query_id
int64 0
1.03k
| database_id
stringclasses 20
values | table_id
listlengths 1
4
| query
stringlengths 18
174
| answer
stringlengths 20
422
| difficulty
stringclasses 4
values |
---|---|---|---|---|---|
0 |
concert_singer
|
[
"singer"
] |
How many singers do we have?
|
SELECT count(*) FROM singer
|
easy
|
1 |
concert_singer
|
[
"singer"
] |
What is the total number of singers?
|
SELECT count(*) FROM singer
|
easy
|
2 |
concert_singer
|
[
"singer"
] |
Show name, country, age for all singers ordered by age from the oldest to the youngest.
|
SELECT name , country , age FROM singer ORDER BY age DESC
|
medium
|
3 |
concert_singer
|
[
"singer"
] |
What are the names, countries, and ages for every singer in descending order of age?
|
SELECT name , country , age FROM singer ORDER BY age DESC
|
medium
|
4 |
concert_singer
|
[
"singer"
] |
What is the average, minimum, and maximum age of all singers from France?
|
SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'
|
medium
|
5 |
concert_singer
|
[
"singer"
] |
What is the average, minimum, and maximum age for all French singers?
|
SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'
|
medium
|
6 |
concert_singer
|
[
"singer"
] |
Show the name and the release year of the song by the youngest singer.
|
SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1
|
medium
|
7 |
concert_singer
|
[
"singer"
] |
What are the names and release years for all the songs of the youngest singer?
|
SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1
|
medium
|
8 |
concert_singer
|
[
"singer"
] |
What are all distinct countries where singers above age 20 are from?
|
SELECT DISTINCT country FROM singer WHERE age > 20
|
easy
|
9 |
concert_singer
|
[
"singer"
] |
What are the different countries with singers above age 20?
|
SELECT DISTINCT country FROM singer WHERE age > 20
|
easy
|
10 |
concert_singer
|
[
"singer"
] |
Show all countries and the number of singers in each country.
|
SELECT country , count(*) FROM singer GROUP BY country
|
medium
|
11 |
concert_singer
|
[
"singer"
] |
How many singers are from each country?
|
SELECT country , count(*) FROM singer GROUP BY country
|
medium
|
12 |
concert_singer
|
[
"singer"
] |
List all song names by singers above the average age.
|
SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)
|
hard
|
13 |
concert_singer
|
[
"singer"
] |
What are all the song names by singers who are older than average?
|
SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)
|
hard
|
14 |
concert_singer
|
[
"stadium"
] |
Show location and name for all stadiums with a capacity between 5000 and 10000.
|
SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000
|
medium
|
15 |
concert_singer
|
[
"stadium"
] |
What are the locations and names of all stations with capacity between 5000 and 10000?
|
SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000
|
medium
|
16 |
concert_singer
|
[
"stadium"
] |
What is the maximum capacity and the average of all stadiums ?
|
select max(capacity), average from stadium
|
medium
|
17 |
concert_singer
|
[
"stadium"
] |
What is the average and maximum capacities for all stadiums ?
|
select avg(capacity) , max(capacity) from stadium
|
medium
|
18 |
concert_singer
|
[
"stadium"
] |
What is the name and capacity for the stadium with highest average attendance?
|
SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1
|
medium
|
19 |
concert_singer
|
[
"stadium"
] |
What is the name and capacity for the stadium with the highest average attendance?
|
SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1
|
medium
|
20 |
concert_singer
|
[
"concert"
] |
How many concerts are there in year 2014 or 2015?
|
SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015
|
medium
|
21 |
concert_singer
|
[
"concert"
] |
How many concerts occurred in 2014 or 2015?
|
SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015
|
medium
|
22 |
concert_singer
|
[
"stadium",
"concert"
] |
Show the stadium name and the number of concerts in each stadium.
|
SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
|
medium
|
23 |
concert_singer
|
[
"stadium",
"concert"
] |
For each stadium, how many concerts play there?
|
SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
|
medium
|
24 |
concert_singer
|
[
"stadium",
"concert"
] |
Show the stadium name and capacity with most number of concerts in year 2014 or after.
