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movielens
|
Which genre contains the greatest number of non-English films?
|
isEnglish = 'F' means non-English
|
SELECT T2.genre FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.isEnglish = 'F' GROUP BY T2.genre ORDER BY COUNT(T1.movieid) DESC LIMIT 1
| 2,300 | |
movielens
|
List the cast and the director of the movie with the id 1949144.
|
SELECT T1.actorid, T2.directorid FROM movies2actors AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.movieid = 1949144
| 2,301 | ||
movielens
|
Among the actors who acted in UK movies, what percentage of actors received a rating of at least 3?
|
UK is a country
|
SELECT CAST(SUM(IIF(T3.a_quality >= 3, 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid INNER JOIN actors AS T3 ON T2.actorid = T3.actorid WHERE T1.country = 'UK'
| 2,302 | |
movielens
|
What is the proportion of action movies directors who are called 'box office success paradox'?
|
'box office success paradox' means average revenue exceeds their quality; The proportion can be computed by [(avg_revenue > d_quality) / ()] * 100%
|
SELECT CAST(SUM(IIF(T2.avg_revenue > T2.d_quality, 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM movies2directors AS T1 INNER JOIN directors AS T2 ON T1.directorid = T2.directorid WHERE T1.genre = 'Action'
| 2,303 | |
movielens
|
Please list the actor IDs whose movies have the newest published date.
|
Year contains relative value, higher year value refers to newer date; Year = 4 refers to newest date
|
SELECT T1.actorid FROM movies2actors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.year = 4
| 2,304 | |
movielens
|
Who are cast members in an English movie which has a running time equal to 2? Please list their IDs.
|
isEnglish = 'T' means English movie
|
SELECT T2.actorid FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.runningtime = 2 AND T1.isEnglish = 'T'
| 2,305 | |
movielens
|
Which actor has acted in at least 2 French films? Please list their IDs.
|
France is a country
|
SELECT T2.actorid FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'France' GROUP BY T2.actorid HAVING COUNT(T1.movieid) > 2
| 2,306 | |
movielens
|
How many American movies have cast number more than 1?
|
USA is a country
|
SELECT COUNT(T2.actorid) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'USA' AND T2.cast_num > 1
| 2,307 | |
movielens
|
Please list movie IDs which has the oldest publication date and the cast numbers are zero.
|
Year contains relative value, higher year value refers to newer date; Year = 1 refer to oldest date
|
SELECT DISTINCT T1.movieid FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.year = 1 AND T2.cast_num = 0
| 2,308 | |
movielens
|
How many actors have acted in both US or UK films?
|
US and UK are 2 countries
|
SELECT COUNT(T1.actorid) FROM movies2actors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.country = 'USA' OR T2.country = 'UK'
| 2,309 | |
movielens
|
How many directors with average revenue of 4 have made either action or adventure films?
|
SELECT COUNT(T1.directorid) FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.avg_revenue = 4 AND (T2.genre = 'Adventure' OR T2.genre = 'Action')
| 2,310 | ||
movielens
|
Please list director IDs who have the quality of at least 3 and have made at least 2 different genres of movies.
|
SELECT T1.directorid FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality >= 3 GROUP BY T1.directorid HAVING COUNT(T2.movieid) >= 2
| 2,311 | ||
movielens
|
How many American comedies are there?
|
USA is a country
|
SELECT COUNT(T1.movieid) FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'USA' AND T2.genre = 'comedy'
| 2,312 | |
movielens
|
How many latest released dramas and action movies?
|
SELECT COUNT(T1.movieid) FROM movies2directors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.year = 4 AND T1.genre IN ('Action', 'drama')
| 2,313 | ||
movielens
|
What horror movies have a running time of at least 2? Please list movie IDs.
|
Higher value of running time means running time is longer
|
SELECT T1.movieid FROM movies2directors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.runningtime >= 2 AND T1.genre = 'Horror'
| 2,314 | |
movielens
|
Please calculate negative critical reception of American movies
|
'negative critical reception' refers to percentage of movies with a rating of 1, which = [count(rating = 1) / count(all movies)] * 100%
|
SELECT CAST(SUM(IIF(T1.rating = 1, 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM u2base AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.country = 'USA'
| 2,315 | |
movielens
|
What is the disparate number of the comedy films that got the 1 rating?
