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For this Question: You are given a NxN matrix. You need to find the <a href = "https://en.wikipedia.org/wiki/Transpose">transpose</a> of the matrix.
The matrix is of form:
a b c ...
d e f ...
g h i ...
...........
There are N elements in each row.The first line of the input contains an integer N denoting the size of the square matrix.
The next N lines contain N single-spaced integers.
<b>Constraints</b>
1 <= N <= 100
1 <=Ai <= 100000Output the transpose of the matrix in similar format as that of the input.Sample Input
2
1 3
2 2
Sample Output
1 2
3 2
Sample Input:
1 2
3 4
Sample Output:
1 3
2 4, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main
{
public static void main (String[] args) throws IOException
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int n=Integer.parseInt(br.readLine());
String arr[][]=new String[n][n];
String transpose[][]=new String[n][n];
int row;
int cols;
for(row=0;row<n;row++)
{
String rowNum=br.readLine();
String rowVals[]=rowNum.split(" ");
for(cols=0; cols<n;cols++)
{
arr[row][cols]=rowVals[cols];
}
}
for(row=0;row<n;row++)
{
for(cols=0; cols<n;cols++)
{
transpose[row][cols]=arr[cols][row];
System.out.print(transpose[row][cols]+" ");
}
System.out.println();
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a NxN matrix. You need to find the <a href = "https://en.wikipedia.org/wiki/Transpose">transpose</a> of the matrix.
The matrix is of form:
a b c ...
d e f ...
g h i ...
...........
There are N elements in each row.The first line of the input contains an integer N denoting the size of the square matrix.
The next N lines contain N single-spaced integers.
<b>Constraints</b>
1 <= N <= 100
1 <=Ai <= 100000Output the transpose of the matrix in similar format as that of the input.Sample Input
2
1 3
2 2
Sample Output
1 2
3 2
Sample Input:
1 2
3 4
Sample Output:
1 3
2 4, I have written this Solution Code: x=int(input())
l1=[]
for i in range(x):
a1=list(map(int,input().split()))
l1.append(a1)
l4=[]
for j in range(x):
l3=[]
for i in range(x):
l3.append(l1[i][j])
l4.append(l3)
for i in range(x):
for j in range(x):
print(l4[i][j], end=" ")
print(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a NxN matrix. You need to find the <a href = "https://en.wikipedia.org/wiki/Transpose">transpose</a> of the matrix.
The matrix is of form:
a b c ...
d e f ...
g h i ...
...........
There are N elements in each row.The first line of the input contains an integer N denoting the size of the square matrix.
The next N lines contain N single-spaced integers.
<b>Constraints</b>
1 <= N <= 100
1 <=Ai <= 100000Output the transpose of the matrix in similar format as that of the input.Sample Input
2
1 3
2 2
Sample Output
1 2
3 2
Sample Input:
1 2
3 4
Sample Output:
1 3
2 4, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int n;
cin>>n;
int a[n][n];
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
cin>>a[j][i];
}
}
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
cout<<a[i][j]<<" ";
}
cout<<endl;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Complete the function <strong>handleCallback</strong> which has a single argument <code>callback</code>, which may or may not be a function.
Create a <strong>try</strong>, and <strong>catch</strong> block. Call the <code>callback</code> function inside the <strong>try</strong> block. In case <code>callback</code> is not a function, an error will be thrown which should be caught in the <strong>catch</strong> block. The <code>catch</code> block should print <code>"error thrown"</code> to the console.
<strong>Note:</strong> To check the expected output, we have already created a <code>anyCallback</code> function which prints <code>"No error thrown"</code> to the console. Just add <code>anyCallback</code> function without the parenthesis, to the input field to check the result.The <strong>handleCallback</strong> function takes in one argument, which may or may not be a function.The <strong>handleCallback</strong> function prints a string <code>"error thrown"</code> in the console, if the argument is not a function, otherwise nothing should be returned or printed.<strong>Example 1:</strong> Giving no function as an argument to the function
handleCallback() // prints "error thrown"
<strong>Example 2:</strong> Giving <code>anyCallback</code> function as an argument to the function
handleCallback(anyCallback) // prints "No error thrown", I have written this Solution Code: function handleCallback(callback) {
try {
callback();
} catch (error) {
console.log("error thrown");
}
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: // arr is unsorted array
// n is the number of elements in the array
function insertionSort(arr, n) {
// write code here
// do not console.log the answer
// return sorted array
return arr.sort((a, b) => a - b)
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void insertionSort(int[] arr){
for(int i = 0; i < arr.length-1; i++){
for(int j = i+1; j < arr.length; j++){
if(arr[i] > arr[j]){
int temp = arr[j];
arr[j] = arr[i];
arr[i] = temp;
}
}
}
}
public static void main (String[] args) {
Scanner scan = new Scanner(System.in);
int T = scan.nextInt();
while(T > 0){
int n = scan.nextInt();
int arr[] = new int[n];
for(int i = 0; i<n; i++){
arr[i] = scan.nextInt();
}
insertionSort(arr);
for(int i = 0; i<n; i++){
System.out.print(arr[i] + " ");
}
System.out.println();
T--;
System.gc();
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N];
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n; cin >> n;
for(int i = 1; i <= n; i++)
cin >> a[i];
sort(a + 1, a + n + 1);
for(int i = 1; i <= n; i++)
cout << a[i] << " ";
cout << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: def InsertionSort(arr):
arr.sort()
return arr, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N and F(N) find value of F(1), if, F(i)=(F(i-1) + F(i-1))%1000000007 and 0 <= F(1) < 1000000007.First and the only line of input contains two integers N and F(N).
Constraints:
1 <= N <= 1000000000
0 <= F(N) < 1000000007Print a single integer, F(1).Sample Input 1
2 6
Sample Output 1
3
Exlpanation: F(1) = 3, F(2)=(3+3)%1000000007 = 6.
Sample Input 2
3 6
Sample Input 2
500000005
Explanation:
F(1) = 500000005
F(2) = (500000005+500000005)%1000000007 = 3
F(3)= (3+3)%1000000007 = 6, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws NumberFormatException, IOException {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st=new StringTokenizer(br.readLine());
int n=Integer.parseInt(st.nextToken());
int fn=Integer.parseInt(st.nextToken());
long ans=fn;
int P=1000000007;
long inv2n=(long)pow(pow(2,n-1,P)%P,P-2,P);
ans=((ans%P)*(inv2n%P))%P;
System.out.println((ans)%P);
}
static long pow(long x, long y,long P)
{
long res = 1l;
while (y > 0)
{
if ((y & 1) == 1)
res = (res * x)%P;
y = y >> 1;
x = (x * x)%P;
}
return res;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N and F(N) find value of F(1), if, F(i)=(F(i-1) + F(i-1))%1000000007 and 0 <= F(1) < 1000000007.First and the only line of input contains two integers N and F(N).
Constraints:
1 <= N <= 1000000000
0 <= F(N) < 1000000007Print a single integer, F(1).Sample Input 1
2 6
Sample Output 1
3
Exlpanation: F(1) = 3, F(2)=(3+3)%1000000007 = 6.
Sample Input 2
3 6
Sample Input 2
500000005
Explanation:
F(1) = 500000005
F(2) = (500000005+500000005)%1000000007 = 3
F(3)= (3+3)%1000000007 = 6, I have written this Solution Code: n,f=map(int,input().strip().split())
mod=10**9+7
m1=pow(2,n-1,mod)
m=pow(m1,mod-2,mod)
print(f*m%mod), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N and F(N) find value of F(1), if, F(i)=(F(i-1) + F(i-1))%1000000007 and 0 <= F(1) < 1000000007.First and the only line of input contains two integers N and F(N).
Constraints:
1 <= N <= 1000000000
0 <= F(N) < 1000000007Print a single integer, F(1).Sample Input 1
2 6
Sample Output 1
3
Exlpanation: F(1) = 3, F(2)=(3+3)%1000000007 = 6.
Sample Input 2
3 6
Sample Input 2
500000005
Explanation:
F(1) = 500000005
F(2) = (500000005+500000005)%1000000007 = 3
F(3)= (3+3)%1000000007 = 6, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
long long powerm(long long x, unsigned long long y, long long p)
{
long long res = 1;
x = x % p;
while (y > 0)
{
if (y & 1)
res = (res*x) % p;
y = y>>1;
x = (x*x) % p;
}
return res;
}
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n,fn;
cin>>n>>fn;
int mo=1000000007;
cout<<(fn*powerm(powerm(2,n-1,mo),mo-2,mo))%mo;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: // arr is unsorted array
// n is the number of elements in the array
function insertionSort(arr, n) {
// write code here
// do not console.log the answer
// return sorted array
return arr.sort((a, b) => a - b)
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void insertionSort(int[] arr){
for(int i = 0; i < arr.length-1; i++){
for(int j = i+1; j < arr.length; j++){
if(arr[i] > arr[j]){
int temp = arr[j];
arr[j] = arr[i];
arr[i] = temp;
}
}
}
}
public static void main (String[] args) {
Scanner scan = new Scanner(System.in);
int T = scan.nextInt();
while(T > 0){
int n = scan.nextInt();
int arr[] = new int[n];
for(int i = 0; i<n; i++){
arr[i] = scan.nextInt();
}
insertionSort(arr);
for(int i = 0; i<n; i++){
System.out.print(arr[i] + " ");
}
System.out.println();
T--;
System.gc();
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int a[N];
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n; cin >> n;
for(int i = 1; i <= n; i++)
cin >> a[i];
sort(a + 1, a + n + 1);
for(int i = 1; i <= n; i++)
cout << a[i] << " ";
cout << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array A[] of size N, containing positive integers. You need to sort the elements of array using Insertion sort algorithm.First line of the input denotes number of test cases T. First line of the testcase is the size of array N and second line consists of array elements separated by space.
Constraints:
1 <= T <= 100
1 <= N <= 10^3
1 <= A[i] <= 10^3For each testcase print the sorted array in a new line.Input:
2
5
4 1 3 9 7
10
10 9 8 7 6 5 4 3 2 1
Output:
1 3 4 7 9
1 2 3 4 5 6 7 8 9 10
Explanation:
Testcase 1: The array after perfoming insertion sort: 1 3 4 7 9.
Testcase 2: The array after performing insertion sort: 1 2 3 4 5 6 7 8 9 10., I have written this Solution Code: def InsertionSort(arr):
arr.sort()
return arr, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. The task is to print all permutations of the characters in the given string.The only line of input contains a string S with all distinct uppercase letters of the English alphabet.
Constraints:-
1<=|S|<=8Print all permutations of a given string S with single space and all permutations should be in lexicographically increasing order.Sample Input:
ABC
Sample Output:
ABC ACB BAC BCA CAB CBA, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
static ArrayList<String> solution = new ArrayList<String>();
public static char[] swap(char[] charArray, int i, int j){
char temp;
temp = charArray[i];
charArray[i] = charArray[j];
charArray[j] = temp;
return charArray;
}
public static void permute(char[] charArray, int left, int right){
if(left == right){
String str = new String(charArray);
solution.add(str);
}
else{
for(int i=left; i<=right; i++)
{
charArray = swap(charArray, left, i);
permute(charArray, left+1, right);
charArray = swap(charArray, left, i);
}
}
}
public static void main(String[] args)
{
Scanner s = new Scanner(System.in);
String str = s.nextLine();
int n = str.length();
char[] charArray = str.toCharArray();
permute(charArray, 0, n-1);
Collections.sort(solution);
for(int i = 0; i < solution.size(); i++){
System.out.print(solution.get(i)+" ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. The task is to print all permutations of the characters in the given string.The only line of input contains a string S with all distinct uppercase letters of the English alphabet.
Constraints:-
1<=|S|<=8Print all permutations of a given string S with single space and all permutations should be in lexicographically increasing order.Sample Input:
ABC
Sample Output:
ABC ACB BAC BCA CAB CBA, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
vector<string> v;
void permute(string a, int l, int r)
{
// Base case
if (l == r)
v.push_back(a);
else
{
// Permutations made
for (int i = l; i <= r; i++)
{
// Swapping done
swap(a[l], a[i]);
// Recursion called
permute(a, l+1, r);
//backtrack
swap(a[l], a[i]);
}
}
}
signed main() {
IOS;
string s;
cin >> s;
sort(s.begin(), s.end());
permute(s, 0, s.length()-1);
sort(v.begin(),v.end());
for(int i=0;i<v.size();i++)
cout<<v[i]<<" ";
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S. The task is to print all permutations of the characters in the given string.The only line of input contains a string S with all distinct uppercase letters of the English alphabet.
Constraints:-
1<=|S|<=8Print all permutations of a given string S with single space and all permutations should be in lexicographically increasing order.Sample Input:
ABC
Sample Output:
ABC ACB BAC BCA CAB CBA, I have written this Solution Code: from itertools import permutations
s = input()
l1 = list(s)
s1 = "".join(sorted(l1))
l = permutations(s1,len(s1))
for i in l:
print("".join(i),end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a year(an integer variable) as input, find if it is a leap year or not.
Note: Leap year is the year that is multiple of 4. But, if the year is a multiple of 100 and not a multiple of 400, then it is not a leap year.<b>User Task:</b>
Complete the function <b>LeapYear()</b> that takes integer n as a parameter.
<b>Constraint:</b>
1 <= n <= 5000If it is a leap year then print <b>YES</b> and if it is not a leap year, then print <b>NO</b>Sample Input:
2000
Sample Output:
YES
Sample Input:
2003
Sample Output:
NO
Sample Input:
1900
Sample Output:
NO, I have written this Solution Code: n = int(input())
if (n%4==0 and n%100!=0 or n%400==0):
print("YES")
elif n==0:
print("YES")
else:
print("NO"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a year(an integer variable) as input, find if it is a leap year or not.
Note: Leap year is the year that is multiple of 4. But, if the year is a multiple of 100 and not a multiple of 400, then it is not a leap year.<b>User Task:</b>
Complete the function <b>LeapYear()</b> that takes integer n as a parameter.
