combined_text
stringlengths 106
1.05k
|
|---|
###question:Find the name of physicians whose position title contains the word 'senior'.###answer:SELECT name FROM physician WHERE POSITION LIKE '%senior%'###context:CREATE TABLE physician (name VARCHAR, POSITION VARCHAR) |
###question:Find the patient who has the most recent undergoing treatment?###answer:SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1###context:CREATE TABLE undergoes (patient VARCHAR, dateundergoes VARCHAR) |
###question:Find the names of all patients who have an undergoing treatment and are staying in room 111.###answer:SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111###context:CREATE TABLE undergoes (patient VARCHAR, Stay VARCHAR); CREATE TABLE stay (StayID VARCHAR, room VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR) |
###question:List the names of all distinct nurses ordered by alphabetical order?###answer:SELECT DISTINCT name FROM nurse ORDER BY name###context:CREATE TABLE nurse (name VARCHAR) |
###question:Find the names of nurses who are nursing an undergoing treatment.###answer:SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID###context:CREATE TABLE undergoes (AssistingNurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR) |
###question:List the names of all distinct medications, ordered in an alphabetical order.###answer:SELECT DISTINCT name FROM medication ORDER BY name###context:CREATE TABLE medication (name VARCHAR) |
###question:What are the names of the physician who prescribed the highest dose?###answer:SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1###context:CREATE TABLE prescribes (physician VARCHAR, dose VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR) |
###question:List the physicians' employee ids together with their primary affiliation departments' ids.###answer:SELECT physician, department FROM affiliated_with WHERE primaryaffiliation = 1###context:CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR, primaryaffiliation VARCHAR) |
###question:List the names of departments where some physicians are primarily affiliated with.###answer:SELECT DISTINCT T2.name FROM affiliated_with AS T1 JOIN department AS T2 ON T1.department = T2.departmentid WHERE PrimaryAffiliation = 1###context:CREATE TABLE affiliated_with (department VARCHAR); CREATE TABLE department (name VARCHAR, departmentid VARCHAR) |
###question:What nurses are on call with block floor 1 and block code 1? Tell me their names.###answer:SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1###context:CREATE TABLE on_call (nurse VARCHAR, blockfloor VARCHAR, blockcode VARCHAR) |
###question:What are the highest cost, lowest cost and average cost of procedures?###answer:SELECT MAX(cost), MIN(cost), AVG(cost) FROM procedures###context:CREATE TABLE procedures (cost INTEGER) |
###question:List the name and cost of all procedures sorted by the cost from the highest to the lowest.###answer:SELECT name, cost FROM procedures ORDER BY cost DESC###context:CREATE TABLE procedures (name VARCHAR, cost VARCHAR) |
###question:Find the three most expensive procedures.###answer:SELECT name FROM procedures ORDER BY cost LIMIT 3###context:CREATE TABLE procedures (name VARCHAR, cost VARCHAR) |
###question:Find the physicians who are trained in a procedure that costs more than 5000.###answer:SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost INTEGER) |
###question:Find the physician who was trained in the most expensive procedure?###answer:SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost VARCHAR) |
###question:What is the average cost of procedures that physician John Wen was trained in?###answer:SELECT AVG(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (cost INTEGER, code VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR) |
###question:Find the names of procedures which physician John Wen was trained in.###answer:SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) |
###question:Find all procedures which cost more than 1000 or which physician John Wen was trained in.###answer:SELECT name FROM procedures WHERE cost > 1000 UNION SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) |
###question:Find the names of all procedures which cost more than 1000 but which physician John Wen was not trained in?###answer:SELECT name FROM procedures WHERE cost > 1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) |
###question:Find the names of all procedures such that the cost is less than 5000 and physician John Wen was trained in.###answer:SELECT name FROM procedures WHERE cost < 5000 INTERSECT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"###context:CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) |
###question:Find the name of physicians who are affiliated with both Surgery and Psychiatry departments.###answer:SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Psychiatry'###context:CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR) |
###question:Find the name of physicians who are affiliated with Surgery or Psychiatry department.###answer:SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry'###context:CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR) |
###question:Find the names of patients who are not using the medication of Procrastin-X.###answer:SELECT name FROM patient EXCEPT SELECT T1.name FROM patient AS T1 JOIN Prescribes AS T2 ON T2.Patient = T1.SSN JOIN Medication AS T3 ON T2.Medication = T3.Code WHERE T3.name = 'Procrastin-X'###context:CREATE TABLE Prescribes (Patient VARCHAR, Medication VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR); CREATE TABLE patient (name VARCHAR) |
