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###context:CREATE TABLE matches (tourney_name VARCHAR) ###human: Find the name of tourney that has more than 10 matches. ###assistant: SELECT tourney_name FROM matches GROUP BY tourney_name HAVING COUNT(*) > 10
###context:CREATE TABLE matches (winner_name VARCHAR, YEAR VARCHAR) ###human: List the names of all winners who played in both 2013 and 2016. ###assistant: SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016
###context:CREATE TABLE matches (YEAR VARCHAR) ###human: List the number of all matches who played in years of 2013 or 2016. ###assistant: SELECT COUNT(*) FROM matches WHERE YEAR = 2013 OR YEAR = 2016
###context:CREATE TABLE matches (winner_id VARCHAR, tourney_name VARCHAR); CREATE TABLE players (country_code VARCHAR, first_name VARCHAR, player_id VARCHAR) ###human: What are the country code and first name of the players who won in both tourney WTA Championships and Australian Open? ###assistant: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open'
###context:CREATE TABLE players (first_name VARCHAR, country_code VARCHAR, birth_date VARCHAR) ###human: Find the first name and country code of the oldest player. ###assistant: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1
###context:CREATE TABLE players (first_name VARCHAR, last_name VARCHAR, birth_date VARCHAR) ###human: List the first and last name of all players in the order of birth date. ###assistant: SELECT first_name, last_name FROM players ORDER BY birth_date
###context:CREATE TABLE players (first_name VARCHAR, last_name VARCHAR, hand VARCHAR, birth_date VARCHAR) ###human: List the first and last name of all players who are left / L hand in the order of birth date. ###assistant: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date
###context:CREATE TABLE players (country_code VARCHAR, first_name VARCHAR, player_id VARCHAR); CREATE TABLE rankings (player_id VARCHAR, tours VARCHAR) ###human: Find the first name and country code of the player who did the most number of tours. ###assistant: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1
###context:CREATE TABLE matches (YEAR VARCHAR) ###human: Find the year that has the most number of matches. ###assistant: SELECT YEAR FROM matches GROUP BY YEAR ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE matches (winner_name VARCHAR, winner_rank_points VARCHAR) ###human: Find the name and rank points of the winner who won the most times. ###assistant: SELECT winner_name, winner_rank_points FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE matches (winner_name VARCHAR, tourney_name VARCHAR, winner_rank_points VARCHAR) ###human: Find the name of the winner who has the highest rank points and participated in the Australian Open tourney. ###assistant: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1
###context:CREATE TABLE matches (winner_name VARCHAR, loser_name VARCHAR, minutes VARCHAR) ###human: find the names of loser and winner who played in the match with greatest number of minutes. ###assistant: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1
###context:CREATE TABLE players (first_name VARCHAR, player_id VARCHAR); CREATE TABLE rankings (player_id VARCHAR) ###human: Find the average ranking for each player and their first name. ###assistant: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
###context:CREATE TABLE players (first_name VARCHAR, player_id VARCHAR); CREATE TABLE rankings (player_id VARCHAR) ###human: Find the total ranking points for each player and their first name. ###assistant: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
###context:CREATE TABLE players (country_code VARCHAR) ###human: find the number of players for each country. ###assistant: SELECT COUNT(*), country_code FROM players GROUP BY country_code
###context:CREATE TABLE players (country_code VARCHAR) ###human: find the code of the country where has the greatest number of players. ###assistant: SELECT country_code FROM players GROUP BY country_code ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE players (country_code VARCHAR) ###human: Find the codes of countries that have more than 50 players. ###assistant: SELECT country_code FROM players GROUP BY country_code HAVING COUNT(*) > 50
###context:CREATE TABLE rankings (ranking_date VARCHAR, tours INTEGER) ###human: Find the total number of tours for each ranking date. ###assistant: SELECT SUM(tours), ranking_date FROM rankings GROUP BY ranking_date
