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X is a 30 digit number starting with the digit 4 followed by the digit 7 Then the number X 3 will have 90 digits 91 digits 92 digits 93 digits | No Of Digits | 115 |
X is a 30 digit number starting with the digit 4 followed by the digit 7 Then the number X 3 will have 90 digits 91 digits 92 digits 93 digits | No Of Digits | 115 |
X is a 30 digit number starting with the digit 4 followed by the digit 7 Then the number X 3 will have 90 digits 91 digits 92 digits 93 digits | No Of Digits | 115 |
X is a 30 digit number starting with the digit 4 followed by the digit 7 Then the number X 3 will have 90 digits 91 digits 92 digits 93 digits | No Of Digits | 115 |
X is a 30 digit number starting with the digit 4 followed by the digit 7 Then the number X 3 will have 90 digits 91 digits 92 digits 93 digits | No Of Digits | 115 |
X is a 30 digit number starting with the digit 4 followed by the digit 7 Then the number X 3 will have 90 digits 91 digits 92 digits 93 digits | No Of Digits | 115 |
Let N_f and N_p denote the classes of languages accepted by non deterministic finite automata and non deterministic push down automata respectively Let D_f and D_p denote the classes of languages accepted by deterministic finite automata and deterministic push down automata respectively Which one of the following is TRUE D_f subset N_f ext and D_p subset N_p D_f subset N_f ext and D_p N_p D_f N_f ext and D_p N_p D_f N_f ext and D_p subset N_p | Non Determinism | 116 |
Regarding the power of recognition of languages which of the following statements is false The non deterministic finite state automata are equivalent to deterministic finite state automata Non deterministic Push down automata are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Turing machines Multi tape Turing machines are available are equivalent to Single tape Turing machines | Non Determinism | 116 |
Regarding the power of recognition of languages which of the following statements is false The non deterministic finite state automata are equivalent to deterministic finite state automata Non deterministic Push down automata are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Turing machines Multi tape Turing machines are available are equivalent to Single tape Turing machines | Non Determinism | 116 |
Let N_f and N_p denote the classes of languages accepted by non deterministic finite automata and non deterministic push down automata respectively Let D_f and D_p denote the classes of languages accepted by deterministic finite automata and deterministic push down automata respectively Which one of the following is TRUE D_f subset N_f ext and D_p subset N_p D_f subset N_f ext and D_p N_p D_f N_f ext and D_p N_p D_f N_f ext and D_p subset N_p | Non Determinism | 116 |
02 Choose the correct alternatives more than one may be correct and write the corresponding letters only In which of the cases stated below is the following statement true For every non deterministic machine M_ 1 there exists an equivalent deterministic machine M_ 2 recognizing the same language M_ 1 is non deterministic finite automaton M_ 1 is non deterministic PDA M_ 1 is a non deteministic Turing machine For no machines M_ 1 and M_2 the above statement true | Non Determinism | 116 |
Regarding the power of recognition of languages which of the following statements is false The non deterministic finite state automata are equivalent to deterministic finite state automata Non deterministic Push down automata are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Turing machines Multi tape Turing machines are available are equivalent to Single tape Turing machines | Non Determinism | 116 |
Let N_f and N_p denote the classes of languages accepted by non deterministic finite automata and non deterministic push down automata respectively Let D_f and D_p denote the classes of languages accepted by deterministic finite automata and deterministic push down automata respectively Which one of the following is TRUE D_f subset N_f ext and D_p subset N_p D_f subset N_f ext and D_p N_p D_f N_f ext and D_p N_p D_f N_f ext and D_p subset N_p | Non Determinism | 116 |
Let N_f and N_p denote the classes of languages accepted by non deterministic finite automata and non deterministic push down automata respectively Let D_f and D_p denote the classes of languages accepted by deterministic finite automata and deterministic push down automata respectively Which one of the following is TRUE D_f subset N_f ext and D_p subset N_p D_f subset N_f ext and D_p N_p D_f N_f ext and D_p N_p D_f N_f ext and D_p subset N_p | Non Determinism | 116 |
Let N_f and N_p denote the classes of languages accepted by non deterministic finite automata and non deterministic push down automata respectively Let D_f and D_p denote the classes of languages accepted by deterministic finite automata and deterministic push down automata respectively Which one of the following is TRUE D_f subset N_f ext and D_p subset N_p D_f subset N_f ext and D_p N_p D_f N_f ext and D_p N_p D_f N_f ext and D_p subset N_p | Non Determinism | 116 |
