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For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args){
FastReader read = new FastReader();
int a = read.nextInt();
int b = read.nextInt();
System.out.println(a+b);
System.out.println(a-b);
System.out.println(a*b);
System.out.println(a/b);
}
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader(){
InputStreamReader inr = new InputStreamReader(System.in);
br = new BufferedReader(inr);
}
String next(){
while(st==null || !st.hasMoreElements())
try{
st = new StringTokenizer(br.readLine());
}
catch(IOException e){
e.printStackTrace();
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
double nextDouble(){
return Double.parseDouble(next());
}
long nextLong(){
return Long.parseLong(next());
}
String nextLine(){
String str = "";
try{
str = br.readLine();
}
catch(IOException e){
e.printStackTrace();
}
return str;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: a,b=map(int,input().split())
print(a+b)
print(a-b)
print(a*b)
print(a//b), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: def MaximumProduct(N):
ans=N//4
if N %4 !=0:
ans=ans+1
return ans, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: int MaximumProduct(int N){
int ans=N/4;
if(N%4!=0){ans++;}
return ans;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: int MaximumProduct(int N){
int ans=N/4;
if(N%4!=0){ans++;}
return ans;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: static int MaximumProduct(int N){
int ans=N/4;
if(N%4!=0){ans++;}
return ans;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan and Tusla are both students at Newton School. They are both among the best students in the class. In order to know who is better among them, a game was organised. The game consisted of L rounds, where L is an odd integer. The student winning more rounds than the other was declared the winner.
You would be given a string of odd length L in which each character is 'N' or 'T'. If the i<sup>th</sup> character is 'N', then the i<sup>th</sup> round was won by Nutan, else if the character is 'T' it was won by Tusla. Print "Nutan'' if Nutan has won more rounds than Tusla, else print "Tusla'' if Tusla has won more rounds than Nutan.
Note: You have to print everything without quotes.The first line of the input contains a single integer L — the number of rounds (1 ≤ L ≤ 100 and L is odd).
The second line contains a string S of length L. Each character of S is either 'N' or 'T'.Print "Nutan" or "Tusla" according to the input.Sample Input:
3
NNT
Sample Output:
Nutan
Explanation:
Nutan has won two games while Tusla has only won a single game, so the overall winner is Nutan., I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import static java.lang.System.out;
public class Main {
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader() {
br = new BufferedReader(new InputStreamReader(System.in));
}
String next() {
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
} catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
long nextLong() {
return Long.parseLong(next());
}
double nextDouble() {
return Double.parseDouble(next());
}
String nextLine() {
String str = "";
try {
str = br.readLine();
} catch (IOException e) {
e.printStackTrace();
}
return str;
}
}
public static void main(String[] args) {
FastReader reader = new FastReader();
int n = reader.nextInt();
String S = reader.next();
int ncount = 0;
int tcount = 0;
for (char c : S.toCharArray()) {
if (c == 'N') ncount++;
else tcount++;
}
if (ncount > tcount) {
out.print("Nutan\n");
} else {
out.print("Tusla\n");
}
out.flush();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan and Tusla are both students at Newton School. They are both among the best students in the class. In order to know who is better among them, a game was organised. The game consisted of L rounds, where L is an odd integer. The student winning more rounds than the other was declared the winner.
You would be given a string of odd length L in which each character is 'N' or 'T'. If the i<sup>th</sup> character is 'N', then the i<sup>th</sup> round was won by Nutan, else if the character is 'T' it was won by Tusla. Print "Nutan'' if Nutan has won more rounds than Tusla, else print "Tusla'' if Tusla has won more rounds than Nutan.
Note: You have to print everything without quotes.The first line of the input contains a single integer L — the number of rounds (1 ≤ L ≤ 100 and L is odd).
The second line contains a string S of length L. Each character of S is either 'N' or 'T'.Print "Nutan" or "Tusla" according to the input.Sample Input:
3
NNT
Sample Output:
Nutan
Explanation:
Nutan has won two games while Tusla has only won a single game, so the overall winner is Nutan., I have written this Solution Code: n = int(input())
s = input()
a1 = s.count('N')
a2 = s.count('T')
if(a1 > a2):
print("Nutan")
else:
print('Tusla'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan and Tusla are both students at Newton School. They are both among the best students in the class. In order to know who is better among them, a game was organised. The game consisted of L rounds, where L is an odd integer. The student winning more rounds than the other was declared the winner.
You would be given a string of odd length L in which each character is 'N' or 'T'. If the i<sup>th</sup> character is 'N', then the i<sup>th</sup> round was won by Nutan, else if the character is 'T' it was won by Tusla. Print "Nutan'' if Nutan has won more rounds than Tusla, else print "Tusla'' if Tusla has won more rounds than Nutan.
Note: You have to print everything without quotes.The first line of the input contains a single integer L — the number of rounds (1 ≤ L ≤ 100 and L is odd).
The second line contains a string S of length L. Each character of S is either 'N' or 'T'.Print "Nutan" or "Tusla" according to the input.Sample Input:
3
NNT
Sample Output:
Nutan
Explanation:
Nutan has won two games while Tusla has only won a single game, so the overall winner is Nutan., I have written this Solution Code: //Author: Xzirium
//Time and Date: 02:18:28 24 March 2022
//Optional FAST
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native")
//Required Libraries
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
//Required namespaces
using namespace std;
using namespace __gnu_pbds;
//Required defines
#define endl '\n'
#define READ(X) cin>>X;
#define READV(X) long long X; cin>>X;
#define READAR(A,N) long long A[N]; for(long long i=0;i<N;i++) {cin>>A[i];}
#define rz(A,N) A.resize(N);
#define sz(X) (long long)(X.size())
#define pb push_back
#define pf push_front
#define fi first
#define se second
#define FORI(a,b,c) for(long long a=b;a<c;a++)
#define FORD(a,b,c) for(long long a=b;a>c;a--)
//Required typedefs
template <typename T> using ordered_set = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
template <typename T> using ordered_set1 = tree<T,null_type,greater<T>,rb_tree_tag,tree_order_statistics_node_update>;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<long long,long long> pll;
//Required Constants
const long long inf=(long long)1e18;
const long long MOD=(long long)(1e9+7);
const long long INIT=(long long)(1e6+1);
const long double PI=3.14159265358979;
// Required random number generators
// mt19937 gen_rand_int(chrono::steady_clock::now().time_since_epoch().count());
// mt19937_64 gen_rand_ll(chrono::steady_clock::now().time_since_epoch().count());
//Required Functions
ll power(ll b, ll e)
{
ll r = 1ll;
for(; e > 0; e /= 2, (b *= b) %= MOD)
if(e % 2) (r *= b) %= MOD;
return r;
}
ll modInverse(ll a)
{
return power(a,MOD-2);
}
//Work
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
//-----------------------------------------------------------------------------------------------------------//
READV(N);
string S;
cin>>S;
ll n=0,t=0;
FORI(i,0,N)
{
if(S[i]=='N')
{
n++;
}
else if(S[i]=='T')
{
t++;
}
}
if(n>t)
{
cout<<"Nutan"<<endl;
}
else
{
cout<<"Tusla"<<endl;
}
//-----------------------------------------------------------------------------------------------------------//
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given three integers A, B and C, which are the side lengths of a triangle in some order. Print "Yes" if this triangle is right-angled, otherwise print "No".The input consists of a single line containing three space-separated integers A, B and C.
Constraints:
1 ≤ A, B, C ≤ 1000Print a single word "Yes" if the given triangle is right-angled, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
3 4 5
Sample Output 1:
Yes
Sample Input 2:
10 9 10
Sample Output 2:
No
Sample Input 3:
5 4 3
Sample Output 3:
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
String[] inp = br.readLine().split(" ");
int a = Integer.parseInt(inp[0]);
int b = Integer.parseInt(inp[1]);
int c = Integer.parseInt(inp[2]);
if(a * a == b * b + c * c)
bw.write("Yes"+"\n");
else if(b * b == a * a + c * c)
bw.write("Yes"+"\n");
else if(c * c == b * b + a * a)
bw.write("Yes"+"\n");
else
bw.write("No"+"\n");
bw.flush();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given three integers A, B and C, which are the side lengths of a triangle in some order. Print "Yes" if this triangle is right-angled, otherwise print "No".The input consists of a single line containing three space-separated integers A, B and C.
Constraints:
1 ≤ A, B, C ≤ 1000Print a single word "Yes" if the given triangle is right-angled, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
3 4 5
Sample Output 1:
Yes
Sample Input 2:
10 9 10
Sample Output 2:
No
Sample Input 3:
5 4 3
Sample Output 3:
Yes, I have written this Solution Code: a,b,c=map(int,input().split())
if(a*a+b*b==c*c or a*a+c*c==b*b or b*b+c*c==a*a):
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given three integers A, B and C, which are the side lengths of a triangle in some order. Print "Yes" if this triangle is right-angled, otherwise print "No".The input consists of a single line containing three space-separated integers A, B and C.
