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CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films are there under the category of "Horror"?
SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Horror'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Please list the titles of all the films under the category of "Horror" and has a rental rate of $2.99.
SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror' AND T1.rental_rate = 2.99
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
For how many times has the customer RUTH MARTINEZ rented a film?
SELECT COUNT(T2.rental_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Please list the titles of all the films that the customer RUTH MARTINEZ has rented.
SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the films that the customer RUTH MARTINEZ has rented, how many of them are released in 2006?
SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T4.release_year = 2006 AND T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the films that the customer RUTH MARTINEZ has rented, what is the title of the one with the highest replacement cost?
SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' ORDER BY T4.replacement_cost DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Please list the full names of all the customers who have rented the film with the highest replacement cost.
SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id ORDER BY T4.replacement_cost DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films rented to the customer RUTH MARTINEZ were returned in August, 2005?
SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' AND STRFTIME('%m',T2.return_date) = '8' AND STRFTIME('%Y', T2.return_date) = '2005'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Please give the full name of the customer that have rented the most films.
SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.rental_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the customers who have rented the film ACADEMY DINOSAUR, how many of them are active?
SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.active = 1 AND T4.title = 'ACADEMY DINOSAUR'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Which film is rented for the most times by the customers? Please give its title.
SELECT T.title FROM ( SELECT T1.title, COUNT(T3.rental_id) AS num FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T1.title ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Which customer has rented more movies, RUTH MARTINEZ or LINDA WILLIAMS?
SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE (T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ') OR (T1.first_name = 'LINDA' AND T1.last_name = 'WILLIAMS') GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among all the films starring PENELOPE GUINESS, what is the title of the one with the highest rental price per day?
SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.rental_rate / T3.rental_duration DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the average replacement cost of the films under the category of "Horror"?
SELECT AVG(T3.replacement_cost) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T2.name = 'Horror'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among all films that the customer RUTH MARTINEZ has rented, what is the percentage of it being a Music film?
SELECT CAST(SUM(IIF(T3.name = 'Music', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id INNER JOIN inventory AS T4 ON T1.film_id = T4.film_id INNER JOIN customer AS T5 ON T4.store_id = T5.store_id INNER JOIN rental AS T6 ON T4.inventory_id = T6.inventory_id WHERE T5.first_name = 'RUTH' AND T5.last_name = 'MARTINEZ'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the average duration time of the films starring PENELOPE GUINESS?
SELECT AVG(T3.length) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is Diane Collins' email address?
SELECT email FROM customer WHERE first_name = 'DIANE' AND last_name = 'COLLINS'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the number of inactive customers.
SELECT COUNT(customer_id) FROM customer WHERE active = 0
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Who is the owner of email address "[email protected]"? Give the full name.
SELECT first_name, last_name FROM customer WHERE email = '[email protected]'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the postal code for the address No.65.
SELECT postal_code FROM address WHERE address_id = 65
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
State the number of addresses in the Nordrhein-Westfalen district.
SELECT COUNT(address_id) FROM address WHERE district = 'Nordrhein-Westfalen'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the phone number of address No.72?
SELECT phone FROM address WHERE address_id = '72'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
State the number of films that are 178 minutes long.
SELECT COUNT(film_id) FROM film WHERE length = '178'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Tell the special features of the film Uprising Uptown.
SELECT special_features FROM film WHERE title = 'UPRISING UPTOWN'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the description of the film Artist Coldblooded?
SELECT description FROM film WHERE title = 'ARTIST COLDBLOODED'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the detailed address for store No.2.
SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 2
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Which continent is the mother country of Clarksville city in?
SELECT T1.country FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T2.city = 'Clarksville'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many actors played a role in the 2006 film whose rental duration is 7 days, rental rate is 4.99 and is 98 minutes duration?
SELECT COUNT(T1.actor_id) FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id WHERE T2.release_year = 2006 AND T2.rental_duration = 7 AND T2.rental_duration = 4.99 AND T2.length = 98
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
The actor Dan Harris played in a 77 minute film with replacement cost of 9.99, what was the rating for that film?
SELECT T3.rating FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'DAN' AND T1.last_name = 'HARRIS' AND T3.length = 77 AND T3.replacement_cost = '9.99'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films did actor Daryl Wahlberg appear in?
SELECT COUNT(T1.film_id) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id WHERE T2.first_name = 'DARYL' AND T2.last_name = 'WAHLBERG'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Sherri Rhodes rented a film at 12:27:27 on 2005/7/28, when did she/he return that film?
