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###context:CREATE TABLE Songs (SongId VARCHAR); CREATE TABLE Band (firstname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR)
###human: Find the first name of the band mate that has performed in most songs.
###assistant: SELECT t2.firstname FROM Performance AS t1 JOIN Band AS t2 ON t1.bandmate = t2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY firstname ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE vocals (bandmate VARCHAR); CREATE TABLE band (id VARCHAR)
###human: Which vocal type has the band mate with first name "Marianne" played the most?
###assistant: SELECT TYPE FROM vocals AS T1 JOIN band AS T2 ON T1.bandmate = T2.id WHERE firstname = "Marianne" GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE Band (firstname VARCHAR, lastname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR, SongId VARCHAR, StagePosition VARCHAR); CREATE TABLE Songs (SongId VARCHAR, Title VARCHAR)
###human: Who is performing in the back stage position for the song "Der Kapitan"? Show the first name and last name.
###assistant: SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Der Kapitan" AND T1.StagePosition = "back" |
###context:CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR, title VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR)
###human: What are the songs in album "A Kiss Before You Go: Live in Hamburg"?
###assistant: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE T1.title = "A Kiss Before You Go: Live in Hamburg" |
###context:CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR)
###human: What are all the songs in albums under label "Universal Music Group"?
###assistant: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.label = "Universal Music Group" |
###context:CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR)
###human: Find the number of songs in all the studio albums.
###assistant: SELECT COUNT(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.type = "Studio" |
###context:CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR)
###human: Who is the founder of Sony?
###assistant: SELECT founder FROM manufacturers WHERE name = 'Sony' |
###context:CREATE TABLE manufacturers (headquarter VARCHAR, founder VARCHAR)
###human: Where is the headquarter of the company founded by James?
###assistant: SELECT headquarter FROM manufacturers WHERE founder = 'James' |
###context:CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR)
###human: Find all manufacturers' names and their headquarters, sorted by the ones with highest revenue first.
###assistant: SELECT name, headquarter FROM manufacturers ORDER BY revenue DESC |
###context:CREATE TABLE manufacturers (revenue INTEGER)
###human: What are the average, maximum and total revenues of all companies?
###assistant: SELECT AVG(revenue), MAX(revenue), SUM(revenue) FROM manufacturers |
###context:CREATE TABLE manufacturers (founder VARCHAR)
###human: How many companies were created by Andy?
###assistant: SELECT COUNT(*) FROM manufacturers WHERE founder = 'Andy' |
###context:CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR)
###human: Find the total revenue created by the companies whose headquarter is located at Austin.
###assistant: SELECT SUM(revenue) FROM manufacturers WHERE headquarter = 'Austin' |
###context:CREATE TABLE manufacturers (headquarter VARCHAR)
###human: What are the different cities listed?
###assistant: SELECT DISTINCT headquarter FROM manufacturers |
###context:CREATE TABLE manufacturers (headquarter VARCHAR)
###human: Find the number of manufactures that are based in Tokyo or Beijing.
###assistant: SELECT COUNT(*) FROM manufacturers WHERE headquarter = 'Tokyo' OR headquarter = 'Beijing' |
###context:CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR)
###human: Find the founder of the company whose name begins with the letter 'S'.
###assistant: SELECT founder FROM manufacturers WHERE name LIKE 'S%' |
###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
###human: Find the name of companies whose revenue is between 100 and 150.
###assistant: SELECT name FROM manufacturers WHERE revenue BETWEEN 100 AND 150 |
###context:CREATE TABLE manufacturers (revenue INTEGER, Headquarter VARCHAR)
###human: What is the total revenue of all companies whose main office is at Tokyo or Taiwan?
###assistant: SELECT SUM(revenue) FROM manufacturers WHERE Headquarter = 'Tokyo' OR Headquarter = 'Taiwan' |
###context:CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
###human: Find the name of product that is produced by both companies Creative Labs and Sony.
###assistant: SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Creative Labs' INTERSECT SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony' |
###context:CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, founder VARCHAR, revenue VARCHAR)
###human: Find the name, headquarter and founder of the manufacturer that has the highest revenue.
###assistant: SELECT name, headquarter, founder FROM manufacturers ORDER BY revenue DESC LIMIT 1 |
###context:CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR)
###human: Find the name, headquarter and revenue of all manufacturers sorted by their revenue in the descending order.
###assistant: SELECT name, headquarter, revenue FROM manufacturers ORDER BY revenue DESC |
###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
###human: Find the name of companies whose revenue is greater than the average revenue of all companies.
###assistant: SELECT name FROM manufacturers WHERE revenue > (SELECT AVG(revenue) FROM manufacturers) |
###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER, headquarter VARCHAR)
###human: Find the name of companies whose revenue is smaller than the revenue of all companies based in Austin.
