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918-921
cos–1 1 2 + 2 sin–1 1 2 13 If sin–1 x = y, then (A) 0 ≤ y ≤ π (B) 2 2 y π π − ≤ ≤ (C) 0 < y < π (D) 2 2 y π π − < < 14 tan–1 ( ) 1 3 sec 2 − − − is equal to (A) π (B) −π3 (C) π3 (D) 2 3 π 2 3 Properties of Inverse Trigonometric Functions In this section, we shall prove some important properties of inverse trigonometric functions
1
919-922
If sin–1 x = y, then (A) 0 ≤ y ≤ π (B) 2 2 y π π − ≤ ≤ (C) 0 < y < π (D) 2 2 y π π − < < 14 tan–1 ( ) 1 3 sec 2 − − − is equal to (A) π (B) −π3 (C) π3 (D) 2 3 π 2 3 Properties of Inverse Trigonometric Functions In this section, we shall prove some important properties of inverse trigonometric functions It may be mentioned here that these results are valid within the principal value branches of the corresponding inverse trigonometric functions and wherever they are defined
1
920-923
tan–1 ( ) 1 3 sec 2 − − − is equal to (A) π (B) −π3 (C) π3 (D) 2 3 π 2 3 Properties of Inverse Trigonometric Functions In this section, we shall prove some important properties of inverse trigonometric functions It may be mentioned here that these results are valid within the principal value branches of the corresponding inverse trigonometric functions and wherever they are defined Some results may not be valid for all values of the domains of inverse trigonometric functions
1
921-924
3 Properties of Inverse Trigonometric Functions In this section, we shall prove some important properties of inverse trigonometric functions It may be mentioned here that these results are valid within the principal value branches of the corresponding inverse trigonometric functions and wherever they are defined Some results may not be valid for all values of the domains of inverse trigonometric functions In fact, they will be valid only for some values of x for which inverse trigonometric functions are defined
1
922-925
It may be mentioned here that these results are valid within the principal value branches of the corresponding inverse trigonometric functions and wherever they are defined Some results may not be valid for all values of the domains of inverse trigonometric functions In fact, they will be valid only for some values of x for which inverse trigonometric functions are defined We will not go into the details of these values of x in the domain as this discussion goes beyond the scope of this textbook
1
923-926
Some results may not be valid for all values of the domains of inverse trigonometric functions In fact, they will be valid only for some values of x for which inverse trigonometric functions are defined We will not go into the details of these values of x in the domain as this discussion goes beyond the scope of this textbook Let us recall that if y = sin–1x, then x = sin y and if x = sin y, then y = sin–1x
1
924-927
In fact, they will be valid only for some values of x for which inverse trigonometric functions are defined We will not go into the details of these values of x in the domain as this discussion goes beyond the scope of this textbook Let us recall that if y = sin–1x, then x = sin y and if x = sin y, then y = sin–1x This is equivalent to sin (sin–1 x) = x, x ∈ [– 1, 1] and sin–1 (sin x) = x, x ∈ 2, 2 −π π      For suitable values of domain similar results follow for remaining trigonometric functions
1
925-928
We will not go into the details of these values of x in the domain as this discussion goes beyond the scope of this textbook Let us recall that if y = sin–1x, then x = sin y and if x = sin y, then y = sin–1x This is equivalent to sin (sin–1 x) = x, x ∈ [– 1, 1] and sin–1 (sin x) = x, x ∈ 2, 2 −π π      For suitable values of domain similar results follow for remaining trigonometric functions Rationalised 2023-24 28 MATHEMATICS We now consider some examples
1
926-929
Let us recall that if y = sin–1x, then x = sin y and if x = sin y, then y = sin–1x This is equivalent to sin (sin–1 x) = x, x ∈ [– 1, 1] and sin–1 (sin x) = x, x ∈ 2, 2 −π π      For suitable values of domain similar results follow for remaining trigonometric functions Rationalised 2023-24 28 MATHEMATICS We now consider some examples Example 3 Show that (i) sin–1 ( 2) 2 x1 −x = 2 sin–1 x, 1 1 2 2 x − ≤ ≤ (ii) sin–1 ( 2) 2 x1 −x = 2 cos–1 x, 1 1 2 ≤x ≤ Solution (i) Let x = sin θ
1
927-930
This is equivalent to sin (sin–1 x) = x, x ∈ [– 1, 1] and sin–1 (sin x) = x, x ∈ 2, 2 −π π      For suitable values of domain similar results follow for remaining trigonometric functions Rationalised 2023-24 28 MATHEMATICS We now consider some examples Example 3 Show that (i) sin–1 ( 2) 2 x1 −x = 2 sin–1 x, 1 1 2 2 x − ≤ ≤ (ii) sin–1 ( 2) 2 x1 −x = 2 cos–1 x, 1 1 2 ≤x ≤ Solution (i) Let x = sin θ Then sin–1 x = θ
1
928-931
Rationalised 2023-24 28 MATHEMATICS We now consider some examples Example 3 Show that (i) sin–1 ( 2) 2 x1 −x = 2 sin–1 x, 1 1 2 2 x − ≤ ≤ (ii) sin–1 ( 2) 2 x1 −x = 2 cos–1 x, 1 1 2 ≤x ≤ Solution (i) Let x = sin θ Then sin–1 x = θ We have sin–1 ( 2) 2 x1 −x = sin–1 ( ) 2 2sin 1 sin θ − θ = sin–1 (2sinθ cosθ) = sin–1 (sin2θ) = 2θ = 2 sin–1 x (ii) Take x = cos θ, then proceeding as above, we get, sin–1 ( 2) 2 x1 −x = 2 cos–1 x Example 4 Express 1 cos tan 1 sin x x − − , 23 2 π π − < x< in the simplest form
