# Copyright (C) 2021-2024, Mindee. # This program is licensed under the Apache License 2.0. # See LICENSE or go to for full license details. import multiprocessing as mp import os from multiprocessing.pool import ThreadPool from typing import Any, Callable, Iterable, Iterator, Optional from doctr.file_utils import ENV_VARS_TRUE_VALUES __all__ = ["multithread_exec"] def multithread_exec(func: Callable[[Any], Any], seq: Iterable[Any], threads: Optional[int] = None) -> Iterator[Any]: """Execute a given function in parallel for each element of a given sequence >>> from doctr.utils.multithreading import multithread_exec >>> entries = [1, 4, 8] >>> results = multithread_exec(lambda x: x ** 2, entries) Args: ---- func: function to be executed on each element of the iterable seq: iterable threads: number of workers to be used for multiprocessing Returns: ------- iterator of the function's results using the iterable as inputs Notes: ----- This function uses ThreadPool from multiprocessing package, which uses `/dev/shm` directory for shared memory. If you do not have write permissions for this directory (if you run `doctr` on AWS Lambda for instance), you might want to disable multiprocessing. To achieve that, set 'DOCTR_MULTIPROCESSING_DISABLE' to 'TRUE'. """ threads = threads if isinstance(threads, int) else min(16, mp.cpu_count()) # Single-thread if threads < 2 or os.environ.get("DOCTR_MULTIPROCESSING_DISABLE", "").upper() in ENV_VARS_TRUE_VALUES: results = map(func, seq) # Multi-threading else: with ThreadPool(threads) as tp: # ThreadPool's map function returns a list, but seq could be of a different type # That's why wrapping result in map to return iterator results = map(lambda x: x, tp.map(func, seq)) # noqa: C417 return results