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For this Question: Given a number <b>N</b>, find the count of pairs(x, y) such that the absolute value of sum of x<sup>3</sup> and y<sup>3</sup> is equal to N, i. e |x<sup>3</sup> + y<sup>3</sup>|=N<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pairs()</b> that takes the integer N as parameter
<b>Constraints</b>
1 <= N <= 10<sup>8</sup>Return the <b>count of pairs</b> which satisfies the given condition.Sample Input:-
8
Sample Output:-
2
Explanation:-
The required pairs are (0, -2), (0, 2)
Sample Input:-
3
Sample Output:-
0, I have written this Solution Code:
int Pairs(long N){
int cnt=0;
long int sum=0,a,b,i,j;
for(i=-6000 ;i<=6000;i++){
for(j=i; j<=6000;j++){
a=i*i*i;
b=j*j*j;
if(abs(a+b)==N){
cnt++;}
}
}
return cnt;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: function simpleArrangement(n, arr) {
// write code here
// do not console.log
// return the output as an array
const newArr = []
// for (let i = 0; i < n; i++) {
// arr[i] += (arr[arr[i]] % n) * n;
// }
// Second Step: Divide all values by n
for (let i = 0; i < n; i++) {
newArr.push(arr[arr[i]])
}
return newArr
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: n = int(input())
a = input().split()
print(" ".join(a[int(x)] for x in a)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
String s = br.readLine();
String[] str = s.split(" ");
int arr[] = new int[n];
for(int i=0;i<n;i++){
arr[i]=Integer.parseInt(str[i]);
}
for(int i =0;i<n;i++){
System.out.print(arr[arr[i]]+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
long long n,k;
cin>>n;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
for(int i=0;i<n;i++){
cout<<a[a[i]]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Stickler the thief wants to loot money from a society having n houses in a single line. He is a weird person and follows a certain rule when looting the houses. According to the rule, he will never loot two consecutive houses. At the same time, he wants to maximise the amount he loots. The thief knows which house has what amount of money but is unable to come up with an optimal looting strategy. He asks for your help to find the maximum money he can get if he strictly follows the rule. Each house has a[i] amount of money present in it.The first line of input contains an integer T denoting the number of test cases. T testcases follow. Each test case contains an integer n which denotes the number of houses. Next line contains space separated numbers denoting the amount of money in each house.
1 <= T <= 100
1 <= n <= 10^4
1 <= a[i] <= 10^4For each testcase, in a newline, print an integer which denotes the maximum amount he can take home.Sample Input:
2
6
5 5 10 100 10 5
3
1 2 3
Sample Output:
110
4
Explanation:
Testcase1:
5 + 100 + 5 = 110
Testcase2:
1 + 3 = 4, I have written this Solution Code: def maximize_loot(hval, n):
if n == 0:
return 0
value1 = hval[0]
if n == 1:
return value1
value2 = max(hval[0], hval[1])
if n == 2:
return value2
max_val = None
for i in range(2, n):
max_val = max(hval[i]+value1, value2)
value1 = value2
value2 = max_val
return max_val
t=int(input())
for l in range(0,t):
n=int(input())
arr=input().split()
one=0
two=0
for i in range(0,n):
arr[i]=int(arr[i])
print (maximize_loot(arr,n)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Stickler the thief wants to loot money from a society having n houses in a single line. He is a weird person and follows a certain rule when looting the houses. According to the rule, he will never loot two consecutive houses. At the same time, he wants to maximise the amount he loots. The thief knows which house has what amount of money but is unable to come up with an optimal looting strategy. He asks for your help to find the maximum money he can get if he strictly follows the rule. Each house has a[i] amount of money present in it.The first line of input contains an integer T denoting the number of test cases. T testcases follow. Each test case contains an integer n which denotes the number of houses. Next line contains space separated numbers denoting the amount of money in each house.
1 <= T <= 100
1 <= n <= 10^4
1 <= a[i] <= 10^4For each testcase, in a newline, print an integer which denotes the maximum amount he can take home.Sample Input:
2
6
5 5 10 100 10 5
3
1 2 3
Sample Output:
110
4
Explanation:
Testcase1:
5 + 100 + 5 = 110
Testcase2:
1 + 3 = 4, I have written this Solution Code: #include<bits/stdc++.h>
#define int long long
#define ld long double
#define ll long long
#define pb push_back
#define endl '\n'
#define pi pair<int,int>
#define vi vector<int>
#define all(a) (a).begin(),(a).end()
#define fi first
#define se second
#define sz(x) (int)x.size()
#define hell 1000000007
#define rep(i,a,b) for(int i=a;i<b;i++)
#define dep(i,a,b) for(int i=a;i>=b;i--)
#define lbnd lower_bound
#define ubnd upper_bound
#define bs binary_search
#define mp make_pair
using namespace std;
const int N = 1e4 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N], dp[N][2];
void solve(){
int n; cin >> n;
for(int i = 1; i <= n; i++){
cin >> a[i];
dp[i][0] = max(dp[i-1][1], dp[i-1][0]);
dp[i][1] = a[i] + dp[i-1][0];
}
cout << max(dp[n][1], dp[n][0]) << endl;
}
void testcases(){
int tt = 1;
cin >> tt;
while(tt--){
solve();
}
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
clock_t start = clock();
testcases();
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms: ";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Linear probing is a collision handling technique in hashing. Linear probing says that whenever a collision occurs, search for the immediate next position.
In this question, we'll learn how to fill up the hash table using linear probing technique. You are given hash table size which you'll use to insert elements into their correct position in the hash table i.e.(arr[i]%hashSize). You are also given an array arr of size n. You need to fill up the hash table using linear probing and print the resultant hash table.
Note: All the positions that are unoccupied are denoted by -1 in the hash table.
If there is no more space to insert, then just drop that element.The first line of input contains T denoting the number of test cases. T-test cases follow. Each test case contains 2 lines of input. The first line contains the size of the hashtable and the size of the array. The third line contains elements of the array.
<b>Constraints:-</b>
1 ≤ T ≤ 100
1 ≤ hashSize ≤ 10<sup>3</sup>
1 ≤ sizeOfArray ≤ 10<sup>3</sup>
0 ≤ Array[] ≤ 10<sup>5</sup>
For each testcase, in a new line, print the hash table as shown in example.Input:
2
10 4
4 14 24 44
10 4
9 99 999 9999
Output:
-1 -1 -1 -1 4 14 24 44 -1 -1
99 999 9999 -1 -1 -1 -1 -1 -1 9
Explanation:
Testcase1: 4%10=4. So put 4 in hashtable[4]. Now, 14%10=4, but hashtable[4] is already filled so put 14 in the next slot and so on.
Testcase2: 9%10=9. So put 9 in hashtable[9]. Now, 99%10=9, but hashtable[9] is already filled so put 99 in the (99+1)%10 =0 slot so 99 goes into hashtable[0] and so on., I have written this Solution Code:
// author-Shivam gupta
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define max1 1000001
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
const double pi=acos(-1.0);
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<string> VS;
typedef vector<PII> VII;
typedef vector<VI> VVI;
typedef map<int,int> MPII;
typedef set<int> SETI;
typedef multiset<int> MSETI;
typedef long int li;
typedef unsigned long int uli;
typedef long long int ll;
typedef unsigned long long int ull;
bool isPowerOfTwo (int x)
{
/* First x in the below expression is
for the case when x is 0 */
return x && (!(x&(x-1)));
}
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
ll power(ll x, ll y, ll p)
{
ll res = 1; // Initialize result
x = x % p; // Update x if it is more than or
// equal to p
while (y > 0)
{
// If y is odd, multiply x with result
if (y & 1)
res = (res*x) % p;
// y must be even now
y = y>>1; // y = y/2
x = (x*x) % p;
}
return res;
}
// Returns n^(-1) mod p
ll modInverse(ll n, ll p)
{
return power(n, p-2, p);
}
// Returns nCr % p using Fermat's little
// theorem.
int main(){
int t;
cin>>t;
while(t--){
int n,p;
cin>>p>>n;
int a[n];
li sum;
ll cur=0;
int b[p];
FOR(i,p){
b[i]=-1;}
unordered_map<ll,int> m;
ll cnt=0;
FOR(i,n){cin>>a[i];}
for(int i=0;i<min(n,p);i++){
cur=a[i]%p;
int j=0;
while(b[(cur+j)%p]!=-1){
j++;
}
b[(cur+j)%p]=a[i];
}
FOR(i,p){
out1(b[i]);
}
END;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Linear probing is a collision handling technique in hashing. Linear probing says that whenever a collision occurs, search for the immediate next position.
In this question, we'll learn how to fill up the hash table using linear probing technique. You are given hash table size which you'll use to insert elements into their correct position in the hash table i.e.(arr[i]%hashSize). You are also given an array arr of size n. You need to fill up the hash table using linear probing and print the resultant hash table.
Note: All the positions that are unoccupied are denoted by -1 in the hash table.
If there is no more space to insert, then just drop that element.The first line of input contains T denoting the number of test cases. T-test cases follow. Each test case contains 2 lines of input. The first line contains the size of the hashtable and the size of the array. The third line contains elements of the array.
<b>Constraints:-</b>
1 ≤ T ≤ 100
1 ≤ hashSize ≤ 10<sup>3</sup>
1 ≤ sizeOfArray ≤ 10<sup>3</sup>
0 ≤ Array[] ≤ 10<sup>5</sup>
For each testcase, in a new line, print the hash table as shown in example.Input:
2
10 4
4 14 24 44
10 4
9 99 999 9999
Output:
-1 -1 -1 -1 4 14 24 44 -1 -1
99 999 9999 -1 -1 -1 -1 -1 -1 9
Explanation:
Testcase1: 4%10=4. So put 4 in hashtable[4]. Now, 14%10=4, but hashtable[4] is already filled so put 14 in the next slot and so on.
Testcase2: 9%10=9. So put 9 in hashtable[9]. Now, 99%10=9, but hashtable[9] is already filled so put 99 in the (99+1)%10 =0 slot so 99 goes into hashtable[0] and so on., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine());
while(t-- > 0){
String str[] = read.readLine().trim().split("\\s+");
int hashSize = Integer.parseInt(str[0]);
int N = Integer.parseInt(str[1]);
int arr[] = new int[N];
str = read.readLine().trim().split("\\s+");
for(int i = 0; i < N; i++){
arr[i] = Integer.parseInt(str[i]);
}
int hashTable[] = new int[hashSize];
for(int i=0; i<hashSize; i++){
hashTable[i] = -1;
}
for(int i = 0; i< Math.min(N, hashSize); i++){
int idx = arr[i] % hashSize;
int j = 0;
while(hashTable[(idx + j) % hashSize] != -1){
j++;
}
hashTable[(idx + j) % hashSize] = arr[i];
}
for(int i=0; i<hashSize; i++){
System.out.print(hashTable[i] +" ");
}
System.out.println();
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Linear probing is a collision handling technique in hashing. Linear probing says that whenever a collision occurs, search for the immediate next position.
In this question, we'll learn how to fill up the hash table using linear probing technique. You are given hash table size which you'll use to insert elements into their correct position in the hash table i.e.(arr[i]%hashSize). You are also given an array arr of size n. You need to fill up the hash table using linear probing and print the resultant hash table.
Note: All the positions that are unoccupied are denoted by -1 in the hash table.
If there is no more space to insert, then just drop that element.The first line of input contains T denoting the number of test cases. T-test cases follow. Each test case contains 2 lines of input. The first line contains the size of the hashtable and the size of the array. The third line contains elements of the array.
<b>Constraints:-</b>
1 ≤ T ≤ 100
1 ≤ hashSize ≤ 10<sup>3</sup>
1 ≤ sizeOfArray ≤ 10<sup>3</sup>
0 ≤ Array[] ≤ 10<sup>5</sup>
For each testcase, in a new line, print the hash table as shown in example.Input:
2
10 4
4 14 24 44
10 4
9 99 999 9999
Output:
-1 -1 -1 -1 4 14 24 44 -1 -1
99 999 9999 -1 -1 -1 -1 -1 -1 9
Explanation:
Testcase1: 4%10=4. So put 4 in hashtable[4]. Now, 14%10=4, but hashtable[4] is already filled so put 14 in the next slot and so on.