|
SELECT COUNT(DISTINCT T1.movieid) FROM movies2directors AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid WHERE T2.rating = 1 AND T1.genre = 'comedy'
| 2,316 | ||
movielens
|
What's different average revenue status for director who directed the movie that got the most 1 ratings?
|
SELECT DISTINCT T1.avg_revenue FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 5
| 2,317 | ||
movielens
|
How many French movies got the highest ranking?
|
France is a country
|
SELECT COUNT(movieid) FROM movies WHERE country = 'France' AND movieid IN ( SELECT movieid FROM u2base WHERE rating = ( SELECT MAX(rating) FROM u2base ) )
| 2,318 | |
movielens
|
List the movie that has been rated most by 25 years old users.
|
SELECT T2.movieid FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid WHERE T1.age = 25 GROUP BY T2.movieid ORDER BY COUNT(T1.userid) DESC LIMIT 1
| 2,319 | ||
movielens
|
How many separate 35 year-old uesers have rated the movie from UK?
|
UK is a country
|
SELECT COUNT(DISTINCT T2.userid) FROM movies AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid INNER JOIN users AS T3 ON T2.userid = T3.userid WHERE T1.country = 'UK' AND T3.age = 35
| 2,320 | |
movielens
|
List the user ids and ages who gave the rate 2 to the movie No. 2409051.
|
SELECT T1.userid, T1.age FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid WHERE T2.movieid = '2409051' AND T2.rating = 2
| 2,321 | ||
movielens
|
Please give the ids of the oldest films that got the most ratings.
|
Films and movies share the same meaning; oldest film refers to the movie with year = 1
|
SELECT DISTINCT T1.movieid FROM u2base AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T1.rating = 5 AND T2.year = 1
| 2,322 | |
movielens
|
Which different movies from France got the least ratings?
|
France is a country
|
SELECT DISTINCT T1.movieid FROM u2base AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.country = 'France' AND T1.rating = 1
| 2,323 | |
movielens
|
How many female actors have been played a role in any of French or USA movies?
|
French and USA are two countries; Female actors mean that a_gender = 'F'
|
SELECT COUNT(T2.actorid) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.country IN ('France', 'USA')
| 2,324 | |
movielens
|
How many different actors have played a role in the highest rating movie?
|
highest rating of a movie is 5
|
SELECT COUNT(DISTINCT T2.actorid) FROM u2base AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.rating = 5
| 2,325 | |
movielens
|
Which Crime film got the lowest average rating?
|
SELECT T2.movieid FROM u2base AS T2 INNER JOIN movies2directors AS T3 ON T2.movieid = T3.movieid WHERE T3.genre = 'Crime' GROUP BY T2.movieid ORDER BY AVG(T2.rating) LIMIT 1
| 2,326 | ||
movielens
|
What's the ratio of gender in actors to actress in all the UK movies?
|
UK is a country; Male actors mean that a_gender = 'M'; Female actors mean that a_gender = 'F'; ratio; ratio of gender in actors = count(a_gender = 'M') / a_gender = 'F'
|
SELECT CAST(SUM(IIF(T3.a_gender = 'M', 1, 0)) AS REAL) / SUM(IIF(T3.a_gender = 'F', 1, 0)) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid INNER JOIN actors AS T3 ON T2.actorid = T3.actorid WHERE T1.country = 'UK'
| 2,327 | |
movielens
|
How many 35-year-old female users gave the movie 1711133 a rating of 3?
|
Female users mean that u_gender = 'F'
|
SELECT COUNT(T1.userid) FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid WHERE T2.rating = 3 AND T2.movieid = '1711133' AND T1.age = 35 AND T1.u_gender = 'F'
| 2,328 | |
movielens
|
How many users have rated 1 each for the UK's second newest movies with a running time of 2?
|
second newest movies refers to year = 2 since year in this database is a relative value, less is the newer
|
SELECT COUNT(T2.userid) FROM movies AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'UK' AND T1.runningtime = 2 AND T2.rating = 1 AND T1.year = 2
| 2,329 | |
movielens
|
How many unique directors with an average earnings of 2 and a quality of 3 have not made comedy films? List them.
|
SELECT DISTINCT T1.directorid FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 3 AND T1.avg_revenue = 2 AND T2.genre != 'Comedy'
| 2,330 | ||
movielens
|
Calculate the percentage of female actors and quality 2 who have appeared twice at the casting of the film 1672580.
