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###question:Show the start dates and end dates of all the apartment bookings made by guests with gender code "Female".###answer:SELECT T1.booking_start_date, T1.booking_start_date FROM Apartment_Bookings AS T1 JOIN Guests AS T2 ON T1.guest_id = T2.guest_id WHERE T2.gender_code = "Female"###context:CREATE TABLE Apartment_Bookings (booking_start_date VARCHAR, guest_id VARCHAR); CREATE TABLE Guests (guest_id VARCHAR, gender_code VARCHAR) |
###question:Show the first names and last names of all the guests that have apartment bookings with status code "Confirmed".###answer:SELECT T2.guest_first_name, T2.guest_last_name FROM Apartment_Bookings AS T1 JOIN Guests AS T2 ON T1.guest_id = T2.guest_id WHERE T1.booking_status_code = "Confirmed"###context:CREATE TABLE Apartment_Bookings (guest_id VARCHAR, booking_status_code VARCHAR); CREATE TABLE Guests (guest_first_name VARCHAR, guest_last_name VARCHAR, guest_id VARCHAR) |
###question:Show the facility codes of apartments with more than 4 bedrooms.###answer:SELECT T1.facility_code FROM Apartment_Facilities AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T2.bedroom_count > 4###context:CREATE TABLE Apartment_Facilities (facility_code VARCHAR, apt_id VARCHAR); CREATE TABLE Apartments (apt_id VARCHAR, bedroom_count INTEGER) |
###question:Show the total number of rooms of all apartments with facility code "Gym".###answer:SELECT SUM(T2.room_count) FROM Apartment_Facilities AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T1.facility_code = "Gym"###context:CREATE TABLE Apartments (room_count INTEGER, apt_id VARCHAR); CREATE TABLE Apartment_Facilities (apt_id VARCHAR, facility_code VARCHAR) |
###question:Show the total number of rooms of the apartments in the building with short name "Columbus Square".###answer:SELECT SUM(T2.room_count) FROM Apartment_Buildings AS T1 JOIN Apartments AS T2 ON T1.building_id = T2.building_id WHERE T1.building_short_name = "Columbus Square"###context:CREATE TABLE Apartment_Buildings (building_id VARCHAR, building_short_name VARCHAR); CREATE TABLE Apartments (room_count INTEGER, building_id VARCHAR) |
###question:Show the addresses of the buildings that have apartments with more than 2 bathrooms.###answer:SELECT T1.building_address FROM Apartment_Buildings AS T1 JOIN Apartments AS T2 ON T1.building_id = T2.building_id WHERE T2.bathroom_count > 2###context:CREATE TABLE Apartment_Buildings (building_address VARCHAR, building_id VARCHAR); CREATE TABLE Apartments (building_id VARCHAR, bathroom_count INTEGER) |
###question:Show the apartment type codes and apartment numbers in the buildings managed by "Kyle".###answer:SELECT T2.apt_type_code, T2.apt_number FROM Apartment_Buildings AS T1 JOIN Apartments AS T2 ON T1.building_id = T2.building_id WHERE T1.building_manager = "Kyle"###context:CREATE TABLE Apartment_Buildings (building_id VARCHAR, building_manager VARCHAR); CREATE TABLE Apartments (apt_type_code VARCHAR, apt_number VARCHAR, building_id VARCHAR) |
###question:Show the booking status code and the corresponding number of bookings.###answer:SELECT booking_status_code, COUNT(*) FROM Apartment_Bookings GROUP BY booking_status_code###context:CREATE TABLE Apartment_Bookings (booking_status_code VARCHAR) |
###question:Return all the apartment numbers sorted by the room count in ascending order.###answer:SELECT apt_number FROM Apartments ORDER BY room_count###context:CREATE TABLE Apartments (apt_number VARCHAR, room_count VARCHAR) |
###question:Return the apartment number with the largest number of bedrooms.###answer:SELECT apt_number FROM Apartments ORDER BY bedroom_count DESC LIMIT 1###context:CREATE TABLE Apartments (apt_number VARCHAR, bedroom_count VARCHAR) |
