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###question:Find the dates on which more than one revisions were made.###answer:SELECT date_of_latest_revision FROM Catalogs GROUP BY date_of_latest_revision HAVING COUNT(*) > 1###context:CREATE TABLE Catalogs (date_of_latest_revision VARCHAR) |
###question:How many products are there in the records?###answer:SELECT COUNT(*) FROM catalog_contents###context:CREATE TABLE catalog_contents (Id VARCHAR) |
###question:Name all the products with next entry ID greater than 8.###answer:SELECT catalog_entry_name FROM catalog_contents WHERE next_entry_id > 8###context:CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, next_entry_id INTEGER) |
###question:How many aircrafts do we have?###answer:SELECT COUNT(*) FROM Aircraft###context:CREATE TABLE Aircraft (Id VARCHAR) |
###question:Show name and distance for all aircrafts.###answer:SELECT name, distance FROM Aircraft###context:CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR) |
###question:Show ids for all aircrafts with more than 1000 distance.###answer:SELECT aid FROM Aircraft WHERE distance > 1000###context:CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER) |
###question:How many aircrafts have distance between 1000 and 5000?###answer:SELECT COUNT(*) FROM Aircraft WHERE distance BETWEEN 1000 AND 5000###context:CREATE TABLE Aircraft (distance INTEGER) |
###question:What is the name and distance for aircraft with id 12?###answer:SELECT name, distance FROM Aircraft WHERE aid = 12###context:CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR, aid VARCHAR) |
###question:What is the minimum, average, and maximum distance of all aircrafts.###answer:SELECT MIN(distance), AVG(distance), MAX(distance) FROM Aircraft###context:CREATE TABLE Aircraft (distance INTEGER) |
###question:Show the id and name of the aircraft with the maximum distance.###answer:SELECT aid, name FROM Aircraft ORDER BY distance DESC LIMIT 1###context:CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR, distance VARCHAR) |
###question:Show the name of aircrafts with top three lowest distances.###answer:SELECT name FROM Aircraft ORDER BY distance LIMIT 3###context:CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR) |
###question:Show names for all aircrafts with distances more than the average.###answer:SELECT name FROM Aircraft WHERE distance > (SELECT AVG(distance) FROM Aircraft)###context:CREATE TABLE Aircraft (name VARCHAR, distance INTEGER) |
###question:How many employees do we have?###answer:SELECT COUNT(*) FROM Employee###context:CREATE TABLE Employee (Id VARCHAR) |
###question:Show name and salary for all employees sorted by salary.###answer:SELECT name, salary FROM Employee ORDER BY salary###context:CREATE TABLE Employee (name VARCHAR, salary VARCHAR) |
###question:Show ids for all employees with at least 100000 salary.###answer:SELECT eid FROM Employee WHERE salary > 100000###context:CREATE TABLE Employee (eid VARCHAR, salary INTEGER) |
###question:How many employees have salary between 100000 and 200000?###answer:SELECT COUNT(*) FROM Employee WHERE salary BETWEEN 100000 AND 200000###context:CREATE TABLE Employee (salary INTEGER) |
###question:What is the name and salary for employee with id 242518965?###answer:SELECT name, salary FROM Employee WHERE eid = 242518965###context:CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR) |
###question:What is average and maximum salary of all employees.###answer:SELECT AVG(salary), MAX(salary) FROM Employee###context:CREATE TABLE Employee (salary INTEGER) |
###question:Show the id and name of the employee with maximum salary.###answer:SELECT eid, name FROM Employee ORDER BY salary DESC LIMIT 1###context:CREATE TABLE Employee (eid VARCHAR, name VARCHAR, salary VARCHAR) |
###question:Show the name of employees with three lowest salaries.###answer:SELECT name FROM Employee ORDER BY salary LIMIT 3###context:CREATE TABLE Employee (name VARCHAR, salary VARCHAR) |
###question:Show names for all employees with salary more than the average.###answer:SELECT name FROM Employee WHERE salary > (SELECT AVG(salary) FROM Employee)###context:CREATE TABLE Employee (name VARCHAR, salary INTEGER) |
###question:Show the id and salary of Mark Young.###answer:SELECT eid, salary FROM Employee WHERE name = 'Mark Young'###context:CREATE TABLE Employee (eid VARCHAR, salary VARCHAR, name VARCHAR) |
###question:How many flights do we have?###answer:SELECT COUNT(*) FROM Flight###context:CREATE TABLE Flight (Id VARCHAR) |
###question:Show flight number, origin, destination of all flights in the alphabetical order of the departure cities.###answer:SELECT flno, origin, destination FROM Flight ORDER BY origin###context:CREATE TABLE Flight (flno VARCHAR, origin VARCHAR, destination VARCHAR) |
###question:Show all flight number from Los Angeles.###answer:SELECT flno FROM Flight WHERE origin = "Los Angeles"###context:CREATE TABLE Flight (flno VARCHAR, origin VARCHAR) |
###question:Show origins of all flights with destination Honolulu.###answer:SELECT origin FROM Flight WHERE destination = "Honolulu"###context:CREATE TABLE Flight (origin VARCHAR, destination VARCHAR) |
