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SELECT card_id , customer_id , card_type_code , card_number FROM Customers_cards | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are card ids, customer ids, card types, and card numbers for each customer card? |
SELECT date_valid_from , date_valid_to FROM Customers_cards WHERE card_number = "4560596484842" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the date valid from and the date valid to for the card with card number '4560596484842'. |
SELECT date_valid_from , date_valid_to FROM Customers_cards WHERE card_number = "4560596484842" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the valid from and valid to dates for the card with the number 4560596484842? |
SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What is the first name, last name, and phone of the customer with card 4560596484842. |
SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Return the full name and phone of the customer who has card number 4560596484842. |
SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. How many cards does customer Art Turcotte have? |
SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Count the number of cards the customer with the first name Art and last name Turcotte has. |
SELECT count(*) FROM Customers_cards WHERE card_type_code = "Debit" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. How many debit cards do we have? |
SELECT count(*) FROM Customers_cards WHERE card_type_code = "Debit" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Count the number of customer cards of the type Debit. |
SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. How many credit cards does customer Blanche Huels have? |
SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Count the number of credit cards that the customer with first name Blanche and last name Huels has. |
SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show all customer ids and the number of cards owned by each customer. |
SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different customer ids, and how many cards does each one hold? |
SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What is the customer id with most number of cards, and how many does he have? |
SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Return the id of the customer who has the most cards, as well as the number of cards. |
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show id, first and last names for all customers with at least two cards. |
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the ids and full names of customers who hold two or more cards? |
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What is the customer id, first and last name with least number of accounts. |
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Return the id and full name of the customer who has the fewest accounts. |
SELECT card_type_code , count(*) FROM Customers_cards GROUP BY card_type_code | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show all card type codes and the number of cards in each type. |
SELECT card_type_code , count(*) FROM Customers_cards GROUP BY card_type_code | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different card types, and how many cards are there of each? |
SELECT card_type_code FROM Customers_cards GROUP BY card_type_code ORDER BY count(*) DESC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What is the card type code with most number of cards? |
SELECT card_type_code FROM Customers_cards GROUP BY card_type_code ORDER BY count(*) DESC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Return the code of the card type that is most common. |
SELECT card_type_code FROM Customers_cards GROUP BY card_type_code HAVING count(*) >= 5 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show card type codes with at least 5 cards. |
SELECT card_type_code FROM Customers_cards GROUP BY card_type_code HAVING count(*) >= 5 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the codes of card types that have 5 or more cards? |
SELECT card_type_code , count(DISTINCT customer_id) FROM Customers_cards GROUP BY card_type_code | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show all card type codes and the number of customers holding cards in each type. |
SELECT card_type_code , count(DISTINCT customer_id) FROM Customers_cards GROUP BY card_type_code | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different card type codes, and how many different customers hold each type? |
SELECT customer_id , customer_first_name FROM Customers EXCEPT SELECT T1.customer_id , T2.customer_first_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE card_type_code = "Credit" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the customer ids and firstname without a credit card. |
SELECT customer_id , customer_first_name FROM Customers EXCEPT SELECT T1.customer_id , T2.customer_first_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE card_type_code = "Credit" | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the ids and first names of customers who do not hold a credit card? |
SELECT DISTINCT card_type_code FROM Customers_Cards | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show all card type codes. |
SELECT DISTINCT card_type_code FROM Customers_Cards | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different card type codes? |
SELECT count(DISTINCT card_type_code) FROM Customers_Cards | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the number of card types. |
SELECT count(DISTINCT card_type_code) FROM Customers_Cards | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. How many different card types are there? |
SELECT DISTINCT transaction_type FROM Financial_Transactions | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show all transaction types. |
SELECT DISTINCT transaction_type FROM Financial_Transactions | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different types of transactions? |
SELECT count(DISTINCT transaction_type) FROM Financial_Transactions | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the number of transaction types. |
SELECT count(DISTINCT transaction_type) FROM Financial_Transactions | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. How many different types of transactions are there? |
SELECT avg(transaction_amount) , sum(transaction_amount) FROM Financial_transactions | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What is the average and total transaction amount? |
SELECT avg(transaction_amount) , sum(transaction_amount) FROM Financial_transactions | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Return the average transaction amount, as well as the total amount of all transactions. |
