Update README.md

README.md

@@ -93,4 +93,36 @@ So, there are 15 cows. Now, we can substitute \( K = 15 \) back into the first e
 \[ C = 5 \]
 
 Therefore, there are 5 chickens on Farmer Brown's farm.
+```
+
+To solve the same problem in Chinese.
+```bash
+python rwkv_llama/test_custom_cache_rwkv.py --config_file configs/step_wise/test_hybrid_2_layer_qwenmlp_local.yaml --ckpt_file /home/yueyulin/model/qwen/layer2.pth --input_text "## Question: \n\nFarmer Brown has 20 animals on his farm, all either chickens or cows. They have a total of 70 legs, all together. How many of the animals are chickens? ## Instruction \n\nPlease answer this question by first reasoning and then providing your answer. Please answer it in Chinese."
+...
+...
+user
+## Question: \n\nFarmer Brown has 20 animals on his farm, all either chickens or cows. They have a total of 70 legs, all together. How many of the animals are chickens? ## Instruction \n\nPlease answer this question by first reasoning and then providing your answer. Please answer it in Chinese.
+assistant
+为了解决这个问题，我们可以先设定一些变量。假设鸡的数量为x，牛的数量为y。
+
+根据题目信息，我们有两个方程：
+1. 鸤和牛的总数是20，即 \(x + y = 20\)
+2. 鸤有2条腿，牛有4条腿，总共有70条腿，即 \(2x + 4y = 70\)
+
+接下来，我们可以通过解这个方程组来找到x和y的值。
+
+首先简化第二个方程，除以2得到 \(x + 2y = 35\)。
+
+然后我们用第一个方程减去这个新方程的一部分，即：
+\[ (x + y) - (x + 2y) = 20 - 35 \]
+\[ -y = -15 \]
+\[ y = 15 \]
+
+知道了y（牛的数量）是15，我们可以很容易地求出x（鸡的数量）：
+\[ x + 15 = 20 \]
+\[ x = 5 \]
+
+所以，农民布朗的农场上有5只鸡。
+
+答案：5只鸡。
 ```