###context:CREATE TABLE matches (YEAR VARCHAR) ###human: Find the number of matches happened in each year. ###assistant: SELECT COUNT(*), YEAR FROM matches GROUP BY YEAR
###context:CREATE TABLE matches (winner_name VARCHAR, winner_rank VARCHAR, winner_age VARCHAR) ###human: Find the name and rank of the 3 youngest winners across all matches. ###assistant: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3
###context:CREATE TABLE matches (winner_name VARCHAR, tourney_name VARCHAR, winner_hand VARCHAR) ###human: How many different winners both participated in the WTA Championships and were left handed? ###assistant: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L'
###context:CREATE TABLE players (first_name VARCHAR, country_code VARCHAR, birth_date VARCHAR, player_id VARCHAR); CREATE TABLE matches (winner_id VARCHAR, winner_rank_points VARCHAR) ###human: Find the first name, country code and birth date of the winner who has the highest rank points in all matches. ###assistant: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1
###context:CREATE TABLE players (hand VARCHAR) ###human: Find the number of players for each hand type. ###assistant: SELECT COUNT(*), hand FROM players GROUP BY hand
###context:CREATE TABLE ship (disposition_of_ship VARCHAR) ###human: How many ships ended up being 'Captured'? ###assistant: SELECT COUNT(*) FROM ship WHERE disposition_of_ship = 'Captured'
###context:CREATE TABLE ship (name VARCHAR, tonnage VARCHAR) ###human: List the name and tonnage ordered by in descending alphaetical order for the names. ###assistant: SELECT name, tonnage FROM ship ORDER BY name DESC
###context:CREATE TABLE battle (name VARCHAR, date VARCHAR) ###human: List the name, date and result of each battle. ###assistant: SELECT name, date FROM battle
###context:CREATE TABLE death (killed INTEGER) ###human: What is maximum and minimum death toll caused each time? ###assistant: SELECT MAX(killed), MIN(killed) FROM death
###context:CREATE TABLE death (injured INTEGER) ###human: What is the average number of injuries caused each time? ###assistant: SELECT AVG(injured) FROM death
###context:CREATE TABLE ship (Id VARCHAR); CREATE TABLE death (killed VARCHAR, injured VARCHAR, caused_by_ship_id VARCHAR) ###human: What are the death and injury situations caused by the ship with tonnage 't'? ###assistant: SELECT T1.killed, T1.injured FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id WHERE T2.tonnage = 't'
###context:CREATE TABLE battle (name VARCHAR, RESULT VARCHAR, bulgarian_commander VARCHAR) ###human: What are the name and results of the battles when the bulgarian commander is not 'Boril' ###assistant: SELECT name, RESULT FROM battle WHERE bulgarian_commander <> 'Boril'
###context:CREATE TABLE ship (lost_in_battle VARCHAR, ship_type VARCHAR); CREATE TABLE battle (id VARCHAR, name VARCHAR) ###human: What are the different ids and names of the battles that lost any 'Brig' type shipes? ###assistant: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.ship_type = 'Brig'
###context:CREATE TABLE death (caused_by_ship_id VARCHAR, killed INTEGER); CREATE TABLE battle (id VARCHAR, name VARCHAR); CREATE TABLE ship (lost_in_battle VARCHAR, id VARCHAR) ###human: What are the ids and names of the battles that led to more than 10 people killed in total. ###assistant: SELECT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle JOIN death AS T3 ON T2.id = T3.caused_by_ship_id GROUP BY T1.id HAVING SUM(T3.killed) > 10
###context:CREATE TABLE death (caused_by_ship_id VARCHAR); CREATE TABLE ship (Id VARCHAR) ###human: What is the ship id and name that caused most total injuries? ###assistant: SELECT T2.id, T2.name FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id GROUP BY T2.id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE battle (name VARCHAR, bulgarian_commander VARCHAR, latin_commander VARCHAR) ###human: What are the distinct battle names which are between bulgarian commander 'Kaloyan' and latin commander 'Baldwin I'? ###assistant: SELECT name FROM battle WHERE bulgarian_commander = 'Kaloyan' AND latin_commander = 'Baldwin I'
###context:CREATE TABLE battle (RESULT VARCHAR) ###human: How many different results are there for the battles? ###assistant: SELECT COUNT(DISTINCT RESULT) FROM battle