1
929-932
Example 3 Show that (i) sin–1 ( 2) 2 x1 −x = 2 sin–1 x, 1 1 2 2 x − ≤ ≤ (ii) sin–1 ( 2) 2 x1 −x = 2 cos–1 x, 1 1 2 ≤x ≤ Solution (i) Let x = sin θ Then sin–1 x = θ We have sin–1 ( 2) 2 x1 −x = sin–1 ( ) 2 2sin 1 sin θ − θ = sin–1 (2sinθ cosθ) = sin–1 (sin2θ) = 2θ = 2 sin–1 x (ii) Take x = cos θ, then proceeding as above, we get, sin–1 ( 2) 2 x1 −x = 2 cos–1 x Example 4 Express 1 cos tan 1 sin x x − − , 23 2 π π − < x< in the simplest form Solution We write 2 2 1 –1 2 2 cos sin cos 2 2 tan tan 1 sin cos sin 2sin cos 2 2 2 2 x x x x x x x x −   −     =     −    + −   = –1 2 cos sin cos sin 2 2 2 2 tan cos sin 2 2 x x x x x x      + −               −         = –1 cos sin 2 2 tan cos sin 2 2 x x x x   +       −   –1 1 tan 2 tan 1 tan 2 x x   +  =     −  = tan–1 tan 4 2 4 2 x x   π π   + = +         Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 29 Example 5 Write –1 12 cot 1 x    −   , x > 1 in the simplest form
1
930-933
Then sin–1 x = θ We have sin–1 ( 2) 2 x1 −x = sin–1 ( ) 2 2sin 1 sin θ − θ = sin–1 (2sinθ cosθ) = sin–1 (sin2θ) = 2θ = 2 sin–1 x (ii) Take x = cos θ, then proceeding as above, we get, sin–1 ( 2) 2 x1 −x = 2 cos–1 x Example 4 Express 1 cos tan 1 sin x x − − , 23 2 π π − < x< in the simplest form Solution We write 2 2 1 –1 2 2 cos sin cos 2 2 tan tan 1 sin cos sin 2sin cos 2 2 2 2 x x x x x x x x −   −     =     −    + −   = –1 2 cos sin cos sin 2 2 2 2 tan cos sin 2 2 x x x x x x      + −               −         = –1 cos sin 2 2 tan cos sin 2 2 x x x x   +       −   –1 1 tan 2 tan 1 tan 2 x x   +  =     −  = tan–1 tan 4 2 4 2 x x   π π   + = +         Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 29 Example 5 Write –1 12 cot 1 x    −   , x > 1 in the simplest form Solution Let x = sec θ, then 2 1 x − = sec2 1 θ − =tan θ Therefore, –1 12 cot 1 x − = cot–1 (cot θ) = θ = sec–1 x, which is the simplest form
1
931-934
We have sin–1 ( 2) 2 x1 −x = sin–1 ( ) 2 2sin 1 sin θ − θ = sin–1 (2sinθ cosθ) = sin–1 (sin2θ) = 2θ = 2 sin–1 x (ii) Take x = cos θ, then proceeding as above, we get, sin–1 ( 2) 2 x1 −x = 2 cos–1 x Example 4 Express 1 cos tan 1 sin x x − − , 23 2 π π − < x< in the simplest form Solution We write 2 2 1 –1 2 2 cos sin cos 2 2 tan tan 1 sin cos sin 2sin cos 2 2 2 2 x x x x x x x x −   −     =     −    + −   = –1 2 cos sin cos sin 2 2 2 2 tan cos sin 2 2 x x x x x x      + −               −         = –1 cos sin 2 2 tan cos sin 2 2 x x x x   +       −   –1 1 tan 2 tan 1 tan 2 x x   +  =     −  = tan–1 tan 4 2 4 2 x x   π π   + = +         Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 29 Example 5 Write –1 12 cot 1 x    −   , x > 1 in the simplest form Solution Let x = sec θ, then 2 1 x − = sec2 1 θ − =tan θ Therefore, –1 12 cot 1 x − = cot–1 (cot θ) = θ = sec–1 x, which is the simplest form EXERCISE 2
1
932-935
Solution We write 2 2 1 –1 2 2 cos sin cos 2 2 tan tan 1 sin cos sin 2sin cos 2 2 2 2 x x x x x x x x −   −     =     −    + −   = –1 2 cos sin cos sin 2 2 2 2 tan cos sin 2 2 x x x x x x      + −               −         = –1 cos sin 2 2 tan cos sin 2 2 x x x x   +       −   –1 1 tan 2 tan 1 tan 2 x x   +  =     −  = tan–1 tan 4 2 4 2 x x   π π   + = +         Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 29 Example 5 Write –1 12 cot 1 x    −   , x > 1 in the simplest form Solution Let x = sec θ, then 2 1 x − = sec2 1 θ − =tan θ Therefore, –1 12 cot 1 x − = cot–1 (cot θ) = θ = sec–1 x, which is the simplest form EXERCISE 2 2 Prove the following: 1
1
933-936
Solution Let x = sec θ, then 2 1 x − = sec2 1 θ − =tan θ Therefore, –1 12 cot 1 x − = cot–1 (cot θ) = θ = sec–1 x, which is the simplest form EXERCISE 2 2 Prove the following: 1 3sin–1 x = sin–1 (3x – 4x3), 1 1 – 2, 2 x   ∈    2
1
934-937
EXERCISE 2 2 Prove the following: 1 3sin–1 x = sin–1 (3x – 4x3), 1 1 – 2, 2 x   ∈    2 3cos–1 x = cos–1 (4x3 – 3x), 21 , 1 x   ∈    Write the following functions in the simplest form: 3
1
935-938
2 Prove the following: 1 3sin–1 x = sin–1 (3x – 4x3), 1 1 – 2, 2 x   ∈    2 3cos–1 x = cos–1 (4x3 – 3x), 21 , 1 x   ∈    Write the following functions in the simplest form: 3 2 1 1 1 tan x x − + − , x ≠ 0 4
1
936-939
3sin–1 x = sin–1 (3x – 4x3), 1 1 – 2, 2 x   ∈    2 3cos–1 x = cos–1 (4x3 – 3x), 21 , 1 x   ∈    Write the following functions in the simplest form: 3 2 1 1 1 tan x x − + − , x ≠ 0 4 1 1 cos tan 1 cos x x −   −     +   , 0 < x < π 5
1
937-940
3cos–1 x = cos–1 (4x3 – 3x), 21 , 1 x   ∈    Write the following functions in the simplest form: 3 2 1 1 1 tan x x − + − , x ≠ 0 4 1 1 cos tan 1 cos x x −   −     +   , 0 < x < π 5 1 cos sin tan cos sin x x x x −   −   +   , 4 −π < x < 3 4 π 6
1
938-941
2 1 1 1 tan x x − + − , x ≠ 0 4 1 1 cos tan 1 cos x x −   −     +   , 0 < x < π 5 1 cos sin tan cos sin x x x x −   −   +   , 4 −π < x < 3 4 π 6 1 2 2 tan x a x − − , |x| < a 7
1
939-942
1 1 cos tan 1 cos x x −   −     +   , 0 < x < π 5 1 cos sin tan cos sin x x x x −   −   +   , 4 −π < x < 3 4 π 6 1 2 2 tan x a x − − , |x| < a 7 2 3 1 3 2 3 tan 3 a x x a ax −   −   −   , a > 0; 3 3 − < < a a x Find the values of each of the following: 8
1
940-943