|
Female actors mean that a_gender = 'F'; percentage can be computed by [cast_num = 2 AND a_quality = 2 in female) / (all female actors)] * 100%
|
SELECT CAST(SUM(IIF(T2.cast_num = 2 AND T1.a_quality = 2, 1, 0)) AS REAL) * 100 / COUNT(T1.actorid) FROM actors AS T1 INNER JOIN movies2actors AS T2 ON T1.actorid = T2.actorid WHERE T2.movieid = 1672580 AND T1.a_gender = 'F'
| 2,331 | |
movielens
|
How many of the worst actors are men and how many of the worst actors are women? Indicate your answer in ratio form.
|
The worst actors means a_quality = 0; Men and male share the same meaning; men actors refers to a_gender = 'M'
|
SELECT CAST(SUM(IIF(a_gender = 'M', 1, 0)) AS REAL) / SUM(IIF(a_gender = 'F', 1, 0)) FROM actors WHERE a_quality = 0
| 2,332 | |
movielens
|
Which actor has appeared in the most films?
|
SELECT actorid FROM movies2actors GROUP BY actorid ORDER BY COUNT(movieid) DESC LIMIT 1
| 2,333 | ||
movielens
|
What is the most popular genre of film directed by directors?
|
Most popular genre indicates that the genre has the most number of movies
|
SELECT genre FROM movies2directors GROUP BY genre ORDER BY COUNT(movieid) DESC LIMIT 1
| 2,334 | |
movielens
|
What are the most common film genres made by the worst directors?
|
d_quality = 5 refers to the best directors, d_quality = 0 refers to the worst directors
|
SELECT T2.genre FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 0 GROUP BY T2.genre ORDER BY COUNT(T2.movieid) DESC LIMIT 1
| 2,335 | |
movielens
|
What non-English American film/s has received the lowest user ratings? Mention the movie's I.D.
|
USA is a country; non-English means isEnglish = 'F'
|
SELECT T2.movieid FROM movies AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid WHERE T1.isEnglish = 'F' AND T1.country = 'USA' ORDER BY T2.rating LIMIT 1
| 2,336 | |
movielens
|
What is the total average movie directed by the directors who's quality and revenue is 4?
|
SELECT CAST(SUM(CASE WHEN T1.d_quality = 4 AND T1.avg_revenue = 4 THEN 1 ELSE 0 END) AS REAL) / COUNT(T2.movieid) FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid
| 2,337 | ||
movielens
|
Which movies have received the greatest ratings from female users whose occupations fall within the category of 3?
|
Female users mean that u_gender = 'F'
|
SELECT T2.movieid FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid INNER JOIN movies AS T3 ON T2.movieid = T3.movieid WHERE T1.u_gender = 'F' AND T1.occupation = 3 AND T2.rating = 5
| 2,338 | |
movielens
|
How many female actresses appeared in the movie 2312852, what country was it in, and what was it's running time?
|
female actresses mean that a_gender = 'F'
|
SELECT SUM(IIF(T1.a_gender = 'F', 1, 0)) , T3.country, T3.runningtime FROM actors AS T1 INNER JOIN movies2actors AS T2 ON T1.actorid = T2.actorid INNER JOIN movies AS T3 ON T2.movieid = T3.movieid WHERE T2.movieid = 2312852 GROUP BY T3.country, T3.runningtime
| 2,339 | |
movielens
|
How many horror movies were made by the worst directors?
|
d_quality = 5 refers to direct the best, d_quality = 0 refers to direct the worst
|
SELECT COUNT(T1.movieid) FROM movies2directors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid INNER JOIN directors AS T3 ON T1.directorid = T3.directorid WHERE T1.genre = 'horror' AND T3.d_quality = 0
| 2,340 | |
movielens
|
What are the genres of all the English-language foreign films having a runtime of two hours or less? List each one.
|
isEnglish = 'T' means films in English; Film and movie share the same meaning
|
SELECT T2.genre FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.runningtime <= 2 AND T1.isEnglish = 'T' AND T1.country = 'other'
| 2,341 | |
movielens
|
Among the English comedy movies produced in the UK, how many movies with a running time of 3 was rated the highest by users between the age 45-50? Indicate the movie names.
|
UK is a country
|
SELECT DISTINCT T1.movieid FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid INNER JOIN u2base AS T3 ON T1.movieid = T3.movieid INNER JOIN users AS T4 ON T3.userid = T4.userid WHERE T1.country = 'UK' AND T2.genre = 'Comedy' AND T1.runningtime = 3 AND T3.rating = 5 AND T4.age BETWEEN 45 AND 50 AND T1.isEnglish = 'T'
| 2,342 | |
movielens
|
What is the percentage difference of English and non-English-language crime movies in other countries in year 3?