<b>Constraint:</b>
1 <= n <= 5000If it is a leap year then print <b>YES</b> and if it is not a leap year, then print <b>NO</b>Sample Input:
2000
Sample Output:
YES
Sample Input:
2003
Sample Output:
NO
Sample Input:
1900
Sample Output:
NO, I have written this Solution Code:
import java.util.Scanner;
class Main {
public static void main (String[] args)
{
//Capture the user's input
Scanner scanner = new Scanner(System.in);
//Storing the captured value in a variable
int n = scanner.nextInt();
LeapYear(n);
}
static void LeapYear(int year){
if(year%400==0 || (year%100 != 0 && year%4==0)){System.out.println("YES");}
else {
System.out.println("NO");}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an N-size array of unique integers, your task is to print the array in a waveform, i. e a1 >= a2 <= a3 >= a4 <= a5.. . print the lexicographically smallest array possible.The first line of input contains a single integer N, next line contains N space-separated integers depicting the values of the array.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Arr[i] ≤ 10<sup>9</sup>Print the array in wave form as mentioned.Sample Input :-
5
2 1 3 5 4
Sample Output:-
2 1 4 3 5
Sample Input:-
3
1 2 3
Sample Output:-
2 1 3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int N = Integer.parseInt(read.readLine());
StringTokenizer st = new StringTokenizer(read.readLine());
int[] arr = new int[N];
for(int i=0; i<N; i++) {
arr[i] = Integer.parseInt(st.nextToken());
}
Arrays.sort(arr);
StringBuilder res = new StringBuilder();
for(int i=0; i<N-1; i+=2) {
int temp = arr[i];
arr[i] = arr[i+1];
arr[i+1] = temp;
res.append(arr[i] + " ");
res.append(arr[i+1] + " ");
}
if(N % 2 != 0) {
res.append(arr[N-1]);
}
System.out.print(res);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an N-size array of unique integers, your task is to print the array in a waveform, i. e a1 >= a2 <= a3 >= a4 <= a5.. . print the lexicographically smallest array possible.The first line of input contains a single integer N, next line contains N space-separated integers depicting the values of the array.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Arr[i] ≤ 10<sup>9</sup>Print the array in wave form as mentioned.Sample Input :-
5
2 1 3 5 4
Sample Output:-
2 1 4 3 5
Sample Input:-
3
1 2 3
Sample Output:-
2 1 3, I have written this Solution Code: n = int(input())
a = list(map(int,input().strip().split()))
a.sort()
for i in range(0,n-1,2):
print("{} ".format(a[i+1]),end="")
print("{} ".format(a[i]),end="")
if n&1:
print("{} ".format(a[n-1])), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an N-size array of unique integers, your task is to print the array in a waveform, i. e a1 >= a2 <= a3 >= a4 <= a5.. . print the lexicographically smallest array possible.The first line of input contains a single integer N, next line contains N space-separated integers depicting the values of the array.
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ Arr[i] ≤ 10<sup>9</sup>Print the array in wave form as mentioned.Sample Input :-
5
2 1 3 5 4
Sample Output:-
2 1 4 3 5
Sample Input:-
3
1 2 3
Sample Output:-
2 1 3, I have written this Solution Code: #include<bits/stdc++.h>
#define int long long
using namespace std;
signed main()
{
int n,m;
cin>>n;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
sort(a,a+n);
for(int i=0;i<n-1;i+=2){
cout<<a[i+1]<<" ";
cout<<a[i]<<" ";
}
if(n&1){
cout<<a[n-1]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws Exception {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String str[]=br.readLine().split(" ");
int a[]=new int[str.length];
int sum=0;
for(int i=0;i<str.length;i++)
{
a[i]=Integer.parseInt(str[i]);
sum=sum+a[i];
}
System.out.println(sum/4);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: a,b,c,d = map(int,input().split())
print((a+b+c+d)*100//400), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two non-negative integers, A and B. You are required to print the smallest non-negative integer such that it is not equal to both A and B.The input consists of two space separated integers A and B.
Constraints:
0 ≤ A ≤ 10
0 ≤ B ≤ 10
A ≠ B
Print a single integer denoting the answer.Sample Input 1:
0 1
Sample Output 1:
2
Sample Input 2:
4 5
Sample Output 2:
0, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main
{
public static void main(String args[])throws Exception
{
BufferedReader bu=new BufferedReader(new InputStreamReader(System.in));
StringBuilder sb=new StringBuilder();
Set<Integer> set=new HashSet<>();
String s[]=bu.readLine().split(" ");
for(String x:s) set.add(Integer.parseInt(x));
int mex=0;
while(set.contains(mex)) mex++;
System.out.println(mex);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two non-negative integers, A and B. You are required to print the smallest non-negative integer such that it is not equal to both A and B.The input consists of two space separated integers A and B.
Constraints:
0 ≤ A ≤ 10
0 ≤ B ≤ 10
A ≠ B
Print a single integer denoting the answer.Sample Input 1:
0 1
Sample Output 1:
2
Sample Input 2:
4 5
Sample Output 2:
0, I have written this Solution Code: p=input()
q=list(p.split(" "))
for i in range(0,int(q[1])+2):
if(int(q[0])!=i and int(q[1])!=i):
print(i)
break, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two non-negative integers, A and B. You are required to print the smallest non-negative integer such that it is not equal to both A and B.The input consists of two space separated integers A and B.
Constraints:
0 ≤ A ≤ 10
0 ≤ B ≤ 10
A ≠ B
Print a single integer denoting the answer.Sample Input 1:
0 1
Sample Output 1:
2
Sample Input 2:
4 5
Sample Output 2:
0, I have written this Solution Code: //Author: Xzirium
//Time and Date: 15:00:01 23 April 2022
#include <bits/stdc++.h>
using namespace std;
int main()
{
#ifndef ONLINE_JUDGE
if (fopen("INPUT.txt", "r"))
{
freopen ("INPUT.txt" , "r" , stdin);
//freopen ("OUTPUT.txt" , "w" , stdout);
}
#endif
int A,B;
cin>>A>>B;
for(int i=0 ; i<=10 ; i++)
{
if(i!=A && i!=B)
{
cout<<i<<endl;
break;
}
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int T=sc.nextInt();
for(int i=0;i<T;i++)
{
int a=sc.nextInt();
int b=sc.nextInt();
int c=sc.nextInt();
if(a>b && a>c)
{
System.out.println("Alice");
}
else if(b>a && b>c)
{
System.out.println("Bob");
}
else if(c>a && c>b)
{
System.out.println("Charlie");
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: #include <bits/stdc++.h>
int main() {
int T = 0;
std::cin >> T;
while (T--) {
int A = 0, B = 0, C = 0;
std::cin >> A >> B >> C;
assert(A != B && B != C && C != A);
if (A > B && A > C) {
std::cout << "Alice" << '\n';
} else if (B > A && B > C) {
std::cout << "Bob" << '\n';
} else {
std::cout << "Charlie" << '\n';
}
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: T = int(input())
for i in range(T):
A,B,C = list(map(int,input().split()))
if A>B and A>C:
print("Alice")
elif B>A and B>C:
print("Bob")
else:
print("Charlie"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Newton's garden has N apple trees. Initially, there are A<sub>i</sub> apples attached to the ith tree. Also, there are M apples which newton has to attach to these tress for testing gravity laws.
In one minute, at most B<sub>i</sub> apples fall from the ith tree.
Help newton find the minimum time he has to wait after which he can safely sit under any apple tree.The first line contains two space-separated integers – N and M indicating the number of apple trees and the number of apples to be attached.
Each of the next N lines contains two integers A<sub>i</sub> and B<sub>i</sub> specifying the initial count of apples and rate of fall of apples per minute for ith tree.
<b> Constraints: </b>
1 <= N <= 2*10<sup>5</sup>
0 <= A<sub>i</sub> <= 10<sup>6</sup>
1 <= M, B<sub>i</sub> <= 10<sup>6</sup>Output minimum time Newton has to waitInput:
3 6
4 3
7 4
1 5
Output:
2
Explanation:
Attach 2, 1, 3 apples to 1st, 2nd, 3rd tree respectively. Then, 2, 2, 1 minutes are required for all apples to fall from 1st, 2nd, 3rd tree respectively. So, Wait time is max(2, 2, 1) = 2., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
typedef long long int ll;
const int N = 2*1e5+5;
ll n,m;
vector<ll> a(N),b(N);
bool possible(ll time) {
ll lim = 0;
for(int i=0 ; i<n ; i++) lim += b[i] * time;
ll tot = m;
for(int i=0 ; i<n ; i++) tot += a[i];
if (tot > lim) return false;
for(int i=0 ; i<n ; i++) if (a[i] > b[i]*time) return false;
return true;
}
int main(){
cin >> n >> m;
for(int i=0 ; i<n ; i++){
cin >> a[i] >> b[i];
}
ll lo = 1, hi = 2*1e6+1000;
while(hi - lo > 1) {
ll mid = (hi+lo)/2;
if (possible(mid)){
hi = mid;
}else{
lo = mid;
}
}
cout << hi << endl;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram has recently purchased an empty rectangular grid of NxM dimension. He wants to fill the grid but in a special way. His way of filling is, He choose any block which is not filled yet and fills it and the points obtained in particular step is the number of filled neighbouring block. Neighbour block denotes the block which shares some common side between them. When Ram fills all the blocks then he will stop and calculate the total number of points. Ram wants to know the maximum points he can get?The first line of the input contains a single Integer T, denoting number of test cases.
The next T lines contains two space separated integer N, M i.e dimensions of grid.
<b>Constraints</b>
1 ≤ T ≤ 100
1 ≤ N, M ≤ 1000Print the maximum number of points Ram can get.Sample Input
1
2 2
Sample Output
4
Explanation
Ram can obtain total score 4 in the following way.
First he filled top right block, point = 0;
Then he filled bottom left block, point = 0;
Then when he fill either top left and bottom right, the points obtained in both the cases will be 2 hence maximum 4 points are possible., I have written this Solution Code: t = int(input())
for _ in range(t):
a, b = list(map(int, input().split()))
count = 0
count+= 2*(a-1)*(b-1)
count+= b-1
count+= a-1
print(count), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram has recently purchased an empty rectangular grid of NxM dimension. He wants to fill the grid but in a special way. His way of filling is, He choose any block which is not filled yet and fills it and the points obtained in particular step is the number of filled neighbouring block. Neighbour block denotes the block which shares some common side between them. When Ram fills all the blocks then he will stop and calculate the total number of points. Ram wants to know the maximum points he can get?The first line of the input contains a single Integer T, denoting number of test cases.
The next T lines contains two space separated integer N, M i.e dimensions of grid.
<b>Constraints</b>
1 ≤ T ≤ 100
1 ≤ N, M ≤ 1000Print the maximum number of points Ram can get.Sample Input
1
2 2
Sample Output
4
Explanation
Ram can obtain total score 4 in the following way.
First he filled top right block, point = 0;
Then he filled bottom left block, point = 0;
Then when he fill either top left and bottom right, the points obtained in both the cases will be 2 hence maximum 4 points are possible., I have written this Solution Code: /**
* author: tourist1256
* created: 2022-06-24 16:26:02
**/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template <class key, class value, class cmp = std::less<key>>
using ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>;
// find_by_order(k) returns iterator to kth element starting from 0;
// order_of_key(k) returns count of elements strictly smaller than k;
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
#define int long long
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
inline int64_t random_long(long long l = LLONG_MIN, long long r = LLONG_MAX) {
uniform_int_distribution<int64_t> generator(l, r);
return generator(rng);
}
int32_t main() {
ios::sync_with_stdio(false);
cin.tie(0);
int tt;
cin >> tt;
while (tt--) {
int n, m;
cin >> n >> m;
int array[n][m];
array[0][0] = 1;
int ans = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (i > 0 && array[i - 1][j] == 1) {
ans++;
}
if (j > 0 && array[i][j - 1] == 1) {
ans++;
}
array[i][j] = 1;
}
}
cout << ans << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram has recently purchased an empty rectangular grid of NxM dimension. He wants to fill the grid but in a special way. His way of filling is, He choose any block which is not filled yet and fills it and the points obtained in particular step is the number of filled neighbouring block. Neighbour block denotes the block which shares some common side between them. When Ram fills all the blocks then he will stop and calculate the total number of points. Ram wants to know the maximum points he can get?The first line of the input contains a single Integer T, denoting number of test cases.
The next T lines contains two space separated integer N, M i.e dimensions of grid.
<b>Constraints</b>
1 ≤ T ≤ 100
1 ≤ N, M ≤ 1000Print the maximum number of points Ram can get.Sample Input
1
2 2
Sample Output
4
Explanation
Ram can obtain total score 4 in the following way.
First he filled top right block, point = 0;
Then he filled bottom left block, point = 0;
Then when he fill either top left and bottom right, the points obtained in both the cases will be 2 hence maximum 4 points are possible., I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader()
{
br = new BufferedReader(
new InputStreamReader(System.in));
}
String next()
{
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
}
catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() { return Integer.parseInt(next()); }
long nextLong() { return Long.parseLong(next()); }
double nextDouble()
{
return Double.parseDouble(next());
}
String nextLine()
{
String str = "";
try {
str = br.readLine();
}
catch (IOException e) {
e.printStackTrace();
}
return str;
}
}
static boolean prime[]= new boolean[10000001];
public static void sieve()
{
for(int i=0;i<=10000000;i++)
prime[i] = true;
prime[0] = prime[1] = false;
for(int p = 2; p*p <=10000000; p++)
{
// If prime[p] is not changed, then it is a prime
if(prime[p] == true)
{
// Update all multiples of p
for(int i = p*p; i <= 10000000; i += p)
prime[i] = false;
}
}
}
static ArrayList<Integer> primeFactors(int n)
{
ArrayList<Integer> pflist=new ArrayList<>();
int c = 2;
while (n > 1) {
if (n % c == 0) {
pflist.add(c);
n /= c;
}
else
c++;
}
return pflist;
}
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
FastReader sc = new FastReader();
BufferedWriter out = new BufferedWriter(new OutputStreamWriter(System.out));
int cases = sc.nextInt();
//sieve();
while(cases-->0)
{
int n=sc.nextInt();
int m=sc.nextInt();
out.write((2*m*n-m-n)+"\n");
}
out.flush();
}
public static void reverse(int[] array)
{
int n=array.length;
for(int i=0;i<n/2;i++)
{
int temp=array[i];
array[i]=array[n-i-1];
array[n-i-1]=temp;
}
}
}
class Pair implements Comparable<Pair> {
int first,second;
public Pair(int first,int second)
{
this.first =first;
this.second=second;
}
public int compareTo(Pair b)
{
//first element in descending order
if (this.first!=b.first)
return (this.first>b.first)?-1:1;
else
return this.second<b.second?-1:1;
//second element in incresing order
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number s called rare if all of its digits are divisible by K. Given a number N your task is to check if the given number is rare or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Rare()</b> that takes integer N and K as arguments.
