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http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Lua | Lua | local file = io.open("input.txt","r")
local data = file:read("*a")
file:close()
local output = {}
local key = nil
-- iterate through lines
for line in data:gmatch("(.-)\r?\n") do
if line:match("%s") then
error("line contained space")
elseif line:sub(1,1) == ">" then
key = line:sub(2)
-- if key already exists, append to the previous input
output[key] = output[key] or ""
elseif key ~= nil then
output[key] = output[key] .. line
end
end
-- print result
for k,v in pairs(output) do
print(k..": "..v)
end |
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #M2000_Interpreter | M2000 Interpreter |
Module CheckIt {
Class FASTA_MACHINE {
Events "GetBuffer", "header", "DataLine", "Quit"
Public:
Module Run {
Const lineFeed$=chr$(13)+chr$(10)
Const WhiteSpace$=" "+chr$(9)+chrcode$(160)
Def long state=1, idstate=1
Def boolean Quit=False
Def Buf$, waste$, Packet$
GetNextPacket:
Call Event "Quit", &Quit
If Quit then exit
Call Event "GetBuffer", &Packet$
Buf$+=Packet$
If len(Buf$)=0 Then exit
On State Goto GetStartIdentifier, GetIdentifier, GetStartData, GetData, GetStartIdentifier2
exit
GetStartIdentifier:
waste$=rightpart$(Buf$, ">")
GetStartIdentifier2:
If len(waste$)=0 Then waste$=rightpart$(Buf$, ";") : idstate=2
If len(waste$)=0 Then idstate=1 : Goto GetNextPacket ' we have to read more
buf$=waste$
state=2
GetIdentifier:
If Len(Buf$)=len(lineFeed$) then {
if buf$<>lineFeed$ then Goto GetNextPacket
waste$=""
} Else {
if instr(buf$, lineFeed$)=0 then Goto GetNextPacket
waste$=rightpart$(Buf$, lineFeed$)
}
If idstate=2 Then {
idstate=1
\\ it's a comment, drop it
state=1
Goto GetNextPacket
} Else Call Event "header", filter$(leftpart$(Buf$,lineFeed$), WhiteSpace$)
Buf$=waste$
State=3
GetStartData:
while left$(buf$, 2)=lineFeed$ {buf$=Mid$(buf$,3)}
waste$=Leftpart$(Buf$, lineFeed$)
If len(waste$)=0 Then Goto GetNextPacket ' we have to read more
waste$=Filter$(waste$,WhiteSpace$)
Call Event "DataLine", leftpart$(Buf$,lineFeed$)
Buf$=Rightpart$(Buf$,lineFeed$)
state=4
GetData:
while left$(buf$, 2)=lineFeed$ {buf$=Mid$(buf$,3)}
waste$=Leftpart$(Buf$, lineFeed$)
If len(waste$)=0 Then Goto GetNextPacket ' we have to read more
If Left$(waste$,1)=";" Then wast$="": state=5 : Goto GetStartIdentifier2
If Left$(waste$,1)=">" Then state=1 : Goto GetStartIdentifier
waste$=Filter$(waste$,WhiteSpace$)
Call Event "DataLine", waste$
Buf$=Rightpart$(Buf$,lineFeed$)
Goto GetNextPacket
}
}
Group WithEvents K=FASTA_MACHINE()
Document Final$, Inp$
\\ In documents, "="" used for append data. Final$="append this"
Const NewLine$=chr$(13)+chr$(10)
Const Center=2
\\ Event's Functions
Function K_GetBuffer (New &a$) {
Input "IN:", a$
inp$=a$+NewLine$
while right$(a$, 1)="\" {
Input "IN:", b$
inp$=b$+NewLine$
if b$="" then b$="n"
a$+=b$
}
a$= replace$("\N","\n", a$)
a$= replace$("\n",NewLine$, a$)
}
Function K_header (New a$) {
iF Doc.Len(Final$)=0 then {
Final$=a$+": "
} Else Final$=Newline$+a$+": "
}
Function K_DataLine (New a$) {
Final$=a$
}
Function K_Quit (New &q) {
q=keypress(1)
}
Cls , 0
Report Center, "FASTA Format"
Report "Simulate input channel in packets (\n for new line). Use empty input to exit after new line, or press left mouse button and Enter to quit. Use ; to write comments. Use > to open a title"
Cls, row ' scroll from current row
K.Run
Cls
Report Center, "Input File"
Report Inp$
Report Center, "Output File"
Report Final$
}
checkit
|
http://rosettacode.org/wiki/Fibonacci_sequence | Fibonacci sequence | The Fibonacci sequence is a sequence Fn of natural numbers defined recursively:
F0 = 0
F1 = 1
Fn = Fn-1 + Fn-2, if n>1
Task
Write a function to generate the nth Fibonacci number.
Solutions can be iterative or recursive (though recursive solutions are generally considered too slow and are mostly used as an exercise in recursion).
The sequence is sometimes extended into negative numbers by using a straightforward inverse of the positive definition:
Fn = Fn+2 - Fn+1, if n<0
support for negative n in the solution is optional.
Related tasks
Fibonacci n-step number sequences
Leonardo numbers
References
Wikipedia, Fibonacci number
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #0815 | 0815 |
%<:0D:>~$<:01:~%>=<:a94fad42221f2702:>~>
}:_s:{x{={~$x+%{=>~>x~-x<:0D:~>~>~^:_s:?
|
http://rosettacode.org/wiki/Factors_of_an_integer | Factors of an integer |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Compute the factors of a positive integer.
These factors are the positive integers by which the number being factored can be divided to yield a positive integer result.
(Though the concepts function correctly for zero and negative integers, the set of factors of zero has countably infinite members, and the factors of negative integers can be obtained from the factors of related positive numbers without difficulty; this task does not require handling of either of these cases).
Note that every prime number has two factors: 1 and itself.
Related tasks
count in factors
prime decomposition
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
sequence: smallest number greater than previous term with exactly n divisors
| #360_Assembly | 360 Assembly | * Factors of an integer - 07/10/2015
FACTOR CSECT
USING FACTOR,R15 set base register
LA R7,PG pgi=@pg
LA R6,1 i
L R3,N loop count
LOOP L R5,N n
LA R4,0
DR R4,R6 n/i
LTR R4,R4 if mod(n,i)=0
BNZ NEXT
XDECO R6,PG+120 edit i
MVC 0(6,R7),PG+126 output i
LA R7,6(R7) pgi=pgi+6
NEXT LA R6,1(R6) i=i+1
BCT R3,LOOP loop
XPRNT PG,120 print buffer
XR R15,R15 set return code
BR R14 return to caller
N DC F'12345' <== input value
PG DC CL132' ' buffer
YREGS
END FACTOR |
http://rosettacode.org/wiki/Fast_Fourier_transform | Fast Fourier transform | Task
Calculate the FFT (Fast Fourier Transform) of an input sequence.
The most general case allows for complex numbers at the input
and results in a sequence of equal length, again of complex numbers.
If you need to restrict yourself to real numbers, the output should
be the magnitude (i.e.: sqrt(re2 + im2)) of the complex result.
The classic version is the recursive Cooley–Tukey FFT. Wikipedia has pseudo-code for that.
Further optimizations are possible but not required.
| #C | C |
#include <stdio.h>
#include <math.h>
#include <complex.h>
double PI;
typedef double complex cplx;
void _fft(cplx buf[], cplx out[], int n, int step)
{
if (step < n) {
_fft(out, buf, n, step * 2);
_fft(out + step, buf + step, n, step * 2);
for (int i = 0; i < n; i += 2 * step) {
cplx t = cexp(-I * PI * i / n) * out[i + step];
buf[i / 2] = out[i] + t;
buf[(i + n)/2] = out[i] - t;
}
}
}
void fft(cplx buf[], int n)
{
cplx out[n];
for (int i = 0; i < n; i++) out[i] = buf[i];
_fft(buf, out, n, 1);
}
void show(const char * s, cplx buf[]) {
printf("%s", s);
for (int i = 0; i < 8; i++)
if (!cimag(buf[i]))
printf("%g ", creal(buf[i]));
else
printf("(%g, %g) ", creal(buf[i]), cimag(buf[i]));
}
int main()
{
PI = atan2(1, 1) * 4;
cplx buf[] = {1, 1, 1, 1, 0, 0, 0, 0};
show("Data: ", buf);
fft(buf, 8);
show("\nFFT : ", buf);
return 0;
}
|
http://rosettacode.org/wiki/Factors_of_a_Mersenne_number | Factors of a Mersenne number | A Mersenne number is a number in the form of 2P-1.
If P is prime, the Mersenne number may be a Mersenne prime
(if P is not prime, the Mersenne number is also not prime).
In the search for Mersenne prime numbers it is advantageous to eliminate exponents by finding a small factor before starting a, potentially lengthy, Lucas-Lehmer test.
There are very efficient algorithms for determining if a number divides 2P-1 (or equivalently, if 2P mod (the number) = 1).
Some languages already have built-in implementations of this exponent-and-mod operation (called modPow or similar).
The following is how to implement this modPow yourself:
For example, let's compute 223 mod 47.
Convert the exponent 23 to binary, you get 10111. Starting with square = 1, repeatedly square it.
Remove the top bit of the exponent, and if it's 1 multiply square by the base of the exponentiation (2), then compute square modulo 47.
Use the result of the modulo from the last step as the initial value of square in the next step:
remove optional
square top bit multiply by 2 mod 47
──────────── ─────── ───────────── ──────
1*1 = 1 1 0111 1*2 = 2 2
2*2 = 4 0 111 no 4
4*4 = 16 1 11 16*2 = 32 32
32*32 = 1024 1 1 1024*2 = 2048 27
27*27 = 729 1 729*2 = 1458 1
Since 223 mod 47 = 1, 47 is a factor of 2P-1.
(To see this, subtract 1 from both sides: 223-1 = 0 mod 47.)
Since we've shown that 47 is a factor, 223-1 is not prime.
Further properties of Mersenne numbers allow us to refine the process even more.
Any factor q of 2P-1 must be of the form 2kP+1, k being a positive integer or zero. Furthermore, q must be 1 or 7 mod 8.
Finally any potential factor q must be prime.
As in other trial division algorithms, the algorithm stops when 2kP+1 > sqrt(N).
These primality tests only work on Mersenne numbers where P is prime. For example, M4=15 yields no factors using these techniques, but factors into 3 and 5, neither of which fit 2kP+1.
Task
Using the above method find a factor of 2929-1 (aka M929)
Related tasks
count in factors
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
See also
Computers in 1948: 2127 - 1
(Note: This video is no longer available because the YouTube account associated with this video has been terminated.)
| #Arturo | Arturo | mersenneFactors: function [q][
if not? prime? q -> print "number not prime!"
r: new q
while -> r > 0
-> shl 'r 1
d: new 1 + 2 * q
while [true][
i: new 1
p: new r
while [p <> 0][
i: new (i * i) % d
if p < 0 -> 'i * 2
if i > d -> 'i - d
shl 'p 1
]
if? i <> 1 -> 'd + 2 * q
else -> break
]
print ["2 ^" q "- 1 = 0 ( mod" d ")"]
]
mersenneFactors 929 |
http://rosettacode.org/wiki/Factors_of_a_Mersenne_number | Factors of a Mersenne number | A Mersenne number is a number in the form of 2P-1.
If P is prime, the Mersenne number may be a Mersenne prime
(if P is not prime, the Mersenne number is also not prime).
In the search for Mersenne prime numbers it is advantageous to eliminate exponents by finding a small factor before starting a, potentially lengthy, Lucas-Lehmer test.
There are very efficient algorithms for determining if a number divides 2P-1 (or equivalently, if 2P mod (the number) = 1).
Some languages already have built-in implementations of this exponent-and-mod operation (called modPow or similar).
The following is how to implement this modPow yourself:
For example, let's compute 223 mod 47.
Convert the exponent 23 to binary, you get 10111. Starting with square = 1, repeatedly square it.
Remove the top bit of the exponent, and if it's 1 multiply square by the base of the exponentiation (2), then compute square modulo 47.
Use the result of the modulo from the last step as the initial value of square in the next step:
remove optional
square top bit multiply by 2 mod 47
──────────── ─────── ───────────── ──────
1*1 = 1 1 0111 1*2 = 2 2
2*2 = 4 0 111 no 4
4*4 = 16 1 11 16*2 = 32 32
32*32 = 1024 1 1 1024*2 = 2048 27
27*27 = 729 1 729*2 = 1458 1
Since 223 mod 47 = 1, 47 is a factor of 2P-1.
(To see this, subtract 1 from both sides: 223-1 = 0 mod 47.)
Since we've shown that 47 is a factor, 223-1 is not prime.
Further properties of Mersenne numbers allow us to refine the process even more.
Any factor q of 2P-1 must be of the form 2kP+1, k being a positive integer or zero. Furthermore, q must be 1 or 7 mod 8.
Finally any potential factor q must be prime.
As in other trial division algorithms, the algorithm stops when 2kP+1 > sqrt(N).
These primality tests only work on Mersenne numbers where P is prime. For example, M4=15 yields no factors using these techniques, but factors into 3 and 5, neither of which fit 2kP+1.
Task
Using the above method find a factor of 2929-1 (aka M929)
Related tasks
count in factors
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
See also
Computers in 1948: 2127 - 1
(Note: This video is no longer available because the YouTube account associated with this video has been terminated.)
| #AutoHotkey | AutoHotkey | MsgBox % MFact(27) ;-1: 27 is not prime
MsgBox % MFact(2) ; 0
MsgBox % MFact(3) ; 0
MsgBox % MFact(5) ; 0
MsgBox % MFact(7) ; 0
MsgBox % MFact(11) ; 23
MsgBox % MFact(13) ; 0
MsgBox % MFact(17) ; 0
MsgBox % MFact(19) ; 0
MsgBox % MFact(23) ; 47
MsgBox % MFact(29) ; 233
MsgBox % MFact(31) ; 0
MsgBox % MFact(37) ; 223
MsgBox % MFact(41) ; 13367
MsgBox % MFact(43) ; 431
MsgBox % MFact(47) ; 2351
MsgBox % MFact(53) ; 6361
MsgBox % MFact(929) ; 13007
MFact(p) { ; blank if 2**p-1 can be prime, otherwise a prime divisor < 2**32
If !IsPrime32(p)
Return -1 ; Error (p must be prime)
Loop % 2.0**(p<64 ? p/2-1 : 31)/p ; test prime divisors < 2**32, up to sqrt(2**p-1)
If (((q:=2*p*A_Index+1)&7 = 1 || q&7 = 7) && IsPrime32(q) && PowMod(2,p,q)=1)
Return q
Return 0
}
IsPrime32(n) { ; n < 2**32
If n in 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97
Return 1
If (!(n&1)||!mod(n,3)||!mod(n,5)||!mod(n,7)||!mod(n,11)||!mod(n,13)||!mod(n,17)||!mod(n,19))
Return 0
n1 := d := n-1, s := 0
While !(d&1)
d>>=1, s++
Loop 3 {
x := PowMod( A_Index=1 ? 2 : A_Index=2 ? 7 : 61, d, n)
If (x=1 || x=n1)
Continue
Loop % s-1
If (1 = x:=PowMod(x,2,n))
Return 0
Else If (x = n1)
Break
IfLess x,%n1%, Return 0
}
Return 1
}
PowMod(x,n,m) { ; x**n mod m
y := 1, i := n, z := x
While i>0
y := i&1 ? mod(y*z,m) : y, z := mod(z*z,m), i >>= 1
Return y
} |
http://rosettacode.org/wiki/Farey_sequence | Farey sequence | The Farey sequence Fn of order n is the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to n, arranged in order of increasing size.
The Farey sequence is sometimes incorrectly called a Farey series.
Each Farey sequence:
starts with the value 0 (zero), denoted by the fraction
0
1
{\displaystyle {\frac {0}{1}}}
ends with the value 1 (unity), denoted by the fraction
1
1
{\displaystyle {\frac {1}{1}}}
.
The Farey sequences of orders 1 to 5 are:
F
1
=
0
1
,
1
1
{\displaystyle {\bf {\it {F}}}_{1}={\frac {0}{1}},{\frac {1}{1}}}
F
2
=
0
1
,
1
2
,
1
1
{\displaystyle {\bf {\it {F}}}_{2}={\frac {0}{1}},{\frac {1}{2}},{\frac {1}{1}}}
F
3
=
0
1
,
1
3
,
1
2
,
2
3
,
1
1
{\displaystyle {\bf {\it {F}}}_{3}={\frac {0}{1}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {1}{1}}}
F
4
=
0
1
,
1
4
,
1
3
,
1
2
,
2
3
,
3
4
,
1
1
{\displaystyle {\bf {\it {F}}}_{4}={\frac {0}{1}},{\frac {1}{4}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {3}{4}},{\frac {1}{1}}}
F
5
=
0
1
,
1
5
,
1
4
,
1
3
,
2
5
,
1
2
,
3
5
,
2
3
,
3
4
,
4
5
,
1
1
{\displaystyle {\bf {\it {F}}}_{5}={\frac {0}{1}},{\frac {1}{5}},{\frac {1}{4}},{\frac {1}{3}},{\frac {2}{5}},{\frac {1}{2}},{\frac {3}{5}},{\frac {2}{3}},{\frac {3}{4}},{\frac {4}{5}},{\frac {1}{1}}}
Task
Compute and show the Farey sequence for orders 1 through 11 (inclusive).
Compute and display the number of fractions in the Farey sequence for order 100 through 1,000 (inclusive) by hundreds.
Show the fractions as n/d (using the solidus [or slash] to separate the numerator from the denominator).
The length (the number of fractions) of a Farey sequence asymptotically approaches:
3 × n2 ÷
π
{\displaystyle \pi }
2
See also
OEIS sequence A006842 numerators of Farey series of order 1, 2, ···
OEIS sequence A006843 denominators of Farey series of order 1, 2, ···
OEIS sequence A005728 number of fractions in Farey series of order n
MathWorld entry Farey sequence
Wikipedia entry Farey sequence
| #Crystal | Crystal | require "big"
def farey(n)
a, b, c, d = 0, 1, 1, n
fracs = [] of BigRational
fracs << BigRational.new(0,1)
while c <= n
k = (n + b) // d
a, b, c, d = c, d, k * c - a, k * d - b
fracs << BigRational.new(a,b)
end
fracs.uniq.sort
end
puts "Farey sequence for order 1 through 11 (inclusive):"
(1..11).each do |n|
puts "F(#{n}): 0/1 #{farey(n)[1..-2].join(" ")} 1/1"
end
puts "Number of fractions in the Farey sequence:"
(100..1000).step(100) do |i|
puts "F(%4d) =%7d" % [i, farey(i).size]
end
|
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #Haskell | Haskell | import Data.Bool (bool)
import Data.List (intercalate, unfoldr)
import Data.Tuple (swap)
------------- FAIR SHARE BETWEEN TWO AND MORE ------------
thueMorse :: Int -> [Int]
thueMorse base = baseDigitsSumModBase base <$> [0 ..]
baseDigitsSumModBase :: Int -> Int -> Int
baseDigitsSumModBase base n =
mod
( sum $
unfoldr
( bool Nothing
. Just
. swap
. flip quotRem base
<*> (0 <)
)
n
)
base
--------------------------- TEST -------------------------
main :: IO ()
main =
putStrLn $
fTable
( "First 25 fairshare terms "
<> "for a given number of players:\n"
)
show
( ('[' :) . (<> "]") . intercalate ","
. fmap show
)
(take 25 . thueMorse)
[2, 3, 5, 11]
------------------------- DISPLAY ------------------------
fTable ::
String ->
(a -> String) ->
(b -> String) ->
(a -> b) ->
[a] ->
String
fTable s xShow fxShow f xs =
unlines $
s :
fmap
( ((<>) . justifyRight w ' ' . xShow)
<*> ((" -> " <>) . fxShow . f)
)
xs
where
w = maximum (length . xShow <$> xs)
justifyRight :: Int -> Char -> String -> String
justifyRight n c = (drop . length) <*> (replicate n c <>) |
http://rosettacode.org/wiki/Faulhaber%27s_triangle | Faulhaber's triangle | Named after Johann Faulhaber, the rows of Faulhaber's triangle are the coefficients of polynomials that represent sums of integer powers, which are extracted from Faulhaber's formula:
∑
k
=
1
n
k
p
=
1
p
+
1
∑
j
=
0
p
(
p
+
1
j
)
B
j
n
p
+
1
−
j
{\displaystyle \sum _{k=1}^{n}k^{p}={1 \over p+1}\sum _{j=0}^{p}{p+1 \choose j}B_{j}n^{p+1-j}}
where
B
n
{\displaystyle B_{n}}
is the nth-Bernoulli number.
