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5755a7e7f9a2f98c7972b95a39c4171c
hi i've scored 117 in enat (b.e.) and would like to know my approximate rank thanks in advance :)
askiitians.com
2021.21
[ { "text": "hi , cut off rank for admission in manipal institute of technology during the last three years course cut off rank 2005-06 2006-07 2007-08 b.arch 115 52 104 be-biomedical engineering 3598 6262 13708 be-biotechnology 2364 6325 6653 be-chemical engineering 3789 7371 13077 be-civil engineering 5143 9094 9819 be-computer engineering 1141 1218 2775 be-e&e engineering 1831 1964 4029 be-e&c engineering 838 1007 2370 be-i&p engineering 3589 5075 9931 be- mechanical engineering 2237 2459 3987 be-printing technology 14754 14414 22373 be-information science 1444 1636 3308 be-i&c engineering 2438 2996 9124 b e- mechotronics -- 3876 3937 askiitiians expert amit - it bhu", "name": "", "is_accepted": false } ]
bb9e4706833457d95456c61189818d4a
please solve the question provided in the attachment. ............. ....... .... .. .............
askiitians.com
2021.25
[ { "text": "potential at a point outside the charged solid sphere = kq/r (r=distance from centre) take a full positive charged solid sphere of radius 2r. find out potential (v1) at point p take a full negative charged solid sphere of radius r . find potential (v2) at point p (v2 will be -ve) v(net)=v1+v2 btw is the answer 14 ρr²/9e e means epsilon knot", "name": "", "is_accepted": false } ]
bd64c46ac5e8d91f53715ba9957b6f7b
sir i will be scoring 214 or 219 in aieee 2012. what may be my rank? which nits can i expect? nit warangal trichy surathkal allahabad bhopal..? i reside in madhya pradesh. plz guide me..
askiitians.com
2021.25
[ { "text": "as your marks are more than 50% so u will get rank around 5000 (less) . so getting admission in ur reqrd nit will be very easy", "name": "", "is_accepted": false } ]
a5c578a2c11e447a43784911666e98cf
what is thermal conductivity?
askiitians.com
2021.21
[ { "text": "thermal conductivity is the property of a material to conduct heat. it is evaluated primarily in terms of fouriers law for heat conduction", "name": "", "is_accepted": false }, { "text": "thermal conductivity is the property of a material to conduct heat. it is evaluated primarily in terms of fouriers law for heat conduction", "name": "", "is_accepted": false }, { "text": "the amount of heat per unit time per unit area that can be conducted through a plate of unit t hickness of a given material, the faces of the plate differing by one unit of temperature", "name": "", "is_accepted": false } ]
050115f31eb0745e0fbeb26eaa7e24f7
want to tell my opinion ……..and please recommend and advice me please……. i want to drop after class 10……..and i currently reading in resonance ..in class 11 program …….then after i will take admission after one year in class 11 …….then i take admission in class 12 either in resonance or allen institute for class 12 ……. then when i will in class 12 ……i prepared for ntse…olympiad ……kvpy……and after all i want to take admission in foreign institute……like mit …howard….and so many reputed collage ……,……and this is my dream of life ……. so please advise me and give me correct recommendation…….please……please
askiitians.com
2021.43
[ { "text": "if i drop after class 10 .....then it makes any problem ...to appear in olympiad and kvpy........please", "name": "", "is_accepted": false } ]
8b7ad6f229b1c5978528f5d36e474482
(vii) 10/(x+y) + 2/(x-y) = 4 15/(x+y) – 5/(x-y) = -2
askiitians.com
2021.43
[ { "text": "solution: substituting 1/x+y = m and 1/x-y = n in the given equations, we get, 10m + 2n = 4 => 10m + 2n – 4 = 0 ………………..…..(i) 15m – 5n = -2 => 15m – 5n + 2 = 0 ……………………..(ii) using cross-multiplication method, we get, m/(4-20) = n/(-60-(20)) = 1/(-50 -30) m/-16 = n/-80 = 1/-80 m/-16 = 1/-80 and n/-80 = 1/-80 m = 1/5 and n = 1 m = 1/(x+y) = 1/5 x+y = 5 …………………………………………(iii) n = 1/(x-y) = 1 x-y = 1……………………………………………(iv) adding equation (iii) and (iv), we get 2x = 6 => x = 3 …….(v) putting the value of x = 3 in equation (3), we get y = 2 hence, x = 3 and y = 2", "name": "", "is_accepted": false } ]
dab7066c1fbc6985359aa38bdf8c1d2d
i got 4000 rank in jee advanced, i intend to pursue cse in iit goa, is that a good option?
askiitians.com
2021.31
[ { "text": "no with this rank you can get many better options . do not go for iit goa", "name": "", "is_accepted": false } ]
6e6f979e0b7647d293a64da39441f2e4
find the area of loop of curve xy^2+(x+a)^2(x+2a)=0
askiitians.com
2021.31
[ { "text": "dear student question is not clear please attach an image, we will happy to help you good luck cheers", "name": "", "is_accepted": false } ]
9f129776ce696fc1c3d2a37ccb167063
i have not received icar admit card.when it dispatched
askiitians.com
2021.25
[ { "text": "i hope the query is resolved.", "name": "", "is_accepted": false } ]
7d4a826ad65feb01c7c6fe5eb0114065
please explain the mechanism and direction of force of friction in circular roads where vehicles move without banking
askiitians.com
2021.31
[ { "text": "dear argha, when a vehicle goes round a curved road, it requires some centripetal force. while rounding the curve, the wheels of the vehicle have a tendency to leave the curved path and regain the straight line path. force of friction between wheels and the roads opposes this tendency of the wheels. this force of friction therefore, acts towards the centre of circular track and provides the necessary centripetal force. fig. (1) vehicle moving on level road in fig (1), it is shown that a vehicle of weight ‘mg’ (acts vertically downwards) is moving on a level curved road. r1 and r2 are the forces of normal reaction of the road on the wheels. these are vertically upward since road is leveled. hence, r1 + r2 = mg let f1 & f2 are forces of frictions between tyre and road directed towards centre of curved road. ∴ f1 = μ r1 and f2 = μ r2 where μ is coefficient of friction between tyres and road. if ‘v’ is the velocity of the vehicle while rounding the curve, the centripetal force required is mv²/r. as this force is provided by the force of friction therefore hence the maximum velocity with which a vehicle can go round a level curve; without skidding is banking of roads in the above discussion, we see that the maximum permissible velocity with which a vehicle can go round a level curved road depends on μ, the coefficient of friction between tyres and road. the value of μ decreases when road is wet or extra smooth or tyres of the vehicle are worn out. thus force of friction is not a reliable source for providing the required centripetal force to the vehicle. especially in hilly areas where the vehicle has to move constantly along the curved track, the maximum speed at which it can run will be very low. if any attempt is made to run it at a greater speed, the vehicle is likely to skid and go out of track. in order that the vehicle can go round the curved track at a reasonable speed without skidding, the sufficient centripetal force is managed for it by raising the outer edge of the track a little above the inner edge. it is called banking of the circular track or banking of roads . consider a vehicle of weight ‘mg’ moving round a curved path of radius ‘r’ with speed ‘v’ on a road banked through angle θ. if oa is banked road and ox is horizontal line, then ∠aox = θ is called angle of banking of road . refer fig (2) fig.(2) vehicle moving on banked road following forces are involved: the weight ‘mg’ acting vertically downwards the reaction ‘r’ of the ground to the vehicle acting along normal to the banked road oa in upward direction the vertical component r.cos θ of r will balance the weight of the vehicle. the horizontal component r.sin θ of r will provide necessary centripetal force to the vehicle. thus, r.cos θ = mg ….(1) and on dividing equation (1) & equation (2),we get cracking iit just got more exciting,it s not just all about getting assistance from iitians, alongside target achievement and rewards play an important role. askiitians has it all for you, wherein you get assistance only from iitians for your preparation and win by answering queries in the discussion forums. reward points 5 + 15 for all those who upload their pic and download the askiitians toolbar, just a simple to download the toolbar…. so start the brain storming…. become a leader with elite expert league askiitians thanks aman bansal askiitian expert", "name": "", "is_accepted": false } ]
7469e99fa5a2617687e98d48ecd3a0a4
can those ppl who had personal prbs on may 1 attend aieee on may 11?????