02 Choose the correct alternatives more than one may be correct and write the corresponding letters only In which of the cases stated below is the following statement true For every non deterministic machine M_ 1 there exists an equivalent deterministic machine M_ 2 recognizing the same language M_ 1 is non deterministic finite automaton M_ 1 is non deterministic PDA M_ 1 is a non deteministic Turing machine For no machines M_ 1 and M_2 the above statement true | Non Determinism | 116 |
Let N_f and N_p denote the classes of languages accepted by non deterministic finite automata and non deterministic push down automata respectively Let D_f and D_p denote the classes of languages accepted by deterministic finite automata and deterministic push down automata respectively Which one of the following is TRUE D_f subset N_f ext and D_p subset N_p D_f subset N_f ext and D_p N_p D_f N_f ext and D_p N_p D_f N_f ext and D_p subset N_p | Non Determinism | 116 |
Regarding the power of recognition of languages which of the following statements is false The non deterministic finite state automata are equivalent to deterministic finite state automata Non deterministic Push down automata are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Push down automata Non deterministic Turing machines are equivalent to deterministic Turing machines Multi tape Turing machines are available are equivalent to Single tape Turing machines | Non Determinism | 116 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Let X be a random variable following normal distribution with mean 1 and variance 4 Let Y be another normal variable with mean 1 and variance unknown If P X u2264 1 P Y u2265 2 the standard deviation of Y is 3 2 sqrt 2 1 | Normal Distribution | 117 |
Consider the following floating point number representation 31 24 23 0 Exponent Mantissa The exponent is in 2 u2019s complement representation and mantissa is in the sign magnitude representation The range of the magnitude of the normalized numbers in this representation is 0 to 1 0 5 to 1 2 23 to 0 5 0 5 to left 1 2 23 right | Number Representation | 118 |
Find the sum of the expression frac 1 sqrt 1 sqrt 2 frac 1 sqrt 2 sqrt 3 frac 1 sqrt 3 sqrt 4 frac 1 sqrt 80 sqrt 81 7 8 9 10 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
Find the sum of the expression frac 1 sqrt 1 sqrt 2 frac 1 sqrt 2 sqrt 3 frac 1 sqrt 3 sqrt 4 frac 1 sqrt 80 sqrt 81 7 8 9 10 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
Find the sum of the expression frac 1 sqrt 1 sqrt 2 frac 1 sqrt 2 sqrt 3 frac 1 sqrt 3 sqrt 4 frac 1 sqrt 80 sqrt 81 7 8 9 10 | Number Series | 119 |
The value of sqrt 12 sqrt 12 sqrt 12 dots is 3 464 3 932 4 000 4 444 | Number Series | 119 |
Find the sum of the expression frac 1 sqrt 1 sqrt 2 frac 1 sqrt 2 sqrt 3 frac 1 sqrt 3 sqrt 4 frac 1 sqrt 80 sqrt 81 7 8 9 10 | Number Series | 119 |
Find the sum of the expression frac 1 sqrt 1 sqrt 2 frac 1 sqrt 2 sqrt 3 frac 1 sqrt 3 sqrt 4 frac 1 sqrt 80 sqrt 81 7 8 9 10 | Number Series | 119 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
Consider the quadratic equation x 2 13x 36 0 with coefficients in a base b The solutions of this equation in the same base b are x 5 and x 6 Then b _____ | Number System | 120 |
The minimum positive integer p such that 3 p pmod 17 1 is 5 8 12 16 | Number Theory | 121 |
The number of distinct positive integral factors of 2014 is _____________ | Number Theory | 121 |
Show that the product of the least common multiple and the greatest common divisor of two positive integers a and b is a imes b | Number Theory | 121 |
The number of divisors of 2100 is ____ | Number Theory | 121 |
Show that the product of the least common multiple and the greatest common divisor of two positive integers a and b is a imes b | Number Theory | 121 |
Show that the product of the least common multiple and the greatest common divisor of two positive integers a and b is a imes b | Number Theory | 121 |
Show that the product of the least common multiple and the greatest common divisor of two positive integers a and b is a imes b | Number Theory | 121 |
Show that the product of the least common multiple and the greatest common divisor of two positive integers a and b is a imes b | Number Theory | 121 |
The number of distinct positive integral factors of 2014 is _____________ | Number Theory | 121 |
The number of divisors of 2100 is ____ | Number Theory | 121 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
A CPU has two modes privileged and non privileged In order to change the mode from privileged to non privileged a hardware interrupt is needed a software interrupt is needed a privileged instruction which does not generate an interrupt is needed a non privileged instruction which does not generate an interrupt is needed | Os Protection | 122 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
In the following pairs of OSI protocol layer sub layer and its functionality the INCORRECT pair is Network layer and Routing Data Link Layer and Bit synchronization Transport layer and End to end process communication Medium Access Control sub layer and Channel sharing | Osi Protocol | 123 |
The overlay tree for a program is as shown below What will be the size of the partition in physical memory required to load and run this program 12 KB 14 KB 10 KB 8 KB | Overlay | 124 |
The overlay tree for a program is as shown below What will be the size of the partition in physical memory required to load and run this program 12 KB 14 KB 10 KB 8 KB | Overlay | 124 |
Subsets and Splits