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ape210k__01153939 | The school has a bunker with a length of 4.2 meters, a width of 2 meters and a depth of 0.5 meters. How many cubic meters of yellow sand are needed to fill this bunker? | 学校有一个长4.2米，宽2米，深0.5米的沙坑．要填满这个沙坑，需要黄沙多少立方米？ | <gadget id="calculator">4.2 * 2 * 0.5</gadget>
<output>4.2</output>
<result>4.2</result> | 4.2 | 4.2 | x=4.2*2*0.5 | calcformer-instruct-flan-xl_step-128k | The volume of the bunker is 4.2 x 2 x 0.5 =<gadget id="calculator">4.2*2*0.5</gadget><output>4.2</output> 4.2 cubic meters.<result>4.2</result> | 4.2 x 2 x 0.5 =<gadget id="calculator">4.2*2*0.5</gadget><output>4.2</output> 4.2 cubic meters 4.2 * 2 * 2.5 =<gadget id="calculator">4.2*2*2.5</gadget><output>21</output> 21 cubic meters.<result>21</result> |
ape210k__00418218 | The school planted 200 trees, and 190 survived. What is the death rate? | 学校植了200棵树，活了190棵，死亡率是多少 | <gadget id="calculator">190 / 200</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">(19/20) * 1</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 - (19/20)</gadget>
<output>1/20 = around 0.05</output>
<result>1/20 = around 0.05</result> | 1/20 | 0.05 | x=1-((190/200)*100%) | calcformer-instruct-flan-xl_step-128k | The school had only 190 trees survive, so there were 200 - 190 =<gadget id="calculator">200-190</gadget><output>10</output> 10 trees that died. This is a death rate of 10 / 200 =<gadget id="calculator">10/200</gadget><output>1/20 = around 0.05</output> 0.05.<result>1/20 = around 0.05</result> | The death rate is 10 / 200 x 100% = 25%.<result>25</result> |
ape210k__00297805 | Divide a pile of sugar into 4 parts on average, and 3 parts is the amount of this pile of sugar (expressed in fractions). | 把一堆糖平均分成4份，3份是这堆糖的多少(用分数表示)． | <gadget id="calculator">4 / 1</gadget>
<output>4</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>3/4 = around 0.75</result> | 3/4 | 0.75 | x=(3/(4/1)) | calcformer-instruct-flan-xl_step-128k | Since 1 full pile of sugar is divided into 4 piles of sugar on average, then 3 parts is (3/4) of a pile of sugar. This expression can be simplified to 3/4 =<gadget id="calculator">3/4</gadget><output>3/4 = around 0.75</output> 0.75.<result>0.75</result> | If 1 pile of sugar has 4 parts, then 3 parts is equal to 3/4 = 9/4 parts. On the other hand, if 1 part is equal to 1/8 of the sugar, then 3 parts equals 3 (8/4)*3 = 12/4 = 3 (3/8) of a pile of sugar.<result>3</result> |
ape210k__00037838 | How many decimal places does the product of 0.79*32 have. | 0.79*32的积有多少位小数． | <result>2</result> | 2 | 2 | x=2 | calcformer-instruct-flan-xl_step-128k | There are 2 decimal places in the result.<result>2</result> | One. The answer is 1 because one minus one equals one.<result>1</result> |
ape210k__00083135 | My younger brother reads a storybook, and he has already read 72 pages, which is 63 pages more than he has not read. How many times has he read more pages than he has not read? | 弟弟看一本故事书，已经看了72页，比没看的多63页，看的页数是没看的几倍？ | <gadget id="calculator">72 - 63</gadget>
<output>9</output>
<gadget id="calculator">72 / 9</gadget>
<output>8</output>
<result>8</result> | 8 | 8 | x=72/(72-63) | calcformer-instruct-flan-xl_step-128k | Let n be the number of pages he has not read. Therefore, he has read 72 - n =<gadget id="calculator">72-63</gadget><output>9</output> 9 more pages than he has not read. Therefore, he has read more pages than he has not read by 72 / 9 =<gadget id="calculator">72/9</gadget><output>8</output> 8 times.<result>8</result> | Let n be the number of pages he has not read. Then 72 - n = 72 - 63 =<gadget id="calculator">72-63</gadget><output>9</output> 9 n =<gadget id="calculator">9</gadget><output>9</output> 9 times.<result>9</result> |
ape210k__00009784 | Honghong's mother bought 2 coats and spent a total of 88 yuan. How much is each coat on average? How many | 红红的妈妈买了2件上衣，一共花了88元，平均每件上衣多少元？多少 | <gadget id="calculator">88 / 2</gadget>
<output>44</output>
<result>44</result> | 44 | 44 | x=88/2 | calcformer-instruct-flan-xl_step-128k | Each coat costs 88/2 =<gadget id="calculator">88/2</gadget><output>44</output> 44 yuan.<result>44</result> | The total cost of the two coats is 88 / 2 =<gadget id="calculator">88/2</gadget><output>44</output> 44 yuan. So each coat costs 44 / 2 =<gadget id="calculator">44/2</gadget><output>22</output> 22 yuan.<result>22</result> |
ape210k__00427467 | The distance between A and B is 4.2 kilometers, and a car travels the whole distance (5/7), how many meters does it travel? | 甲乙两地相距4.2千米，一辆汽车行驶了全程的(5/7)，行驶了多少米？ | <gadget id="calculator">4.2 * 1_000</gadget>
<output>4_200</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">4_200 * (5/7)</gadget>
<output>3_000</output>
<result>3_000</result> | 3_000 | 3,000 | x=(4.2*1000)*(5/7) | calcformer-instruct-flan-xl_step-128k | The car travels 4.2 x 5/7 =<gadget id="calculator">4.2*5/7</gadget><output>3</output> 3 kilometers. So, it travels 3 x 1000 =<gadget id="calculator">3000</gadget><output>3_000</output> 3000 meters.<result>3_000</result> | 5/7 = 5/7 x 1000 =<gadget id="calculator">5/7*1000</gadget><output>5_000/7 = around 714.285714</output> 714 meters 4.2 km =<gadget id="calculator">4.2*1000</gadget><output>4_200</output> 4200 meters. The car travels 714 meters.<result>714</result> |
ape210k__01158983 | The sixth grade students of Dongfeng Primary School planted 150 trees, which is 25% less than the fifth grade. How many trees are planted in the fifth grade? | 东风小学六年级学生植树150棵，比五年级植树少25%，五年级植树多少棵？ | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">150 / (3/4)</gadget>
<output>200</output>
<result>200</result> | 200 | 200 | x=150/(1-25%) | calcformer-instruct-flan-xl_step-128k | The sixth grade is 25% less than the fifth grade, thus meaning there are 100% - 25% = 75% of the trees planted in the fifth grade. Since 75% is equal to 150 trees, then this means 100% = 150/75% =<gadget id="calculator">150/75%</gadget><output>ERROR: invalid syntax (<string>, line 1)</output> ERROR= 150. Thus, the fifth grade students planted 150/0.75=<gadget id="calculator">150/0.75</gadget><output>200</output> 200 trees in the fifth grade.<result>200</result> | If the sixth grade is 25% less than the fifth grade, then there are 100 - 25 =<gadget id="calculator">100-25</gadget><output>75</output> 75% of the fifth grade's trees. The total number of trees in the sixth grade is 150/0.75 =<gadget id="calculator">150/0.75</gadget><output>200</output> 200. Since there are 200 plants in the sixth grade, then there are 200/0.75 =<gadget id="calculator">200/0.75</gadget><output>266.666667</output> 266.66667 trees in the fifth grade.<result>266.666667</result> |
ape210k__00411655 | The quotient of two numbers is 3, the dividend is increased by 100 times, and the divisor is increased by 10 times, what is the quotient? | 两个数的商是3，被除数扩大100倍，除数扩大10倍，商是多少． | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<result>30</result> | 30 | 30 | x=3*100/10 | calcformer-instruct-flan-xl_step-128k | The dividend is increased by 100 times and the divisor is increased by 10 times, so the quotient is increased by 100/10 =<gadget id="calculator">100/10</gadget><output>10</output> 10 times. The result is a new quotient of 3*10 =<gadget id="calculator">3*10</gadget><output>30</output> 30.<result>30</result> | If the original divided by the new divisor, the quotient becomes 100/10=<gadget id="calculator">100/10</gadget><output>10</output> 10 times. If the quotient of the two numbers is three, the new divided by the new divisor is 100/(10*100)=<gadget id="calculator">100/(10*100)</gadget><output>1/10 = around 0.1</output> 0.01 times higher.<result>0.1</result> |
ape210k__00011019 | If two cubes with side lengths of 5 cm are put together to form a cuboid, does the surface area change? How much has it changed? | 把两个棱长是5厘米的正方体拼成一个长方体，表面积有变化吗？变化了多少？ | <gadget id="calculator">5 * 5 * 2</gadget>
<output>50</output>
<result>50</result> | 50 | 50 | x=5*5*2 | calcformer-instruct-flan-xl_step-128k | First calculate the surface area of one cube: 5*5 =<gadget id="calculator">5*5</gadget><output>25</output> 25 square cm. Then calculate the surface area of the two cubes: 25*2 =<gadget id="calculator">25*2</gadget><output>50</output> 50 square cm.<result>50</result> | The surface area of one cube is 5*5=<gadget id="calculator">5*5</gadget><output>25</output> 25 square cm. The surface area of two cubes is two*25=<gadget id="calculator">2*25</gadget><output>50</output> 50 square cm. The answer is 50*5=<gadget id="calculator">50*5</gadget><output>250</output> 250 cm2.<result>250</result> |
ape210k__00027541 | If Xiao Ming insists on remembering 2 different English words every day, how many different English words can he remember in February 2011? | 如果小明每天坚持记住2个不同的英语单词，2011年的2月能记住多少个不同的英语单词． | <gadget id="calculator">28 * 2</gadget>
<output>56</output>
<result>56</result> | 56 | 56 | x=28*2 | calcformer-instruct-flan-xl_step-128k | There are 28 days in February 2011. If Xiao Ming remembers 2 different English words every day, then in February 2011 he can remember 28*2 =<gadget id="calculator">28*2</gadget><output>56</output> 56 different English words.<result>56</result> | There are 29 days in February 2011. If Xiao Ming remembers 2 different English words every day, then in 29 days, he can remember 2*29 =<gadget id="calculator">2*29</gadget><output>58</output> 58 different English words.<result>58</result> |
ape210k__00852333 | Xiao Ming can make one flower every two minutes, from 9:15 am to 9:31 am, how many flowers can he make in total? | 小明每两分钟可以做1朵花，他从上午9：15做到9：31，一共可以做几朵花？ | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 1</gadget>
<output>8</output>
<result>8</result> | 8 | 8 | x=16/2*1 | calcformer-instruct-flan-xl_step-128k | First find the total number of minutes by subtracting the time difference from the time Ming spent making flowers: 31 minutes - 15 minutes =<gadget id="calculator">31-15</gadget><output>16</output> 16 minutes. Then divide that time by two to find how many flowers Ming makes in that time period: 16 minutes / 2 minutes/flower =<gadget id="calculator">16/2</gadget><output>8</output> 8 flowers.<result>8</result> | From 9:15 am to 9:31 am, there are 8*12=<gadget id="calculator">8*12</gadget><output>96</output> 96 minutes. Since there are 2 minutes in every two minutes, then he can make 96/2=<gadget id="calculator">96/2</gadget><output>48</output> 48 flowers.<result>48</result> |
ape210k__00105643 | What is the sum of all prime numbers up to 20? | 20以内所有质数的和是多少． | <gadget id="calculator">2 + 3 + 5 + 7 + 11 + 13 + 17 + 19</gadget>
<output>77</output>
<result>77</result> | 77 | 77 | x=2+3+5+7+11+13+17+19 | calcformer-instruct-flan-xl_step-128k | The sum of the seven primes up to 20 is 2+3+5+7+11+13+17+19=<gadget id="calculator">2+3+5+7+11+13+17+19</gadget><output>77</output> 77.<result>77</result> | The sum of the primes up to 20 is 2, 3, 5, 7, 11, 13, 17, 19 = 20.<result>20</result> |
ape210k__00527730 | A school is divided into 4 groups to do good deeds for the nursing home, 25 deeds in the first week, 30 deeds in the second week, 29 deeds in the third week, how many deeds are done on average per week? What is the correct column | 某校分4组为敬老院做好事，第一星期做25件，第二星期做30件，第三星期做29件，平均每星期做多少件？列式正确的是多少 | <gadget id="calculator">25 + 30 + 29</gadget>
<output>84</output>
<gadget id="calculator">84 / 3</gadget>
<output>28</output>
<result>28</result> | 28 | 28 | x=(25+30+29)/3 | calcformer-instruct-flan-xl_step-128k | 25 + 30 + 29 =<gadget id="calculator">25+30+29</gadget><output>84</output> 84 deeds 84 / 3</gadget><output>28</output> 28 deeds/week.<result>28</result> | Total deeds done in 3 weeks = 25 + 30 + 29 =<gadget id="calculator">25+30+29</gadget><output>84</output> 84 deeds 84/4 =<gadget id="calculator">84/4</gadget><output>21</output> 21 deeds done on average per week.<result>21</result> |
ape210k__00307315 | If m*4=n*5 (both m and n are not 0), then ((m)/(n))=how much. | 如果m*4=n*5(m和n都不为0)，那么((m)/(n))=多少． | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<result>5/4 = around 1.25</result> | 5/4 | 1.25 | x=5/4 | calcformer-instruct-flan-xl_step-128k | The equation is m*4 = n*5, so multiply both sides by 4 to get m*4 = n*5m. Then divide both sides by 5 to get m/n = 5/4 = 5/4.<result>5/4 = around 1.25</result> | First, we need to determine the ratio of m*4 and n*5. To do this, we perform m*4 / n*5 = 2/3. We also find the value of m/n which is 4/5 / 3 = 2/15. The result of dividing both sides of the equation by 2 is m/n = 2/15 = 1/5.<result>1/5 = around 0.2</result> |
ape210k__00634223 | A butterfly flies 15.5 kilometers in 2 hours, and a bee flies 2.4 times faster than the butterfly. How many kilometers does the bee fly per hour? | 一只蝴蝶2小时飞行15.5千米，一只蜜蜂的飞行速度是蝴蝶的2.4倍，这只蜜蜂每小时飞行多少千米？ | <gadget id="calculator">15.5 / 2</gadget>
<output>7.75</output>
<gadget id="calculator">7.75 * 2.4</gadget>
<output>18.6</output>