The first 5 rows of Faulhaber's triangle, are:
1
1/2 1/2
1/6 1/2 1/3
0 1/4 1/2 1/4
-1/30 0 1/3 1/2 1/5
Using the third row of the triangle, we have:
∑
k
=
1
n
k
2
=
1
6
n
+
1
2
n
2
+
1
3
n
3
{\displaystyle \sum _{k=1}^{n}k^{2}={1 \over 6}n+{1 \over 2}n^{2}+{1 \over 3}n^{3}}
Task
show the first 10 rows of Faulhaber's triangle.
using the 18th row of Faulhaber's triangle, compute the sum:
∑
k
=
1
1000
k
17
{\displaystyle \sum _{k=1}^{1000}k^{17}}
(extra credit).
See also
Bernoulli numbers
Evaluate binomial coefficients
Faulhaber's formula (Wikipedia)
Faulhaber's triangle (PDF)
| #Haskell | Haskell | import Data.Ratio (Ratio, denominator, numerator, (%))
------------------------ FAULHABER -----------------------
faulhaber :: Int -> Rational -> Rational
faulhaber p n =
sum $
zipWith ((*) . (n ^)) [1 ..] (faulhaberTriangle !! p)
faulhaberTriangle :: [[Rational]]
faulhaberTriangle =
tail $
scanl
( \rs n ->
let xs = zipWith ((*) . (n %)) [2 ..] rs
in 1 - sum xs : xs
)
[]
[0 ..]
--------------------------- TEST -------------------------
main :: IO ()
main = do
let triangle = take 10 faulhaberTriangle
widths = maxWidths triangle
mapM_
putStrLn
[ unlines
( (justifyRatio widths 8 ' ' =<<)
<$> triangle
),
(show . numerator) (faulhaber 17 1000)
]
------------------------- DISPLAY ------------------------
justifyRatio ::
(Int, Int) -> Int -> Char -> Rational -> String
justifyRatio (wn, wd) n c nd =
go $
[numerator, denominator] <*> [nd]
where
-- Minimum column width, or more if specified.
w = max n (wn + wd + 2)
go [num, den]
| 1 == den = center w c (show num)
| otherwise =
let (q, r) = quotRem (w - 1) 2
in concat
[ justifyRight q c (show num),
"/",
justifyLeft (q + r) c (show den)
]
justifyLeft :: Int -> a -> [a] -> [a]
justifyLeft n c s = take n (s <> replicate n c)
justifyRight :: Int -> a -> [a] -> [a]
justifyRight n c = (drop . length) <*> (replicate n c <>)
center :: Int -> a -> [a] -> [a]
center n c s =
let (q, r) = quotRem (n - length s) 2
pad = replicate q c
in concat [pad, s, pad, replicate r c]
maxWidths :: [[Rational]] -> (Int, Int)
maxWidths xss =
let widest f xs = maximum $ fmap (length . show . f) xs
in ((,) . widest numerator <*> widest denominator) $
concat xss |
http://rosettacode.org/wiki/Faulhaber%27s_formula | Faulhaber's formula | In mathematics, Faulhaber's formula, named after Johann Faulhaber, expresses the sum of the p-th powers of the first n positive integers as a (p + 1)th-degree polynomial function of n, the coefficients involving Bernoulli numbers.
Task
Generate the first 10 closed-form expressions, starting with p = 0.
Related tasks
Bernoulli numbers.
evaluate binomial coefficients.
See also
The Wikipedia entry: Faulhaber's formula.
The Wikipedia entry: Bernoulli numbers.
The Wikipedia entry: binomial coefficients.
| #J | J | Bsecond=:verb define"0
+/,(<:*(_1^[)*!*(y^~1+[)%1+])"0/~i.1x+y
)
Bfirst=: Bsecond - 1&=
Faul=:adverb define
(0,|.(%m+1x) * (_1x&^ * !&(m+1) * Bfirst) i.1+m)&p.
) |
http://rosettacode.org/wiki/Fermat_numbers | Fermat numbers | In mathematics, a Fermat number, named after Pierre de Fermat who first studied them, is a positive integer of the form Fn = 22n + 1 where n is a non-negative integer.
Despite the simplicity of generating Fermat numbers, they have some powerful mathematical properties and are extensively used in cryptography & pseudo-random number generation, and are often linked to other number theoric fields.
As of this writing, (mid 2019), there are only five known prime Fermat numbers, the first five (F0 through F4). Only the first twelve Fermat numbers have been completely factored, though many have been partially factored.
Task
Write a routine (function, procedure, whatever) to generate Fermat numbers.
Use the routine to find and display here, on this page, the first 10 Fermat numbers - F0 through F9.
Find and display here, on this page, the prime factors of as many Fermat numbers as you have patience for. (Or as many as can be found in five minutes or less of processing time). Note: if you make it past F11, there may be money, and certainly will be acclaim in it for you.
See also
Wikipedia - Fermat numbers
OEIS:A000215 - Fermat numbers
OEIS:A019434 - Fermat primes
| #Wren | Wren | import "/big" for BigInt
var fermat = Fn.new { |n| BigInt.two.pow(2.pow(n)) + 1 }
var fns = List.filled(10, null)
System.print("The first 10 Fermat numbers are:")
for (i in 0..9) {
fns[i] = fermat.call(i)
System.print("F%(String.fromCodePoint(0x2080+i)) = %(fns[i])")
}
System.print("\nFactors of the first 7 Fermat numbers:")
for (i in 0..6) {
System.write("F%(String.fromCodePoint(0x2080+i)) = ")
var factors = BigInt.primeFactors(fns[i])
System.write("%(factors)")
if (factors.count == 1) {
System.print(" (prime)")
} else if (!factors[1].isProbablePrime(5)) {
System.print(" (second factor is composite)")
} else {
System.print()
}
} |
http://rosettacode.org/wiki/Fibonacci_n-step_number_sequences | Fibonacci n-step number sequences | These number series are an expansion of the ordinary Fibonacci sequence where:
For
n
=
2
{\displaystyle n=2}
we have the Fibonacci sequence; with initial values
[
1
,
1
]
{\displaystyle [1,1]}
and
F
k
2
=
F
k
−
1
2
+
F
k
−
2
2
{\displaystyle F_{k}^{2}=F_{k-1}^{2}+F_{k-2}^{2}}
For
n
=
3
{\displaystyle n=3}
we have the tribonacci sequence; with initial values
[
1
,
1
,
2
]
{\displaystyle [1,1,2]}
and
F
k
3
=
F
k
−
1
3
+
F
k
−
2
3
+
F
k
−
3
3
{\displaystyle F_{k}^{3}=F_{k-1}^{3}+F_{k-2}^{3}+F_{k-3}^{3}}
For
n
=
4
{\displaystyle n=4}
we have the tetranacci sequence; with initial values
[
1
,
1
,
2
,
4
]
{\displaystyle [1,1,2,4]}
and
F
k
4
=
F
k
−
1
4
+
F
k
−
2
4
+
F
k
−
3
4
+
F
k
−
4
4
{\displaystyle F_{k}^{4}=F_{k-1}^{4}+F_{k-2}^{4}+F_{k-3}^{4}+F_{k-4}^{4}}
...
For general
n
>
2
{\displaystyle n>2}
we have the Fibonacci
n
{\displaystyle n}
-step sequence -
F
k
n
{\displaystyle F_{k}^{n}}
; with initial values of the first
n
{\displaystyle n}
values of the
(
n
−
1
)
{\displaystyle (n-1)}
'th Fibonacci
n
{\displaystyle n}
-step sequence
F
k
n
−
1
{\displaystyle F_{k}^{n-1}}
; and
k
{\displaystyle k}
'th value of this
n
{\displaystyle n}
'th sequence being
F
k
n
=
∑
i
=
1
(
n
)
F
k
−
i
(
n
)
{\displaystyle F_{k}^{n}=\sum _{i=1}^{(n)}{F_{k-i}^{(n)}}}
For small values of
n
{\displaystyle n}
, Greek numeric prefixes are sometimes used to individually name each series.
Fibonacci
n
{\displaystyle n}
-step sequences
n
{\displaystyle n}
Series name
Values
2
fibonacci
1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 ...
3
tribonacci
1 1 2 4 7 13 24 44 81 149 274 504 927 1705 3136 ...
4
tetranacci
1 1 2 4 8 15 29 56 108 208 401 773 1490 2872 5536 ...
5
pentanacci
1 1 2 4 8 16 31 61 120 236 464 912 1793 3525 6930 ...
6
hexanacci
1 1 2 4 8 16 32 63 125 248 492 976 1936 3840 7617 ...
7
heptanacci
1 1 2 4 8 16 32 64 127 253 504 1004 2000 3984 7936 ...
8
octonacci
1 1 2 4 8 16 32 64 128 255 509 1016 2028 4048 8080 ...
9
nonanacci
1 1 2 4 8 16 32 64 128 256 511 1021 2040 4076 8144 ...
10
decanacci
1 1 2 4 8 16 32 64 128 256 512 1023 2045 4088 8172 ...
Allied sequences can be generated where the initial values are changed:
The Lucas series sums the two preceding values like the fibonacci series for
n
=
2
{\displaystyle n=2}
but uses
[
2
,
1
]
{\displaystyle [2,1]}
as its initial values.
Task
Write a function to generate Fibonacci
n
{\displaystyle n}
-step number sequences given its initial values and assuming the number of initial values determines how many previous values are summed to make the next number of the series.
Use this to print and show here at least the first ten members of the Fibo/tribo/tetra-nacci and Lucas sequences.
Related tasks
Fibonacci sequence
Wolfram Mathworld
Hofstadter Q sequence
Leonardo numbers
Also see
Lucas Numbers - Numberphile (Video)
Tribonacci Numbers (and the Rauzy Fractal) - Numberphile (Video)
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #C | C | /*
The function anynacci determines the n-arity of the sequence from the number of seed elements. 0 ended arrays are used since C does not have a way of determining the length of dynamic and function-passed integer arrays.*/
#include<stdlib.h>
#include<stdio.h>
int *
anynacci (int *seedArray, int howMany)
{
int *result = malloc (howMany * sizeof (int));
int i, j, initialCardinality;
for (i = 0; seedArray[i] != 0; i++);
initialCardinality = i;
for (i = 0; i < initialCardinality; i++)
result[i] = seedArray[i];
for (i = initialCardinality; i < howMany; i++)
{
result[i] = 0;
for (j = i - initialCardinality; j < i; j++)
result[i] += result[j];
}
return result;
}
int
main ()
{
int fibo[] = { 1, 1, 0 }, tribo[] = { 1, 1, 2, 0 }, tetra[] = { 1, 1, 2, 4, 0 }, luca[] = { 2, 1, 0 };
int *fibonacci = anynacci (fibo, 10), *tribonacci = anynacci (tribo, 10), *tetranacci = anynacci (tetra, 10),
*lucas = anynacci(luca, 10);
int i;
printf ("\nFibonacci\tTribonacci\tTetranacci\tLucas\n");
for (i = 0; i < 10; i++)
printf ("\n%d\t\t%d\t\t%d\t\t%d", fibonacci[i], tribonacci[i],
tetranacci[i], lucas[i]);
return 0;
} |
http://rosettacode.org/wiki/Feigenbaum_constant_calculation | Feigenbaum constant calculation | Task
Calculate the Feigenbaum constant.
See
Details in the Wikipedia article: Feigenbaum constant.
| #zkl | zkl | fcn feigenbaum{
maxIt,maxItJ,a1,a2,d1,a,d := 13, 10, 1.0, 0.0, 3.2, 0, 0;
println(" i d");
foreach i in ([2..maxIt]){
a=a1 + (a1 - a2)/d1;
foreach j in ([1..maxItJ]){
x,y := 0.0, 0.0;
foreach k in ([1..(1).shiftLeft(i)]){ y,x = 1.0 - 2.0*y*x, a - x*x; }
a-=x/y
}
d=(a1 - a2)/(a - a1);
println("%2d %.8f".fmt(i,d));
d1,a2,a1 = d,a1,a;
}
}(); |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #Smalltalk | Smalltalk | |a|
a := File name: 'input.txt'.
(a lastModifyTime) printNl. |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #Standard_ML | Standard ML | val mtime = OS.FileSys.modTime filename; (* returns a Time.time data structure *)
(* unfortunately it seems like you have to set modification & access times together *)
OS.FileSys.setTime (filename, NONE); (* sets modification & access time to now *)
(* equivalent to: *)
OS.FileSys.setTime (filename, SOME (Time.now ())) |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #Tcl | Tcl | # Get the modification time:
set timestamp [file mtime $filename]
# Set the modification time to ‘now’:
file mtime $filename [clock seconds] |
http://rosettacode.org/wiki/Fibonacci_word/fractal | Fibonacci word/fractal |
The Fibonacci word may be represented as a fractal as described here:
(Clicking on the above website (hal.archives-ouvertes.fr) will leave a cookie.)
For F_wordm start with F_wordCharn=1
Draw a segment forward
If current F_wordChar is 0
Turn left if n is even
Turn right if n is odd
next n and iterate until end of F_word
Task
Create and display a fractal similar to Fig 1.
(Clicking on the above website (hal.archives-ouvertes.fr) will leave a cookie.)
| #Tcl | Tcl | package require Tk
# OK, this stripped down version doesn't work for n<2…
proc fibword {n} {
set fw {1 0}
while {[llength $fw] < $n} {
lappend fw [lindex $fw end][lindex $fw end-1]
}
return [lindex $fw end]
}
proc drawFW {canv fw {w {[$canv cget -width]}} {h {[$canv cget -height]}}} {
set w [subst $w]
set h [subst $h]
# Generate the coordinate list using line segments of unit length
set d 3; # Match the orientation in the sample paper
set eo [set x [set y 0]]
set coords [list $x $y]
foreach c [split $fw ""] {
switch $d {
0 {lappend coords [incr x] $y}
1 {lappend coords $x [incr y]}
2 {lappend coords [incr x -1] $y}
3 {lappend coords $x [incr y -1]}
}
if {$c == 0} {
set d [expr {($d + ($eo ? -1 : 1)) % 4}]
}
set eo [expr {!$eo}]
}
# Draw, and rescale to fit in canvas
set id [$canv create line $coords]
lassign [$canv bbox $id] x1 y1 x2 y2
set sf [expr {min(($w-20.) / ($y2-$y1), ($h-20.) / ($x2-$x1))}]
$canv move $id [expr {-$x1}] [expr {-$y1}]
$canv scale $id 0 0 $sf $sf
$canv move $id 10 10
# Return the item ID to allow user reconfiguration
return $id
}
pack [canvas .c -width 500 -height 500]
drawFW .c [fibword 23] |
http://rosettacode.org/wiki/Find_common_directory_path | Find common directory path | Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test'
'/home/user1/tmp/covert/operator'
'/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory '/home/user1/tmp' and not the longest common string '/home/user1/tmp/cove'.
If your language has a routine that performs this function (even if it does not have a changeable separator character), then mention it as part of the task.
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #PHP | PHP | <?php
/*
This works with dirs and files in any number of combinations.
*/
function _commonPath($dirList)
{
$arr = array();
foreach($dirList as $i => $path)
{
$dirList[$i] = explode('/', $path);
unset($dirList[$i][0]);
$arr[$i] = count($dirList[$i]);
}
$min = min($arr);
for($i = 0; $i < count($dirList); $i++)
{
while(count($dirList[$i]) > $min)
{
array_pop($dirList[$i]);
}
$dirList[$i] = '/' . implode('/' , $dirList[$i]);
}
$dirList = array_unique($dirList);
while(count($dirList) !== 1)
{
$dirList = array_map('dirname', $dirList);
$dirList = array_unique($dirList);
}
reset($dirList);
return current($dirList);
}
/* TEST */
$dirs = array(
'/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator',
'/home/user1/tmp/coven/members',
);
if('/home/user1/tmp' !== common_path($dirs))
{
echo 'test fail';
} else {
echo 'test success';
}
?> |
http://rosettacode.org/wiki/Filter | Filter | Task
Select certain elements from an Array into a new Array in a generic way.
To demonstrate, select all even numbers from an Array.
As an option, give a second solution which filters destructively,
by modifying the original Array rather than creating a new Array.
| #D.C3.A9j.C3.A0_Vu | Déjà Vu | filter pred lst:
]
for value in copy lst:
if pred @value:
@value
[
even x:
= 0 % x 2
!. filter @even [ 0 1 2 3 4 5 6 7 8 9 ] |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #Ruby | Ruby | def recurse x
puts x
recurse(x+1)
end
recurse(0) |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #Run_BASIC | Run BASIC | a = recurTest(1)
function recurTest(n)
if n mod 100000 then cls:print n
if n > 327000 then [ext]
n = recurTest(n+1)
[ext]
end function |
http://rosettacode.org/wiki/FizzBuzz | FizzBuzz | Task
Write a program that prints the integers from 1 to 100 (inclusive).
But:
for multiples of three, print Fizz (instead of the number)
for multiples of five, print Buzz (instead of the number)
for multiples of both three and five, print FizzBuzz (instead of the number)
The FizzBuzz problem was presented as the lowest level of comprehension required to illustrate adequacy.
Also see
(a blog) dont-overthink-fizzbuzz
(a blog) fizzbuzz-the-programmers-stairway-to-heaven
| #GW-BASIC | GW-BASIC | fizzbuzz :: Int -> String
fizzbuzz x
| f 15 = "FizzBuzz"
| f 3 = "Fizz"
| f 5 = "Buzz"
| otherwise = show x
where
f = (0 ==) . rem x
main :: IO ()
main = mapM_ (putStrLn . fizzbuzz) [1 .. 100] |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #Pascal | Pascal | my $size1 = -s 'input.txt';
my $size2 = -s '/input.txt'; |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #Perl | Perl | my $size1 = -s 'input.txt';
my $size2 = -s '/input.txt'; |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #Phix | Phix | function file_size(sequence file_name)
object d = dir(file_name)
if atom(d) or length(d)!=1 then return -1 end if
return d[1][D_SIZE]
end function
procedure test(sequence file_name)
integer size = file_size(file_name)
if size<0 then
printf(1,"%s file does not exist.\n",{file_name})
else
printf(1,"%s size is %d.\n",{file_name,size})
end if
end procedure
test("input.txt") -- in the current working directory
test("/input.txt") -- in the file system root
|
http://rosettacode.org/wiki/File_input/output | File input/output | File input/output is part of Short Circuit's Console Program Basics selection.
Task
Create a file called "output.txt", and place in it the contents of the file "input.txt", via an intermediate variable.
In other words, your program will demonstrate:
how to read from a file into a variable
how to write a variable's contents into a file
Oneliners that skip the intermediate variable are of secondary interest — operating systems have copy commands for that.
| #Go | Go | package main
import (
"fmt"
"io/ioutil"
)
func main() {
b, err := ioutil.ReadFile("input.txt")
if err != nil {
fmt.Println(err)
return
}
if err = ioutil.WriteFile("output.txt", b, 0666); err != nil {
fmt.Println(err)
}
} |
http://rosettacode.org/wiki/File_input/output | File input/output | File input/output is part of Short Circuit's Console Program Basics selection.
Task
Create a file called "output.txt", and place in it the contents of the file "input.txt", via an intermediate variable.
In other words, your program will demonstrate:
how to read from a file into a variable
how to write a variable's contents into a file
Oneliners that skip the intermediate variable are of secondary interest — operating systems have copy commands for that.
| #Groovy | Groovy | content = new File('input.txt').text
new File('output.txt').write(content) |
http://rosettacode.org/wiki/Fibonacci_word | Fibonacci word | The Fibonacci Word may be created in a manner analogous to the Fibonacci Sequence as described here:
Define F_Word1 as 1
Define F_Word2 as 0
Form F_Word3 as F_Word2 concatenated with F_Word1 i.e.: 01
Form F_Wordn as F_Wordn-1 concatenated with F_wordn-2
Task
Perform the above steps for n = 37.
