combined_text
stringlengths 106
1.05k
|
|---|
###question:Find the first name of the band mate that has performed in most songs.###answer:SELECT t2.firstname FROM Performance AS t1 JOIN Band AS t2 ON t1.bandmate = t2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY firstname ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Songs (SongId VARCHAR); CREATE TABLE Band (firstname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR) |
###question:Which vocal type has the band mate with first name "Marianne" played the most?###answer:SELECT TYPE FROM vocals AS T1 JOIN band AS T2 ON T1.bandmate = T2.id WHERE firstname = "Marianne" GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE vocals (bandmate VARCHAR); CREATE TABLE band (id VARCHAR) |
###question:Who is performing in the back stage position for the song "Der Kapitan"? Show the first name and last name.###answer:SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Der Kapitan" AND T1.StagePosition = "back"###context:CREATE TABLE Band (firstname VARCHAR, lastname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR, SongId VARCHAR, StagePosition VARCHAR); CREATE TABLE Songs (SongId VARCHAR, Title VARCHAR) |
###question:What are the songs in album "A Kiss Before You Go: Live in Hamburg"?###answer:SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE T1.title = "A Kiss Before You Go: Live in Hamburg"###context:CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR, title VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR) |
###question:What are all the songs in albums under label "Universal Music Group"?###answer:SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.label = "Universal Music Group"###context:CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR) |
###question:Find the number of songs in all the studio albums.###answer:SELECT COUNT(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.type = "Studio"###context:CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR) |
###question:Who is the founder of Sony?###answer:SELECT founder FROM manufacturers WHERE name = 'Sony'###context:CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR) |
###question:Where is the headquarter of the company founded by James?###answer:SELECT headquarter FROM manufacturers WHERE founder = 'James'###context:CREATE TABLE manufacturers (headquarter VARCHAR, founder VARCHAR) |
###question:Find all manufacturers' names and their headquarters, sorted by the ones with highest revenue first.###answer:SELECT name, headquarter FROM manufacturers ORDER BY revenue DESC###context:CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR) |
###question:What are the average, maximum and total revenues of all companies?###answer:SELECT AVG(revenue), MAX(revenue), SUM(revenue) FROM manufacturers###context:CREATE TABLE manufacturers (revenue INTEGER) |
###question:How many companies were created by Andy?###answer:SELECT COUNT(*) FROM manufacturers WHERE founder = 'Andy'###context:CREATE TABLE manufacturers (founder VARCHAR) |
###question:Find the total revenue created by the companies whose headquarter is located at Austin.###answer:SELECT SUM(revenue) FROM manufacturers WHERE headquarter = 'Austin'###context:CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR) |
###question:What are the different cities listed?###answer:SELECT DISTINCT headquarter FROM manufacturers###context:CREATE TABLE manufacturers (headquarter VARCHAR) |
###question:Find the number of manufactures that are based in Tokyo or Beijing.###answer:SELECT COUNT(*) FROM manufacturers WHERE headquarter = 'Tokyo' OR headquarter = 'Beijing'###context:CREATE TABLE manufacturers (headquarter VARCHAR) |
###question:Find the founder of the company whose name begins with the letter 'S'.###answer:SELECT founder FROM manufacturers WHERE name LIKE 'S%'###context:CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR) |
###question:Find the name of companies whose revenue is between 100 and 150.###answer:SELECT name FROM manufacturers WHERE revenue BETWEEN 100 AND 150###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER) |
###question:What is the total revenue of all companies whose main office is at Tokyo or Taiwan?###answer:SELECT SUM(revenue) FROM manufacturers WHERE Headquarter = 'Tokyo' OR Headquarter = 'Taiwan'###context:CREATE TABLE manufacturers (revenue INTEGER, Headquarter VARCHAR) |
###question:Find the name of product that is produced by both companies Creative Labs and Sony.###answer:SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Creative Labs' INTERSECT SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony'###context:CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR) |
###question:Find the name, headquarter and founder of the manufacturer that has the highest revenue.###answer:SELECT name, headquarter, founder FROM manufacturers ORDER BY revenue DESC LIMIT 1###context:CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, founder VARCHAR, revenue VARCHAR) |
###question:Find the name, headquarter and revenue of all manufacturers sorted by their revenue in the descending order.###answer:SELECT name, headquarter, revenue FROM manufacturers ORDER BY revenue DESC###context:CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR) |
###question:Find the name of companies whose revenue is greater than the average revenue of all companies.###answer:SELECT name FROM manufacturers WHERE revenue > (SELECT AVG(revenue) FROM manufacturers)###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER) |
###question:Find the name of companies whose revenue is smaller than the revenue of all companies based in Austin.###answer:SELECT name FROM manufacturers WHERE revenue < (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin')###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER, headquarter VARCHAR) |
###question:Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin.###answer:SELECT SUM(revenue) FROM manufacturers WHERE revenue > (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin')###context:CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR) |
