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d322dae95a8251e0d486b0ba53d05e54 | 1.integration of tan^-1(secx+tanx) 2.tan^-1(2cos^2theta/2-2-sin2theta)sec^2theta 2.integration of (1+2tanx(tanx+secx)^1/2 | askiitians.com | 2021.39 | [
{
"text": "1) i=tan^-1secx+tanx)dx secx+tanx=1+sinx/cosx 1+sinx=(sinx/2+cosx/2)^2 cosx=(cosx/2-sinx/2)(cosx/2+sinx/2) i=tan^-1(sinx/2+cosx/2)/(cosx/2-sinx/2)dx =tan^-(tanpi/4+x/2)dx =(pi/4+x/2)dx =(pi/5)x + x^2/4 +k 2)i=(1+2tanx(tanx+secx)^1/2dx =(1+tan^2x + tan^2x +2secxtanx)^1/2 dx =( sec^2x +tan^2x +2tanxsecx)^1/2dx = ((secx+tanx)^2 )^1/2dx = ( secx+tanx )dx =logsecx+tanx +logsecx +c =log(secx+tanx)secx +c",
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{
"text": "=tan -1 (1+sinx/cosx) =tan -1 ((sinx+cosx) 2 /(cosx 2 -sinx 2 )) =tan -1 (tan(x+∏/4) =x+pi/4",
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{
"text": "i=integ.of. tan^-1(1+sinx)/cosx.dx i=integ.of. tan^-1(cos^2x/2+sin^2x/2+2.sin x/2.cos x/2).dx /(cos^2x/2-sin^2x/2) i=integ.of tan^-1(cos x/2+sin x/2)^2.dx/(cos x/2+sin x/2).(cos x/2-sin x/2). i=integ.of tan^-1(cos x/2+sin x/2).dx/(cos x/2-sin x/2). i=integ.of tan^-1 (1+tan x/2)/(1-tan x/2).dx i=integ.of tan^-1 (tanπ/4+tan x/2)/(1-tan π/4.tan x/2).dx i=integ.of tan^-1 tan (π/4+x/2).dx i=integ.of. (π/4+x/2).dx i = π/4. x. +x^2/(2.2). +c i= π.x/4. +x^2/4. +c. answer.",
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ae2eacd4602a5e0008fa5f266074034f | i am getting cse in iiit hyderabad but my advanced rank is 1690 obc.should i prefer other branches in iit’s or cse in iiit.please help!!! | askiitians.com | 2021.21 | [
{
"text": "cse is a good branch, but you can get maths and computing at some old iits , which is also a good branch and better than cs at iiit. sher mohammad faculty askiitians b.tech, iit delhi",
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2c6da7f3a161f970986c78ad32552753 | i got 203 marks in jee advance & i dont know my interest so which branch i prefer among cse,ee,& me | askiitians.com | 2021.43 | [
{
"text": "i think you should try getting mechanical & electrical/electronics at one of the old iits. after that you should go for cs at new iits. your preference order should be like: me & ee (old iits) > cs (new iits) > other branches good luck! thanks & regards jitender singh iit delhi askiitians faculty",
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6d47a7885af619fdc2547b2726708dcb | ovulation is stimulated by a)lh b)fsh c) estrogen d) progesterone | askiitians.com | 2021.39 | [
{
"text": "ans: (a) lh ovulation in females is stimulated by luteinizing hormone (lh) secreted by anterior lobe of pituitary gland. abhishek dogra",
"name": "",
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] |
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9e0d94d3fa3c021b882ad886fec571bf | the eq formed by decreasing each of ax 2 +bx+c=0 by 1 is 2x 2 +8x+2=0. then prove b=-c | askiitians.com | 2021.21 | [
{
"text": "ans: hello student, please find answer to your question below now if we decrease x by 1, we have by comparing,",
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1160a81b44de1ddca657d0571e320572 | consider the adjacent figure. the cube shaped carriage abcdefgh of side l has a mass m and it can slide over two frictionless rails pq and rs. a shot of mass m is thrown from corner a such that it lands at corner f. the angle of projected as seen from the carriage is 450. while the shot is in the air, the velocity of carriage as seen from the ground is : | askiitians.com | 2021.21 | [
{
"text": "dear mainak please check given diagram is not for this problem. post the correct diagram please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best. regards, askiitians experts badiuddin",
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434f78bd496ab7dc77125cba1d6eb445 | sin(cos×) ..a . equal . b greater . c less to cosx kc8c ocuco zuid please solve it | askiitians.com | 2021.39 | [
{
"text": "please write question properly",
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}
] |
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31957599fa462fbd41d27532d53c5f7b | i m gtting prduction & engg. at iitr & getting electronics & comm. at nit kurushetra whre to go???? | askiitians.com | 2021.43 | [
{
"text": "hi prashant, if u r getting production & engg. at iitroorkee den wat wud be better dan dat...simply i will tell u one thing to do just compare d two institutes , one is iit roorkee n other one is nit , iit roorkee is ranked 6 th in d list of top engg colleges in india n also it is an iit ,which is known for its excellence .... iit roorkee is a well recognised institute which is among d top colleges even before becoming an iit, n also u will get d famous iit tag which will help u a lot in ur professional life......if u r bothering abt d branch ,den also u needn't hav to think as placements at any iit is always better dan nits...n nit kurushetra is not even d top nits, so its placements will be far behind d iit roorkee..... iit roorkee has got recognisation globally before getting d iit tag, so u can think of its excellence...so finally i hope dat ur confusion will end after thinking a little abt d pride to be known as an iitian..",
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"text": "hi iit roorkee is a far better institute than nit kurukshetra and should be a better choice over it. iit roorkee is one of the oldest instiute in india although it has been given the tag iit recently only. the placements too would be better at iit r than nit kurukshetra. production engineering : these deals with integrated design and efficient planning of the entire manufacturing system, which is becoming increasingly complex with the emergence of sophisticated, production methods and control systems. job and scope: opportunities are available in public and private sector manufacturing organizations engaged in implementation, development and management of new production process, information and control systems and computer controlled inspection, assembly and handling. jobs could be lyk : plant and production engineering maintenance engineer manufacturing engineer manufacturing systems engineer plant manager production manager production supervisor",
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"text": "hi, iit-r should be better option. production and engg. is a good branch. it is mostly related to mechanical. and in iit's the production and engg. and mechanical offers same courses and also many of the classes of these two branches also overlap. also, the companies which come for placement generally take these two branches as almost same. although, electronics and comm. is a better branch than production and engg.. but here it is worth to take the production and engg. coz your are getting a much better college. the placement of iit-r is far - far better than nit kurushetra. last year also there was a 100% placement in iit-r and the companies which come for on campus placement offers a very good package. mostly big companies come to good institute, which definitly iit - r is. some big companies which come last year to iit-r are schlumberger, hindustan aeronautics, beca, itc ltd. , forbes marshall etc. also if you are looking for higher studies than also you can continue your studies in which iit-r will help you the most. so, you can easily judge that iit-r provide you a perfect environment which a student idealy required for better future.",
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a25ff31cfc2b07e8ac8683eb7df7bee9 | the figure below shows a cross section through a very large nonconducting slab ofthickness d=9.40 mm and uniform volume charge density p=5.80 fc/m3. the originof an x axis is at the slab’s centre. what is the magnitude of the slab’s electric fieldat an x coordinate of (a) 0, (b) 2.00 mm, (c) 4.70mm, (d) 26 mm? | askiitians.com | 2021.31 | [
{
"text": "volume charge density = 5.80 fc/m3 thickness d = 9.40 mm at 0, electric field will be zero. at 2 mm the electric field will be e.f. = volume density * volume = 5.80 * 18.8 =109.04 at 4.70 mm electric field will be e.f. = volume density* volume = 5.80* 9.40 = 256.244 at 26mm e.f. = volume density * volume = 5.80 * 244.4 = 1417.52",
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9daae6bcdebf4121c80e0787aafed016 | i am a student of 12 which chapter to do now | askiitians.com | 2021.39 | [
{
"text": "dear sahil, you please specify the subject so that we can help you more.... most scoring topics include: maths:calculas,algebra physics:mechanics,electrostatics chemistry: physical and organic we are all iitians and here to help you in your iit jee preparation. all the best. if you like this answer please approve it.... win exciting gifts by answering the questions on discussion forum sagar singh b.tech iit delhi",
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eac0cbf62af28dfe74d8ca3bbcb9b480 | a particle executing shm of amplitude 4 cm and t=4sec the time taken by it to move from positive extreme position to half the amplitude is | askiitians.com | 2021.43 | [
{
"text": "dear pallavi, please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best pallavi !!! regards, askiitians experts rohith gandhi p",
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{
"text": "at half distance from the extreme positions, k.e = pe 1/2mv 2 =1/2kx 2 please try to understand the answer. i felt it as the easy way and so i am sharing it with you. as the typing of equations took me time in my computer, i made it really short. if you are going to appear for the boards, you can include a lot more steps.",