###context:CREATE TABLE ship (id VARCHAR, lost_in_battle VARCHAR, tonnage VARCHAR); CREATE TABLE battle (id VARCHAR, lost_in_battle VARCHAR, tonnage VARCHAR) ###human: How many battles did not lose any ship with tonnage '225'? ###assistant: SELECT COUNT(*) FROM battle WHERE NOT id IN (SELECT lost_in_battle FROM ship WHERE tonnage = '225')
###context:CREATE TABLE ship (lost_in_battle VARCHAR, name VARCHAR); CREATE TABLE battle (name VARCHAR, date VARCHAR, id VARCHAR) ###human: List the name and date the battle that has lost the ship named 'Lettice' and the ship named 'HMS Atalanta' ###assistant: SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta'
###context:CREATE TABLE ship (lost_in_battle VARCHAR, location VARCHAR); CREATE TABLE battle (name VARCHAR, RESULT VARCHAR, bulgarian_commander VARCHAR); CREATE TABLE battle (name VARCHAR, result VARCHAR, bulgarian_commander VARCHAR, id VARCHAR) ###human: Show names, results and bulgarian commanders of the battles with no ships lost in the 'English Channel'. ###assistant: SELECT name, RESULT, bulgarian_commander FROM battle EXCEPT SELECT T1.name, T1.result, T1.bulgarian_commander FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.location = 'English Channel'
###context:CREATE TABLE death (note VARCHAR) ###human: What are the notes of the death events which has substring 'East'? ###assistant: SELECT note FROM death WHERE note LIKE '%East%'
###context:CREATE TABLE addresses (line_1 VARCHAR, line_2 VARCHAR) ###human: what are all the addresses including line 1 and line 2? ###assistant: SELECT line_1, line_2 FROM addresses
###context:CREATE TABLE Courses (Id VARCHAR) ###human: How many courses in total are listed? ###assistant: SELECT COUNT(*) FROM Courses
###context:CREATE TABLE Courses (course_description VARCHAR, course_name VARCHAR) ###human: How is the math course described? ###assistant: SELECT course_description FROM Courses WHERE course_name = 'math'
###context:CREATE TABLE Addresses (zip_postcode VARCHAR, city VARCHAR) ###human: What is the zip code of the address in the city Port Chelsea? ###assistant: SELECT zip_postcode FROM Addresses WHERE city = 'Port Chelsea'
###context:CREATE TABLE Degree_Programs (department_id VARCHAR); CREATE TABLE Departments (department_name VARCHAR, department_id VARCHAR) ###human: Which department offers the most number of degrees? List department name and id. ###assistant: SELECT T2.department_name, T1.department_id FROM Degree_Programs AS T1 JOIN Departments AS T2 ON T1.department_id = T2.department_id GROUP BY T1.department_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE degree_programs (department_id VARCHAR); CREATE TABLE departments (department_name VARCHAR, department_id VARCHAR) ###human: What is the name and id of the department with the most number of degrees ? ###assistant: SELECT t2.department_name, t1.department_id FROM degree_programs AS t1 JOIN departments AS t2 ON t1.department_id = t2.department_id GROUP BY t1.department_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Degree_Programs (department_id VARCHAR) ###human: How many departments offer any degree? ###assistant: SELECT COUNT(DISTINCT department_id) FROM Degree_Programs
###context:CREATE TABLE Degree_Programs (degree_summary_name VARCHAR) ###human: How many different degree names are offered? ###assistant: SELECT COUNT(DISTINCT degree_summary_name) FROM Degree_Programs
###context:CREATE TABLE Degree_Programs (department_id VARCHAR); CREATE TABLE Departments (department_id VARCHAR, department_name VARCHAR) ###human: How many degrees does the engineering department offer? ###assistant: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer'
###context:CREATE TABLE Sections (section_name VARCHAR, section_description VARCHAR) ###human: What are the names and descriptions of all the sections? ###assistant: SELECT section_name, section_description FROM Sections
###context:CREATE TABLE Courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE Sections (course_id VARCHAR) ###human: What are the names and id of courses having at most 2 sections? ###assistant: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2
###context:CREATE TABLE Sections (section_name VARCHAR) ###human: List the section_name in reversed lexicographical order. ###assistant: SELECT section_name FROM Sections ORDER BY section_name DESC
