V نهائية ال V hat
+
+220
+00:17:25,700 --> 00:17:29,160
+النهائية هنا بتسير بتعود عن ال V النهائية اللي هي
+
+221
+00:17:29,160 --> 00:17:32,920
+أخدناها القانون الأول V النهائية بتساوي V0 زائد AT
+
+222
+00:17:32,920 --> 00:17:39,040
+صار عندي نص V0 زائد V0 اتنين V0 زائد AT
+
+223
+00:17:51,730 --> 00:17:54,770
+طبعا الـ T دخلت على الحد هذا و الحد هذا و الحد هذا
+
+224
+00:17:55,200 --> 00:17:59,240
+صار عندى انا delta X بتساوى V naught في T زائد نص
+
+225
+00:17:59,240 --> 00:18:04,640
+لإنه نص هنا A T تربيع DX بتساوى V naught T زائد نص
+
+226
+00:18:04,640 --> 00:18:09,060
+A T تربيع إذن هذا يعتبر هو القانون التانى من
+
+227
+00:18:09,060 --> 00:18:15,780
+قوانين الحركة بخط بعد واحد بسرعة بتسارع ثابتة
+
+228
+00:18:16,320 --> 00:18:20,200
+القانون التالت عشان أوجده «we can obtain an
+
+229
+00:18:20,200 --> 00:18:23,020
+expression that does not contain time» ممكن أوجد
+
+230
+00:18:23,020 --> 00:18:26,740
+أنا القانون التالت لو أنا ماعندي أنا زمان ولكن
+
+231
+00:18:26,740 --> 00:18:30,160
+عندي سرعة نهائية وعندي سرعة ابتدائية وعندي مسافة
+
+232
+00:18:30,160 --> 00:18:34,720
+فعندي أنا delta X من القانون السابق بالثورة نص V
+
+233
+00:18:34,720 --> 00:18:40,300
+زائد V naughtفي V ناقص V naught على A هذا طبعا
+
+234
+00:18:40,300 --> 00:18:45,300
+اللي هو T عوضت عن T عوضنا عن T وبالتالي لما هذا
+
+235
+00:18:45,300 --> 00:18:49,860
+الحد V ناقص V naught على V مضروبة في V زائد V
+
+236
+00:18:49,860 --> 00:18:54,260
+naught هذا بسميهم فرق مربعين بتساوى V في V V تربيع
+
+237
+00:18:54,440 --> 00:18:59,180
+ناقص V not ناقص في نوجة ناقص V not تربيع على اتنين
+
+238
+00:18:59,180 --> 00:19:02,320
+A الاتنين ضربتها في اتنين صارت Delta X بدها تساوي
+
+239
+00:19:02,320 --> 00:19:06,460
+لإن أنا ضيعت ال T لإن أنا بدي علاقة بدون T Delta X
+
+240
+00:19:06,460 --> 00:19:09,620
+بتساوي V تربيع ناقص V not تربيع على الاتنين A أو
+
+241
+00:19:09,620 --> 00:19:15,540
+بكتبها بطريقة تانية V تربيع بدها تساوي V not تربيع
+
+242
+00:19:15,540 --> 00:19:19,420
+زائد اتنين A X وهذا القانون التالت من قوانين
+
+243
+00:19:19,420 --> 00:19:25,010
+الحركة في خط مستقيم بتسارع ثابتهذه القوانين
+
+244
+00:19:25,010 --> 00:19:28,990
+التلاتة هي عبارة عن حركة جسم في اتجاه الـ X-axis
+
+245
+00:19:28,990 --> 00:19:32,750
+اتجاه محور X الأفقي لأنها تتحرك بخط مستقيم مثل
+
+246
+00:19:32,750 --> 00:19:37,230
+حركة سيارة، حركة دراجة، حركة إنسان، كل هذا تتحرك
+
+247
+00:19:37,230 --> 00:19:43,060
+بخط مستقيمعلى الـ X-axis بتسارع ثابت وبعد واحد
+
+248
+00:19:43,060 --> 00:19:47,340
+طبعا هو الـ X-axis التلت قوانين بيمثلوا V بساوة V0
+
+249
+00:19:47,340 --> 00:19:50,920
+زائد AT هذا القانون الأول بتمثل اللي هي عبارة عن
+
+250
+00:19:50,920 --> 00:19:55,300
+السرعة كدالة في الزمن و Delta X بتساوة V0 T زائد
+
+251
+00:19:55,300 --> 00:19:58,840
+نص AT تربيع هذا القانون التاني هي عبارة عن الإزاحة
+
+252
+00:19:58,840 --> 00:20:01,980
+as a function of time كدالة في الزمن القانون
+
+253
+00:20:01,980 --> 00:20:08,640
+التالت هو عبارة عن V تربيعبدها تساوي V0 تربيع زائد
+
+254
+00:20:08,640 --> 00:20:12,120
+2AX
+
+255
+00:20:12,120 --> 00:20:16,200
+هي عبارة عن السرعة كدالة في الإزاحة في حالة عدم
+
+256
+00:20:16,200 --> 00:20:20,280
+وجود الزمن، هذا الخانون التالت فإحنا التلت قوانين
+
+257
+00:20:20,280 --> 00:20:24,860
+ممكن نستخدمهم لحل بعض المسائل على اعتبار أن T
+
+258
+00:20:24,860 --> 00:20:30,220
+الابتدائية بيساوي 0 وT النهائية بتساوي T و V
+
+259
+00:20:30,220 --> 00:20:34,040
+initial بتساوي V0هذا الكلام Problem Solving
+
+260
+00:20:34,040 --> 00:20:36,920
+Strategy يعني كيف أنا أحل المسائل من هذا النوع
+
+261
+00:20:36,920 --> 00:20:40,820
+مسائل من هذا النوع اللي هي الحركة في بعد واحد
+
+262
+00:20:40,820 --> 00:20:45,820
+بتسارق ثابتبحكي لي أن الـ following procedure is
+
+263
+00:20:45,820 --> 00:20:48,640
+recommended for solving problems involving
+
+264
+00:20:48,640 --> 00:20:52,880
+accelerated motions في عندي أنا بعض الخطوات عشان
+
+265
+00:20:52,880 --> 00:20:58,020
+أنا أحل طبعا مسائل بخط مستقيم طبعا هذه ممكن تفيدني
+
+266
+00:20:58,020 --> 00:21:03,590
+لمعظم المسائل أول حاجة بقرأ المسألة قراءة متأنيةو
+
+267
+00:21:03,590 --> 00:21:11,150
+بكتب المعطيات الموجودة بعدين أرسم
+
+268
+00:21:11,150 --> 00:21:18,910
+منحناء أو محاور X و Y في البداية ممكن أرسم على
+
+269
+00:21:18,910 --> 00:21:23,640
+الصيني بشوف نقطة البداية و نقطة النهايةإذا كان في
+
+270
+00:21:23,640 --> 00:21:26,640
+عندي أنا منحنى نقطة البداية ونقطة النهاية بالنسبة
+
+271
+00:21:26,640 --> 00:21:31,440
+لمحور X أو محور Y إذا كان عندي أنا علاقة بين
+
+272
+00:21:31,440 --> 00:21:34,980
+السرعة أو التسارع label all a quantity ممكن أنا
+
+273
+00:21:34,980 --> 00:21:38,820
+على المنحنى اللي أنا أكتبه لازم أحدد اللي هي نوع
+
+274
+00:21:38,820 --> 00:21:43,880
+هذه الكمية محور X تمثل مثلا T او محور Y تمثل V أو
+
+275
+00:21:43,880 --> 00:21:49,020
+A circle the unknown convert units are need ممكن
+
+276
+00:21:49,020 --> 00:21:55,780
+أنا أحددالوحدة اللي أنا طبعا label all quantity كل
+
+277
+00:21:55,780 --> 00:22:02,340
+الكميات circling the unknowns convert units as
+
+278
+00:22:02,340 --> 00:22:08,880
+need ممكن أي وحدة أنا محتاج إن أناأحولها لأنه لازم
+
+279
+00:22:08,880 --> 00:22:13,780
+طبعا تناسق الوحدات وتجانس الوحدات أن اتحل أي مسألة
+
+280
+00:22:13,780 --> 00:22:19,040
+مانفعش مثلا أحل مسألة مثلا السرعة متر في الثانه
+
+281
+00:22:19,040 --> 00:22:23,660
+وبيعطيني مسافة بالقدم أو المسافة بال foot أو
+
+282
+00:22:23,660 --> 00:22:27,600
+المسافة بال yard أو المسافة بنوع تاني وبالتالي
+
+283
+00:22:27,600 --> 00:22:29,560
+لازم انا اوحد الوحدات
+
+284
+00:22:37,940 --> 00:22:40,640
+معظم المسائل ممكن أحلها بالقانون أو القانون التاني
+
+285
+00:22:40,640 --> 00:22:44,400
+إذا كان في عندي أنا زمن ممكن أجيب الزمن من
+
+286
+00:22:44,400 --> 00:22:48,300
+المعادلة الأولى و أحلها في التانية أو العكس بعد
+
+287
+00:22:48,300 --> 00:22:52,440
+هيك بقى أحل المسئلة for the unknowns though it so
+
+288
+00:22:52,440 --> 00:22:55,060
+often involves solving the two equations for two
+
+289
+00:22:55,060 --> 00:22:59,520
+unknowns لو كان عندي أنا مجهولينفانا محتاج
+
+290
+00:22:59,520 --> 00:23:01,940
+معادلتين هذا لو كنت عندي مجهولين كنت أكتب
+
+291
+00:23:01,940 --> 00:23:06,860
+المعادلتين و من خلال المعادلتين أنا بجيب المتغير
+
+292
+00:23:06,860 --> 00:23:09,700
+الأول بدلالة المتغير التاني و بروح أعوض في
+
+293
+00:23:09,700 --> 00:23:14,620
+المعادلة التانية ممكن أنا يعني أفحص هل الشغل صح
+
+294
+00:23:14,620 --> 00:23:18,040
+ولا لأ من خلال أن أنا أعوض في قوانين اللي هي
+
+295
+00:23:18,040 --> 00:23:21,770
+القانون التالت و هكذامعنى الكلام أنه أنا عندي تلت
+
+296
+00:23:21,770 --> 00:23:26,850
+قوانين أساسية هذه القوانين الأساسية هي قوانين
+
+297
+00:23:26,850 --> 00:23:30,450
+الحركة في بعد واحد باتجاه الـ X-axis المرة الجاية
+
+298
+00:23:30,450 --> 00:23:34,110
+إن شاء الله بنحل بعض المسائل أو بنشرح فكرة أنه لو
+
+299
+00:23:34,110 --> 00:23:38,530
+كان عندي أنا حركة بخط مستقيم لكن باتجاه ال Y-axis
+
+300
+00:23:38,530 --> 00:23:41,450
+وهي عبارة عن الـ Free Falling هنستكمل إن شاء الله
+
+301
+00:23:41,450 --> 00:23:42,750
+المحاضرة القادمة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NNZUj3-WXd0_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NNZUj3-WXd0_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..819d98148bab9bf820bf123a6dd8c9944034bf9f
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NNZUj3-WXd0_postprocess.srt
@@ -0,0 +1,1332 @@
+1
+00:00:00,000 --> 00:00:05,340
+بسم الله الرحمن الرحيم نستكمل محاضرات chapter
+
+2
+00:00:05,340 --> 00:00:10,020
+أربعة الآن section أربعة تلاتة the normal and
+
+3
+00:00:10,020 --> 00:00:14,040
+kinetic friction forces اللي هي قوة الاحتكاك وقوة
+
+4
+00:00:14,040 --> 00:00:17,140
+قوة رد الفاية العمودية اللي هي اسمها normal و ال
+
+5
+00:00:17,140 --> 00:00:20,890
+kinetic friction قوة الاحتكاكIn two-dimensional
+
+6
+00:00:20,890 --> 00:00:25,010
+second law problems, the Y component is often used
+
+7
+00:00:25,010 --> 00:00:28,510
+to determine the normal force acting on the object
+
+8
+00:00:28,510 --> 00:00:32,770
+في قانون نيوتن التاني اللي هو بيحكي مجموعة القوة
+
+9
+00:00:32,770 --> 00:00:38,010
+summation لل F بالساوية MA فإذا كنت أنا يعني ماشي
+
+10
+00:00:38,010 --> 00:00:42,370
+في اتجاه ال Y component مركبة ال Y فأنا بهد الحالة
+
+11
+00:00:42,370 --> 00:00:45,990
+والحركة باتجاه ال Xفبكون عندى انا مجموع القوة في
+
+12
+00:00:45,990 --> 00:00:49,790
+اتجاه ال Y بيبقى تساوي ال M في A Y المجموع القوة
+
+13
+00:00:49,790 --> 00:00:52,590
+في اتجاه ال Y هتكون اللى هى ال normal force من ضمن
+
+14
+00:00:52,590 --> 00:00:56,570
+هذه القوة اللى تؤثر على الجسم this section
+
+15
+00:00:56,570 --> 00:01:00,110
+introduce the most common four cases في هذا ال
+
+16
+00:01:00,110 --> 00:01:03,630
+section بنتكلم عن اربع حالاتEffectively, knowledge
+
+17
+00:01:03,630 --> 00:01:06,470
+of these four cases reduced many complexes to
+
+18
+00:01:06,470 --> 00:01:10,130
+codimensional, second-law problems to one
+
+19
+00:01:10,130 --> 00:01:12,830
+-dimensional problems because the normal force is
+
+20
+00:01:12,830 --> 00:01:16,630
+known as advanced طبعا في هذه .. في .. هنتكلم عن
+
+21
+00:01:16,630 --> 00:01:20,630
+أربع حالات للnormal force حسب وضع الجسم وإيجاد ال
+
+22
+00:01:20,630 --> 00:01:23,450
+normal force اللي هو قوة رد الفعل العمودية في
+
+23
+00:01:23,450 --> 00:01:28,600
+حالات مختلفةلأنه بصفة عامة normal force is used in
+
+24
+00:01:28,600 --> 00:01:32,500
+the x component of the second law ممكن أنا أستخدم
+
+25
+00:01:32,500 --> 00:01:36,680
+ال normal force للقوة في اتجاه ال X على أساس أنه
+
+26
+00:01:36,680 --> 00:01:40,660
+هي جزء من قوة الاحتكاك عند إيجاد قوة الاحتكاك فانا
+
+27
+00:01:40,660 --> 00:01:45,460
+محتاج قوة ال normal forcesection أربعة تلاتة واحدة
+
+28
+00:01:45,460 --> 00:01:48,360
+اللي هي ال case الأولى الحالة الأولى the normal
+
+29
+00:01:48,360 --> 00:01:53,180
+force on a level surface لما يكون عندي أنا إيجاد
+
+30
+00:01:53,180 --> 00:01:58,680
+قوة ترد الفعل العمودية على سطح يعني مستوي عندي أنا
+
+31
+00:01:58,680 --> 00:02:04,420
+الشكل اللي طبعا اللاحق shows a block traced at
+
+32
+00:02:04,420 --> 00:02:09,440
+flat surface في عندي أنا سطح يعني flat يعني مستوي
+
+33
+00:02:11,200 --> 00:02:14,060
+السطح المستوى موجود عليه كتلة اللي هي block كتلتها
+
+34
+00:02:14,060 --> 00:02:17,240
+M the two forces acting on the block are the
+
+35
+00:02:17,240 --> 00:02:22,620
+normal force في عندي أنا الشكل طبعا القادم سيوضح
+
+36
+00:02:22,620 --> 00:02:27,000
+إلي أنه في عندي أنا جسم كتلته M في عندي two يعني
+
+37
+00:02:27,000 --> 00:02:30,760
+كتلتين قوتين بتأثر على هذا الجسم عندي أنا جسم
+
+38
+00:02:30,760 --> 00:02:35,360
+كتلته Mالجسم ال M عند رسم ال free body diagram أو
+
+39
+00:02:35,360 --> 00:02:38,400
+القوة المؤثرة على هذا الجسم هذا الجسم breast
+
+40
+00:02:38,400 --> 00:02:42,500
+ماتتحركش معناته في عندي ال MG نازلة تحت ونتيجة
+
+41
+00:02:42,500 --> 00:02:45,660
+وجود هذا الجسم على السطح flat surface بيكون عندي
+
+42
+00:02:45,660 --> 00:02:49,760
+قوة رد الفعل عمودية اللي هي N لما أجي أرسم أنا ال
+
+43
+00:02:49,760 --> 00:02:52,960
+free body diagram برسمه بهذا الشكل هي الجسمو مين
+
+44
+00:02:52,960 --> 00:02:55,900
+القوة المؤثرة عليه في عندى ال normal force upward
+
+45
+00:02:55,900 --> 00:02:59,520
+يعني قوة رد الفعل العمودية إلى أعلى و قوة الوزن
+
+46
+00:02:59,520 --> 00:03:05,760
+إلى أسفل اللى هى اسمها ال MG طبعا هذا الشكل
+
+47
+00:03:05,760 --> 00:03:09,680
+بيعطينا ال free body diagram زى ما حكينا which for
+
+48
+00:03:09,680 --> 00:03:12,660
+clarity consists of showing thus the forces acting
+
+49
+00:03:12,660 --> 00:03:16,160
+on the block ال free body diagram بوضحلى فقط مين
+
+50
+00:03:16,160 --> 00:03:21,340
+القوة المؤثرة على الجسم بسميه ال free body diagram
+
+51
+00:03:21,770 --> 00:03:25,430
+included only the force acting directly on the
+
+52
+00:03:25,430 --> 00:03:30,650
+object بوضّح القوة التي تؤثر على الجسم مباشرة هذا
+
+53
+00:03:30,650 --> 00:03:35,230
+هو الشكل المثالة و هنا لازم نوضّح حاجة اسمها ال
+
+54
+00:03:35,230 --> 00:03:39,650
+free body diagram يعني المخطط التفصيلي للقوة
+
+55
+00:03:39,650 --> 00:03:44,730
+المؤثرة على الجسم طبعا الجسم كان at rest فعندي فقط
+
+56
+00:03:44,730 --> 00:03:50,010
+عندي قوتين رأسيتين في عند ال MG لتحت و في عند ال
+
+57
+00:03:50,010 --> 00:03:55,860
+normal force لأعلىلما بدأت أطبق قانون نيوتن التاني
+
+58
+00:03:55,860 --> 00:03:59,420
+على اتجاه ال Y summation لل FY بتساوي ال M في AY
+
+59
+00:03:59,420 --> 00:04:03,640
+طبعا طالما أنه مافي حركة باتجاه ال Y إذا ال normal
+
+60
+00:04:03,640 --> 00:04:07,940
+موجبة لإنها إلى أعلى ناقص ال MG لأسفل بتساوي سفر
+
+61
+00:04:07,940 --> 00:04:12,780
+لإن ال AY Zero لإن الجسم على يعني rest على flat
+
+62
+00:04:12,780 --> 00:04:17,430
+surface فال AY بدها تساوي Zero وليست Gإذا ال
+
+63
+00:04:17,430 --> 00:04:20,110
+normal في هذه الحالة بتساوي ال mg هذه حالة من
+
+64
+00:04:20,110 --> 00:04:25,470
+الحالات لما يكون الجسم موجود على flat surface فال
+
+65
+00:04:25,470 --> 00:04:30,070
+normal بتساوي ال mg وليس في كل الحالات وليس في كل
+
+66
+00:04:30,070 --> 00:04:34,850
+الحالات إذا الحالة التانية الآن ال case two the
+
+67
+00:04:34,850 --> 00:04:38,450
+normal force on a level surface with an applied
+
+68
+00:04:38,450 --> 00:04:43,590
+force لو كان عندي أنا جسم موجود على سطح يعني flat
+
+69
+00:04:43,590 --> 00:04:49,590
+ام لا يعني سطح مستويأنا قوة مؤثرة على هذا الجسم
+
+70
+00:04:49,590 --> 00:04:53,090
+الـ three forces acting on the block are the
+
+71
+00:04:53,090 --> 00:04:56,190
+normal force ففي هذه الحالة اللي بأثر على الجسم في
+
+72
+00:04:56,190 --> 00:05:00,450
+عندي ال normal force وفي عندي قوة الوزن الأسفل وفي
+
+73
+00:05:00,450 --> 00:05:03,610
+عندي طبعا قوة الوزن اللي هي gravity force قوة
+
+74
+00:05:03,610 --> 00:05:07,490
+الجاذبية الأسفل directed downwardand applied force
+
+75
+00:05:07,490 --> 00:05:11,110
+بقوة اللي هي المؤثرة على الجسم طبعا ممكن تكون
+
+76
+00:05:11,110 --> 00:05:14,570
+القوة باتجاه ال X-axis وممكن تكون القوة مائلة طبعا
+
+77
+00:05:14,570 --> 00:05:18,690
+هذا الشكل بيوضح ان في عندي أنا جسم كتلتو M في عندي
+
+78
+00:05:18,690 --> 00:05:21,430
+قوة F اللي هي applied force هذه ال F القوة اللي
+
+79
+00:05:21,430 --> 00:05:25,950
+أنا بعطيها له هذه القوة مؤثرة على الجسم وبتميل في
+
+80
+00:05:25,950 --> 00:05:30,060
+زاوية θطبعا في هذه الحالة بدي أرسم لـ free body
+
+81
+00:05:30,060 --> 00:05:34,020
+diagram لازم أحدد .. هو هذه ال F ال applied لازم
+
+82
+00:05:34,020 --> 00:05:37,360
+أنا أحللها إلى two components إلى المراكبات ..
+
+83
+00:05:37,360 --> 00:05:42,160
+المراكبات ال X axis و Y axis فبروح بحلل ال F إلى F
+
+84
+00:05:42,160 --> 00:05:45,720
+applied cosine و هنا .. هنا هتكون ال F applied
+
+85
+00:05:45,720 --> 00:05:49,840
+sine يعني هذه تقنع .. يعني موازية و هذه عمودية على
+
+86
+00:05:49,840 --> 00:05:54,820
+الصفحةلما اجى ارسم ال free body diagram ففي عند ال
+
+87
+00:05:54,820 --> 00:05:59,000
+normal force الا اعلى ايضا ال F applied sign الا
+
+88
+00:05:59,000 --> 00:06:03,520
+اعلى اتجاه السهم و ال MG الاسفل لما بدى اجى اعمل
+
+89
+00:06:03,520 --> 00:06:09,460
+اللي هي طبق قانون نيوتن التاني بنطبق قانون التاني
+
+90
+00:06:09,460 --> 00:06:12,040
+اول حاجة ال Y component of the second law of
+
+91
+00:06:12,040 --> 00:06:16,630
+motion مركبات ال Yبستخدم قانون يوتن التاني
+
+92
+00:06:16,630 --> 00:06:20,710
+summation للـfy بتساوي ال M في Ay بأجيب القوة اللي
+
+93
+00:06:20,710 --> 00:06:25,490
+في اتجاه ال Y كانت عند ال Normal موجبة وناقص MG
+
+94
+00:06:25,490 --> 00:06:29,170
+اللي هو قوة الجاذبية MG أو الوزن إلى أسفل ناقص
+
+95
+00:06:29,170 --> 00:06:33,450
+زائد ال F applied sin θ موجبة لإنه اتجاه ال vector
+
+96
+00:06:33,450 --> 00:06:37,690
+أو المتجه إلى أعلىكله بيساوي Zero هذا باتجاه ال Y
+
+97
+00:06:37,690 --> 00:06:41,470
+لإنه مافي حركة باتجاه ال Y ولكن الجسم هيتحرك على
+
+98
+00:06:41,470 --> 00:06:46,210
+سطح أفقي وبالتالي الحركة باتجاه ال X Axis فال AY
+
+99
+00:06:46,210 --> 00:06:48,890
+هنا بتساوي صفر إذا ال Normal في هذه الحالة بدها
+
+100
+00:06:48,890 --> 00:06:52,270
+تساوي ال MG ال MG بجيبها على الطرف التاني موجة
+
+101
+00:06:52,270 --> 00:06:58,810
+بناقص ال F Applied Sine F Theta في هذه الحالةطبعا
+
+102
+00:06:58,810 --> 00:07:03,590
+تلك المعادلة بسهولة تتم حل المعادلة السابقة
+
+103
+00:07:03,590 --> 00:07:06,070
+المعادلة السابقة حلتها أو جدت المعادلة السابقة
+
+104
+00:07:06,070 --> 00:07:09,230
+المعادلة السابقة بسهولة Mg ناقص F applied sin θ
+
+105
+00:07:09,230 --> 00:07:13,570
+إذا المعادلة السابقة الآن عند إضافة قوة إلى الجسم
+
+106
+00:07:14,340 --> 00:07:18,760
+تساوي mg ناقص ال F applied sin θ if the angle is
+
+107
+00:07:18,760 --> 00:07:22,460
+positive إذا كانت الزاوية sin الزاوية الآن هذه
+
+108
+00:07:22,460 --> 00:07:27,660
+كلها موجبة فبيكون طبعا الحد هذا كله سالب فال
+
+109
+00:07:27,660 --> 00:07:31,140
+normal بيكون ساعتها أقل من الوزن لأن normal بتساوي
+
+110
+00:07:31,140 --> 00:07:36,440
+ال mg ناقص هذا الحدلو كان sin θ موجب فالهدى الحد
+
+111
+00:07:36,440 --> 00:07:41,000
+كله هيكون سالب فال normal بدى يساوي mg ناقص هذا
+
+112
+00:07:41,000 --> 00:07:45,020
+الحد وبالتالي ال normal بدى يساوي أقل من الوزن ال
+
+113
+00:07:45,020 --> 00:07:49,160
+normal في هذه الحالة بدى يكون أقل من الوزن إذا
+
+114
+00:07:49,160 --> 00:07:54,520
+كانت الزاوية هذه في sin θ 0 إذا كانت سفر معنى
+
+115
+00:07:54,520 --> 00:07:58,380
+الكلام في هذه الحالة ال normal بدى يساوي ال mgIf
+
+116
+00:07:58,380 --> 00:08:01,520
+the angle is negative إذا الزاوية هذه كانت sign
+
+117
+00:08:01,520 --> 00:08:05,260
+الزاوية negative هذا ال sign negative معناته هذه
+
+118
+00:08:05,260 --> 00:08:08,400
+القيمة كلها بتكون موجبة فبصير عنا ال normal بده
+
+119
+00:08:08,400 --> 00:08:11,700
+يساوي ال MG زائد هذه القيمة وبالتالي ال normal بده
+
+120
+00:08:11,700 --> 00:08:16,320
+يساوي ال MG زائد قيمة إذا ال normal بده يساوي قيمة
+
+121
+00:08:16,320 --> 00:08:19,820
+أكبر من الوزن then this result is in positive
+
+122
+00:08:19,820 --> 00:08:23,820
+contribution to the normal force as كما هو مضح
+
+123
+00:08:23,820 --> 00:08:30,300
+بالشكل 4.15The normal force must be larger في هذه
+
+124
+00:08:30,300 --> 00:08:35,680
+الحالة حتكون قيمة ال normal force أكبر من الوزن
+
+125
+00:08:35,680 --> 00:08:39,760
+and in magnitude equal to the sum of the weight
+
+126
+00:08:39,760 --> 00:08:44,600
+and the y component of the applied forceزي ما هو
+
+127
+00:08:44,600 --> 00:08:49,400
+موضح في الشكل إذا كانت عندي أنا الحالة التانية هذا
+
+128
+00:08:49,400 --> 00:08:54,720
+لو كانت القوة موجهة إلى أسفل و الزاوية موجودة تحت
+
+129
+00:08:54,720 --> 00:09:00,020
+اتجاه X تحت محور X أو يعني بتعمل زاوية ثيتا مع
+
+130
+00:09:00,020 --> 00:09:03,780
+اتجاه X ولكن باتجاه السلب أو باتجاه عقارب الساعة
+
+131
+00:09:03,780 --> 00:09:07,620
+لما أجي أحلل هذه الزاوية راح أحللها إلى مركبتين
+
+132
+00:09:07,620 --> 00:09:10,620
+مركبة باتجاه ال X axis هتكون F applied
+
+133
+00:09:28,220 --> 00:09:32,550
+مجموع الهواء باتجاه ال Y هتكون in Nو بدها تساوي
+
+134
+00:09:32,550 --> 00:09:36,810
+ناقص mg ناقص ال f applied sine الزاوية فبطلع عندى
+
+135
+00:09:36,810 --> 00:09:41,590
+حسب ما انا بدى احدد بيه ال الهي f ال normal force
+
+136
+00:09:41,590 --> 00:09:46,690
+فده الحالة بدها تساوي ال mg زائد f applied sine
+
+137
+00:09:46,690 --> 00:09:51,710
+الزاوية معنى الكلام ان ال normal بيكون اقل ما يمكن
+
+138
+00:09:51,710 --> 00:09:57,440
+اذا كانإذا كانت الجسم مشدود بزاوية theta موجبة
+
+139
+00:09:57,440 --> 00:10:02,220
+يعني ال sign ال theta موجب بيكون قليل نوعا ما أو
+
+140
+00:10:02,220 --> 00:10:07,320
+بيساوي normal بيساوي ال MG إذا كانت الزاوية صفر و
+
+141
+00:10:07,320 --> 00:10:10,860
+بيكون عند ال normal بيضها تساوي ال MG زائد F
+
+142
+00:10:10,860 --> 00:10:13,860
+applied ال sign الزاوية بيكون يعني اللي بيساوي
+
+143
+00:10:13,860 --> 00:10:18,700
+larger أكتر من الوزن إذا كانت الزاوية موجودة أسفل
+
+144
+00:10:18,700 --> 00:10:23,260
+اللي هو ال X axis أو باتجاه السالبلـ X axis يعني
+
+145
+00:10:23,260 --> 00:10:29,250
+في بداية الربع الرابع الحالة التالتةالحالة التالتة
+
+146
+00:10:29,250 --> 00:10:32,130
+اللي هي normal force on a level surface under
+
+147
+00:10:32,130 --> 00:10:37,130
+acceleration لو كان عندي طبعا الشكل .. الشكل في
+
+148
+00:10:37,130 --> 00:10:40,950
+هذا الشكل لو كان عندي أنا جسم لو كان عندي أنا جسم
+
+149
+00:10:40,950 --> 00:10:45,510
+بتحرك زي المصعد جسم داخل المصعد و المصعد بيتحرك
+
+150
+00:10:45,510 --> 00:10:49,070
+فده الحالة في عندي أنا جسم هيه الأم الجسم هذا
+
+151
+00:10:49,070 --> 00:10:54,680
+wrist موجود على المصعدالمصعد بتحرك بحركة هادر
+
+152
+00:10:54,680 --> 00:10:59,140
+اتجاه ال MAA يعني في عندي تسارع إلى أعلى بدأ أرسم
+
+153
+00:10:59,140 --> 00:11:01,980
+ال free body diagram معناته عندي normal إلى أعلى و
+
+154
+00:11:01,980 --> 00:11:05,760
+عندي MG اللي هو قوة الوزن إلى أسفل في هذه الحالة
+
+155
+00:11:05,760 --> 00:11:10,210
+الجسم بتحرك باتجاه ال Y Axisإذا راح أحكي إنه
+
+156
+00:11:10,210 --> 00:11:13,910
+summation اللي هي للfy بدها تساوي ال M في Ay إذا
+
+157
+00:11:13,910 --> 00:11:18,570
+راح أحكي إنه ال normal ناقص ال MG بدها تساوي ال M
+
+158
+00:11:18,570 --> 00:11:23,250
+في A و بنرجع لاللي هي الحالة الشكل الموضة في عندي
+
+159
+00:11:23,250 --> 00:11:28,510
+أنا flat surface ال block موجود على سطح أفقيthat
+
+160
+00:11:28,510 --> 00:11:32,090
+is under acceleration تحت أثير تسارع زي اللي بيصير
+
+161
+00:11:32,090 --> 00:11:34,770
+عندنا في elevator اللي هو المصعد the two forces
+
+162
+00:11:34,770 --> 00:11:38,650
+acting on the block are the normal force اللي طبعا
+
+163
+00:11:38,650 --> 00:11:41,610
+في عنده قوتين بأثره على الجسم قوة رد الفعل
+
+164
+00:11:41,610 --> 00:11:45,550
+العمودية إلى أعلى وقوة الجاذبية اللي هو الوزن MG
+
+165
+00:11:45,550 --> 00:11:49,730
+لأسفل directed downwardan acceleration upward
+
+166
+00:11:49,730 --> 00:11:54,770
+والتسارع إلى أعلى بصفة عامة will increase the
+
+167
+00:11:54,770 --> 00:11:59,670
+magnitude of the normal force إذا هذا الشيء أو
+
+168
+00:11:59,670 --> 00:12:03,030
+التسارع إذا كان إلى أعلى بده يعمل على زيادة
+
+169
+00:12:03,030 --> 00:12:08,530
+increasing the magnitude of the normal force إذا
+
+170
+00:12:08,530 --> 00:12:12,740
+بده أطبق قانون نيوتن التاني على محور Yفي حالة ما
+
+171
+00:12:12,740 --> 00:12:16,880
+تكون .. في حالة ما تكون .. ما يكون الجسم موجود
+
+172
+00:12:16,880 --> 00:12:22,700
+داخل مسعد اذا summation للfy بتساوي ال M في Ay ال
+
+173
+00:12:22,700 --> 00:12:26,500
+normal موجبة ناقص MG بدها تساوي ال M في Ay اذا ال
+
+174
+00:12:26,500 --> 00:12:31,200
+normal في هذه الحالة بدها تساوي MAY زائد ال MG ال
+
+175
+00:12:31,200 --> 00:12:36,240
+normal بتساوي ال M في Ay زائد ال MG طبعا لأن الجسم
+
+176
+00:12:36,240 --> 00:12:41,040
+صاعد الأعلى في الAY بتكون موجبةلكن إذا كان الجسم
+
+177
+00:12:41,040 --> 00:12:46,380
+نازل إذا كان الجسم نازل لأسفل في هذه الحالة the
+
+178
+00:12:46,380 --> 00:12:48,700
+magnitude of the normal force vector must equal
+
+179
+00:12:48,700 --> 00:12:51,040
+the sum of the magnitude of the gravitational
+
+180
+00:12:51,040 --> 00:12:55,700
+forces and the inertial quantity اللي هي MA زي ما
+
+181
+00:12:55,700 --> 00:12:59,440
+احنا شوفنا بهذا الشكل لكن لو كان الجسم نازل إلى
+
+182
+00:12:59,440 --> 00:13:03,820
+أسفل لو كان الجسم نازل إلى أسفل و MA لتحت فبصير
+
+183
+00:13:03,820 --> 00:13:09,240
+عنده summation لل FY بدها تساوي ال M في AYهيكون
+
+184
+00:13:09,240 --> 00:13:12,600
+عندي ال normal ناقص ال mg بيضها تساوي ال m في ناقص
+
+185
+00:13:12,600 --> 00:13:16,120
+ال a يعني في هذه الحالة هيكون عندي ال normal بيضها
+
+186
+00:13:16,120 --> 00:13:22,000
+تساوي ال mg ناقص اللي هي بتطلع عندي ma ناقص ال mg
+
+187
+00:13:22,000 --> 00:13:26,890
+ma هيطلع عندي ناقص ال mgالحالة الرابعة اللي هي
+
+188
+00:13:26,890 --> 00:13:31,390
+normal force on a slope لو كان عندي أنا جسم موجود
+
+189
+00:13:31,390 --> 00:13:36,150
+على سطح مائل بزاوية ثيتا simplification of the
+
+190
+00:13:36,150 --> 00:13:38,770
+problem can be achieved by selecting coordinates
+
+191
+00:13:38,770 --> 00:13:43,310
+that are similarly titled with the x-axis running
+
+192
+00:13:43,310 --> 00:13:46,730
+parallel to the slope and y-axis perpendicular to
+
+193
+00:13:46,730 --> 00:13:49,690
+the slope زي ما هو موضح بالشكل طبعا لو كان عندي
+
+194
+00:13:49,690 --> 00:13:53,950
+أنا سطح مائل بزاوية ثيتافبدأ أخلّي أن السطح المايل
+
+195
+00:13:53,950 --> 00:13:58,510
+نفس السطح كأنه هو ال X axis و العمودي عليه كأنه ال
+
+196
+00:13:58,510 --> 00:14:03,210
+Y axis زي ما هو مضح بالشكل في عندي أنا جسم كتلته M
+
+197
+00:14:03,210 --> 00:14:08,950
+موجود على سطح مايل فلما بدأجي أحلل أول شي بنزل ال
+
+198
+00:14:08,950 --> 00:14:14,290
+MG عمودية في اتجاه الناقص Y عمودية في اتجاه الناقص
+
+199
+00:14:14,290 --> 00:14:18,430
+Y هذا قوة الجاذبية بعدين بحط ال normal عمودية على
+
+200
+00:14:18,430 --> 00:14:23,780
+السطح هي ال normal عمودية على السطحو بعدين بقى
+
+201
+00:14:23,780 --> 00:14:27,100
+أحلل ال MG على أساس أنه هذا السطح المايل هو
+
+202
+00:14:27,100 --> 00:14:32,220
+باعتبره X Axis و المستوى تبع ال Y باعتبره Y Axis
+
+203
+00:14:32,220 --> 00:14:35,260
+طبعا سمنها X شرطة و Y شرطة لإنه بيختلف عن ال X و
+
+204
+00:14:35,260 --> 00:14:40,700
+ال Y الأساسي فبدأ أحلل ال MG إلى قوتين مع السطح مع
+
+205
+00:14:40,700 --> 00:14:45,000
+السطح راح أحكي MG Sine Theta و العمودية على السطح
+
+206
+00:14:45,000 --> 00:14:51,430
+في هذا الاتجاه راح أحكي MG Cosine Thetaبدأ أطبخ
+
+207
+00:14:51,430 --> 00:14:56,270
+الآن قوانون نيوتن التاني the force due to the
+
+208
+00:14:56,270 --> 00:14:59,190
+gravity can then be broken into two components
+
+209
+00:14:59,190 --> 00:15:03,950
+بيحكي لإن مركبة ال MG ممكن أحللها إلى مركبتين اللي
+
+210
+00:15:03,950 --> 00:15:07,450
+هي Fx شرطة إلى ال gravity بتساوي ال MG sin بنفس
+
+211
+00:15:07,450 --> 00:15:12,540
+المستوىبنفسي على نفس سطح المستوى و ال fy شرطة
+
+212
+00:15:12,540 --> 00:15:16,760
+عبارة عن ناقص mg cos θ باطبق قانون ال newton
+
+213
+00:15:16,760 --> 00:15:22,080
+التاني على أساس أنه القوة الموازية للسطح بسميها x
+
+214
+00:15:22,080 --> 00:15:25,420
+axis شرطة و القوة العمودية على السطح بسميها ال y
+
+215
+00:15:25,420 --> 00:15:28,460
+axis شرطة فبصير عندي أنا مجموعة القوة بتجاه ال y
+
+216
+00:15:28,460 --> 00:15:33,540
+اللي هي ال normalنقص Mg cos θ بالساوي صفر لأنه
+
+217
+00:15:33,540 --> 00:15:37,860
+مافي حركة باتجاه ال Y هنا بدأ احكي هنا normal هيها
+
+218
+00:15:37,860 --> 00:15:43,480
+وهنا هتجيني Mg cos normal ناقص Mg cos ساوي سيرو
+
+219
+00:15:43,480 --> 00:15:47,030
+لأنه مافي حركة باتجاه ال Yهنحكي summation of fy
+
+220
+00:15:47,030 --> 00:15:50,870
+بتساوي m في ay ال normal موجبة على أساس أنه هذا
+
+221
+00:15:50,870 --> 00:15:55,830
+محور y الموجب ناقص mg cosine بتساوي ال m في ay و
+
+222
+00:15:55,830 --> 00:15:59,570
+ال ay في هذه الحالة zero إذن ال normal بتساوي mg
+
+223
+00:15:59,570 --> 00:16:04,050
+cosine الزاويةThe normal force on the slope is
+
+224
+00:16:04,050 --> 00:16:07,070
+equal to the magnitude بهاد الحالة بيحكيه لإن قوة
+
+225
+00:16:07,070 --> 00:16:12,010
+رد الفعل قوة رد الفعل العمودية تساوي ال component
+
+226
+00:16:12,010 --> 00:16:14,730
+of the gravity force perpendicular to the slope
+
+227
+00:16:14,730 --> 00:16:18,170
+اللي هي عبارة ال normal بساوي ال mg cosine it is
+
+228
+00:16:18,170 --> 00:16:22,190
+also useful to know that كمان لازم نعرف إنه the
+
+229
+00:16:22,190 --> 00:16:26,130
+force on the block directed down the slope due to
+
+230
+00:16:26,130 --> 00:16:31,520
+the gravity is إذن نيجي على المستوى نفسهمين القوة
+
+231
+00:16:31,520 --> 00:16:35,640
+المؤثرة على الجسم بالنسبة للمستوى فشلة mg sin θ
+
+232
+00:16:35,640 --> 00:16:40,720
+إذا ال Fx شرطة بدها تساوي ال mg sin θ في هذه
+
+233
+00:16:40,720 --> 00:16:43,940
+الحالة ممكن أحكي مجموعة القوة بتساوي ma إذا كان هو
+
+234
+00:16:43,940 --> 00:16:48,920
+بتحرك إذا كان هو بتحرك طبعا بيكون عندي mg sin θ
+
+235
+00:16:48,920 --> 00:16:54,850
+بتساوي max لكن هنا الجسم ساكن إذاالـ Fx شرطة
+
+236
+00:16:54,850 --> 00:17:00,290
+بتتساوي الـ mg sin θ باتجاه اللي هو ال surface أو
+
+237
+00:17:00,290 --> 00:17:04,210
+السطح المائل نفسه ال normal force هذه الجزئية عند
+
+238
+00:17:04,210 --> 00:17:09,490
+atomic pressure هذه طبعا احنا لغيينها في عندي
+
+239
+00:17:09,490 --> 00:17:14,720
+section اللي هو أربعة تلاتةThe force of kinetic
+
+240
+00:17:14,720 --> 00:17:20,440
+friction هي قوة الاحتكاك قوة الاحتكاك المتحرك
+
+241
+00:17:20,440 --> 00:17:23,660
+بالنسبة لحاجة اسمها ال friction اللي هو الاحتكاك
+
+242
+00:17:23,660 --> 00:17:26,860
+هو الاحتكاك عبارة عن contact force عبارة عن قوة
+
+243
+00:17:26,860 --> 00:17:30,580
+التلامس that derives from the microscopic
+
+244
+00:17:30,580 --> 00:17:34,480
+interaction between the body and its environment
+
+245
+00:17:34,480 --> 00:17:40,480
+هو عبارة عن قوة احتكاك بين الجسم و أي شيءفي
+
+246
+00:17:40,480 --> 00:17:44,160
+الطبيعة في تلامس بينه وبينها ده بيسميه قوة احتكاك
+
+247
+00:17:44,160 --> 00:17:48,880
+عبارة عن قوة تلامس زي مثلا ال air friction احتكاك
+
+248
+00:17:48,880 --> 00:17:54,520
+اللي هو effect vehicles from cars to rockets ممكن
+
+249
+00:17:54,520 --> 00:17:59,850
+ال fluid friction برضهفي عندي احتكاك للسوائل بتأثر
+
+250
+00:17:59,850 --> 00:18:04,470
+على حركة السوائل ممكن تحرك على the passage of the
+
+251
+00:18:04,470 --> 00:18:08,550
+fluid in pipes ال friction is not always something
+
+252
+00:18:08,550 --> 00:18:13,390
+that embeds motion على أي حال without friction we
+
+253
+00:18:13,390 --> 00:18:18,550
+would be able to walk or pick up and hold objects
+
+254
+00:18:18,910 --> 00:18:23,170
+يعني ممكن الجسم نعتبر ال friction ممكن يكون ال
+
+255
+00:18:23,170 --> 00:18:26,650
+friction ساكن أو friction على سطح أملس أو friction
+
+256
+00:18:26,650 --> 00:18:32,470
+على سطح متحرك خشن طبعا هذا ال friction ممكن أنه
+
+257
+00:18:32,470 --> 00:18:36,810
+يسبب caused when an object is in contact يعني أي
+
+258
+00:18:36,810 --> 00:18:43,180
+frictionأي احتكاك يظهر معايا في السؤال بسبب وجود
+
+259
+00:18:43,180 --> 00:18:47,100
+contact بأي سطح في حاجة اسمها ال kinetic friction
+
+260
+00:18:47,100 --> 00:18:50,400
+اللي هو الاحتكاك المتحرك is a friction that arises
+
+261
+00:18:50,400 --> 00:18:55,580
+during motion هذا الاحتكاك المتحرك طبعا يظهر اندي
+
+262
+00:18:55,580 --> 00:19:00,960
+او يكون موجودبسبب وجود اللي هي حركة للجسم it
+
+263
+00:19:00,960 --> 00:19:03,580
+depends on the material هذا الاحتكاك المتحرك
+
+264
+00:19:03,580 --> 00:19:07,980
+بيعتمد على المادة and the surface are made على نوع
+
+265
+00:19:07,980 --> 00:19:12,440
+السطح من أي مادة مصنوعة ونوع السطح as well as how
+
+266
+00:19:12,440 --> 00:19:15,760
+smooth they are and how firmly that are in contact
+
+267
+00:19:15,760 --> 00:19:20,700
+هل هو يعني مدى نعومته او مدى خشونة هذا السطحالـ
+
+268
+00:19:20,700 --> 00:19:24,420
+Normal force is the measured of the fire mass of
+
+269
+00:19:24,420 --> 00:19:27,740
+the contact طبعا ال normal force لها علاقة بال
+
+270
+00:19:27,740 --> 00:19:32,080
+contact لها علاقة بالسطح نفسه لها علاقة في ال
+
+271
+00:19:32,080 --> 00:19:35,380
+frictional force it makes sense that the larger
+
+272
+00:19:35,380 --> 00:19:38,300
+the normal force a surface exerted on an object
+
+273
+00:19:38,300 --> 00:19:42,040
+ضرورية طبعا ال normal force لها علاقة بقانون ال
+
+274
+00:19:42,040 --> 00:19:45,390
+frictionوالها علاقة مباشرة بقانون ال friction
+
+275
+00:19:45,390 --> 00:19:50,710
+بتعطيني مدى حساسية هذا السطح ومدى قوة الاحتكاك من
+
+276
+00:19:50,710 --> 00:19:55,230
+قيمة ال normal force المؤثرة على الجسم the larger
+
+277
+00:19:55,230 --> 00:19:58,830
+the kinetic friction force بيكون عنده اللي هو ال
+
+278
+00:19:58,830 --> 00:20:01,970
+normal force is larger في علاقة ترضية بين ال
+
+279
+00:20:01,970 --> 00:20:05,470
+normal force و بين ال kinetic frictional force في
+
+280
+00:20:05,470 --> 00:20:10,690
+علاقة ترضية بين ال normal force و بين قوة الاحتكاك
+
+281
+00:20:10,690 --> 00:20:16,240
+على السطحالـ kinetic friction قوة الاحتكاك المتحرك
+
+282
+00:20:16,240 --> 00:20:20,940
+طبعا هذه قوة احتكاك متحرك هذا نوع من قوة الاحتكاك
+
+283
+00:20:20,940 --> 00:20:24,140
+the magnitude of the kinetic friction قيمة
+
+284
+00:20:24,140 --> 00:20:28,100
+الاحتكاك قوة الاحتكاك المتحرك يرمز لها بالرمز FK
+
+285
+00:20:28,100 --> 00:20:33,400
+الاحتكاك هذا المتحرك acting on an object moving on
+
+286
+00:20:33,400 --> 00:20:36,820
+surface is given by طبعا قانون هذه قوة الاحتكاك
+
+287
+00:20:36,820 --> 00:20:40,880
+بتساوي Mu K في الnormalالـ Normal هي عبارة عن قوة
+
+288
+00:20:40,880 --> 00:20:45,980
+الرد الفعل العمودية اللى بتأثر على الجسم والميوكة
+
+289
+00:20:45,980 --> 00:20:49,000
+بيسموها ال coefficient of kinetic friction أو
+
+290
+00:20:49,000 --> 00:20:53,360
+معامل الاحتكاك المتحرك طبعا هذا معامل الاحتكاك
+
+291
+00:20:53,360 --> 00:20:56,480
+بيعتمد على نوع الجسم زى ما حكينا على نوع السطح
+
+292
+00:20:56,480 --> 00:21:00,740
+وعلى ال material مادة هذا الجسمالـ coefficient of
+
+293
+00:21:00,740 --> 00:21:04,200
+country friction هو معامل الاحتكاك المتحرك بين
+
+294
+00:21:04,200 --> 00:21:08,800
+الجسم والسطح the force FK acts in the direction
+
+295
+00:21:08,800 --> 00:21:11,720
+opposite that of the motion من مميزات ال
+
+296
+00:21:11,720 --> 00:21:15,980
+frictional force قوة الاحتكاك انها بتكون عكس اتجاه
+
+297
+00:21:15,980 --> 00:21:20,380
+الحركة كمان قوة الاحتكاك بتكون عمودية على ال
+
+298
+00:21:20,380 --> 00:21:24,920
+normal force قوة الاحتكاك بتكون موازية للصفح هذه
+
+299
+00:21:24,920 --> 00:21:31,640
+من مميزات قوة الاحتكاكهيكون عندى انا طبعا دياجرام
+
+300
+00:21:31,640 --> 00:21:36,000
+بيوضح the effect of a kind of friction force in a
+
+301
+00:21:36,000 --> 00:21:41,240
+block قوة الاحتكاك و تأثيرها على الجسم لو كان عندى
+
+302
+00:21:41,240 --> 00:21:46,540
+انا جسم موجود على صفح و الصفح هذا يعني عنده
+
+303
+00:21:46,540 --> 00:21:50,280
+الاحتكاك فى معامل احتكاك بين الجسم و بين الصفح
+
+304
+00:21:50,280 --> 00:21:55,100
+الجسم هذا انا حركته بقوة applied force القوة دى
+
+305
+00:21:55,100 --> 00:21:59,480
+ميلة بزاوية θو في عندى طبعا طالما ان انا بتحرك
+
+306
+00:21:59,480 --> 00:22:02,720
+باتجاه في عندى MA في حركة باتجاه اليمين او باتجاه
+
+307
+00:22:02,720 --> 00:22:07,480
+ال waist في عندى قوة احتكاك FK عكس باتجاه الحركة
+
+308
+00:22:07,480 --> 00:22:11,540
+طبعا اول حاجة بنعملها في هذا السؤال انه احلل زى ما
+
+309
+00:22:11,540 --> 00:22:15,360
+حكينا ال F applied إلى two component بدي انا احلل
+
+310
+00:22:15,360 --> 00:22:19,340
+analysis the F applied into two componentبدي أحلل
+
+311
+00:22:19,340 --> 00:22:24,240
+القوة المعطاة إلى مركبتين F applied cos θ هيها
+
+312
+00:22:24,240 --> 00:22:28,280
+والـ F applied sin θ الآن أنا بدي أتحرك بالقوة
+
+313
+00:22:28,280 --> 00:22:33,180
+الموجودة على summation للـ Fx بتساوي MFAX من القوة
+
+314
+00:22:33,180 --> 00:22:36,500
+الموجودة على الـ Fx اللي هي F applied موجبة cos θ
+
+315
+00:22:36,500 --> 00:22:43,360
+ناقص الـ Fk بتساوي MFA طبعا لإيجاد الـ Fk بحتاج
+
+316
+00:22:43,360 --> 00:22:49,130
+أنا الnormal إذا بدي أجي أطبق المعادلاتالـ x
+
+317
+00:22:49,130 --> 00:22:52,490
+component of the second law of the motion هحكي انا
+
+318
+00:22:52,490 --> 00:22:58,090
+انه ال Fax بتساوي الموجة ب Fax اللي هي اللي هي
+
+319
+00:22:58,090 --> 00:23:01,170
+باتجاه اللي هي F applied cosine ال .. F applied
+
+320
+00:23:01,170 --> 00:23:05,610
+cosine ال theta ناقص ال Fk F cosine .. F applied
+
+321
+00:23:05,610 --> 00:23:08,610
+cosine ال theta ناقص ال Fk ال Fk بتساوي ميو K في
+
+322
+00:23:08,610 --> 00:23:13,500
+ال normalالان بدأ اوجد ال normal محتاجين نوجد ال
+
+323
+00:23:13,500 --> 00:23:18,340
+normal فبنروح على مين على اتجاه ال y axis لإيجاد
+
+324
+00:23:18,340 --> 00:23:22,660
+ال normal اذا مافي حركة باتجاه ال normal فاتجاه ال
+
+325
+00:23:22,660 --> 00:23:27,320
+normal عندي F normal زائد F applied sin θ بدها
+
+326
+00:23:27,320 --> 00:23:31,940
+تساوي ال mg اذا ال normal بدها تساوي ال mg ناقص ال
+
+327
+00:23:31,940 --> 00:23:36,620
+F applied sin θ و بنعود فيه ال normal في هذه
+
+328
+00:23:36,620 --> 00:23:42,500
+المعادلة اذا ال maxبدها تساوي F applied cos θ ناقص
+
+329
+00:23:42,500 --> 00:23:46,580
+Mu K مضروبة في ال normal اللي هي ال MG ناقص F
+
+330
+00:23:46,580 --> 00:23:49,360
+applied sin θ فهذه الحالة ال normal ما بتساوي ال
+
+331
+00:23:49,360 --> 00:23:53,900
+MG ولكن حسب السؤال احنا بنطلع ال normal و بنعوض
+
+332
+00:23:53,900 --> 00:23:57,480
+فيها المرة القادمة ان شاء الله بنتكلم عن ال static
+
+333
+00:23:57,480 --> 00:23:59,580
+friction وهي قوة الاحتكاك الساكن
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NNZUj3-WXd0_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NNZUj3-WXd0_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..819d98148bab9bf820bf123a6dd8c9944034bf9f
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NNZUj3-WXd0_raw.srt
@@ -0,0 +1,1332 @@
+1
+00:00:00,000 --> 00:00:05,340
+بسم الله الرحمن الرحيم نستكمل محاضرات chapter
+
+2
+00:00:05,340 --> 00:00:10,020
+أربعة الآن section أربعة تلاتة the normal and
+
+3
+00:00:10,020 --> 00:00:14,040
+kinetic friction forces اللي هي قوة الاحتكاك وقوة
+
+4
+00:00:14,040 --> 00:00:17,140
+قوة رد الفاية العمودية اللي هي اسمها normal و ال
+
+5
+00:00:17,140 --> 00:00:20,890
+kinetic friction قوة الاحتكاكIn two-dimensional
+
+6
+00:00:20,890 --> 00:00:25,010
+second law problems, the Y component is often used
+
+7
+00:00:25,010 --> 00:00:28,510
+to determine the normal force acting on the object
+
+8
+00:00:28,510 --> 00:00:32,770
+في قانون نيوتن التاني اللي هو بيحكي مجموعة القوة
+
+9
+00:00:32,770 --> 00:00:38,010
+summation لل F بالساوية MA فإذا كنت أنا يعني ماشي
+
+10
+00:00:38,010 --> 00:00:42,370
+في اتجاه ال Y component مركبة ال Y فأنا بهد الحالة
+
+11
+00:00:42,370 --> 00:00:45,990
+والحركة باتجاه ال Xفبكون عندى انا مجموع القوة في
+
+12
+00:00:45,990 --> 00:00:49,790
+اتجاه ال Y بيبقى تساوي ال M في A Y المجموع القوة
+
+13
+00:00:49,790 --> 00:00:52,590
+في اتجاه ال Y هتكون اللى هى ال normal force من ضمن
+
+14
+00:00:52,590 --> 00:00:56,570
+هذه القوة اللى تؤثر على الجسم this section
+
+15
+00:00:56,570 --> 00:01:00,110
+introduce the most common four cases في هذا ال
+
+16
+00:01:00,110 --> 00:01:03,630
+section بنتكلم عن اربع حالاتEffectively, knowledge
+
+17
+00:01:03,630 --> 00:01:06,470
+of these four cases reduced many complexes to
+
+18
+00:01:06,470 --> 00:01:10,130
+codimensional, second-law problems to one
+
+19
+00:01:10,130 --> 00:01:12,830
+-dimensional problems because the normal force is
+
+20
+00:01:12,830 --> 00:01:16,630
+known as advanced طبعا في هذه .. في .. هنتكلم عن
+
+21
+00:01:16,630 --> 00:01:20,630
+أربع حالات للnormal force حسب وضع الجسم وإيجاد ال
+
+22
+00:01:20,630 --> 00:01:23,450
+normal force اللي هو قوة رد الفعل العمودية في
+
+23
+00:01:23,450 --> 00:01:28,600
+حالات مختلفةلأنه بصفة عامة normal force is used in
+
+24
+00:01:28,600 --> 00:01:32,500
+the x component of the second law ممكن أنا أستخدم
+
+25
+00:01:32,500 --> 00:01:36,680
+ال normal force للقوة في اتجاه ال X على أساس أنه
+
+26
+00:01:36,680 --> 00:01:40,660
+هي جزء من قوة الاحتكاك عند إيجاد قوة الاحتكاك فانا
+
+27
+00:01:40,660 --> 00:01:45,460
+محتاج قوة ال normal forcesection أربعة تلاتة واحدة
+
+28
+00:01:45,460 --> 00:01:48,360
+اللي هي ال case الأولى الحالة الأولى the normal
+
+29
+00:01:48,360 --> 00:01:53,180
+force on a level surface لما يكون عندي أنا إيجاد
+
+30
+00:01:53,180 --> 00:01:58,680
+قوة ترد الفعل العمودية على سطح يعني مستوي عندي أنا
+
+31
+00:01:58,680 --> 00:02:04,420
+الشكل اللي طبعا اللاحق shows a block traced at
+
+32
+00:02:04,420 --> 00:02:09,440
+flat surface في عندي أنا سطح يعني flat يعني مستوي
+
+33
+00:02:11,200 --> 00:02:14,060
+السطح المستوى موجود عليه كتلة اللي هي block كتلتها
+
+34
+00:02:14,060 --> 00:02:17,240
+M the two forces acting on the block are the
+
+35
+00:02:17,240 --> 00:02:22,620
+normal force في عندي أنا الشكل طبعا القادم سيوضح
+
+36
+00:02:22,620 --> 00:02:27,000
+إلي أنه في عندي أنا جسم كتلته M في عندي two يعني
+
+37
+00:02:27,000 --> 00:02:30,760
+كتلتين قوتين بتأثر على هذا الجسم عندي أنا جسم
+
+38
+00:02:30,760 --> 00:02:35,360
+كتلته Mالجسم ال M عند رسم ال free body diagram أو
+
+39
+00:02:35,360 --> 00:02:38,400
+القوة المؤثرة على هذا الجسم هذا الجسم breast
+
+40
+00:02:38,400 --> 00:02:42,500
+ماتتحركش معناته في عندي ال MG نازلة تحت ونتيجة
+
+41
+00:02:42,500 --> 00:02:45,660
+وجود هذا الجسم على السطح flat surface بيكون عندي
+
+42
+00:02:45,660 --> 00:02:49,760
+قوة رد الفعل عمودية اللي هي N لما أجي أرسم أنا ال
+
+43
+00:02:49,760 --> 00:02:52,960
+free body diagram برسمه بهذا الشكل هي الجسمو مين
+
+44
+00:02:52,960 --> 00:02:55,900
+القوة المؤثرة عليه في عندى ال normal force upward
+
+45
+00:02:55,900 --> 00:02:59,520
+يعني قوة رد الفعل العمودية إلى أعلى و قوة الوزن
+
+46
+00:02:59,520 --> 00:03:05,760
+إلى أسفل اللى هى اسمها ال MG طبعا هذا الشكل
+
+47
+00:03:05,760 --> 00:03:09,680
+بيعطينا ال free body diagram زى ما حكينا which for
+
+48
+00:03:09,680 --> 00:03:12,660
+clarity consists of showing thus the forces acting
+
+49
+00:03:12,660 --> 00:03:16,160
+on the block ال free body diagram بوضحلى فقط مين
+
+50
+00:03:16,160 --> 00:03:21,340
+القوة المؤثرة على الجسم بسميه ال free body diagram
+
+51
+00:03:21,770 --> 00:03:25,430
+included only the force acting directly on the
+
+52
+00:03:25,430 --> 00:03:30,650
+object بوضّح القوة التي تؤثر على الجسم مباشرة هذا
+
+53
+00:03:30,650 --> 00:03:35,230
+هو الشكل المثالة و هنا لازم نوضّح حاجة اسمها ال
+
+54
+00:03:35,230 --> 00:03:39,650
+free body diagram يعني المخطط التفصيلي للقوة
+
+55
+00:03:39,650 --> 00:03:44,730
+المؤثرة على الجسم طبعا الجسم كان at rest فعندي فقط
+
+56
+00:03:44,730 --> 00:03:50,010
+عندي قوتين رأسيتين في عند ال MG لتحت و في عند ال
+
+57
+00:03:50,010 --> 00:03:55,860
+normal force لأعلىلما بدأت أطبق قانون نيوتن التاني
+
+58
+00:03:55,860 --> 00:03:59,420
+على اتجاه ال Y summation لل FY بتساوي ال M في AY
+
+59
+00:03:59,420 --> 00:04:03,640
+طبعا طالما أنه مافي حركة باتجاه ال Y إذا ال normal
+
+60
+00:04:03,640 --> 00:04:07,940
+موجبة لإنها إلى أعلى ناقص ال MG لأسفل بتساوي سفر
+
+61
+00:04:07,940 --> 00:04:12,780
+لإن ال AY Zero لإن الجسم على يعني rest على flat
+
+62
+00:04:12,780 --> 00:04:17,430
+surface فال AY بدها تساوي Zero وليست Gإذا ال
+
+63
+00:04:17,430 --> 00:04:20,110
+normal في هذه الحالة بتساوي ال mg هذه حالة من
+
+64
+00:04:20,110 --> 00:04:25,470
+الحالات لما يكون الجسم موجود على flat surface فال
+
+65
+00:04:25,470 --> 00:04:30,070
+normal بتساوي ال mg وليس في كل الحالات وليس في كل
+
+66
+00:04:30,070 --> 00:04:34,850
+الحالات إذا الحالة التانية الآن ال case two the
+
+67
+00:04:34,850 --> 00:04:38,450
+normal force on a level surface with an applied
+
+68
+00:04:38,450 --> 00:04:43,590
+force لو كان عندي أنا جسم موجود على سطح يعني flat
+
+69
+00:04:43,590 --> 00:04:49,590
+ام لا يعني سطح مستويأنا قوة مؤثرة على هذا الجسم
+
+70
+00:04:49,590 --> 00:04:53,090
+الـ three forces acting on the block are the
+
+71
+00:04:53,090 --> 00:04:56,190
+normal force ففي هذه الحالة اللي بأثر على الجسم في
+
+72
+00:04:56,190 --> 00:05:00,450
+عندي ال normal force وفي عندي قوة الوزن الأسفل وفي
+
+73
+00:05:00,450 --> 00:05:03,610
+عندي طبعا قوة الوزن اللي هي gravity force قوة
+
+74
+00:05:03,610 --> 00:05:07,490
+الجاذبية الأسفل directed downwardand applied force
+
+75
+00:05:07,490 --> 00:05:11,110
+بقوة اللي هي المؤثرة على الجسم طبعا ممكن تكون
+
+76
+00:05:11,110 --> 00:05:14,570
+القوة باتجاه ال X-axis وممكن تكون القوة مائلة طبعا
+
+77
+00:05:14,570 --> 00:05:18,690
+هذا الشكل بيوضح ان في عندي أنا جسم كتلتو M في عندي
+
+78
+00:05:18,690 --> 00:05:21,430
+قوة F اللي هي applied force هذه ال F القوة اللي
+
+79
+00:05:21,430 --> 00:05:25,950
+أنا بعطيها له هذه القوة مؤثرة على الجسم وبتميل في
+
+80
+00:05:25,950 --> 00:05:30,060
+زاوية θطبعا في هذه الحالة بدي أرسم لـ free body
+
+81
+00:05:30,060 --> 00:05:34,020
+diagram لازم أحدد .. هو هذه ال F ال applied لازم
+
+82
+00:05:34,020 --> 00:05:37,360
+أنا أحللها إلى two components إلى المراكبات ..
+
+83
+00:05:37,360 --> 00:05:42,160
+المراكبات ال X axis و Y axis فبروح بحلل ال F إلى F
+
+84
+00:05:42,160 --> 00:05:45,720
+applied cosine و هنا .. هنا هتكون ال F applied
+
+85
+00:05:45,720 --> 00:05:49,840
+sine يعني هذه تقنع .. يعني موازية و هذه عمودية على
+
+86
+00:05:49,840 --> 00:05:54,820
+الصفحةلما اجى ارسم ال free body diagram ففي عند ال
+
+87
+00:05:54,820 --> 00:05:59,000
+normal force الا اعلى ايضا ال F applied sign الا
+
+88
+00:05:59,000 --> 00:06:03,520
+اعلى اتجاه السهم و ال MG الاسفل لما بدى اجى اعمل
+
+89
+00:06:03,520 --> 00:06:09,460
+اللي هي طبق قانون نيوتن التاني بنطبق قانون التاني
+
+90
+00:06:09,460 --> 00:06:12,040
+اول حاجة ال Y component of the second law of
+
+91
+00:06:12,040 --> 00:06:16,630
+motion مركبات ال Yبستخدم قانون يوتن التاني
+
+92
+00:06:16,630 --> 00:06:20,710
+summation للـfy بتساوي ال M في Ay بأجيب القوة اللي
+
+93
+00:06:20,710 --> 00:06:25,490
+في اتجاه ال Y كانت عند ال Normal موجبة وناقص MG
+
+94
+00:06:25,490 --> 00:06:29,170
+اللي هو قوة الجاذبية MG أو الوزن إلى أسفل ناقص
+
+95
+00:06:29,170 --> 00:06:33,450
+زائد ال F applied sin θ موجبة لإنه اتجاه ال vector
+
+96
+00:06:33,450 --> 00:06:37,690
+أو المتجه إلى أعلىكله بيساوي Zero هذا باتجاه ال Y
+
+97
+00:06:37,690 --> 00:06:41,470
+لإنه مافي حركة باتجاه ال Y ولكن الجسم هيتحرك على
+
+98
+00:06:41,470 --> 00:06:46,210
+سطح أفقي وبالتالي الحركة باتجاه ال X Axis فال AY
+
+99
+00:06:46,210 --> 00:06:48,890
+هنا بتساوي صفر إذا ال Normal في هذه الحالة بدها
+
+100
+00:06:48,890 --> 00:06:52,270
+تساوي ال MG ال MG بجيبها على الطرف التاني موجة
+
+101
+00:06:52,270 --> 00:06:58,810
+بناقص ال F Applied Sine F Theta في هذه الحالةطبعا
+
+102
+00:06:58,810 --> 00:07:03,590
+تلك المعادلة بسهولة تتم حل المعادلة السابقة
+
+103
+00:07:03,590 --> 00:07:06,070
+المعادلة السابقة حلتها أو جدت المعادلة السابقة
+
+104
+00:07:06,070 --> 00:07:09,230
+المعادلة السابقة بسهولة Mg ناقص F applied sin θ
+
+105
+00:07:09,230 --> 00:07:13,570
+إذا المعادلة السابقة الآن عند إضافة قوة إلى الجسم
+
+106
+00:07:14,340 --> 00:07:18,760
+تساوي mg ناقص ال F applied sin θ if the angle is
+
+107
+00:07:18,760 --> 00:07:22,460
+positive إذا كانت الزاوية sin الزاوية الآن هذه
+
+108
+00:07:22,460 --> 00:07:27,660
+كلها موجبة فبيكون طبعا الحد هذا كله سالب فال
+
+109
+00:07:27,660 --> 00:07:31,140
+normal بيكون ساعتها أقل من الوزن لأن normal بتساوي
+
+110
+00:07:31,140 --> 00:07:36,440
+ال mg ناقص هذا الحدلو كان sin θ موجب فالهدى الحد
+
+111
+00:07:36,440 --> 00:07:41,000
+كله هيكون سالب فال normal بدى يساوي mg ناقص هذا
+
+112
+00:07:41,000 --> 00:07:45,020
+الحد وبالتالي ال normal بدى يساوي أقل من الوزن ال
+
+113
+00:07:45,020 --> 00:07:49,160
+normal في هذه الحالة بدى يكون أقل من الوزن إذا
+
+114
+00:07:49,160 --> 00:07:54,520
+كانت الزاوية هذه في sin θ 0 إذا كانت سفر معنى
+
+115
+00:07:54,520 --> 00:07:58,380
+الكلام في هذه الحالة ال normal بدى يساوي ال mgIf
+
+116
+00:07:58,380 --> 00:08:01,520
+the angle is negative إذا الزاوية هذه كانت sign
+
+117
+00:08:01,520 --> 00:08:05,260
+الزاوية negative هذا ال sign negative معناته هذه
+
+118
+00:08:05,260 --> 00:08:08,400
+القيمة كلها بتكون موجبة فبصير عنا ال normal بده
+
+119
+00:08:08,400 --> 00:08:11,700
+يساوي ال MG زائد هذه القيمة وبالتالي ال normal بده
+
+120
+00:08:11,700 --> 00:08:16,320
+يساوي ال MG زائد قيمة إذا ال normal بده يساوي قيمة
+
+121
+00:08:16,320 --> 00:08:19,820
+أكبر من الوزن then this result is in positive
+
+122
+00:08:19,820 --> 00:08:23,820
+contribution to the normal force as كما هو مضح
+
+123
+00:08:23,820 --> 00:08:30,300
+بالشكل 4.15The normal force must be larger في هذه
+
+124
+00:08:30,300 --> 00:08:35,680
+الحالة حتكون قيمة ال normal force أكبر من الوزن
+
+125
+00:08:35,680 --> 00:08:39,760
+and in magnitude equal to the sum of the weight
+
+126
+00:08:39,760 --> 00:08:44,600
+and the y component of the applied forceزي ما هو
+
+127
+00:08:44,600 --> 00:08:49,400
+موضح في الشكل إذا كانت عندي أنا الحالة التانية هذا
+
+128
+00:08:49,400 --> 00:08:54,720
+لو كانت القوة موجهة إلى أسفل و الزاوية موجودة تحت
+
+129
+00:08:54,720 --> 00:09:00,020
+اتجاه X تحت محور X أو يعني بتعمل زاوية ثيتا مع
+
+130
+00:09:00,020 --> 00:09:03,780
+اتجاه X ولكن باتجاه السلب أو باتجاه عقارب الساعة
+
+131
+00:09:03,780 --> 00:09:07,620
+لما أجي أحلل هذه الزاوية راح أحللها إلى مركبتين
+
+132
+00:09:07,620 --> 00:09:10,620
+مركبة باتجاه ال X axis هتكون F applied
+
+133
+00:09:28,220 --> 00:09:32,550
+مجموع الهواء باتجاه ال Y هتكون in Nو بدها تساوي
+
+134
+00:09:32,550 --> 00:09:36,810
+ناقص mg ناقص ال f applied sine الزاوية فبطلع عندى
+
+135
+00:09:36,810 --> 00:09:41,590
+حسب ما انا بدى احدد بيه ال الهي f ال normal force
+
+136
+00:09:41,590 --> 00:09:46,690
+فده الحالة بدها تساوي ال mg زائد f applied sine
+
+137
+00:09:46,690 --> 00:09:51,710
+الزاوية معنى الكلام ان ال normal بيكون اقل ما يمكن
+
+138
+00:09:51,710 --> 00:09:57,440
+اذا كانإذا كانت الجسم مشدود بزاوية theta موجبة
+
+139
+00:09:57,440 --> 00:10:02,220
+يعني ال sign ال theta موجب بيكون قليل نوعا ما أو
+
+140
+00:10:02,220 --> 00:10:07,320
+بيساوي normal بيساوي ال MG إذا كانت الزاوية صفر و
+
+141
+00:10:07,320 --> 00:10:10,860
+بيكون عند ال normal بيضها تساوي ال MG زائد F
+
+142
+00:10:10,860 --> 00:10:13,860
+applied ال sign الزاوية بيكون يعني اللي بيساوي
+
+143
+00:10:13,860 --> 00:10:18,700
+larger أكتر من الوزن إذا كانت الزاوية موجودة أسفل
+
+144
+00:10:18,700 --> 00:10:23,260
+اللي هو ال X axis أو باتجاه السالبلـ X axis يعني
+
+145
+00:10:23,260 --> 00:10:29,250
+في بداية الربع الرابع الحالة التالتةالحالة التالتة
+
+146
+00:10:29,250 --> 00:10:32,130
+اللي هي normal force on a level surface under
+
+147
+00:10:32,130 --> 00:10:37,130
+acceleration لو كان عندي طبعا الشكل .. الشكل في
+
+148
+00:10:37,130 --> 00:10:40,950
+هذا الشكل لو كان عندي أنا جسم لو كان عندي أنا جسم
+
+149
+00:10:40,950 --> 00:10:45,510
+بتحرك زي المصعد جسم داخل المصعد و المصعد بيتحرك
+
+150
+00:10:45,510 --> 00:10:49,070
+فده الحالة في عندي أنا جسم هيه الأم الجسم هذا
+
+151
+00:10:49,070 --> 00:10:54,680
+wrist موجود على المصعدالمصعد بتحرك بحركة هادر
+
+152
+00:10:54,680 --> 00:10:59,140
+اتجاه ال MAA يعني في عندي تسارع إلى أعلى بدأ أرسم
+
+153
+00:10:59,140 --> 00:11:01,980
+ال free body diagram معناته عندي normal إلى أعلى و
+
+154
+00:11:01,980 --> 00:11:05,760
+عندي MG اللي هو قوة الوزن إلى أسفل في هذه الحالة
+
+155
+00:11:05,760 --> 00:11:10,210
+الجسم بتحرك باتجاه ال Y Axisإذا راح أحكي إنه
+
+156
+00:11:10,210 --> 00:11:13,910
+summation اللي هي للfy بدها تساوي ال M في Ay إذا
+
+157
+00:11:13,910 --> 00:11:18,570
+راح أحكي إنه ال normal ناقص ال MG بدها تساوي ال M
+
+158
+00:11:18,570 --> 00:11:23,250
+في A و بنرجع لاللي هي الحالة الشكل الموضة في عندي
+
+159
+00:11:23,250 --> 00:11:28,510
+أنا flat surface ال block موجود على سطح أفقيthat
+
+160
+00:11:28,510 --> 00:11:32,090
+is under acceleration تحت أثير تسارع زي اللي بيصير
+
+161
+00:11:32,090 --> 00:11:34,770
+عندنا في elevator اللي هو المصعد the two forces
+
+162
+00:11:34,770 --> 00:11:38,650
+acting on the block are the normal force اللي طبعا
+
+163
+00:11:38,650 --> 00:11:41,610
+في عنده قوتين بأثره على الجسم قوة رد الفعل
+
+164
+00:11:41,610 --> 00:11:45,550
+العمودية إلى أعلى وقوة الجاذبية اللي هو الوزن MG
+
+165
+00:11:45,550 --> 00:11:49,730
+لأسفل directed downwardan acceleration upward
+
+166
+00:11:49,730 --> 00:11:54,770
+والتسارع إلى أعلى بصفة عامة will increase the
+
+167
+00:11:54,770 --> 00:11:59,670
+magnitude of the normal force إذا هذا الشيء أو
+
+168
+00:11:59,670 --> 00:12:03,030
+التسارع إذا كان إلى أعلى بده يعمل على زيادة
+
+169
+00:12:03,030 --> 00:12:08,530
+increasing the magnitude of the normal force إذا
+
+170
+00:12:08,530 --> 00:12:12,740
+بده أطبق قانون نيوتن التاني على محور Yفي حالة ما
+
+171
+00:12:12,740 --> 00:12:16,880
+تكون .. في حالة ما تكون .. ما يكون الجسم موجود
+
+172
+00:12:16,880 --> 00:12:22,700
+داخل مسعد اذا summation للfy بتساوي ال M في Ay ال
+
+173
+00:12:22,700 --> 00:12:26,500
+normal موجبة ناقص MG بدها تساوي ال M في Ay اذا ال
+
+174
+00:12:26,500 --> 00:12:31,200
+normal في هذه الحالة بدها تساوي MAY زائد ال MG ال
+
+175
+00:12:31,200 --> 00:12:36,240
+normal بتساوي ال M في Ay زائد ال MG طبعا لأن الجسم
+
+176
+00:12:36,240 --> 00:12:41,040
+صاعد الأعلى في الAY بتكون موجبةلكن إذا كان الجسم
+
+177
+00:12:41,040 --> 00:12:46,380
+نازل إذا كان الجسم نازل لأسفل في هذه الحالة the
+
+178
+00:12:46,380 --> 00:12:48,700
+magnitude of the normal force vector must equal
+
+179
+00:12:48,700 --> 00:12:51,040
+the sum of the magnitude of the gravitational
+
+180
+00:12:51,040 --> 00:12:55,700
+forces and the inertial quantity اللي هي MA زي ما
+
+181
+00:12:55,700 --> 00:12:59,440
+احنا شوفنا بهذا الشكل لكن لو كان الجسم نازل إلى
+
+182
+00:12:59,440 --> 00:13:03,820
+أسفل لو كان الجسم نازل إلى أسفل و MA لتحت فبصير
+
+183
+00:13:03,820 --> 00:13:09,240
+عنده summation لل FY بدها تساوي ال M في AYهيكون
+
+184
+00:13:09,240 --> 00:13:12,600
+عندي ال normal ناقص ال mg بيضها تساوي ال m في ناقص
+
+185
+00:13:12,600 --> 00:13:16,120
+ال a يعني في هذه الحالة هيكون عندي ال normal بيضها
+
+186
+00:13:16,120 --> 00:13:22,000
+تساوي ال mg ناقص اللي هي بتطلع عندي ma ناقص ال mg
+
+187
+00:13:22,000 --> 00:13:26,890
+ma هيطلع عندي ناقص ال mgالحالة الرابعة اللي هي
+
+188
+00:13:26,890 --> 00:13:31,390
+normal force on a slope لو كان عندي أنا جسم موجود
+
+189
+00:13:31,390 --> 00:13:36,150
+على سطح مائل بزاوية ثيتا simplification of the
+
+190
+00:13:36,150 --> 00:13:38,770
+problem can be achieved by selecting coordinates
+
+191
+00:13:38,770 --> 00:13:43,310
+that are similarly titled with the x-axis running
+
+192
+00:13:43,310 --> 00:13:46,730
+parallel to the slope and y-axis perpendicular to
+
+193
+00:13:46,730 --> 00:13:49,690
+the slope زي ما هو موضح بالشكل طبعا لو كان عندي
+
+194
+00:13:49,690 --> 00:13:53,950
+أنا سطح مائل بزاوية ثيتافبدأ أخلّي أن السطح المايل
+
+195
+00:13:53,950 --> 00:13:58,510
+نفس السطح كأنه هو ال X axis و العمودي عليه كأنه ال
+
+196
+00:13:58,510 --> 00:14:03,210
+Y axis زي ما هو مضح بالشكل في عندي أنا جسم كتلته M
+
+197
+00:14:03,210 --> 00:14:08,950
+موجود على سطح مايل فلما بدأجي أحلل أول شي بنزل ال
+
+198
+00:14:08,950 --> 00:14:14,290
+MG عمودية في اتجاه الناقص Y عمودية في اتجاه الناقص
+
+199
+00:14:14,290 --> 00:14:18,430
+Y هذا قوة الجاذبية بعدين بحط ال normal عمودية على
+
+200
+00:14:18,430 --> 00:14:23,780
+السطح هي ال normal عمودية على السطحو بعدين بقى
+
+201
+00:14:23,780 --> 00:14:27,100
+أحلل ال MG على أساس أنه هذا السطح المايل هو
+
+202
+00:14:27,100 --> 00:14:32,220
+باعتبره X Axis و المستوى تبع ال Y باعتبره Y Axis
+
+203
+00:14:32,220 --> 00:14:35,260
+طبعا سمنها X شرطة و Y شرطة لإنه بيختلف عن ال X و
+
+204
+00:14:35,260 --> 00:14:40,700
+ال Y الأساسي فبدأ أحلل ال MG إلى قوتين مع السطح مع
+
+205
+00:14:40,700 --> 00:14:45,000
+السطح راح أحكي MG Sine Theta و العمودية على السطح
+
+206
+00:14:45,000 --> 00:14:51,430
+في هذا الاتجاه راح أحكي MG Cosine Thetaبدأ أطبخ
+
+207
+00:14:51,430 --> 00:14:56,270
+الآن قوانون نيوتن التاني the force due to the
+
+208
+00:14:56,270 --> 00:14:59,190
+gravity can then be broken into two components
+
+209
+00:14:59,190 --> 00:15:03,950
+بيحكي لإن مركبة ال MG ممكن أحللها إلى مركبتين اللي
+
+210
+00:15:03,950 --> 00:15:07,450
+هي Fx شرطة إلى ال gravity بتساوي ال MG sin بنفس
+
+211
+00:15:07,450 --> 00:15:12,540
+المستوىبنفسي على نفس سطح المستوى و ال fy شرطة
+
+212
+00:15:12,540 --> 00:15:16,760
+عبارة عن ناقص mg cos θ باطبق قانون ال newton
+
+213
+00:15:16,760 --> 00:15:22,080
+التاني على أساس أنه القوة الموازية للسطح بسميها x
+
+214
+00:15:22,080 --> 00:15:25,420
+axis شرطة و القوة العمودية على السطح بسميها ال y
+
+215
+00:15:25,420 --> 00:15:28,460
+axis شرطة فبصير عندي أنا مجموعة القوة بتجاه ال y
+
+216
+00:15:28,460 --> 00:15:33,540
+اللي هي ال normalنقص Mg cos θ بالساوي صفر لأنه
+
+217
+00:15:33,540 --> 00:15:37,860
+مافي حركة باتجاه ال Y هنا بدأ احكي هنا normal هيها
+
+218
+00:15:37,860 --> 00:15:43,480
+وهنا هتجيني Mg cos normal ناقص Mg cos ساوي سيرو
+
+219
+00:15:43,480 --> 00:15:47,030
+لأنه مافي حركة باتجاه ال Yهنحكي summation of fy
+
+220
+00:15:47,030 --> 00:15:50,870
+بتساوي m في ay ال normal موجبة على أساس أنه هذا
+
+221
+00:15:50,870 --> 00:15:55,830
+محور y الموجب ناقص mg cosine بتساوي ال m في ay و
+
+222
+00:15:55,830 --> 00:15:59,570
+ال ay في هذه الحالة zero إذن ال normal بتساوي mg
+
+223
+00:15:59,570 --> 00:16:04,050
+cosine الزاويةThe normal force on the slope is
+
+224
+00:16:04,050 --> 00:16:07,070
+equal to the magnitude بهاد الحالة بيحكيه لإن قوة
+
+225
+00:16:07,070 --> 00:16:12,010
+رد الفعل قوة رد الفعل العمودية تساوي ال component
+
+226
+00:16:12,010 --> 00:16:14,730
+of the gravity force perpendicular to the slope
+
+227
+00:16:14,730 --> 00:16:18,170
+اللي هي عبارة ال normal بساوي ال mg cosine it is
+
+228
+00:16:18,170 --> 00:16:22,190
+also useful to know that كمان لازم نعرف إنه the
+
+229
+00:16:22,190 --> 00:16:26,130
+force on the block directed down the slope due to
+
+230
+00:16:26,130 --> 00:16:31,520
+the gravity is إذن نيجي على المستوى نفسهمين القوة
+
+231
+00:16:31,520 --> 00:16:35,640
+المؤثرة على الجسم بالنسبة للمستوى فشلة mg sin θ
+
+232
+00:16:35,640 --> 00:16:40,720
+إذا ال Fx شرطة بدها تساوي ال mg sin θ في هذه
+
+233
+00:16:40,720 --> 00:16:43,940
+الحالة ممكن أحكي مجموعة القوة بتساوي ma إذا كان هو
+
+234
+00:16:43,940 --> 00:16:48,920
+بتحرك إذا كان هو بتحرك طبعا بيكون عندي mg sin θ
+
+235
+00:16:48,920 --> 00:16:54,850
+بتساوي max لكن هنا الجسم ساكن إذاالـ Fx شرطة
+
+236
+00:16:54,850 --> 00:17:00,290
+بتتساوي الـ mg sin θ باتجاه اللي هو ال surface أو
+
+237
+00:17:00,290 --> 00:17:04,210
+السطح المائل نفسه ال normal force هذه الجزئية عند
+
+238
+00:17:04,210 --> 00:17:09,490
+atomic pressure هذه طبعا احنا لغيينها في عندي
+
+239
+00:17:09,490 --> 00:17:14,720
+section اللي هو أربعة تلاتةThe force of kinetic
+
+240
+00:17:14,720 --> 00:17:20,440
+friction هي قوة الاحتكاك قوة الاحتكاك المتحرك
+
+241
+00:17:20,440 --> 00:17:23,660
+بالنسبة لحاجة اسمها ال friction اللي هو الاحتكاك
+
+242
+00:17:23,660 --> 00:17:26,860
+هو الاحتكاك عبارة عن contact force عبارة عن قوة
+
+243
+00:17:26,860 --> 00:17:30,580
+التلامس that derives from the microscopic
+
+244
+00:17:30,580 --> 00:17:34,480
+interaction between the body and its environment
+
+245
+00:17:34,480 --> 00:17:40,480
+هو عبارة عن قوة احتكاك بين الجسم و أي شيءفي
+
+246
+00:17:40,480 --> 00:17:44,160
+الطبيعة في تلامس بينه وبينها ده بيسميه قوة احتكاك
+
+247
+00:17:44,160 --> 00:17:48,880
+عبارة عن قوة تلامس زي مثلا ال air friction احتكاك
+
+248
+00:17:48,880 --> 00:17:54,520
+اللي هو effect vehicles from cars to rockets ممكن
+
+249
+00:17:54,520 --> 00:17:59,850
+ال fluid friction برضهفي عندي احتكاك للسوائل بتأثر
+
+250
+00:17:59,850 --> 00:18:04,470
+على حركة السوائل ممكن تحرك على the passage of the
+
+251
+00:18:04,470 --> 00:18:08,550
+fluid in pipes ال friction is not always something
+
+252
+00:18:08,550 --> 00:18:13,390
+that embeds motion على أي حال without friction we
+
+253
+00:18:13,390 --> 00:18:18,550
+would be able to walk or pick up and hold objects
+
+254
+00:18:18,910 --> 00:18:23,170
+يعني ممكن الجسم نعتبر ال friction ممكن يكون ال
+
+255
+00:18:23,170 --> 00:18:26,650
+friction ساكن أو friction على سطح أملس أو friction
+
+256
+00:18:26,650 --> 00:18:32,470
+على سطح متحرك خشن طبعا هذا ال friction ممكن أنه
+
+257
+00:18:32,470 --> 00:18:36,810
+يسبب caused when an object is in contact يعني أي
+
+258
+00:18:36,810 --> 00:18:43,180
+frictionأي احتكاك يظهر معايا في السؤال بسبب وجود
+
+259
+00:18:43,180 --> 00:18:47,100
+contact بأي سطح في حاجة اسمها ال kinetic friction
+
+260
+00:18:47,100 --> 00:18:50,400
+اللي هو الاحتكاك المتحرك is a friction that arises
+
+261
+00:18:50,400 --> 00:18:55,580
+during motion هذا الاحتكاك المتحرك طبعا يظهر اندي
+
+262
+00:18:55,580 --> 00:19:00,960
+او يكون موجودبسبب وجود اللي هي حركة للجسم it
+
+263
+00:19:00,960 --> 00:19:03,580
+depends on the material هذا الاحتكاك المتحرك
+
+264
+00:19:03,580 --> 00:19:07,980
+بيعتمد على المادة and the surface are made على نوع
+
+265
+00:19:07,980 --> 00:19:12,440
+السطح من أي مادة مصنوعة ونوع السطح as well as how
+
+266
+00:19:12,440 --> 00:19:15,760
+smooth they are and how firmly that are in contact
+
+267
+00:19:15,760 --> 00:19:20,700
+هل هو يعني مدى نعومته او مدى خشونة هذا السطحالـ
+
+268
+00:19:20,700 --> 00:19:24,420
+Normal force is the measured of the fire mass of
+
+269
+00:19:24,420 --> 00:19:27,740
+the contact طبعا ال normal force لها علاقة بال
+
+270
+00:19:27,740 --> 00:19:32,080
+contact لها علاقة بالسطح نفسه لها علاقة في ال
+
+271
+00:19:32,080 --> 00:19:35,380
+frictional force it makes sense that the larger
+
+272
+00:19:35,380 --> 00:19:38,300
+the normal force a surface exerted on an object
+
+273
+00:19:38,300 --> 00:19:42,040
+ضرورية طبعا ال normal force لها علاقة بقانون ال
+
+274
+00:19:42,040 --> 00:19:45,390
+frictionوالها علاقة مباشرة بقانون ال friction
+
+275
+00:19:45,390 --> 00:19:50,710
+بتعطيني مدى حساسية هذا السطح ومدى قوة الاحتكاك من
+
+276
+00:19:50,710 --> 00:19:55,230
+قيمة ال normal force المؤثرة على الجسم the larger
+
+277
+00:19:55,230 --> 00:19:58,830
+the kinetic friction force بيكون عنده اللي هو ال
+
+278
+00:19:58,830 --> 00:20:01,970
+normal force is larger في علاقة ترضية بين ال
+
+279
+00:20:01,970 --> 00:20:05,470
+normal force و بين ال kinetic frictional force في
+
+280
+00:20:05,470 --> 00:20:10,690
+علاقة ترضية بين ال normal force و بين قوة الاحتكاك
+
+281
+00:20:10,690 --> 00:20:16,240
+على السطحالـ kinetic friction قوة الاحتكاك المتحرك
+
+282
+00:20:16,240 --> 00:20:20,940
+طبعا هذه قوة احتكاك متحرك هذا نوع من قوة الاحتكاك
+
+283
+00:20:20,940 --> 00:20:24,140
+the magnitude of the kinetic friction قيمة
+
+284
+00:20:24,140 --> 00:20:28,100
+الاحتكاك قوة الاحتكاك المتحرك يرمز لها بالرمز FK
+
+285
+00:20:28,100 --> 00:20:33,400
+الاحتكاك هذا المتحرك acting on an object moving on
+
+286
+00:20:33,400 --> 00:20:36,820
+surface is given by طبعا قانون هذه قوة الاحتكاك
+
+287
+00:20:36,820 --> 00:20:40,880
+بتساوي Mu K في الnormalالـ Normal هي عبارة عن قوة
+
+288
+00:20:40,880 --> 00:20:45,980
+الرد الفعل العمودية اللى بتأثر على الجسم والميوكة
+
+289
+00:20:45,980 --> 00:20:49,000
+بيسموها ال coefficient of kinetic friction أو
+
+290
+00:20:49,000 --> 00:20:53,360
+معامل الاحتكاك المتحرك طبعا هذا معامل الاحتكاك
+
+291
+00:20:53,360 --> 00:20:56,480
+بيعتمد على نوع الجسم زى ما حكينا على نوع السطح
+
+292
+00:20:56,480 --> 00:21:00,740
+وعلى ال material مادة هذا الجسمالـ coefficient of
+
+293
+00:21:00,740 --> 00:21:04,200
+country friction هو معامل الاحتكاك المتحرك بين
+
+294
+00:21:04,200 --> 00:21:08,800
+الجسم والسطح the force FK acts in the direction
+
+295
+00:21:08,800 --> 00:21:11,720
+opposite that of the motion من مميزات ال
+
+296
+00:21:11,720 --> 00:21:15,980
+frictional force قوة الاحتكاك انها بتكون عكس اتجاه
+
+297
+00:21:15,980 --> 00:21:20,380
+الحركة كمان قوة الاحتكاك بتكون عمودية على ال
+
+298
+00:21:20,380 --> 00:21:24,920
+normal force قوة الاحتكاك بتكون موازية للصفح هذه
+
+299
+00:21:24,920 --> 00:21:31,640
+من مميزات قوة الاحتكاكهيكون عندى انا طبعا دياجرام
+
+300
+00:21:31,640 --> 00:21:36,000
+بيوضح the effect of a kind of friction force in a
+
+301
+00:21:36,000 --> 00:21:41,240
+block قوة الاحتكاك و تأثيرها على الجسم لو كان عندى
+
+302
+00:21:41,240 --> 00:21:46,540
+انا جسم موجود على صفح و الصفح هذا يعني عنده
+
+303
+00:21:46,540 --> 00:21:50,280
+الاحتكاك فى معامل احتكاك بين الجسم و بين الصفح
+
+304
+00:21:50,280 --> 00:21:55,100
+الجسم هذا انا حركته بقوة applied force القوة دى
+
+305
+00:21:55,100 --> 00:21:59,480
+ميلة بزاوية θو في عندى طبعا طالما ان انا بتحرك
+
+306
+00:21:59,480 --> 00:22:02,720
+باتجاه في عندى MA في حركة باتجاه اليمين او باتجاه
+
+307
+00:22:02,720 --> 00:22:07,480
+ال waist في عندى قوة احتكاك FK عكس باتجاه الحركة
+
+308
+00:22:07,480 --> 00:22:11,540
+طبعا اول حاجة بنعملها في هذا السؤال انه احلل زى ما
+
+309
+00:22:11,540 --> 00:22:15,360
+حكينا ال F applied إلى two component بدي انا احلل
+
+310
+00:22:15,360 --> 00:22:19,340
+analysis the F applied into two componentبدي أحلل
+
+311
+00:22:19,340 --> 00:22:24,240
+القوة المعطاة إلى مركبتين F applied cos θ هيها
+
+312
+00:22:24,240 --> 00:22:28,280
+والـ F applied sin θ الآن أنا بدي أتحرك بالقوة
+
+313
+00:22:28,280 --> 00:22:33,180
+الموجودة على summation للـ Fx بتساوي MFAX من القوة
+
+314
+00:22:33,180 --> 00:22:36,500
+الموجودة على الـ Fx اللي هي F applied موجبة cos θ
+
+315
+00:22:36,500 --> 00:22:43,360
+ناقص الـ Fk بتساوي MFA طبعا لإيجاد الـ Fk بحتاج
+
+316
+00:22:43,360 --> 00:22:49,130
+أنا الnormal إذا بدي أجي أطبق المعادلاتالـ x
+
+317
+00:22:49,130 --> 00:22:52,490
+component of the second law of the motion هحكي انا
+
+318
+00:22:52,490 --> 00:22:58,090
+انه ال Fax بتساوي الموجة ب Fax اللي هي اللي هي
+
+319
+00:22:58,090 --> 00:23:01,170
+باتجاه اللي هي F applied cosine ال .. F applied
+
+320
+00:23:01,170 --> 00:23:05,610
+cosine ال theta ناقص ال Fk F cosine .. F applied
+
+321
+00:23:05,610 --> 00:23:08,610
+cosine ال theta ناقص ال Fk ال Fk بتساوي ميو K في
+
+322
+00:23:08,610 --> 00:23:13,500
+ال normalالان بدأ اوجد ال normal محتاجين نوجد ال
+
+323
+00:23:13,500 --> 00:23:18,340
+normal فبنروح على مين على اتجاه ال y axis لإيجاد
+
+324
+00:23:18,340 --> 00:23:22,660
+ال normal اذا مافي حركة باتجاه ال normal فاتجاه ال
+
+325
+00:23:22,660 --> 00:23:27,320
+normal عندي F normal زائد F applied sin θ بدها
+
+326
+00:23:27,320 --> 00:23:31,940
+تساوي ال mg اذا ال normal بدها تساوي ال mg ناقص ال
+
+327
+00:23:31,940 --> 00:23:36,620
+F applied sin θ و بنعود فيه ال normal في هذه
+
+328
+00:23:36,620 --> 00:23:42,500
+المعادلة اذا ال maxبدها تساوي F applied cos θ ناقص
+
+329
+00:23:42,500 --> 00:23:46,580
+Mu K مضروبة في ال normal اللي هي ال MG ناقص F
+
+330
+00:23:46,580 --> 00:23:49,360
+applied sin θ فهذه الحالة ال normal ما بتساوي ال
+
+331
+00:23:49,360 --> 00:23:53,900
+MG ولكن حسب السؤال احنا بنطلع ال normal و بنعوض
+
+332
+00:23:53,900 --> 00:23:57,480
+فيها المرة القادمة ان شاء الله بنتكلم عن ال static
+
+333
+00:23:57,480 --> 00:23:59,580
+friction وهي قوة الاحتكاك الساكن
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NZ3sivP_tAw_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NZ3sivP_tAw_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..6b60b59a785c9d82f3a6adb29d81f8e7508c94c4
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NZ3sivP_tAw_raw.json
@@ -0,0 +1 @@
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M1", "probability": 0.991455078125}, {"start": 68.26, "end": 68.66, "word": " طبعا", "probability": 0.9725341796875}, {"start": 68.66, "end": 69.8, "word": " كتلتين", "probability": 0.9744140625}, {"start": 69.8, "end": 70.84, "word": " معلقات", "probability": 0.95849609375}, {"start": 70.84, "end": 71.48, "word": " بخيط", "probability": 0.9757080078125}, {"start": 71.48, "end": 72.36, "word": " الخيط", "probability": 0.9632161458333334}, {"start": 72.36, "end": 72.68, "word": " هذا", "probability": 0.79541015625}, {"start": 72.68, "end": 73.4, "word": " خفيف", "probability": 0.9729817708333334}], "temperature": 1.0}, {"id": 4, "seek": 10317, "start": 73.89, "end": 103.17, "text": "بسموه cord hung over frictionless pulley طبعا بواسطة بكرة بكرة ملساق هذا الحبلين طبعا أو الحبل كتلته مجهولة مطلوب مني find the magnitude of the acceleration أوجد قيمة التسارع لهذا ال system وشد في الخيط طبعا هذا ال .. هذا الكتلتين بسميهم system عندي كتلتين او واحد او اتنين", "tokens": [3555, 38251, 2407, 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"probability": 0.9552408854166666}, {"start": 884.17, "end": 884.95, "word": " فال", "probability": 0.942626953125}, {"start": 884.95, "end": 885.13, "word": " F", "probability": 0.69580078125}, {"start": 885.13, "end": 885.39, "word": " أسلة", "probability": 0.9794921875}, {"start": 885.39, "end": 885.69, "word": " الصغيرة", "probability": 0.97802734375}, {"start": 885.69, "end": 886.03, "word": " هتكون", "probability": 0.966796875}, {"start": 886.03, "end": 886.57, "word": " مساوية", "probability": 0.9111328125}, {"start": 886.57, "end": 886.93, "word": " إيها", "probability": 0.6746419270833334}, {"start": 886.93, "end": 887.11, "word": " في", "probability": 0.9462890625}, {"start": 887.11, "end": 887.53, "word": " المقدار", "probability": 0.99560546875}], "temperature": 1.0}, {"id": 35, "seek": 91517, "start": 887.81, "end": 915.17, "text": "ومتعاكسة بالاتجاه بسبب تلامس السطحين في عندي N واحد إلى أعلى وفي عندي MG إلى أسفل هدولة اللي هي ال free body diagram أو القوة المؤثرة عليها ال solution مطلوب find the maximum force بده أقصى قيمة للقوة التي تسحب الخط بحيث أنه الكتلة التي أعلى الكتلة الكتلة الصغيرة التي أعلى الكتلة الكبيرة", "tokens": [20498, 2655, 3615, 995, 4117, 3794, 3660, 20666, 9307, 7435, 40294, 4724, 35457, 3555, 6055, 37440, 3794, 21136, 9566, 5016, 9957, 8978, 18871, 16254, 426, 36764, 24401, 30731, 5551, 3615, 23942, 4032, 41185, 18871, 16254, 36856, 30731, 5551, 3794, 5172, 1211, 8032, 3215, 12610, 3660, 13672, 1829, 39896, 2423, 1737, 1772, 10686, 34051, 25062, 2407, 3660, 9673, 33604, 12984, 25720, 25894, 11296, 2423, 3827, 3714, 9566, 1211, 37746, 915, 264, 6674, 3464, 47525, 3224, 5551, 4587, 9381, 7578, 12174, 32640, 3660, 24976, 4587, 2407, 3660, 38392, 6055, 3794, 5016, 3555, 33962, 9566, 4724, 5016, 1829, 12984, 14739, 3224, 33251, 2655, 37977, 38392, 5551, 3615, 23942, 33251, 2655, 37977, 33251, 2655, 37977, 31767, 17082, 48923, 38392, 5551, 3615, 23942, 33251, 2655, 37977, 33251, 3555, 48923], "avg_logprob": -0.15312499809265137, 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{"start": 1033.59, "end": 1033.89, "word": " زائد", "probability": 0.7022705078125}, {"start": 1033.89, "end": 1034.05, "word": " M", "probability": 0.9912109375}, {"start": 1034.05, "end": 1034.25, "word": " في", "probability": 0.90576171875}, {"start": 1034.25, "end": 1034.49, "word": " A", "probability": 0.9853515625}, {"start": 1034.49, "end": 1035.07, "word": " إذا", "probability": 0.768798828125}, {"start": 1035.07, "end": 1035.19, "word": " أن", "probability": 0.400634765625}, {"start": 1035.19, "end": 1035.29, "word": " ال", "probability": 0.92431640625}, {"start": 1035.29, "end": 1035.35, "word": " A", "probability": 0.94140625}, {"start": 1035.35, "end": 1035.85, "word": " بتساوي", "probability": 0.956298828125}, {"start": 1035.85, "end": 1036.03, "word": " T", "probability": 0.90380859375}, {"start": 1036.03, "end": 1036.29, "word": " على", "probability": 0.873046875}, {"start": 1036.29, "end": 1037.75, "word": " مطلوب", "probability": 0.75592041015625}, {"start": 1037.75, 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"word": " تلاتة", "probability": 0.8494873046875}, {"start": 1041.87, "end": 1042.17, "word": " point", "probability": 0.9248046875}, {"start": 1042.17, "end": 1042.85, "word": " أربعة", "probability": 0.8038736979166666}, {"start": 1042.85, "end": 1043.47, "word": " تلاتة", "probability": 0.84588623046875}, {"start": 1043.47, "end": 1043.59, "word": " إذا", "probability": 0.937255859375}, {"start": 1043.59, "end": 1043.87, "word": " أخدت", "probability": 0.9263916015625}, {"start": 1043.87, "end": 1044.01, "word": " ال", "probability": 0.95654296875}, {"start": 1044.01, "end": 1044.47, "word": " system", "probability": 0.9814453125}, {"start": 1044.47, "end": 1045.55, "word": " كله", "probability": 0.878173828125}, {"start": 1045.55, "end": 1045.83, "word": " هيك", "probability": 0.82275390625}, {"start": 1045.83, "end": 1046.01, "word": " أحنا", "probability": 0.7821451822916666}, {"start": 1046.01, "end": 1046.33, "word": " بنكون", "probability": 0.90087890625}, {"start": 1046.33, 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NZ3sivP_tAw_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NZ3sivP_tAw_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..829e0d85c080205b64314adcc88a1fe935c8ffb8
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NZ3sivP_tAw_raw.srt
@@ -0,0 +1,932 @@
+1
+00:00:00,340 --> 00:00:04,860
+بسم الله الرحمن الرحيم بنستكمل chapter 4 section
+
+2
+00:00:04,860 --> 00:00:09,740
+47 بعنوان two body problems لو كان عندي أنا مسائل
+
+3
+00:00:09,740 --> 00:00:14,560
+تحتوي على جسمين Newton's second law of motion also
+
+4
+00:00:14,560 --> 00:00:17,000
+apply to the system of the object لو كان عندي أنا
+
+5
+00:00:17,000 --> 00:00:21,810
+يعني نظام عبارة عن أكتر من جسمممكن أستخدم قانون
+
+6
+00:00:21,810 --> 00:00:26,490
+نيوتن التاني طبعا if they are connected in some
+
+7
+00:00:26,490 --> 00:00:29,750
+way can influence each other يعني لو كانوا التنين
+
+8
+00:00:29,750 --> 00:00:33,890
+متصلين مع بعض ممكن التنين أو الجثمين بيأثروا على
+
+9
+00:00:33,890 --> 00:00:38,310
+بعض ممكن يكونوا جثمين أو تلاتة بنحل هاي المسائل
+
+10
+00:00:38,310 --> 00:00:43,010
+اللي بتكون من two bodies problem solving such two
+
+11
+00:00:43,010 --> 00:00:46,270
+body problems is a matter of writing the second
+
+12
+00:00:46,270 --> 00:00:50,740
+law for both objects بأستخدمقانون in Newton التاني
+
+13
+00:00:50,740 --> 00:00:57,420
+علشان أحل المسائل المكونة من أكتر مائن جسم هاي
+
+14
+00:00:57,420 --> 00:01:03,120
+example بيمثل عندي أنا جسمين كتلة الأول M1 وكتلة
+
+15
+00:01:03,120 --> 00:01:10,840
+التاني M2 with M2 أكبر من M1 طبعا كتلتين معلقات
+
+16
+00:01:10,840 --> 00:01:16,170
+بخيط الخيط هذا خفيفبسموه cord hung over
+
+17
+00:01:16,170 --> 00:01:21,830
+frictionless pulley طبعا بواسطة بكرة بكرة ملساق
+
+18
+00:01:21,830 --> 00:01:28,590
+هذا الحبلين طبعا أو الحبل كتلته مجهولة مطلوب مني
+
+19
+00:01:28,590 --> 00:01:32,310
+find the magnitude of the acceleration أوجد قيمة
+
+20
+00:01:32,310 --> 00:01:38,210
+التسارع لهذا ال system وشد في الخيط طبعا هذا ال ..
+
+21
+00:01:38,210 --> 00:01:42,710
+هذا الكتلتين بسميهم system عندي كتلتين او واحد او
+
+22
+00:01:42,710 --> 00:01:48,380
+اتنينM2 أكبر من M1 التنتين مربوطين بخيط بيسموه
+
+23
+00:01:48,380 --> 00:01:53,400
+light cord خيط خفيف الخيط الخفيف هذا اسمه massless
+
+24
+00:01:53,400 --> 00:01:58,920
+يعني بنهمي وزنه أو كتلته بيتحرك الإشارة هذه معناته
+
+25
+00:01:58,920 --> 00:02:01,740
+في عندي حركة للكتلة الأولى اللي أعلى و الكتلة
+
+26
+00:02:01,740 --> 00:02:05,820
+التانية اللي أسفل باستخدم قانون ال Newton التاني
+
+27
+00:02:05,820 --> 00:02:10,020
+لجسمين لكن قبل ما أستخدم القوانين لازم أرسم ال
+
+28
+00:02:10,020 --> 00:02:15,520
+free body diagram للكتلة الأولى M1و M2 M1 معرضة
+
+29
+00:02:15,520 --> 00:02:20,740
+إلى الشد في هذا الاتجاه هي الأعلى باتجاه البكرة
+
+30
+00:02:20,740 --> 00:02:26,340
+طالع من الجسم وكمان لها وزن M1G M2 فيه برضه شد
+
+31
+00:02:26,340 --> 00:02:29,740
+طالع من الجسم ناحية البكرة وفي عنده اللي هو الوزن
+
+32
+00:02:29,740 --> 00:02:35,840
+M2G والتسارع إلى أسفل بالنسبة للكتلة M2 علشان انحل
+
+33
+00:02:35,840 --> 00:02:40,450
+بستخدم قانون نيوتن التانيرح أحكي للجسم الأول في
+
+34
+00:02:40,450 --> 00:02:45,890
+عندي انا T الشد إلى أعلى موجب ناقص M1G إلى أسفل
+
+35
+00:02:45,890 --> 00:02:49,450
+بعتبرها سالب يعني مجموعة القوة باتجاه طبعا هذه
+
+36
+00:02:49,450 --> 00:02:53,250
+هيكون القوة باتجاه ال Y ساوة Zero اذا T ناقص M1G
+
+37
+00:02:53,250 --> 00:02:59,470
+بساوة M1 في A1 و الكتلة التانية رح يكون T ناقص M2G
+
+38
+00:02:59,470 --> 00:03:08,210
+بساوة M2 في A2 لكن A1 كانت موجبةأو A2 بيساوي ناقص
+
+39
+00:03:08,210 --> 00:03:13,730
+A1 لكن التسارع الأول هو نفسه التسارع التاني ولكن
+
+40
+00:03:13,730 --> 00:03:18,510
+في اتجاه المعاكس فإذا اللي هي معادلة الكتلة
+
+41
+00:03:18,510 --> 00:03:24,690
+التانية هتصير M2A 1 بيساوي ناقص T زائد M2G ممكن
+
+42
+00:03:24,690 --> 00:03:29,370
+أعتبر أن A1 بيساوي A2 بيساوي A لكن واحدة موجبة أو
+
+43
+00:03:29,370 --> 00:03:32,530
+واحدة سالبة لأن الأولاني بتحرك إلى أعلى والكتلة
+
+44
+00:03:32,530 --> 00:03:35,310
+التانية بتحرك إلى أسفل يعني اللي أعلى كانت تسارعها
+
+45
+00:03:35,310 --> 00:03:40,200
+موجبةو عند تحركها إلى أسفل بيكون تسارعها A سالب
+
+46
+00:03:40,200 --> 00:03:44,580
+بدي أجمع المعادلة الأولى و التالتة عشان أوجد قيمة
+
+47
+00:03:44,580 --> 00:03:51,320
+ال A بتساوي M2-M1 على M1 زايد M2 في G بنعوض عن A
+
+48
+00:03:51,320 --> 00:03:55,080
+واحد في إحدى المعادلات أو المعادلة الأولى بأوجد
+
+49
+00:03:55,080 --> 00:03:58,540
+الشد بنلاحظ أن الشد للكتلة الأولى هو نفس الشد
+
+50
+00:03:58,540 --> 00:04:03,520
+للكتلة التانية لإن الخيط كتلة مهملة
+
+51
+00:04:06,270 --> 00:04:10,430
+و ال .. البقرة frictionless يعني ما لسه .. مالفش
+
+52
+00:04:10,430 --> 00:04:15,170
+فيها احتكاك هذا .. هذه نوع من مسائل كتلتين معلقات
+
+53
+00:04:15,170 --> 00:04:24,190
+بخيط نيجي ل section 4.7 the SESAME approach لو كان
+
+54
+00:04:24,190 --> 00:04:27,710
+عندى جسمين connected by a inextensible ..
+
+55
+00:04:27,710 --> 00:04:33,840
+inextensible string كتلتين مربوطين بخيطso that the
+
+56
+00:04:33,840 --> 00:04:36,720
+body have common acceleration هي ملاحظة اللي احنا
+
+57
+00:04:36,720 --> 00:04:44,400
+حكيناها لو كان عندي جسمين مربوطين بخيط وكمان الخيط
+
+58
+00:04:44,400 --> 00:04:48,060
+هذا يعني بمر على بكره frictionless بلاحظ ان
+
+59
+00:04:48,060 --> 00:04:51,640
+التسارع هو نفسه وكمان الشد نفسه it's possible to
+
+60
+00:04:51,640 --> 00:04:56,380
+use the system approach which treat .. treat the
+
+61
+00:04:56,380 --> 00:04:59,760
+body as a single object the second law of the
+
+62
+00:04:59,760 --> 00:05:04,960
+motionfor the system approach is ممكن أنا أستخدم
+
+63
+00:05:04,960 --> 00:05:09,000
+هذا الكلام لو كان عندي أنا جسمين مربوطين بخيط
+
+64
+00:05:09,000 --> 00:05:13,500
+فالتسارع للأول هو نفس التسارع للتاني بأستخدم قانون
+
+65
+00:05:13,500 --> 00:05:17,460
+نيوتن التاني عساس كأنهم باعتبرهم كأنهم system واحد
+
+66
+00:05:17,460 --> 00:05:21,160
+ونظام واحد وبنحكي مجموعة الخوة الخارجية المؤثرة
+
+67
+00:05:21,160 --> 00:05:24,680
+على هذا النظام بده يساويsummation اللي هي ال M في
+
+68
+00:05:24,680 --> 00:05:29,220
+A ال A لل system كله نفسها summation لل M I يعني
+
+69
+00:05:29,220 --> 00:05:33,540
+ال M الأولى و التانى و التالتى إلى I من المرات ال
+
+70
+00:05:33,540 --> 00:05:37,540
+F external بيسموها الفورس external to the system
+
+71
+00:05:37,540 --> 00:05:41,280
+هي عبارة عن القوة الخارجية للنظام القوة الداخلية
+
+72
+00:05:41,280 --> 00:05:45,160
+زى tension force holding the system together don't
+
+73
+00:05:45,160 --> 00:05:50,970
+appear يعني القوة الداخلية زى اتشد ما بيظهرالقوة
+
+74
+00:05:50,970 --> 00:05:55,890
+الداخلية ممكن احنا برضه نوجدها عن طريق قانون نيوتن
+
+75
+00:05:55,890 --> 00:06:01,350
+التاني كل جسم لوحده the system approach naturally
+
+76
+00:06:01,350 --> 00:06:05,610
+can be extend to three or more body ممكن الجسم
+
+77
+00:06:05,610 --> 00:06:10,470
+يكون عندي مكوّن من جسمين أو تلاتة أو أكتر من جسم
+
+78
+00:06:10,470 --> 00:06:13,850
+it constructs the two approach to solving these
+
+79
+00:06:13,850 --> 00:06:19,480
+problems هناخد مثالمثلا اربعة اربعة اتعاش a block
+
+80
+00:06:19,480 --> 00:06:25,380
+of mass with mass M واحد عندي أنا كتلة block جسم
+
+81
+00:06:25,380 --> 00:06:30,530
+كتلته M واحد اربعة كيلو جرامwith mass برضه كرة
+
+82
+00:06:30,530 --> 00:06:35,010
+كتلتها M2مساوة سبعة مربوطين بخيط string light
+
+83
+00:06:35,010 --> 00:06:38,210
+string يعني خيط خفيف it passes over massless
+
+84
+00:06:38,210 --> 00:06:43,070
+frictionless pulley مربوطة برضه على بكرة ملساة كما
+
+85
+00:06:43,070 --> 00:06:46,350
+هو موضح بالشكل في عندي coefficient of kinetic
+
+86
+00:06:46,350 --> 00:06:49,850
+friction في عندي معامل احتكاك متحرك بين ال block و
+
+87
+00:06:49,850 --> 00:06:54,090
+بين الصفح قيمته point تلاتة مطلوب find the
+
+88
+00:06:54,090 --> 00:06:56,730
+acceleration of the two body and the tension in
+
+89
+00:06:56,730 --> 00:07:01,450
+the stringمطلب إيجاد التسارع لجسمين و الشد في
+
+90
+00:07:01,450 --> 00:07:05,890
+الخيط كمان في بيه بيحكي لنا check the answer for
+
+91
+00:07:05,890 --> 00:07:08,710
+the acceleration by using the system approach طبعا
+
+92
+00:07:08,710 --> 00:07:14,870
+بدي أستخدم بالأول قانون نيوتن التاني و بعد هيك بدي
+
+93
+00:07:14,870 --> 00:07:17,990
+أطبق اللي هو system approach اللي لان في عندي
+
+94
+00:07:17,990 --> 00:07:22,810
+جسمين زي ما هو موضح بالشكلام واحد وام اتنين ام
+
+95
+00:07:22,810 --> 00:07:28,630
+واحد بيتحرك على سطح خشن وام اتنين نازل من البكرة
+
+96
+00:07:28,630 --> 00:07:35,110
+ام واحد وام اتنين مربوطين ب .. بخيط خفيف وبي .. بي
+
+97
+00:07:35,110 --> 00:07:39,230
+.. بيمور على البكرة هي مسلس معنى الكلام انه ال ..
+
+98
+00:07:39,230 --> 00:07:42,190
+التسارق اللي بينزل فيه هذا ام اتنين هو نفس التسارق
+
+99
+00:07:42,190 --> 00:07:46,190
+ام واحد والشد للخيط ام اللي هو للام اتنين هو نفسه
+
+100
+00:07:46,190 --> 00:07:52,610
+لام واحد لكن في اندهانةجسم يعني أو سطح خشم إذا بدأ
+
+101
+00:07:52,610 --> 00:07:57,010
+أروح للجسم الأول و أعمله free body diagram اللي هو
+
+102
+00:07:57,010 --> 00:07:59,830
+مخطط يعني جميع القوة المؤثرة على هذا الجسم اللي هو
+
+103
+00:07:59,830 --> 00:08:03,930
+M1 في عندي أنا هنشد طالع من الجسم و أرايح للبقرة
+
+104
+00:08:03,930 --> 00:08:08,790
+في عندي قوة احتكاك متحرك عكس اتجاه الحركة و في
+
+105
+00:08:08,790 --> 00:08:12,550
+عندي ال normal force اللي هي عمودية على السطح و في
+
+106
+00:08:12,550 --> 00:08:17,570
+عندي M1G إلى أسفل هذه هي القوة المؤثرة على الكتلة
+
+107
+00:08:17,570 --> 00:08:21,550
+M1الكتلة M2 المؤثر عليها في عندي shed طالع من
+
+108
+00:08:21,550 --> 00:08:25,850
+البقرة من الكتلة ورايح على البقرة وفي عندي M2G هذا
+
+109
+00:08:25,850 --> 00:08:29,630
+بيسموه ال free body diagram اللي هي اللي .. اللي
+
+110
+00:08:29,630 --> 00:08:34,190
+هو المؤثر على .. على اللي هي الكتلة ل .. ل .. ل ..
+
+111
+00:08:34,190 --> 00:08:38,790
+لبداية الحال مطلوب مني find .. find acceleration
+
+112
+00:08:38,790 --> 00:08:42,210
+of the object and the tension in the string مطلوب
+
+113
+00:08:42,210 --> 00:08:47,500
+مني أوجد التسارع و ال shed في الخيط للكتلتينبدي
+
+114
+00:08:47,500 --> 00:08:50,340
+أكتب write the component of newton's second law of
+
+115
+00:08:50,340 --> 00:08:53,380
+the block بدي أكتب طبعا أطبق قانون ال newton
+
+116
+00:08:53,380 --> 00:08:57,940
+التاني للكتلة الأولى للكتلة التانية الكتلة الأولى
+
+117
+00:08:57,940 --> 00:09:01,700
+موجودة كإنها موجودة على محور X على السطح فبنحكي
+
+118
+00:09:01,700 --> 00:09:06,140
+summation لل Fx بتساوي T ناقص Fk بتساوي M1 في M
+
+119
+00:09:06,140 --> 00:09:10,160
+بالنسبة للكتلة التانية طبعا كإنها مجموعة القوة في
+
+120
+00:09:10,160 --> 00:09:16,060
+تجاه ال Y summation ل Fy بتساوي N ناقص M1 G بتساوي
+
+121
+00:09:16,060 --> 00:09:24,570
+0هذا بالنسبة للكتلة الأولى لدي Normal نقص M1G
+
+122
+00:09:24,570 --> 00:09:26,690
+بساوية Zero و لا توجد تسارع في تجاه Y بالنسبة
+
+123
+00:09:26,690 --> 00:09:29,550
+للكتلة الأولى يعني الكتلة الأولى فيها لدي مجموع
+
+124
+00:09:29,550 --> 00:09:34,710
+قوة باتجاه X و مجموع قوة باتجاه Y المعادلة باتجاه
+
+125
+00:09:34,710 --> 00:09:39,170
+Y Axis فبين هذه المعادلة ال Normal force للكتلة
+
+126
+00:09:39,170 --> 00:09:44,630
+الأولى بتساوي M1 في G سأعود عن ال Normal and
+
+127
+00:09:44,630 --> 00:09:48,760
+بالنسبة ل FK بساوية MuK في ال Normalف ال FK بتسوي
+
+128
+00:09:48,760 --> 00:09:53,200
+ميو كي في ال normal هي M1G في المعادلة بتطلع عند T
+
+129
+00:09:53,200 --> 00:09:58,560
+ناقص ميو كي في M1G بتسوي M1A عوضت عن ال FK ميو كي
+
+130
+00:09:58,560 --> 00:10:03,520
+في ال normal و ال normal M1G بتسوي M1A ده استخدم
+
+131
+00:10:03,520 --> 00:10:06,780
+قانون نيوتن التاني للكتلة التانية طبعا الكتلة
+
+132
+00:10:06,780 --> 00:10:11,680
+التانية هي نازلة بتسارع ولكن عكس تسارع الكتلة
+
+133
+00:10:11,680 --> 00:10:16,980
+الأولى هم التسارعين متساويين لكن باتجاه مخالفلأن
+
+134
+00:10:16,980 --> 00:10:19,600
+الكتلة الأولى رايحة بتجاه اليمين، الكتلة التانية
+
+135
+00:10:19,600 --> 00:10:25,480
+نازلة بتجاه اللى هو الأسفل فمجموع القوة بتجاه ال Y
+
+136
+00:10:25,480 --> 00:10:30,160
+للكتلة التانية بتساوي T ناقص M2G بتساوي M2A بتساوي
+
+137
+00:10:30,160 --> 00:10:35,980
+ناقص M2 في A، اذا T بتساوي T ناقص M2G بتساوي ناقص
+
+138
+00:10:35,980 --> 00:10:41,710
+M2 في Aهعود المعادلة التانية في المعادلة الأولى
+
+139
+00:10:41,710 --> 00:10:46,170
+عشان اوجد اللي هي T من المعادلة الأولى والتانية
+
+140
+00:10:46,170 --> 00:10:50,270
+بأوجد ال A ومن A بأوجد ال T زي ما انتوا شايفين في
+
+141
+00:10:50,270 --> 00:10:54,080
+عندي انا معادلتينممكن انا يعني اجمع او اطرح
+
+142
+00:10:54,080 --> 00:10:58,620
+المعادلتين عساس اوجد انا ال A و من ال A بأوجد T
+
+143
+00:10:58,620 --> 00:11:02,700
+بعوض في احدى المعادلتين بأوجد ال T طبعا باوز ..
+
+144
+00:11:02,700 --> 00:11:06,520
+مدام او يعني اوجدت A عوضت في ال .. اللي هي M1 و ال
+
+145
+00:11:06,520 --> 00:11:11,600
+G 9.8 هنا Mu K 0.3 ال Normal اللي هى M في G اللي
+
+146
+00:11:11,600 --> 00:11:16,660
+هى 4 في 9.8 على M1 زائد M2 بتطلع عندى A1 سوى 5.17
+
+147
+00:11:17,460 --> 00:11:22,140
+A1 بتساوي A2 نفس التسارع لإن هم مربوطين بنفس
+
+148
+00:11:22,140 --> 00:11:26,780
+الخياط بعدين بعوض عن A1 في المعادلة الأولى بأوجد
+
+149
+00:11:26,780 --> 00:11:33,040
+اللي هو ال T اللي هو الشات برضه T1 بتساوي T2 الآن
+
+150
+00:11:33,040 --> 00:11:36,860
+لإيجاد ال acceleration using the system approach
+
+151
+00:11:36,860 --> 00:11:40,560
+عشان أوجد طبعا التسارع باستخدام ال system approach
+
+152
+00:11:40,560 --> 00:11:43,300
+where the system consists of two blocks يعني بتاخد
+
+153
+00:11:43,300 --> 00:11:46,720
+ال system كلهال system أبرزش يعني بدي أخد النظام
+
+154
+00:11:46,720 --> 00:11:50,800
+كله كإنه كتلة واحدة بستخدم قانون نيوتن التاني عشان
+
+155
+00:11:50,800 --> 00:11:57,140
+أوجد a فبلاحظ أنه عندي M1 زي M2 في A بتساوي M2 في
+
+156
+00:11:57,140 --> 00:12:03,140
+G ناقص Muk في N بتساوي M2G ناقص Muk في M1G يعني
+
+157
+00:12:03,140 --> 00:12:06,900
+هذا الطرف بتساوي هذا الطرف إذن ال A بتساوي M2G
+
+158
+00:12:06,900 --> 00:12:10,940
+ناقص Muk في M1G على M1 زي M2 يعني ما .. يعني لا
+
+159
+00:12:10,940 --> 00:12:13,700
+أعتبر أن ال .. ال T .. ال T هذه بعتبرها متساوي ده
+
+160
+00:12:13,700 --> 00:12:17,270
+الطرفينو باخد ال system كأنه system نظام واحد
+
+161
+00:12:17,270 --> 00:12:21,030
+كتلتين ال M1 و M2 في A يعني ال mass في ال
+
+162
+00:12:21,030 --> 00:12:24,490
+acceleration و ال mass هي عبارة عن M1 و M2 بدها
+
+163
+00:12:24,490 --> 00:12:27,510
+تساوي الكلام هذا و بالتالي بقوش ال delay تطلع نفس
+
+164
+00:12:27,510 --> 00:12:33,550
+الحل طبعا و نفس الجواب exam بالاربعة خمس طعاش في
+
+165
+00:12:33,550 --> 00:12:38,070
+عندي جسمين جسمين طبعا الجسمين على بعض زي ما هو
+
+166
+00:12:38,070 --> 00:12:43,070
+موضح بالشكل هي كتل M و هي M ال M الكبيرة مربوطة
+
+167
+00:12:43,070 --> 00:12:50,350
+بخيط طبعاshed مشدودة في shed طبعا هي الكتلتين كتلة
+
+168
+00:12:50,350 --> 00:12:54,970
+لتحت مشدودة طبعا ال .. السؤال بيحكي أنه في عند
+
+169
+00:12:54,970 --> 00:12:58,590
+كتلة اللي هي ال M5 ride on a top of second block
+
+170
+00:12:58,590 --> 00:13:01,210
+of mass عشرة الكتلة الكبيرة عشر الكتلة الصغيرة
+
+171
+00:13:01,210 --> 00:13:05,610
+خمسة في شخص a person attached string to the bottom
+
+172
+00:13:05,610 --> 00:13:09,250
+block and pull the system horizontally across the
+
+173
+00:13:09,250 --> 00:13:13,290
+frictionless surface أجى شخص و سحب الكتلة الكبيرة
+
+174
+00:13:13,650 --> 00:13:18,710
+بواسطة خيط سحبها طبعا بقوة horizontally على سطح
+
+175
+00:13:18,710 --> 00:13:21,890
+اللي هو أملاس friction لل surface ال friction
+
+176
+00:13:21,890 --> 00:13:25,230
+between the two blocks الآن في عند احتكاك بين
+
+177
+00:13:25,230 --> 00:13:30,070
+الكتلتين بيمنع الكتلة أنها تنزلر هذا يعني بيحافظ
+
+178
+00:13:30,070 --> 00:13:33,550
+على أن الكتلة خمسة إش أنها ما تنزلر if the
+
+179
+00:13:33,550 --> 00:13:36,190
+coefficient of static friction طبعا هذا الاحتكاك
+
+180
+00:13:36,190 --> 00:13:40,170
+هو احتكاك ساكن لإن الكتلة اللي فوق اللي هي الصغيرة
+
+181
+00:13:40,170 --> 00:13:46,070
+ما اتحركتمامشيت وبالتالي فى احتكاك ساكن مطلوب مننا
+
+182
+00:13:46,070 --> 00:13:51,930
+نوجد what maximum force بده أقصى قيمة للقوة can be
+
+183
+00:13:51,930 --> 00:13:54,570
+exceeded by the string on the عشر block without
+
+184
+00:13:54,570 --> 00:14:00,190
+causing the five kilogram block to slip بده أقصى
+
+185
+00:14:00,190 --> 00:14:04,610
+قيمة للقوة اللى أنا بسحب فيها الكتلة العشرة بحيث
+
+186
+00:14:04,610 --> 00:14:09,850
+أن الكتلة الخمسة لا تنزلخ الآن علشان نحل بنرسم ال
+
+187
+00:14:09,850 --> 00:14:13,170
+free body diagramفهذه اللي هي الكتلة الكبيرة
+
+188
+00:14:13,170 --> 00:14:16,910
+الخمسة مين بأثر عليها؟ بأثر عليها في عندي أنا شد
+
+189
+00:14:16,910 --> 00:14:22,030
+لليمين، في عندي قوة احتكاك ساكن على الشمال هو بين
+
+190
+00:14:22,030 --> 00:14:26,250
+السطح هذا والسطح اللي أعلى، في عندي M كبيرة G اللي
+
+191
+00:14:26,250 --> 00:14:30,310
+هي للكيلو .. للعشر كيلوفي عندي n اتنين، كمان في
+
+192
+00:14:30,310 --> 00:14:33,510
+عندي أنواح g اللي هى M1G اللي هى أنواح الضغط على
+
+193
+00:14:33,510 --> 00:14:36,350
+الكتلة الكبيرة هدى من الكتلة الصغيرة طبعا الكتلة
+
+194
+00:14:36,350 --> 00:14:40,250
+الصغيرة بين السطحين في قوتين متساوتين في المقدار
+
+195
+00:14:40,250 --> 00:14:43,570
+ومتعاكستن بالاتجاه طالما أنا عرفت أفواق F أسلة
+
+196
+00:14:43,570 --> 00:14:47,110
+الكبيرة فال F أسلة الصغيرة هتكون مساوية إيها في
+
+197
+00:14:47,110 --> 00:14:51,650
+المقدارومتعاكسة بالاتجاه بسبب تلامس السطحين في
+
+198
+00:14:51,650 --> 00:14:56,510
+عندي N واحد إلى أعلى وفي عندي MG إلى أسفل هدولة
+
+199
+00:14:56,510 --> 00:14:58,790
+اللي هي ال free body diagram أو القوة المؤثرة
+
+200
+00:14:58,790 --> 00:15:05,150
+عليها ال solution مطلوب find the maximum force بده
+
+201
+00:15:05,150 --> 00:15:10,850
+أقصى قيمة للقوة التي تسحب الخط بحيث أنه الكتلة
+
+202
+00:15:10,850 --> 00:15:14,650
+التي أعلى الكتلة الكتلة الصغيرة التي أعلى الكتلة
+
+203
+00:15:14,650 --> 00:15:19,160
+الكبيرةالتي تقع فوق الكتلة الكبيرة لا تتحرك الان
+
+204
+00:15:19,160 --> 00:15:22,840
+بالنسبة لل X-axis في عندي M U S في N واحد هذا
+
+205
+00:15:22,840 --> 00:15:27,140
+للكتلة الصغيرة اللي هي الكتلة for the top block
+
+206
+00:15:27,140 --> 00:15:32,020
+التي تقع أعلى الكتلة الكبيرة ف M U S في N في M في
+
+207
+00:15:32,020 --> 00:15:37,340
+A بالنسبة لل Y-axis اللي هي Normal N واحد ناقص M
+
+208
+00:15:37,340 --> 00:15:39,640
+جي بالساوة Zero هذا بالنسبة للكتلة الصغيرة اللي هي
+
+209
+00:15:39,640 --> 00:15:43,700
+الخمسة بدا أسأل solve بالنسبة solve the Y
+
+210
+00:15:43,700 --> 00:15:48,040
+componentfor n واحد عشان اوجد n واحد تطلع لي m في
+
+211
+00:15:48,040 --> 00:15:52,920
+g بالنسبة للكتلة الصغيرة ان n واحد بتساوي ال m في
+
+212
+00:15:52,920 --> 00:15:59,300
+g m a بتساوي من هنا mu s في m في g اذا ان ال a
+
+213
+00:15:59,300 --> 00:16:06,700
+بتساوي mu s في g الان بدأ اكتب اللي هو اللي اللي
+
+214
+00:16:06,700 --> 00:16:12,380
+هي قانون نيوتن التاني في ال x axis للكتلة التانية
+
+215
+00:16:12,380 --> 00:16:18,560
+او الكتلة الكبيرةفبكون عندى انا في شد T ناقص Mu S
+
+216
+00:16:18,560 --> 00:16:23,960
+في M G اللى هى .. اللى هى F S Mu S فى ال normal و
+
+217
+00:16:23,960 --> 00:16:27,440
+ال normal بساوة ال M G بساوة ال M فى A اذا صار
+
+218
+00:16:27,440 --> 00:16:30,380
+عندى انا معادلة الكتلة الكبيرة معادلة الكتلة
+
+219
+00:16:30,380 --> 00:16:35,440
+الصغيرة اذا M فى Mu S فى G بساوة T ناقص Mu S G اذا
+
+220
+00:16:35,440 --> 00:16:40,540
+T بساوة M زايد M فى Mu S فى G لإيجاد ال T عشان
+
+221
+00:16:40,540 --> 00:16:45,080
+اوجد ال Tطبعا بنعوض عن ال M لصغيرة خمسة و ال M
+
+222
+00:16:45,080 --> 00:16:48,720
+لكبيرة عشرة ميو أس بوين تلاتة خمسة و الجي تسعة و
+
+223
+00:16:48,720 --> 00:16:52,660
+اتنين و عشرة تطلع اندي T واحد و خمسين و نص علشان
+
+224
+00:16:52,660 --> 00:16:56,800
+استخدم ال system approach في هذه الحالة ماعنديش
+
+225
+00:16:56,800 --> 00:17:01,820
+الا كتلتين كأنه ما .. كأنه .. كأنه قوة الاحتكاك
+
+226
+00:17:01,820 --> 00:17:05,440
+الساكنة مش موجودة كأنه كتلة ال M واحد و ال M اتنين
+
+227
+00:17:05,440 --> 00:17:10,070
+كتلة واحدة و أنا شدهم بخير ففي عندي some machineلأ
+
+228
+00:17:10,070 --> 00:17:12,270
+القوة بتساوي ال M في A و القوة اللي عندي هي قوة
+
+229
+00:17:12,270 --> 00:17:16,030
+الشد T بتساوي M زائد M في A إذا أن ال A بتساوي T
+
+230
+00:17:16,030 --> 00:17:20,910
+على مطلوب من ال A بتساوي T على M زائد M تطلع ال A
+
+231
+00:17:20,910 --> 00:17:25,830
+تلاتة point أربعة تلاتة إذا أخدت ال system كله هيك
+
+232
+00:17:25,830 --> 00:17:29,490
+أحنا بنكون خلصنا وانتهينا من chapter أربعة إن شاء
+
+233
+00:17:29,490 --> 00:17:29,670
+الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI.srt
new file mode 100644
index 0000000000000000000000000000000000000000..86c4901450b9b23204448f4b38b4f1800924fae0
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI.srt
@@ -0,0 +1,987 @@
+1
+00:00:00,000 --> 00:00:04,820
+بسم الله الرحمن الرحيم نستكمل chapter.. chapter
+
+2
+00:00:04,820 --> 00:00:12,960
+الرابع بعدة مسائل problems أربعة واحد an airport
+
+3
+00:00:12,960 --> 00:00:16,860
+with mass ثلاثة و نصف في عشرة أس اثنين كيلو جرام
+
+4
+00:00:16,860 --> 00:00:22,290
+including the passengers has an engine that produces
+
+5
+00:00:22,290 --> 00:00:29,090
+a net horizontal force of 7.7×10² Newton في عندي
+
+6
+00:00:29,090 --> 00:00:35,910
+قارب بحري موجود عليه مجموعة مسافرين، الـ motor طبعاً
+
+7
+00:00:35,910 --> 00:00:41,630
+بيشتغل بقوة أفقية، horizontal force قوة أفقية 7
+
+8
+00:00:41,630 --> 00:00:46,870
+.7×10² Newton after accounting for forces of
+
+9
+00:00:46,870 --> 00:00:52,370
+resistance طبعاً، وهو ماشي خلال الطريق هناك قوة..
+
+10
+00:00:52,370 --> 00:00:56,630
+قوة معاكسة أو ممانعة، مطلوب find the acceleration
+
+11
+00:00:56,630 --> 00:01:00,570
+of the airport، المفروض التسارع أو جد التسارع، و
+
+12
+00:01:00,570 --> 00:01:05,030
+بعدين starting from rest، how long does it take the
+
+13
+00:01:05,030 --> 00:01:10,110
+airport to reach a speed of اثني عشر متر في الثانية
+
+14
+00:01:10,370 --> 00:01:16,570
+بدو إذا اح.. إذا القارب بدأ من السكون، كم الوقت
+
+15
+00:01:16,570 --> 00:01:21,530
+اللازم ليصل إلى سرعة اثني عشر متر في الثانية أيضاً
+
+16
+00:01:21,530 --> 00:01:26,130
+مطلوب after reaching that speed، بعد ما يوصل هذه
+
+17
+00:01:26,130 --> 00:01:33,940
+السرعة، الـ.. السائق أو البحار بده يرجع return of
+
+18
+00:01:33,940 --> 00:01:38,460
+engine and drift to stop over a distance خمسين، بده
+
+19
+00:01:38,460 --> 00:01:42,980
+يرجع ويمشي مسافة خمسين متر، find the resistance force
+
+20
+00:01:42,980 --> 00:01:47,560
+مطلوب الـ resistance force، هي السؤال، في عندي بحار
+
+21
+00:01:47,560 --> 00:01:54,180
+راكب air boat،  فيه مركب، المركب طبعاً هيمشي باتجاه
+
+22
+00:01:54,180 --> 00:01:59,020
+الـ.. اللي هي الـ horizontal، اتجاه الشرق أو اليمين
+
+23
+00:01:59,080 --> 00:02:06,520
+بقوة F، أعطانيها، حتى يصل إلى سرعة 12، نمشي واحد
+
+24
+00:02:06,520 --> 00:02:10,320
+واحد، المطلوب الأول solution، find the acceleration
+
+25
+00:02:10,320 --> 00:02:14,100
+of the air boat، بده الـ acceleration لإيجاد الـ
+
+26
+00:02:14,100 --> 00:02:17,880
+acceleration، بده أطبق قانون نيوتن الثاني، summation
+
+27
+00:02:17,880 --> 00:02:22,500
+للـ F بتساوي M في A، طبعاً الـ F الآن في اتجاه الـ X
+
+28
+00:02:23,130 --> 00:02:26,170
+Summation للـ F بدها تساوي، أو الـ F net بدها تساوي
+
+29
+00:02:26,170 --> 00:02:29,690
+الـ M في A، إذا الـ A بدها تساوي الـ F net على M،
+
+30
+00:02:29,690 --> 00:02:33,010
+أعطاني الـ F باتجاه الـ horizontal، 7.7 في 10 أس 2
+
+31
+00:02:33,010 --> 00:02:37,630
+نيوتن على الـ mass، 3.5 في 10 أس 2، تطلع عندي الـ A
+
+32
+00:02:37,630 --> 00:02:43,650
+2.2 متر في الثانية تربيع، Find the time necessary to
+
+33
+00:02:43,650 --> 00:02:47,890
+reach the speed of 12، بدنا نوجد الزمن اللازم لتصل
+
+34
+00:02:47,890 --> 00:02:54,550
+سرعة القارب إلى 12 متر في الثانية، بنطبق قانون الـ
+
+35
+00:02:54,550 --> 00:02:57,430
+kinematic، velocity equation، قانون من قوانين
+
+36
+00:02:57,430 --> 00:03:00,890
+الحركة، القوانين الأول من قوانين الحركة، V بتساوي V
+
+37
+00:03:00,890 --> 00:03:07,240
+naught زائد A T، أنا بدي أو اللي هي أيّاً كانت وصلت
+
+38
+00:03:07,240 --> 00:03:12,320
+إثني عشر، V not بدأ من الـ rest، صفر، الـ A اللي هي طلعت
+
+39
+00:03:12,320 --> 00:03:16,480
+عندي 2.2، هي في المطلوب الأول، والـ T
+
+40
+00:03:16,480 --> 00:03:20,820
+هو طلبها، إذا الـ T بتطلع لي خمسة point أربع خمسة
+
+41
+00:03:20,820 --> 00:03:25,580
+ثانية، هذا الزمن اللي لازم يتصل سرعته إلى اثني عشر
+
+42
+00:03:25,580 --> 00:03:29,310
+متر في الثانية، في المطلوب C، find the resistance
+
+43
+00:03:29,310 --> 00:03:36,430
+force after the engine is turned off، بده اللي هي
+
+44
+00:03:36,430 --> 00:03:40,010
+resistance force، قوة الممانعة، اللي هي يعني اللي
+
+45
+00:03:40,010 --> 00:03:44,950
+بتعاكس القوة الأصلية أو الحركة الأصلية، find a net
+
+46
+00:03:44,950 --> 00:03:48,450
+acceleration due to resist the resistance force، في
+
+47
+00:03:48,450 --> 00:03:52,290
+البداية بدي أوجد اللي هي اللي بدي أوجد اللي هي
+
+48
+00:03:52,290 --> 00:03:57,090
+resistance force، هأوجد اللي هي التسارع اللي هي
+
+49
+00:03:57,090 --> 00:04:01,920
+العكسية من خلال الحركة، V تربيع ناقص V not تربيع
+
+50
+00:04:01,920 --> 00:04:07,000
+بتساوي 2 A Delta X، طبعاً هذا من القانون، V تربيع بدها
+
+51
+00:04:07,000 --> 00:04:12,460
+تساوي V not تربيع زائد 2 A X، طبعاً هيوصل لإنه هيوقف
+
+52
+00:04:12,460 --> 00:04:17,140
+بعد مسافة 50، اللي هي السرعة اللي أنا انتهيت منها
+
+53
+00:04:17,140 --> 00:04:20,540
+من الحركة الأولى، هابدأ فيها في الحركة الثانية اللي
+
+54
+00:04:20,540 --> 00:04:24,900
+هي V not تربيع اللي هي الـ 12، يعني أنا عندي مرحلتين
+
+55
+00:04:24,900 --> 00:04:28,900
+المرحلة الأولى رايح للشرق، المرحلة الثانية راح لاقي
+
+56
+00:04:28,900 --> 00:04:34,520
+الغرب، فـ V نهائية 0، ناقص V naught اللي هي الـ 12، هي
+
+57
+00:04:34,520 --> 00:04:38,680
+الـ 12 هي السرعة النهائية اللي انتهى فيها
+
+58
+00:04:38,680 --> 00:04:42,260
+في المرحلة الأولى، تعتبر سرعة ابتدائية للمرحلة
+
+59
+00:04:42,260 --> 00:04:45,870
+الثانية، اللي هي 12 متر في الثانية تربيع لكل تربيع
+
+60
+00:04:45,870 --> 00:04:58,310
+بتساوي 2 A في المسافة 50، إذا الـ A تطلع ناقص 1.44 متر
+
+61
+00:04:58,310 --> 00:05:02,710
+في الثانية تربيع لكل تربيع، رح أعود عن التسارع هذا
+
+62
+00:05:02,710 --> 00:05:07,530
+في قانون نيوتن الثاني، إذا الـ F resistance بتساوي
+
+63
+00:05:07,530 --> 00:05:11,550
+الـ M في A، الـ M ثلاثة و نصف في عشرة أس اثنين، و الـ A
+
+64
+00:05:11,550 --> 00:05:15,210
+كانت ناقص واحد point أربعة أربعة، إذا تطلع للـ F
+
+65
+00:05:15,210 --> 00:05:19,390
+ناقص خمسمائة وأربعة نيوتن، طبعاً الناقص لأنها عكس
+
+66
+00:05:19,390 --> 00:05:24,870
+الحركة الأصلية، فالـ F بتساوي ناقص خمسمائة وأربعة
+
+67
+00:05:24,870 --> 00:05:31,200
+نيوتن، ناخد سؤال ثاني example، أربعة اثنين، في عندي
+
+68
+00:05:31,200 --> 00:05:35,200
+two horses are pulling a barge with mass اثنين
+
+69
+00:05:35,200 --> 00:05:38,680
+في عشرة أو ثلاثة kilogram along a canal، في عندي
+
+70
+00:05:38,680 --> 00:05:43,780
+حصانين بدهم يشدوا باخرة أو بارجة في وسط قناة أو
+
+71
+00:05:43,780 --> 00:05:49,520
+وسط فرع من النهر، كتلتها اثنين في عشرة أس ثلاثة
+
+72
+00:05:49,520 --> 00:05:53,180
+kilogram along a canal as shown in the figure، الـ
+
+73
+00:05:53,180 --> 00:05:56,640
+cable connected to the first horse، في عندي طبعاً
+
+74
+00:05:56,640 --> 00:06:02,580
+الحصان الأول مربوط بحبل بيعمل زاوية ثلاثين with
+
+75
+00:06:02,580 --> 00:06:05,420
+respect to the direction of the canal while the
+
+76
+00:06:05,420 --> 00:06:09,320
+cable connected to the second horse makes an angle of
+
+77
+00:06:09,320 --> 00:06:13,480
+ناقص خمسة و أربعين، طبعاً زي ما هو موضح بالشكل، في
+
+78
+00:06:13,480 --> 00:06:18,820
+عندي أنا حصانين، الحصانين بدهم يشدوا برج أو باخرة
+
+79
+00:06:18,820 --> 00:06:25,960
+الحصان الأول ماسك الباخرة بخيط أو حبل أو كابل
+
+80
+00:06:25,960 --> 00:06:31,280
+بيميل بزاوية θ واحد، ثلاثين، الحصان الثاني بيشدّه
+
+81
+00:06:31,280 --> 00:06:35,820
+بقوة ومايل بزاوية ناقص خمسة وأربعين، يعني ناقص عن
+
+82
+00:06:35,820 --> 00:06:41,060
+الـ X axis، اللي هو الموجب بخمسة وأربعين، بدي أوجد الـ
+
+83
+00:06:41,060 --> 00:06:44,440
+acceleration of the barge، بدي أوجد التسارع لهذه الـ
+
+84
+00:06:44,440 --> 00:06:48,180
+barge، starting at rest، if each horse exerts a
+
+85
+00:06:48,180 --> 00:06:51,880
+force of magnitude 6 في عشرة أس اثنين نيوتن on the
+
+86
+00:06:51,880 --> 00:06:55,400
+barge، إذا كانت القوة للحصان الأول هي نفس القوة
+
+87
+00:06:55,400 --> 00:06:58,520
+للحصان الثاني، يعني F واحد بتساوي الـ F اثنين
+
+88
+00:06:58,520 --> 00:07:03,780
+وتساوي 6 في عشرة أس اثنين، طبعاً بدنا نهمل اللي هي
+
+89
+00:07:04,130 --> 00:07:08,470
+الممانعة اللي بيلاقيها الـ.. البرج أو تلاقيها
+
+90
+00:07:08,470 --> 00:07:13,390
+البرج بـ.. أو اللي هي بتلاقيها البرج من الميّة اللي
+
+91
+00:07:13,390 --> 00:07:16,390
+هي بينهم، المقاومة اللي هي الممانعة اللي بتلاقيها
+
+92
+00:07:16,390 --> 00:07:22,860
+خلال شدّها من الحصانين، الحال، طبعاً أنا عندي اللي هي
+
+93
+00:07:22,860 --> 00:07:26,700
+المقاومة الأولى، القوة الأولى للحصان الأول، F1 cos
+
+94
+00:07:26,700 --> 00:07:34,820
+θ1 في اتجاه الـ X، و F2 X بتساوي F2 cos θ2، الآن F
+
+95
+00:07:34,820 --> 00:07:37,940
+اللي هي القوة الأولى باتجاه الـ X للحصان الأول، F1
+
+96
+00:07:37,940 --> 00:07:41,870
+cos θ1، إذا أنا حللت أو المركبة الأولى في اتجاه الـ X
+
+97
+00:07:41,870 --> 00:07:46,710
+للقوة الأولى، 6 في 10 أس 2 كوزاين الثلاثين، المركبة
+
+98
+00:07:46,710 --> 00:07:51,670
+الـ X للقوة الثانية، 6 في 10 أس 2 كوزاين الناقص 45
+
+99
+00:07:51,670 --> 00:07:57,830
+لأنه الـ 45 نازلة باتجاه X السالب، الآن طلعت القوة
+
+100
+00:07:57,830 --> 00:08:00,630
+الأولى باتجاه الـ X والقوة الثانية باتجاه X، إذا
+
+101
+00:08:00,630 --> 00:08:07,130
+المركبة X للقوة الأولى والثانية بدها تساوي 5.2×10²
+
+102
+00:08:07,130 --> 00:08:14,050
+زائد 4.2×10²، تطلع 9.44×10²، هذه هي عبارة عن القوة
+
+103
+00:08:14,050 --> 00:08:19,320
+الكلية في اتجاه الـ X، القوة المحصلة لقوة شد الحصان
+
+104
+00:08:19,320 --> 00:08:24,040
+الأول والثاني، الآن بدنا نحسب الـ F باتجاه الـ Y، يعني
+
+105
+00:08:24,040 --> 00:08:28,400
+لما أنا حللت القوة راح تطلع F1Y sin θ1
+
+106
+00:08:31,830 --> 00:08:41,830
+6×10²N sin 30، و F2Y 6×10² sin -45، يظهر الجواب ناقص 4
+
+107
+00:08:41,830 --> 00:08:46,530
+.24×10²، هاي القوة في اتجاه Y المحصلة، وهي القوة
+
+108
+00:08:46,530 --> 00:08:49,830
+المحصلة في اتجاه X، الآن بدي أجيب الـ magnitude لهذه
+
+109
+00:08:49,830 --> 00:08:54,790
+المحصلة، اللي هي عبارة عن جذر التربيعي، الآن FY
+
+110
+00:08:54,790 --> 00:09:00,260
+المحصلة للنتين بدها تساوي F واحد زائد F اثنين Y
+
+111
+00:09:00,260 --> 00:09:05,140
+بدي أجمع اللي هي محصلة الـ Y للقوة الأولى والقوة
+
+112
+00:09:05,140 --> 00:09:09,000
+الثانية، جمعتهم بتطلع ناقص واحد point اثنين أربعة
+
+113
+00:09:09,000 --> 00:09:13,400
+في عشرة أس اثنين، الآن جيبت F X المحصلة، و جيبت F Y
+
+114
+00:09:13,400 --> 00:09:21,510
+المحصلة، بدي أجيب الـ AX، اتجاه التسارع باتجاه الـ X، و
+
+115
+00:09:21,510 --> 00:09:26,390
+بعدين اتجاه التسارع باتجاه الـ Y، إذا الـ AX بدها
+
+116
+00:09:26,390 --> 00:09:31,870
+تساوي FX على M، هذه أجت من أن الـ FX بتساوي M في AX
+
+117
+00:09:31,870 --> 00:09:38,090
+إذا الـ AX بدها تساوي FX على M، اللي هي الـ Fx المحصلة
+
+118
+00:09:38,090 --> 00:09:46,650
+9.44×10² نيوتن على M، 2×10³ كيلو جرام، بتطلع الجواب 0
+
+119
+00:09:46,650 --> 00:09:51,850
+.472 متر في الثانية تربيع، هذا التسارع باتجاه الـ X
+
+120
+00:09:51,850 --> 00:09:57,310
+نيجي للتسارع باتجاه الـ Y، الـ AY، ده آخذ محصلة AY على
+
+121
+00:09:57,310 --> 00:10:07,450
+M، محصلة ay هي ناقص 1.24×10² نيوتن على 2×10³ كيلو
+
+122
+00:10:07,450 --> 00:10:13,850
+جرام، تطلع عندنا ناقص 0.062 متر في الثانية تربيع
+
+123
+00:10:13,850 --> 00:10:18,250
+إذا جيبت الـ a، مركبة التسارع باتجاه الـ X، مركبة
+
+124
+00:10:18,250 --> 00:10:22,860
+الصادية باتجاه الـ Y، الآن بده أجيب الـ magnitude والـ
+
+125
+00:10:22,860 --> 00:10:26,760
+direction للـ a، بده الـ magnitude، راح أعمل اللي هو
+
+126
+00:10:26,760 --> 00:10:34,400
+القانون، جذر AX تربيع زائد AY تربيع، بيطلع عندي طبعاً
+
+127
+00:10:34,400 --> 00:10:38,000
+قيمة الـ AX تربيع زائد قيمة الـ AY تربيع اللي احنا
+
+128
+00:10:38,000 --> 00:10:42,480
+طلعناها، بيطلع عندي 0.476 متر في
+
+129
+00:10:42,480 --> 00:10:46,540
+الثانية تربيع، هذه هي كـ magnitude، قيمة التسارع كـ
+
+130
+00:10:46,540 --> 00:10:50,870
+magnitude، بالنسبة للاتجاه المحصلة، calculate the
+
+131
+00:10:50,870 --> 00:10:54,350
+direction of the acceleration using the tangent
+
+132
+00:10:54,350 --> 00:11:01,770
+function، إذا تان الثيتا بتساوي AY على AX، اللي هي
+
+133
+00:11:01,770 --> 00:11:08,350
+بآخذ الـ AY بإشارتها، والـ AX بإشارتها، الـ AY ناقص، و
+
+134
+00:11:08,350 --> 00:11:13,750
+الـ AX موجب، معناها موجودة بالربع، بالربع الرابع
+
+135
+00:11:13,750 --> 00:11:17,770
+موجودة بالربع الرابع، إذا تان الثيتا بتساوي ناقص
+
+136
+00:11:19,460 --> 00:11:23,860
+0.131، إذا الـ θ بيساوي tan inverse لهذه القيمة
+
+137
+00:11:23,860 --> 00:11:29,640
+بيساوي ناقص 7.46، طبعاً ما بضيف لها 180، هذه بتكون
+
+138
+00:11:29,640 --> 00:11:35,580
+الزاوية اللي هي 7.46 تحت، تحت اتجاه الـ X الموجب
+
+139
+00:11:35,580 --> 00:11:39,970
+بالناحية، يعني باتجاه عقارب الساعة، ما بضيف لها الـ 180
+
+140
+00:11:39,970 --> 00:11:43,610
+لأنها موجودة في الربع الرابع، the quantity that obey
+
+141
+00:11:43,610 --> 00:11:48,770
+the rules of ordinary arithmetic، طبعاً هذه القيمة
+
+142
+00:11:48,770 --> 00:11:53,190
+طبعاً بدنا نمشي، بتنطبق علينا قوانين اللي احنا
+
+143
+00:11:53,190 --> 00:11:58,550
+استخدمناها سابقاً، أنّه إذا كان الزاوية المحصلة في
+
+144
+00:11:58,550 --> 00:12:04,690
+الربع الثاني أو الثالث، بأضيف لها 180، وإذا
+
+145
+00:12:04,690 --> 00:12:07,530
+كانت في الربع الأول أو الرابع ما بـ.. ما بأضيف
+
+146
+00:12:07,530 --> 00:12:10,970
+إذا كانت في الربع الأول مع اتجاه عقارب الساعة بتكون
+
+147
+00:12:10,970 --> 00:12:14,290
+موجبة، أو مع اتجاه عقارب الساعة بتكون سالبة، وعكس اتجاه
+
+148
+00:12:14,290 --> 00:12:18,050
+الساعة بتكون الموجبة، اللي هي الزاوية موجبة من اتجاه
+
+149
+00:12:18,050 --> 00:12:22,170
+X الموجب، نيجي لها نكمل، نستكمل القوانين نيوتن
+
+150
+00:12:22,170 --> 00:12:27,860
+للحركة، قوانين الحركة، قانون الثالث لنيوتن، consider
+
+151
+00:12:27,860 --> 00:12:31,740
+the task of driving a nail into a block of wood
+
+152
+00:12:31,740 --> 00:12:34,540
+for example as illustrated in the figure، لو أنا
+
+153
+00:12:34,540 --> 00:12:40,960
+فرضت في عندي، أنا بدي أنا أضرب مسمار في شاكوش زي هو
+
+154
+00:12:40,960 --> 00:12:45,060
+موضح بالشكل، to accelerate the nail and drive it
+
+155
+00:12:45,060 --> 00:12:48,950
+into the block، علشان طبعاً أنا يعني أدخل المسمار
+
+156
+00:12:48,950 --> 00:12:52,870
+داخل الخشبة، the.. the hammer must exert a net
+
+157
+00:12:52,870 --> 00:12:56,230
+force on the nail، طبعاً في عندي أنا.. أنا بأضرب
+
+158
+00:12:56,230 --> 00:13:00,310
+اللي هي نضرب احنا اللي زي هو موضح بالشكل، تضرب أنتَ
+
+159
+00:13:00,310 --> 00:13:04,410
+الشاكوش.. المسمار بالشاكوش، الشاكوش طبعاً المسمار داخل
+
+160
+00:13:04,410 --> 00:13:07,470
+في الخشب أو في أيّ حائط أو في أيّ.. ف.. ف.. فبجد
+
+161
+00:13:07,470 --> 00:13:11,590
+في عندي أنا بقى.. بقى أشعر إنّه في هناك ردّ فعل
+
+162
+00:13:11,590 --> 00:13:16,570
+لهذه.. لهذه الحركة.. لهذه الحركة، طبعاً قانون نيوتن
+
+163
+00:13:16,570 --> 00:13:22,290
+الثالث بيحكي، إنّه لكل فعل في عندي ردّ فعل مساوٍ له
+
+164
+00:13:22,290 --> 00:13:26,030
+بالمقدار، ومضاد له بالاتجاه، that forces is nature
+
+165
+00:13:26,030 --> 00:13:29,550
+always exist in pairs، طبعاً هذه القوة اللي هي
+
+166
+00:13:29,550 --> 00:13:33,350
+القوة هي طبيعية بين الزوجين، according to Newton's
+
+167
+00:13:33,350 --> 00:13:36,090
+as the nail is driven into the block by the force
+
+168
+00:13:36,090 --> 00:13:39,580
+exerted by the hammer
+
+223
+00:17:28,980 --> 00:17:34,680
+monitor هنا على الطاولة، ففي عندي أنا الـ FG لأسفل
+
+224
+00:17:34,680 --> 00:17:38,280
+قوة جاذبية الأرض، وهنا بيصير عندي الطاولة نفسها
+
+225
+00:17:38,280 --> 00:17:42,280
+بتأثر على الـ monitor بقوة اسمها N، اسمها الـ normal
+
+226
+00:17:42,280 --> 00:17:47,040
+force أو قوة رد الفعل العمودية، تعاكس هذه القوة
+
+227
+00:17:47,040 --> 00:17:51,180
+وتساويها في المقدار، لكي يحدث عندي أنا اتزان في
+
+228
+00:17:51,180 --> 00:17:57,480
+الأجسام. القوة لها كمية حركة
+
+229
+00:17:57,480 --> 00:18:00,580
+(This line seems to be a repetition and should be removed)
+
+230
+00:18:00,580 --> 00:18:02,900
+(This line seems to be a repetition and should be removed)
+
+231
+00:18:02,900 --> 00:18:04,880
+(This line seems to be a repetition and should be removed)
+
+232
+00:18:04,880 --> 00:18:06,400
+(This line seems to be a repetition and should be removed)
+
+233
+00:18:06,400 --> 00:18:08,960
+(This line seems to be a repetition and should be removed)
+
+234
+00:18:08,960 --> 00:18:10,400
+(This line seems to be a repetition and should be removed)
+
+235
+00:18:10,400 --> 00:18:11,700
+(This line seems to be a repetition and should be removed)
+
+236
+00:18:11,700 --> 00:18:19,240
+(This line seems to be a repetition and should be removed)
+
+237
+00:18:19,240 --> 00:18:24,730
+كمعلى أي سطح، وهذا الجسم ما بتسارع، ما بيتحرك بأي
+
+238
+00:18:24,730 --> 00:18:28,930
+أحوال. في عندي اتزان. معنى الكلام أنه summation للـ
+
+239
+00:18:28,930 --> 00:18:33,370
+F، راح أحكي FG زائد الـ N بتساوي zero. معنى الكلام
+
+240
+00:18:33,370 --> 00:18:38,790
+أنه الـ FG بدها تساوي ناقص MG. إذا الـ normal بدها
+
+241
+00:18:38,790 --> 00:18:42,890
+تساوي الـ MG في هذه الحالة، لإنه في عندي حالة اتزان.
+
+242
+00:18:44,630 --> 00:18:48,590
+نأخذ الـ quiz: small sport car collided head-on with a
+
+243
+00:18:48,590 --> 00:18:56,470
+massive truck. في عندي سيارة رياضة صغيرة، طبعاً خبطت
+
+244
+00:18:56,470 --> 00:19:00,930
+أو اصطدمت مع truck كبير، شاحنة كبيرة. The greater
+
+245
+00:19:00,930 --> 00:19:07,230
+impact force acts on. طبعاً مين الأكثر قوة أثرت؟ هل
+
+246
+00:19:07,230 --> 00:19:11,330
+السيارة أثرت على الشاحنة، أم الشاحنة أثرت على السيارة؟
+
+247
+00:19:11,330 --> 00:19:16,410
+مين أثر على الثاني بقوة أكبر؟ طبعاً هل الـ car ولا الـ
+
+248
+00:19:16,410 --> 00:19:20,030
+truck؟ هل السيارة... السيارة قوتها أكبر، ولا الـ
+
+249
+00:19:20,030 --> 00:19:23,470
+truck قوته أكبر؟ ولا neither the force is the same?
+
+250
+00:19:23,470 --> 00:19:29,030
+on the force. طبعاً هي الإجابة C، لإنه الشاحنة أثرت على
+
+251
+00:19:29,030 --> 00:19:33,150
+السيارة، والسيارة أثرت على الشاحنة بقوة متساوية
+
+252
+00:19:33,150 --> 00:19:37,700
+بالمقدار، ومتضادة... مضادة بالاتجاه. هذا بالنسبة
+
+253
+00:19:37,700 --> 00:19:43,440
+لمين؟ بالنسبة للقوة. لكن which vehicle undergoes
+
+254
+00:19:43,440 --> 00:19:46,480
+the greater magnitude acceleration؟ لو احنا اتفقنا
+
+255
+00:19:46,480 --> 00:19:50,740
+أن الـ F مقدار ثابت، بتساوي الـ M في A. إذا زادت الـ M،
+
+256
+00:19:50,740 --> 00:19:54,820
+بتقل الـ A. فمعنى الكلام لما بيجي بيحكي لي which
+
+257
+00:19:54,820 --> 00:19:56,860
+vehicle undergoes the greater magnitude
+
+258
+00:19:56,860 --> 00:20:00,780
+acceleration؟ مين اللي له تسارع أكبر؟ بنحكي اللي
+
+259
+00:20:00,780 --> 00:20:04,630
+له تسارع أكبر هو اللي كتلته أقل، وبالتالي السيارة
+
+260
+00:20:04,630 --> 00:20:08,690
+هتتسارع بتسارع أكبر، لإنه الشاحنة خبطتها، وبالتالي
+
+261
+00:20:08,690 --> 00:20:14,350
+كتلتها أقل، فتسارعها أكبر. الشاحنة كتلته كبيرة، تسارعه
+
+262
+00:20:14,350 --> 00:20:17,630
+أقل. لكن القوة الأولى تساوي القوة الثانية، القوتان
+
+263
+00:20:17,630 --> 00:20:22,030
+متساويتان في المقدار، ومتعاكستان بالاتجاه. لكن تسارع
+
+264
+00:20:22,030 --> 00:20:25,610
+الكتلة الصغيرة بتكون أكبر، اللي هي الـ car، وتسارع
+
+265
+00:20:25,610 --> 00:20:32,530
+الكتلة الكبيرة بيكون أقل، اللي هو الشاحنة. نستكمل طبعاً
+
+266
+00:20:32,530 --> 00:20:38,210
+الأمثلة. في عندي man example: أربعة، خمسة... man of mass
+
+267
+00:20:38,210 --> 00:20:42,150
+M: خمسة وسبعين kilogram، and woman of mass: خمسة
+
+268
+00:20:42,150 --> 00:20:46,270
+وخمسين. في عندي امرأة ورجل، الرجل كتلته خمسة وسبعين
+
+269
+00:20:46,270 --> 00:20:49,450
+kilogram، والمرأة كتلتها خمسة وخمسين kilogram.
+
+270
+00:20:49,450 --> 00:20:53,850
+stand... stand facing each other on ice ring.
+
+271
+00:20:53,850 --> 00:21:00,490
+موجودين على سطح جليد، مقابل بعض. both wearing
+
+272
+00:21:00,490 --> 00:21:06,010
+ice skater. لابسين طبعاً اللي هي الأحذية الخاصة بتزلج
+
+273
+00:21:06,010 --> 00:21:10,110
+على الجليد. The woman pushes the man with a
+
+274
+00:21:10,110 --> 00:21:13,610
+horizontal force F بتساوي 85. المرأة وهي ماشية
+
+275
+00:21:13,610 --> 00:21:19,910
+دفعت الرجل، أو اصطدمت بالرجل بقوة 85 نيوتن، in the
+
+276
+00:21:19,910 --> 00:21:24,280
+positive x axis. assuming the ice is frictionless.
+
+277
+00:21:24,280 --> 00:21:27,920
+طبعاً في الـ ice في عندي أنا، ما في عندي احتكاك، معناته
+
+278
+00:21:27,920 --> 00:21:31,400
+frictionless. what is the man’s acceleration؟ الآن
+
+279
+00:21:31,400 --> 00:21:35,760
+what is the man’s acceleration؟ أول حاجة هكتب قانون
+
+280
+00:21:35,760 --> 00:21:38,480
+نيوتن الثاني، اللي هو الـ F بدها تساوي الـ M في A.
+
+281
+00:21:38,480 --> 00:21:42,940
+إذا الـ F بدها تساوي الـ M في A. الـ F اللي أثرت
+
+282
+00:21:42,940 --> 00:21:46,480
+عليها المرأة على الرجل كانت خمسة وثمانين، يعني
+
+283
+00:21:46,480 --> 00:21:50,900
+الخمسة وثمانين. الرجل تأثر بقوة خمسة وثمانين من
+
+284
+00:21:50,900 --> 00:21:56,190
+المرأة. الـ F موجودة، اللي هي الـ 85. إذا، والـ A، والـ M
+
+285
+00:21:56,190 --> 00:22:02,290
+للرجل 75. إذا الـ A للـ M، الـ A للـ M للـ man، للرجل
+
+286
+00:22:02,290 --> 00:22:07,250
+بتساوي الـ F: 85 على اللي هي الـ 75، كتلة الرجل. بتطلع
+
+287
+00:22:07,250 --> 00:22:13,850
+1.13 متر في الثانية تربيع. الآن بيحكي لنا what is the
+
+288
+00:22:13,850 --> 00:22:17,210
+reaction force acting on the woman؟ الـ woman أثرت
+
+289
+00:22:17,210 --> 00:22:22,770
+على الرجل بقوة 85 لليمين، فالرجل هيدفع للمرأة بقوة
+
+290
+00:22:22,770 --> 00:22:26,830
+مساوية لها باتجاه اليسار. فبيكون قوة الـ reaction
+
+291
+00:22:26,830 --> 00:22:32,490
+force من الرجل على المرأة بتساوي ناقص 85. المرأة هي
+
+292
+00:22:32,490 --> 00:22:37,170
+اللي دفعت الرجل بقوة 85، يعني الرجل متأثر بقوة 85
+
+293
+00:22:37,170 --> 00:22:42,950
+لليمين.  حقيقة الرجل هيرد الضربة للمرأة بقوة ناقص 85
+
+294
+00:22:42,950 --> 00:22:47,530
+إلى اليسار. الآن بدي أحسب الـ acceleration للمرأة.
+
+295
+00:22:47,530 --> 00:22:51,650
+بأستخدم قانون نيوتن: F بدها تساوي الـ M في A. طبعاً الـ
+
+296
+00:22:51,650 --> 00:22:56,670
+F للمرأة كانت ناقص 85، و الـ mass للمرأة 55. إذا الـ A
+
+297
+00:22:56,670 --> 00:23:02,450
+للـ woman بتساوي ناقص F على M: ناقص 85 على 55، بتطلع
+
+298
+00:23:02,450 --> 00:23:07,780
+ناقص 1.55. إذا الـ acceleration للمرأة هتساوي...
+
+299
+00:23:07,780 --> 00:23:12,460
+هتساوي ناقص واحد فاصلة خمسة خمسة. المرأة  إن شاء الله
+
+300
+00:23:12,460 --> 00:23:16,020
+نستكمل المواضيع القادمة بالـ...
+
+301
+00:23:16,020 --> 00:23:17,940
+بالمحاضرات القادمة، إن شاء الله.
