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http://catalog.kellogg.edu/preview_course_nopop.php?catoid=16&coid=13319&print
[ "May 18, 2022\n Select a Publication 2022-2023 Academic Catalog 2021-2022 Student Handbook 2021-2022 Academic Catalog [ARCHIVED CATALOG] 2020-2021 Academic Catalog [ARCHIVED CATALOG] 2020-2021 Student Handbook [ARCHIVED CATALOG] 2019-2020 Academic Catalog [ARCHIVED CATALOG] 2019-2020 Student Handbook [ARCHIVED CATALOG] 2018-2019 Academic Catalog [ARCHIVED CATALOG] 2017-2018 Academic Catalog [ARCHIVED CATALOG]\n HELP 2020-2021 Academic Catalog [ARCHIVED CATALOG]", null, "Print this Page\n\n# MATH 105 - Beginning Algebra\n\n4 CR\nCourse content includes operations on integers and rational numbers, geometric formulas, algebraic expressions, solutions of linear equations and inequalities, graphs of linear equations and linear systems, systems of linear equations in two variables, polynomials and factoring, rational expressions and equations, and radical expressions and equations. Lab Fee\n\nRequisites: Next Gen ACCUPLACER® arithmetic score of at least 250, or Next Gen ACCUPLACER® quantitative reason score of at least 237, or TSMA 45  with at least a grade of C.\nCourse Learning Outcomes:\n1. Understand, interpret and use the basic symbols and words in the language of arithmetic and algebra.\n2. Use algebraic methods to solve a linear equation or inequality.\n3. Graph linear equations and inequalities in two variables.\n4. Solve systems of equations in two variables using multiple methods.\n5. Apply problem-solving strategies with applications of systems involving two variables.\n6. Factor algebraic expressions using all methods and use this skill to solve quadratic equations by factoring.\n7. Solve rational and radical equations.\n8. Simplify, multiply, divide, add and subtract real numbers, polynomials, rational expressions, and radical expressions." ]
[ null, "http://catalog.kellogg.edu/img/print.gif", null ]
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https://e2e.ti.com/blogs_/archives/b/precisionhub/posts/the-impact-of-voltage-reference-noise-on-delta-sigma-adc-resolution
[ "Other Parts Discussed in Post: ADS1259\n\nHave you ever evaluated the noise performance of an ADC and found that your measured performance differs from the specified performance given in the device datasheet? Achieving high resolution in a precision data-acquisition system requires some understanding of analog-to-digital converter (ADC) noise. It is important to know how the datasheet specifies noise performance and how external noise sources may affect overall system performance. One example of such a noise source is the power-supply noise my colleague Ryan Andrews discussed in his post, “Caution! Your ADC may be only as good as its power supply.” In this post, I’ll look at how reference noise affects DC noise performance in delta-sigma ADCs.\n\nYou can specify and measure the DC noise performance of an ADC with the positive and negative inputs shorted to a mid-supply voltage, as shown in Figure 1. By measuring noise under this condition, the noise in the ADC’s output codes is nearly immune to changes in reference voltage, reference noise or input-signal noise. While this test condition is more of an ideal scenario than a practical application, it does provide a good representation of ADC noise performance isolated from some external noise sources.", null, "Figure 1: ADC noise performance test (and debugging) configuration\n\nTip: When debugging, begin evaluating the system’s noise performance with a shorted-input test to assess the isolated ADC noise performance before moving on to other system noise performance tests.\n\nHow reference noise affects ADC DC noise performance\n\nThis effect is related to the basic task of an ADC, which is to provide an output code that is a representation of the ratio of the input-signal voltage to the reference voltage. Both input and reference voltages add a noise term to this ratio, as shown in Equation 1:", null, "(1)\n\nThe effect of input signal noise,", null, ", on ADC conversion results is fairly straightforward. The ADC will capture any noise not filtered out – either with an external resistor-capacitor (RC) filter or with the delta-sigma ADC’s digital filter. You can observe this in the output codes, since", null, "has a direct effect on the ratio in Equation 1.\n\nTip: Make sure that the input signal is a low-noise source when evaluating ADC noise performance, since the input signal’s noise directly affects the ADC’s output result.\n\nThe effect of reference noise,", null, ", on the ADC conversion result is not quite as straightforward, however, because", null, "appears in the denominator. When the numerator is equal to zero (as is the case when the ADC inputs are shorted), the ratio will always equal zero and the", null, "term will not effect on the ratio. When the numerator is nearly equal to the denominator,", null, "will have a strong effect on the ratio. When ratio values are between 0 and 1, the effect of", null, "is weighted by the value of the ratio. Figure 2 shows the resulting characteristic behavior.", null, "Figure 2: ADC and reference noise vs. input voltage\n\nWhen adding reference noise to the ADC’s noise contribution using root-sum-of-squares addition, the combined noise performance is a function of the input voltage, which increases for larger positive or negative input voltages. The important points to notice on the curve in Figure 2 are:\n\n• Point A, which is the ADC noise measured with shorted inputs given in the ADC’s datasheet.\n• Point B, which is the total bandwidth-limited reference noise, typically limited by the ADC’s digital filter bandwidth.\n\nYou can calculate the reference noise (point B) if you know the noise-spectral density and noise bandwidth for the reference source; otherwise, applying a full-scale voltage input to the ADC and measuring the noise performance will generally be a good measure of reference noise.\n\nHow to select a reference voltage source\n\nA low-noise reference is important for achieving low-noise/high-resolution performance across the full ADC input range. The reference-noise requirements will depend on the system’s targeted resolution, the input-signal span and the data rate (as this usually limits both the input and reference-noise bandwidth). The system can tolerate additional reference noise when the noise bandwidth is limited by a slower data rate, or if the input-signal span is limited to a small percentage of the ADC’s full-scale range.\n\nMany delta-sigma ADCs include an integrated reference that provides sufficient performance for most applications. For more demanding applications, using an external reference may improve noise performance for inputs near the positive and negative full-scale range. External precision references can achieve lower noise performance because of their higher power consumption. Figure 3 compares the 24-bit ADS1259 delta-sigma ADC’s noise performance with the internal reference source, an external REF5025 voltage source, and a ratiometric reference source.", null, "Figure 3: ADS1259 noise performance with internal, external and ratiometric reference sources\n\nWhile external references may achieve better noise performance than their integrated counterparts, ratiometric reference configurations can perform even better. A ratiometric configuration shares the same voltage source for the reference voltage and input-signal excitation. By sharing a common voltage and noise source,", null, "and", null, "from Equation 1 tend to cancel each other out in the ratio.\n\nNext time you’re evaluating an ADC’s noise performance, make sure to consider the reference noise effects. Also, whenever a sensor requires an excitation source, always consider a ratiometric measurement implementation." ]
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https://de.mathworks.com/matlabcentral/cody/problems/2240-sum-the-edge-values-of-a-matrix/solutions/418459
[ "Cody\n\n# Problem 2240. Sum the 'edge' values of a matrix\n\nSolution 418459\n\nSubmitted on 14 Mar 2014 by Vincent\nThis solution is locked. To view this solution, you need to provide a solution of the same size or smaller.\n\n### Test Suite\n\nTest Status Code Input and Output\n1   Pass\n%% x = [1 2 3; 4 5 6;7 8 9]; y_correct = 40; assert(isequal(AddMatrixLim(x),y_correct))\n\ny = 40\n\n2   Pass\n%% x= [1 5 6 7; 4 9 4 7; 9 4 2 1; 0 1 2 8] y_correct = 51; assert(isequal(AddMatrixLim(x),y_correct))\n\nx = 1 5 6 7 4 9 4 7 9 4 2 1 0 1 2 8 y = 51" ]
[ null ]
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https://www.xarg.org/puzzle/project-euler/problem-3/
[ "# Project Euler 3 Solution: Largest prime factor\n\nProblem 3\n\nThe prime factors of 13195 are 5, 7, 13 and 29.\n\nWhat is the largest prime factor of the number 600851475143?\n\n## JavaScript Solution\n\nFactorizing a number is a quite common problem and I'll not go into details here. A pretty straighforward implementation can be stated as this:\n\n```function factorize(num) {\nvar factors = {};\n\nvar n = num;\nvar i = 2;\n\nfunction count(n) {\nif (factors[n])\n++factors[n];\nelse\nfactors[n] = 1;\n}\n\nwhile (i * i <= n) {\n\nwhile (n % i === 0) {\nn/= i;\ncount(i);\n}\ni++;\n}\n\nif (n !== num) {\nif (n > 1)\ncount(n);\n} else {\ncount(num);\n}\nreturn factors;\n}```\n\nWith it, the problem can be solved quite easily:\n\n```function solution(n) {\n\nvar tmp = factorize(n);\nvar max = 0;\nfor (var i in tmp) {\nmax = Math.max(max, i);\n}\nreturn max;\n}```\n\nAlternatively, we can combine the two functions into a much smaller one, custom tailored for this task. Since the largest prime has an exponent of 1, we don't need extra checks and can go with (otherwise the commented out check is needed):\n\n```function solution(n) {\n\nfor (var i = 2; i * i <= n; i++) {\nwhile(n % i === 0 /* && i * i <= n */) {\nn/= i;\n}\n}\nreturn n;\n}\nsolution(600851475143);```\n\n« Back to problem overview" ]
[ null ]
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https://visbis.com/newsinfo/batteries-basics-about-batteries-part-vocabularysymantics.html
[ "# Batteries, basics about batteries, Part!: Introduction and Vocabulary/Semantics\n\nAt this point in time battery world experiencing revolution in shapes configurations and chemistry. Sometimes it is confusing to understand which battery is the best to use for your particulate application. Also users sometimes can’t find the right substitution for the battery they had before. I will try to help in this article to understand what is what and basic ideas about batteries.", null, "The most common are carbon-zinc, alkaline, lead acid, nickle metal hydride, nickle cadmium and lithium ion. But there are many other types of chemistry, which used more seldom. Below we discuss different of the battery designs currently used, some of the chemistry involved, and advantages and disadvantages of each design. We have also included some useful definitions and a list of parameters to guide you in matching your battery requirements to a specific battery design.\n\n________________________________________\nDefinitions\nAnode: The electrode where oxidation (loss of electrons) takes place. While discharging, it is the negative electrode; while charging it becomes the positive electrode.\n• Amps (A): Also known as Amperes. This is the rate at which electrons flow in a wire. Or simply “Current”\n• Amp hours (Ahr, mAh, mah etc): Also known as ampere hours. This is a measure of the amount of charge stored or used. This parameter characterize how “big” is the battery in electrical sense.\nSo Amp-Hours, (AH), or milliamp-Hours (mAH) is a measure of the size of the battery a 200 mAH battery is twice as big as a 100 mAH battery, even though they may be in the same physical dimension and size.\n• Batteries: Two or more electrochemical cells, electrically interconnected,\n• Battery cell: One battery of given chemistry, not connected in formation. Normally it contains two electrodes and an electrolyte. The redox (oxidation-reduction) reactions that occur at these electrodes convert electrochemical energy into electrical energy. Very often people commonly calling something a “battery” but intermixing the definitions of a single sell or battery pack formed with single cells. Very often it is not obvious that battery does consist of a few single cells.\n• C:C represents the capacity of a battery divided by 1 hour, its units are amps. In most of specifications you will commonly find that C parameter. Don’t be confused, it is just the battery capacity in mAh or Ah said in one letter C.\nIt represents a 1 hour discharge rate using the nominal capacity of the battery. So a discharge rate of 10C for a 5AH battery would be 50 amps. The concept of “C” is also used for charge currents, since both charge and discharge properties are proportional to the capacity of the battery, so a 5C charge rate for a 5 AH battery would be 25 amps.\n• Capacity: The total quantity of electricity or total ampere-hours available from a fully charged cell or battery.\n• Cathode: The electrode where reduction (gain of electrons) takes place. When discharging, it is the positive electrode, when charging, it becomes the negative electrode.\n• Charge: The conversion of electrical energy, provided in the form of current from an external source, into chemical energy stored at the electrodes of a cell or battery.\n• Discharge: The conversion of the chemical energy of a cell into electrical energy, which can then be used to supply power to a system.\n• Discharge curve: A plot of cell voltage over time into the discharge, at a constant temperature and constant current discharge rate.\n\nCharge-Discharge curve for LiFePO4 battery", null, "Typical discharge curves for LiFePO4 battery\n\nEach curve in this graph represents cell performance at a different discharge rate. The farther right the curve ends, the lower the discharge rate.\n• Dry cell: A Leclanché cell, so called because of its non-fluid electrolyte (to prevent spillage). This is achieved by adding an inert metal oxide so that the electrolyte forms a gel or paste.\n• Efficiency: For a secondary cell, the ratio of the output on discharge to the input required to restore it to its initial state of charge under specified conditions. Can be measured in ampere-hour, voltage, and watt-hour efficiency.\n• Electrolyte: The chemistry of a battery requires a medium that provides the ion transport mechanism between the positive and negative electrodes of a cell.\n• Energy density (specific energy): These two terms are often used interchangeably. Energy density refers mainly to the ratio of a battery’s available energy to its volume (watt hour/liter). Specific energy refers to the ratio of energy to mass (watt hour/kg). The energy is determined by the charge that can be stored and the cell voltage (E=qV).\n• Fuel cell: A cell in which one or both of the reactants are used in the battery to convert it to electricity. Unlike the metal anodes typically used in batteries, the fuels in a fuel cell are usually gas or liquid, with oxygen as the oxidant. The hydrogen/oxygen fuel cell is the most common. In this fuel cell, hydrogen is oxidized at the anode: 2H2 > 4H+ + 4e\n\n•Polarization: The voltage drop in a cell during discharge due to the flow of an electrical current. The cell’s internal resistance increases with the buildup of a product of oxidation or a reduction of an electrode, preventing further reaction.\n\n•Power: Measured by Watts. Power: P=VI. where V is voltage (V) and I is current ,\n\nSince V=IR, P=I2R and P=V2/R\n\nPower also can be described by energy emitted per unit of time: P=E/t.\n\nThus E=VIt=qV.\n\n•Power density (specific power): Power density is the ratio of the power available from a battery to its volume (watts/liter). Specific power generally refers to the ratio of power to mass (watts/kg). Comparison of power to cell mass is more common.\n\n•Primary cells: A cell that is not designed for recharging and is discarded once it has produced all its electrical energy.\n\n•Prismatic: Just a word to say that the cells are not cylindrical, as nature intended battery cells to be, but fit nicely into a parallelepiped, rectangular or any other such flattened shape.\n\nViewed: 378" ]
[ null, "http://visbis.com/image/catalog/news/allbatsmsm.jpg", null, "http://visbis.com/image/catalog/news/chrgdischarge1-300x161.jpg", null ]
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https://www.libhunt.com/compare-matplotlib-vs-pyqtgraph
[ "matplotlib VS PyQtGraph\n\nCompare matplotlib vs PyQtGraph and see what are their differences.", null, "matplotlib\n\nmatplotlib: plotting with Python (by matplotlib)", null, "PyQtGraph\n\nFast data visualization and GUI tools for scientific / engineering applications (by pyqtgraph)\n• OPS - Build and Run Open Source Unikernels\n• SonarQube - Static code analysis for 29 languages.\n• Scout APM - Less time debugging, more time building\nmatplotlib PyQtGraph\n12 11\n14,900 2,689\n2.0% 1.7%\n9.9 9.6\n1 day ago 9 days ago\nPython Python\nThe number of mentions indicates the total number of mentions that we've tracked plus the number of user suggested alternatives.\nStars - the number of stars that a project has on GitHub. Growth - month over month growth in stars.\nActivity is a relative number indicating how actively a project is being developed. Recent commits have higher weight than older ones.\nFor example, an activity of 9.0 indicates that a project is amongst the top 10% of the most actively developed projects that we are tracking.\n\nmatplotlib\n\nPosts with mentions or reviews of matplotlib. We have used some of these posts to build our list of alternatives and similar projects. The last one was on 2021-10-30.\n• Looking for help formatting a line graph\n1 project | reddit.com/r/libreoffice | 10 Dec 2021\nmatplotlib + their User's Guide.\n• Problem with surface plot color and legend\n1 project | reddit.com/r/learnpython | 24 Nov 2021\n# https://old.reddit.com/r/learnpython/comments/r1etmt/problem_with_surface_plot_color_and_legend/ # AmericaRL_03.py # Comparação entre random walk e difusão em 1d import numpy as np import matplotlib.pyplot as plt M = 100000 # Número de walkers L = 100 # Tamanho da malha # A cada intervalo de tempo, mover o walker e propagar a difusão p = 0.1 # Probabilidade de andar pinv = 1.0 - p nsteps = 2001 # Número de intervalos de tempo # Iniciando as concentrações c = np.zeros((2, 2 * L + 1, 2 * L + 1)) i0 = 0 i1 = 1 c[:, L, L] = M # c[:,L,L] corresponde a (x,y) = (0,0) edgesdiff = np.array(range(-L - 1, L + 1)) - 0.5 xc = 0.5 * (edgesdiff[:-1] + edgesdiff[1:]) xx, yy = np.meshgrid(xc, xc) D = p noutput = 100 for it in range(nsteps): # Executar a etapa na equação de difusão for ix in range(1, len(c) - 1): for iy in range(1, len(c) - 1): # Usar i0 e gerar i1 c[i1, ix, iy] = c[i0, ix, iy] + D * ( c[i0, ix - 1, iy] + c[i0, ix + 1, iy] - 4 * c[i0, ix, iy] + c[i0, ix, iy - 1] + c[i0, ix, iy + 1] ) # Inverter i0 e i1 ii = i1 i1 = i0 i0 = ii # Plotar as concentrações if np.mod(it, noutput) == 0: fig = plt.figure() ax = fig.add_subplot(111, projection=\"3d\") # ax.cla() diff = ax.plot_surface(xx, yy, c[0, :, :], cmap=\"Reds\", label=\"Difusão\") plt.title(\"Tempo = {}, M = {}, p = {}\".format(it, M, p)) ax.set_xlabel(\"Distância percorrida (x)\") ax.set_ylabel(\"Distância percorrida (y)\") ax.set_zlabel(\"Concentração\") # ax.legend() fails getting proper label key color in 3D plots # # AttributeError missing _facecolors2d and _edgecolors2d are raised # in 3D projection method get_facecolor() used by legend handler # # Is open issue since 2015 # https://github.com/matplotlib/matplotlib/issues/4067 if False: # OP's way: Set values manually to keep legend() quiet diff._facecolors2d = diff._facecolor3d diff._edgecolors2d = diff._edgecolor3d ax.legend() # But then problems with legend() getting proper legend key color # default (blue) is used instead of a value from set cmap (Reds) else: # DIFFERENT FIX: Draw legend key and legend label manually # # First get suitable cmap color (instead blue default) # https://stackoverflow.com/a/25408562 from matplotlib.cm import get_cmap cmap = get_cmap('Reds') my_red_rgba = cmap(0.5) # e.g. a color in middle of range (0..1) # Then insert own artist for legend key and legend label # https://matplotlib.org/stable/tutorials/intermediate/legend_guide.html import matplotlib.patches as mpatches red_patch = mpatches.Patch(color=my_red_rgba, label='Difusão') ax.legend(handles=[red_patch]) # plt.show() plt.savefig('tempo_{}.png'.format(it),dpi = 600) plt.pause(0.001) ax.cla() # is nicer placed here instead above\n• Python 3.8, 3.9 or 3.10 for new projects?\n3 projects | reddit.com/r/Python | 30 Oct 2021\nmatplotlib supports 3.10 since May\n• Top 10 Python Libraries for Machine Learning\n14 projects | dev.to | 9 Sep 2021\nWebsite: https://matplotlib.org/ Github Repository: https://github.com/matplotlib/matplotlib Developed By: Micheal Droettboom, Community Primary purpose: Data Visualization\n• Should you learn Julia or Python for Machine Learning?\n8 projects | reddit.com/r/learnmachinelearning | 15 Aug 2021\nBut, now we have to get used to Python's library of Machine Learning packages: tensorflow, numpy, matplotlib, and finally pandas\n• Is there a way to improve this code?\n1 project | reddit.com/r/learnpython | 3 Apr 2021\n• Top 10 Python Libraries\n14 projects | dev.to | 24 Mar 2021\n• Matplotlib: why do plot and axes interfaces use different method names to do the exact same thing?\n1 project | reddit.com/r/learnpython | 5 Mar 2021\nI think sloppiness explains it, this explains how you can fix it ;)\n• How I create GitHub project reporting from scratch\n10 projects | dev.to | 5 Mar 2021\nFirstly, I tried the most popular visualization library matplotlib. But its configuration didn’t seem clear to me, so moved on with other options.\n• Valentine's Day Challenge\n1 project | reddit.com/r/cryptography | 17 Feb 2021\nThat would explain the link to https://matplotlib.org/ in the file...\n\nPyQtGraph\n\nPosts with mentions or reviews of PyQtGraph. We have used some of these posts to build our list of alternatives and similar projects. The last one was on 2021-08-22.\n\nWhat are some alternatives?\n\nWhen comparing matplotlib and PyQtGraph you can also consider the following projects:\n\nplotly - The interactive graphing library for Python (includes Plotly Express) :sparkles:\n\npygal - PYthon svg GrAph plotting Library\n\nVisPy - Main repository for Vispy\n\nbokeh - Interactive Data Visualization in the browser, from Python\n\nbqplot - Plotting library for IPython/Jupyter notebooks\n\nplotnine - A grammar of graphics for Python\n\nggplot - ggplot port for python\n\nGraphviz - Simple Python interface for Graphviz\n\nseaborn - Statistical data visualization in Python" ]
[ null, "https://avatars.githubusercontent.com/u/215947", null, "https://avatars.githubusercontent.com/u/5440571", null ]
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http://code.abettergeek.com/ABG/CasioPomrie/src/branch/master/translator.ps1
[ "Work to localize the Japanese-language Casio Pomrie software, which is required to use the Wi-Fi features of the Pomrie stamp maker.\nYou can not select more than 25 topics Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.\n\n#### 93 lines 2.8 KiB Raw Permalink Blame History\n\n `# read in the xib, original encoding is utf8` `\\$lines = Get-Content .\\MainMenu.xib -Encoding UTF8` `# set new variable for output` `# this is where we make our translation edits` `\\$output = \\$lines` `# pull out every line with a string keyed \"NSDev\"` `\\$regex = '(?.+?)<\\/string>'` `# regex results` `\\$strings = [regex]::Matches(\\$lines,\\$regex)` `# public translation API - no key required!` `# throttled to 40 requests per 60 seconds` `# one request per 1.5 seconds` `\\$url = 'https://translate.mentality.rip/translate'` `# log errors` `\\$errors = @()` `# create a CSV of translated values, to make corrections easier` `# this is because the final XIB still has base64-encoded strings` `\\$csv = 'Base64JP,UTF8JP,Base64EN,UTF8EN'` `# process every regex match` `foreach(\\$string in \\$strings) {` ` # get the base64 value` ` # uses named regex key` ` \\$txt = \\$string.Groups[\"txt\"].Value` ` # append appropriate padding` ` # sauce: https://gist.github.com/obscuresec/82775093ad892ef5fd00` ` \\$mod = (\\$txt.length % 4) ` ` switch (\\$mod) {` ` '0' {\\$txtp = \\$txt}` ` '1' {\\$txtp = \\$txt.Substring(0,\\$txt.Length - 1)}` ` '2' {\\$txtp = \\$txt + ('=' * (4 - \\$mod))}` ` '3' {\\$txtp = \\$txt + ('=' * (4 - \\$mod))}` ` ` ` }` ` # convert the base64 to UTF8 text` ` \\$utf = [Text.Encoding]::Utf8.GetString([Convert]::FromBase64String(\\$txtp))` ` # get current array index (for progress bar)` ` \\$idx = [array]::IndexOf(\\$strings,\\$string)` ` # get percent complete (for progress bar)` ` \\$pct = ((\\$idx + 1) / \\$strings.Count) * 100` ` # round the percent to one decimal` ` \\$pcn = [math]::Round(\\$pct,2)` ` # update the status bar` ` Write-Progress -Activity (\"Translating <<\" + \\$utf + \">>\") -Status \"\\$pcn% Complete:\" -PercentComplete \\$pct` ` # create the json request using Japanese string` ` \\$json = '{\"q\":\"' + \\$utf + '\",\"source\":\"ja\",\"target\":\"en\"}'` ` # add delay due to api throttle` ` Start-Sleep -Seconds 1.5` ` try {` ` # post the request to the translation service` ` \\$result = Invoke-WebRequest -Method 'Post' -Uri \\$url -Body \\$json -ContentType \"application/json; charset=utf-8\"` ` ` ` # this is the english translation` ` \\$ttxt = (\\$result.Content | ConvertFrom-Json).translatedText` ` ` ` # convert the english translation to base64 using .net` ` \\$txt64 = [Convert]::ToBase64String([Text.Encoding]::UTF8.GetBytes(\\$ttxt))` ` ` ` # remove the padding == because these don't exist in the original XIB` ` \\$txt64clean = \\$txt64 -replace '=',''` ` ` ` # replace the value everywhere it occurs in the source data` ` \\$output = \\$output -replace \\$txt,\\$txt64clean` ` # add to the csv` ` \\$csv += \"`n\"\"\\$txt\"\",\"\"\\$utf\"\",\"\"\\$txt64clean\"\",\"\"\\$ttxt\"\"\"` ` } catch {` ` # couldn't translate, probably because it's already English` ` Write-Host (\"Couldn't translate <<\" + \\$utf + \">>\")` ` \\$errors += \\$utf` ` }` `}` `# save the xib` `\\$output | Out-File Output.xib -Encoding utf8` `# save the csv` `\\$csv | Out-File output.csv -Encoding utf8`" ]
[ null ]
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https://kerodon.net/tag/023L
[ "# Kerodon\n\n$\\Newextarrow{\\xRightarrow}{5,5}{0x21D2}$ $\\newcommand\\empty{}$\n\n### 5.1.5 Equivalences of Fibered $\\infty$-Categories\n\nLet $\\operatorname{\\mathcal{D}}$ be an $\\infty$-category. Our primary goal in this section is to show that, when studying $\\infty$-categories $\\operatorname{\\mathcal{C}}$ equipped with a cartesian fibration $\\operatorname{\\mathcal{C}}\\rightarrow \\operatorname{\\mathcal{D}}$, equivalence can be detected fiberwise. More precisely, we have the following result:\n\nTheorem 5.1.5.1. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{ \\overline{F} } & \\operatorname{\\mathcal{D}}' }$\n\nwhere $U$ is a cartesian fibration of $\\infty$-categories, $U'$ is an isofibration of $\\infty$-categories, and $\\overline{F}$ is an equivalence of $\\infty$-categories. Then the functor $F$ is an equivalence of $\\infty$-categories if and only if it satisfies the following conditions:\n\n$(1)$\n\nFor every object $D \\in \\operatorname{\\mathcal{D}}$ having image $D' = \\overline{F}(D)$ in $\\operatorname{\\mathcal{D}}'$, the induced functor\n\n$F_{D}: \\operatorname{\\mathcal{C}}_{D} = \\{ D\\} \\times _{\\operatorname{\\mathcal{D}}} \\operatorname{\\mathcal{C}}\\rightarrow \\{ D' \\} \\times _{\\operatorname{\\mathcal{D}}'} \\operatorname{\\mathcal{C}}' = \\operatorname{\\mathcal{C}}'_{D'}$\n\nis an equivalence of $\\infty$-categories.\n\n$(2)$\n\nThe functor $F$ carries $U$-cartesian morphisms of $\\operatorname{\\mathcal{C}}$ to $U'$-cartesian morphisms of $\\operatorname{\\mathcal{C}}'$.\n\nMoreover, if these conditions are satisfied, then $U'$ is also a cartesian fibration of $\\infty$-categories.\n\nWe will give the proof of Theorem 5.1.5.1 at the end of this section. First, let us collect some of its consequences.\n\nCorollary 5.1.5.2. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{ \\overline{F} } & \\operatorname{\\mathcal{D}}'. }$\n\nAssume that $U$ and $U'$ are isofibrations of $\\infty$-categories and that $F$ and $\\overline{F}$ are equivalences of $\\infty$-categories. Then:\n\n• The functor $U$ is a cartesian fibration if and only if $U'$ is a cartesian fibration.\n\n• The functor $U$ is a cocartesian fibration if and only if $U'$ is a cocartesian fibration.\n\nProof. We will prove the first assertion; the second follows by a similar argument. It follows from Theorem 5.1.5.1 that if $U$ is a cartesian fibration, then $U'$ is also a cartesian fibration. To prove the converse, choose functors $G': \\operatorname{\\mathcal{C}}' \\rightarrow \\operatorname{\\mathcal{C}}$ and $\\overline{G}: \\operatorname{\\mathcal{D}}' \\rightarrow \\operatorname{\\mathcal{D}}$ which are homotopy inverse to the equivalences $F$ and $\\overline{F}$, respectively. We then have isomorphisms\n\n$U \\circ G' \\circ F \\simeq U \\simeq \\overline{G} \\circ \\overline{F} \\circ U = \\overline{G} \\circ U' \\circ F$\n\nin the functor $\\infty$-category $\\operatorname{Fun}(\\operatorname{\\mathcal{C}}, \\operatorname{\\mathcal{D}})$. Since $F$ is an equivalence of $\\infty$-categories, it follows that there exists an isomorphism $\\overline{\\alpha }: U \\circ G' \\rightarrow \\overline{G} \\circ U'$ in the functor $\\infty$-category $\\operatorname{Fun}(\\operatorname{\\mathcal{C}}', \\operatorname{\\mathcal{D}})$. Using our assumption that $U'$ is an isofibration, we can lift $\\overline{\\alpha }$ to an isomorphism of functors $\\alpha : G' \\rightarrow G$ (Proposition 4.4.5.8). Applying Theorem 5.1.5.1 to the commutative diagram\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}' \\ar [r]^-{G} \\ar [d]^-{U'} & \\operatorname{\\mathcal{C}}\\ar [d]^-{U} \\\\ \\operatorname{\\mathcal{D}}' \\ar [r]^-{\\overline{G}} & \\operatorname{\\mathcal{D}}, }$\n\nwe conclude that if $U'$ is a cartesian fibration, then $U$ is also a cartesian fibration. $\\square$\n\nCorollary 5.1.5.3. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{ \\overline{F} } & \\operatorname{\\mathcal{D}}'. }$\n\nAssume that $U$ and $U'$ are isofibrations of $\\infty$-categories and that $F$ and $\\overline{F}$ are equivalences of $\\infty$-categories. Then:\n\n• The functor $U$ is a right fibration if and only if $U'$ is a right fibration.\n\n• The functor $U$ is a left fibration if and only if $U'$ is a left fibration.\n\nProof. We will prove the first assertion; the second follows by a similar argument. Assume first that $U'$ is a right fibration of $\\infty$-categories. Then $U'$ is a cartesian fibration (Proposition 5.1.4.14), so Corollary 5.1.5.2 implies that $U$ is a cartesian fibration. To prove that $U$ is a right fibration, it will suffice to show that for every object $D \\in \\operatorname{\\mathcal{D}}$, the fiber $\\operatorname{\\mathcal{C}}_{D} = \\{ D\\} \\times _{\\operatorname{\\mathcal{D}}} \\operatorname{\\mathcal{C}}$ is a Kan complex (Proposition 5.1.4.14). This follows from Remark 4.5.1.21, since the functor $F$ induces an equivalence of $\\infty$-categories $F_{D}: \\operatorname{\\mathcal{C}}_{D} \\rightarrow \\operatorname{\\mathcal{C}}'_{ \\overline{F}(D)}$ (Corollary 4.5.4.7).\n\nWe now prove the reverse implication. Arguing as in the proof of Corollary 5.1.5.2, we can construct a commutative diagram\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}' \\ar [r]^-{G} \\ar [d]^-{U'} & \\operatorname{\\mathcal{C}}\\ar [d]^-{U} \\\\ \\operatorname{\\mathcal{D}}' \\ar [r]^-{\\overline{G}} & \\operatorname{\\mathcal{D}}, }$\n\nwhere $G$ and $\\overline{G}$ are homotopy inverses of the equivalences $F$ and $\\overline{F}$, respectively. It then follows from the preceding argument that if $U$ is a right fibration of $\\infty$-categories, then $U'$ is also a right fibration of $\\infty$-categories. $\\square$\n\nCorollary 5.1.5.4. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{\\overline{F}} & \\operatorname{\\mathcal{D}}'. }$\n\nwhere $U$ and $U'$ are right fibrations and the functor $\\overline{F}$ is an equivalence of $\\infty$-categories. Then $F$ is an equivalence of $\\infty$-categories if and only if, for every object $D \\in \\operatorname{\\mathcal{D}}$ having image $D' = \\overline{F}(D) \\in \\operatorname{\\mathcal{D}}'$, the induced map of fibers $F_{D}: \\operatorname{\\mathcal{C}}_{D} \\rightarrow \\operatorname{\\mathcal{C}}'_{D'}$ is a homotopy equivalence of Kan complexes.\n\nThe proof of Theorem 5.1.5.1 will require some preliminaries. Our first step is to show that if $U: \\operatorname{\\mathcal{C}}\\rightarrow \\operatorname{\\mathcal{D}}$ is an isofibration of $\\infty$-categories, then the collection of $U$-cartesian morphisms of $\\operatorname{\\mathcal{C}}$ is invariance under categorical equivalence.\n\nLemma 5.1.5.5. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{ \\overline{F} } & \\operatorname{\\mathcal{D}}', }$\n\nwhere the functors $U$ and $U'$ are inner fibrations and the functors $F$ and $\\overline{F}$ are fully faithful. Let $g: Y \\rightarrow Z$ be a morphism in $\\operatorname{\\mathcal{C}}$. If $F(g)$ is a $U'$-cartesian morphism of $\\operatorname{\\mathcal{C}}'$, then $g$ is a $U$-cartesian morphism of $\\operatorname{\\mathcal{C}}$.\n\nProof. By virtue of Proposition 5.1.2.1, it will suffice to show that for every object $X \\in \\operatorname{\\mathcal{C}}$, the diagram of Kan complexes\n\n5.9\n\\begin{equation} \\begin{gathered}\\label{equation:fully-faithful-check-cartesian} \\xymatrix@R =50pt@C=50pt{ \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(X,Y,Z) \\times _{ \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(Y,Z) } \\{ g\\} \\ar [r] \\ar [d] & \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(X,Z) \\ar [d] \\\\ \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}}( U(X), U(Y), U(Z) ) \\times _{ \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}}( U(Y), U(Z)) } \\{ U(g) \\} \\ar [r] & \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}}( U(X), U(Z) ) } \\end{gathered} \\end{equation}\n\nis a homotopy pullback square. Set $X' = F(X)$, $Y' = F(Y)$, $Z' = F(Z)$, and $g' = F(g)$. Since the functors $F$ and $\\overline{F}$ are fully faithful, (5.9) is homotopy equivalent to the diagram\n\n5.10\n\\begin{equation} \\begin{gathered}\\label{equation:fully-faithful-check-cartesian2} \\xymatrix@R =50pt@C=25pt{ \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}'}(X',Y',Z') \\times _{ \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(Y',Z') } \\{ g'\\} \\ar [r] \\ar [d] & \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}'}(X',Z') \\ar [d] \\\\ \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}'}( U'(X'), U'(Y'), U'(Z') ) \\times _{ \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}'}( U'(Y), U'(Z)) } \\{ U'(g') \\} \\ar [r] & \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}'}( U'(X'), U'(Z') ). } \\end{gathered} \\end{equation}\n\nOur assumption that $g'$ is $U'$-cartesian guarantees that (5.10) is a homotopy pullback square of Kan complexes (Proposition 5.1.2.1), so that (5.9) is also a homotopy pullback square (Corollary 3.4.1.10). $\\square$\n\nProposition 5.1.5.6. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{ \\overline{F} } & \\operatorname{\\mathcal{D}}', }$\n\nwhere the functors $U$ and $U'$ are isofibrations and the functors $F$ and $\\overline{F}$ are equivalences of $\\infty$-categories. Let $g: Y \\rightarrow Z$ be a morphism in $\\operatorname{\\mathcal{C}}$. Then $g$ is $U$-cartesian if and only if $F(g)$ is $U'$-cartesian.\n\nProof. It follows from Lemma 5.1.5.5 that if $F(g)$ is $U'$-cartesian, then $g$ is $U$-cartesian. For the converse, suppose that $g$ is $U$-cartesian. Arguing as in the proof of Corollary 5.1.5.2, we can construct a commutative diagram\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}' \\ar [r]^-{G} \\ar [d]^-{U'} & \\operatorname{\\mathcal{C}}\\ar [d]^-{U} \\\\ \\operatorname{\\mathcal{D}}' \\ar [r]^-{\\overline{G}} & \\operatorname{\\mathcal{D}}, }$\n\nwhere $G$ and $\\overline{G}$ are homotopy inverses of the equivalences $F$ and $\\overline{F}$, respectively. Then $G( F(g) )$ is isomorphic to $g$ as an object of the arrow $\\infty$-category $\\operatorname{Fun}(\\Delta ^1, \\operatorname{\\mathcal{C}})$. Invoking Corollary 5.1.2.5, we conclude that $G( F(g) )$ is $U$-cartesian, so that $F(g)$ is $U'$-cartesian by virtue of Lemma 5.1.5.5. $\\square$\n\nProposition 5.1.5.7. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{q} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{q'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{\\overline{F}} & \\operatorname{\\mathcal{D}}'. }$\n\nAssume that:\n\n$(1)$\n\nThe functors $q$ and $q'$ are inner fibrations.\n\n$(2)$\n\nThe inner fibration $q$ is cartesian and the functor $F$ carries $q$-cartesian morphisms of $\\operatorname{\\mathcal{C}}$ to locally $q'$-cartesian morphisms of $\\operatorname{\\mathcal{C}}'$.\n\n$(3)$\n\nThe functor $\\overline{F}: \\operatorname{\\mathcal{D}}\\rightarrow \\operatorname{\\mathcal{D}}'$ is fully faithful.\n\nThen $F$ is fully faithful if and only if, for every object $D \\in \\operatorname{\\mathcal{D}}$ having image $D' = \\overline{F}(D) \\in \\operatorname{\\mathcal{D}}'$, the induced map of fibers $F_{D}: \\operatorname{\\mathcal{C}}_{D} \\rightarrow \\operatorname{\\mathcal{C}}'_{D'}$ is fully faithful.\n\nProof. The “only if” direction follows from Proposition 4.6.2.6. For the converse, assume that each of the functors $F_{D}$ is fully faithful; we will show that $F$ is fully faithful. Let $X$ and $Z$ be objects of $\\operatorname{\\mathcal{C}}$ having images $\\overline{X}, \\overline{Z} \\in \\operatorname{\\mathcal{D}}$; we wish to show that the upper horizontal map in the diagram of Kan complexes\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(X,Z) \\ar [r] \\ar [d] & \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}'}( F(X), F(Z) ) \\ar [d] \\\\ \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}}( \\overline{X}, \\overline{Z} ) \\ar [r] & \\operatorname{Hom}_{\\operatorname{\\mathcal{D}}'}( \\overline{F}( \\overline{X} ), \\overline{F}( \\overline{Z} )) }$\n\nis a homotopy equivalence. Since $q$ and $q'$ are inner fibrations, the vertical maps are Kan fibrations (Proposition 4.6.1.19). Assumption $(3)$ guarantees that the lower horizontal map is a homotopy equivalence. By virtue of Proposition 3.2.8.1, it will suffice to show that for every morphism $\\overline{e}: \\overline{X} \\rightarrow \\overline{Z}$ in $\\operatorname{\\mathcal{D}}$, the induced map of fibers\n\n$\\theta : \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(X,Z)_{\\overline{e}} \\rightarrow \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}'}( F(X), F(Z) )_{ \\overline{F}(\\overline{e} ) }$\n\nis a homotopy equivalence.\n\nLet $[\\theta ]$ denote the homotopy class of $\\theta$, regarded as a morphism in the homotopy category $\\mathrm{h} \\mathit{\\operatorname{Kan}}$. Since $q$ is a cartesian fibration, there exists a $q$-cartesian morphism $g: Y \\rightarrow Z$ of $\\operatorname{\\mathcal{C}}$ satisfying $q(g) = \\overline{e}$. We then have a commutative diagram\n\n$\\xymatrix@C =50pt@R=50pt{ \\operatorname{Hom}_{ \\operatorname{\\mathcal{C}}_{ \\overline{X} }}(X,Y) \\ar [d]^-{ [g] \\circ } \\ar [r] & \\operatorname{Hom}_{ \\operatorname{\\mathcal{C}}'_{ \\overline{F}(\\overline{X})} }( F(X), F(Y) ) \\ar [d]^-{ [F(g)] \\circ } \\\\ \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}}(X,Z)_{ \\overline{e} } \\ar [r]^-{ [ \\theta ] } & \\operatorname{Hom}_{\\operatorname{\\mathcal{C}}'}( F(X), F(Z) )_{ \\overline{F}( \\overline{e} ) } }$\n\nin $\\mathrm{h} \\mathit{\\operatorname{Kan}}$, where the vertical maps are given by the composition law of Notation 5.1.3.10. Assumption $(2)$ guarantees that $F(g)$ is locally $q'$-cartesian, so that the vertical maps in this diagram are isomorphisms in $\\mathrm{h} \\mathit{\\operatorname{Kan}}$ (Proposition 5.1.3.11). It will therefore suffice to show that the functor $F_{\\overline{X}}$ induces a homotopy equivalence of mapping spaces $\\operatorname{Hom}_{ \\operatorname{\\mathcal{C}}_{ \\overline{X} }}(X,Y) \\rightarrow \\operatorname{Hom}_{ \\operatorname{\\mathcal{C}}'_{ \\overline{F}(\\overline{X})} }( F(X), F(Y) )$, which follows from our assumption that $F_{ \\overline{X} }$ is fully faithful. $\\square$\n\nRemark 5.1.5.8. In the situation of Proposition 5.1.5.7, we can replace $(2)$ with the following a priori weaker assumption:\n\n$(2')$\n\nFor every object $Z \\in \\operatorname{\\mathcal{C}}$ and every morphism $\\overline{u}: \\overline{Y} \\rightarrow q(Z)$ in $\\operatorname{\\mathcal{D}}$, there exists a $q$-cartesian $u: Y \\rightarrow Z$ of $\\operatorname{\\mathcal{C}}$ satisfying $q(u) = \\overline{u}$ and for which $F(u)$ is locally $q'$-cartesian.\n\nAssume that $(2)$ is satisfied and let $v: X \\rightarrow Z$ be any $q$-cartesian morphism in $\\operatorname{\\mathcal{C}}$; we wish to show that $F(v)$ is locally $q'$-cartesian. To prove this, we can assume without loss of generality that $\\operatorname{\\mathcal{D}}= \\Delta ^1 = \\operatorname{\\mathcal{D}}'$ and that $\\overline{F}$ is the identity map. Using $(2')$, we can choose another $q$-cartesian morphism $u: Y \\rightarrow Z$ satisfying $q(u) = q(v)$ for which $F(u)$ is $q'$-cartesian. Applying Remark 5.1.3.8, we see that $v$ can be obtained as a composition of $u$ with an isomorphism in the $\\infty$-category $\\operatorname{\\mathcal{C}}$. Then $F(v)$ can be obtained as the composition of $F(u)$ with an isomorphism in the $\\infty$-category $\\operatorname{\\mathcal{C}}'$, and is therefore $q$-cartesian by virtue of Corollary 5.1.2.4 (and Proposition 5.1.1.8).\n\nProof of Theorem 5.1.5.1. Suppose we are given a commutative diagram of $\\infty$-categories\n\n$\\xymatrix@R =50pt@C=50pt{ \\operatorname{\\mathcal{C}}\\ar [r]^-{F} \\ar [d]^-{U} & \\operatorname{\\mathcal{C}}' \\ar [d]^-{U'} \\\\ \\operatorname{\\mathcal{D}}\\ar [r]^-{ \\overline{F} } & \\operatorname{\\mathcal{D}}' }$\n\nwhere $U$ is a cartesian fibration of $\\infty$-categories, $U'$ is an isofibration of $\\infty$-categories, and $\\overline{F}$ is an equivalence of $\\infty$-categories. If $F$ satisfies conditions $(1)$ and $(2)$ of Theorem 5.1.5.1, then it is fully faithful (Proposition 5.1.5.7) and essentially surjective (Remark 4.6.2.16), hence an equivalence of $\\infty$-categories by virtue of Theorem 4.6.2.17. Conversely, if $F$ is an equivalence of $\\infty$-categories, then it satisfies conditions $(1)$ and $(2)$ by virtue of Corollary 4.5.4.7 and Proposition 5.1.5.7, respectively. To complete the proof, we must show that if these conditions are satisfied, then $U'$ is also a cartesian fibration of $\\infty$-categories.\n\nLet $Z'$ be an object of $\\operatorname{\\mathcal{C}}'$ and let $\\overline{g}': \\overline{Y}' \\rightarrow U'(Z')$ be a morphism in $\\operatorname{\\mathcal{D}}'$; we wish to show that $\\overline{g}'$ can be lifted to a $U'$-cartesian morphism $Y' \\rightarrow Z'$ in $\\operatorname{\\mathcal{C}}'$. Since $F$ is essentially surjective, we can choose an object $Z \\in \\operatorname{\\mathcal{C}}$ and an isomorphism $v: F(Z) \\rightarrow Z'$ in the $\\infty$-category $\\operatorname{\\mathcal{C}}'$. Since $\\overline{F}$ is essentially surjective, we can choose an object $\\overline{Y} \\in \\operatorname{\\mathcal{D}}$ and an isomorphism $\\overline{u}: \\overline{F}(\\overline{Y}) \\rightarrow \\overline{Y}'$ in the $\\infty$-category $\\operatorname{\\mathcal{D}}'$. Since $\\overline{F}$ is fully faithful at the level of homotopy categories, we can choose a morphism $\\overline{g}: \\overline{Y} \\rightarrow U(Z)$ in $\\operatorname{\\mathcal{D}}$ for which the diagram\n\n$\\xymatrix@R =50pt@C=50pt{ \\overline{F}( \\overline{Y} ) \\ar [r]^-{ \\overline{F}( \\overline{g} ) } \\ar [d] & \\overline{F}( U(Z) ) \\ar [d]^-{ U'(v) } \\\\ \\overline{Y}' \\ar [r]^-{ \\overline{g}' } & \\overline{Z}', }$\n\ncommutes in the homotopy category $\\mathrm{h} \\mathit{\\operatorname{\\mathcal{D}}'}$, and can therefore be lifted to a commutative diagram $\\overline{\\sigma }$ in $\\infty$-category $\\operatorname{\\mathcal{D}}'$ (see Exercise 1.4.2.10). Using our assumption that $U$ is a cartesian fibration, we can lift $\\overline{g}$ to a $U$-cartesian morphism $g: Y \\rightarrow Z$ of $\\operatorname{\\mathcal{C}}$. Since $U'$ is an isofibration, Proposition 4.4.5.8 guarantees that we can lift $\\overline{\\sigma }$ to a commutative diagram $\\sigma :$\n\n$\\xymatrix@R =50pt@C=50pt{ F(Y) \\ar [r]^-{ F(g) } \\ar [d] & F(Z) \\ar [d]^-{ v } \\\\ Y' \\ar [r]^-{ g' } & Z' }$\n\nin the $\\infty$-category $\\operatorname{\\mathcal{C}}'$, where the vertical maps are isomorphisms. To complete the proof, it will suffice to show that the morphism $g'$ is $U'$-cartesian. This follows from Corollary 5.1.2.5, since the morphism $F(g)$ is $U'$-cartesian (Proposition 5.1.5.6). $\\square$" ]
[ null ]
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[ "• 为什么平均磁盘寻道时间是完整寻道时间的三分之一?(Why is average disk seek time one-third of the full...\n2021-07-16 02:02:54\n\n为什么平均磁盘寻道时间是完整寻道时间的三分之一?(Why is average disk seek time one-third of the full seek time?)\n\n考虑到磁盘性能,我已经阅读过很多书和论文,平均搜索时间大约是完整搜索时间的三分之一,但没有人真正提供任何解释。 这是从哪里来的?\n\nI have read in many books and papers, considering disk performance, that the average seek time is roughly one-third of the full seek time, but no one really offers any explanation about that. Where does this come from?\n\n原文:https://stackoverflow.com/questions/9828736\n\n更新时间:2020-01-09 20:34\n\n最满意答案\n\n平均值使用微积分进行数学计算。 我们使用非常基本的公式来计算平均值。\n\n平均寻道时间=(所有可能寻道时间的总和)/(可能寻道时间的总数)\n\n假定磁盘具有N个磁道,所以这些磁道的编号从1 ... N。在任何时间点磁头的位置可以是从0到N(包含)的任何值。 让我们说,磁头的初始位置在轨道'x'处,并且磁头的最终位置在轨道'y'处,以便x可以从0变化到N,并且y可以从0变化到N.\n\n根据我们对平均寻道时间的定义,我们可以这样说,\n\n平均寻道距离=(所有可能寻道距离之和)/(可能寻道距离的总数)\n\n按照x和y的定义,Total no。 (x = 0,N)SIGMA(y = 0,N)| xy | = INTEGRAL(x = 0,N)INTEGRAL(y = 0,N)| xy | dy dx\n\n为了解决这个问题,使用将表达式的模数分解为y = 0到x和y = x到N的技巧。然后求解x = 0到N.\n\n这出来是(N ^ 3)/ 3。\n\n平均搜索距离=(N ^ 3)/ 3 * N * N = N / 3\n\n平均寻道时间=平均寻道距离/寻道率\n\n如果从位置0到轨道N的寻道时间需要't'秒,则寻找速率= N / t\n\n因此,avg寻道时间=(N / 3)/(N / t)= t / 3\n\n参考:\n\nThe average is calculated mathematically using calculus. We use the very basic formula for calculation of average.\n\nAverage seek time = (Sum of all possible seek times)/(Total no. of possible seek times)\n\nThe disk is assumed to have N number of tracks, so that these are numbered from 1...N The position of the head at any point of time can be anything from 0 to N (inclusive). Let us say that the initial position of the disk head is at track 'x' and the final position of the disk head is at track 'y' , so that x can vary from 0 to N and also, y can vary from 0 to N.\n\nOn similar lines as we defined average seek time, we can say that,\n\nAverage seek distance = (Sum of all possible seek distances)/(total no. of possible seek distances)\n\nBy definition of x and y, Total no. of possible seek distances = N*N and Sum of all possible seek distances = SIGMA(x=0,N) SIGMA(y=0,N) |x-y| = INTEGRAL(x=0,N)INTEGRAL(y=0,N) |x-y| dy dx\n\nTo solve this, use the technique of splitting modulus of the expression for y = 0 to x and for y = x to N. Then solve for x = 0 to N.\n\nThis comes out to be (N^3)/3.\n\nAvg seek distance = (N^3)/3*N*N = N/3\n\nAverage seek time = Avg seek distance / seek rate\n\nIf the seek time for the from position 0 to track N takes 't' seconds then seek rate = N/t\n\nTherefore, avg seek time = (N/3)/(N/t) = t/3\n\nReference:\n\n相关问答\n\n当您向BufferedOutputStream写入100,000个字节时,您的程序将显式访问文件的每个字节并写入零。 在本地文件上使用RandomAccessFile.seek()时,您间接使用C系统调用fseek() 。 如何处理取决于操作系统。 在大多数现代操作系统中,支持稀疏文件 。 这意味着如果您要求空的100,000字节文件,则实际上不会使用100,000字节的磁盘空间。 当您写入字节100,001时,操作系统仍然不使用100,001字节的磁盘。 它为包含“真实”数据的块分配少量空间,并\n\n...\n\n所有寻求系统调用都会改变下一次读取文件的位置。 它不会移动驱动器头。 读取或写入数据时驱动器磁头会移动,而您无法直接控制下一步操作系统的操作。 读取大量不需要的数据会产生影响,因为所有读取的数据都需要OS缓冲区中的空间,并导致旧数据丢失。 因此,使用查找大文件将会导致文件系统缓存更少。 我所写的所有内容都假设你无法在内存中放入整个数据库。 如果可以的话,就这样做。 阅读所有内容并尝试在文件末尾添加新的和已更改的数据。 不要担心浪费的空间,只是偶尔做一些压缩。 如果你的数据库太大: 数据以块(或页面\n\n...\n\n经过很多反复试验,我想我终于明白了这一点。 首先你需要计算你的文件的采样率。 为此,获取AudioNode的最后渲染时间: var nodetime: AVAudioTime = self.playerNode.lastRenderTime\n\nvar playerTime: AVAudioTime = self.playerNode.playerTimeForNodeTime(nodetime)\n\nvar sampleRate = playerTime.sampleRate\n\n然后,以秒为单位将采样\n\n...\n\n磁头可能会到位,但磁盘可能不在该位置的正确位置。 所以想象首先必须移动头部,然后等待主轴旋转。 当头部到达时,它可能就在那里,但是可能需要等待至少半圈才能达到正确的扇区。 所以总结它们两者都允许。 编辑: 所以想象它就像一个Merry Go Round。 你可以在2秒内跑到最快乐的地方(你是头脑)。 但是你可能需要等待5到10秒才能让你的特定马匹在你抵达后到达你身边(马是你想要进入的部门)。 The head may get into place, but the disk might not b\n\n...\n\n平均值使用微积分进行数学计算。 我们使用非常基本的公式来计算平均值。 平均寻道时间=(所有可能寻道时间的总和)/(可能寻道时间的总数) 假定磁盘具有N个磁道,所以这些磁道的编号从1 ... N。在任何时间点磁头的位置可以是从0到N(包含)的任何值。 让我们说,磁头的初始位置在轨道'x'处,并且磁头的最终位置在轨道'y'处,以便x可以从0变化到N,并且y可以从0变化到N. 根据我们对平均寻道时间的定义,我们可以这样说, 平均寻道距离=(所有可能寻道距离之和)/(可能寻道距离的总数) 按照x和y的定义\n\n...\n\n这在seekToTime:的文档中seekToTime: : 寻求的时间可能与指定的效率时间不同。 对于样本的准确求求,请参阅seekToTime:toleranceBefore:toleranceAfter: . 因此,尝试使用seekToTime:toleranceBefore:toleranceAfter:相反,指定低容差或零容差。 在创建可能正在使用的任何AVURLAssets时,您可能还希望为AVURLAssetPreferPreciseDurationAndTimingKey指定tru\n\n...\n\n确保你有良好的联系 视频应该压缩为流媒体(产生巨大的差异) 使用bufferTime参数来获得理想的设置 用代码创建一个玩家,不要使用UI组件。 你会有更多的灵活性: http : //blog.martinlegris.com/2008/06/03/tutorial-playing-flv-video-in-plain-as3-part-1/ 警告,更长的缓冲区将允许更平滑的播放,更短的将寻求更快,但权衡是它将更频繁地击中缓冲区...不理想 make sure you have a good c\n\n...\n\n但是视频的AVCodecContext-> time_base == 1001/60000 这让我很困惑,我不明白。 time_base是AVRational类型的,它是一个由分子和分母组成的有理数,而不是使用小数点。 我假设他们不只是使用double的原因是这样你不会失去任何精度。 AVRational在来源中定义为: typedef struct AVRational{\n\nint num; ///< numerator\n\nint den; ///< denominator\n\n} AV\n\n...\n\n问题是,流程图只能寻求关键帧,以便能够寻找任何秒,你需要每秒钟都有关键帧。 很可能这意味着您需要在使用配置为每秒强制关键帧的ffmpeg上传视频时重新编码视频。 The issue is that flowplayer can seek to keyframes only so in order to be able to seek to any second you need to have keyframe for every second. Most probably that means\n\n...\n\n经过几次实验后,我找到了自己问题的答案。 经过非常频繁的文件concat操作(大约每分钟1k)后,数据节点在一天左右开始抱怨太多块,这导致我相信这确实会导致磁盘碎片化和块数增加。 我使用的解决方案是编写一个单独的作业,将这些文件连接(并压缩在我的情况下)为单个可拆分的归档文件(注意gzip不可拆分!)。 After a few experiments I found the answer to my own question. After very frequent file concat ope\n\n...\n\n更多相关内容\n• 最短寻道时间优先(SSTF)和扫描(SCAN)算法。理解各调度算法的工作原理 对给出的任意的磁盘请求序列、计算平均寻道长度;要求可定制磁盘请求序列长度、磁头起始位置、磁头移动方向。 测试:假设磁盘访问序列:98,...", null, "操作系统实验\n• 操作系统中的,4种寻道算法。FCFS(先来先服务) SSTF(最短寻道时间) SCAN(扫描算法) CSCAN(循环扫描法)\n• 可以对给出的任意的磁盘请求序列、计算平均寻道长度; 要求可定制磁盘请求序列长度、磁头起始位置、磁头移动方向。 测试:假设磁盘访问序列:98,183,37,122,14,124,65,67;读写头起始位置:53,方向:磁道...", null, "算法\n• 操作系统实验-磁盘调度:先来先服务、最短寻道时间算法", null, "计算机实验\n• 操作系统模拟之磁盘寻道算法。 文件共1份,代码如下: import math import random import copy def alo_fcfs(): print(\"您选择了FCFS算法,执行结果如下:\") print(\"当前磁道号 下一磁道号 绝对差\") print('{:...\n\n操作系统模拟之磁盘寻道算法。\n文件共1份,代码如下:\n\nimport math\nimport random\nimport copy\n\ndef alo_fcfs():\nprint(\"您选择了FCFS算法,执行结果如下:\")\nprint(\"当前磁道号 下一磁道号 绝对差\")\nprint('{:6d}{:10d}{:8d}'.format(start_numer, disk_queue, abs(start_numer - disk_queue)))\nsum_distance = abs(start_numer - disk_queue)\nfor i in range(disk_queue_length - 1):\nsum_distance = sum_distance + abs(disk_queue[i] - disk_queue[i + 1])\nprint('{:6d}{:10d}{:8d}'.format(disk_queue[i], disk_queue[i + 1], abs(disk_queue[i] - disk_queue[i + 1])))\nprint('{:6d} {} {}'.format(disk_queue[i], \"None\", \"None\"))\nprint('寻道序列总长{:d},FCFS算法的平均寻道长度为{:.2f}'.format(sum_distance, sum_distance / (disk_queue_length + 1)))\n\ndef alo_sstf():\nprint(\"您选择了SSTF算法,执行结果如下:\")\nprint(\"当前磁道号 下一磁道号 绝对差\")\nsum_distance = 0\nlast_number = start_numer\ntemp_queue = copy.deepcopy(disk_queue)\nwhile len(temp_queue) > 0:\nindex = 0\nmin_diff = 0x3f3f3f3f\nfor i in range(len(temp_queue)):\nif abs(temp_queue[i] - last_number) < min_diff:\nindex = i\nmin_diff = abs(temp_queue[i] - last_number)\nprint('{:6d}{:10d}{:8d}'.format(last_number, temp_queue[index], min_diff))\nlast_number = temp_queue[index]\nsum_distance = sum_distance + min_diff\ntemp_queue.pop(index)\nprint('{:6d} {} {}'.format(last_number, \"None\", \"None\"))\nprint('寻道序列总长{:d},SSTF算法的平均寻道长度为{:.2f}'.format(sum_distance, sum_distance / (disk_queue_length + 1)))\n\ndef cal(temp_queue, start_number, index, left1, left2, right1, right2, step1, step2):\nlast_number = start_number\nprint('{:6d}{:10d}{:8d}'.format(last_number, temp_queue[index], abs(last_number - temp_queue[index])))\nsum_distance = abs(last_number - temp_queue[index])\nlast_number = temp_queue[index]\nfor j in range(left1, right1, step1):\nprint('{:6d}{:10d}{:8d}'.format(last_number, temp_queue[j], abs(last_number - temp_queue[j])))\nsum_distance = sum_distance + abs(last_number - temp_queue[j])\nlast_number = temp_queue[j]\nfor j in range(left2, right2, step2):\nprint('{:6d}{:10d}{:8d}'.format(last_number, temp_queue[j], abs(last_number - temp_queue[j])))\nsum_distance = sum_distance + abs(last_number - temp_queue[j])\nlast_number = temp_queue[j]\nprint('{:6d} {} {}'.format(last_number, \"None\", \"None\"))\nprint('寻道序列总长{:d},FCFS算法的平均寻道长度为{:.2f}'.format(sum_distance, sum_distance / (disk_queue_length + 1)))\n\ndef alo_scan():\nprint(\"您选择了SCAN算法,执行结果如下:\")\nprint(\"请继续选择当前磁头运动方向\")\nprint(\"由低到高请输入1\")\nprint(\"由高到低请输入2\")\nlast_number = start_numer\ndirection_choice = int(input())\ntemp_queue = copy.deepcopy(disk_queue)\ntemp_queue.sort()\nprint()\nprint(\"当前磁道号 下一磁道号 绝对差\")\nif direction_choice == 1:\nfor j in temp_queue:\nif j > start_numer:\nindex = temp_queue.index(j)\nbreak\ncal(temp_queue, start_numer, index, index + 1, index - 1, disk_queue_length, -1, 1, -1)\nelif direction_choice == 2:\nfor j in range(disk_queue_length - 1, -1, -1):\nif temp_queue[j] < start_numer:\nindex = j\nbreak\ncal(temp_queue, start_numer, index, index - 1, index + 1, -1, disk_queue_length, -1, 1)\n\ndef alo_cscan():\nprint(\"您选择了CSCAN算法,执行结果如下:\")\nprint(\"请继续选择当前磁头运动方向\")\nprint(\"由低到高请输入1\")\nprint(\"由高到低请输入2\")\nlast_number = start_numer\ndirection_choice = int(input())\ntemp_queue = copy.deepcopy(disk_queue)\ntemp_queue.sort()\nprint()\nprint(\"当前磁道号 下一磁道号 绝对差\")\nif direction_choice == 1:\nfor j in temp_queue:\nif j > start_numer:\nindex = temp_queue.index(j)\nbreak\ncal(temp_queue, start_numer, index, index + 1, 0, disk_queue_length, index, 1, 1)\nelif direction_choice == 2:\nfor j in range(disk_queue_length - 1, -1, -1):\nif temp_queue[j] < start_numer:\nindex = j\nbreak\ncal(temp_queue, start_numer, index, index - 1, disk_queue_length - 1, -1, index, -1, -1)\n\nif __name__ == \"__main__\":\nprint(\"欢迎进入操作系统演示之磁盘寻道算法\")\nprint(\"现在开始数据初始化\")\nprint(\"请输入磁盘寻道序列长度(10-20,含端点):\")\ndisk_queue_length = int(input())\nif 10 <= disk_queue_length <= 20:\nprint(\"输入成功!\")\nelse:\nprint(\"您输入的磁盘寻道序列长度超出给定范围,请重新输入10-20(含端点)的数字:\")\nprint(\"请输入磁盘寻道序列长度(10-20,含端点):\")\ndisk_queue_length = int(input())\n\ndisk_queue = []\nfor k in range(disk_queue_length):\ndisk_queue.append(random.randint(0, 200))\nstart_numer = random.randint(0, 200)\nprint()\nprint('生成的磁盘寻道序列为:{}'.format(disk_queue))\n\nwhile True:\nprint()\nprint(\"请选择要执行的磁盘寻道算法:\")\nprint(\"选择FCFS请输入1\")\nprint(\"选择SSTF请输入2\")\nprint(\"选择SCAN请输入3\")\nprint(\"选择CSCAN请输入4\")\nalo_fcfs()\nalo_sstf()\nalo_scan()\nalo_cscan()\nelse:\nprint(\"您选择的不在范围内,请重新输入\")\nprint()\ncontinue\nprint()\nprint(\"继续尝试其他算法请输入1\")\nprint(\"更新数据请输入2\")\nprint(\"结束程序请输入3\")\nend_choice = int(input())\nif end_choice == 1:\ncontinue\nelif end_choice == 2:\nprint(\"现在开始更新数据\")\nprint(\"请输入更新的磁盘寻道序列长度(10-20,含端点):\")\ndisk_queue_length = int(input())\nif 10 <= disk_queue_length <= 20:\nprint(\"更新成功!\")\nelse:\nprint(\"您输入的磁盘寻道序列长度超出给定范围,请重新输入10-20(含端点)的数字:\")\nprint(\"请输入磁盘寻道序列长度(10-20,含端点):\")\ndisk_queue_length = int(input())\ndisk_queue = []\nfor k in range(disk_queue_length):\ndisk_queue.append(random.randint(0, 200))\nprint()\nprint('更新的磁盘寻道序列为:{}'.format(disk_queue))\nstart_numer = random.randint(0, 200)\nelse:\nprint(\"程序退出成功!\")\nbreak\n\n\n展开全文", null, "• 含本人实验报告,有具体流程图,实验课上写的,有更好的想法可以提出,大家一起学习,赚点积分不容易 C语言编写,调试过可运行,含实验...实验7,磁盘调度算法(一)——先来先服务(FCFS)和最短寻道时间优先(SSTF)\n• 操作系统的课程设计,可以直接拿来用,比较完整,C++语言\n• 原创最近操作系统实习,敲了实现最短寻道优先(SSTF)——磁盘调度管理的代码。题目阐述如下:设计五:磁盘调度管理设计目的:加深对请求磁盘调度管理实现原理的理解,掌握磁盘调度算法。设计内容:通过编程实现不同...\n\n原创\n\n最近操作系统实习,敲了实现最短寻道优先(SSTF)——磁盘调度管理的代码。\n\n题目阐述如下:\n\n设计五:磁盘调度管理\n\n设计目的:\n\n加深对请求磁盘调度管理实现原理的理解,掌握磁盘调度算法。\n\n设计内容:\n\n通过编程实现不同磁盘调度算法。\n\n设定开始磁道号寻道范围,依据起始扫描磁道号和最大磁道号数,随机产生要进行寻道的磁道号序列。\n\n选择磁盘调度算法,显示该算法的磁道访问顺序,计算出移动的磁道总数和平均寻道总数。\n\n常用的磁盘调度算法简介如下,请在以下算法中任意选择两种实现,并对算法性能进行分析对比。\n\n1. 最短寻道优先算法SSTF:该算法选择这样的进程:其要求访问的磁道与当前磁头所在的磁道距离最近,以使每次的寻道时间最短。\n\n2. 扫描算法SCAN:该算法不仅考虑到欲访问的磁道与当前磁道间的距离,更优先考虑的是磁头当前的移动方向。\n\n例如,当磁头正在自里向外移动时,SCAN算法所考虑的下一个访问对象,应是其欲访问的磁道既在当前磁道之外,又是距离最近的。\n\n这样自里向外地访问,直至再无更外的磁道需要访问时,才将磁臂换向为自外向里移动。\n\n3.循环扫描算法CSCAN:CSCAN算法规定磁头单向移动,例如,只是自里向外移动,当磁头移到最外的磁道并访问后,\n\n磁头立即返回到最里的欲访问的磁道,亦即将最小磁道号紧接着最大磁道号构成循环,进行循环扫描。\n\n首先用 rand 函数随机产生磁道号序列,随机选择一磁道号为起点开始寻道。\n\n下一磁道满足在所有磁道中其离当前被访问磁道最近,可用一数组 num_track 存放其他磁道与当前被访问磁道的距离。\n\n在数组 num_track 筛选出数值最小(即离当前被访问磁道最近)的磁道,再以当前磁道为起点,继续计算其他未被访\n\n问磁道与其的距离,再从 num_track 中筛选出数值最小的的磁道来访问......\n\n#include#include#include#include\n\n#define MAX 50 //可访问的最大磁道号\n\n#define N 20 //磁道号数目\n\nint track[N]; //存放随机产生的要进行寻道访问的磁道号序列\n\nint num_track[N]; //记录其他磁道与当前被访问磁道的距离\n\nint total=0; //统计已被访问的磁道号数\n\nint all_track=0; //移动的磁道总数\n\ndouble aver_track; //平均寻道总数\n\nvoid SSTF(int order){ //order为track中当前被访问的磁道下标\n\nprintf(\"%d\",track[order]);\n\nnum_track[order]=-1;\n\ntotal++; //已被访问磁道号+1\n\nif(total==N){return;\n\n}int i=0;for(i=0;i<=N-1;i++){ //计算其他磁道与当前被访问磁道的距离\n\nif(num_track[i]!=-1){\n\nnum_track[i]=abs(track[order]-track[i]);\n\n}\n\n}int min=9999;intx;for(i=0;i<=N-1;i++){ //找出track中与当前被访问磁道距离最短的\n\nif(num_track[i]!=-1){if(num_track[i]\n\nmin=num_track[i];\n\nx=i;\n\n}\n\n}\n\n}\n\nall_track+=abs(track[order]-track[x]); //计算当前被访问磁道与下一被访问磁道的距离\n\nSSTF(x);\n\n}intmain(){int i=0;\n\nsrand(time(0));\n\nprintf(\"磁道号序列为:\");for(i=0;i<=N-1;i++){ //随机产生要进行寻道访问的磁道号序列\n\ntrack[i]=rand()%(MAX+1);\n\nprintf(\"%d\",track[i]);\n\n}\n\nprintf(\"n\");\n\nprintf(\"寻道序列为:\");\n\nSSTF(rand()%N); //随机选择起点磁道\n\nprintf(\"n移动的磁道总数: %dn\",all_track);\n\nprintf(\"平均寻道总数: %0.2lf\",(double)all_track/N);return 0;\n\n}", null, "(运行结果截图)\n\n17:54:20\n\n2018-05-22\n\n内容来源于网络如有侵权请私信删除\n\n展开全文", null, "• 操作系统试验面置换算法先来先服务最短寻道优先答案参考.pdf操作系统试验面置换算法先来先服务最短寻道优先答案参考.pdf操作系统试验面置换算法先来先服务最短寻道优先答案参考.pdf操作系统试验面置换算法先来先服务...\n• //-----寻道序列。 double AverageDistance; //-----平均寻道长度 bool direction; //-----方向 true时为向外,false为向里 int BeginNum; //----开始磁道号。 int M; //----磁道数。 int N; //-----提出磁盘I/O...\n#include <stdio.h>\n#include <iostream>\n#include<stack>\n#include<queue>\n#include<cmath>\n#include<stdlib.h>\n#include<string.h>\n#include<cstring>\n#include<algorithm>\n#include<cstdio>\n#include<iomanip>\nusing namespace std;\n\n/*\n\n*/\n\nconst int MaxNumber=300;\nint TrackOrder[MaxNumber]; //----初始序列\nint MoveDistance[MaxNumber]; //----移动距离;\nint FindOrder[MaxNumber]; //-----寻道序列。\ndouble AverageDistance; //-----平均寻道长度\nbool direction; //-----方向 true时为向外,false为向里\nint BeginNum; //----开始磁道号。\nint M; //----磁道数。\nint N; //-----提出磁盘I/O申请的进程数\nint SortOrder[MaxNumber]; //----排序后的序列\nbool Finished[MaxNumber];\n\nvoid input(){\ncout<<\"请输入磁道数:\";\ncin>>M;\ncout<<\"请输入提出磁盘I/O申请的进程数:\";\ncin>>N;\ncout<<\"请依次输入要访问的磁道号:\";\nfor(int i=0;i<N;i++)\ncin>>TrackOrder[i];\nfor(int j=0;j<N;j++)\nMoveDistance[j]=0;\ncout<<\"请输入开始磁道号:\";\ncin>>BeginNum;\nfor(int k=0; k<N; k++)\nFinished[k]=false;\nfor(int l=0;l<N;l++)\nSortOrder[l]=TrackOrder[l];\n}\n\n//============FCFS,先来先服务=================================\nvoid FCFS()\n{\nint temp;\ntemp=BeginNum;\nfor(int i=0;i<N;i++)\n{\nMoveDistance[i]=abs(TrackOrder[i]-temp); //(1)请解释abs函数的作用 和此行代码的含义\ntemp=TrackOrder[i];\nFindOrder[i]=TrackOrder[i]; //(2)请解释FindOrder最终存放的数据的含义\n}\n}\n\n//========SSTF,最短寻道法=============================\n\nvoid SSTF()\n{\nint temp,n;\nint A=M;\ntemp=BeginNum;\nfor(int i=0;i<N;i++){\nfor(int j=0;j<N;j++){ //(3) 请解释该for循环的作用\nif(abs(TrackOrder[j]-temp)<A&&Finished[j]==false){\nA = abs(TrackOrder[j]-temp);\nn = j; //(4)请补充赋值号右侧的语句\n}\n}\nFinished[n] = true;\nMoveDistance[i] = A;\ntemp = TrackOrder[n];\nFindOrder[i] = TrackOrder[n];\nA = M;\n}\n}\n\n//=====================SCAN,扫描算法==========================\nvoid SCAN()\n{\nint direction,pos,temp;\ntemp=BeginNum;\nsort(SortOrder,SortOrder+N); //升序排序\ncout<<\"请选择开始方向:0向里,1向外\"; //向里为延柱面号增加的方向\ncin>>direction;\n\nfor(int i=0;i<N;i++){ // (5)请解释该for循环的作用\nif(SortOrder[i]>BeginNum){\npos = i;\nbreak;\n}\n}\nint k=0;\nif(!direction){\nfor(int i=pos;i<N;i++){\nMoveDistance[k] = abs(SortOrder[i]-temp);\ntemp = SortOrder[i];\nFindOrder[k]=SortOrder[i];\nk++;\n}\nfor(int j=pos-1;j>=0;j--){ //调转方向\nMoveDistance[k] = abs(SortOrder[j]-temp);\ntemp = SortOrder[j];\nFindOrder[k]=SortOrder[j];\nk++;\n}\n} else {\nfor(int i=pos-1;i>=0;i--){\nMoveDistance[k] = abs(SortOrder[i]-temp);\ntemp = SortOrder[i];\nFindOrder[k]=SortOrder[i];\nk++;\n}\nfor(int j=pos;j<N;j++){ //(6)请将该for循环的条件补充完整\nMoveDistance[k] = abs(SortOrder[j]-temp);\ntemp = SortOrder[j];\nFindOrder[k]=SortOrder[j];\nk++;\n}\n}\n}\n\n//=================CSCAN,循环扫描算法=======================\nvoid CSCAN()\n{\nint pos,temp,i;\ntemp=BeginNum;\nsort(SortOrder,SortOrder+N);\nfor(i=0;i<N;i++){\nif(SortOrder[i]>BeginNum){\npos = i;\nbreak;\n}\n}\nint k=0;\nfor(int j=0;j<N;j++,i++){\nif(i==N){i=0;}\nMoveDistance[k] = abs(SortOrder[i]-temp);\ntemp = SortOrder[i];\nFindOrder[k]=SortOrder[i];\nk++;\n}\n}\n\n//========计算平均寻道时间==============\nvoid Count()\n{\ndouble all=0;\n\nfor(int i=0;i<N;i++)\n{all+=MoveDistance[i];}\nall=all/N;\ncout<<\"平均寻道长度 \"<<all<<endl;\n}\n//========输出函数================\nvoid Show()\n{\ncout<<\"============从\"<<BeginNum<<\"磁道开始=================\";\ncout<<endl;\ncout<<\"被访问的下一个磁道 \"<<\" 移动距离\"<<endl;\nfor(int i=0;i<N;i++)\n{\ncout<<FindOrder[i]<<\" \"<<MoveDistance[i]<<endl;\n}\n}\n\nint main()\n{\nint flag=1;\nint s;\ninput();\nwhile(flag==1)\n{\ncout<<\"请选择寻道方式:\"<<endl;\ncout<<\"1--先来先服务\"<<endl;\ncout<<\"2--最短寻道优先\"<<endl;\ncout<<\"3--扫描\"<<endl;\ncout<<\"4--循环扫描\"<<endl;\ncin>>s;\nswitch(s){\ncase 1:FCFS();Count();Show();break;\ncase 2:SSTF();Count();Show();break;\ncase 3:SCAN();Count();Show();break;\ncase 4:CSCAN();Count();Show();break;\n}\ncout<<\"是否继续选择寻道算法?1--是;2--否\";\ncin>>flag;\n}\nsystem(\"pause\");\nreturn 0;\n}\n\n/*\n86 147 91 177 94 150 102 175 130\n*/\n\n\n展开全文", null, "• /*最短寻道时间优先SSTF(Shortest Seek Time First)算法:选择这样的进程,其要求访 问的磁道与当前磁头所在的磁道距离最近,以使每次的寻道时间最短。*/ #include <malloc.h> #include<stdio.h> #...\n• 【电梯算法】 SCAN 电梯总是保持一个方向运行,直到该方向没有请求为止,然后改变运行方向。 电梯算法(扫描算法)和电梯的运行过程类似,总是按一个方向来进行磁盘调度,直到该方向上没有未完成的磁盘请求,然后...", null, "csnote\n• ## 磁盘寻道调度算法\n\n千次阅读 2020-03-31 11:03:03\n磁盘调度在多道程序设计的计算机系统中,各个进程可能会不断提出不同的对磁盘进行读 / 写操作的请求。...最短寻道时间优先算法(SSTF), 扫描算法(SCAN), 循环扫描算法(CSCAN)   例: 假定某磁盘共有 ...\n• 实验内容:编写一个程序处理磁盘调度中寻道时间的策略。 实验目的:磁盘调度中寻道时间直接影响到数据访问的快慢,处理好磁盘寻道时间是关键。 实验题目: 采用先来先服务策略处理 采用最短寻道策略处理 实验原理 ...", null, "算法 java 操作系统\n• 写数寻道正齿音。...工作秘密用于络的网存储,计算机据管理进行保密参照。习、往硬人最最少毛泽评价青年保守东曾思想肯学,会力个社最积最有极、量中量的力是整生气。共产中国坚持领导党的,盘上小康证建设也是全面...\n• (如下图示,表示SSTF示意图) 不是最优的例子: 若干个等待访问磁盘者依次要访问的磁道为 100,142,150,155,170,300,当前磁头位于 150 号柱面,若用最短寻道时间优先磁盘调度算法,则访问序列为 [ 150 , 155 ,...\n• 最短寻道优先算法(SSTF) 算法简介:SSTF即最短寻道时间优先(ShortestSeekTimeFirst),该算法选择这样的进程,其要求访问的磁道与当前磁头所在的磁道距离最近,以使每次的寻道时间最短,但这种调度算法却不能保证...", null, "python\n• 分别采用先来先服务算法(FCFS),最短寻道时间优先算法(SSTF),扫描算法(SCAN),循环扫描算法(CSCAN),分别求总寻道长度和平均寻道长度? 解析: 移臂调度算法在于有效利用磁盘,保证磁盘的快速访问。移臂调度主要有...", null, "操作系统\n• 背景:磁盘调度 题目描述 1、对于如下给定的一组磁盘访问进行调度: 请求服务到达 A B C D E F G H I J K L M N 访问的磁道号 30 50 100 180 20 90 150 ...2、要求分别采用先来先服务、最短寻道优先以及电梯调度算法进", null, "算法 c++ 操作系统\n• 最短寻道时间优先算法(SSTF) 扫描算法(SCAN) 循环扫描算法(CSCAN) 先来先服务算法(FCFS,First Come First Served)  根据进程请求访问磁盘的先后次序进行调度。此算法的优点是公平、简单,且每个...\n• 我们最先开始HD Tune 平均读写速度、寻道时间测试的相关对比:■测试软件:HD Tune Pro v5.00HD Tune是一款硬盘性能诊断测试工具。它能检测硬盘的传输率、突发数据传输率、数据存取时间、CPU 使用率、健康状态,温度...\n• 代码 ①最短寻道时间优先算法函数SSTF() int SSTF(int *cyclist, int *cycorder, int n, int start){ //参数:cyclist[] 输入的待操作的柱面数组,cycorder[] 操作柱面的顺序结果 // n 柱面的个数,start 初始的柱面...", null, "算法 操作系统 c++\n• 学号 P71514032 专业 计算机科学与技术 姓名 实验日期 2017/12/7 教师签字 成绩 实验报告 实验名称 磁盘调度先来先服务策略 最短寻道策略 实验目的 磁盘调度中寻道时间直接影响到数据访问的快慢通过本次实验学习如何...\n• 试问: (1)如果磁盘的平均寻道时间是10ms, 那么读一个扇区的平均时间是什么? (2)在一个请求分页系统中,若将该磁盘用作交换设备,而且页面大小和扇区的大小相同。读入一个换出页的平均时间和上面计算的相同。假设如果...\n• 先来先服务(FCFS)、最短寻道时间优先(SSTf)、扫描算法(SCAN)、循环扫描算法(CSCAN)最后有运行截图。#include#include#include#includeint a; //当前磁道号int b; //磁头运动方向int c; //要访问的柱面号int num;...\n• 该算法要求访问的磁道与当前磁头所在的距离你最近,使寻道时间最短 例如给数据90,58,55,39,38,18,150,160,184 平均寻道长度为27.5 原理见汤子瀛的《操作系统》第四版 p233页 首要的是分析如何才能找到第一个最接近...", null, "c++", null, "", null, "..." ]
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https://www.calculatoratoz.com/en/ishita-goyal/652009cd-c9f1-4030-8da1-50f5802de670/profile
[ "🔍\n🔍\n\n# Calculators Created by Ishita Goyal", null, "Meerut Institute of Engineering and Technology (MIET), Meerut\n626\nFormulas Created\n3076\nFormulas Verified\n585\nAcross Categories\n\n## List of Calculators by Ishita Goyal\n\nFollowing is a combined list of all the calculators that have been created and verified by Ishita Goyal. Ishita Goyal has created 626 and verified 3076 calculators across 585 different categories till date.\nVerified Angle of Inclination when Horizontal Length of Prism is Given\nVerified Angle of Inclination when Normal Stress Component is Given\nVerified Angle of Inclination when Shear Stress Component is Given\nVerified Angle of Inclination when Vertical Stress on the Surface of Prism is Given\nVerified Angle of Inclination when Volume Per Unit Length of Prism is Given\nVerified Angle of Inclination when Weight of Soil Prism is Given\nVerified Angle of Inclination when Saturated Unit Weight is Given\nVerified Angle of Inclination when Shear Strength and Submerged Unit Weight is Given\nVerified Angle of Inclination when Submerged Unit Weight is Given\nVerified Angle of Inclination when Vertical Stress and Saturated Unit Weight is Given\nVerified Angle of Internal Friction when Factor of Safety for Cohesive Soil is Given\nVerified Angle of Internal Friction when Shear Strength of Cohesive Soil is Given\nVerified Angle of Internal Friction when Stability Number is Given\nVerified Angle of Internal Friction when Resisting Force from Coulomb's Equation is Given\nVerified Angle of Internal Friction when Resisting Moment is Given\nVerified Angle of Internal Friction when Sum of Tangential Component is Given\nVerified Apparent Velocity of Seepage\nVerified Apparent velocity of seepage when discharge and cross sectional area is given\nVerified Coefficient of Permeability when Apparent Velocity of Seepage is Given\nVerified Hydraulic Gradient when Apparent Velocity of Seepage is Given\n3 More Apparent Velocity of Seepage Calculators\nVerified Depth of Prism when Normal Stress Component is Given\nVerified Depth of Prism when Shear Stress Component is Given\nVerified Depth of Prism when Vertical Stress on the Surface of Prism is Given\nVerified Depth of Prism when Volume Per Unit Length of Prism is Given\nVerified Depth of Prism when Weight of Soil Prism is Given\nVerified Depth of Prism when Effective Normal Stress is Given\nVerified Depth of Prism when Normal Stress and Saturated Unit Weight is Given\nVerified Depth of Prism when Saturated Unit Weight is Given\nVerified Depth of Prism when Shear Stress and Saturated Unit Weight is Given\nVerified Depth of Prism when Submerged Unit Weight and Effective Normal Stress is Given\nVerified Depth of Prism when Upward Force due to Seepage Water is Given\nVerified Depth of Prism when Upward Force is Given\nVerified Depth of Prism when Vertical Stress and Saturated Unit Weight is Given\nVerified Dynamic Viscosity when Rate of Flow is Given\nVerified Dynamic Viscosity when Shear Force Resisting the Motion of Piston with Piston Velocity is Given\n4 More Dynamic Viscosity Calculators\nVerified Factor of Safety for Cohesive Soil\nVerified Factor of Safety for Cohesive Soil when Cohesion is Given\nVerified Factor of Safety with Respect to Cohesion when Critical Depth is Given\nVerified Factor of Safety with Respect to Cohesion when Mobilised Cohesion is Given\nVerified Factor of Safety with Respect to Cohesion when Stability Number is Given\nVerified Factor of Safety when Angle of Inclination and Slope angle is Given\nVerified Factor of Safety when Angle of Mobilised Friction is Given\nVerified Factor of Safety when Length of Slip Plane is Given\nVerified Factor of Safety when Mobilised Shear resistance of Soil is Given\nVerified Factor of Safety when Moment of Resistance is Given\nVerified Factor of Safety when Sum of Tangential Component is Given\nVerified Factor of Safety when Unit Cohesion is Given\nVerified Mean Velocity of Flow when Maximum Velocity is Given\nVerified Mean Velocity of Flow when Pressure Gradient is Given\n3 More Mean Velocity of Flow Calculators\nVerified Normal Stress when Member Subjected to Axial Load\nVerified Stress along Y-direction when Shear Stress when Member Subjected to Axial Load is Given\n3 More Normal Stress of members Subjected to Axial Load Calculators\nVerified Pressure Gradient when Discharge is Given\nVerified Pressure Gradient when Mean Velocity of Flows is Given\nVerified Saturated Unit Weight when Effective Normal Stress is Given\nVerified Saturated Unit Weight when Factor of Safety is Given\nVerified Saturated Unit Weight when Normal Stress Component is Given\nVerified Saturated Unit Weight when Shear Strength is Given\nVerified Saturated Unit Weight when Shear Stress Component is Given\nVerified Saturated Unit Weight when Vertical Stress on the Prism is Given\nVerified Saturated Unit Weight when Weight of Soil Prism is Given\nVerified Shear Force Acting on the Slice when Weight of Slice is Given\nVerified Shear Force in Bishop's Analysis\nVerified Shear Force in Bishop's Analysis when Factor of Safety is Given\nVerified Shear Strength when Normal Stress on the Slice is Given\nVerified Shear Stress when Shear Force in Bishop's Analysis is Given\nVerified Total Shear Force on the Slice when Radius of Arc is Given\nVerified Stability Number for Cohesive Soil\nVerified Stability Number for Cohesive Soil when Mobilised Cohesion is Given\nVerified Stability Number when Angle of Internal Friction is Given\nVerified Stability Number when Factor of Safety with Respect to Cohesion is Given\nVerified Unit Cohesion when Factor of Safety is Given\nVerified Unit Cohesion when Mobilised Shear resistance of Soil is Given\nVerified Unit Cohesion when Moment of Resistance is Given\nVerified Unit Cohesion when Resisting Force from Coulomb's Equation is Given\nVerified Unit Cohesion when Resisting Moment is Given\nVerified Unit Cohesion when Sum of Tangential Component is Given\nVerified Unit Weight of Soil when Angle of Inclination and Slope angle is Given\nVerified Unit Weight of Soil when Angle of Mobilised Friction is Given\nVerified Unit Weight of Soil when Height from Toe of Wedge to Top of Wedge is Given\nVerified Unit Weight of Soil when Safe Height from Toe to Top of Wedge is Given\nVerified Unit Weight of Soil when Weight of Wedge is Given\nVerified Velocity of Piston when Rate of Flow is Given\nVerified Velocity of Piston when Shear Stress resisting the Motion of Piston is Given\n4 More Velocity of Piston Calculators\nVerified Weight of Wedge of Soil\nVerified Weight of Wedge when Factor of Safety is Given\nVerified Weight of Wedge when Height from Toe of Wedge to Top of Wedge is Given\nVerified Weight of Wedge when Shear Strength along the Slip Plane is Given\nVerified Weight of Wedge when Shear Stress along the Slip Plane is Given\nCreated Acceleration due to Gravity when Displacement Velocity by Camp is Given\nCreated Acceleration due to Gravity when Impelling Force is Given\nCreated Acceleration due to Gravity when Settling Velocity is Given\nCreated Acceleration due to Gravity when Settling Velocity with respect to Dynamic Viscosity is Given\nCreated Acceleration due to Gravity when Settling Velocity with respect to Kinematic Viscosity is Given\nCreated Acceleration due to Gravity when Settling Velocity with respect to Specific Gravity is Given\nCreated Acceleration due to Gravity when Specific Gravity of Particle and Viscosity is Given\nVerified Acceleration Due to Gravity when Settling Velocity and Diameter is Given\nVerified Acceleration Due to Gravity when Settling Velocity for Turbulent Settling is Given\nVerified Acceleration Due to Gravity when Settling Velocity within Transition Zone is Given\nVerified Adjusted Design Value for Extreme Fiber Bending\nVerified Adjusted Design Value for Shear\n4 More Adjustment Factors for Design Values Calculators\nVerified Adjusted Design Value for Withdrawal for Drift Bolts and Pins\nVerified Adjusted Design Value for Withdrawal for Lag Screws\n7 More Adjustment of Design Values for Connections with Fasteners Calculators\nCreated Allowable Stress in Stirrup Steel when Area in Legs of a Vertical Stirrup is Given\nCreated Area Required in Legs of a Vertical Stirrup\nCreated Distance from Extreme Compression to Centroid when Area in Legs of a Vertical Stirrup is Given\nCreated Distance from Extreme Compression to Centroid when Nominal Unit Shear Stress is Given\nCreated Excess Shear when Area in Legs of a Vertical Stirrup is Given\nCreated Excess Shear when Stirrup Leg Area is Given for Group of Bars Bent up Different Distances\nCreated Excess Shear when Vertical Stirrup Leg Area is Given for Single Bar Bent at Angle α\nCreated Nominal Unit Shear Stress\nCreated Shear when Nominal Unit Shear Stress is Given\nCreated Stirrups Spacing when Area in Legs of a Vertical Stirrup is Given\nCreated Stirrups Spacing when Stirrup Leg Area is Given for Group of Bars Bent up Different Distances\nCreated Vertical Stirrup Leg Area when Group of Bars is Bent at Different Distances\nCreated Vertical Stirrup Leg Area when Single Bar is Bent at an Angle α\nVerified Allowable Stress when Area of Compression Flange is Solid and Not Less than Tension Flange\nVerified Allowable Stress when Simplifying Term is Between 0.2 and 1\nVerified Allowable Stress when Simplifying Term is Greater than 1\nVerified Maximum Fiber Stress in Bending for Laterally Supported Compact Beams and Girders\nVerified Maximum Fiber Stress in Bending for Laterally Supported Noncompact Beams and Girders\nVerified Maximum Unsupported Length of Compression Flange-1\nVerified Maximum Unsupported Length of Compression Flange-2\nVerified Simplifying Term for Allowable Stress Equations\nVerified Allowable Compressive Stress when Slenderness Ratio is Less than Cc\nVerified Allowable Compressive Stress when Slenderness Ration is Greater than Cc\nVerified Effective Length Factor\nVerified Safety Factor for Allowable Compressive Stress\nVerified Slenderness Ratio Used for Separation\nVerified Amplitude of vibrations when acceleration of particles is given\nVerified Amplitude of vibrations when velocity of particle is given\nVerified Frequency of Vibration when Acceleration of Particles is Given\nVerified Frequency of vibration when velocity of particle is given\nVerified Frequency of Vibrations Caused by Blasting\nVerified Angle of Internal Friction when Angle of Inclination and Slope angle is Given\nVerified Angle of Internal Friction when Angle of Mobilised Friction is Given\nVerified Angle of Internal Friction when Effective Normal Stress is Given\nVerified Angle of Internal Friction when Shear Strength along the Slip Plane is Given\nVerified Angle of Internal Friction when Shear Strength and Submerged Unit Weight is Given\nVerified Angle of Internal Friction when Submerged Unit Weight is Given\nVerified Angle of Internal Friction when Weight of Wedge is Given\nVerified Aquifer Constant when Difference Between Modified Drawdowns is Given\nVerified Aquifer Constant when Modified Drawdown is Given\nVerified Aquifer Constant\nVerified Aquifer Constant when Difference in Drawdowns at Two Wells is Given\nVerified Aquifer Constant when Drawdown in Well is Given\nVerified Discharge from Two Wells with Base 10\nVerified Discharge in Unconfined Aquifer\nVerified Discharge in Unconfined Aquifer with Base 10\nVerified Discharge when Length of the Strainer is Given\nVerified Discharge when Two Observation Well is Taken\nVerified Rate of Flow when Coefficient of Permeability is Given\nVerified Rate of Flow when Flow Velocity is Given\nVerified Confined Aquifer Discharge when Coefficient of Transmissibility and Depth of Water is Given\nVerified Confined Aquifer Discharge when Coefficient of Transmissibility is Given\nVerified Confined Aquifer Discharge when Depth of Water in Two Wells are Given\nVerified Confined Aquifer Discharge when Drawdown at the Well is Given\nVerified Confined Aquifer Discharge with Base 10 when Coefficient of Transmissibility is Given\nVerified Confined Aquifer Discharge with Base 10 when Drawdown at the Well is Given\nVerified Discharge in Confined Aquifer\nVerified Discharge in Confined Aquifer when Coefficient of Transmissibility is Given\nVerified Discharge in Confined Aquifer with Base 10\nVerified Discharge in Confined Aquifer with Base 10 when Coefficient of Transmissibility is Given\nVerified Aquifer Loss Coefficient\nVerified Aquifer Loss when Aquifer Loss Coefficient is Given\nVerified Aquifer Loss when Drawdown is Given\nVerified Thickness of Aquifer when Discharge in Unconfined Aquifer is Given\nVerified Thickness of Aquifer when Discharge in Unconfined Aquifer with Base 10 is Given\nVerified Thickness of Aquifer when Drawdown Value measured at the Well is Given\nVerified Aquifer Thickness from Impermeable Layer when Coefficient of Transmissibility is Given\nVerified Aquifer Thickness from Impermeable Layer when Coefficient of Transmissibility with Base 10 is Given\nVerified Aquifer Thickness from Impermeable Layer when Discharge in Confined Aquifer is Given\nVerified Aquifer Thickness from Impermeable Layer when Discharge in Confined Aquifer with Base 10 is Given\nVerified Aquifer Thickness when Confined Aquifer Discharge is Given\nVerified Aquifer Thickness when Confined Aquifer Discharge with Base 10 is Given\nVerified Aquifer Thickness when Depth of Water in Two Wells are Given\nVerified Thickness of Confined Aquifer when Discharge in Confined Aquifer is Given\nVerified Thickness of Confined Aquifer when Discharge in Confined Aquifer with Base 10 is Given\nVerified Thickness of Aquifer from Impermeable Layer when Modified Drawdown in Well 1 is Given\nVerified Thickness of Aquifer from Impermeable Layer when Modified Drawdown in Well 2 is Given\nVerified Thickness of Aquifer from Impermeable Layer when Drawdown in Well 1 is Given\nVerified Thickness of Aquifer from Impermeable Layer when Drawdown in Well 2 is Given\nVerified Angle Between Crown and Abutments when Thrust at Abutments of an Arch Dam is Given\nVerified Constant K5 when Rotation Due to Shear on a Arch Dam is Given\nVerified Deflection Due to Moments on a Arch Dam\nVerified Normal Radial Pressure at the centerline when Moment at Crown of an Arch Dam is Given\nVerified Normal Radial Pressure at the centerline when Thrust at Abutments of an Arch Dam is Given\nVerified Radius to the centerline when Thrust at Abutments of an Arch Dam is Given\n16 More Arch Dams Calculators\nVerified Area of Basin when Flood Discharge by Dicken's Formula for Northern India is Given\nVerified Area of Basin when Flood Discharge by Dicken's Formula in F.P.S Unit for Northern India is Given\nVerified Area of Basin when Flood Discharge by Dicken's Formula in F.P.S Unit is Given\nVerified Area of Basin when Flood Discharge by Dicken's Formula is Given\nVerified Area of Cross-section for Full Flow when Hydraulic Mean Depth and Discharge Ratio is Given\nVerified Area of Cross-section for Full Flow when Only Discharge Ratio is Given\nVerified Area of Cross-section for Full Flow when Only Hydraulic Mean Depth Ratio is Given\nVerified Area of Cross-section for Partial Flow when Hydraulic Mean Depth and Discharge Ratio is Given\nVerified Area of Cross-section for Partial Flow when Only Discharge Ratio is Given\nVerified Area of Cross-section for Partial Flow when Only Hydraulic Mean Depth Ratio is Given\nVerified Area of Filter when Volumetric Flowrate Applied Per Unit of Filter Area is Given\nVerified Area of Trickling Filter when Volumetric Flowrate is Given\nCreated Area of Tank when Height at Outlet Zone with respect to Area of Tank is Given\nCreated Area of Tank when Ratio of Removal with respect to Discharge is Given\nCreated Area of Tank when Vertical Falling Speed in Sedimentation Tank with respect to Area is Given\nCreated Area of the Tank when Discharge Rate with respect to Settling Velocity is Given\nCreated Cross Sectional Area of Sedimentation Tank\nCreated Cross Sectional Area when Length of Sedimentation Tank with respect to Surface Area is Given\nCreated Cross Sectional Area when Surface Area w.r.t Cross-section Area for Practical Purpose is Given\nCreated Cross Sectional Area when Surface Area with respect to Darcy Weishbach Friction Factor is Given\nCreated Cross Sectional Area when Surface Area with respect to Settling Velocity is Given\nVerified Cross-section Area of Tank when Flow Velocity is Given\nVerified Plan Area when Settling Velocity is Given\nVerified Plan Area when Settling Velocity of Particular Sized Particle is Given\nVerified Average Increment for a Decade when Future Population at End of 2 Decades is Given\nVerified Average Increment for a Decade when Future Population at End of 3 Decades is Given\nVerified Average Increment for a Decade when Future Population is Given\nVerified Future Population at the End of 2 Decades\nVerified Future Population at the End of 3 Decades\nVerified Future Population at the End of n Decades\nVerified Number of Decades when Future Population is Given\nVerified Present Population when Future Population at the End of 2 Decades is Given\nVerified Present Population when Future Population at the End of 3 Decades is Given\nVerified Present Population when Future Population at the End of n Decades is Given\nCreated Average Daily Influent Flow Rate when Hydraulic Retention Time is given\nCreated Average Daily Influent Flow Rate When Net Waste Activated Sludge is Given\nCreated Average Daily Influent Flow Rate when RAS Pumping Rate from Aeration Tank is Given\nCreated Average Daily Influent Flow Rate when Reactor Volume is known\nCreated Average Daily Influent Flow Rate when Recirculation Ratio is Given\nCreated Average daily influent flow rate when theoretical oxygen requirement is given\nVerified Allowable Bearing Pressure When Flange Thickness for H shaped Column is Given\nVerified Area Required by Base Plate\nVerified Bearing Pressure When Plate Thickness is Given\nVerified Column Depth When Plate Length is Given\nVerified Column Flange Width When Plate Length is Given\nVerified Column load for given base plate area required\nVerified Flange Thickness for H shaped Columns\nVerified Plate Length\nVerified Thickness of Plate\nVerified Thickness of Plate When Flange Thickness for H shaped Column is Given\nVerified Bazin's Constant Chezy's Constant by Bazin's Formula\nVerified Chezy's Constant by Bazin's Formula\nVerified Hydraulic Mean Depth when Chezy's Constant by Bazin's Formula is Given\nBeams (9)\nVerified Beam Buckling Factor 1\nVerified Beam Buckling Factor 2\nVerified Limiting Buckling Moment\nVerified Limiting Laterally Unbraced Length for Full Plastic Bending Capacity for I and Channel Sections\nVerified Limiting Laterally Unbraced Length for Full Plastic Bending Capacity for Solid Bar and Box Beams\nVerified Limiting Laterally Unbraced Length for Inelastic Lateral Buckling\nVerified Maximum Laterally Unbraced Length for Plastic Analysis\nVerified Maximum Laterally Unbraced Length for Plastic Analysis in Solid Bars and Box Beams\nVerified Specified Minimum Yield Stress for Web if Lr is Given\n3 More Beams Calculators\nVerified Bearing Area Factor\n2 More Bearing Area Factor Calculators\nVerified Bearing Capacity Factor Dependent on Cohesion when Effective Surcharge is Given\nVerified Bearing Capacity Factor Dependent on Cohesion when Safe Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Cohesion when Ultimate Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Surcharge when Effective Surcharge is Given\nVerified Bearing Capacity Factor Dependent on Surcharge when Safe Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Surcharge when Ultimate Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Weight when Effective Surcharge is Given\nVerified Bearing Capacity Factor Dependent on Weight when Safe Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Weight when Ultimate Bearing Capacity is Given\nVerified Depth of Footing when Effective Surcharge is Given\nVerified Depth of Footing when Net Ultimate Bearing Capacity is Given\nVerified Depth of Footing when Safe Bearing Capacity is Given\nVerified Depth of Footing when Ultimate Bearing Capacity is Given\nVerified Effective Surcharge when Depth of Footing is Given\nVerified Effective Surcharge when Factor of Safety is Given\nVerified Effective Surcharge when Ultimate Bearing Capacity is Given\nVerified Factor of Safety when Net Safe Bearing Capacity is Given\nVerified Factor of Safety when Safe Bearing Capacity is Given\nVerified Factor of Safety when Ultimate Bearing Capacity is Given\nVerified Net Safe Bearing Capacity\nVerified Net Safe Bearing Capacity when Safe Bearing Capacity is Given\nVerified Net Safe Bearing Capacity when Ultimate Bearing Capacity is Given\nVerified Net Ultimate Bearing Capacity when Depth of Footing is Given\nVerified Net Ultimate Bearing Capacity when Net Safe Bearing Capacity is Given\nVerified Net Ultimate Bearing Capacity when Safe Bearing Capacity is Given\nVerified Net Ultimate Bearing Capacity when Ultimate Bearing Capacity is Given\nVerified Safe Bearing Capacity\nVerified Safe Bearing Capacity when Net Ultimate Bearing Capacity is Given\nVerified Ultimate Bearing Capacity\nVerified Ultimate Bearing Capacity of Soil Under a Long Footing at the Surface of a Soil\nVerified Ultimate Bearing Capacity when Depth of Footing is Given\nVerified Ultimate Bearing Capacity when Factor of Safety is Given\nVerified Steel Yield Strength for milled surface when allowable Bearing Stress for d < 635 mm is Given\n5 More Bearing on Milled Surfaces Calculators\nVerified Actual Bearing Pressure