Testcase2: 9%10=9. So put 9 in hashtable[9]. Now, 99%10=9, but hashtable[9] is already filled so put 99 in the (99+1)%10 =0 slot so 99 goes into hashtable[0] and so on., I have written this Solution Code: t = int(input())
for _ in range(t):
n,arrSize = map(int,input().split())
nums = list(map(int,input().split()))
hashSet = [-1]*n
for i in nums:
if hashSet[i%n] == -1:
hashSet[i%n] = i
else:
j = i%n + 1
while j!=i%n:
if hashSet[j%n] == -1:
hashSet[j%n] = i
break
j += 1
if hashSet.count(-1) == 0:
break
print(*hashSet), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a binary array A of size N. Now, an array P is calculated from A such that:
P[i] = A[i] + P[i-1]
(for 1 <= i <= N and P[0] = 0)
Now, you have to handle two types of queries:
1 L R - invert every element of A from L to R (If A[i] = 0, change it to 1 and vice versa)
2 L R - print the sum of array P from L to R
The array P is updated after every query of type 1.The first line contains two integers N and Q denoting the number of elements of the array and the number of queries respectively. The next line contains N boolean values representing the element of array A. The next Q lines contain three integers T L R denoting the queries.
1 <= N, Q <= 200000
0 <= A[i] <= 1
1 <= T <= 2
1 <= L <= R <= NFor every query of type 2, print a single integer denoting the sum of range from L to R in a separate line. Since the sum can be quite large, print sum modulo (10^9 + 7)Sample Input:
9 6
1 0 0 1 1 0 0 0 1
1 2 6
1 4 8
2 1 9
2 3 5
1 2 7
2 5 8
Sample Output:
41
12
8
Explanation:
Array P initially: [1, 1, 1, 2, 3, 3, 3, 3, 4]
After 1st query:
A: [1, 1, 1, 0, 0, 1, 0, 0, 1]
P: [1, 2, 3, 3, 3, 4, 4, 4, 5]
After 2nd query:
A: [1, 1, 1, 1, 1, 0, 1, 1, 1]
P: [1, 2, 3, 4, 5, 5, 6, 7, 8], I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int n, q;
bool a[N], lz[4*N];
int sum[4*N][2], sumi[4*N][2];
void merge(int nd){
for(int i = 0; i < 2; i++){
sum[nd][i] = sum[nd << 1][i] + sum[nd << 1 | 1][i];
sumi[nd][i] = sumi[nd << 1][i] + sumi[nd << 1 | 1][i];
}
}
void modify(int nd){
swap(sum[nd][0], sum[nd][1]);
swap(sumi[nd][0], sumi[nd][1]);
}
void pushdown(int nd, int s, int e){
if(lz[nd] == 0) return;
modify(nd);
if(s != e){
lz[nd << 1] ^= lz[nd];
lz[nd << 1 | 1] ^= lz[nd];
}
lz[nd] = 0;
}
void build(int nd, int s, int e){
if(s == e){
sum[nd][a[s]] = n-s+1;
sumi[nd][a[s]]++;
return;
}
int md = (s + e) >> 1;
build(nd << 1, s, md);
build(nd << 1 | 1, md+1, e);
merge(nd);
}
void upd(int nd, int s, int e, int l, int r){
pushdown(nd, s, e);
if(s > e || s > r || e < l)
return;
if(s >= l && e <= r){
modify(nd);
if(s != e){
lz[nd << 1] ^= 1;
lz[nd << 1 | 1] ^= 1;
}
return;
}
int md = (s + e) >> 1;
upd(nd << 1, s, md, l, r);
upd(nd << 1 | 1, md+1, e, l, r);
merge(nd);
}
pi query(int nd, int s, int e, int l, int r){
pushdown(nd, s, e);
if(s > e || s > r || e < l)
return {0, 0};
if(s >= l && e <= r)
return {sum[nd][0], sumi[nd][0]};
int md = (s + e) >> 1;
pi p = query(nd << 1, s, md, l, r);
pi q = query(nd << 1 | 1, md+1, e, l, r);
return {p.fi+q.fi, p.se+q.se};
}
void solve(){
cin >> n >> q;
for(int i = 1; i <= n; i++)
cin >> a[i];
build(1, 1, n);
while(q--){
int t, l, r;
cin >> t >> l >> r;
if(t == 1)
upd(1, 1, n, l, r);
else{
pi x = query(1, 1, n, l, r);
pi y = query(1, 1, n, 1, l-1);
int ans = r*(r+1)/2 - (l-1)*l/2;
ans = ans - (x.fi - x.se*(n-r)) - y.se*(r-l+1);
cout << ans % mod << endl;
}
}
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
clock_t start = clock();
testcases();
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms" << endl;
return 0;
} , In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two matrices A and B of size (M x N) and (N x P) respectively, Find matrix C, the product of matrix A and B.
<a href="https://en.wikipedia.org/wiki/Matrix_multiplication">Matrix Multiplication</aThe first line contains three integers M, N, and P as mentioned in the problem statement.
Next M lines contain N integers denoting the elements of matrix A
Next N lines contain P integers denoting the elements of matrix B
<b>Constraints</b>
1 ≤ M, N, P ≤ 100
1 ≤ A[i][j], B[i][j] ≤ 100Print M lines each containing P integers denoting the elements of matrix C respectivelySample input 1:
2 2 2
1 0
0 1
2 3
1 0
Sample output 1:
2 3
1 0
<b>Explanation:</b>
[ [1 , 0] , [0 , 1] ] X [ [2 , 3] , [1 , 0] ] = [ [2 , 3] , [1 , 0] ] , I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader rd=new BufferedReader(new InputStreamReader(System.in));
String inp1[]=rd.readLine().split(" ");
int m=Integer.parseInt(inp1[0]);
int n=Integer.parseInt(inp1[1]);
int p=Integer.parseInt(inp1[2]);
int m1[][]=new int[m][n];
int m2[][]=new int[n][p];
for(int i=0;i<m;i++)
{
String inp[]=rd.readLine().split(" ");
for(int j=0;j<n;j++)
m1[i][j]=Integer.parseInt(inp[j]);
}
for(int i=0;i<n;i++)
{
String inp[]=rd.readLine().split(" ");
for(int j=0;j<p;j++)
m2[i][j]=Integer.parseInt(inp[j]);
}
int m3[][]=new int[m][p];
for(int i=0;i<m;i++)
{
for(int j=0;j<p;j++)
{
for(int k=0;k<n;k++){
m3[i][j]+=m1[i][k]*m2[k][j];
}
}
}
for(int i=0;i<m;i++)
{
for(int j=0;j<p;j++)
System.out.print(m3[i][j]+" ");
System.out.println();
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two matrices A and B of size (M x N) and (N x P) respectively, Find matrix C, the product of matrix A and B.
<a href="https://en.wikipedia.org/wiki/Matrix_multiplication">Matrix Multiplication</aThe first line contains three integers M, N, and P as mentioned in the problem statement.
Next M lines contain N integers denoting the elements of matrix A
Next N lines contain P integers denoting the elements of matrix B
<b>Constraints</b>
1 ≤ M, N, P ≤ 100
1 ≤ A[i][j], B[i][j] ≤ 100Print M lines each containing P integers denoting the elements of matrix C respectivelySample input 1:
2 2 2
1 0
0 1
2 3
1 0
Sample output 1:
2 3
1 0
<b>Explanation:</b>
[ [1 , 0] , [0 , 1] ] X [ [2 , 3] , [1 , 0] ] = [ [2 , 3] , [1 , 0] ] , I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 1e2 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N][N], b[N][N], c[N][N];
void solve(){
int m, n, p;
cin >> m >> n >> p;
for(int i = 1; i <= m; i++)
for(int j = 1; j <= n; j++)
cin >> a[i][j];
for(int i = 1; i <= n; i++)
for(int j = 1; j <= p; j++)
cin >> b[i][j];
for(int i = 1; i <= m; i++){
for(int j = 1; j <= n; j++){
for(int k = 1; k <= p; k++)
c[i][k] += a[i][j]*b[j][k];
}
}
for(int i = 1; i <= m; i++){
for(int j = 1; j <= p; j++)
cout << c[i][j] << " ";
cout << endl;
}
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
clock_t start = clock();
testcases();
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms" << endl;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int t=Integer.parseInt(br.readLine());
while(t>0) {
t--;
char [] arr = br.readLine().toCharArray();
int [] hash = new int[256];
int i = 0,j=0,max=0;
while(j != arr.length) {
hash[arr[j]]++;
while (hash[arr[j]] > 1) {
hash[arr[i]]--;
i++;
}
max = Math.max(max, j-i+1);
j++;
}
System.out.println(max);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code:
def longestUniqueSubsttr(string):
last_idx = {}
max_len = 0
start_idx = 0
for i in range(0, len(string)):
if string[i] in last_idx:
start_idx = max(start_idx, last_idx[string[i]] + 1)
max_len = max(max_len, i-start_idx + 1)
last_idx[string[i]] = i
return max_len
t=int(input())
while t > 0:
s=input()
print(longestUniqueSubsttr(s))
t -= 1, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code:
// str is input string
function longestDistinctSubstr(s) {
const mostRecent = new Map(); // Stores the most recent idx
let startIdx = 0, res = 0;
for (let i = 0; i < s.length; i++) {
if (mostRecent.has(s[i]) && mostRecent.get(s[i]) >= startIdx) {
res = Math.max(res, i - startIdx);
startIdx = mostRecent.get(s[i]) + 1;
}
mostRecent.set(s[i], i);
}
return Math.max(res, s.length - startIdx);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code: // C++ program to find the length of the longest substring
// without repeating characters
#include <bits/stdc++.h>
using namespace std;
int longestUniqueSubsttr(string str)
{
int n = str.size();
int res = 0; // result
// last index of all characters is initialized
// as -1
vector<int> lastIndex(256, -1);
// Initialize start of current window
int i = 0;
// Move end of current window
for (int j = 0; j < n; j++) {
// Find the last index of str[j]
// Update i (starting index of current window)
// as maximum of current value of i and last
// index plus 1
i = max(i, lastIndex[str[j]] + 1);
// Update result if we get a larger window
res = max(res, j - i + 1);
// Update last index of j.
lastIndex[str[j]] = j;
}
return res;
}
// Driver code
int main()
{
int t;
cin>>t;
while(t>0)
{ t--;
string s;
cin>>s;
int len = longestUniqueSubsttr(s);
cout<<len<<endl;
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Calculate inversion count of array of integers.
Inversion count of an array is quantisation of how much unsorted an array is. A sorted array has inversion count 0, while an unsorted array has maximum inversion count.
Formally speaking inversion count = number of pairs i, j such that i < j and a[i] > a[j].The first line contain integers N.
The second line of the input contains N singly spaces integers.
1 <= N <= 100000
1 <= A[i] <= 1000000000Output one integer the inversion count.Sample Input
5
1 1 3 2 2
Sample Output
2
Sample Input
5
5 4 3 2 1
Sample Output
10, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static long count(int[] arr, int l, int h, int[] aux) {
if (l >= h) return 0;
int mid = (l +h) / 2;
long count = 0;
count += count(aux, l, mid, arr);
count += count(aux, mid + 1, h, arr);
count += merge(arr, l, mid, h, aux);
return count;
}
static long merge(int[] arr, int l, int mid, int h, int[] aux) {
long count = 0;
int i = l, j = mid + 1, k = l;
while (i <= mid || j <= h) {
if (i > mid) {
arr[k++] = aux[j++];
} else if (j > h) {
arr[k++] = aux[i++];
} else if (aux[i] <= aux[j]) {
arr[k++] = aux[i++];
} else {
arr[k++] = aux[j++];
count += mid + 1 - i;
}
}
return count;
}
public static void main (String[] args)throws IOException {
BufferedReader br =new BufferedReader(new InputStreamReader(System.in));
String str[];
str = br.readLine().split(" ");
int n = Integer.parseInt(str[0]);
str = br.readLine().split(" ");
int arr[] =new int[n];
for (int j = 0; j < n; j++) {
arr[j] = Integer.parseInt(str[j]);
}
int[] aux = arr.clone();
System.out.print(count(arr, 0, n - 1, aux));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Calculate inversion count of array of integers.
Inversion count of an array is quantisation of how much unsorted an array is. A sorted array has inversion count 0, while an unsorted array has maximum inversion count.
Formally speaking inversion count = number of pairs i, j such that i < j and a[i] > a[j].The first line contain integers N.
The second line of the input contains N singly spaces integers.
1 <= N <= 100000
1 <= A[i] <= 1000000000Output one integer the inversion count.Sample Input
5
1 1 3 2 2
Sample Output
2
Sample Input
5
5 4 3 2 1
Sample Output
10, I have written this Solution Code: count=0
def implementMergeSort(arr,s,e):
global count
if e-s==1:
return
mid=(s+e)//2
implementMergeSort(arr,s,mid)
implementMergeSort(arr,mid,e)
count+=merge_sort_place(arr,s,mid,e)
return count
def merge_sort_place(arr,s,mid,e):
arr3=[]
i=s
j=mid
count=0
while i<mid and j<e:
if arr[i]>arr[j]:
arr3.append(arr[j])
j+=1
count+=(mid-i)
else:
arr3.append(arr[i])
i+=1
while (i<mid):
arr3.append(arr[i])
i+=1
while (j<e):
arr3.append(arr[j])
j+=1
for x in range(len(arr3)):
arr[s+x]=arr3[x]
return count
n=int(input())
arr=list(map(int,input().split()[:n]))
c=implementMergeSort(arr,0,len(arr))
print(c), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Calculate inversion count of array of integers.
