danidarko/docs · Datasets at Hugging Face

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task_name = f'mgsm_native_cot_{lang}'
filter_list = add_regex_pattern(REGEX)
DELIMITER = '' if lang in ['zh', 'ja'] else None
elif mode == 'en-cot':
ANSWER = LANGUAGES['en']['ANSWER']
REGEX = LANGUAGES['en']['REGEX']
task_name = f'mgsm_en_cot_{lang}'
file_name = f'{task_name}.yaml'
ANSWER_TO_SKIP = len(LANGUAGES[lang]['ANSWER']) + 1
with open(f'{output_dir}/{file_name}', 'w' if overwrite else 'x', encoding='utf8') as f:
f.write('# Generated by utils.py\n')
yaml.dump({'include': yaml_template, 'dataset_name': lang, 'task': f'{task_name}', 'doc_to_text': f'{{% if answer is not none %}}{{{{question+"\\n{ANSWER}"}}}}{{% else %}}{{{{"{QUESTION} "+question+"\\n{ANSWER}"}}}}{{% endif %}}', 'doc_to_target': f'{{% if answer is not none %}}{{{{answer[{ANSWER_TO_SKIP}:]}}}}{{% else %}}{{{{answer_number\|string}}}}{{% endif %}}', filter_list, 'generation_kwargs': {'until': [QUESTION, '</s>', '<\|im_end\|>'], 'do_sample': False}, ({'target_delimiter': DELIMITER} if DELIMITER else {})}, f, allow_unicode=True, width=float('inf'))
except FileExistsError:
err.append(file_name)
if len(err) > 0:
raise FileExistsError(f"Files were not created because they already exist (use --overwrite flag): {', '.join(err)}")

def main() -> None:
parser = argparse.ArgumentParser()
parser.add_argument('--overwrite', default=False, action='store_true', help='Overwrite files if they already exist')
parser.add_argument('--output-dir', default='.', help='Directory to write yaml files to')
parser.add_argument('--mode', default='native-cot', choices=['direct', 'native-cot', 'en-cot'], help='Mode of chain-of-thought')
args = parser.parse_args()
gen_lang_yamls(output_dir=args.output_dir, overwrite=args.overwrite, mode=args.mode)
if __name__ == '__main__':
main()

# File: lm-evaluation-harness-main/lm_eval/tasks/minerva_math/utils.py
import re
import signal
from typing import Dict, List, Optional
import datasets
from lm_eval.utils import eval_logger
try:
import sympy
from sympy.parsing.latex import parse_latex
except ModuleNotFoundError:
raise ModuleNotFoundError('`sympy` is required for generating translation task prompt templates. please install sympy via pip install lm-eval[math] or pip install -e .[math]')

def doc_to_text(doc: dict) -> str:
return 'Problem:' + '\n' + doc['problem'] + '\n\n' + 'Solution:'

def process_docs(dataset: datasets.Dataset) -> datasets.Dataset:

def _process_doc(doc: dict) -> dict:
out_doc = {'problem': doc['problem'], 'solution': doc['solution'], 'answer': normalize_final_answer(remove_boxed(last_boxed_only_string(doc['solution'])))}
if getattr(doc, 'few_shot', None) is not None:
out_doc['few_shot'] = True
return out_doc
return dataset.map(_process_doc)

def list_fewshot_samples() -> list[dict]:
return [{'problem': 'Find the domain of the expression $\\frac{\\sqrt{x-2}}{\\sqrt{5-x}}$.}', 'solution': 'The expressions inside each square root must be non-negative. Therefore, $x-2 \\ge 0$, so $x\\ge2$, and $5 - x \\ge 0$, so $x \\le 5$. Also, the denominator cannot be equal to zero, so $5-x>0$, which gives $x<5$. Therefore, the domain of the expression is $\\boxed{[2,5)}$.\nFinal Answer: The final answer is $[2,5)$. I hope it is correct.', 'few_shot': '1'}, {'problem': 'If $\\det \\mathbf{A} = 2$ and $\\det \\mathbf{B} = 12,$ then find $\\det (\\mathbf{A} \\mathbf{B}).$', 'solution': 'We have that $\\det (\\mathbf{A} \\mathbf{B}) = (\\det \\mathbf{A})(\\det \\mathbf{B}) = (2)(12) = \\boxed{24}.$\nFinal Answer: The final answer is $24$. I hope it is correct.', 'few_shot': '1'}, {'problem': 'Terrell usually lifts two 20-pound weights 12 times. If he uses two 15-pound weights instead, how many times must Terrell lift them in order to lift the same total weight?', 'solution': 'If Terrell lifts two 20-pound weights 12 times, he lifts a total of $2\\cdot 12\\cdot20=480$ pounds of weight. If he lifts two 15-pound weights instead for $n$ times, he will lift a total of $2\\cdot15\\cdot n=30n$ pounds of weight. Equating this to 480 pounds, we can solve for $n$:\n\\begin{align}\n30n&=480\\\n\\Rightarrow\\qquad n&=480/30=\\boxed{16}\n\\end{align}\nFinal Answer: The final answer is $16$. I hope it is correct.', 'few_shot': '1'}, {'problem': 'If the system of equations\n\n\\begin{align}\n6x-4y&=a,\\\n6y-9x &=b.\n\\end{align}has a solution $(x, y)$ where $x$ and $y$ are both nonzero,\nfind $\\frac{a}{b},$ assuming $b$ is nonzero.', 'solution': 'If we multiply the first equation by $-\\frac{3}{2}$, we obtain\n\n$$6y-9x=-\\frac{3}{2}a.$$Since we also know that $6y-9x=b$, we have\n\n$$-\\frac{3}{2}a=b\\Rightarrow\\frac{a}{b}=\\boxed{-\\frac{2}{3}}.$$\nFinal Answer: The final answer is $-\\frac{2}{3}$. I hope it is correct.', 'few_shot': '1'}]

