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1 | 3590-3593 | Rationalised 2023-24
117
Moving Charges and
Magnetism
EXAMPLE 4 6
Example 4 6 A straight wire carrying a current of 12 A is bent into a
semi-circular arc of radius 2 0 cm as shown in Fig |
1 | 3591-3594 | 6
Example 4 6 A straight wire carrying a current of 12 A is bent into a
semi-circular arc of radius 2 0 cm as shown in Fig 4 |
1 | 3592-3595 | 6 A straight wire carrying a current of 12 A is bent into a
semi-circular arc of radius 2 0 cm as shown in Fig 4 11(a) |
1 | 3593-3596 | 0 cm as shown in Fig 4 11(a) Consider
the magnetic field B at the centre of the arc |
1 | 3594-3597 | 4 11(a) Consider
the magnetic field B at the centre of the arc (a) What is the magnetic
field due to the straight segments |
1 | 3595-3598 | 11(a) Consider
the magnetic field B at the centre of the arc (a) What is the magnetic
field due to the straight segments (b) In what way the contribution
to B from the semicircle differs from that of a circular loop and in
what way does it resemble |
1 | 3596-3599 | Consider
the magnetic field B at the centre of the arc (a) What is the magnetic
field due to the straight segments (b) In what way the contribution
to B from the semicircle differs from that of a circular loop and in
what way does it resemble (c) Would your answer be different if the
wire were bent into a semi-circular arc of the same radius but in the
opposite way as shown in Fig |
1 | 3597-3600 | (a) What is the magnetic
field due to the straight segments (b) In what way the contribution
to B from the semicircle differs from that of a circular loop and in
what way does it resemble (c) Would your answer be different if the
wire were bent into a semi-circular arc of the same radius but in the
opposite way as shown in Fig 4 |
1 | 3598-3601 | (b) In what way the contribution
to B from the semicircle differs from that of a circular loop and in
what way does it resemble (c) Would your answer be different if the
wire were bent into a semi-circular arc of the same radius but in the
opposite way as shown in Fig 4 11(b) |
1 | 3599-3602 | (c) Would your answer be different if the
wire were bent into a semi-circular arc of the same radius but in the
opposite way as shown in Fig 4 11(b) FIGURE 4 |
1 | 3600-3603 | 4 11(b) FIGURE 4 11
Solution
(a) dl and r for each element of the straight segments are parallel |
1 | 3601-3604 | 11(b) FIGURE 4 11
Solution
(a) dl and r for each element of the straight segments are parallel Therefore, dl × r = 0 |
1 | 3602-3605 | FIGURE 4 11
Solution
(a) dl and r for each element of the straight segments are parallel Therefore, dl × r = 0 Straight segments do not contribute to
|B| |
1 | 3603-3606 | 11
Solution
(a) dl and r for each element of the straight segments are parallel Therefore, dl × r = 0 Straight segments do not contribute to
|B| (b) For all segments of the semicircular arc, dl × r are all parallel to
each other (into the plane of the paper) |
1 | 3604-3607 | Therefore, dl × r = 0 Straight segments do not contribute to
|B| (b) For all segments of the semicircular arc, dl × r are all parallel to
each other (into the plane of the paper) All such contributions
add up in magnitude |
1 | 3605-3608 | Straight segments do not contribute to
|B| (b) For all segments of the semicircular arc, dl × r are all parallel to
each other (into the plane of the paper) All such contributions
add up in magnitude Hence direction of B for a semicircular arc
is given by the right-hand rule and magnitude is half that of a
circular loop |
1 | 3606-3609 | (b) For all segments of the semicircular arc, dl × r are all parallel to
each other (into the plane of the paper) All such contributions
add up in magnitude Hence direction of B for a semicircular arc
is given by the right-hand rule and magnitude is half that of a
circular loop Thus B is 1 |
1 | 3607-3610 | All such contributions
add up in magnitude Hence direction of B for a semicircular arc
is given by the right-hand rule and magnitude is half that of a
circular loop Thus B is 1 9 × 10–4 T normal to the plane of the
paper going into it |
1 | 3608-3611 | Hence direction of B for a semicircular arc
is given by the right-hand rule and magnitude is half that of a
circular loop Thus B is 1 9 × 10–4 T normal to the plane of the
paper going into it (c) Same magnitude of B but opposite in direction to that in (b) |