Inversion count of an array is quantisation of how much unsorted an array is. A sorted array has inversion count 0, while an unsorted array has maximum inversion count.
Formally speaking inversion count = number of pairs i, j such that i < j and a[i] > a[j].The first line contain integers N.
The second line of the input contains N singly spaces integers.
1 <= N <= 100000
1 <= A[i] <= 1000000000Output one integer the inversion count.Sample Input
5
1 1 3 2 2
Sample Output
2
Sample Input
5
5 4 3 2 1
Sample Output
10, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
long long _mergeSort(long long arr[], int temp[], int left, int right);
long long merge(long long arr[], int temp[], int left, int mid, int right);
/* This function sorts the input array and returns the
number of inversions in the array */
long long mergeSort(long long arr[], int array_size)
{
int temp[array_size];
return _mergeSort(arr, temp, 0, array_size - 1);
}
/* An auxiliary recursive function that sorts the input array and
returns the number of inversions in the array. */
long long _mergeSort(long long arr[], int temp[], int left, int right)
{
long long mid, inv_count = 0;
if (right > left) {
/* Divide the array into two parts and
call _mergeSortAndCountInv()
for each of the parts */
mid = (right + left) / 2;
/* Inversion count will be sum of
inversions in left-part, right-part
and number of inversions in merging */
inv_count += _mergeSort(arr, temp, left, mid);
inv_count += _mergeSort(arr, temp, mid + 1, right);
/*Merge the two parts*/
inv_count += merge(arr, temp, left, mid + 1, right);
}
return inv_count;
}
/* This funt merges two sorted arrays
and returns inversion count in the arrays.*/
long long merge(long long arr[], int temp[], int left,
int mid, int right)
{
int i, j, k;
long long inv_count = 0;
i = left; /* i is index for left subarray*/
j = mid; /* j is index for right subarray*/
k = left; /* k is index for resultant merged subarray*/
while ((i <= mid - 1) && (j <= right)) {
if (arr[i] <= arr[j]) {
temp[k++] = arr[i++];
}
else {
temp[k++] = arr[j++];
/* this is tricky -- see above
explanation/diagram for merge()*/
inv_count = inv_count + (mid - i);
}
}
/* Copy the remaining elements of left subarray
(if there are any) to temp*/
while (i <= mid - 1)
temp[k++] = arr[i++];
/* Copy the remaining elements of right subarray
(if there are any) to temp*/
while (j <= right)
temp[k++] = arr[j++];
/*Copy back the merged elements to original array*/
for (i = left; i <= right; i++)
arr[i] = temp[i];
return inv_count;}
int main(){
int n;
cin>>n;
long long a[n];
for(int i=0;i<n;i++){
cin>>a[i];}
long long ans = mergeSort(a, n);
cout << ans; }
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc =new Scanner(System.in);
int T= sc.nextInt();
for(int i=0;i<T;i++){
int arrsize=sc.nextInt();
int max=0,secmax=0,thirdmax=0,j;
for(int k=0;k<arrsize;k++){
j=sc.nextInt();
if(j>max){
thirdmax=secmax;
secmax=max;
max=j;
}
else if(j>secmax){
thirdmax=secmax;
secmax=j;
}
else if(j>thirdmax){
thirdmax=j;
}
if(k%10000==0){
System.gc();
}
}
System.out.println(max+" "+secmax+" "+thirdmax+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: t=int(input())
while t>0:
t-=1
n=int(input())
l=list(map(int,input().strip().split()))
li=[0,0,0]
for i in l:
x=i
for j in range(0,3):
y=min(x,li[j])
li[j]=max(x,li[j])
x=y
print(li[0],end=" ")
print(li[1],end=" ")
print(li[2]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin>>t;
while(t--){
long long n;
cin>>n;
vector<long> a(n);
long ans[3]={0};
long x,y;
for(int i=0;i<n;i++){
cin>>a[i];
x=a[i];
for(int j=0;j<3;j++){
y=min(x,ans[j]);
ans[j]=max(x,ans[j]);
// cout<<ans[j]<<" ";
x=y;
}
}
if(ans[1]<ans[0]){
swap(ans[1],ans[0]);
}
if(ans[2]<ans[1]){
swap(ans[1],ans[2]);
}
if(ans[1]<ans[0]){
swap(ans[1],ans[0]);
}
cout<<ans[2]<<" "<<ans[1]<<" "<<ans[0]<<endl;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: function maxNumbers(arr,n) {
// write code here
// do not console.log the answer
// return the answer as an array of 3 numbers
return arr.sort((a,b)=>b-a).slice(0,3)
};
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, you need to check whether the given number is Armstrong number or not. Now what is Armstrong number let us see below:
<b>A number is said to be Armstrong if it is equal to sum of cube of its digits. </b>User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>isArmstrong()</b> which contains N as a parameter.
Constraints:
1 <= N <= 10^4You need to return "true" if the given number is an Armstrong number otherwise "false"Sample Input 1:
1
Sample Output 1:
true
Sample Input 2:
147
Sample Output 2:
false
Sample Input 3:
371
Sample Output 3:
true
, I have written this Solution Code: static boolean isArmstrong(int N)
{
int num = N;
int sum = 0;
while(N > 0)
{
int digit = N%10;
sum += digit*digit*digit;
N = N/10;
}
if(num == sum)
return true;
else return false;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, you need to check whether the given number is Armstrong number or not. Now what is Armstrong number let us see below:
<b>A number is said to be Armstrong if it is equal to sum of cube of its digits. </b>User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>isArmstrong()</b> which contains N as a parameter.
Constraints:
1 <= N <= 10^4You need to return "true" if the given number is an Armstrong number otherwise "false"Sample Input 1:
1
Sample Output 1:
true
Sample Input 2:
147
Sample Output 2:
false
Sample Input 3:
371
Sample Output 3:
true
, I have written this Solution Code: function isArmstrong(n) {
// write code here
// do no console.log the answer
// return the output using return keyword
let sum = 0
let k = n;
while(k !== 0){
sum += Math.pow( k%10,3)
k = Math.floor(k/10)
}
return sum === n
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Phoebe is a big GCD fan. Being bored, she starts counting number of pairs of integers (A, B) such that following conditions are satisfied:
<li> GCD(A, B) = X (As X is Phoebe's favourite integer)
<li> A <= B <= L
As Phoebe's performance is coming up, she needs your help to find the number of such pairs possible.
Note: GCD refers to the <a href="https://en.wikipedia.org/wiki/Greatest_common_divisor">Greatest common divisor</a>.Input contains two integers L and X.
Constraints:
1 <= L, X <= 1000000000Print a single integer denoting number of pairs possible.Sample Input
5 2
Sample Output
2
Explanation: Pairs satisfying all conditions are: (2, 2), (2, 4)
Sample Input
5 3
Sample Output
1
Explanation: Pairs satisfying all conditions are: (3, 3), I have written this Solution Code: import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.InputMismatchException;
class Main {
InputStream is;
PrintWriter out;
String INPUT = "";
void solve()
{
out.println(sumTotient(ni()/ni()));
}
public static int[] enumTotientByLpf(int n, int[] lpf)
{
int[] ret = new int[n+1];
ret[1] = 1;
for(int i = 2;i <= n;i++){
int j = i/lpf[i];
if(lpf[j] != lpf[i]){
ret[i] = ret[j] * (lpf[i]-1);
}else{
ret[i] = ret[j] * lpf[i];
}
}
return ret;
}
public static int[] enumLowestPrimeFactors(int n)
{
int tot = 0;
int[] lpf = new int[n+1];
int u = n+32;
double lu = Math.log(u);
int[] primes = new int[(int)(u/lu+u/lu/lu*1.5)];
for(int i = 2;i <= n;i++)lpf[i] = i;
for(int p = 2;p <= n;p++){
if(lpf[p] == p)primes[tot++] = p;
int tmp;
for(int i = 0;i < tot && primes[i] <= lpf[p] && (tmp = primes[i]*p) <= n;i++){
lpf[tmp] = primes[i];
}
}
return lpf;
}
public static long sumTotient(int n)
{
if(n == 0)return 0L;
if(n == 1)return 1L;
int s = (int)Math.sqrt(n);
long[] cacheu = new long[n/s];
long[] cachel = new long[s+1];
int X = (int)Math.pow(n, 0.66);
int[] lpf = enumLowestPrimeFactors(X);
int[] tot = enumTotientByLpf(X, lpf);
long sum = 0;
int p = cacheu.length-1;
for(int i = 1;i <= X;i++){
sum += tot[i];
if(i <= s){
cachel[i] = sum;
}else if(p > 0 && i == n/p){
cacheu[p] = sum;
p--;
}
}
for(int i = p;i >= 1;i--){
int x = n/i;
long all = (long)x*(x+1)/2;
int ls = (int)Math.sqrt(x);
for(int j = 2;x/j > ls;j++){
long lval = i*j < cacheu.length ? cacheu[i*j] : cachel[x/j];
all -= lval;
}
for(int v = ls;v >= 1;v--){
long w = x/v-x/(v+1);
all -= cachel[v]*w;
}
cacheu[(int)i] = all;
}
return cacheu[1];
}
void run() throws Exception
{
is = INPUT.isEmpty() ? System.in : new ByteArrayInputStream(INPUT.getBytes());
out = new PrintWriter(System.out);
long s = System.currentTimeMillis();
solve();
out.flush();
if(!INPUT.isEmpty())tr(System.currentTimeMillis()-s+"ms");
}
public static void main(String[] args) throws Exception { new Main().run(); }
private byte[] inbuf = new byte[1024];
private int lenbuf = 0, ptrbuf = 0;
private int readByte()
{
if(lenbuf == -1)throw new InputMismatchException();
if(ptrbuf >= lenbuf){
ptrbuf = 0;
try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); }
if(lenbuf <= 0)return -1;
}
return inbuf[ptrbuf++];
}
private boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }
private int skip() { int b; while((b = readByte()) != -1 && isSpaceChar(b)); return b; }
private double nd() { return Double.parseDouble(ns()); }
private char nc() { return (char)skip(); }
private String ns()
{
int b = skip();
StringBuilder sb = new StringBuilder();
while(!(isSpaceChar(b))){
sb.appendCodePoint(b);
b = readByte();
}
return sb.toString();
}
private char[] ns(int n)
{
char[] buf = new char[n];
int b = skip(), p = 0;
while(p < n && !(isSpaceChar(b))){
buf[p++] = (char)b;
b = readByte();
}
return n == p ? buf : Arrays.copyOf(buf, p);
}
private char[][] nm(int n, int m)
{
char[][] map = new char[n][];
for(int i = 0;i < n;i++)map[i] = ns(m);
return map;
}
private int[] na(int n)
{
int[] a = new int[n];
for(int i = 0;i < n;i++)a[i] = ni();
return a;
}
private int ni()
{
int num = 0, b;
boolean minus = false;
while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
if(b == '-'){
minus = true;
b = readByte();
}
while(true){
if(b >= '0' && b <= '9'){
num = num * 10 + (b - '0');
}else{
return minus ? -num : num;
}
b = readByte();
}
}
private long nl()
{
long num = 0;
int b;
boolean minus = false;
while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
if(b == '-'){
minus = true;
b = readByte();
}
while(true){
if(b >= '0' && b <= '9'){
num = num * 10 + (b - '0');
}else{
return minus ? -num : num;
}
b = readByte();
}
}
private static void tr(Object... o) { System.out.println(Arrays.deepToString(o)); }
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Phoebe is a big GCD fan. Being bored, she starts counting number of pairs of integers (A, B) such that following conditions are satisfied:
<li> GCD(A, B) = X (As X is Phoebe's favourite integer)
<li> A <= B <= L
As Phoebe's performance is coming up, she needs your help to find the number of such pairs possible.
Note: GCD refers to the <a href="https://en.wikipedia.org/wiki/Greatest_common_divisor">Greatest common divisor</a>.Input contains two integers L and X.
