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SELECT COUNT(*) FROM railway
Ada berapa kereta api?
CREATE TABLE railway (Id VARCHAR)
SELECT Builder FROM railway ORDER BY Builder
Sebutkan pembangun kereta api dalam urutan abjad naik.
CREATE TABLE railway (Builder VARCHAR)
SELECT Wheels, LOCATION FROM railway
Sebutkan roda dan lokasi kereta api.
CREATE TABLE railway (Wheels VARCHAR, LOCATION VARCHAR)
SELECT MAX(LEVEL) FROM manager WHERE Country <> "Australia "
Berapa tingkat maksimum manajer di negara -negara yang bukan "Australia"?
CREATE TABLE manager (LEVEL INTEGER, Country VARCHAR)
SELECT AVG(Age) FROM manager
Berapa usia rata -rata untuk semua manajer?
CREATE TABLE manager (Age INTEGER)
SELECT Name FROM manager ORDER BY LEVEL
Apa nama -nama manajer dalam urutan level naik?
CREATE TABLE manager (Name VARCHAR, LEVEL VARCHAR)
SELECT Name, Arrival FROM train
Apa nama dan waktu kedatangan kereta?
CREATE TABLE train (Name VARCHAR, Arrival VARCHAR)
SELECT Name FROM manager ORDER BY Age DESC LIMIT 1
Apa nama manajer tertua?
CREATE TABLE manager (Name VARCHAR, Age VARCHAR)
SELECT T2.Name, T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID
Tunjukkan nama kereta dan lokasi kereta api tempat mereka berada.
CREATE TABLE railway (Location VARCHAR, Railway_ID VARCHAR); CREATE TABLE train (Name VARCHAR, Railway_ID VARCHAR)
SELECT T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID WHERE T2.Name = "Andaman Exp"
Tunjukkan pembangun kereta api yang terkait dengan kereta yang bernama "Andaman Exp".
CREATE TABLE railway (Builder VARCHAR, Railway_ID VARCHAR); CREATE TABLE train (Railway_ID VARCHAR, Name VARCHAR)
SELECT T2.Railway_ID, T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID HAVING COUNT(*) > 1
Tampilkan ID dan lokasi kereta api yang dikaitkan dengan lebih dari satu kereta.
CREATE TABLE railway (Location VARCHAR, Railway_ID VARCHAR); CREATE TABLE train (Railway_ID VARCHAR)
SELECT T2.Railway_ID, T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID ORDER BY COUNT(*) DESC LIMIT 1
Tunjukkan ID dan pembangun kereta api yang terkait dengan paling banyak kereta.
CREATE TABLE train (Railway_ID VARCHAR); CREATE TABLE railway (Builder VARCHAR, Railway_ID VARCHAR)
SELECT Builder, COUNT(*) FROM railway GROUP BY Builder
Tunjukkan berbagai pembangun kereta api, bersama dengan jumlah kereta api yang sesuai menggunakan masing -masing pembangun.
CREATE TABLE railway (Builder VARCHAR)
SELECT Builder FROM railway GROUP BY Builder ORDER BY COUNT(*) DESC LIMIT 1
Tunjukkan pembangun kereta api yang paling umum.
CREATE TABLE railway (Builder VARCHAR)
SELECT LOCATION, COUNT(*) FROM railway GROUP BY LOCATION
Tunjukkan lokasi kereta api yang berbeda bersama dengan jumlah kereta api yang sesuai di setiap lokasi.
CREATE TABLE railway (LOCATION VARCHAR)
SELECT LOCATION FROM railway GROUP BY LOCATION HAVING COUNT(*) > 1
Tunjukkan lokasi yang memiliki lebih dari satu kereta api.
CREATE TABLE railway (LOCATION VARCHAR)
SELECT ObjectNumber FROM railway WHERE NOT Railway_ID IN (SELECT Railway_ID FROM train)
Sebutkan jumlah objek kereta api yang tidak memiliki kereta api.
CREATE TABLE train (ObjectNumber VARCHAR, Railway_ID VARCHAR); CREATE TABLE railway (ObjectNumber VARCHAR, Railway_ID VARCHAR)
SELECT Country FROM manager WHERE Age > 50 INTERSECT SELECT Country FROM manager WHERE Age < 46
Tunjukkan negara -negara yang memiliki manajer usia di atas 50 dan manajer usia di bawah 46.