You may display the first few but not the larger values of n.
{Doing so will get the task's author into trouble with them what be (again!).}
Instead, create a table for F_Words 1 to 37 which shows:
The number of characters in the word
The word's Entropy
Related tasks
Fibonacci word/fractal
Entropy
Entropy/Narcissist
| #jq | jq | # Input: an array of strings.
# Output: an object with the strings as keys,
# the values of which are the corresponding frequencies.
def counter:
reduce .[] as $item ( {}; .[$item] += 1 ) ;
# entropy in bits of the input string
def entropy:
(explode | map( [.] | implode ) | counter | [ .[] | . * (.|log) ] | add) as $sum
| ((length|log) - ($sum / length)) / (2|log) ; |
http://rosettacode.org/wiki/Fibonacci_word | Fibonacci word | The Fibonacci Word may be created in a manner analogous to the Fibonacci Sequence as described here:
Define F_Word1 as 1
Define F_Word2 as 0
Form F_Word3 as F_Word2 concatenated with F_Word1 i.e.: 01
Form F_Wordn as F_Wordn-1 concatenated with F_wordn-2
Task
Perform the above steps for n = 37.
You may display the first few but not the larger values of n.
{Doing so will get the task's author into trouble with them what be (again!).}
Instead, create a table for F_Words 1 to 37 which shows:
The number of characters in the word
The word's Entropy
Related tasks
Fibonacci word/fractal
Entropy
Entropy/Narcissist
| #Julia | Julia | using DataStructures
entropy(s::AbstractString) = -sum(x -> x / length(s) * log2(x / length(s)), values(counter(s)))
function fibboword(n::Int64)
# Initialize the result
r = Array{String}(n)
# First element
r[1] = "0"
# If more than 2, set the second element
if n ≥ 2 r[2] = "1" end
# Recursively create elements > 3
for i in 3:n
r[i] = r[i - 1] * r[i - 2]
end
return r
end
function testfibbo(n::Integer)
fib = fibboword(n)
for i in 1:length(fib)
@printf("%3d%9d%12.6f\n", i, length(fib[i]), entropy(fib[i]))
end
return 0
end
println(" n\tlength\tentropy")
testfibbo(37) |
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Mathematica.2FWolfram_Language | Mathematica/Wolfram Language | ImportString[">Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
", "FASTA"] |
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Nim | Nim |
import strutils
let input = """>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED""".unindent
proc fasta*(input: string) =
var row = ""
for line in input.splitLines:
if line.startsWith(">"):
if row != "": echo row
row = line[1..^1] & ": "
else:
row &= line.strip
echo row
fasta(input)
|
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Objeck | Objeck | class Fasta {
function : Main(args : String[]) ~ Nil {
if(args->Size() = 1) {
is_line := false;
tokens := System.Utility.Parser->Tokenize(System.IO.File.FileReader->ReadFile(args[0]))<String>;
each(i : tokens) {
token := tokens->Get(i);
if(token->Get(0) = '>') {
is_line := true;
if(i <> 0) {
"\n"->Print();
};
}
else if(is_line) {
"{$token}: "->Print();
is_line := false;
}
else {
token->Print();
};
};
};
};
}
}
|
http://rosettacode.org/wiki/Fibonacci_sequence | Fibonacci sequence | The Fibonacci sequence is a sequence Fn of natural numbers defined recursively:
F0 = 0
F1 = 1
Fn = Fn-1 + Fn-2, if n>1
Task
Write a function to generate the nth Fibonacci number.
Solutions can be iterative or recursive (though recursive solutions are generally considered too slow and are mostly used as an exercise in recursion).
The sequence is sometimes extended into negative numbers by using a straightforward inverse of the positive definition:
Fn = Fn+2 - Fn+1, if n<0
support for negative n in the solution is optional.
Related tasks
Fibonacci n-step number sequences
Leonardo numbers
References
Wikipedia, Fibonacci number
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #11l | 11l | F fib_iter(n)
I n < 2
R n
V fib_prev = 1
V fib = 1
L 2 .< n
(fib_prev, fib) = (fib, fib + fib_prev)
R fib
L(i) 1..20
print(fib_iter(i), end' ‘ ’)
print() |
http://rosettacode.org/wiki/Factors_of_an_integer | Factors of an integer |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Compute the factors of a positive integer.
These factors are the positive integers by which the number being factored can be divided to yield a positive integer result.
(Though the concepts function correctly for zero and negative integers, the set of factors of zero has countably infinite members, and the factors of negative integers can be obtained from the factors of related positive numbers without difficulty; this task does not require handling of either of these cases).
Note that every prime number has two factors: 1 and itself.
Related tasks
count in factors
prime decomposition
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
sequence: smallest number greater than previous term with exactly n divisors
| #68000_Assembly | 68000 Assembly | ;max input range equals 0 to 0xFFFFFFFF.
jsr GetInput ;unimplemented routine to get user input for a positive (nonzero) integer.
;output of this routine will be in D0.
MOVE.L D0,D1 ;D1 will be used for temp storage.
MOVE.L #1,D2 ;start with 1.
computeFactors:
DIVU D2,D1 ;remainder is in top 2 bytes, quotient in bottom 2.
MOVE.L D1,D3 ;temporarily store into D3 to check the remainder
SWAP D3 ;swap the high and low words of D3. Now bottom 2 bytes contain remainder.
CMP.W #0,D3 ;is the bottom word equal to 0?
BNE D2_Wasnt_A_Divisor ;if not, D2 was not a factor of D1.
JSR PrintD2 ;unimplemented routine to print D2 to the screen as a decimal number.
D2_Wasnt_A_Divisor:
MOVE.L D0,D1 ;restore D1.
ADDQ.L #1,D2 ;increment D2
CMP.L D2,D1 ;is D2 now greater than D1?
BLS computeFactors ;if not, loop again
;end of program |
http://rosettacode.org/wiki/Fast_Fourier_transform | Fast Fourier transform | Task
Calculate the FFT (Fast Fourier Transform) of an input sequence.
The most general case allows for complex numbers at the input
and results in a sequence of equal length, again of complex numbers.
If you need to restrict yourself to real numbers, the output should
be the magnitude (i.e.: sqrt(re2 + im2)) of the complex result.
The classic version is the recursive Cooley–Tukey FFT. Wikipedia has pseudo-code for that.
Further optimizations are possible but not required.
| #C.23 | C# | using System;
using System.Numerics;
using System.Linq;
using System.Diagnostics;
// Fast Fourier Transform in C#
public class Program {
/* Performs a Bit Reversal Algorithm on a postive integer
* for given number of bits
* e.g. 011 with 3 bits is reversed to 110 */
public static int BitReverse(int n, int bits) {
int reversedN = n;
int count = bits - 1;
n >>= 1;
while (n > 0) {
reversedN = (reversedN << 1) | (n & 1);
count--;
n >>= 1;
}
return ((reversedN << count) & ((1 << bits) - 1));
}
/* Uses Cooley-Tukey iterative in-place algorithm with radix-2 DIT case
* assumes no of points provided are a power of 2 */
public static void FFT(Complex[] buffer) {
#if false
int bits = (int)Math.Log(buffer.Length, 2);
for (int j = 1; j < buffer.Length / 2; j++) {
int swapPos = BitReverse(j, bits);
var temp = buffer[j];
buffer[j] = buffer[swapPos];
buffer[swapPos] = temp;
}
// Said Zandian
// The above section of the code is incorrect and does not work correctly and has two bugs.
// BUG 1
// The bug is that when you reach and index that was swapped previously it does swap it again
// Ex. binary value n = 0010 and Bits = 4 as input to BitReverse routine and returns 4. The code section above // swaps it. Cells 2 and 4 are swapped. just fine.
// now binary value n = 0010 and Bits = 4 as input to BitReverse routine and returns 2. The code Section
// swap it. Cells 4 and 2 are swapped. WROOOOONG
//
// Bug 2
// The code works on the half section of the cells. In the case of Bits = 4 it means that we are having 16 cells
// The code works on half the cells for (int j = 1; j < buffer.Length / 2; j++) buffer.Length returns 16
// and divide by 2 makes 8, so j goes from 1 to 7. This covers almost everything but what happened to 1011 value
// which must be swap with 1101. and this is the second bug.
//
// use the following corrected section of the code. I have seen this bug in other languages that uses bit
// reversal routine.
#else
for (int j = 1; j < buffer.Length; j++)
{
int swapPos = BitReverse(j, bits);
if (swapPos <= j)
{
continue;
}
var temp = buffer[j];
buffer[j] = buffer[swapPos];
buffer[swapPos] = temp;
}
// First the full length is used and 1011 value is swapped with 1101. Second if new swapPos is less than j
// then it means that swap was happen when j was the swapPos.
#endif
for (int N = 2; N <= buffer.Length; N <<= 1) {
for (int i = 0; i < buffer.Length; i += N) {
for (int k = 0; k < N / 2; k++) {
int evenIndex = i + k;
int oddIndex = i + k + (N / 2);
var even = buffer[evenIndex];
var odd = buffer[oddIndex];
double term = -2 * Math.PI * k / (double)N;
Complex exp = new Complex(Math.Cos(term), Math.Sin(term)) * odd;
buffer[evenIndex] = even + exp;
buffer[oddIndex] = even - exp;
}
}
}
}
public static void Main(string[] args) {
Complex[] input = {1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0};
FFT(input);
Console.WriteLine("Results:");
foreach (Complex c in input) {
Console.WriteLine(c);
}
}
} |
http://rosettacode.org/wiki/Factors_of_a_Mersenne_number | Factors of a Mersenne number | A Mersenne number is a number in the form of 2P-1.
If P is prime, the Mersenne number may be a Mersenne prime
(if P is not prime, the Mersenne number is also not prime).
In the search for Mersenne prime numbers it is advantageous to eliminate exponents by finding a small factor before starting a, potentially lengthy, Lucas-Lehmer test.
There are very efficient algorithms for determining if a number divides 2P-1 (or equivalently, if 2P mod (the number) = 1).
Some languages already have built-in implementations of this exponent-and-mod operation (called modPow or similar).
The following is how to implement this modPow yourself:
For example, let's compute 223 mod 47.
Convert the exponent 23 to binary, you get 10111. Starting with square = 1, repeatedly square it.
Remove the top bit of the exponent, and if it's 1 multiply square by the base of the exponentiation (2), then compute square modulo 47.
Use the result of the modulo from the last step as the initial value of square in the next step:
remove optional
square top bit multiply by 2 mod 47
──────────── ─────── ───────────── ──────
1*1 = 1 1 0111 1*2 = 2 2
2*2 = 4 0 111 no 4
4*4 = 16 1 11 16*2 = 32 32
32*32 = 1024 1 1 1024*2 = 2048 27
27*27 = 729 1 729*2 = 1458 1
Since 223 mod 47 = 1, 47 is a factor of 2P-1.
(To see this, subtract 1 from both sides: 223-1 = 0 mod 47.)
Since we've shown that 47 is a factor, 223-1 is not prime.
Further properties of Mersenne numbers allow us to refine the process even more.
Any factor q of 2P-1 must be of the form 2kP+1, k being a positive integer or zero. Furthermore, q must be 1 or 7 mod 8.
Finally any potential factor q must be prime.
As in other trial division algorithms, the algorithm stops when 2kP+1 > sqrt(N).
These primality tests only work on Mersenne numbers where P is prime. For example, M4=15 yields no factors using these techniques, but factors into 3 and 5, neither of which fit 2kP+1.
Task
Using the above method find a factor of 2929-1 (aka M929)
Related tasks
count in factors
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
See also
Computers in 1948: 2127 - 1
(Note: This video is no longer available because the YouTube account associated with this video has been terminated.)
| #BBC_BASIC | BBC BASIC | PRINT "A factor of M929 is "; FNmersenne_factor(929)
PRINT "A factor of M937 is "; FNmersenne_factor(937)
END
DEF FNmersenne_factor(P%)
LOCAL K%, Q%
IF NOT FNisprime(P%) THEN = -1
FOR K% = 1 TO 1000000
Q% = 2*K%*P% + 1
IF (Q% AND 7) = 1 OR (Q% AND 7) = 7 THEN
IF FNisprime(Q%) IF FNmodpow(2, P%, Q%) = 1 THEN = Q%
ENDIF
NEXT K%
= 0
DEF FNisprime(N%)
LOCAL D%
IF N% MOD 2=0 THEN = (N% = 2)
IF N% MOD 3=0 THEN = (N% = 3)
D% = 5
WHILE D% * D% <= N%
IF N% MOD D% = 0 THEN = FALSE
D% += 2
IF N% MOD D% = 0 THEN = FALSE
D% += 4
ENDWHILE
= TRUE
DEF FNmodpow(X%, N%, M%)
LOCAL I%, Y%, Z%
I% = N% : Y% = 1 : Z% = X%
WHILE I%
IF I% AND 1 THEN Y% = (Y% * Z%) MOD M%
Z% = (Z% * Z%) MOD M%
I% = I% >>> 1
ENDWHILE
= Y%
|
http://rosettacode.org/wiki/Factors_of_a_Mersenne_number | Factors of a Mersenne number | A Mersenne number is a number in the form of 2P-1.
If P is prime, the Mersenne number may be a Mersenne prime
(if P is not prime, the Mersenne number is also not prime).
In the search for Mersenne prime numbers it is advantageous to eliminate exponents by finding a small factor before starting a, potentially lengthy, Lucas-Lehmer test.
There are very efficient algorithms for determining if a number divides 2P-1 (or equivalently, if 2P mod (the number) = 1).
Some languages already have built-in implementations of this exponent-and-mod operation (called modPow or similar).
The following is how to implement this modPow yourself:
For example, let's compute 223 mod 47.
Convert the exponent 23 to binary, you get 10111. Starting with square = 1, repeatedly square it.
Remove the top bit of the exponent, and if it's 1 multiply square by the base of the exponentiation (2), then compute square modulo 47.
Use the result of the modulo from the last step as the initial value of square in the next step:
remove optional
square top bit multiply by 2 mod 47
──────────── ─────── ───────────── ──────
1*1 = 1 1 0111 1*2 = 2 2
2*2 = 4 0 111 no 4
4*4 = 16 1 11 16*2 = 32 32
32*32 = 1024 1 1 1024*2 = 2048 27
27*27 = 729 1 729*2 = 1458 1
Since 223 mod 47 = 1, 47 is a factor of 2P-1.
(To see this, subtract 1 from both sides: 223-1 = 0 mod 47.)
Since we've shown that 47 is a factor, 223-1 is not prime.
Further properties of Mersenne numbers allow us to refine the process even more.
Any factor q of 2P-1 must be of the form 2kP+1, k being a positive integer or zero. Furthermore, q must be 1 or 7 mod 8.
Finally any potential factor q must be prime.
As in other trial division algorithms, the algorithm stops when 2kP+1 > sqrt(N).
These primality tests only work on Mersenne numbers where P is prime. For example, M4=15 yields no factors using these techniques, but factors into 3 and 5, neither of which fit 2kP+1.
Task
Using the above method find a factor of 2929-1 (aka M929)
Related tasks
count in factors
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
See also
Computers in 1948: 2127 - 1
(Note: This video is no longer available because the YouTube account associated with this video has been terminated.)
| #Bracmat | Bracmat | ( ( modPow
= square P divisor highbit log 2pow
. !arg:(?P.?divisor)
& 1:?square
& 2\L!P:#%?log+?
& 2^!log:?2pow
& whl
' ( mod
$ ( ( div$(!P.!2pow):1&2
| 1
)
* !square^2
. !divisor
)
: ?square
& mod$(!P.!2pow):?P
& 1/2*!2pow:~/:?2pow
)
& !square
)
& ( isPrime
= incs nextincs primeCandidate nextPrimeCandidate quotient
. 1 1 2 2 (4 2 4 2 4 6 2 6:?incs)
: ?nextincs
& 1:?primeCandidate
& ( nextPrimeCandidate
= ( !nextincs:&!incs:?nextincs
|
)
& !nextincs:%?inc ?nextincs
& !inc+!primeCandidate:?primeCandidate
)
& whl
' ( (!nextPrimeCandidate:?divisor)^2:~>!arg
& !arg*!divisor^-1:?quotient:/
)
& !quotient:/
)
& ( Factors-of-a-Mersenne-Number
= P k candidate bignum
. !arg:?P
& 2^!P+-1:?bignum
& 0:?k
& whl
' ( 2*(1+!k:?k)*!P+1:?candidate
& !candidate^2:~>!bignum
& ( ~(mod$(!candidate.8):(1|7))
| ~(isPrime$!candidate)
| modPow$(!P.!candidate):?mp:~1
)
)
& !mp:1
& (!candidate.(2^!P+-1)*!candidate^-1)
)
& ( Factors-of-a-Mersenne-Number$929:(?divisorA.?divisorB)
& out
$ ( str
$ ("found some divisors of 2^" !P "-1 : " !divisorA " and " !divisorB)
)
| out$"no divisors found"
)
); |
http://rosettacode.org/wiki/Farey_sequence | Farey sequence | The Farey sequence Fn of order n is the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to n, arranged in order of increasing size.
The Farey sequence is sometimes incorrectly called a Farey series.
Each Farey sequence:
starts with the value 0 (zero), denoted by the fraction
0
1
{\displaystyle {\frac {0}{1}}}
ends with the value 1 (unity), denoted by the fraction
1
1
{\displaystyle {\frac {1}{1}}}
.
The Farey sequences of orders 1 to 5 are:
F
1
=
0
1
,
1
1
{\displaystyle {\bf {\it {F}}}_{1}={\frac {0}{1}},{\frac {1}{1}}}
F
2
=
0
1
,
1
2
,
1
1
{\displaystyle {\bf {\it {F}}}_{2}={\frac {0}{1}},{\frac {1}{2}},{\frac {1}{1}}}
F
3
=
0
1
,
1
3
,
1
2
,
2
3
,
1
1
{\displaystyle {\bf {\it {F}}}_{3}={\frac {0}{1}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {1}{1}}}
F
4
=
0
1
,
1
4
,
1
3
,
1
2
,
2
3
,
3
4
,
1
1
{\displaystyle {\bf {\it {F}}}_{4}={\frac {0}{1}},{\frac {1}{4}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {3}{4}},{\frac {1}{1}}}
F
5
=
0
1
,
1
5
,
1
4
,
1
3
,
2
5
,
1
2
,
3
5
,
2
3
,
3
4
,
4
5
,
1
1
{\displaystyle {\bf {\it {F}}}_{5}={\frac {0}{1}},{\frac {1}{5}},{\frac {1}{4}},{\frac {1}{3}},{\frac {2}{5}},{\frac {1}{2}},{\frac {3}{5}},{\frac {2}{3}},{\frac {3}{4}},{\frac {4}{5}},{\frac {1}{1}}}
Task
Compute and show the Farey sequence for orders 1 through 11 (inclusive).
Compute and display the number of fractions in the Farey sequence for order 100 through 1,000 (inclusive) by hundreds.
Show the fractions as n/d (using the solidus [or slash] to separate the numerator from the denominator).