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{
"text": "dear student please see the solution in the attachment. i hope this solution will help you. thanks & regards yash chourasiya",
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|
ed00800d3d45d76658fe21277d498967 | represent the following situations mathematically: (i) john and jivanti together have 45 marbles. both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. we would like to find out how many marbles they had to start with. | askiitians.com | 2021.25 | [
{
"text": "dear student let us say, the number of marbles john have = x. therefore, number of marble jivanti have = 45 - x after losing 5 marbles each, number of marbles john have = x - 5 number of marble jivanti have = 45 - x - 5 = 40 - x given that the product of their marbles is 124. ∴ (x - 5)(40 - x) = 124 → x^2 – 45x + 324 = 0 → x^2 – 36x - 9x + 324 = 0 → x(x - 36) -9(x - 36) = 0 → (x - 36)(x - 9) = 0 thus, we can say, x - 36 = 0 or x - 9 = 0 → x = 36 or x = 9 therefore, if, john's marbles = 36, then, jivanti's marbles = 45 - 36 = 9 and if john's marbles = 9, then, jivanti's marbles = 45 - 9 = 36 thanks",
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1ad9cabb7f6cb4d81a7856f448d9cca2 | in common base configuration, collector and base are reverse bias.when a negative potential is applied to the base-collector, why does that behave as if it is forward biased??do u say that when a negative potential or voltage is appliied to a system in reverse bias...it behaves as forward biased??pls explain with reasons????? | askiitians.com | 2021.21 | [
{
"text": "hi murali pls specify whether it is n-p-n transistor or p-n-p transistor and when you apply any voltage across base and collector it actually is a diode in case of n-p-n base acts as p and collector acts as n and vice versa in p - n - p so when you apply a negative voltage across base and collector it will be forward bias . in case of n-p-n hi murali pls specify whether the transistor is npn or pnp configuration and forward bias is when n is connceted to lower voltage than p and reverse bias is when n is connected to higher voltage than p you can easily see that in diode biasing when p is connected to + voltage and n to - voltage then it is forward bias and behaves as short circuit .",
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393ea6fe314be48d8edaa13e3cfd59fc | which of the following react with pcl5 to give pocl3? o2,co2,h2o,h2so4,p4o10,so2 | askiitians.com | 2021.21 | [
{
"text": "dear samir answer is p4o10 p4o10 + 6 pcl5 = 10 pocl3 please feel free to ask your queries here. we are all iitians and here to help you in your iit jee preparation. all the best. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar.. rathod shankar iit bombay",
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7504e519555e005eeac6138fb2e5edbb | bombardment of aluminium by a-particle leads to its artificial disintegration in two ways, (i) and (ii) as shown. products x, y and z respectively are | askiitians.com | 2021.25 | [
{
"text": "dear student please attach the image of the question regards",
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7a3ce81a42e0d6ad9ee4a09752374fc2 | state and proove bernallis theorem...........???????????????? | askiitians.com | 2021.25 | [
{
"text": "bernoulli’s equation states that the work done on a unit volume of fluid by the surrounding fluid is equal to the sum of the changes in kinetic and potential energies per unit volume that occur during the flow. dw = p 1 a 1 ds 1 - p 2 a 2 ds 2 = (p 1 - p 2 )dv the net change in kinetic energy dk during time dt is dk = ½ ∂ dv(v 2 2 - v 1 2 ) du = ∂ dv g(y 2 - y 1 ) dw = dk + du, we obtain (p 1 - p 2 )dv = ½ ∂ dv(v 2 2 – v 1 2 ) + ∂ dv g(y 2 - y 1 ) p 1 - p 2 = ½ ∂ (v 2 2 - v 1 2 ) + ∂ g(y 2 - y 1 ) p 1 +∂gy 1 + ½ p v 1 2 + ∂gy 1 + ½ ∂v 1 2 = p 2 + ∂gy 2 + ½ ∂v 2 2 (bernoulli’s equation) {∂= density} thanq...",
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563fd71828677c407b992482cd65e0b3 | sir i can secure 125 marks in jee advanced .in obc category which rank and collage i can secure with good branch | askiitians.com | 2021.39 | [
{
"text": "yes, i concur these things will come up to your psyche, however finding a correct solution to this is not in any way conceivable, as this likewise relies on how others performed in the exam however i figure you would be getting a rank to some degree around 10k yet who knows, anything can happen yet with a rank of fairly around 10k, you will have the capacity to get a portion of the branches in the recently opened up iits, so yes you can plan to be an iitian soon.",
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74657ef7d21868a5695e3d66df9884ce | if the earth is drilled through the centre of the core and if we drop a metal ball from one end what happens to the ball ? | askiitians.com | 2021.43 | [
{
"text": "in first half i.e going from surface to the centre it would continually accelerate as the gravitational force is in towards the centre but as soon as it crosses the centre it would start deccelerate as now the gravitational force would be in opposite direction to motion and hence it would just reach the other end .. if it helped please click the yes button",
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"text": "if we drop a metal ball from one end the accelerates some distance but at the centre of the earth it will stop it does not go to the other end because at the center of the earth the acceleration is zero thats there is no acceleration at the centre. please approve my answer by clicking yes",
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{
"text": "the acceleration vanishes but the ball has a good velocity and it moves further to negate that velocity",
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e866c320fa93f2b3dafd76914849c9c8 | please explain: the liquefaction behavior of temporary gases like co2 approaches that of n2, o2 (permanent gases) as we go above critical temperature. | askiitians.com | 2021.39 | [
{
"text": "the liquefaction of a gas occurs when the intermolecular forces of attraction reach a point (or become that much high) that they become capable to bind the gas molecules together to convert it into a liquid state. the critical temperature of the gas on the other hand, is the measure to identify the strength of the intermolecular forces of attraction. as we move above the critical temperature, the liquefaction behaviour of co 2 would approach that of n 2 and o 2 due to the same reason. when liquefaction is complete, a steep curve is observed, and when we increase the temperature, the horizontal portion start becoming smaller, and after reaching a temperature 30.98 o c, it gets reduced to a point 'e'. above this temperature, we cannot liquefy the gas but we can apply high pressure. so, this temperature of 30.98 o c is known as critical temperature. so, weaker the intermolecular forces of attraction, the more difficult it would be to liquefy the gas, and therefore, the critical temperature will be lower for that gas. carbon dioxide gas has strong intermolecular forces of attraction, so they can be easily liquefied and hence, there critical temperature would be higher. and, co 2 below the critical temperature is known as carbon dioxide vapour. next, in n 2 and o 2 , intermolecular forces of attraction are weak, therefore it would be difficult to liquefy these gases, and thus their critical temperature would be lower than these gases. regards arun",
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0c7c1815e9d5031d9303e2e219662d19 | pls give me the definitions of ac and dc curents? | askiitians.com | 2021.39 | [
{
"text": "ac current is a typeof current in which the direction of flow of electron switches back and forth at regular interval of time ex- current flowing in household and power line dc current is electrical current which flows constantly in one direction.ex-current in flashlight or in appliances running in batteries. thanks and regards sunil kr askiitian faculty",
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03fa9e6e95bca57d6f698baea9f122ac | i am a student of x grade, studying in sharjah, u.a.e. i would like to know the courses to be studied for iit admission. also please let me know about the admission procedure for those students doing their x and xii abroad. tks. aparna sharma | askiitians.com | 2021.31 | [
{
"text": "u must hav phy, maths n one of computer or chemistry or biotech as optional subject.. if u hav indian nationality u can give d xam d same way as other ppl in india give. more info check this site http://jee.iitd.ac.in/ plzzz approve d answer if u like it",
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18ecf4975148fc558b1a840d6b49ff9e | 4. the chemical symbol for sodium is : (a) so (b) sd (c) na (d) na | askiitians.com | 2021.43 | [
{
"text": "(d) na",
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b6d9d4251cf27d95f68cd8487adc522c | if it is not written to arrange the word such as allahabad in different words will we use the formula n!/p! | askiitians.com | 2021.39 | [
{
"text": "we can write it as n!/p!.",
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288248f2b6e0821f77f617ac86a0453c | i can get 280 marks in iit jee 2010 what rank and courses can i get in iit mumbai,delhi or kanpur | askiitians.com | 2021.39 | [
