id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__rCc9KTX1w4vC0a2O
|
P and Q invested in a business. The profit earned was divided in the ratio 4 : 5. If P invested Rs 52000, the amount invested by Q is Choose the correct choice from the following options: A) 30000 B) 50000 C) 40000 D) 20000 E) 65000
|
<gadget id="calculator">52_000 / 4</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 * 5</gadget>
<output>65_000</output>
<result>E</result>
|
E
| 65,000 |
P and Q invested in a business. The profit earned was divided in the ratio 4 : 5. If P invested Rs 52000, the amount invested by Q is
|
{
"A": "30000",
"B": "50000",
"C": "40000",
"D": "20000",
"E": "65000"
}
|
multiply(divide(52000, 4), 5)
|
divide(n2,n0)|multiply(n1,#0)|
|
"let the amount invested by q = q 52000 : q = 4 : 5 ⇒ 52000 × 5 = 4 q ⇒ q = ( 52000 × 5 ) / 4 = 65000 answer is e ."
|
gain
|
math_qa__7DRkMPSDaIYwG6Rl
|
A goods train runs at the speed of 72 km/hr and crosses a 280 m long platform in 26 sec. What is the length of the goods train? Options
A) 240 B) 277 C) 276 D) 270 E) 281
|
<gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 280</gadget>
<output>240</output>
<result>A</result>
|
A
| 240 |
A goods train runs at the speed of 72 km/hr and crosses a 280 m long platform in 26 sec. What is the length of the goods train?
|
{
"A": "240",
"B": "277",
"C": "276",
"D": "270",
"E": "281"
}
|
subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 280)
|
divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)|
|
"speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 280 ) / 26 = 20 x = 240 m . answer : a"
|
physics
|
math_qa__0znW5lKplyJ2xt0t
|
A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.13 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost? Choose the correct option:
A) 1276
B) 1560
C) 2832
D) 1299
E) 1236
|
<gadget id="calculator">1_200 / 30</gadget>
<output>40</output>
<gadget id="calculator">30 + 40</gadget>
<output>70</output>
<gadget id="calculator">30 ** 2</gadget>
<output>900</output>
<gadget id="calculator">40 ** 2</gadget>
<output>1_600</output>
<gadget id="calculator">900 + 1_600</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 ** (1/2)</gadget>
<output>50</output>
<gadget id="calculator">70 + 50</gadget>
<output>120</output>
<gadget id="calculator">120 * 13</gadget>
<output>1_560</output>
<result>B</result>
|
B
| 1,560 |
A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.13 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?
|
{
"A": "1276",
"B": "1560",
"C": "2832",
"D": "1299",
"E": "1236"
}
|
multiply(add(add(30, divide(1200, 30)), sqrt(add(power(30, 2), power(divide(1200, 30), 2)))), 13)
|
divide(n1,n3)|power(n3,n2)|add(n3,#0)|power(#0,n2)|add(#1,#3)|sqrt(#4)|add(#2,#5)|multiply(n0,#6)|
|
"explanation : l * 30 = 1200 è l = 40 40 + 30 + 50 = 120 120 * 13 = 1560 answer : option b"
|
geometry
|
math_qa__ckzrLWF7j6LFG3KP
|
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 50 sq. feet, how many feet of fencing will be required? Choose the correct choice from the following:
A) 34 B) 40 C) 25 D) 88 E) 78
|
<gadget id="calculator">50 / 20</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 20</gadget>
<output>25</output>
<result>C</result>
|
C
| 25 |
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 50 sq. feet, how many feet of fencing will be required?
|
{
"A": "34",
"B": "40",
"C": "25",
"D": "88",
"E": "78"
}
|
add(multiply(divide(50, 20), const_2), 20)
|
divide(n1,n0)|multiply(#0,const_2)|add(n0,#1)|
|
"we have : l = 20 ft and lb = 50 sq . ft . so , b = 2.5 ft . length of fencing = ( l + 2 b ) = ( 20 + 5 ) ft = 25 ft . answer : c"
|
geometry
|
math_qa__qmZ6j5rlBhqr6Qzu
|
The average weight of 24 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class. Choose the correct option
A) 48.975 B) 42.255 C) 50 D) 51.255 E) 52.253
|
<gadget id="calculator">24 * 50.25</gadget>
<output>1_206</output>
<gadget id="calculator">8 * 45.15</gadget>
<output>361.2</output>
<gadget id="calculator">1_206 + 361.2</gadget>
<output>1_567.2</output>
<gadget id="calculator">24 + 8</gadget>
<output>32</output>
<gadget id="calculator">1_567.2 / 32</gadget>
<output>48.975</output>
<result>A</result>
|
A
| 48.975 |
The average weight of 24 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
|
{
"A": "48.975",
"B": "42.255",
"C": "50",
"D": "51.255",
"E": "52.253"
}
|
divide(add(multiply(24, 50.25), multiply(8, 45.15)), add(24, 8))
|
add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)|
|
"explanation : average weight of 24 boys = 50.25 total weight of 24 boys = 50.25 × 24 average weight of remaining 8 boys = 45.15 total weight of remaining 8 boys = 45.15 × 8 total weight of all boys in the class = ( 50.25 × 24 ) + ( 45.15 × 8 ) total boys = 24 + 8 = 32 average weight of all the boys = ( 50.25 × 24 ) + ( 45.15 × 8 ) / 32 = 48.975 answer : option a"
|
general
|
math_qa__F4OxqqSgAswjMxQF
|
If 'y' is a positive integer exactly divisible by 4 or 5 but not divisible by 8.What could possibly be the value of 'y' ? Choose the correct answer
A) 40 B) 80 C) 20 D) 24 E) 36
|
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<result>C</result>
|
C
| 20 |
If 'y' is a positive integer exactly divisible by 4 or 5 but not divisible by 8.What could possibly be the value of 'y' ?
|
{
"A": "40",
"B": "80",
"C": "20",
"D": "24",
"E": "36"
}
|
multiply(4, 5)
|
multiply(n0,n1)
|
40 and 80 are both divisible by 4 and 5 but also by 8 . so they are not the right answer . 24 and 36 are both clearly not divisible by 5 ( not correct ) 20 is both divisible by 4 and 5 but not by 8 . answer : ( c )
|
general
|
math_qa__0t4Mt5kLtVZrd6Du
|
How many figures are required to number the pages the pages of a book containing 1000 pages? Select the correct option.
A) 2793 B) 2333 C) 2993 D) 2893 E) 2693
|
<gadget id="calculator">1_000 / 10</gadget>
<output>100</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">99 - 9</gadget>
<output>90</output>
<gadget id="calculator">9 + 90</gadget>
<output>99</output>
<gadget id="calculator">1_000 - 1</gadget>
<output>999</output>
<gadget id="calculator">999 - 99</gadget>
<output>900</output>
<gadget id="calculator">900 * 3</gadget>
<output>2_700</output>
<gadget id="calculator">99 + 2_700</gadget>
<output>2_799</output>
<result>D</result>
|
D
| 2,893 |
How many figures are required to number the pages the pages of a book containing 1000 pages?
|
{
"A": "2793",
"B": "2333",
"C": "2993",
"D": "2893",
"E": "2693"
}
|
add(add(subtract(divide(divide(1000, const_10), const_10), const_1), subtract(subtract(divide(1000, const_10), const_1), subtract(divide(divide(1000, const_10), const_10), const_1))), multiply(subtract(subtract(1000, const_1), subtract(divide(1000, const_10), const_1)), const_3))
|
divide(n0,const_10)|subtract(n0,const_1)|divide(#0,const_10)|subtract(#0,const_1)|subtract(#2,const_1)|subtract(#1,#3)|multiply(#5,const_3)|subtract(#3,#4)|add(#4,#7)|add(#8,#6)
|
1 to 9 = 9 * 1 = 9 10 to 99 = 90 * 2 = 180 100 to 999 = 900 * 3 = 2700 1000 = 4 - - - - - - - - - - - 2893 answer : d
|
general
|
math_qa__j0kNkFQ28ZTR1mvM
|
The diagonal of a rhombus are 65 m and 60 m. Its area is:
Choose the correct choice from the following choices
A) 1940 B) 1950 C) 1960 D) 1990 E) 1980
|
<gadget id="calculator">(65 * 60) / 2</gadget>
<output>1_950</output>
<result>B</result>
|
B
| 1,950 |
The diagonal of a rhombus are 65 m and 60 m. Its area is:
|
{
"A": "1940",
"B": "1950",
"C": "1960",
"D": "1990",
"E": "1980"
}
|
rhombus_area(65, 60)
|
rhombus_area(n0,n1)|
|
"area of the rhombus = 1 / 2 d 1 d 2 = ( 1 / 2 × 65 × 60 ) cm ( power ) 2 = 65 × 30 = 1950 cm ( power ) 2 answer is b ."
|
geometry
|
math_qa__AUOnGBqtvaHjs3Ug
|
A and B finish the job in 15 days.while A,B and C can finish it in 10 days . C alone will finish the job in Choose the correct choice from the following options:
A) 40 days B) 30 days C) 60 days D) 70 days E) 50 days
|
<gadget id="calculator">10 * 15</gadget>
<output>150</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">150 / 5</gadget>
<output>30</output>
<result>B</result>
|
B
| 30 |
A and B finish the job in 15 days.while A,B and C can finish it in 10 days . C alone will finish the job in
|
{
"A": "40 days",
"B": "30 days",
"C": "60 days",
"D": "70 days",
"E": "50 days"
}
|
divide(multiply(10, 15), subtract(15, 10))
|
multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)|
|
"explanation : 10 = ( 15 * x ) / ( 15 + x ) 150 + 10 x = 15 x 5 x = 150 x = 30 answer : option b"
|
physics
|
math_qa__Pn40B6VLukXm0c7n
|
The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 1 year?
Choose the correct choice from the following answers.
A) 3277 B) 2977 C) 30000 D) 6077 E) 17112
|
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 10_000</gadget>
<output>40_000</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 1</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">40_000 * (3/4)</gadget>
<output>30_000</output>
<result>C</result>
|
C
| 30,000 |
The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 1 year?
|
{
"A": "3277",
"B": "2977",
"C": "30000",
"D": "6077",
"E": "17112"
}
|
multiply(multiply(4, multiply(const_100, const_100)), power(divide(3, 4), 1))
|
divide(n0,n1)|multiply(const_100,const_100)|multiply(n1,#1)|power(#0,n3)|multiply(#2,#3)|
|
"explanation : 40,000 * ( 3 / 4 ) ^ 1 answer : c"
|
general
|
math_qa__IR8CRzLYsCMemfXD
|
the greatest number by which the product of 3 consecutive multiples of 4 is always divisible is Choices
A) 54 B) 76 C) 152 D) 384 E) none of these
|
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">32 * 12</gadget>
<output>384</output>
<result>D</result>
|
D
| 384 |
the greatest number by which the product of 3 consecutive multiples of 4 is always divisible is
|
{
"A": "54",
"B": "76",
"C": "152",
"D": "384",
"E": "none of these"
}
|
multiply(multiply(4, multiply(4, const_2)), multiply(4, 3))
|
multiply(n1,const_2)|multiply(n0,n1)|multiply(n1,#0)|multiply(#2,#1)
|
solution required number = product of first three multiplies of 3 = ( 4 ã — 8 ã — 12 ) = 384 . answer d
|
general
|
math_qa__6JHJkxN4YwEM1QYD
|
If both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3), what is the smallest possible positive value of n?
. Pick:
A) 25
B) 27
C) 45
D) 75
E) 125
|
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 3</gadget>
<output>75</output>
<result>D</result>
|
D
| 75 |
If both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3), what is the smallest possible positive value of n?
.
|
{
"A": "25",
"B": "27",
"C": "45",
"D": "75",
"E": "125"
}
|
multiply(power(5, 2), 3)
|
power(n0,n1)|multiply(n2,#0)
|
if both 5 ^ 2 & 3 ^ 3 are factors , then they must be present in the number . leaving rest of the prime factors and splitting 6 ^ 2 into 3 ^ 2 * 2 ^ 3 . the number is lacking 5 ^ 2 & a 3 , so that 5 ^ 2 and 3 ^ 3 is a factor . hence the smallest number is 5 ^ 2 * 3 = 75 answer : d
|
other
|
math_qa__Be9luxoszwy4pUTg
|
rajesh spends 40 % of his monthly salary on food , 20 % of the medicines and saves 60 % of the remaining amount . if his monthly salary is rs . 15000 , how much money does he save every month ? Choose the correct choice from the following choices:
A) rs . 1000 B) rs . 2596 C) rs . 4320 D) rs . 6489 E) rs . 4789
|
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(9/25) * (4/5)</gadget>
<output>36/125 = around 0.288</output>
<gadget id="calculator">(36/125) * 15_000</gadget>
<output>4_320</output>
<result>C</result>
|
C
| 4,320 |
rajesh spends 40 % of his monthly salary on food , 20 % of the medicines and saves 60 % of the remaining amount . if his monthly salary is rs . 15000 , how much money does he save every month ?