Constraints:
1 <= L, X <= 1000000000Print a single integer denoting number of pairs possible.Sample Input
5 2
Sample Output
2
Explanation: Pairs satisfying all conditions are: (2, 2), (2, 4)
Sample Input
5 3
Sample Output
1
Explanation: Pairs satisfying all conditions are: (3, 3), I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
template<class C> void mini(C&a4, C b4){a4=min(a4,b4);}
typedef unsigned long long ull;
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define mod 1000000007ll
#define pii pair<int,int>
/////////////
ull X[20000001];
ull cmp(ull N){
return N*(N+1)/2;
}
ull solve(ull N){
if(N==1)
return 1;
if(N < 20000001 && X[N] != 0)
return X[N];
ull res = 0;
ull q = floor(sqrt(N));
for(int k=2;k<N/q+1;++k){
res += solve(N/k);
}
for(int m=1;m<q;++m){
res += (N/m - N/(m+1)) * solve(m);
}
res = cmp(N) - res;
if(N < 20000001)
X[N] = res;
return res;
}
signed main(){
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int l,x;
cin>>l>>x;
if(l<x)
cout<<0;
else
cout<<solve(l/x);
#ifdef ANIKET_GOYAL
cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){cout<<"FizzBuzz"<<" ";}
else if(i%5==0){cout<<"Buzz ";}
else if(i%3==0){cout<<"Fizz ";}
else{cout<<i<<" ";}
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int x= sc.nextInt();
fizzbuzz(x);
}
static void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){System.out.print("FizzBuzz ");}
else if(i%5==0){System.out.print("Buzz ");}
else if(i%3==0){System.out.print("Fizz ");}
else{System.out.print(i+" ");}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: def fizzbuzz(n):
for i in range (1,n+1):
if (i%3==0 and i%5==0):
print("FizzBuzz",end=' ')
elif i%3==0:
print("Fizz",end=' ')
elif i%5==0:
print("Buzz",end=' ')
else:
print(i,end=' '), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){printf("FizzBuzz ");}
else if(i%5==0){printf("Buzz ");}
else if(i%3==0){printf("Fizz ");}
else{printf("%d ",i);}
}
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a sorted array of N integers a[], and Q queries. For each query, you will be given a positive integer K and your task is to print the number of elements in array a[] that are smaller than or equal to K.<b>In case of Java only</b>
<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>smallerElements()</b> that takes the array a[], integer N and integer k as arguments.
<b>Custom Input</b>
The first line of input contains a single integer N.
The second line of input contains N space- separated integers depicting the values of the array.
The third line of input contains a single integer Q, the number of queries.
Each of the next Q lines of input contain a single integer, the value of K.
<b>Constraints:-</b>
1 <= N <= 10<sup>5</sup>
1 <= K, Arr[i] <= 10<sup>12</sup>
1 <= Q <= 10<sup>4</sup>Return the count of elements smaller than or equal to K.Sample Input:-
5
2 5 6 11 15
5
2
4
8
1
16
Sample Output:-
1
1
3
0
5, I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define max1 1001
#define MOD 1000000007
#define read(type) readInt<type>()
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
#define sz(v) ((int)(v).size())
#define all(v) (v).begin(), (v).end()
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
signed main(){
int n;
cin>>n;
vector<int> v(n);
FOR(i,n){
cin>>v[i];}
int q;
cin>>q;
int x;
while(q--){
cin>>x;
auto it = upper_bound(v.begin(),v.end(),x);
out(it-v.begin());
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a sorted array of N integers a[], and Q queries. For each query, you will be given a positive integer K and your task is to print the number of elements in array a[] that are smaller than or equal to K.<b>In case of Java only</b>
<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>smallerElements()</b> that takes the array a[], integer N and integer k as arguments.
<b>Custom Input</b>
The first line of input contains a single integer N.
The second line of input contains N space- separated integers depicting the values of the array.
The third line of input contains a single integer Q, the number of queries.
Each of the next Q lines of input contain a single integer, the value of K.
<b>Constraints:-</b>
1 <= N <= 10<sup>5</sup>
1 <= K, Arr[i] <= 10<sup>12</sup>
1 <= Q <= 10<sup>4</sup>Return the count of elements smaller than or equal to K.Sample Input:-
5
2 5 6 11 15
5
2
4
8
1
16
Sample Output:-
1
1
3
0
5, I have written this Solution Code: static int smallerElements(int a[], int n, int k){
int l=0;
int h=n-1;
int m;
int ans=n;
while(l<=h){
m=l+h;
m/=2;
if(a[m]<=k){
l=m+1;
}
else{
h=m-1;
ans=m;
}
}
return ans;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Toros went to the supermarket to buy K items. There were a total of N items. Each item had a distinct price P<sub>i</sub>. He is cost-effective, so he would buy the K cheapest item. But he knows that the more cheaper an item is, the more is the chances that it can be defective. So he planned to ignore 2 cheapest items and buy K from the remaining ones.
Find the total cost of all items that he would buy.The first line contains two integers N and K, denoting the total number of items in the supermarket and the number of items Toros is going to buy.
The second line contains N distinct integers P<sub>i</sub> , denoting the prices of the items
<b>Constraints:</b>
1 <= N <= 100000
1 <= K <= N - 2
1 <= P<sub>i</sub> <= 1000000Print a single integer denoting the total cost of items Toros would buy.Sample Input:
5 2
4 1 2 3 5
Sample Output:
7
Explanation:
Toros will ignore items with price 1 and 2 and would buy items with price 4 and 3.
Sample Input:
10 8
99 56 50 93 47 36 65 25 87 16
Sample Output:
533, I have written this Solution Code: function supermarket(prices, n, k) {
// write code here
// do not console.log the answer
// return sorted array
const newPrices = prices.sort((a, b) => a - b).slice(2)
let kk = k
let price = 0;
let i = 0
while (kk-- && i < newPrices.length) {
price += newPrices[i]
i += 1
}
return price
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Toros went to the supermarket to buy K items. There were a total of N items. Each item had a distinct price P<sub>i</sub>. He is cost-effective, so he would buy the K cheapest item. But he knows that the more cheaper an item is, the more is the chances that it can be defective. So he planned to ignore 2 cheapest items and buy K from the remaining ones.
Find the total cost of all items that he would buy.The first line contains two integers N and K, denoting the total number of items in the supermarket and the number of items Toros is going to buy.
The second line contains N distinct integers P<sub>i</sub> , denoting the prices of the items
<b>Constraints:</b>
1 <= N <= 100000
1 <= K <= N - 2
1 <= P<sub>i</sub> <= 1000000Print a single integer denoting the total cost of items Toros would buy.Sample Input:
5 2
4 1 2 3 5
Sample Output:
7
Explanation:
Toros will ignore items with price 1 and 2 and would buy items with price 4 and 3.
Sample Input:
10 8
99 56 50 93 47 36 65 25 87 16
Sample Output:
533, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String str[]= br.readLine().trim().split(" ");
int n=Integer.parseInt(str[0]);
int k=Integer.parseInt(str[1]);
str= br.readLine().trim().split(" ");
int arr[]=new int[n];
for(int i=0;i<n;i++)
arr[i]=Integer.parseInt(str[i]);
Arrays.sort(arr);
long sum=0;
for(int i=2;i<k+2;i++)
sum+=arr[i];
System.out.print(sum);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Toros went to the supermarket to buy K items. There were a total of N items. Each item had a distinct price P<sub>i</sub>. He is cost-effective, so he would buy the K cheapest item. But he knows that the more cheaper an item is, the more is the chances that it can be defective. So he planned to ignore 2 cheapest items and buy K from the remaining ones.
Find the total cost of all items that he would buy.The first line contains two integers N and K, denoting the total number of items in the supermarket and the number of items Toros is going to buy.
The second line contains N distinct integers P<sub>i</sub> , denoting the prices of the items
<b>Constraints:</b>
1 <= N <= 100000
1 <= K <= N - 2
1 <= P<sub>i</sub> <= 1000000Print a single integer denoting the total cost of items Toros would buy.Sample Input:
5 2
4 1 2 3 5
Sample Output:
7
Explanation:
Toros will ignore items with price 1 and 2 and would buy items with price 4 and 3.
Sample Input:
10 8
99 56 50 93 47 36 65 25 87 16
Sample Output:
533, I have written this Solution Code: a=input().split()
for i in range(len(a)):
a[i]=int(a[i])
b=input().split()
for i in range(len(b)):
b[i]=int(b[i])
b.sort()
b.reverse()
b.pop()
b.pop()
s=0
while a[1]>0:
s+=b.pop()
a[1]-=1
print(s), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Toros went to the supermarket to buy K items. There were a total of N items. Each item had a distinct price P<sub>i</sub>. He is cost-effective, so he would buy the K cheapest item. But he knows that the more cheaper an item is, the more is the chances that it can be defective. So he planned to ignore 2 cheapest items and buy K from the remaining ones.
Find the total cost of all items that he would buy.The first line contains two integers N and K, denoting the total number of items in the supermarket and the number of items Toros is going to buy.
The second line contains N distinct integers P<sub>i</sub> , denoting the prices of the items
<b>Constraints:</b>
1 <= N <= 100000
1 <= K <= N - 2
1 <= P<sub>i</sub> <= 1000000Print a single integer denoting the total cost of items Toros would buy.Sample Input:
5 2
4 1 2 3 5
Sample Output:
7
Explanation:
Toros will ignore items with price 1 and 2 and would buy items with price 4 and 3.
Sample Input:
10 8
99 56 50 93 47 36 65 25 87 16
Sample Output:
533, I have written this Solution Code: #include<bits/stdc++.h>
#define int long long
#define ll long long
#define pb push_back
#define endl '\n'
#define pii pair<int,int>
#define vi vector<int>
#define all(a) (a).begin(),(a).end()
#define F first
#define S second
#define sz(x) (int)x.size()
#define hell 1000000007
#define rep(i,a,b) for(int i=a;i<b;i++)
#define dep(i,a,b) for(int i=a;i>=b;i--)
#define lbnd lower_bound
#define ubnd upper_bound
#define bs binary_search
#define mp make_pair
using namespace std;
const int N = 1e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N];
void solve(){
int n, k;
cin >> n >> k;
for(int i = 1; i <= n; i++)
cin >> a[i];
sort(a + 1, a + n + 1);
int ans = 0;
for(int i = 3; i <= 2 + k; i++)
ans += a[i];
cout << ans << endl;
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
clock_t start = clock();
testcases();
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms: ";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Aniket has a binary string of length n. He challenges you to build the lexographically minimum possible string using this string.
In one move you can swap two adjacent characters of the string. You can make at most k swaps.
Note that you can swap the same pair of adjacent characters with indices i and i+1 arbitrary (possibly, zero) number of times. Each such swap is considered a separate move.The first line of the input contains two integers n and k — the length of the string and the number of swaps you can perform.
The second line of the test case contains one string consisting of n characters '0' and '1'.
Constraints
1 <= n <= 1000000
1 <= k <= n*nOutput a single binary string, the answer to the query.Sample Input
8 5
11011010
Sample Output
01011110
Sample Input
7 9
1111100
Sample Output
0101111, I have written this Solution Code: n,k=map(int,input().split())
s=input()
foundZero=False
cntOfOnes=0
ans=""
for i in range(len(s)):
if s[i]=="0":
if cntOfOnes<=k:
ans+="0"
k-=cntOfOnes
else:
ans+="1"*(cntOfOnes-k)
ans+="0"
ans+="1"*k
ans+=s[i+1:]
foundZero=True
break
else:
cntOfOnes+=1
if not foundZero:
ans+="1"*cntOfOnes
print(ans), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Aniket has a binary string of length n. He challenges you to build the lexographically minimum possible string using this string.
In one move you can swap two adjacent characters of the string. You can make at most k swaps.
Note that you can swap the same pair of adjacent characters with indices i and i+1 arbitrary (possibly, zero) number of times. Each such swap is considered a separate move.The first line of the input contains two integers n and k — the length of the string and the number of swaps you can perform.
The second line of the test case contains one string consisting of n characters '0' and '1'.
Constraints
1 <= n <= 1000000
1 <= k <= n*nOutput a single binary string, the answer to the query.Sample Input
8 5
11011010
Sample Output
01011110
Sample Input
7 9
1111100
Sample Output
0101111, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String ss[]=br.readLine().split(" ");
long n=Long.parseLong(ss[0]);
long t=Long.parseLong(ss[1]);
String str = br.readLine();
StringBuilder sb=new StringBuilder(str);
int j=0;
for(int i=0;i<n;i++){
if(sb.charAt(i) == '0'){
int m = (int)Math.min(t,i-j);
t = t-m;
char temp = sb.charAt(i-m);
sb.setCharAt(i-m, sb.charAt(i));
sb.setCharAt(i,temp);
j++;
}
}
System.out.println(sb);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Aniket has a binary string of length n. He challenges you to build the lexographically minimum possible string using this string.
In one move you can swap two adjacent characters of the string. You can make at most k swaps.
Note that you can swap the same pair of adjacent characters with indices i and i+1 arbitrary (possibly, zero) number of times. Each such swap is considered a separate move.The first line of the input contains two integers n and k — the length of the string and the number of swaps you can perform.
The second line of the test case contains one string consisting of n characters '0' and '1'.