CREATE TABLE manager (Country VARCHAR, Age INTEGER)
SELECT DISTINCT Country FROM manager
Tunjukkan negara -negara manajer yang berbeda.
CREATE TABLE manager (Country VARCHAR)
SELECT Working_year_starts FROM manager ORDER BY LEVEL DESC
Tunjukkan tahun -tahun kerja manajer dalam urutan turunnya level mereka.
CREATE TABLE manager (Working_year_starts VARCHAR, LEVEL VARCHAR)
SELECT Country FROM manager WHERE Age > 50 OR Age < 46
Tunjukkan negara -negara yang memiliki manajer usia di atas 50 atau di bawah 46.
CREATE TABLE manager (Country VARCHAR, Age VARCHAR)
SELECT COUNT(*) FROM addresses WHERE country = 'USA'
Ada berapa alamat di Country USA?
CREATE TABLE addresses (country VARCHAR)
SELECT DISTINCT city FROM addresses
Tunjukkan semua kota berbeda dalam catatan alamat.
CREATE TABLE addresses (city VARCHAR)
SELECT state_province_county, COUNT(*) FROM addresses GROUP BY state_province_county
Tunjukkan setiap negara bagian dan jumlah alamat di setiap negara bagian.
CREATE TABLE addresses (state_province_county VARCHAR)
SELECT customer_name, customer_phone FROM customers WHERE NOT customer_id IN (SELECT customer_id FROM customer_address_history)
Tunjukkan nama dan ponsel pelanggan yang tidak memiliki informasi alamat.
CREATE TABLE customer_address_history (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR)
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) DESC LIMIT 1
Tunjukkan nama pelanggan yang memiliki pesanan terbanyak.
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR)
SELECT product_type_code FROM products GROUP BY product_type_code HAVING COUNT(*) >= 2
Tunjukkan kode jenis produk yang memiliki setidaknya dua produk.
CREATE TABLE products (product_type_code VARCHAR)
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = 'Completed' INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = 'Part'
Tunjukkan nama -nama pelanggan yang memiliki pesanan dalam status lengkap dan status pesanan dalam bagian.
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_status_code VARCHAR)
SELECT customer_name, customer_phone, payment_method_code FROM customers ORDER BY customer_number DESC
Tampilkan nama, telepon, dan kode metode pembayaran untuk semua pelanggan dalam urutan nomor pelanggan yang menurun.
CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, payment_method_code VARCHAR, customer_number VARCHAR)
SELECT T1.product_name, SUM(T2.order_quantity) FROM products AS T1 JOIN order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id
Tunjukkan nama produk dan jumlah pesanan total untuk setiap produk.
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, product_id VARCHAR)
SELECT MIN(product_price), MAX(product_price), AVG(product_price) FROM products
Tunjukkan harga minimum, maksimum, rata -rata untuk semua produk.
CREATE TABLE products (product_price INTEGER)
SELECT COUNT(*) FROM products WHERE product_price > (SELECT AVG(product_price) FROM products)
Berapa banyak produk yang memiliki harga lebih tinggi dari rata -rata?
CREATE TABLE products (product_price INTEGER)
SELECT T2.customer_name, T3.city, T1.date_from, T1.date_to FROM customer_address_history AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id JOIN addresses AS T3 ON T1.address_id = T3.address_id
Tunjukkan nama pelanggan, Kota Alamat Pelanggan, tanggal dari, dan tanggal untuk setiap riwayat alamat pelanggan.
CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_address_history (date_from VARCHAR, date_to VARCHAR, customer_id VARCHAR, address_id VARCHAR)
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.payment_method_code = 'Credit Card' GROUP BY T1.customer_id HAVING COUNT(*) > 2
Tunjukkan nama pelanggan yang menggunakan metode pembayaran kartu kredit dan memiliki lebih dari 2 pesanan.
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, payment_method_code VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR)
SELECT T1.customer_name, T1.customer_phone FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T3.order_id = T2.order_id GROUP BY T1.customer_id ORDER BY SUM(T3.order_quantity) DESC LIMIT 1
Apa nama dan telepon pelanggan dengan jumlah produk yang paling dipesan?
CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
SELECT product_type_code, product_name FROM products WHERE product_price > 1000 OR product_price < 500
Tunjukkan jenis dan nama produk untuk produk dengan harga lebih tinggi dari 1000 atau lebih rendah dari 500.