###question:Find the total revenue of companies of each founder.###answer:SELECT SUM(revenue), founder FROM manufacturers GROUP BY founder###context:CREATE TABLE manufacturers (founder VARCHAR, revenue INTEGER) |
###question:Find the name and revenue of the company that earns the highest revenue in each city.###answer:SELECT name, MAX(revenue), Headquarter FROM manufacturers GROUP BY Headquarter###context:CREATE TABLE manufacturers (name VARCHAR, Headquarter VARCHAR, revenue INTEGER) |
###question:Find the total revenue for each manufacturer.###answer:SELECT SUM(revenue), name FROM manufacturers GROUP BY name###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER) |
###question:Find the average prices of all products from each manufacture, and list each company's name.###answer:SELECT AVG(T1.price), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name###context:CREATE TABLE products (price INTEGER, Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR) |
###question:Find the number of different products that are produced by companies at different headquarter cities.###answer:SELECT COUNT(DISTINCT T1.name), T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter###context:CREATE TABLE manufacturers (Headquarter VARCHAR, code VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR) |
###question:Find number of products which Sony does not make.###answer:SELECT COUNT(DISTINCT name) FROM products WHERE NOT name IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')###context:CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR) |
###question:Find the name of companies that do not make DVD drive.###answer:SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'###context:CREATE TABLE manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Manufacturer VARCHAR, name VARCHAR); CREATE TABLE manufacturers (name VARCHAR) |
###question:Find the number of products for each manufacturer, showing the name of each company.###answer:SELECT COUNT(*), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name###context:CREATE TABLE products (Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR) |
###question:Select the names of all the products in the store.###answer:SELECT Name FROM Products###context:CREATE TABLE Products (Name VARCHAR) |
###question:Select the names and the prices of all the products in the store.###answer:SELECT name, price FROM products###context:CREATE TABLE products (name VARCHAR, price VARCHAR) |
###question:Select the name of the products with a price less than or equal to $200.###answer:SELECT name FROM products WHERE price <= 200###context:CREATE TABLE products (name VARCHAR, price VARCHAR) |
###question:Find all information of all the products with a price between $60 and $120.###answer:SELECT * FROM products WHERE price BETWEEN 60 AND 120###context:CREATE TABLE products (price INTEGER) |
###question:Compute the average price of all the products.###answer:SELECT AVG(price) FROM products###context:CREATE TABLE products (price INTEGER) |
###question:Compute the average price of all products with manufacturer code equal to 2.###answer:SELECT AVG(price) FROM products WHERE Manufacturer = 2###context:CREATE TABLE products (price INTEGER, Manufacturer VARCHAR) |
###question:Compute the number of products with a price larger than or equal to $180.###answer:SELECT COUNT(*) FROM products WHERE price >= 180###context:CREATE TABLE products (price VARCHAR) |
###question:Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order).###answer:SELECT name, price FROM products WHERE price >= 180 ORDER BY price DESC, name###context:CREATE TABLE products (name VARCHAR, price VARCHAR) |
###question:Select all the data from the products and each product's manufacturer.###answer:SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code###context:CREATE TABLE products (manufacturer VARCHAR); CREATE TABLE Manufacturers (code VARCHAR) |
###question:Select the average price of each manufacturer's products, showing only the manufacturer's code.###answer:SELECT AVG(Price), Manufacturer FROM Products GROUP BY Manufacturer###context:CREATE TABLE Products (Manufacturer VARCHAR, Price INTEGER) |
###question:Select the average price of each manufacturer's products, showing the manufacturer's name.###answer:SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name###context:CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR) |
###question:Select the names of manufacturer whose products have an average price higher than or equal to $150.###answer:SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING AVG(T1.price) >= 150###context:CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER) |
###question:Select the name and price of the cheapest product.###answer:SELECT name, price FROM Products ORDER BY price LIMIT 1###context:CREATE TABLE Products (name VARCHAR, price VARCHAR) |
###question:Select the name of each manufacturer along with the name and price of its most expensive product.###answer:SELECT T1.Name, MAX(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name###context:CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Name VARCHAR, Price INTEGER, manufacturer VARCHAR) |
###question:Select the code of the product that is cheapest in each product category.###answer:SELECT code, name, MIN(price) FROM products GROUP BY name###context:CREATE TABLE products (code VARCHAR, name VARCHAR, price INTEGER) |
###question:What is the id of the problem log that is created most recently?###answer:SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1###context:CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR) |
###question:What is the oldest log id and its corresponding problem id?###answer:SELECT problem_log_id, problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1###context:CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR) |
###question:Find all the ids and dates of the logs for the problem whose id is 10.###answer:SELECT problem_log_id, log_entry_date FROM problem_log WHERE problem_id = 10###context:CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR, problem_id VARCHAR) |