|
SELECT T2.name , T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
25 |
concert_singer
|
[
"stadium",
"concert"
] |
What is the name and capacity of the stadium with the most concerts after 2013 ?
|
select t2.name , t2.capacity from concert as t1 join stadium as t2 on t1.stadium_id = t2.stadium_id where t1.year > 2013 group by t2.stadium_id order by count(*) desc limit 1
|
extra
|
26 |
concert_singer
|
[
"concert"
] |
Which year has most number of concerts?
|
SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1
|
hard
|
27 |
concert_singer
|
[
"concert"
] |
What is the year that had the most concerts?
|
SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1
|
hard
|
28 |
concert_singer
|
[
"stadium",
"concert"
] |
Show the stadium names without any concert.
|
SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)
|
hard
|
29 |
concert_singer
|
[
"stadium",
"concert"
] |
What are the names of the stadiums without any concerts?
|
SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)
|
hard
|
30 |
concert_singer
|
[
"singer"
] |
Show countries where a singer above age 40 and a singer below 30 are from.
|
SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30
|
hard
|
31 |
concert_singer
|
[
"stadium",
"concert"
] |
Show names for all stadiums except for stadiums having a concert in year 2014.
|
SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014
|
hard
|
32 |
concert_singer
|
[
"stadium",
"concert"
] |
What are the names of all stadiums that did not have a concert in 2014?
|
SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014
|
hard
|
33 |
concert_singer
|
[
"concert",
"singer_in_concert"
] |
Show the name and theme for all concerts and the number of singers in each concert.
|
SELECT T2.concert_name , T2.theme , count(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id
|
medium
|
34 |
concert_singer
|
[
"concert",
"singer_in_concert"
] |
What are the names , themes , and number of singers for every concert ?
|
select t2.concert_name , t2.theme , count(*) from singer_in_concert as t1 join concert as t2 on t1.concert_id = t2.concert_id group by t2.concert_id
|
medium
|
35 |
concert_singer
|
[
"singer",
"singer_in_concert"
] |
List singer names and number of concerts for each singer.
|
SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
|
medium
|
36 |
concert_singer
|
[
"singer",
"singer_in_concert"
] |
What are the names of the singers and number of concerts for each person?
|
SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
|
medium
|
37 |
concert_singer
|
[
"singer",
"concert",
"singer_in_concert"
] |
List all singer names in concerts in year 2014.
|
SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
|
hard
|
38 |
concert_singer
|
[
"singer",
"concert",
"singer_in_concert"
] |
What are the names of the singers who performed in a concert in 2014?
|
SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
|
hard
|
39 |
concert_singer
|
[
"singer"
] |
what is the name and nation of the singer who have a song having 'Hey' in its name?
|
SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'
|
medium
|
40 |
concert_singer
|
[
"singer"
] |
What is the name and country of origin of every singer who has a song with the word 'Hey' in its title?
|
SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'
|
medium
|
41 |
concert_singer
|
[
"stadium",
"concert"
] |
Find the name and location of the stadiums which some concerts happened in the years of both 2014 and 2015.
|
SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015
|
extra
|
42 |
concert_singer
|
[
"stadium",
"concert"
] |
What are the names and locations of the stadiums that had concerts that occurred in both 2014 and 2015?
|
SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015
|
extra
|
43 |
concert_singer
|
[
"stadium",
"concert"
] |
Find the number of concerts happened in the stadium with the highest capacity .
|
select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)
|
hard
|
44 |
concert_singer
|
[
"stadium",
"concert"
] |
What are the number of concerts that occurred in the stadium with the largest capacity ?
|
select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)
|
hard
|
45 |
pets_1
|
[
"pets"
] |
Find the number of pets whose weight is heavier than 10.
|
SELECT count(*) FROM pets WHERE weight > 10
|
easy
|
46 |
pets_1
|
[
"pets"
] |
How many pets have a greater weight than 10?
