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Question: Which winery is the wine that has the highest score from?
Context: CREATE TABLE WINE (Winery VARCHAR, SCORE VARCHAR)
Answer:
|
SELECT Winery FROM WINE ORDER BY SCORE LIMIT 1
|
Question: Find the names of all wines produced in 2008.
Context: CREATE TABLE WINE (Name VARCHAR, YEAR VARCHAR)
Answer:
|
SELECT Name FROM WINE WHERE YEAR = "2008"
|
Question: List the grapes and appelations of all wines.
Context: CREATE TABLE WINE (Grape VARCHAR, Appelation VARCHAR)
Answer:
|
SELECT Grape, Appelation FROM WINE
|
Question: List the names and scores of all wines.
Context: CREATE TABLE WINE (Name VARCHAR, Score VARCHAR)
Answer:
|
SELECT Name, Score FROM WINE
|
Question: List the area and county of all appelations.
Context: CREATE TABLE APPELLATIONS (Area VARCHAR, County VARCHAR)
Answer:
|
SELECT Area, County FROM APPELLATIONS
|
Question: What are the prices of wines produced before the year of 2010?
Context: CREATE TABLE WINE (Price VARCHAR, YEAR INTEGER)
Answer:
|
SELECT Price FROM WINE WHERE YEAR < 2010
|
Question: List the names of all distinct wines that have scores higher than 90.
Context: CREATE TABLE WINE (Name VARCHAR, score INTEGER)
Answer:
|
SELECT Name FROM WINE WHERE score > 90
|
Question: List the names of all distinct wines that are made of red color grape.
Context: CREATE TABLE GRAPES (Grape VARCHAR, Color VARCHAR); CREATE TABLE WINE (Name VARCHAR, Grape VARCHAR)
Answer:
|
SELECT DISTINCT T2.Name FROM GRAPES AS T1 JOIN WINE AS T2 ON T1.Grape = T2.Grape WHERE T1.Color = "Red"
|
Question: Find the names of all distinct wines that have appellations in North Coast area.
Context: CREATE TABLE APPELLATIONs (Appelation VARCHAR, Area VARCHAR); CREATE TABLE WINE (Name VARCHAR, Appelation VARCHAR)
Answer:
|
SELECT DISTINCT T2.Name FROM APPELLATIONs AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation WHERE T1.Area = "North Coast"
|
Question: How many wines are produced at Robert Biale winery?
Context: CREATE TABLE WINE (Winery VARCHAR)
Answer:
|
SELECT COUNT(*) FROM WINE WHERE Winery = "Robert Biale"
|
Question: How many appelations are in Napa Country?
Context: CREATE TABLE APPELLATIONS (County VARCHAR)
Answer:
|
SELECT COUNT(*) FROM APPELLATIONS WHERE County = "Napa"
|
Question: Give me the average prices of wines that are produced by appelations in Sonoma County.
Context: CREATE TABLE WINE (Price INTEGER, Appelation VARCHAR); CREATE TABLE APPELLATIONS (Appelation VARCHAR, County VARCHAR)
Answer:
|
SELECT AVG(T2.Price) FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation WHERE T1.County = "Sonoma"
|
Question: What are the names and scores of wines that are made of white color grapes?
Context: CREATE TABLE GRAPES (Grape VARCHAR, Color VARCHAR); CREATE TABLE WINE (Name VARCHAR, Score VARCHAR, Grape VARCHAR)
Answer:
|
SELECT T2.Name, T2.Score FROM GRAPES AS T1 JOIN WINE AS T2 ON T1.Grape = T2.Grape WHERE T1.Color = "White"
|
Question: Find the maximum price of wins from the appelations in Central Coast area and produced before the year of 2005.
Context: CREATE TABLE APPELLATIONS (Appelation VARCHAR, Area VARCHAR); CREATE TABLE WINE (Price INTEGER, Appelation VARCHAR, year VARCHAR)
Answer:
|
SELECT MAX(T2.Price) FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation WHERE T1.Area = "Central Coast" AND T2.year < 2005
|
Question: Find the the grape whose white color grapes are used to produce wines with scores higher than 90.