1 cos sin tan cos sin x x x x −   −   +   , 4 −π < x < 3 4 π 6 1 2 2 tan x a x − − , |x| < a 7 2 3 1 3 2 3 tan 3 a x x a ax −   −   −   , a > 0; 3 3 − < < a a x Find the values of each of the following: 8 –1 –1 1 tan 2cos 2sin 2             9
1
941-944
1 2 2 tan x a x − − , |x| < a 7 2 3 1 3 2 3 tan 3 a x x a ax −   −   −   , a > 0; 3 3 − < < a a x Find the values of each of the following: 8 –1 –1 1 tan 2cos 2sin 2             9 2 –1 –1 2 2 1 2 1 tan sin cos 2 1 1 x y x y   − +   + +   , |x | < 1, y > 0 and xy < 1 Rationalised 2023-24 30 MATHEMATICS Find the values of each of the expressions in Exercises 16 to 18
1
942-945
2 3 1 3 2 3 tan 3 a x x a ax −   −   −   , a > 0; 3 3 − < < a a x Find the values of each of the following: 8 –1 –1 1 tan 2cos 2sin 2             9 2 –1 –1 2 2 1 2 1 tan sin cos 2 1 1 x y x y   − +   + +   , |x | < 1, y > 0 and xy < 1 Rationalised 2023-24 30 MATHEMATICS Find the values of each of the expressions in Exercises 16 to 18 10
1
943-946
–1 –1 1 tan 2cos 2sin 2             9 2 –1 –1 2 2 1 2 1 tan sin cos 2 1 1 x y x y   − +   + +   , |x | < 1, y > 0 and xy < 1 Rationalised 2023-24 30 MATHEMATICS Find the values of each of the expressions in Exercises 16 to 18 10 –1 2 sin sin 3 π       11
1
944-947
2 –1 –1 2 2 1 2 1 tan sin cos 2 1 1 x y x y   − +   + +   , |x | < 1, y > 0 and xy < 1 Rationalised 2023-24 30 MATHEMATICS Find the values of each of the expressions in Exercises 16 to 18 10 –1 2 sin sin 3 π       11 –1 3 tan tan 4 π       12
1
945-948
10 –1 2 sin sin 3 π       11 –1 3 tan tan 4 π       12 –1 –1 3 3 tan sin cot 5 2   +     13
1
946-949
–1 2 sin sin 3 π       11 –1 3 tan tan 4 π       12 –1 –1 3 3 tan sin cot 5 2   +     13 1 7 cos cos is equal to 6 − π       (A) 7 π6 (B) 5 π6 (C) π3 (D) 6 π 14
1
947-950
–1 3 tan tan 4 π       12 –1 –1 3 3 tan sin cot 5 2   +     13 1 7 cos cos is equal to 6 − π       (A) 7 π6 (B) 5 π6 (C) π3 (D) 6 π 14 1 1 sin sin ( ) 3 2 − π  − −     is equal to (A) 1 2 (B) 1 3 (C) 1 4 (D) 1 15
1
948-951
–1 –1 3 3 tan sin cot 5 2   +     13 1 7 cos cos is equal to 6 − π       (A) 7 π6 (B) 5 π6 (C) π3 (D) 6 π 14 1 1 sin sin ( ) 3 2 − π  − −     is equal to (A) 1 2 (B) 1 3 (C) 1 4 (D) 1 15 1 1 tan 3 cot ( 3) − − − − is equal to (A) π (B) −π2 (C) 0 (D) 2 3 Miscellaneous Examples Example 6 Find the value of 1 3 sin (sin ) 5 − π Solution We know that sin1 (sin ) x x − =
1
949-952
1 7 cos cos is equal to 6 − π       (A) 7 π6 (B) 5 π6 (C) π3 (D) 6 π 14 1 1 sin sin ( ) 3 2 − π  − −     is equal to (A) 1 2 (B) 1 3 (C) 1 4 (D) 1 15 1 1 tan 3 cot ( 3) − − − − is equal to (A) π (B) −π2 (C) 0 (D) 2 3 Miscellaneous Examples Example 6 Find the value of 1 3 sin (sin ) 5 − π Solution We know that sin1 (sin ) x x − = Therefore, 1 3 3 sin (sin 5) 5 − π π = But 3 , 5 2 2 π π π   ∉ −     , which is the principal branch of sin–1 x However 3 3 2 sin ( ) sin( ) sin 5 5 5 π π π = π − = and 2 , 5 2 2 π π π   ∈ −     Therefore 1 1 3 2 2 sin (sin ) sin (sin ) 5 5 5 − − π π π = = Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 31 Miscellaneous Exercise on Chapter 2 Find the value of the following: 1
1
950-953
1 1 sin sin ( ) 3 2 − π  − −     is equal to (A) 1 2 (B) 1 3 (C) 1 4 (D) 1 15 1 1 tan 3 cot ( 3) − − − − is equal to (A) π (B) −π2 (C) 0 (D) 2 3 Miscellaneous Examples Example 6 Find the value of 1 3 sin (sin ) 5 − π Solution We know that sin1 (sin ) x x − = Therefore, 1 3 3 sin (sin 5) 5 − π π = But 3 , 5 2 2 π π π   ∉ −     , which is the principal branch of sin–1 x However 3 3 2 sin ( ) sin( ) sin 5 5 5 π π π = π − = and 2 , 5 2 2 π π π   ∈ −     Therefore 1 1 3 2 2 sin (sin ) sin (sin ) 5 5 5 − − π π π = = Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 31 Miscellaneous Exercise on Chapter 2 Find the value of the following: 1 –1 13 cos cos 6 π       2
1
951-954
1 1 tan 3 cot ( 3) − − − − is equal to (A) π (B) −π2 (C) 0 (D) 2 3 Miscellaneous Examples Example 6 Find the value of 1 3 sin (sin ) 5 − π Solution We know that sin1 (sin ) x x − = Therefore, 1 3 3 sin (sin 5) 5 − π π = But 3 , 5 2 2 π π π   ∉ −     , which is the principal branch of sin–1 x However 3 3 2 sin ( ) sin( ) sin 5 5 5 π π π = π − = and 2 , 5 2 2 π π π   ∈ −     Therefore 1 1 3 2 2 sin (sin ) sin (sin ) 5 5 5 − − π π π = = Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 31 Miscellaneous Exercise on Chapter 2 Find the value of the following: 1 –1 13 cos cos 6 π       2 –1 7 tan tan 6 π       Prove that 3
1
952-955
Therefore, 1 3 3 sin (sin 5) 5 − π π = But 3 , 5 2 2 π π π   ∉ −     , which is the principal branch of sin–1 x However 3 3 2 sin ( ) sin( ) sin 5 5 5 π π π = π − = and 2 , 5 2 2 π π π   ∈ −     Therefore 1 1 3 2 2 sin (sin ) sin (sin ) 5 5 5 − − π π π = = Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 31 Miscellaneous Exercise on Chapter 2 Find the value of the following: 1 –1 13 cos cos 6 π       2 –1 7 tan tan 6 π       Prove that 3 –1 –1 3 24 2sin tan 5 7 = 4
1
953-956
–1 13 cos cos 6 π       2 –1 7 tan tan 6 π       Prove that 3 –1 –1 3 24 2sin tan 5 7 = 4 –1 –1 –1 8 3 77 sin sin tan 17 5 36 + = 5
1
954-957
–1 7 tan tan 6 π       Prove that 3 –1 –1 3 24 2sin tan 5 7 = 4 –1 –1 –1 8 3 77 sin sin tan 17 5 36 + = 5 –1 –1 –1 4 12 33 cos cos cos 5 13 65 + = 6
1
955-958
