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1,700 | <question>: How many institutions are there? <context>: CREATE TABLE inst (Id VARCHAR) | SELECT COUNT(*) FROM inst |
1,701 | <question>: How many papers are published in total? <context>: CREATE TABLE papers (Id VARCHAR) | SELECT COUNT(*) FROM papers |
1,702 | <question>: What are the titles of papers published by "Jeremy Gibbons"? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Jeremy" AND t1.lname = "Gibbons" |
1,703 | <question>: Find all the papers published by "Aaron Turon". <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Aaron" AND t1.lname = "Turon" |
1,704 | <question>: How many papers have "Atsushi Ohori" published? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE papers (paperid VARCHAR) | SELECT COUNT(*) FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Atsushi" AND t1.lname = "Ohori" |
1,705 | <question>: What is the name of the institution that "Matthias Blume" belongs to? <context>: CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE inst (name VARCHAR, instid VARCHAR) | SELECT DISTINCT t3.name FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t1.fname = "Matthias" AND t1.lname = "Blume" |
1,706 | <question>: Which institution does "Katsuhiro Ueno" belong to? <context>: CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE inst (name VARCHAR, instid VARCHAR) | SELECT DISTINCT t3.name FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t1.fname = "Katsuhiro" AND t1.lname = "Ueno" |
1,707 | <question>: Who belong to the institution "University of Oxford"? Show the first names and last names. <context>: CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (fname VARCHAR, lname VARCHAR, authid VARCHAR); CREATE TABLE inst (instid VARCHAR, name VARCHAR) | SELECT DISTINCT t1.fname, t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "University of Oxford" |
1,708 | <question>: Which authors belong to the institution "Google"? Show the first names and last names. <context>: CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (fname VARCHAR, lname VARCHAR, authid VARCHAR); CREATE TABLE inst (instid VARCHAR, name VARCHAR) | SELECT DISTINCT t1.fname, t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Google" |
1,709 | <question>: What are the last names of the author of the paper titled "Binders Unbound"? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (lname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR) | SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title = "Binders Unbound" |
1,710 | <question>: Find the first and last name of the author(s) who wrote the paper "Nameless, Painless". <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR); CREATE TABLE authors (fname VARCHAR, lname VARCHAR, authid VARCHAR) | SELECT t1.fname, t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title = "Nameless , Painless" |
1,711 | <question>: What are the papers published under the institution "Indiana University"? <context>: CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | SELECT DISTINCT t1.title FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Indiana University" |
1,712 | <question>: Find all the papers published by the institution "Google". <context>: CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | SELECT DISTINCT t1.title FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Google" |
1,713 | <question>: How many papers are published by the institution "Tokohu University"? <context>: CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | SELECT COUNT(DISTINCT t1.title) FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Tokohu University" |
1,714 | <question>: Find the number of papers published by the institution "University of Pennsylvania". <context>: CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | SELECT COUNT(DISTINCT t1.title) FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "University of Pennsylvania" |
1,715 | <question>: Find the papers which have "Olin Shivers" as an author. <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Olin" AND t1.lname = "Shivers" |
1,716 | <question>: Which papers have "Stephanie Weirich" as an author? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Stephanie" AND t1.lname = "Weirich" |
