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SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING count(*) > 4 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the policy types more than 4 customers use. Show their type code. |
SELECT sum(settlement_amount) , avg(settlement_amount) FROM settlements | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the total and average amount of settlements. |
SELECT sum(settlement_amount) , avg(settlement_amount) FROM settlements | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Return the sum and average of all settlement amounts. |
SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING count(*) > 2 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the name of services that have been used for more than 2 times in first notification of loss. |
SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING count(*) > 2 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Which services have been used more than twice in first notification of loss? Return the service name. |
SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY sum(t2.settlement_amount) DESC LIMIT 1 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What is the effective date of the claim that has the largest amount of total settlement? |
SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY sum(t2.settlement_amount) DESC LIMIT 1 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the claim that has the largest total settlement amount. Return the effective date of the claim. |
SELECT count(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Dayana Robel" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. How many policies are listed for the customer named "Dayana Robel"? |
SELECT count(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Dayana Robel" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Count the total number of policies used by the customer named "Dayana Robel". |
SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What is the name of the customer who has the most policies listed? |
SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1 | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Which customer uses the most policies? Give me the customer name. |
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "Dayana Robel" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What are all the policy types of the customer named "Dayana Robel"? |
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "Dayana Robel" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Tell me the types of the policy used by the customer named "Dayana Robel". |
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1) | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What are all the policy types of the customer that has the most policies listed? |
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1) | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. List all the policy types used by the customer enrolled in the most policies. |
SELECT service_name FROM services ORDER BY service_name | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. List all the services in the alphabetical order. |
SELECT service_name FROM services ORDER BY service_name | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Give me a list of all the service names sorted alphabetically. |
SELECT count(*) FROM services | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. How many services are there? |
SELECT count(*) FROM services | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Count the total number of available services. |
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the names of users who do not have a first notification of loss record. |
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Which customers do not have a first notification of loss record? Give me the customer names. |
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" OR t3.service_name = "Upgrade a policy" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the names of customers who have used either the service "Close a policy" or the service "Upgrade a policy". |
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" OR t3.service_name = "Upgrade a policy" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Which customers have used the service named "Close a policy" or "Upgrade a policy"? Give me the customer names. |
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "New policy application" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the names of customers who have used both the service "Close a policy" and the service "New policy application". |
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "New policy application" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Which customers have used both the service named "Close a policy" and the service named "Upgrade a policy"? Give me the customer names. |
SELECT customer_id FROM customers WHERE customer_name LIKE "%Diana%" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the IDs of customers whose name contains "Diana". |
SELECT customer_id FROM customers WHERE customer_name LIKE "%Diana%" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What are the IDs of customers who have "Diana" in part of their names? |
SELECT max(settlement_amount) , min(settlement_amount) FROM settlements | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What are the maximum and minimum settlement amount on record? |
SELECT max(settlement_amount) , min(settlement_amount) FROM settlements | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Find the maximum and minimum settlement amount. |
SELECT customer_id , customer_name FROM customers ORDER BY customer_id ASC | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. List all the customers in increasing order of IDs. |
SELECT customer_id , customer_name FROM customers ORDER BY customer_id ASC | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What is the ordered list of customer ids? |
SELECT t2.date_opened , t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "%Diana%" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. Retrieve the open and close dates of all the policies associated with the customer whose name contains "Diana" |