{
"text": "dear bilal, congratulations for this good score !! click for opening and closing ranks: http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx askiitians provide the iit jee cut off along with the opening and closing ran given below for iit jee cut off: http://www.askiitians.com/iit-jee-2010-cut-offs.aspx you can check out the cutoff in new iits, check the link given below : http://jee.iitd.ac.in/openclose09.htm (this link includes the more detail analysis) for code of the cources check the councelling broucher 2009. please feel free to post as many doubts on our disucssion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best. regards askiitians expert amit yadav",
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{
"text": "i think that u wiil get under 700 rank. all the best",
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8fbb5d92ae506263ec41fd5ea13f92bc | i wanna study automobile engineering what are the colleges i can have a view(only elite colleges) | askiitians.com | 2021.21 | [
{
"text": "dear akshay some of the elite institutes offering a b. tech. in automobile engineering apart from several other state level engineering colleges are • iits • nits • birla institute of technology • institute of technology (banaras hindu university) • college of engineering and technology (anna university) • manipal institute of technology, manipal • rajalakshmi engineering college, chennai • srm university, chennai • madras institute of technology, chennai it is always suggested that you do mechanical first and then specialize in automobile engineering..... all iits offer b.tech in mechanical enggineering and in iit madras they offer a 5 yr course in engg. design and automotive engg apart frm this 2 yr m.tech programmes are avaialble in some iits please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best. regards, askiitians experts badiuddin",
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1926bf6fafd0b4c9d93b813970c1e587 | ch3---ch3---ch3 i i i cn cn cn give the iupac name also is their any word like chemical abstract name plzz explain that.. | askiitians.com | 2021.25 | [
{
"text": "dear raj , ch 2 -ch 2 -ch 2 cn cn cn [ propane1,2,3 tricarbonitrile ] each cn will be counted as substituent...",
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{
"text": "dear raj , inpac name of this compound is propane 123 tri carbonitrile",
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{
"text": "propane-1,2,3-trinitrile... chemical abstract is the name of an american chemical company.. please approve!!",
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{
"text": "1 ch3- 2 ch3- 3 ch3 i i i cn cn cn the iupac name goes as :propan e -1,2,3-tri carbo nitrile remember :1.their is 'e' after propan 2.whenever there are more than 3 func grps of same type we use the word 'carbo' ahead of the func grp name 3. for cn group 'nitrile' is the word added",
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1d94149f35cd34b7deb3271e1ac93bf2 | speed of decomposition of h 2 o 2 is reduced by | askiitians.com | 2021.25 | [
{
"text": "it is reduced by mno2 and water is formed.",
"name": "",
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},
{
"text": "i checked the ans its coming alcohol.pls tell me how .",
"name": "",
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},
{
"text": "i think urea is used to slow down the decomposition speed of h2o2 ",
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ab745ec72a09d686bb7e969a3304556a | 5/8 and 3/8 are proper fraction. 5/8 and 3/8 are proper fraction. | askiitians.com | 2021.31 | [
{
"text": "dear student 5/8 and 3/8 are like proper fraction. fractions with same denominators are called like fractions. thanks",
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|
a84bf878faa9f5425a41bc52466a7b24 | sir plz suggest me some good books for iit jee | askiitians.com | 2021.25 | [
{
"text": "chemistry books s.no authors /publisher name of books remarks 1 p.bahadur(g.r.bathla & sons) numerical chemistry physical chemistry 2 o.p. tandon physical chemistry physical chemistry 3 o.p. tandon inorganic chemistry inorganic chemistry 4 o.p. tandon organic chemistry base book 5 paula bruice yurkanis organic chemistry reference book 6 j.d. lee inorganic chemistry reference book 7 bruce h. mahan university chemistry reference book 6 organic chemistry by morrison & boyd organic chemistry reference book physics books s.no authors /publisher name of books remarks 1 h.c.verma concepts of physica vol i and ii for text books and problem books. 2 i.e. irodov problems in general physics selected problems 3 halliday, resnick & walker fundamentals of physics reference book mathematics books s.no authors /publisher name of books remarks 1 r.d. sharma maths xi & xii basic text books 2 s. l. loney trigonometry recommended 3 s. l. loney co-ordinate geometry reference book 4 hall knight higher algebra reference book 5 i.a. maron problems in calculus of one variable reference book 6 arihant algebra reference book 7 arihant differential calculus reference book 8 arihant integral calculus reference book you can even try play with graphs by arihant publications. approve if you are satisfied",
"name": "",
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},
{
"text": "phy- hc verma part- 1&2 -physics by resnick, halliday, krane- volume 1&2 - ie irodov chem- modern approach to chemica calculations by rc mukerjee maths- plane trigonometry by sl loney-part 1&2 - coordinate geometry by sl loney -part 1&2 -higher algebra by hall & knight tata mc graw hill -modern iit jee 2010 for phy,chem nd maths. aproove if you like the answer.",
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},
{
"text": "maths tmh subjective a das gupta objective s.l. loney for trigno and coordinate hall and knight for algebra physics d mukherji university physics for theory hc verma chemistry new era p bahadur",
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] |
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655e581f619e015c16a1eec991b92a97 | structural formula of methane | askiitians.com | 2021.43 | [
{
"text": "dear joseph methane is a chemical compound with the chemical formula ch 4 . it is the simplest alkane, and the principal component of natural gas all the best. akash goyal askiitiansexpert-iitd please feel free to post as many doubts on our discussion forum as you can. we are all iitians and here to help you in your iit jee preparation. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar respectively : click here to download the toolbar..",
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b728112f1c126bd747f2b297a600ceac | 1. describe joint diastole 2. what is the difference between atherosclerosis and arteriosclerosis? | askiitians.com | 2021.25 | [
{
"text": "hi shivani, thank you for asking joint diastole is the relaxation of the four chambers of the heart. atherosclerosis is the narrowing of the arteries due plaque build-up in the artery wall. arteriosclerosis is a diseased condition of thearteries. the artery walls are thickened, hardened and lose stretchiness, called elasticity.",
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] |
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e56af3f24df4805f43ae1d66c5369715 | a six faced fair dice is thrown until 1 comes, then the probability that 1 comes in even no. of trials is (a) 5/11 (b) 5/6 (c) 6/11 (d) 1/6 | askiitians.com | 2021.31 | [
{
"text": "1/6*5/6 + 1/6*(5/6) 3 so answer is by using infine sum of gp (a) 5/11",
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},
{
"text": "1/6 is right answer",
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}
] |
|
900be63a709688aae455d7939e3f21f2 | how many seats are available in iit preperatory cource | askiitians.com | 2021.21 | [
{
"text": "i hope the query is resolved.",
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}
] |
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b2d6afa0010bb98481029ce095225c9f | aman drops an apple in the lift. he finds that the apple remains stationary and does not fall. the lift is | askiitians.com | 2021.39 | [
{
"text": "when the apple is dropped due to free fall means that object is under force of gravity on it. inside the lift , man and apple are under the acceleration due to the action of gravity. so the lift is moving in downward acceleration due to gravity.",
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] |
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4a1201ab95336a30e72392ecd06d5397 | what are independent events?? | askiitians.com | 2021.21 | [
{
"text": "independent event are a type of compound event whre the outcome of event doesn''t effect theprobability of any other event that happen after it for example-- rolling two dice",
"name": "",
"is_accepted": false
},
{
"text": "whose probabiltiy doesnt depends upon the occurence of any other event",
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] |
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d434b9a7e51e5530bc81c2724399e6dd | sir , is joining in vit worthy,my score is around 60 in vit will i be able to get into it. kindly reply soon | askiitians.com | 2021.25 | [
{
