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Question: What are the names of the tourist attractions that have parking or shopping as their feature details? Context: CREATE TABLE Tourist_Attraction_Features (tourist_attraction_id VARCHAR, Feature_ID VARCHAR); CREATE TABLE Features (Feature_ID VARCHAR, feature_Details VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, tourist_attraction_id VARCHAR) Answer:
SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'park' UNION SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'shopping'
Question: What are the names of tourist attractions that can be reached by bus or is at address 254 Ottilie Junction? Context: CREATE TABLE Tourist_Attractions (Name VARCHAR, Location_ID VARCHAR, How_to_Get_There VARCHAR); CREATE TABLE Locations (Location_ID VARCHAR, Address VARCHAR) Answer:
SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID = T2.Location_ID WHERE T1.Address = "254 Ottilie Junction" OR T2.How_to_Get_There = "bus"
Question: What are the names of the tourist attractions Vincent and Marcelle visit? Context: CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR, Tourist_ID VARCHAR); CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR) Answer:
SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Vincent" INTERSECT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Marcelle"
Question: What are the names of tourist attraction that Alison visited but Rosalind did not visit? Context: CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR, Tourist_ID VARCHAR); CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR) Answer:
SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Alison" EXCEPT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Rosalind"
Question: How many tourists did not make any visit? Context: CREATE TABLE Visitors (Tourist_ID VARCHAR); CREATE TABLE Visits (Tourist_ID VARCHAR) Answer:
SELECT COUNT(*) FROM Visitors WHERE NOT Tourist_ID IN (SELECT Tourist_ID FROM Visits)
Question: How many video games exist? Context: CREATE TABLE Video_games (Id VARCHAR) Answer:
SELECT COUNT(*) FROM Video_games
Question: How many video game types exist? Context: CREATE TABLE Video_games (gtype VARCHAR) Answer:
SELECT COUNT(DISTINCT gtype) FROM Video_games
Question: Show all video game types. Context: CREATE TABLE Video_games (gtype VARCHAR) Answer:
SELECT DISTINCT gtype FROM Video_games
Question: Show all video games and their types in the order of their names. Context: CREATE TABLE Video_games (gname VARCHAR, gtype VARCHAR) Answer:
SELECT gname, gtype FROM Video_games ORDER BY gname
Question: Show all video games with type Collectible card game. Context: CREATE TABLE Video_games (gname VARCHAR, gtype VARCHAR) Answer:
SELECT gname FROM Video_games WHERE gtype = "Collectible card game"
Question: What is the type of video game Call of Destiny. Context: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR) Answer:
SELECT gtype FROM Video_games WHERE gname = "Call of Destiny"
Question: How many video games have type Massively multiplayer online game? Context: CREATE TABLE Video_games (gtype VARCHAR) Answer:
SELECT COUNT(*) FROM Video_games WHERE gtype = "Massively multiplayer online game"
Question: Show all video game types and the number of video games in each type. Context: CREATE TABLE Video_games (gtype VARCHAR) Answer:
SELECT gtype, COUNT(*) FROM Video_games GROUP BY gtype
Question: Which game type has most number of games? Context: CREATE TABLE Video_games (gtype VARCHAR) Answer:
SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) DESC LIMIT 1
Question: Which game type has least number of games? Context: CREATE TABLE Video_games (gtype VARCHAR) Answer:
SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) LIMIT 1
Question: Show ids for all students who live in CHI. Context: CREATE TABLE Student (StuID VARCHAR, city_code VARCHAR) Answer:
SELECT StuID FROM Student WHERE city_code = "CHI"
Question: Show ids for all students who have advisor 1121. Context: CREATE TABLE Student (StuID VARCHAR, Advisor VARCHAR) Answer:
SELECT StuID FROM Student WHERE Advisor = 1121
Question: Show first name for all students with major 600. Context: CREATE TABLE Student (Fname VARCHAR, Major VARCHAR) Answer:
SELECT Fname FROM Student WHERE Major = 600
Question: Show the average, minimum, and maximum age for different majors. Context: CREATE TABLE Student (major VARCHAR, age INTEGER) Answer:
SELECT major, AVG(age), MIN(age), MAX(age) FROM Student GROUP BY major
Question: Show all advisors who have at least two students. Context: CREATE TABLE Student (advisor VARCHAR) Answer:
SELECT advisor FROM Student GROUP BY advisor HAVING COUNT(*) >= 2
Question: How many sports do we have? Context: CREATE TABLE Sportsinfo (sportname VARCHAR) Answer:
SELECT COUNT(DISTINCT sportname) FROM Sportsinfo
Question: How many students play sports? Context: CREATE TABLE Sportsinfo (StuID VARCHAR) Answer:
SELECT COUNT(DISTINCT StuID) FROM Sportsinfo
Question: List ids for all student who are on scholarship. Context: CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR) Answer:
SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
Question: Show last names for all student who are on scholarship. Context: CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR) Answer:
SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y'
Question: How many games are played for all students? Context: CREATE TABLE Sportsinfo (gamesplayed INTEGER) Answer:
SELECT SUM(gamesplayed) FROM Sportsinfo
Question: How many games are played for all football games by students on scholarship? Context: CREATE TABLE Sportsinfo (gamesplayed INTEGER, sportname VARCHAR, onscholarship VARCHAR) Answer:
SELECT SUM(gamesplayed) FROM Sportsinfo WHERE sportname = "Football" AND onscholarship = 'Y'
Question: Show all sport name and the number of students. Context: CREATE TABLE Sportsinfo (sportname VARCHAR) Answer:
SELECT sportname, COUNT(*) FROM Sportsinfo GROUP BY sportname
Question: Show all student IDs with the number of sports and total number of games played Context: CREATE TABLE Sportsinfo (StuID VARCHAR, gamesplayed INTEGER) Answer:
SELECT StuID, COUNT(*), SUM(gamesplayed) FROM Sportsinfo GROUP BY StuID
Question: Show all student IDs with more than total 10 hours per week on all sports played. Context: CREATE TABLE Sportsinfo (StuID VARCHAR, hoursperweek INTEGER) Answer:
SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING SUM(hoursperweek) > 10
Question: What is the first name and last name of the student who have most number of sports? Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR) Answer:
SELECT T2.Fname, T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1
Question: Which sport has most number of students on scholarship? Context: CREATE TABLE Sportsinfo (sportname VARCHAR, onscholarship VARCHAR) Answer:
SELECT sportname FROM Sportsinfo WHERE onscholarship = 'Y' GROUP BY sportname ORDER BY COUNT(*) DESC LIMIT 1
Question: Show student ids who don't have any sports. Context: CREATE TABLE Sportsinfo (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR) Answer:
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
Question: Show student ids who are on scholarship and have major 600. Context: CREATE TABLE Sportsinfo (StuID VARCHAR, major VARCHAR, onscholarship VARCHAR); CREATE TABLE Student (StuID VARCHAR, major VARCHAR, onscholarship VARCHAR) Answer:
SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
Question: Show student ids who are female and play football. Context: CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR); CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR) Answer:
SELECT StuID FROM Student WHERE sex = 'F' INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "Football"
Question: Show all male student ids who don't play football. Context: CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR); CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR) Answer:
SELECT StuID FROM Student WHERE sex = 'M' EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "Football"
Question: Show total hours per week and number of games played for student David Shieber. Context: CREATE TABLE Student (StuID VARCHAR, Fname VARCHAR, Lname VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR) Answer:
SELECT SUM(hoursperweek), SUM(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "David" AND T2.Lname = "Shieber"
Question: Show total hours per week and number of games played for students under 20. Context: CREATE TABLE Student (StuID VARCHAR, age INTEGER); CREATE TABLE Sportsinfo (StuID VARCHAR) Answer:
SELECT SUM(hoursperweek), SUM(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20
Question: How many students play video games? Context: CREATE TABLE Plays_games (StuID VARCHAR) Answer:
SELECT COUNT(DISTINCT StuID) FROM Plays_games
Question: Show ids of students who don't play video game. Context: CREATE TABLE Plays_games (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR) Answer:
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
Question: Show ids of students who play video game and play sports. Context: CREATE TABLE Plays_games (StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR) Answer:
SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
Question: Show all game ids and the number of hours played. Context: CREATE TABLE Plays_games (gameid VARCHAR, hours_played INTEGER) Answer:
SELECT gameid, SUM(hours_played) FROM Plays_games GROUP BY gameid
Question: Show all student ids and the number of hours played. Context: CREATE TABLE Plays_games (Stuid VARCHAR, hours_played INTEGER) Answer:
SELECT Stuid, SUM(hours_played) FROM Plays_games GROUP BY Stuid
Question: Show the game name that has most number of hours played. Context: CREATE TABLE Plays_games (gameid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR) Answer:
SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY SUM(hours_played) DESC LIMIT 1
Question: Show all game names played by at least 1000 hours. Context: CREATE TABLE Plays_games (gameid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR) Answer:
SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING SUM(hours_played) >= 1000
Question: Show all game names played by Linda Smith Context: CREATE TABLE Student (Stuid VARCHAR, Lname VARCHAR, Fname VARCHAR); CREATE TABLE Plays_games (gameid VARCHAR, Stuid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR) Answer:
SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "Smith" AND T3.Fname = "Linda"
Question: Find the last and first name of students who are playing Football or Lacrosse. Context: CREATE TABLE SportsInfo (StuID VARCHAR, SportName VARCHAR); CREATE TABLE Student (lname VARCHAR, fname VARCHAR, StuID VARCHAR) Answer:
SELECT T2.lname, T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "Football" OR T1.SportName = "Lacrosse"
Question: Find the first name and age of the students who are playing both Football and Lacrosse. Context: CREATE TABLE Student (fname VARCHAR, age VARCHAR, StuID VARCHAR, SportName VARCHAR); CREATE TABLE Sportsinfo (fname VARCHAR, age VARCHAR, StuID VARCHAR, SportName VARCHAR) Answer:
SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "Football" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "Lacrosse")
Question: Find the last name and gender of the students who are playing both Call of Destiny and Works of Widenius games. Context: CREATE TABLE Plays_games (StuID VARCHAR, GameID VARCHAR); CREATE TABLE Student (lname VARCHAR, sex VARCHAR, StuID VARCHAR); CREATE TABLE Video_games (GameID VARCHAR, Gname VARCHAR) Answer:
SELECT lname, sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Call of Destiny" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Works of Widenius")
Question: Find the name of all customers. Context: CREATE TABLE customers (customer_name VARCHAR) Answer:
SELECT customer_name FROM customers
Question: What is the average amount of items ordered in each order? Context: CREATE TABLE order_items (order_quantity INTEGER) Answer:
SELECT AVG(order_quantity) FROM order_items
Question: What are the names of customers who use payment method "Cash"? Context: CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR) Answer:
SELECT customer_name FROM customers WHERE payment_method = "Cash"
Question: Find the "date became customers" of the customers whose ID is between 10 and 20. Context: CREATE TABLE customers (date_became_customer VARCHAR, customer_id INTEGER) Answer:
SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
Question: Which payment method is used by most customers? Context: CREATE TABLE customers (payment_method VARCHAR) Answer:
SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1
Question: What are the names of customers using the most popular payment method? Context: CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR) Answer:
SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1)
Question: What are all the payment methods? Context: CREATE TABLE customers (payment_method VARCHAR) Answer:
SELECT DISTINCT payment_method FROM customers
Question: What are the details of all products? Context: CREATE TABLE products (product_details VARCHAR) Answer:
SELECT DISTINCT product_details FROM products
Question: Find the name of all customers whose name contains "Alex". Context: CREATE TABLE customers (customer_name VARCHAR) Answer:
SELECT customer_name FROM customers WHERE customer_name LIKE "%Alex%"
Question: Find the detail of products whose detail contains the word "Latte" or the word "Americano" Context: CREATE TABLE products (product_details VARCHAR) Answer:
SELECT product_details FROM products WHERE product_details LIKE "%Latte%" OR product_details LIKE "%Americano%"
Question: What is the address content of the customer named "Maudie Kertzmann"? Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE addresses (address_content VARCHAR, address_id VARCHAR) Answer:
SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "Maudie Kertzmann"
Question: How many customers are living in city "Lake Geovannyton"? Context: CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, city VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR) Answer:
SELECT COUNT(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "Lake Geovannyton"
Question: Find the name of customers who are living in Colorado? Context: CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) Answer:
SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "Colorado"
Question: Find the list of cities that no customer is living in. Context: CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE addresses (city VARCHAR) Answer:
SELECT city FROM addresses WHERE NOT city IN (SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id)
Question: Which city has the most customers living in? Context: CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR) Answer:
SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY COUNT(*) DESC LIMIT 1
Question: Find the city with post code 255. Context: CREATE TABLE addresses (city VARCHAR, zip_postcode VARCHAR) Answer:
SELECT city FROM addresses WHERE zip_postcode = 255
Question: Find the state and country of all cities with post code starting with 4. Context: CREATE TABLE addresses (state_province_county VARCHAR, country VARCHAR, zip_postcode VARCHAR) Answer:
SELECT state_province_county, country FROM addresses WHERE zip_postcode LIKE "4%"
Question: List the countries having more than 4 addresses listed. Context: CREATE TABLE addresses (country VARCHAR, address_id VARCHAR) Answer:
SELECT country FROM addresses GROUP BY country HAVING COUNT(address_id) > 4
Question: List all the contact channel codes that were used less than 5 times. Context: CREATE TABLE customer_contact_channels (channel_code VARCHAR, customer_id VARCHAR) Answer:
SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING COUNT(customer_id) < 5
Question: Which contact channel has been used by the customer with name "Tillman Ernser"? Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_contact_channels (customer_id VARCHAR) Answer:
SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser"
Question: What is the "active to date" of the latest contact channel used by "Tillman Ernser"? Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_contact_channels (active_to_date INTEGER, customer_id VARCHAR) Answer:
SELECT MAX(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser"
Question: What is the average time span of contact channels in the database? Context: CREATE TABLE customer_contact_channels (active_to_date VARCHAR, active_from_date VARCHAR) Answer:
SELECT AVG(active_to_date - active_from_date) FROM customer_contact_channels
Question: What is the channel code and contact number of the customer contact channel that was active for the longest time? Context: CREATE TABLE customer_contact_channels (channel_code VARCHAR, contact_number VARCHAR, active_to_date VARCHAR, active_from_date VARCHAR) Answer:
SELECT channel_code, contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1)
Question: Find the name and active date of the customer that use email as the contact channel. Context: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_contact_channels (active_from_date VARCHAR, customer_id VARCHAR, channel_code VARCHAR) Answer:
SELECT t1.customer_name, t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = 'Email'
Question: What is the name of the customer that made the order with the largest quantity? Context: CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE order_items (order_quantity INTEGER); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) Answer:
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = (SELECT MAX(order_quantity) FROM order_items)
Question: What is the name of the customer that has purchased the most items? Context: CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) Answer:
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY SUM(t3.order_quantity) DESC LIMIT 1
Question: What is the payment method of the customer that has purchased the least quantity of items? Context: CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) Answer:
SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY SUM(t3.order_quantity) LIMIT 1
Question: How many types of products have Rodrick Heaney bought in total? Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE order_items (product_id VARCHAR, order_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) Answer:
SELECT COUNT(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney"
Question: What is the total quantity of products purchased by "Rodrick Heaney"? Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) Answer:
SELECT SUM(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney"
Question: How many customers have at least one order with status "Cancelled"? Context: CREATE TABLE customer_orders (customer_id VARCHAR, order_status VARCHAR) Answer:
SELECT COUNT(DISTINCT customer_id) FROM customer_orders WHERE order_status = "Cancelled"
Question: How many orders have detail "Second time"? Context: CREATE TABLE customer_orders (order_details VARCHAR) Answer:
SELECT COUNT(*) FROM customer_orders WHERE order_details = "Second time"
Question: Find the customer name and date of the orders that have the status "Delivered". Context: CREATE TABLE customer_orders (order_date VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) Answer:
SELECT t1.customer_name, t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "Delivered"
Question: What is the total number of products that are in orders with status "Cancelled"? Context: CREATE TABLE customer_orders (order_id VARCHAR, order_status VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR) Answer:
SELECT SUM(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "Cancelled"
Question: Find the total amount of products ordered before 2018-03-17 07:13:53. Context: CREATE TABLE customer_orders (order_id VARCHAR, order_date INTEGER); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR) Answer:
SELECT SUM(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018-03-17 07:13:53"
Question: Who made the latest order? Context: CREATE TABLE customer_orders (customer_id VARCHAR, order_date VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) Answer:
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1
Question: Which product has been ordered most number of times? Context: CREATE TABLE products (product_details VARCHAR, product_id VARCHAR); CREATE TABLE order_items (product_id VARCHAR) Answer:
SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY COUNT(*) DESC LIMIT 1
Question: Find the name and ID of the product whose total order quantity is the largest. Context: CREATE TABLE order_items (product_id VARCHAR, order_quantity INTEGER); CREATE TABLE products (product_details VARCHAR, product_id VARCHAR) Answer:
SELECT t2.product_details, t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY SUM(t1.order_quantity) LIMIT 1
Question: Find all the addresses in East Julianaside, Texas or in Gleasonmouth, Arizona. Context: CREATE TABLE addresses (address_content VARCHAR, city VARCHAR, state_province_county VARCHAR) Answer:
SELECT address_content FROM addresses WHERE city = "East Julianaside" AND state_province_county = "Texas" UNION SELECT address_content FROM addresses WHERE city = "Gleasonmouth" AND state_province_county = "Arizona"
Question: Find the name of customers who did not pay with Cash. Context: CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR) Answer:
SELECT customer_name FROM customers WHERE payment_method <> 'Cash'
Question: Find the names of customers who never ordered product Latte. Context: CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_details VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) Answer:
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte'
Question: Find the names of customers who never placed an order. Context: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR) Answer:
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id
Question: Find the names of customers who ordered both products Latte and Americano. Context: CREATE TABLE products (product_id VARCHAR, product_details VARCHAR); CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) Answer:
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Americano'
Question: List the age of all music artists. Context: CREATE TABLE artist (Age VARCHAR) Answer:
SELECT Age FROM artist
Question: What is the average age of all artists? Context: CREATE TABLE artist (Age INTEGER) Answer:
SELECT AVG(Age) FROM artist
Question: What are the famous titles of the artist "Triumfall"? Context: CREATE TABLE artist (Famous_Title VARCHAR, Artist VARCHAR) Answer:
SELECT Famous_Title FROM artist WHERE Artist = "Triumfall"
Question: What are the distinct Famous release dates? Context: CREATE TABLE artist (Famous_Release_date VARCHAR) Answer:
SELECT DISTINCT (Famous_Release_date) FROM artist
Question: Return the dates of ceremony and the results of all music festivals Context: CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR) Answer:
SELECT Date_of_ceremony, RESULT FROM music_festival
Question: What are the category of music festivals with result "Awarded"? Context: CREATE TABLE music_festival (Category VARCHAR, RESULT VARCHAR) Answer:
SELECT Category FROM music_festival WHERE RESULT = "Awarded"
Question: What are the maximum and minimum week on top of all volumes? Context: CREATE TABLE volume (Weeks_on_Top INTEGER) Answer:
SELECT MAX(Weeks_on_Top), MIN(Weeks_on_Top) FROM volume
Question: What are the songs in volumes with more than 1 week on top? Context: CREATE TABLE volume (Song VARCHAR, Weeks_on_Top INTEGER) Answer:
SELECT Song FROM volume WHERE Weeks_on_Top > 1
Question: Please list all songs in volumes in ascending alphabetical order. Context: CREATE TABLE volume (Song VARCHAR) Answer:
SELECT Song FROM volume ORDER BY Song
Question: How many distinct artists do the volumes associate to? Context: CREATE TABLE volume (Artist_ID VARCHAR) Answer:
SELECT COUNT(DISTINCT Artist_ID) FROM volume