|
{
"A": "rs . 1000",
"B": "rs . 2596",
"C": "rs . 4320",
"D": "rs . 6489",
"E": "rs . 4789"
}
|
multiply(multiply(multiply(divide(60, const_100), divide(subtract(const_100, 40), const_100)), divide(subtract(const_100, 20), const_100)), 15000)
|
divide(n2,const_100)|subtract(const_100,n1)|subtract(const_100,n0)|divide(#1,const_100)|divide(#2,const_100)|multiply(#0,#4)|multiply(#3,#5)|multiply(n3,#6)
|
explanation : ramesh ' s monthly income = rs . 15000 he spends 40 % on food . the total money spent on food = 40 / 100 * 15000 = rs . 6000 now , his monthly remaining income = rs . 15000 – rs . 6000 = rs . 9000 out of rs . 9000 , he spends 20 % on medicines . the total money spent on medicines = 20 / 100 * 9000 = rs . 1800 now , his monthly remaining income = rs . 9000 – rs . 1800 = rs . 7200 out of rs . 7200 , he saves 600 % . amount saved = 60 / 100 * 7200 = rs . 4320 answer : c
|
gain
|
math_qa__EnM38j95JyElkXBy
|
The average (arithmetic mean) of 14, 32, and 53 is 3 more than the average of 21, 47, and x. What is x? Choose the correct choice from the following: A) 20 B) 21 C) 22 D) 23 E) 24
|
<gadget id="calculator">14 + 32</gadget>
<output>46</output>
<gadget id="calculator">46 + 53</gadget>
<output>99</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 21</gadget>
<output>30</output>
<gadget id="calculator">30 + 47</gadget>
<output>77</output>
<gadget id="calculator">99 - 77</gadget>
<output>22</output>
<result>C</result>
|
C
| 22 |
The average (arithmetic mean) of 14, 32, and 53 is 3 more than the average of 21, 47, and x. What is x?
|
{
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
}
|
subtract(add(add(14, 32), 53), add(add(multiply(3, const_3), 21), 47))
|
add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)|
|
"the average of 14 , 32 , and 53 is 33 . the average of 21 , 47 and x is 30 . then 21 + 47 + x = 90 . x = 22 . the answer is c ."
|
general
|
math_qa__VSxfz9tQ3mXXNXHe
|
How long does a train 165 meters long running at the rate of 36 kmph take to cross a bridge 660 meters in length? Choose the correct choice from the following answers:
A) 33 B) 72 C) 55 D) 82.5 E) 62
|
<gadget id="calculator">165 + 660</gadget>
<output>825</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">825 / 10</gadget>
<output>165/2 = around 82.5</output>
<result>D</result>
|
D
| 82.5 |
How long does a train 165 meters long running at the rate of 36 kmph take to cross a bridge 660 meters in length?
|
{
"A": "33",
"B": "72",
"C": "55",
"D": "82.5",
"E": "62"
}
|
divide(add(165, 660), multiply(36, const_0_2778))
|
add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)|
|
"explanation : t = ( 660 + 165 ) / 36 * 18 / 5 t = 82.5 answer : option d"
|
physics
|
math_qa__cPvjRZusVLFu3xqg
|
A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 4500 as profit , what is their total profit?
Select the correct option
A) 28000 B) 30000 C) 31500 D) 34000 E) none of these
|
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">4_500 / (1/7)</gadget>
<output>31_500</output>
<result>C</result>
|
C
| 31,500 |
A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 4500 as profit , what is their total profit?
|
{
"A": "28000",
"B": "30000",
"C": "31500",
"D": "34000",
"E": "none of these"
}
|
divide(4500, divide(multiply(const_1, const_1), add(multiply(const_3, const_2), multiply(const_1, const_1))))
|
multiply(const_1,const_1)|multiply(const_2,const_3)|add(#1,#0)|divide(#0,#2)|divide(n0,#3)|
|
"explanation : suppose b ' s investment = x . then a ' s investment = 3 x suppose bs period of investment = y , then a ' s period of investment = 2 y a : b = 3 x * 2 y : xy = 6 : 1 total profit * 1 / 7 = 4500 = > total profit = 4500 * 7 = 31500 . answer : option c"
|
general
|
math_qa__XFzyiKRkhuebUpSP
|
Robert's salary was decreased by 30% and subsequently increased by 30%. how much percentage does he lose? Choose the most appropriate option: A) 10 % B) 9 % C) 25 % D) 30 % E) 50 %
|
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">70 * 130</gadget>
<output>9_100</output>
<gadget id="calculator">10_000 - 9_100</gadget>
<output>900</output>
<gadget id="calculator">900 / 10_000</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 100</gadget>
<output>9</output>
<result>B</result>
|
B
| 9 |
Robert's salary was decreased by 30% and subsequently increased by 30%. how much percentage does he lose?
|
{
"A": "10 %",
"B": "9 %",
"C": "25 %",
"D": "30 %",
"E": "50 %"
}
|
multiply(divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 30), add(const_100, 30))), multiply(const_100, const_100)), const_100)
|
add(n0,const_100)|multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,#1)|multiply(#5,const_100)|
|
"let original salary be $ 100 salary after decreasing 30 % = 100 - 100 x 30 / 100 = $ 70 salary after increasing 30 % on $ 70 = 70 + 70 x 30 / 100 = $ 91 percentage of loss = 100 - 91 = 9 % answer : b"
|
general
|
math_qa__bqVNvNpFg3RdqMxb
|
The total age of A and B is 20 years more than the total age of B and C. C is how many years younger than A.? Pick one
A) 20 B) 12 C) 15 D) 16 E) 10
|
<gadget id="calculator">20 * 1</gadget>
<output>20</output>
<result>A</result>
|
A
| 20 |
The total age of A and B is 20 years more than the total age of B and C. C is how many years younger than A.?
|
{
"A": "20",
"B": "12",
"C": "15",
"D": "16",
"E": "10"
}
|
multiply(20, const_1)
|
multiply(n0,const_1)|
|
"( a + b ) - ( b - c ) = 20 a - c = 20 answer is a"
|
general
|
math_qa__6ZCRyN45xcDm5ctj
|
If 6 cats can kill 6 rats in 6 minutes, how long will it take 100 cats to kill 100 rats? Choose one
A) 1 minutes B) 2 minutes C) 3 minutes D) 4 minutes E) 6 minutes
|
<gadget id="calculator">6 * 1</gadget>
<output>6</output>
<result>E</result>
|
E
| 6 |
If 6 cats can kill 6 rats in 6 minutes, how long will it take 100 cats to kill 100 rats?
|
{
"A": "1 minutes",
"B": "2 minutes",
"C": "3 minutes",
"D": "4 minutes",
"E": "6 minutes"
}
|
multiply(6, const_1)
|
multiply(n0,const_1)|
|
"it will take 6 minutes for 100 cats to kill 100 rats . 1 cat can kill 1 rat in 6 minutes , so 100 cats can kill 100 rats in 6 minutes answer e"
|
physics
|
math_qa__g8IhrvBxxtNHSVDb
|
3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 175kg then find the average weight of all the 7 rounds?
Choose the correct choice from the following options:
A) 100 kgs B) 88.5 kgs C) 86.5 kgs D) 67.5 kgs E) 88.2 kgs
|
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 175</gadget>
<output>700</output>
<gadget id="calculator">700 / 7</gadget>
<output>100</output>
<result>A</result>
|
A
| 100 |
3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 175kg then find the average weight of all the 7 rounds?
|
{
"A": "100 kgs",
"B": "88.5 kgs",
"C": "86.5 kgs",
"D": "67.5 kgs",
"E": "88.2 kgs"
}
|
divide(multiply(add(const_1, 3), 175), 7)
|
add(const_1,n0)|multiply(n2,#0)|divide(#1,n1)|
|
"average weight = [ ( a + b + c + ( a + b ) + ( b + c ) + ( c + a ) + ( a + b + c ) ] / 7 = 4 ( a + b + c ) / 7 = 4 x 175 / 7 = 100 kgs answer : a"
|
general
|
math_qa__kmVtUmsr72JRgG0K
|
if price of t.v set is reduced by 18%, then its sale increases by 72%, find net effect on sale value Choose the correct option.
A) 41 B) 45 C) 46 D) 47 E) 48
|
<gadget id="calculator">100 - 18</gadget>
<output>82</output>
<gadget id="calculator">82 / 100</gadget>
<output>41/50 = around 0.82</output>
<gadget id="calculator">100 + 72</gadget>
<output>172</output>
<gadget id="calculator">172 / 100</gadget>
<output>43/25 = around 1.72</output>
<gadget id="calculator">(41/50) * (43/25)</gadget>
<output>1_763/1_250 = around 1.4104</output>
<gadget id="calculator">(1_763/1_250) - 1</gadget>
<output>513/1_250 = around 0.4104</output>
<gadget id="calculator">(513/1_250) * 100</gadget>
<output>1_026/25 = around 41.04</output>
<result>A</result>
|
A
| 41 |
if price of t.v set is reduced by 18%, then its sale increases by 72%, find net effect on sale value
|
{
"A": "41",
"B": "45",
"C": "46",
"D": "47",
"E": "48"
}
|
multiply(subtract(multiply(divide(subtract(const_100, 18), const_100), divide(add(const_100, 72), const_100)), const_1), const_100)
|
add(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|divide(#0,const_100)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)|
|
"- a + b + ( ( - a ) ( b ) / 100 ) = - 18 + 72 + ( - 18 * 72 ) / 100 = - 18 + 72 - 13 = 41 answer : a"
|
gain
|
math_qa__B6mZUT3eTqhfvXJ8
|
Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 155 per Kg , the price of the third variety per Kg will be? Choose the correct choice:
A) rs . 147.50 B) rs . 785.50 C) rs . 177.50 D) rs . 258.50 E) none of these
|
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">155 * 4</gadget>
<output>620</output>
<gadget id="calculator">126 + 135</gadget>
<output>261</output>
<gadget id="calculator">620 - 261</gadget>
<output>359</output>
<gadget id="calculator">359 / 2</gadget>
<output>359/2 = around 179.5</output>
<result>C</result>
|
C
| 177.5 |
Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 155 per Kg , the price of the third variety per Kg will be?
|
{
"A": "rs . 147.50",
"B": "rs . 785.50",
"C": "rs . 177.50",
"D": "rs . 258.50",
"E": "none of these"
}
|
divide(subtract(multiply(155, add(add(1, 1), 2)), add(126, 135)), 2)
|
add(n2,n2)|add(n0,n1)|add(n4,#0)|multiply(n5,#2)|subtract(#3,#1)|divide(#4,n4)|
|
"explanation : since first and second varieties are mixed in equal proportions . so , their average price = rs . ( 126 + 135 ) / 2 . = > rs . 130.50 . so , the mixture is formed by mixing two varieties , one at rs . 130.50 per kg and the other at say , rs . x per kg in the ratio 2 : 2 , i . e . , 1 : 1 . we have to find x . by the rule of alligation , we have : cost of 1 kg cost of 1 kg of 1 st kind of 2 nd kind ( rs . 130.50 ) ( rs . x ) \ / mean price ( rs . 155 ) / \ x â ˆ ’ 155 22.50 = > x â ˆ ’ ( 155 / 22.50 ) = 1 . = > x â ˆ ’ 155 = 22.50 . = > x = 177.50 rs . answer : c"
|
other
|
math_qa__pS0R7MgJrjDFwcPr
|
Solution for 4.75+.303+.432
Choose the correct choice from the following.
A) 2.91 B) 5.911 C) 5.485 D) 5.986 E) 2.999
|
<gadget id="calculator">303 / 1_000</gadget>
<output>303/1_000 = around 0.303</output>
<gadget id="calculator">4.75 + (303/1_000)</gadget>
<output>5.053</output>
<gadget id="calculator">432 / 1_000</gadget>
<output>54/125 = around 0.432</output>
<gadget id="calculator">5.053 + (54/125)</gadget>
<output>5.485</output>
<result>C</result>
|
C
| 5.485 |
Solution for 4.75+.303+.432
|
{
"A": "2.91",
"B": "5.911",
"C": "5.485",
"D": "5.986",
"E": "2.999"
}
|
add(add(4.75, divide(303, const_1000)), divide(432, const_1000))
|
divide(n1,const_1000)|divide(n2,const_1000)|add(n0,#0)|add(#2,#1)|
|
"4.75 + . 303 + . 432 = 0 0 = 0 - 4.75 - 0.303 - 0.432 0 = - 5.485 answer : c"
|
general
|
math_qa__l0z3ITkopkCm32F7
|
What number is 70 more than one-fourth of itself? Choose the correct choice from the following answers.
A) 93 B) 225 C) 288 D) 324 E) 336
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">70 / (3/4)</gadget>
<output>280/3 = around 93.333333</output>
<result>A</result>
|
A
| 93 |
What number is 70 more than one-fourth of itself?
|
{
"A": "93",
"B": "225",
"C": "288",
"D": "324",
"E": "336"
}
|
divide(70, subtract(const_1, divide(const_1, const_4)))
|
divide(const_1,const_4)|subtract(const_1,#0)|divide(n0,#1)
|
1 / 4 x + 70 = x that means 70 = 3 / 4 x x = ( 70 * 4 ) / 3 = 280 / 3 = 93 a is the answer .
|
general
|
math_qa__nTaBBQ4fZ4vpHlF5
|
2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school? Choose the correct choice from the following options:
A) 500 B) 600 C) 800 D) 900 E) 1200
|
<gadget id="calculator">550 - 150</gadget>
<output>400</output>
<gadget id="calculator">400 * 3</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 2</gadget>
<output>600</output>
<gadget id="calculator">150 * 4</gadget>
<output>600</output>
<gadget id="calculator">600 / 3</gadget>
<output>200</output>
<gadget id="calculator">600 + 200</gadget>
<output>800</output>
<result>C</result>
|
C
| 800 |
2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?
