id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__Mt9phL6cSQjxaZbE
|
There were two candidates in an election. Winner candidate received 60% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate? Choose the correct choice from the following options
A) 776 B) 864 C) 299 D) 257 E) 125
|
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">288 / (1/5)</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 * 60</gadget>
<output>86_400</output>
<gadget id="calculator">86_400 / 100</gadget>
<output>864</output>
<result>B</result>
|
B
| 864 |
There were two candidates in an election. Winner candidate received 60% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
|
{
"A": "776",
"B": "864",
"C": "299",
"D": "257",
"E": "125"
}
|
divide(multiply(divide(288, divide(subtract(60, subtract(const_100, 60)), const_100)), 60), const_100)
|
subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)|
|
"w = 60 % l = 40 % 60 % - 40 % = 20 % 20 % - - - - - - - - 288 60 % - - - - - - - - ? = > 864 answer : b"
|
gain
|
math_qa__4bipnhUJjezAvqKD
|
In the rectangular coordinate system, what is the x-intercept of a line passing through (10, 3) and (β2, β3)? Select the correct option: A) 4 B) 2 C) 0 D) β 2 E) β 4
|
<gadget id="calculator">-3</gadget>
<output>-3</output>
<gadget id="calculator">(-3) - 3</gadget>
<output>-6</output>
<gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">(-2) - 10</gadget>
<output>-12</output>
<gadget id="calculator">(-6) / (-12)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">2 / (1/2)</gadget>
<output>4</output>
<result>A</result>
|
A
| 4 |
In the rectangular coordinate system, what is the x-intercept of a line passing through (10, 3) and (β2, β3)?
|
{
"A": "4",
"B": "2",
"C": "0",
"D": "β 2",
"E": "β 4"
}
|
divide(subtract(multiply(divide(subtract(negate(3), 3), subtract(negate(2), 10)), 10), 3), divide(subtract(negate(3), 3), subtract(negate(2), 10)))
|
negate(n3)|negate(n2)|subtract(#0,n1)|subtract(#1,n0)|divide(#2,#3)|multiply(n0,#4)|subtract(#5,n1)|divide(#6,#4)|
|
"slope = rise / run = 6 / 12 = 1 / 2 the equation of the line is y = ( 1 / 2 ) x + b 3 = ( 1 / 2 ) ( 10 ) + b b = - 2 the equation of the line is y = ( 1 / 2 ) x - 2 to find the x - intercept , let y = 0 : 0 = ( 1 / 2 ) x - 2 x = 4 the answer is a ."
|
general
|
math_qa__1YQyjhNSKA4VZegk
|
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: Select the correct option:
A) 276
B) 299
C) 322
D) 345
E) 355
|
<gadget id="calculator">23 * 14</gadget>
<output>322</output>
<result>C</result>
|
C
| 322 |
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
|
{
"A": "276",
"B": "299",
"C": "322",
"D": "345",
"E": "355"
}
|
multiply(23, 14)
|
multiply(n0,n2)|
|
"clearly , the numbers are ( 23 x 13 ) and ( 23 x 14 ) . larger number = ( 23 x 14 ) = 322 . answer : option c"
|
other
|
math_qa__VV9aKahpC79lUFVP
|
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions
Choose the correct choice:
A) 700 B) 704 C) 704 D) 706 E) 707
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 22.4</gadget>
<output>70.4</output>
<gadget id="calculator">70.4 * 2</gadget>
<output>140.8</output>
<gadget id="calculator">140.8 * 500</gadget>
<output>70_400</output>
<gadget id="calculator">70_400 / 100</gadget>
<output>704</output>
<result>B</result>
|
B
| 704 |
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions
|
{
"A": "700",
"B": "704",
"C": "704",
"D": "706",
"E": "707"
}
|
divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 22.4), const_2), 500), const_100)
|
add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)|
|
"in one resolution , the distance covered by the wheel is its own circumference . distance covered in 500 resolutions . = 500 * 2 * 22 / 7 * 22.4 = 70400 cm = 704 m answer : option b"
|
physics
|
math_qa__JPSSnHIACze8uBdm
|
A 220 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Choose the correct choice from the following answers
A) 280 B) 270 C) 260 D) 250 E) 240
|
<gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 220</gadget>
<output>280</output>
<result>A</result>
|
A
| 280 |
A 220 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
|
{
"A": "280",
"B": "270",
"C": "260",
"D": "250",
"E": "240"
}
|
subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 220)
|
add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)|
|
"relative speed = 120 + 80 = 200 km / hr . = 200 * 5 / 18 = 500 / 9 m / sec . let the length of the other train be x m . then , ( x + 220 ) / 9 = 500 / 9 = > x = 280 . answer : option a"
|
physics
|
math_qa__9wX5LyEhYesq8FKo
|
The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 402 to 500 inclusive? Choose the most appropriate option:
A) 14,550
B) 18,550
C) 22,550
D) 26,550
E) 30,550
|
<gadget id="calculator">500 + 402</gadget>
<output>902</output>
<gadget id="calculator">902 / 2</gadget>
<output>451</output>
<gadget id="calculator">500 - 402</gadget>
<output>98</output>
<gadget id="calculator">98 / 2</gadget>
<output>49</output>
<gadget id="calculator">49 + 1</gadget>
<output>50</output>
<gadget id="calculator">451 * 50</gadget>
<output>22_550</output>
<result>C</result>
|
C
| 22,550 |
The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 402 to 500 inclusive?
|
{
"A": "14,550",
"B": "18,550",
"C": "22,550",
"D": "26,550",
"E": "30,550"
}
|
multiply(divide(add(500, 402), const_2), add(divide(subtract(500, 402), const_2), const_1))
|
add(n2,n3)|subtract(n3,n2)|divide(#1,const_2)|divide(#0,const_2)|add(#2,const_1)|multiply(#4,#3)|
|
"2 + 4 + 6 + 8 + . . . + 100 = 2550 402 + 404 + . . . + 500 = 50 ( 400 ) + ( 2 + 4 + . . . + 100 ) = 20,000 + 2550 = 22,550 the answer is c ."
|
general
|
math_qa__UbAF0c2R1TTtKxiM
|
We run a business that rents out canoes and kayaks. A canoe rental costs $9 per day, and a kayak rental costs $12 dollars per day. One day, our business rents out 4 canoes for every 3 kayaks and receives a total of $432 in revenue. How many more canoes than kayaks were rented out? Choose the correct choice from the following choices:
A) 10 B) 9 C) 8 D) 7 E) 6
|
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">4 * 9</gadget>
<output>36</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">36 + 36</gadget>
<output>72</output>
<gadget id="calculator">432 / 72</gadget>
<output>6</output>
<gadget id="calculator">1 * 6</gadget>
<output>6</output>
<result>E</result>
|
E
| 6 |
We run a business that rents out canoes and kayaks. A canoe rental costs $9 per day, and a kayak rental costs $12 dollars per day. One day, our business rents out 4 canoes for every 3 kayaks and receives a total of $432 in revenue. How many more canoes than kayaks were rented out?
|
{
"A": "10",
"B": "9",
"C": "8",
"D": "7",
"E": "6"
}
|
multiply(subtract(4, 3), divide(432, add(multiply(4, 9), multiply(3, 12))))
|
multiply(n0,n2)|multiply(n1,n3)|subtract(n2,n3)|add(#0,#1)|divide(n4,#3)|multiply(#4,#2)|
|
"let x be the number of canoes . then 3 x / 4 is the number of kayaks . 9 x + ( 3 x / 4 ) * 12 = 432 9 x + 9 x = 432 18 x = 432 x = 24 ( canoes ) 3 x / 4 = 18 ( kayaks ) there were 24 - 18 = 6 more canoes rented out . the answer is e ."
|
general
|
math_qa__BPppf1nqJsmSYpY6
|
Ramu bought an old car for Rs. 48000. He spent Rs. 14000 on repairs and sold it for Rs. 72900. What is his profit percent?
Choose the correct choice from the following answers
A) 16 % B) 17.5 % C) 18.2 % D) 58.5 % E) 13 %
|
<gadget id="calculator">48_000 + 14_000</gadget>
<output>62_000</output>
<gadget id="calculator">72_900 - 62_000</gadget>
<output>10_900</output>
<gadget id="calculator">10_900 / 62_000</gadget>
<output>109/620 = around 0.175806</output>
<gadget id="calculator">(109/620) * 100</gadget>
<output>545/31 = around 17.580645</output>
<result>B</result>
|
B
| 17.5 |
Ramu bought an old car for Rs. 48000. He spent Rs. 14000 on repairs and sold it for Rs. 72900. What is his profit percent?
|
{
"A": "16 %",
"B": "17.5 %",
"C": "18.2 %",
"D": "58.5 %",
"E": "13 %"
}
|
multiply(divide(subtract(72900, add(48000, 14000)), add(48000, 14000)), const_100)
|
add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)|
|
"total cp = rs . 48000 + rs . 14000 = rs . 62000 and sp = rs . 72900 profit ( % ) = ( 72900 - 62000 ) / 62000 * 100 = 17.5 % answer : b"
|
gain
|
math_qa__r1LL1nadH0Cjoym4
|
Rs.2600 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%? Pick
A) 1600 B) 1700 C) 1800 D) 1900 E) 2000
|
<gadget id="calculator">6 * 2_600</gadget>
<output>15_600</output>
<gadget id="calculator">15_600 / 100</gadget>
<output>156</output>
<gadget id="calculator">140 - 156</gadget>
<output>-16</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(1/20) - (3/50)</gadget>
<output>-1/100 = around -0.01</output>
<gadget id="calculator">(-16) / (-1/100)</gadget>
<output>1_600</output>
<result>A</result>
|
A
| 1,600 |
Rs.2600 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
|
{
"A": "1600",
"B": "1700",
"C": "1800",
"D": "1900",
"E": "2000"
}
|
divide(subtract(140, divide(multiply(6, 2600), const_100)), subtract(divide(5, const_100), divide(6, const_100)))
|
divide(n1,const_100)|divide(n2,const_100)|multiply(n0,n2)|divide(#2,const_100)|subtract(#0,#1)|subtract(n3,#3)|divide(#5,#4)|
|
"( x * 5 * 1 ) / 100 + [ ( 2600 - x ) * 6 * 1 ] / 100 = 140 x = 1600 answer : a"
|
gain
|
math_qa__1qyts2wIZFnjjh3k
|
A bag contains 6 white marbles and 6 black marbles. If each of 6 girls and 6 boys randomly selects and keeps a marble, what is the probability that all of the girls select the same colored marble? Select the correct option:
A) 1 / 35
B) 1 / 10
C) 1 / 3
D) 1 / 462
E) 1 / 252
|
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 6)</gadget>
<output>924</output>
<gadget id="calculator">2 / 924</gadget>
<output>1/462 = around 0.002165</output>
<result>D</result>
|
D
| 0.002165 |
A bag contains 6 white marbles and 6 black marbles. If each of 6 girls and 6 boys randomly selects and keeps a marble, what is the probability that all of the girls select the same colored marble?
|
{
"A": "1 / 35",
"B": "1 / 10",
"C": "1 / 3",
"D": "1 / 462",
"E": "1 / 252"
}
|
divide(const_2, choose(add(6, 6), 6))
|
add(n0,n0)|choose(#0,n0)|divide(const_2,#1)|
|
"first , total ways to select for all boys and girls , i . e 12 ! / ( 6 ! * 6 ! ) = 12 * 11 * 10 * 9 * 8 * 7 / 6 * 5 * 4 * 3 * 2 = 924 then there are one two way girls can have all same colors , either white or black . the number of ways in which 6 girls can select 6 white balls = 6 c 6 = 1 the number of ways in which 6 girls can select 6 black balls = 6 c 6 = 1 therefore , total favorable outcomes / total outcomes = 2 / 924 = 1 / 462 d"
|
probability
|
math_qa__zbjWCtacZkW80grW
|
The average weight of 7 person's increases by 3.5 kg when a new person comes in place of one of them weighing 75 kg. What might be the weight of the new person?
Choose the correct choice from the following:
A) 74 kg B) 78.5 kg C) 99.5 kg D) data inadequate E) none of these
|
<gadget id="calculator">7 * 3.5</gadget>
<output>24.5</output>
<gadget id="calculator">24.5 + 75</gadget>
<output>99.5</output>
<result>C</result>
|
C
| 99.5 |
The average weight of 7 person's increases by 3.5 kg when a new person comes in place of one of them weighing 75 kg. What might be the weight of the new person?
|
{
"A": "74 kg",
"B": "78.5 kg",
"C": "99.5 kg",
"D": "data inadequate",
"E": "none of these"
}
|
add(multiply(7, 3.5), 75)
|
multiply(n0,n1)|add(n2,#0)|
|
"total weight increased = ( 7 x 3.5 ) kg = 24.5 kg . weight of new person = ( 75 + 24.5 ) kg = 99.5 kg . answer : option c"
|
general
|
math_qa__7ZJGSUFNnn241szy
|
In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 32 people were made to stand in a column, how many columns could be formed? Choose the correct choice from the following answers
A) 15 B) 20 C) 25 D) 30 E) 35
|
<gadget id="calculator">32 / 16</gadget>
<output>2</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result>
|
A
| 15 |
In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 32 people were made to stand in a column, how many columns could be formed?
|
{
"A": "15",
"B": "20",
"C": "25",
"D": "30",
"E": "35"
}
|
divide(30, divide(32, 16))
|
divide(n2,n1)|divide(n0,#0)|
|
"16 * 30 = 32 * n n = 15 the answer is a ."
|
other
|
math_qa__OSO1k0y3h79xdlT2
|
What least number must be subtracted from 427398 so that remaining no.is divisible by 10
Answers: A) 3 B) 5 C) 6 D) 7 E) 8
|
<gadget id="calculator">427_398 / 10</gadget>
<output>213_699/5 = around 42_739.8</output>
<gadget id="calculator">floor(213_699/5)</gadget>
<output>42_739</output>
<gadget id="calculator">42_739 * 10</gadget>
<output>427_390</output>
<gadget id="calculator">427_398 - 427_390</gadget>
<output>8</output>
<result>E</result>
|
E
| 8 |
What least number must be subtracted from 427398 so that remaining no.is divisible by 10
|
{
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
}
|
subtract(427398, multiply(floor(divide(427398, 10)), 10))
|
divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)|
|
"explanation : on dividing 427398 by 10 we get the remainder 8 , so 8 should be subtracted answer : option e"
|
general
|
math_qa__DocrTpAWXCOSfmBk
|
The average age of applicants for a new job is 10, with a standard deviation of 8. The hiring manager is only willing to accept applicants whose age is within one standard deviation of the average age. Assuming that all applicants' ages are integers and that the endpoints of the range are included, what is the maximum number of different ages of the applicants? Choose the correct choice from the following choices: A) 8 B) 16 C) 17 D) 18 E) 34
|
<gadget id="calculator">10 + 8</gadget>
<output>18</output>
<gadget id="calculator">10 - 8</gadget>
<output>2</output>
<gadget id="calculator">18 - 2</gadget>
<output>16</output>
<gadget id="calculator">16 + 1</gadget>
<output>17</output>
<result>C</result>
|
C
| 17 |
The average age of applicants for a new job is 10, with a standard deviation of 8. The hiring manager is only willing to accept applicants whose age is within one standard deviation of the average age. Assuming that all applicants' ages are integers and that the endpoints of the range are included, what is the maximum number of different ages of the applicants?
