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Please show the titles of films and the types of market estimations. | CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Type VARCHAR, Film_ID VARCHAR) | SELECT T1.Title, T2.Type FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID | ### Context: CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Type VARCHAR, Film_ID VARCHAR) ### Question: Please show the titles of films and the types of market estimations. ### Answer: SELECT T1.Title, T2.Type FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID |
Show the distinct director of films with market estimation in the year of 1995. | CREATE TABLE film (Director VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Film_ID VARCHAR, Year VARCHAR) | SELECT DISTINCT T1.Director FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID WHERE T2.Year = 1995 | ### Context: CREATE TABLE film (Director VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Film_ID VARCHAR, Year VARCHAR) ### Question: Show the distinct director of films with market estimation in the year of 1995. ### Answer: SELECT DISTINCT T1.Director FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID WHERE T2.Year = 1995 |
What is the average number of cities of markets with low film market estimate bigger than 10000? | CREATE TABLE market (Number_cities INTEGER, Market_ID VARCHAR); CREATE TABLE film_market_estimation (Market_ID VARCHAR, Low_Estimate INTEGER) | SELECT AVG(T2.Number_cities) FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T1.Low_Estimate > 10000 | ### Context: CREATE TABLE market (Number_cities INTEGER, Market_ID VARCHAR); CREATE TABLE film_market_estimation (Market_ID VARCHAR, Low_Estimate INTEGER) ### Question: What is the average number of cities of markets with low film market estimate bigger than 10000? ### Answer: SELECT AVG(T2.Number_cities) FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T1.Low_Estimate > 10000 |
Please list the countries and years of film market estimations. | CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Country VARCHAR, Market_ID VARCHAR) | SELECT T2.Country, T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID | ### Context: CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Country VARCHAR, Market_ID VARCHAR) ### Question: Please list the countries and years of film market estimations. ### Answer: SELECT T2.Country, T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID |
Please list the years of film market estimations when the market is in country "Japan" in descending order. | CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Market_ID VARCHAR, Country VARCHAR) | SELECT T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T2.Country = "Japan" ORDER BY T1.Year DESC | ### Context: CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Market_ID VARCHAR, Country VARCHAR) ### Question: Please list the years of film market estimations when the market is in country "Japan" in descending order. ### Answer: SELECT T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T2.Country = "Japan" ORDER BY T1.Year DESC |
List the studios of each film and the number of films produced by that studio. | CREATE TABLE film (Studio VARCHAR) | SELECT Studio, COUNT(*) FROM film GROUP BY Studio | ### Context: CREATE TABLE film (Studio VARCHAR) ### Question: List the studios of each film and the number of films produced by that studio. ### Answer: SELECT Studio, COUNT(*) FROM film GROUP BY Studio |
List the name of film studio that have the most number of films. | CREATE TABLE film (Studio VARCHAR) | SELECT Studio FROM film GROUP BY Studio ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE film (Studio VARCHAR) ### Question: List the name of film studio that have the most number of films. ### Answer: SELECT Studio FROM film GROUP BY Studio ORDER BY COUNT(*) DESC LIMIT 1 |
List the names of studios that have at least two films. | CREATE TABLE film (Studio VARCHAR) | SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2 | ### Context: CREATE TABLE film (Studio VARCHAR) ### Question: List the names of studios that have at least two films. ### Answer: SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2 |
List the title of films that do not have any market estimation. | CREATE TABLE film_market_estimation (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR) | SELECT Title FROM film WHERE NOT Film_ID IN (SELECT Film_ID FROM film_market_estimation) | ### Context: CREATE TABLE film_market_estimation (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR) ### Question: List the title of films that do not have any market estimation. ### Answer: SELECT Title FROM film WHERE NOT Film_ID IN (SELECT Film_ID FROM film_market_estimation) |
Show the studios that have produced films with director "Nicholas Meyer" and "Walter Hill". | CREATE TABLE film (Studio VARCHAR, Director VARCHAR) | SELECT Studio FROM film WHERE Director = "Nicholas Meyer" INTERSECT SELECT Studio FROM film WHERE Director = "Walter Hill" | ### Context: CREATE TABLE film (Studio VARCHAR, Director VARCHAR) ### Question: Show the studios that have produced films with director "Nicholas Meyer" and "Walter Hill". ### Answer: SELECT Studio FROM film WHERE Director = "Nicholas Meyer" INTERSECT SELECT Studio FROM film WHERE Director = "Walter Hill" |
Find the titles and studios of the films that are produced by some film studios that contained the word "Universal". | CREATE TABLE film (title VARCHAR, Studio VARCHAR) | SELECT title, Studio FROM film WHERE Studio LIKE "%Universal%" | ### Context: CREATE TABLE film (title VARCHAR, Studio VARCHAR) ### Question: Find the titles and studios of the films that are produced by some film studios that contained the word "Universal". ### Answer: SELECT title, Studio FROM film WHERE Studio LIKE "%Universal%" |