askiitians.com
2021.31
[ { "text": "hi, i am afraid to say, that personal problems are not considered by cbse. only those, who had to appear for both aieee & aipmt 2011 , are allowed to take aieee exam on the 8th of may.", "name": "", "is_accepted": false } ]
7c98234da22f18c5d7e3927348a0d39a
a compound forms hexagonal close packed structure. what is the total number of voids in 0.5 mol of it? how many of these are tetrahedral voids?
askiitians.com
2021.21
[ { "text": "a compound forms hexagonal close packed structure.", "name": "", "is_accepted": false } ]
8339d36ddd23af07a3fdf08ae49376fc
calculate the position of the planet of 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force
askiitians.com
2021.21
[ { "text": "hiii the gravitation force acting between two bodies is given by f = g m1m2/d 2 so, let us assume the distance between 10^20 kg and 10^5 kg mass be d then distance between 10^24 kg and 10^5 kg mass wil be equal to 6000-d, apply gravitational force formula on both you will get the value of d .", "name": "", "is_accepted": false } ]
cf687e5ba5f8af1d21487c3368e65a4a
the period of thin magnet is 4 sec. if it is divided into two equal halves then the time period of each part will be (a) 4 sec (b) 1 sec (c) 2 sec (d) 8 sec
askiitians.com
2021.21
[ { "text": "as we discussed in concept physical pendulum - any rigid body suspended from a fixed support constitute a physical pendulum. - wherein e.g. a circular ring suspended on a nail in a wall etc. if it is divided into two equal halves the time period will be half t = 2sec", "name": "", "is_accepted": false }, { "text": "dear stduent please refer https://www.askiitians.com/iit-jee-magnetism/assignment-and-questions/ ////////////////", "name": "", "is_accepted": false } ]
b5e41ceba835f8928b08bcbae50fe70f
i couldn`t get it.we use sign convention in deriving formulae.then why again we should use sign convention when solving numericals?
askiitians.com
2021.39
[ { "text": "in the mirror and lens formula that we use, v,u and f is are not distances (of image, object and focus resp.)they are coordinateshence, in the derivation when you take distances, you have to take modulus of the coordinatesand in the formula, put coordinates", "name": "", "is_accepted": false } ]
a0cfc16d34118b0a1e57829088337c65
4ab5 is a four digit number divisible by 55 where a, b are unknown digits. then b – a is :
askiitians.com
2021.31
[ { "text": "hii it is very easy as he number given is a multiple of 11*5 so it must follow he divsibility rule of 11 and 5 use that and you will get the relation in a and b which will give you answer", "name": "", "is_accepted": false }, { "text": "55=5*11. we know in the no. 4ab5 last digit is 5 so its divisible by 5. its divisible by 11 also if its divisible by 11 then the sum of its odd and even terms must be divisible by 11. 4+b-(a+5)=a no. divisible by 11. b-a=(a no. divisible by 11 ) +1. now since b and a are single digit no. so 0 is the only no. which satisfies the equation. so the answer is 1.", "name": "", "is_accepted": false } ]
fec8c3dac3e00d377b64a23fb310767a
which ml khanna book is better: iit mathematics or objective mathematics ?
askiitians.com
2021.25
[ { "text": "@ nirm iit mathematics book is the better one for jee main as well as advanced . for objective question u can opt for objective mathematics by r d sharma otherwis etake last 37 years papers of jee by arihant publication . all the best ..", "name": "", "is_accepted": false } ]
e1b8361456c5a179c7b876d761869cf8
if n c 12 = n c 8 then what is the value of n? please answer this with brief explination.
askiitians.com
2021.43
[ { "text": "dear student the formula for ‘n choose k’ is n!/(n-k)!k! therefore we have n!/(n-8)!8! = n!/(n-12)!12! (n-8)!8! = (n-12)!12! ….1 now there are 2 methods to proceed- guess and check and algebraic i will first present the guess and check method to make equation 1 true we must try to equate n-8 to 12 and n-12 to 8 now we have 2 equations n – 8 = 12 and n – 12 = 8 which give us n = 20 now the algebraic approach (n – 8)!8! = (n – 12)!12! (n – 8)! = (n – 12)! x 12 x 11 x 10 x 9 (n – 8)! / (n – 12)! = 12 x 11 x 10 x 9 on replacing n – 8 by p, we get p! / (p – 4)! = 12 x 11 x 10 x 9 p x (p-1) x (p-2) x (p-3) = 12 x 11 x 10 x 9 therefore p = 12 and n – 8 = p n – 8 = 12 hence n = 20 regards vedant", "name": "", "is_accepted": false }, { "text": "whenever you see the expression to be then either r = s or r + s = n here r = 12 and s = 8 clearly r is not equal to s so n = r + s implies n = 12 + 8 implies n = 20 (ans) hope it helps! p.s – this is the shortest method in which you can do these kinds of sums rather than breaking them into factorials on both sides.", "name": "", "is_accepted": false }, { "text": "whenever you see the expression to be then either r = s or r + s = n here r = 12 and s = 8 clearly r is not equal to s so n = r + s implies n = 12 + 8 implies n = 20 (ans)", "name": "", "is_accepted": false } ]
9dfdec2f88866ae640cbc2e18c85e8dc
q. what are the main sources of carbon?
askiitians.com
2021.31
[ { "text": "hello student, please find answer to your question below: carbon is a versatile element and found everywhere, but its main sources are air, water, fossil fuel, and rocks etc.", "name": "", "is_accepted": false }, { "text": "living form is the main source of carbon. all living forms on earth are made of carbon.", "name": "", "is_accepted": false } ]
706ad0ed908c15b0e5418a17c8fcb553
what are carbohydrates ???????? ???????????????????????? ???????????????????? ??????
askiitians.com
2021.39
[ { "text": "dear student carbohydratesare the sugars, starches and fibers found in fruits, grains, vegetables and milk products. though often maligned in trendy diets,carbohydrates— one of the basic food groups — are important to a healthy life", "name": "", "is_accepted": false }, { "text": "carbohydrates represent one of the three main classes of foods. carbs are a source of energy; they are mainly sugars and starches that the body breaks down into glucose that the body uses to feed its.", "name": "", "is_accepted": false } ]
76dc5399f55bef3f23739605bac6bcfd
add without using number line: (a) 11 + (–7) (b) (–13) + (+18) (c) (–10) + (+19) yhx,kyhk,tktlyu8l;8ypy
askiitians.com
2021.25
[ { "text": "dear student (a) 11 + (-7) = 4 (b) (-13) + (+18) = 5 (c) (-10) + (+19) = 9 thanks", "name": "", "is_accepted": false } ]
c83480b8d3ae37a9564ac32e98b96b47
in general, liquids expand\_\_\_\_\_\_\_\_\_\_times than solids
askiitians.com
2021.43
[ { "text": "in general , liquids expand slightly more than solids.", "name": "", "is_accepted": false } ]
11999dd7f5dda4602f47b07e2e4f3b1e
if a2 sec 2 θ - b2 tan2 θ =c2 , prove that = ± √(c^2-a^2 )/√(c^2-b^2 )
askiitians.com
2021.43
[ { "text": "dear alok you have not provided the lhs of part which is to be proved. please check and respost it. regards arun (askiitians forum expert)", "name": "", "is_accepted": false } ]
421549c3ff58dcf665e3116d2d17c5d9
solve the following equations. t/5 = 10 solve the following equations. t/5 = 10
askiitians.com
2021.31
[ { "text": "dear student t/5=10 t = 10 × 5 t=50 thanks", "name": "", "is_accepted": false } ]
6f2bbc111daf0c5ecb01955c3797e3f0
in a year, seema earns ₹ 1,50,000 and saves ₹ 50,000. find the ratio of money that she saves to the money she spends.