"text": "dear raghu, as your score is 60 in vit then most probably chances are less that you can get through the vit, bit luckily is you somehow manage to get into vit , then definately you would be not be getting your desired branch . however score may vary and as a result rank may also vary, a slight difference may create lots of difference in rank. askiitians.com provides online iit jee courses and iit jee test series with iitians. click here to get free online test series and check your status timely or you can join us as our registered user for getting best iit jee study material or iit jee test series. click here to find iit jee packages or course details with askiitians. for further details visit the folowing links: http://www.askiitians.com//iit-jee-online-coaching.aspx http://www.askiitians.com/iit-jee-test-series.aspx http://www.askiitians.com/iit-study-material/ askiitians provide you all the best possible information, feel free to ask. all the best. thanks and regards. akhilesh shukla",
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546f29a339ef64bd4a33eea6d13c4256 | a balloon of mass m is found to accelerate up at the rate of g/6. the quantity of water that should be put inside the balloon so that it may acc. doun at the rate of g/6 is??? | askiitians.com | 2021.25 | [
{
"text": "dear student, in going up g will act upward so subtract it from acceleration in going gown add it to acceleration....",
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},
{
"text": "2m/7.......ans",
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},
{
"text": "the answer is m/3",
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}
] |
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dbd5ecd3877bd475c784028d8bdb73ad | sir if i got 137 marks in jee mains 2017 obc category can i get a seat in any nit? my home state is up. | askiitians.com | 2021.43 | [
{
"text": "yes, there are good chances to get an admission to nit allahabad. you can also get admission to other nits. but you should look for an iit work hard for jee advanced.",
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}
] |
|
c16d41d474ddd8347a08dff97c136bec | why does kinetic energy increase quadratically, not linearly, with speed? | askiitians.com | 2021.21 | [
{
"text": "that’s because kinetic energy is the integral of force operating over a distance. if we apply a force of 1 newton to a mass of 1 kg at rest for 1 second, the the body will accelerate at a uniform rate from 0 to 1 m/s and, in doing so, will have covered 0.5 metres. that means the energy expended will be 1 x 0.5 = 0.5 joules (a joule has units of newton-metres). now say we apply another force of 1 newton to that 1 kg mass now moving at 1 m/s for 1 second. it’s going to accelerate to 2 m/s. however, unlike in that first second, the object is already moving at 1 m/s, so the total distance it will have moved in this time will have been 1.5 metres. thus, this time, the energy required was 1 x 1.5 = 1.5 joules. with the energy expended in the first interval, that is now 2 joules. so, getting the object to 1 m/s required 0.5 j whilst doubling it to 2 m/s required a total of 2 j, of 4 times as much for doubling the speed. do this again for a third second, and you get 1 x 2.5 = 2.5 j, and then for a fourth second, it’s 1 x 3.5 = 3.5 j at 4 m/s. thus out body at 4 m/s has 0.5 + 1.5 + 2.5 + 3.5 = 8 j of energy, or 16 times as much as it had at 1 m/s. i’ve deliberately made this as simple as possible using basic numbers. it’s not meant to be a formal proof as it tackles a special, and not the general case. it’s there to illustrated the principle. for the general case it would be necessary to allow for variable forces and use a bit of calculus, but it would ultimately come out with the formula ke=12mv2ke=1/2mv^2 .",
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|
46116a46e3cfa99a024264b1fe98fa63 | is there no eml for the year 2010 in iit?please help | askiitians.com | 2021.25 | [
{
"text": "nothing has been published regarding eml's this year but i hope there ll b eml's this year as some of the institutes are going to use the iit jee ranks as the basis of admissions",
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] |
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ce5ef866acd02bd204e51ca45f102cbe | given m1=300g , m2=600g the system is released from rest. after 2 seconds the larger mass (m2) is stopped. find the time elapsed before the string is taut again ?? | askiitians.com | 2021.43 | [
{
"text": "hello ashray...! probably the answer of this question should be 2 seconds... firstly you have to find the force due to tension of the strings...well, after that u must find out the displacement and acceleration of the string...and then apply the 2nd equation of motion i.e., s=ut+1/2at²...where u=0 and a=3.26(after my calculating)...by this u get the answer which is 2 seconds...!",
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4d7e7c2081a21d1ded63ae9b00b94514 | if y = tan ^-1 (secx + tan x). find d^2y/dx^2 at x = π/4 | askiitians.com | 2021.43 | [
{
"text": "dear student dy/dx = [1 /1 + (secx + tanx)² ][secx tanx + sec²x] dy/ dx = sec x(secx + tanx) /(1+ sec² x + tan²x + 2secx tanx) dy/dx = sec x(secx + tanx) / 2secx ( secx + tanx) dy/dx = ½ hence d²y /dx² = 0",
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},
{
"text": "y=tan-¹(secx+tanx)y=tan-¹((1+sinx)/cos)y=tan-¹((sinx/2+cosx/2)/(cosx/2-sinx/2))y=tan-¹(tan(pi/4+x/2)y=pi/4+x/2dy/dx=1/2d²y/dx²=0",
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}
] |
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90557c12c13b394cb049d3000b3231b5 | in the given figure when the switch s is closed the current through all the branches are | askiitians.com | 2021.25 | [
{
"text": "ans;0 through all branches solution; when the switch is closed the potential difference between all the resistors is 0.hence current won’t flow through any resistors or we can say that all the resistors are short circuited. hope u liked the solution",
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7ecbc8b6d4c188f8840d5a2c9110cc1d | rewrite the following rational numbers in the simplest form: -8/6 | askiitians.com | 2021.31 | [
{
"text": "dear student the given rational numbers can be simplified further, then, = -4/3 …[∵divide both numerator and denominator by 2] thanks",
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a58168f14a64d9076492cd29fad57f14 | i really cannot understand where 1 should be substitued by i^2 and where it should be substituted by(w+w^2).the attachment is attached herewith. | askiitians.com | 2021.43 | [
{
"text": "if you have an equation: f(x) = a.x 2 +bx+c, it can always written as f(x) = [x - (-b+(b 2 -4ac) 1/2 )/2a] * [x + (-b+(b 2 -4ac) 1/2 )/2a] – (1), in first equation roots will be +i and -i, in second equation the roots will be w and w 2 . verify this by putting values of a,b,c in eq(1). normally for problems that have cubic powers, you have to use (1,w,w 2 ) to substitute 1, as i 3 is not equal to 1.",
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e8e4974e9807c4545e99d72c369c4c08 | sir do u have any idea about tmh physics for jee mains 2016 only | askiitians.com | 2021.21 | [
{
"text": "you should prefer cengage pubilications over tmh...",
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] |
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46ca1570dcd0bb4e57bcc2c8be700616 | dear sir i want to know that how many marks required for take admisson in dce(delhi college of eng.) if i get 15000 rank in aieee am i eligible for it sir please tell me in detail | askiitians.com | 2021.25 | [
{
"text": "yes all those candidiates who clear the aieee exam are eligible for applying in dce. u just have to deposit an extra amount of fees of 1000 rs through challan for more details refer the link given below http://www.dtuadmissions.nic.in/documents2011/4.admission%20procedure.pdf",
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{
"text": "i request all candidates who had not get admission in 1st list at dtu, just go at www.dtuadmissions.nic.in , and check the list of seats vacant after 1st round. you will be pleassantly shocked that about 50% of the total seats are still vacant. most surprising is that 56 out of total 73 seats of delhi general category in cse are vacant. just chill u guys, 2nd list cutt off at dtu would be around 16000 and delhi general candidates with about 4250 raks would be getting cse in 2nd list itself",
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] |
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ef5407987842b95db36596b6aec09ae9 | sir.........its not clear from the given link about the opening and closing ranks of nits for general students in the site......so i wanted to know with what rank can we expect to get into nit suratkal....?????? | askiitians.com | 2021.21 | [
{
"text": "dear siddhartha chemical engineering 2792- 7195 civil engineering 3514 7417 computer engineering 756 2201 electronics & communication engineering 79 - 1893 electrical & electronics engineering 2067 - 3419 information technology 2676- 4232 mechanical engineering 1757 -4392 mining engineering 9500 -12514 metallurgy and materials engineering 8274 - 10685 all the best regards badiuddin",
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e72e3d1dd0c1b0e73f26627160d9c918 | this doubt is not related with studies, i just wanted to know as to how to build up the mind to sit and study with concentration for 12 hrs a day. | askiitians.com | 2021.21 | [
{