###question:Show me the departure date and arrival date for all flights from Los Angeles to Honolulu.###answer:SELECT departure_date, arrival_date FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu"###context:CREATE TABLE Flight (departure_date VARCHAR, arrival_date VARCHAR, origin VARCHAR, destination VARCHAR) |
###question:Show flight number for all flights with more than 2000 distance.###answer:SELECT flno FROM Flight WHERE distance > 2000###context:CREATE TABLE Flight (flno VARCHAR, distance INTEGER) |
###question:What is the average price for flights from Los Angeles to Honolulu.###answer:SELECT AVG(price) FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu"###context:CREATE TABLE Flight (price INTEGER, origin VARCHAR, destination VARCHAR) |
###question:Show origin and destination for flights with price higher than 300.###answer:SELECT origin, destination FROM Flight WHERE price > 300###context:CREATE TABLE Flight (origin VARCHAR, destination VARCHAR, price INTEGER) |
###question:Show the flight number and distance of the flight with maximum price.###answer:SELECT flno, distance FROM Flight ORDER BY price DESC LIMIT 1###context:CREATE TABLE Flight (flno VARCHAR, distance VARCHAR, price VARCHAR) |
###question:Show the flight number of flights with three lowest distances.###answer:SELECT flno FROM Flight ORDER BY distance LIMIT 3###context:CREATE TABLE Flight (flno VARCHAR, distance VARCHAR) |
###question:What is the average distance and average price for flights from Los Angeles.###answer:SELECT AVG(distance), AVG(price) FROM Flight WHERE origin = "Los Angeles"###context:CREATE TABLE Flight (distance INTEGER, price INTEGER, origin VARCHAR) |
###question:Show all origins and the number of flights from each origin.###answer:SELECT origin, COUNT(*) FROM Flight GROUP BY origin###context:CREATE TABLE Flight (origin VARCHAR) |
###question:Show all destinations and the number of flights to each destination.###answer:SELECT destination, COUNT(*) FROM Flight GROUP BY destination###context:CREATE TABLE Flight (destination VARCHAR) |
###question:Which origin has most number of flights?###answer:SELECT origin FROM Flight GROUP BY origin ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Flight (origin VARCHAR) |
###question:Which destination has least number of flights?###answer:SELECT destination FROM Flight GROUP BY destination ORDER BY COUNT(*) LIMIT 1###context:CREATE TABLE Flight (destination VARCHAR) |
###question:What is the aircraft name for the flight with number 99###answer:SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99###context:CREATE TABLE Flight (aid VARCHAR, flno VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR) |
###question:Show all flight numbers with aircraft Airbus A340-300.###answer:SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"###context:CREATE TABLE Flight (flno VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR) |
###question:Show aircraft names and number of flights for each aircraft.###answer:SELECT T2.name, COUNT(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid###context:CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR) |
###question:Show names for all aircraft with at least two flights.###answer:SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING COUNT(*) >= 2###context:CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR) |
###question:How many employees have certificate.###answer:SELECT COUNT(DISTINCT eid) FROM Certificate###context:CREATE TABLE Certificate (eid VARCHAR) |
###question:Show ids for all employees who don't have a certificate.###answer:SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate###context:CREATE TABLE Employee (eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR) |
###question:Show names for all aircrafts of which John Williams has certificates.###answer:SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"###context:CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Employee (eid VARCHAR, name VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR) |
###question:Show names for all employees who have certificate of Boeing 737-800.###answer:SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"###context:CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR) |
###question:Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300.###answer:SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"###context:CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR) |
###question:Show names for all employees who do not have certificate of Boeing 737-800.###answer:SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"###context:CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Employee (name VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR) |
###question:Show the name of aircraft which fewest people have its certificate.###answer:SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR) |
###question:Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate.###answer:SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY COUNT(*) >= 5###context:CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR, distance INTEGER) |
###question:what is the salary and name of the employee who has the most number of aircraft certificates?###answer:SELECT T1.name, T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Certificate (eid VARCHAR); CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR) |