Constraints
1 <= n <= 1000000
1 <= k <= n*nOutput a single binary string, the answer to the query.Sample Input
8 5
11011010
Sample Output
01011110
Sample Input
7 9
1111100
Sample Output
0101111, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(ll i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define int long long
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
#define MOD 1000000007
#define INF 1000000000000000007
#define MAXN 200005
// it's swapnil07 ;)
signed main(){
fast
#ifdef SWAPNIL07
freopen("/home/swapnil/Desktop/c++/input.txt","r",stdin);
freopen("/home/swapnil/Desktop/c++/output.txt","w",stdout);
#endif
int q;
// cin>>q;
q=1;
while(q--){
int n, k; cin>>n>>k;
string s; cin>>s;
vector<int> z;
For(i, 0, n){
if(s[i]=='0')
z.pb(i);
}
For(i, 0, z.size()){
if(z[i] > i){
int need = z[i]-i;
if(k > need){
z[i]=i;
k-=need;
}
else{
z[i]=z[i]-k;
break;
}
}
}
bool ans[n];
memset(ans, true, sizeof(ans));
For(i, 0, z.size()){
ans[z[i]]=false;
}
For(i, 0, n){
cout<<ans[i];
}
cout<<"\n";
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string your task is to reverse the given string.The first line of the input contains a string.
Constraints:-
1 <= string length <= 100
String contains only lowercase english lettersThe output should contain reverse of the input string.Sample Input
abc
Sample Output
cba, I have written this Solution Code: s = input("")
print (s[::-1]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string your task is to reverse the given string.The first line of the input contains a string.
Constraints:-
1 <= string length <= 100
String contains only lowercase english lettersThe output should contain reverse of the input string.Sample Input
abc
Sample Output
cba, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
reverse(s.begin(),s.end());
cout<<s;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string your task is to reverse the given string.The first line of the input contains a string.
Constraints:-
1 <= string length <= 100
String contains only lowercase english lettersThe output should contain reverse of the input string.Sample Input
abc
Sample Output
cba, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
String s = sc.next();
for(int i = s.length()-1;i>=0;i--){
System.out.print(s.charAt(i));
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args){
FastReader read = new FastReader();
int a = read.nextInt();
int b = read.nextInt();
System.out.println(a+b);
System.out.println(a-b);
System.out.println(a*b);
System.out.println(a/b);
}
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader(){
InputStreamReader inr = new InputStreamReader(System.in);
br = new BufferedReader(inr);
}
String next(){
while(st==null || !st.hasMoreElements())
try{
st = new StringTokenizer(br.readLine());
}
catch(IOException e){
e.printStackTrace();
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
double nextDouble(){
return Double.parseDouble(next());
}
long nextLong(){
return Long.parseLong(next());
}
String nextLine(){
String str = "";
try{
str = br.readLine();
}
catch(IOException e){
e.printStackTrace();
}
return str;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: a,b=map(int,input().split())
print(a+b)
print(a-b)
print(a*b)
print(a//b), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: def compound_interest(principle, rate, time):
Amount = principle * (pow((1 + rate / 100), time))
CI = Amount - principle
print( '%.2f'%CI)
principle,rate,time=map(int, input().split())
compound_interest(principle,rate,time), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: function calculateCI(P, R, T)
{
let interest = P * (Math.pow(1.0 + R/100.0, T) - 1);
return interest.toFixed(2);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int p,r,t;
cin>>p>>r>>t;
double rate= (float)r/100;
double amt = (float)p*(pow(1+rate,t));
cout << fixed << setprecision(2) << (amt - p);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.lang.Math;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] s= br.readLine().split(" ");
double[] darr = new double[s.length];
for(int i=0;i<s.length;i++){
darr[i] = Double.parseDouble(s[i]);
}
double ans = darr[0]*Math.pow(1+darr[1]/100,darr[2])-darr[0];
System.out.printf("%.2f",ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The universe contains a magic number <b>z</b>. Thor's power is known to <b>x</b> and Loki's power to be <b>y</b>.
One's strength is defined to be <b>z - a</b>, if his power is <b>a</b>. Your task is to find out who among Thor and Loki has the highest strength, and print that strength.
<b>Note:</b> The input and answer may not fit in a 32-bit integer type. In particular, if you are using C++ consider using <em>long long int</em> over <em>int</em>.The first line contains one integer t — the number of test cases.
Each test case consists of one line containing three space-separated integers x, y and z.
<b> Constraints: </b>
1 ≤ t ≤ 10<sup>4</sup>
1 ≤ x, y ≤ 10<sup>15</sup>
max(x, y) < z ≤ 10<sup>15</sup>For each test case, print a single value - the largest strength among Thor and Loki.Sample Input
2
2 3 4
1 1 5
Sample Output
2
4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
long z=0,x=0,y=0;
int choice;
Scanner in = new Scanner(System.in);
choice = in.nextInt();
String s="";
int f = 1;
while(f<=choice){
x = in.nextLong();
y = in.nextLong();
z = in.nextLong();
System.out.println((long)(Math.max((z-x),(z-y))));
f++;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The universe contains a magic number <b>z</b>. Thor's power is known to <b>x</b> and Loki's power to be <b>y</b>.
One's strength is defined to be <b>z - a</b>, if his power is <b>a</b>. Your task is to find out who among Thor and Loki has the highest strength, and print that strength.
<b>Note:</b> The input and answer may not fit in a 32-bit integer type. In particular, if you are using C++ consider using <em>long long int</em> over <em>int</em>.The first line contains one integer t — the number of test cases.
Each test case consists of one line containing three space-separated integers x, y and z.
<b> Constraints: </b>
1 ≤ t ≤ 10<sup>4</sup>
1 ≤ x, y ≤ 10<sup>15</sup>
max(x, y) < z ≤ 10<sup>15</sup>For each test case, print a single value - the largest strength among Thor and Loki.Sample Input
2
2 3 4
1 1 5
Sample Output
2
4, I have written this Solution Code: n = int(input())
for i in range(n):
l = list(map(int,input().split()))
print(l[2]-min(l)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The universe contains a magic number <b>z</b>. Thor's power is known to <b>x</b> and Loki's power to be <b>y</b>.
One's strength is defined to be <b>z - a</b>, if his power is <b>a</b>. Your task is to find out who among Thor and Loki has the highest strength, and print that strength.
<b>Note:</b> The input and answer may not fit in a 32-bit integer type. In particular, if you are using C++ consider using <em>long long int</em> over <em>int</em>.The first line contains one integer t — the number of test cases.
Each test case consists of one line containing three space-separated integers x, y and z.
<b> Constraints: </b>
1 ≤ t ≤ 10<sup>4</sup>
1 ≤ x, y ≤ 10<sup>15</sup>
max(x, y) < z ≤ 10<sup>15</sup>For each test case, print a single value - the largest strength among Thor and Loki.Sample Input
2
2 3 4
1 1 5
Sample Output
2
4, I have written this Solution Code: #include <bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;
typedef long long ll;
typedef long double ld;
#define db(x) cerr << #x << ": " << x << '\n';
#define read(a) int a; cin >> a;
#define reads(s) string s; cin >> s;
#define readb(a, b) int a, b; cin >> a >> b;
#define readc(a, b, c) int a, b, c; cin >> a >> b >> c;
#define readarr(a, n) int a[(n) + 1] = {}; FOR(i, 1, (n)) {cin >> a[i];}
#define readmat(a, n, m) int a[n + 1][m + 1] = {}; FOR(i, 1, n) {FOR(j, 1, m) cin >> a[i][j];}
#define print(a) cout << a << endl;
#define printarr(a, n) FOR (i, 1, n) cout << a[i] << " "; cout << endl;
#define printv(v) for (int i: v) cout << i << " "; cout << endl;
#define printmat(a, n, m) FOR (i, 1, n) {FOR (j, 1, m) cout << a[i][j] << " "; cout << endl;}
#define all(v) v.begin(), v.end()
#define sz(v) (int)(v.size())
#define rz(v, n) v.resize((n) + 1);
#define pb push_back
#define fi first
#define se second
#define vi vector <int>
#define pi pair <int, int>
#define vpi vector <pi>
#define vvi vector <vi>
#define setprec cout << fixed << showpoint << setprecision(20);
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define FORD(i, a, b) for (int i = (a); i >= (b); i--)
const ll inf = 1e18;
const ll mod = 1e9 + 7;
const ll mod2 = 998244353;
const ll N = 2e5 + 1;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int power (int a, int b = mod - 2)
{
int res = 1;
while (b > 0) {
if (b & 1)
res = res * a % mod;
a = a * a % mod;
b >>= 1;
}
return res;
}
signed main()
{
read(t);
assert(1 <= t && t <= ll(1e4));
while (t--)
{
readc(x, y, z);
assert(1 <= x && x <= ll(1e15));
assert(1 <= y && y <= ll(1e15));
assert(max(x, y) < z && z <= ll(1e15));
int r = 2*z - x - y - 1;
int l = z - max(x, y);
print(r - l + 1);
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The universe contains a magic number <b>z</b>. Thor's power is known to <b>x</b> and Loki's power to be <b>y</b>.
One's strength is defined to be <b>z - a</b>, if his power is <b>a</b>. Your task is to find out who among Thor and Loki has the highest strength, and print that strength.
<b>Note:</b> The input and answer may not fit in a 32-bit integer type. In particular, if you are using C++ consider using <em>long long int</em> over <em>int</em>.The first line contains one integer t — the number of test cases.
Each test case consists of one line containing three space-separated integers x, y and z.
<b> Constraints: </b>
1 ≤ t ≤ 10<sup>4</sup>
1 ≤ x, y ≤ 10<sup>15</sup>
max(x, y) < z ≤ 10<sup>15</sup>For each test case, print a single value - the largest strength among Thor and Loki.Sample Input
2
2 3 4
1 1 5
Sample Output
2
4, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define int long long
void solve()
{
int t;
cin>>t;
while(t--)
{
int x, y, z;
cin>>x>>y>>z;
cout<<max(z - y, z- x)<<endl;
}
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cerr.tie(NULL);
#ifndef ONLINE_JUDGE
if (fopen("INPUT.txt", "r"))
{
freopen("INPUT.txt", "r", stdin);
freopen("OUTPUT.txt", "w", stdout);
}
#endif
solve();
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Bob has a fantasy for integer 200. He has an integer N and wants you to do the given operation K times and print the result.
<b>Operation:</b>
1. Add 200 to the end of it, if N is not divisible by 200.
2. Otherwise divide it by 200.
For example, 6 would become 6200 and 434 would become 434200.The first line contains two integers N and K.
Constraints
All values in the input are integers.
1≤N≤10 ^ 5
1≤K≤20Print the answer as an integer.Sample Input 1
2021 4
Sample Output 1
50531
Applying the operation on N=2021 results in N becoming 2021→2021200→10106→10106200→50531.
Sample Input 2
40000 2
Sample Output 2
1
Sample Input 3
8691 20
Sample Output 3
84875488281
The answer may not fit into the signed 32- bit integer type., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String[] str=br.readLine().split(" ");
long N=Long.parseLong(str[0]);
long K=Long.parseLong(str[1]);
for(int i=0; i<K; i++)
{
if(N % 200 == 0)
N /=200L;
else
N =(N *1000L) + 200L;
}
System.out.println(N);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Bob has a fantasy for integer 200. He has an integer N and wants you to do the given operation K times and print the result.
<b>Operation:</b>
1. Add 200 to the end of it, if N is not divisible by 200.
2. Otherwise divide it by 200.
For example, 6 would become 6200 and 434 would become 434200.The first line contains two integers N and K.
Constraints
All values in the input are integers.
1≤N≤10 ^ 5
1≤K≤20Print the answer as an integer.Sample Input 1
2021 4
Sample Output 1
50531
Applying the operation on N=2021 results in N becoming 2021→2021200→10106→10106200→50531.
Sample Input 2
40000 2
Sample Output 2
1
Sample Input 3
8691 20
Sample Output 3
84875488281
The answer may not fit into the signed 32- bit integer type., I have written this Solution Code: a,b=input().split()
for i in range(int(b)):
a=str(a)+'200' if int(a)%200!=0 else int(a)//200
print(a), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Bob has a fantasy for integer 200. He has an integer N and wants you to do the given operation K times and print the result.
<b>Operation:</b>
1. Add 200 to the end of it, if N is not divisible by 200.
2. Otherwise divide it by 200.
For example, 6 would become 6200 and 434 would become 434200.The first line contains two integers N and K.
Constraints
All values in the input are integers.
1≤N≤10 ^ 5
1≤K≤20Print the answer as an integer.Sample Input 1
2021 4
Sample Output 1
50531
Applying the operation on N=2021 results in N becoming 2021→2021200→10106→10106200→50531.
