id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__OAUwle2DrkqXcHIg
|
Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves one-fourth of his income, find the ratio of their monthly savings?
A. 3 : 5 Choose the correct choice from the following answers:
A) 3 : 9 B) 3 : 10 C) 3 : 21 D) 3 : 12 E) 3 : 14
|
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) / 4</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(3/8) / (5/4)</gadget>
<output>3/10 = around 0.3</output>
<result>B</result>
|
B
| 0.3 |
Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves one-fourth of his income, find the ratio of their monthly savings?
A. 3 : 5
|
{
"A": "3 : 9",
"B": "3 : 10",
"C": "3 : 21",
"D": "3 : 12",
"E": "3 : 14"
}
|
divide(divide(divide(3, 2), const_4), divide(5, const_4))
|
divide(n2,n3)|divide(n1,const_4)|divide(#0,const_4)|divide(#2,#1)
|
let the monthly incomes of amar and bhuvan be 6 x and 5 x respectively . let the monthly expenditure of amar and bhuvan be 3 y and 2 y respectively . savings of bhuvan every month = 1 / 4 ( 5 x ) = ( his income ) - ( his expenditure ) = 5 x - 2 y . = > 5 x = 20 x - 8 y = > y = 15 x / 8 . ratio of savings of amar and bhuvan = 6 x - 3 y : 1 / 4 ( 5 x ) = 6 x - 3 ( 15 x / 8 ) : 5 x / 4 = 3 x / 8 : 5 x / 4 = 3 : 10 . answer : option b
|
general
|
math_qa__uLu0PfTM2HJWmZ3p
|
If 3 cm of a pencil is purple, 2 cm of the remaining is black and the remaining 1 cm is blue, what is the total length of the pencil? Choose the correct choice from the following options:
A) 6 B) 3 C) 1 D) 4 E) 2
|
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>A</result>
|
A
| 6 |
If 3 cm of a pencil is purple, 2 cm of the remaining is black and the remaining 1 cm is blue, what is the total length of the pencil?
|
{
"A": "6",
"B": "3",
"C": "1",
"D": "4",
"E": "2"
}
|
add(add(3, 2), 1)
|
add(n0,n1)|add(n2,#0)
|
answer is a ) 6
|
physics
|
math_qa__bajKjuvWWmVtgKxL
|
A car covers a distance of 624 km in 2 2/5 hours. Find its speed? Choose the correct answer:
A) 104 kmph B) 194 kmph C) 109 kmph D) 260 kmph E) 271 kmph
|
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">2 + (2/5)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">624 / (12/5)</gadget>
<output>260</output>
<result>D</result>
|
D
| 260 |
A car covers a distance of 624 km in 2 2/5 hours. Find its speed?
|
{
"A": "104 kmph",
"B": "194 kmph",
"C": "109 kmph",
"D": "260 kmph",
"E": "271 kmph"
}
|
divide(624, add(2, divide(2, 5)))
|
divide(n2,n3)|add(n1,#0)|divide(n0,#1)|
|
"624 / 2 2 / 5 = 260 kmph answer : d"
|
physics
|
math_qa__l64c62OQ0GbR8W2b
|
Find the perimetri of trapezium with sides 4,6,12 and distance between two parallel side is 3. Choose one.
A) 27 B) 26 C) 28 D) 25 E) 24
|
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">16 - 9</gadget>
<output>7</output>
<gadget id="calculator">7 ** (1/2)</gadget>
<output>sqrt(7) = around 2.645751</output>
<gadget id="calculator">6 + (sqrt(7))</gadget>
<output>sqrt(7) + 6 = around 8.645751</output>
<gadget id="calculator">12 - (sqrt(7) + 6)</gadget>
<output>6 - sqrt(7) = around 3.354249</output>
<gadget id="calculator">(6 - sqrt(7)) ** 2</gadget>
<output>(6 - sqrt(7))**2 = around 11.250984</output>
<gadget id="calculator">((6 - sqrt(7))**2) + 9</gadget>
<output>9 + (6 - sqrt(7))**2 = around 20.250984</output>
<gadget id="calculator">(9 + (6 - sqrt(7))**2) ** (1/2)</gadget>
<output>sqrt(9 + (6 - sqrt(7))**2) = around 4.500109</output>
<gadget id="calculator">10 + (sqrt(9 + (6 - sqrt(7))**2))</gadget>
<output>sqrt(9 + (6 - sqrt(7))**2) + 10 = around 14.500109</output>
<gadget id="calculator">(sqrt(9 + (6 - sqrt(7))**2) + 10) + 12</gadget>
<output>sqrt(9 + (6 - sqrt(7))**2) + 22 = around 26.500109</output>
<result>A</result>
|
A
| 27 |
Find the perimetri of trapezium with sides 4,6,12 and distance between two parallel side is 3.
|
{
"A": "27",
"B": "26",
"C": "28",
"D": "25",
"E": "24"
}
|
add(add(add(4, add(3, 3)), sqrt(add(power(subtract(multiply(4, 3), add(add(3, 3), sqrt(subtract(power(4, const_2), power(3, const_2))))), const_2), power(3, const_2)))), multiply(4, 3))
|
add(n2,n2)|multiply(n0,n2)|power(n0,const_2)|power(n2,const_2)|add(n0,#0)|subtract(#2,#3)|sqrt(#5)|add(#0,#6)|subtract(#1,#7)|power(#8,const_2)|add(#9,#3)|sqrt(#10)|add(#4,#11)|add(#12,#1)
|
1 / 2 * ( 6 + 12 ) * 3 = 27 answer : a
|
physics
|
math_qa__rIqyhyjemsJibc7i
|
A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 6 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B? Choose one: A) 12 B) 9 C) 15 D) 21 E) 30
|
<gadget id="calculator">0.06 * 6</gadget>
<output>0.36</output>
<gadget id="calculator">0.6 - 0.36</gadget>
<output>0.24</output>
<gadget id="calculator">0.08 - 0.06</gadget>
<output>0.02</output>
<gadget id="calculator">0.24 / 0.02</gadget>
<output>12</output>
<result>A</result>
|
A
| 12 |
A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 6 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B?
|
{
"A": "12",
"B": "9",
"C": "15",
"D": "21",
"E": "30"
}
|
divide(subtract(0.60, multiply(0.06, 6)), subtract(0.08, 0.06))
|
multiply(n1,n2)|subtract(n3,n2)|subtract(n0,#0)|divide(#2,#1)|
|
"let the duration , in minutes , for which the company charges the same under plan a and plan b be t minutes . then under plan a the cost would be $ 0.6 + 0.06 ( t - 6 ) and under plan b the cost would be $ 0.08 t . we want these amount to be equal : 0.6 + 0.06 ( t - 6 ) = 0.08 t - - > 60 + 6 ( t - 6 ) = 8 t - - > t = 12 . answer : a ."
|
other
|
math_qa__VH1PFHxeaJtTgZ0h
|
Solution X is 10% chemical A and 90% chemical B by volume. Solution Y is 20% chemical A and 80% chemical B by volume. If a mixture of X and Y is 12% chemical A, what percent of the mixture is Solution X?
Pick one
A) 80 % B) 75 % C) 70 % D) 65 % E) 60 %
|
<gadget id="calculator">20 - 12</gadget>
<output>8</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>A</result>
|
A
| 80 |
Solution X is 10% chemical A and 90% chemical B by volume. Solution Y is 20% chemical A and 80% chemical B by volume. If a mixture of X and Y is 12% chemical A, what percent of the mixture is Solution X?
|
{
"A": "80 %",
"B": "75 %",
"C": "70 %",
"D": "65 %",
"E": "60 %"
}
|
multiply(divide(divide(subtract(20, 12), subtract(12, 10)), add(divide(subtract(20, 12), subtract(12, 10)), const_1)), const_100)
|
subtract(n2,n4)|subtract(n4,n0)|divide(#0,#1)|add(#2,const_1)|divide(#2,#3)|multiply(#4,const_100)|
|
"the volume of the mixture be x + y . 0.1 x + 0.2 y = 0.12 ( x + y ) x = 4 y x / ( x + y ) = 4 / 5 = 80 % . the answer is a ."
|
gain
|
math_qa__zmcZ78Ipl42Z0b6N
|
The flowerman sale, all of the prices of the flowers sold were different. If the price of a radio sold at the flowerman sale was both the 17th highest price and the 42th lowest price among the prices of the slowers sold, how many flowers were sold at the flowerman sale?
Choose one
A) 38 B) 34 C) 58 D) 63 E) 73
|
<gadget id="calculator">42 + 17</gadget>
<output>59</output>
<gadget id="calculator">59 - 1</gadget>
<output>58</output>
<result>C</result>
|
C
| 58 |
The flowerman sale, all of the prices of the flowers sold were different. If the price of a radio sold at the flowerman sale was both the 17th highest price and the 42th lowest price among the prices of the slowers sold, how many flowers were sold at the flowerman sale?
|
{
"A": "38",
"B": "34",
"C": "58",
"D": "63",
"E": "73"
}
|
subtract(add(42, 17), const_1)
|
add(n0,n1)|subtract(#0,const_1)
|
16 + 41 + 1 = 58 answer : c
|
other
|
math_qa__8qXzIulns3PcMjOV
|
Milk contains 5% water.What quantity of pure milk should be added to 10 litres of milk to reduce this 2%? Options.
A) 15 litres B) 16 litres C) 17 litres D) 25 litres E) 35 litres
|
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/2) / (1/50)</gadget>
<output>25</output>
<gadget id="calculator">25 - 10</gadget>
<output>15</output>
<result>A</result>
|
A
| 15 |
Milk contains 5% water.What quantity of pure milk should be added to 10 litres of milk to reduce this 2%?
|
{
"A": "15 litres",
"B": "16 litres",
"C": "17 litres",
"D": "25 litres",
"E": "35 litres"
}
|
subtract(divide(multiply(divide(5, const_100), 10), divide(2, const_100)), 10)
|
divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|divide(#2,#1)|subtract(#3,n1)
|
present ration of milk to water is 95 : 5 amount of milk is 10 litres hence , pure milk content is 9.5 litre and water content is 0.5 litres now , we should not disturb the water content so , 0.5 litres of water is equivalent to 2 % so 100 % mixture is : ( 0.5 / 2 ) * 100 = 25 litre thus , milk should be added = 25 - 10 = 15 litres of pure milk answer : a
|
gain
|
math_qa__bogaJzyMM4Lptfdg
|
Dan's age after 18 years will be 8 times his age 3 years ago. What is the present age of Dan? Choose the correct choice from the following options: A) 4 B) 6 C) 8 D) 10 E) 12
|
<gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">18 + 24</gadget>
<output>42</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">42 / 7</gadget>
<output>6</output>
<result>B</result>
|
B
| 6 |
Dan's age after 18 years will be 8 times his age 3 years ago. What is the present age of Dan?
|
{
"A": "4",
"B": "6",
"C": "8",
"D": "10",
"E": "12"
}
|
divide(add(18, multiply(3, 8)), subtract(8, const_1))
|
multiply(n1,n2)|subtract(n1,const_1)|add(n0,#0)|divide(#2,#1)|
|
"let dan ' s present age be x . x + 18 = 8 ( x - 3 ) 7 x = 42 x = 6 the answer is b ."
|
general
|
math_qa__LhdJKOPG2gNPRZK2
|
Solution P is 20 percent lemonade and 80 percent carbonated water by volume; solution Q is 45 percent lemonade and 55 percent carbonated water by volume. If a mixture of PQ contains 67.5% percent carbonated water, what percent of the volume of the mixture is P? Select: A) 25 % B) 40 % C) 50 % D) 60 % E) 75 %
|
<gadget id="calculator">67.5 / 100</gadget>
<output>0.675</output>
<gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">0.675 - (11/20)</gadget>
<output>0.125</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) - 0.675</gadget>
<output>0.125</output>
<gadget id="calculator">0.125 + 0.125</gadget>
<output>0.25</output>
<gadget id="calculator">0.125 / 0.25</gadget>
<output>0.5</output>
<gadget id="calculator">0.5 * 100</gadget>
<output>50</output>
<result>C</result>
|
C
| 50 |
Solution P is 20 percent lemonade and 80 percent carbonated water by volume; solution Q is 45 percent lemonade and 55 percent carbonated water by volume. If a mixture of PQ contains 67.5% percent carbonated water, what percent of the volume of the mixture is P?
|
{
"A": "25 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "75 %"
}
|
multiply(divide(subtract(divide(67.5, const_100), divide(55, const_100)), add(subtract(divide(67.5, const_100), divide(55, const_100)), subtract(divide(80, const_100), divide(67.5, const_100)))), const_100)
|
divide(n4,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(#2,#0)|add(#3,#4)|divide(#3,#5)|multiply(#6,const_100)|
|
"67.5 % is 12.5 % - points below 80 % and 12.5 % - points above 55 % . so the ratio of solution p to solution q is 1 : 1 . mixture p is 1 / 2 = 50 % of the volume of mixture pq . the answer is c ."
|
gain
|
math_qa__JfnoTVnP6NdDxvbS
|
At what rate percent per annum will a sum of money double in 7 years. Choose the most appropriate option
A) 12.5 % B) 13.5 % C) 14.2 % D) 14.5 % E) 21.5 %
|
<gadget id="calculator">100 / 7</gadget>
<output>100/7 = around 14.285714</output>
<result>C</result>
|
C
| 14.2 |
At what rate percent per annum will a sum of money double in 7 years.
|
{
"A": "12.5 %",
"B": "13.5 %",
"C": "14.2 %",
"D": "14.5 %",
"E": "21.5 %"
}
|
divide(const_100, 7)
|
divide(const_100,n0)|
|
"let principal = p , then , s . i . = p and time = 8 years rate = [ ( 100 x p ) / ( p x 8 ) ] % = 14.2 % per annum . answer : c"
|
gain
|
math_qa__fhLHW1TK61YKQ3tK
|
Sum of the squares of 3 no.'s is 99 and the sum of their products taken two at a time is 131. Find the sum? Choose the correct answer
A) 20 B) 24 C) 19 D) 28 E) 30
|
<gadget id="calculator">131 * 2</gadget>
<output>262</output>
<gadget id="calculator">262 + 99</gadget>
<output>361</output>
<gadget id="calculator">361 ** (1/2)</gadget>
<output>19</output>
<result>C</result>
|
C
| 19 |
Sum of the squares of 3 no.'s is 99 and the sum of their products taken two at a time is 131. Find the sum?
|
{
"A": "20",
"B": "24",
"C": "19",
"D": "28",
"E": "30"
}
|
sqrt(add(multiply(131, const_2), 99))
|
multiply(n2,const_2)|add(n1,#0)|sqrt(#1)|
|
"( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 99 + 2 * 131 a + b + c = √ 361 = 19 c"
|
general
|
math_qa__Q0YeRcc8K4bAx2F1
|
A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.2 per sq m? Select the correct option:
A) 2288 B) 2779 C) 2779 D) 3900 E) 2600
|
<gadget id="calculator">80 + 60</gadget>
<output>140</output>
<gadget id="calculator">140 - 10</gadget>
<output>130</output>
<gadget id="calculator">130 * 10</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 * 2</gadget>
<output>2_600</output>
<result>E</result>
|
E
| 2,600 |
A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.2 per sq m?