Constraints:-
1 <= N <= 100000
1 <= K <= 9Return 1 if the given number is rare else return 0.Sample Input:-
2468 2
Sample Output:-
1
Sample Input:-
234 2
Sample Output:-
0
Explanation :
3 is not divisible by 2., I have written this Solution Code: class Solution {
public static int Rare(int n, int k){
while(n>0){
if((n%10)%k!=0){
return 0;
}
n/=10;
}
return 1;
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number s called rare if all of its digits are divisible by K. Given a number N your task is to check if the given number is rare or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Rare()</b> that takes integer N and K as arguments.
Constraints:-
1 <= N <= 100000
1 <= K <= 9Return 1 if the given number is rare else return 0.Sample Input:-
2468 2
Sample Output:-
1
Sample Input:-
234 2
Sample Output:-
0
Explanation :
3 is not divisible by 2., I have written this Solution Code: def Rare(N,K):
while N>0:
if(N%10)%K!=0:
return 0
N=N//10
return 1
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number s called rare if all of its digits are divisible by K. Given a number N your task is to check if the given number is rare or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Rare()</b> that takes integer N and K as arguments.
Constraints:-
1 <= N <= 100000
1 <= K <= 9Return 1 if the given number is rare else return 0.Sample Input:-
2468 2
Sample Output:-
1
Sample Input:-
234 2
Sample Output:-
0
Explanation :
3 is not divisible by 2., I have written this Solution Code:
int Rare(int n, int k){
while(n){
if((n%10)%k!=0){
return 0;
}
n/=10;
}
return 1;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number s called rare if all of its digits are divisible by K. Given a number N your task is to check if the given number is rare or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>Rare()</b> that takes integer N and K as arguments.
Constraints:-
1 <= N <= 100000
1 <= K <= 9Return 1 if the given number is rare else return 0.Sample Input:-
2468 2
Sample Output:-
1
Sample Input:-
234 2
Sample Output:-
0
Explanation :
3 is not divisible by 2., I have written this Solution Code:
int Rare(int n, int k){
while(n){
if((n%10)%k!=0){
return 0;
}
n/=10;
}
return 1;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Saloni has recently distributed N chocolates to some kids. She does not remember the number of kids she distributed the chocolates to. But she knows for sure that she did not break any chocolate while distributing. Can you tell her the number of possible values for the number of children?The first and the only line of input contains an integer N.
Constraints
1 <= N <= 10<sup>12</sup>Output a single integer, the number of possible values for the number of children.Sample Input
6
Sample Output
4
Explanation: The possible values for the number of children are 1, 2, 3, and 6.
Sample Input
10
Sample Output
4, I have written this Solution Code: import math
n=int(input())
count=0
i = 1
while i <= math.sqrt(n):
if (n % i == 0) :
if (n / i == i) :
count=count+1
else:
count=count+2
i = i + 1
print(count), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Saloni has recently distributed N chocolates to some kids. She does not remember the number of kids she distributed the chocolates to. But she knows for sure that she did not break any chocolate while distributing. Can you tell her the number of possible values for the number of children?The first and the only line of input contains an integer N.
Constraints
1 <= N <= 10<sup>12</sup>Output a single integer, the number of possible values for the number of children.Sample Input
6
Sample Output
4
Explanation: The possible values for the number of children are 1, 2, 3, and 6.
Sample Input
10
Sample Output
4, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(int i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define ld long double
#define int long long
#define double long double
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
typedef vector<int> vi;
#define pi 3.141592653589793238
const int MOD = 1e9+7;
const int INF = 1LL<<60;
const int N = 2e5+5;
// it's swapnil07 ;)
#ifdef SWAPNIL07
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
cout << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
int begtime = clock();
#define end_routine() cout << "\n\nTime elapsed: " << (clock() - begtime)*1000/CLOCKS_PER_SEC << " ms\n\n";
#else
#define endl '\n'
#define trace(...)
#define end_routine()
#endif
void solve(){
int n; cin>>n;
int ans = 0;
for(int i=1; i*i<n; i++){
if(n%i == 0){
ans += 2;
}
}
int nn = sqrt(n);
if(nn*nn == n) {
ans++;
}
cout<<ans;
}
signed main()
{
fast
#ifdef SWAPNIL07
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
int t=1;
// cin>>t;
while(t--){
solve();
cout<<"\n";
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Saloni has recently distributed N chocolates to some kids. She does not remember the number of kids she distributed the chocolates to. But she knows for sure that she did not break any chocolate while distributing. Can you tell her the number of possible values for the number of children?The first and the only line of input contains an integer N.
Constraints
1 <= N <= 10<sup>12</sup>Output a single integer, the number of possible values for the number of children.Sample Input
6
Sample Output
4
Explanation: The possible values for the number of children are 1, 2, 3, and 6.
Sample Input
10
Sample Output
4, I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
long num = sc.nextLong();
System.out.println(possibleValues(num));
}
static int possibleValues(long num)
{
int ans = 0;
for(int i = 1; (long)i*i < num; i++)
{
if(num%i == 0)
ans += 2;
}
int nn = (int)Math.sqrt(num);
if((long)(nn*nn) == num)
ans++;
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: n=int(input())
a=map(int,input().split())
b=[]
mx=-200000
cnt=0
for i in a:
if i>mx:
cnt+=1
mx=i
print(cnt), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: function numberOfRoofs(arr)
{
let count=1;
let max = arr[0];
for(let i=1;i<arrSize;i++)
{
if(arr[i] > max)
{
count++;
max = arr[i];
}
}
return count;
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: import java.util.*;
import java.io.*;
class Main{
public static void main(String args[]){
Scanner s=new Scanner(System.in);
int n=s.nextInt();
int []a=new int[n];
for(int i=0;i<n;i++){
a[i]=s.nextInt();
}
int count=1;
int max = a[0];
for(int i=1;i<n;i++)
{
if(a[i] > max)
{
count++;
max = a[i];
}
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nobita wants to become rich so he came up with an idea, So, he buys some gadgets from the future at a price of C and sells them at a price of S to his friends. Now Nobita wants to know how much he gains by selling all gadget. As we all know Nobita is weak in maths help him to find the profit he getsYou don't have to worry about the input, you just have to complete the function <b>Profit()</b>
<b>Constraints:-</b>
1 <= C <= S <= 1000Print the profit Nobita gets from selling one gadget.Sample Input:-
3 5
Sample Output:-
2
Sample Input:-
9 16
Sample Output:-
7, I have written this Solution Code: def profit(C, S):
print(S - C), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nobita wants to become rich so he came up with an idea, So, he buys some gadgets from the future at a price of C and sells them at a price of S to his friends. Now Nobita wants to know how much he gains by selling all gadget. As we all know Nobita is weak in maths help him to find the profit he getsYou don't have to worry about the input, you just have to complete the function <b>Profit()</b>
<b>Constraints:-</b>
1 <= C <= S <= 1000Print the profit Nobita gets from selling one gadget.Sample Input:-
3 5
Sample Output:-
2
Sample Input:-
9 16
Sample Output:-
7, I have written this Solution Code: static void Profit(int C, int S){
System.out.println(S-C);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: In the morning assembly, there are N students standing in a line, such that the ith student from the front has height H[i].
In one move, you can pick any two students and swap their positions.
If you are allowed to do only one swap, can you arrange the students in increasing order of their hieghts?The first line of input contains T, the number of test cases.
The first line of each test case contains N, the number of students in the line.
The second line of each test case contains the heights of N students, where the ith index is the height of ith student.
<b>Constraints:</b>
1 <= T <= 10<sup>3</sup>
1 <= N <= 10<sup>4</sup>
1 <= H_i <= 10<sup>5</sup>For each test case, output YES or NOSample Input
2
3
1 2 3
4
2 1 4 3
Sample Output
YES
NO
Explanation:
The students are already standing in increasing order in the first test case, hence the answer is YES., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner input=new Scanner(System.in);
int t = input.nextInt();
for(int i = 0; i< t; i++){
int n = input.nextInt();
int[] arr = new int[n];
for (int j = 0; j < n; j++) {
arr[j] = input.nextInt();
}
System.out.println(arrStu(arr, n));
}
}
public static String arrStu(int[] arr, int n ){
int[] newArr = new int[n];
for(int i = 0; i<n ;i++){
newArr[i] = arr[i];
}
Arrays.sort(newArr);
int count = 0;
for(int i = 0 ; i< n ;i++){
if(arr[i] != newArr[i]) count++;
}
if(count > 2) return "NO";
else return "YES";
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: In the morning assembly, there are N students standing in a line, such that the ith student from the front has height H[i].
In one move, you can pick any two students and swap their positions.
If you are allowed to do only one swap, can you arrange the students in increasing order of their hieghts?The first line of input contains T, the number of test cases.
The first line of each test case contains N, the number of students in the line.
The second line of each test case contains the heights of N students, where the ith index is the height of ith student.
<b>Constraints:</b>
1 <= T <= 10<sup>3</sup>
1 <= N <= 10<sup>4</sup>
1 <= H_i <= 10<sup>5</sup>For each test case, output YES or NOSample Input
2
3
1 2 3
4
2 1 4 3
Sample Output
YES
NO
Explanation:
The students are already standing in increasing order in the first test case, hence the answer is YES., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
signed main(){
int t=1;
cin>>t;
while(t--){
int n; cin>>n;
vector<int> v(n);
for(int i=0;i<n;i++){
cin>>v[i];
}
vector<int> b= v;
sort(b.begin(),b.end());
int cnt=0;
for(int i=0;i<n;i++){
if(b[i]!=v[i]) cnt++;
}
if(cnt==0 or cnt==2){
cout<<"YES\n";
}else cout<<"NO\n";
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string s of length n. Find all the repeating characters and count their occurrence. A character is a repeating character if it occurs more than once.First line contains n.
Next line contains the string s.
<b>Constraints</b>
1 ≤ n ≤ 10<sup>5</sup>
s contains only lowercase English letters.Print all the repeating characters and their frequency. Print in order from 'a' to 'z'.Input:
6
banana
Output:
a 3
n 2
Explanation :
b occurs only once., I have written this Solution Code: import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) {
InputStream inputStream = System.in;
OutputStream outputStream = System.out;
InputReader in = new InputReader(inputStream);
OutputWriter out = new OutputWriter(outputStream);
int n=Integer.parseInt(in.next());
String s=in.next();
int a[] = new int[26];
Arrays.fill(a,0);
for(int i=0;i<n;i++)
{
int j=s.charAt(i) - 'a';
a[j]++;
}
for(int i=0;i<26;i++){
if(a[i] > 1){
out.println((char)('a' + i) + " " + a[i]);
}
}
out.close();
}
static class InputReader {
BufferedReader reader;
StringTokenizer tokenizer;
public InputReader(InputStream stream) {
reader = new BufferedReader(new InputStreamReader(stream), 32768);
tokenizer = null;
}
public String next() {
while (tokenizer == null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(reader.readLine());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
static class OutputWriter {
private final PrintWriter writer;
public OutputWriter(OutputStream outputStream) {
writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
}
public OutputWriter(Writer writer) {
this.writer = new PrintWriter(writer);
}
public void print(Object... objects) {
for (int i = 0; i < objects.length; i++) {
if (i != 0) {
writer.print(' ');
}
writer.print(objects[i]);
}
}
public void println(Object... objects) {
print(objects);
writer.println();
}
public void close() {
writer.close();
}
public void println(int i) {
writer.println(i);
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is giving a True False exam consisting of 10 questions. In which she knows that exactly X of the given questions are True and the rest are false (thanks to her friend) but she does not know the order. This time she decided to fill it optimally so that in any case she can get the maximum of minimum marks possible.
Given the value of X, your task is to tell Sara what can be the maximum of minimum marks she can get. i. e out of every minimum mark for a different number of True and False what will be the maximum of that minimum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>maximumMarks()</b> that takes integer X as argument.
Constraints:-
0 <= X <= 10Return the maximum marks of all the minimum possible.Sample Input:-
X = 5
Sample Output:-
5
Explanation:-
One of the possible solutions is she can mark all the answers true.
Sample Input:-
1
Sample Output:-
9, I have written this Solution Code: static int maximumMarks(int X){
if(X>5){
return X;
}
return 10-X;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is giving a True False exam consisting of 10 questions. In which she knows that exactly X of the given questions are True and the rest are false (thanks to her friend) but she does not know the order. This time she decided to fill it optimally so that in any case she can get the maximum of minimum marks possible.
Given the value of X, your task is to tell Sara what can be the maximum of minimum marks she can get. i. e out of every minimum mark for a different number of True and False what will be the maximum of that minimum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>maximumMarks()</b> that takes integer X as argument.
Constraints:-
0 <= X <= 10Return the maximum marks of all the minimum possible.Sample Input:-
X = 5
Sample Output:-
5
Explanation:-
One of the possible solutions is she can mark all the answers true.
