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For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Implement the function <code>round</code>, which should take a number which can be a float(decimal)
and return its result as an integer rounded of (Use JS In built functions)Function will take a float as input (can be negative or positive)Function will return a rounded off numberconsole. log(round(1.112)) // prints 1
console. log(round(1.9)) // prints 2
console. log(round(-0.66)) // prints -1, I have written this Solution Code: function round(num){
// write code here
// return the output , do not use console.log here
return Math.round(num)
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Implement the function <code>round</code>, which should take a number which can be a float(decimal)
and return its result as an integer rounded of (Use JS In built functions)Function will take a float as input (can be negative or positive)Function will return a rounded off numberconsole. log(round(1.112)) // prints 1
console. log(round(1.9)) // prints 2
console. log(round(-0.66)) // prints -1, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.math.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
double n=sc.nextDouble();
System.out.println(Math.round(n));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, the task is to find the number of divisors of N which are divisible by 2.The input line contains T, denoting the number of testcases. First line of each testcase contains integer N
Constraints:
1 <= T <= 50
1 <= N <= 10^9For each testcase in new line, you need to print the number of divisors of N which are exactly divisble by 2Input:
2
9
8
Output
0
3, I have written this Solution Code: import math
n = int(input())
for i in range(n):
x = int(input())
count = 0
for i in range(1, int(math.sqrt(x))+1):
if x % i == 0:
if (i%2 == 0):
count+=1
if ((x/i) %2 == 0):
count+=1
print(count), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, the task is to find the number of divisors of N which are divisible by 2.The input line contains T, denoting the number of testcases. First line of each testcase contains integer N
Constraints:
1 <= T <= 50
1 <= N <= 10^9For each testcase in new line, you need to print the number of divisors of N which are exactly divisble by 2Input:
2
9
8
Output
0
3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(br.readLine());
while(t-->0){
int n = Integer.parseInt(br.readLine());
int count=0;
for(int i=1;i<=Math.sqrt(n);i++){
if(n%i == 0)
{
if(i%2==0) {
count++;
}
if(i*i != n && (n/i)%2==0) {
count++;
}
}
}
System.out.println(count);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, the task is to find the number of divisors of N which are divisible by 2.The input line contains T, denoting the number of testcases. First line of each testcase contains integer N
Constraints:
1 <= T <= 50
1 <= N <= 10^9For each testcase in new line, you need to print the number of divisors of N which are exactly divisble by 2Input:
2
9
8
Output
0
3, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int t;
cin>>t;
while(t--){
long long n;
cin>>n;
if(n&1){cout<<0<<endl;continue;}
long x=sqrt(n);
int cnt=0;
for(long long i=1;i<=x;i++){
if(!(n%i)){
if(!(i%2)){cnt++;}
if(i*i!=n){
if(!((n/i)%2)){cnt++;}
}
}
}
cout<<cnt<<endl;}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int n, m;
cin >> n >> m;
cout << __gcd(n, m);
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: def hcf(a, b):
if(b == 0):
return a
else:
return hcf(b, a % b)
li= list(map(int,input().strip().split()))
print(hcf(li[0], li[1])), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given 2 non-negative integers m and n, find gcd(m, n)
GCD of 2 integers m and n is defined as the greatest integer g such that g is a divisor of both m and n. Both m and n fit in a 32 bit signed integer.
NOTE: DO NOT USE LIBRARY FUNCTIONSInput contains two space separated integers, m and n
Constraints:-
1 < = m, n < = 10^18Output the single integer denoting the gcd of the above integers.Sample Input:
6 9
Sample Output:
3
Sample Input:-
5 6
Sample Output:-
1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] sp = br.readLine().trim().split(" ");
long m = Long.parseLong(sp[0]);
long n = Long.parseLong(sp[1]);
System.out.println(GCDAns(m,n));
}
private static long GCDAns(long m,long n){
if(m==0)return n;
if(n==0)return m;
return GCDAns(n%m,m);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: function simpleArrangement(n, arr) {
// write code here
// do not console.log
// return the output as an array
const newArr = []
// for (let i = 0; i < n; i++) {
// arr[i] += (arr[arr[i]] % n) * n;
// }
// Second Step: Divide all values by n
for (let i = 0; i < n; i++) {
newArr.push(arr[arr[i]])
}
return newArr
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: n = int(input())
a = input().split()
print(" ".join(a[int(x)] for x in a)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
String s = br.readLine();
String[] str = s.split(" ");
int arr[] = new int[n];
for(int i=0;i<n;i++){
arr[i]=Integer.parseInt(str[i]);
}
for(int i =0;i<n;i++){
System.out.print(arr[arr[i]]+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A (0 indexed) of n integers from 0 to n-1 (each integer exactly once), output an array such that A[i] becomes A[A[i]].
Make sure you don't use extra memory than the array itself.The first line of the input contains a number n, the number of integers in the array.
The second line of the input contains n numbers, the elements of A.
<b>Constraints:</b>
1 <= n <= 100000
0 <= A[i] <= n-1Output the required array of n integers.Sample Input 1:
5
4 2 3 0 1
Sample Output 1:
1 3 0 4 2
Sample Input 2:
10
9 5 1 4 7 8 0 6 3 2
Sample Output 2:
2 8 5 7 6 3 9 0 4 1
<b>Explanation 1:</b>
A[0] will be A[A[0]]=A[4]=1
A[1] will be A[A[1]]=A[2]=3
A[2] will be A[A[2]]=A[3]=0
A[3] will be A[A[3]]=A[0]=4
A[4] will be A[A[4]]=A[1]=2, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
long long n,k;
cin>>n;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
for(int i=0;i<n;i++){
cout<<a[a[i]]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You have N kilograms of fruits with you and M types of polybags to put the fruits into. The holding capacity of the i<sup>th</sup> polybag is p<sub>i</sub>. Find the minimum number of polybags required to carry all N kilograms of fruits.The first line contains two integers N and M.
The second line contains M space-separated integers.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>12</sup>
1 ≤ M ≤ 10<sup>5</sup>
1 ≤ p<sub>i</sub> ≤ 10<sup>8</sup>Print the minimum number of polybags required to carry all N-kilograms of fruits.Sample Input:
10 4
4 9 8 2
Sample Output:
2
<b>Explaination:</b>
We can carry fruits in polybag 1 and polybag 3. This will give us a total capacity of 4 + 8 = 12 kilograms which is more than that required to carry the fruits., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
long N = sc.nextLong();
int M = sc.nextInt();
int arr[] = new int[M];
for(int i=0; i<M; i++){
arr[i] = sc.nextInt();
}
Arrays.sort(arr);
int count = 0;
for(int i=arr.length-1; i>=0; i--){
if(N >= 0){
N -= arr[i];
count++;
}
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You have N kilograms of fruits with you and M types of polybags to put the fruits into. The holding capacity of the i<sup>th</sup> polybag is p<sub>i</sub>. Find the minimum number of polybags required to carry all N kilograms of fruits.The first line contains two integers N and M.
The second line contains M space-separated integers.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>12</sup>
1 ≤ M ≤ 10<sup>5</sup>
1 ≤ p<sub>i</sub> ≤ 10<sup>8</sup>Print the minimum number of polybags required to carry all N-kilograms of fruits.Sample Input:
10 4
4 9 8 2
Sample Output:
2
<b>Explaination:</b>
We can carry fruits in polybag 1 and polybag 3. This will give us a total capacity of 4 + 8 = 12 kilograms which is more than that required to carry the fruits., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
signed main(){
int n, m;
cin >> n >> m;
vector<int> a(m);
for(auto &i : a) cin >> i;
sort(a.rbegin(), a.rend());
int ans = 0, cur = 0;
for(int i = 0; i < m; i++){
ans++;
cur += a[i];
if(cur >= n){
break;
}
}
cout << ans;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The product sum of two equal length arrays num1 and num2 is equal to the sum of a[i] * b[i] for all 0 <= i < a.length (0- indexed).
For example, if num1 = [1, 2, 3, 4] and num2 = [5, 2, 3, 1], the product sum would be 1*5 + 2*2 + 3*3 + 4*1 = 22.
Given two arrays num1 and num2 of length n, return the minimum product sum if you are allowed to rearrange the order of the elements in num1.The first line of the input contains the n (size of the array)
The Second line of the input contains the array num1.
Next line of the input contains the array num2.
<b>Constraints</b>
1 <= n <= 1e5
1 <= num1[i], num2[i] <= 100Print the minimum product sum.Sample Input 1:
4
5 3 4 2
4 2 2 5
Sample Output 1:
40
Explanation :
We can rearrange num1 to become [3, 5, 4, 2]. The product sum of [3, 5, 4, 2] and [4, 2, 2, 5] is 3*4 + 5*2 + 4*2 + 2*5 = 40., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
int n = Integer.parseInt(st.nextToken());
int[] num1 = new int[n];
int[] num2 = new int[n];
int i, ans=0;
st = new StringTokenizer(br.readLine());
for(i=0;i<n;i++)
num1[i] = Integer.parseInt(st.nextToken());
st = new StringTokenizer(br.readLine());
for(i=0;i<n;i++)
num2[i] = Integer.parseInt(st.nextToken());
Arrays.sort(num1);
Arrays.sort(num2);
for(i=0;i<n;i++)
ans+= num1[i]*num2[n-i-1];
System.out.println(ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The product sum of two equal length arrays num1 and num2 is equal to the sum of a[i] * b[i] for all 0 <= i < a.length (0- indexed).