Show the studios that have not produced films with director "Walter Hill". | CREATE TABLE film (Studio VARCHAR, Director VARCHAR) | SELECT Studio FROM film EXCEPT SELECT Studio FROM film WHERE Director = "Walter Hill" | ### Context: CREATE TABLE film (Studio VARCHAR, Director VARCHAR) ### Question: Show the studios that have not produced films with director "Walter Hill". ### Answer: SELECT Studio FROM film EXCEPT SELECT Studio FROM film WHERE Director = "Walter Hill" |
List the studios which average gross is above 4500000. | CREATE TABLE film (Studio VARCHAR, Gross_in_dollar INTEGER) | SELECT Studio FROM film GROUP BY Studio HAVING AVG(Gross_in_dollar) >= 4500000 | ### Context: CREATE TABLE film (Studio VARCHAR, Gross_in_dollar INTEGER) ### Question: List the studios which average gross is above 4500000. ### Answer: SELECT Studio FROM film GROUP BY Studio HAVING AVG(Gross_in_dollar) >= 4500000 |
What is the title of the film that has the highest high market estimation. | CREATE TABLE film_market_estimation (Film_ID VARCHAR); CREATE TABLE film (Film_ID VARCHAR) | SELECT t1.title FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID ORDER BY high_estimate DESC LIMIT 1 | ### Context: CREATE TABLE film_market_estimation (Film_ID VARCHAR); CREATE TABLE film (Film_ID VARCHAR) ### Question: What is the title of the film that has the highest high market estimation. ### Answer: SELECT t1.title FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID ORDER BY high_estimate DESC LIMIT 1 |
What are the titles and directors of the films were never presented in China? | CREATE TABLE film (title VARCHAR, director VARCHAR, film_id VARCHAR, country VARCHAR); CREATE TABLE market (Market_ID VARCHAR); CREATE TABLE film_market_estimation (market_id VARCHAR) | SELECT title, director FROM film WHERE NOT film_id IN (SELECT film_id FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.market_id = T2.Market_ID WHERE country = 'China') | ### Context: CREATE TABLE film (title VARCHAR, director VARCHAR, film_id VARCHAR, country VARCHAR); CREATE TABLE market (Market_ID VARCHAR); CREATE TABLE film_market_estimation (market_id VARCHAR) ### Question: What are the titles and directors of the films were never presented in China? ### Answer: SELECT title, director FROM film WHERE NOT film_id IN (SELECT film_id FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.market_id = T2.Market_ID WHERE country = 'China') |
How many calendar items do we have? | CREATE TABLE Ref_calendar (Id VARCHAR) | SELECT COUNT(*) FROM Ref_calendar | ### Context: CREATE TABLE Ref_calendar (Id VARCHAR) ### Question: How many calendar items do we have? ### Answer: SELECT COUNT(*) FROM Ref_calendar |
Show all calendar dates and day Numbers. | CREATE TABLE Ref_calendar (calendar_date VARCHAR, day_Number VARCHAR) | SELECT calendar_date, day_Number FROM Ref_calendar | ### Context: CREATE TABLE Ref_calendar (calendar_date VARCHAR, day_Number VARCHAR) ### Question: Show all calendar dates and day Numbers. ### Answer: SELECT calendar_date, day_Number FROM Ref_calendar |
Show the number of document types. | CREATE TABLE Ref_document_types (Id VARCHAR) | SELECT COUNT(*) FROM Ref_document_types | ### Context: CREATE TABLE Ref_document_types (Id VARCHAR) ### Question: Show the number of document types. ### Answer: SELECT COUNT(*) FROM Ref_document_types |
List all document type codes and document type names. | CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR) | SELECT document_type_code, document_type_name FROM Ref_document_types | ### Context: CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR) ### Question: List all document type codes and document type names. ### Answer: SELECT document_type_code, document_type_name FROM Ref_document_types |
What is the name and description for document type code RV? | CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_description VARCHAR, document_type_code VARCHAR) | SELECT document_type_name, document_type_description FROM Ref_document_types WHERE document_type_code = "RV" | ### Context: CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_description VARCHAR, document_type_code VARCHAR) ### Question: What is the name and description for document type code RV? ### Answer: SELECT document_type_name, document_type_description FROM Ref_document_types WHERE document_type_code = "RV" |
What is the document type code for document type "Paper"? | CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR) | SELECT document_type_code FROM Ref_document_types WHERE document_type_name = "Paper" | ### Context: CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR) ### Question: What is the document type code for document type "Paper"? ### Answer: SELECT document_type_code FROM Ref_document_types WHERE document_type_name = "Paper" |
Show the number of documents with document type code CV or BK. | CREATE TABLE All_documents (document_type_code VARCHAR) | SELECT COUNT(*) FROM All_documents WHERE document_type_code = "CV" OR document_type_code = "BK" | ### Context: CREATE TABLE All_documents (document_type_code VARCHAR) ### Question: Show the number of documents with document type code CV or BK. ### Answer: SELECT COUNT(*) FROM All_documents WHERE document_type_code = "CV" OR document_type_code = "BK" |
What is the date when the document "Marry CV" was stored? | CREATE TABLE All_documents (date_stored VARCHAR, Document_name VARCHAR) | SELECT date_stored FROM All_documents WHERE Document_name = "Marry CV" | ### Context: CREATE TABLE All_documents (date_stored VARCHAR, Document_name VARCHAR) ### Question: What is the date when the document "Marry CV" was stored? ### Answer: SELECT date_stored FROM All_documents WHERE Document_name = "Marry CV" |