###question:List all the log ids and their descriptions from the problem logs.###answer:SELECT problem_log_id, log_entry_description FROM problem_log###context:CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_description VARCHAR) |
###question:List the first and last names of all distinct staff members who are assigned to the problem whose id is 1.###answer:SELECT DISTINCT staff_first_name, staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1###context:CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) |
###question:List the problem id and log id which are assigned to the staff named Rylan Homenick.###answer:SELECT DISTINCT T2.problem_id, T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"###context:CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR) |
###question:How many problems are there for product voluptatem?###answer:SELECT COUNT(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR) |
###question:How many problems does the product with the most problems have? List the number of the problems and product name.###answer:SELECT COUNT(*), T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) |
###question:Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop.###answer:SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"###context:CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR); CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR) |
###question:Find the ids of the problems that are reported by the staff whose last name is Bosco.###answer:SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"###context:CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR) |
###question:What are the ids of the problems which are reported after 1978-06-26?###answer:SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"###context:CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER) |
###question:What are the ids of the problems which are reported before 1978-06-26?###answer:SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"###context:CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER) |
###question:For each product which has problems, what are the number of problems and the product id?###answer:SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR) |
###question:For each product that has problems, find the number of problems reported after 1986-11-13 and the product id?###answer:SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id###context:CREATE TABLE product (product_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER) |
###question:List the names of all the distinct product names in alphabetical order?###answer:SELECT DISTINCT product_name FROM product ORDER BY product_name###context:CREATE TABLE product (product_name VARCHAR) |
###question:List all the distinct product names ordered by product id?###answer:SELECT DISTINCT product_name FROM product ORDER BY product_id###context:CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) |
###question:What are the id of problems reported by the staff named Dameon Frami or Jolie Weber?###answer:SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"###context:CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR) |
###question:What are the product ids for the problems reported by Christop Berge with closure authorised by Ashley Medhurst?###answer:SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"###context:CREATE TABLE problems (reported_by_staff_id VARCHAR, closure_authorised_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR) |
###question:What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte?###answer:SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < (SELECT MIN(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte")###context:CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) |
###question:What are the ids of the problems reported after the date of any problems reported by Rylan Homenick?###answer:SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > (SELECT MAX(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick")###context:CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) |
###question:Find the top 3 products which have the largest number of problems?###answer:SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY COUNT(*) DESC LIMIT 3###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) |
###question:List the ids of the problems from the product "voluptatem" that are reported after 1995?###answer:SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"###context:CREATE TABLE problems (problem_id VARCHAR, product_id VARCHAR, date_problem_reported VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR) |
###question:Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"?###answer:SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"###context:CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_first_name VARCHAR, staff_last_name VARCHAR, staff_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR) |
###question:Find the products which have problems reported by both Lacey Bosco and Kenton Champlin?###answer:SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"###context:CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR) |
###question:How many branches where have more than average number of memberships are there?###answer:SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch)###context:CREATE TABLE branch (membership_amount INTEGER) |
###question:Show name, address road, and city for all branches sorted by open year.###answer:SELECT name, address_road, city FROM branch ORDER BY open_year###context:CREATE TABLE branch (name VARCHAR, address_road VARCHAR, city VARCHAR, open_year VARCHAR) |
###question:What are names for top three branches with most number of membership?###answer:SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3###context:CREATE TABLE branch (name VARCHAR, membership_amount VARCHAR) |
###question:Show all distinct city where branches with at least 100 memberships are located.###answer:SELECT DISTINCT city FROM branch WHERE membership_amount >= 100###context:CREATE TABLE branch (city VARCHAR, membership_amount VARCHAR) |
###question:List all open years when at least two shops are opened.###answer:SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2###context:CREATE TABLE branch (open_year VARCHAR) |
###question:Show minimum and maximum amount of memberships for all branches opened in 2011 or located at city London.###answer:SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London'###context:CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR) |
###question:Show the city and the number of branches opened before 2010 for each city.###answer:SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city###context:CREATE TABLE branch (city VARCHAR, open_year INTEGER) |
###question:How many different levels do members have?###answer:SELECT COUNT(DISTINCT LEVEL) FROM member###context:CREATE TABLE member (LEVEL VARCHAR) |
###question:Show card number, name, and hometown for all members in a descending order of level.###answer:SELECT card_number, name, hometown FROM member ORDER BY LEVEL DESC###context:CREATE TABLE member (card_number VARCHAR, name VARCHAR, hometown VARCHAR, LEVEL VARCHAR) |
###question:Show the membership level with most number of members.###answer:SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE member (LEVEL VARCHAR) |
###question:Show all member names and registered branch names sorted by register year.###answer:SELECT T3.name, T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year###context:CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR) |
###question:Show all branch names with the number of members in each branch registered after 2015.###answer:SELECT T2.name, COUNT(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id###context:CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year INTEGER) |
###question:Show member names without any registered branch.###answer:SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch)###context:CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (name VARCHAR, member_id VARCHAR) |
###question:List the branch name and city without any registered members.###answer:SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch)###context:CREATE TABLE membership_register_branch (name VARCHAR, city VARCHAR, branch_id VARCHAR); CREATE TABLE branch (name VARCHAR, city VARCHAR, branch_id VARCHAR) |
###question:What is the name and open year for the branch with most number of memberships registered in 2016?###answer:SELECT T2.name, T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, open_year VARCHAR, branch_id VARCHAR) |
###question:Show the member name and hometown who registered a branch in 2016.###answer:SELECT T2.name, T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016###context:CREATE TABLE member (name VARCHAR, hometown VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (member_id VARCHAR, register_year VARCHAR) |
###question:Show all city with a branch opened in 2001 and a branch with more than 100 membership.###answer:SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100###context:CREATE TABLE branch (city VARCHAR, open_year VARCHAR, membership_amount VARCHAR) |
###question:Show all cities without a branch having more than 100 memberships.###answer:SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100###context:CREATE TABLE branch (city VARCHAR, membership_amount INTEGER) |
###question:What is the sum of total pounds of purchase in year 2018 for all branches in London?###answer:SELECT SUM(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018###context:CREATE TABLE purchase (branch_id VARCHAR, year VARCHAR); CREATE TABLE branch (branch_id VARCHAR, city VARCHAR) |
###question:What is the total number of purchases for members with level 6?###answer:SELECT COUNT(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6###context:CREATE TABLE member (member_id VARCHAR, level VARCHAR); CREATE TABLE purchase (member_id VARCHAR) |
###question:Find the name of branches where have some members whose hometown is in Louisville, Kentucky and some in Hiram, Georgia.###answer:SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Louisville , Kentucky' INTERSECT SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Hiram , Georgia'###context:CREATE TABLE member (member_id VARCHAR, Hometown VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR) |
###question:list the card number of all members whose hometown address includes word "Kentucky".###answer:SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%"###context:CREATE TABLE member (card_number VARCHAR, Hometown VARCHAR) |
###question:Find the number of students in total.###answer:SELECT COUNT(*) FROM STUDENT###context:CREATE TABLE STUDENT (Id VARCHAR) |
###question:Find the number of voting records in total.###answer:SELECT COUNT(*) FROM VOTING_RECORD###context:CREATE TABLE VOTING_RECORD (Id VARCHAR) |
###question:Find the distinct number of president votes.###answer:SELECT COUNT(DISTINCT President_Vote) FROM VOTING_RECORD###context:CREATE TABLE VOTING_RECORD (President_Vote VARCHAR) |
###question:Find the maximum age of all the students.###answer:SELECT MAX(Age) FROM STUDENT###context:CREATE TABLE STUDENT (Age INTEGER) |
###question:Find the last names of students with major 50.###answer:SELECT LName FROM STUDENT WHERE Major = 50###context:CREATE TABLE STUDENT (LName VARCHAR, Major VARCHAR) |
###question:Find the first names of students with age above 22.###answer:SELECT Fname FROM STUDENT WHERE Age > 22###context:CREATE TABLE STUDENT (Fname VARCHAR, Age INTEGER) |
###question:What are the majors of male (sex is M) students?###answer:SELECT Major FROM STUDENT WHERE Sex = "M"###context:CREATE TABLE STUDENT (Major VARCHAR, Sex VARCHAR) |
###question:What is the average age of female (sex is F) students?###answer:SELECT AVG(Age) FROM STUDENT WHERE Sex = "F"###context:CREATE TABLE STUDENT (Age INTEGER, Sex VARCHAR) |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.