###question:Show the apartment type codes and the corresponding number of apartments sorted by the number of apartments in ascending order.###answer:SELECT apt_type_code, COUNT(*) FROM Apartments GROUP BY apt_type_code ORDER BY COUNT(*)###context:CREATE TABLE Apartments (apt_type_code VARCHAR) |
###question:Show the top 3 apartment type codes sorted by the average number of rooms in descending order.###answer:SELECT apt_type_code FROM Apartments GROUP BY apt_type_code ORDER BY AVG(room_count) DESC LIMIT 3###context:CREATE TABLE Apartments (apt_type_code VARCHAR, room_count INTEGER) |
###question:Show the apartment type code that has the largest number of total rooms, together with the number of bathrooms and number of bedrooms.###answer:SELECT apt_type_code, bathroom_count, bedroom_count FROM Apartments GROUP BY apt_type_code ORDER BY SUM(room_count) DESC LIMIT 1###context:CREATE TABLE Apartments (apt_type_code VARCHAR, bathroom_count VARCHAR, bedroom_count VARCHAR, room_count INTEGER) |
###question:Show the most common apartment type code.###answer:SELECT apt_type_code FROM Apartments GROUP BY apt_type_code ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Apartments (apt_type_code VARCHAR) |
###question:Show the most common apartment type code among apartments with more than 1 bathroom.###answer:SELECT apt_type_code FROM Apartments WHERE bathroom_count > 1 GROUP BY apt_type_code ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE Apartments (apt_type_code VARCHAR, bathroom_count INTEGER) |
###question:Show each apartment type code, and the maximum and minimum number of rooms for each type.###answer:SELECT apt_type_code, MAX(room_count), MIN(room_count) FROM Apartments GROUP BY apt_type_code###context:CREATE TABLE Apartments (apt_type_code VARCHAR, room_count INTEGER) |
###question:Show each gender code and the corresponding count of guests sorted by the count in descending order.###answer:SELECT gender_code, COUNT(*) FROM Guests GROUP BY gender_code ORDER BY COUNT(*) DESC###context:CREATE TABLE Guests (gender_code VARCHAR) |
###question:How many apartments do not have any facility?###answer:SELECT COUNT(*) FROM Apartments WHERE NOT apt_id IN (SELECT apt_id FROM Apartment_Facilities)###context:CREATE TABLE Apartment_Facilities (apt_id VARCHAR); CREATE TABLE Apartments (apt_id VARCHAR) |
###question:Show the apartment numbers of apartments with bookings that have status code both "Provisional" and "Confirmed"###answer:SELECT T2.apt_number FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T1.booking_status_code = "Confirmed" INTERSECT SELECT T2.apt_number FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T1.booking_status_code = "Provisional"###context:CREATE TABLE Apartments (apt_number VARCHAR, apt_id VARCHAR); CREATE TABLE Apartment_Bookings (apt_id VARCHAR, booking_status_code VARCHAR) |
###question:Show the apartment numbers of apartments with unit status availability of both 0 and 1.###answer:SELECT T1.apt_number FROM Apartments AS T1 JOIN View_Unit_Status AS T2 ON T1.apt_id = T2.apt_id WHERE T2.available_yn = 0 INTERSECT SELECT T1.apt_number FROM Apartments AS T1 JOIN View_Unit_Status AS T2 ON T1.apt_id = T2.apt_id WHERE T2.available_yn = 1###context:CREATE TABLE View_Unit_Status (apt_id VARCHAR, available_yn VARCHAR); CREATE TABLE Apartments (apt_number VARCHAR, apt_id VARCHAR) |
###question:How many games are held after season 2007?###answer:SELECT COUNT(*) FROM game WHERE season > 2007###context:CREATE TABLE game (season INTEGER) |
###question:List the dates of games by the home team name in descending order.###answer:SELECT Date FROM game ORDER BY home_team DESC###context:CREATE TABLE game (Date VARCHAR, home_team VARCHAR) |
###question:List the season, home team, away team of all the games.###answer:SELECT season, home_team, away_team FROM game###context:CREATE TABLE game (season VARCHAR, home_team VARCHAR, away_team VARCHAR) |