"text": "see the truth is that you can’t . what i mean to say is that you cannot study for 12 hours in one go ,it requires practice and method to build enough stamina to perform this task. first of all if you do not have habit of studying for long then start with this method – 1)study with studying for 2 and that also not in continuity but taking 5 min of break after studying for every 25 min. 2) gradually increase the time by an hour every week 3) after 21 days it starts becoming your habit to study without getting much distracted and in about 3 months you will be able to study for 12 hours or at least for 10 hours 3)for making up your mind to sit and study then you are the only one who can push yourself but after one week of doing this you will able to feel the differences , this is my personal experience 4) last but not the least. stay away as much as you can from social sites , ipad , mobile etc or at least minimize their use as they distract your mind and you end up losing concentration . best of luck :):):):)",
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1a7ff4705a6f30bfd9b55cc940b179c5 | iit advance 2015 rank 1736,suggest branch with college. | askiitians.com | 2021.31 | [
{
"text": "hi many congratulations to you for your results. you can refer to the following link for your query : http://www.askiitians.com/iit-jee/advanced/opening-cl",
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c593266efa125737108aa18dd01bda24 | i am a girl student from orissa. i am getting all branches at nit, rourkela. i am in a dilemma regarding what to choose from the following branches: cse or electrical or ece or electronics and instrumentation or mechanical please suggest which will be better from career, placement and future prospects . | askiitians.com | 2021.39 | [
{
"text": "dear payal, check out the order given below: cse > electrical = ece > mechanical > electronics and instrumentation. best is cse .. try for that. please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. askiitians expert amit yadav now you can win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian.",
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7090c4e30f4ad4afd606ff907f494349 | a cell develops the same power across 2 resistance r1 and r2 separately the internal resistance of the cell is | askiitians.com | 2021.25 | [
{
"text": "dear student let r be the internal resistance of the cell and e its emf. when connected across the resistance r 1 in the circuit, current passing through the resistance is i = e/r 1 + r so, p 1 = i 2 r 1 = [e/(r 1 +r)] 2 r 1 similarly p 2 = [e/(r 2 +r)] 2 r 2 given that p 1 = p 2 substituting the values, we get, r = √(r 1 r 2 ) regards arun (askiitians forum expert)",
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3dcd26249a5d5236c0c209f9c5f98033 | is there any differents between ncert and cbse books for class 11 &12 | askiitians.com | 2021.39 | [
{
"text": "no bro ncert books are the books prescribed by the cbse itself. if u are preparing for any exam always read ncert",
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{
"text": "ncert books are the books prescribed by the cbse itself. if u are preparing for any exam always read ncert. ncert solutions are available on askiitians.com also. you can refer this link – http://www.askiitians.com/school-exams/cbse/ncert-solutions.html",
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"is_accepted": false
},
{
"text": "ncert books are in no way different from cbse books as these books are prescribed by cbse itself as their course books. ncert books are always a great help in cbse board exams, iit-jee and other competitive level exams.to understand basic concepts about any subject, ncert is the best choice.",
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1e790470f0441582811885f8fe136810 | defining and testing custom made dft functionals? | askiitians.com | 2021.43 | [
{
"text": "depending on what you're after, you might want to look for programs usinglibxc, so you can completely define your own functionals. from the libxc section of the octopus wiki, these include: abinit– plane-wave code ape– an atomic code atomistix toolkit– numerical orbitals code atompaw– projector augmented wave functions generator bigdft– wavelet code cp2k- a program to perform atomistic and molecular simulations of solid state, liquid, molecular, and biological systems. dp– dielectric properties, a linear response tddft code elk– fp-lapw code erkale– a dft/hf molecular electronic structure code based on gaussian orbitals exciting– fp-lapw code gpaw– grid-based projector-augmented wave method jdftx– plane-wave code designed for joint density functional theory molgw- a small, but accurate mbpt code for molecules octopus– real-space (td)dft code yambo– solid state and molecular physics many-body calculations code on a more personal note, and this is just my opinion, if you're just arbitrarily mixing functionals, you should really make sure you have a scientific justification for doing this, otherwise you're just generating numbers without basis.",
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634a554321e11ca26cd583c2fd85a1e3 | how can we find the ph of 0.5m naoh of volume 500ml, 0.6m hcl of volume 600ml, 900ml of water | askiitians.com | 2021.25 | [
{
"text": "find the millimoles of hcl and millimoles of naoh(no.of moles * volume). you will find hcl is in larger quantity. subtract millimoles of naoh from millimoles of hcl and divide it by total volume of the solution in litre. then take the negative log of the resultant.",
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ac46c8f510d055bcf79a14df48c0515d | q. the charge per unit length of four quadrant of the ring of radius r is 2 lambda, -2 lambda, 1 lambda and -1 lambda respectively. the electric field at the centre is (a) - (lambda/2pie epsilon r) i cap (b) (lambda/2 pie epsilon r) j cap (c) (square root (2)lambda/4 pie epsilon r) j cap (d) none of the above | askiitians.com | 2021.21 | [
{
"text": "first draw the net force of electric field due to each segment of ring. every sector of charge q(=lambda) will exert a net force f in the direction of 45 degrees with the x-axis.(the +ve x-axis is towards your right>>>) the net force after each force cancels is 2fcos45 along negative x-axis. therefore a) is the answer.",
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4a85e75f7e291b1fbf4cd336e1112a2d | if i opt to take ece as my branch..then which iit campus should i choose which is giving me this opportunity? my expected score is 213/366 for jee advanced | askiitians.com | 2021.25 | [
{
"text": "rank = 10001-20000 marks = 190-218 with this iit kanpur and iit roorkee are possible",
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] |
|
6037de856d00b726434c2e58d1329f08 | what should be the order: mechanical iit rooorkee, production and industrial iit delhi, electrical in iit roorkee | askiitians.com | 2021.25 | [
{
"text": "production and industrial iit delhi mechanical iit rooorkee electrical in iit roorkee",
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}
] |
|
58b63fbbe11b41ab8cd11933b5682d06 | what is isomerism and resonance effect? what is metamerism? | askiitians.com | 2021.21 | [
{
"text": "isomerism is the phenomenon whereby certain compounds, with the same molecular formula, exist in different forms owing to their different organisations of atoms. the concept of isomerism illustrates the fundamental importance of molecular structure and shape in organic chemistry. the effect is used in a qualitative way and describes the electron withdrawing or releasing properties of substituents based on relevant resonance structures and is symbolized by the letter m. the mesomeric effect is a permanent effect and operates in compounds containing at least one double bond and another double … in colorimetry, metamerism is the matching of the color of objects as humans perceive them without matching their spectral power distribution. colors that match this way are called metamers.",
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61dc0b05c9d4701b87137849f598be67 | when we differentiate any f`n likef2x+7) than why we differentiae f`n seperately 2x+7 | askiitians.com | 2021.31 | [
{
"text": "h(x)=f(g(x)) h'(x)=f'(g(x))*g'(x) it is called chain rule of differentiation h(x)=f(2x+7) h'(x)=f'(2x+7)*2x, sher mohammad askiitians, faculty b.tech, iit delhi",
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b5473aaff95d51bf3b662e6166c6a3c7 | parabola part 4 doubts | askiitians.com | 2021.39 | [
{
"text": "try finding the centre and radius of the circle. (centre is negative and passes through origin). also, find the point of intersection of circle and parabola, which will give 2 values. one is zero and other in terms of lambda. but from the figure, it can be deduced that both intersect at only origin. hence, equate the one value in terms of lambda to zero and get the value of lambda.",
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{
"text": "i am not getting the answer....i have attached my approach sheet also along with the question....please look into that and tell me what is wrong.....and please give me the answer....",
"name": "",
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},
{
"text": "why tangent? it would take you more time to solve the eqn. completion of squares of eqn of circle will give you centre and radius. (-2l,0) and radius(2l) solve for points of intersection of circle and parabola, to get the solution: x=0,-8-4l as only point lies where both intersect i.e. at origin. so -8-4l=0 and the value of l from here is not far off...",
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] |
|
fcf5963f40ea035bcd397210bd070710 | 2. hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. what mass of oxygen gas would be required to react completely with 3 g of hydrogen gas? | askiitians.com | 2021.43 | [
{
"text": "it is given that the ratio of hydrogen and oxygen by mass to form water is 1 : 8. then, the mass of oxygen gas required to react completely with 1 g of hydrogen gas is 8 g. therefore, the mass of oxygen gas required to react completely with 3 g of hydrogen gas is 8 × 3 g = 24 g.",
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}
] |
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70e18e9f7851ee0e6650fdf2e6045420 | apolar neurons are found in?a.white matter of brain b.grey matter of brain c.endoderm of hydra d.mesoderm of hydra | askiitians.com | 2021.39 | [
{
"text": "inhydrozoaandanthozoa, interstitial stem cells from the endoderm generateneuroblastsand nematoblasts which migrate to the ectoderm and provide for the formation of the nervous system along theanterior-posterioraxis. non-hydrozoa lack interstitial stem cells, and the neurons arise fromepithelial cells, which are most likely differentiated from the ectoderm as occurs invertebrates. differentiation occurs near theaboralpore and this is where most neurons remain.",
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33543b5c67b053bc51a3bb8c6a742034 | you spill a bucket of soapy water on a marble floor accidently. would it make it easier or more difficult for you on the floor? why? | askiitians.com | 2021.31 | [
{
"text": "dear student the layer of soap makes floor smooth due to which the friction is reduced and the foot cannot make a proper grip on the floor. therefore it is difficult to walk on a soapy floor and we start to slip on the floor. thanks",
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] |
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588de6c9e774f3dc0f536ca9a7e671d8 | i am sorry for posting all that trash. i promise that i will never do it again. i sincerly apologise lavanya for using her name. i also apologise swetha. yours sincerly a true friend. | askiitians.com | 2021.21 | [
{
"text": "it’s alright.please don’t repeat that again.",
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|
885574d84b0fca35e48b49f66928719f | please can i get explanation to the concept behind the question.. | askiitians.com | 2021.21 | [
{
"text": "",
"name": "",
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},
{
"text": "@ amit the question deals with the electric field intensity in a spherical chrged shell . u can calculate it by applying the formula e= rho *i / 3 e0 where e0 is the permittivity of free space and rho is the resisitivity of the spherical shell . keep in mind that inside the shell the electric field are 0 and only its exist in between and outside of the shell . hope it clears your doubt if u want the solution then let me know ,",
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|
9a24471b26c00f9fd5622892b0c4547d | the refractive index of air w.r.t. glass is 2/3. the refractive index of diamond w.r.t. air is 12/5. then the refractive index of glass w.r.t. diamond will be? | askiitians.com | 2021.39 | [
{
"text": "refractive index of air w.r.t to glass is 2/3=mu1 refractive index of diamond w.r.t air is 12/5=mu2 refractive index of glass w.r.t diamond=refractive index of air w.r.tdiamond/refractive index of air w.r.t glass mu2/mu1=mu mu=5/12/2/3 mu=5/8",
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] |
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cdec9842e1f43491633f0bd165ea7945 | the number of permutations by taking all letters and keeping the vowels of the word combine in the odd places is (a) 96 (b) 144 (c) 512 (d) 576 | askiitians.com | 2021.21 | [
{
"text": "the required number of ways can the letters of the word 'therapy' be arranged so that the vowels never come together = 7! - (6! x 2!) ways = 5040 - 1440 = 3600 ways.",
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f65df0573d520d413c1c0374dc78ff88 | i want to get admitted into some engineering college. please let me know about iit jee form and applications in dubai? | askiitians.com | 2021.21 | [
{
"text": "hi, there are many top engineering colleges in india which cater to the need to indian origin students. please also check engineering colleges and exams in south india . the students in uae and middle east region can apply online for iit jee/aieee and aipmt exams. for iit jee form and applications in dubai , you need to visit askiitians website. the govt. of india has made this provision, so if you want, you can keep your test centre in dubai. thanks sunil",
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cba977990bc2e55f465c7f97f0ee5979 | question: what is redox reaction? explain with one example | askiitians.com | 2021.39 | [
{
"text": "an oxidation-reduction(redox)reactionis a type of chemicalreactionthat involves a transfer of electrons between two species.an oxidation-reduction reactionis any chemicalreactionin which the oxidation number of a molecule, atom, or ion changes by gaining or losinganelectron. the formation of hydrogen fluoride is an example of a redox reaction. we can break the reaction down to analyze the oxidation and reduction ofreactants. the hydrogen is oxidized and loses two electrons, so each hydrogen becomes positive. h2+2f→2hf",
"name": "",
"is_accepted": false
},
{
"text": "an oxidation-reduction ( redox ) reaction is a type of chemical reaction that involves a transfer of electrons between two species. an oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron. the formation of hydrogen fluoride is an example of a redox reaction. we can break the reaction down to analyze the oxidation and reduction of reactants . the hydrogen is oxidized and loses two electrons, so each hydrogen becomes positive. h 2 + 2 f → 2 h f",
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] |
|
eebab1091ecd75c59bde2114236be28a | what's the stratagy for scoring more & more marks in iit jee? | askiitians.com | 2021.39 | [
{
"text": "dont just guess, do only that question which u know!! and without knowing nothing can be solved, so study well!",
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}
] |
|
2aeb613aa3ecabcbc8a3da2a71887b1e | wat college i should refer??? | askiitians.com | 2021.43 | [
{
"text": "can u please tell me u are asking for college regarding which field?",
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] |
|
c8d4d9b299a3adc2efa95e8ddb899a0a | please reply me soon???? | askiitians.com | 2021.43 | [
{
"text": "dear gaurav, the most scoring topics in physics in my knowledge would be waves, modern physics, heat, circuits etc. the preparation of these topics would take relatively lesser time than other topics and the level of hardness of questions of these topics is relatively lower than other topics in jee. please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best gaurav. regards, askiitians experts vinayak",
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daf5a4e82ff27db09f3189c0da48ef08 | hello sir sir i m getting 253 marks according to the latest jee key but i am afraid about one thing. while filling the ors is erased many bubbles n refilled them. i jst want to ask that if this can affect my score. my bubbling was quite neat. | askiitians.com | 2021.21 | [
{
"text": "dear abhishek, don't worry, u r in heaven now!!!!!!!!!!! it won't affect ors reader much, authority know, how much u worked hard for iit!!!!!!!! good luck!!!!!!!!!! plz. approve by clicking 'yes' given below!!!!!!! plz. plz. plz.!!!!!!!!",
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|
1192fa3c192711141ade87e1d4168916 | defination of ampere’s law???????????????????????????????????????????????????????//// | askiitians.com | 2021.39 | [
{
"text": "amperes law states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.",
"name": "",
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{
"text": "hello prabhakar ampere's law . the magnetic field in space around an electric current is proportional to the electric current which serves as its source, just as the electric field in space is proportional to the charge which serves as its source.",
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{
"text": "ampere's law states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.",
"name": "",
"is_accepted": false
},
{
"text": "hallo prabhakarampere's law . the magnetic field in space around an electric current is proportional to the electric current which serves as its source, just as the electric field in space is proportional to the charge which serves as its source.",
"name": "",
"is_accepted": false
},
{
"text": "hello prabhakar, ampere’s law means the magnetic field in space around an electric current is proportional to the electric current which serves as its source, just as the electric field in space is proportional to the charge which serves as its source .",
"name": "",
"is_accepted": false
},
{
"text": "ampere's law states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop",
"name": "",
"is_accepted": false
},
{
"text": "the integral of a magnetic field in the direction of the path is equals to “mue not”times the current intercepted bythe area.................................................................",
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},
{
"text": ". ampere’s law: the magnetic field in space around an electric current is proportional to the electric current which serves as its source, just as the electric field in space is proportional to the charge which serves as its source",
"name": "",
"is_accepted": false
},
{
"text": "prabhakar ampere’s law is defined as the states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.",
"name": "",
"is_accepted": false
},
{
"text": "the amperes law defined as for closed loop the line integral of product of the magnetic field and displacment.it is equals to muenot i means current.",
"name": "",
"is_accepted": false
},
{
"text": "dear prabhakrar......... ampère's circuital law , discovered by andré-marie ampère in 1826, relates the integrated magnetic field around a closed loop to the electric current passing through the loop.…....",
"name": "",
"is_accepted": false
},
{
"text": "the line integral of the magnetic field in any closed path is m 0 times of the current passing through the closed path",
"name": "",
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}
] |
|
e2ef5797f43bdd02522a9171781de0e3 | what are the different laws of friction? | askiitians.com | 2021.43 | [
{
"text": "laws of friction 1. laws of static friction static friction force is always equal and opposite to the net external force acting on the body. 2. laws of limiting friction (i) limiting frictional force is independent of the apparent area of contact till the value of the normal reaction remains same. (ii) the direction of limiting frictional force is opposite to the direction in which one body is on the verge of starting its motion. (iii) the limiting frictional force depends upon the nature of surfaces in contact. (iv) quantitatively, the magnitude of the force of limiting friction (f) on one of the two bodies in contact, is directly proportional to the normal reaction (r) on this body due to the other. f µ r or f = m r where m is the constant of proportionally called coefficient of friction.",
"name": "",
"is_accepted": false
},
{
"text": "the laws of friction are: 1) it always acts in the direction opposite to the tendency of relative motion b/w two bodies 2) its magnitude can be any <un 3) if we consider the rotational motion, then static friction opposes the direction of net force while kinetic opposes direction of relative motion",
"name": "",
"is_accepted": false
}
] |
|
f82ab017f08cc94480e8bb1c9193ea85 | how flowering and fruit ripening habitat occure in plants seasonwise | askiitians.com | 2021.43 | [
{
"text": "due to regulation of plant hormone florigen and certain pgrs. it is also due to photoperiodism, which is the response of plants to periods of day/night.",
"name": "",
"is_accepted": false
},
{
"text": "atmospheric condition tus secretion of particular hormonr results in the ipenong differently",
"name": "",
"is_accepted": false
},
{
"text": "please approve if my answer is correct.",
"name": "",
"is_accepted": false
}
] |
|
1910856ad3de65f58373806378d0c521 | sir, can u help me solving this one... a short electric dipole of moment p is placed in a uniform electric field of e 0. in this case, one of the eqipotential sufaces enclosing the dipoles makes a sphere. find the radius of such sphere | askiitians.com | 2021.25 | [
{
"text": "i thnk the radius of the sphere enclosing the dipole will be dependent on how big the sphere is i.e. whether it just takes in the dipole exactly at its terminal points i.e. the lenght 2a is the diameter of the sphere , then the radius will be a. or else the radius can be found out only when the potential at that surface is given alog with the charge in the dipole.......",
"name": "",
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}
] |
|
77a25b0707602286db8e91e7b6434bc0 | heat of neutralisation of a strong acid and strong base is always a. 13.7 kcal/mol b. 9.6 kcal/mol c. 6 kcal/mol d. 11.4 kcal/mol | askiitians.com | 2021.21 | [
{
"text": "enthalpy of neutralisation:- it is the enthalpy charge that takes place when 1g-equivalent of an acid (or base) in neutralised by 1 g-equivalent of a base (or acid) in dilute solution. the enthalpy of neutralization of any strong acid and strong base is always constant, i.e. 57.1 kj because both the acid and base undergo complete ionization.",
"name": "",
"is_accepted": false
},
{
"text": "∵δg∘=δh∘−tδs∘ ∴δh∘ for h2o⇔h++oh− is+13.7kcal ∴δs∘=δh∘−δg∘ / t =(+13.7+19.14)/298=110.2calk^−1mol^−1 …....................................................",
"name": "",
"is_accepted": false
}
] |
|
cd618b88a95946974e64e5ff3d88ed6c | what is the refractive index? | askiitians.com | 2021.25 | [
{
"text": "the ratio of the velocity of light in a vacuum to its velocity in a specified medium.",
"name": "",
"is_accepted": false
}
] |
|
38c27e917b96aaef077973545219225a | eml | askiitians.com | 2021.21 | [
{
"text": "there is no question here..",
"name": "",
"is_accepted": false
}
] |
|
4d67ed5dd885cbcb5d29ea869c9090bb | in a lottery 10000 tickets are sold and ten prizes are awarded..what is the probability of not getting a prize if you buy two tickets..?????? | askiitians.com | 2021.25 | [
{
"text": "probabilty of not getting a prize = no. of tickets which doesnt have a prize/ total tickets = 9990 = 10000 = 0.999 thanks bharat bajaj iit delhi askiitians faculty",
"name": "",
"is_accepted": false
}
] |
|
c01494482dae9050d7e8e11eab38f133 | if , & are in ap., 2 = hint cot = cot ---------- 2>please help out with this problem | askiitians.com | 2021.31 | [
{
"text": "dear student, whats the question? what do we have to find out ? thanks",
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"is_accepted": false
}
] |
|
95e0097271f4e272f6b15fb79638a4fa | dear sir/madam, please tell me who is the discoverer of trinomial taxanomy-huxley stricklandt or lamarck or both | askiitians.com | 2021.31 | [
{
"text": "the trinomial system was proposed by huxley and stricklandt.according to this system name of any plant or species is composed of three names (i) generic name (ii) specific name (iii) subspecifie name (name of variety). when members of any species have large variations then trinomial system is used. on the basis of dissimilarities this species is classified into subspecies.",
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] |
|
554bc83e244d32ca461f68784034b527 | two small magnets each of magnetic moment 10a-m^2 are placed in end on position 0.1m apart from their centres. the force acting between them will me? 0.6n 0.06n 0.06*10^7 n 0.6*10^7 n. [ap ch8 pg 76 q59] | askiitians.com | 2021.39 | [
{
"text": "formula for force bt parallel placed magnet f=mo/4π(6m1m2/r4) no=4π×10^-7 therefore f=10^-7(6×10×10/(0.1^4)=0.6n",
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"is_accepted": false
}
] |
|
c8f1142cb4a83e4b92f5da95e3c8a130 | pls tell me if uicet is a good college to take admission in terms of its faculty & placements?what is its rank amongst chemical engg. colleges in india? | askiitians.com | 2021.25 | [
{
"text": "hi the institutions listed below (in alphabetical order) have built up reputations for producing top notch chemical engineers: alagappa chettiar college of technology (ac tech.), anna university, chennai annamalai university, annamalai nagar, tamilnadu birla institute of technology & science (bits), pilani, rajasthan department of chemical engineering panjab university(since 1958) indian institute of technology, chennai indian institute of technology, kanpur indian institute of technology, mumbai lakshminarayanan institute of technology, nagpur regional engineering college, trichy, tamilnadu university department of chemical technology (udct), mumbai there is good placement of chemical engineering graduates in chemical and alliedindustries. a large number of reputed companies in chemical and allied areas visit the institute forcampus placements, and employ their graduates. many of the fortune 500 companies have visited the institute and recruited their students. some of the companies who have visited the institute are: shell technip bechtel flour corporation pepsico indian oil cadbury samsung engineering eil lurgi india essar oil dscl energy jubilant indian acrylics evalue serve accenture infosys wipro ranbaxy triveni engineering trident wrigley itc amul uop l&t reliance the packages offered varied from 2.8 lacs to 11.5 lacs p.a.",
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|
9388a9f715c88ba6ceb236c5da72d0fc | how difficult will be the exam level of 2019 jee and neet exams | askiitians.com | 2021.25 | [
{
"text": "that exam was not so hard.it depends on you how you take that exam as a burden or for your future. jee and neet exams are not hard.this was our feeling that makes it hard or easy. if you work hard ;you will really got success in your future means 2019 jee and neet exams",
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] |
|
a39f07e92d4f35bbb413437bf3d568d4 | how many types of silicones are there?what are they? | askiitians.com | 2021.43 | [
{
"text": "there are 3 types of silicones they are 1.straight chain 2.cyclic and 3.cross linked silicones",
"name": "",
"is_accepted": false
},
{
"text": "there are three types of sillicones: 1.straight chains 2.cyclic 3.cross linked",
"name": "",
"is_accepted": false
}
] |
|
4a19f20cebf8f0d0ebca3b0bc86138ed | if 2(acosx-cos2x)=1 for x belongs to r then find all the possible real values of a. | askiitians.com | 2021.39 | [
{