|
{
"A": "2288",
"B": "2779",
"C": "2779",
"D": "3900",
"E": "2600"
}
|
multiply(multiply(subtract(add(80, 60), 10), 10), 2)
|
add(n0,n1)|subtract(#0,n2)|multiply(n2,#1)|multiply(n3,#2)|
|
"area = ( l + b â € “ d ) d ( 80 + 60 â € “ 10 ) 10 = > 1300 m 2 1300 * 2 = rs . 2600 answer : e"
|
geometry
|
math_qa__enxfgiangMS9ynvG
|
The ratio of ducks and frogs in a pond is 37 : 39 respectively. The average number of ducks and frogs in the pond is 150. What is the number of frogs in the pond ? Pick one: A) 148 B) 154 C) 156 D) 144 E) none
|
<gadget id="calculator">37 + 39</gadget>
<output>76</output>
<gadget id="calculator">76 + 2</gadget>
<output>78</output>
<gadget id="calculator">78 / 2</gadget>
<output>39</output>
<gadget id="calculator">150 / 39</gadget>
<output>50/13 = around 3.846154</output>
<gadget id="calculator">39 * (50/13)</gadget>
<output>150</output>
<result>B</result>
|
B
| 154 |
The ratio of ducks and frogs in a pond is 37 : 39 respectively. The average number of ducks and frogs in the pond is 150. What is the number of frogs in the pond ?
|
{
"A": "148",
"B": "154",
"C": "156",
"D": "144",
"E": "none"
}
|
multiply(39, divide(150, divide(add(add(37, 39), const_2), const_2)))
|
add(n0,n1)|add(#0,const_2)|divide(#1,const_2)|divide(n2,#2)|multiply(n1,#3)|
|
"solution : ratio of ducks and frogs in pond , = 37 : 39 . average of ducks and frogs in pond , = 150 . so , total number of ducks and frogs in the pond , = 2 * 150 = 300 . therefore , number of frogs , = ( 300 * 39 ) / 76 = 154 . answer : option b"
|
general
|
math_qa__ArtIcjaxnAz6nvQ3
|
The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 14000, then find the annual income of A? Pick: A) rs . 420000 B) rs . 180000 C) rs . 201600 D) rs . 470400 E) none of these
|
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">14_000 * (28/25)</gadget>
<output>15_680</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">15_680 * (5/2)</gadget>
<output>39_200</output>
<gadget id="calculator">39_200 * 12</gadget>
<output>470_400</output>
<result>D</result>
|
D
| 470,400 |
The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 14000, then find the annual income of A?
|
{
"A": "rs . 420000",
"B": "rs . 180000",
"C": "rs . 201600",
"D": "rs . 470400",
"E": "none of these"
}
|
multiply(multiply(multiply(14000, add(const_1, divide(12, const_100))), divide(5, 2)), 12)
|
divide(n0,n1)|divide(n2,const_100)|add(#1,const_1)|multiply(n3,#2)|multiply(#0,#3)|multiply(n2,#4)|
|
"b ' s monthly income = 14000 * 112 / 100 = rs . 15680 b ' s monthly income = 2 parts - - - - > rs . 15680 a ' s monthly income = 5 parts = 5 / 2 * 15680 = rs . 39200 a ' s annual income = rs . 39200 * 12 = rs . 470400 answer : d"
|
other
|
math_qa__f5U0WAyPAeAEX9q0
|
In the rectangular coordinate system, points (2, 0) and (– 2, 0) both lie on circle C. What is the maximum possible value of the radius of C ? Choices:
A) 2 B) 4 C) 8 D) 16 E) none of the above
|
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<result>A</result>
|
A
| 2 |
In the rectangular coordinate system, points (2, 0) and (– 2, 0) both lie on circle C. What is the maximum possible value of the radius of C ?
|
{
"A": "2",
"B": "4",
"C": "8",
"D": "16",
"E": "none of the above"
}
|
sqrt(power(2, const_2))
|
power(n0,const_2)|sqrt(#0)|
|
"the answer is a it takes 3 distinct points to define a circle . only 2 are given here . the two points essentially identify a single chord of the circle c . since no other information is provided , however , the radius of the circle can essentially be anything . all this information tell us is that the radius isgreater 2"
|
geometry
|
math_qa__8bnJjsCkRyAqJnBw
|
If Ram and gohul can do a job in 10 days and 15 days independently, How many days would they take to complete the same job working simultaneously? Select the correct option.
A) 10 B) 5 C) 8 D) 6 E) 13
|
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result>
|
D
| 6 |
If Ram and gohul can do a job in 10 days and 15 days independently, How many days would they take to complete the same job working simultaneously?
|
{
"A": "10",
"B": "5",
"C": "8",
"D": "6",
"E": "13"
}
|
inverse(add(divide(const_1, 10), divide(const_1, 15)))
|
divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)
|
if total work is x . ram working rate = x / 10 per day . working rate of gohul = x / 15 per day . rate of work = ( x / 10 ) + ( x + 15 ) = 30 x / 5 x = 6 days the answer is option d
|
physics
|
math_qa__dxQZYYIEJM2yBhZE
|
Trapezoid JKLM in the x-y plane has coordinates J = (–2, –4), K = (–2, 2), L = (6, 8), and M = (6, –4). What is its perimeter? Choose the most appropriate option:
A) 34
B) 36
C) 38
D) 40
E) ( f ) 42
|
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">10 + 6</gadget>
<output>16</output>
<gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">16 + 8</gadget>
<output>24</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<result>B</result>
|
B
| 36 |
Trapezoid JKLM in the x-y plane has coordinates J = (–2, –4), K = (–2, 2), L = (6, 8), and M = (6, –4). What is its perimeter?
|
{
"A": "34",
"B": "36",
"C": "38",
"D": "40",
"E": "( f ) 42"
}
|
add(add(add(const_10, add(2, 4)), add(2, 6)), add(8, 4))
|
add(n1,n3)|add(n0,n4)|add(n1,n5)|add(#0,const_10)|add(#3,#1)|add(#4,#2)|
|
"jk = 6 lm = 12 kl = using distance formula 10 jm = using distance formula 8 sum of all is 36 b"
|
physics
|
math_qa__fpxBmFtryrZ2VEXZ
|
a box contains 7 purple , 5 blue and 11 yellow balls . what is the minimum number of tries required to get one blue and one yellow ball ? Choose the correct choice from the following choices
A) 16
B) 17
C) 18
D) 19
E) 20
|
<gadget id="calculator">7 + 11</gadget>
<output>18</output>
<gadget id="calculator">18 + 1</gadget>
<output>19</output>
<result>D</result>
|
D
| 19 |
a box contains 7 purple , 5 blue and 11 yellow balls . what is the minimum number of tries required to get one blue and one yellow ball ?
|
{
"A": "16",
"B": "17",
"C": "18",
"D": "19",
"E": "20"
}
|
add(add(7, 11), const_1)
|
add(n0,n2)|add(#0,const_1)
|
11 yellow + 7 purple + after that we have only one option that is to be blue so answer is 19 answer : d
|
general
|
math_qa__CeRmkgjdccsoIZ9P
|
the length of a rectangular floor is more than its breadth by 200 % . if rs . 361 is required to paint the floor at the rate of rs . 3.00001 / sq m , what would be the length of the floor ? Choose the correct answer.
A) 18 B) 19 C) 20 D) 22 E) 24
|
<gadget id="calculator">361 / 3.00001</gadget>
<output>120.332932</output>
<gadget id="calculator">120.332932 / 3</gadget>
<output>40.110977</output>
<gadget id="calculator">40.110977 ** (1/2)</gadget>
<output>6.333323</output>
<gadget id="calculator">6.333323 * 3</gadget>
<output>18.999969</output>
<result>B</result>
|
B
| 19 |
the length of a rectangular floor is more than its breadth by 200 % . if rs . 361 is required to paint the floor at the rate of rs . 3.00001 / sq m , what would be the length of the floor ?
|
{
"A": "18",
"B": "19",
"C": "20",
"D": "22",
"E": "24"
}
|
multiply(sqrt(divide(divide(361, 3.00001), const_3)), const_3)
|
divide(n1,n2)|divide(#0,const_3)|sqrt(#1)|multiply(#2,const_3)|
|
"let the length and the breadth of the floor be l m and b m respectively . l = b + 200 % of b = l + 2 b = 3 b area of the floor = 361 / 3 = 120.33 sq m l b = 120.33 i . e . , l * l / 3 = 120.33 l ^ 2 = 361 = > l = 19 . b"
|
gain
|
math_qa__PUz0ZH51HMYrU5mx
|
3 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)
Choose one.
A) 12 B) 15 C) 18 D) 36 E) 24
|
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<result>D</result>
|
D
| 36 |
3 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other)
|
{
"A": "12",
"B": "15",
"C": "18",
"D": "36",
"E": "24"
}
|
multiply(factorial(3), factorial(3))
|
factorial(n0)|factorial(n1)|multiply(#0,#1)|
|
the list should be wmwmw . hence , from women 3 ! and men 3 ! , we get ( 3 ! ) ( 3 ! ) = 36 . therefore , the correct answer is d .
|
general
|
math_qa__EqS9ACMFJlZHSZDV
|
Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 12 inches by 15 inches and Jordan's rectangle is 6 inches long, how wide is Jordan's rectangle, in inches? Choose one.
A) 24 B) 26 C) 28 D) 30 E) 32
|
<gadget id="calculator">12 * 15</gadget>
<output>180</output>
<gadget id="calculator">180 / 6</gadget>
<output>30</output>
<result>D</result>
|
D
| 30 |
Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 12 inches by 15 inches and Jordan's rectangle is 6 inches long, how wide is Jordan's rectangle, in inches?
|
{
"A": "24",
"B": "26",
"C": "28",
"D": "30",
"E": "32"
}
|
divide(rectangle_area(12, 15), 6)
|
rectangle_area(n0,n1)|divide(#0,n2)
|
area of first rectangle is 12 * 15 = 180 hence area of second would be 6 x = 180 x x = 30 answer is d
|
geometry
|
math_qa__Qb0hAIVLwtppXkAk
|
The calendar of the year 2080 can be used again in the year? Options
A) 2105 B) 1955 C) 1945 D) 1935 E) 2108
|
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">14 * 2</gadget>
<output>28</output>
<gadget id="calculator">28 + 2_080</gadget>
<output>2_108</output>
<result>E</result>
|
E
| 2,108 |
The calendar of the year 2080 can be used again in the year?
|
{
"A": "2105",
"B": "1955",
"C": "1945",
"D": "1935",
"E": "2108"
}
|
add(multiply(subtract(multiply(const_4, const_4), const_2), const_2), 2080)
|
multiply(const_4,const_4)|subtract(#0,const_2)|multiply(#1,const_2)|add(n0,#2)|
|
"explanation : given year 2080 when divided by 4 , leaves a remainder 0 . note : when remainder is 0 , 28 is added to the given year to get the result . so , 2080 + 28 = 2108 answer : e"
|
gain
|
math_qa__xpYmpAc61V0P1get
|
Sum of 42 odd numbers is? Choose the correct choice from the following options
A) 1764
B) 1774
C) 1784
D) 1794
E) 1754
|
<gadget id="calculator">42 * 2</gadget>
<output>84</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">84 * 21</gadget>
<output>1_764</output>
<result>A</result>
|
A
| 1,764 |
Sum of 42 odd numbers is?
|
{
"A": "1764",
"B": "1774",
"C": "1784",
"D": "1794",
"E": "1754"
}
|
multiply(multiply(42, const_2), divide(42, const_2))
|
divide(n0,const_2)|multiply(n0,const_2)|multiply(#0,#1)|
|
"sum of 1 st n odd no . s = 1 + 3 + 5 + 7 + . . . = n ^ 2 so , sum of 1 st 42 odd numbers = 42 ^ 2 = 1764 answer : a"
|
general
|
math_qa__kr31TfHMTwfEPOLr
|
A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 5,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride? Choose the correct choice from the following options:
A) 1.25 % B) 3.75 % C) 6.25 % D) 6.67 % E) 11.11 %
|
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">10_000 * (1/20)</gadget>
<output>500</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">5 * 1_000</gadget>
<output>5_000</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">5_000 + 500</gadget>
<output>5_500</output>
<gadget id="calculator">10_000 - 5_500</gadget>
<output>4_500</output>
<gadget id="calculator">500 / 4_500</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/9) * 100</gadget>
<output>100/9 = around 11.111111</output>
<result>E</result>
|
E
| 11.11 |
A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 5,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
|
{
"A": "1.25 %",
"B": "3.75 %",
"C": "6.25 %",
"D": "6.67 %",
"E": "11.11 %"
}
|
multiply(divide(multiply(multiply(const_100, const_100), divide(5, const_100)), subtract(multiply(const_100, const_100), add(multiply(add(const_2, const_3), multiply(multiply(add(const_2, const_3), const_2), const_100)), multiply(add(const_2, const_3), const_100)))), const_100)
|
add(const_2,const_3)|divide(n1,const_100)|multiply(const_100,const_100)|multiply(#1,#2)|multiply(#0,const_2)|multiply(#0,const_100)|multiply(#4,const_100)|multiply(#0,#6)|add(#7,#5)|subtract(#2,#8)|divide(#3,#9)|multiply(#10,const_100)
|
the remaining solution will be approximately what percent sodium chloride ? means : what percent of the remaining solution is sodium chloride . now , since the remaining solution is 10,000 - 5,500 = 4,500 gallons and sodium chloride is 500 gallons ( 5 % of initial solution of 10,000 gallons ) then sodium chloride is 500 / 4,500 * 100 = ~ 11.11 % of the remaining solution of 4,500 gallons . answer : e .
|
gain
|
math_qa__Dm2aVpDkqmmNw6wy
|
A larger cube has 8 cubic inch as a volume and in the cube there are 8 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 8 smaller cubes and the surface area of the larger cube, in square inch?
Choose the correct choice from the following:
A) 24 B) 64 C) 81 D) 108 E) 120
|
<gadget id="calculator">1 ** (1/3)</gadget>
<output>1</output>
<gadget id="calculator">6 * (1 ** 2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">8 ** (1/3)</gadget>
<output>2</output>
<gadget id="calculator">6 * (2 ** 2)</gadget>
<output>24</output>
<gadget id="calculator">48 - 24</gadget>
<output>24</output>
<result>A</result>
|
A
| 24 |
A larger cube has 8 cubic inch as a volume and in the cube there are 8 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 8 smaller cubes and the surface area of the larger cube, in square inch?
|
{
"A": "24",
"B": "64",
"C": "81",
"D": "108",
"E": "120"
}
|
subtract(multiply(surface_cube(cube_edge_by_volume(1)), 8), surface_cube(cube_edge_by_volume(8)))
|
cube_edge_by_volume(n2)|cube_edge_by_volume(n0)|surface_cube(#0)|surface_cube(#1)|multiply(n0,#2)|subtract(#4,#3)
|
volume of larger cube = 8 = 2 ^ 3 side of larger cube = 2 volume of smaller cube = 1 - - > side of smaller cube = 1 surface area of larger cube = 6 * 2 ^ 2 = 24 surface area of 27 smaller cubes = 8 * 6 * 1 = 48 difference = 48 - 24 = 24 answer : a
|
geometry
|
math_qa__lpPjBltNzeFbzhbf
|
The distance from Steve's house to work is 20 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?
Choices: A) 5 . B) 10 . C) 14 . D) 15 . E) 20 .
|
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>B</result>
|
B
| 10 |
The distance from Steve's house to work is 20 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?
|
{
"A": "5 .",
"B": "10 .",
"C": "14 .",
"D": "15 .",
"E": "20 ."