What is the day Number and date of all the documents? | CREATE TABLE All_documents (Date_Stored VARCHAR, date_stored VARCHAR); CREATE TABLE Ref_calendar (day_Number VARCHAR, calendar_date VARCHAR) | SELECT T2.day_Number, T1.Date_Stored FROM All_documents AS T1 JOIN Ref_calendar AS T2 ON T1.date_stored = T2.calendar_date | ### Context: CREATE TABLE All_documents (Date_Stored VARCHAR, date_stored VARCHAR); CREATE TABLE Ref_calendar (day_Number VARCHAR, calendar_date VARCHAR) ### Question: What is the day Number and date of all the documents? ### Answer: SELECT T2.day_Number, T1.Date_Stored FROM All_documents AS T1 JOIN Ref_calendar AS T2 ON T1.date_stored = T2.calendar_date |
What is the document type name for the document with name "How to read a book"? | CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_code VARCHAR); CREATE TABLE All_documents (document_type_code VARCHAR, document_name VARCHAR) | SELECT T2.document_type_name FROM All_documents AS T1 JOIN Ref_document_types AS T2 ON T1.document_type_code = T2.document_type_code WHERE T1.document_name = "How to read a book" | ### Context: CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_code VARCHAR); CREATE TABLE All_documents (document_type_code VARCHAR, document_name VARCHAR) ### Question: What is the document type name for the document with name "How to read a book"? ### Answer: SELECT T2.document_type_name FROM All_documents AS T1 JOIN Ref_document_types AS T2 ON T1.document_type_code = T2.document_type_code WHERE T1.document_name = "How to read a book" |
Show the number of locations. | CREATE TABLE Ref_locations (Id VARCHAR) | SELECT COUNT(*) FROM Ref_locations | ### Context: CREATE TABLE Ref_locations (Id VARCHAR) ### Question: Show the number of locations. ### Answer: SELECT COUNT(*) FROM Ref_locations |
List all location codes and location names. | CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR) | SELECT location_code, location_name FROM Ref_locations | ### Context: CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR) ### Question: List all location codes and location names. ### Answer: SELECT location_code, location_name FROM Ref_locations |
What are the name and description for location code x? | CREATE TABLE Ref_locations (location_name VARCHAR, location_description VARCHAR, location_code VARCHAR) | SELECT location_name, location_description FROM Ref_locations WHERE location_code = "x" | ### Context: CREATE TABLE Ref_locations (location_name VARCHAR, location_description VARCHAR, location_code VARCHAR) ### Question: What are the name and description for location code x? ### Answer: SELECT location_name, location_description FROM Ref_locations WHERE location_code = "x" |
What is the location code for the country "Canada"? | CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR) | SELECT location_code FROM Ref_locations WHERE location_name = "Canada" | ### Context: CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR) ### Question: What is the location code for the country "Canada"? ### Answer: SELECT location_code FROM Ref_locations WHERE location_name = "Canada" |
How many roles are there? | CREATE TABLE ROLES (Id VARCHAR) | SELECT COUNT(*) FROM ROLES | ### Context: CREATE TABLE ROLES (Id VARCHAR) ### Question: How many roles are there? ### Answer: SELECT COUNT(*) FROM ROLES |
List all role codes, role names, and role descriptions. | CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR, role_description VARCHAR) | SELECT role_code, role_name, role_description FROM ROLES | ### Context: CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR, role_description VARCHAR) ### Question: List all role codes, role names, and role descriptions. ### Answer: SELECT role_code, role_name, role_description FROM ROLES |
What are the name and description for role code "MG"? | CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR) | SELECT role_name, role_description FROM ROLES WHERE role_code = "MG" | ### Context: CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR) ### Question: What are the name and description for role code "MG"? ### Answer: SELECT role_name, role_description FROM ROLES WHERE role_code = "MG" |
Show the description for role name "Proof Reader". | CREATE TABLE ROLES (role_description VARCHAR, role_name VARCHAR) | SELECT role_description FROM ROLES WHERE role_name = "Proof Reader" | ### Context: CREATE TABLE ROLES (role_description VARCHAR, role_name VARCHAR) ### Question: Show the description for role name "Proof Reader". ### Answer: SELECT role_description FROM ROLES WHERE role_name = "Proof Reader" |
Show the name, role code, and date of birth for the employee with name 'Armani'. | CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR, date_of_birth VARCHAR, employee_Name VARCHAR) | SELECT employee_name, role_code, date_of_birth FROM Employees WHERE employee_Name = 'Armani' | ### Context: CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR, date_of_birth VARCHAR, employee_Name VARCHAR) ### Question: Show the name, role code, and date of birth for the employee with name 'Armani'. ### Answer: SELECT employee_name, role_code, date_of_birth FROM Employees WHERE employee_Name = 'Armani' |
What is the id for the employee called Ebba? | CREATE TABLE Employees (employee_ID VARCHAR, employee_name VARCHAR) | SELECT employee_ID FROM Employees WHERE employee_name = "Ebba" | ### Context: CREATE TABLE Employees (employee_ID VARCHAR, employee_name VARCHAR) ### Question: What is the id for the employee called Ebba? ### Answer: SELECT employee_ID FROM Employees WHERE employee_name = "Ebba" |
Show the names of all the employees with role "HR". | CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR) | SELECT employee_name FROM Employees WHERE role_code = "HR" | ### Context: CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR) ### Question: Show the names of all the employees with role "HR". ### Answer: SELECT employee_name FROM Employees WHERE role_code = "HR" |