###question:What are the maximum, minimum and average home games each stadium held?###answer:SELECT MAX(home_games), MIN(home_games), AVG(home_games) FROM stadium###context:CREATE TABLE stadium (home_games INTEGER) |
###question:What is the average attendance of stadiums with capacity percentage higher than 100%?###answer:SELECT average_attendance FROM stadium WHERE capacity_percentage > 100###context:CREATE TABLE stadium (average_attendance VARCHAR, capacity_percentage INTEGER) |
###question:What are the player name, number of matches, and information source for players who do not suffer from injury of 'Knee problem'?###answer:SELECT player, number_of_matches, SOURCE FROM injury_accident WHERE injury <> 'Knee problem'###context:CREATE TABLE injury_accident (player VARCHAR, number_of_matches VARCHAR, SOURCE VARCHAR, injury VARCHAR) |
###question:What is the season of the game which causes the player 'Walter Samuel' to get injured?###answer:SELECT T1.season FROM game AS T1 JOIN injury_accident AS T2 ON T1.id = T2.game_id WHERE T2.player = 'Walter Samuel'###context:CREATE TABLE injury_accident (game_id VARCHAR, player VARCHAR); CREATE TABLE game (season VARCHAR, id VARCHAR) |
###question:What are the ids, scores, and dates of the games which caused at least two injury accidents?###answer:SELECT T1.id, T1.score, T1.date FROM game AS T1 JOIN injury_accident AS T2 ON T2.game_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 2###context:CREATE TABLE game (id VARCHAR, score VARCHAR, date VARCHAR); CREATE TABLE injury_accident (game_id VARCHAR) |
###question:What are the id and name of the stadium where the most injury accidents happened?###answer:SELECT T1.id, T1.name FROM stadium AS T1 JOIN game AS T2 ON T1.id = T2.stadium_id JOIN injury_accident AS T3 ON T2.id = T3.game_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE stadium (id VARCHAR, name VARCHAR); CREATE TABLE injury_accident (game_id VARCHAR); CREATE TABLE game (stadium_id VARCHAR, id VARCHAR) |
###question:In which season and which stadium did any player have an injury of 'Foot injury' or 'Knee problem'?###answer:SELECT T1.season, T2.name FROM game AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.id JOIN injury_accident AS T3 ON T1.id = T3.game_id WHERE T3.injury = 'Foot injury' OR T3.injury = 'Knee problem'###context:CREATE TABLE stadium (name VARCHAR, id VARCHAR); CREATE TABLE injury_accident (game_id VARCHAR, injury VARCHAR); CREATE TABLE game (season VARCHAR, stadium_id VARCHAR, id VARCHAR) |
###question:How many different kinds of information sources are there for injury accidents?###answer:SELECT COUNT(DISTINCT SOURCE) FROM injury_accident###context:CREATE TABLE injury_accident (SOURCE VARCHAR) |
###question:How many games are free of injury accidents?###answer:SELECT COUNT(*) FROM game WHERE NOT id IN (SELECT game_id FROM injury_accident)###context:CREATE TABLE injury_accident (id VARCHAR, game_id VARCHAR); CREATE TABLE game (id VARCHAR, game_id VARCHAR) |
###question:How many distinct kinds of injuries happened after season 2010?###answer:SELECT COUNT(DISTINCT T1.injury) FROM injury_accident AS T1 JOIN game AS T2 ON T1.game_id = T2.id WHERE T2.season > 2010###context:CREATE TABLE injury_accident (injury VARCHAR, game_id VARCHAR); CREATE TABLE game (id VARCHAR, season INTEGER) |
###question:List the name of the stadium where both the player 'Walter Samuel' and the player 'Thiago Motta' got injured.###answer:SELECT T2.name FROM game AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.id JOIN injury_accident AS T3 ON T1.id = T3.game_id WHERE T3.player = 'Walter Samuel' INTERSECT SELECT T2.name FROM game AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.id JOIN injury_accident AS T3 ON T1.id = T3.game_id WHERE T3.player = 'Thiago Motta'###context:CREATE TABLE stadium (name VARCHAR, id VARCHAR); CREATE TABLE game (stadium_id VARCHAR, id VARCHAR); CREATE TABLE injury_accident (game_id VARCHAR, player VARCHAR) |
