target-benchmark/spider-queries-validation

query_id int64 0 1.03k	database_id stringclasses 20 values	table_id listlengths 1 4	query stringlengths 18 174	answer stringlengths 20 422	difficulty stringclasses 4 values
0	concert_singer	[ "singer" ]	How many singers do we have?	SELECT count(*) FROM singer	easy
1	concert_singer	[ "singer" ]	What is the total number of singers?	SELECT count(*) FROM singer	easy
2	concert_singer	[ "singer" ]	Show name, country, age for all singers ordered by age from the oldest to the youngest.	SELECT name , country , age FROM singer ORDER BY age DESC	medium
3	concert_singer	[ "singer" ]	What are the names, countries, and ages for every singer in descending order of age?	SELECT name , country , age FROM singer ORDER BY age DESC	medium
4	concert_singer	[ "singer" ]	What is the average, minimum, and maximum age of all singers from France?	SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'	medium
5	concert_singer	[ "singer" ]	What is the average, minimum, and maximum age for all French singers?	SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'	medium
6	concert_singer	[ "singer" ]	Show the name and the release year of the song by the youngest singer.	SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1	medium
7	concert_singer	[ "singer" ]	What are the names and release years for all the songs of the youngest singer?	SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1	medium
8	concert_singer	[ "singer" ]	What are all distinct countries where singers above age 20 are from?	SELECT DISTINCT country FROM singer WHERE age > 20	easy
9	concert_singer	[ "singer" ]	What are the different countries with singers above age 20?	SELECT DISTINCT country FROM singer WHERE age > 20	easy
10	concert_singer	[ "singer" ]	Show all countries and the number of singers in each country.	SELECT country , count(*) FROM singer GROUP BY country	medium
11	concert_singer	[ "singer" ]	How many singers are from each country?	SELECT country , count(*) FROM singer GROUP BY country	medium
12	concert_singer	[ "singer" ]	List all song names by singers above the average age.	SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)	hard
13	concert_singer	[ "singer" ]	What are all the song names by singers who are older than average?	SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)	hard
14	concert_singer	[ "stadium" ]	Show location and name for all stadiums with a capacity between 5000 and 10000.	SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000	medium
15	concert_singer	[ "stadium" ]	What are the locations and names of all stations with capacity between 5000 and 10000?	SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000	medium
16	concert_singer	[ "stadium" ]	What is the maximum capacity and the average of all stadiums ?	select max(capacity), average from stadium	medium
17	concert_singer	[ "stadium" ]	What is the average and maximum capacities for all stadiums ?	select avg(capacity) , max(capacity) from stadium	medium
18	concert_singer	[ "stadium" ]	What is the name and capacity for the stadium with highest average attendance?	SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1	medium
19	concert_singer	[ "stadium" ]	What is the name and capacity for the stadium with the highest average attendance?	SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1	medium
20	concert_singer	[ "concert" ]	How many concerts are there in year 2014 or 2015?	SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015	medium
21	concert_singer	[ "concert" ]	How many concerts occurred in 2014 or 2015?	SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015	medium
22	concert_singer	[ "stadium", "concert" ]	Show the stadium name and the number of concerts in each stadium.	SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id	medium
23	concert_singer	[ "stadium", "concert" ]	For each stadium, how many concerts play there?	SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id	medium
24	concert_singer	[ "stadium", "concert" ]	Show the stadium name and capacity with most number of concerts in year 2014 or after.	SELECT T2.name , T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY count(*) DESC LIMIT 1	extra
25	concert_singer	[ "stadium", "concert" ]	What is the name and capacity of the stadium with the most concerts after 2013 ?	select t2.name , t2.capacity from concert as t1 join stadium as t2 on t1.stadium_id = t2.stadium_id where t1.year > 2013 group by t2.stadium_id order by count(*) desc limit 1	extra
26	concert_singer	[ "concert" ]	Which year has most number of concerts?	SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1	hard
27	concert_singer	[ "concert" ]	What is the year that had the most concerts?	SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1	hard
28	concert_singer	[ "stadium", "concert" ]	Show the stadium names without any concert.	SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)	hard
29	concert_singer	[ "stadium", "concert" ]	What are the names of the stadiums without any concerts?	SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)	hard
30	concert_singer	[ "singer" ]	Show countries where a singer above age 40 and a singer below 30 are from.	SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30	hard
31	concert_singer	[ "stadium", "concert" ]	Show names for all stadiums except for stadiums having a concert in year 2014.	SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014	hard
32	concert_singer	[ "stadium", "concert" ]	What are the names of all stadiums that did not have a concert in 2014?	SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014	hard