SELECT T2.card_type_code , count(*) FROM Financial_transactions AS T1 JOIN Customers_cards AS T2 ON T1.card_id = T2.card_id GROUP BY T2.card_type_code | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the card type codes and the number of transactions. |
SELECT T2.card_type_code , count(*) FROM Financial_transactions AS T1 JOIN Customers_cards AS T2 ON T1.card_id = T2.card_id GROUP BY T2.card_type_code | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different card types, and how many transactions have been made with each? |
SELECT transaction_type , count(*) FROM Financial_transactions GROUP BY transaction_type | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the transaction type and the number of transactions. |
SELECT transaction_type , count(*) FROM Financial_transactions GROUP BY transaction_type | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different transaction types, and how many transactions of each have taken place? |
SELECT transaction_type FROM Financial_transactions GROUP BY transaction_type ORDER BY sum(transaction_amount) DESC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What is the transaction type that has processed the greatest total amount in transactions? |
SELECT transaction_type FROM Financial_transactions GROUP BY transaction_type ORDER BY sum(transaction_amount) DESC LIMIT 1 | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Return the type of transaction with the highest total amount. |
SELECT account_id , count(*) FROM Financial_transactions GROUP BY account_id | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Show the account id and the number of transactions for each account |
SELECT account_id , count(*) FROM Financial_transactions GROUP BY account_id | Given the Table accounts having columns as account_id has datatype number, customer_id has datatype number, account_name has datatype text, other_account_details has datatype text which has account_id and Given the Table customers having columns as customer_id has datatype number, customer_first_name has datatype text, customer_last_name has datatype text, customer_address has datatype text, customer_phone has datatype text, customer_email has datatype text, other_customer_details has datatype text which has customer_id and Given the Table customers cards having columns as card_id has datatype number, customer_id has datatype number, card_type_code has datatype text, card_number has datatype text, date_valid_from has datatype time, date_valid_to has datatype time, other_card_details has datatype text which has card_id and Given the Table financial transactions having columns as transaction_id has datatype number, previous_transaction_id has datatype number, account_id has datatype number, card_id has datatype number, transaction_type has datatype text, transaction_date has datatype time, transaction_amount has datatype number, transaction_comment has datatype text, other_transaction_details has datatype text which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. What are the different account ids that have made financial transactions, as well as how many transactions correspond to each? |
SELECT count(*) FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. How many tracks do we have? |
SELECT count(*) FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Count the number of tracks. |
SELECT name , LOCATION FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the name and location for all tracks. |
SELECT name , LOCATION FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names and locations of all tracks? |
SELECT name , seating FROM track WHERE year_opened > 2000 ORDER BY seating | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show names and seatings, ordered by seating for all tracks opened after 2000. |
SELECT name , seating FROM track WHERE year_opened > 2000 ORDER BY seating | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names and seatings for all tracks opened after 2000, ordered by seating? |
SELECT name , LOCATION , seating FROM track ORDER BY year_opened DESC LIMIT 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What is the name, location and seating for the most recently opened track? |
SELECT name , LOCATION , seating FROM track ORDER BY year_opened DESC LIMIT 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Return the name, location, and seating of the track that was opened in the most recent year. |
SELECT min(seating) , max(seating) , avg(seating) FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What is the minimum, maximum, and average seating for all tracks. |
SELECT min(seating) , max(seating) , avg(seating) FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Return the minimum, maximum, and average seating across all tracks. |
SELECT name , LOCATION , year_opened FROM track WHERE seating > (SELECT avg(seating) FROM track) | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the name, location, open year for all tracks with a seating higher than the average. |
SELECT name , LOCATION , year_opened FROM track WHERE seating > (SELECT avg(seating) FROM track) | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names, locations, and years of opening for tracks with seating higher than average? |
SELECT DISTINCT LOCATION FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are distinct locations where tracks are located? |
SELECT DISTINCT LOCATION FROM track | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Give the different locations of tracks. |
SELECT count(*) FROM race | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. How many races are there? |
SELECT count(*) FROM race | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Count the number of races. |
SELECT DISTINCT CLASS FROM race | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the distinct classes that races can have? |
SELECT DISTINCT CLASS FROM race | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Return the different classes of races. |
SELECT name , CLASS , date FROM race | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show name, class, and date for all races. |
SELECT name , CLASS , date FROM race | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names, classes, and dates for all races? |
SELECT CLASS , count(*) FROM race GROUP BY CLASS | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the race class and number of races in each class. |
SELECT CLASS , count(*) FROM race GROUP BY CLASS | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the different classes of races, and how many races correspond to each? |
SELECT CLASS FROM race GROUP BY CLASS ORDER BY count(*) DESC LIMIT 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What is the race class with most number of races. |
SELECT CLASS FROM race GROUP BY CLASS ORDER BY count(*) DESC LIMIT 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Give the class of races that is most common. |