###question:Show the name, average attendance, total attendance for stadiums where no accidents happened.###answer:SELECT name, average_attendance, total_attendance FROM stadium EXCEPT SELECT T2.name, T2.average_attendance, T2.total_attendance FROM game AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.id JOIN injury_accident AS T3 ON T1.id = T3.game_id###context:CREATE TABLE stadium (name VARCHAR, average_attendance VARCHAR, total_attendance VARCHAR, id VARCHAR); CREATE TABLE stadium (name VARCHAR, average_attendance VARCHAR, total_attendance VARCHAR); CREATE TABLE game (stadium_id VARCHAR, id VARCHAR); CREATE TABLE injury_accident (game_id VARCHAR) |
###question:Which stadium name contains the substring "Bank"?###answer:SELECT name FROM stadium WHERE name LIKE "%Bank%"###context:CREATE TABLE stadium (name VARCHAR) |
###question:How many games has each stadium held?###answer:SELECT T1.id, COUNT(*) FROM stadium AS T1 JOIN game AS T2 ON T1.id = T2.stadium_id GROUP BY T1.id###context:CREATE TABLE stadium (id VARCHAR); CREATE TABLE game (stadium_id VARCHAR) |
###question:For each injury accident, find the date of the game and the name of the injured player in the game, and sort the results in descending order of game season.###answer:SELECT T1.date, T2.player FROM game AS T1 JOIN injury_accident AS T2 ON T1.id = T2.game_id ORDER BY T1.season DESC###context:CREATE TABLE game (date VARCHAR, id VARCHAR, season VARCHAR); CREATE TABLE injury_accident (player VARCHAR, game_id VARCHAR) |
###question:List all country and league names.###answer:SELECT T1.name, T2.name FROM Country AS T1 JOIN League AS T2 ON T1.id = T2.country_id###context:CREATE TABLE League (name VARCHAR, country_id VARCHAR); CREATE TABLE Country (name VARCHAR, id VARCHAR) |
###question:How many leagues are there in England?###answer:SELECT COUNT(*) FROM Country AS T1 JOIN League AS T2 ON T1.id = T2.country_id WHERE T1.name = "England"###context:CREATE TABLE League (country_id VARCHAR); CREATE TABLE Country (id VARCHAR, name VARCHAR) |
###question:What is the average weight of all players?###answer:SELECT AVG(weight) FROM Player###context:CREATE TABLE Player (weight INTEGER) |
###question:What is the maximum and minimum height of all players?###answer:SELECT MAX(weight), MIN(weight) FROM Player###context:CREATE TABLE Player (weight INTEGER) |
###question:List all player names who have an overall rating higher than the average.###answer:SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id WHERE T2.overall_rating > (SELECT AVG(overall_rating) FROM Player_Attributes)###context:CREATE TABLE Player (player_name VARCHAR, player_api_id VARCHAR); CREATE TABLE Player_Attributes (overall_rating INTEGER); CREATE TABLE Player_Attributes (player_api_id VARCHAR, overall_rating INTEGER) |
###question:What are the names of players who have the best dribbling?###answer:SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id WHERE T2.dribbling = (SELECT MAX(overall_rating) FROM Player_Attributes)###context:CREATE TABLE Player (player_name VARCHAR, player_api_id VARCHAR); CREATE TABLE Player_Attributes (player_api_id VARCHAR, dribbling VARCHAR); CREATE TABLE Player_Attributes (overall_rating INTEGER) |
###question:List the names of all players who have a crossing score higher than 90 and prefer their right foot.###answer:SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id WHERE T2.crossing > 90 AND T2.preferred_foot = "right"###context:CREATE TABLE Player (player_name VARCHAR, player_api_id VARCHAR); CREATE TABLE Player_Attributes (player_api_id VARCHAR, crossing VARCHAR, preferred_foot VARCHAR) |
