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# Copyright (c) Facebook, Inc. and its affiliates.
import logging
import numpy as np
import pprint
import sys
from collections.abc import Mapping
def print_csv_format(results):
"""
Print main metrics in a format similar to Detectron,
so that they are easy to copypaste into a spreadsheet.
Args:
results (OrderedDict[dict]): task_name -> {metric -> score}
unordered dict can also be printed, but in arbitrary order
"""
assert isinstance(results, Mapping) or not len(results), results
logger = logging.getLogger(__name__)
for task, res in results.items():
if isinstance(res, Mapping):
# Don't print "AP-category" metrics since they are usually not tracked.
important_res = [(k, v) for k, v in res.items() if "-" not in k]
logger.info("copypaste: Task: {}".format(task))
logger.info("copypaste: " + ",".join([k[0] for k in important_res]))
logger.info("copypaste: " + ",".join(["{0:.4f}".format(k[1]) for k in important_res]))
else:
logger.info(f"copypaste: {task}={res}")
def verify_results(cfg, results):
"""
Args:
results (OrderedDict[dict]): task_name -> {metric -> score}
Returns:
bool: whether the verification succeeds or not
"""
expected_results = cfg.TEST.EXPECTED_RESULTS
if not len(expected_results):
return True
ok = True
for task, metric, expected, tolerance in expected_results:
actual = results[task].get(metric, None)
if actual is None:
ok = False
continue
if not np.isfinite(actual):
ok = False
continue
diff = abs(actual - expected)
if diff > tolerance:
ok = False
logger = logging.getLogger(__name__)
if not ok:
logger.error("Result verification failed!")
logger.error("Expected Results: " + str(expected_results))
logger.error("Actual Results: " + pprint.pformat(results))
sys.exit(1)
else:
logger.info("Results verification passed.")
return ok
def flatten_results_dict(results):
"""
Expand a hierarchical dict of scalars into a flat dict of scalars.
If results[k1][k2][k3] = v, the returned dict will have the entry
{"k1/k2/k3": v}.
Args:
results (dict):
"""
r = {}
for k, v in results.items():
if isinstance(v, Mapping):
v = flatten_results_dict(v)
for kk, vv in v.items():
r[k + "/" + kk] = vv
else:
r[k] = v
return r
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