For example, if num1 = [1, 2, 3, 4] and num2 = [5, 2, 3, 1], the product sum would be 1*5 + 2*2 + 3*3 + 4*1 = 22.
Given two arrays num1 and num2 of length n, return the minimum product sum if you are allowed to rearrange the order of the elements in num1.The first line of the input contains the n (size of the array)
The Second line of the input contains the array num1.
Next line of the input contains the array num2.
<b>Constraints</b>
1 <= n <= 1e5
1 <= num1[i], num2[i] <= 100Print the minimum product sum.Sample Input 1:
4
5 3 4 2
4 2 2 5
Sample Output 1:
40
Explanation :
We can rearrange num1 to become [3, 5, 4, 2]. The product sum of [3, 5, 4, 2] and [4, 2, 2, 5] is 3*4 + 5*2 + 4*2 + 2*5 = 40., I have written this Solution Code: n = int(input())
num1 = [int(x) for x in input().split()]
num2 = [int(x) for x in input().split()]
num1.sort()
num2.sort()
res = 0
for i in range(n):
res += num1[i] * num2[n-i-1]
print(res), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: The product sum of two equal length arrays num1 and num2 is equal to the sum of a[i] * b[i] for all 0 <= i < a.length (0- indexed).
For example, if num1 = [1, 2, 3, 4] and num2 = [5, 2, 3, 1], the product sum would be 1*5 + 2*2 + 3*3 + 4*1 = 22.
Given two arrays num1 and num2 of length n, return the minimum product sum if you are allowed to rearrange the order of the elements in num1.The first line of the input contains the n (size of the array)
The Second line of the input contains the array num1.
Next line of the input contains the array num2.
<b>Constraints</b>
1 <= n <= 1e5
1 <= num1[i], num2[i] <= 100Print the minimum product sum.Sample Input 1:
4
5 3 4 2
4 2 2 5
Sample Output 1:
40
Explanation :
We can rearrange num1 to become [3, 5, 4, 2]. The product sum of [3, 5, 4, 2] and [4, 2, 2, 5] is 3*4 + 5*2 + 4*2 + 2*5 = 40., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
int32_t main() {
int n;
cin >> n;
vector<int> a(n), b(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
for (int i = 0; i < n; i++) {
cin >> b[i];
}
debug(a);
debug(b);
sort(a.begin(), a.end());
// sort(b.begin(), b.end(), greater<int>());
priority_queue<int, vector<int>> pq;
for (int i = 0; i < n; i++) {
pq.push(b[i]);
}
int sum = 0;
int i = 0;
while (pq.size() > 0) {
int x = pq.top();
sum += a[i] * x;
i += 1;
pq.pop();
}
cout << sum << "\n";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s=br.readLine().toString();
int n=Integer.parseInt(s);
int ch=0;
if(n>0){
ch=1;
}
else if(n<0) ch=-1;
switch(ch){
case 1: System.out.println("Positive");break;
case 0: System.out.println("Zero");break;
case -1: System.out.println("Negative");break;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: n = input()
if '-' in list(n):
print('Negative')
elif int(n) == 0 :
print('Zero')
else:
print('Positive'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: #include <stdio.h>
int main()
{
int num;
scanf("%d", &num);
switch (num > 0)
{
// Num is positive
case 1:
printf("Positive");
break;
// Num is either negative or zero
case 0:
switch (num < 0)
{
case 1:
printf("Negative");
break;
case 0:
printf("Zero");
break;
}
break;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers a and b. Find out which datatype is more suitable - "integer" or "double" - for storing the result of division of a and b i.e. b/a.
Integer datatype is preferred if the result can be stored without any error.Only line contains two integers a and b.
<b>Constraints</b>
1 ≤ a, b ≤ 10<sup>18</sup>Print a single string either "integer" or "double" denoting which data type is suitable.Input:
2 18
Output:
integer
Input:
3 8
Output:
double
Explanation:
18/2 = 9 which can be stored in integer data type .
8/3 = 2.6666 can not be store in integer datatype , we must use double datatype., I have written this Solution Code: import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) {
InputStream inputStream = System.in;
OutputStream outputStream = System.out;
InputReader in = new InputReader(inputStream);
OutputWriter out = new OutputWriter(outputStream);
Long a=Long.parseLong(in.next());
Long b=Long.parseLong(in.next());
if(b%a == 0){
out.print("integer");
}
else {
out.print("double");
}
out.close();
}
static class InputReader {
BufferedReader reader;
StringTokenizer tokenizer;
public InputReader(InputStream stream) {
reader = new BufferedReader(new InputStreamReader(stream), 32768);
tokenizer = null;
}
public String next() {
while (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
static class OutputWriter {
private final PrintWriter writer;
public OutputWriter(OutputStream outputStream) {
writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
}
public OutputWriter(Writer writer) {
this.writer = new PrintWriter(writer);
}
public void print(Object... objects) {
for (int i = 0; i < objects.length; i++) {
if (i != 0) {
writer.print(' ');
}
writer.print(objects[i]);
}
}
public void println(Object... objects) {
print(objects);
writer.println();
}
public void close() {
writer.close();
}
public void println(int i) {
writer.println(i);
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int T=sc.nextInt();
for(int i=0;i<T;i++)
{
int a=sc.nextInt();
int b=sc.nextInt();
int c=sc.nextInt();
if(a>b && a>c)
{
System.out.println("Alice");
}
else if(b>a && b>c)
{
System.out.println("Bob");
}
else if(c>a && c>b)
{
System.out.println("Charlie");
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: #include <bits/stdc++.h>
int main() {
int T = 0;
std::cin >> T;
while (T--) {
int A = 0, B = 0, C = 0;
std::cin >> A >> B >> C;
assert(A != B && B != C && C != A);
if (A > B && A > C) {
std::cout << "Alice" << '\n';
} else if (B > A && B > C) {
std::cout << "Bob" << '\n';
} else {
std::cout << "Charlie" << '\n';
}
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: T = int(input())
for i in range(T):
A,B,C = list(map(int,input().split()))
if A>B and A>C:
print("Alice")
elif B>A and B>C:
print("Bob")
else:
print("Charlie"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: static void printString(String stringVariable){
System.out.println(stringVariable);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: S=input()
print(S), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: void printString(string s){
cout<<s;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given marks of a student in 5 subjects. You need to find the grade that a student would get on the basis of the percentage obtained. Grades computed are as follows:
If the percentage is >= 80 then print Grade ‘A’
If the percentage is <80 and >=60 then print Grade ‘B’
If the percentage is <60 and >=40 then print Grade ‘C’
else print Grade ‘D’The input contains 5 integers separated by spaces.
<b>Constraints:</b>
1 ≤ marks ≤ 100You need to print the grade obtained by a student.Sample Input:
75 70 80 90 100
Sample Output:
A
<b>Explanation</b>
((75+70+80+90+100)/5)*100=83%
A grade.
, I have written this Solution Code: import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;
import java.io.*;
public class Main {
static final int MOD = 1000000007;
public static void main(String args[]) throws IOException {
BufferedReader br
= new BufferedReader(new InputStreamReader(System.in));
String str[] = br.readLine().trim().split(" ");
int a = Integer.parseInt(str[0]);
int b = Integer.parseInt(str[1]);
int c = Integer.parseInt(str[2]);
int d = Integer.parseInt(str[3]);
int e = Integer.parseInt(str[4]);
System.out.println(grades(a, b, c, d, e));
}
static char grades(int a, int b, int c, int d, int e)
{
int sum = a+b+c+d+e;
int per = sum/5;
if(per >= 80)
return 'A';
else if(per >= 60)
return 'B';
else if(per >= 40)
return 'C';
else
return 'D';
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given marks of a student in 5 subjects. You need to find the grade that a student would get on the basis of the percentage obtained. Grades computed are as follows:
If the percentage is >= 80 then print Grade ‘A’
If the percentage is <80 and >=60 then print Grade ‘B’
If the percentage is <60 and >=40 then print Grade ‘C’
else print Grade ‘D’The input contains 5 integers separated by spaces.
<b>Constraints:</b>
1 ≤ marks ≤ 100You need to print the grade obtained by a student.Sample Input:
75 70 80 90 100
Sample Output:
A
<b>Explanation</b>
((75+70+80+90+100)/5)*100=83%
A grade.
, I have written this Solution Code: li = list(map(int,input().strip().split()))
avg=0
for i in li:
avg+=i
avg=avg/5
if(avg>=80):
print("A")
elif(avg>=60 and avg<80):
print("B")
elif(avg>=40 and avg<60):
print("C")
else:
print("D"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: static void printString(String stringVariable){
System.out.println(stringVariable);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: S=input()
print(S), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: void printString(string s){
cout<<s;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of N integers. You have to find whether A has some subsequence of length at least 3 that is a palindrome.First line of the input contains an integer N.
The second line of the input contains N space seperated integers.
Constraints:
1 <= N <= 5000
1 <= A<sub>i</sub> <= 10<sup>9</sup>Print "YES" if A has some subseqeuence of length at least 3 that is a palindrome, else print "NO", without the quotes.Sample Input:
5
1 5 2 2 1
Sample Output:
YES
Explanation:
We pick the elements at indices 1, 3, 4, 5 (1- indexed) making the subsequence: [1, 2, 2, 1], which is a palindrome., I have written this Solution Code: def sunpal(n,a):
ok=False
for i in range(n):
for j in range(i+2,n):
if a[i]==a[j]:
ok=True
return("YES" if ok else "NO")
if __name__=="__main__":
n=int(input())
a=input().split()
res=sunpal(n,a)
print(res), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of N integers. You have to find whether A has some subsequence of length at least 3 that is a palindrome.First line of the input contains an integer N.