Under Plate\nVerified Allowable Bearing Stress on Concrete when Full Area is Used for Support\nVerified Allowable Bearing Stress on Concrete when Less Than Full Area is Used for Support\nVerified Allowable Bending Stress When Plate Thickness is Given\nVerified Beam Reaction when Actual Bearing Pressure is Given\nVerified Beam Reaction when Area Required by Bearing Plate is Given\nVerified Bearing plate area for full concrete area support usage\nVerified Bearing plate area for less than full concrete area usage\nVerified Minimum Bearing Length of Plate When Actual Bearing Pressure is Given\nVerified Minimum Width of Plate When Actual Bearing Pressure is Given\nVerified Minimum Width of Plate When Plate Thickness is Given\nVerified Plate Thickness\nVerified Bed Slope for Full Flow when Bed Slope for Partial Flow is Given\nVerified Bed Slope for Full Flow when Velocity Ratio is Given\nVerified Bed Slope for Partial Flow\nVerified Bed Slope for Partial Flow when Velocity Ratio is Given\nVerified Ratio of Bed Slope when Velocity Ratio is Given\nVerified Maximum Bending Stress for Load Applied to Narrow Member Face\nVerified Maximum Compressive Stress for Biaxial Bending\nVerified Maximum Compressive Stress for Uniaxial Bending\nVerified Live Load Moment when Stress in Steel for Shored Members is Given\n9 More Bending Stresses Calculators\nVerified BOD5 of Influent Wastewater to Trickling Filter\nVerified BOD5 of Settled Effluent from Trickling Filter\nCreated BOD in Sewage\nCreated BOD of Industry when Population Equivalent is Given\nCreated BOD when Dilution Factor is Given\nVerified Change in Normal Stress when Overall Pore Pressure Coefficient is Given\nVerified Change in Pore Pressure when Overall Pore Pressure Coefficient is Given\nVerified Effective Angle of Internal Friction when Shear Force in Bishop's Analysis is Given\nVerified Effective Angle of Internal Friction when Shear Strength is Given\nVerified Effective Cohesion of Soil when Normal Stress on the Slice is Given\nVerified Effective Cohesion of Soil when Shear Force in Bishop's Analysis is Given\nVerified Effective Stress on the Slice\nVerified Factor of Safety Given by Bishop\nVerified Factor of Safety when Shear Force in Bishop's Analysis is Given\nVerified Height of Slice when Pore Pressure Ratio is Given\nVerified Horizontal Distance of Slice from Centre of Rotation\nVerified Length of the Arc of the Slice\nVerified Length of the Arc of the Slice when Effective Stress is Given\nVerified Length of the Arc of the Slice when Shear Force in Bishop's Analysis is Given\nVerified Normal Stress on the Slice\nVerified Normal Stress on the Slice when Shear Strength is Given\nVerified Radius of Arc when Total Shear Force on the Slice is Given\nVerified Resultant Vertical Shear Force on Section N\nVerified Resultant Vertical Shear Force on Section N+1\nVerified Total Weight of Slice when Total Shear Force on the Slice is Given\nVerified Unit weight of Soil when Pore Pressure Ratio is Given\nVerified Weight of Slice when Total Normal Force Acting on the Slice is Given\nCreated BOD Loading to Filter when Efficiency of First Filter Stage is Given\nCreated BOD Loading to Second Filter Stage when Efficiency of Second Filter Stage is given\nVerified Ratio of BOD to Ultimate BOD\nVerified Ratio of BOD to Ultimate when Oxygen Demand of Biomass is Given\nVerified Ratio of BOD to Ultimate when Oxygen Required in Aeration Tank is Given\nBOD5 (3)\nVerified BOD5 when Oxygen Required in Aeration Tank is Given\nVerified BOD5 when Ratio of BOD to Ultimate BOD is 0.68\nVerified BOD5 when Ratio of BOD to Ultimate BOD is Given\nVerified Length of Borehole when Burden is Given\nVerified Minimum Length of the Borehole in Feet\nVerified Minimum Length of the Borehole in Meter\n1 More Borehole length Calculators\nVerified Breaking Distance when Velocity is in Kmph\n5 More Braking Distance Calculators\nVerified Burden Suggested in Konya Formula\nVerified Burden Suggested in Langefors' Formula\nVerified Burden when Stemming at Top of Borehole is Given\nVerified Degree of Packing when Burden Suggested in Langefors' Formula is Given\nVerified Diameter of Borehole when Burden is Given\n1 More Burden in blasting Calculators\nVerified Drainage Area when Peak Rate of Runoff is Given\nVerified Maximum Rainfall Intensity when Peak Rate of Runoff is Given\nVerified Peak Rate of Runoff from Burkli-Ziegler Formula\nVerified Runoff Coefficient when Peak Rate of Runoff is Given\nVerified Slope of Ground Surface when Peak Rate of Runoff is Given\nVerified Population when Quantity of Water by Buston's Formula is Given\nVerified Quantity of Water by Buston's Formula\nVerified Moment of Inertia when Maximum Intensity in horizontal plane on a Buttress Dam is Given\nVerified Moment when Maximum Intensity in horizontal plane on a Buttress Dam is Given\nVerified Moment when Minimum Intensity in horizontal plane on a Buttress Dam is Given\nVerified Sectional Area of Base when Minimum Intensity in horizontal plane on a Buttress Dam is Given\n8 More Buttress Dams Calculators\nVerified Average Domestic Demand when Total Storage Capacity is Given\nVerified Average Domestic Demand when Value of McDonald Coefficient is Given\nVerified Capacity of Pump when Total Storage Capacity is Given\nVerified Capacity of Pump when Value of McDonald Coefficient is Given\nVerified Duration of Fire when Reserve Storage is Given\nVerified Fire Demand when Reserve Storage is Given\nVerified Fire Demand when Total Storage Capacity is Given\nVerified Fire Demand when Value of McDonald Coefficient is Given\nVerified McDonald Coefficient a when Total Storage Capacity is Given\nVerified McDonald Coefficient b when Total Storage Capacity is Given\nVerified Reserve Fire Pumping Capacity when Reserve Storage is Given\nVerified Reserve Storage\nVerified Total Storage Capacity of Reservoirs\nVerified Total Storage Capacity of Reservoirs when Value of McDonald Coefficient is Given\nVerified Diameter of Pipe when Dynamic Viscosity with length is Given\nVerified Dynamic Viscosity of fluids in flow\nVerified Length of Pipe when Dynamic Viscosity is Given\nVerified Length of Reservoir when Dynamic Viscosity is Given\nVerified Reservoir Area when Dynamic Viscosity is Given\nVerified Specific Weight of Liquid when Dynamic Viscosity is Given\n12 More Capillary Tube Viscometer Calculators\nVerified Catchment Area in FPS Unit when Average Value of Constant is Given\nVerified Catchment Area when Average Value of Constant is Given\nVerified Catchment Area when Discharge in FPS Unit for Area within 24 KM to 161 KM from the Coast is Given\nVerified Catchment Area when Flood Discharge by Fanning's Formula is Given\nVerified Catchment Area when Flood Discharge for Area within 24 KM from the Coast is Given\nVerified Catchment Area when Flood Discharge for Area within 24 KM to 161 KM from the Coast is Given\nVerified Catchment Area when Flood Discharge for Catchment of Former Bombay Presidency is Given\nVerified Catchment Area when Flood Discharge for Limited Area Near Hills is Given\nVerified Catchment Area when Flood Discharge for Madras Catchment in F.P.S Unit is Given\nVerified Catchment Area when Flood Discharge for Madras Catchment is Given\nVerified Catchment Area when Flood Discharge in FPS Unit by Fanning's Formula is Given\nVerified Catchment Area when Flood Discharge in FPS Unit by Inglis Formula is Given\nVerified Catchment Area when Flood Discharge in FPS Unit for Area within 24 KM from the Coast is Given\nVerified Catchment Area when Flood Discharge in FPS Unit for Limited Area Near Hills is Given\nVerified Catchment Area when Flood Discharge is Given\nVerified Bowl Radius when Centrifugal Acceleration Force is Given\nVerified Centrifugal Acceleration Force in Centrifuge\nVerified Rotational Speed of Centrifuge when Centrifugal Acceleration Force is Given\nVerified Channel Flow Time Or Gutter Flow Time\nVerified Length of the Drain when Channel Flow Time is Given\nVerified Peak Rate of Runoff from Nawab Jung Bahadur Formula\nVerified Velocity in the Drain when Channel Flow Time is Given\nVerified Coefficient of Permeability when Aquifer Loss Coefficient is Given\nVerified Discharge when Aquifer Loss is Given\nVerified Drawdown when Well Loss is Given\nVerified Radius of Influence when Aquifer Loss Coefficient is Given\nVerified Radius of Well when Aquifer Loss Coefficient is Given\nCreated Pressure at Any Time when Root Mean Square Pressure is Given\nCreated Temperature in Kelvin when Speed of Sound is Given\nCreated Wavelength of Wave\nVerified Chezy's Constant when Velocity of Flow by Chezy's Formula is Given\nVerified Hydraulic Gradient when Velocity of Flow by Chezy's Formula is Given\nVerified Hydraulic Mean Radius of Channel\nVerified Hydraulic Mean Radius of Channel when Velocity of Flow by Chezy's Formula is Given\nVerified Velocity of Flow by Chezy's Formula\nVerified Wetted Perimeter when Hydraulic Mean Radius of Channel is Given\nVerified Chow's Function when Constant dependent on Well Function is Given\nVerified Chow's Function when Drawdown is Given\nVerified Chow's Function when Well Function is Given\nVerified Angle of Sector when Top Width is Given\nVerified Diameter of Section when Hydraulic Depth is Given\nVerified Diameter of Section when Hydraulic Radius for channel is Given\nVerified Diameter of Section when Wetted Area is Given\nVerified Hydraulic Depth of circle\nVerified Hydraulic Radius when angle is given\nVerified Section Factor for circle\nVerified Wetted Area for circle\nVerified Wetted Perimeter for circle\n5 More Circular Section Calculators\nVerified Depth of flow in most efficient channel for maximum velocity\nVerified Diameter of Section when Hydraulic Radius in most efficient channel for maximum velocity is Given\nVerified Radius of Section when Depth of flow in Efficient Channel is Given\nVerified Radius of Section when Depth of flow in most efficient channel for maximum velocity is Given\nVerified Wetted Perimeter when Discharge through Channels is Given\n14 More Circular section Calculators\nVerified Area of Cross-section when Central Angle is Given\nVerified Area of Cross-section when Discharge is Given\nVerified Diameter of pipe when Area of Cross-section is Given\nVerified Diameter of the pipe when Hydraulic Mean Depth is Given\nVerified Discharge when Pipe is Running Full\nVerified Hydraulic Mean Depth when Central Angle is Given\nVerified Velocity while Running Full when Discharge is Given\nVerified Area of Cross-section while Running Partially Full when Discharge is Given\nVerified Area of Cross-section while Running Partially Full when Proportionate Area is Given\nVerified Area of Cross-section while Running Partially Full when Proportionate Discharge is Given\nVerified Discharge when Pipe Running Partially Full\nVerified Discharge when Pipe Running Partially Full when Proportionate Discharge is Given\nVerified Hydraulic Mean Depth while Running Partially Full when Only Proportionate Velocity is Given\nVerified Hydraulic Mean Depth while Running Partially Full when Proportionate Hydraulic Mean Depth is Given\nVerified Hydraulic Mean Depth while Running Partially Full when Proportionate Velocity is Given\nVerified Roughness Coefficient while Running Partially Full when Proportionate Velocity is Given\nVerified Velocity while Running Partially Full when Discharge is Given\nVerified Velocity while Running Partially Full when Proportionate Discharge is Given\nVerified Velocity while Running Partially Full when Proportionate Velocity is Given\nVerified Inflow Rate between Inter-Isochrone Area\nVerified Inter-Isochrone Area when Inflow is Given\n6 More Clark's Method for IUH Calculators\nVerified Clearance when Radius of Cylinder is Given\nVerified Dynamic Viscosity of Fluid Flow when torque is known\nVerified Dynamic Viscosity when Total Torque is Given\nVerified Height of Cylinder when Dynamic Viscosity of Fluid is Given\nVerified Radius of Inner Cylinder when Torque exerted on Outer Cylinder is Given\nVerified Speed of Outer Cylinder when Total Torque is Given\nVerified Speed of Outer Cylinder when Velocity Gradient is Given\nVerified Torque exerted on Outer Cylinder\n14 More Coaxial Cylinder Viscometers Calculators\nVerified Coefficient of Drag for Transition Settling\nVerified Coefficient of Drag for Transition Settling when Reynold Number is Given\nVerified Coefficient of Drag when Drag Force Offered by the Fluid is Given\nVerified Coefficient of Drag when Reynold Number is Given\nVerified Coefficient of Drag when Settling Velocity is Given\nVerified Coefficient of Drag when Settling Velocity of Spherical Particle is Given\nVerified Coefficient of friction when stopping sight distance is given\nVerified Coefficient of Longitudinal Friction when velocity in Breaking Distance in in Kmph is Given\n2 More Coefficient of friction Calculators\nVerified Coefficient of Permeability when Discharge and Length of the Strainer is Given\nVerified Coefficient of Permeability when Discharge from Two Wells with Base 10 is Given\nVerified Coefficient of Permeability when Discharge in Unconfined Aquifer is Given\nVerified Coefficient of Permeability when Discharge in Unconfined Aquifer with Base 10 is Given\nVerified Coefficient of Permeability when Discharge of Two Wells under Consideration is Given\nVerified Coefficient of Permeability when Flow Velocity is Given\nVerified Coefficient of Permeability when Radius of Influence is Given\nVerified Coefficient of Permeability when Rate of Flow is Given\nVerified Coefficient of Permeability when Confined Aquifer Discharge is Given\nVerified Coefficient of Permeability when Confined Aquifer Discharge with Base 10 is Given\nVerified Coefficient of Permeability when Depth of Water in Two Wells are Given\nVerified Coefficient of Permeability when Discharge in Confined Aquifer is Given\nVerified Coefficient of Permeability when Discharge in Confined Aquifer with Base 10 is Given\nVerified Coefficient of Transmissibility when Confined Aquifer Discharge is Given\nVerified Coefficient of Transmissibility when Confined Aquifer Discharge with Base 10 is Given\nVerified Coefficient of Transmissibility when Depth of Water in Two Wells are Given\nVerified Coefficient of Transmissibility when Discharge in Confined Aquifer with Base 10 is Given\nVerified Coefficient of Transmissibility when Discharge is Given\nVerified Angle of Inclination when Factor of Safety against Sliding is Given\nVerified Angle of Inclination when Shear Strength of Soil is Given\nVerified Angle of Internal Friction when Factor of Safety against Sliding is Given\nVerified Angle of Internal Friction when Normal Stress of Cohesionless Soil is Given\nVerified Angle of Internal Friction when Shear Strength of Cohesionless Soil is Given\nVerified Angle of Internal Friction when Shear Strength of Soil is Given\nVerified Factor of Safety against Sliding when Angle of Internal Friction is Given\nVerified Normal Stress when Shear Strength of Cohesionless Soil is Given\nVerified Normal Stress when Shear Stress of Cohesionless Soil is Given\nVerified Shear Strength of Cohesionless Soil\nVerified Shear Strength of Soil when Angle of Internal Friction is Given\nVerified Shear Stress of Soil when Angle of Internal Friction is Given\nVerified Shear Stress when Normal Stress of Cohesionless Soil is Given\nVerified Cohesion of Soil when Factor of Safety for Cohesive Soil is Given\nVerified Cohesion of Soil when Factor of Safety with Respect to Cohesion is Given\nVerified Cohesion of Soil when Mobilised Cohesion is Given\nVerified Cohesion when Critical Depth for Cohesive Soil is Given\nVerified Cohesion when Factor of Safety for Cohesive Soil is Given\nVerified Cohesion when Shear Strength of Cohesive Soil is Given\nVerified Cohesion when Stability Number for Cohesive Soil is Given\nVerified Critical Depth for Cohesive Soil\nVerified Critical Depth for Cohesive Soil when Factor of Safety with Respect to Cohesion is Given\nVerified Critical Depth when Stability Number for Cohesive Soil is Given\nVerified Depth at which Mobilised Cohesion is Considered when Critical Depth is Given\nVerified Depth at which Mobilised Cohesion is Considered when Stability Number is Given\nVerified Depth at which Mobilised Cohesion is Given\nVerified Depth of Prism when Factor of Safety for Cohesive Soil is Given\nVerified Mobilised Cohesion\nVerified Mobilised Cohesion when Stability Number for Cohesive Soil is Given\nVerified Normal Stress when Factor of Safety for Cohesive Soil is Given\nVerified Normal Stress when Shear Strength of Cohesive Soil is Given\nVerified Shear Strength of Cohesive Soil\nVerified Shear Stress when Factor of Safety for Cohesive Soil is Given\nVerified Unit Weight of Soil when Critical Depth for Cohesive Soil is Given\nVerified Unit Weight of Soil when Factor of Safety for Cohesive Soil is Given\nVerified Unit Weight of Soil when Factor of Safety with Respect to Cohesion is Given\nVerified Unit Weight of Soil when Mobilised Cohesion is Given\nVerified Unit Weight of Soil when Stability Number for Cohesive Soil is Given\nVerified Bearing Capacity Factor Dependent on Cohesion for Circular Footing\nVerified Bearing Capacity Factor Dependent on Cohesion for Square Footing\nVerified Bearing Capacity for Circular Footing when Value of Bearing Capacity Factor is Given\nVerified Bearing Capacity of Cohesive Soil for Circular Footing\nVerified Bearing Capacity of Cohesive Soil for Square Footing\nVerified Cohesion of Soil for Circular Footing when Value of Bearing Capacity Factor is Given\nVerified Cohesion of Soil when Bearing Capacity for Circular Footing is Given\nVerified Cohesion of Soil when Bearing Capacity for Square Footing is Given\nVerified Effective Surcharge for Circular Footing when Value of Bearing Capacity Factor is Given\nVerified Effective Surcharge when Bearing Capacity for Circular Footing is Given\nVerified Effective Surcharge when Bearing Capacity for Square Footing is Given\nVerified Length of Footing when Bearing Capacity for Square Footing is Given\nVerified Width of Footing when Bearing Capacity for Square Footing is Given\nVerified Basic Design Stress when Flat Width Ratio is between 10 and 25\nVerified Compressive Stress When Basic Design Stress is restricted to 20000 psi\nVerified Compressive Stress When Flat Width Ratio is between 10 and 25\nVerified Depth of Stiffener Lip\nVerified Flat Width Ratio for Deflection Determination\nVerified Flat Width Ratio for Safe Load Determination\nVerified Flat Width Ratio if Depth of Stiffener Lip is Provided\nVerified Flat Width Ratio if Plate Slenderness Factor is Given\nVerified Plate Slenderness Factor\nVerified Reduction Factor for Cold Form Strength Determination\n6 More Cold Formed or Light Weighted Steel Structures Calculators\nCreated Design Shear when Shear Friction Reinforcement Area is Given\nCreated Eccentricity of Shear\nCreated Reinforcement Yield Strength when Shear Friction Reinforcement Area is Given\nCreated Shear Friction Reinforcement Area\nVerified Critical Buckling Stress when Slenderness Parameter is Greater than 1.5\nVerified Critical Buckling Stress when Slenderness Parameter is Less than 1.5\nVerified Slenderness Parameter\nVerified Height when Wind Pressure is Given\n4 More Columns Calculators\nVerified Distance from extreme fiber when Young's Modulus, Radius and stress induced is given\nVerified Young's Modulus when Moment of Resistance, Moment of Inertia and Radius is given\n19 More Combined Axial and Bending Loads Calculators\nVerified Compaction Production by Compaction Equipment\nVerified Compaction Production by Compaction Equipment when Efficiency Factor is Average\nVerified Compaction Production by Compaction Equipment when Efficiency Factor is Excellent\nVerified Compaction Production by Compaction Equipment when Efficiency Factor is Poor\nVerified Efficiency Factor when Compaction Production by Compaction Equipment is Given\nVerified Number of Passes when Compaction Production by Compaction Equipment is Given\nVerified Ratio of Pay to Loose when Compaction Production by Compaction Equipment is Given\nVerified Speed of Roller when Compaction Production by Compaction Equipment is Given\nVerified Thickness of lift when Compaction Production by Compaction Equipment is Given\nVerified Width of Roller when Compaction Production by Compaction Equipment is Given\nVerified Back Bearing in Whole Circle Bearing System\nVerified Fore Bearing in Whole Circle Bearing System\nVerified Included Angle from Two Lines\nVerified Included Angle when Bearings are Measured in Opposite Side of Common Meridian\nVerified Included Angle when Bearings are Measured in Same Side of different meridian\nVerified Magnetic Bearing if True Bearing with East Declination is Given\nVerified Magnetic Bearing if True Bearing with West Declination is Given\nVerified Magnetic Declination to East\nVerified Magnetic Declination to West for Compass Surveying\nVerified True Bearing if Declination is in East\nVerified True Bearing if Declination is in West\n1 More Compass Surveying Calculators\nVerified Stress when Complementary Induced Shear Stress is Given\n5 More Complementary Induced Stress Calculators\nVerified Allowable stress in the flanges\n10 More Composite Construction Calculators\nCreated 28-Day Concrete Compressive Strength\nCreated 28-Day Concrete Compressive Strength when Water Cement Ratio is Given\nCreated Water Cement Ratio when 28-Day Concrete Compressive Strength is Given\n18 More Compression Calculators\nVerified Allowable Compressive Stress Inclined to Grain\nVerified Pressure at AC\nVerified Pressure at BC\nVerified Mean Temperature in Entire Catchment when Run-off in cm is Given\nVerified Mean Temperature in Entire Catchment when Run-off is Given\nVerified Rainfall Intensity when Runoff Coefficient is Given\nVerified Runoff Coefficient when Rainfall Intensity is Given\nVerified Run-off Coefficient when Run-off is Given\nVerified Run-off when Run-off Coefficient is Given\nVerified Bed Slope when Discharge is Given\nVerified Conveyance of Channel Section\nVerified Conveyance of Section through Manning's Formula\nVerified Hydraulic Radius of Channel Section when Conveyance of Channel Section is Given\n15 More Computation of Uniform Flow Calculators\nVerified Concentration of Solids in the Effluent when Mass of the Solids Removed is Given\nVerified Concentration of Solids in the Effluent when Sludge Age is Given\nVerified Concentration of Solids in the Returned Sludge\nVerified Concentration of Solids in the Returned Sludge when MLSS is Given\nVerified Concentration of Solids in the Returned Sludge when Sludge Age is Given\nCreated Concentration of Sludge in Return Line when RAS Pumping Rate from Aeration Tank is Given\nCreated Concentration of Sludge in Return Line when Wasting Rate from Return Line is Given\nCreated Concentration of Solids in Effluent When Wasting Rate from Return Line is Given\nVerified Confidence interval of variate bounded by X2\nVerified Equation for confidence interval of variate bounded by x2\n6 More Confidence Limits Calculators\nVerified Constant Depending upon Soil at Base of Well\nVerified Constant Depending upon Soil at Base of Well when Clay Soil is Given\nVerified Constant Depending upon Soil at Base of Well when Discharge from a Well is Given\nVerified Constant Depending upon Soil at Base of Well when Fine Sand is Given\nVerified Constant Depending upon Soil at Base of Well when Specific Capacity is Given\nVerified Constant Depending upon Soil at Base of Well with Base 10\nVerified Constant Depression Head when Discharge and Time in Hours is Given\nVerified Constant Depression Head when Discharge from a Well is Given\nVerified Mean Velocity of Water Percolating into the Well\nVerified Percolation Intensity Coefficient when Discharge is Given\nVerified Time in Hours when Specific Capacity of an Open Well is Given\nVerified Time in Hours when Specific Capacity of an Open Well with Base 10 is Given\nCreated Acceleration due to Gravity when Area for Siphon Throat is given\nCreated Area for Siphon Throat\nCreated Coefficient of Discharge when Area for Siphon Throat is given\nCreated Depth of Flow over Weir when Flow Diversion is given\nCreated Discharge when Area for Siphon Throat is given\nCreated Flow Diversion for Side Weir\nCreated Head when Area for Siphon Throat is given\nCreated Length of Weir when Flow Diversion is given\nVerified Bed Slope of the Sewer when Flow Velocity by Crimp and Burge's Formula is Given\nVerified Flow Velocity by Crimp and Burge's Formula\nVerified Hydraulic Mean Depth when Flow Velocity by Crimp and Burge's Formula is Given\nVerified Critical Depth in the Control Section\nVerified Critical Depth when Discharge Through the Control Section is Given\nVerified Critical Depth when Total Critical Energy is Given\nVerified Critical Depth when Total Energy at Critical Point is Given\n3 More Critical Depth Calculators\nVerified Critical Depth for Parabolic Channel\nVerified Critical Depth for Triangular Channel\nVerified Critical Depth of Flow when Critical Energy for Parabolic Channel is Given\nVerified Critical Depth when Critical Energy for Rectangular Channel is Given\nVerified Critical Energy for Parabolic Channel\nVerified Critical Energy for Rectangular Channel\nVerified Critical Section Factor\nVerified Discharge when Critical Depth for Parabolic Channel is Given\nVerified Discharge when Critical Section Factor is Given\nVerified Side Slope of Channel when Critical Depth for Parabolic Channel is Given\nVerified Side Slope of Channel when Critical Depth for Triangular Channel is Given\n5 More Critical Flow And Its Computation Calculators\nCreated Critical Oxygen Deficit\nCreated Critical Oxygen Deficit in First Stage Equation\nCreated Critical Oxygen Deficit when Self Purification Constant is Given\nCreated Critical Time\nCreated Critical Time in terms of Self Purification Constant when Critical Oxygen Deficit is Given\nCreated Critical Time in terms of Self Purification Factor\nCreated Critical Time when Critical Oxygen Deficit is Given\nCreated Critical Time when Log value of Critical Oxygen Deficit is Given\nCreated Critical Time when Self Purification Constant is Given\nVerified Critical Velocity when Acceleration Due to Gravity is Given\nVerified Critical Velocity when Critical Depth in the Control Section is Given\nVerified Critical Velocity when Depth of Section is Given\nVerified Critical Velocity when Discharge Through the Control Section is Given\nVerified Critical Velocity when Head Loss is Given\nVerified Critical Velocity when Total Energy at Critical Point is Given\n2 More Critical Velocity Calculators\nVerified Cross-sectional Area of Flow into the well when Discharge from an Open Well is Given\nVerified Cross-sectional Area of Flow into the well when Discharge is Given\nVerified Cross-sectional Area of Well when Specific Capacity for Clay Soil is Given\nVerified Cross-sectional Area of Well when Specific Capacity for Coarse Sand is Given\nVerified Cross-sectional Area of Well when Specific Capacity for Fine Sand is Given\nVerified Cross-sectional Area of Well when Specific Capacity is Given\nVerified Cross-sectional Area of Well when Clay Soil is Given\nVerified Cross-sectional Area of Well when Constant Depending upon Soil at Base is Given\nVerified Cross-sectional Area of Well when Constant Depending upon Soil at Base with Base 10 is Given\nVerified Cross-sectional Area of well when Discharge and Constant Depression Head is Given\nVerified Cross-sectional Area of Well when Discharge from a Well is Given\nVerified Cross-sectional Area of Well when Fine Sand is Given\nVerified Bed Slope when Head on Entrance using Mannings formula is Given\nVerified Bed Slope when Velocity of Flow through Mannings Formulas in Culverts is Given\nVerified Entrance Loss Coefficient when Head on Entrance using Mannings formula is Given\nVerified Head on Entrance measured from Bottom of Culvert using Mannings formula\nVerified Hydraulic Radius when Head on Entrance using Mannings formula is Given\nVerified Normal Depth of Flow when Head on Entrance measured from Bottom using Mannings formula is Given\nVerified Roughness Coefficient when Head on Entrance using Mannings formula is Given\nVerified Roughness Coefficient when Velocity of Flow through Mannings Formulas in Culverts is Given\nVerified Velocity of Flow through Mannings Formulas in Culverts\n5 More Culverts on Subcritical Slopes Calculators\nCurves (3)\nVerified Deflection Angle when Length of Curve is Given\nVerified Length of Curve\nVerified Radius of Curve when Length is Given\n9 More Curves Calculators\nVerified D.O Saturation for Sewage when Correction Factor is 0.8\nVerified D.O Saturation for Sewage when Correction Factor is 0.85\nVerified D.O Saturation for Sewage when Oxygen Transfer Capacity is Given\nVerified Area when Discharge under Dams on Soft or Porous Foundations is Given\nVerified Depth below Surface when Neutral stress per unit area for Dams on Soft Foundations is Given\nVerified Equipotential Lines when Hydraulic gradient per unit head for Dams on Soft Foundations is Given\nVerified Length of Conduit when Neutral stress per unit area for Dams on Soft Foundations is Given\nVerified New Material Coefficient C2 for Dams on Soft or Porous Foundations\nVerified Number of Beds when Hydraulic gradient per unit head for Dams on Soft Foundations is Given\nVerified Permeability when Hydraulic gradient per unit head for Dams on Soft Foundations is Given\n17 More Dams on Soft or Porous Foundations Calculators\nVerified Shear Velocity\n20 More Darcy – Weisbach Equation Calculators\nVerified Average Velocity of Flow when Head Loss is Given\nVerified Average Velocity of Flow when Internal Radius of Pipe is Given\nVerified Darcy's Coefficient of Friction when Head Loss is Given\nVerified Darcy's Coefficient of Friction when Internal Radius of Pipe is Given\nVerified Head Loss due to Friction by Darcy Weisbach Equation\nVerified Head Loss due to Friction when Internal Radius of Pipe is Given\nVerified Internal Diameter of Pipe when Head Loss is Given\nVerified Length of Pipe When Head Loss due to Friction is Given\nVerified Length of Pipe When Internal Radius of Pipe is Given\nCreated Darcy Weishbach Friction Factor when Length of Tank with respect to Darcy Weishbach Factor is Given\nCreated Darcy Weishbach Friction Factor when Surface Area with respect to Darcy Weishbach Factor is Given\nCreated Darcy-Weishbach Friction Factor when Displacement Velocity by Camp is Given\nCreated Darcy-Weishbach Friction Factor when Displacement Velocity for Fine Particles is Given\nVerified Diameter of Piston when Pressure reduction over the Length of Piston is Given\nVerified Diameter of Piston when Vertical Upward Force on Piston is Given\nVerified Length of Piston when Pressure Drop over the Piston is Given\nVerified Length of Piston when Shear Force Resisting the Motion of Piston with Piston Velocity is Given\nVerified Pressure Drop over the Length of Piston when Vertical Upward Force on Piston is Given\nVerified Shear Force Resisting the Motion of Piston when Piston Velocity is Given\nVerified Shear Force when Total Force is Given\nVerified Shear Stress when Shear Force Resisting the Motion of Piston is Given\nVerified Vertical Upward Force on Piston\n15 More Dash - Pot Mechanism Calculators\nCreated Air content w.r.t degree of saturation\nVerified Buoyant Unit Weight of Soil with Saturation 100 Percent\nCreated Degree of saturation of soil sample\nCreated Degree of saturation when air content w.r.t degree of saturation is given\nCreated Degree of saturation when percentage air voids in terms of void ratio is given\nCreated Degree of saturation when void ratio in terms of specific gravity is given\nCreated Volume of voids when degree of saturation of soil sample is given\nCreated Volume of water when degree of saturation of soil sample is given\nCreated Mass Density of Fluid when Frictional Drag is Given\nCreated Mass Density of Fluid when Impelling Force is Given\nCreated Mass Density of Fluid when Particle Reynold's Number is Given\nCreated Mass Density of Fluid when Settling Velocity is Given\nCreated Mass Density of Fluid when Settling Velocity with respect to Dynamic Viscosity is Given\nCreated Mass Density of Particle when Impelling Force is Given\nCreated Mass Density of Particle when Settling Velocity is Given\nCreated Mass Density of Particle when Settling Velocity with respect to Dynamic Viscosity is Given\nCreated Bulk density of soil\nCreated Density of solids\nCreated Density of water when submerged density w.r.t saturated density is given\nCreated Dry density of soil\nCreated Mass of saturated sample when saturated density of soil is given\nCreated Mass of solids when density of solids is given\nCreated Mass of solids when dry density of soil is given\nCreated Saturated density of soil\nCreated Saturated density when submerged density w.r.t saturated density is given\nCreated Submerged density of soil\nCreated Submerged density w.r.t saturated density\nCreated Submerged mass of soil when submerged density of soil is given\nCreated Total mass of soil when bulk density of soil is given\nCreated Total volume of soil when bulk density of soil is given\nCreated Total volume of soil when dry density of soil is given\nCreated Total volume when saturated density of soil is given\nCreated Total volume when submerged density of soil is given\nVerified Density of Water when Coefficient of Drag is Given\nVerified Density of Water when Drag Force Offered by the Fluid is Given\nVerified Density of Water when Kinematic Viscosity of Water is Given\nCreated Deoxygenation Coefficient when Self Purification Constant is Given\nCreated Deoxygenation Constant in terms of Self Purification Constant when Critical Oxygen Deficit is Given\nCreated Deoxygenation Constant when Critical Time in terms of Self Purification Factor is Given\nCreated Deoxygenation Constant when Log value of Critical Oxygen Deficit is Given\nCreated Deoxygenation Constant\nCreated De-oxygenation Constant\nCreated Deoxygenation Constant at 20°C when Deoxygenation Constant at Temperature T is Given\nCreated Deoxygenation Constant at Temperature T\nCreated Deoxygenation Constant using Best Fit Line\nCreated De-oxygenation Constant when Organic Matter Present at the Start of BOD is Given\nCreated Deoxygenation Constant when Organic Matter Present at the Start of BOD using Best Fit Line is Given\nCreated De-oxygenation Constant when Total Amount of Organic Matter Oxidised is Given\nVerified Constant Depression Head when Specific Capacity for Clay Soil is Given\nVerified Constant Depression Head when Specific Capacity for Coarse Sand is Given\nVerified Constant Depression Head when Specific Capacity for Fine Sand is Given\nVerified Constant Depression Head when Specific Capacity is Given\nVerified Depression Head when Discharge is Given\nVerified Depression Head in the Well at a Time T after Pumping Stopped\nVerified Depression Head in the Well at a Time T after Pumping Stopped and Clay Soil is Present\nVerified Depression Head in the Well at a Time T after Pumping Stopped and Coarse Sand is Present\nVerified Depression Head in the Well at a Time T after Pumping Stopped and Constant is Given\nVerified Depression Head in the Well at a Time T after Pumping Stopped and Constant with Base 10 is Given\nVerified Depression Head in the Well at a Time T after Pumping Stopped and Fine Sand is Present\nVerified Depression Head in the Well at a Time T after Pumping Stopped when Discharge and Time is Given\nVerified Depression Head in the Well at a Time T after Pumping Stopped with Base 10\nVerified Depression Head in the Well at a Time T after Pumping Stopped with Base 10 and Clay soil is Present\nVerified Depression Head in the Well at a Time T after Pumping Stopped with Base 10 and Coarse Sand is Given\nVerified Depression Head in the Well at a Time T after Pumping Stopped with Base 10 and Fine Sand is Present\nVerified Depression Head in the Well when Pumping Stopped\nVerified Depression Head in the Well when Pumping Stopped and Clay Soil is Present\nVerified Depression Head in the Well when Pumping Stopped and Coarse Sand is Present\nVerified Depression Head in the Well when Pumping Stopped and Constant is Given\nVerified Depression Head in the Well when Pumping Stopped and Constant with Base 10 is Given\nVerified Depression Head in the Well when Pumping Stopped and Fine Sand is Present\nVerified Depression Head in the Well when Pumping Stopped with Base 10\nVerified Depression Head in the Well when Pumping Stopped with Base 10 and Clay soil is Present\nVerified Depression Head in the Well when Pumping Stopped with Base 10 and Coarse Sand is Present\nVerified Depression Head in the Well when Pumping Stopped with Base 10 and Fine Sand is Present\nVerified Depression Head in the Well when Pumping Stopped with Discharge and Time in Hours is Given\nVerified Depth when Critical Velocity is Given\nVerified Depth when Discharge for Rectangular Channel Section is given\n2 More Depth of Channel Calculators\nVerified Depth of Actual Filter when Treatability Constant is Given\nVerified Depth of Filter when Treatability Constant is Given\nVerified Depth of Tank when Detention Time is Given\nVerified Depth of Tank when Flow Velocity is Given\nVerified Depth of tank when Height to Length Ratio is Given\nVerified Height of Tank when Detention Time for a Circular Tank is Given\nVerified Height of Tank when Flow Velocity is Given\nVerified Depth of Water in Well 1 when Drawdown in Well 1 is Given\nVerified Depth of Water in Well 2 when Drawdown in Well 2 is Given\nVerified Radial Distance from Well 1 when Aquifer Constant is Given\nVerified Radial Distance from Well 2 when Aquifer Constant is Given\nVerified Depth of Water at Point 1 when Discharge from Two Wells with Base 10 is Given\nVerified Depth of Water at Point 1 when Discharge of Two Wells under Consideration is Given\nVerified Depth of Water at Point 2 when Discharge from Two Wells with Base 10 is Given\nVerified Depth of Water at Point 2 when Discharge of Two Wells under Consideration is Given\nVerified Depth of Water in the Well when Discharge in Unconfined Aquifer is Given\nVerified Depth of Water in the Well when Discharge in Unconfined Aquifer with Base 10 is Given\nVerified Depth of Water in Well when Drawdown Value measured at the Well is Given\nVerified Depth of Water in 1st Well when Coefficient of Transmissibility is Given\nVerified Depth of Water in 1st Well when Confined Aquifer Discharge is Given\nVerified Depth of Water in 2nd Well when Coefficient of Transmissibility is Given\nVerified Depth of Water in 2nd Well when Confined Aquifer Discharge is Given\nVerified Depth of Water in Well when Coefficient of Transmissibility is Given\nVerified Depth of Water in Well when Coefficient of Transmissibility with Base 10 is Given\nVerified Depth of Water in Well when Discharge in Confined Aquifer is Given\nVerified Depth of Water in Well when Discharge in Confined Aquifer with Base 10 is Given\nVerified Average Daily Consumption of Chlorine\nVerified Average Flow when Average Daily Consumption of Chlorine is Given\nVerified Average Flow when Capacity of the Chlorinator at Peak Flow is Given\nVerified Capacity of the Chlorinator at Peak Flow\nVerified Dosage Used when Average Daily Consumption of Chlorine is Given\nVerified Dosage Used when Capacity of the Chlorinator at Peak Flow is Given\nVerified Number of Coliform Organisms at Any Initial Time\nVerified Number of Coliform Organisms at Any Particular Time\nVerified Peaking Factor when Capacity of the Chlorinator at Peak Flow is Given\nVerified Residence Time when Number of Coliform Organisms at Any Particular Time is Given\nVerified Total Chlorine Residual at Any Particular Time\nVerified Average Daily Load when Peak Discharge in Circular Settling Tanks is Given\nVerified Design Surface Loading Rate when Surface Area of Circular Settling Tank is Given\nVerified Influent Flow Rate when Return Activated Sludge Flow Rate is Given\nVerified Maximum Solids Entering the Clarifier\nVerified Mixed Liquor Suspended Solids in Aeration Tank when Maximum Solids is Given\nVerified Peak Discharge in Circular Settling Tanks\nVerified Peak Discharge when Maximum Solids Entering the Clarifier is Given\nVerified Peak Discharge when Surface Area of Circular Settling Tank is Given\nVerified Peaking Factor when Peak Discharge in Circular Settling Tanks is Given\nVerified Return Activated Sludge Flow Rate\nVerified Return Activated Sludge Flow Rate when Maximum Solids Entering the Clarifier is Given\nVerified Surface Area of Circular Settling Tank\nVerified Total Settling Tank Surface Area when Actual Solid Loading Rate is Given\nCreated Recirculation Ratio\nCreated Sludge Concentration Using Wasting Rate from Return Line when Solid Concentration in Effluent is Low\nVerified Dewatered Sludge or Cake Discharge Rate\nVerified Percent Reduction in Sludge Volume\nVerified Solids Recovery when Dewatered Sludge Discharge Rate is Given\n1 More Design of a Solid Bowl Centrifuge for Sludge Dewatering Calculators\nVerified Air supply required in Grit Chamber\nVerified Assumed Grit Quantity when Volume of Aerated Grit Chamber is Given\nVerified Chamber Length when Air supply required is Given\nVerified Chosen Air Supply when Air supply required is Given\nVerified Chosen Depth when Width of Grit Chamber is Given\nVerified Depth when Length of Grit Chamber is Given\nVerified Detention Time when Volume of Each Grit Chamber is Given\nVerified Length of Grit Chamber\nVerified Peak Flow Rate when Volume of Each Grit Chamber is Given\nVerified Selected Width-Ratio when Width of Grit Chamber is Given\nVerified Volume Flow Rate Handled when Volume of Aerated Grit Chamber is Given\nVerified Volume of Aerated Grit Chamber\nVerified Volume of Each Grit Chamber\nVerified Volume when Length of Grit Chamber is Given\nVerified Width of Grit Chamber\nVerified Width when Length of Grit Chamber is Given\nVerified Density of air when Volume of Air Required is Given\nVerified Density of Water when Volume of Digested Sludge is Given\nVerified Digester Total Suspended Solids when Volume of Aerobic Digester is Given\nVerified Influent Average Flow Rate when Volume of Aerobic Digester is Given\nVerified Influent Suspended Solids when Volume of Aerobic Digester is Given\nVerified Initial Weight of Oxygen when Weight of Oxygen Required is Given\nVerified Percent Solids when Volume of Digested Sludge is Given\nVerified Reaction Rate Constant when Volume of Aerobic Digester is Given\nVerified Solids Retention Time when Volume of Aerobic Digester is Given\nVerified Specific Gravity of Digested Sludge when Volume of Digested Sludge is Given\nVerified Volatile Fraction of Digester Suspended Solids when Volume of Aerobic Digester is Given\nVerified Volume of Aerobic Digester\nVerified Volume of Air Required at Standard Conditions\nVerified Volume of Digested Sludge\nVerified VSS as Mass Flow Rate when Weight of Oxygen Required is Given\nVerified Weight of Oxygen Required to Destroy the VSS\nVerified Weight of Oxygen Required when Volume of Air Required is Given\nVerified Weight of Sludge when Volume of Digested Sludge is Given\nVerified Weight of VSS when Weight of Oxygen Required is Given\nVerified BOD In when Percent Stabilization is Given\nVerified BOD In when Quantity of Volatile Solids is Given\nVerified BOD In when Volume of Methane Gas Produced is Given\nVerified BOD Out when Percent Stabilization is Given\nVerified BOD Out when Quantity of Volatile Solids is Given\nVerified BOD Out when Volume of Methane Gas Produced is Given\nVerified BOD Per Day when Volumetric Loading in an Anaerobic Digester is Given\nVerified Endogenous Coefficient when Quantity of Volatile Solids is Given\nVerified Hydraulic Retention Time when Volume Required for an Anaerobic Digester is Given\nVerified Influent Sludge Flow Rate when Volume Required for an Anaerobic Digester is Given\nVerified Mean Cell Residence Time when Quantity of Volatile Solids is Given\nVerified Percent Stabilization\nVerified Quantity of Volatile Solids Produced Each Day\nVerified Volatile Solids Produced when Percent Stabilization is Given\nVerified Volatile Solids Produced when Volume of Methane Gas Produced is Given\nVerified Volume of Methane Gas Produced at Standard Conditions\nVerified Volume Required for an Anaerobic Digester\nVerified Volumetric Flow Rate when Volumetric Loading in an Anaerobic Digester is Given\nVerified Yield Coefficient when Quantity of Volatile Solids is Given\nVerified Depth of Tank when Volume of Conical Humus Tank is Given\nVerified Depth of the Tank when Top Area is Given\nVerified Diameter of Tank when Volume of Conical Humus Tank is Given\nVerified Top Area of Tank when Volume of Conical Humus Tank is Given\nVerified Volume of Conical Humus Tank\nVerified Volume of Conical Humus Tank when Top Area is Given\nVerified Height to Length Ratio when Settling Velocity is Given\nVerified Length to Depth Ratio when Settling Velocity is Given\nVerified Overflow Rate when Discharge is Given\nVerified Rate of Flow when Detention Time is Given\nVerified Volume of Tank when Detention Time is Given\nVerified Coefficient of Discharge when Distance in X Direction from Center of Weir is Given\nVerified Distance in X Direction from Center of Weir\nVerified Distance in Y Direction from Crest of Weir\nVerified Half Width of Bottom Portion of the Weir\nVerified Horizontal Flow Velocity when Distance in X Direction from Center of Weir is Given\nVerified Horizontal Flow Velocity when Half Width of Bottom Portion of the Weir is Given\nVerified Width of Channel when Distance in X Direction from Center of Weir is Given\nVerified Width of Channel when Half Width of Bottom Portion of the Weir is Given\nVerified Number of Threads in Engagement With Nut given Unit Bearing Pressure\n21 More Design of Screw and Nut Calculators\nVerified Depth of Drains for Drains upto 15 Cumecs\nVerified Width of Drain when Depth of Drains for Drains upto 15 Cumecs is Given\nCreated Axial Load at Balanced Condition\nCreated Axial Load for Spiral Columns\nCreated Axial Load for Tied Columns\nCreated Axial Moment at Balanced Condition\nCreated Reinforcement Yield Strength when Axial Load for Tied Columns is Given\nCreated Tension Reinforcement Area when Axial Load for Tied Columns is Given\n7 More Design Under Axial Compression with Biaxial Bending Calculators\nVerified Detention Time for a Circular Tank\nVerified Detention Time for a Rectangular Tank\nVerified Detention Time when Discharge is Given\nCreated Detention Period when Falling Speed of Smaller Particle is Given\nCreated Detention Time in Sedimentation Tank\nCreated Detention Time when Displacement Efficiency of Sedimentation Tank is Given\nCreated Detention Time with respect to Discharge Rate\nVerified Constant Factor when Population at Last Census is Given\nVerified Earlier Census Date when Constant Factor is Given\nVerified Earlier Census Date when Proportionality Factor is Given\nVerified Last Census Date when Constant Factor is Given\nVerified Last Census Date when Proportionality Factor is Given\nVerified Population at Earlier Census\nVerified Population at Last Census\nVerified Population at Last Census when Proportionality Factor is Given\nVerified Proportionality Factor when Population at Last Census is Given\nCreated Average Rainfall Rate when Stormwater is given\nCreated Coefficient of Runoff when Stormwater is given\nCreated Drainage Area when Stormwater is given\nCreated Stormwater Flow\nVerified Diameter of the Grain when Friction Factor is Given\nVerified Diameter of the Grain when Rugosity Coefficient is Given\nVerified Diameter of the Grain when Self Cleaning Invert Slope is Given\nVerified Diameter of the Grain when Self Cleansing velocity is Given\nVerified Diameter of Particle Settling Velocity for Inorganic Solids is Given\nVerified Diameter of Particle when Settling Velocity and Coefficient of Drag is Given\nVerified Diameter of Particle when Settling Velocity for Modified Hazen's Equation is Given\nVerified Diameter of Particle when Settling Velocity for Organic Matter is Given\nVerified Diameter of Particle when Settling Velocity for Turbulent Settling is Given\nVerified Diameter of Particle when Settling Velocity within Transition Zone is Given\nVerified Diameter of the Particle when Coefficient of Drag is Given\nVerified Diameter of the Particle when Reynold Number is Given\nVerified Diameter of the Particle when Settling Velocity of Spherical Particle is Given\nCreated Diameter of Particle when Particle Reynold's Number is Given\nCreated Diameter of Particle when Settling Velocity is Given\nCreated Diameter of Particle when Settling Velocity with respect to Specific Gravity is Given\nCreated Diameter of Particle when Volume of Particle is Given\nCreated Diameter when Displacement Velocity by Camp is Given\nCreated Diameter when Settling Velocity at 10°C is Given\nCreated Diameter when Settling Velocity in terms of °C for d> 0.1mm is Given\nCreated Diameter when Settling Velocity in terms of °C is Given\nCreated Diameter when Settling Velocity in terms of °F for d> 0.1mm is Given\nCreated Diameter when Settling Velocity in terms of °F is Given\nCreated Diameter when Settling Velocity with respect to Dynamic Viscosity is Given\nCreated Diameter when Settling Velocity with respect to Kinematic Viscosity is Given\nCreated Diameter when Specific Gravity of Particle and Viscosity is Given\nVerified Catchment Area when Peak Rate of Runoff is Given\nVerified Factors Dependent Constant when Peak Rate of Runoff is Given\nVerified Peak Rate of Runoff from Dicken's Formula\nVerified Confined Aquifer Discharge when Aquifer Constant is Given\nVerified Discharge when Aquifer Constant is Given\nVerified Discharge when Difference in Drawdowns at Two Wells is Given\nVerified Discharge of Full Flow when Hydraulic Mean Depth for Partial flow is Given\nVerified Discharge of Full Flow when Hydraulic Mean Depth Ratio is Given\nVerified Discharge Ratio when Hydraulic Mean Depth for Full Flow is Given\nVerified Discharge Ratio when Hydraulic Mean Depth Ratio is Given\nVerified Self Cleansing Discharge when Hydraulic Mean Depth for Full Flow is Given\nVerified Self Cleansing Discharge when Hydraulic Mean Depth Ratio is Given\nVerified Discharge from a Well when Specific Capacity for Clay Soil is Given\nVerified Discharge from a Well when Specific Capacity for Coarse Sand is Given\nVerified Discharge from a Well when Specific Capacity for Fine Sand is Given\nVerified Discharge from a Well when Specific Capacity is Given\nVerified Discharge from an Open Well when Depression Head is Given\nVerified Discharge from an Open Well when Mean Velocity of Water Percolating is Given\nVerified Discharge Coefficient when Discharge is Given\nVerified Discharge for Rectangular Channel Section\nVerified Discharge Passing Through the Parshall Flume when Discharge Coefficient is Given\nVerified Discharge Through the Control Section\n3 More Discharge in Channel Calculators\nVerified Discharge Entering the Basin when Cross-section Area of Tank is Given\nVerified Discharge Entering the Basin when Flow Velocity is Given\nVerified Discharge Entering the Basin when Settling Velocity is Given\nVerified Discharge when Detention Time for a Circular Tank is Given\nVerified Discharge when Detention Time for a Rectangular Tank is Given\nVerified Discharge when Height to Length Ratio is Given\nVerified Discharge when Overflow Rate is Given\nVerified Discharge when Plan Area is Given\nVerified Discharge when Plan Area is Given for Particular Sized Particle\nVerified Discharge when Settling Velocity of Particular Sized Particle is Given\nVerified Discharge when Difference Between Modified Drawdowns is Given\nVerified Unconfined Aquifer Discharge when Aquifer Constant is Given\nVerified Discharge in Well under Constant Depression Head\nVerified Discharge in Well when Constant Depression Head and Area of Well is Given\nVerified Discharge when Drawdown is Given\nVerified Discharge when Formation Constant T is Given\nVerified Discharge when Time at 1st and 2nd Instance is Given\nCreated Discharge Rate when Detention Time in Sedimentation Tank is Given\nCreated Discharge Rate when Detention Time is Given\nCreated Discharge Rate when Height at Outlet Zone with respect to Area of Tank is Given\nCreated Discharge Rate when Height at Outlet Zone with respect to Discharge is Given\nCreated Discharge Rate when Ratio of Removal with respect to Discharge is Given\nCreated Discharge Rate when Vertical Falling Speed in Sedimentation Tank is Given\nCreated Discharge Rate when Vertical Falling Speed in Sedimentation Tank with respect to Area is Given\nCreated Discharge Rate with respect to Settling Velocity\nCreated Displacement Efficiency of Sedimentation Tank\nCreated Flow through Period when Displacement Efficiency of Sedimentation Tank is Given\nCreated Beta Constant when Displacement Velocity by Camp is Given\nCreated Displacement Velocity by Camp\nCreated Displacement Velocity for Fine Particles\nCreated Displacement Velocity in terms of Settling Velocity\nCreated Displacement Velocity when f=0.025\nVerified Maximum Rate of Effluent Application of Leaching Surface\nVerified Maximum Rate of Effluent Application of Leaching Surface by BIS\nVerified Standard Percolation Rate when Maximum Rate of Effluent Application by BIS is Given\nVerified Standard Percolation Rate when Maximum Rate of Effluent Application is Given\nCreated Acceleration due to Gravity when Inlet Capacity for Flow Depth more than 1ft 5in is given\nCreated Area of Opening when Inlet Capacity for Flow Depth more than 1ft 5in is given\nVerified Depression in Curb Inlet when Runoff Quantity with Full Gutter flow is given\nCreated Depth of Flow when Inlet Capacity for Flow Depth more than 1ft 5in is given\nCreated Inlet Capacity for Flow Depth more than 1ft 5in\n6 More Disposing of storm water Calculators\nCreated Actual DO\nCreated Mixing Concentration\nCreated River Stream Concentration\nCreated River Stream Flow Rate\nCreated Saturation DO\nCreated Sewage Concentration\nCreated Sewage Flow Rate\nCreated DO Consumed by Diluted Sample when BOD in Sewage is Given\nCreated DO Consumed by Diluted Sample when Dilution Factor is Given\nVerified Dosing Rate\nVerified Dosing Rate when Rotational Speed is Given\nCreated Drag Coefficient when Frictional Drag is Given\nCreated Drag Coefficient when Settling Velocity is Given\nCreated Drag Coefficient when Settling Velocity with respect to Specific Gravity is Given\nCreated Drag Coefficient with respect to Reynold's Number\nCreated General form of Drag Coefficient\nVerified Angle of Inclination when Drag Force is Given\nVerified Bed Slope of the Channel when Drag Force is Given\nVerified Drag Force Exerted by Flowing Water\nVerified Drag Force or Intensity of Tractive force\nVerified Rugosity Coefficient when Drag Force is Given\nVerified Thickness of Sediment when Drag Force is Given\nVerified Unit weight of Water when Drag Force is Given\nVerified Area of Particle when Drag Force Offered by the Fluid is Given\nVerified Drag Force Offered by the Fluid\nVerified Velocity of Fall when Drag Force Offered by the Fluid is Given\nCreated Drag Force as per Stokes Law\nCreated Frictional Drag\nCreated Projected Area when Frictional Drag is Given\nCreated The Diameter when Drag Force as per Stokes Law is Given\nVerified Change in Drawdown when Chow's Function is Given\nVerified Change in Drawdown when Formation Constant T is Given\nVerified Change in Drawdown when Time at 1st and 2nd Instance is Given\nVerified Drawdown when Chow's Function is Given\nVerified Drawdown when Well Function is Given\nVerified Drawdown at the Well when Coefficient of Transmissibility is Given\nVerified Drawdown at the Well when Coefficient of Transmissibility with Base 10 is Given\nVerified Drawdown at the Well when Confined Aquifer Discharge is Given\nVerified Drawdown at the Well when Confined Aquifer Discharge with Base 10 is Given\nVerified Drawdown at the Well when Radius of Influence is Given\nVerified Drawdown Value measured at the Well\nVerified Difference in Drawdowns at Two Wells when Aquifer Constant is Given\nVerified Drawdown in Well 1 when Aquifer Constant and Discharge is Given\nVerified Drawdown in Well 1 when Aquifer Constant is Given\nVerified Drawdown in Well 1 when Thickness of Aquifer from Impermeable Layer is Given\nVerified Drawdown in Well 2 when Aquifer Constant and Discharge is Given\nVerified Drawdown in Well 2 when Aquifer Constant is Given\nVerified Drawdown in Well 2 when Thickness of Aquifer from Impermeable Layer is Given\nVerified Catchment Area when Peak Rate of Runoff from Dredge Formula is Given\nVerified Length of the Drain when Peak Rate of Runoff from Dredge Formula is Given\nVerified Peak Rate of Runoff from Dredge Formula\nCreated Dry unit weight in terms of percentage of air voids\nCreated Dry unit weight in terms of unit weight of solids\nCreated Dry unit weight in terms of water content\nCreated Dry unit weight in terms of water content at full saturation\nVerified Dry Unit Weight of Soil when Saturation is 0 Percent\nCreated Dry unit weight when bulk unit weight in terms of degree of saturation is given\nCreated Dry unit weight when submerged unit weight of soil in terms of porosity is given\nVerified Dynamic Viscosity when Mean Velocity of Flow with Pressure Gradient is Given\nVerified Dynamic Viscosity when Pressure Head Drop is Given\n4 More Dynamic Viscosity Calculators\nCreated Dynamic Viscosity when Drag Force as per Stokes Law is Given\nCreated Dynamic Viscosity when Particle Reynold's Number is Given\nCreated Dynamic Viscosity when Settling Velocity with respect to Dynamic Viscosity is Given\nVerified Average depth of water when Setup above Pool level through Zuider Zee formula is Given\nVerified Coefficient of Permeability when Maximum and Minimum permeability is Given for a Earth Dam\nVerified Coefficient of Permeability when Quantity of seepage in length of dam is given\nVerified Maximum Permeability when Coefficient of Permeability is Given for a Earth Dam\nVerified Minimum Permeability when Coefficient of Permeability is Given for a Earth Dam\nVerified Setup above Pool level through Zuider Zee formula\nVerified Superficial area of flow when Seepage Discharge in an Earth Dam is Given\n18 More Earth Dam Calculators\nVerified Compacted volume of Soil After Excavation of Soil\nVerified Load Factor when Original Volume of Soil is Given\nVerified Loaded Volume of Soil when Original Volume of Soil is Given\nVerified Loaded Volume of Soil when Percent Swell is Given\nVerified Original Volume of Soil Before Excavation\nVerified Original Volume of Soil Before Excavation when Percent Swell is Given\nVerified Swell in Soil when Original Volume of Soil is Given\n2 More Earth quantities hauled Calculators\nVerified Coefficient of Traction when Usable Pull is Given\nVerified Total Road Resistance when Rolling Resistance and Grade Resistance is Given\nVerified Usable Pull to Overcome Loss of Power with Altitude\nVerified Weight on Wheels when Total Road Resistance is Given\n11 More Earthmoving Calculators\nVerified BOD of the Effluent Getting Out of the Filter\nVerified BOD of the Influent Entering the Filter\nVerified Depth of Filter when BOD of the Influent Entering the Filter is Given\nVerified Hydraulic Loading Rate when BOD of the Influent Entering the Filter is Given\nVerified Rate Constant when BOD of the Influent Entering the Filter is Given\nVerified Barometric Pressure in Essen and Froome Formula for Group Refractive Index\nVerified Barometric Pressure in I. U. C. G Formula for Refractive Index\nVerified Barometric Pressure when Group Refractive Index is Given\nVerified Barometric Pressure when Partial Pressure of Water Vapour in I. U. C. G Formula is Given\nVerified Corrected Slope Distance for Refractive Index\nVerified Essen and Froome Formula for Group Refractive Index\nVerified Group Refractive Index at Standard Conditions\nVerified Group Refractive Index if Temperature and Humidity are different from Standard Values\nVerified I. U. C. G Formula for Refractive Index\nVerified Overall Standard Error\nVerified Partial Pressure of Water Vapour in I. U. C. G Formula for Refractive Index\nVerified Partial Pressure of Water Vapour when Refractive Index is Given\nVerified Partial Pressure of Water Vapour when Temperature Effects are Considered\nVerified Temperature Difference when Partial Pressure is Given\nVerified Wave Velocity in a Medium\nVerified Wave Velocity in Vacuum\nVerified Reduced Distance\nVerified Spheroidal Distance\nVerified Spheroidal Distance for Geodimeters\nVerified Spheroidal Distance for Tellurometers\nVerified Buoyancy when Effective Weight of the Particle is Given\nVerified Effective Weight of the Particle\nVerified Effective Weight of the Particle when Buoyancy is Given\nVerified Radius of Particle when Effective Weight of the Particle is Given\nVerified Total Weight when Effective Weight of the Particle is Given\nVerified Unit weight of Particle when Effective Weight of the Particle is Given\nVerified Unit Weight of Water when Effective Weight of the Particle is Given\nCreated Efficiency of First Filter Stage\nCreated Efficiency of First Filter Stage using Efficiency of Second Filter Stage\nCreated Efficiency of First Filter Stage when Overall Efficiency is given\nCreated Efficiency of First Filter when BOD Loading for Second Filter is Given\nCreated Efficiency of Second Filter Stage\nCreated Efficiency of Second Filter Stage when Overall Efficiency is given\nCreated Overall Efficiency of Two Stage Trickling Filter\nCreated Overall Efficiency when Efficiency of First and Second Filter Stage is Given\nVerified Efficiency of Single Stage High Rate Trickling Filter\nVerified Efficiency of Single Stage High Rate Trickling Filter when Unit Organic Loading is Given\nVerified Filter Volume when Efficiency of Filter is Given\nVerified Filter Volume when Volume of Raw Sewage is Given\nVerified Final Efficiency After Two Stage Filtration\nVerified Initial Efficiency when Final Efficiency After Two Stage Filtration is Given\nVerified Recirculation Factor for the Second Stage Filter\nVerified Recirculation Factor when Efficiency of Filter is Given\nVerified Recirculation Factor when Recirculation ratio is Given\nVerified Recirculation Factor when Volume of Raw Sewage is Given\nVerified Recirculation Ratio when Volume of Raw Sewage is Given\nVerified Total BOD in Effluent when Final Efficiency After Two Stage Filtration is Given\nVerified Total Organic Load when Efficiency of Filter is Given\nVerified Total Organic Load when Volume of Raw Sewage is Given\nVerified Unit Organic Loading on Filter when volume of Raw Sewage is Given\nVerified Volume of Raw Sewage when Recirculation ratio is Given\nVerified Volume of Raw Sewage when Unit Organic Loading on Filter is Given\nVerified Volume of Recirculated Sewage when Recirculation ratio is Given\nVerified Volume of Recirculated Sewage when Unit Organic Loading on Filter is Given\nVerified Volume of Second Stage Filter\nVerified Effluent BOD when Oxygen Demand and Ultimate BOD Both is Given\nVerified Effluent BOD when Oxygen Demand of Biomass is Given\nVerified Effluent BOD when Oxygen Required in Aeration Tank is Given\nVerified Effluent BOD when Ultimate BOD is Given\nCreated Effluent Flow Rate when Wasting Rate from Return Line is Given\nCreated Effluent Substrate Concentration when Net Waste Activated Sludge is given\nCreated Effluent Substrate Concentration when Theoretical Oxygen Requirement is given\nCreated Effluent Substrate Concentration when Volume of Reactor is given\nVerified Diameter of Circular Section\nVerified Width of Egg Shaped Section when Diameter of Circular Section is Given\nVerified Elastic Modulus of Rock when Deflection Due to Moments on a Arch Dam is Given\nVerified Elastic Modulus of Rock when Deflection Due to Shear on a Arch Dam is Given\n4 More Elastic Modulus of Rock Calculators\nVerified Completion time for given distance of path\nVerified Distance Measured\nVerified Velocity in Medium when Distance is Given\nVerified Elongation of Tapering Bar due to Self Weight\nVerified Length of Bar when Elongation of Tapering Bar with Cross-sectional area is Given\nVerified Length of Rod when Elongation due to Self Weight in Uniform Bar is Given\nVerified Modulus of Elasticity of Bar when Elongation of Tapering Bar due to Self Weight is Given\nVerified Stress when Elongation of Tapering Rod due to Self Weight is Given\n9 More Elongation of Tapering Bar due to Self Weight Calculators\nCreated Endogenous Decay Coefficient when Observed Cell Yield is given\nCreated Endogenous Decay Constant when Volume of Reactor is given\nVerified Endogenous Respiration Rate Constant when Mass of Wasted Activated Sludge is Given\nVerified Endogenous Respiration Rate Constant when Maximum Yield Coefficient is Given\nVerified Endogenous Respiration Rate Constant when Reciprocal of Sludge Age is Given\nVerified Energy Slope of channel when Energy Gradient is Given\nVerified Energy Slope of Rectangular channel\nVerified Energy Slope of Rectangular channel through Chezy formula\nVerified Energy Slope when Slope of Dynamic Equation of Gradually Varied Flow is Given\nVerified Length of Culvert when Velocity of Flow Fields is Given\n5 More Entrance and Exit Submerged Calculators\nVerified Average Daily Flow when Maximum Daily Flow for Areas of Moderate Sizes is Given\nVerified Average Daily Flow when Maximum Hourly Flow is Given\nVerified Average Daily Flow when Minimum Daily Flow for Areas of Moderate Sizes is Given\nVerified Average Daily Flow when Minimum Hourly Flow is Given\nVerified Average Daily Sewage Flow when Peak Sewage Flow is Given\nVerified Maximum Daily Flow for Areas of Moderate Sizes\nVerified Maximum Daily Flow when Maximum Hourly Flow is Given\nVerified Maximum Hourly Flow when Average Daily Flow is Given\nVerified Maximum Hourly Flow when Maximum Daily Flow for Areas of Moderate Sizes is Given\nVerified Minimum Daily Flow for Areas of Moderate Sizes\nVerified Minimum Daily Flow when Minimum Hourly Flow is Given\nVerified Minimum Hourly Flow when Average Daily Flow is Given\nVerified Minimum Hourly Flow when Minimum Daily Flow for Areas of Moderate Sizes is Given\nVerified Peak Sewage Flow when Population in Thousands is Given\nVerified Population in Thousands when Peak Sewage Flow is Given\nVerified Flood Frequency when Recurrence Interval is Given\nVerified Flood Index when Flood Discharge is Given\nVerified Number of Years After which Such a Flood Recorded for Fuller's Formula\nVerified Number of Years After which Such a Flood Recorded when Flood Discharge by Fuller's Formula is Given\nVerified Number of Years when Recurrence Interval by California Method is Given\nVerified Number of Years when Recurrence Interval by Hazen's Method is Given\nVerified Actual Vapour Pressure when Evaporation Loss Per Day is Given\nVerified Actual Vapour Pressure when Evaporation Loss Per Month is Given\nVerified Atmospheric Pressure when Change in Vapour Pressure is Given\nVerified Atmospheric Pressure when Evaporation Loss Per Day is Given\nVerified Change in Vapour Pressure when Evaporation Loss Per Day is Given\nVerified Change in Vapour Pressure when Evaporation Loss Per Month is Given\nVerified Constant Dependent on Depth of Water Bodies when Change in Vapour Pressure is Given\nVerified Constant Dependent on Depth of Water Bodies when Evaporation Loss Per Month is Given\nVerified Constant Used in Meyer's Formula when Evaporation Loss Per Month is Given\nVerified Constant used in Rohwer's Formula when Change in Vapour Pressure is Given\nVerified Constant used in Rohwer's Formula when Evaporation Loss Per Day is Given\nVerified Evaporation Loss Per Day\nVerified Evaporation Loss Per Day when Change in Vapour Pressure is Given\nVerified Evaporation Loss Per Month\nVerified Evaporation Loss Per Month when Change in Vapour Pressure is Given\nVerified Evaporation Loss Per Month when Constant Used in Meyer's Formula is 16\nVerified Evaporation Loss Per Month when Deep Water Body is Given\nVerified Evaporation Loss Per Month when Shallow Water Body is Given\nVerified Maximum Vapour Pressure when Evaporation Loss Per Day is Given\nVerified Maximum Vapour Pressure when Evaporation Loss Per Month is Given\nVerified Mean Wind Velocity at Ground Level when Evaporation Loss Per Day is Given\nVerified Monthly Mean Wind Velocity when Evaporation Loss Per Month is Given\nCreated Falling Speed of Smaller Particle\nCreated Falling Speed when Height at Outlet Zone with respect to Area of Tank is Given\nCreated Falling Speed when Ratio of Removal with respect to Discharge is Given\nCreated Falling Speed when Ratio of Removal with respect to Settling Velocity is Given\nCreated Falling Speed when Surface Area with respect to Settling Velocity is Given\nCreated Concrete Column Elasticity Modulus when Flexural Stiffness is Given\nCreated Moment of Inertia about Centroidal Axis when Flexural Stiffness is Given\n4 More Flat Plate Construction Calculators\nVerified External Diameter of Pipe when Load Per Unit Length for Flexible Pipes is Given\nVerified Fill Coefficient when Load Per Unit Length for Flexible Pipes is Given\nVerified Load Per Unit Length for Flexible Pipes\nVerified Specific Weight of Fill Material when Load Per Unit Length for Flexible Pipes is Given\nVerified Width of Trench when Load Per Unit Length for Flexible Pipes is Given\nVerified Flood Coefficient when Flood Discharge is Given\nVerified Flood Discharge\nVerified Flood Discharge by Dicken's Formula\nVerified Flood Discharge by Dicken's Formula for Northern India\nVerified Flood Discharge by Dicken's Formula in F.P.S Unit\nVerified Flood Discharge by Dicken's Formula in F.P.S Unit for Northern India\nVerified Flood Discharge by Fanning's Formula\nVerified Flood Discharge by Fanning's Formula when Average Value of Constant is Given\nVerified Flood Discharge by Fuller's Formula\nVerified Flood Discharge by Inglis Formula\nVerified Flood Discharge by Nawab Jang Bahadur Formula\nVerified Flood Discharge for Area within 24 KM from the Coast\nVerified Flood Discharge for Area within 24 KM to 161 KM from the Coast\nVerified Flood Discharge for Catchment of Former Bombay Presidency\nVerified Flood Discharge for Limited Area Near Hills\nVerified Flood Discharge for Madras Catchment\nVerified Flood Discharge for Madras Catchment in F.P.S Unit\nVerified Flood Discharge in FPS Unit by Creager's Formula\nVerified Flood Discharge in FPS Unit by Fanning's Formula\nVerified Flood Discharge in FPS Unit by Fanning's Formula when Average Value of Constant is Given\nVerified Flood Discharge in FPS Unit by Fuller's Formula\nVerified Flood Discharge in FPS Unit by Inglis Formula\nVerified Flood Discharge in FPS Unit by Nawab Jang Bahadur Formula\nVerified Flood Discharge in FPS Unit for Area within 24 KM from the Coast\nVerified Flood Discharge in FPS Unit for Area within 24 KM to 161 KM from the Coast\nVerified Flood Discharge in FPS Unit for Catchment of Former Bombay Presidency\nVerified Flood Discharge in FPS Unit for Limited Area Near Hills\nVerified Change in Storage denoting the beginning and end of Time Interval with respect to Inflow and Outflow\nVerified Rate of Change of Storage\n16 More Flood Routing Calculators\nVerified Flood Serial Number when Recurrence Interval by California Method is Given\nVerified Flood Serial Number when Recurrence Interval by Gumbel's Method is Given\nVerified Flood Serial Number when Recurrence Interval by Hazen's Method is Given\nVerified Hydraulic Depth when Section Factor is Given\nVerified Section Factor in open channel\nVerified Top Width when Section Factors is Given\nVerified Wetted Area when Section Factor is Given\nVerified Coefficient of Permeability when Discharge is Given\nVerified Depth of Water in Gallery when Discharge is Given\nVerified Discharge Passing Through the Vertical Section of Infiltration Gallery\nVerified Distance between Infiltration Gallery and Source when Discharge is Given\nVerified Height of Saturated Zone when Discharge is Given\nVerified Cost when Most economical pipe diameter for a distribution system is Given\nVerified Most economical pipe diameter for a distribution system for water\nVerified Power when Most economical pipe diameter for a distribution system is Given\n5 More Flow Over Notches and Weirs Calculators\nVerified Flow Velocity when Coefficient of Permeability is Given\nVerified Flow Velocity when Rate of Flow is Given\nVerified Flow Velocity when Reynold's Number is Unity\nVerified Flow Velocity of Water Entering the Tank\nVerified Flow Velocity of Water Entering the Tank when Cross-section Area of Tank is Given\nVerified Flow Velocity when Length of Tank is Given\nVerified Flow Velocity when Length to Depth Ratio is Given\nVerified Conversion Factor when Flow Velocity is given\nVerified Energy Loss when Flow Velocity is given\nVerified Flow Velocity using Manning's formula\nVerified Hydraulic Radius when Flow Velocity is given\nVerified Water Flow Equation\n3 More Flow velocity in straight sewers Calculators\nVerified Self Cleansing Velocity when Bed Slope for Partial Flow is Given\nVerified Self Cleansing Velocity when Hydraulic Mean Depth for Full Flow is Given\nVerified Self Cleansing Velocity when Hydraulic Mean Depth Ratio is Given\nVerified Self Cleansing Velocity when Ratio of Bed Slope is Given\nVerified Velocity of Full Flow when Hydraulic Mean Depth for Full Flow is Given\nVerified Velocity of Full Flow when Hydraulic Mean Depth Ratio is Given\nVerified Velocity Ratio when Hydraulic Mean Depth Ratio is Given\nVerified Velocity Ratio when Ratio of Bed Slope is Given\nVerified Velocity when Running Full when Bed Slope for Partial Flow is Given\nVerified Velocity when Running Full when Ratio of Bed Slope is Given\nVerified BOD Influent when F/M Ratio is Given\nVerified BOD Influent when MLSS is Given\nVerified BOD Load applied to the Aeration System\nVerified BOD Load Applied when MLSS is Given\nVerified BOD of the Influent Sewage when BOD Load applied is Given\nVerified Daily BOD Load when Food to Microorganism Ratio is Given\nVerified F/M Ratio when MLSS is Given\nVerified Food to Microorganism Ratio\nVerified Microbial Mass in the Aeration System\nVerified Microbial Mass in the Aeration System when MLSS is Given\nVerified MLSS when BOD Load Applied to the Aeration System is Given\nVerified MLSS when F/M Ratio is Given\nVerified MLSS when Microbial Mass in the Aeration System is Given\nVerified Sewage Flow into the Aeration System when BOD Load applied is Given\nVerified Sewage Flow when F/M Ratio is Given\nVerified Sewage Flow when MLSS is Given\nVerified Total Microbial Mass when Food to Microorganism Ratio is Given\nVerified Volume of Tank when F/M Ratio is Given\nVerified Volume of Tank when Microbial Mass in the Aeration System is Given\nVerified Volume of Tank when MLSS is Given\nVerified Maximum Moment for Symmetrical Concrete Wall Footing\nVerified Uniform Pressure on Soil when Maximum Moment is Given\n1 More Footing Calculators\nVerified Allowable Compressive Stress Parallel to Grain for Short Columns\nVerified Elasticity Modulus when Allowable Compressive Stress in a Rectangular Section is Given\n3 More Forest Products Laboratory Recommendations Calculators\nVerified Form Drag of a Vessel when Total Longitudinal Current Load on a Vessel is known\n6 More Form Drag Calculators\nVerified Constant dependent on Well Function when Formation Constant S is Given\nVerified Formation Constant S\nVerified Formation Constant S when Radial Distance is Given\nVerified Formation Constant T when Change in Drawdown is Given\nVerified Formation Constant T when Drawdown is Given\nVerified Formation Constant T when Formation Constant S is Given\nVerified Formation Constant T when Radial Distance is Given\nVerified Net Bearing Capacity of a Long Footing in Foundation Stability Analysis\n10 More Foundation Stability Analysis Calculators\nVerified Constant used in F.P.S Unit when Flood Discharge by Dicken's Formula is Given\nVerified Constant used in F.P.S Unit when Flood Discharge for Madras Catchment is Given\nVerified Constant used in FPS Unit when Flood Discharge by Creager's Formula is Given\nVerified Constant used in FPS Unit when Flood Discharge by Fanning's Formula is Given\nVerified Constant used in FPS Unit when Flood Discharge by Fuller's Formula is Given\nVerified Constant used in FPS Unit when Flood Discharge by Nawab Jang Bahadur Formula is Given\nVerified Number of Simultaneous Fire Stream\nVerified Population when Number of Simultaneous Fire Stream is Given\nVerified Population when Quantity of Water by Freeman's Formula is Given\nVerified Quantity of Water by Freeman's Formula\nVerified Friction Factor when Head Loss due to Frictional Resistance is Given\n5 More Friction Factor Calculators\nVerified Bearing Capacity Factor Dependent on Cohesion for Rectangular Footing\nVerified Bearing Capacity Factor Dependent on Cohesion for Rectangular Footing when Shape Factor is Given\nVerified Bearing Capacity Factor Dependent on Surcharge for Rectangular Footing\nVerified Bearing Capacity Factor Dependent on Surcharge for Rectangular Footing when Shape Factor is Given\nVerified Bearing Capacity Factor Dependent on Unit Weight for Rectangular Footing\nVerified Bearing Capacity Factor Dependent on Weight for Rectangular Footing when Shape Factor is Given\nVerified Cohesion of Soil for Rectangular Footing when Shape Factor is Given\nVerified Cohesion of Soil when Ultimate Bearing Capacity for Rectangular Footing is Given\nVerified Effective Surcharge for Rectangular Footing\nVerified Effective Surcharge for Rectangular Footing when Shape Factor is Given\nVerified Length of Rectangular Footing when Ultimate Bearing Capacity is Given\nVerified Ultimate Bearing Capacity for Rectangular Footing\nVerified Ultimate Bearing Capacity for Rectangular Footing when Shape Factor is Given\nVerified Unit Weight of Soil for Rectangular Footing when Shape Factor is Given\nVerified Unit Weight of Soil when Ultimate Bearing Capacity for Rectangular Footing is Given\nVerified Width of Rectangular Footing when Ultimate Bearing Capacity is Given\nVerified Coefficient of Permeability when Discharge for Fully Penetrating Well is Given\nVerified Depth of Water in Well when Discharge for Fully Penetrating Well is Given\nVerified Discharge for Fully Penetrating Well\nVerified Radius of Influence when Discharge for Fully Penetrating Well is Given\nVerified Radius of Well when Discharge for Fully Penetrating Well is Given\nVerified Thickness of Aquifer when Discharge for Fully Penetrating Well is Given\nVerified Bearing Capacity Factor Dependent on Cohesion for General Shear Failure\nVerified Bearing Capacity Factor Dependent on Surcharge for General Shear Failure\nVerified Bearing Capacity Factor Dependent on Unit Weight for General Shear Failure\nVerified Cohesion of Soil when Net Ultimate Bearing Capacity for General Shear Failure is Given\nVerified Effective Surcharge when Net Ultimate Bearing Capacity for General Shear Failure is Given\nVerified Net Ultimate Bearing Capacity for General Shear Failure\nVerified Unit Weight of Soil under Strip Footing for General Shear Failure\nVerified Width of Strip Footing when Net Ultimate Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Cohesion when Modified Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Surcharge when Modified Bearing Capacity is Given\nVerified Bearing Capacity Factor Dependent on Unit Weight when Modified Bearing Capacity is Given\nVerified Cohesion of Soil when Modified Bearing Capacity for General Shear Failure is Given\nVerified Correction Factor Applied Due to Water Table for General Shear Failure\nVerified Effective Surcharge when Modified Bearing Capacity for General Shear Failure is Given\nVerified Modified Bearing Capacity for General Shear Failure\nVerified Shape Factor with Cohesion when Modified Bearing Capacity for General Shear Failure is Given\nVerified Shape Factor with Surcharge when Modified Bearing Capacity for General Shear Failure is Given\nVerified Shape Factor with Unit Weight when Modified Bearing Capacity for General Shear Failure is Given\nVerified Unit Weight of Soil when Modified Bearing Capacity for General Shear Failure is Given\nVerified Width of Footing when Modified Bearing Capacity for General Shear Failure is Given\nVerified Average Percentage Increase when Future Population from Geometrical Increase Method is Given\nVerified Average Percentage Increase when Future Population of 2 Decades by Geometrical Method is Given\nVerified Average Percentage Increase when Future Population of 3 Decades by Geometrical Method is Given\nVerified Future Population at the End of 2 Decades in Geometrical Increase Method\nVerified Future Population at the End of 3 Decades in Geometrical Increase Method\nVerified Future Population at the End of n Decades in Geometrical Increase Method\nVerified Number of Decades when Future Population from Geometrical Increase Method is Given\nVerified Present Population when Future Population from Geometrical Increase Method is Given\nVerified Present Population when Future Population of 2 Decades by Geometrical Increase Method is Given\nVerified Present Population when Future Population of 3 Decades by Geometrical Increase Method is Given\nVerified Wetted Perimeter when Hydraulic Mean Depth is Given\n5 More Geometrical Properties of Channel Section Calculators\nVerified Allowable Bending Stress in Compression Flange\nVerified Allowable Shear Stress with Tension Field Action\nVerified Allowable Shear Stress without Tension Field Action\nVerified Area of Flange When Plate Girder Stress Reduction Factor is Given\nVerified Area of Web When Plate Girder Stress Reduction Factor is Given\nVerified Depth to Thickness Ratio of Girder With Transverse Stiffeners\nVerified Hybrid Girder Factor\nVerified Maximum depth to thickness Ratio for Unstiffened Web\nVerified Plate Girder Stress Reduction Factor\nVerified Camber when Gradient is given\nVerified Area of Section when Energy Gradient is Given\nVerified Area of Section when Total Energy is Given\nVerified Bed Slope when Energy Slope of Rectangular channel is Given\nVerified Bed Slope when Energy Slope of Rectangular channel through Chezy formula is Given\nVerified Bed Slope when Slope of Dynamic Equation of Gradually Varied Flow is Given\nVerified Bottom Slope of channel when Energy Gradient is Given\nVerified Depth of Flow when Energy Slope of Rectangular channel is Given\nVerified Depth of Flow when Energy Slope of Rectangular channel through Chezy formula is Given\nVerified Depth of Flow when Total Energy is Given\nVerified Discharge when Energy Gradient is Given\nVerified Discharge when Froude Number is Given\nVerified Discharge when Total Energy is Given\nVerified Energy Gradient when bed slope is given\nVerified Energy Gradient when slope is given\nVerified Froude Number when Slope of Dynamic Equation of Gradually Varied Flow is Given\nVerified Froude Number with top width given\nVerified Normal Depth when Energy Slope of Rectangular channel is Given\nVerified Slope of Dynamic Equation of Gradually Varied Flow when Energy Gradient is Given\nVerified Slope of Dynamic Equation of Gradually Varied Flows\nVerified Top Width when Energy Gradient is Given\nVerified Top Width when Froude Number is Given\n3 More Gradually Varied Flow Calculators\nVerified Pressure P1 when the Resultant is within the Middle Third and Width of Base is Given\nVerified Pressure P2 when the Resultant is within the Middle Third and Width of Base is Given\n5 More Gravity Retaining Wall Calculators\nVerified Reynolds Number of Value Unity\n6 More Groundwater Hydrology Calculators\nVerified Average Birth Rate Per Year when Natural Increase is Given\nVerified Average Death Rate Per Year when Natural Increase is Given\nVerified Design Period when Natural Increase is Given\nVerified Future Population at the End of n Decades when Migration is Given\nVerified Migration when Future Population at the End of n Decades is Given\nVerified Natural Increase when Design Period is Given\nVerified Natural Increase when Future Population at the End of n Decades is Given\nVerified Present Population when Future Population is Given\nVerified Present Population when Natural Increase is Given\nVerified Average Flood Discharge when Flood Discharge Having Highest Frequency is Given\nVerified Flood Discharge Having Highest Frequency\nVerified Flood Discharge Having Highest Frequency when Gumbel's Reduced Variate is Given\nVerified Flood Discharge when Gumbel's Reduced Variate is Given\nVerified Gumbel's Constant when Gumbel's Reduced Variate is Given\nVerified Gumbel's Constant when Standard Deviation is Given\nVerified Gumbel's Correction when Recurrence Interval by Gumbel's Method is Given\nVerified Gumbel's Reduced Variate\nVerified Number of Years when Recurrence Interval by Gumbel's Method is Given\nVerified Probability of Occurrence when Recurrence Interval is Given\nVerified Recurrence Interval by Gumbel's Method\nVerified Recurrence Interval when Probability is Given\nVerified Standard Deviation when Flood Discharge Having Highest Frequency is Given\nVerified Standard Deviation when Gumbel's Constant is Given\nVerified Dynamic Viscosity when Pressure Drop over the Length of Pipe with Discharge is Given\n20 More Hagen–Poiseuille Equation Calculators\nVerified Coefficient Dependent on Pipe when Head Loss is Given\nVerified Coefficient Dependent on Pipe when Radius of Pipe is Given\nVerified Coefficient of Roughness of Pipe when Diameter of Pipe is Given\nVerified Coefficient of Roughness of Pipe when Mean Velocity of Flow is Given\nVerified Diameter of Pipe when Head Loss by Hazen Williams Formula is Given\nVerified Diameter of Pipe when Hydraulic Gradient is Given\nVerified Head Loss by Hazen Williams Formula\nVerified Head Loss by Hazen Williams Formula when Radius of Pipe is Given\nVerified Hydraulic Gradient when Diameter of Pipe is Given\nVerified Hydraulic Gradient when Mean Velocity of Flow is Given\nVerified Hydraulic Radius when Mean Velocity of Flow is Given\nVerified Length of Pipe by Hazen Williams Formula when Radius of Pipe is Given\nVerified Length of Pipe when Head Loss by Hazen Williams Formula is Given\nVerified Mean Velocity of Flow in Pipe by Hazen Williams Formula\nVerified Mean Velocity of Flow in Pipe when Diameter of Pipe is Given\nVerified Radius of Pipe by Hazen Williams Formula when Length of Pipe is Given\nVerified Velocity of Flow by Hazen Williams Formula when Radius of Pipe is Given\nVerified Velocity of Flow when Head Loss by Hazen Williams Formula is Given\nCreated Height at Outlet Zone when Falling Speed of Smaller Particle is Given\nCreated Height at Outlet Zone when Ratio of Removal with respect to Tank Height is Given\nCreated Height at Outlet Zone with respect to Area of Tank\nCreated Height at Outlet Zone with respect to Discharge\nCreated Height at Outlet Zone with respect to Settling Velocity\nCreated Height of Settling Zone when Cross-section Area of Sedimentation Tank is Given\nCreated Height of Settling Zone when Detention Time is Given\nCreated Height of Settling Zone when Height at Outlet Zone with respect to Area of Tank is Given\nCreated Height of Settling Zone when Height at Outlet Zone with respect to Discharge is Given\nCreated Height of Settling Zone when Height at Outlet Zone with respect to Settling Velocity is Given\nCreated Height of Settling Zone when Length of Sedimentation Tank with respect to Surface Area is Given\nCreated Height of Settling Zone when Length of Tank with respect to Darcy Weishbach Factor is Given\nCreated Height of Settling Zone when Length of Tank with respect to Height for Practical Purpose is Given\nCreated Height of Settling Zone when Ratio of Removal with respect to Tank Height is Given\nVerified Modulus of Elasticity when Hoop Stress due to temperature fall with strain is Given\nVerified Strain when Hoop Stress due to temperature fall is Given" ]