Context: CREATE TABLE GRAPES (Grape VARCHAR, Color VARCHAR); CREATE TABLE WINE (Grape VARCHAR, score VARCHAR)
Answer:
|
SELECT DISTINCT T1.Grape FROM GRAPES AS T1 JOIN WINE AS T2 ON T1.Grape = T2.Grape WHERE T1.Color = "White" AND T2.score > 90
|
Question: What are the wines that have prices higher than 50 and made of Red color grapes?
Context: CREATE TABLE WINE (Name VARCHAR, Grape VARCHAR, price VARCHAR); CREATE TABLE Grapes (Grape VARCHAR, Color VARCHAR)
Answer:
|
SELECT T2.Name FROM Grapes AS T1 JOIN WINE AS T2 ON T1.Grape = T2.Grape WHERE T1.Color = "Red" AND T2.price > 50
|
Question: What are the wines that have prices lower than 50 and have appelations in Monterey county?
Context: CREATE TABLE APPELLATIONS (Appelation VARCHAR, County VARCHAR); CREATE TABLE WINE (Name VARCHAR, Appelation VARCHAR, price VARCHAR)
Answer:
|
SELECT T2.Name FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation WHERE T1.County = "Monterey" AND T2.price < 50
|
Question: What are the numbers of wines for different grapes?
Context: CREATE TABLE WINE (Grape VARCHAR)
Answer:
|
SELECT COUNT(*), Grape FROM WINE GROUP BY Grape
|
Question: What are the average prices of wines for different years?
Context: CREATE TABLE WINE (YEAR VARCHAR, Price INTEGER)
Answer:
|
SELECT AVG(Price), YEAR FROM WINE GROUP BY YEAR
|
Question: Find the distinct names of all wines that have prices higher than some wines from John Anthony winery.
Context: CREATE TABLE wine (Name VARCHAR, Price INTEGER, Winery VARCHAR); CREATE TABLE WINE (Name VARCHAR, Price INTEGER, Winery VARCHAR)
Answer:
|
SELECT DISTINCT Name FROM WINE WHERE Price > (SELECT MIN(Price) FROM wine WHERE Winery = "John Anthony")
|
Question: List the names of all distinct wines in alphabetical order.
Context: CREATE TABLE WINE (Name VARCHAR)
Answer:
|
SELECT DISTINCT Name FROM WINE ORDER BY Name
|
Question: List the names of all distinct wines ordered by price.
Context: CREATE TABLE WINE (Name VARCHAR, price VARCHAR)
Answer:
|
SELECT DISTINCT Name FROM WINE ORDER BY price
|
Question: What is the area of the appelation that produces the highest number of wines before the year of 2010?
Context: CREATE TABLE WINE (Appelation VARCHAR, year VARCHAR); CREATE TABLE APPELLATIONS (Area VARCHAR, Appelation VARCHAR)
Answer:
|
SELECT T1.Area FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation GROUP BY T2.Appelation HAVING T2.year < 2010 ORDER BY COUNT(*) DESC LIMIT 1
|
Question: What is the color of the grape whose wine products has the highest average price?
Context: CREATE TABLE GRAPES (Color VARCHAR, Grape VARCHAR); CREATE TABLE WINE (Grape VARCHAR)
Answer:
|
SELECT T1.Color FROM GRAPES AS T1 JOIN WINE AS T2 ON T1.Grape = T2.Grape GROUP BY T2.Grape ORDER BY AVG(Price) DESC LIMIT 1
|
Question: Find the distinct names of wines produced before the year of 2000 or after the year of 2010.
Context: CREATE TABLE WINE (Name VARCHAR, YEAR VARCHAR)
Answer:
|
SELECT DISTINCT Name FROM WINE WHERE YEAR < 2000 OR YEAR > 2010
|
Question: Find the distinct winery of wines having price between 50 and 100.