askiitians.com
2021.25
[ { "text": "dear student money earned by seema=₹150000 money saved by her =₹50000 money spent by her =₹150000 -₹50000 =₹100000 ratio of money saved to money spent = 50000 / 100000 = 5 / 10 = 1/2 thanks", "name": "", "is_accepted": false } ]
93fe41096ae920ad12408db2392cf758
i am in love why..? is there really hormones only responsible. then what about my feelings?
askiitians.com
2021.25
[ { "text": "dear student lust is driven by the desire for sexual gratification. the evolutionary basis for this stems from our need to reproduce, a need shared among all living things. through reproduction, organisms pass on their genes, and thus contribute to the perpetuation of their species. the hypothalamus of the brain plays a big role in this, stimulating the production of the sex hormones testosterone and estrogen from the testes and ovaries . while these chemicals are often stereotyped as being “male” and “female,” respectively, both play a role in men and women. as it turns out, testosterone increases libido in just about everyone. the effects are less pronounced with estrogen, but some women report being more sexually motivated around the time they ovulate, when estrogen levels are highest.", "name": "", "is_accepted": false } ]
f22b40823bc40f4d961411b19b7c5ac7
40. the mode of the numbers 2, 3, 4, 4. 3, 5, 3, 6 is \_\_\_\_\_\_ .
askiitians.com
2021.43
[ { "text": "answer: explaination: 3", "name": "", "is_accepted": false } ]
a5fb30e1ce7b5e8c5735e9590427d208
my parents are bringing too much pressure on me though i am performing as usual. i feel to leave iit.
askiitians.com
2021.31
[ { "text": "dear student, usually parents are worried abt your future and you have to be confident and dont loose hope. just focus on concepts and increase your study hours and make your parents feel proud by clearing jee with a good ran... please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar.. askiitians expert sagar singh b.tech, iit delhi [email protected]", "name": "", "is_accepted": false }, { "text": "thankx", "name": "", "is_accepted": false } ]
6ccc857dd6850994b2ea9e1551155c01
what is the mrameanof the term cyclosis or cytoplasmic streaming?
askiitians.com
2021.31
[ { "text": "it is circulation of protoplasm within the cell.the motion transports nutrients, proteins, and organelles withincells.", "name": "", "is_accepted": false } ]
8a336b404d849184fffccbfb5f8d5067
hi my sc cat rank in 72 please guide me which branch to select
askiitians.com
2021.25
[ { "text": "you can easily get cse at good iits,so good with cse at iits like delhi, bombay, kanput, karagpur etc. sher mohammad faculty askiitans b.tech, iit delhi", "name": "", "is_accepted": false }, { "text": "i am confused between electical and computer science which one to choose first", "name": "", "is_accepted": false }, { "text": "cse is good.", "name": "", "is_accepted": false } ]
dde9258ed918058d9b8ed03489ccbbf7
what rank should i have in aieee 2011 to get in dce(not from delhi) cs branch general category
askiitians.com
2021.39
[ { "text": "dear student, you have to be in top 3000.....", "name": "", "is_accepted": false } ]
9fc8929cc230f4b4b510882f3110a17c
can anyone tell me how many seats are there in bits? and upto what rank would i get cs in bits, pilani
askiitians.com
2021.25
[ { "text": "candidates compete for a total of 2000 admission seats (800 in pilani campus, 600 in goa campus and 600 in hyderabad campus) thorugh bitsat every year. the cut off bit score for cs at pilani is arnd 350 whersas at goa campus cs its arnd 330 -- regards ramesh", "name": "", "is_accepted": false } ]
185e404f0a4f9a1e48f869839b767913
sir i m getting cs in ism for dual degree and cs in nit warangal . which is better option
askiitians.com
2021.25
[ { "text": "go for cs at nit warangal followed by second option.. good luck.", "name": "", "is_accepted": false }, { "text": "dear aman, give priority to warangal and if you cna compare and contrast some more renowned institutions, then i may suggest you here to add these name too in your list – jjtu, rajasthan,............................banasthali university, banasthali,...........................lovely professional university, phagwara etc.", "name": "", "is_accepted": false } ]
22e37ed1578cfe5fa3008622a8549efb
hello sir/mam iam st student i have scored 130 in 2010 iit.che 60 mat 68 phy 02.am i get seat in iit.please reply
askiitians.com
2021.25
[ { "text": "hi , please click the link given below for the cut off: http://www.askiitians.com/iit-jee-2010-cut-offs.aspx and for opening and closing ranks .. please click here : http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx all the best !! regards vijay luxmi", "name": "", "is_accepted": false } ]
07b134e1d439568802b6e886ce73881f
a charged particle of mass m and change q is released form rest in an electric field of constant magnitude e .the kinetic energy of the particle after time t is
askiitians.com
2021.25
[ { "text": "according to the question, force= q*e so acceleration is (q*e)/m after time t velocity is (q*e*t)/m so kinetic energy is 1/2*m*((q*e*t)/m)^2=1/2*((q*e*t)^2)/m thanks", "name": "", "is_accepted": false } ]
a5f319d57a1b1b22845d5b7ce6d5693a
sir i have secured 137 rank in cusat , 3060 in uptu and 38513 in aieee i am not ble to decide what college to joint some are telling cusat will be better and some are saying to join uptu colleges such as jss noida, kamla nit, mmm college, akgec , kiet. sir plz tell what will be more appropriate
askiitians.com
2021.25
[ { "text": "you should try to get an nit under your home state quota. best of luck.", "name": "", "is_accepted": false }, { "text": "sir i am a citizen of uttar pradesh and under its state quota there is only 1 nit and that to closes at 10000. so plz tell what college i should joint.................. i am thinking of cusat with electronics and communication sir plz tell whether it will be appropriate or not", "name": "", "is_accepted": false } ]
bb77dafdc244de561e71faf51432c1dc
plz tel me which r d most scoring topics in jee????
askiitians.com
2021.39
[ { "text": "wht subjects if u lag in learn tht subjects, if any interval between preparations physics basics must be perfect", "name": "", "is_accepted": false } ]
4296867ff8f69dfa8bc5e1946338001d
please send me method of extraction of tin from casseterite notes
askiitians.com
2021.43
[ { "text": "he cassiterite is then mixed with approximately equal volumes of charcoal dust and a mixture of sodium and potassium carbonates (as a flux). the crucible used must have a lid to prevent atmospheric oxygen from forming excessive carbon dioxide. during smelting, the flux helps to remove impurities from the metal being formed. the overall reaction (upon heating) is: sno2 (s) + 2 c (s) --> sn (l) + 2 co (g) some write this as: sno2 (s) + c (s) --> sn (l) + co2 (g) the liquid tin is drained or poured into molds.", "name": "", "is_accepted": false } ]
d82ad15b02b52d1b67e461185cd913ca
mathematics and computing at iit delhi vs aerospace at iit bombay.......????which is good ????which is having good placements
askiitians.com
2021.25
[ { "text": "for placement statistics please visit respectively websites. both are good branches as well as colleges. i will suggest you to look for your interest. thanks", "name": "", "is_accepted": false } ]
2c652914e2b3319e401dd4c9eb9f68ed
how do i improve my marks in physics???? i have not scored upto the mark in class test...i got 15 marks out of 80...i am giving jee in 2012...please help me out!!! suggest me the books or the hours i need to study physics!!