Show all role codes and the number of employees in each role. | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code, COUNT(*) FROM Employees GROUP BY role_code | ### Context: CREATE TABLE Employees (role_code VARCHAR) ### Question: Show all role codes and the number of employees in each role. ### Answer: SELECT role_code, COUNT(*) FROM Employees GROUP BY role_code |
What is the role code with the largest number of employees? | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Employees (role_code VARCHAR) ### Question: What is the role code with the largest number of employees? ### Answer: SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1 |
Show all role codes with at least 3 employees. | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code FROM Employees GROUP BY role_code HAVING COUNT(*) >= 3 | ### Context: CREATE TABLE Employees (role_code VARCHAR) ### Question: Show all role codes with at least 3 employees. ### Answer: SELECT role_code FROM Employees GROUP BY role_code HAVING COUNT(*) >= 3 |
Show the role code with the least employees. | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) LIMIT 1 | ### Context: CREATE TABLE Employees (role_code VARCHAR) ### Question: Show the role code with the least employees. ### Answer: SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) LIMIT 1 |
What is the role name and role description for employee called Ebba? | CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR); CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR) | SELECT T2.role_name, T2.role_description FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T1.employee_name = "Ebba" | ### Context: CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR); CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR) ### Question: What is the role name and role description for employee called Ebba? ### Answer: SELECT T2.role_name, T2.role_description FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T1.employee_name = "Ebba" |
Show the names of employees with role name Editor. | CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR) | SELECT T1.employee_name FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Editor" | ### Context: CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR) ### Question: Show the names of employees with role name Editor. ### Answer: SELECT T1.employee_name FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Editor" |
Show the employee ids for all employees with role name "Human Resource" or "Manager". | CREATE TABLE Employees (employee_id VARCHAR, role_code VARCHAR); CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR) | SELECT T1.employee_id FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Human Resource" OR T2.role_name = "Manager" | ### Context: CREATE TABLE Employees (employee_id VARCHAR, role_code VARCHAR); CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR) ### Question: Show the employee ids for all employees with role name "Human Resource" or "Manager". ### Answer: SELECT T1.employee_id FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Human Resource" OR T2.role_name = "Manager" |
What are the different location codes for documents? | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT DISTINCT location_code FROM Document_locations | ### Context: CREATE TABLE Document_locations (location_code VARCHAR) ### Question: What are the different location codes for documents? ### Answer: SELECT DISTINCT location_code FROM Document_locations |
Show the location name for document "Robin CV". | CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR); CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (document_id VARCHAR, location_code VARCHAR) | SELECT T3.location_name FROM All_documents AS T1 JOIN Document_locations AS T2 ON T1.document_id = T2.document_id JOIN Ref_locations AS T3 ON T2.location_code = T3.location_code WHERE T1.document_name = "Robin CV" | ### Context: CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR); CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (document_id VARCHAR, location_code VARCHAR) ### Question: Show the location name for document "Robin CV". ### Answer: SELECT T3.location_name FROM All_documents AS T1 JOIN Document_locations AS T2 ON T1.document_id = T2.document_id JOIN Ref_locations AS T3 ON T2.location_code = T3.location_code WHERE T1.document_name = "Robin CV" |
Show the location code, the starting date and ending data in that location for all the documents. | CREATE TABLE Document_locations (location_code VARCHAR, date_in_location_from VARCHAR, date_in_locaton_to VARCHAR) | SELECT location_code, date_in_location_from, date_in_locaton_to FROM Document_locations | ### Context: CREATE TABLE Document_locations (location_code VARCHAR, date_in_location_from VARCHAR, date_in_locaton_to VARCHAR) ### Question: Show the location code, the starting date and ending data in that location for all the documents. ### Answer: SELECT location_code, date_in_location_from, date_in_locaton_to FROM Document_locations |
What is "the date in location from" and "the date in location to" for the document with name "Robin CV"? | CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (date_in_location_from VARCHAR, date_in_locaton_to VARCHAR, document_id VARCHAR) | SELECT T1.date_in_location_from, T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV" | ### Context: CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (date_in_location_from VARCHAR, date_in_locaton_to VARCHAR, document_id VARCHAR) ### Question: What is "the date in location from" and "the date in location to" for the document with name "Robin CV"? ### Answer: SELECT T1.date_in_location_from, T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV" |
Show the location codes and the number of documents in each location. | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT location_code, COUNT(*) FROM Document_locations GROUP BY location_code | ### Context: CREATE TABLE Document_locations (location_code VARCHAR) ### Question: Show the location codes and the number of documents in each location. ### Answer: SELECT location_code, COUNT(*) FROM Document_locations GROUP BY location_code |