1,717 | <question>: Which paper is published in an institution in "USA" and have "Turon" as its second author? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR, instid VARCHAR, authorder VARCHAR); CREATE TABLE authors (authid VARCHAR, lname VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE inst (instid VARCHAR, country VARCHAR) | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid JOIN inst AS t4 ON t2.instid = t4.instid WHERE t4.country = "USA" AND t2.authorder = 2 AND t1.lname = "Turon" |
1,718 | <question>: Find the titles of papers whose first author is affiliated with an institution in the country "Japan" and has last name "Ohori"? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR, instid VARCHAR, authorder VARCHAR); CREATE TABLE authors (authid VARCHAR, lname VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE inst (instid VARCHAR, country VARCHAR) | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid JOIN inst AS t4 ON t2.instid = t4.instid WHERE t4.country = "Japan" AND t2.authorder = 1 AND t1.lname = "Ohori" |
1,719 | <question>: What is the last name of the author that has published the most papers? <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (lname VARCHAR, fname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR) | SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.fname, t1.lname ORDER BY COUNT(*) DESC LIMIT 1 |
1,720 | <question>: Retrieve the country that has published the most papers. <context>: CREATE TABLE inst (country VARCHAR, instid VARCHAR); CREATE TABLE authorship (instid VARCHAR, paperid VARCHAR); CREATE TABLE papers (paperid VARCHAR) | SELECT t1.country FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.country ORDER BY COUNT(*) DESC LIMIT 1 |
1,721 | <question>: Find the name of the organization that has published the largest number of papers. <context>: CREATE TABLE inst (name VARCHAR, instid VARCHAR); CREATE TABLE authorship (instid VARCHAR, paperid VARCHAR); CREATE TABLE papers (paperid VARCHAR) | SELECT t1.name FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.name ORDER BY COUNT(*) DESC LIMIT 1 |
1,722 | <question>: Find the titles of the papers that contain the word "ML". <context>: CREATE TABLE papers (title VARCHAR) | SELECT title FROM papers WHERE title LIKE "%ML%" |
1,723 | <question>: Which paper's title contains the word "Database"? <context>: CREATE TABLE papers (title VARCHAR) | SELECT title FROM papers WHERE title LIKE "%Database%" |
1,724 | <question>: Find the first names of all the authors who have written a paper with title containing the word "Functional". <context>: CREATE TABLE authors (fname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR); CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR) | SELECT t1.fname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Functional%" |
1,725 | <question>: Find the last names of all the authors that have written a paper with title containing the word "Monadic". <context>: CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (lname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR) | SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Monadic%" |
1,726 | <question>: Retrieve the title of the paper that has the largest number of authors. <context>: CREATE TABLE authorship (authorder INTEGER); CREATE TABLE authorship (paperid VARCHAR, authorder INTEGER); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | SELECT t2.title FROM authorship AS t1 JOIN papers AS t2 ON t1.paperid = t2.paperid WHERE t1.authorder = (SELECT MAX(authorder) FROM authorship) |
1,727 | <question>: What is the first name of the author with last name "Ueno"? <context>: CREATE TABLE authors (fname VARCHAR, lname VARCHAR) | SELECT fname FROM authors WHERE lname = "Ueno" |
1,728 | <question>: Find the last name of the author with first name "Amal". <context>: CREATE TABLE authors (lname VARCHAR, fname VARCHAR) | SELECT lname FROM authors WHERE fname = "Amal" |
1,729 | <question>: Find the first names of all the authors ordered in alphabetical order. <context>: CREATE TABLE authors (fname VARCHAR) | SELECT fname FROM authors ORDER BY fname |
1,730 | <question>: Retrieve all the last names of authors in alphabetical order. <context>: CREATE TABLE authors (lname VARCHAR) | SELECT lname FROM authors ORDER BY lname |
1,731 | <question>: Retrieve all the first and last names of authors in the alphabetical order of last names. <context>: CREATE TABLE authors (fname VARCHAR, lname VARCHAR) | SELECT fname, lname FROM authors ORDER BY lname |
1,732 | <question>: How many different last names do the actors and actresses have? <context>: CREATE TABLE actor (last_name VARCHAR) | SELECT COUNT(DISTINCT last_name) FROM actor |