The length (the number of fractions) of a Farey sequence asymptotically approaches:
3 × n2 ÷
π
{\displaystyle \pi }
2
See also
OEIS sequence A006842 numerators of Farey series of order 1, 2, ···
OEIS sequence A006843 denominators of Farey series of order 1, 2, ···
OEIS sequence A005728 number of fractions in Farey series of order n
MathWorld entry Farey sequence
Wikipedia entry Farey sequence
| #D | D | import std.stdio, std.algorithm, std.range, arithmetic_rational;
auto farey(in int n) pure nothrow @safe {
return rational(0, 1).only.chain(
iota(1, n + 1)
.map!(k => iota(1, k + 1).map!(m => rational(m, k)))
.join.sort().uniq);
}
void main() @safe {
writefln("Farey sequence for order 1 through 11:\n%(%s\n%)",
iota(1, 12).map!farey);
writeln("\nFarey sequence fractions, 100 to 1000 by hundreds:\n",
iota(100, 1_001, 100).map!(i => i.farey.walkLength));
} |
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #J | J | fairshare=: [ | [: +/"1 #.inv
2 3 5 11 fairshare"0 1/i.25
0 1 1 0 1 0 0 1 1 0 0 1 0 1 1 0 1 0 0 1 0 1 1 0 0
0 1 2 1 2 0 2 0 1 1 2 0 2 0 1 0 1 2 2 0 1 0 1 2 1
0 1 2 3 4 1 2 3 4 0 2 3 4 0 1 3 4 0 1 2 4 0 1 2 3
0 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 0 2 3 4
NB. In the 1st 50000 how many turns does each get? answered:
<@({.,#)/.~"1 ] 2 3 5 11 fairshare"0 1/i.50000
+-------+-------+-------+-------+-------+------+------+------+------+------+-------+
|0 25000|1 25000| | | | | | | | | |
+-------+-------+-------+-------+-------+------+------+------+------+------+-------+
|0 16667|1 16667|2 16666| | | | | | | | |
+-------+-------+-------+-------+-------+------+------+------+------+------+-------+
|0 10000|1 10000|2 10000|3 10000|4 10000| | | | | | |
+-------+-------+-------+-------+-------+------+------+------+------+------+-------+
|0 4545 |1 4545 |2 4545 |3 4545 |4 4546 |5 4546|6 4546|7 4546|8 4546|9 4545|10 4545|
+-------+-------+-------+-------+-------+------+------+------+------+------+-------+
|
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #Java | Java |
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class FairshareBetweenTwoAndMore {
public static void main(String[] args) {
for ( int base : Arrays.asList(2, 3, 5, 11) ) {
System.out.printf("Base %d = %s%n", base, thueMorseSequence(25, base));
}
}
private static List<Integer> thueMorseSequence(int terms, int base) {
List<Integer> sequence = new ArrayList<Integer>();
for ( int i = 0 ; i < terms ; i++ ) {
int sum = 0;
int n = i;
while ( n > 0 ) {
// Compute the digit sum
sum += n % base;
n /= base;
}
// Compute the digit sum module base.
sequence.add(sum % base);
}
return sequence;
}
}
|
http://rosettacode.org/wiki/Faulhaber%27s_triangle | Faulhaber's triangle | Named after Johann Faulhaber, the rows of Faulhaber's triangle are the coefficients of polynomials that represent sums of integer powers, which are extracted from Faulhaber's formula:
∑
k
=
1
n
k
p
=
1
p
+
1
∑
j
=
0
p
(
p
+
1
j
)
B
j
n
p
+
1
−
j
{\displaystyle \sum _{k=1}^{n}k^{p}={1 \over p+1}\sum _{j=0}^{p}{p+1 \choose j}B_{j}n^{p+1-j}}
where
B
n
{\displaystyle B_{n}}
is the nth-Bernoulli number.
The first 5 rows of Faulhaber's triangle, are:
1
1/2 1/2
1/6 1/2 1/3
0 1/4 1/2 1/4
-1/30 0 1/3 1/2 1/5
Using the third row of the triangle, we have:
∑
k
=
1
n
k
2
=
1
6
n
+
1
2
n
2
+
1
3
n
3
{\displaystyle \sum _{k=1}^{n}k^{2}={1 \over 6}n+{1 \over 2}n^{2}+{1 \over 3}n^{3}}
Task
show the first 10 rows of Faulhaber's triangle.
using the 18th row of Faulhaber's triangle, compute the sum:
∑
k
=
1
1000
k
17
{\displaystyle \sum _{k=1}^{1000}k^{17}}
(extra credit).
See also
Bernoulli numbers
Evaluate binomial coefficients
Faulhaber's formula (Wikipedia)
Faulhaber's triangle (PDF)
| #J | J | faulhaberTriangle=: ([: %. [: x: (1 _2 (p.) 2 | +/~) * >:/~ * (!~/~ >:))@:i.
faulhaberTriangle 10
1 0 0 0 0 0 0 0 0 0
1r2 1r2 0 0 0 0 0 0 0 0
1r6 1r2 1r3 0 0 0 0 0 0 0
0 1r4 1r2 1r4 0 0 0 0 0 0
_1r30 0 1r3 1r2 1r5 0 0 0 0 0
0 _1r12 0 5r12 1r2 1r6 0 0 0 0
1r42 0 _1r6 0 1r2 1r2 1r7 0 0 0
0 1r12 0 _7r24 0 7r12 1r2 1r8 0 0
_1r30 0 2r9 0 _7r15 0 2r3 1r2 1r9 0
0 _3r20 0 1r2 0 _7r10 0 3r4 1r2 1r10
NB.--------------------------------------------------------------
NB. matrix inverse (%.) of the extended precision (x:) product of
(!~/~ >:)@:i. 5 NB. Pascal's triangle
1 1 0 0 0
1 2 1 0 0
1 3 3 1 0
1 4 6 4 1
1 5 10 10 5
NB. second task in progress
(>:/~)@: i. 5 NB. lower triangle
1 0 0 0 0
1 1 0 0 0
1 1 1 0 0
1 1 1 1 0
1 1 1 1 1
(1 _2 p. (2 | +/~))@:i. 5 NB. 1 + (-2) * (parity table)
1 _1 1 _1 1
_1 1 _1 1 _1
1 _1 1 _1 1
_1 1 _1 1 _1
1 _1 1 _1 1
|
http://rosettacode.org/wiki/Faulhaber%27s_formula | Faulhaber's formula | In mathematics, Faulhaber's formula, named after Johann Faulhaber, expresses the sum of the p-th powers of the first n positive integers as a (p + 1)th-degree polynomial function of n, the coefficients involving Bernoulli numbers.
Task
Generate the first 10 closed-form expressions, starting with p = 0.
Related tasks
Bernoulli numbers.
evaluate binomial coefficients.
See also
The Wikipedia entry: Faulhaber's formula.
The Wikipedia entry: Bernoulli numbers.
The Wikipedia entry: binomial coefficients.
| #Java | Java | import java.util.Arrays;
import java.util.stream.IntStream;
public class FaulhabersFormula {
private static long gcd(long a, long b) {
if (b == 0) {
return a;
}
return gcd(b, a % b);
}
private static class Frac implements Comparable<Frac> {
private long num;
private long denom;
public static final Frac ZERO = new Frac(0, 1);
public static final Frac ONE = new Frac(1, 1);
public Frac(long n, long d) {
if (d == 0) throw new IllegalArgumentException("d must not be zero");
long nn = n;
long dd = d;
if (nn == 0) {
dd = 1;
} else if (dd < 0) {
nn = -nn;
dd = -dd;
}
long g = Math.abs(gcd(nn, dd));
if (g > 1) {
nn /= g;
dd /= g;
}
num = nn;
denom = dd;
}
public Frac plus(Frac rhs) {
return new Frac(num * rhs.denom + denom * rhs.num, rhs.denom * denom);
}
public Frac unaryMinus() {
return new Frac(-num, denom);
}
public Frac minus(Frac rhs) {
return this.plus(rhs.unaryMinus());
}
public Frac times(Frac rhs) {
return new Frac(this.num * rhs.num, this.denom * rhs.denom);
}
@Override
public int compareTo(Frac o) {
double diff = toDouble() - o.toDouble();
return Double.compare(diff, 0.0);
}
@Override
public boolean equals(Object obj) {
return null != obj && obj instanceof Frac && this.compareTo((Frac) obj) == 0;
}
@Override
public String toString() {
if (denom == 1) {
return Long.toString(num);
}
return String.format("%d/%d", num, denom);
}
private double toDouble() {
return (double) num / denom;
}
}
private static Frac bernoulli(int n) {
if (n < 0) throw new IllegalArgumentException("n may not be negative or zero");
Frac[] a = new Frac[n + 1];
Arrays.fill(a, Frac.ZERO);
for (int m = 0; m <= n; ++m) {
a[m] = new Frac(1, m + 1);
for (int j = m; j >= 1; --j) {
a[j - 1] = a[j - 1].minus(a[j]).times(new Frac(j, 1));
}
}
// returns 'first' Bernoulli number
if (n != 1) return a[0];
return a[0].unaryMinus();
}
private static int binomial(int n, int k) {
if (n < 0 || k < 0 || n < k) throw new IllegalArgumentException();
if (n == 0 || k == 0) return 1;
int num = IntStream.rangeClosed(k + 1, n).reduce(1, (a, b) -> a * b);
int den = IntStream.rangeClosed(2, n - k).reduce(1, (acc, i) -> acc * i);
return num / den;
}
private static void faulhaber(int p) {
System.out.printf("%d : ", p);
Frac q = new Frac(1, p + 1);
int sign = -1;
for (int j = 0; j <= p; ++j) {
sign *= -1;
Frac coeff = q.times(new Frac(sign, 1)).times(new Frac(binomial(p + 1, j), 1)).times(bernoulli(j));
if (Frac.ZERO.equals(coeff)) continue;
if (j == 0) {
if (!Frac.ONE.equals(coeff)) {
if (Frac.ONE.unaryMinus().equals(coeff)) {
System.out.print("-");
} else {
System.out.print(coeff);
}
}
} else {
if (Frac.ONE.equals(coeff)) {
System.out.print(" + ");
} else if (Frac.ONE.unaryMinus().equals(coeff)) {
System.out.print(" - ");
} else if (coeff.compareTo(Frac.ZERO) > 0) {
System.out.printf(" + %s", coeff);
} else {
System.out.printf(" - %s", coeff.unaryMinus());
}
}
int pwr = p + 1 - j;
if (pwr > 1)
System.out.printf("n^%d", pwr);
else
System.out.print("n");
}
System.out.println();
}
public static void main(String[] args) {
for (int i = 0; i <= 9; ++i) {
faulhaber(i);
}
}
} |
http://rosettacode.org/wiki/Fermat_numbers | Fermat numbers | In mathematics, a Fermat number, named after Pierre de Fermat who first studied them, is a positive integer of the form Fn = 22n + 1 where n is a non-negative integer.
Despite the simplicity of generating Fermat numbers, they have some powerful mathematical properties and are extensively used in cryptography & pseudo-random number generation, and are often linked to other number theoric fields.
As of this writing, (mid 2019), there are only five known prime Fermat numbers, the first five (F0 through F4). Only the first twelve Fermat numbers have been completely factored, though many have been partially factored.
Task
Write a routine (function, procedure, whatever) to generate Fermat numbers.
Use the routine to find and display here, on this page, the first 10 Fermat numbers - F0 through F9.
Find and display here, on this page, the prime factors of as many Fermat numbers as you have patience for. (Or as many as can be found in five minutes or less of processing time). Note: if you make it past F11, there may be money, and certainly will be acclaim in it for you.
See also
Wikipedia - Fermat numbers
OEIS:A000215 - Fermat numbers
OEIS:A019434 - Fermat primes
| #zkl | zkl | fermatsW:=[0..].tweak(fcn(n){ BI(2).pow(BI(2).pow(n)) + 1 });
println("First 10 Fermat numbers:");
foreach n in (10){ println("F",n,": ",fermatsW.next()) } |
http://rosettacode.org/wiki/Fibonacci_n-step_number_sequences | Fibonacci n-step number sequences | These number series are an expansion of the ordinary Fibonacci sequence where:
For
n
=
2
{\displaystyle n=2}
we have the Fibonacci sequence; with initial values
[
1
,
1
]
{\displaystyle [1,1]}
and
F
k
2
=
F
k
−
1
2
+
F
k
−
2
2
{\displaystyle F_{k}^{2}=F_{k-1}^{2}+F_{k-2}^{2}}
For
n
=
3
{\displaystyle n=3}
we have the tribonacci sequence; with initial values
[
1
,
1
,
2
]
{\displaystyle [1,1,2]}
and
F
k
3
=
F
k
−
1
3
+
F
k
−
2
3
+
F
k
−
3
3
{\displaystyle F_{k}^{3}=F_{k-1}^{3}+F_{k-2}^{3}+F_{k-3}^{3}}
For
n
=
4
{\displaystyle n=4}
we have the tetranacci sequence; with initial values
[
1
,
1
,
2
,
4
]
{\displaystyle [1,1,2,4]}
and
F
k
4
=
F
k
−
1
4
+
F
k
−
2
4
+
F
k
−
3
4
+
F
k
−
4
4
{\displaystyle F_{k}^{4}=F_{k-1}^{4}+F_{k-2}^{4}+F_{k-3}^{4}+F_{k-4}^{4}}
...
For general
n
>
2
{\displaystyle n>2}
we have the Fibonacci
n
{\displaystyle n}
-step sequence -
F
k
n
{\displaystyle F_{k}^{n}}
; with initial values of the first
n
{\displaystyle n}
values of the
(
n
−
1
)
{\displaystyle (n-1)}
'th Fibonacci
n
{\displaystyle n}
-step sequence
F
k
n
−
1
{\displaystyle F_{k}^{n-1}}
; and
k
{\displaystyle k}
'th value of this
n
{\displaystyle n}
'th sequence being
F
k
n
=
∑
i
=
1
(
n
)
F
k
−
i
(
n
)
{\displaystyle F_{k}^{n}=\sum _{i=1}^{(n)}{F_{k-i}^{(n)}}}
For small values of
n
{\displaystyle n}
, Greek numeric prefixes are sometimes used to individually name each series.
Fibonacci
n
{\displaystyle n}
-step sequences
n
{\displaystyle n}
Series name
Values
2
fibonacci
1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 ...
3
tribonacci
1 1 2 4 7 13 24 44 81 149 274 504 927 1705 3136 ...
4
tetranacci
1 1 2 4 8 15 29 56 108 208 401 773 1490 2872 5536 ...
5
pentanacci
1 1 2 4 8 16 31 61 120 236 464 912 1793 3525 6930 ...
6
hexanacci
1 1 2 4 8 16 32 63 125 248 492 976 1936 3840 7617 ...
7
heptanacci
1 1 2 4 8 16 32 64 127 253 504 1004 2000 3984 7936 ...
8
octonacci
1 1 2 4 8 16 32 64 128 255 509 1016 2028 4048 8080 ...
9
nonanacci
1 1 2 4 8 16 32 64 128 256 511 1021 2040 4076 8144 ...
10
decanacci
1 1 2 4 8 16 32 64 128 256 512 1023 2045 4088 8172 ...
Allied sequences can be generated where the initial values are changed:
The Lucas series sums the two preceding values like the fibonacci series for
n
=
2
{\displaystyle n=2}
but uses
[
2
,
1
]
{\displaystyle [2,1]}
as its initial values.
Task
Write a function to generate Fibonacci
n
{\displaystyle n}
-step number sequences given its initial values and assuming the number of initial values determines how many previous values are summed to make the next number of the series.
Use this to print and show here at least the first ten members of the Fibo/tribo/tetra-nacci and Lucas sequences.
Related tasks
Fibonacci sequence
Wolfram Mathworld
Hofstadter Q sequence
Leonardo numbers
Also see
Lucas Numbers - Numberphile (Video)
Tribonacci Numbers (and the Rauzy Fractal) - Numberphile (Video)
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #C.23 | C# | using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Fibonacci
{
class Program
{
static void Main(string[] args)
{
PrintNumberSequence("Fibonacci", GetNnacciNumbers(2, 10));
PrintNumberSequence("Lucas", GetLucasNumbers(10));
PrintNumberSequence("Tribonacci", GetNnacciNumbers(3, 10));
PrintNumberSequence("Tetranacci", GetNnacciNumbers(4, 10));
Console.ReadKey();
}
private static IList<ulong> GetLucasNumbers(int length)
{
IList<ulong> seedSequence = new List<ulong>() { 2, 1 };
return GetFibLikeSequence(seedSequence, length);
}
private static IList<ulong> GetNnacciNumbers(int seedLength, int length)
{
return GetFibLikeSequence(GetNacciSeed(seedLength), length);
}
private static IList<ulong> GetNacciSeed(int seedLength)
{
IList<ulong> seedSquence = new List<ulong>() { 1 };
for (uint i = 0; i < seedLength - 1; i++)
{
seedSquence.Add((ulong)Math.Pow(2, i));
}
return seedSquence;
}
private static IList<ulong> GetFibLikeSequence(IList<ulong> seedSequence, int length)
{
IList<ulong> sequence = new List<ulong>();
int count = seedSequence.Count();
if (length <= count)
{
sequence = seedSequence.Take((int)length).ToList();
}
else
{
sequence = seedSequence;
for (int i = count; i < length; i++)
{
ulong num = 0;
for (int j = 0; j < count; j++)
{
num += sequence[sequence.Count - 1 - j];
}
sequence.Add(num);
}
}
return sequence;
}
private static void PrintNumberSequence(string Title, IList<ulong> numbersequence)
{
StringBuilder output = new StringBuilder(Title).Append(" ");
foreach (long item in numbersequence)
{
output.AppendFormat("{0}, ", item);
}
Console.WriteLine(output.ToString());
}
}
} |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #TUSCRIPT | TUSCRIPT |
$$ MODE TUSCRIPT
file="rosetta.txt"
ERROR/STOP OPEN (file,READ,-std-)
modified=MODIFIED (file)
PRINT "file ",file," last modified: ",modified
|
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #UNIX_Shell | UNIX Shell | T=`stat -c %Y $F` |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #Ursa | Ursa | decl java.util.Date d
decl file f
f.open "example.txt"
d.setTime (f.lastmodified)
out d endl console
f.setlastmodified 10 |
http://rosettacode.org/wiki/Fibonacci_word/fractal | Fibonacci word/fractal |
The Fibonacci word may be represented as a fractal as described here:
(Clicking on the above website (hal.archives-ouvertes.fr) will leave a cookie.)
For F_wordm start with F_wordCharn=1
Draw a segment forward
If current F_wordChar is 0
Turn left if n is even
Turn right if n is odd
next n and iterate until end of F_word
Task
Create and display a fractal similar to Fig 1.
(Clicking on the above website (hal.archives-ouvertes.fr) will leave a cookie.)
| #Wren | Wren | import "graphics" for Canvas, Color
import "dome" for Window
class FibonacciWordFractal {
construct new(width, height, n) {
Window.title = "Fibonacci Word Fractal"
Window.resize(width, height)
Canvas.resize(width, height)
_fore = Color.green
_wordFractal = wordFractal(n)
}
init() {
drawWordFractal(20, 20, 1, 0)
}
wordFractal(i) {
if (i < 2) return (i == 1) ? "1" : ""
var f1 = "1"
var f2 = "0"
for (j in i-2...0) {
var tmp = f2
f2 = f2 + f1
f1 = tmp
}
return f2
}
drawWordFractal(x, y, dx, dy) {
for (i in 0..._wordFractal.count) {
Canvas.line(x, y, x + dx, y + dy, _fore)
x = x + dx
y = y + dy
if (_wordFractal[i] == "0") {
var tx = dx
dx = (i % 2 == 0) ? -dy : dy
dy = (i % 2 == 0) ? tx : - tx
}
}
}
update() {}
draw(alpha) {}
}
var Game = FibonacciWordFractal.new(450, 620, 23) |
http://rosettacode.org/wiki/Find_common_directory_path | Find common directory path | Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test'
'/home/user1/tmp/covert/operator'
'/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory '/home/user1/tmp' and not the longest common string '/home/user1/tmp/cove'.
If your language has a routine that performs this function (even if it does not have a changeable separator character), then mention it as part of the task.
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Picat | Picat | find_common_directory_path(Dirs) = Path =>
maxof( (common_prefix(Dirs, Path,Len), append(_,"/",Path)), Len).
%
% Find a common prefix of all lists/strings in Ls.
% Using append/3.
%
common_prefix(Ls, Prefix,Len) =>
foreach(L in Ls)
append(Prefix,_,L)
end,
Len = Prefix.length. |
http://rosettacode.org/wiki/Find_common_directory_path | Find common directory path | Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test'
'/home/user1/tmp/covert/operator'
'/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory '/home/user1/tmp' and not the longest common string '/home/user1/tmp/cove'.
If your language has a routine that performs this function (even if it does not have a changeable separator character), then mention it as part of the task.
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #PicoLisp | PicoLisp | (de commonPath (Lst Chr)
(glue Chr
(make
(apply find
(mapcar '((L) (split (chop L) Chr)) Lst)
'(@ (or (pass <>) (nil (link (next))))) ) ) ) ) |
http://rosettacode.org/wiki/Filter | Filter | Task
Select certain elements from an Array into a new Array in a generic way.