###context:CREATE TABLE Student_Enrolment (semester_id VARCHAR); CREATE TABLE Semesters (semester_name VARCHAR, semester_id VARCHAR) ###human: What is the semester which most student registered in? Show both the name and the id. ###assistant: SELECT T1.semester_name, T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Departments (department_description VARCHAR, department_name VARCHAR) ###human: What is the description of the department whose name has the substring the computer? ###assistant: SELECT department_description FROM Departments WHERE department_name LIKE '%computer%'
###context:CREATE TABLE Students (first_name VARCHAR, middle_name VARCHAR, last_name VARCHAR, student_id VARCHAR); CREATE TABLE Student_Enrolment (student_id VARCHAR) ###human: Who are enrolled in 2 degree programs in one semester? List the first name, middle name and last name and the id. ###assistant: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2
###context:CREATE TABLE Degree_Programs (degree_program_id VARCHAR, degree_summary_name VARCHAR); CREATE TABLE Students (first_name VARCHAR, middle_name VARCHAR, last_name VARCHAR, student_id VARCHAR); CREATE TABLE Student_Enrolment (student_id VARCHAR, degree_program_id VARCHAR) ###human: Who is enrolled in a Bachelor degree program? List the first name, middle name, last name. ###assistant: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor'
###context:CREATE TABLE Student_Enrolment (degree_program_id VARCHAR); CREATE TABLE Degree_Programs (degree_summary_name VARCHAR, degree_program_id VARCHAR) ###human: Find the kind of program which most number of students are enrolled in? ###assistant: SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Degree_Programs (degree_program_id VARCHAR, degree_summary_name VARCHAR); CREATE TABLE Student_Enrolment (degree_program_id VARCHAR) ###human: Find the program which most number of students are enrolled in. List both the id and the summary. ###assistant: SELECT T1.degree_program_id, T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Students (student_id VARCHAR, first_name VARCHAR, middle_name VARCHAR, last_name VARCHAR); CREATE TABLE Student_Enrolment (student_id VARCHAR) ###human: Which student has enrolled for the most times in any program? List the id, first name, middle name, last name, the number of enrollments and student id. ###assistant: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Student_Enrolment (semester_name VARCHAR, semester_id VARCHAR); CREATE TABLE Semesters (semester_name VARCHAR, semester_id VARCHAR) ###human: Which semesters do not have any student enrolled? List the semester name. ###assistant: SELECT semester_name FROM Semesters WHERE NOT semester_id IN (SELECT semester_id FROM Student_Enrolment)
###context:CREATE TABLE Courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE Student_Enrolment_Courses (course_id VARCHAR) ###human: What are all the course names of the courses which ever have students enrolled in? ###assistant: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
###context:CREATE TABLE Courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE Student_Enrolment_Courses (course_id VARCHAR) ###human: What's the name of the course with most number of enrollments? ###assistant: SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Addresses (address_id VARCHAR, state_province_county VARCHAR); CREATE TABLE Students (last_name VARCHAR, current_address_id VARCHAR); CREATE TABLE Students (last_name VARCHAR, student_id VARCHAR); CREATE TABLE Student_Enrolment (student_id VARCHAR) ###human: Find the last name of the students who currently live in the state of North Carolina but have not registered in any degree program. ###assistant: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id
###context:CREATE TABLE Transcript_Contents (transcript_id VARCHAR); CREATE TABLE Transcripts (transcript_date VARCHAR, transcript_id VARCHAR) ###human: Show the date and id of the transcript with at least 2 course results. ###assistant: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
###context:CREATE TABLE Students (cell_mobile_number VARCHAR, first_name VARCHAR, last_name VARCHAR) ###human: What is the phone number of the man with the first name Timmothy and the last name Ward? ###assistant: SELECT cell_mobile_number FROM Students WHERE first_name = 'Timmothy' AND last_name = 'Ward'