Sample Input:-
1
Sample Output:-
9, I have written this Solution Code:
int maximumMarks(int X){
if(X>5){
return X;
}
return 10-X;
}
, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is giving a True False exam consisting of 10 questions. In which she knows that exactly X of the given questions are True and the rest are false (thanks to her friend) but she does not know the order. This time she decided to fill it optimally so that in any case she can get the maximum of minimum marks possible.
Given the value of X, your task is to tell Sara what can be the maximum of minimum marks she can get. i. e out of every minimum mark for a different number of True and False what will be the maximum of that minimum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>maximumMarks()</b> that takes integer X as argument.
Constraints:-
0 <= X <= 10Return the maximum marks of all the minimum possible.Sample Input:-
X = 5
Sample Output:-
5
Explanation:-
One of the possible solutions is she can mark all the answers true.
Sample Input:-
1
Sample Output:-
9, I have written this Solution Code: def maximumMarks(X):
if X>5:
return (X)
return (10-X)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Sara is giving a True False exam consisting of 10 questions. In which she knows that exactly X of the given questions are True and the rest are false (thanks to her friend) but she does not know the order. This time she decided to fill it optimally so that in any case she can get the maximum of minimum marks possible.
Given the value of X, your task is to tell Sara what can be the maximum of minimum marks she can get. i. e out of every minimum mark for a different number of True and False what will be the maximum of that minimum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>maximumMarks()</b> that takes integer X as argument.
Constraints:-
0 <= X <= 10Return the maximum marks of all the minimum possible.Sample Input:-
X = 5
Sample Output:-
5
Explanation:-
One of the possible solutions is she can mark all the answers true.
Sample Input:-
1
Sample Output:-
9, I have written this Solution Code:
int maximumMarks(int X){
if(X>5){
return X;
}
return 10-X;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix Mat of m rows and n columns. The matrix is boolean so the elements of the matrix can only be either 0 or 1.
Now, if any row of the matrix contains a 1, then you need to fill that whole row with 1. After doing the mentioned operation, you need to print the modified matrix.The first line of input contains T denoting the number of test cases. T test cases follow.
The first line of each test case contains m and n denotes the number of rows and a number of columns.
Then next m lines contain n elements denoting the elements of the matrix.
Constraints:
1 ≤ T ≤ 20
1 ≤ m, n ≤ 700
Mat[I][j] ∈ {0,1}For each testcase, in a new line, print the modified matrix.Input:
1
5 4
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Output:
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1
Explanation:
Rows = 5 and columns = 4
The given matrix is
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Evidently, the first row contains a 1 so fill the whole row with 1. The third row also contains a 1 so that row will be filled too. Finally, the last row contains a 1 and therefore it needs to be filled with 1 too.
The final matrix is
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1, I have written this Solution Code: t=int(input())
while t!=0:
m,n=input().split()
m,n=int(m),int(n)
for i in range(m):
arr=input().strip()
if '1' in arr:
arr='1 '*n
else:
arr='0 '*n
print(arr)
t-=1, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix Mat of m rows and n columns. The matrix is boolean so the elements of the matrix can only be either 0 or 1.
Now, if any row of the matrix contains a 1, then you need to fill that whole row with 1. After doing the mentioned operation, you need to print the modified matrix.The first line of input contains T denoting the number of test cases. T test cases follow.
The first line of each test case contains m and n denotes the number of rows and a number of columns.
Then next m lines contain n elements denoting the elements of the matrix.
Constraints:
1 ≤ T ≤ 20
1 ≤ m, n ≤ 700
Mat[I][j] ∈ {0,1}For each testcase, in a new line, print the modified matrix.Input:
1
5 4
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Output:
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1
Explanation:
Rows = 5 and columns = 4
The given matrix is
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Evidently, the first row contains a 1 so fill the whole row with 1. The third row also contains a 1 so that row will be filled too. Finally, the last row contains a 1 and therefore it needs to be filled with 1 too.
The final matrix is
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define N 1000
int a[N][N];
// Driver code
int main()
{
int t;
cin>>t;
while(t--){
int n,m;
cin>>n>>m;
bool b[n];
for(int i=0;i<n;i++){
b[i]=false;
}
for(int i=0;i<n;i++){
for(int j=0;j<m;j++){
cin>>a[i][j];
if(a[i][j]==1){
b[i]=true;
}
}
}
for(int i=0;i<n;i++){
if(b[i]){
for(int j=0;j<m;j++){
cout<<1<<" ";
}}
else{
for(int j=0;j<m;j++){
cout<<0<<" ";
}
}
cout<<endl;
}
}}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a matrix Mat of m rows and n columns. The matrix is boolean so the elements of the matrix can only be either 0 or 1.
Now, if any row of the matrix contains a 1, then you need to fill that whole row with 1. After doing the mentioned operation, you need to print the modified matrix.The first line of input contains T denoting the number of test cases. T test cases follow.
The first line of each test case contains m and n denotes the number of rows and a number of columns.
Then next m lines contain n elements denoting the elements of the matrix.
Constraints:
1 ≤ T ≤ 20
1 ≤ m, n ≤ 700
Mat[I][j] ∈ {0,1}For each testcase, in a new line, print the modified matrix.Input:
1
5 4
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Output:
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1
Explanation:
Rows = 5 and columns = 4
The given matrix is
1 0 0 0
0 0 0 0
0 1 0 0
0 0 0 0
0 0 0 1
Evidently, the first row contains a 1 so fill the whole row with 1. The third row also contains a 1 so that row will be filled too. Finally, the last row contains a 1 and therefore it needs to be filled with 1 too.
The final matrix is
1 1 1 1
0 0 0 0
1 1 1 1
0 0 0 0
1 1 1 1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main(String[] args) throws Exception{
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader bf = new BufferedReader(isr);
int t = Integer.parseInt(bf.readLine());
while (t-- > 0){
String inputs[] = bf.readLine().split(" ");
int m = Integer.parseInt(inputs[0]);
int n = Integer.parseInt(inputs[1]);
String[] matrix = new String[m];
for(int i=0; i<m; i++){
matrix[i] = bf.readLine();
}
StringBuffer ones = new StringBuffer("");
StringBuffer zeros = new StringBuffer("");
for(int i=0; i<n; i++){
ones.append("1 ");
zeros.append("0 ");
}
for(int i=0; i<m; i++){
if(matrix[i].contains("1")){
System.out.println(ones);
}else{
System.out.println(zeros);
}
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of integers. Consider absolute difference between all the pairs of the the elements. You need to find Kth smallest absolute difference. If the size of the array is N then value of K will be less than N and more than or equal to 1.The first line of input contains number of test cases T.
The first line of each test case contains a two integers N and K denoting the number of elements in the array A and difference you need to output. The second line of each test case contains N space separated integers denoting the elements of the array A
Constraints:
1<= T <= 10
2 <= N <= 100000
1 <= K < N < 100000
0 <= A[i] <= 100000For each test case, output Kth smallest absolute difference.Input :
1
6 2
1 3 4 1 3 8
Output :
0
Explanation :
Test case 1: First smallest difference is 0, between the pair (1, 1) and second smallest absolute difference difference is also 0 between the pairs (3, 3)., I have written this Solution Code: import java.util.*;
import java.io.*;
import java.lang.*;
class Main{
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine().trim());
while (t-- > 0) {
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
int arr[] = new int[n];
str = read.readLine().trim().split(" ");
for (int i = 0; i < n; i++)
arr[i] = Integer.parseInt(str[i]);
System.out.println(Math.abs(small(arr, k)));
}
}
public static int small(int arr[], int k) {
Arrays.sort(arr);
int l = 0, r = arr[arr.length - 1] - arr[0];
while (r > l) {
int mid = l + (r - l) / 2;
if (count(arr, mid) < k) {
l = mid + 1;
} else {
r = mid;
}
}
return r;
}
public static int count(int arr[], int mid) {
int ans = 0, j = 0;
for (int i = 1; i < arr.length; ++i) {
while (j < i && arr[i] - arr[j] > mid) {
++j;
}
ans += i - j;
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: def MaximumProduct(N):
ans=N//4
if N %4 !=0:
ans=ans+1
return ans, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: int MaximumProduct(int N){
int ans=N/4;
if(N%4!=0){ans++;}
return ans;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: int MaximumProduct(int N){
int ans=N/4;
if(N%4!=0){ans++;}
return ans;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: For a given integer N, find the number of minimum elements the N has to be broken into such that their product is maximum.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>MaximumProduct()</b> that takes integer N as parameter.
Constraints:-
1 <= N <= 10000Return the minimum number of elements the N has to be broken intoSample Input:-
5
Sample output
2
Explanation:-
N has to be broken into 2 and 3 to get the maximum product 6.
Sample Input:-
7
Sample Output:-
2
Explanation:- 4 + 3, I have written this Solution Code: static int MaximumProduct(int N){
int ans=N/4;
if(N%4!=0){ans++;}
return ans;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are n cities in the universe and our beloved Spider-Man is in city 1. He doesn't like to travel by vehicles, so he shot webs forming edges between some pairs of cities. Eventually, there were m edges and each had some cost associated with it.
Spider-Man now defines the cost of a path p from cities p<sub>1</sub> to p<sub>k</sub> as w<sub>1</sub> + 2w<sub>2</sub> + 3w<sub>3</sub> . . . + (k-1)*w<sub>k-1</sub>, where w<sub>i</sub> is the cost of an edge from p<sub>i</sub> to p<sub>i+1</sub>.
Thus, the minimum distance between cities i and j is the smallest cost of a path starting from i and ending at j.
Find the minimum distance from city 1 to all the cities i (1 ≤ i ≤ n). If there exists no way to go from city 1 to city i, print -1.
<b>Note: </b>
All the edges are bidirectional. There may be multiple edges and self-loops in the input.The first line contains two space separated integers n and m - the number of nodes and edges respectively.
The next m lines contain three-space separated integers x, y, w - representing an edge between x and y with cost w.
<b>Constraints:</b>
1 ≤ n ≤ 3000
0 ≤ m ≤ 10000
1 ≤ x, y ≤ n
1 ≤ w ≤ 10<sup>9</sup>Output n lines. In the i<sup>th</sup> line, output the minimum distance from city 1 to the i<sup>th</sup> city. If there exists no such path, output -1.Sample Input
6 5
2 4 3
2 3 4
2 1 2
2 5 6
1 5 2
Sample Output
0
2
10
8
2
-1
Explanation:
Shortest path from 1 to 3 is (1->2->3) with total weight= 1*2+2*4=10
Shortest path from 1 to 5 is (1->5) with total weight= 1*2=2
There doesn't exist any path from 1 to 6 so print -1
, I have written this Solution Code:
import sys
from collections import defaultdict
from heapq import heappush, heappop
n, m = map(int, input().split())
d = defaultdict(list)
dist = [sys.maxsize]*n
dist[0] = 0
for _ in range(m):
start, dest, wt = map(int, input().split())
d[start-1].append((dest-1, wt))
d[dest-1].append((start-1, wt))
heap = [(0, 0, 0)]
while heap:
count, cost, u= heappop(heap)
for vertex, weight in d[u]:
if dist[vertex] > cost + weight*(count+1):
dist[vertex] = cost + weight*(count+1)
heappush(heap, (count+1, dist[vertex], vertex))
for d in dist:
if d == sys.maxsize:
print(-1)
else:
print(d), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are n cities in the universe and our beloved Spider-Man is in city 1. He doesn't like to travel by vehicles, so he shot webs forming edges between some pairs of cities. Eventually, there were m edges and each had some cost associated with it.
Spider-Man now defines the cost of a path p from cities p<sub>1</sub> to p<sub>k</sub> as w<sub>1</sub> + 2w<sub>2</sub> + 3w<sub>3</sub> . . . + (k-1)*w<sub>k-1</sub>, where w<sub>i</sub> is the cost of an edge from p<sub>i</sub> to p<sub>i+1</sub>.
Thus, the minimum distance between cities i and j is the smallest cost of a path starting from i and ending at j.
Find the minimum distance from city 1 to all the cities i (1 ≤ i ≤ n). If there exists no way to go from city 1 to city i, print -1.
<b>Note: </b>
All the edges are bidirectional. There may be multiple edges and self-loops in the input.The first line contains two space separated integers n and m - the number of nodes and edges respectively.
The next m lines contain three-space separated integers x, y, w - representing an edge between x and y with cost w.
<b>Constraints:</b>
1 ≤ n ≤ 3000
0 ≤ m ≤ 10000
1 ≤ x, y ≤ n
1 ≤ w ≤ 10<sup>9</sup>Output n lines. In the i<sup>th</sup> line, output the minimum distance from city 1 to the i<sup>th</sup> city. If there exists no such path, output -1.Sample Input
6 5
2 4 3
2 3 4
2 1 2
2 5 6
1 5 2
Sample Output
0
2
10
8
2
-1
Explanation:
Shortest path from 1 to 3 is (1->2->3) with total weight= 1*2+2*4=10
Shortest path from 1 to 5 is (1->5) with total weight= 1*2=2
There doesn't exist any path from 1 to 6 so print -1
, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
#define int long long
const int INF =1e18;
vector<tuple<int, int, int>> adj;
void solve()
{
int n, m;
cin>>n>>m;
// assert(1<=n && n<=3000);
// assert(0<=m && m<=10000);
adj.resize(n);
for(int i = 0;i<m;i++)
{
int x, y, w;
cin>>x>>y>>w;
x--;
y--;
// assert(0<=x && x<n);
// assert(0<=y && y<n);
// assert(1<=w && w<=1e9);
adj.push_back({x, y, w});
adj.push_back({y, x, w});
}
vector<int> dp_old(n, INF);
vector<int> dp_new(n, INF);
dp_old[0] = 0;
for(int i = 1;i<=n;i++)
{
fill(dp_new.begin(), dp_new.end(), INF);
for(auto [x, y,w]:adj)
{
dp_new[y]= min({dp_new[y], dp_old[x] + i * w});
}
for(int j = 0;j<n;j++)
dp_new[j] = min(dp_new[j], dp_old[j]);
swap(dp_new, dp_old);
}
for(int i = 0;i<n;i++)
{
if(dp_old[i] == INF)
dp_old[i] = -1;
cout<<dp_old[i]<<"\n";
}
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cerr.tie(NULL);
#ifndef ONLINE_JUDGE
if (fopen("INPUT.txt", "r"))
{
freopen("INPUT.txt", "r", stdin);
freopen("OUTPUT.txt", "w", stdout);
}
#endif
solve();
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are n cities in the universe and our beloved Spider-Man is in city 1. He doesn't like to travel by vehicles, so he shot webs forming edges between some pairs of cities. Eventually, there were m edges and each had some cost associated with it.
