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iamgojoof6eyes
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37da43b
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Parent(s):
9c0772d
Encountered problem while doing changes `reverted`
Browse files- Powers/utils/kbhelpers.py +14 -37
Powers/utils/kbhelpers.py
CHANGED
@@ -1,42 +1,19 @@
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from re import findall
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from pykeyboard import InlineKeyboard
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from pyrogram.types import InlineKeyboardButton as kb
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# CREDIT WILLIAM BUTCHER BOT
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def is_url(text: str) -> bool:
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regex = r"""(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]
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[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(
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\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\
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()<>]+\)))*\)|[^\s`!()\[\]{};:'".,<>?«»“”‘’]))""".strip()
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return [x[0] for x in findall(regex, str(text))]
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"""
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Buttons builder, pass buttons in a list and it will
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return pyrogram.types.IKB object
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Ex: keyboard([["click here", "https://google.com"]])
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if theres, a url, it will make url button, else callback button
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"""
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buttons = InlineKeyboard(row_width=row_width)
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data = [
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(
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kb(text=str(i[0]), callback_data=str(i[1]))
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if not is_url(i[1])
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else kb(text=str(i[0]), url=str(i[1]))
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)
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for i in buttons_list
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]
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buttons.add(*data)
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return buttons
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def ikb(data: dict, row_width: int = 2):
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"""
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Converts a dict to pyrogram buttons
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Ex: dict_to_keyboard({"click here": "this is callback data"})
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"""
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return keyboard(data.items(), row_width=row_width)
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from pyrogram.types import InlineKeyboardButton, InlineKeyboardMarkup
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def ikb(rows=None):
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if rows is None:
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rows = []
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lines = []
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for row in rows:
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line = []
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for button in row:
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button = btn(*button) # InlineKeyboardButton
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line.append(button)
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lines.append(line)
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return InlineKeyboardMarkup(inline_keyboard=lines)
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def btn(text, value, type="callback_data"):
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return InlineKeyboardButton(text, **{type: value})
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