|
{
"A": "500",
"B": "600",
"C": "800",
"D": "900",
"E": "1200"
}
|
add(divide(multiply(subtract(550, 150), 3), 2), divide(multiply(150, 4), 3))
|
multiply(n3,n5)|subtract(n4,n5)|divide(#0,n1)|multiply(n1,#1)|divide(#3,n0)|add(#4,#2)
|
let total number of boys be x and total number of girls be y . y = 400 = > x = 600 and ^ = i 50 = > y = 200 now , x + y = 800 c
|
general
|
math_qa__Nmxv8QO9bfGIhjD8
|
Length of a rectangular plot is 30 mtr more than its breadth. If the cost of fencin g the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? Select:
A) 46 m B) 60 m C) 65 m D) 78 m E) 80 m
|
<gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">200 + 60</gadget>
<output>260</output>
<gadget id="calculator">260 / 4</gadget>
<output>65</output>
<result>C</result>
|
C
| 65 |
Length of a rectangular plot is 30 mtr more than its breadth. If the cost of fencin g the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
|
{
"A": "46 m",
"B": "60 m",
"C": "65 m",
"D": "78 m",
"E": "80 m"
}
|
divide(add(divide(5300, 26.50), multiply(const_2, 30)), const_4)
|
divide(n2,n1)|multiply(n0,const_2)|add(#0,#1)|divide(#2,const_4)|
|
"let breadth = x metres . then , length = ( x + 30 ) metres . perimeter = 5300 / 26.5 m = 200 m . 2 [ ( x + 30 ) + x ] = 200 2 x + 30 = 100 2 x = 70 x = 35 . hence , length = x + 30 = 65 m c"
|
physics
|
math_qa__B7O7vYdO4c5QEIon
|
A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5 hours, then the distance covered at 40 kmph is Select the correct option
A) 130 km B) 120 km C) 100 km D) 140 km E) none of these
|
<gadget id="calculator">60 * 5</gadget>
<output>300</output>
<gadget id="calculator">300 - 250</gadget>
<output>50</output>
<gadget id="calculator">40 - 60</gadget>
<output>-20</output>
<gadget id="calculator">-(-20)</gadget>
<output>20</output>
<gadget id="calculator">50 / 20</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 40</gadget>
<output>100</output>
<result>C</result>
|
C
| 100 |
A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5 hours, then the distance covered at 40 kmph is
|
{
"A": "130 km",
"B": "120 km",
"C": "100 km",
"D": "140 km",
"E": "none of these"
}
|
multiply(divide(subtract(multiply(60, 5), 250), negate(subtract(40, 60))), 40)
|
multiply(n2,n3)|subtract(n1,n2)|negate(#1)|subtract(#0,n0)|divide(#3,#2)|multiply(n1,#4)|
|
"let the partial distance covered at 40 kmph be x let the another partial distance covered at 60 kmph be ( 250 - x ) thus , x / 40 - ( 250 - x ) / 60 = 5 or , x / 40 + ( 250 - x ) / 60 = 5 or , ( 3 x + 500 - 2 x ) / / 120 = 5 or 500 + x = 600 x = 100 answer : c"
|
physics
|
math_qa__lMiLBQar3dbrwbYw
|
How many litres of pure acid are there in 5 litres of a 30% solution Choose the correct choice from the following choices
A) 1.5 B) 1.6 C) 1.7 D) 1.8 E) 1.9
|
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 5</gadget>
<output>3/2 = around 1.5</output>
<result>A</result>
|
A
| 1.5 |
How many litres of pure acid are there in 5 litres of a 30% solution
|
{
"A": "1.5",
"B": "1.6",
"C": "1.7",
"D": "1.8",
"E": "1.9"
}
|
multiply(divide(30, const_100), 5)
|
divide(n1,const_100)|multiply(n0,#0)|
|
explanation : question of this type looks a bit typical , but it is too simple , as below . . . it will be 5 * 30 / 100 = 1.5 answer : option a
|
gain
|
math_qa__lM8ybYKTzhGWkbF2
|
In a college students can play cricket or basketball. 500 play cricket.220 played both and 600 played basketball. What is the total strength of college? Select.
A) 800 B) 880 C) 920 D) 950 E) 980
|
<gadget id="calculator">500 + 600</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 - 220</gadget>
<output>880</output>
<result>B</result>
|
B
| 880 |
In a college students can play cricket or basketball. 500 play cricket.220 played both and 600 played basketball. What is the total strength of college?
|
{
"A": "800",
"B": "880",
"C": "920",
"D": "950",
"E": "980"
}
|
subtract(add(500, 600), 220)
|
add(n0,n2)|subtract(#0,n1)
|
p ( c ) = 500 p ( b ) = 600 p ( c n b ) = 220 p ( c u b ) = p ( c ) + p ( b ) - p ( c n b ) = 500 + 600 - 220 = 880 answer : b
|
other
|
math_qa__fIkaFjqBZNsf1nZ5
|
If an average hard drive had a capacity of 0.2 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050?
Pick
A) 256 B) 5122 C) 768 D) 2048 E) 1536
|
<gadget id="calculator">0.2 * 2</gadget>
<output>0.4</output>
<gadget id="calculator">0.4 * 2</gadget>
<output>0.8</output>
<gadget id="calculator">0.8 * 2</gadget>
<output>1.6</output>
<gadget id="calculator">1.6 * 2</gadget>
<output>3.2</output>
<gadget id="calculator">3.2 * 2</gadget>
<output>6.4</output>
<gadget id="calculator">6.4 * 2</gadget>
<output>12.8</output>
<gadget id="calculator">12.8 * 2</gadget>
<output>25.6</output>
<gadget id="calculator">25.6 * 2</gadget>
<output>51.2</output>
<gadget id="calculator">51.2 * 2</gadget>
<output>102.4</output>
<gadget id="calculator">102.4 * 2</gadget>
<output>204.8</output>
<gadget id="calculator">204.8 + 0.2</gadget>
<output>205</output>
<gadget id="calculator">205 * 10</gadget>
<output>2_050</output>
<result>D</result>
|
D
| 2,048 |
If an average hard drive had a capacity of 0.2 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050?
|
{
"A": "256",
"B": "5122",
"C": "768",
"D": "2048",
"E": "1536"
}
|
multiply(add(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(0.2, const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), 0.2), const_10)
|
multiply(n0,const_2)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#2,const_2)|multiply(#3,const_2)|multiply(#4,const_2)|multiply(#5,const_2)|multiply(#6,const_2)|multiply(#7,const_2)|multiply(#8,const_2)|add(n0,#9)|multiply(#10,const_10)|
|
"0.2 * 2 ^ 10 = 0.2 * 1024 = 204.8 the answer is d ."
|
general
|
math_qa__iblcxlFBAX7d7w2v
|
The cricket team of 11members is 24yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? Pick one.
A) 21
B) 22
C) 23
D) 25
E) 28
|
<gadget id="calculator">24 + 3</gadget>
<output>27</output>
<gadget id="calculator">27 + 24</gadget>
<output>51</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">51 - 9</gadget>
<output>42</output>
<gadget id="calculator">11 - 9</gadget>
<output>2</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<result>A</result>
|
A
| 21 |
The cricket team of 11members is 24yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?
|
{
"A": "21",
"B": "22",
"C": "23",
"D": "25",
"E": "28"
}
|
divide(subtract(add(add(24, 3), 24), subtract(11, 2)), subtract(11, subtract(11, 2)))
|
add(n1,n2)|subtract(n0,n3)|add(n1,#0)|subtract(n0,#1)|subtract(#2,#1)|divide(#4,#3)|
|
"let the average age of the whole team be x years . 11 x - ( 24 + 27 ) = 9 ( x - 1 ) = > 11 x - 9 x = 42 = > 2 x = 42 = > x = 21 . so , average age of the team is 21 years . a"
|
general
|
math_qa__OIMDMLAgLU9Eyri9
|
what is the least number. which should be added to 0.0320 to make it a perfect square? Choose one.
A) 0.0005
B) 0.0004
C) 0.0006
D) 0.0002
E) 0.0001
|
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * (9/50)</gadget>
<output>81/2_500 = around 0.0324</output>
<gadget id="calculator">(81/2_500) - 0.032</gadget>
<output>0.0004</output>
<result>B</result>
|
B
| 0.0004 |
what is the least number. which should be added to 0.0320 to make it a perfect square?
|
{
"A": "0.0005",
"B": "0.0004",
"C": "0.0006",
"D": "0.0002",
"E": "0.0001"
}
|
subtract(multiply(divide(add(add(const_12, const_4), const_2), const_100), divide(add(add(const_12, const_4), const_2), const_100)), 0.032)
|
add(const_12,const_4)|add(#0,const_2)|divide(#1,const_100)|multiply(#2,#2)|subtract(#3,n0)
|
0.0320 + 0.0004 = 0.0324 ( 0.18 ) ^ 2 answer : b
|
general
|
math_qa__8z8pGhsKR19fQ4Ey
|
A 21 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
Choose one.
A) 12 B) 6 C) 88 D) 77 E) 14
|
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) + 1</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">21 / (7/5)</gadget>
<output>15</output>
<gadget id="calculator">21 - 15</gadget>
<output>6</output>
<result>B</result>
|
B
| 6 |
A 21 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
|
{
"A": "12",
"B": "6",
"C": "88",
"D": "77",
"E": "14"
}
|
subtract(21, divide(21, add(divide(2, 5), const_1)))
|
divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|
|
"1 : 2 / 5 = 5 : 2 2 / 7 * 21 = 6 answer : b"
|
physics
|
math_qa__IMxEkywVMPtoEz1d
|
A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.340. How much does C have? Choose the correct choice from the following answers.
A) 50 B) 40 C) 267 D) 29 E) 27
|
<gadget id="calculator">200 + 340</gadget>
<output>540</output>
<gadget id="calculator">540 - 500</gadget>
<output>40</output>
<result>B</result>
|
B
| 40 |
A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.340. How much does C have?
|
{
"A": "50",
"B": "40",
"C": "267",
"D": "29",
"E": "27"
}
|
subtract(add(200, 340), 500)
|
add(n1,n2)|subtract(#0,n0)|
|
"a + b + c = 500 a + c = 200 b + c = 340 - - - - - - - - - - - - - - a + b + 2 c = 540 a + b + c = 500 - - - - - - - - - - - - - - - - c = 40 answer : b"
|
general
|
math_qa__07p5c1M5UZE4MW6M
|
Light glows for every 15 seconds . How many times did it between 1:57:58 and 3:20:47 am
Choices.
A) 381 B) 332 C) 383 D) 334 E) 385
|
<gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 15</gadget>
<output>4_969/15 = around 331.266667</output>
<result>B</result>
|
B
| 332 |
Light glows for every 15 seconds . How many times did it between 1:57:58 and 3:20:47 am
|
{
"A": "381",
"B": "332",
"C": "383",
"D": "334",
"E": "385"
}
|
divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 15)
|
add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0)|
|
"the diff in sec between 1 : 57 : 58 and 3 : 20 : 47 is 4969 sec , 4969 / 13 = 331 . so total 332 times light ll glow answer : b"
|
physics
|
math_qa__SMuFR5fDzps37iSi
|
The average age of 29 students in a group is 15 years. when teacher's age is included to it, the average increases by one.What is the teacher's age in years? Pick one.
A) 31 B) 36 C) 29 D) 53 E) 57
|
<gadget id="calculator">29 + 1</gadget>
<output>30</output>
<result>C</result>
|
C
| 29 |
The average age of 29 students in a group is 15 years. when teacher's age is included to it, the average increases by one.What is the teacher's age in years?
|
{
"A": "31",
"B": "36",
"C": "29",
"D": "53",
"E": "57"
}
|
add(29, const_1)
|
add(n0,const_1)
|
age of the teacher = ( 29 * 16 - 29 * 15 ) = 29 years . answer : c
|
general
|
math_qa__LYpywJN3obAP5qaZ
|
Find the perimeter of a triangle with sides measuring 5 centimeters,20 centimeters and 30 centimeters.
Choose the correct choice from the following choices
A) 30 cm B) 40 cm C) 50 cm D) 55 cm E) 60 cm
|
<gadget id="calculator">5 + 20 + 30</gadget>
<output>55</output>
<result>D</result>
|
D
| 55 |
Find the perimeter of a triangle with sides measuring 5 centimeters,20 centimeters and 30 centimeters.
|
{
"A": "30 cm",
"B": "40 cm",
"C": "50 cm",
"D": "55 cm",
"E": "60 cm"
}
|
triangle_perimeter(5, 20, 30)
|
triangle_perimeter(n0,n1,n2)|
|
"perimeter of triangle = a + b + c perimeter = 5 cm + 20 cm + 30 cm = 55 cm answer : d ."
|
geometry
|
math_qa__3dKS9bKRvEOmOyvW
|
A and B invests Rs.6000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year? Choose the correct answer:
A) 32 : 99
B) 82 : 31
C) 24 : 45
D) 34 : 89
E) 35 : 21
|
<gadget id="calculator">6_000 * 4</gadget>
<output>24_000</output>
<gadget id="calculator">9_000 / 3</gadget>
<output>3_000</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">3_000 * 8</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 + 24_000</gadget>
<output>48_000</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">9_000 * 6</gadget>
<output>54_000</output>
<gadget id="calculator">9_000 - 3_000</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 6</gadget>
<output>36_000</output>
<gadget id="calculator">54_000 + 36_000</gadget>
<output>90_000</output>
<gadget id="calculator">48_000 / 90_000</gadget>
<output>8/15 = around 0.533333</output>
<result>C</result>
|
C
| 0.533333 |
A and B invests Rs.6000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
|
{
"A": "32 : 99",
"B": "82 : 31",
"C": "24 : 45",
"D": "34 : 89",
"E": "35 : 21"
}
|
divide(add(multiply(6000, 4), multiply(divide(9000, const_3), multiply(2, 4))), add(multiply(9000, multiply(2, const_3)), multiply(subtract(9000, divide(9000, const_3)), multiply(2, const_3))))
|
divide(n1,const_3)|multiply(n0,n2)|multiply(n3,n2)|multiply(n3,const_3)|multiply(#0,#2)|multiply(n1,#3)|subtract(n1,#0)|add(#1,#4)|multiply(#3,#6)|add(#5,#8)|divide(#7,#9)|
|
"a : b ( 6000 * 4 ) + ( 3000 * 8 ) : ( 9000 * 6 ) + ( 6000 * 6 ) 48000 : 90000 24 : 45 answer : c"
|
gain
|
math_qa__mUPkDKfBD8v0XvEv
|
What is the remainder when 8^1 + 8^2 + 8^3 +...+ 8^9 is divided by 8?