###question:List the names of all left-footed players who have overall rating between 85 and 90.###answer:SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id WHERE T2.preferred_foot = "left" AND T2.overall_rating >= 85 AND T2.overall_rating <= 90###context:CREATE TABLE Player (player_name VARCHAR, player_api_id VARCHAR); CREATE TABLE Player_Attributes (player_api_id VARCHAR, overall_rating VARCHAR, preferred_foot VARCHAR) |
###question:What is the average rating for right-footed players and left-footed players?###answer:SELECT preferred_foot, AVG(overall_rating) FROM Player_Attributes GROUP BY preferred_foot###context:CREATE TABLE Player_Attributes (preferred_foot VARCHAR, overall_rating INTEGER) |
###question:Of all players with an overall rating greater than 80, how many are right-footed and left-footed?###answer:SELECT preferred_foot, COUNT(*) FROM Player_Attributes WHERE overall_rating > 80 GROUP BY preferred_foot###context:CREATE TABLE Player_Attributes (preferred_foot VARCHAR, overall_rating INTEGER) |
###question:List all of the player ids with a height of at least 180cm and an overall rating higher than 85.###answer:SELECT player_api_id FROM Player WHERE height >= 180 INTERSECT SELECT player_api_id FROM Player_Attributes WHERE overall_rating > 85###context:CREATE TABLE Player_Attributes (player_api_id VARCHAR, height VARCHAR, overall_rating INTEGER); CREATE TABLE Player (player_api_id VARCHAR, height VARCHAR, overall_rating INTEGER) |
###question:List all of the ids for left-footed players with a height between 180cm and 190cm.###answer:SELECT player_api_id FROM Player WHERE height >= 180 AND height <= 190 INTERSECT SELECT player_api_id FROM Player_Attributes WHERE preferred_foot = "left"###context:CREATE TABLE Player_Attributes (player_api_id VARCHAR, preferred_foot VARCHAR, height VARCHAR); CREATE TABLE Player (player_api_id VARCHAR, preferred_foot VARCHAR, height VARCHAR) |
###question:Who are the top 3 players in terms of overall rating?###answer:SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id ORDER BY overall_rating DESC LIMIT 3###context:CREATE TABLE Player (player_name VARCHAR, player_api_id VARCHAR); CREATE TABLE Player_Attributes (player_api_id VARCHAR) |
###question:List the names and birthdays of the top five players in terms of potential.###answer:SELECT DISTINCT T1.player_name, T1.birthday FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id ORDER BY potential DESC LIMIT 5###context:CREATE TABLE Player_Attributes (player_api_id VARCHAR); CREATE TABLE Player (player_name VARCHAR, birthday VARCHAR, player_api_id VARCHAR) |
###question:How many performances are there?###answer:SELECT COUNT(*) FROM performance###context:CREATE TABLE performance (Id VARCHAR) |
###question:List the hosts of performances in ascending order of attendance.###answer:SELECT HOST FROM performance ORDER BY Attendance###context:CREATE TABLE performance (HOST VARCHAR, Attendance VARCHAR) |
###question:What are the dates and locations of performances?###answer:SELECT Date, LOCATION FROM performance###context:CREATE TABLE performance (Date VARCHAR, LOCATION VARCHAR) |
###question:Show the attendances of the performances at location "TD Garden" or "Bell Centre"###answer:SELECT Attendance FROM performance WHERE LOCATION = "TD Garden" OR LOCATION = "Bell Centre"###context:CREATE TABLE performance (Attendance VARCHAR, LOCATION VARCHAR) |
###question:What is the average number of attendees for performances?###answer:SELECT AVG(Attendance) FROM performance###context:CREATE TABLE performance (Attendance INTEGER) |
###question:What is the date of the performance with the highest number of attendees?###answer:SELECT Date FROM performance ORDER BY Attendance DESC LIMIT 1###context:CREATE TABLE performance (Date VARCHAR, Attendance VARCHAR) |