|
non-English-language refers to isEnglish = 'F'; The percentage difference can be computed by [count(isEnglish = 'T' in movies) - count(isEnglish = 'F' in movies) / (all movies)] * 100%
|
SELECT CAST(SUM(IIF(T1.isEnglish = 'T', 1, 0)) - SUM(IIF(T1.isEnglish = 'F', 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'other' AND T1.year = 3
| 2,343 | |
movielens
|
What is the total amount male and female actors who were casted in movie ID 1684910 and what is the proportion between the highest quality actors against the worst quality of actors? Indicate your answer in percentage. List the the director as well as the genre.
|
Female actors mean that a_gender = 'F'; Male actors mean that a_gender = 'M'; a_quality = 5 refers to act the best, a_quality = 0 refers to act the worst
|
SELECT SUM(IIF(a_gender = 'M', 1, 0)) , SUM(IIF(a_gender = 'F', 1, 0)) , CAST(SUM(IIF(a_quality = 5, 1, 0)) AS REAL) * 100 / COUNT(*) , CAST(SUM(IIF(a_quality = 0, 1, 0)) AS REAL) * 100 / COUNT(*), ( SELECT directorid FROM movies2directors WHERE movieid = 1684910 ) , ( SELECT genre FROM movies2directors WHERE movieid = 1684910 ) FROM actors WHERE actorid IN ( SELECT actorid FROM movies2actors WHERE movieid = 1684910 )
| 2,344 | |
superstore
|
Please list the names of all the products ordered in order CA-2011-112326 in superstores in the center.
|
names of all the products refers to "Product Name"; order CA-2011-112326 refers to "Order ID" = 'CA-2011-112326'; in the center refers to Region = 'Central';
|
SELECT DISTINCT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Order ID` = 'CA-2011-112326'
| 2,345 | |
superstore
|
Among all the orders made by Aimee Bixby, what was the longest shipment time?
|
made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; longest shipment time refers to MAX(SUM(SUTRACT(julianday("Ship Date"), julianday("Order Date")), 1))
|
SELECT MAX(strftime('%J', `Ship Date`) - strftime('%J', `Order Date`)) AS longestTimeDays FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby'
| 2,346 | |
superstore
|
Among all the orders made by Aimee Bixby, how many of them chose the slowest delivery speed?
|
made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; the slowest delivery speed refers to "Ship Mode" = 'Standard Class';
|
SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T2.`Ship Mode` = 'Standard Class'
| 2,347 | |
superstore
|
How many orders has Aimee Bixby made?
|
Aimee Bixby made refers to "Customer Name" = 'Aimee Bixby';
|
SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby'
| 2,348 | |
superstore
|
Please list the IDs of the orders made by Aimee Bixby with more than 3 kinds of products ordered.
|
made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; with more than 3 kinds of products ordered refers to count("Product ID") > 3;
|
SELECT DISTINCT T2.`Order ID` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby' GROUP BY T2.`Product ID` HAVING COUNT(T2.`Product ID`) > 3
| 2,349 | |
superstore
|
Among the orders made by Aimee Bixby, how many of them included at least one kind of product under the category "Furniture"?
|
made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby';
|
SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T3.Category = 'Furniture' AND T1.`Customer Name` = 'Aimee Bixby'
| 2,350 | |
superstore
|
Please list the names of all the products ordered by Aimee Bixby in 2016.
|
ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; ordered n 2016 refers to strftime('%Y', "Order Date") = '2016';
|
SELECT DISTINCT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND STRFTIME('%Y', T2.`Ship Date`) = '2016'
| 2,351 | |
superstore
|
What is the total quantity of "Telescoping Adjustable Floor Lamp" ordered from central superstores?
|
"Telescoping Adjustable Floor Lamp" is a "Product Name"; from central superstores refers to Region = 'Central';
|
SELECT SUM(T1.Quantity) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Telescoping Adjustable Floor Lamp'
| 2,352 | |
superstore
|
Please list the names of all the customers who had ordered the product "Telescoping Adjustable Floor Lamp".
|
"Telescoping Adjustable Floor Lamp" is a product name; names of all the customers refers to "Customer Name"
|
SELECT DISTINCT T1.`Customer Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T3.`Product Name` = 'Telescoping Adjustable Floor Lamp'
| 2,353 | |
superstore
|
Among the customers who have ordered the product "Telescoping Adjustable Floor Lamp", how many of them are consumers?
|
"Telescoping Adjustable Floor Lamp" is a "Product Name"; consumers refers to Segment = 'Consumer';
|
SELECT COUNT(DISTINCT T1.`Customer Name`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T3.`Product Name` = 'Telescoping Adjustable Floor Lamp' AND T1.Segment = 'Consumer'
| 2,354 | |
superstore
|
What was the quantity of Xerox 1952 ordered by Aimee Bixby on 2014/9/10?
|
Xerox 1952 is a "Product Name"; ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; on 2014/9/10 refers to "Order Date" = date('2014-09-10');
|
SELECT SUM(T2.Quantity) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952' AND T2.`Order Date` = '2014-09-10'
| 2,355 | |
superstore
|
For how many times has Aimee Bixby ordered the product Xerox 1952?
|
Xerox 1952 is a "Product Name"; Aimee Bixby ordered refers to "Customer Name" = 'Aimee Bixby';
|
SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952'
| 2,356 | |
superstore
|
What was the original price of Xerox 1952 ordered by Aimee Bixby on 2014/9/10?
|
Xerox 1952 is a "Product Name"; ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; on 2014/9/10 refers to "Order Date" = date('2014-09-10'); original price refers to DIVIDE(Sales, SUTRACT(1, discount))
|
SELECT DISTINCT T2.Sales / (1 - T2.Discount) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952' AND T2.`Order Date` = '2014-09-10'
| 2,357 | |
superstore
|
What was the total cost of Xerox 1952 ordered by Aimee Bixby on 2014/9/10?
|
Xerox 1952 is a "Product Name"; ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; on 2014/9/10 refers to "Order Date" = date('2014-09-10'); total cost refers to SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit)
|
SELECT DISTINCT (T2.Sales / (1 - T2.discount)) * T2.Quantity - Profit FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952' AND T2.`Order Date` = '2014-09-10'
| 2,358 | |
superstore
|
How many art products were ordered in 2013 in the east superstore?
|
ordered in 2013 refers to strftime('%Y', "Order Date") = '2013'; art products refers to "Sub-Category" = 'Art'
|
SELECT COUNT(DISTINCT T1.`Product ID`) FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Sub-Category` = 'Art' AND T1.Region = 'East' AND STRFTIME('%Y', T1.`Order Date`) = '2013'
| 2,359 | |
superstore
|
Who is the customer who purchased the largest total cost of products in a single order?
|
largest total cost refers to MAX(SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit))
|
SELECT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` GROUP BY T1.`Order ID`, T2.`Customer Name` ORDER BY SUM((T1.Sales / (1 - T1.Discount)) * T1.Quantity - T1.Profit) DESC LIMIT 1
| 2,360 | |
superstore
|
What is the name of the product that has the highest original price?
|
has the highest original price refers to MAX(DIVIDE(Sales, SUTRACT(1, discount))); name of the product refers to "Product Name"
|
SELECT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` ORDER BY (T1.Sales / (1 - T1.Discount)) DESC LIMIT 1
| 2,361 | |
superstore
|
What is the name of the product that was ordered recently by Darren Powers?
|
Darren Powers is the "Customer Name"; name of the product refers to "Product Name"; recently refers to MAX("Order Date")
|
SELECT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Darren Powers' ORDER BY T2.`Order Date` DESC LIMIT 1
| 2,362 | |
superstore
|
How many quantities of Advantus plastic paper clips were ordered overall?
|
Advantus plastic paper clips is the "Product Name";
|
SELECT SUM(T1.Quantity) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Advantus Plastic Paper Clips'
| 2,363 | |
superstore
|
Which order of Logitech G600 MMO Gaming Mouse has the highest total cost?
|
Logitech G600 MMO Gaming Mouse refers to "Product Name"; highest total cost refers to MAX(SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit))
|
SELECT T1.`Order ID` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Logitech G600 MMO Gaming Mouse' GROUP BY T1.`Order ID` ORDER BY SUM((T1.Sales / (1 - T1.Discount)) * T1.Quantity - T1.Profit) DESC LIMIT 1
| 2,364 | |
superstore
|
What are the names of the products that were ordered by Alejandro Grove?
|
ordered by Alejandro Grove refers to "Customer Name" = 'Alejandro Grove'; names of the products refers to "Product Name"
|
SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Alejandro Grove'
| 2,365 | |
superstore
|
How many customers in Chicago ordered at least 10 Cardinal EasyOpen D-Ring Binders in a single order?
|
at least 10 goods refers to Quantity > = 14; Cardinal EasyOpen D-Ring Binders refers to "Product Name"; customers in Chicago refers to City = 'Chicago'
|
SELECT COUNT(DISTINCT T1.`Customer ID`) FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Cardinal EasyOpen D-Ring Binders' AND T2.City = 'Chicago' AND T1.Quantity > 10
| 2,366 | |
superstore
|
What are the names of the products with a profit of no less than 1,000 in one single order?
|
profit of no less than 1,000 refers to Profit > = 1000; names of the products refers to "Product Name"
|
SELECT DISTINCT T2.`Product Name` FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.Profit > 1000
| 2,367 | |
superstore
|
Name 10 products that were shipped first class from the East region.
|
shipped first class refers to "Ship Mode" = 'First Class'; Region = 'East'
|
SELECT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Ship Mode` = 'First Class' AND T2.Region = 'East' LIMIT 10
| 2,368 | |
superstore
|
List the products ordered by Becky Martin around the Central region.
|
ordered by Becky Martin refers to "Customer Name" = 'Becky Martin'; Region = 'Central'; products refers to "Product Name"
|
SELECT DISTINCT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Becky Martin' AND T3.Region = 'Central'
| 2,369 | |
superstore
|
List 5 customers in the West region who had their item shipped 'Second Class.'
|
shipped 'Second Class.' refers to "Ship Mode" = 'Second Class'; customers refers to "Customer Name"; Region = 'West'
|
SELECT DISTINCT T2.`Customer Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'West' AND T1.`Ship Mode` = 'Second Class' LIMIT 5
| 2,370 | |
superstore
|
Add the total profit of Patrick Gardner in the Central region.
|
Patrick Gardner is the "Customer Name"; Region = 'Central'
|
SELECT SUM(T2.Profit) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Patrick Gardner' AND T1.Region = 'Central'
| 2,371 | |
superstore
|
Which item was shipped on 3/4/2013 and scheduled for same day delivery in the South region?
|
shipped on 3/4/2013 refers to "Order Date" = date('2013-03-04'); same day delivery refers to "Ship Mode" = 'Same Day'; item refers to "Product Name"
|
SELECT T2.`Product Name` FROM south_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Ship Date` = '2013-03-04' AND T2.Region = 'South' AND T1.`Order Date` = '2013-03-04'
| 2,372 | |
superstore
|
What is the total sales of 'Avery Hi-Liter EverBold Pen Style Fluorescent Highlighters, 4/Pack' in the Central region?
|
'Avery Hi-Liter EverBold Pen Style Fluorescent Highlighters, 4/Pack' is the "Product Name";
|
SELECT SUM(T1.Sales) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Avery Hi-Liter EverBold Pen Style Fluorescent Highlighters, 4/Pack' AND T2.Region = 'Central'
| 2,373 | |
superstore
|
Name the item ordered by Jonathan Doherty with the highest quantity in the East region.
|
Jonathan Doherty is the "Customer Name"; highest quantity refers to MAX(Quantity); Region = 'East'
|
SELECT T3.`Product Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Jonathan Doherty' AND T2.Region = 'East' ORDER BY T1.Quantity DESC LIMIT 1
| 2,374 | |
superstore
|
How much is the total quantity of items from the East region shipped on 3/25/2015? Name the products.
|
shipped on 3/25/2015 refers to "Ship Date" = Date('2015-03-25');
|
SELECT SUM(T1.Quantity), T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Ship Date` = '2015-03-25' AND T2.Region = 'East'
| 2,375 | |
superstore
|
Which customer ordered 'Global High-Back Leather Tilter, Burgundy' on 10/13/2013 in the East region?
|
'Global High-Back Leather Tilter, Burgundy' is the "Product Name"; on 10/13/2013 refers to "Order Date" = Date('2013-10-13'); Region = 'East'
|
SELECT DISTINCT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Global High-Back Leather Tilter, Burgundy' AND T1.`Order Date` = '2013-10-13' AND T1.Region = 'East'
| 2,376 | |
superstore
|
What category does the item ordered by Katherine Murray on 11/4/2018 in the South region belong to?