}
|
multiply(divide(add(20, divide(20, const_2)), 6), const_2)
|
divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|multiply(#2,const_2)|
|
"time is in the ratio 2 : 1 : : to : fro office therefore , 2 x + 1 x = 6 hrs time take to come back - 2 hrs , distance travelled - 20 km = > speed = 10 kmph b"
|
physics
|
math_qa__YZwbS5NWZsQ4xg9B
|
30 pens and 75 pencils were purchased for 510. If the average price of a pencil was 2.00, find the average price of a pen.
Choose the correct choice from the following answers.
A) 10
B) 11
C) 12
D) can not be determined
E) none of the above
|
<gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">510 - 150</gadget>
<output>360</output>
<gadget id="calculator">360 / 30</gadget>
<output>12</output>
<result>C</result>
|
C
| 12 |
30 pens and 75 pencils were purchased for 510. If the average price of a pencil was 2.00, find the average price of a pen.
|
{
"A": "10",
"B": "11",
"C": "12",
"D": "can not be determined",
"E": "none of the above"
}
|
divide(subtract(510, multiply(75, 2.00)), 30)
|
multiply(n1,n3)|subtract(n2,#0)|divide(#1,n0)|
|
"since average price of a pencil = 2 ∴ price of 75 pencils = 150 ∴ price of 30 pens = ( 510 – 150 ) = 360 ∴ average price of a pen = 360 ⁄ 60 = 12 answer c"
|
general
|
math_qa__ajzWYH2twy8USjHZ
|
A rectangular carpet has an area of 60 sq.m. If its diagonal and longer side together equal 5 times the shorter side, the length of the carpet is: Choose the correct option:
A) 5 m B) 12 m C) 13 m D) 14.5 m E) 15.5 m
|
<gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">600 / 24</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>B</result>
|
B
| 12 |
A rectangular carpet has an area of 60 sq.m. If its diagonal and longer side together equal 5 times the shorter side, the length of the carpet is:
|
{
"A": "5 m",
"B": "12 m",
"C": "13 m",
"D": "14.5 m",
"E": "15.5 m"
}
|
divide(60, sqrt(divide(multiply(60, const_10), subtract(power(5, const_2), const_1))))
|
multiply(n0,const_10)|power(n1,const_2)|subtract(#1,const_1)|divide(#0,#2)|sqrt(#3)|divide(n0,#4)
|
let , length = x meters and breadth = y meters then xy = 60 and ( x 2 + y 2 ) + x = 5 therefore , x = 60 and ( x 2 + y 2 ) = ( 5 y - x ) 2 or xy = 60 and 24 y 2 - 10 xy = 0 . therefore , 24 y 2 - 10 * 60 = 0 or y 2 = 25 or = 5 . therefore , x = ( 60 / 5 ) m = 12 m . so , length of the carpet = 12 m answer : b
|
geometry
|
math_qa__NdFpDr8pkhtp2MLw
|
A train is 357 meter long is running at a speed of 42 km/hour. In what time will it pass a bridge of 137 meter length? Choose the correct choice from the following answers.
A) 44 B) 42.343 C) 50 D) 39.252 E) 27.851
|
<gadget id="calculator">357 + 137</gadget>
<output>494</output>
<gadget id="calculator">42 * 1_000</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 / 3_600</gadget>
<output>35/3 = around 11.666667</output>
<gadget id="calculator">494 / (35/3)</gadget>
<output>1_482/35 = around 42.342857</output>
<result>B</result>
|
B
| 42.343 |
A train is 357 meter long is running at a speed of 42 km/hour. In what time will it pass a bridge of 137 meter length?
|
{
"A": "44",
"B": "42.343",
"C": "50",
"D": "39.252",
"E": "27.851"
}
|
divide(add(357, 137), divide(multiply(42, const_1000), const_3600))
|
add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)|
|
"speed = 42 km / hr = 42 * ( 5 / 18 ) m / sec = 35 / 3 m / sec total distance = 357 + 137 = 494 meter time = distance / speed = 494 * ( 3 / 35 ) = 42.343 seconds . answer : b"
|
physics
|
math_qa__9ialALBaqacoIUYq
|
In a rectangular metallic piece of paper that covers exactly the area of a cube. The length of the piece of paper is 48 inches and the width is 72 inches. What is the volume of the cube in cubic feet is 1 feet is 12 inches?
Select the correct option:
A) a 8 B) b 22 C) c 27 D) d 40 E) e 51
|
<gadget id="calculator">48 / 12</gadget>
<output>4</output>
<gadget id="calculator">72 / 12</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 / 6</gadget>
<output>4</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<result>A</result>
|
A
| 8 |
In a rectangular metallic piece of paper that covers exactly the area of a cube. The length of the piece of paper is 48 inches and the width is 72 inches. What is the volume of the cube in cubic feet is 1 feet is 12 inches?
|
{
"A": "a 8",
"B": "b 22",
"C": "c 27",
"D": "d 40",
"E": "e 51"
}
|
volume_cube(square_edge_by_area(divide(rectangle_area(divide(48, 12), divide(72, 12)), divide(72, 12))))
|
divide(n0,n3)|divide(n1,n3)|rectangle_area(#0,#1)|divide(#2,#1)|square_edge_by_area(#3)|volume_cube(#4)
|
l = 48 / 12 = 4 ft w = 72 / 12 = 6 ft area of paper = 24 area of cube = 4 * side ^ 2 side of cube = 2 v of cube = 8
|
geometry
|
math_qa__0WAME2xP8TTyoUHv
|
The value of (0.137+0.098)²-(0.137 - 0.098)² / 0.137×0.098 is
Choose the correct choice from the following:
A) 0.039 B) 0.235 C) 0.25 D) 4 E) 5
|
<gadget id="calculator">0.137 + 0.098</gadget>
<output>0.235</output>
<gadget id="calculator">0.235 ** 2</gadget>
<output>0.055225</output>
<gadget id="calculator">0.137 - 0.098</gadget>
<output>0.039</output>
<gadget id="calculator">0.039 ** 2</gadget>
<output>0.001521</output>
<gadget id="calculator">0.055225 - 0.001521</gadget>
<output>0.053704</output>
<gadget id="calculator">0.137 * 0.098</gadget>
<output>0.013426</output>
<gadget id="calculator">0.053704 / 0.013426</gadget>
<output>4</output>
<result>D</result>
|
D
| 4 |
The value of (0.137+0.098)²-(0.137 - 0.098)² / 0.137×0.098 is
|
{
"A": "0.039",
"B": "0.235",
"C": "0.25",
"D": "4",
"E": "5"
}
|
divide(subtract(power(add(0.137, 0.098), const_2), power(subtract(0.137, 0.098), const_2)), multiply(0.137, 0.098))
|
add(n0,n1)|multiply(n0,n1)|subtract(n0,n1)|power(#0,const_2)|power(#2,const_2)|subtract(#3,#4)|divide(#5,#1)
|
solution given expression = ( a + b ) ² - ( a - b ) ² / ab = 4 ab / ab = 4 . answer d
|
general
|
math_qa__JIzSpTV6lcKdDaUb
|
A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6900?
Choose the most appropriate option.
A) s . 4991 B) s . 5991 C) s . 6001 D) s . 6991 E) s . 7391
|
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 6_900</gadget>
<output>41_400</output>
<gadget id="calculator">6_435 + 6_927</gadget>
<output>13_362</output>
<gadget id="calculator">13_362 + 6_855</gadget>
<output>20_217</output>
<gadget id="calculator">20_217 + 7_230</gadget>
<output>27_447</output>
<gadget id="calculator">27_447 + 6_562</gadget>
<output>34_009</output>
<gadget id="calculator">41_400 - 34_009</gadget>
<output>7_391</output>
<result>E</result>
|
E
| 7,391 |
A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6900?
|
{
"A": "s . 4991",
"B": "s . 5991",
"C": "s . 6001",
"D": "s . 6991",
"E": "s . 7391"
}
|
subtract(multiply(add(5, const_1), 6900), add(add(add(add(6435, 6927), 6855), 7230), 6562))
|
add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)|
|
"total fr 5 mnths = ( 6435 + 6927 + 6855 + 7230 + 6562 ) = rs 34009 . reqd . sale = rs . [ ( 6900 * 6 ) - 34009 ] = rs . ( 41400 - 34009 ) = rs . 7391 . answer : e"
|
general
|
math_qa__4zb9caHs7FayqkSG
|
Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 457? Choose the correct choice from the following choices.
A) 26.4 %
B) 21 %
C) 20 %
D) 19 %
E) none of these
|
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">540 * (23/20)</gadget>
<output>621</output>
<gadget id="calculator">621 - 457</gadget>
<output>164</output>
<gadget id="calculator">164 * 100</gadget>
<output>16_400</output>
<gadget id="calculator">16_400 / 621</gadget>
<output>16_400/621 = around 26.409018</output>
<result>A</result>
|
A
| 26.4 |
Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 457?
|
{
"A": "26.4 %",
"B": "21 %",
"C": "20 %",
"D": "19 %",
"E": "none of these"
}
|
divide(multiply(subtract(multiply(540, divide(add(const_100, 15), const_100)), 457), const_100), multiply(540, divide(add(const_100, 15), const_100)))
|
add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|subtract(#2,n2)|multiply(#3,const_100)|divide(#4,#2)|
|
"cp = rs . 540 , mp = 540 + 15 % of 540 = rs . 621 sp = rs . 457 , discount = 621 - 457 = 164 discount % = 164 / 621 * 100 = 26.4 % answer : a"
|
gain
|
math_qa__cql45UiMJ441NFUc
|
Boy sells a book for Rs. 450 he gets a loss of 10%, To gain 10%, at price he should sell?
Select
A) rs . 400 B) rs . 450 C) rs . 550 D) rs . 600 E) rs . 650
|
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">450 / (9/10)</gadget>
<output>500</output>
<gadget id="calculator">500 * (1/10)</gadget>
<output>50</output>
<gadget id="calculator">500 + 50</gadget>
<output>550</output>
<result>C</result>
|
C
| 550 |
Boy sells a book for Rs. 450 he gets a loss of 10%, To gain 10%, at price he should sell?
|
{
"A": "rs . 400",
"B": "rs . 450",
"C": "rs . 550",
"D": "rs . 600",
"E": "rs . 650"
}
|
add(divide(450, subtract(const_1, divide(10, const_100))), multiply(divide(450, subtract(const_1, divide(10, const_100))), divide(10, const_100)))
|
divide(n1,const_100)|divide(n2,const_100)|subtract(const_1,#0)|divide(n0,#2)|multiply(#3,#1)|add(#3,#4)|
|
"find selling price to gain 10 % . now , we are asked to find selling price to gain 10 % profit . hint : selling price = ( 100 + gain % ) × c . p . 100 selling price = ( 100 + 10 ) × 500 100 selling price = ( 110 ) × 500 100 therefore , selling price = rs . 550 c"
|
gain
|
math_qa__0NzdjgkqZbfm2DGC
|
How many seconds does Sandy take to cover a distance of 700 meters, if Sandy runs at a speed of 18 km/hr?
Choose the most appropriate option.
A) 100 B) 120 C) 140 D) 160 E) 180
|
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">700 / 5</gadget>
<output>140</output>
<result>C</result>
|
C
| 140 |
How many seconds does Sandy take to cover a distance of 700 meters, if Sandy runs at a speed of 18 km/hr?
|
{
"A": "100",
"B": "120",
"C": "140",
"D": "160",
"E": "180"
}
|
divide(700, multiply(18, const_0_2778))
|
multiply(n1,const_0_2778)|divide(n0,#0)|
|
"18 km / hr = 18000 m / 3600 s = 5 m / s time = 700 / 5 = 140 seconds the answer is c ."
|
physics
|
math_qa__PVYbY3dqCqEFUoGD
|
A company purchased raw material worth 1/4 of it capital, 1/10 of the remaining is spent on machinery. How much fraction of the capital was left with the company after its expenditures on raw material and machinery? Choices:
A) 1 / 5
B) 2 / 8
C) 5 / 9
D) 27 / 40
E) 15 / 30
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) / 10</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">(3/4) - (3/40)</gadget>
<output>27/40 = around 0.675</output>
<result>D</result>
|
D
| 0.675 |
A company purchased raw material worth 1/4 of it capital, 1/10 of the remaining is spent on machinery. How much fraction of the capital was left with the company after its expenditures on raw material and machinery?
|
{
"A": "1 / 5",
"B": "2 / 8",
"C": "5 / 9",
"D": "27 / 40",
"E": "15 / 30"
}
|
subtract(subtract(1, divide(const_1, 4)), divide(subtract(1, divide(const_1, 4)), 10))
|
divide(const_1,n1)|subtract(n0,#0)|divide(#1,n3)|subtract(#1,#2)
|
the amount spent by the company on raw material is 1 / 4 , so remaining is 3 / 4 . 1 / 10 of the remaining is spent on machinery , 1 / 10 * 3 / 4 = 3 / 40 total amount spent on raw material and machinery is 1 / 4 + 3 / 40 to make the denominator common we use 40 , so 1 / 4 is 10 / 40 10 / 40 + 3 / 40 = 13 / 40 is spent on raw material and machinery remaining 27 / 40 is left with the company answer is d
|
general
|
math_qa__jd3U1QX1RyPazhwd
|
If x=y=2z and xyz=256 then what is the value of x? Choose the most appropriate option.
A) 12 B) 8 C) 16 D) 6 E) 2
|
<gadget id="calculator">256 * 2</gadget>
<output>512</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">512 ** (1/3)</gadget>
<output>8</output>
<result>B</result>
|
B
| 8 |
If x=y=2z and xyz=256 then what is the value of x?
|
{
"A": "12",
"B": "8",
"C": "16",
"D": "6",
"E": "2"
}
|
power(multiply(256, 2), divide(const_1, const_3))
|
divide(const_1,const_3)|multiply(n0,n1)|power(#1,#0)
|
given that x = y = z . so , x = y , x = 2 z , y = 2 z . given xyz = 256 = > ( 2 z ) * ( 2 z ) * z = 256 = > 4 z ^ 3 = 256 = > z = 4 then x = 2 z = 2 ( 4 ) = 8 answer : b
|
general
|
math_qa__54ZASj3mVNfPsyJw
|
Danny is sitting on a rectangular box. The area of the front face of the box is half the area of the top face, and the area of the top face is 1.5 times the area of the side face. If the volume of the box is 5184, what is the area of the side face of the box?
Choose the correct answer: A) 123 B) 167 C) 178 D) 199 E) 288
|
<gadget id="calculator">5_184 ** 2</gadget>
<output>26_873_856</output>
<gadget id="calculator">3 * 26_873_856</gadget>
<output>80_621_568</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">80_621_568 ** (1/3)</gadget>
<output>432</output>
<gadget id="calculator">432 / 1.5</gadget>
<output>288</output>
<result>E</result>
|
E
| 288 |
Danny is sitting on a rectangular box. The area of the front face of the box is half the area of the top face, and the area of the top face is 1.5 times the area of the side face. If the volume of the box is 5184, what is the area of the side face of the box?
|
{
"A": "123",
"B": "167",
"C": "178",
"D": "199",
"E": "288"
}
|
divide(power(multiply(const_3, power(5184, const_2)), divide(const_1, const_3)), 1.5)
|
divide(const_1,const_3)|power(n1,const_2)|multiply(#1,const_3)|power(#2,#0)|divide(#3,n0)|
|
"lets suppose length = l , breadth = b , depth = d front face area = l * w = 1 / 2 w * d ( l = 1 / 2 d or d = 2 l ) top face area = w * d side face area = w * d = 1.5 d * l ( w = 1.5 l ) volume = l * w * d = 5184 l * 1.5 l * 2 l = 5184 l = 12 side face area = l * d = l * 2 l = 12 * 2 * 12 = 288 e is the answer"
|
geometry
|
math_qa__5T8QquCxosJcYC9C
|
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed R of the train.
