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import zipfile
import os
def create_zip_archive(directory_to_zip: str) -> str:
"""
Creates a zip archive of the given directory, excluding 'log.txt'.
Returns the path to the zip file, or None if an error occurred.
"""
zip_file_path = os.path.join(os.path.dirname(directory_to_zip), os.path.basename(directory_to_zip) + ".zip")
try:
with zipfile.ZipFile(zip_file_path, 'w', zipfile.ZIP_DEFLATED) as zipf:
for root, _, files in os.walk(directory_to_zip):
for file in files:
if file == "log.txt":
continue # Skip the log file
file_path = os.path.join(root, file)
zipf.write(file_path, os.path.relpath(file_path, directory_to_zip))
return zip_file_path
except Exception as e:
print(f"Error creating zip archive: {e}")
return None
if __name__ == "__main__":
dir_path = os.path.join(os.path.dirname(__file__), '..', 'expert', 'test_data')
zip_path = create_zip_archive(dir_path)
print(f"Zip archive created at: {zip_path}") |