The full dataset viewer is not available (click to read why). Only showing a preview of the rows.
The dataset generation failed because of a cast error
Error code: DatasetGenerationCastError
Exception: DatasetGenerationCastError
Message: An error occurred while generating the dataset
All the data files must have the same columns, but at some point there are 3 new columns ({'Category', 'Filename', 'Unnamed: 0'}) and 5 missing columns ({'FunctionCall', 'ExecutedLines_Symbols', 'Code_Symbols', 'HumanEval_ID', 'Name'}).
This happened while the csv dataset builder was generating data using
hf://datasets/ClaasBeger/CoCoNUT/program_traces_Python_Concurrency_Lines.csv (at revision e53780c76af971f87c71cfa0423fb3c22a75b4ac)
Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)
Traceback: Traceback (most recent call last):
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1870, in _prepare_split_single
writer.write_table(table)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/arrow_writer.py", line 622, in write_table
pa_table = table_cast(pa_table, self._schema)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2292, in table_cast
return cast_table_to_schema(table, schema)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2240, in cast_table_to_schema
raise CastError(
datasets.table.CastError: Couldn't cast
Unnamed: 0: int64
Filename: string
Category: string
ExecutedLines: string
Code_Indices: string
-- schema metadata --
pandas: '{"index_columns": [{"kind": "range", "name": null, "start": 0, "' + 860
to
{'HumanEval_ID': Value(dtype='string', id=None), 'Name': Value(dtype='string', id=None), 'FunctionCall': Value(dtype='string', id=None), 'ExecutedLines': Value(dtype='string', id=None), 'ExecutedLines_Symbols': Value(dtype='string', id=None), 'Code_Indices': Value(dtype='string', id=None), 'Code_Symbols': Value(dtype='string', id=None)}
because column names don't match
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1420, in compute_config_parquet_and_info_response
parquet_operations = convert_to_parquet(builder)
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1052, in convert_to_parquet
builder.download_and_prepare(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 924, in download_and_prepare
self._download_and_prepare(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1000, in _download_and_prepare
self._prepare_split(split_generator, **prepare_split_kwargs)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1741, in _prepare_split
for job_id, done, content in self._prepare_split_single(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1872, in _prepare_split_single
raise DatasetGenerationCastError.from_cast_error(
datasets.exceptions.DatasetGenerationCastError: An error occurred while generating the dataset
All the data files must have the same columns, but at some point there are 3 new columns ({'Category', 'Filename', 'Unnamed: 0'}) and 5 missing columns ({'FunctionCall', 'ExecutedLines_Symbols', 'Code_Symbols', 'HumanEval_ID', 'Name'}).
This happened while the csv dataset builder was generating data using
hf://datasets/ClaasBeger/CoCoNUT/program_traces_Python_Concurrency_Lines.csv (at revision e53780c76af971f87c71cfa0423fb3c22a75b4ac)
Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)Need help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
HumanEval_ID
string | Name
string | FunctionCall
string | ExecutedLines
string | ExecutedLines_Symbols
string | Code_Indices
string | Code_Symbols
string |
|---|---|---|---|---|---|---|
HumanEval/0 | has_close_elements | [1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 19] | nopopqropqropqropqropqronopqropopqropqropqropqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 14, 21] | nopopqropqropqropqropqronopqropopqropqropqropqronopqropqropopqropqropqronopqropqropqropopqropqronopqropqropqropqropopqronopqropqropqropqropqroponu | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 5.9, 4.0, 5.0], 0.95 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 19] | nopopqropqropqropqronopqropopqropqropqronopqropqropopqropqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 5.9, 4.0, 5.0], 0.8 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 14, 21] | nopopqropqropqropqronopqropopqropqropqronopqropqropopqropqronopqropqropqropopqronopqropqropqropqroponu | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 19] | nopopqropqropqropqropqronopqropopqropqropqropqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.1, 2.2, 3.1, 4.1, 5.1], 1.0 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 19] | nopopqropqropqropqronopqropopqrs | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/0 | has_close_elements | [1.1, 2.2, 3.1, 4.1, 5.1], 0.5 | [14, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 16, 17, 18, 15, 14, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 17, 18, 15, 16, 15, 14, 21] | nopopqropqropqropqronopqropopqropqropqronopqropqropopqropqronopqropqropqropopqronopqropqropqropqroponu | from typing import List # 1
# 2
# 3
def has_close_elements(numbers: List[float], threshold: float) -> bool: # 4
# 5
""" Check if in given list of numbers, are any two numbers closer to each other than # 6
given threshold. # 7
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # 8
False # 9
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # 10
True # 11
""" # 12
# 13
for idx, elem in enumerate(numbers): # 14
for idx2, elem2 in enumerate(numbers): # 15
if idx != idx2: # 16
distance = abs(elem - elem2) # 17
if distance < threshold: # 18
return True # 19
# 20
return False # 21
# 22 | from typing import List # a
# b
# c
def has_close_elements(numbers: List[float], threshold: float) -> bool: # d
# e
""" Check if in given list of numbers, are any two numbers closer to each other than # f