|
ordered by Katherine Murray refers to "Customer Name" = 'Katherine Murray'; on 11/4/2018 refers to "Order Date" = Date('2018-11-04');
|
SELECT DISTINCT T3.Category FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Katherine Murray' AND T1.`Order Date` = '2018-11-04' AND T2.Region = 'South'
| 2,377 | |
superstore
|
What percentage do items under the category of 'Furniture' make up the total number of items ordered that are shipped as standard in the West region?
|
shipped as standard refers to "Ship Mode" = 'Standard Class'; Region = 'West'; percentage refers to DIVIDE(SUM(Quantity where Category = 'Furniture'), SUM(Quantity)) * 1.0
|
SELECT CAST(SUM(CASE WHEN T2.Category = 'Furniture' THEN 1 ELSE 0 END) AS REAL) * 100 / SUM(T1.Quantity) FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'West' AND T1.`Ship Mode` = 'Standard Class'
| 2,378 | |
superstore
|
What is the ship date of the order by the customer named Ann Chong in the central region?
|
Ann Chong' is the "Customer Name"; Region = 'Central'
|
SELECT T2.`Ship Date` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Ann Chong' AND T1.Region = 'Central'
| 2,379 | |
superstore
|
Give the customer segment from the West region that orders the order ID CA-2011-108189.
|
Region = 'West'
|
SELECT DISTINCT T2.Segment FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'West' AND T1.`Order ID` = 'CA-2011-108189'
| 2,380 | |
superstore
|
What are the total sales of the accumulated orders of Hon Valutask Swivel Chairs in the West region?
|
'Hon Valutask Swivel Chairs' is the "Product Name"
|
SELECT SUM(T1.Sales) FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Hon Valutask Swivel Chairs' AND T1.Region = 'West'
| 2,381 | |
superstore
|
Provide the order ID of Frank Olsen of the South region.
|
Frank Olsen' is the "Customer Name"; Region = 'South'
|
SELECT T1.`Order ID` FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.Region = 'South' AND T2.`Customer Name` = 'Frank Olsen'
| 2,382 | |
superstore
|
What product was ordered in the Central region on April 26, 2018, and shipped by April 27, 2018?
|
on April 26, 2018 refers to "Order Date" = date('2018-04-26'); shipped by April 27, 2018 refers to "Ship Date" = date('2018-04-27');
|
SELECT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Order Date` = '2018-04-26' AND T1.`Ship Date` = '2018-04-27' AND T2.Region = 'Central'
| 2,383 | |
superstore
|
From which city and state does the customer that bought the product with the highest sales?
|
highest sales refers to max(Sales)
|
SELECT T5.City, T5.State FROM west_superstore AS T1 INNER JOIN east_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN central_superstore AS T3 ON T3.`Customer ID` = T2.`Customer ID` INNER JOIN south_superstore AS T4 ON T4.`Customer ID` = T3.`Customer ID` INNER JOIN people AS T5 ON T5.`Customer ID` = T4.`Customer ID` ORDER BY T2.Sales DESC LIMIT 1
| 2,384 | |
superstore
|
Who is the customer from the East region that purchased the order with the highest profit?
|
highest profit refers to MAX(profit); Region = 'East'
|
SELECT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'East' ORDER BY T1.Profit DESC LIMIT 1
| 2,385 | |
superstore
|
Among the customers from Chicago, Illinois, what is the highest quantity of products bought in a single order?
|
from Chicago refers to City = 'Chicago'; Illinois refers to State = 'Illinois'; highest quantity refers to max(Quantity)
|
SELECT T1.Quantity FROM west_superstore AS T1 INNER JOIN east_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN central_superstore AS T3 ON T3.`Customer ID` = T2.`Customer ID` INNER JOIN south_superstore AS T4 ON T4.`Customer ID` = T3.`Customer ID` INNER JOIN people AS T5 ON T5.`Customer ID` = T4.`Customer ID` WHERE T5.City = 'Chicago' AND T5.State = 'Illinois' ORDER BY T1.Quantity DESC LIMIT 1
| 2,386 | |
superstore
|
What are the order date and product name of the order ID CA-2011-137274 from the Central region?
|
SELECT T1.`Order Date`, T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Order ID` = 'CA-2011-137274' AND T2.Region = 'Central'
| 2,387 | ||
superstore
|
List down the customers that purchased the product named Xerox 23 in the South region.