To demonstrate, select all even numbers from an Array.
As an option, give a second solution which filters destructively,
by modifying the original Array rather than creating a new Array.
| #E | E | pragma.enable("accumulator")
accum [] for x ? (x %% 2 <=> 0) in [1,2,3,4,5,6,7,8,9,10] { _.with(x) } |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #Rust | Rust | fn recurse(n: i32) {
println!("depth: {}", n);
recurse(n + 1)
}
fn main() {
recurse(0);
} |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #Sather | Sather | class MAIN is
attr r:INT;
recurse is
r := r + 1;
#OUT + r + "\n";
recurse;
end;
main is
r := 0;
recurse;
end;
end; |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #Scala | Scala | def recurseTest(i:Int):Unit={
try{
recurseTest(i+1)
} catch { case e:java.lang.StackOverflowError =>
println("Recursion depth on this system is " + i + ".")
}
}
recurseTest(0) |
http://rosettacode.org/wiki/FizzBuzz | FizzBuzz | Task
Write a program that prints the integers from 1 to 100 (inclusive).
But:
for multiples of three, print Fizz (instead of the number)
for multiples of five, print Buzz (instead of the number)
for multiples of both three and five, print FizzBuzz (instead of the number)
The FizzBuzz problem was presented as the lowest level of comprehension required to illustrate adequacy.
Also see
(a blog) dont-overthink-fizzbuzz
(a blog) fizzbuzz-the-programmers-stairway-to-heaven
| #Haskell | Haskell | fizzbuzz :: Int -> String
fizzbuzz x
| f 15 = "FizzBuzz"
| f 3 = "Fizz"
| f 5 = "Buzz"
| otherwise = show x
where
f = (0 ==) . rem x
main :: IO ()
main = mapM_ (putStrLn . fizzbuzz) [1 .. 100] |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #PHP | PHP | <?php
echo filesize('input.txt'), "\n";
echo filesize('/input.txt'), "\n";
?> |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #PicoLisp | PicoLisp | (println (car (info "input.txt")))
(println (car (info "/input.txt"))) |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #Pike | Pike | import Stdio;
int main(){
write(file_size("input.txt") + "\n");
write(file_size("/input.txt") + "\n");
} |
http://rosettacode.org/wiki/File_input/output | File input/output | File input/output is part of Short Circuit's Console Program Basics selection.
Task
Create a file called "output.txt", and place in it the contents of the file "input.txt", via an intermediate variable.
In other words, your program will demonstrate:
how to read from a file into a variable
how to write a variable's contents into a file
Oneliners that skip the intermediate variable are of secondary interest — operating systems have copy commands for that.
| #GUISS | GUISS | Start,My Documents,Rightclick:input.txt,Copy,Menu,Edit,Paste,
Rightclick:Copy of input.txt,Rename,Type:output.txt[enter] |
http://rosettacode.org/wiki/File_input/output | File input/output | File input/output is part of Short Circuit's Console Program Basics selection.
Task
Create a file called "output.txt", and place in it the contents of the file "input.txt", via an intermediate variable.
In other words, your program will demonstrate:
how to read from a file into a variable
how to write a variable's contents into a file
Oneliners that skip the intermediate variable are of secondary interest — operating systems have copy commands for that.
| #Haskell | Haskell | main = readFile "input.txt" >>= writeFile "output.txt" |
http://rosettacode.org/wiki/Fibonacci_word | Fibonacci word | The Fibonacci Word may be created in a manner analogous to the Fibonacci Sequence as described here:
Define F_Word1 as 1
Define F_Word2 as 0
Form F_Word3 as F_Word2 concatenated with F_Word1 i.e.: 01
Form F_Wordn as F_Wordn-1 concatenated with F_wordn-2
Task
Perform the above steps for n = 37.
You may display the first few but not the larger values of n.
{Doing so will get the task's author into trouble with them what be (again!).}
Instead, create a table for F_Words 1 to 37 which shows:
The number of characters in the word
The word's Entropy
Related tasks
Fibonacci word/fractal
Entropy
Entropy/Narcissist
| #Kotlin | Kotlin | // version 1.0.6
fun fibWord(n: Int): String {
if (n < 1) throw IllegalArgumentException("Argument can't be less than 1")
if (n == 1) return "1"
val words = Array(n){ "" }
words[0] = "1"
words[1] = "0"
for (i in 2 until n) words[i] = words[i - 1] + words[i - 2]
return words[n - 1]
}
fun log2(d: Double) = Math.log(d) / Math.log(2.0)
fun shannon(s: String): Double {
if (s.length <= 1) return 0.0
val count0 = s.count { it == '0' }
val count1 = s.length - count0
val nn = s.length.toDouble()
return -(count0 / nn * log2(count0 / nn) + count1 / nn * log2(count1 / nn))
}
fun main(args: Array<String>) {
println("N Length Entropy Word")
println("-- -------- ------------------ ----------------------------------")
for (i in 1..37) {
val s = fibWord(i)
print(String.format("%2d %8d %18.16f", i, s.length, shannon(s)))
if (i < 10) println(" $s")
else println()
}
} |
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #OCaml | OCaml |
(* This program reads from the standard input and writes to standard output.
* Examples of use:
* $ ocaml fasta.ml < fasta_file.txt
* $ ocaml fasta.ml < fasta_file.txt > my_result.txt
*
* The FASTA file is assumed to have a specific format, where the first line
* contains a label in the form of '>blablabla', i.e. with a '>' as the first
* character.
*)
let labelstart = '>'
let is_label s = s.[0] = labelstart
let get_label s = String.sub s 1 (String.length s - 1)
let read_in channel = input_line channel |> String.trim
let print_fasta chan =
let rec doloop currlabel line =
if is_label line then begin
if currlabel <> "" then print_newline ();
let newlabel = get_label line in
print_string (newlabel ^ ": ");
doloop newlabel (read_in chan)
end
else begin
print_string line;
doloop currlabel (read_in chan)
end
in
try
match read_in chan with
| line when is_label line -> doloop "" line
| _ -> failwith "Badly formatted FASTA file?"
with
End_of_file -> print_newline ()
let () =
print_fasta stdin
|
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Pascal | Pascal |
program FASTA_Format;
// FPC 3.0.2
var InF,
OutF: Text;
ch: char;
First: Boolean=True;
InDef: Boolean=False;
begin
Assign(InF,'');
Reset(InF);
Assign(OutF,'');
Rewrite(OutF);
While Not Eof(InF) do
begin
Read(InF,ch);
Case Ch of
'>': begin
if Not(First) then
Write(OutF,#13#10)
else
First:=False;
InDef:=true;
end;
#13: Begin
if InDef then
begin
InDef:=false;
Write(OutF,': ');
end;
Ch:=#0;
end;
#10: ch:=#0;
else Write(OutF,Ch);
end;
end;
Close(OutF);
Close(InF);
end.
|
http://rosettacode.org/wiki/Fibonacci_sequence | Fibonacci sequence | The Fibonacci sequence is a sequence Fn of natural numbers defined recursively:
F0 = 0
F1 = 1
Fn = Fn-1 + Fn-2, if n>1
Task
Write a function to generate the nth Fibonacci number.
Solutions can be iterative or recursive (though recursive solutions are generally considered too slow and are mostly used as an exercise in recursion).
The sequence is sometimes extended into negative numbers by using a straightforward inverse of the positive definition:
Fn = Fn+2 - Fn+1, if n<0
support for negative n in the solution is optional.
Related tasks
Fibonacci n-step number sequences
Leonardo numbers
References
Wikipedia, Fibonacci number
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #360_Assembly | 360 Assembly | * Fibonacci sequence 05/11/2014
* integer (31 bits) = 10 decimals -> max fibo(46)
FIBONACC CSECT
USING FIBONACC,R12 base register
SAVEAREA B STM-SAVEAREA(R15) skip savearea
DC 17F'0' savearea
DC CL8'FIBONACC' eyecatcher
STM STM R14,R12,12(R13) save previous context
ST R13,4(R15) link backward
ST R15,8(R13) link forward
LR R12,R15 set addressability
* ----
LA R1,0 f(n-2)=0
LA R2,1 f(n-1)=1
LA R4,2 n=2
LA R6,1 step
LH R7,NN limit
LOOP EQU * for n=2 to nn
LR R3,R2 f(n)=f(n-1)
AR R3,R1 f(n)=f(n-1)+f(n-2)
CVD R4,PW n convert binary to packed (PL8)
UNPK ZW,PW packed (PL8) to zoned (ZL16)
MVC CW,ZW zoned (ZL16) to char (CL16)
OI CW+L'CW-1,X'F0' zap sign
MVC WTOBUF+5(2),CW+14 output
CVD R3,PW f(n) binary to packed decimal (PL8)
MVC ZN,EM load mask
ED ZN,PW packed dec (PL8) to char (CL20)
MVC WTOBUF+9(14),ZN+6 output
WTO MF=(E,WTOMSG) write buffer
LR R1,R2 f(n-2)=f(n-1)
LR R2,R3 f(n-1)=f(n)
BXLE R4,R6,LOOP endfor n
* ----
LM R14,R12,12(R13) restore previous savearea pointer
XR R15,R15 return code set to 0
BR R14 return to caller
* ---- DATA
NN DC H'46' nn max n
PW DS PL8 15num
ZW DS ZL16
CW DS CL16
ZN DS CL20
* ' b 0 0 0 , 0 0 0 , 0 0 0 , 0 0 0 , 0 0 0' 15num
EM DC XL20'402020206B2020206B2020206B2020206B202120' mask
WTOMSG DS 0F
DC H'80',XL2'0000'
* fibo(46)=1836311903
WTOBUF DC CL80'fibo(12)=1234567890'
REGEQU
END FIBONACC |
http://rosettacode.org/wiki/Factors_of_an_integer | Factors of an integer |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Compute the factors of a positive integer.
These factors are the positive integers by which the number being factored can be divided to yield a positive integer result.
(Though the concepts function correctly for zero and negative integers, the set of factors of zero has countably infinite members, and the factors of negative integers can be obtained from the factors of related positive numbers without difficulty; this task does not require handling of either of these cases).
Note that every prime number has two factors: 1 and itself.
Related tasks
count in factors
prime decomposition
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
sequence: smallest number greater than previous term with exactly n divisors
| #AArch64_Assembly | AArch64 Assembly |
/* ARM assembly AARCH64 Raspberry PI 3B */
/* program factorst64.s */
/*******************************************/
/* Constantes file */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"
.equ CHARPOS, '@'
/*******************************************/
/* Initialized data */
/*******************************************/
.data
szMessDeb: .ascii "Factors of : @ are : \n"
szMessFactor: .asciz "@ \n"
szCarriageReturn: .asciz "\n"
/*******************************************/
/* UnInitialized data */
/*******************************************/
.bss
sZoneConversion: .skip 100
/*******************************************/
/* code section */
/*******************************************/
.text
.global main
main: // entry of program
mov x0,#100
bl factors
mov x0,#97
bl factors
ldr x0,qNumber
bl factors
100: // standard end of the program
mov x0, #0 // return code
mov x8, #EXIT // request to exit program
svc 0 // perform the system call
qNumber: .quad 32767
qAdrszCarriageReturn: .quad szCarriageReturn
/******************************************************************/
/* calcul factors of number */
/******************************************************************/
/* x0 contains the number to factorize */
factors:
stp x1,lr,[sp,-16]! // save registers
stp x2,x3,[sp,-16]! // save registers
mov x5,x0 // limit calcul
ldr x1,qAdrsZoneConversion // conversion register in decimal string
bl conversion10S
ldr x0,qAdrszMessDeb // display message
ldr x1,qAdrsZoneConversion
bl strInsertAtChar
bl affichageMess
mov x6,#1 // counter loop
1: // loop
udiv x0,x5,x6 // division
msub x3,x0,x6,x5 // compute remainder
cbnz x3,2f // remainder not = zero -> loop
// display result if yes
mov x0,x6
ldr x1,qAdrsZoneConversion
bl conversion10S
ldr x0,qAdrszMessFactor // display message
ldr x1,qAdrsZoneConversion
bl strInsertAtChar
bl affichageMess
2:
add x6,x6,#1 // add 1 to loop counter
cmp x6,x5 // <= number ?
ble 1b // yes loop
100:
ldp x2,x3,[sp],16 // restaur 2 registers
ldp x1,lr,[sp],16 // restaur 2 registers
ret
qAdrszMessDeb: .quad szMessDeb
qAdrszMessFactor: .quad szMessFactor
qAdrsZoneConversion: .quad sZoneConversion
/******************************************************************/
/* insert string at character insertion */
/******************************************************************/
/* x0 contains the address of string 1 */
/* x1 contains the address of insertion string */
/* x0 return the address of new string on the heap */
/* or -1 if error */
strInsertAtChar:
stp x2,lr,[sp,-16]! // save registers
stp x3,x4,[sp,-16]! // save registers
stp x5,x6,[sp,-16]! // save registers
stp x7,x8,[sp,-16]! // save registers
mov x3,#0 // length counter
1: // compute length of string 1
ldrb w4,[x0,x3]
cmp w4,#0
cinc x3,x3,ne // increment to one if not equal
bne 1b // loop if not equal
mov x5,#0 // length counter insertion string
2: // compute length to insertion string
ldrb w4,[x1,x5]
cmp x4,#0
cinc x5,x5,ne // increment to one if not equal
bne 2b // and loop
cmp x5,#0
beq 99f // string empty -> error
add x3,x3,x5 // add 2 length
add x3,x3,#1 // +1 for final zero
mov x6,x0 // save address string 1
mov x0,#0 // allocation place heap
mov x8,BRK // call system 'brk'
svc #0
mov x5,x0 // save address heap for output string
add x0,x0,x3 // reservation place x3 length
mov x8,BRK // call system 'brk'
svc #0
cmp x0,#-1 // allocation error
beq 99f
mov x2,0
mov x4,0
3: // loop copy string begin
ldrb w3,[x6,x2]
cmp w3,0
beq 99f
cmp w3,CHARPOS // insertion character ?
beq 5f // yes
strb w3,[x5,x4] // no store character in output string
add x2,x2,1
add x4,x4,1
b 3b // and loop
5: // x4 contains position insertion
add x8,x4,1 // init index character output string
// at position insertion + one
mov x3,#0 // index load characters insertion string
6:
ldrb w0,[x1,x3] // load characters insertion string
cmp w0,#0 // end string ?
beq 7f // yes
strb w0,[x5,x4] // store in output string
add x3,x3,#1 // increment index
add x4,x4,#1 // increment output index
b 6b // and loop
7: // loop copy end string
ldrb w0,[x6,x8] // load other character string 1
strb w0,[x5,x4] // store in output string
cmp x0,#0 // end string 1 ?
beq 8f // yes -> end
add x4,x4,#1 // increment output index
add x8,x8,#1 // increment index
b 7b // and loop
8:
mov x0,x5 // return output string address
b 100f
99: // error
mov x0,#-1
100:
ldp x7,x8,[sp],16 // restaur 2 registers
ldp x5,x6,[sp],16 // restaur 2 registers
ldp x3,x4,[sp],16 // restaur 2 registers
ldp x2,lr,[sp],16 // restaur 2 registers
ret
/********************************************************/
/* File Include fonctions */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"
|
http://rosettacode.org/wiki/Fast_Fourier_transform | Fast Fourier transform | Task
Calculate the FFT (Fast Fourier Transform) of an input sequence.
The most general case allows for complex numbers at the input
and results in a sequence of equal length, again of complex numbers.
If you need to restrict yourself to real numbers, the output should
be the magnitude (i.e.: sqrt(re2 + im2)) of the complex result.
The classic version is the recursive Cooley–Tukey FFT. Wikipedia has pseudo-code for that.
Further optimizations are possible but not required.
| #C.2B.2B | C++ | #include <complex>
#include <iostream>
#include <valarray>
const double PI = 3.141592653589793238460;
typedef std::complex<double> Complex;
typedef std::valarray<Complex> CArray;
// Cooley–Tukey FFT (in-place, divide-and-conquer)
// Higher memory requirements and redundancy although more intuitive
void fft(CArray& x)
{
const size_t N = x.size();
if (N <= 1) return;
// divide
CArray even = x[std::slice(0, N/2, 2)];
CArray odd = x[std::slice(1, N/2, 2)];
// conquer
fft(even);
fft(odd);
// combine
for (size_t k = 0; k < N/2; ++k)
{
Complex t = std::polar(1.0, -2 * PI * k / N) * odd[k];
x[k ] = even[k] + t;
x[k+N/2] = even[k] - t;
}
}
// Cooley-Tukey FFT (in-place, breadth-first, decimation-in-frequency)
// Better optimized but less intuitive
// !!! Warning : in some cases this code make result different from not optimased version above (need to fix bug)
// The bug is now fixed @2017/05/30
void fft(CArray &x)
{
// DFT
unsigned int N = x.size(), k = N, n;
double thetaT = 3.14159265358979323846264338328L / N;
Complex phiT = Complex(cos(thetaT), -sin(thetaT)), T;
while (k > 1)
{
n = k;
k >>= 1;
phiT = phiT * phiT;
T = 1.0L;
for (unsigned int l = 0; l < k; l++)
{
for (unsigned int a = l; a < N; a += n)
{
unsigned int b = a + k;
Complex t = x[a] - x[b];
x[a] += x[b];
x[b] = t * T;
}
T *= phiT;
}
}
// Decimate
unsigned int m = (unsigned int)log2(N);
for (unsigned int a = 0; a < N; a++)
{
unsigned int b = a;
// Reverse bits
b = (((b & 0xaaaaaaaa) >> 1) | ((b & 0x55555555) << 1));
b = (((b & 0xcccccccc) >> 2) | ((b & 0x33333333) << 2));
b = (((b & 0xf0f0f0f0) >> 4) | ((b & 0x0f0f0f0f) << 4));
b = (((b & 0xff00ff00) >> 8) | ((b & 0x00ff00ff) << 8));
b = ((b >> 16) | (b << 16)) >> (32 - m);
if (b > a)
{
Complex t = x[a];
x[a] = x[b];
x[b] = t;
}
}
//// Normalize (This section make it not working correctly)
//Complex f = 1.0 / sqrt(N);
//for (unsigned int i = 0; i < N; i++)
// x[i] *= f;
}
// inverse fft (in-place)
void ifft(CArray& x)
{
// conjugate the complex numbers
x = x.apply(std::conj);
// forward fft
fft( x );
// conjugate the complex numbers again
x = x.apply(std::conj);
// scale the numbers
x /= x.size();
}
int main()
{
const Complex test[] = { 1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0 };
CArray data(test, 8);
// forward fft
fft(data);
std::cout << "fft" << std::endl;
for (int i = 0; i < 8; ++i)
{
std::cout << data[i] << std::endl;
}
// inverse fft
ifft(data);
std::cout << std::endl << "ifft" << std::endl;
for (int i = 0; i < 8; ++i)
{
std::cout << data[i] << std::endl;
}
return 0;
} |
http://rosettacode.org/wiki/Factors_of_a_Mersenne_number | Factors of a Mersenne number | A Mersenne number is a number in the form of 2P-1.
If P is prime, the Mersenne number may be a Mersenne prime
(if P is not prime, the Mersenne number is also not prime).
In the search for Mersenne prime numbers it is advantageous to eliminate exponents by finding a small factor before starting a, potentially lengthy, Lucas-Lehmer test.
There are very efficient algorithms for determining if a number divides 2P-1 (or equivalently, if 2P mod (the number) = 1).
Some languages already have built-in implementations of this exponent-and-mod operation (called modPow or similar).
The following is how to implement this modPow yourself:
For example, let's compute 223 mod 47.
Convert the exponent 23 to binary, you get 10111. Starting with square = 1, repeatedly square it.
Remove the top bit of the exponent, and if it's 1 multiply square by the base of the exponentiation (2), then compute square modulo 47.
Use the result of the modulo from the last step as the initial value of square in the next step:
remove optional
square top bit multiply by 2 mod 47
──────────── ─────── ───────────── ──────
1*1 = 1 1 0111 1*2 = 2 2
2*2 = 4 0 111 no 4
4*4 = 16 1 11 16*2 = 32 32
32*32 = 1024 1 1 1024*2 = 2048 27
27*27 = 729 1 729*2 = 1458 1
Since 223 mod 47 = 1, 47 is a factor of 2P-1.
(To see this, subtract 1 from both sides: 223-1 = 0 mod 47.)
Since we've shown that 47 is a factor, 223-1 is not prime.
Further properties of Mersenne numbers allow us to refine the process even more.
Any factor q of 2P-1 must be of the form 2kP+1, k being a positive integer or zero. Furthermore, q must be 1 or 7 mod 8.
Finally any potential factor q must be prime.
As in other trial division algorithms, the algorithm stops when 2kP+1 > sqrt(N).
These primality tests only work on Mersenne numbers where P is prime. For example, M4=15 yields no factors using these techniques, but factors into 3 and 5, neither of which fit 2kP+1.
Task
Using the above method find a factor of 2929-1 (aka M929)
Related tasks
count in factors
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
See also
Computers in 1948: 2127 - 1
(Note: This video is no longer available because the YouTube account associated with this video has been terminated.)
| #C | C | int isPrime(int n){
if (n%2==0) return n==2;
if (n%3==0) return n==3;
int d=5;
while(d*d<=n){
if(n%d==0) return 0;
d+=2;
if(n%d==0) return 0;
d+=4;}
return 1;}
main() {int i,d,p,r,q=929;
if (!isPrime(q)) return 1;
r=q;
while(r>0) r<<=1;
d=2*q+1;
do { for(p=r, i= 1; p; p<<= 1){
i=((long long)i * i) % d;
if (p < 0) i *= 2;
if (i > d) i -= d;}
if (i != 1) d += 2*q;
else break;
} while(1);
printf("2^%d - 1 = 0 (mod %d)\n", q, d);} |
http://rosettacode.org/wiki/Farey_sequence | Farey sequence | The Farey sequence Fn of order n is the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to n, arranged in order of increasing size.
The Farey sequence is sometimes incorrectly called a Farey series.
Each Farey sequence:
starts with the value 0 (zero), denoted by the fraction
0
1
{\displaystyle {\frac {0}{1}}}
ends with the value 1 (unity), denoted by the fraction
1
1
{\displaystyle {\frac {1}{1}}}
.
The Farey sequences of orders 1 to 5 are:
F
1
=
0
1
,
1
1
{\displaystyle {\bf {\it {F}}}_{1}={\frac {0}{1}},{\frac {1}{1}}}
F
2
=
0
1
,
1
2
,
1
1
{\displaystyle {\bf {\it {F}}}_{2}={\frac {0}{1}},{\frac {1}{2}},{\frac {1}{1}}}
F
3
=
0
1
,
1
3
,
1
2
,
2
3
,
1
1
{\displaystyle {\bf {\it {F}}}_{3}={\frac {0}{1}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {1}{1}}}
F
4
=
0
1
,
1
4
,
1
3
,
1
2
,
2
3
,
3
4
,
1
1
{\displaystyle {\bf {\it {F}}}_{4}={\frac {0}{1}},{\frac {1}{4}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {3}{4}},{\frac {1}{1}}}
F
5
=
0
1
,
1
5
,
1
4
,
1
3
,
2
5
,
1
2
,
3
5
,
2
3
,
3
4
,
4
5
,
1
1
{\displaystyle {\bf {\it {F}}}_{5}={\frac {0}{1}},{\frac {1}{5}},{\frac {1}{4}},{\frac {1}{3}},{\frac {2}{5}},{\frac {1}{2}},{\frac {3}{5}},{\frac {2}{3}},{\frac {3}{4}},{\frac {4}{5}},{\frac {1}{1}}}
Task
Compute and show the Farey sequence for orders 1 through 11 (inclusive).
Compute and display the number of fractions in the Farey sequence for order 100 through 1,000 (inclusive) by hundreds.
Show the fractions as n/d (using the solidus [or slash] to separate the numerator from the denominator).
The length (the number of fractions) of a Farey sequence asymptotically approaches:
3 × n2 ÷
π
{\displaystyle \pi }
2
See also
OEIS sequence A006842 numerators of Farey series of order 1, 2, ···
OEIS sequence A006843 denominators of Farey series of order 1, 2, ···
OEIS sequence A005728 number of fractions in Farey series of order n
MathWorld entry Farey sequence
Wikipedia entry Farey sequence
| #Delphi | Delphi |
(define distinct-divisors
(compose make-set prime-factors))
;; euler totient : Φ : n / product(p_i) * product (p_i - 1)
;; # of divisors <= n
(define (Φ n)
(let ((pdiv (distinct-divisors n)))
(/ (* n (for/product ((p pdiv)) (1- p))) (for/product ((p pdiv)) p))))
;; farey-sequence length |Fn| = 1 + sigma (m=1..) Φ(m)
(define ( F-length n) (1+ (for/sum ((m (1+ n))) (Φ m))))
;; farey sequence
;; apply the definition : O(n^2)
(define (Farey N)
(set! N (1+ N))
(make-set (for*/list ((n N) (d (in-range n N))) (rational n d))))
|
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #JavaScript | JavaScript | (() => {
'use strict';
// thueMorse :: Int -> [Int]
const thueMorse = base =>
// Thue-Morse sequence for a given base
fmapGen(baseDigitsSumModBase(base))(
enumFrom(0)
)
// baseDigitsSumModBase :: Int -> Int -> Int
const baseDigitsSumModBase = base =>
// For any integer n, the sum of its digits
// in a given base, modulo that base.
n => sum(unfoldl(
x => 0 < x ? (
Just(quotRem(x)(base))
) : Nothing()
)(n)) % base
// ------------------------TEST------------------------
const main = () =>
console.log(
fTable(
'First 25 fairshare terms for a given number of players:'
)(str)(
xs => '[' + map(
compose(justifyRight(2)(' '), str)
)(xs) + ' ]'
)(
compose(take(25), thueMorse)
)([2, 3, 5, 11])
);
// -----------------GENERIC FUNCTIONS------------------
// Just :: a -> Maybe a
const Just = x => ({
type: 'Maybe',
Nothing: false,
Just: x
});
// Nothing :: Maybe a
const Nothing = () => ({
type: 'Maybe',
Nothing: true,
});
// Tuple (,) :: a -> b -> (a, b)
const Tuple = a => b => ({
type: 'Tuple',
'0': a,
'1': b,
length: 2
});
// compose (<<<) :: (b -> c) -> (a -> b) -> a -> c
const compose = (...fs) =>
x => fs.reduceRight((a, f) => f(a), x);
// enumFrom :: Enum a => a -> [a]
function* enumFrom(x) {
// A non-finite succession of enumerable
// values, starting with the value x.
let v = x;
while (true) {
yield v;
v = 1 + v;
}
}
// fTable :: String -> (a -> String) -> (b -> String)
// -> (a -> b) -> [a] -> String
const fTable = s => xShow => fxShow => f => xs => {
// Heading -> x display function ->
// fx display function ->
// f -> values -> tabular string
const
ys = xs.map(xShow),
w = Math.max(...ys.map(length));
return s + '\n' + zipWith(
a => b => a.padStart(w, ' ') + ' -> ' + b
)(ys)(
xs.map(x => fxShow(f(x)))
).join('\n');
};
// fmapGen <$> :: (a -> b) -> Gen [a] -> Gen [b]
const fmapGen = f =>
function*(gen) {
let v = take(1)(gen);
while (0 < v.length) {
yield(f(v[0]))
v = take(1)(gen)
}
};
// justifyRight :: Int -> Char -> String -> String
const justifyRight = n =>
// The string s, preceded by enough padding (with
// the character c) to reach the string length n.
c => s => n > s.length ? (
s.padStart(n, c)
) : s;
// length :: [a] -> Int
const length = xs =>
// Returns Infinity over objects without finite
// length. This enables zip and zipWith to choose
// the shorter argument when one is non-finite,
// like cycle, repeat etc
(Array.isArray(xs) || 'string' === typeof xs) ? (
xs.length
) : Infinity;
// map :: (a -> b) -> [a] -> [b]
const map = f =>
// The list obtained by applying f to each element of xs.
// (The image of xs under f).
xs => (Array.isArray(xs) ? (
xs
) : xs.split('')).map(f);
// quotRem :: Int -> Int -> (Int, Int)
const quotRem = m => n =>
Tuple(Math.floor(m / n))(
m % n
);
// str :: a -> String
const str = x => x.toString();
// sum :: [Num] -> Num
const sum = xs =>
// The numeric sum of all values in xs.
xs.reduce((a, x) => a + x, 0);
// take :: Int -> [a] -> [a]
// take :: Int -> String -> String
const take = n =>
// The first n elements of a list,
// string of characters, or stream.
xs => 'GeneratorFunction' !== xs
.constructor.constructor.name ? (
xs.slice(0, n)
) : [].concat.apply([], Array.from({
length: n
}, () => {
const x = xs.next();
return x.done ? [] : [x.value];
}));
// unfoldl :: (b -> Maybe (b, a)) -> b -> [a]
const unfoldl = f => v => {
// Dual to reduce or foldl.
// Where these reduce a list to a summary value, unfoldl
// builds a list from a seed value.
// Where f returns Just(a, b), a is appended to the list,
// and the residual b is used as the argument for the next
// application of f.
// Where f returns Nothing, the completed list is returned.
let
xr = [v, v],
xs = [];
while (true) {
const mb = f(xr[0]);
if (mb.Nothing) {
return xs
} else {
xr = mb.Just;
xs = [xr[1]].concat(xs);
}
}
};
// zipWith :: (a -> b -> c) -> [a] -> [b] -> [c]
const zipWith = f =>
xs => ys => {
const
lng = Math.min(length(xs), length(ys)),
vs = take(lng)(ys);
return take(lng)(xs)
.map((x, i) => f(x)(vs[i]));
};
// MAIN ---
return main();
})(); |
http://rosettacode.org/wiki/Faulhaber%27s_triangle | Faulhaber's triangle | Named after Johann Faulhaber, the rows of Faulhaber's triangle are the coefficients of polynomials that represent sums of integer powers, which are extracted from Faulhaber's formula:
∑
k
=
1
n
k
p
=
1
p
+
1
∑
j
=
0
p
(
p
+
1
j
)
B
j
n
p
+
1
−
j
{\displaystyle \sum _{k=1}^{n}k^{p}={1 \over p+1}\sum _{j=0}^{p}{p+1 \choose j}B_{j}n^{p+1-j}}
where
B
n
{\displaystyle B_{n}}
is the nth-Bernoulli number.
The first 5 rows of Faulhaber's triangle, are:
1
1/2 1/2
1/6 1/2 1/3
0 1/4 1/2 1/4
-1/30 0 1/3 1/2 1/5
Using the third row of the triangle, we have:
∑
k
=
1
n
k
2
=
1
6
n
+
1
2
n
2
+
1
3
n
3
{\displaystyle \sum _{k=1}^{n}k^{2}={1 \over 6}n+{1 \over 2}n^{2}+{1 \over 3}n^{3}}
Task
show the first 10 rows of Faulhaber's triangle.
using the 18th row of Faulhaber's triangle, compute the sum:
∑
k
=
1
1000
k
17
{\displaystyle \sum _{k=1}^{1000}k^{17}}
(extra credit).
See also
Bernoulli numbers
Evaluate binomial coefficients
Faulhaber's formula (Wikipedia)
Faulhaber's triangle (PDF)
| #Java | Java | import java.math.BigDecimal;
import java.math.MathContext;
import java.util.Arrays;
import java.util.stream.LongStream;
public class FaulhabersTriangle {
private static final MathContext MC = new MathContext(256);
private static long gcd(long a, long b) {
if (b == 0) {
return a;
}
return gcd(b, a % b);
}
private static class Frac implements Comparable<Frac> {
private long num;
private long denom;
public static final Frac ZERO = new Frac(0, 1);
public Frac(long n, long d) {
if (d == 0) throw new IllegalArgumentException("d must not be zero");
long nn = n;
long dd = d;
if (nn == 0) {
dd = 1;
} else if (dd < 0) {
nn = -nn;
dd = -dd;
}
long g = Math.abs(gcd(nn, dd));
if (g > 1) {
nn /= g;
dd /= g;
}
num = nn;
denom = dd;
}
public Frac plus(Frac rhs) {
return new Frac(num * rhs.denom + denom * rhs.num, rhs.denom * denom);
}
public Frac unaryMinus() {
return new Frac(-num, denom);
}
public Frac minus(Frac rhs) {
return this.plus(rhs.unaryMinus());
}
public Frac times(Frac rhs) {
return new Frac(this.num * rhs.num, this.denom * rhs.denom);
}
@Override
public int compareTo(Frac o) {
double diff = toDouble() - o.toDouble();
return Double.compare(diff, 0.0);
}
@Override
public boolean equals(Object obj) {
return null != obj && obj instanceof Frac && this.compareTo((Frac) obj) == 0;
}
@Override
public String toString() {
if (denom == 1) {
return Long.toString(num);
}
return String.format("%d/%d", num, denom);
}
public double toDouble() {
return (double) num / denom;
}
public BigDecimal toBigDecimal() {
return BigDecimal.valueOf(num).divide(BigDecimal.valueOf(denom), MC);
}
}
private static Frac bernoulli(int n) {
if (n < 0) throw new IllegalArgumentException("n may not be negative or zero");
Frac[] a = new Frac[n + 1];
Arrays.fill(a, Frac.ZERO);
for (int m = 0; m <= n; ++m) {
a[m] = new Frac(1, m + 1);
for (int j = m; j >= 1; --j) {
a[j - 1] = a[j - 1].minus(a[j]).times(new Frac(j, 1));
}
}
// returns 'first' Bernoulli number
if (n != 1) return a[0];
return a[0].unaryMinus();
}
private static long binomial(int n, int k) {
if (n < 0 || k < 0 || n < k) throw new IllegalArgumentException();
if (n == 0 || k == 0) return 1;
long num = LongStream.rangeClosed(k + 1, n).reduce(1, (a, b) -> a * b);
long den = LongStream.rangeClosed(2, n - k).reduce(1, (acc, i) -> acc * i);
return num / den;
}
private static Frac[] faulhaberTriangle(int p) {
Frac[] coeffs = new Frac[p + 1];
Arrays.fill(coeffs, Frac.ZERO);
Frac q = new Frac(1, p + 1);
int sign = -1;
for (int j = 0; j <= p; ++j) {
sign *= -1;
coeffs[p - j] = q.times(new Frac(sign, 1)).times(new Frac(binomial(p + 1, j), 1)).times(bernoulli(j));
}
return coeffs;
}
public static void main(String[] args) {
for (int i = 0; i <= 9; ++i) {
Frac[] coeffs = faulhaberTriangle(i);
for (Frac coeff : coeffs) {
System.out.printf("%5s ", coeff);
}
System.out.println();
}
System.out.println();
// get coeffs for (k + 1)th row
int k = 17;
Frac[] cc = faulhaberTriangle(k);
int n = 1000;
BigDecimal nn = BigDecimal.valueOf(n);
BigDecimal np = BigDecimal.ONE;
BigDecimal sum = BigDecimal.ZERO;
for (Frac c : cc) {
np = np.multiply(nn);
sum = sum.add(np.multiply(c.toBigDecimal()));
}
System.out.println(sum.toBigInteger());
}
} |
http://rosettacode.org/wiki/Faulhaber%27s_formula | Faulhaber's formula | In mathematics, Faulhaber's formula, named after Johann Faulhaber, expresses the sum of the p-th powers of the first n positive integers as a (p + 1)th-degree polynomial function of n, the coefficients involving Bernoulli numbers.
Task
Generate the first 10 closed-form expressions, starting with p = 0.
Related tasks
Bernoulli numbers.
evaluate binomial coefficients.
See also
The Wikipedia entry: Faulhaber's formula.
The Wikipedia entry: Bernoulli numbers.
The Wikipedia entry: binomial coefficients.
| #Julia | Julia | module Faulhaber
function bernoulli(n::Integer)
n ≥ 0 || throw(DomainError(n, "n must be a positive-or-0 number"))
a = fill(0 // 1, n + 1)
for m in 1:n
a[m] = 1 // (m + 1)
for j in m:-1:2
a[j - 1] = (a[j - 1] - a[j]) * j
end
end
return ifelse(n != 1, a[1], -a[1])
end
const _exponents = collect(Char, "⁰¹²³⁴⁵⁶⁷⁸⁹")
toexponent(n) = join(_exponents[reverse(digits(n)) .+ 1])
function formula(p::Integer)
print(p, ": ")
q = 1 // (p + 1)
s = -1
for j in 0:p
s *= -1
coeff = q * s * binomial(p + 1, j) * bernoulli(j)
iszero(coeff) && continue
if iszero(j)
print(coeff == 1 ? "" : coeff == -1 ? "-" : "$coeff")
else
print(coeff == 1 ? " + " : coeff == -1 ? " - " : coeff > 0 ? " + $coeff " : " - $(-coeff) ")
end
pwr = p + 1 - j
if pwr > 1
print("n", toexponent(pwr))
else
print("n")
end
end
println()
end
end # module Faulhaber |
http://rosettacode.org/wiki/Fibonacci_n-step_number_sequences | Fibonacci n-step number sequences | These number series are an expansion of the ordinary Fibonacci sequence where:
For
n
=
2
{\displaystyle n=2}
we have the Fibonacci sequence; with initial values
[
1
,
1
]
{\displaystyle [1,1]}
and
F
k
2
=
F
k
−
1
2
+
F
k
−
2
2
{\displaystyle F_{k}^{2}=F_{k-1}^{2}+F_{k-2}^{2}}
For
n
=
3
{\displaystyle n=3}
we have the tribonacci sequence; with initial values
[
1
,
1
,
2
]
{\displaystyle [1,1,2]}
and
F
k
3
=
F
k
−
1
3
+
F
k
−
2
3
+
F
k
−
3
3
{\displaystyle F_{k}^{3}=F_{k-1}^{3}+F_{k-2}^{3}+F_{k-3}^{3}}
For
n
=
4
{\displaystyle n=4}
we have the tetranacci sequence; with initial values
[
1
,
1
,
2
,
4
]
{\displaystyle [1,1,2,4]}
and
F
k
4
=
F
k
−
1
4
+
F
k
−
2
4
+
F
k
−
3
4
+
F
k
−
4
4
{\displaystyle F_{k}^{4}=F_{k-1}^{4}+F_{k-2}^{4}+F_{k-3}^{4}+F_{k-4}^{4}}
...
For general
n
>
2
{\displaystyle n>2}
we have the Fibonacci
n
{\displaystyle n}
-step sequence -
F
k
n
{\displaystyle F_{k}^{n}}
; with initial values of the first
n
{\displaystyle n}
values of the
(
n
−
1
)
{\displaystyle (n-1)}
'th Fibonacci
n
{\displaystyle n}
-step sequence
F
k
n
−
1
{\displaystyle F_{k}^{n-1}}
; and
k
{\displaystyle k}
'th value of this
n
{\displaystyle n}
'th sequence being
F
k
n
=
∑
i
=
1
(
n
)
F
k
−
i
(
n
)
{\displaystyle F_{k}^{n}=\sum _{i=1}^{(n)}{F_{k-i}^{(n)}}}
For small values of
n
{\displaystyle n}
, Greek numeric prefixes are sometimes used to individually name each series.
Fibonacci
n
{\displaystyle n}
-step sequences
n
{\displaystyle n}
Series name
Values
2
fibonacci
1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 ...
3
tribonacci
1 1 2 4 7 13 24 44 81 149 274 504 927 1705 3136 ...
4
tetranacci
1 1 2 4 8 15 29 56 108 208 401 773 1490 2872 5536 ...
5
pentanacci
1 1 2 4 8 16 31 61 120 236 464 912 1793 3525 6930 ...
6
hexanacci
1 1 2 4 8 16 32 63 125 248 492 976 1936 3840 7617 ...
7
heptanacci
1 1 2 4 8 16 32 64 127 253 504 1004 2000 3984 7936 ...
8
octonacci
1 1 2 4 8 16 32 64 128 255 509 1016 2028 4048 8080 ...
9
nonanacci
1 1 2 4 8 16 32 64 128 256 511 1021 2040 4076 8144 ...
10
decanacci
1 1 2 4 8 16 32 64 128 256 512 1023 2045 4088 8172 ...
Allied sequences can be generated where the initial values are changed:
The Lucas series sums the two preceding values like the fibonacci series for
n
=
2
{\displaystyle n=2}
but uses
[
2
,
1
]
{\displaystyle [2,1]}
as its initial values.
Task
Write a function to generate Fibonacci
n
{\displaystyle n}
-step number sequences given its initial values and assuming the number of initial values determines how many previous values are summed to make the next number of the series.
Use this to print and show here at least the first ten members of the Fibo/tribo/tetra-nacci and Lucas sequences.
Related tasks
Fibonacci sequence
Wolfram Mathworld
Hofstadter Q sequence
Leonardo numbers
Also see
Lucas Numbers - Numberphile (Video)
Tribonacci Numbers (and the Rauzy Fractal) - Numberphile (Video)
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #C.2B.2B | C++ | #include <vector>
#include <iostream>
#include <numeric>
#include <iterator>
#include <memory>
#include <string>
#include <algorithm>
#include <iomanip>
std::vector<int> nacci ( const std::vector<int> & start , int arity ) {
std::vector<int> result ( start ) ;
int sumstart = 1 ;//summing starts at vector's begin + sumstart as
//soon as the vector is longer than arity
while ( result.size( ) < 15 ) { //we print out the first 15 numbers
if ( result.size( ) <= arity )
result.push_back( std::accumulate( result.begin( ) ,
result.begin( ) + result.size( ) , 0 ) ) ;
else {
result.push_back( std::accumulate ( result.begin( ) +
sumstart , result.begin( ) + sumstart + arity , 0 )) ;
sumstart++ ;
}
}
return std::move ( result ) ;
}
int main( ) {
std::vector<std::string> naccinames {"fibo" , "tribo" ,
"tetra" , "penta" , "hexa" , "hepta" , "octo" , "nona" , "deca" } ;
const std::vector<int> fibo { 1 , 1 } , lucas { 2 , 1 } ;
for ( int i = 2 ; i < 11 ; i++ ) {
std::vector<int> numberrow = nacci ( fibo , i ) ;
std::cout << std::left << std::setw( 10 ) <<
naccinames[ i - 2 ].append( "nacci" ) <<
std::setw( 2 ) << " : " ;
std::copy ( numberrow.begin( ) , numberrow.end( ) ,
std::ostream_iterator<int>( std::cout , " " ) ) ;
std::cout << "...\n" ;
numberrow = nacci ( lucas , i ) ;
std::cout << "Lucas-" << i ;
if ( i < 10 ) //for formatting purposes
std::cout << " : " ;
else
std::cout << " : " ;
std::copy ( numberrow.begin( ) , numberrow.end( ) ,
std::ostream_iterator<int>( std::cout , " " ) ) ;
std::cout << "...\n" ;
}
return 0 ;
} |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #VBScript | VBScript |
WScript.Echo CreateObject("Scripting.FileSystemObject").GetFile("input.txt").DateLastModified
|
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #Vedit_macro_language | Vedit macro language | Num_Type(File_Stamp_Time("input.txt")) |
http://rosettacode.org/wiki/File_modification_time | File modification time | Task
Get and set the modification time of a file.
| #Visual_Basic_.NET | Visual Basic .NET | Dim file As New IO.FileInfo("test.txt")
'Creation Time
Dim createTime = file.CreationTime
file.CreationTime = createTime.AddHours(1)
'Write Time
Dim writeTime = file.LastWriteTime
file.LastWriteTime = writeTime.AddHours(1)
'Access Time
Dim accessTime = file.LastAccessTime
file.LastAccessTime = accessTime.AddHours(1) |
http://rosettacode.org/wiki/Fibonacci_word/fractal | Fibonacci word/fractal |
The Fibonacci word may be represented as a fractal as described here:
(Clicking on the above website (hal.archives-ouvertes.fr) will leave a cookie.)
For F_wordm start with F_wordCharn=1
Draw a segment forward
If current F_wordChar is 0
Turn left if n is even
Turn right if n is odd
next n and iterate until end of F_word
Task
Create and display a fractal similar to Fig 1.
(Clicking on the above website (hal.archives-ouvertes.fr) will leave a cookie.)
| #zkl | zkl | fcn drawFibonacci(img,x,y,word){ // word is "01001010...", 75025 characters
dx:=0; dy:=1; // turtle direction
foreach i,c in ([1..].zip(word)){ // Walker.zip(list)-->Walker of zipped list
a:=x; b:=y; x+=dx; y+=dy;
img.line(a,b, x,y, 0x00ff00);
if (c=="0"){
dxy:=dx+dy;
if(i.isEven){ dx=(dx - dxy)%2; dy=(dxy - dy)%2; }// turn left
else { dx=(dxy - dx)%2; dy=(dy - dxy)%2; }// turn right
}
}
}
img:=PPM(1050,1050);
fibWord:=L("1","0"); do(23){ fibWord.append(fibWord[-1] + fibWord[-2]); }
drawFibonacci(img,20,20,fibWord[-1]);
img.write(File("foo.ppm","wb")); |
http://rosettacode.org/wiki/Find_common_directory_path | Find common directory path | Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test'
'/home/user1/tmp/covert/operator'
'/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory '/home/user1/tmp' and not the longest common string '/home/user1/tmp/cove'.
If your language has a routine that performs this function (even if it does not have a changeable separator character), then mention it as part of the task.
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Pike | Pike | array paths = ({ "/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members" });
// append a / to each entry, so that a path like "/home/user1/tmp" will be recognized as a prefix
// without it the prefix would end up being "/home/user1/"
paths = paths[*]+"/";
string cp = String.common_prefix(paths);
cp = cp[..sizeof(cp)-search(reverse(cp), "/")-2];
Result: "/home/user1/tmp" |
http://rosettacode.org/wiki/Find_common_directory_path | Find common directory path | Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test'
'/home/user1/tmp/covert/operator'
'/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory '/home/user1/tmp' and not the longest common string '/home/user1/tmp/cove'.
If your language has a routine that performs this function (even if it does not have a changeable separator character), then mention it as part of the task.
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #PowerBASIC | PowerBASIC | #COMPILE EXE
#DIM ALL
#COMPILER PBCC 6
$PATH_SEPARATOR = "/"
FUNCTION CommonDirectoryPath(Paths() AS STRING) AS STRING
LOCAL s AS STRING
LOCAL i, j, k AS LONG
k = 1
DO
FOR i = 0 TO UBOUND(Paths)
IF i THEN
IF INSTR(k, Paths(i), $PATH_SEPARATOR) <> j THEN
EXIT DO
ELSEIF LEFT$(Paths(i), j) <> LEFT$(Paths(0), j) THEN
EXIT DO
END IF
ELSE
j = INSTR(k, Paths(i), $PATH_SEPARATOR)
IF j = 0 THEN
EXIT DO
END IF
END IF
NEXT i
s = LEFT$(Paths(0), j + CLNG(k <> 1))
k = j + 1
LOOP
FUNCTION = s
END FUNCTION
FUNCTION PBMAIN () AS LONG
' testing the above function
LOCAL s() AS STRING
LOCAL i AS LONG
REDIM s(0 TO 2)
ARRAY ASSIGN s() = "/home/user1/tmp/coverage/test", _
"/home/user1/tmp/covert/operator", _
"/home/user1/tmp/coven/members"
FOR i = 0 TO UBOUND(s()): CON.PRINT s(i): NEXT i
CON.PRINT CommonDirectoryPath(s()) & " <- common"
CON.PRINT
REDIM s(0 TO 3)
ARRAY ASSIGN s() = "/home/user1/tmp/coverage/test", _
"/home/user1/tmp/covert/operator", _
"/home/user1/tmp/coven/members", _
"/home/user1/abc/coven/members"
FOR i = 0 TO UBOUND(s()): CON.PRINT s(i): NEXT i
CON.PRINT CommonDirectoryPath(s()) & " <- common"
CON.PRINT
REDIM s(0 TO 2)
ARRAY ASSIGN s() = "/home/user1/tmp/coverage/test", _
"/hope/user1/tmp/covert/operator", _
"/home/user1/tmp/coven/members"
FOR i = 0 TO UBOUND(s()): CON.PRINT s(i): NEXT i
CON.PRINT CommonDirectoryPath(s()) & " <- common"
CON.PRINT
CON.PRINT "hit any key to end program"
CON.WAITKEY$
END FUNCTION |
http://rosettacode.org/wiki/Filter | Filter | Task
Select certain elements from an Array into a new Array in a generic way.
To demonstrate, select all even numbers from an Array.
As an option, give a second solution which filters destructively,
by modifying the original Array rather than creating a new Array.
| #EasyLang | EasyLang | a[] = [ 1 2 3 4 5 6 7 8 9 ]
for i range len a[]
if a[i] mod 2 = 0
b[] &= a[i]
.
.
print b[] |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #Scheme | Scheme | (define (recurse number)
(begin (display number) (newline) (recurse (+ number 1))))
(recurse 1) |
http://rosettacode.org/wiki/Find_limit_of_recursion | Find limit of recursion | Find limit of recursion is part of Short Circuit's Console Program Basics selection.
Task
Find the limit of recursion.
| #SenseTalk | SenseTalk | put recurse(1)
function recurse n
put n
get the recurse of (n+1)
end recurse |
http://rosettacode.org/wiki/FizzBuzz | FizzBuzz | Task
Write a program that prints the integers from 1 to 100 (inclusive).
But:
for multiples of three, print Fizz (instead of the number)
for multiples of five, print Buzz (instead of the number)
for multiples of both three and five, print FizzBuzz (instead of the number)
The FizzBuzz problem was presented as the lowest level of comprehension required to illustrate adequacy.
Also see
(a blog) dont-overthink-fizzbuzz
(a blog) fizzbuzz-the-programmers-stairway-to-heaven
| #hexiscript | hexiscript | for let i 1; i <= 100; i++
if i % 3 = 0 && i % 5 = 0; println "FizzBuzz"
elif i % 3 = 0; println "Fizz"
elif i % 5 = 0; println "Buzz"
else println i; endif
endfor |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #PL.2FI | PL/I |
/* To obtain file size of files in root as well as from current directory. */
test: proc options (main);
declare ch character (1);
declare i fixed binary (31);
declare in1 file record;
/* Open a file in the root directory. */
open file (in1) title ('//asd.log,type(fixed),recsize(1)');
on endfile (in1) go to next1;
do i = 0 by 1;
read file (in1) into (ch);
end;
next1:
put skip list ('file size in root directory =' || trim(i));
close file (in1);
/* Open a file in the current dorectory. */
open file (in1) title ('/asd.txt,type(fixed),recsize(1)');
on endfile (in1) go to next2;
do i = 0 by 1;
read file (in1) into (ch);
end;
next2:
put skip list ('local file size=' || trim(i));
end test;
|
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #Pop11 | Pop11 | ;;; prints file size in bytes
sysfilesize('input.txt') =>
sysfilesize('/input.txt') => |
http://rosettacode.org/wiki/File_size | File size | Verify the size of a file called input.txt for a file in the current working directory, and another one in the file system root.
| #PostScript | PostScript | (input.txt ) print
(input.txt) status pop pop pop = pop
(/input.txt ) print
(/input.txt) status pop pop pop = pop |
http://rosettacode.org/wiki/File_input/output | File input/output | File input/output is part of Short Circuit's Console Program Basics selection.
Task
Create a file called "output.txt", and place in it the contents of the file "input.txt", via an intermediate variable.
In other words, your program will demonstrate:
how to read from a file into a variable
how to write a variable's contents into a file
Oneliners that skip the intermediate variable are of secondary interest — operating systems have copy commands for that.
| #hexiscript | hexiscript | let in openin "input.txt"
let out openout "output.txt"
while !(catch (let c read char in))
write c out
endwhile
close in; close out |
http://rosettacode.org/wiki/File_input/output | File input/output | File input/output is part of Short Circuit's Console Program Basics selection.
Task
Create a file called "output.txt", and place in it the contents of the file "input.txt", via an intermediate variable.
In other words, your program will demonstrate:
how to read from a file into a variable
how to write a variable's contents into a file
Oneliners that skip the intermediate variable are of secondary interest — operating systems have copy commands for that.
| #HicEst | HicEst | CHARACTER input='input.txt ', output='output.txt ', c, buffer*4096
SYSTEM(COPY=input//output, ERror=11) ! on error branch to label 11 (not shown) |
http://rosettacode.org/wiki/Fibonacci_word | Fibonacci word | The Fibonacci Word may be created in a manner analogous to the Fibonacci Sequence as described here:
Define F_Word1 as 1
Define F_Word2 as 0
Form F_Word3 as F_Word2 concatenated with F_Word1 i.e.: 01
Form F_Wordn as F_Wordn-1 concatenated with F_wordn-2
Task
Perform the above steps for n = 37.
You may display the first few but not the larger values of n.
{Doing so will get the task's author into trouble with them what be (again!).}
Instead, create a table for F_Words 1 to 37 which shows:
The number of characters in the word
The word's Entropy
Related tasks
Fibonacci word/fractal
Entropy
Entropy/Narcissist
| #Lua | Lua | -- Return the base two logarithm of x
function log2 (x) return math.log(x) / math.log(2) end
-- Return the Shannon entropy of X
function entropy (X)
local N, count, sum, i = X:len(), {}, 0
for char = 1, N do
i = X:sub(char, char)
if count[i] then
count[i] = count[i] + 1
else
count[i] = 1
end
end
for n_i, count_i in pairs(count) do
sum = sum + count_i / N * log2(count_i / N)
end
return -sum
end
-- Return a table of the first n Fibonacci words
function fibWords (n)
local fw = {1, 0}
while #fw < n do fw[#fw + 1] = fw[#fw] .. fw[#fw - 1] end
return fw
end
-- Main procedure
print("n\tWord length\tEntropy")
for k, v in pairs(fibWords(37)) do
v = tostring(v)
io.write(k .. "\t" .. #v)
if string.len(#v) < 8 then io.write("\t") end
print("\t" .. entropy(v))
end |
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Perl | Perl | my $fasta_example = <<'END_FASTA_EXAMPLE';
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
END_FASTA_EXAMPLE
my $num_newlines = 0;
while ( < $fasta_example > ) {
if (/\A\>(.*)/) {
print "\n" x $num_newlines, $1, ': ';
}
else {
$num_newlines = 1;
print;
}
} |
http://rosettacode.org/wiki/FASTA_format | FASTA format | In bioinformatics, long character strings are often encoded in a format called FASTA.
A FASTA file can contain several strings, each identified by a name marked by a > (greater than) character at the beginning of the line.
Task
Write a program that reads a FASTA file such as:
>Rosetta_Example_1
THERECANBENOSPACE
>Rosetta_Example_2
THERECANBESEVERAL
LINESBUTTHEYALLMUST
BECONCATENATED
Output:
Rosetta_Example_1: THERECANBENOSPACE
Rosetta_Example_2: THERECANBESEVERALLINESBUTTHEYALLMUSTBECONCATENATED
Note that a high-quality implementation will not hold the entire file in memory at once; real FASTA files can be multiple gigabytes in size.
| #Phix | Phix | bool first = true
integer fn = open("fasta.txt","r")
if fn=-1 then ?9/0 end if
while true do
object line = trim(gets(fn))
if atom(line) then puts(1,"\n") exit end if
if length(line) then
if line[1]=='>' then
if not first then puts(1,"\n") end if
printf(1,"%s: ",{line[2..$]})
first = false
elsif first then
printf(1,"Error : File does not begin with '>'\n")
exit
elsif not find_any(" \t",line) then
puts(1,line)
else
printf(1,"\nError : Sequence contains space(s)\n")
exit
end if
end if
end while
close(fn)
|
http://rosettacode.org/wiki/Fibonacci_sequence | Fibonacci sequence | The Fibonacci sequence is a sequence Fn of natural numbers defined recursively:
F0 = 0
F1 = 1
Fn = Fn-1 + Fn-2, if n>1
Task
Write a function to generate the nth Fibonacci number.
Solutions can be iterative or recursive (though recursive solutions are generally considered too slow and are mostly used as an exercise in recursion).
The sequence is sometimes extended into negative numbers by using a straightforward inverse of the positive definition:
Fn = Fn+2 - Fn+1, if n<0
support for negative n in the solution is optional.
Related tasks
Fibonacci n-step number sequences
Leonardo numbers
References
Wikipedia, Fibonacci number
Wikipedia, Lucas number
MathWorld, Fibonacci Number
Some identities for r-Fibonacci numbers
OEIS Fibonacci numbers
OEIS Lucas numbers
| #6502_Assembly | 6502 Assembly | LDA #0
STA $F0 ; LOWER NUMBER
LDA #1
STA $F1 ; HIGHER NUMBER
LDX #0
LOOP: LDA $F1
STA $0F1B,X
STA $F2 ; OLD HIGHER NUMBER
ADC $F0
STA $F1 ; NEW HIGHER NUMBER
LDA $F2
STA $F0 ; NEW LOWER NUMBER
INX
CPX #$0A ; STOP AT FIB(10)
BMI LOOP
RTS ; RETURN FROM SUBROUTINE |
http://rosettacode.org/wiki/Factors_of_an_integer | Factors of an integer |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Compute the factors of a positive integer.
These factors are the positive integers by which the number being factored can be divided to yield a positive integer result.
(Though the concepts function correctly for zero and negative integers, the set of factors of zero has countably infinite members, and the factors of negative integers can be obtained from the factors of related positive numbers without difficulty; this task does not require handling of either of these cases).
Note that every prime number has two factors: 1 and itself.
Related tasks
count in factors
prime decomposition
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
sequence: smallest number greater than previous term with exactly n divisors
| #ACL2 | ACL2 | (defun factors-r (n i)
(declare (xargs :measure (nfix (- n i))))
(cond ((zp (- n i))
(list n))
((= (mod n i) 0)
(cons i (factors-r n (1+ i))))
(t (factors-r n (1+ i)))))
(defun factors (n)
(factors-r n 1)) |
http://rosettacode.org/wiki/Fast_Fourier_transform | Fast Fourier transform | Task
Calculate the FFT (Fast Fourier Transform) of an input sequence.
The most general case allows for complex numbers at the input
and results in a sequence of equal length, again of complex numbers.
If you need to restrict yourself to real numbers, the output should
be the magnitude (i.e.: sqrt(re2 + im2)) of the complex result.
The classic version is the recursive Cooley–Tukey FFT. Wikipedia has pseudo-code for that.
Further optimizations are possible but not required.
| #Common_Lisp | Common Lisp |
(defun fft (a &key (inverse nil) &aux (n (length a)))
"Perform the FFT recursively on input vector A.
Vector A must have length N of power of 2."
(declare (type boolean inverse)
(type (integer 1) n))
(if (= n 1)
a
(let* ((n/2 (/ n 2))
(2iπ/n (complex 0 (/ (* 2 pi) n (if inverse -1 1))))
(⍵_n (exp 2iπ/n))
(⍵ #c(1.0d0 0.0d0))
(a0 (make-array n/2))
(a1 (make-array n/2)))
(declare (type (integer 1) n/2)
(type (complex double-float) ⍵ ⍵_n))
(symbol-macrolet ((a0[j] (svref a0 j))
(a1[j] (svref a1 j))
(a[i] (svref a i))
(a[i+1] (svref a (1+ i))))
(loop :for i :below (1- n) :by 2
:for j :from 0
:do (setf a0[j] a[i]
a1[j] a[i+1])))
(let ((â0 (fft a0 :inverse inverse))
(â1 (fft a1 :inverse inverse))
(â (make-array n)))
(symbol-macrolet ((â[k] (svref â k))
(â[k+n/2] (svref â (+ k n/2)))
(â0[k] (svref â0 k))
(â1[k] (svref â1 k)))
(loop :for k :below n/2
:do (setf â[k] (+ â0[k] (* ⍵ â1[k]))
â[k+n/2] (- â0[k] (* ⍵ â1[k])))
:when inverse
:do (setf â[k] (/ â[k] 2)
â[k+n/2] (/ â[k+n/2] 2))
:do (setq ⍵ (* ⍵ ⍵_n))
:finally (return â)))))))
|
http://rosettacode.org/wiki/Factors_of_a_Mersenne_number | Factors of a Mersenne number | A Mersenne number is a number in the form of 2P-1.
If P is prime, the Mersenne number may be a Mersenne prime
(if P is not prime, the Mersenne number is also not prime).
In the search for Mersenne prime numbers it is advantageous to eliminate exponents by finding a small factor before starting a, potentially lengthy, Lucas-Lehmer test.
There are very efficient algorithms for determining if a number divides 2P-1 (or equivalently, if 2P mod (the number) = 1).
Some languages already have built-in implementations of this exponent-and-mod operation (called modPow or similar).
The following is how to implement this modPow yourself:
For example, let's compute 223 mod 47.
Convert the exponent 23 to binary, you get 10111. Starting with square = 1, repeatedly square it.
Remove the top bit of the exponent, and if it's 1 multiply square by the base of the exponentiation (2), then compute square modulo 47.
Use the result of the modulo from the last step as the initial value of square in the next step:
remove optional
square top bit multiply by 2 mod 47
──────────── ─────── ───────────── ──────
1*1 = 1 1 0111 1*2 = 2 2
2*2 = 4 0 111 no 4
4*4 = 16 1 11 16*2 = 32 32
32*32 = 1024 1 1 1024*2 = 2048 27
27*27 = 729 1 729*2 = 1458 1
Since 223 mod 47 = 1, 47 is a factor of 2P-1.
(To see this, subtract 1 from both sides: 223-1 = 0 mod 47.)
Since we've shown that 47 is a factor, 223-1 is not prime.
Further properties of Mersenne numbers allow us to refine the process even more.
Any factor q of 2P-1 must be of the form 2kP+1, k being a positive integer or zero. Furthermore, q must be 1 or 7 mod 8.
Finally any potential factor q must be prime.
As in other trial division algorithms, the algorithm stops when 2kP+1 > sqrt(N).
These primality tests only work on Mersenne numbers where P is prime. For example, M4=15 yields no factors using these techniques, but factors into 3 and 5, neither of which fit 2kP+1.
Task
Using the above method find a factor of 2929-1 (aka M929)
Related tasks
count in factors
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
trial factoring of a Mersenne number
partition an integer X into N primes
sequence of primes by Trial Division
See also
Computers in 1948: 2127 - 1
(Note: This video is no longer available because the YouTube account associated with this video has been terminated.)
| #C.23 | C# | using System;
namespace prog
{
class MainClass
{
public static void Main (string[] args)
{
int q = 929;
if ( !isPrime(q) ) return;
int r = q;
while( r > 0 )
r <<= 1;
int d = 2 * q + 1;
do
{
int i = 1;
for( int p=r; p!=0; p<<=1 )
{
i = (i*i) % d;
if (p < 0) i *= 2;
if (i > d) i -= d;
}
if (i != 1) d += 2 * q; else break;
}
while(true);
Console.WriteLine("2^"+q+"-1 = 0 (mod "+d+")");
}
static bool isPrime(int n)
{
if ( n % 2 == 0 ) return n == 2;
if ( n % 3 == 0 ) return n == 3;
int d = 5;
while( d*d <= n )
{
if ( n % d == 0 ) return false;
d += 2;
if ( n % d == 0 ) return false;
d += 4;
}
return true;
}
}
} |
http://rosettacode.org/wiki/Farey_sequence | Farey sequence | The Farey sequence Fn of order n is the sequence of completely reduced fractions between 0 and 1 which, when in lowest terms, have denominators less than or equal to n, arranged in order of increasing size.
The Farey sequence is sometimes incorrectly called a Farey series.
Each Farey sequence:
starts with the value 0 (zero), denoted by the fraction
0
1
{\displaystyle {\frac {0}{1}}}
ends with the value 1 (unity), denoted by the fraction
1
1
{\displaystyle {\frac {1}{1}}}
.
The Farey sequences of orders 1 to 5 are:
F
1
=
0
1
,
1
1
{\displaystyle {\bf {\it {F}}}_{1}={\frac {0}{1}},{\frac {1}{1}}}
F
2
=
0
1
,
1
2
,
1
1
{\displaystyle {\bf {\it {F}}}_{2}={\frac {0}{1}},{\frac {1}{2}},{\frac {1}{1}}}
F
3
=
0
1
,
1
3
,
1
2
,
2
3
,
1
1
{\displaystyle {\bf {\it {F}}}_{3}={\frac {0}{1}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {1}{1}}}
F
4
=
0
1
,
1
4
,
1
3
,
1
2
,
2
3
,
3
4
,
1
1
{\displaystyle {\bf {\it {F}}}_{4}={\frac {0}{1}},{\frac {1}{4}},{\frac {1}{3}},{\frac {1}{2}},{\frac {2}{3}},{\frac {3}{4}},{\frac {1}{1}}}
F
5
=
0
1
,
1
5
,
1
4
,
1
3
,
2
5
,
1
2
,
3
5
,
2
3
,
3
4
,
4
5
,
1
1
{\displaystyle {\bf {\it {F}}}_{5}={\frac {0}{1}},{\frac {1}{5}},{\frac {1}{4}},{\frac {1}{3}},{\frac {2}{5}},{\frac {1}{2}},{\frac {3}{5}},{\frac {2}{3}},{\frac {3}{4}},{\frac {4}{5}},{\frac {1}{1}}}
Task
Compute and show the Farey sequence for orders 1 through 11 (inclusive).
Compute and display the number of fractions in the Farey sequence for order 100 through 1,000 (inclusive) by hundreds.
Show the fractions as n/d (using the solidus [or slash] to separate the numerator from the denominator).
The length (the number of fractions) of a Farey sequence asymptotically approaches:
3 × n2 ÷
π
{\displaystyle \pi }
2
See also
OEIS sequence A006842 numerators of Farey series of order 1, 2, ···
OEIS sequence A006843 denominators of Farey series of order 1, 2, ···
OEIS sequence A005728 number of fractions in Farey series of order n
MathWorld entry Farey sequence
Wikipedia entry Farey sequence
| #EchoLisp | EchoLisp |
(define distinct-divisors
(compose make-set prime-factors))
;; euler totient : Φ : n / product(p_i) * product (p_i - 1)
;; # of divisors <= n
(define (Φ n)
(let ((pdiv (distinct-divisors n)))
(/ (* n (for/product ((p pdiv)) (1- p))) (for/product ((p pdiv)) p))))
;; farey-sequence length |Fn| = 1 + sigma (m=1..) Φ(m)
(define ( F-length n) (1+ (for/sum ((m (1+ n))) (Φ m))))
;; farey sequence
;; apply the definition : O(n^2)
(define (Farey N)
(set! N (1+ N))
(make-set (for*/list ((n N) (d (in-range n N))) (rational n d))))
|
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #jq | jq | # Using a "reverse array" representations of the integers base b (b>=2),
# generate an unbounded stream of the integers from [0] onwards.
# E.g. for binary: [0], [1], [0,1], [1,1] ...
def integers($base):
def add1:
[foreach (.[], null) as $d ({carry: 1};
if $d then ($d + .carry ) as $r
| if $r >= $base
then {carry: 1, emit: ($r - $base)}
else {carry: 0, emit: $r }
end
elif (.carry == 0) then .emit = null
else .emit = .carry
end;
select(.emit).emit)];
[0] | recurse(add1);
def fairshare($base; $numberOfTerms):
limit($numberOfTerms;
integers($base) | add | . % $base);
# The task:
(2,3,5,11)
| "Fairshare \((select(.>2)|"among") // "between") \(.) people: \([fairshare(.; 25)])"
|
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #Julia | Julia | fairshare(nplayers,len) = [sum(digits(n, base=nplayers)) % nplayers for n in 0:len-1]
for n in [2, 3, 5, 11]
println("Fairshare ", n > 2 ? "among" : "between", " $n people: ", fairshare(n, 25))
end
|
http://rosettacode.org/wiki/Fairshare_between_two_and_more | Fairshare between two and more | The Thue-Morse sequence is a sequence of ones and zeros that if two people
take turns in the given order, the first persons turn for every '0' in the
sequence, the second for every '1'; then this is shown to give a fairer, more
equitable sharing of resources. (Football penalty shoot-outs for example, might
not favour the team that goes first as much if the penalty takers take turns
according to the Thue-Morse sequence and took 2^n penalties)
The Thue-Morse sequence of ones-and-zeroes can be generated by:
"When counting in binary, the digit sum modulo 2 is the Thue-Morse sequence"
Sharing fairly between two or more
Use this method:
When counting base b, the digit sum modulo b is the Thue-Morse sequence of fairer sharing between b people.
Task
Counting from zero; using a function/method/routine to express an integer count in base b,
sum the digits modulo b to produce the next member of the Thue-Morse fairshare series for b people.
Show the first 25 terms of the fairshare sequence:
For two people:
For three people
For five people
For eleven people
Related tasks
Non-decimal radices/Convert
Thue-Morse
See also
A010060, A053838, A053840: The On-Line Encyclopedia of Integer Sequences® (OEIS®)
| #Kotlin | Kotlin | fun turn(base: Int, n: Int): Int {
var sum = 0
var n2 = n
while (n2 != 0) {
val re = n2 % base
n2 /= base
sum += re
}
return sum % base
}
fun fairShare(base: Int, count: Int) {
print(String.format("Base %2d:", base))
for (i in 0 until count) {
val t = turn(base, i)
print(String.format(" %2d", t))
}
println()
}
fun turnCount(base: Int, count: Int) {
val cnt = IntArray(base) { 0 }
for (i in 0 until count) {
val t = turn(base, i)
cnt[t]++
}
var minTurn = Int.MAX_VALUE
var maxTurn = Int.MIN_VALUE
var portion = 0
for (i in 0 until base) {
val num = cnt[i]
if (num > 0) {
portion++
}
if (num < minTurn) {
minTurn = num
}
if (num > maxTurn) {
maxTurn = num
}
}
print(" With $base people: ")
when (minTurn) {
0 -> {
println("Only $portion have a turn")
}
maxTurn -> {
println(minTurn)
}
else -> {
println("$minTurn or $maxTurn")
}
}
}
fun main() {
fairShare(2, 25)
fairShare(3, 25)
fairShare(5, 25)
fairShare(11, 25)
println("How many times does each get a turn in 50000 iterations?")
turnCount(191, 50000)
turnCount(1377, 50000)
turnCount(49999, 50000)
turnCount(50000, 50000)
turnCount(50001, 50000)
}
|
http://rosettacode.org/wiki/Faulhaber%27s_triangle | Faulhaber's triangle | Named after Johann Faulhaber, the rows of Faulhaber's triangle are the coefficients of polynomials that represent sums of integer powers, which are extracted from Faulhaber's formula:
∑
k
=
1
n
k
p
=
1
p
+
1
∑
j
=
0
p
(
p
+
1
j
)
B
j
n
p
+
1
−
j
{\displaystyle \sum _{k=1}^{n}k^{p}={1 \over p+1}\sum _{j=0}^{p}{p+1 \choose j}B_{j}n^{p+1-j}}
where
B
n
{\displaystyle B_{n}}
is the nth-Bernoulli number.
The first 5 rows of Faulhaber's triangle, are:
1
1/2 1/2
1/6 1/2 1/3
0 1/4 1/2 1/4
-1/30 0 1/3 1/2 1/5
Using the third row of the triangle, we have:
∑
k
=
1
n
k
2
=
1
6
n
+
1
2
n
2
+
1
3
n
3
{\displaystyle \sum _{k=1}^{n}k^{2}={1 \over 6}n+{1 \over 2}n^{2}+{1 \over 3}n^{3}}
Task
show the first 10 rows of Faulhaber's triangle.
using the 18th row of Faulhaber's triangle, compute the sum:
∑
k
=
1
1000
k
17
{\displaystyle \sum _{k=1}^{1000}k^{17}}
(extra credit).
See also
Bernoulli numbers
Evaluate binomial coefficients
Faulhaber's formula (Wikipedia)
Faulhaber's triangle (PDF)
| #JavaScript | JavaScript | (() => {
// Order of Faulhaber's triangle -> rows of Faulhaber's triangle
// faulHaberTriangle :: Int -> [[Ratio Int]]
const faulhaberTriangle = n =>
map(x => tail(
scanl((a, x) => {
const ys = map((nd, i) =>
ratioMult(nd, Ratio(x, i + 2)), a);
return cons(ratioMinus(Ratio(1, 1), ratioSum(ys)), ys);
}, [], enumFromTo(0, x))
),
enumFromTo(0, n));
// p -> n -> Sum of the p-th powers of the first n positive integers
// faulhaber :: Int -> Ratio Int -> Ratio Int
const faulhaber = (p, n) =>
ratioSum(map(
(nd, i) => ratioMult(nd, Ratio(raise(n, i + 1), 1)),
last(faulhaberTriangle(p))
));
// RATIOS -----------------------------------------------------------------
// (Max numr + denr widths) -> Column width -> Filler -> Ratio -> String
// justifyRatio :: (Int, Int) -> Int -> Char -> Ratio Integer -> String
const justifyRatio = (ws, n, c, nd) => {
const
w = max(n, ws.nMax + ws.dMax + 2),
[num, den] = [nd.num, nd.den];
return all(Number.isSafeInteger, [num, den]) ? (
den === 1 ? center(w, c, show(num)) : (() => {
const [q, r] = quotRem(w - 1, 2);
return concat([
justifyRight(q, c, show(num)),
'/',
justifyLeft(q + r, c, (show(den)))
]);
})()
) : "JS integer overflow ... ";
};
// Ratio :: Int -> Int -> Ratio
const Ratio = (n, d) => ({
num: n,
den: d
});
// ratioMinus :: Ratio -> Ratio -> Ratio
const ratioMinus = (nd, nd1) => {
const
d = lcm(nd.den, nd1.den);
return simpleRatio({
num: (nd.num * (d / nd.den)) - (nd1.num * (d / nd1.den)),
den: d
});
};
// ratioMult :: Ratio -> Ratio -> Ratio
const ratioMult = (nd, nd1) => simpleRatio({
num: nd.num * nd1.num,
den: nd.den * nd1.den
});
// ratioPlus :: Ratio -> Ratio -> Ratio
const ratioPlus = (nd, nd1) => {
const
d = lcm(nd.den, nd1.den);
return simpleRatio({
num: (nd.num * (d / nd.den)) + (nd1.num * (d / nd1.den)),
den: d
});
};
// ratioSum :: [Ratio] -> Ratio
const ratioSum = xs =>
simpleRatio(foldl((a, x) => ratioPlus(a, x), {
num: 0,
den: 1
}, xs));
// ratioWidths :: [[Ratio]] -> {nMax::Int, dMax::Int}
const ratioWidths = xss => {
return foldl((a, x) => {
const [nw, dw] = ap(
[compose(length, show)], [x.num, x.den]
), [an, ad] = ap(
[curry(flip(lookup))(a)], ['nMax', 'dMax']
);
return {
nMax: nw > an ? nw : an,
dMax: dw > ad ? dw : ad
};
}, {
nMax: 0,
dMax: 0
}, concat(xss));
};
// simpleRatio :: Ratio -> Ratio
const simpleRatio = nd => {
const g = gcd(nd.num, nd.den);
return {
num: nd.num / g,
den: nd.den / g
};
};
// GENERIC FUNCTIONS ------------------------------------------------------
// all :: (a -> Bool) -> [a] -> Bool
const all = (f, xs) => xs.every(f);
// A list of functions applied to a list of arguments
// <*> :: [(a -> b)] -> [a] -> [b]
const ap = (fs, xs) => //
[].concat.apply([], fs.map(f => //
[].concat.apply([], xs.map(x => [f(x)]))));
// Size of space -> filler Char -> Text -> Centered Text
// center :: Int -> Char -> Text -> Text
const center = (n, c, s) => {
const [q, r] = quotRem(n - s.length, 2);
return concat(concat([replicate(q, c), s, replicate(q + r, c)]));
};
// compose :: (b -> c) -> (a -> b) -> (a -> c)
const compose = (f, g) => x => f(g(x));
// concat :: [[a]] -> [a] | [String] -> String
const concat = xs =>
xs.length > 0 ? (() => {
const unit = typeof xs[0] === 'string' ? '' : [];
return unit.concat.apply(unit, xs);
})() : [];
// cons :: a -> [a] -> [a]
const cons = (x, xs) => [x].concat(xs);
// 2 or more arguments
// curry :: Function -> Function
const curry = (f, ...args) => {
const go = xs => xs.length >= f.length ? (f.apply(null, xs)) :
function () {
return go(xs.concat(Array.from(arguments)));
};
return go([].slice.call(args, 1));
};
// enumFromTo :: Int -> Int -> [Int]
const enumFromTo = (m, n) =>
Array.from({
length: Math.floor(n - m) + 1
}, (_, i) => m + i);
// flip :: (a -> b -> c) -> b -> a -> c
const flip = f => (a, b) => f.apply(null, [b, a]);
// foldl :: (b -> a -> b) -> b -> [a] -> b
const foldl = (f, a, xs) => xs.reduce(f, a);
// gcd :: Integral a => a -> a -> a
const gcd = (x, y) => {
const _gcd = (a, b) => (b === 0 ? a : _gcd(b, a % b)),
abs = Math.abs;
return _gcd(abs(x), abs(y));
};
// head :: [a] -> a
const head = xs => xs.length ? xs[0] : undefined;
// intercalate :: String -> [a] -> String
const intercalate = (s, xs) => xs.join(s);
// justifyLeft :: Int -> Char -> Text -> Text
const justifyLeft = (n, cFiller, strText) =>
n > strText.length ? (
(strText + cFiller.repeat(n))
.substr(0, n)
) : strText;
// justifyRight :: Int -> Char -> Text -> Text
const justifyRight = (n, cFiller, strText) =>
n > strText.length ? (
(cFiller.repeat(n) + strText)
.slice(-n)
) : strText;
// last :: [a] -> a
const last = xs => xs.length ? xs.slice(-1)[0] : undefined;
// length :: [a] -> Int
const length = xs => xs.length;
// lcm :: Integral a => a -> a -> a
const lcm = (x, y) =>
(x === 0 || y === 0) ? 0 : Math.abs(Math.floor(x / gcd(x, y)) * y);
// lookup :: Eq a => a -> [(a, b)] -> Maybe b
const lookup = (k, pairs) => {
if (Array.isArray(pairs)) {
let m = pairs.find(x => x[0] === k);
return m ? m[1] : undefined;
} else {
return typeof pairs === 'object' ? (
pairs[k]
) : undefined;
}
};
// map :: (a -> b) -> [a] -> [b]
const map = (f, xs) => xs.map(f);
// max :: Ord a => a -> a -> a
const max = (a, b) => b > a ? b : a;
// min :: Ord a => a -> a -> a
const min = (a, b) => b < a ? b : a;
// quotRem :: Integral a => a -> a -> (a, a)
const quotRem = (m, n) => [Math.floor(m / n), m % n];
// raise :: Num -> Int -> Num
const raise = (n, e) => Math.pow(n, e);
// replicate :: Int -> a -> [a]
const replicate = (n, x) =>
Array.from({
length: n
}, () => x);
// scanl :: (b -> a -> b) -> b -> [a] -> [b]
const scanl = (f, startValue, xs) =>
xs.reduce((a, x) => {
const v = f(a.acc, x);
return {
acc: v,
scan: cons(a.scan, v)
};
}, {
acc: startValue,
scan: [startValue]
})
.scan;
// show :: a -> String
const show = (...x) =>
JSON.stringify.apply(
null, x.length > 1 ? [x[0], null, x[1]] : x
);
// tail :: [a] -> [a]
const tail = xs => xs.length ? xs.slice(1) : undefined;
// unlines :: [String] -> String
const unlines = xs => xs.join('\n');
// TEST -------------------------------------------------------------------
const
triangle = faulhaberTriangle(9),
widths = ratioWidths(triangle);
return unlines(
map(row =>
concat(map(cell =>
justifyRatio(widths, 8, ' ', cell), row)), triangle)
) +
'\n\n' + unlines(
[
'faulhaber(17, 1000)',
justifyRatio(widths, 0, ' ', faulhaber(17, 1000)),
'\nfaulhaber(17, 8)',
justifyRatio(widths, 0, ' ', faulhaber(17, 8)),
'\nfaulhaber(4, 1000)',
justifyRatio(widths, 0, ' ', faulhaber(4, 1000)),
]
);
})(); |
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