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The dataset generation failed because of a cast error
Error code: DatasetGenerationCastError
Exception: DatasetGenerationCastError
Message: An error occurred while generating the dataset
All the data files must have the same columns, but at some point there are 3 new columns ({'Category', 'Filename', 'Unnamed: 0'}) and 5 missing columns ({'FunctionCall', 'ExecutedLines_Symbols', 'Code_Symbols', 'HumanEval_ID', 'Name'}).
This happened while the csv dataset builder was generating data using
hf://datasets/ClaasBeger/CoCoNUT/program_traces_Python_Concurrency_Lines.csv (at revision e53780c76af971f87c71cfa0423fb3c22a75b4ac)
Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)
Traceback: Traceback (most recent call last):
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1870, in _prepare_split_single
writer.write_table(table)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/arrow_writer.py", line 622, in write_table
pa_table = table_cast(pa_table, self._schema)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2292, in table_cast
return cast_table_to_schema(table, schema)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2240, in cast_table_to_schema
raise CastError(
datasets.table.CastError: Couldn't cast
Unnamed: 0: int64
Filename: string
Category: string
ExecutedLines: string
Code_Indices: string
-- schema metadata --
pandas: '{"index_columns": [{"kind": "range", "name": null, "start": 0, "' + 860
to
{'HumanEval_ID': Value(dtype='string', id=None), 'Name': Value(dtype='string', id=None), 'FunctionCall': Value(dtype='string', id=None), 'ExecutedLines': Value(dtype='string', id=None), 'ExecutedLines_Symbols': Value(dtype='string', id=None), 'Code_Indices': Value(dtype='string', id=None), 'Code_Symbols': Value(dtype='string', id=None)}
because column names don't match
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1420, in compute_config_parquet_and_info_response
parquet_operations = convert_to_parquet(builder)
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1052, in convert_to_parquet
builder.download_and_prepare(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 924, in download_and_prepare
self._download_and_prepare(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1000, in _download_and_prepare
self._prepare_split(split_generator, **prepare_split_kwargs)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1741, in _prepare_split
for job_id, done, content in self._prepare_split_single(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1872, in _prepare_split_single
raise DatasetGenerationCastError.from_cast_error(
datasets.exceptions.DatasetGenerationCastError: An error occurred while generating the dataset
All the data files must have the same columns, but at some point there are 3 new columns ({'Category', 'Filename', 'Unnamed: 0'}) and 5 missing columns ({'FunctionCall', 'ExecutedLines_Symbols', 'Code_Symbols', 'HumanEval_ID', 'Name'}).
This happened while the csv dataset builder was generating data using
hf://datasets/ClaasBeger/CoCoNUT/program_traces_Python_Concurrency_Lines.csv (at revision e53780c76af971f87c71cfa0423fb3c22a75b4ac)
Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)Need help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
HumanEval_ID
string | Name
string | FunctionCall
string | ExecutedLines
string | ExecutedLines_Symbols
string | Code_Indices
string | Code_Symbols
string |
|---|---|---|---|---|---|---|
HumanEval/0 | has_close_elements | [1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 19] | nopopqropqropqropqropqronopqropopqropqropqropqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 14, 21] | nopopqropqropqropqropqronopqropopqropqropqropqronopqropqropopqropqropqronopqropqropqropopqropqronopqropqropqropqropopqronopqropqropqropqropqroponu | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 5.9, 4.0, 5.0], 0.95 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 19] | nopopqropqropqropqronopqropopqropqropqronopqropqropopqropqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 5.9, 4.0, 5.0], 0.8 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 14, 