Choose the correct answer:
A) 4
B) 0
C) 2
D) 5
E) none of the above
|
<gadget id="calculator">8 ** 1</gadget>
<output>8</output>
<gadget id="calculator">8 - 8</gadget>
<output>0</output>
<gadget id="calculator">0 / 8</gadget>
<output>0</output>
<result>B</result>
|
B
| 0 |
What is the remainder when 8^1 + 8^2 + 8^3 +...+ 8^9 is divided by 8?
|
{
"A": "4",
"B": "0",
"C": "2",
"D": "5",
"E": "none of the above"
}
|
divide(subtract(power(8, 1), power(8, 1)), 8)
|
power(n0,n1)|power(n2,n1)|subtract(#0,#1)|divide(#2,n4)|
|
"notice that in the brackets we have the sum of 9 even multiples of 8 , which yields remainder of 0 upon division by 8 . answer : b"
|
general
|
math_qa__6jgwZkGcvnxyfg4Q
|
If [[x]] = x^2 + 2x + 4, what is the value of [[2]]? Choose the correct choice from the following.
A) 3
B) 9
C) 12
D) 19
E) 25
|
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<result>C</result>
|
C
| 12 |
If [[x]] = x^2 + 2x + 4, what is the value of [[2]]?
|
{
"A": "3",
"B": "9",
"C": "12",
"D": "19",
"E": "25"
}
|
add(add(power(2, 2), multiply(2, 2)), 4)
|
multiply(n0,n0)|power(n0,n0)|add(#0,#1)|add(n2,#2)
|
these functions questions might look intimidating , but they just test your knowledge about how well you can substitute values [ [ x ] ] = x ^ 2 + 2 x + 4 [ [ 2 ] ] = 2 ^ 2 + 2 * 2 + 4 = 12 . option c
|
general
|
math_qa__KcEFVpjN8aplq3L1
|
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 13 percent, what was the annual interest rate last year? Choose the correct answer.
A) 1 % B) 1.1 % C) 9.1 % D) 11.81 % E) 11.50 %
|
<gadget id="calculator">13 * 100</gadget>
<output>1_300</output>
<gadget id="calculator">13 + 100</gadget>
<output>113</output>
<gadget id="calculator">1_300 / 113</gadget>
<output>1_300/113 = around 11.504425</output>
<result>D</result>
|
D
| 11.81 |
The annual interest rate earned by an investment increased by 10 percent from last year to this year. If the annual interest rate earned by the investment this year was 13 percent, what was the annual interest rate last year?
|
{
"A": "1 %",
"B": "1.1 %",
"C": "9.1 %",
"D": "11.81 %",
"E": "11.50 %"
}
|
divide(multiply(13, const_100), add(13, const_100))
|
add(n1,const_100)|multiply(n1,const_100)|divide(#1,#0)
|
13 = 1.1 * x x = 11.81 % answer d )
|
gain
|
math_qa__dIntysVRBM0JUZU2
|
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.62000? Choose the correct choice from the following.
A) 81000 B) 78468.75 C) 81008 D) 81066 E) 81022
|
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 62_000</gadget>
<output>7_750</output>
<gadget id="calculator">62_000 + 7_750</gadget>
<output>69_750</output>
<gadget id="calculator">(1/8) * 69_750</gadget>
<output>34_875/4 = around 8_718.75</output>
<gadget id="calculator">69_750 + (34_875/4)</gadget>
<output>313_875/4 = around 78_468.75</output>
<result>B</result>
|
B
| 78,468.75 |
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.62000?
|
{
"A": "81000",
"B": "78468.75",
"C": "81008",
"D": "81066",
"E": "81022"
}
|
add(add(62000, multiply(divide(1, 8), 62000)), multiply(divide(1, 8), add(62000, multiply(divide(1, 8), 62000))))
|
divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3)|
|
"62000 * 9 / 8 * 9 / 8 = 78468.75 answer : b"
|
general
|
math_qa__M005pHrt1mH8gvd8
|
Tanks M and B are each in the shape of a right circular cylinder. The interior of tank M has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank M is what percent of the capacity of tank B?
Choose the correct choice from the following choices:
A) 75 %
B) 80 %
C) 100 %
D) 120 %
E) 125 %
|
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 10</gadget>
<output>160</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 8</gadget>
<output>200</output>
<gadget id="calculator">160 / 200</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>B</result>
|
B
| 80 |
Tanks M and B are each in the shape of a right circular cylinder. The interior of tank M has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank M is what percent of the capacity of tank B?
|
{
"A": "75 %",
"B": "80 %",
"C": "100 %",
"D": "120 %",
"E": "125 %"
}
|
multiply(divide(multiply(multiply(divide(8, const_2), divide(8, const_2)), 10), multiply(multiply(divide(10, const_2), divide(10, const_2)), 8)), const_100)
|
divide(n1,const_2)|divide(n0,const_2)|multiply(#0,#0)|multiply(#1,#1)|multiply(n0,#2)|multiply(n1,#3)|divide(#4,#5)|multiply(#6,const_100)
|
b . for m , r = 8 / 2 pi . its capacity = ( 4 pi ) ^ 2 * 10 = 160 pi for b , r = 10 / pi . its capacity = ( 5 pi ) ^ 2 * 8 = 200 pi m / b = 160 pi / 200 pi = 0.8
|
physics
|
math_qa__RwgxeofR8xsS5QZo
|
In a class, 20% of the students were absent for an exam. 30% failed by 20 marks and 10% just passed. Find the average score of the class if the remaining students scored an average of 65 marks and the cut off for passing the exam is 40. Choose the correct choice from the following answers
A) 36 B) 302 C) 272 D) 292 E) 271
|
<gadget id="calculator">30 * 20</gadget>
<output>600</output>
<gadget id="calculator">10 * 40</gadget>
<output>400</output>
<gadget id="calculator">600 + 400</gadget>
<output>1_000</output>
<gadget id="calculator">65 * 40</gadget>
<output>2_600</output>
<gadget id="calculator">1_000 + 2_600</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 100</gadget>
<output>36</output>
<result>A</result>
|
A
| 36 |
In a class, 20% of the students were absent for an exam. 30% failed by 20 marks and 10% just passed. Find the average score of the class if the remaining students scored an average of 65 marks and the cut off for passing the exam is 40.
|
{
"A": "36",
"B": "302",
"C": "272",
"D": "292",
"E": "271"
}
|
divide(add(add(multiply(30, 20), multiply(10, 40)), multiply(65, 40)), const_100)
|
multiply(n0,n1)|multiply(n3,n5)|multiply(n4,n5)|add(#0,#1)|add(#3,#2)|divide(#4,const_100)
|
explanation : let total students be 100 . hence , marks of 20 students is 0 as they were absent . 30 students scored 20 marks ( as they failed by 20 marks ) 10 students scored 40 marks ( just passed ) 40 students scored 65 marks ( average of 65 ) therefore , average score of the class is : ( 0 + 600 + 400 + 2600 ) / 100 = 3600 / 100 = 36 answer : a
|
general
|
math_qa__98N7WpIyVhojViZQ
|
A library has an average of 510 visitors on sundays and 240 on other days . The avearge number of visitors per day in a month of 30 days beginning with a sunday is?
Options.
A) 150
B) 225
C) 285
D) 315
E) 374
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 510</gadget>
<output>2_550</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 240</gadget>
<output>6_000</output>
<gadget id="calculator">2_550 + 6_000</gadget>
<output>8_550</output>
<gadget id="calculator">8_550 / 30</gadget>
<output>285</output>
<result>C</result>
|
C
| 285 |
A library has an average of 510 visitors on sundays and 240 on other days . The avearge number of visitors per day in a month of 30 days beginning with a sunday is?
|
{
"A": "150",
"B": "225",
"C": "285",
"D": "315",
"E": "374"
}
|
divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 510), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 240)), 30)
|
add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)|
|
"since the month begin with sunday , so there will be five sundays in the month required average = ( 510 * 5 + 240 * 25 ) / 30 = 8550 / 30 = 285 answer is c"
|
general
|
math_qa__QzETv4FDoVBFosTW
|
The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 40 kg. What is the weight of the new person?
Choices
A) 75 B) 65 C) 85 D) 95 E) 60
|
<gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 40</gadget>
<output>60</output>
<result>E</result>
|
E
| 60 |
The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 40 kg. What is the weight of the new person?
|
{
"A": "75",
"B": "65",
"C": "85",
"D": "95",
"E": "60"
}
|
add(multiply(8, 2.5), 40)
|
multiply(n0,n1)|add(n2,#0)|
|
"total increase in weight = 8 × 2.5 = 20 if x is the weight of the new person , total increase in weight = x − 40 = > 20 = x - 40 = > x = 20 + 40 = 60 answer is e ."
|
general
|
math_qa__nDpzFcy9mqd5Yv3B
|
How long does a train 110 m long traveling at 72 kmph takes to cross a bridge of 170 m in length? Choose the correct choice from the following answers.
A) 16.5
B) 16.0
C) 16.4
D) 14
E) 16.1
|
<gadget id="calculator">110 + 170</gadget>
<output>280</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">280 / 20</gadget>
<output>14</output>
<result>D</result>
|
D
| 14 |
How long does a train 110 m long traveling at 72 kmph takes to cross a bridge of 170 m in length?
|
{
"A": "16.5",
"B": "16.0",
"C": "16.4",
"D": "14",
"E": "16.1"
}
|
divide(add(110, 170), multiply(72, const_0_2778))
|
add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)|
|
"d = 110 + 170 = 280 m s = 72 * 5 / 18 = 20 t = 280 * 1 / 20 = 14 sec answer : d"
|
physics
|
math_qa__Mn7T5ZcsBNTtu9hj
|
Find large number from below question The difference of two numbers is 250. On dividing the larger number by the smaller, we get 5 as quotient and the 14 as remainder Choose the correct choice from the following options.
A) 120 B) 135 C) 140 D) 309 E) 369
|
<gadget id="calculator">250 - 14</gadget>
<output>236</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">236 / 4</gadget>
<output>59</output>
<gadget id="calculator">59 * 5</gadget>
<output>295</output>
<result>D</result>
|
D
| 309 |
Find large number from below question The difference of two numbers is 250. On dividing the larger number by the smaller, we get 5 as quotient and the 14 as remainder
|
{
"A": "120",
"B": "135",
"C": "140",
"D": "309",
"E": "369"
}
|
multiply(divide(subtract(250, 14), subtract(5, const_1)), 5)
|
subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)|
|
"let the smaller number be x . then larger number = ( x + 250 ) . x + 250 = 5 x + 14 4 x = 236 x = 59 large number = 59 + 250 = 309 d"
|
general
|
math_qa__u498fxHdWoXqm1GS
|
an amount of rs . 1000 is to be distributed amongst p , q , r and s such that “ p ” gets twice as that of “ q ” and “ s ” gets 4 times as that of “ r ” . if “ q ” and “ r ” are to receive equal amount , what is the difference between the amounts received by s and p ? Choose the correct option: A) 2378 B) 2697 C) 250 D) 5000 E) 6971
|
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">1_000 / 8</gadget>
<output>125</output>
<gadget id="calculator">4 * 125</gadget>
<output>500</output>
<gadget id="calculator">2 * 125</gadget>
<output>250</output>
<gadget id="calculator">500 - 250</gadget>
<output>250</output>
<result>C</result>
|
C
| 250 |
an amount of rs . 1000 is to be distributed amongst p , q , r and s such that “ p ” gets twice as that of “ q ” and “ s ” gets 4 times as that of “ r ” . if “ q ” and “ r ” are to receive equal amount , what is the difference between the amounts received by s and p ?
|
{
"A": "2378",
"B": "2697",
"C": "250",
"D": "5000",
"E": "6971"
}
|
subtract(multiply(4, divide(1000, add(add(add(const_2, const_1), const_1), const_4))), multiply(const_2, divide(1000, add(add(add(const_2, const_1), const_1), const_4))))
|
add(const_1,const_2)|add(#0,const_1)|add(#1,const_4)|divide(n0,#2)|multiply(n1,#3)|multiply(#3,const_2)|subtract(#4,#5)
|
explanation : we have , p = 2 q & s = 4 r further q = r & p + q + r + s = 1,000 thus we get , 2 q + q + q + 4 q = 1,000 8 q = 1,000 or q = rs . 125 thus , r = rs . 125 , p = 250 & s = rs . 500 hence , the required difference = ( s – p ) = ( 500 – 250 ) = rs . 250 answer : c
|
general
|
math_qa__7rIrlo2ckg9g4vxy
|
Ajay can walk 6km in 1 hour. In how many hours he can walk 45km? Select the correct option.