Choose one: A) 45 B) 33 C) 48 D) 55 E) 61
|
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">96 / 3</gadget>
<output>32</output>
<gadget id="calculator">32 - 24</gadget>
<output>8</output>
<gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">10 + 50</gadget>
<output>60</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">8 * 6</gadget>
<output>48</output>
<result>C</result>
|
C
| 48 |
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed R of the train.
|
{
"A": "45",
"B": "33",
"C": "48",
"D": "55",
"E": "61"
}
|
multiply(subtract(divide(multiply(24, 4), 3), 24), divide(add(subtract(35, 25), 50), subtract(35, 25)))
|
multiply(n2,n4)|subtract(n3,n5)|add(n0,#1)|divide(#0,n1)|divide(#2,#1)|subtract(#3,n4)|multiply(#4,#5)|
|
"let y be the balance distance to be covered and x be the former speed . a train after traveling for 50 km meets with an accident and then proceeds at 3 / 4 of its former speed and arrives at its destination 35 minutes late so , y / ( 3 x / 4 ) - y / x = 35 / 60 4 y / 3 x - y / x = 7 / 12 y / x ( 4 / 3 - 1 ) = 7 / 12 y / x * 1 / 3 = 7 / 12 y / x = 7 / 4 4 y - 7 x = 0 . . . . . . . . 1 had the accident occurred 24 km farther , it would have reached the destination only 25 minutes late so , ( y - 24 ) / ( 3 x / 4 ) - ( y - 24 ) / x = 25 / 60 4 ( y - 24 ) / 3 x - ( y - 24 ) / x = 5 / 12 ( y - 24 ) / x ( 4 / 3 - 1 ) = 5 / 12 ( y - 24 ) / x * 1 / 3 = 5 / 12 ( y - 24 ) * 12 = 3 x * 5 ( y - 24 ) * 4 = 5 x 4 y - 5 x = 96 . . . . . . . 2 eq 2 - eq 1 2 x = 96 x = 48 = r ans = c"
|
physics
|
math_qa__DuUmYOrDV7YXb863
|
What is the difference between the place values of two sevens in the numeral 54179759 ? Pick
A) 699990
B) 99990
C) 99980
D) 69300
E) none of these
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">70 * 1_000</gadget>
<output>70_000</output>
<gadget id="calculator">70_000 - 70</gadget>
<output>69_930</output>
<result>D</result>
|
D
| 69,300 |
What is the difference between the place values of two sevens in the numeral 54179759 ?
|
{
"A": "699990",
"B": "99990",
"C": "99980",
"D": "69300",
"E": "none of these"
}
|
subtract(multiply(multiply(add(const_3, const_4), const_10), const_1000), multiply(add(const_3, const_4), const_10))
|
add(const_3,const_4)|multiply(#0,const_10)|multiply(#1,const_1000)|subtract(#2,#1)
|
explanation : required difference = 70000 - 700 = 69300 answer is d
|
general
|
math_qa__OAJkvaGfLzdcLoOw
|
The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 34 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add? Choose the correct choice from the following choices:
A) 17 litres
B) 22.67 litres
C) 11 litres
D) 07 litres
E) 38.67 litres
|
<gadget id="calculator">34 * 1_399.45</gadget>
<output>47_581.3</output>
<gadget id="calculator">34 * 262.85</gadget>
<output>8_936.9</output>
<gadget id="calculator">47_581.3 - 8_936.9</gadget>
<output>38_644.4</output>
<gadget id="calculator">3_104.35 - 1_399.45</gadget>
<output>1_704.9</output>
<gadget id="calculator">38_644.4 / 1_704.9</gadget>
<output>22.666667</output>
<result>B</result>
|
B
| 22.67 |
The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 34 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add?
|
{
"A": "17 litres",
"B": "22.67 litres",
"C": "11 litres",
"D": "07 litres",
"E": "38.67 litres"
}
|
divide(subtract(multiply(34, 1399.45), multiply(34, 262.85)), subtract(3104.35, 1399.45))
|
multiply(n0,n3)|multiply(n1,n3)|subtract(n2,n0)|subtract(#0,#1)|divide(#3,#2)|
|
"262.85 ( 34 ) + 3 , 104.35 x = 1 , 399.45 ( 34 + x ) solve the equation . 262.85 ( 34 ) + 3 , 104.35 x = 1 , 399.45 ( 34 + x ) 8936.9 + 3 , 104.35 x = 47 , 581.3 + 1 , 399.45 x 8936.9 + 1 , 704.9 x = 47 , 581.3 1 , 704.9 x = 38 , 644.40 x ≈ 22.67 answer is b ."
|
general
|
math_qa__u4cOxO6MzMRgEI0y
|
The equation of line s is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line s?
Pick.
A) 48 B) 50 C) 60 D) 75 E) 100
|
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">16 + 9</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">300 / 5</gadget>
<output>60</output>
<result>C</result>
|
C
| 60 |
The equation of line s is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line s?
|
{
"A": "48",
"B": "50",
"C": "60",
"D": "75",
"E": "100"
}
|
divide(multiply(100, const_3), sqrt(add(power(4, const_2), power(3, const_2))))
|
multiply(n2,const_3)|power(n0,const_2)|power(n1,const_2)|add(#1,#2)|sqrt(#3)|divide(#0,#4)
|
this can be solve in two steps and without any complex calculation . given : equation of line s as y = ( 4 / 3 ) x - 100 . so the line intercept the axes at ( 0 , - 100 ) and ( 75,0 ) . this can be considered a right angle triangle with right angle at ( 0,0 ) . so base = 100 , height = 75 and hypotenuse = 125 ( by pythagoras triplet ) so a perpendicular from the ( 0,0 ) to hypotenuse will be the answer . area of triangle = 0.5 * 100 * 75 = 0.5 * 125 * x = > x = 60 ; so answer is 60 = c
|
general
|
math_qa__u9qCYwMGxhJ47iAo
|
Jim’s Taxi Service charges an initial fee of $2.0 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? Choices:
A) $ 5.15 B) $ 4.45 C) $ 4.80 D) $ 5.05 E) $ 5.40
|
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3.6 / (2/5)</gadget>
<output>9</output>
<gadget id="calculator">9 * 0.35</gadget>
<output>3.15</output>
<gadget id="calculator">3.15 + 2</gadget>
<output>5.15</output>
<result>A</result>
|
A
| 5.15 |
Jim’s Taxi Service charges an initial fee of $2.0 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
|
{
"A": "$ 5.15",
"B": "$ 4.45",
"C": "$ 4.80",
"D": "$ 5.05",
"E": "$ 5.40"
}
|
add(multiply(divide(3.6, divide(2, 5)), 0.35), 2.0)
|
divide(n2,n3)|divide(n4,#0)|multiply(n1,#1)|add(n0,#2)|
|
"let the fixed charge of jim â € ™ s taxi service = 2 $ and charge per 2 / 5 mile ( . 4 mile ) = . 35 $ total charge for a trip of 3.6 miles = 2 + ( 3.6 / . 4 ) * . 35 = 2 + 9 * . 35 = 5.15 $ answer a"
|
general
|
math_qa__MUKY4iKSlhwAa9NE
|
Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 2/3 of all the paint. During the second week, he uses 1/5 of the remaining paint. How many gallons of paint has Joe used?
Select the correct option
A) 18 B) 144 C) 175 D) 216 E) 264
|
<gadget id="calculator">360 / 3</gadget>
<output>120</output>
<gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">360 - 240</gadget>
<output>120</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<gadget id="calculator">240 + 24</gadget>
<output>264</output>
<result>E</result>
|
E
| 264 |
Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 2/3 of all the paint. During the second week, he uses 1/5 of the remaining paint. How many gallons of paint has Joe used?
|
{
"A": "18",
"B": "144",
"C": "175",
"D": "216",
"E": "264"
}
|
add(multiply(divide(360, 3), 2), divide(subtract(360, multiply(divide(360, 3), 2)), 5))
|
divide(n0,n2)|multiply(n1,#0)|subtract(n0,#1)|divide(#2,n4)|add(#3,#1)
|
total paint initially = 360 gallons paint used in the first week = ( 2 / 3 ) * 360 = 240 gallons . remaning paint = 120 gallons paint used in the second week = ( 1 / 5 ) * 120 = 24 gallons total paint used = 264 gallons . option e
|
physics
|
math_qa__eGi9R9eLcZ6Vh2HE
|
A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is? Choose the correct choice: A) 1 B) 2 C) 6 D) 8 E) 9
|
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">18 / 9</gadget>
<output>2</output>
<result>B</result>
|
B
| 2 |
A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is?
|
{
"A": "1",
"B": "2",
"C": "6",
"D": "8",
"E": "9"
}
|
divide(18, subtract(const_10, const_1))
|
subtract(const_10,const_1)|divide(n1,#0)
|
let the ten ' s and unit digit be x and 8 respectively . x then , 10 x + 8 + 18 = 10 x 8 + x x x 10 x 2 + 8 + 18 x = 80 + x 2 9 x 2 + 18 x - 72 = 0 x 2 + 2 x - 8 = 0 ( x + 4 ) ( x - 2 ) = 0 x = 2 option b
|
general
|
math_qa__1hiVyYDQiA1hwwvv
|
How many numbers from 10 to 47 are exactly divisible by 3? Choose the correct option
A) 12 B) 15 C) 16 D) 17 E) 18
|
<gadget id="calculator">47 / 3</gadget>
<output>47/3 = around 15.666667</output>
<gadget id="calculator">floor(47/3)</gadget>
<output>15</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">10 / 3</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">floor(10/3)</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">45 - 12</gadget>
<output>33</output>
<gadget id="calculator">33 / 3</gadget>
<output>11</output>
<gadget id="calculator">11 + 1</gadget>
<output>12</output>
<result>A</result>
|
A
| 12 |
How many numbers from 10 to 47 are exactly divisible by 3?
|
{
"A": "12",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
}
|
add(divide(subtract(multiply(floor(divide(47, 3)), 3), multiply(add(floor(divide(10, 3)), const_1), 3)), 3), const_1)
|
divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)|
|
"12 , 15 , 18 , 21 , 24 , 27 , 30 , 33 , 36 , 39 , 42 , 45 , . 12 numbers . 10 / 3 = 3 and 47 / 3 = 15 = = > 15 - 3 = 12 . therefore 12 digits a )"
|
general
|
math_qa__36RKevJKVvjrZ8qy
|
A 7% stock yields 10%. The market value of the stock is: Choose the correct option:
A) rs 60 B) rs 70 C) rs 90 D) rs 75 E) rs 50
|
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<result>B</result>
|
B
| 70 |
A 7% stock yields 10%. The market value of the stock is:
|
{
"A": "rs 60",
"B": "rs 70",
"C": "rs 90",
"D": "rs 75",
"E": "rs 50"
}
|
multiply(divide(const_100, 10), 7)
|
divide(const_100,n1)|multiply(n0,#0)|
|
"explanation : for an income of rs . 10 , investment = rs . 100 . for an income of rs 7 , investment = rs . 100 / 10 x 7 = rs 70 market value of rs . 100 stock = rs . 70 answer is b"
|
gain
|
math_qa__saHbtPQuxqKvYYPu
|
There were two candidates in an election. Winner candidate received 62% of votes and won the election by 360 votes. Find the number of votes casted to the winning candidate?
Select the correct option.
A) 288 B) 744 C) 788 D) 298 E) 930
|
<gadget id="calculator">100 - 62</gadget>
<output>38</output>
<gadget id="calculator">62 - 38</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">360 / (6/25)</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 * 62</gadget>
<output>93_000</output>
<gadget id="calculator">93_000 / 100</gadget>
<output>930</output>
<result>E</result>
|
E
| 930 |
There were two candidates in an election. Winner candidate received 62% of votes and won the election by 360 votes. Find the number of votes casted to the winning candidate?
|
{
"A": "288",
"B": "744",
"C": "788",
"D": "298",
"E": "930"
}
|
divide(multiply(divide(360, divide(subtract(62, subtract(const_100, 62)), const_100)), 62), const_100)
|
subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)|
|
"w = 62 % l = 38 % 62 % - 38 % = 24 % 24 % - - - - - - - - 360 62 % - - - - - - - - ? = > 930 answer : e"
|
gain
|
math_qa__icHTM7ao9kgnoEWa
|
a light flashes every 6 seconds, how many times will it flash in ? of an hour? Choose the correct option:
A) 550 B) 600 C) 650 D) 700 E) 750
|
<gadget id="calculator">3_600 / 6</gadget>
<output>600</output>
<result>B</result>
|
B
| 600 |
a light flashes every 6 seconds, how many times will it flash in ? of an hour?
|
{
"A": "550",
"B": "600",
"C": "650",
"D": "700",
"E": "750"
}
|
divide(const_3600, 6)
|
divide(const_3600,n0)|
|
"1 flash = 6 sec for 1 min = 10 flashes so for 1 hour = 10 * 60 = 600 flashes . answer : b"
|
physics
|
math_qa__ZG6RnVhDETHtwGiL
|
UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought more of Toyota than Honda at the ratio of 6:4. If 60% of the Toyota bought and 40% of the Honda bought were SUV’s. How many SUV’s did UBA capital buy in the aforementioned purchase? Choose the correct choice from the following answers.
