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MilesCranmer
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Describe speedup on second PySR calls
Browse files- README.md +4 -0
- docs/start.md +4 -0
README.md
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@@ -124,6 +124,10 @@ which gives:
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x0**2 + 2.000016*cos(x3) - 1.9999845
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```
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One can also use `best_tex` to get the LaTeX form,
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or `best_callable` to get a function you can call.
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This uses a score which balances complexity and error;
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x0**2 + 2.000016*cos(x3) - 1.9999845
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```
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The second and additional calls of `pysr` will be significantly
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faster in startup time, since the first call to Julia will compile
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and cache functions from the symbolic regression backend.
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One can also use `best_tex` to get the LaTeX form,
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or `best_callable` to get a function you can call.
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This uses a score which balances complexity and error;
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docs/start.md
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@@ -42,6 +42,10 @@ which gives:
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x0**2 + 2.000016*cos(x3) - 1.9999845
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```
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One can also use `best_tex` to get the LaTeX form,
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or `best_callable` to get a function you can call.
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This uses a score which balances complexity and error;
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x0**2 + 2.000016*cos(x3) - 1.9999845
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```
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+
The second and additional calls of `pysr` will be significantly
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+
faster in startup time, since the first call to Julia will compile
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+
and cache functions from the symbolic regression backend.
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+
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One can also use `best_tex` to get the LaTeX form,
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or `best_callable` to get a function you can call.
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This uses a score which balances complexity and error;
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