|
{
"A": "8",
"B": "16",
"C": "17",
"D": "18",
"E": "34"
}
|
add(subtract(add(10, 8), subtract(10, 8)), const_1)
|
add(n0,n1)|subtract(n0,n1)|subtract(#0,#1)|add(#2,const_1)
|
minimum age = average - 1 standard deviation = 10 - 8 = 2 maximum age = average + 1 standard deviation = 10 + 8 = 18 maximum number of different ages of the applicants = 18 - 2 + 1 = 17 answer c
|
general
|
math_qa__b27yMNSjHqswubka
|
Ajay can ride 50km in 1 hour. In how many hours he can ride 900km? Choose the correct answer:
A) 10 hrs
B) 15 hrs
C) 20 hrs
D) 25 hrs
E) 18 hrs
|
<gadget id="calculator">900 / 50</gadget>
<output>18</output>
<result>E</result>
|
E
| 18 |
Ajay can ride 50km in 1 hour. In how many hours he can ride 900km?
|
{
"A": "10 hrs",
"B": "15 hrs",
"C": "20 hrs",
"D": "25 hrs",
"E": "18 hrs"
}
|
divide(900, 50)
|
divide(n2,n0)
|
1 hour he ride 50 km he ride 900 km in = 900 / 50 * 1 = 18 hours answer is e
|
physics
|
math_qa__i00i5us9xU1omVJh
|
Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 7 even numbers. His mother immediately worked out the answer. How much had he scored in Math? Choose the correct choice from the following options: A) 80 B) 90 C) 56 D) 70 E) 60
|
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<result>C</result>
|
C
| 56 |
Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 7 even numbers. His mother immediately worked out the answer. How much had he scored in Math?
|
{
"A": "80",
"B": "90",
"C": "56",
"D": "70",
"E": "60"
}
|
multiply(add(7, const_1), 7)
|
add(n0,const_1)|multiply(n0,#0)|
|
"c 56 sum = ( n x n ) + n hence , 7 x 7 = 49 + 7 = 56"
|
physics
|
math_qa__jJeEOsj1H11vrTFf
|
The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 80 metres? Choose the correct choice from the following options
A) 16 seconds
B) 76 seconds
C) 26 seconds
D) 12 seconds
E) 18 seconds
|
<gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<result>A</result>
|
A
| 16 |
The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 80 metres?
|
{
"A": "16 seconds",
"B": "76 seconds",
"C": "26 seconds",
"D": "12 seconds",
"E": "18 seconds"
}
|
divide(80, multiply(add(15, 3), const_0_2778))
|
add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)|
|
"speed of the boat downstream = 15 + 3 = 18 kmph = 18 * 5 / 18 = 5 m / s hence time taken to cover 80 m = 80 / 5 = 16 seconds . answer : a"
|
physics
|
math_qa__ImLi3sOLchMy2ZLl
|
A certain clock marks every hour by striking a number of times equal to the hour,and the time required for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stroke and the end of the last stroke is 44 seconds. at 12:00 ,how many seconds elapse between the beginning of the first stroke and the end of the last stroke?
Select the correct option:
A) a . 72 B) b . 50 C) c . 92 D) d . 46 E) e . 44
|
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">44 / 11</gadget>
<output>4</output>
<gadget id="calculator">12 + 11</gadget>
<output>23</output>
<gadget id="calculator">4 * 23</gadget>
<output>92</output>
<result>C</result>
|
C
| 92 |
A certain clock marks every hour by striking a number of times equal to the hour,and the time required for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stroke and the end of the last stroke is 44 seconds. at 12:00 ,how many seconds elapse between the beginning of the first stroke and the end of the last stroke?
|
{
"A": "a . 72",
"B": "b . 50",
"C": "c . 92",
"D": "d . 46",
"E": "e . 44"
}
|
multiply(divide(44, add(6, add(const_1, const_4))), add(12, add(6, add(const_1, const_4))))
|
add(const_1,const_4)|add(n0,#0)|add(n3,#1)|divide(n2,#1)|multiply(#2,#3)
|
at 6 : 00 it ' ll chime 6 times . if we assume that the time taken to chime is x , then time between chimes is also x . so you have 6 chimes , which is 6 x and 5 time intervals between chimes . this means that 11 x = 44 seconds . thus x = 4 seconds . by a similar logic , at 12 : 00 , there are 12 chimes and 11 intervals so the total time is ( 12 + 11 ) x = 23 x = 92 seconds . answer c
|
general
|
math_qa__IaFXBY0gBO6gCnFv
|
Each week, Harry is paid x dollars per hour for the first 21 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ? Choose the correct choice from the following answers:
A) 35 B) 36 C) 37 D) 38 E) 39
|
<gadget id="calculator">40 + 2</gadget>
<output>42</output>
<gadget id="calculator">42 - 21</gadget>
<output>21</output>
<gadget id="calculator">21 / 1.5</gadget>
<output>14</output>
<gadget id="calculator">14 + 21</gadget>
<output>35</output>
<result>A</result>
|
A
| 35 |
Each week, Harry is paid x dollars per hour for the first 21 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
|
{
"A": "35",
"B": "36",
"C": "37",
"D": "38",
"E": "39"
}
|
add(divide(subtract(add(40, 2), 21), 1.5), 21)
|
add(n2,n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)|
|
"42 x = 21 x + 1.5 x ( h - 21 ) = = > 42 = 21 + 1.5 ( h - 21 ) = = > h - 21 = 21 / 1.5 = 14 = > h = 35 answer is a"
|
general
|
math_qa__z9QkksorfB4BStN1
|
The volume of a cube is 729 cc. Find its surface.
Choose one.
A) 486
B) 556
C) 255
D) 287
E) 267
|
<gadget id="calculator">729 ** (1/3)</gadget>
<output>9</output>
<gadget id="calculator">6 * (9 ** 2)</gadget>
<output>486</output>
<result>A</result>
|
A
| 486 |
The volume of a cube is 729 cc. Find its surface.
|
{
"A": "486",
"B": "556",
"C": "255",
"D": "287",
"E": "267"
}
|
surface_cube(cube_edge_by_volume(729))
|
cube_edge_by_volume(n0)|surface_cube(#0)|
|
"a 3 = 729 = > a = 9 6 a 2 = 6 * 9 * 9 = 486 answer : a"
|
geometry
|
math_qa__OsUCKq7eEJxMZVHW
|
A bag contains 4 white marbles and 4 black marbles. If each of 4 girls and 4 boys randomly selects and keeps a marble, what is the probability that all of the girls select the same colored marble? Choose the most appropriate option
A) 1 / 35 B) 1 / 9 C) 1 / 10 D) 1 / 20 E) 1 / 30
|
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">binomial(8, 4)</gadget>
<output>70</output>
<gadget id="calculator">2 / 70</gadget>
<output>1/35 = around 0.028571</output>
<result>A</result>
|
A
| 0.028571 |
A bag contains 4 white marbles and 4 black marbles. If each of 4 girls and 4 boys randomly selects and keeps a marble, what is the probability that all of the girls select the same colored marble?
|
{
"A": "1 / 35",
"B": "1 / 9",
"C": "1 / 10",
"D": "1 / 20",
"E": "1 / 30"
}
|
divide(const_2, choose(add(4, 4), 4))
|
add(n0,n0)|choose(#0,n0)|divide(const_2,#1)|
|
"first , total ways to select for all boys and girls , i . e 8 ! / ( 4 ! * 4 ! ) = 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 / 4 * 3 * 2 * 1 * 4 * 3 * 2 * 1 = 70 then there are one two way girls can have all same colors , either white or black . the number of ways in which 4 girls can select 4 white balls = 4 c 4 = 1 the number of ways in which 4 girls can select 4 black balls = 4 c 4 = 1 therefore , total favorable outcomes / total outcomes = 2 / 70 = 1 / 35 a"
|
probability
|
math_qa__5Nl63ujgsvEAYTVb
|
A can knit a pair of socks in 3 days. B can knit the same thing in 6 days. If they are knitting together, in how many days will they knit two pairs of socks? Select: A) 4 days B) 2 days C) 4 1 β 2 days D) 3 days E) none of these
|
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/3) + (1/6)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) / 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>A</result>
|
A
| 4 |
A can knit a pair of socks in 3 days. B can knit the same thing in 6 days. If they are knitting together, in how many days will they knit two pairs of socks?
|
{
"A": "4 days",
"B": "2 days",
"C": "4 1 β 2 days",
"D": "3 days",
"E": "none of these"
}
|
inverse(divide(add(inverse(3), inverse(6)), const_2))
|
inverse(n0)|inverse(n1)|add(#0,#1)|divide(#2,const_2)|inverse(#3)
|
explanationa β s one day β s work = 1 β 3 rd work . b β s one day β s work = 1 β 6 rd work . ( a + b ) β s one day β s work = 1 β 3 + 1 β 6 = 1 β 2 nd work . β΄ a and b together can complete the work ( knit a pair of socks ) in 2 days . β΄ they together knit two pair of socks in 4 days . answer a
|
physics
|
math_qa__BvM54UUCPxdzNWbQ
|
If 2x + y = 26 and x + 2y = 10, then (x + y)/3 =
Select the correct option
A) 1 B) 4 / 3 C) 17 / 5 D) 18 / 5 E) 4
|
<gadget id="calculator">26 * 2</gadget>
<output>52</output>
<gadget id="calculator">52 - 10</gadget>
<output>42</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">42 / 3</gadget>
<output>14</output>
<gadget id="calculator">2 * 14</gadget>
<output>28</output>
<gadget id="calculator">26 - 28</gadget>
<output>-2</output>
<gadget id="calculator">14 + (-2)</gadget>
<output>12</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>E</result>
|
E
| 4 |
If 2x + y = 26 and x + 2y = 10, then (x + y)/3 =
|
{
"A": "1",
"B": "4 / 3",
"C": "17 / 5",
"D": "18 / 5",
"E": "4"
}
|
divide(add(divide(subtract(multiply(26, 2), 10), subtract(multiply(2, 2), const_1)), subtract(26, multiply(2, divide(subtract(multiply(26, 2), 10), subtract(multiply(2, 2), const_1))))), 3)
|
multiply(n0,n1)|multiply(n0,n0)|subtract(#0,n3)|subtract(#1,const_1)|divide(#2,#3)|multiply(n0,#4)|subtract(n1,#5)|add(#4,#6)|divide(#7,n4)|
|
"we have two equations : 2 x + y = 26 x + 2 y = 10 notice that something nice happens when we add them . we get : 3 x + 3 y = 36 divide both sides by 3 to get : x + y = 12 so , ( x + y ) / 3 = 12 / 3 = 4 answer : e"
|
general
|
math_qa__dVQojUQvuRJLfLje
|
Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.16 per cubic meter? Choose the correct answer: A) 2998 B) 2799 C) 2890 D) 1485 E) 1584
|
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">pi * ((3/2) ** 2) * 14</gadget>
<output>63*pi/2 = around 98.960169</output>
<gadget id="calculator">(63*pi/2) * 16</gadget>
<output>504*pi = around 1_583.362697</output>
<result>E</result>
|
E
| 1,584 |
Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.16 per cubic meter?
|
{
"A": "2998",
"B": "2799",
"C": "2890",
"D": "1485",
"E": "1584"
}
|
multiply(volume_cylinder(divide(3, const_2), 14), 16)
|
divide(n1,const_2)|volume_cylinder(#0,n0)|multiply(n2,#1)|
|
"22 / 7 * 14 * 3 / 2 * 3 / 2 = 99 m 2 99 * 16 = 1584 answer : e"
|
physics
|
math_qa__lsWmfyVXLiTFlJZP
|
Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.1015. Find the cost of each ice-cream cup? Choose the correct choice from the following options: A) 34 B) 76 C) 29 D) 12 E) 20
|
<gadget id="calculator">16 * 6</gadget>
<output>96</output>
<gadget id="calculator">1_015 - 96</gadget>
<output>919</output>
<gadget id="calculator">5 * 45</gadget>
<output>225</output>
<gadget id="calculator">919 - 225</gadget>
<output>694</output>
<gadget id="calculator">7 * 70</gadget>
<output>490</output>
<gadget id="calculator">694 - 490</gadget>
<output>204</output>
<gadget id="calculator">204 / 6</gadget>
<output>34</output>
<result>A</result>
|
A
| 34 |
Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.1015. Find the cost of each ice-cream cup?
|
{
"A": "34",
"B": "76",
"C": "29",
"D": "12",
"E": "20"
}
|
divide(subtract(subtract(subtract(1015, multiply(16, 6)), multiply(5, 45)), multiply(7, 70)), 6)
|
multiply(n0,n3)|multiply(n1,n5)|multiply(n2,n6)|subtract(n7,#0)|subtract(#3,#1)|subtract(#4,#2)|divide(#5,n3)|
|
"explanation : let the cost of each ice - cream cup be rs . x 16 ( 6 ) + 5 ( 45 ) + 7 ( 70 ) + 6 ( x ) = 1015 96 + 225 + 490 + 6 x = 1015 6 x = 204 = > x = 34 . answer : a"
|
general
|
math_qa__nOheLLI2zAKbREWn
|
a , b , c subscribe rs . 50000 for a business , a subscribes rs . 4000 more than b and b rs . 5000 more thanc . out of a total profit of rs . 35000 , a receives : Choose the correct choice
A) 14700 B) 14703 C) 37798 D) 13777 E) 14778
|
<gadget id="calculator">5_000 + 4_000</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 + 5_000</gadget>
<output>14_000</output>
<gadget id="calculator">50_000 - 14_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 + 9_000</gadget>
<output>21_000</output>
<gadget id="calculator">21_000 / 50_000</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">35_000 * (21/50)</gadget>
<output>14_700</output>
<result>A</result>
|
A
| 14,700 |
a , b , c subscribe rs . 50000 for a business , a subscribes rs . 4000 more than b and b rs . 5000 more thanc . out of a total profit of rs . 35000 , a receives :
|
{
"A": "14700",
"B": "14703",
"C": "37798",
"D": "13777",
"E": "14778"
}
|
multiply(35000, divide(add(divide(subtract(50000, add(add(5000, 4000), 5000)), const_3), add(5000, 4000)), 50000))
|
add(n1,n2)|add(n2,#0)|subtract(n0,#1)|divide(#2,const_3)|add(#0,#3)|divide(#4,n0)|multiply(n3,#5)
|
explanation : let c = x . then , b = x + 5000 and a = x + 5000 + 4000 = x + 9000 . so , x + x + 5000 + x + 9000 = 50000 < = > 3 x = 36000 < = > x = 12000 . a : b : c = 21000 : 17000 : 12000 = 21 : 17 : 12 . a ' s share = rs . ( 35000 * 21 / 50 ) = rs . 14,700 . answer : a ) 14700
|
general
|
math_qa__moQWZeEkzk9Xk1dR
|
A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 6 days before the completion of the work. In how many days was the work completed? Choose the most appropriate option: A) 12 days B) 16 days C) 18 days D) 11.5 days E) 38 days
|
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/24) + (1/30)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">(3/40) * 6</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 - (9/20)</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/60) + (3/40)</gadget>
<output>11/120 = around 0.091667</output>
<gadget id="calculator">(11/20) / (11/120)</gadget>
<output>6</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<result>D</result>
|
D
| 11.5 |
A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 6 days before the completion of the work. In how many days was the work completed?