What is the location code with the most documents? | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT location_code FROM Document_locations GROUP BY location_code ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Document_locations (location_code VARCHAR) ### Question: What is the location code with the most documents? ### Answer: SELECT location_code FROM Document_locations GROUP BY location_code ORDER BY COUNT(*) DESC LIMIT 1 |
Show the location codes with at least 3 documents. | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT location_code FROM Document_locations GROUP BY location_code HAVING COUNT(*) >= 3 | ### Context: CREATE TABLE Document_locations (location_code VARCHAR) ### Question: Show the location codes with at least 3 documents. ### Answer: SELECT location_code FROM Document_locations GROUP BY location_code HAVING COUNT(*) >= 3 |
Show the location name and code with the least documents. | CREATE TABLE Document_locations (location_code VARCHAR); CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR) | SELECT T2.location_name, T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code = T2.location_code GROUP BY T1.location_code ORDER BY COUNT(*) LIMIT 1 | ### Context: CREATE TABLE Document_locations (location_code VARCHAR); CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR) ### Question: Show the location name and code with the least documents. ### Answer: SELECT T2.location_name, T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code = T2.location_code GROUP BY T1.location_code ORDER BY COUNT(*) LIMIT 1 |
What are the names of the employees who authorised the destruction and the employees who destroyed the corresponding documents? | CREATE TABLE Employees (employee_name VARCHAR, employee_id VARCHAR); CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR, Destroyed_by_Employee_ID VARCHAR) | SELECT T2.employee_name, T3.employee_name FROM Documents_to_be_destroyed AS T1 JOIN Employees AS T2 ON T1.Destruction_Authorised_by_Employee_ID = T2.employee_id JOIN Employees AS T3 ON T1.Destroyed_by_Employee_ID = T3.employee_id | ### Context: CREATE TABLE Employees (employee_name VARCHAR, employee_id VARCHAR); CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR, Destroyed_by_Employee_ID VARCHAR) ### Question: What are the names of the employees who authorised the destruction and the employees who destroyed the corresponding documents? ### Answer: SELECT T2.employee_name, T3.employee_name FROM Documents_to_be_destroyed AS T1 JOIN Employees AS T2 ON T1.Destruction_Authorised_by_Employee_ID = T2.employee_id JOIN Employees AS T3 ON T1.Destroyed_by_Employee_ID = T3.employee_id |
Show the id of each employee and the number of document destruction authorised by that employee. | CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT Destruction_Authorised_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destruction_Authorised_by_Employee_ID | ### Context: CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR) ### Question: Show the id of each employee and the number of document destruction authorised by that employee. ### Answer: SELECT Destruction_Authorised_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destruction_Authorised_by_Employee_ID |
Show the employee ids and the number of documents destroyed by each employee. | CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR) | SELECT Destroyed_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destroyed_by_Employee_ID | ### Context: CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR) ### Question: Show the employee ids and the number of documents destroyed by each employee. ### Answer: SELECT Destroyed_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destroyed_by_Employee_ID |
Show the ids of the employees who don't authorize destruction for any document. | CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR); CREATE TABLE Employees (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT employee_id FROM Employees EXCEPT SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed | ### Context: CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR); CREATE TABLE Employees (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR) ### Question: Show the ids of the employees who don't authorize destruction for any document. ### Answer: SELECT employee_id FROM Employees EXCEPT SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed |
Show the ids of all employees who have authorized destruction. | CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT DISTINCT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed | ### Context: CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR) ### Question: Show the ids of all employees who have authorized destruction. ### Answer: SELECT DISTINCT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed |
Show the ids of all employees who have destroyed a document. | CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR) | SELECT DISTINCT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed | ### Context: CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR) ### Question: Show the ids of all employees who have destroyed a document. ### Answer: SELECT DISTINCT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed |
Show the ids of all employees who don't destroy any document. | CREATE TABLE Employees (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR); CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR) | SELECT employee_id FROM Employees EXCEPT SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed | ### Context: CREATE TABLE Employees (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR); CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR) ### Question: Show the ids of all employees who don't destroy any document. ### Answer: SELECT employee_id FROM Employees EXCEPT SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed |
Show the ids of all employees who have either destroyed a document or made an authorization to do this. | CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed UNION SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed | ### Context: CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR) ### Question: Show the ids of all employees who have either destroyed a document or made an authorization to do this. ### Answer: SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed UNION SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed |
What are the names of all clubs? | CREATE TABLE club (clubname VARCHAR) | SELECT clubname FROM club | ### Context: CREATE TABLE club (clubname VARCHAR) ### Question: What are the names of all clubs? ### Answer: SELECT clubname FROM club |
How many students are there? | CREATE TABLE student (Id VARCHAR) | SELECT COUNT(*) FROM student | ### Context: CREATE TABLE student (Id VARCHAR) ### Question: How many students are there? ### Answer: SELECT COUNT(*) FROM student |
What are the first names of all the students? | CREATE TABLE student (fname VARCHAR) | SELECT DISTINCT fname FROM student | ### Context: CREATE TABLE student (fname VARCHAR) ### Question: What are the first names of all the students? ### Answer: SELECT DISTINCT fname FROM student |
Find the last names of the members of the club "Bootup Baltimore". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: Find the last names of the members of the club "Bootup Baltimore". ### Answer: SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" |
Who are the members of the club named "Hopkins Student Enterprises"? Show the last name. | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: Who are the members of the club named "Hopkins Student Enterprises"? Show the last name. ### Answer: SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" |
How many members does the club "Tennis Club" has? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR) ### Question: How many members does the club "Tennis Club" has? ### Answer: SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" |
Find the number of members of club "Pen and Paper Gaming". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Pen and Paper Gaming" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR) ### Question: Find the number of members of club "Pen and Paper Gaming". ### Answer: SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Pen and Paper Gaming" |
How many clubs does "Linda Smith" belong to? | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Linda" AND t3.lname = "Smith" | ### Context: CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR) ### Question: How many clubs does "Linda Smith" belong to? ### Answer: SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Linda" AND t3.lname = "Smith" |
Find the number of clubs where "Tracy Kim" is a member. | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Tracy" AND t3.lname = "Kim" | ### Context: CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR) ### Question: Find the number of clubs where "Tracy Kim" is a member. ### Answer: SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Tracy" AND t3.lname = "Kim" |
Find all the female members of club "Bootup Baltimore". Show the first name and last name. | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.sex = "F" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: Find all the female members of club "Bootup Baltimore". Show the first name and last name. ### Answer: SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.sex = "F" |
Find all the male members of club "Hopkins Student Enterprises". Show the first name and last name. | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t3.sex = "M" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: Find all the male members of club "Hopkins Student Enterprises". Show the first name and last name. ### Answer: SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t3.sex = "M" |
Find all members of "Bootup Baltimore" whose major is "600". Show the first name and last name. | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, major VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.major = "600" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, major VARCHAR) ### Question: Find all members of "Bootup Baltimore" whose major is "600". Show the first name and last name. ### Answer: SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.major = "600" |
Which club has the most members majoring in "600"? | CREATE TABLE student (stuid VARCHAR, major VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = "600" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE student (stuid VARCHAR, major VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) ### Question: Which club has the most members majoring in "600"? ### Answer: SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = "600" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 |
Find the name of the club that has the most female students. | CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) ### Question: Find the name of the club that has the most female students. ### Answer: SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 |
What is the description of the club named "Tennis Club"? | CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR) | SELECT clubdesc FROM club WHERE clubname = "Tennis Club" | ### Context: CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR) ### Question: What is the description of the club named "Tennis Club"? ### Answer: SELECT clubdesc FROM club WHERE clubname = "Tennis Club" |