Context: CREATE TABLE WINE (Winery VARCHAR, Price INTEGER)
Answer:
|
SELECT DISTINCT Winery FROM WINE WHERE Price BETWEEN 50 AND 100
|
Question: What are the average prices and cases of wines produced in the year of 2009 and made of Zinfandel grape?
Context: CREATE TABLE WINE (Price INTEGER, Cases INTEGER, YEAR VARCHAR, Grape VARCHAR)
Answer:
|
SELECT AVG(Price), AVG(Cases) FROM WINE WHERE YEAR = 2009 AND Grape = "Zinfandel"
|
Question: What are the maximum price and score of wines produced by St. Helena appelation?
Context: CREATE TABLE WINE (Price INTEGER, Score INTEGER, Appelation VARCHAR)
Answer:
|
SELECT MAX(Price), MAX(Score) FROM WINE WHERE Appelation = "St. Helena"
|
Question: What are the maximum price and score of wines in each year?
Context: CREATE TABLE WINE (YEAR VARCHAR, Price INTEGER, Score INTEGER)
Answer:
|
SELECT MAX(Price), MAX(Score), YEAR FROM WINE GROUP BY YEAR
|
Question: What are the average price and score of wines grouped by appelation?
Context: CREATE TABLE WINE (Appelation VARCHAR, Price INTEGER, Score INTEGER)
Answer:
|
SELECT AVG(Price), AVG(Score), Appelation FROM WINE GROUP BY Appelation
|
Question: Find the wineries that have at least four wines.
Context: CREATE TABLE WINE (Winery VARCHAR)
Answer:
|
SELECT Winery FROM WINE GROUP BY Winery HAVING COUNT(*) >= 4
|
Question: Find the country of all appelations who have at most three wines.
Context: CREATE TABLE APPELLATIONS (County VARCHAR, Appelation VARCHAR); CREATE TABLE WINE (Appelation VARCHAR)
Answer:
|
SELECT T1.County FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation GROUP BY T2.Appelation HAVING COUNT(*) <= 3
|
Question: What are the names of wines whose production year are before the year of all wines by Brander winery?
Context: CREATE TABLE WINE (Name VARCHAR, YEAR INTEGER, Winery VARCHAR)
Answer:
|
SELECT Name FROM WINE WHERE YEAR < (SELECT MIN(YEAR) FROM WINE WHERE Winery = "Brander")
|
Question: What are the names of wines that are more expensive then all wines made in the year 2006?
Context: CREATE TABLE WINE (Name VARCHAR, Price INTEGER, YEAR VARCHAR)
Answer:
|
SELECT Name FROM WINE WHERE Price > (SELECT MAX(Price) FROM WINE WHERE YEAR = 2006)
|
Question: Find the top 3 wineries with the greatest number of wines made of white color grapes.
Context: CREATE TABLE GRAPES (GRAPE VARCHAR, Color VARCHAR); CREATE TABLE WINE (Winery VARCHAR, GRAPE VARCHAR)
Answer:
|
SELECT T2.Winery FROM GRAPES AS T1 JOIN WINE AS T2 ON T1.GRAPE = T2.GRAPE WHERE T1.Color = "White" GROUP BY T2.Winery ORDER BY COUNT(*) DESC LIMIT 3
|
Question: List the grape, winery and year of the wines whose price is bigger than 100 ordered by year.
Context: CREATE TABLE WINE (Grape VARCHAR, Winery VARCHAR, YEAR VARCHAR, Price INTEGER)
Answer:
|
SELECT Grape, Winery, YEAR FROM WINE WHERE Price > 100 ORDER BY YEAR
|
Question: List the grape, appelation and name of wines whose score is higher than 93 ordered by Name.
Context: CREATE TABLE WINE (Grape VARCHAR, Appelation VARCHAR, Name VARCHAR, Score INTEGER)
Answer:
|
SELECT Grape, Appelation, Name FROM WINE WHERE Score > 93 ORDER BY Name
|
Question: Find the appelations that produce wines after the year of 2008 but not in Central Coast area.
