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For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: int DivisorProblem(int N){
int ans=0;
while(N>1){
int cnt=2;
while(N%cnt!=0){
cnt++;
}
N/=cnt;
ans++;
}
return ans;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: def DivisorProblem(N):
ans=0
while N>1:
cnt=2
while N%cnt!=0:
cnt=cnt+1
N = N//cnt
ans=ans+1
return ans
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: static int DivisorProblem(int N){
int ans=0;
while(N>1){
int cnt=2;
while(N%cnt!=0){
cnt++;
}
N/=cnt;
ans++;
}
return ans;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is solving a math problem in which she has been given an integer N and her task is to find the number of operations required to convert N into 1.
Where in one operation you replace the number with its second-highest divisor.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DivisorProblem()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 100000Return the number of operations required.Sample Input:-
100
Sample Output:-
4
Explanation:-
100 - > 50
50 - > 25
25 - > 5
5 - > 1
Sample Input:-
10
Sample Output:-
2, I have written this Solution Code: int DivisorProblem(int N){
int ans=0;
while(N>1){
int cnt=2;
while(N%cnt!=0){
cnt++;
}
N/=cnt;
ans++;
}
return ans;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integer N and K, find the minimum number of times N must be multiplied by X to make it divisible by (2<sup>K</sup>).
Where X = Summation (2<sup>(4*i)</sup>) for 1 <= i <= 25.The first and the only line of input contains two space separated integers N and K.
Constraints
1 <= N <= 10^18
1 <= K <= 10^18Print a single integer which is the minimum number of times N must be multiplied by X to make it divisible by (2<sup>K</sup>).Sample Input 1
40 4
Sample Output 1
1
Sample Input
40 3
Sample Output
0, I have written this Solution Code: import java.util.InputMismatchException;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
public class Main {
InputStream is;
PrintWriter out;
String INPUT = "";
int MAX = (int) 1e5, MOD = (int)1e9+7;
void solve(int TC) {
long n = nl();
long k = nl();
int p = 0;
while(n>0 && n%2==0) {
n/=2;
++p;
}
if(p>=k) {pn(0);return;}
k -= p;
long ans = (k+3L)/4L;
pn(ans);
}
boolean TestCases = false;
public static void main(String[] args) throws Exception { new Main().run(); }
long pow(long a, long b) {
if(b==0 || a==1) return 1;
long o = 1;
for(long p = b; p > 0; p>>=1) {
if((p&1)==1) o = (o*a) % MOD;
a = (a*a) % MOD;
} return o;
}
long inv(long x) {
long o = 1;
for(long p = MOD-2; p > 0; p>>=1) {
if((p&1)==1)o = (o*x)%MOD;
x = (x*x)%MOD;
} return o;
}
long gcd(long a, long b) { return (b==0) ? a : gcd(b,a%b); }
int gcd(int a, int b) { return (b==0) ? a : gcd(b,a%b); }
void run() throws Exception {
is = INPUT.isEmpty() ? System.in : new ByteArrayInputStream(INPUT.getBytes());
out = new PrintWriter(System.out);
long s = System.currentTimeMillis();
int T = TestCases ? ni() : 1;
for(int t=1;t<=T;t++) solve(t);
out.flush();
if(!INPUT.isEmpty())tr(System.currentTimeMillis()-s+"ms");
}
void p(Object o) { out.print(o); }
void pn(Object o) { out.println(o); }
void pni(Object o) { out.println(o);out.flush(); }
double PI = 3.141592653589793238462643383279502884197169399;
int ni() {
int num = 0, b;
boolean minus = false;
while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
if(b == '-') {
minus = true;
b = readByte();
}
while(true) {
if(b >= '0' && b <= '9'){
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
b = readByte();
}
}
long nl() {
long num = 0;
int b;
boolean minus = false;
while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
if(b == '-') {
minus = true;
b = readByte();
}
while(true) {
if(b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
b = readByte();
}
}
double nd() { return Double.parseDouble(ns()); }
char nc() { return (char)skip(); }
int BUF_SIZE = 1024 * 8;
byte[] inbuf = new byte[BUF_SIZE];
int lenbuf = 0, ptrbuf = 0;
int readByte() {
if(lenbuf == -1)throw new InputMismatchException();
if(ptrbuf >= lenbuf){
ptrbuf = 0;
try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); }
if(lenbuf <= 0)return -1;
} return inbuf[ptrbuf++];
}
boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }
int skip() { int b; while((b = readByte()) != -1 && isSpaceChar(b)); return b; }
String ns() {
int b = skip();
StringBuilder sb = new StringBuilder();
while(!(isSpaceChar(b))) {
sb.appendCodePoint(b); b = readByte();
} return sb.toString();
}
char[] ns(int n) {
char[] buf = new char[n];
int b = skip(), p = 0;
while(p < n && !(isSpaceChar(b))){
buf[p++] = (char)b;
b = readByte();
} return n == p ? buf : Arrays.copyOf(buf, p);
}
void tr(Object... o) { if(INPUT.length() > 0)System.out.println(Arrays.deepToString(o)); }
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integer N and K, find the minimum number of times N must be multiplied by X to make it divisible by (2<sup>K</sup>).
Where X = Summation (2<sup>(4*i)</sup>) for 1 <= i <= 25.The first and the only line of input contains two space separated integers N and K.
Constraints
1 <= N <= 10^18
1 <= K <= 10^18Print a single integer which is the minimum number of times N must be multiplied by X to make it divisible by (2<sup>K</sup>).Sample Input 1
40 4
Sample Output 1
1
Sample Input
40 3
Sample Output
0, I have written this Solution Code: [n,k]=[int(j) for j in input().split()]
a=0
while n%2==0:
a+=1
n=n//2
if k>a:
print((k-a-1)//4+1)
else:
print(0), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integer N and K, find the minimum number of times N must be multiplied by X to make it divisible by (2<sup>K</sup>).
Where X = Summation (2<sup>(4*i)</sup>) for 1 <= i <= 25.The first and the only line of input contains two space separated integers N and K.
Constraints
1 <= N <= 10^18
1 <= K <= 10^18Print a single integer which is the minimum number of times N must be multiplied by X to make it divisible by (2<sup>K</sup>).Sample Input 1
40 4
Sample Output 1
1
Sample Input
40 3
Sample Output
0, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n,k;
cin>>n>>k;
while(k&&n%2==0){
n/=2;
--k;
}
cout<<(k+3)/4;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Today is Newton School's first class of this year. Nutan, a student at Newton School, has received his first assignment. He will be given a string as input. His task is to print "Gravity'' if the input is "Apple''; otherwise, he will have to print "Space''.
Can you help Nutan in solving his first assignment? Note that the quotation marks are just for clarity. They are not part of the input string, and should not be a part of your output string.The input consists of a single line that contains a string S (1 ≤ length of S ≤ 10). The string only consists of lowercase and uppercase letters.Print "Gravity'' or "Space'' according to the input.Sample Input 1:
Apple
Sample Output 1:
Gravity
Sample Input 2:
Mango
Sample Output 2:
Space
Sample Input 3:
AppLE
Sample Output 3:
Space, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader()
{
br = new BufferedReader(
new InputStreamReader(System.in));
}
String next()
{
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
}
catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() { return Integer.parseInt(next()); }
long nextLong() { return Long.parseLong(next()); }
double nextDouble()
{
return Double.parseDouble(next());
}
String nextLine()
{
String str = "";
try {
str = br.readLine();
}
catch (IOException e) {
e.printStackTrace();
}
return str;
}
}
public static void main (String[] args) {
FastReader sc= new FastReader();
String str= sc.nextLine();
String a="Apple";
if(a.equals(str)){
System.out.println("Gravity");
}
else{
System.out.println("Space");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Today is Newton School's first class of this year. Nutan, a student at Newton School, has received his first assignment. He will be given a string as input. His task is to print "Gravity'' if the input is "Apple''; otherwise, he will have to print "Space''.
Can you help Nutan in solving his first assignment? Note that the quotation marks are just for clarity. They are not part of the input string, and should not be a part of your output string.The input consists of a single line that contains a string S (1 ≤ length of S ≤ 10). The string only consists of lowercase and uppercase letters.Print "Gravity'' or "Space'' according to the input.Sample Input 1:
Apple
Sample Output 1:
Gravity
Sample Input 2:
Mango
Sample Output 2:
Space
Sample Input 3:
AppLE
Sample Output 3:
Space, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
//Work
int main()
{
#ifndef ONLINE_JUDGE
if (fopen("INPUT.txt", "r"))
{
freopen ("INPUT.txt" , "r" , stdin);
//freopen ("OUTPUT.txt" , "w" , stdout);
}
#endif
//-----------------------------------------------------------------------------------------------------------//
string S;
cin>>S;
if(S=="Apple")
{
cout<<"Gravity"<<endl;
}
else
{
cout<<"Space"<<endl;
}
//-----------------------------------------------------------------------------------------------------------//
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Today is Newton School's first class of this year. Nutan, a student at Newton School, has received his first assignment. He will be given a string as input. His task is to print "Gravity'' if the input is "Apple''; otherwise, he will have to print "Space''.