1,733 | <question>: What is the most popular first name of the actors? <context>: CREATE TABLE actor (first_name VARCHAR) | SELECT first_name FROM actor GROUP BY first_name ORDER BY COUNT(*) DESC LIMIT 1 |
1,734 | <question>: What is the most popular full name of the actors? <context>: CREATE TABLE actor (first_name VARCHAR, last_name VARCHAR) | SELECT first_name, last_name FROM actor GROUP BY first_name, last_name ORDER BY COUNT(*) DESC LIMIT 1 |
1,735 | <question>: Which districts have at least two addresses? <context>: CREATE TABLE address (district VARCHAR) | SELECT district FROM address GROUP BY district HAVING COUNT(*) >= 2 |
1,736 | <question>: What is the phone number and postal code of the address 1031 Daugavpils Parkway? <context>: CREATE TABLE address (phone VARCHAR, postal_code VARCHAR, address VARCHAR) | SELECT phone, postal_code FROM address WHERE address = '1031 Daugavpils Parkway' |
1,737 | <question>: Which city has the most addresses? List the city name, number of addresses, and city id. <context>: CREATE TABLE address (city_id VARCHAR); CREATE TABLE city (city VARCHAR, city_id VARCHAR) | SELECT T2.city, COUNT(*), T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,738 | <question>: How many addresses are in the district of California? <context>: CREATE TABLE address (district VARCHAR) | SELECT COUNT(*) FROM address WHERE district = 'California' |
1,739 | <question>: Which film is rented at a fee of 0.99 and has less than 3 in the inventory? List the film title and id. <context>: CREATE TABLE film (title VARCHAR, film_id VARCHAR, rental_rate VARCHAR); CREATE TABLE inventory (film_id VARCHAR); CREATE TABLE film (title VARCHAR, film_id VARCHAR) | SELECT title, film_id FROM film WHERE rental_rate = 0.99 INTERSECT SELECT T1.title, T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id HAVING COUNT(*) < 3 |
1,740 | <question>: How many cities are in Australia? <context>: CREATE TABLE country (country_id VARCHAR, country VARCHAR); CREATE TABLE city (country_id VARCHAR) | SELECT COUNT(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id WHERE T2.country = 'Australia' |
1,741 | <question>: Which countries have at least 3 cities? <context>: CREATE TABLE country (country VARCHAR, country_id VARCHAR); CREATE TABLE city (country_id VARCHAR) | SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id GROUP BY T2.country_id HAVING COUNT(*) >= 3 |
1,742 | <question>: Find all the payment dates for the payments with an amount larger than 10 and the payments handled by a staff person with the first name Elsa. <context>: CREATE TABLE payment (payment_date VARCHAR, staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, first_name VARCHAR); CREATE TABLE payment (payment_date VARCHAR, amount INTEGER) | SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Elsa' |
1,743 | <question>: How many customers have an active value of 1? <context>: CREATE TABLE customer (active VARCHAR) | SELECT COUNT(*) FROM customer WHERE active = '1' |
1,744 | <question>: Which film has the highest rental rate? And what is the rate? <context>: CREATE TABLE film (title VARCHAR, rental_rate VARCHAR) | SELECT title, rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1 |
1,745 | <question>: Which film has the most number of actors or actresses? List the film name, film id and description. <context>: CREATE TABLE film_actor (film_id VARCHAR); CREATE TABLE film (title VARCHAR, film_id VARCHAR, description VARCHAR) | SELECT T2.title, T2.film_id, T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T2.film_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,746 | <question>: Which film actor (actress) starred the most films? List his or her first name, last name and actor id. <context>: CREATE TABLE film_actor (actor_id VARCHAR); CREATE TABLE actor (first_name VARCHAR, last_name VARCHAR, actor_id VARCHAR) | SELECT T2.first_name, T2.last_name, T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,747 | <question>: Which film actors (actresses) played a role in more than 30 films? List his or her first name and last name. <context>: CREATE TABLE film_actor (actor_id VARCHAR); CREATE TABLE actor (first_name VARCHAR, last_name VARCHAR, actor_id VARCHAR) | SELECT T2.first_name, T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id HAVING COUNT(*) > 30 |