A) 66 % B) 64 % C) 68 % D) 52 % E) 72 %
|
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 + 24</gadget>
<output>48</output>
<gadget id="calculator">100 - 48</gadget>
<output>52</output>
<result>D</result>
|
D
| 52 |
UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought more of Toyota than Honda at the ratio of 6:4. If 60% of the Toyota bought and 40% of the Honda bought were SUV’s. How many SUV’s did UBA capital buy in the aforementioned purchase?
|
{
"A": "66 %",
"B": "64 %",
"C": "68 %",
"D": "52 %",
"E": "72 %"
}
|
subtract(const_100, add(multiply(6, 4), multiply(4, 6)))
|
multiply(n0,n1)|add(#0,#0)|subtract(const_100,#1)|
|
"let total no of vehicles bought be 100 , toyota 60 and honda 40 , so total number of suv ' s bought for toyota and honda respectively 60 * 60 / 100 = 36 and 40 * 40 / 100 = 16 so total 52 suv ' s were bought out of 100 vehicles bought . . so required % is 52 % answer : d"
|
other
|
math_qa__J7e1omJXlvQ8WFvU
|
A clothing store purchased a pair of pants for $81 and was selling it at a price that equaled the purchase price of the pants plus a markup that was 25 percent of the selling price. After some time a clothing store owner decided to decrease the selling price by 20 percent. What was the clothing store's gross profit on this sale? Select:
A) $ 14 B) $ 5.4 C) $ 4.4 D) $ 1.2 E) $ 5.0
|
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">81 / 3</gadget>
<output>27</output>
<gadget id="calculator">27 + 81</gadget>
<output>108</output>
<gadget id="calculator">80 * 108</gadget>
<output>8_640</output>
<gadget id="calculator">8_640 / 100</gadget>
<output>432/5 = around 86.4</output>
<gadget id="calculator">(432/5) - 81</gadget>
<output>27/5 = around 5.4</output>
<result>B</result>
|
B
| 5.4 |
A clothing store purchased a pair of pants for $81 and was selling it at a price that equaled the purchase price of the pants plus a markup that was 25 percent of the selling price. After some time a clothing store owner decided to decrease the selling price by 20 percent. What was the clothing store's gross profit on this sale?
|
{
"A": "$ 14",
"B": "$ 5.4",
"C": "$ 4.4",
"D": "$ 1.2",
"E": "$ 5.0"
}
|
subtract(divide(multiply(subtract(const_100, 20), add(divide(81, const_3), 81)), const_100), 81)
|
divide(n0,const_3)|subtract(const_100,n2)|add(n0,#0)|multiply(#2,#1)|divide(#3,const_100)|subtract(#4,n0)|
|
"sale price ( sp ) = 81 + markup ( mp ) - - > mp = sp - 81 and given mp = sp / 4 ( 25 % is 1 / 4 th ) so sp / 4 = sp - 81 3 sp / 4 = 81 sp = 108 now a discount of 20 % is given so new sp is . 8 * 108 = 86.4 profit = 86.4 - 81 = 5.4 $ answer is b"
|
general
|
math_qa__8K3bE8peg5eEc3lS
|
A train 240 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? Choose the correct choice from the following choices
A) 4 B) 6 C) 12 D) 9 E) 13
|
<gadget id="calculator">240 / 1_000</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">(6/25) / 66</gadget>
<output>1/275 = around 0.003636</output>
<gadget id="calculator">3_600 * (1/275)</gadget>
<output>144/11 = around 13.090909</output>
<result>E</result>
|
E
| 13 |
A train 240 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
|
{
"A": "4",
"B": "6",
"C": "12",
"D": "9",
"E": "13"
}
|
multiply(const_3600, divide(divide(240, const_1000), add(60, 6)))
|
add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)|
|
"speed of train relative to man = ( 60 + 6 ) km / hr = 66 km / hr [ 66 * 5 / 18 ] m / sec = [ 55 / 3 ] m / sec . time taken to pass the man = [ 240 * 3 / 55 ] sec = 13 sec answer : e"
|
physics
|
math_qa__8gx5Lq5HPiGki16V
|
The wages earned by Robin is 30% more than that earned by Erica. The wages earned by Charles is 70% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin?
Choose the correct choice from the following options:
A) 18.75 % B) 23 % C) 30 % D) 31 % E) 100 %
|
<gadget id="calculator">100 + 70</gadget>
<output>170</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">170 - 130</gadget>
<output>40</output>
<gadget id="calculator">40 / 130</gadget>
<output>4/13 = around 0.307692</output>
<gadget id="calculator">(4/13) * 100</gadget>
<output>400/13 = around 30.769231</output>
<result>D</result>
|
D
| 31 |
The wages earned by Robin is 30% more than that earned by Erica. The wages earned by Charles is 70% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin?
|
{
"A": "18.75 %",
"B": "23 %",
"C": "30 %",
"D": "31 %",
"E": "100 %"
}
|
multiply(divide(subtract(add(const_100, 70), add(const_100, 30)), add(const_100, 30)), const_100)
|
add(n1,const_100)|add(n0,const_100)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100)|
|
"let wage of erica = 10 wage of robin = 1.3 * 10 = 13 wage of charles = 1.7 * 10 = 17 percentage by which wage earned by charles is more than that earned by robin = ( 17 - 13 ) / 13 * 100 % = 4 / 13 * 100 % = 31 % answer d"
|
general
|
math_qa__5T1lY4UQQno2yqhH
|
Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 3/7 and that of Ravi is 1/5. Find the probability that both of them are selected.
Choose the most appropriate option: A) 3 / 35 B) 2 / 3 C) 7 / 35 D) 5 / 7 E) 7 / 5
|
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/7) * (1/5)</gadget>
<output>3/35 = around 0.085714</output>
<result>A</result>
|
A
| 0.085714 |
Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 3/7 and that of Ravi is 1/5. Find the probability that both of them are selected.
|
{
"A": "3 / 35",
"B": "2 / 3",
"C": "7 / 35",
"D": "5 / 7",
"E": "7 / 5"
}
|
multiply(divide(3, 7), divide(1, 5))
|
divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)|
|
"let a be the event that ram is selected and b is the event that ravi is selected . p ( a ) = 3 / 7 p ( b ) = 1 / 5 let c be the event that both are selected . p ( c ) = p ( a ) x p ( b ) as a and b are independent events : = 3 / 7 x 1 / 5 = 3 / 35 answer : a"
|
general
|
math_qa__8KnSEy8SQoVNOyD7
|
Two trains start at same time from two stations and proceed towards each other at the rate of 20 km/hr and 25 km/hr respectively. When they meet, it is found that one train has traveled 60 km more than the other. What is the distance between the two stations?
Answers
A) 540 km B) 767 km C) 276 km D) 178 km E) 176 km
|
<gadget id="calculator">20 + 25</gadget>
<output>45</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">45 * 12</gadget>
<output>540</output>
<result>A</result>
|
A
| 540 |
Two trains start at same time from two stations and proceed towards each other at the rate of 20 km/hr and 25 km/hr respectively. When they meet, it is found that one train has traveled 60 km more than the other. What is the distance between the two stations?
|
{
"A": "540 km",
"B": "767 km",
"C": "276 km",
"D": "178 km",
"E": "176 km"
}
|
multiply(add(20, 25), divide(60, subtract(25, 20)))
|
add(n0,n1)|subtract(n1,n0)|divide(n2,#1)|multiply(#0,#2)|
|
"explanation : let us assume that trains meet after ' x ' hours distance = speed * time distance traveled by two trains = 20 x km and 25 x km resp . as one train travels 60 km more than the other , 25 x – 20 x = 60 5 x = 60 x = 12 hours as the two trains are moving towards each other , relative speed = 20 + 25 = 45 km / hr therefore , total distance = 45 * 12 = 540 km . answer : a"
|
general
|
math_qa__wgsn44Ym2zXn8PKN
|
A snooker tournament charges $45.00 for VIP seats and $20.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats? Choose the correct choice from the following answers.
A) 200
B) 276
C) 230
D) 240
E) 250
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 1_000</gadget>
<output>7_000</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">7_000 + 500</gadget>
<output>7_500</output>
<gadget id="calculator">320 * 20</gadget>
<output>6_400</output>
<gadget id="calculator">7_500 - 6_400</gadget>
<output>1_100</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">1_100 / 25</gadget>
<output>44</output>
<gadget id="calculator">320 - 44</gadget>
<output>276</output>
<result>B</result>
|
B
| 276 |
A snooker tournament charges $45.00 for VIP seats and $20.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats?
|
{
"A": "200",
"B": "276",
"C": "230",
"D": "240",
"E": "250"
}
|
subtract(320, divide(subtract(add(multiply(add(const_3, const_4), const_1000), multiply(add(const_2, const_3), const_100)), multiply(320, 20.00)), multiply(add(const_2, const_3), add(const_2, const_3))))
|
add(const_3,const_4)|add(const_2,const_3)|multiply(n1,n2)|multiply(#0,const_1000)|multiply(#1,const_100)|multiply(#1,#1)|add(#3,#4)|subtract(#6,#2)|divide(#7,#5)|subtract(n2,#8)|
|
"let no of sits in vip enclosure is x then x * 45 + 20 ( 320 - x ) = 7500 or 25 x = 7500 - 6400 , x = 1100 / 25 = 44 vip = 44 general 320 - 44 = 276 b"
|
geometry
|
math_qa__a74yJWMHVvvvlMNA
|
A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed? Choices.
A) 3
B) 4
C) 5
D) 6
E) 78
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) + (1/12)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / (1/3)</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<result>D</result>
|
D
| 6 |
A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed?
|
{
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "78"
}
|
multiply(inverse(add(inverse(4), inverse(12))), const_2)
|
inverse(n0)|inverse(n1)|add(#0,#1)|inverse(#2)|multiply(#3,const_2)|
|
"work done by a and b in the first two hours , working alternately = first hour a + second hour b = 1 / 4 + 1 / 12 = 1 / 3 . total time required to complete the work = 2 * 3 = 6 days . answer : d"
|
physics
|
math_qa__jbhP7TzYOAVewV4Q
|
John had a stock of 1300 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold? Pick:
A) 50.4 % B) 23.8 % C) 66.5 % D) 69.0 % E) 43.5 %
|
<gadget id="calculator">75 + 50</gadget>
<output>125</output>
<gadget id="calculator">64 + 78</gadget>
<output>142</output>
<gadget id="calculator">125 + 142</gadget>
<output>267</output>
<gadget id="calculator">267 + 135</gadget>
<output>402</output>
<gadget id="calculator">1_300 - 402</gadget>
<output>898</output>
<gadget id="calculator">898 / 1_300</gadget>
<output>449/650 = around 0.690769</output>
<gadget id="calculator">(449/650) * 100</gadget>
<output>898/13 = around 69.076923</output>
<result>D</result>
|
D
| 69 |
John had a stock of 1300 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
|
{
"A": "50.4 %",
"B": "23.8 %",
"C": "66.5 %",
"D": "69.0 %",
"E": "43.5 %"
}
|
multiply(divide(subtract(1300, add(add(add(75, 50), add(64, 78)), 135)), 1300), const_100)
|
add(n1,n2)|add(n3,n4)|add(#0,#1)|add(n5,#2)|subtract(n0,#3)|divide(#4,n0)|multiply(#5,const_100)|
|
"let n be the total number of books sold . hence n = 75 + 50 + 64 + 78 + 135 = 402 let m be the books not sold m = 1300 - n = 1300 - 402 = 898 percentage books not sold / total number of books = 898 / 1300 = 0.69 = 69 % correct answer d"
|
gain
|
math_qa__gEdAtBnnUmeRfeUT
|
A farm is made up of brown and white goats. the number of male brown goats is 35% less than the total number of brown goats. The total number of female goats is 20 times more than the number of female brown goats. If the total population of male goats is half the population of the female goats, what percentage of male goats are brown? Choose the correct choice from the following answers
A) 30.1 B) 20.5 C) 15.2 D) 10.2 E) 28.6
|
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 20</gadget>
<output>7</output>
<gadget id="calculator">7 * 4</gadget>
<output>28</output>
<result>E</result>
|
E
| 28.6 |
A farm is made up of brown and white goats. the number of male brown goats is 35% less than the total number of brown goats. The total number of female goats is 20 times more than the number of female brown goats. If the total population of male goats is half the population of the female goats, what percentage of male goats are brown?
|
{
"A": "30.1",
"B": "20.5",
"C": "15.2",
"D": "10.2",
"E": "28.6"
}
|
multiply(multiply(divide(35, const_100), 20), const_4)
|
divide(n0,const_100)|multiply(n1,#0)|multiply(#1,const_4)
|
since we are dealing in percentage let us pick 100 as the number of brown male goats . that means that the total number of brown goats is = 135 ( number of male brown goats is 35 % less than the total number of brown goats ) , therefore the number of brown female goats is 35 . the total number of female goats is 15 x the number of brown female goats = 35 * 20 = 700 female goats . male goats total population is half the population of the female goats = 700 / 2 = 350 therefore percentage of male horses goats that are brown = 100 / 350 * 100 = 28.6 correct option is e
|
general
|
math_qa__oHOsTc3JYX0heZsy
|
The average of 7 consecutive numbers is 20. The largest of these numbers is Select
A) 12 B) 27 C) 23 D) 28 E) 11
|
<gadget id="calculator">20 * 7</gadget>
<output>140</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">1 + 7</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">10 + 11</gadget>
<output>21</output>
<gadget id="calculator">140 - 21</gadget>
<output>119</output>
<gadget id="calculator">119 / 7</gadget>
<output>17</output>
<gadget id="calculator">17 + 6</gadget>
<output>23</output>
<result>C</result>
|
C
| 23 |
The average of 7 consecutive numbers is 20. The largest of these numbers is
|
{
"A": "12",
"B": "27",
"C": "23",
"D": "28",
"E": "11"
}
|
add(divide(subtract(multiply(20, 7), add(add(add(add(const_1, add(add(add(add(add(const_1, const_2), const_1), const_1), const_1), const_1)), const_1), const_1), add(add(add(add(const_1, add(add(add(add(add(const_1, const_2), const_1), const_1), const_1), const_1)), const_1), const_1), const_1))), 7), add(add(add(add(const_1, const_2), const_1), const_1), const_1))
|
add(const_1,const_2)|multiply(n0,n1)|add(#0,const_1)|add(#2,const_1)|add(#3,const_1)|add(#4,const_1)|add(#5,const_1)|add(#6,const_1)|add(#7,const_1)|add(#8,const_1)|add(#8,#9)|subtract(#1,#10)|divide(#11,n0)|add(#4,#12)
|
let the numbers be x , x + 1 , x + 2 , x + 3 , x + 4 , x + 5 and x + 6 , then ( x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) + ( x + 6 ) ) / 7 = 20 . or 7 x + 21 = 140 or 7 x = 119 or x = 17 . latest number = x + 6 = 23 . answer : c
|
general
|
math_qa__3N5AD6dugMVK99nz
|
A bookseller sells his books at a 15% markup in price. If he sells a book for $23.00, how much did he pay for it? Choose one:
A) $ 14.40
B) $ 14.00
C) $ 21.00
D) $ 19.60
E) $ 20.00
|
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 23</gadget>
<output>69/20 = around 3.45</output>
<gadget id="calculator">23 - (69/20)</gadget>
<output>391/20 = around 19.55</output>
<result>E</result>
|
E
| 20 |
A bookseller sells his books at a 15% markup in price. If he sells a book for $23.00, how much did he pay for it?
|
{
"A": "$ 14.40",
"B": "$ 14.00",
"C": "$ 21.00",
"D": "$ 19.60",
"E": "$ 20.00"
}
|
subtract(23.00, multiply(divide(15, const_100), 23.00))
|
divide(n0,const_100)|multiply(n1,#0)|subtract(n1,#1)|
|
"let the cost price of book = x selling price of book = 23 $ markup % = 15 ( 115 / 100 ) x = 23 = > x = 20 answer e"
|
gain
|
math_qa__OBFueYglA4uvqWpu
|
There are 20 poles with a constant distance between each pole. A car takes 24 second to reach the 12th pole. How much will it take to reach the last pole.