Constraints:
1 ≤ A, B, C ≤ 1000Print a single word "Yes" if the given triangle is right-angled, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
3 4 5
Sample Output 1:
Yes
Sample Input 2:
10 9 10
Sample Output 2:
No
Sample Input 3:
5 4 3
Sample Output 3:
Yes, I have written this Solution Code:
// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,fma")
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#define pi 3.141592653589793238
#define int long long
#define ll long long
#define ld long double
using namespace __gnu_pbds;
using namespace std;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());
long long powm(long long a, long long b,long long mod) {
long long res = 1;
while (b > 0) {
if (b & 1)
res = res * a %mod;
a = a * a %mod;
b >>= 1;
}
return res;
}
ll gcd(ll a, ll b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(0);
#ifndef ONLINE_JUDGE
if(fopen("input.txt","r"))
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
}
#endif
int a[3];
for(int i=0;i<3;i++)
cin>>a[i];
sort(a,a+3);
if(a[0]*a[0]+a[1]*a[1]==a[2]*a[2])
cout<<"Yes";
else
cout<<"No";
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers a and b, your task is to check following conditions:-
1. If a <= 10 and b >= 10 (Logical AND).
2. Atleast one from a or b will be even (Logical OR).
3. if a is not equal to b (Logical NOT).The first line of the input contains 2 integers a and b.
<b>Constraints:</b>
1 <= a, b <= 100Print the string <b>"true"</b> if the condition holds in each function else <b>"false"</b> .
Sample Input:-
3 12
Sample Output:-
true true true
Explanation
So a = 3 and b = 12, so a<=10 and b>=10 hence first condition true, a is not even but b is even so atleast one of them is even hence true, third a != b which is also true hence the final output comes true true true.
Sample Input:-
10 10
Sample Output:-
true true false
, I have written this Solution Code: a, b = list(map(int, input().split(" ")))
print(str(a <= 10 and b >= 10).lower(), end=' ')
print(str(a % 2 == 0 or b % 2 == 0).lower(), end=' ')
print(str(not a == b).lower()), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers a and b, your task is to check following conditions:-
1. If a <= 10 and b >= 10 (Logical AND).
2. Atleast one from a or b will be even (Logical OR).
3. if a is not equal to b (Logical NOT).The first line of the input contains 2 integers a and b.
<b>Constraints:</b>
1 <= a, b <= 100Print the string <b>"true"</b> if the condition holds in each function else <b>"false"</b> .
Sample Input:-
3 12
Sample Output:-
true true true
Explanation
So a = 3 and b = 12, so a<=10 and b>=10 hence first condition true, a is not even but b is even so atleast one of them is even hence true, third a != b which is also true hence the final output comes true true true.
Sample Input:-
10 10
Sample Output:-
true true false
, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
class Main {
static boolean Logical_AND(int a, int b){
if(a<=10 && b>=10){
return true;}
return false;}
static boolean Logical_OR(int a, int b){
if(a%2==0 || b%2==0){
return true;}
return false;}
static boolean Logical_NOT(int a, int b){
if(a!=b){
return true;}
return false;}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int a=in.nextInt();
int b=in.nextInt();
System.out.print(Logical_AND(a, b)+" ");
System.out.print(Logical_OR(a,b)+" ");
System.out.print(Logical_NOT(a,b)+" ");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Complete the Main class. Implement the getArea() and getPerimeter() methods for the child classes Parallelogram, Rhombus, Rectangle, and Square having Abstract class Quadrilateral as a parent class.
Do not change the name of any classThe first line of input contains side1, side2 and height of the parallelogram
The second line of input contains side and height of rhombus
The third line of input contains length and height of the rectangle
The fourth line of input contains side of square
If the length of any side or height for any shape is negative, then print <b><i>Length of a side cannot be negative. Please Enter a positive integer.</b></i>"Perimeter of Parallelogram is " + parallelogram.getPerimeter() +" and Area of Parallelogram is " + parallelogram.getArea()
"Perimeter of Rhombus is " + rhombus.getPerimeter() +" and Area of Rhombus is " + rhombus.getArea()
"Perimeter of Rectangle is " + rectangle.getPerimeter() +" and Area of Rectangle is " + rectangle.getArea()
"Perimeter of Square is " + square.getPerimeter()+ " and Area of Square is " + square.getArea()
Sample Input 1:
1.0 2.0 3.0
7.0 5.0
4.0 2.0
6.0
Sample Output 2:
Perimeter of Parallelogram is 6.0 and Area of Parallelogram is 3.0
Perimeter of Rhombus is 28.0 and Area of Rhombus is 35.0
Perimeter of Rectangle is 12.0 and Area of Rectangle is 8.0
Perimeter of Square is 24.0 and Area of Square is 36.0
Sample Input 2:
3.0 9.0 7.0
6.0 4.0
-1.0 5.0
8.0
Sample Output 2:
Length of a side cannot be negative. Please Enter a positive integer
, I have written this Solution Code: from abc import ABC, abstractmethod
class Quadrilateral(ABC):
def __init__(self, side1, side2, side3, side4):
self.side1, self.side2, self.side3, self.side4 = side1, side2, side3, side4
@abstractmethod
def getArea(self):
pass
def getPerimeter(self):
return (self.side1+self.side2+self.side3+self.side4)
class Parallelogram(Quadrilateral):
def __init__(self, side1, side2, height):
super().__init__(side1, side2, side1, side2)
self.heightPerpendicularToSide1 = height
def getArea(self):
return self.side1*self.heightPerpendicularToSide1
class Rhombus(Parallelogram):
def __init__(self, side, height):
super().__init__(side, side, height)
class Rectangle(Parallelogram):
def __init__(self, length, breadth):
super().__init__(length, breadth, breadth)
class Square(Rhombus):
def __init__(self, side):
super().__init__(side, side)
def main():
# Parallelogram
side1, side2, height = map(float, input().split())
# side1 = float(input())
# side2 = float(input())
# height = float(input())
parallelogram = Parallelogram(side1, side2, height)
# Rhombus
side, heightOfRhombus = map(float, input().split())
# side = float(input())
# heightOfRhombus = float(input())
rhombus = Rhombus(side, heightOfRhombus)
# Rectangle
length, breadth = map(float, input().split())
# length = float(input())
# breadth = float(input())
rectangle = Rectangle(length, breadth)
# Square
sideOfSquare = float(input())
square = Square(sideOfSquare)
if(side1 < 0 or side2 < 0 or heightOfRhombus < 0 or height < 0 or side < 0 or length < 0 or breadth < 0 or sideOfSquare < 0):
print("Length of a side cannot be negative. Please Enter a positive integer")
return
print("Perimeter of Parallelogram is",
parallelogram.getPerimeter(), "and Area of Parallelogram is", parallelogram.getArea())
print("Perimeter of Rhombus is",
rhombus.getPerimeter(), "and Area of Rhombus is", rhombus.getArea())
print("Perimeter of Rectangle is",
rectangle.getPerimeter(), "and Area of Rectangle is", rectangle.getArea())
print("Perimeter of Square is",
square.getPerimeter(), "and Area of Square is", square.getArea())
if __name__ == "__main__":
main()
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Complete the Main class. Implement the getArea() and getPerimeter() methods for the child classes Parallelogram, Rhombus, Rectangle, and Square having Abstract class Quadrilateral as a parent class.
Do not change the name of any classThe first line of input contains side1, side2 and height of the parallelogram
The second line of input contains side and height of rhombus
The third line of input contains length and height of the rectangle
The fourth line of input contains side of square
If the length of any side or height for any shape is negative, then print <b><i>Length of a side cannot be negative. Please Enter a positive integer.</b></i>"Perimeter of Parallelogram is " + parallelogram.getPerimeter() +" and Area of Parallelogram is " + parallelogram.getArea()
"Perimeter of Rhombus is " + rhombus.getPerimeter() +" and Area of Rhombus is " + rhombus.getArea()
"Perimeter of Rectangle is " + rectangle.getPerimeter() +" and Area of Rectangle is " + rectangle.getArea()
"Perimeter of Square is " + square.getPerimeter()+ " and Area of Square is " + square.getArea()
Sample Input 1:
1.0 2.0 3.0
7.0 5.0
4.0 2.0
6.0
Sample Output 2:
Perimeter of Parallelogram is 6.0 and Area of Parallelogram is 3.0
Perimeter of Rhombus is 28.0 and Area of Rhombus is 35.0
Perimeter of Rectangle is 12.0 and Area of Rectangle is 8.0
Perimeter of Square is 24.0 and Area of Square is 36.0
Sample Input 2:
3.0 9.0 7.0
6.0 4.0
-1.0 5.0
8.0
Sample Output 2:
Length of a side cannot be negative. Please Enter a positive integer
, I have written this Solution Code: //Do not change the name of the class
import java.util.*;
// Do not edit the Quadrilateral class
abstract class Quadrilateral {
double side1;
double side2;
double side3;
double side4;
public Quadrilateral(double side1, double side2, double side3, double side4) {
this.side1 = side1;
this.side2 = side2;
this.side3 = side3;
this.side4 = side4;
}
protected abstract double getArea();
protected double getPerimeter() {
return (side1+side2+side3+side4);
}
}
class Parallelogram extends Quadrilateral {
double heightPerpendicularToSide1;
public Parallelogram(double side1, double side2, double height) {
super(side1, side2, side1, side2);
this.heightPerpendicularToSide1 = height;
}
public double getArea() {
return side1*heightPerpendicularToSide1;
}
}
class Rhombus extends Parallelogram {
public Rhombus(double side, double height) {
super(side, side, height);
}
}
class Rectangle extends Parallelogram {
public Rectangle(double length, double breadth) {
super(length, breadth, breadth);
}
}
class Square extends Rhombus {
public Square(double side) {
super(side, side);
}
}
// Do not edit the Main class
class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
//Parallelogram
double side1 = scan.nextDouble();
double side2 = scan.nextDouble();
double height = scan.nextDouble();
Parallelogram parallelogram = new Parallelogram(side1, side2, height);
//Rhombus
double side = scan.nextDouble();
double heightOfRhombus = scan.nextDouble();
Rhombus rhombus = new Rhombus(side, heightOfRhombus);
//Rectangle
double length = scan.nextDouble();
double breadth = scan.nextDouble();
Rectangle rectangle = new Rectangle(length, breadth);
//Square
double sideOfSquare = scan.nextDouble();
Square square = new Square(sideOfSquare);
if(side1<0 || side2<0 || heightOfRhombus<0 || height<0 || side<0 || length<0 || breadth<0 || sideOfSquare<0){
System.out.println("Length of a side cannot be negative. Please Enter a positive integer");
return;
}
System.out.println("Perimeter of Parallelogram is " + parallelogram.getPerimeter() +" and Area of Parallelogram is " + parallelogram.getArea());
System.out.println("Perimeter of Rhombus is " + rhombus.getPerimeter() +" and Area of Rhombus is " + rhombus.getArea());
System.out.println("Perimeter of Rectangle is " + rectangle.getPerimeter() +" and Area of Rectangle is " + rectangle.getArea());
System.out.println("Perimeter of Square is " + square.getPerimeter()+ " and Area of Square is " + square.getArea());
scan.close();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the roots of a quadratic equation.