askiitians.com
2021.31
[ { "text": "dear student, physics plays a very crucial role in deciding the rank... you shud go thru dc pandey and hc verma to make your concepts pretty clear... please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar.. askiitians expert sagar singh b.tech, iit delhi", "name": "", "is_accepted": false } ]
104ddca2ccc6d03c9f1e42447e9bb23d
dear sir i am interested in b tech chemical eng course and i am interested to do organic chemistry m tech. is it correct way or need youy advice that what is correct way to select couses. pls advice. thx
askiitians.com
2021.31
[ { "text": "chemical engineering if pursued sincerely is highly profitable and the scope in india is huge. we are the top paid when compared with the pass outs of other branches and lately there has been a boom in this field and placements are sure. but first you should know what chemical engineering is because students have a misconception about it. a common fear that the work conditions of chemical engineers are hazardous is a fluke. chemical engineers work in safe environment and direct contact with chemicals is minimum. chemical engineers in india recruited in many sectors. some being : petroleum and petrochemicals, paper, fertilizers, rubber, pharmaceuticals, organic and inorganic industries etc. petroleum and the pharmaceutical sectors are booming and quite in demand. some of the major companies are listed below : in petroleum and gases reliance industries essar oils gujarat oils ongc bpcl fertilizers indo gulf fertilizers fertilizers and chemicals travancore ltd coromandel fertilizers some other companies being : bengal chemical and pharmaceuticals orissa drugs and chemical ltd indian drugs and pharmaceutical ltd (idpl) bihar drugs and organic chemical ltd naramada colours pvt ltd honeywell indian drugs and pharmaceuticals ltd aditya birla chemicals arati industries ltd l&t many students also get recruited to the it sector. a student desiring such option must additionally have knowledge of any of the computer languages. some of the companies being tcs, infosys, wipro, cts etc. but it is always best to go for core companies. the fact i understood is that one's profile should be good. every student undergoes internship during their course and for you to be outstanding and to get an upper hand in placements it is always better to do internship abroad during your engineering course . you can also go for higher studies to make your career firm. the undergraduates can take m.tech or ms in various fields and courses are offered in various iit's and nit's in india. the topics being : environmental engineering, piping and design, nanotechnology, metallurgy, chemical engineering etc. the students can also take up research options in their interested fields and earn while pursuing their course. you need to write gate to get into iit's and nit's. the companies these days consider gate score too for recruitment and therefore preparing for gate is very important. you can also do ms in india and abroad as well. the students can take up research options in their interested field and earn while pursuing their course. the basic criteria to do ms abroad is write graduate record examination (gre) and get a good score. next is english proficiency tests such as ielts, toefl etc. get atleast 6.5 out 9 to get admissions in college abroad. to do ms in us or uk is too high its not easy to extend your visa after your course. but you can also do post graduation cheaply but with more value . thanks & regards rinkoo gupta askiitiansfaculty", "name": "", "is_accepted": false } ]
439c12ef4fe414695222f71cc3622a97
sir do jee mains or the sate rank given by the state,count for admission in the nit of the state of residence?
askiitians.com
2021.21
[ { "text": "you can go to the homepage of askiitians.com . there you will find out the rank and college predictor which you can use for finding out the rank, the branch and college options available for you after filling out your marks or rank and other credentials. ------------------------------x--------------------------", "name": "", "is_accepted": false } ]
58825d207b8dc60548468b84f9e38b7f
why is a whiptail lizard referred to as parthogenetic?
askiitians.com
2021.39
[ { "text": "whiptail lizard is parthenogenetic because , an unfertilized egg develops into a new individual. this process of reproduction without fertilization is called parthenogenesis.", "name": "", "is_accepted": false } ]
4783166a9d3c9edf90f622387544f46d
sir, how can i predict whether a reaction will undergo an sn2 mechanism or e2 mechanism?
askiitians.com
2021.31
[ { "text": "hi, the e2 mechanism is analogous to the sn2 . and both competes . usually in most of the cases we get both the substituition as well as elimination product . the ratio of e : s varies , which depends upon certain factors normally all nuclephiles are base . but when we have good nucleophiles sn2 is favoured . &when we have strong bases e2 is favoured. it also depends upon how acidic the h , which is attatched to the adjacent c , is. if it is more acidic than obviously we will get a favoured ellimination product.", "name": "", "is_accepted": false } ]
9f3487327e1ed814e5376f23d8f58b0e
suppose a vertical plane mirror and a object which is placed at a distance of 4 m from the mirror. if we start moving the mirror with a velocity of 2m/s and also start moving the object at 3m/s. then how should i can find the velocity at which the image moves and also the direction of motion of the image?
askiitians.com
2021.39
[ { "text": "what is the direction of motion of the mirror and object? are they moving towards each other.? in general when the mirror is moving with velocity v towards stationary object, the image moves with velocity 2v towards it. direction can be found out by a simple logic, if the object is moving towards the mirror then image also moves towards mirror and vise versa", "name": "", "is_accepted": false }, { "text": "both the mirror and the object are moving in the same direction.", "name": "", "is_accepted": false } ]
011ee62e3afdc2cbadf7852d545d4440
the focal length of converging lens is measured for violet, green and red colours. it is respectively f v , f g , f r , we will get (a) f v = fg (b) f g > f r (c) f v < f r (d) f v > f r
askiitians.com
2021.21
[ { "text": "(c) according to cauchy relation .''. red light has wavelength greater than violet light. therefore focal length of lens for red is greater than for violet. (f r > f v )", "name": "", "is_accepted": false }, { "text": "fv>fg bcz f is inversely proportional to lemda we know wavelength of red is max ..............................................", "name": "", "is_accepted": false } ]
f3f0059acc20735049849c402b6e2be1
kinetic energy of a body decreases by 19%. what is the percentage decrease in linear momentum? (a) 15% (b) 5% (c) 20% (d) 10%
askiitians.com
2021.25
[ { "text": "", "name": "", "is_accepted": false }, { "text": "simply answer is 10%", "name": "", "is_accepted": false } ]
abd519f8eeb73ccf216db0756c662503
sir i got 80 marks in jee mains 2014.i got 98.16%in kerala hse examination. what would be my rank? is there any chance to get admission in nits through general category?
askiitians.com
2021.39
[ { "text": "you can predict your rank in jee mains with the help of the following provided links. compare your rank with previous year cut-off of various institutes. this will give you an idea of the various branches in different institutes open for you. 1.http://blog.askiitians.com/calculation-percentile-normalization-marks-composite-score/ 2.http://www.askiitians.com/iit-jee/main/rank-predictor.html thanks and regards apoorva arora iit roorkee askiitians faculty", "name": "", "is_accepted": false } ]
7be30479b97cc805c7e7088c28e1faa4
i would like to know about nit calicut - branch production enginnering , is there good scope for production eng
askiitians.com
2021.21
[ { "text": "dear bala, nit calicut is among the best collehes in india. and production engineering is a good branch. best of luck plz approve the answer...!!!! cracking iit just got more exciting,it’s not just all about getting assistance from iitians, alongside target achievement and rewards play an important role. askiitians has it all for you, wherein you get assistance only from iitians for your preparation and win exciting gifts by answering queries in the discussion forums. reward points 5 + 15 for all those who upload their pic and download the askiitians toolbar, just a simple click here to download the toolbar…. so start the brain storming…. become a leader with elite expert league askiitians thanks aman bansal askiitian expert", "name": "", "is_accepted": false } ]
a8d872be02e53ad44facffc1257a56ee
what i can do what i have to just waiting for a chance how much amout needed live in risod - washim - maharshtra
askiitians.com
2021.31
[ { "text": "dear yash, the initial investmen for setting up new business depends on many factoors such as type of business, scale of business, etc, etc cracking iit just got more exciting,it s not just all about getting assistance from iitians, alongside target achievement and rewards play an important role. askiitians has it all for you, wherein you get assistance only from iitians for your preparation and win by answering queries in the discussion forums. http://www.askiitians.com/packages/packages.aspx so start the brain storming…. become a leader with elite expert league askiitians thanks aman bansal askiitian expert", "name": "", "is_accepted": false } ]
6db2e39634c437c2b6346d1db08f0e90
two convex lenses with focal length f are kept apart from each other at a distance of 3f. what will be the object distance so that the image formed by the lenses are real?
askiitians.com
2021.31
[ { "text": "central length = f cm picture distance = v cm from the lens recipe, 1/v-1/u = 1/f 1/u = (f-v)/fv u = fv/(f-v) as v = 3f  u = 3f2/(- 2f)  u = - 3f/2", "name": "", "is_accepted": false } ]
c813613874b8c566754e9ec15de86f8d
in sterioisomerism there is ma 2 xy type, in that a is neutral ligand and x,yare anionic ligand. eg for this is [ptnh 3 cl(py) 2 ]. ---------- in this eg according to the rule there is one neutral ligand and two anionic ligand, but nh 3 , (py) 2 are neutral ligand and only one anionic ligand that is cl. then can u pls explain how this eg being apt for this kind of sterio isomerism. can u give another eg for this????? pls give the ans immediately.......