###question:Find the number of patients who are not using the medication of Procrastin-X.###answer:SELECT COUNT(*) FROM patient WHERE NOT SSN IN (SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X')###context:CREATE TABLE Prescribes (patient VARCHAR, Medication VARCHAR); CREATE TABLE patient (SSN VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR) |
###question:How many appointments are there?###answer:SELECT COUNT(*) FROM appointment###context:CREATE TABLE appointment (Id VARCHAR) |
###question:Find the names of nurses who are on call.###answer:SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse###context:CREATE TABLE on_call (nurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR) |
###question:How many ships are there?###answer:SELECT COUNT(*) FROM ship###context:CREATE TABLE ship (Id VARCHAR) |
###question:List the name of ships in ascending order of tonnage.###answer:SELECT Name FROM ship ORDER BY Tonnage###context:CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR) |
###question:What are the type and nationality of ships?###answer:SELECT TYPE, Nationality FROM ship###context:CREATE TABLE ship (TYPE VARCHAR, Nationality VARCHAR) |
###question:List the name of ships whose nationality is not "United States".###answer:SELECT Name FROM ship WHERE Nationality <> "United States"###context:CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR) |
###question:Show the name of ships whose nationality is either United States or United Kingdom.###answer:SELECT Name FROM ship WHERE Nationality = "United States" OR Nationality = "United Kingdom"###context:CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR) |
###question:What is the name of the ship with the largest tonnage?###answer:SELECT Name FROM ship ORDER BY Tonnage DESC LIMIT 1###context:CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR) |
###question:Show different types of ships and the number of ships of each type.###answer:SELECT TYPE, COUNT(*) FROM ship GROUP BY TYPE###context:CREATE TABLE ship (TYPE VARCHAR) |
###question:Please show the most common type of ships.###answer:SELECT TYPE FROM ship GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE ship (TYPE VARCHAR) |
###question:List the nations that have more than two ships.###answer:SELECT Nationality FROM ship GROUP BY Nationality HAVING COUNT(*) > 2###context:CREATE TABLE ship (Nationality VARCHAR) |
###question:Show different types of ships and the average tonnage of ships of each type.###answer:SELECT TYPE, AVG(Tonnage) FROM ship GROUP BY TYPE###context:CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER) |
###question:Show codes and fates of missions, and names of ships involved.###answer:SELECT T1.Code, T1.Fate, T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID###context:CREATE TABLE mission (Code VARCHAR, Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR) |
###question:Show names of ships involved in a mission launched after 1928.###answer:SELECT T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T1.Launched_Year > 1928###context:CREATE TABLE mission (Ship_ID VARCHAR, Launched_Year INTEGER); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR) |
###question:Show the distinct fate of missions that involve ships with nationality "United States"###answer:SELECT DISTINCT T1.Fate FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T2.Nationality = "United States"###context:CREATE TABLE mission (Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Ship_ID VARCHAR, Nationality VARCHAR) |
###question:List the name of ships that are not involved in any mission###answer:SELECT Name FROM ship WHERE NOT Ship_ID IN (SELECT Ship_ID FROM mission)###context:CREATE TABLE mission (Name VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR) |
###question:Show the types of ships that have both ships with tonnage larger than 6000 and ships with tonnage smaller than 4000.###answer:SELECT TYPE FROM ship WHERE Tonnage > 6000 INTERSECT SELECT TYPE FROM ship WHERE Tonnage < 4000###context:CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER) |
###question:Find the number of students in total.###answer:SELECT COUNT(*) FROM list###context:CREATE TABLE list (Id VARCHAR) |
###question:Find the last names of students studying in room 111.###answer:SELECT lastname FROM list WHERE classroom = 111###context:CREATE TABLE list (lastname VARCHAR, classroom VARCHAR) |
###question:Find the first names of students studying in room 108.###answer:SELECT firstname FROM list WHERE classroom = 108###context:CREATE TABLE list (firstname VARCHAR, classroom VARCHAR) |
###question:What are the first names of students studying in room 107?###answer:SELECT DISTINCT firstname FROM list WHERE classroom = 107###context:CREATE TABLE list (firstname VARCHAR, classroom VARCHAR) |
###question:For each classroom report the grade that is taught in it. Report just the classroom number and the grade number.###answer:SELECT DISTINCT classroom, grade FROM list###context:CREATE TABLE list (classroom VARCHAR, grade VARCHAR) |
###question:Which grade is studying in classroom 103?###answer:SELECT DISTINCT grade FROM list WHERE classroom = 103###context:CREATE TABLE list (grade VARCHAR, classroom VARCHAR) |
###question:Find the grade studying in room 105.###answer:SELECT DISTINCT grade FROM list WHERE classroom = 105###context:CREATE TABLE list (grade VARCHAR, classroom VARCHAR) |
###question:Which classrooms are used by grade 4?###answer:SELECT DISTINCT classroom FROM list WHERE grade = 4###context:CREATE TABLE list (classroom VARCHAR, grade VARCHAR) |
###question:Which classrooms are used by grade 5?###answer:SELECT DISTINCT classroom FROM list WHERE grade = 5###context:CREATE TABLE list (classroom VARCHAR, grade VARCHAR) |