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..0c35a7b12aef006b30ef7389a9d738b4dcb6af66
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI_raw.json
@@ -0,0 +1 @@
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34256, "start": 327.12, "end": 342.56, "text": "ناخد سؤال تاني example أربعة اتنين في عندي two horses are pulled a barge with mass اتنين فعشرة أو ثلاثة kilogram along a canal في عندي إحصانين بدهم يشدوا باخرة أو بارجة في وسط", "tokens": [1863, 47283, 3215, 8608, 33604, 6027, 6055, 7649, 1829, 1365, 5551, 25513, 27884, 1975, 2655, 1863, 9957, 8978, 18871, 16254, 732, 13112, 366, 7373, 257, 2159, 432, 365, 2758, 1975, 2655, 1863, 9957, 6156, 3615, 8592, 25720, 34051, 38637, 1211, 5718, 104, 3660, 21741, 2051, 257, 9911, 8978, 18871, 16254, 11933, 5016, 9381, 7649, 9957, 47525, 16095, 7251, 8592, 3215, 14407, 4724, 47283, 25720, 34051, 4724, 9640, 7435, 3660, 8978, 46952, 9566], "avg_logprob": -0.15421661285504903, "compression_ratio": 1.430939226519337, "no_speech_prob": 1.8477439880371094e-06, "words": [{"start": 327.12, "end": 327.52, "word": "ناخد", "probability": 0.9632161458333334}, {"start": 327.52, "end": 327.84, "word": " سؤال", "probability": 0.9952799479166666}, {"start": 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..489951b08e25e17c8989f37e9e6cb4e50f15dd8f
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/Nrjbns1BeAI_raw.srt
@@ -0,0 +1,1204 @@
+1
+00:00:00,000 --> 00:00:04,820
+بسم الله الرحمن الرحيم نستكمل chapter .. chapter
+
+2
+00:00:04,820 --> 00:00:12,960
+الرابع بعدة مسائل problems أربعة واحد an airport
+
+3
+00:00:12,960 --> 00:00:16,860
+with mass تلاتة و نص في عشرة قصة اتنين كيلو جرام
+
+4
+00:00:16,860 --> 00:00:22,290
+including the passengerhas an engine that produce
+
+5
+00:00:22,290 --> 00:00:29,090
+a net horizontal force of 7.7×10² Newton في عندي
+
+6
+00:00:29,090 --> 00:00:35,910
+قارب بحري موجود عليه مجموعة مسافرين ال motor طبعا
+
+7
+00:00:35,910 --> 00:00:41,630
+بيشتغل بقوة بقوة horizontal force قوة أفقية 7
+
+8
+00:00:41,630 --> 00:00:46,870
+.7×10² Newtonafter accounting for forces of
+
+9
+00:00:46,870 --> 00:00:52,370
+resistance طبعا و هو ماشي خلال الطريق هناك قوة ..
+
+10
+00:00:52,370 --> 00:00:56,630
+قوة معاكسة أو ممانعة مطلوب find the acceleration
+
+11
+00:00:56,630 --> 00:01:00,570
+of the airport المفروض التسارع أو جد التسارع و
+
+12
+00:01:00,570 --> 00:01:05,030
+بعدين starting from rest how long does it take the
+
+13
+00:01:05,030 --> 00:01:10,110
+airport to reach a speed of اتناشر متر في الثانية
+
+14
+00:01:10,370 --> 00:01:16,570
+بدو اذا اح .. اذا القارب بدأ من السكون كام الوقت
+
+15
+00:01:16,570 --> 00:01:21,530
+اللازم ليصل الى سرعة اتناشر متر فى الثانية ايضا
+
+16
+00:01:21,530 --> 00:01:26,130
+مطلوب after reaching that speed بعد ما يوصل هذه
+
+17
+00:01:26,130 --> 00:01:33,940
+السرعة ال .. السائقأو البحار بده يرجع return of
+
+18
+00:01:33,940 --> 00:01:38,460
+engine and drift to stop over a distance خمسين بده
+
+19
+00:01:38,460 --> 00:01:42,980
+يرجع ويمشي مسافة خمسين find the resistance force
+
+20
+00:01:42,980 --> 00:01:47,560
+مطلوب ال resistance force هي السؤال في عند بحار
+
+21
+00:01:47,560 --> 00:01:54,180
+راكب air boat مفيه مركب المركب طبعا هيمشي باتجاه
+
+22
+00:01:54,180 --> 00:01:59,020
+ال .. اللي هي ال horizontal اتجاه الشرق او اليمين
+
+23
+00:01:59,080 --> 00:02:06,520
+بقوة F اعطانياها حتى يصل الى سرعة 12 نمشي واحد
+
+24
+00:02:06,520 --> 00:02:10,320
+واحد المطلوب الأول solution find the acceleration
+
+25
+00:02:10,320 --> 00:02:14,100
+of the air boat بده ال acceleration لإيجاد ال
+
+26
+00:02:14,100 --> 00:02:17,880
+acceleration بده اطبق قانون نيوتن التاني summation
+
+27
+00:02:17,880 --> 00:02:22,500
+لل F بتساوي M في A طبعا ال F الآن في التجاه ال X
+
+28
+00:02:23,130 --> 00:02:26,170
+Summation لل F بدها تساوي او ال F net بدها تساوي
+
+29
+00:02:26,170 --> 00:02:29,690
+ال M في A، اذا ال A بدها تساوي ال F net على M،
+
+30
+00:02:29,690 --> 00:02:33,010
+اعطاني ال F باتجاه ال horizontal 7.7 في 10 عصر 2
+
+31
+00:02:33,010 --> 00:02:37,630
+نيوتن على ال mass 3.5 في 10 عصر 2، تطلع عندي ال A
+
+32
+00:02:37,630 --> 00:02:43,650
+2.2 متر في الثانية تربيعFind the time necessary to
+
+33
+00:02:43,650 --> 00:02:47,890
+reach the speed of 12 بدنا نوجد الزمن اللازم لتصل
+
+34
+00:02:47,890 --> 00:02:54,550
+سرعة القارب إلى 12 متر في الثانية بنطبق قانون الهو
+
+35
+00:02:54,550 --> 00:02:57,430
+a kinematic velocity equation قانون من قوانين
+
+36
+00:02:57,430 --> 00:03:00,890
+الحركة القوانين الأول من قوانين الحركة V بتساوي V
+
+37
+00:03:00,890 --> 00:03:07,240
+naught زائد ATV انا بدي او اللي هي ايا كانت وصلت
+
+38
+00:03:07,240 --> 00:03:12,320
+اتناش V not بدأ من ال rest سفر ال A اللي هي طلعت
+
+39
+00:03:12,320 --> 00:03:16,480
+اندي اتنين point اتنين هي في المطلوب الاول و ال T
+
+40
+00:03:16,480 --> 00:03:20,820
+هو طلبها اذا ال T بتطلعلي خمسة point اربع خمس
+
+41
+00:03:20,820 --> 00:03:25,580
+ثانية هذا الزمن اللي لازم يتصل سرعته الى اتناشر
+
+42
+00:03:25,580 --> 00:03:29,310
+متر في الثانيةفي المطلوب C find the resistance
+
+43
+00:03:29,310 --> 00:03:36,430
+force after the engine is turned off بده اللي هي
+
+44
+00:03:36,430 --> 00:03:40,010
+resistance force قوة الممانعة اللي هي يعني اللي
+
+45
+00:03:40,010 --> 00:03:44,950
+بتعاكس القوة الأصلية أو الحركة الأصلية find a net
+
+46
+00:03:44,950 --> 00:03:48,450
+acceleration due to resist the resistance force في
+
+47
+00:03:48,450 --> 00:03:52,290
+البداية بدي أوجد اللي هي اللي بدي أوجد اللي هي
+
+48
+00:03:52,290 --> 00:03:57,090
+resistance force هأوجد اللي هي التسارعاللي هي
+
+49
+00:03:57,090 --> 00:04:01,920
+العكسىمن خلال الحركة V تربيع بتناقص V not تربيع
+
+50
+00:04:01,920 --> 00:04:07,000
+بتساوي 2A Delta X طبعا هذا من القانون V تربيع بدها
+
+51
+00:04:07,000 --> 00:04:12,460
+تساوي V not تربيع زائد 2AX طبعا هيوصل لإنه هي توقف
+
+52
+00:04:12,460 --> 00:04:17,140
+بعد مسافة 50 اللي هي السرعة اللي أنا انتهيت منها
+
+53
+00:04:17,140 --> 00:04:20,540
+من الحركة الأولى هابدأ فيها في الحركة التانية اللي
+
+54
+00:04:20,540 --> 00:04:24,900
+هي V not تربيع اللي هي ال 12 يعني أنا عندي مرحلتين
+
+55
+00:04:24,900 --> 00:04:28,900
+المرحلة الأولى رايح للشرق المرحلة التانيةراح لاقى
+
+56
+00:04:28,900 --> 00:04:34,520
+الغرب ف V نهائية 0 ناقص V naught اللى هى ال 12 هى
+
+57
+00:04:34,520 --> 00:04:38,680
+المرحلة ال 12 هى السرعة النهائية اللى انتهى فيها
+
+58
+00:04:38,680 --> 00:04:42,260
+فى المرحلة الاولى تعتبر سرعة ابتدائية للمرحلة
+
+59
+00:04:42,260 --> 00:04:45,870
+التانية اللى هى 12متر في الثانية تربيع لكل تربيع
+
+60
+00:04:45,870 --> 00:04:58,310
+تسوى 2A في المسافة 50 اذا ال A تطلع ناقص 1.44 متر
+
+61
+00:04:58,310 --> 00:05:02,710
+في الثانية تربيع لكل تربيعرح اعود عن التسارع هذا
+
+62
+00:05:02,710 --> 00:05:07,530
+في قانون النيوتن التاني اذا ال F resistance بتساوي
+
+63
+00:05:07,530 --> 00:05:11,550
+ال M في A ال M تلاتة و نص في عشرة أوس اتنين و ال A
+
+64
+00:05:11,550 --> 00:05:15,210
+كانت ناقص واحد point أربعة أربعة اذا تطلع لل F
+
+65
+00:05:15,210 --> 00:05:19,390
+ناقص خمس مائة و أربعة نيوتن طبعا الناقص لإنها عكس
+
+66
+00:05:19,390 --> 00:05:24,870
+الحركة الأصلية فال F بتساوي ناقص خمس مائة و أربعة
+
+67
+00:05:24,870 --> 00:05:31,200
+نيوتنناخد سؤال تاني example أربعة اتنين في عندي
+
+68
+00:05:31,200 --> 00:05:35,200
+two horses are pulled a barge with mass اتنين
+
+69
+00:05:35,200 --> 00:05:38,680
+فعشرة أو ثلاثة kilogram along a canal في عندي
+
+70
+00:05:38,680 --> 00:05:43,780
+إحصانين بدهم يشدوا باخرة أو بارجة في وسطقناة أو
+
+71
+00:05:43,780 --> 00:05:49,520
+وسط فرق من النهر كتلتها اتنين في عشرة او ثلاثة
+
+72
+00:05:49,520 --> 00:05:53,180
+kilogram along a canal as shown in the figure ال
+
+73
+00:05:53,180 --> 00:05:56,640
+cable connected to the first horse في عندي طبعا
+
+74
+00:05:56,640 --> 00:06:02,580
+الحصان الأول مربوط بحبل بيعمل زاوية تلاتين with
+
+75
+00:06:02,580 --> 00:06:05,420
+respect to the direction of the canal while the
+
+76
+00:06:05,420 --> 00:06:09,320
+cable connect to the second horse make an angle of
+
+77
+00:06:09,320 --> 00:06:13,480
+ناقص خمسة او اربعينطبعا زى ما هو مضح بالشكل فى
+
+78
+00:06:13,480 --> 00:06:18,820
+عندي انا احصانين الاحصانين بدهم يشدوا برج او باخرة
+
+79
+00:06:18,820 --> 00:06:25,960
+الاحصان الاول ماسك الباخرة بخيط او حبل او كابل
+
+80
+00:06:25,960 --> 00:06:31,280
+بيميل بزاوية θ واحد تلاتين الاحصان التانى بيشده
+
+81
+00:06:31,280 --> 00:06:35,820
+بقوة ومايل بزاوية ناقص خمسة واربعين يعني ناقص عن
+
+82
+00:06:35,820 --> 00:06:41,060
+ال X axis اللى هو الموجة بخمسة واربعينبدي اوجد ال
+
+83
+00:06:41,060 --> 00:06:44,440
+acceleration of the barge بدي اوجد التسارع لهذه ال
+
+84
+00:06:44,440 --> 00:06:48,180
+barge starting at rest if each horse exerts a
+
+85
+00:06:48,180 --> 00:06:51,880
+force of magnitude 6 في عشرة أس اتنين نيوتن on the
+
+86
+00:06:51,880 --> 00:06:55,400
+barge إذا كانت الأف للحصان الأول هي نفس الأف
+
+87
+00:06:55,400 --> 00:06:58,520
+للحصان التاني يعني أف واحد بتساوي الأف اتنين
+
+88
+00:06:58,520 --> 00:07:03,780
+وتساوي 6 في عشرة أس اتنين طبعا بدي نهمل اللي هي
+
+89
+00:07:04,130 --> 00:07:08,470
+الممانعة اللى بيلاقيها ال .. البرج او تلاقيها
+
+90
+00:07:08,470 --> 00:07:13,390
+البرج ب .. او اللى هى بتلاقيها البرج من الميه اللى
+
+91
+00:07:13,390 --> 00:07:16,390
+هى ابنانهم المقاومة اللى هى الممانعة اللى بتلاقيها
+
+92
+00:07:16,390 --> 00:07:22,860
+خلال شدها من الحصانين الحلطبعا انا عندى اللى هى
+
+93
+00:07:22,860 --> 00:07:26,700
+المقاومة الاولى القوة الاولى للحصان الاول F1 cos
+
+94
+00:07:26,700 --> 00:07:34,820
+θ1 فى اتجاه ال X و F2 X بتسوى F2 cos θ2 الان F
+
+95
+00:07:34,820 --> 00:07:37,940
+اللى هى القوة الاولى بتجاه ال X للحصان الاول F1
+
+96
+00:07:37,940 --> 00:07:41,870
+cos θ1 اذا انا حللتأو المركبة الأولى في اتجاه ال X
+
+97
+00:07:41,870 --> 00:07:46,710
+للقوة الأولى 6 فى 10 رقص 2 كوزاين التلاتين المركبة
+
+98
+00:07:46,710 --> 00:07:51,670
+ال X للقوة التانية 6 فى 10 رقص 2 كوزاين الناقص 45
+
+99
+00:07:51,670 --> 00:07:57,830
+لأنه ال 45 نازلة باتجاه X السالبالان طلعت القوة
+
+100
+00:07:57,830 --> 00:08:00,630
+الاولى بالاتجاه ال X والقوة التانية بالاتجاه X اذا
+
+101
+00:08:00,630 --> 00:08:07,130
+المركبة X للقوة الاولى والتانية بدها تساوي 5.2×10²
+
+102
+00:08:07,130 --> 00:08:14,050
+زائد 4.2×10² تطلع 9.44×10² هذه هي عبارة عن القوة
+
+103
+00:08:14,050 --> 00:08:19,320
+الكلية في اتجاه ال X القوة المحصلةلقوة شد الإحصان
+
+104
+00:08:19,320 --> 00:08:24,040
+الأول والاتنين الآن بدأ أحسب ال F باتجاه ال Y يعني
+
+105
+00:08:24,040 --> 00:08:28,400
+لما أنا حللت القوة راح تطلع F1Y sin θ1
+
+106
+00:08:31,830 --> 00:08:41,830
+6×10²Nsin 30 و F2Y 6×10²Sin-45 يظهر الجواب ناقص 4
+
+107
+00:08:41,830 --> 00:08:46,530
+.24×10² هاي القوة في اتجاه Y المحصلة وهي القوة
+
+108
+00:08:46,530 --> 00:08:49,830
+المحصلة في اتجاه X الان بدي اجيب ال magnitude لهذه
+
+109
+00:08:49,830 --> 00:08:54,790
+المحصلة اللي هي عبارة عن جزر التربيعي الان FY
+
+110
+00:08:54,790 --> 00:09:00,260
+المحصلة لتنتين بدها تساويفي واحد زائد اف اتنين Y
+
+111
+00:09:00,260 --> 00:09:05,140
+بدي اجمع اللي هي محصلة ال Y للقوة الأولى و القوة
+
+112
+00:09:05,140 --> 00:09:09,000
+التانية جمعتهم بتلع ناقص واحد point اتنين اربع
+
+113
+00:09:09,000 --> 00:09:13,400
+فعشرة اقصى اتنين الان جيبت F X المحصلة و جيبت F Y
+
+114
+00:09:13,400 --> 00:09:21,510
+المحصلة بدي اجيب ال A X اتجاه التسارع باتجاه ال Xو
+
+115
+00:09:21,510 --> 00:09:26,390
+بعدين اتجاه التسارع باتجاه ال Y اذا ال AX بدها
+
+116
+00:09:26,390 --> 00:09:31,870
+تساوي FX على M هذه أجت من ان ال FX بتساوي M في AX
+
+117
+00:09:31,870 --> 00:09:38,090
+اذا ال AX بدها تساوي FX على Mاللي هي ال Fx المحصلة
+
+118
+00:09:38,090 --> 00:09:46,650
+9.44102 نيوتن على M 2.103 كيلو جرام بتطلع الجواب 0
+
+119
+00:09:46,650 --> 00:09:51,850
+.472 متر في الثانية تربية هذا التسارع باتجاه ال X
+
+120
+00:09:51,850 --> 00:09:57,310
+نيجي للتسارع باتجاه ال Y ال AY ده أخد محصلة AY على
+
+121
+00:09:57,310 --> 00:10:07,450
+Mمحصلة ay هي ناقص 1.24×10−2 نيوتين على 2×10−3 كيلو
+
+122
+00:10:07,450 --> 00:10:13,850
+جرام تطلع عندنا ناقص 0.062 متر في الثانية تربيع
+
+123
+00:10:13,850 --> 00:10:18,250
+إذا جيبت ال a مركبة التسارع بتجاه ال X مركبة
+
+124
+00:10:18,250 --> 00:10:22,860
+الصادية بتجاه ال Yالان بده اجيب ال magnitude و ال
+
+125
+00:10:22,860 --> 00:10:26,760
+direction لل a بده ال magnitude راح اعمل اللي هو
+
+126
+00:10:26,760 --> 00:10:34,400
+القانون جزر ax تربيع زائد ay تربيع بيطلع عندي طبعا
+
+127
+00:10:34,400 --> 00:10:38,000
+قيمة ال ax تربيع زائد قيمة ال ay تربيع اللي احنا
+
+128
+00:10:38,000 --> 00:10:42,480
+طلعناها بيطلع عندي point أربع سبعة ستة متر في
+
+129
+00:10:42,480 --> 00:10:46,540
+الثانية تربيع هذه هي ك magnitude قيمة التسارع ك
+
+130
+00:10:46,540 --> 00:10:50,870
+magnitude بالنسبة للاتجاه المحصلةcalculate the
+
+131
+00:10:50,870 --> 00:10:54,350
+direction of the acceleration using the tangent
+
+132
+00:10:54,350 --> 00:11:01,770
+function اذا تاني الثيتا بتساوي ay على ax اللي هي
+
+133
+00:11:01,770 --> 00:11:08,350
+باخد ال ay بإشارتها و ال ax بإشارتها ال ay ناقص و
+
+134
+00:11:08,350 --> 00:11:13,750
+ال ax موجة معناها موجودة بالربع بالربع او الرابع
+
+135
+00:11:13,750 --> 00:11:17,770
+موجودة بالربع الرابع اذا تاني الثيتا بتساوي ناقص
+
+136
+00:11:19,460 --> 00:11:23,860
+.131 إذا الـ θ بيساوي 10 inverse لهذه القيمة
+
+137
+00:11:23,860 --> 00:11:29,640
+بيساوي ناقص 7.46 طبعا ما بضيفلها 180 هذه بتكون
+
+138
+00:11:29,640 --> 00:11:35,580
+الزاوية اللي هي 7.46 تحت تحت اتجاه ال X الموجب
+
+139
+00:11:35,580 --> 00:11:39,970
+بالناحيةيعني باتجاه حقارب الساعة ما باضفلها ال 180
+
+140
+00:11:39,970 --> 00:11:43,610
+لإنها موجودة في الربع الرابع ال quantity that obey
+
+141
+00:11:43,610 --> 00:11:48,770
+the rules of ordinary arithmetic طبعا هذه القيمة
+
+142
+00:11:48,770 --> 00:11:53,190
+طبعا بدنا نمشي تنطبق علينا قوانين اللي احنا
+
+143
+00:11:53,190 --> 00:11:58,550
+استخدمناها سابقا انه اذا كان الزاوية المحصلة في
+
+144
+00:11:58,550 --> 00:12:04,690
+الربع التاني او التالت باضفلهابأضيف لها 180 وإذا
+
+145
+00:12:04,690 --> 00:12:07,530
+كانت في الرُبع الأول أو التاني ما ب .. ما باضيف
+
+146
+00:12:07,530 --> 00:12:10,970
+إذا كانت في الرُبع الأول مع اتجاه الساعة بتكون
+
+147
+00:12:10,970 --> 00:12:14,290
+موجبة أو مع اتجاه الساعة بتكون سالب وعكس اتجاه
+
+148
+00:12:14,290 --> 00:12:18,050
+الساعة بتكون الموجة اللي هي الزاوية موجبة من اتجاه
+
+149
+00:12:18,050 --> 00:12:22,170
+X الموجة نيجي لها نكمل استكمل القوانين النيوتن
+
+150
+00:12:22,170 --> 00:12:27,860
+للحركة قوانين الحركة قانون التالت لنيوتنconsider
+
+151
+00:12:27,860 --> 00:12:31,740
+the task of driving a nail into a block of wood
+
+152
+00:12:31,740 --> 00:12:34,540
+for example as illustrated in the figure لو أنا
+
+153
+00:12:34,540 --> 00:12:40,960
+فرضت في عندي انا بدي انا اضرب مسمار في شكوش زي هو
+
+154
+00:12:40,960 --> 00:12:45,060
+موضح بالشكل to accelerate the nail and drive it
+
+155
+00:12:45,060 --> 00:12:48,950
+into the blockعلشان طبعا انا يعني ادخل المصمار
+
+156
+00:12:48,950 --> 00:12:52,870
+داخل الخشبة the .. the hammer must exert a net
+
+157
+00:12:52,870 --> 00:12:56,230
+force on the nail طبعا في عندي انا .. انا بدرب
+
+158
+00:12:56,230 --> 00:13:00,310
+اللي هي نضرب احنا اللي زي هم موضح بالشكل تضرب انت
+
+159
+00:13:00,310 --> 00:13:04,410
+الشكوش .. المصمار بالشكوش الشكوش طبعا المصمار داخل
+
+160
+00:13:04,410 --> 00:13:07,470
+في الخشب او في اي حيط او في اي .. ف .. ف .. فبجد
+
+161
+00:13:07,470 --> 00:13:11,590
+في عندي انا بقى .. بقى اشعر بإنه في هناك رد فعل
+
+162
+00:13:11,590 --> 00:13:16,570
+لهذا .. لهذه الحركة .. لهذه الحركةطبعا قانون نيوتن
+
+163
+00:13:16,570 --> 00:13:22,290
+التالت بيحكي لإنه لكل فعل في عندى رد فعل مساوي إله
+
+164
+00:13:22,290 --> 00:13:26,030
+بالمقدار ومضاد إله بالاتجاه that forces is nature
+
+165
+00:13:26,030 --> 00:13:29,550
+always exist in pairs طبعا هذه الزاوية اللى هى
+
+166
+00:13:29,550 --> 00:13:33,350
+القوة هى طبيعية بين الزوجين according to newtons
+
+167
+00:13:33,350 --> 00:13:36,090
+as the nail is driving into the block by the force
+
+168
+00:13:36,090 --> 00:13:39,580
+exerted by the hammerthe hammer is slowed down and
+
+169
+00:13:39,580 --> 00:13:42,560
+stopped by the force exceeded by the nail. Newton
+
+170
+00:13:42,560 --> 00:13:45,700
+describes such bears forces with his third law
+
+171
+00:13:45,700 --> 00:13:50,240
+طبعا حركة الشكوش والمصمار داخل الحائط أو داخل
+
+172
+00:13:50,240 --> 00:13:54,980
+الخشب فسرليها نيوتن بسمها قانون نوتن التاني لو كان
+
+173
+00:13:54,980 --> 00:13:59,460
+عندي أنا جسمين جسم واحد وجسم تاني interact the
+
+174
+00:13:59,460 --> 00:14:03,700
+force أف واحد يعني بيأثروا على بعض بقوة أف الأول
+
+175
+00:14:03,700 --> 00:14:07,340
+بيأثر على التاني والتاني بيأثر على الأولفالأو
+
+176
+00:14:07,340 --> 00:14:10,980
+اتنين بيأثروا على بعض لو عندي أنا جسمين هد أم واحد
+
+177
+00:14:10,980 --> 00:14:14,760
+هد أم اتنين او هد واحد و اتنين واحد أثر على اتنين
+
+178
+00:14:14,760 --> 00:14:18,260
+و اتنين أثر على واحد بي .. بيصير عندي انه ال F
+
+179
+00:14:18,260 --> 00:14:22,200
+واحد اتنين بدها تساوي ناقص F اتنين واحد يعني عندي
+
+180
+00:14:22,200 --> 00:14:25,720
+أنا كتلتين او جسمينجسم الأول وجسم التاني أثروا على
+
+181
+00:14:25,720 --> 00:14:29,820
+بعض بقوتين فبأثروا على بعض بقوتين متساوتين في
+
+182
+00:14:29,820 --> 00:14:34,060
+المقدار ومتعاكستين بالاتجاه هذا قانون نيوتن التالت
+
+183
+00:14:34,060 --> 00:14:38,940
+انه لكل فعل رد فعل مساوي له في المقدار ومعاكس له
+
+184
+00:14:38,940 --> 00:14:41,820
+بالاتجاه this law which is illiterated in the
+
+185
+00:14:41,820 --> 00:14:44,960
+figure state that يعني ينص هذا القانون على ان
+
+186
+00:14:44,960 --> 00:14:50,320
+single isolated force can't existمستحيل يكون عندي
+
+187
+00:14:50,320 --> 00:14:54,960
+أناقوة لحالها يعني انه .. انه لل .. لل .. لل
+
+188
+00:14:54,960 --> 00:15:00,720
+single particle او single يعني لأي جسم body انه
+
+189
+00:15:00,720 --> 00:15:06,580
+يأثر على حاله the force F12 exerted by object 1 on
+
+190
+00:15:06,580 --> 00:15:12,340
+object 2 ال F12 انه F1 أثرت يعني الجسم الأول أثر
+
+191
+00:15:12,340 --> 00:15:16,900
+على الت .. التنين و التاني و التاني أثر على الأول
+
+192
+00:15:16,900 --> 00:15:20,560
+بقوة مساوية بالمقدارو معاكسة بالاتجاه بيسموه
+
+193
+00:15:20,560 --> 00:15:24,000
+reaction force معناته في عندي قوة ال action و في
+
+194
+00:15:24,000 --> 00:15:29,060
+عندي قوة reaction لكل فعل رد فعل the action force
+
+195
+00:15:29,060 --> 00:15:32,360
+is equal in magnitude to the reaction force and
+
+196
+00:15:32,360 --> 00:15:35,940
+opposite in direction in all cases يعني قوة الفعل
+
+197
+00:15:35,940 --> 00:15:41,120
+تساوي قوة رد الفعلمساوى بالمقدار ومعاكسة بالاتجاه
+
+198
+00:15:41,120 --> 00:15:44,040
+the action and reaction force act on different
+
+199
+00:15:44,040 --> 00:15:48,820
+objects قوة الفعل وقوة رد الفعل بيأثروا على جسمين
+
+200
+00:15:48,820 --> 00:15:53,100
+مختلفين وليست على جسم واحد it is known that earth
+
+201
+00:15:53,100 --> 00:15:57,880
+exerted gravitational force FG on any object ممكن
+
+202
+00:15:57,880 --> 00:16:02,720
+قوة الجاذبية القوة الناتجة عن الأرض تؤثر على أي
+
+203
+00:16:02,720 --> 00:16:06,000
+جسم if the object is a monitor at rest on the
+
+204
+00:16:06,000 --> 00:16:11,840
+tablethe reaction force to FG is the gravitational
+
+205
+00:16:11,840 --> 00:16:15,880
+force the momentum exerted on earth FG شرطة the
+
+206
+00:16:15,880 --> 00:16:19,160
+momentum does not accelerate downward because it's
+
+207
+00:16:19,160 --> 00:16:23,840
+held up by the table the table therefore exerted
+
+208
+00:16:23,840 --> 00:16:31,300
+an upward force N إذا لو أنا حطيت أي جسم على طاولة
+
+209
+00:16:31,300 --> 00:16:35,320
+باجد أنه فيه قوة جاذبية قوة شدت الكتاب من عن
+
+210
+00:16:35,320 --> 00:16:40,570
+الطاولة لكن الطاولةبتأثر على الكتاب بقوة رد فعل
+
+211
+00:16:40,570 --> 00:16:44,490
+اسمها ال N بيسموها ال normal force او قوة رد الفعل
+
+212
+00:16:44,490 --> 00:16:49,110
+العمودية قوة رد الفعل العمودية the normal force
+
+213
+00:16:49,110 --> 00:16:51,710
+balance the gravitational force acting on the
+
+214
+00:16:51,710 --> 00:16:55,210
+monitor طبعا هذه ال normal force بتعمل ميزان او
+
+215
+00:16:55,210 --> 00:17:00,670
+بتعمل اتزان للجسم انه هذا الجسم يبقى على هذا ال ..
+
+216
+00:17:00,670 --> 00:17:04,240
+طبعا هذا المستوى او على هذا الصدمةpreventing the
+
+217
+00:17:04,240 --> 00:17:07,980
+monitor from falling through the table بتمنع هذا
+
+218
+00:17:07,980 --> 00:17:12,160
+الجسم انه يسقط على الأرض the reaction to and is
+
+219
+00:17:12,160 --> 00:17:15,540
+the force exerted by the monitor on the table and
+
+220
+00:17:15,540 --> 00:17:21,060
+شرطة therefore اذا ال FG قولت ناتج عن الجاذبية
+
+221
+00:17:21,060 --> 00:17:24,880
+بتساوي ناقص FG شرطة و ال and بتساوي ناقص ال and
+
+222
+00:17:24,880 --> 00:17:28,980
+شرطة بصفة عامة انه في لو انا حطيت كتاب او اي
+
+223
+00:17:28,980 --> 00:17:34,680
+monitor هناعلى الطاولة ففي عندي أنا ال FG لأسفل
+
+224
+00:17:34,680 --> 00:17:38,280
+قوة جاذبية الأرض و هنا بيصير عندي الطاولة نفسها
+
+225
+00:17:38,280 --> 00:17:42,280
+بتأثر على ال monitor بقوة اسمها N اسمها ال normal
+
+226
+00:17:42,280 --> 00:17:47,040
+force أو قوة رد الفعل العمودية تعاكس هذه القوة
+
+227
+00:17:47,040 --> 00:17:51,180
+وتسوية في المقدار لكي يحدث عندي انا اتزان في
+
+228
+00:17:51,180 --> 00:17:57,480
+الأجسامالقوة ان وان شرطه لديها كمية ان وفجي كمية
+
+229
+00:17:57,480 --> 00:18:00,580
+ان وفجي
+
+230
+00:18:00,580 --> 00:18:02,900
+كمية ان وفجي كمية ان وفجي كمية ان وفجي كمية ان
+
+231
+00:18:02,900 --> 00:18:04,880
+وفجي كمية ان وفجي كمية ان وفجي كمية ان وفجي كمية
+
+232
+00:18:04,880 --> 00:18:06,400
+ان وفجي كمية ان وفجي كمية ان وفجي كمية ان وفجي
+
+233
+00:18:06,400 --> 00:18:08,960
+كمية ان وفجي كمية ان وفجي كمية ان وفجي كمية ان
+
+234
+00:18:08,960 --> 00:18:10,400
+وفجي كمية ان وفجي كمية ان وفجي كمية ان وفجي كمية
+
+235
+00:18:10,400 --> 00:18:11,700
+ان وفجي كمية ان وفجي كمية ان وفجي كمية ان وفجي
+
+236
+00:18:11,700 --> 00:18:19,240
+كمية ان وفجي كمية ان وفجي
+
+237
+00:18:19,240 --> 00:18:24,730
+كمعلى أي سطح و هذا الجسم ما بتسارع ما بتحرك بكل
+
+238
+00:18:24,730 --> 00:18:28,930
+الأحوال في عندى اتزان معنى الكلام انه summation لل
+
+239
+00:18:28,930 --> 00:18:33,370
+F راح احكي FG زائد ال N بتساوي zero معنى الكلام
+
+240
+00:18:33,370 --> 00:18:38,790
+انه ال FG بدها تساوي ناقص MG اذا ال normal بدها
+
+241
+00:18:38,790 --> 00:18:42,890
+تساوي ال MG في هذه الحالة لإنه في عندى حالة اتزان
+
+242
+00:18:44,630 --> 00:18:48,590
+ناخد ال quiz small sport car collided head-on with
+
+243
+00:18:48,590 --> 00:18:56,470
+massive truck فى عندى سيارة رياضة صغيرة طبعا خبطت
+
+244
+00:18:56,470 --> 00:19:00,930
+او اصطدمت مع truck كبير شاحن كبير the greater
+
+245
+00:19:00,930 --> 00:19:07,230
+impact force acts on طبعا مين الأكتر قوة أثرت هل
+
+246
+00:19:07,230 --> 00:19:11,330
+السيارة أثرت على الشاحن أم الشاحن أثر على السيارة
+
+247
+00:19:11,330 --> 00:19:16,410
+مين أثر على التاني بقوة أكبرطبعا هل ال car ولا ال
+
+248
+00:19:16,410 --> 00:19:20,030
+truck .. هل السيارة .. السيارة قوتها أكبر ولا ال
+
+249
+00:19:20,030 --> 00:19:23,470
+truck قوته أكبر ولا neither the force is the same
+
+250
+00:19:23,470 --> 00:19:29,030
+on the force طبعا هي الإجابة C لإنه الشحن أثر على
+
+251
+00:19:29,030 --> 00:19:33,150
+السيارة والسيارة أثرت على الشحن بقوة متساوية
+
+252
+00:19:33,150 --> 00:19:37,700
+بالمقدار ومتضادة .. ومضادة بالاتجاههذا بالنسبة
+
+253
+00:19:37,700 --> 00:19:43,440
+لمين؟ بالنسبة للقوة لكن which vehicle undergoes
+
+254
+00:19:43,440 --> 00:19:46,480
+the greater magnitude acceleration؟ لو احنا اتفقنا
+
+255
+00:19:46,480 --> 00:19:50,740
+ان ال F مقدار ثابت بتساوي ال M في A إذا زادت ال M
+
+256
+00:19:50,740 --> 00:19:54,820
+بتقل ال A فمعنى الكلام لما بيجي بيحكي لي which
+
+257
+00:19:54,820 --> 00:19:56,860
+vehicle undergoes the greater magnitude
+
+258
+00:19:56,860 --> 00:20:00,780
+acceleration؟ مين اللي له تسارع أكبر؟ بنحكي اللي
+
+259
+00:20:00,780 --> 00:20:04,630
+له تسارع أكبر هو اللي كتلته أقل وبالتاليالسيارة
+
+260
+00:20:04,630 --> 00:20:08,690
+هتتسارع بتسارع أكبر لإن الشحن خبطها وبالتالي
+
+261
+00:20:08,690 --> 00:20:14,350
+كتلتها أقل فتسارعها أكبر الشحن كتلته كبيرة تسارعه
+
+262
+00:20:14,350 --> 00:20:17,630
+أقل لكن القوة الأولى تساوي القوة التانية القوتين
+
+263
+00:20:17,630 --> 00:20:22,030
+متساويتين في المقدار ومتعكستين بالاتجاه لكن تسارع
+
+264
+00:20:22,030 --> 00:20:25,610
+الكتلة الصغيرة بتكون أكبر اللى هى ال car وتسارع
+
+265
+00:20:25,610 --> 00:20:32,530
+الكتلة الكبيرة بيكون أقل اللى هو الشحننستكمل طبعا
+
+266
+00:20:32,530 --> 00:20:38,210
+الأمثلة في عندي man example أربع خمسة man of mass
+
+267
+00:20:38,210 --> 00:20:42,150
+M خمسة وسبعين kilogram and woman of mass خمسة
+
+268
+00:20:42,150 --> 00:20:46,270
+وخمسين في عندي مرأة ورجل الرجل كتلته خمسة وسبعين
+
+269
+00:20:46,270 --> 00:20:49,450
+kilogram و المرأة كتلتها خمسة وخمسين kilogram
+
+270
+00:20:49,450 --> 00:20:53,850
+stand .. stand facing each other on ice ring
+
+271
+00:20:53,850 --> 00:21:00,490
+موجودين على مقابل بعض في عن سطح جليدboth wearing
+
+272
+00:21:00,490 --> 00:21:06,010
+ice skater لابسين طبعا اللي هي الحذاء الخاص بتزلج
+
+273
+00:21:06,010 --> 00:21:10,110
+على إثاء الثلج the woman push the man with
+
+274
+00:21:10,110 --> 00:21:13,610
+horizontal force F بتساوية 85 المرأة و هي ماشية
+
+275
+00:21:13,610 --> 00:21:19,910
+دفعت الرجل أو اصطدمت بالرجل بقوة 85 نيوتن in the
+
+276
+00:21:19,910 --> 00:21:24,280
+positive x axisassuming the ice is frictionless
+
+277
+00:21:24,280 --> 00:21:27,920
+طبعا في ال ice في عندي انا فيش عندي احتكاك معناته
+
+278
+00:21:27,920 --> 00:21:31,400
+frictionless what is the man acceleration الان
+
+279
+00:21:31,400 --> 00:21:35,760
+what is the man acceleration اول حاجة هكتب قانون
+
+280
+00:21:35,760 --> 00:21:38,480
+نيوتن التاني اللي هو ال F بدها تساوي ال M في ايه
+
+281
+00:21:38,480 --> 00:21:42,940
+اذا ال F بدها تساوي ال M في ايه ال F اللي اثرت
+
+282
+00:21:42,940 --> 00:21:46,480
+عليها المرأة على الرجل كانت خمسة و تمانين يعني
+
+283
+00:21:46,480 --> 00:21:50,900
+الخمسة و تمانين الرجل اتأثر بقوة خمسة و تمانين من
+
+284
+00:21:50,900 --> 00:21:56,190
+المرأةال F موجودة اللي هي ال 85 اذا و ال A ال M
+
+285
+00:21:56,190 --> 00:22:02,290
+للرجل 75 اذا ال A لل M ال A لل M لل man للرجل
+
+286
+00:22:02,290 --> 00:22:07,250
+بتساوي ال F 85 على اللي هي ال 75 كتلة الرجل بتطلع
+
+287
+00:22:07,250 --> 00:22:13,850
+1.13 متر في الثانية تربيةالان بيحكيلنا what is the
+
+288
+00:22:13,850 --> 00:22:17,210
+reaction force acting on the woman ال woman أثرت
+
+289
+00:22:17,210 --> 00:22:22,770
+على الرجل بقوة 85 لليمين فالرجل هيدفع للمرأة بقوة
+
+290
+00:22:22,770 --> 00:22:26,830
+مساوية إلها باتجاه اليسار فبيكون قوة ال reaction
+
+291
+00:22:26,830 --> 00:22:32,490
+force من الرجل على المرأة بتساوي ناقص 85 المرأة هي
+
+292
+00:22:32,490 --> 00:22:37,170
+اللي دفعت الرجل بقوة 85 يعني الرجل متأثر بقوة 85
+
+293
+00:22:37,170 --> 00:22:42,950
+لليمينحقيقة الراجل هيرد الضربة للمرأة بقوة ناقص 85
+
+294
+00:22:42,950 --> 00:22:47,530
+إلى اليسار الآن بدي أحسب ال acceleration للمرأة
+
+295
+00:22:47,530 --> 00:22:51,650
+بستخدم قانون Newton F بدها تساوي ال M في A طبعا ال
+
+296
+00:22:51,650 --> 00:22:56,670
+F للمرأة كانت ناقص 85 و ال mass للمرأة 55 إذا ال A
+
+297
+00:22:56,670 --> 00:23:02,450
+لل woman بتساوي ناقص F على M ناقص 85 على 55 بتطلع
+
+298
+00:23:02,450 --> 00:23:07,780
+ناقص 1.55إذا ال acceleration للمرأة هتسيب ..
+
+299
+00:23:07,780 --> 00:23:12,460
+هتساوي ناقص واحد point خمسة خمسة المرأة الجاية ان
+
+300
+00:23:12,460 --> 00:23:16,020
+شاء الله بنستكمل المواضيع القادمة بال ..
+
+301
+00:23:16,020 --> 00:23:17,940
+بالمحاضرات القادمة ان شاء الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NvglVbgEE2Q.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NvglVbgEE2Q.srt
new file mode 100644
index 0000000000000000000000000000000000000000..da1aff1e9801d383ea7751597ed6a2d949de34a6
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NvglVbgEE2Q.srt
@@ -0,0 +1,1189 @@
+1
+00:00:00,000 --> 00:00:05,360
+بسم الله الرحمن الرحيم نستكمل الفصل الثاني بعنوان
+
+2
+00:00:05,360 --> 00:00:09,500
+اللي هي الـ displacement, velocity and acceleration
+
+3
+00:00:09,500 --> 00:00:15,460
+بناخد الـ quiz اللي هو 2-1 زي ما احنا ملاحظين بهذا
+
+4
+00:00:15,460 --> 00:00:22,680
+الشكل لاعب كرة ماشي ورمى الكرة، مشيت مسافة
+
+5
+00:00:22,680 --> 00:00:27,920
+100 yard، الـ yard هذه هي عبارة عن ثلاثة قدم ورجع
+
+6
+00:00:27,920 --> 00:00:32,020
+لنفس المكان، هذا هو الشكل الموضح
+
+7
+00:00:33,560 --> 00:00:40,740
+بالنسبة للاعب الكرة، بالنسبة للاعب الكرة، السؤال
+
+8
+00:00:40,740 --> 00:00:44,800
+choose the path of the football player he runs to
+
+9
+00:00:44,800 --> 00:00:48,720
+within 100 yard, then reverse direction and races back
+
+10
+00:00:48,720 --> 00:00:53,370
+to his initial position، لاعب كرة طبعا رمى الكورة
+
+11
+00:00:53,370 --> 00:00:58,250
+ورجعت لنفس المكان، during this run طبعا خلال
+
+12
+00:00:58,250 --> 00:01:01,890
+المشوار اللي .. طبعا سواء هو رمى الكورة أو رجعت أو
+
+13
+00:01:01,890 --> 00:01:06,410
+هو ماشي مشوار ورجع جري، which took خمسة وعشرين
+
+14
+00:01:06,410 --> 00:01:11,420
+second، أخد زمن قدره خمسة وعشرين ثانية، what is the
+
+15
+00:01:11,420 --> 00:01:14,840
+path length he traveled؟ طالب مني المسار اللي هو
+
+16
+00:01:14,840 --> 00:01:18,720
+ماشيه، طبعا هو ماشي هيك مئة ورجع نفس المكان مئة
+
+17
+00:01:18,720 --> 00:01:23,800
+فمعنى الكلام المسار الفعلي اللي هو ماشيه بيكون مئة
+
+18
+00:01:23,800 --> 00:01:28,620
+زائد مئة، بعد هيك طالب displacement اللي هي الإزاحة
+
+19
+00:01:29,180 --> 00:01:33,260
+طبعا هنمشي مع السؤال، هو ماشي .. ماشي لأخر المشوار
+
+20
+00:01:33,260 --> 00:01:38,020
+من قيمته مئة ورجع مئة، يعني الـ path المشوار الكلي
+
+21
+00:01:38,020 --> 00:01:43,780
+الفعلي هو عبارة عن مئة زائد مئة، بالنسبة لـ طبعا الـ
+
+22
+00:01:43,780 --> 00:01:47,480
+path الفعلي، المشوار الفعلي أو الـ distance المسافة
+
+23
+00:01:47,480 --> 00:01:52,340
+الفعلية هي عبارة عن مئتين yard، بالنسبة للـ yard هذه
+
+24
+00:01:52,340 --> 00:01:57,020
+هي عبارة عن ثلاثة قدم بتساوي ستة وثلاثين انش أو
+
+25
+00:01:57,020 --> 00:02:01,180
+واحد وتسعين point أربعة سانتي، هذه الـ yard، الإزاحة
+
+26
+00:02:01,180 --> 00:02:06,760
+displacement، طبعا الـ .. الـ player هذا اللاعب ماشي
+
+27
+00:02:06,760 --> 00:02:11,720
+.. ماشي لغاية ما وصل مئة ورجع لنفس المكان
+
+28
+00:02:11,720 --> 00:02:15,820
+فالازاحة هي عبارة عن أقصر مسافة بين نقطة البداية و
+
+29
+00:02:15,820 --> 00:02:22,380
+النهاية، فبتكون الإزاحة صفراً، في المطلوب c، مطلوب his
+
+30
+00:02:22,380 --> 00:02:27,620
+average velocity، his average velocity، عبارة عن
+
+31
+00:02:27,620 --> 00:02:32,260
+إزاحة على زمن، بالتالي هتكون zero، الـ average speed
+
+32
+00:02:32,260 --> 00:02:35,040
+هي عبارة عن الـ distance اللي هي المسافة اللي مشيها
+
+33
+00:02:35,040 --> 00:02:39,200
+على الزمن الكلي، بتطلع مئتين على خمسة وعشرين، ثمانية
+
+34
+00:02:39,200 --> 00:02:45,190
+yards per second، graphical interpretation of the
+
+35
+00:02:45,190 --> 00:02:50,750
+velocity، الآن if a car moves along x axis، لو كان
+
+36
+00:02:50,750 --> 00:02:56,010
+عند السيارة بتتحرك من النقطة a للنقطة b ثم للنقطة c
+
+37
+00:02:56,010 --> 00:02:59,630
+we can plot the position، ممكن أنا أرسم الآن حركة
+
+38
+00:02:59,630 --> 00:03:04,350
+السيارة رسم بياني، we can plot the positions of
+
+39
+00:03:04,350 --> 00:03:08,590
+these points، ممكن أرسم أنا مكان هدول النقاط الثلاث
+
+40
+00:03:08,590 --> 00:03:14,390
+كما هو موضح بالشكل، كما هو موضح بالشكل الأول أنا
+
+41
+00:03:14,390 --> 00:03:18,150
+عندي الآن الشكل هذا، الـ graph البياني، علاقة بين x
+
+42
+00:03:18,150 --> 00:03:23,160
+و t، العلاقة بين x و t، والآن أنا عندي سيارة بتتحرك
+
+43
+00:03:23,160 --> 00:03:28,540
+من النقطة A بعدين للنقطة B ثم للنقطة C في هذا
+
+44
+00:03:28,540 --> 00:03:33,780
+المسار، بنلاحظ إيه؟ إنه في هذا الشكل، في الشكل
+
+45
+00:03:33,780 --> 00:03:39,500
+الأولاني، في عندي أنا علاقة طردية، في الشكل الأولاني
+
+46
+00:03:39,500 --> 00:03:45,020
+بيمثل عندي علاقة طردية، يعني في علاقة ثابتة، علاقة
+
+47
+00:03:45,020 --> 00:03:50,700
+ثابتة بين الـ x و الـ t، معنى الكلام Δx على Δ
+
+48
+00:03:50,700 --> 00:03:54,820
+t مقدار ثابت، في هذه الحالة الـ average velocity is
+
+49
+00:03:54,820 --> 00:03:59,160
+always the same and is equal to Δx على Δ
+
+50
+00:03:59,160 --> 00:04:03,160
+t، في هذه الحالة فالـ average velocity هي عبارة عن
+
+51
+00:04:03,160 --> 00:04:07,950
+مقدار ثابت، ممثلة في اللي هي ميل الخط المستقيم كما
+
+52
+00:04:07,950 --> 00:04:12,550
+هو موضح في الشكل، بنحكي أن هذا الجسم أو هذا الـ car
+
+53
+00:04:12,550 --> 00:04:17,570
+تتحرك بـ constant velocity بسرعة ثابتة، لأن Δx
+
+54
+00:04:17,570 --> 00:04:22,670
+على Δt في كل النقاط مقدار ثابت، في الشكل الثاني
+
+55
+00:04:22,670 --> 00:04:27,970
+بنلاحظ أنه الـ cars السيارة مشت من نقطة A لنقطة B
+
+56
+00:04:27,970 --> 00:04:32,650
+ثم C ثم D ثم E، هم A ثم F، في عندي علاقة بين x هذا
+
+57
+00:04:32,650 --> 00:04:40,160
+الخط الرأسي يمثل x والخط الأفقي يمثل t، في هذه
+
+58
+00:04:40,160 --> 00:04:44,200
+الحالة عند إيجاد الـ .. الـ .. the average velocity
+
+59
+00:04:44,200 --> 00:04:48,560
+between any two points، متوسط السرعة الاتجاهية بين
+
+60
+00:04:48,560 --> 00:04:52,520
+نقطتين بتساوي the slope of the blue line
+
+61
+00:04:52,520 --> 00:04:56,720
+connecting the points، يعني لو بدي أنا الـ average
+
+62
+00:04:56,720 --> 00:04:59,760
+velocity بين النقطة a و b وأنا عندي منحنى curve
+
+63
+00:04:59,760 --> 00:05:04,600
+فبروح بوصل a و b، ميل الخط هذا الأزرق هو عبارة عن
+
+64
+00:05:04,600 --> 00:05:08,380
+يمثل الـ average velocity، لو بدي أنا بين a و c
+
+65
+00:05:08,380 --> 00:05:14,700
+فبطبعا أوصل بين النقطتين a و c، وميل الخط هذا يمثل
+
+66
+00:05:14,700 --> 00:05:18,920
+اللي هي السرعة المتوسطة الاتجاهية وهكذا
+
+67
+00:05:22,730 --> 00:05:26,270
+نيجي لتعريف آخر اسمه الـ instantaneous velocity
+
+68
+00:05:26,270 --> 00:05:30,290
+السرعة اللحظية عند أي لحظة، الـ instantaneous
+
+69
+00:05:30,290 --> 00:05:35,290
+velocity، طبعا رمزها V is the limit of the average
+
+70
+00:05:35,290 --> 00:05:39,480
+velocity as the time interval ΔT becomes infinitesimally
+
+71
+00:05:39,480 --> 00:05:44,600
+small، الآن لما أجي أعرف أنا اللي هي السرعة
+
+72
+00:05:44,600 --> 00:05:49,200
+اللحظية هي عبارة عن limit Δx على Δt لما
+
+73
+00:05:49,200 --> 00:05:52,800
+Δt تقول إلى الـ zero، الفترة الزمنية Δt
+
+74
+00:05:52,800 --> 00:05:57,420
+تقول إلى الـ zero، يعني فترة زمنية صغيرة جداً، معنى
+
+75
+00:05:57,420 --> 00:06:01,940
+الكلام هذا أن السرعة اللحظية بدها تساوي مشتقة الـ x
+
+76
+00:06:01,940 --> 00:06:07,070
+بالنسبة للزمن، كمان لو كان عندي أنا منحنى فالسرعة
+
+77
+00:06:07,070 --> 00:06:12,270
+اللحظية هي عبارة عن the slope of the line tangent
+
+78
+00:06:12,270 --> 00:06:16,090
+to the curve at that point، يعني لو كان عندي أنا
+
+79
+00:06:16,090 --> 00:06:21,890
+منحنى وهذا المنحنى بهذا الشكل، المنحنى بهذا الشكل و
+
+80
+00:06:21,890 --> 00:06:26,270
+أريد أن أوجد عند النقطة B اللي هي السرعة الـ
+
+81
+00:06:26,270 --> 00:06:30,390
+instantaneous اللحظية اللحظية اللحظية اللحظية
+
+82
+00:06:30,390 --> 00:06:31,250
+اللحظية اللحظية اللحظية اللحظية اللحظية اللحظية
+
+83
+00:06:31,250 --> 00:06:31,390
+اللحظية اللحظية اللحظية اللحظية اللحظية اللحظية
+
+84
+00:06:31,390 --> 00:06:31,610
+اللحظية اللحظية اللحظية اللحظية اللحظية اللحظية
+
+85
+00:06:31,610 --> 00:06:33,070
+اللحظية اللحظية اللحظية اللحظية اللحظية اللحظية
+
+86
+00:06:33,070 --> 00:06:37,510
+اللحظية اللحظية اللحظية اللحظية اللحظية اللحظية
+
+87
+00:06:37,510 --> 00:06:45,030
+اللحظية اللحظية الـ
+
+88
+00:06:46,200 --> 00:06:50,360
+المتوسطة الاتجاهية، لو كان عندي أنا منحنى بأخد ..
+
+89
+00:06:50,360 --> 00:06:54,640
+بأخد يعني علاقة بين مثلاً نقطتين، بوصل بين النقطتين
+
+90
+00:06:54,640 --> 00:06:57,460
+وبيكون ميل الخط هو عبارة عن السرعة المتجهة
+
+91
+00:06:57,460 --> 00:07:02,200
+الاتجاهية المتوسطة، لكن لو أنا عندي curve وطُلب مني
+
+92
+00:07:02,200 --> 00:07:07,690
+الـ instantaneous velocity بيكون هو اللي هو عند نقطة
+
+93
+00:07:07,690 --> 00:07:10,870
+معينة، هو الميل المماس عند هذه النقطة، فالـ
+
+94
+00:07:10,870 --> 00:07:16,590
+instantaneous speed، برضه هذا تعريف لسرعة القياسية
+
+95
+00:07:16,590 --> 00:07:20,930
+اللحظية، بسميها speed of the object، هي عبارة عن
+
+96
+00:07:20,930 --> 00:07:24,750
+سرعة أي جسم which is a scalar quantity، كمية قياسية
+
+97
+00:07:24,750 --> 00:07:29,290
+زي ما حكينا وهي عبارة عن the magnitude of the
+
+98
+00:07:29,290 --> 00:07:33,110
+instantaneous velocity، هي عبارة عن قيمة السرعة
+
+99
+00:07:33,110 --> 00:07:39,890
+الاتجاهية اللحظية، مثال عندي، احنا train moves slowly
+
+100
+00:07:39,890 --> 00:07:43,370
+along a straight portion of track according to the
+
+101
+00:07:43,370 --> 00:07:48,450
+graph of the position versus time، في عندي طبعاً
+
+102
+00:07:48,450 --> 00:07:53,250
+الشكل هذا، موضح علاقة بين الـ x و t، x على محور y
+
+103
+00:07:53,250 --> 00:07:57,840
+و t على محور x، في عندي train أو قطار أو أي object
+
+104
+00:07:57,840 --> 00:08:02,120
+أو أي شخص ماشي في هذه الحركة من عند الـ zero ماشي
+
+105
+00:08:02,120 --> 00:08:07,720
+لمنطقة A بعدين راح لنقطة B بعدين ماشي لنقطة C من
+
+106
+00:08:07,720 --> 00:08:12,880
+النقطة zero لنقطة A، بلاحظ إنه هو خط مستقيم، يعني
+
+107
+00:08:12,880 --> 00:08:18,180
+Δx على Δt مقدار ثابت، من النقطة A لـ B طبعاً
+
+108
+00:08:18,180 --> 00:08:24,020
+ما تغيرش عندي، ما لهوش ميل هذا الخط، وبالتالي Δx
+
+109
+00:08:24,020 --> 00:08:28,830
+على Δt هيكون صفر، من النقطة B للنقطة C كان
+
+110
+00:08:28,830 --> 00:08:32,350
+عندي curve، مطلوب منها the average velocity of the
+
+111
+00:08:32,350 --> 00:08:36,790
+total trip، الـ average velocity، الـ average velocity
+
+112
+00:08:36,790 --> 00:08:41,250
+هي عبارة عن إزاحة على زمن، عشان أوجد الإزاحة هي
+
+113
+00:08:41,250 --> 00:08:46,110
+أقصر مسافة من نقطة البداية للنهاية، إذا المسافة
+
+114
+00:08:46,110 --> 00:08:51,030
+من A من النقطة zero هنا لـ C هي عبارة عن الـ
+
+115
+00:08:51,030 --> 00:08:55,030
+distance، الـ distance اللي .. اللي هي أقصد الـ ..
+
+116
+00:08:55,030 --> 00:09:00,740
+اللي هي الـ displacement، Δx، Δx على الزمن
+
+117
+00:09:00,740 --> 00:09:06,880
+اللي هو على Δt، بالنسبة لنشوف الحل، أول حاجة
+
+118
+00:09:06,880 --> 00:09:09,940
+طالب مني find the average velocity، الـ average
+
+119
+00:09:09,940 --> 00:09:15,080
+velocity عبارة عن Δx على Δt، Δx زي
+
+120
+00:09:15,080 --> 00:09:20,890
+ما احنا شايفين بواجه ميل الخط، ميل الخط أو أقصر
+
+121
+00:09:20,890 --> 00:09:25,270
+مسافة، المسافة على الـ x-axis من هاللّيهان اللي هي
+
+122
+00:09:25,270 --> 00:09:30,750
+عشرة ناقص صفر، Δx، Δt، اثنان وعشرون ناقص صفر
+
+123
+00:09:30,750 --> 00:09:35,050
+وبالتالي صارت عندي Δx على Δt، عشرة على
+
+124
+00:09:35,050 --> 00:09:39,700
+اثنان وعشرين، في المطلوب b، find the average velocity
+
+125
+00:09:39,700 --> 00:09:44,040
+during the first four seconds of the train motion
+
+126
+00:09:44,040 --> 00:09:49,920
+حكالي أوجد متوسط السرعة الاتجاهية في الفترة
+
+127
+00:09:49,920 --> 00:09:55,520
+الزمنية خلال الأربع ثواني الأولى، يعني من zero
+
+128
+00:09:55,520 --> 00:10:01,240
+لأربعة، بده الـ average velocity، طبعاً طبعاً الـ average
+
+129
+00:10:01,240 --> 00:10:06,060
+من zero للنقطة a عبارة عن خط مستقيم، فعبارة عن
+
+130
+00:10:06,060 --> 00:10:10,440
+Δx على Δt، Δx، أربعة ناقص صفر على
+
+131
+00:10:10,440 --> 00:10:14,240
+أربعة ناقص صفر، يعني أربعة على أربعة بيطلع واحد
+
+132
+00:10:14,240 --> 00:10:18,760
+خلال الفترة الزمنية الأولى كما هو موضح، find the
+
+133
+00:10:18,760 --> 00:10:22,420
+average velocity during the next four seconds، طالب
+
+134
+00:10:22,420 --> 00:10:30,450
+إيجاد اللي هي المتوسط السرعة الاتجاهية خلال الأربع
+
+135
+00:10:30,450 --> 00:10:34,830
+ثواني الثانية، من الأربع إلى الثمانية، اتفقنا أنه طبعاً
+
+136
+00:10:34,830 --> 00:10:38,910
+نوصل احنا من النقطة A لـ B، ميل الخط من A لـ B هو
+
+137
+00:10:38,910 --> 00:10:41,550
+عبارة عن الـ average velocity، بأجد أنه من A لـ B
+
+138
+00:10:41,550 --> 00:10:45,750
+الخط مستقيم وبالتالي Δx على Δt بدها
+
+139
+00:10:45,750 --> 00:10:53,600
+تساوي صفر، في المطلوب الثالث، مطلوب منها نوجد find في
+
+140
+00:10:53,600 --> 00:10:58,060
+C، find the average velocity during the next 4
+
+141
+00:10:58,060 --> 00:11:03,220
+seconds، احنا جبناها هيها 0 على 4، بالنسبة للمطلوب
+
+142
+00:11:03,220 --> 00:11:08,980
+بالنسبة للمطلوب الرابع، find the instantaneous
+
+143
+00:11:08,980 --> 00:11:15,200
+velocity، الـ t بدها تساوي 2، عند t بدها تساوي 2 هيها
+
+144
+00:11:16,940 --> 00:11:20,280
+بقى إن t بدها تساوي اثنين، فـ x بدها تساوي اثنين
+
+145
+00:11:20,280 --> 00:11:24,180
+فبيكون إن اثنين على اثنين بدها تساوي واحد، هو عبارة
+
+146
+00:11:24,180 --> 00:11:29,360
+عن ميل الخط، بده يساوي واحد في المنطقة .. في
+
+147
+00:11:29,360 --> 00:11:34,590
+المنطقة عند B، find the average during the next four
+
+148
+00:11:34,590 --> 00:11:41,490
+seconds، كانت طلعت أربعة في المنطقة B، لو أنا أوجدت
+
+149
+00:11:41,490 --> 00:11:45,590
+الـ instantaneous velocity عند المنطقة B أو عند
+
+150
+00:11:45,590 --> 00:11:50,470
+النقطة B بتكون هو ميل المماس للنقطة عند النقطة B
+
+151
+00:11:50,470 --> 00:11:53,570
+ميل المماس هو النقطة هذه من هنا لهنا، وبتكون هي
+
+152
+00:11:53,570 --> 00:11:57,530
+المسافة هذه على هذه المسافة، اللي هي Δx على
+
+153
+00:11:57,530 --> 00:12:01,840
+Δt، هذه بيسموها اللي هي الـ instantaneous عند
+
+154
+00:12:01,840 --> 00:12:08,060
+نقطة معينة، اللي هي النقطة B، زي ما هو موضح أيضاً في
+
+155
+00:12:08,060 --> 00:12:14,140
+هذا السؤال، find the instantaneous velocity at t
+
+156
+00:12:14,140 --> 00:12:18,080
+بدها تساوي تسعة، find the instantaneous velocity
+
+157
+00:12:18,080 --> 00:12:23,680
+at t بدها تساوي تسعة، at t بدها تساوي تسعة، هي t
+
+158
+00:12:23,680 --> 00:12:27,610
+بدها تساوي تسعة، عند المنطقة هذه اللي هو ميل المماس
+
+159
+00:12:27,610 --> 00:12:31,030
+عند هذه النقطة، ميل المماس عند هذه النقطة بأجيب ميل
+
+160
+00:12:31,030 --> 00:12:35,210
+المماس اللي هي عبارة عن المسافة هذه على هذه أو بنفع
+
+161
+00:12:35,210 --> 00:12:39,270
+المسافة من هذا الّيهان، أو بنفع اللي هي تسعة على هذا
+
+162
+00:12:39,270 --> 00:12:42,810
+المقدار إيه؟ بأوجد الـ instantaneous اللي هي عبارة
+
+163
+00:12:42,810 --> 00:12:46,750
+عن ميل المماس عند هذه النقطة، كان عندي أربعة ونصف
+
+164
+00:12:46,750 --> 00:12:49,750
+ناقص صفر وتسعة ناقص ثلاثة بتطلع point سبعة خمس
+
+165
+00:12:49,750 --> 00:12:53,320
+متر في الثانية، هيك احنا اتعرفنا على الـ average
+
+166
+00:12:53,320 --> 00:12:58,920
+velocity والـ instantaneous velocity واللي هي الـ
+
+167
+00:12:58,920 --> 00:13:03,180
+average speed والـ instantaneous speed، نيجي لتعريف
+
+168
+00:13:03,180 --> 00:13:08,140
+آخر اسمه الـ acceleration، هي التسارع، التسارع طبعاً هي
+
+169
+00:13:08,140 --> 00:13:12,540
+عبارة عن معدل تغير السرعة بالنسبة للزمن، بسميه
+
+170
+00:13:12,540 --> 00:13:16,520
+تسارع، معدل تغير السرعة على الزمن هو تسارع، يعني
+
+171
+00:13:16,520 --> 00:13:22,180
+Δv على Δt، بسميها الـ average acceleration
+
+172
+00:13:22,180 --> 00:13:25,580
+الـ average acceleration هي عبارة عن التغير في
+
+173
+00:13:25,580 --> 00:13:30,480
+السرعة على التغير في الزمن، لو أنت السيارة ماشية على
+
+174
+00:13:30,480 --> 00:13:36,600
+خط سريع بالشكل هذا، السيارة ماشية طبعاً لما t بتساوي
+
+1
+
+223
+00:17:25,230 --> 00:17:30,790
+change بدي أفرض أنه سرقة السيارة بدأت من ناقص عشرة
+
+224
+00:17:30,790 --> 00:17:35,230
+متر في الثانية إلى ناقص عشرين in a time interval of
+
+225
+00:17:35,230 --> 00:17:39,700
+اثنين في فترة زمنية اثنين، الـ minus sign هذه
+
+226
+00:17:39,700 --> 00:17:43,740
+الإشارة السالبة تدل indicates that the velocities
+
+227
+00:17:43,740 --> 00:17:47,040
+of the car are in the negative x direction الإشارة
+
+228
+00:17:47,040 --> 00:17:51,520
+السالبة معناها أن السيارة ماشية باتجاه x السالب
+
+229
+00:17:52,370 --> 00:17:55,710
+they don't mean that the car is slowing down هذا
+
+230
+00:17:55,710 --> 00:18:00,270
+مش معناه أن السيارة تتباطأ، معناها أن السيارة
+
+231
+00:18:00,270 --> 00:18:05,150
+تتحرك في اتجاه X السالب the average acceleration
+
+232
+00:18:05,150 --> 00:18:08,090
+of the car في هذه الحالة، الـ average acceleration
+
+233
+00:18:08,090 --> 00:18:12,850
+of the car، طبعًا النهائية ناقص 20 ناقص الابتدائية
+
+234
+00:18:12,850 --> 00:18:18,470
+ناقص 10، هيصير عندي ناقص 20 زائد 10 على 2 ناقص 5
+
+235
+00:18:18,470 --> 00:18:21,910
+متر في الثانية تربيع، التسارع الـ average
+
+236
+00:18:21,910 --> 00:18:25,810
+acceleration، صار عندنا ناقص خمسة متر في الثانية
+
+237
+00:18:25,810 --> 00:18:29,430
+تربيع، الآن الإشارة السالبة the minus sign
+
+238
+00:18:29,430 --> 00:18:33,450
+indicates that تدل على أن الـ acceleration متجه
+
+239
+00:18:33,450 --> 00:18:36,810
+اللي هو التسارع is also in the negative x
+
+240
+00:18:36,810 --> 00:18:42,980
+direction، متجه التسارع باتجاه محور X السالب، والـ
+
+241
+00:18:42,980 --> 00:18:45,580
+positive and negative acceleration specify
+
+242
+00:18:45,580 --> 00:18:49,300
+directions relative to the chosen axis, not
+
+243
+00:18:49,300 --> 00:18:53,500
+speeding up or slowing down، معنى الكلام لو طلعت
+
+244
+00:18:53,500 --> 00:18:59,820
+عندي تسارع سالب أو موجب، هذا يدل على اتجاه X الموجب
+
+245
+00:18:59,820 --> 00:19:05,480
+أو اتجاه X السالب، ولا يعني أن الجسم يتسارع أو
+
+246
+00:19:05,480 --> 00:19:10,540
+يتباطأ، this term speeding up, the term speeding up
+
+247
+00:19:10,540 --> 00:19:19,140
+or slowing، يعني لو أنا عندي، أنا يعني مثلًا أنّه أنّه
+
+248
+00:19:19,140 --> 00:19:23,060
+الجسم يتسارع أو يتباطأ، هذا معنى الكلام، refer to an
+
+249
+00:19:23,060 --> 00:19:28,890
+increase، معناها أنه هناك زيادة أو نقصان في قيمة
+
+250
+00:19:28,890 --> 00:19:32,590
+السرعة، اللي هي الـ speed، سواء كان لو كانت to
+
+251
+00:19:32,590 --> 00:19:37,250
+increase، بحكي عنه speeding، لو كان decrease بكون
+
+252
+00:19:37,250 --> 00:19:40,610
+عندي slowing، هذا معناه الكلام، respectively، يعني
+
+253
+00:19:40,610 --> 00:19:46,090
+على التوالي، وبالتالي لو كان عندي أنا الجسم طالع
+
+254
+00:19:46,090 --> 00:19:50,710
+التسارع سالب، معناه الكلام أن الجسم باتجاه… ماشي
+
+255
+00:19:50,710 --> 00:19:54,570
+باتجاه… يعني أن الجسم، decrease، سرعته بتقل في
+
+256
+00:19:54,570 --> 00:19:58,270
+اتجاه… أو هو ماشي باتجاه الـ X اللي هي السالبة، لو
+
+257
+00:19:58,270 --> 00:20:04,560
+كانت موجبة معناته الجسم سرعته بتزيد، نجلا هذا الـ
+
+258
+00:20:04,560 --> 00:20:11,340
+quiz، true or false، الآن، مين من الجمل التالية يعني
+
+259
+00:20:11,340 --> 00:20:16,660
+صحيحة، ومين من الجمل خاطئة، الجملة الأولى، a car
+
+260
+00:20:16,660 --> 00:20:19,860
+must always have an acceleration in the same
+
+261
+00:20:19,860 --> 00:20:24,040
+direction as its velocity، السؤال بيحكي أن السيارة
+
+262
+00:20:25,090 --> 00:20:29,910
+must always have، لازم لازم تكون الـ acceleration
+
+263
+00:20:29,910 --> 00:20:36,870
+بنفس اتجاه السرعة، يعني هي خاطئة، لأن كلمة always
+
+264
+00:20:36,870 --> 00:20:41,290
+يعني أنه… أنه يجب، طبعًا هذا ممكن موجب، ممكن سالب
+
+265
+00:20:41,950 --> 00:20:46,750
+Number b، it's possible، من الممكن أو من المحتمل for
+
+266
+00:20:46,750 --> 00:20:50,290
+a slowing car to have positive acceleration، صحيحة، من
+
+267
+00:20:50,290 --> 00:20:53,690
+المحتمل يكون عند السيارة تتباطأ، و يكون لها positive
+
+268
+00:20:53,690 --> 00:20:58,510
+acceleration، احتمال ممكن بتصير، Number c، an object
+
+269
+00:20:58,510 --> 00:21:04,390
+with constant non-zero acceleration، جسم له تسارع
+
+270
+00:21:04,390 --> 00:21:09,270
+ثابت لا يساوي zero، can never stop and remain at
+
+271
+00:21:09,270 --> 00:21:15,490
+rest، لا يمكن أن تقف وتظل واقفة، وبعد هيك، and remain
+
+272
+00:21:15,490 --> 00:21:20,890
+at rest، يعني ممكن هي إذا كانت، can never stop، هذه
+
+273
+00:21:20,890 --> 00:21:24,390
+خاطئة، لكن can never stop and remain at rest، هذه
+
+274
+00:21:24,390 --> 00:21:31,540
+جملة صحيحة، الـ Instantaneous Acceleration اللي هي A
+
+275
+00:21:31,540 --> 00:21:38,120
+عبارة عن اللي هي مشتقة الـ V بالنسبة لـ T، طبعًا هذا
+
+276
+00:21:38,120 --> 00:21:42,560
+القانون، limit Δ V على Δ T، لما Δ T تقول إلى الـ Zero
+
+277
+00:21:42,560 --> 00:21:46,300
+بيسموها، هي عبارة عن السرعة اللحظية، أو إذا جاني
+
+278
+00:21:46,300 --> 00:21:53,280
+معادلة، هي عبارة عن مشتقة السرعة بالنسبة للزمن، وحدة
+
+279
+00:21:53,280 --> 00:21:56,540
+الـ Instantaneous Acceleration، تسارع اللحظة عند أي
+
+280
+00:21:56,540 --> 00:22:01,950
+لحظة، اللي هو في النظام الدولي بده يساوي متر في
+
+281
+00:22:01,950 --> 00:22:06,990
+الثانية تربيع، بيساوي متر في الثانية تربيع، بالنسبة
+
+282
+00:22:06,990 --> 00:22:11,850
+للشكل… بالنسبة للشكل اللي هي اثنين تسعة، زي ما
+
+283
+00:22:11,850 --> 00:22:16,730
+احنا شايفين، هذا الشكل، في عندي سيارة بتتحرك بـ
+
+284
+00:22:16,730 --> 00:22:21,350
+different velocity، بتتحرك بسرعات مختلفة، من النقطة
+
+285
+00:22:21,350 --> 00:22:24,810
+B، كانت عندي أنا لما بدأت أمشي من عند B، كانت T
+
+286
+00:22:24,810 --> 00:22:30,050
+initial، كانت سرعتها V initial، لما وصلت للمنطقة Q
+
+287
+00:22:30,050 --> 00:22:37,790
+كانت T final و V final، هذا المثال بيحكيه لأنه
+
+288
+00:22:37,790 --> 00:22:44,300
+في هذا الشكل، الـ velocity vs time graph plots the
+
+289
+00:22:44,300 --> 00:22:47,540
+velocity of an object against time، في عندي علاقة
+
+290
+00:22:47,540 --> 00:22:52,580
+بالشكل، طبعًا اللي القادم شكل 2-9، علاقة بين اللي هي
+
+291
+00:22:52,580 --> 00:22:57,140
+الـ velocity و الـ time، الـ velocity باتجاه الـ y axis
+
+292
+00:22:57,140 --> 00:23:00,720
+و الـ time بالـ x axis، the average acceleration of
+
+293
+00:23:00,720 --> 00:23:05,180
+the car between two times t initial or t final can
+
+294
+00:23:05,180 --> 00:23:08,500
+be found by determining the slope of the line
+
+295
+00:23:08,830 --> 00:23:14,410
+joining point P and Q، لو أنا جيت للرسمة هذه
+
+296
+00:23:14,410 --> 00:23:19,290
+الموضحة بالشكل، بلاحظ أني عندي علاقة بين الـ V و
+
+297
+00:23:19,290 --> 00:23:24,090
+الـ T، عندي أنا نقطة P، نقطة البداية، عند النقطة P في
+
+298
+00:23:24,090 --> 00:23:28,630
+عندي T initial و V initial، عند النقطة Q في عندي T
+
+299
+00:23:28,630 --> 00:23:35,150
+final و V final، لو بدي أوجد أنا الـ V، الـ average
+
+300
+00:23:35,150 --> 00:23:39,030
+acceleration، الـ average acceleration، احنا بروح
+
+301
+00:23:39,030 --> 00:23:43,250
+بنوصل اللي هي النقطة الـ initial و الـ final بخط
+
+302
+00:23:43,250 --> 00:23:48,170
+مستقيم اللي هو اللون الأزرق، و بتكون ميل المماس…
+
+303
+00:23:48,170 --> 00:23:51,830
+ميل الخط هذا الأزرق هو عبارة عن الـ average
+
+304
+00:23:51,830 --> 00:23:55,950
+acceleration، يعني delta V على delta T هو الـ
+
+305
+00:23:55,950 --> 00:23:58,330
+average acceleration، أو ميل الخط هذا اللي باللون
+
+306
+00:23:58,330 --> 00:24:03,250
+الأزرق، لو طلب مني الـ instantaneous acceleration عند
+
+307
+00:24:03,250 --> 00:24:09,390
+النقطة Q، عند النقطة Q، فبروح بعمل ميل المماس عند
+
+308
+00:24:09,390 --> 00:24:12,990
+هذه النقطة، بأخذ مماس، وبأخذ ميل المماس اللي هو
+
+309
+00:24:12,990 --> 00:24:17,990
+اللون الأخضر، هو عبارة عن ميل المماس، هي عبارة عن الـ
+
+310
+00:24:17,990 --> 00:24:21,830
+instantaneous acceleration
+
+311
+00:24:23,410 --> 00:24:27,250
+الآن، الـ slope of the blue line connecting، يعني
+
+312
+00:24:27,250 --> 00:24:33,550
+ميل الخط الأزرق بين B و Q، ميل الخط الأزرق بين B و Q
+
+313
+00:24:33,550 --> 00:24:39,970
+هذا هو يعتبر الـ average acceleration، وكمان اللي هو
+
+314
+00:24:39,970 --> 00:24:43,810
+the slope of the green line، ميل الخط الأخضر اللي
+
+315
+00:24:43,810 --> 00:24:47,170
+هو عبارة عن ميل المماس عند النقطة Q، تعتبر
+
+316
+00:24:47,170 --> 00:24:51,110
+instantaneous acceleration، يعني عند إيجاد الـ
+
+317
+00:24:51,110 --> 00:24:55,290
+average acceleration، بأوصل نقطة البداية والنهاية
+
+318
+00:24:55,290 --> 00:24:59,740
+بخّط، ميل الخط هذا هو يعتبر الـ average acceleration
+
+319
+00:24:59,740 --> 00:25:05,320
+لو كان عندي منحنى، وحدد نقطة معينة، وطلب ميل المماس
+
+320
+00:25:05,320 --> 00:25:09,520
+عند هذه النقطة، بأخذ ميل المماس عند هذه النقطة، في
+
+321
+00:25:09,520 --> 00:25:13,620
+هذه الحالة، يساوي اللي هي الـ instantaneous
+
+322
+00:25:13,620 --> 00:25:17,660
+acceleration
+
+323
+00:25:17,660 --> 00:25:21,000
+in the special case where the velocity versus time
+
+324
+00:25:21,000 --> 00:25:23,480
+graph of an object motion is a straight line
+
+325
+00:25:26,910 --> 00:25:31,230
+في حالة خاصة، عندما يكون الموقع متسلسل على أي موقع
+
+326
+00:25:31,230 --> 00:25:31,830
+متسلسل على أي موقع متسلسل على أي موقع متسلسل على
+
+327
+00:25:31,830 --> 00:25:32,070
+أي موقع متسلسل على أي موقع متسلسل على
+
+328
+00:25:32,070 --> 00:25:33,070
+أي موقع متسلسل على أي موقع متسلسل على أي موقع
+
+329
+00:25:33,070 --> 00:25:34,270
+متسلسل على أي موقع متسلسل على أي موقع متسلسل على
+
+330
+00:25:34,270 --> 00:25:34,910
+أي موقع متسلسل على أي موقع متسلسل على أي موقع
+
+331
+00:25:34,910 --> 00:25:38,850
+متسلسل على أي موقع متسلسل على أي موقع متسلسل على
+
+332
+00:25:38,850 --> 00:25:43,510
+أي موقع، في حالة خاصة لما تكون السرعة، يعني أنا عندي
+
+333
+00:25:43,510 --> 00:25:47,830
+علاقة بين السرعة و الـ time، يعني a curve بين السرعة
+
+334
+00:25:47,830 --> 00:25:51,750
+الـ velocity و الـ time لأي جسم أو لأي حركة جسم
+
+335
+00:25:51,750 --> 00:25:56,810
+بتحرك بخط مستقيم، لو الجسم بتحرك بخط مستقيم أو عندي
+
+336
+00:25:56,810 --> 00:26:02,840
+أنا علاقة بين الـ V و الـ T، أو منحنى يعني curve بين
+
+337
+00:26:02,840 --> 00:26:06,860
+الـ V و الـ T، والـ curve هذا يمثل خط مستقيم، في هذه
+
+338
+00:26:06,860 --> 00:26:11,080
+الحالة، لأن instantaneous acceleration بتساوي الـ
+
+339
+00:26:11,080 --> 00:26:14,580
+average acceleration، هاي حالة خاصة، لو كان عندي أنا
+
+340
+00:26:14,580 --> 00:26:20,920
+علاقة أو curve، يعني شكل بياني بين الـ V و الـ T و
+
+341
+00:26:20,920 --> 00:26:24,560
+كانت العلاقة بين الـ V و الـ T علاقة خط مستقيم، في
+
+342
+00:26:24,560 --> 00:26:28,100
+هذه الحالة، الـ instantaneous acceleration، تسارع
+
+343
+00:26:28,100 --> 00:26:33,440
+اللحظي، بيساوي التسارع اللي… اللي هو اللي… اللي هي الـ
+
+344
+00:26:33,440 --> 00:26:38,080
+average acceleration، اللي هي التسارع المتوسط
+
+345
+00:26:38,080 --> 00:26:41,380
+التسارع اللحظي بيساوي التسارع المتوسط
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NvglVbgEE2Q_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NvglVbgEE2Q_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..1c13a650af0a25880b607dbd6b386f3beb982429
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/NvglVbgEE2Q_raw.json
@@ -0,0 +1 @@
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عندي أنا علاقة ترضية في الشكل الأولاني بيمثل عندي علاقة ترضية يعني في علاقة ثابتة علاقة ثابتة بين ال X و ال T", "tokens": [6027, 3615, 15040, 28671, 49374, 1783, 4032, 314, 4032, 6024, 48506, 41850, 18871, 16254, 8608, 1829, 9640, 3660, 39894, 2655, 5016, 31747, 9154, 28239, 47432, 3660, 316, 39182, 9957, 24976, 1863, 47432, 3660, 363, 38637, 2304, 24976, 1863, 47432, 3660, 383, 8978, 23758, 9673, 3794, 9640, 44945, 15040, 5016, 19913, 1975, 1829, 3224, 16472, 3224, 8978, 23758, 25124, 28820, 8978, 25124, 28820, 16247, 12610, 7649, 1829, 8978, 18871, 16254, 41850, 11203, 995, 28671, 6055, 43042, 10632, 8978, 25124, 28820, 16247, 12610, 7649, 1829, 4724, 32640, 12984, 1211, 18871, 16254, 11203, 995, 28671, 6055, 43042, 10632, 37495, 22653, 8978, 11203, 995, 28671, 38637, 16758, 2655, 3660, 11203, 995, 28671, 38637, 16758, 2655, 3660, 49374, 2423, 1783, 4032, 2423, 314], "avg_logprob": -0.11626838059986339, "compression_ratio": 2.27, "no_speech_prob": 8.940696716308594e-07, "words": 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{"start": 241.86, "end": 242.62, "word": " velocity", "probability": 0.833984375}, {"start": 242.62, "end": 242.8, "word": " هي", "probability": 0.91650390625}, {"start": 242.8, "end": 243.02, "word": " عبارة", "probability": 0.9136962890625}, {"start": 243.02, "end": 243.16, "word": " عن", "probability": 0.99267578125}, {"start": 243.16, "end": 243.5, "word": " مقدار", "probability": 0.9860026041666666}, {"start": 243.5, "end": 243.86, "word": " ثابت", "probability": 0.9943033854166666}, {"start": 243.86, "end": 244.92, "word": " ممثلة", "probability": 0.890869140625}, {"start": 244.92, "end": 245.28, "word": " فيه", "probability": 0.851806640625}], "temperature": 1.0}, {"id": 13, "seek": 26064, "start": 245.55, "end": 260.65, "text": "اللي هي ميل الخط المستقيم كما هو مضح في الشكل بنحكي أن هذا الجسم أو هذا الـ car تتحرك ب constant velocity بسرعة ثابتة لأن Delta X على Delta T في كل النقاط مقدار ثابت", "tokens": [6027, 20292, 39896, 3714, 26895, 33962, 9566, 9673, 14851, 4587, 32640, 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"word": " يعني", "probability": 0.907470703125}, {"start": 866.71, "end": 867.19, "word": " V", "probability": 0.9619140625}, {"start": 867.19, "end": 867.75, "word": " final", "probability": 0.81396484375}, {"start": 867.75, "end": 868.21, "word": " ناقص", "probability": 0.98681640625}, {"start": 868.21, "end": 868.37, "word": " V", "probability": 0.96826171875}, {"start": 868.37, "end": 868.85, "word": " initial", "probability": 0.908203125}, {"start": 868.85, "end": 869.65, "word": " على", "probability": 0.84814453125}, {"start": 869.65, "end": 870.13, "word": " T", "probability": 0.97900390625}, {"start": 870.13, "end": 870.67, "word": " final", "probability": 0.943359375}, {"start": 870.67, "end": 871.37, "word": " ناقص", "probability": 0.9945068359375}, {"start": 871.37, "end": 871.71, "word": " T", "probability": 0.9892578125}, {"start": 871.71, "end": 872.17, "word": " initial", "probability": 0.9462890625}, {"start": 872.17, "end": 872.39, "word": " وهي", "probability": 0.685302734375}, {"start": 872.39, "end": 872.67, "word": " عبارة", "probability": 0.99560546875}, {"start": 872.67, "end": 873.21, "word": " عن", "probability": 0.99755859375}, {"start": 873.21, "end": 874.25, "word": " متوسط", "probability": 0.9737955729166666}, {"start": 874.25, "end": 875.03, "word": " التسارع", "probability": 0.9849853515625}], "temperature": 1.0}, {"id": 42, "seek": 90227, "start": 875.59, "end": 902.27, "text": "الاتجاه طبعا طبعا ال .. الوحدة اللي هي التسارع بالنظام ال system international الدولي هو عبارة عن متر في الثانية تربيع متر في الثانية تربيع for example بناخد مثال suppose the car shown in the figures to 2.8 accelerate from an initial velocity بفرض في عند سيارة بتتحرك بسرعة ابتدائية V initial عشرة", "tokens": [6027, 9307, 7435, 40294, 23032, 3555, 3615, 995, 23032, 3555, 3615, 995, 2423, 4386, 2423, 2407, 24401, 3660, 13672, 1829, 39896, 16712, 3794, 9640, 3615, 20666, 1863, 19913, 10943, 2423, 1185, 5058, 32748, 12610, 1829, 31439, 6225, 3555, 9640, 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878.07, "end": 878.81, "word": " الوحدة", "probability": 0.875732421875}, {"start": 878.81, "end": 879.07, "word": " اللي", "probability": 0.893310546875}, {"start": 879.07, "end": 879.41, "word": " هي", "probability": 0.8955078125}, {"start": 879.41, "end": 880.27, "word": " التسارع", "probability": 0.9840087890625}, {"start": 880.27, "end": 881.11, "word": " بالنظام", "probability": 0.889404296875}, {"start": 881.11, "end": 881.31, "word": " ال", "probability": 0.87255859375}, {"start": 881.31, "end": 881.59, "word": " system", "probability": 0.9140625}, {"start": 881.59, "end": 882.17, "word": " international", "probability": 0.73974609375}, {"start": 882.17, "end": 882.97, "word": " الدولي", "probability": 0.93212890625}, {"start": 882.97, "end": 883.41, "word": " هو", "probability": 0.97802734375}, {"start": 883.41, "end": 883.81, "word": " عبارة", "probability": 0.96142578125}, {"start": 883.81, "end": 883.97, "word": " عن", "probability": 0.97412109375}, {"start": 883.97, "end": 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{"start": 896.17, "end": 896.51, "word": " initial", "probability": 0.83544921875}, {"start": 896.51, "end": 897.01, "word": " velocity", "probability": 0.76904296875}, {"start": 897.01, "end": 897.77, "word": " بفرض", "probability": 0.7867838541666666}, {"start": 897.77, "end": 897.91, "word": " في", "probability": 0.91259765625}, {"start": 897.91, "end": 898.09, "word": " عند", "probability": 0.93896484375}, {"start": 898.09, "end": 898.67, "word": " سيارة", "probability": 0.984130859375}, {"start": 898.67, "end": 899.67, "word": " بتتحرك", "probability": 0.942626953125}, {"start": 899.67, "end": 900.49, "word": " بسرعة", "probability": 0.96484375}, {"start": 900.49, "end": 901.07, "word": " ابتدائية", "probability": 0.92939453125}, {"start": 901.07, "end": 901.25, "word": " V", "probability": 0.5966796875}, {"start": 901.25, "end": 901.65, "word": " initial", "probability": 0.73193359375}, {"start": 901.65, "end": 902.27, "word": " عشرة", "probability": 0.8556315104166666}], "temperature": 1.0}, {"id": 43, "seek": 91738, "start": 902.96, "end": 917.38, "text": "متر في الثانية و Vfinal كانت عشرين متر في الثانية في فترة زمنية قدرها اتنين الفترة الزمنية القدرها اتنين ممكن تكون T initial صفر و T final اتنين او فترة زمنية Delta T بتساوي اتنين", "tokens": [2304, 2655, 2288, 8978, 6024, 104, 7649, 10632, 4032, 691, 69, 2071, 25961, 2655, 6225, 46309, 9957, 44650, 2288, 8978, 6024, 104, 7649, 10632, 8978, 6156, 2655, 25720, 30767, 27842, 10632, 12174, 3215, 2288, 11296, 1975, 2655, 1863, 9957, 27188, 2655, 25720, 6024, 110, 27842, 10632, 25062, 3215, 2288, 11296, 1975, 2655, 1863, 9957, 3714, 43020, 6055, 30544, 314, 5883, 20328, 5172, 2288, 4032, 314, 2572, 1975, 2655, 1863, 9957, 1975, 2407, 6156, 2655, 25720, 30767, 27842, 10632, 18183, 314, 39894, 3794, 995, 45865, 1975, 2655, 1863, 9957], "avg_logprob": -0.13737710004442194, "compression_ratio": 1.8860759493670887, "no_speech_prob": 6.973743438720703e-06, "words": [{"start": 902.96, "end": 903.84, "word": 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راح احل انه اللي ال average acceleration Delta V على Delta T V final كانت عشرين و V initial عشرة و Delta T كانت اتنين فالتسارع طلع لموجة ب X موجة بخمسة متر في الثانية تربيع", "tokens": [9566, 3555, 3615, 995, 21136, 2288, 34268, 9957, 1293, 7806, 1088, 366, 3030, 281, 264, 558, 23032, 3555, 3615, 995, 21136, 2288, 34268, 9957, 25961, 14407, 8717, 39319, 10632, 2423, 32640, 9957, 12602, 39319, 1975, 5016, 1211, 16472, 3224, 13672, 1829, 2423, 4274, 17162, 18183, 691, 15844, 18183, 314, 691, 2572, 25961, 2655, 6225, 46309, 9957, 4032, 691, 5883, 6225, 8592, 25720, 4032, 18183, 314, 25961, 2655, 1975, 2655, 1863, 9957, 6156, 6027, 2655, 3794, 9640, 3615, 23032, 1211, 3615, 32767, 29245, 3660, 4724, 1783, 3714, 29245, 3660, 4724, 9778, 2304, 3794, 3660, 44650, 2288, 8978, 6024, 104, 7649, 10632, 6055, 2288, 21292, 3615], "avg_logprob": -0.14925595351627896, "compression_ratio": 1.6594827586206897, "no_speech_prob": 1.7881393432617188e-07, "words": [{"start": 918.03, "end": 918.85, "word": 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"word": " direction", "probability": 0.98095703125}], "temperature": 1.0}, {"id": 48, "seek": 103827, "start": 1016.99, "end": 1038.27, "text": "معنى الكلام قيمة السرعة اللى هى ال speed تزداد مع الوقت لما يكون الجسم بسرعته و تسارعه عكس بعض فمعنى الكلام او باتجاهين متعاكسين قيمة ال speed تقل مع الزمن قيمة ال speed اللى هى قيمة السرعة تقل مع الزمن", "tokens": [2304, 3615, 1863, 7578, 2423, 28820, 10943, 12174, 32640, 3660, 21136, 2288, 27884, 13672, 7578, 8032, 7578, 2423, 3073, 6055, 11622, 3215, 18513, 20449, 2423, 30543, 2655, 5296, 15042, 7251, 30544, 25724, 38251, 4724, 3794, 2288, 34268, 3224, 4032, 6055, 3794, 9640, 3615, 3224, 6225, 4117, 3794, 45030, 11242, 6156, 2304, 3615, 1863, 7578, 2423, 28820, 10943, 1975, 2407, 4724, 9307, 7435, 40294, 9957, 44650, 3615, 995, 4117, 3794, 9957, 12174, 32640, 3660, 2423, 3073, 6055, 4587, 1211, 20449, 6024, 110, 27842, 12174, 32640, 3660, 2423, 3073, 13672, 7578, 8032, 7578, 12174, 32640, 3660, 21136, 2288, 27884, 6055, 4587, 1211, 20449, 6024, 110, 27842], "avg_logprob": -0.053906250851494926, "compression_ratio": 2.147239263803681, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 1016.99, "end": 1017.35, "word": "معنى", "probability": 0.96044921875}, {"start": 1017.35, "end": 1018.01, "word": " الكلام", "probability": 0.9454752604166666}, {"start": 1018.01, "end": 1018.81, "word": " قيمة", "probability": 0.9851888020833334}, {"start": 1018.81, "end": 1019.35, "word": " السرعة", "probability": 0.9695638020833334}, {"start": 1019.35, "end": 1019.51, "word": " اللى", "probability": 0.823974609375}, {"start": 1019.51, "end": 1019.65, "word": " هى", "probability": 0.89990234375}, {"start": 1019.65, "end": 1019.75, "word": " ال", "probability": 0.87939453125}, {"start": 1019.75, "end": 1020.21, "word": " speed", "probability": 0.87890625}, {"start": 1020.21, "end": 1021.05, "word": " تزداد", "probability": 0.9833984375}, {"start": 1021.05, "end": 1021.23, "word": " مع", "probability": 0.9951171875}, {"start": 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"end": 1030.95, "word": " باتجاهين", "probability": 0.91611328125}, {"start": 1030.95, "end": 1031.79, "word": " متعاكسين", "probability": 0.97705078125}, {"start": 1031.79, "end": 1032.49, "word": " قيمة", "probability": 0.9903971354166666}, {"start": 1032.49, "end": 1032.65, "word": " ال", "probability": 0.96923828125}, {"start": 1032.65, "end": 1033.11, "word": " speed", "probability": 0.99072265625}, {"start": 1033.11, "end": 1034.01, "word": " تقل", "probability": 0.9967447916666666}, {"start": 1034.01, "end": 1034.57, "word": " مع", "probability": 0.99755859375}, {"start": 1034.57, "end": 1035.21, "word": " الزمن", "probability": 0.93994140625}, {"start": 1035.21, "end": 1035.83, "word": " قيمة", "probability": 0.9562174479166666}, {"start": 1035.83, "end": 1035.97, "word": " ال", "probability": 0.9482421875}, {"start": 1035.97, "end": 1036.41, "word": " speed", "probability": 0.9892578125}, {"start": 1036.41, "end": 1036.59, "word": " اللى", "probability": 0.985107421875}, {"start": 1036.59, "end": 1036.71, "word": " هى", "probability": 0.96044921875}, {"start": 1036.71, "end": 1037.05, "word": " قيمة", "probability": 0.9962565104166666}, {"start": 1037.05, "end": 1037.39, "word": " السرعة", "probability": 0.98876953125}, {"start": 1037.39, "end": 1037.75, "word": " تقل", "probability": 0.9973958333333334}, {"start": 1037.75, "end": 1037.91, "word": " مع", "probability": 0.99853515625}, {"start": 1037.91, "end": 1038.27, "word": " الزمن", "probability": 0.9765625}], "temperature": 1.0}, {"id": 49, "seek": 105695, "start": 1038.91, "end": 1056.95, "text": "to clarify this point عشان احنا نوضح هذه النقطة suppose the velocity of the car change بدي افرض انه سرقة السيارة بدت من ناقص عشرة متر في الثانية لناقص عشرين in a time interval of اتنين في فترة زمانية اتنين", "tokens": [1353, 17594, 341, 935, 6225, 8592, 7649, 1975, 5016, 8315, 8717, 2407, 11242, 5016, 29538, 28239, 47432, 3660, 7297, 264, 9269, 295, 264, 1032, 1319, 4724, 16254, 1975, 5172, 43042, 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"word": " نوضح", "probability": 0.988525390625}, {"start": 1042.03, "end": 1042.23, "word": " هذه", "probability": 0.7119140625}, {"start": 1042.23, "end": 1043.13, "word": " النقطة", "probability": 0.9851888020833334}, {"start": 1043.13, "end": 1043.83, "word": " suppose", "probability": 0.8818359375}, {"start": 1043.83, "end": 1044.11, "word": " the", "probability": 0.9052734375}, {"start": 1044.11, "end": 1044.43, "word": " velocity", "probability": 0.93310546875}, {"start": 1044.43, "end": 1044.67, "word": " of", "probability": 0.984375}, {"start": 1044.67, "end": 1044.93, "word": " the", "probability": 0.8896484375}, {"start": 1044.93, "end": 1045.23, "word": " car", "probability": 0.88232421875}, {"start": 1045.23, "end": 1045.75, "word": " change", "probability": 0.442138671875}, {"start": 1045.75, "end": 1046.01, "word": " بدي", "probability": 0.4639892578125}, {"start": 1046.01, "end": 1046.35, "word": " افرض", "probability": 0.8597005208333334}, {"start": 1046.35, "end": 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1053.15, "end": 1053.91, "word": " in", "probability": 0.92724609375}, {"start": 1053.91, "end": 1054.05, "word": " a", "probability": 0.99267578125}, {"start": 1054.05, "end": 1054.29, "word": " time", "probability": 0.89892578125}, {"start": 1054.29, "end": 1054.91, "word": " interval", "probability": 0.974609375}, {"start": 1054.91, "end": 1055.23, "word": " of", "probability": 0.98046875}, {"start": 1055.23, "end": 1055.63, "word": " اتنين", "probability": 0.9178466796875}, {"start": 1055.63, "end": 1055.79, "word": " في", "probability": 0.720703125}, {"start": 1055.79, "end": 1056.09, "word": " فترة", "probability": 0.9934895833333334}, {"start": 1056.09, "end": 1056.61, "word": " زمانية", "probability": 0.868896484375}, {"start": 1056.61, "end": 1056.95, "word": " اتنين", "probability": 0.98388671875}], "temperature": 1.0}, {"id": 50, "seek": 107152, "start": 1058.26, "end": 1071.52, "text": "الـ minus sign هذه الإشارة السالبة تدل indicates that the velocities of the car are in the negative x direction الإشارة السالبة معناها إن السيارة ماشية باتجاه x السالب", "tokens": [6027, 39184, 3175, 1465, 29538, 33688, 8592, 9640, 3660, 21136, 6027, 49401, 6055, 3215, 1211, 16203, 300, 264, 7806, 1088, 295, 264, 1032, 366, 294, 264, 3671, 2031, 3513, 33688, 8592, 9640, 3660, 21136, 6027, 49401, 20449, 8315, 11296, 36145, 21136, 1829, 9640, 3660, 3714, 33599, 10632, 4724, 9307, 7435, 40294, 2031, 21136, 6027, 3555], "avg_logprob": -0.12841797433793545, "compression_ratio": 1.5324675324675325, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 1058.26, "end": 1058.76, "word": "الـ", "probability": 0.4599609375}, {"start": 1058.76, "end": 1059.02, "word": " minus", "probability": 0.7236328125}, {"start": 1059.02, "end": 1059.48, "word": " sign", "probability": 0.90673828125}, {"start": 1059.48, "end": 1059.7, "word": " هذه", "probability": 0.5185546875}, {"start": 1059.7, "end": 1060.14, "word": " الإشارة", "probability": 0.983642578125}, {"start": 1060.14, 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"word": " negative", "probability": 0.916015625}, {"start": 1065.34, "end": 1065.62, "word": " x", "probability": 0.69775390625}, {"start": 1065.62, "end": 1066.16, "word": " direction", "probability": 0.873046875}, {"start": 1066.16, "end": 1067.04, "word": " الإشارة", "probability": 0.9427490234375}, {"start": 1067.04, "end": 1067.62, "word": " السالبة", "probability": 0.9881184895833334}, {"start": 1067.62, "end": 1068.58, "word": " معناها", "probability": 0.9723307291666666}, {"start": 1068.58, "end": 1068.8, "word": " إن", "probability": 0.6181640625}, {"start": 1068.8, "end": 1069.42, "word": " السيارة", "probability": 0.97021484375}, {"start": 1069.42, "end": 1069.82, "word": " ماشية", "probability": 0.9290364583333334}, {"start": 1069.82, "end": 1070.54, "word": " باتجاه", "probability": 0.928955078125}, {"start": 1070.54, "end": 1070.96, "word": " x", "probability": 0.791015625}, {"start": 1070.96, "end": 1071.52, "word": " السالب", "probability": 0.89990234375}], "temperature": 1.0}, {"id": 51, "seek": 109989, "start": 1072.37, "end": 1099.89, "text": "they don't mean that the car is slowing down هذا مش معناه أنه السيارة بتتباطأ معناها أن السيارة بتتحرك في اتجاه X السالب the average acceleration of the car في هذه الحالة ال average acceleration of the car طبعا النهائية ناقص 20 ناقص لابتدائية ناقص 10 هيصير اندي ناقص 20 زائد 10 على 2 ناقص 5 متر في الثانية تربيع", "tokens": [13162, 500, 380, 914, 300, 264, 1032, 307, 26958, 760, 23758, 37893, 20449, 8315, 3224, 14739, 3224, 21136, 1829, 9640, 3660, 39894, 2655, 3555, 41193, 10721, 20449, 8315, 11296, 14739, 21136, 1829, 9640, 3660, 39894, 2655, 5016, 31747, 8978, 1975, 2655, 7435, 40294, 1783, 21136, 6027, 3555, 264, 4274, 17162, 295, 264, 1032, 8978, 29538, 21542, 6027, 3660, 2423, 4274, 17162, 295, 264, 1032, 23032, 3555, 3615, 995, 28239, 3224, 16373, 10632, 8717, 995, 4587, 9381, 945, 8717, 995, 4587, 9381, 5296, 16758, 2655, 3215, 16373, 10632, 8717, 995, 4587, 9381, 1266, 39896, 9381, 13546, 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/TRcnjALZO3I.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/TRcnjALZO3I.srt
new file mode 100644
index 0000000000000000000000000000000000000000..77bdaf877d4289bce3c4371dece1b83a98ecf66d
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/TRcnjALZO3I.srt
@@ -0,0 +1,515 @@
+1
+00:00:00,570 --> 00:00:04,710
+بسم الله الرحمن الرحيم. هنبدأ في شرح المحاضرات
+
+2
+00:00:04,710 --> 00:00:08,550
+chapter خمسة بعنوان: الـ energy section الأول
+
+3
+00:00:08,550 --> 00:00:13,570
+work، يعني الشغل، in physics. الـ work is done only if
+
+4
+00:00:13,570 --> 00:00:17,470
+an object is moved through some displacement while
+
+5
+00:00:17,470 --> 00:00:21,670
+a force is applied to it. تعريف الشغل في الفيزياء
+
+6
+00:00:21,670 --> 00:00:27,310
+ممكن أنا أعتبر أنه أي جسم يبذل شغلاً إذا كان ماشياً
+
+7
+00:00:27,310 --> 00:00:31,760
+بإزاحة معينة، اللي هي displacement، بواسطة القوة اللي
+
+8
+00:00:31,760 --> 00:00:35,580
+أنا أعطيتها لهذا الجسم. if either the force or
+
+9
+00:00:35,580 --> 00:00:39,740
+displacement is doubled. لو إحنا ضعفنا القوة أو
+
+10
+00:00:39,740 --> 00:00:43,740
+الإزاحة، معنى الكلام أن الشغل is doubled، الشغل هي
+
+11
+00:00:43,740 --> 00:00:48,120
+... يعني يتضاعف، doubled in both. لو أنا ضعفت الإثنين،
+
+12
+00:00:48,120 --> 00:00:52,780
+معنى الكلام أن الشغل هيصير مضاعف إلى إيه؟ يعني
+
+13
+00:00:52,780 --> 00:00:56,840
+إثنين في إثنين، يعني أربع مرات. تعريف الشغل: the
+
+14
+00:00:56,840 --> 00:01:03,340
+definition for work might be taken as: الـ work
+
+15
+00:01:03,340 --> 00:01:07,740
+بتساوي الـ F في الـ D. الـ work، الـ W، وهذه رمز الشغل، والـ
+
+16
+00:01:07,740 --> 00:01:11,840
+F هي عبارة عن القوة في الإزاحة. الـ F is magnitude
+
+17
+00:01:11,840 --> 00:01:15,380
+of the force. هي عبارة عن قيمة القوة المؤثرة على
+
+18
+00:01:15,380 --> 00:01:19,140
+الجسم، والـ D هي عبارة عن قيمة اللي هي displacement،
+
+19
+00:01:19,140 --> 00:01:25,260
+أو الإزاحة اللي مشيها هذا الجسم، اللي طبعاً اللي
+
+20
+00:01:25,260 --> 00:01:29,760
+معرض لقوة معينة اسمها F. the definition, however,
+
+21
+00:01:29,760 --> 00:01:34,880
+gives only هذا التعريف ممكن يعطينا قيمة الـ
+
+22
+00:01:34,880 --> 00:01:38,700
+magnitude للـ work المبذول on an object when the
+
+23
+00:01:38,700 --> 00:01:42,340
+force is constant and parallel to the displacement.
+
+24
+00:01:42,340 --> 00:01:46,400
+هذا التعريف بيعطيني هذا الـ omega أو الـ W  بساوي F
+
+25
+00:01:46,400 --> 00:01:52,360
+دي، بيعطيني تعريف الشغل المبذول، بتعطيني قيمة هذا
+
+26
+00:01:52,360 --> 00:01:56,600
+الشغل المبذول إذا كانت القوة والإزاحة متوازيتان
+
+27
+00:01:56,870 --> 00:02:00,810
+وبالتالي الزاوية اللي بينهم صفر، فبيكون الشغل أقصى ما
+
+28
+00:02:00,810 --> 00:02:06,610
+يمكن. الشكل التالي بيوضح جسم undergoing
+
+29
+00:02:06,610 --> 00:02:11,970
+displacement. جسم اتعرض لقوة F ومشي إزاحة Delta
+
+30
+00:02:11,970 --> 00:02:17,870
+X في نفس الاتجاه. ممكن إحنا نعرف أنه في هذه الحالة
+
+31
+00:02:17,870 --> 00:02:24,930
+هي الشكل: في عندي أنا جسم، طبعاً، أعطيته قوة F applied
+
+32
+00:02:24,930 --> 00:02:30,190
+فمشي إزاحة Delta X. فمعنى الكلام خلال during the
+
+33
+00:02:30,190 --> 00:02:35,430
+linear displacement along the x-axis، W بتساوي Fx
+
+34
+00:02:35,430 --> 00:02:40,470
+في Delta x. طبعاً هذا الجسم ماشي في الـ x-axis، معناها
+
+35
+00:02:40,470 --> 00:02:43,130
+القوة في اتجاه الـ x، والإزاحة في اتجاه الـ x. إذن
+
+36
+00:02:43,130 --> 00:02:47,920
+هذا الشغل بيكون في اتجاه الـ x-axis. القوة Fx is x
+
+37
+00:02:47,920 --> 00:02:51,540
+component of the F، وDelta x عبارة عن x final
+
+38
+00:02:51,540 --> 00:02:56,620
+ناقص x initial للجسم. وحدة الشغل هي عبارة عن الجول،
+
+39
+00:02:56,620 --> 00:03:01,760
+والجول بيساوي Newton dot meter، نيوتن في متر، و
+
+40
+00:03:01,760 --> 00:03:04,400
+نيوتن هو عبارة عن قوة، اللي هي الـ mass في الـ
+
+41
+00:03:04,400 --> 00:03:07,640
+acceleration، يعني كيلوجرام متر تربيع على second
+
+42
+00:03:07,640 --> 00:03:13,100
+تربيع. كيلوجرام نيوتن، كيلوجرام متر في الثانية تربيع.
+
+43
+00:03:13,100 --> 00:03:16,000
+وفيها نيوتن متر، صار لنا كيلوجرام متر تربيع على second
+
+44
+00:03:16,000 --> 00:03:20,820
+تربيع. إذن الجول عبارة عن نيوتن متر، أو
+
+45
+00:03:20,820 --> 00:03:26,720
+كيلوجرام متر تربيع على الثانية تربيع. باللاحظ: note
+
+46
+00:03:26,720 --> 00:03:31,620
+that in one dimension. باللاحظ في بعد واحد، الإزاحة
+
+47
+00:03:31,620 --> 00:03:36,820
+Delta X عبارة عن vector quantity، كمية متجهة، وDelta
+
+48
+00:03:36,820 --> 00:03:40,920
+x بيساوي x final ناقص x initial، x final ناقص x
+
+49
+00:03:40,920 --> 00:03:45,080
+initial. ممكن تكون موجبة أو سالبة حسب اللي هي قيمة الـ
+
+50
+00:03:45,080 --> 00:03:49,600
+x final والـ x initial. الـ work as defined in
+
+51
+00:03:49,600 --> 00:03:54,180
+equation خمسة إثنين is rigorous of displacement of
+
+52
+00:03:54,180 --> 00:03:58,420
+any object along the x axis while constant force
+
+53
+00:03:58,420 --> 00:04:04,170
+act on it. therefore بناء عليه، طبعاً، إذا كان الجسم
+
+54
+00:04:04,170 --> 00:04:08,390
+يتحرك في one dimension، ممكن يكون x, y أو z. فإذا
+
+55
+00:04:08,390 --> 00:04:13,750
+كان الجسم أنا أعطيته قوة Fx باتجاه الـ x axis، ومشي
+
+56
+00:04:13,750 --> 00:04:18,350
+إزاحة Delta x، في معنى الكلام، وكانت Fx موازية لـ Delta
+
+57
+00:04:18,350 --> 00:04:22,930
+x للإزاحة، إذاً... والإثنين كانت طبعاً موجبة، فالشغل
+
+58
+00:04:22,930 --> 00:04:27,870
+عبارة عن إيش؟ عن موجب. إذا كانوا الإثنين سالبات، فالشغل
+
+59
+00:04:27,870 --> 00:04:32,650
+برضه هيكون موجب. in this case, in which case the
+
+60
+00:04:32,650 --> 00:04:36,990
+discussion as discussed in the next section. الـ
+
+61
+00:04:36,990 --> 00:04:41,050
+work increases the mechanical energy of the object.
+
+62
+00:04:41,050 --> 00:04:46,890
+الشغل increases، بيزيد، بيزود the mechanical energy
+
+63
+00:04:46,890 --> 00:04:50,830
+of the object، بيزود اللي هي الطاقة الميكانيكية لأي
+
+64
+00:04:50,830 --> 00:04:54,600
+جسم. إذا كانت القوة في اتجاه الـ X axis positive،
+
+65
+00:04:54,600 --> 00:04:59,400
+موجبة، وDelta X سالبة، أو العكس، معنى الكلام الشغل
+
+66
+00:04:59,400 --> 00:05:04,820
+هيكون سالب، والجسم هيفقد اللي هي طاقة ميكانيكية.
+
+67
+00:05:04,820 --> 00:05:07,630
+اللي هي mechanical energy. the definition in
+
+68
+00:05:07,630 --> 00:05:11,810
+equation. فتعريف الشغل في المعادلة السابقة، اللي هي
+
+69
+00:05:11,810 --> 00:05:15,530
+خمسة إثنين. الـ work even when constant force F is
+
+70
+00:05:15,530 --> 00:05:19,710
+not parallel to the X axis. الـ work is only done by
+
+71
+00:05:19,710 --> 00:05:22,250
+the part of the force acting parallel to the
+
+72
+00:05:22,250 --> 00:05:28,090
+object, the direction of the motion. الشغل ممكن إنه
+
+73
+00:05:28,090 --> 00:05:33,950
+يعني نبدأ الشغل بالقوة المعطاة، إذا كانت هذه القوة
+
+74
+00:05:33,950 --> 00:05:39,120
+موازية لـ الإزاحة. بيكون عندي شغل طبعاً موجب أو سالب
+
+75
+00:05:39,120 --> 00:05:43,980
+حسب اتجاه الإزاحة. الـ work طبعاً، ليه؟ فالشغل
+
+76
+00:05:43,980 --> 00:05:48,560
+عبارة عن كمية قياسية. الشغل لا يعتمد على الزمن،
+
+77
+00:05:48,560 --> 00:05:52,280
+which can be an advantage in problems involving
+
+78
+00:05:52,280 --> 00:05:56,180
+only velocity and positions. فوحدة الشغل زي ما
+
+79
+00:05:56,180 --> 00:05:59,140
+حكينا نيوتن في متر. another name of the Newton
+
+80
+00:05:59,140 --> 00:06:02,680
+عبارة عن نيوتن متر، هو عبارة عن جول. إذا وحدة الشغل
+
+81
+00:06:02,680 --> 00:06:06,460
+هي الجول. والجول بيساوي نيوتن متر، كما تحدثنا
+
+82
+00:06:06,460 --> 00:06:10,640
+سابقا. useful alternate definition related to the
+
+83
+00:06:10,640 --> 00:06:13,190
+work done on an object to the angle. the
+
+84
+00:06:13,190 --> 00:06:16,690
+displacement makes with respect to the force. ممكن
+
+85
+00:06:16,690 --> 00:06:22,510
+نعرف الشغل بتعريف آخر، هندخل فيه الزاوية على أساس
+
+86
+00:06:22,510 --> 00:06:25,390
+إنه هذه الزاوية هي عبارة عن الزاوية المحصورة بين
+
+87
+00:06:25,390 --> 00:06:30,110
+الإزاحة واللي هي القوة. الزاوية هذه: this
+
+88
+00:06:30,110 --> 00:06:33,650
+definition exploits a triangle shown. طبعاً هذه
+
+89
+00:06:33,650 --> 00:06:37,990
+الزاوية بتعتمد على اللي هو اللي هي المعادلات
+
+90
+00:06:37,990 --> 00:06:42,760
+الرياضية، وحساب المثلثات لأي مثلث. Fx بتساوي F
+
+91
+00:06:42,760 --> 00:06:45,460
+Cos الزاوية، وFy بتساوي F Sin الزاوية. إذا كانت
+
+92
+00:06:45,460 --> 00:06:49,940
+الزاوية... إذا كانت القوة مائلة بزاوية θ على الـ X
+
+93
+00:06:49,940 --> 00:06:54,200
+axis، فلما نحللها إلى مركباتها، بالنسبة
+
+94
+00:06:54,200 --> 00:06:59,260
+للقوة، Fx بتساوي F Cos الزاوية، وFy، F Sin الزاوية.
+
+95
+00:06:59,260 --> 00:07:05,320
+إذا كان الإزاحة في نفس اتجاه القوة، فبتكون عندنا
+
+96
+00:07:05,320 --> 00:07:09,460
+إحنا طبعاً الـ Fx maximum. لكن إذا كان الـ... هنا الـ F
+
+97
+00:07:09,460 --> 00:07:14,130
+Sin الزاوية عمودية على الإزاحة، فبتكون الـ FY في هذه
+
+98
+00:07:14,130 --> 00:07:18,570
+الحالة صفر. فعشان هيك بيحكي لنا only the X
+
+99
+00:07:18,570 --> 00:07:23,110
+component. فقط مركبة الـ X، which is parallel، مركبة
+
+100
+00:07:23,110 --> 00:07:27,690
+الـ X هي اللي هيكون لها الشغل. في تجاه الـ X axis موجود
+
+101
+00:07:27,690 --> 00:07:35,470
+لأن القوة والإزاحة متوازيتان. وبالتالي إذا كانت...
+
+102
+00:07:35,470 --> 00:07:39,430
+اللي هي الشغل الناتج عن القوة العمودية، هيكون zero.
+
+103
+00:07:39,790 --> 00:07:43,490
+طبعاً هي القوة مائلة بزاوية ثيتا، راح ينحل الـ F
+
+104
+00:07:43,490 --> 00:07:48,110
+Cosine، وهنا F Sine. فالـ F Sine عمودية على الإزاحة،
+
+105
+00:07:48,110 --> 00:07:52,430
+فشغلها zero. وده بيعطينا الـ F Cosine وDelta X.
+
+106
+00:07:52,430 --> 00:07:56,370
+الإزاحة، الزاوية بينهم صفر، فبيكون الشغل أقصى ما
+
+107
+00:07:56,370 --> 00:08:01,950
+يمكن، لأن الإزاحة والقوة متوازيتان وبنفس الاتجاه.
+
+108
+00:08:01,950 --> 00:08:06,270
+the work W done on an object by constant F during
+
+109
+00:08:06,270 --> 00:08:10,640
+the linear displacement Delta X. إذا تعريف للشغل إذا
+
+110
+00:08:10,640 --> 00:08:18,820
+كانت الشغل والقوة ثابتة، وهي القوة بتسحب الجسم
+
+111
+00:08:18,820 --> 00:08:25,440
+بإزاحة Delta X، إذن الشغل بيساوي F Cos θ في D. D هي
+
+112
+00:08:25,440 --> 00:08:29,250
+عبارة عن magnitude of displacement، والـ θ هي
+
+113
+00:08:29,250 --> 00:08:33,850
+عبارة عن الزاوية بين الـ F والـ Delta X. is the
+
+114
+00:08:33,850 --> 00:08:36,730
+angle between the vector F and Delta X، اللي هي الـ
+
+115
+00:08:36,730 --> 00:08:41,430
+θ، الزاوية بين الـ F وDelta X. لو كان عندي أنا
+
+116
+00:08:41,430 --> 00:08:48,910
+هنا جسم، بدي أنا أحمل هذا اللي... اللي هو الـ... هذا
+
+117
+00:08:48,910 --> 00:08:52,890
+الجردل أو هذا السطل أو هذا الـ bucket، بدي أحمله، هي
+
+118
+00:08:52,890 --> 00:08:58,900
+القوة اللي لأعلى، وبدأ أمشي مسافة Delta X. بلاحظ أن
+
+119
+00:08:58,900 --> 00:09:02,860
+الشغل المبذول في هذه الحالة صفر، لأنه القوة
+
+120
+00:09:02,860 --> 00:09:10,780
+والإزاحة متعامدتان. a man
+
+121
+00:09:10,780 --> 00:09:15,000
+carrying a bucket of water. جردل أو وسط اللي يعني م...
+
+122
+00:09:15,000 --> 00:09:19,420
+طبعاً يعني موجود مملوء بالماء. هو راسمه، تلقى تكون
+
+123
+00:09:19,420 --> 00:09:23,140
+الصندوق،  فلوسي. بيتحرك هذا الرجل بسرعة... بسرعة
+
+124
+00:09:23,140 --> 00:09:28,950
+ثابتة في الـ X axis. the upward force، القوة طبعاً
+
+125
+00:09:28,950 --> 00:09:32,530
+هتكون في اتجاه الـ y axis، اللي هو القوة اللي هي
+
+126
+00:09:32,530 --> 00:09:36,990
+الرجل حامل هذا الـ settle أو هذا الـ package،
+
+127
+00:09:36,990 --> 00:09:41,370
+perpendicular to the direction of the motion, so it
+
+128
+00:09:41,370 --> 00:09:47,030
+does not do work. وبالتالي مافيش شغل، لأنه الإزاحة و
+
+129
+00:09:47,030 --> 00:09:48,490
+القوة متعامدتان.
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/TRcnjALZO3I_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/TRcnjALZO3I_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..e91004ff3a00b80caecd84b4018a85fef567cd6d
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/TRcnjALZO3I_raw.srt
@@ -0,0 +1,516 @@
+1
+00:00:00,570 --> 00:00:04,710
+بسم الله الرحمن الرحيم هنبدأ في شرح محاضرات
+
+2
+00:00:04,710 --> 00:00:08,550
+chapter خمسة بعنوان ال energy section الأول ال
+
+3
+00:00:08,550 --> 00:00:13,570
+work يعني الشغل in physics ال work is done only if
+
+4
+00:00:13,570 --> 00:00:17,470
+an object is moved through some displacement while
+
+5
+00:00:17,470 --> 00:00:21,670
+a force is applied to it تعريف الشغل بيه الفيزيا
+
+6
+00:00:21,670 --> 00:00:27,310
+ممكن أنا اعتبر أنه أي جسم بيبذل شغل إذا كان ماشي
+
+7
+00:00:27,310 --> 00:00:31,760
+إزاحة معينة اللي هي displacementبواسطة القوة اللي
+
+8
+00:00:31,760 --> 00:00:35,580
+انا اعطيتها لهذا الجسم if either the force or
+
+9
+00:00:35,580 --> 00:00:39,740
+displacement is doubled لو احنا ضعفنا القوة او
+
+10
+00:00:39,740 --> 00:00:43,740
+الإزاحة معنى الكلام ان الشغل is doubled الشغل هي
+
+11
+00:00:43,740 --> 00:00:48,120
+.. يعني يتضاعف doubled in both لو انا ضعفت اتنين
+
+12
+00:00:48,120 --> 00:00:52,780
+معنى الكلام ان الشغل هيصير يعني مضاعف الى ايه يعني
+
+13
+00:00:52,780 --> 00:00:56,840
+اتنين في اتنين يعني اربع مرات تعريف الشغل the
+
+14
+00:00:56,840 --> 00:01:03,340
+definition for workmight be taken as ال A ال work
+
+15
+00:01:03,340 --> 00:01:07,740
+بتساوي ال F في D ال work ال W و هذه رمز الشغل و ال
+
+16
+00:01:07,740 --> 00:01:11,840
+F هي عبارة عن القوة في الإزاحة ال F is magnitude
+
+17
+00:01:11,840 --> 00:01:15,380
+of the force هي عبارة عن قيمة القوة المؤثرة على
+
+18
+00:01:15,380 --> 00:01:19,140
+الجسم و ال D هي عبارة عن قيمة اللي هي displacement
+
+19
+00:01:19,140 --> 00:01:25,260
+أو الإزاحة اللي مشيها هذا الجسم اللي طبعا اللي
+
+20
+00:01:25,260 --> 00:01:29,760
+معرض لقوة معينة اسمها Fthe definition however
+
+21
+00:01:29,760 --> 00:01:34,880
+gives only هذا التعريف ممكن يعطينا قيمة ال
+
+22
+00:01:34,880 --> 00:01:38,700
+magnitude لل work المبذول on an object when the
+
+23
+00:01:38,700 --> 00:01:42,340
+force is constant and parallel to the displacement
+
+24
+00:01:42,340 --> 00:01:46,400
+هذا التعريف بيعطيني هذا ال omega أو ال W بسوة و F
+
+25
+00:01:46,400 --> 00:01:52,360
+دي بيعطيني تعريف الشغل المبذول بتعطيني قيمة هذا
+
+26
+00:01:52,360 --> 00:01:56,600
+الشغل المبذول إذا كانت القوة و الإزاحة متوازية
+
+27
+00:01:56,870 --> 00:02:00,810
+وبالتالي الزاوية اللي بينهم سفر فبيكون الشغل أعلى
+
+28
+00:02:00,810 --> 00:02:06,610
+ما يمكن الشكل التالي بيوضح جسم undergoing
+
+29
+00:02:06,610 --> 00:02:11,970
+displacement جسم اتعرض إلى قوة F ومشي ازاحة Delta
+
+30
+00:02:11,970 --> 00:02:17,870
+X في نفس الاتجاه ممكن احنا نعرف انه في هاد الحالة
+
+31
+00:02:17,870 --> 00:02:24,930
+هي الشكل في عندي أنا جسم طبعا عطيته قوة F applied
+
+32
+00:02:24,930 --> 00:02:30,190
+فمشي ازاحة Delta Xفمعنى الكلام خلال during the
+
+33
+00:02:30,190 --> 00:02:35,430
+linear displacement along the x-axis w بساوية fx
+
+34
+00:02:35,430 --> 00:02:40,470
+في delta x طبعا هذا الجسم ماشي في ال x-axis معناها
+
+35
+00:02:40,470 --> 00:02:43,130
+القوة في اتجاه ال x والإزاحة في اتجاه ال x إذا أن
+
+36
+00:02:43,130 --> 00:02:47,920
+هذا الشغل بيكون في اتجاه ال x-axisالقوة ال Fx is x
+
+37
+00:02:47,920 --> 00:02:51,540
+component of the F and delta x عبارة عن x final
+
+38
+00:02:51,540 --> 00:02:56,620
+ناقص x initial للجسم وحدة الشغل هي عبارة عن الجول
+
+39
+00:02:56,620 --> 00:03:01,760
+و الجول بده يساوي Newton dot meter Newton في متر و
+
+40
+00:03:01,760 --> 00:03:04,400
+Newton هو عبارة عن قوة اللي هي ال mass في ال
+
+41
+00:03:04,400 --> 00:03:07,640
+acceleration يعني kilogram متر تربيع على second
+
+42
+00:03:07,640 --> 00:03:13,100
+تربيعkilogram نيوتن kilogram متر في الثاني تربيع
+
+43
+00:03:13,100 --> 00:03:16,000
+وفيها نمتر صار لنا kilogram متر تربيع على second
+
+44
+00:03:16,000 --> 00:03:20,820
+تربيع اذا الجول عبارة عن متر نيوتن في متر او
+
+45
+00:03:20,820 --> 00:03:26,720
+kilogram متر تربيع على second تربيع باللاحظ note
+
+46
+00:03:26,720 --> 00:03:31,620
+that in one dimensions باللاحظ في بعد واحد الإزاحة
+
+47
+00:03:31,620 --> 00:03:36,820
+delta X عبارة عن vector quantity كمية متجهةو delta
+
+48
+00:03:36,820 --> 00:03:40,920
+x بيسوي x final نخص x initial x final نخص x
+
+49
+00:03:40,920 --> 00:03:45,080
+initial ممكن تكون موجب أو سالب حسب اللي هي قيمة ال
+
+50
+00:03:45,080 --> 00:03:49,600
+x final و ال x initial ال work as defined in
+
+51
+00:03:49,600 --> 00:03:54,180
+equation خمسة اتنين is rigorous of displacement of
+
+52
+00:03:54,180 --> 00:03:58,420
+any object along the x axis while constant force
+
+53
+00:03:58,420 --> 00:04:04,170
+act on it therefore بناء عليه طبعاإذا كان الجسم
+
+54
+00:04:04,170 --> 00:04:08,390
+بتحرك في one dimension ممكن يكون x, y أو z فإذا
+
+55
+00:04:08,390 --> 00:04:13,750
+كان الجسم انا أعطيته قوة Fx باتجاه ال x axis ومشي
+
+56
+00:04:13,750 --> 00:04:18,350
+إزاحة delta x في معنى الكلام وكانت Fx موازلة delta
+
+57
+00:04:18,350 --> 00:04:22,930
+x للإزاحة إذا .. والتانين كانت طبعا موجبة فالشغل
+
+58
+00:04:22,930 --> 00:04:27,870
+عبارة إيش عن موجب إذا كانوا التانين سالبات فالشغل
+
+59
+00:04:27,870 --> 00:04:32,650
+برضه هيكون موجبin this case in which case the
+
+60
+00:04:32,650 --> 00:04:36,990
+discussion as discussed in the next section ال
+
+61
+00:04:36,990 --> 00:04:41,050
+work increase the mechanical energy of the object
+
+62
+00:04:41,050 --> 00:04:46,890
+الشغل increase بيزداد بيزود the mechanical energy
+
+63
+00:04:46,890 --> 00:04:50,830
+of the object بيزود اللي هي الطاقة الميكانيكية لأي
+
+64
+00:04:50,830 --> 00:04:54,600
+جسمإذا كانت القوة في اتجاه ال X axis positive
+
+65
+00:04:54,600 --> 00:04:59,400
+موجبة و delta X سالبة أو العكس معناه الكلام الشغل
+
+66
+00:04:59,400 --> 00:05:04,820
+هيكون سالب و الجسم هيفقد اللي هي طاقة ميكانيكية
+
+67
+00:05:04,820 --> 00:05:07,630
+اللي هي mechanical energythe definition in
+
+68
+00:05:07,630 --> 00:05:11,810
+equation فتعريف الشغل في المعادلة السابقة اللي هي
+
+69
+00:05:11,810 --> 00:05:15,530
+خمسة اتنين ال work even when constant force F is
+
+70
+00:05:15,530 --> 00:05:19,710
+not parallel to the X axis ال work is only done by
+
+71
+00:05:19,710 --> 00:05:22,250
+the part of the force acting parallel to the
+
+72
+00:05:22,250 --> 00:05:28,090
+object the direction of the motion الشغل ممكن انه
+
+73
+00:05:28,090 --> 00:05:33,950
+يعني نبدو الشغل بالقوة المعطاة إذا كانت هذه القوة
+
+74
+00:05:33,950 --> 00:05:39,120
+موازية لا الإزاحةبكون عندى شغل طبعا موجب أو سالب
+
+75
+00:05:39,120 --> 00:05:43,980
+حسب اتجاه الإزاح ال work طبعا بنانها ليه؟ فالشغل
+
+76
+00:05:43,980 --> 00:05:48,560
+عبارة عن كمية قياسية الشغل لا يعتمد على الزمن
+
+77
+00:05:48,560 --> 00:05:52,280
+which can be an advantage in problems involving
+
+78
+00:05:52,280 --> 00:05:56,180
+only velocity and positions فوحدة الشغل زى ما
+
+79
+00:05:56,180 --> 00:05:59,140
+حكينا نيوتن في متر another name of the Newton
+
+80
+00:05:59,140 --> 00:06:02,680
+عبارة عن نيوتن متر هو عبارة عن جول إذا وحدة الشغل
+
+81
+00:06:02,680 --> 00:06:06,460
+هي الجولوالجول بدل ساوى newton ammeter كما تحدثنا
+
+82
+00:06:06,460 --> 00:06:10,640
+سابقا useful alternate definition related to the
+
+83
+00:06:10,640 --> 00:06:13,190
+work done on an object to the anglethe
+
+84
+00:06:13,190 --> 00:06:16,690
+displacement make with respect to the force ممكن
+
+85
+00:06:16,690 --> 00:06:22,510
+نعرف الشغل بتعريف آخر هندخل فيه الزاوية على أساس
+
+86
+00:06:22,510 --> 00:06:25,390
+إنه هذه الزاوية هي عبارة عن الزاوية المحصورة بين
+
+87
+00:06:25,390 --> 00:06:30,110
+الإزاحة و اللي هي القوة الزاوية هذه this
+
+88
+00:06:30,110 --> 00:06:33,650
+definition exploit a triangle shown طبعا هذه
+
+89
+00:06:33,650 --> 00:06:37,990
+الزاوية بتعتمد على اللي هو اللي هي المعادلات
+
+90
+00:06:37,990 --> 00:06:42,760
+الحسابة و حساب المثلثات لأي مثلثف Fx بالساوية F
+
+91
+00:06:42,760 --> 00:06:45,460
+Cos الزاوية و Fy بالساوية F Sin الزاوية إذا كانت
+
+92
+00:06:45,460 --> 00:06:49,940
+الزاوية .. إذا كانت القوة ميلة بزاوية θ على ال X
+
+93
+00:06:49,940 --> 00:06:54,200
+axis فلما انحلل إلى المراكبات الصينية بالنسبة
+
+94
+00:06:54,200 --> 00:06:59,260
+للقوة Fx بالساوية F Cos الزاوية و Fy F Sin الزاوية
+
+95
+00:06:59,260 --> 00:07:05,320
+إذا كان الإزاحة في نفس اتجاه القوة فبتكون عندنا
+
+96
+00:07:05,320 --> 00:07:09,460
+احنا طبعا ال Fx maximum لكن إذا كان ال .. هنا ال F
+
+97
+00:07:09,460 --> 00:07:14,130
+Sinالزاوية عمودية على الإزاحة فبتكون ال FY في هاد
+
+98
+00:07:14,130 --> 00:07:18,570
+الحالة سالبة فعشان هيك بيحكي لنا only the X
+
+99
+00:07:18,570 --> 00:07:23,110
+component فقط مراكبة ال X which is parallel مراكبة
+
+100
+00:07:23,110 --> 00:07:27,690
+ال X هي هتكون إلها الشغل في تجاه ال X axis موجود
+
+101
+00:07:27,690 --> 00:07:35,470
+لإن القوة و الإزاحة متوازيات وبالتالي إذا كانت ..
+
+102
+00:07:35,470 --> 00:07:39,430
+اللي هي الشغل الناتج عن القوة العمودية هيكون zero
+
+103
+00:07:39,790 --> 00:07:43,490
+طبعا هي القوة ميلة بزاوية ثيتا راح ينحل ال F
+
+104
+00:07:43,490 --> 00:07:48,110
+cosine و هنا F sine فال F sine عمودية على الإزاحة
+
+105
+00:07:48,110 --> 00:07:52,430
+فشغلها zero و ده لعنا ال F cosine و delta X
+
+106
+00:07:52,430 --> 00:07:56,370
+الإزاحة الزاوية بينهم zero فبيكون الشغل أقصى ما
+
+107
+00:07:56,370 --> 00:08:01,950
+يمكن لإن الإزاحة و القوة متوازيات و بنفس الاتجاه
+
+108
+00:08:01,950 --> 00:08:06,270
+the work W done on an object by constant F during
+
+109
+00:08:06,270 --> 00:08:10,640
+the linear displacement delta Xإذا تعريف للشغل إذا
+
+110
+00:08:10,640 --> 00:08:18,820
+كانت الشغل والقوة ثابتة وهي القوة بتسحب الجسم
+
+111
+00:08:18,820 --> 00:08:25,440
+بإزاحة delta X إذا الشغل بيساوي F cos θ في D D هي
+
+112
+00:08:25,440 --> 00:08:29,250
+عبارة عن magnitude of displacementو ال theta هي
+
+113
+00:08:29,250 --> 00:08:33,850
+عبارة عن الزاوية بين ال F و ال delta X is the
+
+114
+00:08:33,850 --> 00:08:36,730
+angle between the vector F and delta X اللي هي ال
+
+115
+00:08:36,730 --> 00:08:41,430
+theta الزاوية بين ال F و delta X لو كان عندي انا
+
+116
+00:08:41,430 --> 00:08:48,910
+هنا جسم بدي انا احمل هذا اللي .. اللي هو ال .. هذا
+
+117
+00:08:48,910 --> 00:08:52,890
+الجردل او هذا السطل او هذا ال bucket بدي احمله هي
+
+118
+00:08:52,890 --> 00:08:58,900
+القوة اللي اعلىوبدأ أمشي مسافة delta X بلاحظ أن
+
+119
+00:08:58,900 --> 00:09:02,860
+الشغل المفضول في هذه الحالة zero لإنه القوة
+
+120
+00:09:02,860 --> 00:09:10,780
+والإزاحة متعمدات على إبعاط ا man
+
+121
+00:09:10,780 --> 00:09:15,000
+carry a pocket of water جرد الأوساط اللي يعني م ..
+
+122
+00:09:15,000 --> 00:09:19,420
+طبعا يعني موجود مملوق بالماء هو رزين تلقى تكون
+
+123
+00:09:19,420 --> 00:09:23,140
+الصندوق الفلوسي بتحرك هذا الرجل بسرعة .. بسرعة
+
+124
+00:09:23,140 --> 00:09:28,950
+ثابتة في ال X axisthe upward force القوة طبعا
+
+125
+00:09:28,950 --> 00:09:32,530
+هتكون في اتجاه ال y axis اللي هو القوة اللي هي
+
+126
+00:09:32,530 --> 00:09:36,990
+الرجل حامل هذا ال settle او هذا ال package
+
+127
+00:09:36,990 --> 00:09:41,370
+perpendicular to the direction of the motion so it
+
+128
+00:09:41,370 --> 00:09:47,030
+does not work و بالتالي مافيش شغل لإنه الإزاحة و
+
+129
+00:09:47,030 --> 00:09:48,490
+القوة متعامدة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/WnyRIEwBh4c_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/WnyRIEwBh4c_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..3ee7296aba529506f8fa643c0a36fab5ef8ded78
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/WnyRIEwBh4c_raw.json
@@ -0,0 +1 @@
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"text": "بدها تساوي ال kinetic energy طاقة الحركة بدها تساوي P تربية على 2M هي علاقة طاقة الحركة بكمية التحرك نيجي انحل سؤال على هذا الكلام quiz 6-1 two masses M1 and M2 with M1 أقل من M2 have equal kinetic energy في عندي كتلتين M1 و M2", "tokens": [44510, 11296, 6055, 3794, 995, 45865, 2423, 27135, 2281, 23032, 995, 28671, 21542, 31747, 3660, 47525, 11296, 6055, 3794, 995, 45865, 430, 6055, 25513, 10632, 15844, 568, 44, 39896, 11203, 995, 28671, 23032, 995, 28671, 21542, 31747, 3660, 4724, 24793, 10632, 16712, 5016, 31747, 8717, 1829, 7435, 1829, 16472, 5016, 1211, 8608, 33604, 6027, 15844, 23758, 2423, 28820, 10943, 15450, 1386, 12, 16, 732, 23935, 376, 16, 293, 376, 17, 365, 376, 16, 5551, 4587, 1211, 9154, 376, 17, 362, 2681, 27135, 2281, 8978, 18871, 16254, 9122, 2655, 1211, 2655, 9957, 376, 16, 4032, 376, 17], "avg_logprob": -0.15898840206185566, "compression_ratio": 1.5952380952380953, "no_speech_prob": 2.384185791015625e-07, "words": [{"start": 122.76, "end": 123.08, "word": 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142.7, "end": 143.4, "word": " M2", "probability": 0.9951171875}, {"start": 143.4, "end": 144.64, "word": " have", "probability": 0.93896484375}, {"start": 144.64, "end": 145.18, "word": " equal", "probability": 0.91748046875}, {"start": 145.18, "end": 145.58, "word": " kinetic", "probability": 0.98291015625}, {"start": 145.58, "end": 146.24, "word": " energy", "probability": 0.95947265625}, {"start": 146.24, "end": 146.64, "word": " في", "probability": 0.385986328125}, {"start": 146.64, "end": 146.9, "word": " عندي", "probability": 0.81982421875}, {"start": 146.9, "end": 147.56, "word": " كتلتين", "probability": 0.97890625}, {"start": 147.56, "end": 148.32, "word": " M1", "probability": 0.965576171875}, {"start": 148.32, "end": 148.42, "word": " و", "probability": 0.98095703125}, {"start": 148.42, "end": 148.9, "word": " M2", "probability": 0.810302734375}], "temperature": 1.0}, {"id": 7, "seek": 17063, "start": 149.29, "end": 170.63, "text": "الهم نفس طاقة الحركة how do the magnitude of their momenta compare طبعا بدنا نقارن بين كمية التحرك للأولى والتانية فبنلاحظ انه هل بي واحد اقل من بي اتنين ولا بي واحد اكبر من اتنين طبعا هستخدم القانون السابق ان طاقة الحركة بدها تساوي", "tokens": [6027, 16095, 8717, 36178, 23032, 995, 28671, 21542, 31747, 3660, 577, 360, 264, 15668, 295, 641, 1623, 64, 6794, 23032, 3555, 3615, 995, 47525, 8315, 8717, 4587, 9640, 1863, 49374, 9122, 2304, 10632, 16712, 5016, 31747, 24976, 10721, 12610, 7578, 16070, 2655, 7649, 10632, 6156, 3555, 1863, 15040, 5016, 19913, 16472, 3224, 8032, 1211, 4724, 1829, 36764, 24401, 1975, 4587, 1211, 9154, 4724, 1829, 1975, 2655, 1863, 9957, 49429, 4724, 1829, 36764, 24401, 1975, 4117, 26890, 9154, 1975, 2655, 1863, 9957, 23032, 3555, 3615, 995, 8032, 14851, 9778, 40448, 25062, 7649, 11536, 21136, 16758, 4587, 16472, 23032, 995, 28671, 21542, 31747, 3660, 47525, 11296, 6055, 3794, 995, 45865], "avg_logprob": -0.12793865335097007, "compression_ratio": 1.7488584474885844, "no_speech_prob": 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ال zero ممكن المعادلة السابقة تكون صحيحة بحيث أنها تكون اللي هي اللي بتكون القوة يعني ال R نط يكون أصلا غير ثابتة بتكون دلتا تي تقول إلى ال zero", "tokens": [1863, 5016, 4117, 1829, 14739, 11778, 1211, 2655, 995, 4724, 1829, 15844, 11778, 1211, 2655, 995, 6055, 1829, 4032, 3215, 1211, 2655, 995, 6055, 1829, 6055, 4587, 12610, 30731, 2423, 4018, 3714, 43020, 9673, 3615, 18513, 37977, 21136, 16758, 28671, 6055, 30544, 20328, 5016, 1829, 5016, 3660, 4724, 5016, 1829, 12984, 14739, 11296, 6055, 30544, 13672, 1829, 39896, 13672, 1829, 39894, 30544, 25062, 2407, 3660, 37495, 22653, 2423, 497, 8717, 9566, 7251, 30544, 5551, 9381, 15040, 32771, 13546, 38637, 16758, 2655, 3660, 39894, 30544, 11778, 1211, 2655, 995, 6055, 1829, 6055, 4587, 12610, 30731, 2423, 4018], "avg_logprob": -0.17831829896907217, "compression_ratio": 1.9702380952380953, "no_speech_prob": 5.960464477539062e-07, "words": [{"start": 316.13, "end": 316.95, "word": "نحكي", "probability": 0.9083251953125}, {"start": 316.95, 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interaction علشان نحل هذا اللي هو ال interaction التفاعل المعقد it's useful to define average force في حاجة اسمها ال average force أو متوسط القوة", "tokens": [3555, 3794, 2288, 27884, 12910, 281, 12477, 341, 2831, 3997, 9285, 11203, 8592, 7649, 8717, 5016, 1211, 23758, 13672, 1829, 31439, 2423, 9285, 16712, 5172, 995, 30241, 9673, 3615, 28543, 309, 311, 4420, 281, 6964, 4274, 3464, 8978, 11331, 26108, 3660, 24525, 2304, 11296, 2423, 4274, 3464, 34051, 44650, 41779, 9566, 25062, 2407, 3660], "avg_logprob": -0.14232954382896423, "compression_ratio": 1.3846153846153846, "no_speech_prob": 3.635883331298828e-06, "words": [{"start": 555.86, "end": 556.68, "word": "بسرعة", "probability": 0.978271484375}, {"start": 556.68, "end": 557.16, "word": " rapidly", "probability": 0.828125}, {"start": 557.16, "end": 557.62, "word": " to", "probability": 0.80712890625}, {"start": 557.62, "end": 558.0, "word": " analyze", "probability": 0.734375}, {"start": 558.0, "end": 558.28, "word": " this", 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{"start": 590.21, "end": 590.83, "word": " عبارة", "probability": 0.91650390625}, {"start": 590.83, "end": 591.13, "word": " عن", "probability": 0.9970703125}, {"start": 591.13, "end": 593.11, "word": " عبارة", "probability": 0.8804931640625}, {"start": 593.11, "end": 593.53, "word": " عن", "probability": 0.994140625}, {"start": 593.53, "end": 593.87, "word": " اللي", "probability": 0.98583984375}, {"start": 593.87, "end": 594.15, "word": " هو", "probability": 0.99267578125}, {"start": 594.15, "end": 595.21, "word": " الدفع", "probability": 0.9534505208333334}, {"start": 595.21, "end": 596.65, "word": " الدفع", "probability": 0.86083984375}, {"start": 596.65, "end": 597.35, "word": " لأي", "probability": 0.9051106770833334}, {"start": 597.35, "end": 597.83, "word": " جسم", "probability": 0.990966796875}, {"start": 597.83, "end": 598.27, "word": " خلال", "probability": 0.9822591145833334}, {"start": 598.27, "end": 598.57, "word": " فترة", "probability": 0.9650065104166666}, {"start": 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inverse هو نفس ال direction لل force ولو T هي عبارة عن مقدار ثابت example ستة واحد cancels نيجي ل example ستة اتنين في عندي a car of mass في عندي سيارة", "tokens": [10721, 2407, 2423, 479, 6055, 3794, 2407, 7578, 8289, 430, 15844, 314, 13672, 1829, 31439, 2423, 479, 11778, 1829, 39896, 6225, 3555, 9640, 3660, 18871, 2423, 479, 4274, 23032, 3555, 3615, 995, 2423, 3513, 24976, 17340, 31439, 8717, 36178, 2423, 3513, 24976, 3464, 35525, 2407, 314, 39896, 6225, 3555, 9640, 3660, 18871, 3714, 28543, 9640, 38637, 16758, 2655, 1365, 8608, 2655, 3660, 36764, 24401, 393, 66, 1625, 8717, 1829, 7435, 1829, 5296, 1365, 8608, 2655, 3660, 1975, 2655, 1863, 9957, 8978, 18871, 16254, 257, 1032, 295, 2758, 8978, 18871, 16254, 8608, 1829, 9640, 3660], "avg_logprob": -0.1733552590796822, "compression_ratio": 1.6844660194174756, "no_speech_prob": 0.0, "words": [{"start": 622.7, "end": 623.14, "word": "أو", "probability": 0.87158203125}, {"start": 623.14, "end": 623.38, "word": " ال", "probability": 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676.9, "end": 677.26, "word": " متر", "probability": 0.8671875}, {"start": 677.26, "end": 677.4, "word": " في", "probability": 0.8896484375}, {"start": 677.4, "end": 677.82, "word": " الثانية", "probability": 0.9093017578125}, {"start": 677.82, "end": 679.22, "word": " if", "probability": 0.6357421875}, {"start": 679.22, "end": 679.36, "word": " the", "probability": 0.9111328125}, {"start": 679.36, "end": 679.78, "word": " collision", "probability": 0.9326171875}, {"start": 679.78, "end": 680.58, "word": " lasts", "probability": 0.505859375}, {"start": 680.58, "end": 681.08, "word": " for", "probability": 0.9580078125}, {"start": 681.08, "end": 681.5, "word": " ..", "probability": 0.2998046875}, {"start": 681.5, "end": 682.32, "word": " التصادم", "probability": 0.963134765625}, {"start": 682.32, "end": 683.0, "word": " حدثة", "probability": 0.8631591796875}, {"start": 683.0, "end": 683.12, "word": " في", "probability": 0.705078125}, {"start": 683.12, "end": 683.6, "word": " فترة", "probability": 0.9918619791666666}, {"start": 683.6, "end": 684.32, "word": " زمنية", "probability": 0.9298502604166666}, {"start": 684.32, "end": 684.86, "word": " 0", "probability": 0.313720703125}, {"start": 684.86, "end": 685.28, "word": ".15", "probability": 0.989501953125}, {"start": 685.28, "end": 686.0, "word": " second", "probability": 0.7958984375}, {"start": 686.0, "end": 687.0, "word": " مطلوب", "probability": 0.9244384765625}, {"start": 687.0, "end": 687.48, "word": " find", "probability": 0.869140625}, {"start": 687.48, "end": 687.88, "word": " that", "probability": 0.92138671875}, {"start": 687.88, "end": 688.46, "word": " impulse", "probability": 0.91455078125}, {"start": 688.46, "end": 689.1, "word": " delivered", "probability": 0.8154296875}, {"start": 689.1, "end": 689.42, "word": " to", "probability": 0.9765625}, {"start": 689.42, "end": 689.64, "word": " the", "probability": 0.9287109375}, {"start": 689.64, "end": 689.96, "word": " car", "probability": 0.94189453125}, {"start": 689.96, "end": 690.26, "word": " due", "probability": 0.92626953125}, {"start": 690.26, "end": 690.4, "word": " to", "probability": 0.97802734375}, {"start": 690.4, "end": 690.56, "word": " the", "probability": 0.8583984375}, {"start": 690.56, "end": 691.06, "word": " collision", "probability": 0.94580078125}, {"start": 691.06, "end": 691.76, "word": " مطلوب", "probability": 0.9296875}, {"start": 691.76, "end": 691.96, "word": " من", "probability": 0.9755859375}, {"start": 691.96, "end": 692.26, "word": " ال", "probability": 0.9560546875}, {"start": 692.26, "end": 692.76, "word": " impulse", "probability": 0.7861328125}, {"start": 692.76, "end": 693.08, "word": " هي", "probability": 0.362060546875}, {"start": 693.08, "end": 693.9, "word": " السيارة", "probability": 0.9921875}, {"start": 693.9, "end": 694.72, "word": " بتمشي", "probability": 0.8837890625}, {"start": 694.72, "end": 694.88, "word": " إلى", "probability": 0.446533203125}, {"start": 694.88, "end": 695.44, "word": " اليسار", "probability": 0.9952799479166666}, {"start": 695.44, "end": 695.96, "word": " بسرعة", "probability": 0.956787109375}, {"start": 695.96, "end": 696.4, "word": " 15", "probability": 0.85986328125}, {"start": 696.4, "end": 696.94, "word": " متر", "probability": 0.933837890625}, {"start": 696.94, "end": 697.08, "word": " في", "probability": 0.97705078125}, {"start": 697.08, "end": 697.64, "word": " الثانية", "probability": 0.9796142578125}, {"start": 697.64, "end": 698.86, "word": " اصطدمت", "probability": 0.7974609375}, {"start": 698.86, "end": 699.02, "word": " في", "probability": 0.93896484375}, {"start": 699.02, "end": 699.76, "word": " الحائط", "probability": 0.9404296875}, {"start": 699.76, "end": 700.62, "word": " و", "probability": 0.54541015625}, {"start": 700.62, "end": 700.98, "word": " بعد", "probability": 0.876953125}, {"start": 700.98, "end": 701.6, "word": " التصادم", "probability": 0.9930419921875}, {"start": 701.6, "end": 701.94, "word": " طبعا", "probability": 0.9404296875}, {"start": 701.94, "end": 702.54, "word": " رجعت", "probability": 0.9908854166666666}], "temperature": 1.0}, {"id": 28, "seek": 72306, "start": 702.94, "end": 723.06, "text": "بسرعة تانية اللي هي 2.6 متر في الثانية solution find the impulse delivered to the car موجود .. مطلوب نوجد ال impulse عارفين أن احنا ال impulse هو عبارة عن التغير في كمية التحرك لكن هنحلها بإيجاد ال be initial و ال be final", "tokens": [3555, 3794, 2288, 27884, 6055, 7649, 10632, 13672, 1829, 39896, 568, 13, 21, 44650, 2288, 8978, 6024, 104, 7649, 10632, 3827, 915, 264, 26857, 10144, 281, 264, 1032, 3714, 29245, 23328, 4386, 3714, 9566, 1211, 37746, 8717, 29245, 3215, 2423, 26857, 6225, 9640, 5172, 9957, 14739, 1975, 5016, 8315, 2423, 26857, 31439, 6225, 3555, 9640, 3660, 18871, 16712, 17082, 13546, 8978, 9122, 2304, 10632, 16712, 5016, 31747, 44381, 8032, 1863, 5016, 1211, 11296, 4724, 28814, 1829, 7435, 18513, 2423, 312, 5883, 4032, 2423, 312, 2572], "avg_logprob": 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{"start": 709.98, "end": 710.14, "word": " the", "probability": 0.87744140625}, {"start": 710.14, "end": 710.62, "word": " impulse", "probability": 0.9423828125}, {"start": 710.62, "end": 711.14, "word": " delivered", "probability": 0.66796875}, {"start": 711.14, "end": 711.46, "word": " to", "probability": 0.982421875}, {"start": 711.46, "end": 711.64, "word": " the", "probability": 0.927734375}, {"start": 711.64, "end": 711.96, "word": " car", "probability": 0.95361328125}, {"start": 711.96, "end": 712.38, "word": " موجود", "probability": 0.9306640625}, {"start": 712.38, "end": 712.58, "word": " ..", "probability": 0.340576171875}, {"start": 712.58, "end": 712.92, "word": " مطلوب", "probability": 0.9267578125}, {"start": 712.92, "end": 713.32, "word": " نوجد", "probability": 0.7745768229166666}, {"start": 713.32, "end": 713.44, "word": " ال", "probability": 0.96826171875}, {"start": 713.44, "end": 713.92, "word": " impulse", "probability": 0.93603515625}, {"start": 713.92, "end": 714.72, "word": " عارفين", "probability": 0.98046875}, {"start": 714.72, "end": 714.86, "word": " أن", "probability": 0.50341796875}, {"start": 714.86, "end": 715.08, "word": " احنا", "probability": 0.7933756510416666}, {"start": 715.08, "end": 715.18, "word": " ال", "probability": 0.9931640625}, {"start": 715.18, "end": 715.5, "word": " impulse", "probability": 0.94287109375}, {"start": 715.5, "end": 715.7, "word": " هو", "probability": 0.96923828125}, {"start": 715.7, "end": 715.96, "word": " عبارة", "probability": 0.9930419921875}, {"start": 715.96, "end": 716.12, "word": " عن", "probability": 0.98779296875}, {"start": 716.12, "end": 716.52, "word": " التغير", "probability": 0.9324544270833334}, {"start": 716.52, "end": 716.66, "word": " في", "probability": 0.97412109375}, {"start": 716.66, "end": 716.94, "word": " كمية", "probability": 0.9814453125}, {"start": 716.94, "end": 717.58, "word": " التحرك", "probability": 0.9947916666666666}, {"start": 717.58, "end": 718.34, "word": " لكن", "probability": 0.91845703125}, {"start": 718.34, "end": 719.48, "word": " هنحلها", "probability": 0.9498046875}, {"start": 719.48, "end": 720.74, "word": " بإيجاد", "probability": 0.97685546875}, {"start": 720.74, "end": 721.1, "word": " ال", "probability": 0.984375}, {"start": 721.1, "end": 721.38, "word": " be", "probability": 0.199951171875}, {"start": 721.38, "end": 721.92, "word": " initial", "probability": 0.8134765625}, {"start": 721.92, "end": 722.18, "word": " و", "probability": 0.88037109375}, {"start": 722.18, "end": 722.42, "word": " ال", "probability": 0.904296875}, {"start": 722.42, "end": 722.62, "word": " be", "probability": 0.96484375}, {"start": 722.62, "end": 723.06, "word": " final", "probability": 0.94482421875}], "temperature": 1.0}, {"id": 29, "seek": 75095, "start": 723.53, "end": 750.95, "text": "P initial وكمية التحرك الابتدائية بساوي ال M في V initial ال M كانت واحد و نص في عشر أقص ثلاث كيلو جرام و ال V initial كانت ناقص خمستاشر لإن السرعة متجهة إلى اليسار طبعا هيطلع معايا ناقص 2.25 في عشر أقص أربع كيلو جرام متر في الثانية لإيجاد ال P final هنحكي M في V final ساوي واحد و نص في عشر أقص ثلاثة كيلو جرام مضروبة في السرعة", "tokens": [47, 5883, 4032, 24793, 10632, 16712, 5016, 31747, 42963, 3555, 2655, 3215, 16373, 10632, 4724, 3794, 995, 45865, 2423, 376, 8978, 691, 5883, 2423, 376, 25961, 2655, 36764, 24401, 4032, 8717, 9381, 8978, 6225, 46309, 5551, 4587, 9381, 38637, 1211, 5718, 104, 9122, 26895, 2407, 10874, 2288, 10943, 4032, 2423, 691, 5883, 25961, 2655, 8717, 995, 4587, 9381, 16490, 2304, 14851, 33599, 2288, 5296, 28814, 1863, 21136, 2288, 27884, 44650, 7435, 3224, 3660, 30731, 45595, 3794, 9640, 23032, 3555, 3615, 995, 39896, 9566, 1211, 3615, 20449, 995, 25528, 8717, 995, 4587, 9381, 568, 13, 6074, 8978, 6225, 46309, 5551, 4587, 9381, 5551, 25513, 3615, 9122, 26895, 2407, 10874, 2288, 10943, 44650, 2288, 8978, 6024, 104, 7649, 10632, 5296, 28814, 1829, 7435, 18513, 2423, 430, 2572, 8032, 1863, 5016, 4117, 1829, 376, 8978, 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"text": "ناقص اتنين point اتنين خمسة في عشرة اقصى اربعة kilogram متر في الثانية وبيطلع معايا ال inverse اللي هو التغير في كمية التحرك اتنين point ستة اربعة في عشرة اقصى اربعة kilogram متر في الثانية في مطلوب B find .. find the average force exerted on the car طالب انه متوسط السرعة المؤثرة على ال car سيارة", "tokens": [1863, 995, 4587, 9381, 1975, 2655, 1863, 9957, 935, 1975, 2655, 1863, 9957, 16490, 2304, 3794, 3660, 8978, 6225, 8592, 25720, 1975, 4587, 9381, 7578, 1975, 25513, 27884, 21741, 44650, 2288, 8978, 6024, 104, 7649, 10632, 4032, 21292, 9566, 1211, 3615, 20449, 995, 25528, 2423, 17340, 13672, 1829, 31439, 16712, 17082, 13546, 8978, 9122, 2304, 10632, 16712, 5016, 31747, 1975, 2655, 1863, 9957, 935, 8608, 2655, 3660, 1975, 25513, 27884, 8978, 6225, 8592, 25720, 1975, 4587, 9381, 7578, 1975, 25513, 27884, 21741, 44650, 2288, 8978, 6024, 104, 7649, 10632, 8978, 3714, 9566, 1211, 37746, 363, 915, 4386, 915, 264, 4274, 3464, 31941, 292, 322, 264, 1032, 23032, 6027, 3555, 16472, 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1531.37, "word": " عامل", "probability": 0.9080403645833334}, {"start": 1531.37, "end": 1531.81, "word": " الوقت", "probability": 0.9920247395833334}, {"start": 1531.81, "end": 1533.27, "word": " لزيادة", "probability": 0.9662109375}, {"start": 1533.27, "end": 1533.59, "word": " عامل", "probability": 0.9884440104166666}, {"start": 1533.59, "end": 1533.93, "word": " الوقت", "probability": 0.9873046875}, {"start": 1533.93, "end": 1534.19, "word": " في", "probability": 0.84521484375}, {"start": 1534.19, "end": 1534.35, "word": " ..", "probability": 0.505859375}, {"start": 1534.35, "end": 1534.77, "word": " بستخدم", "probability": 0.972900390625}, {"start": 1534.77, "end": 1535.17, "word": " حاز", "probability": 0.7000732421875}, {"start": 1535.17, "end": 1535.27, "word": " ..", "probability": 0.5693359375}, {"start": 1535.27, "end": 1535.59, "word": " اللي", "probability": 0.984130859375}, {"start": 1535.59, "end": 1535.73, "word": " هو", "probability": 0.9921875}, {"start": 1535.73, "end": 1536.05, "word": " حزام", "probability": 0.9763997395833334}, {"start": 1536.05, "end": 1536.47, "word": " الأمان", "probability": 0.9762369791666666}, {"start": 1536.47, "end": 1536.87, "word": " و", "probability": 0.681640625}, {"start": 1536.87, "end": 1537.37, "word": " بستخدم", "probability": 0.96630859375}, {"start": 1537.37, "end": 1537.55, "word": " اللي", "probability": 0.984619140625}, {"start": 1537.55, "end": 1537.69, "word": " هي", "probability": 0.88134765625}, {"start": 1537.69, "end": 1537.81, "word": " ال", "probability": 0.9541015625}, {"start": 1537.81, "end": 1537.97, "word": " air", "probability": 0.87548828125}, {"start": 1537.97, "end": 1538.31, "word": " bag", "probability": 0.517578125}, {"start": 1538.31, "end": 1538.49, "word": " اللي", "probability": 0.9833984375}, {"start": 1538.49, "end": 1538.75, "word": " هي", "probability": 0.96240234375}, {"start": 1538.75, "end": 1539.55, "word": " الوسائد", "probability": 0.83343505859375}, {"start": 1539.55, 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/WnyRIEwBh4c_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/WnyRIEwBh4c_raw.srt
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+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/WnyRIEwBh4c_raw.srt
@@ -0,0 +1,1364 @@
+1
+00:00:00,520 --> 00:00:05,480
+بسم الله الرحمن الرحيم بنبدأ ان شاء الله chapter 6
+
+2
+00:00:05,480 --> 00:00:09,980
+بعنوان momentum, impulse and collisions اللي هو
+
+3
+00:00:09,980 --> 00:00:13,340
+momentum يعني كمية التحرك، ال impulse الدفع و ال
+
+4
+00:00:13,340 --> 00:00:17,880
+collision يعني التصادمات ال momentum and impulse
+
+5
+00:00:17,880 --> 00:00:22,510
+هو كمية التحرك و الدفعالـ momentum depends on an
+
+6
+00:00:22,510 --> 00:00:26,650
+object mass and velocity ال momentum بيعتمد على
+
+7
+00:00:26,650 --> 00:00:31,970
+كتلة الجسم و سرعته و يسمى ال linear momentum ال
+
+8
+00:00:31,970 --> 00:00:36,490
+linear momentum رمز كمية التحرك الخطي اللي هي B of
+
+9
+00:00:36,490 --> 00:00:40,830
+an object of mass M moving with velocity V هو
+
+10
+00:00:40,830 --> 00:00:45,650
+عبارة عن اللي هي كمية التحرك لجسم كتلته M بتتحرك
+
+11
+00:00:45,650 --> 00:00:52,380
+بسرعة V تسمى B إذا ال B بدها تساوي M في Vال B زى
+
+12
+00:00:52,380 --> 00:00:56,300
+ما احنا شايفين هى عبارة عن متجه بدها تساوي ال M فى
+
+13
+00:00:56,300 --> 00:01:00,840
+V و ال V متجه اذا طبعا ال .. ال .. ال B و ال V
+
+14
+00:01:00,840 --> 00:01:03,760
+بيبقى تمدوا على بعض و ال M اللى هى ال mass اللى هى
+
+15
+00:01:03,760 --> 00:01:08,840
+كمية scalar او كمية قياسيةوحدة ال ال P اللى هى ال
+
+16
+00:01:08,840 --> 00:01:11,520
+system international unit عبارة عن kilogram meter
+
+17
+00:01:11,520 --> 00:01:15,040
+per second kilogram meter في الثانية ال momentum
+
+18
+00:01:15,040 --> 00:01:18,260
+is a vector quantity ما حكيناه كمية التحرك كمية
+
+19
+00:01:18,260 --> 00:01:24,440
+متجهها هى نفس اتجاه سرقة الجسم its components are
+
+20
+00:01:24,440 --> 00:01:28,440
+given in two dimensions باي اللى هى مركبتين اذا
+
+21
+00:01:28,440 --> 00:01:32,320
+انا اتمدت X وY اللى هى مركبتين ف اللى هى كمية
+
+22
+00:01:32,320 --> 00:01:36,020
+التحرك بتجاه ال X بسهولة M في VXكمية التحرك باتجاه
+
+23
+00:01:36,020 --> 00:01:42,180
+ال Y M في V Y بي إكس is the momentum of the object
+
+24
+00:01:42,180 --> 00:01:47,280
+بي إكس اللي هي عبارة عن كمية التحرك لجسم اتجاهه
+
+25
+00:01:47,280 --> 00:01:51,920
+بال X axis و ال بي وي عبارة عن كمية التحرك لجسم
+
+26
+00:01:51,920 --> 00:01:56,180
+بتحرك بال Y direction أو باتجاه ال Y the magnitude
+
+27
+00:01:56,180 --> 00:02:01,500
+of the momentum بي قيمة كمية التحرك بي بدلالة ال
+
+28
+00:02:01,500 --> 00:02:04,740
+kinetic energyبدها تساوي ال kinetic energy طاقة
+
+29
+00:02:04,740 --> 00:02:09,640
+الحركة بدها تساوي P تربية على 2M هي علاقة طاقة
+
+30
+00:02:09,640 --> 00:02:13,940
+الحركة بكمية التحرك نيجي انحل سؤال على هذا الكلام
+
+31
+00:02:13,940 --> 00:02:23,400
+quiz 6-1 two masses M1 and M2 with M1 أقل من M2
+
+32
+00:02:23,400 --> 00:02:28,900
+have equal kinetic energy في عندي كتلتين M1 و M2
+
+33
+00:02:29,290 --> 00:02:33,150
+الهم نفس طاقة الحركة how do the magnitude of their
+
+34
+00:02:33,150 --> 00:02:38,030
+momenta compare طبعا بدنا نقارن بين كمية التحرك
+
+35
+00:02:38,030 --> 00:02:43,410
+للأولى والتانية فبنلاحظ انه هل بي واحد اقل من بي
+
+36
+00:02:43,410 --> 00:02:47,410
+اتنين ولا بي واحد اكبر من اتنين طبعا هستخدم
+
+37
+00:02:47,410 --> 00:02:52,160
+القانون السابق ان طاقة الحركة بدها تساويb تربيع
+
+38
+00:02:52,160 --> 00:02:57,000
+على 2m طالما أنه كانت طبعا طاقة الحركة ثابتة و ال
+
+39
+00:02:57,000 --> 00:03:01,360
+M1 أكبر من M2 فبيطلع B1 أكبر من B2 بناء على
+
+40
+00:03:01,360 --> 00:03:06,700
+القانون السابق إذا الجواب هو B وهي عبارة عن B1 أقل
+
+41
+00:03:06,700 --> 00:03:15,380
+من B2 B1 أقل من B2 changing the momentum of an
+
+42
+00:03:15,380 --> 00:03:20,090
+object requires applications تغيركمية التحرك لأي
+
+43
+00:03:20,090 --> 00:03:26,250
+جسم بيحتاج application of force طبعا علاقة طبعا أو
+
+44
+00:03:26,250 --> 00:03:31,230
+تطبيقات على القوة starting هنبدأ ب starting from
+
+45
+00:03:31,230 --> 00:03:35,430
+Newton's second law بنبدأ بقانون النيوتن التاني
+
+46
+00:03:35,430 --> 00:03:39,690
+اللي هو ال F net بتساوي ال M في A ال M بنعوده عن
+
+47
+00:03:39,690 --> 00:03:43,130
+ال A Delta V على Delta T إذا Delta على Delta T
+
+48
+00:03:43,130 --> 00:03:46,670
+دخلنا ال M جوا صارت MV هده هتساوي ال MV بتساوي B
+
+49
+00:03:46,670 --> 00:03:52,520
+إذاالأفنط بالساول Delta P على Delta T هي علاقة
+
+50
+00:03:52,520 --> 00:03:57,200
+القوة في كمية التحرك طبعا ال M هي عبارة عن ال mass
+
+51
+00:03:57,200 --> 00:04:01,600
+الكتلة and اللي هي the forces are assumed constant
+
+52
+00:04:01,600 --> 00:04:06,580
+بنعتبر أن القوة هي ثابتة the quantity is in per
+
+53
+00:04:06,580 --> 00:04:10,880
+thesis is just the momentum هي الكمية هي عبارة عن
+
+54
+00:04:10,880 --> 00:04:14,880
+كمية التحرك اللي هي ال M في V so we have the
+
+55
+00:04:14,880 --> 00:04:19,300
+following results وبالتاليالتغير فيه كمية التحرك
+
+56
+00:04:19,300 --> 00:04:25,040
+لأي جسم Delta P divided by elapsed time إذا Delta
+
+57
+00:04:25,040 --> 00:04:29,660
+P على Delta T بدها تساوي ال net force أو ال F net
+
+58
+00:04:29,660 --> 00:04:35,020
+فبدلا انت تطبيق قانون نيوتن التاني Delta P على
+
+59
+00:04:35,020 --> 00:04:38,760
+Delta T اللي هي عبارة عن ال change in momentum على
+
+60
+00:04:38,760 --> 00:04:43,480
+ال time interval اللي هي عبارة عن تغير فيه كمية
+
+61
+00:04:43,480 --> 00:04:47,930
+التحرك على الفترة الزمنية أو Delta Tبدها تساوي ال
+
+62
+00:04:47,930 --> 00:04:52,690
+F net إذا القوة الكلية بدها تساوي Delta P على
+
+63
+00:04:52,690 --> 00:04:56,890
+Delta T دي situation is also valid when the force
+
+64
+00:04:56,890 --> 00:05:00,750
+are not constant ممكن هذه المعادلة السابقة ستكون
+
+65
+00:05:00,750 --> 00:05:05,170
+صحيحة عندما تكون القوة غير ثابتة provided the
+
+66
+00:05:05,170 --> 00:05:08,790
+limit is taken as Delta T becomes infinite small
+
+67
+00:05:08,790 --> 00:05:14,150
+يعني
+
+68
+00:05:14,150 --> 00:05:18,510
+لما بدنا نجيب احنانحكي أن دلتا بي على دلتا تي
+
+69
+00:05:18,510 --> 00:05:21,950
+ودلتا تي تقول إلى ال zero ممكن المعادلة السابقة
+
+70
+00:05:21,950 --> 00:05:29,250
+تكون صحيحة بحيث أنها تكون اللي
+
+71
+00:05:29,250 --> 00:05:36,170
+هي اللي بتكون القوة يعني ال R نط يكون أصلا غير
+
+72
+00:05:36,170 --> 00:05:38,750
+ثابتة بتكون دلتا تي تقول إلى ال zero
+
+73
+00:05:42,070 --> 00:05:46,430
+بعد هيك ب .. ب .. ب .. معادلة خاصة طلعتها بت ..