askiitians.com
2021.25
[ { "text": "its not a necessary condition that they need to be anions. so yes they will show stereoisomerism of this type.", "name": "", "is_accepted": false } ]
75ffcfd1a6501da1bbdc66010a5d72d5
sir..i got barch all india rank-35478 and obc category rank- 8556, state(tamilnadu) rank- 1392 and obc category rank- 724.. wil i get barch in any good college??? please reply thanks.
askiitians.com
2021.31
[ { "text": "hi , for the last year cut off in architecture, please click the link : www.askiitians.com/aieee-counselling/architecture-counselling.aspx thanks and all the best !!!!", "name": "", "is_accepted": false } ]
687346083056ba32e565e4e6a06ef01e
how does angle of incidence vary with angle of deviation?
askiitians.com
2021.39
[ { "text": "the formula that you gave, namely (1) ..... n = { sin[(a + d)/2] }/sin(a/2) is true only for the angle of incidence θ that gives an angle of refraction α such that α = a/2 , so that the light ray passes symmetricall through the glass prism. in that case (when the light ray passes symmetricall through the prism), (1) holds true and the angle d in (1) is called the angle of minimum deviation. perhaps it would be better to denote this angle by dmin in order not to confuse it with the general angle of deviation d which is not equal to dmin. in that case, we can rewrite (1) as (2) ..... n = { sin[(a + dmin)/2] }/sin(a/2) for a given glass prism with a particular value of the index of refraction n and a specific value of the prism angle a, there is only one minimum angle of deviation dmin. that is why n in (2) is a constant. but the general angle of deviation d is in general different from the minimum angle of deviation dmin. that occurs when the angle of incidence θ makes the light ray pass through the prism unsymmetrically so that the angle of refraction α is no longer equal to a/2. and that is also the angle referred to (not dmin) in yourphysics book, the angle of deviation d that first decreases until it reaches a minimum value (that is now dmin) and then starts increasing afterwards, when the angle of incidence is increased first from a small value. now, if you want to understand why the angle of deviation d (not dmin) first decreases and then increases only later, that has something to do with the double refraction encountered by light in passing through the glass prism. the first refraction (from air to glass) is from a lighter to a denser medium, n1 < n2 , so that θ1 > θ2 in the law of refraction, and light is bent towards the normal, away from the initial direction of incident light. but as`θ1 increases, θ2 also increases, and that brings the refracted light towards the initial direction of the incident light. the second refraction (from glass back to air) is from a denser to a lighter medium, n1 > n2 , so that θ1 < θ2 in the law of refraction, and light is bent away from the normal, also away from the initial direction of incident light. as`θ1 increases, θ2 also increases, and that brings the refracted light farther away from the initial direction of the incident light. starting from a small value of angle of incidence, the change towards the initial direction of the incident light in the first refraction is greater than the change farther away from the initial direction of the incident light in the second refraction, so that theangle of deviation d decreases at first. but after reaching d = dmin, the change towards the initial direction of the incident light in the first refraction becomes smaller than the change farther away from the initial direction of the incident light in the second refraction, so that the angle of deviation d finally increases.", "name": "", "is_accepted": false } ]
c47ac61a3a6329a960dcf24cd1545a3b
by what the speed of a moving body is presented graphically? a simple pendulum takes 32s to complete 20 oscillations. what is the time period of the pendulum a car moves with a speed of 40km/h for 15min and then with a speed of 60km/h for the next 15mins. what is the total distance covered by the car what is the difference between non-uniform motion and uniform motion
askiitians.com
2021.31
[ { "text": "time taken to complete 20 oscillations = 32s time taken to complete one oscillations = ? time period = time taken/ no of oscillations = 32/20 = 1.6s ans = 1.6", "name": "", "is_accepted": false } ]
04ce4063af689f9b37eb5b297412ee16
a graph is plotted between displacement vs time then find the impulse for the each cycle
askiitians.com
2021.43
[ { "text": "dear student there is no graph attached. please check and repost it. i wil be happy to help you. regards arun", "name": "", "is_accepted": false }, { "text": "dear student there is no graph attached. please check and repost it. i wil be happy to help you. regards ekaaant", "name": "", "is_accepted": false } ]
07bdefc8b0034ec720d5ee8e4f477754
why 7/8 is taken in the formula for calculating magnetic length i.,e 2l=​(7/8)×geometric length?
askiitians.com
2021.39
[ { "text": "dear student generally 5/6 is used. please check and repost it. regards arun (askiitians forum expert)", "name": "", "is_accepted": false } ]
f4f438120cfc5775c93381beb797b89b
in ∆oab, e is the mid point of ab and f is a point on oa such that of=2fa.if c is the point of intersection of oe and bf, then find the ratios oc:ce and bc:cf are
askiitians.com
2021.25
[ { "text": "p = 0.5λ b + a /(λ +1) p = yod y/3 = 1/(λ+1) λ/(2(λ+1) = 2/3 y 0.5λ (1/(λ+1) ) = 2/3 * 3/(λ+1) λ = 4 y = 3/5 op = 3/5 od", "name": "", "is_accepted": false } ]
ef884d08e4abf82a09222e9158267d42
1. the concept of grouping elements into triads was given by ……… . 2. mendeleev’s basis for the periodic table is ……… . 3. the basis for modern periodic table is ……… . 4. (a) metallic character ……… down the group. (b) atomic size ……… along the period. (c) electronegative character ……… down the group. 5. isotopes belong to the same ……… in the periodic table. 6. halogens belong to group ……… of the periodic table. 7. an element having electronic configuration (2, 8, 2) belongs to the ……… group. 8. atoms of different elements with the same number of occupied shells are placed in the same ……… . 9. valency of elements ……… and then ……… as we move across the period while it remains the same down the group. 10. non-metals are located on the ……… side of the periodic table.
askiitians.com
2021.39
[ { "text": "1. dobereiner 2. atomic mass 3. atomic no. 4. (a) increases (b) decreases (c) decreases 5. position 6. 17 7. 12th 8. period 9. increases, decreases 10. right", "name": "", "is_accepted": false } ]
2f2e947ad635428a9a07d8ab3c447b15
the catalytic decomposition of n 2 o by gold at 900 0 c and at an initial pressure of 200mm is 50% complete in 53 minute and 73% complete in 100 minutes. what is the order of reaction. i know its first order reaction. but how can we calculate . it may also second order. plz explain.
askiitians.com
2021.31
[ { "text": "calculate k for both the observations and then if k is same for both the exp acc to first order then it will be first order. orelse calsulate it with other equations for k and find out the order", "name": "", "is_accepted": false } ]
7873401f1fe0c34ad9b2dfc6c7eca8e6
hi, i am agarwal and i want to join the online test series. is it free at your website or i have to pay for it?? plz reply asap.
askiitians.com
2021.31
[ { "text": "hi, there is free online test for students. if you are askiitians registered user then you can find the the best solutions and papers with your packages.", "name": "", "is_accepted": false } ]
7977765664241529ddbbd863e97608b4
no of solutions of (6-x)^4 +(8-x)^4=32
askiitians.com
2021.39
[ { "text": "hello student, please find the answer to your question below given (6-x)^4 +(8-x)^4=32........(1) let y am of 6-x and 8-x =7-x so eqn(1) becomes (y+1) 4 +(y-1) 4 =32 on simplifying we get y 4 +6y 2 -15=0 let y 2 =u we get u 2 +6u-15=0 we get u=-3 2 so y=i ,-i ,- , so x=7+ ,7- ,7+ ,7- hence there are 4 solutions", "name": "", "is_accepted": false } ]
b47c9226cd97c079d1da8911c063162d
sir, i need to get into philani bits how can i prepare?
askiitians.com
2021.21
[ { "text": "dear student, first of all you should be aware about the syllabus, pattern for bitsat-2016. seciondly you should also go through its previous year’s paper to know about its level. try to work on your weak areas/subject. and solve more number of questions to clear your conceptual knowledge. thanks.", "name": "", "is_accepted": false } ]
aba8dc89bc78bf926ff0e1302b6cddf6
protective resemblance of animal• with their environment and background •• ( 1) batesian (2 } mimesis (3} mullerian mimicry (4) mimicry.