21] | nopopqropqropqropqronopqropopqropqropqronopqropqropopqropqronopqropqropqropopqronopqropqropqropqroponu | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 19] | nopopqropqropqropqropqronopqropopqropqropqropqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.1, 2.2, 3.1, 4.1, 5.1], 1.0 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 19] | nopopqropqropqropqronopqropopqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.1, 2.2, 3.1, 4.1, 5.1], 0.5 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 14, 21] | nopopqropqropqropqronopqropopqropqropqronopqropqropopqropqronopqropqropqropopqronopqropqropqropqroponu | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/1 | separate_paren_groups | ('( ) (( )) (( )( ))',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprstursvrsvwxzABrsvrsturstursvrsvwxzrsvwxzABrsvrsturstursvrsvwxzrstursvrsvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/1 | separate_paren_groups | ('(()(())((())))',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprsturstursvwxzrsturstursvwxzrsvwxzrstursturstursvwxzrsvwxzrsvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/1 | separate_paren_groups | ('() (()) ((())) (((())))',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprstursvwxzABrsvrsturstursvwxzrsvwxzABrsvrstursturstursvwxzrsvwxzrsvwxzABrsvrsturstursturstursvwxzrsvwxzrsvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/1 | separate_paren_groups | ('(()()) ((())) () ((())()())',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprsturstursvwxzrstursvwxzrsvwxzABrsvrstursturstursvwxzrsvwxzrsvwxzABrsvrstursvwxzABrsvrstursturstursvwxzrsvwxzrstursvwxzrstursvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/10 | make_palindrome | 'x' | [22, 25, 27, 6, 30] | vyAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | 'jerry' | [22, 25, 27, 6, 28, 27, 6, 28, 27, 6, 28, 27, 6, 28, 27, 6, 30] | vyAfBAfBAfBAfBAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | 'xyx' | [22, 25, 27, 6, 30] | vyAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | 'xyz' | [22, 25, 27, 6, 28, 27, 6, 28, 27, 6, 30] | vyAfBAfBAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | '' | [22, 23] | vw | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/100 | make_a_pile | (3,) | [18, 18, 18, 18, 18] | rrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (4,) | [18, 18, 18, 18, 18, 18] | rrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (5,) | [18, 18, 18, 18, 18, 18, 18] | rrrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (6,) | [18, 18, 18, 18, 18, 18, 18, 18] | rrrrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (8,) | [18, 18, 18, 18, 18, 18, 18, 18, 18, 18] | rrrrrrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/101 | words_string | "One, two, three, four, five, six" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrsvrstrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "" | [13, 14] | mn | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "One,, two, three, four, five, six," | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 24, 25] | mprsvrsvrsvrstrstrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrstrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "Hi, my name" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrstrsvrsvrsvrsvrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "ahmed , gamal" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "Hi, my name is John" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrstrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/102 | choose_num | 7, 7 | [13, 15, 17, 18] | moqr | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 33, 12354 | [13, 15, 16] | mop | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 5234, 5233 | [13, 14] | mn | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 6, 29 | [13, 15, 17, 19] | moqs | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 27, 10 | [13, 14] | mn | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 546, 546 | [13, 15, 16] | mop | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 13, 12 | [13, 14] | mn | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 12, 15 | [13, 15, 17, 19] | moqs | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/103 | rounded_avg | 1, 5 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 7, 13 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 964,977 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrsrsrsrsrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 996,997 | [15, 17, 18, 19, 18, 19, 18, 20] | oqrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 197,233 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 7, 5 | [15, 16] | op | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 5, 1 | [15, 16] | op | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 5, 5 | [15, 17, 18, 19, 18, 20] | oqrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/104 | unique_digits | [12345, 2033, 111, 151] | [16, 17, 18, 18, 18, 17, 18, 18, 17, 18, 18, 18, 18, 18, 19, 17, 18, 18, 18, 18, 18, 19, 17, 20] | pqrrrqrrqrrrrrsqrrrrrsqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/104 | unique_digits | [15, 33, 1422, 1] | [16, 17, 18, 18, 18, 18, 19, 17, 18, 18, 18, 18, 19, 17, 18, 18, 18, 17, 18, 18, 18, 19, 17, 20] | pqrrrrsqrrrrsqrrrqrrrsqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/104 | unique_digits | [152, 323, 1422, 10] | [16, 17, 18, 18, 18, 18, 17, 18, 18, 18, 17, 18, 18, 18, 17, 18, 18, 18, 17, 20] | pqrrrrqrrrqrrrqrrrqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/104 | unique_digits | [135, 103, 31] | [16, 17, 18, 18, 18, 18, 18, 19, 17, 18, 18, 18, 17, 18, 18, 18, 18, 19, 17, 20] | pqrrrrrsqrrrqrrrrsqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/105 | by_length | [2, 1, 1, 4, 5, 8, 2, 3] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 44] | ABCDEFGHIzKLMNOMNOMNOMNOMNOMNOMNOMNOMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [1, -1 , 55] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 42, 43, 39, 40, 41, 39, 40, 41, 42, 43, 39, 44] | ABCDEFGHIzKLMNOPQMNOMNOPQMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [1, -1, 3, 2] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 42, 43, 39, 44] | ABCDEFGHIzKLMNOMNOMNOMNOPQMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [9, 4, 8] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 44] | ABCDEFGHIzKLMNOMNOMNOMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 44] | ABCDEFGHIzKLMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/106 | f | 5 | [13, 14, 15, 20, 21, 21, 22, 14, 15, 16, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 22, 14, 15, 16, 17, 17, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 21, 21, 22, 14, 23] | mnotuuvnopqqqrnotuuuuvnopqqqqqrnotuuuuuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/106 | f | 7 | [13, 14, 15, 20, 21, 21, 22, 14, 15, 16, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 22, 14, 15, 16, 17, 17, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 21, 21, 22, 14, 15, 16, 17, 17, 17, 17, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 21, 21, 21, 21, 22, 14, 23] | mnotuuvnopqqqrnotuuuuvnopqqqqqrnotuuuuuuvnopqqqqqqqrnotuuuuuuuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/106 | f | 1 | [13, 14, 15, 20, 21, 21, 22, 14, 23] | mnotuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/106 | f | 3 | [13, 14, 15, 20, 21, 21, 22, 14, 15, 16, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 22, 14, 23] | mnotuuvnopqqqrnotuuuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/107 | even_odd_palindrome | 3 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 38] | ADEGHBIGHJBKGHBIGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 9 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 19 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBGHBIGHJBGHBJGHJBGHBJGHJBGHBJGHJBGHBJGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 1 | [27, 30, 31, 33, 34, 28, 35, 33, 38] | ADEGHBIGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 12 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 35, 33, 34, 36, 28, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBGHBIGHJBGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 25 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 37, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBGHBIGHJBGHBJGHJBGHBJGHJBGHBJGHJBGHBJGHJBGHBJGHJBKGHBJGHJBGHBJGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/108 | count_nums | [-1, -2, 0] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20] | nttopqqqrstopqqqrstopqqqrstttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1, 6, 9, -6, 0, 1, 5] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20, 20] | nttopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1, 100, 98, -7, 1, -1] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20] | nttopqqqrstopqqqqqrstopqqqqrstopqqqrstopqqqrstopqqqrsttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [12, 23, 34, -45, -56, 0] | [14, 20, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20] | nttopqqqqrstopqqqqrstopqqqqrstopqqqqrstopqqqqrstopqqqrsttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [-0, 1**0] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20] | nttopqqqrstopqqqrsttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20] | nttopqqqrstt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1, 1, 2, -2, 3, 4, 5] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20, 20] | nttopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [] | [14, 20, 20] | ntt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/109 | move_one_ball | [4, 3, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 41] | EGHJKLMNMNMNO | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [3, 5, 10, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 39, 40, 39, 40, 39, 42] | EGHJKLMNMNMNMNMNMP | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [3, 5, 4, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 39, 40, 41] | EGHJKLMNMNMNMNO | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [3, 4, 5, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 39, 40, 39, 40, 39, 42] | EGHJKLMNMNMNMNMNMP | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [] | [31, 32] | EF | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/11 | string_xor | ('1', '1') | [12, 18, 18, 13, 14, 18] | lrrmnr | from typing import List # 1
# 2
# 3
def string_xor(a: str, b: str) -> str: # 4
# 5
""" Input are two strings a and b consisting only of 1s and 0s. # 6
Perform binary XOR on these inputs and return result also as a string. # 7
>>> string_xor('010', '110') # 8
'100' # 9
""" # 10
# 11
def xor(i, j): # 12
if i == j: # 13
return '0' # 14
else: # 15
return '1' # 16
# 17
return ''.join(xor(x, y) for x, y in zip(a, b)) # 18
# 19 | from typing import List # a
# b
# c
def string_xor(a: str, b: str) -> str: # d
# e
""" Input are two strings a and b consisting only of 1s and 0s. # f
Perform binary XOR on these inputs and return result also as a string. # g
>>> string_xor('010', '110') # h
'100' # i
""" # j
# k
def xor(i, j): # l
if i == j: # m
return '0' # n
else: # o
return '1' # p
# q
return ''.join(xor(x, y) for x, y in zip(a, b)) # r
# s |
HumanEval/11 | string_xor | ('111000', '101010') | [12, 18, 18, 13, 14, 18, 13, 16, 18, 13, 14, 18, 13, 14, 18, 13, 16, 18, 13, 14, 18] | lrrmnrmprmnrmnrmprmnr | from typing import List # 1
# 2
# 3
def string_xor(a: str, b: str) -> str: # 4
# 5
""" Input are two strings a and b consisting only of 1s and 0s. # 6
Perform binary XOR on these inputs and return result also as a string. # 7
>>> string_xor('010', '110') # 8
'100' # 9
""" # 10
# 11
def xor(i, j): # 12
if i == j: # 13
return '0' # 14
else: # 15
return '1' # 16
# 17
return ''.join(xor(x, y) for x, y in zip(a, b)) # 18
# 19 | from typing import List # a
# b
# c
def string_xor(a: str, b: str) -> str: # d
# e
""" Input are two strings a and b consisting only of 1s and 0s. # f
Perform binary XOR on these inputs and return result also as a string. # g
>>> string_xor('010', '110') # h
'100' # i
""" # j
# k
def xor(i, j): # l
if i == j: # m
return '0' # n
else: # o
return '1' # p
# q
return ''.join(xor(x, y) for x, y in zip(a, b)) # r
# s |
HumanEval/11 | string_xor | ('0101', '0000') | [12, 18, 18, 13, 14, 18, 13, 16, 18, 13, 14, 18, 13, 16, 18] | lrrmnrmprmnrmpr | from typing import List # 1
# 2
# 3
def string_xor(a: str, b: str) -> str: # 4
# 5
""" Input are two strings a and b consisting only of 1s and 0s. # 6
Perform binary XOR on these inputs and return result also as a string. # 7
