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from re import findall
from pykeyboard import InlineKeyboard
from pyrogram.types import InlineKeyboardButton as kb
# CREDIT WILLIAM BUTCHER BOT
def is_url(text: str) -> bool:
regex = r"""(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]
[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(
\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\
()<>]+\)))*\)|[^\s`!()\[\]{};:'".,<>?«»“”‘’]))""".strip()
return [x[0] for x in findall(regex, str(text))]
def keyboard(buttons_list, row_width: int = 2):
"""
Buttons builder, pass buttons in a list and it will
return pyrogram.types.IKB object
Ex: keyboard([["click here", "https://google.com"]])
if theres, a url, it will make url button, else callback button
"""
buttons = InlineKeyboard(row_width=row_width)
data = [
(
kb(text=str(i[0]), callback_data=str(i[1]))
if not is_url(i[1])
else kb(text=str(i[0]), url=str(i[1]))
)
for i in buttons_list
]
buttons.add(*data)
return buttons
def ikb(data: dict, row_width: int = 2):
"""
Converts a dict to pyrogram buttons
Ex: dict_to_keyboard({"click here": "this is callback data"})
"""
return keyboard(data.items(), row_width=row_width)
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