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For this Question: Today is Newton School's first class of this year. Nutan, a student at Newton School, has received his first assignment. He will be given a string as input. His task is to print "Gravity'' if the input is "Apple''; otherwise, he will have to print "Space''.
Can you help Nutan in solving his first assignment? Note that the quotation marks are just for clarity. They are not part of the input string, and should not be a part of your output string.The input consists of a single line that contains a string S (1 ≤ length of S ≤ 10). The string only consists of lowercase and uppercase letters.Print "Gravity'' or "Space'' according to the input.Sample Input 1:
Apple
Sample Output 1:
Gravity
Sample Input 2:
Mango
Sample Output 2:
Space
Sample Input 3:
AppLE
Sample Output 3:
Space, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader()
{
br = new BufferedReader(
new InputStreamReader(System.in));
}
String next()
{
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
}
catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() { return Integer.parseInt(next()); }
long nextLong() { return Long.parseLong(next()); }
double nextDouble()
{
return Double.parseDouble(next());
}
String nextLine()
{
String str = "";
try {
str = br.readLine();
}
catch (IOException e) {
e.printStackTrace();
}
return str;
}
}
public static void main (String[] args) {
FastReader sc= new FastReader();
String str= sc.nextLine();
String a="Apple";
if(a.equals(str)){
System.out.println("Gravity");
}
else{
System.out.println("Space");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Today is Newton School's first class of this year. Nutan, a student at Newton School, has received his first assignment. He will be given a string as input. His task is to print "Gravity'' if the input is "Apple''; otherwise, he will have to print "Space''.
Can you help Nutan in solving his first assignment? Note that the quotation marks are just for clarity. They are not part of the input string, and should not be a part of your output string.The input consists of a single line that contains a string S (1 ≤ length of S ≤ 10). The string only consists of lowercase and uppercase letters.Print "Gravity'' or "Space'' according to the input.Sample Input 1:
Apple
Sample Output 1:
Gravity
Sample Input 2:
Mango
Sample Output 2:
Space
Sample Input 3:
AppLE
Sample Output 3:
Space, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
//Work
int main()
{
#ifndef ONLINE_JUDGE
if (fopen("INPUT.txt", "r"))
{
freopen ("INPUT.txt" , "r" , stdin);
//freopen ("OUTPUT.txt" , "w" , stdout);
}
#endif
//-----------------------------------------------------------------------------------------------------------//
string S;
cin>>S;
if(S=="Apple")
{
cout<<"Gravity"<<endl;
}
else
{
cout<<"Space"<<endl;
}
//-----------------------------------------------------------------------------------------------------------//
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Today is Newton School's first class of this year. Nutan, a student at Newton School, has received his first assignment. He will be given a string as input. His task is to print "Gravity'' if the input is "Apple''; otherwise, he will have to print "Space''.
Can you help Nutan in solving his first assignment? Note that the quotation marks are just for clarity. They are not part of the input string, and should not be a part of your output string.The input consists of a single line that contains a string S (1 ≤ length of S ≤ 10). The string only consists of lowercase and uppercase letters.Print "Gravity'' or "Space'' according to the input.Sample Input 1:
Apple
Sample Output 1:
Gravity
Sample Input 2:
Mango
Sample Output 2:
Space
Sample Input 3:
AppLE
Sample Output 3:
Space, I have written this Solution Code: n=input()
if n=='Apple':print('Gravity')
else:print('Space'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You must have solved the problem 'Tribonacci Numbers'. Now its time for Tribonacci strings.
Given three strings T[1] = "p", T[2] = "q", T[3] = "r",
String T[i] = T[i-1] + T[i-2] + T[i-3]
Find the character at K'th index in string T[N] (assuming 1-indexing)
Solve for Q independent queriesFirst line of input contains a single integer Q
Q lines follow, each containing two space separated numbers N and K
1 <= Q <= 10^5
1 <= N <= 60
1 <= K <= 10^16Print Q lines, each containing the character at K-th index of string T[N].
If K exceeds the length of string, print xSample Input 1:
3
6 2
6 8
6 12
Sample Output 1:
q
p
x
Explanation:
T[1] = p
T[2] = q
T[3] = r
T[4] = rqp
T[5] = rqprq
T[6] = rqprqrqpr, I have written this Solution Code: import java.util.*;
import java.io.*;
class Main{
public static char tribonacci(long arr[],int n,long k)
{
if(arr[n]<k)
return 'x';
if(n==1)
return 'p';
if(n==2)
return 'q';
if(n==3)
return 'r';
if(arr[n-1]>=k)
{
char ans=tribonacci(arr,n-1,k);
return ans;
}
else if(arr[n-1]+arr[n-2]>=k)
{
char ans=tribonacci(arr,n-2,k-arr[n-1]);
return ans;
}
else if(arr[n-1]+arr[n-2]+arr[n-3]>=k)
{
char ans=tribonacci(arr,n-3,k-arr[n-1]-arr[n-2]);
return ans;
}
return 'x';
}
public static void main(String args[])throws IOException
{
InputStreamReader r=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(r);
int t;
t=Integer.parseInt(br.readLine());
while(t-->0)
{
String ar1[]=br.readLine().split(" ");
int n;
n=Integer.parseInt(ar1[0]);
long k;
k=Long.parseLong(ar1[1]);
long arr[]=new long[61];
arr[1]=1;
arr[2]=1;
arr[3]=1;
for(int i=4;i<61;i++)
{
arr[i]=arr[i-1]+arr[i-2]+arr[i-3];
}
char ans=tribonacci(arr,n,k);
System.out.println(ans);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You must have solved the problem 'Tribonacci Numbers'. Now its time for Tribonacci strings.
Given three strings T[1] = "p", T[2] = "q", T[3] = "r",
String T[i] = T[i-1] + T[i-2] + T[i-3]
Find the character at K'th index in string T[N] (assuming 1-indexing)
Solve for Q independent queriesFirst line of input contains a single integer Q
Q lines follow, each containing two space separated numbers N and K
1 <= Q <= 10^5
1 <= N <= 60
1 <= K <= 10^16Print Q lines, each containing the character at K-th index of string T[N].
If K exceeds the length of string, print xSample Input 1:
3
6 2
6 8
6 12
Sample Output 1:
q
p
x
Explanation:
T[1] = p
T[2] = q
T[3] = r
T[4] = rqp
T[5] = rqprq
T[6] = rqprqrqpr, I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N];
char rec(int n, int k){
if(k > a[n])
return 'x';
if(n == 1) return 'p';
if(n == 2) return 'q';
if(n == 3) return 'r';
if(k <= a[n-1]) return rec(n-1, k);
k -= a[n-1];
if(k <= a[n-2]) return rec(n-2, k);
k -= a[n-2];
return rec(n-3, k);
}
signed main() {
IOS;
clock_t start = clock();
int t; cin >> t;
a[1] = a[2] = a[3] = 1;
for(int i = 4; i <= 60; i++)
a[i] = a[i-1] + a[i-2] + a[i-3];
while(t--){
int n, k; cin >> n >> k;
cout << rec(n, k) << endl;
}
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms" << endl;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer, print whether that integer is a prime number or not.First line of input contains an integer T, showing the number of test cases. Every test case is a single integer A.
Constraints
1 <= T <= 100
1 <= A <= 10^8If the given integer is prime, print 'Yes', else print 'No'.Sample Input
3
5
9
13
Output
Yes
No
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
try{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int testcase = Integer.parseInt(br.readLine());
for(int t=0;t<testcase;t++){
int num = Integer.parseInt(br.readLine().trim());
if(num==1)
System.out.println("No");
else if(num<=3)
System.out.println("Yes");
else{
if((num%2==0)||(num%3==0))
System.out.println("No");
else{
int flag=0;
for(int i=5;i*i<=num;i+=6){
if(((num%i)==0)||(num%(i+2)==0)){
System.out.println("No");
flag=1;
break;
}
}
if(flag==0)
System.out.println("Yes");
}
}
}
}catch (Exception e) {
System.out.println("I caught: " + e);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer, print whether that integer is a prime number or not.First line of input contains an integer T, showing the number of test cases. Every test case is a single integer A.
Constraints
1 <= T <= 100
1 <= A <= 10^8If the given integer is prime, print 'Yes', else print 'No'.Sample Input
3
5
9
13
Output
Yes
No
Yes, I have written this Solution Code: t=int(input())
for i in range(t):
number = int(input())
if number > 1:
i=2
while i*i<=number:
if (number % i) == 0:
print("No")
break
i+=1
else:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer, print whether that integer is a prime number or not.First line of input contains an integer T, showing the number of test cases. Every test case is a single integer A.
Constraints
1 <= T <= 100
1 <= A <= 10^8If the given integer is prime, print 'Yes', else print 'No'.Sample Input
3
5
9
13
Output
Yes
No
Yes, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int t;
cin>>t;
while(t--){
long long n,k;
cin>>n;
long x=sqrt(n);
int cnt=0;
vector<int> v;
for(long long i=2;i<=x;i++){
if(n%i==0){
cout<<"No"<<endl;
goto f;
}}
cout<<"Yes"<<endl;
f:;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code: static int focal_length(int R, char Mirror)
{
int f=R/2;
if((R%2==1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code:
int focal_length(int R, char Mirror)
{
int f=R/2;
if((R&1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code:
int focal_length(int R, char Mirror)
{
int f=R/2;
if((R&1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code: def focal_length(R,Mirror):
f=R/2;
if(Mirror == ')'):
f=-f
if R%2==1:
f=f-1
return int(f)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers ‘a’ and ‘m’. The task is to find modular multiplicative inverse of ‘a’ under modulo ‘m’.
Note: Print the smallest modular multiplicative inverse.First line of input contains a single integer T denoting number of test cases, next T lines contains two space separated integers depicting value of a and m.
Constraints :-
1 < = T < = 100
1 < = m < = 100
1 < = a < = mFor each test case, in a new line print the modular multiplicative inverse if exist else print -1.Sample Input:-
2
3 11
10 17
Sample Output:-
4
12, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int t=Integer.parseInt(br.readLine().trim());
while(t-->0){
String str[]=br.readLine().trim().split(" ");
int a=Integer.parseInt(str[0]);
int m=Integer.parseInt(str[1]);
int b;
int flag=0;
for(b=1; b<m; b++){
if(((a%m)*(b%m))%m == 1){
flag=1;
break;
}
}
if(flag==0){
System.out.println(-1);
}else{
System.out.println(b);
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers ‘a’ and ‘m’. The task is to find modular multiplicative inverse of ‘a’ under modulo ‘m’.
Note: Print the smallest modular multiplicative inverse.First line of input contains a single integer T denoting number of test cases, next T lines contains two space separated integers depicting value of a and m.