given threshold. # g
>>> has_close_elements([1.0, 2.0, 3.0], 0.5) # h
False # i
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) # j
True # k
""" # l
# m
for idx, elem in enumerate(numbers): # n
for idx2, elem2 in enumerate(numbers): # o
if idx != idx2: # p
distance = abs(elem - elem2) # q
if distance < threshold: # r
return True # s
# t
return False # u
# v |
HumanEval/1 | separate_paren_groups | ('( ) (( )) (( )( ))',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprstursvrsvwxzABrsvrsturstursvrsvwxzrsvwxzABrsvrsturstursvrsvwxzrstursvrsvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/1 | separate_paren_groups | ('(()(())((())))',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprsturstursvwxzrsturstursvwxzrsvwxzrstursturstursvwxzrsvwxzrsvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/1 | separate_paren_groups | ('() (()) ((())) (((())))',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprstursvwxzABrsvrsturstursvwxzrsvwxzABrsvrstursturstursvwxzrsvwxzrsvwxzABrsvrsturstursturstursvwxzrsvwxzrsvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/1 | separate_paren_groups | ('(()()) ((())) () ((())()())',) | [14, 15, 16, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 27, 28, 18, 19, 22, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 20, 21, 18, 19, 22, 23, 24, 26, 18, 19, 22, 23, 24, 26, 27, 28, 18, 30] | noprsturstursvwxzrstursvwxzrsvwxzABrsvrstursturstursvwxzrsvwxzrsvwxzABrsvrstursvwxzABrsvrstursturstursvwxzrsvwxzrstursvwxzrstursvwxzrsvwxzABrD | from typing import List # 1
# 2
# 3
def separate_paren_groups(paren_string: str) -> List[str]: # 4
# 5
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # 6
separate those group into separate strings and return the list of those. # 7
Separate groups are balanced (each open brace is properly closed) and not nested within each other # 8
Ignore any spaces in the input string. # 9
>>> separate_paren_groups('( ) (( )) (( )( ))') # 10
['()', '(())', '(()())'] # 11
""" # 12
# 13
result = [] # 14
current_string = [] # 15
current_depth = 0 # 16
# 17
for c in paren_string: # 18
if c == '(': # 19
current_depth += 1 # 20
current_string.append(c) # 21
elif c == ')': # 22
current_depth -= 1 # 23
current_string.append(c) # 24
# 25
if current_depth == 0: # 26
result.append(''.join(current_string)) # 27
current_string.clear() # 28
# 29
return result # 30
# 31 | from typing import List # a
# b
# c
def separate_paren_groups(paren_string: str) -> List[str]: # d
# e
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to # f
separate those group into separate strings and return the list of those. # g
Separate groups are balanced (each open brace is properly closed) and not nested within each other # h
Ignore any spaces in the input string. # i
>>> separate_paren_groups('( ) (( )) (( )( ))') # j
['()', '(())', '(()())'] # k
""" # l
# m
result = [] # n
current_string = [] # o
current_depth = 0 # p
# q
for c in paren_string: # r
if c == '(': # s
current_depth += 1 # t
current_string.append(c) # u
elif c == ')': # v
current_depth -= 1 # w
current_string.append(c) # x
# y
if current_depth == 0: # z
result.append(''.join(current_string)) # A
current_string.clear() # B
# C
return result # D
# E |
HumanEval/10 | make_palindrome | 'x' | [22, 25, 27, 6, 30] | vyAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | 'jerry' | [22, 25, 27, 6, 28, 27, 6, 28, 27, 6, 28, 27, 6, 28, 27, 6, 30] | vyAfBAfBAfBAfBAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | 'xyx' | [22, 25, 27, 6, 30] | vyAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | 'xyz' | [22, 25, 27, 6, 28, 27, 6, 28, 27, 6, 30] | vyAfBAfBAfD | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/10 | make_palindrome | '' | [22, 23] | vw | # 1
# 2
def is_palindrome(string: str) -> bool: # 3
# 4
""" Test if given string is a palindrome """ # 5
return string == string[::-1] # 6
# 7
# 8
def make_palindrome(string: str) -> str: # 9
""" Find the shortest palindrome that begins with a supplied string. # 10
Algorithm idea is simple: # 11
- Find the longest postfix of supplied string that is a palindrome. # 12
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # 13
>>> make_palindrome('') # 14
'' # 15
>>> make_palindrome('cat') # 16
'catac' # 17
>>> make_palindrome('cata') # 18
'catac' # 19
""" # 20
# 21
if not string: # 22
return '' # 23
# 24
beginning_of_suffix = 0 # 25
# 26
while not is_palindrome(string[beginning_of_suffix:]): # 27
beginning_of_suffix += 1 # 28
# 29
return string + string[:beginning_of_suffix][::-1] # 30
# 31 | # a
# b
def is_palindrome(string: str) -> bool: # c
# d
""" Test if given string is a palindrome """ # e
return string == string[::-1] # f
# g
# h
def make_palindrome(string: str) -> str: # i
""" Find the shortest palindrome that begins with a supplied string. # j
Algorithm idea is simple: # k
- Find the longest postfix of supplied string that is a palindrome. # l
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. # m
>>> make_palindrome('') # n
'' # o
>>> make_palindrome('cat') # p
'catac' # q
>>> make_palindrome('cata') # r
'catac' # s
""" # t
# u
if not string: # v
return '' # w
# x
beginning_of_suffix = 0 # y
# z
while not is_palindrome(string[beginning_of_suffix:]): # A
beginning_of_suffix += 1 # B
# C
return string + string[:beginning_of_suffix][::-1] # D
# E |
HumanEval/100 | make_a_pile | (3,) | [18, 18, 18, 18, 18] | rrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (4,) | [18, 18, 18, 18, 18, 18] | rrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (5,) | [18, 18, 18, 18, 18, 18, 18] | rrrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (6,) | [18, 18, 18, 18, 18, 18, 18, 18] | rrrrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/100 | make_a_pile | (8,) | [18, 18, 18, 18, 18, 18, 18, 18, 18, 18] | rrrrrrrrrr | # 1