A) 5 hrs
B) 10 hrs
C) 7.5 hrs
D) 20 hrs
E) 30 hrs
|
<gadget id="calculator">45 / 6</gadget>
<output>15/2 = around 7.5</output>
<result>C</result>
|
C
| 7.5 |
Ajay can walk 6km in 1 hour. In how many hours he can walk 45km?
|
{
"A": "5 hrs",
"B": "10 hrs",
"C": "7.5 hrs",
"D": "20 hrs",
"E": "30 hrs"
}
|
divide(45, 6)
|
divide(n2,n0)|
|
"1 hour he walk 6 km he walk 45 km in = 45 / 6 * 1 = 7.5 hours answer is c"
|
physics
|
math_qa__orj0UMGmiXe9f56Y
|
A man sells a car to his friend at 13% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was : Choose the correct choice from the following answers
A) rs . 21724.14 B) rs . 31724.14 C) rs . 51724.14 D) rs . 61724.14 E) none of these
|
<gadget id="calculator">54_000 * 100</gadget>
<output>5_400_000</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">5_400_000 / 120</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 * 100</gadget>
<output>4_500_000</output>
<gadget id="calculator">100 - 13</gadget>
<output>87</output>
<gadget id="calculator">4_500_000 / 87</gadget>
<output>1_500_000/29 = around 51_724.137931</output>
<result>C</result>
|
C
| 51,724.14 |
A man sells a car to his friend at 13% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was :
|
{
"A": "rs . 21724.14",
"B": "rs . 31724.14",
"C": "rs . 51724.14",
"D": "rs . 61724.14",
"E": "none of these"
}
|
divide(multiply(divide(multiply(54000, const_100), add(const_100, 20)), const_100), subtract(const_100, 13))
|
add(n2,const_100)|multiply(n1,const_100)|subtract(const_100,n0)|divide(#1,#0)|multiply(#3,const_100)|divide(#4,#2)|
|
"explanation : s . p = rs . 54,000 . gain earned = 20 % c . p = rs . [ 100 / 120 ã — 54000 ] = rs . 45000 this is the price the first person sold to the second at at loss of 13 % . now s . p = rs . 45000 and loss = 13 % c . p . rs . [ 100 / 87 ã — 45000 ] = rs . 51724.14 . correct option : c"
|
gain
|
math_qa__ZqNkMBEOomIY8ROs
|
n 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B the present age of B is Choose the correct choice from the following answers: A) 22 B) 897 C) 268 D) 20 E) 48
|
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 9</gadget>
<output>39</output>
<gadget id="calculator">9 + 39</gadget>
<output>48</output>
<result>E</result>
|
E
| 48 |
n 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B the present age of B is
|
{
"A": "22",
"B": "897",
"C": "268",
"D": "20",
"E": "48"
}
|
add(9, add(add(multiply(const_2, 10), 10), 9))
|
multiply(n0,const_2)|add(n0,#0)|add(n2,#1)|add(n2,#2)
|
a + 10 = 2 ( b - 10 ) . . . . . . . . ( 1 ) a = b + 9 . . . . . . . . . ( 2 ) from equations . 1 & 2 we get b = 39 a will be 39 + 9 = 48 years old . answer : e
|
general
|
math_qa__NHae1RN7Xqr1Dqbb
|
Rs. 700 is divided among A, B, C so that A receives half as much as B and B half as much as C. Then C's share is Select.
A) rs 429 B) rs 412 C) rs 400 D) rs 129 E) rs 122
|
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">(4/7) * 700</gadget>
<output>400</output>
<result>C</result>
|
C
| 400 |
Rs. 700 is divided among A, B, C so that A receives half as much as B and B half as much as C. Then C's share is
|
{
"A": "rs 429",
"B": "rs 412",
"C": "rs 400",
"D": "rs 129",
"E": "rs 122"
}
|
multiply(divide(const_4, add(const_4, add(const_1, const_2))), 700)
|
add(const_1,const_2)|add(#0,const_4)|divide(const_4,#1)|multiply(n0,#2)|
|
"let c = x . then b = x / 2 and a = x / 4 a : b : c = 1 : 2 : 4 . c ' s share rs . [ ( 4 / 7 ) * 700 ) = 400 answer : c"
|
general
|
math_qa__aScJ1nkGTlZbY1LW
|
If the height of a cone is increased by 130% then its volume is increased by? Options:
A) 100 B) 777 C) 998 D) 729 E) 130
|
<gadget id="calculator">130 * 1</gadget>
<output>130</output>
<result>E</result>
|
E
| 130 |
If the height of a cone is increased by 130% then its volume is increased by?
|
{
"A": "100",
"B": "777",
"C": "998",
"D": "729",
"E": "130"
}
|
rectangle_area(130, const_1)
|
rectangle_area(n0,const_1)|
|
"100 % answer : e"
|
geometry
|
math_qa__nac8Ty2LO2z3SKVS
|
A number exceeds by 15 from its 3/8 part. Then the number is? Choose the most appropriate option:
A) 32 B) 24 C) 39 D) 40 E) 45
|
<gadget id="calculator">15 * 8</gadget>
<output>120</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<result>B</result>
|
B
| 24 |
A number exceeds by 15 from its 3/8 part. Then the number is?
|
{
"A": "32",
"B": "24",
"C": "39",
"D": "40",
"E": "45"
}
|
divide(multiply(15, 8), subtract(8, 3))
|
multiply(n0,n2)|subtract(n2,n1)|divide(#0,#1)
|
x – 3 / 8 x = 15 x = 24 answer : b
|
general
|
math_qa__SSYYFbeUHjp6kHKm
|
Yearly subscription to professional magazines cost a company $940.00. To Make a 20% cut in the magazine budget, how much less must be spent? Pick one
A) 654 B) 752 C) 656 D) 657 E) 658
|
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 940</gadget>
<output>752</output>
<result>B</result>
|
B
| 752 |
Yearly subscription to professional magazines cost a company $940.00. To Make a 20% cut in the magazine budget, how much less must be spent?
|
{
"A": "654",
"B": "752",
"C": "656",
"D": "657",
"E": "658"
}
|
multiply(divide(subtract(const_100, 20), const_100), 940.00)
|
subtract(const_100,n1)|divide(#0,const_100)|multiply(n0,#1)|
|
"total cost 940 940 * 20 / 100 = 188 so the cut in amount is 188 the less amount to be spend is 940 - 188 = 752 answer : b"
|
general
|
math_qa__hPp4mnZmyFhSTxs3
|
A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are Choose the correct answer.
A) 600
B) 500
C) 400
D) 300
E) none of these
|
<gadget id="calculator">125 + 40</gadget>
<output>165</output>
<gadget id="calculator">33 / 100</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">165 / (33/100)</gadget>
<output>500</output>
<result>B</result>
|
B
| 500 |
A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are
|
{
"A": "600",
"B": "500",
"C": "400",
"D": "300",
"E": "none of these"
}
|
divide(add(125, 40), divide(33, const_100))
|
add(n1,n2)|divide(n0,const_100)|divide(#0,#1)
|
explanation : given that the student got 125 marks and still he failed by 40 marks = > the minimum pass mark = 125 + 40 = 165 given that minimum pass mark = 33 % of the total mark = > total mark × ( 33 / 100 ) = 165 = > total mark = 16500 / 33 = 500 answer : option b
|
general
|
math_qa__74R0vWAiaDfzmt8z
|
Find the number of shares that can be bought for Rs.8800 if the market value is Rs.20 each with brokerage being 2.5%. Choose the correct choice from the following
A) 429.3 B) 270 C) 177 D) 166 E) 111
|
<gadget id="calculator">2.5 / 100</gadget>
<output>0.025</output>
<gadget id="calculator">20 + 0.025</gadget>
<output>20.025</output>
<gadget id="calculator">8_800 / 20.025</gadget>
<output>439.450687</output>
<gadget id="calculator">floor(439.450687)</gadget>
<output>439</output>
<result>A</result>
|
A
| 429.3 |
Find the number of shares that can be bought for Rs.8800 if the market value is Rs.20 each with brokerage being 2.5%.
|
{
"A": "429.3",
"B": "270",
"C": "177",
"D": "166",
"E": "111"
}
|
floor(divide(8800, add(20, divide(2.5, const_100))))
|
divide(n2,const_100)|add(n1,#0)|divide(n0,#1)|floor(#2)
|
explanation : cost of each share = ( 20 + 2.5 % of 20 ) = rs . 20.5 therefore , number of shares = 8800 / 20.5 = 429.3 answer : a
|
gain
|
math_qa__tYbXL86LH1s12i5P
|
1/0.08 is equal to
Answers.
A) 25.5
B) 2.5
C) 12.5
D) . 25
E) none of these
|
<gadget id="calculator">1 / 0.08</gadget>
<output>12.5</output>
<result>C</result>
|
C
| 12.5 |
1/0.08 is equal to
|
{
"A": "25.5",
"B": "2.5",
"C": "12.5",
"D": ". 25",
"E": "none of these"
}
|
divide(1, 0.08)
|
divide(n0,n1)|
|
"explanation : 1 / 0.08 = ( 1 * 100 ) / 8 = 100 / 8 = 12.5 option c"
|
general
|
math_qa__DeGrK631RpintQJy
|
When a certain number X is divided by 52, the remainder is 19. What is the remainder when X is divided by 7? Choose one.
A) 2
B) 3
C) 4
D) 5
E) 6
|
<gadget id="calculator">19 % 7</gadget>
<output>5</output>
<result>D</result>
|
D
| 5 |
When a certain number X is divided by 52, the remainder is 19. What is the remainder when X is divided by 7?
|
{
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
}
|
reminder(19, 7)
|
reminder(n1,n2)
|
when a certain number x is divided by 52 , the remainder is 19 . what is the remainder when x is divided by 7 ? putting a value say x = 19 we get remainder as 19 when divided by 52 . when 19 divided by 7 we get 5 as remainder . d is the answer .
|
general
|
math_qa__vAxtJ2FOs2MPtuxo
|
A reduction of 40% in the price of bananas would enable a man to obtain 50 more for Rs.40, what is reduced price per dozen? Pick:
A) 1.34 B) 2.84 C) 3.84 D) 4.34 E) 5
|
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">40 * (2/5)</gadget>
<output>16</output>
<gadget id="calculator">16 / 50</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">12 * (8/25)</gadget>
<output>96/25 = around 3.84</output>
<result>C</result>
|
C
| 3.84 |
A reduction of 40% in the price of bananas would enable a man to obtain 50 more for Rs.40, what is reduced price per dozen?
|
{
"A": "1.34",
"B": "2.84",
"C": "3.84",
"D": "4.34",
"E": "5"
}
|
multiply(const_12, divide(multiply(40, divide(40, const_100)), 50))
|
divide(n0,const_100)|multiply(n0,#0)|divide(#1,n1)|multiply(#2,const_12)|
|
"40 * ( 40 / 100 ) = 16 - - - 50 ? - - - 12 = > rs . 3.84 answer : c"
|
gain
|
math_qa__YUColGTltVjtgXLL
|
The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 10%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? Choose the correct answer.
A) 32.5
B) 35
C) 48
D) 65
E) 67.5
|
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">75 * (1/10)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">75 - (15/2)</gadget>
<output>135/2 = around 67.5</output>
<gadget id="calculator">100 - (135/2)</gadget>
<output>65/2 = around 32.5</output>
<gadget id="calculator">(65/2) / (135/2)</gadget>
<output>13/27 = around 0.481481</output>
<gadget id="calculator">100 * (13/27)</gadget>
<output>1_300/27 = around 48.148148</output>
<result>C</result>
|
C
| 48 |
The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 10%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount?
|
{
"A": "32.5",
"B": "35",
"C": "48",
"D": "65",
"E": "67.5"
}
|
multiply(const_100, divide(subtract(const_100, subtract(subtract(const_100, 25), multiply(subtract(const_100, 25), divide(10, const_100)))), subtract(subtract(const_100, 25), multiply(subtract(const_100, 25), divide(10, const_100)))))
|
divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|subtract(#1,#2)|subtract(const_100,#3)|divide(#4,#3)|multiply(#5,const_100)|
|
"1 ) let the price of jacket initially be $ 100 . 2 ) then it is decreased by 25 % , therefore bringing down the price to $ 75 . 3 ) again it is further discounted by 10 % , therefore bringing down the price to $ 67.5 . 4 ) now 67.5 has to be added by x % in order to equal the original price . 67.5 + ( x % ) 67.5 = 100 . solving this eq for x , we get x = 48.1 answer is c ."
|
gain
|
math_qa__DPSIrUfMojltq0gH
|
If a, b, c, and d are integers; w, x, y, and z are prime numbers; w < x < y < z; and (wa)(xb)(yc)(zd)=660(wa)(xb)(yc)(zd)=660, what is the value of (a + b) – (c + d)? Choices
A) – 1 B) 0 C) 1 D) 2 E) 3
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">660 / 11</gadget>
<output>60</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<result>C</result>
|
C
| 1 |
If a, b, c, and d are integers; w, x, y, and z are prime numbers; w < x < y < z; and (wa)(xb)(yc)(zd)=660(wa)(xb)(yc)(zd)=660, what is the value of (a + b) – (c + d)?
|
{
"A": "– 1",
"B": "0",
"C": "1",
"D": "2",
"E": "3"
}
|
subtract(divide(divide(divide(660, add(add(const_3, const_4), const_4)), const_10), const_2), const_2)
|
add(const_3,const_4)|add(#0,const_4)|divide(n0,#1)|divide(#2,const_10)|divide(#3,const_2)|subtract(#4,const_2)
|
660660 = 2 ^ 2 x 3 ^ 1 x 5 ^ 1 x 11 ^ 1 w < x < y < z = 2 < 3 < 5 < 11 so , can can say - w = 2 x = 3 y = 5 z = 11 hence a = 2 , b = c = d = 1 ( a + b ) – ( c + d ) will be ( 2 + 1 ) – ( 1 + 1 ) = 1 answer will be ( c )
|
general
|
math_qa__IKBkZ6TB70VuHejI
|
A man gains 50% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be.
Choose the correct answer: A) 130 % B) 300 % C) 150 % D) 160 % E) 170 %
|
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 + 100</gadget>
<output>300</output>
<result>B</result>
|
B
| 300 |
A man gains 50% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be.
|
{
"A": "130 %",
"B": "300 %",
"C": "150 %",
"D": "160 %",
"E": "170 %"
}
|
add(multiply(subtract(multiply(add(const_1, divide(50, const_100)), const_2), const_1), const_100), const_100)
|
divide(n0,const_100)|add(#0,const_1)|multiply(#1,const_2)|subtract(#2,const_1)|multiply(#3,const_100)|add(#4,const_100)
|
explanation : let the c . p . = x , then s . p . = ( 150 / 100 ) x = 3 x / 2 new s . p . = 2 ( 3 x / 2 ) = 3 x / 1 profit = 3 x / 1 - x = 3 x / 1 profit % = ( profit / c . p . ) * 100 = > ( 3 x / 1 ) * ( 1 / x ) * 100 = 300 % option b
|
gain
|
math_qa__t0Zs7DL6HzZvDfB3
|
|14 - 5| - |8 - 12| = ? Pick one.
A) 3 B) 2 C) 1 D) 5 E) 4
|
<gadget id="calculator">14 - 5</gadget>
<output>9</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<result>D</result>
|
D
| 5 |
|14 - 5| - |8 - 12| = ?
|
{
"A": "3",
"B": "2",
"C": "1",
"D": "5",
"E": "4"
}
|
subtract(subtract(14, 5), subtract(12, 8))
|
subtract(n0,n1)|subtract(n3,n2)|subtract(#0,#1)
|
| 14 - 5 | - | 8 - 12 | = | 9 | - | - 4 | = 9 - 4 = 5 correct answer d
|
general
|
math_qa__4gBWIVfmkMWyNGSg
|
In Kaya's teacher's desk there are 3 pink highlighters, 7 yellow highlighters, and 5 blue highlighters. How many highlighters are there in all? Choose the correct answer:
A) 11 B) 15 C) 77 D) 33 E) 88
|
<gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<result>B</result>
|
B
| 15 |
In Kaya's teacher's desk there are 3 pink highlighters, 7 yellow highlighters, and 5 blue highlighters. How many highlighters are there in all?
|
{
"A": "11",
"B": "15",
"C": "77",
"D": "33",
"E": "88"
}
|
add(add(3, 7), 5)
|
add(n0,n1)|add(n2,#0)|
|
"add the numbers of highlighters . 3 + 7 + 5 = 15 . answer is b ."
|
general
|
math_qa__9udPJIQcLZH5kMGa
|
The sum of all the digits of the integers from 18 to 21 inclusive is 24 (1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 = 24). What is the sum W of all the digits of the integers from 0 to 99 inclusive? Choose the correct choice from the following answers:
A) 450
B) 810
C) 900
D) 1000
E) 1100
|
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">45 * 20</gadget>
<output>900</output>
<result>C</result>
|
C
| 900 |
The sum of all the digits of the integers from 18 to 21 inclusive is 24 (1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 = 24). What is the sum W of all the digits of the integers from 0 to 99 inclusive?
|
{
"A": "450",
"B": "810",
"C": "900",
"D": "1000",
"E": "1100"
}
|
multiply(divide(multiply(9, add(9, 1)), 2), multiply(2, const_10))
|
add(n6,n3)|multiply(const_10,n7)|multiply(n6,#0)|divide(#2,n7)|multiply(#3,#1)|
|
"we want the sum of the digits from 0 to 99 , so i approximated : 0 - 9 - > 45 - > ( 9 + 0 ) * 10 / 2 40 - 49 - > 85 ( 13 + 4 ) * 10 / 2 90 - 99 - > 135 ( 18 + 9 ) * 10 / 2 we can see at a glance that theweightgoes up as the numbers go up ( meaning the difference between 85 and 45 is 40 , while 135 - 85 is 50 , this means that the second part of this sequence carries more weight for our result ) , so we know that the final answer has to be more than 850 ( 85 * 10 ) but close to it , and that ' s just w = 900 : the answer is c ."
|
general
|
math_qa__o1tSwkexl67r0VHe
|
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. Find the sum Select the correct option:
A) rs 600
B) rs 625
C) rs 650
D) rs 675
E) none of these
|
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) ** 2</gadget>
<output>1/625 = around 0.0016</output>
<gadget id="calculator">(1/625) * 1</gadget>
<output>1/625 = around 0.0016</output>
<gadget id="calculator">1 / (1/625)</gadget>
<output>625</output>
<result>B</result>
|
B
| 625 |
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. Find the sum
|
{
"A": "rs 600",
"B": "rs 625",
"C": "rs 650",
"D": "rs 675",
"E": "none of these"
}
|
inverse(multiply(power(divide(4, const_100), const_2), 1))
|
divide(n1,const_100)|power(#0,const_2)|multiply(n2,#1)|inverse(#2)
|
explanation : let the sum be p s . i . = p ∗ 4 ∗ 2 / 100 = 2 p / 25 c . i . = p ( 1 + 4 / 100 ) 2 − p = 676 p / 625 − p = 51 p / 625 as , c . i . - s . i = 1 = > 51 p / 625 − 2 p / 25 = 1 = > 51 p − 50 p / 625 = 1 p = 625 option b
|
gain
|
math_qa__1aymT2ENDxQ9QDeQ
|
The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.8.4. The true discount is Choose the correct choice from the following choices:
A) rs . 70 B) rs . 36 C) rs . 54 D) rs . 50 E) none
|
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">8.4 / (3/25)</gadget>
<output>70</output>
<result>A</result>
|
A
| 70 |
The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.8.4. The true discount is
|
{
"A": "rs . 70",
"B": "rs . 36",
"C": "rs . 54",
"D": "rs . 50",
"E": "none"
}
|
divide(8.4, divide(12, const_100))
|
divide(n1,const_100)|divide(n2,#0)|
|
"solution t . d = [ b . g x 100 / r x t ] = rs . ( 8.4 x 100 / 12 x 1 ) = rs . 70 . answer a"
|
gain
|
math_qa__5FGuKHWQsWqCMCtC
|
in a basketball game , tim scored 20 points more than joe , but only half as many points as ken . if the 3 players scored a combined total of 100 points , how many points did tim score ? Pick:
A) 15 B) 20 C) 25 D) 30 E) 45
|
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>D</result>
|
D
| 30 |
in a basketball game , tim scored 20 points more than joe , but only half as many points as ken . if the 3 players scored a combined total of 100 points , how many points did tim score ?
|
{
"A": "15",
"B": "20",
"C": "25",
"D": "30",
"E": "45"
}
|
divide(multiply(20, 3), const_2)
|
multiply(n0,n1)|divide(#0,const_2)
|
let joe scored point = x then tim scored = x + 20 ken scored = 2 * ( x + 20 ) = 2 x + 40 as given , x + x + 20 + 2 x + 40 = 100 points 4 x + 60 = 100 x = 100 - 60 / 4 = 10 so tim scored = x + 20 i . e ) 10 + 20 = 30 answer : d
|
general
|
math_qa__ktO65y76ET7hl78T
|
Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 670 then loss of Pyarelal?
Choices: A) 603 B) 703 C) 800 D) 903 E) 1000
|
<gadget id="calculator">9 * 670</gadget>
<output>6_030</output>
<gadget id="calculator">1 + 9</gadget>
<output>10</output>
<gadget id="calculator">6_030 / 10</gadget>
<output>603</output>
<result>A</result>
|
A
| 603 |
Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 670 then loss of Pyarelal?
|
{
"A": "603",
"B": "703",
"C": "800",
"D": "903",
"E": "1000"
}
|
divide(multiply(9, 670), add(1, 9))
|
add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|
|
"let the capital of pyarelal be x , then capital of ashok = x / 9 so ratio of investment of pyarelal and ashok = x : x / 9 = 9 x : x hence out of the total loss of 670 , loss of pyarelal = 670 * 9 x / 10 x = 603 answer : a"
|
gain
|
math_qa__DbzTLfWu5LiWkWnI
|
40% of the population of a village is 23040. The total population of the village is ? Answers: A) 57600 B) 44000 C) 34936 D) 25640 E) none
|
<gadget id="calculator">100 / 40</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 23_040</gadget>
<output>57_600</output>
<result>A</result>
|
A
| 57,600 |
40% of the population of a village is 23040. The total population of the village is ?
|
{
"A": "57600",
"B": "44000",
"C": "34936",
"D": "25640",
"E": "none"
}
|
multiply(divide(const_100, 40), 23040)
|
divide(const_100,n0)|multiply(n1,#0)|
|
"answer ∵ 40 % of p = 23040 ∴ p = ( 23040 x 100 ) / 40 = 57600 correct option : a"
|
general
|
math_qa__GOuPvoD4ohkB7y51
|
If (1/2)^22 (1/81)^k = 1/18^22, then k =
Choose the correct choice from the following: A) 8 B) 12 C) 16 D) 24 E) 11
|
<gadget id="calculator">22 * 2</gadget>
<output>44</output>
<gadget id="calculator">44 / 4</gadget>
<output>11</output>
<result>E</result>
|
E
| 11 |
If (1/2)^22 (1/81)^k = 1/18^22, then k =
|
{
"A": "8",
"B": "12",
"C": "16",
"D": "24",
"E": "11"
}
|
divide(multiply(22, 2), const_4)
|
multiply(n1,n2)|divide(#0,const_4)
|
i ' m going to focus on denominator only . . ( 2 ^ 22 ) . ( ( 3 ^ 4 ) ^ k = 18 ^ 22 ( 2 ^ 22 ) . ( ( 3 ^ 4 k ) = ( 2 . 3 ^ 2 ) ^ 22 ( 2 ^ 22 ) . ( ( 3 ^ 4 k ) = ( 2 ^ 24 ) . ( 3 ^ 2 ) ^ 22 hence 4 k = 44 k = 11 answer e i hope it ' s quite clear
|
general
|
math_qa__wjPKFRcU1j6j91x1
|
A cube of edge 17cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level?
Choose the correct choice from the following
A) 6 cm B) 8.25 cm C) 11.25 cm D) 16.37 cm E) 20.62 cm
|
<gadget id="calculator">17 ** 3</gadget>
<output>4_913</output>
<gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">4_913 / 300</gadget>
<output>4_913/300 = around 16.376667</output>
<result>D</result>
|
D
| 16.37 |
A cube of edge 17cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level?
|
{
"A": "6 cm",
"B": "8.25 cm",
"C": "11.25 cm",
"D": "16.37 cm",
"E": "20.62 cm"
}
|
divide(volume_cube(17), multiply(20, 15))
|
multiply(n1,n2)|volume_cube(n0)|divide(#1,#0)|
|
"increase in volume = volume of the cube = 17 * 17 * 17 cm ^ 3 rise in water level = volume / area = 17 * 17 * 17 / 20 * 15 = 16.37 cm answer is d"
|
geometry
|
math_qa__V0ahqBQ6jg7Blv8P
|
Product of two natural numbers is 11. Then, the sum of reciprocals of their squares is Choose the correct choice
A) 290 / 289 B) 122 / 121 C) 290 / 90 D) 290 / 19 E) none of these
|
<gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) ** 2</gadget>
<output>1/121 = around 0.008264</output>
<gadget id="calculator">1 + (1/121)</gadget>
<output>122/121 = around 1.008264</output>
<result>B</result>
|
B
| 1.008264 |
Product of two natural numbers is 11. Then, the sum of reciprocals of their squares is
|
{
"A": "290 / 289",
"B": "122 / 121",
"C": "290 / 90",
"D": "290 / 19",
"E": "none of these"
}
|
add(power(divide(const_1, const_1), const_2), power(divide(const_1, 11), const_2))
|
divide(const_1,const_1)|divide(const_1,n0)|power(#0,const_2)|power(#1,const_2)|add(#2,#3)|
|
"explanation : if the numbers are a , b , then ab = 17 , as 17 is a prime number , so a = 1 , b = 17 . 1 / a 2 + 1 / b 2 = 1 / 1 ( 2 ) + 1 / 11 ( 2 ) = 122 / 121 option b"
|
general
|
math_qa__uc7wmTjBnainPjya
|
A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 4.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ?
Choose the correct choice from the following choices:
A) 16.5 % B) 20 % C) 33 % D) 55 % E) 65 %
|
<gadget id="calculator">3.5 - 3</gadget>
<output>0.5</output>
<gadget id="calculator">4.5 - 3</gadget>
<output>1.5</output>
<gadget id="calculator">0.5 / 1.5</gadget>
<output>0.333333</output>
<gadget id="calculator">0.333333 * 100</gadget>
<output>33.3333</output>
<result>C</result>
|
C
| 33 |
A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 4.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ?
|
{
"A": "16.5 %",
"B": "20 %",
"C": "33 %",
"D": "55 %",
"E": "65 %"
}
|
multiply(divide(subtract(3.5, 3), subtract(4.5, 3)), const_100)
|
subtract(n1,n2)|subtract(n3,n2)|divide(#0,#1)|multiply(#2,const_100)|
|
"the amount by which employment costs rose is equal to 0.035 ( salary costs + fringe benefit costs ) ; on the other hand the amount by which employment costs rose is equal to 0.03 * salary costs + 0.045 * fringe benefit costs ; so , 35 ( s + f ) = 30 s + 45 f - - > s = 2 f - - > f / s = 1 / 2 - - > f / ( s + f ) = 1 / ( 1 + 2 ) = 1 / 3 = 0.33 . answer : c ."
|
gain
|
math_qa__C7MuZTqnz6FpRvfI
|
Sandy gets 3 marks for each correct sum and loses 2 marks for each incorrect sum. Sandy attempts 30 sums and obtains 45 marks. How many sums did Sandy get correct? Choose the correct choice from the following:
A) 18
B) 21
C) 24
D) 27
E) 28
|
<gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">60 + 45</gadget>
<output>105</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">105 / 5</gadget>
<output>21</output>
<result>B</result>
|
B
| 21 |
Sandy gets 3 marks for each correct sum and loses 2 marks for each incorrect sum. Sandy attempts 30 sums and obtains 45 marks. How many sums did Sandy get correct?
|
{
"A": "18",
"B": "21",
"C": "24",
"D": "27",
"E": "28"
}
|
divide(add(multiply(2, 30), 45), add(2, 3))
|
add(n0,n1)|multiply(n1,n2)|add(n3,#1)|divide(#2,#0)
|
let x be the correct sums and ( 30 - x ) be the incorrect sums . 3 x - 2 ( 30 - x ) = 45 5 x = 105 x = 21 the answer is b .
|
general
|
math_qa__JfXCo98IicxTFAzq
|
Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many Q hours does it currently take Anne to clean the house on her own?