CREATE TABLE products (product_type_code VARCHAR, product_name VARCHAR, product_price VARCHAR)
SELECT dorm_name FROM dorm WHERE gender = 'F'
Temukan nama asrama hanya untuk wanita (jenis kelamin).
CREATE TABLE dorm (dorm_name VARCHAR, gender VARCHAR)
SELECT dorm_name FROM dorm WHERE student_capacity > 300
Temukan nama asrama yang dapat menampung lebih dari 300 siswa.
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity INTEGER)
SELECT COUNT(*) FROM student WHERE sex = 'F' AND age < 25
Berapa banyak siswa perempuan (seks adalah f) usianya di bawah 25?
CREATE TABLE student (sex VARCHAR, age VARCHAR)
SELECT fname FROM student WHERE age > 20
Temukan nama pertama siswa yang lebih tua dari 20.
CREATE TABLE student (fname VARCHAR, age INTEGER)
SELECT fname FROM student WHERE city_code = 'PHL' AND age BETWEEN 20 AND 25
Temukan nama pertama siswa yang tinggal di kota PHL yang usianya antara 20 dan 25.
CREATE TABLE student (fname VARCHAR, city_code VARCHAR, age VARCHAR)
SELECT COUNT(*) FROM dorm
Ada berapa asrama?
CREATE TABLE dorm (Id VARCHAR)
SELECT COUNT(*) FROM dorm_amenity
Temukan jumlah fasilitas yang berbeda.
CREATE TABLE dorm_amenity (Id VARCHAR)
SELECT SUM(student_capacity) FROM dorm
Temukan kapasitas total semua asrama.
CREATE TABLE dorm (student_capacity INTEGER)
SELECT AVG(age), city_code FROM student GROUP BY city_code
Temukan usia rata -rata semua siswa yang tinggal di setiap kota.
CREATE TABLE student (city_code VARCHAR, age INTEGER)
SELECT AVG(student_capacity), SUM(student_capacity) FROM dorm WHERE gender = 'X'
Temukan rata -rata dan total kapasitas asrama untuk siswa dengan jenis kelamin X.
CREATE TABLE dorm (student_capacity INTEGER, gender VARCHAR)
SELECT COUNT(DISTINCT dormid) FROM has_amenity
Temukan jumlah asrama yang memiliki kemudahan.
CREATE TABLE has_amenity (dormid VARCHAR)
SELECT dorm_name FROM dorm WHERE NOT dormid IN (SELECT dormid FROM has_amenity)
Temukan nama asrama yang tidak memiliki kemudahan
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE has_amenity (dorm_name VARCHAR, dormid VARCHAR)
SELECT COUNT(DISTINCT gender) FROM dorm
Temukan jumlah jenis kelamin yang berbeda untuk asrama.
CREATE TABLE dorm (gender VARCHAR)
SELECT student_capacity, gender FROM dorm WHERE dorm_name LIKE '%Donor%'
Temukan kapasitas dan jenis gender dari asrama yang namanya memiliki 'donor'.
CREATE TABLE dorm (student_capacity VARCHAR, gender VARCHAR, dorm_name VARCHAR)
SELECT dorm_name, gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
Temukan nama dan jenis gender asrama yang kapasitasnya lebih besar dari 300 atau kurang dari 100.
CREATE TABLE dorm (dorm_name VARCHAR, gender VARCHAR, student_capacity VARCHAR)
SELECT COUNT(DISTINCT major), COUNT(DISTINCT city_code) FROM student
Temukan jumlah jurusan dan kota yang berbeda.
CREATE TABLE student (major VARCHAR, city_code VARCHAR)
SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'TV Lounge' INTERSECT SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'Study Room'
Temukan nama asrama yang memiliki ruang TV lounge dan ruang belajar sebagai fasilitas.
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'TV Lounge' EXCEPT SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'Study Room'
Temukan nama asrama yang memiliki TV Lounge tetapi tidak ada ruang belajar sebagai kemudahan.
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
SELECT lname FROM student WHERE sex = 'F' AND city_code = 'BAL' UNION SELECT lname FROM student WHERE sex = 'M' AND age < 20
Temukan nama belakang siswa yang perempuan (seks adalah f) dan tinggal di kota kode bal atau pria (seks adalah m) dan di usia di bawah 20.
CREATE TABLE student (lname VARCHAR, sex VARCHAR, city_code VARCHAR, age VARCHAR)
SELECT dorm_name FROM dorm ORDER BY student_capacity DESC LIMIT 1
Temukan nama asrama dengan kapasitas terbesar.