Spider-Man now defines the cost of a path p from cities p<sub>1</sub> to p<sub>k</sub> as w<sub>1</sub> + 2w<sub>2</sub> + 3w<sub>3</sub> . . . + (k-1)*w<sub>k-1</sub>, where w<sub>i</sub> is the cost of an edge from p<sub>i</sub> to p<sub>i+1</sub>.
Thus, the minimum distance between cities i and j is the smallest cost of a path starting from i and ending at j.
Find the minimum distance from city 1 to all the cities i (1 ≤ i ≤ n). If there exists no way to go from city 1 to city i, print -1.
<b>Note: </b>
All the edges are bidirectional. There may be multiple edges and self-loops in the input.The first line contains two space separated integers n and m - the number of nodes and edges respectively.
The next m lines contain three-space separated integers x, y, w - representing an edge between x and y with cost w.
<b>Constraints:</b>
1 ≤ n ≤ 3000
0 ≤ m ≤ 10000
1 ≤ x, y ≤ n
1 ≤ w ≤ 10<sup>9</sup>Output n lines. In the i<sup>th</sup> line, output the minimum distance from city 1 to the i<sup>th</sup> city. If there exists no such path, output -1.Sample Input
6 5
2 4 3
2 3 4
2 1 2
2 5 6
1 5 2
Sample Output
0
2
10
8
2
-1
Explanation:
Shortest path from 1 to 3 is (1->2->3) with total weight= 1*2+2*4=10
Shortest path from 1 to 5 is (1->5) with total weight= 1*2=2
There doesn't exist any path from 1 to 6 so print -1
, I have written this Solution Code: import java.io.*;import java.util.*;import java.math.*;import static java.lang.Math.*;import static java.
util.Map.*;import static java.util.Arrays.*;import static java.util.Collections.*;
import static java.lang.System.*;
public class Main
{
public void tq()throws Exception
{
st=new StringTokenizer(bq.readLine());
int tq=1;
sb=new StringBuilder(2000000);
o:
while(tq-->0)
{
int n=i();
int m=i();
LinkedList<int[]> l[]=new LinkedList[n];
for(int x=0;x<n;x++)l[x]=new LinkedList<>();
for(int x=0;x<m;x++)
{
int a=i()-1;
int b=i()-1;
int c=i();
l[a].add(new int[]{b,c});
l[b].add(new int[]{a,c});
}
long d[]=new long[n];
for(int x=0;x<n;x++)d[x]=maxl;
d[0]=0l;
PriorityQueue<long[]> p=new PriorityQueue<>(5000,(a,b)->a[2]-b[2]<1l?-1:1);
p.add(new long[]{0l,0,0});
while(p.size()>0)
{
long r[]=p.poll();
long di=r[0];
int no=(int)r[1];
long mu=r[2];
for(int e[]:l[no])
{
int node=e[0];
int w=e[1];
long de=di+w*(mu+1);
if(d[node]>de)
{
d[node]=de;
p.add(new long[]{de,node,mu+1});
}
}
}
for(long x:d)
{
sl(x==maxl?-1:x);
}
}
p(sb);
}
int di[][]={{-1,0},{1,0},{0,-1},{0,1}};
int de[][]={{-1,0},{1,0},{0,-1},{0,1},{-1,-1},{1,1},{-1,1},{1,-1}};
long mod=1000000007l;int max=Integer.MAX_VALUE,min=Integer.MIN_VALUE;long maxl=Long.MAX_VALUE, minl=Long.
MIN_VALUE;BufferedReader bq=new BufferedReader(new InputStreamReader(in));StringTokenizer st;
StringBuilder sb;public static void main(String[] a)throws Exception{new Main().tq();}int[] so(int ar[])
{Integer r[]=new Integer[ar.length];for(int x=0;x<ar.length;x++)r[x]=ar[x];sort(r);for(int x=0;x<ar.length;
x++)ar[x]=r[x];return ar;}long[] so(long ar[]){Long r[]=new Long[ar.length];for(int x=0;x<ar.length;x++)
r[x]=ar[x];sort(r);for(int x=0;x<ar.length;x++)ar[x]=r[x];return ar;}
char[] so(char ar[]) {Character
r[]=new Character[ar.length];for(int x=0;x<ar.length;x++)r[x]=ar[x];sort(r);for(int x=0;x<ar.length;x++)
ar[x]=r[x];return ar;}void s(String s){sb.append(s);}void s(int s){sb.append(s);}void s(long s){sb.
append(s);}void s(char s){sb.append(s);}void s(double s){sb.append(s);}void ss(){sb.append(' ');}void sl
(String s){sb.append(s);sb.append("\n");}void sl(int s){sb.append(s);sb.append("\n");}void sl(long s){sb
.append(s);sb.append("\n");}void sl(char s) {sb.append(s);sb.append("\n");}void sl(double s){sb.append(s)
;sb.append("\n");}void sl(){sb.append("\n");}int l(int v){return 31-Integer.numberOfLeadingZeros(v);}
long l(long v){return 63-Long.numberOfLeadingZeros(v);}int sq(int a){return (int)sqrt(a);}long sq(long a)
{return (long)sqrt(a);}long gcd(long a,long b){while(b>0l){long c=a%b;a=b;b=c;}return a;}int gcd(int a,int b)
{while(b>0){int c=a%b;a=b;b=c;}return a;}boolean pa(String s,int i,int j){while(i<j)if(s.charAt(i++)!=
s.charAt(j--))return false;return true;}boolean[] si(int n) {boolean bo[]=new boolean[n+1];bo[0]=true;bo[1]
=true;for(int x=4;x<=n;x+=2)bo[x]=true;for(int x=3;x*x<=n;x+=2){if(!bo[x]){int vv=(x<<1);for(int y=x*x;y<=n;
y+=vv)bo[y]=true;}}return bo;}long mul(long a,long b,long m) {long r=1l;a%=m;while(b>0){if((b&1)==1)
r=(r*a)%m;b>>=1;a=(a*a)%m;}return r;}int i()throws IOException{if(!st.hasMoreTokens())st=new
StringTokenizer(bq.readLine());return Integer.parseInt(st.nextToken());}long l()throws IOException
{if(!st.hasMoreTokens())st=new StringTokenizer(bq.readLine());return Long.parseLong(st.nextToken());}String
s()throws IOException {if (!st.hasMoreTokens())st=new StringTokenizer(bq.readLine());return st.nextToken();}
double d()throws IOException{if(!st.hasMoreTokens())st=new StringTokenizer(bq.readLine());return Double.
parseDouble(st.nextToken());}void p(Object p){out.print(p);}void p(String p){out.print(p);}void p(int p)
{out.print(p);}void p(double p){out.print(p);}void p(long p){out.print(p);}void p(char p){out.print(p);}void
p(boolean p){out.print(p);}void pl(Object p){out.println(p);}void pl(String p){out.println(p);}void pl(int p)
{out.println(p);}void pl(char p){out.println(p);}void pl(double p){out.println(p);}void pl(long p){out.
println(p);}void pl(boolean p)
{out.println(p);}void pl(){out.println();}void s(int a[]){for(int e:a)
{sb.append(e);sb.append(' ');}sb.append("\n");}
void s(long a[])
{for(long e:a){sb.append(e);sb.append(' ')
;}sb.append("\n");}void s(int ar[][]){for(int a[]:ar){for(int e:a){sb.append(e);sb.append(' ');}sb.append
("\n");}}
void s(char a[])
{for(char e:a){sb.append(e);sb.append(' ');}sb.append("\n");}void s(char ar[][])
{for(char a[]:ar){for(char e:a){sb.append(e);sb.append(' ');}sb.append("\n");}}int[] ari(int n)throws
IOException {int ar[]=new int[n];if(!st.hasMoreTokens())st=new StringTokenizer(bq.readLine());for(int x=0;
x<n;x++)ar[x]=Integer.parseInt(st.nextToken());return ar;}int[][] ari(int n,int m)throws
IOException {int ar[][]=new int[n][m];for(int x=0;x<n;x++){if (!st.hasMoreTokens())st=new StringTokenizer
(bq.readLine());for(int y=0;y<m;y++)ar[x][y]=Integer.parseInt(st.nextToken());}return ar;}long[] arl
(int n)throws IOException {long ar[]=new long[n];if(!st.hasMoreTokens()) st=new StringTokenizer(bq.readLine())
;for(int x=0;x<n;x++)ar[x]=Long.parseLong(st.nextToken());return ar;}long[][] arl(int n,int m)throws
IOException {long ar[][]=new long[n][m];for(int x=0;x<n;x++) {if(!st.hasMoreTokens()) st=new
StringTokenizer(bq.readLine());for(int y=0;y<m;y++)ar[x][y]=Long.parseLong(st.nextToken());}return ar;}
String[] ars(int n)throws IOException {String ar[] =new String[n];if(!st.hasMoreTokens())st=new
StringTokenizer(bq.readLine());for(int x=0;x<n;x++)ar[x]=st.nextToken();return ar;}double[] ard
(int n)throws IOException {double ar[] =new double[n];if(!st.hasMoreTokens())st=new StringTokenizer
(bq.readLine());for(int x=0;x<n;x++)ar[x]=Double.parseDouble(st.nextToken());return ar;}double[][] ard
(int n,int m)throws IOException{double ar[][]=new double[n][m];for(int x=0;x<n;x++) {if(!st.hasMoreTokens())
st=new StringTokenizer(bq.readLine());for(int y=0;y<m;y++) ar[x][y]=Double.parseDouble(st.nextToken());}
return ar;}char[] arc(int n)throws IOException{char ar[]=new char[n];if(!st.hasMoreTokens())st=new
StringTokenizer(bq.readLine());for(int x=0;x<n;x++)ar[x]=st.nextToken().charAt(0);return ar;}char[][]
arc(int n,int m)throws IOException {char ar[][]=new char[n][m];for(int x=0;x<n;x++){String s=bq.readLine();
for(int y=0;y<m;y++)ar[x][y]=s.charAt(y);}return ar;}void p(int ar[])
{StringBuilder sb=new StringBuilder
(2*ar.length);for(int a:ar){sb.append(a);sb.append(' ');}out.println(sb);}void p(int ar[][])
{StringBuilder sb=new StringBuilder(2*ar.length*ar[0].length);for(int a[]:ar){for(int aa:a){sb.append(aa);
sb.append(' ');}sb.append("\n");}p(sb);}void p(long ar[]){StringBuilder sb=new StringBuilder
(2*ar.length);for(long a:ar){ sb.append(a);sb.append(' ');}out.println(sb);}
void p(long ar[][])
{StringBuilder sb=new StringBuilder(2*ar.length*ar[0].length);for(long a[]:ar){for(long aa:a){sb.append(aa);
sb.append(' ');}sb.append("\n");}p(sb);}void p(String ar[]){int c=0;for(String s:ar)c+=s.length()+1;
StringBuilder sb=new StringBuilder(c);for(String a:ar){sb.append(a);sb.append(' ');}out.println(sb);}
void p(double ar[])
{StringBuilder sb=new StringBuilder(2*ar.length);for(double a:ar){sb.append(a);
sb.append(' ');}out.println(sb);}void p
(double ar[][]){StringBuilder sb=new StringBuilder(2*
ar.length*ar[0].length);for(double a[]:ar){for(double aa:a){sb.append(aa);sb.append(' ');}sb.append("\n")
;}p(sb);}void p(char ar[])
{StringBuilder sb=new StringBuilder(2*ar.length);for(char aa:ar){sb.append(aa);
sb.append(' ');}out.println(sb);}void p(char ar[][]){StringBuilder sb=new StringBuilder(2*ar.length*ar[0]
.length);for(char a[]:ar){for(char aa:a){sb.append(aa);sb.append(' ');}sb.append("\n");}p(sb);}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Natsu is fighting with a dragon that has A Health and B attack power and Natsu has C health and D attack power. The fight goes in turns first Natsu will attack the Dragon then Dragon will attack Natsu and this goes on. The fight will stop when either the dragon's or Natsu's health drops zero or below. Your task is to check whether Natsu will able to slay the Dragon or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DragonSlayer()</b> that takes integers A, B, C, and D as arguments.
Constraints:-
1 <= A, B, C, D <= 1000Return 0 if Dragon wins else return 1.Sample Input:-
8 2 5 3
Sample Output:-
1
Explanation:-
Natsu's attack:- A = 5, B = 2, C = 5, D = 3
Dragon's attack:- A = 5, B = 2, C = 3, D =3
Natsu's attack:- A = 2, B =2, C = 3, D=3
Dragon's attack:- A = 2, B =2, C = 1, D=3
Natsu's attack:- A = -1, B =2, C = 1, D=3
Natsu's win, I have written this Solution Code:
int DragonSlayer(int A, int B, int C,int D){
int x = C/B;
if(C%B!=0){x++;}
int y = A/D;
if(A%D!=0){y++;}
if(x<y){return 0;}
return 1;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Natsu is fighting with a dragon that has A Health and B attack power and Natsu has C health and D attack power. The fight goes in turns first Natsu will attack the Dragon then Dragon will attack Natsu and this goes on. The fight will stop when either the dragon's or Natsu's health drops zero or below. Your task is to check whether Natsu will able to slay the Dragon or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DragonSlayer()</b> that takes integers A, B, C, and D as arguments.
Constraints:-
1 <= A, B, C, D <= 1000Return 0 if Dragon wins else return 1.Sample Input:-
8 2 5 3
Sample Output:-
1
Explanation:-
Natsu's attack:- A = 5, B = 2, C = 5, D = 3
Dragon's attack:- A = 5, B = 2, C = 3, D =3
Natsu's attack:- A = 2, B =2, C = 3, D=3
Dragon's attack:- A = 2, B =2, C = 1, D=3
Natsu's attack:- A = -1, B =2, C = 1, D=3
Natsu's win, I have written this Solution Code: static int DragonSlayer(int A, int B, int C,int D){
int x = C/B;
if(C%B!=0){x++;}
int y = A/D;
if(A%D!=0){y++;}
if(x<y){return 0;}
return 1;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Natsu is fighting with a dragon that has A Health and B attack power and Natsu has C health and D attack power. The fight goes in turns first Natsu will attack the Dragon then Dragon will attack Natsu and this goes on. The fight will stop when either the dragon's or Natsu's health drops zero or below. Your task is to check whether Natsu will able to slay the Dragon or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DragonSlayer()</b> that takes integers A, B, C, and D as arguments.
Constraints:-
1 <= A, B, C, D <= 1000Return 0 if Dragon wins else return 1.Sample Input:-
8 2 5 3
Sample Output:-
1
Explanation:-
Natsu's attack:- A = 5, B = 2, C = 5, D = 3
Dragon's attack:- A = 5, B = 2, C = 3, D =3
Natsu's attack:- A = 2, B =2, C = 3, D=3
Dragon's attack:- A = 2, B =2, C = 1, D=3
Natsu's attack:- A = -1, B =2, C = 1, D=3
Natsu's win, I have written this Solution Code: int DragonSlayer(int A, int B, int C,int D){
int x = C/B;
if(C%B!=0){x++;}
int y = A/D;
if(A%D!=0){y++;}
if(x<y){return 0;}
return 1;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Natsu is fighting with a dragon that has A Health and B attack power and Natsu has C health and D attack power. The fight goes in turns first Natsu will attack the Dragon then Dragon will attack Natsu and this goes on. The fight will stop when either the dragon's or Natsu's health drops zero or below. Your task is to check whether Natsu will able to slay the Dragon or not.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>DragonSlayer()</b> that takes integers A, B, C, and D as arguments.
Constraints:-
1 <= A, B, C, D <= 1000Return 0 if Dragon wins else return 1.Sample Input:-
8 2 5 3
Sample Output:-
1
Explanation:-
Natsu's attack:- A = 5, B = 2, C = 5, D = 3
Dragon's attack:- A = 5, B = 2, C = 3, D =3
Natsu's attack:- A = 2, B =2, C = 3, D=3
Dragon's attack:- A = 2, B =2, C = 1, D=3
Natsu's attack:- A = -1, B =2, C = 1, D=3
Natsu's win, I have written this Solution Code:
def DragonSlayer(A,B,C,D):
x = C//B
if(C%B!=0):
x=x+1
y = A//D
if(A%D!=0):
y=y+1
if(x<y):
return 0
return 1
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, your task is to print a right-angle triangle pattern of consecutive numbers of height n.<b>User Task:</b>
Take only one user input <b>n</b> the height of right angle triangle.
Constraint:
1 ≤ n ≤100
Print a right angle triangle of numbers of height n.Sample Input:
5
Sample Output:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
Sample Input:
2
Sample Output:
1
1 2, I have written this Solution Code: import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int n = input.nextInt();
int num = 1;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++) {
System.out.print(num + " ");
num++;
}
num=1;
System.out.println();
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Create a class named 'Student' with String variable 'name' and integer variable 'rollNumber'.
You need to perform the below operations in <b>myFunction()</b>:
<ul>
<li>Assign the value of <b>rollNumber</b> as given by the user</li>
<li>Assign the value of <b>name</b> as given by the user</li>
</ul>The input contains a single line of String and integer value separated by space.You just have to assign values to Student class attributes. The driver code is handling the outputInput:
Gaurav 1
Output:
Gaurav 1
Input:
Swapnil 2
Output:
Swapnil 2, I have written this Solution Code:
class Student {
String name;
int rollNumber;
public void myFunction (String name, int rollNumber){
this.name = name;
this.rollNumber = rollNumber;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Create a class named 'Student' with String variable 'name' and integer variable 'rollNumber'.
You need to perform the below operations in <b>myFunction()</b>:
<ul>
<li>Assign the value of <b>rollNumber</b> as given by the user</li>
<li>Assign the value of <b>name</b> as given by the user</li>
</ul>The input contains a single line of String and integer value separated by space.You just have to assign values to Student class attributes. The driver code is handling the outputInput:
Gaurav 1
Output:
Gaurav 1
Input:
Swapnil 2
Output:
Swapnil 2, I have written this Solution Code: class Student:
def __init__(self, name, roll_no):
self.name, self.roll_no = name ,roll_no
def myFunction(name, roll_no):
obj = Student(name, roll_no)
return obj, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: An array Arr is considered Good if its size is more than 1 and the cost of turning the array into palindrome is <b>less than</b> floor((size of Arr)/2). Here, the cost of changing an element of the array into another element is 1. So, the cost of turning the array [1, 2, 3, 2] into [1, 2, 2, 1] is 2.
For example: An array of size 5 is good if the cost of turning it into palindrome is strictly <b>less than 2</b>.
Given N and M you have to find number of arrays of size N consisting of integers values from 1 to M such that none of its subarray is Good.
As the answer can be huge find the answer modulo 1000000007.The first and the only line of input contains two integers N and M.
Constraints:
1 <= N <= 100000
1 <= M <= 1000000000Print the answer modulo 1000000007.Sample Input 1
2 3
Sample Output 1
6
Explanation: the arrays are:
[1, 2]
[1, 3]
[2, 1]
[2, 3]
[3, 1]
[3, 2]
Sample Input 2
3 5
Sample Output 2
60, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String line[] = br.readLine().split(" ");
int n= Integer.parseInt(line[0]);
int m =Integer.parseInt(line[1]);
int r = m-n;
long answer = 1;
long mod = 1000000007;
for(int i=m;i>r;i--){
answer = (answer* i)%mod;
}
System.out.println(answer);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: An array Arr is considered Good if its size is more than 1 and the cost of turning the array into palindrome is <b>less than</b> floor((size of Arr)/2). Here, the cost of changing an element of the array into another element is 1. So, the cost of turning the array [1, 2, 3, 2] into [1, 2, 2, 1] is 2.
For example: An array of size 5 is good if the cost of turning it into palindrome is strictly <b>less than 2</b>.
Given N and M you have to find number of arrays of size N consisting of integers values from 1 to M such that none of its subarray is Good.
As the answer can be huge find the answer modulo 1000000007.The first and the only line of input contains two integers N and M.
Constraints:
1 <= N <= 100000
1 <= M <= 1000000000Print the answer modulo 1000000007.Sample Input 1
2 3
Sample Output 1
6
Explanation: the arrays are:
[1, 2]
[1, 3]
[2, 1]
[2, 3]
[3, 1]
[3, 2]
Sample Input 2
3 5
Sample Output 2
60, I have written this Solution Code: n,m = map(int,input().split())
a = 1
for i in range(n):
a *= m
m-=1
if(a > 1000000007):
a = a%1000000007
print(a%1000000007), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: An array Arr is considered Good if its size is more than 1 and the cost of turning the array into palindrome is <b>less than</b> floor((size of Arr)/2). Here, the cost of changing an element of the array into another element is 1. So, the cost of turning the array [1, 2, 3, 2] into [1, 2, 2, 1] is 2.
For example: An array of size 5 is good if the cost of turning it into palindrome is strictly <b>less than 2</b>.
Given N and M you have to find number of arrays of size N consisting of integers values from 1 to M such that none of its subarray is Good.
As the answer can be huge find the answer modulo 1000000007.The first and the only line of input contains two integers N and M.
Constraints:
1 <= N <= 100000
1 <= M <= 1000000000Print the answer modulo 1000000007.Sample Input 1
2 3
Sample Output 1
6
Explanation: the arrays are:
[1, 2]
[1, 3]
[2, 1]
[2, 3]
[3, 1]
[3, 2]
Sample Input 2
3 5
Sample Output 2
60, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
#define rep(i,n) for (int i=0; i<(n); i++)
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int mo=1000000007;
int n,m;
cin>>n>>m;
int ans=1;
for(int i=0;i<n;++i){
ans=(ans*(m-i))%mo;
}
cout<<ans;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given three integers A, B, and C, your task is to print the sum of these three integers.The input contains 3 integers separated by spaces A, B, and C.
Constraints:-
1 <= A, B, C <= 100Print the sum of A, B and C.Sample Input
1 2 3
Sample Output:-
6
Sample Input:-
5 4 2
Sample Output:-
11, I have written this Solution Code: static void simpleSum(int a, int b, int c){
System.out.println(a+b+c);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given three integers A, B, and C, your task is to print the sum of these three integers.The input contains 3 integers separated by spaces A, B, and C.
Constraints:-
1 <= A, B, C <= 100Print the sum of A, B and C.Sample Input
1 2 3
Sample Output:-
6
Sample Input:-
5 4 2
Sample Output:-
11, I have written this Solution Code: void simpleSum(int a, int b, int c){
cout<<a+b+c;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given three integers A, B, and C, your task is to print the sum of these three integers.The input contains 3 integers separated by spaces A, B, and C.
Constraints:-
1 <= A, B, C <= 100Print the sum of A, B and C.Sample Input
1 2 3
Sample Output:-
6
Sample Input:-
5 4 2
Sample Output:-
11, I have written this Solution Code: x = input()
a, b, c = x.split()
a = int(a)
b = int(b)
c = int(c)
print(a+b+c), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of integers. Consider absolute difference between all the pairs of the the elements. You need to find Kth smallest absolute difference. If the size of the array is N then value of K will be less than N and more than or equal to 1.The first line of input contains number of test cases T.
The first line of each test case contains a two integers N and K denoting the number of elements in the array A and difference you need to output. The second line of each test case contains N space separated integers denoting the elements of the array A
Constraints:
1<= T <= 10
2 <= N <= 100000
1 <= K < N < 100000
0 <= A[i] <= 100000For each test case, output Kth smallest absolute difference.Input :
1
6 2
1 3 4 1 3 8
Output :
0
Explanation :
Test case 1: First smallest difference is 0, between the pair (1, 1) and second smallest absolute difference difference is also 0 between the pairs (3, 3)., I have written this Solution Code: import java.util.*;
import java.io.*;
import java.lang.*;
class Main{
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine().trim());
while (t-- > 0) {
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
int arr[] = new int[n];
str = read.readLine().trim().split(" ");
for (int i = 0; i < n; i++)
arr[i] = Integer.parseInt(str[i]);
System.out.println(Math.abs(small(arr, k)));
}
}
public static int small(int arr[], int k) {
Arrays.sort(arr);
int l = 0, r = arr[arr.length - 1] - arr[0];
while (r > l) {
int mid = l + (r - l) / 2;
if (count(arr, mid) < k) {
l = mid + 1;
} else {
r = mid;
}
}
return r;
}
public static int count(int arr[], int mid) {
int ans = 0, j = 0;
for (int i = 1; i < arr.length; ++i) {
while (j < i && arr[i] - arr[j] > mid) {
++j;
}
ans += i - j;
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: In the morning assembly, there are N students standing in a line, such that the ith student from the front has height H[i].
In one move, you can pick any two students and swap their positions.
If you are allowed to do only one swap, can you arrange the students in increasing order of their hieghts?The first line of input contains T, the number of test cases.
The first line of each test case contains N, the number of students in the line.
The second line of each test case contains the heights of N students, where the ith index is the height of ith student.
<b>Constraints:</b>
1 <= T <= 10<sup>3</sup>
1 <= N <= 10<sup>4</sup>
1 <= H_i <= 10<sup>5</sup>For each test case, output YES or NOSample Input
2
3
1 2 3
4
2 1 4 3
Sample Output
YES
NO
Explanation:
The students are already standing in increasing order in the first test case, hence the answer is YES., I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner input=new Scanner(System.in);
int t = input.nextInt();
for(int i = 0; i< t; i++){
int n = input.nextInt();
int[] arr = new int[n];
for (int j = 0; j < n; j++) {
arr[j] = input.nextInt();
}
System.out.println(arrStu(arr, n));
}
}
public static String arrStu(int[] arr, int n ){
int[] newArr = new int[n];
for(int i = 0; i<n ;i++){
newArr[i] = arr[i];
}
Arrays.sort(newArr);
int count = 0;
for(int i = 0 ; i< n ;i++){
if(arr[i] != newArr[i]) count++;
}
if(count > 2) return "NO";
else return "YES";
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: In the morning assembly, there are N students standing in a line, such that the ith student from the front has height H[i].
In one move, you can pick any two students and swap their positions.
If you are allowed to do only one swap, can you arrange the students in increasing order of their hieghts?The first line of input contains T, the number of test cases.
The first line of each test case contains N, the number of students in the line.
The second line of each test case contains the heights of N students, where the ith index is the height of ith student.
<b>Constraints:</b>
1 <= T <= 10<sup>3</sup>
1 <= N <= 10<sup>4</sup>
1 <= H_i <= 10<sup>5</sup>For each test case, output YES or NOSample Input
2
3
1 2 3
4
2 1 4 3
Sample Output
YES
NO
Explanation:
The students are already standing in increasing order in the first test case, hence the answer is YES., I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
signed main(){
int t=1;
cin>>t;
while(t--){
int n; cin>>n;
vector<int> v(n);
for(int i=0;i<n;i++){
cin>>v[i];
}
vector<int> b= v;
sort(b.begin(),b.end());
int cnt=0;
for(int i=0;i<n;i++){
if(b[i]!=v[i]) cnt++;
}
if(cnt==0 or cnt==2){
cout<<"YES\n";
}else cout<<"NO\n";
}
return 0;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of integers. Consider absolute difference between all the pairs of the the elements. You need to find Kth smallest absolute difference. If the size of the array is N then value of K will be less than N and more than or equal to 1.The first line of input contains number of test cases T.
The first line of each test case contains a two integers N and K denoting the number of elements in the array A and difference you need to output. The second line of each test case contains N space separated integers denoting the elements of the array A
Constraints:
1<= T <= 10
2 <= N <= 100000
1 <= K < N < 100000
0 <= A[i] <= 100000For each test case, output Kth smallest absolute difference.Input :
1
6 2
1 3 4 1 3 8
Output :
0
Explanation :
Test case 1: First smallest difference is 0, between the pair (1, 1) and second smallest absolute difference difference is also 0 between the pairs (3, 3)., I have written this Solution Code: import java.util.*;
import java.io.*;
import java.lang.*;
class Main{
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine().trim());
while (t-- > 0) {
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
int arr[] = new int[n];
str = read.readLine().trim().split(" ");
for (int i = 0; i < n; i++)
arr[i] = Integer.parseInt(str[i]);
System.out.println(Math.abs(small(arr, k)));
}
}
public static int small(int arr[], int k) {
Arrays.sort(arr);
int l = 0, r = arr[arr.length - 1] - arr[0];
while (r > l) {
int mid = l + (r - l) / 2;
if (count(arr, mid) < k) {
l = mid + 1;
} else {
r = mid;
}
}
return r;
}
public static int count(int arr[], int mid) {
int ans = 0, j = 0;
for (int i = 1; i < arr.length; ++i) {
while (j < i && arr[i] - arr[j] > mid) {
++j;
}
ans += i - j;
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a Binary Tree, your task is to convert it to a Doubly Linked List. The left and right pointers in nodes are to be used as previous and next pointers respectively in converted Double linked list. The order of nodes in Double linked list must be same as Inorder of the given Binary Tree. The first node of Inorder traversal (left most node in Binary tree) must be head node of the Doubly linked list.<b>User Task:</b>
Since this will be a functional problem. You don't have to take input. You just have to complete the function <b>BToDLL()</b> that takes "root" node of binary tree as parameter.
Constraint:-
1 <= Number of Nodes <= 1000
1 <= Node.data <= 1000
The printing is done by the driver code you just need to complete the function.Sample Input:-
3
1 2 3
Sample Output:-
2 1 3
Sample Input:-
5
6 5 4 3 2
Sample Output:-
3 5 2 6 4 , I have written this Solution Code: static void BToDLL(Node root)
{
// Base cases
if (root == null)
return ;
// Recursively convert right subtree
BToDLL(root.right);
// insert root into DLL
root.right = head;
// Change left pointer of previous head
if (head != null)
(head).left = root;
// Change head of Doubly linked list
head = root;
// Recursively convert left subtree
BToDLL(root.left);
} , In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each i (1 < = i < = N), you have to print the number except :-
For each multiple of 3, print "Newton" instead of the number.
For each multiple of 5, print "School" instead of the number.
For numbers that are multiples of both 3 and 5, print "NewtonSchool" instead of the number.The first line of the input contains N.
<b>Constraints</b>
1 < = N < = 1000
Print N space separated number or Newton School according to the condition.Sample Input:-
3
Sample Output:-
1 2 Newton
Sample Input:-
5
Sample Output:-
1 2 Newton 4 School, I have written this Solution Code: n=int(input())
for i in range(1,n+1):
if i%3==0 and i%5==0:
print("NewtonSchool",end=" ")
elif i%3==0:
print("Newton",end=" ")
elif i%5==0:
print("School",end=" ")
else:
print(i,end=" "), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a number N for each i (1 < = i < = N), you have to print the number except :-
For each multiple of 3, print "Newton" instead of the number.
For each multiple of 5, print "School" instead of the number.
For numbers that are multiples of both 3 and 5, print "NewtonSchool" instead of the number.The first line of the input contains N.
<b>Constraints</b>
1 < = N < = 1000
Print N space separated number or Newton School according to the condition.Sample Input:-
3
Sample Output:-
1 2 Newton
Sample Input:-
5
Sample Output:-
1 2 Newton 4 School, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
static void NewtonSchool(int n){
for(int i=1;i<=n;i++){
if(i%3==0 && i%5==0){System.out.print("NewtonSchool ");}
else if(i%5==0){System.out.print("School ");}
else if(i%3==0){System.out.print("Newton ");}
else{System.out.print(i+" ");}
}
}
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int x= sc.nextInt();
NewtonSchool(x);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array A of size N, with all values as non-negative integers. Bodega asked you whether it is possible to partition the array into exactly K non-empty subarrays such that the sum of values of each subarray is equal. If it is possible print "Yes", otherwise print "No".
Note:
Every element of the array should belong to exactly one subarray in the partition.The first line consists of two space-separated integers N and K respectively.
The second line consists of N space-separated integers – A<sub>1</sub>, A<sub>2</sub>, ... A<sub>N</sub>.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ K ≤ 20
0 ≤ A<sub>i</sub> ≤ 10<sup>6</sup>
There exists at least one non-zero element in array A.Print a single word "Yes" if the array can be partitioned into K equal sum parts, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
5 2
2 2 1 2 2
Sample Output 1:
No
Sample Input 2:
10 3
3 0 1 2 0 0 6 0 1 5
Sample Output 2:
Yes
Explanation:
The array can be partitioned as {3, 0, 1, 2, 0, 0}, {6}, {0, 1, 5}., I have written this Solution Code: import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.InputMismatchException;
public class Main {
InputStream is;
PrintWriter out;
String INPUT = "";
void solve(int TC) {
int n = ni(), k = ni();
long sum = 0L, tempSum = 0;
int[] a = new int[n];
for (int i = 0; i < n; i++) {
a[i] = ni();
sum += a[i];
}
if (sum % k != 0) {
pn("No");
return;
}
long req = sum / (long) k;
for (int i : a) {
tempSum += i;
if (tempSum == req) {
tempSum = 0;
} else if (tempSum > req) {
pn("No");
return;
}
}
pn(tempSum == 0 ? "Yes" : "No");
}
boolean TestCases = false;
public static void main(String[] args) throws Exception {
new Main().run();
}
void hold(boolean b) throws Exception {
if (!b) throw new Exception("Hold right there, Sparky!");
}
static void dbg(Object... o) {
System.err.println(Arrays.deepToString(o));
}
void run() throws Exception {
is = INPUT.isEmpty() ? System.in : new ByteArrayInputStream(INPUT.getBytes());
out = new PrintWriter(System.out);
long s = System.currentTimeMillis();
int T = TestCases ? ni() : 1;
for (int t = 1; t <= T; t++) solve(t);
out.flush();
if (!INPUT.isEmpty()) tr(System.currentTimeMillis() - s + "ms");
}
void p(Object o) {
out.print(o);
}
void pn(Object o) {
out.println(o);
}
void pni(Object o) {
out.println(o);
out.flush();
}
int ni() {
int num = 0, b;
boolean minus = false;
while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
if (b == '-') {
minus = true;
b = readByte();
}
while (true) {
if (b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
b = readByte();
}
}
long nl() {
long num = 0;
int b;
boolean minus = false;
while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
if (b == '-') {
minus = true;
b = readByte();
}
while (true) {
if (b >= '0' && b <= '9') {
num = num * 10 + (b - '0');
} else {
return minus ? -num : num;
}
b = readByte();
}
}
double nd() {
return Double.parseDouble(ns());
}
char nc() {
return (char) skip();
}
int BUF_SIZE = 1024 * 8;
byte[] inbuf = new byte[BUF_SIZE];
int lenbuf = 0, ptrbuf = 0;
int readByte() {
if (lenbuf == -1) throw new InputMismatchException();
if (ptrbuf >= lenbuf) {
ptrbuf = 0;
try {
lenbuf = is.read(inbuf);
} catch (IOException e) {
throw new InputMismatchException();
}
if (lenbuf <= 0) return -1;
}
return inbuf[ptrbuf++];
}
boolean isSpaceChar(int c) {
return !(c >= 33 && c <= 126);
}
int skip() {
int b;
while ((b = readByte()) != -1 && isSpaceChar(b)) ;
return b;
}
String ns() {
int b = skip();
StringBuilder sb = new StringBuilder();
while (!(isSpaceChar(b))) {
sb.appendCodePoint(b);
b = readByte();
}
return sb.toString();
}
char[] ns(int n) {
char[] buf = new char[n];
int b = skip(), p = 0;
while (p < n && !(isSpaceChar(b))) {
buf[p++] = (char) b;
b = readByte();
}
return n == p ? buf : Arrays.copyOf(buf, p);
}
void tr(Object... o) {
if (INPUT.length() > 0) System.out.println(Arrays.deepToString(o));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array A of size N, with all values as non-negative integers. Bodega asked you whether it is possible to partition the array into exactly K non-empty subarrays such that the sum of values of each subarray is equal. If it is possible print "Yes", otherwise print "No".
Note:
Every element of the array should belong to exactly one subarray in the partition.The first line consists of two space-separated integers N and K respectively.
The second line consists of N space-separated integers – A<sub>1</sub>, A<sub>2</sub>, ... A<sub>N</sub>.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ K ≤ 20
0 ≤ A<sub>i</sub> ≤ 10<sup>6</sup>
There exists at least one non-zero element in array A.Print a single word "Yes" if the array can be partitioned into K equal sum parts, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
5 2
2 2 1 2 2
Sample Output 1:
No
Sample Input 2:
10 3
3 0 1 2 0 0 6 0 1 5
Sample Output 2:
Yes
Explanation:
The array can be partitioned as {3, 0, 1, 2, 0, 0}, {6}, {0, 1, 5}., I have written this Solution Code:
// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,fma")
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#define pi 3.141592653589793238
#define int long long
#define ll long long
#define ld long double
using namespace __gnu_pbds;
using namespace std;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());
long long powm(long long a, long long b,long long mod) {
long long res = 1;
while (b > 0) {
if (b & 1)
res = res * a %mod;
a = a * a %mod;
b >>= 1;
}
return res;
}
ll gcd(ll a, ll b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(0);
#ifndef ONLINE_JUDGE
if(fopen("input.txt","r"))
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
}
#endif
int n,k;
cin>>n>>k;
int a[n];
int sum=0;
for(int i=0;i<n;i++)
{
cin>>a[i];
sum+=a[i];
}
if(sum%k)
cout<<"No";
else
{
int tot=0;
int cur=0;
sum/=k;
for(int i=0;i<n;i++)
{
cur+=a[i];
if(cur==sum)
{
tot++;
cur=0;
}
}
if(cur==0 && tot==k)
cout<<"Yes";
else
cout<<"No";
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array A of size N, with all values as non-negative integers. Bodega asked you whether it is possible to partition the array into exactly K non-empty subarrays such that the sum of values of each subarray is equal. If it is possible print "Yes", otherwise print "No".
Note:
Every element of the array should belong to exactly one subarray in the partition.The first line consists of two space-separated integers N and K respectively.
The second line consists of N space-separated integers – A<sub>1</sub>, A<sub>2</sub>, ... A<sub>N</sub>.
<b>Constraints:</b>
1 ≤ N ≤ 10<sup>5</sup>
1 ≤ K ≤ 20
0 ≤ A<sub>i</sub> ≤ 10<sup>6</sup>
There exists at least one non-zero element in array A.Print a single word "Yes" if the array can be partitioned into K equal sum parts, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
5 2
2 2 1 2 2
Sample Output 1:
No
Sample Input 2:
10 3
3 0 1 2 0 0 6 0 1 5
Sample Output 2:
Yes
Explanation:
The array can be partitioned as {3, 0, 1, 2, 0, 0}, {6}, {0, 1, 5}., I have written this Solution Code: N,K=map(int,input().split())
S=0
a=input().split()
for i in a:
S+=int(i)
if S%K!=0:
print('No')
else:
su=0
count=0
asd=S/K
for i in range(N):
su+=int(a[i])
if su==asd:
count+=1
su=0
if count==K:
print('Yes')
else:
print('No'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a linked list of N nodes. The task is to reverse the list by changing links between nodes (i.e if the list is 1->2->3->4 then it becomes 1<-2<-3<-4) and return the head of the modified list.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b> ReverseLinkedList</b> that takes head node as parameter.
Constraints:
1 <=N <= 1000
1 <= Node.data<= 100Return the head of the modified linked list.Input-1:
6
1 2 3 4 5 6
Output-1:
6 5 4 3 2 1
Explanation:
After reversing the list, elements are as 6->5->4->3->2->1.
Input-2:
5
1 2 8 4 5
Output-2:
5 4 8 2 1, I have written this Solution Code: public static Node ReverseLinkedList(Node head) {
Node prev = null;
Node current = head;
Node next = null;
while (current != null) {
next = current.next;
current.next = prev;
prev = current;
current = next;
}
head = prev;
return head;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of integers. Consider absolute difference between all the pairs of the the elements. You need to find Kth smallest absolute difference. If the size of the array is N then value of K will be less than N and more than or equal to 1.The first line of input contains number of test cases T.
The first line of each test case contains a two integers N and K denoting the number of elements in the array A and difference you need to output. The second line of each test case contains N space separated integers denoting the elements of the array A
Constraints:
1<= T <= 10
2 <= N <= 100000
1 <= K < N < 100000
0 <= A[i] <= 100000For each test case, output Kth smallest absolute difference.Input :
1
6 2
1 3 4 1 3 8
Output :
0
Explanation :
Test case 1: First smallest difference is 0, between the pair (1, 1) and second smallest absolute difference difference is also 0 between the pairs (3, 3)., I have written this Solution Code: import java.util.*;
import java.io.*;
import java.lang.*;
class Main{
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine().trim());
while (t-- > 0) {
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
int arr[] = new int[n];
str = read.readLine().trim().split(" ");
for (int i = 0; i < n; i++)
arr[i] = Integer.parseInt(str[i]);
System.out.println(Math.abs(small(arr, k)));
}
}
public static int small(int arr[], int k) {
Arrays.sort(arr);
int l = 0, r = arr[arr.length - 1] - arr[0];
while (r > l) {
int mid = l + (r - l) / 2;
if (count(arr, mid) < k) {
l = mid + 1;
} else {
r = mid;
}
}
return r;
}
public static int count(int arr[], int mid) {
int ans = 0, j = 0;
for (int i = 1; i < arr.length; ++i) {
while (j < i && arr[i] - arr[j] > mid) {
++j;
}
ans += i - j;
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a string S of uppercase English alphabets. The task is to count the occurrences of all the prefixes of the given string S.The first line of input contains the string S.