|
SELECT count(*) FROM pets WHERE weight > 10
|
easy
|
47 |
pets_1
|
[
"pets"
] |
Find the weight of the youngest dog.
|
SELECT weight FROM pets ORDER BY pet_age LIMIT 1
|
medium
|
48 |
pets_1
|
[
"pets"
] |
How much does the youngest dog weigh?
|
SELECT weight FROM pets ORDER BY pet_age LIMIT 1
|
medium
|
49 |
pets_1
|
[
"pets"
] |
Find the maximum weight for each type of pet. List the maximum weight and pet type.
|
SELECT max(weight) , petType FROM pets GROUP BY petType
|
medium
|
50 |
pets_1
|
[
"pets"
] |
List the maximum weight and type for each type of pet.
|
SELECT max(weight) , petType FROM pets GROUP BY petType
|
medium
|
51 |
pets_1
|
[
"has_pet",
"student"
] |
Find number of pets owned by students who are older than 20.
|
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
|
medium
|
52 |
pets_1
|
[
"has_pet",
"student"
] |
How many pets are owned by students that have an age greater than 20?
|
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
|
medium
|
53 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the number of dog pets that are raised by female students (with sex F).
|
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
|
hard
|
54 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
How many dog pets are raised by female students?
|
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
|
hard
|
55 |
pets_1
|
[
"pets"
] |
Find the number of distinct type of pets.
|
SELECT count(DISTINCT pettype) FROM pets
|
easy
|
56 |
pets_1
|
[
"pets"
] |
How many different types of pet are there?
|
SELECT count(DISTINCT pettype) FROM pets
|
easy
|
57 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the first name of students who have cat or dog pet.
|
SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
|
extra
|
58 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
What are the first names of every student who has a cat or dog as a pet?
|
SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
|
extra
|
59 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the first name of students who have both cat and dog pets .
|
select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'cat' intersect select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'dog'
|
extra
|
60 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
What are the students' first names who have both cats and dogs as pets?
|
SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog'
|
extra
|
61 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the major and age of students who do not have a cat pet.
|
SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
|
extra
|
62 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
What major is every student who does not own a cat as a pet, and also how old are they?
|
SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
|
extra
|
63 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the id of students who do not have a cat pet.
|
SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
|
hard
|
64 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
What are the ids of the students who do not own cats as pets?
|
SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
|
hard
|
65 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the first name and age of students who have a dog but do not have a cat as a pet.
|
SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
|
extra
|
66 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
What is the first name of every student who has a dog but does not have a cat?
|
SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
|
extra
|
67 |
pets_1
|
[
"pets"
] |
Find the type and weight of the youngest pet.
|
SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1
|
medium
|
68 |
pets_1
|
[
"pets"
] |
What type of pet is the youngest animal, and how much does it weigh?
|
SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1
|
medium
|
69 |
pets_1
|
[
"pets"
] |
Find the id and weight of all pets whose age is older than 1.
|
SELECT petid , weight FROM pets WHERE pet_age > 1
|
medium
|
70 |
pets_1
|
[
"pets"
] |
What is the id and weight of every pet who is older than 1?
|
SELECT petid , weight FROM pets WHERE pet_age > 1
|
medium
|
71 |
pets_1
|
[
"pets"
] |
Find the average and maximum age for each type of pet.
|
SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype
|
medium
|
72 |
pets_1
|
[
"pets"
] |
What is the average and maximum age for each pet type?
|
SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype
|
medium
|
73 |
pets_1
|
[
"pets"
] |
Find the average weight for each pet type.
|
SELECT avg(weight) , pettype FROM pets GROUP BY pettype
|
medium
|
74 |
pets_1
|
[
"pets"
] |
What is the average weight for each type of pet?
|
SELECT avg(weight) , pettype FROM pets GROUP BY pettype
|
medium
|
75 |
pets_1
|
[
"has_pet",
"student"
] |
Find the first name and age of students who have a pet.
|
SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid
|
medium
|
76 |
pets_1
|
[
"has_pet",
"student"
] |
What are the different first names and ages of the students who do have pets?