"text": "2acosx-2cos2x-1=0 2acosx-2(2cos 2 x-1)-1=0 4cos 2 x+2acosx+1=0 for real roots d greater then equal to zero 4a 2 -16>=0 a 2 >=4 so a greater then equal to 2 or less then equal to -2. thanks & regards sunil raikwar askiitians faculty",
"name": "",
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] |
|
fab617884433ec900d6f99521ef84668 | the potential energy of an occilator of mass 2 kg in its mean position is 5 joules...if its total energy is 9 joules and apmlitute of 0.01 m....its tym period is????? | askiitians.com | 2021.43 | [
{
"text": "the potential energy of the paricle is 5 joules at the mean pos.(with reference to an arbitary refrence point). with reference to same arbitary refrence point , the total energy of the particle is 9 joules. so the kinetic energies at the mean pos. = 9j -5j = 4 joules at the amplitude the all the kinetic energy will convert into spring potential energy 4 joules = (1/2)kx 2 = (1/2)*k(0.01) 2 k = 8*10 4 time period is 2pi (m/k) 1/2 = 2pi (2/8*10 4 ) 1/2 = 2pi(0.25*10 -4 ) 1/2 = 2 pi (0.5*10 -2 )=3.14*10 -2 s",
"name": "",
"is_accepted": false
}
] |
|
4df91b677884faf40382d05d30c2727a | two particles are released from the same height at an interval of 1s. how long after the first particle begins to fall will be the two particles be 10m apart? 1. 1.5s 2. 2s 3. 1.25s 4. 2.5s | askiitians.com | 2021.31 | [
{
"text": "let the objects be o1 and o2,when the given situation appears, let s1=x , therefore s2=x-10. let t2=t, since o1 started 1s earlier,therefore t1=t+1.☺ now since s=ut+at^2/2 => s=at^2/2 (as u=o).➡eq1: x=9.8×(t+1)^2 /2 & eq2: x-10=9.8×t2 /2 . now eq1-eq2 => +10=9.8(t2+1+2t)/2 - 9.8×t2 /2 => 10=9.8(t2+1+2t-t2) /2 => 20=9.8+19.6t => 10.2/19.6=t => t=0.5(approx.)😆 therefore time take for the process= t+1 =1+0.5=1.5s✒",
"name": "",
"is_accepted": false
}
] |
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f37117830a3b6ec79466c1c755b18798 | sir,i have joined aeronautical engineering at hits,chennai.what are the job oppurtunities in that branch.will there be good placements in this branch in this college.will aerospace engineering be a good option than aeronautics? please reply... reply required urgently | askiitians.com | 2021.39 | [
{
"text": "dear gautam, both the option are options are very good .. jus go with wat interests you more. please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. all the best. regards amit - it bhu",
"name": "",
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] |
|
3d6a8653d14ad7034a8bc5f99e3a4e42 | which is the top 25 colleges in our india | askiitians.com | 2021.25 | [
{
"text": "indian institute of technology iit - kharagpur indian institute of technology iit - kanpur indian institute of technology iit - mumbai indian institute of technology iit - delhi indian institute of technology iit - chennai bits - pilani indian institute of technology iit - roorkee indian institute of technology iit - guwahati it- bhu college of engg, anna university indian school of mines university bit , mesra jadavpur university , faculty of engg & tech - calcutta psg college of technology - coimbatore delhi college of engineering nit - national institute of technology - trichy thapar inst of engineering & technology - patiala nit - national institute of technology - warangal nit - national institute of technology - suratkal punjab engineering college - chandigarh bengal engineering and science university - howrah indian institute of technology iit - hyderabad mumbai university institute of chemical technology netaji subhas institute of technology - new delhi indian institute of information technology - allahabad national institute of technology - calicut motilal nehru national inst. of technology - allahabad malaviya national institute of technology - jaipur the national institute of technology - kurukshetra visvesvaraya national institute of technology - nagpur harcourt butler technological institute - kanpur maulana azad national institute of technology - bhopal rv college of engineering - bangalore sardar vallabhbhai national institute of technology - surat andhra university college of engineering - visakhapatnam college of engineering - pune veermata jijabai technological institute - mumbai national institute of technology - rourkela coimbatore institute of technology - coimbatore thiagarajar college of engineering - madurai college of engineering - thiruvananthapuram national institute of technology - durgapur dhirubhai ambani institute of info & comm tech - gandhinagar alagappa institute of information technology - karaikudi vellore institute of technology - vellore govt college of technology - coimbatore ssn college of engineering - chennai sardar patel college of engineering - mumbai dr b r ambedkar national institute of technology - jalandhar jawaharlal nehru technological university ( jntu ) - hyderabad",
"name": "",
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}
] |
|
d209aff157a1a87ea5dc6d046f85ea4f | multiple choice: susan pushes against a 100 kilogram rock with a force of 5 newtons, but the rock doesnt move. the force the rock exerts on susan is w) 0 newtons x) 5 newtons y) 20 newtons z) 100 newtons | askiitians.com | 2021.25 | [
{
"text": "answer: x -- 5 newtons",
"name": "",
"is_accepted": false
}
] |
|
672e9f812db51238e8927a17021df200 | does ncert books is enough for jee main and advanced ?? | askiitians.com | 2021.39 | [
{
"text": "definitely not ncert books are not enough to crack jee advanced however you can score good in jee mains but make concepts clear and math is a subject of practice, the more you practice, the more you achieve. so dont rely on ncert only.",
"name": "",
"is_accepted": false
}
] |
|
e9495637c9488b44a63645b2dc370872 | i want the easy and valuable(get a good score in jee) method of studying physics.....can anyone please help....... | askiitians.com | 2021.25 | [
{
"text": "dear tapasranjan only method to improve your score is more hard work. you should give more stress to those topics in which you feel difficulty. or in which you are not much confident.and at the same time you should keep revising other topic also. first you should refer h c verma and resnick & halliday for the theory part .and see the solved example and then try to solve excersice problem.after that you should see the previous years iit jee problem based upon this topic..try to solve as much problem as you can . and do not waste your time in solving question that are very difficult .many peaople frame such a question which are not a part of iit jee syllabus.and it is just a wastage of time. just stay calm and focus on understanding rather than mugging. be regular in class and stay with concepts please feel free to post as many doubts on our discussion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee & aieee preparation. all the best. regards, askiitians experts badiuddin",
"name": "",
"is_accepted": false
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] |
|
f214576da45b2c3584c5e0e05da7b689 | i will get elec engg at iit hyderabad and ocean engg at madras..which option is better?? im more interested in ee than ocean engg | askiitians.com | 2021.39 | [
{
"text": "dear akhil, you should always give preference to stream before branch. as you are getting electrical engineering with new iits & ocean engineering with old iits, then i will suggest you to go for electrical engineering with iit hydrabad because it is one of a best stream & moreover you are interested for this . please feel free to post as many doubts on our disucssion forum as you can. if you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. we are all iitians and here to help you in your iit jee preparation. all the best. manisha sharma",
"name": "",
"is_accepted": false
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] |
|
5fc228a246d813fe94fe37fbe78780bd | how many five digits numbers are there out of which all are odd? | askiitians.com | 2021.21 | [
{
"text": "dear student as we odd digit are = 1, 3, 5, 7, 9 now we have to use them to make a 5 digits number. case 1- repetitions allowed 5 *5 *5 *5 *5 = 5 5 case 2- repetitions not allowed 5* 4* 3* 2* 1 = 5! = 120 regards arun(askiitians forum expert)",
"name": "",
"is_accepted": false
},
{
"text": "odd numbers are1,3,5,7,9,11",
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"is_accepted": false
}
] |
|
9394dac2de7e869ee6aa537548c291d9 | sir, what is expected aieee and uget2 cutoff for smit be branches this year? sanjoy | askiitians.com | 2021.31 | [
{
"text": "dear student, cutoff is 40% of the totalmarks.. best of luck..!!!! we are all iitians and here to help you in your iit jee preparation. win exciting gifts by answering the questions on discussion forum. so help discuss any query on askiitians forum and become an elite expert league askiitian. now you score 5+15 points by uploading your pic and downloading the askiitians toolbar : click here to download the toolbar.. askiitians expert sagar singh - iit delhi",
"name": "",
"is_accepted": false
}
] |
|
6f7de015b1297b3b4c57e0638fc46d48 | a fuse wire is made up of an alloy of materials having a low melting point.why the melting point should be low? | askiitians.com | 2021.31 | [
{
"text": "fuse is a safety deviece . it works on heating effect of electricity. it is a thin wire which has high resistance but low melting point when more current pass through it temperature increases and it break",
"name": "",
"is_accepted": false
}
] |
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