<result>18.6</result> | 18.6 | 18.6 | x=15.5/2*2.4 | calcformer-instruct-flan-xl_step-128k | A butterfly flies 15.5 km in 2 hours, so it flies 15.5 / 2 =<gadget id="calculator">15.5/2</gadget><output>7.75</output> 7.75 kilometers per hour. A bee flies 2.4 times faster than the butterfly, so it flies 7.75 x 2.4 =<gadget id="calculator">7.75*2.4</gadget><output>18.6</output> 18.6 kilometers per hour.<result>18.6</result> | A butterfly flies 15.5 kilometers in 2 hours, so it flies 15.5 / 2 =<gadget id="calculator">15.5/2</gadget><output>7.75</output> 7.75 kilometers per hour. A bee flies 2.4 times faster than the butterfly, so it flies 7.75 x 2.4 =<gadget id="calculator">7.5*2.4</gadget><output>18</output> 18 kilometers per hour.<result>18</result> |
ape210k__01111343 | A section of road, 25% of the whole road was repaired for the first time, and 30% of the whole road was repaired for the second time, and there is still 45 kilometers left. How many kilometers are the total length of A and B? | 一段路，第一次修了全路的25%，第二次行了全路的30%，还剩45千米，甲乙两地全长多少千米？ | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/4) - (3/10)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">45 / (9/20)</gadget>
<output>100</output>
<result>100</result> | 100 | 100 | x=45/(1-25%-30%) | calcformer-instruct-flan-xl_step-128k | If 25% and 30% of the whole road is repaired, then the remaining part of the road, which is equal to 45 kilometers, is 100% - 25% - 30% = 75%. Since 75% of the whole road is equal to 45 kilometers, then 75% of the road is equal to 45/75 x 100 =<gadget id="calculator">75/75*100</gadget><output>100</output> 100 kilometers. Therefore, A and B should have a total length of 100 kilometers.<result>100</result> | The total area of the road that was not repaired is 45 x 100/25 =<gadget id="calculator">45*100/25</gadget><output>180</output> 180 kilometers. The total area of the road that was repaired is 180 x 100/30 =<gadget id="calculator">180*100/30</gadget><output>600</output> 600 kilometers. Since A and B is the total length of the road, then 600 + 45 =<gadget id="calculator">600+45</gadget><output>645</output> 645 kilometers is the total length of the road.<result>645</result> |
ape210k__00455351 | How many 0s are there at the end of the quotient of 2000/2? | 2000/2的商末尾有多少个0． | <result>3</result> | 3 | 3 | x=3 | calcformer-instruct-flan-xl_step-128k | First recognize that we have to be adding 0s to the end of the decimal. 2000/2 = 100 which has 2 0s at the end. 2000/2 = 500 which has 2 0s at the end. Thus there are 3 + 1 =<gadget id="calculator">3+1</gadget><output>4</output> 4 0s in the end of the quotient.<result>3</result> | The quotient is 2000/2, so there are 2*2=<gadget id="calculator">2*2</gadget><output>4</output> 4 0s at the end of the quotient.<result>4</result> |
ape210k__01060513 | The students of Hope Primary School donated a total of 3,600 yuan to the children in the disaster-stricken areas of Sichuan. There are 24 classes in the school. How much is the average donation for each class? | 希望小学的学生为四川灾区小朋友捐款，一共捐了3600元，全校有24个班，平均每班捐了多少元钱？ | <gadget id="calculator">3_600 / 24</gadget>
<output>150</output>
<result>150</result> | 150 | 150 | x=3600/24 | calcformer-instruct-flan-xl_step-128k | The total donation from all the classes is 3600yuan / 24 classes =<gadget id="calculator">3600/24</gadget><output>150</output> 150 yuan/class.<result>150</result> | The total donation from the school is 3600 x 24 =<gadget id="calculator">3600*24</gadget><output>86_400</output> 86,400. So, each class donates 86,400/24 = 3400.<result>3_400</result> |
ape210k__00597373 | Xiaoling's average score for Chinese, mathematics, and foreign language last semester was 92, she scored 87 for known Chinese, and 91 for foreign language. How much did she score for mathematics? | 小玲上学期语文、数学、外语三门功课的平均分是92分，已知语文得了87分，外语得了91分，数学得了多少分？ | <gadget id="calculator">92 * 3</gadget>
<output>276</output>
<gadget id="calculator">276 - 87 - 91</gadget>
<output>98</output>
<result>98</result> | 98 | 98 | x=92*3-87-91 | calcformer-instruct-flan-xl_step-128k | The sum of her marks for Chinese and foreign language is 91 + 87 =<gadget id="calculator">91+87</gadget><output>178</output> 178. Thus, her score for mathematics is 92 x 3 - 178 =<gadget id="calculator">92*3-178</gadget><output>98</output> 98.<result>98</result> | The sum of the score for the 3 subjects was 92 x 3 =<gadget id="calculator">92*3</gadget><output>276</output> 276. She scored 87 + 91 =<gadget id="calculator">87+91</gadget><output>178</output> 178. Thus, she scored 276 - 178 =<gadget id="calculator">276-278</gadget><output>-2</output> 292 for mathematics.<result>-2</result> |
ape210k__00302462 | The waterway from Wuhan to Chongqing is 1275 kilometers long. A ship sailed from Wuhan to Chongqing, and it has sailed the entire distance (3/5). How many kilometers away from Chongqing? | 武汉到重庆的水路长1275千米．一艘轮船从武汉开往重庆，已经航行了全程的(3/5)．离重庆还有多少千米？ | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1_275 * (2/5)</gadget>
<output>510</output>
<result>510</result> | 510 | 510 | x=1275*(1-(3/5)) | calcformer-instruct-flan-xl_step-128k | The ship sailed for 3/5 x 1275 =<gadget id="calculator">3/5*1275</gadget><output>765</output> 765 kilometers. Thus, 1275 - 765 =<gadget id="calculator">1275-765</gadget><output>510</output> 510 kilometers remain.<result>510</result> | Since the ship has sailed 3/5 of the distance, the ship is 1275 * (3/5) =<gadget id="calculator">1275*(3/5)</gadget><output>765</output> 765 kilometers away from Chongqing.<result>765</result> |
ape210k__00570630 | The volume of a cylinder is 3.6 cubic meters, the area of the base is 1.2 square meters, and the height is in meters. | 一个圆柱的体积是3.6立方米，底面积是1.2平方米，高是多少米． | <gadget id="calculator">3.6 / 1.2</gadget>
<output>3</output>
<result>3</result> | 3 | 3 | x=3.6/1.2 | calcformer-instruct-flan-xl_step-128k | The volume is 3.6 cubic meters, so it is 3.6/1.2=<gadget id="calculator">3.6/1.2</gadget><output>3</output> 3 meters tall.<result>3</result> | First find the volume of the cylinder: 3.6 cubic meters * 1.2 square meters =<gadget id="calculator">3.6*1.2</gadget><output>4.32</output> 4.32 cubic meters. Then divide the total volume by the volume of the base to find the height: 4.32 cubic meters / 1.2 square meters =<gadget id="calculator">4.32/1.2</gadget><output>3.6</output> 3.6 meters.<result>3.6</result> |
ape210k__00165114 | Spring Breeze Shoe Factory conducts quality inspection. Out of 200 pairs of shoes, 6 pairs are unqualified. What is the pass rate? | 春风制鞋厂进行质量检查，在200双鞋中有6双不合格，合格率是多少． | <gadget id="calculator">200 - 6</gadget>
<output>194</output>
<gadget id="calculator">194 / 200</gadget>
<output>97/100 = around 0.97</output>
<gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">(97/100) * 1</gadget>
<output>97/100 = around 0.97</output>
<result>97/100 = around 0.97</result> | 97/100 | 0.97 | x=((200-6)/200)*100% | calcformer-instruct-flan-xl_step-128k | There are 200 - 6 =<gadget id="calculator">200-6</gadget><output>194</output> 194 pairs of shoes that pass the inspection. The pass rate is 194/200 =<gadget id="calculator">194/200</gadget><output>97/100 = around 0.97</output> 0.97.<result>97/100 = around 0.97</result> | Since 6 pairs are unqualified, the total number of pairs that passed the inspection is 200 - 6 =<gadget id="calculator">200-6</gadget><output>194</output> 194. The pass rate is 194/200 = 94% which is the pass rate.<result>94</result> |
ape210k__00097916 | Measured on a plan with a scale of 1:500, the perimeter of a rectangular classroom is 10 cm, and the ratio of length to width is 3:2. What is the actual size of this classroom? | 在一幅比例尺为1：500的平面图上量得一间长方形教室的周长是10厘米，长与宽的比是3：2．这间教室的实际面积是多大？ | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 500</gadget>
<output>1/500 = around 0.002</output>
<gadget id="calculator">(3/5) / (1/500) / 100</gadget>
<output>3</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) / (1/500) / 100</gadget>
<output>2</output>
<gadget id="calculator">5 * 3 * 5 * 2</gadget>
<output>150</output>
<result>150</result> | 150 | 150 | x=(2+3)*(3/(2+3))/(1/500)/100*(2+3)*(2/(2+3))/(1/500)/100 | calcformer-instruct-flan-xl_step-128k | Let x be the length and y be the width of the classroom. Since the ratio is 3:2 and the scale is 1:500, we can write this equation: 3x + 2y = 10 cm. Subtracting the sides from both sides, we get x + y = 5 cm. Dividing both sides by 5, we get x = 3cm, and y = 2cm. Combining like terms and subtracting 3cm from both sides, we get 2c = 1c. Dividing both sides by 2 and dividing by 1, we get c = 1c/5. Multiplying both sides by 100 gives 100c = (1*10)/5. Dividing both sides by 100, we get c = 5c/10. Therefore, the length of the classroom is 3c = 3 * (5 * 10) =<gadget id="calculator">3* (5 * 10)</gadget><output>150</output> 150 cm, and the width of the classroom is 2c = 2 * (5 * 10) =<gadget id="calculator">2*(5*10)</gadget><output>100</output> 100 cm.<result>150</result> | Let X be the length and Y be the width of the classroom. Since the perimeter of the room is the sum of the length and width, the length has a length of 10*X and the width has a length of 10*Y. If we use X = 3*X and Y = 2*X, we can write: 3*X + 2*X = 10*X. Since we know the length and width from the plan, we can write: 3*X + 2*X = 10*X 2 *3X = 10 * X. We can multiply this fraction by 2 to find the number of units of X that are in the plan: 2 * 3*X = 3 * X. We multiply the fraction by 2 to find the number of units of Y that are in the plan: 2 * 2*Y = 10 * X. Since we know the length and width from the plan, we can write: 3*X = 3 * Y. Solving for Y, we get X = 3 * Y. Solving for X, we get Y = 2 * X. Multiplying by 2 to get Y = 2 * X. Solving for X, we get X = 4 * Y. Solving for Y, we get X = 2 * Y. Solving for Y, we get Y = 2 * X. Solving for Y, we get X = 4 * X. Since we know the length and width of the classroom, the area of the classroom is 3 * Y * 4 * X = 12 * X.<result>12</result> |
ape210k__00404437 | How many square centimeters of iron sheet should be used to make a cylindrical ventilation pipe with a base radius of 12cm and a length of 20cm? | 做一个底面半径为12cm，长为20cm的圆柱形通风管，至少要用多少平方厘米的铁皮？ | <gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">3.14 * 24 * 20</gadget>
<output>1_507.2</output>
<result>1_507.2</result> | 1_507.2 | 1,507.2 | x=3.14*(12*2)*20 | calcformer-instruct-flan-xl_step-128k | The area of the ventilation pipe is 2€r = 2 * 3.14 * 12 =<gadget id="calculator">2*3.14*12</gadget><output>75.36</output> 75.36 cm2. At a length of 20cm, the area is 20*75.36 =<gadget id="calculator">20*75.36</gadget><output>1_507.2</output> 1507.2 cm2.<result>1_507.2</result> | The circumference of the base of the pipe is 2*pi*12*20 = 144cm. The total area of the pipe is 2*pi*144 = 384cm2.<result>384</result> |
ape210k__01124405 | Move the decimal point of 3.0245 four places to the right, and then one place to the left, how many times the decimal point will be. | 把3.0245的小数点向右移动四位，再向左移动一位，这个小数就多少倍． | <gadget id="calculator">10_000 / 10</gadget>
<output>1_000</output>
<result>1_000</result> | 1_000 | 1,000 | x=10000/10 | calcformer-instruct-flan-xl_step-128k | If we move the decimal point three places to the right, it will move to tens of thousands of decimal places, or 10000 times. If we move the decimal point one place to the left, it will move to tens of thousands of decimal places, or 1000 times.<result>1000</result> | Four places to the right, and one place to the left is 10 places. If 3.0245 is a decimal, then 3.0245 is a 10,000,000 decimal.<result>10_000</result> |
ape210k__00418397 | Xiaohong reads a story book, and reads 15 pages on the first day, and then reads 3 pages more than the previous day every day, and finishes it in 5 days. How many pages does this storybook have? | 小红看一本故事书，第一天看15页，以后每一天都比前一天多看了3页，5天看完．这本故事书共多少页？ | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">15 + 12</gadget>
<output>27</output>
<gadget id="calculator">15 + 27</gadget>
<output>42</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">42 * (5/2)</gadget>
<output>105</output>
<result>105</result> | 105 | 105 | x=(15+(15+(5-1)*3))*5/2 | calcformer-instruct-flan-xl_step-128k | 15 pages on the first day. On the second day, he reads 15 + 3 =<gadget id="calculator">15+3</gadget><output>18</output> 18 pages. The third day, he reads 18 + 3 =<gadget id="calculator">18+3</gadget><output>21</output> 21 pages. The fourth day, he reads 21 + 3 =<gadget id="calculator">21+3</gadget><output>24</output> 24 pages. The fifth day, he read 24 + 3 =<gadget id="calculator">24+3</gadget><output>27</output> 27 pages. Therefore, the book has 15 + 18 + 21 + 24 + 27 =<gadget id="calculator">15+18+21+24+27</gadget><output>105</output> 105 pages.<result>105</result> | There are 5 - 1 =<gadget id="calculator">5-1</gadget><output>4</output> 4 days where the pages are 3 more each. The total difference in the pages between the first and fourth days is 3 * 4 =<gadget id="calculator">3*4</gadget><output>12</output> 12. On the second day there was 15 + 3 =<gadget id="calculator">15+3</gadget><output>18</output> 18 pages. On the third day there was 15 + 3 =<gadget id="calculator">15+3</gadget><output>18</output> 18 pages. On the fourth day there was 18 + 3 =<gadget id="calculator">18+3</gadget><output>21</output> 21 pages. The total number of pages on all five days is 15 + 24 + 27 + 30 + 42 =<gadget id="calculator">15+24+27+30+42</gadget><output>138</output> 138 pages.<result>138</result> |