###question:Show different locations and the number of performances at each location.###answer:SELECT LOCATION, COUNT(*) FROM performance GROUP BY LOCATION###context:CREATE TABLE performance (LOCATION VARCHAR) |
###question:Show the most common location of performances.###answer:SELECT LOCATION FROM performance GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1###context:CREATE TABLE performance (LOCATION VARCHAR) |
###question:Show the locations that have at least two performances.###answer:SELECT LOCATION FROM performance GROUP BY LOCATION HAVING COUNT(*) >= 2###context:CREATE TABLE performance (LOCATION VARCHAR) |
###question:Show the locations that have both performances with more than 2000 attendees and performances with less than 1000 attendees.###answer:SELECT LOCATION FROM performance WHERE Attendance > 2000 INTERSECT SELECT LOCATION FROM performance WHERE Attendance < 1000###context:CREATE TABLE performance (LOCATION VARCHAR, Attendance INTEGER) |
###question:Show the names of members and the location of the performances they attended.###answer:SELECT T2.Name, T3.Location FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID###context:CREATE TABLE performance (Location VARCHAR, Performance_ID VARCHAR); CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR); CREATE TABLE member_attendance (Member_ID VARCHAR, Performance_ID VARCHAR) |
###question:Show the names of members and the location of performances they attended in ascending alphabetical order of their names.###answer:SELECT T2.Name, T3.Location FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID ORDER BY T2.Name###context:CREATE TABLE performance (Location VARCHAR, Performance_ID VARCHAR); CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR); CREATE TABLE member_attendance (Member_ID VARCHAR, Performance_ID VARCHAR) |
###question:Show the dates of performances with attending members whose roles are "Violin".###answer:SELECT T3.Date FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID WHERE T2.Role = "Violin"###context:CREATE TABLE performance (Date VARCHAR, Performance_ID VARCHAR); CREATE TABLE member (Member_ID VARCHAR, Role VARCHAR); CREATE TABLE member_attendance (Member_ID VARCHAR, Performance_ID VARCHAR) |
###question:Show the names of members and the dates of performances they attended in descending order of attendance of the performances.###answer:SELECT T2.Name, T3.Date FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID ORDER BY T3.Attendance DESC###context:CREATE TABLE performance (Date VARCHAR, Performance_ID VARCHAR, Attendance VARCHAR); CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR); CREATE TABLE member_attendance (Member_ID VARCHAR, Performance_ID VARCHAR) |
###question:List the names of members who did not attend any performance.###answer:SELECT Name FROM member WHERE NOT Member_ID IN (SELECT Member_ID FROM member_attendance)###context:CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR); CREATE TABLE member_attendance (Name VARCHAR, Member_ID VARCHAR) |
###question:Find the buildings which have rooms with capacity more than 50.###answer:SELECT DISTINCT building FROM classroom WHERE capacity > 50###context:CREATE TABLE classroom (building VARCHAR, capacity INTEGER) |
###question:Count the number of rooms that are not in the Lamberton building.###answer:SELECT COUNT(*) FROM classroom WHERE building <> 'Lamberton'###context:CREATE TABLE classroom (building VARCHAR) |
###question:What is the name and building of the departments whose budget is more than the average budget?###answer:SELECT dept_name, building FROM department WHERE budget > (SELECT AVG(budget) FROM department)###context:CREATE TABLE department (dept_name VARCHAR, building VARCHAR, budget INTEGER) |