1,748 | <question>: Which store owns most items? <context>: CREATE TABLE inventory (store_id VARCHAR) | SELECT store_id FROM inventory GROUP BY store_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,749 | <question>: What is the total amount of all payments? <context>: CREATE TABLE payment (amount INTEGER) | SELECT SUM(amount) FROM payment |
1,750 | <question>: Which customer, who has made at least one payment, has spent the least money? List his or her first name, last name, and the id. <context>: CREATE TABLE payment (customer_id VARCHAR); CREATE TABLE customer (first_name VARCHAR, last_name VARCHAR, customer_id VARCHAR) | SELECT T1.first_name, T1.last_name, T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY SUM(amount) LIMIT 1 |
1,751 | <question>: What is the genre name of the film HUNGER ROOF? <context>: CREATE TABLE film_category (category_id VARCHAR, film_id VARCHAR); CREATE TABLE film (film_id VARCHAR, title VARCHAR); CREATE TABLE category (name VARCHAR, category_id VARCHAR) | SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id = T2.category_id JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'HUNGER ROOF' |
1,752 | <question>: How many films are there in each category? List the genre name, genre id and the count. <context>: CREATE TABLE film_category (category_id VARCHAR); CREATE TABLE category (name VARCHAR, category_id VARCHAR) | SELECT T2.name, T1.category_id, COUNT(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T1.category_id |
1,753 | <question>: Which film has the most copies in the inventory? List both title and id. <context>: CREATE TABLE film (title VARCHAR, film_id VARCHAR); CREATE TABLE inventory (film_id VARCHAR) | SELECT T1.title, T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,754 | <question>: What is the film title and inventory id of the item in the inventory which was rented most frequently? <context>: CREATE TABLE film (title VARCHAR, film_id VARCHAR); CREATE TABLE inventory (inventory_id VARCHAR, film_id VARCHAR); CREATE TABLE rental (inventory_id VARCHAR) | SELECT T1.title, T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T2.inventory_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,755 | <question>: How many languages are in these films? <context>: CREATE TABLE film (language_id VARCHAR) | SELECT COUNT(DISTINCT language_id) FROM film |
1,756 | <question>: What are all the movies rated as R? List the titles. <context>: CREATE TABLE film (title VARCHAR, rating VARCHAR) | SELECT title FROM film WHERE rating = 'R' |
1,757 | <question>: Where is store 1 located? <context>: CREATE TABLE store (address_id VARCHAR); CREATE TABLE address (address VARCHAR, address_id VARCHAR) | SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE store_id = 1 |
1,758 | <question>: Which staff handled least number of payments? List the full name and the id. <context>: CREATE TABLE payment (staff_id VARCHAR); CREATE TABLE staff (first_name VARCHAR, last_name VARCHAR, staff_id VARCHAR) | SELECT T1.first_name, T1.last_name, T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY COUNT(*) LIMIT 1 |
1,759 | <question>: Which language does the film AIRPORT POLLOCK use? List the language name. <context>: CREATE TABLE film (language_id VARCHAR, title VARCHAR); CREATE TABLE LANGUAGE (name VARCHAR, language_id VARCHAR) | SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'AIRPORT POLLOCK' |
1,760 | <question>: How many stores are there? <context>: CREATE TABLE store (Id VARCHAR) | SELECT COUNT(*) FROM store |
1,761 | <question>: How many kinds of different ratings are listed? <context>: CREATE TABLE film (rating VARCHAR) | SELECT COUNT(DISTINCT rating) FROM film |
1,762 | <question>: Which movies have 'Deleted Scenes' as a substring in the special feature? <context>: CREATE TABLE film (title VARCHAR, special_features VARCHAR) | SELECT title FROM film WHERE special_features LIKE '%Deleted Scenes%' |
1,763 | <question>: How many items in inventory does store 1 have? <context>: CREATE TABLE inventory (store_id VARCHAR) | SELECT COUNT(*) FROM inventory WHERE store_id = 1 |
1,764 | <question>: When did the first payment happen? <context>: CREATE TABLE payment (payment_date VARCHAR) | SELECT payment_date FROM payment ORDER BY payment_date LIMIT 1 |
1,765 | <question>: Where does the customer with the first name Linda live? And what is her email? <context>: CREATE TABLE customer (email VARCHAR, address_id VARCHAR, first_name VARCHAR); CREATE TABLE address (address VARCHAR, address_id VARCHAR) | SELECT T2.address, T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id = T1.address_id WHERE T1.first_name = 'LINDA' |