ape210k__00568386 | The construction site transports 500 tons of cement, and the cement transported is (2/5) of the river sand transported. How many tons of river sand are transported? (Write out the quantitative relationship first, and then list the solution to the equation.) | 建筑工地运来500吨水泥，运来的水泥是运来的河沙的(2/5)，运来的河沙多少吨？(先写出数量关系，再列方程解．) | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">500 / (2/5)</gadget>
<output>1_250</output>
<result>1_250</result> | 1_250 | 1,250 | x=500/(2/5) | calcformer-instruct-flan-xl_step-128k | Let's first express the variable in terms of the other variable: 2 / 5 =<gadget id="calculator">2/5</gadget><output>2/5 = around 0.4</output> 0.4. We know that 500 tons of cement is (2/5) of the total amount of river sand, so this means there are 500/(2/5) =<gadget id="calculator">500/(2/5)</gadget><output>1_250</output> 1250 tons of river sand.<result>1_250</result> | Let x be the number of tons of river sand transported. Since there is a 2:1 ratio between the amount of cement transported and the amount of river sand, we can write the equation: 2/5 x = 500. By dividing both sides by 2, we get x = 500/2 / 2 =<gadget id="calculator">500/2</gadget><output>250</output> 250 tons of river sand were transported.<result>250</result> |
ape210k__00913865 | A cuboid water tank is 48cm long, 35cm wide and 20cm deep when measured from the inside. If it is filled with water, how many liters can it hold at most? | 一个长方体水箱，从里面量长48cm、宽35cm、深20cm．如果装水，最多可以装多少升？ | <result>33.6</result> | 33.6 | 33.6 | x=33.6 | calcformer-instruct-flan-xl_step-128k | 48cm x 35cm x 20cm =<gadget id="calculator">48*35*20</gadget><output>33_600</output> 33600cm2 is 33600cm2 / 1 liter =<gadget id="calculator">33600/1000</gadget><output>168/5 = around 33.6</output> 33.6 cubic cm. Therefore, the tank can hold 33.6 cubic cm * 1 liter =<gadget id="calculator">33.6*1</gadget><output>33.6</output> 33.6 liters.<result>33.6</result> | The height of the cuboid is 20cm x 20cm =<gadget id="calculator">20*20*.01</gadget><output>4</output> 4 cm. Since 1 liter is equal to 1000 cubic centimeters, then 48 cm x 35 cm x 4 cm =<gadget id="calculator">48*35*4</gadget><output>6_720</output> 6720 cubic centimeters. Hence, it can hold 6720 cubic centimeters / 1 liter =<gadget id="calculator">6820/1</gadget><output>6_820</output> 6820 cubic centimeters.<result>6_820</result> |
ape210k__00848537 | There are 600 parts in a batch, all (3/10) are completed on the first day, and all (5/12) are completed on the second day, how many more parts are completed on the second day than on the first day? | 一批零件有600个，第一天完成了全部的(3/10)，第二天完成了全部的(5/12)，第二天比第一天多完成多少个零件？ | <gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(5/12) - (3/10)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">600 * (7/60)</gadget>
<output>70</output>
<result>70</result> | 70 | 70 | x=600*((5/12)-(3/10)) | calcformer-instruct-flan-xl_step-128k | First find the number of parts completed on the first day: 3/10 * 600 parts =<gadget id="calculator">3/10*600</gadget><output>180</output> 180 parts. Then find the number of parts completed on the second day: 5/12 * 600 parts =<gadget id="calculator">5/12*600</gadget><output>250</output> 250 parts. Then subtract the number of parts completed on the first day from the number completed on the second day to find the difference: 250 parts - 180 parts =<gadget id="calculator">250-180</gadget><output>70</output> 70 parts.<result>70</result> | 5/12 =<gadget id="calculator">5/12</gadget><output>5/12 = around 0.416667</output> 4/60 of the batch is completed on the second day. (3/10)*600 =<gadget id="calculator">3/10*600</gadget><output>180</output> 180 parts are completed on the first day. 4/60 -1/18 = 1/24 of the batch is completed on the second day. This means 600 * (1/44) =<gadget id="calculator">600*(1/24)</gadget><output>25</output> 25 parts are completed on the second day.<result>25</result> |
ape210k__00324755 | The upper base of a trapezoid is 12 cm. If the upper base is extended by 3 cm, a parallelogram with an area of 120 cm2 is formed. What is the height of the original trapezoid in cm? | 一个梯形的上底是12厘米，如果把上底延长3厘米就成了一个面积是120平方厘米的平行四边形，原来梯形的高是多少厘米． | <gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<result>8</result> | 8 | 8 | x=120/(12+3) | calcformer-instruct-flan-xl_step-128k | The total height of the trapezoid is the sum of the height of the original base + the height of the parallelogram = 12 + 3 =<gadget id="calculator">12+3</gadget><output>15</output> 15 cm. The area of the parallelogram is 120 cm2 so the height of the trapezoid is 120/15 =<gadget id="calculator">120/15</gadget><output>8</output> 8 cm.<result>8</result> | The total height of the trapezoid is 2X (12 + 3) =<gadget id="calculator">2*12+3</gadget><output>27</output> 27 cm. The area of the parallelogram is given by 2 X 12 X 27 = 180 cm2. Therefore, 180 / 27 =<gadget id="calculator">180/27</gadget><output>20/3 = around 6.666667</output> 6.666667 cm2 is the height of the trapezoid.<result>20/3 = around 6.666667</result> |
ape210k__00340596 | Class 2 of grade 6 planted 50 trees in spring, and 4 of them did not survive. What is the survival rate? | 六年级二班同学春季植树50棵，其中4棵没活，则成活率为多少． | <gadget id="calculator">50 - 4</gadget>
<output>46</output>
<gadget id="calculator">46 / 50</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">(23/25) * 1</gadget>
<output>23/25 = around 0.92</output>
<result>23/25 = around 0.92</result> | 23/25 | 0.92 | x=((50-4)/50)*100% | calcformer-instruct-flan-xl_step-128k | The number of trees that survived is 50 - 4 =<gadget id="calculator">50-4</gadget><output>46</output> 46. The proportion of trees that survived is 46 / 50 =<gadget id="calculator">46/50</gadget><output>23/25 = around 0.92</output> 0.92 which is the survival rate.<result>23/25 = around 0.92</result> | The number of trees that survived is 50-4 =<gadget id="calculator">50-4</gadget><output>46</output> 46. The proportion of trees that survived is 46/50 =<gadget id="calculator">46/50</gadget><output>23/25 = around 0.92</output> 0.92. The survival rate is 0.92 x 100% =<gadget id="calculator">0.92*100</gadget><output>92</output> 92%.<result>92</result> |
ape210k__00659927 | The distance between A and B is 495 kilometers. A train travels 225 kilometers from A to B in 5 hours. According to this speed, how many hours will it take for the rest of the journey? | 甲乙两地相距495千米，一列火车从甲地到乙地5小时行了225千米，按照这样的速度，剩下的路程还需要几小时？ | <gadget id="calculator">495 - 225</gadget>
<output>270</output>
<gadget id="calculator">225 / 5</gadget>
<output>45</output>
<gadget id="calculator">270 / 45</gadget>
<output>6</output>
<result>6</result> | 6 | 6 | x=(495-225)/(225/5) | calcformer-instruct-flan-xl_step-128k | The train still has to travel 495 - 225 =<gadget id="calculator">495-225</gadget><output>270</output> 270 kilometers. It will take 270 / 225 =<gadget id="calculator">270/225</gadget><output>6/5 = around 1.2</output> 1.2 hours to travel the rest of the distance.<result>6</result> | The train has travelled 495 - 225 =<gadget id="calculator">495-225</gadget><output>270</output> 270 kilometers. If the train travels 225 kilometers in 5 hours, it will take 270 / 5 =<gadget id="calculator">270/5</gadget><output>54</output> 54 hours for the rest of the journey.<result>54</result> |
ape210k__00528255 | The average score of Xiaoming's three subjects in the mid-term exam is 93 points, and the scores of two subjects are 95 and 96 respectively. What is the score of the other subject? | 小明期中考试三门学科的平均成绩是93分，其中两门学科的成绩分别是95分和96分，另外一门学科的成绩是多少？ | <gadget id="calculator">93 * 3</gadget>
<output>279</output>
<gadget id="calculator">279 - 95 - 96</gadget>
<output>88</output>
<result>88</result> | 88 | 88 | x=93*3-95-96 | calcformer-instruct-flan-xl_step-128k | Xiaoming has to score 93 * 3 =<gadget id="calculator">93*3</gadget><output>279</output> 279 points for the three subjects. He scored 95 + 96 =<gadget id="calculator">95+96</gadget><output>191</output> 191 points in the two subjects above. So, he needs a score of 279 - 191 =<gadget id="calculator">279-191</gadget><output>88</output> 88 to pass the third subject.<result>88</result> | The total score of the three subjects is 93 x 3 =<gadget id="calculator">93*3</gadget><output>279</output> 279. The score of the other subject is 277-95 - 96 =<gadget id="calculator">277-95-96</gadget><output>86</output> 86.<result>86</result> |
ape210k__00057129 | The product of two factors is 3.25. What is the product after one factor is expanded to 10 times and the other factor is reduced to the original (1/10). | 两个因数的积是3.25，一个因数扩大到原来的10倍，另一个因数缩小为原来的(1/10)后积是多少． | <result>3.25</result> | 3.25 | 3.25 | x=3.25 | calcformer-instruct-flan-xl_step-128k | 10/10 =<gadget id="calculator">10/10</gadget><output>1</output> 1/10 reduces the original factor to 3.25. So, 3.25 * 1 =<gadget id="calculator">3.25*1</gadget><output>3.25</output> 3.25<result>3.25</result> | First multiply the product by 10 to find the total value: 3.25 * 10 =<gadget id="calculator">3.25*10</gadget><output>32.5</output> 32.5. Then multiply that value by 1/10 to find the value after the other factor is reduced: 32.5 * (10/10) =<gadget id="calculator">32.5*(10/10)</gadget><output>32.5</output> 32.5.<result>32.5</result> |
ape210k__00531842 | There are 21 students who participated in the science and technology group, which is 25% less than those who participated in the painting group. How many people participated in the painting group? (Solve it with equations. Can you solve it with arithmetic?) | 同学们参加科技小组的有21人，比参加绘画小组的少25%，参加绘画小组的有多少人？(用方程解答．你还会用算术方法解答吗？) | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">21 / (3/4)</gadget>
<output>28</output>
<result>28</result> | 28 | 28 | x=21/(1-25%) | calcformer-instruct-flan-xl_step-128k | If x is the number of students who participated in the painting group, then 0.75x is the number of students in the science and technology group. So 0.7x equals 21. So x equals 21/0.75 =<gadget id="calculator">21/0.75</gadget><output>28</output> 28 students.<result>28</result> | The number of students in the science and technology group is 0.75 times the number of students in the painting group. So, 0.75 * x = 21 students. Thus, x =<gadget id="calculator">21</gadget><output>21</output> 21.<result>21</result> |
ape210k__00017801 | Cut a cylinder of wood into the largest cone, and the volume of the cut part is 36 cubic decimeters, what is the volume of the cone? | 把一个圆柱体木头削成一个最大的圆锥体，削去部分的体积是36立方分米，则这个圆锥的体积是多少立方分米． | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>18</result> | 18 | 18 | x=36/2 | calcformer-instruct-flan-xl_step-128k | If A is the volume of the woodcut, and B is the volume of the remaining wood, then A-B = 36. Dividing both sides of the equation by 2, we get A = 36/2 =<gadget id="calculator">36/2</gadget><output>18</output> 18.<result>18</result> | Let C be the volume of the cone. The volume of the cylinder - that of the cut-away portion is C = 36 cubic decimeters. Thus, the volume of the cone is C = 36/3 =<gadget id="calculator">36/3</gadget><output>12</output> 12 cubic decimeters.<result>12</result> |
ape210k__00700655 | Among the 3 consecutive natural numbers, the smallest one is a, what is the average of these 3 numbers. | 连续的3个自然数中，最小的一个是a，这3个数的平均数是多少． | <result>1</result> | 1 | 1 | x=+1 | calcformer-instruct-flan-xl_step-128k | If the first number is a, then the second and third numbers are a and a+1 respectively. Since the numbers are consecutive, their average is (a+a+1)/3. If we divide this average by 3, we get the average as (a+a+1)/3. Multiplying by 3 gives the average as (a+a+1)/3*3. Since a+a+1+a+2 are consecutive, we simplify to get 3*a+2/3*a=1 Since the average of three consecutive numbers is 1.<result>1</result> | If there are 3 consecutive natural numbers, then the average of these 3 numbers is the middle natural number since there are a total of 3 numbers. If the average of the first natural number and the middle natural number is (a+1), then the average of the second natural number and the third natural numbera is (a+2). Therefore, the total average of these 3 numbers is (a+1+a+2)/3 = (a+3+a+2)/3 = 3*(a+2)/3 = 3*(a+2). Therefore, the average value of these 3 numbers is a + (a+2)/3 = 3*(a+2).<result>3</result> |
ape210k__00218615 | If the diameter of the base of the cylinder is tripled and the height is tripled, how many times is the volume enlarged? | 圆柱的底面直径扩大3倍，高缩小3倍，其体积是扩大多少倍 | <result>3</result> | 3 | 3 | x=3 | calcformer-instruct-flan-xl_step-128k | The volume of a cylinder is given by V = R2h. When the diameter is tripled, the radius increases to increase the volume by 2R2h. Since the height of the cylinder is tripled, the volume increases by 3H. Dividing both sides of the equation by 3 gives 3V = 3h. Dividing both sides by 3 gives V = 3h. The increase in the volume is 3 times.<result>3</result> | If the radius is tripled, the volume increases three-times as much because the area of the expanded cylinder is three times larger. If the height of the increased cylinder is tripled, the area is tripled because the area of the expanded cylinder is three times larger. Thus, the multiplier for increased volume is 3*3=<gadget id="calculator">3*3</gadget><output>9</output> 9.<result>9</result> |
