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220eb2a9b1f08f2603e319259fae26ec | what is gastrula? | askiitians.com | 2021.43 | [
{
"text": "gastrula is embryo at the stage following the blastula, when it is a hollow cup-shaped structure having three layers of cells.it results by the process of gastrulation.which is a phase early in the embryonic development of most animals, during which the single-layered blastula is reorganized into a trilaminar (\"three-layered\") structure known as the gastrula. these three germ layers are the ectoderm, mesoderm, and endoderm repectively.",
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"text": "gastrulation is a phase early in the embryonic development of most animals, during which the single-layered blastula is reorganized into a trilaminar (\"three-layered\") structure known as the gastrula. these three germ layers are known as the ectoderm, mesoderm, and endoderm. gastrulation takes place after cleavage and the formation of the blastula and primitive streak. gastrulation is followed by organogenesis, when individual organs develop within the newly formed germ layers.[3] each layer gives rise to specific tissues and organs in the developing embryo. the ectoderm gives rise to epidermis, and to the neural crest and other tissues that will later form the nervous system. the mesoderm is found between the ectoderm and the endoderm and gives rise to somites, which form muscle; the cartilage of the ribs and vertebrae; the dermis, the notochord, blood and blood vessels, bone, and connective tissue. the endoderm gives rise to the epithelium of the digestive system and respiratory system, and organs associated with the digestive system, such as the liver and pancreas.",
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802ac2c11858a5c7f7f1833201fddf13 | my student is pursuing his 12th exam. can you please tell us about the iit jee forms and registration? | askiitians.com | 2021.21 | [
{
"text": "hi mr.malik, the iit jee examination 2012 forms were made available online from 31st october, 2011 and registrations were active till 10th december, 2011 while the offline forms were made available from 11th november, 2011 and registrations were active till 5th of december 2011. i understand that this is the time when your child must be rushing through the last minute preparations. as an iitians i would like to suggest him/her to try the online test series of askiitians. these are research materials compiled by ex-iitians only. for, iit jee 2012 forms and registration . for, askiitians online test series . thanks, sunil kumar, iit-d",
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1f082e70f63a6369f9310d79b2295b08 | if hot air rises why is it cooler at the top of mountain than near sea level? | askiitians.com | 2021.43 | [
{
"text": "the drop in temperature at the top of mountains is because of the change in atmospheric pressure . we all know the relationship between pressure and temperature. both pressure and temperature vary proportionally. this is what thermodynamics says. but i hate equations and formulas. let's have a practical explanation and good understanding of this. there are two factors why there is a drop in temperature at the top of mountains. 1. drop in pressure 2. the amount of water vapour in the air. 1) drop in pressure the cause of the atmospheric pressure will let us know the reason for this fall in pressure with an increase in altitude. the word pressure is the extension of the word press. the surface of our earth is pressed up by the air present above the surface because we know that air has mass and so it is pulled down to the surface by gravity. the weight of the air acts all over the surface and exerts a pressure ( a force). this pressure is atmospheric pressure. gravity plays an important role in this. gravity is maximum at sea level and it decreases when we move up. above a mountain, the gravity decreases so the atmospheric pressure decreases. the drop in pressure decreases temperature. this is because when the pressure increases, more number of particles or molecules are contained in the space. every particle possesses some heat. when the number is more, the heat possessed by all the particles together is more. also, the collisions between these molecules are more which produces heat. when pressure decreases, the molecules spread out and so the heat is not concentrated so the temperature goes down. 2) the amount of water vapour in air water vapour constitutes 36-70% of greenhouse gases. water vapours absorb heat from the sun and make the surrounding warm. this is at ground level. at higher altitudes, these water vapours condense due to the decrease in pressure and form mist which are suspended water particles. the water vapour present at top of the mountain is less so there is less absorption of heat from the sun which prevents the rise of temperature.",
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3f1e1e35adad4bc01a2656ddd6fe5252 | sodium ethoxide has reacted with ethanoyl chloride. the compound that is produced in the above reaction is?? | askiitians.com | 2021.31 | [
{
"text": "dear student please find the link attached https://www.askiitians.com/forums/physical-chemistry/sodium-ethoxide-has-reacted-with-ethanoyl-chloride\\_84362.htm regards",
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"text": "the correct answer is number 4. diethyl ether is obtained by the reaction of ethyl chloride (alkyl halide) and sodiumethoxide. this reaction is also known as williamson synthesis",
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9b1b571f315e91743954fdc9b2e2e2f6 | sir/mam my epected scores jee mains : 120
cbse : 92%
category obc 1. would i be able to qualify for advance. 2. can i get any good eng. college ? 3. so other institutes also consider advance scores... (other than iits ) please answer... | askiitians.com | 2021.31 | [
{
"text": "you will most probably qualify for jee advance. but jee mains score are not upto the mark to get nits.you can opt for private engineering colleges. no,advance score is considered only by iits. thanks and regards. saurabh singh askiitians faculty b.tech. iit kanpur",
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072dd39b997816b6f28b89fd42a39e2e | what is the functions of heart explain theirs functions and mechanism? | askiitians.com | 2021.25 | [
{
"text": "dear student functions of the heart: (i) it helps in the circulation of oxygen rich blood throughout the body by the pumping. (ii) it receives oxygenated blood from the lungs. (iii) it also pumps back the blood carrying carbon dioxide to the lungs. (iv) it shows rhythmic contraction and relaxation for movement of blood.",
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"text": "heart is the organ in our body which belongs to circulatory system. 1) it pumps the blood (not purifies). 2) the deoxygenated blood from the body reaches the heart through the veins in the left auricle. 3) the blood then passes to left ventricle through contraction and relaxation. 4) the blood is then transferred into lungs through the pulmonary artery. 5) the lungs purifies the blood by making it oxygenated. 6) through pulmonary veins the blood again enters heart in right auricle. 7) the blood is then passed into right ventricle. 8) then finally through the aorta (largest artery) oxygenated blood is pumped into the body. 9) this is the whole mechanism and this mechanism is known as double circulation of blood.",
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5bff2ae109e65e10178e45610d2fd29c | my rank in jee adv is 1822(sc cat), will i get petroleum engineering in rajiv gandhi institute of petroleum technology? | askiitians.com | 2021.21 | [
{
"text": "yes you may get.",
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4a7ef72f1034e1b8b79afb260c4410e9 | sir, my cbse percent is 93.4, mains marks are 188, bitsat score is 298 and expected advance score is 175. what can i expect? | askiitians.com | 2021.25 | [
{
"text": "hi well with jee advanced you can expect a rank like 6300. with jee mains you can expect rank between 5000-10000. with bits you can expect mechanical or chemical . thanks & regards, arun kumar, btech,iit delhi, askiitians faculty",
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a0b4c7f62120022a9dee2f48f9f31b3a | i am getting 198 marks in aieee 2010 (general category) what rank and college i can expect. | askiitians.com | 2021.21 | [
{
"text": "dear tapan, as your score is of 198 marks in aieee 2010. so with these marks your estimate rank would be somewhere between 10000 to 20000. so with this rank definately nit's are not possible but you can admission to any such university falling under the ranking of yours. for further details you can visit the following link : http://www.askiitians.com/aieee/aieee-2009-cut-offs askiitians.com provides online iit jee courses and iit jee test series with iitians. click here to get free online test series and check your status timely or you can join us as our registered user for getting best iit jee study material or iit jee test series. askiitians provide you all the best possible information, feel free to ask. all the best. thanks and regards. akhilesh shukla",
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19a0a8dcfe8fef039d3feb3aa9388023 | if i get 155 out of 432 & i am interested to join civil engineering course, please let me know , the list of colleges | askiitians.com | 2021.31 | [
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"text": "hi, askiitians provide the iit jee cut off along with the opening and closing ran given below for iit jee cut off: http://www.askiitians.com/iit-jee-2010-cut-offs.aspx click for opening and closing ranks: http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx you can check out the cutoff in new iits, check the link given below : http://jee.iitd.ac.in/openclose09.htm (this link includes the more detail analysis) for code of the cources check the councelling broucher 2009. please feel free to post as many doubts on our disucssion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. askiitians expert amit yadav",
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2d128c72eea3aac0fedd6bf415088b68 | perimeter of a parallelogram land is 96m and it`s area is 270 square metres . if one of its side of the parallelogram is 18m. find the length of the other side and also find the length of the altitude t and m. | askiitians.com | 2021.39 | [
{
"text": "lets assume side of parallelogram isa &b another twowill also be a&b) now its given that 2(a+b)=96 so a+b=48 ,one side is given 18 so another is 30 (48-18) and area=base*height so there will be two height because 18&30 both can be choosen as base in caseof 18 it will be 270/18=15m,and in case of 30 it will be 9m",
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afa954fda1107fc58fa7aacf900d7b5f | can i prefer mining over the aerospace in iit kanpuer........ | askiitians.com | 2021.31 | [
{
"text": "you may not",
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"text": "if you are intrested in mining then go for it or else aerospace is a better option",
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10b7a8a047b956815b9d26ad40c788ae | i just wana know proof of angle of intersection of two circle in cordinate geometry ..........interms of cosine angle | askiitians.com | 2021.31 | [
{
"text": "at first find the point of intersection of curves....let it be a.. now make a tangent to the curve separately at this point ... there will be 2 tangents with different slopes...let slope of tangents are m 1 ,m 2 respectively... then we have tan@=m2-m1/1+m1m2 @ is the angle bw tangents and it is called angle of intersection of two curves..... sec 2 @ =(1+tan 2 @) from here calculate cos@",
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c392054e0ad673630be72395656d1bcb | please tell me the proof of the pi(p). | askiitians.com | 2021.43 | [
{
"text": "can please elaborate on what you want to prove ?",
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"text": "succinctly, pi--which is written as the greek letter for p, or --is the ratio of the circumference of any circle to the diameter of that circle. regardless of the circle's size, this ratio will always equal pi. in decimal form, the value of pi is approximately 3.14. but pi is an irrational number, meaning that its decimal form neither ends (like 1/4 = 0.25) nor becomes repetitive (like 1/6 = 0.166666...). (to only 18 decimal places, pi is 3.141592653589793238.) hence, it is useful to have shorthand for this ratio of circumference to diameter. according to petr beckmann's a history of pi , the greek letter was first used for this purpose by william jones in 1706, probably as an abbreviation of periphery, and became standard mathematical notation roughly 30 years later. thank you ruchi askiitians faculty",
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1213bc464dff35b6ae0a5cdd1de0f6da | powdery mildew of pea is caused by a) virusb) protozoa c) fungusd) bacteria | askiitians.com | 2021.21 | [
{
"text": "hi smita powdery mildew of pea is caused by a fungus erysiphe polygoni. so option c} fungus is correct here thanks regards sahil",
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2a785f423f2722e21d232f4fb4b2c5a4 | properties of triangles sin 2 +cos 2 sinx graph tan75 cot16cot44+cot44cot76-cot76cot16 | askiitians.com | 2021.21 | [
{
"text": "dear student please ask complete question in standard notation and one question per post regards",
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"text": "dear student question is not clear please attach an image, we will happy to help you good luck cheers",
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4a89e66f87abe915b8dcf431feb7a63d | explain me about potential difference in conductor in electricity | askiitians.com | 2021.43 | [
{
"text": "electrons move from higher potential to lower potential. when a conductor is connected to electricity,electron moves from negative terminal to positive terminal.hence, the electric current flows in the opposite to the direction of the flow of the current.",
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913098c8e6504eb4d61c02e731780b66 | describe the method to measure the focal length of a concave mirror ? | askiitians.com | 2021.43 | [
{
"text": "following are the ways to obtain the focal length of convex lens: the convex lens is thicker in the middle and thinner at the edges and is also known as the converging lens. the refracted rays from the parallel beam of light converge on the other side of the convex lens. if the image is obtained at the focus of the lens, the image would be real, inverted and very small. f is the focal length which is the difference between the optical centre of the lens and the principal focus. the image can be obtained on the screen as the image formed by the lens is real.",
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"text": "in simple we can get focal length of concave mirror by applying mirror formula 1 bi f is equal to 1 by v + 1 by u four practical just date object in front of concave mirror take any sentimeter that is object distance and you will get image distance in centimetres then apply that applied at distance what we get in mirror formula and you will get the focal length of that concave mirror",
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5eeded1acc8f5ff0a92f2f57c9c6e0e7 | sir please rank them, srm,kattankulathur- it svnit -civil sir please reply its very urgent | askiitians.com | 2021.43 | [
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"text": "go for svnit... srm is nowhere near svnit best of luck!!!!!!!!!!!!!!!! pls approve my answer by clicking on yes below!!!!!!!!!",
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a467763dddf87c57aae39408e931d778 | find the coordinate of the point in the curve y=(1+x 2 ),wfere the tangent to the curve has greatest slope? | askiitians.com | 2021.39 | [
{
"text": "dear upendra y=(1+x 2 ) dy/dx =2x it is clear that at infinity slope is maximum ie tangent is parallel to y axix please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best. regards, askiitians experts badiuddin",
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"text": "hi upendra, y=(1+x 2 ) dy/dx = 2x 2x is maximum when x--->∞ the slope of tangent is maximum when x tends to infinity and y also tends to infinity.",
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b5f9a73c4218be4182111df282ecfc26 | why psi(r) graph of s orbital starts from maxima but not p,d,f....... | askiitians.com | 2021.31 | [
{
"text": "the hydrogen s orbitals correspond to l=0 and only allow ml=0. in this case, the solution for the angular wavefunction, y0,0(θ,ϕ)is a constant. as a result, the ψn,0,0(r,θ,ϕ)wavefunctions only depend on r and the s orbitals are all spherical in shape.because ψn,0,0depends only on r, in case of other orbital it depends on the angle . porbital-the angular wave functiony1,0(θ,ϕ)=cosθonly depends on θ. thus it does not starts from maxima",
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3a1a32f052b78d101a65f60013b43d8f | i secured air 41000 in aieee. which government colleges i can get at this rank? i dont want remote nits like srinagar/agartala ? what about nit delhi ?is it gud decision to join any of these in punjab univ. 1.chandigarh college of engineering& technology (ccet), 2.university institute of engineering & technology (uiet), 3.university institute of chemical engineering & technology (uicet), 4.swami sarvanand giri panjab university regional centre (ssgpurc), bajwara, hoshiarpur, if i get a chance , instead of any private colege ? also wich private coleges will be best choice at this rank? | askiitians.com | 2021.39 | [
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"text": "dear robin, as the counselling is over ...i hope you got the best collage and stream of your choice ... good luck for your future from the askiitians team. we are all iitians and here to help you in your iit jee preparation. all the best. now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar : click here to download the toolbar.. regards askiitians expert vijay luxmi",
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85be33428028143be7a30ab1382f4b77 | prove that 2n > n for all positive integers n by the principle of mathematical induction | askiitians.com | 2021.31 | [
{
"text": "welcome to askiitians assume that p(n): 2n> n if n =1, 21>1. hence p(1) is true let us assume that p(k) is true for any positive integer k, it means that, i.e., 2k> k …(1) we shall now prove that p(k +1) is true whenever p(k) is true. now, multiplying both sides of the equation (1) by 2, we get 2. 2k> 2k now by using the property, i.e., 2k+1> 2k = k + k > k + 1 hence, p(k + 1) is true when p(k) is true. therefore, p(n) is true for every positive integer n is proved using the principle of mathematical induction. thanks",
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c82889d6e6040d9cc0edb5c80aae9012 | .......... are the organism which make their own food. | askiitians.com | 2021.43 | [
{
"text": "plants are the organisms which make their own food hence they are known as autotrophs. they convert solar energy into chemical energy through photosynthesis. it is the process in which green plants use carbon dioxide and water in presence of sunlight to synthesize nutrients such carbohydrates in the form of glucose and release oxygen into the atmosphere.",
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3d592166f40c541ca34a5701739bce2b | plz ans - calculate how much heat energy is required to raise the temperature of a cube of copper of side 2cm. from 300 to 320k. given: density=8933kg/m cube , atomic weight=63.55, cp=24j/k/mole | askiitians.com | 2021.39 | [
{
"text": "dear roopa, your question is based on a simple formula, heat energy required = mct mass=d.v=8933 . (.02)^3 = .0712 kg = 71.2 gm mo of moles = 71.2 / 63.55 = 1.12 moles c=24 j/k-mole. t=20 h= (1.12) . 24 . 20 =537.6 joules (ans) regards.",
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b15c8a4b7807b02c24cbff2849132321 | 4cos(2Ï€/7) cos(Ï€/7)-1=2cos (2Ï€/7) prove this | askiitians.com | 2021.21 | [
{
"text": "4cos(2p/7) cos(p/7)-1= 1.24 2cos (2p/7)=1.24 sher mohammad b.tech, iit delhi.",
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"text": "{2[2sin(p/7)cos(p/7)]cos(2p/7)}/sin(p/7)-1 (by dividing numerator and denominator with sin(p/7)\n=[2sin(2p/7)cos(2p/7)]/sin(p/7)-1\n=sin(4p/7) -1 sin(p/7) =sin(p-4p/7) -1 sin(p/7) =sin(3p/7) -1 sin(p/7) =sin(3p/7)-sin(p/7) sin(p/7) =2cos[(3p+p)/2*7]sin[(3p-p)/2*7] {sinc-sind=2cos[(c+d)/2]sin[(c-d)/2]} sin(p/7) =2cos(2p/7)sin(p/7) (by cancelling sin(p/7) in numerator and denominator) sin(p/7) =2cos(2p/7)",
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"text": "{2[2sin(p/7)cos(p/7)]cos(2p/7)}/sin(p/7)-1 (by dividing numerator and denominator with sin(p/7)\n=[2sin(2p/7)cos(2p/7)]/sin(p/7)-1\n=sin(4p/7) -1 sin(p/7) =sin(p-4p/7) -1 sin(p/7) =sin(3p/7) -1 sin(p/7) =sin(3p/7)-sin(p/7) sin(p/7) =2cos[(3p+p)/2*7]sin[(3p-p)/2*7] sin(p/7) =2cos(2p/7)sin(p/7) (by cancelling sin(p/7) in numerator and denominator) sin(p/7) =2cos(2p/7)",
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"text": "{2[2sin(?/7)cos(?/7)]cos(2?/7)}/sin(?/7)-1 (by dividing numerator and denominator with sin(?/7)\n=[2sin(2?/7)cos(2?/7)]/sin(?/7)-1\n=sin(4?/7) -1 sin(?/7) =sin(?-4?/7) -1 sin(?/7) =sin(3?/7) -1 sin(p/7) =sin(3?/7)-sin(?/7) sin(?/7) =2cos[(3?+?)/2*7]sin[(3?-?)/2*7] sin(?/7) =2cos(2?/7)sin(?/7) (by cancelling sin(?/7) in numerator and denominator) sin(?/7) =2cos(2?/7)",
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81206fe805e70d605c0ef977ad336b1b | 52. list the characteristics of cork. how are they formed? mention their role. | askiitians.com | 2021.43 | [
{
"text": "characteristics of cork : (i) outer rough surface of older stem and roots. (ii) impermeable cells are arranged in layers due to the presence of suberin in the walls. (iii) cells become dead on maturity and store resins, and tannins. (iv) it is usually formed by secondary lateral meristematic tissues, i.e. cork cambium. as plant grow older, a strip of secondary meristem replaces the epidermis of the stem. cells cut on the outer side by this meristem are called cork. importance of corks : a. prevent water loss. b. protected against the mechanical injuries. c. facilitates the gaseous exchange due to presence of lenticels. d. for household usage.",
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0b9c91f83627f525efc58fc0004510dc | the calorie is defined as 1 cal =4.186 joule. why not as 1 cal =4 joule to make the conversions easy | askiitians.com | 2021.43 | [
{
"text": "1 calorie = 4.186 joules but not 4 joules since by observing the decimal figure that is .186 refers that 8 is the number which comes after 5, so it is more than 5 . so we can write it as 4.186 or 4.19 but not 4.",
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e3e4070f5c01888e90b380c50c808780 | 5. the ages of husbands and wives in a community were found to have a correlation coefficient equal to +0.8; the average of husbands’ ages was 25 years and that of wives’ ages 22 years; their standard deviations were respectively 4 and 5 years. find the two lines of regression and from the lines ,measure a. the expected age of husband when wife’s age is 12 years b. the expected age of wife when husband’s age is 33 years | askiitians.com | 2021.21 | [
{
"text": "hello student, (a) the expected age of husband when the wife’s age is 12 years: while considering this, we shall have to consider three things: the correlation coefficient is +0.8, so we haveb 12. (0.8) = 9.6 by rounding off we get it as 10. but, this also spares 0.2 which is not in correlation, so we have 25(0.2) = 5. also, given that on an average husband is 3 years older, so finally we have 10+5+3 = 18. (b) similarly, in this case we have 0.8(33) with standard deviation (0.2)4. this gives the average as 26.4 with standard deviation 0.8 so, it is roughly between 25 to 27.",
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2bcff932d36fbae6f5a605dba1fdaed1 | ​four bulbs b 1, b 2 ,b 3 ,b 4of 100w each are connected to220v main.the reading in an ideal ammeter will be | askiitians.com | 2021.25 | [
{
"text": "we know that p = v2/r here v across all the bulbs is 220 v and p = 100 w. then the resistance of the bulb is r = v2/p = (220)2/100 = 48400/100 = 484 ω the circuit when reduce gives 4 resistors each of resistance r = 484 ω in parallel to each other. hence, the equivalent resistance is r/4 = 484/4 ω = 121 ω total current in the circuit is v/r = 220/121 = 20/11 and this is equally divided among the bulbs. current flowing into b2, b3 and b4 will be reading of the ammeter = 20/11 x 3/4 = 15/11 a = 1.36 a",
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"text": "dear student current through each bulb =100/220=5/11a therefore current through ideal ammeter = 3×5/11=1.35a good luck",
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5f77993628389177b1eeae0f34be31fb | important things in chapter biological classification | askiitians.com | 2021.21 | [
{
"text": "hi avishi, thank you for asking you can go through that topics only which are mentioned in ncert book. take reference from any other standard book as well but only to the topics limited to ncert.",
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588259d7991cc94461b6191a61cdcc99 | a mixture of ethane and ethene occupies 40litres at 1.00atm and at 400k the the mixture reacts completely with 130g of o2 and h2o.assuming ideal gas behaviour,calculate the molefraction of c2h4 and c2h6 in the mixture. | askiitians.com | 2021.43 | [
{
"text": "pv=nrtn=1×40/(0.0821×400)=1.218 molesmoles of (c2h6 +c2h4)=1.218a+b=1.218 — (1)c2h6 + 7/2 o2 —> 2co2 + 2h2oc2h4 + 3o2 —> 2co2 + 2h2o7/2 a + 3b = 130/32 —(2)from equation 1 and 2a=0.817b=0.401mole fraction of ethane= 0.817/1.218 = 0.67mole fraction of ethene= 0.401/1.218 = 0.33",
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{
"text": "by shivam aditya dwit79a03fiitjee dwarkasec 12 question link fiitjee package pinnacle programme 123456791011",
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2478e8650fc81dfef737ed94005f13b9 | in youngs double slit experiment with wavelength 5890a°; there are 60 fringes in the field of vision. how many fringes will be observed in the same field of vision if wavelength used is5460a° | askiitians.com | 2021.39 | [
{
"text": "number of edges is straightforwardly relative to the wavelength n1 α ƛ1 n2 α ƛ2 n1/n2 = ƛ1/ƛ2  60/n2 = 5890/5460  n2 = (5460 *60)/5890  n2 = 55",
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] |
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5bcc769b3aff93749596bfb658cbfdc3 | a flexible chain oh weight w hangs between 2 fixed points a & b which are at same horizontal level the inclination of the chain with the horizontal is x what is the tension of the chain at the mid point | askiitians.com | 2021.31 | [
{
"text": "hii appl the tension at one end and midpoint , to draw the free body diagram of the tension in chain. t2 = t1 cosq where t2 is tension at midpoint ,and t1 is te tensin at end point. t1 = m/2 * gsinq t2 = mg/2 * cot q",
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{
"text": "balance the forces to get the answer. t2 = t1* cosθ t1 = m/2 * g * sinθ so t2 = mg/2 * cotθ. ........................................................................",
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e786a68db9dde28f3ef7d386555d4fab | capicator | askiitians.com | 2021.31 | [
{
"text": "hi aman, i think the ques is incomplete so plz send complete ques and then let me help u",
"name": "",
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{
"text": "my mean to say is that if we connect a capacitor in between number of resistors than what will be effect on its net resistance",
"name": "",
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{
"text": "hi aman, when u connect capacitor wid resistors den then the capacitor would discharge its energy into the resistor. this voltage across the capacitor over time could be found through kirchhoff's current law, where the current coming out of the capacitor must equal the current going through the resistor. this results in the linear differential equation . regarding its equivalent resistance, the equivalent resistance of a capacitor increases in relation to the amount of charge stored on the capacitor. if a capacitor is subjected to an alternating current voltage source, then the voltage of the capacitor would flip to the frequency of the ac voltage source. the faster the voltage of the ac voltage source flips, the less time charge would be allowed to be stored on the capacitor, therefore reducing the capacitor's equivalent resistance. this explains the inverse relationship the equivalent resistance of a capacitor has with the frequency of the voltage source. the resistance, also known as the complex impedance , z c (in ohms) of a capacitor with capacitance c (in farads ) is s is d angular frequency the current in the circuit is the same everywhere since the circuit is in series: u can see dat in d expression of current resistance of capacitor just adds up to d given resistance...",
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f4ba001afcbabe962228b21a3fdfe7e4 | if a be(2,2), b be(5,-2) find all points on x-axis such that ap is perpendicular to pb | askiitians.com | 2021.25 | [
{
"text": "let p is (x,0) then slope of ap = 2/x-2 slope of pb = 5/-2-x if lines are perpendicular then product of slopes = -1 (2/x-2) (-5/x+2) = -1 x 2 - 4 = 10 x 2 = 14 x = +root14 & -root14 points are , (root14,0) & (-root14,0)",
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{
"text": "the points are a(2,2) and b(5,-2) it is given that the point p is in the x-axis therefore lets assume it to be p(x,0) it is also given that ap is perpendicular to bp therefore if m 1 is the slope of ap and m 2 is the slope of bp then we know that m 1 x m 2 = -1 therefore (2-0)/2-x)*(-2-0)/5-x)=-1 you will get a quadratic equation x 2 -7x+6=0 solving you will get x=1 or x=6 so the point required is p(1,0) or p(6,0) hope that you got what you needed best of luck for your examinations",
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80a819aa1b1c4eab7f5bb171d5d75494 | a and b are the two students. probabilities of solving a problem by a and b separately are 5/9 and 7/11 respectively. find the probability that the problem will be solved. | askiitians.com | 2021.39 | [
{
"text": "probability that the problem is solved by a = p (a) = 5/9 probability that the problem is solved by b = p (b) = 7/11 probability that the problem is not solved by a = p (a c ) = 1 – 5/9 = 4/9 probability that the problem is not solved by b = p (b c ) = 1 – 7/11 = 4/11 probability that the problem is solved = p(a) p(b c ) + p(b) p(a c ) + p(a)p(b) = 5/9 . 4/11 + 7/11 . 4/9 + 5/9 . 7/11 = 83/99. thanks & regards latika leekha askiitians faculty",
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] |
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b240962508c3b631d68eca1b232415c1 | 61. a d.c. generator is based on the principle of \_\_\_\_\_\_\_\_\_\_ . | askiitians.com | 2021.31 | [
{
"text": "answer: explanation: electromagnetic induction",
"name": "",
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] |
|
40c5d8be3b6434f3a7ea6d66041ed4d8 | . according to data of question 4, which fruit is liked by most of the students? (a) o (b) g (c) m (d) a | askiitians.com | 2021.39 | [
{
"text": "dear student option (c) is right according to data of question 4, mango(m) is liked by most of the students. thanks",
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}
] |
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3f42915bc52ef83399e3b6f4504394a1 | what is the best way for learning facts of inorganic chemistry ? | askiitians.com | 2021.21 | [
{
"text": "dear aditya, the best way is to do lots of written practise and revise all the topics at a regular interval, best of luck...!!!! cracking iit just got more exciting,it’s not just all about getting assistance from iitians, alongside target achievement and rewards play an important role. askiitians has it all for you, wherein you get assistance only from iitians for your preparation and win by answering queries in the discussion forums. reward points 5 + 15 for all those who upload their pic and download the askiitians toolbar, just a simple to download the toolbar…. so start the brain storming…. become a leader with elite expert league askiitians thanks aman bansal askiitian expert",
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|
1471948b117ac9ced5934859b2e018ef | sir,i am a sc candidatemy subjectwise cutoff is p=22,c=21,m=32,my total marks is 75can i get selected for preparatory course or in eml | askiitians.com | 2021.31 | [
{
"text": "dear student, pls wait for the merit list to be out , your rank depends on several factors",
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}
] |
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b4b5d1156ef717aad99fae69c7cad217 | log 54 to the base 3/log 3 to the base 486-log 1458 to the base 3/log 3 to the base 18=xfind the value of x. | askiitians.com | 2021.43 | [
{
"text": "hello student, thanks & regards arun kumar btech, iit delhi askiitians faculty",
"name": "",
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},
{
"text": "thanks for the approach sir",
"name": "",
"is_accepted": false
}
] |
|
732b3c16ffc4d95adfe9c38d86f35318 | is the theory part given in ncert from inorganic chemistry is enough for jee adv?? | askiitians.com | 2021.21 | [
{
"text": "ncert is without a doubt imperative to the extent inorganic science is concerned yet in the event that you are giving jee 2017 or any future jee, you should realize that ncert is not adequate. you will be unable to discover everything jee asks in ncert however in past year papers jee has made inquiries specifically from ncert in any case, you see a book is a restricted source and now jee is thinking about upon different choices for inorganic inquiries in any case, this doesn't diminish significance of ncert by any stretch of the imagination. ncert ought to b your first need however it is not a definitive book on the off chance that you are going for a plunge rank in jee.",
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2b3ecc5188dfee72e1164a29c6097789 | i am in 12th this year, and h?aven't started preparing for iit yet. i want to buy- chemistry- o.p.tandon- physical, inorganic, organic morrison boyd- organic o.p.bahadur- numerical will these books cover the syllabus completely? will i miss something if i read only these? are these sufficient? please answer in detail. | askiitians.com | 2021.43 | [
{
"text": "dear student, yes these books cover the entire syllabus and are quite good.....",
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b23eb21bbeb59f93a03843c2734d5539 | given vectors p and q are perpendicular and |p|=2|q|, determine the angle between |p-q| and |3p-6q|. (not using dot product as that was not taught yet in this unit) | askiitians.com | 2021.31 | [
{
"text": "if you dont know dot product just assume here that q=i and p =2j here p and q are perpendicular to each other and there mode is always satisfy the given equation here now you can find angle without using dot only by simple trignometry",
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] |
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128c7a723270f47ba95fbd1eeaccd8e6 | when should we use p=h row g and when p=pa+h row g ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, | askiitians.com | 2021.25 | [
{
"text": "p=hrwog is used when we find find pressure over a surface kept in atmosphere (above sea level ) and p =hrwog +pa is used for calculating pressure over an area or object immesersed in a sea",
"name": "",
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},
{
"text": "kindly refer to the following link https:/ww.physicsforums.com/threads/pressure-under-water.307277/ it is used for calculating pressure when a body is immersed in a sea (below the sea level",
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}
] |
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47f05e695a117b5d1fef9f65a0414d20 | well , i think i would like to join some of the iit (preferably kanpur or delhi) .so what rank should i get the minimum to get into iit for doing my courses in computer science . | askiitians.com | 2021.39 | [
{
"text": "dear aswin v http://www.askiitians.com/iit-jee-2009-rank.aspx check above link for datail opening and cloasing rank for all iits please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee & aieee preparation. all the best. regards, askiitians experts badiuddin",
"name": "",
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] |
|
bfc9d0a3072d14743cae9c34c3fed75b | can you please explain how the sound is transferred through our ears? | askiitians.com | 2021.43 | [
{
"text": "the working of an ear the decibel scale is used because it closely corresponds to how we perceive the loudness of sounds. the human ear is really quite an amazing detector of sound, and it's worth spending some time learning how it works. the ear is split into three sections, the outer ear, the middle ear, and the inner ear. the outer ear acts much like a funnel, collecting the sound and transferring it inside the head down a passage that's about 3 cm long, ending at the ear drum. the ear drum separates the outer ear from the middle ear, and, much like the skin on a drum, it is a thin membrane that vibrates in response to a sound wave. the middle ear is connected to the mouth via the eustachian tubes to ensure that the inside of the eardrum is maintained at atmospheric pressure. this is necessary for the drum to be able to respond to the small variations in pressure from atmospheric pressure that make up the sound wave. in the middle ear are three small bones, called the hammer, anvil, and stirrup because of their shapes. these transfer the sound wave from the ear drum to the inner ear. similar to a hydraulic lift, the pressure is transferred from a relatively large area (the eardrum) to a smaller area (the window to the inner ear). by pascal's principle (see the section on fluids), the pressure is constant. the force is smaller at the small-area inner ear, but the work done at each end is equal, so the inner ear experiences a vibration with a much larger amplitude than that at the ear drum. the bones, in effect, act as an audio amplifier. the eardrum and the window to the inner ear have different acoustic properties. if they were directly connected together some energy would be reflected back. the three bones in the middle ear are designed to transfer sound energy from the eardrum to the inner ear without any energy lost to reflections. the technical physics term for this is \"impedance match\": any time energy is transferred from one system to another without any reflected energy, the impedances are matched at the transfer point...in this case, the bones provide the impedance matching. the bottom line is that they will amplify the sound level without losing any sound energy. the inner ear contains a fluid-filled tube, the cochlea. the cochlea is coiled like a snail, is about 3 mm in diameter, and is divided along its length by the basilar membrane. it also contains a set of hair cells that convert the sound wave into electrical pulses; these are transferred along nerves to the brain, to be interpreted as sound. when a sound signal enters the inner ear, a small movement of the basilar membrane or the fluid in the cochlea results in the rubbing of another membrane across the hair cells. the relatively long hairs provide another level of amplification, in the sense that a small force applied at the ends is converted into a relatively large torque. to summarize, then, the outer ear collects sound and transfers it to the middle ear; the middle ear amplifies the sound and passes it to the inner ear; and the inner ear converts the sound into electrical signals to be sent to the brain. the range of human hearing is quite large, both in terms of sound intensity and sound frequency. humans can hear sounds between about 20 hz and 20000 hz; music and speech typically covers the range from 100 hz to 3000 hz. the ear is most sensitive to sound of about 3000 hz, as the following graph shows:",
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] |
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a787af4c22a63f5fa85de29a3456f0f8 | the wave number of hydrogen first line of balmer series is 15200cm. what is the wave number of first line of balmer series in lithium dispositive ion? | askiitians.com | 2021.39 | [
{
"text": "first of all your units of wave number are wrong. it has to be cm -1 . and coming to your question, wave number is directly propotional to square of atomic number. so 15200x9 is your answer.",
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8c909e6649e757fe0626660541c50da0 | i have not received my iitjee madras(zone) admit card till on 24-03-2010. my application no. a161006094 and application status is that, scrutiny is completed massage on iitm web site but till the date i have not received my admit card. kindly i request you give the details of my admit card regarding test centre, reg.no and testcity on my e-mail address ( [email protected] ) or on my mobile no.09907181545. | askiitians.com | 2021.21 | [
{
"text": "hey i too haven't got my hall ticket...as of today.. but i've called iit madras and inquired about my hall ticket by giving them my application number... they told i would receive mine on 28-03-2010...and my friend on 25-03-2010 even you try to call and find out @(044) 22578220",
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}
] |
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da039e57d7b116d1fa3a583e259a37b1 | kindly advise whether one should go for cs/ electrical engg in iit varanasi or new iits | askiitians.com | 2021.43 | [
{
"text": "go for iit varanasi",
"name": "",
"is_accepted": false
},
{
"text": "i think u should go for electrical from bhu(iit varanasi)",
"name": "",
"is_accepted": false
},
{
"text": "iit varanasi for sure",
"name": "",
"is_accepted": false
}
] |
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4de1dd0ce0e73f26bec769ef43c2125e | calculate the wavelength in the visible spectrum (3500-7000)angstrom which coincide with the wavelength 6000 angstrom in 5th order? | askiitians.com | 2021.31 | [
{
"text": "since e=hv and c= v× lambda therefore e=hv = hc/ lambda = hc/6000 . --->1 ze= hv1 = hc/lambda ---->2 from &. zhc/6000. = hc/lambda therefore lambda1 = 3000 a°",
"name": "",
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},
{
"text": "as learnt the energy (e) of a quantum of radiation - where h is plank’s constant and is frequency - and speed of electromagnetic radiation - where frequency is ( , pronounced as nu), wavelength is (λ) and velocity of light is(c) - we know, e= energy of a quantum of radiation h=plank's constant frequency of radiation and now, put in 2",
"name": "",
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},
{
"text": "dear student the above explanation is incorrect , please do not follow.................................................. good luck",
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}
] |
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51db2638290fd93850f5c848fd676f85 | a man is 25m behind a bus, when the bus stars accelerating at 2ms -2 and the man starts movin with a constant velocity of 10m/s. time taken by him to board the bus is : (a) 2s (b) 3s (c) 4s (d) 5s | askiitians.com | 2021.25 | [
{
"text": "acceleration of man is 0 and acc. of bus is 2than relative acc is = 0-2 =-2. than s = ut -1/2at2 25 =0(t) -1/2(-2)t2 t =5 sec.",
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}
] |
|
0aa020809e24c66f06883186545c4e7b | i secured a air of 26032 in aieee 2012 , not getting any govt. colleges, nor even nits. should i commit a suicide, all doors are looking closed for me now. :( | askiitians.com | 2021.31 | [
{
"text": "r u mad?you can get in nit-silichar ,join electronics and instrumentation .you should have patience.life has joy and sorrows,we have to accept both in equal way.remmebr one door closes automatically other door opens.",
"name": "",
"is_accepted": false
},
{
"text": "not at all. your thinking is just stupid. one should have patience and hard work. if u havent got rank u mean that ur career is end. be bware u may try once again. put ur maximum efforts. good luck.",
"name": "",
"is_accepted": false
},
{
"text": "chemical engineering-nit agartala production engieering-nit agartala electrical and electronics-nit manipur electronics and communication-nit manipur computer science and engineering-nit mizoram,nit nagaland electrical and electronics-nit mizoram,nit nagaland electronics and communication-nit mizoram,nit nagaland 5 year msc(chemistry,maths,physics)-nit rourkela bio medical engineering-nit rourkela,nit raipur chemical engineering-nit srinagar civil engineering-nit srinagar information technology-nit srinagar biotechnology-nit raipur take cse,ee or ec at any of the nits mentioned above..",
"name": "",
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}
] |
|
2e718333e8d0b71c2edc23e2b36d8735 | can anybody tell me what is the scope of biomedical engineering in india......... what would be the starting salary | askiitians.com | 2021.31 | [
{
"text": "dear swen, biomedical engineering constitutes human beings earliest efforts to understand the living world in terms of the basic sciences and to comprehend the body mechanism in terms of their technological creations. biomedical engineering involves the study and application of engineering processes for diagnosis and therapy. biomedical engineering (bme) is a rapidly changing interdisciplinary domain, in which each branch of engineering interacts with a number of other disciplines to yield a fundamental understanding of health maintenance processes and improved diagnosis, optimal interventional (surgical, therapeutic & rehabilitative) procedures, prosthesis and organ assist systems, health care systems performance and econometrics. biomedical engineering graduate is expected to be a versatile chemical-electro-mechanical-computer engineer. well acquainted with the hospital and health care arenas. competent in applying biomedical engineering in clinical care and healthcare engineering in health care delivery. we are all iitians and here to help you in your iit jee preparation. all the best. if you like this answer please approve it.... win exciting gifts by answering the questions on discussion forum sagar singh b.tech iit delhi",
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] |
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47bfe50787c73fc1e6b8c1fda92a6529 | hi, pls explain why the output frequency of a center tap full wave rectifier becomes double the input frequency. | askiitians.com | 2021.31 | [
{
"text": "dear devesan, as the current flowing through the load is unidirectional, so the voltage developed across the load is also unidirectional the same as for the previous two diode full-wave rectifier, therefore the average dc voltage across the load is 0.637vmax however in reality, during each half cycle the current flows through two diodes instead of just one so the amplitude of the output voltage is two voltage drops ( 2 x 0.7 = 1.4v ) less than the input vamplitude. the ripple frequency is now twice the supply frequency (e.g. 100hz for a 50hz supply) best of luck...!!!! cracking iit just got more exciting,it’s not just all about getting assistance from iitians, alongside target achievement and rewards play an important role. askiitians has it all for you, wherein you get assistance only from iitians for your preparation and win by answering queries in the discussion forums. reward points 5 + 15 for all those who upload their pic and download the askiitians toolbar, just a simple click here to download the toolbar…. so start the brain storming…. become a leader with elite expert league askiitians thanks aman bansal askiitian expert",
"name": "",
"is_accepted": false
}
] |
|
c436d3634e46825e0c956580e7c21898 | my aieee general rank 27073,can i get any nit. | askiitians.com | 2021.39 | [
{
"text": "nit nagaland,mezoram,meghalaya by 5th round.",
"name": "",
"is_accepted": false
},
{
"text": "yes but u have 2 compromise 4 branch",
"name": "",
"is_accepted": false
}
] |
|
dbc46337b6ab726cff8dde30a44a74bc | my air in jee main 2014 is 377304 and i belongs to sc category …. so can iget admission to any nit | askiitians.com | 2021.43 | [
{
"text": "as your rank is high there is a very less possiblity that you will get into nits. the closing ranks for sc category are even lesser than your rank .but you can get admission into iiit guwahati, itm university etc.",
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"is_accepted": false
}
] |
|
10e14c5082ec337ff3430c20665342b2 | a compound was found to contain 5.37% nitrogen. what is the minimum molecular mass of compound? | askiitians.com | 2021.21 | [
{
"text": "please remove my previous solution: 13n/m=0.0537 m=13n/0.0537=2905",
"name": "",
"is_accepted": false
},
{
"text": "according to the question, 100g of nitrogen compound contains 5.37g of nitrogen, then, for 14g of nitrogen (molar mass of nitrogen), the molecular mass of the compound = (100/5.37)×14=260.7g. (by unitary method)",
"name": "",
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] |
|
bffd991dac1cca01fc35c1ec627dc9dd | find the roots of the following quadratic equations by factorisation: 100x ^2 – 20x + 1 = 0 | askiitians.com | 2021.25 | [
{
"text": "dear student given, 100x^2 – 20x + 1=0 taking lhs, = 100x^2 – 10x - 10x + 1 = 10x(10x - 1) -1(10x - 1) = (10x - 1)^2 the roots of this equation, 100x^2 – 20x + 1=0, are the values of x for which (10x - 1)^2= 0 ∴ (10x - 1) = 0 or (10x - 1) = 0 →x = 1/10 or x = 1/10 thanks",
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}
] |
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f949348034c40262f013d11b02d4272a | do we get a shock if we touch any wires coming from a dc circuit? for example, the wires of a tubelight in a bus etc? | askiitians.com | 2021.21 | [
{
"text": "the flow of electricity require complete close path, if you current gets a path through your body then surely you will get a bad shock, otherwise if path is not complete you will not get shock. sher mohammad askiitians faculty b.tech iit delhi",
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}
] |
|
fdfb5b29ea63b4ac82bf86d8c836bcbe | how did u get 2sinacosa after multiplying | askiitians.com | 2021.21 | [
{
"text": "please reply in the same thread where the question was answered.",
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"is_accepted": false
}
] |
|
bc0be46e19093442ec26412c1b74b404 | meaning of conditional reabsorption in distal convoluted tubule. | askiitians.com | 2021.25 | [
{
"text": "dear navdeep conditional reabsorption are simmilar to tubular reabsorption , as its happening on dct , that means the process by which the solutes and water are removed , from the tubular fluid and transported to the blood . hope it clears now regards",
"name": "",
"is_accepted": false
},
{
"text": "conditional reabsorption means reabsorption under certain condition.... conditions are :1)when aldosterone acts on dct, dct will reabsorb na+2)when adh or vassopressin acts on dct, dct will reabsorb water...hope this makes the word conditional more clearer thankskindly upvote if u r satisfied",
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] |
|
0af6051e33639184106b140ca0cd1a48 | sir, i have passed my 12th class with 95% in pcm. since i could not make it to jee this year, i wish to dropout and prepare for the same. i scored 142 marks in jee. i would like to know the method of preparation i should follow for the next ten months. also, maths is my weak area. how can i improve that? it would be a great help if u could suggest me some good books in maths. | askiitians.com | 2021.21 | [
{
"text": "dear akshita, your score in pcm is quite good .. you seems to do very good in jee exam 2011..the only suggestion i wud like to give is make your concepts very strong and practise as much as possible .. join some coachings for proper guidelines and also join some test series .. jus to judge your level of preparation. study hard .. and focus only on jee preparation for one year. all the very best for your future !. check out the links for best books: http://www.askiitians.com/important-books-iit-jee.aspx you dont need to do much books .. these are sufficient if you do thm with concentration and interest. please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. askiitians expert amit yadav now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian.",
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59e791aa9c038274755f4fdfa9d38ac7 | the atomic weight of an element is 39.the no. of neutrons in its nucleus is one more than the no of protons the no of protons,neutrons and electrons respectively in its atom would be | askiitians.com | 2021.43 | [
{
"text": "hi pallavi, atomic weight = 39 let no of protons = x then no of neutrons = x+1 x+x+1 = 39 2x = 38 x = 19 no of protons = 19 no of neutrons = 20 no of electrons in neutral atom = 19",
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a7163482b69180453d48ffbb698fd835 | commercially available hydrochloric acid contains 38% hcl by mass.
find out the volume of concentrated hydrochloric acid required to make 1litre of 0.10m hcl.(density is 1.19g/ml) | askiitians.com | 2021.25 | [
{
"text": "8 ml will be required. fro this find the weight of hcl required . then from this find the weight of commercial hcl required and then find the volume from the given density.\nmass of hcl req=3.65gm mass of commercial hcl req=365/38 gm\nvolume req=(365/38)/1.19",
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f347b0876f75d13f431a1e9b00318842 | the vertices of a polygon are labelled with natural numbers from 1 to 2000 in increasing order . first we cross out the number 1 and then numbers 16, 31, 46... until one number is crossed out 2 times. what is the number and how many numbers are left uncrossed ? | askiitians.com | 2021.21 | [
{
"text": "dear student the number being crossed are in form 15k+1 firstly numbers will be crossed till 1995, then 11 will come and the numbers will be like 11,26,41,56,.....1191 then it will be like 6,21,36.. similarly,you can observe the coming pattern and find answers thanks",
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9b7a0a098ebbaa98b37eba20f14f5d42 | i want to get admission in iit college for arospace field but i had started to study from 15th october could i do so ? plz guide me for it and some tips to get iit college and scoring topic list for me ! i will be very greatful to you ! | askiitians.com | 2021.25 | [
{
"text": "dear priya don't loose hope as 5.5 month is enough time to crack jee with good rank. you need to speedup your study but don't miss conceptual part. start pcm simultaneously. don't waste your time in confusion just start doing the things and devote as much time as you can in studies.and give emphasis on the revision. revision is very important. i have seen many students who have cracked jee with this much time preparation. just be consistent with your studies. for securing good marks in boards give two hours daily to your non pcm subjects.that will be sufficient. from now onwards manage your time properly and dont waste it. and one important thing give more emphasis on quality rather quantity i.e do one book for each subject but understand the concepts properly and give time for revision. following are the most scoring topics:- mathematics cordinate geometry-easy and scoring calculus-range, domain,limit,differential and integral calculus area under curve maxima minima algebra-series(ap,gp,hp),quadratic trigonometry physics mechanics-kinematics thermodynamics, waves,modern physics-easy and scoring electrostatics and electromagnetic induction chemistry physical chemistry :-gaseous and liquid states , chemical kinetics, chemical equilibrium, solid state, thermodynamics, mole concept inorganic chemistry:- qualitative analysis, transition elements (3d series) organic chemistry: alkanes, alkenes and alkynes, reactions of benzene all the best. akash goyal askiitiansexpert-iitd please feel free to post as many doubts on our discussion forum as you can. we are all iitians and here to help you in your iit jee preparation. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar..",
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"text": "dear priya, first thing , find out hte topics you are good at, make them your strong scoring topics, then move on to general scoring topics solve the problems, to solve problems you need better conceptual knowledge , these are inter related if you solve more number of problems you get more grip on the topic so solve as many problems you caan even though you dont understand them at that point of time.then move on to a bit tuff topics,same applies here.to complete all these thing in 6 months you will minimum require 10 hrs a dya , plan you day according to that.apply the same for all the three subjects.if you follow this you can easily crack a rank in jee. the easisest scoring topics are physics- vectors,basic kinematic topics, gravitation, thermodynamaics , heat and moderphysics chemistry- inorganic is the best if you have patience and memory power,atomic structure and chemical bonding,cant say about organic(the questions are based on all the named reactions), physical chem: chemical kinetics ,basics of electro chemistry maths : analytical geometry, and differential calculus.(maths generally depends on you) please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar.. askiitians expert suryakanth –iitb",
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"text": "please dont ask a question more than once. please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar..",
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86b7d0445efeb6e122a4b41fbc84d7a8 | explain the difference in the nature of bonding in lif and lii. | askiitians.com | 2021.21 | [
{
"text": "lif has more ionic character while lil has more covalent character. the latter is due to the greater polarizability of larger iodide ion than the fluoride ion.",
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eda6d487435f243f882ca3624b9b82c7 | what is the conjugate acid of ammonia? a n h2- b o h- c n h4+ ​ d h3 ​ o+ | askiitians.com | 2021.31 | [
{
"text": "ammonia or n h3​ is a base. it accepts a proton to give its conjugate and n h4+​. similarly, n h4+​ loses a proton to give conjugate base n h3​. hence, n h4+​ is the conjugate acid of ammonia.",
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{
"text": "ammonia or n h3​ is a base. it accepts a proton to give its conjugate and n h4+​. similarly, n h4+​ loses a proton to give conjugate base n h3​. hence, n h4+​ is the conjugate acid of ammonia..",
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"text": "ammonia or n h3​ is a base. it accepts a proton to give its conjugate and n h4+​. similarly, n h4+​ loses a proton to give conjugate base n h3​. hence, n h4+​ is the conjugate acid of ammonia",
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"text": "ammonia or n h3​ is a base. it accepts a proton to give its conjugate and n h4+​. similarly, n h4+​ loses a proton to give conjugate base n h3​. hence, n h4+​ is the conjugate acid of ammonia.,",
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{
"text": "ammonia or nh3​ is a base. it accepts a proton to give its conjugate and nh4+​.similarly, nh4+​ loses a proton to give conjugate base nh3​.hence, nh4+​ is the conjugate acid of ammonia.",
"name": "",
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{
"text": "ammonia or n h3​ is a base. it accepts a proton to give its conjugate and n h4+​. similarly, n h4+​ loses a proton to give conjugate base n h3​. hence, n h4+​ is the conjugate acid of ammonia..,",
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{
"text": "ammonia or n h3​ is a base. it accepts a proton to give its conjugate and n h4+​. similarly, n h4+​ loses a proton to give conjugate base n h3​. hence, n h4+​ is the conjugate acid of ammonia..,/",
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126eac39960f61c9f0e4a4dbcffdc08f | when a thin sheet of mica is introduced in the path of one of the interfering beams , then the fringe width will be a) increases b) decreases c) remains unchanged d) none of these | askiitians.com | 2021.31 | [
{
"text": "dear student, when a thin sheet of mica is introduced in the path of one of the interfering beams , then the fringe width will be decreases. cheers!! regards, vikas (b. tech. 4 th year thapar university)",
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72c5927bf588efdb6e19786f806ac928 | explain the law of independent assortment with a suitable example. | askiitians.com | 2021.31 | [
{
"text": "dear student, law of independent assortment is based on dihybrid cross. it states that inheritance of one character is always independent of the inheritance of other characters within the same individual. in other words, if the inheritance of more than one character is studied simultaneously, the factors or genes for each character assort out independently to the other gene or factor. a good example of independent assortment is mendelian dihybrid cross. the presence of new combinations - round green and wrinkled yellow, suggests that the genes for the shape of the seed and color of the seed are assorted independently.",
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4a83a2efd52100314febff95be21dca7 | 2. find the lcm and hcf of the following pairs of integers and verify that lcm × hcf = product of the two numbers. (i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54 | askiitians.com | 2021.43 | [
{
"text": "solutions: (i) 26 and 91 expressing 26 and 91 as product of its prime factors, we get, 26 = 2 × 13 × 1 91 = 7 × 13 × 1 therefore, lcm (26, 91) = 2 × 7 × 13 × 1 = 182 and hcf (26, 91) = 13 verification now, product of 26 and 91 = 26 × 91 = 2366 and product of lcm and hcf = 182 × 13 = 2366 hence, lcm × hcf = product of the 26 and 91. (ii) 510 and 92 expressing 510 and 92 as product of its prime factors, we get, 510 = 2 × 3 × 17 × 5 × 1 92 = 2 × 2 × 23 × 1 therefore, lcm(510, 92) = 2 × 2 × 3 × 5 × 17 × 23 = 23460 and hcf (510, 92) = 2 verification now, product of 510 and 92 = 510 × 92 = 46920 and product of lcm and hcf = 23460 × 2 = 46920 hence, lcm × hcf = product of the 510 and 92. (iii) 336 and 54 expressing 336 and 54 as product of its prime factors, we get, 336 = 2 × 2 × 2 × 2 × 7 × 3 × 1 54 = 2 × 3 × 3 × 3 × 1 therefore, lcm(336, 54) = = 3024 and hcf(336, 54) = 2×3 = 6 verification now, product of 336 and 54 = 336 × 54 = 18,144 and product of lcm and hcf = 3024 × 6 = 18,144 hence, lcm × hcf = product of the 336 and 54.",
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0db6c4c67eef03bdef6f0bb169014ba0 | there are two blocks of mass m1 and m2.cofficient of friction betweeen both the blocks and ground is u.blocks are connected by a spring.find minimum force to be applid on block m1 so that block m2 starts moving? | askiitians.com | 2021.25 | [
{
"text": "dear student, you have to apply force balance on both the blocks. minimum force you will get is um1m2/m1+m2 please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar.. askiitians expert sagar singh b.tech, iit delhi [email protected]",
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83f00f343ec82aaa11cdd145453f4307 | how many types of wave motions? | askiitians.com | 2021.43 | [
{
"text": "2types -longitudnal and transverse",
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0adf25e6c2fe860059c4937c9d5c0277 | is the electron gain enthalpy and electron affinity the same or different???? | askiitians.com | 2021.25 | [
{
"text": "electron gain enthalpy is the tendency of an gaseous atom to form anion.it is defined as the enthaply change taking place when an isolated gaseous atom accepts an e- to form monovalent gaseous anion.it may be expressed as-- a(g) + e -- ----------------> a - (g) deltah = delta eg h now this process of adding an e- can either be exothermic or endothermic which depends on element.large -ive value of e- gain enthalpy reflects the greater tendency of an atom to accept the e-.for ex- halogens have very high -ive gain enthalpies because by gaining just 1e- they can attain noble gas configuration but noble gases have large positive gain enthalpies because the additional e- goes to the next principal shell resulting in a very unstable electronic configuration. energy changes in the above process can also be represent in terms of electron affinity,which is generally taken to be equal to the --ive of the e- gain enthalpy. 1).if the energy is released on adding an e- to the gaseous atom,then e- affinity is taken as positive . 2).if the energy has to be supplied when an e- is added then e- affinity is taken as negative .",
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4924f377a88942ca34600868b42ddea9 | hello sirm/madam, can you please help me with biomolecules? is it a very important chapter from the point of view of jee. if not can i skip this chapter for jee? i mean, i have to do it for my boards. but if not necessary then i would skip detailed study | askiitians.com | 2021.21 | [
{
"text": "friend this chapter is not much importand .i think so",
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0622f4651a8b188289086119dcbfc44b | could a spatial filter improve a hetrodyne signal? | askiitians.com | 2021.43 | [
{
"text": "dear student please ask questions related to jee this is a question from principle of communications ​ regards",
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c6330614893b4acf9e4f9664186538ec | give 3 reactions to show that benzene contains three double bonds? | askiitians.com | 2021.25 | [
{
"text": "dear stella benzene contains 3 ccarbon with three double bonds. and it is aromatic and most stable due to resonance for 4n + 2 electrons. and by the resonance structure itself u can show that it has 3 pi bonds obvious. regards arun (askiitians forum expert)",
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0ce80e324d9210d59c6185f9fdd2ff97 | are there any good colleges that i can opt for if i get 200 marks in b arch. the college can be anywhere in india .... | askiitians.com | 2021.25 | [
{
"text": "dear yash, visvesvaraya national institute of technology, nagpur is a good b.arch college. best of luck..!!!! we are all iitians and here to help you in your iit jee preparation. now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar : click here to download the toolbar.. aman bansal",
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e77d55349ad17a75ad3c2f5df7663f4a | can u plz explain me how to find equation of common tangents (direct & traverse tangents )of a cirle in every cases...with an example.. thanks | askiitians.com | 2021.21 | [
{
"text": "working rule to find direct common tangent: step i: first find the point of intersection of direct common tangents say q, which divides o 1 o 2 externally in r 1 : r 2 step ii: write the equation of any line passing through q ( α,β), i.e. y- β = m (x- α )…….(1) step iii: find the two values of m, using the fact that the length of the perpendicular on (1) from the centre of one circle is equal to its radius. step iv: substitutes these values of ‘m’ in (1), the equation of the two direct common tangents can be obtained. working rule to find transverse common tangent: to fine the equations of transverse common tangent first find the point of intersection of transverse common tangents say p, which divides o 1 o 2 internally in r 1 :r 2 . then follow the step 2, 3 and 4. case ii: if the distance between the centres of the given circle is equal to sum of theirs radii. in this case both the circle will be touching each other externally. in this case two direct common tangents are real and distinct while the transverse tangents are coincident. o 1 o 2 =|r 1 +r 2 | the point of contact p can be find by using the fact that it divides o 1 o 2 internally in r 1 :r 2 . case iii: it the distance between the centres of the given circles is equal to difference of their radii i.e. |o 1 o 2 | = |r 1 -r 2 |, both the circles touches each other internally. in this case point of contact divides o 1 o 2 externally in r 1 : r 2. in this case only one common tangent exist. case iv: it the distance between the centres of two given circle is less then the sum of their radii but greater then the difference of their radii i.e. |r 1 - r 2 | < o 1 o 2 < r 1 + r 2 , in this case both the circle will intersect at two real and distinct points. in this case there exist two direct common tangents.",
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da405941021e9c61d698c42e2f3cae95 | will iit is going to be recontucted? plz tell me shall we start preparing for it? plz rply fast | askiitians.com | 2021.43 | [
{
"text": "hi , iit will not be reconducted .. you can prepare for other engineering exams ... please feel free to post as many doubts on our disucssion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best.",
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4fae6f142611b0cc040e1b7de97a3390 | image is attached . how to draw graph of this function? | askiitians.com | 2021.25 | [
{
"text": "ans: domain is given as r. function passes through origin. so, function is always increasing . from here, find the region where f’’(x) is +ve & -ve. -> concave up -> concave down thanks & regards jitender singh iit delhi askiitians faculty",
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e1bcee93a819883a6336452aef9e94d7 | tangents and normals find the points on the curve y = x^2 where the slope of the tangent is equal to the x coordinate of the point. | askiitians.com | 2021.21 | [
{
"text": "ans: hello student, please find answer to your question below let the point be (a, b) put in curve",
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5871c4fe68f70d7ca67ffd19199342be | sir i get only 50 marks in iit..................in this year with self studies,,,,,,,,,,,,without any competetive books or any other things....................... sir i want to advice from you,. how to crack this tpye exams iit or aieee. sir plzzzzzzzzzz advice me for books and how to clear bases..........for phy,che,maths | askiitians.com | 2021.25 | [
{
"text": "dear manoj, for the preparation of iit-jee, you have to clear & enhance your concepts. all you have to go through more and more concepts. whenever somebody prepares for iit-jee, just always be with three things: # first is: building the concepts, # second is: proper applications of concepts & # third is: practice. join some good coaching centre.. and do self study without loosing the concentration coz studying 2 hours with very good concentration is equals to studying 5-12 hours without any concentration. . and have a confidence in yourself. please feel free to post as many doubts on our discussion forum as you can. all the best. now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. regards vijay luxmi",
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a8dbb9ebabe285766731fa041ead0f15 | how is 10 cbse results are calculated ? | askiitians.com | 2021.39 | [
{
"text": "the newly introduced cbse grading system in class 9 and class 10 is actually a nine point scale grading system. the performance of students is assessed in nine points starting from a1 to e2.the grades are provided as below: 1. a1 –> for 91 to 100 marks ( grade point is 10) 2. a2 –> for 81 to 90 marks ( grade point is 9) 3. b1 –> for 71 to 80 marks ( grade point is 8 ) 4. b2 –> for 61 to 70 marks ( grade point is 7) 5. c1 –> for 51 to 60 marks ( grade point is 6) 6. c2 –> for 41 to 50 marks ( grade point is 5) 7. d –> for 33 to 40 marks ( grade point is 4) 8. e1 –> for 21 to 32 marks ( no grade point) 9. e2 –> for 00 to 20 marks ( no grade point) individual grades and grade points will be given for each subject. students will also get overall grade point for five subjects. this overall grade point is called cgpa (cumulative grade point average) and it can be used to calculate estimated overall percentage of marks obtained by the student. calculation of percentage for one subject : grade point x 9.5 example : suppose a student get b1 in hindi and his grade point is 8. now his estimated percentage in hindi will be 8 x 9.5 = 76 percent. calculation of overall percentage : cgpa x 9.5 example : suppose cgpa (printed on grade sheet) is 7.8. now his/her estimated overall percentage will be 7.8 x 9.5 = 74.1 percent. note : abbreviations used against result : qual – eligible for qualifying certificate, eiop – eligible for improvement of performance, niop – not eligible for improvement of performance, xxxx – upgradation of performance/additional subject n.e. – not eligible, r.w. – result withheld, r.l. – result later, ufm – unfair means, sjd – subjudice?",
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16800a08d426a397a771c54954a5a23e | got 180 in mains and 96%(all 5 subjects) general in cbse board what are options in delhi for cs or ece at reputed college can i get them at dtu or nsit. | askiitians.com | 2021.21 | [
{
"text": "cs is doubtful at dtu & nsit both but you can easily get ece in both. good luck!!! thnx.",
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"is_accepted": false
},
{
"text": "some of the best options for you to walk in. dhirubhai ambani inst. of infocom. tech, gandhinagar lovely professional university, punjab govt. college of engineering, coimbatore punjab engineering college, chandigarh college of engineering, andhra university, waltair, vishakhapatnam",
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10c12e2ae32ede9a7295dc9f3e9695e4 | solve the following equations: 10p = 100.............. | askiitians.com | 2021.25 | [
{
"text": "dear student we have to divide both sides of the equation by 10, then, we get, = 10p/10 = 100/10 = p = 10 thanks",
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{
"text": "dear student, we can solve the following expression as follows : 10p = 100 p = 100/10 p = 10 hope it helps! thank you",
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7cc901be2866dd6cdbcde6ffdeade1fd | state two main differences between globular proteins and fibrous proteins. | askiitians.com | 2021.21 | [
{
"text": "globular proteins: 1..they are cross-linked condensation polymers of acidic and basic amino acids 2. they are usually soluble inwater. fibrous proteins. 1. they are linear condensation products. 2. insoluble in water",
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cbf74d805d0459bc8c26b1881e3b3eaa | how many types of phenotypic and genotypic categories respectively are produced by genotype aabbccddeeff | askiitians.com | 2021.39 | [
{
"text": "number of genotypes is equal to 2 to the power n. here n stands for number of heterozygosity. so here in aabbccddeeff the number of gamete possible are 4 (2 2 ). they are abcdef, abcdef, abcdef, abcdef",
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d60aae5306a3903355367887b0e60504 | i am in a mess pls i don't want to repeat and waste one year and i want to pursue my career in cs or ece or it. i hv got 4324 in aieee and want to get some decent institute. pls help | askiitians.com | 2021.21 | [
{
"text": "hey apoorva, you seem to be in utter confusion and tension. need not to worry too much. there's so much left in front of you. you just need to pick the best one. see the confusion lies where is that you are not clear whether you want to go for cs ece or it, all three are real different from job , package, interest and application point of view. in general, cs deals with hardware and software relations of computers, ece deals with pure hardware gated logics and devices which communicate with each other. it on the other hand deals with harnessing information at different places using softwares and other applications. decide the once which interests you. there are good coleges available after aieee but it snever bad to go for one year more and give it a try. atleast you wont regret later that you could have given one more year and cleared jee. think positive . else i believe if you go for one more year you will get into jee, plus aieee is your game you 'll definitely have this option next year as well. all the best!!!",
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a26f17b7a4cf4b5df888859f5f0083a0 | i got 714 air in jee adv.2018.acc. to branch predictors i am getting kharagpur e.c.e , kanpur eee and c.s bhu. of these where should i join? | askiitians.com | 2021.25 | [
{
"text": "wow, contracts for such a good rank in jee adv. ece in iit kgp is a very good choice , and the electronics field has immense scope ahead including robotic tech. second option can be cs in bhu because that is very much job oriented.but if you want to go to cs kanpur is almost above iit bhu.all the very best!",
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a7e3143685e13fa7e9dbb6d352cc806b | write the structure of diisomyl borane, | askiitians.com | 2021.43 | [
{
"text": "hello student here is the structure ofdisiamylborane,",
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aee97edc793351eb13c1ffc7d3e39d6c | q. the bond which is responsible for dna strand to be antiparallel is phosphodiester bond h-bond peptide bond disulphide bond | askiitians.com | 2021.39 | [
{
"text": "hello student, please find answer to your question below: correct answer is 1. phosphodiester bond phosphodiester bond connects c3 and c5 of adjacent deoxyribose sugar due to which the two strand of dna are antiparallel",
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] |
|
7180c60b864a8303ee7295af2b7cff2e | what is dot product? | askiitians.com | 2021.43 | [
{
"text": "dot product is a product of two vectors which gives resultant as scalar",
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},
{
"text": "you can calculate the dot product of two vectors this way: a · b = |a| × |b| × cos(θ) where: |a| is the magnitude (length) of vector a |b| is the magnitude (length) of vector b θ is the angle between a and b so we multiply the length of a times the length of b, then multiply by the cosine of the angle between a and b",
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{
"text": "dot product of two vectors is defined as the product of magnitude of the two vectors and the cosine of angle between them. eg: a.b= |a|.|b| cos θ it is maximum when two vectors are two vectors are parallel or anti-parallel and is minimum when they are perpendicular to each other.",
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{
"text": "dot product of two vectors is the product of the magnitude of the two vectors and the cosine of angle between them.",
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{
"text": "it is an operation on two vectors and returs a scalar. it is given as a.b= |a||b|cos(angle b/w a and b).",
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}
] |
|
a09a8b9bf0c15fb44e2d8488a8f3c0a4 | describe how the following changes are brought about: (i) pig iron into steel. (ii) zinc oxide into metallic zinc. (iii) impure titanium into pure titanium. | askiitians.com | 2021.31 | [
{
"text": "pig iron into steel: pig iron is converted to cast iron by heating molten pig iron with scrap iron and coke using hot air blast in specially designed furnaces. cast iron is used in the manufacture of steel by mixing it with other metals. zinc oxide into metallic zinc: zinc oxide is converted to metallic zinc by reacting it with coke at 673 k. impure titanium into pure titanium: the crude titanium is heated in an evacuated vessel with iodine. the metal iodide being more covalent volatilizes.",
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{
"text": "1.pig iron into steel: pig iron is converted to cast iron by heating molten pig iron with scrap iron and coke using hot air blast in specially designed furnaces. cast iron is used in the manufacture of steel by mixing it with other metals. 2.zinc oxide into metallic zinc: zinc oxide is converted to metallic zinc by reacting it with coke at 673 k.3. impure titanium into pure titanium: the crude titanium is heated in an evacuated vessel with iodine. the metal iodide being more covalent volatilizes.",
"name": "",
"is_accepted": false
},
{
"text": "1. pig iron into steel: pig iron is converted to cast iron by heating molten pig iron with scrap iron and coke using hot air blast in specially designed furnaces. cast iron is used in the manufacture of steel by mixing it with other metals. 2. zinc oxide into metallic zinc: zinc oxide is converted to metallic zinc by reacting it with coke at 673 k.3. impure titanium into pure titanium: the crude titanium is heated in an evacuated vessel with iodine. the metal iodide being more covalent volatilizes.",
"name": "",
"is_accepted": false
}
] |
|
26fad0593d1e658d1fe12547433ff45e | sir what is the cut off mark in 2010 iit jee and is the eml is out in iit jee 2010 | askiitians.com | 2021.25 | [
{
"text": "dear student, pls wait for the merit list to be out , your rank depends on several factors",
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"is_accepted": false
}
] |
|
474cb1306f7039519ad326c2e870020d | i have 3500 rank in iit which all iits and branch shud i go for ? | askiitians.com | 2021.25 | [
{
"text": "dear student, you can check last year cutoff from the link below, http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx best of luck..!!!! plz approve the answer....!! we are all iitians and here to help you in your iit jee preparation. now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar : click here to download the toolbar.. aman bansal",
"name": "",
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},
{
"text": "institute name branch name course name iit kharagpur physics five-year m.sc. integrated courses iit patna mechanical engineering five-year m.tech. dual degree courses iit mandi computer science and engineering five-year m.tech. dual degree courses iit kanpur chemistry five-year m.sc. integrated courses iit indore computer science and engineering five-year m.tech. dual degree courses iit bombay chemistry five-year m.sc. integrated courses iit kharagpur mathematics and computing five-year m.sc. integrated courses it bhu mechanical engineering four-year b.tech. courses ism dhanbad petroleum engineering four-year b.tech. courses iit kanpur economics five-year m.sc. integrated courses iit madras biotechnology four-year b.tech. courses iit rajasthan mechanical engineering five-year m.tech. dual degree courses iit bhubaneswar mechanical engineering five-year m.tech. dual degree courses iit madras biotechnology five-year m.tech. dual degree courses iit bhubaneswar electrical engineering five-year m.tech. dual degree courses iit roorkee metallurgical and materials engineering four-year b.tech. courses iit rajasthan electrical engineering five-year m.tech. dual degree courses iit guwahati engineering physics four-year b.tech. courses iit kharagpur agricultural and food engineering with m.tech. in any of the listed specializations four-year b.tech. courses iit kharagpur exploration geophysics five-year m.sc. integrated courses iit patna computer science and engineering five-year m.tech. dual degree courses iit roorkee pulp and paper engineering four-year b.tech. courses iit ropar electrical engineering five-year m.tech. dual degree courses iit indore electrical engineering five-year m.tech. dual degree courses ism dhanbad computer science and engineering four-year b.tech. courses iit indore mechanical engineering five-year m.tech. dual degree courses iit kharagpur biotechnology and biochemical engineering four-year b.tech. courses ism dhanbad mechanical engineering four-year b.tech. courses iit roorkee biotechnology four-year b.tech. courses iit ropar mechanical engineering five-year m.tech. dual degree courses go for ism dhanbad cse or petroleum or it bhu mech",
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}
] |
|
1401b81bb2edce135e1b089e6165832e | |{×}+×|=4. how many solution are there of the equation and what are they? | askiitians.com | 2021.43 | [
{
"text": "{x} + x = ± 4 there are only three solutions x = +4 , – 4 , – 4.5 regards arun (askiitians forum expert)",
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"is_accepted": false
}
] |
|
a7e5a3e1f9c0d396044cfc199e1f3971 | the equation of the normal line of the curve y=(sinhx+3)/(coshx+2) at x=0 is | askiitians.com | 2021.39 | [
{
"text": "arun kumar iit delhi askiitians faculty",
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"is_accepted": false
}
] |
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