1,766 | <question>: Find all the films longer than 100 minutes, or rated PG, except those who cost more than 200 for replacement. List the titles. <context>: CREATE TABLE film (title VARCHAR, replacement_cost INTEGER, LENGTH VARCHAR, rating VARCHAR) | SELECT title FROM film WHERE LENGTH > 100 OR rating = 'PG' EXCEPT SELECT title FROM film WHERE replacement_cost > 200 |
1,767 | <question>: What is the first name and the last name of the customer who made the earliest rental? <context>: CREATE TABLE customer (first_name VARCHAR, last_name VARCHAR, customer_id VARCHAR); CREATE TABLE rental (customer_id VARCHAR, rental_date VARCHAR) | SELECT T1.first_name, T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id = T2.customer_id ORDER BY T2.rental_date LIMIT 1 |
1,768 | <question>: What is the full name of the staff member who has rented a film to a customer with the first name April and the last name Burns? <context>: CREATE TABLE customer (customer_id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE rental (staff_id VARCHAR, customer_id VARCHAR); CREATE TABLE staff (first_name VARCHAR, last_name VARCHAR, staff_id VARCHAR) | SELECT DISTINCT T1.first_name, T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id = T2.staff_id JOIN customer AS T3 ON T2.customer_id = T3.customer_id WHERE T3.first_name = 'APRIL' AND T3.last_name = 'BURNS' |
1,769 | <question>: Which store has most the customers? <context>: CREATE TABLE customer (store_id VARCHAR) | SELECT store_id FROM customer GROUP BY store_id ORDER BY COUNT(*) DESC LIMIT 1 |
1,770 | <question>: What is the largest payment amount? <context>: CREATE TABLE payment (amount VARCHAR) | SELECT amount FROM payment ORDER BY amount DESC LIMIT 1 |
1,771 | <question>: Where does the staff member with the first name Elsa live? <context>: CREATE TABLE staff (address_id VARCHAR, first_name VARCHAR); CREATE TABLE address (address VARCHAR, address_id VARCHAR) | SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Elsa' |
1,772 | <question>: What are the first names of customers who have not rented any films after '2005-08-23 02:06:01'? <context>: CREATE TABLE customer (first_name VARCHAR, customer_id VARCHAR, rental_date INTEGER); CREATE TABLE rental (first_name VARCHAR, customer_id VARCHAR, rental_date INTEGER) | SELECT first_name FROM customer WHERE NOT customer_id IN (SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01') |
1,773 | <question>: How many bank branches are there? <context>: CREATE TABLE bank (Id VARCHAR) | SELECT COUNT(*) FROM bank |
1,774 | <question>: How many customers are there? <context>: CREATE TABLE bank (no_of_customers INTEGER) | SELECT SUM(no_of_customers) FROM bank |
1,775 | <question>: Find the number of customers in the banks at New York City. <context>: CREATE TABLE bank (no_of_customers INTEGER, city VARCHAR) | SELECT SUM(no_of_customers) FROM bank WHERE city = 'New York City' |
1,776 | <question>: Find the average number of customers in all banks of Utah state. <context>: CREATE TABLE bank (no_of_customers INTEGER, state VARCHAR) | SELECT AVG(no_of_customers) FROM bank WHERE state = 'Utah' |
1,777 | <question>: Find the average number of customers cross all banks. <context>: CREATE TABLE bank (no_of_customers INTEGER) | SELECT AVG(no_of_customers) FROM bank |
1,778 | <question>: Find the city and state of the bank branch named morningside. <context>: CREATE TABLE bank (city VARCHAR, state VARCHAR, bname VARCHAR) | SELECT city, state FROM bank WHERE bname = 'morningside' |
1,779 | <question>: Find the branch names of banks in the New York state. <context>: CREATE TABLE bank (bname VARCHAR, state VARCHAR) | SELECT bname FROM bank WHERE state = 'New York' |
1,780 | <question>: List the name of all customers sorted by their account balance in ascending order. <context>: CREATE TABLE customer (cust_name VARCHAR, acc_bal VARCHAR) | SELECT cust_name FROM customer ORDER BY acc_bal |
1,781 | <question>: List the name of all different customers who have some loan sorted by their total loan amount. <context>: CREATE TABLE loan (cust_id VARCHAR, amount INTEGER); CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR) | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY SUM(T2.amount) |