ape210k__01221625 | Xiao Ming reads a 600-page book. On the first day, Xiao Ming reads 135 pages. On the second day, Xiao Ming reads another 165 pages. How many pages are left? | 小明看一本600页的书，第一天小明读了135页，第二天小明又读了165页，还剩多少页没读？ | <gadget id="calculator">135 + 165</gadget>
<output>300</output>
<gadget id="calculator">600 - 300</gadget>
<output>300</output>
<result>300</result> | 300 | 300 | x=600-(135+165) | calcformer-instruct-flan-xl_step-128k | 600 pages - 135 pages - 165 pages =<gadget id="calculator">600-135-165</gadget><output>300</output> 300 pages.<result>300</result> | Pages left after the first day: 600 - 135 - 165 =<gadget id="calculator">600-135-165</gadget><output>300</output> 300 pages. Pages left after the second day: 300 + 165 =<gadget id="calculator">300+165</gadget><output>465</output> 465 pages.<result>465</result> |
ape210k__00625889 | There is a 21-meter-long path between two buildings. On one side of the path, a tree is placed every 3 meters. How many trees should be carried? | 两幢楼中间有一条长21米的小路，在小路的一边每隔3米载一棵树，要载多少棵树． | <gadget id="calculator">7 - 1</gadget>
<output>6</output>
<result>6</result> | 6 | 6 | x=7-1 | calcformer-instruct-flan-xl_step-128k | There are 21/3 =<gadget id="calculator">21/3</gadget><output>7</output> 7 intervals along the path. Thus, 7 - 1 =<gadget id="calculator">7-1</gadget><output>6</output> 6 trees should be carried.<result>6</result> | There are 7 intervals of 3 meters along the path, so you have to pass by 7 trees to get to the first one. Since there are 3 trees on the other side, you have to pass by the first tree + 1 more tree =<gadget id="calculator">7+1</gadget><output>8</output> 8 trees.<result>8</result> |
ape210k__01223061 | The area of a rectangular park is 12 hectares. Expand the length of the park to three times its original size, and keep the width unchanged. What is the area of the park after the expansion? | 一个长方形公园的面积是12公顷．将这个公园的长扩大到原来的3倍，宽不变．扩建后公园的面积是多少？ | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<result>36</result> | 36 | 36 | x=12*3 | calcformer-instruct-flan-xl_step-128k | If the original area of the park is 12 hectares, and its length is three times its original length, it has a length of 3 * 12 =<gadget id="calculator">12*3</gadget><output>36</output> 36 hectares.<result>36</result> | Since 1 hectare is equal to 10 hectares, then the expansion of the park to three times its original size results in 3 * 10 =<gadget id="calculator">3*10</gadget><output>30</output> 30 hectares.<result>30</result> |
ape210k__00581987 | How many kilograms is (3/10) of 8 kilograms; (3/4) meter is ((())/(())) of (5/6) meter. | 8千克的(3/10)是多少千克；(3/4)米是(5/6)米的((())/(()))． | <gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">8 * (3/10)</gadget>
<output>12/5 = around 2.4</output>
<result>12/5 = around 2.4</result> | 12/5 | 2.4 | x=8*(3/10) | calcformer-instruct-flan-xl_step-128k | Three/10 of 8 kilograms is (3/10)*8 =<gadget id="calculator">3/10*8</gadget><output>12/5 = around 2.4</output> 2.4 kilograms.<result>12/5 = around 2.4</result> | 3/10 = 0.3/8 * 8 =<gadget id="calculator">3/10*8</gadget><output>12/5 = around 2.4</output> 2.4. 8 * (23/5) =<gadget id="calculator">8*(24/5)</gadget><output>192/5 = around 38.4</output> 38.4 kilograms.<result>192/5 = around 38.4</result> |
ape210k__00202072 | If the diameter of circle A and the radius of circle B are both 4 cm, what is the circumference of circle A equal to the circumference of circle B? | 如果甲圆的直径和乙圆的半径都为4厘米，那么甲圆的周长是乙圆周长的多少 | <gadget id="calculator">3.14 * 2 * 4</gadget>
<output>25.12</output>
<gadget id="calculator">4 / 25.12</gadget>
<output>0.159236</output>
<gadget id="calculator">3.14 * 0.159236</gadget>
<output>0.500001</output>
<result>0.500001</result> | 0.500001 | 0.500001 | x=3.14*4/(3.14*2*4) | calcformer-instruct-flan-xl_step-128k | The circumference of circle A is 2*pi*4 =<gadget id="calculator">2*pi*4</gadget><output>8*pi = around 25.132741</output> 25.132741 times the circumference of circle B. Since the diameter of circle A is 4 and the radius of circle B is 4, the ratio of the circumference of circle A to the circumference of circle B is 25.132741 / (25.132741 * 2) =<gadget id="calculator">25.132741 / (25.132741 * 2)</gadget><output>0.5</output> 0.5.<result>0.5</result> | The circumference of circle A is 2*pi*4 = 2*pi*16 = 32 cm. The circumference of circle B is 2*pi*4 = 2*pi*16 = 32 cm. The ratio of the circumference of circle A to the circumference of circle B is 32/32 =<gadget id="calculator">32/32</gadget><output>1</output> 1/1.<result>1</result> |
ape210k__00315598 | There are 15 bookshelves in the school library, each book has 5 layers, and each layer can hold 50 books. How many books can these bookshelves hold in total? | 学校图书室有15个书架，每个书有5层，每层可放50本书，这些书架一共可放多少本书？ | <gadget id="calculator">5 * 15 * 50</gadget>
<output>3_750</output>
<result>3_750</result> | 3_750 | 3,750 | x=5*15*50 | calcformer-instruct-flan-xl_step-128k | The 15 bookshelves have 15*5 =<gadget id="calculator">15*5</gadget><output>75</output> 75 layers. This means that 75*50 =<gadget id="calculator">75*50</gadget><output>3_750</output> 3750 books can be kept in these bookshelves.<result>3_750</result> | If 1 bookshelf can hold 50 books, 15 bookshelves can hold 15*50 =<gadget id="calculator">15*50</gadget><output>750</output> 750 books.<result>750</result> |
ape210k__01113609 | A grain store transports 5 carts of flour, 80 bags per cart, 40 kg per bag. How many kilograms of flour did the grain store transport in total? | 一个粮店运进5车面粉，每车80袋，每袋40千克．粮店共运进面粉多少千克？ | <gadget id="calculator">80 * 40 * 5</gadget>
<output>16_000</output>
<result>16_000</result> | 16_000 | 16,000 | x=80*40*5 | calcformer-instruct-flan-xl_step-128k | The store transported 5 carts * 80 bags/cart * 40 kg/bag =<gadget id="calculator">5*80*40</gadget><output>16_000</output> 16000 kg of flour.<result>16_000</result> | The grain store transports 5 * 80 * 40 =<gadget id="calculator">5*80*40</gadget><output>16_000</output> 16000 bags of flour. So in total, the store transports 16000 * 5 =<gadget id="calculator">16000*5</gadget><output>80_000</output> 80000 kg of flour.<result>80_000</result> |
ape210k__01081501 | A book has 80 pages. Xiao Ming reads it every day (1/10). He has read it for 5 days. How many pages are left? | 一本书80页，小明每天看(1/10)，已经看了5天，还剩多少页没看？ | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 5</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">80 * (1/2)</gadget>
<output>40</output>
<result>40</result> | 40 | 40 | x=80*(1-(1/10)*5) | calcformer-instruct-flan-xl_step-128k | 1/10 of the book is 80 x (1/10) =<gadget id="calculator">80*(1/10)</gadget><output>8</output> 8 pages. He has read 8 pages for 5 days so he read 8 x 5 =<gadget id="calculator">8*5</gadget><output>40</output> 40 pages. There are 80 - 40 =<gadget id="calculator">80-40</gadget><output>40</output> 40 pages left.<result>40</result> | There are 1/10 x 5 =<gadget id="calculator">1/10*5</gadget><output>1/2 = around 0.5</output> 0.5 pages of every day that Xio Ming reads. So he has read (1/2) x 5 =<gadget id="calculator">5*0.5</gadget><output>2.5</output> 2.5 pages. Thus, 80 - 2.5 =<gadget id="calculator">80-2.5</gadget><output>77.5</output> 77.5 pages are left.<result>77.5</result> |
ape210k__00039426 | After Xiaopang gave Xiaoqiao 3.35 yuan to buy books, it was 1.32 yuan more than Xiaoqiao. So how much more is Xiaopang than Xiaoqiao? | 小胖给了小巧3.35元钱买书后，还比小巧多1.32元，原来小胖比小巧多几元？ | <gadget id="calculator">3.35 * 2</gadget>
<output>6.7</output>
<gadget id="calculator">6.7 + 1.32</gadget>
<output>8.02</output>
<result>8.02</result> | 8.02 | 8.02 | x=3.35*2+1.32 | calcformer-instruct-flan-xl_step-128k | After giving 3.35 yuan to Xiaoqio, Xiaopang had 3.35 + 3.35 =<gadget id="calculator">3.35+3.35</gadget><output>6.7</output> 6.67 yuan. Since Xiaopang was 1.32 yuan more than Xiaoqio, then he was 6.67 + 1.32 =<gadget id="calculator">6.72+1.22</gadget><output>7.94</output> 7.94 yuan more than Xiaoqio.<result>7.94</result> | After Xiaopang gave away 3.35 yuan, he was left with 3.35+0.35+1.32 =<gadget id="calculator">3.35+0.35+1.32</gadget><output>5.02</output> 5.02 yuan. Xiaopang is 5.02+1.32 =<gadget id="calculator">5.02+1.32</gadget><output>6.34</output> 6.34 yuan more than Xiaoqio.<result>6.34</result> |
ape210k__01167071 | In Huangniwan Primary School, 2 classes of the sixth grade took the math semester exam. The average score of 39 students in class 1 was 75, and the 37 students in class 2 scored a total of 2851 points. What is the average math score of these two classes? | 黄泥完小六年级2个班进行数学期未考试，六1班39人平均75分，六2班37人共得了2851分，这两个班数学平均成绩多少分？ | <gadget id="calculator">75 * 39</gadget>
<output>2_925</output>
<gadget id="calculator">2_925 + 2_851</gadget>
<output>5_776</output>
<gadget id="calculator">39 + 37</gadget>
<output>76</output>
<gadget id="calculator">5_776 / 76</gadget>
<output>76</output>
<result>76</result> | 76 | 76 | x=(75*39+2851)/(39+37) | calcformer-instruct-flan-xl_step-128k | In class 1, 37 students scored an average math score of 75, a total of 75*39 =<gadget id="calculator">75*39</gadget><output>2_925</output> 2925. The total number of students who took the math exam in class 1 and class 2 is 39+37 =<gadget id="calculator">39+37</gadget><output>76</output> 76. Combined, the students in the two classes scored 2851+2925 =<gadget id="calculator">2855+2925</gadget><output>5_780</output> 5780. The average math score of these two classes is 5780/76 =<gadget id="calculator">5780/76</gadget><output>1_445/19 = around 76.052632</output> 76.<result>1_445/19 = around 76.052632</result> | In class 1, the total average score is 75. The total marks for class 1 are 39*75 =<gadget id="calculator">39*75</gadget><output>2_925</output> 2825. In class 2, the total marks for the 37 students are 2851. The total marks for both classes are 2825+2851 =<gadget id="calculator">2825+2851</gadget><output>5_676</output> 5676. The total number of students is 39+37 =<gadget id="calculator">39+37</gadget><output>76</output> 76. The average math score of the two classes is 5676/76 =<gadget id="calculator">5676/76</gadget><output>1_419/19 = around 74.684211</output> 471.<result>1_419/19 = around 74.684211</result> |
ape210k__00526792 | The distance between the two buildings is 24m, and there is a cement road in the middle. Now, trees are to be planted on both sides of this road, every 3m (both ends are not parallel), how many trees will be planted in total? | 两栋楼前后相隔24m，中间有一条水泥路，现在要在这条路的两边种树，每隔3m种一棵(两端都不平行)，一共要种多少棵树？ | <gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<result>14</result> | 14 | 14 | x=(24/3-1)*2 | calcformer-instruct-flan-xl_step-128k | There are 24/3 =<gadget id="calculator">24/3</gadget><output>8</output> 8 gaps between the two buildings. Therefore, there are 8 - 1 =<gadget id="calculator">8-1</gadget><output>7</output> 7 trees planted on both sides of the road. Since they are not parallel, they will have 7 * 2 =<gadget id="calculator">7*2</gadget><output>14</output> 14 trees planted in total.<result>14</result> | There is a gap of 24/3=<gadget id="calculator">24/3</gadget><output>8</output> 8 m between the two buildings. So, there will be 8 - 1 =<gadget id="calculator">8-1</gadget><output>7</output> 7 trees planted on both sides of the road.<result>7</result> |
ape210k__00004804 | Mother pours out 60mL of honey and adds 3L of water, mixes well and distributes to 10 children on average, how much can each drink? | 妈妈倒出60mL蜂蜜加入3L水，搅拌均匀后平均分给10个小朋友，每人可以喝到多少？ | <gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">60 + 3_000</gadget>
<output>3_060</output>
<gadget id="calculator">3_060 / 10</gadget>
<output>306</output>
<result>306</result> | 306 | 306 | x=(60+(3*1000))/10 | calcformer-instruct-flan-xl_step-128k | First find the total volume of the mixture: 3L * 1000mL =<gadget id="calculator">3*1000</gadget><output>3_000</output> 3000mL. Then add the volume of the honey to find the total volume: 3000mL + 60mL =<gadget id="calculator">3000+60</gadget><output>3_060</output> 3060mL. Then divide the volume by the number of children to find the amount each child can drink: 3060mL / 10 children =<gadget id="calculator">3060/10</gadget><output>306</output> 306mL/child.<result>306</result> | 3L is 3*1000 =<gadget id="calculator">3*1000</gadget><output>3_000</output> 3000mL. The total mixture is 3000+60=<gadget id="calculator">3000+60</gadget><output>3_060</output> 3060mL. It is 3060/10 =<gadget id="calculator">3060/10</gadget><output>306</output> 306. Each child can drink 306./10 =<gadget id="calculator">306/10</gadget><output>153/5 = around 30.6</output> 30.6mL.<result>153/5 = around 30.6</result> |
ape210k__00271413 | A project was originally planned to be completed by 10 people in 8 days. If it is to be completed 3 days ahead of schedule, how many people need to be added? (Solve with ratio) | 一项工程，原计划10人8天完成，如果要提前3天完成，需要增加多少人？(用比例解) | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<gadget id="calculator">80 - 80</gadget>
<output>0</output>
<gadget id="calculator">30 + 0</gadget>