|
{
"A": "12 days",
"B": "16 days",
"C": "18 days",
"D": "11.5 days",
"E": "38 days"
}
|
add(divide(subtract(const_1, multiply(add(divide(const_1, 24), divide(const_1, 30)), 6)), add(divide(const_1, multiply(add(const_2, const_3), multiply(const_2, 6))), add(divide(const_1, 24), divide(const_1, 30)))), 6)
|
add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|multiply(const_2,n3)|add(#1,#2)|multiply(#0,#3)|divide(const_1,#5)|multiply(n3,#4)|add(#4,#6)|subtract(const_1,#7)|divide(#9,#8)|add(n3,#10)|
|
"one day work of a , b and c = 1 / 24 + 1 / 30 + 1 / 40 = 1 / 10 work done by a and b together in the last 6 days = 6 * ( 1 / 24 + 1 / 30 ) = 9 / 20 remaining work = 11 / 20 the number of days required for this initial work = 5.5 days . the total number of days required = 6 + 5.5 = 11.5 days . answer : d"
|
physics
|
math_qa__6w6buRUU30Asqxhm
|
Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $300, what were her original savings? Choose the correct choice
A) $ 1200 B) $ 1300 C) $ 1400 D) $ 1800 E) $ 1900
|
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">300 / (1/4)</gadget>
<output>1_200</output>
<result>A</result>
|
A
| 1,200 |
Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $300, what were her original savings?
|
{
"A": "$ 1200",
"B": "$ 1300",
"C": "$ 1400",
"D": "$ 1800",
"E": "$ 1900"
}
|
divide(300, subtract(const_1, divide(3, 4)))
|
divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)|
|
"if linda spent 3 / 4 of her savings on furnitute , the rest 4 / 4 - 3 / 4 = 1 / 4 on a tv but the tv cost her $ 300 . so 1 / 4 of her savings is $ 300 . so her original savings are 4 times $ 300 = $ 1200 correct answer a"
|
general
|
math_qa__UyhmyBmjuHnDeQMD
|
Walking 7/6 of his usual rate, a boy reaches his school 6 min early. Find his usual time to reach the school? Choose the correct choice from the following choices:
A) 22 B) 28 C) 99 D) 42 E) 66
|
<gadget id="calculator">6 * 7</gadget>
<output>42</output>
<result>D</result>
|
D
| 42 |
Walking 7/6 of his usual rate, a boy reaches his school 6 min early. Find his usual time to reach the school?
|
{
"A": "22",
"B": "28",
"C": "99",
"D": "42",
"E": "66"
}
|
multiply(6, 7)
|
multiply(n0,n2)|
|
"speed ratio = 1 : 7 / 6 = 6 : 7 time ratio = 7 : 6 1 - - - - - - - - 7 6 - - - - - - - - - ? = 42 m answer : d"
|
gain
|
math_qa__lKPpC3oRhvNEctGf
|
A jogger running at 9 kmph along side a railway track is 230 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Choose one.
A) 3.6 sec B) 18 sec C) 35 sec D) 72 sec E) none of these
|
<gadget id="calculator">230 + 120</gadget>
<output>350</output>
<gadget id="calculator">350 / 1_000</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">(7/20) / 36</gadget>
<output>7/720 = around 0.009722</output>
<gadget id="calculator">(7/720) * 60</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(7/12) * 60</gadget>
<output>35</output>
<result>C</result>
|
C
| 35 |
A jogger running at 9 kmph along side a railway track is 230 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
|
{
"A": "3.6 sec",
"B": "18 sec",
"C": "35 sec",
"D": "72 sec",
"E": "none of these"
}
|
multiply(multiply(divide(divide(add(230, 120), const_1000), subtract(45, 9)), const_60), const_60)
|
add(n1,n2)|subtract(n3,n0)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_60)|multiply(#4,const_60)|
|
"speed of train relative to jogger = ( 45 β 9 ) km / h = 36 km / h = ( 36 Γ 5 β 18 ) m / sec = 10 m / sec distance to be covered = ( 230 + 120 ) m = 350 m . β΄ time taken = ( 350 β 10 ) sec = 35 sec . answer c"
|
physics
|
math_qa__vwoLi6366W5ZkNU2
|
8 people decided to split the restaurant bill evenly. If the bill was $214.18 dollars, how much money did they 1 cent is the smallest unit?
Select:
A) $ 214.16 B) $ 214.17 C) $ 214.18 D) $ 214.19 E) $ 214.24
|
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">214.18 + (3/100)</gadget>
<output>214.21</output>
<result>E</result>
|
E
| 214.24 |
8 people decided to split the restaurant bill evenly. If the bill was $214.18 dollars, how much money did they 1 cent is the smallest unit?
|
{
"A": "$ 214.16",
"B": "$ 214.17",
"C": "$ 214.18",
"D": "$ 214.19",
"E": "$ 214.24"
}
|
add(214.18, divide(const_3, const_100))
|
divide(const_3,const_100)|add(n1,#0)|
|
"if the last three digits of a whole number are divisible by 8 , then the entire number is divisible by 8 the last 3 digit 418 not divisible by a hence , we need to add 6 to this number for it to be divisible by 8 correct option : e"
|
general
|
math_qa__hKRHMAdONjO8PB3x
|
If 4 women can color 48 m long cloth in 2 days, then 6 women can color 36 m long cloth in Options:
A) 2 days B) 3 days C) 1 day D) 4 days E) 5 days
|
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">36 / 36</gadget>
<output>1</output>
<result>C</result>
|
C
| 1 |
If 4 women can color 48 m long cloth in 2 days, then 6 women can color 36 m long cloth in
|
{
"A": "2 days",
"B": "3 days",
"C": "1 day",
"D": "4 days",
"E": "5 days"
}
|
divide(36, multiply(6, divide(48, multiply(4, 2))))
|
multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)|
|
"the length of cloth painted by one woman in one day = 48 / 4 Γ 2 = 6 m no . of days required to paint 36 m cloth by 6 women = 36 / 6 Γ 6 = 1 day . c"
|
physics
|
math_qa__tUXrNplL8dUbNFPo
|
A cheese factory sells its cheese in rectangular blocks. A normal block has a volume of 4 cubic feet. If a large block has twice the width, twice the depth, and twice the length of a normal block, what is the volume of cheese in a large block in cubic feet? Choose one
A) 16
B) 20
C) 36
D) 32
E) 28
|
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>D</result>
|
D
| 32 |
A cheese factory sells its cheese in rectangular blocks. A normal block has a volume of 4 cubic feet. If a large block has twice the width, twice the depth, and twice the length of a normal block, what is the volume of cheese in a large block in cubic feet?
|
{
"A": "16",
"B": "20",
"C": "36",
"D": "32",
"E": "28"
}
|
multiply(multiply(multiply(const_2, const_2), const_2), 4)
|
multiply(const_2,const_2)|multiply(#0,const_2)|multiply(n0,#1)
|
volume of cube = lbh = 4 new cube l , b , h are increases of 2 l , 2 b , 2 h new volume of cube = 2 l * 2 b * 2 h = 8 * lbh = 8 * 4 = 32 answer : d
|
geometry
|
math_qa__MgJfVfvxKDgczPVz
|
The monthly rent of a shop of dimension 20feet Γ 18feet is Rs.1440. What is the annual rent per square foot of the shop? Select.
A) 48 B) 56 C) 68 D) 87 E) 92
|
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">20 * 18</gadget>
<output>360</output>
<gadget id="calculator">1_440 / 360</gadget>
<output>4</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<result>A</result>
|
A
| 48 |
The monthly rent of a shop of dimension 20feet Γ 18feet is Rs.1440. What is the annual rent per square foot of the shop?
|
{
"A": "48",
"B": "56",
"C": "68",
"D": "87",
"E": "92"
}
|
multiply(add(const_10, const_2), divide(1440, rectangle_area(20, 18)))
|
add(const_10,const_2)|rectangle_area(n0,n1)|divide(n2,#1)|multiply(#0,#2)
|
sol . monthly rent per square feet = 1440 / ( 20 * 18 ) = 4 & annual rent per square feet = 12 * 4 = 48 answer : a
|
geometry
|
math_qa__f5XsYjqgFXGGzw2h
|
Ashley and Betty start a business with $9000 each, and after 3 months, Betty adds another $5000. How should they share the profits at the end of the 24 months?
Choose the most appropriate option:
A) 72 : 107
B) 4 : 5
C) 17 : 23
D) 3 : 4
E) 68 : 95
|
<gadget id="calculator">9_000 * 24</gadget>
<output>216_000</output>
<gadget id="calculator">9_000 * 3</gadget>
<output>27_000</output>
<gadget id="calculator">9_000 + 5_000</gadget>
<output>14_000</output>
<gadget id="calculator">24 - 3</gadget>
<output>21</output>
<gadget id="calculator">14_000 * 21</gadget>
<output>294_000</output>
<gadget id="calculator">27_000 + 294_000</gadget>
<output>321_000</output>
<gadget id="calculator">216_000 / 321_000</gadget>
<output>72/107 = around 0.672897</output>
<result>A</result>
|
A
| 0.672897 |
Ashley and Betty start a business with $9000 each, and after 3 months, Betty adds another $5000. How should they share the profits at the end of the 24 months?
|
{
"A": "72 : 107",
"B": "4 : 5",
"C": "17 : 23",
"D": "3 : 4",
"E": "68 : 95"
}
|
divide(multiply(9000, 24), add(multiply(9000, 3), multiply(add(9000, 5000), subtract(24, 3))))
|
add(n0,n2)|multiply(n0,n3)|multiply(n0,n1)|subtract(n3,n1)|multiply(#0,#3)|add(#2,#4)|divide(#1,#5)
|
ashley invests $ 9000 for 24 months , but betty invests $ 9000 for the first 3 months and then adds $ 5000 . so , the investment of betty for remaining 21 months is $ 14000 . ashley : betty 9000 * 24 : ( 9000 * 3 ) + ( 14000 * 21 ) 216000 : 321000 a : b = 72 : 107 answer : a
|
gain
|
math_qa__BCWczMCExxhApjXh
|
In an examination, 25% of total students failed in Hindi, 50% failed in English and 25% in both. The percentage of these who passed in both the subjects is : Choose the correct choice from the following choices
A) 23 B) 37 C) 28 D) 40 E) 50
|
<gadget id="calculator">25 + 50</gadget>
<output>75</output>
<gadget id="calculator">75 - 25</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<result>E</result>
|
E
| 50 |
In an examination, 25% of total students failed in Hindi, 50% failed in English and 25% in both. The percentage of these who passed in both the subjects is :
|
{
"A": "23",
"B": "37",
"C": "28",
"D": "40",
"E": "50"
}
|
subtract(const_100, subtract(add(25, 50), 25))
|
add(n0,n1)|subtract(#0,n2)|subtract(const_100,#1)|
|
"explanation : formula n ( a Γ’ Λ Βͺ b ) = n ( a ) + n ( b ) Γ’ Λ β n ( a Γ’ Λ Β© b ) fail in hindi or english = 25 + 50 Γ’ β¬ β 25 = 50 therefore students who passed = 100 Γ’ β¬ β 50 = 50 . answer : e"
|
general
|
math_qa__OQkP9I3XYyDdEUHO
|
A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 4000 as profit , what is their total profit? Select the correct option.
A) 28000 B) 30000 C) 32000 D) 34000 E) none of these
|
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">4_000 / (1/7)</gadget>
<output>28_000</output>
<result>A</result>
|
A
| 28,000 |
A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 4000 as profit , what is their total profit?
|
{
"A": "28000",
"B": "30000",
"C": "32000",
"D": "34000",
"E": "none of these"
}
|
divide(4000, divide(multiply(const_1, const_1), add(multiply(const_3, const_2), multiply(const_1, const_1))))
|
multiply(const_1,const_1)|multiply(const_2,const_3)|add(#1,#0)|divide(#0,#2)|divide(n0,#3)|
|
"explanation : suppose b ' s investment = x . then a ' s investment = 3 x suppose bs period of investment = y , then a ' s period of investment = 2 y a : b = 3 x * 2 y : xy = 6 : 1 total profit * 1 / 7 = 4000 = > total profit = 4000 * 7 = 28000 . answer : option a"
|
general
|
math_qa__p1eC0ODBe7Etfz2S
|
Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age? Pick one.
A) 22 B) 15 C) 77 D) 266 E) 182
|
<gadget id="calculator">26 - 6</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<result>B</result>
|
B
| 15 |
Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age?
|
{
"A": "22",
"B": "15",
"C": "77",
"D": "266",
"E": "182"
}
|
divide(multiply(subtract(26, 6), 3), 4)
|
subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)|
|
"present age is 4 x and 3 x , = > 4 x + 6 = 26 = > x = 5 so deepak age is = 3 ( 5 ) = 15 answer : b"
|
other
|
math_qa__hMHKaEj0gQi8JGx5
|
A canoe has two oars, left and right. Each oar either works or breaks. The failure or non-failure of each oar is independent of the failure or non-failure of the other. You can still row the canoe with one oar. The probability that the left oar works is 3/5. The probability that the right oar works is also 3/5. What is the probability J that you can still row the canoe? Select.