–1 –1 3 24 2sin tan 5 7 = 4 –1 –1 –1 8 3 77 sin sin tan 17 5 36 + = 5 –1 –1 –1 4 12 33 cos cos cos 5 13 65 + = 6 –1 –1 –1 12 3 56 cos sin sin 13 5 65 + = 7
1
956-959
–1 –1 –1 8 3 77 sin sin tan 17 5 36 + = 5 –1 –1 –1 4 12 33 cos cos cos 5 13 65 + = 6 –1 –1 –1 12 3 56 cos sin sin 13 5 65 + = 7 –1 –1 –1 63 5 3 tan sin cos 16 13 5 = + Prove that 8
1
957-960
–1 –1 –1 4 12 33 cos cos cos 5 13 65 + = 6 –1 –1 –1 12 3 56 cos sin sin 13 5 65 + = 7 –1 –1 –1 63 5 3 tan sin cos 16 13 5 = + Prove that 8 –1 –1 1 1 tan 2cos 1 x x x − = + , x ∈ [0, 1] 9
1
958-961
–1 –1 –1 12 3 56 cos sin sin 13 5 65 + = 7 –1 –1 –1 63 5 3 tan sin cos 16 13 5 = + Prove that 8 –1 –1 1 1 tan 2cos 1 x x x − = + , x ∈ [0, 1] 9 –1 1 sin 1 sin cot 2 1 sin 1 sin x x x x x   + + − =     + − −   , 0, 4 x π   ∈    10
1
959-962
–1 –1 –1 63 5 3 tan sin cos 16 13 5 = + Prove that 8 –1 –1 1 1 tan 2cos 1 x x x − = + , x ∈ [0, 1] 9 –1 1 sin 1 sin cot 2 1 sin 1 sin x x x x x   + + − =     + − −   , 0, 4 x π   ∈    10 –1 –1 1 1 1 tan cos 4 2 1 1 x x x x x   + − − =π −     + + −   , 1 1 2 x − ≤ ≤ [Hint: Put x = cos 2θ] Solve the following equations: 11
1
960-963
–1 –1 1 1 tan 2cos 1 x x x − = + , x ∈ [0, 1] 9 –1 1 sin 1 sin cot 2 1 sin 1 sin x x x x x   + + − =     + − −   , 0, 4 x π   ∈    10 –1 –1 1 1 1 tan cos 4 2 1 1 x x x x x   + − − =π −     + + −   , 1 1 2 x − ≤ ≤ [Hint: Put x = cos 2θ] Solve the following equations: 11 2tan–1 (cos x) = tan–1 (2 cosec x) 12
1
961-964
–1 1 sin 1 sin cot 2 1 sin 1 sin x x x x x   + + − =     + − −   , 0, 4 x π   ∈    10 –1 –1 1 1 1 tan cos 4 2 1 1 x x x x x   + − − =π −     + + −   , 1 1 2 x − ≤ ≤ [Hint: Put x = cos 2θ] Solve the following equations: 11 2tan–1 (cos x) = tan–1 (2 cosec x) 12 –1 –1 1 1 tan tan ,( 0) 1 2 x x x x − = > + 13
1
962-965
–1 –1 1 1 1 tan cos 4 2 1 1 x x x x x   + − − =π −     + + −   , 1 1 2 x − ≤ ≤ [Hint: Put x = cos 2θ] Solve the following equations: 11 2tan–1 (cos x) = tan–1 (2 cosec x) 12 –1 –1 1 1 tan tan ,( 0) 1 2 x x x x − = > + 13 sin (tan–1 x), |x| < 1 is equal to (A) 2 1 x x − (B) 2 1 1 x − (C) 2 1 1 x + (D) 2 1 x x + 14
1
963-966
2tan–1 (cos x) = tan–1 (2 cosec x) 12 –1 –1 1 1 tan tan ,( 0) 1 2 x x x x − = > + 13 sin (tan–1 x), |x| < 1 is equal to (A) 2 1 x x − (B) 2 1 1 x − (C) 2 1 1 x + (D) 2 1 x x + 14 sin–1 (1 – x) – 2 sin–1 x = 2 π , then x is equal to (A) 0, 1 2 (B) 1, 1 2 (C) 0 (D) 1 2 Rationalised 2023-24 32 MATHEMATICS Summary ® The domains and ranges (principal value branches) of inverse trigonometric functions are given in the following table: Functions Domain Range (Principal Value Branches) y = sin–1 x [–1, 1] 2, 2 −π π      y = cos–1 x [–1, 1] [0, π] y = cosec–1 x R – (–1,1) 2, 2 −π π      – {0} y = sec–1 x R – (–1, 1) [0, π] – { } 2 π y = tan–1 x R , 2 2 π π   −    y = cot–1 x R (0, π) ® sin–1x should not be confused with (sin x)–1
1
964-967
–1 –1 1 1 tan tan ,( 0) 1 2 x x x x − = > + 13 sin (tan–1 x), |x| < 1 is equal to (A) 2 1 x x − (B) 2 1 1 x − (C) 2 1 1 x + (D) 2 1 x x + 14 sin–1 (1 – x) – 2 sin–1 x = 2 π , then x is equal to (A) 0, 1 2 (B) 1, 1 2 (C) 0 (D) 1 2 Rationalised 2023-24 32 MATHEMATICS Summary ® The domains and ranges (principal value branches) of inverse trigonometric functions are given in the following table: Functions Domain Range (Principal Value Branches) y = sin–1 x [–1, 1] 2, 2 −π π      y = cos–1 x [–1, 1] [0, π] y = cosec–1 x R – (–1,1) 2, 2 −π π      – {0} y = sec–1 x R – (–1, 1) [0, π] – { } 2 π y = tan–1 x R , 2 2 π π   −    y = cot–1 x R (0, π) ® sin–1x should not be confused with (sin x)–1 In fact (sin x)–1 = 1 sin x and similarly for other trigonometric functions
1
965-968
sin (tan–1 x), |x| < 1 is equal to (A) 2 1 x x − (B) 2 1 1 x − (C) 2 1 1 x + (D) 2 1 x x + 14 sin–1 (1 – x) – 2 sin–1 x = 2 π , then x is equal to (A) 0, 1 2 (B) 1, 1 2 (C) 0 (D) 1 2 Rationalised 2023-24 32 MATHEMATICS Summary ® The domains and ranges (principal value branches) of inverse trigonometric functions are given in the following table: Functions Domain Range (Principal Value Branches) y = sin–1 x [–1, 1] 2, 2 −π π      y = cos–1 x [–1, 1] [0, π] y = cosec–1 x R – (–1,1) 2, 2 −π π      – {0} y = sec–1 x R – (–1, 1) [0, π] – { } 2 π y = tan–1 x R , 2 2 π π   −    y = cot–1 x R (0, π) ® sin–1x should not be confused with (sin x)–1 In fact (sin x)–1 = 1 sin x and similarly for other trigonometric functions ® The value of an inverse trigonometric functions which lies in its principal value branch is called the principal value of that inverse trigonometric functions
1
966-969
sin–1 (1 – x) – 2 sin–1 x = 2 π , then x is equal to (A) 0, 1 2 (B) 1, 1 2 (C) 0 (D) 1 2 Rationalised 2023-24 32 MATHEMATICS Summary ® The domains and ranges (principal value branches) of inverse trigonometric functions are given in the following table: Functions Domain Range (Principal Value Branches) y = sin–1 x [–1, 1] 2, 2 −π π      y = cos–1 x [–1, 1] [0, π] y = cosec–1 x R – (–1,1) 2, 2 −π π      – {0} y = sec–1 x R – (–1, 1) [0, π] – { } 2 π y = tan–1 x R , 2 2 π π   −    y = cot–1 x R (0, π) ® sin–1x should not be confused with (sin x)–1 In fact (sin x)–1 = 1 sin x and similarly for other trigonometric functions ® The value of an inverse trigonometric functions which lies in its principal value branch is called the principal value of that inverse trigonometric functions For suitable values of domain, we have ® y = sin–1 x ⇒ x = sin y ® x = sin y ⇒ y = sin–1 x ® sin (sin–1 x) = x ® sin–1 (sin x) = x Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 33 Historical Note The study of trigonometry was first started in India