Can you help Nutan in solving his first assignment? Note that the quotation marks are just for clarity. They are not part of the input string, and should not be a part of your output string.The input consists of a single line that contains a string S (1 ≤ length of S ≤ 10). The string only consists of lowercase and uppercase letters.Print "Gravity'' or "Space'' according to the input.Sample Input 1:
Apple
Sample Output 1:
Gravity
Sample Input 2:
Mango
Sample Output 2:
Space
Sample Input 3:
AppLE
Sample Output 3:
Space, I have written this Solution Code: n=input()
if n=='Apple':print('Gravity')
else:print('Space'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code: function numberOfDays(n)
{
let ans;
switch(n)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
ans = Number(31);
break;
case 2:
ans = Number(28);
break;
default:
ans = Number(30);
break;
}
return ans;
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code:
static void numberofdays(int M){
if(M==4 || M ==6 || M==9 || M==11){System.out.print(30);}
else if(M==2){System.out.print(28);}
else{
System.out.print(31);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a Python class named Rectangle constructed by a length and width and a method that will compute the area of a rectangle.The first and only line contains the length and breadth of the rectangle.Prints the area of the rectangle.Sample Input:
2 3
Sample Output:
6
Explanation:
The area of a rectangle with length 2 and breadth 3 is 6., I have written this Solution Code: class Rectangle():
def __init__(self, l, w):
self.length = l
self.width = w
def rectangle_area(self):
return self.length*self.width
l, b = map(int,input().split())
newRectangle = Rectangle(l,b)
a=newRectangle.rectangle_area()
print(a), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N print the last digit of the given integer.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>LastDigit()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 10000Return the last digit of the given integer.Sample Input:-
123
Sample Output:-
3
Sample Input:-
6
Sample Output:-
6, I have written this Solution Code: int LastDigit(int N){
return N%10;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N print the last digit of the given integer.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>LastDigit()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 10000Return the last digit of the given integer.Sample Input:-
123
Sample Output:-
3
Sample Input:-
6
Sample Output:-
6, I have written this Solution Code: static int LastDigit(int N){
return N%10;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N print the last digit of the given integer.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>LastDigit()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 10000Return the last digit of the given integer.Sample Input:-
123
Sample Output:-
3
Sample Input:-
6
Sample Output:-
6, I have written this Solution Code: int LastDigit(int N){
return N%10;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N print the last digit of the given integer.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>LastDigit()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 10000Return the last digit of the given integer.Sample Input:-
123
Sample Output:-
3
Sample Input:-
6
Sample Output:-
6, I have written this Solution Code: def LastDigit(N):
return N%10, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, your task is to convert the number into a single digit by repeatedly replacing the number N with its sum of digits until the number becomes a single digit.The input contains a single integer N.
Constraints:-
1 <= N <= 100000Print the single digit after performing the given operation.Sample Input:-
987
Sample Output:-
6
Explanation:-
987 - > 9 + 8 + 7 => 24 = 2 + 4 => 6
Sample Input:-
91
Sample Output:-
1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(
new InputStreamReader(System.in)
);
int n = Integer.parseInt(br.readLine());
int sum =0;
while(sum>9 || n>0){
if (n == 0) {
n = sum;
sum = 0;
}
sum += n%10;
n /= 10;
}
System.out.println(sum);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, your task is to convert the number into a single digit by repeatedly replacing the number N with its sum of digits until the number becomes a single digit.The input contains a single integer N.
Constraints:-
1 <= N <= 100000Print the single digit after performing the given operation.Sample Input:-
987
Sample Output:-
6
Explanation:-
987 - > 9 + 8 + 7 => 24 = 2 + 4 => 6
Sample Input:-
91
Sample Output:-
1, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int n;
cin>>n;
while(n>9){
int p = n;
int sum=0;
while(p>0){
sum+=p%10;
p/=10;
}
n=sum;
}
cout<<n;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, your task is to convert the number into a single digit by repeatedly replacing the number N with its sum of digits until the number becomes a single digit.The input contains a single integer N.
Constraints:-
1 <= N <= 100000Print the single digit after performing the given operation.Sample Input:-
987
Sample Output:-
6
Explanation:-
987 - > 9 + 8 + 7 => 24 = 2 + 4 => 6
Sample Input:-
91
Sample Output:-
1, I have written this Solution Code: def singleDigit(n):
while(n>9):
p = n
sumDigit = 0
while(p>0):
sumDigit += p%10
p//=10
n = sumDigit
return sumDigit
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array, your task is to sort the array using merge sort.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>implementMergeSort()</b> that takes 3 arguments.
arr: input array
start: starting index which is 0
end: ending index of array
Constraints
1 <= T <= 100
1 <= N <= 10<sup>6</sup>
0 <= Arr[i] <= 10<sup>9</sup>
Sum of 'N' over all test cases does not exceed 10<sup>6</sup>You need to return the sorted array. The driver code will print the array in sorted form.Sample Input:
2
3
3 1 2
3
4 5 6
Sample Output:
1 2 3
4 5 6, I have written this Solution Code:
public static int[] implementMergeSort(int arr[], int start, int end)
{
if (start < end)
{
// Find the middle point
int mid = (start+end)/2;
// Sort first and second halves
implementMergeSort(arr, start, mid);
implementMergeSort(arr , mid+1, end);
// Merge the sorted halves
merge(arr, start, mid, end);
}
return arr;
}
public static void merge(int arr[], int start, int mid, int end)
{
// Find sizes of two subarrays to be merged
int n1 = mid - start + 1;
int n2 = end - mid;
/* Create temp arrays */
int L[] = new int [n1];
int R[] = new int [n2];
/*Copy data to temp arrays*/
for (int i=0; i<n1; ++i)
L[i] = arr[start + i];
for (int j=0; j<n2; ++j)
R[j] = arr[mid + 1+ j];
/* Merge the temp arrays */
// Initial indexes of first and second subarrays
int i = 0, j = 0;
// Initial index of merged subarry array
int k = start;
while (i < n1 && j < n2)
{
if (L[i] <= R[j])
{
arr[k] = L[i];
i++;
}
else
{
arr[k] = R[j];
j++;
}
k++;
}
/* Copy remaining elements of L[] if any */
while (i < n1)
{
arr[k] = L[i];
i++;
k++;
}
/* Copy remaining elements of R[] if any */
while (j < n2)
{
arr[k] = R[j];
j++;
k++;
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array, your task is to sort the array using merge sort.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>implementMergeSort()</b> that takes 3 arguments.
arr: input array
start: starting index which is 0
end: ending index of array
Constraints
1 <= T <= 100
1 <= N <= 10<sup>6</sup>
0 <= Arr[i] <= 10<sup>9</sup>
Sum of 'N' over all test cases does not exceed 10<sup>6</sup>You need to return the sorted array. The driver code will print the array in sorted form.Sample Input:
2
3
3 1 2
3
4 5 6
Sample Output:
1 2 3
4 5 6, I have written this Solution Code: for _ in range(int(input())):
n = int(input())
print(*sorted(list(map(int,input().split())))), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of N integers. You have to find whether A has some subsequence of length at least 3 that is a palindrome.First line of the input contains an integer N.
The second line of the input contains N space seperated integers.
Constraints:
1 <= N <= 5000
1 <= A<sub>i</sub> <= 10<sup>9</sup>Print "YES" if A has some subseqeuence of length at least 3 that is a palindrome, else print "NO", without the quotes.Sample Input:
5
1 5 2 2 1
Sample Output:
YES
Explanation:
We pick the elements at indices 1, 3, 4, 5 (1- indexed) making the subsequence: [1, 2, 2, 1], which is a palindrome., I have written this Solution Code: def sunpal(n,a):
ok=False
for i in range(n):
for j in range(i+2,n):
if a[i]==a[j]:
ok=True
return("YES" if ok else "NO")
if __name__=="__main__":
n=int(input())
a=input().split()
res=sunpal(n,a)
print(res), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of N integers. You have to find whether A has some subsequence of length at least 3 that is a palindrome.First line of the input contains an integer N.
The second line of the input contains N space seperated integers.
Constraints:
1 <= N <= 5000
1 <= A<sub>i</sub> <= 10<sup>9</sup>Print "YES" if A has some subseqeuence of length at least 3 that is a palindrome, else print "NO", without the quotes.Sample Input:
5
1 5 2 2 1
Sample Output:
YES
Explanation:
We pick the elements at indices 1, 3, 4, 5 (1- indexed) making the subsequence: [1, 2, 2, 1], which is a palindrome., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL);
#define int long long
#define pb push_back
#define ff first
#define ss second
#define endl '\n'
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
using T = pair<int, int>;
typedef long double ld;
const int mod = 1e9 + 7;
const int INF = 1e18;
void solve(){
int N;
cin >> N;
map<int, int> mp;
string ans = "NO";
for(int i = 1; i <= N; i++) {
int a;
cin >> a;
if(mp[a] != 0 and mp[a] <= i - 2) {
ans = "YES";
}
if(mp[a] == 0) mp[a] = i;
}
cout << ans;
}
signed main(){
fast
int t = 1;
// cin >> t;
for(int i = 1; i <= t; i++){
solve();
if(i != t) cout << endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <HTML>
  <HEAD>
   <TITLE>IS THIS PROBLEM IN CEPHEUS 2022?</TITLE>
  </HEAD>
  <BODY>
   <H1> YOU WILL FIND SOMETHING USEFUL FROM THIS PROBLEM STATEMENT</H1>
   <H2> LAUGHS IN SITH LORD </H2>
  </BODY>
</HTML>The only line of input contains N, a random number between 1 and 2022.
The above number is irrelevant to the problem statement.<cepheus>Crack the output!</cepheus>Sample Input:
2022
Sample Output:
YES
, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
System.out.print("YES");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <HTML>
  <HEAD>
   <TITLE>IS THIS PROBLEM IN CEPHEUS 2022?</TITLE>
  </HEAD>
  <BODY>
   <H1> YOU WILL FIND SOMETHING USEFUL FROM THIS PROBLEM STATEMENT</H1>
   <H2> LAUGHS IN SITH LORD </H2>
  </BODY>
</HTML>The only line of input contains N, a random number between 1 and 2022.