<output>30</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<result>6</result> | 6 | 6 | x=(10*3+10*8-10*8)/(8-3) | calcformer-instruct-flan-xl_step-128k | 10*8=<gadget id="calculator">10*8</gadget><output>80</output> 80 The project is to be completed in 8-3=<gadget id="calculator">8-3</gadget><output>5</output> 5 days. 80/5=<gadget id="calculator">80/5</gadget><output>16</output> 16 The project requires 16-10=<gadget id="calculator">16-10</gadget><output>6</output> 6 additional people.<result>6</result> | First set up the equation and solve: 10*8 = (3*6)*10 Then multiply 10*8 to find how many people need to be added. Set up equation and solve: 10*8 = (3*6)*10 Then multiply 10*3 to find total new people Then set equation and solve: 10*8=(3*6)*10 Then multiply 10*3 to find total new people Then set equation and solve: 10*3 = (3*6)*10 Then multiply 10*3 to find total new people Then add 3 to the new total to get total new people. The result is 15 and is the correct answer.<result>15</result> |
ape210k__00029609 | There are two films, the first one is shown for 25 minutes, the second one is shown for 21 minutes, and the film (film) is 30 meters long every minute. Which film is longer? How many meters long? | 有两部电影，第一部放映用了25分钟，第二部放映了21分钟，每分钟放映影片(胶片)长30米，哪部影片长？长多少米？ | <gadget id="calculator">30 * 25</gadget>
<output>750</output>
<gadget id="calculator">30 * 21</gadget>
<output>630</output>
<gadget id="calculator">750 - 630</gadget>
<output>120</output>
<result>120</result> | 120 | 120 | x=(30*25)-(30*21) | calcformer-instruct-flan-xl_step-128k | 30 meters are shown for 25 minutes so the first one is 30 * 25 =<gadget id="calculator">30*25</gadget><output>750</output> 750 meters long. 30 meters are shown for 21 minutes so the second one is 30 * 21 =<gadget id="calculator">30*21</gadget><output>630</output> 630 meters long. The first film is 750 meters longer than the second one so it is 750 - 630 =<gadget id="calculator">750-630</gadget><output>120</output> 120 meters long.<result>120</result> | 30 * 25 =<gadget id="calculator">30*25</gadget><output>750</output> 750 meters The second movie is 30 meters longer, so it is 750 - 750 =<gadget id="calculator">750-750</gadget><output>0</output> 0 meters long.<result>0</result> |
ape210k__00678879 | A refrigerator is now priced at 2250 yuan, which is (1/10) lower than the original price. How much is the original price of this refrigerator? | 一台冰箱现在售价是2250元，比原价降低(1/10)．这台冰箱原价多少元？ | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">2_250 / (9/10)</gadget>
<output>2_500</output>
<result>2_500</result> | 2_500 | 2,500 | x=2250/(1-(1/10)) | calcformer-instruct-flan-xl_step-128k | Let X be the original price. The price now is X - 1/10(X) = 9/10 X. So 9/10 X = 2250. And X = 2250 / (9/10) =<gadget id="calculator">2250/(9/10)</gadget><output>2_500</output> 2500.<result>2_500</result> | The price decreased by 1/10 x 1000 =<gadget id="calculator">1/10*1000</gadget><output>100</output> 100. So the original price is 1000 - 100 =<gadget id="calculator">1000-100</gadget><output>900</output> 900.<result>900</result> |
ape210k__00082765 | A truck has a compartment length of 4 meters and a width of 2 meters. The height of the sand in the compartment is 10 decimeters. If the sand weighs 1.5 tons per cubic meter, how many tons of sand can this truck hold? | 一辆货车，车厢长4米，宽2米，车厢内装沙子的高度是10分米，如果每立方米沙子重1.5吨，这辆车可以装沙子多少吨？ | <gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">4 * 2 * 1</gadget>
<output>8</output>
<gadget id="calculator">1.5 * 8</gadget>
<output>12</output>
<result>12</result> | 12 | 12 | x=1.5*(4*2*10/10) | calcformer-instruct-flan-xl_step-128k | 10 decimal places equal 10/10=<gadget id="calculator">10/10</gadget><output>1</output> 1 meter. The volume of the compartment that is 10 cubic meters is 4 * 2 * 1 =<gadget id="calculator">4*2*1</gadget><output>8</output> 8 cubic meters. The weight of sand in this compartment is 1.5 * 8 =<gadget id="calculator">1.5*8</gadget><output>12</output> 12 tons.<result>12</result> | 10 centimeters is equal to 10/100 =<gadget id="calculator">10/100</gadget><output>1/10 = around 0.1</output> 1 meter. So the volume of the compartment is 4 * 2 * (1/10) =<gadget id="calculator">4*2*(1/10)</gadget><output>4/5 = around 0.8</output> 0.8 cubic meters. Therefore, the weight of the sand is 1.5 * 0.8 =<gadget id="calculator">1.5*0.8</gadget><output>1.2</output> 1.2 tons.<result>1.2</result> |
ape210k__00393410 | The length of the base of a triangle is 450 meters and the height is 1200 decimeters. What is its area in m**2. | 一块三角形地的底边长是450米，高是1200分米，它的面积是多少m**2． | <gadget id="calculator">1_200 / 10</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">450 * 60</gadget>
<output>27_000</output>
<result>27_000</result> | 27_000 | 27,000 | x=450*(1200/10)/2 | calcformer-instruct-flan-xl_step-128k | 1200/10=<gadget id="calculator">1200/10</gadget><output>120</output> 120. The height of the triangle is 120/2=<gadget id="calculator">120/2</gadget><output>60</output> 60 meters. Area of the triangle= s2 / 2 = 450 * 60=<gadget id="calculator">450 * 60</gadget><output>27_000</output> 27,000 m2 Answer: 27000<result>27_000</result> | 1/2 * 450 * 1200 =<gadget id="calculator">1_200/100</gadget><output>12</output> 12000 m2 450 * 12=<gadget id="calculator">450 * 12</gadget><output>5_400</output> 5400 m2 5400 * 1/2=<gadget id="calculator">5400 * 1/2</gadget><output>2_700</output> 2700 m2<result>2_700</result> |
ape210k__00430356 | There are a total of 20 5-cent coins and 2-cent coins, and the total value of the coins is 0.7 yuan. How many 2-cent coins are there? | 有5分硬币和2分硬币共20枚，币值一共是0.7元，其中2分硬币有多少枚 | <gadget id="calculator">0.7 * 100</gadget>
<output>70</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">70 - 40</gadget>
<output>30</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<result>10</result> | 10 | 10 | x=20-(0.7*100-20*2)/(5-2) | calcformer-instruct-flan-xl_step-128k | Let C be the number of 2-cent coins. Let N be the number of 5-cent coins. The number of 5- and 2-cent coins is 20C + 10N= 0.7 yuan 20C + 10N = 0.7. Combining like terms, we get 20C + 10N = 0.7. Dividing both sides by 20, we get the number of 5-cent coins = 15. Dividing both sides by 5, we get the number of 2-cent coins = 10.<result>10</result> | Let C be the number of 2-cent coins. The number of 5-cent coins is 20-C. The sum of the values from 1- to 5-cent coins will be 5-C + 2-C = 20C. Subtracting the value of 5-C from the sum of the values will give 20 - 5-C = 20C. Dividing both sides of the equation by 5, we get 20 - 5C = 70. Dividing both sides of the equation by 2, we get 20 - 2C = 70. Dividing both sides by 2, we get C = 20. There are 20 - 20 =<gadget id="calculator">20-20</gadget><output>0</output> 0 2-cent coins.<result>0</result> |
ape210k__01193377 | The 15 people in the mathematics interest group need to take a group photo. A total of 30 yuan will be paid for sending 5 photos at a time, and 2.5 yuan will be paid for one additional photo. | 数学兴趣小组15人要拍集体照，拍一次送5张照片共要付30元，加洗一张要付2.5元，每人一张共要付多少元． | <gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">2.5 * 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 30</gadget>
<output>55</output>
<result>55</result> | 55 | 55 | x=2.5*(15-5)+30 | calcformer-instruct-flan-xl_step-128k | There are 15 - 5 =<gadget id="calculator">15-5</gadget><output>10</output> 10 more photos to be paid. The total cost for these additional photos is 2.5 * 10 =<gadget id="calculator">2.5*10</gadget><output>25</output> 25. Thus, 30 + 25 =<gadget id="calculator">30+25</gadget><output>55</output> 55 dollars will be paid.<result>55</result> | There are 15 - 5 =<gadget id="calculator">15-5</gadget><output>10</output> 10 photos left. Each additional photo cost 2.5 yuan, meaning that 10 * 2.5 =<gadget id="calculator">10*2.5</gadget><output>25</output> 25 dollars will be needed. Subtracting the 30 dollars from the total cost leaves 30 - 25 =<gadget id="calculator">30-25</gadget><output>5</output> 5 dollars for additional photos.<result>5</result> |
ape210k__00207920 | A cylinder has a base circumference of 12.56 cm and a height of 10 cm, what is its volume in cubic centimeters | 一个圆柱体的底面周长是12.56厘米，高10厘米，它的体积是多少立方厘米 | <gadget id="calculator">12.56 / 3.14 / 2</gadget>
<output>2</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">3.14 * 4 * 10</gadget>
<output>125.6</output>
<result>125.6</result> | 125.6 | 125.6 | x=3.14*(12.56/3.14/2)**(12.56/3.14/2)*10 | calcformer-instruct-flan-xl_step-128k | 12.56 / 3.14 / 2 = 3.14 / 2 = 3.14 / 3.14 = 2 cm The volume is given by V = r2h = 22/7 * 3.14 * 2 * 10 = 125.6 cm3<result>125.6</result> | 12.56 / 3.14 / 2 = 3.14 / 2 = 3.14 C = 12.56 / 3.14 / 2 = 3 / 3.14 C = 3.14 C = 10.23 C.P. 3.14 * 3.14 * 10.23 * 10 = 226.06 C.P.<result>226.06</result> |
ape210k__00719647 | A 1-meter-long rope is folded in half and then folded in half again. What is the total length of each section at this time? | 一根1米长的绳子对折再对折，这时每段是全长的多少 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<result>1/4 = around 0.25</result> | 1/4 | 0.25 | x=(1/4) | calcformer-instruct-flan-xl_step-128k | The final stage of the folding process is to reduce the length of the rope to 1 meter / 4 =<gadget id="calculator">1/4</gadget><output>1/4 = around 0.25</output> 0.25 meters. Each section is then 1 meter / 0.25 =<gadget id="calculator">1*0.25</gadget><output>0.25</output> 0.25 meters long.<result>0.25</result> | The total length of the rope is 1 meter, which means it is 1 * 10 =<gadget id="calculator">1*10</gadget><output>10</output> 10 sections. The total length of each section is 10/2 =<gadget id="calculator">10/2</gadget><output>5</output> 5 sections.<result>5</result> |
ape210k__01134645 | To make the quotient of □27/9 a three-digit number, what is the maximum number in □. | 要使□27/9的商是三位数，□里最大填多少． | <result>9</result> | 9 | 9 | x=9 | calcformer-instruct-flan-xl_step-128k | To make the number a three digit number, it must be divisible by 9 and have 27 as the only factor. Since 27/9=<gadget id="calculator">27/9</gadget><output>3</output> 3, the maximum value that '9' can take in a three digit number is 9.<result>9</result> | The sum of the digits in 27/9 is 27+9=<gadget id="calculator">27+9</gadget><output>36</output> 36. The nearest multiple of 9 is 9 (36-9=27). Thus, 36/9 is the highest multiple of 9 that satisfies the constraints of a three-digit number.<result>36</result> |
ape210k__00042563 | The students went to the military training and lined up in groups of 12 or 10. It was just right. At least how many people went to the military training this time? | 同学们去军训，按12个一组或10人一组排队，都正好，这次军训至少去了多少人？ | <gadget id="calculator">2 * 2 * 3 * 5</gadget>
<output>60</output>
<result>60</result> | 60 | 60 | x=2*2*3*5 | calcformer-instruct-flan-xl_step-128k | There were 60 in number.<result>60</result> | Since 12 x 10 =<gadget id="calculator">12*10</gadget><output>120</output> 120, there were at least 120 students who attended the military training.<result>120</result> |
ape210k__00454242 | The distance between A and B is 182 km. A tourist bus travels from A to B at an average of 52 kilometers per hour; a car departs from A at the same time and travels 56 kilometers per hour. Which car arrives first? How early is it? | 甲、乙两地相距182千米．一辆旅游车从甲地开往乙地，平均每小时行驶52千米；一辆小轿车同时从甲地出发，每小时行驶56千米．哪辆车先到？先到多少时间？ | <gadget id="calculator">182 / 52</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">182 / 56</gadget>
<output>13/4 = around 3.25</output>
<gadget id="calculator">(7/2) - (13/4)</gadget>
<output>1/4 = around 0.25</output>
<result>1/4 = around 0.25</result> | 1/4 | 0.25 | x=(182/52)-(182/56) | calcformer-instruct-flan-xl_step-128k | The bus travels 182 km / 52 km/hour =<gadget id="calculator">182/52</gadget><output>7/2 = around 3.5</output> 3.5 hours. The car travels 182 km / 56 km/hour =<gadget id="calculator">182/56</gadget><output>13/4 = around 3.25</output> 3.25 hours. Thus, the car arrives first at 3.5 hours - 3.25 hours =<gadget id="calculator">3.5-3.25</gadget><output>0.25</output> 0.25 hours early.<result>0.25</result> | The bus travels 182 kilometers in 182 / 52 =<gadget id="calculator">182/52</gadget><output>7/2 = around 3.5</output> 3.5 hours. The car travels 182 kilometers in 182 / 56 =<gadget id="calculator">182/56</gadget><output>13/4 = around 3.25</output> 3.25 hours. The car is ahead by 3.25 hours, so it arrives first.<result>3</result> |
ape210k__00345975 | 3050 meters = how many kilometers. | 3050米=多少千米． | <gadget id="calculator">3_050 / 1_000</gadget>
<output>61/20 = around 3.05</output>
<result>61/20 = around 3.05</result> | 61/20 | 3.05 | x=3050/1000 | calcformer-instruct-flan-xl_step-128k | 3050 meters = 30.5 km = 1 km. =<gadget id="calculator">3050/1000</gadget><output>61/20 = around 3.05</output> 3.05 km.<result>61/20 = around 3.05</result> | 3050 / 1_000 = 3.050</result> |
ape210k__00237648 | In the mid-term final exam of class 41, 17 people got excellent in Chinese, 20 people got excellent in mathematics, and the students who got "excellent" by the teacher all stood up and counted 30 people. How many people got "excellent" in both subjects? | 四1班同学中期末考试中，语文得优的有17人，数学得优的有20人，老师请得"优"的同学都站起来，数了数有30人．两科都得"优"的有几人？ | <gadget id="calculator">20 - 30</gadget>
<output>-10</output>
<gadget id="calculator">17 + (-10)</gadget>
<output>7</output>