Constraints :-
1 < = T < = 100
1 < = m < = 100
1 < = a < = mFor each test case, in a new line print the modular multiplicative inverse if exist else print -1.Sample Input:-
2
3 11
10 17
Sample Output:-
4
12, I have written this Solution Code: def modInverse(a, m):
for x in range(1, m):
if (((a%m)*(x%m) % m )== 1):
return x
return -1
t = int(input())
for i in range(t):
a ,m = map(int , input().split())
print(modInverse(a, m)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers ‘a’ and ‘m’. The task is to find modular multiplicative inverse of ‘a’ under modulo ‘m’.
Note: Print the smallest modular multiplicative inverse.First line of input contains a single integer T denoting number of test cases, next T lines contains two space separated integers depicting value of a and m.
Constraints :-
1 < = T < = 100
1 < = m < = 100
1 < = a < = mFor each test case, in a new line print the modular multiplicative inverse if exist else print -1.Sample Input:-
2
3 11
10 17
Sample Output:-
4
12, I have written this Solution Code:
// author-Shivam gupta
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define max1 100001
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
int modInverseNaive(int a, int m) {
a %= m;
for (int x = 1; x < m; x++) {
if ((a*x) % m == 1) return x;
}
return -1;
}
signed main() {
int t;
cin >> t;
while (t-- > 0) {
int a,m;
cin >> a >> m;
cout << modInverseNaive(a, m) << '\n';
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix <b>A</b> of dimensions <b>n x m</b>. The task is to perform <b>boundary traversal</b> on the matrix in clockwise manner.The first line of input contains T denoting the number of testcases. T testcases follow. Each testcase has two lines of input. The first line contains dimensions of the matrix A, n and m. The second line contains n*m elements separated by spaces.
Constraints:
1 <= T <= 100
1 <= n, m <= 30
0 <= A[i][j] <= 100For each testcase, in a new line, print the boundary traversal of the matrix A.Input:
4
4 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
3 4
12 11 10 9 8 7 6 5 4 3 2 1
1 4
1 2 3 4
4 1
1 2 3 4
Output:
1 2 3 4 8 12 16 15 14 13 9 5
12 11 10 9 5 1 2 3 4 8
1 2 3 4
1 2 3 4
Explanation:
Testcase1: The matrix is:
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
The boundary traversal is 1 2 3 4 8 12 16 15 14 13 9 5
Testcase 2: Boundary Traversal will be 12 11 10 9 5 1 2 3 4 8.
Testcase 3: Boundary Traversal will be 1 2 3 4.
Testcase 4: Boundary Traversal will be 1 2 3 4., I have written this Solution Code:
def boundaryTraversal(matrix, N, M): #N = 3, M = 4
start_row = 0
start_col = 0
count = 0
if N != 1 and M != 1:
total = 2 * (N - 1) + 2 * (M - 1)
else:
total = max(M, N)
#First row
for i in range(start_col, M, 1): #0,1, 2, 3
count += 1
print(matrix[start_row][i], end = " ")
if count == total:
return
start_row += 1
#Last column
for i in range(start_row, N, 1): # 1, 2
count += 1
print(matrix[i][M - 1], end = " ")
if count == total:
return
M -= 1
#Last Row
for i in range(M - 1, start_col - 1, -1): # 2, 1, 0
count += 1
print(matrix[N - 1][i], end = " ")
if count == total:
return
#First Column
N -= 1 # 2
for i in range(N - 1, start_row - 1, -1):
count += 1
print(matrix[i][start_col], end = " ")
start_col += 1
testcase = int(input().strip())
for test in range(testcase):
dim = input().strip().split(" ")
N = int(dim[0])
M = int(dim[1])
matrix = []
elements = input().strip().split(" ") #N * M
start = 0
for i in range(N):
matrix.append(elements[start : start + M]) # (0, M - 1) | (M, 2*m-1)
start = start + M
boundaryTraversal(matrix, N, M)
print(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix <b>A</b> of dimensions <b>n x m</b>. The task is to perform <b>boundary traversal</b> on the matrix in clockwise manner.The first line of input contains T denoting the number of testcases. T testcases follow. Each testcase has two lines of input. The first line contains dimensions of the matrix A, n and m. The second line contains n*m elements separated by spaces.
Constraints:
1 <= T <= 100
1 <= n, m <= 30
0 <= A[i][j] <= 100For each testcase, in a new line, print the boundary traversal of the matrix A.Input:
4
4 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
3 4
12 11 10 9 8 7 6 5 4 3 2 1
1 4
1 2 3 4
4 1
1 2 3 4
Output:
1 2 3 4 8 12 16 15 14 13 9 5
12 11 10 9 5 1 2 3 4 8
1 2 3 4
1 2 3 4
Explanation:
Testcase1: The matrix is:
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
The boundary traversal is 1 2 3 4 8 12 16 15 14 13 9 5
Testcase 2: Boundary Traversal will be 12 11 10 9 5 1 2 3 4 8.
Testcase 3: Boundary Traversal will be 1 2 3 4.
Testcase 4: Boundary Traversal will be 1 2 3 4., I have written this Solution Code: import java.io.*;
import java.lang.*;
import java.util.*;
class Main
{
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
while(t-- > 0)
{
int n1 = sc.nextInt();
int m1 = sc.nextInt();
int arr1[][] = new int[n1][m1];
for(int i = 0; i < n1; i++)
{
for(int j = 0; j < m1; j++)
arr1[i][j] = sc.nextInt();
}
boundaryTraversal(n1, m1,arr1);
System.out.println();
}
}
static void boundaryTraversal( int n1, int m1, int arr1[][])
{
// base cases
if(n1 == 1)
{
int i = 0;
while(i < m1)
System.out.print(arr1[0][i++] + " ");
}
else if(m1 == 1)
{
int i = 0;
while(i < n1)
System.out.print(arr1[i++][0]+" ");
}
else
{
// traversing the first row
for(int j=0;j<m1;j++)
{
System.out.print(arr1[0][j]+" ");
}
// traversing the last column
for(int j=1;j<n1;j++)
{
System.out.print(arr1[j][m1-1]+ " ");
}
// traversing the last row
for(int j=m1-2;j>=0;j--)
{
System.out.print(arr1[n1-1][j]+" ");
}
// traversing the first column
for(int j=n1-2;j>=1;j--)
{
System.out.print(arr1[j][0]+" ");
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Is it possible to get a sum of <b>B</b> when throwing a die with six faces 1, 2, …, 6 <b>A</b> times?The input consists of two space-separated integers.
A B
<b>Constraints</b>
1≤A≤100
1≤B≤1000
A and B are integers.If it is possible to get a sum of B, print Yes; otherwise, print No.<b>Sample Input 1</b>
2 11
<b>Sample Output 1</b>
Yes
<b>Sample Input 2</b>
2 13
<b>Sample Output 2</b>
No, I have written this Solution Code: #include <iostream>
using namespace std;
int main() {
int A, B;
cin >> A >> B;
if(A <= B && B <= 6 * A) {
cout << "Yes" << endl;
} else {
cout << "No" << endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String a= br.readLine();
int sum=0;
int n=a.length();
int s=0;
for(int i=0; i<n; i++){
sum=sum+ (a.charAt(i) - '0');
if(i == n-1){
s= (a.charAt(i) - '0');
}
}
if(sum%3==0 && s==0){
System.out.print("Yes");
}else{
System.out.print("No");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: /**
* Author : tourist1256
* Time : 2022-02-10 11:06:49
**/
#include <bits/stdc++.h>
using namespace std;
#define int long long int
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
int solve(string a) {
int n = a.size();
int sum = 0;
if (a[n - 1] != '0') {
return 0;
}
for (auto &it : a) {
sum += (it - '0');
}
debug(sum % 3);
if (sum % 3 == 0) {
return 1;
}
return 0;
}
int32_t main() {
ios_base::sync_with_stdio(NULL);
cin.tie(0);
string str;
cin >> str;
int res = solve(str);
if (res) {
cout << "Yes\n";
} else {
cout << "No\n";
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a big number in form of a string A of characters from 0 to 9.
Check whether the given number is divisible by 30 .The first argument is the string A.
<b>Constraints</b>
1 ≤ |A| ≤ 10<sup>5</sup>Return "Yes" if it is divisible by 30 and "No" otherwise. Sample Input :
3033330
Sample Output:
Yes, I have written this Solution Code: A=int(input())
if A%30==0:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a curried function called <code>reverseWords</code> that takes two string arguments. The first argument will be a sentence and the second argument will be a word. The function should append the word at the end of the sentence after leaving a space. The <code>reverseWords</code> function would return a function called <code>reverseFunc</code>.
The <code>reverseFunc</code> function, when called, should split the new sentence formed into individual words using <code>split()</code> function, reverse the order of the words using <code>reverse()</code> function, and join them back together with a space between each word using <code>join()</code> function. Then the new string formed should be returned by the <code>reverseFunc</code> functionThe <code>reverseWords</code> function takes two string arguments. The first argument will be a sentence consisting of multiple words and the second argument will be a single word.
The <code>reverseFunc</code> function takes no arguments. It used the new sentence formed by appending the second argument to the first argument of the <code>reverseWords</code> function.The <code>reverseWords</code> function should return a function called <code>reverseFunc</code>.
The <code>reverseFunc</code> function should take the new string formed by appending the second argument to the first one of the <code>reverseWords</code> function, split it into individual words, reverse their order, join them back with a space between each word, and return the string formed.const arg1 = "hello world";
const arg2 = "everyone";
const reverseFunc = reverseWords(arg1, arg2);
console.log(reverseFunc()); //prints "everyone world hello"
, I have written this Solution Code: function reverseWords(str, word){
str = str + " " + word;
function reverseFunc() {
const words = str.split(' ');
const reversedWords = words.reverse();
const reversedString = reversedWords.join(' ');
return reversedString;
}
return reverseFunc;
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a Java program to perform following operations:
1. Input an arraylist of size n
2. Sort the arraylist
3. Search for value 2 in arraylist , if present print out its index else print out -1.First line of input contains value of n.
second line of input contains n space-separated integers.
Constraints:-
1 < = N < = 1000
1 < = Arr[i] < = 100000 Print index of 2 if present else print out -1.Sample Input:-
6
1 2 3 4 5 6
Sample output:-
1
Explanation:
2 is present at index value 1 in the sorted arraylist., I have written this Solution Code: import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
public class Main {
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
ArrayList<Integer> list = new ArrayList<Integer>();
int n = sc.nextInt();
for (int i = 0; i < n; i++) {
list.add(sc.nextInt());
}
Collections.sort(list);
int index = Collections.binarySearch(list, 2);
if (index >= 0) {
System.out.println(index);
} else {
System.out.println("-1");
}
sc.close();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each i (1 < = i < = N), you have to print the number except :-
For each multiple of 3, print "Newton" instead of the number.
For each multiple of 5, print "School" instead of the number.
For numbers that are multiples of both 3 and 5, print "NewtonSchool" instead of the number.The first line of the input contains N.