A) 9 / 25 B) 10 / 25 C) 6 / 10 D) 2 / 3 E) 21 / 25
|
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/5) * (2/5)</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) + (6/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">(9/25) + (12/25)</gadget>
<output>21/25 = around 0.84</output>
<result>E</result>
|
E
| 0.84 |
A canoe has two oars, left and right. Each oar either works or breaks. The failure or non-failure of each oar is independent of the failure or non-failure of the other. You can still row the canoe with one oar. The probability that the left oar works is 3/5. The probability that the right oar works is also 3/5. What is the probability J that you can still row the canoe?
|
{
"A": "9 / 25",
"B": "10 / 25",
"C": "6 / 10",
"D": "2 / 3",
"E": "21 / 25"
}
|
add(multiply(divide(3, 5), divide(3, 5)), add(multiply(divide(3, 5), divide(const_2, 5)), multiply(divide(3, 5), divide(const_2, 5))))
|
divide(n0,n1)|divide(const_2,n1)|multiply(#0,#1)|multiply(#0,#0)|add(#2,#2)|add(#4,#3)
|
simply look at the question from the other side . what is the probability that you can β t row the canoe ? this would be 2 / 5 x 2 / 5 = 4 / 25 . using the idea that the probability j of something happening is 1 β the probability that it doesn β t happen , you can use the following equation to reach the right answer : 1 β 4 / 25 = 21 / 25 . answer choice e .
|
general
|
math_qa__Z3nA299qvwQtql1t
|
How many multiples of 7 are there between 14 and 343, exclusive ? Options: A) 48 B) 47 C) 46 D) 45 E) 44
|
<gadget id="calculator">343 - 14</gadget>
<output>329</output>
<gadget id="calculator">329 / 7</gadget>
<output>47</output>
<gadget id="calculator">47 + 1</gadget>
<output>48</output>
<result>C</result>
|
C
| 46 |
How many multiples of 7 are there between 14 and 343, exclusive ?
|
{
"A": "48",
"B": "47",
"C": "46",
"D": "45",
"E": "44"
}
|
add(divide(subtract(343, 14), 7), const_1)
|
subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)|
|
"7 * 2 = 14 7 * 49 = 343 total multiples = ( 49 - 2 ) + 1 = 48 exclude 7 343 = 48 - 2 = 46 answer is ( c )"
|
general
|
math_qa__o2XcOUEYzk2V9f8L
|
The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 5 kmph, what time will he take to cover 60 metres? Pick one: A) 16 seconds B) 76 seconds C) 10.8 seconds D) 12 seconds E) 18 seconds
|
<gadget id="calculator">15 + 5</gadget>
<output>20</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">20 * (5/18)</gadget>
<output>50/9 = around 5.555556</output>
<gadget id="calculator">60 / (50/9)</gadget>
<output>54/5 = around 10.8</output>
<result>C</result>
|
C
| 10.8 |
The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 5 kmph, what time will he take to cover 60 metres?
|
{
"A": "16 seconds",
"B": "76 seconds",
"C": "10.8 seconds",
"D": "12 seconds",
"E": "18 seconds"
}
|
divide(60, multiply(add(15, 5), const_0_2778))
|
add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)|
|
"speed of the boat downstream = 15 + 5 = 20 kmph = 20 * 5 / 18 = 50 / 9 m / s hence time taken to cover 60 m = 60 * 9 / 50 = 10.8 seconds . answer : c"
|
physics
|
math_qa__IaFtu0ZgkLzL7fno
|
David and Lewis leave Chennai for Hyderabad simultaneously at 8 P.M in the night driving in two cars at speeds of 50 mph and 70 mph respectively. As soon as Lewis reaches Hyderabad he returns back to Chennai along the same route and meets David on the way back. If the distance between the two cities is 350 miles, how far from Chennai did David and Lewis meet?
Choose the correct option
A) 250 miles B) 240 miles C) 230 miles D) 235 miles E) 75 miles
|
<gadget id="calculator">350 / 70</gadget>
<output>5</output>
<gadget id="calculator">5 * 50</gadget>
<output>250</output>
<result>A</result>
|
A
| 250 |
David and Lewis leave Chennai for Hyderabad simultaneously at 8 P.M in the night driving in two cars at speeds of 50 mph and 70 mph respectively. As soon as Lewis reaches Hyderabad he returns back to Chennai along the same route and meets David on the way back. If the distance between the two cities is 350 miles, how far from Chennai did David and Lewis meet?
|
{
"A": "250 miles",
"B": "240 miles",
"C": "230 miles",
"D": "235 miles",
"E": "75 miles"
}
|
multiply(divide(350, 70), 50)
|
divide(n3,n2)|multiply(n1,#0)
|
time taken by lewis to reach hyderabad = 350 / 70 = 5 hours in 5 hours , david travels 50 * 5 = 250 miles so distance at which they meet should be greater than 250 miles . only a satisfies . answer is a .
|
physics
|
math_qa__rn8HivA7L5Hvk0XT
|
Divide $600 among A,B in the ratio 1:2. How many $ that A get? Choose the correct choice
A) $ 50
B) $ 500
C) $ 150
D) $ 250
E) $ 600
|
<gadget id="calculator">600 / 1</gadget>
<output>600</output>
<result>E</result>
|
E
| 600 |
Divide $600 among A,B in the ratio 1:2. How many $ that A get?
|
{
"A": "$ 50",
"B": "$ 500",
"C": "$ 150",
"D": "$ 250",
"E": "$ 600"
}
|
divide(600, 1)
|
divide(n0,n1)
|
sum of ratio terms = 1 + 2 = 3 a = 600 * 1 / 3 = $ 200 answer is e
|
other
|
math_qa__uRxk3MThoAQDNtxV
|
Cereal A is 10% sugar by weight, whereas healthier but less delicious Cereal B is 4% sugar by weight. To make a delicious and healthy mixture that is 5% sugar, what should be the ratio of Cereal A to Cereal B, by weight?
Options
A) 2 : 9 B) 2 : 7 C) 1 : 6 D) 1 : 4 E) 1 : 5
|
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<result>E</result>
|
E
| 0.2 |
Cereal A is 10% sugar by weight, whereas healthier but less delicious Cereal B is 4% sugar by weight. To make a delicious and healthy mixture that is 5% sugar, what should be the ratio of Cereal A to Cereal B, by weight?
|
{
"A": "2 : 9",
"B": "2 : 7",
"C": "1 : 6",
"D": "1 : 4",
"E": "1 : 5"
}
|
divide(subtract(5, 4), subtract(10, 5))
|
subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)|
|
"ratio of a / ratio of b = ( average wt of mixture - wt of b ) / ( wt of a - average wt of mixture ) = > ratio of a / ratio of b = ( 5 - 4 ) / ( 10 - 5 ) = 1 / 5 so they should be mixed in the ratio 1 : 5 answer - e"
|
general
|
math_qa__pVgIS3qjgOQ6nHwG
|
What is the HCF of 2/3, 4/9 and 6/18 Select the correct option:
A) 7 / 45 B) 2 / 45 C) 1 / 9 D) 8 / 45 E) 9 / 45
|
<gadget id="calculator">2 / 18</gadget>
<output>1/9 = around 0.111111</output>
<result>C</result>
|
C
| 0.111111 |
What is the HCF of 2/3, 4/9 and 6/18
|
{
"A": "7 / 45",
"B": "2 / 45",
"C": "1 / 9",
"D": "8 / 45",
"E": "9 / 45"
}
|
divide(2, 18)
|
divide(n0,n5)
|
explanation : hcf of fractions = hcf of numerators / lcm of denominators = ( hcf of 2 , 4 , 6 ) / ( lcm of 3 , 9 , 18 ) = 2 / 18 = 1 / 9 answer : option c
|
general
|
math_qa__DyxZt8Sv2O2gHpPS
|
The mean proportional between 234 and 104 is
Pick one.
A) 12 B) 39 C) 54 D) 156 E) none
|
<gadget id="calculator">234 * 104</gadget>
<output>24_336</output>
<gadget id="calculator">24_336 ** (1/2)</gadget>
<output>156</output>
<result>D</result>
|
D
| 156 |
The mean proportional between 234 and 104 is
|
{
"A": "12",
"B": "39",
"C": "54",
"D": "156",
"E": "none"
}
|
sqrt(multiply(234, 104))
|
multiply(n0,n1)|sqrt(#0)|
|
"sol . required mean proportional = β 234 x 104 = β 13 x 9 x 2 x 13 x 8 = ( 13 x 3 x 4 ) = 156 . answer d"
|
general
|
math_qa__cUH29HyR3XN6VUVN
|
A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.6.30 less, he would have gained 30%. Find the cost of the article. Choose the correct choice from the following: A) 30 B) 40 C) 50 D) 60 E) 70
|
<gadget id="calculator">6.3 * 100</gadget>
<output>630</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">130 * 80</gadget>
<output>10_400</output>
<gadget id="calculator">10_400 / 100</gadget>
<output>104</output>
<gadget id="calculator">125 - 104</gadget>
<output>21</output>
<gadget id="calculator">630 / 21</gadget>
<output>30</output>
<result>A</result>
|
A
| 30 |
A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.6.30 less, he would have gained 30%. Find the cost of the article.
|
{
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
}
|
divide(multiply(6.30, const_100), subtract(add(25, const_100), divide(multiply(add(30, const_100), subtract(const_100, 20)), const_100)))
|
add(n0,const_100)|add(n3,const_100)|multiply(n2,const_100)|subtract(const_100,n1)|multiply(#1,#3)|divide(#4,const_100)|subtract(#0,#5)|divide(#2,#6)|
|
"let c . p = 100 gain = 25 % s . p = 125 supposed c . p = 80 gain = 30 % s . p = ( 130 * 80 ) / 100 = 104 diff = ( 125 - 104 ) = 21 diff 21 when c . p = 100 then diff 6.30 when c . p = ( 100 * 6.30 ) / 21 = 30 answer : a"
|
gain
|
math_qa__9jzE63iRgSkiYyl4
|
a bus starts from city x . the number of women in the bus is half of the number of men . in city y , 16 men leave the bus and 8 women enter . now , number of men and women is equal . in the beginning , how many passengers entered the bus ?
Choose the correct option.
A) 15 B) 30 C) 36 D) 72 E) 46
|
<gadget id="calculator">16 + 8</gadget>
<output>24</output>
<gadget id="calculator">3 * 24</gadget>
<output>72</output>
<result>D</result>
|
D
| 72 |
a bus starts from city x . the number of women in the bus is half of the number of men . in city y , 16 men leave the bus and 8 women enter . now , number of men and women is equal . in the beginning , how many passengers entered the bus ?
|
{
"A": "15",
"B": "30",
"C": "36",
"D": "72",
"E": "46"
}
|
multiply(const_3, add(16, 8))
|
add(n0,n1)|multiply(#0,const_3)
|
explanation : originally , let number of women = x . then , number of men = 2 x . so , in city y , we have : ( 2 x - 16 ) = ( x + 8 ) or x = 24 . therefore total number of passengers in the beginning = ( x + 2 x ) = 3 x = 72 . answer : d
|
general
|
math_qa__30x2ftEWcPvFDxP9
|
At Tea factory, each employee working the second shift produced 2/3 as many widgets as each employee working the first shift. If the first shift has 3/4 as many employees, what fraction of the total widgets did the second shift produce? Choose the correct choice from the following answers.
A) 8 / 17
B) 1 / 2
C) 8 / 9
D) 9 / 8
E) 17 / 8
|
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">8 / 17</gadget>
<output>8/17 = around 0.470588</output>
<result>A</result>
|
A
| 0.470588 |
At Tea factory, each employee working the second shift produced 2/3 as many widgets as each employee working the first shift. If the first shift has 3/4 as many employees, what fraction of the total widgets did the second shift produce?
|
{
"A": "8 / 17",
"B": "1 / 2",
"C": "8 / 9",
"D": "9 / 8",
"E": "17 / 8"
}
|
divide(multiply(4, 2), add(multiply(3, 3), multiply(4, 2)))
|
multiply(n0,n3)|multiply(n1,n1)|add(#1,#0)|divide(#0,#2)
|
at tea factory , let the first shift have 3 employee and each produce 3 widgets , so the total number of widgets produced by the first shift is 3 * 3 = 9 ; then the second shift would have 4 employees and each second shift employee would produce 3 * 2 / 3 = 2 widgets , so the total number of widgets produced by the second shift employees would be 4 * 2 = 8 ; the ratio of the second shift production to the total is 8 / ( 9 + 8 ) = 8 / 17 . answer : a .
|
physics
|
math_qa__SongVvRGWtNMY47I
|
There are two concentric circles with radii 6 and 4. If the radius of the outer circle is increased by 50% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase? Choose the correct choice from the following.
A) 160 B) 210 C) 260 D) 310 E) 360
|
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 * (3/2)</gadget>
<output>9</output>
<gadget id="calculator">9 ** 2</gadget>
<output>81</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">4 * (3/4)</gadget>
<output>3</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">81 - 9</gadget>
<output>72</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">36 - 16</gadget>
<output>20</output>
<gadget id="calculator">72 - 20</gadget>
<output>52</output>
<gadget id="calculator">52 / 20</gadget>
<output>13/5 = around 2.6</output>
<gadget id="calculator">(13/5) * 100</gadget>
<output>260</output>
<result>C</result>
|
C
| 260 |
There are two concentric circles with radii 6 and 4. If the radius of the outer circle is increased by 50% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase?
|
{
"A": "160",
"B": "210",
"C": "260",
"D": "310",
"E": "360"
}
|
multiply(divide(subtract(subtract(power(multiply(6, divide(add(const_100, 50), const_100)), const_2), power(multiply(4, divide(subtract(const_100, 25), const_100)), const_2)), subtract(power(6, const_2), power(4, const_2))), subtract(power(6, const_2), power(4, const_2))), const_100)
|
add(n2,const_100)|power(n0,const_2)|power(n1,const_2)|subtract(const_100,n3)|divide(#0,const_100)|divide(#3,const_100)|subtract(#1,#2)|multiply(n0,#4)|multiply(n1,#5)|power(#7,const_2)|power(#8,const_2)|subtract(#9,#10)|subtract(#11,#6)|divide(#12,#6)|multiply(#13,const_100)|
|
"the area of a circle is pir ^ 2 , where r is the radius . the area of the big circle is 36 pi . the area of the small circle is 16 pi . the area a 1 between the circles is 20 pi . when the big circle ' s radius increases , the new area is 81 pi . when the small circle ' s radius decreases , the new area is 9 pi . the area a 2 between the circles is 72 pi . the ratio of a 2 / a 1 is 72 / 20 = 3.6 which is an increase of 260 % . the answer is c ."
|
gain
|
math_qa__kIA9OM4p0WjTGsJv
|
John works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 6 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked? Choose the correct choice from the following answers
A) 1 / 8 B) 1 / 7 C) 1 / 2 D) 1 / 4 E) 1 / 6
|
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>C</result>
|
C
| 0.5 |
John works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 6 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked?
|
{
"A": "1 / 8",
"B": "1 / 7",
"C": "1 / 2",
"D": "1 / 4",
"E": "1 / 6"
}
|
divide(6, multiply(6, const_2))
|
multiply(n0,const_2)|divide(n0,#0)
|
first notice the number of months for which he worked - march to sept i . e . 7 months avg of monthly totals in tips for months other than august = x tips in august = 6 x total tips for all months = 6 * x + 6 x = 12 x tips for august / total tips for all months = 6 x / 12 x = 1 / 2 answer : c
|
general
|
math_qa__Cy9ctyPVPGDLy6v8
|
X does a work in 15 days. Y does the same work in 45 days. In how many days they together will do the same work? Choose one.