askiitians.com
2021.39
[ { "text": "ans. (4). best whishes.", "name": "", "is_accepted": false } ]
7f04d5f3270b9b79040b797e6ca5c821
respected, i hope my the image is clear to you and i will get the solution soon. thank you.
askiitians.com
2021.39
[ { "text": "dear,student the answer to this question must be (b). please approve to get detailed solution to this problem.", "name": "", "is_accepted": false }, { "text": "dear student -1/xy + logy = c ydx +xdy + x^2ydy =0 dxy/x^2y^2 + 1/y dy = 0 -1/xy + log y =c ans will be option b", "name": "", "is_accepted": false } ]
c6a7f234110a491611d69469a7b8af20
do you know of any activity which may be polluting this water source?
askiitians.com
2021.31
[ { "text": "dear student yes, the water is polluted by (a) sewage (b) dumping waste in river, (c) factory waste etc. thanks", "name": "", "is_accepted": false } ]
c13fc036e8f3e58abf1e79ef371616f4
most scoring topics for mathematics in iit jee - aieee ?
askiitians.com
2021.31
[ { "text": "i think most scoring topics in mathematics are vectors , trigonometry , co-ordinate geometry- straight lines, circle, parabola, ellipse, hyperbola | 3 d - straight line in space, plane.", "name": "", "is_accepted": false }, { "text": "the following sub topics have high probability of appearing in the exam. :2d geametry – locus problems on circles/straight lines, 2d geometry – conic sections:parabola, ellipse, 3d geometry – straight line in symmetric form, vectors – vector product, algebra – complex numbers:geometry, algebra – binomial theoram:binomial coeff, trigonometry – properties of triangle, trigonometry – inverse trigonometric functions, differential calculus – applications of derivatives montonicity, integral calculus – differential equations evalution", "name": "", "is_accepted": false } ]
863745d2b9f1e955067d673230bf3958
if (1/ab)+(1/bc)+(1/ac)=1 and a+b+c=1 find value of (1/(1+a+ab))+(1+(1+b+bc))+(1+(1+c+ac))
askiitians.com
2021.39
[ { "text": "given that 1/ab+1/bc+1/ca =1 and a+b+c=1.1/ab+1/bc+1/ca=1=>(a+b+c)/abc =1 abc=1=>bc=1/a,c=1/ab,ac=1/b.(1/1+a+ab)+(1/1+b+bc)+(1/1+c+ac)=(1/1+a+ab)+(1/1+b+1/a)+(1/1+1/ab+1/b)=(1/1+a+ab)+(a/1+a+ab)+(ab/1+a+ab)=(1+a+ab)/(1+a+ab)=1", "name": "", "is_accepted": false } ]
3065570bf84b93a57bc0f8831817a444
which gases are released from petroleum refineries ?
askiitians.com
2021.25
[ { "text": "sulphur dioxide and nitrogen dioxide.", "name": "", "is_accepted": false } ]
62538530435d8c08c09789cc19094e2f
20 cm3 of h2so4 solution neutralizes 21.55cm3 of naoh solution with c = 0.1m. how many cm3 of water should be added to 980cm3 of acid solution so that the concentration of the solution becomes 0.05m.
askiitians.com
2021.31
[ { "text": "dear student question is not clear please attach an image, we will happy to help you good luck cheers", "name": "", "is_accepted": false } ]
1b702aa23928a8425ed72d117d32c09f
how to solve {y^2 - (3/24)^2} {y^2-(1/24)^2} = 5/864?
askiitians.com
2021.31
[ { "text": "write, {y^2 - (3/24)^2} {y^2-(1/24)^2} as => {y^2 - (1/24)^2 – 8/(24)^2} {y^2-(1/24)^2} = 5/864 let {y^2 - (1/24)^2} = xthen,(x -8/(24)^2) x = 5/864now solve this quadratic in x and then equate it to general y form.", "name": "", "is_accepted": false } ]
8f470cd77cf7a7cf84f542d85271186f
two shm are given by y1 =40sinwt and y2=10(sinwt+c.coswt). if their displacement are equal , then the value of c is
askiitians.com
2021.31
[ { "text": "y 2 = 10(sinwt + c.coswt) divide & multiply by (1+c 2 ) 1/2 y 2 =10(1+c 2 ) 1/2 [ sinwt(1/1+c 2 ) 1/2 + (c 2 /1+c 2 ) 1/2 coswt ] now put (1/1+c 2 ) 1/2 = cos@ then (c 2 /1+c 2 ) 1/2 = sin@ now y 2 becomes y 2 = 10(1+c 2 ) 1/2 [ sinwtcos@ + coswtsin@] y 2 = 10(1+c 2 ) 1/2 [sin(wt+@)] y 1 = 40sinwt for same displacement , amplitude must be same so 40 = 10(1+c 2 ) 1/2 c = 15 1/2", "name": "", "is_accepted": false } ]
f90439a3b9fc1695a599a9a075405317
during a thermodynamic process, the pressure p of a diatomic gas depends on its volume v as p ∝ v^-4 . the specific heat of gas during this process 12r 13r/6 17r/5 11r/2
askiitians.com
2021.39
[ { "text": "this is the case of polytropic process and therefore, c is given as: c = r/(y -1) + r/(1-x) where y = cp/cv. where x = 4 given. cp =( f/2+1)*r cv = fr/2 f = 5 for diaatomic gas that is degree of freedom.", "name": "", "is_accepted": false } ]
96a8a63f51544e1e1968c2589da5840c
what is total internal reflection ........................
askiitians.com
2021.43
[ { "text": "no light pases into the rarer medium but the entire light is reflected back into the denser medium . this is called tir", "name": "", "is_accepted": false }, { "text": "when a light ray is traveling from denser medium to rarer medium and made to incident on the separation between two media at an angle greater than critical angle of the medium then the light ray is reflected back into the same denser medium...this is called tir... conditions.... light ray must travel from denser medium to rarer medium... angle of incidence in the denser medium must be greater than critical angle of the medium....", "name": "", "is_accepted": false }, { "text": "total internal reflection, in physics, complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium. the phenomenon occurs if the angle of incidence is greater than a certain limiting angle, called the critical angle", "name": "", "is_accepted": false }, { "text": "use scholr app for solving your doubts. total internal reflection , in physics, complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium. the phenomenon occurs if the angle of incidence is greater than a certain limiting angle, called the critical angle. in general, total internal reflection takes place at the boundary between two transparent media when a ray of light in a medium of higher index of refraction approaches the other medium at an angle of incidence greater than the critical angle. for a water-air surface the critical angle is 48.5°. because indices of refraction depend on wavelength, the critical angle (and hence the angle of total internal reflection) will vary slightly with wavelength and, therefore, with colour. at all angles less than the critical angle, both refraction and reflection occur in varying proportions.", "name": "", "is_accepted": false } ]
7f1f2c1c504700f4e5fc3279b1dfb7b7
limit x tening to 0 [1^(1/sin^2(x))+2^(1/sin^2(x))+.......... +n^(1/sin^2(x))]^sin^2(x)
askiitians.com
2021.43
[ { "text": "lim x tends to 0 it is in the form of a m + b m= ab m and then (a m)n = (ab )m then u will get n factorail as answer.", "name": "", "is_accepted": false } ]
d9ce790554e07156ea01866b86573575
q. in how many groups, plants disease are classified?