###question:What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000?###answer:SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR) |
###question:How many allergies are there?###answer:SELECT COUNT(DISTINCT allergy) FROM Allergy_type###context:CREATE TABLE Allergy_type (allergy VARCHAR) |
###question:How many different allergy types exist?###answer:SELECT COUNT(DISTINCT allergytype) FROM Allergy_type###context:CREATE TABLE Allergy_type (allergytype VARCHAR) |
###question:Show all allergy types.###answer:SELECT DISTINCT allergytype FROM Allergy_type###context:CREATE TABLE Allergy_type (allergytype VARCHAR) |
###question:Show all allergies and their types.###answer:SELECT allergy, allergytype FROM Allergy_type###context:CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR) |
###question:Show all allergies with type food.###answer:SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"###context:CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR) |
###question:What is the type of allergy Cat?###answer:SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"###context:CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR) |
###question:How many allergies have type animal?###answer:SELECT COUNT(*) FROM Allergy_type WHERE allergytype = "animal"###context:CREATE TABLE Allergy_type (allergytype VARCHAR) |
###question:Show all allergy types and the number of allergies in each type.###answer:SELECT allergytype, COUNT(*) FROM Allergy_type GROUP BY allergytype###context:CREATE TABLE Allergy_type (allergytype VARCHAR) |
###question:Which allergy type has most number of allergies?###answer:SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Allergy_type (allergytype VARCHAR) |
###question:Which allergy type has least number of allergies?###answer:SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) LIMIT 1###context:CREATE TABLE Allergy_type (allergytype VARCHAR) |
###question:How many students are there?###answer:SELECT COUNT(*) FROM Student###context:CREATE TABLE Student (Id VARCHAR) |
###question:Show first name and last name for all students.###answer:SELECT Fname, Lname FROM Student###context:CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR) |
###question:How many different advisors are listed?###answer:SELECT COUNT(DISTINCT advisor) FROM Student###context:CREATE TABLE Student (advisor VARCHAR) |
###question:Show all majors.###answer:SELECT DISTINCT Major FROM Student###context:CREATE TABLE Student (Major VARCHAR) |
###question:Show all cities where students live.###answer:SELECT DISTINCT city_code FROM Student###context:CREATE TABLE Student (city_code VARCHAR) |
###question:Show first name, last name, age for all female students. Their sex is F.###answer:SELECT Fname, Lname, Age FROM Student WHERE Sex = 'F'###context:CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Sex VARCHAR) |
###question:Show student ids for all male students.###answer:SELECT StuID FROM Student WHERE Sex = 'M'###context:CREATE TABLE Student (StuID VARCHAR, Sex VARCHAR) |
###question:How many students are age 18?###answer:SELECT COUNT(*) FROM Student WHERE age = 18###context:CREATE TABLE Student (age VARCHAR) |
###question:Show all student ids who are older than 20.###answer:SELECT StuID FROM Student WHERE age > 20###context:CREATE TABLE Student (StuID VARCHAR, age INTEGER) |
###question:Which city does the student whose last name is "Kim" live in?###answer:SELECT city_code FROM Student WHERE LName = "Kim"###context:CREATE TABLE Student (city_code VARCHAR, LName VARCHAR) |
###question:Who is the advisor of student with ID 1004?###answer:SELECT Advisor FROM Student WHERE StuID = 1004###context:CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR) |
###question:How many students live in HKG or CHI?###answer:SELECT COUNT(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"###context:CREATE TABLE Student (city_code VARCHAR) |
###question:Show the minimum, average, and maximum age of all students.###answer:SELECT MIN(age), AVG(age), MAX(age) FROM Student###context:CREATE TABLE Student (age INTEGER) |
###question:What is the last name of the youngest student?###answer:SELECT LName FROM Student WHERE age = (SELECT MIN(age) FROM Student)###context:CREATE TABLE Student (LName VARCHAR, age INTEGER) |
###question:Show the student id of the oldest student.###answer:SELECT StuID FROM Student WHERE age = (SELECT MAX(age) FROM Student)###context:CREATE TABLE Student (StuID VARCHAR, age INTEGER) |
###question:Show all majors and corresponding number of students.###answer:SELECT major, COUNT(*) FROM Student GROUP BY major###context:CREATE TABLE Student (major VARCHAR) |
###question:Which major has most number of students?###answer:SELECT major FROM Student GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Student (major VARCHAR) |
###question:Show all ages and corresponding number of students.###answer:SELECT age, COUNT(*) FROM Student GROUP BY age###context:CREATE TABLE Student (age VARCHAR) |
###question:Show the average age for male and female students.###answer:SELECT AVG(age), sex FROM Student GROUP BY sex###context:CREATE TABLE Student (sex VARCHAR, age INTEGER) |