Pick one:
A) 41.4543
B) 41.4545
C) 41.45128
D) 41.41288
E) 41.41222
|
<gadget id="calculator">24 / 12</gadget>
<output>2</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<result>B</result>
|
B
| 41.4545 |
There are 20 poles with a constant distance between each pole. A car takes 24 second to reach the 12th pole. How much will it take to reach the last pole.
|
{
"A": "41.4543",
"B": "41.4545",
"C": "41.45128",
"D": "41.41288",
"E": "41.41222"
}
|
multiply(divide(24, 12), 20)
|
divide(n1,n2)|multiply(n0,#0)|
|
"assuming the car starts at the first pole . to reach the 12 th pole , the car need to travel 11 poles ( the first pole does n ' t count , as the car is already there ) . 11 poles 24 seconds 1 pole ( 24 / 11 ) seconds to reach the last ( 20 th ) pole , the car needs to travel 19 poles . 19 pole 19 x ( 24 / 11 ) seconds = 41.4545 seconds answer : b"
|
physics
|
math_qa__5IyJQ3tHIej2nX8i
|
A person walks from one end to the other of a 100-meter long moving walkway at a constant rate in 50 seconds, assisted by the walkway. When this person reaches the end, they reverse direction and continue walking with the same speed, but this time it takes 150 seconds because the person is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take this person to walk from one end of the walkway to the other? Answers
A) 63 B) 66 C) 69 D) 72 E) 75
|
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">100 / 150</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 + (2/3)</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) / 2</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">100 / (4/3)</gadget>
<output>75</output>
<result>E</result>
|
E
| 75 |
A person walks from one end to the other of a 100-meter long moving walkway at a constant rate in 50 seconds, assisted by the walkway. When this person reaches the end, they reverse direction and continue walking with the same speed, but this time it takes 150 seconds because the person is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take this person to walk from one end of the walkway to the other?
|
{
"A": "63",
"B": "66",
"C": "69",
"D": "72",
"E": "75"
}
|
divide(100, divide(add(divide(100, 50), divide(100, 150)), const_2))
|
divide(n0,n1)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)|divide(n0,#3)
|
let v be the speed of the person and let x be the speed of the walkway . 50 ( v + x ) = 100 then 150 ( v + x ) = 300 150 ( v - x ) = 100 when we add the two equations : 300 v = 400 v = 4 / 3 time = 100 / ( 4 / 3 ) = 75 seconds the answer is e .
|
physics
|
math_qa__dZigt6kB5LPlmXa7
|
The radius of a wheel is 16.8 cm. What is the distance covered by the wheel in making 300 resolutions? Select.
A) 754 m B) 316.512 m C) 311.512 m D) 311.518 m E) 313.512 m
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 16.8</gadget>
<output>52.8</output>
<gadget id="calculator">52.8 * 2</gadget>
<output>105.6</output>
<gadget id="calculator">105.6 * 300</gadget>
<output>31_680</output>
<gadget id="calculator">31_680 / 100</gadget>
<output>1_584/5 = around 316.8</output>
<result>B</result>
|
B
| 316.512 |
The radius of a wheel is 16.8 cm. What is the distance covered by the wheel in making 300 resolutions?
|
{
"A": "754 m",
"B": "316.512 m",
"C": "311.512 m",
"D": "311.518 m",
"E": "313.512 m"
}
|
divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 16.8), const_2), 300), const_100)
|
add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)|
|
"in one resolution , the distance covered by the wheel is its own circumference . distance covered in 300 resolutions . = 300 * 2 * 22 / 7 * 16.8 = 31651.2 cm = 316.512 m answer : b"
|
physics
|
math_qa__teOkNuAFtghr73b9
|
At present the ratio between the ages of Arun and Deepak is 2:5. After 10 years Arun's age will be 30 years. What is the age of the Deepak?
Choose the correct choice from the following answers
A) 20 B) 40 C) 50 D) 60 E) 45
|
<gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>C</result>
|
C
| 50 |
At present the ratio between the ages of Arun and Deepak is 2:5. After 10 years Arun's age will be 30 years. What is the age of the Deepak?
|
{
"A": "20",
"B": "40",
"C": "50",
"D": "60",
"E": "45"
}
|
divide(multiply(subtract(30, 10), 5), 2)
|
subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)|
|
"let the present age of arun and deepak be 4 x and 3 x 2 x + 10 = 30 2 x = 20 x = 10 deepak ' s age = 5 x = 50 years answer is c"
|
other
|
math_qa__L159vUvyyESSYPcC
|
A rectangular floor that measures 6 meters by 10 meters is to be covered with carpet squares that each measure 2 meters by 2 meters. If the carpet squares cost $15 apiece, what is the total cost for the number of carpet squares needed to cover the floor?
Pick:
A) $ 200
B) $ 240
C) $ 480
D) $ 225
E) $ 1,920
|
<gadget id="calculator">15 * 15</gadget>
<output>225</output>
<result>D</result>
|
D
| 225 |
A rectangular floor that measures 6 meters by 10 meters is to be covered with carpet squares that each measure 2 meters by 2 meters. If the carpet squares cost $15 apiece, what is the total cost for the number of carpet squares needed to cover the floor?
|
{
"A": "$ 200",
"B": "$ 240",
"C": "$ 480",
"D": "$ 225",
"E": "$ 1,920"
}
|
multiply(15, 15)
|
multiply(n4,n4)|
|
"the width of the rectangular floor ( 6 m ) is a multiple of one side of the square ( 2 m ) , and the length of the floor ( 10 m ) is also a multiple of the side of the square . so the number of carpets to cover the floor is ( 6 / 2 ) * ( 10 / 2 ) = 15 . the total cost is 15 * 15 = $ 225 . the answer is , therefore , d ."
|
geometry
|
math_qa__JeekhAKTQnJtezav
|
On multiplying a numberZ by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result. Choose the correct choice from the following options:
A) 104345 B) 107375 C) 108385 D) 109395 E) 105355
|
<gadget id="calculator">100 * 4</gadget>
<output>400</output>
<gadget id="calculator">400 + 400</gadget>
<output>800</output>
<gadget id="calculator">800 - 100</gadget>
<output>700</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">700 + 15</gadget>
<output>715</output>
<gadget id="calculator">715 * 153</gadget>
<output>109_395</output>
<result>D</result>
|
D
| 109,395 |
On multiplying a numberZ by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result.
|
{
"A": "104345",
"B": "107375",
"C": "108385",
"D": "109395",
"E": "105355"
}
|
multiply(add(subtract(add(multiply(const_100, const_4), multiply(const_100, const_4)), const_100), add(multiply(const_3, const_4), const_3)), 153)
|
multiply(const_3,const_4)|multiply(const_100,const_4)|add(#0,const_3)|add(#1,#1)|subtract(#3,const_100)|add(#2,#4)|multiply(n0,#5)
|
the only thing you actually know about the correct number z is that it is divisible by 153 and has 5 as a factor . you should immediately try to find the factors of 153 and look for them in the options . 153 = 9 * 17 divisibility by 9 is easy to check . only ( d ) satisfies .
|
other
|
math_qa__qSYzBGi56BgSgUq7
|
The average age of 40 passengers in a ferry is 35. What is the average age of the new group formed when combining the passengers with the 5 crew members of ferry whose average age is 25?
Choose the correct choice from the following choices:
A) 36.45
B) 38.89
C) 39.67
D) 40.12
E) 41.88
|
<gadget id="calculator">35 * 40</gadget>
<output>1_400</output>
<gadget id="calculator">5 * 25</gadget>
<output>125</output>
<gadget id="calculator">1_400 + 125</gadget>
<output>1_525</output>
<gadget id="calculator">35 + 5</gadget>
<output>40</output>
<gadget id="calculator">1_525 / 40</gadget>
<output>305/8 = around 38.125</output>
<result>B</result>
|
B
| 38.89 |
The average age of 40 passengers in a ferry is 35. What is the average age of the new group formed when combining the passengers with the 5 crew members of ferry whose average age is 25?
|
{
"A": "36.45",
"B": "38.89",
"C": "39.67",
"D": "40.12",
"E": "41.88"
}
|
divide(add(multiply(35, 40), multiply(5, 25)), add(35, 5))
|
add(n1,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)
|
sum of ages of passengers = 40 x 35 = 1400 sum of ages of crew = 25 x 5 = 125 sum of ages of new group formed = 1525 average = 1525 / 45 = 38.89 answer : b
|
general
|
math_qa__00Q6LizXu3Gda61S
|
One side of the bottom layer of a triangular pyramid has 12 balls. How many are there in the whole pyramid?Note that the pyramid is equilateral and solid.
Choose the correct choice from the following answers
A) 286 B) 364 C) 504 D) 164 E) 165
|
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">360 + (1/3)</gadget>
<output>1_081/3 = around 360.333333</output>
<result>B</result>
|
B
| 364 |
One side of the bottom layer of a triangular pyramid has 12 balls. How many are there in the whole pyramid?Note that the pyramid is equilateral and solid.
|
{
"A": "286",
"B": "364",
"C": "504",
"D": "164",
"E": "165"
}
|
add(const_360, const_0_33)
|
add(const_0_33,const_360)
|
as there are 12 balls along one side , it means that there are 12 layers of balls . the top most layer has 1 ball . the second layer has 3 ( 1 + 2 ) balls . the third layer has 6 ( 1 + 2 + 3 ) balls . the fourth layer has 10 ( 1 + 2 + 3 + 4 ) balls . the fifth layer has 15 ( 1 + 2 + 3 + 4 + 5 ) balls . similarly , there are 21 , 28 , 36 , 45 , 55 , 66 and 78 balls in the remaining layers . hence , the total number of balls are = 1 + 3 + 6 + 10 + 15 + 21 + 28 + 36 + 45 + 55 + 66 + 78 = 364 balls answer : b
|
geometry
|
math_qa__ev3h4ltIvKThIr4w
|
A furniture dealer purchased a desk for $150 and then set the selling price equal to the purchase price plus a markup that was 25% of the selling price. If the dealer sold the desk at the selling price, what was the amount of the dealer's gross profit from the purchase and the sale of the desk? Choices
A) 40 %
B) 38 %
C) 36 %
D) 33.33 %
E) 35 %
|
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">150 / (3/4)</gadget>
<output>200</output>
<gadget id="calculator">200 - 150</gadget>
<output>50</output>
<gadget id="calculator">50 * 100</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 150</gadget>
<output>100/3 = around 33.333333</output>
<result>D</result>
|
D
| 33.33 |
A furniture dealer purchased a desk for $150 and then set the selling price equal to the purchase price plus a markup that was 25% of the selling price. If the dealer sold the desk at the selling price, what was the amount of the dealer's gross profit from the purchase and the sale of the desk?
|
{
"A": "40 %",
"B": "38 %",
"C": "36 %",
"D": "33.33 %",
"E": "35 %"
}
|
divide(multiply(subtract(divide(150, subtract(const_1, divide(25, const_100))), 150), const_100), 150)
|
divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1)|subtract(#2,n0)|multiply(#3,const_100)|divide(#4,n0)|
|
"anyway , in this question , there is no discount but the mark up is given as 25 % of the selling price . so it is not 25 % of $ 150 but instead , 40 % of selling price which is obtained by adding mark up to $ 150 . so if selling price is s , 150 + 25 % of s = s s = 200 profit = 50 which is calculated on cost price in % terms . so 50 / 150 * 100 = 33.33 % is profit . d"
|
gain
|
math_qa__4AWHHJQpLcLMWno3
|
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 9 inches than that of a rectangular sheet of paper measuring 4.5 inches by 11 inches? Select the correct option:
A) 50 %
B) 87 %
C) 100 %
D) 187 %
E) 200 %
|
<gadget id="calculator">11 * 9</gadget>
<output>99</output>
<gadget id="calculator">99 * 2</gadget>
<output>198</output>
<gadget id="calculator">4.5 * 11</gadget>
<output>49.5</output>
<gadget id="calculator">49.5 * 2</gadget>
<output>99</output>
<gadget id="calculator">198 - 99</gadget>
<output>99</output>
<gadget id="calculator">99 / 99</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result>
|
C
| 100 |
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 9 inches than that of a rectangular sheet of paper measuring 4.5 inches by 11 inches?
|
{
"A": "50 %",
"B": "87 %",
"C": "100 %",
"D": "187 %",
"E": "200 %"
}
|
multiply(divide(subtract(multiply(rectangle_area(11, 9), const_2), multiply(rectangle_area(4.5, 11), const_2)), rectangle_area(11, 9)), const_100)
|
rectangle_area(n0,n1)|rectangle_area(n0,n2)|multiply(#0,const_2)|multiply(#1,const_2)|subtract(#2,#3)|divide(#4,#0)|multiply(#5,const_100)|
|
"let ' s just look at the dimensions ( no calculation needed ) . with dimension 11 the same , the other dimension 9 is twice 4.5 then the area will be double which means 100 % greater . the answer is c ."
|
geometry
|
math_qa__cVRRHYNg1bnR7VVe
|
The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 850 per sq. metre.
Choose the correct choice from the following:
A) s . 15,550 B) s . 15,600 C) s . 16,500 D) s . 17,600 E) s . 18,700
|
<gadget id="calculator">5.5 * 4</gadget>
<output>22</output>
<gadget id="calculator">850 * 22</gadget>
<output>18_700</output>
<result>E</result>
|
E
| 18,700 |
The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 850 per sq. metre.
|
{
"A": "s . 15,550",
"B": "s . 15,600",
"C": "s . 16,500",
"D": "s . 17,600",
"E": "s . 18,700"
}
|
multiply(850, multiply(5.5, 4))
|
multiply(n0,n1)|multiply(n2,#0)|
|
"area of the floor = ( 5.5 ã — 4 ) m 2 = 22 m 2 . cost of paving = rs . ( 850 ã — 22 ) = rs . 18700 answer : option e"
|
physics
|
math_qa__iOwb8ddalHal0qzA
|
at a conference table , 6 employees gather around a table . one of the employees is the manager and he sits at the head of the table . two of the employees sit on either side of the table . how many different seating arrangements can be made with these 6 employees ? Choose the correct choice from the following choices.
A) 60 B) 80 C) 100 D) 120 E) 140
|
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<result>D</result>
|
D
| 120 |
at a conference table , 6 employees gather around a table . one of the employees is the manager and he sits at the head of the table . two of the employees sit on either side of the table . how many different seating arrangements can be made with these 6 employees ?
|
{
"A": "60",
"B": "80",
"C": "100",
"D": "120",
"E": "140"
}
|
factorial(subtract(6, const_1))
|
subtract(n0,const_1)|factorial(#0)
|
head ' s sit is fixed . now 5 people is left with 5 seats . 5 people can sit on 5 seats in 5 ! ways or 120 ways . ans is d
|
probability
|
math_qa__jXMSsne0Q8KpiCZG
|
If q and t are positive integers, qt + q + t cannot be Choose the correct choice from the following answers
A) 5 B) 6 C) 7 D) 8 E) 9
|
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>B</result>
|
B
| 6 |
If q and t are positive integers, qt + q + t cannot be
|
{
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
}
|
add(add(multiply(const_1, const_2), add(const_1, const_2)), const_1)
|
add(const_1,const_2)|multiply(const_1,const_2)|add(#0,#1)|add(#2,const_1)
|
let qt + t + q = x add 1 on both sides : qt + t + q + 1 = x + 1 tq + 1 ) + q + 1 = x + 1 ( q + 1 ) ( t + 1 ) = x + 1 minimum value of ( q + 1 ) = 2 minimum value of ( t + 1 ) = 2 hence x + 1 can not be prime substitute x from the given options : 6 + 1 = 7 - - > prime - - > qt + t + s can not be 6 answer : b
|
general
|
math_qa__rxAdDqFV3Hd4JXpC
|
A toy factory stores its toys in either a big box or a small box. The big box can store 35 toys while the small box can store 14 toys. If the factory is to store 86 newly manufactured toys, what is the least number of toys that will be left unboxed? Choose the correct choice from the following options.