SELECT T2.return_date FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'SHERRI' AND T1.last_name = 'RHODES' AND T2.rental_date = '2005-07-28 12:27:27'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the name of the manager staff for store No.1.
SELECT T1.first_name, T1.last_name FROM staff AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id WHERE T2.store_id = 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
State the address location of store No.1.
SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Where does the staff Jon Stephens live?
SELECT T1.address, T1.address2 FROM address AS T1 INNER JOIN staff AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'Jon' AND T2.last_name = 'Stephens'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many addresses are there in Woodridge city?
SELECT COUNT(T1.address_id) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id WHERE T2.city = 'Woodridge'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films are in English?
SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the address location of Heather Morris.
SELECT T1.address FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'HEATHER' AND T2.last_name = 'MORRIS'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the email address of the person who lives in "1411 Lillydale Drive".
SELECT T2.email FROM address AS T1 INNER JOIN staff AS T2 ON T1.address_id = T2.address_id WHERE T1.address = '1411 Lillydale Drive'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How much money did the customer No.297 pay for the rental which happened at 12:27:27 on 2005/7/28?
SELECT T1.amount FROM payment AS T1 INNER JOIN rental AS T2 ON T1.rental_id = T2.rental_id WHERE T2.rental_date = '2005-07-28 12:27:27' AND T2.customer_id = 297
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Which category does the film Working Microcosmos belong to?
SELECT T3.name FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.title = 'WORKING MICROCOSMOS'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the number of documentary films.
SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Documentary'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
State the name of the category which has the most number of films.
SELECT T.name FROM ( SELECT T2.name, COUNT(T1.film_id) AS num FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T2.name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Give the name of the film for inventory No.3479.
SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.inventory_id = 3479
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the percentage more for the rental payment for store No.2 than store No.1?
SELECT CAST((SUM(IIF(T2.store_id = 2, T1.amount, 0)) - SUM(IIF(T2.store_id = 1, T1.amount, 0))) AS REAL) * 100 / SUM(IIF(T2.store_id = 1, T1.amount, 0)) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id INNER JOIN store AS T3 ON T2.store_id = T3.store_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many times is the number of Indian cities than Italian cities?
SELECT CAST(SUM(IIF(T1.country = 'India', 1, 0)) AS REAL) / SUM(IIF(T1.country = 'Italy', 1, 0)) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many times is the number of films Gina DeGeneres acted in than Penelope Guinness?
SELECT CAST(SUM(IIF(T2.first_name = 'GINA' AND T2.last_name = 'DEGENERES', 1, 0)) AS REAL) * 100 / SUM(IIF(T2.first_name = 'PENELOPE' AND T2.last_name = 'GUINESS', 1, 0)) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
In 2006, how many restricted films were released?
SELECT COUNT(film_id) FROM film WHERE rating = 'R' AND release_year = 2006
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many actors starred in the film id 508?
SELECT COUNT(actor_id) FROM film_actor WHERE film_id = 508
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What are the special features for the film "Smoochy Control"?
SELECT special_features FROM film WHERE title = 'SMOOCHY CONTROL'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many customers paid over the amount of 10 on August 2005?
SELECT COUNT(customer_id) FROM payment WHERE SUBSTR(payment_date, 1, 7) LIKE '2005-08'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List the names of the films that are more than 180 minutes long.
SELECT title FROM film WHERE length > 180
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How much is the total rental payment for the first 10 rentals?
SELECT SUM(amount) FROM payment WHERE rental_id BETWEEN 1 AND 10
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What are the full names of all the active employees?
SELECT first_name, last_name FROM staff WHERE active = 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Who is the staff manager in store id 2?
SELECT manager_staff_id FROM store WHERE store_id = 2
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many rentals were returned on 5/27/2005?
SELECT COUNT(rental_id) FROM rental WHERE rental_date = '2005-05-27'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What are the names of the movies which Laura Brody starred in?
SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Laura' AND T1.last_name = 'Brody'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List the name of the films that can only be found in store id 2.
SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the full name of the customer who rented movies for 7 consecutive days?
SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN ( SELECT customer_id, COUNT(*) AS num_days FROM ( SELECT *, date(days, '-' || rn || ' day') AS results FROM ( SELECT customer_id, days, row_number() OVER (PARTITION BY customer_id ORDER BY days) AS rn FROM ( SELECT DISTINCT customer_id, date(rental_date) AS days FROM rental ) ) ) GROUP BY customer_id, results HAVING num_days = 7 ) AS T2 ON T1.customer_id = T2.customer_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films are categorized as horror?
SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Horror'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the name of the most rented movie?
SELECT T.title FROM ( SELECT T1.title, COUNT(T3.rental_id) AS num FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T1.title ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the most common special features of science-fiction movies?
SELECT T1.special_features FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'sci-fi' ORDER BY T1.special_features DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the full name of the actor who starred in most movies?
SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.film_id) AS num FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the films with a rental duration of 7 days, how many are comedies?
SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.rental_duration = 7 AND T3.name = 'Comedy'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Who is the staff manager of the store with the most non-active customers?
SELECT T.first_name, T.last_name FROM ( SELECT T3.first_name, T3.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN staff AS T3 ON T2.store_id = T3.store_id WHERE T1.active = 0 GROUP BY T3.first_name, T3.last_name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the rental price per day of the most expensive children's film?
SELECT T1.rental_rate FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Children' ORDER BY T1.rental_rate / T1.rental_duration DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the complete address of store id 1?
SELECT T3.address, T3.address2, T3.district FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN store AS T4 ON T3.address_id = T4.address_id WHERE T4.store_id = 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many customers are from the city of Lethbridge?
SELECT COUNT(T3.customer_id) FROM city AS T1 INNER JOIN address AS T2 ON T1.city_id = T2.city_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.city = 'Lethbridge'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many cities are there in the United States?
SELECT COUNT(T2.city) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T1.country = 'United States'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List the names of the customers from India.
SELECT T4.first_name, T4.last_name FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN customer AS T4 ON T3.address_id = T4.address_id WHERE T1.country = 'India'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the classic movies, how many movies have a rental rate of less than 1?
SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T3.rental_rate < 1 AND T2.name = 'Classics'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the full name of the customer who rented the highest number of movies of all time?
SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.rental_id) AS num FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many times was "Blanket Beverly" rented?
SELECT COUNT(T3.rental_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id WHERE T1.title = 'Blanket Beverly'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the full name of the actor who has the highest number of restricted films?
SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'R' GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Who are the top 5 actors with the highest number of films? List their full names and calculate the average number of films for each of the actors.
SELECT T.first_name, T.last_name, num FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 5
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List the actors' IDs who have "KILMER" as last name.
SELECT actor_id FROM actor WHERE last_name = 'KILMER'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List down the films titles with the lowest replacement cost under the general audiences rating.
SELECT title FROM film WHERE replacement_cost = ( SELECT MIN(replacement_cost) FROM film )
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the films with the longest duration, list any five title with their descriptions and special features.
SELECT title, description, special_features FROM film WHERE length = ( SELECT MAX(length) FROM film ) LIMIT 5
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films rented on 26th May, 2005 were returned on 30th May, 2005?
SELECT COUNT(DISTINCT rental_id) FROM rental WHERE date(rental_date) BETWEEN '2005-05-26' AND '2005-05-30'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Calculate the average payment amount per customer.
SELECT AVG(amount) FROM payment GROUP BY customer_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the name and email of the staff in store ID 2?
SELECT first_name, last_name, email FROM staff WHERE store_id = 2
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many percent of customers were inactive?
SELECT CAST(SUM(IIF(active = 0, 1, 0)) AS REAL) * 100 / COUNT(customer_id) FROM customer
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
What is the description and film title of ID 996?
SELECT description, title FROM film_text WHERE film_id = 996
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Calculate customers' total payment amount in August, 2005.
SELECT SUM(amount) FROM payment WHERE SUBSTR(payment_date, 1, 7) = '2005-08'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List down the film titles performed by Emily Dee.
SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Emily' AND T1.last_name = 'Dee'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List down the actors' full names who performed in "CHOCOLATE DUCK" film.
SELECT T3.first_name, T3.last_name FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = 'CHOCOLATE DUCK'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many films in the horror category were included in PG-13-rated?
SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror' AND T1.rating = 'PG-13'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Distinguish the films performed by Judy Dean according to category.
SELECT T5.name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN film_category AS T4 ON T2.film_id = T4.film_id INNER JOIN category AS T5 ON T4.category_id = T5.category_id WHERE T1.first_name = 'Judy' AND T1.last_name = 'Dean'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Write down any five film names under the documentary category.
SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Documentary' LIMIT 5
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Mention the language of Untouchables Sunrise film and calculate its rental cost per day.
SELECT T2.name, T1.replacement_cost / T1.rental_duration AS cost FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'UNTOUCHABLES SUNRISE'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List the films' titles which were rented on 24th May,2005.
SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id WHERE SUBSTR(T3.rental_date, 1, 10) = '2005-05-24'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
List the films' titles which were rented by Brian Wyman in July, 2005.
SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'BRIAN' AND T1.last_name = 'WYMAN' AND STRFTIME('%Y', T2.rental_date) = '2005' AND STRFTIME('%m',T2.rental_date) = '7'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Write down the inventories' IDs and actors' names of "STREETCAR INTENTIONS".
SELECT T4.inventory_id, T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T2.film_id = T4.film_id WHERE T3.title = 'STREETCAR INTENTIONS'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Among the films rented by Natalie Meyer, describe the titles and categories of the films which were rented in February 2006.
SELECT T3.title, T2.name FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id INNER JOIN customer AS T5 ON T4.store_id = T5.store_id INNER JOIN rental AS T6 ON T4.inventory_id = T6.inventory_id WHERE T5.first_name = 'Natalie' AND T5.last_name = 'Meyer' AND STRFTIME('%Y',T3.rental_rate) = '2006' AND STRFTIME('%m',T3.rental_rate) = '2'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How many rental IDs belong to Eleanor Hunt?
SELECT COUNT(T1.rental_id) FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'Eleanor' AND T2.last_name = 'Hunt'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Describe the full names and cities of the customers who rented "DREAM PICKUP".
SELECT T4.first_name, T4.last_name, T6.city FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN customer AS T4 ON T3.customer_id = T4.customer_id INNER JOIN address AS T5 ON T4.address_id = T5.address_id INNER JOIN city AS T6 ON T5.city_id = T6.city_id WHERE T1.title = 'DREAM PICKUP'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Calculate how many percent of customers were located in India.
SELECT CAST(SUM(IIF(T1.country = 'India', 1, 0)) AS REAL) * 100 / COUNT(T4.customer_id) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN customer AS T4 ON T3.address_id = T4.address_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
How much percentage of the film did Mary Keitel perform more than Angela Witherspoon?
SELECT CAST((SUM(IIF(T1.first_name = 'ANGELA' AND T1.last_name = 'WITHERSPOON', 1, 0)) - SUM(IIF(T1.first_name = 'MARY' AND T1.last_name = 'KEITEL', 1, 0))) AS REAL) * 100 / SUM(IIF(T1.first_name = 'MARY' AND T1.last_name = 'KEITEL', 1, 0)) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Provide the email, address, city, and country of the customer Lillie Kim.
SELECT T1.email, T2.address, T3.city, T4.country FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T2.city_id = T3.city_id INNER JOIN country AS T4 ON T3.country_id = T4.country_id WHERE T1.first_name = 'Lillie' AND T1.last_name = 'Kim'
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Provide any 5 customers' full names who have rented from Mike Hillyer.
SELECT T3.first_name, T3.last_name FROM staff AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.first_name = 'Mike' AND T1.last_name = 'Hillyer' LIMIT 5
bird
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update datetime, city_id integer, city text, country_id integer, last_update datetime, country_id integer, country text, last_update datetime, customer_id integer, store_id integer, first_name text, last_name text, email text, address_id integer, active integer, create_date datetime, last_update datetime, film_id integer, title text, description text, release_year text, language_id integer, original_language_id integer, rental_duration integer, rental_rate real, length integer, replacement_cost real, rating text, special_features text, last_update datetime, actor_id integer, film_id integer, last_update datetime, film_id integer, category_id integer, last_update datetime, inventory_id integer, film_id integer, store_id integer, last_update datetime, language_id integer, name text, last_update datetime, payment_id integer, customer_id integer, staff_id integer, rental_id integer, amount real, payment_date datetime, last_update datetime, rental_id integer, rental_date datetime, inventory_id integer, customer_id integer, return_date datetime, staff_id integer, last_update datetime, staff_id integer, first_name text, last_name text, address_id integer, picture blob, email text, store_id integer, active integer, username text, password text, last_update datetime, store_id integer, manager_staff_id integer, address_id integer, last_update datetime)
Calculate the total payment amount by Diane Collins.
SELECT SUM(T2.amount) FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'Diane' AND T1.last_name = 'Collins'
bird