+
+74
+00:05:46,430 --> 00:05:50,330
+يعني بتحكي says أو تدل أنه that if the net force
+
+75
+00:05:50,330 --> 00:05:54,970
+on an object is zero اللي هي القوة الكلية لأي جسم
+
+76
+00:05:54,970 --> 00:05:58,670
+بالساوية zero the object momentum كمية التحرك لأي
+
+77
+00:05:58,670 --> 00:06:04,050
+جسم does not change لا يتغير in other words بصفة
+
+78
+00:06:04,050 --> 00:06:08,310
+عامة يعني معنى الكلام لما تكون اللي هي ال F net
+
+79
+00:06:08,310 --> 00:06:12,880
+بالساوية zero فتغير فيه كمية التحركit does not
+
+80
+00:06:12,880 --> 00:06:16,640
+change in other words بطريقة أخرى انه ال linear
+
+81
+00:06:16,640 --> 00:06:22,080
+momentum of an object is conserved بنحكي أنه كمية
+
+82
+00:06:22,080 --> 00:06:26,820
+التحرك لأي جسم يعتبر محفوظ لما تكون الأفنط بالساوي
+
+83
+00:06:26,820 --> 00:06:32,360
+zero فمعادلة 6.3 أيضا تظهر أنه التغير في كمية
+
+84
+00:06:32,360 --> 00:06:37,020
+التحرك لأي جسم بيحتاج continuous application of
+
+85
+00:06:37,020 --> 00:06:42,740
+the force بيحتاج إلى تطبيقات مستمرة على القوةعلى
+
+86
+00:06:42,740 --> 00:06:46,240
+اللى هو خلال أو خلال فترة زمانية delta T leading
+
+87
+00:06:46,240 --> 00:06:49,720
+to definition of impulse طبعا هذا يؤدي إلى تعريف
+
+88
+00:06:49,720 --> 00:06:54,800
+لل impulse اللى هى delta P تساوي ال impulse
+
+89
+00:06:54,800 --> 00:06:58,440
+التعريف لل impulse أنه if a constant force إذا
+
+90
+00:06:58,440 --> 00:07:04,260
+كانت القوة بتتصرق لأى جسم ثابتة معناها ال impulse
+
+91
+00:07:04,260 --> 00:07:07,580
+delivered to the object over a time interval delta
+
+92
+00:07:07,580 --> 00:07:13,520
+T isإذا كانت ال F constant معناها ال I بساوي F
+
+93
+00:07:13,520 --> 00:07:18,820
+Delta T ال I يعني هو عبارة عن Delta B ال I وحدته
+
+94
+00:07:18,820 --> 00:07:24,560
+kilogram meter per second طبعا او نيوتن في second
+
+95
+00:07:24,560 --> 00:07:29,080
+بناء على القانون اللي هو 64 ال impulse is a vector
+
+96
+00:07:29,080 --> 00:07:33,560
+quantity with the same direction ال impulse اللي
+
+97
+00:07:33,560 --> 00:07:38,170
+هو الدفع هو عبارة عن كمية متجههاواتجاهه نفس اتجاه
+
+98
+00:07:38,170 --> 00:07:41,870
+اللي هي ال constant force acting on the body او on
+
+99
+00:07:41,870 --> 00:07:46,770
+object اللي تدفع تجاهه نفس اتجاه القوة المؤثرة على
+
+100
+00:07:46,770 --> 00:07:50,790
+الجسم when a single constant force إذا كان عندي
+
+101
+00:07:50,790 --> 00:07:55,910
+أنا قوة واحدة بتأثر على الجسم فالمعادلة هتكون بهذا
+
+102
+00:07:55,910 --> 00:08:01,290
+الشكل ال I اللي هو ال impulse بده يساوي F Delta T
+
+103
+00:08:01,750 --> 00:08:05,850
+أه بدها تساوي delta P اللي هو M في V final ناقص M
+
+104
+00:08:05,850 --> 00:08:10,210
+في V initial هذا طبعا هي عبارة عن special case
+
+105
+00:08:10,210 --> 00:08:14,710
+حالة خاصة له اللي هي نظرية ال impulse momentum
+
+106
+00:08:14,710 --> 00:08:22,790
+theory نظرية الدفع وكمية التحرك المعادلة 65 shows
+
+107
+00:08:23,230 --> 00:08:26,150
+that the impulse of the force acting on the body
+
+108
+00:08:26,150 --> 00:08:29,010
+أو on the object equals the change in the momentum
+
+109
+00:08:29,010 --> 00:08:34,050
+of the object بتوضح المعادلة السابقة أنه اللي هو
+
+110
+00:08:34,050 --> 00:08:37,950
+ال impulse الدفع ال impulse of the force الدفع
+
+111
+00:08:37,950 --> 00:08:41,950
+القوة يؤثر على الجسم يساوي التغير فيه كمية التحرك
+
+112
+00:08:41,950 --> 00:08:46,990
+للجسم in real life situation the force on an
+
+113
+00:08:46,990 --> 00:08:50,970
+object is only really constant for example when a
+
+114
+00:08:50,970 --> 00:08:55,230
+bat hits a pass ballthe force increase sharply
+
+115
+00:08:55,230 --> 00:09:00,530
+كمثال يعني بالنسبة للحياة العملية لما انه اللي هي
+
+116
+00:09:00,530 --> 00:09:04,990
+الكرة .. كرة اللي هي ال basketball انه ضربها بوسطة
+
+117
+00:09:04,990 --> 00:09:11,930
+المضرب the force فبتزيد القوة زيادة حادة حتى تصل
+
+118
+00:09:11,930 --> 00:09:15,570
+إلى أقصى قيمة لها ال maximum value بعد هيك بتقل
+
+119
+00:09:15,860 --> 00:09:19,160
+بسرعة rapidly to analyze this rather complex
+
+120
+00:09:19,160 --> 00:09:24,180
+interaction علشان نحل هذا اللي هو ال interaction
+
+121
+00:09:24,180 --> 00:09:28,520
+التفاعل المعقد it's useful to define average force
+
+122
+00:09:28,520 --> 00:09:33,650
+في حاجة اسمها ال average force أو متوسط القوةThe
+
+123
+00:09:33,650 --> 00:09:37,710
+average force is the constant force delivering the
+
+124
+00:09:37,710 --> 00:09:43,650
+same impulse to the object in the time interval ΔT
+
+125
+00:09:43,650 --> 00:09:47,270
+ففي حاجة اسمت أو متعريف جديد اسمه اللي هو ال
+
+126
+00:09:47,270 --> 00:09:51,130
+average velocity ال average velocity عبارة عن
+
+127
+00:09:51,130 --> 00:09:58,570
+عبارة عن اللي هو الدفع الدفع لأي جسم خلال فترة
+
+128
+00:09:58,570 --> 00:10:04,960
+زمنية ΔTحتى يعني as the actual time varying force
+
+129
+00:10:04,960 --> 00:10:08,900
+actual time varying force يعني الزمن الحقيقي خلال
+
+130
+00:10:08,900 --> 00:10:12,540
+تغير القوة we can then write the impulse momentum
+
+131
+00:10:12,540 --> 00:10:18,340
+theory طبعا معروفة أنه نظرية ال impulse momentum
+
+132
+00:10:18,340 --> 00:10:21,640
+theory اللي هو ال F Delta T بالساوية Delta P أو
+
+133
+00:10:21,640 --> 00:10:25,600
+Delta Bأو ال F تسوى delta P على T اللي هو ال F دي
+
+134
+00:10:25,600 --> 00:10:29,340
+هي عبارة عن ال F average طبعا ال direction لل
+
+135
+00:10:29,340 --> 00:10:32,800
+inverse هو نفس ال direction لل force ولو T هي
+
+136
+00:10:32,800 --> 00:10:38,740
+عبارة عن مقدار ثابت example ستة واحد cancels نيجي
+
+137
+00:10:38,740 --> 00:10:44,800
+ل example ستة اتنين في عندي a car of mass في عندي
+
+138
+00:10:44,800 --> 00:10:48,330
+سيارةبكتلتها واحد point خمسة في عشر قصر ثلاثة
+
+139
+00:10:48,330 --> 00:10:52,370
+kilogram collided with a wall and rebound as
+
+140
+00:10:52,370 --> 00:10:57,810
+انفجار السيارة اصطدمت بالحيط وبعد هيك رجعت the
+
+141
+00:10:57,810 --> 00:11:01,390
+initial and final velocity of the car are V
+
+142
+00:11:01,390 --> 00:11:06,810
+initial ناقص خمستاشر لإن السيارة كانت بتحرك إلى
+
+143
+00:11:06,810 --> 00:11:10,290
+اليسار فسرعتها الابتدائية V initial بتساوي ناقص
+
+144
+00:11:10,290 --> 00:11:15,020
+خمستاشر متر في الثانية و V final كانتبعد الارتداد
+
+145
+00:11:15,020 --> 00:11:19,780
+أو بعد التصادم 2.6 متر في الثانية if the collision
+
+146
+00:11:19,780 --> 00:11:25,280
+lasts for .. التصادم حدثة في فترة زمنية 0.15
+
+147
+00:11:25,280 --> 00:11:29,640
+second مطلوب find that impulse delivered to the
+
+148
+00:11:29,640 --> 00:11:33,080
+car due to the collision مطلوب من ال impulse هي
+
+149
+00:11:33,080 --> 00:11:37,640
+السيارة بتمشي إلى اليسار بسرعة 15 متر في الثانية
+
+150
+00:11:37,640 --> 00:11:43,780
+اصطدمت في الحائط و بعد التصادم طبعا رجعتبسرعة
+
+151
+00:11:43,780 --> 00:11:50,140
+تانية اللي هي 2.6 متر في الثانية solution find the
+
+152
+00:11:50,140 --> 00:11:53,320
+impulse delivered to the car موجود .. مطلوب نوجد
+
+153
+00:11:53,320 --> 00:11:56,120
+ال impulse عارفين أن احنا ال impulse هو عبارة عن
+
+154
+00:11:56,120 --> 00:12:01,380
+التغير في كمية التحرك لكن هنحلها بإيجاد ال be
+
+155
+00:12:01,380 --> 00:12:05,070
+initial و ال be finalP initial وكمية التحرك
+
+156
+00:12:05,070 --> 00:12:09,470
+الابتدائية بساوي ال M في V initial ال M كانت واحد
+
+157
+00:12:09,470 --> 00:12:13,310
+و نص في عشر أقص ثلاث كيلو جرام و ال V initial كانت
+
+158
+00:12:13,310 --> 00:12:17,430
+ناقص خمستاشر لإن السرعة متجهة إلى اليسار طبعا
+
+159
+00:12:17,430 --> 00:12:20,610
+هيطلع معايا ناقص 2.25 في عشر أقص أربع كيلو جرام
+
+160
+00:12:20,610 --> 00:12:25,950
+متر في الثانية لإيجاد ال P final هنحكي M في V
+
+161
+00:12:25,950 --> 00:12:29,790
+final ساوي واحد و نص في عشر أقص ثلاثة كيلو جرام
+
+162
+00:12:29,790 --> 00:12:34,150
+مضروبة في السرعةالنهائية وكانت موجبة لإنها متجهة
+
+163
+00:12:34,150 --> 00:12:38,550
+إلى اليمين أو إلى الشرق ف ال b final تطلع موجبة
+
+164
+00:12:38,550 --> 00:12:41,770
+point تلاتة تسعة في عشر أو أربع kilogram متر في
+
+165
+00:12:41,770 --> 00:12:45,270
+التانية الان احنا جيبنا b initial وb final بدي
+
+166
+00:12:45,270 --> 00:12:48,470
+اجيب ال impulse ال impulse يعبارة عن التغير the
+
+167
+00:12:48,470 --> 00:12:52,630
+difference between the final and the initial فال I
+
+168
+00:12:52,630 --> 00:12:57,330
+اللي هي عبارة عن b final ناقص b initial b final
+
+169
+00:12:57,330 --> 00:13:00,170
+point تلاتة تسعة في عشر أو أربع kilogram متر في
+
+170
+00:13:00,170 --> 00:13:03,910
+التانية ناقصناقص اتنين point اتنين خمسة في عشرة
+
+171
+00:13:03,910 --> 00:13:07,450
+اقصى اربعة kilogram متر في الثانية وبيطلع معايا ال
+
+172
+00:13:07,450 --> 00:13:10,690
+inverse اللي هو التغير في كمية التحرك اتنين point
+
+173
+00:13:10,690 --> 00:13:13,110
+ستة اربعة في عشرة اقصى اربعة kilogram متر في
+
+174
+00:13:13,110 --> 00:13:19,470
+الثانية في مطلوب B find .. find the average force
+
+175
+00:13:19,470 --> 00:13:23,750
+exerted on the car طالب انه متوسط السرعة المؤثرة
+
+176
+00:13:23,750 --> 00:13:30,920
+على ال car سيارةهنطبق قانون 6.6 Apply Cohesion 6.6
+
+177
+00:13:30,920 --> 00:13:34,120
+The Impulse Momentum Theory احنا خدنا ان ال F
+
+178
+00:13:34,120 --> 00:13:38,700
+بتساوي Delta P ع Delta T او Delta P سوا F في Delta
+
+179
+00:13:38,700 --> 00:13:41,700
+T اللي هى ال F average ف Delta P جيبناها من
+
+180
+00:13:41,700 --> 00:13:46,360
+المطلوب الأول 2.64 في 10 أقصى 4 كيلو جرام متر في
+
+181
+00:13:46,360 --> 00:13:52,460
+الثانية على Delta T 0.15 ثانية بتساوي 1.76 في 10
+
+182
+00:13:52,460 --> 00:13:59,980
+أقصى 5 انيوترنجلا section جديد اسمه injury in
+
+183
+00:13:59,980 --> 00:14:04,660
+automobile collisions اللي هي الإصابات التي تحدث
+
+184
+00:14:04,660 --> 00:14:09,260
+نتيجة تصادم اللي هي السيارات the main injuries
+
+185
+00:14:09,260 --> 00:14:12,480
+that occur a person hitting the interior of a car
+
+186
+00:14:12,480 --> 00:14:17,040
+in a crash are brain damage معناها إن الإصابات
+
+187
+00:14:17,040 --> 00:14:22,900
+الأساسية التي تحدث لشخص طبعا انضرب أو انخبط في
+
+188
+00:14:22,900 --> 00:14:27,550
+سيارةهو بيكون داخل السيارة يضرب داخل السيارة في
+
+189
+00:14:27,550 --> 00:14:33,370
+حادث اصطدام or brain damage ممكن يحدث تلف للدماغ
+
+190
+00:14:33,370 --> 00:14:39,410
+ممكن يحدث كسر للعظام ممكن يحدث trauma صدمة في
+
+191
+00:14:39,410 --> 00:14:43,370
+الجلد اللي هي ال trauma to the skin ممكن ال blood
+
+192
+00:14:43,370 --> 00:14:48,150
+vessels او كمان برضه تتأثر القواعد دموية and the
+
+193
+00:14:48,150 --> 00:14:52,870
+internal organ ممكن برضهاللي هم الأعضاء الداخلية
+
+194
+00:14:52,870 --> 00:14:57,630
+تتأثر نتيجة هذا التصادم بناء عليه we compare the
+
+195
+00:14:57,630 --> 00:15:01,070
+rather imprecisely known threshold for human
+
+196
+00:15:01,070 --> 00:15:04,150
+injury with the typical force and acceleration
+
+197
+00:15:04,150 --> 00:15:08,710
+experienced in a car هنا في هذا المثال بدنا نقارن
+
+198
+00:15:08,710 --> 00:15:11,170
+عتبات في حاجة اسمها threshold يعني العتبة أو
+
+199
+00:15:11,170 --> 00:15:15,270
+النقطة اللي بعدها ممكن يحدث درر يعني يعني أخر نقطة
+
+200
+00:15:15,270 --> 00:15:18,970
+ممكن زي مثلا عتبة الصوت بعدها إلنا حد معين للصوت
+
+201
+00:15:18,970 --> 00:15:22,450
+يعني هذه النقطةنقطة بعديها بيصير ضرر بيسموها
+
+202
+00:15:22,450 --> 00:15:26,410
+threshold of human injury طبعا هي العتبة اللي
+
+203
+00:15:26,410 --> 00:15:31,250
+بعدها ممكن الإنسان إذا تم فيه تصادم ممكن يتأثر
+
+204
+00:15:31,250 --> 00:15:37,690
+طبعا with the typical force and acceleration
+
+205
+00:15:37,690 --> 00:15:41,350
+experienced in a car crash هذه ال threshold مش
+
+206
+00:15:41,350 --> 00:15:46,930
+معروفة للاصابات لل human للناس للبشر مع القوة
+
+207
+00:15:46,930 --> 00:15:51,460
+التسارع اللي بتحدث فياللي هي خلال تصادم السيارات
+
+208
+00:15:51,460 --> 00:15:57,720
+ممكن أن القوة about of تسعين كيلو نيوتن تبلغ تسعين
+
+209
+00:15:57,720 --> 00:16:01,980
+كيلو نيوتن هذه هي أبراعا لthreshold force هي عتبة
+
+210
+00:16:01,980 --> 00:16:07,380
+القوة for fracture اللي بعدها ممكن يصير كسر
+
+211
+00:16:07,380 --> 00:16:13,380
+compressing the tibia can cause fracture طبعا اللي
+
+212
+00:16:13,380 --> 00:16:19,020
+هي قوة عتبة .. عتبة الكسر هذه للمعروف أنههذه بتأثر
+
+213
+00:16:19,020 --> 00:16:23,340
+.. ممكن تأثر على اللي هي ضغط اللي .. اللي .. اللي
+
+214
+00:16:23,340 --> 00:16:25,960
+بيصير .. ممكن يصير بعدها كسر .. ممكن يصير بعدها
+
+215
+00:16:25,960 --> 00:16:30,040
+كسر It's well known that rapid acceleration معروف
+
+216
+00:16:30,040 --> 00:16:36,120
+أنه التسارع اللي هو المتزايد سريع على الرأس يعني
+
+217
+00:16:36,120 --> 00:16:39,980
+لما ينضرب الرأس بتسارع سريع even without skull
+
+218
+00:16:39,980 --> 00:16:45,190
+fractureممكن بدون ما تنكسر الجمجمة can be ممكن ي
+
+219
+00:16:45,190 --> 00:16:50,750
+.. يصير يعني هذا التصادم تصادم مميت estimate show
+
+220
+00:16:50,750 --> 00:16:56,730
+that his acceleration of ممكن انه طبعا يكون عندي
+
+221
+00:16:56,730 --> 00:17:03,270
+انا تقديرات معينة الى اللي هي التسارق هذه الرأس
+
+222
+00:17:03,270 --> 00:17:06,910
+ممكن تكون مية و خمسين جرام ممكن مية و خمسين جرام
+
+223
+00:17:06,910 --> 00:17:11,480
+experience for aboutيعني مية و خمسين .. هذا
+
+224
+00:17:11,480 --> 00:17:15,220
+بالنسبة لمية و خمسين G مية و خمسين G تسارع
+
+225
+00:17:15,220 --> 00:17:21,980
+الجاذبية إذا كان عندي أنا التسارع هذا للراس يعني
+
+226
+00:17:21,980 --> 00:17:24,500
+مية و خمسين مرة تسارع الجاذبية experience for
+
+227
+00:17:24,500 --> 00:17:28,740
+about .. يعني مدة التسارع بتكون أربع ملي ثانية أو
+
+228
+00:17:28,740 --> 00:17:33,420
+خمسين G for ستين ملي ثانية are ممكن يكون قاتل ..
+
+229
+00:17:33,420 --> 00:17:37,240
+قاتل يعني أو نص الوقت خمسين ثانية من الزمنsuch
+
+230
+00:17:37,240 --> 00:17:40,160
+injuries from rapid acceleration يعني سرعة عالية
+
+231
+00:17:40,160 --> 00:17:45,060
+تسارع عالية جدا غالبا ما تؤدي هذه الإصابات الناتجة
+
+232
+00:17:45,060 --> 00:17:50,280
+عن التسارع السريع إلى حدوث ثلث الأعصاب results زي
+
+233
+00:17:50,280 --> 00:17:53,920
+ما حكينا ال nerve damage to the spinal cord ممكن
+
+234
+00:17:53,920 --> 00:17:57,800
+يتأثر أو يتحطم أو يعني يصير في خلل فيه اللي هو
+
+235
+00:17:57,800 --> 00:18:02,640
+النخاع الشوكي where the nerve enter the base of
+
+236
+00:18:02,640 --> 00:18:05,420
+the brain ممكن كمان بأثر على الأعصاب اللي بتتصل
+
+237
+00:18:05,420 --> 00:18:11,190
+بيه الدماءthe threshold for damage to skin هي يعني
+
+238
+00:18:11,190 --> 00:18:15,370
+أن عطبة اللي هي ال .. العطبة ال .. ال damage اللي
+
+239
+00:18:15,370 --> 00:18:19,230
+هي الدرر اللي بيصير على الجلد و القوة الدموية و
+
+240
+00:18:19,230 --> 00:18:22,570
+الأعضاء الداخلية ممكن يتأثر الجسم كله بالكامل،
+
+241
+00:18:22,570 --> 00:18:26,250
+ممكن الجسم كله بالكامل يتأثر بهذه الصدمة
+
+242
+00:18:29,090 --> 00:18:32,250
+estimate هو ال body impact data where the force is
+
+243
+00:18:32,250 --> 00:18:34,970
+uniformly distributed over the entire front
+
+244
+00:18:34,970 --> 00:18:40,530
+surface area 0.7 to 0.9 متر تربية ممكن تكون هذه
+
+245
+00:18:40,530 --> 00:18:43,570
+القوة موزعة بشكل موحد على السطح الأمامي بأكمله
+
+246
+00:18:43,570 --> 00:18:47,810
+ممكن هذه القوة يعني .. يعني لما الرأس ينضرب قوة
+
+247
+00:18:47,810 --> 00:18:52,670
+معينة هيخبط في مساحة معينة زي مثلا 0.7 إلى 0.9 متر
+
+248
+00:18:52,670 --> 00:18:55,550
+تربية هذه عبارة عن المساحة اللي ممكن الرأس ينضرب
+
+249
+00:18:55,550 --> 00:18:59,450
+فيهالأن ضربة الرأس هي .. بيصير مدى ضغط هذا القوة
+
+250
+00:18:59,450 --> 00:19:03,330
+على مساحة .. مساحة ف these data shows that if the
+
+251
+00:19:03,330 --> 00:19:07,250
+collision lasts for less than above 70 millisecond
+
+252
+00:19:07,250 --> 00:19:11,870
+هذه البيانات .. هذه البيانات بتظهر إذا استمرت
+
+253
+00:19:11,870 --> 00:19:16,770
+تصادم لأقل من 70 ملي ثانية سيبقى الشخص على قيد
+
+254
+00:19:16,770 --> 00:19:21,730
+الحياة إذا كان الجسم كله اتأثر بالضغط ال impacted
+
+255
+00:19:21,730 --> 00:19:27,780
+pressure فضغط القوة لكل وحدة مساحةهيكون ان اقل من
+
+256
+00:19:27,780 --> 00:19:33,040
+1.9 في 10 عقل 5 نيوت المتر تربيه ممكن يحدث الموت
+
+257
+00:19:33,040 --> 00:19:38,660
+في يعني يمكن 50% من الحالات ممكن يحدث الموت ان
+
+258
+00:19:38,660 --> 00:19:45,440
+واتش اذا كان الجسم كله استضام ووصل الضغط الى 3.4
+
+259
+00:19:45,440 --> 00:19:48,980
+في 10 عقل 5 نيوت المتر تربيهالان باستخدام البيانات
+
+260
+00:19:48,980 --> 00:19:51,140
+الـ earn with the data above باستخدام البيانات
+
+261
+00:19:51,140 --> 00:19:55,520
+السابقة we can estimate the force and acceleration
+
+262
+00:19:55,520 --> 00:20:01,120
+in typical car crash and see how seat built المعنى
+
+263
+00:20:01,120 --> 00:20:05,980
+باستخدام البيانات السابقة تذكر ممكن أن نقدر القوة
+
+264
+00:20:05,980 --> 00:20:09,940
+التسارق في أي حد السيارة نجد طبعا وجود أحزي من
+
+265
+00:20:09,940 --> 00:20:13,900
+المقاعد و الوسائد الهوائية اللي هي ال air bag و ال
+
+266
+00:20:13,900 --> 00:20:18,010
+padded interior اللي هي عبارة عن ديكورات مبطنةcan
+
+267
+00:20:18,010 --> 00:20:20,810
+reduce that change هذه الأشياء الموجودة في السيارة
+
+268
+00:20:20,810 --> 00:20:25,730
+ممكن تقلل فرصة الوفاة أو الإصابة الخطيرة خلال اللي
+
+269
+00:20:25,730 --> 00:20:29,610
+هو التصادم طبعا على سبيل المثال consider a typical
+
+270
+00:20:29,610 --> 00:20:32,490
+collision involving على سبيل المثال بفرض في عندي
+
+271
+00:20:32,490 --> 00:20:38,010
+أنا ركاب طبعا الركاب موجودين داخل السيارة بسنجار
+
+272
+00:20:38,010 --> 00:20:43,610
+او يعني او راكب خمسة و سبعين كيلو جرام كتلته راكب
+
+273
+00:20:43,610 --> 00:20:48,510
+not wearing a seat طبعا مش لابساللي هو حزام الأمان
+
+274
+00:20:48,510 --> 00:20:52,730
+أو حزام المقعد هي السيارة بتسير بسرعة 27 متر في
+
+275
+00:20:52,730 --> 00:20:56,870
+الثانية who comes to rest in about طبعا بعد
+
+276
+00:20:56,870 --> 00:21:00,850
+التصادم ممكن يوصل لوضعه الأصلي بعد واحد من مية
+
+277
+00:21:00,850 --> 00:21:06,330
+ثانية بعد التصادم طبعا هيستغرق زي ما حكينا point
+
+278
+00:21:06,330 --> 00:21:12,130
+واحد عشان يوصل لوضعه الأصلي هذه هتستغرق وقت معين
+
+279
+00:21:12,130 --> 00:21:17,200
+للوصول لحالة التباعت بعد التصادملوجود طبعا لوحة
+
+280
+00:21:17,200 --> 00:21:22,300
+قيادية غير مبطنة زي ما حكينا سابقا الآن إذا طبعا
+
+281
+00:21:22,300 --> 00:21:25,140
+باستخدام اللي هي ال F average Delta T بيساوي ال MV
+
+282
+00:21:25,140 --> 00:21:29,140
+final ناقص MV initial we find that ال F average
+
+283
+00:21:29,140 --> 00:21:33,700
+اللي هي MV final ناقص MV initial على Delta T V
+
+284
+00:21:33,700 --> 00:21:37,300
+final بعد التصادم طبعا بعد ما اصطدم وصل لدرجة ال
+
+285
+00:21:37,300 --> 00:21:41,180
+rest هذه ال V final zero V initial سبعة وعشرين على
+
+286
+00:21:41,630 --> 00:21:44,770
+اللي هي واحد من المئة second بيطلع عندي نقص اتنين
+
+287
+00:21:44,770 --> 00:21:45,530
+فى عشر وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة
+
+288
+00:21:45,530 --> 00:21:45,890
+وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة
+
+289
+00:21:45,890 --> 00:21:46,370
+وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة
+
+290
+00:21:46,370 --> 00:21:53,370
+وعشرة وعشرة وعشرة وعشرة وعشرة
+
+291
+00:21:53,370 --> 00:21:56,930
+وعشرة
+
+292
+00:21:56,930 --> 00:21:57,910
+وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة
+
+293
+00:21:57,910 --> 00:21:57,910
+وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة وعشرة
+
+294
+00:21:57,910 --> 00:22:03,650
+وعشرة وعشرة
+
+295
+00:22:03,650 --> 00:22:09,090
+وعشرة
+
+296
+00:22:09,090 --> 00:22:14,740
+وعشرةهتساوي اتنين و تمانين G يعني هتكون تسعره
+
+297
+00:22:14,740 --> 00:22:21,380
+اتنين و تمانين مرة قدر تسعر الجاذبين الآن لو فرضنا
+
+298
+00:22:21,380 --> 00:22:26,640
+ان الراكب ضبط رأسه crash into the .. يعني الراكب
+
+299
+00:22:26,640 --> 00:22:32,380
+خبط رأسه أثناء التصادم خبط رأسه و صدره على الذجاج
+
+300
+00:22:32,380 --> 00:22:38,270
+الأمامي للسيارة و طبعا .. و لوحة القيادةال
+
+301
+00:22:38,270 --> 00:22:42,670
+steering يعني اللي عند التصادم خبط راسه في الذجاج
+
+302
+00:22:42,670 --> 00:22:47,090
+الأمامي و بلوحة السيارة و ب .. و كمان أيضا ب ..
+
+303
+00:22:47,090 --> 00:22:51,210
+اللي هي الذجاج الأمامي و اللي هي كمان أيضا خبط
+
+304
+00:22:51,210 --> 00:22:57,920
+راسه و صدره بمساحة تساوي تقريبا نص متر تربيةنجد إن
+
+305
+00:22:57,920 --> 00:23:02,080
+الضغط على الجسم كله بساوي ال F average على اللي هي
+
+306
+00:23:02,080 --> 00:23:05,460
+المساحة دي عبارة عن الضغط اللي الجسم اتعرض له
+
+307
+00:23:05,460 --> 00:23:10,260
+تقريبا قوة مساحة تساوي ضغط أربعة في عشر أقصى خمسة
+
+308
+00:23:10,260 --> 00:23:14,440
+نيوتن على متر تربيان في هذه الحالة نجد إن القوة
+
+309
+00:23:14,440 --> 00:23:19,880
+والتسارع وضغط الجسم كله طبعا تجاوز عتبة اللي هو ال
+
+310
+00:23:19,880 --> 00:23:24,560
+موت exceed the threshold of fatality or broken بما
+
+311
+00:23:24,560 --> 00:23:30,230
+ممكناتجاوز عتبة اللي هو ال .. ال .. الموت أو ممكن
+
+312
+00:23:30,230 --> 00:23:35,050
+الإضاءة بتكون تتقصر أو التصادم بيكون هذا غير محمي
+
+313
+00:23:35,050 --> 00:23:39,470
+إذا كان الشخص بيتحرك بسرعة 27 متر بالثانية هذا
+
+314
+00:23:39,470 --> 00:23:43,450
+عبارة عن .. يعني سرعة تقول يعني صعبة بالنسبة لشخص
+
+315
+00:23:43,450 --> 00:23:47,750
+مش محمي يعني مش ماسك أو مش مستخدم اللي هو حزام
+
+316
+00:23:47,750 --> 00:23:51,210
+الأمان أو اللي هي غير موجودة اللي هي ال air bag
+
+317
+00:23:51,210 --> 00:23:55,000
+داخل السيارةwhat can be done to reduce عشان طبعا
+
+318
+00:23:55,000 --> 00:24:02,740
+نخفف .. نخفف طبعا حدة هذا التصادم ماذا نفعل أهم
+
+319
+00:24:02,740 --> 00:24:06,940
+عامل ليه التصادم هو عامل له الزمن أو الوقت اللي
+
+320
+00:24:06,940 --> 00:24:10,980
+يستغرقه الشخص يصل بعد التصادم إلى حالة التبات إذا
+
+321
+00:24:10,980 --> 00:24:15,380
+كان من الممكن زيادة هذا الوقت من عشرة إلى مائة ضعف
+
+322
+00:24:15,380 --> 00:24:19,500
+قيمة اللي هي واحد من المائة ممكن أزيدها من عشرة
+
+323
+00:24:19,500 --> 00:24:23,950
+إلى مائة ضعفfor the hard collision التصادم الشديد
+
+324
+00:24:23,950 --> 00:24:28,350
+that chance يعني بيكون في عنا احنا ممكن يكون فيه
+
+325
+00:24:28,350 --> 00:24:39,130
+امل انه يكون الانسان يعني تحمي من هذا التصادم زي
+
+326
+00:24:39,130 --> 00:24:43,590
+ما احنا شايفين طبعا عشان الإنسان يبقى على قيد
+
+327
+00:24:43,590 --> 00:24:47,830
+الحياة في حادث السير بيكون عندنا لازم يكون فيه قوة
+
+328
+00:24:47,830 --> 00:24:52,370
+تلامس من عشرة انا ازودها ل100 مرةبالنسبة ل delta T
+
+329
+00:24:52,370 --> 00:24:56,990
+فوجود الأحزمة المقاعد بتقيد الناس وجود بيض أيضا
+
+330
+00:24:56,990 --> 00:25:00,930
+المخدة أو ال air bag هذه بتخفف الوسائد الهوائية
+
+331
+00:25:00,930 --> 00:25:04,070
+لإنها بتزيد من وقت اتصاده و ت .. ت .. تانتص اللي
+
+332
+00:25:04,070 --> 00:25:06,970
+هي absorb the energy from the body تنتص الطاقة
+
+333
+00:25:06,970 --> 00:25:12,290
+اللي هي و بالتالي بتمنع الموتى and they spread the
+
+334
+00:25:12,290 --> 00:25:15,610
+contact force over the area of the body ممكن احنا
+
+335
+00:25:15,610 --> 00:25:20,330
+نزود المساحة اللي الجسم بيخبط فيهاممكن تكون نص متر
+
+336
+00:25:20,330 --> 00:25:24,730
+تربيع هذا طبعا بتخفف من ال .. الإصابات اللي ممكن
+
+337
+00:25:24,730 --> 00:25:29,970
+طبعا تحدث عند التصادم مع أن الكلام أهم عامل لت ..
+
+338
+00:25:29,970 --> 00:25:34,350
+بيخفف التصادم و عامل الوقت لزيادة عامل الوقت في ..
+
+339
+00:25:34,350 --> 00:25:37,690
+بستخدم حاز .. اللي هو حزام الأمان و بستخدم اللي هي
+
+340
+00:25:37,690 --> 00:25:43,710
+ال air bag اللي هي الوسائد الهوائية نستكمل ان شاء
+
+341
+00:25:43,710 --> 00:25:45,110
+الله في التسجيل القادم
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs.srt
new file mode 100644
index 0000000000000000000000000000000000000000..92d561d1d719c0c58b47110d0c38906a7d930942
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs.srt
@@ -0,0 +1,1050 @@
+1
+00:00:00,000 --> 00:00:05,260
+بسم الله الرحمن الرحيم نستكمل chapter one بعنوان
+
+2
+00:00:05,260 --> 00:00:11,300
+units and vectors ووصلنا ل section 1.1 بعنوان
+
+3
+00:00:11,300 --> 00:00:16,740
+component of a vector. Consider a vector a in a
+
+4
+00:00:16,740 --> 00:00:20,360
+rectangular coordinate system. بأفرض في عندي متجه a
+
+5
+00:00:21,020 --> 00:00:24,580
+المتجه A موجود في الـ rectangular coordinate
+
+6
+00:00:24,580 --> 00:00:29,860
+system. بمستوى طبعا X و Y. A can be expressed as the
+
+7
+00:00:29,860 --> 00:00:32,920
+sum of two vectors. الـ A ممكن أنا أمثله
+
+8
+00:00:32,920 --> 00:00:39,840
+بمتجهين أو مركبتين بيسموه component vectors. الـ A
+
+9
+00:00:39,840 --> 00:00:45,300
+هذه ممكن أنا أقسمها إلى A باتجاه الـ X و A باتجاه
+
+10
+00:00:45,300 --> 00:00:50,660
+الـ Y. ax و ay يسموا are component vectors. عبارة عن
+
+11
+00:00:50,660 --> 00:00:56,800
+مراكبات المتجه a. ax is called the x component of a. ax
+
+12
+00:00:56,800 --> 00:01:03,830
+بسميها المكونة السينية لـ a, and ay is called the y
+
+13
+00:01:03,830 --> 00:01:09,130
+component of a. These components can be either
+
+14
+00:01:09,130 --> 00:01:12,410
+positive or negative numbers with units. The
+
+15
+00:01:12,410 --> 00:01:17,550
+components of a are الآن هذه المركبات ممكن تكون
+
+16
+00:01:17,550 --> 00:01:25,530
+موجبة أو سالبة طبعا حسب اتجاه المتجه a. The
+
+17
+00:01:25,530 --> 00:01:30,750
+components of a, مركبات ال a اللي هي ال ax تساوي A
+
+18
+00:01:30,750 --> 00:01:36,110
+cos θ. الـ θ هذه الزاوية التي يصنعها المتجه مع
+
+19
+00:01:36,110 --> 00:01:42,570
+اتجاه X الموجب. Ay بتساوي A sin θ. يعني حللنا المتجه
+
+20
+00:01:42,570 --> 00:01:48,650
+A إلى مركبتين: مركبة موازية للمحور X ومركبة عمودية
+
+21
+00:01:48,650 --> 00:01:56,050
+على X. الموازية لـ X تسمى A cos θ، والعمودية على X تسمى A sin θ. It
+
+22
+00:01:56,050 --> 00:01:58,790
+follows that A's magnitude and direction are
+
+23
+00:01:58,790 --> 00:02:01,130
+related to its components through the following
+
+24
+00:02:01,130 --> 00:02:07,330
+relation. الآن ممكن أوجد أنا محصلة متجهين أو مجموعة
+
+25
+00:02:07,330 --> 00:02:13,130
+متجهات كالتالي: A بدها تساوي √(Ax² + Ay²).
+
+26
+00:02:13,130 --> 00:02:16,590
+هذه بسميها الـ magnitude of the vector. يعني
+
+27
+00:02:16,590 --> 00:02:22,540
+قيمة الـ vector كعدد، القيمة العددية للمتجه A. عند
+
+28
+00:02:22,540 --> 00:02:27,760
+إيجاد الـ direction بأوجد tan θ اللي هي عبارة
+
+29
+00:02:27,760 --> 00:02:32,280
+عن Ay / Ax، ثم أوجد θ = tan⁻¹(Ay / Ax).
+
+30
+00:02:32,280 --> 00:02:39,240
+و بأكتب الـ Ay بإشارتها موجب أو سالب، و الـ Ax بإشارتها موجب أو سالب لإيجاد
+
+31
+00:02:39,240 --> 00:02:42,920
+الزاوية. لو أنا عندي الآن بهذا الشكل، موضح عندي متجه
+
+32
+00:02:48,910 --> 00:02:55,030
+A. متجه A بيصنع زاوية θ مع اتجاه X الموجب. لما
+
+33
+00:02:55,030 --> 00:02:58,690
+أحلل مكونات متجه A، راح أحللها إلى مركبة
+
+34
+00:02:58,690 --> 00:03:02,790
+أُخرى، مركبة باتجاه الـ X axis، يعني Ax = A
+
+35
+00:03:02,790 --> 00:03:08,080
+cos θ، و Ay بدها تساوي، Ay هتكون باتجاه الـ Y. ممكن
+
+36
+00:03:08,080 --> 00:03:11,680
+آخذ أنا المتجه اللي باتجاه الـ Y، موازٍ لها اللي هي
+
+37
+00:03:11,680 --> 00:03:16,220
+بالشكل هذا. صار عندي Ay = A sin θ. فهذا
+
+38
+00:03:16,220 --> 00:03:19,840
+المتجه الأول، هذا المتجه الثاني، والـ A اللي هي
+
+39
+00:03:19,840 --> 00:03:24,240
+المحصلة اللي هي بهذا الشكل. لو كان عندي أنا المتجه
+
+40
+00:03:24,240 --> 00:03:28,600
+A بيصنع زاوية θ مع اتجاه Y. ف دائماً الزاوية
+
+41
+00:03:28,600 --> 00:03:33,420
+التي، طبعاً المحور الذي بجانب الزاوية، لما آجي أنا يعني
+
+42
+00:03:33,420 --> 00:03:37,640
+أحلل إلى المكونات، في مكونة هذه اللي مع الخط الـ Y
+
+43
+00:03:37,640 --> 00:03:42,180
+الذي بجانب الزاوية بسميها A cos θ في هذه الحالة Ay،
+
+44
+00:03:42,180 --> 00:03:47,840
+مركبة الـ vertical، مركبة الصادية اللي هي A cos θ،
+
+45
+00:03:47,840 --> 00:03:52,800
+و المركبة السينية هتكون A sin θ لإنه الزاوية قريبة من
+
+46
+00:03:52,800 --> 00:04:00,100
+محور Y. معادلة 1.4 for the x and y components of the
+
+47
+00:04:00,100 --> 00:04:03,760
+vector: associated cosine with x component and sine
+
+48
+00:04:03,760 --> 00:04:09,340
+with y component. طبعاً المعادلة السابقة تؤكد
+
+49
+00:04:09,340 --> 00:04:13,960
+أنّ المركبة الـ X هي عبارة عن المتجه في cos θ،
+
+50
+00:04:13,960 --> 00:04:17,740
+ومركبة الـ Y هي عبارة عن قيمة المتجه في sin θ. إذا
+
+51
+00:04:17,740 --> 00:04:23,220
+كانت الزاوية بتصنع زاوية θ مع اتجاه x الموجب.
+
+52
+00:04:24,450 --> 00:04:28,910
+طبعاً هذا الكلام if the angle were measured with
+
+53
+00:04:28,910 --> 00:04:33,570
+respect to the Y. لو الزاوية كانت قريبة من الـ Y،
+
+54
+00:04:33,570 --> 00:04:39,230
+يعني فالمجاور للزاوية يعتبر A cos θ، والعمود الذي
+
+55
+00:04:39,230 --> 00:04:45,550
+هو بالـ X بكون A sin θ. Inverse tangent on calculator.
+
+56
+00:04:45,550 --> 00:04:50,910
+طبعاً بالنسبة للألة الحاسبة، the inverse tangent
+
+57
+00:04:50,910 --> 00:04:54,090
+function on the calculator returns an
+
+58
+00:04:54,090 --> 00:05:01,750
+angle between -90° and +90°. If
+
+59
+00:05:01,750 --> 00:05:07,430
+الآن إذا كان المتجه المعطى يقع في الربع الثاني
+
+60
+00:05:07,430 --> 00:05:13,270
+والربع الثالث، فالزاوية التي تطلع لازم أضيف لها
+
+61
+00:05:13,270 --> 00:05:19,310
+180° . طبعاً هذا شرط إذا كان المتجه المعطى
+
+62
+00:05:19,310 --> 00:05:24,090
+يقع في الربع الثاني أو الربع الثالث، فإن هذا إيجاد
+
+63
+00:05:24,090 --> 00:05:27,150
+الـ direction. هذا أوجد الزاوية، وبعد إيجاد الزاوية
+
+64
+00:05:27,150 --> 00:05:34,960
+نضيف للمتجه 180°. نجي لـ Quick Quiz، Quiz سريع
+
+65
+00:05:34,960 --> 00:05:38,680
+حسب ما إحنا فهمنا، هذا الشكل الذي... الذي طبعاً
+
+66
+00:05:38,680 --> 00:05:42,820
+الموجود أمامنا shows two vectors. في عندي أنا
+
+67
+00:05:42,820 --> 00:05:48,060
+متجهين: متجه موجود في الربع الثاني اسمه A، ومتجه
+
+68
+00:05:48,060 --> 00:05:53,520
+موجود في الربع الرابع اسمه B. المطلوب مني determine
+
+69
+00:05:53,520 --> 00:05:58,340
+the sign of x and y components. بدي أوجد إشارة
+
+70
+00:05:58,340 --> 00:06:05,010
+المركبات A ومركبات B. زي ما إحنا شايفين في هذا الشكل،
+
+71
+00:06:05,010 --> 00:06:10,790
+مركبة A، مركبة A، عند تحليل الـ A إلى مركبتين هتكون
+
+72
+00:06:10,790 --> 00:06:15,730
+مركبة في هذا الاتجاه بـ -X ومركبة في الـ Y. معنى
+
+73
+00:06:15,730 --> 00:06:22,050
+الكلام الـ X لهذا المتجه A بيساوي سالب، والـ Y للمتجه
+
+74
+00:06:22,050 --> 00:06:27,370
+A موجب. بالنسبة للمتجه B، المركبة السينية موجبة
+
+75
+00:06:27,370 --> 00:06:32,470
+والمركبة الصادية سالبة. إذا إحنا حللناها بالنسبة
+
+76
+00:06:32,470 --> 00:06:37,630
+لهذا المتجه A والمتجه B. لو أنا أوجدت A + B طبعاً
+
+77
+00:06:37,630 --> 00:06:42,550
+المتجه A والمتجه B ما بِينفعش أنا أوجد اللي هي المحصلة
+
+78
+00:06:42,550 --> 00:06:46,820
+من A إلى B، فلازم أنا لأن الاثنين طالعين من نفس النقطة
+
+79
+00:06:46,820 --> 00:06:52,180
+ومن نفس الذيل، لازم أكمل متوازي الأضلاع. بأكمل
+
+80
+00:06:52,180 --> 00:06:56,080
+متوازي الأضلاع، وبطلع من هذه النقطة هي المحصلة
+
+81
+00:06:56,080 --> 00:06:59,840
+بتكون بهذا الاتجاه، المحصلة بتكون بهذا الاتجاه، و
+
+82
+00:06:59,840 --> 00:07:05,140
+بالتالي بتكون المحصلة باتجاه -X و -Y، كما
+
+83
+00:07:05,140 --> 00:07:11,440
+هو موضح في الجدول الذي هو قدامنا. طبعاً هنا المتجه A
+
+84
+00:07:11,440 --> 00:07:16,360
+زي ما اتفقنا في الـ X component كانت سالب، والمركبة
+
+85
+00:07:16,360 --> 00:07:20,920
+الـ Y موجبة. المتجه B موجود في الربع الرابع. إذاً
+
+86
+00:07:20,920 --> 00:07:25,940
+الربع الرابع بيكون الـ X موجب، والـ Y سالب. في A
+
+87
+00:07:25,940 --> 00:07:32,280
++ B، لما أوجد أنا محصلة A + B، فبتكون المحصلة
+
+88
+00:07:32,280 --> 00:07:37,260
+موجودة في الربع الثالث. فالربع الثالث بيكون الـ X
+
+89
+00:07:37,260 --> 00:07:40,580
+مركبته الـ X سالب، مركبة الـ Y سالب.
+
+90
+00:07:42,930 --> 00:07:50,190
+الـ Quiz 1.3. من الشكل 1.19 طبعاً يظهر عندي
+
+91
+00:07:50,190 --> 00:07:53,990
+shows two vectors. في عندي متجهين lying in the XY
+
+92
+00:07:53,990 --> 00:07:58,950
+plane. متجهين موجودين في مستوى XY، يعني بيسموها
+
+93
+00:07:58,950 --> 00:08:02,480
+rectangular coordinate أو two dimensions. Which
+
+94
+00:08:02,480 --> 00:08:05,760
+vector has an angle with respect to the positive x
+
+95
+00:08:05,760 --> 00:08:10,220
+axis that is in the range of the inverse tangent
+
+96
+00:08:10,220 --> 00:08:16,540
+function؟ الشكل المبين هنا، عندي أنا متجهين: متجه A و
+
+97
+00:08:16,540 --> 00:08:20,500
+متجه B. السؤال اللي بيحكي لنا: مين من هدول المتجهات
+
+98
+00:08:20,500 --> 00:08:27,830
+يصنع زاوية سالبة مع اتجاه X الموجب؟ فمين المتجهين؟ هل
+
+99
+00:08:27,830 --> 00:08:32,290
+الـ B يصنع سالب مع اتجاه X الموجب؟ لأ. ف أنا بيعني
+
+100
+00:08:32,290 --> 00:08:37,470
+الجواب إنّه هو المتجه B هو اللي بيصنع طبعاً زاوية
+
+101
+00:08:37,470 --> 00:08:41,030
+سالبة. إذا أنا مشيت من اتجاه الـ X الموجب ومشيت مع
+
+102
+00:08:41,030 --> 00:08:45,070
+عقارب الساعة، فبتظهر عندي هذه اللي هي الزاوية سالبة.
+
+103
+00:08:45,070 --> 00:08:49,550
+لو أنا مشيت مع اتجاه الـ X، عكس اتجاه عقارب الساعة بيكون أنا
+
+104
+00:08:49,550 --> 00:08:54,720
+ماشي اتجاه الموجب. لكن باتجاه الـ -X axis بكون
+
+105
+00:08:54,720 --> 00:09:01,260
+... بكون مع اتجاه عقارب الساعة. فالجواب هو الـ vector B.
+
+106
+00:09:01,260 --> 00:09:08,790
+ناخذ هذا الـ example. بحكي للـ example: find أوجد the
+
+107
+00:09:08,790 --> 00:09:12,090
+horizontal and vertical components of the vector D.
+
+108
+00:09:12,090 --> 00:09:19,310
+أوجد المركبة الأفقية والمركبة الرأسية لـ متجه
+
+109
+00:09:19,310 --> 00:09:25,010
+متجه، يعني مقداره D = 1.2 متر،
+
+110
+00:09:25,010 --> 00:09:29,820
+displacement of superhero. في عندي شخص خارق، بدو
+
+111
+00:09:29,820 --> 00:09:35,700
+يتحرك إزاحة من نقطة الأصل، وبدو يمشي مسافة D اللي
+
+112
+00:09:35,700 --> 00:09:39,540
+هي عبارة عن 1.2 متر، وبيصنع زاوية
+
+113
+00:09:39,540 --> 00:09:43,280
+30° مع اتجاه X السالب. في هذه الزاوية مطلوب مني
+
+114
+00:09:43,280 --> 00:09:49,050
+أوجد الـ X and Y components. من خلال الشكل، من خلال
+
+115
+00:09:49,050 --> 00:09:54,890
+الشكل. D تمثل متجه، هذا المتجه لما آجي أوجد مركباته
+
+116
+00:09:54,890 --> 00:09:59,630
+يعني أحلله، هيظهر عندي أنا مركبتين. هذا المتجه
+
+117
+00:09:59,630 --> 00:10:03,850
+موجود في الربع الرابع، فمركبته السينية هتكون موجبة
+
+118
+00:10:03,850 --> 00:10:09,350
+والمركبة الصادية هتكون سالبة. بمعنى آخر عند إيجاد
+
+119
+00:10:09,350 --> 00:10:14,070
+المركبة السينية راح أستخدم إنّه الـ X اللي هي
+
+120
+00:10:14,070 --> 00:10:18,730
+الزاوية سالبة. إذاً الـ Ax ... أطبّق القوانين: Ax
+
+121
+00:10:18,730 --> 00:10:22,550
+بتساوي A cos θ، الـ A اللي هي عبارة عن المتجه
+
+122
+00:10:22,550 --> 00:10:29,430
+1.2 cos (-30°). Ay بتساوي A sin θ،
+
+123
+00:10:29,430 --> 00:10:34,710
+بتساوي 1.2 sin (-30°). فالجواب طلع عندي
+
+124
+00:10:34,710 --> 00:10:39,130
+مركبته السينية موجبة والمركبة الصادية سالبة، وهذا
+
+125
+00:10:39,130 --> 00:10:46,340
+بيؤكد أنّ هذا المتجه يقع في الربع الرابع. المطلوب الـ
+
+126
+00:10:46,340 --> 00:10:49,940
+B: find the magnitude and direction of the
+
+127
+00:10:49,940 --> 00:10:55,120
+displacement vector B. أعطاني متجه B، المتجه B
+
+128
+00:10:55,120 --> 00:11:00,000
+المركبة السينية أعطانيها -25، والمركبة الصادية
+
+129
+00:11:00,000 --> 00:11:06,690
+أعطانيها 10. يعني السينية -25 والصادية موجب. معنى
+
+130
+00:11:06,690 --> 00:11:11,850
+الكلام هذا المركبة B موجودة في الربع الثاني
+
+131
+00:11:11,850 --> 00:11:18,470
+لأن X سالب و Y موجب. عند إيجاد الـ magnitude،
+
+132
+00:11:18,470 --> 00:11:23,370
+عندما أوجد اللي هي القيمة الـ B كـ magnitude، بطبّق
+
+133
+00:11:23,370 --> 00:11:28,750
+القانون: B = √(Bx² + By²)، وبأخذ
+
+134
+00:11:28,750 --> 00:11:33,010
+الـ Bx بإشارتها وأربعها، و By بإشارتها وأربعها، و
+
+135
+00:11:33,010 --> 00:11:38,150
+الجواب 26.9. عند إيجاد الـ direction، معنى الكلام
+
+136
+00:11:38,150 --> 00:11:41,290
+يعني أنا بدي أوجد الزاوية، الزاوية اللي أنا بدي
+
+137
+00:11:41,290 --> 00:11:45,690
+أوجدها طبعاً بعوض في القانون اللي هي θ = tan⁻¹
+
+138
+00:11:45,690 --> 00:11:52,750
+(By / Bx). بأوجد By / Bx، وبأضعها
+
+139
+00:11:52,750 --> 00:11:57,090
+بإشارتها موجبة، و Bx إشارتها -25.
+
+140
+00:11:57,090 --> 00:12:02,400
+الآن الجواب -21.8°. هل يا
+
+141
+00:12:02,400 --> 00:12:07,380
+ترى أجمع لها 180° ولا أخليها زي ما هي؟ بروح للسؤال.
+
+142
+00:12:07,380 --> 00:12:12,760
+طبعاً طالما أنّ الـ X باتجاه الـ -X والـ Y موجب، إذاً
+
+143
+00:12:12,760 --> 00:12:17,920
+هذا المتجه هيكون في الربع الثاني، وإحنا اتفقنا أنّ
+
+144
+00:12:17,920 --> 00:12:23,340
+أي متجه يعطيني إياه موجود في الربع الثاني أو
+
+145
+00:12:23,340 --> 00:12:29,020
+الثالث، بضيف 180° للزاوية. إذن الزاوية هذه اللي طلعت لي
+
+146
+00:12:29,020 --> 00:12:33,780
+أنا راح أضيف لها 180°، بتطلع عندي 158.2°. فعلاً الـ 158.2°
+
+147
+00:12:33,780 --> 00:12:39,380
+موجودة في الربع الثاني. طبعاً هذه الـ 158.2° مقاسة من اتجاه X الموجب لغاية المتجه وهو يقع
+
+148
+00:12:39,380 --> 00:12:46,200
+في الربع الثاني. طبعاً هذا الـ section بدنا... بدنا
+
+149
+00:12:46,200 --> 00:12:51,250
+نشرح adding vectors... vectors algebraically. يعني
+
+150
+00:12:51,250 --> 00:12:55,210
+بدي أنا أشرح كيف أنا ممكن أجمع متجهات بطريقة
+
+151
+00:12:55,210 --> 00:13:00,690
+جبرية، طريقة جبرية حسابية يعني. ببدأ أفرض في عندي
+
+152
+00:13:05,090 --> 00:13:10,430
+أنا متجه R = A + B، يعني هذا الـ R ممثل
+
+153
+00:13:10,430 --> 00:13:17,210
+للمحصلة بين متجهين A و B. الآن A لها مركبات، A لها
+
+154
+00:13:17,210 --> 00:13:24,530
+مركبات Ax و Ay، و B لها مركبات Bx و By. عند إيجاد الـ
+
+155
+00:13:24,530 --> 00:13:30,110
+Rx طبعاً بأجمع كل مركبات الـ X لمين؟ للمتجه A + B.
+
+156
+00:13:30,110 --> 00:13:36,970
+إذاً الـ Rx هذه تساوي A باتجاه الـ X + B باتجاه الـ X. Ry
+
+157
+00:13:36,970 --> 00:13:41,790
+بتساوي A باتجاه Y + B باتجاه الـ Y. ما بِينفعش أجمع Ax مع
+
+158
+00:13:41,790 --> 00:13:47,830
+By، ما بِينفعش أجمع Ax مع Ay. ما بِينجمعوا. وبالتالي فـ الـ X
+
+159
+00:13:47,830 --> 00:13:52,630
+component are adding only to x component. يعني الـ X
+
+160
+00:13:52,630 --> 00:13:57,850
+بدي أجمع متجهات جمع جبري، بأجمع الـ X مع الـ X والـ Y
+
+161
+00:13:57,850 --> 00:14:02,670
+مع الـ Y. ولكن بدي أراعي الإشارات إذا كان أي متجه
+
+162
+00:14:02,870 --> 00:14:08,010
+يتجه إلى اليمين أو الشرق بيكون موجب، إلى اليسار
+
+163
+00:14:08,010 --> 00:14:13,310
+بيكون سالب، إلى أعلى بيكون موجب، إلى أسفل بيكون سالب.
+
+164
+00:14:13,310 --> 00:14:18,890
+وبالتالي محصلة الـ R كـ magnitude أو كقيمة بيساوي
+
+165
+00:14:18,890 --> 00:14:25,830
+√(Rx² + Ry²) والـ direction بيساوي
+
+166
+00:14:25,830 --> 00:14:29,890
+tan⁻¹ لمين؟ إذا أنا الـ direction يعني بدي قيمة
+
+167
+00:14:29,890 --> 00:14:34,660
+الـ θ، بأوجد tan θ = Ry / Rx، وبعدين
+
+168
+00:14:34,660 --> 00:14:38,280
+بأوجد الـ θ اللي هي عبارة عن tan⁻¹ (Ry / Rx) على
+
+169
+00:14:38,280 --> 
+
+223
+00:19:12,400 --> 00:19:20,030
+بالسالب X بالموجب، و Y بالسالب، X بالموجبة، و Y
+
+224
+00:19:20,030 --> 00:19:23,910
+بالسالب معناته ده موجودة بالربع الرابع، الآن بدي
+
+225
+00:19:23,910 --> 00:19:30,330
+أوجد مركبات الـ B بي X و بي Y، اتجاه الـ 60 كانت
+
+226
+00:19:30,330 --> 00:19:36,270
+شمال الشرق، وبالتالي الـ 60 كانت موجبة، إذا الـ بي X
+
+227
+00:19:36,270 --> 00:19:41,230
+بتساوي بي كوزاين الـ 60، و بي Y بي ساين الـ 60، تطلع عندي
+
+228
+00:19:41,230 --> 00:19:48,870
+20 كم، و هنا 34.6 كم، الآن لإيجاد المحصلة، الآن إيجاد
+
+229
+00:19:48,870 --> 00:19:53,310
+المحصلة الـ R بتساوي المتجه E زائد المتجه B، إذا الـ
+
+230
+00:19:53,310 --> 00:19:58,530
+R هذه المركبات الخاصة بالـ R، R X و R Y، R X بتساوي A
+
+231
+00:19:58,530 --> 00:20:05,310
+X زائد B X، و R Y بتساوي A Y زائد B Y، إذا R X طلعت
+
+232
+00:20:05,310 --> 00:20:11,450
+بـ 37.7 موجبة كيلومتر، و R Y طلعت موجبة بـ 16.9 كيلومتر
+
+233
+00:20:11,450 --> 00:20:15,850
+الآن X موجبة، و Y موجبة، معناها المحصلة موجودة في
+
+234
+00:20:15,850 --> 00:20:22,010
+الربع الأول، لإيجاد الـ magnitude للـ R، إذن R بدها
+
+235
+00:20:22,010 --> 00:20:29,070
+تساوي جذر R X تربيع زائد R Y تربيع، وطبعا هاد الـ R
+
+236
+00:20:29,070 --> 00:20:35,310
+تمثل الـ magnitude، بدها تساوي 41.3 كيلومتر، فيتا
+
+237
+00:20:35,310 --> 00:20:44,050
+بتساوي تان انفرس لـ Ry على Rx، بتساوي 24.1، هذه
+
+238
+00:20:44,050 --> 00:20:51,900
+عبارة عن اتجاه المحصلة، هل أجمع للـ 24.1، 180؟ ليش؟
+
+239
+00:20:51,900 --> 00:20:57,640
+لإن R X موجبة، R Y موجبة، وبالتالي طلع عندي اللي هي
+
+240
+00:20:57,640 --> 00:21:02,240
+موجبة، موجبة، إذا المحصلة بالربع الأول، طبعا ما بيلزم إن
+
+241
+00:21:02,240 --> 00:21:09,280
+أنا أجمع لها اللي هي الـ 180 درجة، section 1.11، طبعا
+
+242
+00:21:09,280 --> 00:21:15,600
+بيشرح problem solving strategy كيف أنا ممكن أحل أي
+
+243
+00:21:15,600 --> 00:21:21,910
+مسألة فيزيائية، بالبداية بقرأ السؤال، نمر اثنين، draw
+
+244
+00:21:21,910 --> 00:21:26,350
+diagram، أرسم السؤال، ثلاثة، label physical quantity
+
+245
+00:21:26,350 --> 00:21:30,750
+أبدأ أُحدد الكميات الفيزيائية، نمر أربعة، identify
+
+246
+00:21:30,750 --> 00:21:35,710
+principles، list data، نمر خمسة، choose equation، بختار
+
+247
+00:21:35,710 --> 00:21:40,370
+المعادلة المناسبة، نمر ستة، بحل solve المعادلة، بحل
+
+248
+00:21:40,370 --> 00:21:46,910
+المعادلات، وبعد هيك بعود طبعا بالقيم المعروفة، و
+
+249
+00:21:46,910 --> 00:21:51,730
+بعد هيك بـ check answer، بأفحص اللي هو الجواب تبعي
+
+250
+00:21:51,730 --> 00:21:56,400
+هل صحيح أم لا، طبعا general problem solving strategy
+
+251
+00:21:56,400 --> 00:22:02,000
+لأي مسألة، أول حاجة إحنا بنقرأ السؤال كويس وبنشوف
+
+252
+00:22:02,000 --> 00:22:06,120
+إيش الكميات اللي عندنا، بنرسم السؤال كـ diagram
+
+253
+00:22:06,120 --> 00:22:10,960
+بعدين بحدد الـ label على هذا الـ diagram، بحدد لكل
+
+254
+00:22:10,960 --> 00:22:15,560
+طبعا جزء، إيش العناصر أو الكميات الفيزيائية الممثلة له
+
+255
+00:22:15,560 --> 00:22:22,430
+هل هو ماس، هل هو مثلا طول، هل هو زمن، بعد هيك بحدد
+
+256
+00:22:22,430 --> 00:22:25,310
+اللي هي أساسيات، اللي هي القانون الفيزيائي اللي أنا
+
+257
+00:22:25,310 --> 00:22:29,750
+ممكن أحل عليه، أو المعادلات اللازمة، ثم أحل هذه
+
+258
+00:22:29,750 --> 00:22:34,270
+المعادلات لإيجاد ايه المتغيرات اللازمة، وبنفحص
+
+259
+00:22:34,270 --> 00:22:39,370
+طبعا الإجابة، هل يعني هل هي تتوافق مع الحل أم لا
+
+260
+00:22:39,970 --> 00:22:44,830
+طبعا آخر سؤال في هذا الـ chapter، السؤال القادم هو
+
+261
+00:22:44,830 --> 00:22:50,530
+عبارة عن problems 114، هذا السؤال هو عبارة عن شخص
+
+262
+00:22:50,530 --> 00:22:54,670
+leaves home and drives to a store located 7
+
+263
+00:22:54,670 --> 00:22:59,030
+kilometer away in a direction 30 درجة north of
+
+264
+00:22:59,030 --> 00:23:04,110
+east، أحد الأشخاص أو الرجال أو الشخص طبعا بيتسوق
+
+265
+00:23:04,110 --> 00:23:08,270
+leaves home، ترك بيته، and drive to a store، ذهب إلى
+
+266
+00:23:08,270 --> 00:23:14,570
+مكان الـ store، المخازن، عشان يشتري بعض الحاجيات، يبعد
+
+267
+00:23:14,570 --> 00:23:17,950
+سبعة كيلومتر، away in a direction، كان ماشي سبعة
+
+268
+00:23:17,950 --> 00:23:22,970
+كيلو في اتجاه ثلاثين درجة، north of east، north of
+
+269
+00:23:22,970 --> 00:23:27,580
+east، ثلاثين درجة شمال الشرق، بعد هيك ترك المكان
+
+270
+00:23:27,580 --> 00:23:33,760
+ومشي كمان إلى بـ .. بمشوار أو مسافة خمسة كيلومتر في
+
+271
+00:23:33,760 --> 00:23:38,160
+اتجاه خمسين درجة، west of north، يعني غرب الشمال
+
+272
+00:23:38,160 --> 00:23:43,020
+find the distance and direction from the shopper’s
+
+273
+00:23:43,020 --> 00:23:47,380
+home to the restaurant، المطلوب مني أوجد الإزاحة
+
+274
+00:23:47,380 --> 00:23:52,120
+أو المسافة اللي مشيها، واتجاهه خلال هذا المشوار أو
+
+275
+00:23:52,120 --> 00:23:57,920
+خلال طبعا رحلته أو مشواره، من المكان بيته طبعا
+
+276
+00:23:57,920 --> 00:24:02,100
+استراتيجيا، يعني كيف أنا ممكن أحل، we finished
+
+277
+00:24:02,100 --> 00:24:05,820
+reading the problem، طبعا أول حاجة بنقرأ السؤال
+
+278
+00:24:05,820 --> 00:24:09,880
+and draw a diagram، بدأ أرسم الـ diagram، طبعا الشكل
+
+279
+00:24:09,880 --> 00:24:15,620
+الموضح أسفل هو بيمثل اللي هو السؤال، بعد هيك we
+
+280
+00:24:15,620 --> 00:24:18,160
+recognize that the vectors are located the results
+
+281
+00:24:18,160 --> 00:24:23,840
+طبعا من خلال السؤال بحدد اللي هي المحصلة، الآن هي
+
+282
+00:24:23,840 --> 00:24:28,930
+الـ home هي البيت، ماشي، ماشي هذا المشوار أو المتجه
+
+283
+00:24:28,930 --> 00:24:34,310
+الأول، بزاوية ثلاثين درجة، بتميل الزاوية شمال الشرق
+
+284
+00:24:34,310 --> 00:24:37,630
+قريبة من الشرق ثلاثين درجة، بعد هيك انتهى هنا
+
+285
+00:24:37,630 --> 00:24:41,870
+المتجه، بدأ المشوار الثاني، المشوار الثاني ماشي
+
+286
+00:24:41,870 --> 00:24:46,910
+خمسين درجة غرب الشمال، يعني الخمسين قريبة من الشمال
+
+287
+00:24:46,910 --> 00:24:52,010
+بعد هيك أخلص، إذا المحصلة هتكون من البيت من بداية
+
+288
+00:24:52,010 --> 00:24:55,550
+المتجه لغاية نهاية اللي هو الـ restaurant، لغاية ما
+
+289
+00:24:55,550 --> 00:24:59,680
+هو ايه توقف، طبعا نحل زي ما حلنا بالسابق، بدي أجيب
+
+290
+00:24:59,680 --> 00:25:04,720
+المركبة السينية والصادية للمتجه الأول، أنا عندي R
+
+291
+00:25:04,720 --> 00:25:10,320
+المحصلة عبارة عن A زائد B، راح أوجد Rx اللي هي Ax
+
+292
+00:25:10,320 --> 00:25:17,970
+زائد Bx، Ry بتساوي Ay زائد By، بلاحظ طبعا أن اللي هي
+
+293
+00:25:17,970 --> 00:25:22,730
+substitute the numbers with units، step 7، the
+
+294
+00:25:22,730 --> 00:25:26,770
+direction of B measured counter clockwise from the
+
+295
+00:25:26,770 --> 00:25:34,210
+positive x axis، لأنه الـ .. لأنه الرجل ماشي عكس آخر
+
+296
+00:25:34,210 --> 00:25:39,950
+الساعة، بزاوية ثلاثين درجة، إذا في اتجاه x الموجب، إذا Rx
+
+297
+00:25:39,950 --> 00:25:43,350
+بتساوي 7 المسافة اللي ماشيها، kilometer، cosine
+
+298
+00:25:43,350 --> 00:25:50,040
+الثلاثين، Ry بتساوي سبعة كيلومتر ساين الثلاثين، راح
+
+299
+00:25:50,040 --> 00:25:54,420
+أجمع لها اللي هي مين هذه، طبعا Ax، المشوار الأول
+
+300
+00:25:54,420 --> 00:25:58,680
+المشوار الثاني كان خمسة كيلومتر كوزاين المئة
+
+301
+00:25:58,680 --> 00:26:05,740
+وأربعين، وخمسة كيلومتر ساين المئة وأربعين، بتساوي 2
+
+302
+00:26:05,740 --> 00:26:10,620
+point، طبعا ثلاثة وعشرين كيلومتر، طبعا من وأنا
+
+303
+00:26:10,620 --> 00:26:15,520
+جيت الـ 140، طرحنا الـ 180، نقص الـ 50، طلعت عندي أنا
+
+304
+00:26:15,520 --> 00:26:21,500
+اللي هي الـ 140 درجة، عشان أحطها طبعا بالموجب، فالجواب
+
+305
+00:26:21,500 --> 00:26:26,120
+النهائي، هي باستخدام المحصلة، القانونية للـ
+
+306
+00:26:26,120 --> 00:26:32,280
+magnitude، بتساوي جذر R X تربيع زائد R Y تربيع، 2
+
+307
+00:26:32,280 --> 00:26:37,780
+.23 كيلومتر تربيع زائد 6.7، طبعا هذه موجبة، موجبة، إذا
+
+308
+00:26:37,780 --> 00:26:40,660
+موجودة في الربع الأول، هي المحصلة موجودة في الربع
+
+309
+00:26:40,660 --> 00:26:46,440
+الأول، بتساوي 7.07 كيلومتر، اتجاه المحصلة فيتا
+
+310
+00:26:46,440 --> 00:26:51,840
+بتساوي تان انفرس Ry على Rx، فبحط الـ Ry إشارتها
+
+311
+00:26:51,840 --> 00:26:58,720
+موجبة، Rx إشارتها موجبة، بتساوي 71.6 درجة، هيك إحنا
+
+312
+00:26:58,720 --> 00:27:03,480
+طبعا حددنا أي متجه، كـ magnitude للمتجه عبارة عن
+
+313
+00:27:03,480 --> 00:27:08,200
+طبعا Rx تربيع زائد Ry تربيع، اتجاه المحصلة هيكون
+
+314
+00:27:08,200 --> 00:27:14,540
+تان انفرس Ry على Rx، وبهذا بنكون طبعا انتهينا من
+
+315
+00:27:14,540 --> 00:27:20,500
+تسجيل وشرح الفصل الأول من فيزياء عامة لطلبة العلوم
+
+316
+00:27:20,500 --> 00:27:21,080
+الصحية
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..88ad2ac664d40c63682fc6e57b6818d44057c06d
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs_postprocess.srt
@@ -0,0 +1,1264 @@
+1
+00:00:00,000 --> 00:00:05,260
+بسم الله الرحمن الرحيم نستكمل chapter one بعنوان
+
+2
+00:00:05,260 --> 00:00:11,300
+units and vectors ووصلنا ل section 11 بعنوان
+
+3
+00:00:11,300 --> 00:00:16,740
+component of a vector consider a vector a in a
+
+4
+00:00:16,740 --> 00:00:20,360
+rectangular coordinate system بأفرض في عندي متجه a
+
+5
+00:00:21,020 --> 00:00:24,580
+المتجه A موجود في الـ Coordinate Rectangular
+
+6
+00:00:24,580 --> 00:00:29,860
+System بمستوى طبعا X و Y A can be expressed as the
+
+7
+00:00:29,860 --> 00:00:32,920
+sum of the two vectors الـ A ممكن أنا أمثله
+
+8
+00:00:32,920 --> 00:00:39,840
+بمتجهين أو مركبتين بيسموه component vectors الـ A
+
+9
+00:00:39,840 --> 00:00:45,300
+هذه ممكن أنا أقسمها إلى A باتجاه الـ X و A باتجاه
+
+10
+00:00:45,300 --> 00:00:50,660
+الـ Yax وay يسموا are component vectors عبارة عن
+
+11
+00:00:50,660 --> 00:00:56,800
+مراكبات المتجه a ax is called x component of a ax
+
+12
+00:00:56,800 --> 00:01:03,830
+بسميها المراكبة الصينية ل aand ay is called the y
+
+13
+00:01:03,830 --> 00:01:09,130
+component of a these components can be either
+
+14
+00:01:09,130 --> 00:01:12,410
+positive or negative numbers with unit the
+
+15
+00:01:12,410 --> 00:01:17,550
+component of a are الآن هذه المركبات ممكن تكون
+
+16
+00:01:17,550 --> 00:01:25,530
+موجبة أو سالبة طبعا حسب اتجاه المتجه a the
+
+17
+00:01:25,530 --> 00:01:30,750
+component of a مركبات ال a اللي هي ال axتساوي A
+
+18
+00:01:30,750 --> 00:01:36,110
+Cos θ الـ θ هذه الزاوية اللتي يصنعها المتجه مع
+
+19
+00:01:36,110 --> 00:01:42,570
+اتجاه X الموجب Ay بتساوي A Sin θ يعني حللنا المتجه
+
+20
+00:01:42,570 --> 00:01:48,650
+A إلى مركبتين مركبة موازية للمستوى X ومركبة عمودية
+
+21
+00:01:48,650 --> 00:01:56,050
+الموازية ل X تسمى A Cos وعمودية على X تسمى A SinIt
+
+22
+00:01:56,050 --> 00:01:58,790
+follows that A's magnitude and direction are
+
+23
+00:01:58,790 --> 00:02:01,130
+related to its component through the following
+
+24
+00:02:01,130 --> 00:02:07,330
+relation الآن ممكن أوجد أنا محصلة متجهين أو مجموعة
+
+25
+00:02:07,330 --> 00:02:13,130
+متجهات كالتالي A بدها تساوي A X تربيع زائد A Y
+
+26
+00:02:13,130 --> 00:02:16,590
+تربيع هذه بسميها ال magnitude of the vectors يعني
+
+27
+00:02:16,590 --> 00:02:22,540
+قيمة ال vector كعدد القيمة العددية على المتجه Aعند
+
+28
+00:02:22,540 --> 00:02:27,760
+إيجاد الـ direction بأوجد tan theta اللي هي عبارة
+
+29
+00:02:27,760 --> 00:02:32,280
+عن ay على ax ثم أوجد theta عبارة عن tan inverse
+
+30
+00:02:32,280 --> 00:02:39,240
+لay على ax و بأكتب ال ay ب ال b طبعا إشارتها موجب
+
+31
+00:02:39,240 --> 00:02:42,920
+أو سالب و ال ax بإشارتها موجب أو سالب لإيجاد
+
+32
+00:02:42,920 --> 00:02:48,910
+الزاويةلو أنا عندى الآن بهذا الشكل موضح عندى متجه
+
+33
+00:02:48,910 --> 00:02:55,030
+A متجه A بيصنع زاوية θ مع مأة اتجاه X الموجب لما
+
+34
+00:02:55,030 --> 00:02:58,690
+أحلل القلة المقنعة لمتجه A راح أحللها إلى مركبة
+
+35
+00:02:58,690 --> 00:03:02,790
+تانية مركبة باتجاه ال X axis يعني AX بتساوي A
+
+36
+00:03:02,790 --> 00:03:08,080
+cosineو أي بدها تساوي أي هتكون باتجاه ال Y ممكن
+
+37
+00:03:08,080 --> 00:03:11,680
+اخد انا المتجه اللي باتجاه ال Y موازي Lه اللي هي
+
+38
+00:03:11,680 --> 00:03:16,220
+بالشكل هذا صار عندي أي بالساوية A sin θ فهذا
+
+39
+00:03:16,220 --> 00:03:19,840
+المتجه الأول هذا المتجه التاني وال A اللي هي
+
+40
+00:03:19,840 --> 00:03:24,240
+المحصلة اللي هي بهذا الشكللو كان عندى انا المتجه
+
+41
+00:03:24,240 --> 00:03:28,600
+ايه بيصنع زاوية θيتا مع اتجاه Y فدائما الزاوية
+
+42
+00:03:28,600 --> 00:03:33,420
+اللى طبعا المحور اللى جنب الزاوية لما اجى انا يعني
+
+43
+00:03:33,420 --> 00:03:37,640
+احلل الى المراكبات فى مراكبة هذه اللى مع الخط ال Y
+
+44
+00:03:37,640 --> 00:03:42,180
+اللى جنب الزاوية بسميهاA cos في هذه الحالة Ay
+
+45
+00:03:42,180 --> 00:03:47,840
+مركبة ال vertical مركبة الصادية اللي هي A cos
+
+46
+00:03:47,840 --> 00:03:52,800
+والمركبة الصينية هتكون A sin لإنه الزاوية قريبة من
+
+47
+00:03:52,800 --> 00:04:00,100
+محور Yمعادلة 1.4 for the x and y components of the
+
+48
+00:04:00,100 --> 00:04:03,760
+vector associated cosine with x component and sine
+
+49
+00:04:03,760 --> 00:04:09,340
+with a with y component طبعا المعادلة السابقة تؤكد
+
+50
+00:04:09,340 --> 00:04:13,960
+إنه ال X مركبة ال X هي عبارة عن المتجه في cosine
+
+51
+00:04:13,960 --> 00:04:17,740
+مركبة ال Y هي عبارة عن قيمة المتجه في sine إذا
+
+52
+00:04:17,740 --> 00:04:23,220
+كانت الزاوية بتصنع زاوية فيتا مع اتجاه x a الموجب
+
+53
+00:04:24,450 --> 00:04:28,910
+طبعا هذا الكلام if the angle were measured with
+
+54
+00:04:28,910 --> 00:04:33,570
+respect to the Y لو الزاوية كانت قريبة من ال Y
+
+55
+00:04:33,570 --> 00:04:39,230
+يعني فالمجاور الزاوية يعتبر A cosine والعمود اللي
+
+56
+00:04:39,230 --> 00:04:45,550
+هو بال X بكون A sineinverse tangent on calculator
+
+57
+00:04:45,550 --> 00:04:50,910
+طبعا بالنسبة للألة الحاسبة the inverse inverse
+
+58
+00:04:50,910 --> 00:04:54,090
+tangent function on the calculator returns at
+
+59
+00:04:54,090 --> 00:05:01,750
+angle between between ناقص تسعين وزائد تسعين if
+
+60
+00:05:01,750 --> 00:05:07,430
+الآن إذا كان المتجه المعطى يقع في الربع التاني
+
+61
+00:05:07,430 --> 00:05:13,270
+والربع التالتفالزاوية اللى بتطلع لازم أضيف لها
+
+62
+00:05:13,270 --> 00:05:19,310
+plus 180 درجة طبعا هذا شرط إذا كان المتجه المعطى
+
+63
+00:05:19,310 --> 00:05:24,090
+يقع في الرُبع التاني أو الرُبع التالت فإن ده إيجاد
+
+64
+00:05:24,090 --> 00:05:27,150
+ال direction ده أوجد الزاوية وبعد إيجاد الزاوية
+
+65
+00:05:27,150 --> 00:05:34,960
+نضيف للمتجه 180 درجةنجي لـ Quick Quiz Quiz سريع
+
+66
+00:05:34,960 --> 00:05:38,680
+حسب ما احنا فهمنا هذا الشكل اللي .. اللي طبعا
+
+67
+00:05:38,680 --> 00:05:42,820
+الموجود أمامنا shows two vectors في اندي أنا
+
+68
+00:05:42,820 --> 00:05:48,060
+متجهين متجه موجود في الربع التاني اسمه A و متجه
+
+69
+00:05:48,060 --> 00:05:53,520
+موجود في الربع الرابع اسمه B المطلوب مني دي ترمي
+
+70
+00:05:53,520 --> 00:05:58,340
+the sign of X and Y component بدي اوجد إشارة
+
+71
+00:05:58,340 --> 00:06:05,010
+المركبات A ومركبات Bزي ما احنا شايفين في هذا الشكل
+
+72
+00:06:05,010 --> 00:06:10,790
+مركبة A مركبة A عند تحليل الـ A لمركبتين هتكون
+
+73
+00:06:10,790 --> 00:06:15,730
+مركبة في هذا الاتجاه بناقص X ومركبة في ال Y معنى
+
+74
+00:06:15,730 --> 00:06:22,050
+الكلام ال X لهذا المتجه A بساوي سالب و ال Y للمتجه
+
+75
+00:06:22,050 --> 00:06:27,370
+A موجببالنسبة للمتجه B المركبة الصينية موجبة
+
+76
+00:06:27,370 --> 00:06:32,470
+والمركبة الصادية سالبة إذا إحنا حللناها بالنسبة
+
+77
+00:06:32,470 --> 00:06:37,630
+لهذا المتجه A والمتجه B لو أنا أوجدت A زائد B طبعا
+
+78
+00:06:37,630 --> 00:06:42,550
+المتجه A والمتجه B ممنفعش أنا أوجد اللي هي المحصلة
+
+79
+00:06:42,550 --> 00:06:46,820
+من A لBفلازم انا لإن الاتنين طالعين من نفس النقطة
+
+80
+00:06:46,820 --> 00:06:52,180
+و من نفس الديل لازم أكمل متوازي الأضلاع بأكمل
+
+81
+00:06:52,180 --> 00:06:56,080
+متوازي الأضلاع و بطلع من هذه النقطة هي المحصلة
+
+82
+00:06:56,080 --> 00:06:59,840
+بتكون بهذا الاتجاه المحصلة بتكون بهذا الاتجاه و
+
+83
+00:06:59,840 --> 00:07:05,140
+بالتالي بتكون المحصلة باتجاه ناقص X و ناقص Y كما
+
+84
+00:07:05,140 --> 00:07:11,440
+هو موضح في الجدول اللي هو قدناهطبعا هنا المتجه A
+
+85
+00:07:11,440 --> 00:07:16,360
+زي ما اتفقنا في ال X component كانت سالب و المركبة
+
+86
+00:07:16,360 --> 00:07:20,920
+ال Y موجبة المتجه B موجود في الرابع الرابع إذا
+
+87
+00:07:20,920 --> 00:07:25,940
+الرابع الرابع بيكون ال X موجب و ال Y سالب في A
+
+88
+00:07:25,940 --> 00:07:32,280
+زائد B لما أوجد أنا محصلة A زائد Bفبتكون المحصلة
+
+89
+00:07:32,280 --> 00:07:37,260
+موجودة في الربع التالت فالربع التالت بيكون ال X
+
+90
+00:07:37,260 --> 00:07:40,580
+مراكبة ال X سالب مراكبة ال Y بالسالب
+
+91
+00:07:42,930 --> 00:07:50,190
+الـ quiz 1.3 من الشكل الـ 1.19 طبعا يظهر عندي
+
+92
+00:07:50,190 --> 00:07:53,990
+shows two vectors في عندي متجهين lying in the XY
+
+93
+00:07:53,990 --> 00:07:58,950
+plane متجهين موجودين في مستوى XY يعني بيسموها
+
+94
+00:07:58,950 --> 00:08:02,480
+rectangular coordinate أو two dimensionsWhich
+
+95
+00:08:02,480 --> 00:08:05,760
+vector has an angle with respect to the positive x
+
+96
+00:08:05,760 --> 00:08:10,220
+-axis that is in the range of the inverse tangent
+
+97
+00:08:10,220 --> 00:08:16,540
+function الشكل المبين هنا عندي أنا متجهين متجه A و
+
+98
+00:08:16,540 --> 00:08:20,500
+متجه B السؤال اللي بيحكي لنا مين من هدول المتجهات
+
+99
+00:08:20,500 --> 00:08:27,830
+يصنع زاوية سالبة مع اتجاه X الموجةفمين المتجهين هل
+
+100
+00:08:27,830 --> 00:08:32,290
+ال Y بيصنع سالب مع اتجاه X الموجب لأ فانا بيعني
+
+101
+00:08:32,290 --> 00:08:37,470
+الجواب ان هو المتجه B هو اللي بيصنع طبعا زاوية
+
+102
+00:08:37,470 --> 00:08:41,030
+سالبة اذا انا مشيت من اتجاه ال X الموجب ومشيت مع
+
+103
+00:08:41,030 --> 00:08:45,070
+اقارب الساعة فبتظهر عندي هذه اللي هي الزاوية سالبة
+
+104
+00:08:45,070 --> 00:08:49,550
+لو انا مشيت مع اتجاه ال X اتجاه الساعة بيكون انا
+
+105
+00:08:49,550 --> 00:08:54,720
+ماشي اتجاه الموجب لكنالاتجاه الـ minus X axis بكون
+
+106
+00:08:54,720 --> 00:09:01,260
+.. بكون مع اتجاه الساعة فالجواب هو ال vector B
+
+107
+00:09:01,260 --> 00:09:08,790
+ناخد هذا ال exampleبحكي لل example find أوجد the
+
+108
+00:09:08,790 --> 00:09:12,090
+horizontal and vertical component of the vector D
+
+109
+00:09:12,090 --> 00:09:19,310
+أوجد المركبة الأفقية والمركبة الرأسية ليه متجه
+
+110
+00:09:19,310 --> 00:09:25,010
+متجه يعني مقدره D بساوي واحد في عشر أقصى اتنين متر
+
+111
+00:09:25,010 --> 00:09:29,820
+displacement of superhero في عندي شخص خارقبدو
+
+112
+00:09:29,820 --> 00:09:35,700
+يتحرك إزاحة من نقطة الأصل و بدو يمشي مسافة D اللي
+
+113
+00:09:35,700 --> 00:09:39,540
+هي عبارة عن واحد في عشر أقصى اتنين و بيصنع زاوية
+
+114
+00:09:39,540 --> 00:09:43,280
+تلاتين مع اتجاه X السالي في هذه الزاوية مطلوب مني
+
+115
+00:09:43,280 --> 00:09:49,050
+أوجد ال X and Y component من خلال الشكلمن خلال
+
+116
+00:09:49,050 --> 00:09:54,890
+الشكل D تمثل متجة المتجة هذا لما اجى اوجد مراكباته
+
+117
+00:09:54,890 --> 00:09:59,630
+يعني احلله هيظهر عندى انا مراكبتين هذا المتجة
+
+118
+00:09:59,630 --> 00:10:03,850
+موجود في الربع الرابع فمراكبة الصينية هتكون موجبة
+
+119
+00:10:03,850 --> 00:10:09,350
+و المراكبة الصادية هتكون سالبة بمعنى اخر عند ايجاد
+
+120
+00:10:09,350 --> 00:10:14,070
+المراكبة الصينيةراح أستخدم إنه الـ X اللي هي
+
+121
+00:10:14,070 --> 00:10:18,730
+الزاوية minus إذاً الـ AX .. أطبّق القوانين AX
+
+122
+00:10:18,730 --> 00:10:22,550
+بتساوي A cosine ثيتا الـ A اللي هي عبارة عن المتجه
+
+123
+00:10:22,550 --> 00:10:29,430
+1 ف10 أقصى 2 cosine minus 30ay بتساوي a sin θ
+
+124
+00:10:29,430 --> 00:10:34,710
+بتساوي 1 فى 10 اقصى 2 sin minus 30 فالجواب طلع عند
+
+125
+00:10:34,710 --> 00:10:39,130
+مركبة الصينية موجبة والمركبة الصادية سالبة وهذا
+
+126
+00:10:39,130 --> 00:10:46,340
+بيؤكد ان هذا المتجه يقع في الربع الرابعالمطلوب الـ
+
+127
+00:10:46,340 --> 00:10:49,940
+B find the magnitude and direction of the
+
+128
+00:10:49,940 --> 00:10:55,120
+displacement of vector B أعطاني متجه B المتجه B
+
+129
+00:10:55,120 --> 00:11:00,000
+المركبة الصينية أعطانيها ناقص 25 و المركبة الصادية
+
+130
+00:11:00,000 --> 00:11:06,690
+أعطانيها عشرة يعني الصيني 25ناقص والصاضي موجب معنى
+
+131
+00:11:06,690 --> 00:11:11,850
+الكلام هذا المراكبة B موجودة في الربع الرابع
+
+132
+00:11:11,850 --> 00:11:18,470
+التاني لأن X minus وY موجب عند إيجاد ال magnitude
+
+133
+00:11:18,470 --> 00:11:23,370
+عندما أوجد اللي هي القيمة ال B ك magnitude بطبخ
+
+134
+00:11:23,370 --> 00:11:28,750
+القانون B بتساوي جزرBX تربيع زائد BY تربيع و باخد
+
+135
+00:11:28,750 --> 00:11:33,010
+الـ BX بإشارتها و بربعها و BY بإشارتها و بربعها و
+
+136
+00:11:33,010 --> 00:11:38,150
+الجواب 26.9 عند إيجاد الـ direction معنا الكلام
+
+137
+00:11:38,150 --> 00:11:41,290
+يعني أنا بدي أوجد الزاوية الزاوية اللي أنا بدي
+
+138
+00:11:41,290 --> 00:11:45,690
+أوجدها طبعا بعوض في القانون اللي هي θ بالساوتين
+
+139
+00:11:45,690 --> 00:11:52,750
+inverse لBY على BXبأوجد بي على بي إكس بي و بأضعها
+
+140
+00:11:52,750 --> 00:11:57,090
+بإشارتها موجبة و بي إكس إشارتها ناقص خمسة و عشرين
+
+141
+00:11:57,090 --> 00:12:02,400
+الآن الجواب minus واحد و عشرين point تمانيةهل يا
+
+142
+00:12:02,400 --> 00:12:07,380
+ترى اجمعلها 180 ولا اخليها زي ما هي بروح للسؤال
+
+143
+00:12:07,380 --> 00:12:12,760
+طبعا طالما ان ال X باتجاه ال minus و ال Y موجب اذا
+
+144
+00:12:12,760 --> 00:12:17,920
+هذا المتجه هيكون في الربع التاني و احنا اتفقنا ان
+
+145
+00:12:17,920 --> 00:12:23,340
+اي متجه يعطينيا معطع موجود في الربع التاني او
+
+146
+00:12:23,340 --> 00:12:29,020
+التالت بضيف 180 للزاوية اذاالزاوية هذه اللى طلعتلى
+
+147
+00:12:29,020 --> 00:12:33,780
+انا راح اضف لها 180 بتطلع عندى 158 فعلا ال 100 و
+
+148
+00:12:33,780 --> 00:12:39,380
+100 و 100 و 158 موجودة في الربع التانى طبعا هذه ال
+
+149
+00:12:39,380 --> 00:12:46,200
+158 مقاسة من اتجاه X الموجب لغاية المتجه وهو يقع
+
+150
+00:12:46,200 --> 00:12:51,250
+في الربع التانىطبعا هذا ال section بدنا .. بدنا
+
+151
+00:12:51,250 --> 00:12:55,210
+نشرح adding vectors .. vectors algebraical يعني
+
+152
+00:12:55,210 --> 00:13:00,690
+بدي أنا أشرح كيف أنا ممكن أجمع متجهات بطريقة
+
+153
+00:13:00,690 --> 00:13:05,090
+جبرية، طريقة جبرية حسابية يعني، بدأ أفرض في عندي
+
+154
+00:13:05,090 --> 00:13:10,430
+أنا متجه R بتساوي A زائد B يعني هذا ال R ممثل
+
+155
+00:13:10,430 --> 00:13:17,210
+للمحصلة بين متجهين A و Bالآن A لها مركبات ال A لها
+
+156
+00:13:17,210 --> 00:13:24,530
+مركبات Ax و Ay و B لها مركبات Bx و By عند إيجاد ال
+
+157
+00:13:24,530 --> 00:13:30,110
+Rx طبعا بأجمع كل مركبات ال X لمين؟ للمتجه A زائد B
+
+158
+00:13:30,110 --> 00:13:36,970
+إذا ال Rx ده تساوي A باتجاه ال X و B باتجاه ال XRY
+
+159
+00:13:36,970 --> 00:13:41,790
+بتساوي A باتجاه Y و B باتجاه ال Y بنفعش أجمع AX مع
+
+160
+00:13:41,790 --> 00:13:47,830
+BY بنفعش أجمع AX مع AY ما بينجمعوا وبالتالي ف ال X
+
+161
+00:13:47,830 --> 00:13:52,630
+component are adding only to X component يعني ال X
+
+162
+00:13:52,630 --> 00:13:57,850
+بدي أجمع متجهات جمع جبري بأجمع ال X مع ال X و ال Y
+
+163
+00:13:57,850 --> 00:14:02,670
+مع ال Y ولكن بدي قراعي الإشارات إذا كان أي متجه
+
+164
+00:14:02,870 --> 00:14:08,010
+يتجه الى اليمين أو الشرخ بيكون موجب الى اليسار
+
+165
+00:14:08,010 --> 00:14:13,310
+بيكون سالب الى أعلى بيكون موجب الى أسفل بيكون سالب
+
+166
+00:14:13,310 --> 00:14:18,890
+وبالتالي محصلة ال R ك magnitude أو كقيمة بيساوي
+
+167
+00:14:18,890 --> 00:14:25,830
+جزر R X تربيع زائد R Y تربيع و ال direction بيساوي
+
+168
+00:14:25,830 --> 00:14:29,890
+tan inverse لمين إذا أنا ال direction يعني بدوجة
+
+169
+00:14:29,890 --> 00:14:34,660
+ال thetaبأوجد tan of θ عبارة عن ry على rx و بعدين
+
+170
+00:14:34,660 --> 00:14:38,280
+بأوجد الـ θ اللي هي عبارة عن tan inverse ل θ على
+
+171
+00:14:38,280 --> 00:14:43,600
+القالة أو القالة الحاسبة الآن لما بدأ أنا طبعا
+
+172
+00:14:43,600 --> 00:14:46,740
+subtracting two vectors works the same way لو بدأ
+
+173
+00:14:46,740 --> 00:14:50,920
+أطرح أنا متجهات برضه بترحها بنفس الطريقة بترحها
+
+174
+00:14:50,920 --> 00:14:55,300
+ترح جبري زي ما حكينا براعي إشارات الموجب أو السالب
+
+175
+00:14:55,300 --> 00:14:59,480
+بالنسبة للمتجهات مثال
+
+176
+00:15:02,220 --> 00:15:07,500
+problems هيكر begins to trip by first walking خمسة
+
+177
+00:15:07,500 --> 00:15:12,240
+و عشرين كيلومتر طبعا خمسة و أربعين درجة south of
+
+178
+00:15:12,240 --> 00:15:17,880
+east الآن ال هيكر هذا عبارة عن مسافرة بدأت رحلتها
+
+179
+00:15:17,880 --> 00:15:22,240
+by first walking بالبداية مشيت مسافة خمسة و عشرين
+
+180
+00:15:22,240 --> 00:15:27,340
+كيلومتر و تميل بزاوية خمسة و ربعين درجة south of
+
+181
+00:15:27,340 --> 00:15:34,110
+eastيعني جنوب الشرق 45 درجة from here base come من
+
+182
+00:15:34,110 --> 00:15:39,570
+.. من مكان اللي هي طبعا نزولها اللي هي ال .. ال ..
+
+183
+00:15:39,570 --> 00:15:44,430
+المكان اللي هي نازلة فيهأو المخيم اللى نزله فيه on
+
+184
+00:15:44,430 --> 00:15:48,370
+the second day في اليوم التانى هذه المسافرة مشيت
+
+185
+00:15:48,370 --> 00:15:52,610
+اربعين kilometer in a direction ستين درجة north of
+
+186
+00:15:52,610 --> 00:15:57,270
+east بعد تانى يوم مشيت اربعين kilometer وكان
+
+187
+00:15:57,270 --> 00:16:02,490
+التميل بزاوية ستين درجة شمال الشرق north of east
+
+188
+00:16:02,490 --> 00:16:08,400
+شمال الشرق يعنى الستين درجة هتكون قريبة من الشرقAt
+
+189
+00:16:08,400 --> 00:16:13,320
+which point she discovers a forest rangers tours
+
+190
+00:16:13,320 --> 00:16:20,280
+بيحكيلي عند أي نقطة هي سوف تكتشف اللي هي الغابة أو
+
+191
+00:16:20,280 --> 00:16:24,860
+بالنسبة له اللي هي المكان اللي كان فيهالجواء هنا
+
+192
+00:16:24,860 --> 00:16:28,620
+طبعا مطلوب من determine the components of the
+
+193
+00:16:28,620 --> 00:16:32,100
+hackers displacement in the first and second days
+
+194
+00:16:32,100 --> 00:16:37,540
+طالب مني انا مراكبات اللي هي المسافرة المراكبات
+
+195
+00:16:37,540 --> 00:16:41,780
+الإزاحة الكلية يعني اتجاه ال X و اتجاه ال Y حسب
+
+196
+00:16:41,780 --> 00:16:47,300
+بأول يوم و تاني يوم الآن عندنا احنا الرسمة هذه
+
+197
+00:16:47,300 --> 00:16:51,140
+تمثل المشوار اللي مشيته المسافرة او البنت هي ال
+
+198
+00:16:51,140 --> 00:16:56,590
+camp المخيم اللي كانت بدأت من هنامشيت مسافة طبعا
+
+199
+00:16:56,590 --> 00:17:01,870
+بالنسبة للمسافة هذه مشيت متهيأل خمس .. مشيت أشرين
+
+200
+00:17:01,870 --> 00:17:08,030
+بدي أشوف بس مشيت مسافة خمسة و عشرين كيلومتر مشيت
+
+201
+00:17:08,030 --> 00:17:12,890
+مسافة خمسة و عشرين كيلومتر بهذا الاتجاه خمسة و
+
+202
+00:17:12,890 --> 00:17:16,950
+عشرين كيلومتر هيها وهي الزاوية خمسة و أربعين درجة
+
+203
+00:17:16,950 --> 00:17:22,480
+عند المنطقة هذه طبعا تاني يوم اتوقفتتاني يوم مشيت
+
+204
+00:17:22,480 --> 00:17:29,820
+.. طبعا تاني يوم مشيت مسافة بهذا الشكل كانت طبعا
+
+205
+00:17:29,820 --> 00:17:35,980
+ميلة بزاوية ستين درجة .. ستين درجة شمال الشرق يعني
+
+206
+00:17:35,980 --> 00:17:40,260
+الستين درجة كانت قريبة من الشرق طبعا في الفترة
+
+207
+00:17:40,260 --> 00:17:46,200
+التانية او تاني يوم مشيت مسافة اربعين kilometer
+
+208
+00:17:46,200 --> 00:17:51,800
+مشيت مسافة اربعين kilometerطبعا بالنسبة لهذه هنا
+
+209
+00:17:51,800 --> 00:17:58,820
+البداية من عند المخيم مشيت ومشيت في هذا الطريق
+
+210
+00:17:58,820 --> 00:18:04,160
+تميل بزاوية 45 درجة عند المنطقة هذه توقفت وتاني
+
+211
+00:18:04,160 --> 00:18:10,060
+يوم طبعا مشيت بمايلة بزاوية 60 درجة شمال الشرق
+
+212
+00:18:10,560 --> 00:18:16,080
+بالنسبة للمحصلة باعتبر هذا متجه الأول باعتبر ال B
+
+213
+00:18:16,080 --> 00:18:20,640
+هو المتجه التاني والمحصلة هتكون من بداية الأول من
+
+214
+00:18:20,640 --> 00:18:23,800
+ال .. من طبعا من نقطة الأصل أو من بداية المتجه
+
+215
+00:18:23,800 --> 00:18:30,090
+الأول إلى نهاية المتجه التانيطبعا لما نجي نحل هذا
+
+216
+00:18:30,090 --> 00:18:37,030
+السؤال ال solution للحل الحل find أول حاجة بتوجد
+
+217
+00:18:37,030 --> 00:18:41,370
+مركبات المتجه الأول a مركبات المتجه ال a هتكون a
+
+218
+00:18:41,370 --> 00:18:47,510
+cos θ مركبات المتجه a بتجاه ال y a sin θ لإن
+
+219
+00:18:47,510 --> 00:18:55,200
+الزاويةتقع أسفل متجه X اللي طبعا متجه X من هناك
+
+220
+00:18:55,200 --> 00:19:00,580
+أنا معاها قريب الساعة فبتكون A cosine minus ال 45
+
+221
+00:19:00,580 --> 00:19:05,920
+و A sine minus ال 45 هيطلع معايا الجواب 17.7
+
+222
+00:19:05,920 --> 00:19:12,400
+كيلومتر بالموجب يعني ال X بالموجب و ناقص 17.7 ال Y
+
+223
+00:19:12,400 --> 00:19:20,030
+بالسالب X بالموجب و ال Y بالسالبX بالموجبة و Y
+
+224
+00:19:20,030 --> 00:19:23,910
+بالسالب معناته ده موجودة بالربع الرابع الان بدي
+
+225
+00:19:23,910 --> 00:19:30,330
+اوجد مراكبات ال B بي X و بي Y اتجاه ال 60 كانت
+
+226
+00:19:30,330 --> 00:19:36,270
+شمال الشرق وبالتالي ال 60 كانت موجبة اذا ال بي X
+
+227
+00:19:36,270 --> 00:19:41,230
+بتساوي بي كزين ال 60 و بي Y بي صين ال 60 تطلع عندى
+
+228
+00:19:41,230 --> 00:19:48,870
+20 كم و هنا 34.6 كم الان لإيجاد المحصلةالان إيجاد
+
+229
+00:19:48,870 --> 00:19:53,310
+المحصلة ال R بتساوي المتجه E زائد المتجه B إذا ال
+
+230
+00:19:53,310 --> 00:19:58,530
+R هذه المركبات الخاصة بال R R X و R Y R X بتساوي A
+
+231
+00:19:58,530 --> 00:20:05,310
+X زائد B X و R Y بتساوي A Y زائد B Y إذا R X طلعت
+
+232
+00:20:05,310 --> 00:20:11,450
+ل 37.7 موجة كيلومتر و R Y طلعت موجة ب 16.9 كيلومتر
+
+233
+00:20:11,450 --> 00:20:15,850
+الآن X موجة ب و Y موجة ب معناها المحصلة موجودة في
+
+234
+00:20:15,850 --> 00:20:22,010
+الربع الأوللإيجاد ال magnitude لل R إذن R بدها
+
+235
+00:20:22,010 --> 00:20:29,070
+تساوي جزر R X تربيع زائد R Y تربيع و طبعا هاد ال R
+
+236
+00:20:29,070 --> 00:20:35,310
+تمثل ال magnitude بدها تساوي 41.3 كيلومترفيتا
+
+237
+00:20:35,310 --> 00:20:44,050
+بتتساوي tan inverse ل ry على rx بتساوي 24.1 هذه
+
+238
+00:20:44,050 --> 00:20:51,900
+عبارة عن اتجاه المحصلة هل أجمع لل 24.1 180 لأليش؟
+
+239
+00:20:51,900 --> 00:20:57,640
+لإن ر X موجبة ر Y موجبة وبالتالي طلع عندي اللي هي
+
+240
+00:20:57,640 --> 00:21:02,240
+موجب موجب إذا المحصلة بالربح الأول طبعا مابيلزم إن
+
+241
+00:21:02,240 --> 00:21:09,280
+أنا أجمعلها اللي هي ال 180 درجة section 1.11 طبعا
+
+242
+00:21:09,280 --> 00:21:15,600
+بيشرح problem solving strategy كيف أنا ممكن أحل أي
+
+243
+00:21:15,600 --> 00:21:21,910
+مسألة فيزيائيةبالبداية بقرأ السؤال نمر اتنين draw
+
+244
+00:21:21,910 --> 00:21:26,350
+diagram بارسم السؤال تلاتة label physical quantity
+
+245
+00:21:26,350 --> 00:21:30,750
+بدأ احدد الكميات الفيزيائية نمر اربع identify
+
+246
+00:21:30,750 --> 00:21:35,710
+principles list dataنمر خمسة choose equation بختار
+
+247
+00:21:35,710 --> 00:21:40,370
+المعادلة المناسبة نمر ستة بحل solve المعادلة بحل
+
+248
+00:21:40,370 --> 00:21:46,910
+المعادلات و بعد هيك بعود طبعا بالقيم المعروفة و
+
+249
+00:21:46,910 --> 00:21:51,730
+بعد هيك ب check answer بافحص اللي هو الجواب تبعي
+
+250
+00:21:51,730 --> 00:21:56,400
+هل صحيح ام لاطبعا general problem solving strategy
+
+251
+00:21:56,400 --> 00:22:02,000
+لأي مسألة أول حاجة إحنا بنقرأ السؤال كويس و بنشوف
+
+252
+00:22:02,000 --> 00:22:06,120
+إيش المواطيات اللي عندنا بنرسم السؤال ك diagram
+
+253
+00:22:06,120 --> 00:22:10,960
+بعدين بحدد ال label على هذا ال diagram بحدد لكل
+
+254
+00:22:10,960 --> 00:22:15,560
+طبعا جزء إيش العناصر أو كيمات الفيزيائي الممثلة له
+
+255
+00:22:15,560 --> 00:22:22,430
+هل هو ماس هل هو مثلا طول هل هو زمنبعد هيك بحدد
+
+256
+00:22:22,430 --> 00:22:25,310
+اللي هي أساسيات اللي هي القانون الفيزيائي اللي أنا
+
+257
+00:22:25,310 --> 00:22:29,750
+ممكن أحل عليه أو المعادلات اللازمة ثم أحل هذه
+
+258
+00:22:29,750 --> 00:22:34,270
+المعادلات لإيجاد أيه المتغيرات اللازمة و بنفحص
+
+259
+00:22:34,270 --> 00:22:39,370
+طبعا الإجابة هل يعني هل هي تتوافق مع الحل أم لا
+
+260
+00:22:39,970 --> 00:22:44,830
+طبعا أخر سؤال في هذا ال chapter السؤال القادم هو
+
+261
+00:22:44,830 --> 00:22:50,530
+عبارة عن problems 114 هذا السؤال هو عبارة عن شبر
+
+262
+00:22:50,530 --> 00:22:54,670
+leaves home and drives to a store located 7
+
+263
+00:22:54,670 --> 00:22:59,030
+kilometer away in a direction 30 درجة north of
+
+264
+00:22:59,030 --> 00:23:04,110
+eastأحد الأشخاص أو الرجال أو الشبر طبعا بيتسوق
+
+265
+00:23:04,110 --> 00:23:08,270
+leave home ترك بيته and drive to a store ذهب إلى
+
+266
+00:23:08,270 --> 00:23:14,570
+مكان ال store المخازن عشان يشتري بعض الحاجيات يبعد
+
+267
+00:23:14,570 --> 00:23:17,950
+سبعة كيلو متر away in a direction كان ماشي سبعة
+
+268
+00:23:17,950 --> 00:23:22,970
+كيلو في اتجاه تلاتين درجة north of east north of
+
+269
+00:23:22,970 --> 00:23:27,580
+east تلاتين درجة شمال الشرقبعد هيك اترك المكان
+
+270
+00:23:27,580 --> 00:23:33,760
+ومشي كمان إلى ب .. بمشوار او مسافة خمسة كيلومتر في
+
+271
+00:23:33,760 --> 00:23:38,160
+اتجاه خمسين درجة west of north يعني غرب الشمال
+
+272
+00:23:38,160 --> 00:23:43,020
+find the distance and direction from the shoppers
+
+273
+00:23:43,020 --> 00:23:47,380
+home to the restaurants المطلوب مني اوجد الإزاحة
+
+274
+00:23:47,380 --> 00:23:52,120
+او المسافة اللى مشيها واتجاهه خلال هذا المشوار او
+
+275
+00:23:52,120 --> 00:23:57,920
+خلال طبعا رحلته او مشوارهمن المكان بيته طبعا
+
+276
+00:23:57,920 --> 00:24:02,100
+استراتيجيا يعني كيف انا ممكن احلwe finished
+
+277
+00:24:02,100 --> 00:24:05,820
+reading the problems طبعا أول حاجة بنقرأ السؤال
+
+278
+00:24:05,820 --> 00:24:09,880
+and draw a diagram بدأ أرسم ال diagram طبعا الشكل
+
+279
+00:24:09,880 --> 00:24:15,620
+الموضح أسفل هو بيمثل ليه اللي هو السؤال بعد هيك we
+
+280
+00:24:15,620 --> 00:24:18,160
+recognize that the vectors are located the results
+
+281
+00:24:18,160 --> 00:24:23,840
+طبعا من خلال السؤال بحدد اللي هي المحصلة الآن هي
+
+282
+00:24:23,840 --> 00:24:28,930
+ال home هي البيت ماشيماشي هذا المشوار او المتجه
+
+283
+00:24:28,930 --> 00:24:34,310
+الاول بزاوية تلاتين درجة بتميل الزاوية شمال الشرق
+
+284
+00:24:34,310 --> 00:24:37,630
+قريبة من الشرق تلاتين درجة بعد هيك انتهى هنا
+
+285
+00:24:37,630 --> 00:24:41,870
+المتجه ببدأ المشوار التاني المشوار التاني ماشي
+
+286
+00:24:41,870 --> 00:24:46,910
+خمسين درجة غرب الشمال يعني الخمسين قريبة من الشمال
+
+287
+00:24:46,910 --> 00:24:52,010
+بعد هيك اخلص اذا المحصلة هتكون من البيت من بداية
+
+288
+00:24:52,010 --> 00:24:55,550
+المتجه لغاية نهاية اللي هو ال restaurant لغاية ما
+
+289
+00:24:55,550 --> 00:24:59,680
+هو ايه توقفطبعا ننحل زي ما حلنا بالسابق بدي أجيب
+
+290
+00:24:59,680 --> 00:25:04,720
+المركبة السينية والصادية للمتجه الأول أنا عندي R
+
+291
+00:25:04,720 --> 00:25:10,320
+المحصلة عبارة عن A زائد B راح أوجد RX اللي هي AX
+
+292
+00:25:10,320 --> 00:25:17,970
+زائد BX RY بتساوي Ay زائد Byبلاحظ طبعا ان اللي هي
+
+293
+00:25:17,970 --> 00:25:22,730
+substitute the number with units step 7 the
+
+294
+00:25:22,730 --> 00:25:26,770
+direction of B measured counter clockwise from the
+
+295
+00:25:26,770 --> 00:25:34,210
+positive x axis لإنه ال .. لإن الرجل ماشي عكس أخر
+
+296
+00:25:34,210 --> 00:25:39,950
+الساعة بزاوية 30 درجة إذا في اتجاه x الموجة إذا rx
+
+297
+00:25:39,950 --> 00:25:43,350
+بتساوي 7 المسافة اللي ماشيها kilometer cosine
+
+298
+00:25:43,350 --> 00:25:50,040
+التلاتينRy بتساوي سبعة كيلومتر صين التلاتين راح
+
+299
+00:25:50,040 --> 00:25:54,420
+أجمع لها اللي هي مين هذه طبعا AX المشوار الأول
+
+300
+00:25:54,420 --> 00:25:58,680
+المشوار التاني كان خمسة كيلومتر كوزاين المية
+
+301
+00:25:58,680 --> 00:26:05,740
+وأربعين وخمسة كيلومتر صين المية وأربعينبساوي 2
+
+302
+00:26:05,740 --> 00:26:10,620
+point طبعا تلاتة و عشرين kilometer طبعا من و انا
+
+303
+00:26:10,620 --> 00:26:15,520
+جت ال 140 طرحنا ال 180 نقص ال 50 طلعت عندي انا
+
+304
+00:26:15,520 --> 00:26:21,500
+اللي هي ال 140 درجة عشان احطها طبعا بالموجبفالجواب
+
+305
+00:26:21,500 --> 00:26:26,120
+النهائي هي باستخدام المحصلة القانونية للـ
+
+306
+00:26:26,120 --> 00:26:32,280
+magnitude بالساوية جزر R X تربيع زائد R Y تربيع 2
+
+307
+00:26:32,280 --> 00:26:37,780
+.23 كيلومتر تربيع زائد 6.7 طبعا هذه موجبة موجبةإذا
+
+308
+00:26:37,780 --> 00:26:40,660
+موجودة في الربع الأول هي المحصلة موجودة في الربع
+
+309
+00:26:40,660 --> 00:26:46,440
+الأول بتساوي 7.07 كيلومتر اتجاه المحصلة فيتا
+
+310
+00:26:46,440 --> 00:26:51,840
+بتساوي tan inverse ry على rx فبحط ال ry إشارتها
+
+311
+00:26:51,840 --> 00:26:58,720
+موجبةRx إشارتها موجبة بتساوي 71.6 درجة هيك إحنا
+
+312
+00:26:58,720 --> 00:27:03,480
+طبعا حددنا أي متجه ك magnitude للمتجه عبارة عن
+
+313
+00:27:03,480 --> 00:27:08,200
+طبعا Rx تربيع زائد Ry تربيع اتجاه المحصلة هيكون
+
+314
+00:27:08,200 --> 00:27:14,540
+tan inverse Ry على Rx وبهذا بنكون طبعا انتهينا من
+
+315
+00:27:14,540 --> 00:27:20,500
+تسجيل وشرح الفصل الأول من فيزياء عامة لطلبة العلوم
+
+316
+00:27:20,500 --> 00:27:21,080
+الصحية
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..a51106c52cbe35f669169ca273b38d9bb4b71d0b
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/XIBxMkksrPs_raw.json
@@ -0,0 +1 @@
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"avg_logprob": -0.20278532219969708, "compression_ratio": 1.3, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 46.34, "end": 46.82, "word": "ax", "probability": 0.2200927734375}, {"start": 46.82, "end": 47.48, "word": " وay", "probability": 0.7412109375}, {"start": 47.48, "end": 48.34, "word": " يسموا", "probability": 0.8170572916666666}, {"start": 48.34, "end": 48.54, "word": " are", "probability": 0.734375}, {"start": 48.54, "end": 49.2, "word": " component", "probability": 0.85302734375}, {"start": 49.2, "end": 49.96, "word": " vectors", "probability": 0.90673828125}, {"start": 49.96, "end": 50.46, "word": " عبارة", "probability": 0.9095458984375}, {"start": 50.46, "end": 50.66, "word": " عن", "probability": 0.994140625}, {"start": 50.66, "end": 51.28, "word": " مراكبات", "probability": 0.81611328125}, {"start": 51.28, "end": 51.86, "word": " المتجه", "probability": 0.8580322265625}, {"start": 51.86, "end": 52.14, "word": " a", "probability": 0.7734375}, {"start": 52.14, "end": 53.54, "word": " ax", "probability": 0.55517578125}, {"start": 53.54, "end": 53.8, "word": " is", "probability": 0.86279296875}, {"start": 53.8, "end": 54.26, "word": " called", "probability": 0.89013671875}, {"start": 54.26, "end": 54.96, "word": " x", "probability": 0.9169921875}, {"start": 54.96, "end": 55.58, "word": " component", "probability": 0.87841796875}, {"start": 55.58, "end": 55.98, "word": " of", "probability": 0.9765625}, {"start": 55.98, "end": 56.24, "word": " a", "probability": 0.9541015625}, {"start": 56.24, "end": 56.8, "word": " ax", "probability": 0.4697265625}, {"start": 56.8, "end": 57.62, "word": " بسميها", "probability": 0.9847412109375}, {"start": 57.62, "end": 58.76, "word": " المراكبة", "probability": 0.9603271484375}, {"start": 58.76, "end": 59.36, "word": " الصينية", "probability": 0.9645182291666666}, {"start": 59.36, "end": 59.5, "word": " ل", "probability": 0.94189453125}, {"start": 59.5, "end": 59.74, "word": " a", "probability": 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{"start": 61.59, "end": 61.93, "word": " ay", "probability": 0.5107421875}, {"start": 61.93, "end": 62.45, "word": " is", "probability": 0.927734375}, {"start": 62.45, "end": 62.95, "word": " called", "probability": 0.9267578125}, {"start": 62.95, "end": 63.45, "word": " the", "probability": 0.86669921875}, {"start": 63.45, "end": 63.83, "word": " y", "probability": 0.87060546875}, {"start": 63.83, "end": 64.65, "word": " component", "probability": 0.84765625}, {"start": 64.65, "end": 65.19, "word": " of", "probability": 0.98681640625}, {"start": 65.19, "end": 65.53, "word": " a", "probability": 0.84423828125}, {"start": 65.53, "end": 66.53, "word": " these", "probability": 0.64697265625}, {"start": 66.53, "end": 67.31, "word": " components", "probability": 0.9453125}, {"start": 67.31, "end": 68.25, "word": " can", "probability": 0.96142578125}, {"start": 68.25, "end": 68.67, "word": " be", "probability": 0.94970703125}, {"start": 68.67, "end": 69.13, "word": " either", "probability": 0.90673828125}, {"start": 69.13, "end": 69.55, "word": " positive", "probability": 0.93115234375}, {"start": 69.55, "end": 69.91, "word": " or", "probability": 0.97119140625}, {"start": 69.91, "end": 70.29, "word": " negative", "probability": 0.9677734375}, {"start": 70.29, "end": 70.91, "word": " numbers", "probability": 0.9033203125}, {"start": 70.91, "end": 71.53, "word": " with", "probability": 0.92236328125}, {"start": 71.53, "end": 72.03, "word": " unit", "probability": 0.9462890625}, {"start": 72.03, "end": 72.41, "word": " the", "probability": 0.87109375}, {"start": 72.41, "end": 72.95, "word": " component", "probability": 0.79443359375}, {"start": 72.95, "end": 73.63, "word": " of", "probability": 0.98193359375}, {"start": 73.63, "end": 74.27, "word": " a", "probability": 0.90966796875}, {"start": 74.27, "end": 74.81, "word": " are", "probability": 0.5419921875}, {"start": 74.81, "end": 75.69, "word": " الآن", "probability": 0.6893310546875}, {"start": 75.69, "end": 76.09, "word": " هذه", "probability": 0.841796875}, {"start": 76.09, "end": 76.89, "word": " المركبات", "probability": 0.865234375}, {"start": 76.89, "end": 77.23, "word": " ممكن", "probability": 0.991455078125}, {"start": 77.23, "end": 77.55, "word": " تكون", "probability": 0.979736328125}, {"start": 77.55, "end": 78.05, "word": " موجبة", "probability": 0.9734700520833334}, {"start": 78.05, "end": 78.39, "word": " أو", "probability": 0.83203125}, {"start": 78.39, "end": 79.61, "word": " سالبة", "probability": 0.9576822916666666}, {"start": 79.61, "end": 81.29, "word": " طبعا", "probability": 0.967041015625}, {"start": 81.29, "end": 82.15, "word": " حسب", "probability": 0.98779296875}, {"start": 82.15, "end": 83.11, "word": " اتجاه", "probability": 0.9527587890625}, {"start": 83.11, "end": 83.85, "word": " المتجه", "probability": 0.878173828125}, {"start": 83.85, "end": 84.21, "word": " a", "probability": 0.892578125}, {"start": 84.21, "end": 85.53, "word": " the", "probability": 0.78515625}, {"start": 85.53, "end": 86.09, "word": " component", "probability": 0.912109375}, {"start": 86.09, "end": 86.43, "word": " of", "probability": 0.9775390625}, {"start": 86.43, "end": 86.97, "word": " a", "probability": 0.9365234375}, {"start": 86.97, "end": 87.63, "word": " مركبات", "probability": 0.88330078125}, {"start": 87.63, "end": 87.81, "word": " ال", "probability": 0.9521484375}, {"start": 87.81, "end": 88.01, "word": " a", "probability": 0.923828125}, {"start": 88.01, "end": 88.15, "word": " اللي", "probability": 0.90234375}, {"start": 88.15, "end": 88.35, "word": " هي", "probability": 0.8837890625}, {"start": 88.35, "end": 88.51, "word": " ال", "probability": 0.76416015625}, {"start": 88.51, "end": 89.01, "word": " ax", "probability": 0.68994140625}], "temperature": 1.0}, {"id": 5, "seek": 11409, "start": 89.87, "end": 114.09, "text": "تساوي A Cos θ الـ θ هذه الزاوية اللتي يصنعها المتجه مع اتجاه X الموجب Ay بتساوي A Sin θ يعني حللنا المتجه A إلى مركبتين مركبة موازية للمستوى X ومركبة عمودية الموازية ل X تسمى A Cos وعمودية على X تسمى A Sin", "tokens": [2655, 3794, 995, 45865, 316, 15855, 12622, 2423, 39184, 12622, 29538, 6024, 110, 995, 2407, 10632, 13672, 31371, 7251, 9381, 1863, 3615, 11296, 9673, 2655, 7435, 3224, 20449, 1975, 2655, 7435, 40294, 1783, 9673, 29245, 3555, 9081, 39894, 3794, 995, 45865, 316, 11187, 12622, 37495, 22653, 11331, 1211, 1211, 8315, 9673, 2655, 7435, 3224, 316, 30731, 3714, 31747, 3555, 2655, 9957, 3714, 31747, 49401, 3714, 2407, 31377, 10632, 5296, 19528, 14851, 2407, 7578, 1783, 4032, 2304, 31747, 49401, 6225, 2304, 2407, 16254, 3660, 9673, 2407, 31377, 10632, 5296, 1783, 6055, 38251, 7578, 316, 15855, 4032, 3615, 2304, 2407, 16254, 3660, 15844, 1783, 6055, 38251, 7578, 316, 11187], "avg_logprob": -0.16579861180097968, "compression_ratio": 1.8797814207650274, "no_speech_prob": 2.396106719970703e-05, "words": [{"start": 89.87, "end": 90.47, "word": "تساوي", "probability": 0.8199462890625}, {"start": 90.47, "end": 90.75, "word": " A", "probability": 0.44775390625}, {"start": 90.75, "end": 91.15, "word": " Cos", "probability": 0.51513671875}, {"start": 91.15, "end": 91.81, "word": " θ", "probability": 0.40283203125}, {"start": 91.81, "end": 92.59, "word": " الـ", "probability": 0.5653076171875}, {"start": 92.59, "end": 92.75, "word": " θ", "probability": 0.417236328125}, {"start": 92.75, "end": 93.09, "word": " هذه", "probability": 0.560546875}, {"start": 93.09, "end": 93.81, "word": " الزاوية", "probability": 0.8765625}, {"start": 93.81, "end": 94.23, "word": " اللتي", "probability": 0.629638671875}, {"start": 94.23, "end": 94.81, "word": " يصنعها", "probability": 0.92509765625}, {"start": 94.81, "end": 95.49, "word": " المتجه", "probability": 0.97021484375}, {"start": 95.49, "end": 96.11, "word": " مع", "probability": 0.951171875}, {"start": 96.11, "end": 96.73, "word": " اتجاه", "probability": 0.973388671875}, {"start": 96.73, "end": 97.09, "word": " X", "probability": 0.888671875}, {"start": 97.09, "end": 97.67, "word": " الموجب", "probability": 0.9892578125}, {"start": 97.67, "end": 98.41, "word": " Ay", "probability": 0.368896484375}, {"start": 98.41, "end": 99.37, "word": " بتساوي", "probability": 0.84228515625}, {"start": 99.37, "end": 99.61, "word": " A", "probability": 0.9560546875}, {"start": 99.61, "end": 100.15, "word": " Sin", "probability": 0.6767578125}, {"start": 100.15, "end": 100.75, "word": " θ", "probability": 0.50927734375}, {"start": 100.75, "end": 101.45, "word": " يعني", "probability": 0.892333984375}, {"start": 101.45, "end": 101.99, "word": " حللنا", "probability": 0.9853515625}, {"start": 101.99, "end": 102.57, "word": " المتجه", "probability": 0.989013671875}, {"start": 102.57, "end": 102.91, "word": " A", "probability": 0.95263671875}, {"start": 102.91, "end": 103.43, "word": " إلى", "probability": 0.73046875}, {"start": 103.43, "end": 104.31, "word": " مركبتين", "probability": 0.85595703125}, {"start": 104.31, "end": 105.35, "word": " مركبة", "probability": 0.8274739583333334}, {"start": 105.35, "end": 106.53, "word": " موازية", "probability": 0.9090576171875}, {"start": 106.53, "end": 107.27, "word": " للمستوى", "probability": 0.958984375}, {"start": 107.27, "end": 107.57, "word": " X", "probability": 0.97802734375}, {"start": 107.57, "end": 108.15, "word": " ومركبة", "probability": 0.83294677734375}, {"start": 108.15, "end": 108.65, "word": " عمودية", "probability": 0.89423828125}, {"start": 108.65, "end": 109.41, "word": " الموازية", "probability": 0.9488525390625}, {"start": 109.41, "end": 109.55, "word": " ل", "probability": 0.96044921875}, {"start": 109.55, "end": 109.79, "word": " X", "probability": 0.68896484375}, {"start": 109.79, "end": 110.25, "word": " تسمى", "probability": 0.9329427083333334}, {"start": 110.25, "end": 110.43, "word": " A", "probability": 0.97998046875}, {"start": 110.43, "end": 110.69, "word": " Cos", "probability": 0.92529296875}, {"start": 110.69, "end": 112.25, "word": " وعمودية", "probability": 0.8426106770833334}, {"start": 112.25, "end": 112.45, "word": " على", "probability": 0.529296875}, {"start": 112.45, "end": 112.71, "word": " X", "probability": 0.9921875}, {"start": 112.71, "end": 113.29, "word": " تسمى", "probability": 0.97509765625}, {"start": 113.29, "end": 113.67, "word": " A", "probability": 0.98779296875}, {"start": 113.67, "end": 114.09, "word": " Sin", "probability": 0.98193359375}], "temperature": 1.0}, {"id": 6, "seek": 14159, "start": 115.51, "end": 141.59, "text": "It follows that A's magnitude and direction are related to its component through the following relation الآن ممكن أوجد أنا محصلة متجهين أو مجموعة متجهات كالتالي A بدها تساوي A X تربيع زائد A Y تربيع هذه بسميها ال magnitude of the vectors يعني قيمة ال vector كعدد القيمة العددية على المتجه A", "tokens": [3522, 10002, 300, 316, 311, 15668, 293, 3513, 366, 4077, 281, 1080, 6542, 807, 264, 3480, 9721, 6024, 48506, 3714, 43020, 5551, 29245, 3215, 41850, 3714, 5016, 36520, 3660, 44650, 7435, 3224, 9957, 34051, 3714, 7435, 2304, 2407, 27884, 44650, 7435, 3224, 9307, 9122, 6027, 2655, 6027, 1829, 316, 47525, 11296, 6055, 3794, 995, 45865, 316, 1783, 6055, 2288, 21292, 3615, 30767, 16373, 3215, 316, 398, 6055, 2288, 21292, 3615, 29538, 4724, 38251, 1829, 11296, 2423, 15668, 295, 264, 18875, 37495, 22653, 12174, 32640, 3660, 2423, 8062, 9122, 22488, 3215, 25062, 32640, 3660, 18863, 3215, 3215, 10632, 15844, 9673, 2655, 7435, 3224, 316], "avg_logprob": -0.19155649582927042, "compression_ratio": 1.6023622047244095, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 115.51, "end": 116.05, "word": "It", "probability": 0.1353759765625}, {"start": 116.05, "end": 116.29, "word": " follows", "probability": 0.55810546875}, {"start": 116.29, "end": 116.71, "word": " that", "probability": 0.94775390625}, {"start": 116.71, "end": 117.11, "word": " A's", "probability": 0.65283203125}, {"start": 117.11, "end": 117.63, "word": " magnitude", "probability": 0.84912109375}, {"start": 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were measured with respect to the Y لو الزاوية كانت قريبة من ال Y يعني فالمجاور الزاوية يعتبر A cosine والعمود اللي هو بال X بكون A sine", "tokens": [9566, 3555, 3615, 995, 23758, 2423, 28820, 10943, 498, 264, 5802, 645, 12690, 365, 3104, 281, 264, 398, 45164, 6024, 110, 995, 2407, 10632, 25961, 2655, 12174, 16572, 49401, 9154, 2423, 398, 37495, 22653, 6156, 45340, 7435, 995, 13063, 6024, 110, 995, 2407, 10632, 7251, 34268, 26890, 316, 23565, 16070, 25957, 23328, 13672, 1829, 31439, 20666, 1783, 4724, 30544, 316, 18609], "avg_logprob": -0.11800655193867222, "compression_ratio": 1.4022988505747127, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 264.45, "end": 265.31, "word": "طبعا", "probability": 0.96630859375}, {"start": 265.31, "end": 265.55, "word": " هذا", "probability": 0.57373046875}, {"start": 265.55, "end": 266.31, "word": " الكلام", "probability": 0.9641927083333334}, {"start": 266.31, "end": 266.67, "word": " if", "probability": 0.818359375}, {"start": 266.67, 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{"start": 528.67, "end": 529.03, "word": " بيكون", "probability": 0.95849609375}, {"start": 529.03, "end": 529.55, "word": " انا", "probability": 0.869140625}, {"start": 529.55, "end": 530.01, "word": " ماشي", "probability": 0.9244791666666666}, {"start": 530.01, "end": 530.61, "word": " اتجاه", "probability": 0.9794921875}, {"start": 530.61, "end": 531.27, "word": " الموجب", "probability": 0.9869791666666666}, {"start": 531.27, "end": 531.93, "word": " لكن", "probability": 0.88720703125}], "temperature": 1.0}, {"id": 25, "seek": 54414, "start": 532.5, "end": 544.14, "text": "الاتجاه الـ minus X axis بكون .. بكون مع اتجاه الساعة فالجواب هو ال vector B ناخد هذا ال example", "tokens": [6027, 9307, 7435, 40294, 2423, 39184, 3175, 1783, 10298, 4724, 30544, 4386, 4724, 30544, 20449, 1975, 2655, 7435, 40294, 21136, 995, 27884, 6156, 6027, 7435, 14407, 3555, 31439, 2423, 8062, 363, 8717, 47283, 3215, 23758, 2423, 1365], "avg_logprob": -0.15501644383919866, "compression_ratio": 1.225, 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"probability": 0.9912109375}, {"start": 1570.4, "end": 1570.52, "word": " و", "probability": 0.6220703125}, {"start": 1570.52, "end": 1570.62, "word": " انا", "probability": 0.576171875}, {"start": 1570.62, "end": 1570.82, "word": " جت", "probability": 0.667724609375}, {"start": 1570.82, "end": 1570.94, "word": " ال", "probability": 0.8583984375}, {"start": 1570.94, "end": 1571.54, "word": " 140", "probability": 0.34423828125}, {"start": 1571.54, "end": 1572.5, "word": " طرحنا", "probability": 0.8824462890625}, {"start": 1572.5, "end": 1572.6, "word": " ال", "probability": 0.9130859375}, {"start": 1572.6, "end": 1573.0, "word": " 180", "probability": 0.921875}, {"start": 1573.0, "end": 1573.52, "word": " نقص", "probability": 0.8684895833333334}, {"start": 1573.52, "end": 1573.64, "word": " ال", "probability": 0.693359375}, {"start": 1573.64, "end": 1574.1, "word": " 50", "probability": 0.9658203125}, {"start": 1574.1, "end": 1574.9, "word": " طلعت", "probability": 0.9656575520833334}, {"start": 1574.9, "end": 1575.22, "word": " عندي", "probability": 0.8515625}, {"start": 1575.22, "end": 1575.52, "word": " انا", "probability": 0.904052734375}, {"start": 1575.52, "end": 1575.76, "word": " اللي", "probability": 0.803955078125}, {"start": 1575.76, "end": 1575.92, "word": " هي", "probability": 0.64208984375}, {"start": 1575.92, "end": 1576.04, "word": " ال", "probability": 0.9111328125}, {"start": 1576.04, "end": 1576.54, "word": " 140", "probability": 0.83447265625}, {"start": 1576.54, "end": 1576.96, "word": " درجة", "probability": 0.9856770833333334}, {"start": 1576.96, "end": 1577.2, "word": " عشان", "probability": 0.9913736979166666}, {"start": 1577.2, "end": 1578.08, "word": " احطها", "probability": 0.90771484375}, {"start": 1578.08, "end": 1579.22, "word": " طبعا", "probability": 0.9935302734375}, {"start": 1579.22, "end": 1579.76, "word": " بالموجب", "probability": 0.7459716796875}], "temperature": 1.0}, {"id": 72, "seek": 159650, "start": 1580.68, "end": 1596.5, "text": "فالجواب النهائي هي باستخدام المحصلة القانونية للـ magnitude بالساوية جزر R X تربيع زائد R Y تربيع 2.23 كيلومتر تربيع زائد 6.7 طبعا هذه موجبة موجبة", "tokens": [5172, 6027, 7435, 14407, 3555, 28239, 3224, 16373, 1829, 39896, 4724, 995, 14851, 9778, 3215, 10943, 9673, 5016, 9381, 37977, 25062, 7649, 11536, 10632, 24976, 39184, 15668, 20666, 3794, 995, 2407, 10632, 10874, 11622, 2288, 497, 1783, 6055, 2288, 21292, 3615, 30767, 16373, 3215, 497, 398, 6055, 2288, 21292, 3615, 568, 13, 9356, 9122, 26895, 20498, 2655, 2288, 6055, 2288, 21292, 3615, 30767, 16373, 3215, 1386, 13, 22, 23032, 3555, 3615, 995, 29538, 3714, 29245, 49401, 3714, 29245, 49401], "avg_logprob": -0.30683593787252905, "compression_ratio": 1.4702380952380953, "no_speech_prob": 2.980232238769531e-07, "words": [{"start": 1580.68, "end": 1581.5, "word": "فالجواب", "probability": 0.76898193359375}, {"start": 1581.5, "end": 1581.96, "word": " النهائي", "probability": 0.8726806640625}, {"start": 1581.96, "end": 1582.16, "word": " هي", "probability": 0.71484375}, {"start": 1582.16, "end": 1583.88, "word": " باستخدام", "probability": 0.85888671875}, {"start": 1583.88, "end": 1585.38, "word": " المحصلة", "probability": 0.62921142578125}, {"start": 1585.38, "end": 1585.92, "word": " القانونية", "probability": 0.7156982421875}, {"start": 1585.92, "end": 1586.12, "word": " للـ", "probability": 0.501220703125}, {"start": 1586.12, "end": 1586.68, "word": " magnitude", "probability": 0.630859375}, {"start": 1586.68, "end": 1587.46, "word": " بالساوية", "probability": 0.68974609375}, {"start": 1587.46, "end": 1587.88, "word": " جزر", "probability": 0.736328125}, {"start": 1587.88, "end": 1588.54, "word": " R", "probability": 0.17529296875}, {"start": 1588.54, "end": 1588.82, "word": " X", "probability": 0.3955078125}, {"start": 1588.82, "end": 1589.36, "word": " تربيع", "probability": 0.7657470703125}, {"start": 1589.36, "end": 1589.8, "word": " زائد", "probability": 0.73095703125}, {"start": 1589.8, "end": 1590.08, "word": " R", "probability": 0.93310546875}, {"start": 1590.08, "end": 1590.52, "word": " Y", "probability": 0.95703125}, {"start": 1590.52, "end": 1591.42, "word": " تربيع", "probability": 0.96337890625}, {"start": 1591.42, "end": 1592.28, "word": " 2", "probability": 0.37255859375}, {"start": 1592.28, "end": 1593.04, "word": ".23", "probability": 0.964599609375}, {"start": 1593.04, "end": 1593.76, "word": " كيلومتر", "probability": 0.77490234375}, {"start": 1593.76, "end": 1594.18, "word": " تربيع", "probability": 0.9176025390625}, {"start": 1594.18, "end": 1594.48, "word": " زائد", "probability": 0.8043619791666666}, {"start": 1594.48, "end": 1594.74, "word": " 6", "probability": 0.98681640625}, {"start": 1594.74, "end": 1595.22, "word": ".7", "probability": 0.991943359375}, {"start": 1595.22, "end": 1595.5, "word": " طبعا", "probability": 0.86968994140625}, {"start": 1595.5, "end": 1595.7, "word": " هذه", "probability": 0.435546875}, {"start": 1595.7, "end": 1596.08, "word": " موجبة", "probability": 0.8811848958333334}, {"start": 1596.08, "end": 1596.5, "word": " موجبة", "probability": 0.9269205729166666}], "temperature": 1.0}, {"id": 73, "seek": 161228, "start": 1597.42, "end": 1612.28, "text": "إذا موجودة في الربع الأول هي المحصلة موجودة في الربع الأول بتساوي 7.07 كيلومتر اتجاه المحصلة فيتا بتساوي tan inverse ry على rx فبحط ال ry إشارتها موجبة", "tokens": [28814, 15730, 3714, 29245, 23328, 3660, 8978, 34892, 3555, 3615, 16247, 12610, 39896, 9673, 5016, 9381, 37977, 3714, 29245, 23328, 3660, 8978, 34892, 3555, 3615, 16247, 12610, 39894, 3794, 995, 45865, 1614, 13, 16231, 9122, 26895, 20498, 2655, 2288, 1975, 2655, 7435, 40294, 9673, 5016, 9381, 37977, 6156, 36081, 995, 39894, 3794, 995, 45865, 7603, 17340, 20791, 15844, 367, 87, 6156, 49628, 9566, 2423, 20791, 11933, 8592, 9640, 2655, 11296, 3714, 29245, 49401], "avg_logprob": -0.20238598677757624, "compression_ratio": 1.655844155844156, "no_speech_prob": 5.960464477539062e-07, "words": [{"start": 1597.42, "end": 1597.78, "word": "إذا", "probability": 0.40740966796875}, {"start": 1597.78, "end": 1598.26, "word": " موجودة", "probability": 0.9078369140625}, {"start": 1598.26, "end": 1598.36, "word": " في", "probability": 0.96044921875}, {"start": 1598.36, "end": 1598.72, "word": " الربع", "probability": 0.7096354166666666}, {"start": 1598.72, "end": 1599.26, "word": " الأول", "probability": 0.98193359375}, {"start": 1599.26, "end": 1599.46, "word": " هي", "probability": 0.6357421875}, {"start": 1599.46, "end": 1599.98, "word": " المحصلة", "probability": 0.89404296875}, {"start": 1599.98, "end": 1600.34, "word": " موجودة", "probability": 0.9632568359375}, {"start": 1600.34, "end": 1600.44, "word": " في", "probability": 0.978515625}, {"start": 1600.44, "end": 1600.66, "word": " الربع", "probability": 0.9557291666666666}, {"start": 1600.66, "end": 1601.1, "word": " الأول", "probability": 0.99267578125}, {"start": 1601.1, "end": 1601.94, "word": " بتساوي", "probability": 0.785888671875}, {"start": 1601.94, "end": 1602.24, "word": " 7", "probability": 0.744140625}, {"start": 1602.24, "end": 1602.88, "word": ".07", "probability": 0.801025390625}, {"start": 1602.88, "end": 1603.7, "word": " كيلومتر", "probability": 0.7517578125}, {"start": 1603.7, "end": 1604.84, "word": " اتجاه", "probability": 0.8834228515625}, {"start": 1604.84, "end": 1605.54, "word": " المحصلة", "probability": 0.9124755859375}, {"start": 1605.54, "end": 1606.44, "word": " فيتا", "probability": 0.74267578125}, {"start": 1606.44, "end": 1607.24, "word": " بتساوي", "probability": 0.9525146484375}, {"start": 1607.24, "end": 1607.48, "word": " tan", "probability": 0.70703125}, {"start": 1607.48, "end": 1608.06, "word": " inverse", "probability": 0.8896484375}, {"start": 1608.06, "end": 1608.66, "word": " ry", "probability": 0.39208984375}, {"start": 1608.66, "end": 1608.92, "word": " على", "probability": 0.5283203125}, {"start": 1608.92, "end": 1609.62, "word": " rx", "probability": 0.887451171875}, {"start": 1609.62, "end": 1610.72, "word": " فبحط", "probability": 0.8810221354166666}, {"start": 1610.72, "end": 1610.82, "word": " ال", "probability": 0.98291015625}, {"start": 1610.82, "end": 1611.2, "word": " ry", "probability": 0.428466796875}, {"start": 1611.2, "end": 1611.84, "word": " إشارتها", "probability": 0.9265625}, {"start": 1611.84, "end": 1612.28, "word": " موجبة", "probability": 0.97119140625}], "temperature": 1.0}, {"id": 74, "seek": 164108, "start": 1612.64, "end": 1641.08, "text": "Rx إشارتها موجبة بتساوي 71.6 درجة هيك إحنا طبعا حددنا أي متجه ك magnitude للمتجه عبارة عن طبعا Rx تربيع زائد Ry تربيع اتجاه المحصلة هيكون tan inverse Ry على Rx وبهذا بنكون طبعا انتهينا من تسجيل وشرح الفصل الأول من فيزياء عامة لطلبة العلوم الصحية", "tokens": [49, 87, 11933, 8592, 9640, 2655, 11296, 3714, 29245, 49401, 39894, 3794, 995, 45865, 30942, 13, 21, 11778, 47341, 3660, 39896, 4117, 11933, 5016, 8315, 23032, 3555, 3615, 995, 11331, 3215, 3215, 8315, 36632, 44650, 7435, 3224, 9122, 15668, 5296, 19528, 2655, 7435, 3224, 6225, 3555, 9640, 3660, 18871, 23032, 3555, 3615, 995, 497, 87, 6055, 2288, 21292, 3615, 30767, 16373, 3215, 13654, 6055, 2288, 21292, 3615, 1975, 2655, 7435, 40294, 9673, 5016, 36520, 3660, 39896, 30544, 7603, 17340, 13654, 15844, 497, 87, 46599, 3224, 15730, 44945, 30544, 23032, 3555, 3615, 995, 16472, 47395, 1829, 8315, 9154, 6055, 3794, 7435, 26895, 4032, 46309, 5016, 27188, 36520, 16247, 12610, 9154, 8978, 11622, 1829, 16606, 6225, 10943, 3660, 5296, 9566, 46152, 3660, 18863, 1211, 20498, 31767, 5016, 10632], "avg_logprob": -0.14689960770719634, "compression_ratio": 1.5968992248062015, "no_speech_prob": 1.0728836059570312e-06, "words": [{"start": 1612.64, "end": 1613.18, "word": "Rx", "probability": 0.5794677734375}, {"start": 1613.18, "end": 1613.66, "word": " إشارتها", "probability": 0.8053955078125}, {"start": 1613.66, "end": 1614.16, "word": " موجبة", "probability": 0.9754231770833334}, {"start": 1614.16, "end": 1615.04, "word": " بتساوي", "probability": 0.8792724609375}, {"start": 1615.04, "end": 1615.56, "word": " 71", "probability": 0.853515625}, {"start": 1615.56, "end": 1616.4, "word": ".6", "probability": 0.983642578125}, {"start": 1616.4, "end": 1617.82, "word": " درجة", "probability": 0.9791666666666666}, {"start": 1617.82, "end": 1618.44, "word": " هيك", "probability": 0.796630859375}, {"start": 1618.44, "end": 1618.72, "word": " إحنا", "probability": 0.811279296875}, {"start": 1618.72, "end": 1619.12, "word": " طبعا", "probability": 0.9752197265625}, {"start": 1619.12, "end": 1620.22, "word": " حددنا", "probability": 0.970947265625}, {"start": 1620.22, "end": 1621.16, "word": " أي", "probability": 0.466552734375}, {"start": 1621.16, "end": 1621.64, "word": " متجه", "probability": 0.92138671875}, {"start": 1621.64, "end": 1621.78, "word": " ك", "probability": 0.97314453125}, {"start": 1621.78, "end": 1622.22, "word": " magnitude", "probability": 0.425048828125}, {"start": 1622.22, "end": 1622.8, "word": " للمتجه", "probability": 0.9517578125}, {"start": 1622.8, "end": 1623.2, "word": " عبارة", "probability": 0.9814453125}, {"start": 1623.2, "end": 1623.48, "word": " عن", "probability": 0.99609375}, {"start": 1623.48, "end": 1624.62, "word": " طبعا", "probability": 0.9415283203125}, {"start": 1624.62, "end": 1625.12, "word": " Rx", "probability": 0.754638671875}, {"start": 1625.12, "end": 1625.5, "word": " تربيع", "probability": 0.8570556640625}, {"start": 1625.5, "end": 1625.78, "word": " زائد", "probability": 0.75048828125}, {"start": 1625.78, "end": 1626.06, "word": " Ry", "probability": 0.5419921875}, {"start": 1626.06, "end": 1626.7, "word": " تربيع", "probability": 0.9669189453125}, {"start": 1626.7, "end": 1627.3, "word": " اتجاه", "probability": 0.92333984375}, {"start": 1627.3, "end": 1627.88, "word": " المحصلة", "probability": 0.8662109375}, {"start": 1627.88, "end": 1628.2, "word": " هيكون", "probability": 0.93603515625}, {"start": 1628.2, "end": 1628.42, "word": " tan", "probability": 0.41748046875}, {"start": 1628.42, "end": 1629.06, "word": " inverse", "probability": 0.908203125}, {"start": 1629.06, "end": 1630.3, "word": " Ry", "probability": 0.4970703125}, {"start": 1630.3, "end": 1630.8, "word": " على", "probability": 0.6044921875}, {"start": 1630.8, "end": 1631.94, "word": " Rx", "probability": 0.9443359375}, {"start": 1631.94, "end": 1633.04, "word": " وبهذا", "probability": 0.7706705729166666}, {"start": 1633.04, "end": 1633.44, "word": " بنكون", "probability": 0.796630859375}, {"start": 1633.44, "end": 1633.72, "word": " طبعا", "probability": 0.9901123046875}, {"start": 1633.72, "end": 1634.16, "word": " انتهينا", "probability": 0.79327392578125}, {"start": 1634.16, "end": 1634.54, "word": " من", "probability": 0.99609375}, {"start": 1634.54, "end": 1635.82, "word": " تسجيل", "probability": 0.9951171875}, {"start": 1635.82, "end": 1636.44, "word": " وشرح", "probability": 0.9051106770833334}, {"start": 1636.44, "end": 1637.18, "word": " الفصل", "probability": 0.943115234375}, {"start": 1637.18, "end": 1637.7, "word": " الأول", "probability": 0.968017578125}, {"start": 1637.7, "end": 1638.06, "word": " من", "probability": 0.9873046875}, {"start": 1638.06, "end": 1639.08, "word": " فيزياء", "probability": 0.8404541015625}, {"start": 1639.08, "end": 1639.48, "word": " عامة", "probability": 0.99658203125}, {"start": 1639.48, "end": 1640.04, "word": " لطلبة", "probability": 0.9495849609375}, {"start": 1640.04, "end": 1640.5, "word": " العلوم", "probability": 0.8232421875}, {"start": 1640.5, "end": 1641.08, "word": " الصحية", "probability": 0.9879557291666666}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1647.897, "duration_after_vad": 1611.7872187499986}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/_ZnJqTzAvfw_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/_ZnJqTzAvfw_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..d847bf6c6fb9ec51a9da1bd954ddf62869560e73
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/_ZnJqTzAvfw_postprocess.srt
@@ -0,0 +1,1024 @@
+1
+00:00:00,000 --> 00:00:05,260
+بسم الله الرحمن الرحيم نستكمل مساق فيزياء عامة
+
+2
+00:00:05,260 --> 00:00:10,220
+لطلب العلوم الصحية ونبدأ بـ chapter التاني بعنوان
+
+3
+00:00:10,220 --> 00:00:14,040
+motion in one dimension يعني الحركة في بعد واحد
+
+4
+00:00:14,040 --> 00:00:18,160
+section 2-1 بعنوان displacement, velocity and
+
+5
+00:00:18,160 --> 00:00:21,580
+acceleration displacement يعني الإزاحة velocity
+
+6
+00:00:21,580 --> 00:00:25,740
+يعني السرعة المتجهة and acceleration التسارع
+
+7
+00:00:25,740 --> 00:00:29,460
+بنتحدث عن displacement, velocity and acceleration
+
+8
+00:00:30,020 --> 00:00:35,200
+في تعريف الـ displacement لdescribe describing
+
+9
+00:00:35,200 --> 00:00:39,020
+motion requires some coordinate coordinate system
+
+10
+00:00:39,020 --> 00:00:44,740
+and specific origin عشان أنا أوصف أي يعني حركة
+
+11
+00:00:44,740 --> 00:00:51,680
+بحتاج إلى نظام محاور معينة وطبعا ومرجعية معينة
+
+12
+00:00:51,680 --> 00:00:56,460
+اللي هي specific origin سواء كان نقطة أو خطفي ..
+
+13
+00:00:56,460 --> 00:01:01,780
+في شكل اتنين اتنين كمثال يعني في عندى سيارة بتتحرك
+
+14
+00:01:01,780 --> 00:01:07,680
+خلال ال X axis سيارة بتتحرك على محور X the
+
+15
+00:01:07,680 --> 00:01:12,380
+coordinate of car at anytime describe its
+
+16
+00:01:12,380 --> 00:01:17,760
+positions طبعا السيارة بتتحرك في محور X المحاور
+
+17
+00:01:17,760 --> 00:01:21,180
+الكارتزية او اللى هو المحور الأفقي اللى بتتحرك فيه
+
+18
+00:01:21,180 --> 00:01:26,770
+السيارةعند أي زمن بيوصفلي طبعا مكان السيارة وين in
+
+19
+00:01:26,770 --> 00:01:30,310
+space and more importantly its displacement at
+
+20
+00:01:30,310 --> 00:01:33,950
+some given time of interest في هذه الحالة ممكن أنا
+
+21
+00:01:33,950 --> 00:01:38,710
+أعرف الإزاحة الإزاحة هي displacement هي عبارة عن
+
+22
+00:01:38,710 --> 00:01:43,750
+إزاحة متجهة لو أنا عند السيارة بدت من نقطة X1
+
+23
+00:01:43,750 --> 00:01:50,170
+وانتهت لنقطة X2فالفرق بين X2 ناقص X1 هي Delta X أو
+
+24
+00:01:50,170 --> 00:01:54,630
+الفرق بين إن السيارة بدأت من نقطة وانتهت لنقطة
+
+25
+00:01:54,630 --> 00:02:01,010
+أخرى في خلال مشوارها على محور X نقول إن الإزاحةهي
+
+26
+00:02:01,010 --> 00:02:04,810
+عبارة عن المسافة بين نقطة البداية والنهاية أو هي
+
+27
+00:02:04,810 --> 00:02:08,890
+عبارة عن X final ناقص X initial وهي تمثل الإزاحة
+
+28
+00:02:08,890 --> 00:02:12,850
+ويرمز لها بالرمز Delta X Delta X يعني هي عبارة عن
+
+29
+00:02:12,850 --> 00:02:18,010
+الفرق بين نقطة النهاية ناقص نقطة البدايةX initial
+
+30
+00:02:18,010 --> 00:02:21,810
+بيسموها ال initial position الموضوع الأول وال X
+
+31
+00:02:21,810 --> 00:02:25,530
+final is the final position إذا إذا أحنا ماشيين
+
+32
+00:02:25,530 --> 00:02:31,610
+على محور X عشان إيه سميتها Delta X طبعا ال unit of
+
+33
+00:02:31,610 --> 00:02:36,670
+displacement وحدة الإزاحة هي ال meter في نظام ال
+
+34
+00:02:36,670 --> 00:02:40,930
+system international أو النظام الدولي وحدتها meter
+
+35
+00:02:41,730 --> 00:02:44,770
+طبعا هذا الشكل اللي احنا حكينا عنه لو كان عندي
+
+36
+00:02:44,770 --> 00:02:50,350
+سيارة تتحرك من النقطة A للنقطة B the car move to
+
+37
+00:02:50,350 --> 00:02:54,110
+the right between positions A and B السيارة بتتحرك
+
+38
+00:02:54,110 --> 00:02:59,030
+خلال ال X-axis من النقطة A إلى النقطة B النقطة A
+
+39
+00:02:59,030 --> 00:03:03,370
+مقدرها 30 ال initial و النقطة B مقدرها 50 اللي هي
+
+40
+00:03:03,370 --> 00:03:06,910
+ال final فمعنى الكلام الإزاحة بهذه الحالة راح نحكي
+
+41
+00:03:06,910 --> 00:03:11,650
+Delta Xيعني X final اللي هي الخمسين ناقص X initial
+
+42
+00:03:11,650 --> 00:03:15,230
+تلاتين و بطلع عندي الجواب Delta X فهذه الحالة
+
+43
+00:03:15,230 --> 00:03:20,170
+عشرين لو كان عندي أنا السيارة في هذا الشكل تتحرك
+
+44
+00:03:20,170 --> 00:03:25,250
+to the left between point position C and F لو
+
+45
+00:03:25,250 --> 00:03:30,190
+السيارة رايحة لليسار بين النقطة C من هذه النقطة
+
+46
+00:03:30,190 --> 00:03:33,970
+اللي هي أربعين لنقطة F يعني السيارة هذه بعتبرها
+
+47
+00:03:33,970 --> 00:03:38,660
+نقطة البداية أربعينو ال F اللي هي minus 60 هي نقطة
+
+48
+00:03:38,660 --> 00:03:42,660
+النهاية فعند إيجاد Delta X لهذه الحالة ال X
+
+49
+00:03:42,660 --> 00:03:47,060
+النهائية كانت ناقص 60 الإبتدائية ناقص 40 فبنحكي
+
+50
+00:03:47,060 --> 00:03:51,520
+النهائية ناقص 60 ناقص ال 40 فبتطلع تقريبا ناقص 100
+
+51
+00:03:51,520 --> 00:03:58,520
+إذا إحنا بدنا نوجد اللي هي الإزاحة لنقطتينالشكل
+
+52
+00:03:58,520 --> 00:04:03,900
+هذا بوضح لي خط يعني منحنى ممثل بين ال X و ال T
+
+53
+00:04:03,900 --> 00:04:08,640
+منحنى بين ال position و بين الزمن المنحنى عندي انا
+
+54
+00:04:08,640 --> 00:04:14,860
+particle او سيارة تحركت من النقطة A لنقطة B لنقطة
+
+55
+00:04:14,860 --> 00:04:22,170
+C ثم D ثم A ثم F كطبعا هذا اللي هو الشكلهنا car في
+
+56
+00:04:22,170 --> 00:04:25,110
+هذا الشكل move back and forth along a straight
+
+57
+00:04:25,110 --> 00:04:30,450
+line taken to be the x-axis في B اللي هو عبارة عن
+
+58
+00:04:30,450 --> 00:04:35,330
+منحنى of position يعني منحنى بيمثل المكان او
+
+59
+00:04:35,330 --> 00:04:38,890
+الموقع versus time بالنسبة الموقع بالنسبة لزمن
+
+60
+00:04:38,890 --> 00:04:42,650
+time for the motion of the car بالنسبة لحركة
+
+61
+00:04:42,650 --> 00:04:49,820
+السيارة او حركة اي particleمن خلال تعريف الإزاحة
+
+62
+00:04:49,820 --> 00:04:54,440
+بلاحظ إن Delta X زي ما حكينا ممكن تكون موجبة أو
+
+63
+00:04:54,440 --> 00:04:59,580
+سالبة ف is positive إذا كانت ال X final أكبر من X
+
+64
+00:04:59,580 --> 00:05:03,180
+initial بتطلع لنا positive لإن Delta X بتساوي X
+
+65
+00:05:03,180 --> 00:05:07,700
+final ناقص X initial إذا كانت X initial أكبر من X
+
+66
+00:05:07,700 --> 00:05:11,590
+أو سالبة يعنيفبطلع ال position إذا كانت ال X
+
+67
+00:05:11,590 --> 00:05:15,250
+initial negative if X final is less than X initial
+
+68
+00:05:15,250 --> 00:05:19,750
+for example مثلا if the car move from A ل B لو
+
+69
+00:05:19,750 --> 00:05:23,310
+راحت من A ل B زي ما حكينا ال X final هنا كان
+
+70
+00:05:23,310 --> 00:05:28,810
+معرفها 52 حسب ال curve و ال X initial 30 فبتطلع
+
+71
+00:05:28,810 --> 00:05:33,650
+Delta X بتساوي 22 فالإزاحة اللي هي displacement is
+
+72
+00:05:33,650 --> 00:05:37,960
+in the positive X directionلو كان عندي أنا بالنسبة
+
+73
+00:05:37,960 --> 00:05:43,870
+لـ اللي حكيناها من المنطقة «C» للـ «File F»فبلاحظ
+
+74
+00:05:43,870 --> 00:05:48,690
+إن X final كانت 53 بالظبط و X initial كانت 38
+
+75
+00:05:48,690 --> 00:05:53,810
+فالجواب ناقص 91 متر هذا الاتجاه بيدللي فقط على
+
+76
+00:05:53,810 --> 00:05:59,770
+اتجاه الإزاحة إلى اليسار إذا ال displacement يعني
+
+77
+00:05:59,770 --> 00:06:04,590
+الإزاحة is in the negative X direction إذا كان هي
+
+78
+00:06:04,590 --> 00:06:09,320
+طلعت لي بالسالبالشكل طبعا اتنين بيه اللي هو عبارة
+
+79
+00:06:09,320 --> 00:06:13,180
+عن ال graph اللي هي عبارة عن يعني curve او منحنى
+
+80
+00:06:13,180 --> 00:06:18,520
+منحنى اللي هو يمثل اللي هو موقع السيارة بالنسبة ل
+
+81
+00:06:18,520 --> 00:06:21,700
+.. ل .. ده اللي فيه الزمن function يعني ده اللي
+
+82
+00:06:21,700 --> 00:06:25,510
+فيه ال time ده اللي في الزمنbecause the
+
+83
+00:06:25,510 --> 00:06:32,570
+displacement has both magnitude لأن الإزاحة لها
+
+84
+00:06:32,570 --> 00:06:38,110
+magnitude and direction فهي تعتبر يعني كمية
+
+85
+00:06:38,110 --> 00:06:42,690
+فيزيائية متجهة فال displacement is vector quantity
+
+86
+00:06:42,690 --> 00:06:47,450
+يعني هي كمية متجهة تعريف ل ال velocity ال velocity
+
+87
+00:06:47,450 --> 00:06:53,050
+هي عبارة عن سرعة ولكن لها اتجاه ولها مقدارin
+
+88
+00:06:53,050 --> 00:06:56,650
+everyday usage the term speed and velocity are
+
+89
+00:06:56,650 --> 00:07:01,130
+interchangeable in physics بالنسبة يعني بالحالة
+
+90
+00:07:01,130 --> 00:07:05,010
+يعني بالأيام العادية أو بحوار الناس مع بعض ممكن
+
+91
+00:07:05,010 --> 00:07:09,110
+يعتبروا ال velocity و ال speed زي بعض لكن بالفيزيا
+
+92
+00:07:09,110 --> 00:07:15,200
+في فرق بين ال velocity and speedالـ speed هي عبارة
+
+93
+00:07:15,200 --> 00:07:19,940
+عن scalar quantity هي عبارة عن مقدار ال velocity
+
+94
+00:07:19,940 --> 00:07:25,740
+وهي عبارة عن كمية يعني قياسية ال speed ده دول فقط
+
+95
+00:07:25,740 --> 00:07:29,820
+على المقدار having only magnitude having only
+
+96
+00:07:29,820 --> 00:07:34,840
+magnitude يعني لها مقدار فقط في حين أن ال velocity
+
+97
+00:07:34,840 --> 00:07:39,900
+عبارة عن كمية متجهة أيضا الكمية المتجهة having
+
+98
+00:07:39,900 --> 00:07:46,240
+both magnitudeand direction why must velocity be a
+
+99
+00:07:46,240 --> 00:07:50,520
+vector if you want to get to a town لو احنا روحنا
+
+100
+00:07:50,520 --> 00:07:56,120
+على بلد مثلا بتبعد سبعين kilometer away in an
+
+101
+00:07:56,120 --> 00:08:02,200
+hours timeفي ساعة it's not enough to drive at
+
+102
+00:08:02,200 --> 00:08:06,460
+speed of سبعين kilometer في الساعة you must travel
+
+103
+00:08:06,460 --> 00:08:09,800
+in the correct direction as well يعني لما بدنا
+
+104
+00:08:09,800 --> 00:08:15,020
+احنا نتجه لمنطقة معينة بتبعد سبعين kilometer نقول
+
+105
+00:08:15,020 --> 00:08:20,680
+ان احنا بنتحرك بسرعة سبعين kilometer في الساعةهذا
+
+106
+00:08:20,680 --> 00:08:24,200
+سبعين كيلومتر في الساعة هو مجرد مقدار السرعة اللي
+
+107
+00:08:24,200 --> 00:08:29,160
+انا بده اتحرك فيها لكي اتوجه الى هذه المدينة لكن
+
+108
+00:08:29,160 --> 00:08:33,480
+لو حكينا انه انا مشيت سبعين كيلومتر في الساعة
+
+109
+00:08:33,480 --> 00:08:37,880
+ناحية الشمال او الشرق او الجنوب معناه الكلام انا
+
+110
+00:08:37,880 --> 00:08:42,880
+بتحرك باتجاه طالما انا بتحرك باتجاه اذا بتكون عندى
+
+111
+00:08:42,880 --> 00:08:46,820
+انا velocity لها مقدار ولها اتجاه نيجي نعرف حاجة
+
+112
+00:08:46,820 --> 00:08:52,400
+اسمها average speedالـ Average Speed اللي هي عبارة
+
+113
+00:08:52,400 --> 00:08:57,920
+عن متوسط السرعة القياسية The average speed of an
+
+114
+00:08:57,920 --> 00:09:02,500
+object متوسط السرعة الاتجاهية لأي جسم over a given
+
+115
+00:09:02,500 --> 00:09:06,780
+time interval في فترة زمانية معينة is the length
+
+116
+00:09:06,780 --> 00:09:10,600
+of the path it traveled divided by the total
+
+117
+00:09:10,600 --> 00:09:15,820
+elapsed timeيعني تعريف السرعة القياسية السرعة
+
+118
+00:09:15,820 --> 00:09:21,200
+القياسية متوسط السرعة القياسية هو عبارة عن المسار
+
+119
+00:09:21,200 --> 00:09:26,140
+الفعلي المسار الفعلي الذي مشيته السيارة أو المسار
+
+120
+00:09:26,140 --> 00:09:32,480
+الفعلي الذي مشيها أي جسم على الزمن المستغرق خلال
+
+121
+00:09:32,480 --> 00:09:37,850
+هذا المشوار ف average speed هي V averageبدها تساوي
+
+122
+00:09:37,850 --> 00:09:41,730
+دي يعني distance المسافة الفعلية أو المسار الفعلي
+
+123
+00:09:41,730 --> 00:09:45,990
+على الزمن الكل أو التغير في الزمن هذا هو ال
+
+124
+00:09:45,990 --> 00:09:50,590
+average speed وتعريفها طبعا وحدة ال average speed
+
+125
+00:09:50,590 --> 00:09:54,130
+هي عبارة عن ال meter per second يعني ال متر في
+
+126
+00:09:54,130 --> 00:09:58,090
+الثانية بالنظام الدولي اللي هو اسمهsystem
+
+127
+00:09:58,090 --> 00:10:02,250
+international النظام الدولي اللى بقيس بال meter
+
+128
+00:10:02,250 --> 00:10:09,290
+kilogram ثانية بالنسبالى ال example ع هذا الكلام a
+
+129
+00:10:09,290 --> 00:10:14,890
+turtle اندي ربيت انجاج in a fortress over a
+
+130
+00:10:14,890 --> 00:10:21,620
+distance of 40 كيلو في عندي سلحفا و أرنببتسابقوا
+
+131
+00:10:21,620 --> 00:10:25,840
+على طريق طبعا على يعني في مسار يعني ماشي على
+
+132
+00:10:25,840 --> 00:10:31,820
+الأقدام في سباق الماشي على الأقدام مسافة أربع كيلو
+
+133
+00:10:31,820 --> 00:10:38,160
+طبعا الأرناب ماشي أو جري جري تقريبا نص كيلومتر بعد
+
+134
+00:10:38,160 --> 00:10:42,740
+هيك then stops بعد هيك توقفأخد هذا الزمن قدره
+
+135
+00:10:42,740 --> 00:10:49,100
+تسعين minutes إنها بعد ما اتوقف الوقوف أو اللي
+
+136
+00:10:49,100 --> 00:10:54,120
+يعني أخد قيلولة مدتها تسعين minutes upon a walking
+
+137
+00:10:54,120 --> 00:11:01,210
+he remember the rest and runs twice as fastهو جالس
+
+138
+00:11:01,210 --> 00:11:08,730
+بياخد قيلولة تذكر أنه في سباق ف جري جري ضعف السرعة
+
+139
+00:11:08,730 --> 00:11:12,980
+اللي هو جري فيها بالأولFinishing the course is a
+
+140
+00:11:12,980 --> 00:11:17,660
+total time طبعا استغلق الزمن الكل لهاي الرحلة
+
+141
+00:11:17,660 --> 00:11:25,000
+تقريبا 1.75 ساعة The rabbit wins طبعا the راس
+
+142
+00:11:25,000 --> 00:11:29,840
+الارنب كسب السبق المطلوب منه نوجد calculate the
+
+143
+00:11:29,840 --> 00:11:33,220
+average speed of the rabbit بد أوجد ال average
+
+144
+00:11:33,220 --> 00:11:38,020
+speedلإيجاد الـ Average Speed أنا محتاج أوجد الـ
+
+145
+00:11:38,020 --> 00:11:42,420
+Total Distance يعني المسافة الفعلية أو المسار
+
+146
+00:11:42,420 --> 00:11:46,280
+الفعلي اللي الأرناب ماشيين طبعا الـ Average Speed
+
+147
+00:11:46,280 --> 00:11:51,080
+أنا المسار الفعلي مقداره 4 كيلومتر و الزمن كله 1
+
+148
+00:11:51,080 --> 00:11:56,660
+.75 ساعة إذا الـ Average Speed بدها تساوي 2.29
+
+149
+00:11:56,660 --> 00:12:01,980
+كيلومتر في الساعةNimra B what was his average
+
+150
+00:12:01,980 --> 00:12:06,640
+speed before he stopped for enough طبعا what was
+
+151
+00:12:06,640 --> 00:12:10,280
+his average speed بده متوسط السرعة القياسية
+
+152
+00:12:10,280 --> 00:12:15,220
+للمرحلة قبل ما انه يتوقف و ياخد قيلولة طبعا هو
+
+153
+00:12:15,220 --> 00:12:21,560
+ماشي نص نص نص kilometerلكن الساعة اللى مشي اللى
+
+154
+00:12:21,560 --> 00:12:26,160
+طبعا انا هو توقف لمدة تسعين دقيقة فالتسعين دقيقة
+
+155
+00:12:26,160 --> 00:12:30,840
+عبارة عن واحد و نص ساعة فهو أخد قيلولة مدتها واحد
+
+156
+00:12:30,840 --> 00:12:36,040
+و نص ساعة من الزمن الكلي فهنطرح الزمن الكلي اللى
+
+157
+00:12:36,040 --> 00:12:40,320
+هو واحد point سبعة خمسة ناقص الواحد و نص حيث هو
+
+158
+00:12:40,320 --> 00:12:45,020
+عندى ربع ساعة هذا الربع ساعة هو الزمن اللى استغرقه
+
+159
+00:12:45,020 --> 00:12:51,030
+الارنب في اللى هىالمشي او الجري او الجري في مرحلة
+
+160
+00:12:51,030 --> 00:12:55,350
+السباق طبعا طرحت منه اللى هو تسعين دقيقة اللى
+
+161
+00:12:55,350 --> 00:13:00,030
+الأرنب كان فيها نايم some of running times الان
+
+162
+00:13:00,030 --> 00:13:04,330
+انا الفترة كلها ال point خمسة اتنينكانت عبارة عن
+
+163
+00:13:04,330 --> 00:13:07,670
+مرحلة أولى ومرحلة تانية طبعا استثنانها مرحلة اللى
+
+164
+00:13:07,670 --> 00:13:13,010
+هو الراحة ال T1 زي ال T2 كانت بتساوي ربع ساعة فT1
+
+165
+00:13:13,010 --> 00:13:18,450
+بدها تساوي D1 على V1 وT2 بدها تساوي D2 على V2
+
+166
+00:13:18,450 --> 00:13:22,390
+الزمن بيساوي مسافة على سرعة والزمن التانية المسافة
+
+167
+00:13:22,390 --> 00:13:27,270
+التانية على السرعة التانيةالمسافة الأولى هو مشي نص
+
+168
+00:13:27,270 --> 00:13:31,950
+كيلو والمسافة الكلية أربعة كيلو فبطرح الأربعة كيلو
+
+169
+00:13:31,950 --> 00:13:35,270
+ناقص النص بطلع عندى المسافة التانية تلاتة و نص
+
+170
+00:13:35,270 --> 00:13:41,110
+المسافة الأولى كانت سريعتها V1 المسافة التانية لما
+
+171
+00:13:41,110 --> 00:13:46,040
+حس أنه متأخرصارت سرعتها 2 ضعف السرعة الأولى 2 V1
+
+172
+00:13:46,040 --> 00:13:52,500
+بدها تساوي 0.25 hour وبالتالي من خلال هذه المعادلة
+
+173
+00:13:52,500 --> 00:13:58,180
+التانية بقى حل لإيجاد V1 وبتطلع عندي السرعة الأولى
+
+174
+00:13:58,180 --> 00:14:02,300
+أو السرعة اللى هو ماشي فيها هي عبارة عن 9 كيلومتر
+
+175
+00:14:02,300 --> 00:14:06,340
+في الساعة طبعا تعريف آخر اللى هو ال average
+
+176
+00:14:06,340 --> 00:14:10,200
+velocityالـ leverage velocity بتشبه ال average
+
+177
+00:14:10,200 --> 00:14:15,240
+speed لكن ال average velocity بحتاج فيها على
+
+178
+00:14:15,240 --> 00:14:19,140
+الاتجاه ال average velocity عبارة عن كمية vector
+
+179
+00:14:19,140 --> 00:14:24,080
+quantity كمية متجهة لها قيمة لها magnitude and
+
+180
+00:14:24,080 --> 00:14:29,020
+direction لها magnitude and directionأذا تعريف الـ
+
+181
+00:14:29,020 --> 00:14:33,120
+Average Velocity الإشارة هذه V وعليها شرطة during
+
+182
+00:14:33,120 --> 00:14:38,300
+a time interval ΔT خلال فترة زمنية ΔT is is the
+
+183
+00:14:38,300 --> 00:14:43,240
+displacement ΔX divided by ΔT فالـ V average اللي
+
+184
+00:14:43,240 --> 00:14:46,540
+عشان أفرقها بين الـ V average speed هي عبارة عن
+
+185
+00:14:46,540 --> 00:14:50,000
+حرف الـ V وعليها شرطة هي عبارة عن هادي متوسط
+
+186
+00:14:50,000 --> 00:14:57,270
+السرعة الاتجاهية بدها تساوي ΔX على ΔTDelta X هي
+
+187
+00:14:57,270 --> 00:15:01,330
+عبارة عن X final ناقص X initial وDelta T هي عبارة
+
+188
+00:15:01,330 --> 00:15:07,030
+عن T final ناقص T initial Unit طبعا نفس وحدة ال
+
+189
+00:15:07,030 --> 00:15:10,230
+speed هي نفس وحدة ال velocity هي عبارة عن meter
+
+190
+00:15:10,230 --> 00:15:14,520
+per second في النظام الدوليunlike the average
+
+191
+00:15:14,520 --> 00:15:17,260
+speed which is always positive طبعا ال average
+
+192
+00:15:17,260 --> 00:15:20,920
+speed هي عبارة عن magnitude لل average velocity
+
+193
+00:15:20,920 --> 00:15:24,780
+وبالتالي ال average speed is always positive هي
+
+194
+00:15:24,780 --> 00:15:29,760
+عبارة عن قيمة مطلقة وهي موجبةلكن ال average
+
+195
+00:15:29,760 --> 00:15:32,800
+velocity of an object is an one dimension can be
+
+196
+00:15:32,800 --> 00:15:36,540
+either ممكن تكون positive و ممكن تكون negative إذا
+
+197
+00:15:36,540 --> 00:15:39,780
+الفرق بين ال average speed و ال average velocity
+
+198
+00:15:39,780 --> 00:15:44,420
+ال average speed هي كمية قياسية و هي دائما موجب ال
+
+199
+00:15:44,420 --> 00:15:48,260
+average velocity كمية متجهة و هي ممكن تكون موجب أو
+
+200
+00:15:48,260 --> 00:15:54,160
+سالب حسب اتجاه الجسمتعتمد على طبعا الإزاحة وتعتمد
+
+201
+00:15:54,160 --> 00:15:58,640
+على اتجاه الجسم وين رايح لناخد مثال على ال average
+
+202
+00:15:58,640 --> 00:16:02,580
+velocity of the car is positive in the upper
+
+203
+00:16:02,580 --> 00:16:04,960
+illustration in the negative in the lower
+
+204
+00:16:04,960 --> 00:16:08,760
+illustration طبعا بالنسبة لهذا الشكل بالنسبة لهذا
+
+205
+00:16:08,760 --> 00:16:13,520
+الشكل بلاحظ أنه ال average velocity كمية متجهة
+
+206
+00:16:13,520 --> 00:16:17,800
+وقيمتها موجبة لإنه أنا عند مشيت انا من ال a ل ال b
+
+207
+00:16:18,490 --> 00:16:22,810
+فمعنى الكلام هنحكي احنا بيه vx final نقص x initial
+
+208
+00:16:22,810 --> 00:16:26,450
+اللي هي delta x تطلع لي موجب لكن بالنسبة للشكل
+
+209
+00:16:26,450 --> 00:16:30,530
+التاني بلاحظ أنه تطلع لي delta x تطلع لي سالب
+
+210
+00:16:30,530 --> 00:16:36,910
+السالب تدل على أنه اتجاه اتجاه هذه الطبعا السرعة
+
+211
+00:16:36,910 --> 00:16:43,210
+اتجاهها بالسالبas an example we can use the data
+
+212
+00:16:43,210 --> 00:16:46,930
+طبعا استخدمنا احنا البيانات اللى فى هذا الجدول لو
+
+213
+00:16:46,930 --> 00:16:49,870
+انا اخدت ان اندي هذا بيمثل ال position موقع
+
+214
+00:16:49,870 --> 00:16:54,810
+السيارة عندى منطقة A و B و C و D و F و E فى عند ال
+
+215
+00:16:54,810 --> 00:16:59,430
+A زى لما كانت T صفر كانت X تلاتين لما عند ال B
+
+216
+00:16:59,430 --> 00:17:06,010
+كانت T عشرة و X اتنين و خمسينطيب لما بدوجد المسافة
+
+217
+00:17:06,010 --> 00:17:10,110
+أو ال average velocity بين A و B راح نحكي X final
+
+218
+00:17:10,110 --> 00:17:15,270
+اللي هي 52 نخص X initial اللي هي 30 فبطلع معايا 2
+
+219
+00:17:15,270 --> 00:17:18,930
+.2 موجة معناه ال velocity في هذه الحالة موجة بقى
+
+220
+00:17:18,930 --> 00:17:25,160
+لكن لو أخدت أنا من عند مثلا C ل F من C ل Fبلاحظ
+
+221
+00:17:25,160 --> 00:17:30,300
+أنه من «C» لـ «F» الـ «Final» كانت ناقص 53، ناقص
+
+222
+00:17:30,300 --> 00:17:38,300
+38، فالجواب بيكون سالب، فعشان أوضح هذه العلاقة بين
+
+223
+00:17:38,300 --> 00:17:41,480
+الـ «Average Speed» و «Average Velocity»، suppose
+
+224
+00:17:41,480 --> 00:17:45,320
+اي car full of bath، طبعا أفرض في عند سيارة مشيت
+
+225
+00:17:45,320 --> 00:17:51,290
+من «B» ل«Q»و سيارة تانية car path from B لـ Q
+
+226
+00:17:51,290 --> 00:17:54,830
+during the same time interval لو في عند السيارة
+
+227
+00:17:54,830 --> 00:17:59,170
+بدأت من النقطة B و راحت لـ Q سيارة تانية بدأت من Q
+
+228
+00:17:59,170 --> 00:18:03,670
+و بدأت أيضًا بمسار تاني برضه أيضًا من B لQ لكن
+
+229
+00:18:03,670 --> 00:18:09,050
+بمسار تاني خلال فترة زمانية Delta T طبعًا في هذه
+
+230
+00:18:09,050 --> 00:18:13,910
+الحالة فـ Delta T للباث الأول بيساوي Delta T
+
+231
+00:18:13,910 --> 00:18:18,690
+للمسار التاني لأنه حكى لي بنفس الفترة الزمانيةلكن
+
+232
+00:18:18,690 --> 00:18:22,150
+ال V average لل bath الأول بتساوي ال V average لل
+
+233
+00:18:22,150 --> 00:18:26,150
+bath التانية، ليش؟ لأنه أنا الإزاحة هي عبارة عن
+
+234
+00:18:26,150 --> 00:18:30,970
+أقصر مسافة من نقطة البداية للنهاية، الإزاحة هي
+
+235
+00:18:30,970 --> 00:18:34,250
+أقصر مسافة من نقطة البداية للنهاية، يعني في عندي
+
+236
+00:18:34,250 --> 00:18:39,310
+جسم بدأ من النقطة B و راح ل Q في المسار الأحمروجسم
+
+237
+00:18:39,310 --> 00:18:42,210
+تاني بدأ من النقطة B للمصاري cube في المصاري
+
+238
+00:18:42,210 --> 00:18:46,250
+الأزرق الباث الأولاني والمصاري الأزرق والمصاري
+
+239
+00:18:46,250 --> 00:18:50,870
+الأحمر اللهم نفس الزمن في هذه الحالة لو بدي أخد
+
+240
+00:18:50,870 --> 00:18:55,730
+أنا المصاري الأحمر الإزاحة تبعته Delta XDelta X
+
+241
+00:18:55,730 --> 00:18:59,510
+اللي هي عبارة عن X final نقص initial المسار الأزرق
+
+242
+00:18:59,510 --> 00:19:03,610
+الإزاحة تبعته هي عبارة عن نقطة أقصر نقطة أو أقصر
+
+243
+00:19:03,610 --> 00:19:07,370
+مسافة بين نقطة البداية لنقطة النهاية فبتطلع X
+
+244
+00:19:07,370 --> 00:19:11,410
+final نقص X initial معنى الكلام ال V average ده
+
+245
+00:19:11,410 --> 00:19:15,630
+المسار الأول بيساوي ال V average ده المسار التاني
+
+246
+00:19:15,630 --> 00:19:20,940
+لكن لو أجيت أخد ال V اللي هي average speedleverage
+
+247
+00:19:20,940 --> 00:19:26,360
+speed ايش مع تعريفها انه هي عبارة عن ال total path
+
+248
+00:19:26,360 --> 00:19:29,720
+يعني المسار كله او ال total distance طيب لو اجت
+
+249
+00:19:29,720 --> 00:19:33,400
+للمسار الأول الأزرق هو ماشي مسافة هاد مسافة كبيرة
+
+250
+00:19:34,720 --> 00:19:39,180
+المسار التاني مشي الأحمر من ال BLQ فالمسار الأول
+
+251
+00:19:39,180 --> 00:19:43,460
+أكبر من المسار التاني والزمن متساوي بيطلع عند V
+
+252
+00:19:43,460 --> 00:19:48,800
+average للمسار الأول أكبر من ال V average للمسار
+
+253
+00:19:48,800 --> 00:19:53,430
+التاني يعني ال average speed للمسار الأول أكبرمن
+
+254
+00:19:53,430 --> 00:19:58,270
+الـ average speed للمسار التاني لأن المسافة اللى
+
+255
+00:19:58,270 --> 00:20:03,650
+مشيها المسار الأول أكبر من المسافة للمسار التاني
+
+256
+00:20:03,650 --> 00:20:08,590
+طبعا المرة الجاية بنستكمل ان شاء الله بقية الشطر
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/amzXVM5Nljk.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/amzXVM5Nljk.srt
new file mode 100644
index 0000000000000000000000000000000000000000..9cfcaa26da147318b26074b3ad2ec75770e7eb80
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/amzXVM5Nljk.srt
@@ -0,0 +1,1390 @@
+1
+00:00:00,740 --> 00:00:05,720
+بسم الله الرحمن الرحيم طبعا بنستمر في شرح chapter
+
+2
+00:00:05,720 --> 00:00:11,300
+5 و مع section spring potential energy او اللي هي
+
+3
+00:00:11,300 --> 00:00:14,540
+ال elastic potential energy تاخد الوضع المرنية
+
+4
+00:00:14,540 --> 00:00:19,720
+داخل ال spring الان بدنا نحسب الشغل المبذول بواسطة
+
+5
+00:00:19,720 --> 00:00:23,870
+ال spring او المبذول consider a horizontal spring
+
+6
+00:00:23,870 --> 00:00:29,250
+and mass  بأُفضّل، في عندي أنا نابض مشبوك بكتلة أو
+
+7
+00:00:29,250 --> 00:00:34,390
+مربوطة مع كتلة وموضوعين بشكل أفقي بوضع الاتزان
+
+8
+00:00:34,390 --> 00:00:37,970
+يعني ال spring لا هو مضغوط ولا هو مشدود we
+
+9
+00:00:37,970 --> 00:00:41,970
+determine the work done بدنا نحسب الشغل المبذول
+
+10
+00:00:41,970 --> 00:00:45,810
+بواسطة هذا النابض when compressed by an applied
+
+11
+00:00:45,810 --> 00:00:49,310
+force from equilibrium to displacement X بدي أحسب
+
+12
+00:00:49,760 --> 00:00:57,200
+الشغل المبذول للنابض عندما يكون مضغوط بواسطة قوة
+
+13
+00:00:57,200 --> 00:01:01,420
+مضافة له من ال equilibrium position مسافة X the
+
+14
+00:01:01,420 --> 00:01:04,000
+spring force points in the direction opposite the
+
+15
+00:01:04,000 --> 00:01:12,440
+motion القوة، نقطة القوة اتجاه عكس الحركة so we
+
+16
+00:01:12,440 --> 00:01:18,300
+expect the work to be negative طبعا الشغل سالب لأن
+
+17
+00:01:18,300 --> 00:01:22,540
+القوة عكس اللي هي الحركة when we studied the
+
+18
+00:01:22,540 --> 00:01:27,160
+constant force عندما أدرس القوة الثابتة، القوة for the
+
+19
+00:01:27,160 --> 00:01:30,560
+gravity near earth surface we found the work done
+
+20
+00:01:30,560 --> 00:01:32,700
+on an object by multiplying the gravitational
+
+21
+00:01:32,700 --> 00:01:36,240
+force by the vertical displacement لما بدي أحسب
+
+22
+00:01:36,240 --> 00:01:42,480
+أنا الشغل المبذول بواسطة الجاذبية، بأحسب طبعا الشغل
+
+23
+00:01:42,480 --> 00:01:47,550
+هو ضرب القوة في الإزاحة، إذا كانت القوة والإزاحة بنفس
+
+24
+00:01:47,550 --> 00:01:51,350
+الاتجاه بيكون الشغل موجب، إذا كانت القوة والإزاحة
+
+25
+00:01:51,350 --> 00:01:56,110
+عكس بعض بيكون الشغل سالب، هذا بالنسبة للجاذبية اللي
+
+26
+00:01:56,110 --> 00:02:00,470
+يعني الحركة باتجاه ال vertical displacement of the
+
+27
+00:02:00,470 --> 00:02:04,890
+object على أي حال this procedure can't be used
+
+28
+00:02:04,890 --> 00:02:09,150
+with varying force spring force طبعا هذا الكلام
+
+29
+00:02:09,150 --> 00:02:15,710
+بيختلف عن ال spring لأنه في قوة متغيرة، فبدأ آخذ أنا
+
+30
+00:02:15,710 --> 00:02:18,710
+ال average force، ال average force بيساوي ال F0
+
+31
+00:02:18,710 --> 00:02:24,810
+زائد F1 على 2، ال F0، F0 بيساوي 0، و F1 = KX على 2، بتطلع
+
+32
+00:02:24,810 --> 00:02:29,990
+ناقص KX على 2، هذه هي ال force اللي هي ال average
+
+33
+00:02:29,990 --> 00:02:34,530
+force، بناء عليه the work done اللي هي average
+
+34
+00:02:34,530 --> 00:02:39,490
+force في X، اللي هي نص KX، طبعا نص KX مضروبة في X
+
+35
+00:02:39,490 --> 00:02:43,800
+بتطلع ناقص نص KX تربيع، هذا WS هو عبارة عن الشغل
+
+36
+00:02:43,800 --> 00:02:49,960
+المبذول بواسطة ال spring، أو spring work بصفة عامة
+
+37
+00:02:49,960 --> 00:02:54,200
+when the spring is stretched or compressed from X
+
+38
+00:02:54,200 --> 00:02:57,720
+initial to X final، the work done by the spring
+
+39
+00:02:57,720 --> 00:03:02,760
+بصفة عامة الشغل المبذول بواسطة ال spring سواء كان
+
+40
+00:03:02,760 --> 00:03:06,810
+مشدود أو مضغوط من نقطة ال X initial ل X final
+
+41
+00:03:06,810 --> 00:03:13,650
+يُعطى بهذا الشكل، WS بتساوي ناقص نص X final تربيع
+
+42
+00:03:13,650 --> 00:03:19,190
+ناقص نص X initial تربيع، الشغل المبذول بواسطة ال
+
+43
+00:03:19,190 --> 00:03:25,390
+spring أيضا ضمن نظرية الشغل والطاقة، فاحنا بنفرض
+
+44
+00:03:25,390 --> 00:03:31,260
+في معادلة 513 كما هو طبعا آت لاحقا، now include the
+
+45
+00:03:31,260 --> 00:03:34,620
+work done by the spring on the left hand side طبعا
+
+46
+00:03:34,620 --> 00:03:38,220
+على الـ ... طبعا ال left hand side بيمثل ال work
+
+47
+00:03:38,220 --> 00:03:42,460
+done by the spring اللي هي WNC = ΔK، زي
+
+48
+00:03:42,460 --> 00:03:48,280
+ΔU ... ΔK = ΔPE، التغير في طاقة الحركة
+
+49
+00:03:48,280 --> 00:03:51,220
+على التغير في طاقة ... زائد التغير في طاقة الوضع
+
+50
+00:03:51,220 --> 00:03:57,840
+بدنا نضيف طبعا الشغل الناتج عن ال spring للناحية
+
+51
+00:03:57,840 --> 00:04:01,560
+اليسار، فبكون عندنا WNC، شغل ال non conservative
+
+52
+00:04:01,560 --> 00:04:06,480
+ناقص الشغل الناتج عن اللي هو ال spring، أو التغير
+
+53
+00:04:06,480 --> 00:04:08,900
+في الشغل الناتج عن ال spring، اللي هو نص K X final
+
+54
+00:04:08,900 --> 00:04:12,860
+تربيع ناقص نص K X initial تربيع = ΔK
+
+55
+00:04:12,860 --> 00:04:17,540
+زائد ΔPE<sub>G</sub>، هي عبارة عن الـ Gravitational
+
+56
+00:04:17,540 --> 00:04:25,820
+Potential Energy، والـ ΔPE<sub>S</sub> هي عبارة عن Spring
+
+57
+00:04:25,820 --> 00:04:29,580
+Potential Energy، ال Elastic Potential Energy
+
+58
+00:04:29,580 --> 00:04:33,660
+مرتبطة بالـ Spring Force Constant، أو Spring Force
+
+59
+00:04:33,660 --> 00:04:38,000
+فالـ Potential Energy for Spring = بسؤ نص K X تربيع
+
+60
+00:04:38,860 --> 00:04:43,160
+ال potential energy for spring طبعا سواء كان مشدود
+
+61
+00:04:43,160 --> 00:04:47,240
+أو مضغوط مسافة X، ال K بيسموها spring constant، وال
+
+62
+00:04:47,240 --> 00:04:50,980
+X هي عبارة عن اللي هي المسافة اللي  النابض أو
+
+63
+00:04:50,980 --> 00:04:55,920
+النابض بينشدها أو بينضغطها من نقطة الاتزان، وحدة
+
+64
+00:04:55,920 --> 00:05:01,140
+اللي هي طاقة الوضع لل spring هي Joule، النظام الـ
+
+65
+00:05:01,140 --> 00:05:05,080
+system international، أو النظام اللي هو العالمي
+
+66
+00:05:05,080 --> 00:05:08,540
+inserting this expression into the previous
+
+67
+00:05:08,540 --> 00:05:11,920
+equation and rearrange gives the new form of the
+
+68
+00:05:11,920 --> 00:05:15,480
+work-energy theorem، طبعا الآن بدنا نضيف اللي
+
+69
+00:05:15,480 --> 00:05:19,080
+هي طاقة الوضع المرنية الخاصة بال spring، لقى القانون
+
+70
+00:05:19,080 --> 00:05:23,640
+الأساسي اللي أخدناه سابقا، بتطلع أن W<sub>NC</sub> =
+
+71
+00:05:23,640 --> 00:05:30,080
+ΔK + ΔPE<sub>G</sub> + ΔPE<sub>S</sub>، بنسميها
+
+72
+00:05:30,080 --> 00:05:32,320
+الـ Spring، هذه الـ Gravitational Potential Energy
+
+73
+00:05:32,320 --> 00:05:35,320
+وهذه اللي هي الـ Elastic Energy، W<sub>NC</sub> is the work
+
+74
+00:05:35,320 --> 00:05:39,760
+done by the non-conservative force، الشغل اللي هو
+
+75
+00:05:39,760 --> 00:05:43,040
+W<sub>NC</sub> هو عبارة عن الشغل المبذول بواسطة القوة الغير
+
+76
+00:05:43,040 --> 00:05:49,400
+محفوظة، زي قوة الاحتكاك، KE عبارة عن طاقة الحركة، PE<sub>G</sub>
+
+77
+00:05:49,400 --> 00:05:55,140
+عبارة عن طاقة الوضع الخاصة بالجاذبية، و PE<sub>S</sub> عبارة عن
+
+78
+00:05:55,140 --> 00:05:57,580
+Elastic Potential Energy، طاقة الوضع الخاص بالـ
+
+79
+00:05:57,580 --> 00:06:02,000
+Spring، PE<sub>S</sub>، ال potential energy will henceforth
+
+80
+00:06:02,000 --> 00:06:04,480
+denote the total potential energy of the system
+
+81
+00:06:04,480 --> 00:06:07,400
+including potential energy due to all
+
+82
+00:06:07,400 --> 00:06:10,760
+conservative forces acting on the system، طبعا ال
+
+83
+00:06:10,760 --> 00:06:15,020
+PE<sub>S</sub> هي ممكن تشمل ال PE<sub>G</sub>، ال gravitational potential
+
+84
+00:06:15,020 --> 00:06:20,960
+energy + ال spring potential energy، الشكل 521C
+
+85
+00:06:20,960 --> 00:06:25,080
+بيظهر أو يبين how the stored elastic potential
+
+86
+00:06:25,080 --> 00:06:28,660
+energy can be recovered، كيف أن طاقة الوضع المرنية
+
+87
+00:06:28,660 --> 00:06:32,660
+المخزونة داخل ال spring ممكن طبعا recover، إنه
+
+88
+00:06:32,660 --> 00:06:36,700
+ترجعها، أو ترجع ال spring أو النابض إلى وضع طبيعي
+
+89
+00:06:36,700 --> 00:06:40,120
+when the block is released، لما الكتلة اللي طبعا
+
+90
+00:06:40,120 --> 00:06:44,780
+اللي متصلة بـ ال spring تنطلق، ال spring snaps
+
+91
+00:06:44,780 --> 00:06:48,520
+back to its original length، يعني ممكن أنا أضغط هذا
+
+92
+00:06:48,520 --> 00:06:51,120
+ال spring بكتلة معينة، وبعدين نتركها، بلاحظ أن ال
+
+93
+00:06:51,120 --> 00:06:56,160
+spring برجع لوضعه الطبيعي، لما تكون x = 0
+
+94
+00:06:56,160 --> 00:07:01,340
+طبعا اللي بيصير اللي هو ال stored elastic
+
+95
+00:07:01,340 --> 00:07:04,380
+potential energy is converted to kinetic energy of
+
+96
+00:07:04,380 --> 00:07:10,080
+the block، لما يكون ال spring مضغوط بيكون مخزون
+
+97
+00:07:10,080 --> 00:07:15,380
+جواه طاقة وضع، عندما طبعا أترك هذه الكتلة، تتحول
+
+98
+00:07:15,380 --> 00:07:18,400
+طاقة الوضع إلى طاقة حركة لهذا ال block، أو هذه
+
+99
+00:07:18,400 --> 00:07:21,840
+الكتلة، The elastic potential energy stored in the
+
+100
+00:07:21,840 --> 00:07:25,720
+spring is zero، ال potential energy، طاقة الوضع لل
+
+101
+00:07:25,720 --> 00:07:29,100
+spring بتكون zero لما تكون في equilibrium position
+
+102
+00:07:29,100 --> 00:07:34,770
+يعني x = 0، تحت الوضع المخزونة داخل ال spring
+
+103
+00:07:34,770 --> 00:07:40,130
+when it's stretched، إذا كانت stretched يعني مشدودة
+
+104
+00:07:40,130 --> 00:07:45,410
+أو مضغوطة = نص K X تربيع، إذا further ...