|
SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid
|
medium
|
77 |
pets_1
|
[
"has_pet",
"student"
] |
Find the id of the pet owned by student whose last name is ‘Smith’.
|
SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
|
medium
|
78 |
pets_1
|
[
"has_pet",
"student"
] |
What is the id of the pet owned by the student whose last name is 'Smith'?
|
SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
|
medium
|
79 |
pets_1
|
[
"has_pet",
"student"
] |
Find the number of pets for each student who has any pet and student id.
|
SELECT count(*) , T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid
|
medium
|
80 |
pets_1
|
[
"has_pet",
"student"
] |
For students who have pets , how many pets does each student have ? list their ids instead of names .
|
select count(*) , t1.stuid from student as t1 join has_pet as t2 on t1.stuid = t2.stuid group by t1.stuid
|
medium
|
81 |
pets_1
|
[
"has_pet",
"student"
] |
Find the first name and gender of student who have more than one pet.
|
SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1
|
medium
|
82 |
pets_1
|
[
"has_pet",
"student"
] |
What is the first name and gender of the all the students who have more than one pet?
|
SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1
|
medium
|
83 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
Find the last name of the student who has a cat that is age 3.
|
SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
|
hard
|
84 |
pets_1
|
[
"has_pet",
"pets",
"student"
] |
What is the last name of the student who has a cat that is 3 years old?
|
SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
|
hard
|
85 |
pets_1
|
[
"has_pet",
"student"
] |
Find the average age of students who do not have any pet .
|
select avg(age) from student where stuid not in (select stuid from has_pet)
|
extra
|
86 |
pets_1
|
[
"has_pet",
"student"
] |
What is the average age for all students who do not own any pets ?
|
select avg(age) from student where stuid not in (select stuid from has_pet)
|
extra
|
87 |
car_1
|
[
"CONTINENTS"
] |
How many continents are there?
|
SELECT count(*) FROM CONTINENTS;
|
easy
|
88 |
car_1
|
[
"CONTINENTS"
] |
What is the number of continents?
|
SELECT count(*) FROM CONTINENTS;
|
easy
|
89 |
car_1
|
[
"COUNTRIES",
"CONTINENTS"
] |
How many countries does each continent have? List the continent id, continent name and the number of countries.
|
SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;
|
medium
|
90 |
car_1
|
[
"COUNTRIES",
"CONTINENTS"
] |
For each continent, list its id, name, and how many countries it has?
|
SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;
|
medium
|
91 |
car_1
|
[
"COUNTRIES"
] |
How many countries are listed?
|
SELECT count(*) FROM COUNTRIES;
|
easy
|
92 |
car_1
|
[
"COUNTRIES"
] |
How many countries exist?
|
SELECT count(*) FROM COUNTRIES;
|
easy
|
93 |
car_1
|
[
"MODEL_LIST",
"CAR_MAKERS"
] |
How many models does each car maker produce? List maker full name, id and the number.
|
SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;
|
medium
|
94 |
car_1
|
[
"MODEL_LIST",
"CAR_MAKERS"
] |
What is the full name of each car maker, along with its id and how many models it produces?
|
SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;
|
medium
|
95 |
car_1
|
[
"CARS_DATA",
"CAR_NAMES"
] |
Which model of the car has the minimum horsepower?
|
SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;
|
hard
|
96 |
car_1
|
[
"CARS_DATA",
"CAR_NAMES"
] |
What is the model of the car with the smallest amount of horsepower?
|
SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;
|
hard
|
97 |
car_1
|
[
"CAR_NAMES",
"CARS_DATA"
] |
Find the model of the car whose weight is below the average weight.
|
SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)
|
extra
|
98 |
car_1
|
[
"CAR_NAMES",
"CARS_DATA"
] |
What is the model for the car with a weight smaller than the average?
|
SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)
|
extra
|
99 |
car_1
|
[
"CAR_NAMES",
"MODEL_LIST",
"CAR_MAKERS",
"CARS_DATA"
] |
Find the name of the makers that produced some cars in the year of 1970?
|
SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970';
|
extra
|
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