| /* stpcpy.c -- copy a string and return pointer to end of new string | |
| Copyright (C) 1992, 1995, 1997-1998, 2006, 2009-2023 Free Software | |
| Foundation, Inc. | |
| NOTE: The canonical source of this file is maintained with the GNU C Library. | |
| Bugs can be reported to [email protected]. | |
| This file is free software: you can redistribute it and/or modify | |
| it under the terms of the GNU Lesser General Public License as | |
| published by the Free Software Foundation; either version 2.1 of the | |
| License, or (at your option) any later version. | |
| This file is distributed in the hope that it will be useful, | |
| but WITHOUT ANY WARRANTY; without even the implied warranty of | |
| MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the | |
| GNU Lesser General Public License for more details. | |
| You should have received a copy of the GNU Lesser General Public License | |
| along with this program. If not, see <https://www.gnu.org/licenses/>. */ | |
| /* Copy SRC to DEST, returning the address of the terminating '\0' in DEST. */ | |
| char * | |
| __stpcpy (char *dest, const char *src) | |
| { | |
| register char *d = dest; | |
| register const char *s = src; | |
| do | |
| *d++ = *s; | |
| while (*s++ != '\0'); | |
| return d - 1; | |
| } | |
| weak_alias (__stpcpy, stpcpy) | |