<result>7</result> | 7 | 7 | x=17+20-30 | calcformer-instruct-flan-xl_step-128k | There were 17+20 =<gadget id="calculator">17+20</gadget><output>37</output> 37 people who got "excellent" in Chinese and mathematics. Therefore, 37-30 =<gadget id="calculator">37-30</gadget><output>7</output> 7 people got "excellent" in both subjects.<result>7</result> | There were 17 students who got Excellent in Chinese - 30 students who got Excellent in mathematics =<gadget id="calculator">17-30</gadget><output>-13</output> 13 students who got Excellent in both subjects.<gadget id="calculator">20-(-13)</gadget><output>33</output> 33 students who got Excellent in two subjects.<result>33</result> |
ape210k__00593049 | cylinder and a cone have the same base and height. If the volume of the cylinder is 42 cubic decimeters, what is the volume of the cone? | 一个圆柱和一个圆锥等底同高，如果圆柱的体积是42立方分米，圆锥的体积是多少立方分米． | <gadget id="calculator">42 / 3</gadget>
<output>14</output>
<result>14</result> | 14 | 14 | x=42/3 | calcformer-instruct-flan-xl_step-128k | The volume of a cone is 1/3*the volume of the cylinder. The volume of the cone is 42/3=<gadget id="calculator">42/3</gadget><output>14</output> 14 cubic decimeters.<result>14</result> | If a cylinder has a volume of 42 cubic decimeters, a cone has a volume of (42/3)*3=<gadget id="calculator">42/3*3</gadget><output>42</output> 42 cubic decimeters.<result>42</result> |
ape210k__00205557 | The road construction team wants to build a road with a length of 80 kilometers. 20% of the total length was repaired on the first day, and 1/4 of the total length was repaired on the second day. How many kilometers were repaired in two days? | 修路队要修一条长80千米的公路．第一天修了全长的20%，第二天修了全长的(1/4)，两天共修了多少千米？ | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) + (1/4)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">80 * (9/20)</gadget>
<output>36</output>
<result>36</result> | 36 | 36 | x=80*(20%+(1/4)) | calcformer-instruct-flan-xl_step-128k | The first day, the road was repaired in 80 x 20/100 =<gadget id="calculator">80*20/100</gadget><output>16</output> 16 kilometers. The second day, the road was repaired in 80 x 1/4 =<gadget id="calculator">80*1/4</gadget><output>20</output> 20 kilometers. Therefore, a total of 16 + 20 =<gadget id="calculator">16+20</gadget><output>36</output> 36 kilometers were repaired in two days.<result>36</result> | A total of 20/100 x 80 =<gadget id="calculator">20/100*80</gadget><output>16</output> 16 kilometers were repaired on the first day. And, 20 / 4 =<gadget id="calculator">20/4</gadget><output>5</output> 5 kilometers were repaired on the second day. Therefore, 16 + 5 =<gadget id="calculator">16+5</gadget><output>21</output> 21 kilometers were repaired in two days.<result>21</result> |
ape210k__00593470 | 6: 9=((())/9)=(2/(()))=how much: 3. | 6：9=((())/9)=(2/(()))=多少：3． | <result>2</result> | 2 | 2 | x=2 | calcformer-instruct-flan-xl_step-128k | 2: 3 2 / 3=<gadget id="calculator">2 / 3</gadget><output>2/3 = around 0.666667</output> 0.666667 (6.66767) / (3.333333)= 2.333333 2.333333<result>2</result> | 2/6=2/9 = 2/18 = 1/18 = 1/9 So, 2/1=(2/9)*3 = (2/3)*3 = 6/18 = (2/3) Hence, 2/3=(2/9)*3 = (2/3) 6 = 2/3 (2/3*3) = (2/3)*3 = (6/3)*3 = (2*3)=<gadget id="calculator">(2*3)</gadget><output>6</output> 6/6=<gadget id="calculator">(2/3)*3</gadget><output>2</output> 2/6= 1/3 Thus, 2/3 is 2/3: 3/2 = (2/3)*3 = 6/6 = 1/6. So, 2/6= (2/3)*3 = 6/6 = 1/6. Thus, 2/3 = (1/6)*3 = 1/6 = 1/6. Thus, 2/3 is 2/3. Thus, 2/3 is 2: 1/6 = 1/3. Since 1/6 is the LCM of 1 and 3, 2/3 is 2/3. Thus, 2/3 is 2/3. Thus, 2: 1 = (2/3)*3 = 2 * 3 = 6/6 = 1/6. The answer is 2/6. = (3/12)*3 = (1/3)*3 = 2/3. Thus, 2/3 is 2/3. = (1/6)*3 = 1/6. The result>1/2 = 1/6 = 0/6 = 0/6 = 0/6. = 1/6. = 1/6 = 0.666667 = 0/6. = 1/6. = 1/6. = 1/6. = 1/6. = 1/6. = 1/6. = 1/6. = 1/6 = 0.666667 = 0.66666. = 0.666666. = 0.666666. = 1/6. = 1/6. = 0.666666. = 0.666666. = 1/6. = 1/6. = 1/6. = 1/6. = 1/6 = 1/6. = 1/6. = 1/6 = 1/6. = 1/6. = 1/6. = 1/6. = 1/12. = 1/12. = 1/6. = 1./6. = 1/6. = 1/6. = 1/12. = 1/6. = 1/6. = 1/12. = 1/12. = 1/6. = 1/6. = 1/12. = 1/12. = 1/6. = 1/12. = 1/12. = 1/12. = 1/12. = 1/12. = 1/12. = 1/12. = 1/12. = 1.666666. = 1/6. Hence 2/3. 2/(1/6) = 2/(1/4) = 1/9. = 1/12. = 1/6. = 1/12. = 1/12. = 1/12. = 1/12. = 1/6. = 1/6. = 1/1. = 1.666666. = 1/1. = 1.666668. 1/14. = 2/3. |
ape210k__00499361 | The train departs from station A at 10:00 p.m. and arrives at station B at 7:00 a.m. the next morning. How many hours did the train run in total? | 火车晚上10时从甲站出发，第二天早晨7时到达乙站．这列火车一共行了多少小时． | <gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">2 + 7</gadget>
<output>9</output>
<result>9</result> | 9 | 9 | x=(12-10)+7 | calcformer-instruct-flan-xl_step-128k | The train ran from 10:00 p.m. to 7:00 a.m., so it operated for 2 + 7 =<gadget id="calculator">2+7</gadget><output>9</output> 9 hours.<result>9</result> | The train ran from 10:00 p.m. to 7:00 a.m., so it ran for 1 + 7 =<gadget id="calculator">1+7</gadget><output>8</output> 8 hours.<result>8</result> |
ape210k__00346666 | To make the quotient of □35/45 have two digits, what should be the minimum number in □. | 要使□35/45的商是两位数，□里最小应填多少． | <result>5</result> | 5 | 5 | x=5 | calcformer-instruct-flan-xl_step-128k | Since the 35/45 is a multiple of 5, it must end with a 5 to make it a two digit number. Thus, the answer is 5.<result>5</result> | The quotient 35/45 = 7/9 so the number must be a multiple of 9. The answer is 9.<result>9</result> |
ape210k__00092631 | How much postage can be paid with one stamp of 80 cents, one stamp of 1.20 yuan and one stamp of 2 yuan. | 用80分、1.20元、2元的邮票各一张，可以支付多少种邮资． | <gadget id="calculator">3 + 3 + 1</gadget>
<output>7</output>
<result>7</result> | 7 | 7 | x=3+3+1 | calcformer-instruct-flan-xl_step-128k | There are three sets of 10 cents postage stamps which are represented by the denomination "10 x 0.8 = 8". So there are a total of 3 sets of stamps representing 8 cents postage. With the first set of 10 cents stamps, you can make a total of 3 + 3 + 1 =<gadget id="calculator">3+3+1</gadget><output>7</output> 7 purchases. With the second set of 10 cents stamps, you can make a total of 3 + 3 + 1 =<gadget id="calculator">3+3+1</gadget><output>7</output> 7 purchases. With the third set of 10 cents stamps, you can make a total of 4 + 3 =<gadget id="calculator">4+3+1</gadget><output>8</output> 8 purchases. Since there are 3 sets of 10 cents stamps, this means that there is a total of 7 purchases. With the third set of 10 cents stamps, you can make a total of 5 purchases. Since there are 3 sets of 10 cents stamps, this means that there is a total of 7 purchases. Therefore, 7 purchases can be made.<result>7</result> | Three stamps are needed to send a letter weighing 80 cents or $0.80. If one person uses a single stamp, then the cost is 80 cents / 0.80 = 5 dollars. If one person uses two stamps, the cost is 1.2 * 2 = $2. If one person uses all three stamps, then the cost is 3 * 2 = $6. The amount of the postage is 6 + 4 + 2 =<gadget id="calculator">6+4+2</gadget><output>12</output> 12 dollars. Since there are three ways of paying, then the total amount of postage paid is 12 + 4 + 2 =<gadget id="calculator">12+4+2</gadget><output>18</output> 18 dollars.<result>18</result> |
ape210k__01156231 | If a cylinder with a base diameter of 5 cm and a height of 12 cm is cut into two half cylinders along the diameter, what is the increase in surface area? | 把一个底面直径为5厘米，高为12厘米的圆柱体沿直径切割成两个半圆柱，表面积增加多少． | <gadget id="calculator">5 * 12 * 2</gadget>
<output>120</output>
<result>120</result> | 120 | 120 | x=5*12*2 | calcformer-instruct-flan-xl_step-128k | With a height of 12 cm along the diameter, the area of a cylinder is 5*12=<gadget id="calculator">5*12</gadget><output>60</output> 60 cm by diameter. When the cylinder is cut into two half along the diameter, the area is increased by 2*60=<gadget id="calculator">2*60</gadget><output>120</output> 120 cm.<result>120</result> | The height of the cylinder is 12 cm because 12 / 2 =<gadget id="calculator">12/2</gadget><output>6</output> 6. The surface area of the cylinder is 30 cm square because 5 X 6 =<gadget id="calculator">5*6</gadget><output>30</output> 30. When the cylinder is cut into two half, the surface area increases to 60 cm square because 2 X 30 =<gadget id="calculator">2*30</gadget><output>60</output> 60.<result>60</result> |
ape210k__00504625 | The number of white rabbits is 540, and the number of black rabbits is five times that of white rabbits. How many more black rabbits are there than white rabbits? | 白兔的只数是540只，黑兔的只数是白兔的5倍，黑兔比白兔多多少只？ | <gadget id="calculator">540 * 5</gadget>
<output>2_700</output>
<gadget id="calculator">2_700 - 540</gadget>
<output>2_160</output>
<result>2_160</result> | 2_160 | 2,160 | x=540*5-540 | calcformer-instruct-flan-xl_step-128k | Black rabbits: 540 * 5 =<gadget id="calculator">540*5</gadget><output>2_700</output> 2700. Difference: 2700 - 540 =<gadget id="calculator">2700-540</gadget><output>2_160</output> 2160. There are 2160 more black rabbits than white rabbits.<result>2_160</result> | Black rabbits:540/5=<gadget id="calculator">540/5</gadget><output>108</output> 108. White rabbits:540/540 =<gadget id="calculator">540/540</gadget><output>1</output> 1. There are 108-540 =<gadget id="calculator">108-540</gadget><output>-432</output> 432 more black rabbits than white rabbits.<result>-432</result> |
ape210k__00121367 | Two ships depart from Wuhan (A) and Shanghai (B) respectively at the same time. After meeting for 23.5 hours, A travels 23 kilometers per hour, and B travels 20 kilometers per hour. How far is it from Wuhan to Shanghai? | 两艘轮船分别从武汉(甲)、上海(乙)同时相对开出，经过23.5小时相遇，甲每小时行23千米，乙每小时行20千米．问武汉到上海相距多远？ | <gadget id="calculator">23 + 20</gadget>
<output>43</output>
<gadget id="calculator">43 * 23.5</gadget>
<output>1_010.5</output>
<result>1_010.5</result> | 1_010.5 | 1,010.5 | x=(23+20)*23.5 | calcformer-instruct-flan-xl_step-128k | A travels 23 + 20 =<gadget id="calculator">23+20</gadget><output>43</output> 43 km per hour. The distance between the two ships is 43 * 23.5 =<gadget id="calculator">43*23.5</gadget><output>1_010.5</output> 1010.5 km.<result>1_010.5</result> | The combined rate of the two ships is 23 + 20 =<gadget id="calculator">23+20</gadget><output>43</output> 43 km per hour. The distance from Wuhan to Shanghai is 43/23 * 23.5 =<gadget id="calculator">43/23*23.5</gadget><output>43.934783</output> 43.934783 kilometers.<result>43.934783</result> |
ape210k__00163090 | How many consecutive 0.05s are subtracted from 4 to leave 1. | 从4里面连续减去多少个0.05，才剩下1． | <gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">3 / 0.05</gadget>
<output>60</output>
<result>60</result> | 60 | 60 | x=(4-1)/0.05 | calcformer-instruct-flan-xl_step-128k | 4 - 1=<gadget id="calculator">4 - 1</gadget><output>3</output> 3 3 / 0.05=<gadget id="calculator">3 / 0.05</gadget><output>60</output> 60.<result>60</result> | 4 - 1 = 3 - 0.05 = 0.05 The number of 0.05s is 3/5 =<gadget id="calculator">3/5</gadget><output>3/5 = around 0.6</output> 0.6 Subtracting 0.05 each time makes the total decrease 0.3/5 =<gadget id="calculator">0.3/5</gadget><output>0.06</output> 0.06 There are 6 sets of 0.05s between each set. The answer is 6!/0.05 = 36.<result>36</result> |
ape210k__01131837 | Grandpa Wang’s family has a rectangular vegetable field with a length of 8 meters and a width of 4 meters. How long should the fence be at least to surround the three sides of the vegetable field? | 王爷爷家有一块长方形菜地的长是8米，宽是4米，在这块菜地的三边围上篱笆，至少需要多长的篱笆？ | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 8</gadget>
<output>16</output>
<result>16</result> | 16 | 16 | x=8+4*2 | calcformer-instruct-flan-xl_step-128k | To create a fence that is at least 2 meters wide, the length of the first part of the fence should be 8 meters long. And the second part of the fence should be at least 4 meters long. So, the length of the second part of the fence will be 4 meters long, and the length of the first part of the fence will be 8 meters long. The whole fence would then be 8 meters long, 4 meters wide, and 4 meters long. Therefore to create a complete fence at least 2 meters wide, the length of the first part plus the length of the second part would be 8+4+4=<gadget id="calculator">8+4+4</gadget><output>16</output> 16 meters.<result>16</result> | The perimeter of the field is 8 meters + 4 meters =<gadget id="calculator">8+4</gadget><output>12</output> 12 meters. Since the length of the fence is 12, the whole fence will be 12 meters long.<result>12</result> |
ape210k__01128379 | Xiaoli has 6 coats and 3 trousers. She wants to choose a suit to participate in the competition. How many different choices are there? | 小丽有6件上衣，3件裤子，她要选择一套衣服去参加比赛，一共有多少种不同的选法． | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<result>18</result> | 18 | 18 | x=6*3 | calcformer-instruct-flan-xl_step-128k | The number of different suits that Xiaoli can choose is 3 x 6 =<gadget id="calculator">3*6</gadget><output>18</output> 18.<result>18</result> | There are 6 x 3 =<gadget id="calculator">6*3</gadget><output>18</output> 18 different ways to choose a coat. There are 3 x 3 =<gadget id="calculator">3*3</gadget><output>9</output> 9 different ways to choose a pair of trousers. Therefore, there are 18 + 9 =<gadget id="calculator">18+9</gadget><output>27</output> 27 different ways to choose a suit.<result>27</result> |
