MinerU / magic_pdf /para /commons.py
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import sys
from magic_pdf.libs.commons import fitz
from termcolor import cprint
if sys.version_info[0] >= 3:
sys.stdout.reconfigure(encoding="utf-8") # type: ignore
def open_pdf(pdf_path):
try:
pdf_document = fitz.open(pdf_path) # type: ignore
return pdf_document
except Exception as e:
print(f"无法打开PDF文件:{pdf_path}。原因是:{e}")
raise e
def print_green_on_red(text):
cprint(text, "green", "on_red", attrs=["bold"], end="\n\n")
def print_green(text):
print()
cprint(text, "green", attrs=["bold"], end="\n\n")
def print_red(text):
print()
cprint(text, "red", attrs=["bold"], end="\n\n")
def print_yellow(text):
print()
cprint(text, "yellow", attrs=["bold"], end="\n\n")
def safe_get(dict_obj, key, default):
val = dict_obj.get(key)
if val is None:
return default
else:
return val
def is_bbox_overlap(bbox1, bbox2):
"""
This function checks if bbox1 and bbox2 overlap or not
Parameters
----------
bbox1 : list
bbox1
bbox2 : list
bbox2
Returns
-------
bool
True if bbox1 and bbox2 overlap, else False
"""
x0_1, y0_1, x1_1, y1_1 = bbox1
x0_2, y0_2, x1_2, y1_2 = bbox2
if x0_1 > x1_2 or x0_2 > x1_1:
return False
if y0_1 > y1_2 or y0_2 > y1_1:
return False
return True
def is_in_bbox(bbox1, bbox2):
"""
This function checks if bbox1 is in bbox2
Parameters
----------
bbox1 : list
bbox1
bbox2 : list
bbox2
Returns
-------
bool
True if bbox1 is in bbox2, else False
"""
x0_1, y0_1, x1_1, y1_1 = bbox1
x0_2, y0_2, x1_2, y1_2 = bbox2
if x0_1 >= x0_2 and y0_1 >= y0_2 and x1_1 <= x1_2 and y1_1 <= y1_2:
return True
else:
return False
def calculate_para_bbox(lines):
"""
This function calculates the minimum bbox of the paragraph
Parameters
----------
lines : list
lines
Returns
-------
para_bbox : list
bbox of the paragraph
"""
x0 = min(line["bbox"][0] for line in lines)
y0 = min(line["bbox"][1] for line in lines)
x1 = max(line["bbox"][2] for line in lines)
y1 = max(line["bbox"][3] for line in lines)
return [x0, y0, x1, y1]
def is_line_right_aligned_from_neighbors(curr_line_bbox, prev_line_bbox, next_line_bbox, avg_char_width, direction=2):
"""
This function checks if the line is right aligned from its neighbors
Parameters
----------
curr_line_bbox : list
bbox of the current line
prev_line_bbox : list
bbox of the previous line
next_line_bbox : list
bbox of the next line
avg_char_width : float
average of char widths
direction : int
0 for prev, 1 for next, 2 for both
Returns
-------
bool
True if the line is right aligned from its neighbors, False otherwise.
"""
horizontal_ratio = 0.5
horizontal_thres = horizontal_ratio * avg_char_width
_, _, x1, _ = curr_line_bbox
_, _, prev_x1, _ = prev_line_bbox if prev_line_bbox else (0, 0, 0, 0)
_, _, next_x1, _ = next_line_bbox if next_line_bbox else (0, 0, 0, 0)
if direction == 0:
return abs(x1 - prev_x1) < horizontal_thres
elif direction == 1:
return abs(x1 - next_x1) < horizontal_thres
elif direction == 2:
return abs(x1 - prev_x1) < horizontal_thres and abs(x1 - next_x1) < horizontal_thres
else:
return False
def is_line_left_aligned_from_neighbors(curr_line_bbox, prev_line_bbox, next_line_bbox, avg_char_width, direction=2):
"""
This function checks if the line is left aligned from its neighbors
Parameters
----------
curr_line_bbox : list
bbox of the current line
prev_line_bbox : list
bbox of the previous line
next_line_bbox : list
bbox of the next line
avg_char_width : float
average of char widths
direction : int
0 for prev, 1 for next, 2 for both
Returns
-------
bool
True if the line is left aligned from its neighbors, False otherwise.
"""
horizontal_ratio = 0.5
horizontal_thres = horizontal_ratio * avg_char_width
x0, _, _, _ = curr_line_bbox
prev_x0, _, _, _ = prev_line_bbox if prev_line_bbox else (0, 0, 0, 0)
next_x0, _, _, _ = next_line_bbox if next_line_bbox else (0, 0, 0, 0)
if direction == 0:
return abs(x0 - prev_x0) < horizontal_thres
elif direction == 1:
return abs(x0 - next_x0) < horizontal_thres
elif direction == 2:
return abs(x0 - prev_x0) < horizontal_thres and abs(x0 - next_x0) < horizontal_thres
else:
return False
def end_with_punctuation(line_text):
"""
This function checks if the line ends with punctuation marks
"""
english_end_puncs = [".", "?", "!"]
chinese_end_puncs = ["。", "?", "!"]
end_puncs = english_end_puncs + chinese_end_puncs
last_non_space_char = None
for ch in line_text[::-1]:
if not ch.isspace():
last_non_space_char = ch
break
if last_non_space_char is None:
return False
return last_non_space_char in end_puncs
def is_nested_list(lst):
if isinstance(lst, list):
return any(isinstance(sub, list) for sub in lst)
return False