+
+105
+00:07:45,410 --> 00:07:49,950
+further، the elastic potential energy is maximum
+
+106
+00:07:49,950 --> 00:07:53,110
+اللي هي ال potential energy بتكون maximum لما ال
+
+107
+00:07:53,110 --> 00:07:57,510
+spring has reached its maximum compression or
+
+108
+00:07:57,510 --> 00:08:01,770
+extension، لما هذا النابض أو هذا الـ spring يكون
+
+109
+00:08:01,770 --> 00:08:05,770
+مشدود على الآخر أو مضغوط على الآخر، ويكون وصل إلى
+
+110
+00:08:05,770 --> 00:08:09,130
+أعلى قيمة لل potential energy لل spring اللي هي
+
+111
+00:08:09,130 --> 00:08:13,890
+نص K X تربيع، وبالتالي ال potential energy لل spring
+
+112
+00:08:13,890 --> 00:08:18,590
+is always positive، لأن ال X<sup>2</sup> = X تربيع
+
+113
+00:08:18,590 --> 00:08:21,670
+وبالتالي لو كان موجب أو سالب، فال X تربيع بيكون
+
+114
+00:08:21,670 --> 00:08:28,250
+موجبة، ف in absence في عدم وجود W<sub>NC</sub> أو اللي هو ال
+
+115
+00:08:28,250 --> 00:08:31,930
+non conservative force، أو الشغل المبذول عن القوة
+
+116
+00:08:31,930 --> 00:08:35,990
+الغير محفوظة، ممكن أنا أعتبره = 0، في عدم
+
+117
+00:08:35,990 --> 00:08:40,030
+وجود ال friction، معنى الكلام إنه في عندي أنا صار
+
+118
+00:08:40,030 --> 00:08:43,010
+عندي طاقة حركة، طاقة وضع، طاقة وضع مرونية لل spring
+
+119
+00:08:43,010 --> 00:08:46,590
+في ال initial بتساوي طاقة حركة + طاقة وضع +
+
+120
+00:08:46,590 --> 00:08:50,230
+طاقة وضع مرونية داخل ال spring في حالة ال final
+
+121
+00:08:51,080 --> 00:08:55,660
+المسائل بتشمل الـ spring والـ gravity، وأي قوة
+
+122
+00:08:55,660 --> 00:09:00,080
+ثانية ممكن تضاف إلى النظام أو إلى النظام، ممكن أنا
+
+123
+00:09:00,080 --> 00:09:03,220
+أحلها، بعين الاعتبار أن ده حل إيه، هاي المسائل
+
+124
+00:09:03,220 --> 00:09:06,400
+باستخدام الـ mechanical energy، أو المسائل المحلولة
+
+125
+00:09:06,400 --> 00:09:11,620
+باستخدام تغيرات الطاقة، طبعا مع ده، نقطة الاتزان
+
+126
+00:09:11,620 --> 00:09:16,460
+بتكون الـ x = 0 بالنسبة لـ spring، نيجي للـ
+
+127
+00:09:16,460 --> 00:09:21,840
+quiz 5-5، Calculate احسب اللي هو الـ Elastic
+
+128
+00:09:21,840 --> 00:09:25,520
+Potential Energy of the Spring with Spring
+
+129
+00:09:25,520 --> 00:09:31,200
+Constant K = 225 نيوتن/متر، بدنا نحسب اللي
+
+130
+00:09:31,200 --> 00:09:37,340
+هي ال PE<sub>S</sub> لما تكون ... لما يكون ال spring مضغوط
+
+131
+00:09:37,340 --> 00:09:42,320
+compressed أو مشدود مسافة 1 × 10<sup>-2</sup> متر
+
+132
+00:09:42,320 --> 00:09:47,820
+طبعا في كل الأحوال إن PE<sub>S</sub> = نص K X تربيع، فبيطلع
+
+133
+00:09:47,820 --> 00:09:54,200
+الجواب 1.13 × 10<sup>2</sup> جول، و 1.13 × 10<sup>2</sup> في حالة ال
+
+134
+00:09:54,200 --> 00:09:58,920
+compressed أو في حالة ال compressed، وفي حالة ال
+
+135
+00:09:58,920 --> 00:10:04,020
+stretched، لإني اعتبرت إن ال PE<sub>S</sub> اللي هي ال spring
+
+136
+00:10:04,020 --> 00:10:07,980
+potential energy بتساوي أو تكافئ نص K X تربيع، وهي
+
+137
+00:10:07,980 --> 00:10:13,750
+دايما موجبة سواء كان stretched or compressed، section
+
+138
+00:10:13,750 --> 00:10:20,350
+quiz خمسة ستة، true or false، صح أو خطأ، the elastic
+
+139
+00:10:20,350 --> 00:10:23,430
+potential energy of the stretched or compressed
+
+140
+00:10:23,430 --> 00:10:28,330
+spring is always positive، هل صح ولا لأ، إن طاقة
+
+141
+00:10:28,330 --> 00:10:33,270
+الوضع المرنية الخاصة بال spring always positive، صح
+
+142
+00:10:33,270 --> 00:10:38,330
+أو خطأ، هي صحيحة، لأنها دائما موجبة، لأن ال X مربعة
+
+143
+00:10:38,330 --> 00:10:44,450
+وأي قيمة داخل التربيع ده يعتبر موجبة، الـ Quiz 5.7
+
+144
+00:10:44,450 --> 00:10:47,750
+Elastic potential energy depends on the spring
+
+145
+00:10:47,750 --> 00:10:52,290
+constant and the distance the spring is stretched
+
+146
+00:10:52,290 --> 00:10:56,010
+or compressed. By what factor does the elastic
+
+147
+00:10:56,010 --> 00:10:59,750
+potential energy change if the spring stretch is
+
+148
+00:10:59,750 --> 00:11:04,730
+doubled or tripled؟ الآن عندنا طاقة وضع مرنية
+
+149
+00:11:04,730 --> 00:11:09,730
+تعتمد على الـ spring constant K، وعلى المسافة، إذا
+
+150
+00:11:09,730 --> 00:11:14,030
+كانت مشدودة أو مضغوطة، الآن ماذا يحدث لهذه الطاقة
+
+151
+00:11:14,030 --> 00:11:19,690
+الخاصة بال spring عندما ... عندما اللي هو ال spring
+
+152
+00:11:19,690 --> 00:11:24,610
+stretched، يعني ال X تصير لها double، لما تتضاعف ال X
+
+153
+00:11:24,610 --> 00:11:28,470
+لما تتضاعف ال X، فاحنا بنعرف إن PE<sub>S</sub> = نص K X
+
+154
+00:11:28,470 --> 00:11:33,090
+تربيع، إذا ال X صارت ضعف، فبيصير عندي أنا النتيجة إنه
+
+155
+00:11:33,090 --> 00:11:36,890
+صارت أربعة أضعاف اللي هي طاقة الوضع، لأن ال X مربعة
+
+156
+00:11:36,890 --> 00:11:41,630
+يعني التربيع = 4، لما تكون صارت ثلاثة أمثالها
+
+157
+00:11:41,630 --> 00:11:45,250
+فبتصير طاقة الوضع الجديدة عبارة عن تسعة أمثال
+
+158
+00:11:45,250 --> 00:11:50,230
+الطاقة الأصلية اللي هي نص K X تربيع، يعني هنا عوضنا
+
+159
+00:11:50,230 --> 00:11:53,770
+عن ال X بـ 2 تربيع، هنا عوضنا عن ال X بـ 3
+
+160
+00:11:53,770 --> 00:12:01,590
+example خمسة تسعة، في عندي block with mass of 5
+
+161
+00:12:01,590 --> 00:12:05,530
+كيلو جرام، attached to a horizontal spring with
+
+162
+00:12:05,530 --> 00:12:08,310
+spring constant 4 × 10<sup>2</sup> نيوتن/متر
+
+163
+00:12:08,310 --> 00:12:14,000
+في عندي كتلة مشبوكة في spring أو في نابض
+
+164
+00:12:14,000 --> 00:12:18,980
+الكتلة كتلتها 5 كيلو جرام، والنابض اللي هو ثابت
+
+165
+00:12:18,980 --> 00:12:22,120
+القوة تبعته، أو ثابت المرونة بيسموها 4 × 10<sup>2</sup>
+
+166
+00:12:22,120 --> 00:12:26,920
+نيوتن/متر، the surface، the surface
+
+167
+00:12:26,920 --> 00:12:30,020
+or the block rests upon a frictionless، الكتلة
+
+168
+00:12:30,020 --> 00:12:34,390
+موجودة على سطح أملس، if the block is pulled، أنا
+
+169
+00:12:34,390 --> 00:12:38,250
+شدينا هذه القطعة أو هذا ال block أو هذه الكتلة
+
+170
+00:12:38,250 --> 00:12:43,330
+مسافة X<sub>initial</sub> = 0.05 متر، وبعد هيك طبعا
+
+171
+00:12:43,330 --> 00:12:47,610
+تركناها، find the speed of the block when it first
+
+172
+00:12:47,610 --> 00:12:52,130
+reached the equilibrium point، طبعا هي كانت في ال
+
+173
+00:12:52,130 --> 00:12:54,890
+equilibrium، بعدين شدناها مسافة 0.05 متر
+
+174
+00:12:54,890 --> 00:12:59,770
+تركناها، مطلوب منها نوجد سرعتها لما توصل للي هي
+
+175
+00:12:59,770 --> 00:13:05,230
+ال equilibrium position، هي الشكل هذا، K له K ثابت
+
+176
+00:13:05,230 --> 00:13:09,810
+اللي هو ال spring constant، وهنا كتلتها اللي هي 5
+
+177
+00:13:09,810 --> 00:13:14,410
+هذه الكتلة شدناها مسافة 0.05 وبعدين تركناها
+
+178
+00:13:14,410 --> 00:13:17,830
+مطلوب منا نوجد، و ال X<sub>initial</sub> هنا كم كانت
+
+179
+00:13:17,830 --> 00:13:23,330
+سرعتها، طبعا ال solution، find the speed
+
+223
+00:16:37,870 --> 00:16:42,230
+على السطح، فعندنا اللي هي الشغل الناتج عن الـ friction
+
+224
+00:16:42,230 --> 00:16:49,880
+هو عبارة عن delta K زائد Delta P.E، بقول Delta P هي
+
+225
+00:16:49,880 --> 00:16:53,760
+Zero، لإنه جالس على المستوى. بدي أعوض عن الـ X
+
+226
+00:16:53,760 --> 00:16:56,300
+initial في Zero، و X final Zero، لإنها وصلت للـ
+
+227
+00:16:56,300 --> 00:16:59,560
+equilibrium position. هذا في الحالة الأولي، بدي أوجد
+
+228
+00:16:59,560 --> 00:17:03,620
+سرعتها لما توصل عند نقطة الاتزان، وبوجود الـ
+
+229
+00:17:03,620 --> 00:17:07,820
+friction، فالـ friction عندنا ناقص Mu K في اللي هي
+
+230
+00:17:07,820 --> 00:17:12,020
+الـ normal في X. طبعاً هذا الشغل عبارة عن قوة في
+
+231
+00:17:12,020 --> 00:17:17,400
+مسافة. القوة عبارة عن FK، في المسافة. Fk=MuK في الـ
+
+232
+00:17:17,400 --> 00:17:20,840
+Normal في X. الـ Inertial الـ Normal بده يساوي اللي هو
+
+233
+00:17:20,840 --> 00:17:23,320
+Mg. أعوذ
+
+234
+00:17:25,060 --> 00:17:28,340
+ناقص mu k في n في x initial بتساوي نص mv final
+
+235
+00:17:28,340 --> 00:17:31,860
+تربيع ناقص نص k x initial تربيع. الـ normal زي ما
+
+236
+00:17:31,860 --> 00:17:36,300
+حكينا بتساوي الـ mg، بنعوض عنها، بنطلع نص mv final
+
+237
+00:17:36,300 --> 00:17:42,040
+تربيع عن ناحية، واللي هو نص k x initial تربيع ناقص
+
+238
+00:17:42,040 --> 00:17:46,040
+mu k في m في g في x initial. بنعوض طبعاً عن
+
+239
+00:17:46,040 --> 00:17:50,400
+المتغيرات الموجودة. الـ k كانت 4 في 10 أوس 2، والـ X
+
+240
+00:17:50,400 --> 00:17:55,580
+initial 5 من 100، والـ M بنعوض عنها اللي هي الكتلة
+
+241
+00:17:55,580 --> 00:17:59,220
+الـ 5 kilogram. ناقص اتنين ميو كيه، أعطانيها point
+
+242
+00:17:59,220 --> 00:18:03,720
+واحد خمسة، والـ G تسعة وثمانية من عشرة، والـ X
+
+243
+00:18:03,720 --> 00:18:07,180
+initial خمسة من مائة. من مئة. فبنطلع الـ V final
+
+244
+00:18:07,180 --> 00:18:13,120
+بوجود الاحتكاك، بتطلع V final point اتنين تلاتة
+
+245
+00:18:13,120 --> 00:18:17,160
+خمسة. point اتنين تلاتة صفر متر في الثانية. ناخد
+
+246
+00:18:17,160 --> 00:18:23,860
+مثلاً example: خمسين kilogram circus acrobat drops
+
+247
+00:18:23,860 --> 00:18:28,200
+from a height of two meters straight down into the
+
+248
+00:18:28,200 --> 00:18:31,100
+spring board with a force constant 8 في عشر و3
+
+249
+00:18:31,100 --> 00:18:35,020
+نيوتن على متر. اللي قاعد فيه عندي طبعاً لاعب
+
+250
+00:18:35,020 --> 00:18:39,980
+acrobat أو في السيرك. هذا اللاعب بده يسقط من ارتفاع
+
+251
+00:18:39,980 --> 00:18:45,290
+معين. طبعاً هو ما يسقط  فيه تحت جسم، الجسم موصول
+
+252
+00:18:45,290 --> 00:18:50,710
+بـ spring حتى لا يتعطل هذا اللاعب. الشكل الموضح
+
+253
+00:18:50,710 --> 00:18:55,290
+موجود عندنا. بدنا نجد. نستخدم اللي هي conservation
+
+254
+00:18:55,290 --> 00:18:59,570
+of mechanical energy. هي الشكل كما هو موضح بالشكل.
+
+255
+00:18:59,570 --> 00:19:04,670
+هي، يقفز اللاعب السيرك بده يقفز drop من مسافة معينة
+
+256
+00:19:04,670 --> 00:19:08,870
+H حتى يصل إلى الـ board. هذا اللي هو مرتبط بـ spring.
+
+257
+00:19:08,870 --> 00:19:14,350
+بدنا المسافة اللي الـ spring ممكن أنه ينضغطها. فالأولى
+
+258
+00:19:14,350 --> 00:19:16,550
+الـ non-zero term are the initial gravitational
+
+259
+00:19:16,550 --> 00:19:19,270
+potential energy and the final spring potential
+
+260
+00:19:19,270 --> 00:19:23,910
+energy. طبعاً في البداية كان إله طاقة واضحة. لما نزل
+
+261
+00:19:23,910 --> 00:19:29,430
+صار له طاقة وضع مرنة داخل الـ spring. في البداية كان
+
+262
+00:19:29,430 --> 00:19:33,710
+إله طاقة الوضع Mg. الارتفاع كان هو على ارتفاع اللي
+
+263
+00:19:33,710 --> 00:19:39,610
+هو H زائد D. تمام. بدها تساوي نص kd تربيع. هي المسافة
+
+264
+00:19:39,610 --> 00:19:43,410
+اللي الـ spring انضغطها. وبالتالي في البداية، طاقة
+
+265
+00:19:43,410 --> 00:19:46,390
+الحركة صفر، اللي بدأ من الـ rest، لإنه drop يعني
+
+266
+00:19:46,390 --> 00:19:50,690
+إنها في initial صفر. وهنا طاقة الوضع، وهنا
+
+267
+00:19:50,690 --> 00:19:55,210
+طاقة الوضع المرنة صفر. الـ final طاقة الحركة صفر.
+
+268
+00:19:55,210 --> 00:19:59,760
+طاقة الوضع صفر، لإن هي آخر حاجة اللي هي level. وطاقة
+
+269
+00:19:59,760 --> 00:20:02,980
+الوضع المرنة موجودة. نص KD تربيع. D هي المسافة اللي
+
+270
+00:20:02,980 --> 00:20:09,000
+الـ spring انضغطها. إذن Mg H زائد D بتساوي نص KD تربيع.
+
+271
+00:20:09,000 --> 00:20:15,920
+من خلال هذه المعادلة، ممكن نجد D.  عشان أنه بنعوض عن
+
+272
+00:20:15,920 --> 00:20:19,160
+الـ M بخمسين، والـ G تسعة وثمانية من عشرة، والـ H
+
+273
+00:20:19,160 --> 00:20:22,600
+اللي كانت اتنين، و D مجهولة. هنا بنعوض عن الـ K
+
+274
+00:20:22,600 --> 00:20:26,040
+ثمانية في عشرة قوّة ثلاثة نيوتن/متر في D تربيع.
+
+275
+00:20:26,960 --> 00:20:31,140
+قيمة اللي هو المسافة اللي انضغطها الـ spring بتساوي
+
+276
+00:20:31,140 --> 00:20:38,520
+point خمسة ستة متر. example: خمسة أحد عشر. في عندنا
+
+277
+00:20:38,520 --> 00:20:43,900
+كتلة نص كيلو جرام block، rest on a horizontal
+
+278
+00:20:43,900 --> 00:20:47,540
+frictionless surface. the block is pressed back
+
+279
+00:20:47,540 --> 00:20:51,220
+against a spring having a constant of K، بتساوي ستمية
+
+280
+00:20:51,220 --> 00:20:54,320
+وخمسة عشر نيوتن/نانومتر. compressing the spring by الـ
+
+281
+00:20:54,320 --> 00:21:00,760
+spring هذا انضغط مسافة 10 سم. عند النقطة A. بعد هيك
+
+282
+00:21:00,760 --> 00:21:05,480
+انتركنا، يعني أُطلقنا الـ spring. مرتبطة في كتلة
+
+283
+00:21:05,480 --> 00:21:11,920
+انضغط مسافة 10 سم. بعد هيك تركناها released. find the
+
+284
+00:21:11,920 --> 00:21:14,220
+maximum distance D the block travels up the
+
+285
+00:21:14,220 --> 00:21:17,260
+frictionless inclined if θ بتساوي 30. الآن هي
+
+286
+00:21:17,260 --> 00:21:24,410
+السؤال: هذا جسم، الجسم كان مضغوط مسافة X. طبعاً هذا الـ
+
+287
+00:21:24,410 --> 00:21:28,570
+equilibrium position. مضغوط مسافة X اللي هي عشرة
+
+288
+00:21:28,570 --> 00:21:35,330
+سم. بعد ذلك تركناها released، فلتت، وارتفعت، ووصلت لمنطقة
+
+289
+00:21:35,330 --> 00:21:39,630
+B. طالب مني المسافة اللي مشتها على المستوى المائل.
+
+290
+00:21:39,630 --> 00:21:43,950
+طبعاً لما وصلت لهنا المنطقة، هنا H على 2، وهنا نعتبرها
+
+291
+00:21:43,950 --> 00:21:47,770
+عند C. H المسافة هي كلها D، من المنطقة اللي هي
+
+292
+00:21:47,770 --> 00:21:49,070
+المستوى المائل.
+
+293
+00:21:52,690 --> 00:21:57,530
+Solution: final distance. المطلوب نوجد المسافة التي
+
+294
+00:21:57,530 --> 00:22:01,930
+تصلها هذه الكتلة على المستوى المائل أو المنحدر.
+
+295
+00:22:01,930 --> 00:22:04,990
+applying conservation of mechanical energy برضه.
+
+296
+00:22:04,990 --> 00:22:09,350
+باستخدام قانون اللي هي الطاقة الميكانيكية المحفوظة.
+
+297
+00:22:09,350 --> 00:22:13,170
+اللي هي طاقة الحركة، طاقة الوضع، وطاقة الـ spring. الـ
+
+298
+00:22:13,170 --> 00:22:16,730
+initial بتساوي طاقة الحركة + طاقة الوضع + طاقة
+
+299
+00:22:16,730 --> 00:22:20,820
+الـ spring الـ final. Vin بتساوي Vf بتساوي 0، لإن هو
+
+300
+00:22:20,820 --> 00:22:25,140
+كانت مضغوطة على الآخر. فـ Vin للكتلة بتساوي 0، ولما
+
+301
+00:22:25,140 --> 00:22:31,120
+وصلت لأقصى مسافة، اللي هي Vf بتساوي 0. Uin بتساوي 0،
+
+302
+00:22:31,120 --> 00:22:34,620
+اللي هي الـ level. و Uf بتساوي MgH. يعني معنى الكلام أنا
+
+303
+00:22:34,620 --> 00:22:40,060
+بده يوصل لمنطقة C. في البداية، فالـ H بتساوي D sin θ.
+
+304
+00:22:40,060 --> 00:22:45,440
+و Xf بتساوي 0. بنعوض: نص KX تربيع. كانت مضغوطة على
+
+305
+00:22:45,440 --> 00:22:49,500
+الآخر. طاقة الحركة صفر. طاقة الوضع صفر. بعد ما فلتت
+
+306
+00:22:49,500 --> 00:22:56,140
+صار لها MgH. طبعاً وطاقة الحركة صفر. MgH بتساوي Mg
+
+307
+00:22:56,140 --> 00:23:01,460
+الـ H كان بيساوي D sin θ. فيه. بنحل هذه المعادلة، بنعوض
+
+308
+00:23:01,460 --> 00:23:08,070
+عن الـ K 625، والـ X initial كانت .1، لأنها كانت
+
+309
+00:23:08,070 --> 00:23:13,450
+مضغوطة على الآخر. وبعدين الـ M هي عبارة عن نص كيلو،
+
+310
+00:23:13,450 --> 00:23:16,870
+تسعة وثمانية من عشرة، والـ H اللي هي عبارة عن D
+
+311
+00:23:16,870 --> 00:23:23,430
+sin الزاوية، وبنعوض عنها طبعاً. هنا الـ D بنوجدها.
+
+312
+00:23:23,430 --> 00:23:28,390
+بنوجد D، بتكون: نص KX تربيع / Mg sin θ. طبعاً بنطلع المسافة التي وصلت
+
+313
+00:23:28,390 --> 00:23:32,030
+لها هذه الكتلة على المستوى المائل عندما تصل لمنطقة
+
+314
+00:23:32,030 --> 00:23:35,910
+C. الآن برضه موجود أو مطلوب، نوجد اللي هو السرعة
+
+315
+00:23:35,910 --> 00:23:40,290
+عندما تصل لمنطقة B على ارتفاع H / 2. طبعاً H في هذه
+
+316
+00:23:40,290 --> 00:23:46,970
+الحالة هتساوي D sin θ. و دي اللي كانت بتساوي 1.28 في
+
+317
+00:23:46,970 --> 00:23:55,490
+sin الزاوية، بتطلع H .64. طبعاً الـ H اللي وصلت لها. بدا
+
+318
+00:23:55,490 --> 00:24:02,330
+نستخدم برضه قانون الـ conservation of energy اللي
+
+319
+00:24:02,330 --> 00:24:07,350
+هي أيضاً: نص Mv initial تربيع + Mgy initial +
+
+320
+00:24:07,350 --> 00:24:12,690
+نص Kx initial تربيع بتساوي نص Mv final تربيع +
+
+321
+00:24:12,690 --> 00:24:17,420
+Mgy final + نص Kx final تربيع. الـ V initial 0، و
+
+322
+00:24:17,420 --> 00:24:21,880
+الـ y initial 0، والـ y final وصلت إلى نص H، و X
+
+323
+00:24:21,880 --> 00:24:26,320
+final بتساوي 0. طبعاً نص KX initial تربيع كانت
+
+324
+00:24:26,320 --> 00:24:32,180
+مضغوطة في البداية، فإلها طاقة وضع مرنة. طاقة وضع
+
+325
+00:24:32,180 --> 00:24:35,660
+صفر، وحركة صفر. لما طبعاً تركت الـ spring و تركت
+
+326
+00:24:35,660 --> 00:24:41,500
+الكتلة، وصلت إلى مسافة المنطقة B على المستوى المائل.
+
+327
+00:24:41,500 --> 00:24:47,020
+صار إلها نص MV تربيع، و Mg H على اتنين. من خلال هذه
+
+328
+00:24:47,020 --> 00:24:52,840
+المعادلات، ممكن أنه نوجد V final. في الطريقة هذه اللي
+
+329
+00:24:58,230 --> 00:25:04,170
+هي: √(K/M X initial تربيع - gH)، وبنطلع الـ V
+
+330
+00:25:04,170 --> 00:25:10,470
+final من خلال المعطيات. طبعاً كالسابق، القسم الآخر
+
+331
+00:25:10,470 --> 00:25:14,550
+section هو system and energy conservation. طبعاً
+
+332
+00:25:14,550 --> 00:25:18,930
+احنا حكينا عنه هذا الكلام، شرحنا إنه W net بتساوي
+
+333
+00:25:18,930 --> 00:25:24,120
+Delta K. نظرية الشغل والطاقة. Wc + Wnc بتساوي Delta K.
+
+334
+00:25:24,120 --> 00:25:28,580
+Delta K بتساوي Delta KE، هي التغير في طاقة الحركة. W
+
+335
+00:25:28,580 --> 00:25:32,200
+nc هي عبارة عن الشغل الناتج عنه اللي هي القوة
+
+336
+00:25:32,200 --> 00:25:35,700
+الغير محفوظة، non conservative force. Wc هي عبارة عن
+
+337
+00:25:35,700 --> 00:25:39,380
+الشغل الناتج عن القوة المحفوظة، اللي هي زي الـ
+
+338
+00:25:39,380 --> 00:25:44,340
+gravity والـ spring. as we have seen, any work done
+
+339
+00:25:44,340 --> 00:25:49,320
+by the conservative force، أي شغل يكون طبعاً.. طبعاً
+
+340
+00:25:49,320 --> 00:25:52,610
+هذا الشغل المبدول وسط القوة المحفوظة، زي الـ
+
+341
+00:25:52,610 --> 00:25:54,910
+gravity والـ spring، can be accounted for its
+
+342
+00:25:54,910 --> 00:26:00,090
+change. ممكن احنا نحسبه وسط التغير في طاقة الوضع.
+
+343
+00:26:00,090 --> 00:26:05,590
+باستخدام طبعاً اللي هي نظرية الشغل والطاقة زي ما
+
+344
+00:26:05,590 --> 00:26:08,770
+حكينا إن Wnc بتساوي التغير في طاقة الحركة +
+
+345
+00:26:08,770 --> 00:26:13,390
+التغير في طاقة الوضع. now, previous state potential
+
+346
+00:26:13,390 --> 00:26:17,060
+energy include، ممكن potential energy بتكون تتضمن
+
+347
+00:26:17,060 --> 00:26:19,820
+اللي هي الـ potential energy لـ spring + الـ
+
+348
+00:26:19,820 --> 00:26:23,780
+gravity. this equation is easy. ممكن استخدم هذه
+
+349
+00:26:23,780 --> 00:26:28,100
+المعادلة. إنه عبارة عن، يعني هنا طاقة الميكانيكية الـ
+
+350
+00:26:28,100 --> 00:26:31,460
+final نخصّ الطاقة الميكانيكية initial. وطبعاً هذا
+
+351
+00:26:31,460 --> 00:26:35,300
+احنا حكينا سابقاً، بس للتأكيد، إذا الـ mechanical
+
+352
+00:26:35,300 --> 00:26:38,900
+energy اللي هي رمزها E، بتساوي طاقة الحركة + طاقة
+
+353
+00:26:38,900 --> 00:26:42,190
+الوضع. الـ Kinetic Energy + الـ Potential Energy.
+
+354
+00:26:42,190 --> 00:26:47,750
+ممكن برضه نستخدمها، يعني قانون شكل مختلف، إن Wnc
+
+355
+00:26:47,750 --> 00:26:52,210
+بيساوي Delta E. E final ناقص E initial. في حالة وجود
+
+356
+00:26:52,210 --> 00:26:57,210
+الاحتكاك. في عدم وجود احتكاك، فبيطلع إن E final ناقص
+
+357
+00:26:57,210 --> 00:27:02,230
+E initial بتساوي Zero. إن if the mechanical energy
+
+358
+00:27:02,230 --> 00:27:05,370
+is changing، إذا تغيرت، it has to be going
+
+359
+00:27:05,370 --> 00:27:09,150
+somewhere، the energy either leaves the system and
+
+360
+00:27:09,150 --> 00:27:12,130
+goes into the surrounding environment. طبعاً الطاقة
+
+361
+00:27:12,130 --> 00:27:15,930
+المفقودة أو الطاقة المتشتتة، ممكن أنها يعني.. يعني
+
+362
+00:27:15,930 --> 00:27:19,730
+تنطلق أو تظهر على شكل حرارة زي ما حكينا، أو.. أو
+
+363
+00:27:19,730 --> 00:27:25,840
+thermal energy، أو.. أو ممكن تكون شكل سؤال. بالنسبة
+
+364
+00:27:25,840 --> 00:27:30,580
+لـ conservation of energy in general، بصفة عامة، the
+
+365
+00:27:30,580 --> 00:27:33,720
+most important feature of energy approach is the
+
+366
+00:27:33,720 --> 00:27:37,100
+idea that energy is conserved. it can't be created
+
+367
+00:27:37,100 --> 00:27:42,080
+or destroyed. بالنسبة للطاقة اللي هي المحفوظة، لأ
+
+368
+00:27:42,080 --> 00:27:50,150
+يعني لأ لا تتبدد، ولا تفنى، ولا يعني.. يعني تستحدث. only
+
+369
+00:27:50,150 --> 00:27:54,050
+transferable. ولكن تنتقل من شكل إلى آخر. ولكن تنتقل
+
+370
+00:27:54,050 --> 00:27:58,490
+من شكل إلى آخر. quiz: خمسة ثمانية. في عندي a book of
+
+371
+00:27:58,490 --> 00:28:01,570
+mass m is projected with speed v across a
+
+372
+00:28:01,570 --> 00:28:05,170
+horizontal surface. the book slides until it stops
+
+373
+00:28:05,170 --> 00:28:07,970
+due to the friction force between the book and the
+
+374
+00:28:07,970 --> 00:28:14,430
+surface. العرض الآن: تلت تلت تلتين. طبعاً تلتين درجة.
+
+375
+00:28:14,430 --> 00:28:19,010
+والقرص مجرد تلت تلت تلت تلت تلت تلت تلت تلت تلت
+
+376
+00:28:19,010 --> 00:28:21,290
+تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت
+
+377
+00:28:21,290 --> 00:28:24,890
+تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت
+
+378
+00:28:24,890 --> 00:28:29,910
+تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت تلت
+
+379
+00:28:29,910 --> 00:28:38,130
+تلت تلت تلت تلت تلت
+
+380
+00:28:38,130 --> 00:28:43,800
+تلت and it's larger on the tilt surface. it's
+
+381
+00:28:43,800 --> 00:28:46,680
+smaller on the tilt surface. ولا more information
+
+382
+00:28:46,680 --> 00:28:50,600
+is needed؟ الآن من خلال هذا السؤال، اتضح إلينا إنه
+
+383
+00:28:50,600 --> 00:28:58,860
+Wnc بتساوي Delta E. ممكن نحكي E final ناقص E
+
+384
+00:28:58,860 --> 00:29:04,500
+initial. وطبعاً الـ E final هتكون أقل من E initial.
+
+385
+00:29:04,500 --> 00:29:07,640
+بطلع السؤال وبالتالي الجواب: it's smaller on the
+
+386
+00:29:07,640 --> 00:29:12,700
+tilt surface. أو.. أو.. أو ممكن نحكي إنه Delta KE +
+
+387
+00:29:12,700 --> 00:29:16,560
+Delta PE. ممكن احنا نحلها، أو بنحكي إنه E final ناقص
+
+388
+00:29:16,560 --> 00:29:19,960
+E initial، بكون في عندي فقد في الطاقة لو الكتاب هذا
+
+389
+00:29:19,960 --> 00:29:25,430
+مثلاً تحرك على مستوى خشن، فهو بيفقد طاقة بواسطة اللي
+
+390
+00:29:25,430 --> 00:29:31,250
+هو الاحتكاك زي ما هو طبعاً موضح في هذا المثال. طبعاً
+
+391
+00:29:31,25
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/amzXVM5Nljk_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/amzXVM5Nljk_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..6457bc3731c6e7a565f30b0d19b13a94b705b8fd
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/amzXVM5Nljk_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 2108, "start": 0.74, "end": 21.08, "text": "بسم الله الرحمن الرحيم طبعا بنستمر في شرح chapter 5 و مع section spring potential energy او اللي هي ال elastic potential energy تاخد الوضع المرنية داخل ال spring الان بدنا نحسب الشغل المبدول بواسطة ال spring او المعبد", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 23032, 3555, 3615, 995, 44945, 14851, 29973, 8978, 13412, 2288, 5016, 7187, 1025, 4032, 20449, 3541, 5587, 3995, 2281, 1975, 2407, 13672, 1829, 39896, 2423, 17115, 3995, 2281, 6055, 47283, 3215, 2423, 2407, 11242, 3615, 9673, 2288, 1863, 10632, 11778, 47283, 1211, 2423, 5587, 2423, 7649, 47525, 8315, 8717, 5016, 35457, 25124, 17082, 1211, 9673, 44510, 12610, 4724, 14407, 3794, 9566, 3660, 2423, 5587, 1975, 2407, 9673, 3615, 44510], "avg_logprob": -0.15081092413467698, "compression_ratio": 1.6381909547738693, "no_speech_prob": 3.7670135498046875e-05, "words": [{"start": 0.74, "end": 1.04, "word": "بسم", "probability": 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مرتبطة بالـ Spring Force Constant أو Spring Force فالـ Potential Energy for Spring بسوء نص K X تربين", "tokens": [5208, 38, 39896, 6225, 3555, 9640, 3660, 18871, 2423, 39184, 8985, 10398, 1478, 9145, 2549, 14939, 4032, 6027, 39184, 18183, 430, 2358, 39896, 6225, 3555, 9640, 3660, 18871, 14013, 9145, 2549, 14939, 2423, 39184, 2699, 2750, 9145, 2549, 14939, 3714, 43500, 3555, 9566, 3660, 20666, 39184, 14013, 10580, 37413, 34051, 14013, 10580, 6156, 6027, 39184, 9145, 2549, 14939, 337, 14013, 4724, 3794, 2407, 38207, 8717, 9381, 591, 1783, 6055, 25513, 9957], "avg_logprob": -0.3118489657839139, "compression_ratio": 1.6627906976744187, "no_speech_prob": 6.616115570068359e-06, "words": [{"start": 255.18000000000004, "end": 256.1, "word": "PEG", "probability": 0.80712890625}, {"start": 256.1, "end": 256.3, "word": " هي", "probability": 0.693359375}, {"start": 256.3, "end": 256.62, "word": " عبارة", "probability": 0.9869384765625}, {"start": 256.62, "end": 256.84, "word": " عن", 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"word": " بالspring", "probability": 0.54736328125}, {"start": 318.38, "end": 318.7, "word": " لقى", "probability": 0.5960286458333334}, {"start": 318.7, "end": 319.08, "word": " القانون", "probability": 0.9952799479166666}, {"start": 319.08, "end": 319.8, "word": " الأساسي", "probability": 0.96337890625}, {"start": 319.8, "end": 320.24, "word": " اللي", "probability": 0.9052734375}, {"start": 320.24, "end": 320.64, "word": " أخدناها", "probability": 0.8890625}, {"start": 320.64, "end": 321.08, "word": " سابقا", "probability": 0.980712890625}, {"start": 321.08, "end": 321.48, "word": " بتطلع", "probability": 0.7783203125}, {"start": 321.48, "end": 321.68, "word": " أن", "probability": 0.328369140625}, {"start": 321.68, "end": 323.12, "word": " WNC", "probability": 0.5714518229166666}, {"start": 323.12, "end": 323.64, "word": " بساوي", "probability": 0.63720703125}, {"start": 323.64, "end": 323.98, "word": " delta", "probability": 0.4228515625}, {"start": 323.98, "end": 324.44, "word": " K", "probability": 0.62353515625}, {"start": 324.44, "end": 325.3, "word": " زائد", "probability": 0.5465494791666666}, {"start": 325.3, "end": 325.64, "word": " delta", "probability": 0.76953125}, {"start": 325.64, "end": 326.5, "word": " BG", "probability": 0.701904296875}, {"start": 326.5, "end": 327.44, "word": " زائد", "probability": 0.9217122395833334}, {"start": 327.44, "end": 328.06, "word": " delta", "probability": 0.8310546875}, {"start": 328.06, "end": 329.3, "word": " BES", "probability": 0.844482421875}], "temperature": 1.0}, {"id": 14, "seek": 35234, "start": 329.6, "end": 352.34, "text": "بنسميها الـSpring، هذه الـGravitational Potential Energy وهذه اللي هي الـQuantum Energy WNC is the work done by the non-conservative force الشغل اللي هو WNC هو عبارة عن الشغل المبدول بواسطة القوة الغير محفوظة زي خوط الاحتكاك KE عبارة عن طاقة الحركة BEG عبارة عن طاقة الوضع الخاصة بالجاذبية", "tokens": [3555, 1863, 38251, 1829, 11296, 2423, 39184, 50, 1424, 278, 12399, 29538, 2423, 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طاقة حركة لهذا ال block أو هذه الكتلة The elastic potential energy stored in the spring is zero ال potential energy طاقة الوضع لل spring بتكون zero لما تكون في equilibrium position يعني x بتساوي", "tokens": [5172, 2655, 2655, 5016, 12610, 23032, 995, 28671, 2423, 2407, 11242, 3615, 30731, 23032, 995, 28671, 11331, 31747, 3660, 46740, 15730, 2423, 3461, 34051, 29538, 33251, 2655, 37977, 440, 17115, 3995, 2281, 12187, 294, 264, 5587, 307, 4018, 2423, 3995, 2281, 23032, 995, 28671, 2423, 2407, 11242, 3615, 24976, 5587, 39894, 30544, 4018, 5296, 15042, 6055, 30544, 8978, 15625, 2535, 37495, 22653, 2031, 39894, 3794, 995, 45865], "avg_logprob": -0.25183824537431493, "compression_ratio": 1.5179487179487179, "no_speech_prob": 2.562999725341797e-06, "words": [{"start": 434.58, "end": 435.38, "word": "فتتحول", "probability": 0.832470703125}, {"start": 435.38, "end": 435.62, "word": " طاقة", "probability": 0.6146647135416666}, {"start": 435.62, "end": 435.96, "word": " الوضع", "probability": 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451.73, "end": 478.07, "text": "تحت الوضع المخزونة داخل ال spring when it's stretched اذا كانت stretch يعني مشدودة او مضغوطة بتساوة نص ك X تربيع اذا further .. further the elastic potential energy is maximum اللي هي ال potential energy بتكون maximum لما ال spring has reached its maximum compression or extension", "tokens": [2655, 33753, 2423, 2407, 11242, 3615, 9673, 9778, 11622, 11536, 3660, 11778, 47283, 1211, 2423, 5587, 562, 309, 311, 23563, 1975, 15730, 25961, 2655, 5985, 37495, 22653, 37893, 3215, 23328, 3660, 1975, 2407, 3714, 11242, 17082, 2407, 9566, 3660, 39894, 3794, 995, 2407, 3660, 8717, 9381, 9122, 1783, 6055, 25513, 40228, 1975, 15730, 3052, 4386, 3052, 264, 17115, 3995, 2281, 307, 6674, 13672, 1829, 39896, 2423, 3995, 2281, 39894, 30544, 6674, 5296, 15042, 2423, 5587, 575, 6488, 1080, 6674, 19355, 420, 10320], "avg_logprob": -0.212161140987672, "compression_ratio": 1.5404255319148936, "no_speech_prob": 5.364418029785156e-07, "words": [{"start": 451.73, "end": 452.41, 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يعني قانون شكل مختلف أن WNC بيساوي Delta E E Final نقص E Initial في حالة وجود الاحتكاك في عدم وجود احتكاك فبيطلع أن E Final نقص E Initial بتساوي Zero", "tokens": [6027, 39184, 27950, 3532, 14939, 30767, 16373, 3215, 2423, 39184, 9145, 2549, 14939, 3714, 43020, 4724, 43042, 3224, 8717, 14851, 9778, 40448, 11296, 37495, 22653, 12174, 7649, 11536, 13412, 28820, 3714, 46456, 46538, 14739, 343, 45, 34, 4724, 1829, 3794, 995, 45865, 18183, 462, 462, 13443, 8717, 4587, 9381, 462, 22937, 831, 8978, 11331, 6027, 3660, 49610, 23328, 42963, 33753, 4117, 995, 4117, 8978, 6225, 40448, 49610, 23328, 1975, 33753, 4117, 995, 4117, 6156, 21292, 9566, 1211, 3615, 14739, 462, 13443, 8717, 4587, 9381, 462, 22937, 831, 39894, 3794, 995, 45865, 17182], "avg_logprob": -0.22429436124781127, "compression_ratio": 1.553921568627451, "no_speech_prob": 0.0003209114074707031, "words": [{"start": 1599.65, "end": 1599.95, "word": "الـ", "probability": 0.5511474609375}, {"start": 1599.95, "end": 1600.25, "word": " 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"end": 1786.99, "word": " is", "probability": 0.94580078125}, {"start": 1786.99, "end": 1787.55, "word": " canceled", "probability": 0.75732421875}, {"start": 1787.55, "end": 1789.03, "word": " طبعا", "probability": 0.9923095703125}, {"start": 1789.03, "end": 1790.51, "word": " نلتقيكم", "probability": 0.878515625}, {"start": 1790.51, "end": 1790.87, "word": " في", "probability": 0.98291015625}, {"start": 1790.87, "end": 1791.47, "word": " تسجيل", "probability": 0.986572265625}, {"start": 1791.47, "end": 1792.05, "word": " قادم", "probability": 0.9847005208333334}, {"start": 1792.05, "end": 1792.21, "word": " في", "probability": 0.98095703125}, {"start": 1792.21, "end": 1792.43, "word": " chapter", "probability": 0.94580078125}, {"start": 1792.43, "end": 1792.77, "word": " ستة", "probability": 0.9554036458333334}, {"start": 1792.77, "end": 1792.91, "word": " ان", "probability": 0.8896484375}, {"start": 1792.91, "end": 1793.01, "word": " شاء", "probability": 0.985107421875}, {"start": 1793.01, "end": 1793.19, "word": " الله", "probability": 0.939453125}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1793.486125, "duration_after_vad": 1770.111874999996}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..5dad93ab8f4f6e550752aebf57ac18ddfc12dfcf
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_postprocess.srt
@@ -0,0 +1,1536 @@
+1
+00:00:00,440 --> 00:00:04,700
+بسم الله الرحمن الرحيم بنستكمل section أربعة خمسة
+
+2
+00:00:04,700 --> 00:00:09,840
+بعنوان attention forces attention force can be
+
+3
+00:00:09,840 --> 00:00:15,580
+exerted by attaching string or cable to an object
+
+4
+00:00:15,580 --> 00:00:22,060
+and pulling itطبعا قوة الشد كان يعني بتحدث عندما
+
+5
+00:00:22,060 --> 00:00:28,880
+طبعا بنشد أو بنسحب جسم بواسطة كابل أو حبل the
+
+6
+00:00:28,880 --> 00:00:31,700
+tension force acts along the direction of the
+
+7
+00:00:31,700 --> 00:00:36,240
+cable and exert a force both on the object and on
+
+8
+00:00:36,240 --> 00:00:41,520
+the person exerted force on the cableقوة الشد تؤثر
+
+9
+00:00:41,520 --> 00:00:48,220
+طوليا على اتجاه هذا الخيط وتؤثر هذه القوة طبعا هذه
+
+10
+00:00:48,220 --> 00:00:56,320
+القوتين على الجسم وعلى أي شخص يتعرض لقوة شد الحبل
+
+11
+00:00:56,320 --> 00:01:03,680
+كما هو موضح بهذا الشكل شكل 423لو كانت ال mass of
+
+12
+00:01:03,680 --> 00:01:08,160
+the given cable is نجلة طبعا باهمال كتلة الحبل
+
+13
+00:01:08,160 --> 00:01:13,860
+طبعا عندنا سيارة السيارة مربوطة بحبل وهذا الرجل
+
+14
+00:01:13,860 --> 00:01:19,080
+يشد هذه السيارة بحبل أو يعني قوة الشد اللي هي T لل
+
+15
+00:01:19,080 --> 00:01:27,260
+car بزاوية θالـ TC has the same magnitude and
+
+16
+00:01:27,260 --> 00:01:33,700
+tension force on the man الراجل بيشد السيارة بقوة
+
+17
+00:01:33,700 --> 00:01:41,570
+شد TC والسيارة بدورها بتشد الراجل بقوة TMفقوة شد
+
+18
+00:01:41,570 --> 00:01:46,050
+السيارة من الرجل بتساوي قوة شد السيارة للرجل يعني
+
+19
+00:01:46,050 --> 00:01:50,530
+T لل car بتساوي T ل ال man هد اسمه قوة الشد هدول
+
+20
+00:01:50,530 --> 00:01:56,050
+قوتين متساوتين في المقدار ومتعاكستين بالاتجاهلكن
+
+21
+00:01:56,050 --> 00:02:02,270
+هذا الشد له حالات الحالة حسب الوضع الشد لما يكون
+
+22
+00:02:02,270 --> 00:02:07,790
+عندي vertical tension forces on static object لو
+
+23
+00:02:07,790 --> 00:02:12,860
+كان عندي أنا جسم و بدأ أشد حركة رأسيةفي هذه الحالة
+
+24
+00:02:12,860 --> 00:02:16,840
+an object is dangling at the end of the vertical
+
+25
+00:02:16,840 --> 00:02:25,060
+string هذا الجسم مربوط بحبل رأسيا بحبل رأسيا وهذا
+
+26
+00:02:25,060 --> 00:02:30,100
+الخط اللي الجسم مربوط في أسفل الحبل the object is
+
+27
+00:02:30,100 --> 00:02:35,240
+in equilibrium الجسم بيكون في حالة اتزان معناها
+
+28
+00:02:35,240 --> 00:02:39,040
+التسارع بساوة zero ال y component of the second
+
+29
+00:02:39,040 --> 00:02:43,350
+law gives an expressionfor the tension لو كان عندي
+
+30
+00:02:43,350 --> 00:02:47,790
+أنا جسم و الجسم مربوط بخيط طبعا قوة الشد هتكون
+
+31
+00:02:47,790 --> 00:02:52,670
+لأعلى و ال MG هتكون لأسفل في عندي حالة توا اتزان
+
+32
+00:02:52,670 --> 00:02:56,950
+معنى الكلام summation لل FY بالساوية M في Ay ال T
+
+33
+00:02:56,950 --> 00:03:00,710
+ناقص MG بالساوية Zero إذا في هذه الحالة ال T
+
+34
+00:03:00,710 --> 00:03:04,870
+بالساوية MG حطينا Zero لإن ال A بتجاه ال Y Zero في
+
+35
+00:03:04,870 --> 00:03:09,180
+حالة اتزان equilibriumSo the acceleration is zero
+
+36
+00:03:09,180 --> 00:03:14,420
+اذا انت بالساوي ال Mg The tension force therefore
+
+37
+00:03:14,420 --> 00:03:17,500
+is equal to the support weight هذا الشكل اللي
+
+38
+00:03:17,500 --> 00:03:22,510
+حكينا عنه هي اندي كتلة اسمها M مربوطةفي نهاية خيط
+
+39
+00:03:22,510 --> 00:03:28,010
+مشدود رأسيا إلى أعلى فطبعا قوة الشد هطلعها من
+
+40
+00:03:28,010 --> 00:03:32,130
+الجسم لازم السهم او ال vector لأ الشد يكون خارج من
+
+41
+00:03:32,130 --> 00:03:36,830
+الجسم اللي هو ال M و ال MG طبعا خارجها اللي هي ال
+
+42
+00:03:36,830 --> 00:03:43,310
+M قوة الجاذبية الجسم في حالة اتزان اذا ال T ناقص
+
+43
+00:03:43,310 --> 00:03:46,850
+ال MG بالساوية صفر اذا ال T بالساوية MG T هذا هو
+
+44
+00:03:46,850 --> 00:03:52,790
+رمز اللي هو ال tension او الشدهذه حالة من الحالات
+
+45
+00:03:52,790 --> 00:03:55,310
+الـ tension in the string supports the block
+
+46
+00:03:55,310 --> 00:03:58,810
+weight هذه حالة من الحالات لما يكون في هذا الشكل
+
+47
+00:03:58,810 --> 00:04:03,270
+الحالة التانية case 2 vertical tension forces on
+
+48
+00:04:03,270 --> 00:04:08,970
+an accelerating object لو كان عندي أنا جسم بيتحرك
+
+49
+00:04:08,970 --> 00:04:13,970
+زي المصعد بهذا الشكل اللي انا عندي أنا جسم مربوط
+
+50
+00:04:13,970 --> 00:04:21,970
+بخيطو هذا الجسم كله بيتحرك إلى أعلى ففي عندي أنا
+
+51
+00:04:21,970 --> 00:04:26,450
+قوة الوزن MG لأسفل و الجسم كله بتحرك إلى أعلى فهنا
+
+52
+00:04:26,450 --> 00:04:29,770
+هذا السهم بيدل على أن الحركة إلى أعلى اللي هي M في
+
+53
+00:04:29,770 --> 00:04:34,390
+A هستخدم قانون نيوتن التاني لكن هذا القانون باتجاه
+
+54
+00:04:34,390 --> 00:04:39,270
+ال Y راح نحكي summation للأف Y بتساوي M في A Y
+
+55
+00:04:39,270 --> 00:04:44,390
+بنرجع ل .. اللي هو حكيه في ال .. في ال section إذا
+
+56
+00:04:44,630 --> 00:04:47,890
+in this case a string is attached to an object and
+
+57
+00:04:47,890 --> 00:04:50,910
+put under such tension that it accelerates the
+
+58
+00:04:50,910 --> 00:04:55,750
+object upward إذا في حركة إلى أعلى the tension
+
+59
+00:04:55,750 --> 00:04:59,750
+force must support the weight and provide
+
+60
+00:04:59,750 --> 00:05:03,610
+acceleration the correct expression can be derived
+
+61
+00:05:03,610 --> 00:05:07,530
+from the y component of the second law استخدمت
+
+62
+00:05:07,530 --> 00:05:12,080
+قانون نيوتن التانيوالمُركّبة الصادرية إذا
+
+63
+00:05:12,080 --> 00:05:16,120
+summation للأف واي بتساوي ال M في Ay summation
+
+64
+00:05:16,120 --> 00:05:20,220
+للأف واي كان T باتجاه الموجب إذا T موجب ناقص MG
+
+65
+00:05:20,220 --> 00:05:26,420
+سالب بدي أعيد ترتيبها هنحكي أن T بتساوي MAY زائد
+
+66
+00:05:26,420 --> 00:05:31,240
+MGالـ M مشتركة فـ T بيساوي Ay زائد الـ G هذه هي
+
+67
+00:05:31,240 --> 00:05:34,400
+برعجي هي تسارع الجاذبية والـ A هي التسارع اللي
+
+68
+00:05:34,400 --> 00:05:39,500
+بتحرك فيها الجسم المربوط بخيط حركة رأسيا إلى أعلى
+
+69
+00:05:41,480 --> 00:05:45,400
+accelerating upward increases the tension whereas
+
+70
+00:05:45,400 --> 00:05:50,520
+accelerating downward decreases the tension طبعا
+
+71
+00:05:50,520 --> 00:05:55,460
+هي يعني ملاحظة أنه تسارع لما يكون في عندي تسارع
+
+72
+00:05:55,460 --> 00:05:59,560
+الجسم إلى أعلى بيعمل على زيادة ال tension لإن ال a
+
+73
+00:05:59,560 --> 00:06:03,520
+y بزاد ال g لكن لما يكون التسارع إلى أسفل بيعمل
+
+74
+00:06:03,520 --> 00:06:08,450
+decreasing the tensionفي الشكل هذا شكل A block
+
+75
+00:06:08,450 --> 00:06:13,170
+hung by string in an elevator accelerating upward
+
+76
+00:06:13,170 --> 00:06:18,250
+block hung by string في عندي أنا جسم مربوط في ال
+
+77
+00:06:18,250 --> 00:06:21,930
+elevator هذا المصعد و المصعد بيصعد إلى أعلى نفس
+
+78
+00:06:21,930 --> 00:06:27,480
+الشكل T ناقص MG تساوي MAفي B هنا الـ free body
+
+79
+00:06:27,480 --> 00:06:32,620
+diagram هاي هو الشد إلى أعلى والشد إلى أعلى the
+
+80
+00:06:32,620 --> 00:06:36,200
+tension supply the acceleration of the block while
+
+81
+00:06:36,200 --> 00:06:42,140
+supporting it against gravity الشد إلى أعلى و ال M
+
+82
+00:06:42,140 --> 00:06:46,920
+A إلى أعلى هذه موجة بموجة و ال M G إلى أسفل هي قوة
+
+83
+00:06:46,920 --> 00:06:52,760
+طبعا ال M G إلى أسفل وبالتالي الجسم بشدأيضا فيها
+
+84
+00:06:52,760 --> 00:06:56,700
+نقوتين MG و هنا فيه بالنسبة لأش لل .. لل .. فيها
+
+85
+00:06:56,700 --> 00:07:02,060
+نقوة اللي هي الجاذبية هذا الحبل إذا كان هنا طبعا
+
+86
+00:07:02,060 --> 00:07:05,380
+في عندي حبل لكن هنا فيش عندي حبل في عندي أنا وزن
+
+87
+00:07:05,380 --> 00:07:08,880
+الجاذبية اللي أسفل وبالتالي ال vector بيساوي ناقص
+
+88
+00:07:08,880 --> 00:07:09,420
+MG
+
+89
+00:07:12,420 --> 00:07:17,560
+ال case التالتة ال two tension forces at symmetric
+
+90
+00:07:17,560 --> 00:07:25,020
+angles لو كان عندي أنا شدين قوتين للشد بوضع متمثل
+
+91
+00:07:25,020 --> 00:07:29,200
+زوايا معينة in this case لو كان عندي أنا هنا حبل و
+
+92
+00:07:29,200 --> 00:07:36,400
+هنا حبل مربوطين مربوطين بجسم ثابت و هذا الحبل بميل
+
+93
+00:07:36,400 --> 00:07:40,860
+بزاوية ثيتا و هذا الحبل بميل بزاوية ثيتا زاويتين
+
+94
+00:07:40,860 --> 00:07:43,950
+متساوتينin this case the tension will be equal في
+
+95
+00:07:43,950 --> 00:07:46,990
+هذه الحالة أن الشد هذا بساوي هذا الشد ال y
+
+96
+00:07:46,990 --> 00:07:50,890
+component of each tension اللي هي T cosine الزاوية
+
+97
+00:07:50,890 --> 00:07:54,130
+في عندي هنا ال M اللي هو الوزن هنا برسم ل فيديو
+
+98
+00:07:54,130 --> 00:07:57,830
+بيه free body diagram في عندي هنا قوة الوزن إلى
+
+99
+00:07:57,830 --> 00:08:04,460
+أسفل MG و هنا في عندي شدT و هنا T شد المتساوية
+
+100
+00:08:04,460 --> 00:08:09,700
+لإنه زاوية متساوية هنا راح أحلل الشد إلى T sin
+
+101
+00:08:09,700 --> 00:08:13,220
+الزاوية أو هنا في اتجاه الرأس T cosine و هنا راح
+
+102
+00:08:13,220 --> 00:08:18,380
+أحلل T sine و هنا T cosine فبصير عندي أنا مجموعة T
+
+103
+00:08:18,380 --> 00:08:22,460
+cosine بده يساوي ال MG لإنه T sine لإنه فيه
+
+104
+00:08:22,460 --> 00:08:26,950
+symmetric تماثل للزواياف T sine ال right بتساوي T
+
+105
+00:08:26,950 --> 00:08:30,290
+sine ال left ف cancel they are cancel أو بيلغوا
+
+106
+00:08:30,290 --> 00:08:35,290
+بعض فبالتالي بيضال عندي انه ال MG بدها تساوي
+
+107
+00:08:35,290 --> 00:08:42,030
+summation ال MG بدها تساوي اللي هو ال MA ال MAY
+
+108
+00:08:42,030 --> 00:08:45,970
+بدها تساوي T cosine θ زائد T cosine θ ناقص ال MG
+
+109
+00:08:45,970 --> 00:08:52,230
+اذا الحركة هو في حالة اتزان ف2T cosine بدها تساوي
+
+110
+00:08:52,230 --> 00:08:57,170
+ال MG اوأتنين T Cos ناقص ال MG بيساوي Zero إذا ال
+
+111
+00:08:57,170 --> 00:09:03,650
+T Cos بدها تساوي ال MG بدها تساوي اتنين T Cos ثيتا
+
+112
+00:09:03,650 --> 00:09:06,970
+إذا ال T بدها تساوي ال MG على اتنين Cos ثيتا في
+
+113
+00:09:06,970 --> 00:09:12,970
+هذه الحالة لو كان عندي أنا الخيط خيطين مربوطين
+
+114
+00:09:12,970 --> 00:09:19,930
+بزوايا متساوية بسميها في حالة اللي هي symmetric
+
+115
+00:09:19,930 --> 00:09:23,890
+tensionWhether the expression involves sine or
+
+116
+00:09:23,890 --> 00:09:26,970
+cosine depends on what angle are given in the
+
+117
+00:09:26,970 --> 00:09:30,310
+problems طبعا هذه الحالة احنا خدنا cosine عساس انه
+
+118
+00:09:30,310 --> 00:09:34,990
+اعتبرنا انه الزاوية بين الحبل و ال vertical هي ال
+
+119
+00:09:34,990 --> 00:09:39,490
+theta فلما احلل ف T sine هي ال cancel و T cosine
+
+120
+00:09:39,490 --> 00:09:43,070
+بتظلها سماشة لأ T cosine لإنه انا عندي حبلين
+
+121
+00:09:43,070 --> 00:09:47,470
+فبتكون عندي اتنين cosine ال thetaالحكيس ال cases
+
+122
+00:09:47,470 --> 00:09:52,990
+for الحالة الرابعة ال tensions at non-equal angles
+
+123
+00:09:52,990 --> 00:09:56,950
+لو كان عندي tension في بزوايا مختلفة there are
+
+124
+00:09:56,950 --> 00:10:01,030
+many contexts in which two tensions may acts at
+
+125
+00:10:01,030 --> 00:10:05,230
+non-equal angles and the context in the figures is
+
+126
+00:10:05,230 --> 00:10:10,960
+one example في الشكل أربعة سبعة وعشرين كexampleلو
+
+127
+00:10:10,960 --> 00:10:14,300
+كان عندي أنا جسم و هارسمله الـ free body diagram
+
+128
+00:10:14,300 --> 00:10:21,300
+اللي هي الجسم، الجسم شديته بزاوية فيتا وهذا الجسم
+
+129
+00:10:21,300 --> 00:10:27,020
+موجود على اللي هي ال X-axis في هذه الحالة و عندي
+
+130
+00:10:27,020 --> 00:10:31,160
+حبل و عندي هنحبل، الحبلين الحبل بال X-axis و الحبل
+
+131
+00:10:31,160 --> 00:10:37,570
+تاني مشدود بزاوية فيتاو T1 و T2 مجهولين هذه الرسمة
+
+132
+00:10:37,570 --> 00:10:45,090
+بتمثل ال T اللي هي بتمثل ال free body diagram يعني
+
+133
+00:10:45,090 --> 00:10:49,090
+في عندي نشد طالع من الحبل هذا طالع من الكتلة بسبب
+
+134
+00:10:49,090 --> 00:10:54,560
+الحبل هذاوفي شد مائل بزاوية ثيتا اسمه T2 هنسمي هذا
+
+135
+00:10:54,560 --> 00:10:59,480
+T1 نسمي هذا T2 وهي ال MG طبعا هذا T2 مائل بزاوية
+
+136
+00:10:59,480 --> 00:11:03,900
+ثيتا إذا بدنا نحلل بدأ أحلل بال X Axis هيكون T2
+
+137
+00:11:03,900 --> 00:11:08,700
+Sin ثيتا و بال Y Axis T2 Cos اللي جانب الزاوية أنا
+
+138
+00:11:08,700 --> 00:11:14,580
+بحللها لأ Cos اللي أول عمودية بتكون Sinالـ block
+
+139
+00:11:14,580 --> 00:11:19,260
+held by two strings الجسم مربوط بحبلين ورسمنا الـ
+
+140
+00:11:19,260 --> 00:11:22,620
+free body diagram because the given angle θ is
+
+141
+00:11:22,620 --> 00:11:25,520
+with respect to the vertical زي ما حكينا أن θ
+
+142
+00:11:25,520 --> 00:11:29,940
+بالنسبة للvertical الرأسي the adjacent side of the
+
+143
+00:11:29,940 --> 00:11:33,840
+triangle formed by the vector T2 corresponding to
+
+144
+00:11:33,840 --> 00:11:38,190
+the Y directionrequire a cosine function اذا حطيت
+
+145
+00:11:38,190 --> 00:11:42,530
+انا اللي جنب ال vector اللي هي بين الحبل و بين ال
+
+146
+00:11:42,530 --> 00:11:47,530
+.. اللي هي ال vertical line هي بتسميها T cosine و
+
+147
+00:11:47,530 --> 00:11:51,590
+العمودية بتكون T sine with a y بيساوي zero يعني في
+
+148
+00:11:51,590 --> 00:11:55,190
+حالة اتزان the y component of the second law بدأ
+
+149
+00:11:55,190 --> 00:12:00,940
+اطبق قانون نيوتنالتانى summation لل Fy بتساوي ال M
+
+150
+00:12:00,940 --> 00:12:07,040
+في Ay ال Ay فرضناها Zero ف summation لل Fy ال MG
+
+151
+00:12:07,040 --> 00:12:13,820
+سالبة و ال T Cos موجبة فببقى عندي أنا MG سالب ناقص
+
+152
+00:12:13,820 --> 00:12:22,070
+زائد T2 Cos Thetaوفي عندى .. في عندى T1 بدها تساوي
+
+153
+00:12:22,070 --> 00:12:28,210
+T2 sin θ إذا بالنسبة لـ T2 which can easily be
+
+154
+00:12:28,210 --> 00:12:32,690
+solved for the tension T2 T2 بدها تساوي MG على
+
+155
+00:12:32,690 --> 00:12:37,700
+cosine θمرة تانية الـ given angle is with respect
+
+156
+00:12:37,700 --> 00:12:41,620
+to the vertical so the opposite side of the
+
+157
+00:12:41,620 --> 00:12:46,340
+triangle formed by the vector T2 corresponds to
+
+158
+00:12:46,340 --> 00:12:51,020
+the X direction المركبة التانية لأ T2 بالنسبة لأ
+
+159
+00:12:51,020 --> 00:12:55,860
+ال X axis هي عبارة عن T2 sin الزاوية لما أتي أطبق
+
+160
+00:12:55,860 --> 00:13:01,700
+أنا قانون النيوتن التاني على ال X axis بيكون Max
+
+161
+00:13:01,700 --> 00:13:07,810
+بدها تساوي summation لل Fxلأ في X في عندي T1 minus
+
+162
+00:13:07,810 --> 00:13:12,770
+لإنها رايحة باتجاه اللي هي ال X السالب زائد T2 sin
+
+163
+00:13:12,770 --> 00:13:18,290
+θ اللي مع ال X الموجب موجب و اللي X سالب سالب و من
+
+164
+00:13:18,290 --> 00:13:25,230
+خلال هذا طبعا نعوض عن T2 نعوض عن T2 ب MG على
+
+165
+00:13:25,230 --> 00:13:34,430
+cosine θ إذا T1بتساوي T2 sin θ T2 مج على cos θ sin
+
+166
+00:13:34,430 --> 00:13:40,670
+θ اذا طبعا sin على cosine بتطلع ل tan بتطلع T1
+
+167
+00:13:40,670 --> 00:13:43,390
+بتساوي mg tan θ
+
+168
+00:13:48,850 --> 00:13:52,510
+هذا طبعا بيوضع how to determine this illustrates
+
+169
+00:13:52,510 --> 00:13:56,150
+how to determine tension when two such tension are
+
+170
+00:13:56,150 --> 00:13:59,490
+involved in supporting an object using the two
+
+171
+00:13:59,490 --> 00:14:02,630
+components of the second law write two equations
+
+172
+00:14:02,630 --> 00:14:05,310
+and then solve for the two unknowns لو كان عندى
+
+173
+00:14:05,310 --> 00:14:08,730
+انا زى ما حلنا ان في عندى two tension حابلين
+
+174
+00:14:08,730 --> 00:14:15,450
+الحابلين بزاوية طبعا معينة ممكن اجيب انا الشدT1
+
+175
+00:14:15,450 --> 00:14:21,110
+وT2 من خلال تحليل هذا الشد إلى مراكبتين السينية
+
+176
+00:14:21,110 --> 00:14:24,950
+والصادية وانعوض فيه اللي هو قانون نيوتن التاني
+
+177
+00:14:24,950 --> 00:14:29,770
+summation للـFx وSummation للـFy وبنرسم الـfree
+
+178
+00:14:29,770 --> 00:14:32,730
+body diagram باتجاه الـX وfree body diagram باتجاه
+
+179
+00:14:32,730 --> 00:14:37,550
+الـY وبنعمل معادلتين لإيجاد اللي هو المجهولين اللي
+
+180
+00:14:37,550 --> 00:14:43,760
+هو TT1 وT2 كالسابق في section 4.6 application of
+
+181
+00:14:43,760 --> 00:14:48,900
+Newton's law يعني كتطبيق لقانون وقوانين نيوتن when
+
+182
+00:14:48,900 --> 00:14:53,020
+we apply Newton's law to an object we are
+
+183
+00:14:53,020 --> 00:14:57,600
+interested only in those forces that act on the
+
+184
+00:14:57,600 --> 00:15:02,160
+object for example لما بدى أنا أطبق قوانين نيوتن
+
+185
+00:15:02,160 --> 00:15:07,570
+لازم أنا أبحث عن قوة مؤثرة على الجسمهذا الشكل
+
+186
+00:15:07,570 --> 00:15:13,530
+figure 412B the only external force acting on the
+
+187
+00:15:13,530 --> 00:15:18,910
+monitor are N and FG بلاحظ أنه هذا monitor ال
+
+188
+00:15:18,910 --> 00:15:21,250
+monitor ضغط على الطاولة اللي بأثر عليه اللي هو في
+
+189
+00:15:21,250 --> 00:15:24,790
+عندي normal قوة رد الفعل العمودية إلى أعلى وفي
+
+190
+00:15:24,790 --> 00:15:31,850
+عندي قوة الوزن ال FG إلى أسفلكمان يعني هذا ال
+
+191
+00:15:31,850 --> 00:15:36,270
+monitor بيأثر على الطاولة ب FG والطاولة بتأثر على
+
+192
+00:15:36,270 --> 00:15:40,690
+ال monitor ب FG شرطة اللي هنا في عندي قوة رد الفعل
+
+193
+00:15:40,690 --> 00:15:44,910
+الان و هي القوة التانية اللي هي اللي .. اللي طبعا
+
+194
+00:15:44,910 --> 00:15:48,710
+لازم يكون في قوتين قوتين مؤثرين على هذا ال .. هذه
+
+195
+00:15:48,710 --> 00:15:54,100
+النقطةاللي هي N شرط N و N شرطة عكس بعض فلما بداجي
+
+196
+00:15:54,100 --> 00:15:57,280
+أرسم أنا لـfree body diagram في عندي أنا الـnormal
+
+197
+00:15:57,280 --> 00:16:03,000
+الأعلى و الـFG الأسفل لأنه احنا ما بنحسبها بالعين
+
+198
+00:16:03,000 --> 00:16:08,260
+الاعتبار اللي هي أن الـN شرطة و الـFG شرطة هدولة
+
+199
+00:16:08,260 --> 00:16:14,030
+طبعا بيبلغوا بعض بهذا الشكلبأفرض create being
+
+200
+00:16:14,030 --> 00:16:17,590
+pulled to the right to the right on a frictionless
+
+201
+00:16:17,590 --> 00:16:21,690
+horizontal surface suppose you wish to find the
+
+202
+00:16:21,690 --> 00:16:24,650
+acceleration of the crate and the force the
+
+203
+00:16:24,650 --> 00:16:28,070
+surface exerted on it the magnitude of T is equal
+
+204
+00:16:28,070 --> 00:16:31,350
+to the tension in the rope بأفرض في عندي عربة
+
+205
+00:16:31,350 --> 00:16:35,790
+والعربة بدي أشدها إلى اليمين على سطح أملس
+
+206
+00:16:35,790 --> 00:16:39,750
+frictionless والسطح طبعا أفقي أملس بيسمو
+
+207
+00:16:39,750 --> 00:16:43,300
+frictionless horizontal surfaceده أفرض أنه أنا
+
+208
+00:16:43,300 --> 00:16:49,520
+شدتها بتسارع معين و بقوة معينة مؤثرة على هذا الجسم
+
+209
+00:16:49,520 --> 00:16:53,440
+قوة الشد طبعا المؤثرة على هذا الجسم أنا شدت هذه
+
+210
+00:16:53,440 --> 00:16:58,660
+العربة على سطح frictionless إلى اليمينطبعا هذه قوة
+
+211
+00:16:58,660 --> 00:17:03,300
+الشد بنسميها T بدا أرسم ال free body diagram طبعا
+
+212
+00:17:03,300 --> 00:17:06,900
+العربة على الأرض هيها بهذا الممثل العربة ال free
+
+213
+00:17:06,900 --> 00:17:09,800
+body diagram في عندي أنا قوة ردفع العمودية إلى
+
+214
+00:17:09,800 --> 00:17:13,400
+أعلى و في عندي قوة وزن اللي هي ال FG إلى أسفل و في
+
+215
+00:17:13,400 --> 00:17:19,660
+عندي اللي هو ال tension قوة الشد إلى اليمين هذا هو
+
+216
+00:17:19,660 --> 00:17:23,570
+ال free body diagramلما بدى انا اكتب معادلات
+
+217
+00:17:23,570 --> 00:17:28,830
+معادلات اللى هى القانونية التانية ممكن احنا اذا
+
+218
+00:17:28,830 --> 00:17:32,730
+كانت الحركة باتجاه ال .. ال .. ال right او تجاه
+
+219
+00:17:32,730 --> 00:17:36,670
+الشرق راح نحكى انه some motion لبقى في X بتساول ام
+
+220
+00:17:36,670 --> 00:17:40,070
+في مين القوة اللى في اتجاه ال X هي T اذا because
+
+221
+00:17:40,070 --> 00:17:42,790
+we are interested only in the tension of the crate
+
+222
+00:17:42,790 --> 00:17:46,460
+مافيش عندى قوة الا الشدوانا بتحرك في تجاه ال X
+
+223
+00:17:46,460 --> 00:17:51,680
+-Axis بتسارع معين نحن يجب أن نكون قادرين على
+
+224
+00:17:51,680 --> 00:17:59,260
+اكتشاف جميع القوات اللي مؤثرة على هذا الجسم لما
+
+225
+00:17:59,260 --> 00:18:02,020
+أرسم ال free body diagram زي ما هو موضح بالشكل
+
+226
+00:18:02,020 --> 00:18:07,320
+figure 429B هاي هو ال free body diagram المؤثرة
+
+227
+00:18:07,320 --> 00:18:14,000
+عليها باتجاه ال X-Axis هي ال Tإذن الـ Force T، الـ
+
+228
+00:18:14,000 --> 00:18:16,500
+Free Body Diagram for the crate اللي including a
+
+229
+00:18:16,500 --> 00:18:19,400
+force of gravity F exerted by earth and the normal
+
+230
+00:18:19,400 --> 00:18:22,720
+force N exerted by the floor الـ Normal Force
+
+231
+00:18:22,720 --> 00:18:26,720
+مؤثرة من الأرض على الـ body أو الـ crate أو العربة
+
+232
+00:18:26,720 --> 00:18:31,160
+وقوة الجاذبية مؤثرة طبعا تأثير قوة جاذبية الأرض
+
+233
+00:18:31,160 --> 00:18:38,770
+لهدأ الجسمالتجارب التي لدينا لسه لسه لسه ليست
+
+234
+00:18:38,770 --> 00:18:41,590
+مضمونة في البرنامج الانفجاري لأنهم يدفعوا على
+
+235
+00:18:41,590 --> 00:18:47,510
+مجموعات أخرى وليس على الـ CreateNow let's apply
+
+236
+00:18:47,510 --> 00:18:51,110
+Newton's second law to the crate first. We choose
+
+237
+00:18:51,110 --> 00:18:55,130
+an appropriate coordinate system in this case it's
+
+238
+00:18:55,130 --> 00:18:59,130
+convenient to use the one shown in the figure with
+
+239
+00:18:59,130 --> 00:19:03,230
+the x-axis horizontal and the y-axis vertical we
+
+240
+00:19:03,230 --> 00:19:06,330
+can apply Newton's second law زي ما حكينا أنهبدي
+
+241
+00:19:06,330 --> 00:19:11,190
+انا اطبق قوانين نيوتن التاني لاللي هي القوة اللي
+
+242
+00:19:11,190 --> 00:19:13,950
+هو summation لل Fy بتساوي ال M في Ay و summation
+
+243
+00:19:13,950 --> 00:19:20,550
+لل Fx بتساوي ال M في Ax بتعتمد طبعا depending on
+
+244
+00:19:20,550 --> 00:19:25,650
+the X and Y اللي هي direction وكمان بتعتمد على انه
+
+245
+00:19:25,650 --> 00:19:30,420
+وين الجسم هو بتتحركأذا في عندي أنا صمشة لل Fx
+
+246
+00:19:30,420 --> 00:19:34,120
+بتساوي ال M في AX Fx باللي هي بارع عن T بتساوي ال
+
+247
+00:19:34,120 --> 00:19:37,480
+M في AX بالنسبة لل Fy عندي أنا ال normal اللي أعلى
+
+248
+00:19:37,480 --> 00:19:40,380
+موجة بناقص ال MG بتساوي ال M في AY طبعا هذه مافيش
+
+249
+00:19:40,380 --> 00:19:44,520
+حركة بتجاه ال Y بتساوي Zero from this situation من
+
+250
+00:19:44,520 --> 00:19:49,790
+هذه المعادلات we find that the accelerationالتسارع
+
+251
+00:19:49,790 --> 00:19:54,730
+بتجاه ال X axis is constant فإذا ال AX بتساوي T
+
+252
+00:19:54,730 --> 00:19:59,490
+على M فده الحالة و ال normal بتساوي ال MG because
+
+253
+00:19:59,490 --> 00:20:03,810
+the acceleration is constant لإنه التسارع ثابت
+
+254
+00:20:03,810 --> 00:20:08,050
+فمعادلة المعادلة ال kinematic can be applied to
+
+255
+00:20:08,050 --> 00:20:13,190
+obtain further information about the velocity and
+
+256
+00:20:13,190 --> 00:20:18,760
+displacement of the object لإنه التسارعهنا موجود
+
+257
+00:20:18,760 --> 00:20:23,040
+باتجاه ال X-axis فحكينا ان ال AX بتساوي T على M
+
+258
+00:20:23,040 --> 00:20:27,020
+فىش تسارع بتجاه ال Y اذا فىش تسارع ولكن فى تسارع
+
+259
+00:20:27,020 --> 00:20:32,620
+جد بيه اذا ال normal بتساوي ال MGهنا بيحكينا إنه
+
+260
+00:20:32,620 --> 00:20:35,340
+كيف أنا ممكن أحل المسائل و كيف أعمل معادلات
+
+261
+00:20:35,340 --> 00:20:39,540
+problem solving strategy قانون نيوتن التاني
+
+262
+00:20:39,540 --> 00:20:43,480
+problem involving Newton's second law can be very
+
+263
+00:20:43,480 --> 00:20:47,620
+complex the following protocol بروتوكولات يعني هي
+
+264
+00:20:47,620 --> 00:20:55,180
+تعليمات لحل هذه المعادلات بطريقة سهلةلتحقيق الهداف
+
+265
+00:20:55,180 --> 00:20:59,860
+أول حاجة بدك تقرأ السؤال طبعا بإناية بعدين بدي
+
+266
+00:20:59,860 --> 00:21:04,140
+أرسم picture بدي أرسم السؤال كيعني رسم بعدين ممكن
+
+267
+00:21:04,140 --> 00:21:08,020
+أرسم ال free body diagram و أحط ال label عليه يعني
+
+268
+00:21:08,020 --> 00:21:11,940
+المعطيات الموجودة عندي ا draw a free body diagram
+
+269
+00:21:11,940 --> 00:21:15,600
+من خلال ال free body diagram يعني و رسم تخطيط اللي
+
+270
+00:21:15,600 --> 00:21:17,280
+هيجيه القوة المؤثرة على الجسم
+
+271
+00:21:24,070 --> 00:21:30,230
+لو كان عندي قوة بتجاه X أو Y ممكن ارسم في البرنامج
+
+272
+00:21:30,230 --> 00:21:34,650
+الاخر مرة بال X و مرة بالYبأطبق قانون نوتن التاني
+
+273
+00:21:34,650 --> 00:21:38,330
+ممكن أطبقه مرة على ال X-axis ومرة على ال Y-axis
+
+274
+00:21:38,330 --> 00:21:41,470
+وعشان نستطيع أن الحل هذا ي solve the desired
+
+275
+00:21:41,470 --> 00:21:45,530
+unknown quantity ممكن أحل المسألة وإيجاد المتغيرات
+
+276
+00:21:45,530 --> 00:21:49,010
+الموجودة في السؤال in the special case of
+
+277
+00:21:49,010 --> 00:21:53,130
+equilibrium في حالة يحكي للسؤال أن الجسم في حالة
+
+278
+00:21:53,130 --> 00:21:56,310
+equilibrium معنى الكلام أن ال acceleration بدها
+
+279
+00:21:56,310 --> 00:21:59,720
+تساوي zeroمعنى كلها أن الـ acceleration بالساوية 0
+
+280
+00:21:59,720 --> 00:22:04,320
+و بأستطيع أن أحل السؤال بإيجاد المتغيرات الموجودة
+
+281
+00:22:04,320 --> 00:22:08,220
+بوجود أن التسارع بالساوية G0 يعني summation لل Fx
+
+282
+00:22:08,220 --> 00:22:11,740
+بالساوية 0 و summation لل Fy بالساوية 0 إذا حكى أن
+
+283
+00:22:11,740 --> 00:22:16,320
+الجسم في حالة equilibriumفي حالة الـ equilibrium
+
+284
+00:22:16,320 --> 00:22:19,660
+الـ object in equilibrium زي ما حكينا سابقا ال
+
+285
+00:22:19,660 --> 00:22:22,540
+object that are either at rest or moving with
+
+286
+00:22:22,540 --> 00:22:26,900
+constant velocity is said to be equilibrium يعني
+
+287
+00:22:26,900 --> 00:22:30,160
+مش شرط أنه الجسم ساكن ممكن الجسم يكون يتحرك ب
+
+288
+00:22:30,160 --> 00:22:35,340
+constant velocity في هذه الحالة الجسم يعتبر بتحرك
+
+289
+00:22:35,340 --> 00:22:40,590
+بتسارع بساوي zero وهو يعتبر في حالة اتزانالـ
+
+290
+00:22:40,590 --> 00:22:42,890
+Newton's second law applied to an object بقى أطبق
+
+291
+00:22:42,890 --> 00:22:47,310
+قانون نيوتن التاني في حالة الإتزان فالـ Fy .. ال F
+
+292
+00:22:47,310 --> 00:22:50,950
+سماشي للـ F سواء Zero سواء Fy أو .. أو .. أو Fx
+
+293
+00:22:50,950 --> 00:22:55,130
+for two dimensional problems سواء كان بالاتجاه ال
+
+294
+00:22:55,130 --> 00:23:00,730
+X أو Y plane المعادلة 4.19 بقى ممكن أطبقها سماشي
+
+295
+00:23:00,730 --> 00:23:04,110
+للـ Fx بسوء Zero سماشي للـ Fy بسوء Zero لإنه هذه
+
+296
+00:23:04,110 --> 00:23:07,710
+متجهة ال vectors ممثلة ممكن تكون X Y Z لكن احنا
+
+297
+00:23:07,710 --> 00:23:12,480
+بنشغل على مستوى X وYهتكون summation ل Fx تساوي 0 و
+
+298
+00:23:12,480 --> 00:23:18,380
+summation ل Fy تساوي 0 ناخد هذا ال quiz أربعة
+
+299
+00:23:18,380 --> 00:23:22,620
+تمانية consider the two situations show in the
+
+300
+00:23:22,620 --> 00:23:27,520
+figure 4.3 in which there is no accelerationin
+
+301
+00:23:27,520 --> 00:23:30,580
+both cases the main ball with the force of
+
+302
+00:23:30,580 --> 00:23:37,700
+magnitude F is reading on the scale in part I of
+
+303
+00:23:37,700 --> 00:23:44,400
+the figure A greater than or B less than Nimra C
+
+304
+00:23:44,400 --> 00:23:51,300
+equal to the reading in part in partin part طبعا
+
+305
+00:23:51,300 --> 00:23:57,360
+ال three هنا في عندي أنا جسم او شخص بيشد skill
+
+306
+00:23:57,360 --> 00:24:02,160
+reading يعني زي زمبرك او عليا زي الها مقياس معين
+
+307
+00:24:02,160 --> 00:24:05,920
+consider the two situation في عندي حالتين لل skill
+
+308
+00:24:05,920 --> 00:24:09,200
+reading which there is no acceleration طبعا في
+
+309
+00:24:09,200 --> 00:24:14,040
+حالة اتزان in both cases the main pole with force
+
+310
+00:24:14,040 --> 00:24:20,430
+of magnitude Fيعني عندنا هنا ال .. هنا الجسم الرجل
+
+311
+00:24:20,430 --> 00:24:25,230
+بشد skill reading بقوة F طبعا هذا ال skill reading
+
+312
+00:24:25,230 --> 00:24:28,630
+بيقيص ال F الآن هنا في عندي skill reading في عندي
+
+313
+00:24:28,630 --> 00:24:35,610
+أنا جسمين أو رجلين بشده بالنسبة للسؤال بيحكيلي is
+
+314
+00:24:35,610 --> 00:24:41,030
+the reading on the scale in part Iin part I of the
+
+315
+00:24:41,030 --> 00:24:45,010
+figure greater than او less than او equal to the
+
+316
+00:24:45,010 --> 00:24:48,670
+reading in part 2 هل scale reading لنقطة لل part
+
+317
+00:24:48,670 --> 00:24:55,480
+oneA is أكبر أو أقل أو بيساوي ال scale reading ل
+
+318
+00:24:55,480 --> 00:24:59,540
+ال part هذا part one هذا part two هل ال scale
+
+319
+00:24:59,540 --> 00:25:04,000
+reading لهذا بيساوي هذا ولا أكبر منه ولا أقل منه
+
+320
+00:25:04,000 --> 00:25:06,960
+طبعا هنا لكل فعل رد فعل مساوئلها في المقدار
+
+321
+00:25:06,960 --> 00:25:10,860
+المتعكس بالاتجاه فهذه ال F بتساوي ال F إذا القوة
+
+322
+00:25:10,860 --> 00:25:17,220
+هي متساوية هذا قانونية التالت لكل فعل رد فعلإنه
+
+323
+00:25:17,220 --> 00:25:21,040
+إذا هذا بشد بقوة F هذا بشد بنفس القوة F برضه هذا
+
+324
+00:25:21,040 --> 00:25:26,320
+ال F هذا بشد بقوة F هذا قوته F إحنا ما بنجمع هدول
+
+325
+00:25:26,320 --> 00:25:28,860
+قوتين متساوتين في المقدار متعاكستين بالاتجاه
+
+326
+00:25:28,860 --> 00:25:34,080
+وبالتالي ال part one ال F لل part one تساوي ال F ل
+
+327
+00:25:34,080 --> 00:25:38,080
+ال tension in each chord is F which is reading the
+
+328
+00:25:38,080 --> 00:25:42,370
+scale the samethe scale reading is the same لإنه
+
+329
+00:25:42,370 --> 00:25:46,630
+جميع القوة هي F F F يعني باجمعش هذه F زائد F لإن
+
+330
+00:25:46,630 --> 00:25:49,590
+هدول القوتين متساوتين في المقدار متعاكسة بالاتجاه
+
+331
+00:25:49,590 --> 00:25:55,050
+كقيمة ك magnitude ال F لل part one بساوي ال F في
+
+332
+00:25:55,050 --> 00:26:00,290
+هذا الشكل ناخد
+
+333
+00:26:00,290 --> 00:26:07,750
+سؤالproblem طبعا example أربعة سبعة أن problems
+
+334
+00:26:07,750 --> 00:26:11,690
+traffic light weighting طبعا واحد في عشر أقصى
+
+335
+00:26:11,690 --> 00:26:15,870
+اتنين نيوتين hang from a vertical cable tied to
+
+336
+00:26:15,870 --> 00:26:19,030
+two other cables that are fastened to support
+
+337
+00:26:19,600 --> 00:26:25,520
+الشبكة تعمل تجارب 37 درجة أو 53 درجة مع اتجارات
+
+338
+00:26:25,520 --> 00:26:28,180
+عالية في كل حبل تعمل تجارب 37 درجة أو 53 درجة مع
+
+339
+00:26:28,180 --> 00:26:30,440
+اتجارات عالية في كل حبل تعمل تجارب 37 درجة أو 53
+
+340
+00:26:30,440 --> 00:26:32,860
+درجة مع اتجارات عالية في كل حبل تعمل تجارب 37 درجة
+
+341
+00:26:32,860 --> 00:26:33,960
+أو 53 درجة مع اتجارات عالية في كل حبل تعمل تجارب
+
+342
+00:26:33,960 --> 00:26:37,160
+37 درجة أو 53 درجة مع اتجارات عالية في كل حبل تعمل
+
+343
+00:26:37,160 --> 00:26:37,260
+تجارب 37 درجة أو 53 درجة مع اتجارات عالية في كل
+
+344
+00:26:37,260 --> 00:26:37,440
+حبل تعمل تجارب 37 درجة أو 53 درجة مع اتجارات عالية
+
+345
+00:26:37,440 --> 00:26:45,860
+في كل حبل تعمل تجارب 37 درجة أو 53 درجةلأن في
+
+346
+00:26:45,860 --> 00:26:51,540
+عندنا نقطة نقطة رابط ف T1 لا تساوي T2 إذا T2 ميلة
+
+347
+00:26:51,540 --> 00:26:58,380
+بزاوية 53 و T1 ميلة بزاوية 37 مطلوب أوجد الشد في
+
+348
+00:26:58,380 --> 00:27:03,260
+T1 و T2 و T3 طبعا لما أجي أرسم أنا ال free body
+
+349
+00:27:03,260 --> 00:27:06,320
+diagram بهذا الشكل بدي أرسم ال free body diagram
+
+350
+00:27:06,320 --> 00:27:13,160
+رسم تخطيتي أول حاجة T2 بدي أحللها إلى قوتينهنا T2
+
+351
+00:27:13,160 --> 00:27:22,800
+T2 هنا هنا sign و هنا T2 cos 53 و هنا T1 sin 37 و
+
+352
+00:27:22,800 --> 00:27:30,980
+T1 cos 37 و في تحت اللي هو T3 و الوزن T3 و قوة
+
+353
+00:27:30,980 --> 00:27:37,450
+الوزن قوة الوزن و في هناT3 بهذا الشكل في البداية
+
+354
+00:27:37,450 --> 00:27:43,370
+طبعا بدي اروح لمين الحل بدي اوجد T3 من الشكل بلاحظ
+
+355
+00:27:43,370 --> 00:27:48,370
+انه انه summation لل FY بساوة 0 فT3 نقص ال FG
+
+356
+00:27:48,370 --> 00:27:52,510
+بساوة 0 اذا T3 بساوة ال FG اللي هي 1 في 10 عقل 2
+
+357
+00:27:52,510 --> 00:27:58,570
+نيوتن T3الان بدى استخدم عندى انا resolve all three
+
+358
+00:27:58,570 --> 00:28:03,370
+tension forces into a component بدى احلل اللى هى
+
+359
+00:28:03,370 --> 00:28:08,490
+عندى تلاتة tension T1, T2, T3 بدى افسر هذه اللى هى
+
+360
+00:28:08,490 --> 00:28:14,550
+قوة الشد الى مراكباتها الصينية والصادية فT1 هتكون
+
+361
+00:28:14,550 --> 00:28:20,110
+ناقص T1 بالنسبة لمركبة الصينية ناقص T1 كزين 37
+
+362
+00:28:20,110 --> 00:28:25,600
+مراكبة الصادية T1 صين 37مُركّب الصينية لـ T2 T2
+
+363
+00:28:25,600 --> 00:28:31,080
+Cos 53 لأنها تتجه إلى اليمين أو الشرق، هنا متجه
+
+364
+00:28:31,080 --> 00:28:38,220
+إلى اليسار T2 بالنسبة للـ Y Axis T2 Sin 53 بالنسبة
+
+365
+00:28:38,220 --> 00:28:44,520
+للـ T0 في الـ X Axis 0 بالـ Y Axis ناقص 1 في 10
+
+366
+00:28:44,520 --> 00:28:50,160
+أقصى 2 نيوتن، هذه التي هي T3بدي اطبق القوانين الـ
+
+367
+00:28:50,160 --> 00:28:55,040
+Newton التاني بالـ X axis والـ Y axis applying the
+
+368
+00:28:55,040 --> 00:28:58,680
+condition for equilibrium to the node using a
+
+369
+00:28:58,680 --> 00:28:59,960
+component in the table
+
+370
+00:29:18,300 --> 00:29:22,800
+زائد T2 Sin 53 ناقص واحد في عشر أقصى اتنين متم
+
+371
+00:29:22,800 --> 00:29:26,540
+ساوي Zero There are two equations في عندي الآن
+
+372
+00:29:26,540 --> 00:29:31,380
+معادلتين and two remaining unknown في عندي أنا
+
+373
+00:29:31,380 --> 00:29:36,160
+معادلتين صاري بمجهولين المعادلتين بمجهولين هأوجد
+
+374
+00:29:36,160 --> 00:29:43,900
+T2 بدها تساوي T1 من المعادلة الأولى T2 بدها تساوي
+
+375
+00:29:44,060 --> 00:29:53,700
+T1 cos 37 على cos 53 فT1 بدها تساوي هذه القيمة
+
+376
+00:29:53,700 --> 00:30:02,410
+عوضت عن cos 37 و عن cos 53 بطلع عندي 1.33T1طبعا T2
+
+377
+00:30:02,410 --> 00:30:07,290
+بدلالة T1 الآن substitute بعوض عن T2 في المعادلة
+
+378
+00:30:07,290 --> 00:30:13,010
+اللي هي التانية بدعوض عن T2 بدلالة T1 اذا T1 sin
+
+379
+00:30:13,010 --> 00:30:22,130
+37 زائد طبعا 1.33 T1 اللي طلعت ليها في sin 53 ناقص
+
+380
+00:30:22,500 --> 00:30:26,460
+1 في 10 أقصى 2 نيوتن بيساوي 0 صرت عندي معادلة
+
+381
+00:30:26,460 --> 00:30:35,480
+بمجهول 1 اللي هو T1 بأوجه T1 بتطلع 60.1 إذا عشان
+
+382
+00:30:35,480 --> 00:30:41,880
+أوجه T2 T2 من المعادلة هذه بتساوي 1.33 في T1 إذا 1
+
+383
+00:30:41,880 --> 00:30:51,050
+.33 في T1 اللي هي 60.1 بتطلع 79.9طبعا بنكمل في
+
+384
+00:30:51,050 --> 00:30:52,910
+التسجيل القادم
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..83dced184bc789c2feae1c3a078c4d703f2066b9
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_raw.json
@@ -0,0 +1 @@
+{"segments": [{"id": 1, "seek": 1764, "start": 0.44, "end": 17.64, "text": "بسم الله الرحمن الرحيم بنستكمل section أربعة خمسة بعنوان attention forces attention force can be exerted by attaching string or cable to an object and pulling it", "tokens": [3555, 38251, 21984, 34892, 5016, 27842, 34892, 5016, 32640, 44945, 14851, 24793, 1211, 3541, 5551, 25513, 27884, 16490, 2304, 3794, 3660, 45030, 1863, 2407, 7649, 3202, 5874, 3202, 3464, 393, 312, 31941, 292, 538, 39074, 6798, 420, 8220, 281, 364, 2657, 293, 8407, 309], "avg_logprob": -0.11336805489328172, "compression_ratio": 1.3557046979865772, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 0.44, "end": 0.72, "word": "بسم", "probability": 0.917724609375}, {"start": 0.72, "end": 0.88, "word": " الله", "probability": 0.9462890625}, {"start": 0.88, "end": 1.24, "word": " الرحمن", "probability": 0.9772135416666666}, {"start": 1.24, "end": 1.66, "word": " الرحيم", "probability": 0.99609375}, {"start": 1.66, "end": 2.56, "word": 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0.830078125}], "temperature": 1.0}, {"id": 18, "seek": 38515, "start": 366.03, "end": 385.15, "text": "في الشكل هذا شكل A block hung by string in an elevator accelerating upward block hung by string في عندي أنا جسم مربوط في ال elevator هذا المصعد و المصعد بيصعد إلى أعلى نفس الشكل T ناقص MG تساوي MA", "tokens": [41185, 25124, 28820, 23758, 13412, 28820, 316, 3461, 5753, 538, 6798, 294, 364, 18782, 34391, 23452, 3461, 5753, 538, 6798, 8978, 18871, 16254, 41850, 10874, 38251, 3714, 25513, 2407, 9566, 8978, 2423, 18782, 23758, 9673, 9381, 22488, 4032, 9673, 9381, 22488, 4724, 1829, 9381, 22488, 30731, 5551, 3615, 23942, 8717, 36178, 25124, 28820, 314, 8717, 995, 4587, 9381, 36856, 6055, 3794, 995, 45865, 12191], "avg_logprob": -0.21057692307692308, "compression_ratio": 1.5449438202247192, "no_speech_prob": 3.5762786865234375e-07, "words": [{"start": 366.03, "end": 366.47, "word": "في", "probability": 0.634765625}, {"start": 366.47, "end": 366.83, "word": " الشكل", "probability": 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" بزاوية", "probability": 0.88173828125}, {"start": 456.82, "end": 457.22, "word": " ثيتا", "probability": 0.6265462239583334}, {"start": 457.22, "end": 457.34, "word": " و", "probability": 0.93994140625}, {"start": 457.34, "end": 457.48, "word": " هذا", "probability": 0.95654296875}, {"start": 457.48, "end": 457.82, "word": " الحبل", "probability": 0.987060546875}, {"start": 457.82, "end": 458.58, "word": " بميل", "probability": 0.8987630208333334}, {"start": 458.58, "end": 458.98, "word": " بزاوية", "probability": 0.989453125}, {"start": 458.98, "end": 459.82, "word": " ثيتا", "probability": 0.9332682291666666}, {"start": 459.82, "end": 460.86, "word": " زاويتين", "probability": 0.887890625}, {"start": 460.86, "end": 461.62, "word": " متساوتين", "probability": 0.901171875}], "temperature": 1.0}, {"id": 22, "seek": 48133, "start": 461.73, "end": 481.33, "text": "in this case the tension will be equal في هذه الحالة أن الشد هذا بساوي هذا الشد ال y component of each tension اللي هي T cosine الزاوية في عندي هنا ال M اللي هو الوزن هنا برسم ل فيديو بيه free body diagram في عندي هنا قوة الوزن إلى أسفل MG و هنا في عندي شد", "tokens": [259, 341, 1389, 264, 8980, 486, 312, 2681, 8978, 29538, 21542, 6027, 3660, 14739, 25124, 3215, 23758, 4724, 3794, 995, 45865, 23758, 25124, 3215, 2423, 288, 6542, 295, 1184, 8980, 13672, 1829, 39896, 314, 23565, 6024, 110, 995, 2407, 10632, 8978, 18871, 16254, 34105, 2423, 376, 13672, 1829, 31439, 2423, 2407, 11622, 1863, 34105, 4724, 2288, 38251, 5296, 8978, 16254, 2407, 4724, 1829, 3224, 1737, 1772, 10686, 8978, 18871, 16254, 34105, 12174, 2407, 3660, 2423, 2407, 11622, 1863, 30731, 5551, 3794, 5172, 1211, 36856, 4032, 34105, 8978, 18871, 16254, 13412, 3215], "avg_logprob": -0.30180028599241504, "compression_ratio": 1.7058823529411764, "no_speech_prob": 4.76837158203125e-07, "words": [{"start": 461.73, "end": 462.03, "word": "in", "probability": 0.07537841796875}, {"start": 462.03, "end": 462.25, "word": " this", "probability": 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"end": 474.13, "word": " فيديو", "probability": 0.4549153645833333}, {"start": 474.13, "end": 474.41, "word": " بيه", "probability": 0.5867513020833334}, {"start": 474.41, "end": 474.75, "word": " free", "probability": 0.53466796875}, {"start": 474.75, "end": 474.91, "word": " body", "probability": 0.662109375}, {"start": 474.91, "end": 475.45, "word": " diagram", "probability": 0.92431640625}, {"start": 475.45, "end": 475.95, "word": " في", "probability": 0.7275390625}, {"start": 475.95, "end": 476.23, "word": " عندي", "probability": 0.8212890625}, {"start": 476.23, "end": 476.49, "word": " هنا", "probability": 0.857421875}, {"start": 476.49, "end": 476.97, "word": " قوة", "probability": 0.9606119791666666}, {"start": 476.97, "end": 477.49, "word": " الوزن", "probability": 0.9971923828125}, {"start": 477.49, "end": 477.83, "word": " إلى", "probability": 0.81640625}, {"start": 477.83, "end": 478.57, "word": " أسفل", "probability": 0.97607421875}, {"start": 478.57, "end": 479.47, "word": " MG", "probability": 0.419921875}, {"start": 479.47, "end": 480.03, "word": " و", "probability": 0.70068359375}, {"start": 480.03, "end": 480.23, "word": " هنا", "probability": 0.6123046875}, {"start": 480.23, "end": 480.41, "word": " في", "probability": 0.935546875}, {"start": 480.41, "end": 480.81, "word": " عندي", "probability": 0.861572265625}, {"start": 480.81, "end": 481.33, "word": " شد", "probability": 0.97216796875}], "temperature": 1.0}, {"id": 23, "seek": 50394, "start": 481.54, "end": 503.94, "text": "T و هنا T شد المتساوية لإنه زاوية متساوية هنا راح أحلل الشد إلى T sin الزاوية أو هنا في اتجاه الرأس T cosine و هنا راح أحلل T sine و هنا T cosine فبصير عندي أنا مجموعة T cosine بده يساوي ال MG لإنه T sine لإنه فيه symmetric تماثل للزوايا", "tokens": [51, 4032, 34105, 314, 13412, 3215, 9673, 2655, 3794, 995, 2407, 10632, 5296, 28814, 1863, 3224, 30767, 995, 2407, 10632, 44650, 3794, 995, 2407, 10632, 34105, 12602, 39319, 5551, 5016, 1211, 1211, 25124, 3215, 30731, 314, 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أعمل معادلات problem solving strategy قانون نيوتن التاني problem involving Newton's second law can be very complex the following protocol بروتوكولات يعني هي تعليمات لحل هذه المعادلات بطريقة سهلة", "tokens": [3224, 8315, 4724, 1829, 5016, 4117, 1829, 8315, 36145, 3224, 9122, 33911, 41850, 3714, 43020, 5551, 5016, 1211, 9673, 3794, 16373, 1211, 4032, 9122, 33911, 5551, 25957, 1211, 20449, 18513, 1211, 9307, 1154, 12606, 5206, 12174, 7649, 11536, 8717, 1829, 35473, 1863, 16712, 7649, 1829, 1154, 17030, 19541, 311, 1150, 2101, 393, 312, 588, 3997, 264, 3480, 10336, 4724, 32887, 2655, 2407, 4117, 12610, 9307, 37495, 22653, 39896, 37279, 20292, 2304, 9307, 5296, 5016, 1211, 29538, 9673, 3615, 18513, 1211, 9307, 4724, 9566, 16572, 28671, 8608, 3224, 37977], "avg_logprob": -0.166257027829631, "compression_ratio": 1.4831932773109244, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 1231.16, "end": 1231.64, "word": "هنا", "probability": 0.96044921875}, {"start": 1231.64, "end": 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that are either at rest or moving with constant velocity is said to be equilibrium يعني مش شرط أنه الجسم ساكن ممكن الجسم يكون يتحرك ب constant velocity في هذه الحالة الجسم يعتبر بتحرك بتسارع بساوي zero وهو يعتبر في حالة اتزان", "tokens": [41185, 11331, 6027, 3660, 2423, 39184, 15625, 2423, 39184, 2657, 294, 15625, 30767, 1829, 19446, 11331, 4117, 1829, 8315, 8608, 16758, 4587, 995, 2423, 2657, 300, 366, 2139, 412, 1472, 420, 2684, 365, 5754, 9269, 307, 848, 281, 312, 15625, 37495, 22653, 37893, 13412, 2288, 9566, 14739, 3224, 25724, 38251, 8608, 995, 19452, 3714, 43020, 25724, 38251, 7251, 30544, 7251, 2655, 5016, 31747, 4724, 5754, 9269, 8978, 29538, 21542, 6027, 3660, 25724, 38251, 7251, 34268, 26890, 39894, 5016, 31747, 39894, 3794, 9640, 3615, 4724, 3794, 995, 45865, 4018, 37037, 2407, 7251, 34268, 26890, 8978, 11331, 6027, 3660, 1975, 2655, 11622, 7649], "avg_logprob": -0.13013174706229977, "compression_ratio": 1.757201646090535, "no_speech_prob": 5.960464477539063e-08, "words": 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1801.0, "text": "T1 cos 37 على cos 53 فT1 بدها تساوي هذه القيمة عوضت عن cos 37 و عن cos 53 بطلع عندي 1.33T1", "tokens": [51, 16, 3792, 13435, 15844, 3792, 21860, 6156, 51, 16, 47525, 11296, 6055, 3794, 995, 45865, 29538, 25062, 32640, 3660, 6225, 2407, 11242, 2655, 18871, 3792, 13435, 4032, 18871, 3792, 21860, 4724, 9566, 1211, 3615, 18871, 16254, 502, 13, 10191, 51, 16], "avg_logprob": -0.33866277960843816, "compression_ratio": 1.1727272727272726, "no_speech_prob": 2.1696090698242188e-05, "words": [{"start": 1784.06, "end": 1785.46, "word": "T1", "probability": 0.6427001953125}, {"start": 1785.46, "end": 1786.3, "word": " cos", "probability": 0.1900634765625}, {"start": 1786.3, "end": 1787.26, "word": " 37", "probability": 0.8974609375}, {"start": 1787.26, "end": 1787.6, "word": " على", "probability": 0.0212249755859375}, {"start": 1787.6, "end": 1788.1, "word": " cos", "probability": 0.7373046875}, {"start": 1788.1, "end": 1789.02, "word": " 53", "probability": 0.962890625}, {"start": 1789.02, "end": 1791.36, "word": " فT1", "probability": 0.6969401041666666}, {"start": 1791.36, "end": 1792.02, "word": " بدها", "probability": 0.59381103515625}, {"start": 1792.02, "end": 1792.54, "word": " تساوي", "probability": 0.97216796875}, {"start": 1792.54, "end": 1793.2, "word": " هذه", "probability": 0.480224609375}, {"start": 1793.2, "end": 1793.7, "word": " القيمة", "probability": 0.9617513020833334}, {"start": 1793.7, "end": 1794.14, "word": " عوضت", "probability": 0.9027099609375}, {"start": 1794.14, "end": 1794.28, "word": " عن", "probability": 0.9541015625}, {"start": 1794.28, "end": 1794.54, "word": " cos", "probability": 0.82568359375}, {"start": 1794.54, "end": 1795.3, "word": " 37", "probability": 0.9677734375}, {"start": 1795.3, "end": 1796.02, "word": " و", "probability": 0.908203125}, {"start": 1796.02, "end": 1796.18, "word": " عن", "probability": 0.173583984375}, {"start": 1796.18, "end": 1796.52, "word": " cos", "probability": 0.9228515625}, {"start": 1796.52, "end": 1797.32, "word": " 53", "probability": 0.96435546875}, {"start": 1797.32, "end": 1797.72, "word": " بطلع", "probability": 0.7967529296875}, {"start": 1797.72, "end": 1798.1, "word": " عندي", "probability": 0.62939453125}, {"start": 1798.1, "end": 1798.72, "word": " 1", "probability": 0.88623046875}, {"start": 1798.72, "end": 1801.0, "word": ".33T1", "probability": 0.8563232421875}], "temperature": 1.0}, {"id": 81, "seek": 182213, "start": 1801.69, "end": 1822.13, "text": "طبعا T2 بدلالة T1 الآن substitute بعوض عن T2 في المعادلة اللي هي التانية بدعوض عن T2 بدلالة T1 اذا T1 sin 37 زائد طبعا 1.33 T1 اللي طلعت ليها في sin 53 ناقص", "tokens": [9566, 3555, 3615, 995, 314, 17, 47525, 1211, 6027, 3660, 314, 16, 6024, 48506, 15802, 45030, 2407, 11242, 18871, 314, 17, 8978, 9673, 3615, 18513, 37977, 13672, 1829, 39896, 16712, 7649, 10632, 47525, 3615, 2407, 11242, 18871, 314, 17, 47525, 1211, 6027, 3660, 314, 16, 1975, 15730, 314, 16, 3343, 13435, 30767, 16373, 3215, 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"end": 1852.91, "text": "طبعا بنكمل في التسجيل القادم", "tokens": [9566, 3555, 3615, 995, 44945, 24793, 1211, 8978, 16712, 3794, 7435, 26895, 25062, 18513, 2304], "avg_logprob": -0.10455321986228228, "compression_ratio": 0.896551724137931, "no_speech_prob": 0.0, "words": [{"start": 1849.35, "end": 1849.97, "word": "طبعا", "probability": 0.986572265625}, {"start": 1849.97, "end": 1850.75, "word": " بنكمل", "probability": 0.7608235677083334}, {"start": 1850.75, "end": 1851.05, "word": " في", "probability": 0.8525390625}, {"start": 1851.05, "end": 1852.33, "word": " التسجيل", "probability": 0.9732666015625}, {"start": 1852.33, "end": 1852.91, "word": " القادم", "probability": 0.98486328125}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1853.138125, "duration_after_vad": 1829.1512499999974}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..5dad93ab8f4f6e550752aebf57ac18ddfc12dfcf
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/b9IcnD8kkDY_raw.srt
@@ -0,0 +1,1536 @@
+1
+00:00:00,440 --> 00:00:04,700
+بسم الله الرحمن الرحيم بنستكمل section أربعة خمسة
+
+2
+00:00:04,700 --> 00:00:09,840
+بعنوان attention forces attention force can be
+
+3
+00:00:09,840 --> 00:00:15,580
+exerted by attaching string or cable to an object
+
+4
+00:00:15,580 --> 00:00:22,060
+and pulling itطبعا قوة الشد كان يعني بتحدث عندما
+
+5
+00:00:22,060 --> 00:00:28,880
+طبعا بنشد أو بنسحب جسم بواسطة كابل أو حبل the
+
+6
+00:00:28,880 --> 00:00:31,700
+tension force acts along the direction of the
+
+7
+00:00:31,700 --> 00:00:36,240
+cable and exert a force both on the object and on
+
+8
+00:00:36,240 --> 00:00:41,520
+the person exerted force on the cableقوة الشد تؤثر
+
+9
+00:00:41,520 --> 00:00:48,220
+طوليا على اتجاه هذا الخيط وتؤثر هذه القوة طبعا هذه
+
+10
+00:00:48,220 --> 00:00:56,320
+القوتين على الجسم وعلى أي شخص يتعرض لقوة شد الحبل
+
+11
+00:00:56,320 --> 00:01:03,680
+كما هو موضح بهذا الشكل شكل 423لو كانت ال mass of
+
+12
+00:01:03,680 --> 00:01:08,160
+the given cable is نجلة طبعا باهمال كتلة الحبل
+
+13
+00:01:08,160 --> 00:01:13,860
+طبعا عندنا سيارة السيارة مربوطة بحبل وهذا الرجل
+
+14
+00:01:13,860 --> 00:01:19,080
+يشد هذه السيارة بحبل أو يعني قوة الشد اللي هي T لل
+
+15
+00:01:19,080 --> 00:01:27,260
+car بزاوية θالـ TC has the same magnitude and
+
+16
+00:01:27,260 --> 00:01:33,700
+tension force on the man الراجل بيشد السيارة بقوة
+
+17
+00:01:33,700 --> 00:01:41,570
+شد TC والسيارة بدورها بتشد الراجل بقوة TMفقوة شد
+
+18
+00:01:41,570 --> 00:01:46,050
+السيارة من الرجل بتساوي قوة شد السيارة للرجل يعني
+
+19
+00:01:46,050 --> 00:01:50,530
+T لل car بتساوي T ل ال man هد اسمه قوة الشد هدول
+
+20
+00:01:50,530 --> 00:01:56,050
+قوتين متساوتين في المقدار ومتعاكستين بالاتجاهلكن
+
+21
+00:01:56,050 --> 00:02:02,270
+هذا الشد له حالات الحالة حسب الوضع الشد لما يكون
+
+22
+00:02:02,270 --> 00:02:07,790
+عندي vertical tension forces on static object لو
+
+23
+00:02:07,790 --> 00:02:12,860
+كان عندي أنا جسم و بدأ أشد حركة رأسيةفي هذه الحالة
+
+24
+00:02:12,860 --> 00:02:16,840
+an object is dangling at the end of the vertical
+
+25
+00:02:16,840 --> 00:02:25,060
+string هذا الجسم مربوط بحبل رأسيا بحبل رأسيا وهذا
+
+26
+00:02:25,060 --> 00:02:30,100
+الخط اللي الجسم مربوط في أسفل الحبل the object is
+
+27
+00:02:30,100 --> 00:02:35,240
+in equilibrium الجسم بيكون في حالة اتزان معناها
+
+28
+00:02:35,240 --> 00:02:39,040
+التسارع بساوة zero ال y component of the second
+
+29
+00:02:39,040 --> 00:02:43,350
+law gives an expressionfor the tension لو كان عندي
+
+30
+00:02:43,350 --> 00:02:47,790
+أنا جسم و الجسم مربوط بخيط طبعا قوة الشد هتكون
+
+31
+00:02:47,790 --> 00:02:52,670
+لأعلى و ال MG هتكون لأسفل في عندي حالة توا اتزان
+
+32
+00:02:52,670 --> 00:02:56,950
+معنى الكلام summation لل FY بالساوية M في Ay ال T
+
+33
+00:02:56,950 --> 00:03:00,710
+ناقص MG بالساوية Zero إذا في هذه الحالة ال T
+
+34
+00:03:00,710 --> 00:03:04,870
+بالساوية MG حطينا Zero لإن ال A بتجاه ال Y Zero في
+
+35
+00:03:04,870 --> 00:03:09,180
+حالة اتزان equilibriumSo the acceleration is zero
+
+36
+00:03:09,180 --> 00:03:14,420
+اذا انت بالساوي ال Mg The tension force therefore
+
+37
+00:03:14,420 --> 00:03:17,500
+is equal to the support weight هذا الشكل اللي
+
+38
+00:03:17,500 --> 00:03:22,510
+حكينا عنه هي اندي كتلة اسمها M مربوطةفي نهاية خيط
+
+39
+00:03:22,510 --> 00:03:28,010
+مشدود رأسيا إلى أعلى فطبعا قوة الشد هطلعها من
+
+40
+00:03:28,010 --> 00:03:32,130
+الجسم لازم السهم او ال vector لأ الشد يكون خارج من
+
+41
+00:03:32,130 --> 00:03:36,830
+الجسم اللي هو ال M و ال MG طبعا خارجها اللي هي ال
+
+42
+00:03:36,830 --> 00:03:43,310
+M قوة الجاذبية الجسم في حالة اتزان اذا ال T ناقص
+
+43
+00:03:43,310 --> 00:03:46,850
+ال MG بالساوية صفر اذا ال T بالساوية MG T هذا هو
+
+44
+00:03:46,850 --> 00:03:52,790
+رمز اللي هو ال tension او الشدهذه حالة من الحالات
+
+45
+00:03:52,790 --> 00:03:55,310
+الـ tension in the string supports the block
+
+46
+00:03:55,310 --> 00:03:58,810
+weight هذه حالة من الحالات لما يكون في هذا الشكل
+
+47
+00:03:58,810 --> 00:04:03,270
+الحالة التانية case 2 vertical tension forces on
+
+48
+00:04:03,270 --> 00:04:08,970
+an accelerating object لو كان عندي أنا جسم بيتحرك
+
+49
+00:04:08,970 --> 00:04:13,970
+زي المصعد بهذا الشكل اللي انا عندي أنا جسم مربوط
+
+50
+00:04:13,970 --> 00:04:21,970
+بخيطو هذا الجسم كله بيتحرك إلى أعلى ففي عندي أنا
+
+51
+00:04:21,970 --> 00:04:26,450
+قوة الوزن MG لأسفل و الجسم كله بتحرك إلى أعلى فهنا
+
+52
+00:04:26,450 --> 00:04:29,770
+هذا السهم بيدل على أن الحركة إلى أعلى اللي هي M في
+
+53
+00:04:29,770 --> 00:04:34,390
+A هستخدم قانون نيوتن التاني لكن هذا القانون باتجاه
+
+54
+00:04:34,390 --> 00:04:39,270
+ال Y راح نحكي summation للأف Y بتساوي M في A Y
+
+55
+00:04:39,270 --> 00:04:44,390
+بنرجع ل .. اللي هو حكيه في ال .. في ال section إذا
+
+56
+00:04:44,630 --> 00:04:47,890
+in this case a string is attached to an object and
+
+57
+00:04:47,890 --> 00:04:50,910
+put under such tension that it accelerates the
+
+58
+00:04:50,910 --> 00:04:55,750
+object upward إذا في حركة إلى أعلى the tension
+
+59
+00:04:55,750 --> 00:04:59,750
+force must support the weight and provide
+
+60
+00:04:59,750 --> 00:05:03,610
+acceleration the correct expression can be derived
+
+61
+00:05:03,610 --> 00:05:07,530
+from the y component of the second law استخدمت
+
+62
+00:05:07,530 --> 00:05:12,080
+قانون نيوتن التانيوالمُركّبة الصادرية إذا
+
+63
+00:05:12,080 --> 00:05:16,120
+summation للأف واي بتساوي ال M في Ay summation
+
+64
+00:05:16,120 --> 00:05:20,220
+للأف واي كان T باتجاه الموجب إذا T موجب ناقص MG
+
+65
+00:05:20,220 --> 00:05:26,420
+سالب بدي أعيد ترتيبها هنحكي أن T بتساوي MAY زائد
+
+66
+00:05:26,420 --> 00:05:31,240
+MGالـ M مشتركة فـ T بيساوي Ay زائد الـ G هذه هي
+
+67
+00:05:31,240 --> 00:05:34,400
+برعجي هي تسارع الجاذبية والـ A هي التسارع اللي
+
+68
+00:05:34,400 --> 00:05:39,500
+بتحرك فيها الجسم المربوط بخيط حركة رأسيا إلى أعلى
+
+69
+00:05:41,480 --> 00:05:45,400
+accelerating upward increases the tension whereas
+
+70
+00:05:45,400 --> 00:05:50,520
+accelerating downward decreases the tension طبعا
+
+71
+00:05:50,520 --> 00:05:55,460
+هي يعني ملاحظة أنه تسارع لما يكون في عندي تسارع
+
+72
+00:05:55,460 --> 00:05:59,560
+الجسم إلى أعلى بيعمل على زيادة ال tension لإن ال a
+
+73
+00:05:59,560 --> 00:06:03,520
+y بزاد ال g لكن لما يكون التسارع إلى أسفل بيعمل
+
+74
+00:06:03,520 --> 00:06:08,450
+decreasing the tensionفي الشكل هذا شكل A block
+
+75
+00:06:08,450 --> 00:06:13,170
+hung by string in an elevator accelerating upward
+
+76
+00:06:13,170 --> 00:06:18,250
+block hung by string في عندي أنا جسم مربوط في ال
+
+77
+00:06:18,250 --> 00:06:21,930
+elevator هذا المصعد و المصعد بيصعد إلى أعلى نفس
+
+78
+00:06:21,930 --> 00:06:27,480
+الشكل T ناقص MG تساوي MAفي B هنا الـ free body
+
+79
+00:06:27,480 --> 00:06:32,620
+diagram هاي هو الشد إلى أعلى والشد إلى أعلى the
+
+80
+00:06:32,620 --> 00:06:36,200
+tension supply the acceleration of the block while
+
+81
+00:06:36,200 --> 00:06:42,140
+supporting it against gravity الشد إلى أعلى و ال M
+
+82
+00:06:42,140 --> 00:06:46,920
+A إلى أعلى هذه موجة بموجة و ال M G إلى أسفل هي قوة
+
+83
+00:06:46,920 --> 00:06:52,760
+طبعا ال M G إلى أسفل وبالتالي الجسم بشدأيضا فيها
+
+84
+00:06:52,760 --> 00:06:56,700
+نقوتين MG و هنا فيه بالنسبة لأش لل .. لل .. فيها
+
+85
+00:06:56,700 --> 00:07:02,060
+نقوة اللي هي الجاذبية هذا الحبل إذا كان هنا طبعا
+
+86
+00:07:02,060 --> 00:07:05,380
+في عندي حبل لكن هنا فيش عندي حبل في عندي أنا وزن
+
+87
+00:07:05,380 --> 00:07:08,880
+الجاذبية اللي أسفل وبالتالي ال vector بيساوي ناقص
+
+88
+00:07:08,880 --> 00:07:09,420
+MG
+
+89
+00:07:12,420 --> 00:07:17,560
+ال case التالتة ال two tension forces at symmetric
+
+90
+00:07:17,560 --> 00:07:25,020
+angles لو كان عندي أنا شدين قوتين للشد بوضع متمثل
+
+91
+00:07:25,020 --> 00:07:29,200
+زوايا معينة in this case لو كان عندي أنا هنا حبل و
+
+92
+00:07:29,200 --> 00:07:36,400
+هنا حبل مربوطين مربوطين بجسم ثابت و هذا الحبل بميل
+
+93
+00:07:36,400 --> 00:07:40,860
+بزاوية ثيتا و هذا الحبل بميل بزاوية ثيتا زاويتين
+
+94
+00:07:40,860 --> 00:07:43,950
+متساوتينin this case the tension will be equal في
+
+95
+00:07:43,950 --> 00:07:46,990
+هذه الحالة أن الشد هذا بساوي هذا الشد ال y
+
+96
+00:07:46,990 --> 00:07:50,890
+component of each tension اللي هي T cosine الزاوية
+
+97
+00:07:50,890 --> 00:07:54,130
+في عندي هنا ال M اللي هو الوزن هنا برسم ل فيديو
+
+98
+00:07:54,130 --> 00:07:57,830
+بيه free body diagram في عندي هنا قوة الوزن إلى
+
+99
+00:07:57,830 --> 00:08:04,460
+أسفل MG و هنا في عندي شدT و هنا T شد المتساوية
+
+100
+00:08:04,460 --> 00:08:09,700
+لإنه زاوية متساوية هنا راح أحلل الشد إلى T sin
+
+101
+00:08:09,700 --> 00:08:13,220
+الزاوية أو هنا في اتجاه الرأس T cosine و هنا راح
+
+102
+00:08:13,220 --> 00:08:18,380
+أحلل T sine و هنا T cosine فبصير عندي أنا مجموعة T
+
+103
+00:08:18,380 --> 00:08:22,460
+cosine بده يساوي ال MG لإنه T sine لإنه فيه
+
+104
+00:08:22,460 --> 00:08:26,950
+symmetric تماثل للزواياف T sine ال right بتساوي T
+
+105
+00:08:26,950 --> 00:08:30,290
+sine ال left ف cancel they are cancel أو بيلغوا
+
+106
+00:08:30,290 --> 00:08:35,290
+بعض فبالتالي بيضال عندي انه ال MG بدها تساوي
+
+107
+00:08:35,290 --> 00:08:42,030
+summation ال MG بدها تساوي اللي هو ال MA ال MAY
+
+108
+00:08:42,030 --> 00:08:45,970
+بدها تساوي T cosine θ زائد T cosine θ ناقص ال MG
+
+109
+00:08:45,970 --> 00:08:52,230
+اذا الحركة هو في حالة اتزان ف2T cosine بدها تساوي
+
+110
+00:08:52,230 --> 00:08:57,170
+ال MG اوأتنين T Cos ناقص ال MG بيساوي Zero إذا ال
+
+111
+00:08:57,170 --> 00:09:03,650
+T Cos بدها تساوي ال MG بدها تساوي اتنين T Cos ثيتا
+
+112
+00:09:03,650 --> 00:09:06,970
+إذا ال T بدها تساوي ال MG على اتنين Cos ثيتا في
+
+113
+00:09:06,970 --> 00:09:12,970
+هذه الحالة لو كان عندي أنا الخيط خيطين مربوطين
+
+114
+00:09:12,970 --> 00:09:19,930
+بزوايا متساوية بسميها في حالة اللي هي symmetric
+
+115
+00:09:19,930 --> 00:09:23,890
+tensionWhether the expression involves sine or
+
+116
+00:09:23,890 --> 00:09:26,970
+cosine depends on what angle are given in the
+
+117
+00:09:26,970 --> 00:09:30,310
+problems طبعا هذه الحالة احنا خدنا cosine عساس انه
+
+118
+00:09:30,310 --> 00:09:34,990
+اعتبرنا انه الزاوية بين الحبل و ال vertical هي ال
+
+119
+00:09:34,990 --> 00:09:39,490
+theta فلما احلل ف T sine هي ال cancel و T cosine
+
+120
+00:09:39,490 --> 00:09:43,070
+بتظلها سماشة لأ T cosine لإنه انا عندي حبلين
+
+121
+00:09:43,070 --> 00:09:47,470
+فبتكون عندي اتنين cosine ال thetaالحكيس ال cases
+
+122
+00:09:47,470 --> 00:09:52,990
+for الحالة الرابعة ال tensions at non-equal angles
+
+123
+00:09:52,990 --> 00:09:56,950
+لو كان عندي tension في بزوايا مختلفة there are
+
+124
+00:09:56,950 --> 00:10:01,030
+many contexts in which two tensions may acts at
+
+125
+00:10:01,030 --> 00:10:05,230
+non-equal angles and the context in the figures is
+
+126
+00:10:05,230 --> 00:10:10,960
+one example في الشكل أربعة سبعة وعشرين كexampleلو
+
+127
+00:10:10,960 --> 00:10:14,300
+كان عندي أنا جسم و هارسمله الـ free body diagram
+
+128
+00:10:14,300 --> 00:10:21,300
+اللي هي الجسم، الجسم شديته بزاوية فيتا وهذا الجسم
+
+129
+00:10:21,300 --> 00:10:27,020
+موجود على اللي هي ال X-axis في هذه الحالة و عندي
+
+130
+00:10:27,020 --> 00:10:31,160
+حبل و عندي هنحبل، الحبلين الحبل بال X-axis و الحبل
+
+131
+00:10:31,160 --> 00:10:37,570
+تاني مشدود بزاوية فيتاو T1 و T2 مجهولين هذه الرسمة
+
+132
+00:10:37,570 --> 00:10:45,090
+بتمثل ال T اللي هي بتمثل ال free body diagram يعني
+
+133
+00:10:45,090 --> 00:10:49,090
+في عندي نشد طالع من الحبل هذا طالع من الكتلة بسبب
+
+134
+00:10:49,090 --> 00:10:54,560
+الحبل هذاوفي شد مائل بزاوية ثيتا اسمه T2 هنسمي هذا
+
+135
+00:10:54,560 --> 00:10:59,480
+T1 نسمي هذا T2 وهي ال MG طبعا هذا T2 مائل بزاوية
+
+136
+00:10:59,480 --> 00:11:03,900
+ثيتا إذا بدنا نحلل بدأ أحلل بال X Axis هيكون T2
+
+137
+00:11:03,900 --> 00:11:08,700
+Sin ثيتا و بال Y Axis T2 Cos اللي جانب الزاوية أنا
+
+138
+00:11:08,700 --> 00:11:14,580
+بحللها لأ Cos اللي أول عمودية بتكون Sinالـ block
+
+139
+00:11:14,580 --> 00:11:19,260
+held by two strings الجسم مربوط بحبلين ورسمنا الـ
+
+140
+00:11:19,260 --> 00:11:22,620
+free body diagram because the given angle θ is
+
+141
+00:11:22,620 --> 00:11:25,520
+with respect to the vertical زي ما حكينا أن θ
+
+142
+00:11:25,520 --> 00:11:29,940
+بالنسبة للvertical الرأسي the adjacent side of the
+
+143
+00:11:29,940 --> 00:11:33,840
+triangle formed by the vector T2 corresponding to
+
+144
+00:11:33,840 --> 00:11:38,190
+the Y directionrequire a cosine function اذا حطيت
+
+145
+00:11:38,190 --> 00:11:42,530
+انا اللي جنب ال vector اللي هي بين الحبل و بين ال
+
+146
+00:11:42,530 --> 00:11:47,530
+.. اللي هي ال vertical line هي بتسميها T cosine و
+
+147
+00:11:47,530 --> 00:11:51,590
+العمودية بتكون T sine with a y بيساوي zero يعني في
+
+148
+00:11:51,590 --> 00:11:55,190
+حالة اتزان the y component of the second law بدأ
+
+149
+00:11:55,190 --> 00:12:00,940
+اطبق قانون نيوتنالتانى summation لل Fy بتساوي ال M
+
+150
+00:12:00,940 --> 00:12:07,040
+في Ay ال Ay فرضناها Zero ف summation لل Fy ال MG
+
+151
+00:12:07,040 --> 00:12:13,820
+سالبة و ال T Cos موجبة فببقى عندي أنا MG سالب ناقص
+
+152
+00:12:13,820 --> 00:12:22,070
+زائد T2 Cos Thetaوفي عندى .. في عندى T1 بدها تساوي
+
+153
+00:12:22,070 --> 00:12:28,210
+T2 sin θ إذا بالنسبة لـ T2 which can easily be
+
+154
+00:12:28,210 --> 00:12:32,690
+solved for the tension T2 T2 بدها تساوي MG على
+
+155
+00:12:32,690 --> 00:12:37,700
+cosine θمرة تانية الـ given angle is with respect
+
+156
+00:12:37,700 --> 00:12:41,620
+to the vertical so the opposite side of the
+
+157
+00:12:41,620 --> 00:12:46,340
+triangle formed by the vector T2 corresponds to
+
+158
+00:12:46,340 --> 00:12:51,020
+the X direction المركبة التانية لأ T2 بالنسبة لأ
+
+159
+00:12:51,020 --> 00:12:55,860
+ال X axis هي عبارة عن T2 sin الزاوية لما أتي أطبق
+
+160
+00:12:55,860 --> 00:13:01,700
+أنا قانون النيوتن التاني على ال X axis بيكون Max
+
+161
+00:13:01,700 --> 00:13:07,810
+بدها تساوي summation لل Fxلأ في X في عندي T1 minus
+
+162
+00:13:07,810 --> 00:13:12,770
+لإنها رايحة باتجاه اللي هي ال X السالب زائد T2 sin
+
+163
+00:13:12,770 --> 00:13:18,290
+θ اللي مع ال X الموجب موجب و اللي X سالب سالب و من
+
+164
+00:13:18,290 --> 00:13:25,230
+خلال هذا طبعا نعوض عن T2 نعوض عن T2 ب MG على
+
+165
+00:13:25,230 --> 00:13:34,430
+cosine θ إذا T1بتساوي T2 sin θ T2 مج على cos θ sin
+
+166
+00:13:34,430 --> 00:13:40,670
+θ اذا طبعا sin على cosine بتطلع ل tan بتطلع T1
+
+167
+00:13:40,670 --> 00:13:43,390
+بتساوي mg tan θ
+
+168
+00:13:48,850 --> 00:13:52,510
+هذا طبعا بيوضع how to determine this illustrates
+
+169
+00:13:52,510 --> 00:13:56,150
+how to determine tension when two such tension are
+
+170
+00:13:56,150 --> 00:13:59,490
+involved in supporting an object using the two
+
+171
+00:13:59,490 --> 00:14:02,630
+components of the second law write two equations
+
+172
+00:14:02,630 --> 00:14:05,310
+and then solve for the two unknowns لو كان عندى
+
+173
+00:14:05,310 --> 00:14:08,730
+انا زى ما حلنا ان في عندى two tension حابلين
+
+174
+00:14:08,730 --> 00:14:15,450
+الحابلين بزاوية طبعا معينة ممكن اجيب انا الشدT1
+
+175
+00:14:15,450 --> 00:14:21,110
+وT2 من خلال تحليل هذا الشد إلى مراكبتين السينية
+
+176
+00:14:21,110 --> 00:14:24,950
+والصادية وانعوض فيه اللي هو قانون نيوتن التاني
+
+177
+00:14:24,950 --> 00:14:29,770
+summation للـFx وSummation للـFy وبنرسم الـfree
+
+178
+00:14:29,770 --> 00:14:32,730
+body diagram باتجاه الـX وfree body diagram باتجاه
+
+179
+00:14:32,730 --> 00:14:37,550
+الـY وبنعمل معادلتين لإيجاد اللي هو المجهولين اللي
+
+180
+00:14:37,550 --> 00:14:43,760
+هو TT1 وT2 كالسابق في section 4.6 application of
+
+181
+00:14:43,760 --> 00:14:48,900
+Newton's law يعني كتطبيق لقانون وقوانين نيوتن when
+
+182
+00:14:48,900 --> 00:14:53,020
+we apply Newton's law to an object we are
+
+183
+00:14:53,020 --> 00:14:57,600
+interested only in those forces that act on the
+
+184
+00:14:57,600 --> 00:15:02,160
+object for example لما بدى أنا أطبق قوانين نيوتن
+
+185
+00:15:02,160 --> 00:15:07,570
+لازم أنا أبحث عن قوة مؤثرة على الجسمهذا الشكل
+
+186
+00:15:07,570 --> 00:15:13,530
+figure 412B the only external force acting on the
+
+187
+00:15:13,530 --> 00:15:18,910
+monitor are N and FG بلاحظ أنه هذا monitor ال
+
+188
+00:15:18,910 --> 00:15:21,250
+monitor ضغط على الطاولة اللي بأثر عليه اللي هو في
+
+189
+00:15:21,250 --> 00:15:24,790
+عندي normal قوة رد الفعل العمودية إلى أعلى وفي
+
+190
+00:15:24,790 --> 00:15:31,850
+عندي قوة الوزن ال FG إلى أسفلكمان يعني هذا ال
+
+191
+00:15:31,850 --> 00:15:36,270
+monitor بيأثر على الطاولة ب FG والطاولة بتأثر على
+
+192
+00:15:36,270 --> 00:15:40,690
+ال monitor ب FG شرطة اللي هنا في عندي قوة رد الفعل
+
+193
+00:15:40,690 --> 00:15:44,910
+الان و هي القوة التانية اللي هي اللي .. اللي طبعا
+
+194
+00:15:44,910 --> 00:15:48,710
+لازم يكون في قوتين قوتين مؤثرين على هذا ال .. هذه
+
+195
+00:15:48,710 --> 00:15:54,100
+النقطةاللي هي N شرط N و N شرطة عكس بعض فلما بداجي
+
+196
+00:15:54,100 --> 00:15:57,280
+أرسم أنا لـfree body diagram في عندي أنا الـnormal
+
+197
+00:15:57,280 --> 00:16:03,000
+الأعلى و الـFG الأسفل لأنه احنا ما بنحسبها بالعين
+
+198
+00:16:03,000 --> 00:16:08,260
+الاعتبار اللي هي أن الـN شرطة و الـFG شرطة هدولة
+
+199
+00:16:08,260 --> 00:16:14,030
+طبعا بيبلغوا بعض بهذا الشكلبأفرض create being
+
+200
+00:16:14,030 --> 00:16:17,590
+pulled to the right to the right on a frictionless
+
+201
+00:16:17,590 --> 00:16:21,690
+horizontal surface suppose you wish to find the
+
+202
+00:16:21,690 --> 00:16:24,650
+acceleration of the crate and the force the
+
+203
+00:16:24,650 --> 00:16:28,070
+surface exerted on it the magnitude of T is equal
+
+204
+00:16:28,070 --> 00:16:31,350
+to the tension in the rope بأفرض في عندي عربة
+
+205
+00:16:31,350 --> 00:16:35,790
+والعربة بدي أشدها إلى اليمين على سطح أملس
+
+206
+00:16:35,790 --> 00:16:39,750
+frictionless والسطح طبعا أفقي أملس بيسمو
+
+207
+00:16:39,750 --> 00:16:43,300
+frictionless horizontal surfaceده أفرض أنه أنا
+
+208
+00:16:43,300 --> 00:16:49,520
+شدتها بتسارع معين و بقوة معينة مؤثرة على هذا الجسم
+
+209
+00:16:49,520 --> 00:16:53,440
+قوة الشد طبعا المؤثرة على هذا الجسم أنا شدت هذه
+
+210
+00:16:53,440 --> 00:16:58,660
+العربة على سطح frictionless إلى اليمينطبعا هذه قوة
+
+211
+00:16:58,660 --> 00:17:03,300
+الشد بنسميها T بدا أرسم ال free body diagram طبعا
+
+212
+00:17:03,300 --> 00:17:06,900
+العربة على الأرض هيها بهذا الممثل العربة ال free
+
+213
+00:17:06,900 --> 00:17:09,800
+body diagram في عندي أنا قوة ردفع العمودية إلى
+
+214
+00:17:09,800 --> 00:17:13,400
+أعلى و في عندي قوة وزن اللي هي ال FG إلى أسفل و في
+
+215
+00:17:13,400 --> 00:17:19,660
+عندي اللي هو ال tension قوة الشد إلى اليمين هذا هو
+
+216
+00:17:19,660 --> 00:17:23,570
+ال free body diagramلما بدى انا اكتب معادلات
+
+217
+00:17:23,570 --> 00:17:28,830
+معادلات اللى هى القانونية التانية ممكن احنا اذا
+
+218
+00:17:28,830 --> 00:17:32,730
+كانت الحركة باتجاه ال .. ال .. ال right او تجاه
+
+219
+00:17:32,730 --> 00:17:36,670
+الشرق راح نحكى انه some motion لبقى في X بتساول ام
+
+220
+00:17:36,670 --> 00:17:40,070
+في مين القوة اللى في اتجاه ال X هي T اذا because
+
+221
+00:17:40,070 --> 00:17:42,790
+we are interested only in the tension of the crate
+
+222
+00:17:42,790 --> 00:17:46,460
+مافيش عندى قوة الا الشدوانا بتحرك في تجاه ال X
+
+223
+00:17:46,460 --> 00:17:51,680
+-Axis بتسارع معين نحن يجب أن نكون قادرين على
+
+224
+00:17:51,680 --> 00:17:59,260
+اكتشاف جميع القوات اللي مؤثرة على هذا الجسم لما
+
+225
+00:17:59,260 --> 00:18:02,020
+أرسم ال free body diagram زي ما هو موضح بالشكل
+
+226
+00:18:02,020 --> 00:18:07,320
+figure 429B هاي هو ال free body diagram المؤثرة
+
+227
+00:18:07,320 --> 00:18:14,000
+عليها باتجاه ال X-Axis هي ال Tإذن الـ Force T، الـ
+
+228
+00:18:14,000 --> 00:18:16,500
+Free Body Diagram for the crate اللي including a
+
+229
+00:18:16,500 --> 00:18:19,400
+force of gravity F exerted by earth and the normal
+
+230
+00:18:19,400 --> 00:18:22,720
+force N exerted by the floor الـ Normal Force
+
+231
+00:18:22,720 --> 00:18:26,720
+مؤثرة من الأرض على الـ body أو الـ crate أو العربة
+
+232
+00:18:26,720 --> 00:18:31,160
+وقوة الجاذبية مؤثرة طبعا تأثير قوة جاذبية الأرض
+
+233
+00:18:31,160 --> 00:18:38,770
+لهدأ الجسمالتجارب التي لدينا لسه لسه لسه ليست
+
+234
+00:18:38,770 --> 00:18:41,590
+مضمونة في البرنامج الانفجاري لأنهم يدفعوا على
+
+235
+00:18:41,590 --> 00:18:47,510
+مجموعات أخرى وليس على الـ CreateNow let's apply
+
+236
+00:18:47,510 --> 00:18:51,110
+Newton's second law to the crate first. We choose
+
+237
+00:18:51,110 --> 00:18:55,130
+an appropriate coordinate system in this case it's
+
+238
+00:18:55,130 --> 00:18:59,130
+convenient to use the one shown in the figure with
+
+239
+00:18:59,130 --> 00:19:03,230
+the x-axis horizontal and the y-axis vertical we
+
+240
+00:19:03,230 --> 00:19:06,330
+can apply Newton's second law زي ما حكينا أنهبدي
+
+241
+00:19:06,330 --> 00:19:11,190
+انا اطبق قوانين نيوتن التاني لاللي هي القوة اللي
+
+242
+00:19:11,190 --> 00:19:13,950
+هو summation لل Fy بتساوي ال M في Ay و summation
+
+243
+00:19:13,950 --> 00:19:20,550
+لل Fx بتساوي ال M في Ax بتعتمد طبعا depending on
+
+244
+00:19:20,550 --> 00:19:25,650
+the X and Y اللي هي direction وكمان بتعتمد على انه
+
+245
+00:19:25,650 --> 00:19:30,420
+وين الجسم هو بتتحركأذا في عندي أنا صمشة لل Fx
+
+246
+00:19:30,420 --> 00:19:34,120
+بتساوي ال M في AX Fx باللي هي بارع عن T بتساوي ال
+
+247
+00:19:34,120 --> 00:19:37,480
+M في AX بالنسبة لل Fy عندي أنا ال normal اللي أعلى
+
+248
+00:19:37,480 --> 00:19:40,380
+موجة بناقص ال MG بتساوي ال M في AY طبعا هذه مافيش
+
+249
+00:19:40,380 --> 00:19:44,520
+حركة بتجاه ال Y بتساوي Zero from this situation من
+
+250
+00:19:44,520 --> 00:19:49,790
+هذه المعادلات we find that the accelerationالتسارع
+
+251
+00:19:49,790 --> 00:19:54,730
+بتجاه ال X axis is constant فإذا ال AX بتساوي T
+
+252
+00:19:54,730 --> 00:19:59,490
+على M فده الحالة و ال normal بتساوي ال MG because
+
+253
+00:19:59,490 --> 00:20:03,810
+the acceleration is constant لإنه التسارع ثابت
+
+254
+00:20:03,810 --> 00:20:08,050
+فمعادلة المعادلة ال kinematic can be applied to
+
+255
+00:20:08,050 --> 00:20:13,190
+obtain further information about the velocity and
+
+256
+00:20:13,190 --> 00:20:18,760
+displacement of the object لإنه التسارعهنا موجود
+
+257
+00:20:18,760 --> 00:20:23,040
+باتجاه ال X-axis فحكينا ان ال AX بتساوي T على M
+
+258
+00:20:23,040 --> 00:20:27,020
+فىش تسارع بتجاه ال Y اذا فىش تسارع ولكن فى تسارع
+
+259
+00:20:27,020 --> 00:20:32,620
+جد بيه اذا ال normal بتساوي ال MGهنا بيحكينا إنه
+
+260
+00:20:32,620 --> 00:20:35,340
+كيف أنا ممكن أحل المسائل و كيف أعمل معادلات
+
+261
+00:20:35,340 --> 00:20:39,540
+problem solving strategy قانون نيوتن التاني
+
+262
+00:20:39,540 --> 00:20:43,480
+problem involving Newton's second law can be very
+
+263
+00:20:43,480 --> 00:20:47,620
+complex the following protocol بروتوكولات يعني هي
+
+264
+00:20:47,620 --> 00:20:55,180
+تعليمات لحل هذه المعادلات بطريقة سهلةلتحقيق الهداف
+
+265
+00:20:55,180 --> 00:20:59,860
+أول حاجة بدك تقرأ السؤال طبعا بإناية بعدين بدي
+
+266
+00:20:59,860 --> 00:21:04,140
+أرسم picture بدي أرسم السؤال كيعني رسم بعدين ممكن
+
+267
+00:21:04,140 --> 00:21:08,020
+أرسم ال free body diagram و أحط ال label عليه يعني
+
+268
+00:21:08,020 --> 00:21:11,940
+المعطيات الموجودة عندي ا draw a free body diagram
+
+269
+00:21:11,940 --> 00:21:15,600
+من خلال ال free body diagram يعني و رسم تخطيط اللي
+
+270
+00:21:15,600 --> 00:21:17,280
+هيجيه القوة المؤثرة على الجسم
+
+271
+00:21:24,070 --> 00:21:30,230
+لو كان عندي قوة بتجاه X أو Y ممكن ارسم في البرنامج
+
+272
+00:21:30,230 --> 00:21:34,650
+الاخر مرة بال X و مرة بالYبأطبق قانون نوتن التاني
+
+273
+00:21:34,650 --> 00:21:38,330
+ممكن أطبقه مرة على ال X-axis ومرة على ال Y-axis
+
+274
+00:21:38,330 --> 00:21:41,470
+وعشان نستطيع أن الحل هذا ي solve the desired
+
+275
+00:21:41,470 --> 00:21:45,530
+unknown quantity ممكن أحل المسألة وإيجاد المتغيرات
+
+276
+00:21:45,530 --> 00:21:49,010
+الموجودة في السؤال in the special case of
+
+277
+00:21:49,010 --> 00:21:53,130
+equilibrium في حالة يحكي للسؤال أن الجسم في حالة
+
+278
+00:21:53,130 --> 00:21:56,310
+equilibrium معنى الكلام أن ال acceleration بدها
+
+279
+00:21:56,310 --> 00:21:59,720
+تساوي zeroمعنى كلها أن الـ acceleration بالساوية 0
+
+280
+00:21:59,720 --> 00:22:04,320
+و بأستطيع أن أحل السؤال بإيجاد المتغيرات الموجودة
+
+281
+00:22:04,320 --> 00:22:08,220
+بوجود أن التسارع بالساوية G0 يعني summation لل Fx
+
+282
+00:22:08,220 --> 00:22:11,740
+بالساوية 0 و summation لل Fy بالساوية 0 إذا حكى أن
+
+283
+00:22:11,740 --> 00:22:16,320
+الجسم في حالة equilibriumفي حالة الـ equilibrium
+
+284
+00:22:16,320 --> 00:22:19,660
+الـ object in equilibrium زي ما حكينا سابقا ال
+
+285
+00:22:19,660 --> 00:22:22,540
+object that are either at rest or moving with
+
+286
+00:22:22,540 --> 00:22:26,900
+constant velocity is said to be equilibrium يعني
+
+287
+00:22:26,900 --> 00:22:30,160
+مش شرط أنه الجسم ساكن ممكن الجسم يكون يتحرك ب
+
+288
+00:22:30,160 --> 00:22:35,340
+constant velocity في هذه الحالة الجسم يعتبر بتحرك
+
+289
+00:22:35,340 --> 00:22:40,590
+بتسارع بساوي zero وهو يعتبر في حالة اتزانالـ
+
+290
+00:22:40,590 --> 00:22:42,890
+Newton's second law applied to an object بقى أطبق
+
+291
+00:22:42,890 --> 00:22:47,310
+قانون نيوتن التاني في حالة الإتزان فالـ Fy .. ال F
+
+292
+00:22:47,310 --> 00:22:50,950
+سماشي للـ F سواء Zero سواء Fy أو .. أو .. أو Fx
+
+293
+00:22:50,950 --> 00:22:55,130
+for two dimensional problems سواء كان بالاتجاه ال
+
+294
+00:22:55,130 --> 00:23:00,730
+X أو Y plane المعادلة 4.19 بقى ممكن أطبقها سماشي
+
+295
+00:23:00,730 --> 00:23:04,110
+للـ Fx بسوء Zero سماشي للـ Fy بسوء Zero لإنه هذه
+
+296
+00:23:04,110 --> 00:23:07,710
+متجهة ال vectors ممثلة ممكن تكون X Y Z لكن احنا
+
+297
+00:23:07,710 --> 00:23:12,480
+بنشغل على مستوى X وYهتكون summation ل Fx تساوي 0 و
+
+298
+00:23:12,480 --> 00:23:18,380
+summation ل Fy تساوي 0 ناخد هذا ال quiz أربعة
+
+299
+00:23:18,380 --> 00:23:22,620
+تمانية consider the two situations show in the
+
+300
+00:23:22,620 --> 00:23:27,520
+figure 4.3 in which there is no accelerationin
+
+301
+00:23:27,520 --> 00:23:30,580
+both cases the main ball with the force of
+
+302
+00:23:30,580 --> 00:23:37,700
+magnitude F is reading on the scale in part I of
+
+303
+00:23:37,700 --> 00:23:44,400
+the figure A greater than or B less than Nimra C
+
+304
+00:23:44,400 --> 00:23:51,300
+equal to the reading in part in partin part طبعا
+
+305
+00:23:51,300 --> 00:23:57,360
+ال three هنا في عندي أنا جسم او شخص بيشد skill
+
+306
+00:23:57,360 --> 00:24:02,160
+reading يعني زي زمبرك او عليا زي الها مقياس معين
+
+307
+00:24:02,160 --> 00:24:05,920
+consider the two situation في عندي حالتين لل skill
+
+308
+00:24:05,920 --> 00:24:09,200
+reading which there is no acceleration طبعا في
+
+309
+00:24:09,200 --> 00:24:14,040
+حالة اتزان in both cases the main pole with force
+
+310
+00:24:14,040 --> 00:24:20,430
+of magnitude Fيعني عندنا هنا ال .. هنا الجسم الرجل
+
+311
+00:24:20,430 --> 00:24:25,230
+بشد skill reading بقوة F طبعا هذا ال skill reading
+
+312
+00:24:25,230 --> 00:24:28,630
+بيقيص ال F الآن هنا في عندي skill reading في عندي
+
+313
+00:24:28,630 --> 00:24:35,610
+أنا جسمين أو رجلين بشده بالنسبة للسؤال بيحكيلي is
+
+314
+00:24:35,610 --> 00:24:41,030
+the reading on the scale in part Iin part I of the
+
+315
+00:24:41,030 --> 00:24:45,010
+figure greater than او less than او equal to the
+
+316
+00:24:45,010 --> 00:24:48,670
+reading in part 2 هل scale reading لنقطة لل part
+
+317
+00:24:48,670 --> 00:24:55,480
+oneA is أكبر أو أقل أو بيساوي ال scale reading ل
+
+318
+00:24:55,480 --> 00:24:59,540
+ال part هذا part one هذا part two هل ال scale
+
+319
+00:24:59,540 --> 00:25:04,000
+reading لهذا بيساوي هذا ولا أكبر منه ولا أقل منه
+
+320
+00:25:04,000 --> 00:25:06,960
+طبعا هنا لكل فعل رد فعل مساوئلها في المقدار
+
+321
+00:25:06,960 --> 00:25:10,860
+المتعكس بالاتجاه فهذه ال F بتساوي ال F إذا القوة
+
+322
+00:25:10,860 --> 00:25:17,220
+هي متساوية هذا قانونية التالت لكل فعل رد فعلإنه
+
+323
+00:25:17,220 --> 00:25:21,040
+إذا هذا بشد بقوة F هذا بشد بنفس القوة F برضه هذا
+
+324
+00:25:21,040 --> 00:25:26,320
+ال F هذا بشد بقوة F هذا قوته F إحنا ما بنجمع هدول
+
+325
+00:25:26,320 --> 00:25:28,860
+قوتين متساوتين في المقدار متعاكستين بالاتجاه
+
+326
+00:25:28,860 --> 00:25:34,080
+وبالتالي ال part one ال F لل part one تساوي ال F ل
+
+327
+00:25:34,080 --> 00:25:38,080
+ال tension in each chord is F which is reading the
+
+328
+00:25:38,080 --> 00:25:42,370
+scale the samethe scale reading is the same لإنه
+
+329
+00:25:42,370 --> 00:25:46,630
+جميع القوة هي F F F يعني باجمعش هذه F زائد F لإن
+
+330
+00:25:46,630 --> 00:25:49,590
+هدول القوتين متساوتين في المقدار متعاكسة بالاتجاه
+
+331
+00:25:49,590 --> 00:25:55,050
+كقيمة ك magnitude ال F لل part one بساوي ال F في
+
+332
+00:25:55,050 --> 00:26:00,290
+هذا الشكل ناخد
+
+333
+00:26:00,290 --> 00:26:07,750
+سؤالproblem طبعا example أربعة سبعة أن problems
+
+334
+00:26:07,750 --> 00:26:11,690
+traffic light weighting طبعا واحد في عشر أقصى
+
+335
+00:26:11,690 --> 00:26:15,870
+اتنين نيوتين hang from a vertical cable tied to
+
+336
+00:26:15,870 --> 00:26:19,030
+two other cables that are fastened to support
+
+337
+00:26:19,600 --> 00:26:25,520
+الشبكة تعمل تجارب 37 درجة أو 53 درجة مع اتجارات
+
+338
+00:26:25,520 --> 00:26:28,180
+عالية في كل حبل تعمل تجارب 37 درجة أو 53 درجة مع
+
+339
+00:26:28,180 --> 00:26:30,440
+اتجارات عالية في كل حبل تعمل تجارب 37 درجة أو 53
+
+340
+00:26:30,440 --> 00:26:32,860
+درجة مع اتجارات عالية في كل حبل تعمل تجارب 37 درجة
+
+341
+00:26:32,860 --> 00:26:33,960
+أو 53 درجة مع اتجارات عالية في كل حبل تعمل تجارب
+
+342
+00:26:33,960 --> 00:26:37,160
+37 درجة أو 53 درجة مع اتجارات عالية في كل حبل تعمل
+
+343
+00:26:37,160 --> 00:26:37,260
+تجارب 37 درجة أو 53 درجة مع اتجارات عالية في كل
+
+344
+00:26:37,260 --> 00:26:37,440
+حبل تعمل تجارب 37 درجة أو 53 درجة مع اتجارات عالية
+
+345
+00:26:37,440 --> 00:26:45,860
+في كل حبل تعمل تجارب 37 درجة أو 53 درجةلأن في
+
+346
+00:26:45,860 --> 00:26:51,540
+عندنا نقطة نقطة رابط ف T1 لا تساوي T2 إذا T2 ميلة
+
+347
+00:26:51,540 --> 00:26:58,380
+بزاوية 53 و T1 ميلة بزاوية 37 مطلوب أوجد الشد في
+
+348
+00:26:58,380 --> 00:27:03,260
+T1 و T2 و T3 طبعا لما أجي أرسم أنا ال free body
+
+349
+00:27:03,260 --> 00:27:06,320
+diagram بهذا الشكل بدي أرسم ال free body diagram
+
+350
+00:27:06,320 --> 00:27:13,160
+رسم تخطيتي أول حاجة T2 بدي أحللها إلى قوتينهنا T2
+
+351
+00:27:13,160 --> 00:27:22,800
+T2 هنا هنا sign و هنا T2 cos 53 و هنا T1 sin 37 و
+
+352
+00:27:22,800 --> 00:27:30,980
+T1 cos 37 و في تحت اللي هو T3 و الوزن T3 و قوة
+
+353
+00:27:30,980 --> 00:27:37,450
+الوزن قوة الوزن و في هناT3 بهذا الشكل في البداية
+
+354
+00:27:37,450 --> 00:27:43,370
+طبعا بدي اروح لمين الحل بدي اوجد T3 من الشكل بلاحظ
+
+355
+00:27:43,370 --> 00:27:48,370
+انه انه summation لل FY بساوة 0 فT3 نقص ال FG
+
+356
+00:27:48,370 --> 00:27:52,510
+بساوة 0 اذا T3 بساوة ال FG اللي هي 1 في 10 عقل 2
+
+357
+00:27:52,510 --> 00:27:58,570
+نيوتن T3الان بدى استخدم عندى انا resolve all three
+
+358
+00:27:58,570 --> 00:28:03,370
+tension forces into a component بدى احلل اللى هى
+
+359
+00:28:03,370 --> 00:28:08,490
+عندى تلاتة tension T1, T2, T3 بدى افسر هذه اللى هى
+
+360
+00:28:08,490 --> 00:28:14,550
+قوة الشد الى مراكباتها الصينية والصادية فT1 هتكون
+
+361
+00:28:14,550 --> 00:28:20,110
+ناقص T1 بالنسبة لمركبة الصينية ناقص T1 كزين 37
+
+362
+00:28:20,110 --> 00:28:25,600
+مراكبة الصادية T1 صين 37مُركّب الصينية لـ T2 T2
+
+363
+00:28:25,600 --> 00:28:31,080
+Cos 53 لأنها تتجه إلى اليمين أو الشرق، هنا متجه
+
+364
+00:28:31,080 --> 00:28:38,220
+إلى اليسار T2 بالنسبة للـ Y Axis T2 Sin 53 بالنسبة
+
+365
+00:28:38,220 --> 00:28:44,520
+للـ T0 في الـ X Axis 0 بالـ Y Axis ناقص 1 في 10
+
+366
+00:28:44,520 --> 00:28:50,160
+أقصى 2 نيوتن، هذه التي هي T3بدي اطبق القوانين الـ
+
+367
+00:28:50,160 --> 00:28:55,040
+Newton التاني بالـ X axis والـ Y axis applying the
+
+368
+00:28:55,040 --> 00:28:58,680
+condition for equilibrium to the node using a
+
+369
+00:28:58,680 --> 00:28:59,960
+component in the table
+
+370
+00:29:18,300 --> 00:29:22,800
+زائد T2 Sin 53 ناقص واحد في عشر أقصى اتنين متم
+
+371
+00:29:22,800 --> 00:29:26,540
+ساوي Zero There are two equations في عندي الآن
+
+372
+00:29:26,540 --> 00:29:31,380
+معادلتين and two remaining unknown في عندي أنا
+
+373
+00:29:31,380 --> 00:29:36,160
+معادلتين صاري بمجهولين المعادلتين بمجهولين هأوجد
+
+374
+00:29:36,160 --> 00:29:43,900
+T2 بدها تساوي T1 من المعادلة الأولى T2 بدها تساوي
+
+375
+00:29:44,060 --> 00:29:53,700
+T1 cos 37 على cos 53 فT1 بدها تساوي هذه القيمة
+
+376
+00:29:53,700 --> 00:30:02,410
+عوضت عن cos 37 و عن cos 53 بطلع عندي 1.33T1طبعا T2
+
+377
+00:30:02,410 --> 00:30:07,290
+بدلالة T1 الآن substitute بعوض عن T2 في المعادلة
+
+378
+00:30:07,290 --> 00:30:13,010
+اللي هي التانية بدعوض عن T2 بدلالة T1 اذا T1 sin
+
+379
+00:30:13,010 --> 00:30:22,130
+37 زائد طبعا 1.33 T1 اللي طلعت ليها في sin 53 ناقص
+
+380
+00:30:22,500 --> 00:30:26,460
+1 في 10 أقصى 2 نيوتن بيساوي 0 صرت عندي معادلة
+
+381
+00:30:26,460 --> 00:30:35,480
+بمجهول 1 اللي هو T1 بأوجه T1 بتطلع 60.1 إذا عشان
+
+382
+00:30:35,480 --> 00:30:41,880
+أوجه T2 T2 من المعادلة هذه بتساوي 1.33 في T1 إذا 1
+
+383
+00:30:41,880 --> 00:30:51,050
+.33 في T1 اللي هي 60.1 بتطلع 79.9طبعا بنكمل في
+
+384
+00:30:51,050 --> 00:30:52,910
+التسجيل القادم
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/bqeWPtolg8c.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/bqeWPtolg8c.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f8727166cc4aeff667ed56c2db5a63a649bf62d9
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/bqeWPtolg8c.srt
@@ -0,0 +1,1059 @@
+1
+00:00:00,000 --> 00:00:02,760
+بسم الله الرحمن الرحيم. نبدأ إن شاء الله ب chapter
+
+2
+00:00:02,760 --> 00:00:06,500
+سابعة بعنوان rotational motion and gravitation
+
+3
+00:00:06,500 --> 00:00:11,320
+الحركات الدورانية، و اللي هي... و الـ gravitation، و
+
+4
+00:00:11,320 --> 00:00:15,060
+اللي هي الجاذبية أو قانون الجاذبية العام. نجي للـ
+
+5
+00:00:15,060 --> 00:00:18,400
+اللي هي الـ angular velocity and angular acceleration
+
+6
+00:00:18,400 --> 00:00:22,640
+اللي هي السرعة الزاوية، الـ angular الزاوية أو الدورانية
+
+7
+00:00:22,640 --> 00:00:28,140
+السرعة الزاوية و التسارع الزاوي. In this, in the
+
+8
+00:00:28,140 --> 00:00:32,730
+study of linear motion. في دراسة الحركة الخطية، كانت
+
+9
+00:00:32,730 --> 00:00:37,650
+دراستنا عن، طبعاً، تعبير مهم جداً اللي هو الإزاحة، و كنا
+
+10
+00:00:37,650 --> 00:00:41,950
+بنعبر عنها بالـ delta X، و السرعة كنا بنعبر عنها بالـ
+
+11
+00:00:41,950 --> 00:00:46,450
+V، و الـ acceleration كان رمزها A. Each... every
+
+12
+00:00:46,450 --> 00:00:50,890
+concept has its own rotational motion. الآن هذه
+
+13
+00:00:50,890 --> 00:00:56,350
+الرموز اللي هي X، و V، و A لها يعني رمز ثاني و تعبير
+
+14
+00:00:56,350 --> 00:01:01,510
+ثاني. كـ angular displacement، رمزها دلتا ثيتا، دلتا
+
+15
+00:01:01,510 --> 00:01:04,710
+Delta X، Delta Theta. الـ Angular Velocity، السرعة
+
+16
+00:01:04,710 --> 00:01:08,270
+الزاوية رمزها Omega، و الـ Angular Acceleration
+
+17
+00:01:08,270 --> 00:01:13,690
+رمزها Alpha. The radian, a unit of angular measurement,
+
+18
+00:01:13,690 --> 00:01:16,310
+is essential to the understanding of these
+
+19
+00:01:16,310 --> 00:01:20,670
+concepts. احنا كنا في الـ linear motion كان عندنا
+
+20
+00:01:20,670 --> 00:01:23,850
+الـ وحدات أو الـ unit كانت متر، و متر في الثانية، و متر
+
+21
+00:01:23,850 --> 00:01:28,950
+على ثانية تربيع. الآن في النظام الدائري، الوحدة اللي هي
+
+22
+00:01:28,950 --> 00:01:34,140
+القياس الدائري. طبعاً ضروري إن احنا نفهمه بالنسبة لـ
+
+23
+00:01:34,140 --> 00:01:37,740
+الـ angle subtended by the arc length. طبعاً الـ
+
+24
+00:01:37,740 --> 00:01:41,300
+angle هو، الشخص هو ماشي أو الـ particle وهي ماشية
+
+25
+00:01:41,300 --> 00:01:46,120
+بتعمل زاوية على، طبعاً، مسار دائري أو مسار دوراني، بتعمل
+
+26
+00:01:46,120 --> 00:01:51,800
+زاوية، و بالتالي بتعمل أقواس. بدل يعني delta x كانت
+
+27
+00:01:51,800 --> 00:01:56,150
+delta theta، و delta theta تمثل بقوس، و نص القطر، هي
+
+28
+00:01:56,150 --> 00:02:00,410
+بتتحرك خلال القوس، الـ arc length and radius R. إذا
+
+29
+00:02:00,410 --> 00:02:03,970
+اللي هي الـ theta، هذه اللي بتمشيها، اللي هي الإزاحة
+
+30
+00:02:03,970 --> 00:02:08,230
+الخطية، الإزاحة الدورانية، بيساوي القوس على الـ R.