A) 10 B) 12 C) 20 D) 11.25 E) 15
|
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(1/15) + (1/45)</gadget>
<output>4/45 = around 0.088889</output>
<gadget id="calculator">1 / (4/45)</gadget>
<output>45/4 = around 11.25</output>
<result>D</result>
|
D
| 11.25 |
X does a work in 15 days. Y does the same work in 45 days. In how many days they together will do the same work?
|
{
"A": "10",
"B": "12",
"C": "20",
"D": "11.25",
"E": "15"
}
|
inverse(add(divide(const_1, 15), divide(const_1, 45)))
|
divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)|
|
"x ' s 1 day ' s work = 1 / 15 y ' s 1 day ' s work = 1 / 45 ( x + y ) ' s 1 day ' s work = ( 1 / 15 + 1 / 45 ) = 1 / 11.25 both together will finish the work in 11.25 days . correct option is d"
|
physics
|
math_qa__0lnhdMeVCc4VQbff
|
In a certain state, the ratio of registered Republicans to registered Democrats is 3 to 2, and every registered voter is either a Republican or a Democrat. If 75 percent of the Republicans and 15 percent of the Democrats are expected to vote for Candidate X, and everyone else is expected to vote for Candidate Y, by what percent is Candidate X expected to win the election? Choose the correct choice from the following answers:
A) 2 % B) 5 % C) 8 % D) 10 % E) 15 %
|
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 2</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 3</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">(3/10) + (9/4)</gadget>
<output>51/20 = around 2.55</output>
<gadget id="calculator">3 - (9/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">2 - (3/10)</gadget>
<output>17/10 = around 1.7</output>
<gadget id="calculator">(3/4) + (17/10)</gadget>
<output>49/20 = around 2.45</output>
<gadget id="calculator">(51/20) - (49/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">(1/10) / 5</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 100</gadget>
<output>2</output>
<result>A</result>
|
A
| 2 |
In a certain state, the ratio of registered Republicans to registered Democrats is 3 to 2, and every registered voter is either a Republican or a Democrat. If 75 percent of the Republicans and 15 percent of the Democrats are expected to vote for Candidate X, and everyone else is expected to vote for Candidate Y, by what percent is Candidate X expected to win the election?
|
{
"A": "2 %",
"B": "5 %",
"C": "8 %",
"D": "10 %",
"E": "15 %"
}
|
multiply(divide(subtract(add(multiply(divide(15, const_100), 2), multiply(divide(75, const_100), 3)), add(subtract(3, multiply(divide(75, const_100), 3)), subtract(2, multiply(divide(15, const_100), 2)))), add(3, 2)), const_100)
|
add(n0,n1)|divide(n3,const_100)|divide(n2,const_100)|multiply(n1,#1)|multiply(n0,#2)|add(#3,#4)|subtract(n0,#4)|subtract(n1,#3)|add(#6,#7)|subtract(#5,#8)|divide(#9,#0)|multiply(#10,const_100)|
|
"since we were expected to find a percentage figure - it thought that it might be easier to pick a ' smart number ' to represent the total number of voters ( republicans and democrats ) . therefore , i picked 100 ( as the total number of voters ) and thus 3 : 2 = = 60 : 40 represents the number ratio of republicans : democrats . if 75 % of republicans ( which is ( 60 * 0.75 ) = 45 ) and 15 % of democrats ( 40 * 0.15 = 6 ) voted for candidate x , means that out of total of 100 voters ; 51 ( 45 + 6 ) voters voted for candidate x and 49 voted for candidate y . thus we can infer that candidate x is expected to win the election by 2 ( 51 - 49 ) votes . therefore candidate x is expected to win the election by ( 2 / 100 ) votes which is equivalent to 2 % . i think the answer is a ."
|
other
|
math_qa__ycXWpJNYjZeuCXxD
|
The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 4000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation? Choose the correct choice from the following answers
A) 500 B) 1,600 / 3 C) 1,000 D) 1,500 E) 2,500
|
<gadget id="calculator">4_000 / 2</gadget>
<output>2_000</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2_000 * (1/2)</gadget>
<output>1_000</output>
<result>C</result>
|
C
| 1,000 |
The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 4000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation?
|
{
"A": "500",
"B": "1,600 / 3",
"C": "1,000",
"D": "1,500",
"E": "2,500"
}
|
multiply(divide(4000, 2), divide(const_1, 2))
|
divide(n8,n3)|divide(const_1,n3)|multiply(#0,#1)|
|
"st + 2 s = 5 st t + 2 = 5 t 2 = 4 t t = 1 / 2 we are looking for distance ( d = s * t ) so we need to solve for speed now that we have time . speed y 14 - speed x 13 speed = d / t 3 d / t - d / t = 4000 ( remember , t is the same because both asteroids were observed for the same amount of time ) 2 d = 4000 2 = 2000 d = s * t d = 2000 * ( 1 / 2 ) d = 1000 answer : c"
|
physics
|
math_qa__g1GKgTkaZcGWkZ1Z
|
A corporation that had $10 billion in profits for the year paid out $500 million in employee benefits. Approximately what percent of the profits were the employee benefits? (Note: 1 billion = 10^9) Choose the correct option: A) 50 % B) 20 % C) 5 % D) 2 % E) 0.2 %
|
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">10 ** 6</gadget>
<output>1_000_000</output>
<gadget id="calculator">500 * 1_000_000</gadget>
<output>500_000_000</output>
<gadget id="calculator">10 ** 9</gadget>
<output>1_000_000_000</output>
<gadget id="calculator">10 * 1_000_000_000</gadget>
<output>10_000_000_000</output>
<gadget id="calculator">500_000_000 / 10_000_000_000</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>C</result>
|
C
| 5 |
A corporation that had $10 billion in profits for the year paid out $500 million in employee benefits. Approximately what percent of the profits were the employee benefits? (Note: 1 billion = 10^9)
|
{
"A": "50 %",
"B": "20 %",
"C": "5 %",
"D": "2 %",
"E": "0.2 %"
}
|
multiply(divide(multiply(500, power(10, add(const_3, const_3))), multiply(10, power(10, 9))), const_100)
|
add(const_3,const_3)|power(n3,n4)|multiply(n0,#1)|power(n3,#0)|multiply(n1,#3)|divide(#4,#2)|multiply(#5,const_100)|
|
"required answer = [ employee benefit / profit ] * 100 = [ ( 500 million ) / ( 10 billion ) ] * 100 = [ ( 500 * 10 ^ 6 ) / ( 10 * 10 ^ 9 ) ] * 100 = ( 50 / 1000 ) * 100 = 5 % so answer is ( c )"
|
general
|
math_qa__ynFjYUvmJvLGU37l
|
If 0.75 : x :: 3 : 8, then x is equal to:
Choose the most appropriate option.
A) 2.12
B) 2.2
C) 1.25
D) 1.3
E) 2.0
|
<gadget id="calculator">0.75 * 8</gadget>
<output>6</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<result>E</result>
|
E
| 2 |
If 0.75 : x :: 3 : 8, then x is equal to:
|
{
"A": "2.12",
"B": "2.2",
"C": "1.25",
"D": "1.3",
"E": "2.0"
}
|
divide(multiply(0.75, 8), 3)
|
multiply(n0,n2)|divide(#0,n1)
|
( x * 3 ) = ( 0.75 * 8 ) x = 6 / 3 x = 2 answer = e
|
general
|
math_qa__wqJrqCuJwznJdj3J
|
A train 280 m long can cross an electric pole in 20 sec and then find the speed of the train?
Choose the correct choice from the following answers:
A) 88 kmph B) 89 kmph C) 72 kmph D) 50 kmph E) 18 kmph
|
<gadget id="calculator">280 / 1_000</gadget>
<output>7/25 = around 0.28</output>
<gadget id="calculator">20 / 3_600</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">(7/25) / (1/180)</gadget>
<output>252/5 = around 50.4</output>
<result>D</result>
|
D
| 50 |
A train 280 m long can cross an electric pole in 20 sec and then find the speed of the train?
|
{
"A": "88 kmph",
"B": "89 kmph",
"C": "72 kmph",
"D": "50 kmph",
"E": "18 kmph"
}
|
divide(divide(280, const_1000), divide(20, const_3600))
|
divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)|
|
"length = speed * time speed = l / t s = 280 / 20 s = 14 m / sec speed = 14 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 50 kmph answer : d"
|
physics
|
math_qa__M02pfUohclZ4jM68
|
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.83200? Choose the most appropriate option: A) 81000 B) 81028 C) 105300 D) 29889 E) 22312
|
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 83_200</gadget>
<output>10_400</output>
<gadget id="calculator">83_200 + 10_400</gadget>
<output>93_600</output>
<gadget id="calculator">(1/8) * 93_600</gadget>
<output>11_700</output>
<gadget id="calculator">93_600 + 11_700</gadget>
<output>105_300</output>
<result>C</result>
|
C
| 105,300 |
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.83200?
|
{
"A": "81000",
"B": "81028",
"C": "105300",
"D": "29889",
"E": "22312"
}
|
add(add(83200, multiply(divide(1, 8), 83200)), multiply(divide(1, 8), add(83200, multiply(divide(1, 8), 83200))))
|
divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3)|
|
83200 * 9 / 8 * 9 / 8 = 105300 . answer : c
|
general
|
math_qa__ExdUsRjjpBK1ZacW
|
The length of a side of a hexagon is 2 inches. What is the perimeter? Answers.
A) 11 B) 12 C) 13 D) 14 E) 15
|
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<result>B</result>
|
B
| 12 |
The length of a side of a hexagon is 2 inches. What is the perimeter?
|
{
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
}
|
multiply(2, multiply(const_3, const_2))
|
multiply(const_2,const_3)|multiply(n0,#0)|
|
"hexagon . it means 6 equal sides . p = 2 + 2 + 2 + 2 + 2 + 2 = 4 + 4 + 4 = 8 + 4 = 12 inches answer b"
|
physics
|
math_qa__wTU36TxgxegdL0Y8
|
How many 3 digit even numbers do not use any digit more than once Pick one
A) 280
B) 216
C) 2240
D) 246
E) 2520
|
<gadget id="calculator">1_000 - 10</gadget>
<output>990</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">10 * 9</gadget>
<output>90</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">90 * 8</gadget>
<output>720</output>
<gadget id="calculator">990 - 720</gadget>
<output>270</output>
<gadget id="calculator">270 + 10</gadget>
<output>280</output>
<result>A</result>
|
A
| 280 |
How many 3 digit even numbers do not use any digit more than once
|
{
"A": "280",
"B": "216",
"C": "2240",
"D": "246",
"E": "2520"
}
|
add(subtract(subtract(const_1000, const_10), multiply(multiply(const_10, multiply(3, 3)), multiply(const_4, const_2))), const_10)
|
multiply(n0,n0)|multiply(const_2,const_4)|subtract(const_1000,const_10)|multiply(#0,const_10)|multiply(#3,#1)|subtract(#2,#4)|add(#5,const_10)
|
the way i solved it is a b c ( hundreds , tens , units ) c can be 0 2 4 6 8 ( any of the 5 digits ) a can be anything except ( d or 0 ) so 8 possibilities b can be anything execpt ( a d c ) so 7 possibilities total ways are 7 * 8 * 5 = 280 ans : a
|
general
|
math_qa__sVIP2FJgU6ch9Z0m
|
A money lender lent Rs. 1000 at 3% per year and Rs. 1200 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years. Pick one
A) 3.5 B) 3.75 C) 3.88 D) 4.25 E) 4.5
|
<gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">1_200 * 5</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 100</gadget>
<output>60</output>
<gadget id="calculator">30 + 60</gadget>
<output>90</output>
<gadget id="calculator">350 / 90</gadget>
<output>35/9 = around 3.888889</output>
<result>C</result>
|
C
| 3.88 |
A money lender lent Rs. 1000 at 3% per year and Rs. 1200 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years.
|
{
"A": "3.5",
"B": "3.75",
"C": "3.88",
"D": "4.25",
"E": "4.5"
}
|
divide(350, add(divide(multiply(3, 1000), const_100), divide(multiply(1200, 5), const_100)))
|
multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|divide(n4,#4)|
|
( 1000 xtx 3 / 100 ) + ( 1200 xtx 5 / 100 ) = 350 Γ’ β β t = 3.88 answer c
|
gain
|
math_qa__TvJTHwzWUShx4aVf
|
Mother,her daughter and her grand child weighs 130 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter? Choose the correct choice from the following choices:
A) 46
B) 47
C) 48
D) 49
E) 50
|
<gadget id="calculator">130 - 60</gadget>
<output>70</output>
<gadget id="calculator">70 / 5</gadget>
<output>14</output>
<gadget id="calculator">60 - 14</gadget>
<output>46</output>
<result>A</result>
|
A
| 46 |
Mother,her daughter and her grand child weighs 130 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter?
|
{
"A": "46",
"B": "47",
"C": "48",
"D": "49",
"E": "50"
}
|
subtract(60, divide(subtract(130, 60), 5))
|
subtract(n0,n1)|divide(#0,n3)|subtract(n1,#1)
|
mother + daughter + child = 130 kg daughter + child = 60 kg mother = 130 - 60 = 70 kg child = 1 / 5 th of mother = ( 1 / 5 ) * 70 = 14 kg so now daughter = 130 - ( mother + child ) = 130 - ( 70 + 14 ) = 46 kg answer : a
|
general
|
math_qa__fDKKBBTaL8l8r8ph
|
The length of a room is 10 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre. Choose the most appropriate option:
A) 25650
B) 25750
C) 26550
D) 42750
E) 55725
|
<gadget id="calculator">10 * 4.75</gadget>
<output>47.5</output>
<gadget id="calculator">900 * 47.5</gadget>
<output>42_750</output>
<result>D</result>
|
D
| 42,750 |
The length of a room is 10 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre.
|
{
"A": "25650",
"B": "25750",
"C": "26550",
"D": "42750",
"E": "55725"
}
|
multiply(900, multiply(10, 4.75))
|
multiply(n0,n1)|multiply(n2,#0)|
|
"area = 10 Γ 4.75 sq . metre . cost for 1 sq . metre . = rs . 900 hence total cost = 10 Γ 4.75 Γ 900 = 10 Γ 4275 = rs . 42750 answer is d ."
|
physics
|
math_qa__h7huP7omYc8DwoYZ
|
Two stations A and B are 200 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? Choose the correct choice from the following answers.