[ null, "https://www.calculatoratoz.com/Images/UserInfo//ishita.jpg", null ]
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https://www.mothur.org/w/index.php?title=Bootstrap&oldid=357
[ "Bootstrap\n\nExample Calculations\n\n*boot*\n\nThese files give the bootstrap estimate as described by Smith and Van Belle (5) but implemented for a single \"quadrant\".\n\n$S_{Bootstrap} = S_{obs} + \\sum_{i=1}^{S_{obs}} \\left ( 1 - \\frac {S_i}{N}\\right )^N$\n\nwhere,\n\nN = The number of individuals sampled\n\n$S_{i}$ = The number of sequences in the ith OTU\n\n$S_{obs}$ = Observed number of species\n\nFor the Amazonian dataset at distance 0.03, $S_{Bootstrap}$ =112.33 and there is not a simple expression for the 95% confidence interval.\n\nFile Samples on the Amazonian Dataset\n\n• .sabund\n\nThis file contains data for constructing a rank-abundance plot of the OTU data for each distance level. The first column contains the distance and the second is the number of OTUs observed at that distance. The successive values in the row are the number of OTUs that were found once, twice, etc.\n\nunique\t 2\t94\t2\n0\t 2\t92\t3\n0.01\t 2\t88\t5\n0.02\t 4\t84\t2\t2\t1\n0.03\t 4\t75\t6\t1\t2\n0.04\t 4\t69\t9\t1\t2\n0.05\t 4\t55\t13\t3\t2\n0.06\t 4\t48\t14\t2\t4\n0.07\t 4\t44\t16\t2\t4\n0.08\t 7\t36\t15\t4\t2\t1\t0\t1\n0.09\t 7\t36\t12\t4\t3\t0\t0\t2\n0.1\t 7\t35\t12\t2\t3\t0\t0\t3\n\n• .bootstrap" ]
[ null ]
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https://se.mathworks.com/help/optim/ug/nonlinear-least-squares-problem-based-basics.html
[ "# Nonlinear Least-Squares, Problem-Based\n\nThis example shows how to perform nonlinear least-squares curve fitting using the Problem-Based Optimization Workflow.\n\n### Model\n\nThe model equation for this problem is\n\n`$y\\left(t\\right)={A}_{1}\\mathrm{exp}\\left({r}_{1}t\\right)+{A}_{2}\\mathrm{exp}\\left({r}_{2}t\\right),$`\n\nwhere ${A}_{1}$, ${A}_{2}$, ${r}_{1}$, and ${r}_{2}$ are the unknown parameters, $y$ is the response, and $t$ is time. The problem requires data for times `tdata` and (noisy) response measurements `ydata`. The goal is to find the best $A$ and $r$, meaning those values that minimize\n\n`$\\sum _{t\\in tdata}{\\left(y\\left(t\\right)-ydata\\right)}^{2}.$`\n\n### Sample Data\n\nTypically, you have data for a problem. In this case, generate artificial noisy data for the problem. Use `A = [1,2]` and `r = [-1,-3]` as the underlying values, and use 200 random values from `0` to 3 as the time data. Plot the resulting data points.\n\n```rng default % For reproducibility A = [1,2]; r = [-1,-3]; tdata = 3*rand(200,1); tdata = sort(tdata); % Increasing times for easier plotting noisedata = 0.05*randn(size(tdata)); % Artificial noise ydata = A(1)*exp(r(1)*tdata) + A(2)*exp(r(2)*tdata) + noisedata; plot(tdata,ydata,'r*') xlabel 't' ylabel 'Response'```", null, "The data are noisy. Therefore, the solution probably will not match the original parameters `A` and `r` very well.\n\n### Problem-Based Approach\n\nTo find the best-fitting parameters `A` and `r`, first define optimization variables with those names.\n\n```A = optimvar('A',2); r = optimvar('r',2);```\n\nCreate an expression for the objective function, which is the sum of squares to minimize.\n\n```fun = A(1)*exp(r(1)*tdata) + A(2)*exp(r(2)*tdata); obj = sum((fun - ydata).^2);```\n\nCreate an optimization problem with the objective function `obj`.\n\n`lsqproblem = optimproblem(\"Objective\",obj);`\n\nFor the problem-based approach, specify the initial point as a structure, with the variable names as the fields of the structure. Specify the initial `A = [1/2,3/2]` and the initial `r = [-1/2,-3/2]`.\n\n```x0.A = [1/2,3/2]; x0.r = [-1/2,-3/2];```\n\nReview the problem formulation.\n\n`show(lsqproblem)`\n``` OptimizationProblem : Solve for: A, r minimize : sum(arg6) where: arg5 = extraParams{3}; arg6 = (((A(1) .* exp((r(1) .* extraParams{1}))) + (A(2) .* exp((r(2) .* extraParams{2})))) - arg5).^2; extraParams ```\n\n### Problem-Based Solution\n\nSolve the problem.\n\n`[sol,fval] = solve(lsqproblem,x0)`\n```Solving problem using lsqnonlin. Local minimum found. Optimization completed because the size of the gradient is less than the value of the optimality tolerance. <stopping criteria details> ```\n```sol = struct with fields: A: [2×1 double] r: [2×1 double] ```\n```fval = 0.4724 ```\n\nPlot the resulting solution and the original data.\n\n```figure responsedata = evaluate(fun,sol); plot(tdata,ydata,'r*',tdata,responsedata,'b-') legend('Original Data','Fitted Curve') xlabel 't' ylabel 'Response' title(\"Fitted Response\")```", null, "The plot shows that the fitted data matches the original noisy data fairly well.\n\nSee how closely the fitted parameters match the original parameters `A = [1,2]` and `r = [-1,-3]`.\n\n`disp(sol.A)`\n``` 1.1615 1.8629 ```\n`disp(sol.r)`\n``` -1.0882 -3.2256 ```\n\nThe fitted parameters are off by about 15% in `A` and 8% in `r`.\n\n### Unsupported Functions Require `fcn2optimexpr`\n\nIf your objective function is not composed of elementary functions, you must convert the function to an optimization expression using `fcn2optimexpr`. See Convert Nonlinear Function to Optimization Expression. For the present example:\n\n```fun = @(A,r) A(1)*exp(r(1)*tdata) + A(2)*exp(r(2)*tdata); response = fcn2optimexpr(fun,A,r); obj = sum((response - ydata).^2);```\n\nThe remainder of the steps in solving the problem are the same. The only other difference is in the plotting routine, where you call `response` instead of `fun`:\n\n`responsedata = evaluate(response,sol);`\n\nFor the list of supported functions, see Supported Operations on Optimization Variables and Expressions." ]
[ null, "https://se.mathworks.com/help/examples/optim/win64/NonlinearLeastSquaresProblemBasedExample_01.png", null, "https://se.mathworks.com/help/examples/optim/win64/NonlinearLeastSquaresProblemBasedExample_02.png", null ]
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https://ianozsvald.com/tag/binary-matrix/
[ "# Archives of #Binary Matrix\n\n#### Visualising the internals of Logistic Regression on a Text Matrix\n\nBelow I have some plots that visualise the term matrix (as a binary matrix and as a TF-IDF matrix) for the brand disambiguation project followed by a visualisation of the coefficients used in scikit-learn’s LogisticRegression classifier using l1 and l2 penalties. Using a CountVectorizer with binary=True we can mark the absence or presence of a […]" ]
[ null ]
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https://mirror.las.iastate.edu/CRAN/web/packages/formulops/readme/README.html
[ "# formulops\n\nThe goal of formulops is to assist with formula modification in R treating formulae as standard mathematical operations as used with `nlme::nlme()` and `lme4::nlmer()` (for treatment as statistical formula see the `Formula` package).\n\n## Installation\n\nYou can install the released version of formulops from CRAN with:\n\n``install.packages(\"formulops\")``\n\n## Example\n\nA few common examples of modifying a formula are given below.\n\n``````library(formulops)\n# Replace a with c in the formula\nmodify_formula(a~b, find=quote(a), replace=quote(c))\n# Replace a with c+d in the formula\nmodify_formula(a~b, find=quote(a), replace=quote(c+d))\n# More complex parts can be replaced, too\nmodify_formula(a~b/c, find=quote(b/c), replace=quote(d))\n# Multiple replacements can occur simultaneously\nmodify_formula(a~b/c+d, find=list(quote(b/c), quote(d)), replace=list(quote(d), quote(e)))\n# Function arguments can be expanded\nmodify_formula(a~b(c), find=quote(c), replace=quote(formulops_expand(d, e)))``````\n\nA substituting formula is a simple way to generate a complex formula from several simpler formulae. Parentheses are appropriately added, if required.\n\n``````foo <- substituting_formula(y~x1+x2, x1~x3*x4, x2~x5/x6+x7)\nas.formula(foo)``````" ]
[ null ]
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https://e-eduanswers.com/mathematics/question3763370
[ " What’s the least common denominator (lcd) for each group of fractions? a. 1⁄6 and 7⁄8 b. 3⁄4 and 7⁄10 c. 7⁄12, 3⁄8 and 11⁄36", null, "", null, ", 18.10.2019 06:30, davidaagurto\n\n# What’s the least common denominator (lcd) for each group of fractions? a. 1⁄6 and 7⁄8 b. 3⁄4 and 7⁄10 c. 7⁄12, 3⁄8 and 11⁄36 d. 8⁄15, 11⁄30 and 3⁄5", null, "### Other questions on the subject: Mathematics", null, "Mathematics, 21.06.2019 16:40, jessicap7pg75\nIf 24 people have the flu out of 360 people, how many would have the flu out of 900. choose many ways you could use proportion that david would use to solve this problem", null, "Mathematics, 21.06.2019 17:40, kiingbr335yoqzaxs\nGiven abcd ac=38 and ae=3x+4 find the value of x", null, "Mathematics, 21.06.2019 18:30, josephmartinelli5\nWhat is the prime factorization of 23 ? me with this question", null, "Mathematics, 21.06.2019 20:30, anniekwilbourne\nKayla made observations about the sellin price of a new brand of coffee that sold in the three different sized bags she recorded those observations in the following table 6 is $2.10 8 is$2.80 and 16 is to \\$5.60 use the relationship to predict the cost of a 20oz bag of coffee.\nDo you know the correct answer?\nWhat’s the least common denominator (lcd) for each group of fractions? a. 1⁄6 and 7⁄8 b. 3⁄4 and 7⁄...\n\n### Questions in other subjects:", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "", null, "Total solved problems on the site: 7551738" ]
[ null, "https://e-eduanswers.com/tpl/images/sovy.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/otvet.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/en.png", null, "https://e-eduanswers.com/tpl/images/cats/himiya.png", null, "https://e-eduanswers.com/tpl/images/cats/istoriya.png", null, "https://e-eduanswers.com/tpl/images/cats/himiya.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/en.png", null, "https://e-eduanswers.com/tpl/images/cats/mat.png", null, "https://e-eduanswers.com/tpl/images/cats/biologiya.png", null, "https://e-eduanswers.com/tpl/images/cats/mkx.png", null, "https://e-eduanswers.com/tpl/images/cats/en.png", null ]
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https://gis.stackexchange.com/questions/258986/plot-two-rasters-with-different-extents
[ "Plot two rasters with different extents\n\nI have two rasters with different extents that overlap partly:\n\next1 <- extent(99500,700500,249500,600500)\next2 <- extent(1356,643990,269903,690810)\n\n#create rasters\nrr1 <- raster(matrix(runif(1000000,0,100), 1000, 1000))\nrr2 <- raster(matrix(runif(1000000,0,100), 1000, 1000))\n\nextent(rr1) <- ext1\nextent(rr2) <- ext2\n\nHow can I plot both rasters in one plot?\n\nI've tried\n\next3 <- extent(min(ext1,ext2),max(ext1,ext2),\nmin(ext1,ext2),max(ext1,ext2))\nplot(rr1, ext = ext3)\n\nBut the only the extent of rr1 is used.\n\nMerge the extents (which saves all that min/max stuff!) and plot the extent, then add the rasters:\n\nem = merge(extent(rr1),extent(rr2))\nplot(em, type=\"n\")" ]
[ null ]
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http://southmiamirealestateblog.com/pandas-dataframe-set-column-names-from-list
[ " Pandas Dataframe Set Column Names From List | southmiamirealestateblog.com\n\nUsing rename is a formally more correct approach. You just have to provide a dictionary that maps your current columns names to the new ones thing that will guarantee expected results even in case of misplaced columns. How to get column names in Pandas dataframe While analyzing the real datasets which are often very huge in size, we might need to get the column names in order to perform some certain operations. Let’s discuss how to get column names in Pandas dataframe. Create a column using for loop in Pandas Dataframe; Create a list from rows in Pandas dataframe; Create a list from rows in Pandas DataFrame Set 2; Creating Pandas dataframe using list of lists; Create a new column in Pandas DataFrame based on the existing columns; Python Pandas DataFrame.fillna to replace Null values in dataframe.\n\nSep 02, 2018 · In this article we discuss how to get a list of column and row names of a DataFrame object in python pandas. First of all, create a DataFrame object of students records i.e. Sep 25, 2018 · Here data parameter can be a numpy ndarray, dict, or an other DataFrame. Also, columns and index are for column and index labels. Let’s use this to convert lists to dataframe object from lists. Create DataFrame from list of lists. Suppose we have a list of lists i.e. Pandas DataFrame is a 2-dimensional labeled data structure with columns of potentially different types. It is generally the most commonly used pandas object. Pandas DataFrame can be created in multiple ways. Let’s discuss how to create Pandas dataframe using list of lists.\n\npandas.DataFrame,pandas.Series and Python's built-in type list can be converted to each other.Here, the following contents will be described.Convert list to pandas.DataFrame, pandas.SeriesFor data-only listFor list containing data and labels row / column names For data-only list For list containin. The other option for creating your DataFrames from python is to include the data in a list structure. The first approach is to use a row oriented approach using pandas from_records. This approach is similar to the dictionary approach but you need to explicitly call out the column labels.\n\nOct 18, 2019 · At times, you may need to convert pandas DataFrame into a list in Python. But how would you do that? To accomplish this task, you can use tolist as follows:. df.values.tolist In this short guide, I’ll show you an example of using tolist to convert pandas DataFrame into a list. pandas.DataFrame » Table Of Contents. class or function name. Set the DataFrame index using existing columns. Set the DataFrame index row labels using one or more existing columns or arrays of the correct length. The index can replace the existing index or expand on it. Parameters: keys: label or array-like or list of labels/arrays. Accessing pandas dataframe columns, rows, and cells. Assigning an index column to pandas dataframe ¶ df2 = df1.set_index\"State\", drop = False. So, the formula to extract a column is still the same, but this time we didn’t pass any index name before and after the first colon. Not passing anything tells Python to include all the rows.\n\nDec 20, 2017 · Rename Column Headers In pandas. 20 Dec 2017. Originally from rgalbo on StackOverflow. 0 first_name 1 last_name 2 age 3 preTestScore Name: 0, dtype: objectReplace the.Rename the dataframe's column values with the header variable df. rename columns = header first_name last_name age preTestScore; 1: Molly. pandas.DataFrame¶ class pandas.DataFrame data=None, index=None, columns=None, dtype=None, copy=False [source] ¶ Two-dimensional size-mutable, potentially heterogeneous tabular data structure with labeled axes rows and columns. Arithmetic operations align on both row and column labels. Can be thought of as a dict-like container for Series. Use drop to delete rows and columns from pandas.DataFrame.Before version 0.21.0, specify row / column with parameter labels and axis. index or columns can be used from 0.21.0.pandas.DataFrame.drop — pandas 0.21.1 documentation Here, the following contents will be described.Delete rows from DataFr. pandas.om_dict¶ classmethod om_dict data, orient='columns', dtype=None, columns=None [source] ¶. Construct DataFrame from dict of array-like or dicts. Creates DataFrame object from dictionary by columns or by index allowing dtype specification. Pandas is one of those packages and makes importing and analyzing data much easier. Pandas rename method is used to rename any index, column or row. Renaming of column can also be done by dataframe.columns = [list]. But in the above case, there isn’t much freedom. Even if one column has to be changed, full column list has to be passed." ]
[ null ]
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https://byjus.com/commerce/sandeep-garg-microeconomics-class-11-solutions-chapter-4-elasticity-of-demand/
[ "", null, "# Sandeep Garg Microeconomics Class 11: Chapter 4 Elasticity of Demand\n\nSandeep Garg Class 11 Microeconomics Solutions Chapter 4 Elasticity of Demand is explained by the expert Economics teachers from the latest edition of Sandeep Garg Microeconomics Class 11 textbook solutions. We at BYJU’S provide Sandeep Garg Economics Class 11 Solutions to give comprehensive insight about the subject to the students. These insights help as a priceless benefit to students while completing their homework or while studying for their exams. There are numerous concepts in economics, however, we at BYJU’S provide the students with the solution from Elasticity of Demand, which will be useful for the students to score well in the board examinations.\n\n## Sandeep Garg Solutions Class 11 – Chapter 4 – Part A – Microeconomics\n\nQuestion 1\n\nWhat is the Elasticity of Demand?\n\nAns: Elasticity of Demand refers to the percentage change in demand for a commodity with respect to the percentage change in any of the factors affecting demand for that commodity.\n\nQuestion 2\n\nHow is the Elasticity of Demand calculated?\n\nAns:\n\n$$\\begin{array}{l}\\frac{Percentage\\, change\\, in\\, demand\\, for\\, X}{Percentage\\, change\\, in\\, a\\, factor \\, affecting\\, the\\, demand\\, for\\, X}\\end{array}$$\n\nQuestion 3\n\nWhat are the 5 Degrees of Elasticity of Demand?\n\nAns: 5 types of price elasticities of demand are:\n\n• Perfectly elastic demand\n• Perfectly inelastic demand\n• Highly elastic demand\n• Less elastic demand\n• Unitary elastic demand\n\nQuestion 4\n\nWhat are the factors that affect the price elasticity of demand?\n\nAns: Factors affecting the price elasticity of demand are:\n\n• Nature of commodity\n• Availability of substitutes\n• Income level\n• Level of price\n• Number of uses\n• Time period\n• Habits\n\nQuestion 5\n\nThe demand for a good falls to 240 units in response to the rise in price by ₹.2. If the original demand was 300 units at the price of ₹.20, calculate the price elasticity of demand.\n\nNew Quantity (\n$$\\begin{array}{l}_{Q_{1}}\\end{array}$$\n) = 240 Units\n\n#### Rise in Price ($$\\begin{array}{l}\\triangle P\\end{array}$$) = ₹2\n\nOriginal Quantity (Q) = 300 Units\n\n#### Original Price = ₹ 20\n\nChange in Quantity (\n$$\\begin{array}{l}\\triangle Q\\end{array}$$\n) = -60 Units\nNew Price (\n$$\\begin{array}{l}_{P_{1}}\\end{array}$$\n) = ₹ 22\nElasticity of demand\n$$\\begin{array}{l}^{_{E_{d}}}\\end{array}$$\n= ?\n\n$$\\begin{array}{l}Price\\, elasticity\\, of\\, Demand\\, _{E^{_{d}}} = \\frac{\\triangle Q}{\\triangle P}\\times \\frac{P}{Q}=\\frac{-60}{2}\\times \\frac{20}{300}=\\left (- \\right )2\\end{array}$$\n\nSolution:\n\n$$\\begin{array}{l}_{E_{d}}=\\left (-\\right )2 \\left ( Demand\\, is \\, highly\\, elastic \\, as\\, {E_{d}} >\\, 1\\right )\\end{array}$$\n\n### State whether the following statements are true or false.\n\nQuestion 6\n\nA commodity with a large number of close substitutes shows high elasticity of demand.\n\nAns: True\n\nQuestion 7\n\nIn the case of the horizontal straight line demand curve, demand does not change even with the change in price.\n\nAns: False\n\nThe above-provided solutions are considered to be the best solution for ‘Sandeep Garg Microeconomics Class 11 Solutions Chapter 4 Elasticity of Demand’. Stay tuned to BYJU’S to learn more.\n\n Important Topics in Economics:\n\n#### 1 Comment\n\n1. This is the best site for study 😄😃" ]
[ null, "https://www.facebook.com/tr", null ]
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https://www.mariedduncan.online/noclegi-augustw-domki-letniskowe-mielno-518787
[ "Noclegi Augustów Domki Letniskowe Mielno\n\n### Noclegi Augustów Domki Letniskowe Mielno\n\nTegoż kina brzmi ozdoba obok: sztuki animacjami: przed grupą łowców i'th model and ε is a small positive constant needed to prevent degenerate behavior when S is near 0. The optimal weight update can be found by taking the partial derivative of the coding cost with respect to w i. The coding cost of a 0 is -log p 1. The coding cost of a 1 is -log p 0. The result is that after coding bit y the weights are updated by moving along the cost gradient weight space: w i:= Counts are discounted to favor newer data over older. A pair of counts is represented as a bit history similar to the one described section but with more aggressive discounting. When a bit is observed and the count for the opposite bit is more than 2, the excess is halved. For example if the state is then successive zero bits result the states Logistic Mixing. PAQ7 introduced logistic mixing, which is now favored because it gives better compression. It is more general, since only a probability is needed as input. This allows the use of direct context models and a more flexible arrangement of different model types. It is used the PAQ8, LPAQ, PAQ8HP series and ZPAQ. Given a set of predictions p i that the next bit be a 1, and a set of weights w i, the combined prediction is: p squash) where stretch ln) squash stretch -1 The probability computation is essentially a neural network evaluation taking stretched probabilities as input. Again we find the optimal weight update by taking the partial derivative of the coding cost with respect to the weights. The result is that the update for bit y is simpler than back propagation w i:= w i λ stretch where λ is the learning rate, typically around 0, and is the prediction error. Unlike linear mixing, weights can be negative. Compression can often be improved by using a set of weights selected by a small context, such as a bytewise order 0 context. PAQ and ZPAQ, squash are implemented using lookup tables. PAQ, both output 12 bit fixed point numbers. A stretched probability has a resolution of 2 and range of -8 to 8. Squashed probabilities are multiples of 2. ZPAQ represents stretched probabilities as 12 bits with a resolution of 2 and range -32 to 32. Squashed probabilities are 15 bits as odd multiple of 2. This representation was found to give slightly better compression than PAQ. ZPAQ allows different components to be connected arbitrary ways. All components output a stretched probability, which simplifies the mixer implementation. ZPAQ has 3 types of mixers: Mixer weights PAQ are 16 bit signed values to facilitate vectorized implementation using SSE2 parallel instructions. ZPAQ, 16 bits was found to be inadequate for best compression. Weights were expanded to 20 bit signed values with range -8 to 8 and precision 2. Secondary Symbol Estimation SSE is implemented all PAQ versions beginning with PAQ2. Like ppmonstr, it inputs a prediction and a context and outputs a refined prediction. The prediction is quantized typically to 32 or 64 values on a nonlinear scale with finer resolution near 0 and 1 and sometimes interpolated between the two closest values. On update, one or both values are adjusted to reduce the prediction error, typically by about 1%. A typical place for SSE is to adjust the output of a mixer using a low order context. SSE components be chained series with contexts typically increasing order. Or they be parallel with independent contexts, and the results mixed or averaged together. The table is initialized that the output prediction is equal to the input prediction for all contexts. SSE was introduced to PAQ PAQ2 2003 with 64 quantization levels and no interpolation. Later versions used 32 levels and interpolation with updates to the two nearest values above and below. some versions of PAQ, SSE is also known as APM ZPAQ allows a SSE to be placed anywhere the prediction sequence with any context. Recall that ZPAQ probabilities are stretched by mapping to ln) as a 12 bit fixed point number the range -32 to +32 with resolution 1. The SSE input prediction is clamped and quantized to odd multiple of 1 between -15 and 15. The low 6 bits serve as interpolation weight. For example, if stretch 2, then the two table entries are selected by below=2 and above=3, and the interpolation weight is 0. Then the output prediction is SSE SSEw. Upon update with bit y, the table entry nearest the input prediction is updated by reducing the prediction error by a user specified fraction. There are other possibilities. CCM, a context mixing compressor by Martelock, uses a 2 dimensional SSE taking 2 quantized predictions as input. Indirect SSE ISSE is a technique introduced paq9a Dec. 2007 and is a component ZPAQ. The idea is to use SSE as a direct prediction method rather than to refine existing prediction. However, SSE does not work well with high order contexts because the large table size uses too much memory. generally, a large model with lots of free parameters overfit the training data and have no predictive power for future input. As a general rule, a model should not be larger than the input it is trained on. ISSE does not use a 2-D table. Instead it first maps a context to a bit history as with indirect context map. Then the" ]
[ null ]
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https://www.whenknowingmatters.com/partial-solutions/?doing_wp_cron=1597362503.4345729351043701171875
[ "## Partial Solutions\n\nEducators can distribute an interactive applied learning activity with a partial solution. This is accomplished by creating the activity in CreatorBasic or CreatorAdvanced, loading it into Presenter as a learner would, and building a partial solution. This partially solved activity in Presenter is saved and distributed to learners.\n\nTwo examples of partially solved case scenarios are shown below. Learners would load each into their browser, complete the solution, and submit their finished work, or print out their solution for turning in prior to class or for peer review.\n\nThe third example demonstrates how learners would enter their answers in a paper-based bubble sheet system for automated grading. The entry in the solution with a 1 would correspond to the first multiple choice question on the bubble sheet and so on. In this particular example, answers for 1,2,and 3, would be interchangeable as would answers 4 and 5; 6 and 7; and 8,9, and 10.\n\nAnother option is to have four multiple choice questions that correspond to each grouping. In this example, 1 would remain as 1 corresponding to the first question, 4 would become 2 corresponding to the second question, 6 would become 3 corresponding to the third question, and 8 would become 4 corresponding to the fourth question. Questions 1 and 4 would have multiple choice options that included combinations of three observations, and questions 2 and 3 would have combinations of two.", null, "" ]
[ null, "https://www.whenknowingmatters.com/wp-content/uploads/2016/09/PaperBasedPrintOutFillIn.png", null ]
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https://chem.libretexts.org/Courses/University_of_California_Davis/UCD_Chem_110A%3A_Physical_Chemistry__I/UCD_Chem_110A%3A_Physical_Chemistry_I_(Larsen)/Lectures/05%3A_Wave_Equations
[ "# 5: Classical Wave Equations and Solutions (Lecture)\n\n•", null, "• Contributed by Delmar Larsen\n• Founder and Director at Libretexts\n\nLecture 4\n\nLast lecture addressed two important aspects: The Bohr atom and the Heisenberg Uncertainty Principle. The Bohr atom was introduced because is was the first successful description of a quantum atom from basic principles (either as a particle or as a wave, both were discussed). From a particle perspective, stable orbits are predicted from the result of opposing forces (Coloumb's force vs. centripetal force). From a wave perspective, stable \"standing waves\" are predicted when the wavelength of the electron is an integer factor of the circumference of the the orbit (otherwise it is not a standing wave and would destructively interfere with itself and disappear). The Bohr atom predicts quantized energies that can be related to Rydberg's phenomenological spectroscopic observation (and decompose his constant $$R$$ into fundamental properties of the universe and matter) via state-to-state transitions (importance for spectroscopy). This is really cool! The problem is that Bohr's theory only applied to hydrogen-like atoms (i..e, atoms or ions with a single electron). So, its quantitative utility for describing quantum chemistry is limited.\n\nHeisenberg's Uncertainty principle is very important and is the realization that trajectories do not exist in quantum mechanics. This is commonly expressed as\n\n$\\Delta{p}\\Delta{x} \\ge \\dfrac{h}{4\\pi} \\nonumber$\n\nand is associated with two properties (in this case, position $$x$$ and momentum $$p$$. As we will show later, not all properties are dictated by Heisenberg's Uncertainly principle. We will also provide a more solid mathematical description of calculating uncertainties (with the standard deviation of a distribution).\n\n## The Heisenberg Uncertainty Principle is responsible for stopping the collapse of the hydrogen atom\n\nAccording to classical mechanics, the electron would simply spiral into the nucleus and the atom would collapse. Quantum mechanics is a different story.", null, "Remember the classical death spiral of an electron around a nucleus. (CC BY; Stephen Lower)\n\nThe total energy of a particle is the sum of kinetic and potential energies\n\n$E= KE + PE$\n\nAs you know, the potential energy of an electron becomes more negative as it moves toward the attractive field of the nucleus; in fact, it approaches negative infinity. However, because the total energy remains constant (a hydrogen atom, sitting peacefully by itself, will neither lose nor acquire energy), the loss in potential energy is compensated for by an increase in the electron's kinetic energy (sometimes referred to in this context as \"confinement\" energy) which determines its momentum and its effective velocity.", null, "Potential energy curve for the Coulombic interactions between a negatively charged electron and a positively charged nucleus.\n\nThe Heisenberg principle says that either the location or the momentum of a quantum particle such as the electron can be known as precisely as desired, but as one of these quantities is specified more precisely, the value of the other becomes increasingly indeterminate.\n\nAs the electron approaches the tiny volume of space occupied by the nucleus, its potential energy dives down toward minus-infinity, and its kinetic energy (momentum and velocity) shoots up toward positive-infinity. This \"battle of the infinities\" cannot be won by either side, so a compromise is reached in which theory tells us that the fall in potential energy is just twice the kinetic energy, and the electron dances at an average distance that corresponds to the Bohr radius.\n\nExample\n\nAn electron is confined to the size of a magnesium atom with a 150 pm radius. What is the minimum uncertainty in its velocity?\n\n$\\Delta{p}\\Delta{x} \\ge \\dfrac{\\hbar}{2} \\nonumber$\n\ncan be written\n\n$\\Delta{p} \\ge \\dfrac{\\hbar}{2 \\Delta{x}} \\nonumber$\n\nand substituting $$\\Delta p=m \\Delta v$$ since the mass is not uncertain.\n\n$\\Delta{v} \\ge \\dfrac{\\hbar}{2\\; m\\; \\Delta{x}} \\nonumber$\n\nthe relevant parameters are\n\nmass of electron $$m=m_e= 9.109383 \\times 10^{-31}\\; kg$$ uncertainty in position: $$\\Delta x=150 \\times 10^{-12} m$$\n\n$\\Delta{v} \\ge \\dfrac{1.0545718 \\times 10^{-34} \\cancel{kg} m^{\\cancel{2}} / s}{(2)\\;( 9.109383 \\times 10^{-31} \\; \\cancel{kg}) \\; (150 \\times 10^{-12} \\; \\cancel{m}) } = 3.9 \\times 10^5\\; m/s \\nonumber$\n\n## Waves Overview\n\nTraveling waves, such as ocean waves or electromagnetic radiation, are waves which “move,” meaning that they have a frequency and are propagated through time and space. In contrast to traveling waves, standing waves, or stationary waves, remain in a constant position with crests and troughs in fixed intervals and specific spots of zero amplitude (node) and maximal amplitude (anti-nodes)", null, "Figure: One-dimensional traveling wave at as a function of time (green and blue curves). Traveling waves propagate energy from one spot to another with a fixed velocity. This is in contrast to a standard wave (red curve) (CC BY-SA 4.0 Internation; Lookangmany via Wikipedia)\n\nDissecting a Wave\n\nMathematically, the most basic wave is the (spatially) one-dimensional sine wave (or harmonic wave or sinusoid) with an amplitude $$u$$ described by the equation:\n\n$u(x,t) = A \\sin (kx - \\omega t + \\phi)$\n\nwhere\n\n• $$A$$ is the maximum amplitude of the wave, maximum distance from the highest point of the disturbance in the medium (the crest) to the equilibrium point during one wave cycle. In the illustration to the right, this is the maximum vertical distance between the baseline and the wave.\n• $$x$$ is the space coordinate\n• $$t$$ is the time coordinate\n• $$k$$ is the wavenumber\n• $$\\nu$$ is the natural frequency\n• $$\\omega$$ is the angular frequency (and $$\\omega= 2\\pi \\nu$$)\n• $$\\phi$$ is the phase (with with respect to what?)", null, "## The Wave Equation\n\nFor a one dimensional wave equation with a fixed length, the function $$u(x,t)$$ describes the position of a string at a specific $$x$$ and $$t$$ value. This leads to the classical wave equation\n\n$\\dfrac {\\partial^2 u}{\\partial x^2} = \\dfrac {1}{v^2} \\cdot \\dfrac {\\partial ^2 u}{\\partial t^2} \\label{W1}$\n\nwhere $$v$$ is the velocity of disturbance along the string. Setting boundary conditions as $$x=0$$, $$u(x=0,t) = 0$$ and $$x = \\ell$$, $$u(x=\\ell , t) = 0$$ allows for this partial differential equation to be solved (to see it in action in the lab see https://youtu.be/BSIw5SgUirg?t=17). Assuming the variables $$x$$ and $$t$$ are independent of each other makes this differential equation easier to solve, as you can use the Separation of Variables technique.\n\nThe separation of variables is common method for solving ordinary and partial differential equations, in which algebra allows one to rewrite an equation so that each of two variables occurs on a different side of the equation.\n\nIn this case, separation of variables \"anzatz\" says that\n\n$u(x,t) = X(x)T(t) \\label{ansatz}$\n\nAnsatz\n\n\"An ansatz is the establishment of the starting equation(s), the theorem(s), or the value(s) describing a mathematical or physical problem or solution. It can take into consideration boundary conditions. After an ansatz has been established (constituting nothing more than an assumption), the equations are solved for the general function of interest (constituting a confirmation of the assumption).\" - Wikipedia", null, "Substituting Equation \\ref{ansatz} into Equation $$\\ref{W1}$$ gives\n\n$T(t) \\cdot \\dfrac {\\partial ^2 X(x)}{\\partial x^2} = \\dfrac {X(x)}{v^2} \\cdot \\dfrac {\\partial ^2 T(t)}{\\partial t^2}$\n\nwhich simplifies to\n\n$\\dfrac {1}{X(x)} \\cdot \\dfrac {\\partial ^2 X(x)}{\\partial x^2} = \\dfrac {1}{T(t) v^2} \\cdot \\dfrac {\\partial ^2 T(t)}{\\partial t^2} = K$\n\nwhere $$K$$ is called the \"separation constant\". By setting each side equal to $$K$$, two 2nd order homogeneous ordinary differential equations are made.\n\n$\\dfrac {d^2 X(x)}{d x^2} - KX(x) = 0 \\label{spatial}$\n\nand\n\n$\\dfrac {d^2 T(t)}{d t^2} - K v^2 T(t) = 0 \\label{time}$\n\nWe are particular interest in this example with specific boundary conditions (the wave has zero amplitude at the ends).\n\n$u(x=0,t)=0$\n\n$u(x=L,t)=0$", null, "The boundary conditions for the wave solution forces it to be a standing wave (vs. a traveling wave)\n\nThis should sound familiar since we did it for the Bohr hydrogen atom (but with the line curved in on itself)\n\n### Solving the Spatial Part\n\nSolving the spatial part (Equation \\ref{spatial}):\n\n$\\dfrac {\\partial ^2 X(x)}{\\partial x^2} - KX(x) = 0 \\label{spatial1}$\n\nEquation \\ref{spatial} is a constant coefficient second order linear ordinary differential equation (ODE), which had general solution of\n\n$X(x) = A\\cdot \\cos \\left(a x \\right) + B\\cdot \\sin \\left(b x\\right) \\label{gen1}$\n\nHowever, these general solutions can be narrowed down by addressing the boundary conditions. Because of the separation of variables above, $$X(x)$$ has specific boundary conditions (that differ from $$T(t)$$):\n\n• $$X(x=0) = 0$$\n• $$X(x=\\ell) = 0$$.\n\nSo there is no way that any cosine function can satisfy the boundary condition (try it if you do not believe me) - hence, $$A=0$$. Moreover, only functions with wavelengths that are integer factors of half the length ($$i.e., n\\ell/2$$) will satisfy the boundary conditions. So Equation \\ref{gen1} simplifies to\n\n$X(x) = B\\cdot \\sin \\left(\\dfrac {n\\pi x}{\\ell}\\right)$\n\nwhere $$\\ell$$ is the length of the string, $$n = 1, 2, 3, ... \\infty$$, and $$B$$ is a constant. By substituting $$X(x)$$ into the partial differential equation for the temporal part (Equation \\ref{spatial1}), the separation constant is easily obtained to be\n\n$K = -\\left(\\dfrac {n\\pi}{\\ell}\\right)^2 \\label{Kequation}$", null, "The first seven $$X(x)$$ solutions of spatial part of the wave equation on a length $$\\ell$$ with two amplitudes (one positive and one negative). (CC BY-SA 3.0 Unported; Adjwilley via Wikipedia).\n\n### Solving the Temporal Part\n\nPlugging the value for $$K$$ from Equation \\ref{Kequation} into the temporal component (Equation \\ref{time}) and then solving to give the general solution (for the temporal behavior of the wave equation):\n\n$T(t) = D\\cos \\left(\\dfrac {n\\pi\\nu}{\\ell} t\\right) + E\\sin \\left(\\dfrac {n\\pi\\nu}{\\ell} t\\right) \\label{gentime}$\n\nwhere $$D$$ and $$E$$ are constants and $$n$$ is an integer ($$\\gt 1$$), which is shared between the spatial and temporal solutions.\n\nUnfortunately, we do not have the boundary conditions like with the spatial solution to simplify the expression of the general temporal solutions in Equation \\ref{gentime}. However, these solutions can be simplified with basic trigonometry identities to\n\n$T_n (t) = A_n \\cos \\left(\\dfrac {n\\pi\\nu}{\\ell} t +\\phi_n\\right) \\label{timetime}$\n\nwhere $$A_n$$ is the maximum displacement of the string (as a function of time), commonly known as amplitude, and $$\\phi_n$$ is the phase and $$n$$ is the number from required to establish the boundary conditions.\n\nTrig Identity\n\nThe evolution of Equation \\ref{gentime} into Equation \\ref{timetime} originates from the sum and difference trigonometric identites. This requires reformulating the $$D$$ and $$E$$ coefficients in Equation \\ref{gentime} in terms of two new constants $$A$$ and $$\\phi$$\n\n$D= A \\cos(\\phi) \\nonumber$\n\nand\n\n$E= A \\sin(\\phi) \\nonumber$\n\nEquation \\ref{gentime} then looks like\n\n$T(t) = A \\cos (\\phi) \\cos \\left(\\dfrac {n\\pi\\nu}{\\ell} t\\right) + A \\sin (\\phi) \\sin \\left(\\dfrac {n\\pi\\nu}{\\ell} t\\right) \\label{gentime3}$\n\nwe use the sum trigonometric identity:\n\n$\\cos (A+B) \\equiv \\cos\\;A ~ \\cos\\;B ~-~ \\sin\\;A ~ \\sin\\;B\\label{eqn:sumcos}$\n\nto rewrite rewrite Equation \\ref{gentime3} into Equation \\ref{timetime}.\n\n## The Total Package: The Spatio-temporal solutions are Standing Waves\n\nRemembering base the Anzatz in this procedure, $$u_n (x,t) = X(x) T(t)$$, and substituting in our determined $$X$$ and $$T$$ functions gives\n\n$u_n = A_n \\cos(\\omega_n t +\\phi_n) \\sin \\left(\\dfrac {n\\pi x}{\\ell}\\right)$\n\nThe first six wave solutions $$u(x,t;n)$$ are standing waves with frequencies based on the number of nodes (0, 1, 2, 3,...) they exhibit (more discussed in the following Section).", null, "The spatio-temporal standing waves solutions to the 1-D wave equation (a string). from Wikipedia.\n\nSince the acceleration of the wave amplitude is proportional to $$\\dfrac{\\partial^2}{\\partial x^2}$$, the greater curvature in the material produces a greater acceleration, i.e., greater changing velocity of the wave and greater frequency of oscillation. As discussed later, the higher frequency waves (i..e, more nodes) are higher energy solutions; this as expected from the experiments discussed in Chapter 1 including Plank's equation $$E=h\\nu$$.\n\nThe higher frequency waves are higher energy solutions.\n\n## Superposition\n\nSince the wave equation is a linear homogeneous differential equation, the total solution can be expressed as a sum of all possible solutions.\n\n\\begin{align} u(x,t) &= \\sum_{n=1}^{\\infty} a_n u_n(x,t) \\\\ &= \\sum_{n=1}^{\\infty} \\left( G_n \\cos (\\omega_n t) + H_n \\sin (\\omega_n t) \\right) \\sin \\left(\\dfrac{n\\pi x}{\\ell}\\right) \\end{align}\n\nThe waveform at a given time is a function of the sources (i.e., external forces, if any, that create or affect the wave) and initial conditions of the system. In many cases (for example, in the classic wave equation), the equation describing the wave is linear. When this is true, the superposition principle can be applied. That means that the net amplitude caused by two or more waves traversing the same space is the sum of the amplitudes which would have been produced by the individual waves separately. For example, two waves traveling towards each other will pass right through each other without any distortion on the other side.", null, "Two waves traveling in opposite directions across the same medium combine linearly. In this animation, both waves have the same wavelength and the sum of amplitudes results in a standing wave. (Public Domain; LucasVB)\n\nThe $$u_n(x,t)$$ solution is called a normal mode. This sort of expansion is ubiquitous in quantum mechanics.\n\nSuperposition in Action\n\nThis java applet is a simulation that demonstrates standing waves on a vibrating string. www.falstad.com/loadedstring/\n\nEverything above is a classical picture of wave, not specifically quantum, although they all apply. We will introduce quantum tomorrow and the waves will be wavefunctions. Since the Schrödinger equation (that is the quantum wave equation) is linear, the behavior of the original wave function can be computed through the superposition principle.\n\nExpansions are important for many aspects of quantum mechanics." ]
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https://tutorme.com/tutors/12214/interview/
[ "TutorMe homepage\nSubjects\nPRICING\nCOURSES\nSIGN IN\nStart Free Trial\nCorbin P.\nUndergraduate at The University of Rhode Island\nTutor Satisfaction Guarantee\nPre-Algebra\nTutorMe\nQuestion:\n\nSimplify the exponents: x^6+x^3\n\nCorbin P.\nAnswer:\n\nSo if exponents have the same base in an addition problem you can add the exponents together. x^6+x^3= x^9\n\nBasic Math\nTutorMe\nQuestion:\n\nAdd the fractions: (2/3) + (1/9)\n\nCorbin P.\nAnswer:\n\nTo start find you need to set the denominator to the same number: (2/3) * 3= (3/9) The simply add the numerators: (3/9)+(1/9)= (4/9)\n\nAlgebra\nTutorMe\nQuestion:\n\nPlease find the X intercept of the following equation. 3x-8y=13\n\nCorbin P.\nAnswer:\n\nTo find the answer you can start by setting Y equal to 0. 3x-0=13 Then solve for X. x= 13/3 So the X intercept is: (13/3,0)\n\nSend a message explaining your\nneeds and Corbin will reply soon.\nContact Corbin\nReady now? Request a lesson.\nStart Session\nFAQs\nWhat is a lesson?\nA lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.\nHow do I begin a lesson?\nIf the tutor is currently online, you can click the \"Start Session\" button above. If they are offline, you can always send them a message to schedule a lesson.\nWho are TutorMe tutors?\nMany of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you." ]
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https://www.techsource-asia.com/userstories-buildingiq
[ "## BuildingIQ Develops Proactive Algorithms for HVAC Energy Optimization in Large-Scale Buildings", null, "“MATLAB has helped accelerate our R&D and deployment with its robust numerical algorithms, extensive visualization and analytics tools, reliable optimization routines, support for object-oriented programming, and ability to run in the cloud with our production Java applications.”\n\n- Borislav Savkovic, BuildingIQ\n\nBuildingIQ has developed Predictive Energy Optimization™ (PEO), a cloud-based software platform that reduces HVAC energy consumption by 10–25% during normal operation. PEO was developed in cooperation with the Commonwealth Scientific and Industrial Research Organisation (CSIRO), Australia’s national science agency. Its advanced algorithms and machine learning methods, implemented in MATLAB®, continuously optimize HVAC performance based on near-term weather forecasts and energy cost signals.\n\n“CSIRO used MATLAB to develop the initial technology. We continue to use MATLAB because it is the best tool available for prototyping algorithms and performing advanced mathematical calculations,” says Borislav Savkovic, lead data scientist at BuildingIQ. “MATLAB enabled us to transition our prototype algorithms directly into production-level algorithms that deal reliably with real-world noise and uncertainty.”\n\n## Challenge\n\nBuildingIQ needed to develop algorithms that could continuously process gigabytes of information from a variety of sources, including power meters, thermometers, and HVAC pressure sensors, as well as weather and energy cost data. A single building often produces billions of data points, and the scientists and engineers needed tools for efficiently filtering, processing, and visualizing this data.\n\nTo run their optimization algorithms, the scientists and engineers had to create an accurate mathematical model of a building’s thermal and power dynamics. The algorithms would use this calculated model to run constrained optimizations that maintained occupant comfort while minimizing energy costs.\n\nBuildingIQ needed a way to rapidly develop mathematical models, test optimization and machine learning approaches, prototype algorithms, and deploy them into its production IT environment.", null, "## Solution\n\nBuildingIQ used MATLAB to speed up the development and deployment of its predictive energy optimization algorithms. The optimization workflow begins in MATLAB, where BuildingIQ engineers import and visualize 3 to 12 months of temperature, pressure, and power data comprising billions of data points. They use Statistics and Machine Learning Toolbox™ to detect spikes and gaps, and remove noise produced by sensor failures and other sources using filtering functions in Signal Processing Toolbox™. BuildingIQ engineers fitted a mathematical model developed in MATLAB to the denoised data using least squares fitting functions from Optimization Toolbox™. This measurement and verification (M&V) model correlates ambient temperature and humidity with power consumed by the HVAC system.\n\nAs part of the modeling process, they use SVM regression, Gaussian mixture models, and k-means clustering machine learning algorithms from Statistics and Machine Learning Toolbox to segment the data and determine the relative contributions of gas, electric, steam, and solar power to heating and cooling processes.\n\nThe team builds a PEO model in MATLAB that captures the effect of the HVAC system and ambient conditions on internal temperatures in each zone, as well as on the total power consumption for the building. Using Control System Toolbox™ they analyze HVAC control system poles and zeros to estimate overall power consumption and determine how quickly each zone is likely to converge to its set point.\n\nBuildingIQ engineers use Optimization Toolbox and the PEO model to run multi-objective optimizations with hundreds of parameters, as well as nonlinear cost functions and constraints to continuously optimize energy efficiency in real time. These optimizations take into account projected weather and energy prices over the next 12 hours, and identify optimal HVAC set points. In operation, Java® software in the cloud invokes the MATLAB optimization algorithms periodically throughout the day.\n\nEach day, BuildingIQ calculates baseline energy cost from the M&V model representing what the client would have paid for HVAC energy without the BuildingIQ PEO platform. Savings range from 10% to 25%.\n\n## ​\n\n• Gigabytes of data analyzed and visualized. “MATLAB makes it easy to process and visualize the big data sets we work with,” says Savkovic. “We create scatter plots, 2D and 3D graphs, and other charts that display in a meaningful way how our system is performing.”\n\n• Algorithm development speed increased tenfold. “Developing algorithms in MATLAB is 10 times faster and more robust than developing in Java,” says Savkovic. “We need to filter our data, look at poles and zeroes, run nonlinear optimizations, and perform numerous other tasks. In MATLAB, those capabilities are all integrated, robust, and commercially validated.”\n\n• Best algorithmic approaches quickly identified. “With MATLAB we can rapidly test new approaches to find the one that works best for our data,” says Savkovic. “For example, we tested several optimization approaches before selecting sequential quadratic programming, and we tried several clustering machine learning algorithms. It’s a huge advantage to explore different methods so quickly.”" ]
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https://mathematica.stackexchange.com/questions/3186/ad-hoc-graphics-primitives-like-objects
[ "# Ad hoc graphics primitives-like objects\n\nSphere is one of the three-dimensional graphics primitives available in Mathematica and can be easily used to created very useful images. For instance, in the figure below I created three images of an ellipsoidal object that is lit from a fixed direction and it is then just rotated around the z-axis.\n\nGraphicsRow[\nTable[\nGraphics3D[\nRotate[Scale[{GrayLevel[.7], Sphere[]}, {1, 1.5, 1}, {0, 0, 0}],\ni Degree, {0, 0, 1}], PlotRange -> {{-2, 2}, {-2, 2}, {-2, 2}},\nAspectRatio -> 1, Background -> Black, Boxed -> False,\nViewPoint -> Front, SphericalRegion -> True,\nLighting -> {{\"Directional\", White, ImageScaled[{0, 0, 1}]}}\n], {i, {0, 45, 90}}]]", null, "Suppose that instead of using the ellipsoidal object I would like to use an object like this bump:\n\nPlot3D[Exp[-(x^2 + y^2)], {x, -2, 2}, {y, -2, 2}]", null, "Is there a way to create a \"graphics primitive\" object of the bump, so as to just use it instead of Sphere in the above example?\n\nI suppose there should be a way to extract all the polygons specifying the shape of the bump, but I couldn't find a way to do it. Any other approach is also more than welcome.\n\nThe result of Plot3D and related functions is something of the form Graphics3D[primitives, options], so to extract the graphics primitives you can simply take the first part of the plot. These can then be manipulated similar to Sphere[] in your example, e.g.\n\nplot = Plot3D[Exp[-(x^2 + y^2)], {x, -2, 2}, {y, -2, 2}][];\n\nGraphicsRow[\nTable[Graphics3D[\nRotate[Scale[{GrayLevel[.7], plot}, {1, 1.5, 1}, {0, 0, 0}],\ni Degree, {0, 0, 1}], PlotRange -> {{-2, 2}, {-2, 2}, {-2, 2}},\nAspectRatio -> 1, Background -> Black, Boxed -> False,\nViewPoint -> Front, SphericalRegion -> True,\nLighting -> {{\"Directional\", White,\nImageScaled[{0, 0, 1}]}}], {i, {0, 45, 90}}]]", null, "• Nice use of [] to extract the GraphicsComplex from the plot! Mar 19, 2012 at 14:22\n• Or slightly more transparently: Cases[(* stuff *), _GraphicsComplex, Infinity] // First. Mar 19, 2012 at 15:21\n• Or if you are baffled by GraphicsComplex, try Cases[Normal[plot], _Polygon, Infinity] which will return the (many many) constituting polygons. Mar 19, 2012 at 16:34\n\nI think what you're looking for is BSplineSurface. For your given example, try:\n\ncpts = Table[{x, y, Exp[-(x^2 + y^2)]}, {x, -2, 2, 0.1}, {y, -2, 2,\n0.1}];\n\nGraphics3D[BSplineSurface[cpts], Boxed -> False]\n\n\nWhich gives:", null, "" ]
[ null, "https://i.stack.imgur.com/qSTdb.png", null, "https://i.stack.imgur.com/Hjfn5.png", null, "https://i.stack.imgur.com/GSjIJ.png", null, "https://i.stack.imgur.com/koYGe.png", null ]
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https://ans.disi.unitn.it/redmine/projects/community-newtork-emulator/repository/mininet/revisions/f4d9e05d05631cf2671822f99108374cfcbd8b41/entry/examples/linearBandwidth.py
[ "Statistics\n| Branch: | Tag: | Revision:\n\n## mininet / examples / linearBandwidth.py @ f4d9e05d\n\n 1 ```#!/usr/bin/python ``` ```\"\"\" ``` ```Test bandwidth on linear networks of varying size, using both ``` ```the kernel and user datapaths. ``` ``` ``` ```Each network looks like: ``` ``` ``` ```h0 <-> s0 <-> s1 .. sN <-> h1 ``` ``` ``` ```Note: by default, the reference controller only supports 16 ``` ```switches, so this test WILL NOT WORK unless you have recompiled ``` ```your controller to support a 100 switches (or more.) ``` ``` ``` ```\"\"\" ``` ``` ``` ```from mininet import init, LinearNet, iperfTest ``` ```def linearBandwidthTest(): ``` ``` datapaths = [ 'kernel', 'user' ] ``` ``` switchCounts = [ 1, 20, 40, 60, 80, 100 ] ``` ``` results = {} ``` ``` for datapath in datapaths: ``` ``` k = datapath == 'kernel' ``` ``` results[ datapath ] = [] ``` ``` for switchCount in switchCounts: ``` ``` print \"*** Creating linear network of size\", switchCount ``` ``` network = LinearNet( switchCount, k) ``` ``` bandwidth = network.run( iperfTest ) ``` ``` results[ datapath ] += [ ( switchCount, bandwidth ) ] ``` ``` ``` ``` for datapath in datapaths: ``` ``` print ``` ``` print \"*** Linear network results for\", datapath, \"datapath:\" ``` ``` print ``` ``` result = results[ datapath ] ``` ``` print \"SwitchCount\\tiPerf results\" ``` ``` for switchCount, bandwidth in result: ``` ``` print switchCount, '\\t\\t', ``` ``` print bandwidth[ 0 ], 'server, ', bandwidth[ 1 ], 'client' ``` ``` print ``` ``` print ``` ``` ``` ```if __name__ == '__main__': ``` ``` init() ``` ``` print \"*** Running linearBandwidthTest\" ``` ``` linearBandwidthTest() ``` ``` exit( 1 ) ``` ``` ```" ]
[ null ]
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https://stats.stackexchange.com/questions/491625/meaning-of-the-weight-argument-in-glmer-and-lmer
[ "# Meaning of the weight argument in glmer and lmer\n\nI have been looking into how to use the weight argument of glmer/lmer to represent \"frequency\" weights. I was comparing model estimations with an expanded dataset, with the frequency weights inputted directly to the weight argument, and with the weights scaled as in Method A in Carle 20091 (i.e. scaled such that their sum matches the number of observations). I have found a puzzling difference in how they affect the results.\n\nSpecifically:\n\n• lmer gives identical results for scaled and unscaled weights, but different results with the expanded dataset\n• glmer gives identical results with the unscaled weights as with the expanded dataset, but different results with the scaled weights\n\nCould anybody clarify what is the reason for the difference?\n\nBackgroud\n\nI want to compare performance of two groups on a cognitive psychology task. The groups have been matched by a collaborator according to relevant covariates (e.g. socioeconomic status) and as a result few participants from the control group have a frequency weight of 2, indicating that they should be counted twice in the analyses in order for the groups to be matched on all the covariates. I would like to use multilevel models, and I am trying to see if I can use the frequency weight with the weight argument of lme4 (Note: I am not sure of whether frequency weight is the correct term here; perhaps sampling weight is more appropriate). The dependent variable is binomial, so we'd need to use a GLMM.\n\nToy example:\n\nGenerate some data\n\n# covariance matrix\nsigma = matrix(c(1, 0.7, 0.7, 1), ncol = 2)\n\n# simulate data\nset.seed(4321)\ndf = mvrnorm(n = 100, mu = c(0,0), Sigma = sigma)\n\n# Simulate clustering and calculate weights\ndf = data.frame(df)\nnames(df) = c(\"Y\", \"X\")\ndf$cluster = rep(1:10, each = 10) df = within(df, { Y = Y + cluster/10 X = X + cluster/10 weights = rep(1:2, each = 50) scaled_weights = weights*2/3 }) #data set with double weighted observations entered twice df2 = rbind(df, df[51:100,]) Effects of weights in lmer. Here the models with weights gives the same results, regardless of the scaling, and the model with the expanded dataset gives different estimates. # Models m.weights = lmer(Y ~ X + (1 | cluster), df, weights = weights) # weights m.double = lmer(Y ~ X + (1 | cluster), df2) # expanded dataset m.scaled = lmer(Y ~ X + (1 | cluster), df, weights = scaled_weights) #scaled weights round(summary(m.weights)$coef,digits=4)\n# Estimate Std. Error t value\n# (Intercept) 0.2498 0.0904 2.7645\n# X 0.6908 0.0658 10.4928\nround(summary(m.scaled)$coef,digits=4) # SAME AS m.weights # Estimate Std. Error t value # (Intercept) 0.2498 0.0904 2.7645 # X 0.6908 0.0658 10.4928 round(summary(m.double)$coef,digits=4) # DIFFERENT\n# Estimate Std. Error t value\n# (Intercept) 0.2445 0.0842 2.9029\n# X 0.6847 0.0538 12.7332\n\n\nEffects of weights in glmer\n\n# discretize dependent variable in 2 levels\ndf$$dY <- ifelse(df$$Y>0.8,1,0)\ndf2$$dY <- ifelse(df2$$Y>0.8,1,0)\n\nm2.weights = glmer(dY ~ X + (1 | cluster), df, weights = weights, family =binomial) # weights (unscaled)\nm2.double = glmer(dY ~ X + (1 | cluster), df2, family =binomial) # expanded dataset\nm2.scaled = glmer(dY ~ X + (1 | cluster), df, weights = scaled_weights, family =binomial) # scaled weights\n# Warning message:\n# In eval(family$initialize, rho) : non-integer #successes in a binomial glm! Note that the model with scaled weights give a warning, because in glm(er) the weights should correspond to the number of trials when the dependent variable is the proportion of successes. However as I understand them the weights are taken into account in the log-likelihood as $$\\log\\mathcal{L}(\\boldsymbol{\\theta}) = \\sum_{i = 1}^{n} w_i \\log \\left[ p(y_i | \\boldsymbol{x}_i,\\boldsymbol{\\theta})\\right]$$ where $$w_i$$ is the weight. If that's correct, each observation $$i$$ contributes $$w_i$$ times its log-likelihood to the total log-likelihood, which should be the same as saying that each $$i$$ represents $$w_i$$ observations. (Since this is what I would like to express with the weights, I thought I could use this argument for my purposes). Furthermore, based on this I would expect to find that the model with the unscaled weight and that with the expanded dataset to give similar or identical results, and indeed that is what I find - in this case is the model with scaled weights that differs from the other two. round(summary(m2.weights)$coef,digits=4)\n# Estimate Std. Error z value Pr(>|z|)\n# (Intercept) -1.3028 0.3902 -3.3390 8e-04\n# X 1.5741 0.2955 5.3263 0e+00\nround(summary(m2.scaled)$coef,digits=4) # DIFFERENT # Estimate Std. Error z value Pr(>|z|) # (Intercept) -1.2620 0.4183 -3.0167 0.0026 # X 1.5579 0.3531 4.4114 0.0000 round(summary(m2.double)$coef,digits=4) # SAME as m.weights\n# Estimate Std. Error z value Pr(>|z|)\n# (Intercept) -1.3028 0.3902 -3.3390 8e-04\n# X 1.5741 0.2955 5.3263 0e+00\n\n\n1 Carle, A. C. (2009). Fitting multilevel models in complex survey data with design weights: Recommendations. BMC Medical Research Methodology, 9 (1), 1–13." ]
[ null ]
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https://godstamps.blogspot.com/2015/10/unity-unityengineevents.html
[ "## 2015年10月25日 星期日\n\n### Unity:使用 UnityEngine.Events 讓程式更靈活、穩定", null, "public 的變數欄位會出現在 Inspector 視窗,可供編輯。", null, "有 SerializeField 的 private 變數欄位也會出現在 Inspector 視窗。", null, "UnityEvent 型別的變數欄位,在 Inspector 視窗會出現事件欄位。\n這個 UnityEvent 欄位在編輯器上的編輯相當彈性,當目標 Component 裡面含有使用 public 宣告的屬性(Property)或方法(Method),並且傳入值的型別為 bool、int、float、string 其中一種的話,就能直接在這裡選擇並提供傳入的值,而且可以設置多個不同型別的目標,並在之後程式執行時直接呼叫執行,另外,如果 Method 並沒有宣告傳入參數的話,在此也可以選擇設置,如果是宣告兩個以上的參數,在這邊的選單就不會出現了。\n\n[System.Serializable]\npublic class PassString : UnityEvent<string>{}\n\n[System.Serializable]\npublic class PassColor : UnityEvent<Color>{}\n\n## 1. Simple Computer\n\n• 點擊運算功能按鈕,會依照計算種類去改變運算符號的文字。\n• 點擊運算功能按鈕之後,在 UI 顯示計算結果文字。\n\nusing UnityEngine.Events;\n\n[System.Serializable]\npublic class PassString : UnityEvent<string>{}\n\nprivate float _value1;\nprivate float _value2;\n\n[SerializeField]\n[SerializeField]\nprivate PassString onSubtract;\n[SerializeField]\nprivate PassString onMultiply;\n[SerializeField]\nprivate PassString onDivide;\n\npublic string value1{\nset{\nfloat.TryParse(value , out this._value1);\n}\n}\n\npublic string value2{\nset{\nfloat.TryParse(value , out this._value2);\n}\n}\n\n}\n\npublic void Subtract(){\n\nthis.onSubtract.Invoke((this._value1 - this._value2).ToString());\n}\n\npublic void Multiply(){\n\nthis.onMultiply.Invoke((this._value1 * this._value2).ToString());\n}\n\npublic void Divide(){\n\nif(this._value2 == 0) return;\n\nthis.onDivide.Invoke((this._value1 / this._value2).ToString());\n}", null, "MyConputer 出現加、減、乘、除的事件欄位。", null, "Value1 Field 輸入的字串傳給 MyComputer 的 value1", null, "Value2 Field 輸入的字串傳給 MyComputer 的 value2", null, "Button + 的 On Click 事件執行 MyComputer 的 Add()", null, "Button - 的 On Click 事件執行 MyComputer 的 Subtract()", null, "Button x 的 On Click 事件執行 MyComputer 的 Multiply()", null, "Button / 的 On Click 事件執行 MyComputer 的 Divide()", null, "每個計算功能事件讓 UI 變更運算符號以及顯示計算結果", null, "計算結果的畫面", null, "計算結果之後關閉按鈕。", null, "計算過的按鈕都關閉了。\n\n[SerializeField]\nprivate UnityEvent onResetStatus;\n\npublic void ResetStatus(){\n\nthis.onResetStatus.Invoke();\n}", null, "狀態重置時,再次啟用按鈕。", null, "End Edit 事件指定執行 MyComputer 的 ResetStatus()。", null, "更改為先執行狀態重置之後,才去執行其他行為。\n\nusing UnityEngine;\nusing UnityEngine.Events;\n\npublic class MyComputer : MonoBehaviour {\n\nprivate float _value1;\nprivate float _value2;\n\n[SerializeField]\n[SerializeField]\nprivate PassString onSubtract;\n[SerializeField]\nprivate PassString onMultiply;\n[SerializeField]\nprivate PassString onDivide;\n[SerializeField]\nprivate UnityEvent onResetStatus;\n\npublic string value1{\nset{\nfloat.TryParse(value , out this._value1);\n}\n}\n\npublic string value2{\nset{\nfloat.TryParse(value , out this._value2);\n}\n}\n\n}\n\npublic void Subtract(){\n\nthis.onSubtract.Invoke((this._value1 - this._value2).ToString());\n}\n\npublic void Multiply(){\n\nthis.onMultiply.Invoke((this._value1 * this._value2).ToString());\n}\n\npublic void Divide(){\nif(this._value2 == 0) return;\nthis.onDivide.Invoke((this._value1 / this._value2).ToString());\n}\n\npublic void ResetStatus(){\n\nthis.onResetStatus.Invoke();\n}\n}\n\n## 2. Sphere Control", null, "原生物件球體的 Componet。\n\n• 球體可以被點擊觸發。\n• 球體可以彈跳起來。\n• 球體可以變色。\n\nusing UnityEngine;\nusing UnityEngine.Events;\n\npublic class SphereTouch : MonoBehaviour {\n\n[SerializeField]\nprivate UnityEvent onTouch;\n\npublic void DoTouch(){\n\nthis.onTouch.Invoke();\n}\n\nvoid OnMouseDown(){\n\nthis.DoTouch();\n}\n}\n\n[SerializeField]\nprivate float hight = 1;\n[SerializeField]\nprivate float speed = 5;\n\nprivate enum Status{\n\nNone,\nMoving\n}\n\nprivate Status _status = Status.None;\n\nprivate IEnumerator Move(Vector3 source , Vector3 target){\n\nfloat t = 0;\n\nwhile(t < 1){\n\ntransform.position = Vector3.Lerp(source , target , t);\nt += Time.deltaTime * this.speed;\n\nyield return null;\n}\n\ntransform.position = target;\n}\n\nVector3.Lerp 的 t 是介於 0 到 1 的值,我們可以把它當作是起點到終點的進度位置來看待,0 是起點,1 是終點。因為實際執行時每次刷新畫面的時間都不一樣,所以,我們不能讓 t 隨著時間的推移增加固定的值,而應該要為我們預計增加的值(即是速度)乘上 Time.deltaTime,於是,我們在這裡透過 yield return null 讓 while 迴圈每經過一個 frame 才執行一次,當 t 超過 1 的時候,表示已經到達終點,即可結束迴圈。\n\nprivate IEnumerator DoJump(){\n\nthis._status = Status.Moving;\n\nVector3 source = transform.position;\nVector3 target = source;\ntarget.y += this.hight;\n\nyield return StartCoroutine(this.Move(source , target));\nyield return StartCoroutine(this.Move(target , source));\n\nthis._status = Status.None;\n}\n\npublic void Jump(){\n\nif(this._status == Status.None) StartCoroutine(this.DoJump());\n}\n\nusing UnityEngine;\nusing System.Collections;\n\npublic class SphereJump : MonoBehaviour {\n\nprivate enum Status{\n\nNone,\nMoving\n}\n\n[SerializeField]\nprivate float hight = 1;\n[SerializeField]\nprivate float speed = 5;\n\nprivate Status _status = Status.None;\n\npublic void Jump(){\n\nif(this._status == Status.None) StartCoroutine(this.DoJump());\n}\n\nprivate IEnumerator Move(Vector3 source , Vector3 target){\n\nfloat t = 0;\n\nwhile(t < 1){\n\ntransform.position = Vector3.Lerp(source , target , t);\nt += Time.deltaTime * this.speed;\n\nyield return null;\n}\n\ntransform.position = target;\n}\n\nprivate IEnumerator DoJump(){\n\nthis._status = Status.Moving;\n\nVector3 source = transform.position;\nVector3 target = source;\ntarget.y += this.hight;\n\nyield return StartCoroutine(this.Move(source , target));\nyield return StartCoroutine(this.Move(target , source));\n\nthis._status = Status.None;\n}\n}\n\n[System.Serializable]\npublic class PassColor : UnityEvent<Color>{}\n\nprivate Material _material;\nprivate Color _color;\n\n[SerializeField]\nprivate Color color = Color.white;\n\nvoid Awake(){\n\nthis._material = GetComponent<Renderer>().material;\nthis.DefaultColor();\n}\n\npublic void DefaultColor(){\n\nthis._material.color = this.color;\nthis._color = this.color;\n}\n\n[SerializeField]\nprivate PassColor onChangeColor;\n\nvoid Awake(){\n\nthis._material = GetComponent<Renderer>().material;\nthis.DefaultColor();\n}\n\npublic void DefaultColor(){\n\nthis._material.color = this.color;\nthis._color = this.color;\n}\n\npublic void Discolor(Color color){\n\nthis._material.color = color;\nthis._color = color;\nthis.onChangeColor.Invoke(color);\n}\n\npublic void RandomColor(){\n\nthis.Discolor(new Color(Random.value , Random.value , Random.value));\n}", null, "第 2 顆球設置被點擊時,第三顆球跳起來,第一顆球隨機改變顏色。", null, "第五顆球被點擊時,前四顆球改變成初始顏色。", null, "第二顆球變色的時候,讓第一顆球和第五顆球改變為隨機的顏色。\n\npublic class PassHolder {\n\npublic object value{set; private get;}\n\npublic T GetValue<T>(){\n\nif(this.value == null) return default(T);\n\nreturn (T)this.value;\n}\n}\n\n[System.Serializable]\npublic class PassColorReturn : UnityEvent<Color , PassHolder>{}\n\n[SerializeField]\nprivate PassColorReturn onSwapColor;\n\npublic void SwapColor(){\n\nPassHolder holder = new PassHolder();\nthis.onSwapColor.Invoke(this._color , holder);\nthis.Discolor(holder.GetValue<Color>());\n}\n\npublic void Discolor(Color color , PassHolder holder){\n\nholder.value = this._color;\nthis.Discolor(color);\n}", null, "當第四顆球被點擊時,使第五顆球跳起來、第三顆球改變顏色、要求自己執行交換顏色並指明與第一顆球交換顏色。\n\nhttps://onedrive.live.com/redir?resid=D13D8A29206AFE69!263&authkey=!AMLBuBYFzZsVtOg&ithint=file%2czip" ]
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https://www.thermal-engineering.org/what-is-emissivity-emissivity-of-materials-definition/
[ "# What is Emissivity – Emissivity of Materials – Definition\n\nThe emissivity, ε, of the surface of a material is its effectiveness in emitting energy as thermal radiation and varies between 0.0 and 1.0.Emissivity of Materials\n\n## Emissivity\n\nThe emissivity, ε, of the surface of a material is its effectiveness in emitting energy as thermal radiation and varies between 0.0 and 1.0.", null, "By definition, a blackbody in thermal equilibrium has an emissivity of ε = 1.0. Real objects do not radiate as much heat as a perfect black body. They radiate less heat than a black body and therefore are called gray bodies. To take into account the fact that real objects are gray bodies, the Stefan-Boltzmann law must include emissivity. Quantitatively, emissivity is the ratio of the thermal radiation from a surface to the radiation from an ideal black surface at the same temperature as given by the Stefan–Boltzmann law. Emissivity is simply a factor by which we multiply the black body heat transfer to take into account that the black body is the ideal case.\n\nThe surface of a blackbody emits thermal radiation at the rate of approximately 448 watts per square metre at room temperature (25 °C, 298.15 K). Real objects with emissivities less than 1.0 (e.g. copper wire) emit radiation at correspondingly lower rates (e.g. 448 x 0.03 = 13.4 W/m2). Emissivity plays important role in heat transfer problems. For example, solar heat collectors incorporate selective surfaces that have very low emissivities. These collectors waste very little of the solar energy through emission of thermal radiation.\n\nAnother important radiation property of a surface is its absorptivityα, which is the fraction of the radiation energy incident on a surface that is absorbed by the surface. Like emissivity, value of absorptivity is in the range 0 < α < 1.\n\nIn general, the absorptivity and the emissivity are interconnected by the Kirchhoff’s Law of thermal radiation, which states:\n\nFor an arbitrary body emitting and absorbing thermal radiation in thermodynamic equilibrium, the emissivity is equal to the absorptivity.\n\nemissivity ε = absorptivity α\n\nNote that visible radiation occupies a very narrow band of the spectrum from 400 to 760 nm, we cannot make any judgments about the blackness of a surface on the basis of visual observations. For example, consider white paper that reflects visible light and thus appear white. On the other hand it is essentially black for infrared radiation (absorptivity α = 0.94) since they strongly absorb long-wavelength radiation.\n\nReferences:\nHeat Transfer:\n1. Fundamentals of Heat and Mass Transfer, 7th Edition. Theodore L. Bergman, Adrienne S. Lavine, Frank P. Incropera. John Wiley & Sons, Incorporated, 2011. ISBN: 9781118137253.\n2. Heat and Mass Transfer. Yunus A. Cengel. McGraw-Hill Education, 2011. ISBN: 9780071077866.\n3. U.S. Department of Energy, Thermodynamics, Heat Transfer and Fluid Flow. DOE Fundamentals Handbook, Volume 2 of 3. May 2016.\n\nNuclear and Reactor Physics:\n\n1. J. R. Lamarsh, Introduction to Nuclear Reactor Theory, 2nd ed., Addison-Wesley, Reading, MA (1983).\n2. J. R. Lamarsh, A. J. Baratta, Introduction to Nuclear Engineering, 3d ed., Prentice-Hall, 2001, ISBN: 0-201-82498-1.\n3. W. M. Stacey, Nuclear Reactor Physics, John Wiley & Sons, 2001, ISBN: 0- 471-39127-1.\n4. Glasstone, Sesonske. Nuclear Reactor Engineering: Reactor Systems Engineering, Springer; 4th edition, 1994, ISBN: 978-0412985317\n5. W.S.C. Williams. Nuclear and Particle Physics. Clarendon Press; 1 edition, 1991, ISBN: 978-0198520467\n6. G.R.Keepin. Physics of Nuclear Kinetics. Addison-Wesley Pub. Co; 1st edition, 1965\n7. Robert Reed Burn, Introduction to Nuclear Reactor Operation, 1988.\n8. U.S. Department of Energy, Nuclear Physics and Reactor Theory. DOE Fundamentals Handbook, Volume 1 and 2. January 1993.\n9. Paul Reuss, Neutron Physics. EDP Sciences, 2008. ISBN: 978-2759800414." ]
[ null, "https://thermal-engineering.org/wp-content/uploads/2019/05/emissivity-of-various-material-table-226x300.png", null ]
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https://www.numbersaplenty.com/7553522
[ "Search a number\nBaseRepresentation\nbin11100110100000111110010\n3112012202111002\n4130310013302\n53413203042\n6425522002\n7121126634\noct34640762\n915182432\n107553522\n11429a089\n122643302\n131746152\n141008a54\n159e3132\nhex7341f2\n\n7553522 has 16 divisors (see below), whose sum is σ = 12206592. Its totient is φ = 3495360.\n\nThe previous prime is 7553521. The next prime is 7553531. The reversal of 7553522 is 2253557.\n\nIt is a super-3 number, since 3×75535223 (a number of 22 digits) contains 333 as substring.\n\nIt is not an unprimeable number, because it can be changed into a prime (7553521) by changing a digit.\n\nIt is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1223 + ... + 4074.\n\nIt is an arithmetic number, because the mean of its divisors is an integer number (762912).\n\nAlmost surely, 27553522 is an apocalyptic number.\n\n7553522 is a deficient number, since it is larger than the sum of its proper divisors (4653070).\n\n7553522 is a wasteful number, since it uses less digits than its factorization.\n\n7553522 is an evil number, because the sum of its binary digits is even.\n\nThe sum of its prime factors is 5353.\n\nThe product of its digits is 10500, while the sum is 29.\n\nThe square root of 7553522 is about 2748.3671516011. The cubic root of 7553522 is about 196.2079044768.\n\nIt can be divided in two parts, 75535 and 22, that added together give a palindrome (75557).\n\nThe spelling of 7553522 in words is \"seven million, five hundred fifty-three thousand, five hundred twenty-two\"." ]
[ null ]
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https://code.tutsplus.com/tutorials/the-binary-search-algorithm-in-javascript--cms-30003?_ga=2.166945853.2025844634.1544813532-1070940998.1539463761
[ "Unlimited Plugins, WordPress themes, videos & courses! Unlimited asset downloads! From \\$16.50/m\nAdvertisement", null, "# The Binary Search Algorithm in JavaScript\n\nDifficulty:IntermediateLength:MediumLanguages:\n\nIn this post, I'll compare linear search and binary search algorithms. You'll see pseudocode for each algorithm, along with examples and a step-by-step guide to implementing each.\n\n## Introduction\n\nAs a programmer, you want to find the best solution to a problem so that your code is not only correct but also efficient. Choosing a suboptimal algorithm could mean a longer completion time, increased code complexity, or worse a program that crashes.\n\nYou may have used a search algorithm to locate items in a collection of data. The JavaScript language has several methods, like `find`, to locate items in an array. However, these methods use linear search. A linear search algorithm starts at the beginning of a list and compares each element with the search value until it is found.\n\nThis is fine when you have a small number of elements. But when you are searching large lists that have thousands or millions of elements, you need a better way to locate items. This is when you would use binary search.\n\nIn this tutorial, I will explain how binary search works and how to implement the algorithm in JavaScript. First, we will review the linear search algorithm.\n\n## Linear Search\n\nWe will begin by explaining how to implement linear search in JavaScript. We will create a function called `linearSearch` that accepts a value that is an integer or string and an array as parameters. The function will search every element in the array for the value and return the position of the value in the array if it is found. If the value is not in the array, it will return -1. For example, calling `linearSearch(1, [3, 4, 2, 1, 5])` would return 3, and calling `linearSearch(0, [3, 4, 2, 1, 5])` would return -1.\n\nHere's some pseudocode for our function:\n\n### JavaScript Implementation of Linear Search\n\nHere is a JavaScript implementation of the linear search algorithm:\n\nIt is important to note that the linear search algorithm does not need to use a sorted list. Also, the algorithm can be customized for use in different scenarios like searching for an array of objects by key. If you have an array of customer data that includes keys for the first and last name, you could test if the array has a customer with a specified first name. In that case, instead of checking if `list[index]` is equal to our search value, you would check for `list[index].first`.\n\nIn the example above, I used the `linearSearch` function on an array with five elements. In the worst case, when the search value is not in the list or is at the end of the list, the function would have to make five comparisons. Because our array is so small, there is no need to optimize by using a different algorithm. However, beyond a certain point, it is no longer efficient to use a linear search algorithm, and that is when using a binary search algorithm would be better.\n\n## Binary Search\n\nImagine you are playing a number guessing game. You are asked to guess a number between 1 and 100. If your number is too high or too low, you will get a hint.\n\nWhat would your strategy be? Would you choose numbers randomly? Would you start with 1, then 2, and so on until you guessed correctly? Even if you had unlimited guesses, you want to make the correct guess in as few tries as possible. Therefore, you might start by guessing 50. If the number is higher, you could guess 75. If it is lower, then that means the number is between 50 and 75, and you would choose a number that's in the middle. You would go on like this until you arrived at the correct number. This is similar to how binary search works.\n\nUnlike linear search, binary search uses a sorted list. To search for a value, you first compare the value to the middle element of the list. If they are equal, the search value has been found. If the search value is greater than the middle element, you search the top half of the data. You then compare the middle element of this section to the search value. Alternatively, if the item is less than the middle element, you search the bottom half of the list and compare its middle value. The list is repeatedly divided in half until the element is found or there are no more items to search.\n\nTo search for 9 in the list:\n\nWe first find the middle element. This is the element at position `Math.floor((first + last)/2)`, where `first` is the first index, and `last` is the last index. We choose to round down so that if the result is a fraction, it becomes a whole number. The middle element in this list is 5. Our search value 9 is greater than 5, so we search the list:\n\nThe middle element of this portion is 8. Nine is greater than 8, so we search the list:\n\nThe middle element is 9, so we can stop our search here.\n\nHere's some pseudocode that expresses the above algorithm for binary search:\n\n### JavaScript Implementation of Binary Search\n\nNow let's code the binary search algorithm in JavaScript!\n\nWe'll create a function, `binarySearch`, that accepts a value and an array as parameters. It will return the index where the value occurs in the list if found. If the value is not found, it returns -1. This is our implementation written in JavaScript:\n\n## Conclusion\n\nIn this tutorial, we saw how to implement a linear search and a binary search algorithm. The linear search algorithm is simpler and doesn't require a sorted array. However, it is inefficient to use with larger arrays. In the worst case, the algorithm would have to search all elements making n comparisons (where n is the number of elements).\n\nThe binary search algorithm, on the other hand, requires you to sort the array first and is more complicated to implement. However, it is more efficient even when considering the cost of sorting. For example, an array with 10 elements would make at most 4 comparisons for a binary search vs. 10 for a linear search—not such a big improvement. However, for an array with 1,000,000 elements, the worst case in binary search is only 20 comparisons. That's a huge improvement over linear search!\n\nKnowing how to use binary search isn't just something to practice for an interview question. It's a practical skill that can make your code work much more efficiently.\n\nAdvertisement\nAdvertisement" ]
[ null, "https://static.tutsplus.com/packs/media/images/redesign/code-de8b2a5e820f2e4ee056ef0473787806.svg", null ]
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https://api.flutter.dev/flutter/vector_math/Quaternion-class.html
[ "# Quaternion class Null safety\n\nDefines a Quaternion (a four-dimensional vector) for efficient rotation calculations.\n\nQuaternion are better for interpolating between rotations and avoid the gimbal lock problem compared to euler rotations.\n\n## Constructors\n\nQuaternion(double x, double y, double z, )\nConstructs a quaternion using the raw values `x`, `y`, `z`, and `w`.\nfactory\nQuaternion.axisAngle(Vector3 axis, double angle)\nConstructs a quaternion from a rotation of `angle` around `axis`.\nfactory\nQuaternion.copy(Quaternion original)\nConstructs a quaternion as a copy of `original`.\nfactory\nQuaternion.dq(Vector3 omega)\nConstructs a quaternion from time derivative of `q` with angular velocity `omega`.\nfactory\nQuaternion.euler(double yaw, double pitch, double roll)\nConstructs a quaternion from `yaw`, `pitch` and `roll`.\nfactory\nQuaternion.fromBuffer(ByteBuffer buffer, int offset)\nConstructs a quaternion with a storage that views given `buffer` starting at `offset`. `offset` has to be multiple of Float32List.bytesPerElement.\nQuaternion.fromFloat32List(Float32List _qStorage)\nConstructs a quaternion with given Float32List as storage.\nQuaternion.fromRotation(Matrix3 rotationMatrix)\nConstructs a quaternion from a rotation matrix `rotationMatrix`.\nfactory\nQuaternion.fromTwoVectors(Vector3 a, )\nConstructs a quaternion to be the rotation that rotates vector `a` to `b`.\nfactory\nQuaternion.identity()\nConstructs a quaternion set to the identity quaternion.\nfactory\nQuaternion.random(Random rn)\nConstructs a quaternion with a random rotation. The random number generator `rn` is used to generate the random numbers for the rotation.\nfactory\n\n## Properties\n\naxis\naxis of rotation.\nhashCode int\nThe hash code for this object. [...]\nlength\nLength.\nlength2\nLength squared.\nradians of rotation around the axis of the rotation.\nruntimeType Type\nA representation of the runtime type of the object.\nstorage\nAccess the internal storage of the quaternions components.\nw\nAccess the w component of the quaternion.\nx\nAccess the x component of the quaternion.\ny\nAccess the y component of the quaternion.\nz\nAccess the z component of the quaternion.\n\n## Methods\n\nabsoluteError(Quaternion correct)\nAbsolute error between this and `correct`.\nAdd `arg` to this.\nasRotationMatrix()\nReturns a rotation matrix containing the same rotation as this.\nclone()\nReturns a new copy of this.\nconjugate() → void\nConjugate this.\nconjugated()\nConjugated copy of this.\ncopyRotationInto(Matrix3 rotationMatrix)\nSet `rotationMatrix` to a rotation matrix containing the same rotation as this.\ninverse() → void\nInvert this.\ninverted()\nInverted copy of this.\nnormalize()\nNormalize this.\nnormalized()\nNormalized copy of this.\nnoSuchMethod(Invocation invocation) → dynamic\nInvoked when a non-existent method or property is accessed. [...]\ninherited\nrelativeError(Quaternion correct)\nRelative error between this and `correct`.\nrotate()\nRotates `v` by this.\nrotated()\nReturns a copy of `v` rotated by quaternion.\nscale(double scale) → void\nScales this by `scale`.\nscaled(double scale)\nScaled copy of this.\nsetAxisAngle(Vector3 axis, double radians) → void\nSet the quaternion with rotation of `radians` around `axis`.\nsetDQ(Vector3 omega) → void\nSet the quaternion to the time derivative of `q` with angular velocity `omega`.\nsetEuler(double yaw, double pitch, double roll) → void\nSet quaternion with rotation of `yaw`, `pitch` and `roll`.\nsetFrom(Quaternion source) → void\nCopy `source` into this.\nsetFromRotation(Matrix3 rotationMatrix) → void\nSet the quaternion with rotation from a rotation matrix `rotationMatrix`.\nsetFromTwoVectors(Vector3 a, ) → void\nsetRandom(Random rn) → void\nSet the quaternion to a random rotation. The random number generator `rn` is used to generate the random numbers for the rotation.\nsetValues(double x, double y, double z, ) → void\nSet the quaternion to the raw values `x`, `y`, `z`, and `w`.\nsub(Quaternion arg) → void\nSubtracts `arg` from this.\ntoString()\nPrintable string.\noverride\n\n## Operators\n\noperator *(Quaternion other)\nthis rotated by `other`.\noperator +(Quaternion other)\nReturns copy of this + `other`.\noperator -(Quaternion other)\nReturns copy of this - `other`.\noperator ==(Object other) bool\nThe equality operator. [...]\ninherited\noperator [](int i)\nAccess the component of the quaternion at the index `i`.\noperator []=(int i, double arg) → void\nSet the component of the quaternion at the index `i`.\noperator unary-()\nReturns negated copy of this." ]
[ null ]
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https://www.actitrainer.com/research-database/kcal-estimates-from-activity-counts-using-the-potential-energy-method/