Sample Input 2
40000 2
Sample Output 2
1
Sample Input 3
8691 20
Sample Output 3
84875488281
The answer may not fit into the signed 32- bit integer type., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;++i)
const int inf = INT_MAX;
using ll = long long;
int main(){
long long int n,k;
cin >> n >> k;
rep(i,k){
if(n%200==0){
n/=200;
}else{
n=n*1000+200;
}
}
cout << n << endl;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string your task is to reverse the given string.The first line of the input contains a string.
Constraints:-
1 <= string length <= 100
String contains only lowercase english lettersThe output should contain reverse of the input string.Sample Input
abc
Sample Output
cba, I have written this Solution Code: s = input("")
print (s[::-1]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string your task is to reverse the given string.The first line of the input contains a string.
Constraints:-
1 <= string length <= 100
String contains only lowercase english lettersThe output should contain reverse of the input string.Sample Input
abc
Sample Output
cba, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
reverse(s.begin(),s.end());
cout<<s;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string your task is to reverse the given string.The first line of the input contains a string.
Constraints:-
1 <= string length <= 100
String contains only lowercase english lettersThe output should contain reverse of the input string.Sample Input
abc
Sample Output
cba, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
String s = sc.next();
for(int i = s.length()-1;i>=0;i--){
System.out.print(s.charAt(i));
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Complete the function <code>repeatWithDelay</code>. You will be given a single argument, <code>count</code>, a number.
This <code>count</code> argument should control the number of times the function should be executed with a 1-second delay. <strong>Use the JS inbuilt function, which repeatedly calls a function after a specific interval of time, to call the function after a 1-second delay </strong>. The function within the inbuilt function (i.e passed as callback) should print <code>"Interval has been executed " + executionCount + " time(s)"</code> to the console. The <code>executionCount</code> should increment as the function is called after every second. When the executionCount is equal to the count argument, clear the interval.
After executing the above function, use another <strong> JS inbuilt function that calls a function after a specific time</strong>. This callback function, within the inbuilt function, should print <code>"Interval execution stopped"</code> to the console. Use the built-in method, to clear the interval after the count+1 delay.
<strong>Note: </strong>You may see <code>"setTimeout was not called"</code> printed on the console. This is because you may have solved the question using loops.The function takes in a number.The function prints a string on the console.let count = 3;
repeatWithDelay(count);
// prints
Interval has been executed 1 time(s)
Interval has been executed 2 time(s)
Interval has been executed 3 time(s)
Interval execution stopped, I have written this Solution Code: function repeatWithDelay(count) {
let executionCount = 0;
let intervalId = setInterval(function() {
executionCount++;
console.log("Interval has been executed " + executionCount + " time(s)");
if (executionCount === count) {
clearInterval(intervalId);
}
}, 1000);
setTimeout(function() {
console.log("Interval execution stopped");
clearInterval(intervalId);
}, (count + 1) * 1000);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each i (1 < = i < = N), you have to print the number except :-
For each multiple of 3, print "Newton" instead of the number.
For each multiple of 5, print "School" instead of the number.
For numbers that are multiples of both 3 and 5, print "NewtonSchool" instead of the number.The first line of the input contains N.
<b>Constraints</b>
1 < = N < = 1000
Print N space separated number or Newton School according to the condition.Sample Input:-
3
Sample Output:-
1 2 Newton
Sample Input:-
5
Sample Output:-
1 2 Newton 4 School, I have written this Solution Code: n=int(input())
for i in range(1,n+1):
if i%3==0 and i%5==0:
print("NewtonSchool",end=" ")
elif i%3==0:
print("Newton",end=" ")
elif i%5==0:
print("School",end=" ")
else:
print(i,end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each i (1 < = i < = N), you have to print the number except :-
For each multiple of 3, print "Newton" instead of the number.
For each multiple of 5, print "School" instead of the number.
For numbers that are multiples of both 3 and 5, print "NewtonSchool" instead of the number.The first line of the input contains N.
<b>Constraints</b>
1 < = N < = 1000
Print N space separated number or Newton School according to the condition.Sample Input:-
3
Sample Output:-
1 2 Newton
Sample Input:-
5
Sample Output:-
1 2 Newton 4 School, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
static void NewtonSchool(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){System.out.print("NewtonSchool ");}
else if(i%5==0){System.out.print("School ");}
else if(i%3==0){System.out.print("Newton ");}
else{System.out.print(i+" ");}
}
}
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int x= sc.nextInt();
NewtonSchool(x);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of length N in which you can swap two elements if their sum is odd i.e for every i (1 to N) and j (1 to N) if (Arr[i] + Arr[j]) is odd then you can swap these elements.
What is the lexicographically smallest array you can obtain?First line of input contains a single integer N. Next line contains N space separated integers depicting the elements of the array.
Constraints:-
1 <= N <= 100000
1 <= Arr[i] <= 100000Print N space separated elements i. e the array which is the lexicographically smallest possibleSample Input:-
3
4 1 7
Sample Output:-
1 4 7
Explanation:-
Swap numbers at indices 1 and 2 as their sum 4 + 1 = 5 is odd
Sample Input:-
2
2 4
Sample Output:-
2 4
Sample Input:-
2
5 3
Sample Output:-
5 3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine().trim());
String array[] = br.readLine().trim().split(" ");
StringBuilder sb = new StringBuilder("");
int[] arr = new int[n];
int oddCount = 0,
evenCount = 0;
for(int i = 0; i < n; i++) {
arr[i] = Integer.parseInt(array[i]);
if(arr[i] % 2 == 0)
++evenCount;
else
++oddCount;
}
if(evenCount > 0 && oddCount > 0)
Arrays.sort(arr);
for(int i = 0; i < n; i++)
sb.append(arr[i] + " ");
System.out.println(sb.substring(0, sb.length() - 1));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of length N in which you can swap two elements if their sum is odd i.e for every i (1 to N) and j (1 to N) if (Arr[i] + Arr[j]) is odd then you can swap these elements.
What is the lexicographically smallest array you can obtain?First line of input contains a single integer N. Next line contains N space separated integers depicting the elements of the array.
Constraints:-
1 <= N <= 100000
1 <= Arr[i] <= 100000Print N space separated elements i. e the array which is the lexicographically smallest possibleSample Input:-
3
4 1 7
Sample Output:-
1 4 7
Explanation:-
Swap numbers at indices 1 and 2 as their sum 4 + 1 = 5 is odd
Sample Input:-
2
2 4
Sample Output:-
2 4
Sample Input:-
2
5 3
Sample Output:-
5 3, I have written this Solution Code: n=int(input())
p=[int(x) for x in input().split()[:n]]
o=0;e=0
for i in range(n):
if (p[i] % 2 == 1):
o += 1;
else:
e += 1;
if (o > 0 and e > 0):
p.sort();
for i in range(n):
print(p[i], end = " ");, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of length N in which you can swap two elements if their sum is odd i.e for every i (1 to N) and j (1 to N) if (Arr[i] + Arr[j]) is odd then you can swap these elements.
What is the lexicographically smallest array you can obtain?First line of input contains a single integer N. Next line contains N space separated integers depicting the elements of the array.
Constraints:-
1 <= N <= 100000
1 <= Arr[i] <= 100000Print N space separated elements i. e the array which is the lexicographically smallest possibleSample Input:-
3
4 1 7
Sample Output:-
1 4 7
Explanation:-
Swap numbers at indices 1 and 2 as their sum 4 + 1 = 5 is odd
Sample Input:-
2
2 4
Sample Output:-
2 4
Sample Input:-
2
5 3
Sample Output:-
5 3, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
int main() {
int n;
cin>>n;
long long a[n];
bool win=false,win1=false;
for(int i=0;i<n;i++){
cin>>a[i];
if(a[i]&1){win=true;}
if(a[i]%2==0){win1=true;}
}
if(win==true && win1==true){sort(a,a+n);}
for(int i=0;i<n;i++){
cout<<a[i]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String a= br.readLine();
int sum=0;
int n=a.length();
int s=0;
for(int i=0; i<n; i++){
sum=sum+ (a.charAt(i) - '0');
if(i == n-1){
s= (a.charAt(i) - '0');
}
}
if(sum%3==0 && s==0){
System.out.print("Yes");
}else{
System.out.print("No");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: /**
* Author : tourist1256
* Time : 2022-02-10 11:06:49
**/
#include <bits/stdc++.h>
using namespace std;
#define int long long int
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
int solve(string a) {
int n = a.size();
int sum = 0;
if (a[n - 1] != '0') {
return 0;
}
for (auto &it : a) {
sum += (it - '0');
}
debug(sum % 3);
if (sum % 3 == 0) {
return 1;
}
return 0;
}
int32_t main() {
ios_base::sync_with_stdio(NULL);
cin.tie(0);
string str;
cin >> str;
int res = solve(str);
if (res) {
cout << "Yes\n";
} else {
cout << "No\n";
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: A=int(input())
if A%30==0:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print a right-angle triangle pattern of consecutive numbers of height n.<b>User Task:</b>
Take only one user input <b>n</b> the height of right angle triangle.
Constraint:
1 ≤ n ≤100
Print a right angle triangle of numbers of height n.Sample Input:
5
Sample Output:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
Sample Input:
2
Sample Output:
1
1 2, I have written this Solution Code: import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int n = input.nextInt();
int num = 1;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++) {
System.out.print(num + " ");
num++;
}
num=1;
System.out.println();
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your friend and you took a true/false exam of n questions. You know your answers, your friend’s
answers, and that your friend got k questions correct.
Compute the maximum number of questions you could have gotten correctly.The first line of input contains a single integer k.
The second line contains a string of n (1 ≤ n ≤ 1000) characters, the answers you wrote down.
Each letter is either a ‘T’ or an ‘F’.
The third line contains a string of n characters, the answers your friend wrote down. Each letter
is either a ‘T’ or an ‘F’.
The input will satisfy 0 ≤ k ≤ n.Print, on one line, the maximum number of questions you could have gotten correctly.Sample Input
3
FTFFF
TFTTT
Sample Output
2, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int k = Integer.parseInt(br.readLine());
String me = br.readLine();
String myFriend = br.readLine();
int N = me.length();
int commonAns = 0;
for(int i=0; i<N; i++) {
if(me.charAt(i) == myFriend.charAt(i) ) commonAns++;
}
int ans = Math.min(k, commonAns) + Math.min(N - k, N - commonAns);
System.out.println(ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your friend and you took a true/false exam of n questions. You know your answers, your friend’s
answers, and that your friend got k questions correct.
Compute the maximum number of questions you could have gotten correctly.The first line of input contains a single integer k.
The second line contains a string of n (1 ≤ n ≤ 1000) characters, the answers you wrote down.
Each letter is either a ‘T’ or an ‘F’.
The third line contains a string of n characters, the answers your friend wrote down. Each letter
is either a ‘T’ or an ‘F’.
The input will satisfy 0 ≤ k ≤ n.Print, on one line, the maximum number of questions you could have gotten correctly.Sample Input
3
FTFFF
TFTTT
Sample Output
2, I have written this Solution Code: k = int(input())
m = 0
a = list(map(str,input()))
b = list(map(str,input()))
#print(a,b)
n = len(b)
for i in range(n):
if a[i] == b[i]:
m += 1
if k >= m :
print(n-k+m)
else:
print(n-m+k), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array A of size N, with all values as non-negative integers. Bodega asked you whether it is possible to partition the array into exactly K non-empty subarrays such that the sum of values of each subarray is equal. If it is possible print "Yes", otherwise print "No".
Note:
Every element of the array should belong to exactly one subarray in the partition.The first line consists of two space-separated integers N and K respectively.