askiitians.com
2021.25
[ { "text": "hello student the plant disease are classified into four groups 1. seed borm disease 2.soil born disease 3. air born disease. 4. disease tranmitted through the diseased part of the plant", "name": "", "is_accepted": false } ]
531459b480c9cc6c074a43013b5d8072
but in my physics tb it is given that it is not (-)tive
askiitians.com
2021.39
[ { "text": "dear student, the first equation comes as a result of conservation of momentum. this results when the initial total momentum is equal to zero and there is no net force acting on the system. the second equation comes when the resultant vector is found in a vectorial notaion. regards sumit", "name": "", "is_accepted": false } ]
4a24e5a516327d4fc0d3015eddde701b
find the midpoint of the chord intercepted on the line lx+my+n=0 by circle x2+y2=a2
askiitians.com
2021.25
[ { "text": "dear student simplify eqn of circle as x= ± (a^2 – y^2)^0.5 put the 2 values in eqn of line and find y and eventually x two points thus obtained can be averaged for themidpoint of the chord regards", "name": "", "is_accepted": false } ]
5503e2a311b47178e0c66dac8121a243
capacitance (in f) of a spherical conductor with radius 1 m is (a) 1.1 x 10 -10 (b) 10 -6 (c) 9x 10 -9 (d) 10 -3
askiitians.com
2021.21
[ { "text": "(a) for an isolated sphere, the\ncapacitance is given by c = 4 p ? 0 r = 1/ 9x 10 9 x 1 = 1.1 x 10 -10 f", "name": "", "is_accepted": false } ]
5eb2799e5e2b78e845e3256e8b864c3d
57. when bulbs are connected in series, the lower power bulb glows brighter. [true/false]
askiitians.com
2021.31
[ { "text": "answer: explanation: true", "name": "", "is_accepted": false } ]
2def63051eaca80b3c276f851561b8f4
sin50-sin70+sin10=
askiitians.com
2021.21
[ { "text": "2.cos(50+70)/2 * sin(50-70)/2 + sin10 (use sin a – sin b = 2 cos (a+b)/2 * sin (a-b)/2 2.cos60 sin(-10) + sin10 2*1/2 * (-sin10) + sin10 -sin10 + sin10 = 0", "name": "", "is_accepted": false } ]
529992c29d1547173d7a956c8594bb89
can u explain theory of equation
askiitians.com
2021.43
[ { "text": "it is not possible for us to explain the whole topic/chapter here. please go through the study material and write down the specific problem. thanks & regards latika leekha askiitians faculty", "name": "", "is_accepted": false } ]
0e918ea94daac22f709a8f162ffb1dee
do quasiperfect numbers exist?
askiitians.com
2021.31
[ { "text": "hello student, a natural number n is called a quasiperfect number if the sum of its proper divisors is n+1 . like odd perfect numbers, no one knows whether a quasiperfect number exists. thanks and regards shaik aasif askiitians faculty", "name": "", "is_accepted": false } ]
8a5f59209afb347aeea9ca1e83b8645d
at 25°c, the solubility product of a salt of mx2 type is 3.2 × 10–8 in water. the solubility (in moles/lit) of mx2 in water at the same temperature will be (a) 1.2 × 10–3 (b) 2 × 10–3 (c) 3.2 × 10–3 (d) 1.75 × 10–3
askiitians.com
2021.21
[ { "text": "dear student the answer is option b regards", "name": "", "is_accepted": false } ]
5ed2951924787f102368c28d74d3cc12
how many natural numbers not exceeding 4321can be formed with the digits 1,2,3,4 if the digits can repeat?
askiitians.com
2021.39
[ { "text": "the answer is 4 4 .", "name": "", "is_accepted": false }, { "text": "anyway, there are 4 one digit numbers (obvious) 16 two digit numbers (there are 4 options for each digit, and two digit numbers are automatically <= 4321) 64 three digit numbers (again, 4 options for each digit) now for the four digit numbers: there are 64 numbers where the first digit is a 3 (4 options for each of the remaining digits, and since the first digit is a 3, the number is < 4321) similarly there are 64 numbers where the first digit is a 2, and another 64 where the first digit is a 1. this is 192 four digit numbers so long. now lets look at what happens if the first digit is a 4. there are 16 numbers where the second digit is a 2 (the last two digits can be anything in this case) and another 16 where the second digit is a 1. if the second digit is a 3: ...if the third digit is a 1, there are 4 numbers, because there are no restrictions on the last digit. ...if the third digit is a 2, there is only one possible number, n.l. 4321. so, there are 16 numbers if the second digit is a 2, 16 numbers if the second digit is a 1, and 4 + 1 = 5 numbers if the second digit is a 3, giving 16 + 16 + 5 = 37 four digit numbers where the first digit is a 4. in total, we have 4 one digit numbers 16 two digit numbers 64 three digit numbers 192 four digit numbers where the first digit is not a 4 37 four digit numbers where the first digit is a 4 this is 313 numbers in total.", "name": "", "is_accepted": false }, { "text": "answer is 4 raise to power 4.", "name": "", "is_accepted": false }, { "text": "no. has to be less than 4321 so, consider no. s less than 4000 1 st place:3 ways 2 nd place:4 ways 3 rd palce:4 ways 4 th place:4 ways therefore, 3*4*4*4=192 now consider no.s starting with 4 2 nd place can be filled in 2 ways (1&2) as no. has to be less than 4321 1 st place:1 way 2 nd place:2 ways 3 rd palce:4 ways 4 th place:4 ways therefore,1*2*4*4=32 now consider no.s starting with 4 and followed by 3 case 1: 432\\_ → 1 way case 2:431\\_ → 4 ways therfore , 1+4= 5 ways so , total no. of numbers formed= 192+32+5=229", "name": "", "is_accepted": false }, { "text": "anweres is when first two digits are fixed that is 4,4 now when two are fixed from satrting that is 4,3=16+8+3=27total ways =340sono.`s less than 4321=340-27=319", "name": "", "is_accepted": false }, { "text": "total no. of ways = 4*4*4*4+4*4*4+4*4+4=340no.`sgreater than 4321fixing first two no.`s i.e.,4,4,\\_,\\_no. of ways ,n1=4*4=16fixing first two no`s i.e.,4,3,\\_,\\_no.of ways,n2 =2*4=8fixing first three no.`s i.e.,4,3,2,\\_no.of ways,n3=3now no.`ss less than 4321are=t-(n1+n2+n3)=340-27=313", "name": "", "is_accepted": false }, { "text": "dear student, please find below the solution to your problem. there are 4 one digit numbers (obvious) 16 two digit numbers (there are 4 options for each digit, and two digit numbers are automatically <= 4321) 64 three digit numbers (again, 4 options for each digit) now for the four digit numbers: consider no. s less than 4000 1stplace:3 ways 2ndplace:4 ways 3rdpalce:4 ways 4thplace:4 ways therefore, 3*4*4*4=192 now consider no.s starting with 4 2ndplace can be filled in 2 ways (1&2) as no. has to be less than 4321 1stplace:1 way 2nd place:2 ways 3rdpalce:4 ways 4thplace:4 ways therefore,1*2*4*4=32 now consider no.s starting with 4 and followed by 3 case 1: 432\\_ → 1 way case 2:431\\_ → 4 ways therfore , 1+4= 5 ways so , total no. of 4 digit numbers formed = 192+32+5=229 hence total number = 4+16+64+229 = 313 thanks and regards", "name": "", "is_accepted": false } ]
0f9121f5380c5e993400058a0da854a1
i can get iiit-allahabad ece. should i go for it or take nit-nagpur ece or nit-rourkela ece or nit-nagpur mech or nit-rourkela\_mech? pl rate these. the first batch of iiit-allahabad is coming out this year. pls tell me i am really confused?
askiitians.com
2021.39
[ { "text": "dear sarath, your preffered options shud be like: 1. ece@ nit nagpur 2. ece@iiit allahabad 3 mech @ nagpur 4 nit rourkela all the best for your future. check out the opening and closing rank for collages under aieee: http://www.askiitians.com/aieee-counselling/aieee-engineering-counsellings.aspx please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. regards vijay luxmi", "name": "", "is_accepted": false } ]
602add4fe699e25506ca4b1b618125dd
if we increase the length of resonance tube by 100 times, what will b its effect on the frequency of sound heard by the observer?
askiitians.com
2021.43
[ { "text": "frequency is inversely proportional to length", "name": "", "is_accepted": false }, { "text": "if you need further help, feel free to reach me on my gmail : amit1235813 i am an iit madras alumnus, would love to help", "name": "", "is_accepted": false }, { "text": "thnk u so much ...... sure ,.....", "name": "", "is_accepted": false } ]
04bc7a51c197bd6e307e79769f3a2edf
please answer the attached question... . .. . . . .. .
