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For this Question: You are given a grid having N*M elements. Find the index of the row (1-base indexing) which has the maximum sum of elements.
Note: if more than two rows have the same sum of elements, then return the smallest index.The first line of the input contains two integers N and M.
The next N lines each contain M space separated integers.
<b>Constraints:</b>
1 <= N, M <= 10<sup>3</sup>
1 <= A<sub>i, j</sub> <= 10<sup>9Print the index of the row (1-base indexing) which has the maximum sum of elements.Sample Input:
4 3
3 4 2
5 1 7
2 8 1
2 3 3
Sample Output:
2
<b>Explaination:</b>
Row number 2 has sum = 5 + 1 + 7 = 13 which is the maximum among all rows., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader()
{
br = new BufferedReader(
new InputStreamReader(System.in));
}
String next()
{
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
}
catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() { return Integer.parseInt(next()); }
long nextLong() { return Long.parseLong(next()); }
double nextDouble()
{
return Double.parseDouble(next());
}
String nextLine()
{
String str = "";
try {
if(st.hasMoreTokens()){
str = st.nextToken("\n");
}
else{
str = br.readLine();
}
}
catch (IOException e) {
e.printStackTrace();
}
return str;
}
}
public static void main (String[] args) {
FastReader sc=new FastReader();
int n=sc.nextInt();
int m=sc.nextInt();
int arr[][]=new int[n][m];
for(int i=0; i<n; i++)
{
for(int j=0; j<m; j++)
{
arr[i][j]= sc.nextInt();
}
}
long maxsum=0;
int index=0;
for(int i=0; i<n; i++)
{
long sum=0;
for(int j=0; j<m; j++)
{
sum += arr[i][j];
}
if(sum > maxsum)
{
maxsum=sum;
index=i+1;
}
}
System.out.print(index);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a grid having N*M elements. Find the index of the row (1-base indexing) which has the maximum sum of elements.
Note: if more than two rows have the same sum of elements, then return the smallest index.The first line of the input contains two integers N and M.
The next N lines each contain M space separated integers.
<b>Constraints:</b>
1 <= N, M <= 10<sup>3</sup>
1 <= A<sub>i, j</sub> <= 10<sup>9Print the index of the row (1-base indexing) which has the maximum sum of elements.Sample Input:
4 3
3 4 2
5 1 7
2 8 1
2 3 3
Sample Output:
2
<b>Explaination:</b>
Row number 2 has sum = 5 + 1 + 7 = 13 which is the maximum among all rows., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
signed main(){
int n, m;
cin >> n >> m;
vector<vector<int>> a(n, vector<int> (m));
vector<int> sum(n);
for(int i = 0; i < n; i++){
for(int j = 0; j < m; j++){
cin >> a[i][j];
sum[i] += a[i][j];
}
}
int mx = 0, ans = 0;
for(int i = 0; i < n; i++){
if(mx < sum[i]){
mx = sum[i];
ans = i;
}
}
cout << ans + 1;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a <b> N X M matrix</b> and a <b>target</b>, return the number of non- empty submatrices that sum to target.
A submatrix x1, y1, x2, y2 is the set of all cells matrix[x][y] with x1 <= x <= x2 and y1 <= y <= y2.
Two submatrices (x1, y1, x2, y2) and (x1', y1', x2', y2') are different if they have some coordinate that is different: for example, if x1 != x1'.First line contains two integers N and M.
Next N lines will contain M integers each denoting the matrix.
Next line contains a single integer target
Constraints:
1 <= N, M <= 100
-1000 <= matrix[i][j] <= 1000
-10^8 <= target <= 10^8A single integer denoting the answer.Input:
3 3
0 1 0
1 1 1
0 1 0
0
Output:
4, I have written this Solution Code: import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) {
InputStream inputStream = System.in;
OutputStream outputStream = System.out;
InputReader in = new InputReader(inputStream);
OutputWriter out = new OutputWriter(outputStream);
int n=Integer.parseInt(in.next());
int m=Integer.parseInt(in.next());
long mat[][] = new long[n][m];
for(int i=0;i<n;i++){
for(int j=0;j<m;j++){
mat[i][j]=Long.parseLong(in.next());
}
}
long target=Long.parseLong(in.next());
long ans=0;
for(int x1=0;x1<n;x1++){
long sum[]=new long[m];
Arrays.fill(sum, 0);
for(int x2=x1;x2<n;x2++){
for(int y=0;y<m;y++){
sum[y] += mat[x2][y];
}
ans += subArraySum(sum,target);
}
}
out.print(ans);
out.close();
}
private static long subArraySum(long sum[],long target){
long ans=0;
HashMap<Long,Long> mp = new HashMap<Long,Long>();
long cur_sum=0;
mp.put((long)0, (long)1);
for(int i=0;i<sum.length;i++){
cur_sum += sum[i];
long req_sum=cur_sum-target;
if(mp.containsKey(req_sum)){
ans += mp.get(req_sum);
}
if(!mp.containsKey(cur_sum)){
mp.put(cur_sum , (long)0);
}
mp.put(cur_sum, mp.get(cur_sum)+1);
}
return ans;
}
static class InputReader {
BufferedReader reader;
StringTokenizer tokenizer;
public InputReader(InputStream stream) {
reader = new BufferedReader(new InputStreamReader(stream), 32768);
tokenizer = null;
}
public String next() {
while (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
static class OutputWriter {
private final PrintWriter writer;
public OutputWriter(OutputStream outputStream) {
writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
}
public OutputWriter(Writer writer) {
this.writer = new PrintWriter(writer);
}
public void print(Object... objects) {
for (int i = 0; i < objects.length; i++) {
if (i != 0) {
writer.print(' ');
}
writer.print(objects[i]);
}
}
public void println(Object... objects) {
print(objects);
writer.println();
}
public void close() {
writer.close();
}
public void println(int i) {
writer.println(i);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Swapnil has finally decided to propose his girlfriend. He is going to write a poem for her. Although he has never written a poem, he thought he should at least give it a try. He knows that a poem contains a lot of <b>Rhyming words</b>. So, he first bought a dictionary.
Swapnil's dictionary contains N words. He considers two words to be rhyming when the length of their longest common suffix is greater than or equal to K. He would like to find the number of pairs of rhyming words.
Since he went to take rest, can you help him?
<b>Note:</b> Word here refers to a string of lowercase English alphabet and Suffix refers to substring at the end of a string.First line of input contains two integers N, number of words in Swapnil's dictionary and K, his criteria for a word to be rhyming or not.
Next N lines contain words in Swapnil's dictionary.
1 <= N, K <= 100
1 <= Length of Words <= 100Print a single integer denoting the number of pairs of words which are rhyming in nature.Sample Input:
5 3
end
lend
friend
stand
wonderland
Sample Output:
4
Explanation:(LCS - longest common suffix)
{end, lend}: LCS = "end", length = 3, Rhyming words
{end, friend}: LCS = "end", length = 3, Rhyming words
{end, stand}: LCS = "nd", length = 2, Not Rhyming words
{end, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{lend, friend}: LCS = "end", length = 3, Rhyming words
{lend, stand}: LCS = "nd", length = 2, Not Rhyming words
{lend, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{friend, stand}: LCS = "nd", length = 2, Not Rhyming words
{friend, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{stand, wonderland}: LCS = "and", length = 3, Rhyming words, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String[] input1=br.readLine().split(" ");
int n=Integer.parseInt(input1[0]);
int k=Integer.parseInt(input1[1]);
String str[]=new String[n];
for(int i=0;i<n;i++){
str[i]=br.readLine();
}
int count=0;
for(int i=0;i<n-1;i++){
if(str[i].length()>=k){
String a=str[i].substring(str[i].length()-k,str[i].length());
for(int j=i+1;j<n;j++){
if(str[j].length()>=k){
String b=str[j].substring(str[j].length()-k,str[j].length());
if(a.equals(b)){
count++;
}
}
}
}
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Swapnil has finally decided to propose his girlfriend. He is going to write a poem for her. Although he has never written a poem, he thought he should at least give it a try. He knows that a poem contains a lot of <b>Rhyming words</b>. So, he first bought a dictionary.
Swapnil's dictionary contains N words. He considers two words to be rhyming when the length of their longest common suffix is greater than or equal to K. He would like to find the number of pairs of rhyming words.
Since he went to take rest, can you help him?
<b>Note:</b> Word here refers to a string of lowercase English alphabet and Suffix refers to substring at the end of a string.First line of input contains two integers N, number of words in Swapnil's dictionary and K, his criteria for a word to be rhyming or not.
Next N lines contain words in Swapnil's dictionary.
1 <= N, K <= 100
1 <= Length of Words <= 100Print a single integer denoting the number of pairs of words which are rhyming in nature.Sample Input:
5 3
end
lend
friend
stand
wonderland
Sample Output:
4
Explanation:(LCS - longest common suffix)
{end, lend}: LCS = "end", length = 3, Rhyming words
{end, friend}: LCS = "end", length = 3, Rhyming words
{end, stand}: LCS = "nd", length = 2, Not Rhyming words
{end, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{lend, friend}: LCS = "end", length = 3, Rhyming words
{lend, stand}: LCS = "nd", length = 2, Not Rhyming words
{lend, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{friend, stand}: LCS = "nd", length = 2, Not Rhyming words
{friend, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{stand, wonderland}: LCS = "and", length = 3, Rhyming words, I have written this Solution Code: n,k=input().split()
n=int(n)
k=int(k)
y=[]
count=0
for i in range(0,n):
y.append(input())
for i in range(0,n):
for j in range(i+1,n):
if(len(y[i])>=k and len(y[j])>=k):
if(y[i][len(y[i])-k:len(y[i])]==y[j][len(y[j])-k:len(y[j])]):
count+=1;
print (count), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Swapnil has finally decided to propose his girlfriend. He is going to write a poem for her. Although he has never written a poem, he thought he should at least give it a try. He knows that a poem contains a lot of <b>Rhyming words</b>. So, he first bought a dictionary.
Swapnil's dictionary contains N words. He considers two words to be rhyming when the length of their longest common suffix is greater than or equal to K. He would like to find the number of pairs of rhyming words.
Since he went to take rest, can you help him?
<b>Note:</b> Word here refers to a string of lowercase English alphabet and Suffix refers to substring at the end of a string.First line of input contains two integers N, number of words in Swapnil's dictionary and K, his criteria for a word to be rhyming or not.
Next N lines contain words in Swapnil's dictionary.
1 <= N, K <= 100
1 <= Length of Words <= 100Print a single integer denoting the number of pairs of words which are rhyming in nature.Sample Input:
5 3
end
lend
friend
stand
wonderland
Sample Output:
4
Explanation:(LCS - longest common suffix)
{end, lend}: LCS = "end", length = 3, Rhyming words
{end, friend}: LCS = "end", length = 3, Rhyming words
{end, stand}: LCS = "nd", length = 2, Not Rhyming words
{end, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{lend, friend}: LCS = "end", length = 3, Rhyming words
{lend, stand}: LCS = "nd", length = 2, Not Rhyming words
{lend, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{friend, stand}: LCS = "nd", length = 2, Not Rhyming words
{friend, wonderland}: LCS = "nd", length = 2, Not Rhyming words
{stand, wonderland}: LCS = "and", length = 3, Rhyming words, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
string s[N];
signed main() {
IOS;
int n, k;
cin >> n >> k;
for(int i = 1; i <= n; i++){
cin >> s[i];
reverse(s[i].begin(), s[i].end());
}
int ans = 0;
for(int i = 1; i <= n; i++){
for(int j = i+1; j <= n; j++){
if(k > (int)s[i].length() || k > (int)s[j].length())
continue;
bool flag = 1;
for(int l = 0; l < k; l++){
if(s[i][l] != s[j][l])
flag = 0;
}
if(flag) ans++;
}
}
cout << ans;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int k = sc.nextInt();
int arr[] = new int[n];
for(int i = 0; i < n; i++)
arr[i] = sc.nextInt();
System.out.println(minValue(arr, n, k));
}
static int minValue(int arr[], int N, int k)
{
int l = 0, h = N;
while(l+1 < h){
int m = (l + h) >> 1;
if(f(arr, m, N) <= k)
h = m;
else
l = m;
}
return h;
}
static int f(int a[], int x, int n)
{
int sum = 0;
for(int i = 0; i < n; i++)
sum += Math.max(a[i]-x, 0);
return sum;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: def minCut(arr,k):
mini = 1
maxi = k
mid = 0
while mini<=maxi:
mid = mini + int((maxi - mini)/2)
wood = 0
for j in range(n):
if(arr[j]-mid>=0):
wood += arr[j] - mid
if wood == k:
break;
elif wood > k:
mini = mid+1
else:
maxi = mid-1
print(mini)
n,k = list(map(int, input().split()))
arr = list(map(int, input().split()))
minCut(arr,k), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define ll long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 1e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N], n, k;
int f(int x){
int sum = 0;
for(int i = 1; i <= n; i++)
sum += max(a[i]-x, 0);
return sum;
}
void solve(){
cin >> n >> k;
for(int i = 1; i <= n; i++)
cin >> a[i];
int l = 0, h = N;
while(l+1 < h){
int m = (l + h) >> 1;
if(f(m) <= k)
h = m;
else
l = m;
}
cout << h;
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
testcases();
return 0;
} , In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program print total number of days in a month using switch case.First line of the input contains Month Number
<b>Constraints</b>
1 <= Month <= 12Print total number of days in a month (in general).Sample Input :
3
Sample Output :
31, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int month=sc.nextInt();
switch(month)
{
case 1:
System.out.println("31");
break;
case 2:
System.out.println("28");
break;
case 3:
System.out.println("31");
break;
case 4:
System.out.println("30");
break;
case 5:
System.out.println("31");
break;
case 6:
System.out.println("30");
break;
case 7:
System.out.println("31");
break;
case 8:
System.out.println("31");
break;
case 9:
System.out.println("30");
break;
case 10:
System.out.println("31");
break;
case 11:
System.out.println("30");
break;
case 12:
System.out.println("31");
break;
default:
System.out.println("invalid month");
break;
} }
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program print total number of days in a month using switch case.First line of the input contains Month Number
<b>Constraints</b>
1 <= Month <= 12Print total number of days in a month (in general).Sample Input :
3
Sample Output :
31, I have written this Solution Code: def MonthDays(N):
if N==1 or N==3 or N==5 or N==7 or N==8 or N==10 or N==12:
print(31)
elif N==4 or N==6 or N==9 or N==11:
print(30)
elif N==2:
print(28)
else:
print("Months out of range")
N = int(input())
MonthDays(N), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program print total number of days in a month using switch case.First line of the input contains Month Number
<b>Constraints</b>
1 <= Month <= 12Print total number of days in a month (in general).Sample Input :
3
Sample Output :
31, I have written this Solution Code: #include <stdio.h>
int main()
{
int month;
scanf("%d", &month);
switch(month)
{
case 1:
printf("31");
break;
case 2:
printf("28");
break;
case 3:
printf("31");
break;
case 4:
printf("30");
break;
case 5:
printf("31");
break;
case 6:
printf("30");
break;
case 7:
printf("31");
break;
case 8:
printf("31");
break;
case 9:
printf("30");
break;
case 10:
printf("31");
break;
case 11:
printf("30");
break;
case 12:
printf("31");
break;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: An array A of size N is called magical if:
1. Each element of the array is a positive integer not exceeding M, that is, 1 ≤ A<sub>i</sub> ≤ M for each i.
2. For each i such that 1 ≤ i ≤ N, define f(i) = A<sub>1</sub> | A<sub>2</sub> | ... A<sub>i</sub>, where x | y denotes the bitwise OR of x and y. Then, f(1) = f(2) = ... f(N) must hold.
Your task is to calculate the number of magical arrays of size N, modulo 998244353.The input consists of two space-separated integers N and M.
<b> Constraints: </b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ M ≤ 10<sup>5</sup>Print a single integer – the number of magical arrays modulo 998244353.Sample Input 1:
2 3
Sample Output 1:
5
Sample Explanation:
The magical arrays are: [1, 1], [2, 2], [3, 3], [3, 1], [3, 2].
Sample Input 2:
1 50
Sample Output 2:
50
Sample Input 3:
707 707
Sample Output 3:
687062898, I have written this Solution Code: #include <bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;
typedef long long ll;
typedef long double ld;
#define db(x) cerr << #x << ": " << x << '\n';
#define read(a) int a; cin >> a;
#define reads(s) string s; cin >> s;
#define readb(a, b) int a, b; cin >> a >> b;
#define readc(a, b, c) int a, b, c; cin >> a >> b >> c;
#define readarr(a, n) int a[(n) + 1] = {}; FOR(i, 1, (n)) {cin >> a[i];}
#define readmat(a, n, m) int a[n + 1][m + 1] = {}; FOR(i, 1, n) {FOR(j, 1, m) cin >> a[i][j];}
#define print(a) cout << a << endl;
#define printarr(a, n) FOR (i, 1, n) cout << a[i] << " "; cout << endl;
#define printv(v) for (int i: v) cout << i << " "; cout << endl;
#define printmat(a, n, m) FOR (i, 1, n) {FOR (j, 1, m) cout << a[i][j] << " "; cout << endl;}
#define all(v) v.begin(), v.end()
#define sz(v) (int)(v.size())
#define rz(v, n) v.resize((n) + 1);
#define pb push_back
#define fi first
#define se second
#define vi vector <int>
#define pi pair <int, int>
#define vpi vector <pi>
#define vvi vector <vi>
#define setprec cout << fixed << showpoint << setprecision(20);
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define FORD(i, a, b) for (int i = (a); i >= (b); i--)
const ll inf = 1e18;
const ll mod = 998244353;
const ll N = 2e5 + 1;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int power (int a, int b = mod - 2)
{
int res = 1;
while (b > 0) {
if (b & 1)
res = res * a % mod;
a = a * a % mod;
b >>= 1;
}
return res;
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
readb(n, m);
int ans = 0;
FOR (i, 1, m)
{
int x = (1 << (__builtin_popcountll(i))) - 1;
ans = (ans + power(x, n - 1)) % mod;
}
cout << ans;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array <b>A[]</b> of size <b>N</b>. A triplet (i, j, k) is said to be special if they satisfy below two conditions:
<b>1. i < j < k</b>
<b>2. A<sub>i</sub> < A<sub>j</sub> < A<sub>k</sub></b>
<b>V<sub>(A<sub>i</sub>,A<sub>j</sub>,A<sub>k</sub>)</sub>: A<sub>i</sub> + (A<sub>j</sub> * A<sub>k</sub>)</b>
You need to find the maximum possible value V<sub>(A<sub>i</sub>,A<sub>j</sub>,A<sub>k</sub>)</sub> which can be obtained from possible triplets satisfying above two conditions.The input line contains T, denoting the number of testcases. Each testcase contains Two lines. First line contains size of array. Second line contains elements of array separated by space.
<b>Constraints:</b>
1 <= T <= 100
1 <= N <= 10^5
1 <= A[i] <= 10^6
Sum of N for all test cases is less than 10^5For each testcase you need find the maximum possible value in new line otherwise print "<b>-1</b>" if no such triplet is found.Sample Input:
2
4
5 20 11 19
4
1 2 2 2
Sample Output:
214
-1
Explanation:
Testcase 1: 5 11 19 forms special triplet fulfilling above conditions, thus giving maximum value 5 + (11*19) = 214.
Testcase 2: None of triplets satisfy the given conditions thus, maximum value is -1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static int[] maxLeft(int[] a){
int N = a.length;
int[] res = new int[N];
TreeSet<Integer> ts = new TreeSet<>();
for(int i=0; i<N; i++){
int curr = a[i];
Integer maxLeftVal = ts.lower(curr);
if(maxLeftVal==null){
res[i] = -1;
}else{
res[i] = maxLeftVal;
}
ts.add(curr);
}
return res;
}
static int[] maxRight(int[] a){
int N = a.length;
int[] res = new int[N];
res[N-1] = -1;
int maxSeenIndexTillNow = N-1;
for(int i=N-2; i>=0; i--){
int curr = a[i];
if(curr<a[maxSeenIndexTillNow]){
res[i] = maxSeenIndexTillNow;
}else{
res[i] = -1;
maxSeenIndexTillNow = i;
}
}return res;
}
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int T = Integer.parseInt(br.readLine());
for(int t=0; t<T; t++){
int N = Integer.parseInt(br.readLine());
int[] arr = new int[N];
String[] strArr = br.readLine().split(" ");
for(int i=0; i<N; i++){
arr[i] = Integer.parseInt(strArr[i]);
}
int[] valOfA = maxLeft(arr);
int[] valOfK = maxRight(arr);
long vMax = -1;
for(int i=0; i<N; i++){
int vA = valOfA[i];
int vK = valOfK[i];
if(vA==-1 || vK==-1){
}else{
long valA = vA;
long valK = arr[vK];
long valJ = arr[i];
long currVmax = vA + (valJ*valK);
vMax = Math.max(vMax, currVmax);
}
}System.out.println(vMax);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array <b>A[]</b> of size <b>N</b>. A triplet (i, j, k) is said to be special if they satisfy below two conditions:
<b>1. i < j < k</b>
<b>2. A<sub>i</sub> < A<sub>j</sub> < A<sub>k</sub></b>
<b>V<sub>(A<sub>i</sub>,A<sub>j</sub>,A<sub>k</sub>)</sub>: A<sub>i</sub> + (A<sub>j</sub> * A<sub>k</sub>)</b>
You need to find the maximum possible value V<sub>(A<sub>i</sub>,A<sub>j</sub>,A<sub>k</sub>)</sub> which can be obtained from possible triplets satisfying above two conditions.The input line contains T, denoting the number of testcases. Each testcase contains Two lines. First line contains size of array. Second line contains elements of array separated by space.
<b>Constraints:</b>
1 <= T <= 100
1 <= N <= 10^5
1 <= A[i] <= 10^6
Sum of N for all test cases is less than 10^5For each testcase you need find the maximum possible value in new line otherwise print "<b>-1</b>" if no such triplet is found.Sample Input:
2
4
5 20 11 19
4
1 2 2 2
Sample Output:
214
-1
Explanation:
Testcase 1: 5 11 19 forms special triplet fulfilling above conditions, thus giving maximum value 5 + (11*19) = 214.
Testcase 2: None of triplets satisfy the given conditions thus, maximum value is -1, I have written this Solution Code: #include <bits/stdc++.h>
typedef long long int ll;
using namespace std;
ll getLowValue(set<ll>& lowValue, ll& n)
{
auto it = lowValue.lower_bound(n);
--it;
return (*it);
}
ll maxTriplet(ll arr[], ll n)
{
ll maxSuffArr[n + 1];
maxSuffArr[n] = 0;
for (int i = n - 1; i >= 0; --i)
maxSuffArr[i] = max(maxSuffArr[i + 1], arr[i]);
ll ans = -1;
set<ll> lowValue;
lowValue.insert(INT_MIN);
for (int i = 0; i < n - 1; ++i) {
if (maxSuffArr[i + 1] > arr[i]) {
ans = max(ans, getLowValue(lowValue,arr[i]) + arr[i] * maxSuffArr[i + 1]);
lowValue.insert(arr[i]);
}
}
return ans;
}
int main()
{
int t;
cin>>t;
while(t--){
ll n;
cin>>n;
ll arr[n];
for(int i=0;i<n;i++)
cin>>arr[i];
cout << maxTriplet(arr, n)<<endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Let us create a table 'STORY' from existing table 'POSTS' which will contain the information about the stories users will create on LinkedIn. This table 'story' will contain the fields (USERNAME, DATETIME_CREATED, PHOTO) of the table 'posts'
( USE ONLY UPPERCASE LETTERS FOR CODE)
<schema>[{'name': 'STORY', 'columns': [{'name': 'USERNAME', 'type': 'VARCHAR(24)'}, {'name': 'DATETIME_CREATED', 'type': 'TEXT'}, {'name': 'PHOTO', 'type': 'BLOB'}]}]</schema>nannannan, I have written this Solution Code:
CREATE TABLE STORY AS
SELECT USERNAME, DATETIME_CREATED, PHOTO
FROM POST;
, In this Programming Language: SQL, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Create a basic table namely TEST_TABLE with 1 field TEST_FIELD as int.
( USE ONLY UPPER CASE LETTERS )
<schema>[{'name': 'TEST_TABLE', 'columns': [{'name': 'TEST_FIELD', 'type': 'INT'}]}]</schema>nannannan, I have written this Solution Code: CREATE TABLE TEST_TABLE (
TEST_FIELD INT
);, In this Programming Language: SQL, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, super primes are those integers from 1 to N whose multiples (other than themselves) do no exist in the range [1, N].
Your task is to generate all super primes <= N in sorted order.
</b>Note: Super primes are not related to primes in any way.</b><b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>SuperPrime()</b> that takes the integer N as a parameter.
Constraints:-
2 < = N <= 1000Printing will be done by the driver code you just need to complete the generator function.Sample Input:-
5
Sample Output:-
3 4 5
Sample Input:-
4
Sample Output:-
3 4, I have written this Solution Code: public static void SuperPrimes(int n){
int x = n/2+1;
for(int i=x ; i<=n ; i++){
out.printf("%d ",i);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, super primes are those integers from 1 to N whose multiples (other than themselves) do no exist in the range [1, N].
Your task is to generate all super primes <= N in sorted order.
</b>Note: Super primes are not related to primes in any way.</b><b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>SuperPrime()</b> that takes the integer N as a parameter.