ape210k__00060842 | A parallelogram and a rectangle have the same area. It is known that the length of the rectangle is 18 cm, the width is 10 cm, and the base of the parallelogram is 15 cm. What is its height in cm? | 一个平行四边形和一个长方形的面积相等，已知长方形的长是18厘米，宽是10厘米，平行四边形的底是15厘米，那么它的高是多少厘米． | <gadget id="calculator">10 / 15</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">18 * (2/3)</gadget>
<output>12</output>
<result>12</result> | 12 | 12 | x=18*10/15 | calcformer-instruct-flan-xl_step-128k | The area of a rectangle is 18 cm x 10 cm =<gadget id="calculator">18*10</gadget><output>180</output> 180 cm2. The area of a parallelogram is equal to 180 cm2 / 15 cm2 =<gadget id="calculator">180/15</gadget><output>12</output> 12 cm2.<result>12</result> | Area of the rectangle is 18 x 10 =<gadget id="calculator">18*10</gadget><output>180</output> 180 cm2. Area of a parallelogram= 180/15 =<gadget id="calculator">180/15</gadget><output>12</output> 12 cm2. The height of the parallelogram is 12 / 15 cm =<gadget id="calculator">12/15</gadget><output>4/5 = around 0.8</output> 0.8 cm.<result>4/5 = around 0.8</result> |
ape210k__00627878 | The Hangzhou Bay Bridge opened to traffic on May 1, 2008. The total length of the bridge is 36 kilometers. Uncle Wang drove across the bridge at a speed of 80 kilometers per hour. How many minutes would it take? | 杭州湾跨海大桥于2008年5月1日通车．大桥全长36千米，王叔叔开车以每小时80千米的速度通过此桥，大约需要几分钟？ | <gadget id="calculator">36 / 80</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 60</gadget>
<output>27</output>
<result>27</result> | 27 | 27 | x=36/80*60 | calcformer-instruct-flan-xl_step-128k | The total distance covered is 36 km, so it would take 36 km / 80 kilometers per hour =<gadget id="calculator">36/80</gadget><output>9/20 = around 0.45</output> 0.45 hours. Thus, it would take 0.45 hour * 60 minutes =<gadget id="calculator">0.45*60</gadget><output>27</output> 27 minutes.<result>27</result> | The total distance covered is 36 kilometers, so it took Wang 36 km / 80 kilometers per hour =<gadget id="calculator">36/80</gadget><output>9/20 = around 0.45</output> 0.45 hours. There are 60 minutes in an hour, so it took Uncle Wang 0.45 hours * 60 minutes =<gadget id="calculator">0.94*60</gadget><output>56.4</output> 56.4 minutes to cross.<result>56.4</result> |
ape210k__00458220 | The quotient of two numbers is 12. If the divisor remains the same and the dividend is divided by 3, what is the quotient? | 两个数的商是12，如果除数不变，被除数除以3，商是多少． | <gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>4</result> | 4 | 4 | x=12/3 | calcformer-instruct-flan-xl_step-128k | If the divisor is 12 and the dividend is $120, the quotient is 12/3=<gadget id="calculator">12/3</gadget><output>4</output> 4.<result>4</result> | If the divisor is 12 and the dividend is divided by 2, each portion is equal to 12/2=<gadget id="calculator">12/2</gadget><output>6</output> 6 pieces. If the divisor remains the same and the dividend is divided by 3, each portion is equal to 6/3=<gadget id="calculator">6/3</gadget><output>2</output> 2 pieces.<result>2</result> |
ape210k__00416735 | The area of the parallelogram is 360 cm**2, and the height is 18 cm. What is the base of the parallelogram in cm? | 平行四边形的面积是360厘米**2，高是18厘米，这个平行四边形的底是多少厘米？ | <gadget id="calculator">360 / 18</gadget>
<output>20</output>
<result>20</result> | 20 | 20 | x=360/18 | calcformer-instruct-flan-xl_step-128k | 360 / 18 =<gadget id="calculator">360/18</gadget><output>20</output> 20 cm.<result>20</result> | 360/18 =<gadget id="calculator">360/18</gadget><output>20</output> 20 cm. The base of the parallelogram is equal to 360/20=<gadget id="calculator">360/20</gadget><output>18</output> 18 cm.<result>18</result> |
ape210k__00167725 | The reciprocal sum of two prime numbers is (7/10), what is the sum of these two prime numbers. | 两个质数的倒数和是(7/10)，则这两个质数的和是多少． | <gadget id="calculator">2 + 5</gadget>
<output>7</output>
<result>7</result> | 7 | 7 | x=2+5 | calcformer-instruct-flan-xl_step-128k | Seven/10 of one's sum is 7/10, and the reciprocal sum is reciprocal, meaning the sum is given by 1/(sum of two primes) = 7/10. Since the reciprocal sum of two primes is 7/10, and the sum of two primes is to be 7/10, then the sum of two primes is 7/10*10 =<gadget id="calculator">7/10*10</gadget><output>7</output> 7.<result>7</result> | If the reciprocal sum of two prime numbers is (7/10), then the sum of those two prime numbers is 7/10 * 2 = 7/5. Since the sum of those two prime numbers is 7/5, then those two prime numbers must be consecutive integers. Two consecutive integers are co-prime, thus the sum must be a multiple of 3. Since multiples of 3 are less than 10, then the sum must be more than 3. Since the sum of those two prime numbers is 7/5, then there must be more than 3 prime numbers. Therefore, the sum of those two prime numbers must be 6+7 =<gadget id="calculator">6+7</gadget><output>13</output> 13.<result>13</result> |
ape210k__01198255 | Two boards of the same length are nailed together to form a new board with a length of 40 cm. The overlapping part in the middle is 12 cm. What is the original length of this board in cm? | 把两块一样长的木板钉在一起，钉成了一块长40厘米的新木板，中间重叠部分是12厘米，这块木板原来长多少厘米． | <gadget id="calculator">40 - 12</gadget>
<output>28</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<gadget id="calculator">14 + 12</gadget>
<output>26</output>
<result>26</result> | 26 | 26 | x=(40-12)/2+12 | calcformer-instruct-flan-xl_step-128k | The new board is 40 cm + 12 cm =<gadget id="calculator">40+12</gadget><output>52</output> 52 cm. If the new board was nailed together, the original board was 52 cm / 2 =<gadget id="calculator">52/2</gadget><output>26</output> 26 cm long.<result>26</result> | The boards have an overlap of 40-12 =<gadget id="calculator">40-12</gadget><output>28</output> 28 cm. Since two boards have the same length and they have to be nailed together, the original length of the board is 28*2 =<gadget id="calculator">28*2</gadget><output>56</output> 56 cm.<result>56</result> |
ape210k__01207407 | There are 216 display boards for an exhibition, and it has been done for 10 days, and the remaining display boards are 8 more than the ones already made. How many panels have you made? | 某展览会要做216块展板，已经做了10天，剩下的展板比已经做好的还多8块．已经做好了多少块展板？ | <gadget id="calculator">216 - 8</gadget>
<output>208</output>
<gadget id="calculator">208 / 2</gadget>
<output>104</output>
<result>104</result> | 104 | 104 | x=(216-8)/2 | calcformer-instruct-flan-xl_step-128k | There are 216 display boards in total, so the ones that are already made are 216 - 8 =<gadget id="calculator">216-8</gadget><output>208</output> 208 boards. So the ones that have been made are 208 / 2 =<gadget id="calculator">208/2</gadget><output>104</output> 104 display boards.<result>104</result> | If the remaining display boards are 8 more than the ones already made, then the ones already made are 216-8 =<gadget id="calculator">216-8</gadget><output>208</output> 208. So the total number of display boards is 208+216 =<gadget id="calculator">208+216</gadget><output>424</output> 424. Therefore, you have made 424/10 =<gadget id="calculator">424/10</gadget><output>212/5 = around 42.4</output> 42.4 display boards.<result>212/5 = around 42.4</result> |
ape210k__00246234 | In a bottle of salt water, the ratio of salt to salt water is 1:10. After adding 1 gram of salt and 9 grams of water, what is the proportion of salt to water? | 一瓶盐水中，盐与盐水的比是1：10，加入1克盐与9克水后，盐占水的多少 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<result>1/9 = around 0.111111</result> | 1/9 | 0.111111 | x=1/(10-1) | calcformer-instruct-flan-xl_step-128k | The original ratio is 1/10, so the salt is 1/10*10 =<gadget id="calculator">1/10*10</gadget><output>1</output> 1/10 of the total volume of the mixture. Since there is a total of 10 grams in the mixture, the amount of salt is (1/10)*10 =<gadget id="calculator">(1/10)*10</gadget><output>1</output> 1 gram of salt. After adding 1 gram of salt and 9 grams of water, the new ratio is 1+1 =<gadget id="calculator">1+1</gadget><output>2</output> 2 gram salt to 10+9 gram water. The total volume is 10+9 =<gadget id="calculator">10+9</gadget><output>19</output> 19 grams. Since the volume is 9 grams, the ratio of the weight of the salt to water is 2/19 = 1/9.<result>1/9</result> | The original proportion of salt to salt water is 1:10, or 1/10. After adding 1 gram salt, the new proportion is 1+1/10 =11/10. Since 1 gram salt contains 1/10 grams salt, the proportion of 1 gram salt to 10 gram salt is 1/10. Since 9 grams of water contain 9 grams water, the proportion of 1 gram water to 10 gram water is 10/(9+1) = 10/9. The proportion of salt to water is 1/10 / 10/9 =<gadget id="calculator">1/10/10-9</gadget><output>-899/100 = around -8.99</output> 0.89.<result>8</result> |
ape210k__00844129 | The fertilizer factory produces 1,550 bags of fertilizer in January (31 days), and 1,540 bags of fertilizer in February (28 days). How many more bags of fertilizer are produced per day in February than in January? | 化肥厂一月份(31天)生产化肥1550袋，二月份(28天)生产化肥1540袋，二月份比一月份平均每天多生产化肥多少袋？ | <gadget id="calculator">1_540 / 28</gadget>
<output>55</output>
<gadget id="calculator">1_550 / 31</gadget>
<output>50</output>
<gadget id="calculator">55 - 50</gadget>
<output>5</output>
<result>5</result> | 5 | 5 | x=1540/28-1550/31 | calcformer-instruct-flan-xl_step-128k | The total number of fertilizer produced in January is 1,550 / 31 =<gadget id="calculator">1550/31</gadget><output>50</output> 50 bags. The total number of fertilizer produced in February is 1,540 / 28 =<gadget id="calculator">1540/28</gadget><output>55</output> 55 bags. The difference is 55 - 50 =<gadget id="calculator">55-50</gadget><output>5</output> 5 bags.<result>5</result> | The total fertilizer produced in January is 1,550 / 31 =<gadget id="calculator">1505/31</gadget><output>1_505/31 = around 48.548387</output> 48.548387 bags. The total fertilizer produced in February is 1,540 / 28 =<gadget id="calculator">1540/28</gadget><output>55</output> 55.548387 bags. The difference is 55.548387 - 48.548387 =<gadget id="calculator">55.548387-48.548387</gadget><output>7</output> 7 more bags of fertilizer per day in February than in January.<result>7</result> |
ape210k__00170743 | Uncle workers make parts, 125 parts a day for the first 3 days, and 160 parts a day after that, how many parts does uncle workers make in total in a week? | 工人叔叔做零件，前3天每天做125个，以后每天做160个，一星期工人叔叔共做零件几个？ | <gadget id="calculator">125 * 3</gadget>
<output>375</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 160</gadget>
<output>640</output>
<gadget id="calculator">375 + 640</gadget>
<output>1_015</output>
<result>1_015</result> | 1_015 | 1,015 | x=125*3+(7-3)*160 | calcformer-instruct-flan-xl_step-128k | The first 3 days make 3*125=<gadget id="calculator">3*125</gadget><output>375</output> 375 parts. There are 7-3=<gadget id="calculator">7-3</gadget><output>4</output> 4 days left in the week. During the next 4 days, they make 4*160=<gadget id="calculator">4*160</gadget><output>640</output> 640 parts. Altogether, uncle workers make 375+640=<gadget id="calculator">375+640</gadget><output>1_015</output> 1015 parts.<result>1_015</result> | The first set of days makes 3*125=<gadget id="calculator">3*125</gadget><output>375</output> 375 parts. The next 5 days make 5*160=<gadget id="calculator">5*160</gadget><output>800</output> 800 parts. Uncle workers make a total of 375+800=<gadget id="calculator">375+800</gadget><output>1_175</output> 1175 parts.<result>1_175</result> |
ape210k__00058372 | 1897+687-897． | 1897+687-897． | <gadget id="calculator">687 - 897</gadget>
<output>-210</output>
<gadget id="calculator">1_897 + (-210)</gadget>
<output>1_687</output>
<result>1_687</result> | 1_687 | 1,687 | x=1897+687-897 | calcformer-instruct-flan-xl_step-128k | 1897+687-897. =>1897+687-897=<gadget id="calculator">1897+687-897</gadget><output>1_687</output> 1687.<result>1_687</result> | 1897+687-897. 246.91+246.91.09<result>246.91</result> |
ape210k__01103303 | The Shanghai-Nanjing Expressway (Shanghai to Nanjing) has a total length of 274.08 kilometers. Two cars, A and B, leave Shanghai and Nanjing at the same time. After meeting each other for 1.6 hours, car A travels 80 kilometers per hour, and how much does car B travel per hour? km? | 沪宁高速公路(上海到南京)全长274.08千米，甲乙两辆汽车车分别从上海和南京同时相对开出，经过1.6小时相遇，甲车每小时行80千米，乙车每小时行多少千米？ | <gadget id="calculator">274.08 / 1.6</gadget>
<output>171.3</output>
<gadget id="calculator">171.3 - 80</gadget>
<output>91.3</output>
<result>91.3</result> | 91.3 | 91.3 | x=274.08/1.6-80 | calcformer-instruct-flan-xl_step-128k | If they meet after 1.6 hours, then A travels for 1.6 * 80 =<gadget id="calculator">1.6*80</gadget><output>128</output> 128 kilometers. If the total distance is 274.08, then the remaining distance equals 274.08 - 128 =<gadget id="calculator">274.08-128</gadget><output>146.08</output> 146.08 kilometers. Since car B travels at a speed of 146.08 kilometers per hour, then car B must travel 146.08 / 1.6 =<gadget id="calculator">146.08/1.6</gadget><output>91.3</output> 91.3 kilometers per hour.<result>91.3</result> | If they meet after 1.6 hours, then the total time they took is 1.6*60 =<gadget id="calculator">1.6*60</gadget><output>96</output> 96 hours. Then the distance traveled by car B is 274.08-96 =<gadget id="calculator">274.08-96</gadget><output>178.08</output> 178.08 km. Since car A travels 80 kilometers per hour, then car B must travel 178.08 / 1.6 =<gadget id="calculator">178.08/1.6</gadget><output>111.3</output> 111.3 km per hour.<result>111.3</result> |