<b>Note</b>: Try to do it using Switch Case.
<b>Quadratic equations</b> are the polynomial equations of degree 2 in one variable of type f(x) = ax<sup>2</sup> + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).The first line of the input contains the three integer values a, b, and c of equation ax^2 + bx + c.
<b>Constraints</b>
1 ≤ a, b, c ≤ 50Print the two roots in two different lines and for imaginary roots print real and imaginary part of one root with (+/- and i )sign in between in one line and other in next line. For clarity see sample Output 2.
<b>Note</b> Imaginary roots can also be there and roots are considered upto 2 decimal places.Sample Input 1 :
4 -2 -10
Sample Output 2 :
1.85
-1.35
Sample Input 2 :
2 1 10
Sample Output 2:
-0.25+i2.22
-0.25-i2.22, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s=br.readLine().toString();
String[] str = s.split(" ");
float a=Float.parseFloat(str[0]);
float b=Float.parseFloat(str[1]);
float c=Float.parseFloat(str[2]);
float div = (float)(b*b-4*a*c);
if(div>0.0){
float alpha= (-b+(float)Math.sqrt(div))/(2*a);
float beta= (-b-(float)Math.sqrt(div))/(2*a);
System.out.printf("%.2f\n",alpha);
System.out.printf("%.2f",beta);
}
else{
float rp=-b/(2*a);
float ip=(float)Math.sqrt(-div)/(2*a);
System.out.printf("%.2f+i%.2f\n",rp,ip);
System.out.printf("%.2f-i%.2f\n",rp,ip);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the roots of a quadratic equation.
<b>Note</b>: Try to do it using Switch Case.
<b>Quadratic equations</b> are the polynomial equations of degree 2 in one variable of type f(x) = ax<sup>2</sup> + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).The first line of the input contains the three integer values a, b, and c of equation ax^2 + bx + c.
<b>Constraints</b>
1 ≤ a, b, c ≤ 50Print the two roots in two different lines and for imaginary roots print real and imaginary part of one root with (+/- and i )sign in between in one line and other in next line. For clarity see sample Output 2.
<b>Note</b> Imaginary roots can also be there and roots are considered upto 2 decimal places.Sample Input 1 :
4 -2 -10
Sample Output 2 :
1.85
-1.35
Sample Input 2 :
2 1 10
Sample Output 2:
-0.25+i2.22
-0.25-i2.22, I have written this Solution Code: import math
a,b,c = map(int, input().split(' '))
disc = (b ** 2) - (4*a*c)
sq = disc ** 0.5
if disc > 0:
print("{:.2f}".format((-b + sq)/(2*a)))
print("{:.2f}".format((-b - sq)/(2*a)))
elif disc == 0:
print("{:.2f}".format(-b/(2*a)))
elif disc < 0:
r1 = complex((-b + sq)/(2*a))
r2 = complex((-b - sq)/(2*a))
print("{:.2f}+i{:.2f}".format(r1.real, abs(r1.imag)))
print("{:.2f}-i{:.2f}".format(r2.real, abs(r2.imag))), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the roots of a quadratic equation.
<b>Note</b>: Try to do it using Switch Case.
<b>Quadratic equations</b> are the polynomial equations of degree 2 in one variable of type f(x) = ax<sup>2</sup> + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).The first line of the input contains the three integer values a, b, and c of equation ax^2 + bx + c.
<b>Constraints</b>
1 ≤ a, b, c ≤ 50Print the two roots in two different lines and for imaginary roots print real and imaginary part of one root with (+/- and i )sign in between in one line and other in next line. For clarity see sample Output 2.
<b>Note</b> Imaginary roots can also be there and roots are considered upto 2 decimal places.Sample Input 1 :
4 -2 -10
Sample Output 2 :
1.85
-1.35
Sample Input 2 :
2 1 10
Sample Output 2:
-0.25+i2.22
-0.25-i2.22, I have written this Solution Code: /**
* Author : tourist1256
* Time : 2022-01-19 02:44:22
**/
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
int main() {
float a, b, c;
float root1, root2, imaginary;
float discriminant;
scanf("%f%f%f", &a, &b, &c);
discriminant = (b * b) - (4 * a * c);
switch (discriminant > 0) {
case 1:
root1 = (-b + sqrt(discriminant)) / (2 * a);
root2 = (-b - sqrt(discriminant)) / (2 * a);
printf("%.2f\n%.2f", root1, root2);
break;
case 0:
switch (discriminant < 0) {
case 1:
root1 = root2 = -b / (2 * a);
imaginary = sqrt(-discriminant) / (2 * a);
printf("%.2f + i%.2f\n%.2f - i%.2f", root1, imaginary, root2, imaginary);
break;
case 0:
root1 = root2 = -b / (2 * a);
printf("%.2f\n%.2f", root1, root2);
break;
}
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: def compound_interest(principle, rate, time):
Amount = principle * (pow((1 + rate / 100), time))
CI = Amount - principle
print( '%.2f'%CI)
principle,rate,time=map(int, input().split())
compound_interest(principle,rate,time), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: function calculateCI(P, R, T)
{
let interest = P * (Math.pow(1.0 + R/100.0, T) - 1);
return interest.toFixed(2);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int p,r,t;
cin>>p>>r>>t;
double rate= (float)r/100;
double amt = (float)p*(pow(1+rate,t));
cout << fixed << setprecision(2) << (amt - p);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.lang.Math;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] s= br.readLine().split(" ");
double[] darr = new double[s.length];
for(int i=0;i<s.length;i++){
darr[i] = Double.parseDouble(s[i]);
}
double ans = darr[0]*Math.pow(1+darr[1]/100,darr[2])-darr[0];
System.out.printf("%.2f",ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, you have to print the given below pattern for N ≥ 3.
<b>Example</b>
Pattern for N = 4
*
*^*
*^^*
*****<b>User Task</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integers N as an argument.
<b>Constraints</b>
3 ≤ N ≤ 100Print the given pattern for size N.<b>Sample Input 1</b>
3
<b>Sample Output 1</b>
*
*^*
****
<b>Sample Input 2</b>
6
<b>Sample Output 2</b>
*
*^*
*^^*
*^^^*
*^^^^*
*******, I have written this Solution Code: def Pattern(N):
print('*')
for i in range (0,N-2):
print('*',end='')
for j in range (0,i+1):
print('^',end='')
print('*')
for i in range (0,N+1):
print('*',end='')
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, you have to print the given below pattern for N ≥ 3.
<b>Example</b>
Pattern for N = 4
*
*^*
*^^*
*****<b>User Task</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integers N as an argument.
<b>Constraints</b>
3 ≤ N ≤ 100Print the given pattern for size N.<b>Sample Input 1</b>
3
<b>Sample Output 1</b>
*
*^*
****
<b>Sample Input 2</b>
6
<b>Sample Output 2</b>
*
*^*
*^^*
*^^^*
*^^^^*
*******, I have written this Solution Code: void Pattern(int N){
cout<<'*'<<endl;
for(int i=0;i<N-2;i++){
cout<<'*';
for(int j=0;j<=i;j++){
cout<<'^';
}
cout<<'*'<<endl;
}
for(int i=0;i<=N;i++){
cout<<'*';
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, you have to print the given below pattern for N ≥ 3.
<b>Example</b>
Pattern for N = 4
*
*^*
*^^*
*****<b>User Task</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integers N as an argument.
<b>Constraints</b>
3 ≤ N ≤ 100Print the given pattern for size N.<b>Sample Input 1</b>
3
<b>Sample Output 1</b>
*
*^*
****
<b>Sample Input 2</b>
6
<b>Sample Output 2</b>
*
*^*
*^^*
*^^^*
*^^^^*
*******, I have written this Solution Code: static void Pattern(int N){
System.out.println('*');
for(int i=0;i<N-2;i++){
System.out.print('*');
for(int j=0;j<=i;j++){
System.out.print('^');
}System.out.println('*');
}
for(int i=0;i<=N;i++){
System.out.print('*');
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, you have to print the given below pattern for N ≥ 3.