A) 9 B) 10 C) 11 D) 12 E) 8
|
<gadget id="calculator">200 - 20</gadget>
<output>180</output>
<gadget id="calculator">25 + 20</gadget>
<output>45</output>
<gadget id="calculator">180 / 45</gadget>
<output>4</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<result>D</result>
|
D
| 12 |
Two stations A and B are 200 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
|
{
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "8"
}
|
add(8, divide(subtract(200, 20), add(25, 20)))
|
add(n2,n4)|subtract(n0,n2)|divide(#1,#0)|add(n3,#2)|
|
"suppose they meet x hours after 7 a . m . distance covered by a in x hours = 20 x km . distance covered by b in ( x - 1 ) hours = 25 ( x - 1 ) km . therefore 20 x + 25 ( x - 1 ) = 200 45 x = 225 x = 5 . so , they meet at 12 a . m . answer : option d"
|
physics
|
math_qa__tBKovmDBp4F4vfca
|
The value of (0.625 * 0.0729 * 28.9)/(0.0017 * 0.025 * 8.1) is Select:
A) 0.3825
B) 3.825
C) 38.25
D) 382.5
E) 0.0382
|
<gadget id="calculator">0.625 * 0.0729</gadget>
<output>0.045563</output>
<gadget id="calculator">0.045563 * 28.9</gadget>
<output>1.316771</output>
<gadget id="calculator">8.1 * 0.025</gadget>
<output>0.2025</output>
<gadget id="calculator">0.2025 * 0.0017</gadget>
<output>0.000344</output>
<gadget id="calculator">1.316771 / 0.000344</gadget>
<output>3_827.822674</output>
<gadget id="calculator">3_827.822674 / 10</gadget>
<output>382.782267</output>
<result>D</result>
|
D
| 382.5 |
The value of (0.625 * 0.0729 * 28.9)/(0.0017 * 0.025 * 8.1) is
|
{
"A": "0.3825",
"B": "3.825",
"C": "38.25",
"D": "382.5",
"E": "0.0382"
}
|
divide(divide(multiply(multiply(0.625, 0.0729), 28.9), multiply(multiply(8.1, 0.025), 0.0017)), const_10)
|
multiply(n0,n1)|multiply(n4,n5)|multiply(n2,#0)|multiply(n3,#1)|divide(#2,#3)|divide(#4,const_10)
|
( 0.625 * 0.0729 * 28.9 ) / ( 0.0017 ) * 0.025 * 8.1 = { ( 625 / 1000 ) * ( 729 / 10000 ) * ( 289 / 10 ) } / { ( 17 / 10000 ) * ( 25 / 1000 ) * ( 81 / 10 ) = 382.5 answer : d
|
general
|
math_qa__kFStMOE16kneemLK
|
The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area? Choose the correct answer.
A) 10000 B) 10008 C) 10005 D) 10004 E) 10001
|
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">125 * 80</gadget>
<output>10_000</output>
<result>A</result>
|
A
| 10,000 |
The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
|
{
"A": "10000",
"B": "10008",
"C": "10005",
"D": "10004",
"E": "10001"
}
|
multiply(add(25, const_100), subtract(const_100, 20))
|
add(n0,const_100)|subtract(const_100,n1)|multiply(#0,#1)
|
100 * 100 = 10000 125 * 80 = 10000 no change answer : a
|
geometry
|
math_qa__EPWuqT5SW7q0P0uB
|
The effective annual rate of interest corresponding to a nominal rate of 10% per annum payable half-yearly is?
Select:
A) 10.06 %
B) 10.25 %
C) 10.35 %
D) 16.09 %
E) 16.19 %
|
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">10 + (1/4)</gadget>
<output>41/4 = around 10.25</output>
<result>B</result>
|
B
| 10.25 |
The effective annual rate of interest corresponding to a nominal rate of 10% per annum payable half-yearly is?
|
{
"A": "10.06 %",
"B": "10.25 %",
"C": "10.35 %",
"D": "16.09 %",
"E": "16.19 %"
}
|
add(add(divide(10, const_2), divide(10, const_2)), divide(multiply(divide(10, const_2), divide(10, const_2)), const_100))
|
divide(n0,const_2)|add(#0,#0)|multiply(#0,#0)|divide(#2,const_100)|add(#1,#3)|
|
"amount of rs . 100 for 1 year when compounded half - yearly = [ 100 * ( 1 + 5 / 100 ) 2 ] = rs . 110.25 effective rate = ( 110.25 - 100 ) = 10.25 % answer : b"
|
gain
|
math_qa__Tsl1RitHjFn2p6y7
|
In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors? Choose the correct choice from the following answers: A) 2 B) 3 C) 5 D) 6 E) 8
|
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<result>B</result>
|
B
| 3 |
In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors?
|
{
"A": "2",
"B": "3",
"C": "5",
"D": "6",
"E": "8"
}
|
add(divide(add(const_1, const_4), divide(divide(divide(60, const_2), const_2), const_3)), const_2)
|
add(const_1,const_4)|divide(n2,const_2)|divide(#1,const_2)|divide(#2,const_3)|divide(#0,#3)|add(#4,const_2)|
|
"14 n / 60 must be an integer . = > 7 n / 30 must be an integer . hence n must be a multiple of 2 * 3 * 5 . = > n has 3 different prime integers and can not have more than 3 different prime integers because 2 * 3 * 5 * 7 = 210 > 200 answer : b"
|
general
|
math_qa__NQgTjPj5Ymeayg2q
|
How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 290 m in length? Select.
A) 18.9 sec
B) 88.9 sec
C) 22.9 sec
D) 24.00 sec
E) 72.0 sec
|
<gadget id="calculator">110 + 290</gadget>
<output>400</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">400 / (50/3)</gadget>
<output>24</output>
<result>D</result>
|
D
| 24 |
How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 290 m in length?
|
{
"A": "18.9 sec",
"B": "88.9 sec",
"C": "22.9 sec",
"D": "24.00 sec",
"E": "72.0 sec"
}
|
divide(add(110, 290), multiply(60, const_0_2778))
|
add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)|
|
"d = 110 + 290 = 400 m s = 60 * 5 / 18 = 50 / 3 t = 400 * 3 / 50 = 24.00 sec answer : d"
|
physics
|
math_qa__YfX9AG4VUroDLL7q
|
The total number of plums that grow during each year on a certain plum tree is equal to the number of plums that grew during the previous year, less the age of the tree in years (rounded down to the nearest integer). During its 8th year, the plum tree grew 50 plums. If this trend continues, how many plums will it grow during its 6th year? Choose the correct choice from the following answers: A) 45 B) 40 C) 35 D) 30 E) 25
|
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">50 + 7</gadget>
<output>57</output>
<gadget id="calculator">6 + 57</gadget>
<output>63</output>
<gadget id="calculator">63 / 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 3</gadget>
<output>24</output>
<result>E</result>
|
E
| 25 |
The total number of plums that grow during each year on a certain plum tree is equal to the number of plums that grew during the previous year, less the age of the tree in years (rounded down to the nearest integer). During its 8th year, the plum tree grew 50 plums. If this trend continues, how many plums will it grow during its 6th year?
|
{
"A": "45",
"B": "40",
"C": "35",
"D": "30",
"E": "25"
}
|
add(divide(add(subtract(subtract(8, const_1), const_1), add(50, subtract(8, const_1))), const_3), const_3)
|
subtract(n0,const_1)|add(n1,#0)|subtract(#0,const_1)|add(#1,#2)|divide(#3,const_3)|add(#4,const_3)
|
1 st year : 0 - 1 ( age ) , we take age = 0 ( as the question says that we have to ( rounded down to the nearest integer ) ) 2 ndyear : 1 - 2 ( age ) , we take age = 1 3 rd year : 2 - 3 ( age ) , we take age = 2 4 th year : 3 - 4 ( age ) , we take age = 3 5 th year : 4 - 5 ( age ) , we take age = 4 6 th year : 5 - 6 ( age ) , we take age = 5 7 th year : 6 - 7 ( age ) , we take age = 6 8 th year : 7 - 8 ( age ) , we take age = 7 thus for the 3 rd year = 50 , 4 th year = 50 - 3 = 47 5 th year = 47 - 4 = 43 6 th year = 43 - 5 = 38 . 7 th year = 38 - 6 = 32 8 th year = 32 - 7 = 25 the correct answer is e .
|
general
|
math_qa__FIZf4i6L3t8qSj72
|
A man covers a distance of 180 Km at 72 Kmph and next 190km at 88 Kmph. what is his average speed For his whole journey of 370 Km? Choose the correct choice from the following choices:
A) 77 kmph B) 77.15 kmph C) 77.25 kmph D) 79 kmph E) 80 kmph
|
<gadget id="calculator">180 / 72</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">190 / 88</gadget>
<output>95/44 = around 2.159091</output>
<gadget id="calculator">(5/2) + (95/44)</gadget>
<output>205/44 = around 4.659091</output>
<gadget id="calculator">370 / (205/44)</gadget>
<output>3_256/41 = around 79.414634</output>
<result>C</result>
|
C
| 77.25 |
A man covers a distance of 180 Km at 72 Kmph and next 190km at 88 Kmph. what is his average speed For his whole journey of 370 Km?
|
{
"A": "77 kmph",
"B": "77.15 kmph",
"C": "77.25 kmph",
"D": "79 kmph",
"E": "80 kmph"
}
|
divide(370, add(divide(180, 72), divide(190, 88)))
|
divide(n0,n1)|divide(n2,n3)|add(#0,#1)|divide(n4,#2)
|
formula = 2 * f . s * s . p / f . s + s . p = 2 * 72 * 88 / 88 + 72 = 79.2 kmph option ' c '
|
physics
|
math_qa__scakZxbaF471b56B
|
in a zoo , the ratio of the number of cheetahs to the number of pandas is 1 : 3 and was the same 5 years ago . if the increase in the number of cheetahs in the zoo since then is 2 , then what is the increase in the number of pandas ? Options.
A) 2 B) 3 C) 5 D) 6 E) 15
|
<gadget id="calculator">lcm(1, 3)</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<result>D</result>
|
D
| 6 |
in a zoo , the ratio of the number of cheetahs to the number of pandas is 1 : 3 and was the same 5 years ago . if the increase in the number of cheetahs in the zoo since then is 2 , then what is the increase in the number of pandas ?
|
{
"A": "2",
"B": "3",
"C": "5",
"D": "6",
"E": "15"
}
|
multiply(lcm(1, 3), 2)
|
lcm(n0,n1)|multiply(n3,#0)
|
one short cut to solve the problem is c : p = 1 : 3 c increased to 3 = > 1 : 3 = 3 : x = > x = 9 = > p increased by 6 d is the answer
|
other
|
math_qa__cpWyyPjAZ4aC0T9H
|
Ramesh purchased a refrigerator for Rs. 16500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
Choose the correct choice from the following choices
A) 34778 B) 26888 C) 22899 D) 23100 E) 32778
|
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">16_500 * 100</gadget>
<output>1_650_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">1_650_000 / 80</gadget>
<output>20_625</output>
<gadget id="calculator">125 + 250</gadget>
<output>375</output>
<gadget id="calculator">20_625 + 375</gadget>
<output>21_000</output>
<gadget id="calculator">110 * 21_000</gadget>
<output>2_310_000</output>
<gadget id="calculator">2_310_000 / 100</gadget>
<output>23_100</output>
<result>D</result>
|
D
| 23,100 |
Ramesh purchased a refrigerator for Rs. 16500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
|
{
"A": "34778",
"B": "26888",
"C": "22899",
"D": "23100",
"E": "32778"
}
|
divide(multiply(add(const_100, 10), add(divide(multiply(16500, const_100), subtract(const_100, 20)), add(125, 250))), const_100)
|
add(n4,const_100)|add(n2,n3)|multiply(n0,const_100)|subtract(const_100,n1)|divide(#2,#3)|add(#1,#4)|multiply(#0,#5)|divide(#6,const_100)|
|
"price at which the tv set is bought = rs . 16,500 discount offered = 20 % marked price = 16500 * 100 / 80 = rs . 20625 the total amount spent on transport and installation = 125 + 250 = rs . 375 \ total price of tv set = 20625 + 375 = rs . 21000 the price at which the tv should be sold to get a profit of 10 % if no discount was offered = 21000 * 110 / 100 = rs . 23100 answer : d"
|
gain
|
math_qa__qTAYmio0nw2AktR5
|
John bought a total of 16 Mangoes and Oranges. Each Mango costs 80 cents and each orange costs 60 cents. If the average price of the 16 mangoes and oranges that John originally purchased was 65 cents, then how many oranges needs to return to raise the average price of his purchase to 72 cents?
Choose the correct choice from the following answers: A) 4 B) 5 C) 6 D) 7 E) 10
|
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) * 16</gadget>
<output>52/5 = around 10.4</output>
<result>E</result>
|
E
| 10 |
John bought a total of 16 Mangoes and Oranges. Each Mango costs 80 cents and each orange costs 60 cents. If the average price of the 16 mangoes and oranges that John originally purchased was 65 cents, then how many oranges needs to return to raise the average price of his purchase to 72 cents?
|
{
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "10"
}
|
multiply(divide(65, const_100), 16)
|
divide(n4,const_100)|multiply(n0,#0)
|
let number of mangoes be x , number of oranges be 16 - x 0.80 x + ( 16 - x ) 0.60 / 16 = 0.65 solving for x , we get x = 4 - - > mangoes 4 , oranges 12 now , number of oranges to be returned be y 0.80 * 4 + ( 12 - y ) * 0.60 / 16 - y = 0.72 solving for y , y = 10 ans : e
|
general
|
math_qa__7t7PERyXFtuvjIPG
|
45 workers work 8 hours to dig a hole 30 meters deep. How many extra workers should be hired to dig another hole 30 meters deep by working for 6 hours? Choose the correct answer
A) 10
B) 15
C) 20
D) 25
E) 30
|
<gadget id="calculator">8 / 6</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">45 * (4/3)</gadget>
<output>60</output>
<gadget id="calculator">30 / 30</gadget>
<output>1</output>
<gadget id="calculator">60 * 1</gadget>
<output>60</output>
<gadget id="calculator">60 - 45</gadget>
<output>15</output>
<result>B</result>
|
B
| 15 |
45 workers work 8 hours to dig a hole 30 meters deep. How many extra workers should be hired to dig another hole 30 meters deep by working for 6 hours?
|
{
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
}
|
subtract(multiply(multiply(45, divide(8, 6)), divide(30, 30)), 45)
|
divide(n3,n2)|divide(n1,n4)|multiply(n0,#1)|multiply(#0,#2)|subtract(#3,n0)|
|
"45 workers * 8 hours / 30 meters = x * 6 / 30 x = 60 total workers 60 - 45 = 15 new workers the answer is b ."
|
physics
|
math_qa__T8IeqAfjQI9cWNrx
|
If the product of 4 integers is negative, at most how many of the integers can be negative? Select the correct option
A) 2 B) 3 C) 4 D) 5 E) 6
|
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<result>B</result>
|
B
| 3 |
If the product of 4 integers is negative, at most how many of the integers can be negative?
|
{
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
}
|
subtract(4, const_1)
|
subtract(n0,const_1)
|
the product of 4 integers is negative thus an odd number of integers need to be negative to have a negative product we are asked at most how many are required . so , the highest odd integer before 6 , i . e . 3 correct option : b
|
general
|
math_qa__UWPeTrp48Uhx6bWR
|
If 12 men can reap 120 acres of land in 36 days, how many acres of land can 44 men reap in 54 days? Choose the correct choice from the following answers
A) 820 acres B) 660 acres C) 620 acres D) 720 acres E) 920 acres
|
<gadget id="calculator">44 / 12</gadget>
<output>11/3 = around 3.666667</output>
<gadget id="calculator">54 / 36</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(11/3) * (3/2)</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">120 * (11/2)</gadget>
<output>660</output>
<result>B</result>
|
B
| 660 |
If 12 men can reap 120 acres of land in 36 days, how many acres of land can 44 men reap in 54 days?
|
{
"A": "820 acres",
"B": "660 acres",
"C": "620 acres",
"D": "720 acres",
"E": "920 acres"
}
|
multiply(120, multiply(divide(44, 12), divide(54, 36)))
|
divide(n3,n0)|divide(n4,n2)|multiply(#0,#1)|multiply(n1,#2)|
|
"12 men 120 acres 36 days 44 men ? 54 days 120 * 44 / 12 * 54 / 36 10 * 44 * 3 / 2 44 * 15 = 660 answer : b"
|
physics
|
math_qa__xH0vPGOphOti1ctA
|
The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 3 years ?