Find the description of the club "Pen and Paper Gaming". | CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR) | SELECT clubdesc FROM club WHERE clubname = "Pen and Paper Gaming" | ### Context: CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR) ### Question: Find the description of the club "Pen and Paper Gaming". ### Answer: SELECT clubdesc FROM club WHERE clubname = "Pen and Paper Gaming" |
What is the location of the club named "Tennis Club"? | CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) | SELECT clublocation FROM club WHERE clubname = "Tennis Club" | ### Context: CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) ### Question: What is the location of the club named "Tennis Club"? ### Answer: SELECT clublocation FROM club WHERE clubname = "Tennis Club" |
Find the location of the club "Pen and Paper Gaming". | CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) | SELECT clublocation FROM club WHERE clubname = "Pen and Paper Gaming" | ### Context: CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) ### Question: Find the location of the club "Pen and Paper Gaming". ### Answer: SELECT clublocation FROM club WHERE clubname = "Pen and Paper Gaming" |
Where is the club "Hopkins Student Enterprises" located? | CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) | SELECT clublocation FROM club WHERE clubname = "Hopkins Student Enterprises" | ### Context: CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) ### Question: Where is the club "Hopkins Student Enterprises" located? ### Answer: SELECT clublocation FROM club WHERE clubname = "Hopkins Student Enterprises" |
Find the name of all the clubs at "AKW". | CREATE TABLE club (clubname VARCHAR, clublocation VARCHAR) | SELECT clubname FROM club WHERE clublocation = "AKW" | ### Context: CREATE TABLE club (clubname VARCHAR, clublocation VARCHAR) ### Question: Find the name of all the clubs at "AKW". ### Answer: SELECT clubname FROM club WHERE clublocation = "AKW" |
How many clubs are located at "HHH"? | CREATE TABLE club (clublocation VARCHAR) | SELECT COUNT(*) FROM club WHERE clublocation = "HHH" | ### Context: CREATE TABLE club (clublocation VARCHAR) ### Question: How many clubs are located at "HHH"? ### Answer: SELECT COUNT(*) FROM club WHERE clublocation = "HHH" |
What are the first and last name of the president of the club "Bootup Baltimore"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t2.position = "President" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR) ### Question: What are the first and last name of the president of the club "Bootup Baltimore"? ### Answer: SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t2.position = "President" |
Who is the "CTO" of club "Hopkins Student Enterprises"? Show the first name and last name. | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t2.position = "CTO" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR) ### Question: Who is the "CTO" of club "Hopkins Student Enterprises"? Show the first name and last name. ### Answer: SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t2.position = "CTO" |
How many different roles are there in the club "Bootup Baltimore"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (position VARCHAR, clubid VARCHAR) | SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = "Bootup Baltimore" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (position VARCHAR, clubid VARCHAR) ### Question: How many different roles are there in the club "Bootup Baltimore"? ### Answer: SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = "Bootup Baltimore" |
How many members of "Bootup Baltimore" are older than 18? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18 | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: How many members of "Bootup Baltimore" are older than 18? ### Answer: SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18 |
How many members of club "Bootup Baltimore" are younger than 18? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18 | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: How many members of club "Bootup Baltimore" are younger than 18? ### Answer: SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18 |
Find the names of all the clubs that have at least a member from the city with city code "BAL". | CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "BAL" | ### Context: CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR) ### Question: Find the names of all the clubs that have at least a member from the city with city code "BAL". ### Answer: SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "BAL" |
Find the names of the clubs that have at least a member from the city with city code "HOU". | CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "HOU" | ### Context: CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR) ### Question: Find the names of the clubs that have at least a member from the city with city code "HOU". ### Answer: SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "HOU" |
How many clubs does the student named "Eric Tai" belong to? | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Eric" AND t3.lname = "Tai" | ### Context: CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) ### Question: How many clubs does the student named "Eric Tai" belong to? ### Answer: SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Eric" AND t3.lname = "Tai" |
List the clubs having "Davis Steven" as a member. | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Davis" AND t3.lname = "Steven" | ### Context: CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) ### Question: List the clubs having "Davis Steven" as a member. ### Answer: SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Davis" AND t3.lname = "Steven" |