###assistant: SELECT name FROM manufacturers WHERE revenue < (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin') |
###context:CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR)
###human: Find the total revenue of companies whose revenue is larger than the revenue of some companies based in Austin.
###assistant: SELECT SUM(revenue) FROM manufacturers WHERE revenue > (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin') |
###context:CREATE TABLE manufacturers (founder VARCHAR, revenue INTEGER)
###human: Find the total revenue of companies of each founder.
###assistant: SELECT SUM(revenue), founder FROM manufacturers GROUP BY founder |
###context:CREATE TABLE manufacturers (name VARCHAR, Headquarter VARCHAR, revenue INTEGER)
###human: Find the name and revenue of the company that earns the highest revenue in each city.
###assistant: SELECT name, MAX(revenue), Headquarter FROM manufacturers GROUP BY Headquarter |
###context:CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
###human: Find the total revenue for each manufacturer.
###assistant: SELECT SUM(revenue), name FROM manufacturers GROUP BY name |
###context:CREATE TABLE products (price INTEGER, Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
###human: Find the average prices of all products from each manufacture, and list each company's name.
###assistant: SELECT AVG(T1.price), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name |
###context:CREATE TABLE manufacturers (Headquarter VARCHAR, code VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
###human: Find the number of different products that are produced by companies at different headquarter cities.
###assistant: SELECT COUNT(DISTINCT T1.name), T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter |
###context:CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
###human: Find number of products which Sony does not make.
###assistant: SELECT COUNT(DISTINCT name) FROM products WHERE NOT name IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony') |
###context:CREATE TABLE manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Manufacturer VARCHAR, name VARCHAR); CREATE TABLE manufacturers (name VARCHAR)
###human: Find the name of companies that do not make DVD drive.
###assistant: SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive' |
###context:CREATE TABLE products (Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
###human: Find the number of products for each manufacturer, showing the name of each company.
###assistant: SELECT COUNT(*), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name |
###context:CREATE TABLE Products (Name VARCHAR)
###human: Select the names of all the products in the store.
###assistant: SELECT Name FROM Products |
###context:CREATE TABLE products (name VARCHAR, price VARCHAR)
###human: Select the names and the prices of all the products in the store.
###assistant: SELECT name, price FROM products |
###context:CREATE TABLE products (name VARCHAR, price VARCHAR)
###human: Select the name of the products with a price less than or equal to $200.
###assistant: SELECT name FROM products WHERE price <= 200 |
###context:CREATE TABLE products (price INTEGER)
###human: Find all information of all the products with a price between $60 and $120.
###assistant: SELECT * FROM products WHERE price BETWEEN 60 AND 120 |
###context:CREATE TABLE products (price INTEGER)
###human: Compute the average price of all the products.
###assistant: SELECT AVG(price) FROM products |
###context:CREATE TABLE products (price INTEGER, Manufacturer VARCHAR)
###human: Compute the average price of all products with manufacturer code equal to 2.
###assistant: SELECT AVG(price) FROM products WHERE Manufacturer = 2 |
###context:CREATE TABLE products (price VARCHAR)
###human: Compute the number of products with a price larger than or equal to $180.
###assistant: SELECT COUNT(*) FROM products WHERE price >= 180 |
###context:CREATE TABLE products (name VARCHAR, price VARCHAR)
###human: Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order).
###assistant: SELECT name, price FROM products WHERE price >= 180 ORDER BY price DESC, name |
###context:CREATE TABLE products (manufacturer VARCHAR); CREATE TABLE Manufacturers (code VARCHAR)
###human: Select all the data from the products and each product's manufacturer.
###assistant: SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code |
###context:CREATE TABLE Products (Manufacturer VARCHAR, Price INTEGER)
###human: Select the average price of each manufacturer's products, showing only the manufacturer's code.
###assistant: SELECT AVG(Price), Manufacturer FROM Products GROUP BY Manufacturer |
###context:CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR)
###human: Select the average price of each manufacturer's products, showing the manufacturer's name.
###assistant: SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name |
###context:CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER)
###human: Select the names of manufacturer whose products have an average price higher than or equal to $150.
###assistant: SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING AVG(T1.price) >= 150 |
###context:CREATE TABLE Products (name VARCHAR, price VARCHAR)
###human: Select the name and price of the cheapest product.
###assistant: SELECT name, price FROM Products ORDER BY price LIMIT 1 |
###context:CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Name VARCHAR, Price INTEGER, manufacturer VARCHAR)
###human: Select the name of each manufacturer along with the name and price of its most expensive product.
###assistant: SELECT T1.Name, MAX(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name |
###context:CREATE TABLE products (code VARCHAR, name VARCHAR, price INTEGER)
###human: Select the code of the product that is cheapest in each product category.