The second line of the input contains N space seperated integers.
Constraints:
1 <= N <= 5000
1 <= A<sub>i</sub> <= 10<sup>9</sup>Print "YES" if A has some subseqeuence of length at least 3 that is a palindrome, else print "NO", without the quotes.Sample Input:
5
1 5 2 2 1
Sample Output:
YES
Explanation:
We pick the elements at indices 1, 3, 4, 5 (1- indexed) making the subsequence: [1, 2, 2, 1], which is a palindrome., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL);
#define int long long
#define pb push_back
#define ff first
#define ss second
#define endl '\n'
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
using T = pair<int, int>;
typedef long double ld;
const int mod = 1e9 + 7;
const int INF = 1e18;
void solve(){
int N;
cin >> N;
map<int, int> mp;
string ans = "NO";
for(int i = 1; i <= N; i++) {
int a;
cin >> a;
if(mp[a] != 0 and mp[a] <= i - 2) {
ans = "YES";
}
if(mp[a] == 0) mp[a] = i;
}
cout << ans;
}
signed main(){
fast
int t = 1;
// cin >> t;
for(int i = 1; i <= t; i++){
solve();
if(i != t) cout << endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, return the number of trailing zeroes in N!.
Where N!=N*(N-1)*(N-2)....1Input contains a single integer N.
Constraints:-
1<= N <=1000000000000000Print the number of zeros in factorial(N)Sample Input
5
Sample Output
1
Explanation:-
5! = 120
number of zeroes = 1
Sample Input;
11
Sample output:
2, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static long findTrailingZeros(long n)
{
long count = 0;
for (long i = 5; n / i >= 1; i *= 5)
count += n / i;
return count;
}
static long fact(long num)
{
long sum=1;
for(int i=1;i<num;i++)
{
sum+=sum*i;
}
return sum;
}
public static void main (String[] args)throws IOException {
BufferedReader bf=new BufferedReader(new InputStreamReader(System.in));
long num=Long.parseLong(bf.readLine());
System.out.println(findTrailingZeros(num));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, return the number of trailing zeroes in N!.
Where N!=N*(N-1)*(N-2)....1Input contains a single integer N.
Constraints:-
1<= N <=1000000000000000Print the number of zeros in factorial(N)Sample Input
5
Sample Output
1
Explanation:-
5! = 120
number of zeroes = 1
Sample Input;
11
Sample output:
2, I have written this Solution Code: n=int(input())
divisible5count=0
while(n>0):
divisible5count=divisible5count+n//5
n=n//5
print(divisible5count), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, return the number of trailing zeroes in N!.
Where N!=N*(N-1)*(N-2)....1Input contains a single integer N.
Constraints:-
1<= N <=1000000000000000Print the number of zeros in factorial(N)Sample Input
5
Sample Output
1
Explanation:-
5! = 120
number of zeroes = 1
Sample Input;
11
Sample output:
2, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
long long fd(long long n)
{
// Initialize result
long long count = 0;
// Keep dividing n by powers of
// 5 and update count
for (long long i = 5; n / i >= 1; i *= 5)
count += n / i;
return count;
}
// Driver code
int main()
{
int t;
t=1;
while(t--){
long long n;
cin>>n;
cout<<fd(n)<<endl;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nishu is trying to clean a room, which is divided up into an N by N grid of squares. Each square is initially either clean or dirty. She can sweep her broom over columns of the grid. Her broom is very strange:
if she sweeps over a clean square, it will become dirty, and if she sweeps over a dirty square, it will become clean.
She wants to sweep some columns of the room to maximize the number of completely clean rows. It is not allowed to sweep over the part of the column, Nishu can only sweep the whole column.
Return the maximum number of rows that she can make completely clean.The first line of the input contains a single integer N.
The next N lines will describe the state of the room. The i- th line will contain a binary string with N characters denoting the state of the i-th row of the room. The j- th character on this line is '1' if the j- th square in the i-th row is clean, and '0' if it is dirty.
Constraints:
1<=N<=100The output should be a single line containing an integer equal to a maximum possible number of rows that are completely clean.Sample Input 1:
4
0101
1000
1111
0101
Sample output 1:
2
Explanations:
Nishu can sweep the 1st and 3rd columns. This will make the 1st and 4th row be completely clean., I have written this Solution Code: n = int(input())
arr = []
for i in range(n):
string = str(input())
string = string[:4]
arr.append(string)
rows = 0
for i in range(n):
count = 0
for j in range(n):
if arr[i] == arr[j]:
count += 1
rows = max(rows,count)
print(rows), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nishu is trying to clean a room, which is divided up into an N by N grid of squares. Each square is initially either clean or dirty. She can sweep her broom over columns of the grid. Her broom is very strange:
if she sweeps over a clean square, it will become dirty, and if she sweeps over a dirty square, it will become clean.
She wants to sweep some columns of the room to maximize the number of completely clean rows. It is not allowed to sweep over the part of the column, Nishu can only sweep the whole column.
Return the maximum number of rows that she can make completely clean.The first line of the input contains a single integer N.
The next N lines will describe the state of the room. The i- th line will contain a binary string with N characters denoting the state of the i-th row of the room. The j- th character on this line is '1' if the j- th square in the i-th row is clean, and '0' if it is dirty.
Constraints:
1<=N<=100The output should be a single line containing an integer equal to a maximum possible number of rows that are completely clean.Sample Input 1:
4
0101
1000
1111
0101
Sample output 1:
2
Explanations:
Nishu can sweep the 1st and 3rd columns. This will make the 1st and 4th row be completely clean., I have written this Solution Code: import java.util.Scanner;
public class Main
{
static String [] ar = new String[105];
public static void main(String[] args)
{
Scanner sc=new Scanner(System.in);
int n = sc.nextInt();
for(int i=0;i<n;i++){
ar[i] = sc.next();
}
int ans = 0;
for(int i=0;i<n;i++){
int counter = 0;
for(int j=0;j<n;j++){
if(ar[i].equals(ar[j]))counter++;
}
ans = Math.max(ans, counter);
}
System.out.println(ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a list of size 2*N in the form as x<sub>1</sub>->x<sub>2</sub>->x<sub>3</sub>.... x<sub>n</sub>, y<sub>1</sub>->y<sub>2</sub>->y<sub>3</sub>,.... y<sub>n</sub>, Your task is to shuffle the list in the form given as x<sub>1</sub>->y<sub>1</sub>->x<sub>2</sub>->y<sub>2</sub>,.... x<sub>n</sub>,->y<sub>n</sub>.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>shuffle()</b> that takes the head node of the linked lists as a parameter.
Constraints:-
1 ≤ N ≤ 1000Return the head of the modified list.Sample Input:-
3
1 2 3 4 5 6
Sample Output:-
1 4 2 5 3 6
Explanation:
1-> 4-> 2-> 5-> 3-> 6
, I have written this Solution Code: public static Node shuffle(Node head){
int cnt=0;
Node temp=head;
while(temp!=null){
cnt++;
temp=temp.next;
}
int p = cnt/2;
cnt=0;
temp=head;
while(cnt!=p){
temp=temp.next;
cnt++;
}
cnt=0;
Node res;
Node rem;
//return temp;
rem=head.next;
res=temp;
Node ans = head;
while(cnt!=p-1){
// System.out.println(res.data+" "+rem.data);
head.next=res;
res=res.next;
head=head.next;
head.next=rem;
rem=rem.next;
head=head.next;
cnt++;
}
head.next=res;
res=null;
return ans;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a list of size 2*N in the form as x<sub>1</sub>->x<sub>2</sub>->x<sub>3</sub>.... x<sub>n</sub>, y<sub>1</sub>->y<sub>2</sub>->y<sub>3</sub>,.... y<sub>n</sub>, Your task is to shuffle the list in the form given as x<sub>1</sub>->y<sub>1</sub>->x<sub>2</sub>->y<sub>2</sub>,.... x<sub>n</sub>,->y<sub>n</sub>.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>shuffle()</b> that takes the head node of the linked lists as a parameter.
Constraints:-
1 ≤ N ≤ 1000Return the head of the modified list.Sample Input:-
3
1 2 3 4 5 6
Sample Output:-
1 4 2 5 3 6
Explanation:
1-> 4-> 2-> 5-> 3-> 6
, I have written this Solution Code:
def shuffle(arr,size):
l=[]
for i in range(size):
print(arr[i],end=" ")
print(arr[size+i],end=" ")
size = int(input())
arr= list(map(int,input().rstrip().split()))
shuffle(arr,size), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a list of size 2*N in the form as x<sub>1</sub>->x<sub>2</sub>->x<sub>3</sub>.... x<sub>n</sub>, y<sub>1</sub>->y<sub>2</sub>->y<sub>3</sub>,.... y<sub>n</sub>, Your task is to shuffle the list in the form given as x<sub>1</sub>->y<sub>1</sub>->x<sub>2</sub>->y<sub>2</sub>,.... x<sub>n</sub>,->y<sub>n</sub>.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>shuffle()</b> that takes the head node of the linked lists as a parameter.
Constraints:-
1 ≤ N ≤ 1000Return the head of the modified list.Sample Input:-
3
1 2 3 4 5 6
Sample Output:-
1 4 2 5 3 6
Explanation:
1-> 4-> 2-> 5-> 3-> 6
, I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define max1 10001
#define MOD 1000000007
#define read(type) readInt<type>()
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
signed main()
{
int n;
cin>>n;
int a[2*n];
FOR(i,2*n){
cin>>a[i];}
FOR(i,n){
cout<<a[i]<<" "<<a[n+i]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Newton knows magic and he can mysteriously combine several items to create new items.
One day, Newton got his hand on N bars of gold. He cannot carry all of the N bars, so he used his magic to combine bars. Each gold bar has a weight represented by W<sub>i</sub> (1 ≤ i ≤ N).
In one operation, Newton can take 2 bars of gold and combine them to create a single bar of gold. The weight of the new bar is (X+Y)/2 where X and Y represent the weights of the two initial bars.
Newton will perform this operation N-1 times and in the end, he will be left with only one bar of gold.
Find out the maximum possible weight of the final bar left with Newton.The first line of the input contains a single integer N
The next line contains N space-separated integers, W<sub>1</sub>, W<sub>2</sub>, . ., W<sub>N</sub>
<b>Constraints:</b>
2 ≤ N ≤ 50
1 ≤ W<sub>i</sub> ≤ 1000Print the answer in a single line with decimal values up to 8 digits.<b>Sample Input 1:</b>
2
2 4
<b>Sample Output 1:</b>
3.00000000
<b>Sample Explanation 1:</b>
(2+4)/2 = 3
<b>Sample Input 2:</b>
3
500 300 200
<b>Sample Output 2:</b>
375.00000000
<b>Sample Explanation 2:</b>
The maximum weight can only be achieved by first combining 300 and 200 to get 250, then combining 250 with 500 to get 375., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
double N, i, x;
cin >> N;
vector<double> v(N);
for (i = 0; i < N; i++){
cin >> v.at(i) ;
}
sort( v.begin(), v.end() );
x = v.at(0);
for (i = 1; i< N; i++){
x = ( x + v.at(i) )/2;
}
cout << fixed << setprecision(8) << x << endl;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: static void printDataTypes(int a, long b, float c, double d, char e)
{
System.out.println(a);
System.out.println(b);
System.out.printf("%.2f",c);
System.out.println();
System.out.printf("%.4f",d);
System.out.println();
System.out.println(e);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: void printDataTypes(int a, long long b, float c, double d, char e){
cout<<a<<endl;
cout<<b<<endl;
cout <<fixed<< std::setprecision(2) << c << '\n';
cout <<fixed<< std::setprecision(4) << d << '\n';
cout<<e<<endl;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: a=int(input())
b=int(input())
x=float(input())
g = "{:.2f}".format(x)
d=float(input())
e = "{:.4f}".format(d)
u=input()
print(a)
print(b)
print(g)
print(e)
print(u), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N cities in a line and your initial position, you want to visit all the cities at least once. You can go to one coordinate P to P+D or P-D where D is the number of steps which you choose initially. Your task is to find the maximum value of D such that you can visit all the cities at least once.The first line of input contains two integers N and X(initial position). The second line of input contains N space separated integers representing the location of cities.
Constraints:-
1 <= N <= 100000
1 <= City[] <= 100000000Print the maximum value of D such that you can visit all the cities.Sample Input:-
3 3
1 7 11
Sample Output:-
2
Sample Input:-
3 81
33 105 57
Sample Output:-
24, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static class FastReader{
BufferedReader br;
StringTokenizer st;
public FastReader(){
br = new BufferedReader(new InputStreamReader(System.in));
}
String next(){
while (st == null || !st.hasMoreElements()){
try{
st = new StringTokenizer(br.readLine());
}
catch (IOException e){
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt(){
return Integer.parseInt(next());
}
}
static int gcd(int a, int b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
public static void main (String[] args) {
FastReader inp = new FastReader();
int n = inp.nextInt();
int x = inp.nextInt();
int[] arr = new int[n];
int result =0;
for (int i = 0 ; i < n ; i++){
arr[i] = inp.nextInt();
arr[i] = Math.abs(arr[i] - x );
if (i ==0 ){
result = arr[i];
}else{
result = gcd(result,arr[i]);
}
}
System.out.print(result);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N cities in a line and your initial position, you want to visit all the cities at least once. You can go to one coordinate P to P+D or P-D where D is the number of steps which you choose initially. Your task is to find the maximum value of D such that you can visit all the cities at least once.The first line of input contains two integers N and X(initial position). The second line of input contains N space separated integers representing the location of cities.
Constraints:-
1 <= N <= 100000
1 <= City[] <= 100000000Print the maximum value of D such that you can visit all the cities.Sample Input:-
3 3
1 7 11
Sample Output:-
2
Sample Input:-
3 81
33 105 57
Sample Output:-
24, I have written this Solution Code: import math
b = []
N, P = input().split()
N = int(N)
P=int(P)
A = input().split()
for i in range(0,N):
A[i] = int(A[i])-P
i=0
while(i<N-1):
b.append(math.gcd(A[i],A[i+1]))
i+=1
b.sort()
print (b[0]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N cities in a line and your initial position, you want to visit all the cities at least once. You can go to one coordinate P to P+D or P-D where D is the number of steps which you choose initially. Your task is to find the maximum value of D such that you can visit all the cities at least once.The first line of input contains two integers N and X(initial position). The second line of input contains N space separated integers representing the location of cities.
Constraints:-
1 <= N <= 100000
1 <= City[] <= 100000000Print the maximum value of D such that you can visit all the cities.Sample Input:-
3 3
1 7 11
Sample Output:-
2
Sample Input:-
3 81
33 105 57
Sample Output:-
24, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
int main(){
int n,k;
cin>>n>>k;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
sort(a,a+n);
int ans = abs(a[0]-k);
for(int i=1;i<n;i++){
ans=__gcd(ans,a[i]-a[i-1]);
}
cout<<ans;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code: static int focal_length(int R, char Mirror)
{
int f=R/2;
if((R%2==1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code:
int focal_length(int R, char Mirror)
{
int f=R/2;
if((R&1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code:
int focal_length(int R, char Mirror)
{
int f=R/2;
if((R&1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code: def focal_length(R,Mirror):
f=R/2;
if(Mirror == ')'):
f=-f
if R%2==1:
f=f-1
return int(f)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two sorted array your task is to merge these two arrays into a single array such that the merged array is also sortedFirst line contain two integers N and M the size of arrays
Second line contains N separated integers the elements of first array
Third line contains M separated integers elements of second array
<b>Constraints:-</b>
1<=N,M<=10<sup>4</sup>
1<=arr1[], arr2[] <=10<sup>5</sup>Output the merged arraySample Input:-
3 4
1 4 7
1 3 3 9
Sample Output:-
1 1 3 3 4 7 9
, I have written this Solution Code: n1,m1=input().split()
n=int(n1)
m=int(m1)
l1=list(map(int,input().strip().split()))
l2=list(map(int,input().strip().split()))
i,j=0,0
while i<n and j<m:
if l1[i]<=l2[j]:
print(l1[i],end=" ")
i+=1
else:
print(l2[j],end=" ")
j+=1
for a in range(i,n):
print(l1[a],end=" ")
for b in range(j,m):
print(l2[b],end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two sorted array your task is to merge these two arrays into a single array such that the merged array is also sortedFirst line contain two integers N and M the size of arrays
Second line contains N separated integers the elements of first array
Third line contains M separated integers elements of second array
<b>Constraints:-</b>
1<=N,M<=10<sup>4</sup>
1<=arr1[], arr2[] <=10<sup>5</sup>Output the merged arraySample Input:-
3 4
1 4 7
1 3 3 9
Sample Output:-
1 1 3 3 4 7 9
, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define max1 10000001
int main(){
int n,m;
cin>>n>>m;
int a[n];
int b[m];
for(int i=0;i<n;i++){
cin>>a[i];
}
for(int i=0;i<m;i++){
cin>>b[i];
}
int c[n+m];
int i=0,j=0,k=0;
while(i!=n && j!=m){
if(a[i]<b[j]){c[k]=a[i];k++;i++;}
else{c[k]=b[j];j++;k++;}
}
while(i!=n){
c[k]=a[i];
k++;i++;
}
while(j!=m){
c[k]=b[j];
k++;j++;
}
for(i=0;i<n+m;i++){
cout<<c[i]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two sorted array your task is to merge these two arrays into a single array such that the merged array is also sortedFirst line contain two integers N and M the size of arrays
Second line contains N separated integers the elements of first array
Third line contains M separated integers elements of second array
<b>Constraints:-</b>
1<=N,M<=10<sup>4</sup>
1<=arr1[], arr2[] <=10<sup>5</sup>Output the merged arraySample Input:-
3 4
1 4 7
1 3 3 9
Sample Output:-
1 1 3 3 4 7 9
, I have written this Solution Code:
import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int m = sc.nextInt();
int a[] = new int[n];
int b[] = new int[m];
for(int i=0;i<n;i++){
a[i]=sc.nextInt();
}
for(int i=0;i<m;i++){
b[i]=sc.nextInt();
}
int c[]=new int[n+m];
int i=0,j=0,k=0;
while(i!=n && j!=m){
if(a[i]<b[j]){c[k]=a[i];k++;i++;}
else{c[k]=b[j];j++;k++;}
}
while(i!=n){
c[k]=a[i];
k++;i++;
}
while(j!=m){
c[k]=b[j];
k++;j++;
}
for(i=0;i<n+m;i++){
System.out.print(c[i]+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A Tribonacci number T(n) is the sum of the preceding three elements in a series.
Calculate the value of the nth Tribonacci number modulo 1000000007. The initial three numbers of this series will be a, b and c i.e., T(1)=a, T(2)=b, T(3)=c.The only line of input contains 4 integers n, a, b, c.
Constraints
4 ≤ n ≤ 10^5
1 ≤ a, b, c ≤ 1000000000Print the result containing one integer i.e., T(n) modulo 1000000007.Input1:
5 1 2 3
Output1:
11
Input2:
4 1 1 1
Output2:
3
Explanation(might now be the optimal solution):
Input 1:
Follow the below steps:-
T(1) = 1
T(2) = 2
T(3) = 3
T(4) = 6
T(5) = 11, I have written this Solution Code: n,a,b,c = map(int, input().split())
m = 1000000007
result = 0
while n > 3:
result = (a%m + b%m + c%m)%m
a = b
b = c
c = result
n -= 1
print(result), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A Tribonacci number T(n) is the sum of the preceding three elements in a series.
Calculate the value of the nth Tribonacci number modulo 1000000007. The initial three numbers of this series will be a, b and c i.e., T(1)=a, T(2)=b, T(3)=c.The only line of input contains 4 integers n, a, b, c.
Constraints
4 ≤ n ≤ 10^5
1 ≤ a, b, c ≤ 1000000000Print the result containing one integer i.e., T(n) modulo 1000000007.Input1:
5 1 2 3
Output1:
11
Input2:
4 1 1 1
Output2:
3
Explanation(might now be the optimal solution):
Input 1:
Follow the below steps:-
T(1) = 1
T(2) = 2
T(3) = 3
T(4) = 6
T(5) = 11, I have written this Solution Code:
import java.io.*;
import java.util.*;
class Main
{
static int mod = 1000000007;
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
//int t = Integer.parseInt(read.readLine());
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
long a =Long.parseLong(str[1]);
long b = Long.parseLong(str[2]);
long c = Long.parseLong(str[3]);
long dp[] = new long[n];
dp[0] = a;
dp[1] = b;
dp[2] = c;
for(int i = 3; i < n; i++)
{
dp[i] = (dp[i-1]%mod + dp[i-2]%mod + dp[i-3]%mod)%mod;
}
System.out.println(dp[n-1]);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A Tribonacci number T(n) is the sum of the preceding three elements in a series.
Calculate the value of the nth Tribonacci number modulo 1000000007. The initial three numbers of this series will be a, b and c i.e., T(1)=a, T(2)=b, T(3)=c.The only line of input contains 4 integers n, a, b, c.
Constraints
4 ≤ n ≤ 10^5
1 ≤ a, b, c ≤ 1000000000Print the result containing one integer i.e., T(n) modulo 1000000007.Input1:
5 1 2 3
Output1:
11
Input2:
4 1 1 1
Output2:
3
Explanation(might now be the optimal solution):
Input 1:
Follow the below steps:-
T(1) = 1
T(2) = 2
T(3) = 3
T(4) = 6
T(5) = 11, I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e3+ 5;
const int mod = 1e9 + 7;
const int inf = 1e18 + 9;
void solve(){
int n, a, b, c;
cin >> n >> a >> b >> c;
for(int i = 4; i <= n; i++){
int x = (a + b + c) % mod;
a = b;
b = c;
c = x;
}
cout << c << endl;
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
clock_t start = clock();
testcases();
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms" << endl;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print the pattern as shown in example:-
For n=5, the pattern is:
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>pattern_making()</b> that takes the integer n as parameter.
Constraints:-
1 <= n <= 100Print the pattern as shown.Sample Input:-
5
Sample output:-
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
Sample Input:-
2
Sample Output:-
1
1 2 1
1, I have written this Solution Code: void pattern_making(int n){
for(int i=1;i<=n;i++){
for(int j=1;j<=i;j++){
cout<<j<<" ";
}
for(int j=i-1;j>=1;j--){
cout<<j<<" ";
}
cout<<endl;
}
for(int i=n-1;i>=1;i--){
for(int j=1;j<=i;j++){
cout<<j<<" ";
}
for(int j=i-1;j>=1;j--){
cout<<j<<" ";
}
cout<<endl;
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print the pattern as shown in example:-
For n=5, the pattern is:
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>pattern_making()</b> that takes the integer n as parameter.
Constraints:-
1 <= n <= 100Print the pattern as shown.Sample Input:-
5
Sample output:-
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
Sample Input:-
2
Sample Output:-
1
1 2 1
1, I have written this Solution Code:
void pattern_making(int n){
for(int i=1;i<=n;i++){
for(int j=1;j<=i;j++){
printf("%d ",j);
}
for(int j=i-1;j>=1;j--){
printf("%d ",j);
}
printf("\n");
}
for(int i=n-1;i>=1;i--){
for(int j=1;j<=i;j++){
printf("%d ",j);
}
for(int j=i-1;j>=1;j--){
printf("%d ",j);
}
printf("\n");
}
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print the pattern as shown in example:-
For n=5, the pattern is:
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>pattern_making()</b> that takes the integer n as parameter.
Constraints:-
1 <= n <= 100Print the pattern as shown.Sample Input:-
5
Sample output:-
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
Sample Input:-
2
Sample Output:-
1
1 2 1
1, I have written this Solution Code: public static void pattern_making(int n){
for(int i=1;i<=n;i++){
for(int j=1;j<=i;j++){
System.out.print(j+" ");
}
for(int j=i-1;j>=1;j--){
System.out.print(j+" ");
}
System.out.println();
}
for(int i=n-1;i>=1;i--){
for(int j=1;j<=i;j++){
System.out.print(j+" ");
}
for(int j=i-1;j>=1;j--){
System.out.print(j+" ");
}
System.out.println();
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print the pattern as shown in example:-
For n=5, the pattern is:
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>pattern_making()</b> that takes the integer n as parameter.
Constraints:-
1 <= n <= 100Print the pattern as shown.Sample Input:-
5
Sample output:-
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
Sample Input:-
2
Sample Output:-
1
1 2 1
1, I have written this Solution Code: function patternMaking(N)
{
for(let j=1; j <= 2*N - 1; j++) {
let k;
if(j<= N) {
k = j;
} else {
k = 2*N - j;
}
let res = "";
for(let i=1; i<=2*k-1; i++) {
if(i<=k) {
res += i + " ";
} else {
res += 2*k - i + " ";
}
}
console.log(res);
}
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print the pattern as shown in example:-
For n=5, the pattern is:
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>pattern_making()</b> that takes the integer n as parameter.
Constraints:-
1 <= n <= 100Print the pattern as shown.Sample Input:-
5
Sample output:-
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
Sample Input:-
2
Sample Output:-
1
1 2 1
1, I have written this Solution Code: def pattern_making(n):
for i in range(1, n+1):
for j in range(1, i+1):
print(j,end=" ")
for j in range (1,i):
print(i-j,end=" ")
print("\r")
i=n-1
while i>=1 :
for j in range(1, i+1):
print(j,end=" ")
for j in range (1,i):
print(i-j,end=" ")
print("\r")
i=i-1
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a sorted array A having N integer elements, find if there exists any pair of elements such that (A[i], A[j]) have the sum equal to X (i < j)The first line of input contains T, denoting the number of testcases. The first line of each test case contains N size of array and X. Second line contains elements of array separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 100000
1 <= X <= 1000
1 <= A[i] <= 1000000For each test case you need to print "Yes" if pair exists otherwise "No".Input:
2
5 4
1 2 3 4 5
5 6
2 3 5 7 8
Output:
Yes
No, I have written this Solution Code: t=int(input())
while(t>0):
n,s=[int(i) for i in input().split()]
arr = [int(i) for i in input().split()]
i=0;j=n-1;c=0;
while i<j:
if((arr[i]+arr[j])==s):
c=1
break
if((arr[i]+arr[j])<s):
i+=1
else:
j-=1
if c==1:
print("Yes")
else:
print("No")
t-=1, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a sorted array A having N integer elements, find if there exists any pair of elements such that (A[i], A[j]) have the sum equal to X (i < j)The first line of input contains T, denoting the number of testcases. The first line of each test case contains N size of array and X. Second line contains elements of array separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 100000
1 <= X <= 1000
1 <= A[i] <= 1000000For each test case you need to print "Yes" if pair exists otherwise "No".Input:
2
5 4
1 2 3 4 5
5 6
2 3 5 7 8
Output:
Yes
No, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main(String args[])throws IOException
{
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine());
while(t-- > 0)
{
String s[] = read.readLine().trim().split("\\s+");
int n = Integer.parseInt(s[0]);
int k = Integer.parseInt(s[1]);
int arr[] = new int[n];
String st[] = read.readLine().trim().split("\\s+");
for(int i = 0; i < n; i++)
{
arr[i] = Integer.parseInt(st[i]);
}
System.out.println(isPair(arr, n, k)? "Yes" : "No");
}
}
static boolean isPair(int A[], int N, int X)
{
int i = 0; // represents first pointer
int j = N - 1; // represents second pointer
while (i < j) {
// If we find a pair
if (A[i] + A[j] == X)
return true;
else if (A[i] + A[j] < X)
i++;
else j--;
}
return false;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a sorted array A having N integer elements, find if there exists any pair of elements such that (A[i], A[j]) have the sum equal to X (i < j)The first line of input contains T, denoting the number of testcases. The first line of each test case contains N size of array and X. Second line contains elements of array separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 100000
1 <= X <= 1000
1 <= A[i] <= 1000000For each test case you need to print "Yes" if pair exists otherwise "No".Input:
2
5 4
1 2 3 4 5
5 6
2 3 5 7 8
Output:
Yes
No, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int t;
cin>>t;
while(t--){
vector<long> pos,neg;
int n;
cin>>n;
long x;
cin>>x;
long long a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
int i=0,j=n-1;
while(i!=j){
if((a[i]+a[j])>x){j--;}
else if((a[i]+a[j])<x){i++;}
else {cout<<"Yes"<<endl;goto f;}
}
cout<<"No"<<endl;
f:;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a positive integer N, we define the set A<sub>N</sub> as {1, 2, 3, ... N-1, N}.
Find the size of the largest subset of A<sub>N</sub>, such that if x belongs to the subset, then 2x does not belong to the subset.The first line of the input contains a single integer T — the number of test cases.
Each test case consists of one line containing a single integer N.
<b>Constraints:</b>
1 ≤ T ≤ 10<sup>5</sup>
1 ≤ N ≤ 10<sup>9</sup>For each test case, print one integer — the size of the largest subset of A<sub>N</sub> satisfying the condition in the problem statement.Sample Input:
4
1
2
3
4
Sample Output:
1
1
2
3
Explanation:
For test case 4, where N = 4, the subset {1, 3, 4} is the largest subset satisfying the conditions.
1 is in the subset whereas 2 is not.
3 is in the subset whereas 6 is not.
4 is in the subset whereas 8 is not., I have written this Solution Code: import java.io.*;
import java.util.*;
public class Main {
static BufferedReader br;
static long compute(long n){
if(n==1||n==2) return 1;
if(n==3) return 2;
if(n%2==0){
long ans=(n/2);
return ans+compute(ans/2);
}
else {
long ans=(n+1)/2;
if(ans%2==1) return ans+compute(ans/2);
else return ans+compute((ans/2)-1);
}
}
public static void main(String[] args) throws Exception
{
br= new BufferedReader(new InputStreamReader(System.in));
PrintWriter pw = new PrintWriter(System.out);
int t=Integer.parseInt(br.readLine());
while(t-->0){
long n=Long.parseLong(br.readLine());
long ans=compute(n);
pw.println(ans);
}
pw.flush();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a positive integer N, we define the set A<sub>N</sub> as {1, 2, 3, ... N-1, N}.
Find the size of the largest subset of A<sub>N</sub>, such that if x belongs to the subset, then 2x does not belong to the subset.The first line of the input contains a single integer T — the number of test cases.
Each test case consists of one line containing a single integer N.
<b>Constraints:</b>
1 ≤ T ≤ 10<sup>5</sup>
1 ≤ N ≤ 10<sup>9</sup>For each test case, print one integer — the size of the largest subset of A<sub>N</sub> satisfying the condition in the problem statement.Sample Input:
4
1
2
3
4
Sample Output:
1
1
2
3
Explanation:
For test case 4, where N = 4, the subset {1, 3, 4} is the largest subset satisfying the conditions.
1 is in the subset whereas 2 is not.
3 is in the subset whereas 6 is not.
4 is in the subset whereas 8 is not., I have written this Solution Code: //Author: Xzirium
//Time and Date: 15:50:05 28 September 2021
//Optional FAST
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native")
//Required Libraries
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
//Required namespaces
using namespace std;
using namespace __gnu_pbds;
//Required defines
#define endl '\n'
#define READ(X) cin>>X;
#define READV(X) long long X; cin>>X;
#define READAR(A,N) long long A[N]; for(long long i=0;i<N;i++) {cin>>A[i];}
#define rz(A,N) A.resize(N);
#define sz(X) (long long)(X.size())
#define pb push_back
#define pf push_front
#define fi first
#define se second
#define FORI(a,b,c) for(long long a=b;a<c;a++)
#define FORD(a,b,c) for(long long a=b;a>c;a--)
//Required typedefs
template <typename T> using ordered_set = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
template <typename T> using ordered_set1 = tree<T,null_type,greater<T>,rb_tree_tag,tree_order_statistics_node_update>;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<long long,long long> pll;
//Required Constants
const long long inf=(long long)1e18;
const long long MOD=(long long)(1e9+7);
const long long INIT=(long long)(1e6+1);
const long double PI=3.14159265358979;
// Required random number generators
// mt19937 gen_rand_int(chrono::steady_clock::now().time_since_epoch().count());
// mt19937_64 gen_rand_ll(chrono::steady_clock::now().time_since_epoch().count());
//Required Functions
ll power(ll b, ll e)
{
ll r = 1ll;
for(; e > 0; e /= 2, (b *= b) %= MOD)
if(e % 2) (r *= b) %= MOD;
return r;
}
ll modInverse(ll a)
{
return power(a,MOD-2);
}
//Work
int main()
{
#ifndef ONLINE_JUDGE
if (fopen("INPUT.txt", "r"))
{
freopen ("INPUT.txt" , "r" , stdin);
//freopen ("OUTPUT.txt" , "w" , stdout);
}
#endif
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
clock_t clk;
clk = clock();
//-----------------------------------------------------------------------------------------------------------//
READV(T);
while(T--)
{
READV(N);
ll ans=0;
while (N>0)
{
ans+=(N+1)/2;
N=N/4;
}
cout<<ans<<endl;
}
//-----------------------------------------------------------------------------------------------------------//
clk = clock() - clk;
cerr << fixed << setprecision(6) << "Time: " << ((double)clk)/CLOCKS_PER_SEC << endl;
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[ ] of size N containing positive integers, find maximum and minimum elements from the array.The first line of input contains an integer T, denoting the number of testcases. The description of T testcases follows. The first line of each testcase contains a single integer N denoting the size of array. The second line contains N space-separated integers denoting the elements of the array.
Constraints:
1 <= T <= 100
1 <= N <= 10^5
1 <= A[i] <= 10^7For each testcase you need to print the maximum and minimum element found separated by space.Sample Input:
2
5
7 3 4 5 6
4
1 2 3 4
Sample Output:
7 3
4 1
, I have written this Solution Code: def solve(a):
maxi = 0
mini = 1e7+1
for i in a:
if(i < mini):
mini = i
if(i > maxi):
maxi = i
return mini,maxi, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[ ] of size N containing positive integers, find maximum and minimum elements from the array.The first line of input contains an integer T, denoting the number of testcases. The description of T testcases follows. The first line of each testcase contains a single integer N denoting the size of array. The second line contains N space-separated integers denoting the elements of the array.
Constraints:
1 <= T <= 100
1 <= N <= 10^5
1 <= A[i] <= 10^7For each testcase you need to print the maximum and minimum element found separated by space.Sample Input:
2
5
7 3 4 5 6
4
1 2 3 4
Sample Output:
7 3
4 1
, I have written this Solution Code:
import java.io.*;
import java.util.*;
class Main
{
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine());
while (t-- > 0) {
int n = Integer.parseInt(read.readLine());
int[] arr = new int[n];
String str[] = read.readLine().trim().split(" ");
for(int i = 0; i < n; i++)
arr[i] = Integer.parseInt(str[i]);
findMinMax(arr, n);
System.out.println();
}
}
public static void findMinMax(int arr[], int n)
{
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
for(int i = 0; i < n; i++)
{
min = Math.min(arr[i], min);
max = Math.max(arr[i], max);
}
System.out.print(max + " " + min);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Let us start our journey by creating a 'PROFILE' table for storing the data of the users of our platform. Create a table profile with 3 fields ( USERNAME VARCHAR (24), FULL_NAME VARCHAR (72), HEADLINE VARCHAR (72) ).
<schema>[{'name': 'PROFILE', 'columns': [{'name': 'USERNAME', 'type': 'VARCHAR (24)'}, {'name': 'FULL_NAME', 'type': 'VARCHAR (72)'}, {'name': 'HEADLINE', 'type': 'VARCHAR (72)'}]}]</schema>NA - User input does not work for this question.The output will be generated in a 2-D array format consisting of rows and columns.nan, I have written this Solution Code: CREATE TABLE PROFILE (
USERNAME VARCHAR(24),
FULL_NAME VARCHAR(72),
HEADLINE VARCHAR(72)
);
, In this Programming Language: SQL, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of N elements, for each element find the value of nearest element to the right which is having frequency greater than as that of current element. If there does not exist an answer for a position, then make the value ‘-1’.Firs line of input contains the size of the array N, next line contains N space separated integers depicting values of the array.
Constraints:-
1 < = N < = 100000
1 < = Arr[i] < = 100000For each element print the value of nearest element to the right which is having frequency greater than as that of current element. If there does not exist an answer for a position, then make the value ‘-1’Sample Input:-
6
1 2 1 3 2 1
Sample Output:-
-1 1 -1 2 1 -1
Sample Input:-
6
1 2 2 3 3 3
Sample Output:-
2 3 3 -1 -1 -1 , I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static void calculate(int arr[],int n,int freq[]){
Stack<Integer>st = new Stack<>();
st.push(0);
int res[] = new int[n];
for(int i=n-1;i>=0;i--){
while(!st.isEmpty() && freq[st.peek()]<=freq[arr[i]]){
st.pop();
}
if(st.isEmpty()){
res[i] = -1;
} else {
res[i] = st.peek();
}
st.push(arr[i]);
}
for(int i=0;i<n;i++){
System.out.print(res[i]+" ");
}
}
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
int arr[] = new int[n];
int max = -1;
String srr[] = br.readLine().split("\\s");
for(int i=0;i<n;i++){
arr[i] = Integer.parseInt(srr[i]);
if(arr[i]>max){
max = arr[i];
}
}
int freq[] = new int[max+1];
for(int i=0;i<max+1;i++){
freq[i] = 0;
}
for(int i=0;i<n;i++){
freq[arr[i]]++;
}
calculate(arr,n,freq);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of N elements, for each element find the value of nearest element to the right which is having frequency greater than as that of current element. If there does not exist an answer for a position, then make the value ‘-1’.Firs line of input contains the size of the array N, next line contains N space separated integers depicting values of the array.
Constraints:-
1 < = N < = 100000
1 < = Arr[i] < = 100000For each element print the value of nearest element to the right which is having frequency greater than as that of current element. If there does not exist an answer for a position, then make the value ‘-1’Sample Input:-
6
1 2 1 3 2 1
Sample Output:-
-1 1 -1 2 1 -1
Sample Input:-
6
1 2 2 3 3 3
Sample Output:-
2 3 3 -1 -1 -1 , I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define MOD 1000000007
#define read(type) readInt<type>()
#define max2 100001
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
int freq[max2];
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
void NFG(int a[], int n)
{
// stack data structure to store the position
// of array element
stack<int> s;
s.push(0);
int res[n] = {0};
for (int i = 0; i < n; i++)
{
if (freq[a[s.top()]] > freq[a[i]])
s.push(i);
else
{
while (s.size()!=0 && freq[a[s.top()]] < freq[a[i]])
{
res[s.top()] = a[i];
s.pop();
}
// now push the current element
s.push(i);
}
}
while (!s.empty())
{
res[s.top()] = -1;
s.pop();
}
for (int i = 0; i < n; i++)
{
// Print the res list containing next
// greater frequency element
cout << res[i] << " ";
}
}
//Driver code
signed main()
{
fast();
int n;
cin>>n;
int a[n];
FOR(i,n){
cin>>a[i];}
int max1 = 0;
for (int i = 0; i < n; i++)
{
//Getting the max element of the array
if (a[i] > max1)
{
max1 = a[i];
}
}
//Calculating frequency of each element
for (int i = 0; i < n; i++)
{
freq[a[i]]++;
}
NFG(a, n);
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has guests coming over to her house for dinner. She has a circular dining table of radius R and circular plates of radius r. Now she wonders if her table has enough space for all the guests, considering each guest takes one plate and the plate should lie completely inside the table.The input contains three space- separated integers N(Number of guests), R, and r.
Constraints:-
1 <= N <= 100
1 <= r, R <= 1000Print "Yes" if there is enough space, else print "No".Sample Input:-
4 10 4
Sample Output:-
Yes
Sample Input:-
5 10 4
Sample Output:-
No, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String a[] = br.readLine().split(" ");
double n = Integer.parseInt(a[0]);
double R = Integer.parseInt(a[1]);
double r = Integer.parseInt(a[2]);
R=R-r;
double count = 0;
double d = Math.asin(r/R);
count = Math.PI/d;
if(n<=count)
System.out.print("Yes");
else
System.out.print("No");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has guests coming over to her house for dinner. She has a circular dining table of radius R and circular plates of radius r. Now she wonders if her table has enough space for all the guests, considering each guest takes one plate and the plate should lie completely inside the table.The input contains three space- separated integers N(Number of guests), R, and r.
Constraints:-
1 <= N <= 100
1 <= r, R <= 1000Print "Yes" if there is enough space, else print "No".Sample Input:-
4 10 4
Sample Output:-
Yes
Sample Input:-
5 10 4
Sample Output:-
No, I have written this Solution Code: import math
arr = list(map(int, input().split()))
n = arr[0]
R = arr[1]
r = arr[2]
if(r>R or n>1 and (R-r)*math.sin(math.acos(-1.0)/n)+1e-8<r):
print("No")
else:
print("Yes"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara has guests coming over to her house for dinner. She has a circular dining table of radius R and circular plates of radius r. Now she wonders if her table has enough space for all the guests, considering each guest takes one plate and the plate should lie completely inside the table.The input contains three space- separated integers N(Number of guests), R, and r.
Constraints:-
1 <= N <= 100
1 <= r, R <= 1000Print "Yes" if there is enough space, else print "No".Sample Input:-
4 10 4
Sample Output:-
Yes
Sample Input:-
5 10 4
Sample Output:-
No, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main()
{
int R,r,n;
cin>>n>>R>>r;
cout<<(r>R || n>1&& (R-r)*sin(acos(-1.0)/n)+1e-8<r ?"No":"Yes");
return 0;
}
//1340
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: n=int(input())
a=map(int,input().split())
b=[]
mx=-200000
cnt=0
for i in a:
if i>mx:
cnt+=1
mx=i
print(cnt), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: function numberOfRoofs(arr)
{
let count=1;
let max = arr[0];
for(let i=1;i<arrSize;i++)
{
if(arr[i] > max)
{
count++;
max = arr[i];
}
}
return count;
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: import java.util.*;
import java.io.*;
class Main{
public static void main(String args[]){
Scanner s=new Scanner(System.in);
int n=s.nextInt();
int []a=new int[n];
for(int i=0;i<n;i++){
a[i]=s.nextInt();
}
int count=1;
int max = a[0];
for(int i=1;i<n;i++)
{
if(a[i] > max)
{
count++;
max = a[i];
}
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Joey and Chandler are super bored. So, Chandler makes up a game they can play. The game is called Chandy Game. Initially, Chandler has A candies and Joey has B candies.
In the first move Joey has to give Chandler 1 candy.
In the second move Chandler has to give Joey 2 candies.
In the third move Joey has to give Chandler 3 candies.
In the fourth move Chandler has to give Joey 4 candies.
In the fifth move Joey has to give Chandler 5 candy.
... and so on.
The game continues till one of the player can not make a move. The player who cannot make a move loses. Help them find who wins the game.Input contains two integers A and B.
Constraints:
0 <= A, B <= 10<sup>15</sup>Print "Chandler" (without quotes) if Chandler wins the game and "Joey" (without quotes) if Joey wins the game.Sample Input
2 1
Sample Output
Chandler
Explanation:
In first move Joey gives Chandler 1 candy so, Chandler has 3 candies and Joey has 0.
In second move Chandler gives Joey 2 candies so, Chandler has 1 candy and Joey has 2.
In third move Joey has to give Chandler 3 candies but he has only 2 candies so he loses., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main
{
public static void main(String args[])throws Exception
{
BufferedReader bu=new BufferedReader(new InputStreamReader(System.in));
StringBuilder sb=new StringBuilder();
String s[]=bu.readLine().split(" ");
long a=Long.parseLong(s[0]),b=Long.parseLong(s[1]);
if(a>=b) sb.append("Chandler");
else sb.append("Joey");
System.out.print(sb);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Joey and Chandler are super bored. So, Chandler makes up a game they can play. The game is called Chandy Game. Initially, Chandler has A candies and Joey has B candies.
In the first move Joey has to give Chandler 1 candy.
In the second move Chandler has to give Joey 2 candies.
In the third move Joey has to give Chandler 3 candies.
In the fourth move Chandler has to give Joey 4 candies.
In the fifth move Joey has to give Chandler 5 candy.
... and so on.
The game continues till one of the player can not make a move. The player who cannot make a move loses. Help them find who wins the game.Input contains two integers A and B.
Constraints:
0 <= A, B <= 10<sup>15</sup>Print "Chandler" (without quotes) if Chandler wins the game and "Joey" (without quotes) if Joey wins the game.Sample Input
2 1
Sample Output
Chandler
Explanation:
In first move Joey gives Chandler 1 candy so, Chandler has 3 candies and Joey has 0.
In second move Chandler gives Joey 2 candies so, Chandler has 1 candy and Joey has 2.
In third move Joey has to give Chandler 3 candies but he has only 2 candies so he loses., I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
template<class C> void mini(C&a4, C b4){a4=min(a4,b4);}
typedef unsigned long long ull;
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define mod 1000000007ll
#define pii pair<int,int>
/////////////
signed main(){
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int a,b;
cin>>a>>b;
if(a>=b)
cout<<"Chandler";
else
cout<<"Joey";
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Joey and Chandler are super bored. So, Chandler makes up a game they can play. The game is called Chandy Game. Initially, Chandler has A candies and Joey has B candies.
In the first move Joey has to give Chandler 1 candy.
In the second move Chandler has to give Joey 2 candies.
In the third move Joey has to give Chandler 3 candies.
In the fourth move Chandler has to give Joey 4 candies.
In the fifth move Joey has to give Chandler 5 candy.
... and so on.
The game continues till one of the player can not make a move. The player who cannot make a move loses. Help them find who wins the game.Input contains two integers A and B.
Constraints:
0 <= A, B <= 10<sup>15</sup>Print "Chandler" (without quotes) if Chandler wins the game and "Joey" (without quotes) if Joey wins the game.Sample Input
2 1
Sample Output
Chandler
Explanation:
In first move Joey gives Chandler 1 candy so, Chandler has 3 candies and Joey has 0.
In second move Chandler gives Joey 2 candies so, Chandler has 1 candy and Joey has 2.