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity VARCHAR)
SELECT amenity_name FROM dorm_amenity ORDER BY amenity_name
Daftar dalam urutan alfabet semua fasilitas yang berbeda.
CREATE TABLE dorm_amenity (amenity_name VARCHAR)
SELECT city_code FROM student GROUP BY city_code ORDER BY COUNT(*) DESC LIMIT 1
Temukan Kode Kota tempat sebagian besar siswa tinggal.
CREATE TABLE student (city_code VARCHAR)
SELECT fname, lname FROM student WHERE age < (SELECT AVG(age) FROM student)
Temukan nama pertama dan belakang siswa yang usianya lebih muda dari usia rata -rata.
CREATE TABLE student (fname VARCHAR, lname VARCHAR, age INTEGER)
SELECT fname, lname FROM student WHERE city_code <> 'HKG' ORDER BY age
Sebutkan nama pertama dan belakang siswa yang tidak tinggal di kota dengan kode HKG, dan mengurutkan hasilnya pada usia mereka.
CREATE TABLE student (fname VARCHAR, lname VARCHAR, city_code VARCHAR, age VARCHAR)
SELECT T1.amenity_name FROM dorm_amenity AS T1 JOIN has_amenity AS T2 ON T2.amenid = T1.amenid JOIN dorm AS T3 ON T2.dormid = T3.dormid WHERE T3.dorm_name = 'Anonymous Donor Hall' ORDER BY T1.amenity_name
Daftar nama semua fasilitas yang dimiliki donor aula anonim, dan mengurutkan hasilnya dalam urutan alfabet.
CREATE TABLE has_amenity (amenid VARCHAR, dormid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
SELECT COUNT(*), SUM(student_capacity), gender FROM dorm GROUP BY gender
Temukan jumlah asrama dan kapasitas total untuk setiap jenis kelamin.
CREATE TABLE dorm (gender VARCHAR, student_capacity INTEGER)
SELECT AVG(age), MAX(age), sex FROM student GROUP BY sex
Temukan usia rata -rata dan tertua untuk siswa dengan jenis kelamin yang berbeda.
CREATE TABLE student (sex VARCHAR, age INTEGER)
SELECT COUNT(*), major FROM student GROUP BY major
Temukan jumlah siswa di setiap jurusan.
CREATE TABLE student (major VARCHAR)
SELECT COUNT(*), AVG(age), city_code FROM student GROUP BY city_code
Temukan jumlah dan usia rata -rata siswa yang tinggal di setiap kota.
CREATE TABLE student (city_code VARCHAR, age INTEGER)
SELECT COUNT(*), AVG(age), city_code FROM student WHERE sex = 'M' GROUP BY city_code
Temukan usia rata -rata dan jumlah siswa pria (dengan seks M) dari masing -masing kota.
CREATE TABLE student (city_code VARCHAR, age INTEGER, sex VARCHAR)
SELECT COUNT(*), city_code FROM student GROUP BY city_code HAVING COUNT(*) > 1
Temukan jumlah siswa untuk kota -kota di mana memiliki lebih dari satu siswa.
CREATE TABLE student (city_code VARCHAR)
SELECT fname, lname FROM student WHERE major <> (SELECT major FROM student GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1)
Temukan nama pertama dan belakang siswa yang tidak berada di jurusan terbesar.
CREATE TABLE student (fname VARCHAR, lname VARCHAR, major VARCHAR)
SELECT COUNT(*), sex FROM student WHERE age > (SELECT AVG(age) FROM student) GROUP BY sex
Temukan jumlah siswa yang usianya lebih tua dari usia rata -rata untuk setiap jenis kelamin.
CREATE TABLE student (sex VARCHAR, age INTEGER)
SELECT AVG(T1.age), T3.dorm_name FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid GROUP BY T3.dorm_name
Temukan usia rata -rata siswa yang tinggal di setiap asrama dan nama asrama.
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR)
SELECT COUNT(*), T1.dormid FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid WHERE T1.student_capacity > 100 GROUP BY T1.dormid
Temukan jumlah fasilitas untuk masing -masing asrama yang dapat menampung lebih dari 100 siswa.
CREATE TABLE dorm (dormid VARCHAR, student_capacity INTEGER); CREATE TABLE has_amenity (dormid VARCHAR)
SELECT COUNT(*), T3.dorm_name FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T1.age > 20 GROUP BY T3.dorm_name
Temukan jumlah siswa yang lebih tua dari 20 di setiap asrama.