SELECT CLASS FROM race GROUP BY CLASS HAVING count(*) >= 2 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. List the race class with at least two races. |
SELECT CLASS FROM race GROUP BY CLASS HAVING count(*) >= 2 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the classes of races that have two or more corresponding races? |
SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id WHERE T1.class = 'GT' | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names for tracks without a race in class 'GT'. |
SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id WHERE T1.class = 'GT' | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Give the names of tracks that do not have a race in the class 'GT'. |
SELECT name FROM track WHERE track_id NOT IN (SELECT track_id FROM race) | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show all track names that have had no races. |
SELECT name FROM track WHERE track_id NOT IN (SELECT track_id FROM race) | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Return the names of tracks that have no had any races. |
SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show year where a track with a seating at least 5000 opened and a track with seating no more than 4000 opened. |
SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the years of opening for tracks with seating between 4000 and 5000? |
SELECT T2.name , count(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the name of track and the number of races in each track. |
SELECT T2.name , count(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names of different tracks, and how many races has each had? |
SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id ORDER BY count(*) DESC LIMIT 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the name of track with most number of races. |
SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id ORDER BY count(*) DESC LIMIT 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What is the name of the track that has had the greatest number of races? |
SELECT T1.name , T1.date , T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the name and date for each race and its track name. |
SELECT T1.name , T1.date , T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names and dates of races, and the names of the tracks where they are held? |
SELECT T2.name , T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id HAVING count(*) = 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Show the name and location of track with 1 race. |
SELECT T2.name , T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id HAVING count(*) = 1 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the names and locations of tracks that have had exactly 1 race? |
SELECT LOCATION FROM track WHERE seating > 90000 INTERSECT SELECT LOCATION FROM track WHERE seating < 70000 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. Find the locations where have both tracks with more than 90000 seats and tracks with less than 70000 seats. |
SELECT LOCATION FROM track WHERE seating > 90000 INTERSECT SELECT LOCATION FROM track WHERE seating < 70000 | Given the Table race having columns as Race_ID has datatype number, Name has datatype text, Class has datatype text, Date has datatype text, Track_ID has datatype text which has Race_ID and Given the Table track having columns as Track_ID has datatype number, Name has datatype text, Location has datatype text, Seating has datatype number, Year_Opened has datatype number which has Track_ID. Answer the question by writing the appropriate SQL code. What are the locations that have both tracks with more than 90000 seats, and tracks with fewer than 70000 seats? |
SELECT count(*) FROM member WHERE Membership_card = 'Black' | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. How many members have the black membership card? |
SELECT count(*) , address FROM member GROUP BY address | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Find the number of members living in each address. |
SELECT name FROM member WHERE address = 'Harford' OR address = 'Waterbury' | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Give me the names of members whose address is in Harford or Waterbury. |
SELECT name , member_id FROM member WHERE Membership_card = 'Black' OR age < 30 | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Find the ids and names of members who are under age 30 or with black membership card. |
SELECT Time_of_purchase , age , address FROM member ORDER BY Time_of_purchase | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Find the purchase time, age and address of each member, and show the results in the order of purchase time. |
SELECT Membership_card FROM member GROUP BY Membership_card HAVING count(*) > 5 | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Which membership card has more than 5 members? |
SELECT address FROM member WHERE age < 30 INTERSECT SELECT address FROM member WHERE age > 40 | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Which address has both members younger than 30 and members older than 40? |
SELECT membership_card FROM member WHERE address = 'Hartford' INTERSECT SELECT membership_card FROM member WHERE address = 'Waterbury' | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. What is the membership card held by both members living in Hartford and ones living in Waterbury address? |
SELECT count(*) FROM member WHERE address != 'Hartford' | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. How many members are not living in Hartford? |
SELECT address FROM member EXCEPT SELECT address FROM member WHERE Membership_card = 'Black' | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Which address do not have any member with the black membership card? |
SELECT address FROM shop ORDER BY open_year | Given the Table shop having columns as Shop_ID has datatype number, Address has datatype text, Num_of_staff has datatype text, Score has datatype number, Open_Year has datatype text which has Shop_ID and Given the Table member having columns as Member_ID has datatype number, Name has datatype text, Membership_card has datatype text, Age has datatype number, Time_of_purchase has datatype number, Level_of_membership has datatype number, Address has datatype text which has Member_ID and Given the Table happy hour having columns as HH_ID has datatype number, Shop_ID has datatype number, Month has datatype text, Num_of_shaff_in_charge has datatype number which has HH_ID and Given the Table happy hour member having columns as HH_ID has datatype number, Member_ID has datatype number, Total_amount has datatype number which has HH_ID. Answer the question by writing the appropriate SQL code. Show the shop addresses ordered by their opening year. |
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