ape210k__00539290 | The product of the upper base, lower base and height of a trapezoid is 60 square centimeters and 100 square centimeters respectively. What is the area of the trapezoid in square centimeters? | 一个梯形的上底、下底与高相乘的积分别是60平方厘米和100平方厘米，这个梯形的面积是多少平方厘米． | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">160 / 2</gadget>
<output>80</output>
<result>80</result> | 80 | 80 | x=(100+60)/2 | calcformer-instruct-flan-xl_step-128k | First find the area of the lower base by multiplying the product of the upper base and the lower base: 60 square centimeters + 100 square centimeters =<gadget id="calculator">60+100</gadget><output>160</output> 160 square centimeters. Now find the area of the trapezoid by dividing the area of the lower base by the area of the upper base: 160 square centimeters / 2 =<gadget id="calculator">160/2</gadget><output>80</output> 80 square centimeters.<result>80</result> | The height of the trapezoid is 100 / 2 =<gadget id="calculator">100/2</gadget><output>50</output> 50 square centimeters. The area of the trapezoid is 60 / 2 =<gadget id="calculator">60/2</gadget><output>30</output> 30 square centimeters.<result>30</result> |
ape210k__00220817 | Define a new operation: We stipulate that "*" is an operation symbol, and its operation rules are: a*b=a*ba/b Please use the above rules to calculate: 1.2*6=how much. | 定义新运算：我们规定"*"是一种运算符号，它的运算规则是：a*b=a*b-a/b请你用上面的规则计算：1.2*6=多少． | <gadget id="calculator">1.2 * 6</gadget>
<output>7.2</output>
<gadget id="calculator">1.2 / 6</gadget>
<output>0.2</output>
<gadget id="calculator">7.2 - 0.2</gadget>
<output>7</output>
<result>7</result> | 7 | 7 | x=1.2*6-1.2/6 | calcformer-instruct-flan-xl_step-128k | The gadget id="calculator">1.2 * 6<output>7.2</output><gadget id="calculator">1.2 / 6</gadget><output>0.2</output><gadget id="calculator">7.2 - 0.2</gadget><output>7</output><result>7</result> | The result>0.8</result> |
ape210k__01121675 | A garment factory planned to process 28,000 sets of garments in October, but it completed the plan in the first half of the month (3/5), and the second half of the month (4/7). How many sets of garments were processed this month more than the original plan? | 某服装厂10月份计划加工服装28000套，结果上半月完成计划的(3/5)，下半月完成计划的(4/7)，这个月比原计划多加工服装多少套？ | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">28_000 * (3/5)</gadget>
<output>16_800</output>
<gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">28_000 * (4/7)</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 - 28_000</gadget>
<output>-12_000</output>
<gadget id="calculator">16_800 + (-12_000)</gadget>
<output>4_800</output>
<result>4_800</result> | 4_800 | 4,800 | x=28000*(3/5)+28000*(4/7)-28000 | calcformer-instruct-flan-xl_step-128k | The factory was able to process 3/5 x 28,000 =<gadget id="calculator">3/5*28000</gadget><output>16_800</output> 16800 sets of garments in the first half of the month. The same factory was able to process 4/7 x 28,000 =<gadget id="calculator">4/7*28000</gadget><output>16_000</output> 16000 sets of garments in the second half of the month. So, it was able to process 16800 + 16000 =<gadget id="calculator">16800+16000</gadget><output>32_800</output> 32800 sets of garments in the entire month. Thus, it was able to process 32800 - 28000 =<gadget id="calculator">32800-28000</gadget><output>4_800</output> 4800 sets more than the original plan.<result>4_800</result> | The first half of the month was more successful than the original plan by 3/5*28000 =<gadget id="calculator">3/5*28000</gadget><output>16_800</output> 16800 sets of garments. The second half of the month was more successful than the original plan by 4/7*28000 =<gadget id="calculator">4/7*28000</gadget><output>16_000</output> 16000 sets of garments. Thus, the total number of sets of garments processed in the month is 16800+16000 =<gadget id="calculator">16800+16000</gadget><output>32_800</output> 38000. Thus, the total number of sets of garments that were processed this month more than the original plan is 38000-16000 =<gadget id="calculator">38000-16000</gadget><output>22_000</output> 22000.<result>22_000</result> |
ape210k__00523691 | There is a magical tree that used to have only one branch. In the first year, it grows a branch. In the second year, each branch grows a branch. In the third year, each branch grows a branch again. Calculate like this , how many branches are there in the tree in the fifth year? | 有一颗神奇的树，原来只有一个树枝，第一年长出一个树枝，第二年每个树枝分别长出1个树枝，第三年每个树枝又都分别长出1个树枝，照这样计算，第五年这棵树上一共有几个树枝？ | <gadget id="calculator">2 ** 5</gadget>
<output>32</output>
<result>32</result> | 32 | 32 | x=2**5 | calcformer-instruct-flan-xl_step-128k | In the third year, the tree grows 12 branches because 2 x 1 =<gadget id="calculator">2*1</gadget><output>2</output> 2. In the fourth year, the tree grows 16 branches because 3 x 2 + 1 =<gadget id="calculator">3*2+1</gadget><output>7</output> 7. In the fifth year, the tree grows 32 branches because 4 x 2 + 1 = 32.<result>32</result> | In the first year, there are 1 + 1 + 1 + 1 + 1 =<gadget id="calculator">1+1 + 1 + 1 + 1</gadget><output>5</output> 5 branches in the tree. In the second year, there are 5 + 1 + 1 =<gadget id="calculator">5+1+1+1</gadget><output>8</output> 8 branches in the tree. In the third year, there are 8 + 1 + 1 =<gadget id="calculator">8+1+1+1</gadget><output>11</output> 11 branches in the tree. In the fourth year, there are 11 + 1 + 1 =<gadget id="calculator">11+1+1+1</gadget><output>14</output> 14 branches in the tree. In the fifth year, there are 14 + 1 + 1 =<gadget id="calculator">14+1+1+1</gadget><output>17</output> 17 branches in the tree.<result>17</result> |
ape210k__00964275 | Xiao Ming and Xiao Li type a manuscript together. If they type alone, Xiao Ming will finish it in 2 hours, and Xiao Li will finish it in 3 hours. How many hours will it take for them to type together? | 小明和小丽共同打一份稿件，如果单独打，小明要2小时完成，小丽要3小时完成，请问他们合打要多少小时？ | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/2) + (1/3)</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 / (5/6)</gadget>
<output>6/5 = around 1.2</output>
<result>6/5 = around 1.2</result> | 6/5 | 1.2 | x=1/((1/2)+(1/3)) | calcformer-instruct-flan-xl_step-128k | If Xiao Ming can type a manuscript in 2 days, then he can type 1/2 of the manuscript in a day. If Xiao Li can type a manuscript in 3 days, then he can type 1/3 of the manuscript in a day. Since the sum of the work done by each of them is 1/2 + 1/3 = 5/6, then they can finish the whole work in 6/5=<gadget id="calculator">6/5</gadget><output>6/5 = around 1.2</output> 1.2 hours.<result>6/5 = around 1.2</result> | If Xiao Ming can type 1/2 of the manuscript in an hour, then the whole manuscript will take 2*1/2 =<gadget id="calculator">1/2*2</gadget><output>1</output> 1 hour to type. If Xiao Li can type 1/3 of the manuscript in an hour, then the whole manuscript will take 1/3*3 =<gadget id="calculator">1/3*3</gadget><output>1</output> 1 hour to type together.<result>1</result> |
ape210k__00559775 | Xiaohong reads a 124-page book of fairy tales. After 5 days of reading, there are still 77 pages left. How many pages has she read? (solution by equation) | 小红看一本124页的童话书，看了5天后还剩77页没有看．她已经看了多少页？(用方程解) | <gadget id="calculator">124 - 77</gadget>
<output>47</output>
<result>47</result> | 47 | 47 | x=124-77 | calcformer-instruct-flan-xl_step-128k | Pages read = 124 - 77 =<gadget id="calculator">124-77</gadget><output>47</output> 47.<result>47</result> | There are 124 - 77=<gadget id="calculator">124-77</gadget><output>47</output> 47 pages left to read. So, she has read 47/5=<gadget id="calculator">47/5</gadget><output>47/5 = around 9.4</output> 9.4 pages.<result>47/5 = around 9.4</result> |
ape210k__00269138 | The factory shipped 1.08 tons of raw materials, and it was planned to take 4.5 days to save 0.06 tons of raw materials per day. How many days can these raw materials actually be used for? | 工厂运来1.08吨原料，计划用4.5天，实际每天节约原料0.06吨，这些原料实际可以用多少天？ | <gadget id="calculator">1.08 / 4.5</gadget>
<output>0.24</output>
<gadget id="calculator">0.24 - 0.06</gadget>
<output>0.18</output>
<gadget id="calculator">1.08 / 0.18</gadget>
<output>6</output>
<result>6</result> | 6 | 6 | x=1.08/(1.08/4.5-0.06) | calcformer-instruct-flan-xl_step-128k | The total planned amount of raw material is 1.08 tons / 4.5 days =<gadget id="calculator">1.08/4.5</gadget><output>0.24</output> 0.24 tons/day. The loss of raw materials per day is 0.24 - 0.06 =<gadget id="calculator">0.24-0.06</gadget><output>0.18</output> 0.18 tons/day. So, the raw materials can be used for 1.08/0.18 =<gadget id="calculator">1.08/0.18</gadget><output>6</output> 6 days.<result>6</result> | There were 1.08 / 4.5 =<gadget id="calculator">1.08/4.5</gadget><output>0.24</output> 0.24 tons of raw materials per day. This means that these raw materials can be used for 1.08 / 0.24 =<gadget id="calculator">1.08/0.24</gadget><output>4.5</output> 4.5 days. But the raw materials are actually available for 4.5 - 0.06 =<gadget id="calculator">4.5-0.06</gadget><output>4.44</output> 4.44 days. Therefore, these raw materials can be used for 4.5 days.<result>4.5</result> |
ape210k__00903391 | A barrel of oil weighs 60 kilograms in total, and after using (3/5) of the oil, the total weight of the barrels is 30 kilograms. What is the net weight of this barrel of oil? | 一桶油连桶共重60千克，用去油的(3/5)后，连桶共重30千克．这桶油净重多少千克？ | <gadget id="calculator">60 - 30</gadget>
<output>30</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">30 / (3/5)</gadget>
<output>50</output>
<result>50</result> | 50 | 50 | x=(60-30)/(3/5) | calcformer-instruct-flan-xl_step-128k | When using 3/5 of the oil, the barrel is left with only 60-30 =<gadget id="calculator">60-30</gadget><output>30</output> 30 kilograms of oil. Since the barrel weighs 30 kilograms, the weight of the oil is 30/(3/5) =<gadget id="calculator">30/(3/5)</gadget><output>50</output> 50 kilograms.<result>50</result> | If the barrel weighs 60 kilograms, and after using (3/5)of the oil, the total weight of the oil becomes 30 kilograms, the remaining weight of oil is 60-30=<gadget id="calculator">60-30</gadget><output>30</output> 30 kilograms. The net weight of the barrel of oil is therefore 30*3/5=<gadget id="calculator">30*3/5</gadget><output>18</output> 18 kilograms.<result>18</result> |
ape210k__00248003 | An extracurricular group erected a 6-meter-high bamboo pole on the ground, and measured the length of the shadow to be 9.6 meters. At the same time, the shadow length of a chimney was measured to be 32 meters. How tall is the chimney? (Solve using ratio method) | 一个课外小组，把6米高的竹竿直立在地上，量得影子的长度是9.6米，同时测得一个烟囱的影长是32米，那么烟囱有多高？(用比例的方法解答) | <gadget id="calculator">32 * 6</gadget>
<output>192</output>
<gadget id="calculator">192 / 9.6</gadget>
<output>20</output>
<result>20</result> | 20 | 20 | x=((32*6)/(9.6)) | calcformer-instruct-flan-xl_step-128k | The height of the pole is 6 meters because 6 / 9.6 =<gadget id="calculator">6/9.6</gadget><output>0.625</output> 0.625. The height of the chimney is 32 meters because 0.625 X 32 =<gadget id="calculator">0.625*32</gadget><output>20</output> 20.<result>20</result> | The height that the shadow of the pole lent was 6 meters. So, x = 6.32 * 32. Then, x = 12.96. The height of the chimney is 12.96 * 32 =<gadget id="calculator">12.96*32</gadget><output>414.72</output> 414.72 meters.<result>414.72</result> |
ape210k__00371769 | The original price of a pair of socks was 1.85 yuan. After the price of each pair was reduced by 0.37 yuan, Xiaohong bought 5 pairs. How much did she spend? | 一种袜子原价每双1.85元，在每双降价0.37元后，小红买了5双，花了多少钱？ | <gadget id="calculator">1.85 - 0.37</gadget>
<output>1.48</output>
<gadget id="calculator">1.48 * 5</gadget>
<output>7.4</output>
<result>7.4</result> | 7.4 | 7.4 | x=(1.85-0.37)*5 | calcformer-instruct-flan-xl_step-128k | The price of each pair of socks reduced by 0.37 yuan, so it is now 1.85 - 0.37 =<gadget id="calculator">1.85-0.37</gadget><output>1.48</output> 1.48. Xiaohong bought 5 pairs of shoes, so she spent 1.48 x 5 = $<gadget id="calculator">1.48*5</gadget><output>7.4</output> 7.4.<result>7.4</result> | The price decrease was 0.37 yuan x 5 pairs =<gadget id="calculator">0.37*5</gadget><output>1.85</output> 1.85 yuan. Therefore, Xiaohong spent 1.85 yuan - 1.85 yuan =<gadget id="calculator">1.85-0.37</gadget><output>1.48</output> 1.48 yuan.<result>1.48</result> |
ape210k__00249209 | How many boxes can 50L of milk be sold in small boxes with a volume of (1/2)L? | 50L的牛奶分装在容积为(1/2)L的小盒内出售可以装多少盒． | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">50 / (1/2)</gadget>
<output>100</output>
<result>100</result> | 100 | 100 | x=50/(1/2) | calcformer-instruct-flan-xl_step-128k | If one box has a volume of (1/2)L, then 50L can be sold in 50/(1/2) =<gadget id="calculator">50/(1/2)</gadget><output>100</output> 100 boxes.<result>100</result> | The volume of one box of milk = (1/2)L. The 50L milk can be sold in 50/2 =<gadget id="calculator">50/2</gadget><output>25</output> 25 small boxes.<result>25</result> |
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