The second line consists of N space-separated integers – A<sub>1</sub>, A<sub>2</sub>, ... A<sub>N</sub>.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ K ≤ 20
0 ≤ A<sub>i</sub> ≤ 10<sup>6</sup>
There exists at least one non-zero element in array A.Print a single word "Yes" if the array can be partitioned into K equal sum parts, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
5 2
2 2 1 2 2
Sample Output 1:
No
Sample Input 2:
10 3
3 0 1 2 0 0 6 0 1 5
Sample Output 2:
Yes
Explanation:
The array can be partitioned as {3, 0, 1, 2, 0, 0}, {6}, {0, 1, 5}., I have written this Solution Code: import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.InputMismatchException;
public class Main {
InputStream is;
PrintWriter out;
String INPUT = "";
void solve(int TC) {
int n = ni(), k = ni();
long sum = 0L, tempSum = 0;
int[] a = new int[n];
for (int i = 0; i < n; i++) {
a[i] = ni();
sum += a[i];
}
if (sum % k != 0) {
pn("No");
return;
}
long req = sum / (long) k;
for (int i : a) {
tempSum += i;
if (tempSum == req) {
tempSum = 0;
} else if (tempSum > req) {
pn("No");
return;
}
}
pn(tempSum == 0 ? "Yes" : "No");
}
boolean TestCases = false;
public static void main(String[] args) throws Exception {
new Main().run();
}
void hold(boolean b) throws Exception {
if (!b) throw new Exception("Hold right there, Sparky!");
}
static void dbg(Object... o) {
System.err.println(Arrays.deepToString(o));
}
void run() throws Exception {
is = INPUT.isEmpty() ? System.in : new ByteArrayInputStream(INPUT.getBytes());
out = new PrintWriter(System.out);
long s = System.currentTimeMillis();
int T = TestCases ? ni() : 1;
for (int t = 1; t <= T; t++) solve(t);
out.flush();
if (!INPUT.isEmpty()) tr(System.currentTimeMillis() - s + "ms");
}
void p(Object o) {
out.print(o);
}
void pn(Object o) {
out.println(o);
}
void pni(Object o) {
out.println(o);
out.flush();
}
int ni() {
int num = 0, b;
boolean minus = false;
while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
if (b == '-') {
minus = true;
b = readByte();
}
while (true) {
if (b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
b = readByte();
}
}
long nl() {
long num = 0;
int b;
boolean minus = false;
while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
if (b == '-') {
minus = true;
b = readByte();
}
while (true) {
if (b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
b = readByte();
}
}
double nd() {
return Double.parseDouble(ns());
}
char nc() {
return (char) skip();
}
int BUF_SIZE = 1024 * 8;
byte[] inbuf = new byte[BUF_SIZE];
int lenbuf = 0, ptrbuf = 0;
int readByte() {
if (lenbuf == -1) throw new InputMismatchException();
if (ptrbuf >= lenbuf) {
ptrbuf = 0;
try {
lenbuf = is.read(inbuf);
} catch (IOException e) {
throw new InputMismatchException();
}
if (lenbuf <= 0) return -1;
}
return inbuf[ptrbuf++];
}
boolean isSpaceChar(int c) {
return !(c >= 33 && c <= 126);
}
int skip() {
int b;
while ((b = readByte()) != -1 && isSpaceChar(b)) ;
return b;
}
String ns() {
int b = skip();
StringBuilder sb = new StringBuilder();
while (!(isSpaceChar(b))) {
sb.appendCodePoint(b);
b = readByte();
}
return sb.toString();
}
char[] ns(int n) {
char[] buf = new char[n];
int b = skip(), p = 0;
while (p < n && !(isSpaceChar(b))) {
buf[p++] = (char) b;
b = readByte();
}
return n == p ? buf : Arrays.copyOf(buf, p);
}
void tr(Object... o) {
if (INPUT.length() > 0) System.out.println(Arrays.deepToString(o));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array A of size N, with all values as non-negative integers. Bodega asked you whether it is possible to partition the array into exactly K non-empty subarrays such that the sum of values of each subarray is equal. If it is possible print "Yes", otherwise print "No".
Note:
Every element of the array should belong to exactly one subarray in the partition.The first line consists of two space-separated integers N and K respectively.
The second line consists of N space-separated integers – A<sub>1</sub>, A<sub>2</sub>, ... A<sub>N</sub>.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ K ≤ 20
0 ≤ A<sub>i</sub> ≤ 10<sup>6</sup>
There exists at least one non-zero element in array A.Print a single word "Yes" if the array can be partitioned into K equal sum parts, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
5 2
2 2 1 2 2
Sample Output 1:
No
Sample Input 2:
10 3
3 0 1 2 0 0 6 0 1 5
Sample Output 2:
Yes
Explanation:
The array can be partitioned as {3, 0, 1, 2, 0, 0}, {6}, {0, 1, 5}., I have written this Solution Code:
// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,fma")
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#define pi 3.141592653589793238
#define int long long
#define ll long long
#define ld long double
using namespace __gnu_pbds;
using namespace std;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());
long long powm(long long a, long long b,long long mod) {
long long res = 1;
while (b > 0) {
if (b & 1)
res = res * a %mod;
a = a * a %mod;
b >>= 1;
}
return res;
}
ll gcd(ll a, ll b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(0);
#ifndef ONLINE_JUDGE
if(fopen("input.txt","r"))
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
}
#endif
int n,k;
cin>>n>>k;
int a[n];
int sum=0;
for(int i=0;i<n;i++)
{
cin>>a[i];
sum+=a[i];
}
if(sum%k)
cout<<"No";
else
{
int tot=0;
int cur=0;
sum/=k;
for(int i=0;i<n;i++)
{
cur+=a[i];
if(cur==sum)
{
tot++;
cur=0;
}
}
if(cur==0 && tot==k)
cout<<"Yes";
else
cout<<"No";
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array A of size N, with all values as non-negative integers. Bodega asked you whether it is possible to partition the array into exactly K non-empty subarrays such that the sum of values of each subarray is equal. If it is possible print "Yes", otherwise print "No".
Note:
Every element of the array should belong to exactly one subarray in the partition.The first line consists of two space-separated integers N and K respectively.
The second line consists of N space-separated integers – A<sub>1</sub>, A<sub>2</sub>, ... A<sub>N</sub>.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ K ≤ 20
0 ≤ A<sub>i</sub> ≤ 10<sup>6</sup>
There exists at least one non-zero element in array A.Print a single word "Yes" if the array can be partitioned into K equal sum parts, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
5 2
2 2 1 2 2
Sample Output 1:
No
Sample Input 2:
10 3
3 0 1 2 0 0 6 0 1 5
Sample Output 2:
Yes
Explanation:
The array can be partitioned as {3, 0, 1, 2, 0, 0}, {6}, {0, 1, 5}., I have written this Solution Code: N,K=map(int,input().split())
S=0
a=input().split()
for i in a:
S+=int(i)
if S%K!=0:
print('No')
else:
su=0
count=0
asd=S/K
for i in range(N):
su+=int(a[i])
if su==asd:
count+=1
su=0
if count==K:
print('Yes')
else:
print('No'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N and an integer K. Print the count of distinct numbers in all subarrays of size k in the array A[].The first line of input contains two integers N and K. The next line contains N space separated values of the array A[].
Constraints:-
1 <= N, K <= 100000
1 <= A[] <= 1000000000Print the space separated values denoting counts of distinct numbers in all subarrays of size k in the array A[].Sample Input :
7 4
1 2 1 3 4 2 3
Sample Output:
3 4 4 3
Explanation:-`
First window's elements is:- 1 2 1 3 which contains 3 different elements.
Second window's elements is:- 2 1 3 4 which contains 4 different elements.
Third window's elements is:- 1 3 4 2 which contains 4 different elements.
Fourth window's elements is:- 3 4 2 3 which contains 3 different elements., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String str[] = br.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
str = br.readLine().trim().split(" ");
int arr[] = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = Integer.parseInt(str[i]);
}
HashMap<Integer, Integer> hm = new HashMap<>();
for (int i = 0; i < k; i++) {
if (hm.containsKey(arr[i])) {
int temp = hm.get(arr[i]);
hm.put(arr[i], temp+1);
}
else {
hm.put(arr[i], 1);
}
}
System.out.print(hm.size() +" ");
for (int i = k; i < n; i++) {
int temp = hm.get(arr[i-k]);
if (temp == 1){
hm.remove(arr[i-k]);
}
else {
hm.put(arr[i-k], temp-1);
}
if (hm.containsKey(arr[i])) {
temp = hm.get(arr[i]);
hm.put(arr[i], temp+1);
}
else {
hm.put(arr[i], 1);
}
System.out.print(hm.size() +" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N and an integer K. Print the count of distinct numbers in all subarrays of size k in the array A[].The first line of input contains two integers N and K. The next line contains N space separated values of the array A[].
Constraints:-
1 <= N, K <= 100000
1 <= A[] <= 1000000000Print the space separated values denoting counts of distinct numbers in all subarrays of size k in the array A[].Sample Input :
7 4
1 2 1 3 4 2 3
Sample Output:
3 4 4 3
Explanation:-`
First window's elements is:- 1 2 1 3 which contains 3 different elements.
Second window's elements is:- 2 1 3 4 which contains 4 different elements.
Third window's elements is:- 1 3 4 2 which contains 4 different elements.
Fourth window's elements is:- 3 4 2 3 which contains 3 different elements., I have written this Solution Code: n,k=input().split()
n=int(n)
k=int(k)
arr=input().split()
for i in range(0,len(arr)):
arr[i]=int(arr[i])
hs={}
for i in range(0,k):
if arr[i] not in hs:
hs[arr[i]]=1
else:
hs[arr[i]]+=1
print (len(hs),end=' ')
for i in range(k,n):
if(hs[arr[i-k]]==1):
del hs[arr[i-k]]
else:
hs[arr[i-k]]-=1
if arr[i] not in hs:
hs[arr[i]]=1
else:
hs[arr[i]]+=1
print (len(hs),end=' '), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N and an integer K. Print the count of distinct numbers in all subarrays of size k in the array A[].The first line of input contains two integers N and K. The next line contains N space separated values of the array A[].
Constraints:-
1 <= N, K <= 100000
1 <= A[] <= 1000000000Print the space separated values denoting counts of distinct numbers in all subarrays of size k in the array A[].Sample Input :
7 4
1 2 1 3 4 2 3
Sample Output:
3 4 4 3
Explanation:-`
First window's elements is:- 1 2 1 3 which contains 3 different elements.
Second window's elements is:- 2 1 3 4 which contains 4 different elements.
Third window's elements is:- 1 3 4 2 which contains 4 different elements.
Fourth window's elements is:- 3 4 2 3 which contains 3 different elements., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
unordered_map<long,int> m;
int n,k;
cin>>n>>k;
long a[n];
for(int i=0;i<n;i++){cin>>a[i];}
for(int i=0;i<k;i++){
m[a[i]]++;
}
cout<<m.size()<<" ";
int ans=m.size();
for(int i=k;i<n;i++){
m[a[i-k]]--;
if(m[a[i-k]]==0){ans--;}
m[a[i]]++;
if(m[a[i]]==1){ans++;}
cout<<ans<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a row of N shops. Each shop sells A[i] candies. Your friend made an array B of (N-1) integers where B[i] = max(A[i], A[i+1]) for i from 1 to (N-1). You are given array B. You want to generate the array A such that the sum of values of the candies in A is maximum. Find the maximum possible sum of candies of array A.The first line of input contains a single integer N.
The second line of input contains (N-1) integers denoting array B.
<b>Constraints:</b>
2 ≤ N ≤ 10<sup>5</sup>
1 ≤ B[i] ≤ 10<sup>9</sup>Print the maximum possible sum of the candies in array A.Sample Input
4
1 3 4
Sample Output
9
<b>Explanation:</b>
Optimal Array A will be [1, 1, 3, 4], I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
long b[] = new long[n-1];
long sum=0;
for(int i=0;i<n-1;i++)
{
b[i] = sc.nextLong();
}
for(int i=0;i<n-2;i++)
{
if(b[i]>b[i+1])
{
sum += b[i+1];
}
else
{
sum += b[i];
}
}
sum += b[n-2];
System.out.println(sum+b[0]);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a row of N shops. Each shop sells A[i] candies. Your friend made an array B of (N-1) integers where B[i] = max(A[i], A[i+1]) for i from 1 to (N-1). You are given array B. You want to generate the array A such that the sum of values of the candies in A is maximum. Find the maximum possible sum of candies of array A.The first line of input contains a single integer N.
The second line of input contains (N-1) integers denoting array B.
<b>Constraints:</b>
2 ≤ N ≤ 10<sup>5</sup>
1 ≤ B[i] ≤ 10<sup>9</sup>Print the maximum possible sum of the candies in array A.Sample Input
4
1 3 4
Sample Output
9
<b>Explanation:</b>
Optimal Array A will be [1, 1, 3, 4], I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
#define rep(i,n) for (int i=0; i<(n); i++)
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n;
cin>>n;
int a[n];
--n;
for(int i=0;i<n;++i){
cin>>a[i];
}
int ans=a[0]+a[n-1];
int v=0;
for(int i=1;i<n;++i){
ans+=min(a[i],a[i-1]);
}
cout<<ans;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a row of N shops. Each shop sells A[i] candies. Your friend made an array B of (N-1) integers where B[i] = max(A[i], A[i+1]) for i from 1 to (N-1). You are given array B. You want to generate the array A such that the sum of values of the candies in A is maximum. Find the maximum possible sum of candies of array A.The first line of input contains a single integer N.
The second line of input contains (N-1) integers denoting array B.