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (stuid VARCHAR, age INTEGER)
SELECT T1.fname FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.dorm_name = 'Smith Hall'
Temukan nama depan siswa yang tinggal di Smith Hall.
CREATE TABLE student (fname VARCHAR, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
SELECT AVG(T1.age) FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.student_capacity = (SELECT MAX(student_capacity) FROM dorm)
Temukan usia rata -rata siswa yang tinggal di asrama dengan kapasitas terbesar.
CREATE TABLE dorm (student_capacity INTEGER); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, student_capacity INTEGER)
SELECT COUNT(*) FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.gender = 'M'
Temukan jumlah total siswa yang tinggal di asrama pria (dengan jenis kelamin M).
CREATE TABLE dorm (dormid VARCHAR, gender VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (stuid VARCHAR)
SELECT COUNT(*) FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.dorm_name = 'Smith Hall' AND T1.sex = 'F'
Temukan jumlah siswa perempuan (dengan seks F) yang tinggal di Smith Hall
CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T1.dorm_name = 'Smith Hall'
Temukan nama asrama Smith Hall yang dimiliki.
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T1.dorm_name = 'Smith Hall' ORDER BY T3.amenity_name
Temukan nama asrama Smith Hall yang dimiliki.Memesan hasil dengan nama fasilitas.
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
SELECT T1.amenity_name FROM dorm_amenity AS T1 JOIN has_amenity AS T2 ON T1.amenid = T2.amenid GROUP BY T2.amenid ORDER BY COUNT(*) DESC LIMIT 1
Temukan nama kemudahan yang paling umum di semua asrama.
CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE has_amenity (amenid VARCHAR)
SELECT T1.fname FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid WHERE T2.dormid IN (SELECT T2.dormid FROM dorm AS T3 JOIN has_amenity AS T4 ON T3.dormid = T4.dormid JOIN dorm_amenity AS T5 ON T4.amenid = T5.amenid GROUP BY T3.dormid ORDER BY COUNT(*) DESC LIMIT 1)
Temukan nama pertama siswa yang tinggal di asrama yang memiliki sebagian besar fasilitas.
CREATE TABLE dorm_amenity (amenid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm (dormid VARCHAR); CREATE TABLE student (fname VARCHAR, stuid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR)
SELECT T1.dorm_name, T1.student_capacity FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid GROUP BY T2.dormid ORDER BY COUNT(*) LIMIT 1
Temukan nama dan kapasitas asrama dengan sedikit fasilitas.
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR); CREATE TABLE dorm (dorm_name VARCHAR, student_capacity VARCHAR, dormid VARCHAR)
SELECT dorm_name FROM dorm EXCEPT SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'TV Lounge'
Temukan nama asrama yang tidak memiliki lounge TV kemudahan.
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dorm_name VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
SELECT T1.fname, T1.lname FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid WHERE T2.dormid IN (SELECT T3.dormid FROM has_amenity AS T3 JOIN dorm_amenity AS T4 ON T3.amenid = T4.amenid WHERE T4.amenity_name = 'TV Lounge')
Temukan nama pertama dan belakang siswa yang tinggal di asrama yang memiliki lounge TV kemudahan.
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
SELECT T1.fname, T1.age FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid WHERE NOT T2.dormid IN (SELECT T3.dormid FROM has_amenity AS T3 JOIN dorm_amenity AS T4 ON T3.amenid = T4.amenid WHERE T4.amenity_name = 'TV Lounge')
Temukan nama depan dan usia siswa yang tinggal di asrama yang tidak memiliki lounge TV fasilitas.
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE student (fname VARCHAR, age VARCHAR, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid JOIN lives_in AS T4 ON T4.dormid = T1.dormid JOIN student AS T5 ON T5.stuid = T4.stuid WHERE T5.lname = 'Smith'
Temukan nama fasilitas asrama tempat siswa dengan nama belakang Smith tinggal.
CREATE TABLE student (stuid VARCHAR, lname VARCHAR); CREATE TABLE dorm (dormid VARCHAR); CREATE TABLE lives_in (dormid VARCHAR, stuid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR)
SELECT email_address, phone_number FROM customers ORDER BY email_address, phone_number
Temukan email dan nomor telepon dari semua pelanggan, dipesan melalui alamat email dan nomor telepon.