1,782 | <question>: Find the state, account type, and credit score of the customer whose number of loan is 0. <context>: CREATE TABLE customer (state VARCHAR, acc_type VARCHAR, credit_score VARCHAR, no_of_loans VARCHAR) | SELECT state, acc_type, credit_score FROM customer WHERE no_of_loans = 0 |
1,783 | <question>: Find the number of different cities which banks are located at. <context>: CREATE TABLE bank (city VARCHAR) | SELECT COUNT(DISTINCT city) FROM bank |
1,784 | <question>: Find the number of different states which banks are located at. <context>: CREATE TABLE bank (state VARCHAR) | SELECT COUNT(DISTINCT state) FROM bank |
1,785 | <question>: How many distinct types of accounts are there? <context>: CREATE TABLE customer (acc_type VARCHAR) | SELECT COUNT(DISTINCT acc_type) FROM customer |
1,786 | <question>: Find the name and account balance of the customer whose name includes the letter ‘a’. <context>: CREATE TABLE customer (cust_name VARCHAR, acc_bal VARCHAR) | SELECT cust_name, acc_bal FROM customer WHERE cust_name LIKE '%a%' |
1,787 | <question>: Find the total account balance of each customer from Utah or Texas. <context>: CREATE TABLE customer (acc_bal INTEGER, state VARCHAR) | SELECT SUM(acc_bal) FROM customer WHERE state = 'Utah' OR state = 'Texas' |
1,788 | <question>: Find the name of customers who have both saving and checking account types. <context>: CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR) | SELECT cust_name FROM customer WHERE acc_type = 'saving' INTERSECT SELECT cust_name FROM customer WHERE acc_type = 'checking' |
1,789 | <question>: Find the name of customers who do not have an saving account. <context>: CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR) | SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = 'saving' |
1,790 | <question>: Find the name of customers who do not have a loan with a type of Mortgages. <context>: CREATE TABLE loan (cust_id VARCHAR, loan_type VARCHAR); CREATE TABLE customer (cust_name VARCHAR); CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR) | SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = 'Mortgages' |
1,791 | <question>: Find the name of customers who have loans of both Mortgages and Auto. <context>: CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR); CREATE TABLE loan (cust_id VARCHAR) | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Mortgages' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Auto' |
1,792 | <question>: Find the name of customers whose credit score is below the average credit scores of all customers. <context>: CREATE TABLE customer (cust_name VARCHAR, credit_score INTEGER) | SELECT cust_name FROM customer WHERE credit_score < (SELECT AVG(credit_score) FROM customer) |
1,793 | <question>: Find the branch name of the bank that has the most number of customers. <context>: CREATE TABLE bank (bname VARCHAR, no_of_customers VARCHAR) | SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1 |
1,794 | <question>: Find the name of customer who has the lowest credit score. <context>: CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR) | SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1 |
1,795 | <question>: Find the name, account type, and account balance of the customer who has the highest credit score. <context>: CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR, acc_bal VARCHAR, credit_score VARCHAR) | SELECT cust_name, acc_type, acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1 |
1,796 | <question>: Find the name of customer who has the highest amount of loans. <context>: CREATE TABLE loan (cust_id VARCHAR, amount INTEGER); CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR) | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY SUM(T2.amount) DESC LIMIT 1 |
1,797 | <question>: Find the state which has the most number of customers. <context>: CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER) | SELECT state FROM bank GROUP BY state ORDER BY SUM(no_of_customers) DESC LIMIT 1 |
1,798 | <question>: For each account type, find the average account balance of customers with credit score lower than 50. <context>: CREATE TABLE customer (acc_type VARCHAR, acc_bal INTEGER, credit_score INTEGER) | SELECT AVG(acc_bal), acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type |
1,799 | <question>: For each state, find the total account balance of customers whose credit score is above 100. <context>: CREATE TABLE customer (state VARCHAR, acc_bal INTEGER, credit_score INTEGER) | SELECT SUM(acc_bal), state FROM customer WHERE credit_score > 100 GROUP BY state |