<b>Constraints</b>
1 < = N < = 1000
Print N space separated number or Newton School according to the condition.Sample Input:-
3
Sample Output:-
1 2 Newton
Sample Input:-
5
Sample Output:-
1 2 Newton 4 School, I have written this Solution Code: n=int(input())
for i in range(1,n+1):
if i%3==0 and i%5==0:
print("NewtonSchool",end=" ")
elif i%3==0:
print("Newton",end=" ")
elif i%5==0:
print("School",end=" ")
else:
print(i,end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each i (1 < = i < = N), you have to print the number except :-
For each multiple of 3, print "Newton" instead of the number.
For each multiple of 5, print "School" instead of the number.
For numbers that are multiples of both 3 and 5, print "NewtonSchool" instead of the number.The first line of the input contains N.
<b>Constraints</b>
1 < = N < = 1000
Print N space separated number or Newton School according to the condition.Sample Input:-
3
Sample Output:-
1 2 Newton
Sample Input:-
5
Sample Output:-
1 2 Newton 4 School, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
static void NewtonSchool(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){System.out.print("NewtonSchool ");}
else if(i%5==0){System.out.print("School ");}
else if(i%3==0){System.out.print("Newton ");}
else{System.out.print(i+" ");}
}
}
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int x= sc.nextInt();
NewtonSchool(x);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){cout<<"FizzBuzz"<<" ";}
else if(i%5==0){cout<<"Buzz ";}
else if(i%3==0){cout<<"Fizz ";}
else{cout<<i<<" ";}
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int x= sc.nextInt();
fizzbuzz(x);
}
static void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){System.out.print("FizzBuzz ");}
else if(i%5==0){System.out.print("Buzz ");}
else if(i%3==0){System.out.print("Fizz ");}
else{System.out.print(i+" ");}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: def fizzbuzz(n):
for i in range (1,n+1):
if (i%3==0 and i%5==0):
print("FizzBuzz",end=' ')
elif i%3==0:
print("Fizz",end=' ')
elif i%5==0:
print("Buzz",end=' ')
else:
print(i,end=' '), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each I (1 < = I < = N), you have to print the number except:-
For each multiple of 3, print "Fizz" instead of the number.
For each multiple of 5, print "Buzz" instead of the number.
For numbers that are multiples of both 3 and 5, print "FizzBuzz" instead of the number.The input contains a single integer N.
<b>Constraints:-</b>
1 ≤ N ≤ 1000Print N space separated number or Fizz buzz according to the condition.Sample Input:-
3
Sample Output:-
1 2 Fizz
Sample Input:-
5
Sample Output:-
1 2 Fizz 4 Buzz, I have written this Solution Code: void fizzbuzz(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){printf("FizzBuzz ");}
else if(i%5==0){printf("Buzz ");}
else if(i%3==0){printf("Fizz ");}
else{printf("%d ",i);}
}
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A containing a permutation of N numbers. Find the number of indices i such that <b>A[i] <= A[j] satisfies for all the values of j satisfying 1 <= j <= i </b>.The first line of the input contains an input N, the size of the permutation.
The second line of the input contains N singly spaced integers, the elements of the permutation P.
<b>Constraints</b>
1 <= N <= 200000
1 <= P[i] <= N
P is a permutation of the first N natural numbers.Output a single integer, the answer to the problem.Sample Input
6
3 2 5 6 1 4
Sample Output
3
Sample Input
3
1 2 3
Sample Output
1
<b>Explanation 1:</b>
The indices i=1, i=2, and i=5 satisfy the condition., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception {
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
int N = Integer.parseInt(reader.readLine());
int min = N + 1;
StringTokenizer tokens = new StringTokenizer(reader.readLine());
int c = 0;
for(int i = 0; i < N; i++) {
int x = Integer.parseInt(tokens.nextToken());
if(x < min) {
c++;
min = x;
}
}
System.out.println(c);
reader.close();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A containing a permutation of N numbers. Find the number of indices i such that <b>A[i] <= A[j] satisfies for all the values of j satisfying 1 <= j <= i </b>.The first line of the input contains an input N, the size of the permutation.
The second line of the input contains N singly spaced integers, the elements of the permutation P.
<b>Constraints</b>
1 <= N <= 200000
1 <= P[i] <= N
P is a permutation of the first N natural numbers.Output a single integer, the answer to the problem.Sample Input
6
3 2 5 6 1 4
Sample Output
3
Sample Input
3
1 2 3
Sample Output
1
<b>Explanation 1:</b>
The indices i=1, i=2, and i=5 satisfy the condition., I have written this Solution Code: n=int(input())
a=map(int,input().split())
c=200001
v=0
for i in a:
if i<c:
c=i
v+=1
print(v), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A containing a permutation of N numbers. Find the number of indices i such that <b>A[i] <= A[j] satisfies for all the values of j satisfying 1 <= j <= i </b>.The first line of the input contains an input N, the size of the permutation.
The second line of the input contains N singly spaced integers, the elements of the permutation P.
<b>Constraints</b>
1 <= N <= 200000
1 <= P[i] <= N
P is a permutation of the first N natural numbers.Output a single integer, the answer to the problem.Sample Input
6
3 2 5 6 1 4
Sample Output
3
Sample Input
3
1 2 3
Sample Output
1
<b>Explanation 1:</b>
The indices i=1, i=2, and i=5 satisfy the condition., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(int i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define ld long double
#define int long long
#define double long double
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
typedef vector<int> vi;
#define pi 3.141592653589793238
const int MOD = 1e9+7;
const int INF = 1LL<<60;
const int N = 2e5+5;
// it's swapnil07 ;)
#ifdef SWAPNIL07
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
cout << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
int begtime = clock();
#define end_routine() cout << "\n\nTime elapsed: " << (clock() - begtime)*1000/CLOCKS_PER_SEC << " ms\n\n";
#else
#define endl '\n'
#define trace(...)
#define end_routine()
#endif
void solve(){
int n; cin>>n;
int mn = INF;
int ans = 0;
For(i, 0, n){
int a; cin>>a;
if(a > mn){
continue;
}
ans++;
mn = a;
}
cout<<ans;
}
signed main()
{
fast
#ifdef SWAPNIL07
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
int t=1;
// cin>>t;
while(t--){
solve();
cout<<"\n";
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of size n containing distinct integers, where n is odd. Find the element which has the same number of lesser elements and the same number of greater elements in the array.First line of the input contains an integer, N, which denotes the length of the array. Next N inputs are elements of the array.
Constraints
1 <= N <= 20
-10000 <= Arr[i] <= 10000Single integer n which has the same number of lesser elements and the same number of greater elements.Input:
3
3 1 2
Output:
2
Explanation:-
2 has one greater element 3 and one smaller element 1
Input:
5
2 3 4 9 1
Output:
3, I have written this Solution Code: n=int(input())
l=list(map(int,input().split()))
l.sort()
m=len(l)//2
print(l[m]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of size n containing distinct integers, where n is odd. Find the element which has the same number of lesser elements and the same number of greater elements in the array.First line of the input contains an integer, N, which denotes the length of the array. Next N inputs are elements of the array.
Constraints
1 <= N <= 20
-10000 <= Arr[i] <= 10000Single integer n which has the same number of lesser elements and the same number of greater elements.Input:
3
3 1 2
Output:
2
Explanation:-
2 has one greater element 3 and one smaller element 1
Input:
5
2 3 4 9 1
Output:
3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String[] str=br.readLine().split("\\s+");
int N=Integer.parseInt(str[0]);
str=br.readLine().split("\\s+");
int arr[]=new int[N];
for(int i=0;i<N;i++){
arr[i]=Integer.parseInt(str[i]);
}
findElement(arr,N);
}
public static void findElement(int arr[],int N){
int start=0;
int end=N;Arrays.sort(arr);
int mid=start+(end-start)/2;
System.out.print(arr[mid]);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of size n containing distinct integers, where n is odd. Find the element which has the same number of lesser elements and the same number of greater elements in the array.First line of the input contains an integer, N, which denotes the length of the array. Next N inputs are elements of the array.
Constraints
1 <= N <= 20
-10000 <= Arr[i] <= 10000Single integer n which has the same number of lesser elements and the same number of greater elements.Input:
3
3 1 2
Output:
2
Explanation:-
2 has one greater element 3 and one smaller element 1
Input:
5
2 3 4 9 1
Output:
3, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int m = 100001;
int main(){
int n,k;
cin>>n;
long long a[n],sum=0;
for(int i=0;i<n;i++){
cin>>a[i];
}
sort(a,a+n);
cout<<a[n/2];;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, you need to check whether the given number is Armstrong number or not. Now what is Armstrong number let us see below:
<b>A number is said to be Armstrong if it is equal to sum of cube of its digits. </b>User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>isArmstrong()</b> which contains N as a parameter.
Constraints:
1 <= N <= 10^4You need to return "true" if the given number is an Armstrong number otherwise "false"Sample Input 1:
1
Sample Output 1:
true
Sample Input 2:
147
Sample Output 2:
false
Sample Input 3:
371
Sample Output 3:
true
, I have written this Solution Code: static boolean isArmstrong(int N)
{
int num = N;
int sum = 0;
while(N > 0)
{
int digit = N%10;
sum += digit*digit*digit;
N = N/10;
}
if(num == sum)
return true;
else return false;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N, you need to check whether the given number is Armstrong number or not. Now what is Armstrong number let us see below:
<b>A number is said to be Armstrong if it is equal to sum of cube of its digits. </b>User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>isArmstrong()</b> which contains N as a parameter.
Constraints:
1 <= N <= 10^4You need to return "true" if the given number is an Armstrong number otherwise "false"Sample Input 1:
1
Sample Output 1:
true
Sample Input 2:
147
Sample Output 2:
false
Sample Input 3:
371
Sample Output 3:
true
, I have written this Solution Code: function isArmstrong(n) {
// write code here
// do no console.log the answer
// return the output using return keyword
let sum = 0
let k = n;
while(k !== 0){
sum += Math.pow( k%10,3)
k = Math.floor(k/10)
}
return sum === n
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number.
If the number is greater than 3 then print "great".
If the number is greater than 5 then print "awesome".
If the number is not greater than 3 or 5, print "bad".A single integer x.
<b>Constraints</b>
-10<sup>8</sup> <= x <= 10<sup>8</sup>Output a single string denoting the required answer.Sample Input 1:
3
Sample Output 1:
bad
Sample Input 2:
4
Sample Output 2:
great
Sample Input 3:
6
Sample Output 3:
awesome, I have written this Solution Code: import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) {
InputStream inputStream = System.in;
OutputStream outputStream = System.out;
InputReader in = new InputReader(inputStream);
OutputWriter out = new OutputWriter(outputStream);
int n=Integer.parseInt(in.next());
if(n>5)out.print("awesome");
else if(n>3)out.print("great");
else out.print("bad");
out.close();
}
static class InputReader {
BufferedReader reader;
StringTokenizer tokenizer;
public InputReader(InputStream stream) {
reader = new BufferedReader(new InputStreamReader(stream), 32768);
tokenizer = null;
}
public String next() {
while (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
static class OutputWriter {
private final PrintWriter writer;
public OutputWriter(OutputStream outputStream) {
writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
}
public OutputWriter(Writer writer) {
this.writer = new PrintWriter(writer);
}
public void print(Object... objects) {
for (int i = 0; i < objects.length; i++) {
if (i != 0) {
writer.print(' ');
}
writer.print(objects[i]);
}
}
public void println(Object... objects) {
print(objects);
writer.println();
}
public void close() {
writer.close();
}
public void println(int i) {
writer.println(i);
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer array A of N integers, find the pair of integers in the array which have minimum XOR value. Report the minimum XOR value.First line denotes N, the size of the array.
Next line denotes N space-separated array elements.
Constraints:
2 <= N <= 100000
0 <= A[i] <= 10^7Print a single integer denoting minimum xor valueSample Input
4
0 2 5 7
Sample Output
2
Explanation:
0 xor 2 = 2
Sample Input
4
0 4 7 9
Sample Output
3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
int ans = 0;
int mini = Integer.MAX_VALUE;
Scanner sc = new Scanner(System.in);
int array_size = sc.nextInt();
int N[] = new int[array_size];
for (int i = 0; i < array_size; i++) {
if(mini == 0){
break;
}
N[i] = sc.nextInt();
for (int j = i - 1; j >= 0; j--) {
ans = N[i] ^ N[j];
if (mini > ans) {
mini = ans;
}
}
}
System.out.println(mini);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer array A of N integers, find the pair of integers in the array which have minimum XOR value. Report the minimum XOR value.First line denotes N, the size of the array.
Next line denotes N space-separated array elements.
Constraints:
2 <= N <= 100000
0 <= A[i] <= 10^7Print a single integer denoting minimum xor valueSample Input
4
0 2 5 7
Sample Output
2
Explanation:
0 xor 2 = 2
Sample Input
4
0 4 7 9
Sample Output
3, I have written this Solution Code: a=int(input())
lis = list(map(int,input().split()))
val=666666789
for i in range(a+1):
for j in range(i+1,a):
temp = lis[i]^lis[j]
if(temp<val):
val = temp
if(val==0):
break
print(val), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer array A of N integers, find the pair of integers in the array which have minimum XOR value. Report the minimum XOR value.First line denotes N, the size of the array.
Next line denotes N space-separated array elements.
Constraints:
2 <= N <= 100000
0 <= A[i] <= 10^7Print a single integer denoting minimum xor valueSample Input
4
0 2 5 7
Sample Output
2
Explanation:
0 xor 2 = 2
Sample Input
4
0 4 7 9
Sample Output
3, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
// Function to find minimum XOR pair
int minXOR(int arr[], int n)
{
// Sort given array
sort(arr, arr + n);
int minXor = INT_MAX;
int val = 0;
// calculate min xor of consecutive pairs
for (int i = 0; i < n - 1; i++) {
val = arr[i] ^ arr[i + 1];
minXor = min(minXor, val);
}
return minXor;
}
// Driver program
int main()
{
int n;
cin>>n;
int arr[n];
for(int i=0;i<n;i++)
{
cin>>arr[i];
}
cout << minXOR(arr, n) << endl;
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two sorted array your task is to merge these two arrays into a single array such that the merged array is also sortedFirst line contain two integers N and M the size of arrays
Second line contains N separated integers the elements of first array
Third line contains M separated integers elements of second array
<b>Constraints:-</b>
1<=N,M<=10<sup>4</sup>
1<=arr1[], arr2[] <=10<sup>5</sup>Output the merged arraySample Input:-
3 4
1 4 7
1 3 3 9
Sample Output:-
1 1 3 3 4 7 9
, I have written this Solution Code: n1,m1=input().split()
n=int(n1)
m=int(m1)
l1=list(map(int,input().strip().split()))
l2=list(map(int,input().strip().split()))
i,j=0,0
while i<n and j<m:
if l1[i]<=l2[j]:
print(l1[i],end=" ")
i+=1
else:
print(l2[j],end=" ")
j+=1
for a in range(i,n):
print(l1[a],end=" ")
for b in range(j,m):
print(l2[b],end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two sorted array your task is to merge these two arrays into a single array such that the merged array is also sortedFirst line contain two integers N and M the size of arrays
Second line contains N separated integers the elements of first array
Third line contains M separated integers elements of second array
<b>Constraints:-</b>
1<=N,M<=10<sup>4</sup>
1<=arr1[], arr2[] <=10<sup>5</sup>Output the merged arraySample Input:-
3 4
1 4 7
1 3 3 9
Sample Output:-
1 1 3 3 4 7 9
, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define max1 10000001
int main(){
int n,m;
cin>>n>>m;
int a[n];
int b[m];
for(int i=0;i<n;i++){
cin>>a[i];
}
for(int i=0;i<m;i++){
cin>>b[i];
}
int c[n+m];
int i=0,j=0,k=0;
while(i!=n && j!=m){
if(a[i]<b[j]){c[k]=a[i];k++;i++;}
else{c[k]=b[j];j++;k++;}
}
while(i!=n){
c[k]=a[i];
k++;i++;
}
while(j!=m){
c[k]=b[j];
k++;j++;
}
for(i=0;i<n+m;i++){
cout<<c[i]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two sorted array your task is to merge these two arrays into a single array such that the merged array is also sortedFirst line contain two integers N and M the size of arrays
Second line contains N separated integers the elements of first array
Third line contains M separated integers elements of second array
<b>Constraints:-</b>
1<=N,M<=10<sup>4</sup>
1<=arr1[], arr2[] <=10<sup>5</sup>Output the merged arraySample Input:-
3 4
1 4 7
1 3 3 9
Sample Output:-
1 1 3 3 4 7 9
, I have written this Solution Code:
import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int m = sc.nextInt();
int a[] = new int[n];
int b[] = new int[m];
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
for(int i=0;i<m;i++){
b[i]=sc.nextInt();
}
int c[]=new int[n+m];
int i=0,j=0,k=0;
while(i!=n && j!=m){
if(a[i]<b[j]){c[k]=a[i];k++;i++;}
else{c[k]=b[j];j++;k++;}
}
while(i!=n){
c[k]=a[i];
k++;i++;
}
while(j!=m){
c[k]=b[j];
k++;j++;
}
for(i=0;i<n+m;i++){
System.out.print(c[i]+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <b><em>Array List In Java</em></b>
There are n integers given.
<ul>
<li>Create an ArrayList</li>
<li>Add elements</li>
<li>Print the elements of arraylist.</li>
</ul>There is an integer n is given in first line of input.
In Second line, n space separated integer are given.
<b>Constraints</b>
1 <= n <= 10<sup>5</sup>
Print the elements of arraylist.Sample Input:
5
1 2 3 4 5
Sample Output:
1 2 3 4 5, I have written this Solution Code: // Java program for the above approach
import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args)
{
ArrayList<Integer> arr = new ArrayList<>();
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
for(int i=0;i<n;i++){
int a=sc.nextInt();
arr.add(a);
}
for(int i=0;i<n;i++){
System.out.print(arr.get(i));
System.out.print(" ");
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a queue of integers and N queries. Your the task is to perform these operations:-
enqueue:-this operation will add an element to your current queue.
dequeue:-this operation will delete the element from the starting of the queue
displayfront:-this operation will print the element presented at front
Note:-if queue is empty than dequeue operation will do nothing, and 0 will be printed as a front element of queue if it is empty.User task:
Since this will be a functional problem, you don't have to take input. You just have to complete the functions:
<b>enqueue()</b>:- that takes the queue and the integer to be added as a parameter.
<b>dequeue</b>:- that takes the queue as parameter.
<b>displayfront</b> :- that takes the queue as parameter.
Constraints:
1 <= N(Number of queries) <= 10<sup>3</sup>You don't need to print anything else other than in displayfront() in which you require to print the element at front of your queue in a new line, if the queue is empty you just need to print 0.Sample Input:-
7
displayfront
enqueue 2
displayfront
enqueue 4
displayfront
dequeue
displayfront
Sample Output:-
0
2
2
4
Sample input:
5
enqueue 4
enqueue 5
displayfront
dequeue
displayfront
Sample output:-
4
5, I have written this Solution Code: public static void enqueue (Queue < Integer > st, int x)
{
st.add (x);
}
public static void dequeue (Queue < Integer > st)
{
if (st.isEmpty () == false)
{
int x = st.remove();
}
}
public static void displayfront(Queue < Integer > st)
{
int x = 0;
if (st.isEmpty () == false)
{
x = st.peek ();
}
System.out.println (x);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array arr[] of size N containing 0s and 1s only. The task is to count the subarrays having an equal number of 0s and 1s.The first line of the input contains an integer N denoting the size of the array and the second line contains N space-separated 0s and 1s.
Constraints:-
1 <= N <= 10^6
0 <= A[i] <= 1For each test case, print the count of required sub-arrays in new line.Sample Input
7
1 0 0 1 0 1 1
Sample Output
8
The index range for the 8 sub-arrays are:
(0, 1), (2, 3), (0, 3), (3, 4), (4, 5)
(2, 5), (0, 5), (1, 6), I have written this Solution Code: size = int(input())
givenList = list(map(int,input().split()))
hs = {}
sm = 0
ct = 0
for i in givenList:
if i == 0:
i = -1
sm = sm + i
if sm == 0:
ct += 1
if sm not in hs.keys():
hs[sm] = 1
else:
freq = hs[sm]
ct = ct +freq
hs[sm] = freq + 1
print(ct), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array arr[] of size N containing 0s and 1s only. The task is to count the subarrays having an equal number of 0s and 1s.The first line of the input contains an integer N denoting the size of the array and the second line contains N space-separated 0s and 1s.
Constraints:-
1 <= N <= 10^6
0 <= A[i] <= 1For each test case, print the count of required sub-arrays in new line.Sample Input
7
1 0 0 1 0 1 1
Sample Output
8
The index range for the 8 sub-arrays are:
(0, 1), (2, 3), (0, 3), (3, 4), (4, 5)
(2, 5), (0, 5), (1, 6), I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define max1 1000001
int a[max1];
int main(){
int n;
cin>>n;
for(int i=0;i<n;i++){
cin>>a[i];
if(a[i]==0){a[i]=-1;}
}
long sum=0;
unordered_map<long,int> m;
long cnt=0;
for(int i=0;i<n;i++){
sum+=a[i];
if(sum==0){cnt++;}
cnt+=m[sum];
m[sum]++;
}
cout<<cnt;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array arr[] of size N containing 0s and 1s only. The task is to count the subarrays having an equal number of 0s and 1s.The first line of the input contains an integer N denoting the size of the array and the second line contains N space-separated 0s and 1s.
Constraints:-
1 <= N <= 10^6
0 <= A[i] <= 1For each test case, print the count of required sub-arrays in new line.Sample Input
7
1 0 0 1 0 1 1
Sample Output
8
The index range for the 8 sub-arrays are:
(0, 1), (2, 3), (0, 3), (3, 4), (4, 5)
(2, 5), (0, 5), (1, 6), I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
int arrSize = sc.nextInt();
long arr[] = new long[arrSize];
for(int i = 0; i < arrSize; i++)
arr[i] = sc.nextInt();
System.out.println(countSubarrays(arr, arrSize));
}
static long countSubarrays(long arr[], int arrSize)
{
for(int i = 0; i < arrSize; i++)
{
if(arr[i] == 0)
arr[i] = -1;
}
long ans = 0;
long sum = 0;
HashMap<Long, Integer> hash = new HashMap<>();
for(int i = 0; i < arrSize; i++)
{
sum += arr[i];
if(sum == 0)
ans++;
if(hash.containsKey(sum) == true)
{
ans += hash.get(sum);
int freq = hash.get(sum);
hash.put(sum, freq+1);
}
else hash.put(sum, 1);
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. The task is to print all permutations of the characters in the given string.The only line of input contains a string S with all distinct uppercase letters of the English alphabet.
Constraints:-
1<=|S|<=8Print all permutations of a given string S with single space and all permutations should be in lexicographically increasing order.Sample Input:
ABC
Sample Output:
ABC ACB BAC BCA CAB CBA, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static ArrayList<String> solution = new ArrayList<String>();
public static char[] swap(char[] charArray, int i, int j){
char temp;
temp = charArray[i];
charArray[i] = charArray[j];
charArray[j] = temp;
return charArray;
}
public static void permute(char[] charArray, int left, int right){
if(left == right){
String str = new String(charArray);
solution.add(str);
}
else{
for(int i=left; i<=right; i++)
{
charArray = swap(charArray, left, i);
permute(charArray, left+1, right);
charArray = swap(charArray, left, i);
}
}
}
public static void main(String[] args)
{
Scanner s = new Scanner(System.in);
String str = s.nextLine();
int n = str.length();
char[] charArray = str.toCharArray();
permute(charArray, 0, n-1);
Collections.sort(solution);
for(int i = 0; i < solution.size(); i++){
System.out.print(solution.get(i)+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. The task is to print all permutations of the characters in the given string.The only line of input contains a string S with all distinct uppercase letters of the English alphabet.
Constraints:-
1<=|S|<=8Print all permutations of a given string S with single space and all permutations should be in lexicographically increasing order.Sample Input:
ABC
Sample Output:
ABC ACB BAC BCA CAB CBA, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
vector<string> v;
void permute(string a, int l, int r)
{
// Base case
if (l == r)
v.push_back(a);
else
{
// Permutations made
for (int i = l; i <= r; i++)
{
// Swapping done
swap(a[l], a[i]);
// Recursion called
permute(a, l+1, r);
//backtrack
swap(a[l], a[i]);
}
}
}
signed main() {
IOS;
string s;
cin >> s;
sort(s.begin(), s.end());
permute(s, 0, s.length()-1);
sort(v.begin(),v.end());
for(int i=0;i<v.size();i++)
cout<<v[i]<<" ";
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. The task is to print all permutations of the characters in the given string.The only line of input contains a string S with all distinct uppercase letters of the English alphabet.
Constraints:-
1<=|S|<=8Print all permutations of a given string S with single space and all permutations should be in lexicographically increasing order.Sample Input:
ABC
Sample Output:
ABC ACB BAC BCA CAB CBA, I have written this Solution Code: from itertools import permutations
s = input()
l1 = list(s)
s1 = "".join(sorted(l1))
l = permutations(s1,len(s1))
for i in l:
print("".join(i),end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. The Force of an element is the square of its value.
<b>Note:</b>
Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
The next line contains n integers denoting elements of the array.
<b>Constraints:</b>
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7Output the maximum force.Sample Input 1:
4 4
1 2 3 4
Sample Output 1:
30
Sample Input 2:
2 1
1 10
Sample Output 2:
100
<b>Explanation:</b>
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int m = 100001;
int main(){
int n,k;
cin>>n>>k;
long long a[n],sum=0;
for(int i=0;i<n;i++){
cin>>a[i];
if(a[i]<0){
a[i]=-a[i];
}
}
sort(a,a+n);
for(int i=0;i<k;i++){
sum+=a[n-i-1]*a[n-i-1];
}
cout<<sum;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. The Force of an element is the square of its value.
<b>Note:</b>
Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
The next line contains n integers denoting elements of the array.
<b>Constraints:</b>
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7Output the maximum force.Sample Input 1:
4 4
1 2 3 4
Sample Output 1:
30
Sample Input 2:
2 1
1 10
Sample Output 2:
100
<b>Explanation:</b>
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
InputStreamReader ir = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(ir);
String[] NK = br.readLine().split(" ");
String[] inputs = br.readLine().split(" ");
int N = Integer.parseInt(NK[0]);
int K = Integer.parseInt(NK[1]);
long[] arr = new long[N];
long answer = 0;
for(int i = 0; i < N; i++){
arr[i] = Math.abs(Long.parseLong(inputs[i]));
}
quicksort(arr, 0, N-1);
for(int i = (N-K); i < N;i++){
answer += (arr[i]*arr[i]);
}
System.out.println(answer);
}
static void quicksort(long[] arr, int start, int end){
if(start < end){
int pivot = partition(arr, start, end);
quicksort(arr, start, pivot-1);
quicksort(arr, pivot+1, end);
}
}
static int partition(long[] arr, int start, int end){
long pivot = arr[end];
int i = start - 1;
for(int j = start; j < end; j++){
if(arr[j] < pivot){
i++;
swap(arr, i, j);
}
}
swap(arr, i+1, end);
return (i+1);
}
static void swap(long[] arr, int i, int j){
long temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size n, and an integer k. Find the maximum force by involving only k elements. The Force of an element is the square of its value.
<b>Note:</b>
Elements are not needed to be continuous.The first line of the input contains two integers denoting n and k.
The next line contains n integers denoting elements of the array.
<b>Constraints:</b>
1 < = k < = n < = 1000
-10^7 <= A[i] <= 10^7Output the maximum force.Sample Input 1:
4 4
1 2 3 4
Sample Output 1:
30
Sample Input 2:
2 1
1 10
Sample Output 2:
100
<b>Explanation:</b>
Force = 1*1 + 2*2 + 3*3 + 4*4 = 30, I have written this Solution Code: x,y = map(int,input().split())
arr = list(map(int,input().split()))
s=0
for i in range(x):
if arr[i]<0:
arr[i]=abs(arr[i])
arr=sorted(arr,reverse=True)
for i in range(0,y):
s = s+arr[i]*arr[i]
print(s)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc =new Scanner(System.in);
int T= sc.nextInt();
for(int i=0;i<T;i++){
int arrsize=sc.nextInt();
int max=0,secmax=0,thirdmax=0,j;
for(int k=0;k<arrsize;k++){
j=sc.nextInt();
if(j>max){
thirdmax=secmax;
secmax=max;
max=j;
}
else if(j>secmax){
thirdmax=secmax;
secmax=j;
}
else if(j>thirdmax){
thirdmax=j;
}
if(k%10000==0){
System.gc();
}
}
System.out.println(max+" "+secmax+" "+thirdmax+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: t=int(input())
while t>0:
t-=1
n=int(input())
l=list(map(int,input().strip().split()))
li=[0,0,0]
for i in l:
x=i
for j in range(0,3):
y=min(x,li[j])
li[j]=max(x,li[j])
x=y
print(li[0],end=" ")
print(li[1],end=" ")
print(li[2]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin>>t;
while(t--){
long long n;
cin>>n;
vector<long> a(n);
long ans[3]={0};
long x,y;
for(int i=0;i<n;i++){
cin>>a[i];
x=a[i];
for(int j=0;j<3;j++){
y=min(x,ans[j]);
ans[j]=max(x,ans[j]);
// cout<<ans[j]<<" ";
x=y;
}
}
if(ans[1]<ans[0]){
swap(ans[1],ans[0]);
}
if(ans[2]<ans[1]){
swap(ans[1],ans[2]);
}
if(ans[1]<ans[0]){
swap(ans[1],ans[0]);
}
cout<<ans[2]<<" "<<ans[1]<<" "<<ans[0]<<endl;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: function maxNumbers(arr,n) {
// write code here
// do not console.log the answer
// return the answer as an array of 3 numbers
return arr.sort((a,b)=>b-a).slice(0,3)
};
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your friend and you took a true/false exam of n questions. You know your answers, your friend’s
answers, and that your friend got k questions correct.
Compute the maximum number of questions you could have gotten correctly.The first line of input contains a single integer k.
The second line contains a string of n (1 ≤ n ≤ 1000) characters, the answers you wrote down.
Each letter is either a ‘T’ or an ‘F’.
The third line contains a string of n characters, the answers your friend wrote down. Each letter
is either a ‘T’ or an ‘F’.
The input will satisfy 0 ≤ k ≤ n.Print, on one line, the maximum number of questions you could have gotten correctly.Sample Input
3
FTFFF
TFTTT
Sample Output
2, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int k = Integer.parseInt(br.readLine());
String me = br.readLine();
String myFriend = br.readLine();
int N = me.length();
int commonAns = 0;
for(int i=0; i<N; i++) {
if(me.charAt(i) == myFriend.charAt(i) ) commonAns++;
}
int ans = Math.min(k, commonAns) + Math.min(N - k, N - commonAns);
System.out.println(ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your friend and you took a true/false exam of n questions. You know your answers, your friend’s
answers, and that your friend got k questions correct.
Compute the maximum number of questions you could have gotten correctly.The first line of input contains a single integer k.
The second line contains a string of n (1 ≤ n ≤ 1000) characters, the answers you wrote down.
Each letter is either a ‘T’ or an ‘F’.
The third line contains a string of n characters, the answers your friend wrote down. Each letter
is either a ‘T’ or an ‘F’.
The input will satisfy 0 ≤ k ≤ n.Print, on one line, the maximum number of questions you could have gotten correctly.Sample Input
3
FTFFF
TFTTT
Sample Output
2, I have written this Solution Code: k = int(input())
m = 0
a = list(map(str,input()))
b = list(map(str,input()))
#print(a,b)
n = len(b)
for i in range(n):
if a[i] == b[i]:
m += 1
if k >= m :
print(n-k+m)
else:
print(n-m+k), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature F in Farenheit, your task is to convert it into Celsius using the following equation:-
T(°c) = (T(°f) - 32)*5/9You don't have to worry about the input, you just have to complete the function <b>fahrenheitToCelsius</b>
Constraints:-
-10^3 <= F <= 10^3
<b>Note:-</b> It is guaranteed that F - 32 will be a multiple of 9.Print an integer containing converted temperature in Fahrenheit.Sample Input 1:
77
Sample Output 1:
25
Sample Input 2:-
-40
Sample Output 2:-
-40
<b>Explanation 1</b>:
T(°c) = (T(°f) - 32)*5/9
T(°c) = (77-32)*5/9
T(°c) =25, I have written this Solution Code: void farhenheitToCelsius(int n){
n-=32;
n/=9;
n*=5;
cout<<n;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature F in Farenheit, your task is to convert it into Celsius using the following equation:-
T(°c) = (T(°f) - 32)*5/9You don't have to worry about the input, you just have to complete the function <b>fahrenheitToCelsius</b>
Constraints:-
-10^3 <= F <= 10^3
<b>Note:-</b> It is guaranteed that F - 32 will be a multiple of 9.Print an integer containing converted temperature in Fahrenheit.Sample Input 1:
77
Sample Output 1:
25
Sample Input 2:-
-40
Sample Output 2:-
-40
<b>Explanation 1</b>:
T(°c) = (T(°f) - 32)*5/9
T(°c) = (77-32)*5/9
T(°c) =25, I have written this Solution Code: Fahrenheit= int(input())
Celsius = int(((Fahrenheit-32)*5)/9 )
print(Celsius), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature F in Farenheit, your task is to convert it into Celsius using the following equation:-
T(°c) = (T(°f) - 32)*5/9You don't have to worry about the input, you just have to complete the function <b>fahrenheitToCelsius</b>
Constraints:-
-10^3 <= F <= 10^3
<b>Note:-</b> It is guaranteed that F - 32 will be a multiple of 9.Print an integer containing converted temperature in Fahrenheit.Sample Input 1:
77
Sample Output 1:
25
Sample Input 2:-
-40
Sample Output 2:-
-40
<b>Explanation 1</b>:
T(°c) = (T(°f) - 32)*5/9
T(°c) = (77-32)*5/9
T(°c) =25, I have written this Solution Code: static void farhrenheitToCelsius(int farhrenheit)
{
int celsius = ((farhrenheit-32)*5)/9;
System.out.println(celsius);
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args){
FastReader read = new FastReader();
int a = read.nextInt();
int b = read.nextInt();
System.out.println(a+b);
System.out.println(a-b);
System.out.println(a*b);
System.out.println(a/b);
}
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader(){
InputStreamReader inr = new InputStreamReader(System.in);
br = new BufferedReader(inr);
}
String next(){
while(st==null || !st.hasMoreElements())
try{
st = new StringTokenizer(br.readLine());
}
catch(IOException e){
e.printStackTrace();
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
double nextDouble(){
return Double.parseDouble(next());
}
long nextLong(){
return Long.parseLong(next());
}
String nextLine(){
String str = "";
try{
str = br.readLine();
}
catch(IOException e){
e.printStackTrace();
}
return str;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers <b>a</b> and <b>b</b>, your task is to calculate and print the following four values:-
a+b
a-b
a*b
a/bThe input contains two integers a and b separated by spaces.
<b>Constraints:</b>
1 ≤ b ≤ a ≤ 1000
<b> It is guaranteed that a will be divisible by b</b>Print the mentioned operations each in a new line.Sample Input:
15 3
Sample Output:
18
12
45
5
<b>Explanation:-</b>
First operation is a+b so 15+3 = 18
The second Operation is a-b so 15-3 = 12
Third Operation is a*b so 15*3 = 45
Fourth Operation is a/b so 15/3 = 5, I have written this Solution Code: a,b=map(int,input().split())
print(a+b)
print(a-b)
print(a*b)
print(a//b), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code: static int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code:
int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code: import array as arr
def King(X, Y):
a = arr.array('i', [0,0,1,1,1,-1,-1,-1])
b = arr.array('i', [-1,1,1,-1,0,1,-1,0])
cnt=0
for i in range (0,8):
if(X+a[i]<=8 and X+a[i]>=1 and Y+b[i]>=1 and Y+b[i]<=8):
cnt=cnt+1
return cnt
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the position of the king in an 8X8 chessboard. Your task is to find the number of positions King can go into in one move.
Note:-
Remember king can move in all eight directions but can not go outside of the chess board<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>King()</b> that takes integers X, and Y as arguments.
Constraints:-
1 <= X, Y <= 8Return the number of positions King can go into in one move.Sample Input:-
2 1
Sample Output:-
5
Explanation:-
the king can go into:- (1, 1), (3, 1), (1, 2). (2, 2), (3, 2)
Sample Input:-
4 4
Sample Output:-
8, I have written this Solution Code:
int King(int X, int Y){
int a[] = {0,0,1,1,1,-1,-1,-1};
int b[] = {-1,1,1,-1,0,1,-1,0};
int cnt=0;
for(int i=0;i<8;i++){
if(X+a[i]<=8 && X+a[i]>=1 && Y+b[i]>=1 && Y+b[i]<=8){cnt++;}
}
return cnt;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Chef and Chefina are playing a game, Chef asks Chefina whether the ith bit is set in the binary representation of the number. Chefina knows how to do it but she is taking quite a lot of time. You are Chefina's friend so help her out of this situation.The first line of the input contains the test case value, T.
Next T lines contain two values N and K, i. e the number N and the Kth bit.
<b>Constraints:</b>
1 ≤ T ≤ 10<sup>5</sup>
1 ≤ N ≤ 10<sup>18</sup>
1 ≤ K ≤ 61Print "SET" if the Kth bit is set and "NOT SET" if it's not.Sample Input
2
2 1
1 1
Sample Output
NOT SET
SET
Explanation
2's binary representation : 10 hence the first bit is 0 which is not set
1's binary representation : 1 hence the first bit is 1 which is set, I have written this Solution Code: /* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int tt=Integer.parseInt(br.readLine());
while(tt > 0){
long n, k;
String s = br.readLine();
String ip[] = s.split(" ");
n = Long.parseLong(ip[0]);
k = Long.parseLong(ip[1]);
// System.out.println((n & (1 << (k - 1))));
if ((n & (1 << (k - 1))) > 0)
System.out.println("SET");
else
System.out.println("NOT SET");
tt-=1;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Chef and Chefina are playing a game, Chef asks Chefina whether the ith bit is set in the binary representation of the number. Chefina knows how to do it but she is taking quite a lot of time. You are Chefina's friend so help her out of this situation.The first line of the input contains the test case value, T.
Next T lines contain two values N and K, i. e the number N and the Kth bit.
<b>Constraints:</b>
1 ≤ T ≤ 10<sup>5</sup>
1 ≤ N ≤ 10<sup>18</sup>
1 ≤ K ≤ 61Print "SET" if the Kth bit is set and "NOT SET" if it's not.Sample Input
2
2 1
1 1
Sample Output
NOT SET
SET
Explanation
2's binary representation : 10 hence the first bit is 0 which is not set
1's binary representation : 1 hence the first bit is 1 which is set, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
#define int long long
int32_t main() {
int tt;
cin >> tt;
while (tt--) {
int n, k;
cin >> n >> k;
if (n & (1 << (k - 1)))
cout << "SET\n";
else
cout << "NOT SET\n";
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Australia hasn’t lost a Test Match at the Gabba since 1988. India has to win this one, but unfortunately all of their players are injured.
You are given the following information:
1. A total of N players are available, all are injured initially.
2. You have M magic pills. Using X pills, you can make any one player fit for match.
3. Alternatively, you can exchange any player for Y magic pills.
Compute the maximum number of players you can make fit for the Gabba Test Match.
Note: "Exchanging" a player means that player will no longer be available and you will gain Y extra magic pills for the exchangeThe input contains a single line containing 4 integers N M X Y.
Constraints:-
0 ≤ N, M, X, Y ≤ 10^9The output should contain a single integer representing the maximum number of players you can make fit before the match.Sample Input:-
5 10 2 1
Sample Output:-
5
Explanation:-
You can make all players fit if you use all the pills.
Sample Input:-
3 10 4 2
Sample Output:-
2
Explanation:-
You can make 2 players fit using the initial candies. Otherwise, Exchanging one player would result in a total of 10+2=12 magic pills. This is enough to make 3 players fit, but you won't have 3 players remaining., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String values[] = br.readLine().trim().split(" ");
long N = Long.parseLong(values[0]);
long M = Long.parseLong(values[1]);
long X = Long.parseLong(values[2]);
long Y = Long.parseLong(values[3]);
if(M/X >= N){
System.out.print(N);
return;
}
else
{
long count = M/X;
M = M % X;
N = N - count;
if(((N-1)*Y+M)<X)
System.out.print(count);
else
System.out.print(count+ N - countSacrifice(1,N,M,X,Y));
}
}
public static long countSacrifice(long min,long max,long M,long X,long Y)
{
long N = max;
while(min<max)
{ long mid = min + (max-min)/2;
if((mid*Y + M)>=((N-mid)*X))
{
max = mid;
}
else
{
min = mid+1;
}
}
return min;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Australia hasn’t lost a Test Match at the Gabba since 1988. India has to win this one, but unfortunately all of their players are injured.
You are given the following information:
1. A total of N players are available, all are injured initially.
2. You have M magic pills. Using X pills, you can make any one player fit for match.
3. Alternatively, you can exchange any player for Y magic pills.
Compute the maximum number of players you can make fit for the Gabba Test Match.
Note: "Exchanging" a player means that player will no longer be available and you will gain Y extra magic pills for the exchangeThe input contains a single line containing 4 integers N M X Y.
Constraints:-
0 ≤ N, M, X, Y ≤ 10^9The output should contain a single integer representing the maximum number of players you can make fit before the match.Sample Input:-
5 10 2 1
Sample Output:-
5
Explanation:-
You can make all players fit if you use all the pills.
Sample Input:-
3 10 4 2
Sample Output:-
2
Explanation:-
You can make 2 players fit using the initial candies. Otherwise, Exchanging one player would result in a total of 10+2=12 magic pills. This is enough to make 3 players fit, but you won't have 3 players remaining., I have written this Solution Code: import math
N,M,X,Y = map(int,input().strip().split())
low = 0
high = N
def possible(mid,M,X,Y):
if M//X >= mid:
return True
elif (N-math.ceil(((X*mid)-M)/Y))>=mid:
return True
return False
while(low<=high):
mid = (high+low)>>1
if possible(mid,M,X,Y):
res = mid
low = mid+1
else:
high = mid-1
print(res), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Australia hasn’t lost a Test Match at the Gabba since 1988. India has to win this one, but unfortunately all of their players are injured.
You are given the following information:
1. A total of N players are available, all are injured initially.
2. You have M magic pills. Using X pills, you can make any one player fit for match.
3. Alternatively, you can exchange any player for Y magic pills.
Compute the maximum number of players you can make fit for the Gabba Test Match.
Note: "Exchanging" a player means that player will no longer be available and you will gain Y extra magic pills for the exchangeThe input contains a single line containing 4 integers N M X Y.
Constraints:-
0 ≤ N, M, X, Y ≤ 10^9The output should contain a single integer representing the maximum number of players you can make fit before the match.Sample Input:-
5 10 2 1
Sample Output:-
5
Explanation:-
You can make all players fit if you use all the pills.
Sample Input:-
3 10 4 2
Sample Output:-
2
Explanation:-
You can make 2 players fit using the initial candies. Otherwise, Exchanging one player would result in a total of 10+2=12 magic pills. This is enough to make 3 players fit, but you won't have 3 players remaining., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define LL long long
void solve() {
LL n, m, x, y;
cin >> n >> m >> x >> y;
LL l = 0, r = n + 1, mid;
while(l < r-1) {
mid = (l + r) / 2;
if(mid * x <= m + (n - mid) * y) l = mid;
else r = mid;
}
cout << l << '\n';
}
int main() {
ios::sync_with_stdio(0), cin.tie(0);
int tt = 1; //cin >> tt;
while(tt--) solve();
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has A number of Pokeballs with her and there are B pokemons in front of Sara. Considering each pokemon takes one Pokeball, your task is to tell Sara if she can catch all the pokemons or not.
Sara can catch a pokemon if she is having at least one pokeball for that pokemon.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>PokemonMaster()</b> that takes integers A and B as arguments.
Constraints:-
1 <= A, B <= 8Return 1 if Sara can catch all the pokemon else return 0.Sample Input:-
4 3
Sample Output:-
1
Sample Input:-
4 6
Sample Output:-
0, I have written this Solution Code: function PokemonMaster(a,b) {
// write code here
// do no console.log the answer
// return the output using return keyword
const ans = (a - b >= 0) ? 1 : 0
return ans
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has A number of Pokeballs with her and there are B pokemons in front of Sara. Considering each pokemon takes one Pokeball, your task is to tell Sara if she can catch all the pokemons or not.
Sara can catch a pokemon if she is having at least one pokeball for that pokemon.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>PokemonMaster()</b> that takes integers A and B as arguments.
Constraints:-
1 <= A, B <= 8Return 1 if Sara can catch all the pokemon else return 0.Sample Input:-
4 3
Sample Output:-
1
Sample Input:-
4 6
Sample Output:-
0, I have written this Solution Code: def PokemonMaster(A,B):
if(A>=B):
return 1
return 0
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has A number of Pokeballs with her and there are B pokemons in front of Sara. Considering each pokemon takes one Pokeball, your task is to tell Sara if she can catch all the pokemons or not.
Sara can catch a pokemon if she is having at least one pokeball for that pokemon.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>PokemonMaster()</b> that takes integers A and B as arguments.
Constraints:-
1 <= A, B <= 8Return 1 if Sara can catch all the pokemon else return 0.Sample Input:-
4 3
Sample Output:-
1
Sample Input:-
4 6
Sample Output:-
0, I have written this Solution Code: int PokemonMaster(int A, int B){
if(A>=B){return 1;}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has A number of Pokeballs with her and there are B pokemons in front of Sara. Considering each pokemon takes one Pokeball, your task is to tell Sara if she can catch all the pokemons or not.
Sara can catch a pokemon if she is having at least one pokeball for that pokemon.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>PokemonMaster()</b> that takes integers A and B as arguments.
Constraints:-
1 <= A, B <= 8Return 1 if Sara can catch all the pokemon else return 0.Sample Input:-
4 3
Sample Output:-
1
Sample Input:-
4 6
Sample Output:-
0, I have written this Solution Code: int PokemonMaster(int A, int B){
if(A>=B){return 1;}
return 0;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has A number of Pokeballs with her and there are B pokemons in front of Sara. Considering each pokemon takes one Pokeball, your task is to tell Sara if she can catch all the pokemons or not.
Sara can catch a pokemon if she is having at least one pokeball for that pokemon.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>PokemonMaster()</b> that takes integers A and B as arguments.
Constraints:-
1 <= A, B <= 8Return 1 if Sara can catch all the pokemon else return 0.Sample Input:-
4 3
Sample Output:-
1
Sample Input:-
4 6
Sample Output:-
0, I have written this Solution Code: static int PokemonMaster(int A, int B){
if(A>=B){return 1;}
return 0;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a cubic dice with 6 faces. All the individual faces have a numbers printed on them. The numbers are in the range of 1 to 6, like any ordinary dice.
Given a number on one face of the dice , you need to print the number on the opposite face .
NOTE : In a normal dice sum of numbers on opposite faces is 7 .The first line of the input contains a single integer T, denoting the number of test cases. Then T test case follows. Each test case contains a single line of the input containing a positive integer N.
Constraints:
1 <= T <= 100
1 <= N <= 6For each testcase, print the number that is on the opposite side of the given face.Input:
2
6
2
Output:
1
5
Explanation:
Testcase 1: For dice facing number 6 opposite face will have the number 1., I have written this Solution Code: def get_opposite_face(n):
return 7-n
t = int(input())
for n in range(t):
print(get_opposite_face(int(input()))), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a cubic dice with 6 faces. All the individual faces have a numbers printed on them. The numbers are in the range of 1 to 6, like any ordinary dice.
Given a number on one face of the dice , you need to print the number on the opposite face .
NOTE : In a normal dice sum of numbers on opposite faces is 7 .The first line of the input contains a single integer T, denoting the number of test cases. Then T test case follows. Each test case contains a single line of the input containing a positive integer N.
Constraints:
1 <= T <= 100
1 <= N <= 6For each testcase, print the number that is on the opposite side of the given face.Input:
2
6
2
Output:
1
5
Explanation:
Testcase 1: For dice facing number 6 opposite face will have the number 1., I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n; cin >> n;
cout << 7-n << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a cubic dice with 6 faces. All the individual faces have a numbers printed on them. The numbers are in the range of 1 to 6, like any ordinary dice.
Given a number on one face of the dice , you need to print the number on the opposite face .
NOTE : In a normal dice sum of numbers on opposite faces is 7 .The first line of the input contains a single integer T, denoting the number of test cases. Then T test case follows. Each test case contains a single line of the input containing a positive integer N.
Constraints:
1 <= T <= 100
1 <= N <= 6For each testcase, print the number that is on the opposite side of the given face.Input:
2
6
2
Output:
1
5
Explanation:
Testcase 1: For dice facing number 6 opposite face will have the number 1., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br =new BufferedReader(new InputStreamReader(System.in));
int t=Integer.parseInt(br.readLine());
while(t-->0){
int n=Integer.parseInt(br.readLine());
System.out.println(6-n+1);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an integer array A of size N and an integer Q denoting the number of queries. Your task is to print the resultant array after applying the all queries.
The queries can be of one of the four types.
"1" Remove the first element
"2" Remove the second element
"3" Remove the last element
"4" Remove the second last element
You can be sure that the queries are always possible.First line contains an integer N - the size of array
Next line contains N space separated integers
Next line contains an integer q - the number of queries
Next line contains Q space separated integers - denoting the type of the query. These integers are in the range of 1 to 4
Constraints
1 <= N <= 100000
1 <= Ai <= 100000
1 <= Q <= 100000Print a line containing a single integer m denoting the size of array after applying all queries.
Next line should contain m space separated integers denoting the array after applying all queries.Sample Input 1:
5
1 2 3 4 5
3
1 4 2
Output:
2
2 5
Explanation:
Initial array = { 1, 2, 3, 4, 5 }
Remove the first element = { 2, 3, 4, 5 }
Remove the second last element = { 2, 3, 5 }
Remove the second element = { 2, 5 }
Sample Input 2:
3
1 2 3
1
1
Output:
2
2 3
Explanation:
Initial array = { 1, 2, 3 }
Remove the first element = { 2, 3 }, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int [] arr =new int[n];
for(int i=0;i<n;i++){
arr[i]=sc.nextInt();
}
int q = sc.nextInt();
int size = n;
int front=0;
int end=n-1;
while(q-->0){
int x = sc.nextInt();
if(x==1){
front++;
size--;
}
else if(x==2){
arr[front+1]=arr[front];
front++;
size--;
}
else if(x==3){
end--;
size--;
}
else if(x==4){
arr[end-1]=arr[end];
end--;
size--;
}
}
System.out.println(size);
for(int i=front;i<=end;i++){
System.out.print(arr[i]+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an integer array A of size N and an integer Q denoting the number of queries. Your task is to print the resultant array after applying the all queries.
The queries can be of one of the four types.
"1" Remove the first element
"2" Remove the second element
"3" Remove the last element
"4" Remove the second last element
You can be sure that the queries are always possible.First line contains an integer N - the size of array
Next line contains N space separated integers
Next line contains an integer q - the number of queries
Next line contains Q space separated integers - denoting the type of the query. These integers are in the range of 1 to 4
Constraints
1 <= N <= 100000
1 <= Ai <= 100000
1 <= Q <= 100000Print a line containing a single integer m denoting the size of array after applying all queries.
Next line should contain m space separated integers denoting the array after applying all queries.Sample Input 1:
5
1 2 3 4 5
3
1 4 2
Output:
2
2 5
Explanation:
Initial array = { 1, 2, 3, 4, 5 }
Remove the first element = { 2, 3, 4, 5 }
Remove the second last element = { 2, 3, 5 }
Remove the second element = { 2, 5 }
Sample Input 2:
3
1 2 3
1
1
Output:
2
2 3
Explanation:
Initial array = { 1, 2, 3 }
Remove the first element = { 2, 3 }, I have written this Solution Code: def task(n,arr):
if n>4:
return
else:
if n==1:
arr=arr.pop(0)
elif n==2:
arr=arr.pop(1)
elif n==3:
del arr[-1]
else:
del arr[-2]
n=int(input())
arr=list(map(int,input().split()))
q=int(input())
qarr=list(map(int,input().split()))
for i in qarr:
task(i,arr)
print(len(arr))
print(*arr), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an integer array A of size N and an integer Q denoting the number of queries. Your task is to print the resultant array after applying the all queries.
The queries can be of one of the four types.
"1" Remove the first element
"2" Remove the second element
"3" Remove the last element
"4" Remove the second last element
You can be sure that the queries are always possible.First line contains an integer N - the size of array
Next line contains N space separated integers
Next line contains an integer q - the number of queries
Next line contains Q space separated integers - denoting the type of the query. These integers are in the range of 1 to 4
Constraints
1 <= N <= 100000
1 <= Ai <= 100000
1 <= Q <= 100000Print a line containing a single integer m denoting the size of array after applying all queries.
Next line should contain m space separated integers denoting the array after applying all queries.Sample Input 1:
5
1 2 3 4 5
3
1 4 2
Output:
2
2 5
Explanation:
Initial array = { 1, 2, 3, 4, 5 }
Remove the first element = { 2, 3, 4, 5 }
Remove the second last element = { 2, 3, 5 }
Remove the second element = { 2, 5 }
Sample Input 2:
3
1 2 3
1
1
Output:
2
2 3
Explanation:
Initial array = { 1, 2, 3 }
Remove the first element = { 2, 3 }, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define endl "\n"
#define ll long long int
#define f(n) for(int i=0;i<n;i++)
#define fo(n) for(int j=0;j<n;j++)
#define foo(n) for(int i=1;i<=n;i++)
#define ff first
#define ss second
#define pb push_back
#define pii pair<int,int>
#define vi vector<int>
#define vp vector<pii>
#define test int tt; cin>>tt; while(tt--)
#define mod 1000000007
void fastio()
{
ios_base::sync_with_stdio(0); cin.tie(0);
#ifndef ONLINE_JUDGE
freopen("Input 4.txt", "r", stdin);
freopen("Output 4.txt", "w", stdout);
#endif
}
int main() {
fastio();
int n;
cin >> n;
deque<int>a;
int x;
f(n) {
cin >> x;
a.push_back(x);
}
int q;
cin >> q;
int t;
while (q--) {
cin >> t;
if (t == 1) {
a.pop_front();
}
else if (t == 2) {
int y = a.front();
a.pop_front();
a.pop_front();
a.push_front(y);
}
else if (t == 3) {
a.pop_back();
}
else {
int y = a.back();
a.pop_back();
a.pop_back();
a.push_back(y);
}
}
cout << a.size() << endl;
f(a.size()) {
cout << a[i] << " ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and M check if N candies can be divided in M people such that each person get equal number of candies.Input contains two integers N and M.
Constraints:
1 <= N <= 10^18
1 <= M <= 10^18Print "Yes" if it is possible otherwise "No".Sample Input
10 5
Sample Output
Yes
Explanation: Give 2 candies to all.
Sample Input:
4 3
Sample Output:
No, I have written this Solution Code: m,n = map(int , input().split())
if (m%n==0):
print("Yes")
else:
print("No");, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and M check if N candies can be divided in M people such that each person get equal number of candies.Input contains two integers N and M.
Constraints:
1 <= N <= 10^18
1 <= M <= 10^18Print "Yes" if it is possible otherwise "No".Sample Input
10 5
Sample Output
Yes
Explanation: Give 2 candies to all.
Sample Input:
4 3
Sample Output:
No, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n,m;
cin>>n>>m;
if(n%m==0)
cout<<"Yes";
else
cout<<"No";
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N and M check if N candies can be divided in M people such that each person get equal number of candies.Input contains two integers N and M.
Constraints:
1 <= N <= 10^18
1 <= M <= 10^18Print "Yes" if it is possible otherwise "No".Sample Input
10 5
Sample Output
Yes
Explanation: Give 2 candies to all.
Sample Input:
4 3
Sample Output:
No, I have written this Solution Code:
import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
long n = sc.nextLong();
Long m = sc.nextLong();
if(n%m==0){
System.out.print("Yes");
}
else{
System.out.print("No");
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A pair is called lucky if its sum is even and positive. Given three numbers find if there exists a lucky pair or not.The only line contains three integers a<sub>1</sub>, a<sub>2</sub>, a<sub>3</sub>
<b>Constraints:</b>
-10<sup>9</sup> <= a<sub>1</sub>, a<sub>2</sub>, a<sub>3</sub> <= 10<sup>9</sup>Print "YES" without quotes if there exists a lucky pair otherwise print "NO" without quotes.Sample Input 1:
23 32 12
Sample Output 1:
YES
Sample Input 2:
1 -1 2
Sample Output 2:
NO, I have written this Solution Code: //HEADER FILES AND NAMESPACES
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#pragma GCC target("popcnt")
using namespace std;
using namespace __gnu_pbds;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template <typename T>
using ordered_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;
// DEFINE STATEMENTS
const long long infty = 1e18;
#define num1 1000000007
#define num2 998244353
#define REP(i,a,n) for(ll i=a;i<n;i++)
#define REPd(i,a,n) for(ll i=a; i>=n; i--)
#define pb push_back
#define pob pop_back
#define fr first
#define sc second
#define fix(f,n) std::fixed<<std::setprecision(n)<<f
#define all(x) x.begin(), x.end()
#define M_PI 3.14159265358979323846
#define epsilon (double)(0.000000001)
#define popcount __builtin_popcountll
#define fileio(x) freopen("input.txt", "r", stdin); freopen(x, "w", stdout);
#define out(x) cout << ((x) ? "Yes\n" : "No\n")
#define sz(x) x.size()
typedef long long ll;
typedef long long unsigned int llu;
typedef vector<long long> vll;
typedef pair<long long, long long> pll;
typedef vector<pair<long long, long long>> vpll;
typedef vector<int> vii;
void solve(){
vector<ll>a(3);
for(ll i = 0;i<3;i++)cin >> a[i];
for(ll i = 0;i<3;i++){
for(ll j = i+1;j<3;j++){
if((a[i]+a[j])>0 && (a[i]+a[j])%2 == 0){
cout << "YES\n";
return;
}
}
}
cout << "NO\n";
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
// cout.tie(NULL);
#ifdef LOCALFLAG
freopen("Input.txt", "r", stdin);
freopen("Output2.txt", "w", stdout);
#endif
ll t = 1;
//cin >> t;
while(t--){
solve();
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: English Team has now adopted a rotation policy for two of their players: Dom and Leach.
On the first day, both of them played but, from the second day onwards, Dom plays every second day, while Leach plays every third day.
For example, on:
Day 1 - Both players play,
Day 2 - Neither of them plays,
Day 3 - Only Dom plays,
Day 4 - Only Leach plays,
Day 5 - Only Dom plays,
Day 6 - Neither of them plays,
Day 7 - Both the players play.. and so on.
Find the number of days in the interval [A, B] (A and B, both inclusive) when neither Dom nor Leach plays.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>RotationPolicy()</b> that takes integers A, and B as arguments.
Constraints:-
1 <= A, B <=100000Return the number of days when neither of the two players played the game.Sample Input:-
3 8
Sample Output:-
2
Sample Input:-
1 4
Sample Output:-
1, I have written this Solution Code:
int RotationPolicy(int A, int B){
int cnt=0;
for(int i=A;i<=B;i++){
if((i-1)%2!=0 && (i-1)%3!=0){cnt++;}
}
return cnt;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: English Team has now adopted a rotation policy for two of their players: Dom and Leach.
On the first day, both of them played but, from the second day onwards, Dom plays every second day, while Leach plays every third day.
For example, on:
Day 1 - Both players play,
Day 2 - Neither of them plays,
Day 3 - Only Dom plays,
Day 4 - Only Leach plays,
Day 5 - Only Dom plays,
Day 6 - Neither of them plays,
Day 7 - Both the players play.. and so on.
Find the number of days in the interval [A, B] (A and B, both inclusive) when neither Dom nor Leach plays.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>RotationPolicy()</b> that takes integers A, and B as arguments.
Constraints:-
1 <= A, B <=100000Return the number of days when neither of the two players played the game.Sample Input:-
3 8
Sample Output:-
2
Sample Input:-
1 4
Sample Output:-
1, I have written this Solution Code:
int RotationPolicy(int A, int B){
int cnt=0;
for(int i=A;i<=B;i++){
if((i-1)%2!=0 && (i-1)%3!=0){cnt++;}
}
return cnt;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: English Team has now adopted a rotation policy for two of their players: Dom and Leach.
On the first day, both of them played but, from the second day onwards, Dom plays every second day, while Leach plays every third day.
For example, on:
Day 1 - Both players play,
Day 2 - Neither of them plays,
Day 3 - Only Dom plays,
Day 4 - Only Leach plays,
Day 5 - Only Dom plays,
Day 6 - Neither of them plays,
Day 7 - Both the players play.. and so on.
Find the number of days in the interval [A, B] (A and B, both inclusive) when neither Dom nor Leach plays.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>RotationPolicy()</b> that takes integers A, and B as arguments.
Constraints:-
1 <= A, B <=100000Return the number of days when neither of the two players played the game.Sample Input:-
3 8
Sample Output:-
2
Sample Input:-
1 4
Sample Output:-
1, I have written this Solution Code: static int RotationPolicy(int A, int B){
int cnt=0;
for(int i=A;i<=B;i++){
if((i-1)%2!=0 && (i-1)%3!=0){cnt++;}
}
return cnt;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: English Team has now adopted a rotation policy for two of their players: Dom and Leach.
On the first day, both of them played but, from the second day onwards, Dom plays every second day, while Leach plays every third day.
For example, on:
Day 1 - Both players play,
Day 2 - Neither of them plays,
Day 3 - Only Dom plays,
Day 4 - Only Leach plays,
Day 5 - Only Dom plays,
Day 6 - Neither of them plays,
Day 7 - Both the players play.. and so on.
Find the number of days in the interval [A, B] (A and B, both inclusive) when neither Dom nor Leach plays.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>RotationPolicy()</b> that takes integers A, and B as arguments.
Constraints:-
1 <= A, B <=100000Return the number of days when neither of the two players played the game.Sample Input:-
3 8
Sample Output:-
2
Sample Input:-
1 4
Sample Output:-
1, I have written this Solution Code:
def RotationPolicy(A, B):
cnt=0
for i in range (A,B+1):
if(i-1)%2!=0 and (i-1)%3!=0:
cnt=cnt+1
return cnt
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: English Team has now adopted a rotation policy for two of their players: Dom and Leach.
On the first day, both of them played but, from the second day onwards, Dom plays every second day, while Leach plays every third day.
For example, on:
Day 1 - Both players play,
Day 2 - Neither of them plays,
Day 3 - Only Dom plays,
Day 4 - Only Leach plays,
Day 5 - Only Dom plays,
Day 6 - Neither of them plays,
Day 7 - Both the players play.. and so on.
Find the number of days in the interval [A, B] (A and B, both inclusive) when neither Dom nor Leach plays.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>RotationPolicy()</b> that takes integers A, and B as arguments.
Constraints:-
1 <= A, B <=100000Return the number of days when neither of the two players played the game.Sample Input:-
3 8
Sample Output:-
2
Sample Input:-
1 4
Sample Output:-
1, I have written this Solution Code: function RotationPolicy(a, b) {
// write code here
// do no console.log the answer
// return the output using return keyword
let count = 0
for (let i = a; i <= b; i++) {
if((i-1)%2 !== 0 && (i-1)%3 !==0){
count++
}
}
return count
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code: function numberOfDays(n)
{
let ans;
switch(n)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
ans = Number(31);
break;
case 2:
ans = Number(28);
break;
default:
ans = Number(30);
break;
}
return ans;
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code:
static void numberofdays(int M){
if(M==4 || M ==6 || M==9 || M==11){System.out.print(30);}
else if(M==2){System.out.print(28);}
else{
System.out.print(31);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Implement the function <code>correctMistake</code>, which should take a string which will be the string we want to change the mistake in, and another string which is the wrong word or character, and third string which is the correct version and return its result as a string with mistakes (Use JS In built functions)Function will take 3 args,
1) line arg which is the string with mistakes
2) incorrectWord(or char) which is the char/word which needs to be replaced
3) toBeReplacedWithChar which is a stringFunction will return string with corrected mistakesconsole. log(correctMistake("Hi World world", "world", "of coding")) // prints "Hi World of coding" since world is replaced by empty char
console. log(correctMistake("hi hi hi", "hi", "hello")) // prints "hello hello hello", I have written this Solution Code: function correctMistake(line, charToBeReplaced, what) {
// write code here
// return the output , do not use console.log here
return line.replace(new RegExp(charToBeReplaced,'g'), what)
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
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