[ "## Kcal Estimates from Activity Counts using the Potential Energy Method\n\n• Published on 01/01/1998\n\nA problem exists in applying the kinetic energy equation KE mv2 to estimates of energy expenditure based on activity counts over long epochs. The instantaneous velocity should be obtained over short time periods (on the order of 0.1 second) and squared to obtain the instantaneous kinetic energy. The instantaneous KE is computed from I/2 In V2 but the square of the average of v is not the same as the average of V2. Since we can only estimate the average velocity from the activity counts integrated over long epochs we should not use the KE equation. An alternative method is to calculate by estimating the “energy potential hill” which is climbed with each step. The Model 7164 summed magnitude algorithm rectiñes the acceleration signal and sums each sample. When the summation value (Epoch Activity Counts) is divided by the number of samples (typically 600 for one minute epochs), one has the average acceleration over the epoch. If the average acceleration is integrated twice over time, one gets distance, In the case for a waist worn Actigraph, the distance measure is in the vertical plane. We can use the potential energy equation, PE = mgh, to calculate the work done in raising and lowering the body against gravity.\n\nThe example that follows here, shows how one can use Activity Counts to estimate caloric expenditure in kcals.\n\nA Model 7164 worn tightly on the hip while walking 4.8 km/hr (3 mi/hr) yields an average of 3000 +/-500 activity counts per minute. The average acceleration over one minute is >>>>>>\n\n3000 counts/mín X 0.01664 g/oount 600 samples/min = 0.0832 g/sample\n\nSubstituting m/sec2 the average acceleration is 0.82 m/sec2\n\nThe vertical distance moved over one second >>>>>>>>\n\nh = 1/2 acceleration t2 = 0.41 meters Note: This is equivalent to a vertical displacement of 0.117 meters\n\n(4.6 inches) with each step and a step rate of 1.75 steps/sec. (1.75 steps X 2 X 0.117m = 0.41m)\n\nFrom the computed vertical distance moved against gravity over each second, an estimate of energy\n\nexpended from Work performed in raising and lowering the body against gravity can be calculated from:\n\nPE = mgh\n\nEnergy expenditure (in Joules/sec) for a body mass of 90 kg >>>>>>\n\n90 kg X 9.8 m/s2 X 0.41 m = 361 Joule/sec or 361 Watts\n\nEnergy expenditure (in kilo calories per mín) is >>>>>>\n\n361 Joules/sec / 4,184 Joules/kcal X 60 sec/min ~= 5 kcals/min\n\nFrom this analysis a simple equation can be written to convert Activity Counts to\n\nKcaìs/min = 0.0000191 * counts/min * body mass in kg\n\nWhile this conversion factor seems quite simple, testing in activities such as walking and running reveals\n\nthe PAEE kcal estimates to be very close to published values for those activities.\n\n, ," ]
[ null ]
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https://www.global-sci.org/intro/article_detail/getBib?article_id=496
[ "@Article{IJNAM-12-401, author = {}, title = {A Priori Error Estimates for Finite Volume Element Approximations to Second Order Linear Hyperbolic Integro-Differential Equations}, journal = {International Journal of Numerical Analysis and Modeling}, year = {2015}, volume = {12}, number = {3}, pages = {401--429}, abstract = {\n\nIn this paper, both semidiscrete and completely discrete finite volume element methods (FVEMs) are analyzed for approximating solutions of a class of linear hyperbolic integro-differential equations in a two-dimensional convex polygonal domain. The effect of numerical quadrature is also examined. In the semidiscrete case, optimal error estimates in \\$L^∞(L^2)\\$ and \\$L^∞(H^1)\\$ norms are shown to hold with minimal regularity assumptions on the initial data, whereas quasi-optimal estimate is derived in \\$L^∞(L^∞)\\$ norm under higher regularity on the data. Based on a second order explicit method in time, a completely discrete scheme is examined and optimal error estimates are established with a mild condition on the space and time discretizing parameters. Finally, some numerical experiments are conducted which confirm the theoretical order of convergence.\n\n}, issn = {2617-8710}, doi = {https://doi.org/}, url = {http://global-sci.org/intro/article_detail/ijnam/496.html} }" ]
[ null ]
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http://dlrgenchem.com/fall98/c1311001/exam1.htm
[ "GENERAL CHEMISTRY I\nCHEM 1311.001\nEXAM 1\nFriday September 18, 1998\n\nName_________________________________________\n\nSSN__________________________________________\n\n1. What is an experiment?\n a) An observation of natural phenomena, carried out in a controlled manner, so that the results are reproducible, and rational conclusions can be obtained b) Use of the senses, or extensions thereof, to acquire information about natural phenomena c) The general process acquiring and refining information about natural phenomena. It was represented in class by a flow chart. d) A tentative explanation of natural phenomena e) A tested explanation of natural phenomena\n2. What is a law?\n a) A tested explanation of natural phenomena b) A tentative explanation of natural phenomena c) A concise statement or mathematical equation about natural phenomena d) Use of the senses, or extensions thereof, to acquire information about natural phenomena e) An observation of natural phenomena, carried out in a controlled manner, so that the results are reproducible and rational conclusions can be obtained\n3. What is a theory?\n a) An observation of natural phenomena, carried out in a controlled manner so that the results are reproducible and rational conclusions can be obtained b) Use of the senses, or extensions thereof, to acquire information about natural phenomena c) A tentative explanation of natural phenomena d) A tested explanation of natural phenomena e) A concise statement, or mathematical equation, about natural phenomena\n4. What term means \"the general process of acquiring information about natural phenomena\" and was represented in class by a flowchart?\n a) experiment b) observation c) hypothesis d) theory e) scientific method\n5. What term means \"use of the senses, or extensions thereof, to acquire information about natural phenomena\"?\n a) experiment b) observation c) hypothesis d) theory e) scientific method\n6. A tentative explanation of natural phenomena is a(n)\n a) law b) experiment c) hypothesis d) observation e) theory\n7. Which of the following could, in some cases, be an incorrect explanation of natural phenomena?\n a) hypothesis b) law c) theory d) all of these e) none of these\n8. True or False: After a theory is supported by the the results of numerous experiments, it becomes a hypothesis.\n a) True b) False\n9. True or False: A law usually applies to a broad variety of cases, rather than just one or two specific cases.\n a) True b) False\n10. True or False: If a scientist proposes an explanation of natural phenomena and then conducts an experiment to test it, the explanation must definitely be correct if the experimental data are in agreement with the proposed explanation.\n a) True b) False\n11. When we convert a quantity expressed in one set of units to a different set of units (such as converting cm to mm) we usually carry out the conversion by\n a) adding 1 (in a special form) to the original quantity b) adding 0 (in a special form) to the original quantity c) multiplying 1 (in a special form) by the original quantity d) multiplying 0 (in a special form) by the original quantity\n12. True or False: When we convert a quantity in one set of units to another set of units, the original quantity and the new quantity are mathematically equal to each other\n a) True b) False\n13. True or False: Since there are 12 inches in a foot, there must be 12 cubic inches in a cubic foot.\n a) True b) False\n14. To what power must 10 be raised to get 10?\n a) 0 b) 1 c) 2 d) 3 e) 4\n15. How should the number 0.0017 be written in order to be in scientific notation in standard form?\n a) 0.0017 x 100 b) 0.017 x 10-1 c) 0.17 x 10-2 d) 1.7 x 10-3 e) 17 x 10-4\n16. Which of the following floating point numbers is equivalent to 1.375 x 102?\n a) 0.001375 b) 0.01375 c) 137.5 d) 1375 e) 13750\n17. After doing a calculation, a student obtained the number 175.8 x 10-3 as the answer. How should this number be re-written in order to be in standard form?\n a) 175.8 x 100 b) 1.758 x 10-1 c) 1.758 x 10-5 d) 1.758 x 100 e) 1758 x 10-4\n18. In the metric system\n a) Different units of measurement are always related by powers of 10 b) Different units of measurement are related by various different factors with no predictable pattern\n19. Use the relationships 1 m = 39.37 in and 1 ft = 12 in to calculate the number of meters in one foot. (That is, starting with a distance of 1 ft, convert it to m)\n a) 0.002117 m b) 0.2540 m c) 0.3048 m d) 3.281 m e) 472.4 m\n20. A graduated cylinder contains 24.8 cm3 of water. What is the volume of water in cubic inches? Note that 1 in = 2.54 cm.\n a) 1.51 in3 b) 9.76 in3 c) 63.0 in3 d) 160 in3 e) 406 in3\n21. A chemist reads the volume of water in a graduated cylinder and reports the volume is 12.21 mL. How many significant figures are there in the number 12.21 as used in this context?\n a) 2 b) 3 c) 4 d) indeterminate e) infinite\n22. A beaker is weigned on an analytical balance and a mass of 63.6100 g is obtained. How many significant figures are there in the number 63.6100 as used in this context?\n a) 4 b) 5 c) 6 d) indeterminate e) infinite\n23. A very small piece of metal is weighed on an analytical balance and the mass is found to be 0.0012 g. How many significant figures are there in the number 0.0012 as used in this context?\n a) 2 b) 3 c) 4 d) indeterminate e) infinite\n24. A piece of string was measured with a ruler and found to have a length of 100.0 cm. How many significant figures are there in the number 100.0 as used in this context?\n a) 1 b) 2 c) 3 d) 4 e) infinite\n25. One mile is defined as a distance of 5280 feet. How many significant figures are there in the number 5280 as used in this context?\n a) 0 b) 3 c) 4 d) indeterminate e) infinite\n26. The original enrollment in this chemistry class was 30 students. How many significant figures are there in the number 30 as used in this context?\n a) 0 b) 1 c) 2 d) indeterminate e) infinite\n27. A piece of glass tubing was weighed on an analytical balance and its mass was found to be 10.0100 g. How many significant figures are there in the number 10.0100 as used in this context?\n a) 2 b) 4 c) 6 d) indeterminate e) infinite\n28. True or False: Numbers obtained from measurements are considered to be exact.\n a) True b) False\n29. If the number of significant figures in a numerical value is infinite, the numerical value is said to be\n a) exact b) indeterminate\n30. How many \"uncertain\" digits should be shown in a measured value or final answer to a calculation?\n\na) none           b) one           c) two\n\nd) whatever number of uncertain digits the person writing the value wants to show\n\ne) an infinite number\n\n31. Density is calculated by dividing the mass of a substance by its volume. That is, d = m / V. If a 5.00 mL sample of an unknown liguid has a mass of 5.100 g, what is the density of the liquid? Select the answer that complies with the appropriate significant figure rules.\n a) 1 g / mL b) 1.0 g / mL c) 1.02 g / mL d) 1.020 g / mL e) 1.0200 g / mL\n32. If one piece of string is reported to have a length of 10.30 m and another piece of string is reported to have a length of 5.010 m, what is the combined length of the two pieces of string? Select the answer that complies with the appropriate significant figure rules.\n a) 15 m b) 15.3 m c) 15.31 m d) 15.310 m e) 15.3100 m\n33. The area of a rectangular figure is calculated by multiplying the length by the width. If a rectangle has a length of 37.523 m and a width of 2.1 m, what is the area of the rectangle? Select the answer that complies with the appropriate significant figure rules.\n a) 8 x 101 m2 b) 79 m2 c) 78.8 m2 d) 78.80 m2 e) 78.798 m2\n34. A lab student weighed a beaker containing a water sample on a top loading balance. The mass was determined to be 225.17 g. The student's lab partner had previously weighed the same beaker -- when it was empty -- on an analytical balance and obtained a mass of 94.1635 g. What mass of water was in the beaker? Select the answer that complies with the appropriate significant figure rules.\n a) 131 g b) 131.0 g c) 131.01 g d) 131.006 g e) 131.0065 g\n35. Two graduated cylinders were sitting on a laboratory bench, each partially filled with water. A chemist noted that one cylinder contained 1.00 mL of water, while the other cylinder contained 47.1 mL of water. What is the total volume of water in the two cylinders? Select the answer that complies with the appropriate significant figure rules.\n a) 5 x 101 mL b) 48 mL c) 48.1 mL d) 48.10 mL e) 48.100 mL\n36. If a piece of metal has a mass of 1.20 g and a volume of 0.2 mL, what is the density of the metal? Select the answer that complies with the appropriate significant figure rules. Note that d = m / V.\n a) 6 g / mL b) 6.0 g / mL c) 6.00 g / mL d) 6.000 g / mL e) 6.0000 g / mL\n37. A student is solving the mixed arithmetic problem 1.3133 x (1.2150 + 2.165) =\nFor simplicity, units have been omitted from the numbers, but assume all numbers come from measurements. With regard to significant figure rules, how should the answer to this calculation be expressed?\n a) 4 b) 4.4 c) 4.44 d) 4.439 e) 4.4390\n38. A student is solving the mixed arithmetic problem (10.48 + 2.103) / (1.0 + 2.107) =\nFor simplicity, units have been omitted from the numbers, but assume all numbers come from measurements. With regard to significant figure rules, how should the answer to this calculation be expressed?\n a) 4 b) 4.0 c) 4.05 d) 4.050 e) 4.0499\n39. If a number with three significant figures is multiplied by a number with two significant figures, how many significant figures will be in the answer to the multiplication problem?\n a) 1 b) 2 c) 3 d) 5 e) 6\n40. The mathematical operation of subtraction follows the same significant figure rules as the mathematical operation of __________\n a) addition b) division c) multiplication\n\n1 a      2 c      3 d      4 e      5 b\n\n6 c      7 d      8 b      9 a      10 b\n\n11 c      12 a      13 b      14 b      15 d\n\n16 c      17 b      18 a      19 c      20 a\n\n21 c      22 c      23 a      24 d      25 e\n\n26 e      27 c      28 b      29 a      30 b\n\n31 c      32 c      33 b      34 c      35 c\n\n36 a      37 d      38 b      39 b      40 a" ]
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https://www.flexiprep.com/Expected-Exam-Questions/Mathematics/Class-10/CBSE-Class-10-Mathematics-Chapter-11-Constructions-Part-13.html
[ "CBSE Class 10-Mathematics: Chapter – 11 Constructions Part 13 (For CBSE, ICSE, IAS, NET, NRA 2022)\n\nGlide to success with Doorsteptutor material for CBSE/Class-10 : get questions, notes, tests, video lectures and more- for all subjects of CBSE/Class-10.\n\nQuestion 22:\n\nConstruct an isosceles triangle whose base is and altitude and then another triangle whose sides are times the corresponding sides of the isosceles triangle.\n\nTo construct: To construct an isosceles triangle whose base is and altitude and then a triangle similar to it whose sides are of the corresponding sides of the first triangle.\n\nSteps of construction:\n\n(a) Draw BC = 8 cm\n\n(b) Draw perpendicular bisector of BC. Let it meets BC at D.\n\n(c) Mark a point A on the perpendicular bisector such that .\n\n(d) Join AB and AC. Thus is the required isosceles triangle.\n\n(e) From any ray BX, making an acute angle with BC on the side opposite to the vertex A.\n\n(f) Locate points and on BX such that .\n\n(g) Join and draw a line through the point , draw a line parallel to intersecting BC at the point C. ′\n\n(h) Draw a line through C ‘parallel to the line CA to intersect BA at A.’\n\nThen, A ‘BC’ is the required triangle.\n\nJustification:\n\n[By construction]\n\n[AA similarity]\n\n[By Basic Proportionality Theorem]\n\n[By construction]\n\n[AA similarity]\n\nBut [By construction]\n\nTherefore,\n\nQuestion 23:\n\nDraw a triangle ABC with side , and . Then construct a triangle whose sides are of the corresponding sides of triangle ABC.\n\nTo construct: To construct a triangle ABC with side , and and and then a triangle similar to it whose sides are of the corresponding sides of the first triangle ABC.\n\nSteps of construction:\n\n(a) Draw a triangle ABC with side , and .\n\n(b) From any ray BX, making an acute angle with BC on the side opposite to the vertex A.\n\n(c) Locate 4 points and on BX such that .\n\n(d) Join and draw a line through the point , draw a line parallel to intersecting BC at the point C. ′\n\n(e) Draw a line through C ‘parallel to the line CA to intersect BA at A.’\n\nThen, A ‘BC’ is the required triangle.\n\nJustification:\n\n[By construction]\n\n[By Basic Proportionality Theorem]\n\nBut [By construction]\n\nTherefore,\n\n[AA similarity]\n\n[From eq. (i) ]\n\nDeveloped by:" ]
[ null ]
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http://mathscinet.ru/catalogue/shadow/
[ "", null, "Shadow matrices S alow construct two circulant cores of Jacobsthal matrices Q: the latest are cores of two border two circulant C-matrices. They can consist of symmetric circulant A-block and B-block based on secuence [b;–Rb], R – reversed identity matrix.", null, "Shadow matrices noted by symbol \"e\": it is \"younger family\" of Euler matrices for orders n=4k ! Two-circulant three level (a,–b,d)-matrices constructed via conference matrices and their orthogonalised cores: a=1, b=1–2*d, d=(sqrt(2*n+1)–3)/(n–4) –diagonal entry (for n=4, d=b=1).\n\nOn Line Procedure", null, "", null, "Euler matrices E alow construct two circulant cores of Jacobsthal matrices Q: the latest are cores of two border two circulant H-matrices. They can consist of the set of symmetric, asymmetric and skew circulant A, B-blocks.\n\nСЛОЖНОСОСТАВНАЯ МАТРИЦА 44\n\nCRETAN MATRICES\n\na=1, b=1–2*d, d=(sqrt(2*n+1)–1)/n – diagonal entry", null, "Conference matrix C6", null, "", null, "Ortagonalised core S5 and shadow matrix e4", null, "Conference matrix C10", null, "", null, "Ortagonalised core S9 and shadow matrix e8 following S9", null, "Conference matrix C14", null, "", null, "Ortagonalised core S13 and shadow matrix e12\n\nСВЯЗЬ С КОНФЕРЕНЦ-МАТРИЦАМИ (ЯДРА)", null, "Conference matrix C6", null, "", null, "Ortagonalised core S5 and shadow matrix e4=H4", null, "Conference matrix C10", null, "", null, "Ortagonalised core S9 and shadow matrix e8", null, "Conference matrix C14", null, "", null, "Ortagonalised core S13 and shadow matrix e12", null, "Conference matrix C18", null, "", null, "Ortagonalised core S17 and shadow matrix e16", null, "EULER MATRICES CATALOGUE | | MERSENNE MATRICES CATALOGUE\n\n ..", null, "" ]
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https://blog.myrank.co.in/parallel-axis-theorem/
[ "# Parallel Axis Theorem\n\nThe theorem determines the moment of inertia of a rigid body about any given axis, given that moment of inertia about the parallel axis through the centre of mass of an object and the perpendicular distance between the axes.\n\nThe moment of inertia of a body about an axis is equal to its moment of inertia about a parallel axis through its centre of gravity plus the product of the mass of the body and the square of the perpendicular distance between the two parallel axes.", null, "Let ‘I’ be the moment of inertia of a plane lamina about an axis YY. Let ‘G’ be the centre of gravity of the lamina. Y¹Y¹ is an axis parallel to YY and passing through ‘G’. Let ‘Ig’ be the moment of inertia of the lamina about Y¹Y¹.\n\nLet GP = x.\n\nMoment of inertia of the particle about\n\nYY = m (x + d)2\n\nMoment of inertia of the whole of lamina about\n\nYY = I = ∑ m (x + d)²\n\n= ∑ m (x² + d² + 2xd)\n\n⇒ I = ∑ mx² + ∑ md² + ∑ 2mxd\n\nBut ∑mx² = Ig, ∑md² = (∑ m)d² = Md²\n\nAlso ∑ 2mxd = 2d∑mx\n\n∴ I = Ig + md² + 2d ∑ mx\n\nThe lamina will balance itself about its centre of gravity. So the algebraic sum of the moments of the weights of constituent particles about the centre of gravity G should be zero.\n\n∴ ∑ mg x X = 0 or g ∑ mx = 0\n\n⇒ ∑ mx = 0\n\n∴ I = Ig + Md².\n\nThe parallel axis theorem can be used to determine the object’s moment of inertia of a rigid body around any axis. This theorem is also known as Huygens – Steiner theorem. According to the parallel axis theorem, there is an affiliation between the inertia of an object rotation around its centre of gravity and an axis parallel to this centre. This theorem can be used to any solid object in rotation, as well as with irregular shapes. For easy understanding, the parallel axis theorem is a relation between the moment of inertia about an axis passing through the centroid, the centre of gravity of a geometrical object of uniform density and the moment of inertia about any parallel axis." ]
[ null, "http://blog.myrank.co.in/wp-content/uploads/2017/11/Parallel-Axis-Theorem.png", null ]
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https://robotics_en_ru.enacademic.com/533/approximation_step
[ "\n\n# approximation step\n\nшаг аппроксимации\n\nАнгло-русский словарь по робототехнике. 2013.\n\n### Смотреть что такое \"approximation step\" в других словарях:\n\n• Approximation theory — In mathematics, approximation theory is concerned with how functions can best be approximated with simpler functions, and with quantitatively characterizing the errors introduced thereby. Note that what is meant by best and simpler will depend on …   Wikipedia\n\n• Step response — The step response of a system in a given initial state consists of the time evolution of its outputs when its control inputs are Heaviside step functions. In electronic engineering and control theory, step response is the time behaviour of the… …   Wikipedia\n\n• Born-Oppenheimer approximation — In quantum chemistry, the computation of the energy and wavefunction of an average size molecule is a formidable task that is alleviated by the Born Oppenheimer (BO) approximation. For instance the benzene molecule consists of 12 nuclei and 42… …   Wikipedia\n\n• Stochastic approximation — methods are a family of iterative stochastic optimization algorithms that attempt to find zeroes or extrema of functions which cannot be computed directly, but only estimated via noisy observations. The first, and prototypical, algorithms of this …   Wikipedia\n\n• Successive approximation ADC — Successive Approximation redirects here. For behaviorist B.F. Skinner s method of guiding learned behavior, see Shaping (psychology). A successive approximation ADC is a type of analog to digital converter that converts a continuous analog… …   Wikipedia\n\n• Rotating wave approximation — The rotating wave approximation is an approximation used in atom optics and magnetic resonance. In this approximation, terms in a Hamiltonian which oscillate rapidly are neglected. This is a valid approximation when the applied electromagnetic… …   Wikipedia\n\n• Successive Approximation ADC — A successive approximation ADC is a type of analog to digital converter that converts a continuous analog waveform into a discrete digital representation via a binary search through all possible quantization levels before finally converging upon… …   Wikipedia\n\n• Heaviside step function — The Heaviside step function, H , also called the unit step function, is a discontinuous function whose value is zero for negative argument and one for positive argument.It seldom matters what value is used for H (0), since H is mostly used as a… …   Wikipedia\n\n• последовательное приближение — — [Л.Г.Суменко. Англо русский словарь по информационным технологиям. М.: ГП ЦНИИС, 2003.] Тематики информационные технологии в целом EN progressive approximationstep by step approximationstep by step approach …   Справочник технического переводчика\n\n• List of numerical analysis topics — This is a list of numerical analysis topics, by Wikipedia page. Contents 1 General 2 Error 3 Elementary and special functions 4 Numerical linear algebra …   Wikipedia\n\n• Methods of computing square roots — There are several methods for calculating the principal square root of a nonnegative real number. For the square roots of a negative or complex number, see below. Contents 1 Rough estimation 2 Babylonian method 2.1 Example …   Wikipedia\n\n### Книги\n\nДругие книги по запросу «approximation step» >>\n\n### Поделиться ссылкой на выделенное\n\n##### Прямая ссылка:\nНажмите правой клавишей мыши и выберите «Копировать ссылку»\n\nWe are using cookies for the best presentation of our site. Continuing to use this site, you agree with this." ]
[ null ]
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https://discuss.codecademy.com/t/what-is-the-point-of-this-function/446936
[ "", null, "# What is the point of this function?\n\nHi,\nSo I alright executing the exercise, but I would like to know WHY the function needs the ‘Russian doll’ like encasing, what is the purpose?\ne.g:\n\n``````function monitorCount(rows, columns) {\nreturn rows * columns;\n};\nconst numOfMonitors=monitorCount(5,4);\nconsole.log(numOfMonitors);\n``````\n\nSo I determine the function on the first line! I am fine with that… then I carry on and set the way the function will be calculated. Great! What is the const line for then? is that were basically the DATA will be input to, so the function can work? I am a bit lost on this concept.\n\nI didn’t see the point of the function to begin with, I could have made a const without calling the function, what is this for?\n\nThx\n\nDespite the verbosity, the function demonstrates how we can keep all multiplication of two factors contained in one function, which any part of the program can call upon if it needs a product of `a` and `b`.\n\nFor this exercise it is more specific so we can see what is happening, but it wouldn’t have to be like that.\n\n`````` const multiply = (a, b) => a * b; // generic function expression\n``````\n\nThen we could use named variables in the program…\n\n``````rows = 5\ncolumns = 4\nlet numOfMonitors = multiply(rows, columns)\nconsole.log(numOfMonitors)\n``````\n\nThe function name says what it does, and we can see that if we want to know how many monitors there are, multiply rows times columns.\n\n1 Like\n\nSure, you could just do this: `console.log(5 * 4)`, but what would that teach you about how functions work, or what the `return` statement does? The lessons use simple examples to teach concepts and techniques that can be used to accomplish very complex tasks.\n\n2 Likes" ]
[ null, "https://aws1.discourse-cdn.com/codecademy/original/5X/e/0/8/c/e08cf790a5972ac52a036a0fb64e4e139baec615.png", null ]
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https://elmprogramming.com/value.html
[ "# 3.7\n\n## Value\n\nWe have used the term value without formally defining it. Mathematics defines a value as the result of a calculation. When we evaluate an expression we are performing a calculation. The terms calculation and computation can be used interchangeably. In Elm, all computations are done by evaluating expressions to yield values. This makes expressions the basic building blocks of any Elm application. No matter how complex an Elm application is, its essentially one big expression comprising of mini expressions.\n\nSo far we have only used numbers and boolean as values, but in Elm anything we can produce as a result of a computation can be considered a value. Here are some examples:\n\nWe will cover each of these values in detail later. All values in Elm can be passed as arguments to functions, returned as results, and placed in data structures." ]
[ null ]
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http://tsayper.blogspot.com/
[ "## Jul 19, 2019\n\n### Intervals 2.0\n\nUpdated intervals combining (splicing/clipping) method with the new features of C# 7.0. Intervals passed can overlap.\nTwo weird classes added for convenience. Pair<T> is handy when you have to switch often between 2 objects. IntBool is a value type which can act as both int and bool.\n\n`````` public static class CombineIntervals\n{\npublic static IEnumerable<(T, T)> Combine<T>(this IEnumerable<(T, T)> inc, IEnumerable<(T, T)> exc = null) where T : IComparable\n{\nif (exc == null) exc = Enumerable.Empty<(T, T)>();\nIEnumerable<(T val, bool br, bool ex) > GetBorders(IEnumerable<(T left, T right)> ranges, bool ex)\n{\nforeach (var (left, right) in ranges)\n{\nyield return (left, true, ex);\nyield return (right, false, ex);\n}\n}\nvar borders = GetBorders(inc, false).Union(GetBorders(exc, true)).OrderBy(x => x.val).ToArray();\nT start = borders.val;\nvar state = new Pair<IntBool>();\nforeach (var (val, br, ex) in borders)\n{\nif (state[ex].Xor(br))\n{\nif (br == state[!ex])\nyield return (start, val);\nelse start = val;\n}\nstate[ex] += br ? 1 : -1;\n}\n}\n}\npublic struct Pair<T>\n{\nT a; T b;\npublic T this[IntBool i]\n{\nget => i ? b : a;\nset\n{\nif (i) b = value;\nelse a = value;\n}\n}\npublic override string ToString()\n{\nreturn \\$\"{a}, {b}\";\n}\ninternal void Deconstruct(out T x, out T y)\n{\nx = a;\ny = b;\n}\n}\npublic struct IntBool\n{\nprivate int val;\npublic static implicit operator IntBool (int x) => new IntBool() { val = x };\npublic static implicit operator int(IntBool x) => x.val;\npublic static implicit operator IntBool(bool x) => new IntBool() { val = x ? 1 : 0 };\npublic static implicit operator bool(IntBool x) => x.val > 0;\npublic override string ToString() => val.ToString();\npublic bool And(bool x) => val == 1 && x;\npublic bool Xor(bool x) => val == 1 && !x || val == 0 && x;\n}``````\n\n## May 18, 2016\n\n### Get a site's Favicon uri\n\nUsing HtmlAgilityPack NuGet package (Ms-Pl license):\n\n``` public async static Task<Uri> GetFaviconUri(Uri page)\n{\nvar doc = await new HtmlAgilityPack.HtmlWeb().LoadFromWebAsync(page.AbsoluteUri);\n.Where(n => n.Attributes.Any(a => a.Name == \"rel\" &&\na.Value == \"icon\" || a.Value == \"shortcut icon\"))\n.FirstOrDefault()?.GetAttributeValue(\"href\", null);\nreturn href == null ? null : new Uri(page, href);\n}```\n\n## Jan 31, 2016\n\n### Splicing, combining, subtracting intervals of IComparable\n\nIdea is simple, you pass two collections of intervals (Tuple<T, T>), one for included values, another for excluded. Then overlapping intervals of the same kind are combined, and excluding intervals are subtracted from including intervals. As a result you get a new set of intervals.\n\nAs T you can use any IComparable, like int, DateTime, double or your custom type.\n\nCode:\n```using System;\nusing System.Collections.Generic;\nusing System.Linq;\n\nnamespace Test\n{\n/*\n\nSubtracting intervals of different kind:\n\ninclude | ***** **** ***** *********** *** |\nexclude | ****** ** ************** |\nborders | i e e i i iee i i e i i i e |\nresult | *** **** * ** ****** |\n\nCombining overlapping intervals of the same kind:\n\nfirst | l....r |\nsecond | l............r |\nthird | l...r |\nall | l..l.r..l...r...r |\nborder | 1..2.1..2...1...0 |\n\n(1..0) constitutes a combined interval\n\n*/\n\npublic class Interval\n{\npublic enum Border { Left, Right };\npublic enum IntervalType { Including, Excluding };\n\n//border point of an interval\nstruct Point<T>\n{\npublic T Val;\npublic int Brdr;\npublic int Intr;\npublic Point(T value, Border border, IntervalType interval)\n{\nVal = value;\nBrdr = (border == Border.Left) ? 1 : -1;\nIntr = (int)interval;\n}\npublic override string ToString() =>\n(Brdr == 1 ? \"L\" : \"R\") + (Intr == 0 ? \"+ \" : \"- \") + Val;\n}\n\nprivate static IEnumerable<Point<T>> GetBorders<T>\n(IEnumerable<Tuple<T, T>> src,\nIntervalType intr) =>\nsrc.Select(p => new[] { p.Item1, p.Item2 }).SelectMany(p => p).\nSelect((v, idx) => new Point<T>(v, (Border)(idx % 2), intr));\n\npublic static IEnumerable<Tuple<T, T>> Combine<T>(\nIEnumerable<Tuple<T, T>> Include, IEnumerable<Tuple<T, T>> Exclude)\nwhere T : IComparable\n{\nvar INs = GetBorders(Include, IntervalType.Including);\nvar EXs = GetBorders(Exclude, IntervalType.Excluding);\n\nvar intrs = new int; //current interval border control In, Ex\nT start = default(T); //left border of a new resulting interval\n//put all points in a line and loop:\nforeach (var p in INs.Union(EXs).OrderBy(x => x.Val))\n{\n//check for start (close) of a new (cur) interval:\nvar change = (intrs[p.Intr] == 0) ^ (intrs[p.Intr] + p.Brdr == 0);\nintrs[p.Intr] += p.Brdr;\nif (!change) continue;\n\nvar In = p.Intr == 0 && intrs == 0; //w no cur Ex\nvar Ex = p.Intr == 1 && intrs > 0; //breaks cur In\nvar Open = intrs[p.Intr] > 0;\nvar Close = !Open;\n\nif (In && Open || Ex && Close)\n{\nstart = p.Val;\n}\nelse if (In && Close || Ex && Open)\n{\nyield return new Tuple<T, T>(start, p.Val);\n}\n}\n}\n}\n}```\n\nExample of usage:\n\nCode:\n```class Program\n{\nstatic void Main(string[] args)\n{\nvar include = new[] {\nnew Tuple<int, int>(10, 100),\nnew Tuple<int, int>(200, 300),\nnew Tuple<int, int>(400, 500),\nnew Tuple<int, int>(420, 480),\n};\nvar exclude = new[] {\nnew Tuple<int, int>(95, 200),\nnew Tuple<int, int>(410, 420),\n};\n\nforeach (var i in Interval.Combine(include, exclude))\nConsole.WriteLine(i.Item1 + \"-\" + i.Item2);\n\n}\n}```\n\nThe output will be\n10-95\n205-300\n400-410\n420-500\n\nNB! border values of excluding intervals are not excluded. E.g. when you subtract (5..10) from [1..7] you end up with [1..5]. To exclude 5, widen the excluding interval like (5..10) => (4..11).\n\n### Alias ugly generic type names\n\nThough aliasing (with using keyword) generic types is not possible as of C# 6.0, sometimes you can go with inheritance:\n\n```public class MyList<T1, T2> :\nList<Tuple<IEnumerable<HashSet<T1>>, IComparable<T2>>>\n{ }\n\npublic void Meth()\n{\nvar x = new MyList<int, bool>();\n}```\n\n## Jan 30, 2016\n\nCode:\n```public static class CircularLinkedList\n{\n{\nreturn current.Next ?? current.List.First;\n}\n\n{\nreturn current.Previous ?? current.List.Last;\n}\n\n{\nwhile (num != 0)\n{\ncurrent = num > 0 ? current.NextOrFirst() : current.PreviousOrLast();\nnum -= Math.Sign(num);\n}\nreturn current;\n}\n}```\n\n### UWP: where are my solution's Content files?\n\nPackage.Current.InstalledLocation\n\n## Sep 11, 2015\n\n### Wrap an object into an IEnumerable of single item\n\nCode:\n```public static IEnumerable<T> Yield<T>(this T item)\n{\nyield return item;\n}```" ]
[ null ]
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https://techfunda.com/howto/930/less-than-or-equal-to-operator
[ "# Less than or Equal to (<=) operator in JavaScript\n\n### Less than or Equal to (<=)\n\nLess than or Equal to operator is an Comparison Operator which is used to check the value of the left operand is either less than or equal to the value of the right operand.\n\nIf the value of the left operand is either less than or equal to the value of the right operand, the result gives 'true'.\n\nThe symbolic representation of Less than or Equal to is `<=`.\n\n### Left operand value is less than right operand\n\n```<b>Assigning left operand value less than the right operand value, the result gives</b>\n<p id=\"myId\"></p>\n\n<script>\nvar a = 1;\nvar b = 3;\nvar c = (a <= b);\ndocument.getElementById(\"myId\").innerHTML = c;\n</script>\n```\n\nIn the above code snippet we assigned lesser value to the left operand and greater value to the right operand, we used less than or equal to operator, so the result gives 'true'.\n\nOUTPUT", null, "### Left operand value is equal to right operand\n\n```<b>Assigning left operand value is equal to the right operand value, the result gives</b>\n<p id=\"myId\"></p>\n\n<script>\nvar a = 3;\nvar b = 3;\nvar c = (a <= b);\ndocument.getElementById(\"myId\").innerHTML = c;\n</script>\n```\n\nLess than or Equal to with two equal values\n\nIn the above code snippet we assigned equal values to the left operand and right operand, so the result gives 'true'.\n\nOUTPUT", null, "### Left operand value is greater than right operand\n\n```<b>Assigning left operand value is greater than the right operand value, the result gives</b>\n<p id=\"myId\"></p>\n\n<script>\nvar a = 3;\nvar b = 1;\nvar c = (a <= b);\ndocument.getElementById(\"myId\").innerHTML = c;\n</script>```\n\nLess than or Equal to with gretaer value at left operand\n\nIn the above code snippet we assigned greater value to the left operand and lesser value to the right operand, so the result gives 'false'.\n\nOUTPUT", null, "Views: 7939 | Post Order: 174" ]
[ null, "https://techfunda.com/HTPictures/635905905524884808.JPG", null, "https://techfunda.com/HTPictures/635905909267784554.JPG", null, "https://techfunda.com/HTPictures/635905933162597657.JPG", null ]
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https://byjus.com/icse-class-8-maths-selina-solutions-chapter-21-surface-area-volume-and-capacity/
[ "", null, "# ICSE Class 8 Maths Selina Solutions for Chapter 21 Surface Area,Volume and Capacity\n\n### CHAPTER 21-SURFACE AREA, VOLUME AND CAPACITY\n\nQuestion 1.\n\nFind the volume and the total surface area of a cuboid, whose:\n\n(i) Length = 15cm, breadth = 10cm and height = 8cm.\n\nSolution:-\n\nWe know that\n\nVolume of a cuboid $=\\text {Length} \\times \\text { Breadth } \\times \\text { Height }=15 \\times 10 \\times 8=1200 \\mathrm{cm}^{3}$\n\nHere\n\nTotal surface area of a cuboid $=2(l \\times b+b \\times h+h \\times l)=2(15 \\times 10+10 \\times 8+8 \\times 15)$\n\nBy further calculation\n\n$=2(150+80+120) 2 \\times 350=700 \\mathrm{cm}^{2}$\n\n(ii) l = 3.5m, b = 2.6m and h = 90cm,\n\nSolution:-\n\nLength = 3.5m breadth = 2.6m, height = 90cm $=\\frac{90}{100} m=0.9 m$.\n\nWe know that\n\nVolume of a cuboid $=l \\times b \\times h=3.5 \\times 2.6 \\times 0.9=8.19 m^{3}$\n\nHere\n\nTotal surface area of a cuboid $=2(l \\times b+b \\times h+h \\times l)=2(3.5 \\times 2.6+2.6 \\times 0.9 \\times 3.5)$\n\nBy further calculation\n\n=2(910+2.34+3.15)=2(14.59) $=29.18 m^{2}$\n\nQuestion 2.\n\n(i)The volume of a cuboid is 3456 $\\mathrm{cm}^{3}$. If its length =24 cm and breadth =18 cm; find its height.\n\nSolution:\n\nVolume of the given cuboid $=3456 \\mathrm{cm}^{3}$.\n\nLength of the given cuboid =24 cm\n\nBreadth of the given cuboid =18 cm\n\nHere\n\nLength × Breadth × Height = Volume of a cuboid\n\nSubstituting the values\n\n24×18× Height =3456\n\nBy further calculation\n\nHeight $=\\frac{3456}{24 \\times 18}$\n\nSo we get\n\nHeight $=\\frac{3456}{432}$\n\nHeight =8cm\n\n(ii) The volume of a cuboid is 7.68 $m^{3}$. If its length = 3.2m and height =1.0m; find its breadth.\n\nSolution:-\n\nVolume of a cuboid =7.68 $\\mathrm{m}^{3}$\n\nLength of a cuboid =3.2 m\n\nHeight of a cuboid =1.0 m\n\nHere\n\nLength x Breadth x Height = Volume of a cuboid\n\nSubstituting the values\n\nBy further calculation\n\n$\\Rightarrow \\text { Breadth }=\\frac{7.68}{3.2 \\times 1.0}$\n\nSo we get\n\n$\\Rightarrow \\text { Breadth }=\\frac{7.68}{3.2}$\n\n(iii) The breadth and height of a rectangular solid are 1.20 m and 80 cm respectively. If the volume of the cuboid is 1.92 $m^{3}$; find its length.\n\nSolution:-\n\nVolume of a rectangular solid =1.92 $\\mathrm{m}^{3}$\n\nBreadth of a rectangular solid = 1.20 m\n\nHeight of a rectangular solid =80 cm=0.8 m\n\nHere\n\nLength × Breadth × Height = Volume of a rectangular solid (cubical)\n\nSubstituting the values\n\nLength × 1.20 × 0.8 = 1.92\n\nBy further calculation\n\nLength × 0.96 = 1.92\n\n$=\\frac{1.92}{0.96}$\n\nSo we get\n\n$=\\frac{192}{96}$\n\nLength =2 m\n\nQuestion 3.\n\nThe length, breadth and height of a cuboid are in the ratio 5:3:2. If its volume is $240 \\mathrm{cm}^{3}$, find its dimensions. (Dimensions means: its length, breadth and height). Also find the total surface area of the cuboid.\n\nSolution:-\n\nConsider length of the given cuboid =5x\n\nBreadth of the given cuboid =3x\n\nHeight of the given cuboid =2x\n\nWe know that\n\nVolume of the given cuboid $=\\text { Length } \\times \\text { Breadth } \\times {height}$\n\nSubstituting the values\n\n$=5 x \\times 3 x \\times 2 x=30 x^{3}$\n\nIt is given that\n\nVolume $=240 \\mathrm{cm}^{3}$\n\nSubstituting the values\n\n$30 x^{3}=240 \\mathrm{cm}^{3}$\n\nBy further calculation\n\n$x^{3}=\\frac{240}{30}$ $x^{3}=8$\n\nSo we get\n\n$x=8^{\\frac{1}{3}}$ $x=(2 \\times 2 \\times 2)^{\\frac{1}{3}}$\n\nx=2 cm\n\nHere\n\nLength of the given cube $=5 x=5 \\times 2=10 \\mathrm{cm}$\n\nBreadth of the given cube $=3 x=3 \\times 2=6 \\mathrm{cm}$\n\nHeight of the given cube $=2 x=2 \\times 2=4 \\mathrm{cm}$\n\nWe know that\n\nTotal surface area of the given cuboid $=2(1 \\times b+b \\times h+h \\times 1)$\n\nSubstituting the values\n\n$=2(10 \\times 6+6 \\times 4+4 \\times 10)=2(60+24+40)=2 \\times 124=248 \\mathrm{cm}^{2}$\n\nQuestion 4.\n\nThe length, breadth and height of a cuboid are in the ratio 6:5:3. If its total surface area is 504 c $m^{2}$; find its dimensions. Also, find the volume of the cuboid.\n\nSolution:-\n\nConsider length of the cuboid =6x\n\nHeight of the cuboid =3x\n\nWe know that\n\nTotal surface area of the given cuboid $=2(1 \\times b+b \\times h+h \\times l)$\n\nSubstituting the values\n\n$=2(6 x \\times 5 x+5 x \\times 3 x+3 x \\times 6 x)=2(30 \\times 2+15 \\times 2+18 \\times 2)$\n\nWe get\n\n$=2 \\times 63 \\times 2=126 x^{2}$\n\nIt is given that\n\nTotal surface area of the given cuboid $=504 \\mathrm{cm}^{2}$\n\nSubstituting the values\n\n$126 x^{2}=504 \\mathrm{cm}^{2}$\n\nBy further calculation\n\n$\\Rightarrow x^{2}=\\frac{504}{126}$\n\nSo we get\n\n$\\Rightarrow x^{2}=4$ $\\Rightarrow x=\\sqrt{4}$\n\nx=2 cm\n\nHere\n\nLength of the cuboid $=6 x=6 \\times 2=12 \\mathrm{cm}$\n\nBreadth of the cuboid $=5 x=5 \\times 2=10 \\mathrm{cm}$\n\nHeight of the cuboid $=3 x=3 \\times 2=6 \\mathrm{cm}$\n\nWe get\n\nVolume of the cuboid $=l \\times b \\times h=12 \\times 10 \\times 6=720 \\mathrm{cm}^{3}$\n\nQuestion 5.\n\nFind the volume and total surface area of a cube whose edge is:\n\n(i) 8 cm\n\nSolution:-\n\nEdge of the given cube =8cm\n\nWe know that\n\nVolume of the given cube $=(\\text { Edge })^{3}=(8)^{3}=8 \\times 8 \\times 8=512 \\mathrm{cm}^{3}$\n\nTotal surface area of a cube $=6(\\text { Edge })^{2}=6 \\times(8)^{2}=384 \\mathrm{cm}^{2}$\n\n(ii) 2m 40 cm.\n\nSolution:-\n\n(ii)Edge of the given cube =2 m 40 cm=2.40 m\n\nWe know that\n\nVolume of a cube $=(\\text { Edge })^{3}$\n\nSubstituting the values\n\nVolume of the given cube $=(2.40)^{3}=2.40 \\times 2.40 \\times 2.40=13.824 \\mathrm{m}^{2}$\n\nTotal surface area of the given cube $=6 \\times 2.4 \\times 2.4=34.56 \\mathrm{m}^{2}$\n\nQuestion 6.\n\nFind the length of each edge of a cube, if its volume is:\n\n(i) $216 \\mathrm{cm}^{3}$\n\nSolution:-\n\n$(\\text { Edge })^{3}$=Volume of a cube\n\nSubstituting the values\n\n$(\\text { Edge })^{3}=216 \\mathrm{cm}^{3}$\n\nIt can be written as\n\nEdge $=(216)^{1 / 3}$\n\nEdge $=(3 \\times 3 \\times 3 \\times 2 \\times 2 \\times 2)^{1 / 3}$\n\nWe get\n\nEdge $=3 \\times 2$\n\nAns. Edge =6 cm.\n\n(ii) $1.728 \\mathrm{m}^{3}$\n\nSolution:-\n\n$(Edge)^3$ = Volume of a cube\n\nSubstituting the values\n\n$(\\mathrm{Edge})^{3}=1.728 \\mathrm{m}^{3}$ $\\Rightarrow(\\text { Edge })^{3}=\\frac{1.728}{1000}=\\frac{1728}{1000}$\n\nIt can be written as\n\n$Edge =\\left(\\frac{1728}{1000}\\right)^{1 / 3}$\n\nBy further calculation\n\n$\\mathrm{Edge}=\\left(\\frac{2 \\times 2 \\times 2 \\times 2 \\times 2 \\times 2 \\times 3 \\times 3 \\times 3}{10 \\times 10 \\times 10}\\right)^{1 / 3}$ $Edge =\\frac{2 \\times 2 \\times 3}{10}$\n\nSo we get\n\n$Edge =\\frac{12}{10} \\mathrm{m}$\n\nEdge =1.2 m.\n\nQuestion 7.\n\nThe total surface area of a cube is 216 cm2. Find its volume.\n\nSolution:-\n\n$6(\\text {Edge})^{2}$= Total surface area of a cube\n\nSubstituting the values\n\n$6(\\text {Edge})^{2}=216 \\mathrm{cm}^{2}$ $(\\text {Edge})^{2}=\\frac{216}{6}$\n\nBy further calculation\n\n$(\\text {Edge})^{2}=36$\n\nEdge $=\\sqrt{36}$\n\nEdge =6 cm\n\nWe know that\n\nVolume of the given cube $=(E d g e)^{3}=(6)^{3}=6 \\times 6 \\times 6=216 \\mathrm{cm}^{3}$\n\nQuestion 8.\n\nA solid cuboid of metal has dimensions 24 cm, 18 cm and 4 cm. Find its volume.\n\nSolution:-\n\nIt is given that\n\nLength of the cuboid =24 cm\n\nBreadth of the cuboid =18 cm\n\nHeight of the cuboid =4 cm\n\nWe know that\n\n$Volume of the cuboid =l \\times \\mathrm{b} \\times \\mathrm{h}=24 \\times 18 \\times 4=1728 \\mathrm{cm}^{3}$\n\nQuestion 9.\n\nA wall 9 m long, 6 m high and 20 cm thick, is to be constructed using bricks of dimensions 30 cm, 15 cm and 10 cm. How many bricks will be required?\n\nSolution:\n\nIt is given that\n\nLength of the wall $=9 \\mathrm{m}=9 \\times 100 \\mathrm{cm}=900 \\mathrm{cm}$\n\nHeight of the wall $=6 \\mathrm{m}=6 \\times 100 \\mathrm{cm}=600 \\mathrm{cm}$\n\nBreadth of the wall =20 cm\n\nWe know that\n\nVolume of the wall $=900 \\times 600 \\times 20 \\mathrm{cm}^{3}=10800000 \\mathrm{cm}^{3}$\n\nVolume of one Brick $=30 \\times 15 \\times 10 \\mathrm{cm}^{3}=4500 \\mathrm{cm}^{3}$\n\nSo we get\n\nNumber of bricks required to construct the wall $=\\frac{\\text { Volume of wall }}{\\text { Volume of one brick}}$ $=\\frac{10800000}{4500}$\n\n=2400\n\nQuestion 10.\n\nA solid cube of edge 14 cm is melted down and recasted into smaller and equal cubes each of edge 2 cm; find the number of smaller cubes obtained.\n\nSolution:-\n\nWe know that\n\nEdge of the big solid cube = 14 cm\n\nVolume of the big solid cube $=14 \\times 14 \\times 14 \\mathrm{cm}^{3}=2744 \\mathrm{cm}^{3}$\n\nSimilarly\n\nEdge of the small cube =2 cm\n\nVolume of one small cube $=2 \\times 2 \\times 2 \\mathrm{cm}^{3}=8 \\mathrm{cm}^{3}$\n\nSo we get\n\nNumber of smaller cubes obtained $=\\frac{\\text { Volume of big cube }}{\\text { Volume of one small cube }}=\\frac{2774}{8}=343$\n\nQuestion 11.\n\nA closed box is cuboid in shape with length =40cm, breadth =30cm and height =50cm. It is made of thin metal sheet. Find the cost of metal sheet required to make 20 such boxes, if 1 $m^{2}$ of metal sheet costs Rs. 45.\n\nSolution:-\n\nIt is given that\n\nLength of closed box (1) =40cm\n\nAnd height (h) =50cm", null, "We know that\n\nTotal surface area $=2(l \\times b+b \\times h+h \\times l)$\n\nSubstituting the values\n\n$=2(40 \\times 30+30 \\times 50+50 \\times 40) \\mathrm{cm}^{2}$\n\nBy further calculation\n\n$=2(1200+1500+2000) \\mathrm{cm}^{2}$\n\nSo we get\n\n$=2 \\times 4700=9400 \\mathrm{cm}^{2}$\n\nHere\n\nSurface area of sheet used for 20 such boxes $=9400 \\times 20=188000 \\mathrm{cm}^{2}=18.8 m^{2}$\n\nCost of $1 \\mathrm{m}^{2} sheet = Rs.45$\n\nWe get\n\nTotal cost $=18.8 \\times 45=Rs.846$\n\nQuestion 12.\n\nFour cubes, each of edge 9 cm, are joined as shown below:", null, "Write the dimensions of the resulting cuboid obtained. Also, find the total surface area and the volume of the resulting cuboid.\n\nSolution:-\n\nEdge of each cube =9cm\n\n(i) We know that\n\nLength of the cuboid formed by 4 cubes (1) $=9 \\times 4=36 \\mathrm{cm}$\n\nBreadth (b) =9cm and height (h) = 9cm\n\n(ii) Total surface area of the cuboid = 2(lb + bh + hl)\n\nSubstituting the values\n\n$=2(36 \\times 9+9 \\times 9+9 \\times 36) \\mathrm{cm}^{2}$\n\nBy further calculation\n\n$=2(324+81+324) \\mathrm{cm}^{2}$\n\nSo we get\n\n$=2 \\times 729 \\mathrm{cm}^{2}$ $=1458 \\mathrm{cm}^{2}$\n\n(iii) $Volume =\\quad l \\times b \\times h=36 \\times 9 \\times 9 cm^{2}=2916 cm^{3}$\n\nQuestion 13.\n\nHow many persons can be accommodated in a big-hall of dimensions 40 m, 25m and 15m; assuming that each person requires $5 m^{3}$ of air?\n\nSolution:-\n\nNo. of persons $=\\frac{\\text { Vol. of the hall }}{\\text { Vol. of air required for each person }}$\n\nIt is given that\n\nLength of the hall =40m\n\nHeight =15m\n\nHere\n\nVolume of the hall$=1 \\times \\mathrm{b} \\times \\mathrm{h}=40 \\times 25 \\times 15=15000 \\mathrm{m}^{3}$\n\nVolume of the air required for each person $=5 \\mathrm{m}^{3}$\n\nSo we get\n\nNo. of persons who can be accommodated $=\\frac{\\text { Volume of the hall }}{\\text { Volume of air required for each person }}=\\frac{15000 \\mathrm{m}^{3}}{5 \\mathrm{m}^{3}}=3000$\n\nQuestion 14.\n\nThe dimension of a class-room are; length = 15m, breadth =12m and height =7.5m. Find, how many children can be accommodated in this class-room; assuming 3.6 $m^{3}$ of air is needed for each child.\n\nSolution:-\n\nIt is given that\n\nLength of the room =15m\n\nHeight of the room =7.5m\n\nWe know that\n\nVolume of the room$=L \\times B \\times H=15 \\times 12 \\times 7.5 \\mathrm{m}^{3}=1350 \\mathrm{m}^{3}$\n\nVolume of air required for each child $=3.6 \\mathrm{m}^{3}$\n\nSo we get\n\nNo. of children who can be accommodated in the class room. $=\\frac{\\text { Volume of class room }}{\\text { Volume of air needed for each child }}=\\frac{1350 \\mathrm{m}^{3}}{3 \\cdot 6 \\mathrm{m}^{3}}$\n\n=375.\n\nQuestion 15.\n\nThe length, breadth and height of a room are 6m, 5.4m and 4 m respectively. Find the area of:\n\n(i) Its four-walls\n\n(ii) Its roof.\n\nSolution:-\n\nIt is given that\n\nLength of the room = 6m\n\nBreadth of the room = 5.4m\n\nHeight of the room = 4m\n\n(i) Area of four walls $=2(L+B) \\times H=2(6+5.4) \\times 4=2 \\times 11.4 \\times 4=91.2 \\mathrm{m}^{2}$\n\n(ii) Area of the roof $=L \\times B=6 \\times 5.4=32.4 \\mathrm{m}^{2}$" ]
[ null, "https://www.facebook.com/tr", null, "https://cdn1.byjus.com/wp-content/uploads/2019/05/class-8-maths-selina-solutions-for-chapter-21-surf.png", null, "https://cdn1.byjus.com/wp-content/uploads/2019/05/class-8-maths-selina-solutions-for-chapter-21-surf1.png", null ]
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https://jp.mathworks.com/matlabcentral/profile/authors/8244785-elvira-osuna-highley
[ "Community Profile", null, "# Elvira Osuna-Highley\n\n### MathWorks\n\n6 2017 年以降の合計貢献数\n\n#### Elvira Osuna-Highley's バッジ\n\nGiven a and b, return the sum a+b in c.\n\n2年弱 前\n\nFind the sum of all the numbers of the input vector\nFind the sum of all the numbers of the input vector x. Examples: Input x = [1 2 3 5] Output y is 11 Input x ...\n\n2年弱 前\n\nMake the vector [1 2 3 4 5 6 7 8 9 10]\nIn MATLAB, you create a vector by enclosing the elements in square brackets like so: x = [1 2 3 4] Commas are optional, s...\n\n2年弱 前\n\nTimes 2 - START HERE\nTry out this test problem first. Given the variable x as your input, multiply it by two and put the result in y. Examples:...\n\n2年弱 前\n\nPizza!\nGiven a circular pizza with radius _z_ and thickness _a_, return the pizza's volume. [ _z_ is first input argument.] Non-scor...\n\n2年弱 前\n\nIs my wife right?\nRegardless of input, output the string 'yes'.\n\n2年弱 前" ]
[ null, "https://jp.mathworks.com/responsive_image/150/0/0/0/0/cache/matlabcentral/profiles/8244785_1522125495546_DEF.jpg", null ]
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https://es.mathworks.com/matlabcentral/answers/510272-xor-operation-on-two-numbers
[ "# Xor operation on two numbers\n\n30 views (last 30 days)\nPRAVEEN GUPTA on 11 Mar 2020\nCommented: Pravindra Kumar on 4 Aug 2022\ni have two numbers 23 and 47, i have to convert them into binary and then perform the Xor operation how to do that\nJohn D'Errico on 11 Mar 2020\nlol\n\nBhaskar R on 11 Mar 2020\nEdited: Bhaskar R on 11 Mar 2020\nSince decimal to binary conversion may not produce same length of inputs to xor, we need to append 0's before the binary value\nin1 = 27;\nin2 = 47;\nx = dec2bin(in1);\ny = dec2bin(in2);\nif length(x)~=length(y)\nmax_len = max(length(x), length(y));\nx = [repmat('0', 1, max_len-length(x)), x];\ny = [repmat('0', 1, max_len-length(y)), y];\nend\nresult = xor(x-'0', y-'0');\n\nJohn D'Errico on 11 Mar 2020\nEdited: John D'Errico on 11 Mar 2020\nUse the 2 argument form of dec2bin, comverting to binary. This allows you to insure the two binary equivalents are stored with the same number of bits. So one of the binary forms may now have leading zero bits. Otherwise, dec2bin may leave one result too short for the xor. By computing the number of bits necessary in advance for each number, then we can use that 2 argument form for dec2bin.\nNext, you need to make the result a logical vector, not the character-form that dec2bin returns. While it looks like a binary number, it is not something that xor can use directly.\nFinally, a call to xor does the final piece.\nIt would look like this:\nx = 23;\ny = 47;\nnbits = floor(log2(max(x,y)))+1;\nxb = dec2bin(x,nbits) == '1';\nyb = dec2bin(y,nbits) == '1';\nresult = xor(xb,yb);\nDid it work? Yes.\nxb\nxb =\n1×6 logical array\n0 1 0 1 1 1\nyb\nyb =\n1×6 logical array\n1 0 1 1 1 1\nresult\nresult =\n1×6 logical array\n1 1 1 0 0 0\nAs you can see, xb now has a leading zero bit, as is needed to make the xor happy. As well, xb and yb are now numeric (logical) vectors, the other thing that xor will need.\nIf you need to convert result back into a decimal integer form, then use bin2dec. Don't forget to convert the binary form from xor back into characters first, else bin2dec will fail. The idea is to add '0' to the binary form, this gives the ascii numeric form for '0' and '1'. Then the function char takes it to characters, and bin2dec gives you an integer.\nbin2dec(char(result + '0'))\nans =\n56\nCould I have done this more compactly? Well, yes. Two lines would have been sufficient, because I never really needed to compute the number of bits in advance. The trick here is to use dec2bin only once, in a \"vectorized\" call.\nB = dec2bin([x,y]) == '1'\nB =\n2×6 logical array\n0 1 0 1 1 1\n1 0 1 1 1 1\nresult = xor(B(1,:),B(2,:))\nresult =\n1×6 logical array\n1 1 1 0 0 0\nYou can see the vectorized form of dec2bin is smart enough to automatically left pad the smaller number as is needed. That allows us to not need to precompute the number of bits needed. And if I really wanted the result returned in an integer form, I could have done that too.\nresult = bin2dec(char(xor(B(1,:),B(2,:)) + '0'))\nresult =\n56\nPravindra Kumar on 4 Aug 2022\nThanks" ]
[ null ]
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https://m.bdmusicbox.com/situation-synonym/
[ "", null, "", null, "# 100个同义词的“情景”\n\n“情境”的另一个词是什么?这节课提供了一个常用的列表同义词为英语“情景”配上非母语英语的图片和有用的例句。学习用这些词来代替“情境”来扩展你的语言英语词汇\n\n## 情况的同义词\n\n### 情境定义及例子\n\n• \"锡亚琴冰川的情况已得到控制,将军\"\n• “情况可能会变得相当危险。”\n• “他拼命想表达情况有多么紧急。”\n\n### “情境”的其他单词\n\n“situation”的常用同义词。\n\n• 球赛(非正式)\n• 情况下\n• 情况下\n• 条件\n• 一锅鱼(非正式用语)\n• 困境\n• 状态\n• 的状态\n• 现状\n\n100多个不同的单词来代替“situation”。\n\n• 能力\n• 事件\n• 气氛\n• 环境\n• 任命\n• 区域\n• 赋值\n• 大气\n• 球赛(非正式)\n• 基础\n• 泊位\n• 钢坯\n• 业务\n• 能力\n• 情况下\n• 挑战\n• 情况下\n• 情况下\n• 气候\n• 关注\n• 条件\n• 条件\n• 紧要关头\n• 上下文\n• 应急\n• 危机\n• 发展\n• 设计\n• 困难\n• 紧急\n• 侵位\n• 就业\n• 环境\n• 环境\n• 建立\n• 房地产\n• 事件\n• 结果为\n• 事实\n• 基础\n• 函数\n• 年级\n• 发生\n• 事件\n• 实例\n• 问题\n• 工作\n• 时刻\n• 一锅鱼(非正式用语)\n• 水平\n• 语言环境\n• 位置\n• 位置\n• 轨迹\n• 模式\n• 场合\n• 占领\n• 发生\n• 办公室\n• 的地方\n• 放置\n• 困境\n• 位置\n• 帖子\n• 的姿势\n• 实践\n• 困境\n• 问题\n• 职业\n• 问题\n• 排名\n• 真正的\n• 现实\n• 角色\n• 场景\n• 座位\n• 设置\n• Sitch\n• 网站\n• 现货\n• 阶段\n• 状态\n• 的状态\n• 驻扎\n• 状态\n• 现状\n• 主题\n• 的事情\n• 贸易\n• 麻烦\n• 真理\n• 空缺\n• 在哪里\n• 下落\n\n### 例子的同义词\n\n• 球赛(非正式)\n\n• 情况下\n\n• 情况下\n\n• 条件\n\n• 一锅鱼(非正式用语)\n\n• 困境\n\n• 状态\n\n• 的状态\n\n• 现状\n\n• 安全部队奉命出动以控制该市的局势。\n• 这个国家的局势几个月来一直保持相对稳定。\n• 记者们报道说,局势现在已经正常化。\n• 政治形势变得越来越令人压抑。\n• 情况变得相当可怕。\n• 他对形势作了深刻的分析。\n• 试着不要担心——你无法改变现状。\n• 没有什么比在战斗中独自一人更可怕的了。\n• 如果一个男人真爱你,永远不会放你走,不管遇到多大的困境。\n• 我必须向上级全面汇报情况。\n\n## 情况的另一个词|信息图", null, "", null, "0评论\n\n0\n\n)\nx" ]
[ null, "https://www.520xingyun.com/images/188_120.gif", null, "https://www.520xingyun.com/images/188_120.gif", null, "data:image/svg+xml,%3Csvg%20xmlns='http://www.w3.org/2000/svg'%20viewBox='0%200%202000%203100'%3E%3C/svg%3E", null, "data:image/svg+xml,%3Csvg%20xmlns='http://www.w3.org/2000/svg'%20viewBox='0%200%2056%2056'%3E%3C/svg%3E", null ]
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https://number.academy/29239
[ "# Number 29239\n\nNumber 29,239 spell 🔊, write in words: twenty-nine thousand, two hundred and thirty-nine . Ordinal number 29239th is said 🔊 and write: twenty-nine thousand, two hundred and thirty-ninth. The meaning of number 29239 in Maths: Is Prime? Factorization and prime factors tree. The square root and cube root of 29239. What is 29239 in computer science, numerology, codes and images, writing and naming in other languages. Other interesting facts related to 29239.\n\n## What is 29,239 in other units\n\nThe decimal (Arabic) number 29239 converted to a Roman number is (X)(X)(IX)CCXXXIX. Roman and decimal number conversions.\n\n#### Weight conversion\n\n29239 kilograms (kg) = 64460.3 pounds (lbs)\n29239 pounds (lbs) = 13262.7 kilograms (kg)\n\n#### Length conversion\n\n29239 kilometers (km) equals to 18169 miles (mi).\n29239 miles (mi) equals to 47056 kilometers (km).\n29239 meters (m) equals to 95928 feet (ft).\n29239 feet (ft) equals 8913 meters (m).\n29239 centimeters (cm) equals to 11511.4 inches (in).\n29239 inches (in) equals to 74267.1 centimeters (cm).\n\n#### Temperature conversion\n\n29239° Fahrenheit (°F) equals to 16226.1° Celsius (°C)\n29239° Celsius (°C) equals to 52662.2° Fahrenheit (°F)\n\n#### Time conversion\n\n(hours, minutes, seconds, days, weeks)\n29239 seconds equals to 8 hours, 7 minutes, 19 seconds\n29239 minutes equals to 2 weeks, 6 days, 7 hours, 19 minutes\n\n### Zip codes 29239\n\n• Zip code 29239 Arroyo Coche (Almogia), Andalucia, Málaga, Spain a map\n• Zip code 29239 4 de Marzo, Chiapas, San Cristóbal de las Casas, Mexico a map\n• Zip code 29239 Peje de Oro, Chiapas, San Cristóbal de las Casas, Mexico a map\n\n### Codes and images of the number 29239\n\nNumber 29239 morse code: ..--- ----. ..--- ...-- ----.\nSign language for number 29239:", null, "", null, "", null, "", null, "", null, "Number 29239 in braille:", null, "Images of the number\nImage (1) of the numberImage (2) of the number", null, "", null, "More images, other sizes, codes and colors ...\n\n#### Number 29239 infographic", null, "## Share in social networks", null, "## Mathematics of no. 29239\n\n### Multiplications\n\n#### Multiplication table of 29239\n\n29239 multiplied by two equals 58478 (29239 x 2 = 58478).\n29239 multiplied by three equals 87717 (29239 x 3 = 87717).\n29239 multiplied by four equals 116956 (29239 x 4 = 116956).\n29239 multiplied by five equals 146195 (29239 x 5 = 146195).\n29239 multiplied by six equals 175434 (29239 x 6 = 175434).\n29239 multiplied by seven equals 204673 (29239 x 7 = 204673).\n29239 multiplied by eight equals 233912 (29239 x 8 = 233912).\n29239 multiplied by nine equals 263151 (29239 x 9 = 263151).\nshow multiplications by 6, 7, 8, 9 ...\n\n### Fractions: decimal fraction and common fraction\n\n#### Fraction table of 29239\n\nHalf of 29239 is 14619,5 (29239 / 2 = 14619,5 = 14619 1/2).\nOne third of 29239 is 9746,3333 (29239 / 3 = 9746,3333 = 9746 1/3).\nOne quarter of 29239 is 7309,75 (29239 / 4 = 7309,75 = 7309 3/4).\nOne fifth of 29239 is 5847,8 (29239 / 5 = 5847,8 = 5847 4/5).\nOne sixth of 29239 is 4873,1667 (29239 / 6 = 4873,1667 = 4873 1/6).\nOne seventh of 29239 is 4177 (29239 / 7 = 4177).\nOne eighth of 29239 is 3654,875 (29239 / 8 = 3654,875 = 3654 7/8).\nOne ninth of 29239 is 3248,7778 (29239 / 9 = 3248,7778 = 3248 7/9).\nshow fractions by 6, 7, 8, 9 ...\n\n### Calculator\n\n 29239\n\n#### Is Prime?\n\nThe number 29239 is not a prime number. The closest prime numbers are 29231, 29243.\n\n#### Factorization and factors (dividers)\n\nThe prime factors of 29239 are 7 * 4177\nThe factors of 29239 are 1 , 7 , 4177 , 29239\nTotal factors 4.\nSum of factors 33424 (4185).\n\n#### Powers\n\nThe second power of 292392 is 854.919.121.\nThe third power of 292393 is 24.996.980.178.919.\n\n#### Roots\n\nThe square root √29239 is 170,994152.\nThe cube root of 329239 is 30,807338.\n\n#### Logarithms\n\nThe natural logarithm of No. ln 29239 = loge 29239 = 10,283259.\nThe logarithm to base 10 of No. log10 29239 = 4,465963.\nThe Napierian logarithm of No. log1/e 29239 = -10,283259.\n\n### Trigonometric functions\n\nThe cosine of 29239 is -0,980624.\nThe sine of 29239 is -0,195898.\nThe tangent of 29239 is 0,199769.\n\n### Properties of the number 29239\n\nIs a Friedman number: No\nIs a Fibonacci number: No\nIs a Bell number: No\nIs a palindromic number: No\nIs a pentagonal number: No\nIs a perfect number: No\n\n## Number 29239 in Computer Science\n\nCode typeCode value\n29239 Number of bytes28.6KB\nUnix timeUnix time 29239 is equal to Thursday Jan. 1, 1970, 8:07:19 a.m. GMT\nIPv4, IPv6Number 29239 internet address in dotted format v4 0.0.114.55, v6 ::7237\n29239 Decimal = 111001000110111 Binary\n29239 Decimal = 1111002221 Ternary\n29239 Decimal = 71067 Octal\n29239 Decimal = 7237 Hexadecimal (0x7237 hex)\n29239 BASE64MjkyMzk=\n29239 MD519b5f0dd9d71b2003189f2d35a7c89d1\n29239 SHA1e0d1916f98917cd200d5cc7a9b85aa9b78a3c07e\n29239 SHA224638e1725750b49e6da05fb7d1f5db231ff012baa66cc34ee9fef8af3\n29239 SHA25665c4c5cb9c378a66c771e231a654201df46e13bcfca71f7bde41ca079a146aa9\nMore SHA codes related to the number 29239 ...\n\nIf you know something interesting about the 29239 number that you did not find on this page, do not hesitate to write us here.\n\n## Numerology 29239\n\n### Character frequency in number 29239\n\nCharacter (importance) frequency for numerology.\n Character: Frequency: 2 2 9 2 3 1\n\n### Classical numerology\n\nAccording to classical numerology, to know what each number means, you have to reduce it to a single figure, with the number 29239, the numbers 2+9+2+3+9 = 2+5 = 7 are added and the meaning of the number 7 is sought.\n\n## Interesting facts about the number 29239\n\n### Asteroids\n\n• (29239) 1992 EJ17 is asteroid number 29239. It was discovered by UESAC from La Silla Observatory on 3/2/1992.\n\n## Number 29,239 in other languages\n\nHow to say or write the number twenty-nine thousand, two hundred and thirty-nine in Spanish, German, French and other languages. The character used as the thousands separator.\n Spanish: 🔊 (número 29.239) veintinueve mil doscientos treinta y nueve German: 🔊 (Anzahl 29.239) neunundzwanzigtausendzweihundertneununddreißig French: 🔊 (nombre 29 239) vingt-neuf mille deux cent trente-neuf Portuguese: 🔊 (número 29 239) vinte e nove mil, duzentos e trinta e nove Chinese: 🔊 (数 29 239) 二万九千二百三十九 Arabian: 🔊 (عدد 29,239) تسعة و عشرون ألفاً و مئتان و تسعة و ثلاثون Czech: 🔊 (číslo 29 239) dvacet devět tisíc dvěstě třicet devět Korean: 🔊 (번호 29,239) 이만 구천이백삼십구 Danish: 🔊 (nummer 29 239) niogtyvetusinde og tohundrede og niogtredive Dutch: 🔊 (nummer 29 239) negenentwintigduizendtweehonderdnegenendertig Japanese: 🔊 (数 29,239) 二万九千二百三十九 Indonesian: 🔊 (jumlah 29.239) dua puluh sembilan ribu dua ratus tiga puluh sembilan Italian: 🔊 (numero 29 239) ventinovemiladuecentotrentanove Norwegian: 🔊 (nummer 29 239) tjue-ni tusen, to hundre og tretti-ni Polish: 🔊 (liczba 29 239) dwadzieścia dziewięć tysięcy dwieście trzydzieści dziewięć Russian: 🔊 (номер 29 239) двадцать девять тысяч двести тридцать девять Turkish: 🔊 (numara 29,239) yirmidokuzbinikiyüzotuzdokuz Thai: 🔊 (จำนวน 29 239) สองหมื่นเก้าพันสองร้อยสามสิบเก้า Ukrainian: 🔊 (номер 29 239) двадцять дев'ять тисяч двiстi тридцять дев'ять Vietnamese: 🔊 (con số 29.239) hai mươi chín nghìn hai trăm ba mươi chín Other languages ...\n\n## News to email\n\nPrivacy Policy.\n\n## Comment\n\nIf you know something interesting about the number 29239 or any natural number (positive integer) please write us here or on facebook." ]
[ null, "https://numero.wiki/s/senas/lenguaje-de-senas-numero-2.png", null, "https://numero.wiki/s/senas/lenguaje-de-senas-numero-9.png", null, "https://numero.wiki/s/senas/lenguaje-de-senas-numero-2.png", null, "https://numero.wiki/s/senas/lenguaje-de-senas-numero-3.png", null, "https://numero.wiki/s/senas/lenguaje-de-senas-numero-9.png", null, "https://number.academy/img/braille-29239.svg", null, "https://numero.wiki/img/a-29239.jpg", null, "https://numero.wiki/img/b-29239.jpg", null, "https://number.academy/i/infographics/9/number-29239-infographic.png", null, "https://numero.wiki/s/share-desktop.png", null ]
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https://www.math.tu-berlin.de/fachgebiete_ag_diskalg/fachgebiet_algebra_zahlentheorie/v_menue/publications/in_proceedings/parameter/en/minhilfe/mobil/?tx_sibibtex_pi1%5Bcontentelement%5D=tt_content%3A541282&tx_sibibtex_pi1%5BshowUid%5D=1351072&cHash=27ae45a48aab71b921c50fb0f2fb2bff
[ "", null, "Fachgebiet Algorithmische AlgebraIn Proceedings\n\nPage Content\n\nCitation key BI-Explicit-Lower-Bounds-Via-Geometric-Complexity-Theory Peter Bürgisser and Christian Ikenmeyer Proceedings 45th ACM Symposium on Theory of Computing 141-150 2013 We prove the lower bound $R(M_m) \\ge \\frac32 m^2 - 2$ on the border rank of $m × m$ matrix multiplication by exhibiting explicit representation theoretic (occurence) obstructions in the sense of Mulmuley and Sohoni's geometric complexity theory (GCT) program. While this bound is weaker than the one recently obtained by Landsberg and Ottaviani, these are the first significant lower bounds obtained within the GCT program. Behind the proof is the new combinatorial concept of obstruction designs, which encode highest weight vectors in $\\mathrmSym^d \\bigotimes^3(\\mathbb C^n)^*$ and provide new insights into Kronecker coefficients." ]
[ null, "https://www.math.tu-berlin.de/fileadmin/Aperto_design/img/logo_03.gif", null ]
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https://answers.everydaycalculation.com/compare-fractions/6-15-and-8-6
[ "# Answers\n\nSolutions by everydaycalculation.com\n\n## Compare 6/15 and 8/6\n\n1st number: 6/15, 2nd number: 1 2/6\n\n6/15 is smaller than 8/6\n\n#### Steps for comparing fractions\n\n1. Find the least common denominator or LCM of the two denominators:\nLCM of 15 and 6 is 30\n\nNext, find the equivalent fraction of both fractional numbers with denominator 30\n2. For the 1st fraction, since 15 × 2 = 30,\n6/15 = 6 × 2/15 × 2 = 12/30\n3. Likewise, for the 2nd fraction, since 6 × 5 = 30,\n8/6 = 8 × 5/6 × 5 = 40/30\n4. Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction\n5. 12/30 < 40/30 or 6/15 < 8/6\n\nMathStep (Works offline)", null, "Download our mobile app and learn to work with fractions in your own time:\nAndroid and iPhone/ iPad\n\n#### Compare Fractions Calculator\n\nand\n\n© everydaycalculation.com" ]
[ null, "https://answers.everydaycalculation.com/mathstep-app-icon.png", null ]
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https://squ.pure.elsevier.com/en/publications/a-priori-hp-estimates-for-discontinuous-galerkin-approximations-t
[ "# A priori hp-estimates for discontinuous Galerkin approximations to linear hyperbolic integro-differential equations\n\nSamir Karaa, Amiya K. Pani*, Sangita Yadav\n\n*Corresponding author for this work\n\nResearch output: Contribution to journalArticlepeer-review\n\n1 Citation (Scopus)\n\n## Abstract\n\nAn hp-discontinuous Galerkin (DG) method is applied to a class of second order linear hyperbolic integro-differential equations. Based on the analysis of an expanded mixed type Ritz-Volterra projection, a priori hp-error estimates in L∞(L2)-norm of the velocity as well as of the displacement, which are optimal in the discretizing parameter h and suboptimal in the degree of polynomial p are derived. For optimal estimates of the displacement in L∞(L2)-norm with reduced regularity on the exact solution, a variant of Baker's nonstandard energy formulation is developed and analyzed. Results on order of convergence which are similar in spirit to linear elliptic and parabolic problems are established for the semidiscrete case after suitably modifying the numerical fluxes. For the completely discrete scheme, an implicit-in-time procedure is formulated, stability results are derived and a priori error estimates are discussed. Finally, numerical experiments on two dimensional domains are conducted which confirm the theoretical results.\n\nOriginal language English 1-23 23 Applied Numerical Mathematics 96 https://doi.org/10.1016/j.apnum.2015.04.006 Published - May 6 2015\n\n## Keywords\n\n• hp-Error estimates\n• Linear second order hyperbolic integro-differential equation\n• Local discontinuous Galerkin method\n• Mixed type Ritz-Volterra projection\n• Nonstandard formulation\n• Numerical experiments\n• Order of convergence\n• Role of stabilizing parameters\n• Semidiscrete and completely discrete schemes\n\n## ASJC Scopus subject areas\n\n• Applied Mathematics\n• Computational Mathematics\n• Numerical Analysis\n\n## Fingerprint\n\nDive into the research topics of 'A priori hp-estimates for discontinuous Galerkin approximations to linear hyperbolic integro-differential equations'. Together they form a unique fingerprint." ]
[ null ]
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https://www.mathworks.com/help/econ/msvar.smooth.html
[ "Main Content\n\n# smooth\n\nSmoothed inference of operative latent states in Markov-switching dynamic regression data\n\n## Syntax\n\n``SS = smooth(Mdl,Y)``\n``SS = smooth(Mdl,Y,Name,Value)``\n``[SS,logL] = smooth(___)``\n\n## Description\n\nexample\n\n``SS = smooth(Mdl,Y)` returns smoothed state probabilities `SS` of the operative latent states in the regime-switching data `Y`. The Markov-switching dynamic regression model `Mdl` models the data. `smooth` performs a forward recursion using `filter`, and then performs the reverse recursion of Kim .`\n\nexample\n\n````SS = smooth(Mdl,Y,Name,Value)` uses additional options specified by one or more name-value pair arguments. For example, `'Y0',Y0` initializes the dynamic component of each submodel by using the presample response data `Y0`.```\n\nexample\n\n``[SS,logL] = smooth(___)` also returns the estimated loglikelihood `logL` using any of the input argument combinations in the previous syntaxes.`\n\n## Examples\n\ncollapse all\n\nCompute smoothed state probabilities from a two-state Markov-switching dynamic regression model for a 1-D response process. This example uses arbitrary parameter values for the data-generating process (DGP).\n\nCreate Fully Specified Model for DGP\n\nCreate a two-state discrete-time Markov chain model for the switching mechanism.\n\n```P = [0.9 0.1; 0.2 0.8]; mc = dtmc(P);```\n\n`mc` is a fully specified `dtmc` object.\n\nFor each state, create an AR(0) (constant only) model for the response process. Store the models in a vector.\n\n```mdl1 = arima('Constant',2,'Variance',3); mdl2 = arima('Constant',-2,'Variance',1); mdl = [mdl1; mdl2];```\n\n`mdl1` and `mdl2` are fully specified `arima` objects.\n\nCreate a Markov-switching dynamic regression model from the switching mechanism `mc` and the vector of submodels `mdl`.\n\n`Mdl = msVAR(mc,mdl);`\n\n`Mdl` is a fully specified `msVAR` object.\n\nSimulate Data from DGP\n\n`smooth` requires responses to compute smoothed state probabilities. Generate one random response and state path, both of length 30, from the DGP.\n\n```rng(1000); % For reproducibility [y,~,sp] = simulate(Mdl,30);```\n\nCompute State Probabilities\n\nCompute filtered and smoothed state probabilities from the Markov-switching model given the simulated response data.\n\n```fs = filter(Mdl,y); ss = smooth(Mdl,y);```\n\n`fs` and `ss` are 30-by-2 matrices of filtered and smoothed state probabilities, respectively, for each period in the simulation horizon. Although the filtered state probabilities at time `t` (`fs(``t``,:)`) are based on the response data through time `t` (`y(1:``t``)`), the smoothed state probabilities at time `t` (`ss(t,:)`) are based on all observations.\n\nPlot the simulated state path and the filtered and smoothed state probabilities on the same graph.\n\n```figure plot(sp,'m') hold on plot(fs(:,2),'r') plot(ss(:,2),'g') yticks([0 1 2]) xlabel(\"Time\") title(\"Observed States with Estimated State Probabilities\") legend({'Simulated states','Filtered probability: state 2',... 'Smoothed probability: state 2'}) hold off```", null, "Consider a two-state Markov-switching dynamic regression model of the postwar US real GDP growth rate. The model has the parameter estimates presented in .\n\nCreate Markov-Switching Dynamic Regression Model\n\nCreate a fully specified discrete-time Markov chain model that describes the regime switching mechanism. Label the regimes.\n\n```P = [0.92 0.08; 0.26 0.74]; mc = dtmc(P,'StateNames',[\"Expansion\" \"Recession\"]);```\n\nCreate separate, fully specified AR(0) models for the two regimes.\n\n```sigma = 3.34; % Homoscedastic models across states mdl1 = arima('Constant',4.62,'Variance',sigma^2); mdl2 = arima('Constant',-0.48,'Variance',sigma^2); mdl = [mdl1 mdl2];```\n\nCreate the Markov-switching dynamic regression model from the switching mechanism `mc` and the state-specific submodels `mdl`.\n\n`Mdl = msVAR(mc,mdl);`\n\n`Mdl` is a fully specified `msVAR` object.\n\nLoad and Preprocess Data\n\nLoad the US GDP data set.\n\n`load Data_GDP`\n\n`Data` contains quarterly measurements of the US real GDP in the period 1947:Q1–2005:Q2. The period of interest in is 1947:Q2–2004:Q2. For more details on the data set, enter `Description` at the command line.\n\nTransform the data to an annualized rate series by:\n\n1. Converting the data to a quarterly rate within the estimation period\n\n2. Annualizing the quarterly rates\n\n```qrate = diff(Data(2:230))./Data(2:229); % Quarterly rate arate = 100*((1 + qrate).^4 - 1); % Annualized rate```\n\nThe transformation drops the first observation.\n\nCompute Smoothed State Probabilities\n\nCompute smoothed state probabilities for the data and model. Display the smoothed state distribution for 1972:Q2.\n\n```SS = smooth(Mdl,arate); SS(end,:)```\n```ans = 1×2 0.9396 0.0604 ```\n\n`SS` is a 228-by-2 matrix of smoothed state probabilities. Rows correspond to periods in the data `arate`, and columns correspond to the regimes.\n\nPlot the smoothed probabilities of recession, as in , Figure 6.\n\n```figure; plot(dates(3:230),SS(:,2),'r') datetick('x') recessionplot title(\"Full-Sample Smoothed Probabilities and NBER Recessions\")```", null, "Compute smoothed state probabilities from a three-state Markov-switching dynamic regression model for a 2-D VARX response process. This example uses arbitrary parameter values for the DGP.\n\nCreate Fully Specified Model for DGP\n\nCreate a three-state discrete-time Markov chain model for the switching mechanism.\n\n```P = [5 1 1; 1 5 1; 1 1 5]; mc = dtmc(P);```\n\n`mc` is a fully specified `dtmc` object. `dtmc` normalizes the rows of `P` so that they sum to `1`.\n\nFor each state, create a fully specified VARX(0) model (constant and regression coefficient matrix only) for the response process. Specify different constant vectors across models. Specify the same regression coefficient for the two regressors, and specify the same covariance matrix. Store the VARX models in a vector.\n\n```% Constants C1 = [1;-1]; C2 = [3;-3]; C3 = [5;-5]; % Regression coefficient Beta = [0.2 0.1;0 -0.3]; % Covariance matrix Sigma = [1.8 -0.4; -0.4 1.8]; % VARX submodels mdl1 = varm('Constant',C1,'Beta',Beta,... 'Covariance',Sigma); mdl2 = varm('Constant',C2,'Beta',Beta,... 'Covariance',Sigma); mdl3 = varm('Constant',C3,'Beta',Beta,... 'Covariance',Sigma); mdl = [mdl1; mdl2; mdl3];```\n\n`mdl` contains three fully specified `varm` model objects.\n\nFor the DGP, create a fully specified Markov-switching dynamic regression model from the switching mechanism `mc` and the submodels `mdl`.\n\n`Mdl = msVAR(mc,mdl);`\n\n`Mdl` is a fully specified `msVAR` model.\n\nSimulate Data from DGP\n\nSimulate data for the two exogenous series by generating 30 observations from the standard 2-D Gaussian distribution.\n\n```rng(1) % For reproducibility X = randn(30,2);```\n\nGenerate one random response and state path, both of length 30, from the DGP. Specify the simulated exogenous data for the submodel regression components.\n\n`[Y,~,SP] = simulate(Mdl,30,'X',X);`\n\n`Y` is a 30-by-2 matrix of one simulated response path. `SP` is a 30-by-1 vector of one simulated state path.\n\nCompute State Probabilities\n\nCompute smoothed state probabilities from the DGP given the simulated response data.\n\n`SS = smooth(Mdl,Y,'X',X);`\n\n`SS` is a 30-by-2 matrix of smoothed state probabilities for each period in the simulation horizon.\n\nPlot the simulated state path and the smoothed state probabilities on subplots in the same figure.\n\n```figure subplot(2,1,1) plot(SP,'m') yticks([1 2 3]) legend({'Simulated states'}) subplot(2,1,2) plot(SS,'-') legend({'Smoothed s1','Smoothed s2','Smoothed s3'})```", null, "Consider the data in Compute Smoothed Probabilities of Recession, but assume that the period of interest is 1960:Q1–2004:Q2. Also, consider adding an autoregressive term to each submodel.\n\nCreate Partially Specified Model for Estimation\n\nCreate a partially specified Markov-switching dynamic regression model for estimation. Specify AR(1) submodels.\n\n```P = NaN(2); mc = dtmc(P,'StateNames',[\"Expansion\" \"Recession\"]); mdl = arima(1,0,0); Mdl = msVAR(mc,[mdl; mdl]);```\n\nBecause the submodels are AR(1), each requires one presample observation to initialize its dynamic component for estimation.\n\nCreate Fully Specified Model Containing Initial Values\n\nCreate the model containing initial parameter values for the estimation procedure.\n\n```mc0 = dtmc(0.5*ones(2),'StateNames',[\"Expansion\" \"Recession\"]); submdl01 = arima('Constant',1,'Variance',1,'AR',0.001); submdl02 = arima('Constant',-1,'Variance',1,'AR',0.001); Mdl0 = msVAR(mc0,[submdl01; submdl02]);```\n\nLoad and Preprocess Data\n\nLoad the data. Transform the entire set to an annualized rate series.\n\n```load Data_GDP qrate = diff(Data)./Data(1:(end - 1)); arate = 100*((1 + qrate).^4 - 1);```\n\nIdentify the presample and estimation sample periods using the dates associated with the annualized rate series. Because the transformation applies the first difference, you must drop the first observation date from the original sample.\n\n```dates = datetime(dates(2:end),'ConvertFrom','datenum',... 'Format','yyyy:QQQ','Locale','en_US'); estPrd = datetime([\"1960:Q2\" \"2004:Q2\"],'InputFormat','yyyy:QQQ',... 'Format','yyyy:QQQ','Locale','en_US'); idxEst = isbetween(dates,estPrd(1),estPrd(2)); idxPre = dates < estPrd(1); ```\n\nEstimate Model\n\nFit the model to the estimation sample data. Specify the presample observation.\n\n```arate0 = arate(idxPre); arateEst = arate(idxEst); EstMdl = estimate(Mdl,Mdl0,arateEst,'Y0',arate0);```\n\n`EstMdl` is a fully specified `msVAR` object.\n\nCompute Smoothed State Probabilities\n\nCompute smoothed state probabilities from the estimated model and data in the estimation period. Specify the presample observation. Plot the estimated probabilities of recession.\n\n```SS = smooth(EstMdl,arateEst,'Y0',arate0); figure; plot(dates(idxEst),SS(:,2),'r') title(\"Full-Sample Smoothed Probabilities and NBER Recessions\") recessionplot```", null, "Consider the model and data in Compute Smoothed Probabilities of Recession.\n\nCreate the fully specified Markov-switching model.\n\n```P = [0.92 0.08; 0.26 0.74]; mc = dtmc(P,'StateNames',[\"Expansion\" \"Recession\"]); sigma = 3.34; mdl1 = arima('Constant',4.62,'Variance',sigma^2); mdl2 = arima('Constant',-0.48,'Variance',sigma^2); mdl = [mdl1; mdl2]; Mdl = msVAR(mc,mdl);```\n\nLoad and preprocess the data.\n\n```load Data_GDP qrate = diff(Data(2:230))./Data(2:229); arate = 100*((1 + qrate).^4 - 1); ```\n\nCompute smoothed state probabilities and the loglikelihood for the data and model.\n\n```[SS,logL] = smooth(Mdl,arate); logL```\n```logL = -640.3016 ```\n\n## Input Arguments\n\ncollapse all\n\nFully specified Markov-switching dynamic regression model, specified as an `msVAR` model object returned by `msVAR` or `estimate`. Properties of a fully specified model object do not contain `NaN` values.\n\nObserved response data, specified as a `numObs`-by-`numSeries` numeric matrix.\n\n`numObs` is the sample size. `numSeries` is the number of response variables (`Mdl.NumSeries`).\n\nRows correspond to observations, and the last row contains the latest observation. Columns correspond to individual response variables.\n\n`Y` represents the continuation of the presample response series in `Y0`.\n\nData Types: `double`\n\n### Name-Value Pair Arguments\n\nSpecify optional comma-separated pairs of `Name,Value` arguments. `Name` is the argument name and `Value` is the corresponding value. `Name` must appear inside quotes. You can specify several name and value pair arguments in any order as `Name1,Value1,...,NameN,ValueN`.\n\nExample: `'Y0',Y0,'X',X` initializes the dynamic component of each submodel in `Mdl` by using the presample response data `Y0`, and includes a linear regression component in each submodel composed of the predictor data in `X` and the specified regression coefficients.\n\nPresample response data, specified as the comma-separated pair consisting of `'Y0'` and a `numPreSampleObs`-by-`numSeries` numeric matrix.\n\nThe number of presample observations `numPreSampleObs` must be sufficient to initialize the AR terms of all submodels. If `numPreSampleObs` exceeds the AR order of any state, `smooth` uses the latest observations. By default, `Y0` is the initial segment of `Y`, which reduces the effective sample size.\n\nData Types: `double`\n\nInitial state probabilities, specified as the comma-separated pair consisting of `'S0'` and a nonnegative numeric vector of length `numStates`.\n\n`smooth` normalizes `S0` to produce a distribution.\n\nBy default, `S0` is a steady-state distribution computed by `asymptotics`.\n\nExample: `'S0',[0.2 0.2 0.6]`\n\nExample: `'S0',[0 1]` specifies state 2 as the initial state.\n\nData Types: `double`\n\nPredictor data used to evaluate regression components in all submodels of `Mdl`, specified as the comma-separated pair consisting of `'X'` and a numeric matrix or a cell vector of numeric matrices.\n\nTo use a subset of the same predictors in each state, specify `X` as a matrix with `numPreds` columns and at least `numObs` rows. Columns correspond to distinct predictor variables. Submodels use initial columns of the associated matrix, in order, up to the number of submodel predictors. The number of columns in the `Beta` property of `Mdl.SubModels(j)` determines the number of exogenous variables in the regression component of submodel `j`. If the number of rows exceeds `numObs`, then `smooth` uses the latest observations.\n\nTo use different predictors in each state, specify a cell vector of such matrices with length `numStates`.\n\nBy default, `smooth` ignores regression components in `Mdl`.\n\nData Types: `double`\n\n## Output Arguments\n\ncollapse all\n\nSmoothed state probabilities, returned as a `numObs`-by-`numStates` nonnegative numeric matrix.\n\nEstimated loglikelihood of the response data `Y`, returned as a numeric scalar.\n\n## Algorithms\n\n`smooth` refines current estimates of the state distribution that `filter` produces by iterating backward from the full sample history `Y`.\n\n Chauvet, M., and J. D. Hamilton. \"Dating Business Cycle Turning Points.\" In Nonlinear Analysis of Business Cycles (Contributions to Economic Analysis, Volume 276). (C. Milas, P. Rothman, and D. van Dijk, eds.). Amsterdam: Emerald Group Publishing Limited, 2006.\n\n Hamilton, J. D. \"A New Approach to the Economic Analysis of Nonstationary Time Series and the Business Cycle.\" Econometrica. Vol. 57, 1989, pp. 357–384.\n\n Hamilton, J. D. \"Analysis of Time Series Subject to Changes in Regime.\" Journal of Econometrics. Vol. 45, 1990, pp. 39–70.\n\n Hamilton, James D. Time Series Analysis. Princeton, NJ: Princeton University Press, 1994.\n\n Kim, C.-J. \"Dynamic Linear Models with Markov Switching.\" Journal of Econometrics. Vol. 60, 1994, pp. 1–22.\n\nDownload ebook" ]
[ null, "https://www.mathworks.com/help/examples/econ/win64/ComputeSmoothedStateProbabilitiesRefExample_01.png", null, "https://www.mathworks.com/help/examples/econ/win64/ComputeSmoothedStateProbabilitiesExample_01.png", null, "https://www.mathworks.com/help/examples/econ/win64/ComputeSmoothedStateProbabilitiesFromModelVARXExample_01.png", null, "https://www.mathworks.com/help/examples/econ/win64/SpecifyPresampleDataSmoothExample_01.png", null ]
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https://insights.thoughtworks.cn/how-to-python-json-serialization/
[ "# 用Python实现Json序列化库\n\n1. 利用标准库的接口:从python标准json库中的`JSONDecoder`继承,然后自定义实现一个`default`方法用来自定义序列化过程\n2. 利用第三方库实现:如`jsonpickle` `jsonweb` `json-tricks`\n\n1. 我们希望能简单的序列化任意自定义对象,只添加一行代码,或者不加入任何代码\n2. 我们希望序列化的结果不加入任何非预期的属性\n3. 我们希望能按照指定的类型进行反序列化,能自动处理嵌套的自定义类,只需要自定义类提供非常简单的支持,或者不需要提供任何支持\n4. 我们希望反序列化的时候能很好的处理属性不存在的情况,以便在我们加入某一属性的时候,可以设置默认值,使得旧版本的序列化结果可以正确的反序列化出来\n\n``````class A(JsonSerializable):\n\ndef __init__(self, a, b):\nsuper().__init__()\nself.a = a\nself.b = b if b is not None else B(0)\n\n@property\ndef id(self):\nreturn self.a\n\ndef _deserialize_prop(self, name, deserialized):\nif name == 'b':\nself.b = B.deserialize(deserialized)\nreturn\nsuper()._deserialize_prop(name, deserialized)\n\nclass B(JsonSerializable):\n\ndef __init__(self, b):\nsuper().__init__()\nself.b = b\n\nclass JsonSerializableTest(unittest.TestCase):\n\ndef test_model_should_serialize_correctly(self):\nself.assertEqual(json.dumps({'a': 1, 'b': {'b': 2}}), A(1, B(2)).serialize())\n\ndef test_model_should_deserialize_correctly(self):\na = A.deserialize(json.dumps({'a': 1, 'b': {'b': 2}}))\nself.assertEqual(1, a.a)\nself.assertEqual(2, a.b.b)\n\ndef test_model_should_deserialize_with_default_value_correctly(self):\na = A.deserialize(json.dumps({'a': 1}))\nself.assertEqual(1, a.a)\nself.assertEqual(0, a.b.b)``````\n\n(上面的测试有很多边界的情况、支持的变量类型并没有覆盖,此测试只是作为示例使用。)\n\n``````def is_normal_prop(obj, key):\nis_prop = isinstance(getattr(type(obj), key, None), property)\nis_func_attr = callable(getattr(obj, key))\nis_private_attr = key.startswith('__')\nreturn not (is_func_attr or is_prop or is_private_attr)\n\ndef is_basic_type(value):\nreturn value is None or type(value) in [int, float, str, bool]\n\nclass JsonSerializable:\n\ndef _serialize_prop(self, name):\nreturn getattr(self, name)\n\ndef _as_dict(self):\nprops = {}\nfor key in dir(self):\nif not is_normal_prop(self, key):\ncontinue\nvalue = self._serialize_prop(key)\nif not (is_basic_type(value) or isinstance(value, JsonSerializable)):\nraise Exception('unknown value to serialize to dict: key={}, value={}'.format(key, value))\nprops[key] = value if is_basic_type(value) else value._as_dict()\nreturn props\n\ndef serialize(self):\nreturn json.dumps(self._as_dict(), ensure_ascii=False)\n\ndef _deserialize_prop(self, name, deserialized):\nsetattr(self, name, deserialized)\n\n@classmethod\ndef deserialize(cls, json_encoded):\nif json_encoded is None:\nreturn None\n\nargs = inspect.getfullargspec(cls)\nargs_without_self = args.args[1:]\nobj = cls(*([None] * len(args_without_self)))\n\ndata = json.loads(json_encoded, encoding='utf8') if type(json_encoded) is str else json_encoded\nfor key in dir(obj):\nif not is_normal_prop(obj, key):\ncontinue\nif key in data:\nobj._deserialize_prop(key, data[key])\nreturn obj``````\n\n1. 当某一属性为自定义类的类型的时候,需要子类覆盖实现`_deserialize_prop`方法为反序列化过程提供支持\n2. 当某一属性为由自定义类构成的一个`list` `tuple` `dict`复杂对象时,需要子类覆盖实现`_deserialize_prop`方法为反序列化过程提供支持\n3. 简单属性必须为python内置的基础类型,比如如果某一属性的类型为`numpy.float64`,序列化反序列化将不能正常工作" ]
[ null ]
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http://sparse.tamu.edu/JGD_Margulies/wheel_5_1