The above number is irrelevant to the problem statement.<cepheus>Crack the output!</cepheus>Sample Input:
2022
Sample Output:
YES
, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
signed main(){
int n; cin>>n;
cout<<"YES";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <HTML>
  <HEAD>
   <TITLE>IS THIS PROBLEM IN CEPHEUS 2022?</TITLE>
  </HEAD>
  <BODY>
   <H1> YOU WILL FIND SOMETHING USEFUL FROM THIS PROBLEM STATEMENT</H1>
   <H2> LAUGHS IN SITH LORD </H2>
  </BODY>
</HTML>The only line of input contains N, a random number between 1 and 2022.
The above number is irrelevant to the problem statement.<cepheus>Crack the output!</cepheus>Sample Input:
2022
Sample Output:
YES
, I have written this Solution Code: print ("YES");, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: for i in range(int(input())):
n, x = map(int, input().split())
if x >= 10:
print(0)
else:
print((10-x)*(n-1)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n, x;
cin >> n >> x;
if(x >= 10)
cout << 0 << endl;
else
cout << (10-x)*(n-1) << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int T = Integer.parseInt(br.readLine());
while (T -->0){
String s[] = br.readLine().split(" ");
int n = Integer.parseInt(s[0]);
int p = Integer.parseInt(s[1]);
if (p<10)
System.out.println(Math.abs(n-1)*(10-p));
else System.out.println(0);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your task is to implement a stack using a linked list and perform given queries
Note:-if stack is already empty than pop operation will do nothing and 0 will be printed as a top element of stack if it is empty.User task:
Since this will be a functional problem, you don't have to take input. You just have to complete the functions:
<b>push()</b>:- that takes the integer to be added as a parameter.
<b>pop()</b>:- that takes no parameter.
<b>top()</b> :- that takes no parameter.
Constraints:
1 <= N(number of queries) <= 10<sup>3</sup>You don't need to print anything else other than in top function in which you require to print the top most element of your stack in a new line, if the stack is empty you just need to print 0.Input:
7
push 1
push 2
top
pop
top
pop
top
Output:
2
1
0
, I have written this Solution Code:
Node top = null;
public void push(int x)
{
Node temp = new Node(x);
temp.next = top;
top = temp;
}
public void pop()
{
if (top == null) {
}
else {
top = (top).next;}
}
public void top()
{
// check for stack underflow
if (top == null) {
System.out.println("0");
}
else {
Node temp = top;
System.out.println(temp.val);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code: function numberOfDays(n)
{
let ans;
switch(n)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
ans = Number(31);
break;
case 2:
ans = Number(28);
break;
default:
ans = Number(30);
break;
}
return ans;
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code:
static void numberofdays(int M){
if(M==4 || M ==6 || M==9 || M==11){System.out.print(30);}
else if(M==2){System.out.print(28);}
else{
System.out.print(31);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix Mat of m rows and n columns. The matrix is boolean so the elements of the matrix can only be either 0 or 1.
Now, if any row of the matrix contains a 1, then you need to fill that whole row with 1. After doing the mentioned operation, you need to print the modified matrix.The first line of input contains T denoting the number of test cases. T test cases follow.
The first line of each test case contains m and n denotes the number of rows and a number of columns.
Then next m lines contain n elements denoting the elements of the matrix.
Constraints:
1 ≤ T ≤ 20
1 ≤ m, n ≤ 700
Mat[I][j] ∈ {0,1}For each testcase, in a new line, print the modified matrix.Input:
1
5 4
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Output:
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1
Explanation:
Rows = 5 and columns = 4
The given matrix is
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Evidently, the first row contains a 1 so fill the whole row with 1. The third row also contains a 1 so that row will be filled too. Finally, the last row contains a 1 and therefore it needs to be filled with 1 too.
The final matrix is
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1, I have written this Solution Code: t=int(input())
while t!=0:
m,n=input().split()
m,n=int(m),int(n)
for i in range(m):
arr=input().strip()
if '1' in arr:
arr='1 '*n
else:
arr='0 '*n
print(arr)
t-=1, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix Mat of m rows and n columns. The matrix is boolean so the elements of the matrix can only be either 0 or 1.
Now, if any row of the matrix contains a 1, then you need to fill that whole row with 1. After doing the mentioned operation, you need to print the modified matrix.The first line of input contains T denoting the number of test cases. T test cases follow.
The first line of each test case contains m and n denotes the number of rows and a number of columns.
Then next m lines contain n elements denoting the elements of the matrix.
Constraints:
1 ≤ T ≤ 20
1 ≤ m, n ≤ 700
Mat[I][j] ∈ {0,1}For each testcase, in a new line, print the modified matrix.Input:
1
5 4
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Output:
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1
Explanation:
Rows = 5 and columns = 4
The given matrix is
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Evidently, the first row contains a 1 so fill the whole row with 1. The third row also contains a 1 so that row will be filled too. Finally, the last row contains a 1 and therefore it needs to be filled with 1 too.
The final matrix is
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define N 1000
int a[N][N];
// Driver code
int main()
{
int t;
cin>>t;
while(t--){
int n,m;
cin>>n>>m;
bool b[n];
for(int i=0;i<n;i++){
b[i]=false;
}
for(int i=0;i<n;i++){
for(int j=0;j<m;j++){
cin>>a[i][j];
if(a[i][j]==1){
b[i]=true;
}
}
}
for(int i=0;i<n;i++){
if(b[i]){
for(int j=0;j<m;j++){
cout<<1<<" ";
}}
else{
for(int j=0;j<m;j++){
cout<<0<<" ";
}
}
cout<<endl;
}
}}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix Mat of m rows and n columns. The matrix is boolean so the elements of the matrix can only be either 0 or 1.
Now, if any row of the matrix contains a 1, then you need to fill that whole row with 1. After doing the mentioned operation, you need to print the modified matrix.The first line of input contains T denoting the number of test cases. T test cases follow.
The first line of each test case contains m and n denotes the number of rows and a number of columns.
Then next m lines contain n elements denoting the elements of the matrix.
Constraints:
1 ≤ T ≤ 20
1 ≤ m, n ≤ 700
Mat[I][j] ∈ {0,1}For each testcase, in a new line, print the modified matrix.Input:
1
5 4
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Output:
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1
Explanation:
Rows = 5 and columns = 4
The given matrix is
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Evidently, the first row contains a 1 so fill the whole row with 1. The third row also contains a 1 so that row will be filled too. Finally, the last row contains a 1 and therefore it needs to be filled with 1 too.
The final matrix is
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main(String[] args) throws Exception{
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader bf = new BufferedReader(isr);
int t = Integer.parseInt(bf.readLine());
while (t-- > 0){
String inputs[] = bf.readLine().split(" ");
int m = Integer.parseInt(inputs[0]);
int n = Integer.parseInt(inputs[1]);
String[] matrix = new String[m];
for(int i=0; i<m; i++){
matrix[i] = bf.readLine();
}
StringBuffer ones = new StringBuffer("");
StringBuffer zeros = new StringBuffer("");
for(int i=0; i<n; i++){
ones.append("1 ");
zeros.append("0 ");
}
for(int i=0; i<m; i++){
if(matrix[i].contains("1")){
System.out.println(ones);
}else{
System.out.println(zeros);
}
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a sequence of 5 integers A. Initially, A<sub>i</sub> (1 ≤ i ≤ 5) assigns i.
But due to some glitch, one of the integers in the array becomes 0.
Find out which integer of A assigned 0.The first line contains 5 integers A<sub>1</sub>, A<sub>2</sub> ... A<sub>5</sub>.
<b>Constraints</b>
The values of A<sub>1</sub>, A<sub>2</sub>, A<sub>3</sub>, A<sub>4</sub>, A<sub>5</sub> given as input are a possible outcome of the assignment.If the integer assigned 0 was A<sub>i</sub>, print the integer i.<b>Sample Input 1:</b>
0 2 3 4 5
<b>Sample Output 1:</b>
1
<b>Sample Input 2:</b>
1 2 0 4 5
<b>Sample Output 2:</b>
3, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
using ll = long long;
#define fi first
#define se second
#define all(a) a.begin(),a.end()
int main(){
for(int i=0; i<5; ++i){
int x;
cin >> x;
if(x==0) cout << i+1 << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: static void printInteger(int N){
System.out.println(N);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: void printInteger(int x){
printf("%d", x);
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: void printIntger(int n)
{
cout<<n;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: n=int(input())
print (n), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a queue of integers and N queries. Your the task is to perform these operations:-
enqueue:-this operation will add an element to your current queue.
dequeue:-this operation will delete the element from the starting of the queue
displayfront:-this operation will print the element presented at front
Note:-if queue is empty than dequeue operation will do nothing, and 0 will be printed as a front element of queue if it is empty.User task:
Since this will be a functional problem, you don't have to take input. You just have to complete the functions:
<b>enqueue()</b>:- that takes the queue and the integer to be added as a parameter.
<b>dequeue</b>:- that takes the queue as parameter.
<b>displayfront</b> :- that takes the queue as parameter.
Constraints:
1 <= N(Number of queries) <= 10<sup>3</sup>You don't need to print anything else other than in displayfront() in which you require to print the element at front of your queue in a new line, if the queue is empty you just need to print 0.Sample Input:-
7
displayfront
enqueue 2
displayfront
enqueue 4
displayfront
dequeue
displayfront
Sample Output:-
0
2
2
4
Sample input:
5
enqueue 4
enqueue 5
displayfront
dequeue
displayfront
Sample output:-
4
5, I have written this Solution Code: public static void enqueue (Queue < Integer > st, int x)
{
st.add (x);
}
public static void dequeue (Queue < Integer > st)
{
if (st.isEmpty () == false)
{
int x = st.remove();
}
}
public static void displayfront(Queue < Integer > st)
{
int x = 0;
if (st.isEmpty () == false)
{
x = st.peek ();
}
System.out.println (x);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: static void printDataTypes(int a, long b, float c, double d, char e)
{
System.out.println(a);
System.out.println(b);
System.out.printf("%.2f",c);
System.out.println();
System.out.printf("%.4f",d);
System.out.println();
System.out.println(e);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: void printDataTypes(int a, long long b, float c, double d, char e){
cout<<a<<endl;
cout<<b<<endl;
cout <<fixed<< std::setprecision(2) << c << '\n';
cout <<fixed<< std::setprecision(4) << d << '\n';
cout<<e<<endl;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: a=int(input())
b=int(input())
x=float(input())
g = "{:.2f}".format(x)
d=float(input())
e = "{:.4f}".format(d)
u=input()
print(a)
print(b)
print(g)
print(e)
print(u), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. The Force of an element is the square of its value.