1
967-970
In fact (sin x)–1 = 1 sin x and similarly for other trigonometric functions ® The value of an inverse trigonometric functions which lies in its principal value branch is called the principal value of that inverse trigonometric functions For suitable values of domain, we have ® y = sin–1 x ⇒ x = sin y ® x = sin y ⇒ y = sin–1 x ® sin (sin–1 x) = x ® sin–1 (sin x) = x Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 33 Historical Note The study of trigonometry was first started in India The ancient Indian Mathematicians, Aryabhata (476A
1
968-971
® The value of an inverse trigonometric functions which lies in its principal value branch is called the principal value of that inverse trigonometric functions For suitable values of domain, we have ® y = sin–1 x ⇒ x = sin y ® x = sin y ⇒ y = sin–1 x ® sin (sin–1 x) = x ® sin–1 (sin x) = x Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 33 Historical Note The study of trigonometry was first started in India The ancient Indian Mathematicians, Aryabhata (476A D
1
969-972
For suitable values of domain, we have ® y = sin–1 x ⇒ x = sin y ® x = sin y ⇒ y = sin–1 x ® sin (sin–1 x) = x ® sin–1 (sin x) = x Rationalised 2023-24 INVERSE TRIGONOMETRIC FUNCTIONS 33 Historical Note The study of trigonometry was first started in India The ancient Indian Mathematicians, Aryabhata (476A D ), Brahmagupta (598 A
1
970-973
The ancient Indian Mathematicians, Aryabhata (476A D ), Brahmagupta (598 A D
1
971-974
D ), Brahmagupta (598 A D ), Bhaskara I (600 A
1
972-975
), Brahmagupta (598 A D ), Bhaskara I (600 A D
1
973-976
D ), Bhaskara I (600 A D ) and Bhaskara II (1114 A
1
974-977
), Bhaskara I (600 A D ) and Bhaskara II (1114 A D
1
975-978
D ) and Bhaskara II (1114 A D ) got important results of trigonometry
1
976-979
) and Bhaskara II (1114 A D ) got important results of trigonometry All this knowledge went from India to Arabia and then from there to Europe
1
977-980
D ) got important results of trigonometry All this knowledge went from India to Arabia and then from there to Europe The Greeks had also started the study of trigonometry but their approach was so clumsy that when the Indian approach became known, it was immediately adopted throughout the world
1
978-981
) got important results of trigonometry All this knowledge went from India to Arabia and then from there to Europe The Greeks had also started the study of trigonometry but their approach was so clumsy that when the Indian approach became known, it was immediately adopted throughout the world In India, the predecessor of the modern trigonometric functions, known as the sine of an angle, and the introduction of the sine function represents one of the main contribution of the siddhantas (Sanskrit astronomical works) to mathematics
1
979-982
All this knowledge went from India to Arabia and then from there to Europe The Greeks had also started the study of trigonometry but their approach was so clumsy that when the Indian approach became known, it was immediately adopted throughout the world In India, the predecessor of the modern trigonometric functions, known as the sine of an angle, and the introduction of the sine function represents one of the main contribution of the siddhantas (Sanskrit astronomical works) to mathematics Bhaskara I (about 600 A
1
980-983
The Greeks had also started the study of trigonometry but their approach was so clumsy that when the Indian approach became known, it was immediately adopted throughout the world In India, the predecessor of the modern trigonometric functions, known as the sine of an angle, and the introduction of the sine function represents one of the main contribution of the siddhantas (Sanskrit astronomical works) to mathematics Bhaskara I (about 600 A D
1
981-984
In India, the predecessor of the modern trigonometric functions, known as the sine of an angle, and the introduction of the sine function represents one of the main contribution of the siddhantas (Sanskrit astronomical works) to mathematics Bhaskara I (about 600 A D ) gave formulae to find the values of sine functions for angles more than 90°
1
982-985
Bhaskara I (about 600 A D ) gave formulae to find the values of sine functions for angles more than 90° A sixteenth century Malayalam work Yuktibhasa contains a proof for the expansion of sin (A + B)
1
983-986
D ) gave formulae to find the values of sine functions for angles more than 90° A sixteenth century Malayalam work Yuktibhasa contains a proof for the expansion of sin (A + B) Exact expression for sines or cosines of 18°, 36°, 54°, 72°, etc
1
984-987
) gave formulae to find the values of sine functions for angles more than 90° A sixteenth century Malayalam work Yuktibhasa contains a proof for the expansion of sin (A + B) Exact expression for sines or cosines of 18°, 36°, 54°, 72°, etc , were given by Bhaskara II
1
985-988
A sixteenth century Malayalam work Yuktibhasa contains a proof for the expansion of sin (A + B) Exact expression for sines or cosines of 18°, 36°, 54°, 72°, etc , were given by Bhaskara II The symbols sin–1 x, cos–1 x, etc
1
986-989
Exact expression for sines or cosines of 18°, 36°, 54°, 72°, etc , were given by Bhaskara II The symbols sin–1 x, cos–1 x, etc , for arc sin x, arc cos x, etc
1
987-990
, were given by Bhaskara II The symbols sin–1 x, cos–1 x, etc , for arc sin x, arc cos x, etc , were suggested by the astronomer Sir John F
1
988-991
The symbols sin–1 x, cos–1 x, etc , for arc sin x, arc cos x, etc , were suggested by the astronomer Sir John F W
1
989-992
, for arc sin x, arc cos x, etc , were suggested by the astronomer Sir John F W Hersehel (1813) The name of Thales (about 600 B
1
990-993
, were suggested by the astronomer Sir John F W Hersehel (1813) The name of Thales (about 600 B C
1
991-994
W Hersehel (1813) The name of Thales (about 600 B C ) is invariably associated with height and distance problems
1
992-995
Hersehel (1813) The name of Thales (about 600 B C ) is invariably associated with height and distance problems He is credited with the determination of the height of a great pyramid in Egypt by measuring shadows of the pyramid and an auxiliary staff (or gnomon) of known height, and comparing the ratios: H S =sh = tan (sun’s altitude) Thales is also said to have calculated the distance of a ship at sea through the proportionality of sides of similar triangles
1
993-996
C ) is invariably associated with height and distance problems He is credited with the determination of the height of a great pyramid in Egypt by measuring shadows of the pyramid and an auxiliary staff (or gnomon) of known height, and comparing the ratios: H S =sh = tan (sun’s altitude) Thales is also said to have calculated the distance of a ship at sea through the proportionality of sides of similar triangles Problems on height and distance using the similarity property are also found in ancient Indian works
1
994-997
) is invariably associated with height and distance problems He is credited with the determination of the height of a great pyramid in Egypt by measuring shadows of the pyramid and an auxiliary staff (or gnomon) of known height, and comparing the ratios: H S =sh = tan (sun’s altitude) Thales is also said to have calculated the distance of a ship at sea through the proportionality of sides of similar triangles Problems on height and distance using the similarity property are also found in ancient Indian works —v v v v v— Rationalised 2023-24 34 MATHEMATICS vThe essence of Mathematics lies in its freedom
1
995-998
He is credited with the determination of the height of a great pyramid in Egypt by measuring shadows of the pyramid and an auxiliary staff (or gnomon) of known height, and comparing the ratios: H S =sh = tan (sun’s altitude) Thales is also said to have calculated the distance of a ship at sea through the proportionality of sides of similar triangles Problems on height and distance using the similarity property are also found in ancient Indian works —v v v v v— Rationalised 2023-24 34 MATHEMATICS vThe essence of Mathematics lies in its freedom — CANTOR v 3
1
996-999
Problems on height and distance using the similarity property are also found in ancient Indian works —v v v v v— Rationalised 2023-24 34 MATHEMATICS vThe essence of Mathematics lies in its freedom — CANTOR v 3 1 Introduction The knowledge of matrices is necessary in various branches of mathematics
1
997-1000
—v v v v v— Rationalised 2023-24 34 MATHEMATICS vThe essence of Mathematics lies in its freedom — CANTOR v 3 1 Introduction The knowledge of matrices is necessary in various branches of mathematics Matrices are one of the most powerful tools in mathematics
1
998-1001
— CANTOR v 3 1 Introduction The knowledge of matrices is necessary in various branches of mathematics Matrices are one of the most powerful tools in mathematics This mathematical tool simplifies our work to a great extent when compared with other straight forward methods
1
999-1002
1 Introduction The knowledge of matrices is necessary in various branches of mathematics Matrices are one of the most powerful tools in mathematics This mathematical tool simplifies our work to a great extent when compared with other straight forward methods The evolution of concept of matrices is the result of an attempt to obtain compact and simple methods of solving system of linear equations
1
1000-1003
Matrices are one of the most powerful tools in mathematics This mathematical tool simplifies our work to a great extent when compared with other straight forward methods The evolution of concept of matrices is the result of an attempt to obtain compact and simple methods of solving system of linear equations Matrices are not only used as a representation of the coefficients in system of linear equations, but utility of matrices far exceeds that use
1
1001-1004