###assistant: SELECT code, name, MIN(price) FROM products GROUP BY name |
###context:CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR)
###human: What is the id of the problem log that is created most recently?
###assistant: SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1 |
###context:CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR)
###human: What is the oldest log id and its corresponding problem id?
###assistant: SELECT problem_log_id, problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1 |
###context:CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR, problem_id VARCHAR)
###human: Find all the ids and dates of the logs for the problem whose id is 10.
###assistant: SELECT problem_log_id, log_entry_date FROM problem_log WHERE problem_id = 10 |
###context:CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_description VARCHAR)
###human: List all the log ids and their descriptions from the problem logs.
###assistant: SELECT problem_log_id, log_entry_description FROM problem_log |
###context:CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR)
###human: List the first and last names of all distinct staff members who are assigned to the problem whose id is 1.
###assistant: SELECT DISTINCT staff_first_name, staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1 |
###context:CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
###human: List the problem id and log id which are assigned to the staff named Rylan Homenick.
###assistant: SELECT DISTINCT T2.problem_id, T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick" |
###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
###human: How many problems are there for product voluptatem?
###assistant: SELECT COUNT(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem" |
###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
###human: How many problems does the product with the most problems have? List the number of the problems and product name.
###assistant: SELECT COUNT(*), T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR); CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR)
###human: Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop.
###assistant: SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" |
###context:CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR)
###human: Find the ids of the problems that are reported by the staff whose last name is Bosco.
###assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco" |
###context:CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
###human: What are the ids of the problems which are reported after 1978-06-26?
###assistant: SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26" |
###context:CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
###human: What are the ids of the problems which are reported before 1978-06-26?
###assistant: SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26" |
###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR)
###human: For each product which has problems, what are the number of problems and the product id?
###assistant: SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id |
###context:CREATE TABLE product (product_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER)
###human: For each product that has problems, find the number of problems reported after 1986-11-13 and the product id?
###assistant: SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id |
###context:CREATE TABLE product (product_name VARCHAR)
###human: List the names of all the distinct product names in alphabetical order?
###assistant: SELECT DISTINCT product_name FROM product ORDER BY product_name |
###context:CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
###human: List all the distinct product names ordered by product id?
###assistant: SELECT DISTINCT product_name FROM product ORDER BY product_id |
###context:CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR)
###human: What are the id of problems reported by the staff named Dameon Frami or Jolie Weber?
###assistant: SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber" |
###context:CREATE TABLE problems (reported_by_staff_id VARCHAR, closure_authorised_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
###human: What are the product ids for the problems reported by Christop Berge with closure authorised by Ashley Medhurst?
###assistant: SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst" |
###context:CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR)
###human: What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte?
###assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < (SELECT MIN(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte") |
###context:CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR)
###human: What are the ids of the problems reported after the date of any problems reported by Rylan Homenick?
###assistant: SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > (SELECT MAX(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick") |
###context:CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
###human: Find the top 3 products which have the largest number of problems?
###assistant: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY COUNT(*) DESC LIMIT 3 |
###context:CREATE TABLE problems (problem_id VARCHAR, product_id VARCHAR, date_problem_reported VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
###human: List the ids of the problems from the product "voluptatem" that are reported after 1995?
###assistant: SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995" |
###context:CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_first_name VARCHAR, staff_last_name VARCHAR, staff_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR)
###human: Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"?
###assistant: SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut" |
###context:CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR)
###human: Find the products which have problems reported by both Lacey Bosco and Kenton Champlin?
###assistant: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin" |
###context:CREATE TABLE branch (membership_amount INTEGER)
###human: How many branches where have more than average number of memberships are there?
###assistant: SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch) |
###context:CREATE TABLE branch (name VARCHAR, address_road VARCHAR, city VARCHAR, open_year VARCHAR)
###human: Show name, address road, and city for all branches sorted by open year.
###assistant: SELECT name, address_road, city FROM branch ORDER BY open_year |
###context:CREATE TABLE branch (name VARCHAR, membership_amount VARCHAR)
###human: What are names for top three branches with most number of membership?
###assistant: SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3 |
###context:CREATE TABLE branch (city VARCHAR, membership_amount VARCHAR)
###human: Show all distinct city where branches with at least 100 memberships are located.
###assistant: SELECT DISTINCT city FROM branch WHERE membership_amount >= 100 |
###context:CREATE TABLE branch (open_year VARCHAR)
###human: List all open years when at least two shops are opened.
###assistant: SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2 |
###context:CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR)
###human: Show minimum and maximum amount of memberships for all branches opened in 2011 or located at city London.
###assistant: SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London' |
###context:CREATE TABLE branch (city VARCHAR, open_year INTEGER)
###human: Show the city and the number of branches opened before 2010 for each city.
###assistant: SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city |
###context:CREATE TABLE member (LEVEL VARCHAR)
###human: How many different levels do members have?
###assistant: SELECT COUNT(DISTINCT LEVEL) FROM member |
###context:CREATE TABLE member (card_number VARCHAR, name VARCHAR, hometown VARCHAR, LEVEL VARCHAR)
###human: Show card number, name, and hometown for all members in a descending order of level.
###assistant: SELECT card_number, name, hometown FROM member ORDER BY LEVEL DESC |
###context:CREATE TABLE member (LEVEL VARCHAR)
###human: Show the membership level with most number of members.
###assistant: SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR)
###human: Show all member names and registered branch names sorted by register year.
###assistant: SELECT T3.name, T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year |
###context:CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year INTEGER)
###human: Show all branch names with the number of members in each branch registered after 2015.
###assistant: SELECT T2.name, COUNT(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id |
###context:CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (name VARCHAR, member_id VARCHAR)
###human: Show member names without any registered branch.
###assistant: SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch) |
###context:CREATE TABLE membership_register_branch (name VARCHAR, city VARCHAR, branch_id VARCHAR); CREATE TABLE branch (name VARCHAR, city VARCHAR, branch_id VARCHAR)
###human: List the branch name and city without any registered members.
###assistant: SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch) |
###context:CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, open_year VARCHAR, branch_id VARCHAR)
###human: What is the name and open year for the branch with most number of memberships registered in 2016?
###assistant: SELECT T2.name, T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE member (name VARCHAR, hometown VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (member_id VARCHAR, register_year VARCHAR)
###human: Show the member name and hometown who registered a branch in 2016.
###assistant: SELECT T2.name, T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016 |
###context:CREATE TABLE branch (city VARCHAR, open_year VARCHAR, membership_amount VARCHAR)
###human: Show all city with a branch opened in 2001 and a branch with more than 100 membership.
###assistant: SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100 |
###context:CREATE TABLE branch (city VARCHAR, membership_amount INTEGER)
###human: Show all cities without a branch having more than 100 memberships.
###assistant: SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100 |
###context:CREATE TABLE purchase (branch_id VARCHAR, year VARCHAR); CREATE TABLE branch (branch_id VARCHAR, city VARCHAR)
###human: What is the sum of total pounds of purchase in year 2018 for all branches in London?
###assistant: SELECT SUM(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018 |
###context:CREATE TABLE member (member_id VARCHAR, level VARCHAR); CREATE TABLE purchase (member_id VARCHAR)
###human: What is the total number of purchases for members with level 6?
###assistant: SELECT COUNT(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6 |
###context:CREATE TABLE member (member_id VARCHAR, Hometown VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR)
###human: Find the name of branches where have some members whose hometown is in Louisville, Kentucky and some in Hiram, Georgia.
###assistant: SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Louisville , Kentucky' INTERSECT SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Hiram , Georgia' |
###context:CREATE TABLE member (card_number VARCHAR, Hometown VARCHAR)
###human: list the card number of all members whose hometown address includes word "Kentucky".
###assistant: SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%" |
###context:CREATE TABLE STUDENT (Id VARCHAR)
###human: Find the number of students in total.
###assistant: SELECT COUNT(*) FROM STUDENT |
###context:CREATE TABLE VOTING_RECORD (Id VARCHAR)
###human: Find the number of voting records in total.
###assistant: SELECT COUNT(*) FROM VOTING_RECORD |
###context:CREATE TABLE VOTING_RECORD (President_Vote VARCHAR)
###human: Find the distinct number of president votes.
###assistant: SELECT COUNT(DISTINCT President_Vote) FROM VOTING_RECORD |
###context:CREATE TABLE STUDENT (Age INTEGER)
###human: Find the maximum age of all the students.
###assistant: SELECT MAX(Age) FROM STUDENT |
###context:CREATE TABLE STUDENT (LName VARCHAR, Major VARCHAR)
###human: Find the last names of students with major 50.
###assistant: SELECT LName FROM STUDENT WHERE Major = 50 |
###context:CREATE TABLE STUDENT (Fname VARCHAR, Age INTEGER)
###human: Find the first names of students with age above 22.
###assistant: SELECT Fname FROM STUDENT WHERE Age > 22 |
###context:CREATE TABLE STUDENT (Major VARCHAR, Sex VARCHAR)
###human: What are the majors of male (sex is M) students?
###assistant: SELECT Major FROM STUDENT WHERE Sex = "M" |
###context:CREATE TABLE STUDENT (Age INTEGER, Sex VARCHAR)
###human: What is the average age of female (sex is F) students?
###assistant: SELECT AVG(Age) FROM STUDENT WHERE Sex = "F" |
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