###context:CREATE TABLE students (cell_mobile_number VARCHAR, first_name VARCHAR, last_name VARCHAR) ###human: What is the mobile phone number of the student named Timmothy Ward ? ###assistant: SELECT cell_mobile_number FROM students WHERE first_name = 'timmothy' AND last_name = 'ward'
###context:CREATE TABLE Students (first_name VARCHAR, middle_name VARCHAR, last_name VARCHAR, date_first_registered VARCHAR) ###human: Who is the first student to register? List the first name, middle name and last name. ###assistant: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered LIMIT 1
###context:CREATE TABLE Students (first_name VARCHAR, middle_name VARCHAR, last_name VARCHAR, date_left VARCHAR) ###human: Who is the earliest graduate of the school? List the first name, middle name and last name. ###assistant: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left LIMIT 1
###context:CREATE TABLE Students (first_name VARCHAR, current_address_id VARCHAR, permanent_address_id VARCHAR) ###human: Whose permanent address is different from his or her current address? List his or her first name. ###assistant: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id
###context:CREATE TABLE Addresses (address_id VARCHAR, line_1 VARCHAR, line_2 VARCHAR); CREATE TABLE Students (current_address_id VARCHAR) ###human: Which address holds the most number of students currently? List the address id and all lines. ###assistant: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Transcripts (transcript_date INTEGER) ###human: On average, when were the transcripts printed? ###assistant: SELECT AVG(transcript_date) FROM Transcripts
###context:CREATE TABLE Transcripts (transcript_date VARCHAR, other_details VARCHAR) ###human: When is the first transcript released? List the date and details. ###assistant: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date LIMIT 1
###context:CREATE TABLE Transcripts (Id VARCHAR) ###human: How many transcripts are released? ###assistant: SELECT COUNT(*) FROM Transcripts
###context:CREATE TABLE Transcripts (transcript_date VARCHAR) ###human: What is the last transcript release date? ###assistant: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1
###context:CREATE TABLE Transcript_Contents (student_course_id VARCHAR) ###human: How many times at most can a course enrollment result show in different transcripts? Also show the course enrollment id. ###assistant: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE Transcript_Contents (transcript_id VARCHAR); CREATE TABLE Transcripts (transcript_date VARCHAR, transcript_id VARCHAR) ###human: Show the date of the transcript which shows the least number of results, also list the id. ###assistant: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) LIMIT 1
###context:CREATE TABLE Degree_Programs (degree_program_id VARCHAR); CREATE TABLE Student_Enrolment (semester_id VARCHAR, degree_program_id VARCHAR) ###human: Find the semester when both Master students and Bachelor students got enrolled in. ###assistant: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor'
###context:CREATE TABLE Students (current_address_id VARCHAR) ###human: How many different addresses do the students currently live? ###assistant: SELECT COUNT(DISTINCT current_address_id) FROM Students
###context:CREATE TABLE Students (other_student_details VARCHAR) ###human: List all the student details in reversed lexicographical order. ###assistant: SELECT other_student_details FROM Students ORDER BY other_student_details DESC
###context:CREATE TABLE Sections (section_description VARCHAR, section_name VARCHAR) ###human: Describe the section h. ###assistant: SELECT section_description FROM Sections WHERE section_name = 'h'
###context:CREATE TABLE students (first_name VARCHAR, permanent_address_id VARCHAR, cell_mobile_number VARCHAR); CREATE TABLE addresses (address_id VARCHAR, country VARCHAR) ###human: Find the first name of the students who permanently live in the country Haiti or have the cell phone number 09700166582 . ###assistant: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582'
###context:CREATE TABLE Cartoon (Title VARCHAR, title VARCHAR) ###human: List the title of all cartoons in alphabetical order. ###assistant: SELECT Title FROM Cartoon ORDER BY title
###context:CREATE TABLE Cartoon (Title VARCHAR, Directed_by VARCHAR) ###human: List all cartoon directed by "Ben Jones". ###assistant: SELECT Title FROM Cartoon WHERE Directed_by = "Ben Jones"