1 | 3609-3612 | Thus B is 1 9 × 10–4 T normal to the plane of the
paper going into it (c) Same magnitude of B but opposite in direction to that in (b) Example 4 |
1 | 3610-3613 | 9 × 10–4 T normal to the plane of the
paper going into it (c) Same magnitude of B but opposite in direction to that in (b) Example 4 7 Consider a tightly wound 100 turn coil of radius 10 cm,
carrying a current of 1 A |
1 | 3611-3614 | (c) Same magnitude of B but opposite in direction to that in (b) Example 4 7 Consider a tightly wound 100 turn coil of radius 10 cm,
carrying a current of 1 A What is the magnitude of the magnetic
field at the centre of the coil |
1 | 3612-3615 | Example 4 7 Consider a tightly wound 100 turn coil of radius 10 cm,
carrying a current of 1 A What is the magnitude of the magnetic
field at the centre of the coil Solution Since the coil is tightly wound, we may take each circular
element to have the same radius R = 10 cm = 0 |
1 | 3613-3616 | 7 Consider a tightly wound 100 turn coil of radius 10 cm,
carrying a current of 1 A What is the magnitude of the magnetic
field at the centre of the coil Solution Since the coil is tightly wound, we may take each circular
element to have the same radius R = 10 cm = 0 1 m |
1 | 3614-3617 | What is the magnitude of the magnetic
field at the centre of the coil Solution Since the coil is tightly wound, we may take each circular
element to have the same radius R = 10 cm = 0 1 m The number of
turns N = 100 |
1 | 3615-3618 | Solution Since the coil is tightly wound, we may take each circular
element to have the same radius R = 10 cm = 0 1 m The number of
turns N = 100 The magnitude of the magnetic field is,
–7
2
0
–1
4
10
10
1
2
2
10
NI
B
µR
π ×
×
×
=
=
×
4
2
10−
=
π ×
4
6 28
10
T |
1 | 3616-3619 | 1 m The number of
turns N = 100 The magnitude of the magnetic field is,
–7
2
0
–1
4
10
10
1
2
2
10
NI
B
µR
π ×
×
×
=
=
×
4
2
10−
=
π ×
4
6 28
10
T −
=
×
4 |
1 | 3617-3620 | The number of
turns N = 100 The magnitude of the magnetic field is,
–7
2
0
–1
4
10
10
1
2
2
10
NI
B
µR
π ×
×
×
=
=
×
4
2
10−
=
π ×
4
6 28
10
T −
=
×
4 6 AMPERE’S CIRCUITAL LAW
There is an alternative and appealing way in which the
Biot-Savart law may be expressed |
1 | 3618-3621 | The magnitude of the magnetic field is,
–7
2
0
–1
4
10
10
1
2
2
10
NI
B
µR
π ×
×
×
=
=
×
4
2
10−
=
π ×
4
6 28
10
T −
=
×
4 6 AMPERE’S CIRCUITAL LAW
There is an alternative and appealing way in which the
Biot-Savart law may be expressed Ampere’s circuital law
considers an open surface with a boundary (Fig |
1 | 3619-3622 | −
=
×
4 6 AMPERE’S CIRCUITAL LAW
There is an alternative and appealing way in which the
Biot-Savart law may be expressed Ampere’s circuital law
considers an open surface with a boundary (Fig 4 |
1 | 3620-3623 | 6 AMPERE’S CIRCUITAL LAW
There is an alternative and appealing way in which the
Biot-Savart law may be expressed Ampere’s circuital law
considers an open surface with a boundary (Fig 4 14) |
1 | 3621-3624 | Ampere’s circuital law
considers an open surface with a boundary (Fig 4 14) The surface has current passing through it |
1 | 3622-3625 | 4 14) The surface has current passing through it We consider
the boundary to be made up of a number of small line
elements |
1 | 3623-3626 | 14) The surface has current passing through it We consider
the boundary to be made up of a number of small line
elements Consider one such element of length dl |
1 | 3624-3627 | The surface has current passing through it We consider
the boundary to be made up of a number of small line
elements Consider one such element of length dl We
take the value of the tangential component of the
magnetic field, Bt, at this element and multiply it by the
FIGURE 4 |
1 | 3625-3628 | We consider
the boundary to be made up of a number of small line
elements Consider one such element of length dl We
take the value of the tangential component of the
magnetic field, Bt, at this element and multiply it by the
FIGURE 4 12
EXAMPLE 4 |
1 | 3626-3629 | Consider one such element of length dl We
take the value of the tangential component of the
magnetic field, Bt, at this element and multiply it by the
FIGURE 4 12
EXAMPLE 4 7
Rationalised 2023-24
Physics
118
length of that element dl [Note: Btdl=B |
1 | 3627-3630 | We
take the value of the tangential component of the
magnetic field, Bt, at this element and multiply it by the
FIGURE 4 12
EXAMPLE 4 7
Rationalised 2023-24
Physics