Context: CREATE TABLE WINE (Appelation VARCHAR, YEAR INTEGER, Area VARCHAR); CREATE TABLE APPELLATIONS (Appelation VARCHAR, YEAR INTEGER, Area VARCHAR)
Answer:
|
SELECT Appelation FROM WINE WHERE YEAR > 2008 EXCEPT SELECT Appelation FROM APPELLATIONS WHERE Area = "Central Coast"
|
Question: Find the average price of wines that are not produced from Sonoma county.
Context: CREATE TABLE wine (price INTEGER, Appelation VARCHAR); CREATE TABLE APPELLATIONS (Appelation VARCHAR, County VARCHAR); CREATE TABLE WINE (Appelation VARCHAR)
Answer:
|
SELECT AVG(price) FROM wine WHERE NOT Appelation IN (SELECT T1.Appelation FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation WHERE T1.County = 'Sonoma')
|
Question: Find the county where produces the most number of wines with score higher than 90.
Context: CREATE TABLE WINE (Appelation VARCHAR, Score INTEGER); CREATE TABLE APPELLATIONS (County VARCHAR, Appelation VARCHAR)
Answer:
|
SELECT T1.County FROM APPELLATIONS AS T1 JOIN WINE AS T2 ON T1.Appelation = T2.Appelation WHERE T2.Score > 90 GROUP BY T1.County ORDER BY COUNT(*) DESC LIMIT 1
|
Question: How many train stations are there?
Context: CREATE TABLE station (Id VARCHAR)
Answer:
|
SELECT COUNT(*) FROM station
|
Question: Show the name, location, and number of platforms for all stations.
Context: CREATE TABLE station (name VARCHAR, LOCATION VARCHAR, number_of_platforms VARCHAR)
Answer:
|
SELECT name, LOCATION, number_of_platforms FROM station
|
Question: What are all locations of train stations?
Context: CREATE TABLE station (LOCATION VARCHAR)
Answer:
|
SELECT DISTINCT LOCATION FROM station
|
Question: Show the names and total passengers for all train stations not in London.
Context: CREATE TABLE station (name VARCHAR, total_passengers VARCHAR, LOCATION VARCHAR)
Answer:
|
SELECT name, total_passengers FROM station WHERE LOCATION <> 'London'
|
Question: Show the names and main services for train stations that have the top three total number of passengers.
Context: CREATE TABLE station (name VARCHAR, main_services VARCHAR, total_passengers VARCHAR)
Answer:
|
SELECT name, main_services FROM station ORDER BY total_passengers DESC LIMIT 3
|
Question: What is the average and maximum number of total passengers for train stations in London or Glasgow?
Context: CREATE TABLE station (total_passengers INTEGER, LOCATION VARCHAR)
Answer:
|
SELECT AVG(total_passengers), MAX(total_passengers) FROM station WHERE LOCATION = 'London' OR LOCATION = 'Glasgow'
|
Question: Show all locations and the total number of platforms and passengers for all train stations in each location.
Context: CREATE TABLE station (LOCATION VARCHAR, number_of_platforms INTEGER, total_passengers INTEGER)
Answer:
|
SELECT LOCATION, SUM(number_of_platforms), SUM(total_passengers) FROM station GROUP BY LOCATION
|
Question: Show all locations that have train stations with at least 15 platforms and train stations with more than 25 total passengers.
Context: CREATE TABLE station (LOCATION VARCHAR, number_of_platforms VARCHAR, total_passengers VARCHAR)
Answer:
|
SELECT DISTINCT LOCATION FROM station WHERE number_of_platforms >= 15 AND total_passengers > 25
|
Question: Show all locations which don't have a train station with at least 15 platforms.
Context: CREATE TABLE station (LOCATION VARCHAR, number_of_platforms VARCHAR)
Answer:
|
SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms >= 15
|
Question: Show the location with most number of train stations.
Context: CREATE TABLE station (LOCATION VARCHAR)
Answer:
|
SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1
|
Question: Show the name, time, and service for all trains.