Constraints:
1<= |S| <= 500Print N space separated integers where the i<sup>th</sup> integer is the number of occurrence of prefix [0. i] in the string S. Here, N is the size of string.Sample Input 1:
AAAA
Output
4 3 2 1
Explanation:
A occurs 4 times
AA occurs 3 times.
AAA occurs 2 times.
AAAA occurs 1 times
Sample Input 2:
ABACABA
Output
4 2 2 1 1 1 1
Explanation
A occurs 4 times
AB occurs 2 times
ABA occurs 2 times
ABAC occurs 1 times
ABACA occurs 1 times
ABACAB occurs 1 times
ABACABA occurs 1 times, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main
{
static int[] prefix_function(String s)
{
int []LPS = new int[s.length()];
LPS[0] = 0;
for (int i = 1;i < s.length(); i++)
{
int j = LPS[i - 1];
while (j > 0 && s.charAt(i) != s.charAt(j)) j = LPS[j - 1];
if (s.charAt(i) == s.charAt(j))LPS[i] = j + 1;
else LPS[i] = 0;
}
return LPS;
}
static void count_occurrence(String s)
{
int n = s.length();
int[] LPS = prefix_function(s);
int []occ = new int[n + 1];
for (int i = 0; i < n; i++) occ[LPS[i]]++;
for (int i = n - 1; i > 0; i--) occ[LPS[i - 1]] += occ[i];
for (int i = 0; i <= n; i++) occ[i]++;
for (int i = 1;i <= s.length(); i++) System.out.print(occ[i] +" ");
}
public static void main(String args[]) throws IOException
{
BufferedReader br = new BufferedReader (new InputStreamReader(System.in));
String line = br.readLine();
count_occurrence(line);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a sequence of numbers of size N. You have to find if there is a way to insert + or - operator in between the numbers so that the result equals K.The first line of input contains two integers N and K. The next line of input contains N space- separated integers depicting the values of the sequence.
Constraints:-
1 <= N <= 20
-10^15 <= K <= 10^15
0 <= Numbers <=10^13Print YES if possible else print NO.Sample Input:-
4 4
1 2 3 4
Sample Output:-
YES
Sample Input:-
4 1
1 2 3 4
Sample Output:-
NO, I have written this Solution Code:
import java.io.*;
import java.util.*;
class Main {
public static boolean isArrangementPossible(long arr[],int n,long sum){
if(n==1){
if(arr[0]==sum)
return true;
else
return false;
}
return(isArrangementPossible(arr,n-1,sum-arr[n-1]) || isArrangementPossible(arr,n-1,sum+arr[n-1]));
}
public static void main (String[] args) throws IOException {
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String str1[]=br.readLine().trim().split(" ");
int n=Integer.parseInt(str1[0]);
long sum=Long.parseLong(str1[1]);
String str[]=br.readLine().trim().split(" ");
long arr[]=new long[n];
for(int i=0;i<n;i++){
arr[i]=Long.parseLong(str[i]);
}
if(isArrangementPossible(arr,n,sum)){
System.out.println("YES");
}else{
System.out.println("NO");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a sequence of numbers of size N. You have to find if there is a way to insert + or - operator in between the numbers so that the result equals K.The first line of input contains two integers N and K. The next line of input contains N space- separated integers depicting the values of the sequence.
Constraints:-
1 <= N <= 20
-10^15 <= K <= 10^15
0 <= Numbers <=10^13Print YES if possible else print NO.Sample Input:-
4 4
1 2 3 4
Sample Output:-
YES
Sample Input:-
4 1
1 2 3 4
Sample Output:-
NO, I have written this Solution Code: def checkIfGivenTargetIsPossible(nums,currSum,i,targetSum):
if i == len(nums):
if currSum == targetSum:
return 1
return 0
if(checkIfGivenTargetIsPossible(nums,currSum + nums[i],i+1,targetSum)):
return 1
return checkIfGivenTargetIsPossible(nums,currSum - nums[i], i+1,targetSum)
n,k = map(int,input().split())
nums = list(map(int,input().split()))
if(checkIfGivenTargetIsPossible(nums,0,0,k)):
print("YES")
else:
print("NO"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a sequence of numbers of size N. You have to find if there is a way to insert + or - operator in between the numbers so that the result equals K.The first line of input contains two integers N and K. The next line of input contains N space- separated integers depicting the values of the sequence.
Constraints:-
1 <= N <= 20
-10^15 <= K <= 10^15
0 <= Numbers <=10^13Print YES if possible else print NO.Sample Input:-
4 4
1 2 3 4
Sample Output:-
YES
Sample Input:-
4 1
1 2 3 4
Sample Output:-
NO, I have written this Solution Code: #include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#define int long long
int k;
using namespace std;
int solve(int n, int a[], int i, int curr ){
if(i==n){
if(curr==k){return 1;}
return 0;
}
if(solve(n,a,i+1,curr+a[i])==1){return 1;}
return solve(n,a,i+1,curr-a[i]);
}
signed main() {
int n;
cin>>n>>k;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
}
if(solve(n,a,1,a[0])){
cout<<"YES";}
else{
cout<<"NO";}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print all the even integer from 1 to N.<b>User task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the functions <b>For_Loop()</b> that take the integer n as a parameter.
</b>Constraints:</b>
1 <= n <= 100
<b>Note:</b>
<i>But there is a catch here, given user function has already code in it which may or may not be correct, now you need to figure out these and correct them if it is required</i>Print all the even numbers from 1 to n. (print all the numbers in the same line, space-separated)Sample Input:-
5
Sample Output:-
2 4
Sample Input:-
6
Sample Output:-
2 4 6, I have written this Solution Code: def For_Loop(n):
string = ""
for i in range(1, n+1):
if i % 2 == 0:
string += "%s " % i
return string
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print all the even integer from 1 to N.<b>User task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the functions <b>For_Loop()</b> that take the integer n as a parameter.
</b>Constraints:</b>
1 <= n <= 100
<b>Note:</b>
<i>But there is a catch here, given user function has already code in it which may or may not be correct, now you need to figure out these and correct them if it is required</i>Print all the even numbers from 1 to n. (print all the numbers in the same line, space-separated)Sample Input:-
5
Sample Output:-
2 4
Sample Input:-
6
Sample Output:-
2 4 6, I have written this Solution Code: public static void For_Loop(int n){
for(int i=2;i<=n;i+=2){
System.out.print(i+" ");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Kiran insures his vehicle. According to the insurance policy : the highest rebatable sum for any damage is X dollars, and if the amount required for fixing the damage is ≤ X dollars then the entire payment is rebated. His bike met with an accident, the repairs cost Y dollars. Calculate the amount that the insurance provider will rebate.The first line of input will contain a single integer T, denoting the number of test cases. The first and only line of each test case contains two space- separated integers X and Y.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ X, Y ≤ 30For each test case, output the amount that will be rebated by the insurance company.Sample Input :
4
5 3
5 8
4 4
15 12
Sample Output :
3
5
4
12, I have written this Solution Code: #include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template <class key, class value, class cmp = std::less<key>>
using ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>;
// find_by_order(k) returns iterator to kth element starting from 0;
// order_of_key(k) returns count of elements strictly smaller than k;
#ifdef LOCAL
#define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#else
#define debug(...) 2351
#endif
#define int long long
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
inline int64_t random_long(long long l = LLONG_MIN, long long r = LLONG_MAX) {
uniform_int_distribution<int64_t> generator(l, r);
return generator(rng);
}
// operator overload of << for vector
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
for (const auto &x : v)
os << x << " ";
return os;
}
int32_t main() {
ios_base::sync_with_stdio(true);
cin.tie(nullptr);
cout.tie(nullptr);
auto start = std::chrono::high_resolution_clock::now();
int t, x, y;
cin >> t;
while (t--) {
cin >> x >> y;
if (x >= y) {
cout << y << endl;
} else {
cout << x << endl;
}
}
auto stop = std::chrono::high_resolution_clock::now();
auto duration = std::chrono::duration_cast<std::chrono::nanoseconds>(stop - start);
cerr << "Time taken : " << ((long double)duration.count()) / ((long double)1e9) << "s\n";
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Kiran insures his vehicle. According to the insurance policy : the highest rebatable sum for any damage is X dollars, and if the amount required for fixing the damage is ≤ X dollars then the entire payment is rebated. His bike met with an accident, the repairs cost Y dollars. Calculate the amount that the insurance provider will rebate.The first line of input will contain a single integer T, denoting the number of test cases. The first and only line of each test case contains two space- separated integers X and Y.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ X, Y ≤ 30For each test case, output the amount that will be rebated by the insurance company.Sample Input :
4
5 3
5 8
4 4
15 12
Sample Output :
3
5
4
12, I have written this Solution Code: import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner s=new Scanner(System.in);
int n=s.nextInt();
while(n-->0){
int a=s.nextInt();
int b=s.nextInt();
if(a<=b)
System.out.println(a);
else
System.out.println(b);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: In this question, you need to create a class <b>Student</b> which has 4 parameters:-
<b>name ( String )</b>
<b>eng (int) </b>
<b>maths (int) </b>
<b>hindi (int) </b>
Also, you need to complete the given three functions:-
<b>createStudentArray</b>:- In which you need to create an array of students and take input
<b>engAverage</b>:- In which you need to create an average of marks in English.
<b>avgPercentageOfClass</b>:- In which you need to calculate the average percentage of the class.
Note:- Scanner is already defined in this question. Use "sc" for scanner.You need to take the input in <b>createStudentArray()</b> only in which you have already provided the number of students N you just have to create an array of size N and take input respectively.
Constraints:-
1 <= N <= 1000Return the Student array in <b>createStudentArray()</b>, Return the floor of average marks in english in <b>engAverage</b>, and return the floor of average percentage of the class in <b.avgPercentageOfClas</b>.
Note:- In <b>avgPercentageOfClas</b> you first need to create the average of individual then find the average of all the students.Sample Input:-
3
Shiv 65 47 78
Negi 55 40 56
Gargi 43 56 40
Sample Output:-
54
53
Explanation:-
Average marks in eng = (65 + 55 + 43)/3 = 163/3 = 54
Average percentage of class =>
shiv = (65 + 47 + 78)/3 = 190/3 = 63
Negi = (55 + 40 + 56)/3 = 151/3 = 50
Gargi = (43 + 56 + 40)/3 = 139/3 = 46
avg = (63 + 50 + 46 )/3 = 159 = 53, I have written this Solution Code:
class Student:
def __init__(self, name, eng, maths, hindi):
self.name=name
self.eng=eng
self.maths=maths
self.hindi=hindi
def createStudentArray(n):
stulist=[]
for i in range(n):
Name,Eng,Maths,Hindi=input().split()
s=Student(Name,int(Eng),int(Maths),int(Hindi))
stulist.append(s)
return stulist
def engAverage(arr):
total=0
for i in arr:
total+=i.eng
return int(total/len(arr))
def avgPercentageOfClass(arr):
subtotal=0
total=0
for i in arr:
subtotal=(i.eng+i.maths+i.hindi)//3
total+=subtotal
return int(total/len(arr))
N=int(input())
arr=createStudentArray(N)
print(engAverage(arr))
print(avgPercentageOfClass(arr)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: In this question, you need to create a class <b>Student</b> which has 4 parameters:-
<b>name ( String )</b>
<b>eng (int) </b>
<b>maths (int) </b>
<b>hindi (int) </b>
Also, you need to complete the given three functions:-
<b>createStudentArray</b>:- In which you need to create an array of students and take input
<b>engAverage</b>:- In which you need to create an average of marks in English.
<b>avgPercentageOfClass</b>:- In which you need to calculate the average percentage of the class.
Note:- Scanner is already defined in this question. Use "sc" for scanner.You need to take the input in <b>createStudentArray()</b> only in which you have already provided the number of students N you just have to create an array of size N and take input respectively.
Constraints:-
1 <= N <= 1000Return the Student array in <b>createStudentArray()</b>, Return the floor of average marks in english in <b>engAverage</b>, and return the floor of average percentage of the class in <b.avgPercentageOfClas</b>.
Note:- In <b>avgPercentageOfClas</b> you first need to create the average of individual then find the average of all the students.Sample Input:-
3
Shiv 65 47 78
Negi 55 40 56
Gargi 43 56 40
Sample Output:-
54
53
Explanation:-
Average marks in eng = (65 + 55 + 43)/3 = 163/3 = 54
Average percentage of class =>
shiv = (65 + 47 + 78)/3 = 190/3 = 63
Negi = (55 + 40 + 56)/3 = 151/3 = 50
Gargi = (43 + 56 + 40)/3 = 139/3 = 46
avg = (63 + 50 + 46 )/3 = 159 = 53, I have written this Solution Code:
static class Student
{
String name;
int eng, maths, hindi;
}
static Student[] createStudentArray(int n)
{
Student st[] = new Student[n];
for(int i = 0; i < n; i++)
{
st[i] = new Student();
st[i].name = sc.next();
st[i].eng = sc.nextInt();
st[i].hindi = sc.nextInt();
st[i].maths = sc.nextInt();
}
return st;
}
static int engAverage(Student st[], int n)
{
int sum = 0;
for(int i = 0; i < n; i++)
{
sum += st[i].eng;
}
return sum/n;
}
static int avgPercentageOfClass(Student st[], int n)
{
int sum = 0; int avg = 0;
for(int i = 0; i < n; i++)
{
sum = 0;
sum += st[i].eng + st[i].maths + st[i].hindi;
avg += sum/3;
}
return avg/(n);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
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