118
length of that element dl [Note: Btdl=B dl] |
1 | 3628-3631 | 12
EXAMPLE 4 7
Rationalised 2023-24
Physics
118
length of that element dl [Note: Btdl=B dl] All such
products are added together |
1 | 3629-3632 | 7
Rationalised 2023-24
Physics
118
length of that element dl [Note: Btdl=B dl] All such
products are added together We consider the limit as the
lengths of elements get smaller and their number gets
larger |
1 | 3630-3633 | dl] All such
products are added together We consider the limit as the
lengths of elements get smaller and their number gets
larger The sum then tends to an integral |
1 | 3631-3634 | All such
products are added together We consider the limit as the
lengths of elements get smaller and their number gets
larger The sum then tends to an integral Ampere’s law
states that this integral is equal to m0 times the total
current passing through the surface, i |
1 | 3632-3635 | We consider the limit as the
lengths of elements get smaller and their number gets
larger The sum then tends to an integral Ampere’s law
states that this integral is equal to m0 times the total
current passing through the surface, i e |
1 | 3633-3636 | The sum then tends to an integral Ampere’s law
states that this integral is equal to m0 times the total
current passing through the surface, i e ,
“B |
1 | 3634-3637 | Ampere’s law
states that this integral is equal to m0 times the total
current passing through the surface, i e ,
“B dl = m0I
[4 |
1 | 3635-3638 | e ,
“B dl = m0I
[4 17(a)]
where I is the total current through the surface |
1 | 3636-3639 | ,
“B dl = m0I
[4 17(a)]
where I is the total current through the surface The
integral is taken over the closed loop coinciding with the
boundary C of the surface |
1 | 3637-3640 | dl = m0I
[4 17(a)]
where I is the total current through the surface The
integral is taken over the closed loop coinciding with the
boundary C of the surface The relation above involves a
sign-convention, given by the right-hand rule |
1 | 3638-3641 | 17(a)]
where I is the total current through the surface The
integral is taken over the closed loop coinciding with the
boundary C of the surface The relation above involves a
sign-convention, given by the right-hand rule Let the
fingers of the right-hand be curled in the sense the
boundary is traversed in the loop integral “B |
1 | 3639-3642 | The
integral is taken over the closed loop coinciding with the
boundary C of the surface The relation above involves a
sign-convention, given by the right-hand rule Let the
fingers of the right-hand be curled in the sense the
boundary is traversed in the loop integral “B dl |
1 | 3640-3643 | The relation above involves a
sign-convention, given by the right-hand rule Let the
fingers of the right-hand be curled in the sense the
boundary is traversed in the loop integral “B dl Then
the direction of the thumb gives the sense in which the
current I is regarded as positive |
1 | 3641-3644 | Let the
fingers of the right-hand be curled in the sense the
boundary is traversed in the loop integral “B dl Then
the direction of the thumb gives the sense in which the
current I is regarded as positive For several applications, a much simplified version of
Eq |
1 | 3642-3645 | dl Then
the direction of the thumb gives the sense in which the
current I is regarded as positive For several applications, a much simplified version of
Eq [4 |
1 | 3643-3646 | Then
the direction of the thumb gives the sense in which the
current I is regarded as positive For several applications, a much simplified version of
Eq [4 17(a)] proves sufficient |
1 | 3644-3647 | For several applications, a much simplified version of
Eq [4 17(a)] proves sufficient We shall assume that, in
such cases, it is possible to choose the loop (called
an amperian loop) such that at each point of the
loop, either
(i)
B is tangential to the loop and is a non-zero constant
B, or
(ii)
B is normal to the loop, or
(iii) B vanishes |
1 | 3645-3648 | [4 17(a)] proves sufficient We shall assume that, in
such cases, it is possible to choose the loop (called
an amperian loop) such that at each point of the
loop, either
(i)
B is tangential to the loop and is a non-zero constant
B, or
(ii)
B is normal to the loop, or
(iii) B vanishes Now, let L be the length (part) of the loop for which B
is tangential |
1 | 3646-3649 | 17(a)] proves sufficient We shall assume that, in
such cases, it is possible to choose the loop (called
an amperian loop) such that at each point of the
loop, either
(i)
B is tangential to the loop and is a non-zero constant
B, or
(ii)
B is normal to the loop, or
(iii) B vanishes Now, let L be the length (part) of the loop for which B
is tangential Let Ie be the current enclosed by the loop |
1 | 3647-3650 | We shall assume that, in
such cases, it is possible to choose the loop (called
an amperian loop) such that at each point of the
loop, either
(i)
B is tangential to the loop and is a non-zero constant
B, or
(ii)
B is normal to the loop, or
(iii) B vanishes Now, let L be the length (part) of the loop for which B
is tangential Let Ie be the current enclosed by the loop Then, Eq |
1 | 3648-3651 | Now, let L be the length (part) of the loop for which B
is tangential Let Ie be the current enclosed by the loop Then, Eq (4 |
1 | 3649-3652 | Let Ie be the current enclosed by the loop Then, Eq (4 17) reduces to,
BL =m0Ie
[4 |
1 | 3650-3653 | Then, Eq (4 17) reduces to,
BL =m0Ie
[4 17(b)]
When there is a system with a symmetry such as for
a straight infinite current-carrying wire in Fig |
1 | 3651-3654 | (4 17) reduces to,
BL =m0Ie
[4 17(b)]
When there is a system with a symmetry such as for
a straight infinite current-carrying wire in Fig 4 |
1 | 3652-3655 | 17) reduces to,
BL =m0Ie
[4 17(b)]
When there is a system with a symmetry such as for
a straight infinite current-carrying wire in Fig 4 13, the
Ampere’s law enables an easy evaluation of the magnetic
field, much the same way Gauss’ law helps in
determination of the electric field |
1 | 3653-3656 | 17(b)]
When there is a system with a symmetry such as for
a straight infinite current-carrying wire in Fig 4 13, the
Ampere’s law enables an easy evaluation of the magnetic
field, much the same way Gauss’ law helps in
determination of the electric field This is exhibited in the
Example 4 |
1 | 3654-3657 | 4 13, the
Ampere’s law enables an easy evaluation of the magnetic
field, much the same way Gauss’ law helps in
determination of the electric field This is exhibited in the
Example 4 9 below |
1 | 3655-3658 | 13, the
Ampere’s law enables an easy evaluation of the magnetic
field, much the same way Gauss’ law helps in
determination of the electric field This is exhibited in the
Example 4 9 below The boundary of the loop chosen is
a circle and magnetic field is tangential to the
circumference of the circle |
1 | 3656-3659 | This is exhibited in the
Example 4 9 below The boundary of the loop chosen is
a circle and magnetic field is tangential to the
circumference of the circle The law gives, for the left hand
side of Eq |
1 | 3657-3660 | 9 below The boundary of the loop chosen is
a circle and magnetic field is tangential to the
circumference of the circle The law gives, for the left hand
side of Eq [4 |
1 | 3658-3661 | The boundary of the loop chosen is
a circle and magnetic field is tangential to the
circumference of the circle The law gives, for the left hand
side of Eq [4 17 (b)], B |
1 | 3659-3662 | The law gives, for the left hand
side of Eq [4 17 (b)], B 2pr |
1 | 3660-3663 | [4 17 (b)], B 2pr We find that the magnetic
field at a distance r outside the wire is tangential and
given by
B × 2pr = m0 I,
B = m0 I/ (2pr)
(4 |
1 | 3661-3664 | 17 (b)], B 2pr We find that the magnetic
field at a distance r outside the wire is tangential and
given by
B × 2pr = m0 I,
B = m0 I/ (2pr)
(4 18)
The above result for the infinite wire is interesting
from several points of view |
1 | 3662-3665 | 2pr We find that the magnetic
field at a distance r outside the wire is tangential and
given by
B × 2pr = m0 I,
B = m0 I/ (2pr)
(4 18)
The above result for the infinite wire is interesting
from several points of view ANDRE AMPERE (1775 –1836)
Andre Ampere (1775 –
1836) Andre Marie Ampere
was a French physicist,
mathematician and chemist
who founded the science of
electrodynamics |
1 | 3663-3666 | We find that the magnetic
field at a distance r outside the wire is tangential and
given by
B × 2pr = m0 I,
B = m0 I/ (2pr)
(4 18)
The above result for the infinite wire is interesting
from several points of view ANDRE AMPERE (1775 –1836)
Andre Ampere (1775 –
1836) Andre Marie Ampere
was a French physicist,
mathematician and chemist
who founded the science of
electrodynamics Ampere
was
a
child
prodigy
who mastered advanced
mathematics by the age of
12 |
1 | 3664-3667 | 18)