Choices
A) 6 B) 7 C) 8 D) 12 E) 14
|
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) - (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>D</result>
|
D
| 12 |
Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many Q hours does it currently take Anne to clean the house on her own?
|
{
"A": "6",
"B": "7",
"C": "8",
"D": "12",
"E": "14"
}
|
inverse(subtract(divide(const_1, 3), divide(const_1, 4)))
|
divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|inverse(#2)|
|
"lets suppose anne and bruce take a and b hrs working separately so in 1 hour they can together finish 1 / a + 1 / b portion of the work which equals 1 / 4 ( as the work is completed in 4 hours ) after anne doubles her rate of work the portion completed by the both is 1 / a + 2 / b which is equal to q = 1 / 3 ( as the work is completed in q = 3 hours ) solving these 2 equations we can find b as 12 so , d"
|
physics
|
math_qa__U6PxLAiw2EQCYMWj
|
The sum of all the integers k such that –24 < k < 24 is Select the correct option
A) 0
B) - 2
C) - 45
D) - 49
E) - 51
|
<gadget id="calculator">-24</gadget>
<output>-24</output>
<gadget id="calculator">(-24) + 1</gadget>
<output>-23</output>
<gadget id="calculator">(-23) + 1</gadget>
<output>-22</output>
<gadget id="calculator">(-23) + (-22)</gadget>
<output>-45</output>
<result>C</result>
|
C
| -45 |
The sum of all the integers k such that –24 < k < 24 is
|
{
"A": "0",
"B": "- 2",
"C": "- 45",
"D": "- 49",
"E": "- 51"
}
|
add(add(negate(24), const_1), add(add(negate(24), const_1), const_1))
|
negate(n0)|add(#0,const_1)|add(#1,const_1)|add(#1,#2)|
|
"- 23 - - - - - - - - - - - - - - - - - - 0 - - - - - - - - - - - - - - - - - 23 values upto + 23 cancels outwe are left with only - 23 - 22 sum of which is - 45 . hence option d . c"
|
general
|
math_qa__01T33E6Bl4zdEme5
|
A student is ranked 21th from right and 11th from left. How many students are there in totality ? Select the correct option: A) 18 B) 19 C) 20 D) 31 E) 22
|
<gadget id="calculator">21 + 11</gadget>
<output>32</output>
<gadget id="calculator">32 - 1</gadget>
<output>31</output>
<result>D</result>
|
D
| 31 |
A student is ranked 21th from right and 11th from left. How many students are there in totality ?
|
{
"A": "18",
"B": "19",
"C": "20",
"D": "31",
"E": "22"
}
|
subtract(add(21, 11), const_1)
|
add(n0,n1)|subtract(#0,const_1)|
|
"from right 21 , from left 11 total = 21 + 11 - 1 = 31 answer : d"
|
general
|
math_qa__42fCSm0eDekvvrJI
|
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 19. The larger of the two numbers is:
Options.
A) 437 B) 299 C) 322 D) 345 E) 355
|
<gadget id="calculator">23 * 19</gadget>
<output>437</output>
<result>A</result>
|
A
| 437 |
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 19. The larger of the two numbers is:
|
{
"A": "437",
"B": "299",
"C": "322",
"D": "345",
"E": "355"
}
|
multiply(23, 19)
|
multiply(n0,n2)|
|
"clearly , the numbers are ( 23 x 13 ) and ( 23 x 19 ) . larger number = ( 23 x 19 ) = 437 . answer : option a"
|
other
|
math_qa__LyXQ5fDZn7wjRdAN
|
find the sum of the number of combinations possible by using 12 , 34 such that no number is repeated ( ex : - 12234322 are invalid 12344321 are valid ) more than once . Choose the correct choice from the following: A) 66660 B) 66760 C) 66860 D) 66960 E) 67660
|
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">34 % 10</gadget>
<output>4</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60 * 100</gadget>
<output>6_000</output>
<gadget id="calculator">60_000 + 6_000</gadget>
<output>66_000</output>
<gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">66_000 + 600</gadget>
<output>66_600</output>
<gadget id="calculator">66_600 + 60</gadget>
<output>66_660</output>
<result>A</result>
|
A
| 66,660 |
find the sum of the number of combinations possible by using 12 , 34 such that no number is repeated ( ex : - 12234322 are invalid 12344321 are valid ) more than once .
|
{
"A": "66660",
"B": "66760",
"C": "66860",
"D": "66960",
"E": "67660"
}
|
add(add(add(multiply(multiply(add(add(const_1, const_2), const_3), add(add(add(const_1, const_2), const_3), reminder(34, const_10))), const_1000), multiply(multiply(add(add(const_1, const_2), const_3), add(add(add(const_1, const_2), const_3), reminder(34, const_10))), const_100)), multiply(multiply(add(add(const_1, const_2), const_3), add(add(add(const_1, const_2), const_3), reminder(34, const_10))), const_10)), multiply(add(add(const_1, const_2), const_3), add(add(add(const_1, const_2), const_3), reminder(34, const_10))))
|
add(const_1,const_2)|reminder(n1,const_10)|add(#0,const_3)|add(#2,#1)|multiply(#2,#3)|multiply(#4,const_1000)|multiply(#4,const_100)|multiply(#4,const_10)|add(#5,#6)|add(#8,#7)|add(#9,#4)
|
total no . formed = 4 ! = 4 * 3 * 2 * 1 = 24 each digit will be used at each positions , 6 times sum of digits at unit place = 6 * 1 + 6 * 2 + 6 * 3 + 6 * 4 = 6 * ( 1 + 2 + 3 + 4 ) = 60 this sum will be same for hundred , tens & unit places sum of all 4 digit numbers formed using digits 12 , 34 = 1000 * 60 + 100 * 60 + 10 * 60 + 60 = 60 * ( 1000 + 100 + 10 + 1 ) = 60 * 1111 = 66660 answer : a
|
general
|
math_qa__cchk6FlojBhEL1O6
|
Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $240, what were her original savings?
Pick one
A) $ 900 B) $ 800 C) $ 960 D) $ 700 E) $ 1500
|
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">240 / (1/4)</gadget>
<output>960</output>
<result>C</result>
|
C
| 960 |
Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $240, what were her original savings?
|
{
"A": "$ 900",
"B": "$ 800",
"C": "$ 960",
"D": "$ 700",
"E": "$ 1500"
}
|
divide(240, subtract(const_1, divide(3, 4)))
|
divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)|
|
"if linda spent 3 / 4 of her savings on furnitute , the rest 4 / 4 - 3 / 4 = 1 / 4 on a tv but the tv cost her $ 240 . so 1 / 4 of her savings is $ 240 . so her original savings are 4 times $ 240 = $ 960 correct answer c"
|
general
|
math_qa__meAQnozh9plK5hbN
|
How many seconds will a 800 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? Choices:
A) 11 B) 30 C) 99 D) 48 E) 61
|
<gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">800 / (50/3)</gadget>
<output>48</output>
<result>D</result>
|
D
| 48 |
How many seconds will a 800 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
|
{
"A": "11",
"B": "30",
"C": "99",
"D": "48",
"E": "61"
}
|
divide(800, multiply(subtract(63, 3), const_0_2778))
|
subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)
|
speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 800 * 3 / 50 = 48 sec . answer : d
|
physics
|
math_qa__NiEVgyh4wnVsh1Rw
|
The student manager of the university theater estimated that for every 6 movie tickets sold on Valentine's Weekend, the theater will sell 3 packs of grain crackers at $2.25 each, 4 bottles of a beverage at $1.50 each, and 4 chocolate bars at $1.00 each. Find the approximate average (arithmetic mean) amount of estimated snack sales per movie ticket sold. Select the correct option: A) $ 1.40 B) $ 1.58 C) $ 2.00 D) $ 2.64 E) $ 2.79
|
<gadget id="calculator">3 * 2.25</gadget>
<output>6.75</output>
<gadget id="calculator">4 * 1.5</gadget>
<output>6</output>
<gadget id="calculator">6.75 + 6</gadget>
<output>12.75</output>
<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">12.75 + 4</gadget>
<output>16.75</output>
<gadget id="calculator">16.75 / 6</gadget>
<output>2.791667</output>
<result>E</result>
|
E
| 2.79 |
The student manager of the university theater estimated that for every 6 movie tickets sold on Valentine's Weekend, the theater will sell 3 packs of grain crackers at $2.25 each, 4 bottles of a beverage at $1.50 each, and 4 chocolate bars at $1.00 each. Find the approximate average (arithmetic mean) amount of estimated snack sales per movie ticket sold.
|
{
"A": "$ 1.40",
"B": "$ 1.58",
"C": "$ 2.00",
"D": "$ 2.64",
"E": "$ 2.79"
}
|
divide(add(add(multiply(3, 2.25), multiply(4, 1.5)), multiply(4, 1)), 6)
|
multiply(n1,n2)|multiply(n3,n4)|multiply(n3,n6)|add(#0,#1)|add(#3,#2)|divide(#4,n0)
|
3 * 2.25 + 4 * 1.50 + 4 * 1 = 6.75 + 6 + 4 = 16.75 . this is the sale for 6 tickets avg sale per ticket : 16.75 / 6 = $ 2 . 79 answer : e
|
general
|
math_qa__yknAI6lywnt5fauZ
|
a 28 cm long wire is to be cut into two pieces so that one piece will be 2.00001 / 5 th of the other , how many centimeters will the shorter piece be ? Pick one
A) 12 B) 8 C) 88 D) 77 E) 14
|
<gadget id="calculator">2.00001 / 5</gadget>
<output>0.400002</output>
<gadget id="calculator">0.400002 + 1</gadget>
<output>1.400002</output>
<gadget id="calculator">28 / 1.400002</gadget>
<output>19.999971</output>
<gadget id="calculator">28 - 19.999971</gadget>
<output>8.000029</output>
<result>B</result>
|
B
| 8 |
a 28 cm long wire is to be cut into two pieces so that one piece will be 2.00001 / 5 th of the other , how many centimeters will the shorter piece be ?
|
{
"A": "12",
"B": "8",
"C": "88",
"D": "77",
"E": "14"
}
|
subtract(28, divide(28, add(divide(2.00001, 5), const_1)))
|
divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|
|
"1 : 2 / 5 = 5 : 2 2 / 7 * 28 = 8 answer : b"
|
physics
|
math_qa__x9XYxkTnlRnywXuj
|
eighteen years ago , a father was 3 times as old as his son . now the father is only twice as old as his son . then the sum of the present ages of the son and the father is : Choose the correct option
A) 120 B) 76 C) 108 D) 105 E) 86
|
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 3</gadget>
<output>54</output>
<gadget id="calculator">54 - 18</gadget>
<output>36</output>
<gadget id="calculator">36 * 2</gadget>
<output>72</output>
<gadget id="calculator">36 + 72</gadget>
<output>108</output>
<result>C</result>
|
C
| 108 |
eighteen years ago , a father was 3 times as old as his son . now the father is only twice as old as his son . then the sum of the present ages of the son and the father is :
|
{
"A": "120",
"B": "76",
"C": "108",
"D": "105",
"E": "86"
}
|
add(subtract(multiply(multiply(multiply(const_2, const_3), const_3), 3), multiply(multiply(const_2, const_3), const_3)), multiply(subtract(multiply(multiply(multiply(const_2, const_3), const_3), 3), multiply(multiply(const_2, const_3), const_3)), const_2))
|
multiply(const_2,const_3)|multiply(#0,const_3)|multiply(n0,#1)|subtract(#2,#1)|multiply(#3,const_2)|add(#4,#3)
|
let the present ages of the father and son be 2 x and x years respectively . then , ( 2 x - 18 ) = 3 ( x - 18 ) x = 36 . required sum = ( 2 x + x ) = 3 x = 108 years . answer is c
|
general
|
math_qa__JfuJZfqU0foyW76O
|
The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 828. What is the banker's discount? Choose the correct choice from the following answers:
A) 1240 B) 1120 C) 1190 D) 1978 E) none of these
|
<gadget id="calculator">828 * 100</gadget>
<output>82_800</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">82_800 / 72</gadget>
<output>1_150</output>
<gadget id="calculator">828 + 1_150</gadget>
<output>1_978</output>
<result>D</result>
|
D
| 1,978 |
The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 828. What is the banker's discount?
|
{
"A": "1240",
"B": "1120",
"C": "1190",
"D": "1978",
"E": "none of these"
}
|
add(828, divide(multiply(828, const_100), multiply(12, 6)))
|
multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)|
|
"explanation : td = ( bg × 100 ) / tr = ( 828 × 100 ) / ( 6 × 12 ) = rs . 1150 bg = bd – td = > 828 = bd - 1150 = > bd = 1978 answer : option d"
|
gain
|
math_qa__Hs6xpWchcwAHagoo
|
A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 12 hours longer than the first half, how many hours did it take the runner to run the second half? Choose the correct choice.