Choose the correct choice from the following choices.
A) 3277 B) 2977 C) 16875 D) 6077 E) 17112
|
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 10_000</gadget>
<output>40_000</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 3</gadget>
<output>27/64 = around 0.421875</output>
<gadget id="calculator">40_000 * (27/64)</gadget>
<output>16_875</output>
<result>C</result>
|
C
| 16,875 |
The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 3 years ?
|
{
"A": "3277",
"B": "2977",
"C": "16875",
"D": "6077",
"E": "17112"
}
|
multiply(multiply(4, multiply(const_100, const_100)), power(divide(3, 4), 3))
|
divide(n0,n1)|multiply(const_100,const_100)|multiply(n1,#1)|power(#0,n3)|multiply(#2,#3)|
|
"explanation : 40,000 ( 34 ) 3 = 1687540,000 ( 34 ) 3 = 16875 answer : c"
|
general
|
math_qa__DSeHcnAsxiRBKvTp
|
The wages earned by Robin is 50% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin? Choose the correct option:
A) 18.75 %
B) 23 %
C) 30 %
D) 50 %
E) 7 %
|
<gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">160 - 150</gadget>
<output>10</output>
<gadget id="calculator">10 / 150</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) * 100</gadget>
<output>20/3 = around 6.666667</output>
<result>E</result>
|
E
| 7 |
The wages earned by Robin is 50% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin?
|
{
"A": "18.75 %",
"B": "23 %",
"C": "30 %",
"D": "50 %",
"E": "7 %"
}
|
multiply(divide(subtract(add(const_100, 60), add(const_100, 50)), add(const_100, 50)), const_100)
|
add(n1,const_100)|add(n0,const_100)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100)|
|
"let wage of erica = 10 wage of robin = 1.5 * 10 = 15 wage of charles = 1.6 * 10 = 16 percentage by which wage earned by charles is more than that earned by robin = ( 16 - 15 ) / 15 * 100 % = 1 / 15 * 100 % = 7 % answer e"
|
general
|
math_qa__7PKOc7h4CWhtcZJf
|
A 20 litre mixture of milk and water contains milk and water in the ratio 3 : 2. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removal and replacement, what is the ratio R of milk and water in the resultant mixture? Choices:
A) 17 : 3 B) 9 : 1 C) 3 : 17 D) 5 : 3 E) 11 : 2
|
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">(3/5) * 10</gadget>
<output>6</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">16 / 20</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 10</gadget>
<output>8</output>
<gadget id="calculator">8 + 10</gadget>
<output>18</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 10</gadget>
<output>4</output>
<gadget id="calculator">4 / 20</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 10</gadget>
<output>2</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<result>B</result>
|
B
| 9 |
A 20 litre mixture of milk and water contains milk and water in the ratio 3 : 2. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removal and replacement, what is the ratio R of milk and water in the resultant mixture?
|
{
"A": "17 : 3",
"B": "9 : 1",
"C": "3 : 17",
"D": "5 : 3",
"E": "11 : 2"
}
|
divide(add(multiply(divide(add(multiply(divide(3, add(3, 2)), subtract(20, 10)), 10), 20), subtract(20, 10)), 10), multiply(divide(multiply(divide(2, add(3, 2)), subtract(20, 10)), 20), subtract(20, 10)))
|
add(n1,n2)|subtract(n0,n3)|divide(n1,#0)|divide(n2,#0)|multiply(#2,#1)|multiply(#3,#1)|add(n3,#4)|divide(#5,n0)|divide(#6,n0)|multiply(#7,#1)|multiply(#8,#1)|add(n3,#10)|divide(#11,#9)|
|
"he 20 litre mixture contains milk and water in the ratio of 3 : 2 . therefore , there will be 12 litres of milk in the mixture and 8 litres of water in the mixture . step 1 . when 10 litres of the mixture is removed , 6 litres of milk is removed and 4 litres of water is removed . therefore , there will be 6 litres of milk and 4 litres of water left in the container . it is then replaced with pure milk of 10 litres . now the container will have 16 litres of milk and 4 litres of water . step 2 . when 10 litres of the new mixture is removed , 8 litres of milk and 2 litres of water is removed . the container will have 8 litres of milk and 2 litres of water in it . now 10 litres of pure milk is added . therefore , the container will have 18 litres of milk and 2 litres of water in it at the end of the second step . therefore , the ratio of milk and water is 18 : 2 or 9 : 1 . shortcut . we are essentially replacing water in the mixture with pure milk . let w _ o be the amount of water in the mixture originally = 8 litres . let w _ r be the amount of water in the mixture after the replacements have taken place . then , { w _ r } / { w _ o } = ( 1 - r / m ) ^ n where r is the amount of the mixture replaced by milk in each of the steps , m is the total volume of the mixture and n is the number of times the cycle is repeated . hence , { w _ r } / { w _ o } Β = ( 1 / 2 ) ^ 2 Β = 1 / 4 therefore r , w _ r Β = { w _ o } / 4 = 8 / 4 Β = 2 litres . b"
|
general
|
math_qa__u1SB6zsY3gl8zdfZ
|
Reb normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Reb averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives? Choose one: A) 135 B) 105 C) 95 D) 75 E) 45
|
<gadget id="calculator">45 / 60</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">40 * (3/4)</gadget>
<output>30</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">30 * (4/5)</gadget>
<output>24</output>
<gadget id="calculator">24 / 12</gadget>
<output>2</output>
<gadget id="calculator">2 * 60</gadget>
<output>120</output>
<gadget id="calculator">120 - 45</gadget>
<output>75</output>
<result>D</result>
|
D
| 75 |
Reb normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Reb averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives?
|
{
"A": "135",
"B": "105",
"C": "95",
"D": "75",
"E": "45"
}
|
subtract(multiply(divide(multiply(multiply(40, divide(45, const_60)), divide(subtract(const_100, 20), const_100)), 12), const_60), 45)
|
divide(n0,const_60)|subtract(const_100,n2)|divide(#1,const_100)|multiply(n1,#0)|multiply(#2,#3)|divide(#4,n3)|multiply(#5,const_60)|subtract(#6,n0)
|
reb normally drives to work in 45 minutes at an average speed of 40 miles per hour . use formula d = rt car : t 1 : 45 min r 1 : 40 mph d 1 : [ ( 40 * 45 ) / 60 ] = 30 miles bike : t 1 : ? r 2 : 12 - 16 mph d 2 : 08 * d 1 = 24 miles t 1 : [ ( 24 * 60 ) / 12 ] = 120 min ( only 12 mph speed yields an answer given in the choices ) therefore , deb has to leave 120 min - 45 min = 75 min early answer : d
|
physics
|
math_qa__EmWNsAtIkVlaOc8E
|
A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 80 percent of books that were loaned out are returned and there are 65 books in the special collection at that time, how many books of the special collection were loaned out during that month? Select.
A) 20 B) 30 C) 35 D) 40 E) 50
|
<gadget id="calculator">75 - 65</gadget>
<output>10</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / (1/5)</gadget>
<output>50</output>
<result>E</result>
|
E
| 50 |
A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 80 percent of books that were loaned out are returned and there are 65 books in the special collection at that time, how many books of the special collection were loaned out during that month?
|
{
"A": "20",
"B": "30",
"C": "35",
"D": "40",
"E": "50"
}
|
divide(subtract(75, 65), subtract(const_1, divide(80, const_100)))
|
divide(n1,const_100)|subtract(n0,n2)|subtract(const_1,#0)|divide(#1,#2)|
|
"there are 10 books less ( 75 - 65 ) which represents 20 % of the loaned books ( 100 - 80 ) so total loaned out books = 50 answer e"
|
gain
|
math_qa__CWXcVkJvy5bnQhH2
|
While driving from A-ville to B-town, Harriet drove at a constant speed of 95 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 155 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town? Choose the correct choice from the following choices:
A) 138
B) 148
C) 150
D) 162
E) 186
|
<gadget id="calculator">95 * 5</gadget>
<output>475</output>
<gadget id="calculator">95 + 155</gadget>
<output>250</output>
<gadget id="calculator">475 / 250</gadget>
<output>19/10 = around 1.9</output>
<gadget id="calculator">5 - (19/10)</gadget>
<output>31/10 = around 3.1</output>
<gadget id="calculator">(31/10) * 60</gadget>
<output>186</output>
<result>E</result>
|
E
| 186 |
While driving from A-ville to B-town, Harriet drove at a constant speed of 95 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 155 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town?
|
{
"A": "138",
"B": "148",
"C": "150",
"D": "162",
"E": "186"
}
|
multiply(subtract(5, divide(multiply(95, 5), add(95, 155))), const_60)
|
add(n0,n1)|multiply(n0,n2)|divide(#1,#0)|subtract(n2,#2)|multiply(#3,const_60)|
|
"5 hr = 300 min . if harriet spend equal hrs on each leg she will spend 150 min on each . since speed a - b is less than speed b - a and distance on each leg is the same , time spent on a - b is more than 150 min , which mean we can eliminate ans . a , b and c . now let plug in ans . d or e and verify which one give same distance on each leg . e . t = 186 min * leg a - b - - - > d = 95.186 / 60 = 17670 / 60 * leg b - a - - - - > d = 155 * 114 / 60 = 17670 / 60 so the correct ans . ise"
|
physics
|
math_qa__bbLONAw8Nmc6Zbo3
|
The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8091 for a computer table, then what was the cost price of the computer table? Pick.
A) 7297 B) 2977 C) 2871 D) 6725 E) 6525
|
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1 + (6/25)</gadget>
<output>31/25 = around 1.24</output>
<gadget id="calculator">8_091 / (31/25)</gadget>
<output>6_525</output>
<result>E</result>
|
E
| 6,525 |
The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8091 for a computer table, then what was the cost price of the computer table?
|
{
"A": "7297",
"B": "2977",
"C": "2871",
"D": "6725",
"E": "6525"
}
|
divide(8091, add(const_1, divide(24, const_100)))
|
divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)|
|
"explanation : cp = sp * ( 100 / ( 100 + profit % ) ) = 8091 ( 100 / 124 ) = rs . 6525 . answer : e"
|
gain
|
math_qa__W84b3FjQgIf5hBfg
|
What is the smallest number which when diminished by 10, is divisible 2, 6, 12 and 24? Choose the correct choice from the following choices: A) 35 B) 34 C) 20 D) 35 E) 342
|
<gadget id="calculator">lcm(2, 6)</gadget>
<output>6</output>
<gadget id="calculator">lcm(12, 24)</gadget>
<output>24</output>
<gadget id="calculator">lcm(6, 24)</gadget>
<output>24</output>
<gadget id="calculator">24 + 10</gadget>
<output>34</output>
<result>B</result>
|
B
| 34 |
What is the smallest number which when diminished by 10, is divisible 2, 6, 12 and 24?
|
{
"A": "35",
"B": "34",
"C": "20",
"D": "35",
"E": "342"
}
|
add(lcm(lcm(2, 6), lcm(12, 24)), 10)
|
lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)|
|
"required number = ( lcm of 2 , 6 , 12 and 24 ) + 12 = 24 + 10 = 34 option b"
|
general
|
math_qa__kozerfjhzxvMqiWt
|
The cash realised on selling a 14% stock is Rs.108.25, brokerage being 1/4% is? Choose the correct answer: A) 366 B) 106 C) 108 D) 192 E) 122
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">108.25 - (1/4)</gadget>
<output>108</output>
<result>C</result>
|
C
| 108 |
The cash realised on selling a 14% stock is Rs.108.25, brokerage being 1/4% is?
|
{
"A": "366",
"B": "106",
"C": "108",
"D": "192",
"E": "122"
}
|
subtract(108.25, divide(1, 4))
|
divide(n2,n3)|subtract(n1,#0)|
|
"cash realised = rs . ( 108.25 - 0.25 ) = rs . 108 . answer : c"
|
general
|
math_qa__MpznmYtiK1IaR9Rv
|
3 boys are ages 4 , 6 and 7 respectively . 3 girls are ages 5 , 8 and 9 , respectively . if two of the boys and two of the girls are randomly selected and the sum of the selected children ' s ages is w , what is the difference between the probability that w is even and the probability that w is odd ? Choose the correct choice from the following
A) 1 / 9
B) 1 / 6
C) 2 / 9
D) 1 / 4
E) 1 / 2
|
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * (1/3)</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * (2/3)</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(1/9) + (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">(1/3) * (2/3)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(2/9) + (2/9)</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(5/9) - (4/9)</gadget>
<output>1/9 = around 0.111111</output>
<result>A</result>
|
A
| 0.111111 |
3 boys are ages 4 , 6 and 7 respectively . 3 girls are ages 5 , 8 and 9 , respectively . if two of the boys and two of the girls are randomly selected and the sum of the selected children ' s ages is w , what is the difference between the probability that w is even and the probability that w is odd ?