Context: CREATE TABLE train (name VARCHAR, TIME VARCHAR, service VARCHAR)
Answer:
|
SELECT name, TIME, service FROM train
|
Question: Show the number of trains
Context: CREATE TABLE train (Id VARCHAR)
Answer:
|
SELECT COUNT(*) FROM train
|
Question: Show the name and service for all trains in order by time.
Context: CREATE TABLE train (name VARCHAR, service VARCHAR, TIME VARCHAR)
Answer:
|
SELECT name, service FROM train ORDER BY TIME
|
Question: Show the station name and number of trains in each station.
Context: CREATE TABLE station (name VARCHAR, station_id VARCHAR); CREATE TABLE train_station (station_id VARCHAR)
Answer:
|
SELECT T2.name, COUNT(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id
|
Question: show the train name and station name for each train.
Context: CREATE TABLE station (name VARCHAR, station_id VARCHAR); CREATE TABLE train (name VARCHAR, train_id VARCHAR); CREATE TABLE train_station (station_id VARCHAR, train_id VARCHAR)
Answer:
|
SELECT T2.name, T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id
|
Question: Show all train names and times in stations in London in descending order by train time.
Context: CREATE TABLE train_station (station_id VARCHAR, train_id VARCHAR); CREATE TABLE station (station_id VARCHAR, location VARCHAR); CREATE TABLE train (name VARCHAR, time VARCHAR, train_id VARCHAR)
Answer:
|
SELECT T3.name, T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T2.location = 'London' ORDER BY T3.time DESC
|
Question: Show the station name with greatest number of trains.
Context: CREATE TABLE station (name VARCHAR, station_id VARCHAR); CREATE TABLE train_station (station_id VARCHAR)
Answer:
|
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id ORDER BY COUNT(*) DESC LIMIT 1
|
Question: Show the station name with at least two trains.
Context: CREATE TABLE station (name VARCHAR, station_id VARCHAR); CREATE TABLE train_station (station_id VARCHAR)
Answer:
|
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id HAVING COUNT(*) >= 2
|
Question: Show all locations with only 1 station.
Context: CREATE TABLE station (LOCATION VARCHAR)
Answer:
|
SELECT LOCATION FROM station GROUP BY LOCATION HAVING COUNT(*) = 1
|
Question: Show station names without any trains.
Context: CREATE TABLE station (name VARCHAR, station_id VARCHAR); CREATE TABLE train_station (name VARCHAR, station_id VARCHAR)
Answer:
|
SELECT name FROM station WHERE NOT station_id IN (SELECT station_id FROM train_station)
|
Question: What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
Context: CREATE TABLE station (name VARCHAR, station_id VARCHAR); CREATE TABLE train (train_id VARCHAR, Name VARCHAR); CREATE TABLE train_station (station_id VARCHAR, train_id VARCHAR)
Answer:
|
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Guruvayur Express"
|
Question: Find the names of the trains that do not pass any station located in London.
Context: CREATE TABLE station (station_id VARCHAR); CREATE TABLE train_station (station_id VARCHAR); CREATE TABLE train_station (train_id VARCHAR, station_id VARCHAR); CREATE TABLE train (name VARCHAR, train_id VARCHAR)
Answer:
|
SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id = T2.train_id WHERE NOT T1.station_id IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id = T4.station_id WHERE t4.location = "London")
|
Question: List the names and locations of all stations ordered by their yearly entry exit and interchange amounts.
Context: CREATE TABLE station (name VARCHAR, LOCATION VARCHAR, Annual_entry_exit VARCHAR, Annual_interchanges VARCHAR)
Answer:
|
SELECT name, LOCATION FROM station ORDER BY Annual_entry_exit, Annual_interchanges
|
Question: List all vehicle id
Context: CREATE TABLE Vehicles (vehicle_id VARCHAR)
Answer:
|
SELECT vehicle_id FROM Vehicles
|
Question: How many vehicle in total?
Context: CREATE TABLE Vehicles (Id VARCHAR)
Answer:
|
SELECT COUNT(*) FROM Vehicles
|
Question: Show the detail of vehicle with id 1.
Context: CREATE TABLE Vehicles (vehicle_details VARCHAR, vehicle_id VARCHAR)
Answer:
|
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1
|
Question: List the first name middle name and last name of all staff.
Context: CREATE TABLE Staff (first_name VARCHAR, middle_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT first_name, middle_name, last_name FROM Staff
|
Question: What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
Context: CREATE TABLE Staff (date_of_birth VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"
|
Question: When did the staff member with first name as Janessa and last name as Sawayn join the company?
Context: CREATE TABLE Staff (date_joined_staff VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"
|
Question: When did the staff member with first name as Janessa and last name as Sawayn leave the company?
Context: CREATE TABLE Staff (date_left_staff VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"
|
Question: How many staff have the first name Ludie?
Context: CREATE TABLE Staff (first_name VARCHAR)
Answer:
|
SELECT COUNT(*) FROM Staff WHERE first_name = "Ludie"
|
Question: What is the nickname of staff with first name as Janessa and last name as Sawayn?
Context: CREATE TABLE Staff (nickname VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"
|
Question: How many staff in total?
Context: CREATE TABLE Staff (Id VARCHAR)
Answer:
|
SELECT COUNT(*) FROM Staff
|
Question: Which city does staff with first name as Janessa and last name as Sawayn live?
Context: CREATE TABLE Staff (staff_address_id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE Addresses (city VARCHAR, address_id VARCHAR)
Answer:
|
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"
|
Question: Which country and state does staff with first name as Janessa and last name as Sawayn lived?
Context: CREATE TABLE Addresses (country VARCHAR, state_province_county VARCHAR, address_id VARCHAR); CREATE TABLE Staff (staff_address_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT T1.country, T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"
|
Question: How long is the total lesson time took by customer with first name as Rylan and last name as Goodwin?
Context: CREATE TABLE Lessons (lesson_time INTEGER, customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT SUM(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin"
|
Question: What is the zip code of staff with first name as Janessa and last name as Sawayn lived?
Context: CREATE TABLE Addresses (zip_postcode VARCHAR, address_id VARCHAR); CREATE TABLE Staff (staff_address_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"
|
Question: How many staff live in state Georgia?
Context: CREATE TABLE Addresses (state_province_county VARCHAR)
Answer:
|
SELECT COUNT(*) FROM Addresses WHERE state_province_county = "Georgia"
|
Question: Find out the first name and last name of staff lived in city Damianfort.
Context: CREATE TABLE Staff (first_name VARCHAR, last_name VARCHAR, staff_address_id VARCHAR); CREATE TABLE Addresses (address_id VARCHAR, city VARCHAR)
Answer:
|
SELECT T2.first_name, T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort"
|
Question: Which city lives most of staffs? List the city name and number of staffs.
Context: CREATE TABLE Staff (staff_address_id VARCHAR); CREATE TABLE Addresses (city VARCHAR, address_id VARCHAR)
Answer:
|
SELECT T1.city, COUNT(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY COUNT(*) DESC LIMIT 1
|
Question: List the states which have between 2 to 4 staffs living there.
Context: CREATE TABLE Addresses (state_province_county VARCHAR, address_id VARCHAR); CREATE TABLE Staff (staff_address_id VARCHAR)
Answer:
|
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING COUNT(*) BETWEEN 2 AND 4
|
Question: List the first name and last name of all customers.
Context: CREATE TABLE Customers (first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT first_name, last_name FROM Customers
|
Question: List email address and birthday of customer whose first name as Carole.
Context: CREATE TABLE Customers (email_address VARCHAR, date_of_birth VARCHAR, first_name VARCHAR)
Answer:
|
SELECT email_address, date_of_birth FROM Customers WHERE first_name = "Carole"
|
Question: List phone number and email address of customer with more than 2000 outstanding balance.