###question:Show all cities and corresponding number of students.###answer:SELECT city_code, COUNT(*) FROM Student GROUP BY city_code###context:CREATE TABLE Student (city_code VARCHAR) |
###question:Show all advisors and corresponding number of students.###answer:SELECT advisor, COUNT(*) FROM Student GROUP BY advisor###context:CREATE TABLE Student (advisor VARCHAR) |
###question:Which advisor has most number of students?###answer:SELECT advisor FROM Student GROUP BY advisor ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Student (advisor VARCHAR) |
###question:How many students have cat allergies?###answer:SELECT COUNT(*) FROM Has_allergy WHERE Allergy = "Cat"###context:CREATE TABLE Has_allergy (Allergy VARCHAR) |
###question:Show all student IDs who have at least two allergies.###answer:SELECT StuID FROM Has_allergy GROUP BY StuID HAVING COUNT(*) >= 2###context:CREATE TABLE Has_allergy (StuID VARCHAR) |
###question:What are the student ids of students who don't have any allergies?###answer:SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy###context:CREATE TABLE Has_allergy (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR) |
###question:How many female students have milk or egg allergies?###answer:SELECT COUNT(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs"###context:CREATE TABLE Student (StuID VARCHAR, sex VARCHAR); CREATE TABLE has_allergy (StuID VARCHAR, allergy VARCHAR) |
###question:How many students have a food allergy?###answer:SELECT COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food"###context:CREATE TABLE Has_allergy (allergy VARCHAR); CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR) |
###question:Which allergy has most number of students affected?###answer:SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Has_allergy (Allergy VARCHAR) |
###question:Show all allergies with number of students affected.###answer:SELECT Allergy, COUNT(*) FROM Has_allergy GROUP BY Allergy###context:CREATE TABLE Has_allergy (Allergy VARCHAR) |
###question:Show all allergy type with number of students affected.###answer:SELECT T2.allergytype, COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype###context:CREATE TABLE Has_allergy (allergy VARCHAR); CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR) |
###question:Find the last name and age of the student who has allergy to both milk and cat.###answer:SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")###context:CREATE TABLE Has_allergy (lname VARCHAR, age VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Student (lname VARCHAR, age VARCHAR, StuID VARCHAR, Allergy VARCHAR) |
###question:What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.###answer:SELECT T1.Allergy, T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy###context:CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR, Fname VARCHAR); CREATE TABLE Allergy_type (Allergy VARCHAR, AllergyType VARCHAR) |
###question:Find the first name and gender of the student who has allergy to milk but not cat.###answer:SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")###context:CREATE TABLE Student (fname VARCHAR, sex VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Has_allergy (fname VARCHAR, sex VARCHAR, StuID VARCHAR, Allergy VARCHAR) |
###question:Find the average age of the students who have allergies with food and animal types.###answer:SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")###context:CREATE TABLE Student (age INTEGER, StuID VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR) |
###question:List the first and last name of the students who do not have any food type allergy.###answer:SELECT fname, lname FROM Student WHERE NOT StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")###context:CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR) |
###question:Find the number of male (sex is 'M') students who have some food type allery.###answer:SELECT COUNT(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")###context:CREATE TABLE Has_allergy (Allergy VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Student (sex VARCHAR, StuID VARCHAR) |
###question:Find the different first names and cities of the students who have allergy to milk or cat.###answer:SELECT DISTINCT T1.fname, T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat"###context:CREATE TABLE Has_Allergy (stuid VARCHAR, Allergy VARCHAR); CREATE TABLE Student (fname VARCHAR, city_code VARCHAR, stuid VARCHAR) |
###question:Find the number of students who are older than 18 and do not have allergy to either food or animal.###answer:SELECT COUNT(*) FROM Student WHERE age > 18 AND NOT StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal")###context:CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (Allergy VARCHAR); CREATE TABLE Student (age VARCHAR, StuID VARCHAR) |
###question:Find the first name and major of the students who are not allegry to soy.###answer:SELECT fname, major FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy")###context:CREATE TABLE Has_allergy (fname VARCHAR, major VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Student (fname VARCHAR, major VARCHAR, StuID VARCHAR, Allergy VARCHAR) |
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