|
{
"A": "1 / 9",
"B": "1 / 6",
"C": "2 / 9",
"D": "1 / 4",
"E": "1 / 2"
}
|
subtract(add(multiply(divide(const_1, 3), divide(const_1, 3)), multiply(divide(const_2, 3), divide(const_2, 3))), add(multiply(divide(const_1, 3), divide(const_2, 3)), multiply(divide(const_1, 3), divide(const_2, 3))))
|
divide(const_1,n0)|divide(const_2,n0)|multiply(#0,#0)|multiply(#1,#1)|multiply(#0,#1)|add(#2,#3)|add(#4,#4)|subtract(#5,#6)
|
age of boys w : 4 , 6 , 7 sum of ages taken 2 at a time : 10 , 1311 ages of girls : 5 , 8 , 9 sum of ages taken 2 at a time : 13 , 1714 9 combinations of sum between sets ( 10 , 1211 ) ( 13 , 1714 ) = 23 , 2724 - 16 , 3017 - 24 , 2825 prob ( even ) = 5 / 9 prob ( odd ) = 4 / 9 answer = 5 / 9 - 4 / 9 = 1 / 9
|
general
|
math_qa__96brZOtGpxbFnp8k
|
8 x 2.25- 5 x 0.85/2.5= ? Choose the correct answer:
A) 3.8 B) 10 C) 5 D) 5.5 E) 7.5
|
<gadget id="calculator">8 * 2.25</gadget>
<output>18</output>
<gadget id="calculator">5 * 0.85</gadget>
<output>4.25</output>
<gadget id="calculator">18 - 4.25</gadget>
<output>13.75</output>
<gadget id="calculator">13.75 / 2.5</gadget>
<output>5.5</output>
<result>D</result>
|
D
| 5.5 |
8 x 2.25- 5 x 0.85/2.5= ?
|
{
"A": "3.8",
"B": "10",
"C": "5",
"D": "5.5",
"E": "7.5"
}
|
divide(subtract(multiply(8, 2.25), multiply(5, 0.85)), 2.5)
|
multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4)|
|
"given expression = ( 18 - 4.25 / 2.5 = 13.75 / 2.5 = 137.5 / 25 = 5.5 answer is d ."
|
general
|
math_qa__PEtAHsrFPMo4CoM1
|
A is a working partner and B is a sleeping partner in the business. A puts in Rs.20000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is? Choose the most appropriate option: A) 1978 B) 2707 C) 7728 D) 4800 E) 7291
|
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">9_600 * (9/10)</gadget>
<output>8_640</output>
<gadget id="calculator">20_000 + 25_000</gadget>
<output>45_000</output>
<gadget id="calculator">25_000 / 45_000</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">8_640 * (5/9)</gadget>
<output>4_800</output>
<gadget id="calculator">9_600 - 4_800</gadget>
<output>4_800</output>
<result>D</result>
|
D
| 4,800 |
A is a working partner and B is a sleeping partner in the business. A puts in Rs.20000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
|
{
"A": "1978",
"B": "2707",
"C": "7728",
"D": "4800",
"E": "7291"
}
|
subtract(9600, multiply(multiply(9600, subtract(const_1, divide(10, const_100))), divide(25000, add(20000, 25000))))
|
add(n0,n1)|divide(n2,const_100)|divide(n1,#0)|subtract(const_1,#1)|multiply(n3,#3)|multiply(#2,#4)|subtract(n3,#5)
|
20 : 25 = > 4 : 5 9600 * 10 / 100 = 960 9600 - 960 = 8640 8640 * 4 / 9 = 3840 + 960 = 4800 answer : d
|
gain
|
math_qa__KuEbnANf2kWnk4U4
|
If Leo gains 10 pounds, he will weigh 50% more than his sister Kendra. Currently their combined weight is 170 pounds. What is Leo's current weight? Choose the correct option.
A) 80 B) 86 C) 92 D) 98 E) 104
|
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">170 * (3/2)</gadget>
<output>255</output>
<gadget id="calculator">255 - 10</gadget>
<output>245</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">245 / (5/2)</gadget>
<output>98</output>
<result>D</result>
|
D
| 98 |
If Leo gains 10 pounds, he will weigh 50% more than his sister Kendra. Currently their combined weight is 170 pounds. What is Leo's current weight?
|
{
"A": "80",
"B": "86",
"C": "92",
"D": "98",
"E": "104"
}
|
divide(subtract(multiply(170, divide(add(const_100, 50), const_100)), 10), add(divide(add(const_100, 50), const_100), const_1))
|
add(n1,const_100)|divide(#0,const_100)|add(#1,const_1)|multiply(n2,#1)|subtract(#3,n0)|divide(#4,#2)|
|
"l + k = 170 and so k = 170 - l l + 10 = 1.5 k = 1.5 ( 170 - l ) 2.5 l = 245 l = 98 the answer is d ."
|
gain
|
math_qa__YHqTqKHOGBdbk1GB
|
12*18*6 is the volume of some material. How many cubes of edge 3 can be insert into it? Choose the correct choice from the following: A) 48 B) 49 C) 50 D) 51 E) 52
|
<gadget id="calculator">12 * 18 * 6</gadget>
<output>1_296</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">1_296 / 27</gadget>
<output>48</output>
<result>A</result>
|
A
| 48 |
12*18*6 is the volume of some material. How many cubes of edge 3 can be insert into it?
|
{
"A": "48",
"B": "49",
"C": "50",
"D": "51",
"E": "52"
}
|
divide(volume_rectangular_prism(12, 18, 6), volume_cube(3))
|
volume_cube(n3)|volume_rectangular_prism(n0,n1,n2)|divide(#1,#0)
|
no . of such cubes = volume of material / volume of one cube ( 12 * 18 * 6 ) / ( 3 * 3 * 3 ) = 48 answer : a
|
geometry
|
math_qa__yJ95RTwiABm9z15Y
|
John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.63 more than Jane, what was the original price of the dish?
Select the correct option.
A) 24 B) 34.8 C) 37.8 D) 42 E) 84
|
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * (3/20)</gadget>
<output>27/200 = around 0.135</output>
<gadget id="calculator">(3/20) - (27/200)</gadget>
<output>3/200 = around 0.015</output>
<gadget id="calculator">0.63 / (3/200)</gadget>
<output>42</output>
<result>D</result>
|
D
| 42 |
John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.63 more than Jane, what was the original price of the dish?
|
{
"A": "24",
"B": "34.8",
"C": "37.8",
"D": "42",
"E": "84"
}
|
divide(0.63, subtract(divide(15, const_100), multiply(subtract(const_1, divide(10, const_100)), divide(15, const_100))))
|
divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#1)|multiply(#0,#2)|subtract(#0,#3)|divide(n2,#4)|
|
"the difference between the amounts john paid and jane paid is the deference between 15 % of p and 15 % of 0.9 p : 0.15 p - 0.15 * 0.9 p = 0.63 - - > 15 p - 13.5 p = 63 - - > p = 42 . answer : d ."
|
gain
|
math_qa__uvfFmE2ZD0mtzNtQ
|
At what rate percent per annum will sum of money double in 20 years? Options: A) 1.2 % B) 2 % C) 4 % D) 5 % E) none of these
|
<gadget id="calculator">100 / 20</gadget>
<output>5</output>
<result>D</result>
|
D
| 5 |
At what rate percent per annum will sum of money double in 20 years?
|
{
"A": "1.2 %",
"B": "2 %",
"C": "4 %",
"D": "5 %",
"E": "none of these"
}
|
divide(const_100, 20)
|
divide(const_100,n0)|
|
"explanation : hint : if sum of money becomes ( z times ) in ( t ) years at simple interest , then rate of interest ( r ) can be calculated using the formula : rate of interest ( r ) % = 100 ( z β 1 ) / t here , principal amount is not given . hence , we can directly use the trick to calculate the rate of interest . rate of interest ( r ) % = 100 ( 2 β 1 ) / 20 rate of interest ( r ) % = 5 % p . a . answer is d"
|
gain
|
math_qa__kYKpM6zZr6WyoTmU
|
I bought two books; for Rs.490. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? Choose the correct choice from the following answers:
A) 337.83
B) 285.83
C) 284.83
D) 266.83
E) 299.83
|
<gadget id="calculator">100 + 19</gadget>
<output>119</output>
<gadget id="calculator">490 * 119</gadget>
<output>58_310</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 + 119</gadget>
<output>204</output>
<gadget id="calculator">58_310 / 204</gadget>
<output>1_715/6 = around 285.833333</output>
<result>B</result>
|
B
| 285.83 |
I bought two books; for Rs.490. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
|
{
"A": "337.83",
"B": "285.83",
"C": "284.83",
"D": "266.83",
"E": "299.83"
}
|
divide(multiply(490, add(const_100, 19)), add(subtract(const_100, 15), add(const_100, 19)))
|
add(n2,const_100)|subtract(const_100,n1)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)|
|
"x * ( 85 / 100 ) = ( 490 - x ) 119 / 100 x = 285.83 answer : b"
|
gain
|
math_qa__kYkNkO25PsKo4NTy
|
If 13 men do a work in 80 days, in how many days will 20 men do it?
Choices:
A) 18 days
B) 38 days
C) 42 days
D) 48 days
E) 52 days
|
<gadget id="calculator">13 * 80</gadget>
<output>1_040</output>
<gadget id="calculator">1_040 / 20</gadget>
<output>52</output>
<result>E</result>
|
E
| 52 |
If 13 men do a work in 80 days, in how many days will 20 men do it?
|
{
"A": "18 days",
"B": "38 days",
"C": "42 days",
"D": "48 days",
"E": "52 days"
}
|
divide(multiply(13, 80), 20)
|
multiply(n0,n1)|divide(#0,n2)|
|
"13 * 80 = 20 * x x = 52 days answer : e"
|
physics
|
math_qa__ezB8blF8bWzQdHrl
|
9773 + x = 13200, then x is ? Select:
A) 3427
B) 3237
C) 3337
D) 2337
E) none of these
|
<gadget id="calculator">13_200 - 9_773</gadget>
<output>3_427</output>
<result>A</result>
|
A
| 3,427 |
9773 + x = 13200, then x is ?
|
{
"A": "3427",
"B": "3237",
"C": "3337",
"D": "2337",
"E": "none of these"
}
|
subtract(13200, 9773)
|
subtract(n1,n0)|
|
"answer x = 13200 - 9773 = 3427 option : a"
|
general
|
math_qa__Omp780FcOnO9gBfZ
|
When 5 + 6 = 305, 6 + 7 = 425, 7 + 8 = 565, then 8 + 9 = ? Choose the correct choice from the following:
A) 705 B) 735 C) 685 D) 665 E) 725
|
<gadget id="calculator">8 * 9</gadget>
<output>72</output>
<gadget id="calculator">72 * 10</gadget>
<output>720</output>
<gadget id="calculator">720 + 5</gadget>
<output>725</output>
<result>E</result>
|
E
| 725 |
When 5 + 6 = 305, 6 + 7 = 425, 7 + 8 = 565, then 8 + 9 = ?
|
{
"A": "705",
"B": "735",
"C": "685",
"D": "665",
"E": "725"
}
|
add(multiply(multiply(8, 9), const_10), 5)
|
multiply(n7,n10)|multiply(#0,const_10)|add(n0,#1)
|
5 + 6 = > 5 Γ£ β 6 = 30 = > 30 Γ£ β 10 + 5 = 305 6 + 7 = > 6 Γ£ β 7 = 42 = > 42 Γ£ β 10 + 5 = 425 7 + 8 = > 7 Γ£ β 8 = 56 = > 56 Γ£ β 10 + 5 = 565 then 8 + 9 = > 8 Γ£ β 9 = 72 = > 72 Γ£ β 10 + 5 = 725 answer : e
|
general
|
math_qa__LH3JA4wCdYcNaW3E
|
A hall is 15m long and 12m broad.If the sum of the areas of the floor and the ceiling is equal to the sum of areas of the four walls, the volume of hall is? Select the correct option:
A) 1100
B) 1200
C) 1300
D) 1400
E) 1500
|
<gadget id="calculator">12 * 15</gadget>
<output>180</output>
<gadget id="calculator">2 * 180</gadget>
<output>360</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">24 + 30</gadget>
<output>54</output>
<gadget id="calculator">360 / 54</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">15 * 12 * (20/3)</gadget>
<output>1_200</output>
<result>B</result>
|
B
| 1,200 |
A hall is 15m long and 12m broad.If the sum of the areas of the floor and the ceiling is equal to the sum of areas of the four walls, the volume of hall is?
|
{
"A": "1100",
"B": "1200",
"C": "1300",
"D": "1400",
"E": "1500"
}
|
volume_rectangular_prism(15, 12, divide(multiply(const_2, rectangle_area(12, 15)), add(multiply(12, const_2), multiply(15, const_2))))
|
multiply(n1,const_2)|multiply(n0,const_2)|rectangle_area(n0,n1)|add(#0,#1)|multiply(#2,const_2)|divide(#4,#3)|volume_rectangular_prism(n0,n1,#5)
|
area of 4 wall = sum of area of floor and celling 2 ( l + b ) * h = 2 ( l * b ) ( 15 + 12 ) * h = 2 ( 12 * 15 ) on solving h = 20 / 3 m volume = l * b * h = 12 * 15 * 20 / 3 = 1200 m ^ 3 answer : b
|
geometry
|
math_qa__fkVTgcMw1ZkHZUNh
|
When the positive integer x is divided by 9,the remainder is 5.What is the remainder when 4x is divided by 9? Select
A) 0
B) 1
C) 2
D) 4
E) 6
|
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 % 9</gadget>
<output>2</output>
<result>C</result>
|
C
| 2 |
When the positive integer x is divided by 9,the remainder is 5.What is the remainder when 4x is divided by 9?
|
{
"A": "0",
"B": "1",
"C": "2",
"D": "4",
"E": "6"
}
|
reminder(multiply(5, 4), 9)
|
multiply(n1,n2)|reminder(#0,n0)|
|
"i tried plugging in numbers x = 9 q + 5 x = 14 4 x = 56 4 x / 9 = 9 * 6 + 2 remainder is 2 . answer is c"
|
general
|
math_qa__fwV5gNfakYgn8za7
|
4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat weavers in 8 days ? Pick one.
A) 12 B) 14 C) 16 D) 18 E) 20
|
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<result>C</result>
|
C
| 16 |
4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat weavers in 8 days ?
|
{
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
}
|
multiply(multiply(4, divide(8, 4)), divide(8, 4))
|
divide(n3,n0)|multiply(n0,#0)|multiply(#0,#1)|
|
"explanation : please always remember , that what exactly we need to calculate before applying chain formula . as in this question we need to find how many mats , right ! so we will compare everything with ` ` number of mats ' ' as , more men , more number of mats ( direct proportion ) more days , more number of mats ( direct proportion ) so , it can be solved as , [ weavers 4 4 days 8 8 ] : : 4 : x = > x β 4 β 4 = 8 β 8 β 4 = > x = 16 option c"
|
gain
|
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