SELECT t2.date_opened , t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "%Diana%" | Given the Table customers having columns as Customer_ID has datatype number, Customer_name has datatype text which has Customer_ID and Given the Table services having columns as Service_ID has datatype number, Service_name has datatype text which has Service_ID and Given the Table available policies having columns as Policy_ID has datatype number, policy_type_code has datatype text, Customer_Phone has datatype text which has Policy_ID and Given the Table customers policies having columns as Customer_ID has datatype number, Policy_ID has datatype number, Date_Opened has datatype time, Date_Closed has datatype time which has Customer_ID and Given the Table first notification of loss having columns as FNOL_ID has datatype number, Customer_ID has datatype number, Policy_ID has datatype number, Service_ID has datatype number which has FNOL_ID and Given the Table claims having columns as Claim_ID has datatype number, FNOL_ID has datatype number, Effective_Date has datatype time which has Claim_ID and Given the Table settlements having columns as Settlement_ID has datatype number, Claim_ID has datatype number, Effective_Date has datatype time, Settlement_Amount has datatype number which has Settlement_ID. Answer the question by writing the appropriate SQL code. What are the open and close dates of all the policies used by the customer who have "Diana" in part of their names? |
SELECT count(*) FROM enzyme | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many kinds of enzymes are there? |
SELECT count(*) FROM enzyme | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the total count of enzymes? |
SELECT name FROM enzyme ORDER BY name DESC | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. List the name of enzymes in descending lexicographical order. |
SELECT name FROM enzyme ORDER BY name DESC | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names of enzymes in descending order? |
SELECT name , LOCATION FROM enzyme | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. List the names and the locations that the enzymes can make an effect. |
SELECT name , LOCATION FROM enzyme | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names and locations of all enzymes listed? |
SELECT max(OMIM) FROM enzyme | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the maximum Online Mendelian Inheritance in Man (OMIM) value of the enzymes? |
SELECT max(OMIM) FROM enzyme | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the maximum OMIM value in the database? |
SELECT product , chromosome , porphyria FROM enzyme WHERE LOCATION = 'Cytosol' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the product, chromosome and porphyria related to the enzymes which take effect at the location 'Cytosol'? |
SELECT product , chromosome , porphyria FROM enzyme WHERE LOCATION = 'Cytosol' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the product, chromosome, and porphyria of the enzymes located at 'Cytosol'? |
SELECT name FROM enzyme WHERE product != 'Heme' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names of enzymes who does not produce 'Heme'? |
SELECT name FROM enzyme WHERE product != 'Heme' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names of enzymes whose product is not 'Heme'? |
SELECT name , trade_name FROM medicine WHERE FDA_approved = 'Yes' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names and trade names of the medicines which has 'Yes' value in the FDA record? |
SELECT name , trade_name FROM medicine WHERE FDA_approved = 'Yes' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names and trade names of the medcines that are FDA approved? |
SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names of enzymes in the medicine named 'Amisulpride' that can serve as an 'inhibitor'? |
SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names of the enzymes used in the medicine Amisulpride that acts as inhibitors? |
SELECT T1.id , T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING count(*) >= 2 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the ids and names of the medicine that can interact with two or more enzymes? |
SELECT T1.id , T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING count(*) >= 2 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. For every medicine id, what are the names of the medicines that can interact with more than one enzyme? |
SELECT T1.id , T1.Name , T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the ids, names and FDA approval status of medicines in descending order of the number of enzymes that it can interact with. |
SELECT T1.id , T1.Name , T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the ids, names, and FDA approval status for medicines ordered by descending number of possible enzyme interactions? |
SELECT T1.id , T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the id and name of the enzyme with most number of medicines that can interact as 'activator'? |
SELECT T1.id , T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the id and name of the enzyme that can interact with the most medicines as an activator? |
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the interaction type of the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'? |
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the type of interaction for the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'? |
SELECT interaction_type , count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC LIMIT 1 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the most common interaction type between enzymes and medicine? And how many are there? |
SELECT interaction_type , count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC LIMIT 1 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the most common types of interactions between enzymes and medicine, and how many types are there? |
SELECT count(*) FROM medicine WHERE FDA_approved = 'No' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many medicines have the FDA approval status 'No' ? |
SELECT count(*) FROM medicine WHERE FDA_approved = 'No' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many medicines were not approved by the FDA? |
SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction ); | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many enzymes do not have any interactions? |
SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction ); | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the count of enzymes without any interactions? |
SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What is the id and trade name of the medicines can interact with at least 3 enzymes? |
SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3 | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the ids and trade names of the medicine that can interact with at least 3 enzymes? |
SELECT DISTINCT T1.name , T1.location , T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the distinct name, location and products of the enzymes which has any 'inhibitor' interaction? |
SELECT DISTINCT T1.name , T1.location , T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the different names, locations, and products of the enzymes that are capable inhibitor interactions? |
SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activitor' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. List the medicine name and trade name which can both interact as 'inhibitor' and 'activitor' with enzymes. |
SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activitor' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the medicine and trade names that can interact as an inhibitor and activitor with enzymes? |