List the clubs that have at least a member with advisor "1121". | CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, advisor VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121 | ### Context: CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, advisor VARCHAR) ### Question: List the clubs that have at least a member with advisor "1121". ### Answer: SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121 |
What is the average age of the members of the club "Bootup Baltimore"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: What is the average age of the members of the club "Bootup Baltimore"? ### Answer: SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" |
Find the average age of members of the club "Hopkins Student Enterprises". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: Find the average age of members of the club "Hopkins Student Enterprises". ### Answer: SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" |
Retrieve the average age of members of the club "Tennis Club". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" | ### Context: CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) ### Question: Retrieve the average age of members of the club "Tennis Club". ### Answer: SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" |
What are the distinct grant amount for the grants where the documents were sent before '1986-08-26 20:49:27' and grant were ended after '1989-03-16 18:27:16'? | CREATE TABLE grants (grant_amount VARCHAR, grant_end_date INTEGER); CREATE TABLE Grants (grant_amount VARCHAR, grant_id VARCHAR); CREATE TABLE Documents (grant_id VARCHAR, sent_date INTEGER) | SELECT T1.grant_amount FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id WHERE T2.sent_date < '1986-08-26 20:49:27' INTERSECT SELECT grant_amount FROM grants WHERE grant_end_date > '1989-03-16 18:27:16' | ### Context: CREATE TABLE grants (grant_amount VARCHAR, grant_end_date INTEGER); CREATE TABLE Grants (grant_amount VARCHAR, grant_id VARCHAR); CREATE TABLE Documents (grant_id VARCHAR, sent_date INTEGER) ### Question: What are the distinct grant amount for the grants where the documents were sent before '1986-08-26 20:49:27' and grant were ended after '1989-03-16 18:27:16'? ### Answer: SELECT T1.grant_amount FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id WHERE T2.sent_date < '1986-08-26 20:49:27' INTERSECT SELECT grant_amount FROM grants WHERE grant_end_date > '1989-03-16 18:27:16' |
List the project details of the project both producing patent and paper as outcomes. | CREATE TABLE Project_outcomes (project_id VARCHAR, outcome_code VARCHAR); CREATE TABLE Projects (project_details VARCHAR, project_id VARCHAR) | SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent' | ### Context: CREATE TABLE Project_outcomes (project_id VARCHAR, outcome_code VARCHAR); CREATE TABLE Projects (project_details VARCHAR, project_id VARCHAR) ### Question: List the project details of the project both producing patent and paper as outcomes. ### Answer: SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent' |
What is the total grant amount of the organisations described as research? | CREATE TABLE organisation_Types (organisation_type VARCHAR, organisation_type_description VARCHAR); CREATE TABLE Grants (organisation_id VARCHAR); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_type VARCHAR) | SELECT SUM(grant_amount) FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id JOIN organisation_Types AS T3 ON T2.organisation_type = T3.organisation_type WHERE T3.organisation_type_description = 'Research' | ### Context: CREATE TABLE organisation_Types (organisation_type VARCHAR, organisation_type_description VARCHAR); CREATE TABLE Grants (organisation_id VARCHAR); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_type VARCHAR) ### Question: What is the total grant amount of the organisations described as research? ### Answer: SELECT SUM(grant_amount) FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id JOIN organisation_Types AS T3 ON T2.organisation_type = T3.organisation_type WHERE T3.organisation_type_description = 'Research' |
List from which date and to which date these staff work: project staff of the project which hires the most staffs | CREATE TABLE Project_Staff (date_from VARCHAR, date_to VARCHAR, project_id VARCHAR, role_code VARCHAR) | SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader' | ### Context: CREATE TABLE Project_Staff (date_from VARCHAR, date_to VARCHAR, project_id VARCHAR, role_code VARCHAR) ### Question: List from which date and to which date these staff work: project staff of the project which hires the most staffs ### Answer: SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader' |
Find the organisation ids and details of the organisations which are involved in | CREATE TABLE Grants (organisation_id VARCHAR, grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_details VARCHAR) | SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000 | ### Context: CREATE TABLE Grants (organisation_id VARCHAR, grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_details VARCHAR) ### Question: Find the organisation ids and details of the organisations which are involved in ### Answer: SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000 |
What is the organisation type and id of the organisation which has the most number of research staff? | CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR) | SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR) ### Question: What is the organisation type and id of the organisation which has the most number of research staff? ### Answer: SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1 |
Which organisation type hires most research staff? | CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR) | SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR) ### Question: Which organisation type hires most research staff? ### Answer: SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1 |
Subsets and Splits