###question:Find the room number of the rooms which can sit 50 to 100 students and their buildings.###answer:SELECT building, room_number FROM classroom WHERE capacity BETWEEN 50 AND 100###context:CREATE TABLE classroom (building VARCHAR, room_number VARCHAR, capacity INTEGER) |
###question:Find the name and building of the department with the highest budget.###answer:SELECT dept_name, building FROM department ORDER BY budget DESC LIMIT 1###context:CREATE TABLE department (dept_name VARCHAR, building VARCHAR, budget VARCHAR) |
###question:What is the name of the student who has the highest total credits in the History department.###answer:SELECT name FROM student WHERE dept_name = 'History' ORDER BY tot_cred DESC LIMIT 1###context:CREATE TABLE student (name VARCHAR, dept_name VARCHAR, tot_cred VARCHAR) |
###question:How many rooms does the Lamberton building have?###answer:SELECT COUNT(*) FROM classroom WHERE building = 'Lamberton'###context:CREATE TABLE classroom (building VARCHAR) |
###question:How many students have advisors?###answer:SELECT COUNT(DISTINCT s_id) FROM advisor###context:CREATE TABLE advisor (s_id VARCHAR) |
###question:How many departments offer courses?###answer:SELECT COUNT(DISTINCT dept_name) FROM course###context:CREATE TABLE course (dept_name VARCHAR) |
###question:How many different courses offered by Physics department?###answer:SELECT COUNT(DISTINCT course_id) FROM course WHERE dept_name = 'Physics'###context:CREATE TABLE course (course_id VARCHAR, dept_name VARCHAR) |
###question:Find the title of courses that have two prerequisites?###answer:SELECT T1.title FROM course AS T1 JOIN prereq AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id HAVING COUNT(*) = 2###context:CREATE TABLE prereq (course_id VARCHAR); CREATE TABLE course (title VARCHAR, course_id VARCHAR) |
###question:Find the title, credit, and department name of courses that have more than one prerequisites?###answer:SELECT T1.title, T1.credits, T1.dept_name FROM course AS T1 JOIN prereq AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id HAVING COUNT(*) > 1###context:CREATE TABLE prereq (course_id VARCHAR); CREATE TABLE course (title VARCHAR, credits VARCHAR, dept_name VARCHAR, course_id VARCHAR) |
###question:How many courses that do not have prerequisite?###answer:SELECT COUNT(*) FROM course WHERE NOT course_id IN (SELECT course_id FROM prereq)###context:CREATE TABLE prereq (course_id VARCHAR); CREATE TABLE course (course_id VARCHAR) |
###question:Find the name of the courses that do not have any prerequisite?###answer:SELECT title FROM course WHERE NOT course_id IN (SELECT course_id FROM prereq)###context:CREATE TABLE prereq (title VARCHAR, course_id VARCHAR); CREATE TABLE course (title VARCHAR, course_id VARCHAR) |
###question:How many different instructors have taught some course?###answer:SELECT COUNT(DISTINCT id) FROM teaches###context:CREATE TABLE teaches (id VARCHAR) |
###question:Find the total budgets of the Marketing or Finance department.###answer:SELECT SUM(budget) FROM department WHERE dept_name = 'Marketing' OR dept_name = 'Finance'###context:CREATE TABLE department (budget INTEGER, dept_name VARCHAR) |
###question:Find the department name of the instructor whose name contains 'Soisalon'.###answer:SELECT dept_name FROM instructor WHERE name LIKE '%Soisalon%'###context:CREATE TABLE instructor (dept_name VARCHAR, name VARCHAR) |
###question:How many rooms whose capacity is less than 50 does the Lamberton building have?###answer:SELECT COUNT(*) FROM classroom WHERE building = 'Lamberton' AND capacity < 50###context:CREATE TABLE classroom (building VARCHAR, capacity VARCHAR) |
###question:Find the name and budget of departments whose budgets are more than the average budget.###answer:SELECT dept_name, budget FROM department WHERE budget > (SELECT AVG(budget) FROM department)###context:CREATE TABLE department (dept_name VARCHAR, budget INTEGER) |