def make_a_pile(n): # 2
# 3
""" # 4
Given a positive integer n, you have to make a pile of n levels of stones. # 5
The first level has n stones. # 6
The number of stones in the next level is: # 7
- the next odd number if n is odd. # 8
- the next even number if n is even. # 9
Return the number of stones in each level in a list, where element at index # 10
i represents the number of stones in the level (i+1). # 11
# 12
Examples: # 13
>>> make_a_pile(3) # 14
[3, 5, 7] # 15
""" # 16
# 17
return [n + 2*i for i in range(n)] # 18
# 19 | # a
def make_a_pile(n): # b
# c
""" # d
Given a positive integer n, you have to make a pile of n levels of stones. # e
The first level has n stones. # f
The number of stones in the next level is: # g
- the next odd number if n is odd. # h
- the next even number if n is even. # i
Return the number of stones in each level in a list, where element at index # j
i represents the number of stones in the level (i+1). # k
# l
Examples: # m
>>> make_a_pile(3) # n
[3, 5, 7] # o
""" # p
# q
return [n + 2*i for i in range(n)] # r
# s |
HumanEval/101 | words_string | "One, two, three, four, five, six" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrsvrstrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "" | [13, 14] | mn | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "One,, two, three, four, five, six," | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 24, 25] | mprsvrsvrsvrstrstrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrstrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "Hi, my name" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrstrsvrsvrsvrsvrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "ahmed , gamal" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrstrsvrsvrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/101 | words_string | "Hi, my name is John" | [13, 16, 18, 19, 22, 18, 19, 22, 18, 19, 20, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 19, 22, 18, 24, 25] | mprsvrsvrstrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrsvrxy | # 1
def words_string(s): # 2
# 3
""" # 4
You will be given a string of words separated by commas or spaces. Your task is # 5
to split the string into words and return an array of the words. # 6
# 7
For example: # 8
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # 9
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # 10
""" # 11
# 12
if not s: # 13
return [] # 14
# 15
s_list = [] # 16
# 17
for letter in s: # 18
if letter == ',': # 19
s_list.append(' ') # 20
else: # 21
s_list.append(letter) # 22
# 23
s_list = "".join(s_list) # 24
return s_list.split() # 25
# 26 | # a
def words_string(s): # b
# c
""" # d
You will be given a string of words separated by commas or spaces. Your task is # e
to split the string into words and return an array of the words. # f
# g
For example: # h
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] # i
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] # j
""" # k
# l
if not s: # m
return [] # n
# o
s_list = [] # p
# q
for letter in s: # r
if letter == ',': # s
s_list.append(' ') # t
else: # u
s_list.append(letter) # v
# w
s_list = "".join(s_list) # x
return s_list.split() # y
# z |
HumanEval/102 | choose_num | 7, 7 | [13, 15, 17, 18] | moqr | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 33, 12354 | [13, 15, 16] | mop | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 5234, 5233 | [13, 14] | mn | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 6, 29 | [13, 15, 17, 19] | moqs | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 27, 10 | [13, 14] | mn | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 546, 546 | [13, 15, 16] | mop | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 13, 12 | [13, 14] | mn | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/102 | choose_num | 12, 15 | [13, 15, 17, 19] | moqs | # 1
def choose_num(x, y): # 2
# 3
"""This function takes two positive numbers x and y and returns the # 4
biggest even integer number that is in the range [x, y] inclusive. If # 5
there's no such number, then the function should return -1. # 6
# 7
For example: # 8
choose_num(12, 15) = 14 # 9
choose_num(13, 12) = -1 # 10
""" # 11
# 12
if x > y: # 13
return -1 # 14
if y % 2 == 0: # 15
return y # 16
if x == y: # 17
return -1 # 18
return y - 1 # 19
# 20 | # a
def choose_num(x, y): # b
# c
"""This function takes two positive numbers x and y and returns the # d
biggest even integer number that is in the range [x, y] inclusive. If # e
there's no such number, then the function should return -1. # f
# g
For example: # h
choose_num(12, 15) = 14 # i
choose_num(13, 12) = -1 # j
""" # k
# l
if x > y: # m
return -1 # n
if y % 2 == 0: # o
return y # p
if x == y: # q
return -1 # r
return y - 1 # s
# t |
HumanEval/103 | rounded_avg | 1, 5 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 7, 13 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 964,977 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrsrsrsrsrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 996,997 | [15, 17, 18, 19, 18, 19, 18, 20] | oqrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 197,233 | [15, 17, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 19, 18, 20] | oqrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 7, 5 | [15, 16] | op | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 5, 1 | [15, 16] | op | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/103 | rounded_avg | 5, 5 | [15, 17, 18, 19, 18, 20] | oqrsrt | # 1
def rounded_avg(n, m): # 2
# 3
"""You are given two positive integers n and m, and your task is to compute the # 4