###question:Find the last names of the teachers that teach fifth grade.###answer:SELECT DISTINCT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 5###context:CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR) |
###question:Find the first names of the teachers that teach first grade.###answer:SELECT DISTINCT T2.firstname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 1###context:CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR) |
###question:Find the first names of all the teachers that teach in classroom 110.###answer:SELECT firstname FROM teachers WHERE classroom = 110###context:CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR) |
###question:Find the last names of teachers teaching in classroom 109.###answer:SELECT lastname FROM teachers WHERE classroom = 109###context:CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR) |
###question:Report the first name and last name of all the teachers.###answer:SELECT DISTINCT firstname, lastname FROM teachers###context:CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR) |
###question:Report the first name and last name of all the students.###answer:SELECT DISTINCT firstname, lastname FROM list###context:CREATE TABLE list (firstname VARCHAR, lastname VARCHAR) |
###question:Find all students taught by OTHA MOYER. Output the first and last names of the students.###answer:SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER"###context:CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:Find all students taught by MARROTTE KIRK. Output first and last names of students.###answer:SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "MARROTTE" AND T2.lastname = "KIRK"###context:CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:Find the first and last name of all the teachers that teach EVELINA BROMLEY.###answer:SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "EVELINA" AND T1.lastname = "BROMLEY"###context:CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:Find the last names of all the teachers that teach GELL TAMI.###answer:SELECT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "GELL" AND T1.lastname = "TAMI"###context:CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:How many students does LORIA ONDERSMA teaches?###answer:SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "LORIA" AND T2.lastname = "ONDERSMA"###context:CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:How many students does KAWA GORDON teaches?###answer:SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "KAWA" AND T2.lastname = "GORDON"###context:CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:Find the number of students taught by TARRING LEIA.###answer:SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "TARRING" AND T2.lastname = "LEIA"###context:CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:How many teachers does the student named CHRISSY NABOZNY have?###answer:SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "CHRISSY" AND T1.lastname = "NABOZNY"###context:CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:How many teachers does the student named MADLOCK RAY have?###answer:SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "MADLOCK" AND T1.lastname = "RAY"###context:CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:Find all first-grade students who are NOT taught by OTHA MOYER. Report their first and last names.###answer:SELECT DISTINCT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 1 EXCEPT SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER"###context:CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) |
###question:Find the last names of the students in third grade that are not taught by COVIN JEROME.###answer:SELECT DISTINCT T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 3 AND T2.firstname <> "COVIN" AND T2.lastname <> "JEROME"###context:CREATE TABLE list (lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, lastname VARCHAR, firstname VARCHAR) |
###question:For each grade, report the grade, the number of classrooms in which it is taught and the total number of students in the grade.###answer:SELECT grade, COUNT(DISTINCT classroom), COUNT(*) FROM list GROUP BY grade###context:CREATE TABLE list (grade VARCHAR, classroom VARCHAR) |
###question:For each classroom, report the classroom number and the number of grades using it.###answer:SELECT classroom, COUNT(DISTINCT grade) FROM list GROUP BY classroom###context:CREATE TABLE list (classroom VARCHAR, grade VARCHAR) |
###question:Which classroom has the most students?###answer:SELECT classroom FROM list GROUP BY classroom ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE list (classroom VARCHAR) |
###question:Report the number of students in each classroom.###answer:SELECT classroom, COUNT(*) FROM list GROUP BY classroom###context:CREATE TABLE list (classroom VARCHAR) |
###question:For each grade 0 classroom, report the total number of students.###answer:SELECT classroom, COUNT(*) FROM list WHERE grade = "0" GROUP BY classroom###context:CREATE TABLE list (classroom VARCHAR, grade VARCHAR) |
###question:Report the total number of students for each fourth-grade classroom.###answer:SELECT classroom, COUNT(*) FROM list WHERE grade = "4" GROUP BY classroom###context:CREATE TABLE list (classroom VARCHAR, grade VARCHAR) |
###question:Find the name of the teacher who teaches the largest number of students.###answer:SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom GROUP BY T2.firstname, T2.lastname ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR) |
###question:Find the number of students in one classroom.###answer:SELECT COUNT(*), classroom FROM list GROUP BY classroom###context:CREATE TABLE list (classroom VARCHAR) |