+
+31
+00:02:08,230 --> 00:02:12,690
+إذا احنا مشينا طبعاً from positive x axis، و عكس
+
+32
+00:02:12,690 --> 00:02:16,750
+عقارب الساعة، طبعاً المبدأ الأساسي للدوران. إذا احنا
+
+33
+00:02:16,750 --> 00:02:20,570
+مشينا counter clockwise، هيكون احنا موجب، و نبدأ من
+
+34
+00:02:20,570 --> 00:02:24,530
+الـ x axis، positive x axis، و نبدأ بالحركة الأولى أو
+
+35
+00:02:24,530 --> 00:02:28,510
+بداية الحركة، بداية الـ x، موجب positive X axis.
+
+36
+00:02:28,510 --> 00:02:33,190
+يعني محور X الموجب، و يبتدي يتحرك عكس عقارب الساعة.
+
+37
+00:02:34,320 --> 00:02:39,700
+الزاوية θ في المعادلة 7-1 هي عبارة عن
+
+38
+00:02:39,700 --> 00:02:43,940
+بيسموها الـ angular displacement، إزاحة زاوية من
+
+39
+00:02:43,940 --> 00:02:50,020
+positive x axis، و الـ S عبارة عن اللي هي بيمثل بـ...
+
+40
+00:02:50,020 --> 00:02:53,680
+اللي هي القوس، اللي هي displacement أو الإزاحة خلال
+
+41
+00:02:53,680 --> 00:02:58,920
+جزء من الدائرة أو القوس الصغير. Again, measured from
+
+42
+00:02:58,920 --> 00:03:03,420
+the positive x axis. طبعاً بتوضح ده size of واحد
+
+43
+00:03:03,420 --> 00:03:07,620
+radian. يعني الواحد radian اللي هي ده واحد دائري
+
+44
+00:03:07,620 --> 00:03:12,980
+بتساوي 57.3 درجة بالدرجات. Converted from
+
+45
+00:03:12,980 --> 00:03:17,980
+degree to radian. لما أحول من درجة إلى... إلى دائري
+
+46
+00:03:17,980 --> 00:03:21,840
+طبعاً بنضرب في π على 180. مثل لو كان عندي
+
+47
+00:03:21,840 --> 00:03:27,600
+45 درجة، بدي أحولها لنظام الدائري، فبنحكي
+
+48
+00:03:27,600 --> 00:03:31,040
+π على 180 مضروبة في 45، بتطلع
+
+49
+00:03:31,040 --> 00:03:36,390
+π على 4 بنظام الراديان. يعني الـ by اللي هي 180, by
+
+50
+00:03:36,390 --> 00:03:41,990
+90, by 3, by 4، و هكذا. هي الحركة بهذا الشكل.
+
+51
+00:03:41,990 --> 00:03:45,910
+أنا هبدأ من الـ x axis الموجب، و نمشي عكس عقارب
+
+52
+00:03:45,910 --> 00:03:49,750
+الساعة. احنا إذا مشينا من هنا عكس عقارب الساعة بكون
+
+53
+00:03:49,750 --> 00:03:54,530
+هنا مشيت قوس، طول r في theta، و هنا أنا مشيت
+
+54
+00:03:54,530 --> 00:03:59,550
+طبعاً إزاحة زاوية أو angular displacement، اسمها
+
+55
+00:03:59,550 --> 00:04:03,030
+theta. الواحد radian بتساوي 57.3
+
+56
+00:04:03,030 --> 00:04:08,610
+درجة. في الشكل التالي. بدأ، أفرض في عندي أنا الـ top
+
+57
+00:04:08,610 --> 00:04:12,310
+view of rotating compact disc، اللي هو الـ CD، بتحرك
+
+58
+00:04:12,310 --> 00:04:15,950
+Such a disc is an angle. الـ CD تبع الـ computer
+
+59
+00:04:15,950 --> 00:04:21,130
+بتحرك، و هو بيلف و بيدور كـ rigid body، جسم يعني مجسم
+
+60
+00:04:21,130 --> 00:04:26,230
+which، طبعاً each part of the body fixed. طبعاً هذا الـ
+
+61
+00:04:26,230 --> 00:04:30,940
+CD أو rigid body بتحرك حوالي محور ثابت بالنسبة
+
+62
+00:04:30,940 --> 00:04:34,600
+لأجزاء الثانية. When a rigid body rotates، عندما
+
+63
+00:04:34,600 --> 00:04:39,340
+يدور هذا الجسم خلال زوايا معينة، كل أجزاء الـ... الـ
+
+64
+00:04:39,340 --> 00:04:42,800
+...الأجزاء الموجودة على الـ CD تتحرك بنفس اللي هي
+
+65
+00:04:42,800 --> 00:04:46,620
+الـ angular velocity أو نفس الـ angle في نفس الفترة
+
+66
+00:04:46,620 --> 00:04:50,640
+الزمنية، لأنه جسم واحد بيتحرك حركة واحدة حوالي محور
+
+67
+00:04:50,640 --> 00:04:55,210
+ثابت أو نقطة اللي هي الـ A، بيدور حوالي اللي هو نقطة
+
+68
+00:04:55,210 --> 00:04:57,750
+واحدة أو محور واحد اللي هي الـ O. هذا عبارة عن الـ CD
+
+69
+00:04:57,750 --> 00:05:01,290
+أو الـ disk. كل نقطة على هذا الـ disk بتحرك بنفس الـ
+
+70
+00:05:01,290 --> 00:05:05,810
+angular velocity، بنفس اللي هي، أقصد نفس اللي هي، نفس
+
+71
+00:05:05,810 --> 00:05:10,250
+الزوايا و نفس الـ angular velocity، صحيح، اللي هي الـ
+
+72
+00:05:10,250 --> 00:05:15,050
+Omega. الآن لو هذا الـ disk كان عنده reference line
+
+73
+00:05:15,050 --> 00:05:17,510
+اللي هو الخط الأساسي. هذا بيسموه الخط الأساسي أو
+
+74
+00:05:17,510 --> 00:05:21,590
+المرجعي. لو كانت النقطة B هنا، و بعدين دار هذا الـ
+
+75
+00:05:21,590 --> 00:05:24,790
+disk، تصبح عنده دوران، وسط النقطة، بيها دي المنطقة.
+
+76
+00:05:24,790 --> 00:05:28,590
+معناته الـ disk عمل زاوية ثيتا، اللي هي الإزاحة، و
+
+77
+00:05:28,590 --> 00:05:36,010
+طبعاً مشي بحركة دورانية. القوس بيساوي S، و هنا بيمثل
+
+78
+00:05:36,010 --> 00:05:40,610
+نص القطر، و الـ S بتساوي الـ R في الثيتا. النقطة B on
+
+79
+00:05:40,610 --> 00:05:44,530
+the rotating compact disk. لما T بيساوي 0، و النقطة
+
+80
+00:05:44,530 --> 00:05:48,390
+الثانية لما T بدها تساوي T، طبعاً خلال قوس معين اسمه
+
+81
+00:05:48,390 --> 00:05:52,650
+S. النقطة B على الـ disk is at distance R from the
+
+82
+00:05:52,650 --> 00:05:56,870
+origin. طبعاً النقطة B على مسافة R من اللي هي نقطة
+
+83
+00:05:56,870 --> 00:06:00,610
+الأصل أو المحور الدوران. We set up a fixed
+
+84
+00:06:00,610 --> 00:06:05,010
+reference. طبعاً ثبتنا خط كمرجعية. And assume that
+
+85
+00:06:05,010 --> 00:06:08,030
+the time T=0, and النقطة B is on the reference line.
+
+86
+00:06:08,030 --> 00:06:12,870
+After time، بعد فترة زمنية Delta T، النقطة B هتنتقل
+
+87
+00:06:12,870 --> 00:06:18,190
+إلى نقطة ثانية خلال إزاحة زاوية ثانية. و بالتالي
+
+88
+00:06:18,190 --> 00:06:21,830
+هيكون عندنا حاجة اسمها الـ angular position، الـ
+
+89
+00:06:21,830 --> 00:06:25,730
+angular position، اللي هو اللي هي اللي هي الإزاحة
+
+90
+00:06:25,730 --> 00:06:29,010
+أو الموقع اللي هو الزاوي بالنسبة لنقطة P. إذا
+
+91
+00:06:29,010 --> 00:06:33,670
+انتقلت من مكان إلى مكان، فالـ... اللي هو رمز بدل الـ
+
+92
+00:06:33,670 --> 00:06:38,250
+X، رح نحط ثيتا. بتصير عندنا دلتا ثيتا بتساوي ثيتا
+
+93
+00:06:38,250 --> 00:06:43,690
+final ناقص ثيتا initial. هي الشكل. طبعاً احنا عندنا
+
+94
+00:06:43,690 --> 00:06:47,770
+مرجعية هنا، الـ X axis. بصي في X axis، النقطة كانت عند
+
+95
+00:06:47,770 --> 00:06:52,550
+المنطقة A، كانت T-initial. الـ disk بدور، فوصلت
+
+96
+00:06:52,550 --> 00:06:56,970
+المنطقة إلى T-final. فهو خلال هذه الفترة عمل زوايا
+
+97
+00:06:56,970 --> 00:07:01,490
+لما كانت T-initial عمل طبعاً زاوية هنا θ initial، و
+
+98
+00:07:01,490 --> 00:07:05,750
+لما T-final عمل θ final. إذن الإزاحة اللي هي delta
+
+99
+00:07:05,750 --> 00:07:11,530
+θ بتساوي θ final ناقص θ initial. هذا الشكل بوضح
+
+100
+00:07:11,530 --> 00:07:14,650
+طبعاً النقطة اللي هي على الـ disk حركت من نقطة A
+
+101
+00:07:14,650 --> 00:07:19,250
+لنقطة B. و الـ disk rotate through the angle، مشي الـ
+
+102
+00:07:19,250 --> 00:07:22,070
+disk خلال زوايا معينة، delta theta، بتساوي theta
+
+103
+00:07:22,070 --> 00:07:27,070
+final ناقص theta initial. في الشكل التالي. 4 في
+
+104
+00:07:27,070 --> 00:07:32,170
+عندنا نقطة على الـ disk المتحرك، تتحرك من نقطة A
+
+105
+00:07:32,170 --> 00:07:36,680
+لنقطة B خلال فترة زمنية delta T. الـ Angle θ initial
+
+106
+00:07:36,680 --> 00:07:41,020
+و Angle θ final. معنى الكلام، θ final ناقص θ initial
+
+107
+00:07:41,020 --> 00:07:45,100
+بتسمى اللي هي الـ angular displacement. تعريف الـ
+
+108
+00:07:45,100 --> 00:07:49,880
+angular displacement، اللي هي delta θ، عبارة عن الـ
+
+109
+00:07:49,880 --> 00:07:52,960
+difference in its final and initial angle. هي عبارة
+
+110
+00:07:52,960 --> 00:07:57,540
+عن الفرق بين اللي هي الزاوية الابتدائية و الزاوية
+
+111
+00:07:57,540 --> 00:08:00,620
+النهائية. اللي هنا بمشي حركة دورانية، و بالتالي بتحرك
+
+112
+00:08:00,620 --> 00:08:05,490
+زاوية و ليس مسافات. الـ unit لـ θ هي عبارة عن الـ
+
+113
+00:08:05,490 --> 00:08:11,790
+rad، اللي هي نظام الدائري. For example, if a point on
+
+114
+00:08:11,790 --> 00:08:15,690
+a disk is at initial، يعني مثال لو كانت النقطة on θ
+
+115
+00:08:15,690 --> 00:08:21,950
+initial 4 rad، اتحركت بطبعاً إزاحة دورانية، وصلت
+
+116
+00:08:21,950 --> 00:08:25,690
+لـ θ final 7 rad. و هتكون بهذا الحالة الـ angular
+
+117
+00:08:25,690 --> 00:08:30,910
+displacement Δ θ بتساوي θ final ناقص θ initial
+
+118
+00:08:30,910 --> 00:08:35,510
+بتساوي 7 rad ناقص 4 rad، يعني 3 rad. بيللاحظ
+
+119
+00:08:35,510 --> 00:08:40,470
+أنه التغير بالزاوية بيوصف اللي هو الدوران اللي هي
+
+120
+00:08:40,470 --> 00:08:43,510
+نقطة من نقطة إلى نقطة. و كل نقطة على الـ disk
+
+121
+00:08:43,510 --> 00:08:47,310
+undergoes the same angular displacement in any
+
+122
+00:08:47,310 --> 00:08:52,140
+given time interval. بالنسبة للـ Angular Average
+
+123
+00:08:52,140 --> 00:08:55,760
+Angular Velocity. زي ما أخدنا الـ Angular، الـ average
+
+124
+00:08:55,760 --> 00:09:00,140
+velocity، هناخد average angular velocity. هنعود بدل
+
+125
+00:09:00,140 --> 00:09:04,140
+طبعاً رمزها Omega average، بدل الـ V صارت Omega
+
+126
+00:09:04,140 --> 00:09:08,060
+الدورانية. Of the rotating rigid object during the
+
+127
+00:09:08,060 --> 00:09:11,980
+time interval Delta T. معنى الكلام، الـ Omega average
+
+128
+00:09:12,300 --> 00:09:15,340
+بتساوي delta theta على delta t، اللي هي
+
+129
+00:09:15,340 --> 00:09:19,460
+displacement، delta theta divided by delta t، و هي theta
+
+130
+00:09:19,460 --> 00:09:23,060
+final ناقص theta initial على t final ناقص t
+
+131
+00:09:23,060 --> 00:09:26,660
+initial. إذا delta theta على delta t هي عبارة عن الـ
+
+132
+00:09:26,660 --> 00:09:31,040
+average angular velocity، و رمزها radian per
+
+133
+00:09:31,040 --> 00:09:36,080
+second، أو radian per second. وحدة ثانية. نجي لتعريف
+
+134
+00:09:36,080 --> 00:09:39,580
+ثاني اللي هو الـ Instantaneous Angular Velocity،
+
+135
+00:09:39,580 --> 00:09:43,120
+اللي هي السرعة الزاوية اللحظية، اللي هي اللحظية،
+
+136
+00:09:43,120 --> 00:09:46,020
+اللي هي السرعة الزاوية اللحظية عند أي لحظة. اسمها
+
+137
+00:09:46,020 --> 00:09:49,900
+Omega. Of a rotating object is the limit of the
+
+138
+00:09:49,900 --> 00:09:52,800
+average velocity. عبارة عن limit Delta T. تعالَ
+
+139
+00:09:52,800 --> 00:09:57,400
+Delta T، عندما Delta T بتؤول إلى Zero. فبرضه وحدتها
+
+140
+00:09:57,400 --> 00:10:00,160
+هي عبارة عن السرعة اللحظية الزاوية، اللي هي الزاوية
+
+141
+00:10:00,160 --> 00:10:04,020
+عند أي لحظة T. وهي عبارة عن Radian Per Second أو
+
+142
+00:10:04,020 --> 00:10:08,490
+Rad Per Second. We took omega to be positive، لأن
+
+143
+00:10:08,490 --> 00:10:14,290
+طبعاً بنعتبر omega موجبة لما theta و theta بتزيد
+
+144
+00:10:14,290 --> 00:10:19,010
+زيادة عكس عقارب الساعة. إذا omega موجبة، and
+
+145
+00:10:19,010 --> 00:10:24,430
+negative، و سالبة عندما تكون الـ theta بتقل، يعني أو
+
+146
+00:10:24,430 --> 00:10:28,990
+باتجاه clockwise. معناته الـ theta بتقل، و الـ omega
+
+147
+00:10:28,990 --> 00:10:32,490
+negative. When the angular velocity is constant، the
+
+148
+00:10:32,490 --> 00:10:35,030
+instantaneous angular velocity equals the
+
+149
+00:10:35,030 --> 00:10:39,810
+average angular velocity. عندما تكون السرعة ثابتة،
+
+150
+00:10:39,810 --> 00:10:44,790
+فاللي هي الـ omega، اللي هي السرعة الزاوية، بتساوي الـ
+
+151
+00:10:44,790 --> 00:10:47,890
+average، السرعة الزاوية بتساوي الـ instantaneous، أو
+
+152
+00:10:47,890 --> 00:10:52,240
+كمان عندما تكون الـ velocity is constant، فالسرعة
+
+153
+00:10:52,240 --> 00:10:56,920
+الزاوية اللحظية بدها تساوي الـ average angular
+
+154
+00:10:56,920 --> 00:11:01,480
+velocity، اللي بتساوي السرعة اللي هي المتوسطة، السرعة
+
+155
+00:11:01,480 --> 00:11:04,580
+الزاوية اللحظية بتساوي المتوسطة في هذه الحالة.
+
+156
+00:11:04,580 --> 00:11:10,000
+عندما تكون الـ velocity is constant. Instantaneous
+
+157
+00:11:10,000 --> 00:11:15,550
+angular speed. Instantaneous angular speed of an
+
+158
+00:11:15,550 --> 00:11:19,150
+object، ممكن أعرفها عبارة عن الـ magnitude of the
+
+159
+00:11:19,150 --> 00:11:22,570
+instantaneous، قيمة الـ instantaneous اللي هي السرعة
+
+160
+00:11:22,570 --> 00:11:26,430
+اللحظية اللي هي الزاوية، قيمة السرعة اللحظية
+
+161
+00:11:26,430 --> 00:11:30,870
+الزاوية. Instantaneous angular speed، السرعة
+
+162
+00:11:30,870 --> 00:11:36,630
+المقياسية اللحظية، اللحظية، أو بيسموها الـ angular
+
+163
+00:11:36,630 --> 00:11:40,880
+speed has no direction. طبعاً مالهاش اتجاه، لكن
+
+164
+00:11:40,880 --> 00:11:48,360
+مرتبطة بالقيمة، و أيضاً it and carry، مالهاش أي إشارة
+
+165
+00:11:48,360 --> 00:11:52,140
+حسب، يعني توضح اتجاه موجب أو سالب، إشارة جبرية.
+
+166
+00:11:52,140 --> 00:11:57,020
+Example 7-1. The rotor of a helicopter
+
+167
+00:11:57,020 --> 00:12:01,920
+turns at an angular velocity of 3.2 × 10² revolution
+
+168
+00:12:01,920 --> 00:12:08,400
+per minute. اللي هي الـ motor اللي بتحرك في الطيارة
+
+169
+00:12:08,400 --> 00:12:13,360
+الفراشة، الخاصة في المطور بتتحرك في الطيارة، بتتحرك بـ
+
+170
+00:12:13,360 --> 00:12:17,380
+...سرعة angular velocity، يعني omega، بسرعة تلاتة
+
+171
+00:12:17,380 --> 00:12:20,320
+و اثنين في عشرة أقصى اثنين revolution per minute.
+
+172
+00:12:20,320 --> 00:12:25,060
+يعني دورة لكل دقيقة. طبعاً في الكتاب ممكن
+
+173
+00:12:25,060 --> 00:12:30,020
+نعطيها برمز ثاني، اللي هي rpm، يعني revolution per
+
+174
+00:12:30,020 --> 00:12:35,020
+minute. معناها هذه
+
+223
+00:16:09,360 --> 00:16:14,080
+الساعة حول محور ثابت، الجسم يدور، من
+
+224
+00:16:14,080 --> 00:16:20,240
+الجمال الآن بتمثل الـ initial angular position and
+
+225
+00:16:20,240 --> 00:16:23,200
+الـ final angular position of the rigid body، لأن
+
+226
+00:16:23,200 --> 00:16:27,840
+هيعطيني أنا خيارات، من هذه الخيارات بتمثل الـ
+
+227
+00:16:27,840 --> 00:16:33,460
+initial و الـ final، حيث أن هاتين القيمتين if the
+
+228
+00:16:33,460 --> 00:16:37,240
+rigid body rotate more than طبعاً الفرق بين هاتين القيمتين
+
+229
+00:16:37,240 --> 00:16:41,000
+بدي أنا الفرق بين هاتين القيمتين، يعني الـ delta theta
+
+230
+00:16:41,000 --> 00:16:46,280
+يعطيني جواب أكبر من 180 درجة
+
+231
+00:16:46,280 --> 00:16:51,380
+الفرق بين هاتين القيمتين يجب أن يعطيني جواب أكبر أو
+
+232
+00:16:51,380 --> 00:16:57,200
+أكبر من 180 درجة. نشوف الآن، احنا الـ delta theta
+
+233
+00:16:57,200 --> 00:17:02,000
+لازم تكون... دلتا ثيتا المطلوبة أن تكون أكبر
+
+234
+00:17:02,000 --> 00:17:08,810
+من 180، الـ 180 هي عبارة عن 3.14 راديان. إذاً، لازم
+
+235
+00:17:08,810 --> 00:17:11,210
+تكون delta theta أكبر من 3.14 راديان. ليش؟
+
+236
+00:17:11,210 --> 00:17:14,710
+الأولى هنا 3، وهذا الـ initial، موثّلها
+
+237
+00:17:14,710 --> 00:17:18,650
+the final، إذاً 6 - 3 = 3. طبعاً
+
+238
+00:17:18,650 --> 00:17:22,690
+الثلاثة أقل من 180 درجة، أقل من 3.14
+
+239
+00:17:22,690 --> 00:17:26,410
+راديان، مانفعش. إذاً طيب، ناقص واحد و واحد، بنحكي
+
+240
+00:17:26,410 --> 00:17:31,510
+واحد ناقص ناقص واحد = 2. طبعاً في B، إذاً
+
+241
+00:17:31,510 --> 00:17:35,990
+2 أقل من 3.14 راديان، اللي هي عبارة عن 180 درجة.
+
+242
+00:17:35,990 --> 00:17:40,330
+نيجي للثالثة C، 1 راديان و 5 راديان، طبعاً هذه تمثل
+
+243
+00:17:40,330 --> 00:17:44,230
+initial displacement وهذا final. هنحكي Delta Theta
+
+244
+00:17:44,230 --> 00:17:48,130
+بإساوي 5 - 1 = 4. إذاً، الأربعة هذه
+
+245
+00:17:48,130 --> 00:17:54,570
+أكبر من 3.14، وبالتالي Delta Theta في هذه الحالة
+
+246
+00:17:54,570 --> 00:17:59,210
+تساوي اللي هي C، Delta Theta أكبر من 180 اللي هي
+
+247
+00:17:59,530 --> 00:18:04,010
+1 rad و 5 rad، الفرق بينهم 4 rad أكبر من
+
+248
+00:18:04,010 --> 00:18:10,750
+180 درجة. في الـ quiz 7.2 بيحكي لي
+
+249
+00:18:10,750 --> 00:18:15,260
+Suppose، أفرض أن the change in angular position for
+
+250
+00:18:15,260 --> 00:18:18,300
+each of the pair of values، quick quiz بيقول، يحكي
+
+251
+00:18:18,300 --> 00:18:21,980
+لنا، إيه جعل الـ quiz الأولى يعني occur in one
+
+252
+00:18:21,980 --> 00:18:24,720
+second، which it shows represents the lowest average
+
+253
+00:18:24,720 --> 00:18:29,880
+angular velocity، من تمثل اللي هي the lowest
+
+254
+00:18:29,880 --> 00:18:34,440
+average angular velocity، من أقل سرعة زاوية في
+
+255
+00:18:34,440 --> 00:18:38,000
+زمن قدره 1 ثانية. طبعاً، الأول، احنا جبنا الـ delta theta
+
+256
+00:18:38,000 --> 00:18:42,040
+هذه أكبر، delta theta كانت أكبر من 3.14 راديان.
+
+257
+00:18:42,040 --> 00:18:47,080
+نروح نرجع لهذا الـ quiz، نشوف بدنا احنا
+
+258
+00:18:47,080 --> 00:18:50,360
+بالأول delta theta / delta T بيعطينا إيه؟ اللي
+
+259
+00:18:50,360 --> 00:18:54,300
+هي omega، average omega. فعشان أوجد الـ average
+
+260
+00:18:54,300 --> 00:18:57,500
+angular velocity لازم أجيب delta theta، delta theta
+
+261
+00:18:57,500 --> 00:19:01,220
+فمين أقل delta theta؟ هل الثلاثة والستة؟ الفرق بينهم
+
+262
+00:19:01,220 --> 00:19:05,080
+3، هنا الفرق بينهم 2، هنا الفرق بينهم 4.
+
+263
+00:19:05,080 --> 00:19:08,380
+فالفرق بينهم 2، اللي هي delta theta، 1 -
+
+264
+00:19:08,380 --> 00:19:11,580
+ناقص 1 = 2، إذاً delta theta هنا 2.
+
+265
+00:19:12,170 --> 00:19:17,370
+و الزمن delta T = 1، فمعنى الكلام أن الـ
+
+266
+00:19:17,370 --> 00:19:21,610
+omega average = delta theta / delta T، لما
+
+267
+00:19:21,610 --> 00:19:26,490
+يكون الجواب اللي هو B، زي ما احنا شايفين الجواب B
+
+268
+00:19:26,490 --> 00:19:30,770
+لما تكون 1 و -1، فـ delta theta =
+
+269
+00:19:30,770 --> 00:19:35,410
+1 - (-1) = 2.
+
+270
+00:19:35,410 --> 00:19:40,330
+فالجواب اللي هو B هو هيكون the lowest angular
+
+271
+00:19:40,330 --> 00:19:44,840
+velocity، the lowest angular velocity في هذه الحالة.
+
+272
+00:19:44,840 --> 00:19:50,320
+ليش؟ لأن الـ average angular acceleration، تعريف جديد
+
+273
+00:19:50,320 --> 00:19:53,760
+اللي هي الـ average angular acceleration، متوسط
+
+274
+00:19:53,760 --> 00:19:57,280
+التسارع الزاوي، الـ angular acceleration، رمزه Alpha
+
+275
+00:19:57,280 --> 00:20:02,500
+(α) average، خلال فترة زمنية، طبعاً زي ما قلنا Delta T
+
+276
+00:20:02,500 --> 00:20:05,480
+عبارة عن التغير في الـ angular velocity، Delta Omega
+
+277
+00:20:05,480 --> 00:20:10,400
+divided by Delta T، فالـ Alpha average = Delta
+
+278
+00:20:10,400 --> 00:20:13,750
+Omega / Delta T، أو أوميجا final - أوميجا initial
+
+279
+00:20:13,750 --> 00:20:19,190
+/ T final - T initial، الـ unit لها هي عبارة عن
+
+280
+00:20:19,190 --> 00:20:23,310
+rad/second²، if as the طبعاً، with the
+
+281
+00:20:23,310 --> 00:20:25,710
+angular velocity positive، angular acceleration are
+
+282
+00:20:25,710 --> 00:20:29,690
+in the counter clockwise، إذا كانت السرعة الزاوية
+
+283
+00:20:29,690 --> 00:20:34,250
+موجبة، فالتسارع الزاوي برضه بيتحرك عكس عقارب الساعة.
+
+284
+00:20:34,250 --> 00:20:37,850
+إذا كانت الـ negative angular acceleration in the
+
+285
+00:20:38,120 --> 00:20:42,000
+clockwise، إذا كانت بتتحرك بحركة disk أو أي جسم
+
+286
+00:20:42,000 --> 00:20:45,820
+بتتحرك أو بتدور مع عقارب الساعة، فالـ angular acceleration
+
+287
+00:20:45,820 --> 00:20:48,740
+is negative. If the angular velocity goes from
+
+288
+00:20:48,740 --> 00:20:54,560
+15 rad إلى 9، إذا كانت الـ angular velocity اللي
+
+289
+00:20:54,560 --> 00:20:58,320
+هي أوميغا، تتحرك من الـ initial 15 و الـ final
+
+290
+00:20:58,320 --> 00:21:02,460
+9 في 3 ثواني، فالـ average angular acceleration
+
+291
+00:21:02,460 --> 00:21:08,060
+during that time interval is، الـ α average
+
+292
+00:21:08,060 --> 00:21:11,920
+average = Delta Omega / Delta T، يعني هنا الـ
+
+293
+00:21:11,920 --> 00:21:16,380
+final 9 - 15 / 3 = -2، معناها هي عبارة عن تسارع زاوي بيتناقص، يعني الـ
+
+294
+00:21:16,380 --> 00:21:21,040
+disk بيبدأ بسرعة، بتبدأ تتناقص حسب التسارع اللي
+
+295
+00:21:21,040 --> 00:21:24,320
+ماشي فيه حتى يقف، طبعاً لأنه بيتناقص. هنا ده negative
+
+296
+00:21:24,320 --> 00:21:28,420
+sign، indicate إشارة الساعة اللي بتدل على إنه
+
+297
+00:21:28,420 --> 00:21:31,980
+التسارع اللي هو التسارع الزاوي بيكون برضه مع عقارب
+
+298
+00:21:31,980 --> 00:21:37,580
+الساعة، although بالإضافة إلى أن الـ angular velocity
+
+299
+00:21:37,580 --> 00:21:41,580
+still positive but slowing down، طبعاً زي ما حكينا
+
+300
+00:21:41,580 --> 00:21:45,340
+أن السرعة موجبة لكن سرعتها بتتناقص، is in the counter
+
+301
+00:21:45,340 --> 00:21:50,000
+clockwise direction. Instantaneous
+
+302
+00:21:50,000 --> 00:21:58,620
+acceleration، برضه زي ما حكينا، رمزه Alpha، عبارة عن
+
+303
+00:22:03,190 --> 00:22:06,890
+limit Delta Omega / Delta T، لما Delta T تؤول إلى
+
+304
+00:22:06,890 --> 00:22:11,070
+0، هي عبارة عن تسارع لحظة عند لحظة معينة، وهي
+
+305
+00:22:11,070 --> 00:22:17,170
+بـ rad/second²، when a rigid object، أي
+
+306
+00:22:17,170 --> 00:22:22,150
+جسم يدور حول محور ثابت، فكل النقاط الموجودة
+
+307
+00:22:22,150 --> 00:22:26,350
+عليه بتتحرك بنفس الـ angular velocity وبنفس الـ
+
+308
+00:22:26,350 --> 00:22:30,010
+angular acceleration، بنفس الـ angular velocity وبنفس
+
+309
+00:22:30,010 --> 00:22:34,050
+الـ angular acceleration، لأنهم بيتحركوا كجسم واحد
+
+310
+00:22:34,050 --> 00:22:39,150
+و بيدور حول محور ثابت، فكل جزئية، كل نقطة على الـ
+
+311
+00:22:39,150 --> 00:22:42,830
+disk بتتحرك بنفس السرعة الزاوية و بتتحرك بنفس
+
+312
+00:22:42,830 --> 00:22:46,410
+التسارع الزاوي. نستكمل إن شاء الله في التسجيل
+
+313
+00:22:46,410 --> 00:22:47,810
+القادم والمحاضرة القادمة.
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/bqeWPtolg8c_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/bqeWPtolg8c_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..f09d9150c9efe02e1ab9b44d7dc8b150e36bece1
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/bqeWPtolg8c_raw.json
@@ -0,0 +1 @@
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"text": "رمزة Alpha عبارة عن limit Delta Omega على Delta T لما Delta T تقول إلى Zero هي عبارة عن تسارق لحظة عند لحظة معينة وهي بثورات per second square when a rigid object أي جسم بدور حوالين محور ثابت فكل النقاط الموجودين عليه بتحركوا بنفس ال angular velocity و بنفس ال angular acceleration بنفس ال angular velocity", "tokens": [2288, 2304, 11622, 3660, 20588, 6225, 3555, 9640, 3660, 18871, 4948, 18183, 27645, 15844, 18183, 314, 5296, 15042, 18183, 314, 6055, 39648, 30731, 17182, 39896, 6225, 3555, 9640, 3660, 18871, 6055, 3794, 9640, 4587, 5296, 5016, 19913, 3660, 43242, 5296, 5016, 19913, 3660, 20449, 9957, 3660, 37037, 1829, 4724, 12984, 13063, 9307, 680, 1150, 3732, 562, 257, 22195, 2657, 36632, 10874, 38251, 47525, 13063, 11331, 2407, 6027, 9957, 3714, 5016, 13063, 38637, 16758, 2655, 6156, 28820, 28239, 4587, 41193, 9673, 29245, 23328, 9957, 47356, 39894, 5016, 31747, 14407, 44945, 36178, 2423, 24413, 9269, 4032, 44945, 36178, 2423, 24413, 17162, 44945, 36178, 2423, 24413, 9269], "avg_logprob": -0.16488094670431955, "compression_ratio": 1.6541353383458646, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 1320.97, "end": 1321.55, "word": "رمزة", "probability": 0.8543701171875}, {"start": 1321.55, "end": 1321.99, "word": " Alpha", "probability": 0.57373046875}, {"start": 1321.99, "end": 1322.97, "word": " عبارة", "probability": 0.81329345703125}, {"start": 1322.97, "end": 1323.19, "word": " عن", "probability": 0.994140625}, {"start": 1323.19, "end": 1323.65, "word": " limit", "probability": 0.595703125}, {"start": 1323.65, "end": 1324.07, "word": " Delta", "probability": 0.37841796875}, {"start": 1324.07, "end": 1324.39, "word": " Omega", "probability": 0.82861328125}, {"start": 1324.39, "end": 1324.67, "word": " على", "probability": 0.71875}, {"start": 1324.67, "end": 1324.99, "word": " Delta", "probability": 0.94384765625}, {"start": 1324.99, "end": 1325.33, "word": " T", "probability": 0.9111328125}, {"start": 1325.33, "end": 1325.91, "word": " 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"probability": 0.9967041015625}, {"start": 1329.61, "end": 1330.39, "word": " معينة", "probability": 0.9894205729166666}, {"start": 1330.39, "end": 1331.07, "word": " وهي", "probability": 0.8134765625}, {"start": 1331.07, "end": 1331.75, "word": " بثورات", "probability": 0.59381103515625}, {"start": 1331.75, "end": 1331.93, "word": " per", "probability": 0.72802734375}, {"start": 1331.93, "end": 1332.25, "word": " second", "probability": 0.91357421875}, {"start": 1332.25, "end": 1332.99, "word": " square", "probability": 0.387939453125}, {"start": 1332.99, "end": 1334.29, "word": " when", "probability": 0.4384765625}, {"start": 1334.29, "end": 1334.93, "word": " a", "probability": 0.63134765625}, {"start": 1334.93, "end": 1335.19, "word": " rigid", "probability": 0.923828125}, {"start": 1335.19, "end": 1336.89, "word": " object", "probability": 0.7939453125}, {"start": 1336.89, "end": 1337.17, "word": " أي", "probability": 0.5966796875}, {"start": 1337.17, "end": 1337.61, "word": " جسم", "probability": 0.978271484375}, {"start": 1337.61, "end": 1338.17, "word": " بدور", "probability": 0.97509765625}, {"start": 1338.17, "end": 1338.99, "word": " حوالين", "probability": 0.89404296875}, {"start": 1338.99, "end": 1339.35, "word": " محور", "probability": 0.9895833333333334}, {"start": 1339.35, "end": 1339.97, "word": " ثابت", "probability": 0.994140625}, {"start": 1339.97, "end": 1340.79, "word": " فكل", "probability": 0.950439453125}, {"start": 1340.79, "end": 1341.47, "word": " النقاط", "probability": 0.9519856770833334}, {"start": 1341.47, "end": 1342.15, "word": " الموجودين", "probability": 0.967529296875}, {"start": 1342.15, "end": 1342.45, "word": " عليه", "probability": 0.95068359375}, {"start": 1342.45, "end": 1343.25, "word": " بتحركوا", "probability": 0.85595703125}, {"start": 1343.25, "end": 1344.05, "word": " بنفس", "probability": 0.984375}, {"start": 1344.05, "end": 1344.27, "word": " ال", "probability": 0.88671875}, {"start": 1344.27, "end": 1344.67, 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acceleration لإن هم بتحركوا كجسم واحد ودور حوالين محور ثابت فكل جزئية كل نقطة على ال disk بتتحرك بنفس السرعه الزاوية وبتتحرك بنفس التسارع الزاوى نستكمل ان شاء الله في التسجيل القادم والمحاضرة القادمة", "tokens": [37746, 1863, 36178, 2423, 24413, 17162, 5296, 28814, 1863, 8032, 2304, 39894, 5016, 31747, 14407, 9122, 7435, 38251, 36764, 24401, 4032, 3215, 13063, 11331, 2407, 6027, 9957, 3714, 5016, 13063, 38637, 16758, 2655, 6156, 28820, 10874, 11622, 19986, 10632, 28242, 8717, 47432, 3660, 15844, 2423, 12355, 39894, 2655, 5016, 31747, 44945, 36178, 21136, 2288, 3615, 3224, 6024, 110, 995, 2407, 10632, 4032, 3555, 2655, 2655, 5016, 31747, 44945, 36178, 16712, 3794, 9640, 3615, 6024, 110, 995, 2407, 7578, 8717, 14851, 24793, 1211, 16472, 13412, 16606, 21984, 8978, 16712, 3794, 7435, 26895, 25062, 18513, 2304, 4032, 45340, 5016, 46958, 25720, 25062, 18513, 46007], "avg_logprob": -0.10459647826778079, "compression_ratio": 1.759433962264151, "no_speech_prob": 7.331371307373047e-06, "words": [{"start": 1349.59, "end": 1350.01, "word": "وبنفس", "probability": 0.8291015625}, {"start": 1350.01, "end": 1350.15, "word": " ال", "probability": 0.9453125}, {"start": 1350.15, "end": 1350.45, "word": " angular", "probability": 0.705078125}, {"start": 1350.45, "end": 1351.49, "word": " acceleration", "probability": 0.806640625}, {"start": 1351.49, "end": 1352.31, "word": " لإن", "probability": 0.7708333333333334}, {"start": 1352.31, "end": 1352.53, "word": " هم", "probability": 0.924560546875}, {"start": 1352.53, "end": 1353.03, "word": " بتحركوا", "probability": 0.9375}, {"start": 1353.03, "end": 1353.43, "word": " كجسم", "probability": 0.9182942708333334}, {"start": 1353.43, "end": 1354.05, "word": " واحد", "probability": 0.978515625}, {"start": 1354.05, "end": 1354.73, "word": " ودور", "probability": 0.8473307291666666}, {"start": 1354.73, "end": 1355.33, "word": " حوالين", "probability": 0.9105224609375}, {"start": 1355.33, "end": 1355.99, "word": " محور", "probability": 0.9895833333333334}, {"start": 1355.99, "end": 1356.69, "word": " ثابت", "probability": 0.9765625}, {"start": 1356.69, "end": 1357.41, "word": " فكل", "probability": 0.970947265625}, {"start": 1357.41, "end": 1358.09, "word": " جزئية", "probability": 0.952880859375}, {"start": 1358.09, "end": 1358.39, "word": " كل", "probability": 0.60791015625}, {"start": 1358.39, "end": 1358.85, "word": " نقطة", "probability": 0.9886067708333334}, {"start": 1358.85, "end": 1359.03, "word": " على", "probability": 0.82958984375}, {"start": 1359.03, "end": 1359.15, "word": " ال", "probability": 0.96923828125}, {"start": 1359.15, "end": 1359.47, "word": " disk", "probability": 0.77001953125}, {"start": 1359.47, "end": 1360.23, "word": " بتتحرك", "probability": 0.9537353515625}, {"start": 1360.23, "end": 1360.77, "word": " بنفس", "probability": 0.96240234375}, {"start": 1360.77, "end": 1361.59, "word": " السرعه", "probability": 0.8607177734375}, {"start": 1361.59, "end": 1361.99, "word": " الزاوية", "probability": 0.97587890625}, {"start": 1361.99, "end": 1362.49, "word": " وبتتحرك", "probability": 0.8504231770833334}, {"start": 1362.49, "end": 1362.83, "word": " بنفس", "probability": 0.986572265625}, {"start": 1362.83, "end": 1363.53, "word": " التسارع", "probability": 0.9871826171875}, {"start": 1363.53, "end": 1364.23, "word": " الزاوى", "probability": 0.84296875}, {"start": 1364.23, "end": 1365.15, "word": " نستكمل", "probability": 0.929443359375}, {"start": 1365.15, "end": 1365.25, "word": " ان", "probability": 0.76806640625}, {"start": 1365.25, "end": 1365.43, "word": " شاء", "probability": 0.987060546875}, {"start": 1365.43, "end": 1365.59, "word": " الله", "probability": 0.947265625}, {"start": 1365.59, "end": 1365.83, "word": " في", "probability": 0.8974609375}, {"start": 1365.83, "end": 1366.41, "word": " التسجيل", "probability": 0.985595703125}, {"start": 1366.41, "end": 1366.91, "word": " القادم", "probability": 0.9925130208333334}, {"start": 1366.91, "end": 1367.39, "word": " والمحاضرة", "probability": 0.79833984375}, {"start": 1367.39, "end": 1367.81, "word": " القادمة", "probability": 0.9811197916666666}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1368.11975, "duration_after_vad": 1351.606593749999}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo.srt
new file mode 100644
index 0000000000000000000000000000000000000000..0885ddff76c86dcebbb75e1ef2d3cf849d71547c
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo.srt
@@ -0,0 +1,1247 @@
+1
+00:00:01,200 --> 00:00:04,720
+بسم الله الرحمن الرحيم، بنستكمل أيضا chapter 6
+
+2
+00:00:04,720 --> 00:00:10,020
+بنبدأ ب quiz 6-2، بيحكينا أن a boy is standing at one
+
+3
+00:00:10,020 --> 00:00:12,780
+end of a floating raft that is stationary relative
+
+4
+00:00:12,780 --> 00:00:15,680
+to the shore, walks to the opposite end of the raft
+
+5
+00:00:15,680 --> 00:00:21,660
+معناها أنه في عندنا ولد أو طفل بيقف على حافة مركب
+
+6
+00:00:21,660 --> 00:00:26,100
+المركب هذه لها حافتين، حافة الأولى ناحية الشاطئ، و
+
+7
+00:00:26,100 --> 00:00:30,270
+الحافة الثانية داخل البحر أو داخل الماء. الآن الطفل
+
+8
+00:00:30,270 --> 00:00:35,170
+يقف على إحدى الحواف، على الحافة التي ناحية الشاطئ،
+
+9
+00:00:35,170 --> 00:00:40,550
+الآن هي المركب طبعا ثابتة بالنسبة للشاطئ، الآن
+
+10
+00:00:40,550 --> 00:00:44,250
+الولد بده يمشي من الحافة التي ناحية الشاطئ ويدخل
+
+11
+00:00:44,250 --> 00:00:48,270
+لجوا، للحافة الثانية، walks to the opposite end of
+
+12
+00:00:48,270 --> 00:00:53,450
+the raft، هو يمشي للطرف الثاني المقابل. طبعا الطرف
+
+13
+00:00:53,450 --> 00:00:57,590
+الأول ناحية الشاطئ، هو واقف ناحية الشاطئ و هيمشي
+
+14
+00:00:57,590 --> 00:01:01,210
+على الطرف الثاني للمركب الذي داخل البحر، away from
+
+15
+00:01:01,210 --> 00:01:06,070
+the shore. طبعا بعيدا عن الشاطئ. الآن هذه الحركة لو
+
+16
+00:01:06,070 --> 00:01:10,130
+تخيلناها، و بيسألنا السؤال بيحكي as the consequence
+
+17
+00:01:10,130 --> 00:01:16,570
+من أن the raft، طبعا هي المركب الصغيرة أو ال
+
+18
+00:01:16,570 --> 00:01:20,910
+... طبعا التي بيسموها الحسكة أو الطوافة، هل هي هتظل
+
+19
+00:01:20,910 --> 00:01:27,550
+ثابتة أم تتحرك ناحية الشاطئ أم تتحرك towards the
+
+20
+00:01:27,550 --> 00:01:31,550
+shore؟ هتتحرك من الشاطئ لجوه ولا هتتحرك ناحية
+
+21
+00:01:31,550 --> 00:01:35,590
+الشاطئ ولا هتظل ثابتة؟ الآن الطفل هيتحرك من الشاطئ
+
+22
+00:01:35,590 --> 00:01:40,270
+ويدخل لجوه. بناء عليه، طبعا الجواب ال ... ال ...
+
+23
+00:01:40,270 --> 00:01:43,570
+الـ المركب هذا الصغير هتتحرك العكس. إذا ... إذا الطفل
+
+24
+00:01:43,570 --> 00:01:47,870
+دخل لجوه هي هتتحرك العكس. إذا الطفل طلع لبره، هيتحرك
+
+25
+00:01:47,870 --> 00:01:52,750
+لجوه، وبالتالي فالجواب الصحيح هو C، إنه الطفل طبعا
+
+26
+00:01:52,750 --> 00:01:56,590
+هيتحرك moves towards ... هي ال ... هذا ال ... ال ...
+
+27
+00:01:56,590 --> 00:02:00,990
+الطفل يتحرك إلى الداخل، المركب هتتحرك ناحية
+
+28
+00:02:00,990 --> 00:02:04,490
+الشاطئ، العكس ... عكس حركة الطفل، لأن كمية التحرك
+
+29
+00:02:04,490 --> 00:02:08,250
+كمية محفوظة في هذه الحالة، إذا الجواب C هو الجواب
+
+30
+00:02:08,250 --> 00:02:14,550
+الصحيح، إنه طبعا ال ... المركب هذه هتتحرك اللي هي ال
+
+31
+00:02:14,550 --> 00:02:18,010
+raft، بيسموها floating raft، هتتحرك towards the
+
+32
+00:02:18,010 --> 00:02:21,730
+shore، اللي هو ناحية الشاطئ، اللي هو جواب C طبعا
+
+33
+00:02:21,730 --> 00:02:26,750
+هذا ال quiz يعني بنحلها عن طريق اللي هي
+
+34
+00:02:26,750 --> 00:02:30,970
+conservation of momentum، كمية ال ... اللي هي حفظ
+
+35
+00:02:30,970 --> 00:02:37,310
+كمية التحرك. ننتقل لـ section 6.3، العنوان collision in
+
+36
+00:02:37,310 --> 00:02:42,550
+one dimension، تصادمات في اتجاه واحد أو بعد واحد. We
+
+37
+00:02:42,550 --> 00:02:46,050
+have seen that for any type of collision، بنلاحظ
+
+38
+00:02:46,050 --> 00:02:50,790
+أنه أي، يعني في أي نوع من التصادمات، كمية التحرك كل
+
+39
+00:02:50,790 --> 00:02:56,210
+أنواع التصادمات، كمية التحرك فيها محفوظة، يعني اللي
+
+40
+00:02:56,210 --> 00:02:59,150
+هي الـ momentum before بيساوي الـ momentum after.
+
+41
+00:02:59,150 --> 00:03:02,230
+before the collision equals the total momentum
+
+42
+00:03:02,230 --> 00:03:05,050
+just after the collision, as long as the system may
+
+43
+00:03:05,050 --> 00:03:10,580
+be considered isolated. إذا اتفقنا أنه في جميع أنواع
+
+44
+00:03:10,580 --> 00:03:15,800
+التصادمات، اللي هي total momentum، كمية التحرك الكلي
+
+45
+00:03:15,800 --> 00:03:21,240
+لأي نظام قبل، بيساوي كمية التحرك بعد التصادم. هذا
+
+46
+00:03:21,240 --> 00:03:24,840
+النظام بيسمى isolated، يعني مفصول أو ما فيش قوة
+
+47
+00:03:24,840 --> 00:03:30,160
+خارجية مؤثرة عليه. The total kinetic energy، اللي هي
+
+48
+00:03:30,160 --> 00:03:35,840
+مجموع طاقة الحركة بصفة عامة، يعني أو يعني من
+
+49
+00:03:35,840 --> 00:03:40,610
+وجهة نظر أخرى، هي التي بتحدد نوع التصادم. In
+
+50
+00:03:40,610 --> 00:03:43,490
+generally not conserved in a collision because
+
+51
+00:03:43,490 --> 00:03:46,390
+some of the kinetic energy is converted to internal
+
+52
+00:03:46,390 --> 00:03:50,870
+energy. لأنه طاقة الحركة ممكن تتحول إلى طاقة داخلية
+
+53
+00:03:50,870 --> 00:03:57,230
+زي مثلا طاقة الصوت، أو طاقة مثلا ممكن يعني نفسرها
+
+54
+00:03:57,230 --> 00:04:04,670
+بأنّه يكون الـ work needed to permanently deform
+
+55
+00:04:04,670 --> 00:04:10,430
+ممكن يصير عندنا تشوّه كامل هذا بعد التصادم، وبالتالي
+
+56
+00:04:10,430 --> 00:04:15,110
+يعني ممكن أنّه ... يعني هذه طاقة الحركة هي التي
+
+57
+00:04:15,110 --> 00:04:19,310
+تأثرت على ... هي التي تأثرت على نوع الـ ... أو هي
+
+58
+00:04:19,310 --> 00:04:23,090
+التي اتحدد نوع التصادم. طاقة الحركة هي التي حددت
+
+59
+00:04:23,090 --> 00:04:27,110
+نوع التصادم. ممكن بعد التشوه الذي يصير، يصير عندي
+
+60
+00:04:27,110 --> 00:04:33,270
+فقد في الطاقة. إذا هذا الكلام معناته أنّه الـ sound
+
+61
+00:04:33,270 --> 00:04:37,690
+energy and the work needed to permanently deform
+
+62
+00:04:37,900 --> 00:04:41,960
+the object before، بيعمل تشويه permanently، التشويه
+
+63
+00:04:41,960 --> 00:04:45,200
+دائم، يعني دائما ... يعني التشويه دائما ما بيرجعش في
+
+64
+00:04:45,200 --> 00:04:50,200
+وضعه الأصلي. إذا طبعا ذهب المؤثر أو إذا إحنا أزلنا
+
+65
+00:04:50,200 --> 00:04:54,700
+المؤثر، and such as a car in a car crash، لو الصادمة
+
+66
+00:04:54,700 --> 00:04:57,840
+تصطدمان في بعض، طبعا بعد التصادم بيصير عندك تشوّه
+
+67
+00:04:57,840 --> 00:05:02,340
+كامل. لكن لو مثلا الكرة مطاطة، أنت ضغطتها ورجعت
+
+68
+00:05:02,340 --> 00:05:05,620
+لوضعها الطبيعي، هذا شيء ... هذا ... هذا مختلف. هذا
+
+69
+00:05:05,620 --> 00:05:09,770
+بيسمّيه conserve. We define من خلال هذا الكلام، ممكن
+
+70
+00:05:09,770 --> 00:05:12,810
+أعرف نوعين من التصادم. في عندنا inelastic
+
+71
+00:05:12,810 --> 00:05:15,590
+collision as collision in which momentum is
+
+72
+00:05:15,590 --> 00:05:20,130
+conserved. في الـ inelastic، اللي هي كمية
+
+73
+00:05:20,130 --> 00:05:23,590
+التحرك محفوظة، لكن الـ kinetic energy is not، طاقة
+
+74
+00:05:23,590 --> 00:05:26,990
+الحركة غير محفوظة. The collision of the rubber ball
+
+75
+00:05:26,990 --> 00:05:33,670
+زي ما حكينا، تصادم كرة من المطاط بسطح طبعا جامد أو
+
+76
+00:05:33,670 --> 00:05:41,660
+يابس، hard is inelastic، بسميها التصادم غير مرن، لأنه
+
+77
+00:05:41,660 --> 00:05:46,760
+بعض من ... يعني جزء من ... من طاقة الحركة سوف تفقد. و
+
+78
+00:05:46,760 --> 00:05:50,840
+هذه الكرة ممكن تصير deform during the contact، تصير
+
+79
+00:05:50,840 --> 00:05:54,820
+لها تشوّه خلال التصادم with the surface. When two
+
+80
+00:05:54,820 --> 00:05:57,820
+objects collide and stick together، لو كان عندي
+
+81
+00:05:57,820 --> 00:06:02,910
+أنا جسمين اصطدما مع بعض، ولزقا وتشبكا في بعض، بعد
+
+82
+00:06:02,910 --> 00:06:06,530
+التصادم صارا جسم واحد، بسميه perfect inelastic
+
+83
+00:06:06,530 --> 00:06:13,030
+تصادم تماما غير مرن أو عديم المرونة. كمثال، لو كان عندي
+
+84
+00:06:13,030 --> 00:06:16,350
+two pieces of putty collide، لو كان عندي أنا قطعتين
+
+85
+00:06:16,350 --> 00:06:21,370
+اصطدما في بعض، فبيكون عندي they stick together and
+
+86
+00:06:21,370 --> 00:06:25,210
+move with some common velocity after the collision.
+
+87
+00:06:25,210 --> 00:06:29,430
+يعني لو كان عندي أنا كتلتين اصطدما في بعض، وبعد
+
+88
+00:06:29,430 --> 00:06:35,110
+التصادم مشيا كجسم واحد، بنحكي أنه هذا بسميه الـ
+
+89
+00:06:35,110 --> 00:06:38,930
+perfect in... inelastic، الـ perfect inelastic
+
+90
+00:06:38,930 --> 00:06:45,590
+التصادم عديم المرونة أو تماما غير مرن، زي مثلا اللي هي
+
+91
+00:06:45,590 --> 00:06:49,270
+الألعاب بتاعة الأطفال أو المعجون أو اللي ... اللي
+
+92
+00:06:49,270 --> 00:06:53,720
+هي الـ ... زي اللي في السلسال أو كده. بسميه بعد
+
+93
+00:06:53,720 --> 00:06:57,240
+التصادم، ممكن لو اصطدما مع بعض، بيلتصقا ببعض، و
+
+94
+00:06:57,240 --> 00:07:02,100
+بيمشوا بسرعة مشتركة أو موحدة. بيسموها اللي هي
+
+95
+00:07:02,100 --> 00:07:05,040
+perfect and elastic، and elastic collision، اللي عن
+
+96
+00:07:05,040 --> 00:07:10,380
+التصادم المرن. الـ elastic يعني مرن. في المرن ممكن
+
+97
+00:07:10,380 --> 00:07:14,020
+أعرفها أنّ momentum and kinetic are conserved.
+
+98
+00:07:14,020 --> 00:07:20,110
+بيكون عندي أنا كمية التحرك وطاقة الحركة محفوظة. زي
+
+99
+00:07:20,110 --> 00:07:22,830
+كورة الـ billiard، يعني الكورة ... الكورة الصغيرة
+
+100
+00:07:22,830 --> 00:07:27,230
+عندما ... عندما تصادم في بعض، أو مثلا in the
+
+101
+00:07:27,230 --> 00:07:31,090
+collision of air، تصادم اللي هي الجزيئات بالـ
+
+102
+00:07:31,090 --> 00:07:35,770
+بالحائط تبع الـ أي container at ordinary temperature.
+
+103
+00:07:35,770 --> 00:07:39,470
+لما أنا أزود درجة الحرارة، بيصير عندك تصادم فيه
+
+104
+00:07:39,470 --> 00:07:43,990
+جزيئات أي مادة معينة. هذا بسميه elastic. فيه كمان
+
+105
+00:07:43,990 --> 00:07:47,710
+ممكن اللي ... اللي هي اللي ... اللي ممكن يعني الـ
+
+106
+00:07:47,710 --> 00:07:51,270
+macro... macro، اللي هي الـ ... الـ macroscopic
+
+107
+00:07:51,270 --> 00:07:54,390
+collision، تصادمات اللي بتُرى بالعين المجردة زي
+
+108
+00:07:54,390 --> 00:07:57,570
+اللي مثلا زي ما حكينا، كرة البلياردو، only
+
+109
+00:07:57,570 --> 00:08:02,880
+approximately elastic، اللي هي تصادم مرن، لأنه بيفقد
+
+110
+00:08:02,880 --> 00:08:06,200
+جزء صغير من الـ kinetic energy، وبالتالي اللي هي
+
+111
+00:08:06,200 --> 00:08:10,680
+طاقة الحركة، عفوا طاقة الحركة و الـ momentum، بيسموهم
+
+112
+00:08:10,680 --> 00:08:15,020
+conserved كمان. In the clicking sound when two poles
+
+113
+00:08:15,020 --> 00:08:19,940
+stick to each other، ممكن كمان لو كتلتين اصطدما في بعض
+
+114
+00:08:19,940 --> 00:08:25,360
+بسمّيه perfect elastic collision، بيحدث perfect
+
+115
+00:08:25,360 --> 00:08:29,260
+elastic collision على أي حال، between ... هذا الكلام
+
+116
+00:08:29,260 --> 00:08:33,200
+بيصير بين الـ perfect elastic ... elastic perfect
+
+117
+00:08:33,200 --> 00:08:38,360
+elastic collision، يعني مرن تماما، زي
+
+118
+00:08:38,360 --> 00:08:43,800
+الذي بيصير بين الجزيئات أو اللي هي أو الذرات أو ما
+
+119
+00:08:43,800 --> 00:08:46,780
+دون الذرات، اللي هي subatomic particles، بين
+
+120
+00:08:46,780 --> 00:08:50,620
+الجزيء وبين الـ atom، بين الذرات أو بين اللي هو
+
+121
+00:08:50,620 --> 00:08:54,860
+الجسيمات اللي هي تحت أو دون الذرات. هذا بسميه الـ
+
+122
+00:08:54,860 --> 00:08:58,740
+perfect elastic collision. لو نأخذ تطبيق على هذا
+
+123
+00:08:58,740 --> 00:09:05,310
+الكلام، اللي هو تطبيق بيسمّوه glaucoma testing، تطبيق
+
+124
+00:09:05,310 --> 00:09:08,270
+الذي بيسمّونه الماء الأزرق، اللي هي الـ glaucoma،
+
+125
+00:09:08,270 --> 00:09:12,270
+الماء الأزرق اللي هي بتكون في العين. In practical
+
+126
+00:09:12,270 --> 00:09:17,670
+as a practical application، يعني في تطبيقات
+
+127
+00:09:17,670 --> 00:09:22,570
+حديثة، بدأ أنا أطبق الآن لتصادمات، إيش بيصير وأمتى
+
+128
+00:09:22,570 --> 00:09:26,070
+بستخدمها؟ بستخدمها في فحص الماء الأزرق الذي داخل
+
+129
+00:09:26,070 --> 00:09:32,310
+العين. Un... un... inelastic collision is used to
+
+130
+00:09:32,310 --> 00:09:35,750
+detect glaucoma، زي ما حكينا اللي هو التصادم
+
+131
+00:09:35,750 --> 00:09:40,830
+الغير مرن، الـ inelastic، ممكن أنا أستخدمه
+
+132
+00:09:40,830 --> 00:09:44,410
+لفحص الـ glaucoma. They say هذا الـ glaucoma مرض
+
+133
+00:09:44,410 --> 00:09:49,530
+طبعا بي ... بيصيب العين بضغط كبير داخل العين، بيكون
+
+134
+00:09:49,530 --> 00:09:53,730
+ضغط العين بيزداد وبيؤدي إلى أحيانا العمى، و damage
+
+135
+00:09:53,730 --> 00:09:59,370
+the cells of the retina، اللي هو بيسبب العمى أو يعني إنّه
+
+136
+00:09:59,370 --> 00:10:05,450
+بتؤدي إلى اللي هي تلف خلايا الشبكية. In this
+
+137
+00:10:05,450 --> 00:10:08,910
+application، في هذا النظام، يعني كيف ممكن أن هم
+
+138
+00:10:08,910 --> 00:10:11,930
+يفحصوا؟ الـ medical professionals، اللي هي يعني
+
+139
+00:10:11,930 --> 00:10:16,890
+المهنيون الطبيون بيستخدموا هذا الشيء، اللي فيه جهاز
+
+140
+00:10:16,890 --> 00:10:23,930
+بيسمّوه tonometer. هذا الـ tonometer بيفحص أو بيقيس ضغط
+
+141
+00:10:23,930 --> 00:10:28,010
+داخل العين، بيقيس الضغط داخل العين. كيف قياسه؟ قياس
+
+142
+00:10:28,010 --> 00:10:33,550
+الضغط داخل العين، ممكن أن هذا الجهاز بيطلق بخات من
+
+143
+00:10:33,550 --> 00:10:37,960
+الهواء، يعني بخة من الهواء أو هيك دفعة من الهواء
+
+144
+00:10:37,960 --> 00:10:43,840
+داخل الجدار الداخلي للعين، وبيقيس سرعة ارتداد هذا
+
+145
+00:10:43,840 --> 00:10:49,060
+الهواء بعد ما يصطدم بالجدار الداخلي للعين. فإنا في
+
+146
+00:10:49,060 --> 00:10:54,660
+الحالة الطبيعية أو الضغط الطبيعي، بيكون الضغط طبعا
+
+147
+00:10:54,660 --> 00:10:58,400
+و الـ pulse تبع العين شيء طبيعي وطبعا ضعيف جدا.
+
+148
+00:10:58,400 --> 00:11:04,040
+بيكون ضعيف و ... وبسيط. هذا ... لكن لما يكون في
+
+149
+00:11:04,040 --> 00:11:07,680
+الحالة التي ... التي هي عنده مشاكل، بيكون الـ pulse
+
+150
+00:11:07,680 --> 00:11:13,340
+فيه مشكلة أو بيكون الجدار الذي ... العين طبعا rigid،
+
+151
+00:11:13,340 --> 00:11:17,760
+أنه شوية جاف. هذا الجفاف بيؤدي إلى أن الهواء بيرتد
+
+152
+00:11:17,760 --> 00:11:23,220
+بسرعة كبيرة، وكمان الـ pulse، يعني ضغط العين بيكون
+
+153
+00:11:23,220 --> 00:11:27,440
+قوي. لكن لما يكون في الحالة الطبيعية، بيكون جدار
+
+154
+00:11:27,440 --> 00:11:32,160
+العين رطبا، رطبا، وفي عنده نوع من نوع اسفنجية بيمتص
+
+155
+00:11:32,160 --> 00:11:35,560
+طبعا جزء من الهواء أو ... وبالتالي ارتداده بتكون قليلة.
+
+156
+00:11:35,560 --> 00:11:40,100
+يعني ارتداد الهواء، سرعة الهواء بتكون قليلة، مقارنة
+
+157
+00:11:40,100 --> 00:11:45,940
+بالتي عند عنده مشاكل في العين، وبالتالي
+
+158
+00:11:45,940 --> 00:11:50,320
+الفرق بين أن هذه العين سليمة أو مش سليمة، قوة
+
+159
+00:11:50,320 --> 00:11:55,720
+ارتداد الهواء. لما تكون ضعيفة ومنخفضة، فبيكون طبيعي.
+
+160
+00:11:55,720 --> 00:12:01,340
+لما تكون قوة ارتداد الهواء قوية، فبيصير أنه في مشكلة،
+
+161
+00:12:01,340 --> 00:12:06,720
+أنّه الضغط الداخلي للعين طبعا يزداد. We can summarize
+
+162
+00:12:06,720 --> 00:12:09,140
+the types of collision. بدأنا به طبعا إحنا دي
+
+163
+00:12:09,140 --> 00:12:14,520
+مثال biology، لكن ممكن إحنا نرجع لموضوعنا اللي هو
+
+164
+00:12:14,520 --> 00:12:18,600
+الـ elastic collision، أنواع التصادمات. في عندي تصادم
+
+165
+00:12:18,600 --> 00:12:21,640
+بيسمّوه elastic collision، تصادم مرن، وفي
+
+166
+00:12:21,640 --> 00:12:24,020
+inelastic collision، وفي perfect inelastic
+
+167
+00:12:24,020 --> 00:12:27,330
+collision. الثلاثة هؤلاء. الآن بالنسبة للـ elastic
+
+168
+00:12:27,330 --> 00:12:32,070
+collision، يعني تعريفه أو كيف أنا بدي أميزه؟ Both
+
+169
+00:12:32,070 --> 00:12:34,950
+momentum and kinetic energy are conserved. الـ
+
+170
+00:12:34,950 --> 00:12:38,290
+momentum، كمية التحرك أو الزخم، زائد طاقة الحركة
+
+171
+00:12:38,290 --> 00:12:42,450
+محفوظة. بالنسبة للـ inelastic collision، الـ momentum
+
+172
+00:12:42,450 --> 00:12:46,370
+محفوظ. طبعا حكينا أن جميع التصادمات الـ momentum is
+
+173
+00:12:46,370 --> 00:12:50,830
+conserved، طاقة الحركة is not. في perfect inelastic
+
+174
+00:12:50,830 --> 00:12:56,080
+collision، momentum is... momentum is conserved، و الـ
+
+175
+00:12:56,080 --> 00:12:59,620
+kinetic energy is not، كمية التح
+
+223
+00:16:20,420 --> 00:16:23,300
+kinetic energy is not conserved. طبعاً صار فيه فقط
+
+224
+00:16:23,300 --> 00:16:28,080
+الطاقة وبالتالي كمية التحرك NDP is not conserved.
+
+225
+00:16:28,080 --> 00:16:30,880
+because the total momentum of the two objects
+
+226
+00:16:30,880 --> 00:16:34,080
+in an isolated system before the collision equals the
+
+227
+00:16:34,080 --> 00:16:36,540
+total momentum of the combined object system after
+
+228
+00:16:36,540 --> 00:16:40,160
+the collision. هيكون عندي أنا الـ B initial بنسبة B
+
+229
+00:16:40,160 --> 00:16:44,150
+final. هيكون إن قانون جديد اللي هو اللي هُيُوِّي بالشكل
+
+230
+00:16:44,150 --> 00:16:50,010
+هذا: M1 V1 initial + M2 V2 initial = M1
+
+231
+00:16:50,010 --> 00:16:56,750
++ M2 في V final. لأن الجسمين اتحركوا بطبعاً سرعة
+
+232
+00:16:56,750 --> 00:17:01,550
+واحدة بعد تصادمهما. إذاً V1 final ممكن من هذا القانون
+
+233
+00:17:01,550 --> 00:17:05,490
+طبعاً هذا الحد اللي هو الحدود هذه على الحد هذا بيطلع
+
+234
+00:17:05,490 --> 00:17:10,700
+عندي V final = M1 V1 initial + M2 V2 initial /
+
+235
+00:17:10,700 --> 00:17:16,920
+M1 + M2. طبعاً مهم جداً ملاحظة أن V1 initial و V2
+
+236
+00:17:16,920 --> 00:17:21,980
+initial و V final موجودين بالـ X axis لأنّه حكالي
+
+237
+00:17:21,980 --> 00:17:26,220
+أنّه head on collision. هي head بالـ X axis وبالتالي الـ
+
+238
+00:17:26,220 --> 00:17:28,680
+car is needed to entering their known value
+
+239
+00:17:28,680 --> 00:17:32,080
+practically with regard to sign. معنى الكلام أنّه
+
+240
+00:17:32,080 --> 00:17:37,380
+بتدخل اللي هي الـ ... الـ ... الـ ... الإشارات بعين
+
+241
+00:17:37,380 --> 00:17:41,110
+الاعتبار. يعني اللي رايح على الشرق موجب واللي غرب
+
+242
+00:17:41,110 --> 00:17:44,730
+سالب، أو اللي على اليمين موجب وعلى الشمال سالب، و
+
+243
+00:17:44,730 --> 00:17:48,050
+اللي فوق موجب واللي تحت سالب، لازم آخذها بعين الاعتبار.
+
+244
+00:17:48,050 --> 00:17:51,230
+معنى الكلام أنّ الـ V1 initial هنا كانت positive
+
+245
+00:17:51,230 --> 00:17:56,950
+value، والـ M1 بتتحرك لليمين، والـ V2 initial
+
+246
+00:17:56,950 --> 00:18:00,850
+كانت negative لأنها بتتحرك لليسار. عشان لما أنا
+
+247
+00:18:00,850 --> 00:18:07,170
+أجي أحل لازم احنا نراعي الإشارات. طبعاً example 6-4.
+
+248
+00:18:07,850 --> 00:18:13,550
+Pick up a truck with mass 1.8×10³ kg. شاحنة pick up
+
+249
+00:18:13,550 --> 00:18:19,590
+بيسموها traveling eastbound at ... بتتحرك ناحية الـ
+
+250
+00:18:19,590 --> 00:18:24,530
+east. ناحية الشرق بسرعة 15 متر في الثانية، ولكن
+
+251
+00:18:24,530 --> 00:18:29,010
+compact car. طبعاً في عندي سيارة ثانية زي ما هو
+
+252
+00:18:29,010 --> 00:18:33,170
+موضح بالشكل. السيارة الثانية هيها بتتحرك ناحية
+
+253
+00:18:33,170 --> 00:18:37,650
+اليمين، الـ pick up شاحنة وهنا سيارة بتتحرك ناحية
+
+254
+00:18:37,650 --> 00:18:43,410
+اليسار. الآن السؤال: السيارة كتلتها تسعة في عشرة أُسّ
+
+255
+00:18:43,410 --> 00:18:47,230
+اثنين، traveling west ناحية الغرب بسرعة ناقص
+
+256
+00:18:47,230 --> 00:18:50,610
+خمسة عشر، لأنها ناحية الغرب، عشان هي طبعاً رايحة ناحية
+
+257
+00:18:50,610 --> 00:18:55,890
+الغرب، أخذنا سالب. the vehicles، العربتين صدموا في
+
+258
+00:18:55,890 --> 00:19:01,950
+بعض head on بالضبط. يعني اجت صادم، becoming طبعاً in
+
+259
+00:19:01,950 --> 00:19:08,240
+angle. صاروا صدموا في بعض، صاروا كتلة واحدة. find
+
+260
+00:19:08,240 --> 00:19:10,660
+the speed of the entangled vehicle after the
+
+261
+00:19:10,660 --> 00:19:16,000
+collision. بدي أنا سرعتهم بعد التصادم عشان أوجد
+
+262
+00:19:16,000 --> 00:19:20,680
+سرعتهم بعد التصادم. find the final speed after the
+
+263
+00:19:20,680 --> 00:19:24,800
+collision. طبعاً بدي أفرض أنّ أم واحد لها V واحد
+
+264
+00:19:24,800 --> 00:19:29,460
+رايحة ناحية اليمين، وأم اثنين V اثنين ناحية اليسار.
+
+265
+00:19:29,760 --> 00:19:34,920
+بدنا نيجي نعوض، نعوض الآن: B initial = B final
+
+266
+00:19:34,920 --> 00:19:40,380
+طبعاً باتجاه الـ X axis. B واحد: M واحد في V واحد، هيها
+
+267
+00:19:40,380 --> 00:19:43,400
+واحد فاصلة ثمانية في عشرة أُسّ ثلاثة، و سرعتها كانت
+
+268
+00:19:43,400 --> 00:19:46,940
+خمسة عشر. M اثنين للسيارة: تسعة في عشرة أُسّ اثنين
+
+269
+00:19:46,940 --> 00:19:50,740
+kilogram، و سرعتها ناقص خمسة عشر، نروح ناحية اليسار.
+
+270
+00:19:50,740 --> 00:19:54,520
+بدها تساوي M واحد للـ truck: واحد فاصلة ثمانية في
+
+271
+00:19:54,520 --> 00:20:00,180
+عشرة أُسّ ثلاثة، و M2: تسعة في عشرة أُسّ اثنين للسيارة، و
+
+272
+00:20:00,180 --> 00:20:03,820
+بوجد V final اللي هي السرعة المشتركة للجهتين.
+
+273
+00:20:03,820 --> 00:20:08,260
+طبعاً ... طبعاً هم خبطوا في بعض والتسقوا في بعض
+
+274
+00:20:08,260 --> 00:20:12,080
+فالسرعة النهائية حتكون موجبة، إذاً هم هيتحركوا
+
+275
+00:20:12,080 --> 00:20:17,320
+باتجاه الـ X axis الموجب. الآن find the change in
+
+276
+00:20:17,320 --> 00:20:20,620
+the velocity for each vehicle. بدي التغير في السرعة
+
+277
+00:20:20,620 --> 00:20:25,910
+ل ... للجهتين. فبدنا نوجد للـ pick up، للـ truck
+
+278
+00:20:25,910 --> 00:20:31,070
+للشاحنة: delta V1 = V final - V initial. V
+
+279
+00:20:31,070 --> 00:20:34,070
+final كانت خمسة اللي هي المشتركة، والـ initial كانت خمسة عشر.
+
+280
+00:20:34,070 --> 00:20:39,210
+بيطلع minus عشرة. و delta V final للسيارة اللي هي
+
+281
+00:20:39,210 --> 00:20:43,150
+الـ change in the plus، التغير في السرعة delta V2
+
+282
+00:20:43,150 --> 00:20:47,510
+بتساوي V final - V initial. V2 initial: خمسة ناقص
+
+283
+00:20:47,510 --> 00:20:51,700
+ناقص الـ خمسة عشر، لازم آخذها بعين الاعتبار، بتطلع عشرين. إذاً
+
+284
+00:20:51,700 --> 00:20:54,940
+هذه delta V للـ truck، وهذه delta V للسيارة. في
+
+285
+00:20:54,940 --> 00:20:59,940
+السؤال C مطلوب: find، أوجد the change in kinetic
+
+286
+00:20:59,940 --> 00:21:03,800
+energy of the system. بدي طبعاً التغير في طاقة
+
+287
+00:21:03,800 --> 00:21:09,960
+الحركة للنظام. إذاً Delta K initial أو K initial
+
+288
+00:21:09,960 --> 00:21:14,660
+بالأول اللي هي: نصف M1 V1 initial تربيع + نصف M2
+
+289
+00:21:14,660 --> 00:21:20,360
+V2 initial تربيع. الـ M1 للـ truck كانت 1.8×10³، V1
+
+290
+00:21:20,360 --> 00:21:27,580
+initial كانت خمسة عشر. + نصف M2 اللي هي تسعة، V2 initial
+
+291
+00:21:27,580 --> 00:21:32,220
+تربيع، بساوي ناقص خمسة عشر، طبعاً لكل تربيع بيطلع الجواب K
+
+292
+00:21:32,220 --> 00:21:38,720
+initial، kinetic energy initial: 3.04×10⁵ joule.
+
+293
+00:21:38,720 --> 00:21:43,040
+هأوجد، calculate the final kinetic energy of the
+
+294
+00:21:43,040 --> 00:21:47,870
+system. النهائية. delta K final،  الآن الـ final طبعاً
+
+295
+00:21:47,870 --> 00:21:53,490
+نصف M1 + M2 V2 تربيع، أو ممكن نحكي: نصف M1 V1 تربيع
+
+296
+00:21:53,490 --> 00:21:57,790
+final + نصف M2 V2 تربيع final. و V final تربيع
+
+297
+00:21:57,790 --> 00:22:00,650
+للتحريك المشتركة. وبالتالي إذا ممكن أستخدم هذا
+
+298
+00:22:00,650 --> 00:22:08,090
+القانون: نصف M1 (1.8×10³) للـ truck + M2 للسيارة
+
+299
+00:22:08,090 --> 00:22:13,570
+(9×10²) في V final تربيع،  لمية للجميع اللي هي خمسة
+
+300
+00:22:13,570 --> 00:22:18,270
+تربيع. بيطلع عندي kinetic energy final: ثلاثة فاصلة
+
+301
+00:22:18,270 --> 00:22:21,930
+ثلاثة ثمانية. لما أجي أحكي delta K E، تغير في طاقة
+
+302
+00:22:21,930 --> 00:22:25,630
+الحركة اللي هي K final - K initial، بيطلع عندي
+
+303
+00:22:25,630 --> 00:22:29,410
+سالب. معنى الكلام في عندي أنا فقد في الطاقة
+
+304
+00:22:29,410 --> 00:22:35,530
+وبالتالي هذا عندي اللي هو ال ... ال ... تصادمهما
+
+305
+00:22:35,530 --> 00:22:43,170
+بيسموه inelastic ... inelastic collision. طبعاً في
+
+306
+00:22:43,170 --> 00:22:49,090
+هذا السؤال في عندي ballistic pendulum، في عندي بندول
+
+307
+00:22:49,090 --> 00:22:55,630
+ballistic، جهاز devices use a measure، لازم بيقيس سرعة
+
+308
+00:22:55,630 --> 00:23:01,580
+مقذوفة زي الرصاصة دخلت فيه،البيوليت يعني الرصاصة is
+
+309
+00:23:01,580 --> 00:23:05,560
+fired into a large block of wood. هاي الرصاصة
+
+310
+00:23:05,560 --> 00:23:14,340
+ضربناها أو قذفناها داخل ناحية خشبة كبيرة معلقة بخط
+
+311
+00:23:14,340 --> 00:23:20,580
+خفيف، معلقة بخط خفيف. الرصاصة سكنت في الخشبة وظلت
+
+312
+00:23:20,580 --> 00:23:26,220
+فيها وارتفعت مسافة. assume that the
+
+313
+00:23:26,220 --> 00:23:29,340
+mass of the bullet، كتلة الرصاصة كانت خمسة جرام
+
+314
+00:23:29,800 --> 00:23:34,560
+وكتلة الخشبة كانت واحد كيلو، والارتفاع اللي وصلته
+
+315
+00:23:34,560 --> 00:23:37,940
+خمسة. find the velocity of the system after the
+
+316
+00:23:37,940 --> 00:23:43,300
+bullet embeds in the block. بدّه السرعة ... سرعة
+
+317
+00:23:43,300 --> 00:23:48,080
+النظام بعد ما ... ما الخشبة دخلت في اللي هو
+
+318
+00:23:48,080 --> 00:23:52,200
+الرصاصة دخلت في الخشبة وطلعوا مسافة. هي رصاصة
+
+319
+00:23:52,200 --> 00:23:57,840
+بتمشي بسرعة معينة V initial، هنا الخشبة ثابتة، الخشب
+
+320
+00:23:57,840 --> 00:24:03,140
+واحد kilogram، هذه خمسين ك ... خمسة و خمسين gram، أو
+
+321
+00:24:03,140 --> 00:24:07,740
+الرصاصة كتلتها ... الرصاصة كتلتها خمس ... لحظة
+
+322
+00:24:07,740 --> 00:24:13,480
+الرصاصة كتلتها كانت خمسة gram. الآن نيجي نحل ...
+
+323
+00:24:13,480 --> 00:24:18,820
+بدنا نحل هذا السؤال: find the velocity of the
+
+324
+00:24:18,820 --> 00:24:21,860
+system after the bullet embeds in the block. بدأ
+
+325
+00:24:21,860 --> 00:24:25,050
+أستخدم، apply conservation of energy، بين الـ block و
+
+326
+00:24:25,050 --> 00:24:27,330
+الـ bullet، الـ block يعني الخشبة، و bullet يعني
+
+327
+00:24:27,330 --> 00:24:30,750
+الرصاصة. هنحكي أنّ طاقة الحركة أو kinetic energy +
+
+328
+00:24:30,750 --> 00:24:35,170
+potential energy after the collision بدها تساوي الـ
+
+329
+00:24:35,170 --> 00:24:37,450
+kinetic energy + الـ potential energy at the top
+
+330
+00:24:37,450 --> 00:24:41,110
+على ارتفاع H. أنا بدي أوجد اللي ... اللي هي السرعة
+
+331
+00:24:41,110 --> 00:24:44,390
+الابتدائية اللي هي بعد التصادم، لكن تعتبر في
+
+332
+00:24:44,390 --> 00:24:47,810
+المرحلة هذه ابتدائية. substitute expression for the
+
+333
+00:24:47,810 --> 00:24:50,650
+kinetic energy and potential energy. طبعاً بستخدم
+
+334
+00:24:50,650 --> 00:24:54,690
+طاقة الحركة أو طاقة الوضع في الحالة هذه، الـ after
+
+335
+00:24:54,690 --> 00:24:57,650
+collision اللي هي تعتبر initial لمرحلة ما بعد
+
+336
+00:24:57,650 --> 00:25:01,930
+التصادم. هنحكي: نصف M1 + M2 لأنّ الرصاصة دخلت في
+
+337
+00:25:01,930 --> 00:25:07,210
+الخشبة في v للنظام كله تربيع + zero اللي هي
+
+338
+00:25:07,210 --> 00:25:09,990
+طاقة الوضع zero عشانها على level، بتساوي طاقة
+
+339
+00:25:09,990 --> 00:25:16,190
+الحركة وصلت أقصى ارتفاع H.  0 + M1 + M2 في G في
+
+340
+00:25:16,190 --> 00:25:19,990
+H. طبعاً الـ M حتروح مع الـ M، بيبقى عندي الـ V =
+
+341
+00:25:19,990 --> 00:25:25,450
+جذر 2GH زي ما كنا ندرس سابقاً، والـ G تسعة فاصلة ثمانية
+
+342
+00:25:25,450 --> 00:25:32,310
+من عشرة، والـ H وصلت أقصى ارتفاع بساوي خمسة طبعاً
+
+343
+00:25:32,310 --> 00:25:37,070
+خمسة سانتي، يعني ضربناها في عشرة أُسّ ناقص اثنين عشان
+
+344
+00:25:37,070 --> 00:25:40,610
+نحوّلها لمتر لأنّ الـ G متر في الثانية تربيع، بيطلع
+
+345
+00:25:40,610 --> 00:25:45,140
+اللي هي الـ V للنظام كله: صفر فاصلة تسعة تسعة. هذا بعد التصادم.
+
+346
+00:25:45,140 --> 00:25:48,880
+الآن عشان أوجد الـ initial speed، بدي السرعة
+
+347
+00:25:48,880 --> 00:25:54,640
+الابتدائية ل ... ل ... للبيوليت طبعاً قبل التصادم
+
+348
+00:25:54,640 --> 00:25:59,920
+راح نستخدم conservation of momentum، قانون حفظ كمية
+
+349
+00:25:59,920 --> 00:26:05,200
+التحرك. هأحكي: P initial = P final. الـ P initial
+
+350
+00:26:05,200 --> 00:26:09,880
+M1 في V1 initial هي للرصاصة + M2 الـ V2 initial هي
+
+351
+00:26:09,880 --> 00:26:15,290
+للخشبة. بتساوي M1 + M2 في V للنظام كله. V2
+
+352
+00:26:15,290 --> 00:26:19,490
+initial كانت zero للخشبة، كانت ثابتة. M1 للرصاصة
+
+353
+00:26:19,490 --> 00:26:25,010
+خمسة مقسومة على ألف عشان تصير بالكيلو، هيها خمسة في
+
+354
+00:26:25,010 --> 00:26:31,110
+عشرة أُسّ ناقص ثلاثة كيلو، و V1 initial بدي إياها مجهولة.
+
+355
+00:26:31,110 --> 00:26:36,590
+M2 كانت zero. إذاً V1 initial بتساوي M1 + M2 هذا
+
+356
+00:26:36,590 --> 00:26:41,500
+ضرب V1 initial بتساوي M1 + M2 في V system على
+
+357
+00:26:41,500 --> 00:26:47,940
+اللي هي الـ M1. تطلع سرعة الرصاصة: 199 متر في الثانية.
+
+358
+00:26:47,940 --> 00:26:52,240
+عشان هي سرعتها كبيرة كتير كانت وسكنت في الخشبة.
+
+359
+00:26:52,240 --> 00:26:57,720
+بنستكمل في التسجيل اللي طبعاً التالي.
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..33e41268de8e4d404d943c5c3effa858e24daa48
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo_postprocess.srt
@@ -0,0 +1,1436 @@
+1
+00:00:01,200 --> 00:00:04,720
+بسم الله الرحمن الرحيم بنستكمل أيضا chapter 6
+
+2
+00:00:04,720 --> 00:00:10,020
+بنبدأ ب quiz 6-2 بيحكينا أن a boy standing at one
+
+3
+00:00:10,020 --> 00:00:12,780
+end of floating raft that is stationary relative
+
+4
+00:00:12,780 --> 00:00:15,680
+to the shore walks to the opposite end of the raft
+
+5
+00:00:15,680 --> 00:00:21,660
+معناها أنه في عندنا ولد أو طفل بيقف على حافة مركب
+
+6
+00:00:21,660 --> 00:00:26,100
+المركب ها دي لها حافتين حافة الأولى ناحية الشاطئ و
+
+7
+00:00:26,100 --> 00:00:30,270
+الحافة التانية داخل البحر أو داخل الميهالآن الطفل
+
+8
+00:00:30,270 --> 00:00:35,170
+يقف على إحدى الحواف، على الحافة اللي ناحية الشاطئ،
+
+9
+00:00:35,170 --> 00:00:40,550
+الآن هي المركب طبعا ثابتة بالنسبة للشاطئ، الآن
+
+10
+00:00:40,550 --> 00:00:44,250
+الولد بده يمشي من الحافة اللي ناحية الشاطئ ويدخل
+
+11
+00:00:44,250 --> 00:00:48,270
+لجوا، للحافة التانية، walks to the opposite end of
+
+12
+00:00:48,270 --> 00:00:53,450
+the raft، هو ميشي للطرف التاني المقابلطبعا الطرف
+
+13
+00:00:53,450 --> 00:00:57,590
+الأولاني ناحية الشاطئ هو واقف ناحية الشاطئ و هيمشي
+
+14
+00:00:57,590 --> 00:01:01,210
+على الطرف التاني للمركب اللي داخل البحر away from
+
+15
+00:01:01,210 --> 00:01:06,070
+the shore طبعا بعيدا عن الشاطئ الآن هذه الحركة لو
+
+16
+00:01:06,070 --> 00:01:10,130
+تخيلناها و بيسألنا السؤال بيحكي as the consequence
+
+17
+00:01:10,130 --> 00:01:16,570
+من أن عليه the raft طبعا هي المركب الصغيرة او ال
+
+18
+00:01:16,570 --> 00:01:20,910
+.. طبعا اللي بيسموها الحسكة او الطوافة هل هي هتظل
+
+19
+00:01:20,910 --> 00:01:27,550
+ثابتةأم تتحرك ناحية الشاطئ أم تتحرك towards the
+
+20
+00:01:27,550 --> 00:01:31,550
+shore هتتحرك من الشاطئ لجوة ولا هتتحرك ناحية
+
+21
+00:01:31,550 --> 00:01:35,590
+الشاطئ ولا هتدل ثابتة الآن الطفل هيتحرك من الشاطئ
+
+22
+00:01:35,590 --> 00:01:40,270
+ويدخل لجوة بناء عليه طبعا الجواب ال .. ال ..
+
+23
+00:01:40,270 --> 00:01:43,570
+البركب هذا الصغير هتتحرك العكس إذا .. إذا الطفل
+
+24
+00:01:43,570 --> 00:01:47,870
+دخل لجوة هي هتتحرك العكسإذا الطفل طلع لبره، هيتحرك
+
+25
+00:01:47,870 --> 00:01:52,750
+لجوه، وبالتالي فالجواب الصحيح هو C إنه الطفل طبعا
+
+26
+00:01:52,750 --> 00:01:56,590
+هيتحرك moves towards .. هي ال .. هذا ال .. ال ..
+
+27
+00:01:56,590 --> 00:02:00,990
+الطفل يتحرك إلى الداخل، المركب هتتحرك راهية
+
+28
+00:02:00,990 --> 00:02:04,490
+الشاطر، العكس .. عكس حركة الطفل، لإن كمية التحرك
+
+29
+00:02:04,490 --> 00:02:08,250
+كمية محفوظة في هذه الحالة، إذا الجواب C هو الجواب
+
+30
+00:02:08,250 --> 00:02:14,550
+الصح، إنه طبعا ال .. المركب هاديهتتحرك اللي هي ال
+
+31
+00:02:14,550 --> 00:02:18,010
+raft بيسموها floating raft هتتحرك towards the
+
+32
+00:02:18,010 --> 00:02:21,730
+shore اللي هو ناحية الشاطر اللي هو جواب HC طبعا
+
+33
+00:02:21,730 --> 00:02:26,750
+هذا ال quiz يعني بنحلها عن طريق اللي هي
+
+34
+00:02:26,750 --> 00:02:30,970
+conservation of momentum كمية ال .. اللي هي حفظ
+
+35
+00:02:30,970 --> 00:02:37,310
+كمية التحرك نجلة section 6 3 العنوان collision in
+
+36
+00:02:37,310 --> 00:02:42,550
+one dimension تصادمات في اتجاه واحد أو بعد واحدwe
+
+37
+00:02:42,550 --> 00:02:46,050
+have seen that for any type of collision بنلاحظ
+
+38
+00:02:46,050 --> 00:02:50,790
+أنه أي يعني في أي نوع من التصادمات كمية التحرك كل
+
+39
+00:02:50,790 --> 00:02:56,210
+أنواع التصادمات كمية التحرك فيها محفوظة يعني اللي
+
+40
+00:02:56,210 --> 00:02:59,150
+هي ال momentum before بيساوي ال momentum after
+
+41
+00:02:59,150 --> 00:03:02,230
+before the collision equals the total momentum
+
+42
+00:03:02,230 --> 00:03:05,050
+just after the collision as long as the system may
+
+43
+00:03:05,050 --> 00:03:10,580
+be considered isolated إذا اتفقنا أنهفي جميع أنواع
+
+44
+00:03:10,580 --> 00:03:15,800
+التصادمات اللي هي total momentum كمية التحرك الكلي
+
+45
+00:03:15,800 --> 00:03:21,240
+لأي نظام قبل بيساوي كمية التحرك بعد التصادم هذا
+
+46
+00:03:21,240 --> 00:03:24,840
+النظام بيسمي isolated يعني مفصول أو مافيش قوة
+
+47
+00:03:24,840 --> 00:03:30,160
+خارجية مؤثرة عليه the total kinetic energy اللي هي
+
+48
+00:03:30,160 --> 00:03:35,840
+المجموعة لطاقة الحركة بصفة عامة يعني او يعني من
+
+49
+00:03:35,840 --> 00:03:40,610
+وجهة نظر أخرى هي اللي بتحددنوع اتصادهم in
+
+50
+00:03:40,610 --> 00:03:43,490
+generally not conserved in a collision because
+
+51
+00:03:43,490 --> 00:03:46,390
+some of the kinetic energy is converted internal
+
+52
+00:03:46,390 --> 00:03:50,870
+energy لإنه طاقة الحركة ممكن تتحول إلى طاقة داخلية
+
+53
+00:03:50,870 --> 00:03:57,230
+زي مثلا طاقة الصوت أو طاقة مثلا ممكن يعني نفسرها
+
+54
+00:03:57,230 --> 00:04:04,670
+بيه أنه يكون ال work needed to permanently deform
+
+55
+00:04:04,670 --> 00:04:10,430
+ممكن يصير عندنا تشوه كاملهذا بعد التصادم وبالتالي
+
+56
+00:04:10,430 --> 00:04:15,110
+يعني ممكن انه .. يعني هذه طاقة الحركة هي اللي
+
+57
+00:04:15,110 --> 00:04:19,310
+اتأثر على .. هي اللي اتأثر على نوع اللي .. او هي
+
+58
+00:04:19,310 --> 00:04:23,090
+اللي اتحدد نوع التصادم طاقة الحركة هي اللي اتحدد
+
+59
+00:04:23,090 --> 00:04:27,110
+نوع التصادم ممكن بعد التشوه اللي يصير يصير اندي
+
+60
+00:04:27,110 --> 00:04:33,270
+فقد في الطاقة اذا هذا الكلام معناته انه ال sound
+
+61
+00:04:33,270 --> 00:04:37,690
+energy and the work needed to permanently deform
+
+62
+00:04:37,900 --> 00:04:41,960
+the object before بيعمل تشويه permanently التشويه
+
+63
+00:04:41,960 --> 00:04:45,200
+دائم يعني دائما ..يعني التشويه دائما مابيرجعش في
+
+64
+00:04:45,200 --> 00:04:50,200
+وضعه العصلي اذا طبعا ذهب المؤثر او اذا احنا ازلنا
+
+65
+00:04:50,200 --> 00:04:54,700
+المؤثر and such as a car in a car crash لو الصادمة
+
+66
+00:04:54,700 --> 00:04:57,840
+تصيرتان في بعض طبعا بعد التصادم بيصير عندك تشوه
+
+67
+00:04:57,840 --> 00:05:02,340
+كامل لكن لو مثلا الكورة مطاطة انت ضغطت ورجعت
+
+68
+00:05:02,340 --> 00:05:05,620
+لوضعها الطبيعي هذا اشي .. هذا .. هذا مختلف هذا
+
+69
+00:05:05,620 --> 00:05:09,770
+بيسميه conservewe define من خلال هذا الكلام ممكن
+
+70
+00:05:09,770 --> 00:05:12,810
+اعرف إلى نوعين من التصادم في عندنا inelastic
+
+71
+00:05:12,810 --> 00:05:15,590
+collision as collision in which momentum is
+
+72
+00:05:15,590 --> 00:05:20,130
+conserved inelastic في ال inelastic اللي هي كمية
+
+73
+00:05:20,130 --> 00:05:23,590
+التحرك محفوظة لكن ال kinetic energy is not تقط
+
+74
+00:05:23,590 --> 00:05:26,990
+الحركة غير محفوظة the collision of the rubber ball
+
+75
+00:05:26,990 --> 00:05:33,670
+زي ما حكينا تصادم كرة من المطاط بسطح طبعا جامد أو
+
+76
+00:05:33,670 --> 00:05:41,660
+يابس hardis inelastic بسميها التصادم غير مرين لإنه
+
+77
+00:05:41,660 --> 00:05:46,760
+بعض من .. يعني جزء من .. من طقس الحركة سوف تفقد و
+
+78
+00:05:46,760 --> 00:05:50,840
+هاي الكرة ممكن تصير deform during the contact تصير
+
+79
+00:05:50,840 --> 00:05:54,820
+لها تشويه خلال التصادم with the surface when two
+
+80
+00:05:54,820 --> 00:05:57,820
+object is collide and stick together لو كان عندي
+
+81
+00:05:57,820 --> 00:06:02,910
+أنا جسمين اصطدموا مع بعض و لزقوا وتسقوا في بعضبعد
+
+82
+00:06:02,910 --> 00:06:06,530
+التصادم صاروا جسم واحد بسميه perfect inelastic
+
+83
+00:06:06,530 --> 00:06:13,030
+تصادم تم المرونة أو عديم المرونة كمثال لو كان عندي
+
+84
+00:06:13,030 --> 00:06:16,350
+two pieces of putty collide لو كان عندي أنا قطعتين
+
+85
+00:06:16,350 --> 00:06:21,370
+أصطدموا في بعض فبيكون عندي they stick together and
+
+86
+00:06:21,370 --> 00:06:25,210
+move with some common velocity after the collision
+
+87
+00:06:25,210 --> 00:06:29,430
+يعني لو كان عندي أنا كتلتين أصطدموا في بعض وبعد
+
+88
+00:06:29,430 --> 00:06:35,110
+التصادم مشيوا كجسم واحدبنحكي أنه هذا بسميه ال
+
+89
+00:06:35,110 --> 00:06:38,930
+perfect in .. in elastic ال perfect in elastic
+
+90
+00:06:38,930 --> 00:06:45,590
+التصادم عديم المرونة أو تم المرونة زي مثلا اللي هي
+
+91
+00:06:45,590 --> 00:06:49,270
+الألعاب بتاعة الأطفال أو المعجون أو اللي .. اللي
+
+92
+00:06:49,270 --> 00:06:53,720
+هي ال .. زي اللي في السلسال أو كدهبسميه بعد
+
+93
+00:06:53,720 --> 00:06:57,240
+التصادم ممكن لو صدموا مع بعض بيلتسقوا ببعض و
+
+94
+00:06:57,240 --> 00:07:02,100
+بيمشوا بسرعة مشتركة أو موحدة بيسموها اللي هي
+
+95
+00:07:02,100 --> 00:07:05,040
+perfect and elastic and elastic collision اللي عن
+
+96
+00:07:05,040 --> 00:07:10,380
+التصادم المرن ال elastic يعني مرن في المرن ممكن
+
+97
+00:07:10,380 --> 00:07:14,020
+اعرفها that انه momentum and kinetic AR concert
+
+98
+00:07:14,020 --> 00:07:20,110
+بيكون عندي أنا كمية التحرك و طاقة الحركة محفوظةزي
+
+99
+00:07:20,110 --> 00:07:22,830
+كورة الـ billiard يعني الكورة .. الكورة الصغيرة
+
+100
+00:07:22,830 --> 00:07:27,230
+عندما .. عندما تصادم في بعض أو مثلا in the
+
+101
+00:07:27,230 --> 00:07:31,090
+collision of air تصادم اللي هي الجزيئات بال ..
+
+102
+00:07:31,090 --> 00:07:35,770
+بالحائط تبع ال أي containerat ordinary temperature
+
+103
+00:07:35,770 --> 00:07:39,470
+لما انا ازود درجة الحرارة بيصير انت تصادم فيه
+
+104
+00:07:39,470 --> 00:07:43,990
+جزيئات اي مادة معينة هذا بيسميه elastic فيه كمان
+
+105
+00:07:43,990 --> 00:07:47,710
+ممكن اللي .. اللي هي اللي .. اللي ممكن يعني ال
+
+106
+00:07:47,710 --> 00:07:51,270
+macro .. macro اللي هي ال .. ال macroscopic
+
+107
+00:07:51,270 --> 00:07:54,390
+collision تصادمات اللي بتورا بالعين المجردة زي
+
+108
+00:07:54,390 --> 00:07:57,570
+اللي مثلا زي ما حكينا كورة البلياردو only
+
+109
+00:07:57,570 --> 00:08:02,880
+approximately elastic اللي هي تصادم مرنلإنه بيفقد
+
+110
+00:08:02,880 --> 00:08:06,200
+جزء صغير من ال kinetic energy وبالتالي اللي هي
+
+111
+00:08:06,200 --> 00:08:10,680
+طاقة الحركة عفوا طاقة الحركة و ال momentum بيسموهم
+
+112
+00:08:10,680 --> 00:08:15,020
+concert كمان in the clicking sound when two poles
+
+113
+00:08:15,020 --> 00:08:19,940
+stick each other ممكن كمان لو كتلتين صدموا في بعض
+
+114
+00:08:19,940 --> 00:08:25,360
+بسميه perfect elastic collision بيحدث perfect
+
+115
+00:08:25,360 --> 00:08:29,260
+elastic collision على أي حال between .. هذا الكلام
+
+116
+00:08:29,260 --> 00:08:33,200
+بيصير بينال perfect elastic .. elastic perfect
+
+117
+00:08:33,200 --> 00:08:38,360
+elastic collision يعني marine اتام قرونة تامة زي
+
+118
+00:08:38,360 --> 00:08:43,800
+اللي بيصير بين الجزيئات او اللي هي او الظرات او ما
+
+119
+00:08:43,800 --> 00:08:46,780
+دون الظرات اللي هي sub atomic particle بين
+
+120
+00:08:46,780 --> 00:08:50,620
+الموليكول و بين ال atom بين الظرات او بين اللي هو
+
+121
+00:08:50,620 --> 00:08:54,860
+الجسمات اللي هي تحت او دون الظرات هذا بسميه ال
+
+122
+00:08:54,860 --> 00:08:58,740
+perfect elastic collision لو ناخد تطبيق على هذا
+
+123
+00:08:58,740 --> 00:09:05,310
+الكلاماللي هو تطبيق بيسموه gelocoma testing تطبيق
+
+124
+00:09:05,310 --> 00:09:08,270
+اللي بيسمونه الماء الزرقاء اللي هي ال gelocoma
+
+125
+00:09:08,270 --> 00:09:12,270
+الماء الزرقاء اللي هي بتكون في العين in practical
+
+126
+00:09:12,270 --> 00:09:17,670
+in as a practical application يعني في تطبيقات
+
+127
+00:09:17,670 --> 00:09:22,570
+حديثة بدأ أنا أطبق الآن لتصادمات إيش بيصير و أمتى
+
+128
+00:09:22,570 --> 00:09:26,070
+بستخدمها بستخدمها في فحص الماء الزرقاء اللي داخل
+
+129
+00:09:26,070 --> 00:09:32,310
+العينun .. un .. inelastic collagen is used to
+
+130
+00:09:32,310 --> 00:09:35,750
+detect the gelocoma زي ما حكينا اللي هو التصادم
+
+131
+00:09:35,750 --> 00:09:40,830
+الاش ال inelastic الغير marine ممكن أنا أستخدمه
+
+132
+00:09:40,830 --> 00:09:44,410
+للفحص ال gelocoma they sees هذا ال gelocoma مرض
+
+133
+00:09:44,410 --> 00:09:49,530
+طبعا بي .. بيصيب العين بضغط كبير داخل العين بيكون
+
+134
+00:09:49,530 --> 00:09:53,730
+ضغط العين بزداد و بيقدي إلى أحيانا العمى و damage
+
+135
+00:09:53,730 --> 00:09:59,370
+the cell of retinaاللي هو بيسبب العمى او يعني انها
+
+136
+00:09:59,370 --> 00:10:05,450
+بتقدي الى اللي هي اتلاف خلايا الشبكية in this
+
+137
+00:10:05,450 --> 00:10:08,910
+application في هذا النظام يعني كيف ممكن ان هم
+
+138
+00:10:08,910 --> 00:10:11,930
+يفحصوا ال medical professional اللي هي يعني
+
+139
+00:10:11,930 --> 00:10:16,890
+المهنيين الطبيين بيستخدموا هذا الشيء اللي فيه جهاز
+
+140
+00:10:16,890 --> 00:10:23,930
+بيسموه tonometer هذا ال tonometer بيفحصأو بقيس ضغط
+
+141
+00:10:23,930 --> 00:10:28,010
+داخل العين بقيس الضغط داخل العين كيف قالية قياس
+
+142
+00:10:28,010 --> 00:10:33,550
+الضغط داخل العين ممكن أن هذا الجهاز بيطلق بخات من
+
+143
+00:10:33,550 --> 00:10:37,960
+الهواءيعني بخة من الهواء أو هيك دفعة من الهواء
+
+144
+00:10:37,960 --> 00:10:43,840
+داخل الجدار الداخل للعين و بقيس سرعة ارتداد هذا
+
+145
+00:10:43,840 --> 00:10:49,060
+الهواء بعد ما يصطدم بالجدار الداخل للعين اتنار في
+
+146
+00:10:49,060 --> 00:10:54,660
+الحالة الطبيعية او الضغط الطبيعي بيكون الضغط طبعا
+
+147
+00:10:54,660 --> 00:10:58,400
+و ال pulse تبع العين اشي طبيعي و طبعا ضعيف جدا
+
+148
+00:10:58,400 --> 00:11:04,040
+بيكون ضعيف و .. و بسيطهذا .. لكن لما يكون في
+
+149
+00:11:04,040 --> 00:11:07,680
+الحالة اللي .. اللي هي عنده مشاكل بيكون ال pulse
+
+150
+00:11:07,680 --> 00:11:13,340
+فيه مشكلة أو بيكون الجدار اللي .. العين طبعا rigid
+
+151
+00:11:13,340 --> 00:11:17,760
+أنه شوية جاف هذا الجاف بيأدى إلى أنه الهواء بيرتد
+
+152
+00:11:17,760 --> 00:11:23,220
+بسرعة كبيرة وكمان ال pulse يعني ضغط العين بيكون
+
+153
+00:11:23,220 --> 00:11:27,440
+قوي لكن لما يكون في الحالة الطبيعية بيكون جدار
+
+154
+00:11:27,440 --> 00:11:32,160
+العين رطبرطب وفي عنده نوع من نوع أسفنجية بيمتص
+
+155
+00:11:32,160 --> 00:11:35,560
+طبعا جزء من الهواء او .. وبقى ارتداده بتكون قليل
+
+156
+00:11:35,560 --> 00:11:40,100
+يعني ارتداد الهواء سرعة الهواء بتكون قليلة مقياسا
+
+157
+00:11:40,100 --> 00:11:45,940
+بي اللي عنده مشاكل في العين وبالتالي
+
+158
+00:11:45,940 --> 00:11:50,320
+الفرق بين إنه هذا العين مصعبة أو مش مصعبة قوة
+
+159
+00:11:50,320 --> 00:11:55,720
+ارتداد الهواء لما تكون ضعيفة ومنخفضة فبيكون طبيعي
+
+160
+00:11:55,720 --> 00:12:01,340
+لما تكون قوة ارتداد الهواءقوية فبصير أنه في مشكلة
+
+161
+00:12:01,340 --> 00:12:06,720
+أنه الضغط الداخل للعين طبعا يزداد we can summarize
+
+162
+00:12:06,720 --> 00:12:09,140
+the type of the collision بدأنا عليه طبعا احنا دي
+
+163
+00:12:09,140 --> 00:12:14,520
+مثال biology لكن ممكن احنا نرجع لموضوعنا اللي هو
+
+164
+00:12:14,520 --> 00:12:18,600
+ال elastic collision أنواع التصادمات في عندى تصادم
+
+165
+00:12:18,600 --> 00:12:21,640
+بيسموه elastic collision تصادم marine وفي
+
+166
+00:12:21,640 --> 00:12:24,020
+inelastic collision وفي perfect inelastic
+
+167
+00:12:24,020 --> 00:12:27,330
+collision التلاتة هدولالان بالنسبة لل elastic
+
+168
+00:12:27,330 --> 00:12:32,070
+collision يعني تعريفه او كيف انا بدي اميزه both
+
+169
+00:12:32,070 --> 00:12:34,950
+momentum and kinetic energy are conserved ال
+
+170
+00:12:34,950 --> 00:12:38,290
+momentum كمية التحرك او الزخم زائد طاقة الحركة
+
+171
+00:12:38,290 --> 00:12:42,450
+محفوظ بالنسبة لل inelastic collision ال momentum
+
+172
+00:12:42,450 --> 00:12:46,370
+محفوظ طبعا حكينا ان جميع التصدمات ال momentum is
+
+173
+00:12:46,370 --> 00:12:50,830
+conserved طاقة الحركة is not in perfect inelastic
+
+174
+00:12:50,830 --> 00:12:56,080
+collision momentumis momentum is conserved و ال
+
+175
+00:12:56,080 --> 00:12:59,620
+kinetic energy is not كمية التحرك محفوظة و طاقة
+
+176
+00:12:59,620 --> 00:13:04,740
+الحركة طبعا غير محفوظة and the two objects stick
+
+177
+00:13:04,740 --> 00:13:09,220
+together بعد التصادم بيلتسق الجسم مع بعض و بيمشوا
+
+178
+00:13:09,220 --> 00:13:13,720
+بسرعة مشتركة أو سرعة نهائية common final velocity
+
+179
+00:13:13,720 --> 00:13:20,180
+نيجي لقى a quick quiz 6.3 بيحكي ليه في a car and a
+
+180
+00:13:20,180 --> 00:13:23,370
+large truck traveling at the samespeed collide
+
+181
+00:13:23,370 --> 00:13:27,950
+head-on and stick together سيارة صغيرة و شاحن كبير
+
+182
+00:13:27,950 --> 00:13:34,190
+طبعا بيمشوا عكس بعض طبعا head-on صار فيه تصادم
+
+183
+00:13:34,190 --> 00:13:39,970
+بينهم يعني head .. head .. head-on يعني بدون زوايا
+
+184
+00:13:39,970 --> 00:13:43,850
+على نفس المستوى which vehicle undergoes larger
+
+185
+00:13:43,850 --> 00:13:46,450
+magnitude of that change in اسمه من تمين من هدول
+
+186
+00:13:46,450 --> 00:13:51,940
+التنتين صار عنده تغير في كمية التحرك أكترهل الـ
+
+187
+00:13:51,940 --> 00:13:55,660
+car هل ال truck هل ال .. هل the magnitude of the
+
+188
+00:13:55,660 --> 00:13:58,520
+change in momentum is the same for both أو
+
+189
+00:13:58,520 --> 00:14:01,560
+impossible to determine without more information
+
+190
+00:14:01,560 --> 00:14:07,120
+طبعا اتفقنا انه كمية التحرك محفوظة وبالتالي الجواب
+
+191
+00:14:07,120 --> 00:14:10,480
+C the total momentum حتى لو كان واحد كبير واحد
+
+192
+00:14:10,480 --> 00:14:14,720
+صغير فما بتبادلوا حتى لو كان اذا ال C the total
+
+193
+00:14:14,720 --> 00:14:17,200
+momentum of the car truck system is conserved
+
+194
+00:14:17,200 --> 00:14:21,020
+محفوظة وبالتاليany change in momentum of a truck
+
+195
+00:14:21,020 --> 00:14:24,220
+must be counterbalanced by an equal magnitude
+
+196
+00:14:24,220 --> 00:14:26,640
+change of which is signed in the momentum of the
+
+197
+00:14:26,640 --> 00:14:30,900
+car أي تغير في كمية التحرك بالنسبة للشاحنة هيصير
+
+198
+00:14:30,900 --> 00:14:34,280
+عندى نفس التغير يعني زى الميزان هيصير عندى نفس
+
+199
+00:14:34,280 --> 00:14:38,480
+الميزان اللى بتفتقده اللى هى ال truck بتكتسبه اللى
+
+200
+00:14:38,480 --> 00:14:44,640
+هى السيارة وعكس وبالتالي كمية التحرك طبعا بيصير
+
+201
+00:14:44,640 --> 00:14:48,740
+عندى the magnitude of that changeof momentum is
+
+202
+00:14:48,740 --> 00:14:53,460
+the same معدل تغير اللي هي قيمة التغير في كمية
+
+203
+00:14:53,460 --> 00:14:59,540
+التحرك بتكون هي واحدة لجهتين يعني الجزء الأول إذا
+
+204
+00:14:59,540 --> 00:15:03,380
+افتقدت سيارة افتقدت فال truck اكتسبت او العكس معنى
+
+205
+00:15:03,380 --> 00:15:06,680
+الكلام انه كمية التحرك قبل بساوي كمية التحرك بعد
+
+206
+00:15:06,680 --> 00:15:13,400
+يعني ال momentum is conserved section 6.3 برضه
+
+207
+00:15:13,400 --> 00:15:18,910
+بنكمل في ال perfect inelastic collisionتصادم تام
+
+208
+00:15:18,910 --> 00:15:22,190
+المرونة أو عادي المرونة بأفرض في عندي جسمين أم
+
+209
+00:15:22,190 --> 00:15:27,110
+واحد أو أم اتنين بتحركوا بطبعا سرعة ابتدائية
+
+210
+00:15:27,110 --> 00:15:32,530
+معروفة V1 initial V2 initial خلال خلال طبعا خط
+
+211
+00:15:32,530 --> 00:15:38,530
+مستقيم الجسمين الصدموا في بعض واتسقوا في بعض
+
+212
+00:15:38,530 --> 00:15:41,930
+ومشيوا مع بعض في common velocity component في
+
+213
+00:15:41,930 --> 00:15:45,380
+final after the collision بعد التصادم مشي ومتنينمع
+
+214
+00:15:45,380 --> 00:15:49,080
+بعض هذا بيسميه time المرونة أو perfect inelastic
+
+215
+00:15:49,080 --> 00:15:53,000
+زي ما احنا شايفين بالشكل هذه أم واحد بتمشي بسرعة
+
+216
+00:15:53,000 --> 00:15:56,320
+في واحد initial وام اتنين بتمشي بسرعة في اتنين
+
+217
+00:15:56,320 --> 00:15:59,020
+initial واتنين head on head يعني ماشيين على ال X
+
+218
+00:15:59,020 --> 00:16:02,680
+axis before perfect inelastic طبعا قبل كانوا
+
+219
+00:16:02,680 --> 00:16:06,100
+التنتين كل واحدة بتتحرك بقاش بسرعة واحدة مختلفة
+
+220
+00:16:06,100 --> 00:16:11,700
+بعد التصادم طبعا الجثمين remained in contact
+
+221
+00:16:11,700 --> 00:16:15,740
+مزالوا في تلامس التثقوا في بعضال system momentum
+
+222
+00:16:15,740 --> 00:16:20,420
+is conserved كمية التحرك محفوظة لكن اللي هي ال
+
+223
+00:16:20,420 --> 00:16:23,300
+kinetic energy is not conserved طبعا صار فيه فقط
+
+224
+00:16:23,300 --> 00:16:28,080
+NDP الطاقة وبالتالي كمية التحرك is not conserved
+
+225
+00:16:28,080 --> 00:16:30,880
+because the total momentum of the two object
+
+226
+00:16:30,880 --> 00:16:34,080
+isolate system before the collision equal the
+
+227
+00:16:34,080 --> 00:16:36,540
+total momentum of the combined object system after
+
+228
+00:16:36,540 --> 00:16:40,160
+the collision هيكون عندي أنا ال B initial بنسبة B
+
+229
+00:16:40,160 --> 00:16:44,150
+finalهيكون إن قانون جديد اللي هو اللي هيوية بالشكل
+
+230
+00:16:44,150 --> 00:16:50,010
+هذا M1 V1 initial زاد M2 V2 initial بدها تساوي M1
+
+231
+00:16:50,010 --> 00:16:56,750
+زاد M2 في V final لإن الجسمين اتحركوا بطبعا سرعة
+
+232
+00:16:56,750 --> 00:17:01,550
+واحدة بعد اتصادهم إذا V1 final ممكن من هذا القانون
+
+233
+00:17:01,550 --> 00:17:05,490
+طبعا هذا الحد اللي هو الحدود هذه على الحد هذا بطلع
+
+234
+00:17:05,490 --> 00:17:10,700
+عندي V final M1 V1 initialزايد M2 V2 initial على
+
+235
+00:17:10,700 --> 00:17:16,920
+M1 زايد M2 طبعا مهم جدا ملاحظة أن V1 initial و V2
+
+236
+00:17:16,920 --> 00:17:21,980
+initial و V final موجودين بال X axis لإنه حكالي
+
+237
+00:17:21,980 --> 00:17:26,220
+أنه head on hood هي head بال X axis وبالتالي ال
+
+238
+00:17:26,220 --> 00:17:28,680
+car is needed to entering their known value
+
+239
+00:17:28,680 --> 00:17:32,080
+practically with regard to sign معنى الكلام أنه
+
+240
+00:17:32,080 --> 00:17:37,380
+بتدخل اللي هي ال .. ال .. ال .. الإشارات بعين
+
+241
+00:17:37,380 --> 00:17:41,110
+الاعتباريعني اللي رايح على الشرق موجب و العرب غرب
+
+242
+00:17:41,110 --> 00:17:44,730
+سالب أو اللي علي اليمين موجب و علي الشمال سالب و
+
+243
+00:17:44,730 --> 00:17:48,050
+اللي فوق موجب و التحت سالب لازم أخدها بين الاعتبار
+
+244
+00:17:48,050 --> 00:17:51,230
+معنى الكلام أن ال V1 initial هنا كانت positive
+
+245
+00:17:51,230 --> 00:17:56,950
+value و ال M1 بتتحرك الي اليمين و ال V2 initial
+
+246
+00:17:56,950 --> 00:18:00,850
+كانت negative لإنها بتتحرك الي الشمال عشان لما أنا
+
+247
+00:18:00,850 --> 00:18:07,170
+جي نحل لازم احنا نراعي الإشارات طبعا example 6-4
+
+248
+00:18:07,850 --> 00:18:13,550
+Pick up a truck with mass 1.8×10³ kg شاحنة pick up
+
+249
+00:18:13,550 --> 00:18:19,590
+بيسموها traveling eastbound at .. بتتحرك ناحية ال
+
+250
+00:18:19,590 --> 00:18:24,530
+east ناحية الشرق بسرعة 15 متر في الثانية ولكن
+
+251
+00:18:24,530 --> 00:18:29,010
+compact و car طبعا في عندى سيارة تانى زى ما هو
+
+252
+00:18:29,010 --> 00:18:33,170
+موضح بالشكل السيارة التانية هيها بتتحرك ناحية
+
+253
+00:18:33,170 --> 00:18:37,650
+اليمين ال pick up شاحنةو هنا سيارة بتتحرك ناحية
+
+254
+00:18:37,650 --> 00:18:43,410
+اليسار الآن السؤال السيارة كتلتها تسعة فعشرة أقصى
+
+255
+00:18:43,410 --> 00:18:47,230
+اتنين traveling west ناحية الغرب بسرعة ناقص
+
+256
+00:18:47,230 --> 00:18:50,610
+خمستاشر انها ناحية الغرب عشانها طبعا رايحة ناحية
+
+257
+00:18:50,610 --> 00:18:55,890
+الغرب خدنا سالب the vehicles كله العربتين صدموا في
+
+258
+00:18:55,890 --> 00:19:01,950
+بعض head on بالظبط يعني أجت صادم becoming طبعا in
+
+259
+00:19:01,950 --> 00:19:08,240
+angle صاروا صدموا في بعضو صاروا كتلة واحدة find
+
+260
+00:19:08,240 --> 00:19:10,660
+the speed of the int angle vehicle after the
+
+261
+00:19:10,660 --> 00:19:16,000
+collision بدي أنا سرعتهم بعد التصادم عشان أوجد
+
+262
+00:19:16,000 --> 00:19:20,680
+سرعتهم بعد التصادم find the final speed after the
+
+263
+00:19:20,680 --> 00:19:24,800
+collision طبعا بدي أفرض أن أم واحد إلها V واحد
+
+264
+00:19:24,800 --> 00:19:29,460
+رايحة ناحية اليمين و أم اتنين V اتنين ناحية اليسار
+
+265
+00:19:29,760 --> 00:19:34,920
+بدنا نيجي نعوض نعوض الان B initial بيساوي B final
+
+266
+00:19:34,920 --> 00:19:40,380
+طبعا بتجاه ال X axis B واحد M واحد في V واحد هيها
+
+267
+00:19:40,380 --> 00:19:43,400
+واحد point تمانية في عشر أقص تلاتة و سرعتها كانت
+
+268
+00:19:43,400 --> 00:19:46,940
+خمس عشر M اتنين للسيارة تسعة في عشر أقص اتنين
+
+269
+00:19:46,940 --> 00:19:50,740
+kilogram و سرعتها ناقص خمس عشر نروح ناحية اليسار
+
+270
+00:19:50,740 --> 00:19:54,520
+بدها تساوي M واحد لل truck واحد point تمانية في
+
+271
+00:19:54,520 --> 00:20:00,180
+عشر أقص تلاتةو M2 تسعة فعشرة أقصى اتنين للسيارة و
+
+272
+00:20:00,180 --> 00:20:03,820
+بوجد V final اللي هي السرعة المشتركة ل الجهتين
+
+273
+00:20:03,820 --> 00:20:08,260
+طبعا .. طبعا هم خبطوا في بعض و التسقوا في بعض
+
+274
+00:20:08,260 --> 00:20:12,080
+فالسرعة النهائية هتكون موجبة اذا هم هيتحركوا
+
+275
+00:20:12,080 --> 00:20:17,320
+باتجاه ال X axis الموجة الان find the change in
+
+276
+00:20:17,320 --> 00:20:20,620
+the velocity for each vehicle بدي التغير في السرعة
+
+277
+00:20:20,620 --> 00:20:25,910
+ل .. للجهتين فبدنا نوجدلأ ال pick up لل truck
+
+278
+00:20:25,910 --> 00:20:31,070
+للشاحنة delta V1 ساوي V final نقص V initial V
+
+279
+00:20:31,070 --> 00:20:34,070
+final كانت 5 اللي هي المشتركة و ال initial كانت 15
+
+280
+00:20:34,070 --> 00:20:39,210
+بطلع minus 10 و delta V final لأ السيارة اللي هي
+
+281
+00:20:39,210 --> 00:20:43,150
+ال change in the plus التغير في السرعة delta V2
+
+282
+00:20:43,150 --> 00:20:47,510
+بتساوي V final نقص V initial V2 initial 5 ناقص
+
+283
+00:20:47,510 --> 00:20:51,700
+ناقص ال 15 لازم أخدها بين الاعتبار بتطلع 20إذاً
+
+284
+00:20:51,700 --> 00:20:54,940
+هذه delta V للـ truck وهذه delta V للسيارة في
+
+285
+00:20:54,940 --> 00:20:59,940
+السؤال C مطلوب find أوجد the change in kinetic
+
+286
+00:20:59,940 --> 00:21:03,800
+energy of the system بدي طبعاً التغير في طاقة
+
+287
+00:21:03,800 --> 00:21:09,960
+الحركة للنظام إذا Delta K initial أو K initial
+
+288
+00:21:09,960 --> 00:21:14,660
+بالأول اللي هي نص M1 V1 initial تربيع زائد نص M2
+
+289
+00:21:14,660 --> 00:21:20,360
+V2 initial تربيع ال M1 لل truck كانت 1.8×10⁳V1
+
+290
+00:21:20,360 --> 00:21:27,580
+initial كانت 15 زائد نص M2 اللي هي 9 V2 initial
+
+291
+00:21:27,580 --> 00:21:32,220
+تربيه بساوي إناقص 15 طبعا لكل تربيه بطلع الجواب K
+
+292
+00:21:32,220 --> 00:21:38,720
+initial kinetic energy initial 3.04×10-5 joule
+
+293
+00:21:38,720 --> 00:21:43,040
+هأوجد calculate the final kinetic energy of the
+
+294
+00:21:43,040 --> 00:21:47,870
+system النهائيةdelta K final الأهنب الـ final طبعا
+
+295
+00:21:47,870 --> 00:21:53,490
+نص M1 زي م2 V2 تربيع أو ممكن نحكي نص M1 V1 تربيع
+
+296
+00:21:53,490 --> 00:21:57,790
+final زي نص M2 V2 تربيع final و V final تربيع
+
+297
+00:21:57,790 --> 00:22:00,650
+لتنتير المشتركة وبالتالي إذا ممكن أستخدم هذا
+
+298
+00:22:00,650 --> 00:22:08,090
+القانون نص M1 1.8×10²3 لل truck زي M2 للسيارة
+
+299
+00:22:08,090 --> 00:22:13,570
+9×10²2في فيه final تربيع لمية للجميع اللي هي خمسة
+
+300
+00:22:13,570 --> 00:22:18,270
+تربيع بطلع عندي kinetic energy final تلاتة point
+
+301
+00:22:18,270 --> 00:22:21,930
+تلاتة تمانية لما أجي أحكي delta K E تغير في طاقة
+
+302
+00:22:21,930 --> 00:22:25,630
+الحركة اللي هي K final ناقص K initial بطلع عندي
+
+303
+00:22:25,630 --> 00:22:29,410
+سالم معنى الكلام في عندي أنا فقد في الطاقة
+
+304
+00:22:29,410 --> 00:22:35,530
+وبالتالي هذا عندياللي هو ال .. ال .. اتصادهم
+
+305
+00:22:35,530 --> 00:22:43,170
+بيسموه inelastic .. inelastic collision طبعا في
+
+306
+00:22:43,170 --> 00:22:49,090
+هذا السؤال في عندي plastic بندولة في عندي بندول
+
+307
+00:22:49,090 --> 00:22:55,630
+plastic جهاز devices use a measure لازم بيقيس سرعة
+
+308
+00:22:55,630 --> 00:23:01,580
+مقذوفة زي الرصاصة دخلت فيهالبيوليت يعني الرصاصة is
+
+309
+00:23:01,580 --> 00:23:05,560
+fired into a large block of wood هاي الرصاصة
+
+310
+00:23:05,560 --> 00:23:14,340
+ضربناها أو قذفناها داخل ناحية خشبة كبيرة معلقة بخط
+
+311
+00:23:14,340 --> 00:23:20,580
+خفيف معلقة بخط خفيف الرصاصة سكنت في الخشبة وضلت
+
+312
+00:23:20,580 --> 00:23:26,220
+فيها وارتفعت مسافاتش او ارتفعتش assume that the
+
+313
+00:23:26,220 --> 00:23:29,340
+mass of the biolet كتلة الرصاصة كانت خمسة جرام
+
+314
+00:23:29,800 --> 00:23:34,560
+وكتلة الخشبة كانت واحد كيلو والارتفاع اللى وصلته
+
+315
+00:23:34,560 --> 00:23:37,940
+خمسة find the velocity of the system after the
+
+316
+00:23:37,940 --> 00:23:43,300
+bullet embeds in the block بده السرعة .. سرعة
+
+317
+00:23:43,300 --> 00:23:48,080
+النظام بعد ما .. ما الخشبة دخلت في اللى هو
+
+318
+00:23:48,080 --> 00:23:52,200
+الارصاصة دخلت في الخشبة وطلعوا مسافة هى ارصاصة
+
+319
+00:23:52,200 --> 00:23:57,840
+بتمشي بسرعة معينة V initial هنا الخشبة ثابتةالخشب
+
+320
+00:23:57,840 --> 00:24:03,140
+واحد kilogram هذه خمسين ك .. خمسين gram أو
+
+321
+00:24:03,140 --> 00:24:07,740
+الارصاصة كتلتها .. الارصاصة كتلتها خمس .. لحظة
+
+322
+00:24:07,740 --> 00:24:13,480
+الارصاصة كتلتها كانت خمسة gram الان نيجي نحل ..
+
+323
+00:24:13,480 --> 00:24:18,820
+بدنا نحل هذا السؤال find the velocity of the
+
+324
+00:24:18,820 --> 00:24:21,860
+system after the bullet embeds in the block بدأ
+
+325
+00:24:21,860 --> 00:24:25,050
+أستخدم apply conservation of energyبين ال block و
+
+326
+00:24:25,050 --> 00:24:27,330
+ال bullet، ال block يعني الخشبة و bullet يعني
+
+327
+00:24:27,330 --> 00:24:30,750
+الرصاصة هنحكي أن طاقة الحركة او كينتك energy زائد
+
+328
+00:24:30,750 --> 00:24:35,170
+potential energy after the collisionبدها تساوي ال
+
+329
+00:24:35,170 --> 00:24:37,450
+kinetic energy زي ال potential energy at the top
+
+330
+00:24:37,450 --> 00:24:41,110
+على ارتفاع H أنا بده اوجد اللي .. اللي هي السرعة
+
+331
+00:24:41,110 --> 00:24:44,390
+الابتدائية اللي هي بعد التصادم لكن تعتبر في
+
+332
+00:24:44,390 --> 00:24:47,810
+المرحلة هذه ابتدائية substitute expression for the
+
+333
+00:24:47,810 --> 00:24:50,650
+kinetic energy and potential energy طبعا بستخدم
+
+334
+00:24:50,650 --> 00:24:54,690
+طاقة الحركة أو طاقة الوضع في الحالة هذه ال after
+
+335
+00:24:54,690 --> 00:24:57,650
+collision اللي هي تعتبر initial لمرحلة ما بعد
+
+336
+00:24:57,650 --> 00:25:01,930
+التصادم هنحكي نص M1 زي M2 لإن الرصاصة دخلت فيه
+
+337
+00:25:01,930 --> 00:25:07,210
+الخشبةفي v لل system كله تربيع زائد zero اللي هي
+
+338
+00:25:07,210 --> 00:25:09,990
+طاقة الوضع zero عشانها عال level بتساوي طاقة
+
+339
+00:25:09,990 --> 00:25:16,190
+الحركة وصلت أقصى ارتفاع H0زائد M1 زائد M2 في G في
+
+340
+00:25:16,190 --> 00:25:19,990
+H طبعا ال M هتروح مع ال M بيبقى لعندي ال V بيساوي
+
+341
+00:25:19,990 --> 00:25:25,450
+جزر 2GH زي ما كنا ندرس سابقا و ال G تسعة و تمانية
+
+342
+00:25:25,450 --> 00:25:32,310
+من عشرة و ال H وصلت أقصى ارتفاع بساوي خمسة طبعا
+
+343
+00:25:32,310 --> 00:25:37,070
+خمسة سانت او يعني ضربناها في عشر و نقصت اتنين عشان
+
+344
+00:25:37,070 --> 00:25:40,610
+نحولها لمتر لإن ال G متر في الثانية تربيه بيطلع
+
+345
+00:25:40,610 --> 00:25:45,140
+اللي هي ال Vللـ system كله 0.99 هذا بعد التصادم
+
+346
+00:25:45,140 --> 00:25:48,880
+الآن عشان أوجد ال initial speed بتدي السرعة
+
+347
+00:25:48,880 --> 00:25:54,640
+الابتدائية ل .. ل .. ل البيوليت طبعا قبل التصادم
+
+348
+00:25:54,640 --> 00:25:59,920
+راح نستخدم conservation of momentum قانون حفظ كمية
+
+349
+00:25:59,920 --> 00:26:05,200
+التحرك هأحكي P initial بساوي P final ال P initial
+
+350
+00:26:05,200 --> 00:26:09,880
+M1 في V1 initial هي للرصاصة زي M2 ال V2 initial هي
+
+351
+00:26:09,880 --> 00:26:15,290
+للخشبةبتساوي M1 زي M2 في V لل system كله V2
+
+352
+00:26:15,290 --> 00:26:19,490
+initial كانت Zero للخشبة كانت ثابتة M1 للارصاصة
+
+353
+00:26:19,490 --> 00:26:25,010
+خمسة مقسمها على الف عشان تصير بالكيلو هيها خمسة في
+
+354
+00:26:25,010 --> 00:26:31,110
+عشر أص ناقص تلاتة كيلو و V1 initial بديها مجهولة
+
+355
+00:26:31,110 --> 00:26:36,590
+M2 كانت Zero اذا V1 initial بتساوي M1 زي M2 هذا
+
+356
+00:26:36,590 --> 00:26:41,500
+سفر V1 initial بتساوي M1 زي M2في villa system على
+
+357
+00:26:41,500 --> 00:26:47,940
+اللي هي ال M1 تطلع سرعة الإرصاص 199 متر في التانية
+
+358
+00:26:47,940 --> 00:26:52,240
+عشان هي سرعتها كبيرة كتير كانت و سكنت في الخشبة
+
+359
+00:26:52,240 --> 00:26:57,720
+بنستكمل في التسجيل اللي طبعا التالي
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..20666b031ae9883fd6d1eb9e63ac4b6e4da675fa
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/dQTiYQxXkpo_raw.json
@@ -0,0 +1 @@
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0.6360677083333334}, {"start": 152.89, "end": 153.35, "word": " section", "probability": 0.7529296875}, {"start": 153.35, "end": 153.77, "word": " 6", "probability": 0.732421875}, {"start": 153.77, "end": 154.21, "word": " 3", "probability": 0.171875}, {"start": 154.21, "end": 156.57, "word": " العنوان", "probability": 0.8785400390625}, {"start": 156.57, "end": 156.97, "word": " collision", "probability": 0.8837890625}, {"start": 156.97, "end": 157.31, "word": " in", "probability": 0.9677734375}, {"start": 157.31, "end": 157.55, "word": " one", "probability": 0.92236328125}, {"start": 157.55, "end": 158.09, "word": " dimension", "probability": 0.94287109375}, {"start": 158.09, "end": 159.39, "word": " تصادمات", "probability": 0.8900390625}, {"start": 159.39, "end": 159.67, "word": " في", "probability": 0.9921875}, {"start": 159.67, "end": 160.29, "word": " اتجاه", "probability": 0.982421875}, {"start": 160.29, "end": 160.73, "word": " واحد", "probability": 0.99267578125}, {"start": 160.73, "end": 160.91, "word": " أو", "probability": 0.54443359375}, {"start": 160.91, "end": 161.19, "word": " بعد", "probability": 0.681640625}, {"start": 161.19, "end": 161.69, "word": " واحد", "probability": 0.994384765625}], "temperature": 1.0}, {"id": 7, "seek": 18859, "start": 162.13, "end": 188.59, "text": "we have seen that for any type of collision بنلاحظ أنه أي يعني في أي نوع من التصادمات كمية التحرك كل أنواع التصادمات كمية التحرك فيها محفوظة يعني اللي هي ال momentum before بيساوي ال momentum after before the collision equals the total momentum just after the collision as long as the system may be considered isolated إذا اتفقنا أنه", "tokens": [826, 362, 1612, 300, 337, 604, 2010, 295, 24644, 4724, 1863, 15040, 5016, 19913, 14739, 3224, 36632, 37495, 22653, 8978, 36632, 8717, 45367, 9154, 16712, 9381, 18513, 2304, 9307, 9122, 2304, 10632, 16712, 5016, 31747, 28242, 14739, 14407, 3615, 16712, 9381, 18513, 2304, 9307, 9122, 2304, 10632, 16712, 5016, 31747, 8978, 11296, 3714, 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momentum", "probability": 0.9638671875}, {"start": 177.03, "end": 177.83, "word": " before", "probability": 0.91796875}, {"start": 177.83, "end": 178.17, "word": " بيساوي", "probability": 0.57451171875}, {"start": 178.17, "end": 178.27, "word": " ال", "probability": 0.865234375}, {"start": 178.27, "end": 178.53, "word": " momentum", "probability": 0.978515625}, {"start": 178.53, "end": 179.15, "word": " after", "probability": 0.89501953125}, {"start": 179.15, "end": 180.47, "word": " before", "probability": 0.841796875}, {"start": 180.47, "end": 180.67, "word": " the", "probability": 0.923828125}, {"start": 180.67, "end": 181.05, "word": " collision", "probability": 0.91455078125}, {"start": 181.05, "end": 181.43, "word": " equals", "probability": 0.90673828125}, {"start": 181.43, "end": 181.63, "word": " the", "probability": 0.85546875}, {"start": 181.63, "end": 181.83, "word": " total", "probability": 0.88330078125}, {"start": 181.83, "end": 182.23, "word": " momentum", "probability": 0.9794921875}, {"start": 182.23, "end": 182.53, "word": " just", "probability": 0.9169921875}, {"start": 182.53, "end": 182.83, "word": " after", "probability": 0.86181640625}, {"start": 182.83, "end": 183.03, "word": " the", "probability": 0.927734375}, {"start": 183.03, "end": 183.39, "word": " collision", "probability": 0.9072265625}, {"start": 183.39, "end": 183.69, "word": " as", "probability": 0.95849609375}, {"start": 183.69, "end": 184.03, "word": " long", "probability": 0.943359375}, {"start": 184.03, "end": 184.35, "word": " as", "probability": 0.98291015625}, {"start": 184.35, "end": 184.51, "word": " the", "probability": 0.89990234375}, {"start": 184.51, "end": 184.83, "word": " system", "probability": 0.96240234375}, {"start": 184.83, "end": 185.05, "word": " may", "probability": 0.87158203125}, {"start": 185.05, "end": 185.17, "word": " be", "probability": 0.96044921875}, {"start": 185.17, "end": 185.55, "word": " considered", "probability": 0.75634765625}, 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204.84, "end": 205.32, "word": " خارجية", "probability": 0.9962158203125}, {"start": 205.32, "end": 205.96, "word": " مؤثرة", "probability": 0.8558349609375}, {"start": 205.96, "end": 206.46, "word": " عليه", "probability": 0.94873046875}, {"start": 206.46, "end": 207.3, "word": " the", "probability": 0.333251953125}, {"start": 207.3, "end": 207.58, "word": " total", "probability": 0.8759765625}, {"start": 207.58, "end": 208.1, "word": " kinetic", "probability": 0.99365234375}, {"start": 208.1, "end": 208.64, "word": " energy", "probability": 0.97314453125}, {"start": 208.64, "end": 209.9, "word": " اللي", "probability": 0.98095703125}, {"start": 209.9, "end": 210.16, "word": " هي", "probability": 0.92919921875}, {"start": 210.16, "end": 210.98, "word": " المجموعة", "probability": 0.90322265625}, {"start": 210.98, "end": 211.76, "word": " لطاقة", "probability": 0.78509521484375}, {"start": 211.76, "end": 212.86, "word": " الحركة", "probability": 0.9889322916666666}, {"start": 212.86, 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24765, "start": 218.73, "end": 247.65, "text": "نوع اتصادهم in generally not conserved in a collision because some of the kinetic energy is converted internal energy لإنه طاقة الحركة ممكن تتحول إلى طاقة داخلية زي مثلا طاقة الصوت أو طاقة مثلا ممكن يعني نفسرها بيه أنه يكون ال work needed to permanently deform ممكن يصير عندنا تشوه كامل", "tokens": [1863, 45367, 1975, 2655, 9381, 18513, 16095, 294, 5101, 406, 1014, 6913, 294, 257, 24644, 570, 512, 295, 264, 27135, 2281, 307, 16424, 6920, 2281, 5296, 28814, 1863, 3224, 23032, 995, 28671, 21542, 31747, 3660, 3714, 43020, 6055, 2655, 5016, 12610, 30731, 23032, 995, 28671, 11778, 47283, 1211, 10632, 30767, 1829, 50113, 15040, 23032, 995, 28671, 31767, 35473, 34051, 23032, 995, 28671, 50113, 15040, 3714, 43020, 37495, 22653, 8717, 36178, 2288, 11296, 4724, 1829, 3224, 14739, 3224, 7251, 30544, 2423, 589, 2978, 281, 24042, 36094, 3714, 43020, 7251, 9381, 13546, 43242, 8315, 6055, 8592, 2407, 3224, 9122, 10943, 1211], "avg_logprob": 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"end": 1348.01, "word": " فقد", "probability": 0.989501953125}, {"start": 1348.01, "end": 1348.65, "word": " في", "probability": 0.80517578125}, {"start": 1348.65, "end": 1349.41, "word": " الطاقة", "probability": 0.9680989583333334}, {"start": 1349.41, "end": 1351.13, "word": " وبالتالي", "probability": 0.8409016927083334}, {"start": 1351.13, "end": 1351.65, "word": " هذا", "probability": 0.62255859375}, {"start": 1351.65, "end": 1352.09, "word": " عندي", "probability": 0.945068359375}], "temperature": 1.0}, {"id": 51, "seek": 137993, "start": 1352.39, "end": 1379.93, "text": "اللي هو ال .. ال .. اتصادهم بيسموه inelastic .. inelastic collision طبعا في هذا السؤال في عندي plastic بندولة في عندي بندول plastic جهاز devices use a measure لازم بيقيس سرعة مقذوفة زي الرصاصة دخلت فيه", "tokens": [6027, 20292, 31439, 2423, 4386, 2423, 4386, 1975, 2655, 9381, 18513, 16095, 4724, 1829, 38251, 2407, 3224, 294, 338, 2750, 4386, 294, 338, 2750, 24644, 23032, 3555, 3615, 995, 8978, 23758, 21136, 33604, 6027, 8978, 18871, 16254, 5900, 44945, 3215, 12610, 3660, 8978, 18871, 16254, 44945, 3215, 12610, 5900, 10874, 3224, 31377, 5759, 764, 257, 3481, 5296, 31377, 2304, 4724, 1829, 38436, 3794, 8608, 2288, 27884, 3714, 4587, 8848, 38688, 3660, 30767, 1829, 34892, 9381, 33546, 3660, 11778, 9778, 1211, 2655, 8978, 3224], "avg_logprob": -0.18963913725955145, "compression_ratio": 1.601063829787234, "no_speech_prob": 4.172325134277344e-07, "words": [{"start": 1352.39, "end": 1352.73, "word": "اللي", "probability": 0.970703125}, {"start": 1352.73, "end": 1353.01, "word": " هو", "probability": 0.96728515625}, {"start": 1353.01, "end": 1353.61, "word": " ال", "probability": 0.6494140625}, {"start": 1353.61, "end": 1353.61, "word": " ..", "probability": 0.8818359375}, {"start": 1353.61, "end": 1354.11, "word": " ال", "probability": 0.88720703125}, {"start": 1354.11, "end": 1354.29, "word": " ..", "probability": 0.56103515625}, {"start": 1354.29, "end": 1355.53, "word": " اتصادهم", "probability": 0.86396484375}, {"start": 1355.53, "end": 1356.61, "word": " بيسموه", "probability": 0.9142578125}, {"start": 1356.61, "end": 1357.53, "word": " inelastic", "probability": 0.9178059895833334}, {"start": 1357.53, "end": 1357.69, "word": " ..", "probability": 0.6943359375}, {"start": 1357.69, "end": 1358.47, "word": " inelastic", "probability": 0.8987630208333334}, {"start": 1358.47, "end": 1360.71, "word": " collision", "probability": 0.93701171875}, {"start": 1360.71, "end": 1363.05, "word": " طبعا", "probability": 0.9866943359375}, {"start": 1363.05, "end": 1363.17, "word": " في", "probability": 0.7001953125}, {"start": 1363.17, "end": 1363.49, "word": " هذا", "probability": 0.58837890625}, {"start": 1363.49, "end": 1364.37, "word": " السؤال", "probability": 0.9873046875}, {"start": 1364.37, "end": 1364.87, "word": " في", "probability": 0.68359375}, {"start": 1364.87, "end": 1365.35, "word": " عندي", "probability": 0.836181640625}, {"start": 1365.35, "end": 1366.55, "word": " plastic", "probability": 0.88427734375}, {"start": 1366.55, "end": 1367.17, "word": " بندولة", "probability": 0.741851806640625}, {"start": 1367.17, "end": 1367.39, "word": " في", "probability": 0.6201171875}, {"start": 1367.39, "end": 1367.83, "word": " عندي", "probability": 0.924072265625}, {"start": 1367.83, "end": 1369.09, "word": " بندول", "probability": 0.8072916666666666}, {"start": 1369.09, "end": 1370.09, "word": " plastic", "probability": 0.8203125}, {"start": 1370.09, "end": 1371.81, "word": " جهاز", "probability": 0.9357096354166666}, {"start": 1371.81, "end": 1373.01, "word": " devices", "probability": 0.8701171875}, {"start": 1373.01, "end": 1373.41, "word": " use", "probability": 0.75244140625}, {"start": 1373.41, "end": 1373.61, "word": " a", "probability": 0.91748046875}, {"start": 1373.61, "end": 1373.89, "word": " measure", "probability": 0.58984375}, {"start": 1373.89, "end": 1374.23, "word": " لازم", "probability": 0.6587727864583334}, {"start": 1374.23, "end": 1374.99, "word": " بيقيس", "probability": 0.642822265625}, {"start": 1374.99, "end": 1375.63, "word": " سرعة", "probability": 0.8819986979166666}, {"start": 1375.63, "end": 1377.83, "word": " مقذوفة", "probability": 0.85263671875}, {"start": 1377.83, "end": 1378.11, "word": " زي", "probability": 0.97265625}, {"start": 1378.11, "end": 1378.85, "word": " الرصاصة", "probability": 0.893310546875}, {"start": 1378.85, "end": 1379.67, "word": " دخلت", "probability": 0.9407958984375}, {"start": 1379.67, "end": 1379.93, "word": " فيه", "probability": 0.989013671875}], "temperature": 1.0}, {"id": 52, "seek": 140934, "start": 1380.1, "end": 1409.34, "text": "البيوليت يعني الرصاصة is fired into a large block of wood هاي الرصاصة ضربناها أو قذفناها داخل ناحية خشبة كبيرة معلقة بخط خفيف معلقة بخط خفيف الرصاصة سكنت في الخشبة وضلت فيها وارتفعت مسافاتش او ارتفعتش assume that the mass of the biolet كتلة الرصاصة كانت خمسة جرام", "tokens": [6027, 21292, 12610, 36081, 37495, 22653, 34892, 9381, 33546, 3660, 307, 11777, 666, 257, 2416, 3461, 295, 4576, 8032, 47302, 34892, 9381, 33546, 3660, 48812, 25513, 8315, 11296, 34051, 12174, 8848, 5172, 8315, 11296, 11778, 47283, 1211, 8717, 39319, 10632, 16490, 8592, 49401, 9122, 3555, 48923, 20449, 1211, 28671, 4724, 9778, 9566, 16490, 5172, 33911, 20449, 1211, 28671, 4724, 9778, 9566, 16490, 5172, 33911, 34892, 9381, 33546, 3660, 8608, 19452, 2655, 8978, 33962, 8592, 49401, 4032, 11242, 1211, 2655, 8978, 11296, 4032, 9640, 2655, 5172, 34268, 47524, 31845, 9307, 8592, 1975, 2407, 1975, 43500, 5172, 34268, 8592, 6552, 300, 264, 2758, 295, 264, 3228, 401, 302, 9122, 2655, 37977, 34892, 9381, 33546, 3660, 25961, 2655, 16490, 2304, 3794, 3660, 10874, 2288, 10943], "avg_logprob": -0.12385670562100605, "compression_ratio": 1.7848101265822784, "no_speech_prob": 5.4717063903808594e-05, "words": [{"start": 1380.1, "end": 1380.68, "word": "البيوليت", "probability": 0.648681640625}, {"start": 1380.68, "end": 1380.9, "word": " يعني", "probability": 0.8984375}, {"start": 1380.9, "end": 1381.4, "word": " الرصاصة", "probability": 0.88330078125}, {"start": 1381.4, "end": 1381.58, "word": " is", "probability": 0.82080078125}, {"start": 1381.58, "end": 1382.0, "word": " fired", "probability": 0.837890625}, {"start": 1382.0, "end": 1382.38, "word": " into", "probability": 0.859375}, {"start": 1382.38, "end": 1382.64, "word": " a", "probability": 0.97705078125}, {"start": 1382.64, "end": 1382.94, "word": " large", "probability": 0.96923828125}, {"start": 1382.94, "end": 1383.3, "word": " block", "probability": 0.93701171875}, {"start": 1383.3, "end": 1383.5, "word": " of", "probability": 0.984375}, {"start": 1383.5, "end": 1383.9, "word": " wood", "probability": 0.841796875}, {"start": 1383.9, "end": 1384.74, "word": " هاي", "probability": 0.5831298828125}, {"start": 1384.74, "end": 1385.56, "word": " الرصاصة", "probability": 0.93896484375}, {"start": 1385.56, "end": 1386.84, "word": " ضربناها", "probability": 0.9619140625}, {"start": 1386.84, "end": 1387.36, "word": " أو", "probability": 0.763671875}, {"start": 1387.36, "end": 1388.88, "word": " قذفناها", "probability": 0.89873046875}, {"start": 1388.88, "end": 1389.66, "word": " داخل", "probability": 0.8642578125}, {"start": 1389.66, "end": 1390.5, "word": " ناحية", "probability": 0.8527018229166666}, {"start": 1390.5, "end": 1391.62, "word": " خشبة", "probability": 0.9601236979166666}, {"start": 1391.62, "end": 1392.16, "word": " كبيرة", "probability": 0.9921875}, {"start": 1392.16, "end": 1393.48, "word": " معلقة", "probability": 0.95703125}, {"start": 1393.48, "end": 1394.34, "word": " بخط", "probability": 0.84716796875}, {"start": 1394.34, "end": 1395.02, "word": " خفيف", "probability": 0.9773763020833334}, {"start": 1395.02, "end": 1395.6, "word": " معلقة", "probability": 0.9033203125}, {"start": 1395.6, "end": 1395.86, "word": " بخط", "probability": 0.9938151041666666}, {"start": 1395.86, "end": 1396.52, "word": " خفيف", "probability": 0.9866536458333334}, {"start": 1396.52, "end": 1397.74, "word": " الرصاصة", "probability": 0.9598388671875}, {"start": 1397.74, "end": 1398.18, "word": " سكنت", "probability": 0.8935546875}, {"start": 1398.18, "end": 1398.36, "word": " في", "probability": 0.97607421875}, {"start": 1398.36, "end": 1399.14, "word": " الخشبة", "probability": 0.9677734375}, {"start": 1399.14, "end": 1400.58, "word": " وضلت", "probability": 0.9156494140625}, {"start": 1400.58, "end": 1401.04, "word": " فيها", "probability": 0.99072265625}, {"start": 1401.04, "end": 1402.18, "word": " وارتفعت", "probability": 0.9873046875}, {"start": 1402.18, "end": 1403.42, "word": " مسافاتش", "probability": 0.8779296875}, {"start": 1403.42, "end": 1403.64, "word": " او", "probability": 0.815185546875}, {"start": 1403.64, "end": 1404.44, "word": " ارتفعتش", "probability": 0.98515625}, {"start": 1404.44, "end": 1405.38, "word": " assume", "probability": 0.7900390625}, {"start": 1405.38, "end": 1405.96, "word": " that", "probability": 0.9501953125}, {"start": 1405.96, "end": 1406.22, "word": " the", "probability": 0.88623046875}, {"start": 1406.22, "end": 1406.54, "word": " mass", "probability": 0.9189453125}, {"start": 1406.54, "end": 1406.7, "word": " of", "probability": 0.9833984375}, {"start": 1406.7, "end": 1406.88, "word": " the", "probability": 0.92138671875}, {"start": 1406.88, "end": 1407.16, "word": " biolet", "probability": 0.4712727864583333}, {"start": 1407.16, "end": 1407.62, "word": " كتلة", "probability": 0.9637044270833334}, {"start": 1407.62, "end": 1408.3, "word": " الرصاصة", "probability": 0.9742431640625}, {"start": 1408.3, "end": 1408.64, "word": " كانت", "probability": 0.97412109375}, {"start": 1408.64, "end": 1409.02, "word": " خمسة", "probability": 0.8934326171875}, {"start": 1409.02, "end": 1409.34, "word": " جرام", "probability": 0.8091634114583334}], "temperature": 1.0}, {"id": 53, "seek": 143682, "start": 1409.8, "end": 1436.82, "text": "وكتلة الخشبة كانت واحد كيلو والارتفاع اللى وصلته خمسة find the velocity of the system after the bullet embeds in the block بده السرعة .. سرعة النظام بعد ما .. ما الخشبة دخلت في اللى هو الارصاصة دخلت في الخشبة وطلعوا مسافة هى ارصاصة بتمشي بسرعة معينة V initial هنا الخشبة ثابتة", "tokens": [2407, 4117, 2655, 37977, 33962, 8592, 49401, 25961, 2655, 36764, 24401, 9122, 26895, 2407, 4032, 6027, 9640, 2655, 5172, 45761, 13672, 7578, 4032, 36520, 47395, 16490, 2304, 3794, 3660, 915, 264, 9269, 295, 264, 1185, 934, 264, 11632, 12240, 82, 294, 264, 3461, 47525, 3224, 21136, 2288, 27884, 4386, 8608, 2288, 27884, 28239, 19913, 10943, 39182, 19446, 4386, 19446, 33962, 8592, 49401, 11778, 9778, 1211, 2655, 8978, 13672, 7578, 31439, 2423, 9640, 9381, 33546, 3660, 11778, 9778, 1211, 2655, 8978, 33962, 8592, 49401, 4032, 9566, 1211, 3615, 14407, 47524, 31845, 3660, 8032, 7578, 1975, 2288, 9381, 33546, 3660, 39894, 2304, 8592, 1829, 4724, 3794, 2288, 27884, 20449, 9957, 3660, 691, 5883, 34105, 33962, 8592, 49401, 38637, 16758, 2655, 3660], "avg_logprob": -0.1671875011175871, "compression_ratio": 1.7389558232931728, "no_speech_prob": 2.384185791015625e-07, "words": [{"start": 1409.8, "end": 1410.38, "word": "وكتلة", "probability": 0.945068359375}, {"start": 1410.38, "end": 1411.12, "word": " الخشبة", "probability": 0.95361328125}, {"start": 1411.12, "end": 1411.98, "word": " كانت", "probability": 0.984375}, {"start": 1411.98, "end": 1412.3, "word": " واحد", "probability": 0.7479248046875}, {"start": 1412.3, "end": 1412.82, "word": " كيلو", "probability": 0.9280598958333334}, {"start": 1412.82, "end": 1414.04, "word": " والارتفاع", "probability": 0.8268229166666666}, {"start": 1414.04, "end": 1414.2, "word": " اللى", "probability": 0.796142578125}, {"start": 1414.2, "end": 1414.56, "word": " وصلته", "probability": 0.7823893229166666}, {"start": 1414.56, "end": 1415.36, "word": " خمسة", "probability": 0.8970947265625}, {"start": 1415.36, "end": 1415.8, "word": " find", "probability": 0.470703125}, {"start": 1415.8, "end": 1416.02, "word": " the", "probability": 0.9189453125}, {"start": 1416.02, "end": 1416.26, "word": " velocity", "probability": 0.275146484375}, {"start": 1416.26, "end": 1416.42, "word": " of", "probability": 0.97412109375}, {"start": 1416.42, "end": 1416.56, "word": " the", "probability": 0.9130859375}, {"start": 1416.56, "end": 1416.86, "word": " system", "probability": 0.86328125}, {"start": 1416.86, "end": 1417.24, "word": " after", "probability": 0.90185546875}, {"start": 1417.24, "end": 1417.94, "word": " the", "probability": 0.87890625}, {"start": 1417.94, "end": 1418.48, "word": " bullet", "probability": 0.298095703125}, {"start": 1418.48, "end": 1419.62, "word": " embeds", "probability": 0.6004638671875}, {"start": 1419.62, "end": 1419.82, "word": " in", "probability": 0.95556640625}, {"start": 1419.82, "end": 1420.0, "word": " the", "probability": 0.88818359375}, {"start": 1420.0, "end": 1420.28, "word": " block", "probability": 0.90673828125}, {"start": 1420.28, "end": 1421.14, "word": " بده", "probability": 0.73095703125}, {"start": 1421.14, "end": 1422.06, "word": " السرعة", "probability": 0.9326171875}, {"start": 1422.06, "end": 1422.46, "word": " ..", "probability": 0.62646484375}, {"start": 1422.46, "end": 1423.3, "word": " سرعة", "probability": 0.87646484375}, {"start": 1423.3, "end": 1423.82, "word": " النظام", "probability": 0.98681640625}, {"start": 1423.82, "end": 1424.42, "word": " بعد", "probability": 0.990234375}, {"start": 1424.42, "end": 1424.58, "word": " ما", "probability": 0.8212890625}, {"start": 1424.58, "end": 1424.8, "word": " ..", "probability": 0.51513671875}, {"start": 1424.8, "end": 1425.04, "word": " ما", "probability": 0.77685546875}, {"start": 1425.04, "end": 1425.7, "word": " الخشبة", "probability": 0.98193359375}, {"start": 1425.7, "end": 1427.14, "word": " دخلت", "probability": 0.9664306640625}, {"start": 1427.14, "end": 1427.36, "word": " في", "probability": 0.935546875}, {"start": 1427.36, "end": 1427.76, "word": " اللى", "probability": 0.95556640625}, {"start": 1427.76, "end": 1428.08, "word": " هو", "probability": 0.8642578125}, {"start": 1428.08, "end": 1429.56, "word": " الارصاصة", "probability": 0.8744140625}, {"start": 1429.56, "end": 1429.84, "word": " دخلت", "probability": 0.968017578125}, {"start": 1429.84, "end": 1429.92, "word": " في", "probability": 0.6396484375}, {"start": 1429.92, "end": 1430.28, "word": " الخشبة", "probability": 0.9921875}, {"start": 1430.28, "end": 1430.66, "word": " وطلعوا", "probability": 0.815576171875}, {"start": 1430.66, "end": 1431.02, "word": " مسافة", "probability": 0.9571940104166666}, {"start": 1431.02, "end": 1431.28, "word": " هى", "probability": 0.416259765625}, {"start": 1431.28, "end": 1432.2, "word": " ارصاصة", "probability": 0.90078125}, {"start": 1432.2, "end": 1434.22, "word": " بتمشي", "probability": 0.9234619140625}, {"start": 1434.22, "end": 1434.52, "word": " بسرعة", "probability": 0.9796142578125}, {"start": 1434.52, "end": 1434.92, "word": " معينة", "probability": 0.9864908854166666}, {"start": 1434.92, "end": 1435.02, "word": " V", "probability": 0.65869140625}, {"start": 1435.02, "end": 1435.52, "word": " initial", "probability": 0.69970703125}, {"start": 1435.52, "end": 1435.82, "word": " هنا", "probability": 0.59716796875}, {"start": 1435.82, "end": 1436.22, "word": " الخشبة", "probability": 0.9912109375}, {"start": 1436.22, "end": 1436.82, "word": " ثابتة", "probability": 0.9564208984375}], "temperature": 1.0}, {"id": 54, "seek": 146378, "start": 1437.34, "end": 1463.78, "text": "الخشب واحد kilogram هذه خمسين ك .. خمسين gram أو الارصاصة كتلتها .. الارصاصة كتلتها خمس .. لحظة الارصاصة كتلتها كانت خمسة gram الان نيجي نحل .. بدنا نحل هذا السؤال find the velocity of the system after the bullet embeds in the block بدأ أستخدم apply conservation of energy", "tokens": [6027, 9778, 8592, 3555, 36764, 24401, 21741, 29538, 16490, 2304, 3794, 9957, 9122, 4386, 16490, 2304, 3794, 9957, 21353, 34051, 2423, 9640, 9381, 33546, 3660, 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potential energy after the collision", "tokens": [3555, 9957, 2423, 3461, 4032, 2423, 11632, 12399, 2423, 3461, 37495, 22653, 33962, 8592, 49401, 4032, 11632, 37495, 22653, 34892, 9381, 33546, 3660, 8032, 1863, 5016, 4117, 1829, 14739, 23032, 995, 28671, 21542, 31747, 3660, 1975, 2407, 9122, 1829, 29399, 4117, 2281, 30767, 16373, 3215, 3995, 2281, 934, 264, 24644], "avg_logprob": -0.2503063748864567, "compression_ratio": 1.4054054054054055, "no_speech_prob": 8.64267349243164e-06, "words": [{"start": 1464.21, "end": 1464.57, "word": "بين", "probability": 0.845703125}, {"start": 1464.57, "end": 1464.67, "word": " ال", "probability": 0.91064453125}, {"start": 1464.67, "end": 1464.91, "word": " block", "probability": 0.783203125}, {"start": 1464.91, "end": 1465.05, "word": " و", "probability": 0.947265625}, {"start": 1465.05, "end": 1465.13, "word": " ال", "probability": 0.783203125}, {"start": 1465.13, "end": 1465.59, "word": " bullet،", "probability": 0.3538818359375}, {"start": 1465.59, 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{"start": 1572.25, "end": 1572.73, "word": " M2", "probability": 0.77978515625}, {"start": 1572.73, "end": 1572.91, "word": " في", "probability": 0.8662109375}, {"start": 1572.91, "end": 1573.03, "word": " V", "probability": 0.86279296875}, {"start": 1573.03, "end": 1573.25, "word": " لل", "probability": 0.5224609375}, {"start": 1573.25, "end": 1573.59, "word": " system", "probability": 0.68359375}, {"start": 1573.59, "end": 1574.53, "word": " كله", "probability": 0.975341796875}, {"start": 1574.53, "end": 1575.29, "word": " V2", "probability": 0.875244140625}, {"start": 1575.29, "end": 1575.63, "word": " initial", "probability": 0.82470703125}, {"start": 1575.63, "end": 1576.05, "word": " كانت", "probability": 0.97021484375}, {"start": 1576.05, "end": 1576.37, "word": " Zero", "probability": 0.400634765625}, {"start": 1576.37, "end": 1576.93, "word": " للخشبة", "probability": 0.833447265625}, {"start": 1576.93, "end": 1577.29, "word": " كانت", "probability": 0.982666015625}, {"start": 1577.29, "end": 1577.99, "word": " ثابتة", "probability": 0.9417724609375}, {"start": 1577.99, "end": 1578.85, "word": " M1", "probability": 0.963623046875}, {"start": 1578.85, "end": 1579.49, "word": " للارصاصة", "probability": 0.89521484375}, {"start": 1579.49, "end": 1580.03, "word": " خمسة", "probability": 0.93408203125}, {"start": 1580.03, "end": 1580.79, "word": " مقسمها", "probability": 0.80889892578125}, {"start": 1580.79, "end": 1581.01, "word": " على", "probability": 0.830078125}, {"start": 1581.01, "end": 1581.35, "word": " الف", "probability": 0.53662109375}, {"start": 1581.35, "end": 1581.59, "word": " عشان", "probability": 0.9724934895833334}, {"start": 1581.59, "end": 1581.97, "word": " تصير", "probability": 0.7725423177083334}, {"start": 1581.97, "end": 1582.63, "word": " بالكيلو", "probability": 0.8052978515625}, {"start": 1582.63, "end": 1583.53, "word": " هيها", "probability": 0.6632080078125}, {"start": 1583.53, "end": 1584.87, "word": " خمسة", "probability": 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0.96533203125}, {"start": 1591.63, "end": 1592.03, "word": " كانت", "probability": 0.9912109375}, {"start": 1592.03, "end": 1592.31, "word": " Zero", "probability": 0.91796875}, {"start": 1592.31, "end": 1592.87, "word": " اذا", "probability": 0.605224609375}, {"start": 1592.87, "end": 1593.43, "word": " V1", "probability": 0.947998046875}, {"start": 1593.43, "end": 1593.89, "word": " initial", "probability": 0.9013671875}, {"start": 1593.89, "end": 1594.45, "word": " بتساوي", "probability": 0.915283203125}, {"start": 1594.45, "end": 1594.91, "word": " M1", "probability": 0.98193359375}, {"start": 1594.91, "end": 1595.13, "word": " زي", "probability": 0.9521484375}, {"start": 1595.13, "end": 1595.91, "word": " M2", "probability": 0.99267578125}, {"start": 1595.91, "end": 1596.59, "word": " هذا", "probability": 0.2225341796875}, {"start": 1596.59, "end": 1597.05, "word": " سفر", "probability": 0.8123372395833334}, {"start": 1597.05, "end": 1597.87, "word": " V1", "probability": 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{"start": 1603.38, "end": 1603.82, "word": " سرعة", "probability": 0.87841796875}, {"start": 1603.82, "end": 1604.38, "word": " الإرصاص", "probability": 0.81585693359375}, {"start": 1604.38, "end": 1605.34, "word": " 199", "probability": 0.80810546875}, {"start": 1605.34, "end": 1607.02, "word": " متر", "probability": 0.93701171875}, {"start": 1607.02, "end": 1607.38, "word": " في", "probability": 0.9072265625}, {"start": 1607.38, "end": 1607.94, "word": " التانية", "probability": 0.79052734375}, {"start": 1607.94, "end": 1608.9, "word": " عشان", "probability": 0.9378255208333334}, {"start": 1608.9, "end": 1609.0, "word": " هي", "probability": 0.92578125}, {"start": 1609.0, "end": 1609.48, "word": " سرعتها", "probability": 0.89990234375}, {"start": 1609.48, "end": 1609.74, "word": " كبيرة", "probability": 0.9793294270833334}, {"start": 1609.74, "end": 1610.04, "word": " كتير", "probability": 0.9635416666666666}, {"start": 1610.04, "end": 1610.46, "word": " كانت", "probability": 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ.srt
new file mode 100644
index 0000000000000000000000000000000000000000..dd5b661eedbddaf3ff6855887ea7b5231f063896
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ.srt
@@ -0,0 +1,1438 @@
+1
+00:00:00,000 --> 00:00:03,780
+بسم الله الرحمن الرحيم. بنستكمل chapter خمسة و
+
+2
+00:00:03,780 --> 00:00:06,780
+بنبدأ بـ section خمسة تلاتة: أنوع gravitational
+
+3
+00:00:06,780 --> 00:00:11,960
+potential energy اللي هي طاقة وضع الخاصة بـ
+
+4
+00:00:11,960 --> 00:00:16,020
+الجاذبية. an object with kinetic energy, energy of
+
+5
+00:00:16,020 --> 00:00:21,240
+motion can do work on another object. ممكن يعني أي
+
+6
+00:00:21,240 --> 00:00:29,430
+جسم بِطاقة حركة معينة يعمل شغل على جسم ثاني. طبعاً هذا
+
+7
+00:00:29,430 --> 00:00:34,390
+الكلام مثال عليه. ممكن يتحرك just طبعاً hammer can
+
+8
+00:00:34,390 --> 00:00:38,610
+drive a nail into a wall. يعني مطرقة ممكن تطرق مسمار
+
+9
+00:00:38,610 --> 00:00:42,870
+داخل الحائط. A crack on a high shelf can also do work.