<b>Note:</b>
Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
The next line contains n integers denoting elements of the array.
<b>Constraints:</b>
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7Output the maximum force.Sample Input 1:
4 4
1 2 3 4
Sample Output 1:
30
Sample Input 2:
2 1
1 10
Sample Output 2:
100
<b>Explanation:</b>
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int m = 100001;
int main(){
int n,k;
cin>>n>>k;
long long a[n],sum=0;
for(int i=0;i<n;i++){
cin>>a[i];
if(a[i]<0){
a[i]=-a[i];
}
}
sort(a,a+n);
for(int i=0;i<k;i++){
sum+=a[n-i-1]*a[n-i-1];
}
cout<<sum;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. The Force of an element is the square of its value.
<b>Note:</b>
Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
The next line contains n integers denoting elements of the array.
<b>Constraints:</b>
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7Output the maximum force.Sample Input 1:
4 4
1 2 3 4
Sample Output 1:
30
Sample Input 2:
2 1
1 10
Sample Output 2:
100
<b>Explanation:</b>
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
InputStreamReader ir = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(ir);
String[] NK = br.readLine().split(" ");
String[] inputs = br.readLine().split(" ");
int N = Integer.parseInt(NK[0]);
int K = Integer.parseInt(NK[1]);
long[] arr = new long[N];
long answer = 0;
for(int i = 0; i < N; i++){
arr[i] = Math.abs(Long.parseLong(inputs[i]));
}
quicksort(arr, 0, N-1);
for(int i = (N-K); i < N;i++){
answer += (arr[i]*arr[i]);
}
System.out.println(answer);
}
static void quicksort(long[] arr, int start, int end){
if(start < end){
int pivot = partition(arr, start, end);
quicksort(arr, start, pivot-1);
quicksort(arr, pivot+1, end);
}
}
static int partition(long[] arr, int start, int end){
long pivot = arr[end];
int i = start - 1;
for(int j = start; j < end; j++){
if(arr[j] < pivot){
i++;
swap(arr, i, j);
}
}
swap(arr, i+1, end);
return (i+1);
}
static void swap(long[] arr, int i, int j){
long temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. The Force of an element is the square of its value.
<b>Note:</b>
Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
The next line contains n integers denoting elements of the array.
<b>Constraints:</b>
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7Output the maximum force.Sample Input 1:
4 4
1 2 3 4
Sample Output 1:
30
Sample Input 2:
2 1
1 10
Sample Output 2:
100
<b>Explanation:</b>
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30, I have written this Solution Code: x,y = map(int,input().split())
arr = list(map(int,input().split()))
s=0
for i in range(x):
if arr[i]<0:
arr[i]=abs(arr[i])
arr=sorted(arr,reverse=True)
for i in range(0,y):
s = s+arr[i]*arr[i]
print(s)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code: static int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code:
int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code: import array as arr
def King(X, Y):
a = arr.array('i', [0,0,1,1,1,-1,-1,-1])
b = arr.array('i', [-1,1,1,-1,0,1,-1,0])
cnt=0
for i in range (0,8):
if(X+a[i]<=8 and X+a[i]>=1 and Y+b[i]>=1 and Y+b[i]<=8):
cnt=cnt+1
return cnt
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code:
int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code:
long long KOperations(long long N, long long K){
long long p;
while(K--){
p=N;
while(p>=10){
p=p/10;
}
if(p==1){return N;}
N*=p;
}
return N;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code:
long long int KOperations(long long N, long long K){
long long int p;
while(K--){
p=N;
while(p>=10){
p=p/10;
}
if(p==1){return N;}
N*=p;
}
return N;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code: public static long KOperations(long N, long K){
long p=N;
while(K-->0){
p=N;
while(p>=10){
p=p/10;
}
if(p==1){return N;}
N=N*p;
}
return N;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code:
def KOperations(N,K) :
# Final result of summation of divisors
while K>0 :
p=N
while(p>=10):
p=p/10
if(int(p)==1):
return N;
N=N*int(p)
K=K-1
return N;
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code:
long long KOperations(long long N, long long K){
long long p;
while(K--){
p=N;
while(p>=10){
p=p/10;
}
if(p==1){return N;}
N*=p;
}
return N;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code:
long long int KOperations(long long N, long long K){
long long int p;
while(K--){
p=N;
while(p>=10){
p=p/10;
}
if(p==1){return N;}
N*=p;
}
return N;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code: public static long KOperations(long N, long K){
long p=N;
while(K-->0){
p=N;
while(p>=10){
p=p/10;
}
if(p==1){return N;}
N=N*p;
}
return N;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and an integer K, Your task is to multiply the first leftmost digit of the number to the number itself. You have to repeat this process K times.
For eg:- if N=3 and K=5 then:
3 * 3 = 9
9 * 9 = 81
81 * 8 = 648
648 * 6 = 3888
3888 * 3 = 11664<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>KOperations()</b> that takes the integer N as parameter.
<b>Constraints:</b>
1 <= N <= 100
1 <= K <= 10^9Return the Number after K operations
<b>Note:</b> It is guaranteed that the output will always be less than 10^17.Sample Input:-
3 5
Sample Output:-
11664
Explanation:- See problem statement for explanation.
Sample Input:-
22 2
Sample Output:-
176, I have written this Solution Code:
def KOperations(N,K) :
# Final result of summation of divisors
while K>0 :
p=N
while(p>=10):
p=p/10
if(int(p)==1):
return N;
N=N*int(p)
K=K-1
return N;
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string of length N consisting of lowercase english alphabets(a-z), in which you are allowed to change at most k consonants into a vowel (a, e, i, o, u).
Find the longest substring that consists of only vowels after changing at most k consonants into vowels.First line of input consists of two integers N and k.
Second line consists of a string of length N.
Constraints:-
0 <= N <= 10^5
0 <= k <= N
String will contain only lowercase english lettersA single integer showing the length of the longest substring consisting of only vowels.Sample Input:-
11 2
aoibbboeaub
Sample Output:-
6
Explanation:-
One of the possibility is:-
aoibbboeaub => aoibbeoeaue (two b(s) converted to e)
now the longest substring is *eoeaue* which consists of only vowels., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String line1[] = in.readLine().trim().split(" ");
int n = Integer.parseInt(line1[0]);
int k = Integer.parseInt(line1[1]);
String line2 = in.readLine().trim();
int maxLen = 0, len = 0, l=0, r=0, consonantCount = 0;
while(r<n){
char indexValue = line2.charAt(r);
if(indexValue!='a' && indexValue!='e' && indexValue!='i' && indexValue!='o' && indexValue!='u')
consonantCount++;
r++;
while(consonantCount>k){
indexValue = line2.charAt(l);
if(indexValue!='a' && indexValue!='e' && indexValue!='i' && indexValue!='o' && indexValue!='u')
consonantCount--;
l++;
}
if(r-l>maxLen)
maxLen = r - l;
}
System.out.println(maxLen);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string of length N consisting of lowercase english alphabets(a-z), in which you are allowed to change at most k consonants into a vowel (a, e, i, o, u).
Find the longest substring that consists of only vowels after changing at most k consonants into vowels.First line of input consists of two integers N and k.
Second line consists of a string of length N.
Constraints:-
0 <= N <= 10^5
0 <= k <= N
String will contain only lowercase english lettersA single integer showing the length of the longest substring consisting of only vowels.Sample Input:-
11 2
aoibbboeaub
Sample Output:-
6
Explanation:-
One of the possibility is:-
aoibbboeaub => aoibbeoeaue (two b(s) converted to e)
now the longest substring is *eoeaue* which consists of only vowels., I have written this Solution Code:
n,k = map(int,input().split())
inp = input()
VOWELS = ["a","e","i","o","u"]
l = 0
h = 0
maxLength = 0
changes = 0
while h<n and l<n:
if changes<=k:
if inp[h] not in VOWELS:
changes += 1
h += 1
elif changes>k:
if inp[l] not in VOWELS:
changes -= 1
l+= 1
if h-l > maxLength and changes<=k:
maxLength = h-l
print(maxLength), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a string of length N consisting of lowercase english alphabets(a-z), in which you are allowed to change at most k consonants into a vowel (a, e, i, o, u).
Find the longest substring that consists of only vowels after changing at most k consonants into vowels.First line of input consists of two integers N and k.
Second line consists of a string of length N.
Constraints:-
0 <= N <= 10^5
0 <= k <= N
String will contain only lowercase english lettersA single integer showing the length of the longest substring consisting of only vowels.Sample Input:-
11 2
aoibbboeaub
Sample Output:-
6
Explanation:-
One of the possibility is:-
aoibbboeaub => aoibbeoeaue (two b(s) converted to e)
now the longest substring is *eoeaue* which consists of only vowels., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
bool check(char c){
if(c=='a' || c=='e' || c=='i' || c=='o' || c=='u'){return true;}
else{
return false;
}
}
int main() {
int n,k;
cin>>n>>k;
string s;
cin>>s;
int j=0;
int cnt=0;
int ans=0;
for(int i=0;i<n;i++){
if(s[i]=='a' || s[i]=='e' || s[i]=='i' || s[i]=='o' || s[i]=='u'){
ans=max(ans,i-j+1);
continue;}
else{
cnt++;
if(cnt>k){
while(j<=i && check(s[j])){
j++;
}
j++;
cnt--;
}
ans=max(ans,i-j+1);
// cout<<ans<<endl;
}
}
ans=max(ans,n-j);
cout<<ans;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. Force of an element is the square of its value.