A) 2
B) 1
C) 3
D) 5
E) 4
|
<gadget id="calculator">86 / 35</gadget>
<output>86/35 = around 2.457143</output>
<gadget id="calculator">floor(86/35)</gadget>
<output>2</output>
<gadget id="calculator">2 * 35</gadget>
<output>70</output>
<gadget id="calculator">86 - 70</gadget>
<output>16</output>
<gadget id="calculator">16 % 14</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">1 * 35</gadget>
<output>35</output>
<gadget id="calculator">86 - 35</gadget>
<output>51</output>
<gadget id="calculator">51 % 14</gadget>
<output>9</output>
<gadget id="calculator">min(2, 9)</gadget>
<output>2</output>
<result>A</result>
|
A
| 2 |
A toy factory stores its toys in either a big box or a small box. The big box can store 35 toys while the small box can store 14 toys. If the factory is to store 86 newly manufactured toys, what is the least number of toys that will be left unboxed?
|
{
"A": "2",
"B": "1",
"C": "3",
"D": "5",
"E": "4"
}
|
min(reminder(subtract(86, multiply(floor(divide(86, 35)), 35)), 14), reminder(subtract(86, multiply(subtract(floor(divide(86, 35)), const_1), 35)), 14))
|
divide(n2,n0)|floor(#0)|multiply(n0,#1)|subtract(#1,const_1)|multiply(n0,#3)|subtract(n2,#2)|reminder(#5,n1)|subtract(n2,#4)|reminder(#7,n1)|min(#6,#8)
|
total toys to be stored 86 the big box can store 35 small box can store 14 storing 85 toys in big box 85 / 35 = 2 r 16 store remainder in small box 16 / 14 = 1 r 2 least number of toys that will be left unboxed = 2 answer : a
|
general
|
math_qa__3E2JBtmgHcvmFqEb
|
A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 35 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet? Choose the correct choice from the following options.
A) 1050 km B) 1150 km C) 1250 km D) 1550 km E) 850 km
|
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">35 - 30</gadget>
<output>5</output>
<gadget id="calculator">150 / 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 35</gadget>
<output>1_050</output>
<result>A</result>
|
A
| 1,050 |
A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 35 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
|
{
"A": "1050 km",
"B": "1150 km",
"C": "1250 km",
"D": "1550 km",
"E": "850 km"
}
|
multiply(divide(multiply(30, add(const_3, 2)), subtract(35, 30)), 35)
|
add(n2,const_3)|subtract(n3,n1)|multiply(n1,#0)|divide(#2,#1)|multiply(n3,#3)|
|
"d = 30 * 5 = 150 rs = 35 – 30 = 5 t = 150 / 5 = 30 d = 35 * 30 = 1050 km answer : a"
|
physics
|
math_qa__wyB3YprIv50dZbtb
|
Total dinning bill for 9 people was $211.00.If they add 15% tip and divided the bill evenly ,approximate.What was each persons find share Choose the correct choice:
A) $ 30.14 B) 45.14 C) 34.66 D) 26.96 E) 33.16
|
<gadget id="calculator">15 * 211</gadget>
<output>3_165</output>
<gadget id="calculator">3_165 / 100</gadget>
<output>633/20 = around 31.65</output>
<gadget id="calculator">211 + (633/20)</gadget>
<output>4_853/20 = around 242.65</output>
<gadget id="calculator">(4_853/20) / 9</gadget>
<output>4_853/180 = around 26.961111</output>
<result>D</result>
|
D
| 26.96 |
Total dinning bill for 9 people was $211.00.If they add 15% tip and divided the bill evenly ,approximate.What was each persons find share
|
{
"A": "$ 30.14",
"B": "45.14",
"C": "34.66",
"D": "26.96",
"E": "33.16"
}
|
divide(add(211.00, divide(multiply(15, 211.00), const_100)), 9)
|
multiply(n1,n2)|divide(#0,const_100)|add(n1,#1)|divide(#2,n0)|
|
"211 * 15 = 3165 / 100 = 31.65 211 + 31.65 = 242.65 242.65 / 9 = 26.96 answer : d"
|
general
|
math_qa__GSZTjTwjy2wwhSWe
|
A small company is planning to rent either computer A or computer B to print customer mailing lists. Both computer A and computer B must be rented on an hourly basis. The rental fee is based only on the amount of time the computer is turned on. It will cost 40 percent more per hour to rent computer A than to rent computer B. Computer B would, however, require 20 hours more than computer A to do the job. If either computer A, or computer B were rented the total cost to rent the computer would be $550.00. What would be the approximate hourly charge to rent computer B? Choose the correct choice from the following answers
A) $ 7.85 B) $ 11.30 C) $ 13.20 D) $ 17.80 E) $ 22.10
|
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(2/5) + (1/20)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">7 + (9/20)</gadget>
<output>149/20 = around 7.45</output>
<gadget id="calculator">(2/5) + (149/20)</gadget>
<output>157/20 = around 7.85</output>
<result>A</result>
|
A
| 7.85 |
A small company is planning to rent either computer A or computer B to print customer mailing lists. Both computer A and computer B must be rented on an hourly basis. The rental fee is based only on the amount of time the computer is turned on. It will cost 40 percent more per hour to rent computer A than to rent computer B. Computer B would, however, require 20 hours more than computer A to do the job. If either computer A, or computer B were rented the total cost to rent the computer would be $550.00. What would be the approximate hourly charge to rent computer B?
|
{
"A": "$ 7.85",
"B": "$ 11.30",
"C": "$ 13.20",
"D": "$ 17.80",
"E": "$ 22.10"
}
|
add(divide(40, const_100), add(add(const_4, const_3), add(divide(40, const_100), divide(divide(20, const_4), const_100))))
|
add(const_3,const_4)|divide(n0,const_100)|divide(n1,const_4)|divide(#2,const_100)|add(#1,#3)|add(#0,#4)|add(#5,#1)
|
pa = price of a pb = price of b ta = time for a to complete the job tb = time for b to complete the job given pa = 1.4 pb ta + 20 = tb pa * ta = pb * tb = 550 1.4 pb * ( tb - 20 ) = pb * tb 1.4 pb tb - pb tb = 1.4 pb * 20 0.4 pbtb = 28 pb tb = 28 / 0.4 = 70 pb = 550 / 70 ~ 7.85 a
|
general
|
math_qa__Z5VmklbA3PU47ggr
|
A candidate got 30% of the votes polled and he lost to his rival by 1760 votes. How many votes were cast? Choices.
A) 4000 B) 4100 C) 4200 D) 4300 E) 4400
|
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) - (3/10)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1_760 / (2/5)</gadget>
<output>4_400</output>
<result>E</result>
|
E
| 4,400 |
A candidate got 30% of the votes polled and he lost to his rival by 1760 votes. How many votes were cast?
|
{
"A": "4000",
"B": "4100",
"C": "4200",
"D": "4300",
"E": "4400"
}
|
divide(1760, subtract(subtract(const_1, divide(30, const_100)), divide(30, const_100)))
|
divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)|
|
"let x be the total number of votes . 0.3 x + 1760 = 0.7 x 0.4 x = 1760 x = 1760 / 0.4 = 4400 the answer is e ."
|
gain
|
math_qa__YJdjfyfJu5WyrDTV
|
If 4/p=8 & 4/q=18 then p-q=? Choose the correct choice from the following answers.
A) 5 / 18 B) 6 / 24 C) 7 / 24 D) 8 / 24 E) 9 / 24
|
<gadget id="calculator">4 / 8</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 / 18</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(1/2) - (2/9)</gadget>
<output>5/18 = around 0.277778</output>
<result>A</result>
|
A
| 0.277778 |
If 4/p=8 & 4/q=18 then p-q=?
|
{
"A": "5 / 18",
"B": "6 / 24",
"C": "7 / 24",
"D": "8 / 24",
"E": "9 / 24"
}
|
subtract(divide(4, 8), divide(4, 18))
|
divide(n0,n1)|divide(n0,n3)|subtract(#0,#1)|
|
"p = 4 / 8 , q = 4 / 18 = > q = 2 / 9 therefore p - q = ( 1 / 2 ) - ( 2 / 9 ) = 5 / 18 answer : a"
|
general
|
math_qa__dmDAzx03pviCJgYU
|
A student completes a 3 part exam as follows. The student completes section A in 10 minutes and takes an equal time to complete the two remaining sections. What is the ratio of time spent on section C to section A if the total duration is 1 hour? Choose the correct choice from the following answers
A) 5 : 2
B) 4 : 1
C) 4 : 3
D) 3 : 2
E) 2 : 1
|
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">60 - 10</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 / 10</gadget>
<output>5/2 = around 2.5</output>
<result>A</result>
|
A
| 2.5 |
A student completes a 3 part exam as follows. The student completes section A in 10 minutes and takes an equal time to complete the two remaining sections. What is the ratio of time spent on section C to section A if the total duration is 1 hour?
|
{
"A": "5 : 2",
"B": "4 : 1",
"C": "4 : 3",
"D": "3 : 2",
"E": "2 : 1"
}
|
divide(divide(subtract(multiply(1, const_60), 10), const_2), 10)
|
multiply(n2,const_60)|subtract(#0,n1)|divide(#1,const_2)|divide(#2,n1)
|
the time spent on section b and section c is 25 minutes each . the ratio of c to a is 25 : 10 = 5 : 2 the answer is a .
|
physics
|
math_qa__Zs4JhphUEFuILcKB
|
A certain drink of type A is prepared by mixing 4 parts milk with 3 parts fruit juice. Another drink of type B is prepared by mixing 4 parts of fruit juice and 3 parts of milk. How many liters of fruit juice must be added to 21 liters of drink A to convert it to drink B? Choose one:
A) 3
B) 4
C) 5
D) 6
E) 7
|
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">(4/7) * 21</gadget>
<output>12</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">48 / 3</gadget>
<output>16</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 21</gadget>
<output>9</output>
<gadget id="calculator">16 - 9</gadget>
<output>7</output>
<result>E</result>
|
E
| 7 |
A certain drink of type A is prepared by mixing 4 parts milk with 3 parts fruit juice. Another drink of type B is prepared by mixing 4 parts of fruit juice and 3 parts of milk. How many liters of fruit juice must be added to 21 liters of drink A to convert it to drink B?
|
{
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
}
|
subtract(divide(multiply(multiply(divide(4, add(4, 3)), 21), 4), 3), multiply(divide(3, add(4, 3)), 21))
|
add(n0,n1)|divide(n0,#0)|divide(n1,#0)|multiply(n4,#1)|multiply(n4,#2)|multiply(n0,#3)|divide(#5,n1)|subtract(#6,#4)|
|
"in 21 liters of drink a , there are 12 liters of milk and 9 liters of juice . with 12 liters of milk , we need a total of 16 liters of juice to make drink b . we need to add 7 liters of juice . the answer is e ."
|
general
|
math_qa__5s9ux1IbFjq2rQVw
|
The L.C.M. of two numbers is 54. The numbers are in the ratio 2 : 3. Then sum of the number is: Choose the correct answer:
A) 28
B) 32
C) 40
D) 45
E) 54
|
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">54 / 6</gadget>
<output>9</output>
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">27 + 18</gadget>
<output>45</output>
<result>D</result>
|
D
| 45 |
The L.C.M. of two numbers is 54. The numbers are in the ratio 2 : 3. Then sum of the number is:
|
{
"A": "28",
"B": "32",
"C": "40",
"D": "45",
"E": "54"
}
|
add(multiply(divide(54, multiply(2, 3)), 3), multiply(divide(54, multiply(2, 3)), 2))
|
multiply(n1,n2)|divide(n0,#0)|multiply(n2,#1)|multiply(n1,#1)|add(#2,#3)|
|
"let the numbers be 2 x and 3 x . then , their l . c . m . = 6 x . so , 6 x = 54 or x = 9 . the numbers are 18 and 27 . hence , required sum = ( 18 + 27 ) = 45 . answer : option d"
|
other
|
math_qa__Lj5VL9MZZLS0iY2q
|
Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is Select the correct option:
A) rs 1650 B) rs 1750 C) rs 1850 D) rs 1950 E) none of these
|
<gadget id="calculator">4_000 * 10</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 100</gadget>
<output>400</output>
<gadget id="calculator">4_000 + 400</gadget>
<output>4_400</output>
<gadget id="calculator">4_400 * 10</gadget>
<output>44_000</output>
<gadget id="calculator">44_000 / 100</gadget>
<output>440</output>
<gadget id="calculator">400 + 440</gadget>
<output>840</output>
<gadget id="calculator">840 / 2</gadget>
<output>420</output>
<gadget id="calculator">420 / 3</gadget>
<output>140</output>
<gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">14_000 / 8</gadget>
<output>1_750</output>
<result>B</result>
|
B
| 1,750 |
Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is
|
{
"A": "rs 1650",
"B": "rs 1750",
"C": "rs 1850",
"D": "rs 1950",
"E": "none of these"
}
|
divide(multiply(divide(divide(add(divide(multiply(4000, 10), const_100), divide(multiply(add(4000, divide(multiply(4000, 10), const_100)), 10), const_100)), 2), 3), const_100), 8)
|
multiply(n2,n4)|divide(#0,const_100)|add(n2,#1)|multiply(n4,#2)|divide(#3,const_100)|add(#1,#4)|divide(#5,n3)|divide(#6,n0)|multiply(#7,const_100)|divide(#8,n1)|
|
"explanation : c . i . = ( 4000 × ( 1 + 10 / 100 ) 2 − 4000 ) = 4000 ∗ 11 / 10 ∗ 11 / 10 − 4000 = 840 so s . i . = 840 / 2 = 420 so sum = s . i . ∗ 100 / r ∗ t = 420 ∗ 100 / 3 ∗ 8 = rs 1750 option b"
|
gain
|
math_qa__4cfLS4uuCUwuZkMk
|
A car is purchased on hire-purchase. The cash price is $21 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly instalments. Interest is charged at 12% p.a. What is the monthly instalment? Select.
A) $ 503 B) $ 504 C) $ 505 D) $ 506 E) $ 507
|
<gadget id="calculator">21 * 1_000</gadget>
<output>21_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">21_000 * (9/10)</gadget>
<output>18_900</output>
<gadget id="calculator">18_900 / 60</gadget>
<output>315</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) / 12</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 18_900</gadget>
<output>189</output>
<gadget id="calculator">315 + 189</gadget>
<output>504</output>
<result>B</result>
|
B
| 504 |
A car is purchased on hire-purchase. The cash price is $21 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly instalments. Interest is charged at 12% p.a. What is the monthly instalment?
|
{
"A": "$ 503",
"B": "$ 504",
"C": "$ 505",
"D": "$ 506",
"E": "$ 507"
}
|
add(divide(multiply(multiply(21, const_1000), subtract(const_1, divide(10, const_100))), 60), multiply(divide(divide(12, const_100), const_12), multiply(multiply(21, const_1000), subtract(const_1, divide(10, const_100)))))
|
divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_1000)|divide(#1,const_12)|subtract(const_1,#0)|multiply(#2,#4)|divide(#5,n3)|multiply(#3,#5)|add(#6,#7)
|
explanation : cash price = $ 21 000 deposit = 10 % × $ 21 000 = $ 2100 loan amount = $ 21000 − $ 2100 = $ 18900 i = p * r * t / 100 i = 11340 total amount = 18900 + 11340 = $ 30240 regular payment = total amount / number of payments answer : b
|
gain
|
math_qa__arEtyuzWTt6Ryle3
|
The radius of a wheel is 25.4 cm. What is the distance covered by the wheel in making 500 resolutions?