This mathematical tool simplifies our work to a great extent when compared with other straight forward methods The evolution of concept of matrices is the result of an attempt to obtain compact and simple methods of solving system of linear equations Matrices are not only used as a representation of the coefficients in system of linear equations, but utility of matrices far exceeds that use Matrix notation and operations are used in electronic spreadsheet programs for personal computer, which in turn is used in different areas of business and science like budgeting, sales projection, cost estimation, analysing the results of an experiment etc
1
1002-1005
The evolution of concept of matrices is the result of an attempt to obtain compact and simple methods of solving system of linear equations Matrices are not only used as a representation of the coefficients in system of linear equations, but utility of matrices far exceeds that use Matrix notation and operations are used in electronic spreadsheet programs for personal computer, which in turn is used in different areas of business and science like budgeting, sales projection, cost estimation, analysing the results of an experiment etc Also, many physical operations such as magnification, rotation and reflection through a plane can be represented mathematically by matrices
1
1003-1006
Matrices are not only used as a representation of the coefficients in system of linear equations, but utility of matrices far exceeds that use Matrix notation and operations are used in electronic spreadsheet programs for personal computer, which in turn is used in different areas of business and science like budgeting, sales projection, cost estimation, analysing the results of an experiment etc Also, many physical operations such as magnification, rotation and reflection through a plane can be represented mathematically by matrices Matrices are also used in cryptography
1
1004-1007
Matrix notation and operations are used in electronic spreadsheet programs for personal computer, which in turn is used in different areas of business and science like budgeting, sales projection, cost estimation, analysing the results of an experiment etc Also, many physical operations such as magnification, rotation and reflection through a plane can be represented mathematically by matrices Matrices are also used in cryptography This mathematical tool is not only used in certain branches of sciences, but also in genetics, economics, sociology, modern psychology and industrial management
1
1005-1008
Also, many physical operations such as magnification, rotation and reflection through a plane can be represented mathematically by matrices Matrices are also used in cryptography This mathematical tool is not only used in certain branches of sciences, but also in genetics, economics, sociology, modern psychology and industrial management In this chapter, we shall find it interesting to become acquainted with the fundamentals of matrix and matrix algebra
1
1006-1009
Matrices are also used in cryptography This mathematical tool is not only used in certain branches of sciences, but also in genetics, economics, sociology, modern psychology and industrial management In this chapter, we shall find it interesting to become acquainted with the fundamentals of matrix and matrix algebra 3
1
1007-1010
This mathematical tool is not only used in certain branches of sciences, but also in genetics, economics, sociology, modern psychology and industrial management In this chapter, we shall find it interesting to become acquainted with the fundamentals of matrix and matrix algebra 3 2 Matrix Suppose we wish to express the information that Radha has 15 notebooks
1
1008-1011
In this chapter, we shall find it interesting to become acquainted with the fundamentals of matrix and matrix algebra 3 2 Matrix Suppose we wish to express the information that Radha has 15 notebooks We may express it as [15] with the understanding that the number inside [ ] is the number of notebooks that Radha has
1
1009-1012
3 2 Matrix Suppose we wish to express the information that Radha has 15 notebooks We may express it as [15] with the understanding that the number inside [ ] is the number of notebooks that Radha has Now, if we have to express that Radha has 15 notebooks and 6 pens
1
1010-1013
2 Matrix Suppose we wish to express the information that Radha has 15 notebooks We may express it as [15] with the understanding that the number inside [ ] is the number of notebooks that Radha has Now, if we have to express that Radha has 15 notebooks and 6 pens We may express it as [15 6] with the understanding that first number inside [ ] is the number of notebooks while the other one is the number of pens possessed by Radha
1
1011-1014
We may express it as [15] with the understanding that the number inside [ ] is the number of notebooks that Radha has Now, if we have to express that Radha has 15 notebooks and 6 pens We may express it as [15 6] with the understanding that first number inside [ ] is the number of notebooks while the other one is the number of pens possessed by Radha Let us now suppose that we wish to express the information of possession Chapter 3 MATRICES Rationalised 2023-24 MATRICES 35 of notebooks and pens by Radha and her two friends Fauzia and Simran which is as follows: Radha has 15 notebooks and 6 pens, Fauzia has 10 notebooks and 2 pens, Simran has 13 notebooks and 5 pens