<b>Note:</b> Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
Next line contains n integers denoting elements of the array.
Constraints:
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7
Functional problem, so implement the predefined functionOutput the maximum force.Sample Input:
4 4
1 2 3 4
Output:
30
Explanation:
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30
Sample Input:
2 1
1 10
Sample Output:
100, I have written this Solution Code: // arr is unsorted array
// n is the number of elements in the array
// k is required number of elements
function maxPower(arr, n,k) {
// write code here
// do not console.log the answer
// return the answer
arr.sort((a,b)=> Math.abs(b) - Math.abs(a))
let sum = 0
for(let i = 0; i < k;i++){
sum += arr[i]*arr[i]
}
return sum
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. Force of an element is the square of its value.
<b>Note:</b> Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
Next line contains n integers denoting elements of the array.
Constraints:
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7
Functional problem, so implement the predefined functionOutput the maximum force.Sample Input:
4 4
1 2 3 4
Output:
30
Explanation:
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30
Sample Input:
2 1
1 10
Sample Output:
100, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int k = sc.nextInt();
long arr[] = new long[n];
long x = 0;
for(int i=0 ; i<n ; i++){
x = sc.nextLong();
arr[i] = x*x;
x=0;
}
Arrays.sort(arr);
long sum = 0;
long count = n - k;
for(int i=n-1; i>=count ; i--){
sum = sum + arr[i];
}
System.out.println(sum);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an integer array A of size N. For each index i (1 <= i <= N), you need to find an index j, such that gcd(A[i], A[j]) = 1, and abs(i-j) is the minimum possible. If there are two values of j satisfying the condition, report the minimum one. If there is no possible value of j, report -1.
Note: gcd(x, y) represents the the greatest common divisor of integers x and y, while abs(i- j) represents the absolute value of (i-j). Eg: gcd(6, 15) = 3 ; abs(6-15) = 9.
See sample for better understanding.The first line of the input contains a single integer N.
The next line of the input contains N space separated integers, the elements of the array A.
Constraints
1 <= N <= 200000
1 <= A[i] <= 50Output N space separated integers, the value of j corresponding to each index. If there is no possible value of j, report -1 instead.Sample Input
5
1 2 4 3 9
Sample Output
1 1 4 3 3
Explanation
For index 1, gcd(A[1], A[1]) = 1, and abs(1-1) = 0.
For index 2, gcd(A[2], A[1]) = 1, and abs(2-1) = 1. gcd(A[2], A[4) is also equal to 1, but abs(2-4) = 2, which is a greater value.
Similarly for index 3, 4, and 5, gcd(A[3], A[4]) = 1, gcd(A[4], A[3]) = 1, and gcd(A[5], A[3]) = 1.
Sample Input
5
3 3 2 3 3
Sample Output
3 3 2 3 3
Sample Input
5
3 21 7 7 21
Sample Output
3 -1 1 1 -1
, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static int gcd(int a,int b){
if(a==0) return b;
return gcd(b%a,a);
}
public static void main (String[] args) throws IOException{
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
int n=Integer.parseInt(br.readLine());
String str[]=br.readLine().split(" ");
int a[]=new int[n+1];
int temp[]=new int[51];
int res[]=new int[n+1];
for(int i=1;i<=n;i++) a[i]=Integer.parseInt(str[i-1]);
for(int i=1;i<=n;i++){
int min=200000;
temp[a[i]]=i;
for(int j=1;j<=50;j++){
if(temp[j]==0) continue;
if(gcd(j,a[i])==1){
if(min>Math.abs(i-temp[j])){
res[i]=temp[j];
min=Math.abs(i-temp[j]);
}
}
}
if(min==200000) res[i]=-1;
}
temp=new int[51];
for(int i=n;i>=1;i--){
temp[a[i]]=i;
for(int j=1;j<=50;j++){
if(temp[j]==0) continue;
if(gcd(j,a[i])==1){
if(res[i]==-1){
res[i] = temp[j];
}
else{
if(Math.abs(i-temp[j]) < Math.abs(i-res[i]))res[i] = temp[j];
}
}
}
}
for(int i=1;i<=n;i++){
System.out.print(res[i]+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an integer array A of size N. For each index i (1 <= i <= N), you need to find an index j, such that gcd(A[i], A[j]) = 1, and abs(i-j) is the minimum possible. If there are two values of j satisfying the condition, report the minimum one. If there is no possible value of j, report -1.
Note: gcd(x, y) represents the the greatest common divisor of integers x and y, while abs(i- j) represents the absolute value of (i-j). Eg: gcd(6, 15) = 3 ; abs(6-15) = 9.
See sample for better understanding.The first line of the input contains a single integer N.
The next line of the input contains N space separated integers, the elements of the array A.
Constraints
1 <= N <= 200000
1 <= A[i] <= 50Output N space separated integers, the value of j corresponding to each index. If there is no possible value of j, report -1 instead.Sample Input
5
1 2 4 3 9
Sample Output
1 1 4 3 3
Explanation
For index 1, gcd(A[1], A[1]) = 1, and abs(1-1) = 0.
For index 2, gcd(A[2], A[1]) = 1, and abs(2-1) = 1. gcd(A[2], A[4) is also equal to 1, but abs(2-4) = 2, which is a greater value.
Similarly for index 3, 4, and 5, gcd(A[3], A[4]) = 1, gcd(A[4], A[3]) = 1, and gcd(A[5], A[3]) = 1.
Sample Input
5
3 3 2 3 3
Sample Output
3 3 2 3 3
Sample Input
5
3 21 7 7 21
Sample Output
3 -1 1 1 -1
, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(int i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define ld long double
#define double long double
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
typedef vector<int> vi;
#define pi 3.141592653589793238
const int MOD = 1e9+7;
const int N = 2e5+5;
// it's swapnil07 ;)
#ifdef SWAPNIL07
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
cout << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
int begtime = clock();
#define end_routine() cout << "\n\nTime elapsed: " << (clock() - begtime)*1000/CLOCKS_PER_SEC << " ms\n\n";
#else
#define endl '\n'
#define trace(...)
#define end_routine()
#endif
int pre[N][55], suf[N][55];
int arr[N];
void solve(){
int n; cin>>n;
For(i, 1, n+1){
cin>>arr[i];
}
For(i, 1, n+1){
For(j, 1, 51){
if(arr[i]==j)
pre[i][j]=i;
else
pre[i][j]=pre[i-1][j];
}
}
for(int i=n; i>=1; i--){
For(j, 1, 51){
if(arr[i]==j){
suf[i][j]=i;
}
else{
suf[i][j]=suf[i+1][j];
}
}
}
vector<int> ans(n+1, -1);
For(i, 1, n+1){
int dist = 3e5;
For(j, 1, 51){
if(__gcd(arr[i], j)==1){
if(pre[i][j] && abs(i-pre[i][j])<=dist){
ans[i]=pre[i][j];
dist=abs(i-pre[i][j]);
}
if(suf[i][j] && abs(i-suf[i][j])<dist){
ans[i]=suf[i][j];
dist=abs(i-suf[i][j]);
}
}
}
}
set<int> s;
For(i, 1, n+1){
s.insert(ans[i]);
cout<<ans[i]<<" ";
}
}
signed main()
{
fast
#ifdef SWAPNIL07
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
int t=1;
// cin>>t;
while(t--){
solve();
cout<<"\n";
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: To seek revenge on Midgard, Loki devises a plan to torture the humans by making them take part in one of his silly games. He makes N people sit in a circle. He says he will kill every kth person sitting in the circle, starting from 1st person.
Loki performs his revenge prank until and unless 1 survivor remains.
What is the initial position of the survivor, if the indexing is clockwise?The first line of input contains a single integer T. The next T line of input contains Two space separated integers each containing value of N and k.
<b>Constraints:</b>
1 <= T <= 100
1 <= k, N <= 20Print the initial position of the survivor.Sample Input:
2
3 2
5 3
Sample Output
3
4
Explanation:
Test case 1: There are 3 people so skipping 1 person i.e 1st person 2nd person will be killed in next step 3rd person will be skipped and 1st person will be killed. Thus the safe position is 3.
Test case 2: 2 people i.e 1and 2 are skipped and person 3 will be killed in next step 4 and 5 will be skipped and 1st person will be killed next step 2 and 4 will be skipped and 5th person will be killed next step first 2 will be skipped then 4 will be skipped and so coming back to 2 therefore person 2 will be killed. Thus the safe position is 4., I have written this Solution Code: t=int(input())
while t>0:
n,k=map(int,input().split())
s=set()
remove=0
for i in range(1,n+1):
s.add(i)
i=1
while True:
if len(s)==1:
break
if i in s:
remove+=1
if remove==k:
if i in s:
s.remove(i)
remove=0
i+=1
if i>n:
i=1
print(*s)
t-=1, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: To seek revenge on Midgard, Loki devises a plan to torture the humans by making them take part in one of his silly games. He makes N people sit in a circle. He says he will kill every kth person sitting in the circle, starting from 1st person.
Loki performs his revenge prank until and unless 1 survivor remains.
What is the initial position of the survivor, if the indexing is clockwise?The first line of input contains a single integer T. The next T line of input contains Two space separated integers each containing value of N and k.
<b>Constraints:</b>
1 <= T <= 100
1 <= k, N <= 20Print the initial position of the survivor.Sample Input:
2
3 2
5 3
Sample Output
3
4
Explanation:
Test case 1: There are 3 people so skipping 1 person i.e 1st person 2nd person will be killed in next step 3rd person will be skipped and 1st person will be killed. Thus the safe position is 3.
Test case 2: 2 people i.e 1and 2 are skipped and person 3 will be killed in next step 4 and 5 will be skipped and 1st person will be killed next step 2 and 4 will be skipped and 5th person will be killed next step first 2 will be skipped then 4 will be skipped and so coming back to 2 therefore person 2 will be killed. Thus the safe position is 4., I have written this Solution Code: import java.io.*;
import java.util.*;
import java.lang.*;
class Main{
public static void main (String[] args)throws IOException
{
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine().trim());
while(t-->0)
{
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
System.out.println(safe_Position(n,k));
}
}
public static int safe_Position(int n, int k)
{
if (n == 1) //base case
return 1;
else
/* The position returned by safe_Position(n - 1, k) is adjusted because the
recursive call safe_Position(n - 1, k) considers the original position
k%n + 1 as position 1 */
return (safe_Position(n - 1, k) + k-1) % n + 1; //recursion
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers ‘a’ and ‘m’. The task is to find modular multiplicative inverse of ‘a’ under modulo ‘m’.
Note: Print the smallest modular multiplicative inverse.First line of input contains a single integer T denoting number of test cases, next T lines contains two space separated integers depicting value of a and m.
Constraints :-
1 < = T < = 100
1 < = m < = 100
1 < = a < = mFor each test case, in a new line print the modular multiplicative inverse if exist else print -1.Sample Input:-
2
3 11
10 17
Sample Output:-
4
12, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int t=Integer.parseInt(br.readLine().trim());
while(t-->0){
String str[]=br.readLine().trim().split(" ");
int a=Integer.parseInt(str[0]);
int m=Integer.parseInt(str[1]);
int b;
int flag=0;
for(b=1; b<m; b++){
if(((a%m)*(b%m))%m == 1){
flag=1;
break;
}
}
if(flag==0){
System.out.println(-1);
}else{
System.out.println(b);
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers ‘a’ and ‘m’. The task is to find modular multiplicative inverse of ‘a’ under modulo ‘m’.
Note: Print the smallest modular multiplicative inverse.First line of input contains a single integer T denoting number of test cases, next T lines contains two space separated integers depicting value of a and m.
Constraints :-
1 < = T < = 100
1 < = m < = 100
1 < = a < = mFor each test case, in a new line print the modular multiplicative inverse if exist else print -1.Sample Input:-
2
3 11
10 17
Sample Output:-
4
12, I have written this Solution Code: def modInverse(a, m):
for x in range(1, m):
if (((a%m)*(x%m) % m )== 1):
return x
return -1
t = int(input())
for i in range(t):
a ,m = map(int , input().split())
print(modInverse(a, m)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers ‘a’ and ‘m’. The task is to find modular multiplicative inverse of ‘a’ under modulo ‘m’.
Note: Print the smallest modular multiplicative inverse.First line of input contains a single integer T denoting number of test cases, next T lines contains two space separated integers depicting value of a and m.
Constraints :-
1 < = T < = 100
1 < = m < = 100
1 < = a < = mFor each test case, in a new line print the modular multiplicative inverse if exist else print -1.Sample Input:-
2
3 11
10 17
Sample Output:-
4
12, I have written this Solution Code:
// author-Shivam gupta
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define max1 100001
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
int modInverseNaive(int a, int m) {
a %= m;
for (int x = 1; x < m; x++) {
if ((a*x) % m == 1) return x;
}
return -1;
}
signed main() {
int t;
cin >> t;
while (t-- > 0) {
int a,m;
cin >> a >> m;
cout << modInverseNaive(a, m) << '\n';
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws Exception {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String str[]=br.readLine().split(" ");
int a[]=new int[str.length];
int sum=0;
for(int i=0;i<str.length;i++)
{
a[i]=Integer.parseInt(str[i]);
sum=sum+a[i];
}
System.out.println(sum/4);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: a,b,c,d = map(int,input().split())
print((a+b+c+d)*100//400), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A contest setter wants to determine the time limits for a given problem. There are n model solutions, and solution k takes tk milliseconds to run on the test data. The contest setter wants the time limit to be an integer number of seconds, and wants the time limit to be at least s times larger than the slowest model solution. Compute the minimum time limit the contest setter can set.The first line of input contains two space-separated integers n and s (1 ≤ n ≤ 100 and 1 ≤ s ≤ 20).
The second line of input contains n space-separated integers t1, . . . , tn (1 ≤ tk ≤ 2000 for all
k = 1, . . . , n).Print, on one line, the minimum time limit (in seconds) as a single integer.sample input
2 5
200 250
sample output
2
Explanation:-
minimum time in millisecond will be 250*5 = 1250ms = 1.25sec
so minimum time in the second will be 2sec
sample input
3 4
47 1032 1107
sample output
5, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader get = new BufferedReader(new InputStreamReader(System.in));
String A[] = get.readLine().trim().split(" ");
int n = Integer.parseInt(A[0]);
int s = Integer.parseInt(A[1]);
String B[] = get.readLine().trim().split(" ");
int max=Integer.parseInt(B[0]);;
for (int i=1; i<n; i++){
int num = Integer.parseInt(B[i]);
if(num>max){
max = num;
}
}
int temp = s*max;
float temp1 = (float)temp/1000;
int result = (int)Math.ceil(temp1);
System.out.println(result);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A contest setter wants to determine the time limits for a given problem. There are n model solutions, and solution k takes tk milliseconds to run on the test data. The contest setter wants the time limit to be an integer number of seconds, and wants the time limit to be at least s times larger than the slowest model solution. Compute the minimum time limit the contest setter can set.The first line of input contains two space-separated integers n and s (1 ≤ n ≤ 100 and 1 ≤ s ≤ 20).
The second line of input contains n space-separated integers t1, . . . , tn (1 ≤ tk ≤ 2000 for all
k = 1, . . . , n).Print, on one line, the minimum time limit (in seconds) as a single integer.sample input
2 5
200 250
sample output
2
Explanation:-
minimum time in millisecond will be 250*5 = 1250ms = 1.25sec
so minimum time in the second will be 2sec
sample input
3 4
47 1032 1107
sample output
5, I have written this Solution Code: import math
b=input().split()
b=int(b[1])/1000
a=input().split()
for i in range(len(a)):
a[i]=int(a[i])
a.sort()
print(math.ceil(b*a.pop())), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A contest setter wants to determine the time limits for a given problem. There are n model solutions, and solution k takes tk milliseconds to run on the test data. The contest setter wants the time limit to be an integer number of seconds, and wants the time limit to be at least s times larger than the slowest model solution. Compute the minimum time limit the contest setter can set.The first line of input contains two space-separated integers n and s (1 ≤ n ≤ 100 and 1 ≤ s ≤ 20).
The second line of input contains n space-separated integers t1, . . . , tn (1 ≤ tk ≤ 2000 for all
k = 1, . . . , n).Print, on one line, the minimum time limit (in seconds) as a single integer.sample input
2 5
200 250
sample output
2
Explanation:-
minimum time in millisecond will be 250*5 = 1250ms = 1.25sec
so minimum time in the second will be 2sec
sample input
3 4
47 1032 1107
sample output
5, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main()
{
int n,s;
cin>> n>> s;
int t[n];
int res = 0, ans;
for(int i=1;i<=n;i++){
cin>> t[i];
res = max(res ,t[i]);
}
ans = res*s/1000;
if((res * s)%1000)
{
ans++;
}
cout << ans;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: After the decimation, the world went into chaos. People had to rebuild the planet so Shield came up with a donation strategy. They feel all the rich guys need to donate more than the poor guys. So, they make a rule. They would make a donation list in which the donation of each person would be shown. But the rule is that a person can’t pay less than what has already been paid before them. Find the extra amount each person will pay, and also, tell shield the total amount of donation.The first line contains n, the total number of people donating. The next line contains n space-separated integers denoting the amount of money paid by the people. The amounts are mentioned in the order in which the people paid.
<b>Constraints:-</b>
1 <= n <= 100000
0 <= money <= 100000The first line contains the extra money that each student has to pay after their teacher applied the rule. The second line contains the total amount collected by the teacher at the end.Sample Input 1:-
10
1 2 3 2 4 3 6 6 7 6
Sample Output 1:-
0 0 0 1 0 1 0 0 0 1
43
Sample Input 2:-
7
10 20 30 40 30 20 10
Sample Output 2:-
0 0 0 0 10 20 30
220, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
InputStreamReader read = new InputStreamReader(System.in);
BufferedReader in = new BufferedReader(read);
int n = Integer.parseInt(in.readLine());
int []donationList = new int[n];
int[] defaulterList = new int[n];
long totalDonations = 0L;
StringTokenizer st = new StringTokenizer(in.readLine());
for(int i=0 ; i<n ; i++){
donationList[i] = Integer.parseInt(st.nextToken());
}
int max = Integer.MIN_VALUE;
for(int i=0; i<n; i++){
totalDonations += donationList[i];
max = Math.max(max,donationList[i]);
if(i>0){
if(donationList[i] >= max)
defaulterList[i] = 0;
else
defaulterList[i] = max - donationList[i];
}
totalDonations += defaulterList[i];
}
for(int i=0; i<n ;i++){
System.out.print(defaulterList[i]+" ");
}
System.out.println();
System.out.print(totalDonations);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: After the decimation, the world went into chaos. People had to rebuild the planet so Shield came up with a donation strategy. They feel all the rich guys need to donate more than the poor guys. So, they make a rule. They would make a donation list in which the donation of each person would be shown. But the rule is that a person can’t pay less than what has already been paid before them. Find the extra amount each person will pay, and also, tell shield the total amount of donation.The first line contains n, the total number of people donating. The next line contains n space-separated integers denoting the amount of money paid by the people. The amounts are mentioned in the order in which the people paid.
<b>Constraints:-</b>
1 <= n <= 100000
0 <= money <= 100000The first line contains the extra money that each student has to pay after their teacher applied the rule. The second line contains the total amount collected by the teacher at the end.Sample Input 1:-
10
1 2 3 2 4 3 6 6 7 6
Sample Output 1:-
0 0 0 1 0 1 0 0 0 1
43
Sample Input 2:-
7
10 20 30 40 30 20 10
Sample Output 2:-
0 0 0 0 10 20 30
220, I have written this Solution Code: n = int(input())
a = input().split()
b = int(a[0])
sum = 0
for i in a:
if int(i)<b:
print(b-int(i),end=' ')
else:
b = int(i)
print(0,end=' ')
sum = sum+b
print()
print(sum), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: After the decimation, the world went into chaos. People had to rebuild the planet so Shield came up with a donation strategy. They feel all the rich guys need to donate more than the poor guys. So, they make a rule. They would make a donation list in which the donation of each person would be shown. But the rule is that a person can’t pay less than what has already been paid before them. Find the extra amount each person will pay, and also, tell shield the total amount of donation.The first line contains n, the total number of people donating. The next line contains n space-separated integers denoting the amount of money paid by the people. The amounts are mentioned in the order in which the people paid.
<b>Constraints:-</b>
1 <= n <= 100000
0 <= money <= 100000The first line contains the extra money that each student has to pay after their teacher applied the rule. The second line contains the total amount collected by the teacher at the end.Sample Input 1:-
10
1 2 3 2 4 3 6 6 7 6
Sample Output 1:-
0 0 0 1 0 1 0 0 0 1
43
Sample Input 2:-
7
10 20 30 40 30 20 10
Sample Output 2:-
0 0 0 0 10 20 30
220, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
void solve(){
int n;
cin>>n;
int a[n];
int ma=0;
int cnt=0;
//map<int,int> m;
for(int i=0;i<n;i++){
cin>>a[i];
ma=max(ma,a[i]);
cout<<ma-a[i]<<" ";
cnt+=ma-a[i];
cnt+=a[i];
//m[a[i]]++;
}
cout<<endl;
cout<<cnt<<endl;
}
signed main(){
int t;
t=1;
while(t--){
solve();}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws Exception {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String str[]=br.readLine().split(" ");
int a[]=new int[str.length];
int sum=0;
for(int i=0;i<str.length;i++)
{
a[i]=Integer.parseInt(str[i]);
sum=sum+a[i];
}
System.out.println(sum/4);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: a,b,c,d = map(int,input().split())
print((a+b+c+d)*100//400), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: It's Solo's 1st birthday and everyone is gifting her chocolates. There are N guests invited, and the i<sup>th</sup> guest gives Solo C<sub>i</sub> chocolates.
Find the total number of chocolates that Solo receives.The first line of the input contains an integer N, the number of guests.
The second line of the input contains N integers C<sub>1</sub>, C<sub>2</sub>, ....C<sub>N</sub>
Constraints
1 <= N <= 100
1 <= C<sub>i</sub> <= 100Output a single integer, the total number of chocolates that Solo receives.Sample Input
5
1 2 4 3 2
Sample Output
12
Explanation: Solo receives a total of 1+2+4+3+2 = 12 chocolates.
Sample Input
1
2
Sample Output
2, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(int i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define ld long double
#define int long long
#define double long double
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
typedef vector<int> vi;
#define pi 3.141592653589793238
const int MOD = 1e9+7;
const int INF = 1LL<<60;
const int N = 2e5+5;
// it's swapnil07 ;)
#ifdef SWAPNIL07
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
cout << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
int begtime = clock();
#define end_routine() cout << "\n\nTime elapsed: " << (clock() - begtime)*1000/CLOCKS_PER_SEC << " ms\n\n";
#else
#define endl '\n'
#define trace(...)
#define end_routine()
#endif
void solve(){
int n; cin>>n;
int ans = 0;
For(i, 0, n){
int a; cin>>a;
ans += a;
}
cout<<ans;
}
signed main()
{
fast
#ifdef SWAPNIL07
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
int t=1;
// cin>>t;
while(t--){
solve();
cout<<"\n";
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: It's Solo's 1st birthday and everyone is gifting her chocolates. There are N guests invited, and the i<sup>th</sup> guest gives Solo C<sub>i</sub> chocolates.
Find the total number of chocolates that Solo receives.The first line of the input contains an integer N, the number of guests.
The second line of the input contains N integers C<sub>1</sub>, C<sub>2</sub>, ....C<sub>N</sub>
Constraints
1 <= N <= 100
1 <= C<sub>i</sub> <= 100Output a single integer, the total number of chocolates that Solo receives.Sample Input
5
1 2 4 3 2
Sample Output
12
Explanation: Solo receives a total of 1+2+4+3+2 = 12 chocolates.
Sample Input
1
2
Sample Output
2, I have written this Solution Code: n = int(input())
chocolates = list(map(int, input().strip().split(" ")))
count = 0
for val in chocolates:
count += val
print(count), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: It's Solo's 1st birthday and everyone is gifting her chocolates. There are N guests invited, and the i<sup>th</sup> guest gives Solo C<sub>i</sub> chocolates.
Find the total number of chocolates that Solo receives.The first line of the input contains an integer N, the number of guests.
The second line of the input contains N integers C<sub>1</sub>, C<sub>2</sub>, ....C<sub>N</sub>
Constraints
1 <= N <= 100
1 <= C<sub>i</sub> <= 100Output a single integer, the total number of chocolates that Solo receives.Sample Input
5
1 2 4 3 2
Sample Output
12
Explanation: Solo receives a total of 1+2+4+3+2 = 12 chocolates.
Sample Input
1
2
Sample Output
2, I have written this Solution Code:
import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int A[] = new int[n];
for(int i=0;i<n;i++){
A[i]=sc.nextInt();
}
int Total=0;
for(int i=0;i<n;i++){
Total+=A[i];
}
System.out.print(Total);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: New Year festival of Ying Yang is approaching. There are <b>N</b> spaces available for stalls to be put up. The i<sup>th</sup> stall's price is p<sub>i</sub>. You have X amount of money with you right now and you want to buy <b>atleast 2 stalls</b> from this money. Find whether it is possible. Print "YES" if it is possible, else print "NO", without the quotes.First line of the input contains two integers N, the number of stall spaces and X, the amount of money you have.
The second line of the input contains N space seperated integers.
Constraints:
2 <= N <= 10<sup>5</sup>
1 <= X <= 10<sup>9</sup>
1 <= p<sub>i</sub> <= 10<sup>9</sup>Print "YES" if it is possible for you to buy atleast two spaces in the festival, else print "NO", without the quotes.Sample Input:
5 10
3 6 5 8 11
Sample Input:
YES
Explaination:
You can buy stall no. s 1 and 2 (1- based indexing) to bring the total amount to 3 + 6 = 9, which is less than 10., I have written this Solution Code: n,p=input().split()
arr=list(map(int,input().split()))
arr.sort()
i=0
for j in range(i+1,int(n)):
if arr[i]+arr[j] <= int(p) :
print("YES")
break
i+=1
else:
print("NO"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: New Year festival of Ying Yang is approaching. There are <b>N</b> spaces available for stalls to be put up. The i<sup>th</sup> stall's price is p<sub>i</sub>. You have X amount of money with you right now and you want to buy <b>atleast 2 stalls</b> from this money. Find whether it is possible. Print "YES" if it is possible, else print "NO", without the quotes.First line of the input contains two integers N, the number of stall spaces and X, the amount of money you have.
The second line of the input contains N space seperated integers.
Constraints:
2 <= N <= 10<sup>5</sup>
1 <= X <= 10<sup>9</sup>
1 <= p<sub>i</sub> <= 10<sup>9</sup>Print "YES" if it is possible for you to buy atleast two spaces in the festival, else print "NO", without the quotes.Sample Input:
5 10
3 6 5 8 11
Sample Input:
YES
Explaination:
You can buy stall no. s 1 and 2 (1- based indexing) to bring the total amount to 3 + 6 = 9, which is less than 10., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL);
#define int long long
#define pb push_back
#define ff first
#define ss second
#define endl '\n'
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
using T = pair<int, int>;
typedef long long ll;
const int mod = 1e9 + 7;
const int INF = 1e9;
void solve() {
int n, x;
cin >> n >> x;
vector<int> p(n);
for(auto &i : p) cin >> i;
sort(all(p));
cout << ((p[0] + p[1]) <= x ? "YES" : "NO");
}
signed main(){
fast
int t = 1;
// cin >> t;
for(int i = 1; i <= t; i++){
solve();
if(i != t) cout << endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args){
FastReader read = new FastReader();
int a = read.nextInt();
int b = read.nextInt();
System.out.println(a+b);
System.out.println(a-b);
System.out.println(a*b);
System.out.println(a/b);
}
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader(){
InputStreamReader inr = new InputStreamReader(System.in);
br = new BufferedReader(inr);
}
String next(){
while(st==null || !st.hasMoreElements())
try{
st = new StringTokenizer(br.readLine());
}
catch(IOException e){
e.printStackTrace();
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
double nextDouble(){
return Double.parseDouble(next());
}
long nextLong(){
return Long.parseLong(next());
}
String nextLine(){
String str = "";
try{
str = br.readLine();
}
catch(IOException e){
e.printStackTrace();
}
return str;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: a,b=map(int,input().split())
print(a+b)
print(a-b)
print(a*b)
print(a//b), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an Array A of size N. For each index i you have to tell the count of numbers which have index greater than i and are multiples of A[i].<b>User task:</b> Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>countOfNumbers(A, n)</b> which contains A(array) and n(size of array) as a parameter
<b>Constraints</b>
1<=N<=1000
1<=A[i]<=1000000
For <b> Custom input:-</b>
The first line of the input should contains an integer N ,length of Array .
Next line contains N integers which are elements of ArrayYou need to return the list which contains the answer for each person ith integer. The driver code will take care of displaying them Sample Input
3
1 2 3
Sample Output
2 0 0
Explanation : 2,3 are multiple of 1
Sample Input
5
6 4 3 4 1
Sample Output
0 1 0 0 0
, I have written this Solution Code: function countOfNumbers(A, n)
{
var list = new Array(n)
for(var i=0; i<n; i++)
{ var cnt=0;
for(var j=i+1;j<n;j++)
{
if(A[j]%A[i]==0)
cnt++;
}
list[i] = Number(cnt);
}
return list
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an Array A of size N. For each index i you have to tell the count of numbers which have index greater than i and are multiples of A[i].<b>User task:</b> Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>countOfNumbers(A, n)</b> which contains A(array) and n(size of array) as a parameter
<b>Constraints</b>
1<=N<=1000
1<=A[i]<=1000000
For <b> Custom input:-</b>
The first line of the input should contains an integer N ,length of Array .
Next line contains N integers which are elements of ArrayYou need to return the list which contains the answer for each person ith integer. The driver code will take care of displaying them Sample Input
3
1 2 3
Sample Output
2 0 0
Explanation : 2,3 are multiple of 1
Sample Input
5
6 4 3 4 1
Sample Output
0 1 0 0 0
, I have written this Solution Code:
int *countOfNumbers(int A[],int n){
static int cnt[10000];
for(int i=0;i<n;i++){
cnt[i]=0;
}
for(int i=0;i<n-1;i++){
int ans=0;
for(int j=i+1;j<n;j++){
if(A[j]%A[i]==0){ans++;}
}
cnt[i]=ans;
}
return cnt;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an Array A of size N. For each index i you have to tell the count of numbers which have index greater than i and are multiples of A[i].<b>User task:</b> Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>countOfNumbers(A, n)</b> which contains A(array) and n(size of array) as a parameter
<b>Constraints</b>
1<=N<=1000
1<=A[i]<=1000000
For <b> Custom input:-</b>
The first line of the input should contains an integer N ,length of Array .
Next line contains N integers which are elements of ArrayYou need to return the list which contains the answer for each person ith integer. The driver code will take care of displaying them Sample Input
3
1 2 3
Sample Output
2 0 0
Explanation : 2,3 are multiple of 1
Sample Input
5
6 4 3 4 1
Sample Output
0 1 0 0 0
, I have written this Solution Code: def countOfNumbers(A,n):
cnt = []
for i in range (0 ,n ):
ans=0;
for j in range (i+1,n):
if A[j]%A[i]==0:
ans=ans+1
cnt.append(ans)
return cnt
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an Array A of size N. For each index i you have to tell the count of numbers which have index greater than i and are multiples of A[i].<b>User task:</b> Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>countOfNumbers(A, n)</b> which contains A(array) and n(size of array) as a parameter
<b>Constraints</b>
1<=N<=1000
1<=A[i]<=1000000
For <b> Custom input:-</b>
The first line of the input should contains an integer N ,length of Array .
Next line contains N integers which are elements of ArrayYou need to return the list which contains the answer for each person ith integer. The driver code will take care of displaying them Sample Input
3
1 2 3
Sample Output
2 0 0
Explanation : 2,3 are multiple of 1
Sample Input
5
6 4 3 4 1
Sample Output
0 1 0 0 0
, I have written this Solution Code: #include <stdio.h>
int *countOfNumbers(int A[],int n){
static int cnt[10000];
for(int i=0;i<n;i++){
cnt[i]=0;
}
for(int i=0;i<n-1;i++){
int ans=0;
for(int j=i+1;j<n;j++){
if(A[j]%A[i]==0){ans++;}
}
cnt[i]=ans;
}
return cnt;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an Array A of size N. For each index i you have to tell the count of numbers which have index greater than i and are multiples of A[i].<b>User task:</b> Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>countOfNumbers(A, n)</b> which contains A(array) and n(size of array) as a parameter
<b>Constraints</b>
1<=N<=1000
1<=A[i]<=1000000
For <b> Custom input:-</b>
The first line of the input should contains an integer N ,length of Array .
Next line contains N integers which are elements of ArrayYou need to return the list which contains the answer for each person ith integer. The driver code will take care of displaying them Sample Input
3
1 2 3
Sample Output
2 0 0
Explanation : 2,3 are multiple of 1
Sample Input
5
6 4 3 4 1
Sample Output
0 1 0 0 0
, I have written this Solution Code: static int [] countOfNumbers(int A[],int n){
int cnt[] = new int[n];
for(int i=0;i<n;i++){
cnt[i]=0;
}
for(int i=0;i<n-1;i++){
int ans=0;
for(int j=i+1;j<n;j++){
if(A[j]%A[i]==0){ans++;}
}
cnt[i]=ans;
}
return cnt;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is playing a game in which she is fighting with N monsters who are standing in a line. Each monster has some HP with him. At every second, Sara hits the monster standing at the front of the line. When the monster gets hit his HP decreases by 1 and he goes to the end of the line(which happens instantaneously).
For example:
if the monster's health are (1, 3, 2)
After 1st hit:- 3, 2 (monster at index 0 dies)
After 2nd hit:- 2, 2
After 3rd hit:- 2, 1
After 4th hit:- 1, 1
After 5th hit:- 1(monster who was originally at index 2 dies)
After 6th hit:- (monster who was originally at index 1 dies)
Now Sara who keeps track of the time wants to know the time when the Kth(0 indexing) monster dies(A monster dies when his HP hits 0).The first line of input contains two space separated integers depicting N and K.
The next line contains N space separated integers depicting the HP of every monster.
<b>Constraints:-</b>
1 <= N <= 100
0 <= K < N
1 <= HP <= 100Print the time when the Kth monster dies.Sample Input:-
3 2
1 3 2
Sample Output:-
5
Sample Input:-
4 0
5 1 1 1
Sample Output:-
8, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner s = new Scanner(System.in);
int N=s.nextInt();
int K=s.nextInt();
int[] arr=new int[N];
for (int i=0;i<=N-1;i++){
arr[i]=s.nextInt();
}
int count=0;
int i=0;
while(arr[K]>0){
i=i%N;
if(arr[i]>0){
arr[i]--;
count++;
}
i++;
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is playing a game in which she is fighting with N monsters who are standing in a line. Each monster has some HP with him. At every second, Sara hits the monster standing at the front of the line. When the monster gets hit his HP decreases by 1 and he goes to the end of the line(which happens instantaneously).
For example:
if the monster's health are (1, 3, 2)
After 1st hit:- 3, 2 (monster at index 0 dies)
After 2nd hit:- 2, 2
After 3rd hit:- 2, 1
After 4th hit:- 1, 1
After 5th hit:- 1(monster who was originally at index 2 dies)
After 6th hit:- (monster who was originally at index 1 dies)
Now Sara who keeps track of the time wants to know the time when the Kth(0 indexing) monster dies(A monster dies when his HP hits 0).The first line of input contains two space separated integers depicting N and K.
The next line contains N space separated integers depicting the HP of every monster.
<b>Constraints:-</b>
1 <= N <= 100
0 <= K < N
1 <= HP <= 100Print the time when the Kth monster dies.Sample Input:-
3 2
1 3 2
Sample Output:-
5
Sample Input:-
4 0
5 1 1 1
Sample Output:-
8, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
int solve(vector<int> a, int k){
int answer=a[k]*a.size();
for(int i=0;i<a.size();i++){
if(i<=k){
answer+=min((int)0,a[i]-a[k]);
}
else{
answer+=min((int)-1,a[i]-a[k]);
}
}
return answer;
}
signed main(){
int n,k;
cin>> n>>k;
vector<int> a(n);
for(int i=0;i<n;i++){
cin>>a[i];
}
cout<<solve(a,k);
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S consisting of opening and closing parenthesis '(' and ')'. Find length of the longest valid parenthesis substring.Each test case have one line string S of character '(' and ')' of length N.
Constraints:
1 <= N <= 10^5Print the length of the longest valid parenthesis substring.Input
((()
Output
2
Input
)()())
Output
4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s = br.readLine();
int n = s.length();
int left = 0, right = 0;
int maxlength = 0;
for(int i = 0; i < n; i++)
{
if (s.charAt(i) == '(')
left++;
else
right++;
if (left == right)
maxlength = Math.max(maxlength, 2 * right);
else if (right > left)
left = right = 0;
}
left = right = 0;
for(int i = n - 1; i >= 0; i--)
{
if (s.charAt(i) == '(')
left++;
else
right++;
if (left == right)
maxlength = Math.max(maxlength, 2 * left);
else if (left > right)
left = right = 0;
}
System.out.println(maxlength);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S consisting of opening and closing parenthesis '(' and ')'. Find length of the longest valid parenthesis substring.Each test case have one line string S of character '(' and ')' of length N.
Constraints:
1 <= N <= 10^5Print the length of the longest valid parenthesis substring.Input
((()
Output
2
Input
)()())
Output
4, I have written this Solution Code: def longestValidParentheses( S):
stack, ans = [-1], 0
for i in range(len(S)):
if S[i] == '(': stack.append(i)
elif len(stack) == 1: stack[0] = i
else:
stack.pop()
ans = max(ans, i - stack[-1])
return ans
n=input()
print(longestValidParentheses(n)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
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