CREATE TABLE customers (email_address VARCHAR, phone_number VARCHAR)
SELECT town_city FROM customers WHERE customer_type_code = "Good Credit Rating" GROUP BY town_city ORDER BY COUNT(*) LIMIT 1
Kota manakah yang memiliki jumlah pelanggan yang paling sedikit yang kode jenisnya adalah "peringkat kredit yang baik"?
CREATE TABLE customers (town_city VARCHAR, customer_type_code VARCHAR)
SELECT t1.product_name, COUNT(*) FROM products AS t1 JOIN complaints AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_name
Sebutkan nama semua produk bersama dengan jumlah keluhan yang telah mereka terima.
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE complaints (product_id VARCHAR)
SELECT t1.email_address FROM customers AS t1 JOIN complaints AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) LIMIT 1
Temukan email pelanggan yang telah mengajukan keluhan produk dengan keluhan terbanyak.
CREATE TABLE customers (email_address VARCHAR, customer_id VARCHAR); CREATE TABLE complaints (customer_id VARCHAR)
SELECT DISTINCT t1.product_name FROM products AS t1 JOIN complaints AS t2 ON t1.product_id = t2.product_id JOIN customers AS t3 GROUP BY t3.customer_id ORDER BY COUNT(*) LIMIT 1
Produk mana yang telah dikeluhkan oleh pelanggan yang telah mengajukan keluhan paling sedikit?
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE complaints (product_id VARCHAR)
SELECT t1.phone_number FROM customers AS t1 JOIN complaints AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.date_complaint_raised DESC LIMIT 1
Berapa nomor telepon pelanggan yang telah mengajukan keluhan terbaru?
CREATE TABLE customers (phone_number VARCHAR, customer_id VARCHAR); CREATE TABLE complaints (customer_id VARCHAR, date_complaint_raised VARCHAR)
SELECT email_address, phone_number FROM customers WHERE NOT customer_id IN (SELECT customer_id FROM complaints)
Temukan email dan nomor telepon pelanggan yang belum pernah mengajukan keluhan sebelumnya.
CREATE TABLE complaints (email_address VARCHAR, phone_number VARCHAR, customer_id VARCHAR); CREATE TABLE customers (email_address VARCHAR, phone_number VARCHAR, customer_id VARCHAR)
SELECT phone_number FROM customers UNION SELECT phone_number FROM staff
Temukan nomor telepon semua pelanggan dan staf.
CREATE TABLE staff (phone_number VARCHAR); CREATE TABLE customers (phone_number VARCHAR)
SELECT product_description FROM products WHERE product_name = "Chocolate"
Apa deskripsi produk bernama "cokelat"?
CREATE TABLE products (product_description VARCHAR, product_name VARCHAR)
SELECT product_name, product_category_code FROM products ORDER BY product_price DESC LIMIT 1
Temukan nama dan kategori produk paling mahal.
CREATE TABLE products (product_name VARCHAR, product_category_code VARCHAR, product_price VARCHAR)
SELECT product_price FROM products WHERE NOT product_id IN (SELECT product_id FROM complaints)
Temukan harga produk yang tidak pernah menerima satu keluhan tunggal.
CREATE TABLE products (product_price VARCHAR, product_id VARCHAR); CREATE TABLE complaints (product_price VARCHAR, product_id VARCHAR)
SELECT AVG(product_price), product_category_code FROM products GROUP BY product_category_code
Berapa harga rata -rata produk untuk setiap kategori?
CREATE TABLE products (product_category_code VARCHAR, product_price INTEGER)
SELECT t1.last_name FROM staff AS t1 JOIN complaints AS t2 ON t1.staff_id = t2.staff_id JOIN products AS t3 ON t2.product_id = t3.product_id ORDER BY t3.product_price LIMIT 1
Temukan nama belakang anggota staf yang memproses keluhan produk termurah.
CREATE TABLE products (product_id VARCHAR, product_price VARCHAR); CREATE TABLE complaints (staff_id VARCHAR, product_id VARCHAR); CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR)
SELECT complaint_status_code FROM complaints GROUP BY complaint_status_code HAVING COUNT(*) > 3
Status keluhan mana yang memiliki lebih dari 3 catatan pada file?
CREATE TABLE complaints (complaint_status_code VARCHAR)
SELECT last_name FROM staff WHERE email_address LIKE "%wrau%"
Temukan nama belakang staf yang alamat emailnya berisi "WRAU".
CREATE TABLE staff (last_name VARCHAR, email_address VARCHAR)