[ "## JGD_Margulies/wheel_5_1\n\nCombinatorial optimization as polynomial eqns, Susan Margulies, UC Davis\nName wheel_5_1 JGD_Margulies 2168 57 61 182 182 Combinatorial Problem No 2008 S. Margulies J.-G. Dumas\nStructural Rank 57 true 12 1 0 0% 0% no no binary\nSVD Statistics\nMatrix Norm 3.467793e+00\nMinimum Singular Value 9.151579e-17\nCondition Number 3.789284e+16\nRank 51\nsprank(A)-rank(A) 6\nNull Space Dimension 6\nFull Numerical Rank? no\nDownload Singular Values\nDownload ```Combinatorial optimization as polynomial eqns, Susan Margulies, UC Davis From Jean-Guillaume Dumas' Sparse Integer Matrix Collection, http://ljk.imag.fr/membres/Jean-Guillaume.Dumas/simc.html http://arxiv.org/abs/0706.0578 Expressing Combinatorial Optimization Problems by Systems of Polynomial Equations and the Nullstellensatz Authors: J.A. De Loera, J. Lee, Susan Margulies, S. Onn (Submitted on 5 Jun 2007) Abstract: Systems of polynomial equations over the complex or real numbers can be used to model combinatorial problems. In this way, a combinatorial problem is feasible (e.g. a graph is 3-colorable, hamiltonian, etc.) if and only if a related system of polynomial equations has a solution. In the first part of this paper, we construct new polynomial encodings for the problems of finding in a graph its longest cycle, the largest planar subgraph, the edge-chromatic number, or the largest k-colorable subgraph. For an infeasible polynomial system, the (complex) Hilbert Nullstellensatz gives a certificate that the associated combinatorial problem is infeasible. Thus, unless P = NP, there must exist an infinite sequence of infeasible instances of each hard combinatorial problem for which the minimum degree of a Hilbert Nullstellensatz certificate of the associated polynomial system grows. We show that the minimum-degree of a Nullstellensatz certificate for the non-existence of a stable set of size greater than the stability number of the graph is the stability number of the graph. Moreover, such a certificate contains at least one term per stable set of G. In contrast, for non-3- colorability, we found only graphs with Nullstellensatz certificates of degree four. Filename in JGD collection: Margulies/wheel_5_1.sms```" ]
[ null ]
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https://wiki.openoffice.org/w/index.php?title=Documentation/OOo3_User_Guides/Calc_Guide/Examples_of_functions&oldid=190775
[ "# Examples of functions\n\n(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)\n\nFor novices, functions are one of the most intimidating features of OpenOffice.org's Calc. New users quickly learn that functions are an important feature of spreadsheets, but there are almost four hundred, and many require input that assumes specialized knowledge. Fortunately, Calc includes dozens of functions that anyone can use.\n\n## Basic arithmetic and statistic functions\n\nThe most basic functions create formulas for basic arithmetic or for evaluating numbers in a range of cells.\n\n### Basic arithmetic\n\nThe simple arithmetic operations are addition, subtraction, multiplication, and division.\n\nExcept for subtraction, each of these operations has its own function.\n\n• PRODUCT for multiplication\n• QUOTIENT for division.\n\nTraditionally, subtraction does not have a function.\n\nSUM, PRODUCT and QUOTIENT are useful for entering ranges of cells in the same way as any other function, with arguments in brackets after the function name.\n\nHowever, for basic equations, many users prefer the time-honored computer symbols for these operations, using the plus sign (+) for addition, the hyphen (–) for subtraction, the asterisk (*) for multiplication and the forward slash (/) for division. These symbols are quick to enter without requiring your hands to stray from the keyboard.\n\nA similar choice is also available if you want to raise a number by the power of another. Instead of entering =POWER(A1;2), you can enter =A1^2.\n\nMoreover, they have the advantage that you enter formulas with them in an order that more closely approximates human readable format than the spreadsheet-readable format used by the equivalent function. For instance, instead of entering =SUM (A1:A2), or possibly =SUM (A1;A2), you enter =A1+A2. This almost-human readable format is especially useful for compound operations, where writing =A1*(A2+A3) is briefer and easier to read than =PRODUCT(A1;SUM(A2:A3)).\n\nThe main disadvantage of using arithmetical operators is that you cannot directly use a range of cells. In other words, to enter the equivalent of =SUM (A1:A3), you would need to type =A1+A2+A3.\n\nOtherwise, whether you use a function or an operator is largely up to you—except, of course, when you are subtracting. However, if you use spreadsheets regularly in a group setting such as a class or an office, you might want to standardize on an entry format so that everyone who handles a spreadsheet becomes accustomed to a standard input.\n\n### Simple statistics\n\nAnother common use for spreadsheet functions is to pull useful information out of a list, such as a series of test scores in a class, or a summary of earnings per quarter for a company.\n\nYou can, of course, scan a list of figures if you want basic information such as the highest or lowest entry or the average. The only trouble is, the longer the list, the more time you waste and the more likely you are to miss what you’re looking for. Instead, it is usually quicker and more efficient to enter a function. Such reasons explain the existence of a function like COUNT, which does no more than give the total number of entries in the designated cell range.\n\nSimilarly, to find the highest or lowest entry, you can use MIN or MAX. For each of these formulas, all arguments are either a range of cells, or a series of cells entered individually.\n\nEach also has a related function, MINA or MAXA, which performs the same function, but treats a cell formatted for text as having a value of 0 (The same treatment of text occurs in any variation of another function that adds an \"A\" to the end). Either function gives the same result, and could be useful if you used a text notation to indicate, for example, if any student were absent when a test was written, and you wanted to check whether you needed to schedule a makeup exam.\n\nFor more flexibility in similar operations, you could use LARGE or SMALL, both of which add a specialized argument of rank. If the rank is 1 used with LARGE, you get the same result as you would with MAX. However, if the rank is 2, then the result is the second largest result. Similarly, a rank of 2 used with SMALL gives you the second smallest number. Both LARGE and SMALL are handy as a permanent control, since, by changing the rank argument, you can quickly scan multiple results.\n\nYou would need to be an expert to want to find the Poisson Distribution of a sample, or to find the skew or negative binominal of a distribution (and, if you are, you will find functions in Calc for such things). However, for the rest of us, there are simpler statistical functions that you can quickly learn to use.\n\nIn particular, if you need an average, you have a number to choose from. You can find the arithmetical means—that is, the result when you add all entries in a list then divided by the number of entries—by using AVERAGE, or AVERAGE A to include text entries and to give them a value of zero.\n\nIn addition, you can get several other forms of averages:\n\n• MEDIAN: The entry that is exactly half way between the highest and lowest number in a list.\n• MODE: The most common entry in a list of numbers.\n• QUARTILE:The entry at a set position in the array of numbers. Besides the cell range, you enter the type of Quartile: O for the lowest entry, 1 for the value of 25%, 2 for the value of 50%, 3 for 75%, and 4 for the highest entry. Note that the result for types 1 through 3 may not represent an actual item entered.\n• RANK: The position of a given entry in the entire list, measured either from top to bottom or bottom to top. You need to enter the cell address for the entry, the range of entries, and the type of rank (0 for the rank from the highest, or 1 for the rank from the bottom.\n\nSome of these functions overlap; for example, MIN and MAX are both covered by QUARTILE. In other cases, a custom sort or filter might give much the same result. Which you use depends on your temperament and your needs. Some might prefer to use MIN and MAX because they are easy to remember, while others might prefer QUARTILE because it is more versatile.\n\n### Using these functions\n\nIn some cases, you may be able to get similar results to some of these functions by setting up a filter or a custom sort. However, in general, functions are more easily adjusted than filters or sorts, and provide a wide range of possibilities.\n\nAt times, you may just want to enter one or more formulas temporarily in a convenient blank square, and delete it once you have finished. However, if you find yourself using the same functions constantly, you should consider creating a template and including space for all the functions you use, with the cell to their left used as a label for them. Once you have created the template, you can easily update each formula as entries change, either automatically and on-the-fly or pressing the F9 key to update all selected cells.\n\nNo matter how you use these functions, you will probably find them simple to use and adaptable to many purposes. And, by the time you have mastered this handful, you will be ready to try more complex functions.\n\n## Rounding off numbers\n\nFor statistical and mathematical purposes, Calc includes a variety of ways to round off numbers. If you’re a programmer, you may also be familiar with some of these methods. However, you don’t need to be a specialist to find some of these methods useful. You may want to round off for billing purposes, or because decimal places don’t translate well into the physical world—for instance, if the parts you need come in packages of 100, then the fact you only need 66 is irrelevant to you; you need to round up for ordering. By learning the options for rounding, you can make your spreadsheets more immediately useful.\n\nWhen you use a rounding function, you have two choices about how to set up your formulas. If you choose, you can nest a calculation within one of the rounding functions. For instance, the formula =ROUND((SUM(A1;A2)) adds the figures in cells A1 and A2, then rounds them off to the nearest whole number. However, even though you don’t need to work with exact figures every day, you may still want to refer to them occasionally. If that is the case, then you are probably better off separating the two functions, placing =SUM(A1;A2) in cell A3, and =ROUND (A3) in A4, and clearly labelling each function. Which choice you make for layout depends largely on your work habits.\n\n### Rounding methods\n\nThe most basic function for rounding numbers in Calc is ROUND. This function will round off a number according to the usual rules of symmetric arithmetic rounding: a decimal place of .4 or less gets rounded down, while one of .5 or more gets rounded up. However, at times, you may not want to follow these rules. For instance, if you are one of those contractors who bills a full hour for any fraction of an hour you work, you would want to always round up so you didn’t lose any money. Conversely, you might choose to round down to give a slight discount to a long-established customer. In these cases, you might prefer to use ROUNDUP or ROUNDDOWN, which, as their names suggest, round a number to the nearest integer above or below it.\n\nAll three of these functions require the single argument of number—the cell or number to be rounded. Used with only this argument, all three functions round to the nearest whole number, so that 46.5 would round to 47 with ROUND or ROUNDUP and 46 with ROUNDDOWN. However, if you use the optional count argument, you can specify the number of decimal places to include. For instance, if number was set to 1, then 48.65 would round to 48.7 with ROUND or ROUNDUP and to 48.6 with ROUNDDOWN.\n\nAs an alternative to ROUNDDOWN when working with decimals, you can use TRUNC (short for truncate). It takes exactly the same arguments as ROUNDDOWN, so which function you use is a matter of choice. If you aren't working with decimals, you might choose to use INT (short for integer), which takes only the number argument.\n\nAnother option is the ODD and EVEN pair of functions. ODD rounds up to the nearest odd number if what is entered in the number argument is a positive number, and rounds down if it is a negative number, while EVEN does the same for an even number.\n\nOptions are the CEILING and FLOOR functions. As you can guess from the names, CEILING rounds up and FLOOR rounds down. For both functions, the number that they round to is determined by the closest multiple of the number that you enter as the significance argument. For instance, if your business insurance is billed by the work week, the fact that you were only open three days one week would be irrelevant to your costs; you would still be charged for an entire week, and therefore might want to use CEILING in your monthly expenses.\n\nConversely, if you are building customized computers and completed 4.5 in a day, your client would only be interested in the number ready to ship, so you might use FLOOR in a report of your progress.If cell E1 contains the value 46.7, =CEILING(E1;7) will return the value 49.\n\nBesides number and significance, both CEILING and FLOOR include an optional argument called mode, which takes a value of 0 or 1. If mode is set to 0, and both the number and the significance are negative numbers, then the result of either function is rounded up; if it is set to 1, and both the number and the significance are negative numbers, the the results are rounded down. In other words, if the number is -11 and the significance is -5, then the result is -10 when the mode is set to 0, but -15 when set to 1.\n\nHowever, if you are exchanging spreadsheets between Calc and MS Excel, remember that the mode argument is not supported by Excel. If you want the answers to be consistent between the two spreadsheets, set the mode in Calc to -1.\n\nA function somewhat similar to CEILING and FLOOR is MROUND. Like CEILING AND FLOOR, MROUND requires two arguments, although, somewhat confusingly, the second one is called multiple rather than significance, even though the two are identical. The difference between MROUND and CEILING and FLOOR is that MROUND rounds up or down using symmetric arithmetic rounding. For example, if the number is 77 and the multiple is 5, then MROUND gives a result of 75. However, if the multiple is changed to 7, then MROUND's result becomes 77.\n\nOnce you tease the various rounding functions out of Calc’s long, undifferentiated list of functions, you can start to decide which is most useful for your purposes.\n\nHowever, one last point is worth mentioning: If you are working with more than two decimal places, don't be surprised if you don’t see the same number of decimal places on the spreadsheet as you do on the function wizard. If you don’t, the reason is that Tools > Options > OpenOffice.org Calc > Calculate > Decimal Places defaults to 2. Change the number of decimal places, and, if necessary, uncheck the Precision as shown box on the same page, and the spreadsheet will display as expected." ]
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https://dsp.stackexchange.com/questions/73067/how-to-find-inverse-fourier-transform-of-summ-of-delta-functions
[ "# How to find inverse Fourier transform of summ of delta functions?\n\nI am practicing for my exam that I have this semester and I stumbled upon this one. How can i find inverse Fourier transform given: $$X(j\\omega) = \\sum_{k=-\\infty}^{\\infty}\\delta(\\omega-2k+1)$$\n\n• Have you tried using the definition of the (inverse) FT and the definition of the delta distribution? It's quite straight forward, really. Feb 6, 2021 at 19:35\n\nUsing Duality Property, we have $$X(j\\omega) = \\delta(\\omega-\\omega_{0})$$. By using this and rewriting our function using $$1-2k = -\\omega_{0}$$, we get: \\begin{align} x(t) &= \\frac{1}{2\\pi}\\int_{-\\infty}^{\\infty}\\delta(\\omega-\\omega_{0})e^{j\\omega t}d\\omega \\\\ &= \\frac{1}{2\\pi}e^{j \\omega_0 t} \\end{align} $$\\sum_{k=-\\infty}^{\\infty}\\delta(\\omega-\\omega_{k})\\leftrightarrow \\frac{1}{2\\pi}\\sum_{k=-\\infty}^{\\infty}e^{j\\omega_{k}t}$$ Hence: $$\\sum_{k=-\\infty}^{\\infty}\\delta(\\omega+1-2k)\\leftrightarrow \\frac{1}{2\\pi}\\sum_{k=-\\infty}^{\\infty}e^{j(2k-1)t}$$" ]
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https://www.numbersaplenty.com/10100
[ "Search a number\nBaseRepresentation\nbin10011101110100\n3111212002\n42131310\n5310400\n6114432\n741306\noct23564\n914762\n1010100\n117652\n125a18\n13479c\n143976\n152ed5\nhex2774\n\n10100 has 18 divisors (see below), whose sum is σ = 22134. Its totient is φ = 4000.\n\nThe previous prime is 10099. The next prime is 10103. The reversal of 10100 is 101.\n\nAdded to its reverse (101) it gives a square (10201 = 1012).\n\n10100 = T15 + T16 + ... + T39.\n\nIt can be written as a sum of positive squares in 3 ways, for example, as 2704 + 7396 = 52^2 + 86^2 .\n\nIt is a sliding number, since 10100 = 100 + 10000 and 1/100 + 1/10000 = 0.010100.\n\nIt is a Harshad number since it is a multiple of its sum of digits (2).\n\nIt is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.\n\nIt is a plaindrome in base 13.\n\nIt is a nialpdrome in base 11.\n\nIt is a congruent number.\n\nIt is not an unprimeable number, because it can be changed into a prime (10103) by changing a digit.\n\nIt is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 50 + ... + 150.\n\n210100 is an apocalyptic number.\n\n10100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.\n\nIt is a pronic number, being equal to 100×101.\n\nIt is an amenable number.\n\nIt is a practical number, because each smaller number is the sum of distinct divisors of 10100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (11067).\n\n10100 is an abundant number, since it is smaller than the sum of its proper divisors (12034).\n\nIt is a pseudoperfect number, because it is the sum of a subset of its proper divisors.\n\n10100 is a wasteful number, since it uses less digits than its factorization.\n\n10100 is an evil number, because the sum of its binary digits is even.\n\nThe sum of its prime factors is 115 (or 108 counting only the distinct ones).\n\nThe product of its (nonzero) digits is 1, while the sum is 2.\n\nThe square root of 10100 is about 100.4987562112. The cubic root of 10100 is about 21.6159233295.\n\nAdding to 10100 its reverse (101), we get a palindrome (10201).\n\nSubtracting from 10100 its reverse (101), we obtain a palindrome (9999).\n\nMultiplying 10100 by its reverse (101), we get a square (1020100 = 10102).\n\n10100 divided by its reverse (101) gives a square (100 = 102).\n\nThe spelling of 10100 in words is \"ten thousand, one hundred\", and thus it is an iban number." ]
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https://codingdots.in/c-program-using-break-continue/
[ "# C program using break & continue.\n\n`01 #include<stdio.h>02 03 int main()04 {05 int num;06 07 while(1) //always true08 {09 printf(\"nnEnter a Number ( < = 100) to find its Square .\");10 printf(\"nPress 0 To Exit. : \");11 scanf(\"%d\",&num);12 if(num==0)13 {14 printf(\"nProgram End. Thank You\");15 break;16 }17 else if(num>100)18 {19 printf(\"nYou Enter number greater than 100 : Try again\");20 continue;21 }22 23 printf(\"nSquare of %d is %d\",num,(num*num));24 25 }26 return 0;27 }`\n` `\n` OUTPUT : Enter a Number ( < = 100) to find its Square . Press 0 To Exit. : 3 Square of 3 is 9 Enter a Number ( < = 100) to find its Square . Press 0 To Exit. : 5 Square of 5 is 25 Enter a Number ( < = 100) to find its Square . Press 0 To Exit. : 0 Program End. Thank You`" ]
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https://metanumbers.com/1530383
[ "1530383 (number)\n\n1,530,383 (one million five hundred thirty thousand three hundred eighty-three) is an odd seven-digits composite number following 1530382 and preceding 1530384. In scientific notation, it is written as 1.530383 × 106. The sum of its digits is 23. It has a total of 2 prime factors and 4 positive divisors. There are 1,522,920 positive integers (up to 1530383) that are relatively prime to 1530383.\n\nBasic properties\n\n• Is Prime? No\n• Number parity Odd\n• Number length 7\n• Sum of Digits 23\n• Digital Root 5\n\nName\n\nShort name 1 million 530 thousand 383 one million five hundred thirty thousand three hundred eighty-three\n\nNotation\n\nScientific notation 1.530383 × 106 1.530383 × 106\n\nPrime Factorization of 1530383\n\nPrime Factorization 211 × 7253\n\nComposite number\nDistinct Factors Total Factors Radical ω(n) 2 Total number of distinct prime factors Ω(n) 2 Total number of prime factors rad(n) 1530383 Product of the distinct prime numbers λ(n) 1 Returns the parity of Ω(n), such that λ(n) = (-1)Ω(n) μ(n) 1 Returns: 1, if n has an even number of prime factors (and is square free) −1, if n has an odd number of prime factors (and is square free) 0, if n has a squared prime factor Λ(n) 0 Returns log(p) if n is a power pk of any prime p (for any k >= 1), else returns 0\n\nThe prime factorization of 1,530,383 is 211 × 7253. Since it has a total of 2 prime factors, 1,530,383 is a composite number.\n\nDivisors of 1530383\n\n4 divisors\n\n Even divisors 0 4 2 2\nTotal Divisors Sum of Divisors Aliquot Sum τ(n) 4 Total number of the positive divisors of n σ(n) 1.53785e+06 Sum of all the positive divisors of n s(n) 7465 Sum of the proper positive divisors of n A(n) 384462 Returns the sum of divisors (σ(n)) divided by the total number of divisors (τ(n)) G(n) 1237.09 Returns the nth root of the product of n divisors H(n) 3.98058 Returns the total number of divisors (τ(n)) divided by the sum of the reciprocal of each divisors\n\nThe number 1,530,383 can be divided by 4 positive divisors (out of which 0 are even, and 4 are odd). The sum of these divisors (counting 1,530,383) is 1,537,848, the average is 384,462.\n\nOther Arithmetic Functions (n = 1530383)\n\n1 φ(n) n\nEuler Totient Carmichael Lambda Prime Pi φ(n) 1522920 Total number of positive integers not greater than n that are coprime to n λ(n) 108780 Smallest positive number such that aλ(n) ≡ 1 (mod n) for all a coprime to n π(n) ≈ 116022 Total number of primes less than or equal to n r2(n) 0 The number of ways n can be represented as the sum of 2 squares\n\nThere are 1,522,920 positive integers (less than 1,530,383) that are coprime with 1,530,383. And there are approximately 116,022 prime numbers less than or equal to 1,530,383.\n\nDivisibility of 1530383\n\n m n mod m 2 3 4 5 6 7 8 9 1 2 3 3 5 1 7 5\n\n1,530,383 is not divisible by any number less than or equal to 9.\n\nClassification of 1530383\n\n• Arithmetic\n• Semiprime\n• Deficient\n\n• Polite\n\n• Square Free\n\nOther numbers\n\n• LucasCarmichael\n\nBase conversion (1530383)\n\nBase System Value\n2 Binary 101110101101000001111\n3 Ternary 2212202021212\n4 Quaternary 11311220033\n5 Quinary 342433013\n6 Senary 52445035\n8 Octal 5655017\n10 Decimal 1530383\n12 Duodecimal 61977b\n20 Vigesimal 9b5j3\n36 Base36 wsun\n\nBasic calculations (n = 1530383)\n\nMultiplication\n\nn×y\n n×2 3060766 4591149 6121532 7651915\n\nDivision\n\nn÷y\n n÷2 765192 510128 382596 306077\n\nExponentiation\n\nny\n n2 2342072126689 3584267367458691887 5485301846613535266102721 8394612695925961941144080472143\n\nNth Root\n\ny√n\n 2√n 1237.09 115.239 35.1722 17.2568\n\n1530383 as geometric shapes\n\nCircle\n\n Diameter 3.06077e+06 9.61568e+06 7.35784e+12\n\nSphere\n\n Volume 1.50137e+19 2.94313e+13 9.61568e+06\n\nSquare\n\nLength = n\n Perimeter 6.12153e+06 2.34207e+12 2.16429e+06\n\nCube\n\nLength = n\n Surface area 1.40524e+13 3.58427e+18 2.6507e+06\n\nEquilateral Triangle\n\nLength = n\n Perimeter 4.59115e+06 1.01415e+12 1.32535e+06\n\nTriangular Pyramid\n\nLength = n\n Surface area 4.05659e+12 4.2241e+17 1.24955e+06\n\nCryptographic Hash Functions\n\nmd5 6822cd9f9bfb475464c5cc8b3f3930e1 a44c591316a19e86ce2ec51752c43c37731ccbe5 1a1952065713dba79f980e0460bfc5bf7e1b8f2471b0ca660b2ae67278ab780f 4abb57f48625ae1d8b5fe137d583d282735974908441a85493f46fd8df7fb65a979bf0a5217f0bebb5f5b32f88ba0c197eadbf7147ae7740bcf981610bfdfef5 259f80f5c51113bf46ed446a9944c9bebdfe25c9" ]
[ null ]
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https://cran.itam.mx/web/packages/ciTools/vignettes/ciTools_survreg_vignette.html
[ "# Accelerated Failure Time Models with ciTools\n\n#### 08 January, 2019\n\nlibrary(tidyverse)\nlibrary(knitr)\nlibrary(ciTools)\nlibrary(here)\nset.seed(20180925)\n\nDisclaimer: ciTools makes three assumptions about your model:\n\n1 - no missing data in the “newdata” matrix, tb.\n\n2 - distribution is one of weibull, lognormal, loglogistic, or exponential.\n\n3 - regression model is unweighted, and without random effects.\n\nThe purpose of this vignette is to introduce and discuss new ciTools capabilities for handling accelerated failure time (AFT) models. Some of the new AFT methods in ciTools are more informative than methods for previous models, and will inform future development decisions that will be made in ciTools. In particular, ciTools now supports intervals for estimated survival time probabilities and quantiles for a range of common AFTs.\n\n## The Accelerated Failure Time Model\n\nThe accelerated failure time model is, like a generalized linear model (GLM), an extension of the standard linear model that accounts for specific types of data and non-linearity. AFTs constitute and important class of models as they can handle censored, highly skewed data – exactly the type of data one would expect to collect when analyzing the failure times of a machine, or the survival times of a group of patients under study.\n\nAFTs are special in the field of survival/reliability analysis in that they are fully parametric models. This provides power to do certain inferences such as the estimation of tail probabilities that would be difficult in a non or semi-parametric framework. The trade-off made is that a specific distribution for survival times must be assumed, and this assumption may be incorrect.\n\nThe structure of accelerated failure time models is as follows. We observe a vector of survival times (failure times, in the reliability literature) $$T$$ given a data matrix $$X$$. We assume the $$\\log$$ of the survival times is affected linearly by the covariates of $$X$$. Because $$T$$ is non-negative, we model the effect of the linear predictor $$X\\beta$$ on $$\\log(T)$$. The model is\n\n$F(T|X) = F \\left( \\frac{\\log(T) - X\\beta}{\\sigma} \\right).$\n\n$$F$$ denotes a vectorized, standard distribution function; $$X\\beta$$ is called the linear predictor; and $$\\sigma$$ is called the scale parameter. $$S(T|X)$$ is called he survivor function; the probability that a unit will fail after time $$T$$. $$S(T|X) = 1 - F(T|X)$$. Thus the AFT model is a family of log-linear models. Examples of $$F$$ that are common are the standard normal, standard logistic, and standard smallest extreme value distribution functions (Meeker and Escobar, Ch. 4). We can more clearly write the model as\n\n$\\log(T) = X\\beta + \\sigma \\varepsilon,$\n\nwhere $$\\varepsilon \\sim F$$ to make the linear effect of $$\\beta$$ on $$\\log(T)$$ a bit more apparent.\n\nLike generalized linear models, survival models are fit through a maximum likelihood procedure. This is most useful in that it allows a practitioner to specify censored data in the statistical model. That AFTs are fully parametric and may account for data censoring were primary reasons for adding them to ciTools. We assume that AFTs are fit in R with the survreg function from the survival library.\n\n### Examples of AFTs\n\nFour examples of AFT models are presented, which are covered completely by ciTools. This list of AFT models is not exhaustive, as other models are available. See the flexsurv package, for example. Models in the flexsurv package do not presently receive treatment by ciTools.\n\n1. Lognormal: Let $$\\varepsilon \\sim N(0,1)$$. Then $$\\log(T) = X\\beta + \\sigma \\varepsilon$$ and $$T$$ is said to be lognormal with parameters $$X\\beta$$ and $$\\sigma$$. Confidence intervals for the following parameters are available in ciTools.\n\n$E(T|X) = \\exp(X \\beta + \\frac{\\sigma^2}{2}) \\qquad (\\text{expected time to failure})$\n\n$\\text{median}(T|X) = \\exp(X\\beta) \\qquad (\\text{median time to failure})$\n\n$S(T|X) = 1 - \\Phi \\left( \\frac{\\log(T) - X\\beta}{\\sigma} \\right) \\qquad \\Phi \\sim \\text{std. Normal CDF}$\n\n$F^{-1}_p(T|X) = \\exp(X\\beta + \\Phi^{-1}(p) \\sigma) \\qquad (\\text{level p quantile of failure time distribution})$\n\n1. Weibull: Let $$\\varepsilon$$ possess smallest extreme value distribution. We write $$\\varepsilon \\sim SEV$$ with $$F_{SEV}(\\varepsilon) = 1-\\exp(-\\exp(\\varepsilon))$$. If $$\\log(T) = X\\beta + \\sigma\\varepsilon$$, then $$T$$ is weibull distributed with scale parameter $$\\sigma$$ and location parameter $$\\exp(X\\beta)$$ in the location-scale parameterization used in the survival package. This parameterization differs from the one used in {p/d/q/r}weibull, see help(survreg) for details.\n\n$E(T|X) = \\exp(X\\beta)\\Gamma(1 + \\sigma)$\n\n$\\text{median}(T|X) = \\exp(X\\beta + F^{-1}_{SEV}(0.5) \\sigma) = \\exp(X\\beta)(\\log(2))^{\\sigma}$\n\n$F^{-1}_p(T|X) = \\exp(X\\beta + F^{-1}_{SEV}(p) \\sigma) = \\exp(X\\beta)(-\\log(1-p))^{\\sigma}$\n\n$S(T|X) = \\exp(-\\exp(z)), \\qquad z = \\frac{\\log(T) - X\\beta}{\\sigma}$\n\n1. Exponential: Like the weibull distribution, except scale parameter $$\\sigma$$ is fixed to $$1$$.\n\n$E(T|X) = \\exp(X\\beta)$\n\n$\\text{median}(T|X) = \\exp(X\\beta + F^{-1}_{SEV}(0.5)) = \\exp(X\\beta)\\log(2)$\n\n$F^{-1}_p(T|X) = \\exp(X\\beta + F^{-1}_{SEV}(p)) = \\exp(X\\beta)(-\\log(1-p))$\n\n$S(T|X) = \\exp(-\\exp(z)), \\qquad z = \\log(T) - X\\beta$\n\n1. Loglogistic: Let $$\\varepsilon \\sim \\text{Logistic}$$. That is, $$F(\\varepsilon) = \\frac{\\exp(\\varepsilon)}{1 + \\exp(\\varepsilon)}$$, the standard logistic distribution. Then $$\\log(T) = X\\beta + \\sigma\\varepsilon$$, and $$T$$ is loglogistic distributed with scale parameter $$\\sigma$$ and location parameter $$X\\beta$$.\n\n$E(T|X) = \\exp(X\\beta)\\Gamma(1 + \\sigma)\\Gamma(1 - \\sigma)$\n\n$\\text{median}(T|X) = \\exp(X\\beta)$\n\n$F^{-1}_p(T|X) = \\exp(X\\beta + \\sigma F^{-1}_{Logistic}(p))$\n\n$S(T|X) = 1 - F_{Logistic} \\left( \\frac{\\log(T) - X\\beta}{\\sigma} \\right)$\n\nNote that the median of each conditional failure time distribution is technically the level $$p=0.5$$ quantile of that same distribution. For this reason, confidence intervals for medians are calculated with add_quantile().\n\n## AFT Uncertainty Intervals\n\nIn the analysis of AFT models, statisticians have several options for making predictions. predict.survreg for example, allows one to predict the median failure time, or any other quantile. These predictions have the same units as the original time scale (time to death or failure). Additionally, predict.survreg can also output the corresponding value of the linear predictor for a given point in the factor space.\n\nciTools hopes to clarify survival times prediction for AFT models by relegating prediction of the expected (mean) survival time to add_ci.survreg, and prediction of the median (or any quantile) of the survival time distribution to add_quantile.survreg. Thus add_ci.survreg is in line with other add_ci S3 methods provided by ciTools by only providing confidence intervals for the expected response conditioned on the predictors.\n\nThere are three popular methods for forming confidence intervals in this case: parametrically, using either the (1) delta method or (2) likelihood ratios, or (3) through a bootstrap resampling procedure. In ciTools, we generally favor parametric methods, except where it makes sense to include bootstrap methods as options, as is the case with many mixed effects models, where bootstrap methods are seen as less controversial than parametric interval methods.\n\nWe have studied these three techniques for interval estimation, and found that the delta method offers the best combination of speed and accuracy for users. Therefore, the delta method is used as the basis of all interval estimation procedures in ciTools for AFT models. This is at odds with the recommendations of Meeker and Escobar in favor of likelihood based intervals, however we implement delta method based intervals as they are much easier to write for multivariate models and do not suffer from any convergence issues. Compared to bootstrap intervals, delta method intervals are faster and have similar probability coverage in many scenarios.\n\n## Example.\n\nData are collected on the failure times of a new spring installed in a car. The spring can be mounted in two types of cars, an SUV or a sedan. An additional variable, ambient temperature was also recorded. Experimental vehicles were fitted with the new springs, and the vehicles are placed into an observational study. Vehicles with the new springs were driven, and the failure times of the springs were noted until the conclusion of the test time. The test concluded after $$2000$$ cumulative hours of testing. At this time, all surviving springs at marked as right censored at $$t=2000$$. All data are notional.\n\nThe time variable indicates of the number of hours driven before a spring failure is observed. If failure = 1, a spring failure is observed at the indicated time.\n\nkable(head(dat))\ntemp car time failure\n40.00000 suv 5.6414974 1\n41.22449 sedan 2.5287376 1\n42.44898 suv 44.3712587 1\n43.67347 sedan 12.1143060 1\n44.89796 suv 0.0344103 1\n46.12245 sedan 198.6757464 1\nggplot(dat, aes(x = temp, y = time)) +\ngeom_point(aes(color = factor(failure)))+\nggtitle(\"Censored obs. in red\") +\ntheme_bw()", null, "Seven of the observations are censored at $$t = 2000$$. This means we assume those $$7$$ springs would eventually fail at some later point in time had we chosen to run the study for a longer period of time. We fit a weibull model to the data. By default, Surv will infer (correctly, in this case) that our observations are right censored at $$t=2000$$. Check the documentation of Surv for how to coordinate a different censoring regime – survreg is very flexible in the types of censoring allowed (another advantage of AFT models). Other distributions (exponential, lognormal, loglogistic) are available in survreg for parametric analysis, and receive treatment in ciTools, but we stick the weibull model for the example.\n\n(fit <- survreg(Surv(time, failure) ~ temp + car, data = dat)) ## weibull dist is default\n## Call:\n## survreg(formula = Surv(time, failure) ~ temp + car, data = dat)\n##\n## Coefficients:\n## (Intercept) temp carsuv\n## 0.31303047 0.08126381 -0.25327482\n##\n## Scale= 1.019839\n##\n## Loglik(model)= -283.3 Loglik(intercept only)= -307.8\n## Chisq= 48.98 on 2 degrees of freedom, p= 2.32e-11\n## n= 50\n\nThe output of survreg indicates that the model on the whole is significantly better than one which does not include any covariates. Maximum likelihood estimates of coefficients are displayed as well. We can analyze the model graphically with the help of ciTools. The summary function can be called on fit to show some additional information about the model coefficients. We calculate confidence and prediction intervals, and append them to the original data set.\n\nwith_ints <- ciTools::add_ci(dat,fit, names = c(\"lcb\", \"ucb\")) %>%\nciTools::add_pi(fit, names = c(\"lpb\", \"upb\"))\nkable(head(with_ints))\ntemp car time failure mean_pred lcb ucb median_pred lpb upb\n40.00000 suv 5.6414974 1 27.62779 15.72767 48.53195 18.85020 0.6447620 103.7026\n41.22449 sedan 2.5287376 1 39.31490 23.04415 67.07392 26.82422 0.9175093 147.5709\n42.44898 suv 44.3712587 1 33.71138 19.77579 57.46708 23.00098 0.7867375 126.5378\n43.67347 sedan 12.1143060 1 47.97198 28.92116 79.57187 32.73086 1.1195433 180.0658\n44.89796 suv 0.0344103 1 41.13457 24.83171 68.14080 28.06576 0.9599757 154.4012\n46.12245 sedan 198.6757464 1 58.53533 36.23626 94.55678 39.93814 1.3660649 219.7160\n\nThe output of ciTools’s functions is always the inputted data with the requested statistics attached. The inputted data can be original data or a data frame of new observations. For this model fit, add_ci calculates conditional means (denoted mean_pred in the data frame) and add_pi calculates conditional medians (median_pred in the data frame).\n\nggplot(with_ints, aes(x = temp, y = time)) +\ngeom_point(aes(color = car)) +\nfacet_wrap(~car)+\ntheme_bw() +\nggtitle(\"Model fit with 95% CIs and PIs\",\n\"solid line = mean, dotted line = median\") +\ngeom_line(aes(y = mean_pred), linetype = 1) +\ngeom_line(aes(y = median_pred), linetype = 2) +\ngeom_ribbon(aes(ymin = lcb, ymax = ucb), alpha = 0.5) +\ngeom_ribbon(aes(ymin = lpb, ymax = upb), alpha = 0.1)", null, "probs <- ciTools::add_probs(dat, fit, q = 500,\nname = c(\"prob\", \"lcb\", \"ucb\"),\ncomparison = \">\")\n\nWe can calculate the estimated survival probabilities as well. Below, we calculate the probability of a spring failing after $$t = 500$$ (alternatively, the probability of a spring not failing before $$t = 500$$). This is not a new feature to ciTools, what’s special to survreg methods is that ciTools will additionally compute confidence intervals for the estimated conditional survival probabilities.\n\nggplot(probs, aes(x = temp, y = prob)) +\nggtitle(\"Estimated prob. of avg. spring lasting longer than 500 hrs.\") +\nylim(c(0,1)) +\nfacet_wrap(~car)+\ntheme_bw() +\ngeom_line(aes(y = prob)) +\ngeom_ribbon(aes(ymin = lcb, ymax = ucb), alpha = 0.5)", null, "quants <- ciTools::add_quantile(dat, fit, p = 0.90,\nname = c(\"quant\", \"lcb\", \"ucb\"))\n\nFurthermore, we can calculate quantiles of the distribution of failure times given the covariates in dat. Again, the special sauce for AFT models comes when ciTools also tacks on confidence intervals for the estimated quantiles. Here, we show the estimated $$0.90$$ quantile, conditioned on the covariate information, with confidence intervals. One may use add_quantile to calculate the median failure time, or any other quantile.\n\nggplot(quants, aes(x = temp, y = time)) +\ngeom_point(aes(color = car)) +\nggtitle(\"Estimated 90th percentile of condtional failure distribution, with CI\") +\nfacet_wrap(~car)+\ntheme_bw() +\ngeom_line(aes(y = quant)) +\ngeom_ribbon(aes(ymin = lcb, ymax = ucb), alpha = 0.5)", null, "## The Delta Method for Regression Models\n\nHere are the mathematical details for calculating the above confidence intervals. For AFT models, we calculate confidence intervals with the delta method (Prediction intervals are calculated using different methods, discussed later).\n\nLet $$\\boldsymbol{\\theta} = (\\beta_0, \\beta_1, \\ldots, \\beta_p, \\sigma)$$ be the vector of maximum likelihood parameter estimates for the statistical model. We wish to form confidence intervals for continuous and twice differentiable functions of $$\\boldsymbol{\\theta}$$, say $$\\mathbf{g}(\\boldsymbol{\\theta})$$. Because $$\\hat{\\boldsymbol{\\theta}}_{ML}$$ is a maximum likelihood estimator of $$\\boldsymbol{\\theta}$$, $$\\mathbf{g}(\\hat{\\boldsymbol{\\theta}_{ML}})$$ is a maximum likelihood estimator of $$\\mathbf{g}(\\boldsymbol{\\theta})$$. In large samples, $$\\mathbf{g}(\\hat{\\boldsymbol{\\theta}})$$ is approximately Normally distributed with mean $$\\mathbf{g}(\\boldsymbol{\\theta})$$ and variance-covariance matrix\n\n$\\Sigma_{\\hat{g}} = \\left[ \\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}}\\right]^T \\Sigma_{\\hat{\\boldsymbol{\\theta}}} \\left[ \\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}}\\right].$\n\nThis approximation is based on the assumption that $$\\mathbf{g}({\\hat{\\boldsymbol{\\theta}}})$$ is linear in $$\\hat{\\boldsymbol{\\theta}}$$ in a region near $$\\boldsymbol{\\theta}$$. The larger the sample, the better, because the variation in $$\\hat{\\boldsymbol{\\theta}}$$ decreases with sample size and thus the region over which $$\\hat{\\boldsymbol{\\theta}}$$ varies is correspondingly smaller. If the region is small enough, the approximation is adequate.\n\nMathematically, the delta method is a statistical rebranding of the a Taylor series expansion for $$\\mathrm{Var}[\\mathbf{g}(\\hat{\\boldsymbol{\\theta}})]$$ . We will use the delta method to form confidence intervals for functions of $$\\boldsymbol{\\theta}$$: expected values, quantiles, and survivor functions.\n\n## Expected Values\n\nBecause it is somewhat easier to explain confidence intervals for the mean if we have a particular model in mind, suppose for the moment that we fit a Weibull AFT model. The expected survival time, $$\\mathrm{E}[T|X]$$, written as a function of $$\\boldsymbol{\\theta}$$, is $$\\mathbf{g}(\\boldsymbol{\\theta}) = \\exp(X\\beta)\\Gamma(1 + \\sigma)$$. We form a confidence interval for this mean survival time based on the estimated regression coefficients ($$\\hat{\\boldsymbol{\\beta}}$$, and $$\\hat{\\sigma}$$) from survreg. Due to some quirks in numerical optimization, it is often advantageous to reparameterize the scale parameter as $$\\delta = \\log(\\sigma)$$ in the model. Let $$x$$ denote a point in the factor space at which we wish to calculate the expected failure time. The relevant derivatives are\n\n$\\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\beta}} = \\exp(x^T \\boldsymbol{\\beta}) x^T \\Gamma(1 + \\exp(\\delta)) ,\\qquad i = 0, \\ldots, p,$ and $\\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\delta} = \\exp(x^T \\boldsymbol{\\beta}) \\Gamma(1 + \\exp(\\delta)) \\psi(1 + \\exp(\\delta)) \\exp(\\delta),$\n\nwhere $$\\psi(\\cdot)$$ denotes the digamma function. Let $$\\frac{\\partial\\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}} = \\left(\\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_0}, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_1}, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_2}, \\ldots, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_p}, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\delta}\\right)^T$$.\n\nThe standard error of the expected survival time estimate is\n\n$\\mathrm{s.e.}(\\mathbf{g} (\\hat{\\boldsymbol{\\theta}})) = \\sqrt{\\left[ \\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}}\\right]^T \\Sigma_{\\hat{\\boldsymbol{\\theta}}} \\left[ \\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}}\\right]}.$\n\nAn approximate $$100\\times(1 - \\alpha)\\%$$ confidence interval for $$\\mathbf{g}(\\boldsymbol{\\theta}) = \\mathrm{E}[T]$$ based on the large sample standard Normal approximation of $$Z_{\\log(\\mathbf{g}(\\hat{\\boldsymbol{\\theta}}))} = \\frac{\\log(\\mathbf{g}(\\hat{\\boldsymbol{\\theta}})) - \\log(\\mathbf{g}(\\boldsymbol{\\theta}))}{s.e.(\\mathbf{g} (\\hat{\\boldsymbol{\\theta}}))}$$ is\n\n$\\left[\\mathrm{lower}, \\mathrm{upper} \\right] = \\left[\\mathbf{g}(\\hat{\\boldsymbol{\\theta}})/w, \\mathbf{g}(\\hat{\\boldsymbol{\\theta}}) \\times w \\right],$\n\nwhere $$w = \\exp(z_{1-\\alpha/2} \\times \\mathrm{s.e.}(\\mathbf{g} (\\hat{\\boldsymbol{\\theta}})) / \\mathbf{g}(\\hat{\\boldsymbol{\\theta}}))$$.\n\nConfidence intervals for the expected response of other AFT models may be calculated similarly, except that the function $$\\mathbf{g}$$ depends on the response distribution. For other functions of $$\\boldsymbol{\\theta}$$ such as the survivor function or response quantile, we apply the delta method as well.\n\n### Simulation Setup\n\nA simulation was conducted to investigate the performance of uncertainty intervals for AFT models. We varied sample size, distribution, and the proportion of observations censored. In all simulations, a simple AFT models with one predictor was used. A time censoring mechanism was assumed and set at one of three levels: no censoring, mild censoring (30% of observations censored) or moderate censoring (50% of observations censored).\n\nThe number of simulations for each combination of distribution and censoring was $$10,000$$ (for the confidence intervals) or $$5000$$ (for prediction intervals, survival probabilities, and quantiles).\n\n### Simulation for expected value CIs\n\nWe produce graphs of the performance of the delta method for confidence intervals on the expected survival time. Below we show the observed coverage probability as sample size, distribution, and censoring proportion vary. The nominal coverage probability is set at 90% for all simulations.\n\nWe observe acceptable performance from the delta method in this case. Larger amounts of censoring (30% and 50%) produce mostly lower coverage probabilities for all distributions except the exponential distribution. The worst case scenario appears to be small sample Lognormal fits with moderate censoring. In this case, there is a near 10% gap between the nominal and observed coverage probabilities.", null, "", null, "Interval widths generally shrink to zero, which is expected. In one case, Lognormal fits with sample size 20 and 50% censoring, the interval widths are too large. This is due to too many unconverged maximum likelihood estimates.", null, "## Survivor Function\n\nCalculating confidence intervals for estimated probabilities requires a bit more care to ensure that the confidence bounds lie in the (0,1) interval. Because the mathematics of the confidence intervals for the survivor function depend less on the actual distribution, we won’t focus on the Weibull model, and will treat all AFT models at once. The predicted probability of survival at time $$T$$, $$\\hat{S}(T|X)$$, written as a function of $$\\boldsymbol{\\theta}$$, is $$\\mathbf{g}(\\boldsymbol{\\theta}) = 1 - \\Phi \\left( \\frac{\\log(T) - X\\boldsymbol{\\beta}}{\\sigma}\\right)$$. Similar to the previous example, we form a confidence interval for this probability of survival based on the estimated regression coefficients ($$\\hat{\\boldsymbol{\\beta}}$$ and $$\\hat{\\sigma}$$) from survreg. The maximum likelihood estimator of the survivor function is $$\\hat{S}(T|X)_{ML} = \\Phi \\left( \\frac{\\log(T) - X\\hat{\\beta}}{\\hat{\\sigma}}\\right)$$. The relevant derivatives are\n\n$\\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\beta} = f \\left(\\frac{\\log(T) - x^T \\boldsymbol{\\beta}}{\\sigma}\\right) \\times \\left(\\frac{-x^T}{\\sigma}\\right),\\qquad i = 0, \\ldots, n,$\n\nand\n\n$\\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\delta} = f \\left(\\frac{\\log(T) - x^T \\boldsymbol{\\beta}}{\\sigma}\\right) \\times \\left(\\frac{x^T \\boldsymbol{\\beta} - \\log(T)}{\\sigma} \\right),$\n\nwhere $$f(\\cdot)$$ denotes the probability density function corresponding to $$\\Psi$$, and $$x_i$$ is a new observation\\$. Let $$\\frac{\\partial\\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}} = \\left(\\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_0}, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_1}, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_2}, \\ldots, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\beta_p}, \\frac{\\partial \\mathbf{g}(\\boldsymbol{\\theta})}{\\partial \\delta}\\right)^T$$.\n\nDue to the delta method, the mathematical form of the standard errors of the estimated survival probability is as it was in the previous example:\n\n$\\mathrm{s.e.}(\\mathbf{g} (\\hat{\\boldsymbol{\\theta}})) = \\sqrt{\\left[ \\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}}\\right]^T \\Sigma_{\\hat{\\boldsymbol{\\theta}}} \\left[ \\frac{\\partial \\mathbf{g} (\\boldsymbol{\\theta})}{\\partial \\boldsymbol{\\theta}}\\right]}$\n\nThe obvious confidence interval based on the statistic $$\\frac{\\hat{S} - S}{\\hat{s.e.}(\\hat{S})}$$ could be potentially a very poor fit approximation. The approximation could be poor due to a small to moderate number of failures in the data (Meeker and Escobar, p. 190) or because the bounds of the confidence interval could far exceed the interval $$[0,1]$$. The chosen solution is to apply a transformation $$u(\\cdot)$$ such that $$\\frac{u(\\hat{S}) - u(S)}{\\hat{s.e.}(\\hat{u})}$$ is closer in distribution to a standard Normal distribution. A transformation that achieves this is the logistic transform.\n\n$u(\\hat{S}) = \\log \\left( \\frac{\\hat{S}}{1 - \\hat{S}} \\right)$\n\nFirst, we find a confidence interval for $$u(\\hat{S})$$, then transform the endpoints of the interval to the $$[0,1]$$ through the inverse logistic function to find a confidence interval for $$\\hat{S}$$.\n\n$\\left[\\mathrm{lower}, \\mathrm{upper} \\right] = \\left[ \\frac{\\hat{S}}{\\hat{S} + (1 - \\hat{S}) \\times w}, \\frac{\\hat{S}}{\\hat{S} + (1 - \\hat{S})/w} \\right]$\n\nwhere $$w = \\exp \\left( \\frac{z_{1 - \\alpha/2} \\hat{s.e.} (\\hat{S}) } {\\hat{S}(1 - \\hat{S})}\\right)$$.\n\n### Simulations for Survivor Function\n\nPlots below show the performance of the delta method for uncertainty intervals of the survivor function. Again we compare the observed coverage probability with the 90% nominal probability. In contrast to intervals for the mean, censoring appears to produce overly conservative intervals. This is particularly clear in the case of the Weibull distribution.", null, "However on the (0,1) probability scale, we find acceptable performance.", null, "Intervals widths go to zero as sample size increases.", null, "## Prediction Intervals\n\nWe have not yet discussed prediction intervals, but ciTools also has methods for creating two different types of prediction intervals. The first type is the “naive” method of Meeker and Escobar. The naive method simply forms a prediction interval based on $$\\alpha/2$$ and $$1-\\alpha/2$$ quantiles of the estimated conditional distribution. The method is naive in the sense that it does not account for uncertainty in the estimates of the parameters $$\\boldsymbol{\\beta}$$ and $$\\sigma$$. This method is simple and works reasonably well in the absence of censoring, as displayed in the plots below.\n\nA slightly better method is included in ciTools, which we call the simulation method. We generate prediction intervals for the next failure time by a parametric bootstrap. This simulation method assumes a multivariate normal distribution for the model coefficients (excluding the scale parameter) and generates new responses that account for this uncertainty in the model coefficients, $$\\boldsymbol{\\beta}$$. This should make the bootstrap method slightly better than the naive method in practice, though a bit more computationally expensive. This is essentially what we have done to produce prediction intervals for GLMs as well, just applied to the new class of AFT models.\n\nFrom the plot below, it’s pretty clear that the bootstrap method outperforms the naive method. The difference is most stark when there is a moderate amount of censoring.\n\nFurther improvements beyond the naive and simulations methods may be made. These techniques are detailed in Meeker and Escobar (Chapter 12), but have yet to be implemented in ciTools.", null, "", null, "Unlike confidence intervals, interval widths of prediction intervals should not shrink to zero as sample size is increased. Instead we should observe interval widths converge to a constant.", null, "", null, "", null, "", null, "References:\n\nMeeker, William Q., and Luis A. Escobar. Statistical methods for reliability data. John Wiley & Sons, 2014. (Chapter 4, 8, and Appendix B)\n\nHarrell, Frank E. Regression modeling strategies. Springer, 2015. (Chapter 17)\n\nsessionInfo()\n## R version 3.5.2 (2018-12-20)\n## Platform: x86_64-w64-mingw32/x64 (64-bit)\n## Running under: Windows 10 x64 (build 16299)\n##\n## Matrix products: default\n##\n## locale:\n## LC_COLLATE=C\n## LC_CTYPE=English_United States.1252\n## LC_MONETARY=English_United States.1252\n## LC_NUMERIC=C\n## LC_TIME=English_United States.1252\n##\n## attached base packages:\n## stats graphics grDevices utils datasets methods base\n##\n## other attached packages:\n## SPREDA_1.0 nlme_3.1-137 survival_2.43-3 here_0.1\n## arm_1.10-1 lme4_1.1-18-1 Matrix_1.2-15 MASS_7.3-51.1\n## knitr_1.20 bindrcpp_0.2.2 broom_0.5.0 ciTools_0.5.1\n## forcats_0.3.0 stringr_1.3.1 dplyr_0.7.7 purrr_0.2.5\n## readr_1.1.1 tidyr_0.8.1 tibble_1.4.2 ggplot2_3.0.0\n## tidyverse_1.2.1\n##\n## loaded via a namespace (and not attached):\n## Rcpp_0.12.17 lubridate_1.7.4 lattice_0.20-38 assertthat_0.2.0\n## rprojroot_1.3-2 digest_0.6.15 utf8_1.1.4 R6_2.3.0\n## cellranger_1.1.0 plyr_1.8.4 backports_1.1.2 evaluate_0.12\n## coda_0.19-2 httr_1.3.1 highr_0.7 pillar_1.3.0\n## rlang_0.2.2 lazyeval_0.2.1 readxl_1.1.0 rstudioapi_0.8\n## minqa_1.2.4 nloptr_1.0.4 rmarkdown_1.10 labeling_0.3\n## splines_3.5.2 munsell_0.5.0 compiler_3.5.2 modelr_0.1.2\n## pkgconfig_2.0.2 htmltools_0.3.6 tidyselect_0.2.4 codetools_0.2-15\n## fansi_0.4.0 crayon_1.3.4 withr_2.1.2 grid_3.5.2\n## jsonlite_1.5 gtable_0.2.0 magrittr_1.5 scales_0.5.0\n## cli_1.0.1 stringi_1.1.7 reshape2_1.4.3 xml2_1.2.0\n## boot_1.3-20 tools_3.5.2 glue_1.3.0 hms_0.4.2\n## abind_1.4-5 yaml_2.1.19 colorspace_1.3-2 rvest_0.3.2\n## bindr_0.1.1 haven_1.1.2" ]
[ null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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", null, 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pAP3o4MgDIImgkA8bPd3VsP8BxAOwkA5gBArXgVEgDAic4EoCQAAGhZUoUCAKbONwKA7skBAEMHAHYACgIAgJYlVSgAYOp8IwDonhwAMHQA0ABATgAA0LKkCgUATJ1vBADdkwMAhg4AmgBY2XeIYBTKNwKAZiMAcKIDAACgqV566wMAK+sOEYxC+UYA0GwEAE50AAAANNVLb70AYGXbIoVRKN8IAJqNAMCJDgAAgKZ66a0fAGjvxwMA8mA1TEgAACc6AAAAmuqlt54AYNkihVEo3wgAmo0AwIkOAACApnrprS8A1G+RwiiUbwQAzUYA4EQHAABAU7301hsAardIYRTKNwKAZiMAcKIDAACgqV566w8AdVukMArlGwFAsxEAONEBAADQVC+99QiAmi1SGIXyjZ4CAIHEYWyVix4APUB2kHvL7wHoLVIYhfKNnvYAXoUEAHCiAwAAoKleeusVAOQWKYxC+UYA0GwEAE50AAAANNVLb/0CgNoihVEo3wgAmo0AwIkOAACApnrprWcAEFukMArlGwFAsxEAONEBAADQVC+99Q0Ac4sURqF8IwBoNgIAJzoAAACa6qW33gFgbJHCKJRvBADNRgDgRAcAAEBTvfTWPwD0LVIYhfKNAKDZCACc6AAAAGiql956CIBJAAAgjgGATecbPQWgQgAAII4BgE3nGz0EwCAAABDHAMCm843eAlC/URwA6FJXthEAONH7AKATAACIYwBg0/lGLwGIqwQAAOIYANh0vtFPAKp9AAAgjgGATecbPQWgQgAAII4BgE3nG30FQCUAABDHAMCm843eAqAQMFUAzvf2z/eiaw8BQHrko7ceA1ASMFUAjhfx8trD5SLXz+6cxE92hRzEF/d2bz/1MiQAgBPdAQAFARMFIOkALg8X8TrvAp7tvnKSHtx+enX/IH7yqpchAQCc6C4AyAmYLgDnezsFAI9ufXBHAnDx9oP44p0T2SF4GBIAwInuBICMgIkCcHm4s946EgMhZQiUiGj5z956KkGI4+cTiSEQWjICJiOVOcDpdrSIj288zvUUABn3ySgoA0CIV20iegAneuFtrx7AXBdEFco3DtoDGJICIGJf6QG8CwkA4ER3BUBGgHV5NN/oAwCP7opuAHOAykkAUHtMEDAFAJIZcJzOf4u7QGnEX70v2v2r+3dxF8gHbycAgEnApAHIBj54DlA5CQAsAOiLQycLQK14FRIAwInuFABtKgwAOtSVbQQATnS3ANiXR/ONAKDZCACc6I4BsC6P5hsBQLMRADjRXQNgWx7NNwKAZiMAcKI7B8CyPJqsSbvqdkpuByDKBQBkRz56OyEA6pdHkzVpV91OyW0AtBKvQgIAONE3AEDt8miyJu2q2yk5AGDoAMAdAHXLo8matKtup+R2AJZbR3IgtAMAsiMfvZ0WADXLo8matKtup+RWAMRKaPE+jHglAADIIx+9nRgA5OJQuibtqtspuQ2Ay8MdsR56P+kJyvXQAMA7b6cGALU4lK5Ju+p2Sm4DIL0NmvQCuA1aHPno7eQAyAkwEPARANn4A4D8yEdvpwdAQUCXt2SGA+DycF9OAWL1lTAA4J23EwSgJKD9WzLDASBafzkFWEf7TfHvV0gAACf6BgHIl0d3eElgQADiY3EH9PJQTAMAgDzy0dtpAkCNg7wDoIV4FRIAwIm+YQBMBACAXWcbAYATfeMA6AgAALvONgIAJ/oAAFQRAAB2nW0EAE70QQBQbwgBALvONgIAJ/owANTdE21d3U7JAQBDBwCbBaD2wVi76nZKbgfgOHsVBk+C8yMfvQ0AABsCIwIgHgDLh2AMACCQflIgMHZFqmuBkn8X6AGKIx+9DaIHEEL3AuP1ACkAYjkQAMiPfPQ2GADo2fDIQyAJAl6Kz4989DYcAGIKgREBiI/TVUCXhwAgO/LR25AAIMZBYwLQQrwKCQDgRB8FAAMBANDeCACc6CMBoCEAANobAYATfTQAKggAgPZGAOBEHxEAZTYMANobAYATfUwA6p8NA4BmIwBwoo8LgNoLtHgu4B4AxqZAvoUEAHCijw1ABYHa18YAgGkEAE708QHQECDfmgEAphEAONF9AMBAoGlOAAA6ZAwASN0PAITRBsHmADjfY4W+hyEBAJzo/gAgpA6CTfYAp9usrdG9CwkA4ET3CwAhFASbBEDIMoqwMVZx5KO3MwJASMOcwDkAMVaDAgCfABC6AUGJwiYA4IhXIQEAnOj+AiCkBgK9V+gLgNgiGgAURz56O1MAhFghSAUA9NcBgK8ACGFAwAIEANTpURQVJ3z0duYAKHoXAIo/LgXA5WH6O9kMBrwKCacAyG8gP+GjtwDAVNsAkP1xZ9wDKE18YdAlu9BHb1t6b3hbe34SAOjuxNofjgFAmsF8ASDCPUAAerSJowLQwCvrj8f64/IAOLtzEsdX93dvPYjji3u7t596GRK8jNmtxHQB4Ee9rU0cEwAnAd4HgKo8230lAeDRQfzs9tOr+wfxk1e9DAm9l+wUB5WIyDP20Vtd7+mtLwA4jm+6YOU8B4BHtz5IeoCLd06EIj5kh+BfSLTt9BsjosjYR28V3ZG7owLgNNw7zHjsT4JFxJ+99W9iCHT21tP44u1kKBQ/n4jtokHFSQxUZWyXWMIJ60Is+TSd35T0iXnHNbGdlAC8eSCiPxkFZQAIGbdN7BnhDa2E4poX3vKHPFTT2L5N3EAPUKlOu0a9NifyNF9vAUDa9Jc9wLghwQrw6nfZsmB/AWCEfdI+tizYCAn3ALSI+iZe2461HABw8fcy8r2YAzDDvl8r4SUAzT53LXjzAPCb+/bVdwzA+d5+ZXNoGfGP5BDo6v7dce8CsZo/kbBtI+I7APzY71TwxgGojXvWVzAsAMeLeHnt4XJRAeDinrwbOupzAHvYa0HQ+UvRVQ8AaOzq+uK+aQAsDb5/ACQdwOWhd78Q0xD8vQPeXwAa+rtuBQ0KgGWs4ykA53s7XgFgbf06ZjwNADTPa5tSjwGoa/pratKuup2SNwBwebiz3joSAyEvAOAEf5eMJwBA1XHbOMJfAGydNFmTdtXtlLwBALEvxCL/qaSRAbA3gN2c5umjA2Cf7jgLAV13C0D1bzUVANiy2ZDQg1/vSzcVAro6BgAWz+nHGl4CoDdVAIBfNyP6zZlUsADonpOzSP8BaKxzC+OwAIitsaJovF+JNIM/HjIEdHVYAMzoXxmeW6vbU3cFADVQnQgA4h7oaD3AdTP66+4jBAgAEf1kJNmq21N3AwBd6YkAkP1W9hgAEMFffxc5NAAo32vj32sAmHVuYRy4BxgJADIC6sI/MADo6F+Vnm8qBHS9PwDlH6ypUL5xUAA4j8A2EBL25o94hhIOAFr06wOJdtXtqfcFQP2DTRGA873CgUEnwZbmj4x+M6epAmC2/dpAomV1e+p9ANDbqykC0EqchYQSAXrzJ79Mzpc0SQDIkU+aSEN/AgAYDdZEAcgmwcOtBaqEQOWvXzcApnKaIgDkuF8mMno+/wEw+2sAQBwbdSH6/8amhDJODwAy+mUiYuDnPQDEcHWSACwLRwZZDKcHQVSROgco4+QAoKN/pQ/+21a3p94RAHK6NkkABn0OYLSBZPiHCUBN9BOjn3bV7al3AoD8o00WAL70DAlzCFDzRQYIgD7lL4QOf68BoBstRqF843AADHcb1Hrjs8EByjgpAIxb/pnUhb/HAKjB37JSfOOwPcBShD5nINQjJMgJYE34BweAfs8rl1r/21S3p94WgEqbFQYAA9wFou772/7+YQFgPvNKJXe/S0iMBIDWZQMAVkgQ9/1X9cMfygHKOBkA1I7PxJ+4qF11e+ptADD+ZGEAkA+Bmn8tu1NIEPf9hbRq/ijjRACojvt0/MmL2lW3p84HgGixAgEgXgu3uPdC20kZ/lV79l1upEyfhPK93CR2jBp1lHLuO3ZNnMhgt0GNqW96qnYeRRNMGafQAxjzftX7dm8OjtkDRIrUec4plG8cuAfYHADmnR+lNyXryjZOAADz2Zc43zSQaFndnjoDADX8az3nFMo3DgdAui+olA1Mgomnn7EWAQEDYHpfiaTamrWrbk+9GQCt0sEBwH0bpkNIUE//9ZVfwQJAOE/H/1QAIHIKAID4mNf4dwkJcvVLrIVAqABks1+1CDr8pwIAlVMIAAiR+6IwIGgXEkQIrCrDf7KubKPfAFBrf+jwnwgAZE6hACBl6XgOQIUAEQNBAkAvfZgyAHROwQBweRhFzc/BOgDQHAIhAlCO/dRkdfHvOQC2FisQAJJpAGNn3JYhQbWBnWeAlNFbAKjn3qs2Cz/bVbenPnsAllG0dcSJ/nYhQbWB3WeAlNFXACpT//JU6ryzkBgMAKPagQHAfx2sVUgQg4CIDoHQAKhZ+5M1pADANwDE8J/9JIAdEi0Wv4UFAL30YVUMJKYJQG3QhwBAnP1AhksAiAXAxQg4aADohR+rciA9OQDMVitAAGIxE+BMBJghQYyCy+F/yADQa39WivsAwFMAxFDI2XMAcxSsTH9DB4DKtR5/smbtqttTtwNAdNshAuD2SbCx/LlyAzBgAKiFH+IfC/58IwDontwGgHgE5nYtkDENrN4ADxcAcuXTqnr3d2IAUCO3wABwvhpUGwdHUTX+AweAKsSGP98IALontwHQShghoa2A08M/YACIlU/ylBV/vnE0APSrAYCWZeVAWwFnxn+wAFBL/8Spqv/TAoCcuwMALcvKgbYCzoz/oAEgCokAQBfjVAHQV8DNBwBq+fPK4dsPYwBA37wCAFqWyoGxAMiM/0ABINf/E/4DAN8AcLk5rrkCzoz/gAEgMm3s//jG4QGouXsbGAAOewBzBZz4BtvWlW30CQBq/f+K4h8ATAGAszsncfxkd3f3lZP44t7u7aeskDBXwEVzAYB8AYbV//GN4wBAXB0gAHIlRDkEeiYCP350II6v7h/ET17lhETNCrjWdWUbPQPANBMToCkBUPf8LjwALg93Lg/3izdjHt36IOkBrt5/IJSLd07SDoEHQMWYfoEzAIB8A8zx+28AoEfyBgBE6B/vxOvivWAR8cnQZ3f3ID5762l88bZg4flE4npJHwBXRA6AZiCE63G+mewI1XEkE69+k+gALBfK7wMIAM6+/kD0As9u5wAIsbSJ5otQxDISDqxsozc9QJtXIKfTA9Su4AivB4iPZfQvKz2AlEcHZQ9gDwniRai5AKAv/k4l4g0A+caBAajewAgcgGQSEB8rr4QpAHDnACYA1FN0js42eg1AxMSfbwQA3ZM3AaCLiHgx9rn63snV/bucu0D6SuCYXkbC0dlGTwAgX4KPggCAwn02AIjnALeSoQ/rOcB1GoBOdWUb/QCA3AUiYuPPNw4LQDQnADi/DtYMQPWLoR8icnS20R8AlJzkoXIDFAAY4h8AYnM43i+E1YSEuRJ4NgDo6ItD9QHARAHQp/CBAxDL7UEZ+6KwAah5hsLR2UYfADDegikAYFaCbwQA3ZMzABAMdF0Naq4EbhMCkwegklNsuYFO6XzjkAAYU/jwATjuvi0KsRS+TQhMGQDT86ZXIAGAjwDwxj82AKqFtgqBCQNAoN/0CuR0AKgmqskpDAD4G0RTIUGsBJ4TANVLI30F3CQBMG/ihg3A5aFbANqFwHQBoD2vrgAFAIb4B0CvHsBcCt+yDZwsAOZbMGb8TxIA4ilG2ADES94PJFEhYbwFZrwHGTQAVWMYAFCP8cIGoM8vxZvvglQfIYYLAPEWTBAARPMDgC9GSBBL4WcCgPkC6GY3gQEAPZIPCYD2CDFoAHSjGf8AwBQfAVhG0T5nIqCHRGUlmDzQn6GHCgD1EgAR/xMEgNwNJXAAjm/8cm//8rD5d8K0kLhOA1CtAACw6XzjYACsiGUsYQNwvie3hFi3ngRXV4KJA+MGcqAA1L4EsDFvBwTAdmA5ZhTKN04CAG0lGAAAAA2F8o2DAhAvxRCI81pMEwDm7ClMAIgtADa9DRgA6JG8CYB4Lf54jNfCKiGhrwSbOQARAJguAFxRQ8JYCqm8Bxw4AOYb0CsAwCmUbxwUgGwtUMs5gLEUMo7mDIB5/5dVCb4RAHRPvgkAzKWQynvAYQNgbgGwAgCsQvnGAQFYRrm0eg5AL4UkKjAPAHLvAYBN5xvH6AFaibEfbMpQ63wmKPVb4Y5QGUhH6T0J1tYCawshQ+4BiE1gBtgHDz1Aj+QNPYD+AxksALTvZj4AmO8BAwBuoXzjoABwVgEBgPygFoBOleAbAUD35A0A9HspXgWAqkBgAJgvwq/UG8AAwKbzjQP3AI4AICsAAGw63wgAuidvAIDzBKABAH0lcLAAEJvA1P6eKEfnGwFA9+QNAPR5JxgArAAAu1C+cdgegC1WAGq+mKAAMHeCWA20EyoA6JF84wAYS+EBAFPnGwFA9+QAgKFzACB2gmi5GzQA8A2AfALQZw5grgQGAEydbwQA3ZNvugeYCwDUVihDbQUMAHokHwKA2i8mdABqnwCydL4RAHRPvmEAiKXwQQJgbgIjBADwC+UbAUCz0Q8A6h+Bs3S+EQB0T75ZAKh3QUIEwNwFSQgAaFEo3wgAmo1eAKDfANHKFm4AAAn8SURBVAYANp1vnBoAeqEBAkBsA7YCAO0K5RsnBAD5LshcADBuAAMAm843AoBm47AAENuArQAAAKB+UKp6HDwAw3gLAHokBwAM3Q6AuQ2Y+Me8AQwAbDrfOBkAapbCAwCmzjcCgO7JAQBDtwJA7IO3InfDAgA2nW8cF4CzOyfi4+r+QRxf3Nu9/dQOAFEoAGDqfCMA6J68JQDPdl+RADzZPZAQPHm1FoC6d0ECA4B4Dyam738BAJvON44JwKNbH8ge4Oyv/u4gvnjnJO8QAMCqGhIAIEwAsiHQ1fv/nrT+Z289jS/efpAYn09ET5g+B52BELuBzsf5IKUZgCd3xfDn2e0cACF6D1D7MlRgPQDZJpI3gNED2HS+cfweIGn6ryo9QB0ATV9S0AAYOQEAm843jg/Ak10hd61zgGjOANA3gAGATecbxwcgTm+DXt2/W38XCAAYOQEAm843egOA7TmAthJsXgDU3P8CADadbxwXgFoBAAAAABRZagthZgVA3f0vAGDT+cYpAKCvBJsTABEA6FIpvhEANBtHBCACAJ0qxTdOAABjJRgA6FAJvhEAdE8OABg6AAAArQGo5k1XIEQA6reDAwA2nW/0HwBzKeSMAKjGPwDgFso3AoBm48gA0DkBAJvON3oPALEUEgB0qATfCAC6J3cPQDRrACIA0K1SfKPnAEQAYGhvAUCP5ACAoQMAAAAA0qMGACIA0LFSfKPnAJDbAc0KgMG9BQA9krsHYEWsBQYAHSrBNwKA7sk3AAD/SwoOgAgAdK0U3wgAmo1jAjC8twCgR3IAwNABAAAAAOmR1Vv9NYjVMN4CgB7JAQBDbwPAanhvAUCP5ACAoQMAAAAA0iObt8Z7QKthvAUAPZI7AwAiARi7DpD+gh6gRw+gX40egFko3+hpDwAAzPeAVsN4CwB6JAcADJ0PgHE1AGAWyjcCgGYjAHCiAwAAoKkWb4lV4KthvAUAPZIDAIbOBsC8GgAwC+UbAUCzEQA40QEAANDUem+p94BWw3gLAHokBwAMnQsAcTUAYBbKNwKAZiMAcKIDAACgqQCg/sByzCiUbwQAzcbhAYgAgOWYUSjfCACajeMAQF0NAJiF8o0AoNkIAJzoAAAAaGqdt3U/igEAuIXyjQCg2TgKAKN5CwB6JAcADB0AAAAAkB7R3kYAwHrMKJRvBADNxjEAGM9bANAjOQBg6AAAAACA9Ij0NgIA9mNGoXwjAGg2jgDAiN4CgB7JAQBDBwAAAACkR5S3+pagAKBDpfhGANBsHB6A1YjeAoAeydsCcHbnJI6f7e6+knxc3Nu9/RQAAAAypzABeCYiX0Dw5NX46v6B+Jg9AMaWoACgQ6X4xjEBeHTrA9EDpD3BxTspCwBA2xAOAHSoFN84ag9QRHzS9J+99TS+ePtBojyfiO2isAV74gYmDADO3rz1IH52OwdAyGx7AHNLUPQAHSrFN/rRAySRX/YAswegmgoAdKgU3+gHAPGjA8wBpAAAOqeAAcjGPlf37+IuELUlKADoUCm+cXwA4ie7u8kcAM8BVvSGcACgQ6X4xnEBqJV5AhBF6AFqcgIAAGA1jLcAoEdyAMDQAQAAAADpke4t5gAAYNYArIgdEQFAh0rxjQCg2TggAB54CwB6JAcADB0AAAAAkB756C0A6JEcADB0AAAAAEB65KO3AKBHcgDA0AEAAAAA6ZGP3gKAHskBAEMHAAAAAKRHPnoLAHokBwAMHQAAAACQHvnoLQDokRwAMHQAAADaiLlFSs2mKU17qfD3WmlI2bMg6+ngvLWeZ3vbt5L8lM6/DQDQ6nRw3gKAhisaJbiQAACWcwCAkeXEQwIAWM4BAAgkKAEAkFkLAIDMWgAAZNYCACCzlh4AnL25u3tQ2TOR+jWlWG6uKOy6Oc/mTnlJTRK1uLrMqnbjNFFKmabqCZ1FON5y3GV7a3fXkbcN7vbytjsAYrP0s68/UH47ifw1pVjsLS3+NcypyN9hys7VJFGLq82sYjdOE6WUaaqe0FmE4y3HXb63VnddeWt3t5+33QF49mps7ptu/ppSUu/35c8K6ObMNfk7TNk5OkmluLrMqnb9NFVKmabqCZ1FON5y3GV7a3XXlbd2d3t6228OYPxyRvXXlLJE93ZFJ6SbcxEVyc7VJVGKq8usajczMkuppjHsRF3C8ZbjLsvbBnfdeNvkbi9vewEgfjSg8ttJxK8pxbJzSxjWzWr1s3N1SZTi6jKr2s2MzFIqaRRParMIx1uOuzxvG9x1422Tu7287QPAxb27sc5rHeuPDnq3ibI4a2aFvW2bqHpSl0U43nLcbeNtvbsOvbW428vbXneBxNTEGIDqI0erOas+Y5yYFWfNTB/qWUtR0lQ8qckiHG857rbytt5dh95a3O3lbXcAskorv51E/ppSar763oluVqufnatLohRXl1nVbmZkllKmqXpCZxGOtxx32d42uOvG2yZ3e3nbHQBxb1ZMTZRbrtSvKdWbleoz7hXnxdVlVrW3ujOueUJmEY63HHf53trddeRtg7u9vMWTYMisBQBAZi0AADJrAQCQWQsAgMxaAABk1gIAILMWAOBOllEUbR01JDp9QUuRX2WcyOXycL/2XGMZ56+1unJ+AgCcyfLawzheR/v2VHosN1+1XNTD0VzG+sbjNpfOTgCAK0kaavFx3BBwWiw3XyXa8B4AZAVAagQAuJLLw5388HQ7GdbsJHH4XnKwI7T9RHk3ipIwF8F5eRhFouGvXJWckNeJxEqCeKlctEj0871o670XH5YF7cfFuaJgpQx0AVYBAM5kLWJPyPnevhzanG4nsbcUUS+Vaw8vD+VoRnzIuK5clTXb4qSaQBKSXST+P9/bSf5P6ZCXnG7vp/b9smC1jJa9x9wEADgUMZ9N4u7XInJlg74v41NRks8XjtYifGWwqldlgSoGQ2oC+ZFflPwjP5cZAHlHkMV4UbBaRlkQhBAA4FbO90Sru5Z3dtIGOvtHfibBmHwu5UAn2qlelUaxDG01QQFA1pqnrXoW+cfpyGedD5fKgssslKEZxBQA4FiS4Dvf2zoqYp4CwByV5wnW8jaqmsAKgJwRZL2CVIqCyywAgFUAgCvJxiF5rK71HkAOgV4U4/O18rCgvEocZWfUBAUAwpYPgcomP4dKHioFl1lgCGQVAOBMjkXMicmnCL7TbQMAZRIsxvlZhBZX5ZDEQlUT1E+CJQfKOaXgMgtMgq0CANzJMh+4J0PzrW9nDXM5BHq3mOuKW5RFC51flZw4luP2rWqCNXEb9N2sB1hnT5Hzc0rBRRbEgAtSCgAYSDo3xNRihhb39vEgzC4AYCDpPhJZLlRtLTuIRV1iQ/AczC4AYCDpDoDWhmePDZiCxXANAgAgsxYAAJm1AADIrAUAQGYtAAAyawEAkFkLAIDMWv4fN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{"ft_lang_label":"__label__en","ft_lang_prob":0.7971096,"math_prob":0.99915457,"size":26193,"snap":"2019-35-2019-39","text_gpt3_token_len":7456,"char_repetition_ratio":0.16300736,"word_repetition_ratio":0.054895304,"special_character_ratio":0.3043943,"punctuation_ratio":0.12682617,"nsfw_num_words":0,"has_unicode_error":false,"math_prob_llama3":0.9998347,"pos_list":[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32],"im_url_duplicate_count":[null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null],"WARC_HEADER":"{\"WARC-Type\":\"response\",\"WARC-Date\":\"2019-08-18T08:59:07Z\",\"WARC-Record-ID\":\"<urn:uuid:de9dedf8-58f8-4e3e-8159-448ffa5c0dd9>\",\"Content-Length\":\"335856\",\"Content-Type\":\"application/http; msgtype=response\",\"WARC-Warcinfo-ID\":\"<urn:uuid:d7923999-be75-45b2-81a0-1a9e2cbc11a2>\",\"WARC-Concurrent-To\":\"<urn:uuid:bb5866a3-0636-4a57-bcc0-c9591bb57ea1>\",\"WARC-IP-Address\":\"148.205.148.16\",\"WARC-Target-URI\":\"https://cran.itam.mx/web/packages/ciTools/vignettes/ciTools_survreg_vignette.html\",\"WARC-Payload-Digest\":\"sha1:HHCIDMPGSKNBCAOZ5DHKW6YOFF6SXD2R\",\"WARC-Block-Digest\":\"sha1:4DH7YCVBS3QGCFSXMXCAWPDZZLTM7IWK\",\"WARC-Identified-Payload-Type\":\"application/xhtml+xml\",\"warc_filename\":\"/cc_download/warc_2019/CC-MAIN-2019-35/CC-MAIN-2019-35_segments_1566027313747.38_warc_CC-MAIN-20190818083417-20190818105417-00156.warc.gz\"}"}
http://ideasof.andersaberg.com/development/typescript-and-knockout-where-did-my-this-instance-go
[ "So, a problem we had at work was that in one of our TypeScript classes, we set up an class variable as a computed, as so: `myComputed = ko.computed( () => { return this.myClassFuntion();});`. The problem with this is that typescript will compile a prototype method, and Knockout will change in what context this is run. The result is that `this` will become `window` instead of the instance of our `class`.\n\nThe solution to this problem is to only create the function as a field in the class, as so: `public myComputed;`. And then, in the constructor, set the value of that field to a lambda function:\n\n``````class myClass {\npublic myComputed;\nconstructor() {\nthis.myComputed = () => { return this.MyInstanceFunction(); }\n}\n\nMyInstanceFunction() {\nreturn 1;\n}\n} The example is very stupid, but it demonstrates how you can set up functions (and in detail, observables) to keep the correct context.\n``````" ]
[ null ]
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https://codeshive.com/product/assignment-6-cs-750-850-machine-learning-solved/
[ "# Assignment 6 CS 750/850 Machine Learning solved\n\n\\$35.00\n\nCategory:\n\n## Description\n\nProblem 1 [33%]\nIn this problem, we will establish some basic properties of vectors and linear functions.\n1. The L2 norm of a vector measures the length (size) of a vector. The norm for a vector x of size n is\ndefined as:\nkxk2 =\nvuutXn\ni=1\nx\n2\ni\nShow that the norm can be expressed as the following quadratic expression:\nkxk\n2\n2 = x\nT x\n.\n2. Let a and x be vectors of size n = 3 and consider the following linear function f(x) = a\nT x. Show that\nthe gradient of f is: ∇xf(x) = a.\n3. Let A be a symmetric matrix of size 3 × 3 and consider the following quadratic function f(x) = x\nT Ax.\nShow that the gradient of f is: ∇xf(x) = 2Ax. A matrix is symmetric if Aij = Aji for all i and j.\nProblem 2 [34%]\nHint: You can follow the slides from the March 4th class, or the LAR reference from the class website. See\nthe class website for some recommended linear algebra references.\nYou will derive the formula used to compute the solution to ridge regression. The objective in ridge regression\nis:\nf(β) = ky − Aβk\n2\n2 + λkβk\n2\n2\nHere, β is the vector of coefficients that we want to optimize, A is the design matrix, y is the target, and λ is\nthe regularization coefficient. The notation k·k2 represents the Euclidean (or L2) norm.\nOur goal is to find β that solves:\nmin\nβ\nf(β)\nFollow the next steps to compute it.\n1. Express the ridge regression objective f(β) in terms of linear and quadratic terms. Recall that\nkβk\n2\n2 = β\nT β. The results should be similar to the objective function of linear regression.\n1\n2. Derive the gradient: ∇βf(β) using the linear and quadratic terms above.\n3. Since f is convex, its minimal value is attained when\n∇βf(β) = 0\nDerive the expression for the β that satisfies the inequality above.\n4. Implement the algorithm for computing β and use it on a small dataset of your choice. Do not forget\n5. Compare your solution with glmnet (or another standard implementation) using a small example. Are\nthe results the same? Why yes, or no?\nProblem 3 [33%]\nUsing the MNIST dataset, which we used already in Assignment 2, compare whether boosting, bagging, and\nrandom forests work the best. You may may want to use only a subset of the data.\nOptional: Use xgboost (also available for Python) to see whether the results are better than other boosting\nmethods.\nOptional Problem 4 [+10%]\nHint: We did not cover this material in class, but it is important regardless. The slides from March 9th may\nIn this problem, you will implement a gradient descent algorithm for solving a linear regression problem.\nRecall that the RSS objective in linear regression is:\nf(β) = ky − Aβk\n2\n2\n1. Consider the problem of predicting revenue as a function of spending on TV and Radio advertising.\nThere are only 4 data points:\n20 3 7\n15 4 6\n32 6 1\n5 1 1\nWrite down the design matrix of predictors, A, and the response vector, y, for this regression problem. Do\nnot forget about the intercept, which can be modeled as a predictor with a constant value over all data points.\nThe matrix A should be 4 × 3 dimensional.\n2. Express the RSS objective f(β) = ky − Aβk\n2\n2\nin terms of linear and quadratic terms.\n3. Derive the gradient ∇βf(β) using the linear and quadratic terms above.\n4. Implement a gradient descent method with a fixed step size in R/Python.\n5. Use your implementation of linear regression to solve the simple problem above and on a small dataset\nof your choice. Compare the solution with linear regression from R or Python (sklearn). Do not forget" ]
[ null ]
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https://www.talks.cam.ac.uk/talk/index/14946
[ "# Projective Limits of Bayes Equations\n\n•", null, "Peter Orbanz (Dept. Engineering, Cambridge)\n•", null, "Friday 28 November 2008, 16:00-17:00\n•", null, "MR12, CMS, Wilberforce Road, Cambridge, CB3 0WB.\n\nBayesian nonparametric models are essentially Bayesian models on infinite-dimensional spaces. Most work along these lines in statistics focusses on probability models over the simplex. In machine learning, the problem has recently received much attention as well, and attempts have been made to define models on a wider range of infinite-dimensional objects, including measures, functions and infinite permutations and graphs.\n\nIn my talk, I will discuss the construction of nonparametric Bayesian models from finite-dimensional Bayes equations, analogous to Daniell-Kolmogorov extension of measures to their projective limits. I will present an extension theorem applicable to regular conditional probabilities. This can be used to guarantee that “conditional” properties of the finite-dimensional marginal models, such as conjugacy and sufficiency, carry over to the infinite-dimensional projective limit model, and to determine the functional form of the nonparametric Bayesian posterior if the model is conjugate.\n\nThis talk is part of the Statistics series." ]
[ null, "https://talks.cam.ac.uk/images/user.jpg", null, "https://talks.cam.ac.uk/images/clock.jpg", null, "https://talks.cam.ac.uk/images/house.jpg", null ]
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https://dsp.stackexchange.com/questions/16885/how-do-i-manually-plot-the-frequency-response-of-a-bandpass-butterworth-filter-i
[ "# How do I manually plot the frequency response of a bandpass Butterworth filter in MATLAB without freqz function?\n\nI have code like below that applies a bandpass filter onto a signal. I am quite a noob at DSP and I want to understand what is going on behind the scenes before I proceed.\n\nTo do this, I want to know how to plot the frequency response of the filter without using freqz.\n\n[b, a] = butter(order, [flo fhi]);\nfiltered_signal = filter(b, a, unfiltered_signal)\n\n\nGiven the outputs [b, a] how would I do this? This seems like it would be a simple task, but I'm having a hard time finding what I need in the documentation or online.\n\nI'd also like to understand how to do this as quickly as possible, e.g. using an fft or other fast algorithm.\n\nWe know that in general transfer function of a filter is given by:\n\n$$H(z)=\\dfrac{\\sum_{k=0}^{M}b_kz^{-k}}{\\sum_{k=0}^{N}a_kz^{-k}}$$\n\nNow substitute $$z=e^{j\\omega}$$ to evaluate the transfer function on the unit circle:\n\n$$H(e^{j\\omega})=\\dfrac{\\sum_{k=0}^{M}b_ke^{-j\\omega k}}{\\sum_{k=0}^{N}a_ke^{-j\\omega k}}$$\n\nThus this becomes only a problem of polynomial evaluation at a given $$\\omega$$. Here are the steps:\n\n• Create a vector of angular frequencies $$\\omega = [0, \\ldots,\\pi]$$ for the first half of spectrum (no need to go up to $$2\\pi$$) and save it in w.\n• Pre-compute exponent $$e^{-j\\omega}$$ at all of them and store it in variable ze.\n• Use the polyval function to calculate the values of numerator and denominator by calling: polyval(b, ze), divide them and store in H. Because we are interested in amplitude, then take the absolute value of the result.\n• Convert to dB scale by using: $$H_{dB}=20\\log_{10} H$$ - in this case $$1$$ is the reference value.\n\nPutting all of that in code:\n\n%% Filter definition\na = [1 -0.5 -0.25]; % Some filter with lot's of static gain\nb = [1 3 2];\n\n%% My freqz calculation\nN = 1024; % Number of points to evaluate at\nupp = pi; % Evaluate only up to fs/2\n% Create the vector of angular frequencies at one more point.\n% After that remove the last element (Nyquist frequency)\nw = linspace(0, pi, N+1);\nw(end) = [];\nze = exp(-1j*w); % Pre-compute exponent\nH = polyval(b, ze)./polyval(a, ze); % Evaluate transfer function and take the amplitude\nHa = abs(H);\nHdb = 20*log10(Ha); % Convert to dB scale\nwn = w/pi;\n% Plot and set axis limits\nxlim = ([0 1]);\nplot(wn, Hdb)\ngrid on\n\n%% MATLAB freqz\nfigure\nfreqz(b,a)\n\n\nOriginal output of freqz:", null, "And the output of my script:", null, "And quick comparison in linear scale - looks great!\n\n[h_f, w_f] = freqz(b,a);\nfigure\nxlim = ([0 1]);\nplot(w, Ha) % mine\ngrid on\nhold on\nplot(w_f, abs(h_f), '--r') % MATLAB\nlegend({'my freqz','MATLAB freqz'})", null, "Now you can rewrite it into some function and add few conditions to make it more useful.\n\nAnother way (previously proposed is more reliable) would be to use the fundamental property, that frequency response of a filter is a Fourier Transform of its impulse response:\n\n$$H(\\omega)=\\mathcal{F}\\{h(t)\\}$$\n\nTherefore you must feed into your system $$\\delta(t)$$ signal, calculate the response of your filter and take the FFT of it:\n\nd = [zeros(1,length(w_f)) 1 zeros(1,length(w_f)-1)];\nh = filter(b, a, d);\nHH = abs(fft(h));\nHH = HH(1:length(w_f));\n\n\nIn comparison this will produce the following:", null, "• Detailed explanation – partida Dec 13 '14 at 14:49\n• I am thinking this line a = [1 -0.5 -0.25]; % Some filter with lot's of static gain. Can you explain me the selection of these parameters here, please. I am reading my Matlab's manual and it says [h,w] = freqz(hfilt,n) in one part of synapse. You are giving two filters (a,b) into freqz. Are both filters in hfilt? Or one in n? – Léo Léopold Hertz 준영 Apr 21 '15 at 21:57\n• Just to clarify for others: \"No need to go up to 2 pi\" is when the coefficients are real. There are applications for filters with complex coefficients and in that case the spectrum will no longer be symmetric and would in that case want to extend the frequency to 2 pi. – Dan Boschen May 14 '17 at 14:10\n\nthis is just an addendum to jojek's answer which is more general and perfectly good when double-precision math is used. when there is less precision, there is a \"cosine problem\" that crops up when either the frequency in the frequency response is very low (much lower than Nyquist) and also when the resonant frequencies of the filter are very low.\n\nwhen you compute the magnitude (squared) frequency response $|H(e^{j\\omega})|^2$ these complex exponentials will be converted to sines and cosines, but when the math is cranked out, only the cosines will survive. this should be clear because the magnitude is an even function $|H(e^{-j\\omega})| = |H(e^{j\\omega})|$ w.r.t. frequency and only the cosines are even functions.\n\nconsider this trig identity:\n\n$$\\cos(\\omega) \\ = \\ 1 - 2 \\sin^2 \\left( \\frac{\\omega}{2} \\right)$$\n\nnow, looking at the right-hand side of the equation, all of the information regarding frequency is in the $\\sin^2 \\left( \\frac{\\omega}{2} \\right)$ term which is being subtracted from 1. and this term gets exceedingly small as $\\omega \\to 0$. so small that the term and the frequency information in that term are getting lost when the term (or it's negative) are added to 1. this is the case even with floating point, but is less a problem with double-precision floats. but some of us putting this frequency response function into gear might not have the resource of double-precision floating point, or any floating point.\n\nso, what i have done is use the trig identity above and eliminate all of the cosine terms, essentially replacing them with terms looking like $\\sin^2 \\left( \\frac{\\omega}{2} \\right)$ and some constants that get combined with other constants. i'll show you the answer for the case of a 2nd-order IIR filter (a.k.a. a \"biquad\"):\n\n$$H(z) = \\frac{b_0 + b_1 z^{-1} + b_2 z^{-2}}{a_0 + a_1 z^{-1} + a_2 z^{-2}}$$\n\nwhich has complex frequency response\n\n$$H(e^{j\\omega}) = \\frac{b_0 + b_1 e^{-j\\omega} + b_2 e^{-j2\\omega}}{a_0 + a_1 e^{-j\\omega} + a_2 e^{-j2\\omega}}$$\n\nwhich has magnitude squared:\n\n\\begin{align} |H(e^{j\\omega})|^2 &= \\frac{|b_0 + b_1 e^{-j\\omega} + b_2 e^{-j2\\omega}|^2}{|a_0 + a_1 e^{-j\\omega} + a_2 e^{-j2\\omega}|^2} \\\\ \\\\ &= \\frac{\\big(b_0 + b_1\\cos(\\omega) + b_2\\cos(2\\omega)\\big)^2 + \\big(b_1\\sin(\\omega) + b_2\\sin(2\\omega)\\big)^2}{\\big(a_0 + a_1\\cos(\\omega) + a_2\\cos(2\\omega)\\big)^2 + \\big(a_1\\sin(\\omega) + a_2\\sin(2\\omega)\\big)^2} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)\\cos(\\omega) + 2b_0b_2\\cos(2\\omega)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)\\cos(\\omega) + 2a_0a_2\\cos(2\\omega)} \\\\ \\end{align}\n\nso, one can see that the magnitude frequency response $|H(e^{j\\omega})|$ is an even symmetry function and depends only on the cosines $\\cos(\\omega)$ and $\\cos(2\\omega)$. for very low $\\omega$, the values of those cosines are so close to $1$ that, with single-precision fixed or floating point, there are few bits remaining that differentiate those values from $1$. that is the \"cosine problem\".\n\nusing the trig identity above, you get for magnitude squared:\n\n\\begin{align} |H(e^{j\\omega})|^2 &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)\\cos(\\omega) + 2b_0b_2\\cos(2\\omega)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)\\cos(\\omega) + 2a_0a_2\\cos(2\\omega)} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right) + 2b_0b_2\\left(1 - 2 \\sin^2(\\omega)\\right)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right) + 2a_0a_2\\left(1 - 2 \\sin^2(\\omega)\\right)} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right) + 2b_0b_2\\left(2\\cos^2(\\omega) - 1\\right)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right) + 2a_0a_2\\left(2\\cos^2(\\omega) - 1\\right)} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right) + 2b_0b_2\\left(2\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right)^2 - 1\\right)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right) + 2a_0a_2\\left(2\\left(1 - 2 \\sin^2 \\left( \\tfrac{\\omega}{2}\\right)\\right)^2 - 1\\right)} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)(1 - 2\\phi) + 2b_0b_2\\left(2(1 - 2\\phi )^2 - 1\\right)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)(1 - 2\\phi) + 2a_0a_2\\left(2(1 - 2\\phi)^2 - 1\\right)} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1(b_0+b_2)(1 - 2\\phi) + 2b_0b_2(1 - 8\\phi + 8\\phi^2)}{a_0^2+a_1^2+a_2^2 + 2a_1(a_0+a_2)(1 - 2\\phi) + 2a_0a_2(1 - 8\\phi + 8\\phi^2)} \\\\ \\\\ &= \\frac{b_0^2+b_1^2+b_2^2 + 2b_1b_0+2b_1b_2 - 4(b_1b_0+b_1b_2)\\phi + 2b_0b_2 - 16b_0b_2\\phi + 16b_0b_2\\phi^2}{a_0^2+a_1^2+a_2^2 + 2a_1a_0+2a_1a_2 - 4(a_1a_0+a_1a_2)\\phi + 2a_0a_2 - 16a_0a_2\\phi + 16a_0a_2\\phi^2} \\\\ \\\\ &= \\frac{\\big(b_0^2+b_1^2+b_2^2 + 2b_1b_0+2b_1b_2+2b_0b_2\\big) - 4(b_1b_0+b_1b_2-4b_0b_2)\\phi + 16b_0b_2\\phi^2}{\\big(a_0^2+a_1^2+a_2^2 + 2a_1a_0+2a_1a_2+2a_0a_2\\big) - 4(a_1a_0+a_1a_2-4a_0a_2)\\phi + 16a_0a_2\\phi^2} \\\\ \\\\ &= \\frac{\\tfrac14\\big(b_0^2+b_1^2+b_2^2 + 2b_1b_0+2b_1b_2+2b_0b_2\\big) - (b_1b_0+b_1b_2-4b_0b_2)\\phi + 4b_0b_2\\phi^2}{\\tfrac14\\big(a_0^2+a_1^2+a_2^2 + 2a_1a_0+2a_1a_2+2a_0a_2\\big) - (a_1a_0+a_1a_2-4a_0a_2)\\phi + 4a_0a_2\\phi^2} \\\\ \\\\ &= \\frac{\\left(\\frac{b_0+b_1+b_2}{2}\\right)^2 - \\phi \\big(4b_0b_2(1-\\phi) + b_1(b_0+b_2)\\big)}{\\left(\\frac{a_0+a_1+a_2}{2}\\right)^2 - \\phi \\big(4a_0a_2(1-\\phi) + a_1(a_0+a_2)\\big)} \\\\ \\end{align}\n\nwhere $\\phi \\triangleq \\sin^2 \\left( \\frac{\\omega}{2} \\right)$\n\nif your gear is intending to plot this as dB, it comes out as\n\n$$20 \\log_{10}|H(e^{j\\omega})| \\ = \\ 10 \\log_{10}\\left( \\left(\\tfrac{b_0+b_1+b_2}{2}\\right)^2 - \\phi \\big(4b_0b_2(1-\\phi) + b_1(b_0+b_2)\\big) \\right) \\\\ - 10 \\log_{10}\\left(\\left(\\tfrac{a_0+a_1+a_2}{2}\\right)^2 - \\phi \\big(4a_0a_2(1-\\phi) + a_1(a_0+a_2)\\big) \\right)$$\n\nso your division turns into subtraction, but you have to be able to compute logarithms to some base or another. numerically, you will have much less trouble with this for low frequencies than doing it the apparent way.\n\n• That's really cool, thank you Robert! +1 – jojek Jul 11 '14 at 11:29\n• @Robert I \"believe\" similar to my comment for Jojek above that this only applies as well when the coefficients are real (and therefore the spectrum is symmetric and thus the magnitude converts to cosines as you show)... Am I correct? – Dan Boschen May 14 '17 at 14:12\n• yes. that commitment is made when you go from the first line of $|H(e^{j\\omega})|^2 = ...$ to the second line. no going back after that. – robert bristow-johnson May 14 '17 at 18:38" ]
[ null, "https://i.stack.imgur.com/PE03p.png", null, "https://i.stack.imgur.com/2vt53.png", null, "https://i.stack.imgur.com/mByGv.png", null, "https://i.stack.imgur.com/D98lD.png", null ]
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https://mathematica.stackexchange.com/questions/153526/solving-a-convex-optimization-problem-using-mathematica
[ "# Solving a Convex Optimization Problem Using Mathematica\n\nI have the following convex optimization problem: $$\\begin{array}{ll} \\text{maximize}_{{f,g}} & \\displaystyle\\int_{\\mathbb{R}} g^u{f}^{1-u}\\mathrm{d}\\mu\\\\ \\text{subject to} & \\displaystyle\\int_{\\mathbb{R}} f \\mathrm{d}\\mu= 1,\\quad \\displaystyle\\int_{\\mathbb{R}} g\\mathrm{d}\\mu =1 \\\\ & f_L \\leq {f} \\leq f_U\\\\ & g_L \\leq g \\leq g_U\\end{array}$$ where $u\\in(0,1)$ and $$\\int_{\\mathbb{R}}f_L \\mathrm{d}\\mu< 1,\\quad\\int_{\\mathbb{R}}g_L \\mathrm{d}\\mu< 1$$\n\n$$\\int_{\\mathbb{R}}f_U \\mathrm{d}\\mu> 1,\\quad\\int_{\\mathbb{R}}g_U \\mathrm{d}\\mu> 1$$ Here, $f$ and $g$ are distinct density functions, $f_L,f_U,g_L,g_U$ are some known positive functions on $\\mathbb{R}$ and $\\mu$ is Lebesgue measure.\n\nI am looking for a code for this case:\n\n$$f_L=0.8*f_{\\mathcal{N}(-1,1)}$$ $$f_U=2*f_{\\mathcal{N}(-1,1)}$$ $$g_L=0.8*f_{\\mathcal{N}(1,1)}$$ $$g_U=2*f_{\\mathcal{N}(1,1)}$$\n\nand here its mathematica code:\n\nfL[y_] := 0.8*PDF[NormalDistribution[-1, 1], y]\nfU[y_] := 2*PDF[NormalDistribution[-1, 1], y]\ngL[y_] := 0.8*PDF[NormalDistribution[1, 1], y]\ngU[y_] := 2*PDF[NormalDistribution[1, 1], y]\n\n\nI asked the same question for any programming language here. It seems Rahul has an answer, which he wants to keep for himself. That's why I decided to ask the same question here.\n\nI am not interested in a symbolic solution. Discretization of the densities is all fine.\n\nHere, you can also see a possible solution for the discrete case. I am also posting the working code for the discrete case here:\n\nu = 0.5;\nn = 20\na = Table[0.6*PDF[BinomialDistribution[20, 0.3], i], {i, n}];\nb = Table[1.5*PDF[BinomialDistribution[20, 0.3], i], {i, n}];\nc = Table[0.4*PDF[BinomialDistribution[20, 0.7], i], {i, n}];\nd = Table[2*PDF[BinomialDistribution[20, 0.7], i], {i, n}];\nX = Array[x, n];\nY = Array[y, n];\n\nFindMaximum[{X^(1 - u).Y^u,\nFlatten[{ Total[X] == 1 , Total[Y] == 1,\nMapThread[#1 <= #2 <= #3 &, {a, X, b}],\nMapThread[#1 <= #2 <= #3 &, {c, Y, d}]}]} , Flatten[Join[{X, Y}]]]\n\n• You are not looking for a discrete solution, right? – anderstood Aug 11 '17 at 16:06\n• In this question, I am looking for a solution for the continuous case. The code for the discrete case is just to provide some ideas. – Seyhmus Güngören Aug 11 '17 at 16:12\n• Rahul mentions quadrature points so I guess he did not solve this problem in the continuous case. I have never done functional optimisation with MMA before and I am not sure if MMA can solve your problem symbolically, but have you checked the package VariationalMethods? – anderstood Aug 11 '17 at 16:17\n• @anderstood no. he should have a solution for the continuous case, for which we also need sampling and interpolation. Check out the question for the discrete case. The best answer works only for $35$ samples. – Seyhmus Güngören Aug 11 '17 at 18:02\n• @anderstood No I dont know anything about that package. I also dont need an almost perfect solution with symbolic computation. It is completely fine to discretize the density functions, lets say with $100$ points, and then to apply the constraints for the interpolated functions $f$ and $g$. – Seyhmus Güngören Aug 11 '17 at 20:28\n\nTrapezoidal rule\n\nHere is a function that approximates an integral using the trapezoidal rule:\n\ntrapezoidalIntegrate[expr_, {x_, x0_, x1_}, n_] := Dot[\nTable[expr, {x, Subdivide[x0, x1, n]}],\n]\n\n\nFor example:\n\ntrapezoidalIntegrate[x^2, {x, 0, 2}, 100] //N\nNIntegrate[x^2, {x, 0, 2}]\n\n\n2.6668\n\n2.66667\n\nIf your version of Mathematica doesn't have Subdivide, you can use:\n\nSubdivide[x0_, x1_, n_] := x0 + Range[0,n] (x1-x0)/n\n\n\nDiscretization\n\nUsing trapezoidalIntegrate we can discretize the optimization problem. First, the inputs:\n\nfL[y_]:=0.8*PDF[NormalDistribution[-1,1],y]\nfU[y_]:=2.*PDF[NormalDistribution[-1,1],y]\ngL[y_]:=0.8*PDF[NormalDistribution[1,1],y]\ngU[y_]:=2.*PDF[NormalDistribution[1,1],y]\n\n\nI will discretize the range $(-8, 8)$ over 101 points, since that is sufficient to get integrals of fL, fU, gL and gU right:\n\ntrapezoidalIntegrate[fL[x], {x, -8, 8}, 100]\ntrapezoidalIntegrate[fU[x], {x, -8, 8}, 100]\ntrapezoidalIntegrate[gL[x], {x, -8, 8}, 100]\ntrapezoidalIntegrate[gU[x], {x, -8, 8}, 100]\n\n\n0.8\n\n2.\n\n0.8\n\n2.\n\nFindMaximum\n\nNow, we just need to construct the FindMaximum expression to evaluate:\n\nu = .8;\nn = 100;\nxi = Subdivide[-8, 8, n];\noptimum = FindMaximum[\nEvaluate @ {\ntrapezoidalIntegrate[f[x]^u g[x]^(1-u), {x, -8, 8}, n],\ntrapezoidalIntegrate[f[x], {x, -8, 8}, n] == 1,\ntrapezoidalIntegrate[g[x], {x, -8, 8}, n] == 1,\nAnd @@ Table[fL[x] < f[x] < fU[x], {x, xi}],\nAnd @@ Table[gL[x] < g[x] < gU[x], {x, xi}]\n},\nEvaluate @ Join[\nTable[f[x], {x, xi}],\nTable[g[x], {x, xi}]\n]\n];\noptimum[]\n\n\n0.853142\n\nAnd plots of f[x] and g[x] along with the upper and lower bounds:\n\nShow[\nPlot[{fL[x], fU[x]}, {x, -8, 8}, PlotRange->All],\nListLinePlot[Thread[{xi, Table[f[x], {x, xi}]}] /. optimum[], PlotStyle->Green]\n]\n\nShow[\nPlot[{gL[x], gU[x]}, {x, -8, 8}, PlotRange->All],\nListLinePlot[Thread[{xi, Table[g[x], {x, xi}]}] /. optimum[], PlotStyle->Green]\n]", null, "", null, "• Thank you very much. It seems so nice. – Seyhmus Güngören Aug 15 '17 at 4:52\n• The choice of using the trapezoidal rule is quite fortuitous. It is well-known (see e.g. this, this or this) that the trapezoidal rule is able to give high accuracy for Gaussian-type integrals. – J. M. will be back soon Aug 15 '17 at 15:06\n• I just had the chance to run it on my computer. I have a little problem. trapezoidalIntegrate[fL[x], {x, -8, 8}, 100] doesnt work in my computer. Which version of mathematica do you use? I have only 9 and 10. – Seyhmus Güngören Aug 16 '17 at 20:13\n• What does it return? Did you evaluate the function definition? – Carl Woll Aug 16 '17 at 20:28\n• @SeyhmusGüngören It looks like the FindMaximum algorithm works better in M11 than M10. You could try using a smaller range, say $(-5, 5)$ and a smaller discretization, say $n=10$, and then M9/M10 will produce a result, albeit with a warning. Or, you can choose a different integral discretization, one that has more points where the functions are significantly different from 0. – Carl Woll Aug 17 '17 at 0:06" ]