SELECT name , trade_name FROM medicine EXCEPT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. Show the medicine names and trade names that cannot interact with the enzyme with product 'Heme'. |
SELECT name , trade_name FROM medicine EXCEPT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX' | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the medicine and trade names that cannot interact with the enzyme with the product 'Heme'? |
SELECT count(DISTINCT FDA_approved) FROM medicine | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many distinct FDA approval statuses are there for the medicines? |
SELECT count(DISTINCT FDA_approved) FROM medicine | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many different FDA approval statuses exist for medicines? |
SELECT name FROM enzyme WHERE name LIKE "%ALA%" | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. Which enzyme names have the substring "ALA"? |
SELECT name FROM enzyme WHERE name LIKE "%ALA%" | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. What are the names of enzymes that include the string 'ALA'? |
SELECT trade_name , count(*) FROM medicine GROUP BY trade_name | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. find the number of medicines offered by each trade. |
SELECT trade_name , count(*) FROM medicine GROUP BY trade_name | Given the Table medicine having columns as id has datatype number, name has datatype text, Trade_Name has datatype text, FDA_approved has datatype text which has id and Given the Table enzyme having columns as id has datatype number, name has datatype text, Location has datatype text, Product has datatype text, Chromosome has datatype text, OMIM has datatype number, Porphyria has datatype text which has id and Given the Table medicine enzyme interaction having columns as enzyme_id has datatype number, medicine_id has datatype number, interaction_type has datatype text which has enzyme_id. Answer the question by writing the appropriate SQL code. How many medicines are offered by each trade name? |
SELECT school , nickname FROM university ORDER BY founded | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. List all schools and their nicknames in the order of founded year. |
SELECT school , nickname FROM university ORDER BY founded | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What are the different schools and their nicknames, ordered by their founding years? |
SELECT school , LOCATION FROM university WHERE affiliation = 'Public' | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. List all public schools and their locations. |
SELECT school , LOCATION FROM university WHERE affiliation = 'Public' | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What are the public schools and what are their locations? |
SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. When was the school with the largest enrollment founded? |
SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Return the founded year for the school with the largest enrollment. |
SELECT founded FROM university WHERE affiliation != 'Public' ORDER BY founded DESC LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Find the founded year of the newest non public school. |
SELECT founded FROM university WHERE affiliation != 'Public' ORDER BY founded DESC LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What is the founded year of the non public school that was founded most recently? |
SELECT count(DISTINCT school_id) FROM basketball_match | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. How many schools are in the basketball match? |
SELECT count(DISTINCT school_id) FROM basketball_match | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Count the number of schools that have had basketball matches. |
SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What is the highest acc percent score in the competition? |
SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Return the highest acc percent across all basketball matches. |
SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What is the primary conference of the school that has the lowest acc percent score in the competition? |
SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Return the primary conference of the school with the lowest acc percentage score. |
SELECT t2.team_name , t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What is the team name and acc regular season score of the school that was founded for the longest time? |
SELECT t2.team_name , t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Return the name of the team and the acc during the regular season for the school that was founded the earliest. |
SELECT t2.All_Games , t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson' | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Find the location and all games score of the school that has Clemson as its team name. |
SELECT t2.All_Games , t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson' | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What are the all games score and location of the school called Clemson? |
SELECT avg(enrollment) FROM university WHERE founded < 1850 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What are the average enrollment size of the universities that are founded before 1850? |
SELECT avg(enrollment) FROM university WHERE founded < 1850 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Return the average enrollment of universities founded before 1850. |
SELECT enrollment , primary_conference FROM university ORDER BY founded LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. Show the enrollment and primary_conference of the oldest college. |
SELECT enrollment , primary_conference FROM university ORDER BY founded LIMIT 1 | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What are the enrollment and primary conference for the university which was founded the earliest? |
SELECT sum(enrollment) , min(enrollment) FROM university | Given the Table basketball match having columns as Team_ID has datatype number, School_ID has datatype number, Team_Name has datatype text, ACC_Regular_Season has datatype text, ACC_Percent has datatype text, ACC_Home has datatype text, ACC_Road has datatype text, All_Games has datatype text, All_Games_Percent has datatype number, All_Home has datatype text, All_Road has datatype text, All_Neutral has datatype text which has Team_ID and Given the Table university having columns as School_ID has datatype number, School has datatype text, Location has datatype text, Founded has datatype number, Affiliation has datatype text, Enrollment has datatype number, Nickname has datatype text, Primary_conference has datatype text which has School_ID. Answer the question by writing the appropriate SQL code. What is the total and minimum enrollment of all schools? |
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