###question:How many companies are headquartered in the US?###answer:SELECT COUNT(*) FROM company WHERE Headquarters = 'USA'###context:CREATE TABLE company (Headquarters VARCHAR) |
###question:List the names of companies by ascending number of sales.###answer:SELECT Name FROM company ORDER BY Sales_in_Billion###context:CREATE TABLE company (Name VARCHAR, Sales_in_Billion VARCHAR) |
###question:What are the headquarters and industries of all companies?###answer:SELECT Headquarters, Industry FROM company###context:CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR) |
###question:Show the names of companies in the banking or retailing industry?###answer:SELECT Name FROM company WHERE Industry = "Banking" OR Industry = "Retailing"###context:CREATE TABLE company (Name VARCHAR, Industry VARCHAR) |
###question:What is the maximum and minimum market value of companies?###answer:SELECT MAX(Market_Value_in_Billion), MIN(Market_Value_in_Billion) FROM company###context:CREATE TABLE company (Market_Value_in_Billion INTEGER) |
###question:What is the headquarter of the company with the largest sales?###answer:SELECT Headquarters FROM company ORDER BY Sales_in_Billion DESC LIMIT 1###context:CREATE TABLE company (Headquarters VARCHAR, Sales_in_Billion VARCHAR) |
###question:Show the different headquarters and number of companies at each headquarter.###answer:SELECT Headquarters, COUNT(*) FROM company GROUP BY Headquarters###context:CREATE TABLE company (Headquarters VARCHAR) |
###question:Show the most common headquarter for companies.###answer:SELECT Headquarters FROM company GROUP BY Headquarters ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE company (Headquarters VARCHAR) |
###question:Show the headquarters that have at least two companies.###answer:SELECT Headquarters FROM company GROUP BY Headquarters HAVING COUNT(*) >= 2###context:CREATE TABLE company (Headquarters VARCHAR) |
###question:Show the headquarters that have both companies in banking industry and companies in oil and gas industry.###answer:SELECT Headquarters FROM company WHERE Industry = "Banking" INTERSECT SELECT Headquarters FROM company WHERE Industry = "Oil and gas"###context:CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR) |
###question:Show the names of companies and of employees.###answer:SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID###context:CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR) |
###question:Show names of companies and that of employees in descending order of number of years working for that employee.###answer:SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID ORDER BY T1.Year_working###context:CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR, Year_working VARCHAR) |
###question:Show the names of employees that work for companies with sales bigger than 200.###answer:SELECT T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID WHERE T3.Sales_in_Billion > 200###context:CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE company (Company_ID VARCHAR, Sales_in_Billion INTEGER); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR) |
###question:Show the names of companies and the number of employees they have###answer:SELECT T3.Name, COUNT(*) FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID GROUP BY T3.Name###context:CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE people (People_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR) |
###question:List the names of people that are not employed by any company###answer:SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM employment)###context:CREATE TABLE employment (Name VARCHAR, People_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR) |
###question:list the names of the companies with more than 200 sales in the descending order of sales and profits.###answer:SELECT name FROM company WHERE Sales_in_Billion > 200 ORDER BY Sales_in_Billion, Profits_in_Billion DESC###context:CREATE TABLE company (name VARCHAR, Sales_in_Billion INTEGER, Profits_in_Billion VARCHAR) |
###question:How many film are there?###answer:SELECT COUNT(*) FROM film###context:CREATE TABLE film (Id VARCHAR) |
###question:List the distinct director of all films.###answer:SELECT DISTINCT Director FROM film###context:CREATE TABLE film (Director VARCHAR) |
###question:What is the average ticket sales gross in dollars of films?###answer:SELECT AVG(Gross_in_dollar) FROM film###context:CREATE TABLE film (Gross_in_dollar INTEGER) |
###question:What are the low and high estimates of film markets?###answer:SELECT Low_Estimate, High_Estimate FROM film_market_estimation###context:CREATE TABLE film_market_estimation (Low_Estimate VARCHAR, High_Estimate VARCHAR) |
###question:What are the types of film market estimations in year 1995?###answer:SELECT TYPE FROM film_market_estimation WHERE YEAR = 1995###context:CREATE TABLE film_market_estimation (TYPE VARCHAR, YEAR VARCHAR) |
###question:What are the maximum and minimum number of cities in all markets.###answer:SELECT MAX(Number_cities), MIN(Number_cities) FROM market###context:CREATE TABLE market (Number_cities INTEGER) |
###question:How many markets have number of cities smaller than 300?###answer:SELECT COUNT(*) FROM market WHERE Number_cities < 300###context:CREATE TABLE market (Number_cities INTEGER) |
###question:List all countries of markets in ascending alphabetical order.###answer:SELECT Country FROM market ORDER BY Country###context:CREATE TABLE market (Country VARCHAR) |
###question:List all countries of markets in descending order of number of cities.###answer:SELECT Country FROM market ORDER BY Number_cities DESC###context:CREATE TABLE market (Country VARCHAR, Number_cities VARCHAR) |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.