+
+10
+00:00:42,870 --> 00:00:49,420
+برضه أيضاً. ممكن طوب في الحائط، يسقط على من أعلى الرف
+
+11
+00:00:49,420 --> 00:00:54,620
+من أعلى ويسقط ويعمل أيضاً شغل. ممكن طبعاً يسقط من
+
+12
+00:00:54,620 --> 00:00:59,360
+أعلى الرف، إذا سقطت من أعلى إلى أسفل بتعمل بتسارع
+
+13
+00:00:59,360 --> 00:01:03,820
+معين. طبعاً هذه هتسقط تلقائياً بتسارع جاذبية إلى أسفل.
+
+14
+00:01:03,820 --> 00:01:07,420
+downward. It’s hit a nail squarely, driving it into
+
+15
+00:01:07,420 --> 00:01:11,400
+a floor. ممكن الطوب يقع على المسمار، وبالتالي
+
+16
+00:01:11,400 --> 00:01:14,560
+يقع على الأرض. معناه الكلام: في عندي أنا أكثر من نوع
+
+17
+00:01:14,560 --> 00:01:18,330
+من الطاقة. في عندي طاقة حركة، في عندي طاقة وضع اللي
+
+18
+00:01:18,330 --> 00:01:20,470
+هي الـ kinetic energy، وفي عندي potential energy.
+
+19
+00:01:20,470 --> 00:01:23,990
+ممكن يعني يكون عندي أنا مثال المطرقة أو المسمار
+
+20
+00:01:23,990 --> 00:01:27,790
+يعمل لي طاقة حركة. ممكن الطوب إذا وقعت على المسمار
+
+21
+00:01:27,790 --> 00:01:31,370
+يعني هو انتقال من مكان لمكان، هو يعني تغير في طاقة
+
+22
+00:01:31,370 --> 00:01:35,590
+الوضع. وبالتالي لو أنا الطوب انتقلت أو وقعت من
+
+23
+00:01:35,590 --> 00:01:39,190
+أعلى إلى أسفل، بنحكي أنه the break is set to be
+
+24
+00:01:39,190 --> 00:01:44,450
+potential energy. أنه عملت طاقة وضع مرتبطة فيها. هي
+
+25
+00:01:44,450 --> 00:01:50,270
+طاقة الوضع تحدث بسبب التغير في المكان. طبعاً مكانها
+
+26
+00:01:50,270 --> 00:01:54,730
+بالنسبة لها اللي هي الـ .. اللي هي الموضوع الرأسي أو
+
+27
+00:01:54,730 --> 00:01:58,630
+اللي هي الـ vertical location. الـ potential energy
+
+28
+00:01:58,630 --> 00:02:01,630
+is a property of the system. برضه طاقة الوضع هي
+
+29
+00:02:01,630 --> 00:02:07,860
+خاصية لأي نظام. ممكن يكون لحاله. ممكن أن هذا الجسم
+
+30
+00:02:07,860 --> 00:02:10,780
+يكون على ارتفاع معين وينزل لارتفاع ثاني، أو يكون
+
+31
+00:02:10,780 --> 00:02:14,600
+على الأرض ويصعد إلى أعلى. وبالتالي طبعاً بتغير
+
+32
+00:02:14,600 --> 00:02:17,380
+relative بالنسبة لـ position لما كان of interacting
+
+33
+00:02:17,380 --> 00:02:22,380
+objects in the system, such as زي المثال خمسة واحد
+
+34
+00:02:22,380 --> 00:02:26,920
+لما كان اللي هو اللي اللي اللي طبعاً الـ .. الـ .. الـ
+
+35
+00:02:26,920 --> 00:02:30,040
+.. البنت أو الصبية كانت على ارتفاع معين وسقطت
+
+36
+00:02:30,040 --> 00:02:33,460
+إلى البحر. يعني هذا فيه تغير في طاقة اللي هي الوضع.
+
+37
+00:02:33,460 --> 00:02:37,440
+It turns out that potential
+
+38
+00:02:37,440 --> 00:02:43,970
+energy is another way for another way of .. for
+
+39
+00:02:43,970 --> 00:02:46,750
+طبعاً looking at the work done by the conservative
+
+40
+00:02:46,750 --> 00:02:50,810
+force. برضه مثال على الـ conservative force اللي هي
+
+41
+00:02:50,810 --> 00:02:53,910
+طاقة الوضع. إذا كان في عندي نوعياً للـ conservative
+
+42
+00:02:53,910 --> 00:02:58,310
+force. إذا كان في عندي أنا الـ gravitational طبعاً
+
+43
+00:02:58,310 --> 00:03:03,320
+potential energy أو اللي هي potential energy. هذه هي
+
+44
+00:03:03,320 --> 00:03:06,300
+أولى gravity. برضه هذه أمثلة على اللي هي الـ
+
+45
+00:03:06,300 --> 00:03:11,280
+conservative force لأنها طاقة، قوة محفوظة في
+
+46
+00:03:11,280 --> 00:03:15,880
+section خمسة تلاتة واحد. بنتحدث عن الشغل الناتج عن
+
+47
+00:03:15,880 --> 00:03:20,360
+الجاذبية وطاقة الوضع. Gravitational work and
+
+48
+00:03:20,360 --> 00:03:24,480
+potential energy. اللي هو طاقة الشغل الناتج عن
+
+49
+00:03:24,480 --> 00:03:29,200
+الجاذبية وطاقة الوضع. Using the work-energy theorem.
+
+50
+00:03:29,200 --> 00:03:34,170
+ده استخدم نظرية الطاقة والشغل في هذه .. في بعض الـ
+
+51
+00:03:34,170 --> 00:03:38,750
+.. طبعاً المسائل وبعض الأمثلة تتضمن gravitation.
+
+52
+00:03:38,750 --> 00:03:41,450
+Requires computing the work done by gravity.
+
+53
+00:03:41,450 --> 00:03:44,350
+ممكن أنه يحسب أنا الشغل الناتج عن الجاذبية في بعض
+
+54
+00:03:44,350 --> 00:03:48,750
+المسائل. زي ما اتفقنا أو ما تكلمنا سابقاً أن الـ
+
+55
+00:03:48,750 --> 00:03:52,470
+gravity، الجاذبية هي نوعاً من الـ conservative force.
+
+56
+00:03:52,470 --> 00:03:56,010
+اللي هي القوة المحفوظة. And for every conservative
+
+57
+00:03:56,010 --> 00:04:00,900
+force, a special expression called لكل طبعاً قوة ..
+
+58
+00:04:00,900 --> 00:04:05,440
+قوة محفوظة، في عندي أنا تعريف معين بيسموه potential
+
+59
+00:04:05,440 --> 00:04:10,180
+energy function، دالة طاقة الوضع. هذه هي مقياس أو
+
+60
+00:04:10,180 --> 00:04:15,400
+يعني إشارة إلى أنها conservative force. إيجاد أو
+
+61
+00:04:15,400 --> 00:04:18,760
+حساب هذه الدالة at any two points in an object’s
+
+62
+00:04:18,760 --> 00:04:21,840
+part of the motion, and finding the difference will
+
+63
+00:04:21,840 --> 00:04:24,700
+give the negative of the work done by the force
+
+64
+00:04:24,700 --> 00:04:30,790
+between those two points. لحساب هذه الدالة بين
+
+65
+00:04:30,790 --> 00:04:36,670
+نقطتين لمسار جسم، خلال نقطتين خلال حركته طبعاً
+
+66
+00:04:36,670 --> 00:04:42,150
+بيبدأ يِوجد الفرق بين هدول النقطتين، بيعطيني سالب
+
+67
+00:04:42,150 --> 00:04:47,850
+الشغل المبذول بواسطة هذه القوة بين النقطتين. طاقة
+
+68
+00:04:47,850 --> 00:04:52,070
+الوضع بتشبه الشغل، وبتشبه أيضاً طاقة الحركة بأنه
+
+69
+00:04:52,070 --> 00:04:55,990
+طاقة الوضع وطاقة الحركة والشغل هي عبارة عن كمية
+
+70
+00:04:56,290 --> 00:05:00,130
+scalar quantity، أي كمية قياسية. إذا الشغل كمية
+
+71
+00:05:00,130 --> 00:05:04,230
+قياسية، طاقة الحركة كمية قياسية، وطاقة الوضع كمية
+
+72
+00:05:04,230 --> 00:05:09,230
+قياسية. بدأ أفرض في عندي كتاب يسقط من ارتفاع معين
+
+73
+00:05:09,230 --> 00:05:14,570
+اسمه y initial. طبعاً عندي أنا الكتاب هنا وهنا في
+
+74
+00:05:14,570 --> 00:05:18,470
+عندي level معين اللي هو الأرض هيها. في الارتفاع كان
+
+75
+00:05:18,470 --> 00:05:21,890
+initial، يعني في البداية كان على ارتفاع Y initial.
+
+76
+00:05:21,890 --> 00:05:27,530
+نزل، سقط، صار في المنطقة هذه على ارتفاع Y final. إذا
+
+77
+00:05:27,530 --> 00:05:31,810
+في تغير في اللي هي النقاط أو الرأسية أو مكان
+
+78
+00:05:31,810 --> 00:05:36,150
+الكتاب. كان في initial وراح لـ final في هذا الشكل.
+
+79
+00:05:36,150 --> 00:05:42,650
+بيحكي لي هنا الـ .. الـ .. مثلاً a book of mass M، كتاب
+
+80
+00:05:42,650 --> 00:05:48,520
+كتلة M، سقط from height y، سقط من ارتفاع y initial
+
+81
+00:05:48,520 --> 00:05:52,140
+to height y final. سقط من ارتفاع y initial إلى y
+
+82
+00:05:52,140 --> 00:05:56,540
+final. حيث أن الـ positive y coordinate represents a
+
+83
+00:05:56,540 --> 00:06:00,780
+position above the ground. طبعاً عندما أتحدث عن تغير
+
+84
+00:06:00,780 --> 00:06:05,580
+في طاقة الوضع، بنختار مستوى معين أو level معين. إذا
+
+85
+00:06:05,580 --> 00:06:09,400
+أنا اخترت الـ level مثلاً للأرض، بهذا كـ level كمستوى
+
+86
+00:06:09,400 --> 00:06:12,860
+أساس يكون مرجعية، reference frame، مرجعية لي عشان
+
+87
+00:06:12,860 --> 00:06:17,120
+أحدد هل طاقة الوضع موجبة أو سالبة أو zero. إذا كان
+
+88
+00:06:17,120 --> 00:06:21,060
+الجسم على الـ level أو على الأرض مباشرة، فبيكون ..
+
+89
+00:06:21,060 --> 00:06:24,960
+تكون طاقة الوضع zero، لأن الـ level .. الجسم على الـ
+
+90
+00:06:24,960 --> 00:06:29,180
+level مباشرة. إذا كان الجسم أعلى من الـ level، فطاقة
+
+91
+00:06:29,180 --> 00:06:32,200
+الوضع موجبة. وإذا كان أسفل من الـ level، فطاقة الوضع
+
+92
+00:06:32,200 --> 00:06:35,600
+سالبة. هاي معنى هذا الكلام، إن الـ positive y
+
+93
+00:06:35,600 --> 00:06:39,080
+coordinate represents a position above the ground. يعني
+
+94
+00:06:39,080 --> 00:06:42,820
+محور Y الموجب، بأعلى اللي هو. إذا كان فرضية أنا
+
+95
+00:06:42,820 --> 00:06:47,110
+الأرض هي الـ level، بيكون اللي بيكون هو طاقة الوضع
+
+96
+00:06:47,110 --> 00:06:52,610
+موجبة لأنه .. لأن الجسم أعلى من الـ level ويمثل
+
+97
+00:06:52,610 --> 00:06:57,430
+اللي هي المحور Y الموجب. We neglect the force of
+
+98
+00:06:57,430 --> 00:07:01,410
+air friction. طبعاً نهمل القوة الناتجة عن احتكاك
+
+99
+00:07:01,410 --> 00:07:06,270
+الهواء. So the only force acting on the book is
+
+100
+00:07:06,270 --> 00:07:09,870
+gravitation. معنا الكلام: مع اهمال القوة الناتجة عن
+
+101
+00:07:09,870 --> 00:07:14,730
+طبعاً احتكاك الهواء أو مقاومة الهواء، بيكون عندي ..
+
+102
+00:07:14,730 --> 00:07:18,860
+بيكون عندنا القوة المؤثرة على الكتاب هي قوة
+
+103
+00:07:18,860 --> 00:07:23,120
+الجاذبية. بدنا نسأل يعني: how much work is done? طبعاً
+
+104
+00:07:23,120 --> 00:07:26,660
+ما هو الشغل المبذول عندما سقط الجسم من ارتفاع y
+
+105
+00:07:26,660 --> 00:07:30,320
+initial و y final? The magnitude of the force
+
+106
+00:07:30,320 --> 00:07:32,740
+طبعاً القوة المؤثرة عندي في هذه الحالة اللي هي الـ
+
+107
+00:07:32,740 --> 00:07:37,660
+mg، قوة الجاذبية، وهي مشت مسافة من الـ initial إلى الـ
+
+108
+00:07:37,660 --> 00:07:42,000
+final. الكتاب ماشي مسافة رأسية اسمها delta Y، وهي
+
+109
+00:07:42,000 --> 00:07:46,460
+عبارة عن Y initial ناقص Y final، اللي هي الـ
+
+110
+00:07:46,460 --> 00:07:50,180
+positive number، لأن الـ Y initial أكبر من الـ Y
+
+111
+00:07:50,180 --> 00:07:53,800
+final. فبيطلع عندي أنا موجب. بينما الـ F والـ والـ delta
+
+112
+00:07:53,800 --> 00:07:59,360
+Y، اللي طبعاً الزاوية بينهم zero، لأنه الاتجاه
+
+113
+00:07:59,360 --> 00:08:02,200
+للأسفل، ودول اتجاه الأسفل. إذا الجسم سقط من
+
+114
+00:08:02,200 --> 00:08:05,480
+أعلى إلى أسفل، وبالتالي الزاوية zero. معناه الكلام
+
+115
+00:08:05,480 --> 00:08:11,140
+دي المسافة المَشيها .. مشيها الكتاب، اللي هو عبارة
+
+116
+00:08:11,140 --> 00:08:14,920
+عن d، بيساوي y initial ناقص y final. We apply the
+
+117
+00:08:14,920 --> 00:08:18,740
+definition of work equation. بدي أنا أُعوّض ..
+
+118
+00:08:18,740 --> 00:08:23,860
+أطبق قانون الشغل، اللي هو عبارة عن WG، اللي هو الشغل
+
+119
+00:08:23,860 --> 00:08:30,390
+الناتج عن الجاذبية، بدي يساوي Fd cos θ. الـ F كانت
+
+120
+00:08:30,390 --> 00:08:34,670
+اللي هي الـ mg، و d، المسافة المَشيها y initial ناقص y final،
+
+121
+00:08:34,670 --> 00:08:40,530
+cos θ، اللي هي cos 0. طبعاً هيتبقى معايا ناقص mg y
+
+122
+00:08:40,530 --> 00:08:45,490
+final ناقص y initial. ممكن أُعدلها زي ما هي mg y
+
+123
+00:08:45,490 --> 00:08:49,750
+initial ناقص y final، في cos 0. cos 0 = 1، فلما
+
+124
+00:08:49,750 --> 00:08:53,730
+ضربناها بـ 1، صارت ناقص mg y final ناقص y initial.
+
+125
+00:08:53,730 --> 00:08:58,330
+ممكن أحط موجب mg y initial ناقص y final، لكن معظم
+
+126
+00:08:58,330 --> 00:09:01,810
+الطلاب متعودين يحطوا اللي هي الـ y final ناقص y
+
+127
+00:09:01,810 --> 00:09:06,430
+initial. وبالتالي في هذه الحالة، إذا سقط جسم من أعلى
+
+128
+00:09:06,430 --> 00:09:11,350
+إلى أسفل خلال مسافة رأسية، فالشغل الناتج عن الجاذبية
+
+129
+00:09:11,350 --> 00:09:15,950
+بيساوي ناقص mg y final ناقص y initial.
+
+130
+00:09:18,980 --> 00:09:23,200
+المعادلة هذه، معادلة خمسة تسعة، for gravitational
+
+131
+00:09:23,200 --> 00:09:27,880
+work، للشغل الناتج عن الجاذبية. ممكن أطبقها لأي جسم
+
+132
+00:09:27,880 --> 00:09:32,980
+regardless of its trajectory in space, because the
+
+133
+00:09:32,980 --> 00:09:35,740
+gravitational force is conservative. بغض النظر عن
+
+134
+00:09:35,740 --> 00:09:41,040
+مسار الجسم في الفضاء، لأن الشغل الناتج عن الجاذبية
+
+135
+00:09:41,040 --> 00:09:45,120
+بسبب الـ gravitational force وهي conservative force.
+
+136
+00:09:45,610 --> 00:09:51,050
+الآن الـ WG، هذا الشغل الناتج عن الجاذبية، ممكن will
+
+137
+00:09:51,050 --> 00:09:54,530
+appear، يظهر as the work done by gravity in the
+
+138
+00:09:54,530 --> 00:09:57,730
+work-energy theorem. ممكن أسميه شغل ناتج عن الجاذبية
+
+139
+00:09:57,730 --> 00:10:02,460
+في نظرية الطاقة والشغل. For the rest of these
+
+140
+00:10:02,460 --> 00:10:06,020
+sections, assume for simplicity that we are dealing
+
+141
+00:10:06,020 --> 00:10:08,620
+only with systems involving gravity and non-
+
+142
+00:10:08,620 --> 00:10:14,020
+conservative forces. الآن بدأ أفرض أنه للسهولة طبعاً
+
+143
+00:10:14,020 --> 00:10:19,720
+أنه نظام طبعاً with systems involving gravity and
+
+144
+00:10:19,720 --> 00:10:23,880
+non-conservative forces. The equation خمسة تمانية
+
+145
+00:10:23,880 --> 00:10:28,100
+can be written. يعني لو كان عندي أنا اللي هو النظام
+
+146
+00:10:28,100 --> 00:10:31,970
+الجاذبية اللي هو الـ conservative، زيادة إلى عندي
+
+147
+00:10:31,970 --> 00:10:35,570
+أنا non-conservative force، فبيصير عندي الشغل الكلي
+
+148
+00:10:35,570 --> 00:10:39,870
+اللي هو عبارة عن delta K. طبعاً عرفناها سابقاً إذا
+
+149
+00:10:39,870 --> 00:10:43,830
+الشغل كله بيساوي WNC، يعني الشغل الناتج عن الـ non-
+
+150
+00:10:43,830 --> 00:10:47,580
+conservative، زائد WG، الشغل الناتج عن اللي هي الـ
+
+151
+00:10:47,580 --> 00:10:51,120
+gravity أو الـ conservative، بيساوي Delta K. إذا
+
+152
+00:10:51,120 --> 00:10:56,220
+الشغل الكل، ممكن نحكي أنه الشغل الكلي W net بيساوي
+
+153
+00:10:56,220 --> 00:11:03,100
+WNC زائد WG، أو WNC زائد WG، بيساوي Delta K. WNC هي
+
+154
+00:11:03,100 --> 00:11:06,060
+عبارة عن الشغل الناتج عن الـ non-conservative
+
+155
+00:11:06,060 --> 00:11:10,300
+force، والـ WG هو الشغل الناتج عن الـ conservative
+
+156
+00:11:10,300 --> 00:11:15,400
+force. إذا لو عوضنا عن WG بـ ناقص mg و y final ناقص
+
+157
+00:11:15,400 --> 00:11:21,580
+y initial، فبيطلع عندنا WNC ناقص
+
+158
+00:11:21,580 --> 00:11:25,620
+mg و y final ناقص y initial، بيساوي Delta K، تغير في
+
+159
+00:11:25,620 --> 00:11:30,680
+طاقة الحركة. وبالتالي،  دل الـ W اللي هو الشغل الناتج
+
+160
+00:11:30,680 --> 00:11:34,600
+عن الـ conservative، بيساوي Delta K زائد mg y final
+
+161
+00:11:34,600 --> 00:11:39,960
+ناقص y initial. Now، هاي هدول قانون طبعاً خمسة عشرة.
+
+162
+00:11:39,960 --> 00:11:44,500
+Now, by definition, we make the connection between
+
+163
+00:11:44,500 --> 00:11:46,380
+gravitational work and gravitational potential
+
+164
+00:11:46,380 --> 00:11:50,280
+energy. طبعاً في علاقة بين الشغل الناتج عن الجاذبية
+
+165
+00:11:50,280 --> 00:11:53,760
+والشغل اللي هي work and gravitational potential
+
+166
+00:11:53,760 --> 00:11:57,200
+energy، طاقة الوضع. طاقة وضع الجاذبية لـ
+
+167
+00:11:57,200 --> 00:11:59,160
+gravitational potential energy of the system
+
+168
+00:11:59,160 --> 00:12:01,960
+consisting of the earth and an object of mass m near
+
+169
+00:12:01,960 --> 00:12:07,120
+the earth’s surface is given by. طبعاً طاقة الوضع الناتج
+
+170
+00:12:07,120 --> 00:12:12,320
+عن الجاذبية لها علاقة بأي جسم بيكون على سطح قريب
+
+171
+00:12:12,320 --> 00:12:16,120
+من سطح الأرض، وعلى ارتفاع معين من الأرض بيكون له
+
+172
+00:12:16,120 --> 00:12:19,660
+طاقة وضع. ممكن الأرض تكون level، ممكن طاولة، ممكن أي
+
+173
+00:12:19,660 --> 00:12:23,920
+شيء. لكن مبدئياً، بصفة عامة، طاقة الوضع ناتج عن
+
+174
+00:12:23,920 --> 00:12:29,570
+الجاذبية هي مرتبطة بالأرض، وأي جسم بيكون قريب من
+
+175
+00:12:29,570 --> 00:12:33,070
+الأرض له طاقة وضع اللي هي potential energy
+
+176
+00:12:33,070 --> 00:12:38,370
+بتساوي mgy. Y هذا
+
+223
+00:16:04,400 --> 00:16:08,620
+Delta K + Delta B هذه المعادلة خمسة طلتاش
+
+224
+00:16:08,620 --> 00:16:12,000
+بتعطيني الشغل الناتج عن ال non-conservative
+
+225
+00:16:12,000 --> 00:16:17,260
+والتغير في طاقة الوضع إضافة إلى التغير في طاقة
+
+226
+00:16:17,260 --> 00:16:21,110
+الحركة، تغير اللي هو the situation says that the
+
+227
+00:16:21,110 --> 00:16:24,450
+work done by the non-conservative force اللي هو W
+
+228
+00:16:24,450 --> 00:16:28,430
+and C is equal to the change in the kinetic energy
+
+229
+00:16:28,430 --> 00:16:30,490
+plus the change in the gravitational potential
+
+230
+00:16:30,490 --> 00:16:36,770
+energy. ننتقل إلى section خمسة، تلاتة، اتنين، بنيجي ل
+
+231
+00:16:36,770 --> 00:16:39,110
+reference levels for gravitational potential
+
+232
+00:16:39,110 --> 00:16:42,590
+energy، اللي هو مستوى المرجعية أو المستوى اللي
+
+233
+00:16:42,590 --> 00:16:48,130
+حكينا عليه سابقًا. يعني عشان أحدد طبعًا طاقة الوضع
+
+234
+00:16:48,130 --> 00:16:52,530
+موجبة أو سالبة أو zero in solving problems
+
+235
+00:16:53,920 --> 00:16:57,380
+involving gravitational potential energy, it's
+
+236
+00:16:57,380 --> 00:17:00,920
+important to choose a location at which to see
+
+237
+00:17:00,920 --> 00:17:05,260
+that energy equal to zero. عشان أحدد اللي هي
+
+238
+00:17:05,260 --> 00:17:08,600
+potential energy موجبة ولا سالبة ولا zero، لازم نحدد
+
+239
+00:17:08,880 --> 00:17:14,680
+location، مكانها، وكمان بنحدد الـ level إذا كانت هي
+
+240
+00:17:14,680 --> 00:17:20,700
+الجسم على الـ level مباشرة، فالـ energy بتساوي zero.
+
+241
+00:17:20,700 --> 00:17:26,400
+نيجي لـ given the form of equation خمسة أحداشر، this
+
+242
+00:17:26,400 --> 00:17:30,760
+is the same as choosing the place لما يكون عندي الـ
+
+243
+00:17:30,760 --> 00:17:34,040
+Y اللي هي الـ vertical location أو الـ vertical
+
+244
+00:17:34,040 --> 00:17:39,010
+displacement بيساوي الـ Y بيساوي zero. بيطلع أن the
+
+245
+00:17:39,010 --> 00:17:41,950
+choice is completely arbitrary because the
+
+246
+00:17:41,950 --> 00:17:43,970
+important quantity is the difference in the
+
+247
+00:17:43,970 --> 00:17:46,850
+potential energy، and this difference will be the
+
+248
+00:17:46,850 --> 00:17:50,350
+same regardless of the choice of this zero level.
+
+249
+00:17:50,350 --> 00:17:55,250
+لما يكون عندي أنا جسم انتقل من مكان أو رجع لنفس
+
+250
+00:17:55,250 --> 00:17:58,070
+المكان، فالـ displacement ساوي zero، أو ممكن احنا
+
+251
+00:17:58,070 --> 00:18:02,030
+نعتبر أنه اللي هو الفرق في طاقة الوضع بيساوي zero.
+
+252
+00:18:02,030 --> 00:18:05,270
+على أساس أن الـ potential energy بيساوي 0. ممكن الـ
+
+253
+00:18:05,270 --> 00:18:09,530
+Y بدها تساوي 0، أو التغير في Delta potential energy
+
+254
+00:18:09,530 --> 00:18:14,650
+بيساوي 0. ممكن يعني نعتبر أنه الـ level هي على level
+
+255
+00:18:14,650 --> 00:18:17,690
+potential energy 0، أو التغير في Delta PE بيساوي 0.
+
+256
+00:18:17,690 --> 00:18:20,790
+أنه الـ Y initial بيساوي الـ Y final، معناته Delta Y
+
+257
+00:18:20,790 --> 00:18:26,850
+بيساوي 0. Example خمسة أربعة بيوضح اللي هو الـ level
+
+258
+00:18:26,850 --> 00:18:32,590
+zero level. بيوضح أيضًا نقاط معينة. على أي حال، once
+
+259
+00:18:32,590 --> 00:18:35,830
+this position is chosen, it must remain fixed for a
+
+260
+00:18:35,830 --> 00:18:39,970
+given problem. نيجي لـ example خمسة أربعة، عشان
+
+261
+00:18:39,970 --> 00:18:44,760
+نحدد نقاط معينة و نوجد عندها طاقة الـ ... الوضع. عندي
+
+262
+00:18:44,760 --> 00:18:49,360
+أنا جسم أو skyer is at the top of the slope as
+
+263
+00:18:49,360 --> 00:18:55,920
+shown. متزلج، وزن .. وزنها أو وزنها طبعًا، هي ستين
+
+264
+00:18:55,920 --> 00:18:58,980
+kilogram. هذا عبارة عن كتلة اللي هي ستين
+
+265
+00:18:58,980 --> 00:19:06,160
+kilogram، موجود على أعلى مكان ميل، اللي الميل طبعًا
+
+266
+00:19:06,160 --> 00:19:10,410
+بـ slope معين، at the initial point N.A. بعدين هذه
+
+267
+00:19:10,410 --> 00:19:15,890
+المتزلجة أو طبعًا البنت، she is عشرة متر vertically
+
+268
+00:19:15,890 --> 00:19:19,630
+above the point B. setting the zero level of the
+
+269
+00:19:19,630 --> 00:19:21,370
+gravitational potential energy at B, find the
+
+270
+00:19:21,370 --> 00:19:23,750
+gravitational potential energy of this system. طبعًا
+
+271
+00:19:23,750 --> 00:19:29,650
+في السؤال بدنا نحدد، هي المتزلجة كانت عند نقطة A،
+
+272
+00:19:29,650 --> 00:19:35,830
+النقطة A هذه على مستوى ميل طبعًا، هذه المتزلجة كانت
+
+273
+00:19:35,830 --> 00:19:40,830
+على بعد عشرة متر رأسيًا بعيدًا عن النقطة B. حكى، عرفني
+
+274
+00:19:40,830 --> 00:19:44,530
+أيه، setting the zero level، بدي أعتبر أن الـ level
+
+275
+00:19:44,530 --> 00:19:48,260
+يعني zero level عند النقطة B. بدنا نوجد، find the
+
+276
+00:19:48,260 --> 00:19:52,200
+gravitational potential energy of this system in
+
+277
+00:19:52,200 --> 00:19:56,940
+this system when the skier is at A and in B. بدنا
+
+278
+00:19:56,940 --> 00:20:00,700
+أوجد طاقة الـ ... الوضع اللي هي الخاصة بالجاذبية
+
+279
+00:20:00,700 --> 00:20:05,560
+عندما كانت البنت انتقلت من نقطة A لنقطة B. نيجي
+
+280
+00:20:05,560 --> 00:20:10,280
+للسؤال، مرسوم، طبعًا، في عندي متزلجة هيها كانت عند
+
+281
+00:20:10,280 --> 00:20:14,730
+النقطة A، بدأت توصل عند النقطة B. كانت عند A، بدأت توصل
+
+282
+00:20:14,730 --> 00:20:18,350
+عند النقطة B. هذا المتزلج عند A، يعني بتسير على
+
+283
+00:20:18,350 --> 00:20:23,470
+مستوى ميل، ارتفاعها الرأسي كان عشرة متر، وطبعًا عند
+
+284
+00:20:23,470 --> 00:20:26,430
+نقطة A و B، واعتبرنا أن الـ B هو الـ level، بدنا
+
+285
+00:20:26,430 --> 00:20:30,010
+نعتبر أن الـ B هو الـ level. في معنى الكلام، هو الـ
+
+286
+00:20:30,010 --> 00:20:35,380
+level، يعني هو المرجعية. بدأنا نقارن عند نقطة A، وأوصل
+
+287
+00:20:35,380 --> 00:20:38,900
+للنقطة B. يعني A initial و B هي الـ final. الحل
+
+288
+00:20:38,900 --> 00:20:44,080
+بنعتبر أن الـ Y0، طبعًا الـ Y0 at the level اللي هو B
+
+289
+00:20:44,080 --> 00:20:48,280
+لأنه حدد، لإنه B بدنا نعتبره هو level. Calculate the
+
+290
+00:20:48,280 --> 00:20:51,860
+potential energy at A and B. بدي أوجد طاقة الوضع عند
+
+291
+00:20:51,860 --> 00:20:56,110
+النقطة A وعند النقطة B. and calculate the change in
+
+292
+00:20:56,110 --> 00:20:58,450
+the potential energy. يعني بتبقى وش طاقة الوضع، and
+
+293
+00:20:58,450 --> 00:21:01,730
+A، طاقة الوضع، and B، بيبقى بين التغير في طاقة الوضع.
+
+294
+00:21:01,730 --> 00:21:05,010
+طاقة الوضع عند النقطة A اللي هي الـ potential
+
+295
+00:21:05,010 --> 00:21:08,690
+energy initial بتساوي الـ M في G في Y. الـ M كانت
+
+296
+00:21:08,690 --> 00:21:12,350
+ستين، و الـ G تسعة وثمانية من عشرة، و الـ Y كانت عشرة.
+
+297
+00:21:12,350 --> 00:21:16,870
+إذن الـ potential energy عند النقطة A بتساوي خمسة
+
+298
+00:21:16,870 --> 00:21:20,300
+point ثمانية ثمانية في عشر أس تلاتة جول. الـ
+
+299
+00:21:20,300 --> 00:21:23,880
+potential energy اللي هي الـ final عند النقطة B
+
+300
+00:21:23,880 --> 00:21:27,900
+زيرو، لإنه الـ Y بيساوي زيرو، أو لإنه احنا وصلنا لـ الـ
+
+301
+00:21:27,900 --> 00:21:31,680
+level. إذن التغير، the difference، the difference
+
+302
+00:21:31,680 --> 00:21:36,100
+in energy between A and B، the difference in potential
+
+303
+00:21:36,100 --> 00:21:40,180
+energy، اللي هو دلتا P، الفرق في طاقة الوضع، بين الـ
+
+304
+00:21:40,180 --> 00:21:44,760
+initial و الـ final. Delta P final ناقص P initial
+
+305
+00:21:44,760 --> 00:21:48,580
+بيساوي، الـ final كانت zero ناقص خمسة point ثمانية
+
+306
+00:21:48,580 --> 00:21:52,400
+ثمانية في عشر أس تلاتة جول، تطلع عندي سالب خمسة
+
+307
+00:21:52,400 --> 00:21:54,380
+point ثمانية ثمانية في عشر أس تلاتة جول. هذه
+
+308
+00:21:54,380 --> 00:21:58,020
+عبارة عن التغير في طاقة الوضع، نتيجة الجاذبية
+
+309
+00:21:58,020 --> 00:22:03,090
+عندما انتقلت البنت من نقطة A لنقطة B. الآن السؤال في
+
+310
+00:22:03,090 --> 00:22:07,370
+B بيحكي لنا repeat، عيد هذا problem لنا، عيد السؤال.
+
+311
+00:22:07,370 --> 00:22:10,090
+إذا كانت الـ Y بيساوي zero at A، يعني أنا بدي أعتبر
+
+312
+00:22:10,090 --> 00:22:15,210
+الـ A هو الـ level. إذا اعتبرت الـ A هو الـ level اللي
+
+313
+00:22:15,210 --> 00:22:18,230
+على الـ A، اللي على الـ A، الـ Y بيساوي zero، اللي تحت
+
+314
+00:22:18,230 --> 00:22:23,250
+الـ level، بعتبر الـ Y سالبة، وبالتالي طاقة الوضع تحت
+
+315
+00:22:23,250 --> 00:22:26,250
+الـ level سالبة. طاقة الوضع فوق الـ level موجبة. طاقة
+
+316
+00:22:26,250 --> 00:22:29,540
+الوضع على الـ level zero. the new reference point so
+
+317
+00:22:29,540 --> 00:22:32,540
+that potential energy. الآن، potential energy عند
+
+318
+00:22:32,540 --> 00:22:36,600
+النقطة A بتساوي zero. الـ potential energy الـ final
+
+319
+00:22:36,600 --> 00:22:39,980
+عند النقطة B، طبعًا الـ Y عند النقطة B بتساوي ناقص
+
+320
+00:22:39,980 --> 00:22:44,760
+عشرة، لأن الـ B أسفل الـ A، وبالتالي الـ potential
+
+321
+00:22:44,760 --> 00:22:48,300
+energy الـ final بتساوي الـ m في g في y final. الـ m
+
+322
+00:22:48,300 --> 00:22:51,900
+كانت ستين kilogram، و الـ g تسعة وثمانية من عشرة،
+
+323
+00:22:51,900 --> 00:22:55,840
+و الـ y ناقص عشرة. تطلع برضه ناقص خمسة point ثمانية
+
+324
+00:22:55,840 --> 00:23:00,140
+ثمانية في عشر أس تلاتة. إذن Delta P بتساوي Delta
+
+325
+00:23:00,140 --> 00:23:04,080
+P final ناقص P initial، وهي بتطلع ناقص خمسة point
+
+326
+00:23:04,080 --> 00:23:07,960
+ثمانية ثمانية في عشر أس تلاتة. usual، في C، حكينا
+
+327
+00:23:07,960 --> 00:23:12,740
+repeat، أي قاعدة هذا problem، أنا قاعدة الـ problem. if Y
+
+328
+00:23:12,740 --> 00:23:16,900
+is zero two meters above B. إذا كانت الـ level عندما
+
+329
+00:23:16,900 --> 00:23:25,340
+تصل النقطة، هذه اللي متزلجة على بعد ضعف... نقطة B،
+
+330
+00:23:25,340 --> 00:23:32,440
+على بعد مترين من النقطة B.
+
+331
+00:23:32,720 --> 00:23:40,300
+B initial، يعني هطرح من اللي هو العشرة، طبعًا،
+
+332
+00:23:40,300 --> 00:23:43,960
+هي كانت هنا، هطرح هنا، وسط المنطقة هذه، وسط المنطقة
+
+333
+00:23:43,960 --> 00:23:47,300
+هذه. إذا هذا هو الـ level، بضبط عندي هنا اتنين، هطرح
+
+334
+00:23:47,300 --> 00:23:50,100
+عشرة ناقص اتنين، بيصير عندي الـ level هنا ثمانية. فالـ
+
+335
+00:23:50,100 --> 00:23:54,000
+initial، من النقطة A لنقطة I، بيكون عندي اللي هي M
+
+336
+00:23:54,000 --> 00:24:00,440
+في G في Y، اللي هي ثمانية، زي ما احنا حاطين هنا. إذن
+
+337
+00:24:02,040 --> 00:24:05,960
+الـ PE initial بيساوي M في G في Y initial. الـ M
+
+338
+00:24:05,960 --> 00:24:08,800
+ستين كيلو في تسعة وثمانية من عشرة في ثمانية.
+
+339
+00:24:08,800 --> 00:24:11,060
+الثمانية اجت من عشرة ناقص اتنين، اللي حكالي هنا two
+
+340
+00:24:11,060 --> 00:24:15,180
+meters above. إذن الـ final potential energy final
+
+341
+00:24:15,180 --> 00:24:19,920
+عند النقطة B، هيكون عندي، عند النقطة B، الـ B تحت، تحت
+
+342
+00:24:19,920 --> 00:24:23,280
+الـ اتنين اللي أنا فرضتها، فبتكون الاتنين سالب. إذن الـ
+
+343
+00:24:23,280 --> 00:24:27,790
+PE final بيساوي M في G في Y final. الآن برضه الـ 2
+
+344
+00:24:27,790 --> 00:24:30,270
+ما تغيرتش، و الـ G تسعة وثمانية من عشرة، الـ Y final
+
+345
+00:24:30,270 --> 00:24:33,890
+كانت ناقص اتنين. ليش ناقص اتنين؟ لإنه ... لإنه حكالي
+
+346
+00:24:33,890 --> 00:24:37,770
+عند نقطة اتنين أعلى من الـ B، اعتبر الـ level. إذن الـ
+
+347
+00:24:37,770 --> 00:24:42,230
+B هتكون أسفل الـ ... النقطة اللي هو الـ level، و
+
+348
+00:24:42,230 --> 00:24:46,400
+بالتالي ناقص اتنين. فبيطلع أن PE final ناقص واحد
+
+349
+00:24:46,400 --> 00:24:51,340
+point واحد ثمانية في عشر أس تلاتة. usual، بدي أحسب
+
+350
+00:24:51,340 --> 00:24:56,240
+the change in potential energy. فطبعًا delta
+
+351
+00:24:56,240 --> 00:25:00,820
+P final ناقص P initial، بيطلع نفس الجواب. مع أن
+
+352
+00:25:00,820 --> 00:25:03,560
+الكلام، لو اخترت الـ level عند النقطة A، أو اخترت الـ
+
+353
+00:25:03,560 --> 00:25:08,300
+level عند النقطة B، أو اخترنا level في أي مكان على
+
+354
+00:25:08,300 --> 00:25:15,510
+الرأسي، بيطلع تقريبًا نفس الـ... بيطلع تقريبًا نفس الحل، نفس
+
+355
+00:25:15,510 --> 00:25:22,050
+الحل. نشرح الـ gravity and the conservation of
+
+356
+00:25:22,050 --> 00:25:26,370
+mechanical energy. section خمسة تلاتة. the kinetic
+
+357
+00:25:26,370 --> 00:25:30,710
+energy، اللي هي رمزها KE، of an object falling only
+
+358
+00:25:30,710 --> 00:25:33,290
+under the influence of gravity is constantly
+
+359
+00:25:33,290 --> 00:25:36,920
+changing، as it's gravitational potential energy PE
+
+360
+00:25:36,920 --> 00:25:40,160
+الآن بالنسبة لـ gravity و الـ conservation of
+
+361
+00:25:40,160 --> 00:25:43,400
+mechanical energy، في عندي حاجة اسمها اللي هي
+
+362
+00:25:43,400 --> 00:25:46,960
+mechanical energy، هي عبارة عن مجموع اللي هي طاقة
+
+363
+00:25:46,960 --> 00:25:49,680
+الحركة وطاقة الوضع. نسموها mechanical energy.
+
+364
+00:25:49,680 --> 00:25:54,900
+المقصود بهذا الكلام أن طاقة الحركة وطاقة الوضع
+
+365
+00:25:54,900 --> 00:25:59,440
+خلال اللي هي gravitational، الـ gravity أو
+
+366
+00:25:59,440 --> 00:26:02,870
+gravitational motion بتكون عندها مقدار ثابت.
+
+367
+00:26:02,870 --> 00:26:05,890
+Constantly it's changing، أو بتتغير تغير ثابت، يعني
+
+368
+00:26:05,890 --> 00:26:09,490
+إذا طاقة الحركة زادت، طاقة الوضع بتقل، لأنه
+
+369
+00:26:09,490 --> 00:26:14,750
+مجموعهم مقدار ثابت. واضح. this quantity aren't
+
+370
+00:26:14,750 --> 00:26:19,190
+conserved because all non-conservative forces are
+
+371
+00:26:19,190 --> 00:26:25,110
+absent. في هذه الحالة، بالنسبة لي الـ gravity هو غير
+
+372
+00:26:25,110 --> 00:26:29,010
+محفوظة، طبعًا مش موجودة، وبالتالي W and C بيساوي zero.
+
+373
+00:26:29,420 --> 00:26:32,420
+لأن اتفقنا أن الـ gravity أو الـ potential energy أو
+
+374
+00:26:32,420 --> 00:26:34,180
+الـ gravitational، الـ potential energy يبقى عن
+
+375
+00:26:34,180 --> 00:26:38,980
+conservative force. معنى الكلام أنه في حالة الـ
+
+376
+00:26:38,980 --> 00:26:42,300
+gravity، أو في حالة حركة الجسم من أعلى إلى أسفل،
+
+377
+00:26:42,300 --> 00:26:46,140
+من أسفل إلى أعلى، لما أستخدم طاقة ... طاقات، بيكون عندي
+
+378
+00:26:46,140 --> 00:26:49,440
+طاقة، في حاجة اسمها طاقة الوضع والحركة initial بيساوي
+
+379
+00:26:49,440 --> 00:26:52,680
+طاقة الحركة + طاقة الوضع final. الآن، according to
+
+380
+00:26:52,680 --> 00:26:56,060
+this equation، بناء على هذه المعادلة، مجموع الـ
+
+381
+00:26:56,060 --> 00:27:00,580
+kinetic energy and الـ potential energy مقدار ثابت
+
+382
+00:27:00,580 --> 00:27:06,360
+أهو في كل اللحظات، وبالتالي هي تعتبر conserved
+
+383
+00:27:06,360 --> 00:27:09,520
+quantity. we denote the total mechanical energy
+
+384
+00:27:09,520 --> 00:27:15,360
+بقى ممكن أنا طبعًا أرمز لها بالرمز اللي هي E، بيسموها
+
+385
+00:27:15,360 --> 00:27:18,600
+الـ mechanical energy أو mechanical ... هذا الـ
+
+386
+00:27:18,600 --> 00:27:21,160
+mechanical ... mechanical energy عبارة عن مجموع
+
+387
+00:27:21,160 --> 00:27:24,420
+طاقة الحركة وطاقة الوضع، وهي مقدار محفوظ أو
+
+388
+00:27:24,420 --> 00:27:27,440
+conserved. طاقة الوضع وطاقة الحركة هي عبارة عن
+
+389
+00:27:27,440 --> 00:27:32,170
+conserved. to show how this concept work, think of
+
+390
+00:27:32,170 --> 00:27:36,310
+tossing a rock off a cliff, ignore the drag force.
+
+391
+00:27:36,310 --> 00:27:40,450
+as the rock falls. لو كان عندي أنا صخرة سقطت من
+
+392
+00:27:40,450 --> 00:27:47,550
+مكان مرتفع، طبعًا هي صخرة موجودة، وفي عندي الصخرة دي
+
+393
+00:27:47,550 --> 00:27:51,150
+وقعت من مكان مرتفع، سرعتها طبعًا هي تبدأ من الـ zero.
+
+394
+00:27:51,740 --> 00:27:56,340
+سرعتها بتزيد، طالما أن سرعتها بتزيد، فطاقة الحركة
+
+395
+00:27:56,340
+
+445
+00:31:14,830 --> 00:31:19,510
+الحل اللي هو الـ answer زي ما هو موضح اللي هو ده
+
+446
+00:31:19,510 --> 00:31:23,970
+اللي التلاتة هيخبطوا الأرض بنفس السرعة بنفس السرعة
+
+447
+00:31:23,970 --> 00:31:29,790
+لأنه هي التلاتة موجودين على ارتفاع معين، والارتفاع هو
+
+448
+00:31:29,790 --> 00:31:34,450
+اللي بيحدد بتكون اللي هم طاقة وضع محددة لما نرميها
+
+449
+00:31:34,450 --> 00:31:38,750
+بتتحول طاقة الوضع لطاقة الحركة، والـ M ليس لها علاقة
+
+450
+00:31:38,750 --> 00:31:44,930
+وبالتالي التلاتة إذا ارتموا أي جسمين بغض النظر عن
+
+451
+00:31:44,930 --> 00:31:48,710
+الكتلة ليس لها أي علاقة، الكتلة لأنه هنا بنكون
+
+452
+00:31:48,710 --> 00:31:52,550
+بنحكي MGH  و نص Mv تربيع، وبالتالي السرعة
+
+453
+00:31:52,550 --> 00:31:56,600
+النهائية = V = جذر 2GH، فالـ G ثابتة، والـ
+
+454
+00:31:56,600 --> 00:32:00,820
+H هو أو الارتفاع هو أو الـ Y هو، طبعاً نرمي من نفس
+
+455
+00:32:00,820 --> 00:32:03,120
+الارتفاع وبالتالي هينزلوا بنفس السرعة
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..dceb76a9503dc04c2a65ae08feb74d343893878b
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ_postprocess.srt
@@ -0,0 +1,1820 @@
+1
+00:00:00,000 --> 00:00:03,780
+بسم الله الرحمن الرحيم بنستكمل chapter خمسة و
+
+2
+00:00:03,780 --> 00:00:06,780
+بنبدأ ب section خمسة تلاتة بانوان gravitational
+
+3
+00:00:06,780 --> 00:00:11,960
+potential energy اللي هي طاقة وضع الخاصة بيه
+
+4
+00:00:11,960 --> 00:00:16,020
+الجاذبية an object with kinetic energy, energy of
+
+5
+00:00:16,020 --> 00:00:21,240
+motion can do work on another object ممكن يعني أي
+
+6
+00:00:21,240 --> 00:00:29,430
+جسم بطاقة حركة معينة يعمل شغل على جسم تانيطبعا هذا
+
+7
+00:00:29,430 --> 00:00:34,390
+الكلام مثال عليه ممكن يتحرك just طبعا hammer can
+
+8
+00:00:34,390 --> 00:00:38,610
+drive a nail into a wall يعني مطرقة ممكن تطرق مصمر
+
+9
+00:00:38,610 --> 00:00:42,870
+داخل الحائط crack on a high shelf can also do work
+
+10
+00:00:42,870 --> 00:00:49,420
+برضه أيضا ممكن طوب في الحائط تسقط علىمن أعلى الرف
+
+11
+00:00:49,420 --> 00:00:54,620
+من أعلى و تسقط و تعمل أيضا شغل ممكن طبعا تسقط من
+
+12
+00:00:54,620 --> 00:00:59,360
+أعلى الرف إذا سقطت من أعلى إلى أسفل بتعمل بتسارعة
+
+13
+00:00:59,360 --> 00:01:03,820
+معينة طبعا هذه هتسقط تلقاء بتسارعة جاذبية إلى أسفل
+
+14
+00:01:03,820 --> 00:01:07,420
+downward it's hit a nail squarely driving in into
+
+15
+00:01:07,420 --> 00:01:11,400
+a floor ممكن الطوب يقع على المصمار و بقى و بالتالي
+
+16
+00:01:11,400 --> 00:01:14,560
+يقع على الأرض معناه الكلام في عندي أنا أكتر من نوع
+
+17
+00:01:14,560 --> 00:01:18,330
+من الطاقة في عندي طاقة حركة في عندي طاقة وضعاللي
+
+18
+00:01:18,330 --> 00:01:20,470
+هي ال kinetic energy و في عنده potential energy
+
+19
+00:01:20,470 --> 00:01:23,990
+ممكن يعني يكون عندي انا مثال المطرق أو المصمر
+
+20
+00:01:23,990 --> 00:01:27,790
+يعمللي طاقة حركة ممكن الطوب اذا وقعت على المصمر
+
+21
+00:01:27,790 --> 00:01:31,370
+يعني هو انتقال من مكان لمكان هو يعني تغير في طاقة
+
+22
+00:01:31,370 --> 00:01:35,590
+الوضع و بالتالي لو انا الطوب انتقلت او وقعت من
+
+23
+00:01:35,590 --> 00:01:39,190
+أعلى الى أسفل بنحكي انه the brake is set to be
+
+24
+00:01:39,190 --> 00:01:44,450
+potential energy انه عملت طاقة وضع مرتبطة فيهاهي
+
+25
+00:01:44,450 --> 00:01:50,270
+طاقة الوضع تحدث بسبب التغير في المكان طبعا مكانها
+
+26
+00:01:50,270 --> 00:01:54,730
+بالنسبالها اللي هي ال .. اللي هي الموضوع الرأسي أو
+
+27
+00:01:54,730 --> 00:01:58,630
+اللي هي ال vertical location ال potential energy
+
+28
+00:01:58,630 --> 00:02:01,630
+is property of the citizen برضه طاقة الوضع هي
+
+29
+00:02:01,630 --> 00:02:07,860
+خاصية لأي نظام ممكن يكون لحالهممكن ان هذا الجسم
+
+30
+00:02:07,860 --> 00:02:10,780
+يكون على ارتفاع معين و ينزل لارتفاع تاني او يكون
+
+31
+00:02:10,780 --> 00:02:14,600
+على الأرض و يصعد الى أعلى و بالتالي طبعا بتغير
+
+32
+00:02:14,600 --> 00:02:17,380
+relative بالنسبة ل position لما كان of interacting
+
+33
+00:02:17,380 --> 00:02:22,380
+object in the systemsuch as زي المثال خمسة واحد
+
+34
+00:02:22,380 --> 00:02:26,920
+لما كان اللي هو اللي اللي اللي طبعا ال .. ال .. ال
+
+35
+00:02:26,920 --> 00:02:30,040
+.. البنت أو الصابية كانت على ارتفاع معين و سقطت
+
+36
+00:02:30,040 --> 00:02:33,460
+إلى البحر يعني هذا فيه تغير في طاقة اللي هي الوضع
+
+37
+00:02:33,460 --> 00:02:37,440
+it turns on other it turns out that potential
+
+38
+00:02:37,440 --> 00:02:43,970
+energy is another wayfor another way of .. for
+
+39
+00:02:43,970 --> 00:02:46,750
+طبعا looking at the work done by the conservative
+
+40
+00:02:46,750 --> 00:02:50,810
+force برضه مثال على ال conservative force اللي هي
+
+41
+00:02:50,810 --> 00:02:53,910
+طاقة الوضع، إذا كان في عندي نوعيا لل conservative
+
+42
+00:02:53,910 --> 00:02:58,310
+force إذا كان في عندي أنا ال gravitational طبعا
+
+43
+00:02:58,310 --> 00:03:03,320
+potential energy أو اللي هي potential energyهذه هي
+
+44
+00:03:03,320 --> 00:03:06,300
+أولى gravity برضه هذه أمثلة على اللى هى ال
+
+45
+00:03:06,300 --> 00:03:11,280
+conservative force لإنها طاقة كقوة محفوظة في
+
+46
+00:03:11,280 --> 00:03:15,880
+section خمسة تلاتة واحد بنتحدث عن الشغل الناتج عن
+
+47
+00:03:15,880 --> 00:03:20,360
+الجاذبية وطاقة الوضع gravitational work and
+
+48
+00:03:20,360 --> 00:03:24,480
+potential energy اللى هو طاقة الشغل الناتج عن
+
+49
+00:03:24,480 --> 00:03:29,200
+الجاذبية وطاقة الوضع using the work energy theorem
+
+50
+00:03:29,200 --> 00:03:34,170
+ده استخدم نظريةالطاقة و الشغل في هذه .. في بعض ال
+
+51
+00:03:34,170 --> 00:03:38,750
+.. طبعا المسائل و بعض الأمثلة تتضمن gravitation
+
+52
+00:03:38,750 --> 00:03:41,450
+requires computing the work done by the gravity
+
+53
+00:03:41,450 --> 00:03:44,350
+ممكن أنه يحسب أنا الشغل الناتج عن الجاذبية في بعض
+
+54
+00:03:44,350 --> 00:03:48,750
+المسائل زي ما اتفقنا او ما تكلمنا سابقا ان ال
+
+55
+00:03:48,750 --> 00:03:52,470
+gravity الجاذبية هي نوعا من ال conservative force
+
+56
+00:03:52,470 --> 00:03:56,010
+اللي هي القوة المحفوظة و for every conservative
+
+57
+00:03:56,010 --> 00:04:00,900
+force a special expression calledلكل طبعا قوة ..
+
+58
+00:04:00,900 --> 00:04:05,440
+قوة محفوظة في عندى انا تعريف معين بيسموه potential
+
+59
+00:04:05,440 --> 00:04:10,180
+energy function دالة طاقة الوضع هذه هي مقياس او
+
+60
+00:04:10,180 --> 00:04:15,400
+يعني إشارة إلى أنها conservative force إيجاد أو
+
+61
+00:04:15,400 --> 00:04:18,760
+حساب هذه الدالة at any two points in an object
+
+62
+00:04:18,760 --> 00:04:21,840
+part of the motion and finding the difference will
+
+63
+00:04:21,840 --> 00:04:24,700
+give the negative of the work done by the force
+
+64
+00:04:24,700 --> 00:04:30,790
+between those two pointsلحساب هذه الدالة بين
+
+65
+00:04:30,790 --> 00:04:36,670
+نقطتين لمسار جسم خلال نقطتين خلال حركته طبعا
+
+66
+00:04:36,670 --> 00:04:42,150
+بيدأوجد الفرق بين هيدول النقطتين بيعطيني سالب
+
+67
+00:04:42,150 --> 00:04:47,850
+الشغل المبذول بواسطة هذه القوة بين النقطتين طاقة
+
+68
+00:04:47,850 --> 00:04:52,070
+الوضع بتشبه الشغل و بتشبه أيضا طاقة الحركة بإنه
+
+69
+00:04:52,070 --> 00:04:55,990
+طاقة الهوضة و طاقة الحركة و الشغل هي عبارة عن كمية
+
+70
+00:04:56,290 --> 00:05:00,130
+scalar quantity أي كمية قياسية اذا الشغل كمية
+
+71
+00:05:00,130 --> 00:05:04,230
+قياسية طاقة الحركة كمية قياسية وطاقة الوضع كمية
+
+72
+00:05:04,230 --> 00:05:09,230
+قياسية بدأ افرض في عندي كتاب يسقط من ارتفاع معين
+
+73
+00:05:09,230 --> 00:05:14,570
+اسمه y initial طبعا عندي انا الكتاب هان و هنا في
+
+74
+00:05:14,570 --> 00:05:18,470
+عندي level معين اللي هو الأرض هيهافي الارتفاع كان
+
+75
+00:05:18,470 --> 00:05:21,890
+initial يعني في البداية كان على ارتفاع Y initial
+
+76
+00:05:21,890 --> 00:05:27,530
+نزل سقط صار في المنطقة هذه على ارتفاع Y final اذا
+
+77
+00:05:27,530 --> 00:05:31,810
+في تغير في اللي هي النقاط او الرأسية او مكان
+
+78
+00:05:31,810 --> 00:05:36,150
+الكتاب كان في initial و راح ل final في هذا الشكل
+
+79
+00:05:36,150 --> 00:05:42,650
+بيحكيلي هنا ال .. ال .. مثلا a book of mass M كتاب
+
+80
+00:05:42,650 --> 00:05:48,520
+كتلة M سقط from height Hyسقط من ارتفاع y initial
+
+81
+00:05:48,520 --> 00:05:52,140
+to height y final سقط من ارتفاع y initial ال y
+
+82
+00:05:52,140 --> 00:05:56,540
+final حيث ان ال positive y coordinate represent a
+
+83
+00:05:56,540 --> 00:06:00,780
+position above the ground طبعا عندما اتحدث عن تغير
+
+84
+00:06:00,780 --> 00:06:05,580
+في طاقة الوضع بنختار مستوى معين او level معين اذا
+
+85
+00:06:05,580 --> 00:06:09,400
+انا اخترت ال level مثلا للأرض بهذا ك level كمستوى
+
+86
+00:06:09,400 --> 00:06:12,860
+عساس يكون مرجعية reference frame مرجعية لي عشان
+
+87
+00:06:12,860 --> 00:06:17,120
+احددهل طاقة الوضع موجبة أو سالبة أو zero إذا كان
+
+88
+00:06:17,120 --> 00:06:21,060
+الجسم على ال level أو على الأرض مباشرة فبيكون ..
+
+89
+00:06:21,060 --> 00:06:24,960
+تكون طاقة الوضع zero لإن ال level .. الجسم على ال
+
+90
+00:06:24,960 --> 00:06:29,180
+level مباشرة إذا كان الجسم أعلى من ال level فطاقة
+
+91
+00:06:29,180 --> 00:06:32,200
+الوضع موجبة وإذا كان أسفل من ال level فطاقة الوضع
+
+92
+00:06:32,200 --> 00:06:35,600
+سالبة هاي معنى هذا الكلام إن ال positive y
+
+93
+00:06:35,600 --> 00:06:39,080
+coordinate represent position above the groundيعني
+
+94
+00:06:39,080 --> 00:06:42,820
+محور Y الموجة بأعلى اللي هو إذا كان فريقة أنا
+
+95
+00:06:42,820 --> 00:06:47,110
+الأرض هي ال level بيكون اللي بيكون هوطاقة الوضع
+
+96
+00:06:47,110 --> 00:06:52,610
+موجبة لإنه .. لإن الجسم أعلى من ال level وبيمثل
+
+97
+00:06:52,610 --> 00:06:57,430
+اللي هي المحور Y الموجب We neglect the force of
+
+98
+00:06:57,430 --> 00:07:01,410
+air friction طبعا نهمل القوة الناتجة عن احتكاك
+
+99
+00:07:01,410 --> 00:07:06,270
+الهواء So the only force acting on the puck is
+
+100
+00:07:06,270 --> 00:07:09,870
+gravitation معنا الكلام مع اهمال القوة الناتجة عن
+
+101
+00:07:09,870 --> 00:07:14,730
+طبعا احتكاك الهواء أو مقاومة الهواء بيكون عندى ..
+
+102
+00:07:14,730 --> 00:07:18,860
+بيكون عندناالقوة المؤثرة على الكتاب هي قوة
+
+103
+00:07:18,860 --> 00:07:23,120
+الجاذبية بدنا نسأل يعني how much work is done طبعا
+
+104
+00:07:23,120 --> 00:07:26,660
+ماهو الشغل المفضول عندما سقط الجسم من ارتفاع why
+
+105
+00:07:26,660 --> 00:07:30,320
+initial و why final the magnitude of the force
+
+106
+00:07:30,320 --> 00:07:32,740
+طبعا القوة المؤثرة عندي في هذه الحالة اللي هي ال
+
+107
+00:07:32,740 --> 00:07:37,660
+MG قوة الجاذبية و هي مشت مسافة من ال initial ل ال
+
+108
+00:07:37,660 --> 00:07:42,000
+final الكتاب ماشي مسافة رأسيةاسمها delta Y وهي
+
+109
+00:07:42,000 --> 00:07:46,460
+عبارة عن Y initial ناقص Y final اللي هي ال
+
+110
+00:07:46,460 --> 00:07:50,180
+positive number لإن ال Y initial أكبر من ال Y
+
+111
+00:07:50,180 --> 00:07:53,800
+final فبطلع عندي أنا موجب بينما ال F و ال و delta
+
+112
+00:07:53,800 --> 00:07:59,360
+Y اللي طبعا الزاوية بينهم zeroلأنه الأف اتجاه
+
+113
+00:07:59,360 --> 00:08:02,200
+الأسفل و دول طواية اتجاه الأسفل إذا الجسم سقط من
+
+114
+00:08:02,200 --> 00:08:05,480
+أعلى إلى أسفل وبالتالي الزاوية zero معناه الكلام
+
+115
+00:08:05,480 --> 00:08:11,140
+دي المسافة المشيتها ..مشيها الكتاب اللي هو عبارة
+
+116
+00:08:11,140 --> 00:08:14,920
+عن دي بساوي y initial ناقص y final we apply the
+
+117
+00:08:14,920 --> 00:08:18,740
+definition of the work questions بدي أنا اعو ..
+
+118
+00:08:18,740 --> 00:08:23,860
+اطبق قانون الشغل اللي هو عبارة عن WG اللي هو الشغل
+
+119
+00:08:23,860 --> 00:08:30,390
+الناتج عن الإجابيةبدي يساوي fd cos θ ال f كانت
+
+120
+00:08:30,390 --> 00:08:34,670
+اللي هي ال mg و دي المشيها y initial ناقص y final
+
+121
+00:08:34,670 --> 00:08:40,530
+cos θ اللي هي cos 0 طبعا هيتلا معايا ناقص mg y
+
+122
+00:08:40,530 --> 00:08:45,490
+final ناقص y initial ممكن اتدالها زي ما هي mg y
+
+123
+00:08:45,490 --> 00:08:49,750
+initial ناقص y final في cos 00 وcos 01فلمّا
+
+124
+00:08:49,750 --> 00:08:53,730
+ضربناها ب zero صارت ناقص mg y final ناقص y initial
+
+125
+00:08:53,730 --> 00:08:58,330
+ممكن أحط موجب mg y initial ناقص y final لكن معظم
+
+126
+00:08:58,330 --> 00:09:01,810
+الطلبة متعودين يحطوا اللي هي ال y final ناقص y
+
+127
+00:09:01,810 --> 00:09:06,430
+initial وبالتالي في هذه الحالة إذا سقط جسم من أعلى
+
+128
+00:09:06,430 --> 00:09:11,350
+إلى أسفل خلال مسافة رأسية فشغل نتج عن الجذبية
+
+129
+00:09:11,350 --> 00:09:15,950
+بيساوي ناقص mg y final ناقص y initial
+
+130
+00:09:18,980 --> 00:09:23,200
+المعادلة هذه معادلة خمس تسعة for gravitational
+
+131
+00:09:23,200 --> 00:09:27,880
+work للشغل الناتج عن الجاذبية ممكن أطبقها لأي جسم
+
+132
+00:09:27,880 --> 00:09:32,980
+regardless of its trajectory in space because the
+
+133
+00:09:32,980 --> 00:09:35,740
+gravitational force is conservative بغض النظر عن
+
+134
+00:09:35,740 --> 00:09:41,040
+مسار الجسم في الفضاء لإن الشغل الناتج عن الجاذبية
+
+135
+00:09:41,040 --> 00:09:45,120
+بسبب ال gravitational force وهي conservative force
+
+136
+00:09:45,610 --> 00:09:51,050
+الان ال WG هذا الشغل الناتج عن الجاذبية ممكن will
+
+137
+00:09:51,050 --> 00:09:54,530
+appear يظهر as the work done by gravity in the
+
+138
+00:09:54,530 --> 00:09:57,730
+work energy theory ممكن أسميه شغل ناتج عن الجاذبية
+
+139
+00:09:57,730 --> 00:10:02,460
+في نظرية الطاقة والشغلfor the rest of these
+
+140
+00:10:02,460 --> 00:10:06,020
+sections assume for simplicity that we are dealing
+
+141
+00:10:06,020 --> 00:10:08,620
+only with systems involving gravity and non
+
+142
+00:10:08,620 --> 00:10:14,020
+conservative force الآن بدأ أفرض أنه للسهولة طبعا
+
+143
+00:10:14,020 --> 00:10:19,720
+أنه نظام طبعا with systems involving gravity and
+
+144
+00:10:19,720 --> 00:10:23,880
+non conservative force the equation خمسة تمانية
+
+145
+00:10:23,880 --> 00:10:28,100
+can be written يعني لو كان عندي أنا اللي هو النظام
+
+146
+00:10:28,100 --> 00:10:31,970
+الجاذبية اللي هو ال conservativeزي إضافة إلى عندي
+
+147
+00:10:31,970 --> 00:10:35,570
+أنا non-conservative force فبصير عندي الشغل الكلي
+
+148
+00:10:35,570 --> 00:10:39,870
+اللي هو عبارة عن delta K طبعا عرفناها سابقا إذا
+
+149
+00:10:39,870 --> 00:10:43,830
+الشغل كله بساوي WNC يعني الشغل الناتج عن ال non
+
+150
+00:10:43,830 --> 00:10:47,580
+-conservative زائد WG الشغل الناتج عناللي هي ال
+
+151
+00:10:47,580 --> 00:10:51,120
+gravity او ال conservative بنفع بساوي Delta K، اذا
+
+152
+00:10:51,120 --> 00:10:56,220
+الشغل الكل ممكن نحكي انه الشغل الكل W net بساوي
+
+153
+00:10:56,220 --> 00:11:03,100
+WNC زاوية WC او WNC زاوية WG بساوي Delta KWNC هي
+
+154
+00:11:03,100 --> 00:11:06,060
+عبارة عن الشغل الناتج عن الـ non-conservative
+
+155
+00:11:06,060 --> 00:11:10,300
+force و الـ WG هو الشغل الناتج عن الـ conservative
+
+156
+00:11:10,300 --> 00:11:15,400
+force إذا لو أعود عن WG بالناقص MG و Y final ناقص
+
+157
+00:11:15,400 --> 00:11:21,580
+Y initial فبطلع عندنا WNC ناقص
+
+158
+00:11:21,580 --> 00:11:25,620
+MG و Y final ناقص Y initial بساوي Delta K تغير في
+
+159
+00:11:25,620 --> 00:11:30,680
+طاقة الحركةو بالتالي دل ال W اللي هو الشغل الناتج
+
+160
+00:11:30,680 --> 00:11:34,600
+عن ال conservative بساوي دلتا K زائد Mg Y final
+
+161
+00:11:34,600 --> 00:11:39,960
+ناقص Y initial Now هاي هدو قانون طبعا خمسة عشرة
+
+162
+00:11:39,960 --> 00:11:44,500
+Now by definition we make the connection between
+
+163
+00:11:44,500 --> 00:11:46,380
+gravitational work and gravitational potential
+
+164
+00:11:46,380 --> 00:11:50,280
+energy طبعا في علاقة بين الشغل الناتج عن الجاذبية
+
+165
+00:11:50,280 --> 00:11:53,760
+و الشغل اللي هي work and gravitational potential
+
+166
+00:11:53,760 --> 00:11:57,200
+energy طاقة الوضع طاقة وضع الجاذبيةلـ
+
+167
+00:11:57,200 --> 00:11:59,160
+gravitational potential energy of the system
+
+168
+00:11:59,160 --> 00:12:01,960
+consisting of earth and an object of mass and near
+
+169
+00:12:01,960 --> 00:12:07,120
+earth surface is given by طبعا طاقة الوضع الناتج
+
+170
+00:12:07,120 --> 00:12:12,320
+عن الجاذبية لها علاقة بأي جسم بيكون على سطح قريب
+
+171
+00:12:12,320 --> 00:12:16,120
+من سطح الأرض وعلى ارتفاع معين من الأرض بيكون له
+
+172
+00:12:16,120 --> 00:12:19,660
+طاقة وضع ممكن الأرض تكون level ممكن طاولة ممكن أي
+
+173
+00:12:19,660 --> 00:12:23,920
+شيء لكن مبدعيا بصفة عامة طاقة الوضع ناتج عن
+
+174
+00:12:23,920 --> 00:12:29,570
+الجاذبيةهي مرتبطة بالأرض و أي جسم بيكون قريب من
+
+175
+00:12:29,570 --> 00:12:33,070
+الأرض له طاقة واضعة اللي هي potential energy
+
+176
+00:12:33,070 --> 00:12:38,370
+بتساوي MGY Y هذا هو ارتفاع الجسم عن سطح الأرض إذا
+
+177
+00:12:38,370 --> 00:12:41,770
+اعتبرنا أن الأرض هي ال level طبعا ال G is the
+
+178
+00:12:41,770 --> 00:12:46,390
+acceleration of gravity اللي هي عجلة الجاذبية أو
+
+179
+00:12:46,390 --> 00:12:49,770
+الجاذبية الأرضية أو التسارع الجاذبية and Y is the
+
+180
+00:12:49,770 --> 00:12:52,050
+vertical position of the mass relative to the
+
+181
+00:12:52,050 --> 00:12:55,910
+surface of the earthال Y هو عبارة عن المسافة
+
+182
+00:12:55,910 --> 00:13:02,250
+الرأسية المسافة الرأسية اللي هي بالنسبة لسطح الأرض
+
+183
+00:13:02,250 --> 00:13:05,870
+باعتبار أنه الأرض هي عبارة عن reference point نقطة
+
+184
+00:13:05,870 --> 00:13:10,970
+مرجعية معنى الكلام أن طاقة الوضع لأي جسم بيرتفع Y
+
+185
+00:13:10,970 --> 00:13:14,490
+عن سطح الأرض سواء بي ام في جي في واي بصفة عامة
+
+186
+00:13:14,490 --> 00:13:19,730
+طاقة الوضع كمية قياسية زي ما تحدثنا سابقا و ال
+
+187
+00:13:19,730 --> 00:13:24,070
+system international unit وحدتهابينها تساوي جول
+
+188
+00:13:24,070 --> 00:13:29,670
+وهي رمزها G في هذا التعريف لو كانت Y بالساوية Zero
+
+189
+00:13:29,670 --> 00:13:34,670
+معناته الجسم على سطح الأرض معناه إذا اللي هي طاقة
+
+190
+00:13:34,670 --> 00:13:38,990
+الوضع لأي جسم ياخد على سطح الأرض بالساوية Zero but
+
+191
+00:13:38,990 --> 00:13:42,450
+that is not strictly necessary as discussed in the
+
+192
+00:13:42,450 --> 00:13:47,770
+next discussion in turn out that only difference
+
+193
+00:13:47,770 --> 00:13:51,930
+in the potential energy really matterطبعا ليس شرطا
+
+194
+00:13:51,930 --> 00:13:56,490
+انها تكون ال .. ال .. ال surface ال earth surface
+
+195
+00:13:56,490 --> 00:14:00,470
+هو اللي .. اللي هي المرجعية ليه عساس انه اعتبر انه
+
+196
+00:14:00,470 --> 00:14:04,210
+اللي هي ال potential energy لأي جسم بيساوي zero
+
+197
+00:14:04,210 --> 00:14:10,370
+ممكن حسب السؤال بيحدد اي mean ال level وبالتالي اي
+
+198
+00:14:10,370 --> 00:14:14,490
+جسم يقع على ال level او اي مستوى المفروض في السؤال
+
+199
+00:14:14,490 --> 00:14:19,810
+بتكون طاقة الوضع بساوي zerofrom this definition we
+
+200
+00:14:19,810 --> 00:14:22,030
+have .. we have the relation between gravitational
+
+201
+00:14:22,030 --> 00:14:25,330
+work and gravitational potential من هذا التعريف
+
+202
+00:14:25,330 --> 00:14:30,310
+نصل إلى معادلة خمسة اتناش وهي عبارة عن ان الشغل
+
+203
+00:14:30,310 --> 00:14:34,230
+الناتج عن الجاذبية بدي يساوي ناقص potential energy
+
+204
+00:14:34,230 --> 00:14:37,630
+final ناقص potential energy initial يعني ناقص
+
+205
+00:14:37,630 --> 00:14:43,530
+delta B Eيعني بتساوى ناقص mg y final ناقص mg y
+
+206
+00:14:43,530 --> 00:14:47,750
+initial أو ناقص mg y final ناقص initial هذا الشغل
+
+207
+00:14:47,750 --> 00:14:51,310
+الناتج عن الجاذبية اذا ال work done by gravity is
+
+208
+00:14:51,310 --> 00:14:54,630
+one and the same as the negative that change in
+
+209
+00:14:54,630 --> 00:14:57,850
+the gravitational potential energy اذا الخلاصة انه
+
+210
+00:14:58,120 --> 00:15:04,100
+الشغل الناتج عن الجاذبية هو عبارة عن ناقص التغير
+
+211
+00:15:04,100 --> 00:15:08,660
+في طاقة الوضع، ناقص التغير في طاقة الوضع اللي هي
+
+212
+00:15:08,660 --> 00:15:12,760
+الخاصة بالجاذبية ل gravitational potential energy
+
+213
+00:15:14,910 --> 00:15:20,410
+Finally using the relation أخيرا باستخدم العلاقة
+
+214
+00:15:20,410 --> 00:15:25,370
+اللى هو خمسة اتناش في المعادلة خمسة عشرة P علشان
+
+215
+00:15:25,370 --> 00:15:30,710
+أوجد اللى هو extension of the work energy برضه بدأ
+
+216
+00:15:30,710 --> 00:15:34,490
+أوجد طبعا اللى هو علاقة بين الشغل ال non
+
+217
+00:15:34,490 --> 00:15:38,550
+-conservative وطقط الوضع وطقط الحركة اذا الشغل ال
+
+218
+00:15:38,550 --> 00:15:45,060
+W and C بدها تساوي Delta K زائد Delta Bدلتا كي
+
+219
+00:15:45,060 --> 00:15:51,400
+بتساوي دلتا اي final ناقص اقصد دلتا اي دلتا كي
+
+220
+00:15:51,400 --> 00:15:55,360
+بتساويالكيانتك energy final ناقص كيانتك energy
+
+221
+00:15:55,360 --> 00:16:00,400
+initial وDelta B بتساوي B potential energy final
+
+222
+00:16:00,400 --> 00:16:04,400
+ناقص potential energy initial اذا W and C بتساوي
+
+223
+00:16:04,400 --> 00:16:08,620
+Delta K زائد Delta B هذه المعادلة خمسة طلتاش
+
+224
+00:16:08,620 --> 00:16:12,000
+بتعطيني الشغل الناتج عن ال non conservative
+
+225
+00:16:12,000 --> 00:16:17,260
+والتغير في طاقة الوضع إضافة إلى التغير في طاقة
+
+226
+00:16:17,260 --> 00:16:21,110
+الحركة تغيراللي هو the situation says that the
+
+227
+00:16:21,110 --> 00:16:24,450
+work done by the non conservative force اللي هو W
+
+228
+00:16:24,450 --> 00:16:28,430
+and C is equal to the change in the kinetic energy
+
+229
+00:16:28,430 --> 00:16:30,490
+plus the change in the gravitational potential
+
+230
+00:16:30,490 --> 00:16:36,770
+energyننتقل إلى section خمسة، تلاتة، اتنين بنيجي ل
+
+231
+00:16:36,770 --> 00:16:39,110
+reference levels for gravitational potential
+
+232
+00:16:39,110 --> 00:16:42,590
+energy اللي هو مستوى المرجعية أو المستوى اللي
+
+233
+00:16:42,590 --> 00:16:48,130
+حكينا عليه سابقا يعني عشان أحدد طبعا طاقت الوضع
+
+234
+00:16:48,130 --> 00:16:52,530
+موجبة أو صالبة أو zero in solving problems
+
+235
+00:16:53,920 --> 00:16:57,380
+involving gravitational potential energy it's
+
+236
+00:16:57,380 --> 00:17:00,920
+important to choose a location at which to see
+
+237
+00:17:00,920 --> 00:17:05,260
+that energy equal to zero عشان أحدد اللي هي
+
+238
+00:17:05,260 --> 00:17:08,600
+potential energy موجبة ولا سلبة ولا zero لازم نحدد
+
+239
+00:17:08,880 --> 00:17:14,680
+location مكانها وكمان بنحدد ال level إذا كانت هي
+
+240
+00:17:14,680 --> 00:17:20,700
+الجسم على ال level مباشرة فال energy بتساوي zero
+
+241
+00:17:20,700 --> 00:17:26,400
+نيجلا given the form of equation خمسة أحداشر this
+
+242
+00:17:26,400 --> 00:17:30,760
+is the same as choosing the place لما يكون عندي ال
+
+243
+00:17:30,760 --> 00:17:34,040
+Y اللي هي ال vertical location او ال vertical
+
+244
+00:17:34,040 --> 00:17:39,010
+displacement بساوي ال Y بساوي Zeroبيطلع أن the
+
+245
+00:17:39,010 --> 00:17:41,950
+choice is completely arbitrary because the
+
+246
+00:17:41,950 --> 00:17:43,970
+important quantity is the difference in the
+
+247
+00:17:43,970 --> 00:17:46,850
+potential energy and this difference will be the
+
+248
+00:17:46,850 --> 00:17:50,350
+same regardless of the choice of this zero level
+
+249
+00:17:50,350 --> 00:17:55,250
+لما يكون عندي أنا جسم انتقل من مكان أو رجع لنفس
+
+250
+00:17:55,250 --> 00:17:58,070
+المكان فال displacement ساوة zero أو ممكن احنا
+
+251
+00:17:58,070 --> 00:18:02,030
+نعتبر انه اللي هو الفرق في طاقة الوضع بالساوة zero
+
+252
+00:18:02,030 --> 00:18:05,270
+على أساس انهالـ potential energy بيساوي 0 ممكن ال
+
+253
+00:18:05,270 --> 00:18:09,530
+Y بدها تساوي 0 أو التغير في Delta potential energy
+
+254
+00:18:09,530 --> 00:18:14,650
+بيساوي 0 ممكن يعني نعتبر أنه ال level هي على level
+
+255
+00:18:14,650 --> 00:18:17,690
+potential energy 0 أو التغير في Delta PE بيساوي 0
+
+256
+00:18:17,690 --> 00:18:20,790
+أنه ال Y initial بيساوي ال Y final معناته Delta Y
+
+257
+00:18:20,790 --> 00:18:26,850
+بيساوي 0Example خمسة أربعة بيوضح اللي هو ال level
+
+258
+00:18:26,850 --> 00:18:32,590
+zero level بيوضح أيضا نقاط معينة على أي حال once
+
+259
+00:18:32,590 --> 00:18:35,830
+this position is chosen it must remain fixed for a
+
+260
+00:18:35,830 --> 00:18:39,970
+given problem نيجي لها example خمسة أربعة عساس
+
+261
+00:18:39,970 --> 00:18:44,760
+نحدد نقاط معينة و نوجد عندها طاقة ال .. الوضععندي
+
+262
+00:18:44,760 --> 00:18:49,360
+أنا جسم او skyer is at the top of the slope as
+
+263
+00:18:49,360 --> 00:18:55,920
+shown متذلج وزن .. وزنه او وزنها طبعا هي بالساعة
+
+264
+00:18:55,920 --> 00:18:58,980
+ستين kilogram هذا عبارة عن كتلة اللي هي ستين
+
+265
+00:18:58,980 --> 00:19:06,160
+kilogram موجود على اعلى مكان ميل اللي ميل طبعا
+
+266
+00:19:06,160 --> 00:19:10,410
+بسلوب معينat the initial point N.A بعدين هذه
+
+267
+00:19:10,410 --> 00:19:15,890
+المتذلجة او طبعا البنت she is عشرة متر vertical
+
+268
+00:19:15,890 --> 00:19:19,630
+above the point B setting the zero level of the
+
+269
+00:19:19,630 --> 00:19:21,370
+gravitational potential energy at B find the
+
+270
+00:19:21,370 --> 00:19:23,750
+gravitational potential energy of this systemطبعا
+
+271
+00:19:23,750 --> 00:19:29,650
+في السؤال بدنا نحدد هى متذلجة كانت عند نقطة A
+
+272
+00:19:29,650 --> 00:19:35,830
+النقطة A هدى على مستوى ميل طبعا هدى المتذلجة كانت
+
+273
+00:19:35,830 --> 00:19:40,830
+على بعد عشرة متر رأسى بعيدا عن النقطة B حكى عرفى
+
+274
+00:19:40,830 --> 00:19:44,530
+ايه sitting the zero level بدى اعتبر انه ال level
+
+275
+00:19:44,530 --> 00:19:48,260
+يعنى zero level عند النقطة Bبدنا نوجد find the
+
+276
+00:19:48,260 --> 00:19:52,200
+gravitational potential energy of this system in
+
+277
+00:19:52,200 --> 00:19:56,940
+this system when the sky is at A and into B بد
+
+278
+00:19:56,940 --> 00:20:00,700
+أوجد طاقة ال .. الوضع اللي هي الخاصة بالجاذبية
+
+279
+00:20:00,700 --> 00:20:05,560
+عندما كانت البنت انتقلت من نقطة A لنقطة B نيجي
+
+280
+00:20:05,560 --> 00:20:10,280
+للسؤال مرسوم طبعا في عندي متزلجة هيها كانت عند
+
+281
+00:20:10,280 --> 00:20:14,730
+النقطة A بدأ توصل عند النقطة Bكانت عند a بدأت توصل
+
+282
+00:20:14,730 --> 00:20:18,350
+عند النقطة b هذا المتجلج عند a يعني بتسير على
+
+283
+00:20:18,350 --> 00:20:23,470
+مستوى ميل ارتفاع الرأس كان عشرة متر و طبعا عند
+
+284
+00:20:23,470 --> 00:20:26,430
+نقطة a و b و أعتبرنا أن ال b هو ال level بدنا
+
+285
+00:20:26,430 --> 00:20:30,010
+نعتبر أن ال b هو ال level في معنى الكلام هو ال
+
+286
+00:20:30,010 --> 00:20:35,380
+level يعني هو المرجعية بدأ أقارن عند نقطة aو اوصل
+
+287
+00:20:35,380 --> 00:20:38,900
+للنقطة B يعني A initial و B هي ال final الحل
+
+288
+00:20:38,900 --> 00:20:44,080
+بتعتبر أن ال Y0 طبعا ال Y0 at the level اللي هو B
+
+289
+00:20:44,080 --> 00:20:48,280
+لإنه حدد لإنه B بدنا نعتبره هو level Calculate the
+
+290
+00:20:48,280 --> 00:20:51,860
+potential energy at A and B بد أوجد طاقة الوضع عند
+
+291
+00:20:51,860 --> 00:20:56,110
+النقطة A و عند النقطة Band calculate the change in
+
+292
+00:20:56,110 --> 00:20:58,450
+the potential energy يعني بتبقى وش طاقة الوضع and
+
+293
+00:20:58,450 --> 00:21:01,730
+a طاقة الوضع and بيبقى بين التغير في طاقة الوضع
+
+294
+00:21:01,730 --> 00:21:05,010
+طاقة الوضع عند النقطة a اللي هي ال potential
+
+295
+00:21:05,010 --> 00:21:08,690
+energy initial بتساوي ال M في G في Y ال M كانت
+
+296
+00:21:08,690 --> 00:21:12,350
+ستين و ال G تسعة و تمانية من عشرة و ال Y كانت عشرة
+
+297
+00:21:12,350 --> 00:21:16,870
+اذا ال potential energy عند النقطة a بتساوي خمسة
+
+298
+00:21:16,870 --> 00:21:20,300
+point تمانية تمانية في عشر أس تلاتة جولال
+
+299
+00:21:20,300 --> 00:21:23,880
+potential energy اللى هى ال final and النقطة بي
+
+300
+00:21:23,880 --> 00:21:27,900
+زيرو لإنه ال y بساوي زيرو او لإنه احنا وصلنا ل ال
+
+301
+00:21:27,900 --> 00:21:31,680
+level اذا التغير ال difference the difference
+
+302
+00:21:31,680 --> 00:21:36,100
+energy between a and b the difference in potential
+
+303
+00:21:36,100 --> 00:21:40,180
+energy اللى هو دلتا بي الفرق فى طاقة الوضعبين ال
+
+304
+00:21:40,180 --> 00:21:44,760
+initial و ال final delta P final ناقص P initial
+
+305
+00:21:44,760 --> 00:21:48,580
+بالساوي ال final كانت zero ناقص خمسة point تمانية
+
+306
+00:21:48,580 --> 00:21:52,400
+تمانية في عشر أقصى ثلاثة جول تطلع عندي سالب خمسة
+
+307
+00:21:52,400 --> 00:21:54,380
+point تمانية تمانية في عشر أقصى ثلاثة جول هذه
+
+308
+00:21:54,380 --> 00:21:58,020
+عبارة عن التغير في طاقة الوضع أنها تجعن الجاذبية
+
+309
+00:21:58,020 --> 00:22:03,090
+عندما انتقلت البنت من نقطة A لنقطة Bالان السؤال في
+
+310
+00:22:03,090 --> 00:22:07,370
+بي بيحكي لنا repeat عيد ده problem لنا عيد السؤال
+
+311
+00:22:07,370 --> 00:22:10,090
+إذا كانت ال y بالساوة zero at a يعني أنا بدي أعتبر
+
+312
+00:22:10,090 --> 00:22:15,210
+ال a هو ال level إذا أعتبرت ال a هو ال level اللي
+
+313
+00:22:15,210 --> 00:22:18,230
+على ال a اللي على ال a ال y بالساوة zero اللي تحت
+
+314
+00:22:18,230 --> 00:22:23,250
+ال level بعتبر ال y سالبة وبالتالي طاقة الوضع تحت
+
+315
+00:22:23,250 --> 00:22:26,250
+ال level سالبة طاقة ال وضع فوق ال level موجبة طاقة
+
+316
+00:22:26,250 --> 00:22:29,540
+ال وضع على ال level zerothe new reference point so
+
+317
+00:22:29,540 --> 00:22:32,540
+that potential energy الان potential energy عند
+
+318
+00:22:32,540 --> 00:22:36,600
+النقطة a بتساوي zero ال potential energy ال final
+
+319
+00:22:36,600 --> 00:22:39,980
+عند النقطة b طبعا ال y عند النقطة b بتساوي ناقص
+
+320
+00:22:39,980 --> 00:22:44,760
+عشرة لإن ال b أسفل ال a وبالتالي ال potential
+
+321
+00:22:44,760 --> 00:22:48,300
+energy ال final بتساوي ال m في g في y final ال m
+
+322
+00:22:48,300 --> 00:22:51,900
+كانت ستين ال kilogram و ال g تسعة و تمانية من عشرة
+
+323
+00:22:51,900 --> 00:22:55,840
+و ال y ناقص عشرةتطلع برضه ناقص خمسة point تمانية
+
+324
+00:22:55,840 --> 00:23:00,140
+تمانية في عشر أقصى ثلاثة اذا Delta P بتساوي Delta
+
+325
+00:23:00,140 --> 00:23:04,080
+P final ناقص P initial وهي بتطلع ناقص خمسة point
+
+326
+00:23:04,080 --> 00:23:07,960
+تمانية تمانية في عشر أقصى ثلاثة usual في C حكيلنا
+
+327
+00:23:07,960 --> 00:23:12,740
+repeat اي قاعد ده problem انا قاعد ال problem if Y
+
+328
+00:23:12,740 --> 00:23:16,900
+is zero two meters above B اذا كانت ال level عندما
+
+329
+00:23:16,900 --> 00:23:25,340
+تصل النقطة هدلز اللي متسلجة على بعد ضعفبنقطة بي
+
+330
+00:23:25,340 --> 00:23:32,440
+على بعد مترين من النقطة بي
+
+331
+00:23:32,720 --> 00:23:40,300
+ب initial يعني هطرح المتبين من اللي هو العشرة طبعا
+
+332
+00:23:40,300 --> 00:23:43,960
+هي كانت هنا هطرح هنا وسط المنطقة هذه وسط المنطقة
+
+333
+00:23:43,960 --> 00:23:47,300
+هذه إذا هذا هو ال level بضبط عندي هنا اتنين هطرح
+
+334
+00:23:47,300 --> 00:23:50,100
+عشرة نقص اتنين بيصير عندي ال level هنا تمانية فال
+
+335
+00:23:50,100 --> 00:23:54,000
+initial من النقطة A لنقطة I بيكون عندي اللي هي M
+
+336
+00:23:54,000 --> 00:24:00,440
+في G في Y اللي هي تمانية زي ما احنا حاطين هنا إذا
+
+337
+00:24:02,040 --> 00:24:05,960
+الـ B initial بيساوي M في G في Y initial الـ M
+
+338
+00:24:05,960 --> 00:24:08,800
+ستين كيلو في تسعة و تمانية من عشرة في تمانية
+
+339
+00:24:08,800 --> 00:24:11,060
+التمانية اجت من عشرة نقص اتنين اللي حكالي هنا two
+
+340
+00:24:11,060 --> 00:24:15,180
+meters above اذا ال final potential energy final
+
+341
+00:24:15,180 --> 00:24:19,920
+عند النقطة B هيكون عندي عند النقطة B ال B تحت تحت
+
+342
+00:24:19,920 --> 00:24:23,280
+الاتنين اللي انا فرضتها فبتكون الاتنين سالب اذا ال
+
+343
+00:24:23,280 --> 00:24:27,790
+B E final بيساوي M في G في Y finalالان برضه ال 2
+
+344
+00:24:27,790 --> 00:24:30,270
+ماتغيرتش و ال G تسعة و تمانية و عشرة ال Y final
+
+345
+00:24:30,270 --> 00:24:33,890
+كانت نقص اتنين ليش نقص اتنين لإنه .. لإنه حكالي
+
+346
+00:24:33,890 --> 00:24:37,770
+عند نقطة اتنين اعلى من ال B اعتبر ال level اذا ال
+
+347
+00:24:37,770 --> 00:24:42,230
+B هتكون اسفل ال .. النقطة اللي هو ال level و
+
+348
+00:24:42,230 --> 00:24:46,400
+بالتالي نقص اتنين فبطلع ان بي Efinal ناقص واحد
+
+349
+00:24:46,400 --> 00:24:51,340
+point واحد تمانية في عشر أقص تلاتة usual بدا أحسب
+
+350
+00:24:51,340 --> 00:24:56,240
+choose the change in potential energy فطبعا delta
+
+351
+00:24:56,240 --> 00:25:00,820
+P final ناقص P initial بطلع نفس الجواب مع أن
+
+352
+00:25:00,820 --> 00:25:03,560
+الكلام لو أخترت ال level عند النقطة A أو أخترت ال
+
+353
+00:25:03,560 --> 00:25:08,300
+level عند النقطة B أو أخترنا level في أي مكان على
+
+354
+00:25:08,300 --> 00:25:15,510
+الرأسي بيطلع تقريبا نفس البطلع تقريبا نفس الحل نفس
+
+355
+00:25:15,510 --> 00:25:22,050
+الحل نشلق ال gravity and the conservation of
+
+356
+00:25:22,050 --> 00:25:26,370
+mechanical energy section خمسة تلاتة the kinetic
+
+357
+00:25:26,370 --> 00:25:30,710
+energy اللي هي رمزها ke of an object falling only
+
+358
+00:25:30,710 --> 00:25:33,290
+under the influence of gravity is constantly
+
+359
+00:25:33,290 --> 00:25:36,920
+changingas it's gravitational potential energy PE
+
+360
+00:25:36,920 --> 00:25:40,160
+الآن بالنسبة لل gravity و ال conservation of
+
+361
+00:25:40,160 --> 00:25:43,400
+mechanical energy فى عندى حاجة اسمها اللى هى
+
+362
+00:25:43,400 --> 00:25:46,960
+mechanical energy هى عبارة عن مجموع اللى هى طاقة
+
+363
+00:25:46,960 --> 00:25:49,680
+الحركة و طاقة الوضع نسموها mechanical energy
+
+364
+00:25:49,680 --> 00:25:54,900
+المقصود بهذا الكلام أن طاقة الحركة و طاقة الوضع
+
+365
+00:25:54,900 --> 00:25:59,440
+خلال اللى هى gravitational ال gravity أو
+
+366
+00:25:59,440 --> 00:26:02,870
+gravitational motionبتكون عندها مقدار ثابت
+
+367
+00:26:02,870 --> 00:26:05,890
+Constantly it's changing أو بتتغير تغير ثابت يعني
+
+368
+00:26:05,890 --> 00:26:09,490
+إذا طاقة الحركة زادت طاقة الحركة الوضع بتقل إنه
+
+369
+00:26:09,490 --> 00:26:14,750
+مجموعة انتن مقدار ثابت واضح this quantity aren't
+
+370
+00:26:14,750 --> 00:26:19,190
+conserved because all non conservative force are
+
+371
+00:26:19,190 --> 00:26:25,110
+absent في هذه الحالة بالنسبالي ال gravity هو غير
+
+372
+00:26:25,110 --> 00:26:29,010
+محفوظة طبعا مش موجودة وبالتالي W and C بسوا zero
+
+373
+00:26:29,420 --> 00:26:32,420
+لأن اتفقنا أن ال gravity أو ال potential energy أو
+
+374
+00:26:32,420 --> 00:26:34,180
+ال gravitational ال potential energy يبقى عن
+
+375
+00:26:34,180 --> 00:26:38,980
+conserved force معناه الكلام أنه في حالة ال
+
+376
+00:26:38,980 --> 00:26:42,300
+gravity أو في حالة حركة الجسم من أعلى إلى أسفل
+
+377
+00:26:42,300 --> 00:26:46,140
+مسفل إلى أعلى لما أستخدم طيارات الطاقةبيكون عندي
+
+378
+00:26:46,140 --> 00:26:49,440
+طاقة في حاجة اسمة طاقة الوضع والحركة initial بساوي
+
+379
+00:26:49,440 --> 00:26:52,680
+طاقة الحركة زاقة الوضع final الآن according to
+
+380
+00:26:52,680 --> 00:26:56,060
+this equation بناء على هذه المعادلة مجموع ال
+
+381
+00:26:56,060 --> 00:27:00,580
+kinetic energy and ال potential energy مقدار ثابت
+
+382
+00:27:00,580 --> 00:27:06,360
+اه في كل اللحظات وبالتاليهي تعتبر conserved
+
+383
+00:27:06,360 --> 00:27:09,520
+quantity, we denote the total mechanical energy
+
+384
+00:27:09,520 --> 00:27:15,360
+بقى ممكن انا طبعا ارمزلها بالرمز اللي هي E بيسموها
+
+385
+00:27:15,360 --> 00:27:18,600
+ال mechanical energy او mechanical .. هذا ال
+
+386
+00:27:18,600 --> 00:27:21,160
+mechanical .. mechanical energy عبارة عن مجموع
+
+387
+00:27:21,160 --> 00:27:24,420
+طاقة الحركة و طاقة الوضع وهي مقدار محفوظ او
+
+388
+00:27:24,420 --> 00:27:27,440
+conserved طاقة الوضع و طاقة الحركة هي عبارة عن
+
+389
+00:27:27,440 --> 00:27:32,170
+conservedto show how this concept work think of
+
+390
+00:27:32,170 --> 00:27:36,310
+tossing a rock of cliff, ignore the drag of force
+
+391
+00:27:36,310 --> 00:27:40,450
+as the rock falls لو كان عندي أنا صخرة سقطت من
+
+392
+00:27:40,450 --> 00:27:47,550
+مكان مرتفع طبعا هي صخرة موجودة وفي عندي الصخرة دي
+
+393
+00:27:47,550 --> 00:27:51,150
+وقعت من مكان مرتفع سرعتها طبعا هي تبدأ من ال zero
+
+394
+00:27:51,740 --> 00:27:56,340
+سرعتها بتزيد طالما أن سرعتها بتزيد فطاقة الحركة
+
+395
+00:27:56,340 --> 00:27:59,940
+بتزيد the rock approach the ground إذا السخرة وصلت
+
+396
+00:27:59,940 --> 00:28:04,400
+لأرض طاقة الحركة بتكون أعلى ما يمكن طاقة الوضع
+
+397
+00:28:04,400 --> 00:28:08,570
+بتكون السفر بتقل معنى الكلاملو كان عندى انا حجر او
+
+398
+00:28:08,570 --> 00:28:12,330
+صخرة او اى جسم انتقل الى مكان مرتفع الى الأرض بدأ
+
+399
+00:28:12,330 --> 00:28:14,950
+من ال rest بدأ من السكون فتغطي الحركة بتبدأ سفر
+
+400
+00:28:14,950 --> 00:28:18,810
+طول ده بتزيد لغاية ما توصل اقصى سرعة لها لما توصل
+
+401
+00:28:18,810 --> 00:28:22,370
+للأرض طبعا just before hitting the ground قبل ما
+
+402
+00:28:22,370 --> 00:28:26,210
+تصدم في الأرض الان لما تكون الصخرة او الحجر او اى
+
+403
+00:28:26,210 --> 00:28:30,750
+جسم على ارتفاع معين من الأرض بيكون ايه طاقة وضعى
+
+404
+00:28:30,750 --> 00:28:34,250
+الان طاقة الوضع potential energy بتبدأ تفقد lost
+
+405
+00:28:34,250 --> 00:28:41,260
+as the rock moveطبعا تبدأ تقل decrease as the ..
+
+406
+00:28:41,260 --> 00:28:44,900
+اللي هي rock move تتحرك downward appear as kinetic
+
+407
+00:28:44,900 --> 00:28:48,120
+energy فمعنى الكلام أنه أي جسم بيكون على ارتفاع
+
+408
+00:28:48,120 --> 00:28:52,140
+معين من الأرض بيكون له طاقة وضع وطاقة الحركة zero
+
+409
+00:28:52,140 --> 00:28:57,000
+تبدأ طاقة الحركة تزيد طاقة الوضع تقل لإنه في حاجة
+
+410
+00:28:57,000 --> 00:28:59,160
+اسمها conservation of mechanical energy لإنه في
+
+411
+00:28:59,160 --> 00:29:02,880
+مقدار ثابت اسم طاقة الطاقة الميكانيكية المحفوظة
+
+412
+00:29:02,880 --> 00:29:06,480
+اللي هي طاقة الحركة وطاقة الوضعIn any isolated
+
+413
+00:29:06,480 --> 00:29:09,080
+system of the object interacting only through a
+
+414
+00:29:09,080 --> 00:29:11,580
+conservative force, the total mechanical energy,
+
+415
+00:29:11,640 --> 00:29:15,660
+زي ما حكينا E سو K E زي P E of this system remain
+
+416
+00:29:15,660 --> 00:29:18,340
+at the same معنى الكلام الطاقة الميكانيكية، هي
+
+417
+00:29:18,340 --> 00:29:21,580
+عبارة عن طاقة الحركة أو طاقة الوضع، وهي مقدار ثابت
+
+418
+00:29:22,730 --> 00:29:25,850
+If the force of gravity is the only force doing
+
+419
+00:29:25,850 --> 00:29:28,170
+work within the system then the principle of
+
+420
+00:29:28,170 --> 00:29:31,130
+conservation of mechanical energy take the form لو
+
+421
+00:29:31,130 --> 00:29:35,370
+كان عندى بس فقط هي طبعا قوة الجاذبية هي الموجودة
+
+422
+00:29:35,370 --> 00:29:39,550
+او هي القوة المسببة لهذا الشغل داخل هذا النظام أو
+
+423
+00:29:39,550 --> 00:29:44,390
+داخل اي system معنى الكلام اللى ممكن نكتب Mv
+
+424
+00:29:44,390 --> 00:29:48,150
+initial تربيه زاد Mgy initial بالساوي Mv final
+
+425
+00:29:48,150 --> 00:29:52,280
+تربيه زاد Mgy finalطاقة حركة initial, طاقة وضع
+
+426
+00:29:52,280 --> 00:29:56,160
+initial, طاقة حركة final وطاقة وضع final اللي هي
+
+427
+00:29:56,160 --> 00:30:00,800
+دي تمثل ال conservation of اللي هي mechanical
+
+428
+00:30:00,800 --> 00:30:06,540
+energy ال quiz خمسة تلاتة في عندي انا three
+
+429
+00:30:06,540 --> 00:30:11,900
+identical poles three identical poles are thrown
+
+430
+00:30:11,900 --> 00:30:15,380
+from the top of the building في عندي تلت كرات
+
+431
+00:30:15,380 --> 00:30:21,030
+سقطوا من اعلى مبنىبنفس with the same initial speed
+
+432
+00:30:21,030 --> 00:30:24,390
+بنفس السرعة the first ball نفس قيمة السرعة ال
+
+433
+00:30:24,390 --> 00:30:26,950
+speed the first ball is thrown horizontal واحدة
+
+434
+00:30:26,950 --> 00:30:30,970
+منهم طبعا قدفناها horizontal و التانية قدفناها
+
+435
+00:30:30,970 --> 00:30:34,670
+بزاوية أعلى من ال horizontal و التالتة قدفتها
+
+436
+00:30:34,670 --> 00:30:39,350
+below the horizontal السؤال neglect مع إهمال
+
+437
+00:30:39,350 --> 00:30:42,990
+مقاومة الهواء rank the speed of the ball as they
+
+438
+00:30:42,990 --> 00:30:49,120
+reach the ground from fastest to lowest طبعابدنا
+
+439
+00:30:49,120 --> 00:30:54,420
+نرتب .. ال .. ال .. بدنا نرتب rank ده اسمه
+
+440
+00:30:54,420 --> 00:30:58,820
+السرعيات هذه الكورات لما توصل الأرض من اللي هي
+
+441
+00:30:58,820 --> 00:31:03,190
+الأسرع إلى الأبطاءهل هي هتكون الأولى و التانى و
+
+442
+00:31:03,190 --> 00:31:06,210
+التالتى او التانى و واحد و التالتى او التالتى و
+
+443
+00:31:06,210 --> 00:31:09,210
+الأولى و التانى او all three balls strike the
+
+444
+00:31:09,210 --> 00:31:14,830
+ground at the same speed الحل اللى هى ال .. ال ..
+
+445
+00:31:14,830 --> 00:31:19,510
+الحل اللى هو ال answer زى ما هو موضح اللى هو دى
+
+446
+00:31:19,510 --> 00:31:23,970
+اللى التلاتة هيخوطوا الأرض بنفس السرعة بنفس السرعة
+
+447
+00:31:23,970 --> 00:31:29,790
+لإنه هي التلاتةموجودين على ارتفاع معين وارتفاع هو
+
+448
+00:31:29,790 --> 00:31:34,450
+اللي بيحدد بتكون اللي هم طاقة وضع محددة لما نرميها
+
+449
+00:31:34,450 --> 00:31:38,750
+بتتحول طاقة الوضع لطاقة الحركة ال M ليس لها علاقة
+
+450
+00:31:38,750 --> 00:31:44,930
+وبالتالي التلاتة إذا ارتموا أي جسمين بغض النظر عن
+
+451
+00:31:44,930 --> 00:31:48,710
+الكتلة ليس لها أي علاقة الكتلة لإنه هنا بنكون
+
+452
+00:31:48,710 --> 00:31:52,550
+..بنحكي MGH بالساعة ونص Mv تربيع وبالتالي السرعة
+
+453
+00:31:52,550 --> 00:31:56,600
+النهائية بالساعة V بالساعة جزر 2GHفال G ثابتة و ال
+
+454
+00:31:56,600 --> 00:32:00,820
+S هو او الارتفاع هو او ال Y هو طبعا نرتموا من نفس
+
+455
+00:32:00,820 --> 00:32:03,120
+الارتفاع وبالتالي هينزلوا من نفس السرعة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..9b9a6ce2b1f1ef56dd38ddf1e0b1940389a7dfae
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/g-QvgdKpEAQ_raw.json
@@ -0,0 +1 @@
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هي الموضوع الرأسي أو اللي هي ال vertical location ال potential energy is property of the citizen برضه طاقة الوضع هي خاصية لأي نظام ممكن يكون لحاله", "tokens": [3224, 1829, 23032, 995, 28671, 2423, 2407, 11242, 3615, 6055, 24401, 12984, 4724, 35457, 3555, 16712, 17082, 13546, 8978, 9673, 41361, 23032, 3555, 3615, 995, 3714, 41361, 11296, 20666, 1863, 35457, 6027, 11296, 13672, 1829, 39896, 2423, 4386, 13672, 1829, 39896, 9673, 2407, 11242, 45367, 34892, 10721, 3794, 1829, 34051, 13672, 1829, 39896, 2423, 9429, 4914, 2423, 3995, 2281, 307, 4707, 295, 264, 13326, 4724, 43042, 3224, 23032, 995, 28671, 2423, 2407, 11242, 3615, 39896, 16490, 33546, 10632, 5296, 10721, 1829, 8717, 19913, 10943, 3714, 43020, 7251, 30544, 5296, 5016, 6027, 3224], "avg_logprob": -0.08879367959114813, "compression_ratio": 1.6559633027522935, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 104.13, "end": 104.45, "word": "هي", "probability": 0.8291015625}, {"start": 104.45, "end": 104.67, "word": " 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rock of cliff, ignore the drag of force as the rock falls لو كان عندي أنا صخرة سقطت من مكان مرتفع طبعا هي صخرة موجودة وفي عندي الصخرة دي وقعت من مكان مرتفع سرعتها طبعا هي تبدأ من ال zero", "tokens": [1353, 855, 577, 341, 3410, 589, 519, 295, 14432, 278, 257, 3727, 295, 22316, 11, 11200, 264, 5286, 295, 3464, 382, 264, 3727, 8804, 45164, 25961, 18871, 16254, 41850, 20328, 9778, 25720, 8608, 47432, 2655, 9154, 3714, 41361, 3714, 43500, 5172, 3615, 23032, 3555, 3615, 995, 39896, 20328, 9778, 25720, 3714, 29245, 23328, 3660, 4032, 41185, 18871, 16254, 31767, 9778, 25720, 11778, 1829, 4032, 4587, 34268, 9154, 3714, 41361, 3714, 43500, 5172, 3615, 8608, 2288, 34268, 11296, 23032, 3555, 3615, 995, 39896, 6055, 44510, 10721, 9154, 2423, 4018], "avg_logprob": -0.17398174693075458, "compression_ratio": 1.5961538461538463, "no_speech_prob": 0.0, "words": [{"start": 1648.37, "end": 1648.55, "word": "to", "probability": 0.544921875}, {"start": 1648.55, "end": 1648.95, "word": " show", 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zero", "probability": 0.81005859375}], "temperature": 1.0}, {"id": 73, "seek": 168704, "start": 1671.74, "end": 1687.04, "text": "سرعتها بتزيد طالما أن سرعتها بتزيد فطاقة الحركة بتزيد the rock approach the ground إذا السخرة وصلت لأرض طاقة الحركة بتكون أعلى ما يمكن طاقة الوضع بتكون السفر بتقل معنى الكلام", "tokens": [3794, 2288, 34268, 11296, 39894, 11622, 25708, 23032, 6027, 15042, 14739, 8608, 2288, 34268, 11296, 39894, 11622, 25708, 6156, 9566, 995, 28671, 21542, 31747, 3660, 39894, 11622, 25708, 264, 3727, 3109, 264, 2727, 11933, 15730, 21136, 9778, 25720, 4032, 36520, 2655, 5296, 10721, 43042, 23032, 995, 28671, 21542, 31747, 3660, 39894, 30544, 5551, 3615, 23942, 19446, 7251, 43020, 23032, 995, 28671, 2423, 2407, 11242, 3615, 39894, 30544, 21136, 5172, 2288, 39894, 4587, 1211, 20449, 1863, 7578, 2423, 28820, 10943], "avg_logprob": -0.13046874850988388, "compression_ratio": 1.75, "no_speech_prob": 3.5762786865234375e-06, "words": [{"start": 1671.74, "end": 1672.44, "word": 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2407, 2423, 9640, 2655, 5172, 45761, 31439, 1975, 2407, 2423, 398, 31439, 23032, 3555, 3615, 995, 8717, 43500, 2304, 14407, 9154, 8717, 36178, 2423, 9640, 2655, 5172, 45761, 46599, 6027, 2655, 6027, 1829, 8032, 9957, 11622, 1211, 14407, 9154, 8717, 36178, 21136, 2288, 27884], "avg_logprob": -0.13569079156507524, "compression_ratio": 1.7714285714285714, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 1915.24, "end": 1915.76, "word": "فال", "probability": 0.87353515625}, {"start": 1915.76, "end": 1915.96, "word": " G", "probability": 0.53759765625}, {"start": 1915.96, "end": 1916.44, "word": " ثابتة", "probability": 0.932861328125}, {"start": 1916.44, "end": 1916.52, "word": " و", "probability": 0.7060546875}, {"start": 1916.52, "end": 1916.6, "word": " ال", "probability": 0.77880859375}, {"start": 1916.6, "end": 1916.78, "word": " S", "probability": 0.89599609375}, {"start": 1916.78, "end": 1916.98, "word": " هو", "probability": 0.54443359375}, {"start": 1916.98, "end": 1917.18, "word": " او", "probability": 0.6990966796875}, {"start": 1917.18, "end": 1917.72, "word": " الارتفاع", "probability": 0.93896484375}, {"start": 1917.72, "end": 1917.94, "word": " هو", "probability": 0.92822265625}, {"start": 1917.94, "end": 1918.18, "word": " او", "probability": 0.95263671875}, {"start": 1918.18, "end": 1918.28, "word": " ال", "probability": 0.98486328125}, {"start": 1918.28, "end": 1918.56, "word": " Y", "probability": 0.92529296875}, {"start": 1918.56, "end": 1919.16, "word": " هو", "probability": 0.94287109375}, {"start": 1919.16, "end": 1919.98, "word": " طبعا", "probability": 0.9544677734375}, {"start": 1919.98, "end": 1920.44, "word": " نرتموا", "probability": 0.70849609375}, {"start": 1920.44, "end": 1920.6, "word": " من", "probability": 0.99267578125}, {"start": 1920.6, "end": 1920.82, "word": " نفس", "probability": 0.9970703125}, {"start": 1920.82, "end": 1921.28, "word": " الارتفاع", "probability": 0.9841796875}, {"start": 1921.28, "end": 1921.68, 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/mVNome5mFKY_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/mVNome5mFKY_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..e8dba466f59b9a3aedae7ea488c287879970c122
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/mVNome5mFKY_raw.srt
@@ -0,0 +1,1256 @@
+1
+00:00:05,030 --> 00:00:09,010
+بسم الله الرحمن الرحيم هنبدأ chapter تلاتة بعنوان
+
+2
+00:00:09,010 --> 00:00:13,310
+emotion in two dimensions يعني الحركة في بعدين
+
+3
+00:00:13,310 --> 00:00:16,970
+طبعا درسنا بالفصول السابقة الحركة في بعد واحد
+
+4
+00:00:16,970 --> 00:00:20,250
+باتجاه ال X والحركة باتجاه ال Y اللي هي ال free
+
+5
+00:00:20,250 --> 00:00:23,710
+falling أو السقوط الحر الآن هنبدأ في section تلاتة
+
+6
+00:00:23,710 --> 00:00:26,790
+واحد بعنوان displacement, velocity and
+
+7
+00:00:26,790 --> 00:00:30,210
+acceleration in two dimensions يعني بتتعرف على
+
+8
+00:00:30,210 --> 00:00:34,500
+الإزاحة والسرعة والتسارع في بعدينin one
+
+9
+00:00:34,500 --> 00:00:38,320
+-dimensional motion as discussed in topics two the
+
+10
+00:00:38,320 --> 00:00:40,940
+direction of the vector quantity can be taken into
+
+11
+00:00:40,940 --> 00:00:43,460
+account by specifying whether the quantity is
+
+12
+00:00:43,460 --> 00:00:47,180
+positive or negative in one-dimensional motion في
+
+13
+00:00:47,180 --> 00:00:51,420
+الحركة في بعد واحدتم شرحها بالتفصيل في chapter
+
+14
+00:00:51,420 --> 00:00:57,400
+فاصل التاني اتجاه طبعا الكمية المتجهة ممكن كنا
+
+15
+00:00:57,400 --> 00:01:02,400
+ناخدها عبارة عن هل هذه الكمية موجبة أو سالبة the
+
+16
+00:01:02,400 --> 00:01:06,740
+velocity of the rocket for example if positive if
+
+17
+00:01:06,740 --> 00:01:09,920
+the rocket is going up يعني لو كان عندى انا صاروخ
+
+18
+00:01:09,920 --> 00:01:14,160
+مثلا او حجر او اي particle قدفتها إلى اعلى فانه
+
+19
+00:01:14,160 --> 00:01:18,400
+بتكون سرعتها موجبة بتكون الإزاحة ايضا موجبةif the
+
+20
+00:01:18,400 --> 00:01:21,680
+rocket is going up and negative if it's going down
+
+21
+00:01:21,680 --> 00:01:26,440
+لو كانت رمناها إلى أسفل بتكون سرعتها بدها تساوي
+
+22
+00:01:26,440 --> 00:01:30,500
+سالبة وإذا حتها برضه بتتساوي سالبة this simple
+
+23
+00:01:30,500 --> 00:01:33,840
+solution is no longer available in two or three
+
+24
+00:01:33,840 --> 00:01:37,340
+dimensions طبعا هذه المعلومة أو هذا التعريف أو هذا
+
+25
+00:01:37,340 --> 00:01:41,940
+المفهوم لا يعطينا الحل الكامل إذا كانت الحركة في
+
+26
+00:01:41,940 --> 00:01:48,110
+بعدين أو بثلاث أبعاد طبعا we must makeWe must make
+
+27
+00:01:48,110 --> 00:01:53,210
+full use of vector concepts الآن بدأ أفرض أن
+
+28
+00:01:53,210 --> 00:01:56,490
+object moving through space as shown in the figure
+
+29
+00:01:56,490 --> 00:02:00,410
+بدأ أفرض الآن في عندي أنا جسم بتحرك في الفضاء أو
+
+30
+00:02:00,410 --> 00:02:04,350
+بال space as shown in the figure تلاتة واحد when
+
+31
+00:02:04,350 --> 00:02:08,230
+an object at some point B at time T its position
+
+32
+00:02:08,230 --> 00:02:12,870
+is described by position vector Ri drawn from the
+
+33
+00:02:12,870 --> 00:02:18,680
+origin to B زي ما احنا مبين في الشكلفي هذا الشكل
+
+34
+00:02:18,680 --> 00:02:23,720
+انبين عندي انا طبعا عندي علاقة بين x و y علاقة بين
+
+35
+00:02:23,720 --> 00:02:29,180
+x و y ك .. كبعدين لو انا عندي النقطة هذه .. هذه
+
+36
+00:02:29,180 --> 00:02:34,200
+النقطة b هيلها إحداثيات x و y النقطة b لو انا فرضت
+
+37
+00:02:34,200 --> 00:02:37,440
+النقطة ال b هي نقطة البداية بسميها اناأشتغلت أو
+
+38
+00:02:37,440 --> 00:02:41,980
+بدأت عن نقطة T initial يعني نقطة البداية ووصلت ل T
+
+39
+00:02:41,980 --> 00:02:46,400
+final برضه T final هي نقطة Q لها إحداثيات X و Y
+
+40
+00:02:46,400 --> 00:02:51,060
+بدل ما أتكلم إحداثيات X و Y طبعا أخدت أنا ال unit
+
+41
+00:02:51,060 --> 00:02:55,820
+vector من النقطة 0 لنقطة B سميتها Riومن النقطة O
+
+42
+00:02:55,820 --> 00:03:00,780
+لنقطة Q سميتها R final الـ R هذه عبارة عن X and Y
+
+43
+00:03:00,780 --> 00:03:04,680
+إحداثيات و الـ R final عبارة عن X and Y وهذا ال
+
+44
+00:03:04,680 --> 00:03:09,200
+path of an object هذا مسار أي جسم اللي ماشي طبعا
+
+45
+00:03:09,200 --> 00:03:12,720
+نكمل التعريف the displacement of the object is a
+
+46
+00:03:12,720 --> 00:03:17,300
+vector deltaR هي عبارة عن الأقصر مسافة بين نقطة
+
+47
+00:03:17,300 --> 00:03:20,440
+البداية والنهاية اللي هي Delta R هي عبارة عن الـR
+
+48
+00:03:20,440 --> 00:03:25,080
+final ناقص الـR initial هذا الكلام احنا بتكلمه إذا
+
+49
+00:03:25,080 --> 00:03:29,560
+كان الحركة في بعدين فDelta R بتتساوي الـR final
+
+50
+00:03:29,560 --> 00:03:35,540
+ناقص الـR initial هذه عبارة عن الإزاحة في بعدين ال
+
+51
+00:03:35,540 --> 00:03:38,540
+unit vector اسمها اللي لها Rهي عبارة عن الـ R
+
+52
+00:03:38,540 --> 00:03:42,400
+final ناقص R initial كنا زمان نحكي اللي هي X final
+
+53
+00:03:42,400 --> 00:03:46,000
+ناقص X initial و Y final ناقص Y initial الآن من
+
+54
+00:03:46,000 --> 00:03:49,260
+هذا الشكل يعني في عندي أنا اللي هو ال position
+
+55
+00:03:49,260 --> 00:03:51,880
+final position و ال initial position of the vector
+
+56
+00:03:51,880 --> 00:03:54,440
+is the sum of the initial position vector and the
+
+57
+00:03:54,440 --> 00:03:57,440
+displacement اللي هي Delta R بتمثل عبارة عن Delta
+
+58
+00:03:57,440 --> 00:04:02,630
+X and Delta Y R final هي عبارة عنx final و y final
+
+59
+00:04:02,630 --> 00:04:10,130
+و ال R initial x initial and y initial معنى الكلام
+
+60
+00:04:10,130 --> 00:04:13,810
+اللي هي ال R هدي موثل عن x و y عند النقطة P إلها
+
+61
+00:04:13,810 --> 00:04:17,130
+إحداثيات x و y initial و عند النقطة Q إلها
+
+62
+00:04:17,130 --> 00:04:22,940
+إحداثيات x و y finalهنا طبعا بمثل هذا الكلام بيه
+
+63
+00:04:22,940 --> 00:04:27,340
+الإزاحة في بعضين الإزاحة في بعضين طبعا Delta R زى
+
+64
+00:04:27,340 --> 00:04:31,100
+ما حكينا هي عبارة عن X and Y هي عبارة عن X and Y
+
+65
+00:04:31,100 --> 00:04:34,360
+الإزاحة طب displacement vector Delta R has
+
+66
+00:04:34,360 --> 00:04:38,120
+component زى ما حكينا Delta R هي عبارة عن مركبتين
+
+67
+00:04:38,120 --> 00:04:42,330
+Delta X and Delta Yfor an object that move from
+
+68
+00:04:42,330 --> 00:04:45,830
+location لو أن الجسم اتحرك من النقطة B لنقطة Q
+
+69
+00:04:45,830 --> 00:04:49,770
+معناها أنه اتحرك من النقطة اللي إحداثياتها X
+
+70
+00:04:49,770 --> 00:04:54,230
+initial وY initial للنقطة اللي إحداثياتها X final
+
+71
+00:04:54,230 --> 00:04:58,710
+لY final in في time interval Delta T في فترة زمنية
+
+72
+00:04:58,710 --> 00:05:00,830
+مقدرها Delta T
+
+73
+00:05:04,240 --> 00:05:07,420
+The X component of the object displacement ال X
+
+74
+00:05:07,420 --> 00:05:11,260
+component بنسميها Delta X اللي هي عبارة عن الإزاحة
+
+75
+00:05:11,260 --> 00:05:14,320
+في اتجاه ال X X final ناقص X initial وال Y
+
+76
+00:05:14,320 --> 00:05:17,620
+component عبارة عن Delta Y هي عبارة عن Y final
+
+77
+00:05:17,620 --> 00:05:23,060
+ناقص Y initial معنى الكلام أنه ال displacement في
+
+78
+00:05:23,060 --> 00:05:27,240
+two dimension في بعضين بسميها Delta R ال Delta R
+
+79
+00:05:27,240 --> 00:05:31,120
+هي عبارة عن two component مركبتين تمثل ب Delta X
+
+80
+00:05:31,120 --> 00:05:35,410
+and Delta Yنجلع تعريف تاني أو مفهوم تاني اللي هو
+
+81
+00:05:35,410 --> 00:05:39,670
+الـ Average Velocity الـ Average Velocity يعني أي
+
+82
+00:05:39,670 --> 00:05:42,810
+جسم an object Average Velocity during time
+
+83
+00:05:42,810 --> 00:05:48,270
+interval ΔT is its displacement divided by ΔT يعني
+
+84
+00:05:48,270 --> 00:05:52,370
+السرعة الاتجاهية المتوسطة لأي جسم خلال فترة زمنية
+
+85
+00:05:52,370 --> 00:05:57,570
+ΔT يعرف بالإزاحة على الزمن لكن عشان إحنا عنا بعدين
+
+86
+00:05:57,570 --> 00:06:03,350
+فالإزاحة هنتمثل بDelta R على Delta Tالـ unit للـ V
+
+87
+00:06:03,350 --> 00:06:06,110
+average الـ unit عبارة عن متر per second اللي
+
+88
+00:06:06,110 --> 00:06:10,010
+عبارة عن متر على الثانية الـ average velocity is
+
+89
+00:06:10,010 --> 00:06:14,410
+the vector quantity directed along Delta R الـ X و
+
+90
+00:06:14,410 --> 00:06:17,030
+Y component of the average velocity are given by
+
+91
+00:06:17,030 --> 00:06:21,330
+طبعا ال average velocity عبارة عن Delta R على
+
+92
+00:06:21,330 --> 00:06:25,670
+Delta T Delta R هي عبارة عن Delta X و Delta Y ممكن
+
+93
+00:06:25,670 --> 00:06:32,110
+نفصلها أن الـ V average باتجاه الـ X كانتDelta X
+
+94
+00:06:32,110 --> 00:06:35,810
+على Delta T والـ V average بالنسبة للـ Y بتساوي
+
+95
+00:06:35,810 --> 00:06:40,330
+Delta Y على Delta T بنلاحظ إنه قيمة اللي هي السرعة
+
+96
+00:06:40,330 --> 00:06:45,650
+الاتجاهية المتوسطة عبارة عن المسافة just the
+
+97
+00:06:45,650 --> 00:06:48,630
+distance between the end point divided by the
+
+98
+00:06:48,630 --> 00:06:52,050
+elapse time المسافة بين نقطة البداية والنهاية
+
+99
+00:06:52,050 --> 00:06:56,210
+وأقصر مسافة بين نقطة البداية والنهاية مقصومة على
+
+100
+00:06:56,210 --> 00:07:00,370
+الزمن الذي طبعا الفترة الزمنية التي استغرقها الجسم
+
+101
+00:07:00,690 --> 00:07:04,550
+عشان يعني يبدأ عشان يعني يمشي او يتحرك مسافة من
+
+102
+00:07:04,550 --> 00:07:08,030
+نقطة البداية لنقطة النهاية Note that the magnitude
+
+103
+00:07:08,030 --> 00:07:11,090
+of the average velocity is just the distance the
+
+104
+00:07:11,090 --> 00:07:16,250
+magnitude قيمة السرعة الإتجاهية المتوسطة هي عبارة
+
+105
+00:07:16,250 --> 00:07:20,370
+عن المسافة distancebetween the end points divided
+
+106
+00:07:20,370 --> 00:07:25,430
+by the elapsed time ال magnitude ال magnitude لل
+
+107
+00:07:25,430 --> 00:07:29,770
+average velocity عبارة عن مسافة على الزمن مسافة
+
+108
+00:07:29,770 --> 00:07:32,810
+على الزمن هي المسافة بين نقطة البداية والنهاية على
+
+109
+00:07:32,810 --> 00:07:37,770
+الزمن هذه بسميها السرعة الاتجاهية المتوسطة وإذا
+
+110
+00:07:37,770 --> 00:07:40,950
+احنا بدنا نجيب اللي هي ال magnitude لل average
+
+111
+00:07:40,950 --> 00:07:44,830
+velocity عبارة عن ال distance المسافة مقصومة على
+
+112
+00:07:44,830 --> 00:07:49,630
+الزمنالـ Instantaneous Velocity عبارة عن السرعة
+
+113
+00:07:49,630 --> 00:07:54,550
+اللحظية، السرعة اللحظية رمزها V عبارة عن limit of
+
+114
+00:07:54,550 --> 00:07:58,310
+its average velocity as ΔT goes to zero، طبعا
+
+115
+00:07:58,310 --> 00:08:01,710
+القانون الرياضي بالنسبة لـ V Instantaneous هو
+
+116
+00:08:01,710 --> 00:08:06,620
+عبارة عن limitDelta R على Delta T عندما Delta T
+
+117
+00:08:06,620 --> 00:08:09,060
+تقول إلى الـ Zero و لا تساوي Zero ولكن تقول إلى
+
+118
+00:08:09,060 --> 00:08:14,420
+الـ Zero فهي تسمى السرعة اللحظية عند زمن معين أو
+
+119
+00:08:14,420 --> 00:08:19,760
+عند لحظة معينة طبعا هذه القيمة ممكن هي تعتبر مشتقة
+
+120
+00:08:19,760 --> 00:08:24,720
+الـ R بالنسبة للـ T أو هي عبارة عن slope of the
+
+121
+00:08:24,720 --> 00:08:29,560
+line tangent هو عبارة عن ميل المماس عن تلك النقطة
+
+122
+00:08:29,890 --> 00:08:34,910
+طبعا سنوضحه في الشكل القادم عبارة عن ميل المماس
+
+123
+00:08:34,910 --> 00:08:38,150
+يتسمى اللي هي ال instantaneous velocity أو السرعة
+
+124
+00:08:38,150 --> 00:08:42,070
+اللحظية ان تلك اللحظة لو كان عندي انا معادلة
+
+125
+00:08:42,070 --> 00:08:45,970
+فالسرعة اللحظية هي عبارة عن مشتقة المسافة بالنسبة
+
+126
+00:08:45,970 --> 00:08:50,570
+للزمن لو كان عندي انا منحنة او curve فهي عبارة عن
+
+127
+00:08:50,570 --> 00:08:56,550
+ميل اللي هي المماس ان تلك النقطة وحدتها اللي هي
+
+128
+00:08:56,550 --> 00:08:58,550
+meter per second meter على second
+
+129
+00:09:08,370 --> 00:09:15,550
+التجاه السرعة اللحظية المتجهة خلال طبعا الخط خط
+
+130
+00:09:15,550 --> 00:09:20,650
+المماس لهذا الجسم and in the direction of its
+
+131
+00:09:20,650 --> 00:09:25,790
+motion هو خط المماس لحركة ال particle خلال هذا ال
+
+132
+00:09:25,790 --> 00:09:30,580
+curve أو هذا المنحنىمفهوم آخر average acceleration
+
+133
+00:09:30,580 --> 00:09:34,800
+ال average acceleration هي عبارة عن اللي هي معدل
+
+134
+00:09:34,800 --> 00:09:39,960
+اللي هي التغير في السرع على الزمن يعني طبعا هي ال
+
+135
+00:09:39,960 --> 00:09:45,230
+average acceleration متوسط التسارععبارة عن during
+
+136
+00:09:45,230 --> 00:09:48,670
+the time interval خلال فترة زمنية Delta T عبارة عن
+
+137
+00:09:48,670 --> 00:09:52,670
+الـ change التغير in its velocity التغير في السرعة
+
+138
+00:09:52,670 --> 00:09:56,790
+Delta V Delta V هي عبارة عن V final ناقص V initial
+
+139
+00:09:56,790 --> 00:10:02,210
+divided by Delta Tمقصومة على التغير في الزمان هذا
+
+140
+00:10:02,210 --> 00:10:07,790
+بيسموها average acceleration اللي هو التسارع متوسط
+
+141
+00:10:07,790 --> 00:10:12,950
+التسارع متوسط التسارع بيساوي Delta V على Delta T و
+
+142
+00:10:12,950 --> 00:10:17,540
+اللي هي وحدة في النظام الدوليsystem international
+
+143
+00:10:17,540 --> 00:10:21,840
+unit عبارة عن متر per second squared يعني متر فترة
+
+144
+00:10:21,840 --> 00:10:25,780
+على ثانية تربيع ال average acceleration has
+
+145
+00:10:25,780 --> 00:10:30,500
+component given by طبعا ال delta V على delta T لو
+
+146
+00:10:30,500 --> 00:10:35,100
+كان عندي أنا بتكلم في two dimensions فال A average
+
+147
+00:10:35,100 --> 00:10:40,300
+في اتجاه ال X بدها تساوي delta VX على delta T
+
+148
+00:10:40,300 --> 00:10:44,670
+اتجاه ال X andالـ A average بتجاه الـ Y بتساوي
+
+149
+00:10:44,670 --> 00:10:48,770
+Delta VY على Delta T يعني الـ V هاي ببدي أنا
+
+150
+00:10:48,770 --> 00:10:53,570
+أفصلها إلى مراكبتين Delta VX على Delta T و Delta
+
+151
+00:10:53,570 --> 00:10:57,090
+VY على Delta T اللي هي عبارة عن الـ two components
+
+152
+00:10:57,090 --> 00:11:04,860
+اللي هي مراكبة اللي هي السرعةVx and Vyr X and Y
+
+153
+00:11:04,860 --> 00:11:09,240
+component مركبات السرعة .. مركبات متجه السرعة
+
+154
+00:11:09,240 --> 00:11:15,360
+بالنسبة لاتجاه ال X واتجاه ال Y بالنسبة لمفهوم
+
+155
+00:11:15,360 --> 00:11:19,160
+instantaneous acceleration طبعا an object
+
+156
+00:11:19,160 --> 00:11:22,950
+instantaneous acceleration التسارع اللحظيالتسارع
+
+157
+00:11:22,950 --> 00:11:26,870
+اللحظي رمزه A is the limit of its average
+
+158
+00:11:26,870 --> 00:11:31,110
+acceleration vector as ΔT goes to 0 وهي عبارة عن
+
+159
+00:11:31,110 --> 00:11:41,170
+المتوسط التسارع المتجه التسارع عندما ΔT تقول إلى
+
+160
+00:11:41,170 --> 00:11:49,490
+الـ0 أو هي عبارة عن مشتقة الـV بالنسبة للـT
+
+161
+00:11:52,040 --> 00:11:55,260
+الوحدة اللي هي التسارع برضه meter per second
+
+162
+00:11:55,260 --> 00:11:58,940
+square أو meter في الثانية تربيع يعني وحدة التسارع
+
+163
+00:11:58,940 --> 00:12:04,060
+متوسط التسارع هو نفس وحدة وحدة السرع التسارع
+
+164
+00:12:04,060 --> 00:12:09,610
+اللحظةAn object can accelerate in several ways أي
+
+165
+00:12:09,610 --> 00:12:14,550
+جسم ممكن يتسرع بأكتر من طريقة The magnitude of the
+
+166
+00:12:14,550 --> 00:12:18,110
+velocity vector may change with time لو كان عندي
+
+167
+00:12:18,110 --> 00:12:25,150
+أنا تغير في السرعة بالنسبة للزمن أو لو أنا عندي
+
+168
+00:12:25,150 --> 00:12:31,790
+the magnitude of the vector of the speed may be
+
+169
+00:12:31,790 --> 00:12:35,260
+أيضا may change with time بيصير عندى تسارعThe
+
+170
+00:12:35,260 --> 00:12:38,060
+direction of the velocity vector may change with
+
+171
+00:12:38,060 --> 00:12:45,140
+time اتجاه السرعة ممكن يتغير مع الزمن even though
+
+172
+00:12:45,140 --> 00:12:48,800
+the speed is constant في هذه الحالة ال speed يعني
+
+173
+00:12:48,800 --> 00:12:52,820
+قيمة السرعة مقدار ثابتboth the magnitude and the
+
+174
+00:12:52,820 --> 00:12:55,480
+direction of the velocity vector may change at the
+
+175
+00:12:55,480 --> 00:13:01,360
+same time ممكن قيمة السرعة واتجاهها ممكن تتغير
+
+176
+00:13:01,360 --> 00:13:08,680
+بنفس الاداسي بنفس الزمن ناخد quiz تلاتة واحدwhich
+
+177
+00:13:08,680 --> 00:13:13,280
+of the following objects can't be accelerating مين
+
+178
+00:13:13,280 --> 00:13:17,020
+من هذه الجمال بالنسبة لأي جسم can't be
+
+179
+00:13:17,020 --> 00:13:21,520
+accelerating يعني ما بتتسرع يعني نشوف الأول an
+
+180
+00:13:21,520 --> 00:13:25,660
+object moving with constant speed إذا اتحرك ب
+
+181
+00:13:25,660 --> 00:13:30,000
+constant speed يعني ال magnitude لل speed ثابتة
+
+182
+00:13:30,000 --> 00:13:34,340
+معنى الكلام التغيرفي ال speed هيكون سفر وبالتالي
+
+183
+00:13:34,340 --> 00:13:37,420
+مافيش تسارع فالتسارع بيساوي zero لإنه التسارع
+
+184
+00:13:37,420 --> 00:13:43,540
+بيساوي التغير بالسرعة على التغير في الزمن في be an
+
+185
+00:13:43,540 --> 00:13:47,360
+object moving with constant velocity with constant
+
+186
+00:13:47,360 --> 00:13:53,680
+velocity هذه مظبوطة لإنه اتجاه السرعة ممكن يتغيرor
+
+187
+00:13:53,680 --> 00:13:57,860
+and the object moving along a curve الآن السؤال
+
+188
+00:13:57,860 --> 00:14:01,060
+which of the following object can't can't be
+
+189
+00:14:01,060 --> 00:14:05,240
+accelerated يعني مين من هدول الجمال لا يحدث لها
+
+190
+00:14:05,240 --> 00:14:10,360
+تسارع لا يحدث لها تسارع هلاقيتها الآن object
+
+191
+00:14:10,360 --> 00:14:14,960
+moving with constant speed ما بيصير تسارع if you
+
+192
+00:14:14,960 --> 00:14:21,950
+see an object moving along a curveبصير بصير عندي
+
+193
+00:14:21,950 --> 00:14:25,410
+أنا تسارع لكن في بيه an object moving with
+
+194
+00:14:25,410 --> 00:14:29,070
+constant velocity هنا ما بيصير في عندي أنا ايه
+
+195
+00:14:29,070 --> 00:14:33,990
+تسارع ما بيصير تسارع لإنه delta V بتساوي zero في
+
+196
+00:14:33,990 --> 00:14:39,510
+هذه الحالةالـ quiz تلاتة تلات اتنين consider the
+
+197
+00:14:39,510 --> 00:14:43,630
+following control in an automobile, gas, pedal,
+
+198
+00:14:43,970 --> 00:14:48,090
+brake, steering, wheel بأفرض انا في عندى انا عشان
+
+199
+00:14:48,090 --> 00:14:52,330
+اتحكم في اي سيارة ممكن اتحكم في السيارة بال ..
+
+200
+00:14:52,330 --> 00:14:56,110
+ممكن اتحكم بالسيارة بالجاز يعني بنزين ده ادعس
+
+201
+00:14:56,110 --> 00:15:00,550
+بنزين او ال brake او ال steeringthe control in
+
+202
+00:15:00,550 --> 00:15:04,990
+this list that can cause an acceleration can cause
+
+203
+00:15:04,990 --> 00:15:12,030
+of acceleration of the .. can acceleration of عفوا
+
+204
+00:15:12,030 --> 00:15:15,910
+مين
+
+205
+00:15:15,910 --> 00:15:19,870
+من هدول الجمال can acceleration of the car هل
+
+206
+00:15:19,870 --> 00:15:23,670
+السيارة بتتسرع لما أنا أحرك ال steering؟ هل
+
+207
+00:15:23,670 --> 00:15:27,270
+السيارة بتتسرع لما أضرب break؟ هل السيارة بتتسرع
+
+208
+00:15:27,270 --> 00:15:28,630
+لما أدعس بنزين؟
+
+209
+00:15:31,760 --> 00:15:34,920
+طبعا less that can cause acceleration of the car
+
+210
+00:15:34,920 --> 00:15:39,520
+نمرأ ايه؟ All three controls ولا the gas بيدال and
+
+211
+00:15:39,520 --> 00:15:44,140
+the brake ولا only the brake ولا only the gas هل
+
+212
+00:15:44,140 --> 00:15:47,900
+consider the following control in the اوتومبيل
+
+213
+00:15:47,900 --> 00:15:52,520
+مين؟من الموجودين بتحكموا بالسيارة طبعا اللي بتحكم
+
+214
+00:15:52,520 --> 00:15:56,580
+بالسيارة اللي هو ال .. ال .. ده .. ده اسة البنزين
+
+215
+00:15:56,580 --> 00:15:59,180
+و ال brake و ال steering هدول التلاتة هم اللي
+
+216
+00:15:59,180 --> 00:16:03,520
+بتحكموا بالسيارة فمعنى الكلام اللي هي ال all three
+
+217
+00:16:03,520 --> 00:16:07,660
+controls all three controls ممكن تحكمهم بالسيارة
+
+218
+00:16:07,660 --> 00:16:12,720
+مش واحدة لحالةdistinction between average velocity
+
+219
+00:16:12,720 --> 00:16:16,340
+and average speed remains important for two
+
+220
+00:16:16,340 --> 00:16:20,440
+-dimensional بده فرق بين ال average velocity و ال
+
+221
+00:16:20,440 --> 00:16:24,760
+average speed طبعا في ال two dimensions في ال
+
+222
+00:16:24,760 --> 00:16:28,620
+figure تلاتة تلاتة shows woman jogging along the
+
+223
+00:16:28,620 --> 00:16:33,880
+rectangular periphery of a small green spacegoing
+
+224
+00:16:33,880 --> 00:16:40,460
+from point A to point B طبعا في هناك بنت بتتحرك في
+
+225
+00:16:40,460 --> 00:16:44,380
+هذا الاتجاه في هذا الاتجاه في مزرعة أو مكان فيه
+
+226
+00:16:44,380 --> 00:16:47,920
+طبعا زرع فهي اتحركت في هذا الاتجاه من النقطة A و
+
+227
+00:16:47,920 --> 00:16:51,360
+راحت لنقطة A مشيت هذا المسار من النقطة A و راحت
+
+228
+00:16:51,360 --> 00:16:56,120
+لنقطة B في هذا المسار مشيت من النقطة A و راحت
+
+229
+00:16:56,120 --> 00:17:01,230
+لنقطة B في هذا المسارالان بدنا افرق بين .. بدنا
+
+230
+00:17:01,230 --> 00:17:05,710
+نفرق بين اللى هى ال .. ال average velocity و ال
+
+231
+00:17:05,710 --> 00:17:09,330
+average speed زى ما عشان عارفين الشكل هى البنت
+
+232
+00:17:09,330 --> 00:17:14,870
+مشيت من النقطة A وصلت للنقطة B خلال هذا المسار حول
+
+233
+00:17:14,870 --> 00:17:21,040
+مزرعة .. مزرعة حشيش أو مزرعة أشجارالسؤال .. السؤال
+
+234
+00:17:21,040 --> 00:17:25,320
+في هذا الشكل بيحكي ليه؟ بدنا ال average speed و ال
+
+235
+00:17:25,320 --> 00:17:29,100
+average acceleration الآن ال average speed هي
+
+236
+00:17:29,100 --> 00:17:33,920
+عبارة عن distance على time عبارة عن distance على
+
+237
+00:17:33,920 --> 00:17:38,340
+time فالمسافة الكلية اللي هي مشيتها هي التلاتين
+
+238
+00:17:38,340 --> 00:17:42,190
+زائد أربعين هي المسار الفعليال actual path هي
+
+239
+00:17:42,190 --> 00:17:44,870
+المسار الفعل اللى مشيته من تلاتين و أربعين هذا
+
+240
+00:17:44,870 --> 00:17:48,750
+بسميها distance عشان أوجد ال average speed بحكي ال
+
+241
+00:17:48,750 --> 00:17:52,470
+distance على ال time طبعا مشيت الفترة خلال فترة
+
+242
+00:17:52,470 --> 00:17:56,970
+زمنية عشرين ثانية فبنجيبها اللى هى تلاتين زائد
+
+243
+00:17:56,970 --> 00:18:00,310
+أربعين على عشرين تطلع تلاتة و نص متر في الثانية
+
+244
+00:18:00,310 --> 00:18:04,510
+لما أوجد ال average ال average velocity ال
+
+245
+00:18:04,510 --> 00:18:09,350
+velocity هي عبارة عن ده طبعاال average velocity
+
+246
+00:18:09,350 --> 00:18:13,150
+عبارة عن displacement على الزمن الإزاحة .. الإزاحة
+
+247
+00:18:13,150 --> 00:18:17,830
+هي أقصر مسافة بين نقطة البداية للنهاية فمن النقطة
+
+248
+00:18:17,830 --> 00:18:21,430
+إيه للنقطة بيها دي اسمها إزاحة كيف أجيبها؟ عندي
+
+249
+00:18:21,430 --> 00:18:25,550
+هنا تلاتين وهنا أربعين باستخدم نظرية في ثغو .. في
+
+250
+00:18:25,550 --> 00:18:29,470
+ثغورت فديها دي هي عبارة عن جزر تلاتين تربيع زي ده
+
+251
+00:18:29,470 --> 00:18:34,770
+اربعين تربيع بتطلع خمسين emeter وبالتاليفال
+
+252
+00:18:34,770 --> 00:18:38,950
+average velocity عبارة عن إزاحة على زمان هي عبارة
+
+253
+00:18:38,950 --> 00:18:42,950
+عن خمسين على عشرين بتساوي اتنين و نص فال average
+
+254
+00:18:42,950 --> 00:18:47,150
+speed بتختلف عن ال average velocity average speed
+
+255
+00:18:47,150 --> 00:18:51,210
+بتختلف عن ال average velocity لو أجيت أنا ل quiz
+
+256
+00:18:51,210 --> 00:18:55,530
+تانيa girl in a bicycle takes 15 seconds فى عندى
+
+257
+00:18:55,530 --> 00:19:03,570
+بنت اتحركت فى bicycle دراجة خلال 15 ثانية to ride
+
+258
+00:19:03,570 --> 00:19:07,930
+half away around circular track هى طبعا اتحركت
+
+259
+00:19:07,930 --> 00:19:14,490
+بمسار نصف دائرةof radius عشرة what is the girl
+
+260
+00:19:14,490 --> 00:19:17,650
+average speed؟ بدأ أوجد ال average speed what is
+
+261
+00:19:17,650 --> 00:19:21,230
+the magnitude of average velocity؟ طبعا لإيجاد ال
+
+262
+00:19:21,230 --> 00:19:25,670
+average speed هي عبارة عن المسافة على الزمن
+
+263
+00:19:25,670 --> 00:19:29,490
+المسافة الفعلية المشيتة هي عبارة عن نص دائرةمحيط
+
+264
+00:19:29,490 --> 00:19:34,290
+الدائرة 2 by R إذا نص الدائرة هذه اللي هي by R
+
+265
+00:19:34,290 --> 00:19:38,250
+اللي هي اللي هي المسافة اللي مشيتها على الزمن 15
+
+266
+00:19:38,250 --> 00:19:43,250
+ال by عوضنا عنها 3.14×10
+
+267
+00:19:43,250 --> 00:19:48,810
+اللي هي نص الخطر اللي هي by R على 15 لإن المحيط
+
+268
+00:19:48,810 --> 00:19:54,850
+عبارة عن 2 by R هي مشيت فعليا نص المحيط اللي هي by
+
+269
+00:19:54,850 --> 00:19:59,710
+R على 15 بطلع 2.09 متر في الثانيةبالنسبة لل
+
+270
+00:19:59,710 --> 00:20:04,290
+average velocity هي عبارة عن الإزاحة على الزمن
+
+271
+00:20:04,290 --> 00:20:08,250
+الإزاحة هي أقصر مسافة من نقطة البداية لنقطة
+
+272
+00:20:08,250 --> 00:20:12,230
+النهاية يعني المسافة من ال T0 ل T15 هذه المسافة
+
+273
+00:20:12,230 --> 00:20:17,410
+عشرة زائد عشرة يعني اشرين على خمستاشر تطلع واحد
+
+274
+00:20:17,410 --> 00:20:23,450
+point تلاتة تلاتة متر في الثانية طبعا ال two
+
+275
+00:20:23,450 --> 00:20:29,220
+dimensional motionالحركة في بعدين في .. في هذا ال
+
+276
+00:20:29,220 --> 00:20:33,080
+section we look at object that move in both X and
+
+277
+00:20:33,080 --> 00:20:36,820
+Y direction الآن في هذا ال section نتكلم عن حركة
+
+278
+00:20:36,820 --> 00:20:41,260
+المخضفات حركة المخضفات راح تتعامل مع الحركة باتجاه
+
+279
+00:20:41,260 --> 00:20:44,820
+X والحركة باتجاه Y طبعا under constant
+
+280
+00:20:44,820 --> 00:20:49,870
+acceleration تحت أثير تسارع ثابتan important
+
+281
+00:20:49,870 --> 00:20:52,410
+special case of this two-dimensional motion is
+
+282
+00:20:52,410 --> 00:20:57,370
+called projectile motion اللي هي حركة المقضوفات
+
+283
+00:20:57,370 --> 00:21:03,070
+كيعني ك special case حالة خاصةanyone who .. who
+
+284
+00:21:03,070 --> 00:21:07,410
+has tossed any kind of object into an air to the
+
+285
+00:21:07,410 --> 00:21:11,470
+air has observed object object motion أي جسم ممكن
+
+286
+00:21:11,470 --> 00:21:16,510
+أرميه في ال .. في الهواء وينزل على الأرض ممكن
+
+287
+00:21:16,510 --> 00:21:20,570
+أسميه بتحرك حركة مقضوفة if the effect of air
+
+288
+00:21:20,570 --> 00:21:23,310
+resistance and the rotation of earth are neglected
+
+289
+00:21:23,310 --> 00:21:27,410
+طبعا .. طبعا في هذه ال section أو في هذا الموضوع
+
+290
+00:21:27,410 --> 00:21:32,720
+نهملاللي هي مقاومة الهواء ونهمل دوران الأرض The
+
+291
+00:21:32,720 --> 00:21:35,800
+path of the projectile in earth's gravity field is
+
+292
+00:21:35,800 --> 00:21:39,400
+curved in the shape of the parabola حركة المقذوفة
+
+293
+00:21:39,400 --> 00:21:44,380
+على سطح الأرض هي حركة قطع ناقص البرابولا كما هو
+
+294
+00:21:44,380 --> 00:21:48,920
+بالشكل الحركة بهذا الشكل هي حركة المقذوفة لو أنا
+
+295
+00:21:48,920 --> 00:21:51,940
+بدأت من هذه المنطقة ورميت الجسم بحركة أو بسرعة
+
+296
+00:21:51,940 --> 00:21:57,680
+اسمها V naught مائلة على الأفق θ نوتطبعا هيكون
+
+297
+00:21:57,680 --> 00:22:01,940
+عندي انا مركبتين لل V هي عبارة عن V not X و V not
+
+298
+00:22:01,940 --> 00:22:05,500
+Y هذه عبارة عن المركبة الصينية للسرعة الابتدائية
+
+299
+00:22:05,500 --> 00:22:10,080
+وهذه المركبة الصادية للسرعة الابتدائية لو مشيت على
+
+300
+00:22:10,080 --> 00:22:14,390
+المنحنة من منطقة هذهطبعا هنا ال V اتغيرت عن ال V
+
+301
+00:22:14,390 --> 00:22:18,910
+naught صار عندى انا V naught X هنا V Y بنلاحظ على
+
+302
+00:22:18,910 --> 00:22:24,050
+طول مسار المخضوفة انه السرعة الابتدائية السرعة
+
+303
+00:22:24,050 --> 00:22:27,450
+الابتدائية في كل نقطة متساوية اللى هى عبارة عن V
+
+304
+00:22:27,450 --> 00:22:30,930
+naught X تساوى السرعة النهائية عند كل .. عند كل
+
+305
+00:22:30,930 --> 00:22:34,880
+نقطة على مسار المخضوفةفي هذه النقطة and هذه
+
+306
+00:22:34,880 --> 00:22:38,780
+المنطقة the y component of the velocity is zero at
+
+307
+00:22:38,780 --> 00:22:44,700
+the peak of the path اعلى and اقصى ارتفاع او اعلى
+
+308
+00:22:44,700 --> 00:22:49,960
+قمة في المقضوفة السرعة باتجاه ال y تساوى سفر لكن
+
+309
+00:22:49,960 --> 00:22:54,120
+السرعة باتجاه ال x هي نفسها بالسرعة اللي هي v
+
+310
+00:22:54,120 --> 00:22:58,510
+naught xفي المنطقة هذه المنطقة the x components of
+
+311
+00:22:58,510 --> 00:23:01,990
+the list remain constant in time في كل مسار
+
+312
+00:23:01,990 --> 00:23:07,690
+المقضوفة ال V النهائية لل X هي نفسها V not X
+
+313
+00:23:07,690 --> 00:23:12,270
+بنستكمل المرة اللي طبعا المحاضرة القادمة بعرض بعض
+
+314
+00:23:12,270 --> 00:23:13,870
+المسائل الخاصة بالمقضوفة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo.srt
new file mode 100644
index 0000000000000000000000000000000000000000..e28493b211c7fd9b4e23f6213af02bdb89a31e50
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo.srt
@@ -0,0 +1,799 @@
+1
+00:00:00,390 --> 00:00:05,290
+بسم الله الرحمن الرحيم، هنبدأ بحل إن شاء الله بعض
+
+2
+00:00:05,290 --> 00:00:11,430
+اللي هي الأمثلة ككويزات، كويز ستة، أربعة، an
+
+3
+00:00:11,430 --> 00:00:15,270
+object of mass m move to the right، في عندنا جسم
+
+4
+00:00:15,270 --> 00:00:20,350
+كتلته m، بتحرك ناحية اليمين بسرعة v، الآن اصطدم، it
+
+5
+00:00:20,350 --> 00:00:24,510
+collides head-on with an object of mass ثلاثة m
+
+6
+00:00:24,510 --> 00:00:29,080
+moving with speed v على ثلاثة، الآن جسم كتلته m بتحرك
+
+7
+00:00:29,080 --> 00:00:33,740
+بسرعة v، بتحرك ناحية اليمين، وجسم كتلته ثلاثة m
+
+8
+00:00:33,740 --> 00:00:38,040
+بتحرك بسرعة v على ثلاثة، بتحرك ناحية اليسار، if
+
+9
+00:00:38,040 --> 00:00:42,360
+the two objects stick together، خبطوا في بعض ومشيوا
+
+10
+00:00:42,360 --> 00:00:49,040
+بعد التصادم، be combined كجسم واحد، بكتلة طبعا أربعة
+
+11
+00:00:49,040 --> 00:00:53,920
+m، لأن الأول كتلته m والثانية ثلاثة m، فمجموعهم أربعة m، بعد
+
+12
+00:00:53,920 --> 00:00:57,500
+التصادم، after the collision، بعد التصادم
+
+13
+00:01:00,210 --> 00:01:06,870
+after the collision، صفر، ولا v على 2، ولا v، ولا 2v
+
+14
+00:01:06,870 --> 00:01:10,670
+اللي هي السرعة النهائية بعد ما صار جسم واحد، مطلوب
+
+15
+00:01:10,670 --> 00:01:14,330
+what is the speed of the combined object after the
+
+16
+00:01:14,330 --> 00:01:18,350
+collision؟ سرعتهم بعد التصادم، طبعا الجواب A اللي هو
+
+17
+00:01:18,350 --> 00:01:23,670
+صفر، لإنه لما آجي أحسب m1 في v1 زائد m2 في v2، m1 في
+
+18
+00:01:23,670 --> 00:01:28,750
+m، وm2 في v، m في v زائد أو هي ناقص لإنه بتجاه
+
+19
+00:01:28,750 --> 00:01:32,110
+المعاكس، of the direction v على ثلاثة مضروبة في ثلاثة m
+
+20
+00:01:32,110 --> 00:01:35,150
+بيطلع ناقص v، بيطلع الجواب صفر، لإنه فعلا السرعة
+
+21
+00:01:35,150 --> 00:01:41,530
+النهائية بتساوي صفر، بتطبيق اللي هي قانون perfect
+
+22
+00:01:41,530 --> 00:01:45,770
+inelastic، وكانوا الإثنين باتجاهين مختلفين، فبيطلع
+
+23
+00:01:45,770 --> 00:01:54,050
+المحصلة، السرعة النهائية بتساوي صفر، quiz 565 skater
+
+24
+00:01:54,050 --> 00:02:00,410
+is using very low friction roller، طبعا plates، في
+
+25
+00:02:00,410 --> 00:02:06,530
+عندي متزلجة بتتحرك على سطح طبعا أملس، ما فيش
+
+26
+00:02:06,530 --> 00:02:11,930
+friction، ضعيف، friend of، في أحد أصدقائها رمى لها طبق
+
+27
+00:02:11,930 --> 00:02:16,150
+الطائر، عشان تمسكه، رمى لها طبعا بخط مستقيم، وهي
+
+28
+00:02:16,150 --> 00:02:21,030
+بتتزلج، along what she is coasting، كيف هي ممكن أن تمسكه؟
+
+29
+00:02:21,030 --> 00:02:24,470
+تمسكه؟ describe each of the following events as an
+
+30
+00:02:24,470 --> 00:02:27,930
+elastic or an inelastic or perfect inelastic، كل
+
+31
+00:02:27,930 --> 00:02:33,310
+جديد، الآن، متزلجة سيدة بتتزلج على جليد، أو بالسكيت
+
+32
+00:02:33,310 --> 00:02:39,610
+بتتحرك، الـ friction طبعا قليل، في شاب أو طبعا صديق
+
+33
+00:02:39,610 --> 00:02:44,370
+رمى لها طبق الطائر بخط مستقيم، طبعا هيعطينا حالات
+
+34
+00:02:44,370 --> 00:02:48,170
+من ضمن هذه الحالات، بدنا نحدد هل التصادم اللي صار
+
+35
+00:02:48,170 --> 00:02:54,250
+بين السيدة والطبق، هل هو elastic ولا inelastic ولا
+
+36
+00:02:54,250 --> 00:02:59,730
+perfect؟ الآن، she catch، في الحالة الأولى، she catch
+
+37
+00:02:59,730 --> 00:03:06,130
+the frisbee and holds it، طبعا هي مسكت الطبق و
+
+38
+00:03:06,130 --> 00:03:11,010
+مسكته، والتصادم فيه، فده الحالة، في الأول، الحالة لما
+
+39
+00:03:11,010 --> 00:03:15,630
+هي، التصادم صار perfect inelastic، كأنه كأنهم جسم
+
+40
+00:03:15,630 --> 00:03:19,290
+واحد، صاروا، هي مسكته، وصاروا جسم واحد، في الحالة
+
+41
+00:03:19,290 --> 00:03:23,510
+الثانية طبعا هي حاولت، she tries to catch the
+
+42
+00:03:23,510 --> 00:03:30,400
+frisbee، بحاولة تمسك الطبق لكن، bounced off، ارتد منها
+
+43
+00:03:30,400 --> 00:03:38,160
+وقع على الأرض، هذا بسميه inelastic، يعني غير مرن
+
+44
+00:03:41,250 --> 00:03:45,170
+في الحالة c، هي… she catch the frisbee and
+
+45
+00:03:45,170 --> 00:03:50,750
+immediately throw، يعني مسكتها ورجعتها ثاني بنفس…
+
+46
+00:03:50,750 --> 00:03:56,110
+بسرعة… بسرعة، يعني هي… يعني يعتبر كأنه elastic، كل
+
+47
+00:03:56,110 --> 00:04:01,650
+شيء يعتبر كأنه elastic، على أساس أنه تصادم بين جسمين
+
+48
+00:04:04,850 --> 00:04:08,930
+النوع الأول اللي هو perfect inelastic، any
+
+49
+00:04:08,930 --> 00:04:11,430
+collision in which the two objects stick together
+
+50
+00:04:11,430 --> 00:04:15,090
+afterward is perfect inelastic، النوع الثاني هنا
+
+51
+00:04:15,090 --> 00:04:20,330
+perfect inelastic، النوع الثاني inelastic، هي مسكته
+
+52
+00:04:20,330 --> 00:04:26,110
+وبعدين هي نزل منها على الأرض، يعني هنا انمسك لكن
+
+53
+00:04:26,110 --> 00:04:30,010
+اسمه inelastic، هنا يبدو فيه خطأ في inelastic، لأنها
+
+54
+00:04:30,010 --> 00:04:35,250
+مسكته ورمته بنفس اللحظة، فبسميه طبعا elastic
+
+55
+00:04:35,250 --> 00:04:39,350
+collision، تصادم مرن، if the total kinetic energy
+
+56
+00:04:39,350 --> 00:04:40,870
+of the system is not conserved
+
+57
+00:04:51,870 --> 00:05:00,570
+Quick quiz 6.6 perfectly inelastic one dimension
+
+58
+00:05:00,570 --> 00:05:07,210
+في التصادم الغير مرن، between two objects، what
+
+59
+00:05:07,210 --> 00:05:11,730
+initial condition alone is necessary so that all
+
+60
+00:05:11,730 --> 00:05:16,270
+of the original kinetic energy of the system is
+
+61
+00:05:16,270 --> 00:05:20,520
+gone after the collision، بالنسبة للـ perfect
+
+62
+00:05:20,520 --> 00:05:23,440
+inelastic، عديم المرونة، في اتجاه واحد، أو في بعد
+
+63
+00:05:23,440 --> 00:05:27,740
+واحد، أو تصادم من جسمين عديم المرونة، what initial
+
+64
+00:05:27,740 --> 00:05:32,700
+condition؟ ما هو الشرط المبدأي الأولاني اللي هو
+
+65
+00:05:32,700 --> 00:05:39,700
+الخاص ب… بدنا الشرط الأساسي، condition alone
+
+66
+00:05:39,700 --> 00:05:44,160
+الوحيد الضروري، so that all of the original kinetic
+
+67
+00:05:44,160 --> 00:05:47,070
+energy of the system is gone after the collision، اللي
+
+68
+00:05:47,070 --> 00:05:52,290
+بيخلي أنه في عندي فقد أو يعني تشتيت لطاقة الحركة
+
+69
+00:05:52,290 --> 00:05:56,750
+طبعا الشرط الأساسي، هل هو: the object must have
+
+70
+00:05:56,750 --> 00:05:59,070
+momentum with the same magnitude but opposite
+
+71
+00:05:59,070 --> 00:06:03,350
+direction، أو the object، هل أن الجسم must have the
+
+72
+00:06:03,350 --> 00:06:06,550
+same mass، أو the same velocity، أو the same، اللي هو
+
+73
+00:06:06,550 --> 00:06:13,170
+speed؟ فالحل الصحيح، أنه الشرط الوحيد عشان أنا يعني
+
+74
+00:06:13,170 --> 00:06:17,530
+يكون عندنا فقد في الطاقة، هو the objects، الأجسام
+
+75
+00:06:17,530 --> 00:06:22,450
+هذه لها نفس كمية التحرك، نفس المقدار، ومعاكسة في
+
+76
+00:06:22,450 --> 00:06:26,490
+الاتجاه،  نِجلّة
+
+77
+00:06:26,490 --> 00:06:31,390
+الـ elastic collision، the elastic collision now
+
+78
+00:06:31,390 --> 00:06:35,590
+consider two objects that undergoes an elastic
+
+79
+00:06:35,590 --> 00:06:40,770
+head-on collision، in this situation both the
+
+80
+00:06:40,770 --> 00:06:43,670
+momentum and the kinetic energy of the system of
+
+81
+00:06:43,670 --> 00:06:49,010
+two objects are conserved، في النسبة للـ elastic
+
+82
+00:06:49,010 --> 00:06:52,730
+collision، هنا نيجي للـ elastic collision، بيحكي لنا
+
+83
+00:06:52,730 --> 00:06:59,150
+بدأ، أفرض في عندي أنا elastic، يعني مرن، المرّن طبعاً
+
+84
+00:06:59,150 --> 00:07:05,890
+كل جسم بعد التصادم يروح بسرعة معينة، في المرّن كمية
+
+85
+00:07:05,890 --> 00:07:10,310
+التحرك محفوظة، وطاقة الحركة محفوظة، وده system
+
+86
+00:07:10,310 --> 00:07:14,470
+معروفة، كمية التحرك محفوظة لجميع، في الـ elastic ولا
+
+87
+00:07:14,470 --> 00:07:19,030
+الـ inelastic، الآن، هنا جسمين، الجسم الأول، أو واحد
+
+88
+00:07:19,030 --> 00:07:22,550
+بتحرك بسرعة v1 initial، والسرعة الجسم الثاني
+
+89
+00:07:23,830 --> 00:07:28,210
+m2 بتحرك بسرعة v2 initial، before، طبعا هذا
+
+90
+00:07:28,210 --> 00:07:32,730
+before the collision، نيجي لتاني، بعد التصادم، اصطدم
+
+91
+00:07:32,730 --> 00:07:38,370
+بعد التصادم الأولاني طبعا انطلق بسرعة v1 final، و
+
+92
+00:07:38,370 --> 00:07:41,750
+انطلق بسرعة v2 final، after the collision، the
+
+93
+00:07:41,750 --> 00:07:45,510
+object velocity it changed، اتغيرت، but both the
+
+94
+00:07:45,510 --> 00:07:49,090
+energy and momentum of the system are conserved، في
+
+95
+00:07:49,090 --> 00:07:52,310
+هذه الحالة، الـ momentum conserved، وطاقة الحركة is
+
+96
+00:07:52,310 --> 00:07:58,500
+conserved، we can write these conditions as، الآن في
+
+97
+00:07:58,500 --> 00:08:03,340
+عندي m1 v1 initial، و m2 v2 initial، بتساوي m1 v1
+
+98
+00:08:03,340 --> 00:08:08,560
+final زائد m2 v2 final، هذا بالنسبة لقانون كمية
+
+99
+00:08:08,560 --> 00:08:13,040
+التحرك، أساس أنها محفوظة، وبستخدم قانون اللي هي
+
+100
+00:08:13,040 --> 00:08:19,500
+الطاقة الحركية، where v is positive، طبعا في هذا
+
+101
+00:08:19,500 --> 00:08:22,800
+الحالة، if an object move to the right، نعتبر أنه
+
+102
+00:08:22,800 --> 00:08:26,500
+السرعة موجبة، بقى إذا اتحرك الجسم لليمين، والسرعة
+
+103
+00:08:26,500 --> 00:08:30,420
+سالبة، بقى إذا اتحرك إلى اليسار، cancelling، بالنسبة
+
+104
+00:08:30,420 --> 00:08:36,240
+للتانية طبعاً بضيع، الإشارات بضيع الإشارات من المعادلة
+
+105
+00:08:36,240 --> 00:08:42,080
+بعدين باخد الـ m1 مشترك، هي الـ m1، باخد هذا الحد مع
+
+106
+00:08:42,080 --> 00:08:45,640
+هذا الحد، يجي من ناحية ثانية، بيصير سالب m1 v1
+
+107
+00:08:45,640 --> 00:08:50,580
+initial تربيع ناقص m1 v1 final تربيع ناقص m2، هنا
+
+108
+00:08:50,580 --> 00:08:55,900
+جبناها ناحية الثانية، صارت m2 v2 final تربيع ناقص
+
+109
+00:08:55,900 --> 00:08:59,620
+v2 initial تربيع، هذا تكنيك عشان أوجد القانون
+
+110
+00:08:59,620 --> 00:09:03,900
+النهائي، بعد هيك، we factor both sides of the
+
+111
+00:09:03,900 --> 00:09:10,680
+equation، الآن، m1 v1 initial، فكيتها فرق مربعين على
+
+112
+00:09:10,680 --> 00:09:14,800
+الجهتين، بعدين، separate the term containing m1 and
+
+113
+00:09:14,800 --> 00:09:18,580
+m2 in the equation، بدأ أفصل المعادلة اللي فيها m1
+
+114
+00:09:18,580 --> 00:09:23,880
+واللي فيها m2، إذا m1 v1 initial ناقص v1 final
+
+115
+00:09:23,880 --> 00:09:31,220
+يساوي m2 v2 final ناقص v2 initial، وبعدين بقسمها على
+
+116
+00:09:31,220 --> 00:09:36,880
+المعادلة 6.13، بيطلع عندي v1 initial زائد v1 final
+
+117
+00:09:36,880 --> 00:09:41,800
+بيساوي v2 final زائد v2 initial، إذا ممكن أستخدم
+
+118
+00:09:41,800 --> 00:09:45,540
+القانون النهائي بهذا الشكل، v1 initial ناقص v2
+
+119
+00:09:45,540 --> 00:09:49,820
+initial، جبنا هذا من ناحية الثانية، بتساوي ناقص v1
+
+120
+00:09:49,820 --> 00:09:54,580
+final ناقص v2 final، هذا عشان أوجد اللي هو v1 final
+
+121
+00:09:54,580 --> 00:10:00,040
+و v2 final، هذا المعادلة، in combination، طبعا
+
+122
+00:10:00,040 --> 00:10:05,240
+بستخدمها بواسطة معادلة 16، وبنحّل، وبنوجد طبعا اللي
+
+123
+00:10:05,240 --> 00:10:10,130
+هي v1 final و v2 final، في حالة الـ elastic collision
+
+124
+00:10:10,130 --> 00:10:15,430
+و perfect elastic collision، نجي نلاقي كيف أنا بنحل
+
+125
+00:10:15,430 --> 00:10:18,910
+اللي هي الـ problem solving strategy،  قليلة حل
+
+126
+00:10:18,910 --> 00:10:23,090
+المسائل، the following procedure is recommended for
+
+127
+00:10:23,090 --> 00:10:28,250
+solving، بعض طبعا الملاحظات لحل المسائل، بتتعلق ب
+
+128
+00:10:28,250 --> 00:10:32,730
+التصادمات بين جسمين، أول حاجة بنختار coordinate
+
+129
+00:10:32,730 --> 00:10:38,970
+بنختار محاور، بختار محاور معينة، سواء x أو y، بعدين
+
+130
+00:10:38,970 --> 00:10:42,310
+برسم diagram، sketch the problem representing the
+
+131
+00:10:42,310 --> 00:10:46,770
+two object، برسم الجسمين، وبرسم اللي هي السرعات، و
+
+132
+00:10:46,770 --> 00:10:50,350
+براعي أنه في عندي أنا اليمين موجب، والشمال سالب
+
+133
+00:10:51,790 --> 00:10:54,750
+conservation of momentum، برضه بستخدم قانون
+
+134
+00:10:54,750 --> 00:10:58,690
+conservation of momentum، قانون حفظ كمية التحرك، بقى
+
+135
+00:10:58,690 --> 00:11:02,210
+إذا كان عندي جسمين، بنكتب m1 v1 initial، و m2 v2
+
+136
+00:11:02,210 --> 00:11:07,370
+initial، بنستخدم m1 v1 final، و m2 v2 final، بنستخدم
+
+137
+00:11:07,370 --> 00:11:10,590
+أيضاً الـ conservation of energy، قانون حفظ
+
+138
+00:11:10,590 --> 00:11:13,370
+الطاقة، if the collision is elastic، إذا الـ
+
+139
+00:11:13,370 --> 00:11:17,250
+collision كان مرن، بقى أكتب الـ general expression
+
+140
+00:11:17,250 --> 00:11:19,590
+اللي هو القانون العام للـ total energy before and
+
+141
+00:11:19,590 --> 00:11:23,230
+after the collision، وبعدين بساوي المعادلتين في بعض
+
+142
+00:11:23,230 --> 00:11:28,790
+ممكن نحلّل، ممكن نقسمهم على بعض، طبعاً، skip this step
+
+143
+00:11:28,790 --> 00:11:33,520
+if the collision is not perfect and elastic، بنحل
+
+144
+00:11:33,520 --> 00:11:36,880
+المعادلات اللي هي طبعاً معادلة خاصة بكمية التحرك
+
+145
+00:11:36,880 --> 00:11:40,920
+معادلة خاصة بالطاقة، بنحل المعادلات مع بعض، وبنوجد
+
+146
+00:11:40,920 --> 00:11:46,720
+v1 final و v2 final، في بعض المعادلات طبعاً بنعوّض v1
+
+147
+00:11:46,720 --> 00:11:50,900
+final بدلالة الأولى، بدلالة الثانية، بتطلع لمعادلتين
+
+148
+00:11:50,900 --> 00:11:56,570
+بمجهولين، ممكن نحل v1 final و v2 final، نشيلة
+
+149
+00:11:56,570 --> 00:12:00,930
+example 6-6 two billiard balls of identical mass
+
+150
+00:12:00,930 --> 00:12:05,050
+في عندي طبعاً كرة، صغيرة تحت الـ billiard، identical
+
+151
+00:12:05,050 --> 00:12:10,290
+mass، يعني الكتلة، الواحدة متساوية بتحرك towards
+
+152
+00:12:10,290 --> 00:12:14,510
+each other، تتحرك ناحية بعض، with a positive x axis
+
+153
+00:12:14,510 --> 00:12:17,910
+to the right، ناحية اليمين، نفرض أن الـ collision
+
+154
+00:12:17,910 --> 00:12:22,430
+between them is perfect elastic، يعني مرن
+
+155
+00:12:22,430 --> 00:12:25,950
+if the initial velocity of the ball، طبعاً الـ
+
+156
+00:12:25,950 --> 00:12:29,330
+initial velocity للكرات كانت ثلاثين سنتيمتر في
+
+157
+00:12:29,330 --> 00:12:32,210
+الثانية وعشرين، يعني الكرة الأولى تتحرك بسرعة
+
+158
+00:12:32,210 --> 00:12:32,830
+ثلاثين
+
+159
+00:12:39,310 --> 00:12:45,530
+بعد التصادم، بدنا نوجد سرعاتهم بعد التصادم، assume
+
+160
+00:12:45,530 --> 00:12:51,750
+friction and rotation are unimportant، يعني بيحكي
+
+161
+00:12:51,750 --> 00:12:55,170
+لنا أنه طبعاً بيهمل الـ friction الاحتكاك، والـ
+
+162
+00:12:55,170 --> 00:13:02,180
+rotation، هنا الكتلتين m1 v1 initial، m2 v2 initial
+
+163
+00:13:02,180 --> 00:13:05,940
+هذا التصادم بيسموه perfect elastic، وليس inelastic
+
+164
+00:13:05,940 --> 00:13:14,840
+perfect elastic، طبعاً اللي هو تصادم مرن، تم after
+
+165
+00:13:14,840 --> 00:13:18,340
+the collision the object lost its change but both
+
+166
+00:13:18,340 --> 00:13:20,660
+the energy and momentum of the system are
+
+167
+00:13:20,660 --> 00:13:24,720
+conserved، طبعاً الـ momentum وكمية التحرك conserved
+
+168
+00:13:24,720 --> 00:13:29,000
+نستخدم القانونين، نيجي نحل، أول حاجة بأستخدم قانون
+
+169
+00:13:29,000 --> 00:13:34,440
+كمية التحرك، طبعاً m1 بيساوي m2، طبعاً هتتلغي الـ m من
+
+170
+00:13:34,440 --> 00:13:38,640
+الجهتين، بعوض عن v1 initial، 30، v2 initial ناقص 20
+
+171
+00:13:38,640 --> 00:13:47,120
+بيصير عندي v1 final و v2 final، نيجي نعوّض v1 30، الـ
+
+172
+00:13:47,120 --> 00:13:52,040
+m راحت، v2 initial ناقص 20، بتساوي v1 final زائد v2
+
+173
+00:13:52,040 --> 00:13:52,460
+final
+
+174
+00:13:59,340 --> 00:14:03,300
+بتجيب معادلة ثانية، معادلة conservation of energy
+
+175
+00:14:03,820 --> 00:14:07,020
+بيصير عندي v1 initial، طبعاً باستخدام الق
+
+223
+00:17:50,180 --> 00:17:53,980
+تقطيع الوضع المرونية برضه zero لإن ماكانش مضغوط
+
+224
+00:17:53,980 --> 00:18:00,080
+بساوي نص M1V1 final تربيع + نص M2 V2 final تربيع
+
+225
+00:18:00,080 --> 00:18:04,160
++ نص K X تربيع، و بنوجد من هذه العلاقة اللي هي
+
+226
+00:18:04,160 --> 00:18:08,340
+من عوض عن كل واحدة الانصاص بيروح، بعوض عن M1 و M2
+
+227
+00:18:08,340 --> 00:18:13,280
+و M3 و أقصد M1 و M2 و V1 و V2 initial و final و
+
+228
+00:18:13,280 --> 00:18:21,220
+بوجد اللي هي ال X، بطلع point 173 emitter مثال 67
+
+229
+00:18:21,220 --> 00:18:26,810
+pulling pole on port space station، طبعا نوتجيز ping
+
+230
+00:18:26,810 --> 00:18:28,830
+pong ball is floating at rest relative to the
+
+231
+00:18:28,830 --> 00:18:34,930
+station, and an astronaut towards
+
+232
+00:18:34,930 --> 00:18:41,390
+it at speed v، طبعا initiating a perfect elastic
+
+233
+00:18:41,390 --> 00:18:45,710
+head on collision. Which answer is closest to the
+
+234
+00:18:45,710 --> 00:18:50,910
+ping pong ball's speed after the collision؟ طبعا احنا
+
+235
+00:18:50,910 --> 00:18:57,030
+هنا ممكن يعني هذا السؤال، في عندي يعني محطة فضائية
+
+236
+00:18:57,030 --> 00:19:01,910
+سفينة فضائية كبيرة، بدنا نضرب فيها أو نرمي عليها
+
+237
+00:19:01,910 --> 00:19:07,010
+كرة، كرة صغيرة. هل الكرة الصغيرة ترتد؟ طبعا الكرة
+
+238
+00:19:07,010 --> 00:19:12,210
+أنا رميتها بسرعة V، كرة صغيرة ناحية اللي هي بسرعة V
+
+239
+00:19:12,210 --> 00:19:16,450
+رميتها على السفينة .. على السفينة .. السفينة الفضاء
+
+240
+00:19:16,450 --> 00:19:20,590
+أو المركبة الفضائية. طبعا المركبة الفضائية كبيرة
+
+241
+00:19:20,590 --> 00:19:26,590
+رميت الكورة عليها، فهترتد، اللي هي الكورة الصغيرة
+
+242
+00:19:26,590 --> 00:19:30,290
+بسرعة V، أو كأنه الكورة الصغيرة رميتها على الحيط، أو
+
+243
+00:19:30,290 --> 00:19:34,290
+رميتها على جسم كبير، هترتد بسرعة .. بنفس السرعة
+
+244
+00:19:34,290 --> 00:19:38,390
+الجواب أنها هترتد بنفس السرعة لأن الكتلة الثانية
+
+245
+00:19:38,390 --> 00:19:42,570
+كبيرة، وأنا رميت كتلة صغيرة، زي ما نرمي كرة صغيرة
+
+246
+00:19:42,570 --> 00:19:46,790
+على الحيط، هترتد تقريبا بنفس السرعة. هيك بنكون خلصنا
+
+247
+00:19:46,790 --> 00:19:48,850
+إن شاء الله chapter 6
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..57d4973bab563dfe39dd9622837aad0997e77369
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo_postprocess.srt
@@ -0,0 +1,988 @@
+1
+00:00:00,390 --> 00:00:05,290
+بسم الله الرحمن الرحيم هنبدأ بحل ان شاء الله بعض
+
+2
+00:00:05,290 --> 00:00:11,430
+اللي هي الأمثلة ككويزات كوكي كويز ستة أربعة an
+
+3
+00:00:11,430 --> 00:00:15,270
+object of mass m move to the right في عندنا جسم
+
+4
+00:00:15,270 --> 00:00:20,350
+كتلته m بتحرك ناحية اليمين بسرعة v الآن اصطدم it
+
+5
+00:00:20,350 --> 00:00:24,510
+collides head-on with an object of mass تلاتة m
+
+6
+00:00:24,510 --> 00:00:29,080
+moving with speed v ع تلاتة الآن جسم كتلته mبتحرك
+
+7
+00:00:29,080 --> 00:00:33,740
+بسرعة V بتحرك راحية اليمين و جسم كتلته تلاتة M
+
+8
+00:00:33,740 --> 00:00:38,040
+بتحرك بسرعة V على تلاتة M بتحرك راحية اليسار if
+
+9
+00:00:38,040 --> 00:00:42,360
+the two objects stick together خبطوا في بعض ومشيوا
+
+10
+00:00:42,360 --> 00:00:49,040
+بعد التصادم be combined كجسم واحد بكتلة طبعا أربع
+
+11
+00:00:49,040 --> 00:00:53,920
+M لأن الأول كتلته M والتالتة M فمجموعهم أربع M بعد
+
+12
+00:00:53,920 --> 00:00:57,500
+التصادم after the collision بعد التصادم
+
+13
+00:01:00,210 --> 00:01:06,870
+after the collision zero و لا V ع 2 و لا V و لا 2V
+
+14
+00:01:06,870 --> 00:01:10,670
+اللي هي السرعة النهائية بعد ما صار جسم واحد مطلوب
+
+15
+00:01:10,670 --> 00:01:14,330
+what is the speed of the combined object after the
+
+16
+00:01:14,330 --> 00:01:18,350
+collision سرعتهم بعد التصادم طبعا الجواب A اللي هو
+
+17
+00:01:18,350 --> 00:01:23,670
+zero لإنه لما أجى أحيل M1 في V1 زي م2 في V2 M1 في
+
+18
+00:01:23,670 --> 00:01:28,750
+M و M2 في V M في Vزائد او هي ناقص لإنه بتجاه
+
+19
+00:01:28,750 --> 00:01:32,110
+المعاكس of the direction V أتلاتة مضربة في تلاتة M
+
+20
+00:01:32,110 --> 00:01:35,150
+بيطلع ناقص V بيطلع الجواب Zero لإنه فعلا السرعة
+
+21
+00:01:35,150 --> 00:01:41,530
+النهائية بتساوي Zero بتطبيق اللي هي قانون perfect
+
+22
+00:01:41,530 --> 00:01:45,770
+in elastic وكانوا التنين باتجاهين مختلفين فبطلع
+
+23
+00:01:45,770 --> 00:01:54,050
+المحصلة السرعة النهائية بساوي Zero quiz 565skater
+
+24
+00:01:54,050 --> 00:02:00,410
+is using very low friction roller طبعا plats في
+
+25
+00:02:00,410 --> 00:02:06,530
+عندي متزلجة بتتحرك على سطح طبعا أملس مافيش
+
+26
+00:02:06,530 --> 00:02:11,930
+friction ضعيف friend of في أحد أصحابهارمالها الطبق
+
+27
+00:02:11,930 --> 00:02:16,150
+الطائر عشان تمسكوه رمال طبعا بخط مستقيم و هي
+
+28
+00:02:16,150 --> 00:02:21,030
+بتتزلج along what she is coasting كيف هي ممكن انها
+
+29
+00:02:21,030 --> 00:02:24,470
+تمسكوه describe each of the following events as an
+
+30
+00:02:24,470 --> 00:02:27,930
+elastic or an inelastic او perfect inelastic كل
+
+31
+00:02:27,930 --> 00:02:33,310
+جديد الان متزلجة سيدة بتتزلج على جليد او بالسكيتر
+
+32
+00:02:33,310 --> 00:02:39,610
+بتتحرك ال friction طبعا قليل في شاب او طبعا صديق
+
+33
+00:02:39,610 --> 00:02:44,370
+رمالهاالطبق الطائر بخط مستقيم طبعا هيعطينا حالات
+
+34
+00:02:44,370 --> 00:02:48,170
+من ضمن هذه الحالات بدنا نحدد هل التصادم اللي صار
+
+35
+00:02:48,170 --> 00:02:54,250
+بين السيدة و الطبق هل هو elastic ولا inelastic ولا
+
+36
+00:02:54,250 --> 00:02:59,730
+perfect الآن she catch في الحالة الأولىshe catch
+
+37
+00:02:59,730 --> 00:03:06,130
+the frisbee and holds it طبعا هي مسكت الطبق و
+
+38
+00:03:06,130 --> 00:03:11,010
+مسكته و التسقط فيه فده الحالة في الأول الحالة لما
+
+39
+00:03:11,010 --> 00:03:15,630
+هي التصادم صار perfect in elastic كأنه كأنهم جسم
+
+40
+00:03:15,630 --> 00:03:19,290
+واحد صاروا هي مسكت فيه و صاروا جسم واحد في الحالة
+
+41
+00:03:19,290 --> 00:03:23,510
+التانية طبعا هي حاولة she tries to catch the
+
+42
+00:03:23,510 --> 00:03:30,400
+frisbeeبحاولة تمسك الطبق لكن bounce off ارتد منها
+
+43
+00:03:30,400 --> 00:03:38,160
+ووقع على الأرض هذا بسميه inelastic يعني غير marine
+
+44
+00:03:41,250 --> 00:03:45,170
+في الحالة C هي ك .. she catch the frisbee and
+
+45
+00:03:45,170 --> 00:03:50,750
+immediately throw يعني مسكتها ورجعتها تاني بنفس ..
+
+46
+00:03:50,750 --> 00:03:56,110
+بسرعة .. بسرعة يعني هي يعني يعتبر كأنه elastic كل
+
+47
+00:03:56,110 --> 00:04:01,650
+جن يعتبر كأنه elastic عساس أنه تصادم بين جسمين
+
+48
+00:04:04,850 --> 00:04:08,930
+النوع الأول اللي هو perfect in elastic any
+
+49
+00:04:08,930 --> 00:04:11,430
+collision in which the two objects stick together
+
+50
+00:04:11,430 --> 00:04:15,090
+afterward is perfect in elasticالنوع التاني هنا
+
+51
+00:04:15,090 --> 00:04:20,330
+perfect inelastic النوع التاني inelastic هي مسكته
+
+52
+00:04:20,330 --> 00:04:26,110
+و بعد هي نزل منها على الأرض يعني هنا انمسك لكن
+
+53
+00:04:26,110 --> 00:04:30,010
+اسمه inelastic هنا يبدو في خطأ في inelastic لأنها
+
+54
+00:04:30,010 --> 00:04:35,250
+مسكته و رمته بنفس اللحظة فبسميه طبعا elastic
+
+55
+00:04:35,250 --> 00:04:39,350
+collision تصادم marine if the total kinetic energy
+
+56
+00:04:39,350 --> 00:04:40,870
+of the system is not conserved
+
+57
+00:04:51,870 --> 00:05:00,570
+Quick quiz 6.6 perfectly inelastic one dimension
+
+58
+00:05:00,570 --> 00:05:07,210
+في التصادم الغير marine between two objects what
+
+59
+00:05:07,210 --> 00:05:11,730
+initial condition alone is necessary so that all
+
+60
+00:05:11,730 --> 00:05:16,270
+of the original kinetic energy of the system is
+
+61
+00:05:16,270 --> 00:05:20,520
+gone after the collisionبالنسبة لل perfect
+
+62
+00:05:20,520 --> 00:05:23,440
+inelastic عديم المرونة في اتجاه واحد او في بعد
+
+63
+00:05:23,440 --> 00:05:27,740
+واحد او تصادم من جسمين عاديم المرونة what initial
+
+64
+00:05:27,740 --> 00:05:32,700
+condition ما هو الشرط المبدأ الاولاني اللي هو
+
+65
+00:05:32,700 --> 00:05:39,700
+الخاص ب .. بدنا الشرط الأساسي condition alone
+
+66
+00:05:39,700 --> 00:05:44,160
+الوحيد الضروري so that all of the original kinetic
+
+67
+00:05:44,160 --> 00:05:47,070
+energy of the system gone after the collisionاللي
+
+68
+00:05:47,070 --> 00:05:52,290
+بيخلي انه في عندي فقد او يعني تشتيت لطاقة الحركة
+
+69
+00:05:52,290 --> 00:05:56,750
+طبعا الشرط الأساسي هل هو the object must have
+
+70
+00:05:56,750 --> 00:05:59,070
+momentum with the same magnitude but opposite
+
+71
+00:05:59,070 --> 00:06:03,350
+direction او the object هل ان الجسم must have the
+
+72
+00:06:03,350 --> 00:06:06,550
+same mass او the same velocity او the same اللي هو
+
+73
+00:06:06,550 --> 00:06:13,170
+speed فالحل الصحيح انه الشرط الوحيدعشان انا يعني
+
+74
+00:06:13,170 --> 00:06:17,530
+يكون عندنا فقد في الطاقة هو the objects الأجسام
+
+75
+00:06:17,530 --> 00:06:22,450
+هذه لها نفس كمية التحرك نفس المقدار ومعاكسة في
+
+76
+00:06:22,450 --> 00:06:26,490
+الاتجاه نجلة
+
+77
+00:06:26,490 --> 00:06:31,390
+ال elastic collision ال elastic collision now
+
+78
+00:06:31,390 --> 00:06:35,590
+consider two objects that undergoes an elastic
+
+79
+00:06:35,590 --> 00:06:40,770
+head-on collision in this situationboth the
+
+80
+00:06:40,770 --> 00:06:43,670
+momentum and the kinetic energy of the system of
+
+81
+00:06:43,670 --> 00:06:49,010
+two objects are conserved في النسبة لل elastic
+
+82
+00:06:49,010 --> 00:06:52,730
+collision هنا نيجي لل elastic collision بيحكي لنا
+
+83
+00:06:52,730 --> 00:06:59,150
+بدأ افرض في عندي اناelastic يعني مرين المرين طبعا
+
+84
+00:06:59,150 --> 00:07:05,890
+كل جسم بعد التصامم يروح بسرعة معينة في المرين كمية
+
+85
+00:07:05,890 --> 00:07:10,310
+التحرك محفوظة و تقطي الحركة محفوظة و ده system
+
+86
+00:07:10,310 --> 00:07:14,470
+معروفة كمية التحرك محفوظة لجميع في ال elastic و لا
+
+87
+00:07:14,470 --> 00:07:19,030
+ال elastic الآن هنا جسمين الجسم الأول او واحد
+
+88
+00:07:19,030 --> 00:07:22,550
+بتتحرك بسرعة في واحد initial والسرقه الجسم التاني
+
+89
+00:07:23,830 --> 00:07:28,210
+م2 بتحرك بسرعة v2 initial before and طبعا هذا
+
+90
+00:07:28,210 --> 00:07:32,730
+before the collision نيجي لتانى بعد التصادم اصطدمه
+
+91
+00:07:32,730 --> 00:07:38,370
+بعد التصادم الاولانى طبعا انطلق بسرعة v1 final و
+
+92
+00:07:38,370 --> 00:07:41,750
+10 انطلق بسرعة v2 final after the collision the
+
+93
+00:07:41,750 --> 00:07:45,510
+object velocity it changed اتغيرت but both the
+
+94
+00:07:45,510 --> 00:07:49,090
+energy and momentum of the system are conserved في
+
+95
+00:07:49,090 --> 00:07:52,310
+هذه الحالة ال momentum conserved وتقط الحركة is
+
+96
+00:07:52,310 --> 00:07:58,500
+conservedwe can write these conditions as الان في
+
+97
+00:07:58,500 --> 00:08:03,340
+عندي M1 V1 initial و M2 V2 initial بتساوي M1 V1
+
+98
+00:08:03,340 --> 00:08:08,560
+final زايد M2 V2 final هذا بالنسبة لقانون كمية
+
+99
+00:08:08,560 --> 00:08:13,040
+التحرك أساس أنها محفوظة وبستخدم قانون اللي هي
+
+100
+00:08:13,040 --> 00:08:19,500
+الطاقة الحركةwhere v is positive طبعا في هذا
+
+101
+00:08:19,500 --> 00:08:22,800
+الحالة if an object move to the right نعتبر أنه
+
+102
+00:08:22,800 --> 00:08:26,500
+السرعة موجة بقى إذا اتحرك الجسم لليمين والسرعة
+
+103
+00:08:26,500 --> 00:08:30,420
+سالة بقى إذا اتحرك إلى اليسار cancelling بالنسبة
+
+104
+00:08:30,420 --> 00:08:36,240
+للتانية طبعا بضيع الانصاص بضيع الانصاص من المعادلة
+
+105
+00:08:36,240 --> 00:08:42,080
+بعدين باخد ال M1 مشترك هي ال M1 باخد هذا الحد مع
+
+106
+00:08:42,080 --> 00:08:45,640
+هذا الحد يجي من ناحية تانية بيصير سالبm1 v1
+
+107
+00:08:45,640 --> 00:08:50,580
+initial تربيع ناقص m1 v1 final تربيع ناقص m2 هنا
+
+108
+00:08:50,580 --> 00:08:55,900
+جبناها ناحية التانية صارت m2 v2 final تربيع ناقص
+
+109
+00:08:55,900 --> 00:08:59,620
+v2 initial ا تربيع هذا تكنيك عشان اوجد القانون
+
+110
+00:08:59,620 --> 00:09:03,900
+النهائي بعد هيكا we factor both sides of the
+
+111
+00:09:03,900 --> 00:09:10,680
+equation الان m1 v1 initial فكيتها فرق مربعين على
+
+112
+00:09:10,680 --> 00:09:14,800
+الجهتينبعدين separate the term containing M1 and
+
+113
+00:09:14,800 --> 00:09:18,580
+M2 in the equation بدأ أفصل المعادلة اللي فيها M1
+
+114
+00:09:18,580 --> 00:09:23,880
+و اللي فيها M2 اذا M1 V1 initial ناقص V1 final
+
+115
+00:09:23,880 --> 00:09:31,220
+سواء M2 V2 final ناقص V2 initial وبعدين بقسمها على
+
+116
+00:09:31,220 --> 00:09:36,880
+المعادلة 6.13 بطلع عندي V1 initial زائد V1 final
+
+117
+00:09:36,880 --> 00:09:41,800
+بسوا V2 final زائد V2 initialأذا ممكن أستخدم
+
+118
+00:09:41,800 --> 00:09:45,540
+القانون النهائي بهذا الشكل v1 initial ناقص v2
+
+119
+00:09:45,540 --> 00:09:49,820
+initial جيبنا هذا من ناحية التانية بتساوي ناقص v1
+
+120
+00:09:49,820 --> 00:09:54,580
+final ناقص v2 final هذا عشان أوجد اللي هو v1 final
+
+121
+00:09:54,580 --> 00:10:00,040
+وv2 final هذا المعادلة in combination طبعا
+
+122
+00:10:00,040 --> 00:10:05,240
+بستخدمها بوسطة معادلة 16 و بنحل و بنوجد طبعا اللي
+
+123
+00:10:05,240 --> 00:10:10,130
+هي v1 final وv2 final في حالةالـ Elastic Collision
+
+124
+00:10:10,130 --> 00:10:15,430
+و Perfect Elastic Collision نجي نلاقي كيف انا بنحل
+
+125
+00:10:15,430 --> 00:10:18,910
+اللي هي ال problem solving strategy قليلة حل
+
+126
+00:10:18,910 --> 00:10:23,090
+المسائل the following procedure is recommended for
+
+127
+00:10:23,090 --> 00:10:28,250
+solving بعض طبعا الغلاحظات لحل المسائلبتتعلق بيه
+
+128
+00:10:28,250 --> 00:10:32,730
+التصادمات بين جسمين أول حاجة بنختار coordinate
+
+129
+00:10:32,730 --> 00:10:38,970
+بنختار محاور بختار محاور معين سواء X أو Y بعدين
+
+130
+00:10:38,970 --> 00:10:42,310
+برسم diagram sketch the problem representing the
+
+131
+00:10:42,310 --> 00:10:46,770
+auto object برسم الجسمين و برسم اللي هي السرعات و
+
+132
+00:10:46,770 --> 00:10:50,350
+براعي أنه في عندي أنا اليمين موجب و الشمال سالب
+
+133
+00:10:51,790 --> 00:10:54,750
+Conservation of momentum برضه بستخدم قانون
+
+134
+00:10:54,750 --> 00:10:58,690
+Conservation of momentum قانون حفظ كمية التحرك بقى
+
+135
+00:10:58,690 --> 00:11:02,210
+إذا كان عندي جسمين بنكتب M1V1 initial و M2V2
+
+136
+00:11:02,210 --> 00:11:07,370
+initial بنستخدم M1V1 final و M2V2 final بنستخدم
+
+137
+00:11:07,370 --> 00:11:10,590
+ايضا ال بعد هي Conservation of energy قانون حفظ
+
+138
+00:11:10,590 --> 00:11:13,370
+الطاقة if the collision is elastic إذا ال
+
+139
+00:11:13,370 --> 00:11:17,250
+collision كان مرن بقى أكتب ال general expression
+
+140
+00:11:17,250 --> 00:11:19,590
+اللي هو القانون العام لل total energy before and
+
+141
+00:11:19,590 --> 00:11:23,230
+after the collisionوبعدين بساوي المعادلتين في بعض
+
+142
+00:11:23,230 --> 00:11:28,790
+ممكن نحلل ممكن نقسمهم على بعض طبعا skype this step
+
+143
+00:11:28,790 --> 00:11:33,520
+if the collision is not perfect and elasticبنحل
+
+144
+00:11:33,520 --> 00:11:36,880
+المعادلات اللى هى طبعا معادلة خاصة بكمية التحرك
+
+145
+00:11:36,880 --> 00:11:40,920
+معادلة خاصة بالطاقة بنحل المعادلات مع بعض و بنوجد
+
+146
+00:11:40,920 --> 00:11:46,720
+V1 Final و V2 Final فى بعض المعادلات طبعا بنعود V1
+
+147
+00:11:46,720 --> 00:11:50,900
+Final بدلالة الأولى بدلالة التانى تطلع لمعادلتين
+
+148
+00:11:50,900 --> 00:11:56,570
+المجهولين ممكن نحل V1 Final و V2 Finalنشيلة
+
+149
+00:11:56,570 --> 00:12:00,930
+example 6-6 two billiard balls of identical mass
+
+150
+00:12:00,930 --> 00:12:05,050
+في عندي طبعا كرة صغيرة تحت ال biliardo identical
+
+151
+00:12:05,050 --> 00:12:10,290
+mass يعني الكتة الواحدة المتمثلة بتتحرك towards
+
+152
+00:12:10,290 --> 00:12:14,510
+each other تتحرك ناحية بعض with a positive x axis
+
+153
+00:12:14,510 --> 00:12:17,910
+to the right ناحية اليمينبفرض that ان ال collision
+
+154
+00:12:17,910 --> 00:12:22,430
+between them is perfect elastic يعني عديم المرونة
+
+155
+00:12:22,430 --> 00:12:25,950
+if the initial velocity of the ball طبعا ال
+
+156
+00:12:25,950 --> 00:12:29,330
+initial velocity للكورات كانت تلاتين centimeter في
+
+157
+00:12:29,330 --> 00:12:32,210
+الثانية وعشرين يعني الكورة الأولى تتحرك بسرعة
+
+158
+00:12:32,210 --> 00:12:32,830
+تلاتين
+
+159
+00:12:39,310 --> 00:12:45,530
+بعد التصادم بدنا نوجد سرعاتهم بعد التصادم assume
+
+160
+00:12:45,530 --> 00:12:51,750
+friction and rotation are unimportant يعني بيحكي
+
+161
+00:12:51,750 --> 00:12:55,170
+لنا أنه طبعا بيهم ال friction الاحتكاك و ال
+
+162
+00:12:55,170 --> 00:13:02,180
+rotationهنا الكتلتين M1 V1 initial M2 V2 initial
+
+163
+00:13:02,180 --> 00:13:05,940
+هذا التصادم بيسموه perfect elastic وليس inelastic
+
+164
+00:13:05,940 --> 00:13:14,840
+perfect elastic طبعا اللي هو تصادم مرين تم after
+
+165
+00:13:14,840 --> 00:13:18,340
+the collision the object lost its change but both
+
+166
+00:13:18,340 --> 00:13:20,660
+the energy and momentum of the system are
+
+167
+00:13:20,660 --> 00:13:24,720
+conserved طبعا ال momentum وكمية التحرك conserved
+
+168
+00:13:24,720 --> 00:13:29,000
+استخدمالقانونين نجي نحل أول حاجة بأستخدم قانون
+
+169
+00:13:29,000 --> 00:13:34,440
+كمية التحرك طبعا M1 بيساوي M2 طبعا هتلتغ ال M من
+
+170
+00:13:34,440 --> 00:13:38,640
+الجهتين بعود عن V1 initial 30 V2 initial ناقص 20
+
+171
+00:13:38,640 --> 00:13:47,120
+بيبقى لعندي V1 final و V2 final نجي نعود V1 30 ال
+
+172
+00:13:47,120 --> 00:13:52,040
+M راحت V2 initial ناقص 20 بتساوي V1 final زائد V2
+
+173
+00:13:52,040 --> 00:13:52,460
+final
+
+174
+00:13:59,340 --> 00:14:03,300
+بتجيب معادلة تانية معادلة conservation of energy
+
+175
+00:14:03,820 --> 00:14:07,020
+بصير عندى v1 initial طبعا باستخدام القوانين
+
+176
+00:14:07,020 --> 00:14:12,900
+السابقة اللى هي معادلة 6 15 ناقص v1 final ناقص v2
+
+177
+00:14:12,900 --> 00:14:17,860
+final بنعود صار عندى معادلتين بمجهولين معادلتين
+
+178
+00:14:17,860 --> 00:14:21,840
+بمجهولين طبعا اللى هى أكتر من طريقة للحل ممكن أجيب
+
+179
+00:14:21,840 --> 00:14:26,840
+مثلا الأولى بدلالتي التانية هنا ممكن أجيب انه هنا
+
+180
+00:14:26,840 --> 00:14:30,880
+v1 final بتساوي عشرة ناقص v2 final أعود أنا في
+
+181
+00:14:30,880 --> 00:14:36,630
+المعادلة أو ممكن نحلهابإجمالهم مع بعض بنفع مع أنها
+
+182
+00:14:36,630 --> 00:14:42,090
+بتطلع V1 final نقص عشرين و V2 final بتساوي تلاتين
+
+183
+00:14:42,090 --> 00:14:51,390
+example 6-7Block of mass M1 كتلة جسم كتلته M1
+
+184
+00:14:51,390 --> 00:14:55,590
+بواحد بين ستة كيلو جرام Initially moving to the
+
+185
+00:14:55,590 --> 00:14:59,350
+right بيصير لحيط اليمين بسرعة أربعة عشر متر في
+
+186
+00:14:59,350 --> 00:15:03,950
+الثانية on frictionless horizontal track على سطح
+
+187
+00:15:03,950 --> 00:15:10,000
+أملس أفقي استضم بكتلة تانية massless springاستضم
+
+188
+00:15:10,000 --> 00:15:15,760
+بكتلة اللى هو نعبد الناعبد هذا كتلة طبعا يعني مجهو
+
+189
+00:15:15,760 --> 00:15:18,920
+يعني massless انه معدومة او احنا بنعتبرها مش
+
+190
+00:15:18,920 --> 00:15:22,680
+موجودة attached to a second block طبعا هداك ال
+
+191
+00:15:22,680 --> 00:15:27,660
+spring مربوط ب .. ب .. يعني عندي أنا كتلة تانية
+
+192
+00:15:27,660 --> 00:15:31,460
+هيها مربوطة ب spring يعني ال spring مربوط بكتلة و
+
+193
+00:15:31,460 --> 00:15:35,180
+هنا كتلةالكتلة الأولى تتحرك بسرعة أربعة والكتلة
+
+194
+00:15:35,180 --> 00:15:37,380
+التانية تتحرك بسرعة اتنين و نصف الكتلة التانية
+
+195
+00:15:37,380 --> 00:15:40,640
+مربوطة بال spring اللي هي ال force constant و
+
+196
+00:15:40,640 --> 00:15:47,200
+كتلته مهملة مهملة الآن طبعا اعطاني ال K اللي هي لل
+
+197
+00:15:47,200 --> 00:15:51,180
+spring ستة فعشرة اقصى اتنين المطلوب determine the
+
+198
+00:15:51,180 --> 00:15:53,700
+velocity of the block اتنين at the instant when
+
+199
+00:15:53,700 --> 00:15:55,780
+the block one is moving to the right with velocity
+
+200
+00:15:55,780 --> 00:16:01,090
+of تلاتة مطلوب مننا سرعة الكتلة M اتنينلما تكون
+
+201
+00:16:01,090 --> 00:16:06,230
+كتلة سرعت M1 بساوة 4 يعني لما M1 تصطدم بالزنبرك أو
+
+202
+00:16:06,230 --> 00:16:10,050
+بالنابط تضغطه مسافة معينة و تسير سرعتها بدل 4
+
+203
+00:16:10,050 --> 00:16:14,090
+تلاتة هذا المطلوب الأول ان انا اشنحل واحدة واحدة
+
+204
+00:16:15,320 --> 00:16:19,800
+مطلوب الاول ان هنا M1 ضغطت ال spring و صارت سرعتها
+
+205
+00:16:19,800 --> 00:16:26,520
+تلاتة لكن لسه في مزال مجال لضغط V2 final طبعا طبعا
+
+206
+00:16:26,520 --> 00:16:31,120
+هتتغير برضه اذا بدي اوجد الان find the velocity
+
+207
+00:16:31,120 --> 00:16:37,560
+بدي اوجد V2 final لما الكتلة M1 صارت سرعتها تلاتة
+
+208
+00:16:37,560 --> 00:16:40,800
+متر في الثانيطبعا المعطيات موجودة أننا بستخدم
+
+209
+00:16:40,800 --> 00:16:46,780
+قانون حفظ كمية التحرك اللي هو M1 V1 initial زاد M2
+
+210
+00:16:46,780 --> 00:16:50,840
+V2 initial بيساوي M1 V1 final زاد M2 V2 final
+
+211
+00:16:50,840 --> 00:16:54,840
+بتطلع V2 final بناء على هذا القانون عوضنا عن M1 1
+
+212
+00:16:54,840 --> 00:17:01,560
+.6 V1 initial 4 الأصلية زاد M2 V2 2 الأصلية نقص 2
+
+213
+00:17:01,560 --> 00:17:09,970
+.5 الان M1 كانت 1.6 V1 final كانت 3و V2 final احنا
+
+214
+00:17:09,970 --> 00:17:14,830
+مش عارفين انها بتطلع ناقص واحد بين سبعة اربع بعد
+
+215
+00:17:14,830 --> 00:17:18,350
+هيك طالب اللي هي المسافة اللي ال spring او
+
+216
+00:17:18,350 --> 00:17:22,010
+الزمبارك بينضغطها find the compression of the
+
+217
+00:17:22,010 --> 00:17:27,110
+spring اذا باستخدم اللي هي conservation of energy
+
+218
+00:17:27,110 --> 00:17:31,570
+of the system بنلاحظ ان طاقة الوضع المخزونة داخل
+
+219
+00:17:31,570 --> 00:17:35,990
+ال spring بنستخدمها في هذه الحالة اذا هنحكي ان E
+
+220
+00:17:35,990 --> 00:17:41,060
+initial بيساوي ال E finalE initial نص M1V1 initial
+
+221
+00:17:41,060 --> 00:17:46,220
+تربيع زاد نص M2V2 initial تربيع تقطي الحركة تقطي
+
+222
+00:17:46,220 --> 00:17:50,180
+الوضع للكتلة طبعا zero لإنها جالسة على نفس المستوى
+
+223
+00:17:50,180 --> 00:17:53,980
+تقطي الوضع المرونية برضه zero لإن ماكانش مضغوط
+
+224
+00:17:53,980 --> 00:18:00,080
+بساوي نص M1V1 final تربيعزائد نص M2 V2 final تربيع
+
+225
+00:18:00,080 --> 00:18:04,160
+زائد نص K X تربيع و بنوجد من هذه العلاقة اللي هي
+
+226
+00:18:04,160 --> 00:18:08,340
+من عوض عن كل واحدة الانصاص بيروحه بعوض عن M1 و M2
+
+227
+00:18:08,340 --> 00:18:13,280
+و M3 و اقصد M1 و M2 و V1 و V2 initial و final و
+
+228
+00:18:13,280 --> 00:18:21,220
+بقوجد اللي هي ال X بطلع point 173 emitter مثال 67
+
+229
+00:18:21,220 --> 00:18:26,810
+pulling pole on port space stationطبعا نوتجيز ping
+
+230
+00:18:26,810 --> 00:18:28,830
+pong ball is floating at rest relative to the
+
+231
+00:18:28,830 --> 00:18:34,930
+station and an astronaut towards
+
+232
+00:18:34,930 --> 00:18:41,390
+it at speed v طبعا initiating at perfect elastic
+
+233
+00:18:41,390 --> 00:18:45,710
+head on collision which answer is closest to the
+
+234
+00:18:45,710 --> 00:18:50,910
+ping pongballs speed after the collision طبعا احنا
+
+235
+00:18:50,910 --> 00:18:57,030
+هنا ممكن يعني هذا السؤال في عندى يعني محطة فضائية
+
+236
+00:18:57,030 --> 00:19:01,910
+سفينة فضائية كبيرة بدنا نضرب فيها او نرمي عليها
+
+237
+00:19:01,910 --> 00:19:07,010
+كرة كرة صغيرة هل الكرة الصغيرة ترتأت طبعا الكرة
+
+238
+00:19:07,010 --> 00:19:12,210
+انا رميتها بسرعة V كرة صغيرة ناحية اللى هي بسرعة V
+
+239
+00:19:12,210 --> 00:19:16,450
+رميتهاعلى السفينة .. على السفينة .. السفينة الفضاء
+
+240
+00:19:16,450 --> 00:19:20,590
+او المركبة الفضائية طبعا المركبة الفضائية كبيرة
+
+241
+00:19:20,590 --> 00:19:26,590
+رميت الكورة عليها فهترتد اللي هي الكورة الصغيرة
+
+242
+00:19:26,590 --> 00:19:30,290
+بسرعة V او كأنه الكورة الصغيرة رميتها على الحيط او
+
+243
+00:19:30,290 --> 00:19:34,290
+رميتها على جسم كبير هترتد بسرعة .. بنفس السرعة
+
+244
+00:19:34,290 --> 00:19:38,390
+الجواب انها هترتد بنفس السرعة لان الكتلة التانية
+
+245
+00:19:38,390 --> 00:19:42,570
+كبيرة و انا رميت كتلة صغيرةزى ما نرمى كرة صغيرة
+
+246
+00:19:42,570 --> 00:19:46,790
+على الحيط هترتد تقريبا بنفس السرعة هيك بنكون خلصنا
+
+247
+00:19:46,790 --> 00:19:48,850
+ان شاء الله chapter 6
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..60d214e0e0d3b771d93ce05ad21575f92d412ac2
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/yMjmQfKgjWo_raw.json
@@ -0,0 +1 @@
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what is the speed of the combined object after the collision سرعتهم بعد التصادم طبعا الجواب A اللي هو zero لإنه لما أجى أحيل M1 في V1 زي م2 في V2 M1 في M و M2 في V M في V", "tokens": [18837, 264, 24644, 4018, 4032, 20193, 691, 6225, 568, 4032, 20193, 691, 4032, 20193, 568, 53, 13672, 1829, 39896, 21136, 2288, 27884, 28239, 3224, 16373, 10632, 39182, 19446, 20328, 9640, 10874, 38251, 36764, 24401, 3714, 9566, 1211, 37746, 437, 307, 264, 3073, 295, 264, 9354, 2657, 934, 264, 24644, 8608, 2288, 34268, 16095, 39182, 16712, 9381, 18513, 2304, 23032, 3555, 3615, 995, 25724, 14407, 3555, 316, 13672, 1829, 31439, 4018, 5296, 28814, 1863, 3224, 5296, 15042, 5551, 7435, 7578, 5551, 5016, 26895, 376, 16, 8978, 691, 16, 30767, 1829, 3714, 17, 8978, 691, 17, 376, 16, 8978, 376, 4032, 376, 17, 8978, 691, 376, 8978, 691], "avg_logprob": -0.23364485591371484, "compression_ratio": 1.6784140969162995, "no_speech_prob": 3.0994415283203125e-06, "words": [{"start": 60.209999999999994, "end": 60.79, "word": 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"end": 71.03, "word": " is", "probability": 0.9560546875}, {"start": 71.03, "end": 71.27, "word": " the", "probability": 0.88720703125}, {"start": 71.27, "end": 71.65, "word": " speed", "probability": 0.9287109375}, {"start": 71.65, "end": 71.83, "word": " of", "probability": 0.96728515625}, {"start": 71.83, "end": 71.99, "word": " the", "probability": 0.89794921875}, {"start": 71.99, "end": 72.47, "word": " combined", "probability": 0.865234375}, {"start": 72.47, "end": 73.21, "word": " object", "probability": 0.85888671875}, {"start": 73.21, "end": 74.01, "word": " after", "probability": 0.88818359375}, {"start": 74.01, "end": 74.33, "word": " the", "probability": 0.88671875}, {"start": 74.33, "end": 74.77, "word": " collision", "probability": 0.919921875}, {"start": 74.77, "end": 75.33, "word": " سرعتهم", "probability": 0.87060546875}, {"start": 75.33, "end": 75.53, "word": " بعد", "probability": 0.9541015625}, {"start": 75.53, "end": 76.15, "word": " التصادم", "probability": 0.9693603515625}, {"start": 76.15, "end": 76.99, "word": " طبعا", "probability": 0.8856201171875}, {"start": 76.99, "end": 77.77, "word": " الجواب", "probability": 0.9010416666666666}, {"start": 77.77, "end": 77.99, "word": " A", "probability": 0.7294921875}, {"start": 77.99, "end": 78.19, "word": " اللي", "probability": 0.882568359375}, {"start": 78.19, "end": 78.35, "word": " هو", "probability": 0.99072265625}, {"start": 78.35, "end": 78.65, "word": " zero", "probability": 0.53076171875}, {"start": 78.65, "end": 79.29, "word": " لإنه", "probability": 0.8951416015625}, {"start": 79.29, "end": 79.85, "word": " لما", "probability": 0.947021484375}, {"start": 79.85, "end": 80.13, "word": " أجى", "probability": 0.688232421875}, {"start": 80.13, "end": 80.41, "word": " أحيل", "probability": 0.7312825520833334}, {"start": 80.41, "end": 80.83, "word": " M1", "probability": 0.801513671875}, {"start": 80.83, "end": 80.99, "word": " في", "probability": 0.7880859375}, {"start": 80.99, "end": 81.41, "word": " V1", "probability": 0.919921875}, {"start": 81.41, "end": 81.57, "word": " زي", "probability": 0.72412109375}, {"start": 81.57, "end": 82.03, "word": " م2", "probability": 0.591064453125}, {"start": 82.03, "end": 82.21, "word": " في", "probability": 0.9765625}, {"start": 82.21, "end": 82.67, "word": " V2", "probability": 0.99072265625}, {"start": 82.67, "end": 83.39, "word": " M1", "probability": 0.620361328125}, {"start": 83.39, "end": 83.67, "word": " في", "probability": 0.26171875}, {"start": 83.67, "end": 84.15, "word": " M", "probability": 0.64306640625}, {"start": 84.15, "end": 84.69, "word": " و", "probability": 0.849609375}, {"start": 84.69, "end": 85.13, "word": " M2", "probability": 0.9189453125}, {"start": 85.13, "end": 85.27, "word": " في", "probability": 0.826171875}, {"start": 85.27, "end": 85.51, "word": " V", "probability": 0.94091796875}, {"start": 85.51, "end": 85.79, "word": " M", "probability": 0.4091796875}, {"start": 85.79, "end": 85.93, "word": " في", "probability": 0.97509765625}, {"start": 85.93, "end": 86.21, "word": " V", "probability": 0.9931640625}], "temperature": 1.0}, {"id": 4, "seek": 11121, "start": 86.57, "end": 111.21, "text": "زائد او هي ناقص لإنه بتجاه المعاكس of the direction V أتلاتة مضربة في تلاتة M بيطلع ناقص V بيطلع الجواب Zero لإنه فعلا السرعة النهائية بتساوي Zero بتطبيق اللي هي قانون perfect in elastic وكانوا التنين باتجاهين مختلفين فبطلع المحصلة السرعة النهائية بساوي Zero quiz 565", "tokens": [11622, 16373, 3215, 1975, 2407, 39896, 8717, 995, 4587, 9381, 5296, 28814, 1863, 3224, 39894, 7435, 40294, 9673, 3615, 995, 4117, 3794, 295, 264, 3513, 691, 5551, 2655, 1211, 9307, 3660, 3714, 11242, 25513, 3660, 8978, 6055, 1211, 9307, 3660, 376, 4724, 1829, 9566, 1211, 3615, 8717, 995, 4587, 9381, 691, 4724, 1829, 9566, 1211, 3615, 25724, 14407, 3555, 17182, 5296, 28814, 1863, 3224, 6156, 3615, 15040, 21136, 2288, 27884, 28239, 3224, 16373, 10632, 39894, 3794, 995, 45865, 17182, 39894, 9566, 21292, 4587, 13672, 1829, 39896, 12174, 7649, 11536, 2176, 294, 17115, 4032, 41361, 14407, 16712, 1863, 9957, 4724, 9307, 7435, 40294, 9957, 3714, 46456, 46538, 9957, 6156, 3555, 9566, 1211, 3615, 9673, 5016, 36520, 3660, 21136, 2288, 27884, 28239, 3224, 16373, 10632, 4724, 3794, 995, 45865, 17182, 15450, 1025, 16824], "avg_logprob": -0.22088068622079762, "compression_ratio": 1.7651821862348178, "no_speech_prob": 1.3589859008789062e-05, "words": [{"start": 86.57, "end": 87.39, "word": "زائد", "probability": 0.4871622721354167}, {"start": 87.39, "end": 87.63, "word": " او", "probability": 0.787109375}, {"start": 87.63, "end": 87.81, "word": " هي", "probability": 0.7568359375}, {"start": 87.81, "end": 88.25, "word": " ناقص", "probability": 0.974365234375}, {"start": 88.25, "end": 88.47, "word": " لإنه", "probability": 0.745147705078125}, {"start": 88.47, "end": 88.75, "word": " بتجاه", "probability": 0.7560221354166666}, {"start": 88.75, "end": 89.23, "word": " المعاكس", "probability": 0.884765625}, {"start": 89.23, "end": 89.35, "word": " of", "probability": 0.7099609375}, {"start": 89.35, "end": 89.49, "word": " the", "probability": 0.73779296875}, {"start": 89.49, "end": 90.13, "word": " direction", "probability": 0.72021484375}, {"start": 90.13, "end": 90.71, "word": " V", "probability": 0.453857421875}, {"start": 90.71, "end": 91.27, "word": " أتلاتة", "probability": 0.66767578125}, {"start": 91.27, "end": 91.65, "word": " مضربة", "probability": 0.7633056640625}, {"start": 91.65, "end": 91.71, "word": " في", "probability": 0.7373046875}, {"start": 91.71, "end": 92.01, "word": " تلاتة", "probability": 0.944091796875}, {"start": 92.01, "end": 92.11, "word": " M", "probability": 0.47998046875}, {"start": 92.11, "end": 92.39, "word": " بيطلع", "probability": 0.740478515625}, {"start": 92.39, "end": 92.75, "word": " ناقص", "probability": 0.9520263671875}, {"start": 92.75, "end": 92.87, "word": " V", "probability": 0.74755859375}, {"start": 92.87, "end": 93.13, "word": " بيطلع", "probability": 0.87548828125}, {"start": 93.13, "end": 93.49, "word": " الجواب", "probability": 0.9798177083333334}, {"start": 93.49, "end": 93.75, "word": " Zero", "probability": 0.53369140625}, {"start": 93.75, "end": 94.11, "word": " لإنه", "probability": 0.9342041015625}, {"start": 94.11, "end": 94.43, "word": " فعلا", "probability": 0.9270833333333334}, {"start": 94.43, "end": 95.15, "word": " السرعة", "probability": 0.8986002604166666}, {"start": 95.15, "end": 95.45, "word": " النهائية", "probability": 0.9835205078125}, {"start": 95.45, "end": 95.97, "word": " بتساوي", "probability": 0.8565673828125}, {"start": 95.97, "end": 96.37, "word": " Zero", "probability": 0.92236328125}, {"start": 96.37, "end": 97.17, "word": " بتطبيق", "probability": 0.9053955078125}, {"start": 97.17, "end": 97.63, "word": " اللي", "probability": 0.85693359375}, {"start": 97.63, "end": 98.01, "word": " هي", "probability": 0.77197265625}, {"start": 98.01, "end": 100.07, "word": " قانون", "probability": 0.8079427083333334}, {"start": 100.07, "end": 101.53, "word": " perfect", "probability": 0.28271484375}, {"start": 101.53, "end": 101.79, "word": " in", "probability": 0.68017578125}, {"start": 101.79, "end": 102.27, "word": " elastic", "probability": 0.77587890625}, {"start": 102.27, "end": 103.17, "word": " وكانوا", "probability": 0.87109375}, {"start": 103.17, "end": 103.51, "word": " التنين", "probability": 0.7425130208333334}, {"start": 103.51, "end": 104.09, "word": " باتجاهين", "probability": 0.96796875}, {"start": 104.09, "end": 104.95, "word": " مختلفين", "probability": 0.9569091796875}, {"start": 104.95, "end": 105.77, "word": " فبطلع", "probability": 0.85244140625}, {"start": 105.77, "end": 106.53, "word": " المحصلة", "probability": 0.8765869140625}, {"start": 106.53, "end": 106.83, "word": " السرعة", "probability": 0.98486328125}, {"start": 106.83, "end": 107.13, "word": " النهائية", "probability": 0.9715576171875}, {"start": 107.13, "end": 107.61, "word": " بساوي", "probability": 0.8648681640625}, {"start": 107.61, "end": 108.05, "word": " Zero", "probability": 0.92822265625}, {"start": 108.05, "end": 110.35, "word": " quiz", "probability": 0.533203125}, {"start": 110.35, "end": 111.21, "word": " 565", "probability": 0.7099609375}], "temperature": 1.0}, {"id": 5, "seek": 13069, "start": 112.81, "end": 130.69, "text": "skater is using very low friction roller طبعا plats في عندي متزلجة بتتحرك على سطح طبعا أملس مافيش friction ضعيف friend of في أحد أصحابها", "tokens": [5161, 771, 307, 1228, 588, 2295, 17710, 15948, 23032, 3555, 3615, 995, 48328, 8978, 18871, 16254, 44650, 11622, 1211, 7435, 3660, 39894, 2655, 5016, 31747, 15844, 8608, 9566, 5016, 23032, 3555, 3615, 995, 5551, 42213, 3794, 19446, 41185, 8592, 17710, 48812, 3615, 33911, 1277, 295, 8978, 5551, 24401, 5551, 9381, 5016, 16758, 11296], "avg_logprob": -0.23741320106718275, "compression_ratio": 1.269736842105263, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 112.81, "end": 114.05, "word": "skater", "probability": 0.57330322265625}, {"start": 114.05, "end": 114.27, "word": " is", "probability": 0.90673828125}, {"start": 114.27, "end": 114.65, "word": " using", "probability": 0.92431640625}, {"start": 114.65, "end": 114.91, "word": " very", "probability": 0.8154296875}, {"start": 114.91, "end": 115.21, "word": " low", "probability": 0.9638671875}, {"start": 115.21, "end": 115.77, "word": " friction", "probability": 0.9697265625}, {"start": 115.77, "end": 118.03, "word": " roller", "probability": 0.325927734375}, {"start": 118.03, "end": 118.59, "word": " طبعا", "probability": 0.86749267578125}, {"start": 118.59, "end": 119.27, "word": " plats", "probability": 0.1866455078125}, {"start": 119.27, "end": 120.41, "word": " في", "probability": 0.5517578125}, {"start": 120.41, "end": 120.67, "word": " عندي", "probability": 0.76416015625}, {"start": 120.67, "end": 121.45, "word": " متزلجة", "probability": 0.9021484375}, {"start": 121.45, "end": 122.05, "word": " بتتحرك", "probability": 0.933349609375}, {"start": 122.05, "end": 122.37, "word": " على", "probability": 0.84423828125}, {"start": 122.37, "end": 123.03, "word": " سطح", "probability": 0.9793294270833334}, {"start": 123.03, "end": 124.59, "word": " طبعا", "probability": 0.9395751953125}, {"start": 124.59, "end": 125.63, "word": " أملس", "probability": 0.734375}, {"start": 125.63, "end": 126.53, "word": " مافيش", "probability": 0.9436848958333334}, {"start": 126.53, "end": 127.43, "word": " friction", "probability": 0.99169921875}, {"start": 127.43, "end": 128.17, "word": " ضعيف", "probability": 0.9903971354166666}, {"start": 128.17, "end": 129.13, "word": " friend", "probability": 0.363037109375}, {"start": 129.13, "end": 129.47, "word": " of", "probability": 0.2939453125}, {"start": 129.47, "end": 129.67, "word": " في", "probability": 0.46923828125}, {"start": 129.67, "end": 129.95, "word": " أحد", "probability": 0.9345703125}, {"start": 129.95, "end": 130.69, "word": " أصحابها", "probability": 0.98759765625}], "temperature": 1.0}, {"id": 6, "seek": 16022, "start": 130.91, "end": 160.23, "text": "رمالها الطبق الطائر عشان تمسكوه رمال طبعا بخط مستقيم و هي بتتزلج along what she is coasting كيف هي ممكن انها تمسكوه describe each of the following events as an elastic or an inelastic او perfect inelastic كل جديد الان متزلجة سيدة بتتزلج على جليد او بالسكيتر بتتحرك ال friction طبعا قليل في شاب او طبعا صديق رمالها", "tokens": [2288, 2304, 6027, 11296, 41950, 3555, 4587, 41950, 16373, 2288, 6225, 8592, 7649, 46811, 3794, 4117, 2407, 3224, 12602, 2304, 6027, 23032, 3555, 3615, 995, 4724, 9778, 9566, 3714, 14851, 4587, 32640, 4032, 39896, 39894, 2655, 11622, 1211, 7435, 2051, 437, 750, 307, 8684, 278, 9122, 33911, 39896, 3714, 43020, 16472, 11296, 46811, 3794, 4117, 2407, 3224, 6786, 1184, 295, 264, 3480, 3931, 382, 364, 17115, 420, 364, 294, 338, 2750, 1975, 2407, 2176, 294, 338, 2750, 28242, 10874, 16254, 3215, 2423, 7649, 44650, 11622, 1211, 7435, 3660, 8608, 25708, 3660, 39894, 2655, 11622, 1211, 7435, 15844, 10874, 20292, 3215, 1975, 2407, 20666, 3794, 4117, 36081, 2288, 39894, 2655, 5016, 31747, 2423, 17710, 23032, 3555, 3615, 995, 12174, 20292, 1211, 8978, 13412, 16758, 1975, 2407, 23032, 3555, 3615, 995, 20328, 16254, 4587, 12602, 2304, 6027, 11296], "avg_logprob": -0.13891422922593832, "compression_ratio": 1.7360594795539033, "no_speech_prob": 2.205371856689453e-06, "words": [{"start": 130.91, "end": 131.51, "word": "رمالها", "probability": 0.913818359375}, {"start": 131.51, "end": 131.93, "word": " الطبق", "probability": 0.82958984375}, {"start": 131.93, "end": 132.65, "word": " الطائر", "probability": 0.9903971354166666}, {"start": 132.65, "end": 133.31, "word": " عشان", "probability": 0.9847005208333334}, {"start": 133.31, "end": 134.21, "word": " تمسكوه", "probability": 0.8845703125}, {"start": 134.21, "end": 134.89, "word": " رمال", "probability": 0.7361653645833334}, {"start": 134.89, "end": 135.15, "word": " طبعا", "probability": 0.951171875}, {"start": 135.15, "end": 135.41, "word": " بخط", "probability": 0.82763671875}, {"start": 135.41, "end": 135.99, "word": " مستقيم", "probability": 0.9560546875}, {"start": 135.99, "end": 136.13, "word": " و", "probability": 0.54443359375}, {"start": 136.13, "end": 136.15, "word": " هي", "probability": 0.56689453125}, {"start": 136.15, "end": 136.91, "word": " بتتزلج", "probability": 0.9052734375}, {"start": 136.91, "end": 137.67, "word": " along", "probability": 0.8173828125}, {"start": 137.67, "end": 137.97, "word": " what", "probability": 0.8505859375}, {"start": 137.97, "end": 138.17, "word": " she", "probability": 0.94482421875}, {"start": 138.17, "end": 138.47, "word": " is", "probability": 0.9150390625}, {"start": 138.47, "end": 139.41, "word": " coasting", "probability": 0.896484375}, {"start": 139.41, "end": 139.73, "word": " كيف", "probability": 0.927490234375}, {"start": 139.73, "end": 140.03, "word": " هي", "probability": 0.9404296875}, {"start": 140.03, "end": 140.67, "word": " ممكن", "probability": 0.986083984375}, {"start": 140.67, "end": 141.03, "word": " انها", "probability": 0.714111328125}, {"start": 141.03, "end": 141.77, "word": " تمسكوه", "probability": 0.98955078125}, {"start": 141.77, "end": 142.33, "word": " describe", "probability": 0.51171875}, {"start": 142.33, "end": 142.81, "word": " each", "probability": 0.96337890625}, {"start": 142.81, "end": 142.97, "word": " of", "probability": 0.9755859375}, {"start": 142.97, "end": 143.11, "word": " the", "probability": 0.9130859375}, {"start": 143.11, "end": 143.45, "word": " following", "probability": 0.83154296875}, {"start": 143.45, "end": 143.97, "word": " events", "probability": 0.8681640625}, {"start": 143.97, "end": 144.25, "word": " as", "probability": 0.97216796875}, {"start": 144.25, "end": 144.47, "word": " an", "probability": 0.9326171875}, {"start": 144.47, "end": 144.93, "word": " elastic", "probability": 0.95654296875}, {"start": 144.93, "end": 145.33, "word": " or", 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now consider two objects that undergoes an elastic head-on collision in this situation", "tokens": [3615, 8592, 7649, 1975, 8315, 37495, 22653, 7251, 30544, 43242, 8315, 6156, 28543, 8978, 41950, 995, 28671, 31439, 264, 6565, 16247, 7435, 3794, 10943, 29538, 5296, 11296, 8717, 36178, 9122, 2304, 10632, 16712, 5016, 31747, 8717, 36178, 9673, 28543, 9640, 4032, 2304, 3615, 995, 4117, 3794, 3660, 8978, 2423, 9307, 7435, 40294, 8717, 7435, 37977, 2423, 17115, 24644, 2423, 17115, 24644, 586, 1949, 732, 6565, 300, 26426, 279, 364, 17115, 1378, 12, 266, 24644, 294, 341, 2590], "avg_logprob": -0.15685095695348886, "compression_ratio": 1.602803738317757, "no_speech_prob": 1.1920928955078125e-07, "words": [{"start": 371.13, "end": 372.23, "word": "عشان", "probability": 0.81103515625}, {"start": 372.23, "end": 372.63, "word": " انا", "probability": 0.67431640625}, {"start": 372.63, "end": 373.17, "word": " يعني", "probability": 0.86767578125}, {"start": 373.17, "end": 373.45, "word": " يكون", 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0.847412109375}, {"start": 442.03, "end": 442.55, "word": " التاني", "probability": 0.8782552083333334}], "temperature": 1.0}, {"id": 19, "seek": 47305, "start": 443.83, "end": 473.05, "text": "م2 بتحرك بسرعة v2 initial before and طبعا هذا before the collision نيجي لتانى بعد التصادم اصطدمه بعد التصادم الاولانى طبعا انطلق بسرعة v1 final و 10 انطلق بسرعة v2 final after the collision the object velocity it changed اتغيرت but both the energy and momentum of the system are conserved في هذه الحالة ال momentum conserved وتقط الحركة is conserved", "tokens": [2304, 17, 39894, 5016, 31747, 4724, 3794, 2288, 27884, 371, 17, 5883, 949, 293, 23032, 3555, 3615, 995, 23758, 949, 264, 24644, 8717, 1829, 7435, 1829, 5296, 2655, 7649, 7578, 39182, 16712, 9381, 18513, 2304, 1975, 9381, 9566, 40448, 3224, 39182, 16712, 9381, 18513, 2304, 42963, 12610, 7649, 7578, 23032, 3555, 3615, 995, 16472, 9566, 1211, 4587, 4724, 3794, 2288, 27884, 371, 16, 2572, 4032, 1266, 16472, 9566, 1211, 4587, 4724, 3794, 2288, 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448.07, "word": " طبعا", "probability": 0.9013671875}, {"start": 448.07, "end": 448.21, "word": " هذا", "probability": 0.59228515625}, {"start": 448.21, "end": 448.45, "word": " before", "probability": 0.87451171875}, {"start": 448.45, "end": 448.63, "word": " the", "probability": 0.6796875}, {"start": 448.63, "end": 449.13, "word": " collision", "probability": 0.93359375}, {"start": 449.13, "end": 450.05, "word": " نيجي", "probability": 0.783935546875}, {"start": 450.05, "end": 451.29, "word": " لتانى", "probability": 0.677001953125}, {"start": 451.29, "end": 451.59, "word": " بعد", "probability": 0.75830078125}, {"start": 451.59, "end": 452.11, "word": " التصادم", "probability": 0.9747314453125}, {"start": 452.11, "end": 452.73, "word": " اصطدمه", "probability": 0.76982421875}, {"start": 452.73, "end": 453.29, "word": " بعد", "probability": 0.80712890625}, {"start": 453.29, "end": 454.41, "word": " التصادم", "probability": 0.993896484375}, {"start": 454.41, "end": 455.43, "word": " الاولانى", "probability": 0.82513427734375}, {"start": 455.43, "end": 455.91, "word": " طبعا", "probability": 0.984619140625}, {"start": 455.91, "end": 456.99, "word": " انطلق", "probability": 0.9598388671875}, {"start": 456.99, "end": 457.33, "word": " بسرعة", "probability": 0.9720458984375}, {"start": 457.33, "end": 457.69, "word": " v1", "probability": 0.90234375}, {"start": 457.69, "end": 458.15, "word": " final", "probability": 0.92138671875}, {"start": 458.15, "end": 458.37, "word": " و", "probability": 0.7998046875}, {"start": 458.37, "end": 458.55, "word": " 10", "probability": 0.393310546875}, {"start": 458.55, "end": 458.89, "word": " انطلق", "probability": 0.9669189453125}, {"start": 458.89, "end": 459.19, "word": " بسرعة", "probability": 0.9774169921875}, {"start": 459.19, "end": 459.55, "word": " v2", "probability": 0.978271484375}, {"start": 459.55, "end": 460.09, "word": " final", "probability": 0.93115234375}, {"start": 460.09, "end": 460.97, "word": " after", "probability": 0.7841796875}, {"start": 460.97, "end": 461.21, "word": " the", "probability": 0.91845703125}, {"start": 461.21, "end": 461.55, "word": " collision", "probability": 0.9482421875}, {"start": 461.55, "end": 461.75, "word": " the", "probability": 0.72216796875}, {"start": 461.75, "end": 462.17, "word": " object", "probability": 0.9658203125}, {"start": 462.17, "end": 462.79, "word": " velocity", "probability": 0.6181640625}, {"start": 462.79, "end": 463.15, "word": " it", "probability": 0.431396484375}, {"start": 463.15, "end": 463.61, "word": " changed", "probability": 0.7333984375}, {"start": 463.61, "end": 464.35, "word": " اتغيرت", "probability": 0.915234375}, {"start": 464.35, "end": 464.89, "word": " but", "probability": 0.748046875}, {"start": 464.89, "end": 465.33, "word": " both", "probability": 0.90966796875}, {"start": 465.33, "end": 465.51, "word": " the", "probability": 0.89892578125}, {"start": 465.51, "end": 465.87, "word": " energy", "probability": 0.95166015625}, {"start": 465.87, "end": 466.19, "word": " and", "probability": 0.94775390625}, {"start": 466.19, "end": 466.51, "word": " momentum", "probability": 0.96435546875}, {"start": 466.51, "end": 466.85, "word": " of", "probability": 0.9697265625}, {"start": 466.85, "end": 467.07, "word": " the", "probability": 0.919921875}, {"start": 467.07, "end": 467.47, "word": " system", "probability": 0.9541015625}, {"start": 467.47, "end": 467.77, "word": " are", "probability": 0.9365234375}, {"start": 467.77, "end": 468.47, "word": " conserved", "probability": 0.86083984375}, {"start": 468.47, "end": 469.09, "word": " في", "probability": 0.8349609375}, {"start": 469.09, "end": 469.25, "word": " هذه", "probability": 0.407470703125}, {"start": 469.25, "end": 469.81, "word": " الحالة", "probability": 0.9807942708333334}, {"start": 469.81, "end": 470.25, "word": " ال", "probability": 0.7080078125}, {"start": 470.25, "end": 470.55, "word": " momentum", "probability": 0.978515625}, {"start": 470.55, "end": 471.21, "word": " conserved", "probability": 0.77587890625}, {"start": 471.21, "end": 471.51, "word": " وتقط", "probability": 0.4346923828125}, {"start": 471.51, "end": 472.05, "word": " الحركة", "probability": 0.8206380208333334}, {"start": 472.05, "end": 472.31, "word": " is", "probability": 0.89453125}, {"start": 472.31, "end": 473.05, "word": " conserved", "probability": 0.90234375}], "temperature": 1.0}, {"id": 20, "seek": 49478, "start": 475.06, "end": 494.78, "text": "we can write these conditions as الان في عندي M1 V1 initial و M2 V2 initial بتساوي M1 V1 final زايد M2 V2 final هذا بالنسبة لقانون كمية التحرك أساس أنها محفوظة وبستخدم قانون اللي هي الطاقة الحركة", "tokens": [826, 393, 2464, 613, 4487, 382, 2423, 7649, 8978, 18871, 16254, 376, 16, 691, 16, 5883, 4032, 376, 17, 691, 17, 5883, 39894, 3794, 995, 45865, 376, 16, 691, 16, 2572, 30767, 995, 25708, 376, 17, 691, 17, 2572, 23758, 20666, 1863, 35457, 3660, 5296, 4587, 7649, 11536, 9122, 2304, 10632, 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"word": " عندي", "probability": 0.837158203125}, {"start": 478.8, "end": 479.2, "word": " M1", "probability": 0.7783203125}, {"start": 479.2, "end": 479.62, "word": " V1", "probability": 0.6859130859375}, {"start": 479.62, "end": 480.16, "word": " initial", "probability": 0.8125}, {"start": 480.16, "end": 480.76, "word": " و", "probability": 0.365966796875}, {"start": 480.76, "end": 481.14, "word": " M2", "probability": 0.80224609375}, {"start": 481.14, "end": 481.52, "word": " V2", "probability": 0.973388671875}, {"start": 481.52, "end": 481.96, "word": " initial", "probability": 0.931640625}, {"start": 481.96, "end": 482.38, "word": " بتساوي", "probability": 0.5850830078125}, {"start": 482.38, "end": 482.88, "word": " M1", "probability": 0.96044921875}, {"start": 482.88, "end": 483.34, "word": " V1", "probability": 0.966064453125}, {"start": 483.34, "end": 483.72, "word": " final", "probability": 0.86181640625}, {"start": 483.72, "end": 483.96, "word": " زايد", "probability": 0.5980631510416666}, {"start": 483.96, "end": 484.42, "word": " M2", "probability": 0.991455078125}, {"start": 484.42, "end": 485.02, "word": " V2", "probability": 0.98974609375}, {"start": 485.02, "end": 485.7, "word": " final", "probability": 0.84423828125}, {"start": 485.7, "end": 487.14, "word": " هذا", "probability": 0.77099609375}, {"start": 487.14, "end": 487.58, "word": " بالنسبة", "probability": 0.8729248046875}, {"start": 487.58, "end": 488.22, "word": " لقانون", "probability": 0.82958984375}, {"start": 488.22, "end": 488.56, "word": " كمية", "probability": 0.9860026041666666}, {"start": 488.56, "end": 489.18, "word": " التحرك", "probability": 0.9933268229166666}, {"start": 489.18, "end": 489.5, "word": " أساس", "probability": 0.7130533854166666}, {"start": 489.5, "end": 489.72, "word": " أنها", "probability": 0.7376708984375}, {"start": 489.72, "end": 490.34, "word": " محفوظة", "probability": 0.978515625}, {"start": 490.34, "end": 491.22, "word": " وبستخدم", "probability": 0.816162109375}, {"start": 491.22, "end": 491.84, "word": " قانون", "probability": 0.9923502604166666}, {"start": 491.84, "end": 492.58, "word": " اللي", "probability": 0.836181640625}, {"start": 492.58, "end": 493.04, "word": " هي", "probability": 0.8984375}, {"start": 493.04, "end": 494.08, "word": " الطاقة", "probability": 0.87548828125}, {"start": 494.08, "end": 494.78, "word": " الحركة", "probability": 0.9427083333333334}], "temperature": 1.0}, {"id": 21, "seek": 52440, "start": 496.44, "end": 524.4, "text": "where v is positive طبعا في هذا الحالة if an object move to the right نعتبر أنه السرعة موجة بقى إذا اتحرك الجسم لليمين والسرعة سالة بقى إذا اتحرك إلى اليسار cancelling بالنسبة للتانية طبعا بضيع الانصاص بضيع الانصاص من المعادلة بعدين باخد ال M1 مشترك هي ال M1 باخد هذا الحد مع هذا الحد يجي من ناحية تانية بيصير سالب", "tokens": [1992, 371, 307, 3353, 23032, 3555, 3615, 995, 8978, 23758, 21542, 6027, 3660, 498, 364, 2657, 1286, 281, 264, 558, 8717, 34268, 26890, 14739, 3224, 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"probability": 0.58544921875}, {"start": 497.16, "end": 497.44, "word": " is", "probability": 0.74560546875}, {"start": 497.44, "end": 498.52, "word": " positive", "probability": 0.60888671875}, {"start": 498.52, "end": 499.28, "word": " طبعا", "probability": 0.8404541015625}, {"start": 499.28, "end": 499.38, "word": " في", "probability": 0.69775390625}, {"start": 499.38, "end": 499.5, "word": " هذا", "probability": 0.273681640625}, {"start": 499.5, "end": 500.1, "word": " الحالة", "probability": 0.9889322916666666}, {"start": 500.1, "end": 500.56, "word": " if", "probability": 0.865234375}, {"start": 500.56, "end": 500.74, "word": " an", "probability": 0.82763671875}, {"start": 500.74, "end": 501.08, "word": " object", "probability": 0.98046875}, {"start": 501.08, "end": 501.32, "word": " move", "probability": 0.5048828125}, {"start": 501.32, "end": 501.5, "word": " to", "probability": 0.9501953125}, {"start": 501.5, "end": 501.62, "word": " the", "probability": 0.890625}, {"start": 501.62, "end": 501.88, "word": " right", "probability": 0.93115234375}, {"start": 501.88, "end": 502.36, "word": " نعتبر", "probability": 0.8046875}, {"start": 502.36, "end": 502.8, "word": " أنه", "probability": 0.631591796875}, {"start": 502.8, "end": 503.54, "word": " السرعة", "probability": 0.9080403645833334}, {"start": 503.54, "end": 504.28, "word": " موجة", "probability": 0.8997395833333334}, {"start": 504.28, "end": 504.42, "word": " بقى", "probability": 0.7679036458333334}, {"start": 504.42, "end": 504.54, "word": " إذا", "probability": 0.923828125}, {"start": 504.54, "end": 504.88, "word": " اتحرك", "probability": 0.891845703125}, {"start": 504.88, "end": 505.18, "word": " الجسم", "probability": 0.929443359375}, {"start": 505.18, "end": 505.76, "word": " لليمين", "probability": 0.8439127604166666}, {"start": 505.76, "end": 506.5, "word": " والسرعة", "probability": 0.8309326171875}, {"start": 506.5, "end": 506.84, "word": " سالة", "probability": 0.80419921875}, {"start": 506.84, "end": 506.94, "word": " بقى", "probability": 0.89697265625}, {"start": 506.94, "end": 507.02, "word": " إذا", "probability": 0.988037109375}, {"start": 507.02, "end": 507.4, "word": " اتحرك", "probability": 0.9195556640625}, {"start": 507.4, "end": 507.6, "word": " إلى", "probability": 0.423583984375}, {"start": 507.6, "end": 508.3, "word": " اليسار", "probability": 0.9952799479166666}, {"start": 508.3, "end": 509.98, "word": " cancelling", "probability": 0.751953125}, {"start": 509.98, "end": 510.42, "word": " بالنسبة", "probability": 0.9732666015625}, {"start": 510.42, "end": 511.08, "word": " للتانية", "probability": 0.967529296875}, {"start": 511.08, "end": 512.24, "word": " طبعا", "probability": 0.94970703125}, {"start": 512.24, "end": 513.02, "word": " بضيع", "probability": 0.841796875}, {"start": 513.02, "end": 513.76, "word": " الانصاص", "probability": 0.86334228515625}, {"start": 513.76, "end": 515.06, "word": " بضيع", "probability": 0.8152669270833334}, {"start": 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520.84, "word": " هذا", "probability": 0.912109375}, {"start": 520.84, "end": 521.32, "word": " الحد", "probability": 0.989501953125}, {"start": 521.32, "end": 522.08, "word": " مع", "probability": 0.97265625}, {"start": 522.08, "end": 522.3, "word": " هذا", "probability": 0.9775390625}, {"start": 522.3, "end": 522.76, "word": " الحد", "probability": 0.990478515625}, {"start": 522.76, "end": 523.08, "word": " يجي", "probability": 0.7545572916666666}, {"start": 523.08, "end": 523.14, "word": " من", "probability": 0.2529296875}, {"start": 523.14, "end": 523.44, "word": " ناحية", "probability": 0.923828125}, {"start": 523.44, "end": 523.66, "word": " تانية", "probability": 0.744140625}, {"start": 523.66, "end": 523.94, "word": " بيصير", "probability": 0.72015380859375}, {"start": 523.94, "end": 524.4, "word": " سالب", "probability": 0.9739583333333334}], "temperature": 1.0}, {"id": 22, "seek": 55134, "start": 524.68, "end": 551.34, "text": "m1 v1 initial تربيع ناقص m1 v1 final تربيع ناقص 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"word": " الجهتين", "probability": 0.9189453125}], "temperature": 1.0}, {"id": 23, "seek": 57894, "start": 551.76, "end": 578.94, "text": "بعدين separate the term containing M1 and M2 in the equation بدأ أفصل المعادلة اللي فيها M1 و اللي فيها M2 اذا M1 V1 initial ناقص V1 final سواء M2 V2 final ناقص V2 initial وبعدين بقسمها على المعادلة 6.13 بطلع عندي V1 initial زائد V1 final بسوا V2 final زائد V2 initial", "tokens": [3555, 22488, 9957, 4994, 264, 1433, 19273, 376, 16, 293, 376, 17, 294, 264, 5367, 47525, 10721, 5551, 5172, 36520, 9673, 3615, 18513, 37977, 13672, 1829, 8978, 11296, 376, 16, 4032, 13672, 1829, 8978, 11296, 376, 17, 1975, 15730, 376, 16, 691, 16, 5883, 8717, 995, 4587, 9381, 691, 16, 2572, 8608, 2407, 16606, 376, 17, 691, 17, 2572, 8717, 995, 4587, 9381, 691, 17, 5883, 46599, 22488, 9957, 4724, 4587, 38251, 11296, 15844, 9673, 3615, 18513, 37977, 1386, 13, 7668, 4724, 9566, 1211, 3615, 18871, 16254, 691, 16, 5883, 30767, 16373, 3215, 691, 16, 2572, 4724, 3794, 14407, 691, 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0.9072265625}, {"start": 567.4, "end": 569.96, "word": " وبعدين", "probability": 0.812744140625}, {"start": 569.96, "end": 570.82, "word": " بقسمها", "probability": 0.82080078125}, {"start": 570.82, "end": 571.22, "word": " على", "probability": 0.65087890625}, {"start": 571.22, "end": 571.78, "word": " المعادلة", "probability": 0.989013671875}, {"start": 571.78, "end": 572.04, "word": " 6", "probability": 0.84814453125}, {"start": 572.04, "end": 572.68, "word": ".13", "probability": 0.5950927734375}, {"start": 572.68, "end": 573.48, "word": " بطلع", "probability": 0.8486328125}, {"start": 573.48, "end": 573.84, "word": " عندي", "probability": 0.76171875}, {"start": 573.84, "end": 574.74, "word": " V1", "probability": 0.9755859375}, {"start": 574.74, "end": 575.32, "word": " initial", "probability": 0.93505859375}, {"start": 575.32, "end": 576.16, "word": " زائد", "probability": 0.7032063802083334}, {"start": 576.16, "end": 576.56, "word": " V1", "probability": 0.99169921875}, {"start": 576.56, "end": 576.88, "word": " final", "probability": 0.92041015625}, {"start": 576.88, "end": 577.2, "word": " بسوا", "probability": 0.6986490885416666}, {"start": 577.2, "end": 577.6, "word": " V2", "probability": 0.86767578125}, {"start": 577.6, "end": 577.94, "word": " final", "probability": 0.86328125}, {"start": 577.94, "end": 578.2, "word": " زائد", "probability": 0.9288736979166666}, {"start": 578.2, "end": 578.52, "word": " V2", "probability": 0.99560546875}, {"start": 578.52, "end": 578.94, "word": " initial", "probability": 0.9013671875}], "temperature": 1.0}, {"id": 24, "seek": 60832, "start": 579.52, "end": 608.32, "text": "أذا ممكن أستخدم القانون النهائي بهذا الشكل v1 initial ناقص v2 initial جيبنا هذا من ناحية التانية بتساوي ناقص v1 final ناقص v2 final هذا عشان أوجد اللي هو v1 final وv2 final هذا المعادلة in combination طبعا بستخدمها بوسطة معادلة 16 و بنحل و بنوجد طبعا اللي هي v1 final وv2 final في حالة", "tokens": [10721, 15730, 3714, 43020, 5551, 14851, 9778, 40448, 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"probability": 0.91376953125}, {"start": 600.68, "end": 601.12, "word": " بوسطة", "probability": 0.8531494140625}, {"start": 601.12, "end": 601.5, "word": " معادلة", "probability": 0.986328125}, {"start": 601.5, "end": 602.08, "word": " 16", "probability": 0.8193359375}, {"start": 602.08, "end": 602.88, "word": " و", "probability": 0.70263671875}, {"start": 602.88, "end": 603.36, "word": " بنحل", "probability": 0.7774251302083334}, {"start": 603.36, "end": 603.54, "word": " و", "probability": 0.7587890625}, {"start": 603.54, "end": 604.12, "word": " بنوجد", "probability": 0.908203125}, {"start": 604.12, "end": 605.06, "word": " طبعا", "probability": 0.9329833984375}, {"start": 605.06, "end": 605.24, "word": " اللي", "probability": 0.93798828125}, {"start": 605.24, "end": 605.52, "word": " هي", "probability": 0.9365234375}, {"start": 605.52, "end": 606.66, "word": " v1", "probability": 0.7373046875}, {"start": 606.66, "end": 607.02, "word": " final", "probability": 0.962890625}, {"start": 607.02, "end": 607.36, "word": " وv2", "probability": 0.8810221354166666}, {"start": 607.36, "end": 607.68, "word": " final", "probability": 0.9521484375}, {"start": 607.68, "end": 607.84, "word": " في", "probability": 0.94287109375}, {"start": 607.84, "end": 608.32, "word": " حالة", "probability": 0.9921875}], "temperature": 1.0}, {"id": 25, "seek": 62711, "start": 608.53, "end": 627.11, "text": "الـ Elastic Collision و Perfect Elastic Collision نجي نلاقي كيف انا بنحل اللي هي ال problem solving strategy قليلة حل المسائل the following procedure is recommended for solving بعض طبعا الغلاحظات لحل المسائل", "tokens": [6027, 39184, 2699, 2750, 4586, 1991, 4032, 10246, 2699, 2750, 4586, 1991, 8717, 7435, 1829, 8717, 15040, 38436, 9122, 33911, 1975, 8315, 44945, 5016, 1211, 13672, 1829, 39896, 2423, 1154, 12606, 5206, 12174, 20292, 37977, 11331, 1211, 9673, 3794, 16373, 1211, 264, 3480, 10747, 307, 9628, 337, 12606, 45030, 11242, 23032, 3555, 3615, 995, 6024, 118, 15040, 5016, 19913, 9307, 5296, 5016, 1211, 9673, 3794, 16373, 1211], "avg_logprob": -0.31456802566261854, "compression_ratio": 1.481283422459893, "no_speech_prob": 2.5033950805664062e-06, "words": [{"start": 608.53, "end": 608.83, "word": "الـ", "probability": 0.3822021484375}, {"start": 608.83, "end": 609.39, "word": " Elastic", "probability": 0.723876953125}, {"start": 609.39, "end": 610.13, "word": " Collision", "probability": 0.81396484375}, {"start": 610.13, "end": 611.59, "word": " و", "probability": 0.491455078125}, {"start": 611.59, "end": 612.25, "word": " Perfect", "probability": 0.51220703125}, {"start": 612.25, "end": 612.83, "word": " Elastic", "probability": 0.93994140625}, {"start": 612.83, "end": 613.35, "word": " Collision", "probability": 0.971435546875}, {"start": 613.35, "end": 614.09, "word": " نجي", "probability": 0.6228841145833334}, {"start": 614.09, "end": 614.35, "word": " نلاقي", "probability": 0.8349609375}, {"start": 614.35, "end": 614.69, "word": " كيف", "probability": 0.908447265625}, {"start": 614.69, "end": 614.87, "word": " انا", "probability": 0.59381103515625}, {"start": 614.87, "end": 615.43, "word": " بنحل", "probability": 0.8038736979166666}, {"start": 615.43, "end": 615.61, "word": " اللي", "probability": 0.6640625}, {"start": 615.61, "end": 615.77, "word": " هي", "probability": 0.83447265625}, {"start": 615.77, "end": 615.91, "word": " ال", "probability": 0.591796875}, {"start": 615.91, "end": 616.23, "word": " problem", "probability": 0.55322265625}, {"start": 616.23, "end": 616.89, "word": " solving", "probability": 0.7998046875}, {"start": 616.89, "end": 617.47, "word": " strategy", "probability": 0.2685546875}, {"start": 617.47, "end": 618.43, "word": " قليلة", "probability": 0.493408203125}, {"start": 618.43, "end": 618.91, "word": " حل", "probability": 0.97509765625}, {"start": 618.91, "end": 619.75, "word": " المسائل", "probability": 0.913330078125}, {"start": 619.75, "end": 620.45, "word": " the", "probability": 0.175537109375}, {"start": 620.45, "end": 620.77, "word": " following", "probability": 0.8681640625}, {"start": 620.77, "end": 621.49, "word": " procedure", "probability": 0.9462890625}, {"start": 621.49, "end": 621.99, "word": " is", "probability": 0.9501953125}, {"start": 621.99, "end": 622.71, "word": " recommended", "probability": 0.72265625}, {"start": 622.71, "end": 623.09, "word": " for", "probability": 0.95703125}, {"start": 623.09, "end": 623.59, "word": " solving", "probability": 0.958984375}, {"start": 623.59, "end": 624.05, "word": " بعض", "probability": 0.9365234375}, {"start": 624.05, "end": 625.07, "word": " طبعا", "probability": 0.86981201171875}, {"start": 625.07, "end": 625.93, "word": " الغلاحظات", "probability": 0.7239176432291666}, {"start": 625.93, "end": 626.37, "word": " لحل", "probability": 0.9749348958333334}, {"start": 626.37, "end": 627.11, "word": " المسائل", "probability": 0.9786376953125}], "temperature": 1.0}, {"id": 26, "seek": 65035, "start": 627.19, "end": 650.35, "text": "بتتعلق بيه التصادمات بين جسمين أول حاجة بنختار coordinate بنختار محاور بختار محاور معين سواء X أو Y بعدين برسم diagram sketch the problem representing the auto object برسم الجسمين و برسم اللي هي السرعات و براعي أنه في عندي أنا اليمين موجب و الشمال سالب", "tokens": [3555, 2655, 2655, 30241, 4587, 4724, 1829, 3224, 16712, 9381, 18513, 2304, 9307, 49374, 10874, 38251, 9957, 5551, 12610, 11331, 26108, 3660, 44945, 46456, 9640, 15670, 44945, 46456, 9640, 3714, 5016, 995, 13063, 4724, 46456, 9640, 3714, 5016, 995, 13063, 20449, 9957, 8608, 2407, 16606, 1783, 34051, 398, 39182, 9957, 4724, 2288, 38251, 10686, 12325, 264, 1154, 13460, 264, 8399, 2657, 4724, 2288, 38251, 25724, 38251, 9957, 4032, 4724, 2288, 38251, 13672, 1829, 39896, 21136, 2288, 3615, 9307, 4032, 4724, 23557, 3615, 1829, 14739, 3224, 8978, 18871, 16254, 41850, 45595, 2304, 9957, 3714, 29245, 3555, 4032, 25124, 2304, 6027, 8608, 6027, 3555], "avg_logprob": -0.18856189349322644, "compression_ratio": 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{"start": 635.53, "end": 636.33, "word": " بختار", "probability": 0.8990885416666666}, {"start": 636.33, "end": 636.69, "word": " محاور", "probability": 0.981201171875}, {"start": 636.69, "end": 637.01, "word": " معين", "probability": 0.9892578125}, {"start": 637.01, "end": 637.29, "word": " سواء", "probability": 0.97412109375}, {"start": 637.29, "end": 637.51, "word": " X", "probability": 0.496826171875}, {"start": 637.51, "end": 637.75, "word": " أو", "probability": 0.77392578125}, {"start": 637.75, "end": 638.07, "word": " Y", "probability": 0.98486328125}, {"start": 638.07, "end": 638.97, "word": " بعدين", "probability": 0.791748046875}, {"start": 638.97, "end": 639.53, "word": " برسم", "probability": 0.8761393229166666}, {"start": 639.53, "end": 639.99, "word": " diagram", "probability": 0.483642578125}, {"start": 639.99, "end": 640.55, "word": " sketch", "probability": 0.80810546875}, {"start": 640.55, "end": 640.81, "word": " the", "probability": 0.48876953125}, {"start": 640.81, "end": 641.37, "word": " problem", "probability": 0.92724609375}, {"start": 641.37, "end": 642.03, "word": " representing", "probability": 0.80322265625}, {"start": 642.03, "end": 642.31, "word": " the", "probability": 0.88720703125}, {"start": 642.31, "end": 642.53, "word": " auto", "probability": 0.6796875}, {"start": 642.53, "end": 642.91, "word": " object", "probability": 0.94189453125}, {"start": 642.91, "end": 643.37, "word": " برسم", "probability": 0.9016927083333334}, {"start": 643.37, "end": 644.09, "word": " الجسمين", "probability": 0.984375}, {"start": 644.09, "end": 644.57, "word": " و", "probability": 0.66455078125}, {"start": 644.57, "end": 645.05, "word": " برسم", "probability": 0.9544270833333334}, {"start": 645.05, "end": 645.35, "word": " اللي", "probability": 0.822998046875}, {"start": 645.35, "end": 645.55, "word": " هي", "probability": 0.83642578125}, {"start": 645.55, "end": 646.21, "word": " السرعات", "probability": 0.9227294921875}, {"start": 646.21, "end": 646.77, "word": " و", "probability": 0.865234375}, {"start": 646.77, "end": 647.19, "word": " براعي", "probability": 0.7584228515625}, {"start": 647.19, "end": 647.61, "word": " أنه", "probability": 0.5577392578125}, {"start": 647.61, "end": 647.73, "word": " في", "probability": 0.8994140625}, {"start": 647.73, "end": 648.03, "word": " عندي", "probability": 0.7021484375}, {"start": 648.03, "end": 648.29, "word": " أنا", "probability": 0.56591796875}, {"start": 648.29, "end": 649.09, "word": " اليمين", "probability": 0.7001953125}, {"start": 649.09, "end": 649.41, "word": " موجب", "probability": 0.9684244791666666}, {"start": 649.41, "end": 649.49, "word": " و", "probability": 0.91357421875}, {"start": 649.49, "end": 649.83, "word": " الشمال", "probability": 0.8702799479166666}, {"start": 649.83, "end": 650.35, "word": " سالب", "probability": 0.9728190104166666}], "temperature": 1.0}, {"id": 27, "seek": 68037, "start": 651.79, "end": 680.37, "text": "Conservation of momentum برضه بستخدم قانون Conservation of momentum قانون حفظ كمية التحرك بقى إذا كان عندي جسمين بنكتب M1V1 initial و M2V2 initial بنستخدم M1V1 final و M2V2 final بنستخدم ايضا ال بعد هي Conservation of energy قانون حفظ الطاقة if the collision is elastic إذا ال collision كان مرن بقى أكتب ال general expression اللي هو القانون العام لل total energy before and after the collision", "tokens": [34, 892, 6864, 295, 11244, 4724, 43042, 3224, 4724, 14851, 9778, 40448, 12174, 7649, 11536, 40131, 295, 11244, 12174, 7649, 11536, 11331, 5172, 19913, 9122, 2304, 10632, 16712, 5016, 31747, 4724, 4587, 7578, 11933, 15730, 25961, 18871, 16254, 10874, 38251, 9957, 44945, 4117, 2655, 3555, 376, 16, 53, 16, 5883, 4032, 376, 17, 53, 17, 5883, 44945, 14851, 9778, 40448, 376, 16, 53, 16, 2572, 4032, 376, 17, 53, 17, 2572, 44945, 14851, 9778, 40448, 1975, 1829, 11242, 995, 2423, 39182, 39896, 40131, 295, 2281, 12174, 7649, 11536, 11331, 5172, 19913, 41950, 995, 28671, 498, 264, 24644, 307, 17115, 11933, 15730, 2423, 24644, 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"end": 655.83, "word": " momentum", "probability": 0.9453125}, {"start": 655.83, "end": 656.23, "word": " قانون", "probability": 0.9490559895833334}, {"start": 656.23, "end": 656.53, "word": " حفظ", "probability": 0.97998046875}, {"start": 656.53, "end": 656.81, "word": " كمية", "probability": 0.8400065104166666}, {"start": 656.81, "end": 657.47, "word": " التحرك", "probability": 0.9908854166666666}, {"start": 657.47, "end": 658.69, "word": " بقى", "probability": 0.880859375}, {"start": 658.69, "end": 658.93, "word": " إذا", "probability": 0.796875}, {"start": 658.93, "end": 659.11, "word": " كان", "probability": 0.91650390625}, {"start": 659.11, "end": 659.31, "word": " عندي", "probability": 0.863525390625}, {"start": 659.31, "end": 659.79, "word": " جسمين", "probability": 0.89794921875}, {"start": 659.79, "end": 660.25, "word": " بنكتب", "probability": 0.9500732421875}, {"start": 660.25, "end": 661.01, "word": " M1V1", "probability": 0.7080078125}, {"start": 661.01, "end": 661.43, "word": " initial", "probability": 0.671875}, {"start": 661.43, "end": 661.55, "word": " و", "probability": 0.93212890625}, {"start": 661.55, "end": 662.21, "word": " M2V2", "probability": 0.8612060546875}, {"start": 662.21, "end": 662.59, "word": " initial", "probability": 0.9326171875}, {"start": 662.59, "end": 662.93, "word": " بنستخدم", "probability": 0.602783203125}, {"start": 662.93, "end": 663.77, "word": " M1V1", "probability": 0.912841796875}, {"start": 663.77, "end": 664.21, "word": " final", "probability": 0.73046875}, {"start": 664.21, "end": 664.71, "word": " و", "probability": 0.98486328125}, {"start": 664.71, "end": 665.53, "word": " M2V2", "probability": 0.961669921875}, {"start": 665.53, "end": 666.21, "word": " final", "probability": 0.888671875}, {"start": 666.21, "end": 667.37, "word": " بنستخدم", "probability": 0.9205322265625}, {"start": 667.37, "end": 667.65, "word": " ايضا", "probability": 0.80377197265625}, {"start": 667.65, "end": 667.73, "word": " ال", 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"probability": 0.96484375}, {"start": 672.53, "end": 673.03, "word": " elastic", "probability": 0.9521484375}, {"start": 673.03, "end": 673.25, "word": " إذا", "probability": 0.78369140625}, {"start": 673.25, "end": 673.37, "word": " ال", "probability": 0.83984375}, {"start": 673.37, "end": 673.63, "word": " collision", "probability": 0.888671875}, {"start": 673.63, "end": 673.97, "word": " كان", "probability": 0.9560546875}, {"start": 673.97, "end": 674.93, "word": " مرن", "probability": 0.8924153645833334}, {"start": 674.93, "end": 675.41, "word": " بقى", "probability": 0.9114583333333334}, {"start": 675.41, "end": 675.93, "word": " أكتب", "probability": 0.911376953125}, {"start": 675.93, "end": 676.05, "word": " ال", "probability": 0.95654296875}, {"start": 676.05, "end": 676.37, "word": " general", "probability": 0.85595703125}, {"start": 676.37, "end": 677.25, "word": " expression", "probability": 0.88525390625}, {"start": 677.25, "end": 677.47, "word": " اللي", "probability": 0.816162109375}, {"start": 677.47, "end": 677.57, "word": " هو", "probability": 0.994140625}, {"start": 677.57, "end": 677.91, "word": " القانون", "probability": 0.98974609375}, {"start": 677.91, "end": 678.23, "word": " العام", "probability": 0.989013671875}, {"start": 678.23, "end": 678.39, "word": " لل", "probability": 0.86328125}, {"start": 678.39, "end": 678.65, "word": " total", "probability": 0.7236328125}, {"start": 678.65, "end": 679.03, "word": " energy", "probability": 0.96435546875}, {"start": 679.03, "end": 679.37, "word": " before", "probability": 0.90234375}, {"start": 679.37, "end": 679.59, "word": " and", "probability": 0.96044921875}, {"start": 679.59, "end": 679.83, "word": " after", "probability": 0.861328125}, {"start": 679.83, "end": 680.01, "word": " the", "probability": 0.90234375}, {"start": 680.01, "end": 680.37, "word": " collision", "probability": 0.9091796875}], "temperature": 1.0}, {"id": 28, "seek": 69099, "start": 681.01, "end": 690.99, "text": "وبعدين بساوي المعادلتين في بعض ممكن نحلل ممكن نقسمهم على بعض طبعا skype this step if the collision is not perfect and elastic", "tokens": [37746, 22488, 9957, 4724, 3794, 995, 45865, 9673, 3615, 18513, 1211, 2655, 9957, 8978, 45030, 11242, 3714, 43020, 8717, 5016, 1211, 1211, 3714, 43020, 8717, 4587, 38251, 16095, 15844, 45030, 11242, 23032, 3555, 3615, 995, 5443, 494, 341, 1823, 498, 264, 24644, 307, 406, 2176, 293, 17115], "avg_logprob": -0.14265949868907532, "compression_ratio": 1.2971014492753623, "no_speech_prob": 2.980232238769531e-07, "words": [{"start": 681.01, "end": 681.53, "word": "وبعدين", "probability": 0.796142578125}, {"start": 681.53, "end": 682.05, "word": " بساوي", "probability": 0.89404296875}, {"start": 682.05, "end": 682.77, "word": " المعادلتين", "probability": 0.8914388020833334}, {"start": 682.77, "end": 682.95, "word": " في", "probability": 0.8330078125}, {"start": 682.95, "end": 683.23, "word": " بعض", "probability": 0.980224609375}, {"start": 683.23, "end": 683.49, "word": " ممكن", "probability": 0.9453125}, {"start": 683.49, "end": 684.05, "word": " نحلل", "probability": 0.970703125}, {"start": 684.05, "end": 684.37, "word": " ممكن", "probability": 0.90673828125}, {"start": 684.37, "end": 684.93, "word": " نقسمهم", "probability": 0.96044921875}, {"start": 684.93, "end": 685.09, "word": " على", "probability": 0.720703125}, {"start": 685.09, "end": 685.59, "word": " بعض", "probability": 0.990966796875}, {"start": 685.59, "end": 687.11, "word": " طبعا", "probability": 0.8712158203125}, {"start": 687.11, "end": 688.19, "word": " skype", "probability": 0.832275390625}, {"start": 688.19, "end": 688.45, "word": " this", "probability": 0.63623046875}, {"start": 688.45, "end": 688.79, "word": " step", "probability": 0.67333984375}, {"start": 688.79, "end": 688.99, "word": " if", "probability": 0.93310546875}, {"start": 688.99, "end": 689.13, "word": " the", "probability": 0.87109375}, {"start": 689.13, "end": 689.47, "word": " collision", "probability": 0.90869140625}, {"start": 689.47, "end": 689.73, "word": " is", "probability": 0.93115234375}, {"start": 689.73, "end": 689.95, "word": " not", "probability": 0.958984375}, {"start": 689.95, "end": 690.33, "word": " perfect", "probability": 0.9150390625}, {"start": 690.33, "end": 690.51, "word": " and", "probability": 0.481689453125}, {"start": 690.51, "end": 690.99, "word": " elastic", "probability": 0.9560546875}], "temperature": 1.0}, {"id": 29, "seek": 71416, "start": 692.94, "end": 714.16, "text": "بنحل المعادلات اللى هى طبعا معادلة خاصة بكمية التحرك معادلة خاصة بالطاقة بنحل المعادلات مع بعض و بنوجد V1 Final و V2 Final فى بعض المعادلات طبعا بنعود V1 Final بدلالة الأولى بدلالة التانى تطلع لمعادلتين المجهولين ممكن نحل V1 Final و V2 Final", "tokens": [3555, 1863, 5016, 1211, 9673, 3615, 18513, 1211, 9307, 13672, 7578, 8032, 7578, 23032, 3555, 3615, 995, 20449, 18513, 37977, 16490, 33546, 3660, 4724, 24793, 10632, 16712, 5016, 31747, 20449, 18513, 37977, 16490, 33546, 3660, 20666, 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"end": 695.24, "word": " طبعا", "probability": 0.83099365234375}, {"start": 695.24, "end": 695.62, "word": " معادلة", "probability": 0.9485677083333334}, {"start": 695.62, "end": 695.94, "word": " خاصة", "probability": 0.9510091145833334}, {"start": 695.94, "end": 696.26, "word": " بكمية", "probability": 0.9329427083333334}, {"start": 696.26, "end": 696.88, "word": " التحرك", "probability": 0.9905598958333334}, {"start": 696.88, "end": 697.64, "word": " معادلة", "probability": 0.9065755208333334}, {"start": 697.64, "end": 698.06, "word": " خاصة", "probability": 0.9720052083333334}, {"start": 698.06, "end": 698.88, "word": " بالطاقة", "probability": 0.9854736328125}, {"start": 698.88, "end": 699.54, "word": " بنحل", "probability": 0.8876953125}, {"start": 699.54, "end": 700.0, "word": " المعادلات", "probability": 0.99091796875}, {"start": 700.0, "end": 700.14, "word": " مع", "probability": 0.8154296875}, {"start": 700.14, "end": 700.38, "word": " بعض", "probability": 0.99609375}, {"start": 700.38, "end": 700.48, "word": " و", "probability": 0.732421875}, {"start": 700.48, "end": 700.92, "word": " بنوجد", "probability": 0.89794921875}, {"start": 700.92, "end": 701.36, "word": " V1", "probability": 0.781494140625}, {"start": 701.36, "end": 701.7, "word": " Final", "probability": 0.451416015625}, {"start": 701.7, "end": 701.82, "word": " و", "probability": 0.92578125}, {"start": 701.82, "end": 702.08, "word": " V2", "probability": 0.9462890625}, {"start": 702.08, "end": 702.44, "word": " Final", "probability": 0.93701171875}, {"start": 702.44, "end": 702.64, "word": " فى", "probability": 0.747314453125}, {"start": 702.64, "end": 702.86, "word": " بعض", "probability": 0.972412109375}, {"start": 702.86, "end": 703.66, "word": " المعادلات", "probability": 0.99306640625}, {"start": 703.66, "end": 705.46, "word": " طبعا", "probability": 0.973876953125}, {"start": 705.46, "end": 705.94, "word": " بنعود", "probability": 0.857421875}, {"start": 705.94, "end": 706.72, "word": " V1", "probability": 0.980712890625}, {"start": 706.72, "end": 708.04, "word": " Final", "probability": 0.92724609375}, {"start": 708.04, "end": 708.72, "word": " بدلالة", "probability": 0.86962890625}, {"start": 708.72, "end": 709.2, "word": " الأولى", "probability": 0.6641031901041666}, {"start": 709.2, "end": 709.56, "word": " بدلالة", "probability": 0.81866455078125}, {"start": 709.56, "end": 709.84, "word": " التانى", "probability": 0.8714192708333334}, {"start": 709.84, "end": 710.24, "word": " تطلع", "probability": 0.8846435546875}, {"start": 710.24, "end": 710.9, "word": " لمعادلتين", "probability": 0.9150390625}, {"start": 710.9, "end": 711.38, "word": " المجهولين", "probability": 0.95859375}, {"start": 711.38, "end": 711.58, "word": " ممكن", "probability": 0.7080078125}, {"start": 711.58, "end": 711.9, "word": " نحل", "probability": 0.9837239583333334}, {"start": 711.9, "end": 712.28, "word": " V1", "probability": 0.979736328125}, {"start": 712.28, "end": 712.7, "word": " Final", "probability": 0.94189453125}, {"start": 712.7, "end": 713.38, "word": " و", "probability": 0.98876953125}, {"start": 713.38, "end": 713.8, "word": " V2", "probability": 0.92529296875}, {"start": 713.8, "end": 714.16, "word": " Final", "probability": 0.95556640625}], "temperature": 1.0}, {"id": 30, "seek": 73613, "start": 715.95, "end": 736.13, "text": "نشيلة example 6-6 two billiard balls of identical mass في عندي طبعا كرة صغيرة تحت ال biliardo identical mass يعني الكتة الواحدة المتمثلة بتتحرك towards each other تتحرك ناحية بعض with a positive x axis to the right ناحية اليمين", "tokens": [1863, 8592, 26895, 3660, 1365, 1386, 12, 21, 732, 2961, 72, 515, 9803, 295, 14800, 2758, 8978, 18871, 16254, 23032, 3555, 3615, 995, 9122, 25720, 20328, 17082, 48923, 6055, 33753, 2423, 20709, 12850, 14800, 2758, 37495, 22653, 33251, 2655, 3660, 2423, 14407, 24401, 3660, 9673, 39237, 12984, 37977, 39894, 2655, 5016, 31747, 3030, 1184, 661, 6055, 2655, 5016, 31747, 8717, 39319, 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mass", "probability": 0.8828125}, {"start": 720.93, "end": 721.09, "word": " في", "probability": 0.16259765625}, {"start": 721.09, "end": 721.47, "word": " عندي", "probability": 0.85888671875}, {"start": 721.47, "end": 722.33, "word": " طبعا", "probability": 0.95703125}, {"start": 722.33, "end": 722.61, "word": " كرة", "probability": 0.9091796875}, {"start": 722.61, "end": 722.97, "word": " صغيرة", "probability": 0.99267578125}, {"start": 722.97, "end": 723.21, "word": " تحت", "probability": 0.6669921875}, {"start": 723.21, "end": 723.33, "word": " ال", "probability": 0.8896484375}, {"start": 723.33, "end": 723.83, "word": " biliardo", "probability": 0.626220703125}, {"start": 723.83, "end": 725.05, "word": " identical", "probability": 0.56787109375}, {"start": 725.05, "end": 725.49, "word": " mass", "probability": 0.9033203125}, {"start": 725.49, "end": 725.79, "word": " يعني", "probability": 0.896728515625}, {"start": 725.79, "end": 726.33, "word": " الكتة", "probability": 0.88134765625}, {"start": 726.33, "end": 727.29, "word": " الواحدة", "probability": 0.9481201171875}, {"start": 727.29, "end": 728.01, "word": " المتمثلة", "probability": 0.8267822265625}, {"start": 728.01, "end": 729.41, "word": " بتتحرك", "probability": 0.9483642578125}, {"start": 729.41, "end": 730.29, "word": " towards", "probability": 0.6884765625}, {"start": 730.29, "end": 730.59, "word": " each", "probability": 0.958984375}, {"start": 730.59, "end": 730.99, "word": " other", "probability": 0.87451171875}, {"start": 730.99, "end": 731.61, "word": " تتحرك", "probability": 0.8104248046875}, {"start": 731.61, "end": 732.25, "word": " ناحية", "probability": 0.8849283854166666}, {"start": 732.25, "end": 732.85, "word": " بعض", "probability": 0.984130859375}, {"start": 732.85, "end": 733.49, "word": " with", "probability": 0.865234375}, {"start": 733.49, "end": 733.61, "word": " a", "probability": 0.630859375}, {"start": 733.61, "end": 733.87, "word": " positive", "probability": 0.91455078125}, {"start": 733.87, "end": 734.15, "word": " x", "probability": 0.8671875}, {"start": 734.15, "end": 734.51, "word": " axis", "probability": 0.607421875}, {"start": 734.51, "end": 734.71, "word": " to", "probability": 0.97216796875}, {"start": 734.71, "end": 734.85, "word": " the", "probability": 0.9248046875}, {"start": 734.85, "end": 735.21, "word": " right", "probability": 0.92431640625}, {"start": 735.21, "end": 735.61, "word": " ناحية", "probability": 0.8377278645833334}, {"start": 735.61, "end": 736.13, "word": " اليمين", "probability": 0.8065592447916666}], "temperature": 1.0}, {"id": 31, "seek": 75283, "start": 736.51, "end": 752.83, "text": "بفرض that ان ال collision between them is perfect elastic يعني عديم المرونة if the initial velocity of the ball طبعا ال initial velocity للكورات كانت تلاتين centimeter في الثانية وعشرين يعني الكورة الأولى تتحرك بسرعة تلاتين", "tokens": [3555, 5172, 43042, 300, 16472, 2423, 24644, 1296, 552, 307, 2176, 17115, 37495, 22653, 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{"start": 738.23, "end": 738.57, "word": " them", "probability": 0.927734375}, {"start": 738.57, "end": 738.83, "word": " is", "probability": 0.9560546875}, {"start": 738.83, "end": 739.33, "word": " perfect", "probability": 0.63232421875}, {"start": 739.33, "end": 739.99, "word": " elastic", "probability": 0.9677734375}, {"start": 739.99, "end": 740.99, "word": " يعني", "probability": 0.8955078125}, {"start": 740.99, "end": 741.79, "word": " عديم", "probability": 0.9225260416666666}, {"start": 741.79, "end": 742.43, "word": " المرونة", "probability": 0.951904296875}, {"start": 742.43, "end": 743.07, "word": " if", "probability": 0.814453125}, {"start": 743.07, "end": 743.23, "word": " the", "probability": 0.85400390625}, {"start": 743.23, "end": 743.61, "word": " initial", "probability": 0.861328125}, {"start": 743.61, "end": 743.99, "word": " velocity", "probability": 0.8349609375}, {"start": 743.99, "end": 744.15, "word": " of", "probability": 0.95556640625}, {"start": 744.15, "end": 744.33, "word": " the", "probability": 0.9072265625}, {"start": 744.33, "end": 744.63, "word": " ball", "probability": 0.859375}, {"start": 744.63, "end": 745.71, "word": " طبعا", "probability": 0.9376220703125}, {"start": 745.71, "end": 745.95, "word": " ال", "probability": 0.97216796875}, {"start": 745.95, "end": 746.37, "word": " initial", "probability": 0.857421875}, {"start": 746.37, "end": 746.77, "word": " velocity", "probability": 0.92626953125}, {"start": 746.77, "end": 747.79, "word": " للكورات", "probability": 0.7760009765625}, {"start": 747.79, "end": 748.11, "word": " كانت", "probability": 0.95166015625}, {"start": 748.11, "end": 748.61, "word": " تلاتين", "probability": 0.84521484375}, {"start": 748.61, "end": 749.05, "word": " centimeter", "probability": 0.30859375}, {"start": 749.05, "end": 749.33, "word": " في", "probability": 0.9130859375}, {"start": 749.33, "end": 749.89, "word": " الثانية", "probability": 0.9471435546875}, {"start": 749.89, "end": 750.77, "word": " وعشرين", "probability": 0.8492431640625}, {"start": 750.77, "end": 750.91, "word": " يعني", "probability": 0.8994140625}, {"start": 750.91, "end": 751.19, "word": " الكورة", "probability": 0.9611002604166666}, {"start": 751.19, "end": 751.45, "word": " الأولى", "probability": 0.96923828125}, {"start": 751.45, "end": 751.87, "word": " تتحرك", "probability": 0.882080078125}, {"start": 751.87, "end": 752.21, "word": " بسرعة", "probability": 0.9129638671875}, {"start": 752.21, "end": 752.83, "word": " تلاتين", "probability": 0.96142578125}], "temperature": 1.0}, {"id": 32, "seek": 77545, "start": 759.31, "end": 775.45, "text": "بعد التصادم بدنا نوجد سرعاتهم بعد التصادم assume friction and rotation are unimportant يعني بيحكي لنا أنه طبعا بيهم ال friction الاحتكاك و ال rotation", "tokens": [3555, 22488, 16712, 9381, 18513, 2304, 47525, 8315, 8717, 29245, 3215, 8608, 2288, 3615, 9307, 16095, 39182, 16712, 9381, 18513, 2304, 6552, 17710, 293, 12447, 366, 517, 41654, 37495, 22653, 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"end": 1160.11, "word": " الفضائية", "probability": 0.9969482421875}, {"start": 1160.11, "end": 1160.59, "word": " كبيرة", "probability": 0.9806315104166666}, {"start": 1160.59, "end": 1161.45, "word": " رميت", "probability": 0.8776041666666666}, {"start": 1161.45, "end": 1161.81, "word": " الكورة", "probability": 0.7742513020833334}, {"start": 1161.81, "end": 1162.45, "word": " عليها", "probability": 0.98828125}, {"start": 1162.45, "end": 1165.07, "word": " فهترتد", "probability": 0.94072265625}, {"start": 1165.07, "end": 1165.35, "word": " اللي", "probability": 0.87109375}, {"start": 1165.35, "end": 1165.53, "word": " هي", "probability": 0.8642578125}, {"start": 1165.53, "end": 1166.11, "word": " الكورة", "probability": 0.9656575520833334}, {"start": 1166.11, "end": 1166.59, "word": " الصغيرة", "probability": 0.97216796875}, {"start": 1166.59, "end": 1167.05, "word": " بسرعة", "probability": 0.956787109375}, {"start": 1167.05, "end": 1167.27, "word": " V", "probability": 0.6435546875}, {"start": 1167.27, "end": 1167.63, "word": " او", "probability": 0.78515625}, {"start": 1167.63, "end": 1168.15, "word": " كأنه", "probability": 0.92626953125}, {"start": 1168.15, "end": 1168.95, "word": " الكورة", "probability": 0.9423828125}, {"start": 1168.95, "end": 1169.29, "word": " الصغيرة", "probability": 0.9833984375}, {"start": 1169.29, "end": 1169.69, "word": " رميتها", "probability": 0.944580078125}, {"start": 1169.69, "end": 1169.83, "word": " على", "probability": 0.87353515625}, {"start": 1169.83, "end": 1170.17, "word": " الحيط", "probability": 0.798583984375}, {"start": 1170.17, "end": 1170.29, "word": " او", "probability": 0.93798828125}, {"start": 1170.29, "end": 1170.69, "word": " رميتها", "probability": 0.9677734375}, {"start": 1170.69, "end": 1170.79, "word": " على", "probability": 0.58056640625}, {"start": 1170.79, "end": 1170.99, "word": " جسم", "probability": 0.986328125}, {"start": 1170.99, "end": 1171.49, "word": " كبير", "probability": 0.9943033854166666}, {"start": 1171.49, "end": 1172.57, "word": " هترتد", "probability": 0.98779296875}, {"start": 1172.57, "end": 1173.37, "word": " بسرعة", "probability": 0.9881591796875}, {"start": 1173.37, "end": 1173.53, "word": " ..", "probability": 0.83935546875}, {"start": 1173.53, "end": 1173.83, "word": " بنفس", "probability": 0.9599609375}, {"start": 1173.83, "end": 1174.29, "word": " السرعة", "probability": 0.9697265625}, {"start": 1174.29, "end": 1175.05, "word": " الجواب", "probability": 0.9371744791666666}, {"start": 1175.05, "end": 1175.25, "word": " انها", "probability": 0.785888671875}, {"start": 1175.25, "end": 1175.65, "word": " هترتد", "probability": 0.993408203125}, {"start": 1175.65, "end": 1175.93, "word": " بنفس", "probability": 0.991943359375}, {"start": 1175.93, "end": 1176.31, "word": " السرعة", "probability": 0.9853515625}, {"start": 1176.31, "end": 1176.69, "word": " لان", "probability": 0.6739501953125}, {"start": 1176.69, "end": 1177.97, "word": " الكتلة", "probability": 0.7433268229166666}, {"start": 1177.97, "end": 1178.39, "word": " التانية", "probability": 0.9733072916666666}, {"start": 1178.39, "end": 1178.95, "word": " كبيرة", "probability": 0.9754231770833334}, {"start": 1178.95, "end": 1179.45, "word": " و", "probability": 0.8798828125}, {"start": 1179.45, "end": 1179.71, "word": " انا", "probability": 0.703125}, {"start": 1179.71, "end": 1180.19, "word": " رميت", "probability": 0.9864908854166666}, {"start": 1180.19, "end": 1180.49, "word": " كتلة", "probability": 0.9952799479166666}, {"start": 1180.49, "end": 1180.91, "word": " صغيرة", "probability": 0.99072265625}], "temperature": 1.0}, {"id": 50, "seek": 118884, "start": 1181.11, "end": 1188.85, "text": "زى ما نرمى كرة صغيرة على الحيط هترتد تقريبا بنفس السرعة هيك بنكون خلصنا ان شاء الله chapter 6", "tokens": [11622, 7578, 19446, 8717, 2288, 2304, 7578, 9122, 25720, 20328, 17082, 48923, 15844, 21542, 1829, 9566, 8032, 2655, 43500, 3215, 6055, 4587, 16572, 3555, 995, 44945, 36178, 21136, 2288, 27884, 39896, 4117, 44945, 30544, 16490, 1211, 9381, 8315, 16472, 13412, 16606, 21984, 7187, 1386], "avg_logprob": -0.1693576349152459, "compression_ratio": 1.25, "no_speech_prob": 6.079673767089844e-06, "words": [{"start": 1181.11, "end": 1181.45, "word": "زى", "probability": 0.3856201171875}, {"start": 1181.45, "end": 1181.55, "word": " ما", "probability": 0.8779296875}, {"start": 1181.55, "end": 1181.91, "word": " نرمى", "probability": 0.9554443359375}, {"start": 1181.91, "end": 1182.11, "word": " كرة", "probability": 0.8037109375}, {"start": 1182.11, "end": 1182.57, "word": " صغيرة", "probability": 0.9908854166666666}, {"start": 1182.57, "end": 1182.75, "word": " على", "probability": 0.671875}, {"start": 1182.75, "end": 1183.07, "word": " الحيط", "probability": 0.7845052083333334}, {"start": 1183.07, "end": 1183.57, "word": " هترتد", "probability": 0.95458984375}, {"start": 1183.57, "end": 1184.19, "word": " تقريبا", "probability": 0.9265625}, {"start": 1184.19, "end": 1184.89, "word": " بنفس", "probability": 0.990966796875}, {"start": 1184.89, "end": 1185.57, "word": " السرعة", "probability": 0.9259440104166666}, {"start": 1185.57, "end": 1186.09, "word": " هيك", "probability": 0.759033203125}, {"start": 1186.09, "end": 1186.39, "word": " بنكون", "probability": 0.759033203125}, {"start": 1186.39, "end": 1186.79, "word": " خلصنا", "probability": 0.935791015625}, {"start": 1186.79, "end": 1186.87, "word": " ان", "probability": 0.66796875}, {"start": 1186.87, "end": 1187.01, "word": " شاء", "probability": 0.983642578125}, {"start": 1187.01, "end": 1187.19, "word": " الله", "probability": 0.9453125}, {"start": 1187.19, "end": 1187.61, "word": " chapter", "probability": 0.61328125}, {"start": 1187.61, "end": 1188.85, "word": " 6", "probability": 0.85107421875}], "temperature": 1.0}], "language": "ar", "language_probability": 1.0, "duration": 1191.833875, "duration_after_vad": 1151.4881250000008}
\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk.srt
new file mode 100644
index 0000000000000000000000000000000000000000..9eb7044907b91df844e579f1da58fc24328d484a
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+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk.srt
@@ -0,0 +1,910 @@
+1
+00:00:00,000 --> 00:00:04,460
+بسم الله الرحمن الرحيم، بنستكمل محاضرات التسجيل
+
+2
+00:00:04,460 --> 00:00:11,320
+chapter خمسة، طبعا وصلنا ل example خمسة، ثلاثة ال
+
+3
+00:00:11,320 --> 00:00:16,180
+problems هي عبارة عن the driver of  ألف kilogram
+
+4
+00:00:16,180 --> 00:00:24,450
+car سيارة كتلتها ألف kilogram traveling on a
+
+5
+00:00:24,450 --> 00:00:28,250
+interstate على، يعني ماشية على خط سريع بسرعة خمسة و
+
+6
+00:00:28,250 --> 00:00:32,830
+ثلاثين متر في الثانية، تقريبا ثمانين متر per hour
+
+7
+00:00:32,830 --> 00:00:37,270
+هذا الرمز متر per hour، slams on his brakes to
+
+8
+00:00:37,270 --> 00:00:40,330
+avoid hitting a second vehicle in front of him.
+
+9
+00:00:40,330 --> 00:00:47,050
+شاهد أمامه شاحنة أو عربة، وخوفا من الاصطدام ضرب
+
+10
+00:00:47,050 --> 00:00:52,770
+brake قويا حتى لا يصطدم بالـعربة التي
+
+11
+00:00:52,770 --> 00:00:56,010
+أمامه، which had come to rest، العربة كانت واقفة
+
+12
+00:00:56,010 --> 00:01:00,490
+بسبب إشارة المرور، أو الرمز
+
+13
+00:01:00,490 --> 00:01:05,120
+الذي يكتسح مجهد الآن، after the brakes are applied, a
+
+14
+00:01:05,120 --> 00:01:08,680
+constant kinetic friction force of magnitude
+
+15
+00:01:08,680 --> 00:01:12,800
+ثمانية في عشرة أس ثلاثة نيوتن، acts on the car، بعد
+
+16
+00:01:12,800 --> 00:01:18,460
+ما السائق ضرب الـ brake، في عندي ك...صار عندي قوة
+
+17
+00:01:18,460 --> 00:01:23,240
+احتكاك متحركة ثابتة مقدارها ثمانية في عشرة أس
+
+18
+00:01:23,240 --> 00:01:28,700
+ثلاثة نيوتن، acts بتأثر على السيارة، طبعا هذا السؤال
+
+19
+00:01:28,700 --> 00:01:32,840
+بيحكي لأن في عندي أنا السيارة أو الشاحنة، الشاحنة كانت
+
+20
+00:01:32,840 --> 00:01:35,340
+واقفة على إشارة المرور، السيارة كانت ماشية بسرعة 35
+
+21
+00:01:35,340 --> 00:01:39,800
+متر في الثانية، اضطر السائق لضرب الـ brake حتى لا تصطدم
+
+22
+00:01:39,800 --> 00:01:44,580
+السيارة بالشاحنة، at what السؤال at what minimum
+
+23
+00:01:44,580 --> 00:01:48,180
+distance should the brakes be applied to avoid a
+
+24
+00:01:48,180 --> 00:01:51,360
+collision with the other vehicle، بيحكيلنا السؤال
+
+25
+00:01:51,360 --> 00:01:58,560
+ما هي أقل مسافة ممكن أن السائق يعني...يعني يحصل
+
+26
+00:01:58,560 --> 00:02:06,230
+عليها حتى لا تصطدم السيارة بالشاحنة، علشان نحله في B
+
+27
+00:02:06,230 --> 00:02:09,790
+يطلب if the distance between the vehicles is
+
+28
+00:02:09,790 --> 00:02:12,430
+initially only 30 meter، إذا كانت المسافة بين
+
+29
+00:02:12,430 --> 00:02:18,550
+السيارة والشاحنة 30 متر، at what speed would the
+
+30
+00:02:18,550 --> 00:02:23,430
+collision occur؟ ما هي السرعة التي سوف تصطدم بها
+
+31
+00:02:23,430 --> 00:02:26,770
+السيارة بالشاحنة؟ طبعا كما هو موضح بالشكل، في عند
+
+32
+00:02:26,770 --> 00:02:30,290
+السيارة تتحرك بسرعة ابتدائية كانت 35 متر في
+
+33
+00:02:30,290 --> 00:02:35,950
+الثانية، وفي عندي طبعا شاحنة، شاحنة كانت واقفة على
+
+34
+00:02:35,950 --> 00:02:40,050
+إشارة المرور، السائق طبعا السيارة الخاصة بالسيارة في هذه
+
+35
+00:02:40,050 --> 00:02:43,030
+المنطقة ضرب الـ brake، طبعا لما ضرب الـ brake صار في
+
+36
+00:02:43,030 --> 00:02:46,970
+عنده قوة احتكاك متحركة، constant frictional force
+
+37
+00:02:46,970 --> 00:02:50,610
+طبعا الـ frictional force هذه، اللي هي عكس اتجاه
+
+38
+00:02:50,610 --> 00:02:55,210
+الحركة الخاصة بالسيارة، الحل مطلوب منها نوجد
+
+39
+00:02:55,480 --> 00:03:02,340
+الـ minimum distance، بده أقل مسافة ممكنة حتى تقف
+
+40
+00:03:02,340 --> 00:03:07,360
+السيارة ولا يحدث تصادم، بعد ما السائق طبعا استخدم
+
+41
+00:03:07,360 --> 00:03:10,340
+الـ brake أو ضرب الـ brake، الآن substitute and
+
+42
+00:03:10,340 --> 00:03:15,200
+expression، نعوض بالشغل
+
+43
+00:03:15,200 --> 00:03:18,740
+اللي هو الاحتكاك، and set أو الشغل الناتج عن الـ
+
+44
+00:03:18,740 --> 00:03:22,720
+non conservative، أو الشغل الكلي باستخدام V final
+
+45
+00:03:22,720 --> 00:03:26,940
+بالساوي zero، فـ الـ W net في هذه الحالة بده يساوي
+
+46
+00:03:26,940 --> 00:03:34,140
+delta K، W net بدها تساوي delta K E، يعني التغير في
+
+47
+00:03:34,140 --> 00:03:39,160
+طاقة الحركة، الـ W net في هذه الحالة بيساوي هي قوة
+
+48
+00:03:39,160 --> 00:03:43,600
+الاحتكاك في المسافة، قوة الاحتكاك بيساوي ناقص FK في
+
+49
+00:03:43,600 --> 00:03:48,340
+Delta X، طبعا السالب لإنه اتجاه الحركة عكس اتجاه
+
+50
+00:03:48,340 --> 00:03:53,620
+قوة الاحتكاك، وبالتالي الزاوية بينهم 180، فـ cos θ
+
+51
+00:03:53,620 --> 00:03:57,800
+بيساوي سالب واحد، إذن الشغل الناتج عن الاحتكاك
+
+52
+00:03:57,800 --> 00:04:03,400
+بيساوي ناقص FK في Delta X، بدها تساوي ناقص نص mv final
+
+53
+00:04:03,400 --> 00:04:07,300
+تربيع، ناقص نص mv initial تربيع، لما سائق السيارة
+
+54
+00:04:07,300 --> 00:04:13,540
+يتوقف، معناها v final بدها تساوي zero، وإحنا إذا طبطبنا
+
+55
+00:04:13,540 --> 00:04:17,500
+الحركة في هذه الحالة هنا بدها تساوي zero، الـ v
+
+56
+00:04:17,500 --> 00:04:20,960
+initial كانت بتساوي 35، إذا بنعود بناء على هذا
+
+57
+00:04:20,960 --> 00:04:26,030
+القانون، substitute بنعوض V initial خمسة وثلاثين
+
+58
+00:04:26,030 --> 00:04:30,010
+متر في الثانية، FK بثمانية في عشرة أس ثلاثة
+
+59
+00:04:30,010 --> 00:04:33,790
+نيوتن، والكتلة ألف في عشرة أس ثلاثة كيلو
+
+60
+00:04:33,790 --> 00:04:37,550
+جرام، يعني ألف كيلو جرام، راح نحل هي نطبق في هذا
+
+61
+00:04:37,550 --> 00:04:42,600
+القانون، بعد تعويض في هذه المتغيرات، وأوجد Delta X، FK
+
+62
+00:04:42,600 --> 00:04:45,460
+كانت ثمانية في عشرة أس ثلاثة، طبعا السالب موجودة
+
+63
+00:04:45,460 --> 00:04:51,060
+Delta X بالساوي نص اللي هي V final صفر، ناقص هنا
+
+64
+00:04:51,060 --> 00:04:54,720
+نص M اللي هي واحد في عشرة أس ثلاثة kilogram في
+
+65
+00:04:54,720 --> 00:04:57,740
+اللي هي V initial خمسة وثلاثين متر في الثانية
+
+66
+00:04:57,740 --> 00:05:02,800
+تربيع، اللي هي الكل تربيع، طبعا عوضنا عن الـ V خمسة و
+
+67
+00:05:02,800 --> 00:05:06,310
+ثلاثين متر في الثانية، وكل تربيع لأنه نص M V تربيع، فـ
+
+68
+00:05:06,310 --> 00:05:12,010
+delta x تطلع لنا 76.6 متر، الآن في السؤال B، في
+
+69
+00:05:12,010 --> 00:05:18,310
+المطلوب B، at the given distance، أنا أعطاني مسافة
+
+70
+00:05:18,310 --> 00:05:21,850
+معينة، ثلاثين، the car is too close to the other
+
+71
+00:05:21,850 --> 00:05:25,960
+vehicle، find the speed at impact، في هذه الحالة
+
+72
+00:05:25,960 --> 00:05:31,620
+عندما تكون المسافة 30، ما هي السرعة التي تكون
+
+73
+00:05:31,620 --> 00:05:35,660
+السيارة؟ يعني الـ V final بتعتبرها لا تساوي 0، وده
+
+74
+00:05:35,660 --> 00:05:39,980
+بتعتبرها موجودة، إذن هنعوض W net بتساوي W ال
+
+75
+00:05:39,980 --> 00:05:43,340
+friction، الشغل الناتج عن الاحتكاك بتساوي ناقص FK
+
+76
+00:05:43,340 --> 00:05:49,000
+في Delta X، بتساوي نص MV final تربيع، ناقص نص MV
+
+77
+00:05:49,000 --> 00:05:55,770
+initial تربيع، هنعود الآن عن V initial نفس 35، إذا V
+
+78
+00:05:55,770 --> 00:06:00,050
+final تربيع بيساوي V initial تربيع، ناقص 2 على M FK
+
+79
+00:06:00,050 --> 00:06:03,850
+في Delta X، طبعا المعادلة السابقة زي ما إحنا شايفين
+
+80
+00:06:03,850 --> 00:06:09,450
+هذه المعادلة ضربناها في طبعا هي عشان أضيع الـ M على
+
+81
+00:06:09,450 --> 00:06:15,070
+M2، ضربناها بـ 2 على M عشان أضيع هذا الـ term أو هذا
+
+82
+00:06:15,070 --> 00:06:19,590
+الحد، يضيع من هنا، ضربناها بـ 2 على M، ضع من هنا وهنا
+
+83
+00:06:19,590 --> 00:06:25,810
+هتكون في 2 على M، صارت المعادلة بهذا الشكل، V final
+
+84
+00:06:25,810 --> 00:06:29,170
+تربيع بيساوي V initial تربيع، ناقص 2 على M FK Delta
+
+85
+00:06:29,170 --> 00:06:35,020
+X، Vfinal تربيع، نعوض عن Vinitial بـ 35 متر في الثانية
+
+86
+00:06:35,020 --> 00:06:39,780
+تربيع، والـ Fk كانت ثمانية ما اتغيرتش، في عشرة أس
+
+87
+00:06:39,780 --> 00:06:45,060
+ثلاثة، الاثنين، والـ M ألف كيلو جرام مضروبة في Delta X
+
+88
+00:06:45,060 --> 00:06:50,380
+اللي هي المعطاة 30 متر، تطلع عندي Vfinal تربيع 745
+
+89
+00:06:50,380 --> 00:06:53,340
+متر تربيع على الثانية تربيع، إذا Vfinal جذر التربيع
+
+90
+00:06:53,340 --> 00:06:57,580
+اللي هو هذا الرقم، بتطلع 27.3، هذه السرعة النهائية
+
+91
+00:06:57,580 --> 00:07:03,900
+للسيارة عندما تكون المسافة ثلاثين متر بين السيارة
+
+92
+00:07:03,900 --> 00:07:07,400
+وبين الـ...اللي هو الشاحنة أو الـ bike أو العربة
+
+93
+00:07:07,400 --> 00:07:13,360
+section خمسة، اثنين، واحد، بعنوان conservative and
+
+94
+00:07:13,360 --> 00:07:17,200
+non conservative force، conservative يعني محفوظة، و
+
+95
+00:07:17,200 --> 00:07:21,000
+non conservative غير محفوظة، يعني القوة المحفوظة و
+
+96
+00:07:21,000 --> 00:07:25,530
+القوة الغير محفوظة، هنا there are two general kinds
+
+97
+00:07:25,530 --> 00:07:31,070
+of force، في عندنا نوعين من اللي هي القوة، so في
+
+98
+00:07:31,070 --> 00:07:35,790
+عامة عندنا نوعين من القوة، the first is called
+
+99
+00:07:35,790 --> 00:07:38,750
+conservative force، الأولى اسمها conservative
+
+100
+00:07:38,750 --> 00:07:43,890
+force، يعني قوة محفوظة، زي اللي هي الجاذبية تعتبر
+
+101
+00:07:43,890 --> 00:07:48,930
+is probably، طبعا probably، the best example
+
+102
+00:07:48,930 --> 00:07:53,710
+of conservative force، الجاذبية هي...هي تعتبر يعني
+
+103
+00:07:53,710 --> 00:07:58,170
+أفضل مثال للقوة المحفوظة، to understand the origin
+
+104
+00:07:58,170 --> 00:08:04,070
+of the name، عشان أفهم أساس هذا الاسم، think of a
+
+105
+00:08:04,070 --> 00:08:09,680
+diver climbing to the top of عشرة متر platform، بدأ
+
+106
+00:08:09,680 --> 00:08:17,680
+أفرض إنه في عندي أنا غواص أو غواصة طبعا تتسلق إلى
+
+107
+00:08:17,680 --> 00:08:22,900
+أعلى منصة، أو أعلى منصة طبعا لل...لل...لغواص
+
+108
+00:08:22,900 --> 00:08:29,080
+المنصة طولها عشرة متر، بدأ الغواص بالتسلق من الأرض
+
+109
+00:08:29,080 --> 00:08:35,010
+ومشي مسافة عشرة متر إلى أعلى، طبعا اللي هي المنصة
+
+110
+00:08:35,010 --> 00:08:39,810
+الـ diver has to do work against gravity، الغواص أو
+
+111
+00:08:39,810 --> 00:08:46,410
+الغواصة طبعا اللي سوف تغطس من على مسافة عشرة متر
+
+112
+00:08:46,410 --> 00:08:51,070
+طبعا عملت شغل، أو عمل شغل طبعا هي غواصة لأن السؤال
+
+113
+00:08:51,070 --> 00:08:57,580
+بالرسم بينها، لسا work against gravity in making the
+
+114
+00:08:57,580 --> 00:09:02,420
+climb، الغواص هو طالع من الأرض إلى نقطة اللي هي
+
+115
+00:09:02,420 --> 00:09:07,640
+بداية القفز، ماشي مسافة عشرة متر رأسيا، once at the
+
+116
+00:09:07,640 --> 00:09:12,060
+top، في نهاية اللي عندما يصل إلى المنصة على بعد
+
+117
+00:09:12,060 --> 00:09:16,260
+عشرة متر من الأرض، she طبعا she لأن هي غواصة أو
+
+118
+00:09:16,260 --> 00:09:19,080
+غواصة، she can recover the work as kinetic energy
+
+119
+00:09:19,080 --> 00:09:24,330
+by taking the diver، طبعا تحولت طاقة الحركة في هذه
+
+120
+00:09:24,330 --> 00:09:29,550
+الحالة إلى طبعا إلى شكل ثاني هو يسمى، تحولت أن
+
+121
+00:09:29,550 --> 00:09:33,190
+طاقة من السفر، بدأت...بدأت...بدأت السرعة تتناقص
+
+122
+00:09:33,190 --> 00:09:36,290
+تتناقص لأن أقصى ارتفاع اللي هو عشرة متر، هتصير
+
+123
+00:09:36,290 --> 00:09:40,760
+سرعتها صفر، بالتالي طاقة الحركة صفر عند أقصى
+
+124
+00:09:40,760 --> 00:09:45,960
+ارتفاع، وبالتالي فاتحولت طاقة الحركة إلى طاقة وضع
+
+125
+00:09:45,960 --> 00:09:49,840
+معنى هذا الكلام، هندرسه إن شاء الله لاحقا
+
+126
+00:09:49,840 --> 00:09:55,660
+لكن هي...هي هذه الغواصة عملت شغل ضد الجاذبية، هذا
+
+127
+00:09:55,660 --> 00:10:00,110
+مثال على الـ conservative force، مثال ثاني اللي هي
+
+128
+00:10:00,110 --> 00:10:04,290
+non-conservative force، القوة الغير محفوظة is
+
+129
+00:10:04,290 --> 00:10:07,990
+generally dissipative،
+
+130
+00:10:07,990 --> 00:10:11,980
+which means that it tends to randomly، it spares the
+
+131
+00:10:11,980 --> 00:10:14,900
+energy of the body on which it acts، الـ non
+
+132
+00:10:14,900 --> 00:10:18,680
+conservative force، هذه القوة الغير محفوظة، بصفة
+
+133
+00:10:18,680 --> 00:10:23,620
+عامة هي بتتشتت، معنى هذا أن هي بتتشتت تشتيت عشوائي
+
+134
+00:10:23,620 --> 00:10:27,200
+أو أنه بتفقد طاقة، بتفقد طاقة، هذه الطاقة تفقد ممكن
+
+135
+00:10:27,200 --> 00:10:31,940
+تكون على شكل حرارة أو على شكل صوت، هذه...هذه تفقد
+
+136
+00:10:31,940 --> 00:10:35,940
+ممكن، فعشان هيك الـ non conservative force المقصودة
+
+137
+00:10:35,940 --> 00:10:39,080
+أنها قوة غير محفوظة، لأن القوة اللي...اللي...اللي
+
+138
+00:10:39,080 --> 00:10:42,720
+أنا ببدأ فيها أو الطاقة اللي أنا ببدأ فيها بتتغير
+
+139
+00:10:42,720 --> 00:10:46,360
+عن الطاقة اللي أنا بنتهي فيها، وبالتالي هذه بسميها
+
+140
+00:10:46,500 --> 00:10:51,140
+قوة غير محفوظة، المثال للقوة الغير محفوظة اللي هي
+
+141
+00:10:51,140 --> 00:10:56,440
+زي الاحتكاك، this dispersal of energy often takes
+
+142
+00:10:56,440 --> 00:10:59,820
+the form of heat or sound، هذه القوة أو الطاقة
+
+143
+00:10:59,820 --> 00:11:05,600
+المتشتتة خلال الشغل بتعطيني طاقة زي طاقة صوتية أو
+
+144
+00:11:05,600 --> 00:11:09,760
+طاقة حرارية، the kinetic friction and air drag are
+
+145
+00:11:09,760 --> 00:11:16,030
+good example، ممكن الطاقة الحركة هي عبارة، أقصد طاقة
+
+146
+00:11:16,030 --> 00:11:20,990
+الـ kinetic friction، قوة الاحتكاك ال...قوة
+
+147
+00:11:20,990 --> 00:11:27,830
+الاحتكاك تعتبر من القوة التي تعتبر قوة ال...
+
+148
+00:11:27,830 --> 00:11:31,570
+الاحتكاك تعتبر من القوة الغير محفوظة، بالإضافة إلى أن
+
+149
+00:11:31,570 --> 00:11:38,870
+الـ air drag يعني...يعني هي قوة الجر، ممكن إحنا...
+
+150
+00:11:38,870 --> 00:11:41,650
+يعني إذا إحنا جرينا جسم على سطح خشن، ممكن إحنا نفقد
+
+151
+00:11:42,150 --> 00:11:46,250
+طاقة، وبالتالي هذه القوة تسمى قوة غير محفوظة
+
+152
+00:11:48,780 --> 00:11:52,740
+طبعا هذا المثال اللي حكيناه، إذا كان شخص...إذا كان
+
+153
+00:11:52,740 --> 00:11:57,480
+شخص أو غواص أو غواصة بدأ يتسلق من الأرض وطلع إلى
+
+154
+00:11:57,480 --> 00:12:02,280
+أعلى هذا المبنى أو أعلى هذه المنصة مسافة عشرة متر
+
+155
+00:12:02,280 --> 00:12:07,040
+إلى أعلى، هيبدأ بسرعة معينة، والسرعة تبعته هتقل
+
+156
+00:12:07,040 --> 00:12:10,240
+لغاية ما توصل للأقصى، هتصير سرعته صفر، لأنه توقف
+
+157
+00:12:10,240 --> 00:12:17,280
+وبعد هيك هيبدأ الغواصة، يبدأ من أعلى إلى أسفل، عندما
+
+158
+00:12:17,280 --> 00:12:22,400
+يصعد أي شخص أو أي divers اللي هو غواص من أسفل إلى
+
+159
+00:12:22,400 --> 00:12:28,000
+أعلى، بيصير عندي أنا تحولات في الطاقة، فهي هو الغواص
+
+160
+00:12:28,000 --> 00:12:30,680
+أو الغواصة، بيبدأ شغل ضد الجاذبية، بيسموه شغل
+
+161
+00:12:30,680 --> 00:12:33,580
+الجاذبية، تتحول طاقة الحركة من هذه الحالة إلى طاقة
+
+162
+00:12:33,580 --> 00:12:37,680
+وضع، هنا بيصير عندنا طاقة وضع عندما يصل إلى هذه
+
+163
+00:12:37,680 --> 00:12:41,520
+المنطقة، بيصير عندنا طاقة وضع، عندما يقفز إلى الأرض
+
+164
+00:12:41,670 --> 00:12:44,870
+بيبدأ من الصفر وبتزداد سرعته، أقصى سرعة ممكن تكون
+
+165
+00:12:44,870 --> 00:12:48,490
+عند الأرض، وبيصير عندنا تحولات للطاقة أو شغل مبذول
+
+166
+00:12:48,490 --> 00:12:52,290
+بواسطة الجاذبية وهكذا، another way to characterize
+
+167
+00:12:52,290 --> 00:12:54,730
+a conservative and non conservative force is to
+
+168
+00:12:54,730 --> 00:12:57,190
+measure the work done by a force on an object
+
+169
+00:12:57,190 --> 00:13:01,590
+traveling between two points، طبعا زي ما حكينا طريقة
+
+170
+00:13:01,590 --> 00:13:06,030
+أخرى لوصف طبعا خصائص اللي هي القوى المحفوظة و
+
+171
+00:13:06,030 --> 00:13:08,970
+القوى الغير محفوظة، أو أنا أقيسها عن طريق الشغل
+
+172
+00:13:08,970 --> 00:13:13,410
+المبذول بواسطة قوة معينة، إذا كان عندي أنا نقطتين
+
+173
+00:13:13,410 --> 00:13:19,190
+النقطتين، طبعا بقيس اللي هي Delta X أو Delta Y حسب
+
+174
+00:1
+
+223
+00:16:59,290 --> 00:17:02,750
+مشيت المسار الأزرق القصير أو المسار الأحمر زي ما
+
+224
+00:17:02,750 --> 00:17:07,280
+حكينا، مسار من A إلى D أو من A إلى B إلى C إلى D، هذا لا يعتمد على
+
+225
+00:17:07,280 --> 00:17:10,860
+المسار، الشغل نفسه يعتمد فقط على نقطة البداية
+
+226
+00:17:10,860 --> 00:17:13,200
+والنهاية، زي ما حكينا، الشغل الناتج عن الـ gravity
+
+227
+00:17:13,200 --> 00:17:18,140
+لكن في الـ non-conservative force، as we have seen،
+
+228
+00:17:18,140 --> 00:17:22,820
+don't have this property، the work energy theorem
+
+229
+00:17:22,820 --> 00:17:25,880
+question خمسة سبعة can be rewritten in terms of
+
+230
+00:17:25,880 --> 00:17:28,990
+the work done by the conservative force، طبعاً هذا
+
+231
+00:17:28,990 --> 00:17:32,310
+استكمال لهذه الفقرة، أنه في حالة الـ non
+
+232
+00:17:32,310 --> 00:17:35,550
+-conservative force، فالشغل المبذول depends on the
+
+233
+00:17:35,550 --> 00:17:41,230
+path، طبعاً يعتمد على المسار، ولا يعتمد على نقطة
+
+234
+00:17:41,230 --> 00:17:43,650
+البداية والنهاية، ولكن يعتمد على المسار، في حالة أن
+
+235
+00:17:43,650 --> 00:17:47,890
+الشغل اللي هو W<sub>C</sub>، بيسموه W<sub>C</sub>، هو بيسموه
+
+236
+00:17:47,890 --> 00:17:52,090
+الشغل الناتج عن الـ non-conservative force، العمل
+
+237
+00:17:52,090 --> 00:17:57,130
+الانرجي هي نظرية الشغل والطاقة، في المعادلة خمسة
+
+238
+00:17:57,130 --> 00:18:04,550
+سبعة، ممكن نعيدها بشكل ثاني عن طريق اللي هو بمصطلح
+
+239
+00:18:04,550 --> 00:18:11,010
+الشغل، واللي هي conservative force W<sub>C</sub>، و الـ W done
+
+240
+00:18:11,010 --> 00:18:13,790
+by non-conservative force، وشغل ناتج عن الـ non
+
+241
+00:18:13,790 --> 00:18:18,270
+-conservative force، because the net work is just
+
+242
+00:18:18,270 --> 00:18:22,030
+the sum of these two، فمعنى الكلام أنه الشغل
+
+243
+00:18:22,030 --> 00:18:29,850
+المبذول بواسطة اللي هي القوة المحفوظة، نسميها W<sub>C</sub>، W<sub>NC</sub>
+
+244
+00:18:29,850 --> 00:18:33,970
+هو الشغل الناتج عن الـ non-conservative force،  سوى
+
+245
+00:18:33,970 --> 00:18:39,500
+ΔKE، هو عبارة عن التغير في طاقة الحركة، يعني هي
+
+246
+00:18:39,500 --> 00:18:43,540
+عبارة عن K<sub>final</sub> ناقص K<sub>initial</sub>، أو ΔK<sub>A</sub> هي
+
+247
+00:18:43,540 --> 00:18:48,260
+عبارة عن W<sub>net</sub>، هي الشغل الكلي، فالشغل الكلي ممكن أنا
+
+248
+00:18:48,260 --> 00:18:54,220
+أسميه، بيساوي W<sub>NC</sub> زائد W<sub>C</sub>، هو الشغل الناتج عن الـ
+
+249
+00:18:54,220 --> 00:18:56,860
+conservative، والشغل الناتج عن الـ non-conservative
+
+250
+00:18:56,860 --> 00:19:01,320
+force، إذن باختصار، أنه الشغل الناتج عن الـ
+
+251
+00:19:01,320 --> 00:19:05,580
+conservative force، مثال زي الـ gravity، والشغل
+
+252
+00:19:05,580 --> 00:19:08,220
+الناتج عن الـ non-conservative force، الشغل الناتج
+
+253
+00:19:08,220 --> 00:19:12,280
+عن القوة الاحتكاك، الشغل اللي ناتج عن الـ
+
+254
+00:19:12,280 --> 00:19:19,460
+conservative force، هو الشغل طبعاً لا يعتمد على، does
+
+255
+00:19:19,460 --> 00:19:22,120
+not depend on the path، الشغل اللي ناتج عن الـ
+
+256
+00:19:22,120 --> 00:19:26,100
+friction is dependent on the path، يعني يعتمد على
+
+257
+00:19:26,100 --> 00:19:30,100
+المسار، الشغل الناتج عن الـ conservative force يعتمد
+
+258
+00:19:30,100 --> 00:19:33,700
+على الـ initial and final points، الشغل الناتج عن
+
+259
+00:19:33,700 --> 00:19:39,400
+اللي هي a non-conservative force، لا يعتمد على الـ
+
+260
+00:19:39,400 --> 00:19:42,120
+initial and final، ولكن يعتمد على المسار، زي ما
+
+261
+00:19:42,120 --> 00:19:48,210
+حكينا سابقاً، سوف ندرس لاحقاً أيضاً الشغل
+
+262
+00:19:48,210 --> 00:19:51,790
+الناتج عن الـ conservative، مثال آخر اللي هو .. اللي
+
+263
+00:19:51,790 --> 00:19:55,470
+هي الشغل الناتج عن الـ spring، أو النابض، أو اللي هو
+
+264
+00:19:55,470 --> 00:19:58,570
+الزنبرك، هو يعتبر شغل conservative force، إذن
+
+265
+00:19:58,570 --> 00:20:02,190
+الـ conservative force، لي هي مثالين، اللي هي ..
+
+266
+00:20:02,190 --> 00:20:06,620
+مثال اللي هي الـ gravity، وهيكون عندنا كمان مثال الـ
+
+267
+00:20:06,620 --> 00:20:10,160
+gravitational potential energy، و الـ spring
+
+268
+00:20:10,160 --> 00:20:13,780
+الشغل الناتج عن الـ gravity، الشغل الناتج عن الـ
+
+269
+00:20:13,780 --> 00:20:17,960
+potential energy، و الشغل الناتج عن الـ spring، بسميه
+
+270
+00:20:17,960 --> 00:20:21,620
+اللي هي conservative work، الشغل الـ non
+
+271
+00:20:21,620 --> 00:20:26,940
+-conservative work، هو الشغل الذي يجعل الاحتكاك فقط
+
+272
+00:20:26,940 --> 00:20:31,600
+فبالتالي، الشغل الـ non-conservative يساوي ناقص F<sub>k</sub>
+
+273
+00:20:31,600 --> 00:20:36,780
+في ΔX، أو كمان Δ ... ΔNC بزاوية Δ
+
+274
+00:20:36,780 --> 00:20:41,320
+C، بيساوي ΔKA، أو بيساوي W<sub>net</sub>، إن شاء الله في ال
+
+275
+00:20:41,320 --> 00:20:46,400
+... في التسجيل القادم سنتكلم عن ما سبق بالتفصيل
+
+276
+00:20:46,400 --> 00:20:49,680
+في section خمسة تلاتة، إن شاء الله
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f2d15c7d4e9cfedaa0c24c626076be6f9fc12e91
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk_postprocess.srt
@@ -0,0 +1,1104 @@
+1
+00:00:00,000 --> 00:00:04,460
+بسم الله الرحمن الرحيم بنستكمل محاضرات تسجيل
+
+2
+00:00:04,460 --> 00:00:11,320
+chapter خمسة طبعا وصلنا ل example خمسة تلاتة ال
+
+3
+00:00:11,320 --> 00:00:16,180
+problems هي عبارة عن the driver of الف kilogram
+
+4
+00:00:16,180 --> 00:00:24,450
+car سيارة كتلتها الف kilogramtraveling on a
+
+5
+00:00:24,450 --> 00:00:28,250
+interstate على يعني ماشية على خط سريع بسرعة خمسة و
+
+6
+00:00:28,250 --> 00:00:32,830
+تلاتين متر في الثانية تقريبا تمانين متر per hour
+
+7
+00:00:32,830 --> 00:00:37,270
+هذا الرمز متر per hour slams on his brakes to
+
+8
+00:00:37,270 --> 00:00:40,330
+avoid hitting a second vehicle in the front of him
+
+9
+00:00:40,330 --> 00:00:47,050
+شاهد أمامه شاحن أو عربة وخوفا من الاصطدام ضرب
+
+10
+00:00:47,050 --> 00:00:52,770
+brake قويحتى لا يصطدم في اللي هي العربة اللتي
+
+11
+00:00:52,770 --> 00:00:56,010
+أمامه which had come to rest العربة كانت واغفة
+
+12
+00:00:56,010 --> 00:01:00,490
+بسبب اللي هي اللي هو الشارعات المرور او الرمزو
+
+13
+00:01:00,490 --> 00:01:05,120
+اللي كتس مجهد الان after the breaks are applieda
+
+14
+00:01:05,120 --> 00:01:08,680
+constant kinetic friction force of magnitude
+
+15
+00:01:08,680 --> 00:01:12,800
+تمانية في عشرة أس تلاتة نيوتن act on the car بعد
+
+16
+00:01:12,800 --> 00:01:18,460
+ما السائق ضرب ال brake فى عندي ك .. صار عندي قوة
+
+17
+00:01:18,460 --> 00:01:23,240
+احتكاك متحرك كثابتة مقدارها تمانية في عشرة أس
+
+18
+00:01:23,240 --> 00:01:28,700
+تلاتة نيوتن acts بتأثر على السيارة طبعا هذا السؤال
+
+19
+00:01:28,700 --> 00:01:32,840
+بيحكي لإن فى عندي أنا السيارة او شاحنالشاحن كان
+
+20
+00:01:32,840 --> 00:01:35,340
+واقف على إشارة الورور السيارة كانت ماشية بسرعة 35
+
+21
+00:01:35,340 --> 00:01:39,800
+متر في الثانية اضغط السائق ال brake حتى لا تصطدم
+
+22
+00:01:39,800 --> 00:01:44,580
+السيارة بالشاحنةat what السؤال at what minimum
+
+23
+00:01:44,580 --> 00:01:48,180
+distance should the brakes be applied to avoid a
+
+24
+00:01:48,180 --> 00:01:51,360
+collision with the other vehicle بيحكيلنا السؤال
+
+25
+00:01:51,360 --> 00:01:58,560
+ما هي أقل مسافة ممكن أنه السائق يعني يعني يحصل
+
+26
+00:01:58,560 --> 00:02:06,230
+عليها حتى لا يتصدم السيارة بالشاحنةعلشان نحله في B
+
+27
+00:02:06,230 --> 00:02:09,790
+طالب if the distance between the vehicles is
+
+28
+00:02:09,790 --> 00:02:12,430
+initially only 30 meter إذا كانت المسافة بين
+
+29
+00:02:12,430 --> 00:02:18,550
+السيارة و الشاحن 30 متر at what speed would the
+
+30
+00:02:18,550 --> 00:02:23,430
+collagen occur ما هي السرعة التي سوف تصدم بها
+
+31
+00:02:23,430 --> 00:02:26,770
+السيارة بالشاحنة طبعا كما هو موضح بالشكل في عند
+
+32
+00:02:26,770 --> 00:02:30,290
+السيارة تتحرك بسرعة في initial كانت 35 متر في
+
+33
+00:02:30,290 --> 00:02:35,950
+الثانيةو في عندي طبعا شاحنة شاحنة كانت واقفة على
+
+34
+00:02:35,950 --> 00:02:40,050
+الرمزون السائق طبعا السيارة الخاص بالسيارة في هذه
+
+35
+00:02:40,050 --> 00:02:43,030
+المنطقة ضرب ال brake طبعا لما ضرب ال brake صار في
+
+36
+00:02:43,030 --> 00:02:46,970
+عنده قوة احتكاك متحرك constant frictional force
+
+37
+00:02:46,970 --> 00:02:50,610
+طبعا ال frictional force هذه اللي هي عكس اتجاه
+
+38
+00:02:50,610 --> 00:02:55,210
+الحركة الخاصة بالسيارة الأولى الحل مطلوب منها نوجد
+
+39
+00:02:55,480 --> 00:03:02,340
+الـ minimum distance بدو أقل مسافة ممكنة حتى تقف
+
+40
+00:03:02,340 --> 00:03:07,360
+السيارة ولا يحدث تصادم بعد ما السائق طبعا استخدم
+
+41
+00:03:07,360 --> 00:03:10,340
+ال brake أو ضرر ال brake الأن substitute and
+
+42
+00:03:10,340 --> 00:03:15,200
+expression نعوض بالشغل
+
+43
+00:03:15,200 --> 00:03:18,740
+اللي هو الاحتكاك and set أو الشغل الناتج عن الـ
+
+44
+00:03:18,740 --> 00:03:22,720
+non conservative أو الشغل الكلي باستخدام V final
+
+45
+00:03:22,720 --> 00:03:26,940
+بالساوة zeroف الـ W net في هذه الحالة بده يساوي
+
+46
+00:03:26,940 --> 00:03:34,140
+delta K W net بدها تساوي delta K E يعني التغير في
+
+47
+00:03:34,140 --> 00:03:39,160
+طاقة الحركةالـ W net في هذه الحالة بيساوي هي قوة
+
+48
+00:03:39,160 --> 00:03:43,600
+الاحتكاك في المسافة قوة الاحتكاك بيساوي ناقص FK في
+
+49
+00:03:43,600 --> 00:03:48,340
+Delta X طبعا السالب لإنه اتجاه الحركة عكس اتجاه
+
+50
+00:03:48,340 --> 00:03:53,620
+قوة الاحتكاك وبالتالي الزاوية بينهم 80 فcos θ
+
+51
+00:03:53,620 --> 00:03:57,800
+بيساوي سالب واحد إذا الشغل الناتج عن الاحتكاك
+
+52
+00:03:57,800 --> 00:04:03,400
+بيساوي ناقص FK في Delta X بدها تساوينص mv final
+
+53
+00:04:03,400 --> 00:04:07,300
+تربيع نقص نص mv initial تربيع لما سائق السيارة
+
+54
+00:04:07,300 --> 00:04:13,540
+اتوقف معناها v final بدها تساوي zero واحنا اذا طبط
+
+55
+00:04:13,540 --> 00:04:17,500
+الحركة في هذه الحالة هنا بدها تساوي zero ال v
+
+56
+00:04:17,500 --> 00:04:20,960
+initial كانت بتساوي 35 اذا بنعود بناء على هذا
+
+57
+00:04:20,960 --> 00:04:26,030
+القانونsubstitute بنعوض V initial خمسة و تلاتين
+
+58
+00:04:26,030 --> 00:04:30,010
+بتر في الثانية FK بالسبع و تمانية في عشر قصر ثلاث
+
+59
+00:04:30,010 --> 00:04:33,790
+نيوتن و الماس الكتلة واحد في عشر قصر ثلاث كيلو
+
+60
+00:04:33,790 --> 00:04:37,550
+جرام يعني الف كيلو جرام راح نحل هي نطبق في هذا
+
+61
+00:04:37,550 --> 00:04:42,600
+القانونبعد تعويض في هذه المتغيرات وأوجد Delta X FK
+
+62
+00:04:42,600 --> 00:04:45,460
+كانت تمانية في عشر أو أستلتة طبعا السلب موجودة
+
+63
+00:04:45,460 --> 00:04:51,060
+Delta X بالساوية نص اللي هي V final Zero ناقص هنا
+
+64
+00:04:51,060 --> 00:04:54,720
+نص M اللي هي واحد في عشر أو أستلتة kilogram في
+
+65
+00:04:54,720 --> 00:04:57,740
+اللي هي V initial خمسة و تلاتين متر في الثانية
+
+66
+00:04:57,740 --> 00:05:02,800
+تربيع اللي هي الكل تربيع طبعا عوضنا عن ال V خمسة و
+
+67
+00:05:02,800 --> 00:05:06,310
+تلاتين متر في الثانية وكل تربيع لأنه نص M V تربيعف
+
+68
+00:05:06,310 --> 00:05:12,010
+delta x تطلع لنا 76.6 متر الان في السؤال B في
+
+69
+00:05:12,010 --> 00:05:18,310
+المطلوب B at the given distance انا اعطاني مسافة
+
+70
+00:05:18,310 --> 00:05:21,850
+معينة تلاتين the car is too close to the other
+
+71
+00:05:21,850 --> 00:05:25,960
+vehicle find the speed at impactفي هذه الحالة
+
+72
+00:05:25,960 --> 00:05:31,620
+عندما تكون المسافة 30 ما هي السرعة التي تكون
+
+73
+00:05:31,620 --> 00:05:35,660
+السيارة يعني الـV final بتعتبرها لاتساوة 0 وده
+
+74
+00:05:35,660 --> 00:05:39,980
+تعتبرها موجودة إذا هنعوض W net بتساوي W ال
+
+75
+00:05:39,980 --> 00:05:43,340
+friction الشغل الناتج عن الاحتكاك بتساوي ناخص FK
+
+76
+00:05:43,340 --> 00:05:49,000
+في Delta X بتساوي نص MV final تربيع ناقص نص MV
+
+77
+00:05:49,000 --> 00:05:55,770
+initial تربيعحنعود الآن عن V initial نفس 35 إذا V
+
+78
+00:05:55,770 --> 00:06:00,050
+final تربيع بيسمو V initial تربيع نخص 2 على M FK
+
+79
+00:06:00,050 --> 00:06:03,850
+في Delta X طبعا المعادلة السابقة زي ما أحنا شايفين
+
+80
+00:06:03,850 --> 00:06:09,450
+هذه المعادلة ضربناها في طبعا هي عشان أضيع ال M على
+
+81
+00:06:09,450 --> 00:06:15,070
+M2 ضربناها ب2 على M عشان أضيع هذا ال term أو هذا
+
+82
+00:06:15,070 --> 00:06:19,590
+الحد يضيع من هنا ضربناها ب2 على Mضع من هنا وهنا
+
+83
+00:06:19,590 --> 00:06:25,810
+هتكون في 2 على M صارت المعادلة بهذا الشكل V final
+
+84
+00:06:25,810 --> 00:06:29,170
+تربيع بيساوي V initial تربيع نقص 2 على M FK Delta
+
+85
+00:06:29,170 --> 00:06:35,020
+XVfinal تربيح نعوض عن Vinitial ب 35 متر في الثاني
+
+86
+00:06:35,020 --> 00:06:39,780
+تربيع و ال Fk كانت تمانية ما اتغيرتش في عشرة أس
+
+87
+00:06:39,780 --> 00:06:45,060
+تلاتة اتنين و ال M ألف كيلو جرام مضروبة في Delta X
+
+88
+00:06:45,060 --> 00:06:50,380
+اللي هي المعطة 30 متر تطلع عندي Vfinal تربيع 745
+
+89
+00:06:50,380 --> 00:06:53,340
+متر تربيع على الثانية تربيع اذا Vfinal جزر التربيع
+
+90
+00:06:53,340 --> 00:06:57,580
+اللي هدا الرقم بتطلع 27.3 هدى السرعة النهائية
+
+91
+00:06:57,580 --> 00:07:03,900
+للسيارةعندما تكون المسافة تلاتين متر بين السيارة
+
+92
+00:07:03,900 --> 00:07:07,400
+وبين اللي .. اللي هو الشاحن أو ال bike أو العربة
+
+93
+00:07:07,400 --> 00:07:13,360
+section خمسة اتنين واحد بعنوان conservative and
+
+94
+00:07:13,360 --> 00:07:17,200
+non conservative force conservative يعني محفوظة و
+
+95
+00:07:17,200 --> 00:07:21,000
+non conservative غير محفوظة يعني القوة المحفوظة و
+
+96
+00:07:21,000 --> 00:07:25,530
+القوة الغير محفوظةهنا there are two general kinds
+
+97
+00:07:25,530 --> 00:07:31,070
+of force، في عندنا نوعين من اللي هي القوة، so في
+
+98
+00:07:31,070 --> 00:07:35,790
+عامة عندنا نوعين من القوة، the first is called
+
+99
+00:07:35,790 --> 00:07:38,750
+conservative force، الأولى اسمها conservative
+
+100
+00:07:38,750 --> 00:07:43,890
+force يعني قوة محفوظة، زي اللي هي ال gravityتعتبر
+
+101
+00:07:43,890 --> 00:07:48,930
+is probability طبعا probability the best example
+
+102
+00:07:48,930 --> 00:07:53,710
+of conservative force الجاذبية هي هي تعتبر يعني
+
+103
+00:07:53,710 --> 00:07:58,170
+أفضل مثال لأقوى المحفوظة to understand the origin
+
+104
+00:07:58,170 --> 00:08:04,070
+of the name عشان أدرس أساس هذا الإسم think of a
+
+105
+00:08:04,070 --> 00:08:09,680
+diver climbing to the top of عشرة متر platformبدأ
+
+106
+00:08:09,680 --> 00:08:17,680
+أفرض إنه في عندي أنا غواص أو غواصة طبعا تتسلق إلى
+
+107
+00:08:17,680 --> 00:08:22,900
+أعلى منصة أو أعلى منصة طبعا لل .. لل .. للغواص
+
+108
+00:08:22,900 --> 00:08:29,080
+المنصة طولها عشرة متر بدأ الغواص بالتسلق من الأرض
+
+109
+00:08:29,080 --> 00:08:35,010
+ومشي مسافة عشرة مترالى اعلى طبعا اللى هى المنصة
+
+110
+00:08:35,010 --> 00:08:39,810
+الـ diver has to do work against gravity الغواص او
+
+111
+00:08:39,810 --> 00:08:46,410
+الغواصة طبعا اللى سوف تغطس من على مسافة عشرة متر
+
+112
+00:08:46,410 --> 00:08:51,070
+طبعا عملت شغل او عمل شغل طبعا هى غواصة لإن السؤال
+
+113
+00:08:51,070 --> 00:08:57,580
+بالرسم بينها لساwork against gravity in making the
+
+114
+00:08:57,580 --> 00:09:02,420
+climb الغواص هو طالع من الأرض إلى نقطة اللي هي
+
+115
+00:09:02,420 --> 00:09:07,640
+بداية القفز ماشي مسافة عشرة متر رأسيا once at the
+
+116
+00:09:07,640 --> 00:09:12,060
+top في نهاية اللي عندما يصل إلى المنصة على بعد
+
+117
+00:09:12,060 --> 00:09:16,260
+عشرة متر من الأرض she طبعا she لإن هي غواصة أو
+
+118
+00:09:16,260 --> 00:09:19,080
+غواصة she can recover the work as kinetic energy
+
+119
+00:09:19,080 --> 00:09:24,330
+bytaking diver طبعا اتحولت طاقة الحركة في هذه
+
+120
+00:09:24,330 --> 00:09:29,550
+الحالة الى طبعا الى شكل تاني هو يتسمى اتحولت انه
+
+121
+00:09:29,550 --> 00:09:33,190
+طاقة من السفر بدت .. بدت .. بدت السرعة تتناقص
+
+122
+00:09:33,190 --> 00:09:36,290
+تتناقص لإن أقصى ارتفاع اللي هو عشرة متر هسير
+
+123
+00:09:36,290 --> 00:09:40,760
+سرعتهاzero بالتالي طاقة الحركة zero عند أقصى
+
+124
+00:09:40,760 --> 00:09:45,960
+ارتفاع وبالتالي فاتحولت طاقة الحركة إلى طاقة وضع
+
+125
+00:09:45,960 --> 00:09:49,840
+معنى الكلام هذا الكلام هندرسه ان شاء الله لاحقا
+
+126
+00:09:49,840 --> 00:09:55,660
+لكن هى هى هذه الغواصة عملت شغل ضد الجاذبية هذا
+
+127
+00:09:55,660 --> 00:10:00,110
+مثال على ال conservative forceمثال تاني اللي هي
+
+128
+00:10:00,110 --> 00:10:04,290
+non-conservative force القوة الغير محفوظة is
+
+129
+00:10:04,290 --> 00:10:07,990
+generally dissipative
+
+130
+00:10:07,990 --> 00:10:11,980
+which means that it tends randomlyit spares the
+
+131
+00:10:11,980 --> 00:10:14,900
+energy of the body on which it acts ال non
+
+132
+00:10:14,900 --> 00:10:18,680
+conservative force هذه القوة الغير محفوظة بصفة
+
+133
+00:10:18,680 --> 00:10:23,620
+عامة هي بتتشتت معنى هذا أن هي بتتشتت تشتت عشوائي
+
+134
+00:10:23,620 --> 00:10:27,200
+أو أنه بتفقد طاقة بتفقد طاقة هذه الطاقة تفقد ممكن
+
+135
+00:10:27,200 --> 00:10:31,940
+تكون على شكل حرارة أو على شكل صوتهدى .. هدى تفقد
+
+136
+00:10:31,940 --> 00:10:35,940
+ممكن فعشان هيك ال non conservative force المقصودة
+
+137
+00:10:35,940 --> 00:10:39,080
+أنها قوة غير محفوظة لإن القوة اللى او اللى .. اللى
+
+138
+00:10:39,080 --> 00:10:42,720
+أنا ببدأ فيها أو الطاقة اللى أنا ببدأ فيها بتتغير
+
+139
+00:10:42,720 --> 00:10:46,360
+عن الطاقة اللى أنا بنتهي فيها وبالتالي هدى بسميها
+
+140
+00:10:46,500 --> 00:10:51,140
+قوة غير محفوظة المثال للقوة الغير محفوظة اللي هي
+
+141
+00:10:51,140 --> 00:10:56,440
+زي الاحتكاك this dispersal of energy often takes
+
+142
+00:10:56,440 --> 00:10:59,820
+the form of heat or sound هذه القوة أو الطاقة
+
+143
+00:10:59,820 --> 00:11:05,600
+المتشتتة خلال الشغل بتعطيني طاقة زي طاقة صوتية أو
+
+144
+00:11:05,600 --> 00:11:09,760
+طاقة حرارية the kinetic friction and air drag are
+
+145
+00:11:09,760 --> 00:11:16,030
+good example ممكن الطاقة الحركةهي عبارة أقصد طاقة
+
+146
+00:11:16,030 --> 00:11:20,990
+الـ kinetic friction قوة الاحتكاك ال .. قوة
+
+147
+00:11:20,990 --> 00:11:27,830
+الاحتكاك تعتبر من القوة التي تعتبر قوة ال ..