<b>Constraints:</b>
2 ≤ N ≤ 10<sup>5</sup>
1 ≤ B[i] ≤ 10<sup>9</sup>Print the maximum possible sum of the candies in array A.Sample Input
4
1 3 4
Sample Output
9
<b>Explanation:</b>
Optimal Array A will be [1, 1, 3, 4], I have written this Solution Code: n=int(input())
arr=list(map(int,input().split()))
summ=arr[-1]
for i in reversed(range(1,len(arr))):
if arr[i]>arr[i-1]:
summ+=arr[i-1]
else:
summ+=arr[i]
summ+=arr[0]
print(summ), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: According to the latest government guidelines, the mass gathering of more than or equal to X people are not allowed but Sara organizes a party in her home and invited Y of her friends. As per the government guidelines your task is to tell Sara if she is in trouble or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>candies()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X <= 1000
1 <= Y <= 1000Return 1 if Sara is in trouble else return 0.Sample Input:-
X = 3, Y = 5
Sample Output:-
1
Explanation:-
Total people in Sara's home = 5, no. of people allowed = 3
Sample Input:-
X = 4, Y = 2
Sample Output:-
0, I have written this Solution Code: static int candies(int X, int Y){
if(X<=Y){return 1;}
return 0;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: According to the latest government guidelines, the mass gathering of more than or equal to X people are not allowed but Sara organizes a party in her home and invited Y of her friends. As per the government guidelines your task is to tell Sara if she is in trouble or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>candies()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X <= 1000
1 <= Y <= 1000Return 1 if Sara is in trouble else return 0.Sample Input:-
X = 3, Y = 5
Sample Output:-
1
Explanation:-
Total people in Sara's home = 5, no. of people allowed = 3
Sample Input:-
X = 4, Y = 2
Sample Output:-
0, I have written this Solution Code: int candies(int X, int Y){
if(X<=Y){return 1;}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: According to the latest government guidelines, the mass gathering of more than or equal to X people are not allowed but Sara organizes a party in her home and invited Y of her friends. As per the government guidelines your task is to tell Sara if she is in trouble or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>candies()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X <= 1000
1 <= Y <= 1000Return 1 if Sara is in trouble else return 0.Sample Input:-
X = 3, Y = 5
Sample Output:-
1
Explanation:-
Total people in Sara's home = 5, no. of people allowed = 3
Sample Input:-
X = 4, Y = 2
Sample Output:-
0, I have written this Solution Code: def candies(X,Y):
if(X<=Y):
return 1
return 0
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: According to the latest government guidelines, the mass gathering of more than or equal to X people are not allowed but Sara organizes a party in her home and invited Y of her friends. As per the government guidelines your task is to tell Sara if she is in trouble or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>candies()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X <= 1000
1 <= Y <= 1000Return 1 if Sara is in trouble else return 0.Sample Input:-
X = 3, Y = 5
Sample Output:-
1
Explanation:-
Total people in Sara's home = 5, no. of people allowed = 3
Sample Input:-
X = 4, Y = 2
Sample Output:-
0, I have written this Solution Code: int candies(int X, int Y){
if(X<=Y){return 1;}
return 0;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a circular linked list consisting of N nodes, your task is to exchange the first and last node of the list.
<b>Note:
Examples in Sample Input and Output just show how a linked list will look depending on the questions. Do not copy-paste as it is in custom input</b><b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>exchangeNodes()</b> that takes head node as parameter.
Constraints:
3 <= N <= 1000
1 <= Node. data<= 1000Return the head of the modified linked list.Sample Input 1:-
3
1- >2- >3
Sample Output 1:-
3- >2- >1
Sample Input 2:-
4
1- >2- >3- >4
Sample Output 2:-
4- >2- >3- >1, I have written this Solution Code: public static Node exchangeNodes(Node head) {
Node p = head;
while (p.next.next != head)
p = p.next;
p.next.next = head.next;
head.next = p.next;
p.next = head;
head = head.next;
return head;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two strings A and B of equal length, We define an operation in which you can replace any substring of A with any substring of B such that the starting and ending points of the strings are the same. Your task is to count the number of unique strings you can transform A into by repeating the above operation any number of times.
<b>Note</b>:- Since the ans might be large print your answer as answer%(10<sup>9</sup> + 7)The first line of input contains a single integer N denoting the length of the string. The second line of the input contains a string A. The last line of input contains string B.
<b>Constraints:</b>
1 < = N < = 100000
<b>String will contain only lowercase english alphabets</b>Print the number of unique strings A can be transformed into modulus 10<sup>9</sup> + 7.Sample Input:-
5
newton
newton
Sample Output:-
1
Sample Input:-
3
abc
xyz
Sample Output:-
8
Explanation:-
unique strings:- { abc, xbc, xbz, xyc, xyz, ayc, ayz, abz}, I have written this Solution Code:
// author-Shivam gupta
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define max1 100001
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
signed main(){
fast();
int n;
cin>>n;
string a,b;
cin>>a>>b;
int cnt=0;
FOR(i,n){
if(a[i]!=b[i]){cnt++;}
}
int ans=1;
int x=2;
FOR(i,cnt){
ans*=x;
ans=ans%MOD;
}
out(ans);
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Palindrome is a word, phrase, or sequence that reads the same backwards as forwards. Use recursion to check if a given string is palindrome or not.User Task:
Since this is a functional problem, you don't have to worry about the input, you just have to complete the function check_Palindrome() where you will get input string, starting index of string (which is 0) and the end index of string( which is str.length-1) as argument.
Constraints:
1 ≤ T ≤ 100
1 ≤ N ≤ 10000Return true if given string is palindrome else return falseSample Input
2
ab
aba
Sample Output
false
true, I have written this Solution Code:
static boolean check_Palindrome(String str,int s, int e)
{
// If there is only one character
if (s == e)
return true;
// If first and last
// characters do not match
if ((str.charAt(s)) != (str.charAt(e)))
return false;
// If there are more than
// two characters, check if
// middle substring is also
// palindrome or not.
if (s < e + 1)
return check_Palindrome(str, s + 1, e - 1);
return true;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a binary tree, with root 1, print the postorder traversal of the tree.
Algorithm Postorder(tree)
1. Traverse the left subtree
2. Traverse the right subtree
3. Visit the rootThe input consists of N+1 lines.
First line contains the integer N, denoting the number of nodes in the binary tree.
Next N lines contains two integers denoting the left and right child of the i'th node respectively.
If the node doesn't have a left or right child, it is denoted by '-1'
1 <= N <= 10<sup>5</sup>Print a single line containing N space separated integers representing the postorder traversal of the given treeSample Input 1:
5
2 4
5 3
-1 -1
-1 -1
-1 -1
Sample output 1:
5 3 2 4 1
Explanation: Given binary tree
1
/ \
2 4
/ \
5 3
, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int n=Integer.parseInt(br.readLine());
ArrayList<ArrayList<Integer>> tree=new ArrayList<>();
ArrayList<Integer> edges=new ArrayList<>();
edges.add(1);
tree.add(edges);
while(n-->0)
{
String s[]=br.readLine().split(" ");
edges=new ArrayList<>();
edges.add(Integer.parseInt(s[0]));
edges.add(Integer.parseInt(s[1]));
tree.add(edges);
}
postOrder(tree,1);
}
static void postOrder(ArrayList<ArrayList<Integer>> tree,int index)
{
ArrayList<Integer> edges=new ArrayList<>();
edges=tree.get(index);
if(edges.get(0)!=-1)
postOrder(tree,edges.get(0));
if(edges.get(1)!=-1)
postOrder(tree,edges.get(1));
System.out.print(index+" ");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a binary tree, with root 1, print the postorder traversal of the tree.
Algorithm Postorder(tree)
1. Traverse the left subtree
2. Traverse the right subtree
3. Visit the rootThe input consists of N+1 lines.
First line contains the integer N, denoting the number of nodes in the binary tree.
Next N lines contains two integers denoting the left and right child of the i'th node respectively.
If the node doesn't have a left or right child, it is denoted by '-1'
1 <= N <= 10<sup>5</sup>Print a single line containing N space separated integers representing the postorder traversal of the given treeSample Input 1:
5
2 4
5 3
-1 -1
-1 -1
-1 -1
Sample output 1:
5 3 2 4 1
Explanation: Given binary tree
1
/ \
2 4
/ \
5 3
, I have written this Solution Code: '''
class Node:
def __init__(self,key):
self.data=key
self.left=None
self.right=None
'''
c=0
n=int(input())
l=[-1]*(n+1)
r=[-1]*(n+1)
for i in range(n):
a,b=map(int,input().split())
l[i+1]=a
r[i+1]=b
def postorder(u):
global c
if c<=n:
if len(l)>u and l[u]!=-1:
postorder(l[u])
if len(r)>u and r[u]!=-1:
postorder(r[u])
print(u,end=' ')
c+=1
postorder(1), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a binary tree, with root 1, print the postorder traversal of the tree.
Algorithm Postorder(tree)
1. Traverse the left subtree
2. Traverse the right subtree
3. Visit the rootThe input consists of N+1 lines.
First line contains the integer N, denoting the number of nodes in the binary tree.
Next N lines contains two integers denoting the left and right child of the i'th node respectively.
If the node doesn't have a left or right child, it is denoted by '-1'
1 <= N <= 10<sup>5</sup>Print a single line containing N space separated integers representing the postorder traversal of the given treeSample Input 1:
5
2 4
5 3
-1 -1
-1 -1
-1 -1
Sample output 1:
5 3 2 4 1
Explanation: Given binary tree
1
/ \
2 4
/ \
5 3
, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int l[N], r[N], c = 0;
void dfs(int u){
if(l[u] != -1)
dfs(l[u]);
if(r[u] != -1)
dfs(r[u]);
cout << u << " ";
c++;
}
signed main() {
IOS;
int n; cin >> n;
for(int i = 1; i <= n; i++){
cin >> l[i] >> r[i];
}
dfs(1);
assert(c == n);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a charity which has N people. Penny wants to donate some of her clothes to the charity in such a way that all people receive equal clothes and each individual receives <b> more than 1 </b>. If she has M clothes with her what is the maximum number of clothes one individual can get?<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Charity()</b> that takes integers N, and M as arguments.
Constraints:-
1 <= M, N <= 1000Return the maximum number of clothes one individual can get if it is impossible to distribute clothes return -1.Sample Input
6 20
Sample Output
3
Sample Input
8 5
Sample Output
-1, I have written this Solution Code: function Charity(n,m) {
// write code here
// do no console.log the answer
// return the output using return keyword
const per = Math.floor(m / n)
return per > 1 ? per : -1
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a charity which has N people. Penny wants to donate some of her clothes to the charity in such a way that all people receive equal clothes and each individual receives <b> more than 1 </b>. If she has M clothes with her what is the maximum number of clothes one individual can get?<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Charity()</b> that takes integers N, and M as arguments.
Constraints:-
1 <= M, N <= 1000Return the maximum number of clothes one individual can get if it is impossible to distribute clothes return -1.Sample Input
6 20
Sample Output
3
Sample Input
8 5
Sample Output
-1, I have written this Solution Code: static int Charity(int n, int m){
int x= m/n;
if(x<=1){return -1;}
return x;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a charity which has N people. Penny wants to donate some of her clothes to the charity in such a way that all people receive equal clothes and each individual receives <b> more than 1 </b>. If she has M clothes with her what is the maximum number of clothes one individual can get?<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Charity()</b> that takes integers N, and M as arguments.
Constraints:-
1 <= M, N <= 1000Return the maximum number of clothes one individual can get if it is impossible to distribute clothes return -1.Sample Input
6 20
Sample Output
3
Sample Input
8 5
Sample Output
-1, I have written this Solution Code: int Charity(int n, int m){
int x= m/n;
if(x<=1){return -1;}
return x;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a charity which has N people. Penny wants to donate some of her clothes to the charity in such a way that all people receive equal clothes and each individual receives <b> more than 1 </b>. If she has M clothes with her what is the maximum number of clothes one individual can get?<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Charity()</b> that takes integers N, and M as arguments.
Constraints:-
1 <= M, N <= 1000Return the maximum number of clothes one individual can get if it is impossible to distribute clothes return -1.Sample Input
6 20
Sample Output
3
Sample Input
8 5
Sample Output
-1, I have written this Solution Code: def Charity(N,M):
x = M//N
if x<=1:
return -1
return x
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a charity which has N people. Penny wants to donate some of her clothes to the charity in such a way that all people receive equal clothes and each individual receives <b> more than 1 </b>. If she has M clothes with her what is the maximum number of clothes one individual can get?<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Charity()</b> that takes integers N, and M as arguments.
Constraints:-
1 <= M, N <= 1000Return the maximum number of clothes one individual can get if it is impossible to distribute clothes return -1.Sample Input
6 20
Sample Output
3
Sample Input
8 5
Sample Output
-1, I have written this Solution Code: int Charity(int n, int m){
int x= m/n;
if(x<=1){return -1;}
return x;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
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