In third move Joey has to give Chandler 3 candies but he has only 2 candies so he loses., I have written this Solution Code: ch,jo=map(int,input().split())
if ch>=jo:
print('Chandler')
else:
print('Joey'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: static void printString(String stringVariable){
System.out.println(stringVariable);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: S=input()
print(S), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S, your task is to print the string S.You don't have to worry about taking input, you just have to complete the function <b>printString</b>Print the string S.Sample Input 1:-
NewtonSchool
Sample Output 1:-
NewtonSchool
Sample Input 2:-
Hello
Sample Output 2:-
Hello, I have written this Solution Code: void printString(string s){
cout<<s;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc =new Scanner(System.in);
int T= sc.nextInt();
for(int i=0;i<T;i++){
int arrsize=sc.nextInt();
int max=0,secmax=0,thirdmax=0,j;
for(int k=0;k<arrsize;k++){
j=sc.nextInt();
if(j>max){
thirdmax=secmax;
secmax=max;
max=j;
}
else if(j>secmax){
thirdmax=secmax;
secmax=j;
}
else if(j>thirdmax){
thirdmax=j;
}
if(k%10000==0){
System.gc();
}
}
System.out.println(max+" "+secmax+" "+thirdmax+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: t=int(input())
while t>0:
t-=1
n=int(input())
l=list(map(int,input().strip().split()))
li=[0,0,0]
for i in l:
x=i
for j in range(0,3):
y=min(x,li[j])
li[j]=max(x,li[j])
x=y
print(li[0],end=" ")
print(li[1],end=" ")
print(li[2]), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin>>t;
while(t--){
long long n;
cin>>n;
vector<long> a(n);
long ans[3]={0};
long x,y;
for(int i=0;i<n;i++){
cin>>a[i];
x=a[i];
for(int j=0;j<3;j++){
y=min(x,ans[j]);
ans[j]=max(x,ans[j]);
// cout<<ans[j]<<" ";
x=y;
}
}
if(ans[1]<ans[0]){
swap(ans[1],ans[0]);
}
if(ans[2]<ans[1]){
swap(ans[1],ans[2]);
}
if(ans[1]<ans[0]){
swap(ans[1],ans[0]);
}
cout<<ans[2]<<" "<<ans[1]<<" "<<ans[0]<<endl;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A of size N, you need to find its maximum, 2<sup>nd</sup> maximum and 3<sup>rd</sup> maximum element.
Try solving it in O(N) per test caseThe first line of the input contains the number of test cases T.
For each test case, the first line of the input contains an integer N denoting the number of elements in the array A. The following line contains N (space-separated) elements of A.
<b>Constraints:</b>
1 <= T <= 100
3 <= N <= 10<sup>6</sup>
1 <= A[i] <= 10<sup>9</sup>
<b>Note</b>:-It is guaranteed that the sum of N over all text cases does not exceed 10<sup>6</sup>For each test case, output the first, second and third maximum elements in the array.Sample Input:
3
5
1 4 2 4 5
6
1 3 5 7 9 8
7
11 22 33 44 55 66 77
Sample Output:
5 4 4
9 8 7
77 66 55
<b>Explanation:</b>
Testcase 1:
[1 4 2 4 5]
First max = 5
Second max = 4
Third max = 4, I have written this Solution Code: function maxNumbers(arr,n) {
// write code here
// do not console.log the answer
// return the answer as an array of 3 numbers
return arr.sort((a,b)=>b-a).slice(0,3)
};
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Give integer values M and N. Using the character ‘*’ draw a rectangle of height M and breadth N.The input contains two integers M and N.
Constraints:-
3 <= M, N <= 20Print the rectangle as shown in the exampleSample Input:-
3 3
Sample Output:-
***
* *
***
Sample Input:-
5 3
Sample Output:-
***
* *
* *
* *
***, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int M=sc.nextInt();
int N=sc.nextInt();
for(int col=0;col<N;col++){
System.out.print("*");
}
System.out.println();
for(int row=0;row<M-2;row++){
System.out.print("*");
for(int col=0;col<N-2;col++){
System.out.print(" ");
}
System.out.print("*");
System.out.println();
}
for(int col=0;col<N;col++){
System.out.print("*");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Give integer values M and N. Using the character ‘*’ draw a rectangle of height M and breadth N.The input contains two integers M and N.
Constraints:-
3 <= M, N <= 20Print the rectangle as shown in the exampleSample Input:-
3 3
Sample Output:-
***
* *
***
Sample Input:-
5 3
Sample Output:-
***
* *
* *
* *
***, I have written this Solution Code: li = list(map(int,input().strip().split()))
m=li[0]
n=li[1]
for i in range(0,n):
if i==n-1:
print("*",end="\n")
else:
print("*",end="")
for i in range(1,m-1):
print("*",end="")
for j in range(0,n-2):
print(" ",end="")
print("*",end="\n")
for i in range(0,n):
print("*",end=""), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Give integer values M and N. Using the character ‘*’ draw a rectangle of height M and breadth N.The input contains two integers M and N.
Constraints:-
3 <= M, N <= 20Print the rectangle as shown in the exampleSample Input:-
3 3
Sample Output:-
***
* *
***
Sample Input:-
5 3
Sample Output:-
***
* *
* *
* *
***, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int m,n;
cin>>m>>n;
for(int i=0;i<n;i++){
cout<<'*';
}
cout<<endl;
m-=2;
while(m--){
cout<<'*';
for(int i=0;i<n-2;i++){
cout<<' ';
}
cout<<'*'<<endl;
}
for(int i=0;i<n;i++){
cout<<'*';
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: After the decimation, the world went into chaos. People had to rebuild the planet so Shield came up with a donation strategy. They feel all the rich guys need to donate more than the poor guys. So, they make a rule. They would make a donation list in which the donation of each person would be shown. But the rule is that a person can’t pay less than what has already been paid before them. Find the extra amount each person will pay, and also, tell shield the total amount of donation.The first line contains n, the total number of people donating. The next line contains n space-separated integers denoting the amount of money paid by the people. The amounts are mentioned in the order in which the people paid.
<b>Constraints:-</b>
1 <= n <= 100000
0 <= money <= 100000The first line contains the extra money that each student has to pay after their teacher applied the rule. The second line contains the total amount collected by the teacher at the end.Sample Input 1:-
10
1 2 3 2 4 3 6 6 7 6
Sample Output 1:-
0 0 0 1 0 1 0 0 0 1
43
Sample Input 2:-
7
10 20 30 40 30 20 10
Sample Output 2:-
0 0 0 0 10 20 30
220, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
InputStreamReader read = new InputStreamReader(System.in);
BufferedReader in = new BufferedReader(read);
int n = Integer.parseInt(in.readLine());
int []donationList = new int[n];
int[] defaulterList = new int[n];
long totalDonations = 0L;
StringTokenizer st = new StringTokenizer(in.readLine());
for(int i=0 ; i<n ; i++){
donationList[i] = Integer.parseInt(st.nextToken());
}
int max = Integer.MIN_VALUE;
for(int i=0; i<n; i++){
totalDonations += donationList[i];
max = Math.max(max,donationList[i]);
if(i>0){
if(donationList[i] >= max)
defaulterList[i] = 0;
else
defaulterList[i] = max - donationList[i];
}
totalDonations += defaulterList[i];
}
for(int i=0; i<n ;i++){
System.out.print(defaulterList[i]+" ");
}
System.out.println();
System.out.print(totalDonations);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: After the decimation, the world went into chaos. People had to rebuild the planet so Shield came up with a donation strategy. They feel all the rich guys need to donate more than the poor guys. So, they make a rule. They would make a donation list in which the donation of each person would be shown. But the rule is that a person can’t pay less than what has already been paid before them. Find the extra amount each person will pay, and also, tell shield the total amount of donation.The first line contains n, the total number of people donating. The next line contains n space-separated integers denoting the amount of money paid by the people. The amounts are mentioned in the order in which the people paid.
<b>Constraints:-</b>
1 <= n <= 100000
0 <= money <= 100000The first line contains the extra money that each student has to pay after their teacher applied the rule. The second line contains the total amount collected by the teacher at the end.Sample Input 1:-
10
1 2 3 2 4 3 6 6 7 6
Sample Output 1:-
0 0 0 1 0 1 0 0 0 1
43
Sample Input 2:-
7
10 20 30 40 30 20 10
Sample Output 2:-
0 0 0 0 10 20 30
220, I have written this Solution Code: n = int(input())
a = input().split()
b = int(a[0])
sum = 0
for i in a:
if int(i)<b:
print(b-int(i),end=' ')
else:
b = int(i)
print(0,end=' ')
sum = sum+b
print()
print(sum), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: After the decimation, the world went into chaos. People had to rebuild the planet so Shield came up with a donation strategy. They feel all the rich guys need to donate more than the poor guys. So, they make a rule. They would make a donation list in which the donation of each person would be shown. But the rule is that a person can’t pay less than what has already been paid before them. Find the extra amount each person will pay, and also, tell shield the total amount of donation.The first line contains n, the total number of people donating. The next line contains n space-separated integers denoting the amount of money paid by the people. The amounts are mentioned in the order in which the people paid.
<b>Constraints:-</b>
1 <= n <= 100000
0 <= money <= 100000The first line contains the extra money that each student has to pay after their teacher applied the rule. The second line contains the total amount collected by the teacher at the end.Sample Input 1:-
10
1 2 3 2 4 3 6 6 7 6
Sample Output 1:-
0 0 0 1 0 1 0 0 0 1
43
Sample Input 2:-
7
10 20 30 40 30 20 10
Sample Output 2:-
0 0 0 0 10 20 30
220, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define int long long
void solve(){
int n;
cin>>n;
int a[n];
int ma=0;
int cnt=0;
//map<int,int> m;
for(int i=0;i<n;i++){
cin>>a[i];
ma=max(ma,a[i]);
cout<<ma-a[i]<<" ";
cnt+=ma-a[i];
cnt+=a[i];
//m[a[i]]++;
}
cout<<endl;
cout<<cnt<<endl;
}
signed main(){
int t;
t=1;
while(t--){
solve();}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
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