+
+148
+00:11:27,830 --> 00:11:31,570
+الاحتكاك تعتبر من القوة الغير محفوظة إضافة إلى أن
+
+149
+00:11:31,570 --> 00:11:38,870
+ال air drag يعني .. يعني هي قوة الجر ممكن إحنا ..
+
+150
+00:11:38,870 --> 00:11:41,650
+يعني إذا إحنا جررنا جسم على سطح خشن ممكن إحنا نفقد
+
+151
+00:11:42,150 --> 00:11:46,250
+طاقة وبالتالي هذه القوة تسمى قوة غير محفوظة
+
+152
+00:11:48,780 --> 00:11:52,740
+طبعا هذا المثال اللي حكيناه إذا كان شخص .. إذا كان
+
+153
+00:11:52,740 --> 00:11:57,480
+شخص أو غواص أو غواصة بدأ يتسلق من الأرض و طلع إلى
+
+154
+00:11:57,480 --> 00:12:02,280
+أعلى هذا المبنى أو أعلى هذه المنصة مسافة عشرة متر
+
+155
+00:12:02,280 --> 00:12:07,040
+إلى أعلى هيبدأ بسرعة معينة و السرعة تبعته هتقل
+
+156
+00:12:07,040 --> 00:12:10,240
+لغاية ما توصل للأخصة هتصير سرعته zero لأنه التوقف
+
+157
+00:12:10,240 --> 00:12:17,280
+و بعد هيك هيبدأ الغواصهيبدأ من أعلى إلى أسفل عندما
+
+158
+00:12:17,280 --> 00:12:22,400
+يصعد أي شخص أو أي divers اللي هو غواص من أسفل إلى
+
+159
+00:12:22,400 --> 00:12:28,000
+أعلى بيصير عندي أنا تحولات في الطاقة فهي هو الغواص
+
+160
+00:12:28,000 --> 00:12:30,680
+أو الغواصة بيبدأ شغل ضد الجاذبية بيسموه شغل
+
+161
+00:12:30,680 --> 00:12:33,580
+الجاذبية تتحور طاقة الحركة من هذه الحالة إلى طاقة
+
+162
+00:12:33,580 --> 00:12:37,680
+وضع هنا بيصير عندنا طاقة وضع عندما يصل إلى هذه
+
+163
+00:12:37,680 --> 00:12:41,520
+المنطقة بيصير عندنا طاقة وضع عندما يقطص إلى الأرض
+
+164
+00:12:41,670 --> 00:12:44,870
+بيبدأ من السفر و بتزاد سرعته أخصى سرعة ممكن تكون
+
+165
+00:12:44,870 --> 00:12:48,490
+عند الأرض و بيصير عندنا تحولات للطاقة أو شغل مبدول
+
+166
+00:12:48,490 --> 00:12:52,290
+بواسطة الجاذبية و هكذا another way to characterize
+
+167
+00:12:52,290 --> 00:12:54,730
+a conservative and non conservative force is to
+
+168
+00:12:54,730 --> 00:12:57,190
+measure the work done by a force on an object
+
+169
+00:12:57,190 --> 00:13:01,590
+traveling between two pointsطبعا زى ما حكينا طريقة
+
+170
+00:13:01,590 --> 00:13:06,030
+أخرى لوصف طبعا خصائص اللى هى القوى المحفوظة و
+
+171
+00:13:06,030 --> 00:13:08,970
+القوى الغير محفوظة أو انا أقيسها عن طريق الشغل
+
+172
+00:13:08,970 --> 00:13:13,410
+المبدول بواسطة قوة معينة إذا كان عندي أنا نقطتين
+
+173
+00:13:13,410 --> 00:13:19,190
+النقطتين طبعا بقيس اللى هى Delta X أو Delta Y حسب
+
+174
+00:13:19,190 --> 00:13:23,830
+المسافة اللى بينهم أو المسافة أو بنسمي اللى هو ال
+
+175
+00:13:23,830 --> 00:13:30,250
+difference distance أو displacementbetween two
+
+176
+00:13:30,250 --> 00:13:33,290
+points along different path the work done by
+
+177
+00:13:33,290 --> 00:13:38,570
+gravity الشغل المبدول بواسطة الجاذبية on some
+
+178
+00:13:38,570 --> 00:13:43,810
+going down frictionless slide يعني لو كان أنا
+
+179
+00:13:43,810 --> 00:13:49,490
+عندنا مثال كما هو موضح بشكل خمسة احداشر الشغل
+
+180
+00:13:49,490 --> 00:13:53,550
+المبدول بواسطة الجاذبية طبعا ما في عنده احتكاك
+
+181
+00:13:53,890 --> 00:13:56,950
+وبالتالي هي conserved زي ما حكينا is the same as
+
+182
+00:13:56,950 --> 00:14:00,430
+that done on someone diving onto the water from
+
+183
+00:14:00,430 --> 00:14:06,490
+the same height يعني لو في شخص سبح في أو غاص في
+
+184
+00:14:06,490 --> 00:14:11,510
+الميه على نفس الارتفاع برضه طبعا مع إحمال اللي هو
+
+185
+00:14:11,510 --> 00:14:15,640
+قوة أو قامة اللي هي المياهوبالتالي هيكون عندنا
+
+186
+00:14:15,640 --> 00:14:20,220
+conservative force اللي عدم وجود اللي هو احتكار
+
+187
+00:14:20,220 --> 00:14:23,320
+this equality does not hold for non-conservative
+
+188
+00:14:23,320 --> 00:14:28,960
+طبعا هذه الخاصية غير موجودة في ال non-conservative
+
+189
+00:14:28,960 --> 00:14:33,310
+forcefor example لو أدرب أنا مثال a sliding book
+
+190
+00:14:33,310 --> 00:14:36,730
+directly from point A to point D in a figure في
+
+191
+00:14:36,730 --> 00:14:42,010
+عندي شكل الشكل هذا الموضح أسفل زي ما أحنا شايفين
+
+192
+00:14:42,010 --> 00:14:45,770
+هذا في عندي أنا الطاولة لو أنا فرضت في عندي أنا
+
+193
+00:14:45,770 --> 00:14:49,010
+هنا الطاولة في عندي frictionless يعني مافي احتكاك
+
+194
+00:14:49,440 --> 00:14:54,600
+فيكون عندى انا كتاب معين الكتاب هيمشي خلال مسارين
+
+195
+00:14:54,600 --> 00:14:57,700
+المسار الأول اللى هو اللون الأزرق هيمشي من ال A ل
+
+196
+00:14:57,700 --> 00:15:02,960
+D والمسار التانى باللون الأحمر هيمشي المسار A B C
+
+197
+00:15:02,960 --> 00:15:07,380
+D لو كان عندى احنا لو كان عندنا friction less هذا
+
+198
+00:15:07,380 --> 00:15:11,940
+السطح friction less فالشغل المبذول لايتأثر بالمسار
+
+199
+00:15:11,940 --> 00:15:16,460
+الشغل المبذول لايتأثر بالمسار كما هو موضح في هذا
+
+200
+00:15:16,460 --> 00:15:21,450
+الشكلزي ما حكينا for example sliding book directly
+
+201
+00:15:21,450 --> 00:15:25,450
+from point A to point D in the figures below
+
+202
+00:15:25,450 --> 00:15:28,510
+requires a certain amount of work against friction
+
+203
+00:15:28,510 --> 00:15:33,370
+but sliding the book along the three other legs of
+
+204
+00:15:33,370 --> 00:15:38,570
+the square لو ماشي الكتاب من نقطة A لنقطة Bو بعدين
+
+205
+00:15:38,570 --> 00:15:44,230
+من B ل C و من C ل D بيحتاج طبعا requires three
+
+206
+00:15:44,230 --> 00:15:49,150
+times as much work بيحتاج شغل أكتر إذا كان السطح
+
+207
+00:15:49,150 --> 00:15:53,230
+هذا .. إذا كان السطح خشن لكن إذا كان السطح
+
+208
+00:15:53,230 --> 00:16:00,950
+frictionless بيكون عندنا لا .. لا يعني .. لا .. لا
+
+209
+00:16:00,950 --> 00:16:04,750
+يعني ليس له علاقة ب .. لا يعني .. لا يعتمد على هذا
+
+210
+00:16:04,750 --> 00:16:09,630
+المسارلا يعتمد على المسار معنى ال clamp إذا الشغل
+
+211
+00:16:09,630 --> 00:16:13,150
+الناتج عن ال conservative force لا تعتمد على
+
+212
+00:16:13,150 --> 00:16:18,310
+المسار ولكن تعتمد على نقطة البداية و النهاية الشغل
+
+213
+00:16:18,310 --> 00:16:22,270
+الناتج عن اللي .. اللي هي الذكاء اللي عندي أنا في
+
+214
+00:16:22,270 --> 00:16:27,130
+rough surface الشغل الناتج عن .. بيعطيني شغل ناتج
+
+215
+00:16:27,130 --> 00:16:30,170
+عن non conservative force و بالتالي يعتمد على
+
+216
+00:16:30,170 --> 00:16:32,770
+المسار لإنه بيبذل شغل أكبر
+
+217
+00:16:35,310 --> 00:16:39,290
+نجلة ال conservative force قوة اللي هي المحفوظة
+
+218
+00:16:39,290 --> 00:16:43,510
+نرجع لها تاني a force is conservative if the work
+
+219
+00:16:43,510 --> 00:16:46,610
+it does moving an object between two points is the
+
+220
+00:16:46,610 --> 00:16:49,670
+same no matter what part is taken هذا نفس اللي
+
+221
+00:16:49,670 --> 00:16:54,670
+احنا شرحناه سابقا انه انا الشغل المبدول بواسطة
+
+222
+00:16:54,670 --> 00:16:59,290
+القوة المحفوظة لا يعتمد على المسار يعني لو انا
+
+223
+00:16:59,290 --> 00:17:02,750
+مشيت المسار الأزرق القصير او المسار الأحمر زي ما
+
+224
+00:17:02,750 --> 00:17:07,280
+حكينامصار من A ل D أو من A B C D هذا لا يعتمد على
+
+225
+00:17:07,280 --> 00:17:10,860
+المصار الشغل نفسه تعتمد بس فقط على نقطة البداية
+
+226
+00:17:10,860 --> 00:17:13,200
+والنهاية زي ما حكينا الشغل الناتج عن ال gravity
+
+227
+00:17:13,200 --> 00:17:18,140
+لكن في ال non conservative force as we have seen
+
+228
+00:17:18,140 --> 00:17:22,820
+don't have this property the work energy theorem
+
+229
+00:17:22,820 --> 00:17:25,880
+question خمسة سبعة can be rewritten in terms of
+
+230
+00:17:25,880 --> 00:17:28,990
+the work done by the conservative forceطبعا هذا
+
+231
+00:17:28,990 --> 00:17:32,310
+استكمال لهذه الفقرة أنه في حالة ال non
+
+232
+00:17:32,310 --> 00:17:35,550
+-conservative force فالشغل المبدول دي bend on the
+
+233
+00:17:35,550 --> 00:17:41,230
+path of طبعا بيعتمد على المسار و لا يعتمد على نقطة
+
+234
+00:17:41,230 --> 00:17:43,650
+البداية و النهاية ولكن يعتمد على المسار في حالة أن
+
+235
+00:17:43,650 --> 00:17:47,890
+الشغل اللي هو W and C بيسموه W and C هو بيسموه
+
+236
+00:17:47,890 --> 00:17:52,090
+الشغل الناتج عن ال non-conservative forceالعمل
+
+237
+00:17:52,090 --> 00:17:57,130
+الانرجد هي نظرية الشغل والطاقة في المعادلة خمسة
+
+238
+00:17:57,130 --> 00:18:04,550
+سبعة ممكن نعيدها بشكل تاني عن طريق اللي هو بمصطلح
+
+239
+00:18:04,550 --> 00:18:11,010
+الشغل واللي هي conservative force WCو الـ W done
+
+240
+00:18:11,010 --> 00:18:13,790
+by non-conservative force وشغل ناتج عن الـ non
+
+241
+00:18:13,790 --> 00:18:18,270
+-conservative force because the net work is just
+
+242
+00:18:18,270 --> 00:18:22,030
+the sum of these two فمعنى الكلام أنه الشغل
+
+243
+00:18:22,030 --> 00:18:29,850
+المبدول بواسطة اللي هي القوة المحفوظة سمنها WC WNC
+
+244
+00:18:29,850 --> 00:18:33,970
+هو الشغل الناتج عن الـ non-conservative force سوى
+
+245
+00:18:33,970 --> 00:18:39,500
+Delta KE هو عبارة عن التغير في طاقة الحركةيعني هي
+
+246
+00:18:39,500 --> 00:18:43,540
+عبارة عن K final نخص K initial او Delta KA هي
+
+247
+00:18:43,540 --> 00:18:48,260
+عبارة عن W net هي الشغل الكل فالشغل الكل ممكن انا
+
+248
+00:18:48,260 --> 00:18:54,220
+اسميه بساوي WNC زائد WC هو الشغل الناتج عنال
+
+249
+00:18:54,220 --> 00:18:56,860
+conservative والشغل الناتج عن ال non-conservative
+
+250
+00:18:56,860 --> 00:19:01,320
+force إذا باختصار أنه الشغل الناتج عن ال
+
+251
+00:19:01,320 --> 00:19:05,580
+conservative force مثال زي ال gravity والشغل
+
+252
+00:19:05,580 --> 00:19:08,220
+الناتج عن ال non-conservative force الشغل الناتج
+
+253
+00:19:08,220 --> 00:19:12,280
+عن القوة الاحتكاكالشغل اللي ناتج عن ال
+
+254
+00:19:12,280 --> 00:19:19,460
+conservative force هو الشغل طبعا لا يعتمد على does
+
+255
+00:19:19,460 --> 00:19:22,120
+not depend on the path الشغل اللي ناتج عن ال
+
+256
+00:19:22,120 --> 00:19:26,100
+friction is dependent on the path يعني يعتمد على
+
+257
+00:19:26,100 --> 00:19:30,100
+المصارالشغل الناتج عن ال conservative force يعتمد
+
+258
+00:19:30,100 --> 00:19:33,700
+على ال initial and final points الشغل الناتج عن
+
+259
+00:19:33,700 --> 00:19:39,400
+اللي هي a non-conservative force لا يعتمد على ال
+
+260
+00:19:39,400 --> 00:19:42,120
+initial and final ولكن يعتمد على المصار زي ما
+
+261
+00:19:42,120 --> 00:19:48,210
+حكينا سابقاسوف ندرس سابقا .. لاحقا أيضا الشغل
+
+262
+00:19:48,210 --> 00:19:51,790
+الناتج عن ال conservative مثال آخر اللي هو .. اللي
+
+263
+00:19:51,790 --> 00:19:55,470
+هي الشغل الناتج عند ال spring أو النابض أو اللي هو
+
+264
+00:19:55,470 --> 00:19:58,570
+الزنبرك هو يعتبر الشغل ال conservative force، إذا
+
+265
+00:19:58,570 --> 00:20:02,190
+ال conservative force اللي هي مثالين، اللي هي ..
+
+266
+00:20:02,190 --> 00:20:06,620
+مثال اللي هي ال gravityو هيكون عندنا كمان مثال الـ
+
+267
+00:20:06,620 --> 00:20:10,160
+gravitational و ال potential energy و ال spring
+
+268
+00:20:10,160 --> 00:20:13,780
+الشغل الناتج عن ال gravity الشغل الناتج عن ال
+
+269
+00:20:13,780 --> 00:20:17,960
+potential energy و الشغل الناتج عن ال spring بسميه
+
+270
+00:20:17,960 --> 00:20:21,620
+اللي هي conservative workالشغل الـ non
+
+271
+00:20:21,620 --> 00:20:26,940
+-conservative work هو الشغل إنها تجعل الاحتكاك فقط
+
+272
+00:20:26,940 --> 00:20:31,600
+فبالتالي الشغل الـ non-conservative تساوي ناقص FK
+
+273
+00:20:31,600 --> 00:20:36,780
+في Delta X أو كمان Delta .. Delta N C بزاوية Delta
+
+274
+00:20:36,780 --> 00:20:41,320
+C بساوي Delta KA أو بساوي W net إن شاء الله في ال
+
+275
+00:20:41,320 --> 00:20:46,400
+.. في التسجيل القادم سنتكلم عن عما سبق بالتفصيل
+
+276
+00:20:46,400 --> 00:20:49,680
+بsection خمسة تلاتة إن شاء الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f2d15c7d4e9cfedaa0c24c626076be6f9fc12e91
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zl4CKFPXxGk_raw.srt
@@ -0,0 +1,1104 @@
+1
+00:00:00,000 --> 00:00:04,460
+بسم الله الرحمن الرحيم بنستكمل محاضرات تسجيل
+
+2
+00:00:04,460 --> 00:00:11,320
+chapter خمسة طبعا وصلنا ل example خمسة تلاتة ال
+
+3
+00:00:11,320 --> 00:00:16,180
+problems هي عبارة عن the driver of الف kilogram
+
+4
+00:00:16,180 --> 00:00:24,450
+car سيارة كتلتها الف kilogramtraveling on a
+
+5
+00:00:24,450 --> 00:00:28,250
+interstate على يعني ماشية على خط سريع بسرعة خمسة و
+
+6
+00:00:28,250 --> 00:00:32,830
+تلاتين متر في الثانية تقريبا تمانين متر per hour
+
+7
+00:00:32,830 --> 00:00:37,270
+هذا الرمز متر per hour slams on his brakes to
+
+8
+00:00:37,270 --> 00:00:40,330
+avoid hitting a second vehicle in the front of him
+
+9
+00:00:40,330 --> 00:00:47,050
+شاهد أمامه شاحن أو عربة وخوفا من الاصطدام ضرب
+
+10
+00:00:47,050 --> 00:00:52,770
+brake قويحتى لا يصطدم في اللي هي العربة اللتي
+
+11
+00:00:52,770 --> 00:00:56,010
+أمامه which had come to rest العربة كانت واغفة
+
+12
+00:00:56,010 --> 00:01:00,490
+بسبب اللي هي اللي هو الشارعات المرور او الرمزو
+
+13
+00:01:00,490 --> 00:01:05,120
+اللي كتس مجهد الان after the breaks are applieda
+
+14
+00:01:05,120 --> 00:01:08,680
+constant kinetic friction force of magnitude
+
+15
+00:01:08,680 --> 00:01:12,800
+تمانية في عشرة أس تلاتة نيوتن act on the car بعد
+
+16
+00:01:12,800 --> 00:01:18,460
+ما السائق ضرب ال brake فى عندي ك .. صار عندي قوة
+
+17
+00:01:18,460 --> 00:01:23,240
+احتكاك متحرك كثابتة مقدارها تمانية في عشرة أس
+
+18
+00:01:23,240 --> 00:01:28,700
+تلاتة نيوتن acts بتأثر على السيارة طبعا هذا السؤال
+
+19
+00:01:28,700 --> 00:01:32,840
+بيحكي لإن فى عندي أنا السيارة او شاحنالشاحن كان
+
+20
+00:01:32,840 --> 00:01:35,340
+واقف على إشارة الورور السيارة كانت ماشية بسرعة 35
+
+21
+00:01:35,340 --> 00:01:39,800
+متر في الثانية اضغط السائق ال brake حتى لا تصطدم
+
+22
+00:01:39,800 --> 00:01:44,580
+السيارة بالشاحنةat what السؤال at what minimum
+
+23
+00:01:44,580 --> 00:01:48,180
+distance should the brakes be applied to avoid a
+
+24
+00:01:48,180 --> 00:01:51,360
+collision with the other vehicle بيحكيلنا السؤال
+
+25
+00:01:51,360 --> 00:01:58,560
+ما هي أقل مسافة ممكن أنه السائق يعني يعني يحصل
+
+26
+00:01:58,560 --> 00:02:06,230
+عليها حتى لا يتصدم السيارة بالشاحنةعلشان نحله في B
+
+27
+00:02:06,230 --> 00:02:09,790
+طالب if the distance between the vehicles is
+
+28
+00:02:09,790 --> 00:02:12,430
+initially only 30 meter إذا كانت المسافة بين
+
+29
+00:02:12,430 --> 00:02:18,550
+السيارة و الشاحن 30 متر at what speed would the
+
+30
+00:02:18,550 --> 00:02:23,430
+collagen occur ما هي السرعة التي سوف تصدم بها
+
+31
+00:02:23,430 --> 00:02:26,770
+السيارة بالشاحنة طبعا كما هو موضح بالشكل في عند
+
+32
+00:02:26,770 --> 00:02:30,290
+السيارة تتحرك بسرعة في initial كانت 35 متر في
+
+33
+00:02:30,290 --> 00:02:35,950
+الثانيةو في عندي طبعا شاحنة شاحنة كانت واقفة على
+
+34
+00:02:35,950 --> 00:02:40,050
+الرمزون السائق طبعا السيارة الخاص بالسيارة في هذه
+
+35
+00:02:40,050 --> 00:02:43,030
+المنطقة ضرب ال brake طبعا لما ضرب ال brake صار في
+
+36
+00:02:43,030 --> 00:02:46,970
+عنده قوة احتكاك متحرك constant frictional force
+
+37
+00:02:46,970 --> 00:02:50,610
+طبعا ال frictional force هذه اللي هي عكس اتجاه
+
+38
+00:02:50,610 --> 00:02:55,210
+الحركة الخاصة بالسيارة الأولى الحل مطلوب منها نوجد
+
+39
+00:02:55,480 --> 00:03:02,340
+الـ minimum distance بدو أقل مسافة ممكنة حتى تقف
+
+40
+00:03:02,340 --> 00:03:07,360
+السيارة ولا يحدث تصادم بعد ما السائق طبعا استخدم
+
+41
+00:03:07,360 --> 00:03:10,340
+ال brake أو ضرر ال brake الأن substitute and
+
+42
+00:03:10,340 --> 00:03:15,200
+expression نعوض بالشغل
+
+43
+00:03:15,200 --> 00:03:18,740
+اللي هو الاحتكاك and set أو الشغل الناتج عن الـ
+
+44
+00:03:18,740 --> 00:03:22,720
+non conservative أو الشغل الكلي باستخدام V final
+
+45
+00:03:22,720 --> 00:03:26,940
+بالساوة zeroف الـ W net في هذه الحالة بده يساوي
+
+46
+00:03:26,940 --> 00:03:34,140
+delta K W net بدها تساوي delta K E يعني التغير في
+
+47
+00:03:34,140 --> 00:03:39,160
+طاقة الحركةالـ W net في هذه الحالة بيساوي هي قوة
+
+48
+00:03:39,160 --> 00:03:43,600
+الاحتكاك في المسافة قوة الاحتكاك بيساوي ناقص FK في
+
+49
+00:03:43,600 --> 00:03:48,340
+Delta X طبعا السالب لإنه اتجاه الحركة عكس اتجاه
+
+50
+00:03:48,340 --> 00:03:53,620
+قوة الاحتكاك وبالتالي الزاوية بينهم 80 فcos θ
+
+51
+00:03:53,620 --> 00:03:57,800
+بيساوي سالب واحد إذا الشغل الناتج عن الاحتكاك
+
+52
+00:03:57,800 --> 00:04:03,400
+بيساوي ناقص FK في Delta X بدها تساوينص mv final
+
+53
+00:04:03,400 --> 00:04:07,300
+تربيع نقص نص mv initial تربيع لما سائق السيارة
+
+54
+00:04:07,300 --> 00:04:13,540
+اتوقف معناها v final بدها تساوي zero واحنا اذا طبط
+
+55
+00:04:13,540 --> 00:04:17,500
+الحركة في هذه الحالة هنا بدها تساوي zero ال v
+
+56
+00:04:17,500 --> 00:04:20,960
+initial كانت بتساوي 35 اذا بنعود بناء على هذا
+
+57
+00:04:20,960 --> 00:04:26,030
+القانونsubstitute بنعوض V initial خمسة و تلاتين
+
+58
+00:04:26,030 --> 00:04:30,010
+بتر في الثانية FK بالسبع و تمانية في عشر قصر ثلاث
+
+59
+00:04:30,010 --> 00:04:33,790
+نيوتن و الماس الكتلة واحد في عشر قصر ثلاث كيلو
+
+60
+00:04:33,790 --> 00:04:37,550
+جرام يعني الف كيلو جرام راح نحل هي نطبق في هذا
+
+61
+00:04:37,550 --> 00:04:42,600
+القانونبعد تعويض في هذه المتغيرات وأوجد Delta X FK
+
+62
+00:04:42,600 --> 00:04:45,460
+كانت تمانية في عشر أو أستلتة طبعا السلب موجودة
+
+63
+00:04:45,460 --> 00:04:51,060
+Delta X بالساوية نص اللي هي V final Zero ناقص هنا
+
+64
+00:04:51,060 --> 00:04:54,720
+نص M اللي هي واحد في عشر أو أستلتة kilogram في
+
+65
+00:04:54,720 --> 00:04:57,740
+اللي هي V initial خمسة و تلاتين متر في الثانية
+
+66
+00:04:57,740 --> 00:05:02,800
+تربيع اللي هي الكل تربيع طبعا عوضنا عن ال V خمسة و
+
+67
+00:05:02,800 --> 00:05:06,310
+تلاتين متر في الثانية وكل تربيع لأنه نص M V تربيعف
+
+68
+00:05:06,310 --> 00:05:12,010
+delta x تطلع لنا 76.6 متر الان في السؤال B في
+
+69
+00:05:12,010 --> 00:05:18,310
+المطلوب B at the given distance انا اعطاني مسافة
+
+70
+00:05:18,310 --> 00:05:21,850
+معينة تلاتين the car is too close to the other
+
+71
+00:05:21,850 --> 00:05:25,960
+vehicle find the speed at impactفي هذه الحالة
+
+72
+00:05:25,960 --> 00:05:31,620
+عندما تكون المسافة 30 ما هي السرعة التي تكون
+
+73
+00:05:31,620 --> 00:05:35,660
+السيارة يعني الـV final بتعتبرها لاتساوة 0 وده
+
+74
+00:05:35,660 --> 00:05:39,980
+تعتبرها موجودة إذا هنعوض W net بتساوي W ال
+
+75
+00:05:39,980 --> 00:05:43,340
+friction الشغل الناتج عن الاحتكاك بتساوي ناخص FK
+
+76
+00:05:43,340 --> 00:05:49,000
+في Delta X بتساوي نص MV final تربيع ناقص نص MV
+
+77
+00:05:49,000 --> 00:05:55,770
+initial تربيعحنعود الآن عن V initial نفس 35 إذا V
+
+78
+00:05:55,770 --> 00:06:00,050
+final تربيع بيسمو V initial تربيع نخص 2 على M FK
+
+79
+00:06:00,050 --> 00:06:03,850
+في Delta X طبعا المعادلة السابقة زي ما أحنا شايفين
+
+80
+00:06:03,850 --> 00:06:09,450
+هذه المعادلة ضربناها في طبعا هي عشان أضيع ال M على
+
+81
+00:06:09,450 --> 00:06:15,070
+M2 ضربناها ب2 على M عشان أضيع هذا ال term أو هذا
+
+82
+00:06:15,070 --> 00:06:19,590
+الحد يضيع من هنا ضربناها ب2 على Mضع من هنا وهنا
+
+83
+00:06:19,590 --> 00:06:25,810
+هتكون في 2 على M صارت المعادلة بهذا الشكل V final
+
+84
+00:06:25,810 --> 00:06:29,170
+تربيع بيساوي V initial تربيع نقص 2 على M FK Delta
+
+85
+00:06:29,170 --> 00:06:35,020
+XVfinal تربيح نعوض عن Vinitial ب 35 متر في الثاني
+
+86
+00:06:35,020 --> 00:06:39,780
+تربيع و ال Fk كانت تمانية ما اتغيرتش في عشرة أس
+
+87
+00:06:39,780 --> 00:06:45,060
+تلاتة اتنين و ال M ألف كيلو جرام مضروبة في Delta X
+
+88
+00:06:45,060 --> 00:06:50,380
+اللي هي المعطة 30 متر تطلع عندي Vfinal تربيع 745
+
+89
+00:06:50,380 --> 00:06:53,340
+متر تربيع على الثانية تربيع اذا Vfinal جزر التربيع
+
+90
+00:06:53,340 --> 00:06:57,580
+اللي هدا الرقم بتطلع 27.3 هدى السرعة النهائية
+
+91
+00:06:57,580 --> 00:07:03,900
+للسيارةعندما تكون المسافة تلاتين متر بين السيارة
+
+92
+00:07:03,900 --> 00:07:07,400
+وبين اللي .. اللي هو الشاحن أو ال bike أو العربة
+
+93
+00:07:07,400 --> 00:07:13,360
+section خمسة اتنين واحد بعنوان conservative and
+
+94
+00:07:13,360 --> 00:07:17,200
+non conservative force conservative يعني محفوظة و
+
+95
+00:07:17,200 --> 00:07:21,000
+non conservative غير محفوظة يعني القوة المحفوظة و
+
+96
+00:07:21,000 --> 00:07:25,530
+القوة الغير محفوظةهنا there are two general kinds
+
+97
+00:07:25,530 --> 00:07:31,070
+of force، في عندنا نوعين من اللي هي القوة، so في
+
+98
+00:07:31,070 --> 00:07:35,790
+عامة عندنا نوعين من القوة، the first is called
+
+99
+00:07:35,790 --> 00:07:38,750
+conservative force، الأولى اسمها conservative
+
+100
+00:07:38,750 --> 00:07:43,890
+force يعني قوة محفوظة، زي اللي هي ال gravityتعتبر
+
+101
+00:07:43,890 --> 00:07:48,930
+is probability طبعا probability the best example
+
+102
+00:07:48,930 --> 00:07:53,710
+of conservative force الجاذبية هي هي تعتبر يعني
+
+103
+00:07:53,710 --> 00:07:58,170
+أفضل مثال لأقوى المحفوظة to understand the origin
+
+104
+00:07:58,170 --> 00:08:04,070
+of the name عشان أدرس أساس هذا الإسم think of a
+
+105
+00:08:04,070 --> 00:08:09,680
+diver climbing to the top of عشرة متر platformبدأ
+
+106
+00:08:09,680 --> 00:08:17,680
+أفرض إنه في عندي أنا غواص أو غواصة طبعا تتسلق إلى
+
+107
+00:08:17,680 --> 00:08:22,900
+أعلى منصة أو أعلى منصة طبعا لل .. لل .. للغواص
+
+108
+00:08:22,900 --> 00:08:29,080
+المنصة طولها عشرة متر بدأ الغواص بالتسلق من الأرض
+
+109
+00:08:29,080 --> 00:08:35,010
+ومشي مسافة عشرة مترالى اعلى طبعا اللى هى المنصة
+
+110
+00:08:35,010 --> 00:08:39,810
+الـ diver has to do work against gravity الغواص او
+
+111
+00:08:39,810 --> 00:08:46,410
+الغواصة طبعا اللى سوف تغطس من على مسافة عشرة متر
+
+112
+00:08:46,410 --> 00:08:51,070
+طبعا عملت شغل او عمل شغل طبعا هى غواصة لإن السؤال
+
+113
+00:08:51,070 --> 00:08:57,580
+بالرسم بينها لساwork against gravity in making the
+
+114
+00:08:57,580 --> 00:09:02,420
+climb الغواص هو طالع من الأرض إلى نقطة اللي هي
+
+115
+00:09:02,420 --> 00:09:07,640
+بداية القفز ماشي مسافة عشرة متر رأسيا once at the
+
+116
+00:09:07,640 --> 00:09:12,060
+top في نهاية اللي عندما يصل إلى المنصة على بعد
+
+117
+00:09:12,060 --> 00:09:16,260
+عشرة متر من الأرض she طبعا she لإن هي غواصة أو
+
+118
+00:09:16,260 --> 00:09:19,080
+غواصة she can recover the work as kinetic energy
+
+119
+00:09:19,080 --> 00:09:24,330
+bytaking diver طبعا اتحولت طاقة الحركة في هذه
+
+120
+00:09:24,330 --> 00:09:29,550
+الحالة الى طبعا الى شكل تاني هو يتسمى اتحولت انه
+
+121
+00:09:29,550 --> 00:09:33,190
+طاقة من السفر بدت .. بدت .. بدت السرعة تتناقص
+
+122
+00:09:33,190 --> 00:09:36,290
+تتناقص لإن أقصى ارتفاع اللي هو عشرة متر هسير
+
+123
+00:09:36,290 --> 00:09:40,760
+سرعتهاzero بالتالي طاقة الحركة zero عند أقصى
+
+124
+00:09:40,760 --> 00:09:45,960
+ارتفاع وبالتالي فاتحولت طاقة الحركة إلى طاقة وضع
+
+125
+00:09:45,960 --> 00:09:49,840
+معنى الكلام هذا الكلام هندرسه ان شاء الله لاحقا
+
+126
+00:09:49,840 --> 00:09:55,660
+لكن هى هى هذه الغواصة عملت شغل ضد الجاذبية هذا
+
+127
+00:09:55,660 --> 00:10:00,110
+مثال على ال conservative forceمثال تاني اللي هي
+
+128
+00:10:00,110 --> 00:10:04,290
+non-conservative force القوة الغير محفوظة is
+
+129
+00:10:04,290 --> 00:10:07,990
+generally dissipative
+
+130
+00:10:07,990 --> 00:10:11,980
+which means that it tends randomlyit spares the
+
+131
+00:10:11,980 --> 00:10:14,900
+energy of the body on which it acts ال non
+
+132
+00:10:14,900 --> 00:10:18,680
+conservative force هذه القوة الغير محفوظة بصفة
+
+133
+00:10:18,680 --> 00:10:23,620
+عامة هي بتتشتت معنى هذا أن هي بتتشتت تشتت عشوائي
+
+134
+00:10:23,620 --> 00:10:27,200
+أو أنه بتفقد طاقة بتفقد طاقة هذه الطاقة تفقد ممكن
+
+135
+00:10:27,200 --> 00:10:31,940
+تكون على شكل حرارة أو على شكل صوتهدى .. هدى تفقد
+
+136
+00:10:31,940 --> 00:10:35,940
+ممكن فعشان هيك ال non conservative force المقصودة
+
+137
+00:10:35,940 --> 00:10:39,080
+أنها قوة غير محفوظة لإن القوة اللى او اللى .. اللى
+
+138
+00:10:39,080 --> 00:10:42,720
+أنا ببدأ فيها أو الطاقة اللى أنا ببدأ فيها بتتغير
+
+139
+00:10:42,720 --> 00:10:46,360
+عن الطاقة اللى أنا بنتهي فيها وبالتالي هدى بسميها
+
+140
+00:10:46,500 --> 00:10:51,140
+قوة غير محفوظة المثال للقوة الغير محفوظة اللي هي
+
+141
+00:10:51,140 --> 00:10:56,440
+زي الاحتكاك this dispersal of energy often takes
+
+142
+00:10:56,440 --> 00:10:59,820
+the form of heat or sound هذه القوة أو الطاقة
+
+143
+00:10:59,820 --> 00:11:05,600
+المتشتتة خلال الشغل بتعطيني طاقة زي طاقة صوتية أو
+
+144
+00:11:05,600 --> 00:11:09,760
+طاقة حرارية the kinetic friction and air drag are
+
+145
+00:11:09,760 --> 00:11:16,030
+good example ممكن الطاقة الحركةهي عبارة أقصد طاقة
+
+146
+00:11:16,030 --> 00:11:20,990
+الـ kinetic friction قوة الاحتكاك ال .. قوة
+
+147
+00:11:20,990 --> 00:11:27,830
+الاحتكاك تعتبر من القوة التي تعتبر قوة ال ..
+
+148
+00:11:27,830 --> 00:11:31,570
+الاحتكاك تعتبر من القوة الغير محفوظة إضافة إلى أن
+
+149
+00:11:31,570 --> 00:11:38,870
+ال air drag يعني .. يعني هي قوة الجر ممكن إحنا ..
+
+150
+00:11:38,870 --> 00:11:41,650
+يعني إذا إحنا جررنا جسم على سطح خشن ممكن إحنا نفقد
+
+151
+00:11:42,150 --> 00:11:46,250
+طاقة وبالتالي هذه القوة تسمى قوة غير محفوظة
+
+152
+00:11:48,780 --> 00:11:52,740
+طبعا هذا المثال اللي حكيناه إذا كان شخص .. إذا كان
+
+153
+00:11:52,740 --> 00:11:57,480
+شخص أو غواص أو غواصة بدأ يتسلق من الأرض و طلع إلى
+
+154
+00:11:57,480 --> 00:12:02,280
+أعلى هذا المبنى أو أعلى هذه المنصة مسافة عشرة متر
+
+155
+00:12:02,280 --> 00:12:07,040
+إلى أعلى هيبدأ بسرعة معينة و السرعة تبعته هتقل
+
+156
+00:12:07,040 --> 00:12:10,240
+لغاية ما توصل للأخصة هتصير سرعته zero لأنه التوقف
+
+157
+00:12:10,240 --> 00:12:17,280
+و بعد هيك هيبدأ الغواصهيبدأ من أعلى إلى أسفل عندما
+
+158
+00:12:17,280 --> 00:12:22,400
+يصعد أي شخص أو أي divers اللي هو غواص من أسفل إلى
+
+159
+00:12:22,400 --> 00:12:28,000
+أعلى بيصير عندي أنا تحولات في الطاقة فهي هو الغواص
+
+160
+00:12:28,000 --> 00:12:30,680
+أو الغواصة بيبدأ شغل ضد الجاذبية بيسموه شغل
+
+161
+00:12:30,680 --> 00:12:33,580
+الجاذبية تتحور طاقة الحركة من هذه الحالة إلى طاقة
+
+162
+00:12:33,580 --> 00:12:37,680
+وضع هنا بيصير عندنا طاقة وضع عندما يصل إلى هذه
+
+163
+00:12:37,680 --> 00:12:41,520
+المنطقة بيصير عندنا طاقة وضع عندما يقطص إلى الأرض
+
+164
+00:12:41,670 --> 00:12:44,870
+بيبدأ من السفر و بتزاد سرعته أخصى سرعة ممكن تكون
+
+165
+00:12:44,870 --> 00:12:48,490
+عند الأرض و بيصير عندنا تحولات للطاقة أو شغل مبدول
+
+166
+00:12:48,490 --> 00:12:52,290
+بواسطة الجاذبية و هكذا another way to characterize
+
+167
+00:12:52,290 --> 00:12:54,730
+a conservative and non conservative force is to
+
+168
+00:12:54,730 --> 00:12:57,190
+measure the work done by a force on an object
+
+169
+00:12:57,190 --> 00:13:01,590
+traveling between two pointsطبعا زى ما حكينا طريقة
+
+170
+00:13:01,590 --> 00:13:06,030
+أخرى لوصف طبعا خصائص اللى هى القوى المحفوظة و
+
+171
+00:13:06,030 --> 00:13:08,970
+القوى الغير محفوظة أو انا أقيسها عن طريق الشغل
+
+172
+00:13:08,970 --> 00:13:13,410
+المبدول بواسطة قوة معينة إذا كان عندي أنا نقطتين
+
+173
+00:13:13,410 --> 00:13:19,190
+النقطتين طبعا بقيس اللى هى Delta X أو Delta Y حسب
+
+174
+00:13:19,190 --> 00:13:23,830
+المسافة اللى بينهم أو المسافة أو بنسمي اللى هو ال
+
+175
+00:13:23,830 --> 00:13:30,250
+difference distance أو displacementbetween two
+
+176
+00:13:30,250 --> 00:13:33,290
+points along different path the work done by
+
+177
+00:13:33,290 --> 00:13:38,570
+gravity الشغل المبدول بواسطة الجاذبية on some
+
+178
+00:13:38,570 --> 00:13:43,810
+going down frictionless slide يعني لو كان أنا
+
+179
+00:13:43,810 --> 00:13:49,490
+عندنا مثال كما هو موضح بشكل خمسة احداشر الشغل
+
+180
+00:13:49,490 --> 00:13:53,550
+المبدول بواسطة الجاذبية طبعا ما في عنده احتكاك
+
+181
+00:13:53,890 --> 00:13:56,950
+وبالتالي هي conserved زي ما حكينا is the same as
+
+182
+00:13:56,950 --> 00:14:00,430
+that done on someone diving onto the water from
+
+183
+00:14:00,430 --> 00:14:06,490
+the same height يعني لو في شخص سبح في أو غاص في
+
+184
+00:14:06,490 --> 00:14:11,510
+الميه على نفس الارتفاع برضه طبعا مع إحمال اللي هو
+
+185
+00:14:11,510 --> 00:14:15,640
+قوة أو قامة اللي هي المياهوبالتالي هيكون عندنا
+
+186
+00:14:15,640 --> 00:14:20,220
+conservative force اللي عدم وجود اللي هو احتكار
+
+187
+00:14:20,220 --> 00:14:23,320
+this equality does not hold for non-conservative
+
+188
+00:14:23,320 --> 00:14:28,960
+طبعا هذه الخاصية غير موجودة في ال non-conservative
+
+189
+00:14:28,960 --> 00:14:33,310
+forcefor example لو أدرب أنا مثال a sliding book
+
+190
+00:14:33,310 --> 00:14:36,730
+directly from point A to point D in a figure في
+
+191
+00:14:36,730 --> 00:14:42,010
+عندي شكل الشكل هذا الموضح أسفل زي ما أحنا شايفين
+
+192
+00:14:42,010 --> 00:14:45,770
+هذا في عندي أنا الطاولة لو أنا فرضت في عندي أنا
+
+193
+00:14:45,770 --> 00:14:49,010
+هنا الطاولة في عندي frictionless يعني مافي احتكاك
+
+194
+00:14:49,440 --> 00:14:54,600
+فيكون عندى انا كتاب معين الكتاب هيمشي خلال مسارين
+
+195
+00:14:54,600 --> 00:14:57,700
+المسار الأول اللى هو اللون الأزرق هيمشي من ال A ل
+
+196
+00:14:57,700 --> 00:15:02,960
+D والمسار التانى باللون الأحمر هيمشي المسار A B C
+
+197
+00:15:02,960 --> 00:15:07,380
+D لو كان عندى احنا لو كان عندنا friction less هذا
+
+198
+00:15:07,380 --> 00:15:11,940
+السطح friction less فالشغل المبذول لايتأثر بالمسار
+
+199
+00:15:11,940 --> 00:15:16,460
+الشغل المبذول لايتأثر بالمسار كما هو موضح في هذا
+
+200
+00:15:16,460 --> 00:15:21,450
+الشكلزي ما حكينا for example sliding book directly
+
+201
+00:15:21,450 --> 00:15:25,450
+from point A to point D in the figures below
+
+202
+00:15:25,450 --> 00:15:28,510
+requires a certain amount of work against friction
+
+203
+00:15:28,510 --> 00:15:33,370
+but sliding the book along the three other legs of
+
+204
+00:15:33,370 --> 00:15:38,570
+the square لو ماشي الكتاب من نقطة A لنقطة Bو بعدين
+
+205
+00:15:38,570 --> 00:15:44,230
+من B ل C و من C ل D بيحتاج طبعا requires three
+
+206
+00:15:44,230 --> 00:15:49,150
+times as much work بيحتاج شغل أكتر إذا كان السطح
+
+207
+00:15:49,150 --> 00:15:53,230
+هذا .. إذا كان السطح خشن لكن إذا كان السطح
+
+208
+00:15:53,230 --> 00:16:00,950
+frictionless بيكون عندنا لا .. لا يعني .. لا .. لا
+
+209
+00:16:00,950 --> 00:16:04,750
+يعني ليس له علاقة ب .. لا يعني .. لا يعتمد على هذا
+
+210
+00:16:04,750 --> 00:16:09,630
+المسارلا يعتمد على المسار معنى ال clamp إذا الشغل
+
+211
+00:16:09,630 --> 00:16:13,150
+الناتج عن ال conservative force لا تعتمد على
+
+212
+00:16:13,150 --> 00:16:18,310
+المسار ولكن تعتمد على نقطة البداية و النهاية الشغل
+
+213
+00:16:18,310 --> 00:16:22,270
+الناتج عن اللي .. اللي هي الذكاء اللي عندي أنا في
+
+214
+00:16:22,270 --> 00:16:27,130
+rough surface الشغل الناتج عن .. بيعطيني شغل ناتج
+
+215
+00:16:27,130 --> 00:16:30,170
+عن non conservative force و بالتالي يعتمد على
+
+216
+00:16:30,170 --> 00:16:32,770
+المسار لإنه بيبذل شغل أكبر
+
+217
+00:16:35,310 --> 00:16:39,290
+نجلة ال conservative force قوة اللي هي المحفوظة
+
+218
+00:16:39,290 --> 00:16:43,510
+نرجع لها تاني a force is conservative if the work
+
+219
+00:16:43,510 --> 00:16:46,610
+it does moving an object between two points is the
+
+220
+00:16:46,610 --> 00:16:49,670
+same no matter what part is taken هذا نفس اللي
+
+221
+00:16:49,670 --> 00:16:54,670
+احنا شرحناه سابقا انه انا الشغل المبدول بواسطة
+
+222
+00:16:54,670 --> 00:16:59,290
+القوة المحفوظة لا يعتمد على المسار يعني لو انا
+
+223
+00:16:59,290 --> 00:17:02,750
+مشيت المسار الأزرق القصير او المسار الأحمر زي ما
+
+224
+00:17:02,750 --> 00:17:07,280
+حكينامصار من A ل D أو من A B C D هذا لا يعتمد على
+
+225
+00:17:07,280 --> 00:17:10,860
+المصار الشغل نفسه تعتمد بس فقط على نقطة البداية
+
+226
+00:17:10,860 --> 00:17:13,200
+والنهاية زي ما حكينا الشغل الناتج عن ال gravity
+
+227
+00:17:13,200 --> 00:17:18,140
+لكن في ال non conservative force as we have seen
+
+228
+00:17:18,140 --> 00:17:22,820
+don't have this property the work energy theorem
+
+229
+00:17:22,820 --> 00:17:25,880
+question خمسة سبعة can be rewritten in terms of
+
+230
+00:17:25,880 --> 00:17:28,990
+the work done by the conservative forceطبعا هذا
+
+231
+00:17:28,990 --> 00:17:32,310
+استكمال لهذه الفقرة أنه في حالة ال non
+
+232
+00:17:32,310 --> 00:17:35,550
+-conservative force فالشغل المبدول دي bend on the
+
+233
+00:17:35,550 --> 00:17:41,230
+path of طبعا بيعتمد على المسار و لا يعتمد على نقطة
+
+234
+00:17:41,230 --> 00:17:43,650
+البداية و النهاية ولكن يعتمد على المسار في حالة أن
+
+235
+00:17:43,650 --> 00:17:47,890
+الشغل اللي هو W and C بيسموه W and C هو بيسموه
+
+236
+00:17:47,890 --> 00:17:52,090
+الشغل الناتج عن ال non-conservative forceالعمل
+
+237
+00:17:52,090 --> 00:17:57,130
+الانرجد هي نظرية الشغل والطاقة في المعادلة خمسة
+
+238
+00:17:57,130 --> 00:18:04,550
+سبعة ممكن نعيدها بشكل تاني عن طريق اللي هو بمصطلح
+
+239
+00:18:04,550 --> 00:18:11,010
+الشغل واللي هي conservative force WCو الـ W done
+
+240
+00:18:11,010 --> 00:18:13,790
+by non-conservative force وشغل ناتج عن الـ non
+
+241
+00:18:13,790 --> 00:18:18,270
+-conservative force because the net work is just
+
+242
+00:18:18,270 --> 00:18:22,030
+the sum of these two فمعنى الكلام أنه الشغل
+
+243
+00:18:22,030 --> 00:18:29,850
+المبدول بواسطة اللي هي القوة المحفوظة سمنها WC WNC
+
+244
+00:18:29,850 --> 00:18:33,970
+هو الشغل الناتج عن الـ non-conservative force سوى
+
+245
+00:18:33,970 --> 00:18:39,500
+Delta KE هو عبارة عن التغير في طاقة الحركةيعني هي
+
+246
+00:18:39,500 --> 00:18:43,540
+عبارة عن K final نخص K initial او Delta KA هي
+
+247
+00:18:43,540 --> 00:18:48,260
+عبارة عن W net هي الشغل الكل فالشغل الكل ممكن انا
+
+248
+00:18:48,260 --> 00:18:54,220
+اسميه بساوي WNC زائد WC هو الشغل الناتج عنال
+
+249
+00:18:54,220 --> 00:18:56,860
+conservative والشغل الناتج عن ال non-conservative
+
+250
+00:18:56,860 --> 00:19:01,320
+force إذا باختصار أنه الشغل الناتج عن ال
+
+251
+00:19:01,320 --> 00:19:05,580
+conservative force مثال زي ال gravity والشغل
+
+252
+00:19:05,580 --> 00:19:08,220
+الناتج عن ال non-conservative force الشغل الناتج
+
+253
+00:19:08,220 --> 00:19:12,280
+عن القوة الاحتكاكالشغل اللي ناتج عن ال
+
+254
+00:19:12,280 --> 00:19:19,460
+conservative force هو الشغل طبعا لا يعتمد على does
+
+255
+00:19:19,460 --> 00:19:22,120
+not depend on the path الشغل اللي ناتج عن ال
+
+256
+00:19:22,120 --> 00:19:26,100
+friction is dependent on the path يعني يعتمد على
+
+257
+00:19:26,100 --> 00:19:30,100
+المصارالشغل الناتج عن ال conservative force يعتمد
+
+258
+00:19:30,100 --> 00:19:33,700
+على ال initial and final points الشغل الناتج عن
+
+259
+00:19:33,700 --> 00:19:39,400
+اللي هي a non-conservative force لا يعتمد على ال
+
+260
+00:19:39,400 --> 00:19:42,120
+initial and final ولكن يعتمد على المصار زي ما
+
+261
+00:19:42,120 --> 00:19:48,210
+حكينا سابقاسوف ندرس سابقا .. لاحقا أيضا الشغل
+
+262
+00:19:48,210 --> 00:19:51,790
+الناتج عن ال conservative مثال آخر اللي هو .. اللي
+
+263
+00:19:51,790 --> 00:19:55,470
+هي الشغل الناتج عند ال spring أو النابض أو اللي هو
+
+264
+00:19:55,470 --> 00:19:58,570
+الزنبرك هو يعتبر الشغل ال conservative force، إذا
+
+265
+00:19:58,570 --> 00:20:02,190
+ال conservative force اللي هي مثالين، اللي هي ..
+
+266
+00:20:02,190 --> 00:20:06,620
+مثال اللي هي ال gravityو هيكون عندنا كمان مثال الـ
+
+267
+00:20:06,620 --> 00:20:10,160
+gravitational و ال potential energy و ال spring
+
+268
+00:20:10,160 --> 00:20:13,780
+الشغل الناتج عن ال gravity الشغل الناتج عن ال
+
+269
+00:20:13,780 --> 00:20:17,960
+potential energy و الشغل الناتج عن ال spring بسميه
+
+270
+00:20:17,960 --> 00:20:21,620
+اللي هي conservative workالشغل الـ non
+
+271
+00:20:21,620 --> 00:20:26,940
+-conservative work هو الشغل إنها تجعل الاحتكاك فقط
+
+272
+00:20:26,940 --> 00:20:31,600
+فبالتالي الشغل الـ non-conservative تساوي ناقص FK
+
+273
+00:20:31,600 --> 00:20:36,780
+في Delta X أو كمان Delta .. Delta N C بزاوية Delta
+
+274
+00:20:36,780 --> 00:20:41,320
+C بساوي Delta KA أو بساوي W net إن شاء الله في ال
+
+275
+00:20:41,320 --> 00:20:46,400
+.. في التسجيل القادم سنتكلم عن عما سبق بالتفصيل
+
+276
+00:20:46,400 --> 00:20:49,680
+بsection خمسة تلاتة إن شاء الله
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ.srt
new file mode 100644
index 0000000000000000000000000000000000000000..ee3f8ff24106228480a92084668d43ee9674e6fb
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ.srt
@@ -0,0 +1,987 @@
+1
+00:00:00,000 --> 00:00:04,360
+بسم الله الرحمن الرحيم نستكمل chapter أربعة هذا
+
+2
+00:00:04,360 --> 00:00:07,820
+section أربعة أربعة one upon one static friction
+
+3
+00:00:07,820 --> 00:00:12,160
+forces when a horizontal force F is exerted
+
+4
+00:00:12,160 --> 00:00:17,780
+against an object such as a trash can
+
+5
+00:00:17,780 --> 00:00:20,760
+the trash can does not move unless the force exceeds
+
+6
+00:00:20,760 --> 00:00:25,640
+some critical value معامل هذه قوة الاحتكاك الساكنة
+
+7
+00:00:25,640 --> 00:00:32,400
+عندما طبعا عندما يكون لدينا قوة في اتجاه الأفقي
+
+8
+00:00:32,400 --> 00:00:38,950
+إذا زادت هذه القوة عن قوة معينة أو حد
+
+9
+00:00:38,950 --> 00:00:42,350
+معين اللي هي ال critical value ممكن أن هذه العربة
+
+10
+00:00:42,350 --> 00:00:46,510
+أو سلة القمامة أن ت ... ت ... تنزاح أو تنجر
+
+11
+00:00:46,510 --> 00:00:51,290
+لكن إذا كان أنا بأعطي هذه ال ... هذا ... هذا ال ...
+
+12
+00:00:51,290 --> 00:00:54,210
+يعني هذه السلة أو هذا البرميل بأعطيه قوة ولم ...
+
+13
+00:00:54,210 --> 00:00:59,420
+ولم يتحرك فإذا هناك ... هناك قوة احتكاك ساكنة the
+
+14
+00:00:59,420 --> 00:01:03,040
+critical value is maximum static friction في قوة
+
+15
+00:01:03,040 --> 00:01:06,920
+حرجة بيسموها اللي هي maximum static friction أقصى
+
+16
+00:01:06,920 --> 00:01:11,080
+قوة الاحتكاك بعدها الجسم يتحرك يعني لو أعطيت
+
+17
+00:01:11,080 --> 00:01:16,330
+أنا جسم برميل أو طاولة أو كتلة كبيرة يعني دفعتها
+
+18
+00:01:16,330 --> 00:01:19,670
+بقوة لم تتحرك و دفعتها بقوة أخرى ولم تتحرك كل هذه
+
+19
+00:01:19,670 --> 00:01:23,110
+القوة اللي أنا بدفعها فيها اسمها قوة احتكاك ساكنة
+
+20
+00:01:23,110 --> 00:01:26,750
+لأنه في معامل احتكاك ساكن بين الجسم وبين هذه
+
+21
+00:01:26,750 --> 00:01:30,370
+الكتلة the actual static force is always less
+
+22
+00:01:30,370 --> 00:01:34,540
+than or equal to the maximum معنى الكلام أنه قيمة
+
+23
+00:01:34,540 --> 00:01:40,360
+اللي هي قوة الاحتكاك الساكنة الحقيقية هي عبارة
+
+24
+00:01:40,360 --> 00:01:44,780
+عن تساوي اللي هي القوة ال maximum أو أقل منها طبعا
+
+25
+00:01:44,780 --> 00:01:50,590
+هذا الشكل يبين graphically كيف أننا ممكن الشكل
+
+26
+00:01:50,590 --> 00:01:54,990
+ال ... ال ... هذا ال ... الأسفل يبين لي أنه في عندي
+
+27
+00:01:54,990 --> 00:01:59,350
+انحناءة معينة في عندي قوة احتكاك قوة يعني applied
+
+28
+00:01:59,350 --> 00:02:03,330
+force وطبعا هذه قوة احتكاك ساكنة عكس هذه القوة
+
+29
+00:02:03,330 --> 00:02:07,350
+طالما أنا أشـد هذا الجسم ولم يتحرك وأشد ولم
+
+30
+00:02:07,350 --> 00:02:12,870
+يتحرك فـ إزالة قوة احتكاك ساكنة قيمة هذه القوة قوة
+
+31
+00:02:12,870 --> 00:02:16,070
+احتكاك ساكنة تساوي قيمة ال applied force في هذه
+
+32
+00:02:16,070 --> 00:02:19,690
+الحالة أنه برضه مش هيتحرك في عندنا ال normal force
+
+33
+00:02:19,690 --> 00:02:22,850
+اللي هي عكس قوة الجاذبية عكس الوزن اللي هو ال mg
+
+34
+00:02:22,850 --> 00:02:26,890
+الآن في هذا الشكل ألاحظ أنني زودت القوة التي
+
+35
+00:02:26,890 --> 00:02:31,270
+أعطيتها إياه فالجسم تحرك تحرك معناته عامل حركة
+
+36
+00:02:31,270 --> 00:02:34,370
+اللي هو ال motion عندما يتحرك الاسـاس بتتحول قوة
+
+37
+00:02:34,370 --> 00:02:38,990
+الاحتكاك الساكنة إلى قوة احتكاك متحركة يحكي لي هذا
+
+38
+00:02:38,990 --> 00:02:41,730
+الشكل when the magnitude of the applied force إذا
+
+39
+00:02:41,730 --> 00:02:46,430
+كانت قيمة القوة المعطاة زادت عن قيمة اللي هي
+
+40
+00:02:46,430 --> 00:02:50,310
+maximum force of static friction أعلى من قيمة قوة
+
+41
+00:02:50,310 --> 00:02:54,130
+الاحتكاك الساكنة معناها هذه سلة القمامة وبرميل
+
+42
+00:02:54,130 --> 00:02:58,050
+القمامة ممكن أن يتحرك و brakes free and
+
+43
+00:02:58,050 --> 00:03:03,540
+accelerate to the right يتحرك لليمين طبعا الجملة
+
+44
+00:03:03,540 --> 00:03:07,840
+السابقة تسبق هذا الكلام نحكي أن when the applied
+
+45
+00:03:07,840 --> 00:03:11,000
+force exceeds the maximum static force the object
+
+46
+00:03:11,000 --> 00:03:14,700
+begins to move الجسم يتحرك بتتحول قوة الاحتكاك
+
+47
+00:03:14,700 --> 00:03:21,000
+ال ساكنة إلى قوة احتكاك متحركة كمان بدل ما أستخدم μs
+
+48
+00:03:21,000 --> 00:03:24,900
+أستخدم μk الـ kinetic friction coefficient معامل
+
+49
+00:03:24,900 --> 00:03:30,240
+الاحتكاك المتحركة أقل من قوة الاحتكاك الساكنة كما هو
+
+50
+00:03:30,240 --> 00:03:37,360
+موضح μk أقل من μs معنى الكلام أن قوة الاحتكاك
+
+51
+00:03:37,360 --> 00:03:43,600
+ال ساكنة لها قيمة عظمى ولها تدرج من ال zero لأعلى
+
+52
+00:03:43,600 --> 00:03:48,340
+قيمة عظمى كما هو موضح بهذا الشكل أنا أُـريـ ... أُـريـ
+
+53
+00:03:48,340 --> 00:03:51,520
+أنا هنا في static region هذه المنطقة منطقة احتكاك
+
+54
+00:03:51,520 --> 00:03:54,780
+ساكنة يعني لما يكون عندي جسم أنا ... أنا دفعت
+
+55
+00:03:54,780 --> 00:03:58,460
+وما تحرك أعطيته قوة لكن ما تحرك قوة احتكاك
+
+56
+00:03:58,460 --> 00:04:02,440
+ساكنة أعطيته زودت القوة ما تحرك زودت القوة ما
+
+57
+00:04:02,440 --> 00:04:06,320
+تحرك إلى حد معين بيسموها ال critical طبعا هي
+
+58
+00:04:06,320 --> 00:04:10,240
+point أو النقطة الحرجة هذه بعدها إذا هو تحرك
+
+59
+00:04:10,240 --> 00:04:14,080
+بتكون أنا وصلت لل maximum static friction force
+
+60
+00:04:14,080 --> 00:04:17,060
+اللي هي أعلى قيمة لقوة الاحتكاك الساكنة بعدها
+
+61
+00:04:17,060 --> 00:04:21,240
+يتحرك فـ يتحول قوة الاحتكاك الساكنة إلى قوة احتكاك
+
+62
+00:04:21,240 --> 00:04:24,760
+متحركة وبالتالي في عندي أنا هنا منطقة الاحتكاك
+
+63
+00:04:24,760 --> 00:04:25,620
+المتحركة
+
+64
+00:04:28,480 --> 00:04:31,840
+الـ static friction force الـ static friction
+
+65
+00:04:31,840 --> 00:04:35,480
+force the magnitude of the static friction force
+
+66
+00:04:35,480 --> 00:04:41,480
+اللي هي قيمة قوة الاحتكاك الساكنة ورمزها Fs تؤثر
+
+67
+00:04:41,480 --> 00:04:48,080
+على الجسم at rest satisfy the inequality أن الـ Fs
+
+68
+00:04:48,080 --> 00:04:52,760
+تتراوح بين الـ 0 و الـ F maximum هذه ال Fs تتراوح بين
+
+69
+00:04:52,760 --> 00:04:57,820
+أكبر من أو تساوي 0 أو أقل من أو تساوي ال F static force
+
+70
+00:04:57,820 --> 00:05:01,960
+maximum و تساوي μs في ال normal قيمتها μs في
+
+71
+00:05:01,960 --> 00:05:05,180
+ال normal اللي هي ال F static friction force
+
+72
+00:05:05,180 --> 00:05:09,440
+maximum تساوي μs في ال normal لكنها تتراوح من ال
+
+73
+00:05:09,440 --> 00:05:14,870
+0 إلى Fs maximum الـ N is the normal force الـ N هذه
+
+74
+00:05:14,870 --> 00:05:19,030
+عبارة عن قوة رد الفعل العمودية و μs is the
+
+75
+00:05:19,030 --> 00:05:22,650
+coefficient of maximum static friction اللي هي
+
+76
+00:05:22,650 --> 00:05:25,910
+عبارة عن معامل الاحتكاك الساكن بين
+
+77
+00:05:25,910 --> 00:05:30,150
+object and the surface بين أي جسم وبين السطح the
+
+78
+00:05:30,150 --> 00:05:34,350
+force Fs قوة الاحتكاك الساكنة act in the direction
+
+79
+00:05:34,350 --> 00:05:39,350
+opposite that of the impending motion قوة الاحتكاك
+
+80
+00:05:39,350 --> 00:05:44,750
+الساكنة يكون اتجاهها عكس اتجاه الحركة هذا الكلام
+
+81
+00:05:44,750 --> 00:05:49,470
+يشبه قوة الاحتكاك المتحركة على أساس أن اتجاه قوة
+
+82
+00:05:49,470 --> 00:05:53,730
+الاحتكاك المتحركة أو الساكنة يكون عكس الحركة قوة
+
+83
+00:05:53,730 --> 00:05:56,890
+الاحتكاك الساكنة تكون عكس القوة قوة الاحتكاك
+
+84
+00:05:56,890 --> 00:06:01,930
+المتحركة تكون عكس اللي هو القوة أو الحركة the
+
+85
+00:06:01,930 --> 00:06:05,550
+static friction force takes on any value between
+
+86
+00:06:05,550 --> 00:06:09,690
+zero and its maximum value قوة الاحتكاك الساكنة
+
+87
+00:06:09,690 --> 00:06:14,850
+تأخذ قيم من zero إلى أقصى قيمة اللي هي بيسموها ال
+
+88
+00:06:14,850 --> 00:06:19,530
+maximum value μs في ال normal تعتمد على قيمة
+
+89
+00:06:19,530 --> 00:06:23,250
+القوة المعطاة depending on the magnitude of the
+
+90
+00:06:23,250 --> 00:06:27,470
+applied force The static friction force self
+
+91
+00:06:27,470 --> 00:06:31,510
+-adjusts depending on the net force acting on the
+
+92
+00:06:31,510 --> 00:06:36,010
+object برضه ال static frictional force قوة احتكاك
+
+93
+00:06:36,010 --> 00:06:40,630
+ال ساكنة ممكن أن نضبطها أو نعيرها بحيث أنها تعتمد
+
+94
+00:06:40,630 --> 00:06:46,000
+على محصلة القوة المؤثرة على الجسم such
+
+95
+00:06:46,000 --> 00:06:49,340
+self-adjustment is illustrated in the figure مثل
+
+96
+00:06:49,340 --> 00:06:54,060
+هذا الشكل اللي هي القوة المحصلة المؤثرة على الجسم
+
+97
+00:06:54,060 --> 00:06:59,340
+كذلك الشكل طبعا عندي أنا هنا applied force الشخص
+
+98
+00:06:59,340 --> 00:07:04,920
+يدفع ثلاجة إلى الأمام في عندها ال F applied فالثلاجة
+
+99
+00:07:04,920 --> 00:07:09,100
+لم تتحرك وبالتالي ال Fs يجب أن تساوي أقل من ال
+
+100
+00:07:09,100 --> 00:07:13,060
+μs في ال normal ال Fs اللي هي موجودة حكينا
+
+101
+00:07:13,060 --> 00:07:17,240
+تتراوح من ال zero إلى ال F maximum فالمؤثر على هذه
+
+102
+00:07:17,240 --> 00:07:21,940
+الثلاجة F applied اللي هي تساوي أقل من ال μs في
+
+103
+00:07:21,940 --> 00:07:27,220
+ال normal لو أنا زودت القوة، زودنا القوة، زودت
+
+104
+00:07:27,220 --> 00:07:31,120
+القوة صارت ال Fs يجب أن تساوي μs في ال normal في
+
+105
+00:07:31,120 --> 00:07:34,220
+هذه الحالة و ال F اللي هي ال applied هذه يجب أن
+
+106
+00:07:34,220 --> 00:07:40,050
+تساوي ال Fs اللي هي ال μs في ال normal بعد هيك
+
+107
+00:07:40,050 --> 00:07:44,870
+زودنا القوة شوية صارت عندي ال F applied أكبر من ال
+
+108
+00:07:44,870 --> 00:07:51,570
+Fs إذا الجسم هيتحرك بدل ال Fs نضع ال Fk صارت
+
+109
+00:07:51,570 --> 00:07:56,790
+عندي أنه في عندي حركة تحولت ال Fs إلى Fk وبالتالي
+
+110
+00:07:56,790 --> 00:08:00,270
+بقي أنا بيصير عندي حركة تصبح ال F applied ناقص ال
+
+111
+00:08:00,270 --> 00:08:03,630
+Fk تساوي ال mass في ال acceleration صار عندي
+
+112
+00:08:03,630 --> 00:08:08,900
+مجموعة القوة باتجاه ال X axis تساوي m في a طبعا
+
+113
+00:08:08,900 --> 00:08:13,360
+هذا هو موضح في الشكل 24 بنحكي أنه ال ... أنا في
+
+114
+00:08:13,360 --> 00:08:17,800
+عندي قوة زودتها شوية شوية حتى في ... في أكثر من
+
+115
+00:08:17,800 --> 00:08:21,400
+حالة الحالة الأولى أنها لم تتحرك الثلاجة الحالة
+
+116
+00:08:21,400 --> 00:08:24,360
+الثانية كانت القوة التي أعطيتهيا مساوية لأقصى قيمة
+
+117
+00:08:24,360 --> 00:08:27,520
+الحالة الثالثة أن القوة كانت أكبر من أقصى قيمة إذا
+
+118
+00:08:27,520 --> 00:08:32,530
+تحرك الجسم example as shown in the figures في عندي
+
+119
+00:08:32,530 --> 00:08:38,290
+block جسم having mass جسم له كتلة أربعة كيلوغرام
+
+120
+00:08:38,290 --> 00:08:42,210
+at rest on a slope that makes an angle of ثلاثين هذه
+
+121
+00:08:42,210 --> 00:08:46,530
+الجسم موضوع على سطح مائل بزاوية ثلاثين درجة كتلة
+
+122
+00:08:46,530 --> 00:08:51,850
+هذا الجسم أربعة كيلوغرام with the horizontal طبعا
+
+123
+00:08:51,850 --> 00:08:54,710
+الثلاثين هي الزاوية المحصورة بين المستوى
+
+124
+00:08:54,710 --> 00:08:57,550
+وبين اللي هي ال horizontal if the coefficient of
+
+125
+00:08:57,550 --> 00:09:00,310
+static friction between the block and the surface
+
+126
+00:09:00,310 --> 00:09:07,090
+it rests upon is ال معامل الاحتكاك الساكن 0.65
+
+127
+00:09:07,860 --> 00:09:12,040
+calculate مطلوب إيجاد the normal force و ال
+
+128
+00:09:12,040 --> 00:09:15,680
+maximum static force بده قوة رد الفعل العمودية
+
+129
+00:09:15,680 --> 00:09:19,880
+وبده أقصى قيمة لل static force أيضا مطلوب ال
+
+130
+00:09:19,880 --> 00:09:24,040
+actual static friction force required to prevent
+
+131
+00:09:24,040 --> 00:09:27,700
+the block from moving بده ال actual static
+
+132
+00:09:27,700 --> 00:09:33,380
+friction force بده قيمة قوة الاحتكاك الساكنة
+
+133
+00:09:33,380 --> 00:09:37,040
+الحقيقية التي أحتاجها لمنع حركة هذا الجسم
+
+134
+00:09:37,530 --> 00:09:41,070
+وبعدين سيقول لنا will the block begin to move or
+
+135
+00:09:41,070 --> 00:09:46,510
+remain at rest هل الجسم سيبدأ في التحرك أم سيظل ثابتاً
+
+136
+00:09:46,510 --> 00:09:50,110
+يعني هو الجسم كتلته أربعة مائل بزاوية ثلاثين درجة
+
+137
+00:09:50,110 --> 00:09:55,770
+أعطاني معامل الاحتكاك الساكن μs 0.65 من خلال
+
+138
+00:09:55,770 --> 00:10:00,210
+هذا الشكل بدي أوجد أنا ال actual اللي هي ال static
+
+139
+00:10:00,210 --> 00:10:03,630
+friction طبعا أول شيء لازم أرسم free body diagram
+
+140
+00:10:03,630 --> 00:10:08,020
+لهذا الشكل نزل ال mg أو قوة الجاذبية اللي هي ال Fg
+
+141
+00:10:08,020 --> 00:10:12,460
+هي عبارة عن حاصل ضرب ال m في g نحلل اللي هي ال mg إلى
+
+142
+00:10:12,460 --> 00:10:18,220
+mg cos و mg sin على المستوى mg cos و mg sin على
+
+143
+00:10:18,220 --> 00:10:22,640
+المستوى في عندي هنا Normal طبعا الجسم يريد أن ينزل إلى
+
+144
+00:10:22,640 --> 00:10:26,760
+أسفل في عندي قوة احتكاك ساكنة تمنعه من الحركة نريد أن
+
+145
+00:10:26,760 --> 00:10:31,180
+نرى هل الجسم يريد أن يتحرك أم الجسم يريد أن يبقى ساكنا كما
+
+146
+00:10:31,180 --> 00:10:36,360
+هو لإيجاد المطلوب الأول الآن هي ال three forces في
+
+147
+00:10:36,360 --> 00:10:40,000
+عندي ثلاث قوى مؤثرة على الجسم في عندي قوة الجاذبية
+
+148
+00:10:40,000 --> 00:10:44,300
+mg وفي عندي ال normal force اللي هي ال N و ال
+
+149
+00:10:44,300 --> 00:10:48,560
+static friction force Fs بدي أختار ال coordinate
+
+150
+00:10:48,560 --> 00:10:53,040
+على أساس أنني سأختار محاور x و y باختار ال x
+
+151
+00:10:53,040 --> 00:10:57,020
+axis positive x axis اللي هي أسفل اللي هو المنحدر
+
+152
+00:10:57,020 --> 00:11:01,610
+أو أسفل السطح المائل لليمين يُعتَبر x الموجب ال y
+
+153
+00:11:01,610 --> 00:11:06,910
+العمودي عليه اللي هو ال positive y axis is
+
+154
+00:11:06,910 --> 00:11:10,090
+perpendicular to the عمودي على اللي هو هذا
+
+155
+00:11:10,090 --> 00:11:14,010
+الخط نحسب ال normal force طبعا عشان أحسب ال normal
+
+156
+00:11:14,010 --> 00:11:16,350
+force ال normal force في هذه الحالة تساوي ال mg
+
+157
+00:11:16,350 --> 00:11:20,260
+cosine الزاوية ال m كانت أربعة وال g تسعة وثمانية من عشرة كوساين الثلاثين 33.9
+
+158
+00:11:20,260 --> 00:11:23,600
+هذه ال normal force لإيجاد ال maximum
+
+159
+00:11:26,900 --> 00:11:31,620
+possible static frictional force ال Fs maximum
+
+160
+00:11:31,620 --> 00:11:36,640
+عبارة عن μs في ال normal اللي هو coefficient of
+
+161
+00:11:36,640 --> 00:11:40,100
+static friction مضروب في ال ... اللي ... اللي هو ال
+
+162
+00:11:40,100 --> 00:11:42,660
+normal force إذا 0.65 مضروبة في ال
+
+163
+00:11:42,660 --> 00:11:45,480
+normal force التي حسبناها هنا 33.9 22.1 هذه ... هذه ال
+
+164
+00:11:45,480 --> 00:11:49,580
+maximum static friction force لإيجاد ال actual
+
+165
+00:11:54,980 --> 00:11:59,020
+static friction force required to keep the block
+
+166
+00:11:59,020 --> 00:12:03,680
+at rest بدي أوجد ال actual اللي هي قوة الاحتكاك
+
+167
+00:12:03,680 --> 00:12:08,060
+الحقيقية الموجودة على الجسم وتمنع الجسم أن
+
+168
+00:12:08,060 --> 00:12:12,020
+يتحرك طبعا بالنسبة للقوة في اتجاه ال x
+
+169
+00:12:12,020 --> 00:12:16,550
+مجموع Fx تساوي m في ax تساوي صفر
+
+170
+00:12:16,550 --> 00:12:19,670
+لا توجد حركة في اتجاه ال x الذي اعتبرناه
+
+171
+00:12:19,670 --> 00:12:23,990
+السطح المائل and expressions for two
+
+172
+00:12:23,990 --> 00:12:27,630
+forces acting parallel to the x-axis الآن في عندي
+
+173
+00:12:27,630 --> 00:12:30,950
+قوة الجاذبية ناقص Fs تساوي صفر لا توجد حركة
+
+174
+00:12:30,950 --> 00:12:35,270
+نعتبر أنه لا توجد حركة فال ax قوة الجاذبية اللي هي
+
+175
+00:12:35,270 --> 00:12:38,990
+عبارة عن mg sin الزاوية ناقص Fs تساوي
+
+176
+00:12:38,990 --> 00:12:44,130
+صفر بدي أحل أوجد اللي هي Fs من هذه من هي
+
+177
+00:12:44,130 --> 00:12:49,790
+المعادلة فال Fs يجب أن تساوي القوة اللي هي القوة اللي
+
+178
+00:12:49,790 --> 00:12:54,990
+هي mg sin الزاوية هي هي علشان أوجدها هي Fs
+
+179
+00:12:54,990 --> 00:12:57,490
+تساوي mg sin الزاوية لأننا اعتبرنا Fs
+
+180
+00:12:57,490 --> 00:13:00,390
+
+223
+00:16:14,890 --> 00:16:18,550
+اتجاه هيكون قوة الاحتكاك الساكن المؤثرة على العربة
+
+224
+00:16:18,550 --> 00:16:24,210
+الصغيرة الآن ال .. الآن الشاحنة العربة الكبيرة
+
+225
+00:16:24,210 --> 00:16:29,790
+الشاحنة بتمشي للشرق فقوة الاحتكاك الساكن على السطح
+
+226
+00:16:31,320 --> 00:16:37,900
+على سطح العربة قوة الاحتكاك الساكن على سطح العربة
+
+227
+00:16:37,900 --> 00:16:42,900
+اللي هو فوق العربة اللي مش على الأرض اللي هو السطح
+
+228
+00:16:42,900 --> 00:16:46,820
+البيت تبع الtruck هيكون غرب .. للغرب لأن هذا
+
+229
+00:16:46,820 --> 00:16:52,910
+العربة بتمشي للشرق فهيكون هو للغرب وبالتالي السطح
+
+230
+00:16:52,910 --> 00:16:57,330
+التحتاني تبقى العربة الصغيرة هيتعرض لقوة احتكاك
+
+231
+00:16:57,330 --> 00:17:01,450
+تساوي قوة الاحتكاك سطح الtruck ولكن باتجاه
+
+232
+00:17:01,450 --> 00:17:05,690
+المعاكس طبعا سطح الtruck هيتعرض لقوة احتكاك إلى
+
+233
+00:17:05,690 --> 00:17:10,560
+الغرب لأنه الحركة إلى الشرق فقوة الاحتكاك الخاصة
+
+234
+00:17:10,560 --> 00:17:13,600
+بالعربة الصغيرة اللي هو السطح التحتاني للعربة
+
+235
+00:17:13,600 --> 00:17:17,660
+الصغيرة هيكون إلى الشرق يعني في عندي أنا جسمين
+
+236
+00:17:17,660 --> 00:17:22,320
+الجسمين متلامسين متلامسين وبيحتكوا في بعض السطح ال
+
+237
+00:17:22,320 --> 00:17:28,140
+.. ال .. السطح الأعلى للشاحنة هيتعرض لقوة احتكاك
+
+238
+00:17:28,140 --> 00:17:31,660
+ساكنة إلى الغرب لإن حركة العرب الشاحنة الكبيرة
+
+239
+00:17:31,660 --> 00:17:36,150
+للشرق العربة الصغيرة اللي جالسة على الشاحنة السطح
+
+240
+00:17:36,150 --> 00:17:40,750
+التحتاني للعربة الصغيرة هيتعرض لاحتكاك باتجاه
+
+241
+00:17:40,750 --> 00:17:41,330
+الشرق
+
+242
+00:17:46,540 --> 00:17:50,200
+Suppose your friend is sitting on the sled and asks
+
+243
+00:17:50,200 --> 00:17:55,100
+you to move her across a flat  لو كان عندي أنا عرب
+
+244
+00:17:55,100 --> 00:18:00,040
+التزلج زي ما هو موضح بالشكل طلبت مني و أنا جالس
+
+245
+00:18:00,040 --> 00:18:06,460
+عليها طلبت من زميل يدفعني بزاوية بهذا الشكل بيدفع
+
+246
+00:18:06,460 --> 00:18:12,300
+فالزاوية هتكون لتحت هيك هنا الزاوية فالزاوية
+
+247
+00:18:12,300 --> 00:18:15,480
+ثلاثين هتكون تحت الhorizontal تحت الhorizontal
+
+248
+00:18:17,070 --> 00:18:23,190
+هيدفع العربة بقوة معينة Suppose your friend is
+
+249
+00:18:23,190 --> 00:18:27,830
+sitting on a sled and asks you to move her across
+
+250
+00:18:27,830 --> 00:18:31,350
+a flat horizontal field. You have a choice يا ترى
+
+251
+00:18:31,350 --> 00:18:34,950
+pushing her from behind by applying a force
+
+252
+00:18:34,950 --> 00:18:38,370
+downward on her shoulder at thirty degrees below the
+
+253
+00:18:38,370 --> 00:18:44,230
+horizontal, or attaching a rope to the front of the
+
+254
+00:18:44,230 --> 00:18:47,110
+sled and pulling with a force thirty degrees above the
+
+255
+00:18:47,110 --> 00:18:51,760
+horizontal. Which option would be
+
+256
+00:18:51,760 --> 00:18:57,660
+easier and why؟ الآن لو كان عندي أنا الحركتين لو
+
+257
+00:18:57,660 --> 00:19:04,660
+أنا دفعته دفع أو شديته شد مين أسهل بالحركة؟ مين أسهل
+
+258
+00:19:04,660 --> 00:19:09,660
+بالحركة؟ لو أنا دفعته دفع ولا شديته شد؟ الآن مين
+
+259
+00:19:09,660 --> 00:19:15,400
+أسهل بالحركة؟ لازم نجيب اللي هي الnormal force لو
+
+260
+00:19:15,400 --> 00:19:19,240
+أنا حددت الnormal force هنا، الnormal وتحت الmg
+
+261
+00:19:19,240 --> 00:19:25,420
+هحلل الF إلى F cosine وهنا F sine هيطلع لF اللي
+
+262
+00:19:25,420 --> 00:19:28,200
+هي F sine الزاوية زاد الnormal بتساوي الmg
+
+263
+00:19:28,200 --> 00:19:33,160
+فبيطلع الnormal بده يساوي الmg ناقص اللي هي
+
+264
+00:19:33,160 --> 00:19:37,640
+الF sine الثلاثين فمعنى الكلام الnormal هيكون
+
+265
+00:19:37,640 --> 00:19:42,850
+الmg ناقص الF sine الثلاثين في هذه الحالة الحالة
+
+266
+00:19:42,850 --> 00:19:47,390
+الأولى لو بدي أنا يعني أحلل هو هو نازل بهذا الشكل
+
+267
+00:19:47,390 --> 00:19:54,810
+أحلل اللي هي القوة إلى بهذا الشكل إلى F لو أنا
+
+268
+00:19:54,810 --> 00:19:59,450
+أخذته بهذا ال .. هنا هيكون عندي هنا F cosine و
+
+269
+00:19:59,450 --> 00:20:04,090
+لتحت هتكون الF sine وفيه إلى أعلى الnormal هيكون
+
+270
+00:20:04,090 --> 00:20:07,830
+عندي الnormal بتساوي الMG زائد اللي هي ال
+
+271
+00:20:07,830 --> 00:20:11,850
+normal زائد الF sine الزاوية وبالتالي اللي ال
+
+272
+00:20:11,850 --> 00:20:17,170
+normal اللي الnormal الخاص بها بيكون قليل بيكون
+
+273
+00:20:17,170 --> 00:20:22,250
+قوة الاحتكاك أقل لأن الFS بتساوي أو الFK بتساوي
+
+274
+00:20:22,250 --> 00:20:27,380
+ميو كي في الnormal. الحل By exerting an upward
+
+275
+00:20:27,380 --> 00:20:31,520
+force component on the sled, you reduce the normal
+
+276
+00:20:31,520 --> 00:20:35,280
+force on the ground and so reduce the force of
+
+277
+00:20:35,280 --> 00:20:39,360
+friction. لو أنا اتحركت بدأ أطلع الnormal
+
+278
+00:20:39,360 --> 00:20:45,780
+إذا كان الnormal كبير فبتكون قوة الاحتكاك من
+
+279
+00:20:45,780 --> 00:20:51,950
+المتحركة كبيرة، وبيكون إيه؟ بيكون يعني أقل حركة أو
+
+280
+00:20:51,950 --> 00:20:55,970
+صعوبة في الحركة لو كانت قوة الnormal قليلة
+
+281
+00:20:55,970 --> 00:20:58,750
+بتكون قوة الاحتكاك قليلة وبتكون سهلة في الحركة
+
+282
+00:20:58,750 --> 00:21:04,150
+فاللي أسهل بالحركة اللي هو B الحالة هذه لإنه
+
+283
+00:21:04,150 --> 00:21:06,830
+بيكون عندي أنا هنا لما أجي أحل الhand بيكون عندك F
+
+284
+00:21:06,830 --> 00:21:11,400
+sine وفيه normal وفتحت الMG فهنا الnormal زائد ال
+
+285
+00:21:11,400 --> 00:21:15,860
+MG sine الF sine بتساوي الMG إذا الnormal
+
+286
+00:21:15,860 --> 00:21:20,220
+بتساوي الMG ناقص الF sine الMG ناقص الF sine
+
+287
+00:21:20,220 --> 00:21:24,220
+اللي بالأعلى بدها تكون الnormal بتساوي الMG زائد
+
+288
+00:21:24,220 --> 00:21:29,200
+F sine فهذه أسهل في الحركة لإنه الnormal أقل
+
+289
+00:21:29,200 --> 00:21:33,380
+بيكون قيمته أقل وبالتالي أسهل في الحركة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_postprocess.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_postprocess.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f55446dcc5abfca1f98f836b76c8cb14529ff463
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_postprocess.srt
@@ -0,0 +1,1156 @@
+1
+00:00:00,000 --> 00:00:04,360
+بسم الله الرحمن الرحيم نستكمل chapter أربعة هذا
+
+2
+00:00:04,360 --> 00:00:07,820
+section أربعة أربعة one upon one static friction
+
+3
+00:00:07,820 --> 00:00:12,160
+forces when a horizontal force F is exerted
+
+4
+00:00:12,160 --> 00:00:17,780
+against an object such as trash canthe trash can
+
+5
+00:00:17,780 --> 00:00:20,760
+type licker does not move unless the force exceeds
+
+6
+00:00:20,760 --> 00:00:25,640
+some critical value معامل هذه قوة الاحتكاك الساكنة
+
+7
+00:00:25,640 --> 00:00:32,400
+عندما طبعا عندما يكون لدينا قوة في اتجاه الأفقي ال
+
+8
+00:00:32,400 --> 00:00:38,950
+horizontal إذا زادت هذه القوةعن قوة معينة او حد
+
+9
+00:00:38,950 --> 00:00:42,350
+معين اللي هي ال critical value ممكن انه هذه العربة
+
+10
+00:00:42,350 --> 00:00:46,510
+او سلة القمامة انها يعني ت .. ت .. تنزاح او تنجر
+
+11
+00:00:46,510 --> 00:00:51,290
+لكن اذا كان انا باعطي هذه ال .. هذا .. هذا ال ..
+
+12
+00:00:51,290 --> 00:00:54,210
+يعني هذه السلة او هذا البرميل باعطيه قوة ولم ..
+
+13
+00:00:54,210 --> 00:00:59,420
+ولم يتحرك فإذا هناك .. هناك قوة احتكاك ساكنthe
+
+14
+00:00:59,420 --> 00:01:03,040
+critical value is maximum static friction في قوة
+
+15
+00:01:03,040 --> 00:01:06,920
+حرجة بيسموها اللي هي maximum static friction أقصى
+
+16
+00:01:06,920 --> 00:01:11,080
+قوة لقوة الاحتكاك بعدها الجسم بتحرك يعني لو أعطيت
+
+17
+00:01:11,080 --> 00:01:16,330
+أنا جسم برميل ولا طاولة ولا كتلة كبيرةيعني دفعتها
+
+18
+00:01:16,330 --> 00:01:19,670
+بقوة لم تتحرك و دفعتها بكمان قوة و لم تتحرك كل هذه
+
+19
+00:01:19,670 --> 00:01:23,110
+القوة اللي أنا بدفعها فيها اسمها قوة احتكاك ساكن
+
+20
+00:01:23,110 --> 00:01:26,750
+لإنه في معامل احتكاك ساكن بين الجسم و بين هذه
+
+21
+00:01:26,750 --> 00:01:30,370
+الكتلة the actual aesthetic force is always less
+
+22
+00:01:30,370 --> 00:01:34,540
+than or equal to the maximumمعنى الكلام أنه قيمة
+
+23
+00:01:34,540 --> 00:01:40,360
+اللي هو قوة الاحتكاك الساكنة الحقيقية هي عبارة
+
+24
+00:01:40,360 --> 00:01:44,780
+تساوي اللي هي القوة ال maximum أو أقل منها طبعا
+
+25
+00:01:44,780 --> 00:01:50,590
+هذا الشكل بيبين graphicallyكيف انه احنا ممكن الشكل
+
+26
+00:01:50,590 --> 00:01:54,990
+ال .. ال .. هذا ال .. الأسفل تبين لي انه في عندي
+
+27
+00:01:54,990 --> 00:01:59,350
+أنحاوية معينة في عندي قوة احتكاك قوة يعني applied
+
+28
+00:01:59,350 --> 00:02:03,330
+force و طبعا هذه قوة احتكاك ساكن عكس هذه القوة
+
+29
+00:02:03,330 --> 00:02:07,350
+طالما انا بشد هذا الجسم ولا ما يتحرك و شدت ولا ما
+
+30
+00:02:07,350 --> 00:02:12,870
+يتحرك في ازوية قوة احتكاك ساكن قيمة هذه القوة قوة
+
+31
+00:02:12,870 --> 00:02:16,070
+احتكاك الساكن بتساويقيمة ال applied force في هذه
+
+32
+00:02:16,070 --> 00:02:19,690
+الحالة انه برضه مش هيتحرك في عندنا ال normal force
+
+33
+00:02:19,690 --> 00:02:22,850
+اللي هي عكس قوة الجاذبية عكس الوزن اللي هو ال MG
+
+34
+00:02:22,850 --> 00:02:26,890
+الآن في هذا الشكل بلاحظ انه انا زودت القوة اللي
+
+35
+00:02:26,890 --> 00:02:31,270
+اعطته إياها فالجسم اتحرك اتحرك معناته عامل حركة
+
+36
+00:02:31,270 --> 00:02:34,370
+اللي هو ال motionعندما يتحرك الاساسم بتتحور قوة
+
+37
+00:02:34,370 --> 00:02:38,990
+الاحتكاك الساكن إلى قوة احتكاك متحرك بيحكي لي هذا
+
+38
+00:02:38,990 --> 00:02:41,730
+الشكل when the magnitude of the applied force إذا
+
+39
+00:02:41,730 --> 00:02:46,430
+كانت قيمة القوة المعطاة زادت عن قيمة اللي هي
+
+40
+00:02:46,430 --> 00:02:50,310
+maximum force of static friction أعلى من قيمة قوة
+
+41
+00:02:50,310 --> 00:02:54,130
+الاحتكاك الساكن معناها هذا هذه سالة القمامة وبرميل
+
+42
+00:02:54,130 --> 00:02:58,050
+القمامة ممكن أنه يتحرك و brakes free and
+
+43
+00:02:58,050 --> 00:03:03,540
+accelerate to the right بتحرك لليامينطبعا الجمال
+
+44
+00:03:03,540 --> 00:03:07,840
+السابقة تسبق هذا الكلام نحكي ان when the applied
+
+45
+00:03:07,840 --> 00:03:11,000
+force exceed the maximum static force the object
+
+46
+00:03:11,000 --> 00:03:14,700
+begin to move الجسم بيتحرك بتتحول قوة الاحتكاك
+
+47
+00:03:14,700 --> 00:03:21,000
+الساكنالى قوة احتكاك متحرك كمان بدل ما استخدم mus
+
+48
+00:03:21,000 --> 00:03:24,900
+باستخدم muk الـ kinetic friction coefficient معامل
+
+49
+00:03:24,900 --> 00:03:30,240
+الاحتكاك المتحرك أقل من قوة الاحتكاك الساكن كما هو
+
+50
+00:03:30,240 --> 00:03:37,360
+موضح muk أقل من musمعنى الكلام إنه النقوة الاحتكاك
+
+51
+00:03:37,360 --> 00:03:43,600
+الساكن إلها قيمة عظمة وإلها تدرج من ال zero لأعلى
+
+52
+00:03:43,600 --> 00:03:48,340
+قيمة عظمة كما هو موضح بهذا الشكل أنا هندي .. هندي
+
+53
+00:03:48,340 --> 00:03:51,520
+أنا هنا في static region هذا المنطقة منطقة احتكاك
+
+54
+00:03:51,520 --> 00:03:54,780
+ولكن ساكن يعني لما يكون عندي جسم انا .. انا دفعت
+
+55
+00:03:54,780 --> 00:03:58,460
+وما اتحركأنا أعطيته قوة لكن ما اتحرك قوة احتكاك
+
+56
+00:03:58,460 --> 00:04:02,440
+ساكن أعطيته زودت القوة ما اتحرك زودت القوة ما
+
+57
+00:04:02,440 --> 00:04:06,320
+اتحرك إلى حد معين بيسموها ال critical طبعا هي
+
+58
+00:04:06,320 --> 00:04:10,240
+point أو النقطة الحرجة هذه بعدها إذا هو اتحرك
+
+59
+00:04:10,240 --> 00:04:14,080
+بتكون أنا وصلت لل maximum static friction ال force
+
+60
+00:04:14,080 --> 00:04:17,060
+اللي هي أعلى قيمة لقوة الاحتكاك الساكن بعدها
+
+61
+00:04:17,060 --> 00:04:21,240
+بيتحرك فبيتحول قوة الاحتكاك الساكن إلى قوة احتكاك
+
+62
+00:04:21,240 --> 00:04:24,760
+متحرك وبالتالي في عندي أنا هنا منطقة الاحتكاك
+
+63
+00:04:24,760 --> 00:04:25,620
+المتحرك
+
+64
+00:04:28,480 --> 00:04:31,840
+الـ static friction force الـ static friction
+
+65
+00:04:31,840 --> 00:04:35,480
+force the magnitude of the static friction force
+
+66
+00:04:35,480 --> 00:04:41,480
+اللي هي قيمة قوة الاحتكاك الساكن ورمزها Fs تؤثر
+
+67
+00:04:41,480 --> 00:04:48,080
+على الجسم at rest satisfy the inequality أن الـ Fs
+
+68
+00:04:48,080 --> 00:04:52,760
+تتراوح بين الـ 0 للـ F maximumهذه ال Fs تتروح بين
+
+69
+00:04:52,760 --> 00:04:57,820
+أكبر أو تساوي 0 أو أقل أو تساوي ال F static force
+
+70
+00:04:57,820 --> 00:05:01,960
+maximum وده تساوي Mu S في ال normal قيمتها Mu S في
+
+71
+00:05:01,960 --> 00:05:05,180
+ال normal اللي هي ال F static friction force
+
+72
+00:05:05,180 --> 00:05:09,440
+maximum تساوي Mu S في ال normal لكنها تتروح من ال
+
+73
+00:05:09,440 --> 00:05:14,870
+0 ل Fs maximumالـ N is the normal force الـ N هذه
+
+74
+00:05:14,870 --> 00:05:19,030
+عبارة عن قوت رد الفعل العمودية و Mu S is the
+
+75
+00:05:19,030 --> 00:05:22,650
+coefficient of maximum static friction اللي هي
+
+76
+00:05:22,650 --> 00:05:25,910
+عبارة عن معامل الاحتكاك الساكن between بين ال
+
+77
+00:05:25,910 --> 00:05:30,150
+object and the surface بين أي جسم و بين السطح the
+
+78
+00:05:30,150 --> 00:05:34,350
+force Fs قوت الاحتكاك الساكن acts in the direction
+
+79
+00:05:34,350 --> 00:05:39,350
+opposite that of the embedding motionقوة الاحتكاك
+
+80
+00:05:39,350 --> 00:05:44,750
+الساكن بيكون اتجاهها عكس اتجاه الحركة هذا الكلام
+
+81
+00:05:44,750 --> 00:05:49,470
+بتشبه قوة الاحتكاك المتحرك على أساس أنه اتجاه قوة
+
+82
+00:05:49,470 --> 00:05:53,730
+الاحتكاك المتحرك أو الساكن بيكون عكس الحركة قوة
+
+83
+00:05:53,730 --> 00:05:56,890
+الاحتكاك الساكن بتكون عكس القوة قوة الاحتكاك
+
+84
+00:05:56,890 --> 00:06:01,930
+المتحرك بتكون عكس اللي هو القوةأو الحركة the
+
+85
+00:06:01,930 --> 00:06:05,550
+static friction force takes on any value between
+
+86
+00:06:05,550 --> 00:06:09,690
+zero and its maximum value قوة الاحتكاك الساكن
+
+87
+00:06:09,690 --> 00:06:14,850
+تاخد قيم من zero إلى أقصى قيمة اللي هي بيسموها ال
+
+88
+00:06:14,850 --> 00:06:19,530
+maximum value mu S في ال normal تعتمد على قيمة
+
+89
+00:06:19,530 --> 00:06:23,250
+القوة المعطاة depending on the magnitude of the
+
+90
+00:06:23,250 --> 00:06:27,470
+applied forceThe static friction force self
+
+91
+00:06:27,470 --> 00:06:31,510
+-adjusts depending on the net force acting on the
+
+92
+00:06:31,510 --> 00:06:36,010
+object برضه ال static frictional force قوة احتكاك
+
+93
+00:06:36,010 --> 00:06:40,630
+الساكن ممكن احنا نضبطها او نعيرها بحيث انها تعتمد
+
+94
+00:06:40,630 --> 00:06:46,000
+على مجموعة او محصلة القوة المؤثرة على الجسمsuch
+
+95
+00:06:46,000 --> 00:06:49,340
+self-adjustment is illustrated in the figure زي
+
+96
+00:06:49,340 --> 00:06:54,060
+هذا الشكل اللي هي القوة المحصلة المؤثرة على الجسم
+
+97
+00:06:54,060 --> 00:06:59,340
+كهذا الشكل طبعا عندي أنا هنا applied force الشخص
+
+98
+00:06:59,340 --> 00:07:04,920
+دفع تلاجة إلى الأمامفي عندها ال F applied فالتلاجة
+
+99
+00:07:04,920 --> 00:07:09,100
+دي ما اتحركت وبالتالي ال Fs بدها تساوي أقل من ال
+
+100
+00:07:09,100 --> 00:07:13,060
+Mu S في ال normal ال Fs اللي هي موجودة حكينا
+
+101
+00:07:13,060 --> 00:07:17,240
+بتتروح من ال zero ل ال F maximum فالمؤثر على هذه
+
+102
+00:07:17,240 --> 00:07:21,940
+التلاجة F applied اللي هي بتساوي أقل من ال Mu S في
+
+103
+00:07:21,940 --> 00:07:27,220
+ال normalلو أنا زودت القوة، زودنا القوة، زودت
+
+104
+00:07:27,220 --> 00:07:31,120
+القوة صارت ال Fs بدها تساوي Mu S في ال normal في
+
+105
+00:07:31,120 --> 00:07:34,220
+هذه الحالة و ال F اللي هي ال applied هذه بدها
+
+106
+00:07:34,220 --> 00:07:40,050
+تساوي ال Fs اللي هي ال Mu S في ال normalبعد هيك
+
+107
+00:07:40,050 --> 00:07:44,870
+زودنا القوة شوية صارت عندي ال F applied أكبر من ال
+
+108
+00:07:44,870 --> 00:07:51,570
+Fs إذا الجسم هيتحرك بدل ال Fs حطينا ال Fk صارت
+
+109
+00:07:51,570 --> 00:07:56,790
+عندي أنه في عندي حركة اتحولت ال Fs إلى Fk وبالتالي
+
+110
+00:07:56,790 --> 00:08:00,270
+بقى أنا بيصير عندي حركة بتصير ال F applied ناقص ال
+
+111
+00:08:00,270 --> 00:08:03,630
+Fk بتساوي ال mass في ال acceleration صار عندي
+
+112
+00:08:03,630 --> 00:08:08,900
+مجموعة القوة باتجاه ال X axis بتساوي M في Aطبعا
+
+113
+00:08:08,900 --> 00:08:13,360
+هذا هو موضح في الشكل 24 بنحكي أنه ال .. أنا في
+
+114
+00:08:13,360 --> 00:08:17,800
+عندى قوة زودتها شوية شوية حتى في .. في أكتر من
+
+115
+00:08:17,800 --> 00:08:21,400
+حالة الحالة الأولى أنه ما اتحركت التلاجة الحالة
+
+116
+00:08:21,400 --> 00:08:24,360
+التانى كانت القوة اللى انا أعطيتهيا بالساوية أفقاس
+
+117
+00:08:24,360 --> 00:08:27,520
+الحالة التالتة أن القوة كانت أكبر من الأفقاس إذا
+
+118
+00:08:27,520 --> 00:08:32,530
+اتحرك الجسمexample as shown in the figures في عندي
+
+119
+00:08:32,530 --> 00:08:38,290
+block جسم having mass جسم له كتلة أربع كيلو جرام
+
+120
+00:08:38,290 --> 00:08:42,210
+rest on slope that make an angle of تلاتين هذا
+
+121
+00:08:42,210 --> 00:08:46,530
+الجسم محطوط على سطح ميل بزاوية تلاتين درجة كتلة
+
+122
+00:08:46,530 --> 00:08:51,850
+هذا الجسم أربع كيلو جرامwith the horizontal طبعا
+
+123
+00:08:51,850 --> 00:08:54,710
+التلاتين هي عبارة عن الزاوية المحصورة بين المستوى
+
+124
+00:08:54,710 --> 00:08:57,550
+وبين اللي هي ال horizontal if the coefficient of
+
+125
+00:08:57,550 --> 00:09:00,310
+static friction between the block and the surface
+
+126
+00:09:00,310 --> 00:09:07,090
+it rests upon is ال معامل الاحتكاك الساكن point 65
+
+127
+00:09:07,860 --> 00:09:12,040
+calculate مطلوب إيجاد the normal force و ال
+
+128
+00:09:12,040 --> 00:09:15,680
+maximum static force بده قوة إيراد الفعل العمودية
+
+129
+00:09:15,680 --> 00:09:19,880
+و بده أقصى قيمة لل static force كمان مطلوب ال
+
+130
+00:09:19,880 --> 00:09:24,040
+actual static friction force required to prevent
+
+131
+00:09:24,040 --> 00:09:27,700
+the block from moving بده ال actual static
+
+132
+00:09:27,700 --> 00:09:33,380
+friction هي force بده قيمة القوة الاحتكاك الساكن
+
+133
+00:09:33,380 --> 00:09:37,040
+الحقيقية اللي أنا بحتاجها عشان أمنع حركة هذا الجسم
+
+134
+00:09:37,530 --> 00:09:41,070
+و بعدين حكيلنا will the block begin to move or
+
+135
+00:09:41,070 --> 00:09:46,510
+remain at rest هل الجسم بدى يتحرك ولا بدى ضال ثابت
+
+136
+00:09:46,510 --> 00:09:50,110
+يعني هى الجسم كتلته أربعة بميلة بزاوية تلاتين درجة
+
+137
+00:09:50,110 --> 00:09:55,770
+أعطانى معامل احتجازات الساكن ال US 0.65 من خلال
+
+138
+00:09:55,770 --> 00:10:00,210
+هذا الشكل بدى أوجد انا ال actual اللى هى ال static
+
+139
+00:10:00,210 --> 00:10:03,630
+friction طبعا اول حاجة لازم اعمل free body diagram
+
+140
+00:10:03,630 --> 00:10:08,020
+لهذا الشكل بنزل ال MGأو قوة الجاذبية اللي هي ال FG
+
+141
+00:10:08,020 --> 00:10:12,460
+هي عبارة عن سوء ال M في G بنحلل اللي هي ال MG إلى
+
+142
+00:10:12,460 --> 00:10:18,220
+MG Cos و MG Sin على المستوى MG Cos و MG Sin على
+
+143
+00:10:18,220 --> 00:10:22,640
+المستوى في عندي هنا Normal طبعا الجسم بده ينزل إلى
+
+144
+00:10:22,640 --> 00:10:26,760
+أسفل في عندي قوة احتكاك ساكن تمنعه من الحركة بدنا
+
+145
+00:10:26,760 --> 00:10:31,180
+نشوف هل الجسم بده يتحرك ام الجسم بده يبقى ساكن كما
+
+146
+00:10:31,180 --> 00:10:36,360
+هولإيجاد المطلوب الأول الان دى ال three forces فى
+
+147
+00:10:36,360 --> 00:10:40,000
+عندى تلت قوة مؤثرة على الجسم فى عندى قوت الجاذبية
+
+148
+00:10:40,000 --> 00:10:44,300
+MG وفى عندى ال normal force اللى هى ال N و ال
+
+149
+00:10:44,300 --> 00:10:48,560
+static friction force Fs بدي أختار ال coordinate
+
+150
+00:10:48,560 --> 00:10:53,040
+على أساس أنه بدي أختار محاور X و Y باختار ال X
+
+151
+00:10:53,040 --> 00:10:57,020
+axis positive X axis اللى هى أسفل اللى هو المنحدر
+
+152
+00:10:57,020 --> 00:11:01,610
+أو أسفل السطح المايل لليمين بيعتبر X الموجبو ال y
+
+153
+00:11:01,610 --> 00:11:06,910
+العمودي عليه اللي هو ال positive y axis is
+
+154
+00:11:06,910 --> 00:11:10,090
+perpendicular to the أسلوب عمودي على اللي هو هذا
+
+155
+00:11:10,090 --> 00:11:14,010
+الخط نحسب ال normal force طبعا عشان أحسب ال normal
+
+156
+00:11:14,010 --> 00:11:16,350
+force ال normal force في هذه الحالة بتساوي ال mg
+
+157
+00:11:16,350 --> 00:11:20,260
+cosine الزاويةالـ M كانت أربعة والـ G تسعة و
+
+158
+00:11:20,260 --> 00:11:23,600
+تمانية من عشرة كزاين التلاتين تلاتة و تلاتين point
+
+159
+00:11:23,600 --> 00:11:26,900
+تسعة هذا ال normal force لإيجاد ال maximum
+
+160
+00:11:26,900 --> 00:11:31,620
+possible static frictional force ال Fs maximum
+
+161
+00:11:31,620 --> 00:11:36,640
+عبارة عن Mu S في ال normal اللي هو coefficient of
+
+162
+00:11:36,640 --> 00:11:40,100
+static friction مضروب في ال .. اللي .. اللي هو ال
+
+163
+00:11:40,100 --> 00:11:42,660
+normal force إذا point ستة خمسة مضروبة في ال
+
+164
+00:11:42,660 --> 00:11:45,480
+normal force اللي إحنا جبناها هنا تلاتة و تلاتين
+
+165
+00:11:45,480 --> 00:11:49,580
+point تسعة اتنين و عشرين point واحدهذه .. هذه ال
+
+166
+00:11:49,580 --> 00:11:54,980
+maximum static friction force لإيجاد ال actual
+
+167
+00:11:54,980 --> 00:11:59,020
+static friction force required to keep the block
+
+168
+00:11:59,020 --> 00:12:03,680
+to rest بدي أوجد ال actual اللي هو قوة الاحتكاك
+
+169
+00:12:03,680 --> 00:12:08,060
+الحقيقية اللي موجودة على الجسم و بتمنع الجسم انه
+
+170
+00:12:08,060 --> 00:12:12,020
+يتحرك طبعا بالنسبة للقوة اللي في تجاه ال X
+
+171
+00:12:12,020 --> 00:12:16,550
+summation لل Fx بتساوي ال M في Xax بتساوي zero
+
+172
+00:12:16,550 --> 00:12:19,670
+مافيش حركة باتجاه ال x اللي هو اللي احنا اعتبرناه
+
+173
+00:12:19,670 --> 00:12:23,990
+السطح اللي هو المائل and expressions for two
+
+174
+00:12:23,990 --> 00:12:27,630
+forces acting parallel to the x-axis الان في عندى
+
+175
+00:12:27,630 --> 00:12:30,950
+قوة الجاذبية ناقص أف أس بتساوي zero مافيش حركة
+
+176
+00:12:30,950 --> 00:12:35,270
+بنعتبر أنه مافيش حركة فالax ال gravity اللي هي
+
+177
+00:12:35,270 --> 00:12:38,990
+عبارة عن ال mg صين الزاوية ناقص الأف أس بتساوي
+
+178
+00:12:38,990 --> 00:12:44,130
+zeroبدي أحل أوجد اللى هى ال Fs من هذا ال من هى
+
+179
+00:12:44,130 --> 00:12:49,790
+المعادلة فال Fs بدها تساوي ال F اللى هى ال F اللى
+
+180
+00:12:49,790 --> 00:12:54,990
+هى MG صين الزاوية هى هى علشان أوجدها هى ال Fs
+
+181
+00:12:54,990 --> 00:12:57,490
+بتساوي ال MG صين الزاوية لإنه احنا اعتبرت ال Fs
+
+182
+00:12:57,490 --> 00:13:00,390
+ناقص ال MG بساوي Zero اذا ال Fs بتساوي ال MG صين
+
+183
+00:13:00,390 --> 00:13:04,430
+الزاوية فبتطلع ال actual static frictional force
+
+184
+00:13:04,430 --> 00:13:10,260
+acting on the body بتساوي 19.6لكن ال maximum .. ال
+
+185
+00:13:10,260 --> 00:13:13,940
+frictional .. maximum static force acting on the
+
+186
+00:13:13,940 --> 00:13:19,200
+.. on the body كانت واحد و عشرين .. واحد و عشرين
+
+187
+00:13:19,200 --> 00:13:22,540
+point واحد فبدى أعرف هنا determine whether the
+
+188
+00:13:22,540 --> 00:13:27,160
+block will begin to moveهل الجسم بده يتحرك ولا لأ
+
+189
+00:13:27,160 --> 00:13:31,260
+فمن خلال انه ال maximum static frictional force 22
+
+190
+00:13:31,260 --> 00:13:35,900
+.1 و القوة اللى انا اعطتهياها 19.6 او القوة اللى
+
+191
+00:13:35,900 --> 00:13:40,740
+موجودة عليه ال actual static frictional force 19.6
+
+192
+00:13:40,740 --> 00:13:47,180
+معناته الجسم لا يتحرك the block remains at rest on
+
+193
+00:13:47,180 --> 00:13:50,840
+the slope لإنه ال maximum frictional force بتساوي
+
+194
+00:13:50,840 --> 00:13:58,160
+22.1و بالتالي الجسم لايتحرك نجي لهذا ال quiz quiz
+
+195
+00:13:58,160 --> 00:14:03,200
+number four point five if you press a block flat
+
+196
+00:14:03,200 --> 00:14:07,400
+against a vertical wall لو كان عندي أنا حيطة هيها
+
+197
+00:14:07,400 --> 00:14:12,320
+مثلا و بدي أنا أضغط الكتاب على الحيطة بإيدي بدي
+
+198
+00:14:12,320 --> 00:14:17,500
+أضغط الكتاب على الحيطة بإيدي will with your hand
+
+199
+00:14:17,500 --> 00:14:20,760
+in what direction is the friction force exerted by
+
+200
+00:14:20,760 --> 00:14:24,800
+the wall in the blockهل بدى يكون downward ولا
+
+201
+00:14:24,800 --> 00:14:30,220
+upward ولا out from the wall ولا into the wall؟
+
+202
+00:14:30,220 --> 00:14:34,810
+الآن أنا بضغط الكتاب بإيدي على الحيطةإيدي هتكون
+
+203
+00:14:34,810 --> 00:14:39,010
+عمودية على الحيطة وبالتالي ال normal force هتكون
+
+204
+00:14:39,010 --> 00:14:43,310
+طالعة من الصفحة ال normal force لتحت هيكون عندنا
+
+205
+00:14:43,310 --> 00:14:49,750
+احنا لتحت هيكون عندنا اللي هو ال MG اللي اللي اللي
+
+206
+00:14:49,750 --> 00:14:53,830
+بيمنع الجسم انه يتحرك هي في عندنا static
+
+207
+00:14:53,830 --> 00:14:58,150
+frictional force بيكون اتجاهها ل .. لأعلى عكس اللي
+
+208
+00:14:58,150 --> 00:15:02,290
+هو ال MG لو انه كان لو كان ال MG أكبر من الأفقاس
+
+209
+00:15:02,290 --> 00:15:06,780
+الجسم هيتحركلكن طالما أن الجسم مش هيتحرك و القوة
+
+210
+00:15:06,780 --> 00:15:11,440
+اللى بتمنع الجسم انه يتحرك كانت Fs وكانت باتجاه
+
+211
+00:15:11,440 --> 00:15:16,320
+اللى هو downward اللى هو إلى أعلى لإن ال MG هتكون
+
+212
+00:15:16,320 --> 00:15:23,000
+لأسفلال quiz تاني a crate is sitting in the center
+
+213
+00:15:23,000 --> 00:15:27,240
+of a flat bed truck as the truck accelerate to the
+
+214
+00:15:27,240 --> 00:15:34,220
+east يعني لو كان عندي انا يعني عربة كبيرة زي شاحنة
+
+215
+00:15:34,220 --> 00:15:41,020
+بتتحرك والشاحنة عليها عليها جسم او عربة صغيرةذاكرت
+
+216
+00:15:41,020 --> 00:15:45,340
+العربة move with it and does not slide هلاقيتها
+
+217
+00:15:45,340 --> 00:15:51,680
+الشاحنة محملة على ظهرها عربة صغيرة الشاحنة بتمشي
+
+218
+00:15:51,680 --> 00:15:56,940
+لإلي الشارق ل الشارق الشاحنة بتمشي العربة مش اللي
+
+219
+00:15:56,940 --> 00:16:00,820
+.. العربة الصغيرة اللي على الشاحنة مش هتمشي ولكن
+
+220
+00:16:00,820 --> 00:16:04,910
+هتتحركلكن does not slide on the bed of the truck
+
+221
+00:16:04,910 --> 00:16:09,150
+in what direction is the friction force exerted by
+
+222
+00:16:09,150 --> 00:16:14,890
+the bed of the truck on the crate بيحكيلي أنه بأي
+
+223
+00:16:14,890 --> 00:16:18,550
+اتجاه هيكون قوة الاحتكاك الساكن المؤثرة على العربة
+
+224
+00:16:18,550 --> 00:16:24,210
+الصغيرة الآن ال .. الآن الشاحنة العربة الكبيرة
+
+225
+00:16:24,210 --> 00:16:29,790
+الشاحنة بتمشي للشرق فقوة الاحتكاك الساكن على السطح
+
+226
+00:16:31,320 --> 00:16:37,900
+على سطح العربة قوة الاحتكاك الساكن على سطح العربة
+
+227
+00:16:37,900 --> 00:16:42,900
+اللى هو فوق العربة اللى مش على الأرض اللى هو السطح
+
+228
+00:16:42,900 --> 00:16:46,820
+البيت تبع ال truck هيكون غرب .. للغرب لأن هذا
+
+229
+00:16:46,820 --> 00:16:52,910
+العربة بتمشي للشرق فهيكون هو للغرب وبالتاليالسطح
+
+230
+00:16:52,910 --> 00:16:57,330
+التحتاني تبقى العربة الصغيرة هيتعرض لقوة احتكاك
+
+231
+00:16:57,330 --> 00:17:01,450
+تساوي قوة الاحتكاك سطح ال truck ولكن باتجاه
+
+232
+00:17:01,450 --> 00:17:05,690
+المعاكس طبعا سطح ال truck هيتعرض لقوة احتكاك إلى
+
+233
+00:17:05,690 --> 00:17:10,560
+الغرب لأنه الحركة إلى الشارقفقوة الاحتكاك الخاصة
+
+234
+00:17:10,560 --> 00:17:13,600
+بالعربة الصغيرة اللي هو السطح التحتاني للعربة
+
+235
+00:17:13,600 --> 00:17:17,660
+الصغيرة هيكون إلى الشرق يعني في عندي أنا جسمين
+
+236
+00:17:17,660 --> 00:17:22,320
+الجسمين متلامسين متلامسين وبيحتكوا في بعض السطح ال
+
+237
+00:17:22,320 --> 00:17:28,140
+.. ال .. السطح الأعلى للشاحنة هيتعرض لقوة احتكاك
+
+238
+00:17:28,140 --> 00:17:31,660
+ساكنة إلى الغرب لإن حركة العرب الشاحنة الكبيرة
+
+239
+00:17:31,660 --> 00:17:36,150
+للشرقالعربة الصغيرة اللى جالسة على الشاحنة السطح
+
+240
+00:17:36,150 --> 00:17:40,750
+التحتانى للعربة الصغيرة هيتعرض لاحتكاك باتجاه
+
+241
+00:17:40,750 --> 00:17:41,330
+الشرق
+
+242
+00:17:46,540 --> 00:17:50,200
+suppose your friend is sitting on the sled and ask
+
+243
+00:17:50,200 --> 00:17:55,100
+you to move hair across flat لو كان عندى انا عرب
+
+244
+00:17:55,100 --> 00:18:00,040
+التزلج زى ما هو موضح بالشكل طلبت منى و انا جالس
+
+245
+00:18:00,040 --> 00:18:06,460
+عليها طلبت من زميل يدفعنى بزاوية بهذا الشكل بيدفع
+
+246
+00:18:06,460 --> 00:18:12,300
+فالزاوية هتكون لتحت هيك هنا الزاوية فالزاوية
+
+247
+00:18:12,300 --> 00:18:15,480
+تلاتين هتكون تحت ال horizontal تحت ال horizontal
+
+248
+00:18:17,070 --> 00:18:23,190
+هيدفع العربة بقوة معينة suppose your friend is
+
+249
+00:18:23,190 --> 00:18:27,830
+sitting on a sled and asks you to move her across
+
+250
+00:18:27,830 --> 00:18:31,350
+a flat horizontal field you have a choice يا ترى
+
+251
+00:18:31,350 --> 00:18:34,950
+pushing her from behind by applying a force
+
+252
+00:18:34,950 --> 00:18:38,370
+downward in her shoulder at تلاتين below the
+
+253
+00:18:38,370 --> 00:18:44,230
+horizontal orattaching a rope to the front of the
+
+254
+00:18:44,230 --> 00:18:47,110
+sled and bull with force التلاتين above the
+
+255
+00:18:47,110 --> 00:18:51,760
+horizontal ولا which optionwhich option would be
+
+256
+00:18:51,760 --> 00:18:57,660
+easier and why الان لو كان عندى انا الحركتين لو
+
+257
+00:18:57,660 --> 00:19:04,660
+انا دفعته دفع او شدته شد مين اسهل بالحركة مين اسهل
+
+258
+00:19:04,660 --> 00:19:09,660
+بالحركة لو هو انا دفعته دفع ولا شدته شد الان مين
+
+259
+00:19:09,660 --> 00:19:15,400
+اسهل بالحركة لازم نجيب اللى هى ال normal forceلو
+
+260
+00:19:15,400 --> 00:19:19,240
+انا حددت ال normal force هنا ال normal و تحت ال mg
+
+261
+00:19:19,240 --> 00:19:25,420
+هحلل ال F إلى F cosine و هنا F sine هيطلع ل F اللي
+
+262
+00:19:25,420 --> 00:19:28,200
+هي F sine الزاوية زاد ال normal بتساوي ال mg
+
+263
+00:19:28,200 --> 00:19:33,160
+فبيطلع ال normal بده يساوي ال mg ناقص ال mg اللي
+
+264
+00:19:33,160 --> 00:19:37,640
+هي ال F sine التلاتين فمعنى الكلام ال normal هيكون
+
+265
+00:19:37,640 --> 00:19:42,850
+ال mg ناقص ال F sine التلاتين في هذه الحالةالحالة
+
+266
+00:19:42,850 --> 00:19:47,390
+الأولى لو بدى انا يعني احلل هو هو نازل بهذا الشكل
+
+267
+00:19:47,390 --> 00:19:54,810
+احلل اللى هى القوة الى بهذا الشكل الى F لو أنا
+
+268
+00:19:54,810 --> 00:19:59,450
+أخدته بهذا ال .. هنا هيكون عندى هنا F cosine و
+
+269
+00:19:59,450 --> 00:20:04,090
+لتحت هتكون ال F sineوفيه إلى أعلى ال normal حيكون
+
+270
+00:20:04,090 --> 00:20:07,830
+عندي ال normal بتساوي ال MG زائد N اللي هي ال
+
+271
+00:20:07,830 --> 00:20:11,850
+normal زائد ال F sign الزاوية وبالتالي اللي ال
+
+272
+00:20:11,850 --> 00:20:17,170
+normal اللي ال normal الخاص بيها بيكون قليل بيكون
+
+273
+00:20:17,170 --> 00:20:22,250
+قوة الاحتكاك أقل لإن ال FS بتساوي أو ال FK بتساوي
+
+274
+00:20:22,250 --> 00:20:27,380
+ميو كي في ال normalالحل by exerting an upward
+
+275
+00:20:27,380 --> 00:20:31,520
+force component on the sled you reduce the normal
+
+276
+00:20:31,520 --> 00:20:35,280
+force on the ground and so reduce the force of a
+
+277
+00:20:35,280 --> 00:20:39,360
+kind of friction لو أنا اتحركت بدأ اطلع ال normal
+
+278
+00:20:39,360 --> 00:20:45,780
+إذا كان ال normal كبير فبتكون قوة الاحتكاك من
+
+279
+00:20:45,780 --> 00:20:51,950
+متحركة كبيرة و بيكون ايه بيكونيعني أقل حركة أو
+
+280
+00:20:51,950 --> 00:20:55,970
+صعوبة في الحركة لو كانت قوة ال .. ال normal قليلة
+
+281
+00:20:55,970 --> 00:20:58,750
+بتكون قوة الاحتكاق قليلة و بتكون سهلة في الحركة
+
+282
+00:20:58,750 --> 00:21:04,150
+فاللي سهل بالحركة اللي هو B الحركة الحالة هذه لإنه
+
+283
+00:21:04,150 --> 00:21:06,830
+بيكون عندي أنا هنا لما أجي حل ال hand بيكون عندك F
+
+284
+00:21:06,830 --> 00:21:11,400
+signوفيه normal وفتحت ال MG فهنا ال normal زائد ال
+
+285
+00:21:11,400 --> 00:21:15,860
+MG sign ال F sign بتساوي ال MG إذا ال normal
+
+286
+00:21:15,860 --> 00:21:20,220
+بتساوي ال MG ناقص ال F sign ال MG ناقص ال F sign
+
+287
+00:21:20,220 --> 00:21:24,220
+اللي بالأعلى بدها تكون ال normal بتساوي ال MG زائد
+
+288
+00:21:24,220 --> 00:21:29,200
+F sign فهذه أسهل في الحركة لإنه ال normal أقل
+
+289
+00:21:29,200 --> 00:21:33,380
+بيكون قيمته أقل وبالتالي أسهل في الحركة
+
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_raw.json b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_raw.json
new file mode 100644
index 0000000000000000000000000000000000000000..46dc99f4d4af74a389f1c4e412767eccb845d8f6
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_raw.json
@@ -0,0 +1 @@
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"أنا أعطيته قوة لكن ما اتحرك قوة احتكاك ساكن أعطيته زودت القوة ما اتحرك زودت القوة ما اتحرك إلى حد معين بيسموها ال critical طبعا هي point أو النقطة الحرجة هذه بعدها إذا هو اتحرك بتكون أنا وصلت لل maximum static friction ال force اللي هي أعلى قيمة لقوة الاحتكاك الساكن بعدها بيتحرك فبيتحول قوة الاحتكاك الساكن إلى قوة احتكاك متحرك وبالتالي في عندي أنا هنا منطقة الاحتكاك المتحرك", "tokens": [10721, 8315, 5551, 3615, 9566, 36081, 3224, 12174, 2407, 3660, 44381, 19446, 1975, 2655, 5016, 31747, 12174, 2407, 3660, 1975, 33753, 4117, 995, 4117, 8608, 995, 19452, 5551, 3615, 9566, 36081, 3224, 30767, 23328, 2655, 25062, 2407, 3660, 19446, 1975, 2655, 5016, 31747, 30767, 23328, 2655, 25062, 2407, 3660, 19446, 1975, 2655, 5016, 31747, 30731, 11331, 3215, 20449, 9957, 4724, 1829, 38251, 2407, 11296, 2423, 4924, 23032, 3555, 3615, 995, 39896, 935, 34051, 28239, 47432, 3660, 21542, 47341, 3660, 29538, 39182, 11296, 11933, 15730, 31439, 1975, 2655, 5016, 31747, 39894, 30544, 41850, 4032, 36520, 2655, 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"probability": 0.9521484375}, {"start": 1090.4, "end": 1090.96, "word": " الزاوية", "probability": 0.9833984375}, {"start": 1090.96, "end": 1092.3, "word": " فالزاوية", "probability": 0.9786783854166666}, {"start": 1092.3, "end": 1092.8, "word": " تلاتين", "probability": 0.8763427734375}, {"start": 1092.8, "end": 1093.32, "word": " هتكون", "probability": 0.96826171875}, {"start": 1093.32, "end": 1093.7, "word": " تحت", "probability": 0.997314453125}, {"start": 1093.7, "end": 1093.84, "word": " ال", "probability": 0.98291015625}, {"start": 1093.84, "end": 1094.34, "word": " horizontal", "probability": 0.81787109375}, {"start": 1094.34, "end": 1094.9, "word": " تحت", "probability": 0.966064453125}, {"start": 1094.9, "end": 1095.04, "word": " ال", "probability": 0.98876953125}, {"start": 1095.04, "end": 1095.48, "word": " horizontal", "probability": 0.8486328125}], "temperature": 1.0}, {"id": 50, "seek": 111979, "start": 1097.07, "end": 1119.79, "text": "هيدفع العربة بقوة معينة suppose your friend is sitting on a sled and asks you to move her across a flat horizontal field you have a choice يا ترى pushing her from behind by applying a force downward in her shoulder at تلاتين below the horizontal or", "tokens": [3224, 25708, 5172, 3615, 18863, 25513, 3660, 4724, 4587, 2407, 3660, 20449, 9957, 3660, 7297, 428, 1277, 307, 3798, 322, 257, 46242, 293, 8962, 291, 281, 1286, 720, 2108, 257, 4962, 12750, 2519, 291, 362, 257, 3922, 35186, 6055, 2288, 7578, 7380, 720, 490, 2261, 538, 9275, 257, 3464, 24805, 294, 720, 7948, 412, 6055, 1211, 9307, 9957, 2507, 264, 12750, 420], "avg_logprob": -0.16220238757511926, "compression_ratio": 1.3609756097560977, "no_speech_prob": 5.960464477539063e-08, "words": [{"start": 1097.0700000000002, "end": 1097.8700000000001, "word": "هيدفع", "probability": 0.936767578125}, {"start": 1097.8700000000001, "end": 1098.67, "word": " العربة", "probability": 0.9415690104166666}, {"start": 1098.67, "end": 1099.77, "word": " بقوة", "probability": 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بالحركة لو هو انا دفعته دفع ولا شدته شد الان مين اسهل بالحركة لازم نجيب اللى هى ال normal force", "tokens": [13690, 3614, 576, 312, 3571, 293, 983, 2423, 7649, 45164, 25961, 43242, 7578, 1975, 8315, 21542, 31747, 2655, 9957, 45164, 1975, 8315, 11778, 5172, 34268, 3224, 11778, 5172, 3615, 1975, 2407, 13412, 3215, 47395, 13412, 3215, 3714, 9957, 24525, 3224, 1211, 20666, 5016, 31747, 3660, 3714, 9957, 24525, 3224, 1211, 20666, 5016, 31747, 3660, 45164, 31439, 1975, 8315, 11778, 5172, 34268, 3224, 11778, 5172, 3615, 49429, 13412, 3215, 47395, 13412, 3215, 2423, 7649, 3714, 9957, 24525, 3224, 1211, 20666, 5016, 31747, 3660, 5296, 31377, 2304, 8717, 7435, 1829, 3555, 13672, 7578, 8032, 7578, 2423, 2710, 3464], "avg_logprob": -0.10591172926204721, "compression_ratio": 1.9942528735632183, "no_speech_prob": 4.76837158203125e-07, "words": [{"start": 1130.18, "end": 1130.52, "word": "which", "probability": 0.66162109375}, {"start": 1130.52, "end": 1131.04, "word": " option", "probability": 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\ No newline at end of file
diff --git a/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_raw.srt b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_raw.srt
new file mode 100644
index 0000000000000000000000000000000000000000..f55446dcc5abfca1f98f836b76c8cb14529ff463
--- /dev/null
+++ b/PL9fwy3NUQKwZQAaxAfnPN_bHKqBBLqmvi/zzE9xZalaUQ_raw.srt
@@ -0,0 +1,1156 @@
+1
+00:00:00,000 --> 00:00:04,360
+بسم الله الرحمن الرحيم نستكمل chapter أربعة هذا
+
+2
+00:00:04,360 --> 00:00:07,820
+section أربعة أربعة one upon one static friction
+
+3
+00:00:07,820 --> 00:00:12,160
+forces when a horizontal force F is exerted
+
+4
+00:00:12,160 --> 00:00:17,780
+against an object such as trash canthe trash can
+
+5
+00:00:17,780 --> 00:00:20,760
+type licker does not move unless the force exceeds
+
+6
+00:00:20,760 --> 00:00:25,640
+some critical value معامل هذه قوة الاحتكاك الساكنة
+
+7
+00:00:25,640 --> 00:00:32,400
+عندما طبعا عندما يكون لدينا قوة في اتجاه الأفقي ال
+
+8
+00:00:32,400 --> 00:00:38,950
+horizontal إذا زادت هذه القوةعن قوة معينة او حد
+
+9
+00:00:38,950 --> 00:00:42,350
+معين اللي هي ال critical value ممكن انه هذه العربة
+
+10
+00:00:42,350 --> 00:00:46,510
+او سلة القمامة انها يعني ت .. ت .. تنزاح او تنجر
+
+11
+00:00:46,510 --> 00:00:51,290
+لكن اذا كان انا باعطي هذه ال .. هذا .. هذا ال ..
+
+12
+00:00:51,290 --> 00:00:54,210
+يعني هذه السلة او هذا البرميل باعطيه قوة ولم ..
+
+13
+00:00:54,210 --> 00:00:59,420
+ولم يتحرك فإذا هناك .. هناك قوة احتكاك ساكنthe
+
+14
+00:00:59,420 --> 00:01:03,040
+critical value is maximum static friction في قوة
+
+15
+00:01:03,040 --> 00:01:06,920
+حرجة بيسموها اللي هي maximum static friction أقصى
+
+16
+00:01:06,920 --> 00:01:11,080
+قوة لقوة الاحتكاك بعدها الجسم بتحرك يعني لو أعطيت
+
+17
+00:01:11,080 --> 00:01:16,330
+أنا جسم برميل ولا طاولة ولا كتلة كبيرةيعني دفعتها
+
+18
+00:01:16,330 --> 00:01:19,670
+بقوة لم تتحرك و دفعتها بكمان قوة و لم تتحرك كل هذه
+
+19
+00:01:19,670 --> 00:01:23,110
+القوة اللي أنا بدفعها فيها اسمها قوة احتكاك ساكن
+
+20
+00:01:23,110 --> 00:01:26,750
+لإنه في معامل احتكاك ساكن بين الجسم و بين هذه
+
+21
+00:01:26,750 --> 00:01:30,370
+الكتلة the actual aesthetic force is always less
+
+22
+00:01:30,370 --> 00:01:34,540
+than or equal to the maximumمعنى الكلام أنه قيمة
+
+23
+00:01:34,540 --> 00:01:40,360
+اللي هو قوة الاحتكاك الساكنة الحقيقية هي عبارة
+
+24
+00:01:40,360 --> 00:01:44,780
+تساوي اللي هي القوة ال maximum أو أقل منها طبعا
+
+25
+00:01:44,780 --> 00:01:50,590
+هذا الشكل بيبين graphicallyكيف انه احنا ممكن الشكل
+
+26
+00:01:50,590 --> 00:01:54,990
+ال .. ال .. هذا ال .. الأسفل تبين لي انه في عندي
+
+27
+00:01:54,990 --> 00:01:59,350
+أنحاوية معينة في عندي قوة احتكاك قوة يعني applied
+
+28
+00:01:59,350 --> 00:02:03,330
+force و طبعا هذه قوة احتكاك ساكن عكس هذه القوة
+
+29
+00:02:03,330 --> 00:02:07,350
+طالما انا بشد هذا الجسم ولا ما يتحرك و شدت ولا ما
+
+30
+00:02:07,350 --> 00:02:12,870
+يتحرك في ازوية قوة احتكاك ساكن قيمة هذه القوة قوة
+
+31
+00:02:12,870 --> 00:02:16,070
+احتكاك الساكن بتساويقيمة ال applied force في هذه
+
+32
+00:02:16,070 --> 00:02:19,690
+الحالة انه برضه مش هيتحرك في عندنا ال normal force
+
+33
+00:02:19,690 --> 00:02:22,850
+اللي هي عكس قوة الجاذبية عكس الوزن اللي هو ال MG
+
+34
+00:02:22,850 --> 00:02:26,890
+الآن في هذا الشكل بلاحظ انه انا زودت القوة اللي
+
+35
+00:02:26,890 --> 00:02:31,270
+اعطته إياها فالجسم اتحرك اتحرك معناته عامل حركة
+
+36
+00:02:31,270 --> 00:02:34,370
+اللي هو ال motionعندما يتحرك الاساسم بتتحور قوة
+
+37
+00:02:34,370 --> 00:02:38,990
+الاحتكاك الساكن إلى قوة احتكاك متحرك بيحكي لي هذا
+
+38
+00:02:38,990 --> 00:02:41,730
+الشكل when the magnitude of the applied force إذا
+
+39
+00:02:41,730 --> 00:02:46,430
+كانت قيمة القوة المعطاة زادت عن قيمة اللي هي
+
+40
+00:02:46,430 --> 00:02:50,310
+maximum force of static friction أعلى من قيمة قوة
+
+41
+00:02:50,310 --> 00:02:54,130
+الاحتكاك الساكن معناها هذا هذه سالة القمامة وبرميل
+
+42
+00:02:54,130 --> 00:02:58,050
+القمامة ممكن أنه يتحرك و brakes free and
+
+43
+00:02:58,050 --> 00:03:03,540
+accelerate to the right بتحرك لليامينطبعا الجمال
+
+44
+00:03:03,540 --> 00:03:07,840
+السابقة تسبق هذا الكلام نحكي ان when the applied
+
+45
+00:03:07,840 --> 00:03:11,000
+force exceed the maximum static force the object
+
+46
+00:03:11,000 --> 00:03:14,700
+begin to move الجسم بيتحرك بتتحول قوة الاحتكاك
+
+47
+00:03:14,700 --> 00:03:21,000
+الساكنالى قوة احتكاك متحرك كمان بدل ما استخدم mus
+
+48
+00:03:21,000 --> 00:03:24,900
+باستخدم muk الـ kinetic friction coefficient معامل
+
+49
+00:03:24,900 --> 00:03:30,240
+الاحتكاك المتحرك أقل من قوة الاحتكاك الساكن كما هو
+
+50
+00:03:30,240 --> 00:03:37,360
+موضح muk أقل من musمعنى الكلام إنه النقوة الاحتكاك
+
+51
+00:03:37,360 --> 00:03:43,600
+الساكن إلها قيمة عظمة وإلها تدرج من ال zero لأعلى
+
+52
+00:03:43,600 --> 00:03:48,340
+قيمة عظمة كما هو موضح بهذا الشكل أنا هندي .. هندي
+
+53
+00:03:48,340 --> 00:03:51,520
+أنا هنا في static region هذا المنطقة منطقة احتكاك
+
+54
+00:03:51,520 --> 00:03:54,780
+ولكن ساكن يعني لما يكون عندي جسم انا .. انا دفعت
+
+55
+00:03:54,780 --> 00:03:58,460
+وما اتحركأنا أعطيته قوة لكن ما اتحرك قوة احتكاك
+
+56
+00:03:58,460 --> 00:04:02,440
+ساكن أعطيته زودت القوة ما اتحرك زودت القوة ما
+
+57
+00:04:02,440 --> 00:04:06,320
+اتحرك إلى حد معين بيسموها ال critical طبعا هي
+
+58
+00:04:06,320 --> 00:04:10,240
+point أو النقطة الحرجة هذه بعدها إذا هو اتحرك
+
+59
+00:04:10,240 --> 00:04:14,080
+بتكون أنا وصلت لل maximum static friction ال force
+
+60
+00:04:14,080 --> 00:04:17,060
+اللي هي أعلى قيمة لقوة الاحتكاك الساكن بعدها
+
+61
+00:04:17,060 --> 00:04:21,240
+بيتحرك فبيتحول قوة الاحتكاك الساكن إلى قوة احتكاك
+
+62
+00:04:21,240 --> 00:04:24,760
+متحرك وبالتالي في عندي أنا هنا منطقة الاحتكاك
+
+63
+00:04:24,760 --> 00:04:25,620
+المتحرك
+
+64
+00:04:28,480 --> 00:04:31,840
+الـ static friction force الـ static friction
+
+65
+00:04:31,840 --> 00:04:35,480
+force the magnitude of the static friction force
+
+66
+00:04:35,480 --> 00:04:41,480
+اللي هي قيمة قوة الاحتكاك الساكن ورمزها Fs تؤثر
+
+67
+00:04:41,480 --> 00:04:48,080
+على الجسم at rest satisfy the inequality أن الـ Fs
+
+68
+00:04:48,080 --> 00:04:52,760
+تتراوح بين الـ 0 للـ F maximumهذه ال Fs تتروح بين
+
+69
+00:04:52,760 --> 00:04:57,820
+أكبر أو تساوي 0 أو أقل أو تساوي ال F static force
+
+70
+00:04:57,820 --> 00:05:01,960
+maximum وده تساوي Mu S في ال normal قيمتها Mu S في
+
+71
+00:05:01,960 --> 00:05:05,180
+ال normal اللي هي ال F static friction force
+
+72
+00:05:05,180 --> 00:05:09,440
+maximum تساوي Mu S في ال normal لكنها تتروح من ال
+
+73
+00:05:09,440 --> 00:05:14,870
+0 ل Fs maximumالـ N is the normal force الـ N هذه
+
+74
+00:05:14,870 --> 00:05:19,030
+عبارة عن قوت رد الفعل العمودية و Mu S is the
+
+75
+00:05:19,030 --> 00:05:22,650
+coefficient of maximum static friction اللي هي
+
+76
+00:05:22,650 --> 00:05:25,910
+عبارة عن معامل الاحتكاك الساكن between بين ال
+
+77
+00:05:25,910 --> 00:05:30,150
+object and the surface بين أي جسم و بين السطح the
+
+78
+00:05:30,150 --> 00:05:34,350
+force Fs قوت الاحتكاك الساكن acts in the direction
+
+79
+00:05:34,350 --> 00:05:39,350
+opposite that of the embedding motionقوة الاحتكاك
+
+80
+00:05:39,350 --> 00:05:44,750
+الساكن بيكون اتجاهها عكس اتجاه الحركة هذا الكلام
+
+81
+00:05:44,750 --> 00:05:49,470
+بتشبه قوة الاحتكاك المتحرك على أساس أنه اتجاه قوة
+
+82
+00:05:49,470 --> 00:05:53,730
+الاحتكاك المتحرك أو الساكن بيكون عكس الحركة قوة
+
+83
+00:05:53,730 --> 00:05:56,890
+الاحتكاك الساكن بتكون عكس القوة قوة الاحتكاك
+
+84
+00:05:56,890 --> 00:06:01,930
+المتحرك بتكون عكس اللي هو القوةأو الحركة the
+
+85
+00:06:01,930 --> 00:06:05,550
+static friction force takes on any value between
+
+86
+00:06:05,550 --> 00:06:09,690
+zero and its maximum value قوة الاحتكاك الساكن
+
+87
+00:06:09,690 --> 00:06:14,850
+تاخد قيم من zero إلى أقصى قيمة اللي هي بيسموها ال
+
+88
+00:06:14,850 --> 00:06:19,530
+maximum value mu S في ال normal تعتمد على قيمة
+
+89
+00:06:19,530 --> 00:06:23,250
+القوة المعطاة depending on the magnitude of the
+
+90
+00:06:23,250 --> 00:06:27,470
+applied forceThe static friction force self
+
+91
+00:06:27,470 --> 00:06:31,510
+-adjusts depending on the net force acting on the
+
+92
+00:06:31,510 --> 00:06:36,010
+object برضه ال static frictional force قوة احتكاك
+
+93
+00:06:36,010 --> 00:06:40,630
+الساكن ممكن احنا نضبطها او نعيرها بحيث انها تعتمد
+
+94
+00:06:40,630 --> 00:06:46,000
+على مجموعة او محصلة القوة المؤثرة على الجسمsuch
+
+95
+00:06:46,000 --> 00:06:49,340
+self-adjustment is illustrated in the figure زي
+
+96
+00:06:49,340 --> 00:06:54,060
+هذا الشكل اللي هي القوة المحصلة المؤثرة على الجسم
+
+97
+00:06:54,060 --> 00:06:59,340
+كهذا الشكل طبعا عندي أنا هنا applied force الشخص
+
+98
+00:06:59,340 --> 00:07:04,920
+دفع تلاجة إلى الأمامفي عندها ال F applied فالتلاجة
+
+99
+00:07:04,920 --> 00:07:09,100
+دي ما اتحركت وبالتالي ال Fs بدها تساوي أقل من ال
+
+100
+00:07:09,100 --> 00:07:13,060
+Mu S في ال normal ال Fs اللي هي موجودة حكينا
+
+101
+00:07:13,060 --> 00:07:17,240
+بتتروح من ال zero ل ال F maximum فالمؤثر على هذه
+
+102
+00:07:17,240 --> 00:07:21,940
+التلاجة F applied اللي هي بتساوي أقل من ال Mu S في
+
+103
+00:07:21,940 --> 00:07:27,220
+ال normalلو أنا زودت القوة، زودنا القوة، زودت
+
+104
+00:07:27,220 --> 00:07:31,120
+القوة صارت ال Fs بدها تساوي Mu S في ال normal في
+
+105
+00:07:31,120 --> 00:07:34,220
+هذه الحالة و ال F اللي هي ال applied هذه بدها
+
+106
+00:07:34,220 --> 00:07:40,050
+تساوي ال Fs اللي هي ال Mu S في ال normalبعد هيك
+
+107
+00:07:40,050 --> 00:07:44,870
+زودنا القوة شوية صارت عندي ال F applied أكبر من ال
+
+108
+00:07:44,870 --> 00:07:51,570
+Fs إذا الجسم هيتحرك بدل ال Fs حطينا ال Fk صارت
+
+109
+00:07:51,570 --> 00:07:56,790
+عندي أنه في عندي حركة اتحولت ال Fs إلى Fk وبالتالي
+
+110
+00:07:56,790 --> 00:08:00,270
+بقى أنا بيصير عندي حركة بتصير ال F applied ناقص ال
+
+111
+00:08:00,270 --> 00:08:03,630
+Fk بتساوي ال mass في ال acceleration صار عندي
+
+112
+00:08:03,630 --> 00:08:08,900
+مجموعة القوة باتجاه ال X axis بتساوي M في Aطبعا
+
+113
+00:08:08,900 --> 00:08:13,360
+هذا هو موضح في الشكل 24 بنحكي أنه ال .. أنا في
+
+114
+00:08:13,360 --> 00:08:17,800
+عندى قوة زودتها شوية شوية حتى في .. في أكتر من
+
+115
+00:08:17,800 --> 00:08:21,400
+حالة الحالة الأولى أنه ما اتحركت التلاجة الحالة
+
+116
+00:08:21,400 --> 00:08:24,360
+التانى كانت القوة اللى انا أعطيتهيا بالساوية أفقاس
+
+117
+00:08:24,360 --> 00:08:27,520
+الحالة التالتة أن القوة كانت أكبر من الأفقاس إذا
+
+118
+00:08:27,520 --> 00:08:32,530
+اتحرك الجسمexample as shown in the figures في عندي
+
+119
+00:08:32,530 --> 00:08:38,290
+block جسم having mass جسم له كتلة أربع كيلو جرام
+
+120
+00:08:38,290 --> 00:08:42,210
+rest on slope that make an angle of تلاتين هذا
+
+121
+00:08:42,210 --> 00:08:46,530
+الجسم محطوط على سطح ميل بزاوية تلاتين درجة كتلة
+
+122
+00:08:46,530 --> 00:08:51,850
+هذا الجسم أربع كيلو جرامwith the horizontal طبعا
+
+123
+00:08:51,850 --> 00:08:54,710
+التلاتين هي عبارة عن الزاوية المحصورة بين المستوى
+
+124
+00:08:54,710 --> 00:08:57,550
+وبين اللي هي ال horizontal if the coefficient of
+
+125
+00:08:57,550 --> 00:09:00,310
+static friction between the block and the surface
+
+126
+00:09:00,310 --> 00:09:07,090
+it rests upon is ال معامل الاحتكاك الساكن point 65
+
+127
+00:09:07,860 --> 00:09:12,040
+calculate مطلوب إيجاد the normal force و ال
+
+128
+00:09:12,040 --> 00:09:15,680
+maximum static force بده قوة إيراد الفعل العمودية
+
+129
+00:09:15,680 --> 00:09:19,880
+و بده أقصى قيمة لل static force كمان مطلوب ال
+
+130
+00:09:19,880 --> 00:09:24,040
+actual static friction force required to prevent
+
+131
+00:09:24,040 --> 00:09:27,700
+the block from moving بده ال actual static
+
+132
+00:09:27,700 --> 00:09:33,380
+friction هي force بده قيمة القوة الاحتكاك الساكن
+
+133
+00:09:33,380 --> 00:09:37,040
+الحقيقية اللي أنا بحتاجها عشان أمنع حركة هذا الجسم
+
+134
+00:09:37,530 --> 00:09:41,070
+و بعدين حكيلنا will the block begin to move or
+
+135
+00:09:41,070 --> 00:09:46,510
+remain at rest هل الجسم بدى يتحرك ولا بدى ضال ثابت
+
+136
+00:09:46,510 --> 00:09:50,110
+يعني هى الجسم كتلته أربعة بميلة بزاوية تلاتين درجة
+
+137
+00:09:50,110 --> 00:09:55,770
+أعطانى معامل احتجازات الساكن ال US 0.65 من خلال
+
+138
+00:09:55,770 --> 00:10:00,210
+هذا الشكل بدى أوجد انا ال actual اللى هى ال static
+
+139
+00:10:00,210 --> 00:10:03,630
+friction طبعا اول حاجة لازم اعمل free body diagram
+
+140
+00:10:03,630 --> 00:10:08,020
+لهذا الشكل بنزل ال MGأو قوة الجاذبية اللي هي ال FG
+
+141
+00:10:08,020 --> 00:10:12,460
+هي عبارة عن سوء ال M في G بنحلل اللي هي ال MG إلى
+
+142
+00:10:12,460 --> 00:10:18,220
+MG Cos و MG Sin على المستوى MG Cos و MG Sin على
+
+143
+00:10:18,220 --> 00:10:22,640
+المستوى في عندي هنا Normal طبعا الجسم بده ينزل إلى
+
+144
+00:10:22,640 --> 00:10:26,760
+أسفل في عندي قوة احتكاك ساكن تمنعه من الحركة بدنا
+
+145
+00:10:26,760 --> 00:10:31,180
+نشوف هل الجسم بده يتحرك ام الجسم بده يبقى ساكن كما
+
+146
+00:10:31,180 --> 00:10:36,360
+هولإيجاد المطلوب الأول الان دى ال three forces فى
+
+147
+00:10:36,360 --> 00:10:40,000
+عندى تلت قوة مؤثرة على الجسم فى عندى قوت الجاذبية
+
+148
+00:10:40,000 --> 00:10:44,300
+MG وفى عندى ال normal force اللى هى ال N و ال
+
+149
+00:10:44,300 --> 00:10:48,560
+static friction force Fs بدي أختار ال coordinate
+
+150
+00:10:48,560 --> 00:10:53,040
+على أساس أنه بدي أختار محاور X و Y باختار ال X
+
+151
+00:10:53,040 --> 00:10:57,020
+axis positive X axis اللى هى أسفل اللى هو المنحدر
+
+152
+00:10:57,020 --> 00:11:01,610
+أو أسفل السطح المايل لليمين بيعتبر X الموجبو ال y
+
+153
+00:11:01,610 --> 00:11:06,910
+العمودي عليه اللي هو ال positive y axis is
+
+154
+00:11:06,910 --> 00:11:10,090
+perpendicular to the أسلوب عمودي على اللي هو هذا
+
+155
+00:11:10,090 --> 00:11:14,010
+الخط نحسب ال normal force طبعا عشان أحسب ال normal
+
+156
+00:11:14,010 --> 00:11:16,350
+force ال normal force في هذه الحالة بتساوي ال mg
+
+157
+00:11:16,350 --> 00:11:20,260
+cosine الزاويةالـ M كانت أربعة والـ G تسعة و
+
+158
+00:11:20,260 --> 00:11:23,600
+تمانية من عشرة كزاين التلاتين تلاتة و تلاتين point
+
+159
+00:11:23,600 --> 00:11:26,900
+تسعة هذا ال normal force لإيجاد ال maximum
+
+160
+00:11:26,900 --> 00:11:31,620
+possible static frictional force ال Fs maximum
+
+161
+00:11:31,620 --> 00:11:36,640
+عبارة عن Mu S في ال normal اللي هو coefficient of
+
+162
+00:11:36,640 --> 00:11:40,100
+static friction مضروب في ال .. اللي .. اللي هو ال
+
+163
+00:11:40,100 --> 00:11:42,660
+normal force إذا point ستة خمسة مضروبة في ال
+
+164
+00:11:42,660 --> 00:11:45,480
+normal force اللي إحنا جبناها هنا تلاتة و تلاتين
+
+165
+00:11:45,480 --> 00:11:49,580
+point تسعة اتنين و عشرين point واحدهذه .. هذه ال
+
+166
+00:11:49,580 --> 00:11:54,980
+maximum static friction force لإيجاد ال actual
+
+167
+00:11:54,980 --> 00:11:59,020
+static friction force required to keep the block
+
+168
+00:11:59,020 --> 00:12:03,680
+to rest بدي أوجد ال actual اللي هو قوة الاحتكاك
+
+169
+00:12:03,680 --> 00:12:08,060
+الحقيقية اللي موجودة على الجسم و بتمنع الجسم انه
+
+170
+00:12:08,060 --> 00:12:12,020
+يتحرك طبعا بالنسبة للقوة اللي في تجاه ال X
+
+171
+00:12:12,020 --> 00:12:16,550
+summation لل Fx بتساوي ال M في Xax بتساوي zero
+
+172
+00:12:16,550 --> 00:12:19,670
+مافيش حركة باتجاه ال x اللي هو اللي احنا اعتبرناه
+
+173
+00:12:19,670 --> 00:12:23,990
+السطح اللي هو المائل and expressions for two
+
+174
+00:12:23,990 --> 00:12:27,630
+forces acting parallel to the x-axis الان في عندى
+
+175
+00:12:27,630 --> 00:12:30,950
+قوة الجاذبية ناقص أف أس بتساوي zero مافيش حركة
+
+176
+00:12:30,950 --> 00:12:35,270
+بنعتبر أنه مافيش حركة فالax ال gravity اللي هي
+
+177
+00:12:35,270 --> 00:12:38,990
+عبارة عن ال mg صين الزاوية ناقص الأف أس بتساوي
+
+178
+00:12:38,990 --> 00:12:44,130
+zeroبدي أحل أوجد اللى هى ال Fs من هذا ال من هى
+
+179
+00:12:44,130 --> 00:12:49,790
+المعادلة فال Fs بدها تساوي ال F اللى هى ال F اللى
+
+180
+00:12:49,790 --> 00:12:54,990
+هى MG صين الزاوية هى هى علشان أوجدها هى ال Fs
+
+181
+00:12:54,990 --> 00:12:57,490
+بتساوي ال MG صين الزاوية لإنه احنا اعتبرت ال Fs
+
+182
+00:12:57,490 --> 00:13:00,390
+ناقص ال MG بساوي Zero اذا ال Fs بتساوي ال MG صين
+
+183
+00:13:00,390 --> 00:13:04,430
+الزاوية فبتطلع ال actual static frictional force
+
+184
+00:13:04,430 --> 00:13:10,260
+acting on the body بتساوي 19.6لكن ال maximum .. ال
+
+185
+00:13:10,260 --> 00:13:13,940
+frictional .. maximum static force acting on the
+
+186
+00:13:13,940 --> 00:13:19,200
+.. on the body كانت واحد و عشرين .. واحد و عشرين
+
+187
+00:13:19,200 --> 00:13:22,540
+point واحد فبدى أعرف هنا determine whether the
+
+188
+00:13:22,540 --> 00:13:27,160
+block will begin to moveهل الجسم بده يتحرك ولا لأ
+
+189
+00:13:27,160 --> 00:13:31,260
+فمن خلال انه ال maximum static frictional force 22
+
+190
+00:13:31,260 --> 00:13:35,900
+.1 و القوة اللى انا اعطتهياها 19.6 او القوة اللى
+
+191
+00:13:35,900 --> 00:13:40,740
+موجودة عليه ال actual static frictional force 19.6
+
+192
+00:13:40,740 --> 00:13:47,180
+معناته الجسم لا يتحرك the block remains at rest on
+
+193
+00:13:47,180 --> 00:13:50,840
+the slope لإنه ال maximum frictional force بتساوي
+
+194
+00:13:50,840 --> 00:13:58,160
+22.1و بالتالي الجسم لايتحرك نجي لهذا ال quiz quiz
+
+195
+00:13:58,160 --> 00:14:03,200
+number four point five if you press a block flat
+
+196
+00:14:03,200 --> 00:14:07,400
+against a vertical wall لو كان عندي أنا حيطة هيها
+
+197
+00:14:07,400 --> 00:14:12,320
+مثلا و بدي أنا أضغط الكتاب على الحيطة بإيدي بدي
+
+198
+00:14:12,320 --> 00:14:17,500
+أضغط الكتاب على الحيطة بإيدي will with your hand
+
+199
+00:14:17,500 --> 00:14:20,760
+in what direction is the friction force exerted by
+
+200
+00:14:20,760 --> 00:14:24,800
+the wall in the blockهل بدى يكون downward ولا
+
+201
+00:14:24,800 --> 00:14:30,220
+upward ولا out from the wall ولا into the wall؟
+
+202
+00:14:30,220 --> 00:14:34,810
+الآن أنا بضغط الكتاب بإيدي على الحيطةإيدي هتكون
+
+203
+00:14:34,810 --> 00:14:39,010
+عمودية على الحيطة وبالتالي ال normal force هتكون
+
+204
+00:14:39,010 --> 00:14:43,310
+طالعة من الصفحة ال normal force لتحت هيكون عندنا
+
+205
+00:14:43,310 --> 00:14:49,750
+احنا لتحت هيكون عندنا اللي هو ال MG اللي اللي اللي
+
+206
+00:14:49,750 --> 00:14:53,830
+بيمنع الجسم انه يتحرك هي في عندنا static
+
+207
+00:14:53,830 --> 00:14:58,150
+frictional force بيكون اتجاهها ل .. لأعلى عكس اللي
+
+208
+00:14:58,150 --> 00:15:02,290
+هو ال MG لو انه كان لو كان ال MG أكبر من الأفقاس
+
+209
+00:15:02,290 --> 00:15:06,780
+الجسم هيتحركلكن طالما أن الجسم مش هيتحرك و القوة
+
+210
+00:15:06,780 --> 00:15:11,440
+اللى بتمنع الجسم انه يتحرك كانت Fs وكانت باتجاه
+
+211
+00:15:11,440 --> 00:15:16,320
+اللى هو downward اللى هو إلى أعلى لإن ال MG هتكون
+
+212
+00:15:16,320 --> 00:15:23,000
+لأسفلال quiz تاني a crate is sitting in the center
+
+213
+00:15:23,000 --> 00:15:27,240
+of a flat bed truck as the truck accelerate to the
+
+214
+00:15:27,240 --> 00:15:34,220
+east يعني لو كان عندي انا يعني عربة كبيرة زي شاحنة
+
+215
+00:15:34,220 --> 00:15:41,020
+بتتحرك والشاحنة عليها عليها جسم او عربة صغيرةذاكرت
+
+216
+00:15:41,020 --> 00:15:45,340
+العربة move with it and does not slide هلاقيتها
+
+217
+00:15:45,340 --> 00:15:51,680
+الشاحنة محملة على ظهرها عربة صغيرة الشاحنة بتمشي
+
+218
+00:15:51,680 --> 00:15:56,940
+لإلي الشارق ل الشارق الشاحنة بتمشي العربة مش اللي
+
+219
+00:15:56,940 --> 00:16:00,820
+.. العربة الصغيرة اللي على الشاحنة مش هتمشي ولكن
+
+220
+00:16:00,820 --> 00:16:04,910
+هتتحركلكن does not slide on the bed of the truck
+
+221
+00:16:04,910 --> 00:16:09,150
+in what direction is the friction force exerted by
+
+222
+00:16:09,150 --> 00:16:14,890
+the bed of the truck on the crate بيحكيلي أنه بأي
+
+223
+00:16:14,890 --> 00:16:18,550
+اتجاه هيكون قوة الاحتكاك الساكن المؤثرة على العربة
+
+224
+00:16:18,550 --> 00:16:24,210
+الصغيرة الآن ال .. الآن الشاحنة العربة الكبيرة
+
+225
+00:16:24,210 --> 00:16:29,790
+الشاحنة بتمشي للشرق فقوة الاحتكاك الساكن على السطح
+
+226
+00:16:31,320 --> 00:16:37,900
+على سطح العربة قوة الاحتكاك الساكن على سطح العربة
+
+227
+00:16:37,900 --> 00:16:42,900
+اللى هو فوق العربة اللى مش على الأرض اللى هو السطح
+
+228
+00:16:42,900 --> 00:16:46,820
+البيت تبع ال truck هيكون غرب .. للغرب لأن هذا
+
+229
+00:16:46,820 --> 00:16:52,910
+العربة بتمشي للشرق فهيكون هو للغرب وبالتاليالسطح
+
+230
+00:16:52,910 --> 00:16:57,330
+التحتاني تبقى العربة الصغيرة هيتعرض لقوة احتكاك
+
+231
+00:16:57,330 --> 00:17:01,450
+تساوي قوة الاحتكاك سطح ال truck ولكن باتجاه
+
+232
+00:17:01,450 --> 00:17:05,690
+المعاكس طبعا سطح ال truck هيتعرض لقوة احتكاك إلى
+
+233
+00:17:05,690 --> 00:17:10,560
+الغرب لأنه الحركة إلى الشارقفقوة الاحتكاك الخاصة
+
+234
+00:17:10,560 --> 00:17:13,600
+بالعربة الصغيرة اللي هو السطح التحتاني للعربة
+
+235
+00:17:13,600 --> 00:17:17,660
+الصغيرة هيكون إلى الشرق يعني في عندي أنا جسمين
+
+236
+00:17:17,660 --> 00:17:22,320
+الجسمين متلامسين متلامسين وبيحتكوا في بعض السطح ال
+
+237
+00:17:22,320 --> 00:17:28,140
+.. ال .. السطح الأعلى للشاحنة هيتعرض لقوة احتكاك
+
+238
+00:17:28,140 --> 00:17:31,660
+ساكنة إلى الغرب لإن حركة العرب الشاحنة الكبيرة
+
+239
+00:17:31,660 --> 00:17:36,150
+للشرقالعربة الصغيرة اللى جالسة على الشاحنة السطح
+
+240
+00:17:36,150 --> 00:17:40,750
+التحتانى للعربة الصغيرة هيتعرض لاحتكاك باتجاه
+
+241
+00:17:40,750 --> 00:17:41,330
+الشرق
+
+242
+00:17:46,540 --> 00:17:50,200
+suppose your friend is sitting on the sled and ask
+
+243
+00:17:50,200 --> 00:17:55,100
+you to move hair across flat لو كان عندى انا عرب
+
+244
+00:17:55,100 --> 00:18:00,040
+التزلج زى ما هو موضح بالشكل طلبت منى و انا جالس
+
+245
+00:18:00,040 --> 00:18:06,460
+عليها طلبت من زميل يدفعنى بزاوية بهذا الشكل بيدفع
+
+246
+00:18:06,460 --> 00:18:12,300
+فالزاوية هتكون لتحت هيك هنا الزاوية فالزاوية
+
+247
+00:18:12,300 --> 00:18:15,480
+تلاتين هتكون تحت ال horizontal تحت ال horizontal
+
+248
+00:18:17,070 --> 00:18:23,190
+هيدفع العربة بقوة معينة suppose your friend is
+
+249
+00:18:23,190 --> 00:18:27,830
+sitting on a sled and asks you to move her across
+
+250
+00:18:27,830 --> 00:18:31,350
+a flat horizontal field you have a choice يا ترى
+
+251
+00:18:31,350 --> 00:18:34,950
+pushing her from behind by applying a force
+
+252
+00:18:34,950 --> 00:18:38,370
+downward in her shoulder at تلاتين below the
+
+253
+00:18:38,370 --> 00:18:44,230
+horizontal orattaching a rope to the front of the
+
+254
+00:18:44,230 --> 00:18:47,110
+sled and bull with force التلاتين above the
+
+255
+00:18:47,110 --> 00:18:51,760
+horizontal ولا which optionwhich option would be
+
+256
+00:18:51,760 --> 00:18:57,660
+easier and why الان لو كان عندى انا الحركتين لو
+
+257
+00:18:57,660 --> 00:19:04,660
+انا دفعته دفع او شدته شد مين اسهل بالحركة مين اسهل
+
+258
+00:19:04,660 --> 00:19:09,660
+بالحركة لو هو انا دفعته دفع ولا شدته شد الان مين
+
+259
+00:19:09,660 --> 00:19:15,400
+اسهل بالحركة لازم نجيب اللى هى ال normal forceلو
+
+260
+00:19:15,400 --> 00:19:19,240
+انا حددت ال normal force هنا ال normal و تحت ال mg
+
+261
+00:19:19,240 --> 00:19:25,420
+هحلل ال F إلى F cosine و هنا F sine هيطلع ل F اللي
+
+262
+00:19:25,420 --> 00:19:28,200
+هي F sine الزاوية زاد ال normal بتساوي ال mg
+
+263
+00:19:28,200 --> 00:19:33,160
+فبيطلع ال normal بده يساوي ال mg ناقص ال mg اللي
+
+264
+00:19:33,160 --> 00:19:37,640
+هي ال F sine التلاتين فمعنى الكلام ال normal هيكون
+
+265
+00:19:37,640 --> 00:19:42,850
+ال mg ناقص ال F sine التلاتين في هذه الحالةالحالة
+
+266
+00:19:42,850 --> 00:19:47,390
+الأولى لو بدى انا يعني احلل هو هو نازل بهذا الشكل
+
+267
+00:19:47,390 --> 00:19:54,810
+احلل اللى هى القوة الى بهذا الشكل الى F لو أنا
+
+268
+00:19:54,810 --> 00:19:59,450
+أخدته بهذا ال .. هنا هيكون عندى هنا F cosine و
+
+269
+00:19:59,450 --> 00:20:04,090
+لتحت هتكون ال F sineوفيه إلى أعلى ال normal حيكون
+
+270
+00:20:04,090 --> 00:20:07,830
+عندي ال normal بتساوي ال MG زائد N اللي هي ال
+
+271
+00:20:07,830 --> 00:20:11,850
+normal زائد ال F sign الزاوية وبالتالي اللي ال
+
+272
+00:20:11,850 --> 00:20:17,170
+normal اللي ال normal الخاص بيها بيكون قليل بيكون
+
+273
+00:20:17,170 --> 00:20:22,250
+قوة الاحتكاك أقل لإن ال FS بتساوي أو ال FK بتساوي
+
+274
+00:20:22,250 --> 00:20:27,380
+ميو كي في ال normalالحل by exerting an upward
+
+275
+00:20:27,380 --> 00:20:31,520
+force component on the sled you reduce the normal
+
+276
+00:20:31,520 --> 00:20:35,280
+force on the ground and so reduce the force of a
+
+277
+00:20:35,280 --> 00:20:39,360
+kind of friction لو أنا اتحركت بدأ اطلع ال normal
+
+278
+00:20:39,360 --> 00:20:45,780
+إذا كان ال normal كبير فبتكون قوة الاحتكاك من
+
+279
+00:20:45,780 --> 00:20:51,950
+متحركة كبيرة و بيكون ايه بيكونيعني أقل حركة أو
+
+280
+00:20:51,950 --> 00:20:55,970
+صعوبة في الحركة لو كانت قوة ال .. ال normal قليلة
+
+281
+00:20:55,970 --> 00:20:58,750
+بتكون قوة الاحتكاق قليلة و بتكون سهلة في الحركة
+
+282
+00:20:58,750 --> 00:21:04,150
+فاللي سهل بالحركة اللي هو B الحركة الحالة هذه لإنه
+
+283
+00:21:04,150 --> 00:21:06,830
+بيكون عندي أنا هنا لما أجي حل ال hand بيكون عندك F
+
+284
+00:21:06,830 --> 00:21:11,400
+signوفيه normal وفتحت ال MG فهنا ال normal زائد ال
+
+285
+00:21:11,400 --> 00:21:15,860
+MG sign ال F sign بتساوي ال MG إذا ال normal
+
+286
+00:21:15,860 --> 00:21:20,220
+بتساوي ال MG ناقص ال F sign ال MG ناقص ال F sign
+
+287
+00:21:20,220 --> 00:21:24,220
+اللي بالأعلى بدها تكون ال normal بتساوي ال MG زائد
+
+288
+00:21:24,220 --> 00:21:29,200
+F sign فهذه أسهل في الحركة لإنه ال normal أقل
+
+289
+00:21:29,200 --> 00:21:33,380
+بيكون قيمته أقل وبالتالي أسهل في الحركة
+