Constraints:-
2 < = N <= 1000Printing will be done by the driver code you just need to complete the generator function.Sample Input:-
5
Sample Output:-
3 4 5
Sample Input:-
4
Sample Output:-
3 4, I have written this Solution Code: def SuperPrimes(N):
for i in range (int(N/2)+1,N+1):
yield i
return
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int k = sc.nextInt();
int arr[] = new int[n];
for(int i = 0; i < n; i++)
arr[i] = sc.nextInt();
System.out.println(minValue(arr, n, k));
}
static int minValue(int arr[], int N, int k)
{
int l = 0, h = N;
while(l+1 < h){
int m = (l + h) >> 1;
if(f(arr, m, N) <= k)
h = m;
else
l = m;
}
return h;
}
static int f(int a[], int x, int n)
{
int sum = 0;
for(int i = 0; i < n; i++)
sum += Math.max(a[i]-x, 0);
return sum;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: def minCut(arr,k):
mini = 1
maxi = k
mid = 0
while mini<=maxi:
mid = mini + int((maxi - mini)/2)
wood = 0
for j in range(n):
if(arr[j]-mid>=0):
wood += arr[j] - mid
if wood == k:
break;
elif wood > k:
mini = mid+1
else:
maxi = mid-1
print(mini)
n,k = list(map(int, input().split()))
arr = list(map(int, input().split()))
minCut(arr,k), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define ll long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 1e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N], n, k;
int f(int x){
int sum = 0;
for(int i = 1; i <= n; i++)
sum += max(a[i]-x, 0);
return sum;
}
void solve(){
cin >> n >> k;
for(int i = 1; i <= n; i++)
cin >> a[i];
int l = 0, h = N;
while(l+1 < h){
int m = (l + h) >> 1;
if(f(m) <= k)
h = m;
else
l = m;
}
cout << h;
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
testcases();
return 0;
} , In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to print Five stars ('*') <b><i>vertically</i></b> and 5 <b><i>horizontally</i></b>
There will be two functions:
<ul>
<li>verticalFive(): Print stars in vertical order</li>
<li>horizontalFive(): Print stars in horizontal order</l>
</ul><b>User Task:</b>
Your task is to complete the functions <b>verticalFive()</b> and <b>horizontalFive()</b>.
Print 5 vertical stars in <b> verticalFive</b> and 5 horizontal stars(separated by whitespace) in <b>horizontalFive</b> function.
<b>Note</b>: You don't need to print the extra blank line it will be printed by the driver codeNo Sample Input:
Sample Output:
*
*
*
*
*
* * * * *, I have written this Solution Code: static void verticalFive(){
System.out.println("*");
System.out.println("*");
System.out.println("*");
System.out.println("*");
System.out.println("*");
}
static void horizontalFive(){
System.out.print("* * * * *");
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to print Five stars ('*') <b><i>vertically</i></b> and 5 <b><i>horizontally</i></b>
There will be two functions:
<ul>
<li>verticalFive(): Print stars in vertical order</li>
<li>horizontalFive(): Print stars in horizontal order</l>
</ul><b>User Task:</b>
Your task is to complete the functions <b>verticalFive()</b> and <b>horizontalFive()</b>.
Print 5 vertical stars in <b> verticalFive</b> and 5 horizontal stars(separated by whitespace) in <b>horizontalFive</b> function.
<b>Note</b>: You don't need to print the extra blank line it will be printed by the driver codeNo Sample Input:
Sample Output:
*
*
*
*
*
* * * * *, I have written this Solution Code: def vertical5():
for i in range(0,5):
print("*",end="\n")
#print()
def horizontal5():
for i in range(0,5):
print("*",end=" ")
vertical5()
print(end="\n")
horizontal5(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: How would you add your own method to the Array object so
the following code would work?
const arr = [1, 2, 3]
console. log(arr.average())
// 2input will be an array, run like this
const anyArray = [5,6...]
anyArray.average should return average of the arraysAverage of the given arrayconst myArray = [1,2,3,4,5]
console.log(myArray.average())
// 3, I have written this Solution Code: Array.prototype.average = function() {
// calculate sum
var sum = this.reduce(function(prev, cur) { return prev + cur; });
// return sum divided by number of elements
return sum / this.length;
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: N people are waiting in line to get food. The ith person takes Arr[i] amount of time to get food. A person is happy if the amount of time he has to wait is less than or equal to the amount of time he takes to get food. The time a person waits is the sum of time people in front of him take to get food. Now you have to rearrange the people in the line such that the maximum number of people in the line are happy and report the maximum number of people that can be happy.The first line of input contains a single integer N.
The second line of input contains N integers denoting Arr[i].
Constraints:
1 <= N <= 100000
1 <= Arr[i] <= 1000000000Print the maximum number of people that can be happy after the rearrangement.Sample Input
4
3 1 3 10
Sample Output
3
Explanation:
The optimal arrangement is 1 3 10 3
This way person 1 waits 0 units so he is happy.
Person 2 waits for 1 unit so he is happy.
Person 3 waits for 4 units so is happy.
Person 4 waits 14 units so he is unhappy., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
int n=Integer.parseInt(in.readLine());
String s[]=in.readLine().split(" ");
long[] a=new long[n];
for(int i=0;i<n;i++){
a[i]=Long.parseLong(s[i]);
}
long sum=0;
int count=0;
Arrays.sort(a);
for(int i=0;i<n;i++){
if(sum<=a[i]){
sum+=a[i];
count++;
}
}
System.out.print(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: N people are waiting in line to get food. The ith person takes Arr[i] amount of time to get food. A person is happy if the amount of time he has to wait is less than or equal to the amount of time he takes to get food. The time a person waits is the sum of time people in front of him take to get food. Now you have to rearrange the people in the line such that the maximum number of people in the line are happy and report the maximum number of people that can be happy.The first line of input contains a single integer N.
The second line of input contains N integers denoting Arr[i].
Constraints:
1 <= N <= 100000
1 <= Arr[i] <= 1000000000Print the maximum number of people that can be happy after the rearrangement.Sample Input
4
3 1 3 10
Sample Output
3
Explanation:
The optimal arrangement is 1 3 10 3
This way person 1 waits 0 units so he is happy.
Person 2 waits for 1 unit so he is happy.
Person 3 waits for 4 units so is happy.
Person 4 waits 14 units so he is unhappy., I have written this Solution Code: n = int(input())
li = input().split()
li = list(map(int, li))
curr = 0
ans = 0
li.sort()
for i in li:
if i >= curr:
curr += i
ans += 1
print(ans), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: N people are waiting in line to get food. The ith person takes Arr[i] amount of time to get food. A person is happy if the amount of time he has to wait is less than or equal to the amount of time he takes to get food. The time a person waits is the sum of time people in front of him take to get food. Now you have to rearrange the people in the line such that the maximum number of people in the line are happy and report the maximum number of people that can be happy.The first line of input contains a single integer N.
The second line of input contains N integers denoting Arr[i].
Constraints:
1 <= N <= 100000
1 <= Arr[i] <= 1000000000Print the maximum number of people that can be happy after the rearrangement.Sample Input
4
3 1 3 10
Sample Output
3
Explanation:
The optimal arrangement is 1 3 10 3
This way person 1 waits 0 units so he is happy.
Person 2 waits for 1 unit so he is happy.
Person 3 waits for 4 units so is happy.
Person 4 waits 14 units so he is unhappy., I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
typedef unsigned long long ull;
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main(){
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n;
cin >> n;
int arr[n];
for(int i = 0; i < n;i++) cin >> arr[i];
sort(arr,arr+n);
int cur=0;
int ans = 0;
for(int i = 0; i < n;i++){
if(cur <= arr[i]) cur += arr[i],ans++;
}
cout << ans << endl;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a circular linked list consisting of N nodes and an integer K, your task is to add the integer K at the end of the list.
<b>Note:
Sample Input and Output just show how a linked list will look depending on the questions. Do not copy-paste as it is in custom input</b><b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Insertion()</b> that takes head node of circular linked list and the integer K as parameter.
Constraints:
1 <=N <= 1000
1 <= Node.data, K<= 1000Return the head node of the modified circular linked list.Sample Input 1:-
3
1- >2- >3
4
Sample Output 1:-
1- >2- >3- >4
Sample Input 2:-
3
1- >3- >2
1
Sample Output 2:-
1- >3- >2- >1, I have written this Solution Code: public static Node Insertion(Node head, int K){
Node node=head;
while ( node.next != head)
{node = node.next; }
Node temp = new Node(K);
node.next=temp;
temp.next=head;
return head;}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array arr[] of N integers and another integer D, your task is to perform D right circular rotations on the array and print the modified array.User task:
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>circularRotate() </b> which takes the deque, number of rotation and the number of elements in deque as parameters.
Constraint:
1 <= T <= 100
1 <= N <= 100000
1 <= elements <= 10000
1 <= D <= 100000You don't need to print anything you just need to complete the function.Input:
2
5
1 2 3 4 5
6
4
1 2 3 4
7
Output:
5 1 2 3 4
2 3 4 1, I have written this Solution Code: static void circularRotate(Deque<Integer> deq, int d, int n)
{
// Push first d elements
// from last to the beginning
for (int i = 0; i < d%n; i++) {
int val = deq.peekLast();
deq.pollLast();
deq.addFirst(val);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to return the sum of all of its divisors.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>SumOfDivisors()</b> that takes the integer N as parameter.
Constraints:-
1<=N<=10^9Return the sum of all of the divisors.Sample Input:-
4
Sample Output:-
7
Sample Input:-
13
Sample Output:-
14, I have written this Solution Code: public static long SumOfDivisors(long N){
long sum=0;
long c=(long)Math.sqrt(N);
for(long i=1;i<=c;i++){
if(N%i==0){
sum+=i;
if(i*i!=N){sum+=N/i;}
}
}
return sum;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to return the sum of all of its divisors.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>SumOfDivisors()</b> that takes the integer N as parameter.
Constraints:-
1<=N<=10^9Return the sum of all of the divisors.Sample Input:-
4
Sample Output:-
7
Sample Input:-
13
Sample Output:-
14, I have written this Solution Code:
long long SumOfDivisors(long long N){
long long sum=0;
long sq=sqrt(N);
for(long i=1;i<=sq;i++){
if(N%i==0){
sum+=i;
if(i*i!=N){
sum+=N/i;
}
}
}
return sum;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to return the sum of all of its divisors.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>SumOfDivisors()</b> that takes the integer N as parameter.
Constraints:-
1<=N<=10^9Return the sum of all of the divisors.Sample Input:-
4
Sample Output:-
7
Sample Input:-
13
Sample Output:-
14, I have written this Solution Code:
long long SumOfDivisors(long long N){
long long sum=0;
long sq=sqrt(N);
for(long i=1;i<=sq;i++){
if(N%i==0){
sum+=i;
if(i*i!=N){
sum+=N/i;
}
}
}
return sum;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to return the sum of all of its divisors.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>SumOfDivisors()</b> that takes the integer N as parameter.
Constraints:-
1<=N<=10^9Return the sum of all of the divisors.Sample Input:-
4
Sample Output:-
7
Sample Input:-
13
Sample Output:-
14, I have written this Solution Code:
def SumOfDivisors(num) :
# Final result of summation of divisors
result = 0
# find all divisors which divides 'num'
i = 1
while i<= (math.sqrt(num)) :
# if 'i' is divisor of 'num'
if (num % i == 0) :
# if both divisors are same then
# add it only once else add both
if (i == (num / i)) :
result = result + i;
else :
result = result + (i + num/i);
i = i + 1
# Add 1 to the result as 1 is also
# a divisor
return (result); , In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Print a right angled triangle of stars of given height N as shown in example.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 10Print the Right angled triangle of height N.Sample Input:-
3
Sample Output:-
*
**
***
Sample Input:-
4
Sample Output:-
*
**
***
****, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int n=Integer.parseInt(br.readLine());
for(int i =1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print("*") ;
}
System.out.println();
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Print a right angled triangle of stars of given height N as shown in example.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 10Print the Right angled triangle of height N.Sample Input:-
3
Sample Output:-
*
**
***
Sample Input:-
4
Sample Output:-
*
**
***
****, I have written this Solution Code: x=int(input(""))
for i in range(x):
for j in range(i+1):
print("*",end='')
print(""), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Print a right angled triangle of stars of given height N as shown in example.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 10Print the Right angled triangle of height N.Sample Input:-
3
Sample Output:-
*
**
***
Sample Input:-
4
Sample Output:-
*
**
***
****, I have written this Solution Code: #include <iostream>
using namespace std;
int main(){
int n;
cin>>n;
for(int i=0;i<n;i++){
for(int j=0;j<i+1;j++){
cout<<'*';}
cout<<endl;
}}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int k = sc.nextInt();
int arr[] = new int[n];
for(int i = 0; i < n; i++)
arr[i] = sc.nextInt();
System.out.println(minValue(arr, n, k));
}
static int minValue(int arr[], int N, int k)
{
int l = 0, h = N;
while(l+1 < h){
int m = (l + h) >> 1;
if(f(arr, m, N) <= k)
h = m;
else
l = m;
}
return h;
}
static int f(int a[], int x, int n)
{
int sum = 0;
for(int i = 0; i < n; i++)
sum += Math.max(a[i]-x, 0);
return sum;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: def minCut(arr,k):
mini = 1
maxi = k
mid = 0
while mini<=maxi:
mid = mini + int((maxi - mini)/2)
wood = 0
for j in range(n):
if(arr[j]-mid>=0):
wood += arr[j] - mid
if wood == k:
break;
elif wood > k:
mini = mid+1
else:
maxi = mid-1
print(mini)
n,k = list(map(int, input().split()))
arr = list(map(int, input().split()))
minCut(arr,k), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer K and an array height[] of size N, where height[i] denotes the height of the ith tree in a forest. The task is to make a cut of height X from the ground such that at max K units wood is collected. Find the minimum value of X
<b>If you make a cut of height X from the ground then every tree with a height greater than X will be reduced to X and the remaining part of the wood can be collected</b>The first line contains two integers N and K.