|
product named Xerox 23 refers to "Product Name" = 'Xerox 23'; customers refers to "Customer Name"
|
SELECT DISTINCT T2.`Customer Name` FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T1.Region = 'South' AND T3.`Product Name` = 'Xerox 23'
| 2,388 | |
superstore
|
Among the products under the office supplies category, what is the product that made the highest sales in the Central region?
|
made the highest sales refers to MAX(Sales)
|
SELECT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Category = 'Office Supplies' AND T2.Region = 'Central' ORDER BY T1.Sales DESC LIMIT 1
| 2,389 | |
superstore
|
Who is the customer from the West region that received the highest discount?
|
received the highest discount refers to MAX(discount); customer refers to "Customer Name"
|
SELECT T2.`Customer Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'West' ORDER BY T1.Discount DESC LIMIT 1
| 2,390 | |
superstore
|
Provide the names of the products with a profit greater than 98% of the average profit of all products in the East region.
|
names of the products refers to "Product Name"; profit greater than 98% of the average profit refers to Profit > MULTIPLY(AVG(Profit), 0.98)
|
SELECT DISTINCT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'East' AND T1.Profit > ( SELECT AVG(Profit) * 0.98 FROM east_superstore )
| 2,391 | |
superstore
|
Name the customers from the Eastern region whose orders cost above 80000.
|
cost above 80000 refers to SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit) > 80000
|
SELECT DISTINCT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'East' AND T1.Sales / (1 - T1.Discount) * T1.Quantity - T1.Profit > 80000
| 2,392 | |
superstore
|
How many orders were made by Maxwell Schwartz in 2015?
|
Maxwell Schwartz' is the "Customer Name"; in 2015 refers to strftime('%Y', "Order Date") = '2015';
|
SELECT COUNT(DISTINCT T1.`Order ID`) FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.`Customer Name` = 'Maxwell Schwartz' AND STRFTIME('%Y', T1.`Order Date`) = '2015'
| 2,393 | |
superstore
|
Who ordered the Bush Mission Pointe Library in the Central Region?
|
Bush Mission Pointe Library' is the "Product Name";
|
SELECT DISTINCT T2.`Customer Name` FROM central_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Bush Mission Pointe Library' AND T3.Region = 'Central'
| 2,394 | |
superstore
|
Calculate the total profit by Cisco SPA301 for all regions.
|
Cisco SPA301' is the "Product Name"; all regions refers to central_superstore, south_superstore, west_superstore, east_superstore
|
SELECT SUM(T1.Profit) + SUM(T2.Profit) + SUM(T3.Profit) + SUM(T4.Profit) AS totalProfit FROM west_superstore AS T1 INNER JOIN east_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN central_superstore AS T3 ON T3.`Customer ID` = T2.`Customer ID` INNER JOIN south_superstore AS T4 ON T4.`Customer ID` = T3.`Customer ID` INNER JOIN product AS T5 ON T5.`Product ID` = T4.`Product ID` WHERE T5.`Product Name` = 'Cisco SPA301'
| 2,395 | |
superstore
|
List the products that were ordered by Anne McFarland from the Western store.
|
Anne McFarland' is the "Customer Name"; Western store refers to west_superstore; products refers to "Product Name"
|
SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Anne McFarland'
| 2,396 | |
superstore
|
List the products ordered by customers in Coachella.
|
in Coachella refers to City = 'Coachella'; products refers to "Product Name"
|
SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.City = 'Coachella'
| 2,397 | |
superstore
|
Compare the numbers of orders between the Eastern and Western stores in 2015.
|
in 2015 refers to strftime('%Y', "Order Date") = '2015'; Eastern store refers to east_superstore; Western store refers west_superstore;
|
SELECT east, west FROM ( SELECT COUNT(`Order ID`) AS east , ( SELECT COUNT(`Order ID`) FROM west_superstore WHERE `Order Date` LIKE '2015%' ) AS west FROM east_superstore WHERE `Order Date` LIKE '2015%' )
| 2,398 | |
superstore
|
List the products ordered by Matt Abelman from the Western store in 2013.
|
ordered by Matt Abelman refers to "Customer Name" = 'Matt Abelman'; in 2013 refers to "Order Date" like '2013%'
|
SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Matt Abelman' AND STRFTIME('%Y', T1.`Order Date`) = '2013'
| 2,399 |
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