Context: CREATE TABLE Customers (phone_number VARCHAR, email_address VARCHAR, amount_outstanding INTEGER)
Answer:
|
SELECT phone_number, email_address FROM Customers WHERE amount_outstanding > 2000
|
Question: What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina?
Context: CREATE TABLE Customers (customer_status_code VARCHAR, cell_mobile_phone_number VARCHAR, email_address VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT customer_status_code, cell_mobile_phone_number, email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
|
Question: When are the birthdays of customer who are classified as 'Good Customer' status?
Context: CREATE TABLE Customers (date_of_birth VARCHAR, customer_status_code VARCHAR)
Answer:
|
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
|
Question: When did customer with first name as Carole and last name as Bernhard became a customer?
Context: CREATE TABLE Customers (date_became_customer VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard"
|
Question: List all customer status codes and the number of customers having each status code.
Context: CREATE TABLE Customers (customer_status_code VARCHAR)
Answer:
|
SELECT customer_status_code, COUNT(*) FROM Customers GROUP BY customer_status_code
|
Question: Which customer status code has least number of customers?
Context: CREATE TABLE Customers (customer_status_code VARCHAR)
Answer:
|
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY COUNT(*) LIMIT 1
|
Question: How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed?
Context: CREATE TABLE Lessons (customer_id VARCHAR, lesson_status_code VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
|
SELECT COUNT(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed"
|
Question: What is maximum, minimum and average amount of outstanding of customer?
Context: CREATE TABLE Customers (amount_outstanding INTEGER)
Answer:
|
SELECT MAX(amount_outstanding), MIN(amount_outstanding), AVG(amount_outstanding) FROM Customers
|
Question: List the first name and last name of customers have the amount of outstanding between 1000 and 3000.
Context: CREATE TABLE Customers (first_name VARCHAR, last_name VARCHAR, amount_outstanding INTEGER)
Answer:
|
SELECT first_name, last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000
|
Question: List first name and last name of customers lived in city Lockmanfurt.
Context: CREATE TABLE Customers (first_name VARCHAR, last_name VARCHAR, customer_address_id VARCHAR); CREATE TABLE Addresses (address_id VARCHAR, city VARCHAR)
Answer:
|
SELECT T1.first_name, T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt"
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Question: Which country does customer with first name as Carole and last name as Bernhard lived in?
Context: CREATE TABLE Addresses (country VARCHAR, address_id VARCHAR); CREATE TABLE Customers (customer_address_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
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SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
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Question: What is zip code of customer with first name as Carole and last name as Bernhard?
Context: CREATE TABLE Addresses (zip_postcode VARCHAR, address_id VARCHAR); CREATE TABLE Customers (customer_address_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
Answer:
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SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
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Question: Which city does has most number of customers?
Context: CREATE TABLE Customers (customer_address_id VARCHAR); CREATE TABLE Addresses (city VARCHAR, address_id VARCHAR)
Answer:
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SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY COUNT(*) DESC LIMIT 1
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Question: How much in total does customer with first name as Carole and last name as Bernhard paid?
Context: CREATE TABLE Customers (customer_id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE Customer_Payments (amount_payment INTEGER, customer_id VARCHAR)
Answer:
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SELECT SUM(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
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Question: List the number of customers that did not have any payment history.
Context: CREATE TABLE Customers (customer_id VARCHAR); CREATE TABLE Customer_Payments (customer_id VARCHAR)
Answer:
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SELECT COUNT(*) FROM Customers WHERE NOT customer_id IN (SELECT customer_id FROM Customer_Payments)
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Question: List first name and last name of customers that have more than 2 payments.
Context: CREATE TABLE Customers (first_name VARCHAR, last_name VARCHAR, customer_id VARCHAR); CREATE TABLE Customer_Payments (customer_id VARCHAR)
Answer:
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SELECT T2.first_name, T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) > 2
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Question: List all payment methods and number of payments using each payment methods.
Context: CREATE TABLE Customer_Payments (payment_method_code VARCHAR)
Answer:
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SELECT payment_method_code, COUNT(*) FROM Customer_Payments GROUP BY payment_method_code
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