The next line contains N integers denoting the elements of the array height[]
<b>Constraints</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ arr[i] ≤ 10<sup>5</sup>
1 ≤ K ≤ 10<sup>7</sup>Print a single integer with the value of X.Sample Input:
4 2
1 2 1 2
Sample Output:
1
<b>Explanation:</b>
Make a cut at height 1, the updated array will be {1, 1, 1, 1} and
the collected wood will be {0, 1, 0, 1} i. e. 0 + 1 + 0 + 1 = 2., I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define ll long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 1e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N], n, k;
int f(int x){
int sum = 0;
for(int i = 1; i <= n; i++)
sum += max(a[i]-x, 0);
return sum;
}
void solve(){
cin >> n >> k;
for(int i = 1; i <= n; i++)
cin >> a[i];
int l = 0, h = N;
while(l+1 < h){
int m = (l + h) >> 1;
if(f(m) <= k)
h = m;
else
l = m;
}
cout << h;
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
testcases();
return 0;
} , In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given Q queries. Each query consists of a single number N. You can perform any of the 2 operations on N in each move:
1: If we take 2 integers a and b where N = a x b(a≠1, b≠1), then we can change N = max(a, b)
2: Decrease the value of N by 1.
Determine the minimum number of moves required to reduce the value of N to 0.The first line contains the integer Q.
The next Q lines each contain an integer, N.
<b>Constraints</b>
1 ≤ Q ≤ 10<sup>3</sup>
1 ≤ N ≤ 10<sup>6</sup>Output Q lines. Each line containing the minimum number of moves required to reduce the value of N to 0.Sample Input
2
3
4
Sample Output
3
3
Explanation
For test case 1, We only have one option that gives the minimum number of moves.
Follow 3- >2- >1- >0. Hence, moves.
For the case 2, we can either go 4- >3- >2- >1- >0 or 4- >2- >1- >0. The 2nd option is more optimal. Hence, 3 moves., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
solve(1000000);
int t = sc.nextInt();
for(int i=0; i<t; i++)
System.out.println(table[sc.nextInt()]);
}
public static int[] table = new int[1000001];
public static void solve(int n){
for(int i=1; i<=n; i++)
table[i] = n+1;
ArrayDeque<Integer> q = new ArrayDeque<Integer>();
q.add(0);
while (!q.isEmpty()){
int next = q.poll();
if (next > 0)
for (int i=Math.min(next, n/next); i > 0; i--){
if (table[i*next] > table[next] + 1){
table[i*next] = table[next] + 1;
q.add(i*next);
}
}
if (next < n && table[next+1] > table[next]+1){
table[next+1] = table[next] + 1;
q.add(next+1);
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given Q queries. Each query consists of a single number N. You can perform any of the 2 operations on N in each move:
1: If we take 2 integers a and b where N = a x b(a≠1, b≠1), then we can change N = max(a, b)
2: Decrease the value of N by 1.
Determine the minimum number of moves required to reduce the value of N to 0.The first line contains the integer Q.
The next Q lines each contain an integer, N.
<b>Constraints</b>
1 ≤ Q ≤ 10<sup>3</sup>
1 ≤ N ≤ 10<sup>6</sup>Output Q lines. Each line containing the minimum number of moves required to reduce the value of N to 0.Sample Input
2
3
4
Sample Output
3
3
Explanation
For test case 1, We only have one option that gives the minimum number of moves.
Follow 3- >2- >1- >0. Hence, moves.
For the case 2, we can either go 4- >3- >2- >1- >0 or 4- >2- >1- >0. The 2nd option is more optimal. Hence, 3 moves., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main() {
int test;
cin >> test;
while (test--) {
int n;
cin >> n;
if (n == 0) {
cout << 0 << endl;
continue;
}
if (n == 1) {
cout << 1 << endl;
continue;
}
vector<int> dist(n + 1, 0);
queue<int> q;
q.push(n);
dist[n] = 1;
while (1) {
int element = q.front();
q.pop();
if (element == 2) {
cout << dist[2] + 1 << endl;
break;
}
if (dist[element - 1] == 0) {
dist[element - 1] = dist[element] + 1;
q.push(element - 1);
}
for (int i = 2; i * i <= element; i++) {
if (element % i == 0) {
int maxfrac = element / i;
if (dist[maxfrac] == 0) dist[maxfrac] = dist[element] + 1, q.push(maxfrac);
}
}
}
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Newton is standing before a typical staircase with N steps. Newton is standing on the 0-th step and wants to go to the N-th step. To reach the top he can either take a single step or he can take a double step (two steps) at the same time.
However, M of the N steps are broken i. e. S<sub>1</sub>, S<sub>2</sub>, ... , S<sub>M</sub> are broken and Newton cannot visit those steps,
Find out the number of different ways in which Newton can climb to the top of the staircase. Since the number can be very large, find it modulo 1,000,000,007The first line contains two integers, N and M.
The next M lines contains a single integer each, S<sub>i</sub>
<b>Constraints:</b>
1) 1 ≤ N ≤ 2 x 10<sup>5</sup>
2) 0 ≤ M ≤ N - 1
3) 1 ≤ S<sub>1</sub> < S<sub>2</sub>, < ... < S<sub>M</sub> ≤ N - 1Print the number of ways<b>Sample Input 1:</b>
6 1
3
<b>Sample Output 1:</b>
4
<b>Sample Explanation 1:</b>
There are four ways to climb up the stairs, as follows:
0→1→2→4→5→6
0→1→2→4→6
0→2→4→5→6
0→2→4→6
<b>Sample Input 2:</b>
100 5
1
23
45
67
89
<b>Sample Output 2:</b>
608200469, I have written this Solution Code: #include <bits/stdc++.h>
#define int long long
using namespace std;
int32_t main()
{
int x,n,m;
cin>>n>>m;
vector<int>v(n+1,0);
for(int i=1;i<=m;i++){
cin>>x;
v[x]=1;
}
vector<int>dp(n+1,0);
int M = 1e9+7;
dp[0]=1;
for(int i=0;i<n+1;i++){
if(v[i]==0){
if(i+2<=n)dp[i+2]+=dp[i];
if(i+1<=n)dp[i+1]+=dp[i];
dp[i+2]%=M;
dp[i+1]%=M;
}
}
int ans = dp[n]%M;
cout<<ans;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two arrays - value and frequency both containing N elements.
There is also a third array C which is currently empty. Then you perform N insertion operation in the array. For ith operation you insert value[i] to the end of the array frequency[i] number of times.
Finally you have to tell the kth smallest element in the array C.First line of input contains N.
Second line contains N integers denoting array - value
Third line contains N integers denoting array - frequency
Fourth line contains single integer K.
Constraints
1 <= N, value[i], frequency[i] <= 100000
1 <= k <= frequency[1] + frequency[2] +frequency[3] +........ + frequency[N]
Output a single integer which is the kth smallest element of the array C.Sample input 1
5
1 2 3 4 5
1 1 1 2 2
3
Sample output 1
3
Explanation 1:
Array C constructed is 1 2 3 4 4 5 5
Third smallest element is 3
Sample input 2
3
2 1 3
3 3 2
2
sample output 2
1
Explanation 2:
Array C constructed is 2 2 2 1 1 1 3 3
Second smallest element is 1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
StringTokenizer st = new StringTokenizer(br.readLine());
int[] val = new int[n];
for(int i=0; i<n; i++){
val[i] = Integer.parseInt(st.nextToken());
}
st = new StringTokenizer(br.readLine());
int[] freq = new int[n];
for(int i=0; i<n; i++){
freq[i] = Integer.parseInt(st.nextToken());
}
int k = Integer.parseInt(br.readLine());
for (int i=0; i<n; i++) {
for (int j=i+1; j<n; j++) {
if (val[j] < val[i]) {
int temp = val[i];
val[i] = val[j];
val[j] = temp;
int temp1 = freq[i];
freq[i] = freq[j];
freq[j] = temp1;
}
}
}
int element=0;
for(int i=0; i<n; i++){
for(int j=0; j<freq[i]; j++){
element++;
int value = val[i];
if(element==k){
System.out.print(value);
break;
}
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two arrays - value and frequency both containing N elements.
There is also a third array C which is currently empty. Then you perform N insertion operation in the array. For ith operation you insert value[i] to the end of the array frequency[i] number of times.
Finally you have to tell the kth smallest element in the array C.First line of input contains N.
Second line contains N integers denoting array - value
Third line contains N integers denoting array - frequency
Fourth line contains single integer K.
Constraints
1 <= N, value[i], frequency[i] <= 100000
1 <= k <= frequency[1] + frequency[2] +frequency[3] +........ + frequency[N]
Output a single integer which is the kth smallest element of the array C.Sample input 1
5
1 2 3 4 5
1 1 1 2 2
3
Sample output 1
3
Explanation 1:
Array C constructed is 1 2 3 4 4 5 5
Third smallest element is 3
Sample input 2
3
2 1 3
3 3 2
2
sample output 2
1
Explanation 2:
Array C constructed is 2 2 2 1 1 1 3 3
Second smallest element is 1, I have written this Solution Code: def myFun():
n = int(input())
arr1 = list(map(int,input().strip().split()))
arr2 = list(map(int,input().strip().split()))
k = int(input())
arr = []
for i in range(n):
arr.append((arr1[i], arr2[i]))
arr.sort()
c = 0
for i in arr:
k -= i[1]
if k <= 0:
print(i[0])
return
myFun()
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two arrays - value and frequency both containing N elements.
There is also a third array C which is currently empty. Then you perform N insertion operation in the array. For ith operation you insert value[i] to the end of the array frequency[i] number of times.
Finally you have to tell the kth smallest element in the array C.First line of input contains N.
Second line contains N integers denoting array - value
Third line contains N integers denoting array - frequency
Fourth line contains single integer K.
Constraints
1 <= N, value[i], frequency[i] <= 100000
1 <= k <= frequency[1] + frequency[2] +frequency[3] +........ + frequency[N]
Output a single integer which is the kth smallest element of the array C.Sample input 1
5
1 2 3 4 5
1 1 1 2 2
3
Sample output 1
3
Explanation 1:
Array C constructed is 1 2 3 4 4 5 5
Third smallest element is 3
Sample input 2
3
2 1 3
3 3 2
2
sample output 2
1
Explanation 2:
Array C constructed is 2 2 2 1 1 1 3 3
Second smallest element is 1, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define inf 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> oset;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int N;ll K;
cin>>N;
int c=0;
pair<int, ll> A[N];
for(int i=0;i<N;++i){
cin >> A[i].first ;
}
for(int i=0;i<N;++i){
cin >> A[i].second ;
}
cin>>K;
sort(A, A+N);
for(int i=0;i<N;++i){
K -= A[i].second;
if(K <= 0){
cout << A[i].first << endl;;
break;
}
}
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array A of size N of non-negative integers, find a continuous sub-array which adds to a given number S.Each test case consists of two lines. The first line of each test case is N and S, where N is the size of the array and S is the sum. The second line of each test case contains N space-separated integers denoting the array elements.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Ai ≤ 10<sup>5</sup>Print the starting and ending positions (1 indexing) of first such occurring subarray from the left if sum equals to subarray, else print -1.Sample Input
5 12
1 2 3 7 5
Sample Output
2 4
Explanation:
subarray starting from index 2 and ending at index 4 => {2 , 3 , 7}
sum = 2 + 3 + 7 = 12
Sample Input
10 15
1 2 3 4 5 6 7 8 9 10
Sample Output
1 5, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException
{
try{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String StrInput[] = br.readLine().trim().split(" ");
int n = Integer.parseInt(StrInput[0]);
int s = Integer.parseInt(StrInput[1]);
int arr[] = new int[n];
String StrInput2[] = br.readLine().trim().split(" ");
for(int i=0;i<n;i++)
{
arr[i] = Integer.parseInt(StrInput2[i]);
}
int sum = arr[0];
int startingindex = 0;
int endingindex = 1;
int j = 0;
int i;
for(i=1;i<=n;i++)
{
if(sum < s && arr[i] != 0)
{
sum += arr[i];
}
while(sum > s && startingindex < i-1)
{
sum -= arr[startingindex];
startingindex++;
}
if(sum == s)
{
endingindex = i+1;
if(arr[0] == 0)
{
System.out.print(startingindex+2 + " " + endingindex);
}
else
{
System.out.print(startingindex+1 + " "+ endingindex);
}
break;
}
if(i == n && sum < s)
{
System.out.print(-1);
break;
}
}
}
catch(Exception e)
{
System.out.print(-1);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array A of size N of non-negative integers, find a continuous sub-array which adds to a given number S.Each test case consists of two lines. The first line of each test case is N and S, where N is the size of the array and S is the sum. The second line of each test case contains N space-separated integers denoting the array elements.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Ai ≤ 10<sup>5</sup>Print the starting and ending positions (1 indexing) of first such occurring subarray from the left if sum equals to subarray, else print -1.Sample Input
5 12
1 2 3 7 5
Sample Output
2 4
Explanation:
subarray starting from index 2 and ending at index 4 => {2 , 3 , 7}
sum = 2 + 3 + 7 = 12
Sample Input
10 15
1 2 3 4 5 6 7 8 9 10
Sample Output
1 5, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int n,k;
cin>>n>>k;
int a[n];
for(int i=0;i<n;i++)
{
cin>>a[i];
}
int sum=0;
unordered_map<int,int> m;
for(int i=0;i<n;i++){
sum+=a[i];
if(sum==k){cout<<1<<" "<<i+1;return 0;}
if(m.find(sum-k)!=m.end()){
cout<<m[sum-k]+2<<" "<<i+1;
return 0;
}
m[sum]=i;
}
cout<<-1;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array A of size N of non-negative integers, find a continuous sub-array which adds to a given number S.Each test case consists of two lines. The first line of each test case is N and S, where N is the size of the array and S is the sum. The second line of each test case contains N space-separated integers denoting the array elements.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Ai ≤ 10<sup>5</sup>Print the starting and ending positions (1 indexing) of first such occurring subarray from the left if sum equals to subarray, else print -1.Sample Input
5 12
1 2 3 7 5
Sample Output
2 4
Explanation:
subarray starting from index 2 and ending at index 4 => {2 , 3 , 7}
sum = 2 + 3 + 7 = 12
Sample Input
10 15
1 2 3 4 5 6 7 8 9 10
Sample Output
1 5, I have written this Solution Code: def sumFinder(N,S,a):
currentSum = a[0]
start = 0
i = 1
while i <= N:
while currentSum > S and start < i-1:
currentSum = currentSum - a[start]
start += 1
if currentSum == S:
return (start+1,i)
if i < N:
currentSum = currentSum + a[i]
i += 1
return(-1)
N, S = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
ans = sumFinder(N,S,a)
if(ans==-1):
print(ans)
else:
print(ans[0],ans[1]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer <b>N</b>, you need to typecast this integer to String. If the typecasting is done successfully then we will print "<b>Nice Job</b>" otherwise "<b>Wrong answer</b>".User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>checkConvertion()</b>, which contains N as a parameter.You need to return the typecasted string value. The driver code will print "<b>Nice Job</b>" otherwise "<b>Wrong answer</b>".Sample Input:
5
Sample Output:
Nice Job
Sample Input:
6
Sample Output:
Nice Job, I have written this Solution Code: def checkConevrtion(a):
return str(a)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer <b>N</b>, you need to typecast this integer to String. If the typecasting is done successfully then we will print "<b>Nice Job</b>" otherwise "<b>Wrong answer</b>".User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>checkConvertion()</b>, which contains N as a parameter.You need to return the typecasted string value. The driver code will print "<b>Nice Job</b>" otherwise "<b>Wrong answer</b>".Sample Input:
5
Sample Output:
Nice Job
Sample Input:
6
Sample Output:
Nice Job, I have written this Solution Code: static String checkConevrtion(int a)
{
return String.valueOf(a);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara selects two different numbers from the range 1 to 50 and noted their sum as N. However later she Forgets which numbers she selected and now wants to know the total number of possible combinations she can have.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>forgottenNumbers()</b> that takes integer N argument.
Constraints:-
3 <= N <= 99Return the total number of choices Sara has.Sample Input:-
8
Sample Output:-
3
Explanation:-
(1, 7), (2, 6), (3, 5)
Sample Input:-
3
Sample Output:-
1, I have written this Solution Code: int forgottenNumbers(int N){
int ans=0;
for(int i=1;i<=50;i++){
for(int j=1;j<=50;j++){
if(i!=j && i+j==N){
ans++;
}
}
}
return ans/2;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara selects two different numbers from the range 1 to 50 and noted their sum as N. However later she Forgets which numbers she selected and now wants to know the total number of possible combinations she can have.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>forgottenNumbers()</b> that takes integer N argument.
Constraints:-
3 <= N <= 99Return the total number of choices Sara has.Sample Input:-
8
Sample Output:-
3
Explanation:-
(1, 7), (2, 6), (3, 5)
Sample Input:-
3
Sample Output:-
1, I have written this Solution Code: static int forgottenNumbers(int N){
int ans=0;
for(int i=1;i<=50;i++){
for(int j=1;j<=50;j++){
if(i!=j && i+j==N){
ans++;
}
}
}
return ans/2;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara selects two different numbers from the range 1 to 50 and noted their sum as N. However later she Forgets which numbers she selected and now wants to know the total number of possible combinations she can have.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>forgottenNumbers()</b> that takes integer N argument.
Constraints:-
3 <= N <= 99Return the total number of choices Sara has.Sample Input:-
8
Sample Output:-
3
Explanation:-
(1, 7), (2, 6), (3, 5)
Sample Input:-
3
Sample Output:-
1, I have written this Solution Code: int forgottenNumbers(int N){
int ans=0;
for(int i=1;i<=50;i++){
for(int j=1;j<=50;j++){
if(i!=j && i+j==N){
ans++;
}
}
}
return ans/2;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara selects two different numbers from the range 1 to 50 and noted their sum as N. However later she Forgets which numbers she selected and now wants to know the total number of possible combinations she can have.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>forgottenNumbers()</b> that takes integer N argument.
Constraints:-
3 <= N <= 99Return the total number of choices Sara has.Sample Input:-
8
Sample Output:-
3
Explanation:-
(1, 7), (2, 6), (3, 5)
Sample Input:-
3
Sample Output:-
1, I have written this Solution Code: def forgottenNumbers(N):
ans = 0
for i in range (1,51):
for j in range (1,51):
if i != j and i+j==N:
ans=ans+1
return ans//2
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N. <b>Value</b> of an element A<sub>i</sub> is defined as the sum of the absolute difference of all elements of the array with A<sub>i</sub>. More formally, the value of an element at index i is the sum of |A<sub>i</sub> - A<sub>j</sub>| over all j (1 <= j <= N). Find the maximum such value over all i (1 <= i <= N) in the array.
<b>Note</b>: Given array is 1-based indexThe first line of the input contains a single integer N.
The second line of the input contains N space-separated integers.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ A<sub>i</sub> ≤ 10<sup>9</sup>Print the maximum such value over all i (1 <= i <= N) in the array.Sample Input:
6
1 1 5 5 8 9
Sample Output:
25
<b>Explanation:</b>
For, i = 6,
|A<sub>1</sub> - A<sub>6</sub>| = 8
|A<sub>2</sub> - A<sub>6</sub>| = 8
|A<sub>3</sub> - A<sub>6</sub>| = 4
|A<sub>4</sub> - A<sub>6</sub>| = 4
|A<sub>5</sub> - A<sub>6</sub>| = 1
Value = 8 + 8 + 4 + 4 + 1 = 25
For all other i, give values less than 25., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL);
#define int long long
#define pb push_back
#define ff first
#define ss second
#define endl '\n'
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
using T = pair<int, int>;
typedef long double ld;
const int mod = 1e9 + 7;
const int INF = 2e9;
void solve(){
int n;
cin >> n;
vector<int> a(n + 1);
for(int i = 1; i <= n; i++) cin >> a[i];
sort(a.begin(), a.end());
vector<int> pre(n + 1);
for(int i = 1; i <= n; i++){
pre[i] = pre[i - 1] + a[i];
}
int ans = 0;
for(int i = 1; i <= n; i++){
ans = max(ans, (pre[n] - pre[i]) - ((n - i) * (a[i])) + ((i-1)* a[i]) - pre[i - 1]);
}
cout << ans;
}
signed main(){
fast
int t = 1;
// cin >> t;
for(int i = 1; i <= t; i++){
solve();
if(i != t) cout << endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given number N, Consider a table of N X N in which elements at the intersection of ith row and jth column are the product of i and j, i. e i x j.
Also given a positive integer X. Your task is to count the number of elements in the table that contain the integer X.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>OccurenceOfX()</b> that takes the integer N and the integer X as parameter.
Constraints:-
1 <= N <= 10^5
1 <= X <= 10^9Return the count of X.Sample Input:-
5 5
Sample Output:-
2
Explanation:-
table :-
1 2 3 4 5
2 4 6 8 10
3 6 9 12 15
4 8 12 16 20
5 10 15 20 25
Count of occurrence of X is :- 2
Sample Input:-
10 13
Sample Output:-
0, I have written this Solution Code: def OccurenceOfX(N,X):
cnt=0
for i in range(1, N+1):
if(X%i==0 and X/i<=N):
cnt=cnt+1
return cnt, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given number N, Consider a table of N X N in which elements at the intersection of ith row and jth column are the product of i and j, i. e i x j.
Also given a positive integer X. Your task is to count the number of elements in the table that contain the integer X.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>OccurenceOfX()</b> that takes the integer N and the integer X as parameter.
Constraints:-
1 <= N <= 10^5
1 <= X <= 10^9Return the count of X.Sample Input:-
5 5
Sample Output:-
2
Explanation:-
table :-
1 2 3 4 5
2 4 6 8 10
3 6 9 12 15
4 8 12 16 20
5 10 15 20 25
Count of occurrence of X is :- 2
Sample Input:-
10 13
Sample Output:-
0, I have written this Solution Code:
int OccurenceOfX(int N,long X){
int cnt=0,i;
for( i=1;i<=N;i++){
if(X%i==0 && X/i<=N){cnt++;}}
return cnt;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given number N, Consider a table of N X N in which elements at the intersection of ith row and jth column are the product of i and j, i. e i x j.
Also given a positive integer X. Your task is to count the number of elements in the table that contain the integer X.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>OccurenceOfX()</b> that takes the integer N and the integer X as parameter.
Constraints:-
1 <= N <= 10^5
1 <= X <= 10^9Return the count of X.Sample Input:-
5 5
Sample Output:-
2
Explanation:-
table :-
1 2 3 4 5
2 4 6 8 10
3 6 9 12 15
4 8 12 16 20
5 10 15 20 25
Count of occurrence of X is :- 2
Sample Input:-
10 13
Sample Output:-
0, I have written this Solution Code:
int OccurenceOfX(int N,long X){
int cnt=0,i;
for( i=1;i<=N;i++){
if(X%i==0 && X/i<=N){cnt++;}}
return cnt;
}
int main()
{
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given number N, Consider a table of N X N in which elements at the intersection of ith row and jth column are the product of i and j, i. e i x j.
Also given a positive integer X. Your task is to count the number of elements in the table that contain the integer X.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>OccurenceOfX()</b> that takes the integer N and the integer X as parameter.
Constraints:-
1 <= N <= 10^5
1 <= X <= 10^9Return the count of X.Sample Input:-
5 5
Sample Output:-
2
Explanation:-
table :-
1 2 3 4 5
2 4 6 8 10
3 6 9 12 15
4 8 12 16 20
5 10 15 20 25
Count of occurrence of X is :- 2
Sample Input:-
10 13
Sample Output:-
0, I have written this Solution Code: public static int OccurenceOfX(int N,int X){
int cnt=0,i;
for( i=1;i<=N;i++){
if(X%i==0 && X/i<=N){cnt++;}}
return cnt;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Insertion is a basic but frequently used operation. Arrays in most languages cannnot be dynamically shrinked or expanded. Here, we will work with such arrays and try to insert an element at the end of array.
You are given an array arr. The size of the array is N. You need to insert an element at its end and print this newly modified array.The first line of input contains T denoting the number of testcases.
T testcases follow. Each testcase contains two lines of input.
The first line contains size of the array denoted by N and element to be inserted.
The third line contains N elements separated by spaces.
Constraints:
1 <= T <= 20
2 <= N <= 10000
0 <= element, arri <= 10^6For each testcase, in a new line, print the modified array.Input:
2
5 90
1 2 3 4 5
3 50
1 2 3
Output:
1 2 3 4 5 90
1 2 3 50
Explanation:
Testcase 1: After inserting 90 at end, we have array elements as 1 2 3 4 5 90.
Testcase 2: After inserting 50 at end, we have array elements as 1 2 3 50., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
int main() {
int t;
cin>>t;
while(t--) {
long int n, el;
cin>>n>>el;
long int arr[n+1];
for(long int i=0; i<n; i++) {
cin>>arr[i];
}
arr[n] = el;
for(long int i=0; i<=n; i++) {
cout<<arr[i];
if (i != n) {
cout<<" ";
}
else if(t != 0) {
cout<<endl;
}
}
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Insertion is a basic but frequently used operation. Arrays in most languages cannnot be dynamically shrinked or expanded. Here, we will work with such arrays and try to insert an element at the end of array.
You are given an array arr. The size of the array is N. You need to insert an element at its end and print this newly modified array.The first line of input contains T denoting the number of testcases.
T testcases follow. Each testcase contains two lines of input.
The first line contains size of the array denoted by N and element to be inserted.
The third line contains N elements separated by spaces.
Constraints:
1 <= T <= 20
2 <= N <= 10000
0 <= element, arri <= 10^6For each testcase, in a new line, print the modified array.Input:
2
5 90
1 2 3 4 5
3 50
1 2 3
Output:
1 2 3 4 5 90
1 2 3 50
Explanation:
Testcase 1: After inserting 90 at end, we have array elements as 1 2 3 4 5 90.
Testcase 2: After inserting 50 at end, we have array elements as 1 2 3 50., I have written this Solution Code: t=int(input())
while t>0:
t-=1
li = list(map(int,input().strip().split()))
n=li[0]
num=li[1]
a= list(map(int,input().strip().split()))
a.insert(len(a),num)
for i in a:
print(i,end=" ")
print(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Insertion is a basic but frequently used operation. Arrays in most languages cannnot be dynamically shrinked or expanded. Here, we will work with such arrays and try to insert an element at the end of array.
You are given an array arr. The size of the array is N. You need to insert an element at its end and print this newly modified array.The first line of input contains T denoting the number of testcases.
T testcases follow. Each testcase contains two lines of input.
The first line contains size of the array denoted by N and element to be inserted.
The third line contains N elements separated by spaces.
Constraints:
1 <= T <= 20
2 <= N <= 10000
0 <= element, arri <= 10^6For each testcase, in a new line, print the modified array.Input:
2
5 90
1 2 3 4 5
3 50
1 2 3
Output:
1 2 3 4 5 90
1 2 3 50
Explanation:
Testcase 1: After inserting 90 at end, we have array elements as 1 2 3 4 5 90.
Testcase 2: After inserting 50 at end, we have array elements as 1 2 3 50., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n =Integer.parseInt(br.readLine().trim());
while(n-->0){
String str[]=br.readLine().trim().split(" ");
String newel =br.readLine().trim()+" "+str[1];
System.out.println(newel);
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a binary array A[] of size N. The task is to arrange an array in increasing order.
(O(N) time complexity solution)Every test case contains two lines, first line contains an integer N (size of array) and second line contains space separated elements of array.
1 <= N <= 20
0 <= A[i] <= 1Print a single line containing space separated elements of sorted arrays.Input:
5
1 0 1 1 0
Output:
0 0 1 1 1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void cal(int arr[], int n){
int countZ = 0;
for(int i = 0; i < n; i++) {
if(arr[i] == 0) {
countZ++;
}
}
for(int i = 1; i <= countZ; i++) {
System.out.print("0 ");
}
for(int i = 1; i <= n - countZ; i++) {
System.out.print("1 ");
}
}
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String nD = br.readLine();
String nDArr[] = nD.split(" ");
int n = Integer.parseInt(nDArr[0]);
int arr[]= new int[n];
String input = br.readLine();
String sar[] = input.split(" ");
for(int i = 0; i < n; i++){
arr[i] = Integer.parseInt(sar[i]);
}
cal(arr, n);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a binary array A[] of size N. The task is to arrange an array in increasing order.
(O(N) time complexity solution)Every test case contains two lines, first line contains an integer N (size of array) and second line contains space separated elements of array.
1 <= N <= 20
0 <= A[i] <= 1Print a single line containing space separated elements of sorted arrays.Input:
5
1 0 1 1 0
Output:
0 0 1 1 1, I have written this Solution Code: n = int(input())
l = list(map(int, input().split()))
l = sorted(l)
for i in l:
print(i, end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a binary array A[] of size N. The task is to arrange an array in increasing order.
(O(N) time complexity solution)Every test case contains two lines, first line contains an integer N (size of array) and second line contains space separated elements of array.
1 <= N <= 20
0 <= A[i] <= 1Print a single line containing space separated elements of sorted arrays.Input:
5
1 0 1 1 0
Output:
0 0 1 1 1, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int n; cin >> n;
int a[2] = {0};
for(int i = 1; i <= n; i++){
int p; cin >> p;
a[p]++;
}
for(int i = 0; i <= 1; i++)
for(int j = 0; j < a[i]; j++)
cout << i << " ";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number, you task is to reverse its digits. If the reversed number contains 0s in the beginning, you must remove them as well.First line consists of a single integer denoting n.
Constraint:-
1<=size of n<=100Output is a single line containing reversed number n.Sample Input
123445
Sample Output
544321
Sample Input
16724368
Sample Output
86342761, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String str=br.readLine();
int i=str.length()-1;
if(i==0){
int number=Integer.parseInt(str);
System.out.println(number);
}else{
while(str.charAt(i)=='0'){
i--;
}
for(int j=i;j>=0;j--){
System.out.print(str.charAt(j));
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number, you task is to reverse its digits. If the reversed number contains 0s in the beginning, you must remove them as well.First line consists of a single integer denoting n.
Constraint:-
1<=size of n<=100Output is a single line containing reversed number n.Sample Input
123445
Sample Output
544321
Sample Input
16724368
Sample Output
86342761, I have written this Solution Code: n=int(input())
def reverse(n):
return int(str(n)[::-1])
print(reverse(n)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number, you task is to reverse its digits. If the reversed number contains 0s in the beginning, you must remove them as well.First line consists of a single integer denoting n.
Constraint:-
1<=size of n<=100Output is a single line containing reversed number n.Sample Input
123445
Sample Output
544321
Sample Input
16724368
Sample Output
86342761, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin>>s;
reverse(s.begin(),s.end());
int I;
for( I=0;I<s.length();I++){
if(s[I]!='0'){break;}
}
if(I==s.length()){cout<<0;return 0;}
for(int j=I;j<s.length();j++){
cout<<s[j];}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, you need to check whether the given number is <b>Palindrome</b> or not. A number is said to be Palindrome when it reads the same from backward as forward.User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>isPalindrome()</b> which contains N as a parameter.
<b>Constraints:</b>
1 <= N <= 9999You need to return "true" is the number is palindrome otherwise "false".Sample Input:
5
Sample Output:
true
Sample Input:
121
Sample Output:
true, I have written this Solution Code: static boolean isPalindrome(int N)
{
int sum = 0;
int rev = N;
while(N > 0)
{
int digit = N%10;
sum = sum*10+digit;
N = N/10;
}
if(rev == sum)
return true;
else return false;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, you need to check whether the given number is <b>Palindrome</b> or not. A number is said to be Palindrome when it reads the same from backward as forward.User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>isPalindrome()</b> which contains N as a parameter.
<b>Constraints:</b>
1 <= N <= 9999You need to return "true" is the number is palindrome otherwise "false".Sample Input:
5
Sample Output:
true
Sample Input:
121
Sample Output:
true, I have written this Solution Code: def isPalindrome(N):
sum1 = 0
rev = N
while(N > 0):
digit = N%10
sum1 = sum1*10+digit
N = N//10
if(rev == sum1):
return True
return False, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ronaldo has challenged Messi to beat his team in the upcoming “Friendly” fixture. But both these legends are tired of the original football rules, so they decided to play Football with a twist. Each player is assigned an ID, from 1 to 10^6. Initially Ronaldo has the ball in his posession. Given a sequence of N passes, help Messi Know which ID player has the ball, after N passes.
Note: Passes are of two types :
i) P ID, which means the player currently having the ball passes it to Player with identity ID.
ii) B, which means the player currently having the ball passes it back to the Player he got the Pass From.
Also, It is guaranteed that the given order of passes will be a valid order.The first line of input contains number of testcases T. The 1st line of each testcase, contains two integers, N and ID1, denoting the total number of passes and the ID of Ronaldo. Respectively. Each of the next N lines, contains the information of a Pass which can be either of the above two types, i.e:
1) P ID
2) B
Constraints
1 <= T <= 100
1 <= N <= 10^5
1 <= IDs <= 10^6
Sum of N for every test case is less than 10^6For each testcase you need to print the ID of the Player having the ball after N passes.Input :
2
3 1
P 13
P 14
B
5 1
P 12
P 13
P 14
B
B
Output :
13
14
Explanation :
Testcase 1: Initially, the ball is with Ronaldo, having ID 1.
In the first pass, he passes the ball to Player with ID 13.
In the Second Pass, the player currently having the ball, ie Player with ID 13, passes it to player with ID 14.
In the last pass the player currently having the ball, ie Player with ID 14 passed the ball back to the player from whom he got the Pass, i.e the ball is passed back to Player with Player ID 13, as Player ID 13 had passed the ball to player ID 14 in the previous pass.
Testcase 2: Initially, the ball is with Ronaldo, having ID 1.
In the first pass he passes the ball to player with ID 12.
In the second pass, the second player passes the ball to palyer with ID 13, again the player with ID 13 passes the ball to player with ID 14.
Now, player with ID 14 passed back the ball to 13, and again 13 passes back the ball to 14., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(br.readLine().trim());
while (t-- > 0) {
String[] line = br.readLine().trim().split(" ");
int n = Integer.parseInt(line[0]);
int curr = Integer.parseInt(line[1]);
int prev = curr;
while (n-- > 0) {
String[] currLine = br.readLine().trim().split(" ");
if (currLine[0].equals("P")) {
prev = curr;
curr = Integer.parseInt(currLine[1]);
}
if (currLine[0].equals("B")) {
int temp = curr;
curr = prev;
prev = temp;
}
}
System.out.println(curr);
System.gc();
}
br.close();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ronaldo has challenged Messi to beat his team in the upcoming “Friendly” fixture. But both these legends are tired of the original football rules, so they decided to play Football with a twist. Each player is assigned an ID, from 1 to 10^6. Initially Ronaldo has the ball in his posession. Given a sequence of N passes, help Messi Know which ID player has the ball, after N passes.
Note: Passes are of two types :
i) P ID, which means the player currently having the ball passes it to Player with identity ID.
ii) B, which means the player currently having the ball passes it back to the Player he got the Pass From.
Also, It is guaranteed that the given order of passes will be a valid order.The first line of input contains number of testcases T. The 1st line of each testcase, contains two integers, N and ID1, denoting the total number of passes and the ID of Ronaldo. Respectively. Each of the next N lines, contains the information of a Pass which can be either of the above two types, i.e:
1) P ID
2) B
Constraints
1 <= T <= 100
1 <= N <= 10^5
1 <= IDs <= 10^6
Sum of N for every test case is less than 10^6For each testcase you need to print the ID of the Player having the ball after N passes.Input :
2
3 1
P 13
P 14
B
5 1
P 12
P 13
P 14
B
B
Output :
13
14
Explanation :
Testcase 1: Initially, the ball is with Ronaldo, having ID 1.
In the first pass, he passes the ball to Player with ID 13.
In the Second Pass, the player currently having the ball, ie Player with ID 13, passes it to player with ID 14.
In the last pass the player currently having the ball, ie Player with ID 14 passed the ball back to the player from whom he got the Pass, i.e the ball is passed back to Player with Player ID 13, as Player ID 13 had passed the ball to player ID 14 in the previous pass.
Testcase 2: Initially, the ball is with Ronaldo, having ID 1.
In the first pass he passes the ball to player with ID 12.
In the second pass, the second player passes the ball to palyer with ID 13, again the player with ID 13 passes the ball to player with ID 14.
Now, player with ID 14 passed back the ball to 13, and again 13 passes back the ball to 14., I have written this Solution Code: for i in range(int(input())):
N, ID = map(int,input().split())
pre = 0
for i in range(N):
arr = input().split()
if len(arr)==2:
pre,ID = ID,arr[1]
else:
ID,pre = pre,ID
print(ID) if pre else print(0), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ronaldo has challenged Messi to beat his team in the upcoming “Friendly” fixture. But both these legends are tired of the original football rules, so they decided to play Football with a twist. Each player is assigned an ID, from 1 to 10^6. Initially Ronaldo has the ball in his posession. Given a sequence of N passes, help Messi Know which ID player has the ball, after N passes.
Note: Passes are of two types :
i) P ID, which means the player currently having the ball passes it to Player with identity ID.
ii) B, which means the player currently having the ball passes it back to the Player he got the Pass From.
Also, It is guaranteed that the given order of passes will be a valid order.The first line of input contains number of testcases T. The 1st line of each testcase, contains two integers, N and ID1, denoting the total number of passes and the ID of Ronaldo. Respectively. Each of the next N lines, contains the information of a Pass which can be either of the above two types, i.e:
1) P ID
2) B
Constraints
1 <= T <= 100
1 <= N <= 10^5
1 <= IDs <= 10^6
Sum of N for every test case is less than 10^6For each testcase you need to print the ID of the Player having the ball after N passes.Input :
2
3 1
P 13
P 14
B
5 1
P 12
P 13
P 14
B
B
Output :
13
14
Explanation :
Testcase 1: Initially, the ball is with Ronaldo, having ID 1.
In the first pass, he passes the ball to Player with ID 13.
In the Second Pass, the player currently having the ball, ie Player with ID 13, passes it to player with ID 14.
In the last pass the player currently having the ball, ie Player with ID 14 passed the ball back to the player from whom he got the Pass, i.e the ball is passed back to Player with Player ID 13, as Player ID 13 had passed the ball to player ID 14 in the previous pass.
Testcase 2: Initially, the ball is with Ronaldo, having ID 1.
In the first pass he passes the ball to player with ID 12.
In the second pass, the second player passes the ball to palyer with ID 13, again the player with ID 13 passes the ball to player with ID 14.
Now, player with ID 14 passed back the ball to 13, and again 13 passes back the ball to 14., I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n, id; cin >> n >> id;
int pre = 0, cur = id;
for(int i = 1; i <= n; i++){
char c; cin >> c;
if(c == 'P'){
int x; cin >> x;
pre = cur;
cur = x;
}
else{
swap(pre, cur);
}
}
cout << cur << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N containing non-negative integers. You have to move all 0's to the end of array while maintaining the relative order of the non-zero elements.
Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.The first line of input line contains T, denoting the number of testcases. Each test cases contains 2 lines. First-line contains N, size of array. Second-line contains elements of array separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^5
1 <= A[i] <= 10^5
<b>Sum of N over all testcases does not exceed 10^6</b>
For each testcase you need to print the updated array.Sample Input:
2
5
0 1 0 3 12
8
0 0 0 0 1 2 3 4
Sample Output:
1 3 12 0 0
1 2 3 4 0 0 0 0, I have written this Solution Code:
import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int t;
t=sc.nextInt();
while(t-->0){
int n=sc.nextInt();
int a[] = new int[n];
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
int j=-1;
for(int i=0;i<n;i++){
if(a[i]==0 && j==-1){
j=i;
}
if(j!=-1 && a[i]!=0){
a[j]=a[i];
a[i]=0;
j++;
}
}
for(int i=0;i<n;i++){
System.out.print(a[i]+" ");
}
System.out.println();
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N containing non-negative integers. You have to move all 0's to the end of array while maintaining the relative order of the non-zero elements.
Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.The first line of input line contains T, denoting the number of testcases. Each test cases contains 2 lines. First-line contains N, size of array. Second-line contains elements of array separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^5
1 <= A[i] <= 10^5
<b>Sum of N over all testcases does not exceed 10^6</b>
For each testcase you need to print the updated array.Sample Input:
2
5
0 1 0 3 12
8
0 0 0 0 1 2 3 4
Sample Output:
1 3 12 0 0
1 2 3 4 0 0 0 0, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int t;
cin>>t;
while(t--){
int n,k;
cin>>n;
int a[n];
int cnt=0;
for(int i=0;i<n;i++){
cin>>a[i];\
if(a[i]==0){cnt++;}
}
for(int i=0;i<n;i++){
if(a[i]!=0){
cout<<a[i]<<" ";
}
}
while(cnt--){
cout<<0<<" ";
}
cout<<endl;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a rule in ludo that a token can only be unlocked when either a 1 or 6 shown in the die. Given the die number N, Your task is to check whether the token can be unlocked or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>ludo()</b> that takes integers N as argument.
Constraints:-
1 <= N <= 6Return 1 if the token can be unlocked else return 0.Sample Input:-
1
Sample Output:-
1
Sample Input:-
2
Sample Output:-
0, I have written this Solution Code: int ludo(int N){
return (N==1||N==6);
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a rule in ludo that a token can only be unlocked when either a 1 or 6 shown in the die. Given the die number N, Your task is to check whether the token can be unlocked or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>ludo()</b> that takes integers N as argument.
Constraints:-
1 <= N <= 6Return 1 if the token can be unlocked else return 0.Sample Input:-
1
Sample Output:-
1
Sample Input:-
2
Sample Output:-
0, I have written this Solution Code: def ludo(N):
if N==1 or N==6:
return 1
return 0
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a rule in ludo that a token can only be unlocked when either a 1 or 6 shown in the die. Given the die number N, Your task is to check whether the token can be unlocked or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>ludo()</b> that takes integers N as argument.
Constraints:-
1 <= N <= 6Return 1 if the token can be unlocked else return 0.Sample Input:-
1
Sample Output:-
1
Sample Input:-
2
Sample Output:-
0, I have written this Solution Code:
int ludo(int N){
return (N==1||N==6);
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a rule in ludo that a token can only be unlocked when either a 1 or 6 shown in the die. Given the die number N, Your task is to check whether the token can be unlocked or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>ludo()</b> that takes integers N as argument.
Constraints:-
1 <= N <= 6Return 1 if the token can be unlocked else return 0.Sample Input:-
1
Sample Output:-
1
Sample Input:-
2
Sample Output:-
0, I have written this Solution Code: static int ludo(int N){
if(N==1 || N==6){return 1;}
return 0;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array A of size N of non-negative integers, find a continuous sub-array which adds to a given number S.Each test case consists of two lines. The first line of each test case is N and S, where N is the size of the array and S is the sum. The second line of each test case contains N space-separated integers denoting the array elements.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Ai ≤ 10<sup>5</sup>Print the starting and ending positions (1 indexing) of first such occurring subarray from the left if sum equals to subarray, else print -1.Sample Input
5 12
1 2 3 7 5
Sample Output
2 4
Explanation:
subarray starting from index 2 and ending at index 4 => {2 , 3 , 7}
sum = 2 + 3 + 7 = 12
Sample Input
10 15
1 2 3 4 5 6 7 8 9 10
Sample Output
1 5, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException
{
try{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String StrInput[] = br.readLine().trim().split(" ");
int n = Integer.parseInt(StrInput[0]);
int s = Integer.parseInt(StrInput[1]);
int arr[] = new int[n];
String StrInput2[] = br.readLine().trim().split(" ");
for(int i=0;i<n;i++)
{
arr[i] = Integer.parseInt(StrInput2[i]);
}
int sum = arr[0];
int startingindex = 0;
int endingindex = 1;
int j = 0;
int i;
for(i=1;i<=n;i++)
{
if(sum < s && arr[i] != 0)
{
sum += arr[i];
}
while(sum > s && startingindex < i-1)
{
sum -= arr[startingindex];
startingindex++;
}
if(sum == s)
{
endingindex = i+1;
if(arr[0] == 0)
{
System.out.print(startingindex+2 + " " + endingindex);
}
else
{
System.out.print(startingindex+1 + " "+ endingindex);
}
break;
}
if(i == n && sum < s)
{
System.out.print(-1);
break;
}
}
}
catch(Exception e)
{
System.out.print(-1);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array A of size N of non-negative integers, find a continuous sub-array which adds to a given number S.Each test case consists of two lines. The first line of each test case is N and S, where N is the size of the array and S is the sum. The second line of each test case contains N space-separated integers denoting the array elements.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Ai ≤ 10<sup>5</sup>Print the starting and ending positions (1 indexing) of first such occurring subarray from the left if sum equals to subarray, else print -1.Sample Input
5 12
1 2 3 7 5
Sample Output
2 4
Explanation:
subarray starting from index 2 and ending at index 4 => {2 , 3 , 7}
sum = 2 + 3 + 7 = 12
Sample Input
10 15
1 2 3 4 5 6 7 8 9 10
Sample Output
1 5, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int n,k;
cin>>n>>k;
int a[n];
for(int i=0;i<n;i++)
{
cin>>a[i];
}
int sum=0;
unordered_map<int,int> m;
for(int i=0;i<n;i++){
sum+=a[i];
if(sum==k){cout<<1<<" "<<i+1;return 0;}
if(m.find(sum-k)!=m.end()){
cout<<m[sum-k]+2<<" "<<i+1;
return 0;
}
m[sum]=i;
}
cout<<-1;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an unsorted array A of size N of non-negative integers, find a continuous sub-array which adds to a given number S.Each test case consists of two lines. The first line of each test case is N and S, where N is the size of the array and S is the sum. The second line of each test case contains N space-separated integers denoting the array elements.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Ai ≤ 10<sup>5</sup>Print the starting and ending positions (1 indexing) of first such occurring subarray from the left if sum equals to subarray, else print -1.Sample Input
5 12
1 2 3 7 5
Sample Output
2 4
Explanation:
subarray starting from index 2 and ending at index 4 => {2 , 3 , 7}
sum = 2 + 3 + 7 = 12
Sample Input
10 15
1 2 3 4 5 6 7 8 9 10
Sample Output
1 5, I have written this Solution Code: def sumFinder(N,S,a):
currentSum = a[0]
start = 0
i = 1
while i <= N:
while currentSum > S and start < i-1:
currentSum = currentSum - a[start]
start += 1
if currentSum == S:
return (start+1,i)
if i < N:
currentSum = currentSum + a[i]
i += 1
return(-1)
N, S = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
ans = sumFinder(N,S,a)
if(ans==-1):
print(ans)
else:
print(ans[0],ans[1]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array Arr of N distinct integers. Find the number of ways to divide the array into some subarrays such that:
> All elements must be in exactly one subarray
> All the subarrays have strictly increasing values
> For any subarray S1 that ends before subarray S2, length of S1 >= length of S2
> For any subarray S1 that ends before subarray S2, S1 should be lexographically smaller than S2
As the number of ways can be huge print answer modulo 1000000007.First line of input contains a single integer N.
Second line contains N integers, denoting array Arr.
Constraints:
1 <= N <= 1000
1 <= Arr[i] <= 1000Print the answer modulo 1000000007.Sample Input
4
1 3 2 4
Sample Output
2
Explanation:
Division 1: (1, 3) (2) (4)
Lengths of subarrays: 2 1 1 (non increasing)
Subarray (1, 3) is lexographically smaller than (2) which is lexographically is smaller (4)
Division 2: (1, 3) (2, 4)
Lengths of subarrays: 2 2 (non increasing)
Subarray (1, 3) is lexographically smaller than (2, 4)., I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
using namespace std;
const int lb = 17;
long long f[1010][1010];
int a[1010];
int g[1010][1010], mx[1010];
signed main() {
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n;
cin>>n;
int mo=1000000007;
for(int i=0;i<n;++i)
cin>>a[i];
for (int i = n; i >= 0; i--)
for (int j = n; j >= 0; j--)
if (i == n || j == n) g[i][j] = 0; else
if (a[i] < a[j]) g[i][j] = g[i + 1][j + 1] + 1;
else g[i][j] = 0;
mx[n] = 0;
mx[n - 1] = 1;
for (int i = n - 2; i >= 0; i--)
if (a[i] < a[i + 1]) mx[i] = mx[i + 1] + 1;
else mx[i] = 1;
for (int i = 0; i <= n; i++)
for (int j = 0; j <= n; j++) f[i][j]= 0;
f[0][mx[0] - 1] = 1;
long long ans = 0;
for (int i = 0; i < n; i++) {
ans += f[i][n - 1];
ans%=mo;
for (int j = n - 2; j >= i; j--) {
f[i][j] += f[i][j + 1];
f[i][j]%=mo;
int k = g[i][j + 1];
if (k > mx[j + 1]) k = mx[j + 1];
if (k > j - i + 1) k = j - i + 1;
if (k > 0) {
f[j + 1][j + k] += f[i][j];
f[j + 1][j + k]%=mo;
}
}
}
cout<<ans;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram has a military dog who has the special ability of hearing, He can hear frequencies starting from 70Hz to 44000Hz (both inclusive). Now Ram wants to detect some unusual sounds across him. Tell "Yes" or "No" whether his dog can detect the sound or not.First line of the input contains the value of Test cases T.
Each test case consists of a single integer X - the frequency of unusual sound in Hertz.
<b>Constraints</b>
1 ≤ T ≤ 10<sup>4</sup>
1 ≤ X ≤ 10<sup>5</sup>Print Yes or No wether his dog can detect them or not for each test case.Sample Input
3
21
453
45000
Sample Output
No
Yes
No, I have written this Solution Code: /**
* author: tourist1256
* created: 2022-09-20 14:02:39
**/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template <class key, class value, class cmp = std::less<key>>
using ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>;
// find_by_order(k) returns iterator to kth element starting from 0;
// order_of_key(k) returns count of elements strictly smaller than k;
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
#define int long long
#define yn(ans) printf("%s\n", (ans) ? "Yes" : "No");
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
inline int64_t random_long(int l = LLONG_MIN, int r = LLONG_MAX) {
uniform_int_distribution<int64_t> generator(l, r);
return generator(rng);
}
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
auto start = std::chrono::high_resolution_clock::now();
int tt;
cin >> tt;
while (tt--) {
int N;
cin >> N;
yn(N >= 70 && N <= 44000);
}
auto stop = std::chrono::high_resolution_clock::now();
auto duration = std::chrono::duration_cast<std::chrono::nanoseconds>(stop - start);
cerr << "Time taken : " << ((long double)duration.count()) / ((long double)1e9) << "s " << endl;
return 0;
};
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram has a military dog who has the special ability of hearing, He can hear frequencies starting from 70Hz to 44000Hz (both inclusive). Now Ram wants to detect some unusual sounds across him. Tell "Yes" or "No" whether his dog can detect the sound or not.First line of the input contains the value of Test cases T.
Each test case consists of a single integer X - the frequency of unusual sound in Hertz.
<b>Constraints</b>
1 ≤ T ≤ 10<sup>4</sup>
1 ≤ X ≤ 10<sup>5</sup>Print Yes or No wether his dog can detect them or not for each test case.Sample Input
3
21
453
45000
Sample Output
No
Yes
No, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner s=new Scanner(System.in);
int t=s.nextInt();
while(t>0){
int x=s.nextInt();
boolean flag=false;
for(int i=70;i<=44000;i++){
if(x==i){
flag=true;
}
}
if(flag){
System.out.println("Yes");
}
else{
System.out.println("No");
}
t--;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram has a military dog who has the special ability of hearing, He can hear frequencies starting from 70Hz to 44000Hz (both inclusive). Now Ram wants to detect some unusual sounds across him. Tell "Yes" or "No" whether his dog can detect the sound or not.First line of the input contains the value of Test cases T.
Each test case consists of a single integer X - the frequency of unusual sound in Hertz.
<b>Constraints</b>
1 ≤ T ≤ 10<sup>4</sup>
1 ≤ X ≤ 10<sup>5</sup>Print Yes or No wether his dog can detect them or not for each test case.Sample Input
3
21
453
45000
Sample Output
No
Yes
No, I have written this Solution Code: T = int(input())
for i in range(T):
X = int(input())
if X>=70 and X<=44000:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers N and D, your task is to find the numbers between 1 to N which contains the digit D at least 1 time.Input contains only two integers N and D.
Constraints:-
1 < = N < = 100000
1 < = D < = 9Print all the numbers from 1 to N which contains the digit D in it separated by space in non decreasing order.Sample Input:-
20 5
Sample Output:-
5 15
Sample Input:-
15 1
Sample Output:-
1 10 11 12 13 14 15, I have written this Solution Code: /**
* author: tourist1256
* created: 2022-07-08 04:16:54
**/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template <class key, class value, class cmp = std::less<key>>
using ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>;
// find_by_order(k) returns iterator to kth element starting from 0;
// order_of_key(k) returns count of elements strictly smaller than k;
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
#define int long long
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
inline int64_t random_long(int l = LLONG_MIN, int r = LLONG_MAX) {
uniform_int_distribution<int64_t> generator(l, r);
return generator(rng);
}
int32_t main() {
auto start = std::chrono::high_resolution_clock::now();
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, d;
cin >> n >> d;
int cnt = 0;
function<int(int, int)> f = [&](int d, int m) {
while (d) {
int x = d % 10;
d /= 10;
if (x == m) {
return 1;
}
}
return 0;
};
for (int i = 1; i <= n; i++) {
if (f(i, d)) {
cout << i << " ";
}
}
auto stop = std::chrono::high_resolution_clock::now();
auto duration = std::chrono::duration_cast<std::chrono::nanoseconds>(stop - start);
cerr << "Time taken : " << ((long double)duration.count()) / ((long double)1e9) << "s\n";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers N and D, your task is to find the numbers between 1 to N which contains the digit D at least 1 time.Input contains only two integers N and D.
Constraints:-
1 < = N < = 100000
1 < = D < = 9Print all the numbers from 1 to N which contains the digit D in it separated by space in non decreasing order.Sample Input:-
20 5
Sample Output:-
5 15
Sample Input:-
15 1
Sample Output:-
1 10 11 12 13 14 15, I have written this Solution Code: def index(st, ch):
for i in range(len(st)):
if (st[i] == ch):
return i;
return -1
def printNumbers(n, d):
# Converting d to character
st = "" + str(d)
ch = st[0]
l = []
# Loop to check each digit one by one.
for i in range(0, n + 1, 1):
# initialize the string
st = ""
st = st + str(i)
# checking for digit
if (i == d or index(st, ch) >= 0):
# print(i, end = " ")
l.append(i)
for k in range(0, len(l) - 1):
print(l[k], end=" ")
print(l[len(l) - 1])
# Driver code
if __name__ == '__main__':
li = list(map(int, input().strip().split()))
n = li[0]
d = li[1]
printNumbers(n, d), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers N and D, your task is to find the numbers between 1 to N which contains the digit D at least 1 time.Input contains only two integers N and D.
Constraints:-
1 < = N < = 100000
1 < = D < = 9Print all the numbers from 1 to N which contains the digit D in it separated by space in non decreasing order.Sample Input:-
20 5
Sample Output:-
5 15
Sample Input:-
15 1
Sample Output:-
1 10 11 12 13 14 15, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int d=sc.nextInt();
printnumber(n,d);
}
static boolean ispresent(int n,int d){
while(n>0){
if(n%10==d)
break;
n=n / 10;
}
return n>0;
}
static void printnumber(int n,int d){
for(int i=0;i<=n;i++){
if(i==d||ispresent(i,d)){
System.out.print(i+" ");
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara does not like strings which have both the uppercase and the lowercase characters. She thinks only those strings are good which have only lowercase characters(a-z) or only uppercase characters(A-Z).
Given a string s consisting of english alphabets. Find the minimum number of operations required to make it good.
In one operation you can choose any character of the string and change it into uppercase or lowercase.Input contains a single line containing the string s.
Constraint:-
1<=|s|<=100Print the minimum number of operation required to make the string good.Sample Input:
Sara
Sample Output:
1
Explanation:-
'S' should be converted to 's' respectively
Sample Input:
HELLO
Sample Output:-
0
Sample Input:-
pEOpLE
Sample Output:-
2
, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String args[])throws Exception
{
BufferedReader br =new BufferedReader(new InputStreamReader(System.in));
String name=br.readLine();
int lower=0;
int uper=0;
for(int i=0;i<name.length();i++)
{
Character ch=name.charAt(i);
if (ch >= 'a' && ch <= 'z')
{
lower++;
}
else if(ch>='A' && ch <='Z')
{
uper++;
}
}
if(lower<uper)
{
System.out.print(lower);
}
else
{
System.out.print(uper);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara does not like strings which have both the uppercase and the lowercase characters. She thinks only those strings are good which have only lowercase characters(a-z) or only uppercase characters(A-Z).
Given a string s consisting of english alphabets. Find the minimum number of operations required to make it good.
In one operation you can choose any character of the string and change it into uppercase or lowercase.Input contains a single line containing the string s.
Constraint:-
1<=|s|<=100Print the minimum number of operation required to make the string good.Sample Input:
Sara
Sample Output:
1
Explanation:-
'S' should be converted to 's' respectively
Sample Input:
HELLO
Sample Output:-
0
Sample Input:-
pEOpLE
Sample Output:-
2
, I have written this Solution Code: n = input()
smallAlphabets = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
bigAlphabets = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
count = 0
count1 = 0
for i in n:
if i in smallAlphabets:
count += 1
if i in bigAlphabets:
count1 += 1
if count < count1:
print(count)
else:
print(count1), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara does not like strings which have both the uppercase and the lowercase characters. She thinks only those strings are good which have only lowercase characters(a-z) or only uppercase characters(A-Z).
Given a string s consisting of english alphabets. Find the minimum number of operations required to make it good.
In one operation you can choose any character of the string and change it into uppercase or lowercase.Input contains a single line containing the string s.
Constraint:-
1<=|s|<=100Print the minimum number of operation required to make the string good.Sample Input:
Sara
Sample Output:
1
Explanation:-
'S' should be converted to 's' respectively
Sample Input:
HELLO
Sample Output:-
0
Sample Input:-
pEOpLE
Sample Output:-
2
, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int x=0,y=0;
string s;
cin>>s;
for(int i=0;i<s.length();i++){
if(s[i]<'a'){x++;}
}
cout<<min(x,(int)s.length()-x);
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Everyone has heard of palindromes, right! A palindrome is a string that remains the same if reversed.
Let's define a new term, Dalindrome.
A Dalindrome is a string whose atleast one of the substrings is a palindrome.
Given a string, find whether it's a Dalindrome.The only line of input contains a string to be checked.
Constraints
1 <= length of string <= 100Output "Yes" if string is a Dalindrome, else output "No".Sample Input
cbabcc
Sample Output
Yes
Explanation: "bab" is one of the substrings of the string that is a palindrome. There may be other substrings that are palindrome as well like "cc", or "cbabc". The question requires atleast one., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
System.out.println("Yes");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Everyone has heard of palindromes, right! A palindrome is a string that remains the same if reversed.
Let's define a new term, Dalindrome.
A Dalindrome is a string whose atleast one of the substrings is a palindrome.
Given a string, find whether it's a Dalindrome.The only line of input contains a string to be checked.
Constraints
1 <= length of string <= 100Output "Yes" if string is a Dalindrome, else output "No".Sample Input
cbabcc
Sample Output
Yes
Explanation: "bab" is one of the substrings of the string that is a palindrome. There may be other substrings that are palindrome as well like "cc", or "cbabc". The question requires atleast one., I have written this Solution Code: string = str(input())
print("Yes"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Everyone has heard of palindromes, right! A palindrome is a string that remains the same if reversed.
Let's define a new term, Dalindrome.
A Dalindrome is a string whose atleast one of the substrings is a palindrome.
Given a string, find whether it's a Dalindrome.The only line of input contains a string to be checked.
Constraints
1 <= length of string <= 100Output "Yes" if string is a Dalindrome, else output "No".Sample Input
cbabcc
Sample Output
Yes
Explanation: "bab" is one of the substrings of the string that is a palindrome. There may be other substrings that are palindrome as well like "cc", or "cbabc". The question requires atleast one., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(ll i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define int long long
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
typedef vector<int> vi;
#define MOD 1000000007
#define INF 1000000000000000007LL
const int N = 100005;
// it's swapnil07 ;)
#ifdef SWAPNIL07
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
cout << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
int begtime = clock();
#define end_routine() cout << "\n\nTime elapsed: " << (clock() - begtime)*1000/CLOCKS_PER_SEC << " ms\n\n";
#else
#define endl '\n'
#define trace(...)
#define end_routine()
#endif
signed main()
{
fast
#ifdef SWAPNIL07
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
string s; cin>>s;
cout<<"Yes";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a saying in Sara's village that "A number is called prime if the sum of all the factors of N is less than or equal to (3*N)/2 ". Given the number N, your task is to check if it is a myth or a fact for the number given.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>mythOrFact()</b> that takes integer N as argument.
Constraints:-
2 <= N <= 1000Return 1 if it is a fact else return 0.Sample Input:-
2
Sample Output:-
1
Explanation:-
Sum = 2 + 1 = 3
3*(2) / 2 = 3
Sample Input:-
9
Sample Output:-
0, I have written this Solution Code:
int mythOrFact(int N){
int prime =1;
int cnt = N+1;
for(int i=2;i<N;i++){
if(N%i==0){cnt+=i;prime=0;}
}
int p = 3*N;
p/=2;
if((cnt<=p && prime==1) || (cnt>p && prime==0) ){return 1;}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a saying in Sara's village that "A number is called prime if the sum of all the factors of N is less than or equal to (3*N)/2 ". Given the number N, your task is to check if it is a myth or a fact for the number given.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>mythOrFact()</b> that takes integer N as argument.
Constraints:-
2 <= N <= 1000Return 1 if it is a fact else return 0.Sample Input:-
2
Sample Output:-
1
Explanation:-
Sum = 2 + 1 = 3
3*(2) / 2 = 3
Sample Input:-
9
Sample Output:-
0, I have written this Solution Code:
int mythOrFact(int N){
int prime =1;
int cnt = N+1;
for(int i=2;i<N;i++){
if(N%i==0){cnt+=i;prime=0;}
}
int p = 3*N;
p/=2;
if((cnt<=p && prime==1) || (cnt>p && prime==0) ){return 1;}
return 0;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a saying in Sara's village that "A number is called prime if the sum of all the factors of N is less than or equal to (3*N)/2 ". Given the number N, your task is to check if it is a myth or a fact for the number given.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>mythOrFact()</b> that takes integer N as argument.
Constraints:-
2 <= N <= 1000Return 1 if it is a fact else return 0.Sample Input:-
2
Sample Output:-
1
Explanation:-
Sum = 2 + 1 = 3
3*(2) / 2 = 3
Sample Input:-
9
Sample Output:-
0, I have written this Solution Code: static int mythOrFact(int N){
int prime =1;
int cnt = N+1;
for(int i=2;i<N;i++){
if(N%i==0){cnt+=i;prime=0;}
}
int p = 3*N;
p/=2;
if((cnt<=p && prime==1) || (cnt>p && prime==0) ){return 1;}
return 0;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There is a saying in Sara's village that "A number is called prime if the sum of all the factors of N is less than or equal to (3*N)/2 ". Given the number N, your task is to check if it is a myth or a fact for the number given.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>mythOrFact()</b> that takes integer N as argument.
Constraints:-
2 <= N <= 1000Return 1 if it is a fact else return 0.Sample Input:-
2
Sample Output:-
1
Explanation:-
Sum = 2 + 1 = 3
3*(2) / 2 = 3
Sample Input:-
9
Sample Output:-
0, I have written this Solution Code: def mythOrFact(N):
prime=1
cnt=N+1
for i in range (2,N):
if N%i==0:
prime=0
cnt=cnt+i
x = 3*N
x=x//2
if(cnt <= x and prime==1) or (cnt>x and prime==0):
return 1
return 0
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
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