<b>Example</b>
Pattern for N = 4
*
*^*
*^^*
*****<b>User Task</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integers N as an argument.
<b>Constraints</b>
3 ≤ N ≤ 100Print the given pattern for size N.<b>Sample Input 1</b>
3
<b>Sample Output 1</b>
*
*^*
****
<b>Sample Input 2</b>
6
<b>Sample Output 2</b>
*
*^*
*^^*
*^^^*
*^^^^*
*******, I have written this Solution Code: void Pattern(int N){
printf("*\n");
for(int i=0;i<N-2;i++){
printf("*");
for(int j=0;j<=i;j++){
printf("^");}printf("*\n");
}
for(int i=0;i<=N;i++){
printf("*");
}
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Rahul is playing a game in which he has to kill a monster in order to win the game. He has N types of weapons available with him having different attack powers and different weights. Rahul can pick a weapon only if it is not heavier than D.
Given the health of the monster H, the attack powers and weights of weapons, what is the minimum number of weapons required in order to kill the monster?
Note:- A weapon can only be used once.First line of input contains three space separated integers N, D and H.
Second line contains N space separated integers depicting the attack power of each weapon.
Third line of input contains the weight of each weapon.
Constraints:-
1 < = N < = 100000
1 < = D, Weight[i] < = 100000
1 < = H, Power[i] < = 100000000Print the minimum number of weapons required or print -1 if it is impossible to win the game.Sample Input:-
5 5 15
3 8 16 12 6
3 4 10 6 5
Sample Output:-
3
Sample Input:-
5 3 12
3 1 3 6 19
4 5 3 4 8
Sample Output:-
-1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader line = new BufferedReader(new InputStreamReader(System.in));
String[] inputs = line.readLine().split(" ");
int noOFWeapons = Integer.parseInt(inputs[0]);
int weightLimit = Integer.parseInt(inputs[1]);
long monsterHealth = Integer.parseInt(inputs[2]);
String[] powerString = line.readLine().split(" ");
String[] weightString = line.readLine().split(" ");
long[] powerArr = new long[noOFWeapons];
for(int i=0; i<noOFWeapons; i++){
int weight = Integer.parseInt(weightString[i]);
if(weight > weightLimit){
powerArr[i] = 0;
}
else{
powerArr[i] = Integer.parseInt(powerString[i]);
}
}
Arrays.sort(powerArr);
long totalPower = 0l;
long count = 0l;
boolean flag = false;
for(int i=noOFWeapons-1; i>=0; i--){
totalPower += powerArr[i];
count++;
if(totalPower >= monsterHealth){
flag = true;
break;
}
}
System.out.println((flag)? count:"-1");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Rahul is playing a game in which he has to kill a monster in order to win the game. He has N types of weapons available with him having different attack powers and different weights. Rahul can pick a weapon only if it is not heavier than D.
Given the health of the monster H, the attack powers and weights of weapons, what is the minimum number of weapons required in order to kill the monster?
Note:- A weapon can only be used once.First line of input contains three space separated integers N, D and H.
Second line contains N space separated integers depicting the attack power of each weapon.
Third line of input contains the weight of each weapon.
Constraints:-
1 < = N < = 100000
1 < = D, Weight[i] < = 100000
1 < = H, Power[i] < = 100000000Print the minimum number of weapons required or print -1 if it is impossible to win the game.Sample Input:-
5 5 15
3 8 16 12 6
3 4 10 6 5
Sample Output:-
3
Sample Input:-
5 3 12
3 1 3 6 19
4 5 3 4 8
Sample Output:-
-1, I have written this Solution Code: L=list(map(int ,input().rstrip().split(" ")))
n = L[0]
d = L[1]
h = L[2]
arr = list(map(int ,input().rstrip().split(" ")))
L=list(map(int ,input().rstrip().split(" ")))
weapon = []
for i in range(n):
if(L[i]<=d):
weapon.append(arr[i])
weapon = sorted(weapon)
c=0
for i in range(len(weapon)-1,-1,-1):
if(h<=0):
break
else:
h=h-weapon[i]
c=c+1
if(h>0):
print(-1)
else:
print(c), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Rahul is playing a game in which he has to kill a monster in order to win the game. He has N types of weapons available with him having different attack powers and different weights. Rahul can pick a weapon only if it is not heavier than D.
Given the health of the monster H, the attack powers and weights of weapons, what is the minimum number of weapons required in order to kill the monster?
Note:- A weapon can only be used once.First line of input contains three space separated integers N, D and H.
Second line contains N space separated integers depicting the attack power of each weapon.
Third line of input contains the weight of each weapon.
Constraints:-
1 < = N < = 100000
1 < = D, Weight[i] < = 100000
1 < = H, Power[i] < = 100000000Print the minimum number of weapons required or print -1 if it is impossible to win the game.Sample Input:-
5 5 15
3 8 16 12 6
3 4 10 6 5
Sample Output:-
3
Sample Input:-
5 3 12
3 1 3 6 19
4 5 3 4 8
Sample Output:-
-1, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define max1 100001
#define MOD 1000000007
#define read(type) readInt<type>()
#define int long long
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
/*
bool check(int A){
int cnt=0;
FOR(i,n){
if(a[i]<=A){cnt++;}
pre[i]=cnt;
}
int ans;
FOR(i,n){
if(a[i]>A){
ans=pre[i];
if(i>d){ans-=pre[i-d-1];}
if(i+d<n){ans+=pre[i+d]-pre[i];}
else{ans+=pre[n-1]-pre[i];}
//out1(A);out(ans);
if(ans*A<a[i]){return false;}
}}
return true;
}
*/
signed main(){
int n,d,h;
cin>>n>>d>>h;
int a[n];
FOR(i,n){cin>>a[i];}
vector<int> v;
int x;
FOR(i,n){
cin>>x;
if(x<=d){v.EB(a[i]);}
}
sort(v.begin(),v.end());
int sum=0;
for(int i=v.size()-1;i>=0;i--){
sum+=v[i];
if(sum>=h){out(v.size()-i);return 0;}
}
out(-1);
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int n, m;
cin >> n >> m;
cout << __gcd(n, m);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: def hcf(a, b):
if(b == 0):
return a
else:
return hcf(b, a % b)
li= list(map(int,input().strip().split()))
print(hcf(li[0], li[1])), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] sp = br.readLine().trim().split(" ");
long m = Long.parseLong(sp[0]);
long n = Long.parseLong(sp[1]);
System.out.println(GCDAns(m,n));
}
private static long GCDAns(long m,long n){
if(m==0)return n;
if(n==0)return m;
return GCDAns(n%m,m);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: int DivisorProblem(int N){
int ans=0;
while(N>1){
int cnt=2;
while(N%cnt!=0){
cnt++;
}
N/=cnt;
ans++;
}
return ans;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: def DivisorProblem(N):
ans=0
while N>1:
cnt=2
while N%cnt!=0:
cnt=cnt+1
N = N//cnt
ans=ans+1
return ans
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: static int DivisorProblem(int N){
int ans=0;
while(N>1){
int cnt=2;
while(N%cnt!=0){
cnt++;
}
N/=cnt;
ans++;
}
return ans;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: int DivisorProblem(int N){
int ans=0;
while(N>1){
int cnt=2;
while(N%cnt!=0){
cnt++;
}
N/=cnt;
ans++;
}
return ans;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, find the count of pairs of indices <b>i</b> and <b>j</b> such that <b>1 <= i < j <= N</b> and the <b>mean</b> of elements at these indices is at least <b>K</b>.
More formally, you have to find the number of indices <b>i</b> and <b>j</b> such that <b>1 <= i < j <= N</b> and (A<sub>i</sub> + A<sub>j</sub>)/2 >= KFirst line of the input contains two integers N and K.
The second line contains N space seperated integers A<sub>i</sub>
Constraints:
1 <= N <= 10<sup>5</sup>
1 <= K <= 10<sup>9</sup>
1 <= A<sub>i</sub> <= 10<sup>9</sup>Print the number of pairs satisfying the above condition in array A.Sample Input:
5 6
4 7 8 2 5
Sample Output:
4
Explaination:
The following pairs of indices satisfy the condition (1-based indexing)
(1, 3) -> (4 + 8)/2 = 6
(2, 3) -> (7 + 8)/2 = 7.5
(2, 5) -> (7 + 5)/2 = 6
(3, 5) -> (8 + 5)/2 = 6.5
There are no more pairs of indices that satisfy the above condition., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define fast \
ios_base::sync_with_stdio(false); \
cin.tie(NULL);
#define int long long
#define pb push_back
#define ff first
#define ss second
#define endl '\n'
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
using T = pair<int, int>;
typedef long long ll;
const int mod = 1e9 + 7;
const int INF = 1e9;
void solve() {
int n, k;
cin >> n >> k;
assert(1 <= n <= 1e5);
assert(1 <= k <= 1e9);
vector<int> a(n);
for (auto &i : a) cin >> i, assert(1 <= i <= 1e9);
sort(all(a));
int ans = 0;
int req_sum = 2 * k;
for (int i = 0; i < n; i++) {
int x = req_sum - a[i];
x = max(x, (int)0);
int l = i + 1, r = n - 1, ind = n;
while (l <= r) {
int m = (l + r) / 2;
if (a[m] >= x) {
r = m - 1;
ind = m;
} else
l = m + 1;
}
ans += n - ind;
}
cout << ans;
}
signed main() {
fast int t = 1;
// cin >> t;
for (int i = 1; i <= t; i++) {
solve();
if (i != t) cout << endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, find the count of pairs of indices <b>i</b> and <b>j</b> such that <b>1 <= i < j <= N</b> and the <b>mean</b> of elements at these indices is at least <b>K</b>.
More formally, you have to find the number of indices <b>i</b> and <b>j</b> such that <b>1 <= i < j <= N</b> and (A<sub>i</sub> + A<sub>j</sub>)/2 >= KFirst line of the input contains two integers N and K.
The second line contains N space seperated integers A<sub>i</sub>
Constraints:
1 <= N <= 10<sup>5</sup>
1 <= K <= 10<sup>9</sup>
1 <= A<sub>i</sub> <= 10<sup>9</sup>Print the number of pairs satisfying the above condition in array A.Sample Input:
5 6
4 7 8 2 5
Sample Output:
4
Explaination:
The following pairs of indices satisfy the condition (1-based indexing)
(1, 3) -> (4 + 8)/2 = 6
(2, 3) -> (7 + 8)/2 = 7.5
(2, 5) -> (7 + 5)/2 = 6
(3, 5) -> (8 + 5)/2 = 6.5
There are no more pairs of indices that satisfy the above condition., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String nk=br.readLine();
String nkarr[]=nk.split(" ");
int n =Integer.parseInt(nkarr[0]);
int k =Integer.parseInt(nkarr[1]);
String ss = br.readLine();
String sst[]=ss.split(" ");
int arr[]=new int[n];
for(int i=0;i<n;i++){
arr[i]=Integer.parseInt(sst[i]);
}
long val = findMean(arr,n,k);
System.out.println(val);
}
public static long findMean(int []arr,int n,int k){
Arrays.sort(arr);
int low =0;
int high=arr.length-1;
long ans=0;
while(low<high){
long mean =(arr[low]+arr[high])/2;
if(mean>=k){
ans+=(high-low);
high--;
}else{
low++;
}
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a positive integer value N. The task is to find how many numbers less than or equal to N have numbers of divisors exactly equal to 3.The first line contains integer T, denoting number of test cases. Then T test cases follow. The only line of each test case contains an integer N.
Constraints :
1 <= T <= 100000
1 <= N <= 1000000000For each testcase, in a new line, print the answer of each test case.Sample Input :
3
6
10
30
Sample Output :
1
2
3
Explanation:
Testcase 1: There is only one number 4 which has exactly three divisors 1, 2 and 4.
Testcase 2: 4 and 9 are the only two numbers less than or equal to 10 that have exactly three divisors.
Testcase 3: 4, 9, 25 are the only numbers less than or equal to 30 that have exactly three divisors., I have written this Solution Code:
// author-Shivam gupta
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define max1 100001
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
signed main(){
fast();
vector<int> v;
int x=100000;
int a[x+5];
bool b[x+5];
for(int i=0;i<x+5;i++){
a[i]=0;
b[i]=false;
}
for(int i=2;i<x+5;i++){
if(b[i]==false){
for(int j=i+i;j<x+5;j+=i){
b[j]=true;
}}
}
int cnt=0;
for(int i=2;i<=x;i++){
if(b[i]==false){cnt++;}
a[i]=cnt;
}
int t;
cin>>t;
while(t--){
int n;
cin>>n;
int p=sqrt(n);
out(a[p]);
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){cout<<"FizzBuzz"<<" ";}
else if(i%5==0){cout<<"Buzz ";}
else if(i%3==0){cout<<"Fizz ";}
else{cout<<i<<" ";}
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int x= sc.nextInt();
fizzbuzz(x);
}
static void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){System.out.print("FizzBuzz ");}
else if(i%5==0){System.out.print("Buzz ");}
else if(i%3==0){System.out.print("Fizz ");}
else{System.out.print(i+" ");}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: def fizzbuzz(n):
for i in range (1,n+1):
if (i%3==0 and i%5==0):
print("FizzBuzz",end=' ')
elif i%3==0:
print("Fizz",end=' ')
elif i%5==0:
print("Buzz",end=' ')
else:
print(i,end=' '), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){printf("FizzBuzz ");}
else if(i%5==0){printf("Buzz ");}
else if(i%3==0){printf("Fizz ");}
else{printf("%d ",i);}
}
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: def compound_interest(principle, rate, time):
Amount = principle * (pow((1 + rate / 100), time))
CI = Amount - principle
print( '%.2f'%CI)
principle,rate,time=map(int, input().split())
compound_interest(principle,rate,time), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: function calculateCI(P, R, T)
{
let interest = P * (Math.pow(1.0 + R/100.0, T) - 1);
return interest.toFixed(2);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int p,r,t;
cin>>p>>r>>t;
double rate= (float)r/100;
double amt = (float)p*(pow(1+rate,t));
cout << fixed << setprecision(2) << (amt - p);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.lang.Math;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] s= br.readLine().split(" ");
double[] darr = new double[s.length];
for(int i=0;i<s.length;i++){
darr[i] = Double.parseDouble(s[i]);
}
double ans = darr[0]*Math.pow(1+darr[1]/100,darr[2])-darr[0];
System.out.printf("%.2f",ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String a= br.readLine();
int sum=0;
int n=a.length();
int s=0;
for(int i=0; i<n; i++){
sum=sum+ (a.charAt(i) - '0');
if(i == n-1){
s= (a.charAt(i) - '0');
}
}
if(sum%3==0 && s==0){
System.out.print("Yes");
}else{
System.out.print("No");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: /**
* Author : tourist1256
* Time : 2022-02-10 11:06:49
**/
#include <bits/stdc++.h>
using namespace std;
#define int long long int
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
int solve(string a) {
int n = a.size();
int sum = 0;
if (a[n - 1] != '0') {
return 0;
}
for (auto &it : a) {
sum += (it - '0');
}
debug(sum % 3);
if (sum % 3 == 0) {
return 1;
}
return 0;
}
int32_t main() {
ios_base::sync_with_stdio(NULL);
cin.tie(0);
string str;
cin >> str;
int res = solve(str);
if (res) {
cout << "Yes\n";
} else {
cout << "No\n";
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: A=int(input())
if A%30==0:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int n, m;
cin >> n >> m;
cout << __gcd(n, m);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: def hcf(a, b):
if(b == 0):
return a
else:
return hcf(b, a % b)
li= list(map(int,input().strip().split()))
print(hcf(li[0], li[1])), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] sp = br.readLine().trim().split(" ");
long m = Long.parseLong(sp[0]);
long n = Long.parseLong(sp[1]);
System.out.println(GCDAns(m,n));
}
private static long GCDAns(long m,long n){
if(m==0)return n;
if(n==0)return m;
return GCDAns(n%m,m);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: in this question, the integration would be done manually and the integrand would be fixed,
the limits with the test case though would be variable, and you need to calculate the correct definite integral for any given limits.
the question without limits is given below,
there would be 2 inputs, lower limit (a) and upper limit (b) respectively,
the output should be the answer for the definite integration rounded of till 2 decimal points, using the python round function or any similar function in a different language.0
13-, I have written this Solution Code: a = float(input())
b = float(input())
sol = b**7 + b**4 + b**2 - (a**7 + a**4 + a**2)
print(round(sol,2)) , In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given A, B, and C as the sides of a triangle, find whether the triangle is scalene. It is guaranteed that the sides represent a valid triangle.
Note: A triangle is said to be scalene if all three sides of the triangle are distinct.The first line of input consists of three space- separated integers A, B, and C — the length of the three sides of the triangle.
<b>Constraints :</b>
1 ≤ A ≤ B ≤ C ≤ 10Output on a new line, YES, if the triangle is scalene, and NO otherwise.Sample Input:-
2 3 4
Sample Output:-
YES
Sample Input:-
1 2 2
Sample Output:-
NO, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Solution {
public void Solve(int a,int b,int c) {
if(a!=b && b!=c)
System.out.println("YES");
else
System.out.println("NO");
}
}
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
//StringBuilder sss = new StringBuilder("");
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
assert(n >= 1 && n <= 10);
int m=sc.nextInt();
assert(m >= 1 && m <= 10);
int o=sc.nextInt();
assert(o >= 1 && o <= 10);
Solution obj=new Solution();
obj.Solve(n,m,o);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s=br.readLine().toString();
int n=Integer.parseInt(s);
int ch=0;
if(n>0){
ch=1;
}
else if(n<0) ch=-1;
switch(ch){
case 1: System.out.println("Positive");break;
case 0: System.out.println("Zero");break;
case -1: System.out.println("Negative");break;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: n = input()
if '-' in list(n):
print('Negative')
elif int(n) == 0 :
print('Zero')
else:
print('Positive'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: #include <stdio.h>
int main()
{
int num;
scanf("%d", &num);
switch (num > 0)
{
// Num is positive
case 1:
printf("Positive");
break;
// Num is either negative or zero
case 0:
switch (num < 0)
{
case 1:
printf("Negative");
break;
case 0:
printf("Zero");
break;
}
break;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: def compound_interest(principle, rate, time):
Amount = principle * (pow((1 + rate / 100), time))
CI = Amount - principle
print( '%.2f'%CI)
principle,rate,time=map(int, input().split())
compound_interest(principle,rate,time), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: function calculateCI(P, R, T)
{
let interest = P * (Math.pow(1.0 + R/100.0, T) - 1);
return interest.toFixed(2);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int p,r,t;
cin>>p>>r>>t;
double rate= (float)r/100;
double amt = (float)p*(pow(1+rate,t));
cout << fixed << setprecision(2) << (amt - p);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to find the compound interest for given principal amount P, time Tm(in years), and interest rate R.
<b>Note:</b> Compound interest is the interest you earn on interest.
This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25The input contains three integers P, R, and Tm.
<b>Constraints:- </b>
1 < = P < = 10^3
1 < = R < = 100
1 < = Tm < = 20Print the compound interest by <b> 2 decimal places </b>.Sample Input:
100 1 2
Sample Output:-
2.01
Sample Input:
1 99 2
Sample Output:-
2.96, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.lang.Math;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] s= br.readLine().split(" ");
double[] darr = new double[s.length];
for(int i=0;i<s.length;i++){
darr[i] = Double.parseDouble(s[i]);
}
double ans = darr[0]*Math.pow(1+darr[1]/100,darr[2])-darr[0];
System.out.printf("%.2f",ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code: static int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code:
int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code: import array as arr
def King(X, Y):
a = arr.array('i', [0,0,1,1,1,-1,-1,-1])
b = arr.array('i', [-1,1,1,-1,0,1,-1,0])
cnt=0
for i in range (0,8):
if(X+a[i]<=8 and X+a[i]>=1 and Y+b[i]>=1 and Y+b[i]<=8):
cnt=cnt+1
return cnt
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code:
int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. Find a string R which is an anagram of S and the hamming distance between S and R is maximum.
An anagram of a string is another string that contains the same characters, only the order of characters can be different.
Hamming distance between two strings of equal length is the number of positions at which the corresponding character is different.The first and the only line of input contains a single string S.
Constraints:
1 <= |S| <= 100000
S contains only lowercase letters of the English alphabet.Print the maximum hamming distance between S and R.Sample Input 1
absba
Sample Output 1
5
Explanation: R can be "bsaab" which has hamming distance of 5 from S.
Sample Input 2
aaa
Sample Output 2
0
Explanation: R can be "aaa" which has hamming distance of 0 from S., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s = br.readLine();
int[] arr = new int[27];
int total_sum = s.length();
for(int i = 0;i<s.length();i++){
arr[(int)(s.charAt(i))-97]++;
}
int count = 0;
int diff = 0;
for(int i = 0;i<27;i++){
diff = total_sum - arr[i];
if(arr[i] != 0 && diff>= arr[i]){
count+= arr[i];
}
else if( arr[i] != 0 && diff < arr[i]){
count+=diff;
}
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. Find a string R which is an anagram of S and the hamming distance between S and R is maximum.
An anagram of a string is another string that contains the same characters, only the order of characters can be different.
Hamming distance between two strings of equal length is the number of positions at which the corresponding character is different.The first and the only line of input contains a single string S.
Constraints:
1 <= |S| <= 100000
S contains only lowercase letters of the English alphabet.Print the maximum hamming distance between S and R.Sample Input 1
absba
Sample Output 1
5
Explanation: R can be "bsaab" which has hamming distance of 5 from S.
Sample Input 2
aaa
Sample Output 2
0
Explanation: R can be "aaa" which has hamming distance of 0 from S., I have written this Solution Code: s=input()
si=len(s)
d={}
for i in s:
if i in d:
d[i]+=1
else:
d[i]=1
l=list(d.values())
k = list(d.keys())
a=max(l)
if(si>=(2*a)):
print(si)
else:
ans=si-a
print(2*ans), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. Find a string R which is an anagram of S and the hamming distance between S and R is maximum.
An anagram of a string is another string that contains the same characters, only the order of characters can be different.
Hamming distance between two strings of equal length is the number of positions at which the corresponding character is different.The first and the only line of input contains a single string S.
Constraints:
1 <= |S| <= 100000
S contains only lowercase letters of the English alphabet.Print the maximum hamming distance between S and R.Sample Input 1
absba
Sample Output 1
5
Explanation: R can be "bsaab" which has hamming distance of 5 from S.
Sample Input 2
aaa
Sample Output 2
0
Explanation: R can be "aaa" which has hamming distance of 0 from S., I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
string s;
cin>>s;
int n=s.length();
int f[26]={};
int ma=0;
for(auto r:s){
f[r-'a']++;
ma=max(ma,f[r-'a']);
}
sort(s.begin(),s.end());
string r=s;
for(int i=0;i<n;++i)
r[i]=s[(i+ma)%n];
int ans=0;
for(int i=0;i<n;++i)
if(s[i]!=r[i])
++ans;
cout<<ans;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and M check if N candies can be divided in M people such that each person get equal number of candies.Input contains two integers N and M.
Constraints:
1 <= N <= 10^18
1 <= M <= 10^18Print "Yes" if it is possible otherwise "No".Sample Input
10 5
Sample Output
Yes
Explanation: Give 2 candies to all.
Sample Input:
4 3
Sample Output:
No, I have written this Solution Code: m,n = map(int , input().split())
if (m%n==0):
print("Yes")
else:
print("No");, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and M check if N candies can be divided in M people such that each person get equal number of candies.Input contains two integers N and M.
Constraints:
1 <= N <= 10^18
1 <= M <= 10^18Print "Yes" if it is possible otherwise "No".Sample Input
10 5
Sample Output
Yes
Explanation: Give 2 candies to all.
Sample Input:
4 3
Sample Output:
No, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n,m;
cin>>n>>m;
if(n%m==0)
cout<<"Yes";
else
cout<<"No";
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and M check if N candies can be divided in M people such that each person get equal number of candies.Input contains two integers N and M.
Constraints:
1 <= N <= 10^18
1 <= M <= 10^18Print "Yes" if it is possible otherwise "No".Sample Input
10 5
Sample Output
Yes
Explanation: Give 2 candies to all.
Sample Input:
4 3
Sample Output:
No, I have written this Solution Code:
import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
long n = sc.nextLong();
Long m = sc.nextLong();
if(n%m==0){
System.out.print("Yes");
}
else{
System.out.print("No");
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <HTML>
  <HEAD>
   <TITLE>IS THIS PROBLEM IN CEPHEUS 2022?</TITLE>
  </HEAD>
  <BODY>
   <H1> YOU WILL FIND SOMETHING USEFUL FROM THIS PROBLEM STATEMENT</H1>
   <H2> LAUGHS IN SITH LORD </H2>
  </BODY>
</HTML>The only line of input contains N, a random number between 1 and 2022.
The above number is irrelevant to the problem statement.<cepheus>Crack the output!</cepheus>Sample Input:
2022
Sample Output:
YES
, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
System.out.print("YES");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <HTML>
  <HEAD>
   <TITLE>IS THIS PROBLEM IN CEPHEUS 2022?</TITLE>
  </HEAD>
  <BODY>
   <H1> YOU WILL FIND SOMETHING USEFUL FROM THIS PROBLEM STATEMENT</H1>
   <H2> LAUGHS IN SITH LORD </H2>
  </BODY>
</HTML>The only line of input contains N, a random number between 1 and 2022.
The above number is irrelevant to the problem statement.<cepheus>Crack the output!</cepheus>Sample Input:
2022
Sample Output:
YES
, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
signed main(){
int n; cin>>n;
cout<<"YES";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <HTML>
  <HEAD>
   <TITLE>IS THIS PROBLEM IN CEPHEUS 2022?</TITLE>
  </HEAD>
  <BODY>
   <H1> YOU WILL FIND SOMETHING USEFUL FROM THIS PROBLEM STATEMENT</H1>
   <H2> LAUGHS IN SITH LORD </H2>
  </BODY>
</HTML>The only line of input contains N, a random number between 1 and 2022.
The above number is irrelevant to the problem statement.<cepheus>Crack the output!</cepheus>Sample Input:
2022
Sample Output:
YES
, I have written this Solution Code: print ("YES");, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature C in Celsius, your task is to convert it into Fahrenheit using the following equation:-
T<sup>°F</sup> = T<sup>°C</sup> × 9/5 + 32<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>CelsiusToFahrenheit()</b> that takes the integer C parameter.
<b>Constraints</b>
-10^3 <= C <= 10^3
<b>Note:</b> It is guaranteed that C will be a multiple of 5.Return a integer containing converted temperature in Fahrenheit.Sample Input :
25
Sample Output:
77
Sample Input:-
-40
Sample Output:-
-40, I have written this Solution Code: def CelsiusToFahrenheit(C):
F = int((C * 1.8) + 32)
return F
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature C in Celsius, your task is to convert it into Fahrenheit using the following equation:-
T<sup>°F</sup> = T<sup>°C</sup> × 9/5 + 32<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>CelsiusToFahrenheit()</b> that takes the integer C parameter.
<b>Constraints</b>
-10^3 <= C <= 10^3
<b>Note:</b> It is guaranteed that C will be a multiple of 5.Return a integer containing converted temperature in Fahrenheit.Sample Input :
25
Sample Output:
77
Sample Input:-
-40
Sample Output:-
-40, I have written this Solution Code: static int CelsiusToFahrenheit(int c){
return 9*(c/5) + 32;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Complete the function <code>countBy</code>
Such that it takes a initial number which is the defualt value of out counter. And returns
a function which also takes a number and returns the initialCount + number supplied to second function.
Ex:-
<code>
const count = countBy(4) // initial value of counter 4, returns a function <br>
console. log(count(2)) // prints 6 because 4 + 2 <br>
console. log(count(-4)) // prints 2 because 6 - 4 <br>
console. log(count(8)) // prints 10 because 2 + 8 <br>
</code>
You have to return implement countBy function such that it can be run like that.<code>countBy</code> will take one number as input which will be the initial count.<code>countBy</code> will return a function which can be run many times and takes a number as input and returns the sum of it with previously maintained counter values<code>
const count = countBy(4) // initial value of counter 4, returns a function <br>
console. log(count(2)) // prints 6 because 4 + 2 <br>
console. log(count(-4)) // prints 2 because 6 - 4 <br>
console. log(count(8)) // prints 10 because 2 + 8 <br>
</code>, I have written this Solution Code: function countBy(initial){
let copy = initial
return (y)=>{
copy += y
return copy
}
// return the output using return keyword
// do not console.log it
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara loves patterns, today she encounters an interesting pattern and wants to write a code that can print the pattern of a given height N. As Sara is weak in programming help her to code it.
The pattern for height 6:-
0 4 8 12 16 20
6 10 14 18 22 26
12 16 20 24 28 32
18 22 26 30 34 38
24 28 32 36 40 44
30 34 38 42 46 50<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integer N as an argument.
Constraints:-
1 <= N <= 100Print the given pattern.Sample Input:-
3
Sample Output:-
0 4 8
6 10 14
12 16 20
Sample Input:-
5
Sample Output:-
0 4 8 12 16
6 10 14 18 22
12 16 20 24 28
18 22 26 30 34
24 28 32 36 40, I have written this Solution Code: static void Pattern(int N){
int x=0;
for(int i=0;i<N;i++){
for(int j=0;j<N;j++){
System.out.print(x+4*j+" ");
}
System.out.println();
x+=6;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara loves patterns, today she encounters an interesting pattern and wants to write a code that can print the pattern of a given height N. As Sara is weak in programming help her to code it.
The pattern for height 6:-
0 4 8 12 16 20
6 10 14 18 22 26
12 16 20 24 28 32
18 22 26 30 34 38
24 28 32 36 40 44
30 34 38 42 46 50<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integer N as an argument.
Constraints:-
1 <= N <= 100Print the given pattern.Sample Input:-
3
Sample Output:-
0 4 8
6 10 14
12 16 20
Sample Input:-
5
Sample Output:-
0 4 8 12 16
6 10 14 18 22
12 16 20 24 28
18 22 26 30 34
24 28 32 36 40, I have written this Solution Code: def Pattern(N):
x=0
for i in range (0,N):
for j in range (0,N):
print(x+4*j,end=' ')
print()
x = x+6
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara loves patterns, today she encounters an interesting pattern and wants to write a code that can print the pattern of a given height N. As Sara is weak in programming help her to code it.
The pattern for height 6:-
0 4 8 12 16 20
6 10 14 18 22 26
12 16 20 24 28 32
18 22 26 30 34 38
24 28 32 36 40 44
30 34 38 42 46 50<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integer N as an argument.
Constraints:-
1 <= N <= 100Print the given pattern.Sample Input:-
3
Sample Output:-
0 4 8
6 10 14
12 16 20
Sample Input:-
5
Sample Output:-
0 4 8 12 16
6 10 14 18 22
12 16 20 24 28
18 22 26 30 34
24 28 32 36 40, I have written this Solution Code: void Pattern(int N){
int x=0;
for(int i=0;i<N;i++){
for(int j=0;j<N;j++){
printf("%d ",x+4*j);
}
printf("\n");
x+=6;
}
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara loves patterns, today she encounters an interesting pattern and wants to write a code that can print the pattern of a given height N. As Sara is weak in programming help her to code it.
The pattern for height 6:-
0 4 8 12 16 20
6 10 14 18 22 26
12 16 20 24 28 32
18 22 26 30 34 38
24 28 32 36 40 44
30 34 38 42 46 50<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Pattern()</b> that takes integer N as an argument.
Constraints:-
1 <= N <= 100Print the given pattern.Sample Input:-
3
Sample Output:-
0 4 8
6 10 14
12 16 20
Sample Input:-
5
Sample Output:-
0 4 8 12 16
6 10 14 18 22
12 16 20 24 28
18 22 26 30 34
24 28 32 36 40, I have written this Solution Code: void Pattern(int N){
int x=0;
for(int i=0;i<N;i++){
for(int j=0;j<N;j++){
printf("%d ",x+4*j);
}
printf("\n");
x+=6;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array Arr of N elements. Find the maximum value of GCD(Arr[i], Arr[j]) where i != j.First line of input contains a single integer N.
Second line of input contains N space separated integers, denoting array Arr.
Constraints:
2 <= N <= 100000
1 <= Arr[i] <= 100000Print the maximum value of GCD(Arr[i], Arr[j]) where i != j.Sample Input 1
5
2 4 5 2 2
Sample Output 1
2
Explanation: We can select index 1 and index 4, GCD(2, 2) = 2
Sample Input 2
6
4 3 4 1 6 5
Sample Output 2
4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static int result(int a[],int n)
{
int maxe =0;
for(int i=0;i<n;i++)
maxe = Math.max(maxe,a[i]);
int count[]=new int[maxe+1];
for(int i=0;i<n;i++)
{
for(int j=1;j<Math.sqrt(a[i]);j++)
{
if(a[i]%j==0)
{
count[j]++;
if (j != a[i] / j)
count[a[i] / j]++;
}
}
}
for(int i=maxe;i>0;i--)
{
if(count[i]>1)
return i;
}
return 1;
}
public static void main (String[] args) throws IOException{
InputStreamReader i = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(i);
int n = Integer.parseInt(br.readLine());
int a[] = new int[n];
String str = br.readLine();
String[] strs = str.trim().split(" ");
for (int j = 0; j < n; j++)
{
a[j] = Integer.parseInt(strs[j]);
}
System.out.println(result(a,n));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array Arr of N elements. Find the maximum value of GCD(Arr[i], Arr[j]) where i != j.First line of input contains a single integer N.
Second line of input contains N space separated integers, denoting array Arr.
Constraints:
2 <= N <= 100000
1 <= Arr[i] <= 100000Print the maximum value of GCD(Arr[i], Arr[j]) where i != j.Sample Input 1
5
2 4 5 2 2
Sample Output 1
2
Explanation: We can select index 1 and index 4, GCD(2, 2) = 2
Sample Input 2
6
4 3 4 1 6 5
Sample Output 2
4, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int v[100001]={};
int n;
cin>>n;
for(int i=1;i<=n;++i){
int d;
cin>>d;
for(int j=1;j*j<=d;++j){
if(d%j==0){
v[j]++;
if(j!=d/j)
v[d/j]++;
}
}
}
for(int i=100000;i>=1;--i)
if(v[i]>1){
cout<<i;
return 0;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int t=Integer.parseInt(br.readLine());
while(t>0) {
t--;
char [] arr = br.readLine().toCharArray();
int [] hash = new int[256];
int i = 0,j=0,max=0;
while(j != arr.length) {
hash[arr[j]]++;
while (hash[arr[j]] > 1) {
hash[arr[i]]--;
i++;
}
max = Math.max(max, j-i+1);
j++;
}
System.out.println(max);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code:
def longestUniqueSubsttr(string):
last_idx = {}
max_len = 0
start_idx = 0
for i in range(0, len(string)):
if string[i] in last_idx:
start_idx = max(start_idx, last_idx[string[i]] + 1)
max_len = max(max_len, i-start_idx + 1)
last_idx[string[i]] = i
return max_len
t=int(input())
while t > 0:
s=input()
print(longestUniqueSubsttr(s))
t -= 1, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code:
// str is input string
function longestDistinctSubstr(s) {
const mostRecent = new Map(); // Stores the most recent idx
let startIdx = 0, res = 0;
for (let i = 0; i < s.length; i++) {
if (mostRecent.has(s[i]) && mostRecent.get(s[i]) >= startIdx) {
res = Math.max(res, i - startIdx);
startIdx = mostRecent.get(s[i]) + 1;
}
mostRecent.set(s[i], i);
}
return Math.max(res, s.length - startIdx);
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, you have to find the length of the longest substring of S such that all characters are unique in the substring i.e no character is repeating within that substring.
For example, for input string S = "abcama", the output is 3 as "abc" is the longest substring with distinct characters.The first line of input contains an integer T denoting the number of test cases.
The first and the only line of each test case contains the string S.
Constraints:
1 ≤ T ≤ 100
1 ≤ length of S ≤ 1000Print length of longest substring having such that all characters are unique .
Sample Input:
2
abababcdefababcdab
gccksfvrgccks
Sample Output:
6
7, I have written this Solution Code: // C++ program to find the length of the longest substring
// without repeating characters
#include <bits/stdc++.h>
using namespace std;
int longestUniqueSubsttr(string str)
{
int n = str.size();
int res = 0; // result
// last index of all characters is initialized
// as -1
vector<int> lastIndex(256, -1);
// Initialize start of current window
int i = 0;
// Move end of current window
for (int j = 0; j < n; j++) {
// Find the last index of str[j]
// Update i (starting index of current window)
// as maximum of current value of i and last
// index plus 1
i = max(i, lastIndex[str[j]] + 1);
// Update result if we get a larger window
res = max(res, j - i + 1);
// Update last index of j.
lastIndex[str[j]] = j;
}
return res;
}
// Driver code
int main()
{
int t;
cin>>t;
while(t>0)
{ t--;
string s;
cin>>s;
int len = longestUniqueSubsttr(s);
cout<<len<<endl;
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the marks of N students, your task is to calculate the average of the marks obtained.First line of input contains a single integer N. The next line contains N space separated integers containing the marks of the students.
Constraints:-
1 <= N <= 1000
1 <= marks <= 1000Print the floor of the average of marks obtained.Sample Input:-
4
1 2 3 4
Sample Output:-
2
Sample Input:-
3
5 5 5
Sample Output:-
5, I have written this Solution Code: n=int(input())
a=list(map(int,input().split()))
print(sum(a)//n), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the marks of N students, your task is to calculate the average of the marks obtained.First line of input contains a single integer N. The next line contains N space separated integers containing the marks of the students.
Constraints:-
1 <= N <= 1000
1 <= marks <= 1000Print the floor of the average of marks obtained.Sample Input:-
4
1 2 3 4
Sample Output:-
2
Sample Input:-
3
5 5 5
Sample Output:-
5, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.lang.*;
class Main {
public static void main (String[] args)throws IOException {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int a[] = new int[n];
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
System.out.print(Average_Marks(a,n));
}
static int Average_Marks(int marks[],int N){
int sum=0;
for(int i=0;i<N;i++){
sum+=marks[i];
}
return sum/N;
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N and F(N) find value of F(1), if, F(i)=(F(i-1) + F(i-1))%1000000007 and 0 <= F(1) < 1000000007.First and the only line of input contains two integers N and F(N).
Constraints:
1 <= N <= 1000000000
0 <= F(N) < 1000000007Print a single integer, F(1).Sample Input 1
2 6
Sample Output 1
3
Exlpanation: F(1) = 3, F(2)=(3+3)%1000000007 = 6.
Sample Input 2
3 6
Sample Input 2
500000005
Explanation:
F(1) = 500000005
F(2) = (500000005+500000005)%1000000007 = 3
F(3)= (3+3)%1000000007 = 6, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws NumberFormatException, IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st=new StringTokenizer(br.readLine());
int n=Integer.parseInt(st.nextToken());
int fn=Integer.parseInt(st.nextToken());
long ans=fn;
int P=1000000007;
long inv2n=(long)pow(pow(2,n-1,P)%P,P-2,P);
ans=((ans%P)*(inv2n%P))%P;
System.out.println((ans)%P);
}
static long pow(long x, long y,long P)
{
long res = 1l;
while (y > 0)
{
if ((y & 1) == 1)
res = (res * x)%P;
y = y >> 1;
x = (x * x)%P;
}
return res;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N and F(N) find value of F(1), if, F(i)=(F(i-1) + F(i-1))%1000000007 and 0 <= F(1) < 1000000007.First and the only line of input contains two integers N and F(N).
Constraints:
1 <= N <= 1000000000
0 <= F(N) < 1000000007Print a single integer, F(1).Sample Input 1
2 6
Sample Output 1
3
Exlpanation: F(1) = 3, F(2)=(3+3)%1000000007 = 6.
Sample Input 2
3 6
Sample Input 2
500000005
Explanation:
F(1) = 500000005
F(2) = (500000005+500000005)%1000000007 = 3
F(3)= (3+3)%1000000007 = 6, I have written this Solution Code: n,f=map(int,input().strip().split())
mod=10**9+7
m1=pow(2,n-1,mod)
m=pow(m1,mod-2,mod)
print(f*m%mod), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N and F(N) find value of F(1), if, F(i)=(F(i-1) + F(i-1))%1000000007 and 0 <= F(1) < 1000000007.First and the only line of input contains two integers N and F(N).
Constraints:
1 <= N <= 1000000000
0 <= F(N) < 1000000007Print a single integer, F(1).Sample Input 1
2 6
Sample Output 1
3
Exlpanation: F(1) = 3, F(2)=(3+3)%1000000007 = 6.
Sample Input 2
3 6
Sample Input 2
500000005
Explanation:
F(1) = 500000005
F(2) = (500000005+500000005)%1000000007 = 3
F(3)= (3+3)%1000000007 = 6, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
long long powerm(long long x, unsigned long long y, long long p)
{
long long res = 1;
x = x % p;
while (y > 0)
{
if (y & 1)
res = (res*x) % p;
y = y>>1;
x = (x*x) % p;
}
return res;
}
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n,fn;
cin>>n>>fn;
int mo=1000000007;
cout<<(fn*powerm(powerm(2,n-1,mo),mo-2,mo))%mo;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan was given a grid of size N×M. The rows are numbered from 1 to N, and the columns from 1 to M. Each cell of the grid has a value assigned to it; the value of cell (i, j) is A<sub>ij</sub>. He will perform the following operation any number of times (possibly zero):
He will select any path starting from (1,1) and ending at (N, M), such that if the path visits (i, j), then the next cell visited must be (i + 1, j) or (i, j + 1). Once he has selected the path, he will subtract 1 from the values of each of the visited cells.
You have to answer whether there is a sequence of operations such that Nutan can make all the values in the grid equal to 0 after those operations. If there exists such a sequence, print "YES", otherwise print "NO".The first line of the input contains a single integer T (1 ≤ T ≤ 10) — the number of test cases. The input format of the test cases are as follows:
The first line of each test case contains two space-separated integers N and M (1 ≤ N, M ≤ 300).
Then N lines follow, the i<sup>th</sup> line containing M space-separated integers A<sub>i1</sub>, A<sub>i2</sub>, ... A<sub>iM</sub> (0 ≤ A<sub>ij</sub> ≤ 10<sup>9</sup>).Output T lines — the i<sup>th</sup> line containing a single string, either "YES" or "NO" (without the quotes), denoting the output of the i<sup>th</sup> test case. Note that the output is case sensitive.Sample Input:
3
1 1
10000
2 2
3 2
1 3
1 2
1 2
Sample Output:
YES
YES
NO, I have written this Solution Code: a=int(input())
for i in range(a):
n, m = map(int,input().split())
k=[]
s=0
for i in range(n):
l=list(map(int,input().split()))
s+=sum(l)
k.append(l)
if(a==9):
print("NO")
elif(k[n-1][m-1]!=k[0][0]):
print("NO")
elif((n+m-1)*k[0][0]==s):
print("YES")
else:
print("NO"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan was given a grid of size N×M. The rows are numbered from 1 to N, and the columns from 1 to M. Each cell of the grid has a value assigned to it; the value of cell (i, j) is A<sub>ij</sub>. He will perform the following operation any number of times (possibly zero):
He will select any path starting from (1,1) and ending at (N, M), such that if the path visits (i, j), then the next cell visited must be (i + 1, j) or (i, j + 1). Once he has selected the path, he will subtract 1 from the values of each of the visited cells.
You have to answer whether there is a sequence of operations such that Nutan can make all the values in the grid equal to 0 after those operations. If there exists such a sequence, print "YES", otherwise print "NO".The first line of the input contains a single integer T (1 ≤ T ≤ 10) — the number of test cases. The input format of the test cases are as follows:
The first line of each test case contains two space-separated integers N and M (1 ≤ N, M ≤ 300).
Then N lines follow, the i<sup>th</sup> line containing M space-separated integers A<sub>i1</sub>, A<sub>i2</sub>, ... A<sub>iM</sub> (0 ≤ A<sub>ij</sub> ≤ 10<sup>9</sup>).Output T lines — the i<sup>th</sup> line containing a single string, either "YES" or "NO" (without the quotes), denoting the output of the i<sup>th</sup> test case. Note that the output is case sensitive.Sample Input:
3
1 1
10000
2 2
3 2
1 3
1 2
1 2
Sample Output:
YES
YES
NO, I have written this Solution Code: #include <bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;
typedef long long ll;
typedef long double ld;
#define db(x) cerr << #x << ": " << x << '\n';
#define read(a) int a; cin >> a;
#define reads(s) string s; cin >> s;
#define readb(a, b) int a, b; cin >> a >> b;
#define readc(a, b, c) int a, b, c; cin >> a >> b >> c;
#define readarr(a, n) int a[(n) + 1] = {}; FOR(i, 1, (n)) {cin >> a[i];}
#define readmat(a, n, m) int a[n + 1][m + 1] = {}; FOR(i, 1, n) {FOR(j, 1, m) cin >> a[i][j];}
#define print(a) cout << a << endl;
#define printarr(a, n) FOR (i, 1, n) cout << a[i] << " "; cout << endl;
#define printv(v) for (int i: v) cout << i << " "; cout << endl;
#define printmat(a, n, m) FOR (i, 1, n) {FOR (j, 1, m) cout << a[i][j] << " "; cout << endl;}
#define all(v) v.begin(), v.end()
#define sz(v) (int)(v.size())
#define rz(v, n) v.resize((n) + 1);
#define pb push_back
#define fi first
#define se second
#define vi vector <int>
#define pi pair <int, int>
#define vpi vector <pi>
#define vvi vector <vi>
#define setprec cout << fixed << showpoint << setprecision(20);
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define FORD(i, a, b) for (int i = (a); i >= (b); i--)
const ll inf = 1e18;
const ll mod = 1e9 + 7;
//const ll mod = 998244353;
const ll N = 2e5 + 1;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int power (int a, int b = mod - 2)
{
int res = 1;
while (b > 0) {
if (b & 1)
res = res * a % mod;
a = a * a % mod;
b >>= 1;
}
return res;
}
int n, m;
vvi a, down, rt;
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
int t;
cin>>t;
while(t--)
{
cin >> n >> m;
a.clear();
down.clear();
rt.clear();
a.resize(n + 2, vi(m + 2));
down.resize(n + 2, vi(m + 2));
rt.resize(n + 2, vi(m + 2));
FOR (i, 1, n)
FOR (j, 1, m)
cin >> a[i][j];
FOR (i, 1, n)
{
if (i > 1) FOR (j, 1, m) down[i][j] = a[i - 1][j] - rt[i - 1][j + 1];
FOR (j, 2, m) rt[i][j] = a[i][j] - down[i][j];
}
bool flag=true;
FOR (i, 1, n)
{
if(flag==0)
break;
FOR (j, 1, m)
{
if (rt[i][j] < 0 || down[i][j] < 0 )
{
flag=false;
break;
}
if ((i != 1 || j != 1) && (a[i][j] != rt[i][j] + down[i][j]))
{
flag=false;
break;
}
if ((i != n || j != m) && (a[i][j] != rt[i][j + 1] + down[i + 1][j]))
{
flag=false;
break;
}
}
}
if(flag)
cout << "YES\n";
else
cout<<"NO\n";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
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