average of the integers from n through m (including n and m). # 5
Round the answer to the nearest integer and convert that to binary. # 6
If n is greater than m, return -1. # 7
Example: # 8
rounded_avg(1, 5) => "0b11" # 9
rounded_avg(7, 5) => -1 # 10
rounded_avg(10, 20) => "0b1111" # 11
rounded_avg(20, 33) => "0b11010" # 12
""" # 13
# 14
if m < n: # 15
return -1 # 16
summation = 0 # 17
for i in range(n, m+1): # 18
summation += i # 19
return bin(round(summation/(m - n + 1))) # 20
# 21 | # a
def rounded_avg(n, m): # b
# c
"""You are given two positive integers n and m, and your task is to compute the # d
average of the integers from n through m (including n and m). # e
Round the answer to the nearest integer and convert that to binary. # f
If n is greater than m, return -1. # g
Example: # h
rounded_avg(1, 5) => "0b11" # i
rounded_avg(7, 5) => -1 # j
rounded_avg(10, 20) => "0b1111" # k
rounded_avg(20, 33) => "0b11010" # l
""" # m
# n
if m < n: # o
return -1 # p
summation = 0 # q
for i in range(n, m+1): # r
summation += i # s
return bin(round(summation/(m - n + 1))) # t
# u |
HumanEval/104 | unique_digits | [12345, 2033, 111, 151] | [16, 17, 18, 18, 18, 17, 18, 18, 17, 18, 18, 18, 18, 18, 19, 17, 18, 18, 18, 18, 18, 19, 17, 20] | pqrrrqrrqrrrrrsqrrrrrsqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/104 | unique_digits | [15, 33, 1422, 1] | [16, 17, 18, 18, 18, 18, 19, 17, 18, 18, 18, 18, 19, 17, 18, 18, 18, 17, 18, 18, 18, 19, 17, 20] | pqrrrrsqrrrrsqrrrqrrrsqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/104 | unique_digits | [152, 323, 1422, 10] | [16, 17, 18, 18, 18, 18, 17, 18, 18, 18, 17, 18, 18, 18, 17, 18, 18, 18, 17, 20] | pqrrrrqrrrqrrrqrrrqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/104 | unique_digits | [135, 103, 31] | [16, 17, 18, 18, 18, 18, 18, 19, 17, 18, 18, 18, 17, 18, 18, 18, 18, 19, 17, 20] | pqrrrrrsqrrrqrrrrsqt | # 1
def unique_digits(x): # 2
# 3
"""Given a list of positive integers x. return a sorted list of all # 4
elements that hasn't any even digit. # 5
# 6
Note: Returned list should be sorted in increasing order. # 7
# 8
For example: # 9
>>> unique_digits([15, 33, 1422, 1]) # 10
[1, 15, 33] # 11
>>> unique_digits([152, 323, 1422, 10]) # 12
[] # 13
""" # 14
# 15
odd_digit_elements = [] # 16
for i in x: # 17
if all (int(c) % 2 == 1 for c in str(i)): # 18
odd_digit_elements.append(i) # 19
return sorted(odd_digit_elements) # 20
# 21 | # a
def unique_digits(x): # b
# c
"""Given a list of positive integers x. return a sorted list of all # d
elements that hasn't any even digit. # e
# f
Note: Returned list should be sorted in increasing order. # g
# h
For example: # i
>>> unique_digits([15, 33, 1422, 1]) # j
[1, 15, 33] # k
>>> unique_digits([152, 323, 1422, 10]) # l
[] # m
""" # n
# o
odd_digit_elements = [] # p
for i in x: # q
if all (int(c) % 2 == 1 for c in str(i)): # r
odd_digit_elements.append(i) # s
return sorted(odd_digit_elements) # t
# u |
HumanEval/105 | by_length | [2, 1, 1, 4, 5, 8, 2, 3] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 44] | ABCDEFGHIzKLMNOMNOMNOMNOMNOMNOMNOMNOMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [1, -1 , 55] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 42, 43, 39, 40, 41, 39, 40, 41, 42, 43, 39, 44] | ABCDEFGHIzKLMNOPQMNOMNOPQMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [1, -1, 3, 2] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 40, 41, 42, 43, 39, 44] | ABCDEFGHIzKLMNOMNOMNOMNOPQMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [9, 4, 8] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 40, 41, 39, 40, 41, 39, 40, 41, 39, 44] | ABCDEFGHIzKLMNOMNOMNOMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/105 | by_length | [] | [27, 28, 29, 30, 31, 32, 33, 34, 35, 26, 37, 38, 39, 44] | ABCDEFGHIzKLMR | # 1
def by_length(arr): # 2
# 3
""" # 4
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # 5
reverse the resulting array, and then replace each digit by its corresponding name from # 6
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # 7
# 8
For example: # 9
arr = [2, 1, 1, 4, 5, 8, 2, 3] # 10
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # 11
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # 12
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # 13
# 14
If the array is empty, return an empty array: # 15
arr = [] # 16
return [] # 17
# 18
If the array has any strange number ignore it: # 19
arr = [1, -1 , 55] # 20
-> sort arr -> [-1, 1, 55] # 21
-> reverse arr -> [55, 1, -1] # 22
return = ['One'] # 23
""" # 24
# 25
dic = { # 26
1: "One", # 27
2: "Two", # 28
3: "Three", # 29
4: "Four", # 30
5: "Five", # 31
6: "Six", # 32
7: "Seven", # 33
8: "Eight", # 34
9: "Nine", # 35
} # 36
sorted_arr = sorted(arr, reverse=True) # 37
new_arr = [] # 38
for var in sorted_arr: # 39
try: # 40
new_arr.append(dic[var]) # 41
except: # 42
pass # 43
return new_arr # 44
# 45 | # a
def by_length(arr): # b
# c
""" # d
Given an array of integers, sort the integers that are between 1 and 9 inclusive, # e
reverse the resulting array, and then replace each digit by its corresponding name from # f
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". # g
# h
For example: # i
arr = [2, 1, 1, 4, 5, 8, 2, 3] # j
-> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] # k
-> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1] # l
return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] # m
# n
If the array is empty, return an empty array: # o
arr = [] # p
return [] # q
# r
If the array has any strange number ignore it: # s
arr = [1, -1 , 55] # t
-> sort arr -> [-1, 1, 55] # u
-> reverse arr -> [55, 1, -1] # v
return = ['One'] # w
""" # x
# y
dic = { # z
1: "One", # A
2: "Two", # B
3: "Three", # C
4: "Four", # D
5: "Five", # E
6: "Six", # F
7: "Seven", # G
8: "Eight", # H
9: "Nine", # I
} # J
sorted_arr = sorted(arr, reverse=True) # K
new_arr = [] # L
for var in sorted_arr: # M
try: # N
new_arr.append(dic[var]) # O
except: # P
pass # Q
return new_arr # R
# S |
HumanEval/106 | f | 5 | [13, 14, 15, 20, 21, 21, 22, 14, 15, 16, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 22, 14, 15, 16, 17, 17, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 21, 21, 22, 14, 23] | mnotuuvnopqqqrnotuuuuvnopqqqqqrnotuuuuuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/106 | f | 7 | [13, 14, 15, 20, 21, 21, 22, 14, 15, 16, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 22, 14, 15, 16, 17, 17, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 21, 21, 22, 14, 15, 16, 17, 17, 17, 17, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 21, 21, 21, 21, 22, 14, 23] | mnotuuvnopqqqrnotuuuuvnopqqqqqrnotuuuuuuvnopqqqqqqqrnotuuuuuuuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/106 | f | 1 | [13, 14, 15, 20, 21, 21, 22, 14, 23] | mnotuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/106 | f | 3 | [13, 14, 15, 20, 21, 21, 22, 14, 15, 16, 17, 17, 17, 18, 14, 15, 20, 21, 21, 21, 21, 22, 14, 23] | mnotuuvnopqqqrnotuuuuvnw | # 1
def f(n): # 2
# 3
""" Implement the function f that takes n as a parameter, # 4
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # 5
or the sum of numbers from 1 to i otherwise. # 6
i starts from 1. # 7
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # 8
Example: # 9
f(5) == [1, 2, 6, 24, 15] # 10
""" # 11
# 12
ret = [] # 13
for i in range(1,n+1): # 14
if i%2 == 0: # 15
x = 1 # 16
for j in range(1,i+1): x *= j # 17
ret += [x] # 18
else: # 19
x = 0 # 20
for j in range(1,i+1): x += j # 21
ret += [x] # 22
return ret # 23
# 24 | # a
def f(n): # b
# c
""" Implement the function f that takes n as a parameter, # d
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even # e
or the sum of numbers from 1 to i otherwise. # f
i starts from 1. # g
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i). # h
Example: # i
f(5) == [1, 2, 6, 24, 15] # j
""" # k
# l
ret = [] # m
for i in range(1,n+1): # n
if i%2 == 0: # o
x = 1 # p
for j in range(1,i+1): x *= j # q
ret += [x] # r
else: # s
x = 0 # t
for j in range(1,i+1): x += j # u
ret += [x] # v
return ret # w
# x |
HumanEval/107 | even_odd_palindrome | 3 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 38] | ADEGHBIGHJBKGHBIGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 9 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 19 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBGHBIGHJBGHBJGHJBGHBJGHJBGHBJGHJBGHBJGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 1 | [27, 30, 31, 33, 34, 28, 35, 33, 38] | ADEGHBIGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 12 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 35, 33, 34, 36, 28, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBGHBIGHJBGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/107 | even_odd_palindrome | 25 | [27, 30, 31, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 37, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 35, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 34, 36, 28, 37, 33, 34, 28, 36, 33, 34, 36, 28, 33, 34, 28, 36, 33, 38] | ADEGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBKGHBIGHJBGHBIGHJBGHBJGHJBGHBJGHJBGHBJGHJBGHBJGHJBGHBJGHJBKGHBJGHJBGHBJGL | # 1
def even_odd_palindrome(n): # 2
# 3
""" # 4
Given a positive integer n, return a tuple that has the number of even and odd # 5
integer palindromes that fall within the range(1, n), inclusive. # 6
# 7
Example 1: # 8
# 9
Input: 3 # 10
Output: (1, 2) # 11
Explanation: # 12
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # 13
# 14
Example 2: # 15
# 16
Input: 12 # 17
Output: (4, 6) # 18
Explanation: # 19
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # 20
# 21
Note: # 22
1. 1 <= n <= 10^3 # 23
2. returned tuple has the number of even and odd integer palindromes respectively. # 24
""" # 25
# 26
def is_palindrome(n): # 27
return str(n) == str(n)[::-1] # 28
# 29
even_palindrome_count = 0 # 30
odd_palindrome_count = 0 # 31
# 32
for i in range(1, n+1): # 33
if i%2 == 1 and is_palindrome(i): # 34
odd_palindrome_count += 1 # 35
elif i%2 == 0 and is_palindrome(i): # 36
even_palindrome_count += 1 # 37
return (even_palindrome_count, odd_palindrome_count) # 38
# 39 | # a
def even_odd_palindrome(n): # b
# c
""" # d
Given a positive integer n, return a tuple that has the number of even and odd # e
integer palindromes that fall within the range(1, n), inclusive. # f
# g
Example 1: # h
# i
Input: 3 # j
Output: (1, 2) # k
Explanation: # l
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. # m
# n
Example 2: # o
# p
Input: 12 # q
Output: (4, 6) # r
Explanation: # s
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. # t
# u
Note: # v
1. 1 <= n <= 10^3 # w
2. returned tuple has the number of even and odd integer palindromes respectively. # x
""" # y
# z
def is_palindrome(n): # A
return str(n) == str(n)[::-1] # B
# C
even_palindrome_count = 0 # D
odd_palindrome_count = 0 # E
# F
for i in range(1, n+1): # G
if i%2 == 1 and is_palindrome(i): # H
odd_palindrome_count += 1 # I
elif i%2 == 0 and is_palindrome(i): # J
even_palindrome_count += 1 # K
return (even_palindrome_count, odd_palindrome_count) # L
# M |
HumanEval/108 | count_nums | [-1, -2, 0] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20] | nttopqqqrstopqqqrstopqqqrstttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1, 6, 9, -6, 0, 1, 5] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20, 20] | nttopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1, 100, 98, -7, 1, -1] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20] | nttopqqqrstopqqqqqrstopqqqqrstopqqqrstopqqqrstopqqqrsttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [12, 23, 34, -45, -56, 0] | [14, 20, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20] | nttopqqqqrstopqqqqrstopqqqqrstopqqqqrstopqqqqrstopqqqrsttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [-0, 1**0] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20] | nttopqqqrstopqqqrsttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20] | nttopqqqrstt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [1, 1, 2, -2, 3, 4, 5] | [14, 20, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 15, 16, 17, 17, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20, 20] | nttopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstopqqqrstttttttt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/108 | count_nums | [] | [14, 20, 20] | ntt | # 1
def count_nums(arr): # 2
# 3
""" # 4
Write a function count_nums which takes an array of integers and returns # 5
the number of elements which has a sum of digits > 0. # 6
If a number is negative, then its first signed digit will be negative: # 7
e.g. -123 has signed digits -1, 2, and 3. # 8
>>> count_nums([]) == 0 # 9
>>> count_nums([-1, 11, -11]) == 1 # 10
>>> count_nums([1, 1, 2]) == 3 # 11
""" # 12
# 13
def digits_sum(n): # 14
neg = 1 # 15
if n < 0: n, neg = -1 * n, -1 # 16
n = [int(i) for i in str(n)] # 17
n[0] = n[0] * neg # 18
return sum(n) # 19
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # 20
# 21 | # a
def count_nums(arr): # b
# c
""" # d
Write a function count_nums which takes an array of integers and returns # e
the number of elements which has a sum of digits > 0. # f
If a number is negative, then its first signed digit will be negative: # g
e.g. -123 has signed digits -1, 2, and 3. # h
>>> count_nums([]) == 0 # i
>>> count_nums([-1, 11, -11]) == 1 # j
>>> count_nums([1, 1, 2]) == 3 # k
""" # l
# m
def digits_sum(n): # n
neg = 1 # o
if n < 0: n, neg = -1 * n, -1 # p
n = [int(i) for i in str(n)] # q
n[0] = n[0] * neg # r
return sum(n) # s
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr]))) # t
# u |
HumanEval/109 | move_one_ball | [4, 3, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 41] | EGHJKLMNMNMNO | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [3, 5, 10, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 39, 40, 39, 40, 39, 42] | EGHJKLMNMNMNMNMNMP | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [3, 5, 4, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 39, 40, 41] | EGHJKLMNMNMNMNO | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [3, 4, 5, 1, 2] | [31, 33, 34, 36, 37, 38, 39, 40, 39, 40, 39, 40, 39, 40, 39, 40, 39, 42] | EGHJKLMNMNMNMNMNMP | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/109 | move_one_ball | [] | [31, 32] | EF | # 1
def move_one_ball(arr): # 2
# 3
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # 4
numbers in the array will be randomly ordered. Your task is to determine if # 5
it is possible to get an array sorted in non-decreasing order by performing # 6
the following operation on the given array: # 7
You are allowed to perform right shift operation any number of times. # 8
# 9
One right shift operation means shifting all elements of the array by one # 10
position in the right direction. The last element of the array will be moved to # 11
the starting position in the array i.e. 0th index. # 12
# 13
If it is possible to obtain the sorted array by performing the above operation # 14
then return True else return False. # 15
If the given array is empty then return True. # 16
# 17
Note: The given list is guaranteed to have unique elements. # 18
# 19
For Example: # 20
# 21
move_one_ball([3, 4, 5, 1, 2])==>True # 22
Explanation: By performin 2 right shift operations, non-decreasing order can # 23
be achieved for the given array. # 24
move_one_ball([3, 5, 4, 1, 2])==>False # 25
Explanation:It is not possible to get non-decreasing order for the given # 26
array by performing any number of right shift operations. # 27
# 28
""" # 29
# 30
if len(arr)==0: # 31
return True # 32
sorted_array=sorted(arr) # 33
my_arr=[] # 34
# 35
min_value=min(arr) # 36
min_index=arr.index(min_value) # 37
my_arr=arr[min_index:]+arr[0:min_index] # 38
for i in range(len(arr)): # 39
if my_arr[i]!=sorted_array[i]: # 40
return False # 41
return True # 42
# 43 | # a
def move_one_ball(arr): # b
# c
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The # d
numbers in the array will be randomly ordered. Your task is to determine if # e
it is possible to get an array sorted in non-decreasing order by performing # f
the following operation on the given array: # g
You are allowed to perform right shift operation any number of times. # h
# i
One right shift operation means shifting all elements of the array by one # j
position in the right direction. The last element of the array will be moved to # k
the starting position in the array i.e. 0th index. # l
# m
If it is possible to obtain the sorted array by performing the above operation # n
then return True else return False. # o
If the given array is empty then return True. # p
# q
Note: The given list is guaranteed to have unique elements. # r
# s
For Example: # t
# u
move_one_ball([3, 4, 5, 1, 2])==>True # v
Explanation: By performin 2 right shift operations, non-decreasing order can # w
be achieved for the given array. # x
move_one_ball([3, 5, 4, 1, 2])==>False # y
Explanation:It is not possible to get non-decreasing order for the given # z
array by performing any number of right shift operations. # A
# B
""" # C
# D
if len(arr)==0: # E
return True # F
sorted_array=sorted(arr) # G
my_arr=[] # H
# I
min_value=min(arr) # J
min_index=arr.index(min_value) # K
my_arr=arr[min_index:]+arr[0:min_index] # L
for i in range(len(arr)): # M
if my_arr[i]!=sorted_array[i]: # N
return False # O
return True # P
# Q |
HumanEval/11 | string_xor | ('1', '1') | [12, 18, 18, 13, 14, 18] | lrrmnr | from typing import List # 1
# 2
# 3
def string_xor(a: str, b: str) -> str: # 4
# 5
""" Input are two strings a and b consisting only of 1s and 0s. # 6
Perform binary XOR on these inputs and return result also as a string. # 7
>>> string_xor('010', '110') # 8
'100' # 9
""" # 10
# 11
def xor(i, j): # 12
if i == j: # 13
return '0' # 14
else: # 15
return '1' # 16
# 17
return ''.join(xor(x, y) for x, y in zip(a, b)) # 18
# 19 | from typing import List # a
# b
# c
def string_xor(a: str, b: str) -> str: # d
# e
""" Input are two strings a and b consisting only of 1s and 0s. # f
Perform binary XOR on these inputs and return result also as a string. # g
>>> string_xor('010', '110') # h
'100' # i
""" # j
# k
def xor(i, j): # l
if i == j: # m
return '0' # n
else: # o
return '1' # p
# q
return ''.join(xor(x, y) for x, y in zip(a, b)) # r
# s |
HumanEval/11 | string_xor | ('111000', '101010') | [12, 18, 18, 13, 14, 18, 13, 16, 18, 13, 14, 18, 13, 14, 18, 13, 16, 18, 13, 14, 18] | lrrmnrmprmnrmnrmprmnr | from typing import List # 1
# 2
# 3
def string_xor(a: str, b: str) -> str: # 4
# 5
""" Input are two strings a and b consisting only of 1s and 0s. # 6
Perform binary XOR on these inputs and return result also as a string. # 7
>>> string_xor('010', '110') # 8
'100' # 9
""" # 10
# 11
def xor(i, j): # 12
if i == j: # 13
return '0' # 14
else: # 15
return '1' # 16
# 17
return ''.join(xor(x, y) for x, y in zip(a, b)) # 18
# 19 | from typing import List # a
# b
# c
def string_xor(a: str, b: str) -> str: # d
# e
""" Input are two strings a and b consisting only of 1s and 0s. # f
Perform binary XOR on these inputs and return result also as a string. # g
>>> string_xor('010', '110') # h
'100' # i
""" # j
# k
def xor(i, j): # l
if i == j: # m
return '0' # n
else: # o
return '1' # p
# q
return ''.join(xor(x, y) for x, y in zip(a, b)) # r
# s |
HumanEval/11 | string_xor | ('0101', '0000') | [12, 18, 18, 13, 14, 18, 13, 16, 18, 13, 14, 18, 13, 16, 18] | lrrmnrmprmnrmpr | from typing import List # 1
# 2
# 3
def string_xor(a: str, b: str) -> str: # 4
# 5
""" Input are two strings a and b consisting only of 1s and 0s. # 6
Perform binary XOR on these inputs and return result also as a string. # 7
>>> string_xor('010', '110') # 8
'100' # 9
""" # 10
# 11
def xor(i, j): # 12
if i == j: # 13
return '0' # 14
else: # 15
return '1' # 16
# 17
return ''.join(xor(x, y) for x, y in zip(a, b)) # 18
# 19 | from typing import List # a
# b
# c
def string_xor(a: str, b: str) -> str: # d
# e
""" Input are two strings a and b consisting only of 1s and 0s. # f
Perform binary XOR on these inputs and return result also as a string. # g
>>> string_xor('010', '110') # h
'100' # i
""" # j
# k
def xor(i, j): # l
if i == j: # m
return '0' # n
else: # o
return '1' # p
# q
return ''.join(xor(x, y) for x, y in zip(a, b)) # r
# s |
HumanEval/110 | exchange | [3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 19, 20, 21, 19, 20, 19, 20, 21, 19, 22, 23, 22, 23, 22, 23, 22, 23, 22, 23, 22, 23, 22, 25, 27] | qrstustststuststusvwvwvwvwvwvwvyA | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [5, 7, 3], [2, 6, 3] | [17, 18, 19, 20, 21, 19, 20, 21, 19, 20, 21, 19, 22, 23, 24, 22, 23, 24, 22, 23, 22, 25, 27] | qrstustustusvwxvwxvwvyA | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [5, 7, 3], [2, 6, 4] | [17, 18, 19, 20, 21, 19, 20, 21, 19, 20, 21, 19, 22, 23, 24, 22, 23, 24, 22, 23, 24, 22, 25, 26] | qrstustustusvwxvwxvwxvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [1, 2, 3, 4], [2, 1, 4, 3] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 21, 19, 20, 19, 22, 23, 24, 22, 23, 22, 23, 24, 22, 23, 22, 25, 26] | qrstuststustsvwxvwvwxvwvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [1, 2, 3, 4], [1, 5, 3, 4] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 21, 19, 20, 19, 22, 23, 22, 23, 22, 23, 22, 23, 24, 22, 25, 27] | qrstuststustsvwvwvwvwxvyA | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [100, 200], [200, 200] | [17, 18, 19, 20, 19, 20, 19, 22, 23, 24, 22, 23, 24, 22, 25, 26] | qrststsvwxvwxvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/110 | exchange | [1, 2, 3, 4], [1, 2, 3, 4] | [17, 18, 19, 20, 21, 19, 20, 19, 20, 21, 19, 20, 19, 22, 23, 22, 23, 24, 22, 23, 22, 23, 24, 22, 25, 26] | qrstuststustsvwvwxvwvwxvyz | # 1
def exchange(lst1, lst2): # 2
# 3
"""In this problem, you will implement a function that takes two lists of numbers, # 4
and determines whether it is possible to perform an exchange of elements # 5
between them to make lst1 a list of only even numbers. # 6
There is no limit on the number of exchanged elements between lst1 and lst2. # 7
If it is possible to exchange elements between the lst1 and lst2 to make # 8
all the elements of lst1 to be even, return "YES". # 9
Otherwise, return "NO". # 10
For example: # 11
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # 12
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # 13
It is assumed that the input lists will be non-empty. # 14
""" # 15
# 16
odd = 0 # 17
even = 0 # 18
for i in lst1: # 19
if i%2 == 1: # 20
odd += 1 # 21
for i in lst2: # 22
if i%2 == 0: # 23
even += 1 # 24
if even >= odd: # 25
return "YES" # 26
return "NO" # 27
# 28
# 29 | # a
def exchange(lst1, lst2): # b
# c
"""In this problem, you will implement a function that takes two lists of numbers, # d
and determines whether it is possible to perform an exchange of elements # e
between them to make lst1 a list of only even numbers. # f
There is no limit on the number of exchanged elements between lst1 and lst2. # g
If it is possible to exchange elements between the lst1 and lst2 to make # h
all the elements of lst1 to be even, return "YES". # i
Otherwise, return "NO". # j
For example: # k
exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES" # l
exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO" # m
It is assumed that the input lists will be non-empty. # n
""" # o
# p
odd = 0 # q
even = 0 # r
for i in lst1: # s
if i%2 == 1: # t
odd += 1 # u
for i in lst2: # v
if i%2 == 0: # w
even += 1 # x
if even >= odd: # y
return "YES" # z
return "NO" # A
# B
# C |
HumanEval/111 | histogram | 'a b b a' | [17, 18, 19, 21, 22, 23, 21, 22, 21, 22, 21, 22, 21, 24, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 29] | qrsuvwuvuvuvuxyzByzByzByzByC | # 1
def histogram(test): # 2
# 3
"""Given a string representing a space separated lowercase letters, return a dictionary # 4
of the letter with the most repetition and containing the corresponding count. # 5
If several letters have the same occurrence, return all of them. # 6
# 7
Example: # 8
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # 9
histogram('a b b a') == {'a': 2, 'b': 2} # 10
histogram('a b c a b') == {'a': 2, 'b': 2} # 11
histogram('b b b b a') == {'b': 4} # 12
histogram('') == {} # 13
# 14
""" # 15
# 16
dict1={} # 17
list1=test.split(" ") # 18
t=0 # 19
# 20
for i in list1: # 21
if(list1.count(i)>t) and i!='': # 22
t=list1.count(i) # 23
if t>0: # 24
for i in list1: # 25
if(list1.count(i)==t): # 26
# 27
dict1[i]=t # 28
return dict1 # 29
# 30 | # a
def histogram(test): # b
# c
"""Given a string representing a space separated lowercase letters, return a dictionary # d
of the letter with the most repetition and containing the corresponding count. # e
If several letters have the same occurrence, return all of them. # f
# g
Example: # h
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # i
histogram('a b b a') == {'a': 2, 'b': 2} # j
histogram('a b c a b') == {'a': 2, 'b': 2} # k
histogram('b b b b a') == {'b': 4} # l
histogram('') == {} # m
# n
""" # o
# p
dict1={} # q
list1=test.split(" ") # r
t=0 # s
# t
for i in list1: # u
if(list1.count(i)>t) and i!='': # v
t=list1.count(i) # w
if t>0: # x
for i in list1: # y
if(list1.count(i)==t): # z
# A
dict1[i]=t # B
return dict1 # C
# D |
HumanEval/111 | histogram | 'r t g' | [17, 18, 19, 21, 22, 23, 21, 22, 21, 22, 21, 24, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 29] | qrsuvwuvuvuxyzByzByzByC | # 1
def histogram(test): # 2
# 3
"""Given a string representing a space separated lowercase letters, return a dictionary # 4
of the letter with the most repetition and containing the corresponding count. # 5
If several letters have the same occurrence, return all of them. # 6
# 7
Example: # 8
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # 9
histogram('a b b a') == {'a': 2, 'b': 2} # 10
histogram('a b c a b') == {'a': 2, 'b': 2} # 11
histogram('b b b b a') == {'b': 4} # 12
histogram('') == {} # 13
# 14
""" # 15
# 16
dict1={} # 17
list1=test.split(" ") # 18
t=0 # 19
# 20
for i in list1: # 21
if(list1.count(i)>t) and i!='': # 22
t=list1.count(i) # 23
if t>0: # 24
for i in list1: # 25
if(list1.count(i)==t): # 26
# 27
dict1[i]=t # 28
return dict1 # 29
# 30 | # a
def histogram(test): # b
# c
"""Given a string representing a space separated lowercase letters, return a dictionary # d
of the letter with the most repetition and containing the corresponding count. # e
If several letters have the same occurrence, return all of them. # f
# g
Example: # h
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # i
histogram('a b b a') == {'a': 2, 'b': 2} # j
histogram('a b c a b') == {'a': 2, 'b': 2} # k
histogram('b b b b a') == {'b': 4} # l
histogram('') == {} # m
# n
""" # o
# p
dict1={} # q
list1=test.split(" ") # r
t=0 # s
# t
for i in list1: # u
if(list1.count(i)>t) and i!='': # v
t=list1.count(i) # w
if t>0: # x
for i in list1: # y
if(list1.count(i)==t): # z
# A
dict1[i]=t # B
return dict1 # C
# D |
HumanEval/111 | histogram | 'b b b b a' | [17, 18, 19, 21, 22, 23, 21, 22, 21, 22, 21, 22, 21, 22, 21, 24, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 26, 28, 25, 26, 25, 29] | qrsuvwuvuvuvuvuxyzByzByzByzByzyC | # 1
def histogram(test): # 2
# 3
"""Given a string representing a space separated lowercase letters, return a dictionary # 4
of the letter with the most repetition and containing the corresponding count. # 5
If several letters have the same occurrence, return all of them. # 6
# 7
Example: # 8
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # 9
histogram('a b b a') == {'a': 2, 'b': 2} # 10
histogram('a b c a b') == {'a': 2, 'b': 2} # 11
histogram('b b b b a') == {'b': 4} # 12
histogram('') == {} # 13
# 14
""" # 15
# 16
dict1={} # 17
list1=test.split(" ") # 18
t=0 # 19
# 20
for i in list1: # 21
if(list1.count(i)>t) and i!='': # 22
t=list1.count(i) # 23
if t>0: # 24
for i in list1: # 25
if(list1.count(i)==t): # 26
# 27
dict1[i]=t # 28
return dict1 # 29
# 30 | # a
def histogram(test): # b
# c
"""Given a string representing a space separated lowercase letters, return a dictionary # d
of the letter with the most repetition and containing the corresponding count. # e
If several letters have the same occurrence, return all of them. # f
# g
Example: # h
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} # i
histogram('a b b a') == {'a': 2, 'b': 2} # j
histogram('a b c a b') == {'a': 2, 'b': 2} # k
histogram('b b b b a') == {'b': 4} # l
histogram('') == {} # m
# n
""" # o
# p
dict1={} # q
list1=test.split(" ") # r
t=0 # s
# t
for i in list1: # u
if(list1.count(i)>t) and i!='': # v
t=list1.count(i) # w
if t>0: # x
for i in list1: # y
if(list1.count(i)==t): # z
# A
dict1[i]=t # B
return dict1 # C
# D |
End of preview.