[ null, "https://i.stack.imgur.com/9W0qE.png", null, "https://i.stack.imgur.com/63ip4.png", null ]
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https://fr.scribd.com/document/400743796/UNIT-5
[ "Vous êtes sur la page 1sur 16\n\n# CIRCULAR WAVEGUIDES\n\nThe waveguides of circular cross-section (Fig. 6.14) are used to transmit EM waves from one\npoint to another. Unlike rectangular waveguides, the circular waveguides do not have unique\norientation as it is perfectly symmetrical around the axis.\n\n## 6.23 SALIENT FEATURES OF CIRCULAR WAVEGUIDES\n\n1. It is easy to manufacture.\n2. They are used in rotational coupling.\n3. Rotation of polarisation exists and this can be overcome by rotating modes\nsymmetrically.\n4. TM01 mode is preferred to TE01 as it requires a smaller diameter for the same cut-off\nwavelength.\n5. TE01 does not have practical application.\n6. For f > 10 GHz, TE01 has the lowest attenuation per unit length of the waveguide.\n7. The main disadvantage is that its cross-section is larger than that of a rectangular\nwaveguide for carrying the same signal.\n8. The space occupied by circular waveguides is more than that of a rectangular waveguide.\n9. The determination of fields here consists of differential equations of certain type. Their\nsolutions involve Bessel functions.\n10. Here also TE and TM modes exist.\n\n## and for TE wave, it is\n\nHz,nm = Jn (Kc r) (A′ cos nϕ + B′ sin nϕ)\n\n## where Jn(Kc r) = Bessel function of the first kind\n\nr = the radius of the guide\nKc = the cut-off wave number\nA, B, A′, B′ = constants\n\nThe solutions for the Bessel function are obtained for certain values of Kc where these values of\nKc are known as eigen values. If Kc is to produce solution of the Bessel function, (Kcr) must be\nthe roots of the Bessel function. Then\n\nJn (Kcr) = 0\n\nPhase constant,\n\nwhere\n\nand\n\n## The cut-off wavelength for TM wave,\n\nThe roots of the Bessel function for TM mode are shown in Table 6.1.\n\n## Table 6.1 Roots of Bessel Function (TM Mode)\n\nThe roots of the Bessel function for TE mode are shown in Table 6.2.\n\n## Table 6.2 Roots of Bessel Function (TE Mode)\n\nFor circular waveguides, TE11 is the dominant mode. The propagation parameters for TEnm mode\nare:\n\nwhere\n\nGuide wavelength,\nProblem 6.11 If the radius of a circular waveguide r = 1.27 cm, f = 10 GHz, find the cut-off\nwavelength for the dominant mode and phase constant. Assume that the waveguide is air-filled.\nTake p′11 = 1.841.\n\nm = 1, n = 1\n\n## The phase constant,\n\nHere\nProblem 6.12 Determine the size of the circular waveguide required to propagate TE11 mode\nif λc = 8 cm (ρ′11 = 1.841).\n\nSolution We have\n\nor,\n\n## Radius of the guide\n\nPOINTS/FORMULAE TO REMEMBER\n\n##  EM wave propagates in a waveguide with multiple reflections.\n\n TE and TM waves exist in a waveguide.\n TEM wave does not exist in a hollow waveguide.\n TEM wave exists between parallel plates.\n The dominant mode has the lowest cut-off frequency.\n The propagation constant between parallel plates is\n The cut-off frequency is a frequency below which the wave is attenuated completely.\n\n##  Between the parallel plates,\n\n λc for TE1 = 2a\n Group velocity, phase velocity and free space velocity are related by v20 =vp vg\n Attenuation of TE waves between parallel plates is\n\n##  Attenuation of TE waves between parallel plates is\n\n A rectangular waveguide is used as a radiator, a high pass filter, a transmission line and\nfeed element to an antenna.\n\n TEM = TM00\n For TEM, Ez = 0, Hz = 0\n λg =λ, βg =β, η = η0, α = 0 for TEM\n\n##  Typically, wave impedance for TEmn wave\n\n Circular waveguides can be used to produce circular polarisation. c TEM wave has zero\ncut-off frequency.\n The field components of TE wave between parallel plates are Ey, Hx, Hz.\n The field components of TM wave between parallel plates are Ex, Ez, Hy.\n TEM wave between parallel plates has only Ex and Hy components.\n The field components of TE in a hollow rectangular waveguide are Ex, Ey, Hx, Hy and Hz.\n The field components of TM in a hollow rectangular waveguide are Ex, Ey, Ez, Hx and Hy.\n\n## A waveguide resonator is a resonator at high frequencies. It is made up of a rectangular\n\nwaveguide with its open ends closed by shorts (Fig. 6.13).\n\n## Fig. 6.13 Rectangular cavity\n\nIt is used for energy storage. As there is no propagation through the shorted ports, standing\nwaves exist inside the cavity. These resonators are used for various applications, particularly in\nklystrons and wave metres.\n\nFeatures of Resonators\n\n1. A rectangular cavity (Fig. 6.13) is a rectangular waveguide whose open ends are shorted.\nIn this type of structure, standing waves, TE and TM waves exist.\n2. Resonators are mainly used for energy storage. At high frequencies RLC circuit elements\nare inefficient when used as resonators. This is because the dimensions of the circuits are\nof the order of operating wavelength. Because of this, radiation takes place which is\nundesirable.\n3. The EM resonator cavities find extensive applications in klystron tubes, band pass filters,\nwave metres and microwave ovens.\nTM Mode (Hz = 0)\n\n## If Ez = (x, y, z) = X(x) Y(y) Z(z),\n\nWe can write, X(x) = C1 cos Ax + C2 sin Ax\nY(y) = C3 cos By + C4 sin By\nZ(z) = C5 cos Cz + C6 sin Cz\n\nwhere\n\nand\n\nHere, we have three boundary conditions to solve the constants, C1, C2,…etc.\n\nEz = 0 at x = 0 and at x = a\n\nEz = 0 at y = 0 and at y = b\n\nEx = 0, Ey = 0 at z = 0 and at z = c\n\n## After simplification, Ezr becomes\n\nwhere Em = C2 C4 C5\n\nor,\nand\n\nTE Mode (Ez = 0)\n\n## Hz (x, y, z) = X(x) Y(y) Z(z)\n\nwhere X(x) = p1 cos Bx + p2 sin Bx\nY(y) = p3 cos Ay + p4 sin Ay\nZ(z) = p5 cos Cz + p6 sin Cz\n\n## Using the boundary conditions, and simplifying, we get\n\nWhere m = 0,1,2,3,…\nn = 0,1,2,3,…\nl = 0,1,2,3,…\n\nDominant Mode\nDominant mode is defined as the mode which has the lowest resonant frequency for a given\ncavity size (a, b, c).\n\n## The waves are represented by TEmnl, TMmnl.\n\nDegenerate Mode\n\nModes having the same resonant frequency are called degenerate modes. Ideally, the walls of the\nresonant cavity have infinite conductivity. But practically, cavity walls have finite conductivity.\nAs a result, some stored energy is lost.\n\nQuality Factor, Q\n\n## Quality factor is defined as\n\nwhere ω = 2πf\nWL = average power loss in a cycle\nWav = average stored energy\n\n## 6.21 SALIENT FEATURES OF CAVITY RESONATORS\n\n1. A completely closed metallic structure forms a cavity and it is called cavity resonator.\n2. It stores energy.\n3. TE and TM modes exist in the cavity.\n4. In TE mode, Ez = 0 (z is propagation direction) and Ex, Ey, Hx, Hy and Hz are present.\n5. In TM mode, Hz = 0 and Hx, Hy, Ex, Ey and Ez are present.\n6. In cavities, the electric and magnetic fields do not propagate along z-axis but they\noscillate with time at a specified location.\n7. The lowest order of TMmnl mode is TM110.\n8. The resonant frequency of the lowest order TM mode is\n\n## 9. The lowest order for TEmnl is TE101.\n\n10. The resonant frequency of the lowest order TE mode is\n\nProblem 6.8 A copper rectangular cavity resonator is structured by 3 × 1 × 4 cm. Find its\nresonant frequency for TM110 mode.\n\n## Solution The dimensions of resonator are:\n\na = 3 cm = 0.03 m\nb = 1 cm = 0.01 m\nc = 4 cm = 0.04 m\n\n## For TM110, the resonant frequency is\n\nProblem 6.9 A copper walled rectangular cavity resonator is structured by 3 × 1 × 4 cm and\noperates at the dominant modes of TE and TM. Find its resonant frequency and quality factor.\nThe conductivity of copper is 5.8 × 107 mho/m. There is air inside the cavity.\n\nSolution For TM mode, the dominant mode is TM100. Its resonant frequency is\n\nHere\nFor TE mode, the resonant frequency of the dominant, TE101 is\n\n## The quality factor, Q for TE101\n\nwhere\nProblem 6.10 A copper walled resonant cavity is dielectric (∈r = 4) filled and its dimensions\nare 5 × 4 × 10 cm. Determine the resonant frequency of TE101 and its quality factor.\n\na = 5 cm\n\nb = 4 cm\n\nc = 10 cm\n\n## The resonant frequency of TE101 is\n\nThe quality factor, Q for this mode is\n\nand" ]
[ null ]
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http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2020/p1831r1.html
[ "# P1831R1Deprecating `volatile`: library\n\n## Published Proposal, 2020-02-12\n\nThis version:\nAuthor:\nAudience:\nLWG\nProject:\nISO/IEC JTC1/SC22/WG21 14882: Programming Language — C++\nSource:\ngithub.com/jfbastien/papers/blob/master/source/P1831R1.bs\n\n## 1. Abstract\n\nThis paper is the library part of P1152. The Core language parts of the deprecation were voted into C++20 at the Cologne meeting as [P1152R4]. LWG was unable to review library wording, this paper therefore carries forward the library parts of [P1152R3].\n\n## 2. Edit History\n\n### 2.1. r0 → r1\n\n• Change one \"they\" to \"it\".\n\n• Don’t use Mandates: clause, use Constraints: instead.\n\n• Clarify why we don’t have a feature test macro.\n\n## 3. Wording\n\nThe proposed wording follows the library approach to deprecation: library deprecation presents the library without the deprecated feature, and only mentions said feature in Annex D.\n\nNo feature test macro is added, per SG10 guidance: developers cannot use a feature test macro to decide to do something else after this deprecation, they should instead fix the code even before the deprecation.\n\n### 3.1. Tuples [tuple]\n\nModify as follows.\n\nHeader `<tuple>` synopsis [tuple.syn]:\n\n``````namespace std {\n\n[...]\n\n// [tuple.helper], tuple helper classes\ntemplate<class T> class tuple_size; // not defined\ntemplate<class T> class tuple_size<const T>;\ntemplate<class T> class tuple_size<volatile T>;\ntemplate<class T> class tuple_size<const volatile T>;\n\ntemplate<class... Types> class tuple_size<tuple<Types...>>;\n\ntemplate<size_t I, class T> class tuple_element; // not defined\ntemplate<size_t I, class T> class tuple_element<I, const T>;\ntemplate<size_t I, class T> class tuple_element<I, volatile T>;\ntemplate<size_t I, class T> class tuple_element<I, const volatile T>;\n\n[...]\n\n}\n\n``````\n\n[...]\n\nTuple helper classes [tuple.helper]\n\n`````` template<class T> class tuple_size<const T>;\ntemplate<class T> class tuple_size<volatile T>;\ntemplate<class T> class tuple_size<const volatile T>;\n``````\n\nLet `TS` denote `tuple_size<T>` of the cv-unqualified type `T`. If the expression `TS::value` is well-formed when treated as an unevaluated operand, then each of the three templates the template shall satisfy the `TransformationTrait` requirements with a base characteristic of\n\n``integral_constant<size_t, TS::value>``\n\nOtherwise, they it shall have no member `value`.\n\nAccess checking is performed as if in a context unrelated to `TS` and `T`. Only the validity of the immediate context of the expression is considered. [ Note: The compilation of the expression can result in side effects such as the instantiation of class template specializations and function template specializations, the generation of implicitly-defined functions, and so on. Such side effects are not in the \"immediate context\" and can result in the program being ill-formed. —end note ]\n\nIn addition to being available via inclusion of the `<tuple>` header, the three templates are template is available when any of the headers `<array>`, `<ranges>`, or `<utility>` are included.\n\n``````\ntemplate<size_t I, class T> class tuple_element<I, const T>;\ntemplate<size_t I, class T> class tuple_element<I, volatile T>;\ntemplate<size_t I, class T> class tuple_element<I, const volatile T>;\n``````\n\nLet `TE` denote `tuple_element_t<I, T>` of the cv-unqualified type `T`. Then each of the three templates the template shall satisfy the `TransformationTrait` requirements with a member typedef `type` that names the following type : `add_const_t<TE>`.\n\n• for the first specialization, `add_const_t<TE>`,\n• for the second specialization, `add_volatile_t<TE>`, and\n• for the third specialization, `add_cv_t<TE>`.\n\nIn addition to being available via inclusion of the `<tuple>` header, the three templates are template is available when any of the headers `<array>`, `<ranges>`, or `<utility>` are included.\n\n### 3.2. Variants [variant]\n\nModify as follows.\n\n`<variant>` synopsis [variant.syn]\n\n``````\nnamespace std {\n// [variant.variant], class template variant\ntemplate<class... Types>\nclass variant;\n\n// [variant.helper], variant helper classes\ntemplate<class T> struct variant_size; // not defined\ntemplate<class T> struct variant_size<const T>;\ntemplate<class T> struct variant_size<volatile T>;\ntemplate<class T> struct variant_size<const volatile T>;\ntemplate<class T>\ninline constexpr size_t variant_size_v = variant_size<T>::value;\n\ntemplate<class... Types>\nstruct variant_size<variant<Types...>>;\n\ntemplate<size_t I, class T> struct variant_alternative; // not defined\ntemplate<size_t I, class T> struct variant_alternative<I, const T>;\ntemplate<size_t I, class T> struct variant_alternative<I, volatile T>;\ntemplate<size_t I, class T> struct variant_alternative<I, const volatile T>;\n\n[...]\n\n}\n\n``````\n\n`variant` helper classes [variant.helper]\n\n``template<class T> struct variant_size;``\n\nRemark: All specializations of `variant_size` shall satisfy the `UnaryTypeTrait` requirements with a base characteristic of `integral_constant<size_t, N>` for some `N`.\n\n```template<class T> class variant_size<const T>;\ntemplate<class T> class variant_size<volatile T>;\ntemplate<class T> class variant_size<const volatile T>;\n```\n\nLet `VS` denote `variant_size<T>` of the cv-unqualified type `T`. Then each of the three templates the template shall satisfy the `UnaryTypeTrait` requirements with a base characteristic of `integral_constant<size_t, VS::value>`.\n\n``````template<class... Types>\nstruct variant_size<variant<Types...>> : integral_constant<size_t, sizeof...(Types)> { };\n``````\n``````template<size_t I, class T> class variant_alternative<I, const T>;\ntemplate<size_t I, class T> class variant_alternative<I, volatile T>;\ntemplate<size_t I, class T> class variant_alternative<I, const volatile T>;\n``````\n\nLet `VA` denote `variant_alternative<I, T>` of the cv-unqualified type `T`. Then each of the three templates the template shall meet the `TransformationTrait` requirements with a member typedef `type` that names the following type : `add_const_t<VA::type>`.\n\n• for the first specialization, `add_const_t<VA::type>`,\n• for the second specialization, `add_volatile_t<VA::type>`, and\n• for the third specialization, `add_cv_t<VA::type>`.\n\n### 3.3. Atomic operations library [atomics]\n\nModify as follows.\n\nOperations on atomic types [atomics.types.operations]\n\n[ Note: Many operations are `volatile`-qualified. The \"volatile as device register\" semantics have not changed in the standard. This qualification means that volatility is preserved when applying these operations to volatile objects. It does not mean that operations on non-volatile objects become volatile. —end note ]\n\n[...]\n\n``````bool is_lock_free() const volatile noexcept;\nbool is_lock_free() const noexcept;\n``````\n\nReturns: `true` if the object’s operations are lock-free, `false` otherwise.\n\n[ Note: The return value of the `is_lock_free` member function is consistent with the value of `is_always_lock_free` for the same type. —end note ]\n\n``````void store(T desired, memory_order order = memory_order::seq_cst) volatile noexcept;\nvoid store(T desired, memory_order order = memory_order::seq_cst) noexcept;\n``````\n\nRequires: The `order` argument shall not be `memory_order::consume`, `memory_order::acquire`, nor `memory_order::acq_rel`.\n\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Atomically replaces the value pointed to by `this` with the value of `desired`. Memory is affected according to the value of `order`.\n\n``````T operator=(T desired) volatile noexcept;\nT operator=(T desired) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to `store(desired)`.\n\nReturns: `desired`.\n\n``````T load(memory_order order = memory_order::seq_cst) const volatile noexcept;\nT load(memory_order order = memory_order::seq_cst) const noexcept;\n``````\n\nRequires: The `order` argument shall not be `memory_order::release` nor `memory_order::acq_rel`.\n\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Memory is affected according to the value of `order`.\n\nReturns: Atomically returns the value pointed to by `this`.\n\n``````operator T() const volatile noexcept;\noperator T() const noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return load();`\n\n``````T exchange(T desired, memory_order order = memory_order::seq_cst) volatile noexcept;\nT exchange(T desired, memory_order order = memory_order::seq_cst) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Atomically replaces the value pointed to by `this` with `desired`. Memory is affected according to the value of `order`. These operations are atomic read-modify-write operations.\n\nReturns: Atomically returns the value pointed to by `this` immediately before the effects.\n\n``````bool compare_exchange_weak(T& expected, T desired,\nmemory_order success, memory_order failure) volatile noexcept;\nbool compare_exchange_weak(T& expected, T desired,\nmemory_order success, memory_order failure) noexcept;\nbool compare_exchange_strong(T& expected, T desired,\nmemory_order success, memory_order failure) volatile noexcept;\nbool compare_exchange_strong(T& expected, T desired,\nmemory_order success, memory_order failure) noexcept;\nbool compare_exchange_weak(T& expected, T desired,\nmemory_order order = memory_order::seq_cst) volatile noexcept;\nbool compare_exchange_weak(T& expected, T desired,\nmemory_order order = memory_order::seq_cst) noexcept;\nbool compare_exchange_strong(T& expected, T desired,\nmemory_order order = memory_order::seq_cst) volatile noexcept;\nbool compare_exchange_strong(T& expected, T desired,\nmemory_order order = memory_order::seq_cst) noexcept;\n``````\n\nRequires: The `failure` argument shall not be `memory_order::release` nor `memory_order::acq_rel`.\n\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Retrieves the value in `expected`. It then atomically compares the value representation of the value pointed to by `this` for equality with that previously retrieved from `expected`,eand if true, replaces the value pointed to by `this` with that in `desired`. If and only if the comparison is true, memory is affected according to the value of `success`, and if the comparison is false, memory is affected according to the value of `failure`. When only one `memory_order` argument is supplied, the value of `success` is `order`, and the value of `failure` is `order` except that a value of `memory_order::acq_rel` shall be replaced by the value `memory_order::acquire` and a value of `memory_order::release` shall be replaced by the value `memory_order::relaxed`. If and only if the comparison is false then, after the atomic operation, the value in `expected` is replaced by the value pointed to by `this` during the atomic comparison. If the operation returns `true`, these operations are atomic read-modify-write operations on the memory pointed to by `this`. Otherwise, these operations are atomic load operations on that memory.\n\nReturns: The result of the comparison.\n\n[...]\n\nSpecializations for integers [atomics.types.int]\n\n``````T fetch_key(T operand, memory_order order = memory_order::seq_cst) volatile noexcept;\nT fetch_key(T operand, memory_order order = memory_order::seq_cst) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Atomically replaces the value pointed to by `this` with the result of the computation applied to the value pointed to by `this` and the given `operand`. Memory is affected according to the value of `order`. These operations are atomic read-modify-write operations.\n\nReturns: Atomically, the value pointed to by `this` immediately before the effects.\n\nRemarks: For signed integer types, the result is as if the object value and parameters were converted to their corresponding unsigned types, the computation performed on those types, and the result converted back to the signed type. [ Note: There are no undefined results arising from the computation. —end note ]\n\n``````T operator op=(T operand) volatile noexcept;\nT operator op=(T operand) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_key(operand) op operand;`\n\nSpecializations for floating-point types [atomics.types.float]\n\nThe following operations perform arithmetic addition and subtraction computations. The key, operator, and computation correspondence are identified in [atomic.arithmetic.computations].\n\n``````T A::fetch_key(T operand, memory_order order = memory_order_seq_cst) volatile noexcept;\nT A::fetch_key(T operand, memory_order order = memory_order_seq_cst) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Atomically replaces the value pointed to by `this` with the result of the computation applied to the value pointed to by `this` and the given `operand`. Memory is affected according to the value of `order`. These operations are atomic read-modify-write operations.\n\nReturns: Atomically, the value pointed to by `this` immediately before the effects.\n\nRemarks: If the result is not a representable value for its type the result is unspecified, but the operations otherwise have no undefined behavior. Atomic arithmetic operations on `floating-point` should conform to the `std::numeric_limits<floating-point>` traits associated with the floating-point type. The floating-point environment for atomic arithmetic operations on `floating-point` may be different than the calling thread’s floating-point environment.\n\n``````T operator op=(T operand) volatile noexcept;\nT operator op=(T operand) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_key(operand) op operand;`\n\nRemarks: If the result is not a representable value for its type the result is unspecified, but the operations otherwise have no undefined behavior. Atomic arithmetic operations on `floating-point` should conform to the `std::numeric_limits<floating-point>` traits associated with the floating-point type. The floating-point environment for atomic arithmetic operations on `floating-point` may be different than the calling thread’s floating-point environment.\n\nPartial specialization for pointers [atomics.types.pointer]\n\n``````T* fetch_key(ptrdiff_t operand, memory_order order = memory_order::seq_cst) volatile noexcept;\nT* fetch_key(ptrdiff_t operand, memory_order order = memory_order::seq_cst) noexcept;\n``````\n\nRequires: T shall be an object type, otherwise the program is ill-formed. [ Note: Pointer arithmetic on `void*` or function pointers is ill-formed. —end note ]\n\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Atomically replaces the value pointed to by `this` with the result of the computation applied to the value pointed to by `this` and the given `operand`. Memory is affected according to the value of `order`. These operations are atomic read-modify-write operations.\n\nReturns: Atomically, the value pointed to by `this` immediately before the effects.\n\nRemarks: The result may be an undefined address, but the operations otherwise have no undefined behavior.\n\n``````T* operator op=(ptrdiff_t operand) volatile noexcept;\nT* operator op=(ptrdiff_t operand) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_key(operand) op operand;`\n\nMember operators common to integers and pointers to objects [atomics.types.memop]\n\n``````T operator++(int) volatile noexcept;\nT operator++(int) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_add(1);`\n\n``````T operator--(int) volatile noexcept;\nT operator--(int) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_sub(1);`\n\n``````T operator++() volatile noexcept;\nT operator++() noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_add(1) + 1;`\n\n``````T operator--() volatile noexcept;\nT operator--() noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Equivalent to: `return fetch_sub(1) - 1;`\n\nNon-member functions [atomics.nonmembers]\n\nA non-member function template whose name matches the pattern `atomic_f` or the pattern `atomic_f_explicit` invokes the member function `f`, with the value of the first parameter as the object expression and the values of the remaining parameters (if any) as the arguments of the member function call, in order. An argument for a parameter of type `atomic<T>::value_type*` is dereferenced when passed to the member function call. If no such member function exists, the program is ill-formed.\n\n``````template<class T>\nvoid atomic_init(volatile atomic<T>* object, typename atomic<T>::value_type desired) noexcept;\ntemplate<class T>\nvoid atomic_init(atomic<T>* object, typename atomic<T>::value_type desired) noexcept;\n``````\nConstraints: For the `volatile` overload of this function, `atomic<T>::is_always_lock_free` is `true`.\n\nEffects: Non-atomically initializes `*object` with value `desired`. This function shall only be applied to objects that have been default constructed, and then only once. [ Note: These semantics ensure compatibility with C. —end note ] [ Note: Concurrent access from another thread, even via an atomic operation, constitutes a data race. —end note ]\n\n[ Note: The non-member functions enable programmers to write code that can be compiled as either C or C++, for example in a shared header file. —end note ]\n\n### 3.4. Annex D\n\nAdd the following wording to Annex D:\n\n#### 3.4.1. Tuple [depr.tuple]\n\nHeader `<tuple>` synopsis [depr.tuple.syn]:\n\n``````namespace std {\n\n[...]\n\n// [tuple.helper], tuple helper classes\ntemplate<class T> class tuple_size<volatile T>;\ntemplate<class T> class tuple_size<const volatile T>;\n\ntemplate<size_t I, class T> class tuple_element<I, volatile T>;\ntemplate<size_t I, class T> class tuple_element<I, const volatile T>;\n\n[...]\n\n}\n\n``````\n\nTuple helper classes [depr.tuple.helper]\n\n``````template<class T> class tuple_size<volatile T>;\ntemplate<class T> class tuple_size<const volatile T>;\n``````\n\nLet `TS` denote `tuple_size<T>` of the cv-unqualified type `T`. If the expression `TS::value` is well-formed when treated as an unevaluated operand, then each of the two templates shall satisfy the `TransformationTrait` requirements with a base characteristic of\n\n``integral_constant<size_t, TS::value>``\n\nOtherwise, they shall have no member `value`.\n\nAccess checking is performed as if in a context unrelated to `TS` and `T`. Only the validity of the immediate context of the expression is considered.\n\nIn addition to being available via inclusion of the `<tuple>` header, the two templates are available when any of the headers `<array>`, `<ranges>`, or `<utility>` are included.\n\n``````\ntemplate<size_t I, class T> class tuple_element<I, volatile T>;\ntemplate<size_t I, class T> class tuple_element<I, const volatile T>;\n``````\n\nLet `TE` denote `tuple_element_t<I, T>` of the cv-unqualified type `T`. Then each of the two templates shall satisfy the `TransformationTrait` requirements with a member typedef `type` that names the following type:\n\n• for the first specialization, `add_volatile_t<TE>`, and\n• for the second specialization, `add_cv_t<TE>`.\n\nIn addition to being available via inclusion of the `<tuple>` header, the two templates are available when any of the headers `<array>`, `<ranges>`, or `<utility>` are included.\n\n#### 3.4.2. Variant [depr.variant]\n\n`<variant>` synopsis [depr.variant.syn]\n\n``````\nnamespace std {\n\n// [variant.helper], variant helper classes\ntemplate<class T> struct variant_size<volatile T>;\ntemplate<class T> struct variant_size<const volatile T>;\n\ntemplate<size_t I, class T> struct variant_alternative<I, volatile T>;\ntemplate<size_t I, class T> struct variant_alternative<I, const volatile T>;\n\n}\n\n``````\n\n`variant` helper classes [depr.variant.helper]\n\n```template<class T> class variant_size<volatile T>;\ntemplate<class T> class variant_size<const volatile T>;\n```\n\nLet `VS` denote `variant_size<T>` of the cv-unqualified type `T`. Then each of the two templates shall satisfy the `UnaryTypeTrait` requirements with a base characteristic of `integral_constant<size_t, VS::value>`.\n\n``````template<size_t I, class T> class variant_alternative<I, volatile T>;\ntemplate<size_t I, class T> class variant_alternative<I, const volatile T>;\n``````\n\nLet `VA` denote `variant_alternative<I, T>` of the cv-unqualified type `T`. Then each of the two templates shall meet the `TransformationTrait` requirements with a member typedef `type` that names the following type:\n\n• for the first specialization, `add_volatile_t<VA::type>`, and\n• for the second specialization, `add_cv_t<VA::type>`.\n\n#### 3.4.3. Atomic operations library [depr.atomics]\n\nIf an atomic specialization has one of the following overloads, then that overload is available when `atomic<T>::is_always_lock_free` is `false`:\n\n``````void store(T desired, memory_order order = memory_order::seq_cst) volatile noexcept;\nT operator=(T desired) volatile noexcept;\nT load(memory_order order = memory_order::seq_cst) const volatile noexcept;\noperator T() const volatile noexcept;\nT exchange(T desired, memory_order order = memory_order::seq_cst) volatile noexcept;\nbool compare_exchange_weak(T& expected, T desired, memory_order success, memory_order failure) volatile noexcept;\nbool compare_exchange_strong(T& expected, T desired, memory_order success, memory_order failure) volatile noexcept;\nbool compare_exchange_weak(T& expected, T desired, memory_order order = memory_order::seq_cst) volatile noexcept;\nbool compare_exchange_strong(T& expected, T desired, memory_order order = memory_order::seq_cst) volatile noexcept;\nT fetch_key(T operand, memory_order order = memory_order::seq_cst) volatile noexcept;\nT operator op=(T operand) volatile noexcept;\nT* fetch_key(ptrdiff_t operand, memory_order order = memory_order::seq_cst) volatile noexcept;\n``````\n\nThe following non-member function is available when `atomic<T>::is_always_lock_free` is `false`:\n\n``````template<class T>\nvoid atomic_init(volatile atomic<T>* object, typename atomic<T>::value_type desired) noexcept;\n``````\n\n### Informative References\n\n[P1152R3]\nJF Bastien. Deprecating volatile. 15 June 2019. URL: https://wg21.link/p1152r3\n[P1152R4]\nJF Bastien. Deprecating volatile. 22 July 2019. URL: https://wg21.link/P1152R4" ]
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https://answers.everydaycalculation.com/multiply-fractions/21-18-times-10-30
[ "Solutions by everydaycalculation.com\n\n## Multiply 21/18 with 10/30\n\n1st number: 1 3/18, 2nd number: 10/30\n\nThis multiplication involving fractions can also be rephrased as \"What is 21/18 of 10/30?\"\n\n21/18 × 10/30 is 7/18.\n\n#### Steps for multiplying fractions\n\n1. Simply multiply the numerators and denominators separately:\n2. 21/18 × 10/30 = 21 × 10/18 × 30 = 210/540\n3. After reducing the fraction, the answer is 7/18\n\nMathStep (Works offline)", null, "Download our mobile app and learn to work with fractions in your own time:" ]
[ null, "https://answers.everydaycalculation.com/mathstep-app-icon.png", null ]
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https://metanumbers.com/27217
[ "27217 (number)\n\n27,217 (twenty-seven thousand two hundred seventeen) is an odd five-digits composite number following 27216 and preceding 27218. In scientific notation, it is written as 2.7217 × 104. The sum of its digits is 19. It has a total of 2 prime factors and 4 positive divisors. There are 25,600 positive integers (up to 27217) that are relatively prime to 27217.\n\nBasic properties\n\n• Is Prime? No\n• Number parity Odd\n• Number length 5\n• Sum of Digits 19\n• Digital Root 1\n\nName\n\nShort name 27 thousand 217 twenty-seven thousand two hundred seventeen\n\nNotation\n\nScientific notation 2.7217 × 104 27.217 × 103\n\nPrime Factorization of 27217\n\nPrime Factorization 17 × 1601\n\nComposite number\nDistinct Factors Total Factors Radical ω(n) 2 Total number of distinct prime factors Ω(n) 2 Total number of prime factors rad(n) 27217 Product of the distinct prime numbers λ(n) 1 Returns the parity of Ω(n), such that λ(n) = (-1)Ω(n) μ(n) 1 Returns: 1, if n has an even number of prime factors (and is square free) −1, if n has an odd number of prime factors (and is square free) 0, if n has a squared prime factor Λ(n) 0 Returns log(p) if n is a power pk of any prime p (for any k >= 1), else returns 0\n\nThe prime factorization of 27,217 is 17 × 1601. Since it has a total of 2 prime factors, 27,217 is a composite number.\n\nDivisors of 27217\n\n1, 17, 1601, 27217\n\n4 divisors\n\n Even divisors 0 4 4 0\nTotal Divisors Sum of Divisors Aliquot Sum τ(n) 4 Total number of the positive divisors of n σ(n) 28836 Sum of all the positive divisors of n s(n) 1619 Sum of the proper positive divisors of n A(n) 7209 Returns the sum of divisors (σ(n)) divided by the total number of divisors (τ(n)) G(n) 164.976 Returns the nth root of the product of n divisors H(n) 3.77542 Returns the total number of divisors (τ(n)) divided by the sum of the reciprocal of each divisors\n\nThe number 27,217 can be divided by 4 positive divisors (out of which 0 are even, and 4 are odd). The sum of these divisors (counting 27,217) is 28,836, the average is 7,209.\n\nOther Arithmetic Functions (n = 27217)\n\n1 φ(n) n\nEuler Totient Carmichael Lambda Prime Pi φ(n) 25600 Total number of positive integers not greater than n that are coprime to n λ(n) 1600 Smallest positive number such that aλ(n) ≡ 1 (mod n) for all a coprime to n π(n) ≈ 2979 Total number of primes less than or equal to n r2(n) 16 The number of ways n can be represented as the sum of 2 squares\n\nThere are 25,600 positive integers (less than 27,217) that are coprime with 27,217. And there are approximately 2,979 prime numbers less than or equal to 27,217.\n\nDivisibility of 27217\n\n m n mod m 2 3 4 5 6 7 8 9 1 1 1 2 1 1 1 1\n\n27,217 is not divisible by any number less than or equal to 9.\n\nClassification of 27217\n\n• Arithmetic\n• Semiprime\n• Deficient\n\n• Polite\n\n• Square Free\n\nOther numbers\n\n• LucasCarmichael\n\nBase conversion (27217)\n\nBase System Value\n2 Binary 110101001010001\n3 Ternary 1101100001\n4 Quaternary 12221101\n5 Quinary 1332332\n6 Senary 330001\n8 Octal 65121\n10 Decimal 27217\n12 Duodecimal 13901\n20 Vigesimal 380h\n36 Base36 l01\n\nBasic calculations (n = 27217)\n\nMultiplication\n\nn×y\n n×2 54434 81651 108868 136085\n\nDivision\n\nn÷y\n n÷2 13608.5 9072.33 6804.25 5443.4\n\nExponentiation\n\nny\n n2 740765089 20161403427313 548732917081177921 14934863804198419475857\n\nNth Root\n\ny√n\n 2√n 164.976 30.0802 12.8443 7.70847\n\n27217 as geometric shapes\n\nCircle\n\n Diameter 54434 171009 2.32718e+09\n\nSphere\n\n Volume 8.44519e+13 9.30873e+09 171009\n\nSquare\n\nLength = n\n Perimeter 108868 7.40765e+08 38490.7\n\nCube\n\nLength = n\n Surface area 4.44459e+09 2.01614e+13 47141.2\n\nEquilateral Triangle\n\nLength = n\n Perimeter 81651 3.20761e+08 23570.6\n\nTriangular Pyramid\n\nLength = n\n Surface area 1.28304e+09 2.37604e+12 22222.6\n\nCryptographic Hash Functions\n\nmd5 ea2c6871f6c0a711fe98331e411daa42 4ecfe08eed0eb27e94f58ee28d08e3374a011f46 d30e4640a4588524f31c0b7872980d0cdeabc601c7af1891724312864e11b5b7 ba94f252017e66bba4e6e9a97c02b98ed3a0567aec23ed28ce29306b1512fdba4ef62b5dda1ad4d99f5cb621a8cd4591da6f3ea789ed365388a99caccc3fb089 dc115fdd6936cb8c60f79f3809d55379ae050302" ]
[ null ]
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https://www.fz-juelich.de/en/ias/ias-9/teaching/introduction-to-data-mining-and-machine-learning
[ "# Introduction to Data Mining and Machine Learning\n\n### Content\n\nData mining and data analysis plays a growing role for the extraction of information both from simulations and experiments/microscopy. This requires knowledge of the algorithms and methods, the underlying statistical/probabilistic concepts as well as the ability to practically use such methods, e.g. through programming. The topic of this module consists of the following sections:\n\n1. basics of stochastics and statistics: events, probability, conditional probability, variance, mean, median, likelihood; Introduction to key concepts of probability theory: probability distributions, expectation values, central limit theorem;\n2. fundamentals of regression and classification;\n3. concepts of linear approaches, Bayesian methods, support vector machines, decision trees, neural networks ;\n4. training validation, testing, overfitting and corss-validation;\n5. selection of appropriate algorithms;\n6. implementation using python and open source libraries\n\n### Objective\n\nStudents will be exposed to fundamental knowledge in stochastics, statistics and combinatorics and will be able to apply this knowledge to test problems using the programming language Python. They will acquire an overview over data mining and machine learning approaches and the corresponding algorithms and will be able to choose the appropriate algorithm for a specific problem. Furthermore, they will be able to implement their own data analysis and machine learning algorithms using python and to independently deign solution approaches to solve problems of materials scientific relevance. Students will be able to analyze their results, judge their qualit and are able to validate them based on their domain knowledge.\n\n### Recommended previous knowledge\n\nbasic python programming knowledge; basic knowledge of concepts of statistical learning, e.g., regression, classifications\n\n• Phuong Vo. T. H, Martin Czygan, Getting Started with Python Data Analysis, 2015, Packt Publishing, Birminham, UK\n• G. James, D. Witten, T. Hastie, and R. Tibshirani. An Introduction to Statistical Learning, with applications in R. Springer, 2013\n\n### Lecture and exercise dates SS23\n\nExercise: Thursdays, 17:30 - 19:00 in GRS001, Schinkelstr. 2a\nLecture: Fridays, 08:30 - 10:00 in GRS001, Schinkelstr. 2a\n\n### Exam SS23\n\nAugust 4 2023, 10:00 - 12:00, H03 (C.A.R.L., Claßenstr. 11)\n\n### Repeat Exam WS23/24\n\nFebruary 29 2024, 11:30 - 13:30, room 002 (TEMP, Republikplatz 6)" ]
[ null ]
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http://mediawiki.feverous.co.uk/index.php/Permutations_and_combinations
[ "# Twelvefold way\n\nIn combinatorics, the twelvefold way is a systematic classification of 12 related enumerative problems concerning two finite sets, which include the classical problems of counting permutations, combinations, multisets, and partitions either of a set or of a number. Twelvefold way_sentence_0\n\nThe idea of the classification is credited to Gian-Carlo Rota, and the name was suggested by Joel Spencer. Twelvefold way_sentence_1\n\n## Overview Twelvefold way_section_0\n\nThe functions are subject to one of the three following restrictions: Twelvefold way_sentence_2\n\nThere are four different equivalence relations which may be defined on the set of functions f from N to X: Twelvefold way_sentence_3\n\nTwelvefold way_ordered_list_0\n\n1. equality;Twelvefold way_item_0_0\n2. equality up to a permutation of N;Twelvefold way_item_0_1\n3. equality up to a permutation of X;Twelvefold way_item_0_2\n4. equality up to permutations of N and X.Twelvefold way_item_0_3\n\nThe three conditions on the functions and the four equivalence relations can be paired in 3 × 4 = 12 ways. Twelvefold way_sentence_4\n\nThe twelve problems of counting equivalence classes of functions do not involve the same difficulties, and there is not one systematic method for solving them. Twelvefold way_sentence_5\n\nTwo of the problems are trivial (the number of equivalence classes is 0 or 1), five problems have an answer in terms of a multiplicative formula of n and x, and the remaining five problems have an answer in terms of combinatorial functions (Stirling numbers and the partition function for a given number of parts). Twelvefold way_sentence_6\n\nThe incorporation of classical enumeration problems into this setting is as follows. Twelvefold way_sentence_7\n\nTwelvefold way_unordered_list_1\n\n## Viewpoints Twelvefold way_section_1\n\nThe various problems in the twelvefold way may be considered from different points of view. Twelvefold way_sentence_8\n\n### Balls and boxes Twelvefold way_section_2\n\nTraditionally many of the problems in the twelvefold way have been formulated in terms of placing balls in boxes (or some similar visualization) instead of defining functions. Twelvefold way_sentence_9\n\nThe set N can be identified with a set of balls, and X with a set of boxes; the function ƒ : N → X then describes a way to distribute the balls into the boxes, namely by putting each ball a into box ƒ(a). Twelvefold way_sentence_10\n\nThus the property that a function ascribes a unique image to each value in its domain is reflected by the property that any ball can go into only one box (together with the requirement that no ball should remain outside of the boxes), whereas any box can accommodate (in principle) an arbitrary number of balls. Twelvefold way_sentence_11\n\nRequiring in addition ƒ to be injective means forbidding to put more than one ball in any one box, while requiring ƒ to be surjective means insisting that every box contain at least one ball. Twelvefold way_sentence_12\n\nCounting modulo permutations of N or X (or both) is reflected by calling the balls or the boxes, respectively, \"indistinguishable\". Twelvefold way_sentence_13\n\nThis is an imprecise formulation (in practice individual balls and boxes can always be distinguished by their location, and one could not assign different balls to different boxes without distinguishing them), intended to indicate that different configurations are not to be counted separately if one can be transformed into the other by some interchange of balls or of boxes. Twelvefold way_sentence_14\n\nThis possibility of transformation is formalized by the action by permutations. Twelvefold way_sentence_15\n\n### Sampling Twelvefold way_section_3\n\nAnother way to think of some of the cases is in terms of sampling, in statistics. Twelvefold way_sentence_16\n\nImagine a population of X items (or people), of which we choose N. Two different schemes are normally described, known as \"sampling with replacement\" and \"sampling without replacement\". Twelvefold way_sentence_17\n\nIn the former case (sampling with replacement), once we've chosen an item, we put it back in the population, so that we might choose it again. Twelvefold way_sentence_18\n\nThe result is that each choice is independent of all the other choices, and the set of samples is technically referred to as independent identically distributed. Twelvefold way_sentence_19\n\nIn the latter case, however, once we've chosen an item, we put it aside so that we can't choose it again. Twelvefold way_sentence_20\n\nThis means that the act of choosing an item has an effect on all the following choices (the particular item can't be seen again), so our choices are dependent on one another. Twelvefold way_sentence_21\n\nIn the terminology below, the case of sampling with replacement is termed \"Any f\", while the case of sampling without replacement is termed \"Injective f\". Twelvefold way_sentence_22\n\nEach box indicates how many different sets of choices there are, in a particular sampling scheme. Twelvefold way_sentence_23\n\nThe row labeled \"Distinct\" means that the ordering matters. Twelvefold way_sentence_24\n\nFor example, if we have ten items, of which we choose two, then the choice (4,7) is different from (7,4). Twelvefold way_sentence_25\n\nOn the other hand, the row labeled \"Sn orders\" means that ordering doesn't matter: Choice (4,7) and (7,4) are equivalent. Twelvefold way_sentence_26\n\n(Another way to think of this is to sort each choice by the item number, and throw out any duplicates that result.) Twelvefold way_sentence_27\n\nIn terms of probability distributions, sampling with replacement where ordering matters is comparable to describing the joint distribution of N separate random variables, each with an X-fold categorical distribution. Twelvefold way_sentence_28\n\nThe case where ordering doesn't matter, however, is comparable to describing a single multinomial distribution of N draws from an X-fold category, where only the number seen of each category matters. Twelvefold way_sentence_29\n\nThe case where ordering doesn't matter and sampling is without replacement is comparable to a single multivariate hypergeometric distribution, and the fourth possibility does not seem to have a correspondence. Twelvefold way_sentence_30\n\nNote that in all the \"injective\" cases (i.e. sampling without replacement), the number of sets of choices is zero unless N ≤ X. Twelvefold way_sentence_31\n\n(\"Comparable\" in the above cases means that each element of the sample space of the corresponding distribution corresponds to a separate set of choices, and hence the number in the appropriate box indicates the size of the sample space for the given distribution.) Twelvefold way_sentence_32\n\nFrom this perspective, the case labeled \"Surjective f\" is somewhat strange: Essentially, we keep sampling with replacement until we've chosen each item at least once. Twelvefold way_sentence_33\n\nThen, we count how many choices we've made, and if it's not equal to N, throw out the entire set and repeat. Twelvefold way_sentence_34\n\nThis is vaguely comparable to the coupon collector's problem, where the process involves \"collecting\" (by sampling with replacement) a set of X coupons until each coupon has been seen at least once. Twelvefold way_sentence_35\n\nNote that in all \"surjective\" cases, the number of sets of choices is zero unless N ≥ X. Twelvefold way_sentence_36\n\n### Labelling, selection, grouping Twelvefold way_section_4\n\nA function ƒ : N → X can be considered from the perspective of X or of N. This leads to different views: Twelvefold way_sentence_37\n\nTwelvefold way_unordered_list_2\n\n• the function ƒ labels each element of N by an element of X.Twelvefold way_item_2_10\n• the function ƒ selects (chooses) an element of the set X for each element of N, a total of n choices.Twelvefold way_item_2_11\n• the function ƒ groups the elements of N together that are mapped to the same element of X.Twelvefold way_item_2_12\n\nThese points of view are not equally suited to all cases. Twelvefold way_sentence_38\n\nThe labelling and selection points of view are not well compatible with permutation of the elements of X, since this changes the labels or the selection; on the other hand the grouping point of view does not give complete information about the configuration unless the elements of X may be freely permuted. Twelvefold way_sentence_39\n\nThe labelling and selection points of view are more or less equivalent when N is not permuted, but when it is, the selection point of view is more suited. Twelvefold way_sentence_40\n\nThe selection can then be viewed as an unordered selection: a single choice of a (multi-)set of n elements from X is made. Twelvefold way_sentence_41\n\n### Labelling and selection with or without repetition Twelvefold way_section_5\n\nWhen viewing ƒ as a labelling of the elements of N, the latter may be thought of as arranged in a sequence, and the labels as being successively assigned to them. Twelvefold way_sentence_42\n\nA requirement that ƒ be injective means that no label can be used a second time; the result is a sequence of labels without repetition. Twelvefold way_sentence_43\n\nIn the absence of such a requirement, the terminology \"sequences with repetition\" is used, meaning that labels may be used more than once (although sequences that happen to be without repetition are also allowed). Twelvefold way_sentence_44\n\nFor an unordered selection the same kind of distinction applies. Twelvefold way_sentence_45\n\nIf ƒ must be injective, then the selection must involve n distinct elements of X, so it is a subset of X of size n, also called an n-combination. Twelvefold way_sentence_46\n\nWithout the requirement, a same element of X may occur multiple times in the selection, and the result is a multiset of size n of elements from X, also called an n-multicombination or n-combination with repetition. Twelvefold way_sentence_47\n\nIn these cases the requirement of a surjective ƒ means that every label is to be used at least once, respectively that every element of X be included in the selection at least once. Twelvefold way_sentence_48\n\nSuch a requirement is less natural to handle mathematically, and indeed the former case is more easily viewed first as a grouping of elements of N, with in addition a labelling of the groups by the elements of X. Twelvefold way_sentence_49\n\n### Partitions of sets and numbers Twelvefold way_section_6\n\nWhen viewing ƒ as a grouping of the elements of N (which assumes one identifies under permutations of X), requiring ƒ to be surjective means the number of groups must be exactly x. Twelvefold way_sentence_50\n\nWithout this requirement the number of groups can be at most x. Twelvefold way_sentence_51\n\nThe requirement of injective ƒ means each element of N must be a group in itself, which leaves at most one valid grouping and therefore gives a rather uninteresting counting problem. Twelvefold way_sentence_52\n\nWhen in addition one identifies under permutations of N, this amounts to forgetting the groups themselves but retaining only their sizes. Twelvefold way_sentence_53\n\nThese sizes moreover do not come in any definite order, while the same size may occur more than once; one may choose to arrange them into a weakly decreasing list of numbers, whose sum is the number n. This gives the combinatorial notion of a partition of the number n, into exactly x (for surjective ƒ) or at most x (for arbitrary ƒ) parts. Twelvefold way_sentence_54\n\n## Formulas Twelvefold way_section_7\n\nFormulas for the different cases of the twelvefold way are summarized in the following table; each table entry links to a subsection below explaining the formula. Twelvefold way_sentence_55\n\nThe particular notations used are: Twelvefold way_sentence_56\n\n### Intuitive meaning of the rows and columns Twelvefold way_section_8\n\nThis is a quick summary of what the different cases mean. Twelvefold way_sentence_57\n\nThe cases are described in detail below. Twelvefold way_sentence_58\n\nThen the columns mean: Twelvefold way_sentence_59\n\nAnd the rows mean: Twelvefold way_sentence_60\n\nTwelvefold way_unordered_list_3\n\n• Distinct: Leave the lists alone; count them directly.Twelvefold way_item_3_13\n• Sn orbits: Before counting, sort the lists by the item number of the items chosen, so that order doesn't matter, e.g. (5,2,10), (10,2,5), (2,10,5), etc. all → (2,5,10).Twelvefold way_item_3_14\n• Sx orbits: Before counting, renumber the items seen so that the first item seen has number 1, the second 2, etc. Numbers may repeat if an item was seen more than once, e.g. (3,5,3), (5,2,5), (4,9,4), etc. → (1,2,1) while (3,3,5), (5,5,3), (2,2,9), etc. → (1,1,2).Twelvefold way_item_3_15\n• Sn×Sx orbits: Before counting, sort the lists and then renumber them, as described above. (Note: Renumbering then sorting will produce different lists in some cases, but the number of possible lists does not change.)Twelvefold way_item_3_16\n\n### Details of the different cases Twelvefold way_section_9\n\nThe cases below are ordered in such a way as to group those cases for which the arguments used in counting are related, which is not the ordering in the table given. Twelvefold way_sentence_61\n\n#### Functions from N to X Twelvefold way_section_10\n\nThis case is equivalent to counting sequences of n elements of X with no restriction: a function f : N → X is determined by the n images of the elements of N, which can each be independently chosen among the elements of x. Twelvefold way_sentence_62\n\nThis gives a total of x possibilities. Twelvefold way_sentence_63\n\n#### Injective functions from N to X Twelvefold way_section_11\n\nThis case is equivalent to counting sequences of n distinct elements of X, also called n-permutations of X, or sequences without repetitions; again this sequence is formed by the n images of the elements of N. This case differs from the one of unrestricted sequences in that there is one choice fewer for the second element, two fewer for the third element, and so on. Twelvefold way_sentence_64\n\nTherefore instead of by an ordinary power of x, the value is given by a falling factorial power of x, in which each successive factor is one fewer than the previous one. Twelvefold way_sentence_65\n\nThe formula is Twelvefold way_sentence_66\n\nNote that if n > x then one obtains a factor zero, so in this case there are no injective functions N → X at all; this is just a restatement of the pigeonhole principle. Twelvefold way_sentence_67\n\n#### Functions from N to X, up to a permutation of N Twelvefold way_section_13\n\nThis case is equivalent to counting multisets with n elements from X (also called n-multicombinations). Twelvefold way_sentence_68\n\nThe reason is that for each element of X it is determined how many elements of N are mapped to it by f, while two functions that give the same such \"multiplicities\" to each element of X can always be transformed into another by a permutation of N. The formula counting all functions N → X is not useful here, because the number of them grouped together by permutations of N varies from one function to another. Twelvefold way_sentence_69\n\nRather, as explained under combinations, the number of n-multicombinations from a set with x elements can be seen to be the same as the number of n-combinations from a set with x + n − 1 elements. Twelvefold way_sentence_70\n\nThis reduces the problem to another one in the twelvefold way, and gives as result Twelvefold way_sentence_71\n\n#### Surjective functions from N to X, up to a permutation of N Twelvefold way_section_14\n\nThis case is equivalent to counting multisets with n elements from X, for which each element of X occurs at least once. Twelvefold way_sentence_72\n\nThis is also equivalent to counting the compositions of n with x (non-zero) terms, by listing the multiplicities of the elements of x in order. Twelvefold way_sentence_73\n\nThe correspondence between functions and multisets is the same as in the previous case, and the surjectivity requirement means that all multiplicities are at least one. Twelvefold way_sentence_74\n\nBy decreasing all multiplicities by 1, this reduces to the previous case; since the change decreases the value of n by x, the result is Twelvefold way_sentence_75\n\nNote that when n < x there are no surjective functions N → X at all (a kind of \"empty pigeonhole\" principle); this is taken into account in the formula, by the convention that binomial coefficients are always 0 if the lower index is negative. Twelvefold way_sentence_76\n\nThe same value is also given by the expression Twelvefold way_sentence_77\n\nThe form of the result suggests looking for a manner to associate a class of surjective functions N → X directly to a subset of n − x elements chosen from a total of n − 1, which can be done as follows. Twelvefold way_sentence_78\n\nFirst choose a total ordering of the sets N and X, and note that by applying a suitable permutation of N, every surjective function N → X can be transformed into a unique weakly increasing (and of course still surjective) function. Twelvefold way_sentence_79\n\nIf one connects the elements of N in order by n − 1 arcs into a linear graph, then choosing any subset of n − x arcs and removing the rest, one obtains a graph with x connected components, and by sending these to the successive elements of X, one obtains a weakly increasing surjective function N → X; also the sizes of the connected components give a composition of n into x parts. Twelvefold way_sentence_80\n\nThis argument is basically the one given at stars and bars, except that there the complementary choice of x − 1 \"separations\" is made. Twelvefold way_sentence_81\n\n### Extremal cases Twelvefold way_section_22\n\nThe above formulas give the proper values for all finite sets N and X. Twelvefold way_sentence_82\n\nIn some cases there are alternative formulas which are almost equivalent, but which do not give the correct result in some extremal cases, such as when N or X are empty. Twelvefold way_sentence_83\n\nThe following considerations apply to such cases. Twelvefold way_sentence_84\n\nTwelvefold way_unordered_list_4\n\n• For every set X there is exactly one function from the empty set to X (there are no values of this function to specify), which is always injective, but never surjective unless X is (also) empty.Twelvefold way_item_4_17\n• For every non-empty set N there are no functions from N to the empty set (there is at least one value of the function that must be specified, but it cannot).Twelvefold way_item_4_18\n• When n > x there are no injective functions N → X, and if n < x there are no surjective functions N → X.Twelvefold way_item_4_19\n• The expressions used in the formulas have as particular valuesTwelvefold way_item_4_20\n\n## Generalizations Twelvefold way_section_23\n\n### The twentyfold way Twelvefold way_section_24\n\nAnother generalization called the twentyfold way was developed by Kenneth P. Bogart in his book \"Combinatorics Through Guided Discovery\". Twelvefold way_sentence_85\n\nIn the problem of distributing objects to boxes both the objects and the boxes may be identical or distinct. Twelvefold way_sentence_86\n\nBogart identifies 20 cases. Twelvefold way_sentence_87" ]
[ null ]
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https://docs.scipy.org/doc/numpy-1.9.3/reference/generated/numpy.ma.mean.html
[ "# numpy.ma.mean¶\n\nnumpy.ma.mean(self, axis=None, dtype=None, out=None) = <numpy.ma.core._frommethod instance at 0x4243f4ac>\n\nReturns the average of the array elements.\n\nMasked entries are ignored. The average is taken over the flattened array by default, otherwise over the specified axis. Refer to numpy.mean for the full documentation.\n\nParameters: a : array_like Array containing numbers whose mean is desired. If a is not an array, a conversion is attempted. axis : int, optional Axis along which the means are computed. The default is to compute the mean of the flattened array. dtype : dtype, optional Type to use in computing the mean. For integer inputs, the default is float64; for floating point, inputs it is the same as the input dtype. out : ndarray, optional Alternative output array in which to place the result. It must have the same shape as the expected output but the type will be cast if necessary. mean : ndarray, see dtype parameter above If out=None, returns a new array containing the mean values, otherwise a reference to the output array is returned.\n\nnumpy.ma.mean\nEquivalent function.\nnumpy.mean\nnumpy.ma.average\nWeighted average.\n\nExamples\n\n```>>> a = np.ma.array([1,2,3], mask=[False, False, True])\n>>> a" ]
[ null ]
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https://kidinfo.com/mathematics/mathematics.html
[ "Brain Teasers and Math Puzzles for Fun\nBarry's Brain Teasers and Puzzles Interactive Math Miscellany and Puzzles\nBraingle: Math Teasers Math Teasers and Brain Puzzles\nMath and Logic Puzzles Math is Fun: Math and Logic Puzzles\nData Analysis and Probability Lessons\nInteractive Activities: Probability\nProbability Interactive Learning Games\n\nMath Calculators Math Calculators Online\n\nMath Flash Cards Math Flash Cards Online\nDictionaries Illustrated Math Flash Dictionary Online\nMath Games Math Game Time\nFree Math Worksheets\n\nDadsworksheets.com (EXCELLENT RESOURCE! 8,153 worksheets and counting: This site has a plethora of math fact worksheets: place value problems, addition, subtraction, multiplication, fractions, word problems, Pre-Algebra, Money, Investing, Geometry, Analog Time, Place Value, Inches, and so MUCH MORE\n\nMath Worksheets - Over 2,000 Free Math Printables by Topic and Grade Level\n\nMathematics Worksheet Creator SuperKids: SuperKids Math Worksheet Creator\n\nSpecific Category Mathematic Skill Sites\nBasic Numbers and Operations (+ - x ÷) - Lessons\nNumbers and Operations Interactive: Order of Operations Math is Fun: Basic Numbers\nKidsNumbers.com Number and Operations Movie Tutorials\nMath.com: Basic Math Skills Virtual Manipulatives: Numbers and Operations\nFractions Lessons and Fraction Help\nVideo: Basic Math For Kids: Addition and Subtraction Interactive Fraction Tutorial\nAAA Math: All About Fractions Fractions for Kids\n\nFinancial Literacy for Kids & Teens: Saving, Investing, Budgeting & Beyond : Financial literacy is one of the most important skills a young person can learn, and fewer than half of American schools carry requirements for it. This extensive site offers vast resources available for teaching kids and teens about how to save, budget, and even invest their money through a wealth of tutorials, games, and tips!\n\nMathematics Sites to Help Improve Your Math Skills Specifically for Students\n\nAAA Math: Features a comprehensive set of interactive arithmetic lessons. Unlimited practice is available on each topic which allows thorough mastery of the concepts. A wide range of lessons (Kindergarten through Eighth grade level) enables learning or review to occur at each individual's current level.\n\nAplusMath: Developed to help students improve their math skills interactive; math game room; flashcards; create and print your own set of flashcards online using the flashcard creator; worksheets section to print worksheets to practice offline. Try the homework helper to check homework solutions.\n\nCoolmath4Kids.com: A fun site to reinforce ALL math skills including geometry and pre-algebra; games, puzzles, and MORE\n\nDiscovery Education Webmath:The internet math site that solves your math problems; Immediate solutions to your problems, complete with the steps. Topics range from general math, K-8 math, algebra, geometry and MORE\n\nFigure This! Math Challenges: Sponsored in part by a grant from the U.S. Department of Education and the National Science Foundation, presents intriguing and challenging math activities in the areas of Algebra, Geometry, Measurement, Numbers, Statistics and Probability.\n\nJohnnie's Math Page: The site to find fun math for kids, math games, and even a little math homework help. Interactive math activities from across the web have been organized by topic to make math learning enjoyable and interesting.\n\nKidsNumbers.com: Free math resource designed by teachers, specifically for students and children of all ages. A place where students can practice all aspects of math, including addition, subtraction, multiplication, and division\n\nIlluminations: Resources for Teaching Math: Illuminations has 102 online interactive activities available. Select which types of activities you're looking for, and click Search; Activities organized by grade levels K - 12\n\nMath Cats: Created for students grades 3 - 8; Includes fun activities on place value, addition and subtraction multiplication and division conversions, measurement, estimation, probability, statistics, fractions, decimals, coordinate geometry, real-life math and offline math crafts and fun math games and puzzles.\n\nMath Goodies: Math lessons are designed to make math meaningful to the student. Each math lesson provides in-depth instruction ideal for learners of all ages and abilities.\n\nMathnook: Free online math games that target a variety of skills; free math worksheet generators as well as teaching tools and other fun and educational material\n\nMath Playground: Welcome to Math Playground, an action-packed site for elementary and middle school students. Practice your math skills, play a logic game and have some fun!\n\nMe and My Math: Slide shows explaining, numbers and place values, addition, subtraction, multiplication, division, the number line, fractions, and the laws of arithmetic\n\nMath Videos Online: Instructional videos which explain mathematics concepts in ALL areas of math\n\nNational Library of Virtual Manipulatives: The National Library of Virtual Manipulatives (NLVM) is an NSF supported project that began in 1999 to develop a library of uniquely interactive, web-based virtual manipulatives or concept tutorials, mostly in the form of Java applets, for mathematics\n\nOnline Interactive Maths: Educational math games in the following areas: addition, subtraction, division and multiplication. Also covered are clock reading skills, time using not only numbers. Several areas are dedicated to problem solving, fractions, roman numerals and the multiplication tables. Ellipses, triangle and circle puzzles. For older students included are percentages and equations, with helpful explanations. Pythagoras theorem, arithmetic progressions, algebra, geometry, trigonometry and probability with explanations are part of our maths games too\n\nQuia Mathematics: 1,961 math activities by grade level\n\nWyzAnt Math Help: A free resource for some of the toughest math subjects including algebra, geometry, and calculus. Filled with images and interactive examples, the help sections can be great for beginners or students looking to review before an exam.", null, "" ]
[ null, "https://kidinfo.com/DidYouKnow.png", null ]
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https://www.geeksforgeeks.org/numpy-zeros-python/
[ "# numpy.zeros() in Python\n\nnumpy.zeros(shape, dtype = None, order = ‘C’) : Return a new array of given shape and type, with zeros.\nParameters :\n\n```shape : integer or sequence of integers\norder : C_contiguous or F_contiguous\nC-contiguous order in memory(last index varies the fastest)\nC order means that operating row-rise on the array will be slightly quicker\nFORTRAN-contiguous order in memory (first index varies the fastest).\nF order means that column-wise operations will be faster.\ndtype : [optional, float(byDeafult)] Data type of returned array.\n```\n\nReturns :\n\n`ndarray of zeros having given shape, order and datatype.`\n\nCode 1 :\n\n `# Python Program illustrating ` `# numpy.zeros method ` ` `  `import` `numpy as geek ` ` `  `b ``=` `geek.zeros(``2``, dtype ``=` `int``) ` `print``(``\"Matrix b : \\n\"``, b) ` ` `  `a ``=` `geek.zeros([``2``, ``2``], dtype ``=` `int``) ` `print``(``\"\\nMatrix a : \\n\"``, a) ` ` `  `c ``=` `geek.zeros([``3``, ``3``]) ` `print``(``\"\\nMatrix c : \\n\"``, c) `\n\nOutput :\n\n```Matrix b :\n[0 0]\n\nMatrix a :\n[[0 0]\n[0 0]]\n\nMatrix c :\n[[ 0. 0. 0.]\n[ 0. 0. 0.]\n[ 0. 0. 0.]]\n```\n\nCode 2 : Manipulating data types\n\n `# Python Program illustrating ` `# numpy.zeros method ` ` `  `import` `numpy as geek ` ` `  `# manipulation with data-types ` `b ``=` `geek.zeros((``2``,), dtype``=``[(``'x'``, ``'float'``), (``'y'``, ``'int'``)]) ` `print``(b) `\n\nOutput :\n\n```[(0.0, 0) (0.0, 0)]\n```\n\nReference :\nhttps://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.zeros.html#numpy.zeros\nNote : zeros, unlike zeros and empty, does not set the array values to zero or random values respectively.Also, these codes won’t run on online-ID. Please run them on your systems to explore the working.\n\nThis article is contributed by Mohit Gupta_OMG 😀. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to [email protected]. See your article appearing on the GeeksforGeeks main page and help other Geeks." ]
[ null ]
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https://dsp.stackexchange.com/questions/43836/complex-iir-to-real-iir/43869
[ "# Complex IIR to Real IIR\n\nI have created an IIR design algorithm that generates complex coefficients (there is no symmetry in the poles and zeros). However, the IIRs will be used to filter a real signal. Is there a closed form (analytical) way to convert the IIR to real coefficients. I did think that using the output of the difference equation to solve a system of linear equations might be a known solution?\n\nAnother way to put the question: when both complex and real IIRs are acting as a digital filter processing discrete samples, for a given real input they produce the same real output (discarding the imaginary component).\n\nAnother way to put the question: Both the complex and real IIRs have the same magnitude response.\n\n• converting a real signal to complex would seem more straightforward – user28715 Sep 20 '17 at 13:03\n• The real output is half the sum of the complex output and its complex conjugate. The complex conjugate output is produced by the filter with complex conjugate coefficients. Using linearity, the filter you want is the parallel concatenation of the original filter and the complex conjugate filter, scaled by 1/2. – Jazzmaniac Sep 20 '17 at 13:44\n• @Jazzmaniac what is parallel concatenation? – Olli Niemitalo Sep 20 '17 at 13:59\n• Your new edits are problematic. It is important to mention that you discard the imaginary part of the filter output. – Olli Niemitalo Sep 22 '17 at 11:20\n• @Olli Niemitalo, yes I feel embarrassed that I haven't defined the problem particularly well. I am not sure if I need to defined the output of the complex filter. I'm hoping the impulse response of the real filter is well defined by the change in constraint? If it doesn't make sense, I probably need some help understanding why not. – keith Sep 22 '17 at 11:53\n\nThis answer shows how to create a real-coefficient infinite-impulse-response (IIR) filter, the output of which equals the real part of the output of a given complex-coefficient IIR filter. Also an example is given that shows that the approach can be useful.\n\nZ-transform $\\mathcal{Z}\\{h[n]\\}$ of a time-domain sequence $h[n]$ has the property that:\n\n$$\\mathcal{Z}\\{h^*[n]\\} = H^*(z^*),\\quad\\text{where }H(z) = \\mathcal{Z}\\{h[n]\\}.\\tag{1}$$\n\nGiven an IIR filter transfer function:\n\n$$H(z) = H_0\\frac{\\prod^M_{k=1}\\left(1-q_kz^{-1}\\right)}{\\prod^N_{k=1}\\left(1-p_kz^{-1}\\right)},\\tag{2}$$\n\nwith real coefficient $H_0$ and $M$ complex zeros $q_k$ and $N$ complex poles $p_k,$ discarding of the imaginary part of its output $h[n]$ to form real output $g[n]$:\n\n$$g[n] = \\operatorname{Re}(h[n]) = \\frac{1}{2}\\left(h[n]+h^*[n]\\right),\\tag{3}$$\n\nis equivalent to having a filter with transfer function:\n\n$$G(z) = \\frac{1}{2}\\big(H(z) + H^*(z^*)\\big).\\tag{4}$$\n\nEquivalently, with $z = e^{i\\omega},$ this new filter has a frequency response $\\frac{1}{2}\\big(F(\\omega) + F^*(-\\omega)\\big),$ where $F(\\omega)$ is the frequency response of the full complex filter. Using further properties of complex conjugation:\n\n$$G(z) = \\frac{1}{2}H_0\\left(\\frac{\\prod^M_{k=1}\\left(1-q_kz^{-1}\\right)}{\\prod^N_{k=1}\\left(1-p_kz^{-1}\\right)} + \\frac{\\prod^M_{k=1}\\left(1-q^*_kz^{-1}\\right)}{\\prod^N_{k=1}\\left(1-p^*_kz^{-1}\\right)}\\right)\\\\ = \\frac{\\frac{1}{2}H_0\\left(\\prod^M_{k=1}\\left(1-q_kz^{-1}\\right)\\prod^N_{k=1}\\left(1-p^*_kz^{-1}\\right) + \\prod^M_{k=1}\\left(1-q^*_kz^{-1}\\right)\\prod^N_{k=1}\\left(1-p_kz^{-1}\\right)\\right)}{\\prod^N_{k=1}\\left(1-p_kz^{-1}\\right)\\prod^N_{k=1}\\left(1-p^*_kz^{-1}\\right)}\\\\ = \\frac{\\mathcal{Z}\\bigg\\{\\operatorname{Re}\\Big(\\mathcal{Z}^{-1}\\left\\{H_0\\prod^M_{k=1}\\left(1-q_kz^{-1}\\right)\\prod^N_{k=1}\\left(1-p^*_kz^{-1}\\right)\\right\\}\\Big)\\bigg\\}}{\\prod^N_{k=1}\\Big(\\left(1-p_kz^{-1}\\right)\\left(1-p^*_kz^{-1}\\right)\\Big)}.$$$\\tag{5}$\n\nBy expanding the products to polynomials of $z^{-1}$, the above gives the procedure to calculate the coefficients of the real filter given the coefficients of the original complex filter, by convolutions of sequences of polynomial coefficients. If the original complex filter with input $x[n]$ and output $y[n]$ is in form:\n\n\\begin{align}y[n] &= b_0\\,x[n] + b_1\\,x[n-1] + b_2\\,x[n-2] + \\ldots\\\\ &-a_1\\,y[n-1] - a_2\\,y[n-1] - \\ldots,\\end{align}\\tag{6}\n\nthat readily accepts the coefficients $B = [b_0,\\,b_1,\\,\\ldots]$ and $A = [a_0,\\,a_1,\\,\\ldots]$ of the numerator and denominator polynomials $b_0+b_1\\,z^{-1}+b_2\\,z^{-2}+\\ldots$ and $a_0+a_1\\,z^{-1}+a_2\\,z^{-2}+\\ldots,$ respectively, with a hidden coefficient $a_0 = 1$, then the coefficients $B_\\text{real}$ and $A_\\text{real}$ for the new filter will be given by:\n\n\\begin{align}B_\\text{real} &= \\frac{1}{2}\\left(B*A^* + B^**A\\right) = \\operatorname{Re}\\left( B*A^*\\right)\\\\ A_\\text{real} &= A*A^* = \\operatorname{Re}\\left(A*A^*\\right),\\end{align}\\tag{7}\n\nwhere $*$ represents convolution (or complex conjugate if superscript). The last $\\operatorname{Re}$ is unnecessary, but may be useful in numerical convolution.\n\n# Example 1: Minimal example\n\nA minimal example in Octave starts with a complex filter and generates a real filter that matches the real output of the complex filter:\n\nb = [0.5, 0.35 - 0.35*j]; #Coefficients of numerator polynomial\na = [1, - 0.6 - 0.6*j]; #Coefficients of denominator polynomial\nlength = 1024;\nimpulse = eye(1, length);\n[h_complex, w_complex] = freqz(b, a, length, \"whole\");\nb_real = real(conv(b, conj(a)))\na_real = real(conv(a, conj(a)))\n[h_real, w_real] = freqz(filter(b_real, a_real, impulse), , length, \"whole\");\n\n\nThe generated real coefficients of the numerator and denominator polynomials of the new real filter are:\n\nb_real =\n0.50000 0.05000 0.00000\n\na_real =\n1.00000 -1.20000 0.72000\n\n\nThe frequency response of the new real filter equals that calculated from the real part of the impulse response of the complex filter:", null, "Figure 1. Blue: Frequency response of the complex filter with the imaginary part of its output still present. The frequency response lacks Hermitian symmetry, so no real-coefficient filter can reproduce it. Red: Shared frequency response of the new real-coefficient filter and the complex-coefficient filter with the imaginary part of its output discarded. The shared frequency response has Hermitian symmetry.\n\n# Example 2: Sliding discrete Fourier transform\n\nConstructing a real filter from a complex filter can sometimes be useful. One such case is calculation of the real part of a single term of a sliding discrete Fourier transform (sliding DFT) of length $r$ at frequency $\\omega = 2\\pi m/r,\\, m\\in N.$ The complex IIR filter is:\n\n\\begin{align}y[n] &= x[n] - x[n-r]\\\\ &+e^{-i\\omega}y[n-1]\\end{align}\\tag{8}\n\nWe get using Eqs. 6 and 7 the coefficients of the numerator and denominator polynomials of the transfer function of the real filter $(A_\\text{real},\\,B_\\text{real})$ from those of the complex filter $(A,\\,B).$ Assuming that $r > 1$ (coefficients not given are zero):\n\n$$\\begin{array}{rcllll} k&=&0&1&r&r+1\\\\ \\hline B[k]&=&1&&-1\\\\ A[k]&=&1&-e^{-i\\omega}\\\\ B_\\text{real}[k]&=&\\operatorname{Re}(1)&\\operatorname{Re}(-e^{i\\omega})&\\operatorname{Re}(-1)&\\operatorname{Re}(e^{i\\omega})\\\\ &=&1&-\\cos(\\omega)&-1&\\cos(\\omega)\\\\ A_\\text{real}[k]&=&1&-e^{i\\omega}-e^{-i\\omega}&-e^{-i\\omega}(-e^{i\\omega})\\\\ &=&1&-2\\cos(\\omega)&1\\end{array}$$\n\nThe real filter is thus:\n\n\\begin{align}y[n] &= x[n] -\\cos(\\omega)x[n-1] -x[n-r] -\\cos(\\omega)x[n-r-1]\\\\ &+ 2\\cos(\\omega)y[n-1] - y[n-2]\\end{align}\n\nThe recursive part can be recognized as the Goertzel filter.\n\nIn Octave:\n\nm = 2;\nr = 20;\nw = 2*pi*m/r;\nb = zeros(1, r+2);\nb(1) = 1; b(2) = -cos(w); b(r+1) = -1; b(r+2) = cos(w);\na = [1, -2*cos(w), 1];\nlength = r+10;\nimpulse = eye(1, length);\nplot([0:length-1], filter(b, a, impulse), \"o\");", null, "Figure 2. Impulse response of a real IIR filter that calculates the real part of a single frequency bin of sliding DFT.\n\nThe impulse response can be zero phase aligned to the opposite end by multiplying the complex transfer function by $e^{-i\\omega}:$\n\nm = 2;\nr = 20;\nw = 2*pi*m/r;\nb = zeros(1, r+2);\nb(1) = cos(w); b(2) = -1; b(r+1) = -cos(w); b(r+2) = 1;\na = [1, -2*cos(w), 1];\nlength = r+10;\nimpulse = eye(1, length);\nplot([0:length-1], filter(b, a, impulse), \"o\");", null, "Figure 3. Impulse response of a real IIR filter that calculates the real part of a single frequency bin of sliding DFT, with zero phase aligned to the opposite end than in Fig. 2. This is a circular shift of the impulse response one sampling period to the left, and can sometimes be used to remove one sample of system latency.\n\nIn case of $m=0,$ the numerator and denominator polynomials will have an unnecessary common factor, but for other values of $m$ the approach works fine.\n\n• I need to double check this before I mark it correct, but much appreciate the time you've taken to explain it so well. – keith Sep 22 '17 at 10:16\n• I'm going to check with some designs that contain single complex zeros on the unit disk (such that the angular frequency of the zero is negative) - empirically I've found this to be troublesome. – keith Sep 22 '17 at 10:22\n• The magnitude response of $G(z)$ is not equal to the magnitude response of $H(z)$, which means the approach produces real output, but not of the same magnitude response as the original filter. I think for the approach to work the condition is actually $H^*(z) = H(z^*)$ which implies conjugate symmetry of the response and therefore of the complex poles/zeros and therefore produces a real coefficient filter anyway. Then a $G(z)$ can be constructed with the same magnitude response as $H(z)$. I upvoted you anyways :-) – keith Sep 22 '17 at 11:02\n• Try these coefficients: a = [1, -0.2266324680203 + 0.973980351156536*j]; and b = ; – keith Sep 22 '17 at 11:58\n• @keith Those a and b also give equal plots for _discard_imag and _real. The notch in the magnitude frequency response of the _complex filter (also present in my example) disappears in _discard_imag because discarding the imaginary part gives a new frequency response $\\frac{1}{2}(F(\\omega) + F^*(-\\omega))$ from the original frequency response $F(\\omega)$ and the notch does not survive addition of large-magnitude stuff to it. – Olli Niemitalo Sep 22 '17 at 12:16" ]
[ null, "https://i.stack.imgur.com/ol3Zg.png", null, "https://i.stack.imgur.com/WNdWa.png", null, "https://i.stack.imgur.com/fri70.png", null ]
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http://ask.sagemath.org/question/54684/inconsistentency-in-parent-of-specialization-of-a-polynomial/
[ "# Inconsistentency in parent of specialization of a polynomial?\n\nI have a family of polynomials and I want to consider special members of this family. In other words I'm considering polynomials in a ring $R = K[x]$ where $K = \\mathbb{Q}[t]$. In sage I do the following:\n\nK = PolynomialRing(QQ, [\"t\"])\nR = PolynomialRing(K, [\"x\"])\n\nt = K.gen(0)\nx = R.gen(0)\n\nf = (t**2 - QQ(1/10)*t + 1)*x**2 + (QQ(3/4)*t + QQ(7/2))*x - t + 8\nf1 = f.specialization({t: 1})\n\n\nThis works fine and as expected $f_1$ is a polynomial only in $x$:\n\nf1.parent() == QQ[\"x\"] # True\n\n\nNow I want to do exactly the same but over $\\overline{\\mathbb{Q}}$ instead:\n\nL = PolynomialRing(QQbar, [\"t\"])\nS = PolynomialRing(L, [\"x\"])\n\nt = L.gen(0)\nx = S.gen(0)\n\ng = (t**2 - QQ(1/10)*t + 1)*x**2 + (QQ(3/4)*t + QQ(7/2))*x - t + 8\ng1 = g.specialization({t: 1})\n\n\nI would expect $g_1$ to be a polynomial only in $x$ as above, i.e. I would expect $g_1 \\in \\overline{\\mathbb{Q}}[x]$. However, I get:\n\ng1.parent() == QQbar[\"x\"] # False\ng1.parent() == S # True\n\n\nIs this a bug? Or am I misunderstanding something?\n\nedit retag close merge delete\n\n## Comments\n\nI do not know why SageMath does not reduce the parent ring upon specialization, but it can be enforced either by explicit conversion g1 = QQbar[\"x\"](g1) or by defining a polynomial ring in two variables from the beginning:\n\nLS = PolynomialRing(QQbar, [\"t\",\"x\"])\nt, x = LS.gens()" ]
[ null ]
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https://mechastellar.com/2019/12/28/mechastellar-unit-points-cost/
[ "# MechaStellar: Unit Points Cost", null, "We discussed in previous posts that Frame is the biggest driver in a units cost to field, and in our last post we talked about how Pilot skill has a variable cost depending on whether you are piloting the average grunt or an extreme prototype.  In this post we’ll go over the math on calculating a units cost.  Worry not!  The unit excel sheet autocalculates points based off of your inputted Frame, Performance and Pilot level so you don’t need to do anything by hand.\n\nWe’ll start with Frame Level.  The cost is Frame Level squared times 5,  or 5x (Frame LVL)^2 .\n\nLevel 1 Frame = 1 x 1 x 5 = 5 points\n\nLevel 2 Frame = 2 x 2 x 5 = 20 points\n\nLevel 3 Frame = 3 x 3 x 5 = 45 points\n\nLevel 4 Frame = 4 x 4 x 5 = 80 points\n\nLevel 5 Frame = 5 x 5 x 5 = 125 points\n\nWe decided early on Frame Level would be a big points cost and decided on an exponential growth function.  Since Frame controls HP, AP, and Armor Saves, each one is considerably good and by the time you reach Frame 4 and 5 you are very, very sturdy compared to your peers and the cost reflects that.\n\nFor Performance and Pilot Skill we initially started with something very simple.  Performance was 2 points per level and Pilot Skill was 3 points per Level.  Now as mentioned at the end of last post, pilot skill lets grunt suits keep up with top of the line suits, now if you put an ace pilot in a powerful machine pilot skill becomes even better.\n\nLikewise for Performance, a Frame 5 Performance 0 Machine may have all the firepower but terrible targeting.  But a Frame 5 Performance 10 machine will be unstoppable.  As a result we decided the formula we need to change at higher Frame Levels.  We made the cutoff at Frame Level 3, since Frame 1 & 2 are where we keep all the grunt suits, and 3 is the transition between grunt and unstoppable prototype.\n\nHere is the formula for Performance.  2.5 points per level for Frames 1 & 2.  5 points per level for Frame 3, 4 & 5.\n\nPilot skill is similar.  2.5 points per level for Frames 1 & 2.  5 points per level for Frames 3, 4 & 5.  After summing points between pilot and skill, round down, so cost of 22.5 becomes 22.\n\nAdditionally, if you cross the threshold into Ace Pilot (6+) there is a 10 point premium to pay.  The premium is there to help with the Pilot skill ability to auto-hit against a lower level pilot.  Putting the premium in there means not every unit fielded will be an ace, and those that are will be nearly immune to the effect.\n\nYou may be wondering why we didn’t use a linear formula, making performance or skill cost more at each Frame level? i.e. Frame 5 has a higher performance cost than Frame 4.\n\nThere are two reasons for that.  One is simplicity, you don’t want to have too complicated a formula, especially if you are going by hand.  Two, while a Frame 5 is more powerful than Frame 4 and 3, in playtesting we found that there isn’t enough to justify a bigger points cost for Performance.  They already have a high base due to the Frame cost (45, 80 and 125 respectively) that adding on scaling performance made it more egregious and people less likely to field high frame suits.  Since many iconic suits are Frame 4, we wanted to avoid that outcome.", null, "Lastly there is an EQ Slot option for low production cost.  This is to represent some mass-produced models that were pretty barebones.  It’s also great to take when you know the model should be a high Frame LVL but you don’t want to justify the cost to field such a slow moving behemoth.  This EQ slot is only available at Frame 2+, and it may not exceed your Frame level.  E.g. Frame 3 can have LVL 2 Low Production cost.  At Frame 2 it reduces points by 5, at 3+ it reduces points by 10.\n\nNow time for some examples.\n\nEarly GM Mass Produced – Frame 1, Performance 0, Pilot 0 = 5 + 0 + 0 = 5 points\n\nGM Ground Type – Frame 1, Performance 1, Pilot 1 = 5 + 2 + 3 = 10 points\n\nZaku II Veteran – Frame 1, Performance 2, Pilot 2 = 5 + 4 + 6 = 15 points\n\nDom – Frame 2, Performance 3, Pilot 2 = 20 + 9 + 6 = 35 points\n\nGouf Custom – Frame 2, Performance 5, Pilot 10 = 20 + 10 + 30 + 10 Ace Premium = 70 points\n\nZeong (Char) – Frame 4, Performance 4, Pilot 8 = 80 + 20 + 40 + 10 Ace Premium = 150 points\n\nGundam (Magnetic Coating) – Frame 4, Performance 4, Pilot 8 = 80 + 20 + 40 + 10 Ace Premium = 150 points\n\nGundam (No Magnetic Coating, early show Amuro) – Frame 4, Performance 2, Pilot 2 = 80 + 10 + 10 = 100 points\n\nZeta Gundam (Kamille) – Frame 4, Performance 8, Pilot 10 = 80 + 40 + 50 + 10 Ace Premium = 180 points\n\nZock – Frame 4, Performance 0, Pilot 0, Low Production Cost 1 = 80 + 0 + 0 -10 = 70 points\n\nBarzam – Frame 2, Performance 5, Pilot 0, Low Production Cost 1 = 20 + 10 + 0 -5 = 25 points\n\nGuncannon – Frame 3, Performance 0, Pilot 0, Low Production Cost 2 = 45 + 0 + 0 – 20 = 25 points" ]
[ null, "https://mechastellar.files.wordpress.com/2019/12/gundam-and-tristars.jpg", null, "https://mechastellar.files.wordpress.com/2019/12/zeong.jpg", null ]
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https://jamiecounsell.me/conditionals-tutorial-09/
[ "### Introduction\n\nLoops, functions, and methods have allowed us to deal with a wide range of problems. Usually, these problems have a simple logic flow, which usually involves taking data, performing some action, then outputting the data in some manner (print, write, etc.). Although these skills are important, there are still many problems we are unable to solve.\n\nDigital logic provides a way of thinking that allows us to break complex (often non-numerical) problems into smaller problems, all which evaluate to one of two possible values. The two values are True, and False. These are represented in Boolean data types.\n\n### Type: Boolean\n\nA Boolean is a type in Python, just like a Float or a String is a type. “Bools” or Boolean data are named after George Boole, the logician who prototyped boolean logic.\n\nA Boolean is a type that only has two possible states. The states are True and False. These can also be represented by the digits 1 (True) and 0 (False). For the purposes of this course, we will refer to them as True and False whenever possible.\n\nLet’s define a boolean variable:\n\n``````myBool = True yourBool = False\n``````\n\nRemember that the True and False operators in Python must start with a capital letter!\n\n##### Special Cases\n\n- Any Number except zero evaluates to `True`\n\n``````>>> bool(100)\nTrue\n>>> bool(0)\nFalse\n>>>\n``````\n\n- Any String except the empty string evaluates to `True`\n\n``````>>> bool(\"Hello\")\nTrue\n>>> bool(\"\")\nFalse\n>>>\n``````\n\n- The NULL operator (in Python: `None`) evaluates to `False`\n\n``````>>> bool(None)\nFalse\n``````\n\n### Boolean Expressions\n\nA boolean expression is a Python expression that evaluates to either True or False. Much like Python’s mathematical operations, which evaluate to mathematical data types such as Int or Float, the Python interpreter calculates them inline.\n\n``````# This is a mathematical expression. x is type Float.\nx = 8*6**(9/12.0)\n\n# This is a string expression. y is a String.\ny = \"This is\" + \" a string.\"\n\n#This is a boolean expression. z is a Bool.\n# Is \"z\" True or False?\nz = 1 > 0\n``````\n\nBoolean statements use operators such as `>`, , `<`, `and`, `or`, and `==`.\n\n``````a = 0 == 1\nb = 1 == 1\nw = 1 > 0\nx = 1 < 0\ny = (1 > 0) and (1 < 0)\nz = (1 > 0) or (1 < 0)\n``````\n\nTry these yourself in the Shell. Do you understand why the values of w, x, y, and z are True or False? When you’re done, take a look at the output:\n\n``````>>> a\nFalse\n>>>\nb True\n>>> w\nTrue\n>>> x\nFalse\n>>> y\nFalse\n>>> z\nTrue\n``````\n\nIf it is unclear why these values are returned, let’s break the problem down.\n\n##### Breaking it Down\n\nWe know it is fact that `1 > 0`. Therefore, we expect this value to evaluate to `True`.\nIt is true that 1 is greater than 0.\n\nWe also know from the same logic that:\nIt is false that 1 is less than 0.\n\nThat explains the first two examples, w and x. Let’s look further into our values for y and z.\n\nTo understand all the operators, let’s use a a few examples.\n\n`!=`, `==`, `>`, `<`, `<=`, `>=`\n\nThese operators are used to evaluate the difference between two variables. They are used just like you would think. The only confusing operator is `==` which compares the equivalence of two values, and is often confused with the `=` operator, which sets a variable equal to some value. Another confusing operator is `!=`, which is `True` if both elements are not equal.\n\n##### The `and` Operator\n``````x and y # True if both x and y are True\n``````\n\nLet’s say your 1P03 group has three members. `Member1`, `Member2`, and `Member3`. You are being graded by a computer that checks if each member is in attendance by using the function `memberAttended(member)` where `member` is a group member. This function returns `True` if the member has attended, and `False` otherwise.\n\nIf all group members must attend a tutorial, you can check if you have succeeded the requirement by checking:\n\n``````memberAttended(Member1) and memberAttended(Member2) and memberAttended(Member3)\n``````\n\nIf this evaluates to `True` (`True and True and True`), then you pass. Otherwise, it evaluates to `False` (ex. `False and True and True`) because `Member1` did not attend, you will fail!\n\n##### The `or` Operator\n``````x or y # True if either x or y are True\n``````\n\nIf only one of your group members must be present to hand in an assignment, you can check if you have succeeded the requirement by checking:\n\n``````memberAttended(Member1) or memberAttended(Member2) or memberAttended(Member3)\n``````\n\n### The `if` statement\n\nThe `if` statement is the basic framework for computation based on boolean logic. It executes code based on a boolean expression.\n\nThe basic structure for an if statement is as follows:\n\n``````if (expression):\n# Do something\n``````\n\nThis runs the code in the “Do something” section IF AND ONLY IF the term `expression` returns `True`. Let’s look at a basic example:\n\n``````x = 0\n\nif (x == 0):\nprint \"zero\"\n\nif (x == 1):\nprint \"one\"\n``````\n\nWhat will print? Try running this in IDLE.\n\nANY Boolean statement can be used in the `if` statement. That means as long as (expression) evaluates to `True`, it will run. Otherwise, it will not. We can use the function `bool()` to check the Boolean value of something.\n\n##### `elif`\n\nThe `elif` statement is a little different. It can be read as else, if. For example:\n\n``````if (expression1):\n# Do something\nelif (expression2):\n# Do something else\n``````\n\nThis can be read as “If some statement is true, do something. Else, if some other statement is true, do something else.\n\n##### ELSE\n\nThe `else` statement is just like `elif`, but accounts for ALL other cases (it takes no expression and assumes `True`). It can be read as “else” or “otherwise”. For example:\n\n``````if (expression):\n# Do something\nelse:\n# Do something else\n``````\n\nThis can be read as “If some statement is true, do something. Otherwise, in any other case, do something else.\n\nThis is a great way to “catch” certain interesting cases that variables may have. (Maybe catching a variable to check if it is set to zero before dividing)\n\n`if` statements should be fairly easy, and your textbook has a great section on them. Attempt the practice problems below and let me know if I need to elaborate the `if` statement." ]
[ null ]
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https://tomopt.com/tomlab/products/misqp/
[ "", null, "", null, "", null, "LOGIN", null, "REGISTER (FREE TRIAL)", null, "myTOMLAB\n Products", null, "TOMLAB Base Module", null, "TOMLAB /MINOS", null, "TOMLAB /NPSOL", null, "TOMLAB /DNOPT", null, "TOMLAB /SNOPT", null, "TOMLAB /SOL", null, "TOMLAB /CGO", null, "TOMLAB /CPLEX", null, "TOMLAB /GUROBI", null, "TOMLAB /MINLP", null, "TOMLAB /MIPNLP", null, "TOMLAB /MISQP", null, "Solvers", null, "TOMLAB /PENSDP", null, "TOMLAB /PENBMI", null, "TOMLAB /KNITRO", null, "TOMLAB /OQNLP", null, "TOMLAB /PROPT", null, "TOMLAB /NLPQL", null, "TOMLAB /LGO", null, "TOMLAB /LGO-MINLP", null, "TOMLAB /GP", null, "TOMLAB /GENO", null, "TOMLAB /MAD", null, "TOMLAB /MIDACO\n\n# TOMLAB /MISQP\n\nTOMLAB /MISQP integrates The MathWorks' MATLAB and the MISQP and NLPQL solvers from Klaus Schittkowski.\n\n## Features and capabilities\n\n• The MISQP solver handles dense mixed-integer nonlinear programming problems by a modified sequential quadratic programming (SQP) method. Under the assumption that integer variables have a smooth influence on the model functions, i.e., that function values do not change drastically when in- or decrementing an integer variable, successive quadratic approximations are applied. It is not assumed that integer variables are relaxable, i.e., problem functions are evaluated only at integer points. The code is applicable also to nonconvex optimization problems.\n\n• The MIQL solver solves strictly convex mixed-integer quadratic programming problems subject to linear equality and inequality constraints by a branch-and-cut method.\n\n• The NLPQLP solver handles dense nonlinear programming problems.\n\n• The solver NLPJOB enables interactive solution of multicriteria optimization problems. The user can select from several different options.\n\n• The solver DFNLP Solves constrained nonlinear least squares, L1- and min-max problems, where the objective function is of the following form:\n- sum of squares of function values\n- sum of absolute function values\n- maximum of absolute function values\n- maximum of functions\nIn addition there may be any set of equality or inequality constraints. It is assumed that all individual problem functions are continuously differentiable. Read more about DFNLP at\n\n• TOMLAB /MISQP is integrated with the TOMLAB environment.\n\n• The TOMLAB /MISQP solvers may be used as subproblem solvers in the TOMLAB environment.\n\n## Requirements\n\n• MATLAB 6.5 or later" ]
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https://www.quesba.com/questions/suppose-fit-multiple-regression-model-n-30-data-points-obtain-following-res-632484
[ "# Suppose you fit the multiple regression model to n = 30 data points and obtain the following...\n\nSuppose you fit the multiple regression model", null, "to n = 30 data points and obtain the following result:", null, "The estimated standard errors of", null, "2 and", null, "3 are 1.86 and .29, respectively.\n\na. Test the null hypothesis H0:", null, "2 = 0 against the alternative hypothesis Ha:", null, "2 ≠ 0. Use", null, "= .05.\n\nb. Test the null hypothesis H0:", null, "3 = 0 against the alternative hypothesis Ha:", null, "3 ≠ 0. Use", null, "= .05.\n\nc. The null hypothesis H0:", null, "2 = 0 is not rejected. In contrast, the null hypothesis H0:", null, "3 = 0 is rejected. Explain how this can happen even though", null, "2", null, "", null, "3.\n\nJul 23 2021| 03:19 PM |", null, "" ]
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http://www.rellek.net/book/ch_polya.html
[ "Skip to main content\n\n# Chapter15Pólya's Enumeration Theorem¶ permalink\n\nIn this chapter, we introduce a powerful enumeration technique generally referred to as Pólya's enumeration theorem 1 . Pólya's approach to counting allows us to use symmetries (such as those of geometric objects like polygons) to form generating functions. These generating functions can then be used to answer combinatorial questions such as\n\n1. How many different necklaces of six beads can be formed using red, blue and green beads? What about $500$-bead necklaces?\n\n2. How many musical scales consisting of $6$ notes are there?\n\n3. How many isomers of the compound xylenol, $\\text{C} _6\\text{H} _3(\\text{CH} _3)_2(\\text{OH} )\\text{,}$ are there? What about $\\text{C} _n \\text{H} _{2n+2}\\text{?}$ (In chemistry, isomers are chemical compounds with the same number of molecules of each element but with different arrangements of those molecules.)\n\n4. How many nonisomorphic graphs are there on four vertices? How many of them have three edges? What about on $1000$ vertices with $257,000$ edges? How many $r$-regular graphs are there on $40$ vertices? (A graph is $r$-regular if every vertex has degree $r\\text{.}$)\n\nTo use Pólya's techniques, we will require the idea of a permutation group. However, our treatment will be self-contained and driven by examples. We begin with a simplified version of the first question above." ]
[ null ]
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https://cs.stackexchange.com/questions/101564/number-of-divisors-of-a-number-in-np
[ "# Number of divisors of a number - in NP?\n\nI'm trying to show that the language {(m,n)|m has exactly n divisors} is in NP.\n\nThe input (m,n) is in binary.\n\nThe non-deterministic Turing machine for the language would be:\n\n1) Guess the prime factors of m.\n\n2) Verify that ∏i(di+1)=n.\n\nThe problem is that I can't find a way to factorize in polynomial time (in the input) the number m.\n\nIf stage 1 takes m steps then it would be m=2 ^ log(m) and the whole algorithm would run in exponential time.\n\nHow can I prove that verifying that m has exactly n divisors is in NP ? Perhaps not via factorization but somehow else. I've run out of ideas.\n\n• You seem to be misunderstanding the difference between P and NP. An NP machine doesn’t have to compute a factorization in polytime - it just as to be able to verify a given factorization in polytime. To this end, it’s useful to know that primality testing is in P. – Yuval Filmus Dec 15 '18 at 9:52\n• @YuvalFilmus I know that i can get a certificate and just verify it but what would it be ? If the certificate is the list of prime factors then i need to check if it is of length O(log(m)) but how long do i run to check its length - 2logm, 3 logm, 4logm... ? – caffein Dec 15 '18 at 10:00\n• @YuvalFilmus Also, how do i prove that the number of prime factors of m is log(m) ? If it is longer then the whole machine would run in non polynomial time – caffein Dec 15 '18 at 10:02\n• Take it as an exercise. Use $2^{\\log m} = m$. – Yuval Filmus Dec 15 '18 at 10:02\n• The problem is that i need a formal proof and after googling it doesn't seem trivial at all - to prove that a number with m digits has O(log(m)) prime factors. – caffein Dec 15 '18 at 10:10" ]
[ null ]
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https://ee.sabanciuniv.edu/en/graduate/phd-qualifying-exam
[ "## Ph.D. Qualifying Exam\n\n### Ph.D. Qualifying Exam\n\nLISTEN\n• 1) The EE Qualifier Exam will consist of an equal number of questions from each of the following four areas, the number of questions is identified inside parentheses.\n• Electronic Circuits: ENS203 (2)\n• Signals: ENS211 (2)\n• Engineering (Basic) Math: MATH201 (1), MATH203 (1)\n• Electromagnetics: ENS201 (2)\n• Out of 8 questions students must select and submit only 5 questions consisting of, one question from each of the four areas and one other question from any of the four areas.  A sample selection is: Electronic Circuits (1), Signals (2), Basic Math (1), Electromagnetics (1).\n• 2) Students have to pass the EE Qualifier Exam with a minimum score of 70 to be considered successful at the written stage of the qualifying exam.\n• 3) Students can attempt the EE Qualifier exam at most twice.\n• 4) For each topic, relevant faculty members can provide exam questions and will be responsible for their grading.\n• 5) Relevant faculty members include: instructors of the course in the particular academic year, or instructors who have taught the course in prior semesters, or instructors in the related field. If > 2 relevant faculty members would like to contribute, they will form a sub-committee to agree on the questions.\n• 6) Exam questions will be gathered and combined by the Graduate Coordinator (in the particular academic year) and will be provided to the Dean’s Office for the management and execution of the exam.\n\nEE Qualifier Exam\n\n(Total:8 Questions)\n\nTopics (briefly)\n\nRelevant Courses That Prepare Students (Courses Corresponding to Exam Topics)\n\nSuggested Texts/Materials\n\nElectronic Circuits\n\nPassive components, basic circuit analysis, first order circuits, transient and steady state analysis, second order RLC circuits, resonance, amplifier fundamentals, operational amplifiers, introduction to diodes and transistors.\n\nENS 203 (2 questions)\n\nAllan R. Hambley. Electrical Engineering: Principles & Applications.\n\n7th edition.\n\nJ.W.Nilsson, S.A.Reidel, Electric Circuits, Prentice Hall\n\nAdel S. Sedra, Kenneth C. Smit, Microelectronic Circuits, Oxford University Press\n\nSignals\n\nContinuous and discrete, periodic and aperiodic signals, impulse, unit step signals. Spectrum representation of a signal. Fourier series representation of periodic signals. System concept. Continuous and Discrete Finite Impulse Response (FIR) Systems. Linear Time Invariant (LTI) Systems. Impulse response and Frequency response of LTI systems. Fourier transform of aperiodic and periodic signals. Filtering in time and frequency domain. Sampling of continuous signals. Aliasing. Bandlimited reconstruction, interpolation. Basic Amplitude Modulation.\n\nENS 211 (2 questions)\n\nDSP First\n\nby James H. McClellan, Ronald W. Schafer, and Mark A. Yoder,\n\nPearson Education, 2nd edition 2016.\n\nEngineering Mathematics\n\nMath 201 (Linear Algebra):\n\nSystems of linear equations; Gaussian elimination. Vector spaces, subspaces, linear, independence, dimension, change of basic. Linear transformations. Inner product, orthogonality. Eigenvalues. Diagonalization and canonical forms. Cayley-Hamilton theorem.\n\nMath 203 (Probability):\n\nCounting techniques, combinatorial methods, random experiments, sample spaces, events, probability axioms, some rules of probability, conditional probability, independence, Bayes' theorem, random variables (r.v.'s), probability distributions, discrete and continuous r.v.'s, probability density functions, multivariate distributions, marginal and conditional distributions, expected values, moments, Chebyshev's theorem, product moments, moments of linear combinations of r.v.'s, special discrete distributions, uniform, Bernouilli, binomial, negative binomial, geometric, hypergeoemtric and Poisson distributions, special probability densities, uniform, gamma, exponential and normal densities, normal approximation to binomial, distribution of functions of r.v.'s, distribution function and moment-generating function techniques, distribution of the mean, law of large numbers, the central limit theorem.\n\nMATH 201\n\n(1 question)\n\nMATH 203\n\n(1 question)\n\nMath 201:\n\nG. Strang, Introduction to Linear Algebra. Fifth edition (2016) Wellesley-Cambridge Press and SIAM\n\nMath 203:\n\nJohn Freund's Mathematical Statistics with Applications, 8th Edition, Pearson-\n\nPrentice Hall, 2004\n\nElectromagnetics\n\nReview of vectors and mathematical background. Static and magnetic fields and electromagnetic properties of materials. Faraday's Law with applications to electromechanical systems. Introduction to Maxwell's equations and electromagnetic waves.\n\nENS 201 (2 questions)\n\nF.T. Ulaby, Fundamentals of Applied Electromagnetics, Prentice-Hall\n\nD.K. Cheng, Field and Wave Electromagnetics, 2nd Ed, Addison –Wesley\n\nJ.D. Kraus D.A. Fleisch, Electromagnetics with applications, 5th Ed, McGraw-Hill" ]
[ null ]
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https://mail.haskell.org/pipermail/glasgow-haskell-users/2008-March/014537.html
[ "# [GHC] #2163: GHC makes thunks for Integers we are strict in\n\nDon Stewart dons at galois.com\nWed Mar 19 19:51:53 EDT 2008\n\n```igloo:\n> On Wed, Mar 19, 2008 at 05:31:08PM +0000, Ian Lynagh wrote:\n> > On Tue, Mar 18, 2008 at 04:12:35PM -0000, GHC wrote:\n> > >\n> > > (don't worry, this often catches me out too. Perhaps a strict let\n> > > should be indicated more explicitly in `-ddump-simpl`).\n> >\n> > I'd certainly find it useful if it was clearer.\n>\n> In fact, simpl hides more than I'd realised. With these definitions:\n>\n> f :: Integer -> Integer -> Integer -> Integer\n> f x y z | y == 1 = x * z\n> | otherwise = f (x * x) y (z * z)\n>\n> g :: Integer -> Integer -> Integer -> Integer\n> g x y z | y == 1 = x\n> | otherwise = g (x * x) y (z * z)\n>\n> simpl shows\n>\n> B.f (GHC.Num.timesInteger x_a5B x_a5B) y_a5D\n> (GHC.Num.timesInteger z_a5F z_a5F);\n>\n> and\n>\n> B.g (GHC.Num.timesInteger x_a74 x_a74) y_a76\n> (GHC.Num.timesInteger z_a78 z_a78);\n>\n> for the recursive calls, although in the STG you can see that the\n> multiplication of z is done strictly in f but not g (which is correct,\n> as g is not strict in z).\n>\n> So perhaps the solution is just that I should look at the STG rather\n> than the simpl when I want to see what's going on.\n>\n>\n> Thanks\n\nWe really need an official and blessed view of the optimised core, with\nfull, relevant information, in human readable form.\n\nJust simplifiying the obvious qualified names would be a start, and\nsome simple alpha renaming.\n\n-- Don\n```" ]
[ null ]
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https://mathzsolution.com/the-series-%E2%88%91%E2%88%9En11nsum_n1inftyfrac1n-diverges/
[ "# The series ∑∞n=11n\\sum_{n=1}^\\infty\\frac1n diverges!\n\nWe all know that the following harmonic series\n\ndiverges and grows very slowly!! I have seen many proofs of the result but recently found the following:\nIn this way we see that $S > S$.\n\nCan we conclude from this that $S$ is divergent??\n\nThe proof can be made a bit more rigorous by setting\n\nNote that $a_n\\ge b_n$, $a_n\\gt b_n$ when $n$ is odd, and $a_n=b_{2n-1}+b_{2n}$.\n\nAssuming that\n\nconverges, then\n\nalso converges. However,\n\nSince $a_n\\ge b_n$ and $a_n\\gt b_n$ when $n$ is odd.\n\nNow, $(3)$ says that\n\nand $(4)$ says that\n\nThese last two statements are contradictory, so the assumption that $(2)$ converges must be false." ]
[ null ]
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https://www.ars-una.net/velocity-basic-parameter
[ "# ARS UNA\n\n## Connecting Arts, Religion, Sciences - Alternative Philosophy of Development  A modern Middle Way in Institutions and  Private Life  (in English and German)\n\n### Velocity as basic parameterFractal heuristic ideas on emergence", null, "Each generation passes on to the following generation four essential qualities: its constants, its impulses, its transformations, and what emerges in it (emergence).\n\nThe constants should be scalars, the impulses must be expressed as usual in the natural sciences according to an equation I = m * v, where m is the mass and v the velocity. Transformations can be seen in the kinetic energy (const) m * v2, which is found in extreme form in the Einstein relation E = mc2, which accounts for the important conversion of mass into energy, e.g. in reactors and nuclear weapons.\nThus we have a constant, a linear and a quadratic term of a beginning series expansion as a function of a quantity x, which is obviously the velocity. However, according to the considerations outlined on this website, our world is to be described as four-dimensional, so that a cubic term would have to be added as well, ie of the form m * v3, which does not mean anything to us at the moment, but should contain emergence. Overall, we can write:\nm0 + m1 * xn + m2 * xn2 + m3 * xn3 ==> xn + 1\nwhich would mean that a new velocity can be derived in each new generation, which would be a function of the velocity of the previous generation.\nSpeculation is frowned upon in the natural sciences, but has its legitimacy as a heuristic agent. Since, at least for the time being, no proof can be given for these considerations, consistency should at least be required. In any case, the above formula makes it understandable that the velocity (for example, of the growth of the universe we know) always goes on to increase.\nThe exciting question, however, would be whether there may be a third-power term of velocity which in any way should describe emergence, e.g. in a supernova with possible superfluidity or in pair-formation (e.g., electron and positron). All in all, however, fractal ideas should also be attributed the same importance as to logically derived findings. Beyond a certain complexity these in any case go beyond strict logic and are in agreement to notions of \"fuzzy\" logic. Heuristic approaches to so-called \"fractomatics\" can also be found on this website." ]
[ null, "https://mediaprocessor.websimages.com/width/300/crop/0,0,300x200/www.ars-una.net/fractal_emergence.jpg", null ]
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http://pena.lt/y/2014/04/22/expected-goals-and-exponential-decay/
[ "# Expected Goals And Exponential Decay\n\n## Introduction\n\nIn my last article on expected goals I showed how to incorporate the distance from goal along the Y axis into the expected goal model using Pythagoras' Thereom.\n\nThis all worked pretty well, giving us an r squared value of 0.95. However, while the r squared value was good there was still a flaw in the model we need to fix.\n\n## Better than Ronaldo\n\nEagle-eyed readers will have noticed that the fit of the curve broke down for very short distances, meaning the probability of scoring from zero metres was actually slightly above one. And as reader Benjamin Lindqvist commented, not even Ronaldo will score more than 100% of the time, not even from the goal line. Benjamin also had a good suggestion to improve this, adding an exponential decay function into the model to make it behave better around zero\n\n## Exponential Decay\n\nIf you aren’t familiar with exponential decay it basically means that a value decreases at a rate proportional to its current value. It’s a phenomenon that crops up fairly frequently in science and the natural world. For example, air pressure decays exponentially as you go higher up into the Earth’s atmosphere and radioactivity decreases exponentially over time.\n\nA general equation for exponential decay is shown in Figure 1, where Y(t) is the value at time t, a is the starting value, k is the decay constant and t is time.\n\n\\$y(t)=ae^{kt}\\$\n\nFigure 1: Exponential Decay\n\nSo how do we apply this to football? Well, the first thing to do is replace time with metres and assume that the probability of scoring a goal decreases exponentially based upon the distance from goal the shot is taken from.\n\nNext we need to find the correct value for the decay constant as this controls the shape of the curve. Rather than doing this manually through trial and error, we can use something such as R’s optim function to find it for us. We can also tweak the equation to add in a multiplier for the independent variable and an intercept as found in a traditional regression model giving us the fit shown in Figure 2.", null, "Figure 2: Shots Versus Distance From Goal\n\nNotice how the orange line now hits the Y axis just below 1.0? This fixes the problem we had before where it was possible to score more than one goal from a single shot. In fact, if you’re standing on the goal line the model now predicts around 0.96 expected goals, so very likely to score but with a small chance of screwing up (yes Edin Džeko I’m looking at you).\n\nThe new curve fit also pushes the r squared value up to 0.9883, meaning 98.83% of the variance for the probability of scoring from a shot can be accounted for using just distance from goal along the X and Y axes.\n\nThe final equation (Figure 3) is slightly more complicated now but it’s still pretty simple to use.\n\n\\$expg=e^{-d/4.79}*0.921985+0.036212\\$\n\nFigure 3: Expected Goals Equation Incorporating Exponential Decay\n\nwhere:\n\n\\$d=sqrt(dx^2+dy^2)\\$\n\nFigure 4: Equation for d\n\nand dx, dy are the difference between the x coordinates and y coordinates in metres for the shot location and the goal location.\n\nAs ever, let me know what you think!\n\nOI - April 24, 2014\n\nTwo Questions:\n\n-Did you use two different samples for this article and the last one about the y-axis? Some points seem to be relocated from Figure 3 in the last piece to Figure 2 here. For example, there is hardly a difference in scoring probability between 5 and 6 metres distance in the other diagramm, whereas in this diagramm the difference is approximately 5%!\n\n-Are blocked shots included in your calculations?-\n\nMartin Eastwood - April 24, 2014\n\nYes, in between those articles I increased the number of shots in my database by nearly 25% so hopefully some of the noise for distances where I didn’t have many shots should be smoothed out. Everything categorised as a shot by Squawka is included in the calculation except for penalties and own goals.\n\nBenjamin Lindqvist - April 24, 2014\n\nHi Martin,\n\nGlad to have been of help. If you’re interested in hearning more negativity, I think your function is now probably overfitted :)\n\nIf you have Skype, feel free to add me (benjaminlindqvist). Not all topics regarding football and numbers are suited to the public!\n\nMartin Eastwood - April 25, 2014\n\nAh the perennial conflict between optimising and over-fitting :)\n\nIt’s certainly a risk considering the number of data points I have but I’m not too concerned at the moment as it’s a fairly simple curve rather than some high-order polynomial weaving between the data points. Plus, even though the exponential decay certainly improved the fit the actual expected goal values predicted haven’t really change too much, so in the grand scheme of things any over-fitting probably isn’t having that much of an impact at the moment. It’s certainly something to bear in mind though!\n\nI’ve added you to Skype, would be good to have a chat sometime if you’re free :)\n\nPeP - April 28, 2014\n\nHi Martin,\n\nI’m very intrigued by your expected goals model and I’m very impressed with the accuracy. Would it be possible to include the Z-axis into your model or is the lack of data holding you back on this.\n\nMartin Eastwood - April 28, 2014\n\nBy z axis do you mean location in the goal? If so, then there is no reason it couldn’t be incorporated into the model I just don’t have the data available yet.\n\nPeP - April 28, 2014\n\nI meant at what height the ball is struck from off the pitch. For example if the xy coordinates were kept the same then was the ball struck from off the ground , was the ball struck on the volley or was it an overhead kick.\n\nBenjamin Lindqvist - May 5, 2014\n\nI highly doubt that would be a convex realtionship so that would be hard to fit into this particular model.\n\nMax - May 20, 2014\n\nThis is amazing… How did you the power curve? Did you find it by trial and error?\n\nMartin Eastwood - May 20, 2014\n\nNo, it was created using mathematical optimisation techniques rather than trial and error as they can do a better job than me!\n\nEV - July 21, 2014\n\nThis is an amazing piece of work Martin. And thank you very much for sharing it with us. The effort of gathering the data must have been enormous. I have some questions that will probably be interesting for you:\n\nI assume you group the shot distances into 1m intervals, and got the probability of a goal inside each interval as number of goals / number of shots inside that interval? Then you used some max likehood to fit the curve? However, the number of shots inside each distance interval is different, I’m gussing there were far more shots around 12m than shots around 3m, and probably no shots at 0m, but you would fit a point at (0m,P(goal)=1) for common sense anyway. Does this introduce a bias where some shots are given more weight than others in fitting the curve? So when predicting the total number of goals for a season, this model will be predicting significantly under the actual number of goals? (Because decay constant is too fast due to the heavier weight given to shorter distances)\n\nIs it possible to fit a curve that gives equal weight to each shot? I imagine such a curve is likely to significantly under estimate the probability of scoring from short distances, but will predict season totals more accurately. But the real question is, which curve would predict individual teams’ or even individual matches’ goals more accurately?\n\nMartin Eastwood - July 21, 2014\n\nHi EV,\n\nYes the shots are binned by distance so there will be different numbers of shots per game. One way to investigate whether this causes any biases could be to bin by percentiles instead to normalize the bin sizes. Hopefully the fit of the curve will be stable enough that it wouldn’t really affect the results too much but there is only one way to find out…\n\n## Get In Touch!\n\nSubmit your comments below, and feel free to format them using MarkDown if you want. Comments typically take upto 24 hours to appear on the site and be answered so please be patient.\n\nThanks!" ]
[ null, "http://pena.lt/y/images/20140422_exgp_exp_decay.png", null ]
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https://mk-com.com/determine-equation-of-line-79
[ "## 3.3 Find the Equation of a Line\n\nThe general equation in the point-slope form can be written as: y – y1 = m (x – x1) Where. (x1,\n\n• Do math question\n\nDoing homework can help improve grades.\n\n• Get Help with Homework\n\nGet math help online by speaking to a tutor in a live chat.\n\n• Decide math question\n\n• Get arithmetic help online\n\nIf you're struggling with arithmetic, there's help available online. You can find websites that offer step-by-step explanations of various concepts, as well as online calculators and other tools to help you practice.\n\nThe best way to learn about a new culture is to immerse yourself in it.\n\n• GET HELP INSTANTLY\n\nIf you need help with your homework, our expert writers are here to assist you.", null, "People said", null, "Line Calculator\n\nPoint-Slope Form of the Equation of a Line. In the point-slope form, the equation of a line has slope m and passes through the point (x 1, y 1 ). The equation is given using: y - y1 =\n\nGet mathematics help online\n\nLooking for a little help with your math homework? Check out these online resources for getting mathematics help online.\n\nDecide math equation\n\nIf you're looking for a fun way to teach your kids math, try Decide math. It's a great way to engage them in the subject and help them learn while they're having fun.\n\nFast Delivery\n\nIf you need your order fast, we can deliver it to you in record time.\n\n## Equation of a Straight Line\n\nEquation of a Straight Line Equation of a Straight Line The equation of a straight line is usually written this way: y = mx + b (or y = mx + c in the UK see below) What does it stand for? y = how far up x = how far along m = Slope or Gradient", null, "" ]
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http://learn.e-limu.org/topic/view/?c=216
[ "Area\n\n#### Area is the amount of surface of a shape", null, "When we refer to a solid such as a cube, the amount of surface is called its surface area.\n\nArea is usually measured in the following units:\n\n1. Centimetre square (cm²)\n2. Metre square (m²)\n3. Kilometer square (km²)\n\nIf 1 m = 100 cm then\n\n1m² = 1m x 1 m\n\ntherefore 1m² = 100 cm x 100 cm\n\n= 10 000 cm²\n\nThe following shows how the units of area are related.\n\n1. 10 000 cm² = 1 m²\n2. 10 000 m² = 1 ha\n3. 100 m² = 1 are\n4. 100 are = 1 ha\n5. 100 ha = 1 km²\n\nWe can use the relationships given above to work out the area of specific and combined shapes.\n\nSimilarly we can work out the surface area of solids such as cubes, cuboids and cylinders.\n\n## Let's learn how to calculate area\n\n#### Rectangle", null, "#### Triangle", null, "Circle", null, "Parallelogram", null, "#### Trapezium", null, "#### Can this rectangle become a triangle?", null, "Look at line QP.\n\nIt splits the rectangle into two equal Triangles", null, "That’s why the Area of a Triangle is 1/2 b x h\n\n#### A Circle", null, "Area of a circle is given by:\n\nA = π  ×  r  ×  r\n\nThe line at the center is called Diameter.", null, "Diameter cuts the circle into two equal parts.\n\nEach part is called semi circle.\n\nA semi circle can be divided into two equal parts to form a Quadrant", null, "When diameter is divided into 2, a Radius is formed.\n\nBelow is a song that teaches you more about circles.\n\n#### Example\n\nCalculate the area of the circles below", null, "#### Solution\n\nArea of a circle 1 =Pie  ×  r  × r\n\nPie =`22/7`\n\n= `22/7` × `14/2` cm ×`14/2` cm\n\n=`22/7` × 7cm × 7cm\n\n=22 × 7cm × 1cm\n\n=154cm2\n\nArea of a circle 2 = Pie ×  r  × r\n\nPie =`22/7`\n\n= `22/7 ` × `14/2` cm  × `14/2` cm\n\n=`22/7` × 7cm × 7cm\n\n=22 × 7cm × 1cm\n\n=154cm2\n\nThe two circle have the same areas.\n\nThe first circle has a diameter of 14cm while the second has a radius of 7cm hence a diameter of 14cm\n\nFind the areas of the shaded part of the circle below given that it has a radius of 7cm.", null, "Solution\n\nArea of the whole circle\n\n=`22/7` × 7cm × 7cm\n\n=22 × 1cm × 7cm\n\n= 154cm2\n\nHowever the circle has been divided into 4 equal parts each called a Quadrant\n\nTo get areas of the shaded part divide 154cm2 by 4\n\n= `154/4` cm2\n\n=38.5cm2", null, "#### Parallelogram", null, "The above parallelogram is made up of two right angled triangles and a rectangle.\n\nThe two opposite sides are equal\n\nb=b\n\na=a\n\nThe area of a parallelogram is given by:\n\nBase length  ×  height\n\nFind the area of the shaded regions in the figures below", null, "Area of a parallelogram = base length X height\n\na )                                                                             b)\n\n=9cm × 5cm                                                         =10cm × 4cm\n\n= 45 cm squared                                                     = 40 cm squared\n\n#### Trapezium", null, "The above trapezium is made up of a rectangle and a right angled triangle.\n\nThe area of a Trapezium is given by:\n\n½ h  × sum of the two parallel sides(a+b)\n\nStudy the image below:", null, "What is the area of the shaded region?\n\nRemember\n\nThe area of a Trapezium is given by:\n\n½ h × sum of the two parallel sides(a+b)\n\n½ × 4m × (6m + 8m)\n\n2m × (14m)\n\n=28 metres squared.\n\n1. The area of the figure below is 360m2.\n\nFind the  length of a.", null, "2. The figure below represents a plot of land. What is the area of the plot.", null, "1. 60 m\n\n2. 9000 metres squared\n\nThe figure below shows a circle of radius 7cm touching the vertices of a square.\n\nWhat is the area of the shaded part?", null, "Get the area of the circle A = π r^2\n\n= 3.14 × 7 cm × 7 cm\n\n= 153.86 cm squared\n\nGet the area of the square. The radius gives half the length of the side of the square.\n\nTo get full length= 7cm × 2\n\n=14cm\n\nArea of a square =S × S\n\n=14cm × 14cm\n\n=196cm squared\n\nArea of the shaded part = Area of the circle - Area of the square\n\n= 196cm squared- 153.86cm squared\n\n= 42.14cm squared\n\nFind the area of the shaded part in the figure below\n\nTake pie = 3.14", null, "The shaded part is made up of a semicircle and a right angled triangle", null, "Area of the semicircle = (πr^2)/2\n\n80cm = diameter\n\n= 40cm\n\n3.14 x 40cm x 40cm\n\n=5024 cm2/2\n\n=2512cm squared\n\nArea of the triangle = ½ b  x  h\n\n= ½ x 100cm  x  80cm\n\n=50cm  x  80cm\n\n= 4000cm squared\n\nArea of the shaded part = 2512cm squared+ 4000cm squared\n\n= 6512cm squared\n\nThe image shows a window of a building in Nairobi.\n\nCalculate the area of the window.", null, "#### Solution", null, "Area = area of the rectangle + area of the semicircle\n\nArea of rectangle= l × w\n\n14 m×7 m\n\n=98m2\n\nArea of the semicircle = (πr^2)/2\n\n22/7 ×7 m×7 m\n\n= 154 m2/2\n\n=77 m2\n\nAnswer = 98 m2 + 77 m2\n\n=175 m2\n\n### Sources\n\n• 71cd3aae-e62c-40f6-bd84-3179688e87de by elimu used under CC_BY-SA\n• 23c82f06-c892-4009-9bd5-8b22832fd8e7 by elimu used under CC_BY-SA\n• c980a754-b014-4504-9a44-deda962582e0 by elimu used under CC_BY-SA\n• e56ecb18-9747-40a9-96d9-4eb8e9f6f838 by elimu used under CC_BY-SA\n• 3af72df1-6c80-41f5-a6de-6b951fa4fc5e by elimu used under CC_BY-SA\n• 848862c7-fbb5-41b4-80e1-6ad61ed6bd84 by elimu used under CC_BY-SA\n• d850c7d5-210f-4bc6-b6db-126c7be00f42 by elimu used under CC_BY-SA\n• 641b3946-c602-4ad3-95ff-37aaa8eac7cb by elimu used under CC_BY-SA\n• fa8ba517-d583-4add-b159-f50c07582176 by elimu used under CC_BY-SA\n• 7b732c98-24aa-4fcc-b365-a1229e82b278 by elimu used under CC_BY-SA\n• fec1fd90-a693-424e-955c-e566c62e4848 by elimu used under CC_BY-SA\n• f8752526-1dbd-41a7-80d9-b49aab5aa1f1 by elimu used under CC_BY-SA\n• circle_area_and_cicumference by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• e9986892-b14f-4b77-9a51-bc25796cdc71 by elimu used under CC_BY-SA\n• 540area by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• 1056_area by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• 1057_area by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• 1058_area by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• 1060area by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• 1061_area by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• a by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• b by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• 937fa9fe-5b4c-4c38-8e77-61451fb1570c by elimu used under CC_BY-SA\n• circle_rectangle by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• area_combined_1 by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• window by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n• window_solution by Unknown used under Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License\n\n•", null, "" ]
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https://www.colorhexa.com/0d2d19
[ "# #0d2d19 Color Information\n\nIn a RGB color space, hex #0d2d19 is composed of 5.1% red, 17.6% green and 9.8% blue. Whereas in a CMYK color space, it is composed of 71.1% cyan, 0% magenta, 44.4% yellow and 82.4% black. It has a hue angle of 142.5 degrees, a saturation of 55.2% and a lightness of 11.4%. #0d2d19 color hex could be obtained by blending #1a5a32 with #000000. Closest websafe color is: #003300.\n\n• R 5\n• G 18\n• B 10\nRGB color chart\n• C 71\n• M 0\n• Y 44\n• K 82\nCMYK color chart\n\n#0d2d19 color description : Very dark (mostly black) cyan - lime green.\n\n# #0d2d19 Color Conversion\n\nThe hexadecimal color #0d2d19 has RGB values of R:13, G:45, B:25 and CMYK values of C:0.71, M:0, Y:0.44, K:0.82. Its decimal value is 863513.\n\nHex triplet RGB Decimal 0d2d19 `#0d2d19` 13, 45, 25 `rgb(13,45,25)` 5.1, 17.6, 9.8 `rgb(5.1%,17.6%,9.8%)` 71, 0, 44, 82 142.5°, 55.2, 11.4 `hsl(142.5,55.2%,11.4%)` 142.5°, 71.1, 17.6 003300 `#003300`\nCIE-LAB 15.656, -17.5, 9.529 1.28, 2.032, 1.245 0.281, 0.446, 2.032 15.656, 19.926, 151.432 15.656, -10.918, 9.552 14.256, -8.925, 4.804 00001101, 00101101, 00011001\n\n# Color Schemes with #0d2d19\n\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #2d0d21\n``#2d0d21` `rgb(45,13,33)``\nComplementary Color\n• #112d0d\n``#112d0d` `rgb(17,45,13)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #0d2d29\n``#0d2d29` `rgb(13,45,41)``\nAnalogous Color\n• #2d0d11\n``#2d0d11` `rgb(45,13,17)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #290d2d\n``#290d2d` `rgb(41,13,45)``\nSplit Complementary Color\n• #2d190d\n``#2d190d` `rgb(45,25,13)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #190d2d\n``#190d2d` `rgb(25,13,45)``\nTriadic Color\n• #212d0d\n``#212d0d` `rgb(33,45,13)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #190d2d\n``#190d2d` `rgb(25,13,45)``\n• #2d0d21\n``#2d0d21` `rgb(45,13,33)``\nTetradic Color\n• #000000\n``#000000` `rgb(0,0,0)``\n• #020503\n``#020503` `rgb(2,5,3)``\n• #07190e\n``#07190e` `rgb(7,25,14)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #134124\n``#134124` `rgb(19,65,36)``\n• #18552f\n``#18552f` `rgb(24,85,47)``\n• #1e683a\n``#1e683a` `rgb(30,104,58)``\nMonochromatic Color\n\n# Alternatives to #0d2d19\n\nBelow, you can see some colors close to #0d2d19. Having a set of related colors can be useful if you need an inspirational alternative to your original color choice.\n\n• #0d2d11\n``#0d2d11` `rgb(13,45,17)``\n• #0d2d14\n``#0d2d14` `rgb(13,45,20)``\n• #0d2d16\n``#0d2d16` `rgb(13,45,22)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #0d2d1c\n``#0d2d1c` `rgb(13,45,28)``\n• #0d2d1e\n``#0d2d1e` `rgb(13,45,30)``\n• #0d2d21\n``#0d2d21` `rgb(13,45,33)``\nSimilar Colors\n\n# #0d2d19 Preview\n\nText with hexadecimal color #0d2d19\n\nThis text has a font color of #0d2d19.\n\n``<span style=\"color:#0d2d19;\">Text here</span>``\n#0d2d19 background color\n\nThis paragraph has a background color of #0d2d19.\n\n``<p style=\"background-color:#0d2d19;\">Content here</p>``\n#0d2d19 border color\n\nThis element has a border color of #0d2d19.\n\n``<div style=\"border:1px solid #0d2d19;\">Content here</div>``\nCSS codes\n``.text {color:#0d2d19;}``\n``.background {background-color:#0d2d19;}``\n``.border {border:1px solid #0d2d19;}``\n\n# Shades and Tints of #0d2d19\n\nA shade is achieved by adding black to any pure hue, while a tint is created by mixing white to any pure color. In this example, #040f08 is the darkest color, while #feffff is the lightest one.\n\n• #040f08\n``#040f08` `rgb(4,15,8)``\n• #091e11\n``#091e11` `rgb(9,30,17)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #113c21\n``#113c21` `rgb(17,60,33)``\n• #164b2a\n``#164b2a` `rgb(22,75,42)``\n• #1a5b32\n``#1a5b32` `rgb(26,91,50)``\n• #1f6a3b\n``#1f6a3b` `rgb(31,106,59)``\n• #237943\n``#237943` `rgb(35,121,67)``\n• #27884c\n``#27884c` `rgb(39,136,76)``\n• #2c9854\n``#2c9854` `rgb(44,152,84)``\n• #30a75d\n``#30a75d` `rgb(48,167,93)``\n• #35b665\n``#35b665` `rgb(53,182,101)``\n• #39c56e\n``#39c56e` `rgb(57,197,110)``\nShade Color Variation\n• #48ca79\n``#48ca79` `rgb(72,202,121)``\n• #57ce84\n``#57ce84` `rgb(87,206,132)``\n• #66d38f\n``#66d38f` `rgb(102,211,143)``\n• #75d79a\n``#75d79a` `rgb(117,215,154)``\n• #85dca5\n``#85dca5` `rgb(133,220,165)``\n• #94e0b0\n``#94e0b0` `rgb(148,224,176)``\n• #a3e4bc\n``#a3e4bc` `rgb(163,228,188)``\n• #b2e9c7\n``#b2e9c7` `rgb(178,233,199)``\n• #c1edd2\n``#c1edd2` `rgb(193,237,210)``\n• #d1f2dd\n``#d1f2dd` `rgb(209,242,221)``\n• #e0f6e8\n``#e0f6e8` `rgb(224,246,232)``\n• #effaf3\n``#effaf3` `rgb(239,250,243)``\n• #feffff\n``#feffff` `rgb(254,255,255)``\nTint Color Variation\n\n# Tones of #0d2d19\n\nA tone is produced by adding gray to any pure hue. In this case, #1d1d1d is the less saturated color, while #023816 is the most saturated one.\n\n• #1d1d1d\n``#1d1d1d` `rgb(29,29,29)``\n• #1a201c\n``#1a201c` `rgb(26,32,28)``\n• #18221c\n``#18221c` `rgb(24,34,28)``\n• #16241b\n``#16241b` `rgb(22,36,27)``\n• #14261b\n``#14261b` `rgb(20,38,27)``\n• #11291a\n``#11291a` `rgb(17,41,26)``\n• #0f2b1a\n``#0f2b1a` `rgb(15,43,26)``\n• #0d2d19\n``#0d2d19` `rgb(13,45,25)``\n• #0b2f18\n``#0b2f18` `rgb(11,47,24)``\n• #093118\n``#093118` `rgb(9,49,24)``\n• #063417\n``#063417` `rgb(6,52,23)``\n• #043617\n``#043617` `rgb(4,54,23)``\n• #023816\n``#023816` `rgb(2,56,22)``\nTone Color Variation\n\n# Color Blindness Simulator\n\nBelow, you can see how #0d2d19 is perceived by people affected by a color vision deficiency. This can be useful if you need to ensure your color combinations are accessible to color-blind users.\n\nMonochromacy\n• Achromatopsia 0.005% of the population\n• Atypical Achromatopsia 0.001% of the population\nDichromacy\n• Protanopia 1% of men\n• Deuteranopia 1% of men\n• Tritanopia 0.001% of the population\nTrichromacy\n• Protanomaly 1% of men, 0.01% of women\n• Deuteranomaly 6% of men, 0.4% of women\n• Tritanomaly 0.01% of the population" ]
[ null ]
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http://businessforecastblog.com/quantile-regression/
[ "", null, "Quantile Regression\n\nThere’s a straight-forward way to understand the value and potential significance of quantile regression – consider the hurricane data referenced in James Elsner’s blog Hurricane & Tornado Climate.\n\nHere is a plot of average windspeed of hurricanes in the Atlantic and Gulf Coast since satellite observations began after 1977.", null, "Based on averages, the linear trend line increases about 2 miles per hour over this approximately 30 year period.\n\nAn 80th percentile quantile regression trend line, on the other hand, with this data indicates that the trend in the more violent hurricanes shows an about 15 mph increase over this same period.", null, "In other words, if we look at the hurricanes which are in the 80th percentile or more, there is a much stronger trend in maximum wind speeds, than in the average for all US-related hurricanes in this period.\n\nA quantile q, 0<q<1, splits the data into proportions q below and 1-q above. The most familiar quantile, thus, may be the 50th percentile which is the quantile which splits the data at the median – 50 percent below and 50 percent above.\n\nQuantile regression (QR) was developed, in its modern incarnation by Koenker and Basset in 1978. QR is less influenced by non-normal errors and outliers, and provides a richer characterization of the data.\n\nThus, QR encourages considering the impact of a covariate on the entire distribution of y, not just is conditional mean.\n\nRoger Koenker and Kevin F. Hallock’s Quantile Regression in the Journal of Economic Perspectives 2001 is a standard reference.\n\nWe say that a student scores at the tth quantile of a standardized exam if he performs better than the proportion t of the reference group of students and worse than the proportion (1–t). Thus, half of students perform better than the median student and half perform worse. Similarly, the quartiles divide the population into four segments with equal proportions of the reference population in each segment. The quintiles divide the population into five parts; the deciles into ten parts. The quantiles, or percentiles, or occasionally fractiles, refer to the general case.\n\nJust as we can define the sample mean as the solution to the problem of minimizing a sum of squared residuals, we can define the median as the solution to the problem of minimizing a sum of absolute residuals.\n\nOrdinary least squares (OLS) regression minimizes the sum of squared errors of observations minus estimates. This minimization leads to explicit equations for regression parameters, given standard assumptions.\n\nQuantile regression, on the other hand, minimizes weighted sums of absolute deviations of observations on a quantile minus estimates. This minimization problem is solved by the simplex method of linear programming, rather than differential calculus. The solution is robust to departures from normality of the error process and outliers.\n\nKoenker’s webpage is a valuable resource with directions for available software to estimate QR. I utilized Mathworks Matlab for my estimate of a QR with the hurricane data, along with a supplemental program for quantreg(.) I downloaded from their site.\n\nHere are a couple of short, helpful videos from Econometrics Academy." ]
[ null, "http://businessforecastblog.com/wp-content/uploads/2014/02/HURRICANE-SANDY-1038x576.jpg", null, "http://businessforecastblog.com/wp-content/uploads/2014/02/HurricaneAvgWS-1024x741.png", null, "http://businessforecastblog.com/wp-content/uploads/2014/02/HurricaneQuartileReg-1024x552.png", null ]
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https://www.gradesaver.com/textbooks/math/algebra/algebra-and-trigonometry-10th-edition/chapter-11-cumulative-test-for-chapters-9-11-page-845/34
[ "## Algebra and Trigonometry 10th Edition\n\n$_{14}P_3=2184$\n$_{14}P_3=\\frac{14!}{(14-3)!}=\\frac{14\\times13\\times12\\times11!}{11!}=2184$" ]
[ null ]
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https://gem5.googlesource.com/arm/linux/+/a524c1eea084def85e1122b64beda9bb3aca0e49/drivers/thermal/devfreq_cooling.c
[ "blob: ef59256887ff63d04db5efc08a4f082a68bb75b8 [file] [log] [blame]\n /* * devfreq_cooling: Thermal cooling device implementation for devices using * devfreq * * Copyright (C) 2014-2015 ARM Limited * * This program is free software; you can redistribute it and/or modify * it under the terms of the GNU General Public License version 2 as * published by the Free Software Foundation. * * This program is distributed \"as is\" WITHOUT ANY WARRANTY of any * kind, whether express or implied; without even the implied warranty * of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * TODO: * - If OPPs are added or removed after devfreq cooling has * registered, the devfreq cooling won't react to it. */ #include #include #include #include #include #include #include #include #define SCALE_ERROR_MITIGATION 100 static DEFINE_IDA(devfreq_ida); /** * struct devfreq_cooling_device - Devfreq cooling device * @id: unique integer value corresponding to each * devfreq_cooling_device registered. * @cdev: Pointer to associated thermal cooling device. * @devfreq: Pointer to associated devfreq device. * @cooling_state: Current cooling state. * @power_table: Pointer to table with maximum power draw for each * cooling state. State is the index into the table, and * the power is in mW. * @freq_table: Pointer to a table with the frequencies sorted in descending * order. You can index the table by cooling device state * @freq_table_size: Size of the @freq_table and @power_table * @power_ops: Pointer to devfreq_cooling_power, used to generate the * @power_table. * @res_util: Resource utilization scaling factor for the power. * It is multiplied by 100 to minimize the error. It is used * for estimation of the power budget instead of using * 'utilization' (which is 'busy_time / 'total_time'). * The 'res_util' range is from 100 to (power_table[state] * 100) * for the corresponding 'state'. */ struct devfreq_cooling_device { int id; struct thermal_cooling_device *cdev; struct devfreq *devfreq; unsigned long cooling_state; u32 *power_table; u32 *freq_table; size_t freq_table_size; struct devfreq_cooling_power *power_ops; u32 res_util; int capped_state; }; /** * partition_enable_opps() - disable all opps above a given state * @dfc: Pointer to devfreq we are operating on * @cdev_state: cooling device state we're setting * * Go through the OPPs of the device, enabling all OPPs until * @cdev_state and disabling those frequencies above it. */ static int partition_enable_opps(struct devfreq_cooling_device *dfc, unsigned long cdev_state) { int i; struct device *dev = dfc->devfreq->dev.parent; for (i = 0; i < dfc->freq_table_size; i++) { struct dev_pm_opp *opp; int ret = 0; unsigned int freq = dfc->freq_table[i]; bool want_enable = i >= cdev_state ? true : false; opp = dev_pm_opp_find_freq_exact(dev, freq, !want_enable); if (PTR_ERR(opp) == -ERANGE) continue; else if (IS_ERR(opp)) return PTR_ERR(opp); dev_pm_opp_put(opp); if (want_enable) ret = dev_pm_opp_enable(dev, freq); else ret = dev_pm_opp_disable(dev, freq); if (ret) return ret; } return 0; } static int devfreq_cooling_get_max_state(struct thermal_cooling_device *cdev, unsigned long *state) { struct devfreq_cooling_device *dfc = cdev->devdata; *state = dfc->freq_table_size - 1; return 0; } static int devfreq_cooling_get_cur_state(struct thermal_cooling_device *cdev, unsigned long *state) { struct devfreq_cooling_device *dfc = cdev->devdata; *state = dfc->cooling_state; return 0; } static int devfreq_cooling_set_cur_state(struct thermal_cooling_device *cdev, unsigned long state) { struct devfreq_cooling_device *dfc = cdev->devdata; struct devfreq *df = dfc->devfreq; struct device *dev = df->dev.parent; int ret; if (state == dfc->cooling_state) return 0; dev_dbg(dev, \"Setting cooling state %lu\\n\", state); if (state >= dfc->freq_table_size) return -EINVAL; ret = partition_enable_opps(dfc, state); if (ret) return ret; dfc->cooling_state = state; return 0; } /** * freq_get_state() - get the cooling state corresponding to a frequency * @dfc: Pointer to devfreq cooling device * @freq: frequency in Hz * * Return: the cooling state associated with the @freq, or * THERMAL_CSTATE_INVALID if it wasn't found. */ static unsigned long freq_get_state(struct devfreq_cooling_device *dfc, unsigned long freq) { int i; for (i = 0; i < dfc->freq_table_size; i++) { if (dfc->freq_table[i] == freq) return i; } return THERMAL_CSTATE_INVALID; } static unsigned long get_voltage(struct devfreq *df, unsigned long freq) { struct device *dev = df->dev.parent; unsigned long voltage; struct dev_pm_opp *opp; opp = dev_pm_opp_find_freq_exact(dev, freq, true); if (PTR_ERR(opp) == -ERANGE) opp = dev_pm_opp_find_freq_exact(dev, freq, false); if (IS_ERR(opp)) { dev_err_ratelimited(dev, \"Failed to find OPP for frequency %lu: %ld\\n\", freq, PTR_ERR(opp)); return 0; } voltage = dev_pm_opp_get_voltage(opp) / 1000; /* mV */ dev_pm_opp_put(opp); if (voltage == 0) { dev_err_ratelimited(dev, \"Failed to get voltage for frequency %lu\\n\", freq); } return voltage; } /** * get_static_power() - calculate the static power * @dfc: Pointer to devfreq cooling device * @freq: Frequency in Hz * * Calculate the static power in milliwatts using the supplied * get_static_power(). The current voltage is calculated using the * OPP library. If no get_static_power() was supplied, assume the * static power is negligible. */ static unsigned long get_static_power(struct devfreq_cooling_device *dfc, unsigned long freq) { struct devfreq *df = dfc->devfreq; unsigned long voltage; if (!dfc->power_ops->get_static_power) return 0; voltage = get_voltage(df, freq); if (voltage == 0) return 0; return dfc->power_ops->get_static_power(df, voltage); } /** * get_dynamic_power - calculate the dynamic power * @dfc: Pointer to devfreq cooling device * @freq: Frequency in Hz * @voltage: Voltage in millivolts * * Calculate the dynamic power in milliwatts consumed by the device at * frequency @freq and voltage @voltage. If the get_dynamic_power() * was supplied as part of the devfreq_cooling_power struct, then that * function is used. Otherwise, a simple power model (Pdyn = Coeff * * Voltage^2 * Frequency) is used. */ static unsigned long get_dynamic_power(struct devfreq_cooling_device *dfc, unsigned long freq, unsigned long voltage) { u64 power; u32 freq_mhz; struct devfreq_cooling_power *dfc_power = dfc->power_ops; if (dfc_power->get_dynamic_power) return dfc_power->get_dynamic_power(dfc->devfreq, freq, voltage); freq_mhz = freq / 1000000; power = (u64)dfc_power->dyn_power_coeff * freq_mhz * voltage * voltage; do_div(power, 1000000000); return power; } static inline unsigned long get_total_power(struct devfreq_cooling_device *dfc, unsigned long freq, unsigned long voltage) { return get_static_power(dfc, freq) + get_dynamic_power(dfc, freq, voltage); } static int devfreq_cooling_get_requested_power(struct thermal_cooling_device *cdev, struct thermal_zone_device *tz, u32 *power) { struct devfreq_cooling_device *dfc = cdev->devdata; struct devfreq *df = dfc->devfreq; struct devfreq_dev_status *status = &df->last_status; unsigned long state; unsigned long freq = status->current_frequency; unsigned long voltage; u32 dyn_power = 0; u32 static_power = 0; int res; state = freq_get_state(dfc, freq); if (state == THERMAL_CSTATE_INVALID) { res = -EAGAIN; goto fail; } if (dfc->power_ops->get_real_power) { voltage = get_voltage(df, freq); if (voltage == 0) { res = -EINVAL; goto fail; } res = dfc->power_ops->get_real_power(df, power, freq, voltage); if (!res) { state = dfc->capped_state; dfc->res_util = dfc->power_table[state]; dfc->res_util *= SCALE_ERROR_MITIGATION; if (*power > 1) dfc->res_util /= *power; } else { goto fail; } } else { dyn_power = dfc->power_table[state]; /* Scale dynamic power for utilization */ dyn_power *= status->busy_time; dyn_power /= status->total_time; /* Get static power */ static_power = get_static_power(dfc, freq); *power = dyn_power + static_power; } trace_thermal_power_devfreq_get_power(cdev, status, freq, dyn_power, static_power, *power); return 0; fail: /* It is safe to set max in this case */ dfc->res_util = SCALE_ERROR_MITIGATION; return res; } static int devfreq_cooling_state2power(struct thermal_cooling_device *cdev, struct thermal_zone_device *tz, unsigned long state, u32 *power) { struct devfreq_cooling_device *dfc = cdev->devdata; unsigned long freq; u32 static_power; if (state >= dfc->freq_table_size) return -EINVAL; freq = dfc->freq_table[state]; static_power = get_static_power(dfc, freq); *power = dfc->power_table[state] + static_power; return 0; } static int devfreq_cooling_power2state(struct thermal_cooling_device *cdev, struct thermal_zone_device *tz, u32 power, unsigned long *state) { struct devfreq_cooling_device *dfc = cdev->devdata; struct devfreq *df = dfc->devfreq; struct devfreq_dev_status *status = &df->last_status; unsigned long freq = status->current_frequency; unsigned long busy_time; s32 dyn_power; u32 static_power; s32 est_power; int i; if (dfc->power_ops->get_real_power) { /* Scale for resource utilization */ est_power = power * dfc->res_util; est_power /= SCALE_ERROR_MITIGATION; } else { static_power = get_static_power(dfc, freq); dyn_power = power - static_power; dyn_power = dyn_power > 0 ? dyn_power : 0; /* Scale dynamic power for utilization */ busy_time = status->busy_time ?: 1; est_power = (dyn_power * status->total_time) / busy_time; } /* * Find the first cooling state that is within the power * budget for dynamic power. */ for (i = 0; i < dfc->freq_table_size - 1; i++) if (est_power >= dfc->power_table[i]) break; *state = i; dfc->capped_state = i; trace_thermal_power_devfreq_limit(cdev, freq, *state, power); return 0; } static struct thermal_cooling_device_ops devfreq_cooling_ops = { .get_max_state = devfreq_cooling_get_max_state, .get_cur_state = devfreq_cooling_get_cur_state, .set_cur_state = devfreq_cooling_set_cur_state, }; /** * devfreq_cooling_gen_tables() - Generate power and freq tables. * @dfc: Pointer to devfreq cooling device. * * Generate power and frequency tables: the power table hold the * device's maximum power usage at each cooling state (OPP). The * static and dynamic power using the appropriate voltage and * frequency for the state, is acquired from the struct * devfreq_cooling_power, and summed to make the maximum power draw. * * The frequency table holds the frequencies in descending order. * That way its indexed by cooling device state. * * The tables are malloced, and pointers put in dfc. They must be * freed when unregistering the devfreq cooling device. * * Return: 0 on success, negative error code on failure. */ static int devfreq_cooling_gen_tables(struct devfreq_cooling_device *dfc) { struct devfreq *df = dfc->devfreq; struct device *dev = df->dev.parent; int ret, num_opps; unsigned long freq; u32 *power_table = NULL; u32 *freq_table; int i; num_opps = dev_pm_opp_get_opp_count(dev); if (dfc->power_ops) { power_table = kcalloc(num_opps, sizeof(*power_table), GFP_KERNEL); if (!power_table) return -ENOMEM; } freq_table = kcalloc(num_opps, sizeof(*freq_table), GFP_KERNEL); if (!freq_table) { ret = -ENOMEM; goto free_power_table; } for (i = 0, freq = ULONG_MAX; i < num_opps; i++, freq--) { unsigned long power, voltage; struct dev_pm_opp *opp; opp = dev_pm_opp_find_freq_floor(dev, &freq); if (IS_ERR(opp)) { ret = PTR_ERR(opp); goto free_tables; } voltage = dev_pm_opp_get_voltage(opp) / 1000; /* mV */ dev_pm_opp_put(opp); if (dfc->power_ops) { if (dfc->power_ops->get_real_power) power = get_total_power(dfc, freq, voltage); else power = get_dynamic_power(dfc, freq, voltage); dev_dbg(dev, \"Power table: %lu MHz @ %lu mV: %lu = %lu mW\\n\", freq / 1000000, voltage, power, power); power_table[i] = power; } freq_table[i] = freq; } if (dfc->power_ops) dfc->power_table = power_table; dfc->freq_table = freq_table; dfc->freq_table_size = num_opps; return 0; free_tables: kfree(freq_table); free_power_table: kfree(power_table); return ret; } /** * of_devfreq_cooling_register_power() - Register devfreq cooling device, * with OF and power information. * @np: Pointer to OF device_node. * @df: Pointer to devfreq device. * @dfc_power: Pointer to devfreq_cooling_power. * * Register a devfreq cooling device. The available OPPs must be * registered on the device. * * If @dfc_power is provided, the cooling device is registered with the * power extensions. For the power extensions to work correctly, * devfreq should use the simple_ondemand governor, other governors * are not currently supported. */ struct thermal_cooling_device * of_devfreq_cooling_register_power(struct device_node *np, struct devfreq *df, struct devfreq_cooling_power *dfc_power) { struct thermal_cooling_device *cdev; struct devfreq_cooling_device *dfc; char dev_name[THERMAL_NAME_LENGTH]; int err; dfc = kzalloc(sizeof(*dfc), GFP_KERNEL); if (!dfc) return ERR_PTR(-ENOMEM); dfc->devfreq = df; if (dfc_power) { dfc->power_ops = dfc_power; devfreq_cooling_ops.get_requested_power = devfreq_cooling_get_requested_power; devfreq_cooling_ops.state2power = devfreq_cooling_state2power; devfreq_cooling_ops.power2state = devfreq_cooling_power2state; } err = devfreq_cooling_gen_tables(dfc); if (err) goto free_dfc; err = ida_simple_get(&devfreq_ida, 0, 0, GFP_KERNEL); if (err < 0) goto free_tables; dfc->id = err; snprintf(dev_name, sizeof(dev_name), \"thermal-devfreq-%d\", dfc->id); cdev = thermal_of_cooling_device_register(np, dev_name, dfc, &devfreq_cooling_ops); if (IS_ERR(cdev)) { err = PTR_ERR(cdev); dev_err(df->dev.parent, \"Failed to register devfreq cooling device (%d)\\n\", err); goto release_ida; } dfc->cdev = cdev; return cdev; release_ida: ida_simple_remove(&devfreq_ida, dfc->id); free_tables: kfree(dfc->power_table); kfree(dfc->freq_table); free_dfc: kfree(dfc); return ERR_PTR(err); } EXPORT_SYMBOL_GPL(of_devfreq_cooling_register_power); /** * of_devfreq_cooling_register() - Register devfreq cooling device, * with OF information. * @np: Pointer to OF device_node. * @df: Pointer to devfreq device. */ struct thermal_cooling_device * of_devfreq_cooling_register(struct device_node *np, struct devfreq *df) { return of_devfreq_cooling_register_power(np, df, NULL); } EXPORT_SYMBOL_GPL(of_devfreq_cooling_register); /** * devfreq_cooling_register() - Register devfreq cooling device. * @df: Pointer to devfreq device. */ struct thermal_cooling_device *devfreq_cooling_register(struct devfreq *df) { return of_devfreq_cooling_register(NULL, df); } EXPORT_SYMBOL_GPL(devfreq_cooling_register); /** * devfreq_cooling_unregister() - Unregister devfreq cooling device. * @dfc: Pointer to devfreq cooling device to unregister. */ void devfreq_cooling_unregister(struct thermal_cooling_device *cdev) { struct devfreq_cooling_device *dfc; if (!cdev) return; dfc = cdev->devdata; thermal_cooling_device_unregister(dfc->cdev); ida_simple_remove(&devfreq_ida, dfc->id); kfree(dfc->power_table); kfree(dfc->freq_table); kfree(dfc); } EXPORT_SYMBOL_GPL(devfreq_cooling_unregister);" ]
[ null ]
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https://www.codingeek.com/data-structure/binary-tree-introduction-explanation-and-implementation/
[ "Binary Tree – Introduction, Explanation and Implementation\n\nA specialized form of tree data structure in which each node can have at most two children, such a tree is referred as a Binary Tree.\n\nThe Topmost node is called root node. The two children are referred as Left and Right child. The node with no child is referred as leaf node.\n\nIn above image, 2, 5 and 8 are the roots of their respective trees and 79, 20, and (68, 50, 10) are leaves respectively.\n\nTypes of Binary Tree:\n\nBinary tree can be classified based on its structure,\n\n1. Complete binary tree, if all the levels are completely filled except possibly the last level and the nodes in the last level are as left as possible. In other words, a binary tree where nodes are filled like left to right at each depth(top to down).\n\n2. Full binary tree, All the nodes in such a binary tree possesses either 0 or 2 children.\n\n3. Perfect binary tree\n• It must be a Full binary tree\n• All the leaves must be at the same level\n\nNote:-\n\n•  Full binary tree and Perfect binary tree, have no any standard definition. The aforementioned definition is more widely preferred.\n• There are some lesser known types also such as incomplete binary tree, strict binary tree, almost complete binary tree, degenerate tree etc.\n\nImplementation:\n\n1. For full binary tree and complete binary tree, array is used.\nSee below, an array binTree[] of size 7 is created, each node of the shown binary tree is stored as root at index 0, left child of root at index 1 and so on. If the parent is at index i then left and right child at 2i and 2i+1 respectively.\n\n2. Pointer based implementation,\nUnder this, a node is created like we do for the linked list. There will be a structure that contains a key,  a pointer to the left subtree and a pointer to the right subtree.\n\nstruct node {\nint key;\nstruct node *left;\nstruct node *right;\n};\n\nOperation on Binary Tree:\n\nThe same known operation Insertion, Deletion, Searching, Traversal and some others are applied to the binary tree.\nHowsoever, a binary tree is implemented with modification to have a more optimized operation. Binary Search Tree(BST), Balanced BST are some of the modified binary trees.\nThus, operations on binary tree are more emphasized on BST and Balanced BST rather than plainly applying on it.\n\nProperties:\n\nQ1) What are the maximum number of nodes in a binary tree of height h(that is a perfect binary tree)?\nAns) For height h – maximum number of noder are 2(h+1) -1, where height of the leaf node is zero\n\nQ2) What is the relationship between leaf node and an internal node?\nAns) In a binary tree, the number of leaf node is always one more than the number of internal nodes with two children.\n\nQ3) What is the height of a complete binary tree?\nAns) Height of tree = ⌊logn⌋, where n is the total number of nodes\n\nQ4) What is the number of internal nodes in a tree?\nAns) Internal nodes = ⌊(n/2)⌋ + 1 to n, where n is the total number of nodes\n\nApplications:\n\n• Heap tree, used to implement priority queue, and in dynamic memory allocation\n• Huffman coding used in compression/decompression\n• Syntax tree(compiler)\n\nKnowledge is most useful when liberated and shared. Share this to motivate us to keep writing such online tutorials for free and do comment if anything is missing or wrong or you need any kind of help.\nKeep Learning… Happy Learning.. 🙂" ]
[ null ]
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https://gmatclub.com/forum/the-price-of-a-certain-commodity-increased-at-a-rate-of-126464.html
[ "GMAT Question of the Day - Daily to your Mailbox; hard ones only\n\n It is currently 14 Oct 2019, 07:05", null, "GMAT Club Daily Prep\n\nThank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.\n\nCustomized\nfor You\n\nwe will pick new questions that match your level based on your Timer History\n\nTrack\n\nevery week, we’ll send you an estimated GMAT score based on your performance\n\nPractice\nPays\n\nwe will pick new questions that match your level based on your Timer History\n\nNot interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.", null, "", null, "The price of a certain commodity increased at a rate of\n\n new topic post reply Question banks Downloads My Bookmarks Reviews Important topics\nAuthor Message\nTAGS:\n\nHide Tags\n\nManager", null, "", null, "Status: D-Day is on February 10th. and I am not stressed\nAffiliations: American Management association, American Association of financial accountants\nJoined: 12 Apr 2011\nPosts: 158\nLocation: Kuwait\nSchools: Columbia university\nThe price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\n1\n10", null, "00:00\n\nDifficulty:", null, "", null, "", null, "55% (hard)\n\nQuestion Stats:", null, "67% (02:30) correct", null, "33% (03:01) wrong", null, "based on 123 sessions\n\nHideShow timer Statistics\n\nThe price of a certain commodity increased at a rate of $$X$$ % per year between 2000 and 2004. If the price was $$M$$ dollars in 2001 and $$N$$ dollars in 2003, what was the price in 2002 in terms of $$M$$ and $$N$$ ?\n\nA. $$\\sqrt{MN}$$\n\nB. $$N\\sqrt{\\frac{N}{M}}$$\n\nC. $$N\\sqrt{M}$$\n\nD. $$N\\frac{M}{\\sqrt{N}}$$\n\nE. $$NM^{\\frac{3}{2}}$$\n\n_________________\nSky is the limit\n\nOriginally posted by manalq8 on 23 Jan 2012, 14:25.\nLast edited by Bunuel on 05 Apr 2019, 06:19, edited 4 times in total.\nEdited the answer choices\nMagoosh GMAT Instructor", null, "G\nJoined: 28 Dec 2011\nPosts: 4473\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\n6\n1\nHi there! I'm happy to help with this!", null, "Let's say, the price in 2000 is A. That the original amount. Each year it increases X%. To represent a percent increase (a) write the percent as a fraction/decimal, here X/100; (b) add one ---> 1 + X/100; (c) that's the multiplier -- multiplying a number by that multiplier results in a X% increase.\n\nprice in 2000 = A\nprice in 2001 = A*(1 + X/100)\nprice in 2002 = A*(1 + X/100)^2\nprice in 2003 = A*(1 + X/100)^3\nprice in 2004 = A*(1 + X/100)^4\n\nFor simplicity, I am going to define r = (1 + X/100). Then these equations become:\n\nprice in 2000 = A\nprice in 2001 = A*r\nprice in 2002 = A*r^2\nprice in 2003 = A*r^3\nprice in 2004 = A*r^4\n\nNow, suppose we have M = 2001 price = A*r and N = 2003 price = A*r^3. How do we represent the 2002 prince (A*r^2) in terms of M and N?\n\nThere are two methods.\n\nMethod One: express r in terms of M and N\n\nThis is more a crank-it-out algebraic solution approach. We notice that N/M = (A*r^3)/(A*r) = r^2, so r = sqrt(N/M). Well,\n\n2002 price = (2001 price)*(r) = M * sqrt(N/M) = [sqrt(M)*sqrt(M)]*[sqrt(N)/sqrt(M)] = sqrt(M)*sqrt(N) = sqrt(NM).\n\nThrough some fast-and-loose manipulation of the laws of squareroots, we arrive at answer .\n\nMethod Two: a more elegant solution for a more civilized age . . .\n\nWhen you have an arithmetic sequence --- that is, adding the same number to get new terms (e.g. 8, 11, 14, 17, 20, 23, . . . ), when you take any three numbers in a row, the middle number is the mean, the arithmetic average, of the outer two. For example ---11, 14, 17 --- (11 + 17)/2 = 14. The arithmetic average is the ordinary average --- add the two numbers, and divide by two.\n\nWhen you have a geometric sequence -- that is, multiplying the same ratio to get new terms (e.g. 2, 6, 18, 54, 162, . . . ), when you take any three numbers in a row, the middle number is the geometric mean of the outer two. The geometric mean of two numbers means multiply the two numbers and take the squareroot. For example --- 6, 18, 54 --- 6*54 = 324, and sqrt(324) = 18.\n\nWhen you apply a fixed percentage increase from one term to the next, as we have in this problem, that's a geometric sequence. Thus, to find the 2002 price, all you have to do is take the geometric mean of the 2001 price and the 2003 price. 2002 price = sqrt(MN). Bam. Done. Again, answer = .\n\nThe ideas about arithmetic & geometric sequences, and the associated means, are good tricks to have up your sleeve for the more challenging GMAT math problems.\n\nDoes all this make sense? Please let me know if you have any questions.\n\nMike", null, "_________________\nMike McGarry\nMagoosh Test Prep\n\nEducation is not the filling of a pail, but the lighting of a fire. — William Butler Yeats (1865 – 1939)\nIntern", null, "", null, "Joined: 23 Jan 2012\nPosts: 7\nLocation: India\nConcentration: Strategy, Finance\nGMAT 1: 620 Q51 V23", null, "GPA: 3.29\nWE: Engineering (Other)\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\n5\n2\nThe price in 2001 is M\nThe price in 2002 is M(1+$$\\frac{X}{100}$$) ----------------------(1)\n\nThe price in 2003 is M(1+$$\\frac{X}{100}$$)(1+$$\\frac{X}{100}$$) = N ---------(2)\n\nSolving equation (2) we get\n(1+$$\\frac{X}{100}$$) = $$\\sqrt{\\frac{N}{M}}$$\n\nPutting this value in equation (1) to get the desired answer\nThe price in 2002 is M$$\\sqrt{\\frac{N}{M}}$$ = $$\\sqrt{MN}$$\n\nHence the option A\nGeneral Discussion\nMath Expert", null, "V\nJoined: 02 Sep 2009\nPosts: 58310\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\n1\n1\nmanalq8 wrote:\nThe price of a certain commodity increased at a rate of $$X$$ % per year between 2000 and 2004. If the price was $$M$$ dollars in 2001 and $$N$$ dollars in 2003, what was the price in 2002 in terms of $$M$$ and $$N$$ ?\n\nA. $$\\sqrt{MN}$$\n\nB. $$N\\sqrt{\\frac{N}{M}}$$\n\nC. $$N\\sqrt{M}$$\n\nD. $$N\\frac{M}{\\sqrt{N}}$$\n\nE. $$NM^{\\frac{3}{2}}$$\n\nI think that plug-in method is easiest for this problem.\n\nLet the price in 2001 be 100 and the annual rate be 10%. Then:\n2001 = 100 = M;\n2002 = 110;\n2003 = 121 = N;\n\nNow, plug 100 and 121 in the answer choices to see which one gives 110:\nA. $$\\sqrt{MN}=\\sqrt{100*121}=10*11=110$$, correct answer right away.\n\nP.S. For plug-in method it might happen that for some particular numbers more than one option may give \"correct\" answer. In this case just pick some other numbers and check again these \"correct\" options only.\n\nHope it helps.\n_________________\nManager", null, "", null, "Joined: 04 Oct 2013\nPosts: 150\nLocation: India\nGMAT Date: 05-23-2015\nGPA: 3.45\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\nThe price of a certain commodity increased at a rate of X % per year between 2000 and 2004. If the price was M dollars in 2001 and N dollars in 2003, what was the price in 2002 in terms of M and N ?\n\nGiven:\nPrice in 2001 : M\nPrice in 2003 : N\nRate per year: X %\n\nPrice in 2002 $$= M ( 1 + X/100)$$........................................(1)\nAnd, Price in 2003: $$N = M( 1 + X/100)^2$$\n\nOr, $$(1 + x/100) =\\sqrt{(N/M)}$$........(2)\n\nSubstituting the value of (2) in (1) above,\nPrice in 2002 $$= M \\sqrt{(N/M)} = \\sqrt{MN}$$\n\nSenior Manager", null, "", null, "G\nJoined: 03 Apr 2013\nPosts: 264\nLocation: India\nConcentration: Marketing, Finance\nGMAT 1: 740 Q50 V41", null, "GPA: 3\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\nmanalq8 wrote:\nThe price of a certain commodity increased at a rate of $$X$$ % per year between 2000 and 2004. If the price was $$M$$ dollars in 2001 and $$N$$ dollars in 2003, what was the price in 2002 in terms of $$M$$ and $$N$$ ?\n\nA. $$\\sqrt{MN}$$\n\nB. $$N\\sqrt{\\frac{N}{M}}$$\n\nC. $$N\\sqrt{M}$$\n\nD. $$N\\frac{M}{\\sqrt{N}}$$\n\nE. $$NM^{\\frac{3}{2}}$$\n\nWhen no absolute values(or variables pertaining to them) are given, number plugging is the way to go..\n\nLet the Value initially be = 1\nand let X% = 100%(in other words..value doubles every year)\n\nvalues are..\nM = 2\nN = 8\n\nand we're looking for the value in 2002..which is equal to 4.\n\n_________________\nSpread some love..Like = +1 Kudos", null, "Intern", null, "", null, "B\nJoined: 31 Dec 2017\nPosts: 4\nLocation: India\nConcentration: Entrepreneurship, Technology\nGPA: 3.05\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\n1\nI think this is the easiest approach here:\n\n2001 - M\n\n2002 - ? (Let it be 'x')\n\n2003 - N\n\nNow according to ques, since the rate of increase is equal both year and the rates should be calculated on the previous year's price,\n\n$$\\frac{x-M}{M} * 100= \\frac{N-x}{x}*100$$\n\n$$x^2 - Mx = MN - Mx$$\n\n$$x = \\sqrt{MN}$$\n\nHope it helps\n+1 Kudos would be nice", null, "Non-Human User", null, "Joined: 09 Sep 2013\nPosts: 13117\nRe: The price of a certain commodity increased at a rate of  [#permalink]\n\nShow Tags\n\nHello from the GMAT Club BumpBot!\n\nThanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).\n\nWant to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.\n_________________", null, "Re: The price of a certain commodity increased at a rate of   [#permalink] 22 May 2019, 15:19\nDisplay posts from previous: Sort by\n\nThe price of a certain commodity increased at a rate of\n\n new topic post reply Question banks Downloads My Bookmarks Reviews Important topics\n\n Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne", null, "", null, "" ]
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https://socratic.org/questions/how-do-you-balance-the-equation-c4h10-o2-co2-h2o#590108
[ "# How do you balance the equation C4H10+O2 = CO2+H2O?\n\nApr 7, 2018\n\n$\\textcolor{b l u e}{2 {C}_{4} {H}_{10} \\left(g\\right) + 13 {O}_{2} \\left(g\\right) \\to 8 C {O}_{2} \\left(g\\right) + 10 {H}_{2} O \\left(g\\right)}$\n\n#### Explanation:\n\nWe have the unbalanced equation:\n\n${C}_{4} {H}_{10} \\left(g\\right) + {O}_{2} \\left(g\\right) \\to C {O}_{2} \\left(g\\right) + {H}_{2} O \\left(g\\right)$\n\nThis is the combustion of butane, ${C}_{4} {H}_{10}$.\n\nLet's first balance the carbons. There are four on the $\\text{LHS}$, but only one on the $\\text{RHS}$, so we multiply $C {O}_{2}$ by $4$ to get:\n\n${C}_{4} {H}_{10} \\left(g\\right) + {O}_{2} \\left(g\\right) \\to 4 C {O}_{2} \\left(g\\right) + {H}_{2} O \\left(g\\right)$\n\nNow, let's balance the hydrogens. There are $10$ on the left side, but only two on the right side, so we multiply ${H}_{2} O$ by $5$, and get:\n\n${C}_{4} {H}_{10} \\left(g\\right) + {O}_{2} \\left(g\\right) \\to 4 C {O}_{2} \\left(g\\right) + 5 {H}_{2} O \\left(g\\right)$\n\nFinal step is to balance the oxygens. There are two on the left hand side, but thirteen on the right hand side, so we need to divide thirteen by two to get the \"scale number\", which is $6.5$. The equation is thus:\n\n${C}_{4} {H}_{10} \\left(g\\right) + 6.5 {O}_{2} \\left(g\\right) \\to 4 C {O}_{2} \\left(g\\right) + 5 {H}_{2} O \\left(g\\right)$\n\nBut wait, we cannot have half a molecule! So, we need to multiply the whole equation by $2$, which leads us to the finalized, balanced equation:\n\ncolor(blue)(barul(|2C_4H_10(g)+13O_2(g)->8CO_2(g)+10H_2O(g)|)\n\nApr 7, 2018\n\ncolor(teal)(2C_4H_10+13O_2 -> 8CO_2+10H_2O\n\n#### Explanation:\n\nThe given equation to be balanced is ${C}_{4} {H}_{10} + {O}_{2} \\to C {O}_{2} + {H}_{2} O$\n\nWe begin by counting the number of $C$ atoms on both sides.\nWe have $4 C$ on the left and $1 C$ on the right.\n\n$\\implies {C}_{4} {H}_{10} + {O}_{2} \\to 4 C {O}_{2} + {H}_{2} O$\n\ncolor(white)(wwwwwwwwwwww\n\nNow count the number of $H$ atoms on both sides.\nWe have $10 H$ on the left and $2 H$ on the right.\n\n$\\implies {C}_{4} {H}_{10} + {O}_{2} \\to 4 C {O}_{2} + 5 {H}_{2} O$\n\ncolor(white)(wwwwwwwwwwww\n\nNow, $O$'s turn.\nWe have $2 O$ on the left and $13 O$ on the right.\n\n$\\implies {C}_{4} {H}_{10} + \\frac{13}{2} {O}_{2} \\to 4 C {O}_{2} + 5 {H}_{2} O$\n\ncolor(white)(wwwwwwwwwwww $\\text{or}$\n\ncolor(teal)(2C_4H_10+13O_2 -> 8CO_2+10H_2O\n\nLets verify, by counting the number of each atom on each side.\n\ncolor(white)(wwwwwww $\\text{on left }$ color(white)(wwwwwww $\\text{on right }$\n\n$C$ color(white)(wwwwwww $8$ color(white)(wwwwwwwwtwww $8$\n\n$H$ color(white)(wwwtwww $20$ color(white)(wwwwwwwwwww $20$\n\n$O$ color(white)(wwwuwww $26$ color(white)(wwwwwwwwwww $26$\n\nHence the equation is balanced :)" ]
[ null ]
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https://www.careercup.com/question?id=5140345926975488
[ "## A9 Interview Question for Software Engineer / Developers\n\n•", null, "0\nof 0 votes\n\nCountry: United States\nInterview Type: In-Person\n\nComment hidden because of low score. Click to expand.\n2\nof 2 vote\n\nHi this a tested code i used using backtacking.\n\npublic class combinations {\n\nint arr[];\n\nint sumuptoAi(int m,int n)\n{\nint sum=0;\nfor(int i=m;i<=n;i++)\nsum=sum*10+arr[i];\n\nreturn sum;\n}\n\npublic boolean Combinations(int start,int sum)\n{\n\nif(sum==0&&start==arr.length)\nreturn true;\n\nfor(int i=start;i<arr.length;i++)\n{\n\nif(Combinations(i+1, sum-sumuptoAi(start, i)))\nreturn true;\n\n}\nreturn false;\n}\n\npublic static void main(String args[])\n{\n\nint arr[]= {2,3,7,2};\ncombinations obj=new combinations();\nobj.arr=arr;\n\nSystem.out.println(obj.Combinations(0, 239));\n\n}\n\n}\n\nComment hidden because of low score. Click to expand.\n0\nof 0 votes\n\nwhat is the time complexity for this\n\nComment hidden because of low score. Click to expand.\n0\nof 0 vote\n\nBrute force approach is something in these lines (basically start from individual numbers and then increase the size by 1 and repeat for the subarray) with X to be our target. However I'd be much more interested in dynamic programming solution, which appears could exist for this problem:\n\n``````return foo(A, 0)\n\nbool foo(A, startIndex) {\nfor size in (1...Length-startIndex) {\nn = getNumberOfSize(startIndex, size)\nif (n + foo(A, startIndex + size) == X {\nreturn true;\n}\n}\nreturn false;\n}``````\n\nComment hidden because of low score. Click to expand.\n0\nof 0 vote\n\nUsing a simple example of elements [1,2,3], build a tree of prefixes of the array as below:\n\n123\n/\n-12 -- 3\n\\\n1 --23\n\\\n2 -- 3\n\nTraverse the tree in a DFS fashion starting from the root, each time adding up the node values and checking against the target value.\n\nThe above tree can be created using prefix arrays of the suffix array of the given array.\n\nComment hidden because of low score. Click to expand.\n0\nof 0 votes\n\nThat's a good observation -- prefix tree edges will give you all possible combinations of digits. What are your estimates on running time?\n\nBuilding a tree (or trie) in performant way (linear or close to it) is difficult though so I wonder what would interviewer expectations would be in such case.\n\nComment hidden because of low score. Click to expand.\n0\nof 0 votes\n\nWouldn't the tree, as you've described it, be exponential in size with the size of the input? I might misunderstand your approach, but isn't this tree approach doing the same thing as regular backtracking, with the exception that you first enumerate all the possibilities, store them, and then evaluate them (whereas backtracking evaluates possibilities as they are enumerated)?\n\nComment hidden because of low score. Click to expand.\n0\nof 0 vote\n\nBuild a Prefix tree and while building a tree also ignore the prefixes which are greater than the target. Like in this example {5,2,1,4,3,6,7,8} all those prefix which are greater than 333 will be ignored. 521, 5214, 52143, 521436, 5214367, 52143678 will be ignored . Only valid prefixes are 52 and 5. Similarly for for selecting prefix for child elements ignored alll the prefixes which are greater than the target. Then on that tree Perform DFS (Pre order) and check for sum on each setup.\n.\n\nComment hidden because of low score. Click to expand.\n0\nof 0 vote\n\nYou can use DP, memoization would look like this (I made the code here, so there can be some mistakes, but I think it's enough to get the idea. It could be improved so that it's not necessary to use \"get_val\"):\n\n``````#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<int,int> pii;\n\nint a, target;\nmap <pii, bool> mp;\n\nint get_val(int b, int e){\nint r = 0;\nfor(int i = b; i <= e; i ++)\nr *= 10, r += a[i];\nreturn r;\n}\n\nbool memo(int sum, int px){\nif(sum > target) return false;\nif(px == n) return (sum == target);\nif(mp.find(pii(sum, px)) != mp.end()) return mp[pii(sum, px)];\nbool ok = false;\nfor(int i = px; i < n; i ++)\nok |= memo(sum + get_val(px, i), i + 1);\nreturn (mp[(pii(sum, px)] = ok);\n}\n\nint main(){\n\nscanf(\"%d %d\", &n, &target);\n\nfor(int i = 0; i < n; i ++)\nscanf(\"%d\", &a[i]);\n\nif(memo(0, 0)) printf(\"True\\n\");\nelse printf(\"False\\n\");\n\nreturn 0;\n}``````\n\nComment hidden because of low score. Click to expand.\n0\nof 0 vote\n\nI assume all numbers in the given array are nonnegtive. Following is a solution in C. Please notice that the combinations like 34352 with 56789 can result into an arithmetic overflow.\n\n``````#include <stdio.h>\n\nconst int tenPower = {\n1,\n10,\n100,\n1000,\n10000,\n100000,\n1000000,\n10000000,\n100000000,\n1000000000\n};\n\n//count how many digits the positive number has\nint countDigits(int n)\n{\nint digits = 0;\nfor(; n != 0; n /= 10) ++digits;\nreturn digits;\n}\n\n//check if the integer array can combine into the target number\nint combine(int a[], int i, int n, int target)\n{\nif(i >= n) return target == 0;\nif(a[i] == 0){//a combined decimal number can not start with 0\nreturn combine(a, i+1, n, target);\n}\n\nint sum = 0;\nfor(; i < n; ++i){\n//combine a number in this level\nsum = sum * tenPower[countDigits(a[i])] + a[i];\n//if already larger than target, then no need to search deeper\nif(sum > target) break;\n//search next level\nif(combine(a, i+1, n, target - sum)) return 1;\n}\nreturn 0;\n}\n\nint main()\n{\nint a[] = {5,2,1,4,3,6,7,8}, target = 333;\n\nif(combine(a, 0, sizeof(a)/sizeof(a), target)) puts(\"YES\");\nelse puts(\"NO\");\n\nreturn 0;\n}``````\n\nComment hidden because of low score. Click to expand.\n0\nof 0 vote\n\nI end up giving the following answer to the interviewer..\n\n1) Create all the combination of the given input i.e for {1,2,3} = {1,2,3,12,23,123}\n2) Take the numbers add it if the number is <= target value.. The numbers should be selected in such a way that it's not repeated. E.g. If I select '12' then I cannot select '1','2','23' and '123'\n\nPlease let me know if this make sense. Complexity i worst though :( but in 20 minutes this is the approach that I was able to get too..\n\nComment hidden because of low score. Click to expand.\n-1\nof 1 vote\n\nIf u want to code simple, then just create a bool set B.\nB[i]=true means there will be a '+' between A[i] and A[i+]\nfalse means there will be nothing between the two.\nTime complexity is 0(2^n)\n\nComment hidden because of low score. Click to expand.\n0\nof 0 votes\n\nThis is a good solution. Whoever downvoted it, please explain.\n\nComment hidden because of low score. Click to expand.\n0\nof 0 votes\n\nsdfsdf\n\nAdd a Comment\nName:\n\nWriting Code? Surround your code with {{{ and }}} to preserve whitespace.\n\n### Books\n\nis a comprehensive book on getting a job at a top tech company, while focuses on dev interviews and does this for PMs.\n\nLearn More\n\n### Videos\n\nCareerCup's interview videos give you a real-life look at technical interviews. In these unscripted videos, watch how other candidates handle tough questions and how the interviewer thinks about their performance.\n\nLearn More\n\n### Resume Review\n\nMost engineers make critical mistakes on their resumes -- we can fix your resume with our custom resume review service. And, we use fellow engineers as our resume reviewers, so you can be sure that we \"get\" what you're saying.\n\nLearn More\n\n### Mock Interviews\n\nOur Mock Interviews will be conducted \"in character\" just like a real interview, and can focus on whatever topics you want. 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[ null, "https://www.careercup.com/attributeimages/a9-interview-questions.png", null ]
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http://fangzhi.testrust.com/test/13/481-1.html
[ "2020年11月30日 星期一\n\n• 拉伸性能\n• 撕破强力\n• 顶破/胀破强力\n• 接缝强力\n• 粘合强力\n• 弯曲性能\n• 耐磨性\n• 拉伸弹性回复\n• 单纱强力\n• 帮底剥离强度\n• 鞋耐折性能\n• 鞋底耐磨性能\n• 鞋外底与外中底粘合强度\n• 鞋外底磨耗量\n• 帮底粘合强度\n• 鞋曲挠性能\n• 鞋跟结合力\n• 鞋帮带拉出强度\n• 橡胶与织物的粘合强度\n• 鞋底拉伸强度\n• 鞋底断裂伸长率\n• 鞋带与鞋底的拔出力\n• 鞋钉子拉断力\n• 纰裂\n• 衣带缝纫强力\n• 压缩回弹性\n• 振荡冲击性能\n• 金属镀层的结合强度\n• 负重\n• 纺织品覆粘合衬剥离强度\n• 皮革低温耐折牢度\n• 耐碱液水解牢度\n• 断裂强力及断裂伸长率\n• 单纤维/单纱 断裂强力\n• 单纱断裂强度变异系数\n• 脱缝程度\n• 定伸长强度\n• 纽扣眼孔拉力\n• 扣件结合力\n• 纽扣附着强力\n• 缝合强度\n• 毛丛强度\n• 单纤维/纱断裂伸长率\n• 自开自收伞的开关伞力\n• 伞部件结合牢度\n• 伞杆/伞骨抗风强度\n• 伞面抗拉强度\n• 冲击强度\n• 背胶粘合强度\n• 剪切强度\n• 剥离强度\n• 抗疲劳性能\n• 纽扣分开强力\n• 纽扣扣合强力\n• 围条与鞋帮粘附强力\n• 切断检测\n• 卷缩弹性回复率\n• 定伸长回复率\n• 抗粘连性\n• 撕裂力\n• 规定负荷伸长率\n• 涂层耐折牢度\n• 崩裂高度\n• 崩破强度\n• 涂层粘着牢度\n• 抗张强度\n• 干态剥离\n• 拉伸负荷及断裂伸长率\n• 撕裂负荷\n• 剥离负荷\n• 耐寒性\n• 老化性\n• 耐顶破强度\n• 耐折牢度\n• 耐揉搓性\n• 低温耐折牢度\n• 破裂负荷\n• 崩裂性\n• 缝合强力\n• 耐冲击性能\n• 勾心纵向刚度\n• 勾心硬度\n• 内底纤维板屈挠指数\n• 屈挠\n• 硬度\n• 勾心规格\n• 扯断伸长率\n• 鞋带头拉断力\n• 鞋带强力\n• 后跟牢度\n• 漆膜伸长率\n• 撕裂强度\n• 带体断裂力\n• 带孔撕裂力\n• 带扣咬合力\n• 带齿咬合力\n• 耐热性\n\n• 总数:8   页次:1/2\n• 1 2\n\n### 鞋类", null, "" ]
[ null, "http://wpa.qq.com/pa", null ]
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https://math.stackexchange.com/questions/3137319/how-in-general-does-one-construct-a-cycle-graph-for-a-group/3162746
[ "# How in general does one construct a cycle graph for a group?\n\nI think I know how to interpret a cycle graph for a group, but I don’t know how to construct one. In particular, I don’t know a general rule of how to find the “basic elements” which to take the powers of.\n\nIs there a general algorithm for constructing the cycle graph of a finite group, which always ensures that you get the correct unique cycle graph?\n\n• Do you mean cyclic groups? Mar 6, 2019 at 9:58\n• What's a cycle graph? Mar 6, 2019 at 15:50\n• Mar 6, 2019 at 16:27\n• @Berci, no I don't Mar 6, 2019 at 16:27\n\nYou can just take one element at a time (though I don't know about computational efficiency or stuff like that). Start with the graph containing only the identity element (and no edges). In each step after this, you:\n\n1. Pick an element not already in the graph.\n2. Compute the cyclic subgroup generated by the element and add the cycle to the graph (connecting to already existing nodes as needed).\n3. If the graph contains a sub-cycle of the new cycle, you delete the sub-cycle.\n\nRepeat until you have added all the (finitely many) elements.\n\nLet's say we want to make the cycle graph for $$Z_4 \\times Z_2 = \\langle x\\rangle\\times \\langle y \\rangle$$. We start with the identity element, and then we pick an arbitrary element, say $$x^2$$. We see that $$\\langle x^2 \\rangle = \\{1, x^2\\}$$, so we get the graph:\n\nx^2\n|\n1\n\n\nNow we pick another element, say x, and we find that $$\\langle x \\rangle = \\{1, x, x^2, x^3\\}$$. Since the cycle $$\\{1, x^2\\}$$ on the graph is a subset of the new cycle, we replace it:\n\n x^2\n/ \\\nx^3 x\n\\ /\n1\n\n\nLet's pick $$xy$$ now. We get $$\\langle xy \\rangle = \\{1, xy, x^2, x^3y\\}$$, so we draw:\n\n x^2\n⟋ / \\ ⟍\nx^3y x^3 x xy\n⟍ \\ / ⟋\n1\n\n\n(Please excuse the ascii...). Now we take $$y$$ and find $$\\langle y \\rangle = \\{1, y\\}$$, so we draw:\n\n x^2\n⟋ / \\ ⟍\nx^3y x^3 x xy\n⟍ \\ / ⟋\n1\n|\ny\n\n\nand finally we take $$x^2y$$, giving $$\\langle x^2y \\rangle = \\{1, x^2y\\}$$, which gives us the finished cycle graph:\n\n x^2\n⟋ / \\ ⟍\nx^3y x^3 x xy\n⟍ \\ / ⟋\n1\n/ \\\ny x^2y\n\n\n(Note that it is kind of silly to start with $$x^2$$, since it will certainly be contained in the cycle generated by $$x$$. I did it for illustrative purposes of course.)\n\nEDIT: How to find primitive elements, or \"basic elements\" as you call them. Let's say you want to know if a particular element $$g$$ will be a generator for a cycle on the cycle graph. Then you have to check if $$g$$ can be written as a power of another element, which has order strictly greater than that of $$g$$. If this is not the case, then $$g$$ is a primitive element.\n\nIf we don't know anything about the structure of the group, this would amount to basically drawing up the full graph. However, if we know the group, we can find out more quickly. For example, if $$g$$ is of maximal order in the group, then it must be a primitive element. This immediately shows that $$x$$ and $$xy$$ in our example will be primitive elements. Note that we can easily find them without computing anything. Similarly, if $$D_{2n} = \\langle r, s \\rangle$$ is the dihedral group of order $$2n$$, then $$r$$ will be a primitive element.\n\nGeneralising the situation in the example, I noticed the following: If $$Z_{p^{a_1}}\\times \\cdots \\times Z_{p^{a_t}} = \\langle x_1\\rangle\\times \\cdots \\times \\langle x_t \\rangle$$ is a direct product of cyclic groups, where the order of each one is a power of the same prime, then $$x_1, \\ldots, x_t$$ will all be primitive elements. This is not true for any other direct product of cyclic groups with more than one component.\n\n• Thanks! could you explain this: \"This immediately shows that x and xy in our example will be primitive elements. Note that we can easily find them without computing anything.\" I don't see this immediately. Mar 26, 2019 at 16:46\n• We know that the order of an element in $Z_4\\times Z_2$ divides the order of the group, i.e. 8. Since the group is not cyclic, no element has order 8, so the biggest possible order is 4. Now $x$ generates $Z_4$, so $x$ has order 4. For $xy$ we have: $|xy| = {\\rm lcm}(|x|,|y|) = {\\rm lcm}(4,2) = 4$. So they both have maximal order, meaning they are primitive elements. We can also note that $xy$ is not a power of $x$, so they generate different cycles. Mar 26, 2019 at 19:56\n• I suppose there was a little bit of computation, but we didn't have to compute the powers of the elements. Mar 26, 2019 at 19:59\n• IN your 3rd, 4th, and 5th graph you have non-ASCII characters. Mar 27, 2019 at 17:35\n• Oh, does that mess it up on other computers? Do you have a suggestion on how to fix it? You are welcome to edit. Mar 27, 2019 at 17:47" ]
[ null ]
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https://journals.ametsoc.org/view/journals/mwre/130/2/1520-0493_2002_130_0339_tcmgem_2.0.co_2.xml?rskey=odhgly&result=7
[ "• Benoit, R., M. Desgagné, P. Pellerin, S. Pellerin, Y. Chartier, and S. Desjardins, 1997: The Canadian MC2: A semi-Lagrangian, semi-implicit wideband atmospheric model suited for finescale process studies and simulation. Mon. Wea. Rev, 125 , 23822415.\n\n• Export Citation\n• Bluestein, H. B., E. Rasmussen, R. Davies-Jones, R. Wakimoto, and M. L. Weisman, 1998: VORTEX Workshop Summary, 2–3 December 1997, Pacific Grove, California. Bull. Amer. Meteor. Soc, 79 , 13971400.\n\n• Export Citation\n• Bubnova, R., G. Hello, P. Bénard, and J-F. Geleyn, 1994: An efficient alternative to z-coordinate for compressible flow over orography: Use of hydrostatic pressure as vertical coordinate in a complete NWP mesoscale model. Preprints, 10th Conf. on Numerical Weather Prediction, Portland, OR, Amer. Meteor. Soc., 35–37.\n\n• Export Citation\n• Bubnova, R., G. Hello, P. Bénard, and J-F. Geleyn, 1995: Integration of the fully elastic equations cast in hydrostatic pressure terrain-following coordinate in the framework of the ARPEGE/Aladin NWP system. Mon. Wea. Rev, 123 , 515535.\n\n• Export Citation\n• Côté, J., and A. Staniforth, 1988: A two-time-level semi-Lagrangian semi-implicit scheme for spectral models. Mon. Wea. Rev, 116 , 20032012.\n\n• Export Citation\n• Côté, J., and A. Staniforth, 1990: An accurate and efficient finite-element global model of the shallow-water equations. Mon. Wea. Rev, 118 , 27072717.\n\n• Export Citation\n• Côté, J., M. Roch, A. Staniforth, and L. Fillion, 1993: A variable-resolution semi-Lagrangian finite-element global model of the shallow-water equations. Mon. Wea. Rev, 121 , 231243.\n\n• Export Citation\n• Côté, J., S. Gravel, M. Roch, A. Patoine, and A. Staniforth, 1994: A non-hydrostatic variable-resolution global model of the atmosphere. Preprints, 10th Conf. on Numerical Weather Prediction, Portland, OR, Amer. Meteor. Soc., 171–172.\n\n• Export Citation\n• Côté, J., J-G. Desmarais, S. Gravel, A. Méthot, A. Patoine, M. Roch, and A. Staniforth, 1998a: The operational CMC–MRB Global Environmental Multiscale (GEM) model. Part II: Results. Mon. Wea. Rev, 126 , 13971418.\n\n• Export Citation\n• Côté, J., S. Gravel, A. Méthot, A. Patoine, M. Roch, and A. Staniforth, 1998b: The operational CMC–MRB Global Environmental Multiscale (GEM) model. Part I: Design considerations and formulation. Mon. Wea. Rev, 126 , 13731395.\n\n• Export Citation\n• Cullen, M. J. P., D. Salmond, and P. Smolarkiewicz, 2000: Key numerical issues for the future development of the ECMWF numerical model. Proc. ECMWF Workshop on Development in Numerical Methods for Very High Resolution Global Models, Reading, United Kingdom, ECMWF, 183–206.\n\n• Export Citation\n• Daley, R. W., 1988: The normal modes of the spherical non-hydrostatic equations with applications to the filtering of acoustic modes. Tellus, 40A , 96106.\n\n• Export Citation\n• Fillion, L., H. L. Mitchell, H. Ritchie, and A. Staniforth, 1995: The impact of a digital filter finalization technique in a global data assimilation system. Tellus, 47A , 304323.\n\n• Export Citation\n• Fox-Rabinovitz, M., G. Stenchikov, M. Suarez, and L. Takacs, 1997:: A finite-difference GCM dynamical core with a variable resolution stretched grid. Mon. Wea. Rev, 125 , 29432968.\n\n• Export Citation\n• Gill, A. E., 1982: Atmosphere–Ocean Dynamics. Academic Press, 662 pp.\n\n• Kasahara, A., 1974: Various vertical coordinate systems used for numerical weather prediction. Mon. Wea. Rev, 102 , 509522.\n\n• Laprise, R., 1992: The Euler equations of motion with hydrostatic pressure as an independent variable. Mon. Wea. Rev, 120 , 197207.\n\n• Mailhot, J., and Coauthors,. 1998: Scientific description of RPN Physics Library. Version 3.6. Recherche en Prévision Numérique, 188 pp. [Available online at http://www.cmc.ec.gc.ca/rpn/physics/physic98.pdf.].\n\n• Export Citation\n• Phillips, N. A., 1957: A coordinate system having some special advantages for numerical forecasting. J. Meteor, 14 , 184185.\n\n• Qian, J-H., F. H. M. Semazzi, and J. S. Scroggs, 1998: A global nonhydrostatic semi-Lagrangian atmospheric model with topography. Mon. Wea. Rev, 126 , 747771.\n\n• Export Citation\n• Rasmussen, E. N., J. M. Straka, R. Davies-Jones, C. A. Doswell III, F. H. Carr, M. D. Eilts, and D. R. MacGorman, 1994: Verification of the Origins of Rotation in Tornadoes Experiment: VORTEX. Bull. Amer. Meteor. Soc, 75 , 9951006.\n\n• Export Citation\n• Rivest, C., A. Staniforth, and A. Robert, 1994: Spurious resonant response of semi-Lagrangian discretizations to orographic forcing: Diagnosis and solution. Mon. Wea. Rev, 122 , 366376.\n\n• Export Citation\n• Skamarock, W. C., P. K. Smolarkiewicz, and J. B. Klemp, 1997: Preconditioned conjugate-residual solvers for Helmholtz equations in nonhydrostatic models. Mon. Wea. Rev, 125 , 587599.\n\n• Export Citation\n• Tanguay, M., A. Simard, and A. Staniforth, 1989: A three-dimensional semi-Lagrangian scheme for the Canadian regional finite-element forecast model. Mon. Wea. Rev, 117 , 18611871.\n\n• Export Citation\n• Tanguay, M., A. Robert, and R. Laprise, 1990: A semi-implicit semi-Lagrangian fully compressible regional forecast model. Mon. Wea. Rev, 118 , 19701980.\n\n• Export Citation\n• Tremblay, A., A. Glazer, W. Yu, and R. Benoit, 1996: A mixed-phase cloud scheme based on a single prognostic equation. Tellus, 48A , 483500.\n\n• Export Citation\n• Wang, D., M. Xue, V. Wong, and K. K. Droegemeier, 1996: Prediction and simulation of convective storms during VORTEX 95. Preprints, 11th Conf. on Numerical Weather Prediction, Norfolk, VA, Amer. Meteor. Soc., 301–303.\n\n• Export Citation\n• Wang, D., M. Xue, D. Hou, and K. K. Droegemeier, 1998: Midlatitude squall line propagation and structure as simulated by a 3D nonhydrostatic stormscale model. Preprints, 12th Conf. on Numerical Weather Prediction, Phoenix, AZ, Amer. Meteor. Soc., 209–212.\n\n• Export Citation\n• Xue, M., D. Hou, D. Wang, and K. K. Droegemeier, 1998a: Analysis and prediction of convective initiation along a dryline. Preprints, 16th Conf. on Weather Analysis and Forecasting, Phoenix, AZ, Amer. Meteor. Soc., 161–163.\n\n• Export Citation\n• Xue, M., D. Wang, D. Hou, K. Brewster, and K. K. Droegemeier, 1998b:: Prediction of the 7 May 1995 squall lines over the central U.S. with intermittent data assimilation. Preprints, 12th Conf. on Numerical Weather Prediction, Phoenix, AZ, Amer. Meteor. Soc., 191–194.\n\n• Export Citation\n• Yanenko, N. N., 1971: The Method of Fractional Steps. Springer, 160 pp.\n\nAll Time Past Year Past 30 Days\nAbstract Views 0 0 0\nFull Text Views 398 180 95\n\n# The CMC–MRB Global Environmental Multiscale (GEM) Model. Part III: Nonhydrostatic Formulation\n\nKao-San YehCentre de Recherche en Calcul Appliqué, Montréal, Québec, Canada\n\nSearch for other papers by Kao-San Yeh in\nCurrent site\nPubMed\nClose\n,\n\nSearch for other papers by Jean Côté in\nCurrent site\nPubMed\nClose\n,\n\nSearch for other papers by Sylvie Gravel in\nCurrent site\nPubMed\nClose\n,\n\nSearch for other papers by André Méthot in\nCurrent site\nPubMed\nClose\n,\n\nSearch for other papers by Alaine Patoine in\nCurrent site\nPubMed\nClose\n,\n\nSearch for other papers by Michel Roch in\nCurrent site\nPubMed\nClose\n, and\n\nSearch for other papers by Andrew Staniforth in\nCurrent site\nPubMed\nClose\nFull access\n\n## Abstract\n\nAn integrated forecasting and data assimilation system has been and is continuing to be developed by the Meteorological Research Branch (MRB) in partnership with the Canadian Meteorological Centre (CMC) of Environment Canada. Part III of this series of papers presents the nonhydrostatic formulation and some sample results. The nonhydrostatic formulation uses Laprise's hydrostatic pressure as the basis for its vertical coordinate. This allows the departure from the hydrostatic formulation to be incorporated in an efficient switch-controlled perturbative manner. The time discretization of the model dynamics is (almost) fully implicit semi-Lagrangian, where all terms including the nonlinear terms are (quasi-) centered in time. The spatial discretization for the adjustment step employs a staggered Arakawa C grid that is spatially offset by half a mesh length in the meridional direction with respect to that employed in previous model formulations. It is accurate to second order, whereas the interpolations for the semi-Lagrangian advection are of fourth-order accuracy except for the trajectory estimation. The resulting set of nonlinear equations is solved iteratively using a motionless isothermal reference state that gives the usual semi-implicit problem as a preconditioner. The Helmholtz problem that needs to be solved at each iteration is vertically separable, the impact of nonhydrostatic terms being simply a renormalization of the separation constants. The convergence of this iterative scheme is not greatly modified by the nonhydrostatic perturbation. Three numerical experiments are presented to illustrate the model's performance. The first is a test to show that hydrostatic balance at low resolution is well maintained. The second one is a mild orographic windstorm case, where the flow should remain hydrostatic, to test that hydrostatic balance at high resolution is also well maintained. The third one is a convective case taken from the Verification of the Origins of Rotation in Tornadoes Experiment (VORTEX). Although these results are encouraging, rigorous testing of the model's performance for strongly nonhydrostatic flows still remains to be done.\n\n* Current affiliation: Earth System Science Interdisciplinary Center, University of Maryland, College Park, Maryland.\n\nCorresponding author address: Dr. Andrew Staniforth, Dynamics Research Branch Head, Met Office, London Road, Bracknell, Berkshire RG12 2SZ, United Kingdom. Email: [email protected]\n\n## Abstract\n\nAn integrated forecasting and data assimilation system has been and is continuing to be developed by the Meteorological Research Branch (MRB) in partnership with the Canadian Meteorological Centre (CMC) of Environment Canada. Part III of this series of papers presents the nonhydrostatic formulation and some sample results. The nonhydrostatic formulation uses Laprise's hydrostatic pressure as the basis for its vertical coordinate. This allows the departure from the hydrostatic formulation to be incorporated in an efficient switch-controlled perturbative manner. The time discretization of the model dynamics is (almost) fully implicit semi-Lagrangian, where all terms including the nonlinear terms are (quasi-) centered in time. The spatial discretization for the adjustment step employs a staggered Arakawa C grid that is spatially offset by half a mesh length in the meridional direction with respect to that employed in previous model formulations. It is accurate to second order, whereas the interpolations for the semi-Lagrangian advection are of fourth-order accuracy except for the trajectory estimation. The resulting set of nonlinear equations is solved iteratively using a motionless isothermal reference state that gives the usual semi-implicit problem as a preconditioner. The Helmholtz problem that needs to be solved at each iteration is vertically separable, the impact of nonhydrostatic terms being simply a renormalization of the separation constants. The convergence of this iterative scheme is not greatly modified by the nonhydrostatic perturbation. Three numerical experiments are presented to illustrate the model's performance. The first is a test to show that hydrostatic balance at low resolution is well maintained. The second one is a mild orographic windstorm case, where the flow should remain hydrostatic, to test that hydrostatic balance at high resolution is also well maintained. The third one is a convective case taken from the Verification of the Origins of Rotation in Tornadoes Experiment (VORTEX). Although these results are encouraging, rigorous testing of the model's performance for strongly nonhydrostatic flows still remains to be done.\n\n* Current affiliation: Earth System Science Interdisciplinary Center, University of Maryland, College Park, Maryland.\n\nCorresponding author address: Dr. Andrew Staniforth, Dynamics Research Branch Head, Met Office, London Road, Bracknell, Berkshire RG12 2SZ, United Kingdom. Email: [email protected]\n\n## 1. Introduction\n\nThe hydrostatic assumption, namely, the neglect of vertical acceleration in the vertical momentum equation of the primitive equations, is an excellent approximation that is well respected in the atmosphere down to scales of 10 km or so. However, at these scales the dynamical effects excluded by the hydrostatic assumption, for example, internal wave breaking and overturning, start to become nonnegligible.\n\nTo date, computer limitations have been such that almost all operational weather forecast (and climate simulation) models have been run with horizontal mesh lengths coarse enough to confidently employ the hydrostatic primitive equations. Looking to the future however, this will change (Daley 1988). In particular, if a model is to be applied with meso-γ-scale mesh configurations, then it should use the fully compressible nonhydrostatic primitive equations instead of the so-called hydrostatic primitive ones. This motivates the use of “hydrostatic pressure” as the basis for a vertical coordinate as proposed in Laprise (1992). This coordinate system permits a switch-controlled choice between the hydrostatic primitive equations (for large- and synoptic-scale applications), and the nonhydrostatic primitive equations (for smaller-scale applications). The computational and memory overhead associated with the latter option can then be avoided for applications where the hydrostatic approximation is valid. A terrain-following normalized pressure version (Phillips 1957; Kasahara 1974) is possible (Bubnova et al. 1994, 1995), allowing an easy incorporation of the lower boundary, and a relaxation toward the horizontal upward from the earth's surface. For atmospheric applications, there is virtually no scale restriction on using hydrostatic pressure as vertical coordinate since it only requires density to be positive; integrations are presented in Bubnova et al. (1995) with horizontal resolution as high as 80 m. Note however that terrain-following transformations ultimately break down in the presence of cliffs due to a breakdown of differentiability.\n\nThe model formulation presented here was outlined in Côté et al. (1994). It differs from the Bubnova et al. (1994, 1995) formulation in several aspects besides the horizontal discretization. First, the set of equations used is different: Laprise (1992) gave various alternative formulations, the subset chosen here is the minimal one having as supplementary equations the vertical equation of motion and the definition of vertical velocity (see section 2a). Second, the present dynamical formulation is (quasi-) centered (almost) fully implicit (see section 2c), whereas the Bubnova et al. (1995) one is (quasi-) centered semi-implicit: furthermore, the present formulation was developed for a new model with no constraint on being compatible with another model or system. The present formulation can be summarized as follows: minimal and simplest equation set, (almost) fully implicit (quasi-) centered time discretization, space discretization with consistent treatment of right- and left-hand-sides of the governing equations, algebraic elimination to derive the Helmholtz problem, and consistent backsubstitution.\n\n## 2. Formulation\n\n### a. Hydrostatic pressure and vertical coordinate\n\nThe “hydrostatic pressure” (denoted π) of Laprise (1992) is defined as a pressure field in hydrostatic balance with ϕ, the geopotential height. Thus", null, "where ρ is the density. Equation (2.1a) defines π to within an arbitrary additive horizontal field. The ambiguity is lifted by further requiring that hydrostatic pressure and pressure be equal at the top of the model, taken here to be at constant pressure πT. Full pressure (p) is then represented in the model as a perturbation from π, and so\npπqpπqqT\nwhere subscript T denotes evaluation at the model top and primes denote a perturbation quantity. In the hydrostatic limit hydrostatic pressure and full pressure become identical, and a measure of departure from hydrostatic balance is defined by", null, "referred to herein as the nonhydrostatic index.\nSince ρ is strictly positive, π varies monotonically with height and can be used to define a terrain-following vertical coordinate:", null, "where πS = πS(λ, θ) and the subscripts S and T respectively, refer to evaluation at the surface and at the top of the model.\nTo allow for a more general nonlinear relationship between η and π than (2.3), and to keep a quasi-invariant formulation with little dependence on the exact form of the relationship, the terrain-following vertical coordinate of the model, denoted by Z, is taken to be π*(η), the reference pressure profile. It is a monotonic function of η, which is obtained from η(π, πS, πT) by replacing the fields π, πS, and πT by their reference values Zπ*, ZSπ*S, and ZTπ*T respectively. Thus, for the particular linear case (2.3)", null, "The reference or basic state is motionless and isothermal with temperature T*. The reference potential temperature θ* and geopotential ϕ*, respectively, are therefore", null, "where κ = Rd/cpd, Rd is the gas constant for dry air, cpd is the specific heat of dry air at constant pressure, and p00 ≡ 1015 hPa is a constant pressure.\n\nNote that since the time discretization of the model is (almost) fully implicit (see section 2c below), the basic-state parameters are simply relaxation parameters, which are chosen to accelerate the convergence of the iterative scheme and ensure the stability of the model.\n\n### b. Governing equations\n\nThe governing equations are the forced nonhydrostatic primitive equations:", null, "where", null, "is the substantive derivative following the fluid. Here, VH is horizontal velocity, D is horizontal divergence, Tυ is virtual temperature, s ≡ ln(∂π/∂Z) = ln[(πSπT)/(ZSZT)] is the mass variable and depends only on the horizontal, qυ is specific humidity of water vapor, f is the Coriolis parameter, k is a unit vector along the rotation axis of the earth, g is the vertical acceleration due to gravity, and FH, Fθ, Fυ, and Fqυ are parameterized physical forcings. Equations (2.6)–(2.12) are, respectively, the horizontal momentum, continuity, thermodynamic, vertical momentum, vertical velocity, moisture, and hydrostatic equations, and (2.13) is the equation of state, taken here to be the ideal gas law. A hydrostatic/nonhydrostatic switch δH has been introduced into (2.9). When δH = 0, (2.9) reduces to μ = 0. This implies that πp from (2.1b) and (2.2), that (2.10) decouples completely, and that the governing equations then revert to the usual hydrostatic primitive equation set. When δH = 1, the original nonhydrostatic set is recovered. Thus this set (see Tanguay et al. 1990) only differs from the hydrostatic primitive equations by the inclusion of the vertical acceleration term dw/dt.\nThe boundary conditions are the same for both the nonhydrostatic and hydrostatic sets: periodicity in the horizontal, and no motion across the top and bottom of the atmosphere. Thus\nŻZZSZT\n\n### c. Temporal discretization\n\nThe time discretization is the same as in Côté et al. (1998b), and only the essential elements for what follows are recalled here. Equations (2.6)–(2.12) are first integrated in the absence of forcing, and the parameterized forcing terms appearing on the right-hand sides of (2.6)–(2.11) are then computed and added using the fractional-step time method (Yanenko 1971).\n\nThe time discretization used to integrate the frictionless adiabatic equations of the first step is (almost) fully implicit/semi-Lagrangian. “Fully implicit” refers here to the time discretization of (2.6)–(2.12) in the absence of the parameterized forcings. However these forcing terms are not treated fully implicitly but as a corrector to an adiabatic predictor and, as described at the end of this section, the trajectories are computed in a predictor–corrector manner. Thus the nomenclature “(almost) fully implicit” has been adopted to concisely summarize the time discretization.\n\nConsider a prognostic equation of the form", null, "Such an equation is approximated by time differences and weighted averages along a trajectory determined by an approximate solution to", null, "where r(λ, θ) is the position vector on the sphere of a fluid element and a is the (constant) radius of the earth. The vertical displacement is obtained neglecting acceleration, as is usual in semi-Lagrangian schemes, whereas for the horizontal displacement the motion is constrained to the sphere. Denoting by x3 = {r, Z} the three-dimensional position vector, (2.16) is discretized as", null, "where ψn = ψ(x3, t), ψn−1 = ψ[x3(t − Δt), t − Δt], ψ = {F, G}, t = nΔt.\n\nNote that this scheme is decentered along the trajectory, as in Rivest et al. (1994), to avoid the spurious resonant response arising from a centered approximation in the presence of orography. Cubic interpolation is used everywhere for upstream evaluations [cf. (2.18)] except for the trajectory computations [cf. (2.17)], where linear interpolation is used with no visible degradation in the results.\n\nGrouping terms at the new time on the left-hand side and known quantities on the right-hand side, (2.18) may be rewritten as", null, "where τ ≡ (1 + 2ε)Δt/2. This yields the set of coupled nonlinear equations (B.1) of appendix B for the unknown quantities at the mesh points of a regular grid at the new time t, the solution of which is discussed in section 2e.\n\nTo ensure the stability of this implicit treatment, the trajectory equation (2.17) is solved in a predictor–corrector manner. This is done by first using the time-extrapolated 3D wind at time t − Δt/2 to obtain a predicted estimate of the displacements [cf. (2.17)], and also of the solution. These are then corrected by using the time-interpolated wind at time t − Δt/2 to obtain the final displacements and solution. Further iteration of this procedure is possible, albeit at some cost, but although available it has not to date been needed in practice—whether this will however be an issue for strongly nonhydrostatic flows remains to be seen.\n\n### d. Spatial discretization\n\nThe horizontal and vertical discretization are as in Côté et al. (1998b): a variable-resolution discretization on an Arakawa C grid is used in the horizontal with the supplementary fields related to the inclusion of nonhydrostatic effects located on the scalar grid. The essential elements of the spatial discretization are presented in appendix A. The discretization is centered almost everywhere and, hence, is almost everywhere of second order in space. The only exception is in the variable portion of the horizontal grid, where the computation of the horizontal divergence is not exactly centered, but as argued in Fox-Rabinovitz et al. (1997), for small uniform constant stretching the accuracy is still second order.\n\nThe accuracy of the spatial discretization can be verified by examining the spectra of the discrete operators of appendix A [cf. (A.16)–(A.17), (A.23)–(A.24)] and comparing them to those of the underlying continuous problems. In the λ direction, the generalized eigenvalue problem,\nPλλiiPλii\nis a discretization of the problem of finding the Fourier modes of period 2π, and for a uniform grid the discrete modes are identical to the continuous modes except that the eigenvalues are different. The error on the eigenvalue corresponding to the modes of wavenumber m is", null, "where HOT denotes “higher-order terms” and is therefore of second-order accuracy.\nSimilarly in the θ direction, the generalized eigenvalue problem,\nPθθjjPθjj\nis a discretization of the problem of finding the Legendre polynomials (the zonal spherical harmonics), and the jth discrete eigenvalue should converge to −j(j − 1). This is verified numerically for the third mode [P2(sinθ)]. The latitudes of the uniform grid are given by", null, "Fitting the form aNJb to the error computed with NJ = 51, 71, 91, and 111 respectively, yields a ≈ −27.06, b ≈ −1.9994, thus numerically confirming the formal second-order accuracy.\nIn the Z direction, the generalized eigenvalue problem,\nVZZδHkkVZkk\nis a discretization of the problem of finding the vertical structure functions for P [cf. (B.5)] of the normal modes of the linearized equations. The continuous problem is given by\nLLμLZT\nκLZS\nwhere L ≡ ∂/∂ lnZ. Equation (2.25) can be solved analytically and the eigenvalues (μ) are the roots of the transcendental equation:", null, "Taking ZT = 10 hPa, ZS = 1000 hPa, and κ = 0.285 491 217 95, the first three roots are:\n1. −0.218 119 108 289 177 3,\n\n2. −0.811 620 026 369 796 0, and\n\n3. −2.225 995 779 229 059.\n\nThe convergence to the third eigenvalue is investigated numerically by successive refinement of the vertical grid:", null, "Fitting the form a(NK − 1)b to the error computed with NK = 51, 71, 91, and 111, respectively, yields a ≈ 20.837, b ≈ −2.0018, again numerically confirming the formal second-order accuracy.\n\n### e. Solving the coupled nonlinear set of discretized equations\n\nAfter spatial discretization the coupled set of nonlinear equations still has the form of (2.19). Terms on the right-hand side, which involve upstream interpolation, are first evaluated. The coupled set is rewritten as a linear one (where the coefficients depend on the basic state), plus a nonlinear perturbation, which is placed on the right-hand side and which is relatively cheap to evaluate. The set is then solved iteratively using the linear terms as a kernel, and reevaluating the nonlinear terms on the right-hand side at each of the iterations using the most recent values.\n\nThe nonlinearity is due mostly to the logarithmic terms ln p and ln θ in the governing equations. The logarithmic nonlinearity is the mildest one possible, and provided the reference state is chosen appropriately the fixed point iterations will converge. The convergence, and optimization, of the iterative scheme were analyzed in Côté and Staniforth (1988). Two iterations, the minimum for stability, have been found sufficient for practical convergence in all our work since (Côté and Staniforth 1990; Côté et al. 1993, 1998b). Note however that because of the outer iteration the total number of iterations (and evaluation of the nonlinear terms) is 4, giving a scheme that is more robust than recently proposed predictor–corrector-like schemes at the European Centre for Medium-Range Weather Forecasts (Cullen et al. 2000) and Météo-France (I. G. Gospodinov 2000, personal communication).\n\nThe linear set can be algebraically reduced to the solution of a 3D elliptic boundary value (EBV) problem from which the other variables are obtained by backsubstitution. This EBV problem for P is vertically separable and it is solved efficiently with the same solver described in Côté et al. (1998b)—the nonhydrostatic factors require a simple renormalization of the separation constants. The nonseparability in the horizontal is due to the Coriolis terms on the rotated grid, which are O(fΔt). The preconditioned conjugate gradient method used in Côté et al. (1998b) requires very few iterations to converge, and we can stop at a fixed and small number of iterations that diminish with diminishing equivalent height. The preconditioner is obtained by replacing 2f by a02, with a0 taken as", null, "The linearization and the derivation of the 3D EBV problem along with its vertical separation are outlined in appendix B. Performing a vertical separation in a separable 3D EBV problem, as in the present work, has the virtue that horizontal and vertical scales no longer mix, something that we speculate may have been a source of the convergence difficulties reported in Skamarock et al. (1997) in the context of the solution of a nonseparable EBV problem. The direct solver adopted herein as a preconditioner for the horizontal 2D EBV problems that result from the vertical separation procedure has the virtue that it directly handles the strongest horizontal variations. Only a couple of iterations are then needed to accommodate the slowly varying nonseparable Coriolis terms that result from the use of a rotated lat–lon coordinate system. However these iterations can be avoided by simply handling the nonseparable Coriolis terms together with the nonlinear ones, and this strategy has been adopted in the model since submission of the present paper. It remains to be seen whether the rapid convergence, observed for hydrostatic and mildly nonhydrostatic flows, of the iterative methods adopted herein also holds for strongly nonhydrostatic ones.\n\n## 3. Results\n\nThe nonhydrostatic version of the Global Environmental Multiscale (GEM) model has been tested with real-data cases both at low and high resolutions. The global case at low resolution is a sensitivity test to illustrate the closeness of the results of the nonhydrostatic and hydrostatic versions for the hydrostatic regime, and two mesoscale events at high resolution are used to provide a preliminary assessment of the accuracy of the nonhydrostatic version. The experimental configurations are summarized in Table 1, where the diffusion coefficient is that of horizontal Laplacian diffusion, the digital filter refers to that of Fillion et al. (1995), and the physical parameterizations are based on the Recherche en Prévision Numérique (RPN) Physics 3.6 package described in Mailhot et al. (1998) with appropriate modifications (summarized later) for mesoscale applications. In all the experiments, ZT and ZS are taken as 10 and 1000 hPa, respectively, and T* is 200 K. As in Côté et al. (1998a), the variable-resolution strategy is used to hindcast the mesoscale events. Note also that all computations are performed on a NEC SX-4 supercomputer at 32-bit arithmetic precision, except that 64-bit precision is used to solve the elliptic boundary value problem associated with the implicit time discretization. The experiments are all initiated from hydrostatic initial conditions, and the supplementary fields needed for the nonhydrostatic experiments are computed as described in appendix C.\n\nDetails of the experiments are described in the following subsections. The Courant–Friedrichs–Levy (CFL) numbers for advection are defined locally as", null, "where u, υ, and Ż are the λ, θ, and Z components of the wind, respectively. Unless otherwise mentioned, the poles and the equator refer to those of the computational mesh rather than those of the geographical system.\n\n### a. The global case\n\nThe hydrostatic assumption is globally considered to be well respected for scales larger than 10 km, and nonhydrostatic effects are negligible for scales larger than 100 km (e.g., Gill 1982). A global low-resolution experiment is thus conducted to test how close the forecasts of the two versions are for large- and synoptic-scale flow. As summarized in Table 1, the global sensitivity test is conducted with a uniform resolution of 2° in both the zonal and meridional directions, and with the 28 vertical levels of the operational configuration. The poles of the computational mesh are rotated with respect to the geographical ones, and are located in areas where the winds are climatologically relatively uniform in order to minimize the differences in the vicinity of the numerical poles. The initial atmosphere is obtained via an interpolation of a 16-level Canadian Meteorological Centre (CMC) isobaric analysis on a 400-point × 200-point latitude–longitude grid, valid at 0000 UTC 19 July 1996. A digital filter is employed to control high-frequency oscillations with periods shorter than 6 h. A large time step of 1 h is chosen such that the maximum horizontal CFL number is about 2 around the equator of the computational mesh, while the maximum vertical CFL number is much less than 1 for this case. The total integration time is 48 h. The horizontal diffusion is turned off in order to better highlight the differences between the hydrostatic and nonhydrostatic forecasts. These differences are summarized in Table 2, where “plain dynamics” refers to the experiment without physics and topography, and “physics and topography” refers to the experiment described below with physics and topography included.\n\nThe nonhydrostatic version of the GEM model is first tested without physics and topography, and the same configuration is used to produce the hydrostatic control. The 24-h 500-hPa height difference statistics of the nonhydrostatic and hydrostatic forecasts are displayed in Table 2. The rms difference is 0.012 m, and the maximum absolute (maxnorm) difference is only 0.037 m. The 24-h mean sea level pressure (MSLP) differences are also very small as seen in Table 2. The nonhydrostatic index (μ) at hour 24 is O(10−7) throughout the whole domain, indicating that the vertical acceleration is extremely weak and that nonhydrostatic effects are indeed negligible for this case. The corresponding 48-h difference statistics (see Table 2) are very similar to the 24-h ones, except that the magnitudes are generally larger.\n\nThe sensitivity in the presence of both physics and topography is also examined. The full package of operational physical parameterizations is used for both the hydrostatic and nonhydrostatic integrations, and statistics of the differences are summarized in Table 2. The 24-h 500-hPa rms height difference is 0.284 m, while the maximum difference is 2.378 m, and the average difference is only −0.016 m. The 24-h MSLP rms difference is 0.036 hPa, while the maximum absolute difference is only 0.251 hPa, and the bias is negligible. The 48-h differences (see Table 2) are generally of the same order of magnitude but somewhat larger.\n\nThe above results may be compared to those of a predecessor of the Canadian Mesoscale Compressible Community model (MC2; Tanguay et al. 1990), where the test was carried out without topography but with simple physical parameterizations—a simple form of surface momentum, heat, and moisture fluxes, and a moist convective adjustment. It was reported in Tanguay et al. (1990) that the nonhydrostatic and hydrostatic forecasts for the 24-h 500-hPa height were identical up to three significant figures; that is, the difference was less than 10 m (how much less was not stated) compared to the 0.012-m difference reported herein. Note however that this was not an “identical twin” experiment since different vertical coordinates were employed in their hydrostatic and nonhydrostatic integrations. The GEM model's forecasts can also be compared to those presented in Qian et al. (1998), where an identical twin hydrostatic–nonhydrostatic experiment was carried out with topography but without physics. Those authors found that the maximum magnitude of the 48-h 500-hPa height difference between the nonhydrostatic and the hydrostatic forecasts was greater than 15 m (their Fig. 17c) compared to the 5-m difference observed herein.\n\nThe above initial analysis used by the GEM model was arbitrarily chosen from the CMC archives, and similar results were obtained in tests with other randomly chosen analyses. When tests were repeated using much larger time steps, for example, 2 or 3 h, in order to test the stability of the nonhydrostatic version, the only impact was a gradual increase in the differences due to increasing time-truncation error. It is concluded that the nonhydrostatic dynamics of the GEM model for large- and synoptic-scale flow is very close to the hydrostatic dynamics, confirming that running a global nonhydrostatic model for hydrostatic-scale flows does not introduce a spurious nonhydrostatic response.\n\n### b. The suete case\n\nThe suete case is a small-scale downslope wind event that occurs regularly on the western side of the Cape Breton Highlands, Nova Scotia, Canada. It was studied in Benoit et al. (1997) using the Canadian MC2 model, and in Côté et al. (1998a) using the hydrostatic version of the GEM model. Both studies concluded that the dynamics of this mild windstorm was dominated by the orographic forcing, and that nonhydrostatic effects were relatively unimportant. It is thus considered to be a good test of the dynamical balance of a nonhydrostatic model at high resolution.\n\nBoth hydrostatic and nonhydrostatic hindcasts of the suete event described in Côté et al. (1998a) are presented here using the experimental configuration summarized in Table 1. It has been found that this particular event is not very sensitive to the number of vertical levels nor to the precise value of the horizontal diffusion coefficient. In Côté et al. (1998a), the operational configuration of 28 levels and a horizontal diffusion coefficient of 2500 m2 s−1 were adopted to facilitate comparison with the Benoit et al. (1997) simulations. Here, however, these parameters have been changed to be the same as for the Verification of the Origins of Rotation in Tornadoes Experiment case presented in the following subsection, which has 35 levels (shown in Table 3) and a five-times-smaller diffusion coefficient of 500 m2 s−1. All other configuration parameters are identical to those of Côté et al. (1998a). The GEM model's orography, initial analysis, and rotated variable-resolution mesh are, respectively, shown in Figs. 12, 13a, and 15 of Côté et al. (1998a). The horizontal resolution is 0.02° in the central domain with each successive mesh length increasing by 10% in each of the four coordinate directions when moving away from this high-resolution subdomain. The initial atmosphere, valid at 1800 UTC 21 December 1993, is obtained via interpolation from a 15-level isobaric analysis defined on a 360-point × 180-point Gaussian grid. Physical parameterizations are as in the Côté et al. (1998a) integration: no gravity wave drag, no convection, and simple condensation instead of the Sundqvist parameterization. The total integration time is 12 h with a 1-min time step. The maximum horizontal CFL number in the central domain is about 2.0 and the maximum vertical CFL number is about 1.5 during both the hydrostatic and nonhydrostatic integrations.\n\nThe 6-h 10-m wind forecast for the nonhydrostatic configuration of the GEM model is presented in Fig. 1a, where the orography is contoured every 50 m, the upstream station in Sydney is marked with S, and the station in Grand-Étang is marked with G. A strong downslope wind occurs on the lee side immediately offshore while the surrounding winds are weaker. The 9-h forecast, Fig. 1b, is shown for comparison with Benoit et al. (1997) and Côté et al. (1998a). The wind at this time however is more uniform over the whole region. The hydrostatic forecast (not shown) is very close to the nonhydrostatic one, consistent with the findings of the aforementioned studies.\n\nThe MSL pressure and surface wind forecasts of both the hydrostatic and nonhydrostatic configurations have been compared to observations at the (upstream) Sydney and (downstream) Grand-Étang stations, and time series are presented in Figs. 2 and 3, respectively. The nonhydrostatic MSLP (Fig. 2) forecasts (solid curves) are barely distinguishable from the hydrostatic ones (dashed curves), and all agree quite well with the observations (black triangles). The time series of surface wind (Fig. 3) at the two stations show that the nonhydrostatic forecasts (solid curves) are very close to the hydrostatic ones (dashed curves). They also agree quite well with the observations at the upstream Sydney station, while at the downstream Grand-Étang station the agreement is not quite as good, due partially to the gustiness of the observed winds, something that the model does not properly represent.\n\nTo better understand why the nonhydrostatic forecast is so similar to the hydrostatic one, a vertical cross section of the nonhydrostatic index μ at 6 h, across the mountain crest and along the arrow shown in Fig. 1a, is plotted in Fig. 4. It is seen that the nonhydrostatic index is for the most part confined to low levels (η ≫ 0.95) by the strong stratification of the flow, and thus nonhydrostatic effects are significantly suppressed. The wind speed is also displayed in Fig. 4, and the region of maximum wind speed is well correlated to the nonhydrostatic index.\n\nThis experiment demonstrates that the nonhydrostatic GEM dynamics can maintain proper hydrostatic balance in weakly nonhydrostatic situations. It also indicates that the model is capable of making a reasonable mesoscale forecast despite the lack of a high-resolution initial analysis and adequate physical parameterizations.\n\n### c. The VORTEX case\n\nThe Verification of the Origins of Rotation in Tornadoes Experiment (VORTEX) project was conducted during the springs of 1994 and 1995 with the primary purpose of testing a set of hypotheses concerning tornadogenesis and tornado dynamics (Rasmussen et al. 1994). Data were also collected that are suitable for the study of convective storm dynamics and the structure of features in the boundary layer prior to the onset of convection (Bluestein et al. 1998). One of the interesting events observed in the VORTEX project is a typical squall line that occurred on 7–8 May 1995, and which is referred to here as the VORTEX case for convenience. This case was first studied by Wang et al. (1996), further analyzed by Xue et al. (1998a), and simulated by Wang et al. (1998) with a nonhydrostatic model and by Xue et al. (1998b) by data assimilation. The present goal is to demonstrate the capability of the GEM model to forecast the positions of the mesoscale squall line and the associated precipitation patterns, despite the inadequacies of a synoptic-scale initial analysis and the physical parameterizations employed.\n\nAt 1200 UTC 7 May 1995, a clearly defined dryline was observed along the New Mexico–Texas border. As it moved eastward into Texas, a band of convective clouds started to develop along the dryline around 1600 UTC, and more convective cells developed to the south of the dryline in western Texas within the next 2 h. The convection soon intensified and occurred along a line, which further evolved into a typical midlatitude squall line as it moved across the western border of Oklahoma around 2000 UTC. This squall line lasted more than 10 h and extended more than 1000 km in the south–north direction. Figure 5 shows the 1.5-km-altitude composite radar reflectivity image valid at 0200 UTC 8 May 1995, when the squall line was at its mature stage with a solid leading convective edge and an associated trailing stratiform precipitation band parallel to the convective line. The cloud in the northeast sector of the major convective line corresponds to the tail of a relatively minor squall line formed a few hours earlier than the major one, and attention here is focused on the major squall line in central Oklahoma.\n\nWith the experimental configuration summarized in Table 1, both the hydrostatic and nonhydrostatic versions of the GEM model are used to simulate the squall line. The horizontal resolution is chosen to be 0.04° (≈4.4 km) so that the uniform high-resolution (240- × 323-point) window of the 353- × 415-point mesh covers the evolution of the entire event. Figure 6 shows the grid system of the GEM model for simulating this VORTEX case. The computational poles are rotated with respect to the geographical ones in order to center the uniform high-resolution window over the area of interest. The horizontal resolution is again smoothly degraded by the same 10% factor per successive mesh length when moving away from the uniform-resolution subdomain. Thirty-five vertical levels are adopted here, instead of the operational 28 levels, to better resolve the strong convection. The horizontal diffusion coefficient of 500 m2 s−1 is kept relatively small in order not to unduly smooth small-scale features. The total integration time is 18 h with a 1-min time step, and the maximum horizontal CFL number is about 2.0 in the central domain during both the hydrostatic and nonhydrostatic integrations. The GEM model is initiated from an interpolation of a 21-level CMC analysis valid on a 360- × 180-point Gaussian grid at 1200 UTC 7 May 1995, when no convection was present along the dryline at the New Mexico–Texas border. The digital filter of Fillion et al. (1995) is employed for the model to reach dynamical balance with a cutoff frequency of 3 h. The physical parameterizations are based on the RPN Physics 3.6 package (Mailhot et al. 1998), but without the gravity wave drag and convective parameterizations that were designed for large-scale applications. For condensation, the mixed-phase cloud scheme of Tremblay et al. (1996) is used. The supercooled liquid water parameterization in this cloud scheme is turned off since its formulation is not appropriate for vertical motions stronger than 1 m s−1, and the strong convection in this case leads to vertical motion as strong as 10 m s−1. The physical parameterizations are thus not adequate for fully simulating the precipitation, but are nevertheless adequate for testing the model dynamics. The 14-h forecasts are valid at 0200 UTC 8 May 1995, and the specific total cloud water (including precipitation) at the level η = 0.844 is computed for subjective comparison with the observations shown in Fig. 5, which corresponds to precipitation at a height of approximately 1.5 km.\n\nFigure 7a presents the 14-h hydrostatic forecast of the specific total cloud water at the level η = 0.844. The position of the hydrostatically forecast squall line is nearly perfect, although the convective line is slightly distorted in the middle section with relatively weak and scattered precipitation. Figure 7b shows a vertical cross section of the 14-h hydrostatic forecast of the total cloud water across the squall line, along the arrow plotted in Fig. 7a. The shape of the cloud (Fig. 7b) is reasonably well simulated with a prominent anvil in front of the convective line, although the cloud above the convective line is not quite connected to the cloud over the stratiform region.\n\nFigure 8a shows the 14-h nonhydrostatic forecast of the total cloud water at the level η = 0.844, and Fig. 8b shows a vertical cross section across the squall line along the same arrow shown in both Figs. 7a and 8a. Comparing the nonhydrostatic forecast (Fig. 8a) to the observations (Fig. 5) and to the hydrostatic forecast (Fig. 7a), it is seen that the position of the forecasted squall line remains nearly perfect, and the slight distortion of the convective line in the middle section is improved in the nonhydrostatic simulation. The convection in the middle section of the nonhydrostatic simulation is stronger than that of the hydrostatic one, and the squall line is better defined in the nonhydrostatic simulation. In addition, the nonhydrostatic precipitation pattern (Fig. 8a) resembles the radar observations (Fig. 5) slightly better than the hydrostatic one (Fig. 7a) does, with a better resolved stratiform precipitation band in the southern section of the squall line. The shape of the cloud is also improved in the nonhydrostatic simulation (Fig. 8b) inasmuch as the convective clouds are better connected and the stratiform region is more clearly separated from the convective line, reflecting a stronger inflow from the lower boundary in the nonhydrostatic integration. The simulated stratiform regions (Figs. 7a and 8a) are not as wide as in the observations (Fig. 5), which may be attributed to the coarse initial analysis and the inadequacies of the physical parameterizations.\n\nFigure 9 presents a vertical cross section in the frontal region, between A and B of Fig. 8b of the 14-h nonhydrostatic forecast of the vertical motion (ωdp/dt) and the dimensionless nonhydrostatic index (μ). The mechanism that drives the eastward movement of the convective line is well illustrated with a shift of the maximum convection created by the upward acceleration immediately in front of the convective line, and downward acceleration right behind the convective line. During the integration the vertical acceleration () reaches a maximum absolute value of about 0.1 m s−2, but the nonhydrostatic effects are however quite localized horizontally, being confined to areas of strong convection.\n\nFinally, the maximum vertical CFL number is 2.7 during the nonhydrostatic integration, while the hydrostatic integration attains the much larger value of 6.1, indicating that the strong vertical wind is not properly treated by the hydrostatic dynamics.\n\n## 4. Conclusions\n\nThe hydrostatic formulation of Côté et al. (1998b) has been generalized to include nonhydrostatic effects using a terrain-following coordinate based on Laprise's (1992) hydrostatic pressure. The new version costs approximately 10% more than the hydrostatic one, and the efficiency in integrations performed to date is well maintained in the nonhydrostatic model by the use of the relatively large time steps permitted by the (almost) fully implicit semi-Lagrangian discretization.\n\nResults indicate that for large- and synoptic-scale flow the nonhydrostatic dynamics of the GEM model is highly consistent with that of its hydrostatic subset. For mesoscale flows, the impact of representing nonhydrostatic effects is stronger, and appears physically realistic, despite some inadequacies of the physical parameterizations. The thoroughness of this assessment is however limited by the absence of verifying mesoscale analyses.\n\nDevelopment is continuing on the GEM forecasting system and, for example, the GEM model is now coupled to state-of-the-art microphysics packages, making it a powerful tool for mesoscale case studies in an operational context. Nevertheless much work remains to be done, particularly on rigorous testing of the model's performance for strongly nonhydrostatic flows. One aspect is model validation against known analytic or numerically converged solutions. Another is the model's efficiency and robustness in the strongly nonhydrostatic regime. It remains to be demonstrated that sufficiently large time steps can be used to offset the possible increased cost (particularly in the presence of steep terrain) of iterating the Helmholtz solver and nonlinear terms to an adequate level of convergence—to accomplish this, thorough experimentation will need to be performed using a quantitative convergence measure.\n\n## Acknowledgments\n\nThe first author acknowledges the financial support of the Centre de Recherche en Calcul Appliqué, and the support of RPN's programming section.\n\nThanks are due to Dr. Stéphane Belair for providing the VORTEX data and for his advice on physical parametrizations, and to Yves Chartier for his expert final touch to the artwork. We are also indebted to Prof. René Laprise for many fruitful discussions in the initial phase of this project.\n\n## REFERENCES\n\n• Benoit, R., M. Desgagné, P. Pellerin, S. Pellerin, Y. Chartier, and S. Desjardins, 1997: The Canadian MC2: A semi-Lagrangian, semi-implicit wideband atmospheric model suited for finescale process studies and simulation. Mon. Wea. Rev, 125 , 23822415.\n\n• Export Citation\n• Bluestein, H. B., E. Rasmussen, R. Davies-Jones, R. Wakimoto, and M. L. Weisman, 1998: VORTEX Workshop Summary, 2–3 December 1997, Pacific Grove, California. Bull. Amer. Meteor. Soc, 79 , 13971400.\n\n• Export Citation\n• Bubnova, R., G. Hello, P. Bénard, and J-F. Geleyn, 1994: An efficient alternative to z-coordinate for compressible flow over orography: Use of hydrostatic pressure as vertical coordinate in a complete NWP mesoscale model. Preprints, 10th Conf. on Numerical Weather Prediction, Portland, OR, Amer. Meteor. Soc., 35–37.\n\n• Export Citation\n• Bubnova, R., G. Hello, P. Bénard, and J-F. Geleyn, 1995: Integration of the fully elastic equations cast in hydrostatic pressure terrain-following coordinate in the framework of the ARPEGE/Aladin NWP system. Mon. Wea. Rev, 123 , 515535.\n\n• Export Citation\n• Côté, J., and A. Staniforth, 1988: A two-time-level semi-Lagrangian semi-implicit scheme for spectral models. Mon. Wea. Rev, 116 , 20032012.\n\n• Export Citation\n• Côté, J., and A. Staniforth, 1990: An accurate and efficient finite-element global model of the shallow-water equations. Mon. Wea. Rev, 118 , 27072717.\n\n• Export Citation\n• Côté, J., M. Roch, A. Staniforth, and L. Fillion, 1993: A variable-resolution semi-Lagrangian finite-element global model of the shallow-water equations. Mon. Wea. Rev, 121 , 231243.\n\n• Export Citation\n• Côté, J., S. Gravel, M. Roch, A. Patoine, and A. Staniforth, 1994: A non-hydrostatic variable-resolution global model of the atmosphere. Preprints, 10th Conf. on Numerical Weather Prediction, Portland, OR, Amer. Meteor. Soc., 171–172.\n\n• Export Citation\n• Côté, J., J-G. Desmarais, S. Gravel, A. Méthot, A. Patoine, M. Roch, and A. Staniforth, 1998a: The operational CMC–MRB Global Environmental Multiscale (GEM) model. Part II: Results. Mon. Wea. Rev, 126 , 13971418.\n\n• Export Citation\n• Côté, J., S. Gravel, A. Méthot, A. Patoine, M. Roch, and A. Staniforth, 1998b: The operational CMC–MRB Global Environmental Multiscale (GEM) model. Part I: Design considerations and formulation. Mon. Wea. Rev, 126 , 13731395.\n\n• Export Citation\n• Cullen, M. J. P., D. Salmond, and P. Smolarkiewicz, 2000: Key numerical issues for the future development of the ECMWF numerical model. Proc. ECMWF Workshop on Development in Numerical Methods for Very High Resolution Global Models, Reading, United Kingdom, ECMWF, 183–206.\n\n• Export Citation\n• Daley, R. W., 1988: The normal modes of the spherical non-hydrostatic equations with applications to the filtering of acoustic modes. Tellus, 40A , 96106.\n\n• Export Citation\n• Fillion, L., H. L. Mitchell, H. Ritchie, and A. Staniforth, 1995: The impact of a digital filter finalization technique in a global data assimilation system. Tellus, 47A , 304323.\n\n• Export Citation\n• Fox-Rabinovitz, M., G. Stenchikov, M. Suarez, and L. Takacs, 1997:: A finite-difference GCM dynamical core with a variable resolution stretched grid. Mon. Wea. Rev, 125 , 29432968.\n\n• Export Citation\n• Gill, A. E., 1982: Atmosphere–Ocean Dynamics. Academic Press, 662 pp.\n\n• Kasahara, A., 1974: Various vertical coordinate systems used for numerical weather prediction. Mon. Wea. Rev, 102 , 509522.\n\n• Laprise, R., 1992: The Euler equations of motion with hydrostatic pressure as an independent variable. Mon. Wea. Rev, 120 , 197207.\n\n• Mailhot, J., and Coauthors,. 1998: Scientific description of RPN Physics Library. Version 3.6. Recherche en Prévision Numérique, 188 pp. [Available online at http://www.cmc.ec.gc.ca/rpn/physics/physic98.pdf.].\n\n• Export Citation\n• Phillips, N. A., 1957: A coordinate system having some special advantages for numerical forecasting. J. Meteor, 14 , 184185.\n\n• Qian, J-H., F. H. M. Semazzi, and J. S. Scroggs, 1998: A global nonhydrostatic semi-Lagrangian atmospheric model with topography. Mon. Wea. Rev, 126 , 747771.\n\n• Export Citation\n• Rasmussen, E. N., J. M. Straka, R. Davies-Jones, C. A. Doswell III, F. H. Carr, M. D. Eilts, and D. R. MacGorman, 1994: Verification of the Origins of Rotation in Tornadoes Experiment: VORTEX. Bull. Amer. Meteor. Soc, 75 , 9951006.\n\n• Export Citation\n• Rivest, C., A. Staniforth, and A. Robert, 1994: Spurious resonant response of semi-Lagrangian discretizations to orographic forcing: Diagnosis and solution. Mon. Wea. Rev, 122 , 366376.\n\n• Export Citation\n• Skamarock, W. C., P. K. Smolarkiewicz, and J. B. Klemp, 1997: Preconditioned conjugate-residual solvers for Helmholtz equations in nonhydrostatic models. Mon. Wea. Rev, 125 , 587599.\n\n• Export Citation\n• Tanguay, M., A. Simard, and A. Staniforth, 1989: A three-dimensional semi-Lagrangian scheme for the Canadian regional finite-element forecast model. Mon. Wea. Rev, 117 , 18611871.\n\n• Export Citation\n• Tanguay, M., A. Robert, and R. Laprise, 1990: A semi-implicit semi-Lagrangian fully compressible regional forecast model. Mon. Wea. Rev, 118 , 19701980.\n\n• Export Citation\n• Tremblay, A., A. Glazer, W. Yu, and R. Benoit, 1996: A mixed-phase cloud scheme based on a single prognostic equation. Tellus, 48A , 483500.\n\n• Export Citation\n• Wang, D., M. Xue, V. Wong, and K. K. Droegemeier, 1996: Prediction and simulation of convective storms during VORTEX 95. Preprints, 11th Conf. on Numerical Weather Prediction, Norfolk, VA, Amer. Meteor. Soc., 301–303.\n\n• Export Citation\n• Wang, D., M. Xue, D. Hou, and K. K. Droegemeier, 1998: Midlatitude squall line propagation and structure as simulated by a 3D nonhydrostatic stormscale model. Preprints, 12th Conf. on Numerical Weather Prediction, Phoenix, AZ, Amer. Meteor. Soc., 209–212.\n\n• Export Citation\n• Xue, M., D. Hou, D. Wang, and K. K. Droegemeier, 1998a: Analysis and prediction of convective initiation along a dryline. Preprints, 16th Conf. on Weather Analysis and Forecasting, Phoenix, AZ, Amer. Meteor. Soc., 161–163.\n\n• Export Citation\n• Xue, M., D. Wang, D. Hou, K. Brewster, and K. K. Droegemeier, 1998b:: Prediction of the 7 May 1995 squall lines over the central U.S. with intermittent data assimilation. Preprints, 12th Conf. on Numerical Weather Prediction, Phoenix, AZ, Amer. Meteor. Soc., 191–194.\n\n• Export Citation\n• Yanenko, N. N., 1971: The Method of Fractional Steps. Springer, 160 pp.\n\n## APPENDIX A\n\n### Spatial Discretization\n\n#### Horizontal discretization and finite-differencing\n\nThe scalar grid, the set of points where the scalar fields are defined, is described by giving a list of longitudes (λ) and a list of latitudes (θ), of size NI and NJ, respectively. Thus\nλiθjij\nThe grid points satisfy the constraints", null, "Note that the poles do not belong to the scalar grid. It is convenient to introduce the grid extensions", null, "and grid differences", null, "The grid points of the zonal wind image (U) are located at the same latitudes as the scalar grid points but at longitudes situated halfway between those of the scalar grid. Thus", null, "An extension and differences are also introduced for the U grid:", null, "The grid points of the meridional wind image (V) are located at the same longitudes as the scalar grid points but at latitudes situated halfway between those of the scalar grid. Thus", null, "An extension and differences are similarly introduced for the V grid:", null, "Note that the wind images both vanish at the poles, and we do not need to carry them there.\n\nThe images of the gradient vector of a scalar field ϕ are given by", null, "and each component is computed with a centered difference. This gives for the zonal direction", null, "where the result is on the U grid, likewise for the meridional direction", null, "the result being on the V grid.\nThe horizontal divergence of the wind is given by", null, "and is computed as", null, "which is centered in the case of a uniform grid and in the uniform portion of a variable grid.\nTo compute the horizontal Laplacian of the scalar ϕ\nRa22ϕ,\nthe discrete gradient and divergence operators are applied on ϕ in succession giving\n(θ)(λ)R(θ)λλθθ(λ)ϕ,\nwhere", null, "with a normalization chosen such that all the matrices are symmetric.\n\n#### Coriolis terms\n\nCubic Lagrange interpolation is used to obtain V on the U grid and U on the V grid for the Coriolis terms. The wind images U and V are coupled by the Coriolis terms so", null, "where fU and fV are the U-grid and V-grid Coriolis parameter, respectively, and IntU and IntV are the cubic Lagrange interpolators to the U grid and V grid, respectively.\nThe decoupling of the two wind images required by the elimination procedure [cf. (B.8)] is done with preconditioned Richardson iterations. Thus", null, "where f*2U and f*2V are relaxation parameters taken here as f2U and f2V, respectively. The parameter controlling the convergence is ()2 and two iterations are sufficient in practice. This scheme combined with the discrete gradient and divergence operators gives the discrete distorted Laplacian (2f) appearing in (B.18). Thus", null, "#### Vertical discretization and finite-differencing\n\nThere is no staggering of the variables in the vertical, and the equations where a vertical derivative appears are discretized layer by layer with a centered approximation. For example (B.9) is discretized as", null, "where NK is the number of levels. The above gives an implicit system of equations, which completed by the boundary conditions (2.15) is invertible. This is the same procedure as in Tanguay et al. (1989) and Côté et al. (1998b) but applied here to the nonhydrostatic equation set.\nThe discrete representation, including the boundary conditions, of 𝗥 = L(L + 1)𝗣 appearing in (B.18) is\nZRZZP,\nwhere", null, "", null, "## APPENDIX B\n\n### Linearization and Derivation of the 3D Elliptic-Boundary-Value Problem\n\nThe linearization and the derivation of the 3D EBV problem are outlined here. The derivation is in continuous spatial form to simplify the development, but it is relatively straightforward to obtain the discretized form.\n\nThe set of nonlinear equations resulting from the time discretization can be written as", null, "where τ = (1 + 2ε)Δt/2.\nFirst, ϕ is split into a reference part plus a perturbation:\nϕϕZϕSϕ\nLinearization then proceeds with respect to the following set of variables:\nϕVHw,Żsq\nFor example, the variables Tυ, π, and μ are expanded as", null, "It is convenient to introduce the following auxiliary variables:", null, "from which we obtain", null, "where", null, "Next the nonlinear contributions to the left-hand sides of the prognostic equations are evaluated using the most recent values and put on the right-hand sides along with contributions of known fields, such as ϕS, yielding the following:linearized horizontal momentum and divergence equations,", null, "continuity equation,", null, "linearized thermodynamic equation,", null, "linearized vertical momentum equation,", null, "vertical velocity equation,", null, "In the above 2f is the modified Laplacian (A.20), N denotes the nonlinear contributions from the left-hand side, R′ shows that a contribution from ϕS has been subtracted out, and μϕ is treated as a purely nonlinear term.\n\nAn elliptic boundary value problem for P is obtained by eliminating all of the other variables from (B.8) to (B.12) as follows. Eliminating D between the divergence and continuity equations (B.8) and (B.9) gives", null, "and eliminating w from the linearized vertical momentum and vertical velocity equations (B.11) and (B.12) yields", null, "Eliminating ∂Q/∂Z between (B.14) and the linearized thermodynamic equation (B.10) gives", null, "Equation (B.15) is then used to eliminate X + Q from (B.14) to obtain", null, "where", null, "Finally (B.13) + γ(L + 1)/τ(B.15) + γ/τ (B.16) yields", null, "which, using (A.22)–(A.24) is vertically discretized as", null, "Equation (B.19) is easily decoupled as a set of horizontal problems using the solution of the following auxiliary generalized eigenvalue problem,\nZZψkkZψkkNK,\nand the expansion", null, "## APPENDIX C\n\n### Vertical Velocities at Initial Time\n\nThe computation of the vertical velocities at initial time is given here. The model requires the two vertical velocities Ż and w. As usual Ż is obtained by vertically integrating the continuity equation (2.7) using the boundary conditions (2.15). To obtain w, assume that the integration starts from an hydrostatic and adiabatic state.\n\nKasahara's (1974) form of the continuity equation in the present generalized vertical coordinate gives", null, "and, dividing by ρ, this can be rewritten as", null, "Integrating (C.2) from Z to ZS, and using", null, "", null, "", null, "where", null, "Now from (2.7)", null, "which is integrated again from Z to ZS, making use of the boundary condition (2.15) at the surface, to give", null, "Evaluating (C.8) at the top and applying boundary condition (2.15) then leads to", null, "Inserting (C.9) into (C.8) gives", null, "from which w can be computed by backsubstituting (C.10) and (C.11) into (C.6), then (C.6) into (C.5), and finally (C.5) into (C.4).\nTable 1.\n\nModel configurations for the global, suete and VORTEX cases", null, "Table 2.\n\nStatistics of the global sensitivity test", null, "Table 3.\n\nThe 35 η levels for the suete and VORTEX cases", null, "+\n\nCurrent affiliation: Met Office, Bracknell, Berkshire, United Kingdom.\n\nSave" ]
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https://answers.opencv.org/users/400253/ayushp123/?sort=recent
[ "2020-03-11 12:11:40 -0600 received badge ● Popular Question (source) 2018-11-05 10:38:59 -0600 marked best answer How should a tensorflow model be saved so that it can be loaded in opencv3.3.1 Hi, I am using Tensorflow to train a neural network ( The neural network doesn't contain any variables ). This is my neural network graph in Tensorflow. X = tf.placeholder(tf.float32, [None,training_set.shape],name = 'X') Y = tf.placeholder(tf.float32,[None,training_labels.shape], name = 'Y') A1 = tf.contrib.layers.fully_connected(X, num_outputs = 50, activation_fn = tf.nn.relu) A1 = tf.nn.dropout(A1, 0.8) A2 = tf.contrib.layers.fully_connected(A1, num_outputs = 2, activation_fn = None) cost = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(logits = A2, labels = Y)) global_step = tf.Variable(0, trainable=False) start_learning_rate = 0.001 learning_rate = tf.train.exponential_decay(start_learning_rate, global_step, 100, 0.1, True ) optimizer = tf.train.AdamOptimizer(learning_rate=learning_rate).minimize(cost) I wanted to know how this graph should be saved in tensorflow so as to load it using readNetFromTensorflow 2018-07-08 05:25:10 -0600 asked a question Does having a tf.nn.dropout layer in a tensorflow frozen graph affect dnn::forward Does having a tf.nn.dropout layer in a tensorflow frozen graph affect dnn::forward I wanted to know if frozen tensorflow 2018-06-01 09:57:17 -0600 asked a question How to infer stride, padding information of a convolution layer after importing from a frozen graph (readNetFromTensorFlow) How to infer stride, padding information of a convolution layer after importing from a frozen graph (readNetFromTensorFl 2018-05-17 04:24:47 -0600 asked a question Is it possible to use GPU for forward pass of a tensorflow model in opencv 3.4.1 dnn Is it possible to use GPU for forward pass of a tensorflow model in opencv 3.4.1 dnn Was trying to find a GPU implementa 2018-05-17 04:12:54 -0600 received badge ● Enthusiast 2018-04-13 07:13:09 -0600 received badge ● Student (source) 2018-04-10 07:06:16 -0600 marked best answer How to import a tensorflow model with dropout in opencv Hi, I tried using the advice here -> https://github.com/opencv/opencv/issu.... Saving the checkpoint with dropout and saving the graph without dropout. Here is the issue that I face, along with the name of all the layers read by OpenCV 3.4.1: Conv1/convolution1/Conv2D Conv1/convolution1/Relu Conv1/pooling_1 Conv2/convolution2/Conv2D Conv2/convolution2/Relu Conv2/pooling_2 Conv3/convolution3/Conv2D Conv3/convolution3/Relu Conv3/Reshape/nchw Conv3/Reshape Dense1/fully_connected5/MatMul Dense1/fully_connected5/Relu Dense2/fully_connected6/MatMul Dense2/fully_connected6/Relu Dense2/output_node [ INFO:0] Initialize OpenCL runtime... OpenCV(3.4.1) Error: Backtrace (Can't infer a dim denoted by -1) in computeShapeByReshapeMask, file /home/ayushpandey/opencv/modules/dnn/src/layers/reshape_layer.cpp, line 136 terminate called after throwing an instance of 'cv::Exception' what(): OpenCV(3.4.1) /home/ayushpandey/opencv/modules/dnn/src/layers/reshape_layer.cpp:136: error: (-1) Can't infer a dim denoted by -1 in function computeShapeByReshapeMask Aborted (core dumped) Here is my tensorflow code ->https://pastebin.com/mMgRbHV0 ( Commented lines are uncommented and the lines corresponding to uncommented pool1, pool2 and saver.save is commented for saving graph without dropout ). Then I run the following commands to freeze the graph. python freeze_graph.py --input_graph=./input_graph.pb --input_checkpoint=./with_dropout.ckpt --output_graph=./output_graph.pb --output_node=Dense2/output_node followed by python optimize_for_inference.py --input output_graph.pb --output without_dropout.pb --frozen_graph True --input_names input_node --output_names Dense2/output_node and then I try to load the \"without_dropout.pb\" with OpenCV where I face the issue. 2018-04-10 05:40:44 -0600 commented answer How to import a tensorflow model with dropout in opencv Sorry for wasting your time .... it turns out that I was using the wrong image size .... should I remove this question a 2018-04-10 04:44:26 -0600 commented question How to import a tensorflow model with dropout in opencv Sorry for the mistake .... the input size is [NONE, 250, 250, 1] 2018-04-10 03:36:53 -0600 commented question How to import a tensorflow model with dropout in opencv [NONE, 125, 125, 1] 2018-04-10 03:09:02 -0600 commented question How to import a tensorflow model with dropout in opencv https://drive.google.com/file/d/1fIppXXv_FJEiWKP79xJ92ar0uFO_1iFj/view?usp=sharing 2018-04-09 09:42:02 -0600 asked a question How to import a tensorflow model with dropout in opencv How to import a tensorflow model with dropout in opencv Hi, I tried using the advice here -> https://github.com/openc 2018-04-03 09:05:34 -0600 commented answer Running tensorflow graph through OpenCV gives different result Should I close this question then .... since its an issue of using the latest version?? 2018-04-03 08:45:39 -0600 commented answer Running tensorflow graph through OpenCV gives different result What version should I use ... 3.3 or 3.4 ?? 2018-04-03 08:41:41 -0600 commented answer Running tensorflow graph through OpenCV gives different result Ohh .... thank you for the response :) .... will update OpenCV then. 2018-04-03 08:18:33 -0600 commented answer Running tensorflow graph through OpenCV gives different result @dkurt .... here is the link -> https://drive.google.com/drive/folders/16nWtIdXJ4hjBJLBO3FABKZScfwXCyoRz?usp=sharing 2018-04-03 07:49:04 -0600 commented answer Running tensorflow graph through OpenCV gives different result @dkurt ... its not working ... I checked the model midway and saw the values improved and thought that the problem got s 2018-04-03 07:46:57 -0600 received badge ● Critic (source) 2018-04-03 05:15:57 -0600 commented answer Running tensorflow graph through OpenCV gives different result Your answer solved it ..... initially I was saving using freeze_graph.py from tensorflow .... I saved the model as an in 2018-04-03 05:07:47 -0600 marked best answer Running tensorflow graph through OpenCV gives different result I am trying to run an single channel image of size = ( 125, 125 ) through a frozen tensorflow graph. The result that I am expecting is a vector which is close to [ 125, 131, 203, 203 ]. My Tensorflow Graph is as follows -> https://pastebin.com/tDw3kTWw OpenCV code that I am using for running the graph: Mat image = imread(\"0_1_125_131_203.png\", CV_8UC1); Mat blob = cv::dnn::blobFromImage(image); cv::dnn::Net net = cv::dnn::readNetFromTensorflow(\"output_graph.pb\"); net.setInput(blob, \"input_node\"); Mat result = net.forward(\"Dense4/fully_connected6/MatMul\"); cout << result << endl; The result that I get using OpenCV forward pass is [47.357735, 49.290573, 81.015984, 87.777328]. This is the Tensorflow code that I am using to run the forward pass: import cv2 import numpy as np import tensorflow as tf import argparse def load_graph(frozen_graph_filename): with tf.gfile.GFile(frozen_graph_filename, \"rb\") as f: graph_def = tf.GraphDef() graph_def.ParseFromString(f.read()) with tf.Graph().as_default() as graph: tf.import_graph_def(graph_def, name=\"prefix\") return graph image = cv2.imread(\"0_1_125_131_203.png\", cv2.CV_8UC1) a = np.asarray(image[:,:]) a = np.reshape(a, [1,125,125,1]) parser = argparse.ArgumentParser() parser.add_argument(\"--frozen_model_filename\", default=\"output_graph.pb\", type=str, help=\"Frozen model file to import\") args = parser.parse_args() graph = load_graph(args.frozen_model_filename) x = graph.get_tensor_by_name('prefix/input_node:0') y = graph.get_tensor_by_name('prefix/Dense4/fully_connected6/BiasAdd:0') # We launch a Session with tf.Session(graph=graph) as sess: y_out = sess.run( y, feed_dict={ x: a }) print(\"Result\", y_out) The result that I am getting with tensorflow is relatively quite closer to the actual answer i.e. [[ 139.59773254 135.82391357 217.75576782 214.71946716]]. I am confused as to why there are separate results for after running the same graph. 2018-04-03 03:30:52 -0600 commented answer Running tensorflow graph through OpenCV gives different result Really sorry for wasting your time with wrong edits @dkurt. 2018-04-03 03:30:24 -0600 edited question Running tensorflow graph through OpenCV gives different result Running tensorflow graph through OpenCV gives different result I am trying to run an single channel image of size = ( 12 2018-04-03 03:29:52 -0600 commented answer Running tensorflow graph through OpenCV gives different result I apologize for the wrong tensorflow code @dkurt ... the tensorflow code also gets the image of size ( 125, 125 ) 2018-04-03 03:16:53 -0600 edited question Running tensorflow graph through OpenCV gives different result Running tensorflow graph through OpenCV gives different result I am trying to run an single channel image of size = ( 12 2018-04-03 03:15:35 -0600 commented answer Running tensorflow graph through OpenCV gives different result I apologize for the wrong tensorflow code @dkurt ... the tensorflow code resizes the image first to ( 125, 125 ) 2018-04-03 03:15:02 -0600 commented answer Running tensorflow graph through OpenCV gives different result I apologize for the wrong tensorflow code @dkurt ... the tensorflow code reshapes it to ( 125, 125 ) 2018-04-03 03:13:58 -0600 edited question Running tensorflow graph through OpenCV gives different result Running tensorflow graph through OpenCV gives different result I am trying to run an single channel image of size = ( 12 2018-04-03 02:43:29 -0600 commented answer Running tensorflow graph through OpenCV gives different result @dkurt .... Have made the edits .... I found adding tensorflow code to the question quite difficilt, hence have added th 2018-04-02 09:18:33 -0600 commented answer Running tensorflow graph through OpenCV gives different result dkurt .... Have made the edits .... I found adding tensorflow code to the question quite difficilt, hence have added the 2018-04-02 09:16:57 -0600 edited question Running tensorflow graph through OpenCV gives different result How to set a 1 channel image as an input for cv::dnn::net I am trying to run an single channel image of size = ( 125, 1 2018-04-02 08:45:22 -0600 edited question Running tensorflow graph through OpenCV gives different result How to set a 1 channel image as an input for cv::dnn::net I am trying to run an single channel image of size = ( 125, 1 2018-04-02 07:39:41 -0600 commented answer Running tensorflow graph through OpenCV gives different result Thanks for the response dkurt .... I have added the graph reference on the stack overflow link .... Should I add another 2018-04-02 05:29:59 -0600 commented answer Running tensorflow graph through OpenCV gives different result Thank you for pointing out the error. But I am still facing issue while running the image through OpenCV. I have asked t 2018-04-02 05:28:59 -0600 edited question Running tensorflow graph through OpenCV gives different result How to set a 1 channel image as an input for cv::dnn::net I am trying to run an single channel image of size = ( 125, 1 2018-04-02 00:51:50 -0600 edited question Running tensorflow graph through OpenCV gives different result How to set a 1 channel image as an input for cv::dnn::net I am trying to run an single channel image of size = ( 125, 1 2018-04-02 00:51:50 -0600 received badge ● Editor (source) 2018-04-02 00:49:02 -0600 asked a question Running tensorflow graph through OpenCV gives different result How to set a 1 channel image as an input for cv::dnn::net I am trying to run an single channel image of size = ( 125, 1" ]
[ null ]
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