1
1012-1015
Now, if we have to express that Radha has 15 notebooks and 6 pens We may express it as [15 6] with the understanding that first number inside [ ] is the number of notebooks while the other one is the number of pens possessed by Radha Let us now suppose that we wish to express the information of possession Chapter 3 MATRICES Rationalised 2023-24 MATRICES 35 of notebooks and pens by Radha and her two friends Fauzia and Simran which is as follows: Radha has 15 notebooks and 6 pens, Fauzia has 10 notebooks and 2 pens, Simran has 13 notebooks and 5 pens Now this could be arranged in the tabular form as follows: Notebooks Pens Radha 15 6 Fauzia 10 2 Simran 13 5 and this can be expressed as or Radha Fauzia Simran Notebooks 15 10 13 Pens 6 2 5 which can be expressed as: In the first arrangement the entries in the first column represent the number of note books possessed by Radha, Fauzia and Simran, respectively and the entries in the second column represent the number of pens possessed by Radha, Fauzia and Simran, Rationalised 2023-24 36 MATHEMATICS respectively
1
1013-1016
We may express it as [15 6] with the understanding that first number inside [ ] is the number of notebooks while the other one is the number of pens possessed by Radha Let us now suppose that we wish to express the information of possession Chapter 3 MATRICES Rationalised 2023-24 MATRICES 35 of notebooks and pens by Radha and her two friends Fauzia and Simran which is as follows: Radha has 15 notebooks and 6 pens, Fauzia has 10 notebooks and 2 pens, Simran has 13 notebooks and 5 pens Now this could be arranged in the tabular form as follows: Notebooks Pens Radha 15 6 Fauzia 10 2 Simran 13 5 and this can be expressed as or Radha Fauzia Simran Notebooks 15 10 13 Pens 6 2 5 which can be expressed as: In the first arrangement the entries in the first column represent the number of note books possessed by Radha, Fauzia and Simran, respectively and the entries in the second column represent the number of pens possessed by Radha, Fauzia and Simran, Rationalised 2023-24 36 MATHEMATICS respectively Similarly, in the second arrangement, the entries in the first row represent the number of notebooks possessed by Radha, Fauzia and Simran, respectively
1
1014-1017
Let us now suppose that we wish to express the information of possession Chapter 3 MATRICES Rationalised 2023-24 MATRICES 35 of notebooks and pens by Radha and her two friends Fauzia and Simran which is as follows: Radha has 15 notebooks and 6 pens, Fauzia has 10 notebooks and 2 pens, Simran has 13 notebooks and 5 pens Now this could be arranged in the tabular form as follows: Notebooks Pens Radha 15 6 Fauzia 10 2 Simran 13 5 and this can be expressed as or Radha Fauzia Simran Notebooks 15 10 13 Pens 6 2 5 which can be expressed as: In the first arrangement the entries in the first column represent the number of note books possessed by Radha, Fauzia and Simran, respectively and the entries in the second column represent the number of pens possessed by Radha, Fauzia and Simran, Rationalised 2023-24 36 MATHEMATICS respectively Similarly, in the second arrangement, the entries in the first row represent the number of notebooks possessed by Radha, Fauzia and Simran, respectively The entries in the second row represent the number of pens possessed by Radha, Fauzia and Simran, respectively
1
1015-1018
Now this could be arranged in the tabular form as follows: Notebooks Pens Radha 15 6 Fauzia 10 2 Simran 13 5 and this can be expressed as or Radha Fauzia Simran Notebooks 15 10 13 Pens 6 2 5 which can be expressed as: In the first arrangement the entries in the first column represent the number of note books possessed by Radha, Fauzia and Simran, respectively and the entries in the second column represent the number of pens possessed by Radha, Fauzia and Simran, Rationalised 2023-24 36 MATHEMATICS respectively Similarly, in the second arrangement, the entries in the first row represent the number of notebooks possessed by Radha, Fauzia and Simran, respectively The entries in the second row represent the number of pens possessed by Radha, Fauzia and Simran, respectively An arrangement or display of the above kind is called a matrix
1
1016-1019
Similarly, in the second arrangement, the entries in the first row represent the number of notebooks possessed by Radha, Fauzia and Simran, respectively The entries in the second row represent the number of pens possessed by Radha, Fauzia and Simran, respectively An arrangement or display of the above kind is called a matrix Formally, we define matrix as: Definition 1 A matrix is an ordered rectangular array of numbers or functions
1
1017-1020
The entries in the second row represent the number of pens possessed by Radha, Fauzia and Simran, respectively An arrangement or display of the above kind is called a matrix Formally, we define matrix as: Definition 1 A matrix is an ordered rectangular array of numbers or functions The numbers or functions are called the elements or the entries of the matrix