>>> string_xor('010', '110') # 8
'100' # 9
""" # 10
# 11
def xor(i, j): # 12
if i == j: # 13
return '0' # 14
else: # 15
return '1' # 16
# 17
return ''.join(xor(x, y) for x, y in zip(a, b)) # 18
# 19 | from typing import List # a
# b
# c
def string_xor(a: str, b: str) -> str: # d
# e
""" Input are two strings a and b consisting only of 1s and 0s. # f
Perform binary XOR on these inputs and return result also as a string. # g
>>> string_xor('010', '110') # h
'100' # i
""" # j
# k
def xor(i, j): # l
if i == j: # m
return '0' # n
else: # o
return '1' # p
# q
return ''.join(xor(x, y) for x, y in zip(a, b)) # r
# s |
HumanEval/110 | exchange | [3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 19, 20, 21, 19, 20, 19, 20, 21, 19, 22, 23, 22, 23, 22, 23, 22, 23, 22, 23, 22, 23, 22, 25, 27] | qrstustststuststusvwvwvwvwvwvwvyA | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [5, 7, 3], [2, 6, 3] | [17, 18, 19, 20, 21, 19, 20, 21, 19, 20, 21, 19, 22, 23, 24, 22, 23, 24, 22, 23, 22, 25, 27] | qrstustustusvwxvwxvwvyA | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [5, 7, 3], [2, 6, 4] | [17, 18, 19, 20, 21, 19, 20, 21, 19, 20, 21, 19, 22, 23, 24, 22, 23, 24, 22, 23, 24, 22, 25, 26] | qrstustustusvwxvwxvwxvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [1, 2, 3, 4], [2, 1, 4, 3] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 21, 19, 20, 19, 22, 23, 24, 22, 23, 22, 23, 24, 22, 23, 22, 25, 26] | qrstuststustsvwxvwvwxvwvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [1, 2, 3, 4], [1, 5, 3, 4] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 21, 19, 20, 19, 22, 23, 22, 23, 22, 23, 22, 23, 24, 22, 25, 27] | qrstuststustsvwvwvwvwxvyA | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [100, 200], [200, 200] | [17, 18, 19, 20, 19, 20, 19, 22, 23, 24, 22, 23, 24, 22, 25, 26] | qrststsvwxvwxvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [1, 2, 3, 4], [1, 2, 3, 4] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 21, 19, 20, 19, 22, 23, 22, 23, 24, 22, 23, 22, 23, 24, 22, 25, 26] | qrstuststustsvwvwxvwvwxvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/111 | histogram | 'a b b a' | [17, 18, 19, 21, 22, 23, 21, 22, 21, 22, 21, 22, 21, 24, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 29] | qrsuvwuvuvuvuxyzByzByzByzByC | # 1
def histogram(test): # 2
# 3
"""Given a string representing a space separated lowercase letters, return a dictionary # 4
of the letter with the most repetition and containing the corresponding count. # 5
If several letters have the same occurrence, return all of them. # 6
# 7
Example: # 8
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # 9
histogram('a b b a') == {'a': 2, 'b': 2} # 10
histogram('a b c a b') == {'a': 2, 'b': 2} # 11
histogram('b b b b a') == {'b': 4} # 12
histogram('') == {} # 13
# 14
""" # 15
# 16
dict1={} # 17
list1=test.split(" ") # 18
t=0 # 19
# 20
for i in list1: # 21
if(list1.count(i)>t) and i!='': # 22
t=list1.count(i) # 23
if t>0: # 24
for i in list1: # 25
if(list1.count(i)==t): # 26
# 27
dict1[i]=t # 28
return dict1 # 29
# 30 | # a
def histogram(test): # b
# c
"""Given a string representing a space separated lowercase letters, return a dictionary # d
of the letter with the most repetition and containing the corresponding count. # e
If several letters have the same occurrence, return all of them. # f
# g
Example: # h
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # i
histogram('a b b a') == {'a': 2, 'b': 2} # j
histogram('a b c a b') == {'a': 2, 'b': 2} # k
histogram('b b b b a') == {'b': 4} # l
histogram('') == {} # m
# n
""" # o
# p
dict1={} # q
list1=test.split(" ") # r
t=0 # s
# t
for i in list1: # u
if(list1.count(i)>t) and i!='': # v
t=list1.count(i) # w
if t>0: # x
for i in list1: # y
if(list1.count(i)==t): # z
# A
dict1[i]=t # B
return dict1 # C
# D |
HumanEval/111 | histogram | 'r t g' | [17, 18, 19, 21, 22, 23, 21, 22, 21, 22, 21, 24, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 29] | qrsuvwuvuvuxyzByzByzByC | # 1
def histogram(test): # 2
# 3
"""Given a string representing a space separated lowercase letters, return a dictionary # 4
of the letter with the most repetition and containing the corresponding count. # 5
If several letters have the same occurrence, return all of them. # 6
# 7
Example: # 8
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # 9
histogram('a b b a') == {'a': 2, 'b': 2} # 10
histogram('a b c a b') == {'a': 2, 'b': 2} # 11
histogram('b b b b a') == {'b': 4} # 12
histogram('') == {} # 13
# 14
""" # 15
# 16
dict1={} # 17
list1=test.split(" ") # 18
t=0 # 19
# 20
for i in list1: # 21
if(list1.count(i)>t) and i!='': # 22
t=list1.count(i) # 23
if t>0: # 24
for i in list1: # 25
if(list1.count(i)==t): # 26
# 27
dict1[i]=t # 28
return dict1 # 29
# 30 | # a
def histogram(test): # b
# c
"""Given a string representing a space separated lowercase letters, return a dictionary # d
of the letter with the most repetition and containing the corresponding count. # e
If several letters have the same occurrence, return all of them. # f
# g
Example: # h
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # i
histogram('a b b a') == {'a': 2, 'b': 2} # j
histogram('a b c a b') == {'a': 2, 'b': 2} # k
histogram('b b b b a') == {'b': 4} # l
histogram('') == {} # m
# n
""" # o
# p
dict1={} # q
list1=test.split(" ") # r
t=0 # s
# t
for i in list1: # u
if(list1.count(i)>t) and i!='': # v
t=list1.count(i) # w
if t>0: # x
for i in list1: # y
if(list1.count(i)==t): # z
# A
dict1[i]=t # B
return dict1 # C
# D |
HumanEval/111 | histogram | 'b b b b a' | [17, 18, 19, 21, 22, 23, 21, 22, 21, 22, 21, 22, 21, 22, 21, 24, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 26, 25, 29] | qrsuvwuvuvuvuvuxyzByzByzByzByzyC | # 1
def histogram(test): # 2
# 3
"""Given a string representing a space separated lowercase letters, return a dictionary # 4
of the letter with the most repetition and containing the corresponding count. # 5
If several letters have the same occurrence, return all of them. # 6
# 7
Example: # 8
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # 9
histogram('a b b a') == {'a': 2, 'b': 2} # 10
histogram('a b c a b') == {'a': 2, 'b': 2} # 11
histogram('b b b b a') == {'b': 4} # 12
histogram('') == {} # 13
# 14
""" # 15
# 16
dict1={} # 17
list1=test.split(" ") # 18
t=0 # 19
# 20
for i in list1: # 21
if(list1.count(i)>t) and i!='': # 22
t=list1.count(i) # 23
if t>0: # 24
for i in list1: # 25
if(list1.count(i)==t): # 26
# 27
dict1[i]=t # 28
return dict1 # 29
# 30 | # a
def histogram(test): # b
# c
"""Given a string representing a space separated lowercase letters, return a dictionary # d
of the letter with the most repetition and containing the corresponding count. # e
If several letters have the same occurrence, return all of them. # f
# g
Example: # h
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # i
histogram('a b b a') == {'a': 2, 'b': 2} # j
histogram('a b c a b') == {'a': 2, 'b': 2} # k
histogram('b b b b a') == {'b': 4} # l
histogram('') == {} # m
# n
""" # o
# p
dict1={} # q
list1=test.split(" ") # r
t=0 # s
# t
for i in list1: # u
if(list1.count(i)>t) and i!='': # v
t=list1.count(i) # w
if t>0: # x
for i in list1: # y
if(list1.count(i)==t): # z
# A
dict1[i]=t # B
return dict1 # C
# D |
End of preview.
Dataset Info:
CoCoNUT investigates the capabilities of selected Large Language Models on understanding structural code execution. The dataset includes tasks where models reproduce the code lines executed for specific input arguments, testing advanced code concepts such as Object-Oriented Programming (OOP), Concurrency, and Recursion. The dataset contains short programs, their traces, and the corresponding call arguments. For advanced topics, no call arguments are needed since they are directly contained in the main function. The Code can be found at the github repository: https://github.com/ClaasBeger/StructuralCodeUnderstanding and the paper pre-print is available at \cite{arxiv.org/abs/2501.16456}
Model Performance:
Citation
@misc{beger2025coconutstructuralcodeunderstanding,
title={CoCoNUT: Structural Code Understanding does not fall out of a tree},
author={Claas Beger and Saikat Dutta},
year={2025},
eprint={2501.16456},
archivePrefix={arXiv},
primaryClass={cs.LG},
url={https://arxiv.org/abs/2501.16456},
}
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