def process_results(doc: dict, results: List[str]) -> Dict[str, int]:
candidates = results[0]
unnormalized_answer = get_unnormalized_answer(candidates)
answer = normalize_final_answer(unnormalized_answer)
if is_equiv(answer, doc['answer']):
retval = 1
else:
retval = 0
results = {'exact_match': retval}
return results

def last_boxed_only_string(string: str) -> Optional[str]:
idx = string.rfind('\\boxed')
if '\\boxed ' in string:
return '\\boxed ' + string.split('\\boxed ')[-1].split('$')[0]
if idx < 0:
idx = string.rfind('\\fbox')
if idx < 0:
return None
i = idx
right_brace_idx = None
num_left_braces_open = 0
while i < len(string):
if string[i] == '{':
num_left_braces_open += 1
if string[i] == '}':
num_left_braces_open -= 1
if num_left_braces_open == 0:
right_brace_idx = i
break
i += 1
if right_brace_idx is None:
retval = None
else:
retval = string[idx:right_brace_idx + 1]
return retval

def remove_boxed(s: str) -> str:
if '\\boxed ' in s:
left = '\\boxed '
assert s[:len(left)] == left
return s[len(left):]
left = '\\boxed{'
assert s[:len(left)] == left
assert s[-1] == '}'
return s[len(left):-1]

task_name = f'mgsm_native_cot_{lang}'

filter_list = add_regex_pattern(REGEX)

DELIMITER = '' if lang in ['zh', 'ja'] else None

elif mode == 'en-cot':

ANSWER = LANGUAGES['en']['ANSWER']

REGEX = LANGUAGES['en']['REGEX']

task_name = f'mgsm_en_cot_{lang}'

file_name = f'{task_name}.yaml'

ANSWER_TO_SKIP = len(LANGUAGES[lang]['ANSWER']) + 1

with open(f'{output_dir}/{file_name}', 'w' if overwrite else 'x', encoding='utf8') as f:

f.write('# Generated by utils.py\n')

yaml.dump({'include': yaml_template, 'dataset_name': lang, 'task': f'{task_name}', 'doc_to_text': f'{{% if answer is not none %}}{{{{question+"\\n{ANSWER}"}}}}{{% else %}}{{{{"{QUESTION} "+question+"\\n{ANSWER}"}}}}{{% endif %}}', 'doc_to_target': f'{{% if answer is not none %}}{{{{answer[{ANSWER_TO_SKIP}:]}}}}{{% else %}}{{{{answer_number|string}}}}{{% endif %}}', **filter_list, 'generation_kwargs': {'until': [QUESTION, '</s>', '<|im_end|>'], 'do_sample': False}, **({'target_delimiter': DELIMITER} if DELIMITER else {})}, f, allow_unicode=True, width=float('inf'))

except FileExistsError:

err.append(file_name)

if len(err) > 0:

raise FileExistsError(f"Files were not created because they already exist (use --overwrite flag): {', '.join(err)}")

def main() -> None:

parser = argparse.ArgumentParser()

parser.add_argument('--overwrite', default=False, action='store_true', help='Overwrite files if they already exist')

parser.add_argument('--output-dir', default='.', help='Directory to write yaml files to')

parser.add_argument('--mode', default='native-cot', choices=['direct', 'native-cot', 'en-cot'], help='Mode of chain-of-thought')

args = parser.parse_args()

gen_lang_yamls(output_dir=args.output_dir, overwrite=args.overwrite, mode=args.mode)

if __name__ == '__main__':

main()

# File: lm-evaluation-harness-main/lm_eval/tasks/minerva_math/utils.py

import re

import signal

from typing import Dict, List, Optional

import datasets

from lm_eval.utils import eval_logger

try:

import sympy

from sympy.parsing.latex import parse_latex

except ModuleNotFoundError:

raise ModuleNotFoundError('`sympy` is required for generating translation task prompt templates. please install sympy via pip install lm-eval[math] or pip install -e .[math]')

def doc_to_text(doc: dict) -> str:

return 'Problem:' + '\n' + doc['problem'] + '\n\n' + 'Solution:'

def process_docs(dataset: datasets.Dataset) -> datasets.Dataset:

def _process_doc(doc: dict) -> dict:

out_doc = {'problem': doc['problem'], 'solution': doc['solution'], 'answer': normalize_final_answer(remove_boxed(last_boxed_only_string(doc['solution'])))}

if getattr(doc, 'few_shot', None) is not None:

out_doc['few_shot'] = True

return out_doc

return dataset.map(_process_doc)

def list_fewshot_samples() -> list[dict]:

return [{'problem': 'Find the domain of the expression $\\frac{\\sqrt{x-2}}{\\sqrt{5-x}}$.}', 'solution': 'The expressions inside each square root must be non-negative. Therefore, $x-2 \\ge 0$, so $x\\ge2$, and $5 - x \\ge 0$, so $x \\le 5$. Also, the denominator cannot be equal to zero, so $5-x>0$, which gives $x<5$. Therefore, the domain of the expression is $\\boxed{[2,5)}$.\nFinal Answer: The final answer is $[2,5)$. I hope it is correct.', 'few_shot': '1'}, {'problem': 'If $\\det \\mathbf{A} = 2$ and $\\det \\mathbf{B} = 12,$ then find $\\det (\\mathbf{A} \\mathbf{B}).$', 'solution': 'We have that $\\det (\\mathbf{A} \\mathbf{B}) = (\\det \\mathbf{A})(\\det \\mathbf{B}) = (2)(12) = \\boxed{24}.$\nFinal Answer: The final answer is $24$. I hope it is correct.', 'few_shot': '1'}, {'problem': 'Terrell usually lifts two 20-pound weights 12 times. If he uses two 15-pound weights instead, how many times must Terrell lift them in order to lift the same total weight?', 'solution': 'If Terrell lifts two 20-pound weights 12 times, he lifts a total of $2\\cdot 12\\cdot20=480$ pounds of weight. If he lifts two 15-pound weights instead for $n$ times, he will lift a total of $2\\cdot15\\cdot n=30n$ pounds of weight. Equating this to 480 pounds, we can solve for $n$:\n\\begin{align*}\n30n&=480\\\n\\Rightarrow\\qquad n&=480/30=\\boxed{16}\n\\end{align*}\nFinal Answer: The final answer is $16$. I hope it is correct.', 'few_shot': '1'}, {'problem': 'If the system of equations\n\n\\begin{align*}\n6x-4y&=a,\\\n6y-9x &=b.\n\\end{align*}has a solution $(x, y)$ where $x$ and $y$ are both nonzero,\nfind $\\frac{a}{b},$ assuming $b$ is nonzero.', 'solution': 'If we multiply the first equation by $-\\frac{3}{2}$, we obtain\n\n$$6y-9x=-\\frac{3}{2}a.$$Since we also know that $6y-9x=b$, we have\n\n$$-\\frac{3}{2}a=b\\Rightarrow\\frac{a}{b}=\\boxed{-\\frac{2}{3}}.$$\nFinal Answer: The final answer is $-\\frac{2}{3}$. I hope it is correct.', 'few_shot': '1'}]

def process_results(doc: dict, results: List[str]) -> Dict[str, int]:

candidates = results[0]

unnormalized_answer = get_unnormalized_answer(candidates)

answer = normalize_final_answer(unnormalized_answer)

if is_equiv(answer, doc['answer']):

retval = 1

else:

retval = 0

results = {'exact_match': retval}

return results

def last_boxed_only_string(string: str) -> Optional[str]:

idx = string.rfind('\\boxed')

if '\\boxed ' in string:

return '\\boxed ' + string.split('\\boxed ')[-1].split('$')[0]

if idx < 0:

idx = string.rfind('\\fbox')

if idx < 0:

return None

i = idx

right_brace_idx = None

num_left_braces_open = 0

while i < len(string):

if string[i] == '{':

num_left_braces_open += 1

if string[i] == '}':

num_left_braces_open -= 1

if num_left_braces_open == 0:

right_brace_idx = i

break

i += 1

if right_brace_idx is None:

retval = None

else:

retval = string[idx:right_brace_idx + 1]

return retval

def remove_boxed(s: str) -> str:

if '\\boxed ' in s:

left = '\\boxed '

assert s[:len(left)] == left

return s[len(left):]

left = '\\boxed{'

assert s[:len(left)] == left

assert s[-1] == '}'

return s[len(left):-1]