###context:CREATE TABLE Cartoon (Written_by VARCHAR) ###human: How many cartoons were written by "Joseph Kuhr"? ###assistant: SELECT COUNT(*) FROM Cartoon WHERE Written_by = "Joseph Kuhr"
###context:CREATE TABLE Cartoon (title VARCHAR, Directed_by VARCHAR, Original_air_date VARCHAR) ###human: list all cartoon titles and their directors ordered by their air date ###assistant: SELECT title, Directed_by FROM Cartoon ORDER BY Original_air_date
###context:CREATE TABLE Cartoon (Title VARCHAR, Directed_by VARCHAR) ###human: List the title of all cartoon directed by "Ben Jones" or "Brandon Vietti". ###assistant: SELECT Title FROM Cartoon WHERE Directed_by = "Ben Jones" OR Directed_by = "Brandon Vietti"
###context:CREATE TABLE TV_Channel (Country VARCHAR) ###human: Which country has the most of TV Channels? List the country and number of TV Channels it has. ###assistant: SELECT Country, COUNT(*) FROM TV_Channel GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1
###context:CREATE TABLE TV_Channel (series_name VARCHAR, content VARCHAR) ###human: List the number of different series names and contents in the TV Channel table. ###assistant: SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel
###context:CREATE TABLE TV_Channel (Content VARCHAR, series_name VARCHAR) ###human: What is the content of TV Channel with serial name "Sky Radio"? ###assistant: SELECT Content FROM TV_Channel WHERE series_name = "Sky Radio"
###context:CREATE TABLE TV_Channel (Package_Option VARCHAR, series_name VARCHAR) ###human: What is the Package Option of TV Channel with serial name "Sky Radio"? ###assistant: SELECT Package_Option FROM TV_Channel WHERE series_name = "Sky Radio"
###context:CREATE TABLE TV_Channel (LANGUAGE VARCHAR) ###human: How many TV Channel using language English? ###assistant: SELECT COUNT(*) FROM TV_Channel WHERE LANGUAGE = "English"
###context:CREATE TABLE TV_Channel (LANGUAGE VARCHAR) ###human: List the language used least number of TV Channel. List language and number of TV Channel. ###assistant: SELECT LANGUAGE, COUNT(*) FROM TV_Channel GROUP BY LANGUAGE ORDER BY COUNT(*) LIMIT 1
###context:CREATE TABLE TV_Channel (LANGUAGE VARCHAR) ###human: List each language and the number of TV Channels using it. ###assistant: SELECT LANGUAGE, COUNT(*) FROM TV_Channel GROUP BY LANGUAGE
###context:CREATE TABLE Cartoon (Channel VARCHAR, Title VARCHAR); CREATE TABLE TV_Channel (series_name VARCHAR, id VARCHAR) ###human: What is the TV Channel that shows the cartoon "The Rise of the Blue Beetle!"? List the TV Channel's series name. ###assistant: SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = "The Rise of the Blue Beetle!"
###context:CREATE TABLE Cartoon (Title VARCHAR, Channel VARCHAR); CREATE TABLE TV_Channel (id VARCHAR, series_name VARCHAR) ###human: List the title of all Cartoons showed on TV Channel with series name "Sky Radio". ###assistant: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
###context:CREATE TABLE TV_series (Episode VARCHAR, rating VARCHAR) ###human: List the Episode of all TV series sorted by rating. ###assistant: SELECT Episode FROM TV_series ORDER BY rating
###context:CREATE TABLE TV_series (Episode VARCHAR, Rating VARCHAR) ###human: List top 3 highest Rating TV series. List the TV series's Episode and Rating. ###assistant: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3
###context:CREATE TABLE TV_series (SHARE INTEGER) ###human: What is minimum and maximum share of TV series? ###assistant: SELECT MAX(SHARE), MIN(SHARE) FROM TV_series
###context:CREATE TABLE TV_series (Air_Date VARCHAR, Episode VARCHAR) ###human: What is the air date of TV series with Episode "A Love of a Lifetime"? ###assistant: SELECT Air_Date FROM TV_series WHERE Episode = "A Love of a Lifetime"
###context:CREATE TABLE TV_series (Weekly_Rank VARCHAR, Episode VARCHAR) ###human: What is Weekly Rank of TV series with Episode "A Love of a Lifetime"? ###assistant: SELECT Weekly_Rank FROM TV_series WHERE Episode = "A Love of a Lifetime"
###context:CREATE TABLE TV_series (Channel VARCHAR, Episode VARCHAR); CREATE TABLE TV_Channel (series_name VARCHAR, id VARCHAR) ###human: What is the TV Channel of TV series with Episode "A Love of a Lifetime"? List the TV Channel's series name. ###assistant: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime"