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###context:CREATE TABLE music_festival (Date_of_ceremony VARCHAR, Volume VARCHAR); CREATE TABLE volume (Volume_ID VARCHAR, Weeks_on_Top INTEGER)
###human: Please show the date of ceremony of the volumes that last more than 2 weeks on top.
###assistant: SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T2.Weeks_on_Top > 2 |
###context:CREATE TABLE volume (Song VARCHAR, Volume_ID VARCHAR); CREATE TABLE music_festival (Volume VARCHAR, Result VARCHAR)
###human: Please show the songs that have result "nominated" at music festivals.
###assistant: SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T1.Result = "Nominated" |
###context:CREATE TABLE artist (Artist_ID VARCHAR, Artist VARCHAR); CREATE TABLE volume (Issue_Date VARCHAR, Artist_ID VARCHAR)
###human: What are the issue dates of volumes associated with the artist "Gorgoroth"?
###assistant: SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.Artist = "Gorgoroth" |
###context:CREATE TABLE volume (Song VARCHAR, Artist_ID VARCHAR); CREATE TABLE artist (Artist_ID VARCHAR, age VARCHAR)
###human: What are the songs in volumes associated with the artist aged 32 or older?
###assistant: SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age >= 32 |
###context:CREATE TABLE volume (Weeks_on_Top INTEGER, Artist_ID VARCHAR); CREATE TABLE artist (Artist_ID VARCHAR, age VARCHAR)
###human: What is the average weeks on top of volumes associated with the artist aged 25 or younger?
###assistant: SELECT AVG(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age <= 25 |
###context:CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR); CREATE TABLE volume (Artist_ID VARCHAR, Weeks_on_Top INTEGER)
###human: What are the famous title of the artists associated with volumes with more than 2 weeks on top?
###assistant: SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 |
###context:CREATE TABLE artist (Famous_Title VARCHAR, Age VARCHAR)
###human: Please list the age and famous title of artists in descending order of age.
###assistant: SELECT Famous_Title, Age FROM artist ORDER BY Age DESC |
###context:CREATE TABLE artist (Famous_Release_date VARCHAR, Age VARCHAR)
###human: What is the famous release date of the artist with the oldest age?
###assistant: SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1 |
###context:CREATE TABLE music_festival (Category VARCHAR)
###human: Please show the categories of the music festivals and the count.
###assistant: SELECT Category, COUNT(*) FROM music_festival GROUP BY Category |
###context:CREATE TABLE music_festival (RESULT VARCHAR)
###human: What is the most common result of the music festival?
###assistant: SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE music_festival (Category VARCHAR)
###human: Please show the categories of the music festivals with count more than 1.
###assistant: SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*) > 1 |
###context:CREATE TABLE volume (Song VARCHAR, Weeks_on_Top VARCHAR)
###human: What is the song in the volume with the maximum weeks on top?
###assistant: SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1 |
###context:CREATE TABLE volume (Famous_Title VARCHAR, Artist_ID VARCHAR); CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR)
###human: Find the famous titles of artists that do not have any volume.
###assistant: SELECT Famous_Title FROM artist WHERE NOT Artist_ID IN (SELECT Artist_ID FROM volume) |
###context:CREATE TABLE artist (Famous_Title VARCHAR, Artist_ID VARCHAR); CREATE TABLE volume (Artist_ID VARCHAR, Weeks_on_Top INTEGER)
###human: Show the famous titles of the artists with both volumes that lasted more than 2 weeks on top and volumes that lasted less than 2 weeks on top.
###assistant: SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top < 2 |
###context:CREATE TABLE music_festival (Date_of_ceremony VARCHAR, Category VARCHAR, RESULT VARCHAR)
###human: What are the date of ceremony of music festivals with category "Best Song" and result "Awarded"?
###assistant: SELECT Date_of_ceremony FROM music_festival WHERE Category = "Best Song" AND RESULT = "Awarded" |
###context:CREATE TABLE volume (Issue_Date VARCHAR, Weeks_on_Top VARCHAR)
###human: What is the issue date of the volume with the minimum weeks on top?
###assistant: SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top LIMIT 1 |
###context:CREATE TABLE music_festival (RESULT VARCHAR)
###human: Please show the results of music festivals and the number of music festivals that have had each, ordered by this count.
###assistant: SELECT RESULT, COUNT(*) FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC |
###context:CREATE TABLE volume (Artist_ID VARCHAR); CREATE TABLE artist (Artist_ID VARCHAR, age VARCHAR)
###human: What are the issue dates of volumes associated with the artist aged 23 or younger?
###assistant: SELECT Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age <= 23 |
###context:CREATE TABLE roller_coaster (Id VARCHAR)
###human: How many roller coasters are there?
###assistant: SELECT COUNT(*) FROM roller_coaster |
###context:CREATE TABLE roller_coaster (Name VARCHAR, LENGTH VARCHAR)
###human: List the names of roller coasters by ascending order of length.
###assistant: SELECT Name FROM roller_coaster ORDER BY LENGTH |
###context:CREATE TABLE roller_coaster (LENGTH VARCHAR, Height VARCHAR)
###human: What are the lengths and heights of roller coasters?
###assistant: SELECT LENGTH, Height FROM roller_coaster |
###context:CREATE TABLE country (Name VARCHAR, Languages VARCHAR)
###human: List the names of countries whose language is not "German".
###assistant: SELECT Name FROM country WHERE Languages <> "German" |
###context:CREATE TABLE roller_coaster (Status VARCHAR, LENGTH VARCHAR, Height VARCHAR)
###human: Show the statuses of roller coasters longer than 3300 or higher than 100.
###assistant: SELECT Status FROM roller_coaster WHERE LENGTH > 3300 OR Height > 100 |
###context:CREATE TABLE roller_coaster (Speed VARCHAR, LENGTH VARCHAR)
###human: What are the speeds of the longest roller coaster?
###assistant: SELECT Speed FROM roller_coaster ORDER BY LENGTH DESC LIMIT 1 |
###context:CREATE TABLE roller_coaster (Speed INTEGER)
###human: What is the average speed of roller coasters?
###assistant: SELECT AVG(Speed) FROM roller_coaster |
###context:CREATE TABLE roller_coaster (Status VARCHAR)
###human: Show the different statuses and the numbers of roller coasters for each status.
###assistant: SELECT Status, COUNT(*) FROM roller_coaster GROUP BY Status |
###context:CREATE TABLE roller_coaster (Status VARCHAR)
###human: Please show the most common status of roller coasters.
###assistant: SELECT Status FROM roller_coaster GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE roller_coaster (Status VARCHAR)
###human: List the status shared by more than two roller coaster.
###assistant: SELECT Status FROM roller_coaster GROUP BY Status HAVING COUNT(*) > 2 |
###context:CREATE TABLE roller_coaster (Park VARCHAR, Speed VARCHAR)
###human: Show the park of the roller coaster with the highest speed.
###assistant: SELECT Park FROM roller_coaster ORDER BY Speed DESC LIMIT 1 |
###context:CREATE TABLE country (Name VARCHAR, Country_ID VARCHAR); CREATE TABLE roller_coaster (Name VARCHAR, Country_ID VARCHAR)
###human: Show the names of roller coasters and names of country they are in.
###assistant: SELECT T2.Name, T1.Name FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID = T2.Country_ID |
###context:CREATE TABLE roller_coaster (Country_ID VARCHAR); CREATE TABLE country (Name VARCHAR, Country_ID VARCHAR)
###human: Show the names of countries that have more than one roller coaster.
###assistant: SELECT T1.Name FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID = T2.Country_ID GROUP BY T1.Name HAVING COUNT(*) > 1 |
###context:CREATE TABLE roller_coaster (Country_ID VARCHAR, Height VARCHAR); CREATE TABLE country (Name VARCHAR, population VARCHAR, Country_ID VARCHAR)
###human: Show the name and population of the country that has the highest roller coaster.
###assistant: SELECT T1.Name, T1.population FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID = T2.Country_ID ORDER BY T2.Height DESC LIMIT 1 |
###context:CREATE TABLE roller_coaster (Speed INTEGER, Country_ID VARCHAR); CREATE TABLE country (Name VARCHAR, Country_ID VARCHAR)
###human: Show the names of countries and the average speed of roller coasters from each country.
###assistant: SELECT T1.Name, AVG(T2.Speed) FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID = T2.Country_ID GROUP BY T1.Name |
###context:CREATE TABLE country (country_id VARCHAR, LENGTH INTEGER); CREATE TABLE roller_coaster (country_id VARCHAR, LENGTH INTEGER)
###human: How many countries do not have an roller coaster longer than 3000?
###assistant: SELECT COUNT(*) FROM country WHERE NOT country_id IN (SELECT country_id FROM roller_coaster WHERE LENGTH > 3000) |
###context:CREATE TABLE country (name VARCHAR, area VARCHAR, population VARCHAR, Country_ID VARCHAR); CREATE TABLE roller_coaster (Country_ID VARCHAR, speed INTEGER)
###human: What are the country names, area and population which has both roller coasters with speed higher
###assistant: SELECT T1.name, T1.area, T1.population FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID = T2.Country_ID WHERE T2.speed > 60 INTERSECT SELECT T1.name, T1.area, T1.population FROM country AS T1 JOIN roller_coaster AS T2 ON T1.Country_ID = T2.Country_ID WHERE T2.speed < 55 |
###context:CREATE TABLE captain (rank VARCHAR)
###human: How many different captain ranks are there?
###assistant: SELECT COUNT(DISTINCT rank) FROM captain |
###context:CREATE TABLE captain (rank VARCHAR)
###human: How many captains are in each rank?
###assistant: SELECT COUNT(*), rank FROM captain GROUP BY rank |
###context:CREATE TABLE captain (rank VARCHAR, age INTEGER)
###human: How many captains with younger than 50 are in each rank?
###assistant: SELECT COUNT(*), rank FROM captain WHERE age < 50 GROUP BY rank |
###context:CREATE TABLE captain (name VARCHAR, age VARCHAR)
###human: Sort all captain names by their ages from old to young.
###assistant: SELECT name FROM captain ORDER BY age DESC |
###context:CREATE TABLE captain (name VARCHAR, CLASS VARCHAR, rank VARCHAR)
###human: Find the name, class and rank of all captains.
###assistant: SELECT name, CLASS, rank FROM captain |
###context:CREATE TABLE captain (rank VARCHAR)
###human: Which rank is the most common among captains?
###assistant: SELECT rank FROM captain GROUP BY rank ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE captain (CLASS VARCHAR)
###human: Which classes have more than two captains?
###assistant: SELECT CLASS FROM captain GROUP BY CLASS HAVING COUNT(*) > 2 |
###context:CREATE TABLE captain (name VARCHAR, rank VARCHAR)
###human: Find the name of captains whose rank are either Midshipman or Lieutenant.
###assistant: SELECT name FROM captain WHERE rank = 'Midshipman' OR rank = 'Lieutenant' |
###context:CREATE TABLE captain (CLASS VARCHAR, age INTEGER)
###human: What are the average and minimum age of captains in different class?
###assistant: SELECT AVG(age), MIN(age), CLASS FROM captain GROUP BY CLASS |
###context:CREATE TABLE captain (rank VARCHAR, CLASS VARCHAR)
###human: Find the captain rank that has some captains in both Cutter and Armed schooner classes.
###assistant: SELECT rank FROM captain WHERE CLASS = 'Cutter' INTERSECT SELECT rank FROM captain WHERE CLASS = 'Armed schooner' |
###context:CREATE TABLE captain (rank VARCHAR, CLASS VARCHAR)
###human: Find the captain rank that has no captain in Third-rate ship of the line class.
###assistant: SELECT rank FROM captain EXCEPT SELECT rank FROM captain WHERE CLASS = 'Third-rate ship of the line' |
###context:CREATE TABLE captain (name VARCHAR, age VARCHAR)
###human: What is the name of the youngest captain?
###assistant: SELECT name FROM captain ORDER BY age LIMIT 1 |
###context:CREATE TABLE ship (name VARCHAR, TYPE VARCHAR, flag VARCHAR, built_year VARCHAR)
###human: Find the name, type, and flag of the ship that is built in the most recent year.
###assistant: SELECT name, TYPE, flag FROM ship ORDER BY built_year DESC LIMIT 1 |
###context:CREATE TABLE ship (flag VARCHAR)
###human: Group by ships by flag, and return number of ships that have each flag.
###assistant: SELECT COUNT(*), flag FROM ship GROUP BY flag |
###context:CREATE TABLE ship (flag VARCHAR)
###human: Which flag is most widely used among all ships?
###assistant: SELECT flag FROM ship GROUP BY flag ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE ship (name VARCHAR, built_year VARCHAR, CLASS VARCHAR)
###human: List all ship names in the order of built year and class.
###assistant: SELECT name FROM ship ORDER BY built_year, CLASS |
###context:CREATE TABLE ship (TYPE VARCHAR, flag VARCHAR)
###human: Find the ship type that are used by both ships with Panama and Malta flags.
###assistant: SELECT TYPE FROM ship WHERE flag = 'Panama' INTERSECT SELECT TYPE FROM ship WHERE flag = 'Malta' |
###context:CREATE TABLE ship (built_year VARCHAR)
###human: In which year were most of ships built?
###assistant: SELECT built_year FROM ship GROUP BY built_year ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE captain (ship_id VARCHAR); CREATE TABLE ship (name VARCHAR, ship_id VARCHAR)
###human: Find the name of the ships that have more than one captain.
###assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id GROUP BY t2.ship_id HAVING COUNT(*) > 1 |
###context:CREATE TABLE ship (name VARCHAR, CLASS VARCHAR, ship_id VARCHAR); CREATE TABLE captain (name VARCHAR, CLASS VARCHAR, ship_id VARCHAR)
###human: what are the names and classes of the ships that do not have any captain yet?
###assistant: SELECT name, CLASS FROM ship WHERE NOT ship_id IN (SELECT ship_id FROM captain) |
###context:CREATE TABLE ship (name VARCHAR, ship_id VARCHAR); CREATE TABLE captain (ship_id VARCHAR, age VARCHAR)
###human: Find the name of the ship that is steered by the youngest captain.
###assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id ORDER BY t2.age LIMIT 1 |
###context:CREATE TABLE captain (name VARCHAR, flag VARCHAR, ship_id VARCHAR, rank VARCHAR); CREATE TABLE ship (name VARCHAR, flag VARCHAR, ship_id VARCHAR, rank VARCHAR)
###human: Find the name and flag of ships that are not steered by any captain with Midshipman rank.
###assistant: SELECT name, flag FROM ship WHERE NOT ship_id IN (SELECT ship_id FROM captain WHERE rank = 'Midshipman') |
###context:CREATE TABLE ship (name VARCHAR, ship_id VARCHAR); CREATE TABLE captain (ship_id VARCHAR, rank VARCHAR)
###human: Find the name of the ships that are steered by both a captain with Midshipman rank and a captain with Lieutenant rank.
###assistant: SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id WHERE t2.rank = 'Midshipman' INTERSECT SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id WHERE t2.rank = 'Lieutenant' |
###context:CREATE TABLE hosting_city (host_city VARCHAR, YEAR VARCHAR)
###human: What is id of the city that hosted events in the most recent year?
###assistant: SELECT host_city FROM hosting_city ORDER BY YEAR DESC LIMIT 1 |
###context:CREATE TABLE MATCH (match_id VARCHAR, competition VARCHAR)
###human: Find the match ids of the cities that hosted competition "1994 FIFA World Cup qualification"?
###assistant: SELECT match_id FROM MATCH WHERE competition = "1994 FIFA World Cup qualification" |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR, year INTEGER)
###human: Find the cities which were once a host city after 2010?
###assistant: SELECT T1.city FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city WHERE T2.year > 2010 |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR)
###human: Which city has hosted the most events?
###assistant: SELECT T1.city FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY T2.host_city ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE city (city_id VARCHAR, city VARCHAR); CREATE TABLE MATCH (venue VARCHAR, match_id VARCHAR, competition VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR, match_id VARCHAR)
###human: What is the venue of the competition "1994 FIFA World Cup qualification" hosted by "Nanjing ( Jiangsu )"?
###assistant: SELECT T3.venue FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city JOIN MATCH AS T3 ON T2.match_id = T3.match_id WHERE T1.city = "Nanjing ( Jiangsu )" AND T3.competition = "1994 FIFA World Cup qualification" |
###context:CREATE TABLE city (city_id VARCHAR, city VARCHAR); CREATE TABLE temperature (Jan VARCHAR, city_id VARCHAR)
###human: Give me the temperature of Shanghai in January.
###assistant: SELECT T2.Jan FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T1.city = "Shanghai" |
###context:CREATE TABLE city (city_id VARCHAR, city VARCHAR); CREATE TABLE hosting_city (year VARCHAR, host_city VARCHAR)
###human: What is the host year of city "Taizhou ( Zhejiang )"?
###assistant: SELECT T2.year FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city WHERE T1.city = "Taizhou ( Zhejiang )" |
###context:CREATE TABLE city (city VARCHAR, regional_population VARCHAR)
###human: Which three cities have the largest regional population?
###assistant: SELECT city FROM city ORDER BY regional_population DESC LIMIT 3 |
###context:CREATE TABLE city (city VARCHAR, GDP VARCHAR)
###human: Which city has the lowest GDP? Please list the city name and its GDP.
###assistant: SELECT city, GDP FROM city ORDER BY GDP LIMIT 1 |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Feb VARCHAR)
###human: Which city has the highest temperature in February?
###assistant: SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id ORDER BY T2.Feb DESC LIMIT 1 |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Mar VARCHAR, Jul VARCHAR, Oct VARCHAR)
###human: Give me a list of cities whose temperature in March is lower than that in July or higher than that in Oct?
###assistant: SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Mar < T2.Jul OR T2.Mar > T2.Oct |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Mar INTEGER, Jul VARCHAR)
###human: Give me a list of cities whose temperature in Mar is lower than that in July and which have also served as host cities?
###assistant: SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Mar < T2.Jul INTERSECT SELECT T3.city FROM city AS T3 JOIN hosting_city AS T4 ON T3.city_id = T4.host_city |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Mar INTEGER, Dec VARCHAR)
###human: Give me a list of cities whose temperature in Mar is lower than that in Dec and which have never been host cities.
###assistant: SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Mar < T2.Dec EXCEPT SELECT T3.city FROM city AS T3 JOIN hosting_city AS T4 ON T3.city_id = T4.host_city |
###context:CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Feb INTEGER, Jun VARCHAR)
###human: Give me a list of cities whose temperature in Feb is higher than that in Jun or cities that were once host cities?
###assistant: SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Feb > T2.Jun UNION SELECT T3.city FROM city AS T3 JOIN hosting_city AS T4 ON T3.city_id = T4.host_city |
###context:CREATE TABLE city (city VARCHAR, regional_population INTEGER)
###human: Please give me a list of cities whose regional population is over 10000000.
###assistant: SELECT city FROM city WHERE regional_population > 10000000 |
###context:CREATE TABLE city (city VARCHAR, regional_population INTEGER)
###human: Please give me a list of cities whose regional population is over 8000000 or under 5000000.
###assistant: SELECT city FROM city WHERE regional_population > 10000000 UNION SELECT city FROM city WHERE regional_population < 5000000 |
###context:CREATE TABLE MATCH (Competition VARCHAR)
###human: Find the number of matches in different competitions.
###assistant: SELECT COUNT(*), Competition FROM MATCH GROUP BY Competition |
###context:CREATE TABLE MATCH (venue VARCHAR, date VARCHAR)
###human: List venues of all matches in the order of their dates starting from the most recent one.
###assistant: SELECT venue FROM MATCH ORDER BY date DESC |
###context:CREATE TABLE city (gdp VARCHAR, Regional_Population VARCHAR)
###human: what is the GDP of the city with the largest population.
###assistant: SELECT gdp FROM city ORDER BY Regional_Population DESC LIMIT 1 |
###context:CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE city (city_id VARCHAR)
###human: What are the GDP and population of the city that already served as a host more than once?
###assistant: SELECT t1.gdp, t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING COUNT(*) > 1 |
###context:CREATE TABLE individuals (individual_first_name VARCHAR, individual_middle_name VARCHAR, individual_last_name VARCHAR)
###human: List every individual's first name, middle name and last name in alphabetical order by last name.
###assistant: SELECT individual_first_name, individual_middle_name, individual_last_name FROM individuals ORDER BY individual_last_name |
###context:CREATE TABLE forms (form_type_code VARCHAR)
###human: List all the types of forms.
###assistant: SELECT DISTINCT form_type_code FROM forms |
###context:CREATE TABLE party_forms (form_id VARCHAR); CREATE TABLE forms (form_name VARCHAR, form_id VARCHAR)
###human: Find the name of the most popular party form.
###assistant: SELECT t1.form_name FROM forms AS t1 JOIN party_forms AS t2 ON t1.form_id = t2.form_id GROUP BY t2.form_id ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE parties (payment_method_code VARCHAR, party_phone VARCHAR, party_email VARCHAR)
###human: Find the payment method and phone of the party with email "[email protected]".
###assistant: SELECT payment_method_code, party_phone FROM parties WHERE party_email = "[email protected]" |
###context:CREATE TABLE party_forms (form_id VARCHAR); CREATE TABLE parties (party_email VARCHAR, party_id VARCHAR); CREATE TABLE party_forms (party_id VARCHAR, form_id VARCHAR)
###human: Find the emails of parties with the most popular party form.
###assistant: SELECT t1.party_email FROM parties AS t1 JOIN party_forms AS t2 ON t1.party_id = t2.party_id WHERE t2.form_id = (SELECT form_id FROM party_forms GROUP BY form_id ORDER BY COUNT(*) DESC LIMIT 1) |
###context:CREATE TABLE organizations (organization_name VARCHAR, date_formed VARCHAR)
###human: List all the name of organizations in order of the date formed.
###assistant: SELECT organization_name FROM organizations ORDER BY date_formed |
###context:CREATE TABLE organizations (organization_name VARCHAR, date_formed VARCHAR)
###human: Find the name of the youngest organization.
###assistant: SELECT organization_name FROM organizations ORDER BY date_formed DESC LIMIT 1 |
###context:CREATE TABLE organizations (organization_id VARCHAR, organization_name VARCHAR); CREATE TABLE individuals (individual_last_name VARCHAR, individual_id VARCHAR); CREATE TABLE organization_contact_individuals (organization_id VARCHAR, individual_id VARCHAR, date_contact_to VARCHAR)
###human: Find the last name of the latest contact individual of the organization "Labour Party".
###assistant: SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.organization_name = "Labour Party" ORDER BY t2.date_contact_to DESC LIMIT 1 |
###context:CREATE TABLE organizations (uk_vat_number INTEGER); CREATE TABLE individuals (individual_last_name VARCHAR, individual_id VARCHAR); CREATE TABLE organizations (organization_id VARCHAR, uk_vat_number INTEGER); CREATE TABLE organization_contact_individuals (organization_id VARCHAR, individual_id VARCHAR, date_contact_to VARCHAR)
###human: Find the last name of the first ever contact person of the organization with the highest UK Vat number.
###assistant: SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.uk_vat_number = (SELECT MAX(uk_vat_number) FROM organizations) ORDER BY t2.date_contact_to LIMIT 1 |
###context:CREATE TABLE services (service_name VARCHAR); CREATE TABLE party_services (service_id VARCHAR); CREATE TABLE services (service_name VARCHAR, service_id VARCHAR)
###human: Find name of the services that has never been used.
###assistant: SELECT service_name FROM services EXCEPT SELECT t1.service_name FROM services AS t1 JOIN party_services AS t2 ON t1.service_id = t2.service_id |
###context:CREATE TABLE addresses (town_city VARCHAR, state_province_county VARCHAR)
###human: Find the name of all the cities and states.
###assistant: SELECT town_city FROM addresses UNION SELECT state_province_county FROM addresses |
###context:CREATE TABLE addresses (state_province_county VARCHAR)
###human: How many cities are there in state "Colorado"?
###assistant: SELECT COUNT(*) FROM addresses WHERE state_province_county = "Colorado" |
###context:CREATE TABLE parties (payment_method_code VARCHAR)
###human: Find the payment method code used by more than 3 parties.
###assistant: SELECT payment_method_code FROM parties GROUP BY payment_method_code HAVING COUNT(*) > 3 |
###context:CREATE TABLE organizations (organization_name VARCHAR)
###human: Find the name of organizations whose names contain "Party".
###assistant: SELECT organization_name FROM organizations WHERE organization_name LIKE "%Party%" |
###context:CREATE TABLE parties (payment_method_code VARCHAR)
###human: How many distinct payment methods are used by parties?
###assistant: SELECT COUNT(DISTINCT payment_method_code) FROM parties |
###context:CREATE TABLE parties (party_email VARCHAR, party_id VARCHAR); CREATE TABLE party_services (customer_id VARCHAR)
###human: Which is the email of the party that has used the services the most number of times?
###assistant: SELECT t1.party_email FROM parties AS t1 JOIN party_services AS t2 ON t1.party_id = t2.customer_id GROUP BY t1.party_email ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE addresses (state_province_county VARCHAR, line_1_number_building VARCHAR)
###human: Which state can address "6862 Kaitlyn Knolls" possibly be in?
###assistant: SELECT state_province_county FROM addresses WHERE line_1_number_building LIKE "%6862 Kaitlyn Knolls%" |
###context:CREATE TABLE organization_contact_individuals (organization_id VARCHAR); CREATE TABLE organizations (organization_name VARCHAR, organization_id VARCHAR)
###human: What is the name of organization that has the greatest number of contact individuals?
###assistant: SELECT t1.organization_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id GROUP BY t1.organization_name ORDER BY COUNT(*) DESC LIMIT 1 |
###context:CREATE TABLE individuals (individual_last_name VARCHAR, individual_id VARCHAR); CREATE TABLE organization_contact_individuals (individual_id VARCHAR)
###human: Find the last name of the individuals that have been contact individuals of an organization.
###assistant: SELECT DISTINCT t1.individual_last_name FROM individuals AS t1 JOIN organization_contact_individuals AS t2 ON t1.individual_id = t2.individual_id |
###context:CREATE TABLE driver (Id VARCHAR)
###human: How many drivers are there?
###assistant: SELECT COUNT(*) FROM driver |
###context:CREATE TABLE driver (name VARCHAR, home_city VARCHAR, age VARCHAR)
###human: Show the name, home city, and age for all drivers.
###assistant: SELECT name, home_city, age FROM driver |
###context:CREATE TABLE driver (party VARCHAR)
###human: Show the party and the number of drivers in each party.
###assistant: SELECT party, COUNT(*) FROM driver GROUP BY party |
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