33	concert_singer	[ "concert", "singer_in_concert" ]	Show the name and theme for all concerts and the number of singers in each concert.	SELECT T2.concert_name , T2.theme , count(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id	medium
34	concert_singer	[ "concert", "singer_in_concert" ]	What are the names , themes , and number of singers for every concert ?	select t2.concert_name , t2.theme , count(*) from singer_in_concert as t1 join concert as t2 on t1.concert_id = t2.concert_id group by t2.concert_id	medium
35	concert_singer	[ "singer", "singer_in_concert" ]	List singer names and number of concerts for each singer.	SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id	medium
36	concert_singer	[ "singer", "singer_in_concert" ]	What are the names of the singers and number of concerts for each person?	SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id	medium
37	concert_singer	[ "singer", "concert", "singer_in_concert" ]	List all singer names in concerts in year 2014.	SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014	hard
38	concert_singer	[ "singer", "concert", "singer_in_concert" ]	What are the names of the singers who performed in a concert in 2014?	SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014	hard
39	concert_singer	[ "singer" ]	what is the name and nation of the singer who have a song having 'Hey' in its name?	SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'	medium
40	concert_singer	[ "singer" ]	What is the name and country of origin of every singer who has a song with the word 'Hey' in its title?	SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'	medium
41	concert_singer	[ "stadium", "concert" ]	Find the name and location of the stadiums which some concerts happened in the years of both 2014 and 2015.	SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015	extra
42	concert_singer	[ "stadium", "concert" ]	What are the names and locations of the stadiums that had concerts that occurred in both 2014 and 2015?	SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015	extra
43	concert_singer	[ "stadium", "concert" ]	Find the number of concerts happened in the stadium with the highest capacity .	select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)	hard
44	concert_singer	[ "stadium", "concert" ]	What are the number of concerts that occurred in the stadium with the largest capacity ?	select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)	hard
45	pets_1	[ "pets" ]	Find the number of pets whose weight is heavier than 10.	SELECT count(*) FROM pets WHERE weight > 10	easy
46	pets_1	[ "pets" ]	How many pets have a greater weight than 10?	SELECT count(*) FROM pets WHERE weight > 10	easy
47	pets_1	[ "pets" ]	Find the weight of the youngest dog.	SELECT weight FROM pets ORDER BY pet_age LIMIT 1	medium
48	pets_1	[ "pets" ]	How much does the youngest dog weigh?	SELECT weight FROM pets ORDER BY pet_age LIMIT 1	medium
49	pets_1	[ "pets" ]	Find the maximum weight for each type of pet. List the maximum weight and pet type.	SELECT max(weight) , petType FROM pets GROUP BY petType	medium
50	pets_1	[ "pets" ]	List the maximum weight and type for each type of pet.	SELECT max(weight) , petType FROM pets GROUP BY petType	medium
51	pets_1	[ "has_pet", "student" ]	Find number of pets owned by students who are older than 20.	SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20	medium
52	pets_1	[ "has_pet", "student" ]	How many pets are owned by students that have an age greater than 20?	SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20	medium
53	pets_1	[ "has_pet", "pets", "student" ]	Find the number of dog pets that are raised by female students (with sex F).	SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'	hard
54	pets_1	[ "has_pet", "pets", "student" ]	How many dog pets are raised by female students?	SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'	hard
55	pets_1	[ "pets" ]	Find the number of distinct type of pets.	SELECT count(DISTINCT pettype) FROM pets	easy
56	pets_1	[ "pets" ]	How many different types of pet are there?	SELECT count(DISTINCT pettype) FROM pets	easy
57	pets_1	[ "has_pet", "pets", "student" ]	Find the first name of students who have cat or dog pet.	SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'	extra
58	pets_1	[ "has_pet", "pets", "student" ]	What are the first names of every student who has a cat or dog as a pet?	SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'	extra
59	pets_1	[ "has_pet", "pets", "student" ]	Find the first name of students who have both cat and dog pets .	select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'cat' intersect select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'dog'	extra
60	pets_1	[ "has_pet", "pets", "student" ]	What are the students' first names who have both cats and dogs as pets?	SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog'	extra
61	pets_1	[ "has_pet", "pets", "student" ]	Find the major and age of students who do not have a cat pet.	SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')	extra
62	pets_1	[ "has_pet", "pets", "student" ]	What major is every student who does not own a cat as a pet, and also how old are they?	SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')	extra
63	pets_1	[ "has_pet", "pets", "student" ]	Find the id of students who do not have a cat pet.	SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'	hard
64	pets_1	[ "has_pet", "pets", "student" ]	What are the ids of the students who do not own cats as pets?	SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'	hard
65	pets_1	[ "has_pet", "pets", "student" ]	Find the first name and age of students who have a dog but do not have a cat as a pet.	SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')	extra
66	pets_1	[ "has_pet", "pets", "student" ]	What is the first name of every student who has a dog but does not have a cat?	SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')	extra
67	pets_1	[ "pets" ]	Find the type and weight of the youngest pet.	SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1	medium
68	pets_1	[ "pets" ]	What type of pet is the youngest animal, and how much does it weigh?	SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1	medium
69	pets_1	[ "pets" ]	Find the id and weight of all pets whose age is older than 1.	SELECT petid , weight FROM pets WHERE pet_age > 1	medium
70	pets_1	[ "pets" ]	What is the id and weight of every pet who is older than 1?	SELECT petid , weight FROM pets WHERE pet_age > 1	medium
71	pets_1	[ "pets" ]	Find the average and maximum age for each type of pet.	SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype	medium
72	pets_1	[ "pets" ]	What is the average and maximum age for each pet type?	SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype	medium
73	pets_1	[ "pets" ]	Find the average weight for each pet type.	SELECT avg(weight) , pettype FROM pets GROUP BY pettype	medium
74	pets_1	[ "pets" ]	What is the average weight for each type of pet?	SELECT avg(weight) , pettype FROM pets GROUP BY pettype	medium
75	pets_1	[ "has_pet", "student" ]	Find the first name and age of students who have a pet.	SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid	medium
76	pets_1	[ "has_pet", "student" ]	What are the different first names and ages of the students who do have pets?	SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid	medium
77	pets_1	[ "has_pet", "student" ]	Find the id of the pet owned by student whose last name is ‘Smith’.	SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'	medium
78	pets_1	[ "has_pet", "student" ]	What is the id of the pet owned by the student whose last name is 'Smith'?	SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'	medium
79	pets_1	[ "has_pet", "student" ]	Find the number of pets for each student who has any pet and student id.	SELECT count(*) , T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid	medium
80	pets_1	[ "has_pet", "student" ]	For students who have pets , how many pets does each student have ? list their ids instead of names .	select count(*) , t1.stuid from student as t1 join has_pet as t2 on t1.stuid = t2.stuid group by t1.stuid	medium
81	pets_1	[ "has_pet", "student" ]	Find the first name and gender of student who have more than one pet.	SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1	medium
82	pets_1	[ "has_pet", "student" ]	What is the first name and gender of the all the students who have more than one pet?	SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1	medium
83	pets_1	[ "has_pet", "pets", "student" ]	Find the last name of the student who has a cat that is age 3.	SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'	hard
84	pets_1	[ "has_pet", "pets", "student" ]	What is the last name of the student who has a cat that is 3 years old?	SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'	hard
85	pets_1	[ "has_pet", "student" ]	Find the average age of students who do not have any pet .	select avg(age) from student where stuid not in (select stuid from has_pet)	extra
86	pets_1	[ "has_pet", "student" ]	What is the average age for all students who do not own any pets ?	select avg(age) from student where stuid not in (select stuid from has_pet)	extra
87	car_1	[ "CONTINENTS" ]	How many continents are there?	SELECT count(*) FROM CONTINENTS;	easy
88	car_1	[ "CONTINENTS" ]	What is the number of continents?	SELECT count(*) FROM CONTINENTS;	easy
89	car_1	[ "COUNTRIES", "CONTINENTS" ]	How many countries does each continent have? List the continent id, continent name and the number of countries.	SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;	medium
90	car_1	[ "COUNTRIES", "CONTINENTS" ]	For each continent, list its id, name, and how many countries it has?	SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;	medium
91	car_1	[ "COUNTRIES" ]	How many countries are listed?	SELECT count(*) FROM COUNTRIES;	easy
92	car_1	[ "COUNTRIES" ]	How many countries exist?	SELECT count(*) FROM COUNTRIES;	easy
93	car_1	[ "MODEL_LIST", "CAR_MAKERS" ]	How many models does each car maker produce? List maker full name, id and the number.	SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;	medium
94	car_1	[ "MODEL_LIST", "CAR_MAKERS" ]	What is the full name of each car maker, along with its id and how many models it produces?	SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;	medium
95	car_1	[ "CARS_DATA", "CAR_NAMES" ]	Which model of the car has the minimum horsepower?	SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;	hard
96	car_1	[ "CARS_DATA", "CAR_NAMES" ]	What is the model of the car with the smallest amount of horsepower?	SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;	hard
97	car_1	[ "CAR_NAMES", "CARS_DATA" ]	Find the model of the car whose weight is below the average weight.	SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)	extra
98	car_1	[ "CAR_NAMES", "CARS_DATA" ]	What is the model for the car with a weight smaller than the average?	SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)	extra
99	car_1	[ "CAR_NAMES", "MODEL_LIST", "CAR_MAKERS", "CARS_DATA" ]	Find the name of the makers that produced some cars in the year of 1970?	SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970';	extra

0

concert_singer

[ "singer" ]

How many singers do we have?

SELECT count(*) FROM singer

easy

1

concert_singer

[ "singer" ]

What is the total number of singers?

SELECT count(*) FROM singer

easy

2

concert_singer

[ "singer" ]

Show name, country, age for all singers ordered by age from the oldest to the youngest.

SELECT name , country , age FROM singer ORDER BY age DESC

medium

3

concert_singer

[ "singer" ]

What are the names, countries, and ages for every singer in descending order of age?

SELECT name , country , age FROM singer ORDER BY age DESC

medium

4

concert_singer

[ "singer" ]

What is the average, minimum, and maximum age of all singers from France?

SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'

medium

5

concert_singer

[ "singer" ]

What is the average, minimum, and maximum age for all French singers?

SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'

medium

6

concert_singer

[ "singer" ]

Show the name and the release year of the song by the youngest singer.

SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1

medium

7

concert_singer

[ "singer" ]

What are the names and release years for all the songs of the youngest singer?

SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1

medium

8

concert_singer

[ "singer" ]

What are all distinct countries where singers above age 20 are from?

SELECT DISTINCT country FROM singer WHERE age > 20

easy

9

concert_singer

[ "singer" ]

What are the different countries with singers above age 20?

SELECT DISTINCT country FROM singer WHERE age > 20

easy

10

concert_singer

[ "singer" ]

Show all countries and the number of singers in each country.

SELECT country , count(*) FROM singer GROUP BY country

medium

11

concert_singer

[ "singer" ]

How many singers are from each country?

SELECT country , count(*) FROM singer GROUP BY country

medium

12

concert_singer

[ "singer" ]

List all song names by singers above the average age.

SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)

hard

13

concert_singer

[ "singer" ]

What are all the song names by singers who are older than average?

SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)

hard

14

concert_singer

[ "stadium" ]

Show location and name for all stadiums with a capacity between 5000 and 10000.

SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000

medium

15

concert_singer

[ "stadium" ]

What are the locations and names of all stations with capacity between 5000 and 10000?

SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000

medium

16

concert_singer

[ "stadium" ]

What is the maximum capacity and the average of all stadiums ?

select max(capacity), average from stadium

medium

17

concert_singer

[ "stadium" ]

What is the average and maximum capacities for all stadiums ?

select avg(capacity) , max(capacity) from stadium

medium

18

concert_singer

[ "stadium" ]

What is the name and capacity for the stadium with highest average attendance?

SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1

medium

19

concert_singer

[ "stadium" ]

What is the name and capacity for the stadium with the highest average attendance?

SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1

medium

20

concert_singer

[ "concert" ]

How many concerts are there in year 2014 or 2015?

SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015

medium

21

concert_singer

[ "concert" ]

How many concerts occurred in 2014 or 2015?

SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015

medium

22

concert_singer

[ "stadium", "concert" ]

Show the stadium name and the number of concerts in each stadium.

SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id

medium

23

concert_singer

[ "stadium", "concert" ]

For each stadium, how many concerts play there?

SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id

medium

24

concert_singer

[ "stadium", "concert" ]

Show the stadium name and capacity with most number of concerts in year 2014 or after.

SELECT T2.name , T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY count(*) DESC LIMIT 1

extra

25

concert_singer

[ "stadium", "concert" ]

What is the name and capacity of the stadium with the most concerts after 2013 ?

select t2.name , t2.capacity from concert as t1 join stadium as t2 on t1.stadium_id = t2.stadium_id where t1.year > 2013 group by t2.stadium_id order by count(*) desc limit 1

extra

26

concert_singer

[ "concert" ]

Which year has most number of concerts?

SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1

hard

27

concert_singer

[ "concert" ]

What is the year that had the most concerts?

SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1

hard

28

concert_singer

[ "stadium", "concert" ]

Show the stadium names without any concert.

SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)

hard

29

concert_singer

[ "stadium", "concert" ]

What are the names of the stadiums without any concerts?

SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)

hard

30

concert_singer

[ "singer" ]

Show countries where a singer above age 40 and a singer below 30 are from.

SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30

hard

31

concert_singer

[ "stadium", "concert" ]

Show names for all stadiums except for stadiums having a concert in year 2014.

SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014

hard

32

concert_singer

[ "stadium", "concert" ]

What are the names of all stadiums that did not have a concert in 2014?

SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014

hard

33

concert_singer

[ "concert", "singer_in_concert" ]

Show the name and theme for all concerts and the number of singers in each concert.

SELECT T2.concert_name , T2.theme , count(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id

medium

34

concert_singer

[ "concert", "singer_in_concert" ]

What are the names , themes , and number of singers for every concert ?

select t2.concert_name , t2.theme , count(*) from singer_in_concert as t1 join concert as t2 on t1.concert_id = t2.concert_id group by t2.concert_id

medium

35

concert_singer

[ "singer", "singer_in_concert" ]

List singer names and number of concerts for each singer.

SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id

medium

36

concert_singer

[ "singer", "singer_in_concert" ]

What are the names of the singers and number of concerts for each person?

SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id

medium

37

concert_singer

[ "singer", "concert", "singer_in_concert" ]

List all singer names in concerts in year 2014.

SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014

hard

38

concert_singer

[ "singer", "concert", "singer_in_concert" ]

What are the names of the singers who performed in a concert in 2014?

SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014

hard

39

concert_singer

[ "singer" ]

what is the name and nation of the singer who have a song having 'Hey' in its name?

SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'

medium

40

concert_singer

[ "singer" ]

What is the name and country of origin of every singer who has a song with the word 'Hey' in its title?

SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'

medium

41

concert_singer

[ "stadium", "concert" ]

Find the name and location of the stadiums which some concerts happened in the years of both 2014 and 2015.

SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015

extra

42

concert_singer

[ "stadium", "concert" ]

What are the names and locations of the stadiums that had concerts that occurred in both 2014 and 2015?

SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015

extra

43

concert_singer

[ "stadium", "concert" ]

Find the number of concerts happened in the stadium with the highest capacity .

select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)

hard

44

concert_singer

[ "stadium", "concert" ]

What are the number of concerts that occurred in the stadium with the largest capacity ?

select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)

hard

45

pets_1

[ "pets" ]

Find the number of pets whose weight is heavier than 10.

SELECT count(*) FROM pets WHERE weight > 10

easy

46

pets_1

[ "pets" ]

How many pets have a greater weight than 10?

SELECT count(*) FROM pets WHERE weight > 10

easy

47

pets_1

[ "pets" ]

Find the weight of the youngest dog.

SELECT weight FROM pets ORDER BY pet_age LIMIT 1

medium

48

pets_1

[ "pets" ]

How much does the youngest dog weigh?

SELECT weight FROM pets ORDER BY pet_age LIMIT 1

medium

49

pets_1

[ "pets" ]

Find the maximum weight for each type of pet. List the maximum weight and pet type.

SELECT max(weight) , petType FROM pets GROUP BY petType

medium

50

pets_1

[ "pets" ]

List the maximum weight and type for each type of pet.

SELECT max(weight) , petType FROM pets GROUP BY petType

medium

51

pets_1

[ "has_pet", "student" ]

Find number of pets owned by students who are older than 20.

SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20

medium

52

pets_1

[ "has_pet", "student" ]

How many pets are owned by students that have an age greater than 20?

SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20

medium

53

pets_1

[ "has_pet", "pets", "student" ]

Find the number of dog pets that are raised by female students (with sex F).

SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'

hard

54

pets_1

[ "has_pet", "pets", "student" ]

How many dog pets are raised by female students?

SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'

hard

55

pets_1

[ "pets" ]

Find the number of distinct type of pets.

SELECT count(DISTINCT pettype) FROM pets

easy

56

pets_1

[ "pets" ]

How many different types of pet are there?

SELECT count(DISTINCT pettype) FROM pets

easy

57

pets_1

[ "has_pet", "pets", "student" ]

Find the first name of students who have cat or dog pet.

SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'

extra

58

pets_1

[ "has_pet", "pets", "student" ]

What are the first names of every student who has a cat or dog as a pet?

SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'

extra

59

pets_1

[ "has_pet", "pets", "student" ]

Find the first name of students who have both cat and dog pets .

select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'cat' intersect select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'dog'

extra

60

pets_1

[ "has_pet", "pets", "student" ]

What are the students' first names who have both cats and dogs as pets?

SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog'

extra

61

pets_1

[ "has_pet", "pets", "student" ]

Find the major and age of students who do not have a cat pet.

SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')

extra

62

pets_1

[ "has_pet", "pets", "student" ]

What major is every student who does not own a cat as a pet, and also how old are they?

SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')

extra

63

pets_1

[ "has_pet", "pets", "student" ]

Find the id of students who do not have a cat pet.

SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'

hard

64

pets_1

[ "has_pet", "pets", "student" ]

What are the ids of the students who do not own cats as pets?

SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'

hard

65

pets_1

[ "has_pet", "pets", "student" ]

Find the first name and age of students who have a dog but do not have a cat as a pet.

SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')

extra

66

pets_1

[ "has_pet", "pets", "student" ]

What is the first name of every student who has a dog but does not have a cat?

SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')

extra

67

pets_1

[ "pets" ]

Find the type and weight of the youngest pet.

SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1

medium

68

pets_1

[ "pets" ]

What type of pet is the youngest animal, and how much does it weigh?

SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1

medium

69

pets_1

[ "pets" ]

Find the id and weight of all pets whose age is older than 1.

SELECT petid , weight FROM pets WHERE pet_age > 1

medium

70

pets_1

[ "pets" ]

What is the id and weight of every pet who is older than 1?

SELECT petid , weight FROM pets WHERE pet_age > 1

medium

71

pets_1

[ "pets" ]

Find the average and maximum age for each type of pet.

SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype

medium

72

pets_1

[ "pets" ]

What is the average and maximum age for each pet type?

SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype

medium

73

pets_1

[ "pets" ]

Find the average weight for each pet type.

SELECT avg(weight) , pettype FROM pets GROUP BY pettype

medium

74

pets_1

[ "pets" ]

What is the average weight for each type of pet?

SELECT avg(weight) , pettype FROM pets GROUP BY pettype

medium

75

pets_1

[ "has_pet", "student" ]

Find the first name and age of students who have a pet.

SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid

medium

76

pets_1

[ "has_pet", "student" ]

What are the different first names and ages of the students who do have pets?

SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid

medium

77

pets_1

[ "has_pet", "student" ]

Find the id of the pet owned by student whose last name is ‘Smith’.

SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'

medium

78

pets_1

[ "has_pet", "student" ]

What is the id of the pet owned by the student whose last name is 'Smith'?

SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'

medium

79

pets_1

[ "has_pet", "student" ]

Find the number of pets for each student who has any pet and student id.

SELECT count(*) , T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid

medium

80

pets_1

[ "has_pet", "student" ]

For students who have pets , how many pets does each student have ? list their ids instead of names .

select count(*) , t1.stuid from student as t1 join has_pet as t2 on t1.stuid = t2.stuid group by t1.stuid

medium

81

pets_1

[ "has_pet", "student" ]

Find the first name and gender of student who have more than one pet.

SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1

medium

82

pets_1

[ "has_pet", "student" ]

What is the first name and gender of the all the students who have more than one pet?

SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1

medium

83

pets_1

[ "has_pet", "pets", "student" ]

Find the last name of the student who has a cat that is age 3.

SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'

hard

84

pets_1

[ "has_pet", "pets", "student" ]

What is the last name of the student who has a cat that is 3 years old?

SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'

hard

85

pets_1

[ "has_pet", "student" ]

Find the average age of students who do not have any pet .

select avg(age) from student where stuid not in (select stuid from has_pet)

extra

86

pets_1

[ "has_pet", "student" ]

What is the average age for all students who do not own any pets ?

select avg(age) from student where stuid not in (select stuid from has_pet)

extra

87

car_1

[ "CONTINENTS" ]

How many continents are there?

SELECT count(*) FROM CONTINENTS;

easy

88

car_1

[ "CONTINENTS" ]

What is the number of continents?

SELECT count(*) FROM CONTINENTS;

easy

89

car_1

[ "COUNTRIES", "CONTINENTS" ]

How many countries does each continent have? List the continent id, continent name and the number of countries.

SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;

medium

90

car_1

[ "COUNTRIES", "CONTINENTS" ]

For each continent, list its id, name, and how many countries it has?

SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;

medium

91

car_1

[ "COUNTRIES" ]

How many countries are listed?

SELECT count(*) FROM COUNTRIES;

easy

92

car_1

[ "COUNTRIES" ]

How many countries exist?

SELECT count(*) FROM COUNTRIES;

easy

93

car_1

[ "MODEL_LIST", "CAR_MAKERS" ]

How many models does each car maker produce? List maker full name, id and the number.

SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;

medium

94

car_1

[ "MODEL_LIST", "CAR_MAKERS" ]

What is the full name of each car maker, along with its id and how many models it produces?

SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;

medium

95

car_1

[ "CARS_DATA", "CAR_NAMES" ]

Which model of the car has the minimum horsepower?

SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;

hard

96

car_1

[ "CARS_DATA", "CAR_NAMES" ]

What is the model of the car with the smallest amount of horsepower?

SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;

hard

97

car_1

[ "CAR_NAMES", "CARS_DATA" ]

Find the model of the car whose weight is below the average weight.

SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)

extra

98

car_1

[ "CAR_NAMES", "CARS_DATA" ]

What is the model for the car with a weight smaller than the average?

SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)

extra

99

car_1

[ "CAR_NAMES", "MODEL_LIST", "CAR_MAKERS", "CARS_DATA" ]

Find the name of the makers that produced some cars in the year of 1970?

SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970';

extra