A) 20 B) 22 C) 24 D) 26 E) 28
|
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 12</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">40 / (5/3)</gadget>
<output>24</output>
<result>C</result>
|
C
| 24 |
A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 12 hours longer than the first half, how many hours did it take the runner to run the second half?
|
{
"A": "20",
"B": "22",
"C": "24",
"D": "26",
"E": "28"
}
|
divide(40, divide(divide(40, const_2), 12))
|
divide(n0,const_2)|divide(#0,n1)|divide(n0,#1)|
|
"the runner runs the first 20 miles at speed v and the second 20 miles at speed v / 2 . the time t 2 to run the second half must be twice the time t 1 to run the first half . t 2 = 2 * t 1 = t 1 + 12 t 1 = 12 and so t 2 = 24 . the answer is c ."
|
physics
|
math_qa__BYYuijCyd1oxZdop
|
Every day Daniel drives 96 miles back from work. On Sunday, Daniel drove all the way back from work at a constant speed of x miles per hour. On Monday, Daniel drove the first 32 miles back from work at (2x) miles per hour, and the rest of the way at (x/2) miles per hour. The time it took Daniel to drive back from work on Monday is longer than the time it took him to drive back from work on Sunday by what percent? Choose one
A) 10 % B) 20 % C) 30 % D) 40 % E) 50 %
|
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">96 - 32</gadget>
<output>64</output>
<gadget id="calculator">64 * 2</gadget>
<output>128</output>
<gadget id="calculator">16 + 128</gadget>
<output>144</output>
<gadget id="calculator">144 - 96</gadget>
<output>48</output>
<gadget id="calculator">48 / 96</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result>
|
E
| 50 |
Every day Daniel drives 96 miles back from work. On Sunday, Daniel drove all the way back from work at a constant speed of x miles per hour. On Monday, Daniel drove the first 32 miles back from work at (2x) miles per hour, and the rest of the way at (x/2) miles per hour. The time it took Daniel to drive back from work on Monday is longer than the time it took him to drive back from work on Sunday by what percent?
|
{
"A": "10 %",
"B": "20 %",
"C": "30 %",
"D": "40 %",
"E": "50 %"
}
|
multiply(divide(subtract(add(divide(32, 2), multiply(subtract(96, 32), 2)), 96), 96), const_100)
|
divide(n1,n2)|subtract(n0,n1)|multiply(#1,n2)|add(#0,#2)|subtract(#3,n0)|divide(#4,n0)|multiply(#5,const_100)|
|
"let ' s test x = 4 . . . . on sunday , daniel drove 96 miles at 4 miles / hour . d = ( r ) ( t ) 96 = ( 4 ) ( t ) 96 / 4 = 24 = t it takes 24 hours to drive home on monday , daniel drove the first 32 miles at ( 2 ) ( 4 ) = 8 miles / hour and the rest of the way ( 64 miles ) at 4 / 2 = 2 miles / hour d = ( r ) ( t ) 32 = ( 8 ) ( t ) 32 / 8 = 4 = t it takes 4 hours for the first part d = ( r ) ( t ) 64 = ( 2 ) ( t ) 64 / 2 = 32 = t it takes 32 hours for the second part total time to drive home on monday = 4 + 32 = 36 hours we ' re asked by what percent 36 hours is greater than 32 hours . 36 / 32 = 1.5 , so it is 50 % greater . e"
|
physics
|
math_qa__cvvaj524VwBYLlQ5
|
A train running at the speed of 108 km/hr crosses a pole in 7 seconds. Find the length of the train. Options:
A) 150 meter B) 145 meter C) 140 meter D) 135 meter E) 210 meter
|
<gadget id="calculator">108 * 1_000</gadget>
<output>108_000</output>
<gadget id="calculator">108_000 / 3_600</gadget>
<output>30</output>
<gadget id="calculator">30 * 7</gadget>
<output>210</output>
<result>E</result>
|
E
| 210 |
A train running at the speed of 108 km/hr crosses a pole in 7 seconds. Find the length of the train.
|
{
"A": "150 meter",
"B": "145 meter",
"C": "140 meter",
"D": "135 meter",
"E": "210 meter"
}
|
multiply(divide(multiply(108, const_1000), const_3600), 7)
|
multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)|
|
"explanation : speed = 108 * ( 5 / 18 ) m / sec = 30 m / sec length of train ( distance ) = speed * time = 30 * 7 = 210 meter option e"
|
physics
|
math_qa__mjJa4cA47I0u0nHE
|
A train crosses a bridge of length 2500 m in 120 seconds and a lamp post on the bridge in 30 seconds. What is the length of the train in metres ? Select
A) 375 m B) 750 / 3 m C) 2500 / 3 m D) 800 m E) 300 m
|
<gadget id="calculator">120 - 30</gadget>
<output>90</output>
<gadget id="calculator">2_500 / 90</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">(250/9) * 30</gadget>
<output>2_500/3 = around 833.333333</output>
<result>C</result>
|
C
| 833.333333 |
A train crosses a bridge of length 2500 m in 120 seconds and a lamp post on the bridge in 30 seconds. What is the length of the train in metres ?
|
{
"A": "375 m",
"B": "750 / 3 m",
"C": "2500 / 3 m",
"D": "800 m",
"E": "300 m"
}
|
multiply(divide(2500, subtract(120, 30)), 30)
|
subtract(n1,n2)|divide(n0,#0)|multiply(n2,#1)|
|
"let length of train = l case - 1 : distance = 2500 + l ( while crossing the bridge ) time = 120 seconds i . e . speed = distance / time = ( 2500 + l ) / 120 case - 2 : distance = l ( while passing the lamp post ) time = 30 seconds i . e . speed = distance / time = ( l ) / 30 but since speed has to be same in both cases so ( 2500 + l ) / 120 = ( l ) / 30 i . e . 4 l = 2500 + l i . e . 3 l = 2500 i . e . l = 2500 / 3 answer : option c"
|
physics
|
math_qa__93aVHUbRO6xkkiXt
|
X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 5 days and left the job. how many days does X alone need to finish the remaining work? Choose the correct option.
A) 12
B) 5
C) 6
D) 8
E) 9
|
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">5 * (1/15)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(2/3) / (1/18)</gadget>
<output>12</output>
<result>A</result>
|
A
| 12 |
X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 5 days and left the job. how many days does X alone need to finish the remaining work?
|
{
"A": "12",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
}
|
divide(subtract(const_1, multiply(5, divide(const_1, 15))), divide(const_1, 18))
|
divide(const_1,n1)|divide(const_1,n0)|multiply(n2,#0)|subtract(const_1,#2)|divide(#3,#1)
|
work done by x in 1 day = 1 / 18 work done by y in 1 day = 1 / 15 work done by y in 5 days = 5 / 15 = 1 / 3 remaining work = 1 – 1 / 3 = 2 / 3 number of days in which x can finish the remaining work = ( 2 / 3 ) / ( 1 / 18 ) = 12 a
|
physics
|
math_qa__nZIAE8XTuF2H0slz
|
The diameter of the wheel of a car is 120m. How many revolution/min mustthe wheel makeing order to keep a speed of 60 km/hour approximately? Choose one
A) 140 B) 160 C) 220 D) 250 E) 265
|
<gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 60</gadget>
<output>1_000</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(22/7) * (6/5)</gadget>
<output>132/35 = around 3.771429</output>
<gadget id="calculator">1_000 / (132/35)</gadget>
<output>8_750/33 = around 265.151515</output>
<result>E</result>
|
E
| 265 |
The diameter of the wheel of a car is 120m. How many revolution/min mustthe wheel makeing order to keep a speed of 60 km/hour approximately?
|
{
"A": "140",
"B": "160",
"C": "220",
"D": "250",
"E": "265"
}
|
divide(divide(multiply(60, const_1000), 60), multiply(divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3)), divide(120, const_100)))
|
add(const_3,const_4)|divide(n0,const_100)|multiply(n1,const_1000)|multiply(const_10,const_2)|add(#3,const_2)|divide(#2,n1)|divide(#4,#0)|multiply(#6,#1)|divide(#5,#7)|
|
"distance to be covered in 1 min . = ( 60 x 1000 ) / ( 60 ) m = 1000 m . circumference of the wheel = ( 2 x ( 22 / 7 ) x 0.60 ) m = 3.77 m . number of revolutions per min . = ( 1000 / 3.77 ) = 265 e"
|
physics
|
math_qa__BTC2GjO7ZqYR9HJL
|
If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land heads up exectly twice in 3 consecutive flips ? Choose the correct choice from the following.
A) 0.125 B) 0.25 C) 0.375 D) 0.5 E) 0.666
|
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 3</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3</gadget>
<output>3/8 = around 0.375</output>
<result>C</result>
|
C
| 0.375 |
If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land heads up exectly twice in 3 consecutive flips ?
|
{
"A": "0.125",
"B": "0.25",
"C": "0.375",
"D": "0.5",
"E": "0.666"
}
|
multiply(power(divide(const_1, const_2), 3), 3)
|
divide(const_1,const_2)|power(#0,n0)|multiply(n0,#1)|
|
"p = ncm * p ^ m * q ^ ( n - m ) n - the total number of trials . m - the number of trials with heads . n - m - the number of trials with tails . p - probability of heads . q - probability of tails . p = 3 c 2 * ( 1 / 2 ) ^ 2 * ( 1 / 2 ) ^ 1 = 3 / 8 = 0.375 answer : c"
|
general
|
math_qa__brHj5R5BSA3GXlQY
|
The length of the bridge, which a train 110 metres long and travelling at 45 km/hr can cross in 30 seconds, is: Pick: A) 230 B) 240 C) 245 D) 250 E) 265
|
<gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 110</gadget>
<output>265</output>
<result>E</result>
|
E
| 265 |
The length of the bridge, which a train 110 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
|
{
"A": "230",
"B": "240",
"C": "245",
"D": "250",
"E": "265"
}
|
subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 110)
|
speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)|
|
"speed = [ 45 x 5 / 18 ] m / sec = [ 25 / 2 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 110 + x ) / 30 = 25 / 2 = > 2 ( 110 + x ) = 750 = > x = 265 m . answer : option e"
|
physics
|
math_qa__17WxBPHDZcnsH9e2
|
One hour after Yolanda started walking from X to Y, a distance of 40 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 2 miles per hour and Bobâs was 4 miles per hour, how many miles had Bob walked when they met? Options:
A) 24 B) 23.5 C) 22 D) 21.2 E) 25.32
|
<gadget id="calculator">40 - 2</gadget>
<output>38</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">38 / 6</gadget>
<output>19/3 = around 6.333333</output>
<gadget id="calculator">(19/3) * 4</gadget>
<output>76/3 = around 25.333333</output>
<result>E</result>
|
E
| 25.32 |
One hour after Yolanda started walking from X to Y, a distance of 40 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 2 miles per hour and Bobâs was 4 miles per hour, how many miles had Bob walked when they met?
|
{
"A": "24",
"B": "23.5",
"C": "22",
"D": "21.2",
"E": "25.32"
}
|
multiply(divide(subtract(40, 2), add(2, 4)), 4)
|
add(n1,n2)|subtract(n0,n1)|divide(#1,#0)|multiply(n2,#2)|
|
"let t be the number of hours that bob had walked when he met yolanda . then , when they met , bob had walked 4 t miles and yolanda had walked 2 ( t + 1 ) miles . these distances must sum to 40 miles , so 4 t + 2 ( t + 1 ) = 40 , which may be solved for t as follows 4 t + 2 ( t + 1 ) = 40 4 t + 2 t + 2 = 40 6 t = 38 t = 6.33 ( hours ) therefore , bob had walked 4 t = 4 ( 7.6 ) = 25.32 miles when they met . the best answer is e ."
|
physics
|
math_qa__Rd3woFRK7zPI9Xqx
|
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years? Choices: A) 5 % B) 7 % C) 9 % D) 2 % E) 4 %
|
<gadget id="calculator">100 * 160</gadget>
<output>16_000</output>
<gadget id="calculator">800 * 4</gadget>
<output>3_200</output>
<gadget id="calculator">16_000 / 3_200</gadget>
<output>5</output>
<result>A</result>
|
A
| 5 |
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?
|
{
"A": "5 %",
"B": "7 %",
"C": "9 %",
"D": "2 %",
"E": "4 %"
}
|
divide(multiply(const_100, 160), multiply(800, 4))
|
multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)|
|
"160 = ( 180 * 4 * r ) / 100 r = 5 % answer : a"
|
gain
|
math_qa__tclCp3HHVMnKWnpM
|
A and B can do a piece of work in 4 2/3 days and 5 days respectively. They work together for 1 days and then A leaves. In how many days after that B will complete the work alone.
Choose one.
A) 3.92 days B) 1.92 days C) 2.12 days D) 2.02 days E) 2.92 days
|
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">4 + (2/3)</gadget>
<output>14/3 = around 4.666667</output>
<gadget id="calculator">1 / (14/3)</gadget>
<output>3/14 = around 0.214286</output>
<gadget id="calculator">(1/5) + (3/14)</gadget>
<output>29/70 = around 0.414286</output>
<gadget id="calculator">1 - (29/70)</gadget>
<output>41/70 = around 0.585714</output>
<gadget id="calculator">5 * (41/70)</gadget>
<output>41/14 = around 2.928571</output>
<result>E</result>
|
E
| 2.92 |
A and B can do a piece of work in 4 2/3 days and 5 days respectively. They work together for 1 days and then A leaves. In how many days after that B will complete the work alone.
|
{
"A": "3.92 days",
"B": "1.92 days",
"C": "2.12 days",
"D": "2.02 days",
"E": "2.92 days"
}
|
multiply(5, subtract(const_1, add(inverse(5), inverse(add(const_4, divide(const_2, const_3))))))
|
divide(const_2,const_3)|inverse(n3)|add(#0,const_4)|inverse(#2)|add(#1,#3)|subtract(const_1,#4)|multiply(n3,#5)
|
3 / 14 * 1 + ( 1 + x ) / 5 = 1 x = 2.92 days answer : e
|
physics
|
math_qa__QeNoNh6qZi4bIlr1
|
Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
Pick one:
A) 50 m B) 60 m C) 65 m D) 75 m E) 80 m
|
<gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">200 + 40</gadget>
<output>240</output>
<gadget id="calculator">240 / 4</gadget>
<output>60</output>
<result>B</result>
|
B
| 60 |
Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
|
{
"A": "50 m",
"B": "60 m",
"C": "65 m",
"D": "75 m",
"E": "80 m"
}
|
divide(add(divide(5300, 26.50), multiply(const_2, 20)), const_4)
|
divide(n2,n1)|multiply(n0,const_2)|add(#0,#1)|divide(#2,const_4)|
|
"let breadth = x metres . then , length = ( x + 20 ) metres . perimeter = 5300 m = 200 m . 26.50 2 [ ( x + 20 ) + x ] = 200 2 x + 20 = 100 2 x = 80 x = 40 . hence , length = x + 20 = 60 m b"
|
physics
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.