askiitians.com
2021.25
[ { "text": "hello dear parth verma xanthium also called coclebur is the odd one because xanthium is a short day plant but all others like sugarbeet,carrot,and cabbage are lond day plants thank you", "name": "", "is_accepted": false } ]
a50511ab175a7331420f578a29f88e07
find the value of each of the followinglim e^-x-e^x÷x-1. approach to 1
askiitians.com
2021.43
[ { "text": "please use brackets and write question properly.", "name": "", "is_accepted": false } ]
93ff2b5112c378a3d1127270d81cc5da
getting cs at dce and nsit (dce near my home) and ism dhanbaadf petroleum what is there to study in petroleum what should i prefer
askiitians.com
2021.25
[ { "text": "dear dheeraj prefer your branch rather than college. cracking iit just got more exciting,it s not just all about getting assistance from iitians, alongside target achievement and rewards play an important role. askiitians has it all for you, wherein you get assistance only from iitians for your preparation and win by answering queries in the discussion forums. reward points 5 + 15 for all those who upload their pic and download the askiitians toolbar, just a simple to download the toolbar…. so start the brain storming…. become a leader with elite expert league askiitians thanks aman bansal askiitian expert", "name": "", "is_accepted": false } ]
f747a0798c61b542d29c25daf8f0b72b
an infant feeds only on mother’s milk.but also his faeces are yellow in colour.why?
askiitians.com
2021.31
[ { "text": "it’s due to the bile that get mixed with it in duodenum...................................................................................", "name": "", "is_accepted": false }, { "text": "hi anna, dear, you are right that an infant feeds only on mother’s milk .but also his faeces aer yellow in colour . it os due to release of bile pigments during digestion", "name": "", "is_accepted": false } ]
9bef34b3ddbefb2c9c9d596d99b57ff4
find the number of solutions of the equation: [x]+[2x]+[4x]+[8x]+[16x]+[32x]=12345 where [.] denotes the greatest integer function.
askiitians.com
2021.25
[ { "text": "dear rishabh , let x = i + f where i is the integer part or integral part and f the fractional part of x. we have f < 1, and [x] + [2x] + [4x] + [8x] + [16x] + [32x] = 63i + [f] + [2f] + [4f] + [8f] + [16f] + [32f] since f < 1, [f] = 0, and we now have 63i + [f] + [2f] + [4f] + [8f] + [16f] + [32f] = 63i + [2f] + [4f] + [8f] + [16f] + [32f] = 12345 = 63 × 195 + 60 so i = 195, and [2f] + [4f] + [8f] + [16f] + [32f] = 60 (*) since max[nf] = n - 1, the maximum value of [2f] + [4f] + [8f] + [16f] + [32f] = 1 + 3 + 7 + 15 + 31 = 57. therefore, equation (*) is not possible, and there is no f that can satisfy the equation in the problem, and thus there is no x. please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar.. askiitians expert ajit singh verma iitd", "name": "", "is_accepted": false }, { "text": "let f(x) = [x] + [2x] + [4x] + [8x] + [16x] + [32x]. obviously f is an increasing function (if x < y, then f(x) <= f(y).). f(196) = 12348. but if x is just under 196, then [x], [2x], [4x], [8x], [16x] and [32x] are all smaller by at least 1, so f(x) < 12342. hence f never takes the value 12345.", "name": "", "is_accepted": false } ]
2dd85e6a09660a52c9d21cae6ef7f81e
anna university, chennai is giving any seats basedon iit jee 2010 ranks. if so pl give details. may i get seat in any iit with 7000 rank under general category. if so which iit and which branch.
askiitians.com
2021.21
[ { "text": "yes you can get int iit,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,", "name": "", "is_accepted": false } ]
992e335ea2673e6807b37d91e2cf7f11
how does miller’s experiment support biogenesis theory?
askiitians.com
2021.21
[ { "text": "in 1953, urey and miller conducted an experiment to prove this theory. they created the conditions of primeval earth − high temperature, volcanic storms, reducing atmosphere containing ch 4 , nh 3 , etc at laboratory scale. they then stimulated electric discharge in a closed flask containing ch 4 , h 2 , nh 3 and water vapour at 8000°c. they observed formation of amino acids. in similar experiments others observed, formation of sugars, nitrogen bases, pigment and fats. these small organic molecules are the building blocks for proteins & other components. hence, this experiment supported that life has come from pre-existing non-living organic molecules.", "name": "", "is_accepted": false } ]
621669633948fb0d3bc19baefb00af32
what are the differences between dimond and graphite?give it
askiitians.com
2021.43
[ { "text": "hii i am enlisting the basic difference between diamond and graphite . *diamond is the hardest mineral known to man, graphite is one of the softest. * diamond is an excellent electrical insulator, graphite is a good conductor of electricity. * diamond is the ultimate abrasive, graphite is a very good lubricant. * diamond is usually transparent, graphite is opaque. * diamond crystallizes in the isometric system and graphite crystallizes in the hexagonal system.", "name": "", "is_accepted": false }, { "text": "graphite is soft and good conductor of electricity.but diamond is hard and bad conductor of electricity. both are allotropes of carbon. both diamond and graphite are made entirely out of carbon, as is the more recently discovered buckminsterfullerene (a discrete soccer-ball-shaped molecule containing carbon 60 atoms). the way the carbon atoms are arranged in space, however, is different for the three materials, making them allotropes of carbon.", "name": "", "is_accepted": false }, { "text": "would be that since diamonds have a three dimensional network of strong covalent bonds, which makes it hard, but graphite on the other hand has flat layers of carbon atoms held by weak van der waal's forces which makes graphite a weak object and easily breakable ( what is the differences in physical", "name": "", "is_accepted": false } ]
a3dc2f69ae11dfad347e085ee6f4acdd
what was the most significant trend in the evolution of modern man (homo sapiens) from his ancestors? 1. increasing brain capacity 2. upright posture 3. shortening of jaws 4. binocular vision
askiitians.com
2021.39
[ { "text": "sol: the most significant trend in the evolution of modern man (homo sapiens) from the ancestors is increasing brain capacity. answer: (1)", "name": "", "is_accepted": false } ]
667237a3ae98aa1755aaa15ec996801a
may i know the any changes of question paper model in this year of 2010 iit-jee compare to last year
askiitians.com
2021.25
[ { "text": "dear ramesh there is no change in question paper pattern in jee2010 as compair to last year.(as maintion in information broucher jee 2010). there will be two question papers, each of three hours duration. both the question papers will consist of three separate sections on chemistry, mathematics and physics. questions in these papers will be of objective type. regards badiuddin", "name": "", "is_accepted": false } ]
9cb5fce87946246afe3dbaf782660141
give some examples for elemental semiconductors????
askiitians.com
2021.43
[ { "text": "semiconductors are available as either elements or compounds. silicon and germanium are the most common elemental semiconductors. compound semiconductors include insb , inas , gap, gasb , gaas , sic, gan . si and ge both have a crystalline structure called the diamond lattice.", "name": "", "is_accepted": false }, { "text": "silicon (si) and germanium (ge) are the main elemental semiconductors. hope you got the answer. all the best..", "name": "", "is_accepted": false } ]
3edf36d77471752ea933004fa32a5429
if lattice energy>hydration energy -the system cools down -insoluble. if lattice energy<hydration energy-the system heats up-soluble. how?
askiitians.com
2021.25
[ { "text": "when a substance is dissolved in water its crystal structure is ruptured or it looses its lattice form and since lattice energy is always negative for a substance (because we define it to be the energy that is released during the formation of its lattice ) when the lattice is broken energy needs to be supplied and that is gained through the hydration enthalpy . now since hydration enthalpy is less than lattice enthalpy (numerically) the full energy is not gained through hydration enthalpy and hence it takes it from the surrounding by absorbing heat and hence cools down.", "name": "", "is_accepted": false } ]
118d129d28a96189305df6b37011dc3a
57. an embryo is formed by the growth and development of an foetus. [true/false]
askiitians.com
2021.39
[ { "text": "answer: explanation: false", "name": "", "is_accepted": false } ]