The above result for the infinite wire is interesting
from several points of view ANDRE AMPERE (1775 –1836)
Andre Ampere (1775 –
1836) Andre Marie Ampere
was a French physicist,
mathematician and chemist
who founded the science of
electrodynamics Ampere
was
a
child
prodigy
who mastered advanced
mathematics by the age of
12 Ampere grasped the
significance of Oersted’s
discovery |
1 | 3665-3668 | ANDRE AMPERE (1775 –1836)
Andre Ampere (1775 –
1836) Andre Marie Ampere
was a French physicist,
mathematician and chemist
who founded the science of
electrodynamics Ampere
was
a
child
prodigy
who mastered advanced
mathematics by the age of
12 Ampere grasped the
significance of Oersted’s
discovery He carried out a
large series of experiments
to explore the relationship
between current electricity
and magnetism |
1 | 3666-3669 | Ampere
was
a
child
prodigy
who mastered advanced
mathematics by the age of
12 Ampere grasped the
significance of Oersted’s
discovery He carried out a
large series of experiments
to explore the relationship
between current electricity
and magnetism These
investigations culminated
in
1827
with
the
publication
of
the
‘Mathematical Theory of
Electrodynamic Pheno-
mena Deduced Solely from
Experiments’ |
1 | 3667-3670 | Ampere grasped the
significance of Oersted’s
discovery He carried out a
large series of experiments
to explore the relationship
between current electricity
and magnetism These
investigations culminated
in
1827
with
the
publication
of
the
‘Mathematical Theory of
Electrodynamic Pheno-
mena Deduced Solely from
Experiments’ He hypo-
thesised that all magnetic
phenomena are due to
circulating
electric
currents |
1 | 3668-3671 | He carried out a
large series of experiments
to explore the relationship
between current electricity
and magnetism These
investigations culminated
in
1827
with
the
publication
of
the
‘Mathematical Theory of
Electrodynamic Pheno-
mena Deduced Solely from
Experiments’ He hypo-
thesised that all magnetic
phenomena are due to
circulating
electric
currents Ampere was
humble
and
absent-
minded |
1 | 3669-3672 | These
investigations culminated
in
1827
with
the
publication
of
the
‘Mathematical Theory of
Electrodynamic Pheno-
mena Deduced Solely from
Experiments’ He hypo-
thesised that all magnetic
phenomena are due to
circulating
electric
currents Ampere was
humble
and
absent-
minded He once forgot an
invitation to dine with the
Emperor Napoleon |
1 | 3670-3673 | He hypo-
thesised that all magnetic
phenomena are due to
circulating
electric
currents Ampere was
humble
and
absent-
minded He once forgot an
invitation to dine with the
Emperor Napoleon He died
of pneumonia at the age of
61 |
1 | 3671-3674 | Ampere was
humble
and
absent-
minded He once forgot an
invitation to dine with the
Emperor Napoleon He died
of pneumonia at the age of
61 His gravestone bears
the epitaph: Tandem Felix
(Happy at last) |
1 | 3672-3675 | He once forgot an
invitation to dine with the
Emperor Napoleon He died
of pneumonia at the age of
61 His gravestone bears
the epitaph: Tandem Felix
(Happy at last) (i)
It implies that the field at every point on a circle of
radius r, (with the wire along the axis), is same in
magnitude |
1 | 3673-3676 | He died
of pneumonia at the age of
61 His gravestone bears
the epitaph: Tandem Felix
(Happy at last) (i)
It implies that the field at every point on a circle of
radius r, (with the wire along the axis), is same in
magnitude In other words, the magnetic field
Rationalised 2023-24
119
Moving Charges and
Magnetism
EXAMPLE 4 |
1 | 3674-3677 | His gravestone bears
the epitaph: Tandem Felix
(Happy at last) (i)
It implies that the field at every point on a circle of
radius r, (with the wire along the axis), is same in
magnitude In other words, the magnetic field
Rationalised 2023-24
119
Moving Charges and
Magnetism
EXAMPLE 4 8
possesses what is called a cylindrical symmetry |
1 | 3675-3678 | (i)
It implies that the field at every point on a circle of
radius r, (with the wire along the axis), is same in
magnitude In other words, the magnetic field
Rationalised 2023-24
119
Moving Charges and
Magnetism
EXAMPLE 4 8
possesses what is called a cylindrical symmetry The field that
normally can depend on three coordinates depends only on one: r |
1 | 3676-3679 | In other words, the magnetic field
Rationalised 2023-24
119
Moving Charges and
Magnetism
EXAMPLE 4 8
possesses what is called a cylindrical symmetry The field that
normally can depend on three coordinates depends only on one: r Whenever there is symmetry, the solutions simplify |
1 | 3677-3680 | 8
possesses what is called a cylindrical symmetry The field that
normally can depend on three coordinates depends only on one: r Whenever there is symmetry, the solutions simplify (ii)
The field direction at any point on this circle is tangential to it |
1 | 3678-3681 | The field that
normally can depend on three coordinates depends only on one: r Whenever there is symmetry, the solutions simplify (ii)
The field direction at any point on this circle is tangential to it Thus, the lines of constant magnitude of magnetic field form
concentric circles |
1 | 3679-3682 | Whenever there is symmetry, the solutions simplify (ii)
The field direction at any point on this circle is tangential to it Thus, the lines of constant magnitude of magnetic field form
concentric circles Notice now, in Fig |
1 | 3680-3683 | (ii)
The field direction at any point on this circle is tangential to it Thus, the lines of constant magnitude of magnetic field form
concentric circles Notice now, in Fig 4 |
1 | 3681-3684 | Thus, the lines of constant magnitude of magnetic field form
concentric circles Notice now, in Fig 4 1(c), the iron filings form
concentric circles |
1 | 3682-3685 | Notice now, in Fig 4 1(c), the iron filings form
concentric circles These lines called magnetic field lines form closed
loops |
1 | 3683-3686 | 4 1(c), the iron filings form
concentric circles These lines called magnetic field lines form closed
loops This is unlike the electrostatic field lines which originate
from positive charges and end at negative charges |
1 | 3684-3687 | 1(c), the iron filings form
concentric circles These lines called magnetic field lines form closed
loops This is unlike the electrostatic field lines which originate
from positive charges and end at negative charges The expression
for the magnetic field of a straight wire provides a theoretical
justification to Oersted’s experiments |
1 | 3685-3688 | These lines called magnetic field lines form closed
loops This is unlike the electrostatic field lines which originate
from positive charges and end at negative charges The expression
for the magnetic field of a straight wire provides a theoretical
justification to Oersted’s experiments (iii)
Another interesting point to note is that even though the wire is
infinite, the field due to it at a non-zero distance is not infinite |
1 | 3686-3689 | This is unlike the electrostatic field lines which originate
from positive charges and end at negative charges The expression
for the magnetic field of a straight wire provides a theoretical
justification to Oersted’s experiments (iii)
Another interesting point to note is that even though the wire is
infinite, the field due to it at a non-zero distance is not infinite It
tends to blow up only when we come very close to the wire |
1 | 3687-3690 | The expression
for the magnetic field of a straight wire provides a theoretical
justification to Oersted’s experiments (iii)
Another interesting point to note is that even though the wire is
infinite, the field due to it at a non-zero distance is not infinite It
tends to blow up only when we come very close to the wire The
field is directly proportional to the current and inversely
proportional to the distance from the (infinitely long) current source |
1 | 3688-3691 | (iii)
Another interesting point to note is that even though the wire is
infinite, the field due to it at a non-zero distance is not infinite It
tends to blow up only when we come very close to the wire The
field is directly proportional to the current and inversely
proportional to the distance from the (infinitely long) current source (iv)
There exists a simple rule to determine the direction of the magnetic
field due to a long wire |
1 | 3689-3692 | It
tends to blow up only when we come very close to the wire The
field is directly proportional to the current and inversely
proportional to the distance from the (infinitely long) current source (iv)
There exists a simple rule to determine the direction of the magnetic
field due to a long wire This rule, called the right-hand rule*, is:
Grasp the wire in your right hand with your extended thumb pointing
in the direction of the current |
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