Choose the correct choice from the following: A) 724 m B) 798.3 m C) 287 m D) 278 m E) 927 m
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 25.4</gadget>
<output>79.828571</output>
<gadget id="calculator">79.828571 * 2</gadget>
<output>159.657142</output>
<gadget id="calculator">159.657142 * 500</gadget>
<output>79_828.571</output>
<gadget id="calculator">79_828.571 / 100</gadget>
<output>798.28571</output>
<result>B</result>
|
B
| 798.3 |
The radius of a wheel is 25.4 cm. What is the distance covered by the wheel in making 500 resolutions?
|
{
"A": "724 m",
"B": "798.3 m",
"C": "287 m",
"D": "278 m",
"E": "927 m"
}
|
divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 25.4), const_2), 500), const_100)
|
add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)|
|
"in one resolution , the distance covered by the wheel is its own circumference . distance covered in 500 resolutions . = 500 * 2 * 22 / 7 * 25.4 = 79829 cm = 798.3 m answer : b"
|
physics
|
math_qa__uzuijatUDvUt1UBh
|
Divide $2000 among B,C in the ratio 4:16. How many $ that C get? Choose the correct choice from the following answers:
A) $ 1200
B) $ 1400
C) $ 1600
D) $ 1800
E) $ 2000
|
<gadget id="calculator">4 + 16</gadget>
<output>20</output>
<gadget id="calculator">16 / 20</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2_000 * (4/5)</gadget>
<output>1_600</output>
<result>C</result>
|
C
| 1,600 |
Divide $2000 among B,C in the ratio 4:16. How many $ that C get?
|
{
"A": "$ 1200",
"B": "$ 1400",
"C": "$ 1600",
"D": "$ 1800",
"E": "$ 2000"
}
|
multiply(2000, divide(16, add(4, 16)))
|
add(n1,n2)|divide(n2,#0)|multiply(n0,#1)
|
sum of ratio terms = 4 + 16 = 20 c = 2000 * 16 / 20 = $ 1600 answer is c
|
other
|
math_qa__gka01oOwhqew1h0u
|
An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 15 as commission, the cloth sold through him on that day is worth Choose the correct choice from the following answers:
A) 333 B) 600 C) 887 D) 299 E) 132
|
<gadget id="calculator">2.5 / 100</gadget>
<output>0.025</output>
<gadget id="calculator">15 / 0.025</gadget>
<output>600</output>
<result>B</result>
|
B
| 600 |
An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 15 as commission, the cloth sold through him on that day is worth
|
{
"A": "333",
"B": "600",
"C": "887",
"D": "299",
"E": "132"
}
|
divide(15, divide(2.5, const_100))
|
divide(n0,const_100)|divide(n1,#0)|
|
"explanation : let the total sale be rs . x . then , 2.5 % . of x = 15 < = > ( 25 / 10 * 1 / 100 * x ) = 15 < = > x = 600 . answer : b )"
|
gain
|
math_qa__zrLw01rv1vOLXD14
|
The smallest 6 digit number exactly divisible by 111 is?
Choices.
A) 100009 B) 100010 C) 100011 D) 100015 E) 100017
|
<gadget id="calculator">1_000 * 100</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 % 111</gadget>
<output>100</output>
<gadget id="calculator">111 - 100</gadget>
<output>11</output>
<gadget id="calculator">100_000 + 11</gadget>
<output>100_011</output>
<result>C</result>
|
C
| 100,011 |
The smallest 6 digit number exactly divisible by 111 is?
|
{
"A": "100009",
"B": "100010",
"C": "100011",
"D": "100015",
"E": "100017"
}
|
add(multiply(const_1000, const_100), subtract(111, reminder(multiply(const_1000, const_100), 111)))
|
multiply(const_100,const_1000)|reminder(#0,n1)|subtract(n1,#1)|add(#0,#2)
|
the smallest 6 - digit number 100000 . 111 ) 100000 ( 900 999 - - - - - 100 - - - required number = 100000 + ( 111 - 100 ) = 100011 option c
|
general
|
math_qa__LDKoZgU6BKhkxBQT
|
The length of a rectangular field is 7/5 its width. If the perimeter of the field is 432 meters, what is the width of the field? Pick one
A) 50 B) 60 C) 70 D) 80 E) 90
|
<gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) + (7/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(14/5) + 2</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">432 / (24/5)</gadget>
<output>90</output>
<result>E</result>
|
E
| 90 |
The length of a rectangular field is 7/5 its width. If the perimeter of the field is 432 meters, what is the width of the field?
|
{
"A": "50",
"B": "60",
"C": "70",
"D": "80",
"E": "90"
}
|
divide(432, add(add(divide(7, 5), divide(7, 5)), const_2))
|
divide(n0,n1)|add(#0,#0)|add(#1,const_2)|divide(n2,#2)|
|
"let l be the length and w be the width . l = ( 7 / 5 ) w perimeter : 2 l + 2 w = 432 , 2 ( 7 / 5 ) w + 2 w = 432 solve the above equation to find : w = 90 m and l = 126 m . correct answer e ) 90"
|
geometry
|
math_qa__odqGOVW8tGOfelEx
|
Difference between the length and breadth of a rectangle is 23 m. Ifits perimeter is 206 m, then its area is?? Choose the correct choice from the following.
A) 1220 m ^ 2 B) 1520 m ^ 2 C) 2520 m ^ 2 D) 2600 m ^ 2 E) 3420 m ^ 2
|
<gadget id="calculator">206 / 2</gadget>
<output>103</output>
<gadget id="calculator">103 - 23</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">40 + 23</gadget>
<output>63</output>
<gadget id="calculator">63 * 40</gadget>
<output>2_520</output>
<result>C</result>
|
C
| 2,520 |
Difference between the length and breadth of a rectangle is 23 m. Ifits perimeter is 206 m, then its area is??
|
{
"A": "1220 m ^ 2",
"B": "1520 m ^ 2",
"C": "2520 m ^ 2",
"D": "2600 m ^ 2",
"E": "3420 m ^ 2"
}
|
rectangle_area(add(divide(subtract(divide(206, const_2), 23), const_2), 23), divide(subtract(divide(206, const_2), 23), const_2))
|
divide(n1,const_2)|subtract(#0,n0)|divide(#1,const_2)|add(n0,#2)|rectangle_area(#3,#2)
|
we have : ( l - b ) = 23 and 2 ( l + b ) = 206 or ( l + b ) = 103 . solving the two equations , we get : l = 63 and b = 40 . area = ( l x b ) = ( 63 x 40 ) m 2 = 2520 m ^ 2 c
|
geometry
|
math_qa__cdHIJguvtpD1eva5
|
The salaries of A and B together amount to $2000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? Choose the correct choice from the following options
A) $ 1000 B) $ 1250 C) $ 2500 D) $ 1500 E) $ 1200
|
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">2_000 / 4</gadget>
<output>500</output>
<gadget id="calculator">2_000 - 500</gadget>
<output>1_500</output>
<result>D</result>
|
D
| 1,500 |
The salaries of A and B together amount to $2000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary?
|
{
"A": "$ 1000",
"B": "$ 1250",
"C": "$ 2500",
"D": "$ 1500",
"E": "$ 1200"
}
|
subtract(2000, divide(2000, add(divide(subtract(const_100, 85), subtract(const_100, 95)), const_1)))
|
subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,#1)|add(#2,const_1)|divide(n0,#3)|subtract(n0,#4)|
|
"let a ' s salary is x b ' s salary = 2000 - x ( 100 - 95 ) % of x = ( 100 - 85 ) % of ( 2000 - x ) x = $ 1500 answer is d"
|
gain
|
math_qa__WifcvlZbqHbxIHHP
|
What is the least value of p, so that 123p578 is divisible by 11 Options
A) 7
B) 8
C) 6
D) 5
E) 4
|
<gadget id="calculator">lcm(123, 578)</gadget>
<output>71_094</output>
<gadget id="calculator">71_094 / 578</gadget>
<output>123</output>
<gadget id="calculator">123 / 4</gadget>
<output>123/4 = around 30.75</output>
<gadget id="calculator">(123/4) / 4</gadget>
<output>123/16 = around 7.6875</output>
<result>B</result>
|
B
| 8 |
What is the least value of p, so that 123p578 is divisible by 11
|
{
"A": "7",
"B": "8",
"C": "6",
"D": "5",
"E": "4"
}
|
divide(divide(divide(lcm(123, 578), 578), const_4), const_4)
|
lcm(n0,n1)|divide(#0,n1)|divide(#1,const_4)|divide(#2,const_4)|
|
"explanation : 123 p 578 1 + 3 + 5 + 8 = 17 2 + p + 7 = 17 = > 9 + p = 17 = > p = 17 - 9 = > p = 8 answer : option b"
|
general
|
math_qa__CtQHs36ovqXEjBwc
|
A man invested Rs. 14,400 in Rs. 100 shares of a company at 20% premium. If his company declares 5% dividend at the end of the year, then how much does he get? Choose the correct choice from the following answers.
A) 234 B) 600 C) 388 D) 278 E) 129
|
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 1_000</gadget>
<output>4_000</output>
<gadget id="calculator">10_000 + 4_000</gadget>
<output>14_000</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">14_000 + 400</gadget>
<output>14_400</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">100 * (1/5)</gadget>
<output>20</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">14_400 / 120</gadget>
<output>120</output>
<gadget id="calculator">100 * 120</gadget>
<output>12_000</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">12_000 * (1/20)</gadget>
<output>600</output>
<result>B</result>
|
B
| 600 |
A man invested Rs. 14,400 in Rs. 100 shares of a company at 20% premium. If his company declares 5% dividend at the end of the year, then how much does he get?
|
{
"A": "234",
"B": "600",
"C": "388",
"D": "278",
"E": "129"
}
|
multiply(multiply(100, divide(add(add(multiply(const_10, const_1000), multiply(const_4, const_1000)), multiply(const_4, 100)), add(100, multiply(100, divide(20, 100))))), divide(5, 100))
|
divide(n3,n1)|divide(n2,n1)|multiply(const_10,const_1000)|multiply(const_1000,const_4)|multiply(n1,const_4)|add(#2,#3)|multiply(n1,#1)|add(#5,#4)|add(n1,#6)|divide(#7,#8)|multiply(n1,#9)|multiply(#0,#10)|
|
"explanation : number of shares = = 120 . face value = rs . ( 100 x 120 ) = rs . 12000 . annual income = = rs . 600 answer : b ) rs . 600"
|
gain
|
math_qa__ic79cfsmOYgjJwZf
|
A man sold 18 toys for Rs. 27300, gaining thereby the cost price of 3 toy find the cost price of a toy Pick
A) s . 600 B) s . 800 C) s . 500 D) s . 900 E) s . 1300
|
<gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">27_300 / 21</gadget>
<output>1_300</output>
<result>E</result>
|
E
| 1,300 |
A man sold 18 toys for Rs. 27300, gaining thereby the cost price of 3 toy find the cost price of a toy
|
{
"A": "s . 600",
"B": "s . 800",
"C": "s . 500",
"D": "s . 900",
"E": "s . 1300"
}
|
divide(27300, add(18, 3))
|
add(n0,n2)|divide(n1,#0)|
|
"let the cost of one toy = x . then , cost of 18 toys = 18 x . gain = 3 x . sp of 18 toys = rs . 27300 . gain = sp â € “ cp 3 x = 27300 â € “ 18 x 21 x = 27300 x = rs . 1300 . answer : option e"
|
gain
|
math_qa__vHKOMKwA62DBHwLj
|
If 5 < x < 11 and y = x + 7, what is the greatest possible integer value of x + y?
Choose the correct choice from the following answers: A) 26 B) 27 C) 28 D) 29 E) 30
|
<gadget id="calculator">7 + 10</gadget>
<output>17</output>
<gadget id="calculator">17 + 10</gadget>
<output>27</output>
<result>C</result>
|
C
| 28 |
If 5 < x < 11 and y = x + 7, what is the greatest possible integer value of x + y?
|
{
"A": "26",
"B": "27",
"C": "28",
"D": "29",
"E": "30"
}
|
add(add(7, const_10), const_10)
|
add(n2,const_10)|add(#0,const_10)
|
x + y = x + x + 7 = 2 x + 7 we need to maximize this value and it needs to be an integer . 2 x is an integer when the decimal of x is . 0 or . 5 the largest such value is 10.5 then x + y = 10.5 + 17.5 = 28 . the answer is c .
|
general
|
math_qa__9LYNDUMGXjrJNEUx
|
Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.75 at the candy store. What is John’s weekly allowance? Choose the correct choice from the following choices.
A) $ 2.40 B) $ 2.80 C) $ 3.20 D) $ 3.60 E) $ 4.80
|
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/3) * (2/5)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(3/5) + (2/15)</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">1 - (11/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">0.75 / (4/15)</gadget>
<output>2.8125</output>
<result>B</result>
|
B
| 2.8 |
Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.75 at the candy store. What is John’s weekly allowance?
|
{
"A": "$ 2.40",
"B": "$ 2.80",
"C": "$ 3.20",
"D": "$ 3.60",
"E": "$ 4.80"
}
|
divide(0.75, subtract(const_1, add(divide(3, 5), multiply(divide(const_1, const_3), subtract(const_1, divide(3, 5))))))
|
divide(n0,n1)|divide(const_1,const_3)|subtract(const_1,#0)|multiply(#1,#2)|add(#0,#3)|subtract(const_1,#4)|divide(n2,#5)
|
total allowance = x amount spent at the arcade = 3 / 5 x amount remaining = 2 / 5 x amount spent at the toy store = 2 / 5 * 1 / 3 x = 2 / 15 x amount remaining = 2 / 5 x - 2 / 15 x = 4 / 15 x now , 4 / 15 x = $ 0.8 therefore , x = $ 2.80 . answer b
|
general
|
math_qa__KLp0LMb9o06qzmlS
|
If the simple interest on a certain amount in at 4% rate 5 years amounted to Rs.2080 less than the principal. What was the principal? Options:
A) 1500
B) 2600
C) 2507
D) 3200
E) 11500
|
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2_080 / (4/5)</gadget>
<output>2_600</output>
<result>B</result>
|
B
| 2,600 |
If the simple interest on a certain amount in at 4% rate 5 years amounted to Rs.2080 less than the principal. What was the principal?
|
{
"A": "1500",
"B": "2600",
"C": "2507",
"D": "3200",
"E": "11500"
}
|
divide(2080, subtract(const_1, divide(multiply(4, 5), const_100)))
|
multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)|
|
"p - 2080 = ( p * 5 * 4 ) / 100 p = 2600 answer : b"
|
gain
|
math_qa__fJJjriub1YuznFY4
|
The compound ratio of 2:3, 3:2 and 4:5? Pick one
A) 1 : 9 B) 1 : 7 C) 1 : 2 D) 4 : 5 E) 1 : 4
|
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 6</gadget>
<output>1</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">12 / 10</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1 / (6/5)</gadget>
<output>5/6 = around 0.833333</output>
<result>D</result>
|
D
| 0.8 |
The compound ratio of 2:3, 3:2 and 4:5?
|
{
"A": "1 : 9",
"B": "1 : 7",
"C": "1 : 2",
"D": "4 : 5",
"E": "1 : 4"
}
|
divide(divide(multiply(2, 3), multiply(3, 2)), divide(multiply(3, 4), multiply(2, 5)))
|
multiply(n0,n2)|multiply(n1,n3)|multiply(n2,n4)|multiply(n3,n5)|divide(#0,#1)|divide(#2,#3)|divide(#4,#5)|
|
"2 / 3 * 3 / 2 * 4 / 5 = 4 / 5 = 4 : 5 answer : d"
|
other
|
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