###question:what is the name of the instructor who is in Statistics department and earns the lowest salary?###answer:SELECT name FROM instructor WHERE dept_name = 'Statistics' ORDER BY salary LIMIT 1###context:CREATE TABLE instructor (name VARCHAR, dept_name VARCHAR, salary VARCHAR) |
###question:Find the title of course that is provided by both Statistics and Psychology departments.###answer:SELECT title FROM course WHERE dept_name = 'Statistics' INTERSECT SELECT title FROM course WHERE dept_name = 'Psychology'###context:CREATE TABLE course (title VARCHAR, dept_name VARCHAR) |
###question:Find the title of course that is provided by Statistics but not Psychology departments.###answer:SELECT title FROM course WHERE dept_name = 'Statistics' EXCEPT SELECT title FROM course WHERE dept_name = 'Psychology'###context:CREATE TABLE course (title VARCHAR, dept_name VARCHAR) |
###question:Find the id of instructors who taught a class in Fall 2009 but not in Spring 2010.###answer:SELECT id FROM teaches WHERE semester = 'Fall' AND YEAR = 2009 EXCEPT SELECT id FROM teaches WHERE semester = 'Spring' AND YEAR = 2010###context:CREATE TABLE teaches (id VARCHAR, semester VARCHAR, YEAR VARCHAR) |
###question:Find the name of students who took any class in the years of 2009 and 2010.###answer:SELECT DISTINCT T1.name FROM student AS T1 JOIN takes AS T2 ON T1.id = T2.id WHERE YEAR = 2009 OR YEAR = 2010###context:CREATE TABLE student (name VARCHAR, id VARCHAR); CREATE TABLE takes (id VARCHAR) |
###question:Find the names of the top 3 departments that provide the largest amount of courses?###answer:SELECT dept_name FROM course GROUP BY dept_name ORDER BY COUNT(*) DESC LIMIT 3###context:CREATE TABLE course (dept_name VARCHAR) |
###question:Find the name of the department that offers the highest total credits?###answer:SELECT dept_name FROM course GROUP BY dept_name ORDER BY SUM(credits) DESC LIMIT 1###context:CREATE TABLE course (dept_name VARCHAR, credits INTEGER) |
###question:List the names of all courses ordered by their titles and credits.###answer:SELECT title FROM course ORDER BY title, credits###context:CREATE TABLE course (title VARCHAR, credits VARCHAR) |
###question:Which department has the lowest budget?###answer:SELECT dept_name FROM department ORDER BY budget LIMIT 1###context:CREATE TABLE department (dept_name VARCHAR, budget VARCHAR) |
###question:List the names and buildings of all departments sorted by the budget from large to small.###answer:SELECT dept_name, building FROM department ORDER BY budget DESC###context:CREATE TABLE department (dept_name VARCHAR, building VARCHAR, budget VARCHAR) |
###question:Who is the instructor with the highest salary?###answer:SELECT name FROM instructor ORDER BY salary DESC LIMIT 1###context:CREATE TABLE instructor (name VARCHAR, salary VARCHAR) |
###question:List the information of all instructors ordered by their salary in ascending order.###answer:SELECT * FROM instructor ORDER BY salary###context:CREATE TABLE instructor (salary VARCHAR) |
###question:Find the name of the students and their department names sorted by their total credits in ascending order.###answer:SELECT name, dept_name FROM student ORDER BY tot_cred###context:CREATE TABLE student (name VARCHAR, dept_name VARCHAR, tot_cred VARCHAR) |
###question:list in alphabetic order all course names and their instructors' names in year 2008.###answer:SELECT T1.title, T3.name FROM course AS T1 JOIN teaches AS T2 ON T1.course_id = T2.course_id JOIN instructor AS T3 ON T2.id = T3.id WHERE YEAR = 2008 ORDER BY T1.title###context:CREATE TABLE course (title VARCHAR, course_id VARCHAR); CREATE TABLE teaches (course_id VARCHAR, id VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR) |
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